text stringlengths 0 205 |
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align:start position:0% |
where Phi n was given using the |
align:start position:0% |
where Phi n was given using the |
arctangent formula and |
align:start position:0% |
arctangent formula and |
align:start position:0% |
arctangent formula and |
this gives us a solution which note is |
align:start position:0% |
this gives us a solution which note is |
align:start position:0% |
this gives us a solution which note is |
periodic with period 2 t.o |
align:start position:0% |
periodic with period 2 t.o |
align:start position:0% |
periodic with period 2 t.o |
right I i should also note that 5n is |
align:start position:0% |
right I i should also note that 5n is |
align:start position:0% |
right I i should also note that 5n is |
between |
align:start position:0% |
align:start position:0% |
0 and 2 pi |
align:start position:0% |
0 and 2 pi |
align:start position:0% |
0 and 2 pi |
sorry 0 it and pie |
align:start position:0% |
sorry 0 it and pie |
align:start position:0% |
sorry 0 it and pie |
and |
align:start position:0% |
and |
align:start position:0% |
and |
this gives us this one solution to the |
align:start position:0% |
this gives us this one solution to the |
align:start position:0% |
this gives us this one solution to the |
differential equation with a forcing of |
align:start position:0% |
differential equation with a forcing of |
align:start position:0% |
differential equation with a forcing of |
sine NT on the right hand side |
align:start position:0% |
sine NT on the right hand side |
align:start position:0% |
sine NT on the right hand side |
so now what we want to do is we want to |
align:start position:0% |
so now what we want to do is we want to |
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