text stringlengths 0 205 |
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equals 0 at x at t equals x I get the |
align:start position:0% |
equals 0 at x at t equals x I get the |
natural log of 1 plus X and when I |
align:start position:0% |
natural log of 1 plus X and when I |
align:start position:0% |
natural log of 1 plus X and when I |
evaluate |
align:start position:0% |
evaluate |
align:start position:0% |
evaluate |
the natural log at 0 I get the natural |
align:start position:0% |
the natural log at 0 I get the natural |
align:start position:0% |
the natural log at 0 I get the natural |
log of 1 which is 0 so this is what you |
align:start position:0% |
log of 1 which is 0 so this is what you |
align:start position:0% |
log of 1 which is 0 so this is what you |
get |
align:start position:0% |
get |
align:start position:0% |
get |
ok |
align:start position:0% |
ok |
align:start position:0% |
ok |
this is really a valid by the way for |
align:start position:0% |
align:start position:0% |
for X bigger than minus 1 |
align:start position:0% |
for X bigger than minus 1 |
align:start position:0% |
for X bigger than minus 1 |
but don't want to think about this quite |
align:start position:0% |
but don't want to think about this quite |
align:start position:0% |
but don't want to think about this quite |
like this when X is smaller than that |
align:start position:0% |
like this when X is smaller than that |
align:start position:0% |
like this when X is smaller than that |
ok now I'm going to I'm going to try to |
align:start position:0% |
ok now I'm going to I'm going to try to |
align:start position:0% |
ok now I'm going to I'm going to try to |
apply power series methods here and find |
align:start position:0% |
apply power series methods here and find |
align:start position:0% |
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