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dict | verification_info
dict |
|---|---|---|---|---|---|---|---|
apps
|
verifiable_code
|
156
|
Solve the following coding problem using the programming language python:
Today, Osama gave Fadi an integer $X$, and Fadi was wondering about the minimum possible value of $max(a, b)$ such that $LCM(a, b)$ equals $X$. Both $a$ and $b$ should be positive integers.
$LCM(a, b)$ is the smallest positive integer that is divisible by both $a$ and $b$. For example, $LCM(6, 8) = 24$, $LCM(4, 12) = 12$, $LCM(2, 3) = 6$.
Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?
-----Input-----
The first and only line contains an integer $X$ ($1 \le X \le 10^{12}$).
-----Output-----
Print two positive integers, $a$ and $b$, such that the value of $max(a, b)$ is minimum possible and $LCM(a, b)$ equals $X$. If there are several possible such pairs, you can print any.
-----Examples-----
Input
2
Output
1 2
Input
6
Output
2 3
Input
4
Output
1 4
Input
1
Output
1 1
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import math
x = int(input())
ans = 10**13
ab = [1, 1]
for i in range(1, int(x**(1/2))+1):
if x % i == 0:
a = x//i
b = i
g = math.gcd(a, b)
a *= g
b *= g
if ans > max(a, b):
ans = max(a, b)
ab = [a, b]
print(ab[0], ab[1])
```
|
vfc_10378
|
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apps
|
verifiable_code
|
157
|
Solve the following coding problem using the programming language python:
Nikolay has a lemons, b apples and c pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1: 2: 4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — lemons, apples and pears — should be put in the compote as whole fruits.
Your task is to determine the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. It is possible that Nikolay can't use any fruits, in this case print 0.
-----Input-----
The first line contains the positive integer a (1 ≤ a ≤ 1000) — the number of lemons Nikolay has.
The second line contains the positive integer b (1 ≤ b ≤ 1000) — the number of apples Nikolay has.
The third line contains the positive integer c (1 ≤ c ≤ 1000) — the number of pears Nikolay has.
-----Output-----
Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote.
-----Examples-----
Input
2
5
7
Output
7
Input
4
7
13
Output
21
Input
2
3
2
Output
0
-----Note-----
In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n1 = int( input() )
n2 = int( input() )
n3 = int( input() )
print( min( n1 , n2 // 2 , n3 // 4 ) * 7 )
```
|
vfc_10382
|
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}
|
apps
|
verifiable_code
|
158
|
Solve the following coding problem using the programming language python:
Berland annual chess tournament is coming!
Organizers have gathered 2·n chess players who should be divided into two teams with n people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizers should divide all 2·n players into two teams with n people each in such a way that the first team always wins.
Every chess player has its rating r_{i}. It is known that chess player with the greater rating always wins the player with the lower rating. If their ratings are equal then any of the players can win.
After teams assignment there will come a drawing to form n pairs of opponents: in each pair there is a player from the first team and a player from the second team. Every chess player should be in exactly one pair. Every pair plays once. The drawing is totally random.
Is it possible to divide all 2·n players into two teams with n people each so that the player from the first team in every pair wins regardless of the results of the drawing?
-----Input-----
The first line contains one integer n (1 ≤ n ≤ 100).
The second line contains 2·n integers a_1, a_2, ... a_2n (1 ≤ a_{i} ≤ 1000).
-----Output-----
If it's possible to divide all 2·n players into two teams with n people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO".
-----Examples-----
Input
2
1 3 2 4
Output
YES
Input
1
3 3
Output
NO
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
z = list(map(int, input().split()))
z.sort()
if z[n - 1] < z[n]:
print("YES")
else:
print("NO")
```
|
vfc_10386
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/845/A",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
159
|
Solve the following coding problem using the programming language python:
You are given an array of n elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 10^9 in any place in the array.
An array is co-prime if any two adjacent numbers of it are co-prime.
In the number theory, two integers a and b are said to be co-prime if the only positive integer that divides both of them is 1.
-----Input-----
The first line contains integer n (1 ≤ n ≤ 1000) — the number of elements in the given array.
The second line contains n integers a_{i} (1 ≤ a_{i} ≤ 10^9) — the elements of the array a.
-----Output-----
Print integer k on the first line — the least number of elements needed to add to the array a to make it co-prime.
The second line should contain n + k integers a_{j} — the elements of the array a after adding k elements to it. Note that the new array should be co-prime, so any two adjacent values should be co-prime. Also the new array should be got from the original array a by adding k elements to it.
If there are multiple answers you can print any one of them.
-----Example-----
Input
3
2 7 28
Output
1
2 7 9 28
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import fractions
n = int(input())
A = [int(x) for x in input().split()]
B = []
for i in range(n-1):
B.append(A[i])
if fractions.gcd(A[i], A[i+1]) != 1:
B.append(1)
B.append(A[-1])
print(len(B) - n)
print(' '.join(map(str, B)))
```
|
vfc_10390
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/660/A",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
160
|
Solve the following coding problem using the programming language python:
We have a sequence of N integers: A_1, A_2, \cdots, A_N.
You can perform the following operation between 0 and K times (inclusive):
- Choose two integers i and j such that i \neq j, each between 1 and N (inclusive). Add 1 to A_i and -1 to A_j, possibly producing a negative element.
Compute the maximum possible positive integer that divides every element of A after the operations. Here a positive integer x divides an integer y if and only if there exists an integer z such that y = xz.
-----Constraints-----
- 2 \leq N \leq 500
- 1 \leq A_i \leq 10^6
- 0 \leq K \leq 10^9
- All values in input are integers.
-----Input-----
Input is given from Standard Input in the following format:
N K
A_1 A_2 \cdots A_{N-1} A_{N}
-----Output-----
Print the maximum possible positive integer that divides every element of A after the operations.
-----Sample Input-----
2 3
8 20
-----Sample Output-----
7
7 will divide every element of A if, for example, we perform the following operation:
- Choose i = 2, j = 1. A becomes (7, 21).
We cannot reach the situation where 8 or greater integer divides every element of A.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
# 割り切る数は、Aの総和の約数である
# 自分自身を除く約数について大きい順にすべて試して、当てはまるものがあれば答え
# 8,20を7の倍数に近づけるとき、
# 8 -> mod 7が1であり、-1か+6で7の倍数になる
# 20 -> mod 7が6であり、-6か+1で7の倍数になる
# -1と+1をペアにすることが出来て、この操作回数1をK = 3から引くと2となり、これが偶数ならOK
import sys
readline = sys.stdin.readline
N,K = map(int,readline().split())
A = list(map(int,readline().split()))
all = sum(A)
divisors = []
for i in range(1,int(all ** 0.5) + 1):
if all % i == 0:
divisors.append(i)
divisors.append(all // i)
divisors = sorted(divisors,reverse = True)
#print(divisors)
for d in divisors:
mods = [0] * (N)
for i in range(len(A)):
mods[i] = A[i] % d
mods = sorted(mods)
#print("d",d,"mods",mods)
mods_front = [0] * N
mods_front[0] = mods[0]
for i in range(1,N):
mods_front[i] = mods_front[i - 1] + mods[i]
mods_back = [0] * N
mods_back[-1] = d - mods[-1]
#print("mods_front",mods_front)
for i in range(N - 2,-1,-1):
mods_back[i] = mods_back[i + 1] + (d - mods[i])
#print("mods_back",mods_back)
for i in range(N - 1):
if mods_front[i] == mods_back[i + 1]:
if K >= min(mods_front[i],mods_back[i + 1]):
print(d)
return
else:
print(1)
```
|
vfc_10394
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://atcoder.jp/contests/abc136/tasks/abc136_e",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
161
|
Solve the following coding problem using the programming language python:
Cat Furrier Transform is a popular algorithm among cat programmers to create longcats. As one of the greatest cat programmers ever exist, Neko wants to utilize this algorithm to create the perfect longcat.
Assume that we have a cat with a number $x$. A perfect longcat is a cat with a number equal $2^m - 1$ for some non-negative integer $m$. For example, the numbers $0$, $1$, $3$, $7$, $15$ and so on are suitable for the perfect longcats.
In the Cat Furrier Transform, the following operations can be performed on $x$: (Operation A): you select any non-negative integer $n$ and replace $x$ with $x \oplus (2^n - 1)$, with $\oplus$ being a bitwise XOR operator. (Operation B): replace $x$ with $x + 1$.
The first applied operation must be of type A, the second of type B, the third of type A again, and so on. Formally, if we number operations from one in the order they are executed, then odd-numbered operations must be of type A and the even-numbered operations must be of type B.
Neko wants to produce perfect longcats at industrial scale, thus for each cat Neko only wants to perform at most $40$ operations. Can you help Neko writing a transformation plan?
Note that it is not required to minimize the number of operations. You just need to use no more than $40$ operations.
-----Input-----
The only line contains a single integer $x$ ($1 \le x \le 10^6$).
-----Output-----
The first line should contain a single integer $t$ ($0 \le t \le 40$) — the number of operations to apply.
Then for each odd-numbered operation print the corresponding number $n_i$ in it. That is, print $\lceil \frac{t}{2} \rceil$ integers $n_i$ ($0 \le n_i \le 30$), denoting the replacement $x$ with $x \oplus (2^{n_i} - 1)$ in the corresponding step.
If there are multiple possible answers, you can print any of them. It is possible to show, that there is at least one answer in the constraints of this problem.
-----Examples-----
Input
39
Output
4
5 3
Input
1
Output
0
Input
7
Output
0
-----Note-----
In the first test, one of the transforms might be as follows: $39 \to 56 \to 57 \to 62 \to 63$. Or more precisely: Pick $n = 5$. $x$ is transformed into $39 \oplus 31$, or $56$. Increase $x$ by $1$, changing its value to $57$. Pick $n = 3$. $x$ is transformed into $57 \oplus 7$, or $62$. Increase $x$ by $1$, changing its value to $63 = 2^6 - 1$.
In the second and third test, the number already satisfies the goal requirement.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def main():
x = int(input())
n = x.bit_length()
t = 0
ans = []
while True:
if (x + 1) & (x) == 0:
break
if t & 1:
x += 1
else:
for i in range(n - 1, -1, -1):
if not (1 << i) & x:
ans.append(i + 1)
x ^= (1 << (i + 1)) - 1
break
t += 1
print(t)
print(*ans)
return 0
main()
```
|
vfc_10398
|
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"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1152/B",
"time_limit": "None"
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|
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}
|
apps
|
verifiable_code
|
162
|
Solve the following coding problem using the programming language python:
Luba thinks about watering her garden. The garden can be represented as a segment of length k. Luba has got n buckets, the i-th bucket allows her to water some continuous subsegment of garden of length exactly a_{i} each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length a_{i} if she chooses the i-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding.
-----Input-----
The first line of input contains two integer numbers n and k (1 ≤ n, k ≤ 100) — the number of buckets and the length of the garden, respectively.
The second line of input contains n integer numbers a_{i} (1 ≤ a_{i} ≤ 100) — the length of the segment that can be watered by the i-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket.
-----Output-----
Print one integer number — the minimum number of hours required to water the garden.
-----Examples-----
Input
3 6
2 3 5
Output
2
Input
6 7
1 2 3 4 5 6
Output
7
-----Note-----
In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
maxd = -1
for x in a:
if k % x == 0:
maxd = max(maxd, x)
print(k // maxd)
```
|
vfc_10402
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/915/A",
"time_limit": "None"
}
|
{
"language": "python",
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}
|
apps
|
verifiable_code
|
163
|
Solve the following coding problem using the programming language python:
On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length n such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The grasshopper wants to eat the insect.
Ostap knows that grasshopper is able to jump to any empty cell that is exactly k cells away from the current (to the left or to the right). Note that it doesn't matter whether intermediate cells are empty or not as the grasshopper makes a jump over them. For example, if k = 1 the grasshopper can jump to a neighboring cell only, and if k = 2 the grasshopper can jump over a single cell.
Your goal is to determine whether there is a sequence of jumps such that grasshopper will get from his initial position to the cell with an insect.
-----Input-----
The first line of the input contains two integers n and k (2 ≤ n ≤ 100, 1 ≤ k ≤ n - 1) — the number of cells in the line and the length of one grasshopper's jump.
The second line contains a string of length n consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the corresponding cell is empty, character '#' means that the corresponding cell contains an obstacle and grasshopper can't jump there. Character 'G' means that the grasshopper starts at this position and, finally, 'T' means that the target insect is located at this cell. It's guaranteed that characters 'G' and 'T' appear in this line exactly once.
-----Output-----
If there exists a sequence of jumps (each jump of length k), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes).
-----Examples-----
Input
5 2
#G#T#
Output
YES
Input
6 1
T....G
Output
YES
Input
7 3
T..#..G
Output
NO
Input
6 2
..GT..
Output
NO
-----Note-----
In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4.
In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times.
In the third sample, the grasshopper can't make a single jump.
In the fourth sample, the grasshopper can only jump to the cells with odd indices, thus he won't be able to reach the insect.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
from math import *
from sys import *
from queue import *
from decimal import *
n,k=(int(z) for z in input().split())
s=input()
i=0
while i<len(s) and s[i] not in ["G","T"]:
i+=1
i+=k
while i<len(s) and s[i] not in ["G","T","#"]:
i+=k
if i>=len(s) or s[i]=="#":
print("NO")
else:
print("YES")
```
|
vfc_10406
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/735/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "5 2\n#G#T#\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 1\nT....G\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "7 3\nT..#..G\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"output": "NO\n",
"type": "stdin_stdout"
},
{
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{
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"type": "stdin_stdout"
},
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"input": "100 5\nG####.####.####.####.####.####.####.####.####.####.####.####.####.#########.####.####.####.####T####\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1\nTG\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "99 1\n...T.............................................................................................G.\n",
"output": "YES\n",
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},
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|
apps
|
verifiable_code
|
164
|
Solve the following coding problem using the programming language python:
It's a beautiful April day and Wallace is playing football with his friends. But his friends do not know that Wallace actually stayed home with Gromit and sent them his robotic self instead. Robo-Wallace has several advantages over the other guys. For example, he can hit the ball directly to the specified point. And yet, the notion of a giveaway is foreign to him. The combination of these features makes the Robo-Wallace the perfect footballer — as soon as the ball gets to him, he can just aim and hit the goal. He followed this tactics in the first half of the match, but he hit the goal rarely. The opposing team has a very good goalkeeper who catches most of the balls that fly directly into the goal. But Robo-Wallace is a quick thinker, he realized that he can cheat the goalkeeper. After all, they are playing in a football box with solid walls. Robo-Wallace can kick the ball to the other side, then the goalkeeper will not try to catch the ball. Then, if the ball bounces off the wall and flies into the goal, the goal will at last be scored.
Your task is to help Robo-Wallace to detect a spot on the wall of the football box, to which the robot should kick the ball, so that the ball bounces once and only once off this wall and goes straight to the goal. In the first half of the match Robo-Wallace got a ball in the head and was severely hit. As a result, some of the schemes have been damaged. Because of the damage, Robo-Wallace can only aim to his right wall (Robo-Wallace is standing with his face to the opposing team's goal).
The football box is rectangular. Let's introduce a two-dimensional coordinate system so that point (0, 0) lies in the lower left corner of the field, if you look at the box above. Robo-Wallace is playing for the team, whose goal is to the right. It is an improvised football field, so the gate of Robo-Wallace's rivals may be not in the middle of the left wall. [Image]
In the given coordinate system you are given: y_1, y_2 — the y-coordinates of the side pillars of the goalposts of robo-Wallace's opponents; y_{w} — the y-coordinate of the wall to which Robo-Wallace is aiming; x_{b}, y_{b} — the coordinates of the ball's position when it is hit; r — the radius of the ball.
A goal is scored when the center of the ball crosses the OY axis in the given coordinate system between (0, y_1) and (0, y_2). The ball moves along a straight line. The ball's hit on the wall is perfectly elastic (the ball does not shrink from the hit), the angle of incidence equals the angle of reflection. If the ball bounces off the wall not to the goal, that is, if it hits the other wall or the goal post, then the opposing team catches the ball and Robo-Wallace starts looking for miscalculation and gets dysfunctional. Such an outcome, if possible, should be avoided. We assume that the ball touches an object, if the distance from the center of the ball to the object is no greater than the ball radius r.
-----Input-----
The first and the single line contains integers y_1, y_2, y_{w}, x_{b}, y_{b}, r (1 ≤ y_1, y_2, y_{w}, x_{b}, y_{b} ≤ 10^6; y_1 < y_2 < y_{w}; y_{b} + r < y_{w}; 2·r < y_2 - y_1).
It is guaranteed that the ball is positioned correctly in the field, doesn't cross any wall, doesn't touch the wall that Robo-Wallace is aiming at. The goal posts can't be located in the field corners.
-----Output-----
If Robo-Wallace can't score a goal in the described manner, print "-1" (without the quotes). Otherwise, print a single number x_{w} — the abscissa of his point of aiming.
If there are multiple points of aiming, print the abscissa of any of them. When checking the correctness of the answer, all comparisons are made with the permissible absolute error, equal to 10^{ - 8}.
It is recommended to print as many characters after the decimal point as possible.
-----Examples-----
Input
4 10 13 10 3 1
Output
4.3750000000
Input
1 4 6 2 2 1
Output
-1
Input
3 10 15 17 9 2
Output
11.3333333333
-----Note-----
Note that in the first and third samples other correct values of abscissa x_{w} are also possible.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
y1, y2, w, x, y, r = map(int, input().strip().split())
w -= r
y1 = 2 * w - y1 - y - r
y2 = 2 * w - y2 - y
if x * x * (y2 - y1) * (y2 - y1) <= (y1 * y1 + x * x) * r * r:
print(-1)
else:
print(f"{x * (y1 + y - w) / y1:.10f}")
```
|
vfc_10410
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/248/C",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
165
|
Solve the following coding problem using the programming language python:
Vasiliy spent his vacation in a sanatorium, came back and found that he completely forgot details of his vacation!
Every day there was a breakfast, a dinner and a supper in a dining room of the sanatorium (of course, in this order). The only thing that Vasiliy has now is a card from the dining room contaning notes how many times he had a breakfast, a dinner and a supper (thus, the card contains three integers). Vasiliy could sometimes have missed some meal, for example, he could have had a breakfast and a supper, but a dinner, or, probably, at some days he haven't been at the dining room at all.
Vasiliy doesn't remember what was the time of the day when he arrived to sanatorium (before breakfast, before dinner, before supper or after supper), and the time when he left it (before breakfast, before dinner, before supper or after supper). So he considers any of these options. After Vasiliy arrived to the sanatorium, he was there all the time until he left. Please note, that it's possible that Vasiliy left the sanatorium on the same day he arrived.
According to the notes in the card, help Vasiliy determine the minimum number of meals in the dining room that he could have missed. We shouldn't count as missed meals on the arrival day before Vasiliy's arrival and meals on the departure day after he left.
-----Input-----
The only line contains three integers b, d and s (0 ≤ b, d, s ≤ 10^18, b + d + s ≥ 1) — the number of breakfasts, dinners and suppers which Vasiliy had during his vacation in the sanatorium.
-----Output-----
Print single integer — the minimum possible number of meals which Vasiliy could have missed during his vacation.
-----Examples-----
Input
3 2 1
Output
1
Input
1 0 0
Output
0
Input
1 1 1
Output
0
Input
1000000000000000000 0 1000000000000000000
Output
999999999999999999
-----Note-----
In the first sample, Vasiliy could have missed one supper, for example, in case he have arrived before breakfast, have been in the sanatorium for two days (including the day of arrival) and then have left after breakfast on the third day.
In the second sample, Vasiliy could have arrived before breakfast, have had it, and immediately have left the sanatorium, not missing any meal.
In the third sample, Vasiliy could have been in the sanatorium for one day, not missing any meal.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a = list(map(int, input().split()))
m = max(a)
ans = 0
for i in range(3):
if a[i] < m - 1:
ans += (m - 1) - a[i]
a[i] = m - 1
print(ans)
```
|
vfc_10414
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/732/C",
"time_limit": "None"
}
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|
apps
|
verifiable_code
|
166
|
Solve the following coding problem using the programming language python:
There is a matrix A of size x × y filled with integers. For every $i \in [ 1 . . x ]$, $j \in [ 1 . . y ]$ A_{i}, j = y(i - 1) + j. Obviously, every integer from [1..xy] occurs exactly once in this matrix.
You have traversed some path in this matrix. Your path can be described as a sequence of visited cells a_1, a_2, ..., a_{n} denoting that you started in the cell containing the number a_1, then moved to the cell with the number a_2, and so on.
From the cell located in i-th line and j-th column (we denote this cell as (i, j)) you can move into one of the following cells: (i + 1, j) — only if i < x; (i, j + 1) — only if j < y; (i - 1, j) — only if i > 1; (i, j - 1) — only if j > 1.
Notice that making a move requires you to go to an adjacent cell. It is not allowed to stay in the same cell. You don't know x and y exactly, but you have to find any possible values for these numbers such that you could start in the cell containing the integer a_1, then move to the cell containing a_2 (in one step), then move to the cell containing a_3 (also in one step) and so on. Can you choose x and y so that they don't contradict with your sequence of moves?
-----Input-----
The first line contains one integer number n (1 ≤ n ≤ 200000) — the number of cells you visited on your path (if some cell is visited twice, then it's listed twice).
The second line contains n integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 10^9) — the integers in the cells on your path.
-----Output-----
If all possible values of x and y such that 1 ≤ x, y ≤ 10^9 contradict with the information about your path, print NO.
Otherwise, print YES in the first line, and in the second line print the values x and y such that your path was possible with such number of lines and columns in the matrix. Remember that they must be positive integers not exceeding 10^9.
-----Examples-----
Input
8
1 2 3 6 9 8 5 2
Output
YES
3 3
Input
6
1 2 1 2 5 3
Output
NO
Input
2
1 10
Output
YES
4 9
-----Note-----
The matrix and the path on it in the first test looks like this: [Image]
Also there exist multiple correct answers for both the first and the third examples.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
MAXN = 1000000000
n = int(input())
a = list(map(int, input().split()))
def solve1():
for i in range(n-1):
if abs(a[i]-a[i+1]) != 1:
return False
print("YES\n%d %d" % (MAXN, 1))
return True
def solve2():
w = -1
for i in range(n-1):
d = abs(a[i]-a[i+1])
if d != 1:
if w == -1:
w = d
elif w != d:
return False
if w <= 0:
return False
for i in range(n-1):
if abs(a[i]-a[i+1]) == 1 and (a[i]-1)//w != (a[i+1]-1)//w:
return False
print("YES\n%d %d" % (MAXN, w))
return True
if solve1():
pass
elif solve2():
pass
else:
print("NO")
```
|
vfc_10418
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/954/C",
"time_limit": "None"
}
|
{
"language": "python",
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{
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{
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{
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},
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},
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},
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"input": "4\n999 1000 2000 2001\n",
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},
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"output": "NO\n",
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"input": "2\n500000000 1000000000\n",
"output": "YES\n1000000000 500000000\n",
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},
{
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"input": "3\n4 5 7\n",
"output": "NO\n",
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{
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"input": "5\n1 3 4 5 4\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "7\n550 555 554 553 554 555 560\n",
"output": "YES\n1000000000 5\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
167
|
Solve the following coding problem using the programming language python:
You are given two strings a and b. You have to remove the minimum possible number of consecutive (standing one after another) characters from string b in such a way that it becomes a subsequence of string a. It can happen that you will not need to remove any characters at all, or maybe you will have to remove all of the characters from b and make it empty.
Subsequence of string s is any such string that can be obtained by erasing zero or more characters (not necessarily consecutive) from string s.
-----Input-----
The first line contains string a, and the second line — string b. Both of these strings are nonempty and consist of lowercase letters of English alphabet. The length of each string is no bigger than 10^5 characters.
-----Output-----
On the first line output a subsequence of string a, obtained from b by erasing the minimum number of consecutive characters.
If the answer consists of zero characters, output «-» (a minus sign).
-----Examples-----
Input
hi
bob
Output
-
Input
abca
accepted
Output
ac
Input
abacaba
abcdcba
Output
abcba
-----Note-----
In the first example strings a and b don't share any symbols, so the longest string that you can get is empty.
In the second example ac is a subsequence of a, and at the same time you can obtain it by erasing consecutive symbols cepted from string b.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def get_substr_ends(haystack, needle):
ans = [-1]
index = 0
for char in needle:
while index < len(haystack) and char != haystack[index]:
index += 1
ans.append(index)
if index < len(haystack):
index += 1
return ans
haystack = input()
needle = input()
pref = get_substr_ends(haystack, needle)
suff = get_substr_ends(haystack[::-1], needle[::-1])
pref_index = 0
suff_len = 0
while suff_len < len(suff) and suff[suff_len] < len(haystack):
suff_len += 1
suff_len -= 1
best_str = needle[len(needle) - suff_len:]
if len(best_str) == len(needle):
print(needle)
return
for pref_len in range(1, len(pref)):
while suff_len >= 0 and suff[suff_len] + pref[pref_len] + 2 > len(haystack):
suff_len -= 1
ans = pref_len + suff_len
if ans > len(best_str) and suff_len >= 0:
best_str = needle[:pref_len] + needle[len(needle) - suff_len:]
print(best_str if best_str else '-')
```
|
vfc_10422
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/762/C",
"time_limit": "None"
}
|
{
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"output": "-\n",
"type": "stdin_stdout"
},
{
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"output": "ac\n",
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},
{
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"input": "abacaba\nabcdcba\n",
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},
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},
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},
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},
{
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{
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"output": "zt\n",
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},
{
"fn_name": null,
"input": "aaaaaaaaaaaaaaaaaaaa\naaaaaaaa\n",
"output": "aaaaaaaa\n",
"type": "stdin_stdout"
},
{
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"input": "abba\naba\n",
"output": "aba\n",
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},
{
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"input": "abbba\naba\n",
"output": "aba\n",
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{
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"input": "aaaaaaaaaaaa\naaaaaaaaaaaa\n",
"output": "aaaaaaaaaaaa\n",
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"output": "ashish\n",
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|
apps
|
verifiable_code
|
168
|
Solve the following coding problem using the programming language python:
Vasya has a pile, that consists of some number of stones. $n$ times he either took one stone from the pile or added one stone to the pile. The pile was non-empty before each operation of taking one stone from the pile.
You are given $n$ operations which Vasya has made. Find the minimal possible number of stones that can be in the pile after making these operations.
-----Input-----
The first line contains one positive integer $n$ — the number of operations, that have been made by Vasya ($1 \leq n \leq 100$).
The next line contains the string $s$, consisting of $n$ symbols, equal to "-" (without quotes) or "+" (without quotes). If Vasya took the stone on $i$-th operation, $s_i$ is equal to "-" (without quotes), if added, $s_i$ is equal to "+" (without quotes).
-----Output-----
Print one integer — the minimal possible number of stones that can be in the pile after these $n$ operations.
-----Examples-----
Input
3
---
Output
0
Input
4
++++
Output
4
Input
2
-+
Output
1
Input
5
++-++
Output
3
-----Note-----
In the first test, if Vasya had $3$ stones in the pile at the beginning, after making operations the number of stones will be equal to $0$. It is impossible to have less number of piles, so the answer is $0$. Please notice, that the number of stones at the beginning can't be less, than $3$, because in this case, Vasya won't be able to take a stone on some operation (the pile will be empty).
In the second test, if Vasya had $0$ stones in the pile at the beginning, after making operations the number of stones will be equal to $4$. It is impossible to have less number of piles because after making $4$ operations the number of stones in the pile increases on $4$ stones. So, the answer is $4$.
In the third test, if Vasya had $1$ stone in the pile at the beginning, after making operations the number of stones will be equal to $1$. It can be proved, that it is impossible to have less number of stones after making the operations.
In the fourth test, if Vasya had $0$ stones in the pile at the beginning, after making operations the number of stones will be equal to $3$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
s = input()
b = 0
for i in s:
if i == '+':
b += 1
else:
b -= 1
b = max(b, 0)
print(b)
```
|
vfc_10426
|
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}
|
apps
|
verifiable_code
|
169
|
Solve the following coding problem using the programming language python:
Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much more complicated.
Kolya is hungry, so he went to the nearest milk shop. In 2084 you may buy kefir in a plastic liter bottle, that costs a rubles, or in glass liter bottle, that costs b rubles. Also, you may return empty glass bottle and get c (c < b) rubles back, but you cannot return plastic bottles.
Kolya has n rubles and he is really hungry, so he wants to drink as much kefir as possible. There were no plastic bottles in his 1984, so Kolya doesn't know how to act optimally and asks for your help.
-----Input-----
First line of the input contains a single integer n (1 ≤ n ≤ 10^18) — the number of rubles Kolya has at the beginning.
Then follow three lines containing integers a, b and c (1 ≤ a ≤ 10^18, 1 ≤ c < b ≤ 10^18) — the cost of one plastic liter bottle, the cost of one glass liter bottle and the money one can get back by returning an empty glass bottle, respectively.
-----Output-----
Print the only integer — maximum number of liters of kefir, that Kolya can drink.
-----Examples-----
Input
10
11
9
8
Output
2
Input
10
5
6
1
Output
2
-----Note-----
In the first sample, Kolya can buy one glass bottle, then return it and buy one more glass bottle. Thus he will drink 2 liters of kefir.
In the second sample, Kolya can buy two plastic bottle and get two liters of kefir, or he can buy one liter glass bottle, then return it and buy one plastic bottle. In both cases he will drink two liters of kefir.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n=int(input())
a=int(input())
b=int(input())
c=int(input())
r=n//a
if n > c:
r=max(r,(r-b+c)//a+1,(n-c)//(b-c)+((n-c)%(b-c)+c)//a)
print(r)
```
|
vfc_10430
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/625/A",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
170
|
Solve the following coding problem using the programming language python:
Two bored soldiers are playing card war. Their card deck consists of exactly n cards, numbered from 1 to n, all values are different. They divide cards between them in some manner, it's possible that they have different number of cards. Then they play a "war"-like card game.
The rules are following. On each turn a fight happens. Each of them picks card from the top of his stack and puts on the table. The one whose card value is bigger wins this fight and takes both cards from the table to the bottom of his stack. More precisely, he first takes his opponent's card and puts to the bottom of his stack, and then he puts his card to the bottom of his stack. If after some turn one of the player's stack becomes empty, he loses and the other one wins.
You have to calculate how many fights will happen and who will win the game, or state that game won't end.
-----Input-----
First line contains a single integer n (2 ≤ n ≤ 10), the number of cards.
Second line contains integer k_1 (1 ≤ k_1 ≤ n - 1), the number of the first soldier's cards. Then follow k_1 integers that are the values on the first soldier's cards, from top to bottom of his stack.
Third line contains integer k_2 (k_1 + k_2 = n), the number of the second soldier's cards. Then follow k_2 integers that are the values on the second soldier's cards, from top to bottom of his stack.
All card values are different.
-----Output-----
If somebody wins in this game, print 2 integers where the first one stands for the number of fights before end of game and the second one is 1 or 2 showing which player has won.
If the game won't end and will continue forever output - 1.
-----Examples-----
Input
4
2 1 3
2 4 2
Output
6 2
Input
3
1 2
2 1 3
Output
-1
-----Note-----
First sample: [Image]
Second sample: [Image]
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
k1 = list(map(int, input().split()[1:]))
k2 = list(map(int, input().split()[1:]))
i = 0
while True:
if len(k1) == 0 or len(k2) == 0:
break
if i > 10000:
break
if k1[0] > k2[0]:
k1 = k1[1:] + k2[0:1] + k1[0:1]
k2 = k2[1:]
else:
k2 = k2[1:] + k1[0:1] + k2[0:1]
k1 = k1[1:]
i += 1
if i > 10000:
print(-1)
else:
winner = 1
if len(k1) == 0:
winner = 2
print(i, winner)
```
|
vfc_10434
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/546/C",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
171
|
Solve the following coding problem using the programming language python:
You have probably registered on Internet sites many times. And each time you should enter your invented password. Usually the registration form automatically checks the password's crypt resistance. If the user's password isn't complex enough, a message is displayed. Today your task is to implement such an automatic check.
Web-developers of the company Q assume that a password is complex enough, if it meets all of the following conditions: the password length is at least 5 characters; the password contains at least one large English letter; the password contains at least one small English letter; the password contains at least one digit.
You are given a password. Please implement the automatic check of its complexity for company Q.
-----Input-----
The first line contains a non-empty sequence of characters (at most 100 characters). Each character is either a large English letter, or a small English letter, or a digit, or one of characters: "!", "?", ".", ",", "_".
-----Output-----
If the password is complex enough, print message "Correct" (without the quotes), otherwise print message "Too weak" (without the quotes).
-----Examples-----
Input
abacaba
Output
Too weak
Input
X12345
Output
Too weak
Input
CONTEST_is_STARTED!!11
Output
Correct
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
s = input().strip()
flag1 = len(s) >= 5
d1 = 'qwertyuiopasdfghjklzxcvbnm'
d2 = 'QWERTYUIOPASDFGHJKLZXCVBNM'
d3 = '123456789'
flag2 = False
flag3 = False
flag4 = False
for i in d1:
if i in s:
flag2 = True
for i in d2:
if i in s:
flag3 = True
for i in d3:
if i in s:
flag4 = True
if(flag1 and flag2 and flag3 and flag4):
print("Correct")
else:
print("Too weak")
```
|
vfc_10438
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/411/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
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"input": "X12345\n",
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|
apps
|
verifiable_code
|
172
|
Solve the following coding problem using the programming language python:
In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group A and the group B. Each group consists of exactly n students. An academic performance of each student is known — integer value between 1 and 5.
The school director wants to redistribute students between groups so that each of the two groups has the same number of students whose academic performance is equal to 1, the same number of students whose academic performance is 2 and so on. In other words, the purpose of the school director is to change the composition of groups, so that for each value of academic performance the numbers of students in both groups are equal.
To achieve this, there is a plan to produce a series of exchanges of students between groups. During the single exchange the director selects one student from the class A and one student of class B. After that, they both change their groups.
Print the least number of exchanges, in order to achieve the desired equal numbers of students for each academic performance.
-----Input-----
The first line of the input contains integer number n (1 ≤ n ≤ 100) — number of students in both groups.
The second line contains sequence of integer numbers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 5), where a_{i} is academic performance of the i-th student of the group A.
The third line contains sequence of integer numbers b_1, b_2, ..., b_{n} (1 ≤ b_{i} ≤ 5), where b_{i} is academic performance of the i-th student of the group B.
-----Output-----
Print the required minimum number of exchanges or -1, if the desired distribution of students can not be obtained.
-----Examples-----
Input
4
5 4 4 4
5 5 4 5
Output
1
Input
6
1 1 1 1 1 1
5 5 5 5 5 5
Output
3
Input
1
5
3
Output
-1
Input
9
3 2 5 5 2 3 3 3 2
4 1 4 1 1 2 4 4 1
Output
4
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
A = list(map(int,input().split()))
B = list(map(int,input().split()))
a = [0] * 5
b = [0] * 5
for j in range(n):
a[A[j]-1] += 1
b[B[j]-1] +=1
per = 0
for j in range(5):
if (a[j] + b[j]) % 2 == 1:
per = 1
break
if per == 1:
print(-1)
else:
ans = 0
for j in range(5):
if a[j] > b[j]:
ans += (a[j] - b[j])//2
print(ans)
```
|
vfc_10442
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/779/A",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
173
|
Solve the following coding problem using the programming language python:
Imagine a city with n horizontal streets crossing m vertical streets, forming an (n - 1) × (m - 1) grid. In order to increase the traffic flow, mayor of the city has decided to make each street one way. This means in each horizontal street, the traffic moves only from west to east or only from east to west. Also, traffic moves only from north to south or only from south to north in each vertical street. It is possible to enter a horizontal street from a vertical street, or vice versa, at their intersection.
[Image]
The mayor has received some street direction patterns. Your task is to check whether it is possible to reach any junction from any other junction in the proposed street direction pattern.
-----Input-----
The first line of input contains two integers n and m, (2 ≤ n, m ≤ 20), denoting the number of horizontal streets and the number of vertical streets.
The second line contains a string of length n, made of characters '<' and '>', denoting direction of each horizontal street. If the i-th character is equal to '<', the street is directed from east to west otherwise, the street is directed from west to east. Streets are listed in order from north to south.
The third line contains a string of length m, made of characters '^' and 'v', denoting direction of each vertical street. If the i-th character is equal to '^', the street is directed from south to north, otherwise the street is directed from north to south. Streets are listed in order from west to east.
-----Output-----
If the given pattern meets the mayor's criteria, print a single line containing "YES", otherwise print a single line containing "NO".
-----Examples-----
Input
3 3
><>
v^v
Output
NO
Input
4 6
<><>
v^v^v^
Output
YES
-----Note-----
The figure above shows street directions in the second sample test case.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a, b = list(map(int, input().split(' ')))
hor = input()
ver = input()
if (hor[0], ver[0]) == ('>', 'v') or (hor[0], ver[-1]) == ('<', 'v'):
print("NO")
elif (hor[-1], ver[0]) == ('>', '^') or (hor[-1], ver[-1]) == ('<', '^'):
print("NO")
else:
print("YES")
```
|
vfc_10446
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/475/B",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
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"input": "18 18\n><><<><><>>><>>>><\n^^vvv^v^^^v^vv^^^v\n",
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},
{
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},
{
"fn_name": null,
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"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "14 20\n<>><<<><<>>>>>\nvv^^v^^^^v^^vv^^vvv^\n",
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},
{
"fn_name": null,
"input": "18 18\n><><<><><>>><>>>><\n^^vvv^v^^^v^vv^^^v\n",
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},
{
"fn_name": null,
"input": "8 18\n<<<><>>>\nv^^vvv^^v^v^vvvv^^\n",
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},
{
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},
{
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"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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},
{
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},
{
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},
{
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},
{
"fn_name": null,
"input": "20 20\n><<><<<<<<<>>><>>><<\n^^^^^^^^vvvv^vv^vvvv\n",
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},
{
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},
{
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},
{
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},
{
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{
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{
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},
{
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},
{
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},
{
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{
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{
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},
{
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{
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},
{
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},
{
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"output": "NO\n",
"type": "stdin_stdout"
},
{
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"type": "stdin_stdout"
},
{
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"type": "stdin_stdout"
},
{
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"input": "20 20\n<><><><><><><><><><>\nvvvvvvvvvvvvvvvvvvvv\n",
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},
{
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},
{
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},
{
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{
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"type": "stdin_stdout"
},
{
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{
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{
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{
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{
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}
]
}
|
apps
|
verifiable_code
|
174
|
Solve the following coding problem using the programming language python:
Implication is a function of two logical arguments, its value is false if and only if the value of the first argument is true and the value of the second argument is false.
Implication is written by using character '$\rightarrow$', and the arguments and the result of the implication are written as '0' (false) and '1' (true). According to the definition of the implication:
$0 \rightarrow 0 = 1$
$0 \rightarrow 1 = 1$
$1 \rightarrow 0 = 0$
$1 \rightarrow 1 = 1$
When a logical expression contains multiple implications, then when there are no brackets, it will be calculated from left to fight. For example,
$0 \rightarrow 0 \rightarrow 0 =(0 \rightarrow 0) \rightarrow 0 = 1 \rightarrow 0 = 0$.
When there are brackets, we first calculate the expression in brackets. For example,
$0 \rightarrow(0 \rightarrow 0) = 0 \rightarrow 1 = 1$.
For the given logical expression $a_{1} \rightarrow a_{2} \rightarrow a_{3} \rightarrow \cdots \cdots a_{n}$ determine if it is possible to place there brackets so that the value of a logical expression is false. If it is possible, your task is to find such an arrangement of brackets.
-----Input-----
The first line contains integer n (1 ≤ n ≤ 100 000) — the number of arguments in a logical expression.
The second line contains n numbers a_1, a_2, ..., a_{n} ($a_{i} \in \{0,1 \}$), which means the values of arguments in the expression in the order they occur.
-----Output-----
Print "NO" (without the quotes), if it is impossible to place brackets in the expression so that its value was equal to 0.
Otherwise, print "YES" in the first line and the logical expression with the required arrangement of brackets in the second line.
The expression should only contain characters '0', '1', '-' (character with ASCII code 45), '>' (character with ASCII code 62), '(' and ')'. Characters '-' and '>' can occur in an expression only paired like that: ("->") and represent implication. The total number of logical arguments (i.e. digits '0' and '1') in the expression must be equal to n. The order in which the digits follow in the expression from left to right must coincide with a_1, a_2, ..., a_{n}.
The expression should be correct. More formally, a correct expression is determined as follows: Expressions "0", "1" (without the quotes) are correct. If v_1, v_2 are correct, then v_1->v_2 is a correct expression. If v is a correct expression, then (v) is a correct expression.
The total number of characters in the resulting expression mustn't exceed 10^6.
If there are multiple possible answers, you are allowed to print any of them.
-----Examples-----
Input
4
0 1 1 0
Output
YES
(((0)->1)->(1->0))
Input
2
1 1
Output
NO
Input
1
0
Output
YES
0
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
x = int(input())
seq = list(map(int, input().split(' ')))
if seq == [0]:
print("YES")
print(0)
elif seq == [0, 0]:
print("NO")
elif seq == [1, 0]:
print("YES")
print('1->0')
elif seq == [0, 0, 0]:
print("YES")
print("(0->0)->0")
elif seq == [1, 0, 0]:
print("NO")
elif seq[x-1] == 1:
print("NO")
#ENDS IN 1
elif seq[x-2] == 1:
print("YES")
print('->'.join([str(x) for x in seq]))
#ENDS IN 10
elif seq == [1] * (x-2) + [0, 0]:
print("NO")
#000 BELOW
elif seq[x-3] == 0:
a = ('->'.join([str(x) for x in seq][0:x-3]))
print("YES")
print(a + '->(0->0)->0')
#100
else:
last = 0
for i in range(x-1):
if seq[i] == 0 and seq[i+1] == 1:
last = i
seq[last] = '(0'
seq[last+1] = '(1'
seq[x-2] = '0))'
print("YES")
print('->'.join([str(x) for x in seq]))
```
|
vfc_10450
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/550/E",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
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}
|
apps
|
verifiable_code
|
175
|
Solve the following coding problem using the programming language python:
You have two variables a and b. Consider the following sequence of actions performed with these variables: If a = 0 or b = 0, end the process. Otherwise, go to step 2; If a ≥ 2·b, then set the value of a to a - 2·b, and repeat step 1. Otherwise, go to step 3; If b ≥ 2·a, then set the value of b to b - 2·a, and repeat step 1. Otherwise, end the process.
Initially the values of a and b are positive integers, and so the process will be finite.
You have to determine the values of a and b after the process ends.
-----Input-----
The only line of the input contains two integers n and m (1 ≤ n, m ≤ 10^18). n is the initial value of variable a, and m is the initial value of variable b.
-----Output-----
Print two integers — the values of a and b after the end of the process.
-----Examples-----
Input
12 5
Output
0 1
Input
31 12
Output
7 12
-----Note-----
Explanations to the samples: a = 12, b = 5 $\rightarrow$ a = 2, b = 5 $\rightarrow$ a = 2, b = 1 $\rightarrow$ a = 0, b = 1; a = 31, b = 12 $\rightarrow$ a = 7, b = 12.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a, b = [int(v) for v in input().split()]
while a > 0 and b > 0:
if a >= 2 * b:
a %= 2 * b
elif b >= 2 * a:
b %= 2 * a
else:
break
print(a, b)
```
|
vfc_10454
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/946/B",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
176
|
Solve the following coding problem using the programming language python:
Find the number of k-divisible numbers on the segment [a, b]. In other words you need to find the number of such integer values x that a ≤ x ≤ b and x is divisible by k.
-----Input-----
The only line contains three space-separated integers k, a and b (1 ≤ k ≤ 10^18; - 10^18 ≤ a ≤ b ≤ 10^18).
-----Output-----
Print the required number.
-----Examples-----
Input
1 1 10
Output
10
Input
2 -4 4
Output
5
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
s=input()
ast=[int(i) for i in s.split(' ')]
k,a,b=ast[0],ast[1],ast[2]
s1=(a-1)//k
s2=b//k
print(s2-s1)
```
|
vfc_10458
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/597/A",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
177
|
Solve the following coding problem using the programming language python:
Let's write all the positive integer numbers one after another from $1$ without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...
Your task is to print the $k$-th digit of this sequence.
-----Input-----
The first and only line contains integer $k$ ($1 \le k \le 10000$) — the position to process ($1$-based index).
-----Output-----
Print the $k$-th digit of the resulting infinite sequence.
-----Examples-----
Input
7
Output
7
Input
21
Output
5
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a = int(input())
s = ""
for i in range(1, a+1):
s += str(i)
print(s[a-1])
```
|
vfc_10462
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1177/A",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
178
|
Solve the following coding problem using the programming language python:
A telephone number is a sequence of exactly $11$ digits such that its first digit is 8.
Vasya and Petya are playing a game. Initially they have a string $s$ of length $n$ ($n$ is odd) consisting of digits. Vasya makes the first move, then players alternate turns. In one move the player must choose a character and erase it from the current string. For example, if the current string 1121, after the player's move it may be 112, 111 or 121. The game ends when the length of string $s$ becomes 11. If the resulting string is a telephone number, Vasya wins, otherwise Petya wins.
You have to determine if Vasya has a winning strategy (that is, if Vasya can win the game no matter which characters Petya chooses during his moves).
-----Input-----
The first line contains one integer $n$ ($13 \le n < 10^5$, $n$ is odd) — the length of string $s$.
The second line contains the string $s$ ($|s| = n$) consisting only of decimal digits.
-----Output-----
If Vasya has a strategy that guarantees him victory, print YES.
Otherwise print NO.
-----Examples-----
Input
13
8380011223344
Output
YES
Input
15
807345619350641
Output
NO
-----Note-----
In the first example Vasya needs to erase the second character. Then Petya cannot erase a character from the remaining string 880011223344 so that it does not become a telephone number.
In the second example after Vasya's turn Petya can erase one character character 8. The resulting string can't be a telephone number, because there is no digit 8 at all.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, s = int(input()), input()
cnt = (n - 11) // 2
cnt_8 = len(s[:n - 10].split('8')) - 1
if (cnt >= cnt_8):
print ("NO")
else:
print ("YES")
```
|
vfc_10466
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1155/B",
"time_limit": "None"
}
|
{
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"test_cases": [
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"output": "YES\n",
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{
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|
apps
|
verifiable_code
|
179
|
Solve the following coding problem using the programming language python:
Andrey thinks he is truly a successful developer, but in reality he didn't know about the binary search algorithm until recently. After reading some literature Andrey understood that this algorithm allows to quickly find a certain number $x$ in an array. For an array $a$ indexed from zero, and an integer $x$ the pseudocode of the algorithm is as follows:
BinarySearch(a, x)
left = 0
right = a.size()
while left < right
middle = (left + right) / 2
if a[middle] <= x then
left = middle + 1
else
right = middle
if left > 0 and a[left - 1] == x then
return true
else
return false
Note that the elements of the array are indexed from zero, and the division is done in integers (rounding down).
Andrey read that the algorithm only works if the array is sorted. However, he found this statement untrue, because there certainly exist unsorted arrays for which the algorithm find $x$!
Andrey wants to write a letter to the book authors, but before doing that he must consider the permutations of size $n$ such that the algorithm finds $x$ in them. A permutation of size $n$ is an array consisting of $n$ distinct integers between $1$ and $n$ in arbitrary order.
Help Andrey and find the number of permutations of size $n$ which contain $x$ at position $pos$ and for which the given implementation of the binary search algorithm finds $x$ (returns true). As the result may be extremely large, print the remainder of its division by $10^9+7$.
-----Input-----
The only line of input contains integers $n$, $x$ and $pos$ ($1 \le x \le n \le 1000$, $0 \le pos \le n - 1$) — the required length of the permutation, the number to search, and the required position of that number, respectively.
-----Output-----
Print a single number — the remainder of the division of the number of valid permutations by $10^9+7$.
-----Examples-----
Input
4 1 2
Output
6
Input
123 42 24
Output
824071958
-----Note-----
All possible permutations in the first test case: $(2, 3, 1, 4)$, $(2, 4, 1, 3)$, $(3, 2, 1, 4)$, $(3, 4, 1, 2)$, $(4, 2, 1, 3)$, $(4, 3, 1, 2)$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
MOD = 1000000007
def f(n, cnt):
"""
n! / (n - cnt)!
"""
ans = 1
for _ in range(cnt):
ans = (ans * n) % MOD
n -= 1
return ans
def main():
n, x, pos = list(map(int, input().split()))
chk1 = 0
chk_r = 0
left = 0
right = n
while left < right:
middle = (left + right) // 2
if middle <= pos:
if middle < pos:
chk1 += 1
left = middle + 1
else:
chk_r += 1
right = middle
if chk1 > x - 1 or chk_r > n - x:
print(0)
else:
# (x - 1)! / (x - 1 - chk1)! * (n - x)! / (n - x - chk_r)! * (n - chk1 - chk_r - 1)!
rest = n - chk1 - chk_r - 1
print(f(x - 1, chk1) * f(n - x, chk_r) * f(rest, rest) % MOD)
main()
```
|
vfc_10470
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1436/C",
"time_limit": "None"
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|
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}
|
apps
|
verifiable_code
|
180
|
Solve the following coding problem using the programming language python:
Andrey received a postcard from Irina. It contained only the words "Hello, Andrey!", and a strange string consisting of lowercase Latin letters, snowflakes and candy canes. Andrey thought that this string is an encrypted message, and decided to decrypt it.
Andrey noticed that snowflakes and candy canes always stand after the letters, so he supposed that the message was encrypted as follows. Candy cane means that the letter before it can be removed, or can be left. A snowflake means that the letter before it can be removed, left, or repeated several times.
For example, consider the following string: [Image]
This string can encode the message «happynewyear». For this, candy canes and snowflakes should be used as follows: candy cane 1: remove the letter w, snowflake 1: repeat the letter p twice, candy cane 2: leave the letter n, snowflake 2: remove the letter w, snowflake 3: leave the letter e.
[Image]
Please note that the same string can encode different messages. For example, the string above can encode «hayewyar», «happpppynewwwwwyear», and other messages.
Andrey knows that messages from Irina usually have a length of $k$ letters. Help him to find out if a given string can encode a message of $k$ letters, and if so, give an example of such a message.
-----Input-----
The first line contains the string received in the postcard. The string consists only of lowercase Latin letters, as well as the characters «*» and «?», meaning snowflake and candy cone, respectively. These characters can only appear immediately after the letter. The length of the string does not exceed $200$.
The second line contains an integer number $k$ ($1 \leq k \leq 200$), the required message length.
-----Output-----
Print any message of length $k$ that the given string can encode, or «Impossible» if such a message does not exist.
-----Examples-----
Input
hw?ap*yn?eww*ye*ar
12
Output
happynewyear
Input
ab?a
2
Output
aa
Input
ab?a
3
Output
aba
Input
ababb
5
Output
ababb
Input
ab?a
1
Output
Impossible
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
s = input()
k = int(input())
c = 0
p = 0
has_star = False
for i in range(len(s)):
if s[i] in ['*', '?']:
if s[i] == '*':
has_star = True
c -= 1
else:
p += 1
c += 1
if k < c:
print("Impossible")
elif (not has_star) and (k > p):
print("Impossible")
else:
signs_to_add = k - c
ans = ""
for i in s:
if signs_to_add == 0:
if i not in ['*', '?']:
ans += i
else:
ans = ans[:-1]
continue
if i == '?':
signs_to_add -= 1
elif i == '*':
signs_to_add -= 1
while signs_to_add > 0:
ans += ans[-1]
signs_to_add -= 1
else:
ans += i
print(ans)
```
|
vfc_10474
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1099/C",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
181
|
Solve the following coding problem using the programming language python:
Vasya started working in a machine vision company of IT City. Vasya's team creates software and hardware for identification of people by their face.
One of the project's know-how is a camera rotating around its optical axis on shooting. People see an eye-catching gadget — a rotating camera — come up to it to see it better, look into it. And the camera takes their photo at that time. What could be better for high quality identification?
But not everything is so simple. The pictures from camera appear rotated too (on clockwise camera rotation frame the content becomes rotated counter-clockwise). But the identification algorithm can work only with faces that are just slightly deviated from vertical.
Vasya was entrusted to correct the situation — to rotate a captured image so that image would be minimally deviated from vertical. Requirements were severe. Firstly, the picture should be rotated only on angle divisible by 90 degrees to not lose a bit of information about the image. Secondly, the frames from the camera are so huge and FPS is so big that adequate rotation speed is provided by hardware FPGA solution only. And this solution can rotate only by 90 degrees clockwise. Of course, one can apply 90 degrees turn several times but for the sake of performance the number of turns should be minimized.
Help Vasya implement the program that by the given rotation angle of the camera can determine the minimum number of 90 degrees clockwise turns necessary to get a picture in which up direction deviation from vertical is minimum.
The next figure contains frames taken from an unrotated camera, then from rotated 90 degrees clockwise, then from rotated 90 degrees counter-clockwise. Arrows show direction to "true up". [Image]
The next figure shows 90 degrees clockwise turn by FPGA hardware. [Image]
-----Input-----
The only line of the input contains one integer x ( - 10^18 ≤ x ≤ 10^18) — camera angle in degrees. Positive value denotes clockwise camera rotation, negative — counter-clockwise.
-----Output-----
Output one integer — the minimum required number of 90 degrees clockwise turns.
-----Examples-----
Input
60
Output
1
Input
-60
Output
3
-----Note-----
When the camera is rotated 60 degrees counter-clockwise (the second example), an image from it is rotated 60 degrees clockwise. One 90 degrees clockwise turn of the image result in 150 degrees clockwise total rotation and deviation from "true up" for one turn is 150 degrees. Two 90 degrees clockwise turns of the image result in 240 degrees clockwise total rotation and deviation from "true up" for two turns is 120 degrees because 240 degrees clockwise equal to 120 degrees counter-clockwise. Three 90 degrees clockwise turns of the image result in 330 degrees clockwise total rotation and deviation from "true up" for three turns is 30 degrees because 330 degrees clockwise equal to 30 degrees counter-clockwise.
From 60, 150, 120 and 30 degrees deviations the smallest is 30, and it it achieved in three 90 degrees clockwise turns.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = (-int(input())) % 360
ret, opt = 4, 361
for i in range(4):
x = (n+90*i)%360
x = min(x, 360-x)
if (x, i) < (opt, ret):
opt, ret = x, i
print(ret)
```
|
vfc_10478
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/630/M",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
182
|
Solve the following coding problem using the programming language python:
Carl is a beginner magician. He has a blue, b violet and c orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least x blue, y violet and z orange spheres. Can he get them (possible, in multiple actions)?
-----Input-----
The first line of the input contains three integers a, b and c (0 ≤ a, b, c ≤ 1 000 000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, x, y and z (0 ≤ x, y, z ≤ 1 000 000) — the number of blue, violet and orange spheres that he needs to get.
-----Output-----
If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No".
-----Examples-----
Input
4 4 0
2 1 2
Output
Yes
Input
5 6 1
2 7 2
Output
No
Input
3 3 3
2 2 2
Output
Yes
-----Note-----
In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a, b, c = list(map(int, input().split()))
x, y, z = list(map(int, input().split()))
col = max(0, x - a) + max(0, y - b) + max(0, z - c)
sum = max(0, (a - x) // 2) + max(0, (b - y) // 2) + max(0, (c - z) // 2)
if sum >= col:
print('Yes')
else:
print('No')
```
|
vfc_10482
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/606/A",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
183
|
Solve the following coding problem using the programming language python:
Amr doesn't like Maths as he finds it really boring, so he usually sleeps in Maths lectures. But one day the teacher suspected that Amr is sleeping and asked him a question to make sure he wasn't.
First he gave Amr two positive integers n and k. Then he asked Amr, how many integer numbers x > 0 exist such that: Decimal representation of x (without leading zeroes) consists of exactly n digits; There exists some integer y > 0 such that: $y \operatorname{mod} k = 0$; decimal representation of y is a suffix of decimal representation of x.
As the answer to this question may be pretty huge the teacher asked Amr to output only its remainder modulo a number m.
Can you help Amr escape this embarrassing situation?
-----Input-----
Input consists of three integers n, k, m (1 ≤ n ≤ 1000, 1 ≤ k ≤ 100, 1 ≤ m ≤ 10^9).
-----Output-----
Print the required number modulo m.
-----Examples-----
Input
1 2 1000
Output
4
Input
2 2 1000
Output
45
Input
5 3 1103
Output
590
-----Note-----
A suffix of a string S is a non-empty string that can be obtained by removing some number (possibly, zero) of first characters from S.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n,k,m=list(map(int,input().split()))
d,r,p,P=0,0,1%k,(10**(n-1))*9
F=[0]*k
F[0]=1
while d<n:
d+=1
P//=10
E=[0]*k
if P==0:P=1
i=1
# print("E=",E)
# print("F=",F)
while i<10:
j=(-i*p)%k
f=0
while f<k:
E[f]+=F[j]
f+=1
j+=1
if j==k:j=0
i+=1
r+=E[0]*P
p=p*10%k
E[0]=0
i=1
while i<k:
F[i]=(F[i]+E[i])%m
i+=1
# print(E,P)
F[0]=1
#print("r=",r)
print(r%m)
#i=10**n
#j=10**(n-1)
#r=0
#F=[0]*k
#while j<i:
# x=str(j)
# l=len(x)
# a=l
# while a:
# a-=1
# s=int(x[a:l])
# if s>0 and s%k==0:
# r+=1
# break
# j+=1
#print()
#print(r)
"""
3 6 9
13 16 19 12 15 18
23 26 29 21 24 27
33 36 39 30
43 46 49 42 45 48
53 56 59 51 54 57
63 66 69 60
73 76 79 72 75 78
83 86 89 81 84 87
93 96 99 90
"""
```
|
vfc_10486
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/507/D",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
184
|
Solve the following coding problem using the programming language python:
You are at a water bowling training. There are l people who play with their left hand, r people, who play with their right hand, and a ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively.
-----Input-----
The only line contains three integers l, r and a (0 ≤ l, r, a ≤ 100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training.
-----Output-----
Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players.
-----Examples-----
Input
1 4 2
Output
6
Input
5 5 5
Output
14
Input
0 2 0
Output
0
-----Note-----
In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import base64
import zlib
pro = base64.decodebytes("""eJxtUUFuwyAQvPOKVarKkDhOm2MlX/uC3qqqAhs7KBgswGr6+y4QrLqqL7DD7OzMWk2zdQFGGWbu
PVG59N/rdeLhUu6Om95OpVJBumCtXqlCedkFQgalpYcW3twiSS/FMmLxyrWXhKihzGrwXLx0lEHb
QjU4e5HmWgHOgKTwQgC/0p/EIoDeGh96ZRC0szR0F6QPjTI7lt4fCsMuoVCqREGgqqH6qjIxBSZo
cADdTZTXIFie6dCZM8BhDwJOp7SDZuz6zLn3OMXplv+uTKCKwWAdKECDysxLoKzxs1Z4fpRObkb5
6ZfNTDSDbimlAo44+QDPLI4+MzRBYy1Yto0bxPqINTzCOe7uKSsUlQPKFJFzFtmkWlN3dhKcmhpu
2xw05R14FyyG1NSwdQm/QJxwY/+93OKGdA2uRgtt3hPp1RALLjzV2OkYmZSJCB40ku/AISORju2M
XOEPkISOLVzJ/ShtPCedXfwLCdxjfPIDQSHUSQ==
""".encode())
pro = zlib.decompress(pro)
pro = pro.decode()
exec(pro)
```
|
vfc_10490
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/950/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
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|
apps
|
verifiable_code
|
185
|
Solve the following coding problem using the programming language python:
Finished her homework, Nastya decided to play computer games. Passing levels one by one, Nastya eventually faced a problem. Her mission is to leave a room, where a lot of monsters live, as quickly as possible.
There are $n$ manholes in the room which are situated on one line, but, unfortunately, all the manholes are closed, and there is one stone on every manhole. There is exactly one coin under every manhole, and to win the game Nastya should pick all the coins. Initially Nastya stands near the $k$-th manhole from the left. She is thinking what to do.
In one turn, Nastya can do one of the following: if there is at least one stone on the manhole Nastya stands near, throw exactly one stone from it onto any other manhole (yes, Nastya is strong). go to a neighboring manhole; if there are no stones on the manhole Nastya stays near, she can open it and pick the coin from it. After it she must close the manhole immediately (it doesn't require additional moves).
[Image] The figure shows the intermediate state of the game. At the current position Nastya can throw the stone to any other manhole or move left or right to the neighboring manholes. If she were near the leftmost manhole, she could open it (since there are no stones on it).
Nastya can leave the room when she picks all the coins. Monsters are everywhere, so you need to compute the minimum number of moves Nastya has to make to pick all the coins.
Note one time more that Nastya can open a manhole only when there are no stones onto it.
-----Input-----
The first and only line contains two integers $n$ and $k$, separated by space ($2 \leq n \leq 5000$, $1 \leq k \leq n$) — the number of manholes and the index of manhole from the left, near which Nastya stays initially. Initially there is exactly one stone near each of the $n$ manholes.
-----Output-----
Print a single integer — minimum number of moves which lead Nastya to pick all the coins.
-----Examples-----
Input
2 2
Output
6
Input
4 2
Output
13
Input
5 1
Output
15
-----Note-----
Let's consider the example where $n = 2$, $k = 2$. Nastya should play as follows:
At first she throws the stone from the second manhole to the first. Now there are two stones on the first manhole. Then she opens the second manhole and pick the coin from it. Then she goes to the first manhole, throws two stones by two moves to the second manhole and then opens the manhole and picks the coin from it.
So, $6$ moves are required to win.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, k = list(map(int,input().split()))
if k == 1 or k == n:
print(3 * n)
else:
print(3 * n + min(k - 1, n - k))
```
|
vfc_10494
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1136/B",
"time_limit": "None"
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}
|
apps
|
verifiable_code
|
186
|
Solve the following coding problem using the programming language python:
Students in a class are making towers of blocks. Each student makes a (non-zero) tower by stacking pieces lengthwise on top of each other. n of the students use pieces made of two blocks and m of the students use pieces made of three blocks.
The students don’t want to use too many blocks, but they also want to be unique, so no two students’ towers may contain the same number of blocks. Find the minimum height necessary for the tallest of the students' towers.
-----Input-----
The first line of the input contains two space-separated integers n and m (0 ≤ n, m ≤ 1 000 000, n + m > 0) — the number of students using two-block pieces and the number of students using three-block pieces, respectively.
-----Output-----
Print a single integer, denoting the minimum possible height of the tallest tower.
-----Examples-----
Input
1 3
Output
9
Input
3 2
Output
8
Input
5 0
Output
10
-----Note-----
In the first case, the student using two-block pieces can make a tower of height 4, and the students using three-block pieces can make towers of height 3, 6, and 9 blocks. The tallest tower has a height of 9 blocks.
In the second case, the students can make towers of heights 2, 4, and 8 with two-block pieces and towers of heights 3 and 6 with three-block pieces, for a maximum height of 8 blocks.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, m = list(map(int, input().split()))
start = 0
end = 10**10
while (end - start > 1):
mid = (end + start) // 2
two = mid // 2 - mid // 6
three = mid // 3 - mid // 6
six = mid // 6
nn = n
mm = m
nn -= two
mm -= three
nn = max(nn, 0)
mm = max(mm, 0)
if (six >= nn + mm):
end = mid
else:
start = mid
print(end)
```
|
vfc_10498
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/626/C",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
187
|
Solve the following coding problem using the programming language python:
Petya and Vasya decided to play a game. They have n cards (n is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (different from the number that Petya chose). During the game each player takes all the cards with number he chose. For example, if Petya chose number 5 before the game he will take all cards on which 5 is written and if Vasya chose number 10 before the game he will take all cards on which 10 is written.
The game is considered fair if Petya and Vasya can take all n cards, and the number of cards each player gets is the same.
Determine whether Petya and Vasya can choose integer numbers before the game so that the game is fair.
-----Input-----
The first line contains a single integer n (2 ≤ n ≤ 100) — number of cards. It is guaranteed that n is an even number.
The following n lines contain a sequence of integers a_1, a_2, ..., a_{n} (one integer per line, 1 ≤ a_{i} ≤ 100) — numbers written on the n cards.
-----Output-----
If it is impossible for Petya and Vasya to choose numbers in such a way that the game will be fair, print "NO" (without quotes) in the first line. In this case you should not print anything more.
In the other case print "YES" (without quotes) in the first line. In the second line print two distinct integers — number that Petya should choose and the number that Vasya should choose to make the game fair. If there are several solutions, print any of them.
-----Examples-----
Input
4
11
27
27
11
Output
YES
11 27
Input
2
6
6
Output
NO
Input
6
10
20
30
20
10
20
Output
NO
Input
6
1
1
2
2
3
3
Output
NO
-----Note-----
In the first example the game will be fair if, for example, Petya chooses number 11, and Vasya chooses number 27. Then the will take all cards — Petya will take cards 1 and 4, and Vasya will take cards 2 and 3. Thus, each of them will take exactly two cards.
In the second example fair game is impossible because the numbers written on the cards are equal, but the numbers that Petya and Vasya should choose should be distinct.
In the third example it is impossible to take all cards. Petya and Vasya can take at most five cards — for example, Petya can choose number 10 and Vasya can choose number 20. But for the game to be fair it is necessary to take 6 cards.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def list_input():
return list(map(int,input().split()))
def map_input():
return map(int,input().split())
def map_string():
return input().split()
n = int(input())
a = []
for _ in range(n):
a.append(int(input()))
b = list(set(a[::]))
if(len(b) == 2 and a.count(a[0]) == n//2):
print("YES")
print(b[0],b[1])
else: print("NO")
```
|
vfc_10502
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/864/A",
"time_limit": "None"
}
|
{
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"test_cases": [
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"output": "YES\n1 100\n",
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"type": "stdin_stdout"
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{
"fn_name": null,
"input": "100\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n",
"output": "YES\n1 2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100\n",
"output": "YES\n99 100\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n29\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n",
"output": "YES\n29 43\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n88\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n",
"output": "YES\n88 98\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n",
"output": "YES\n2 34\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n",
"output": "YES\n23 94\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n14\n",
"output": "YES\n14 15\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n23\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n21\n",
"output": "YES\n21 23\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n",
"output": "YES\n32 98\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n3\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n",
"output": "YES\n3 4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n34\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n",
"output": "YES\n12 34\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n19\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n32\n",
"output": "YES\n19 32\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n85\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n54\n",
"output": "YES\n54 85\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n43\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n",
"output": "YES\n12 43\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n96\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n95\n",
"output": "YES\n95 96\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n4\n",
"output": "YES\n4 33\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n99\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n98\n",
"output": "YES\n98 99\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n87\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n",
"output": "YES\n12 87\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n13\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n24\n",
"output": "YES\n13 24\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n49\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n12\n",
"output": "YES\n12 49\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n15\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n94\n",
"output": "YES\n15 94\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n33\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n42\n",
"output": "YES\n33 42\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n16\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n35\n",
"output": "YES\n16 35\n",
"type": "stdin_stdout"
},
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"fn_name": null,
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}
|
apps
|
verifiable_code
|
188
|
Solve the following coding problem using the programming language python:
Daenerys Targaryen has an army consisting of k groups of soldiers, the i-th group contains a_{i} soldiers. She wants to bring her army to the other side of the sea to get the Iron Throne. She has recently bought an airplane to carry her army through the sea. The airplane has n rows, each of them has 8 seats. We call two seats neighbor, if they are in the same row and in seats {1, 2}, {3, 4}, {4, 5}, {5, 6} or {7, 8}.
[Image] A row in the airplane
Daenerys Targaryen wants to place her army in the plane so that there are no two soldiers from different groups sitting on neighboring seats.
Your task is to determine if there is a possible arranging of her army in the airplane such that the condition above is satisfied.
-----Input-----
The first line contains two integers n and k (1 ≤ n ≤ 10000, 1 ≤ k ≤ 100) — the number of rows and the number of groups of soldiers, respectively.
The second line contains k integers a_1, a_2, a_3, ..., a_{k} (1 ≤ a_{i} ≤ 10000), where a_{i} denotes the number of soldiers in the i-th group.
It is guaranteed that a_1 + a_2 + ... + a_{k} ≤ 8·n.
-----Output-----
If we can place the soldiers in the airplane print "YES" (without quotes). Otherwise print "NO" (without quotes).
You can choose the case (lower or upper) for each letter arbitrary.
-----Examples-----
Input
2 2
5 8
Output
YES
Input
1 2
7 1
Output
NO
Input
1 2
4 4
Output
YES
Input
1 4
2 2 1 2
Output
YES
-----Note-----
In the first sample, Daenerys can place the soldiers like in the figure below:
[Image]
In the second sample, there is no way to place the soldiers in the plane since the second group soldier will always have a seat neighboring to someone from the first group.
In the third example Daenerys can place the first group on seats (1, 2, 7, 8), and the second group an all the remaining seats.
In the fourth example she can place the first two groups on seats (1, 2) and (7, 8), the third group on seats (3), and the fourth group on seats (5, 6).
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import sys
def r():
return list(map(int, input().split()))
n, k = list(map(int, input().split()))
a = r()
cnt4 = n
cnt2 = 2*n
cnt1 = 0
for i in range(k):
x = min((a[i]+1)//4, cnt4)
cnt4 -= x
a[i] = max(0, a[i]-4*x)
cnt2 += cnt4
cnt1 += cnt4
for i in range(k):
x = min(a[i]//2, cnt2)
cnt2 -= x
a[i] = max(0, a[i]-2*x)
cnt1 += cnt2
for i in range(k):
cnt1 -= a[i]
if (cnt1 < 0):
print('NO')
else:
print('YES')
```
|
vfc_10506
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/839/B",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
189
|
Solve the following coding problem using the programming language python:
Salem gave you $n$ sticks with integer positive lengths $a_1, a_2, \ldots, a_n$.
For every stick, you can change its length to any other positive integer length (that is, either shrink or stretch it). The cost of changing the stick's length from $a$ to $b$ is $|a - b|$, where $|x|$ means the absolute value of $x$.
A stick length $a_i$ is called almost good for some integer $t$ if $|a_i - t| \le 1$.
Salem asks you to change the lengths of some sticks (possibly all or none), such that all sticks' lengths are almost good for some positive integer $t$ and the total cost of changing is minimum possible. The value of $t$ is not fixed in advance and you can choose it as any positive integer.
As an answer, print the value of $t$ and the minimum cost. If there are multiple optimal choices for $t$, print any of them.
-----Input-----
The first line contains a single integer $n$ ($1 \le n \le 1000$) — the number of sticks.
The second line contains $n$ integers $a_i$ ($1 \le a_i \le 100$) — the lengths of the sticks.
-----Output-----
Print the value of $t$ and the minimum possible cost. If there are multiple optimal choices for $t$, print any of them.
-----Examples-----
Input
3
10 1 4
Output
3 7
Input
5
1 1 2 2 3
Output
2 0
-----Note-----
In the first example, we can change $1$ into $2$ and $10$ into $4$ with cost $|1 - 2| + |10 - 4| = 1 + 6 = 7$ and the resulting lengths $[2, 4, 4]$ are almost good for $t = 3$.
In the second example, the sticks lengths are already almost good for $t = 2$, so we don't have to do anything.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
a = list(map(int,input().split()))
t = 0
mn = 1000000000
for i in range(1,100):
cur = 0
for j in range(n):
cur += max(0,abs(i-a[j])-1)
if cur < mn:
mn = cur
t = i
print(t,mn)
```
|
vfc_10510
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1105/A",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
190
|
Solve the following coding problem using the programming language python:
Карта звёздного неба представляет собой прямоугольное поле, состоящее из n строк по m символов в каждой строке. Каждый символ — это либо «.» (означает пустой участок неба), либо «*» (означает то, что в этом месте на небе есть звезда).
Новое издание карты звёздного неба будет напечатано на квадратных листах, поэтому требуется найти минимально возможную сторону квадрата, в который могут поместиться все звезды. Границы искомого квадрата должны быть параллельны сторонам заданного прямоугольного поля.
-----Входные данные-----
В первой строке входных данных записаны два числа n и m (1 ≤ n, m ≤ 1000) — количество строк и столбцов на карте звездного неба.
В следующих n строках задано по m символов. Каждый символ — это либо «.» (пустой участок неба), либо «*» (звезда).
Гарантируется, что на небе есть хотя бы одна звезда.
-----Выходные данные-----
Выведите одно число — минимально возможную сторону квадрата, которым можно накрыть все звезды.
-----Примеры-----
Входные данные
4 4
....
..*.
...*
..**
Выходные данные
3
Входные данные
1 3
*.*
Выходные данные
3
Входные данные
2 1
.
*
Выходные данные
1
-----Примечание-----
Один из возможных ответов на первый тестовый пример:
[Image]
Один из возможных ответов на второй тестовый пример (обратите внимание, что покрывающий квадрат выходит за пределы карты звездного неба):
[Image]
Ответ на третий тестовый пример:
[Image]
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, m = input().split()
n = int(n)
m = int(m)
a = []
N = n
for i in range(n) :
a.append(input().split())
for i in range(n) :
if a[i][0].find('*') == -1 :
n-=1
else :
break
if n != 1 :
for i in range(len(a)-1,-1,-1) :
if a[i][0].find('*') == -1 :
n-=1
else :
break
#print(n)
M = m
br = 0
for i in range(m) :
count = 0
for j in range(len(a)) :
if a[j][0][i] != ('*') :
count+=1
else :
br = 1
break
if br == 1 :
break
if count == N :
m-=1
br = 0
if m != 1 :
for i in range(M-1,-1,-1) :
count = 0
for j in range(len(a)) :
if a[j][0][i] != ('*') :
count+=1
else :
br = 1
break
if br == 1 :
break
if count == N :
m-=1
#print(m)
if m > n :
print(m)
else :
print(n)
```
|
vfc_10514
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/647/B",
"time_limit": "None"
}
|
{
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"test_cases": [
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|
apps
|
verifiable_code
|
191
|
Solve the following coding problem using the programming language python:
A girl named Sonya is studying in the scientific lyceum of the Kingdom of Kremland. The teacher of computer science (Sonya's favorite subject!) invented a task for her.
Given an array $a$ of length $n$, consisting only of the numbers $0$ and $1$, and the number $k$. Exactly $k$ times the following happens: Two numbers $i$ and $j$ are chosen equiprobable such that ($1 \leq i < j \leq n$). The numbers in the $i$ and $j$ positions are swapped.
Sonya's task is to find the probability that after all the operations are completed, the $a$ array will be sorted in non-decreasing order. She turned to you for help. Help Sonya solve this problem.
It can be shown that the desired probability is either $0$ or it can be represented as $\dfrac{P}{Q}$, where $P$ and $Q$ are coprime integers and $Q \not\equiv 0~\pmod {10^9+7}$.
-----Input-----
The first line contains two integers $n$ and $k$ ($2 \leq n \leq 100, 1 \leq k \leq 10^9$) — the length of the array $a$ and the number of operations.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($0 \le a_i \le 1$) — the description of the array $a$.
-----Output-----
If the desired probability is $0$, print $0$, otherwise print the value $P \cdot Q^{-1}$ $\pmod {10^9+7}$, where $P$ and $Q$ are defined above.
-----Examples-----
Input
3 2
0 1 0
Output
333333336
Input
5 1
1 1 1 0 0
Output
0
Input
6 4
1 0 0 1 1 0
Output
968493834
-----Note-----
In the first example, all possible variants of the final array $a$, after applying exactly two operations: $(0, 1, 0)$, $(0, 0, 1)$, $(1, 0, 0)$, $(1, 0, 0)$, $(0, 1, 0)$, $(0, 0, 1)$, $(0, 0, 1)$, $(1, 0, 0)$, $(0, 1, 0)$. Therefore, the answer is $\dfrac{3}{9}=\dfrac{1}{3}$.
In the second example, the array will not be sorted in non-decreasing order after one operation, therefore the answer is $0$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
N, T = list(map(int, input().split()))
A = [int(a) for a in input().split()]
if sum(A) > N//2:
A = [1-a for a in A][::-1]
K = sum(A)
S = sum(A[-K:])
M = K + 1
P = 10**9+7
inv = pow(N*(N-1)//2, P-2, P)
X = [[0]*M for _ in range(M)]
for i in range(M):
if i > 0: X[i-1][i] = ((K-i+1)**2*inv)%P
if i < M-1: X[i+1][i] = (N-2*K+i+1)*(i+1)*inv%P
X[i][i] = (1-((K-i)**2*inv)-(N-2*K+i)*(i)*inv)%P
def ddd(n):
for i in range(1, 100):
if (n*i%P) < 100:
return (n*i%P), i
return -1, -1
def poww(MM, n):
if n == 1:
return MM
if n % 2:
return mult(poww(MM, n-1), MM)
return poww(mult(MM,MM), n//2)
def mult(M1, M2):
Y = [[0] * M for _ in range(M)]
for i in range(M):
for j in range(M):
for k in range(M):
Y[i][j] += M1[i][k] * M2[k][j]
Y[i][j] %= P
return Y
X = poww(X, T)
print(X[S][K])
```
|
vfc_10518
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1151/F",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
192
|
Solve the following coding problem using the programming language python:
Memory is now interested in the de-evolution of objects, specifically triangles. He starts with an equilateral triangle of side length x, and he wishes to perform operations to obtain an equilateral triangle of side length y.
In a single second, he can modify the length of a single side of the current triangle such that it remains a non-degenerate triangle (triangle of positive area). At any moment of time, the length of each side should be integer.
What is the minimum number of seconds required for Memory to obtain the equilateral triangle of side length y?
-----Input-----
The first and only line contains two integers x and y (3 ≤ y < x ≤ 100 000) — the starting and ending equilateral triangle side lengths respectively.
-----Output-----
Print a single integer — the minimum number of seconds required for Memory to obtain the equilateral triangle of side length y if he starts with the equilateral triangle of side length x.
-----Examples-----
Input
6 3
Output
4
Input
8 5
Output
3
Input
22 4
Output
6
-----Note-----
In the first sample test, Memory starts with an equilateral triangle of side length 6 and wants one of side length 3. Denote a triangle with sides a, b, and c as (a, b, c). Then, Memory can do $(6,6,6) \rightarrow(6,6,3) \rightarrow(6,4,3) \rightarrow(3,4,3) \rightarrow(3,3,3)$.
In the second sample test, Memory can do $(8,8,8) \rightarrow(8,8,5) \rightarrow(8,5,5) \rightarrow(5,5,5)$.
In the third sample test, Memory can do: $(22,22,22) \rightarrow(7,22,22) \rightarrow(7,22,16) \rightarrow(7,10,16) \rightarrow(7,10,4) \rightarrow$
$(7,4,4) \rightarrow(4,4,4)$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
x, y = list(map(int, input().split()))
x, y = y, x
A = x
B = x
curr = x
count = 0
while curr < y:
curr = B + A - 1
A, B = B, curr
count += 1
count += 2
print(count)
```
|
vfc_10522
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/712/C",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
193
|
Solve the following coding problem using the programming language python:
The determinant of a matrix 2 × 2 is defined as follows:$\operatorname{det} \left(\begin{array}{ll}{a} & {b} \\{c} & {d} \end{array} \right) = a d - b c$
A matrix is called degenerate if its determinant is equal to zero.
The norm ||A|| of a matrix A is defined as a maximum of absolute values of its elements.
You are given a matrix $A = \left(\begin{array}{ll}{a} & {b} \\{c} & {d} \end{array} \right)$. Consider any degenerate matrix B such that norm ||A - B|| is minimum possible. Determine ||A - B||.
-----Input-----
The first line contains two integers a and b (|a|, |b| ≤ 10^9), the elements of the first row of matrix A.
The second line contains two integers c and d (|c|, |d| ≤ 10^9) the elements of the second row of matrix A.
-----Output-----
Output a single real number, the minimum possible value of ||A - B||. Your answer is considered to be correct if its absolute or relative error does not exceed 10^{ - 9}.
-----Examples-----
Input
1 2
3 4
Output
0.2000000000
Input
1 0
0 1
Output
0.5000000000
-----Note-----
In the first sample matrix B is $\left(\begin{array}{ll}{1.2} & {1.8} \\{2.8} & {4.2} \end{array} \right)$
In the second sample matrix B is $\left(\begin{array}{ll}{0.5} & {0.5} \\{0.5} & {0.5} \end{array} \right)$
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def seg(x, y, h):
A = [x - h, x + h]
B = [y - h, y + h]
Z = []
for a in A:
for b in B:
Z.append(a * b)
Z.sort()
return (Z[0], Z[-1])
def check(a, b, c, d, h):
x1, y1 = seg(a, d, h)
x2, y2 = seg(b, c, h)
return max(x1, x2) <= min(y1, y2)
a, b = list(map(int, input().split()))
c, d = list(map(int, input().split()))
l = 0
r = max(abs(a), abs(b), abs(c), abs(d))
for i in range(100):
m = (l + r) / 2
if check(a, b, c, d, m):
r = m
else:
l = m
print((r + l) / 2)
```
|
vfc_10526
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/549/H",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
194
|
Solve the following coding problem using the programming language python:
In a small restaurant there are a tables for one person and b tables for two persons.
It it known that n groups of people come today, each consisting of one or two people.
If a group consist of one person, it is seated at a vacant one-seater table. If there are none of them, it is seated at a vacant two-seater table. If there are none of them, it is seated at a two-seater table occupied by single person. If there are still none of them, the restaurant denies service to this group.
If a group consist of two people, it is seated at a vacant two-seater table. If there are none of them, the restaurant denies service to this group.
You are given a chronological order of groups coming. You are to determine the total number of people the restaurant denies service to.
-----Input-----
The first line contains three integers n, a and b (1 ≤ n ≤ 2·10^5, 1 ≤ a, b ≤ 2·10^5) — the number of groups coming to the restaurant, the number of one-seater and the number of two-seater tables.
The second line contains a sequence of integers t_1, t_2, ..., t_{n} (1 ≤ t_{i} ≤ 2) — the description of clients in chronological order. If t_{i} is equal to one, then the i-th group consists of one person, otherwise the i-th group consists of two people.
-----Output-----
Print the total number of people the restaurant denies service to.
-----Examples-----
Input
4 1 2
1 2 1 1
Output
0
Input
4 1 1
1 1 2 1
Output
2
-----Note-----
In the first example the first group consists of one person, it is seated at a vacant one-seater table. The next group occupies a whole two-seater table. The third group consists of one person, it occupies one place at the remaining two-seater table. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, all clients are served.
In the second example the first group consists of one person, it is seated at the vacant one-seater table. The next group consists of one person, it occupies one place at the two-seater table. It's impossible to seat the next group of two people, so the restaurant denies service to them. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, the restaurant denies service to 2 clients.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, a, b = list(map(int,input().split()))
l = input().split()
o = 0
c = 0
for i in l:
if i == '2':
if b > 0:
b -= 1
else:
o += 2
if i == '1':
if a > 0:
a -= 1
elif b > 0:
b -= 1
c += 1
elif c > 0:
c -= 1
else:
o += 1
print(o)
```
|
vfc_10530
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/828/A",
"time_limit": "None"
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}
|
apps
|
verifiable_code
|
195
|
Solve the following coding problem using the programming language python:
Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group were more successful and celebrated after the exam.
Some of them celebrated in the BugDonalds restaurant, some of them — in the BeaverKing restaurant, the most successful ones were fast enough to celebrate in both of restaurants. Students which didn't pass the exam didn't celebrate in any of those restaurants and elected to stay home to prepare for their reexamination. However, this quickly bored Vasya and he started checking celebration photos on the Kilogramm. He found out that, in total, BugDonalds was visited by $A$ students, BeaverKing — by $B$ students and $C$ students visited both restaurants. Vasya also knows that there are $N$ students in his group.
Based on this info, Vasya wants to determine either if his data contradicts itself or, if it doesn't, how many students in his group didn't pass the exam. Can you help him so he won't waste his valuable preparation time?
-----Input-----
The first line contains four integers — $A$, $B$, $C$ and $N$ ($0 \leq A, B, C, N \leq 100$).
-----Output-----
If a distribution of $N$ students exists in which $A$ students visited BugDonalds, $B$ — BeaverKing, $C$ — both of the restaurants and at least one student is left home (it is known that Vasya didn't pass the exam and stayed at home), output one integer — amount of students (including Vasya) who did not pass the exam.
If such a distribution does not exist and Vasya made a mistake while determining the numbers $A$, $B$, $C$ or $N$ (as in samples 2 and 3), output $-1$.
-----Examples-----
Input
10 10 5 20
Output
5
Input
2 2 0 4
Output
-1
Input
2 2 2 1
Output
-1
-----Note-----
The first sample describes following situation: $5$ only visited BugDonalds, $5$ students only visited BeaverKing, $5$ visited both of them and $5$ students (including Vasya) didn't pass the exam.
In the second sample $2$ students only visited BugDonalds and $2$ only visited BeaverKing, but that means all $4$ students in group passed the exam which contradicts the fact that Vasya didn't pass meaning that this situation is impossible.
The third sample describes a situation where $2$ students visited BugDonalds but the group has only $1$ which makes it clearly impossible.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a,b,c,n=list(map(int,input().split()))
x=a+b-c
print(n-x if c<=a and c<=b and x<n else -1)
```
|
vfc_10534
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/991/A",
"time_limit": "None"
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|
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|
apps
|
verifiable_code
|
196
|
Solve the following coding problem using the programming language python:
Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning of the month).
Unfortunately, right after the doubling the wardrobe eats one of the dresses (if any) with the 50% probability. It happens every month except the last one in the year.
Nastya owns x dresses now, so she became interested in the expected number of dresses she will have in one year. Nastya lives in Byteland, so the year lasts for k + 1 months.
Nastya is really busy, so she wants you to solve this problem. You are the programmer, after all. Also, you should find the answer modulo 10^9 + 7, because it is easy to see that it is always integer.
-----Input-----
The only line contains two integers x and k (0 ≤ x, k ≤ 10^18), where x is the initial number of dresses and k + 1 is the number of months in a year in Byteland.
-----Output-----
In the only line print a single integer — the expected number of dresses Nastya will own one year later modulo 10^9 + 7.
-----Examples-----
Input
2 0
Output
4
Input
2 1
Output
7
Input
3 2
Output
21
-----Note-----
In the first example a year consists on only one month, so the wardrobe does not eat dresses at all.
In the second example after the first month there are 3 dresses with 50% probability and 4 dresses with 50% probability. Thus, in the end of the year there are 6 dresses with 50% probability and 8 dresses with 50% probability. This way the answer for this test is (6 + 8) / 2 = 7.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
x, k = map(int, input().split())
if x == 0:
print(0)
else:
mod = 10 ** 9 + 7
p = pow(2, k, mod)
ans = (x * (p * 2) - (p - 1)) % mod
print(ans)
```
|
vfc_10538
|
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|
apps
|
verifiable_code
|
197
|
Solve the following coding problem using the programming language python:
An online contest will soon be held on ForceCoders, a large competitive programming platform. The authors have prepared $n$ problems; and since the platform is very popular, $998244351$ coder from all over the world is going to solve them.
For each problem, the authors estimated the number of people who would solve it: for the $i$-th problem, the number of accepted solutions will be between $l_i$ and $r_i$, inclusive.
The creator of ForceCoders uses different criteria to determine if the contest is good or bad. One of these criteria is the number of inversions in the problem order. An inversion is a pair of problems $(x, y)$ such that $x$ is located earlier in the contest ($x < y$), but the number of accepted solutions for $y$ is strictly greater.
Obviously, both the creator of ForceCoders and the authors of the contest want the contest to be good. Now they want to calculate the probability that there will be no inversions in the problem order, assuming that for each problem $i$, any integral number of accepted solutions for it (between $l_i$ and $r_i$) is equally probable, and all these numbers are independent.
-----Input-----
The first line contains one integer $n$ ($2 \le n \le 50$) — the number of problems in the contest.
Then $n$ lines follow, the $i$-th line contains two integers $l_i$ and $r_i$ ($0 \le l_i \le r_i \le 998244351$) — the minimum and maximum number of accepted solutions for the $i$-th problem, respectively.
-----Output-----
The probability that there will be no inversions in the contest can be expressed as an irreducible fraction $\frac{x}{y}$, where $y$ is coprime with $998244353$. Print one integer — the value of $xy^{-1}$, taken modulo $998244353$, where $y^{-1}$ is an integer such that $yy^{-1} \equiv 1$ $(mod$ $998244353)$.
-----Examples-----
Input
3
1 2
1 2
1 2
Output
499122177
Input
2
42 1337
13 420
Output
578894053
Input
2
1 1
0 0
Output
1
Input
2
1 1
1 1
Output
1
-----Note-----
The real answer in the first test is $\frac{1}{2}$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
from bisect import bisect_left
M = 998244353
def pw(x, y):
if y == 0:
return 1
res = pw(x, y//2)
res = res * res % M
if y % 2 == 1:
res = res * x % M
return res
def cal(x, y):
y += x - 1
res = 1
for i in range(1, x + 1):
res = res * (y - i + 1)
res = res * pw(i, M - 2) % M
return res % M
n = int(input())
a = []
b = []
res = 1
for i in range(n):
a.append(list(map(int, input().split())))
res = res * (a[-1][1] + 1 - a[-1][0]) % M
b.append(a[-1][0])
b.append(a[-1][1] + 1)
b = set(b)
b = sorted(list(b))
g = [b[i + 1] - b[i] for i in range(len(b) - 1)]
for i in range(n):
a[i][0] = bisect_left(b, a[i][0])
a[i][1] = bisect_left(b, a[i][1] + 1)
a = a[::-1]
f = [[0 for _ in range(len(b))] for __ in range(n)]
for i in range(a[0][0], len(b)):
if i == 0:
f[0][i] = g[i]
else:
if i < a[0][1]:
f[0][i] = (f[0][i - 1] + g[i]) % M
else:
f[0][i] = f[0][i - 1]
for i in range(1, n):
for j in range(a[i][0], len(b)):
if j > 0:
f[i][j] = f[i][j - 1]
if j < a[i][1]:
for k in range(i, -1, -1):
if a[k][1] <= j or j < a[k][0]:
break
if k == 0 or j != 0:
tmp = cal(i - k + 1, g[j])
if k > 0:
f[i][j] += f[k - 1][j - 1] * tmp % M
else:
f[i][j] += tmp
f[i][j] %= M
#print(f)
#print(f[n - 1][len(b) - 1], res)
print(f[n - 1][len(b) - 1] * pw(res, M - 2) % M)
```
|
vfc_10542
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1295/F",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
198
|
Solve the following coding problem using the programming language python:
Pasha has a wooden stick of some positive integer length n. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be n.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to split a stick into four parts so that it's possible to form a rectangle using these parts, but is impossible to form a square.
Your task is to help Pasha and count the number of such ways. Two ways to cut the stick are considered distinct if there exists some integer x, such that the number of parts of length x in the first way differ from the number of parts of length x in the second way.
-----Input-----
The first line of the input contains a positive integer n (1 ≤ n ≤ 2·10^9) — the length of Pasha's stick.
-----Output-----
The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square.
-----Examples-----
Input
6
Output
1
Input
20
Output
4
-----Note-----
There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
x = int(input())
if x%2==1:
print(0)
quit()
if x%2 ==0:
x//=2
if x%2==0:
print(x//2-1)
else:
print(x//2)
```
|
vfc_10546
|
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/610/A",
"time_limit": "None"
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}
|
apps
|
verifiable_code
|
199
|
Solve the following coding problem using the programming language python:
The Fair Nut likes kvass very much. On his birthday parents presented him $n$ kegs of kvass. There are $v_i$ liters of kvass in the $i$-th keg. Each keg has a lever. You can pour your glass by exactly $1$ liter pulling this lever. The Fair Nut likes this drink very much, so he wants to pour his glass by $s$ liters of kvass. But he wants to do it, so kvass level in the least keg is as much as possible.
Help him find out how much kvass can be in the least keg or define it's not possible to pour his glass by $s$ liters of kvass.
-----Input-----
The first line contains two integers $n$ and $s$ ($1 \le n \le 10^3$, $1 \le s \le 10^{12}$) — the number of kegs and glass volume.
The second line contains $n$ integers $v_1, v_2, \ldots, v_n$ ($1 \le v_i \le 10^9$) — the volume of $i$-th keg.
-----Output-----
If the Fair Nut cannot pour his glass by $s$ liters of kvass, print $-1$. Otherwise, print a single integer — how much kvass in the least keg can be.
-----Examples-----
Input
3 3
4 3 5
Output
3
Input
3 4
5 3 4
Output
2
Input
3 7
1 2 3
Output
-1
-----Note-----
In the first example, the answer is $3$, the Fair Nut can take $1$ liter from the first keg and $2$ liters from the third keg. There are $3$ liters of kvass in each keg.
In the second example, the answer is $2$, the Fair Nut can take $3$ liters from the first keg and $1$ liter from the second keg.
In the third example, the Fair Nut can't pour his cup by $7$ liters, so the answer is $-1$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def doit():
xx = input().split()
n = int(xx[0])
s = int(xx[1])
v = [int(k) for k in input().split()]
S = sum(v)
newS = S - s
if newS < 0:
return -1
return min(newS//n, min(v))
print(doit())
```
|
vfc_10550
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1084/B",
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|
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|
apps
|
verifiable_code
|
200
|
Solve the following coding problem using the programming language python:
The 9-th grade student Gabriel noticed a caterpillar on a tree when walking around in a forest after the classes. The caterpillar was on the height h_1 cm from the ground. On the height h_2 cm (h_2 > h_1) on the same tree hung an apple and the caterpillar was crawling to the apple.
Gabriel is interested when the caterpillar gets the apple. He noted that the caterpillar goes up by a cm per hour by day and slips down by b cm per hour by night.
In how many days Gabriel should return to the forest to see the caterpillar get the apple. You can consider that the day starts at 10 am and finishes at 10 pm. Gabriel's classes finish at 2 pm. You can consider that Gabriel noticed the caterpillar just after the classes at 2 pm.
Note that the forest is magic so the caterpillar can slip down under the ground and then lift to the apple.
-----Input-----
The first line contains two integers h_1, h_2 (1 ≤ h_1 < h_2 ≤ 10^5) — the heights of the position of the caterpillar and the apple in centimeters.
The second line contains two integers a, b (1 ≤ a, b ≤ 10^5) — the distance the caterpillar goes up by day and slips down by night, in centimeters per hour.
-----Output-----
Print the only integer k — the number of days Gabriel should wait to return to the forest and see the caterpillar getting the apple.
If the caterpillar can't get the apple print the only integer - 1.
-----Examples-----
Input
10 30
2 1
Output
1
Input
10 13
1 1
Output
0
Input
10 19
1 2
Output
-1
Input
1 50
5 4
Output
1
-----Note-----
In the first example at 10 pm of the first day the caterpillar gets the height 26. At 10 am of the next day it slips down to the height 14. And finally at 6 pm of the same day the caterpillar gets the apple.
Note that in the last example the caterpillar was slipping down under the ground and getting the apple on the next day.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
from math import *
h1, h2 = [int(i) for i in input().split()]
a, b = [int(i) for i in input().split()]
a *= 12
b *= 12
if a <= b and h2 - h1 > (a // 12 * 8):
print(-1)
return
h1 += (a // 12 * 8)
if h1 >= h2:
print(0)
return
day = int(ceil((h2 - h1) / (a - b)))
print(day)
```
|
vfc_10554
|
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"memory_limit": null,
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"problem_url": "https://codeforces.com/problemset/problem/652/A",
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|
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|
apps
|
verifiable_code
|
201
|
Solve the following coding problem using the programming language python:
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image]
One day, when he came to his friend Evan, Om Nom didn't find him at home but he found two bags with candies. The first was full of blue candies and the second bag was full of red candies. Om Nom knows that each red candy weighs W_{r} grams and each blue candy weighs W_{b} grams. Eating a single red candy gives Om Nom H_{r} joy units and eating a single blue candy gives Om Nom H_{b} joy units.
Candies are the most important thing in the world, but on the other hand overeating is not good. Om Nom knows if he eats more than C grams of candies, he will get sick. Om Nom thinks that it isn't proper to leave candy leftovers, so he can only eat a whole candy. Om Nom is a great mathematician and he quickly determined how many candies of what type he should eat in order to get the maximum number of joy units. Can you repeat his achievement? You can assume that each bag contains more candies that Om Nom can eat.
-----Input-----
The single line contains five integers C, H_{r}, H_{b}, W_{r}, W_{b} (1 ≤ C, H_{r}, H_{b}, W_{r}, W_{b} ≤ 10^9).
-----Output-----
Print a single integer — the maximum number of joy units that Om Nom can get.
-----Examples-----
Input
10 3 5 2 3
Output
16
-----Note-----
In the sample test Om Nom can eat two candies of each type and thus get 16 joy units.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import sys
f = sys.stdin
C, Hr, Hb, Wr, Wb = map(int, f.readline().strip().split())
if Hr/Wr < Hb/Wb:
Hr, Hb, Wr, Wb = Hb, Hr, Wb, Wr
if (C % Wr) == 0 and (C // Wr) > 0:
print((C // Wr)*Hr)
elif (C // Wr) == 0:
print((C // Wb)*Hb)
else:
nmax = (C // Wr)
pmax = nmax*Hr + ((C - nmax*Wr) // Wb) * Hb
dmax = ((C - (nmax-0)*Wr) % Wb)
#print(0, pmax, dmax)
#
#pm1 = (nmax-1)*Hr + ((C - (nmax-1)*Wr) // Wb) * Hb
#if pm1>pmax:
# pmax = pm1
if Hr/Wr > Hb/Wb:
dx = dmax * (Hb/Wb) / (Hr/Wr - Hb/Wb)
elif Hr/Wr < Hb/Wb:
dx = 0
else:
dx = Wb * Wr
if Wr<Wb:
nmax = (C // Wb)
pmax = nmax*Hb + ((C - nmax*Wb) // Wr) * Hr
if Wr>Wb:
nmax = (C // Wr)
pmax = nmax*Hr + ((C - nmax*Wr) // Wb) * Hb
if Wr>Wb and dx>0:
for k in range(1, C//Wr):
if k*Wr > dx:
break
pk = (nmax-k)*Hr + ((C - (nmax-k)*Wr) // Wb) * Hb
dk = ((C - (nmax-k)*Wr) % Wb)
#print(k, pmax, pk, dk)
if pk>pmax:
pmax = pk
if dk==0 :
break
elif Wr<Wb and dx>0:
for j in range(1, C//Wb+1):
k = nmax - (C-j*Wb)//Wr
if k*Wr > dx:
break
pk = (nmax-k)*Hr + ((C - (nmax-k)*Wr) // Wb) * Hb
dk = ((C - (nmax-k)*Wr) % Wb)
#print(j, k, pmax, pk, dk, (nmax-k), ((C - (nmax-k)*Wr) // Wb) )
if pk>pmax:
pmax = pk
#dmax = dk
if dk==0 :
break
# elif Wr<Wb and dx>0:
# for j in range(1, C//Wb+1):
# k = (j*Wb - dmax)//Wr
# if k*Wr > dx:
# break
# pk = (nmax-k)*Hr + ((C - (nmax-k)*Wr) // Wb) * Hb
# dk = ((C - (nmax-k)*Wr) % Wb)
# print(j, k, pmax, pk, dk, (nmax-k), ((C - (nmax-k)*Wr) // Wb) )
# if pk>pmax:
# pmax = pk
# #dmax = dk
# if dk==0 :
# break
print(pmax)
```
|
vfc_10558
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/526/C",
"time_limit": "None"
}
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]
}
|
apps
|
verifiable_code
|
202
|
Solve the following coding problem using the programming language python:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (x_1, y_1) and should go to the point (x_2, y_2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal number of steps the robot should make to get the finish position.
-----Input-----
The first line contains two integers x_1, y_1 ( - 10^9 ≤ x_1, y_1 ≤ 10^9) — the start position of the robot.
The second line contains two integers x_2, y_2 ( - 10^9 ≤ x_2, y_2 ≤ 10^9) — the finish position of the robot.
-----Output-----
Print the only integer d — the minimal number of steps to get the finish position.
-----Examples-----
Input
0 0
4 5
Output
5
Input
3 4
6 1
Output
3
-----Note-----
In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its y coordinate and get the finish position.
In the second example robot should simultaneously increase x coordinate and decrease y coordinate by one three times.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a, b = map(int, input().split())
d, c = map(int, input().split())
print(max(abs(a - d), abs(b - c)))
```
|
vfc_10562
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/620/A",
"time_limit": "None"
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|
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}
|
apps
|
verifiable_code
|
203
|
Solve the following coding problem using the programming language python:
There are n employees in Alternative Cake Manufacturing (ACM). They are now voting on some very important question and the leading world media are trying to predict the outcome of the vote.
Each of the employees belongs to one of two fractions: depublicans or remocrats, and these two fractions have opposite opinions on what should be the outcome of the vote. The voting procedure is rather complicated: Each of n employees makes a statement. They make statements one by one starting from employees 1 and finishing with employee n. If at the moment when it's time for the i-th employee to make a statement he no longer has the right to vote, he just skips his turn (and no longer takes part in this voting). When employee makes a statement, he can do nothing or declare that one of the other employees no longer has a right to vote. It's allowed to deny from voting people who already made the statement or people who are only waiting to do so. If someone is denied from voting he no longer participates in the voting till the very end. When all employees are done with their statements, the procedure repeats: again, each employees starting from 1 and finishing with n who are still eligible to vote make their statements. The process repeats until there is only one employee eligible to vote remaining and he determines the outcome of the whole voting. Of course, he votes for the decision suitable for his fraction.
You know the order employees are going to vote and that they behave optimal (and they also know the order and who belongs to which fraction). Predict the outcome of the vote.
-----Input-----
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of employees.
The next line contains n characters. The i-th character is 'D' if the i-th employee is from depublicans fraction or 'R' if he is from remocrats.
-----Output-----
Print 'D' if the outcome of the vote will be suitable for depublicans and 'R' if remocrats will win.
-----Examples-----
Input
5
DDRRR
Output
D
Input
6
DDRRRR
Output
R
-----Note-----
Consider one of the voting scenarios for the first sample: Employee 1 denies employee 5 to vote. Employee 2 denies employee 3 to vote. Employee 3 has no right to vote and skips his turn (he was denied by employee 2). Employee 4 denies employee 2 to vote. Employee 5 has no right to vote and skips his turn (he was denied by employee 1). Employee 1 denies employee 4. Only employee 1 now has the right to vote so the voting ends with the victory of depublicans.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
s = input()
countr = s.count('R')
countd = n - countr
cr = 0
cd = 0
i = 0
news = []
while countr != 0 and countd != 0:
if s[i] == 'D':
if cd == 0:
cr += 1
countr -= 1
news.append('D')
else:
cd -= 1
else:
if cr == 0:
cd += 1
countd -= 1
news.append('R')
else:
cr -= 1
i += 1
if i >= n:
s = list(news)
news = []
n = len(s)
i = 0
if countr > 0:
print('R')
else:
print('D')
```
|
vfc_10566
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/749/C",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
204
|
Solve the following coding problem using the programming language python:
Monocarp has decided to buy a new TV set and hang it on the wall in his flat. The wall has enough free space so Monocarp can buy a TV set with screen width not greater than $a$ and screen height not greater than $b$. Monocarp is also used to TV sets with a certain aspect ratio: formally, if the width of the screen is $w$, and the height of the screen is $h$, then the following condition should be met: $\frac{w}{h} = \frac{x}{y}$.
There are many different TV sets in the shop. Monocarp is sure that for any pair of positive integers $w$ and $h$ there is a TV set with screen width $w$ and height $h$ in the shop.
Monocarp isn't ready to choose the exact TV set he is going to buy. Firstly he wants to determine the optimal screen resolution. He has decided to try all possible variants of screen size. But he must count the number of pairs of positive integers $w$ and $h$, beforehand, such that $(w \le a)$, $(h \le b)$ and $(\frac{w}{h} = \frac{x}{y})$.
In other words, Monocarp wants to determine the number of TV sets having aspect ratio $\frac{x}{y}$, screen width not exceeding $a$, and screen height not exceeding $b$. Two TV sets are considered different if they have different screen width or different screen height.
-----Input-----
The first line contains four integers $a$, $b$, $x$, $y$ ($1 \le a, b, x, y \le 10^{18}$) — the constraints on the screen width and height, and on the aspect ratio.
-----Output-----
Print one integer — the number of different variants to choose TV screen width and screen height so that they meet the aforementioned constraints.
-----Examples-----
Input
17 15 5 3
Output
3
Input
14 16 7 22
Output
0
Input
4 2 6 4
Output
1
Input
1000000000000000000 1000000000000000000 999999866000004473 999999822000007597
Output
1000000063
-----Note-----
In the first example, there are $3$ possible variants: $(5, 3)$, $(10, 6)$, $(15, 9)$.
In the second example, there is no TV set meeting the constraints.
In the third example, there is only one variant: $(3, 2)$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def gcd(a, b):
while b:
a, b = b, a % b
return a
a, b, x, y = list(map(int, input().split()))
g = gcd(x, y)
x //= g
y //= g
print(min(a // x, b // y))
```
|
vfc_10570
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1041/B",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
205
|
Solve the following coding problem using the programming language python:
The number "zero" is called "love" (or "l'oeuf" to be precise, literally means "egg" in French), for example when denoting the zero score in a game of tennis.
Aki is fond of numbers, especially those with trailing zeros. For example, the number $9200$ has two trailing zeros. Aki thinks the more trailing zero digits a number has, the prettier it is.
However, Aki believes, that the number of trailing zeros of a number is not static, but depends on the base (radix) it is represented in. Thus, he considers a few scenarios with some numbers and bases. And now, since the numbers he used become quite bizarre, he asks you to help him to calculate the beauty of these numbers.
Given two integers $n$ and $b$ (in decimal notation), your task is to calculate the number of trailing zero digits in the $b$-ary (in the base/radix of $b$) representation of $n\,!$ (factorial of $n$).
-----Input-----
The only line of the input contains two integers $n$ and $b$ ($1 \le n \le 10^{18}$, $2 \le b \le 10^{12}$).
-----Output-----
Print an only integer — the number of trailing zero digits in the $b$-ary representation of $n!$
-----Examples-----
Input
6 9
Output
1
Input
38 11
Output
3
Input
5 2
Output
3
Input
5 10
Output
1
-----Note-----
In the first example, $6!_{(10)} = 720_{(10)} = 880_{(9)}$.
In the third and fourth example, $5!_{(10)} = 120_{(10)} = 1111000_{(2)}$.
The representation of the number $x$ in the $b$-ary base is $d_1, d_2, \ldots, d_k$ if $x = d_1 b^{k - 1} + d_2 b^{k - 2} + \ldots + d_k b^0$, where $d_i$ are integers and $0 \le d_i \le b - 1$. For example, the number $720$ from the first example is represented as $880_{(9)}$ since $720 = 8 \cdot 9^2 + 8 \cdot 9 + 0 \cdot 1$.
You can read more about bases here.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, k = map(int, input().split())
a = []
i = 2
while (i * i <= k):
if (k % i == 0):
a.append([i, 0])
while (k % i == 0):
a[len(a) - 1][1] += 1
k //= i
i += 1
if (k > 1):
a.append([k, 1])
ans = 10 ** 20
for i in a:
cnt = 0
x = i[0]
while (x <= n):
cnt += n // x;
x *= i[0]
ans = min(ans, cnt // i[1])
print(ans)
```
|
vfc_10574
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1114/C",
"time_limit": "None"
}
|
{
"language": "python",
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apps
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verifiable_code
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206
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Solve the following coding problem using the programming language python:
A frog is initially at position $0$ on the number line. The frog has two positive integers $a$ and $b$. From a position $k$, it can either jump to position $k+a$ or $k-b$.
Let $f(x)$ be the number of distinct integers the frog can reach if it never jumps on an integer outside the interval $[0, x]$. The frog doesn't need to visit all these integers in one trip, that is, an integer is counted if the frog can somehow reach it if it starts from $0$.
Given an integer $m$, find $\sum_{i=0}^{m} f(i)$. That is, find the sum of all $f(i)$ for $i$ from $0$ to $m$.
-----Input-----
The first line contains three integers $m, a, b$ ($1 \leq m \leq 10^9, 1 \leq a,b \leq 10^5$).
-----Output-----
Print a single integer, the desired sum.
-----Examples-----
Input
7 5 3
Output
19
Input
1000000000 1 2019
Output
500000001500000001
Input
100 100000 1
Output
101
Input
6 4 5
Output
10
-----Note-----
In the first example, we must find $f(0)+f(1)+\ldots+f(7)$. We have $f(0) = 1, f(1) = 1, f(2) = 1, f(3) = 1, f(4) = 1, f(5) = 3, f(6) = 3, f(7) = 8$. The sum of these values is $19$.
In the second example, we have $f(i) = i+1$, so we want to find $\sum_{i=0}^{10^9} i+1$.
In the third example, the frog can't make any jumps in any case.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import math
m,a,b=map(int,input().split())
g=math.gcd(a,b)
a1=a//g
b1=b//g
alls=g*(a1+b1-1)
dists=[0]+[-1]*(a1+b1-1)
dist=0
far=0
while dist!=b1:
if dist<b1:
dist+=a1
far=max(dist,far)
else:
dist-=b1
if dists[dist]==-1:
dists[dist]=far
tot=0
for i in range(a1+b1):
if i*g<=m and dists[i]*g<=m:
tot+=(m+1-dists[i]*g)
if alls<m:
mod=m%g
times=m//g
diff=times-a1-b1
tot1=g*(diff*(diff+1)//2)+(mod+1)*(diff+1)
tot+=tot1
print(tot)
```
|
vfc_10578
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1146/D",
"time_limit": "None"
}
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}
|
apps
|
verifiable_code
|
207
|
Solve the following coding problem using the programming language python:
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a_1, a_2, ..., a_{n} of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
-----Input-----
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 100) — the elements of the sequence.
-----Output-----
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
-----Examples-----
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
-----Note-----
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def read_ints():
return [int(i) for i in input().split()]
n = read_ints()
a = read_ints()
if len(a) % 2 and a[0] % 2 and a[-1] % 2:
print('Yes')
else:
print('No')
```
|
vfc_10582
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/849/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
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}
|
apps
|
verifiable_code
|
208
|
Solve the following coding problem using the programming language python:
Pashmak has fallen in love with an attractive girl called Parmida since one year ago...
Today, Pashmak set up a meeting with his partner in a romantic garden. Unfortunately, Pashmak has forgotten where the garden is. But he remembers that the garden looks like a square with sides parallel to the coordinate axes. He also remembers that there is exactly one tree on each vertex of the square. Now, Pashmak knows the position of only two of the trees. Help him to find the position of two remaining ones.
-----Input-----
The first line contains four space-separated x_1, y_1, x_2, y_2 ( - 100 ≤ x_1, y_1, x_2, y_2 ≤ 100) integers, where x_1 and y_1 are coordinates of the first tree and x_2 and y_2 are coordinates of the second tree. It's guaranteed that the given points are distinct.
-----Output-----
If there is no solution to the problem, print -1. Otherwise print four space-separated integers x_3, y_3, x_4, y_4 that correspond to the coordinates of the two other trees. If there are several solutions you can output any of them.
Note that x_3, y_3, x_4, y_4 must be in the range ( - 1000 ≤ x_3, y_3, x_4, y_4 ≤ 1000).
-----Examples-----
Input
0 0 0 1
Output
1 0 1 1
Input
0 0 1 1
Output
0 1 1 0
Input
0 0 1 2
Output
-1
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
x1, y1, x2, y2 = map(int, input().split())
#diagonal
if x1 != x2 and y1 != y2:
if abs(x1 - x2) == abs(y1 - y2):
print(x1, y2, x2, y1)
else:
print(-1)
#same side
elif x1 == x2:
aux = abs(y2 - y1)
print(x1 + aux, y1, x1 + aux, y2)
elif y1 == y2:
aux = abs(x2 - x1)
print(x1, y1 + aux, x2, y1 + aux)
```
|
vfc_10586
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/459/A",
"time_limit": "None"
}
|
{
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"output": "15 56 80 56\n",
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}
|
apps
|
verifiable_code
|
209
|
Solve the following coding problem using the programming language python:
Jzzhu has invented a kind of sequences, they meet the following property:$f_{1} = x ; f_{2} = y ; \forall i(i \geq 2), f_{i} = f_{i - 1} + f_{i + 1}$
You are given x and y, please calculate f_{n} modulo 1000000007 (10^9 + 7).
-----Input-----
The first line contains two integers x and y (|x|, |y| ≤ 10^9). The second line contains a single integer n (1 ≤ n ≤ 2·10^9).
-----Output-----
Output a single integer representing f_{n} modulo 1000000007 (10^9 + 7).
-----Examples-----
Input
2 3
3
Output
1
Input
0 -1
2
Output
1000000006
-----Note-----
In the first sample, f_2 = f_1 + f_3, 3 = 2 + f_3, f_3 = 1.
In the second sample, f_2 = - 1; - 1 modulo (10^9 + 7) equals (10^9 + 6).
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def main():
x, y = [int(i) for i in input().split()]
n = int(input())
result = [x, y, y - x, -x, -y, x - y][(n - 1) % 6]
print(result % 1000000007)
main()
```
|
vfc_10590
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/450/B",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
210
|
Solve the following coding problem using the programming language python:
One spring day on his way to university Lesha found an array A. Lesha likes to split arrays into several parts. This time Lesha decided to split the array A into several, possibly one, new arrays so that the sum of elements in each of the new arrays is not zero. One more condition is that if we place the new arrays one after another they will form the old array A.
Lesha is tired now so he asked you to split the array. Help Lesha!
-----Input-----
The first line contains single integer n (1 ≤ n ≤ 100) — the number of elements in the array A.
The next line contains n integers a_1, a_2, ..., a_{n} ( - 10^3 ≤ a_{i} ≤ 10^3) — the elements of the array A.
-----Output-----
If it is not possible to split the array A and satisfy all the constraints, print single line containing "NO" (without quotes).
Otherwise in the first line print "YES" (without quotes). In the next line print single integer k — the number of new arrays. In each of the next k lines print two integers l_{i} and r_{i} which denote the subarray A[l_{i}... r_{i}] of the initial array A being the i-th new array. Integers l_{i}, r_{i} should satisfy the following conditions: l_1 = 1 r_{k} = n r_{i} + 1 = l_{i} + 1 for each 1 ≤ i < k.
If there are multiple answers, print any of them.
-----Examples-----
Input
3
1 2 -3
Output
YES
2
1 2
3 3
Input
8
9 -12 3 4 -4 -10 7 3
Output
YES
2
1 2
3 8
Input
1
0
Output
NO
Input
4
1 2 3 -5
Output
YES
4
1 1
2 2
3 3
4 4
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
from sys import stdin
n = int(input())
a = [int(x) for x in input().split()]
f = False
for i in range(len(a)):
if a[i] != 0:
ln = i
f = True
break
if not f:
print('NO')
else:
print('YES')
l = 0
i = ln + 1
ans = []
while i < len(a):
if a[i] == 0:
i += 1
else:
ans.append((l+1, i))
l = i
i += 1
if l < len(a):
ans.append((l+1, i))
print(len(ans))
for i in ans:
print(i[0],i[1])
```
|
vfc_10594
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/754/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
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"output": "YES\n3\n1 1\n2 2\n3 3\n",
"type": "stdin_stdout"
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},
{
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"input": "1\n0\n",
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{
"fn_name": null,
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"output": "YES\n38\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n10 10\n11 11\n12 12\n13 13\n14 14\n15 15\n16 16\n17 17\n18 18\n19 19\n20 20\n21 21\n22 22\n23 23\n24 25\n26 26\n27 27\n28 28\n29 29\n30 30\n31 31\n32 32\n33 33\n34 34\n35 36\n37 37\n38 38\n39 39\n40 40\n",
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},
{
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"input": "40\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0\n",
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"output": "YES\n60\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n10 10\n11 11\n12 12\n13 13\n14 14\n15 15\n16 16\n17 17\n18 18\n19 19\n20 20\n21 21\n22 22\n23 23\n24 24\n25 25\n26 26\n27 27\n28 28\n29 29\n30 30\n31 31\n32 32\n33 33\n34 34\n35 35\n36 36\n37 37\n38 38\n39 39\n40 40\n41 41\n42 42\n43 43\n44 44\n45 45\n46 46\n47 47\n48 48\n49 49\n50 50\n51 51\n52 52\n53 53\n54 54\n55 55\n56 56\n57 57\n58 58\n59 59\n60 60\n",
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{
"fn_name": null,
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{
"fn_name": null,
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{
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{
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{
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},
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{
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"input": "3\n5 -5 5\n",
"output": "YES\n3\n1 1\n2 2\n3 3\n",
"type": "stdin_stdout"
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"input": "5\n1 0 -1 0 1\n",
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"output": "YES\n3\n1 1\n2 2\n3 3\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
211
|
Solve the following coding problem using the programming language python:
Manao is taking part in a quiz. The quiz consists of n consecutive questions. A correct answer gives one point to the player. The game also has a counter of consecutive correct answers. When the player answers a question correctly, the number on this counter increases by 1. If the player answers a question incorrectly, the counter is reset, that is, the number on it reduces to 0. If after an answer the counter reaches the number k, then it is reset, and the player's score is doubled. Note that in this case, first 1 point is added to the player's score, and then the total score is doubled. At the beginning of the game, both the player's score and the counter of consecutive correct answers are set to zero.
Manao remembers that he has answered exactly m questions correctly. But he does not remember the order in which the questions came. He's trying to figure out what his minimum score may be. Help him and compute the remainder of the corresponding number after division by 1000000009 (10^9 + 9).
-----Input-----
The single line contains three space-separated integers n, m and k (2 ≤ k ≤ n ≤ 10^9; 0 ≤ m ≤ n).
-----Output-----
Print a single integer — the remainder from division of Manao's minimum possible score in the quiz by 1000000009 (10^9 + 9).
-----Examples-----
Input
5 3 2
Output
3
Input
5 4 2
Output
6
-----Note-----
Sample 1. Manao answered 3 questions out of 5, and his score would double for each two consecutive correct answers. If Manao had answered the first, third and fifth questions, he would have scored as much as 3 points.
Sample 2. Now Manao answered 4 questions. The minimum possible score is obtained when the only wrong answer is to the question 4.
Also note that you are asked to minimize the score and not the remainder of the score modulo 1000000009. For example, if Manao could obtain either 2000000000 or 2000000020 points, the answer is 2000000000 mod 1000000009, even though 2000000020 mod 1000000009 is a smaller number.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
MOD = 1000000009
n,m,k = [int(x) for x in input().split()]
num0 = n-m
num1fin = num0*(k-1)
if num1fin >= m:
print(m)
else:
num1open = m-num1fin
sets = num1open//k
rem = num1open%k
print(((pow(2,sets,MOD)-1)*2*k+rem+num1fin)%MOD)
```
|
vfc_10598
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/337/C",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
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"input": "5 3 2\n",
"output": "3\n",
"type": "stdin_stdout"
},
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"fn_name": null,
"input": "5 4 2\n",
"output": "6\n",
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"fn_name": null,
"input": "300 300 3\n",
"output": "17717644\n",
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"fn_name": null,
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"output": "785468433\n",
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"output": "0\n",
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}
|
apps
|
verifiable_code
|
212
|
Solve the following coding problem using the programming language python:
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
-----Input-----
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
-----Output-----
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
-----Examples-----
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n1 = input()
n = []
for i in n1:
n.append(int(i))
k = len(n)
for i in range(k):
if (n[i] % 8) == 0:
print("YES")
print(n[i])
return
if k > 1:
for i in range(k):
t = n[i] * 10
for j in range(i+1, k):
if (t+n[j]) % 8 == 0:
print("YES")
print(t+n[j])
return
if k > 2:
for i in range(k):
t = n[i]*100
for j in range(i+1, k):
l = n[j]*10
for e in range(j+1, k):
#print(t, l, n[e])
if (t+l+n[e]) % 8 == 0:
print("YES")
print(t+l+n[e])
return
print("NO")
```
|
vfc_10602
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/550/C",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
213
|
Solve the following coding problem using the programming language python:
In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to upper floors. That is, the first several flats are on the first floor, the next several flats are on the second and so on. Polycarp don't remember the total number of flats in the building, so you can consider the building to be infinitely high (i.e. there are infinitely many floors). Note that the floors are numbered from 1.
Polycarp remembers on which floors several flats are located. It is guaranteed that this information is not self-contradictory. It means that there exists a building with equal number of flats on each floor so that the flats from Polycarp's memory have the floors Polycarp remembers.
Given this information, is it possible to restore the exact floor for flat n?
-----Input-----
The first line contains two integers n and m (1 ≤ n ≤ 100, 0 ≤ m ≤ 100), where n is the number of the flat you need to restore floor for, and m is the number of flats in Polycarp's memory.
m lines follow, describing the Polycarp's memory: each of these lines contains a pair of integers k_{i}, f_{i} (1 ≤ k_{i} ≤ 100, 1 ≤ f_{i} ≤ 100), which means that the flat k_{i} is on the f_{i}-th floor. All values k_{i} are distinct.
It is guaranteed that the given information is not self-contradictory.
-----Output-----
Print the number of the floor in which the n-th flat is located, if it is possible to determine it in a unique way. Print -1 if it is not possible to uniquely restore this floor.
-----Examples-----
Input
10 3
6 2
2 1
7 3
Output
4
Input
8 4
3 1
6 2
5 2
2 1
Output
-1
-----Note-----
In the first example the 6-th flat is on the 2-nd floor, while the 7-th flat is on the 3-rd, so, the 6-th flat is the last on its floor and there are 3 flats on each floor. Thus, the 10-th flat is on the 4-th floor.
In the second example there can be 3 or 4 flats on each floor, so we can't restore the floor for the 8-th flat.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def floo(num, k):
return (num - 1) // k + 1
def main():
n, m = map(int, input().split())
low = 1
high = 10**9
if (m == 0):
if (n == 1):
print(1)
else:
print(-1)
return
for i in range(m):
k, f = map(int, input().split())
low = max(low, (k + f - 1) // f)
if (f > 1):
high = min(high, (k - 1) // (f - 1))
if (floo(n, low) == floo(n, high)):
print(floo(n, low))
else:
print(-1)
main()
```
|
vfc_10606
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/858/B",
"time_limit": "None"
}
|
{
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"input": "63 70\n82 1\n53 1\n57 1\n46 1\n97 1\n19 1\n36 1\n90 1\n23 1\n88 1\n68 1\n45 1\n2 1\n70 1\n86 1\n8 1\n83 1\n40 1\n99 1\n42 1\n32 1\n52 1\n81 1\n50 1\n77 1\n37 1\n54 1\n75 1\n4 1\n49 1\n73 1\n22 1\n21 1\n98 1\n18 1\n51 1\n14 1\n76 1\n92 1\n80 1\n78 1\n33 1\n79 1\n89 1\n67 1\n9 1\n44 1\n60 1\n64 1\n55 1\n29 1\n100 1\n16 1\n87 1\n10 1\n12 1\n25 1\n85 1\n30 1\n63 1\n39 1\n38 1\n31 1\n5 1\n26 1\n91 1\n43 1\n72 1\n48 1\n94 1\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 0\n",
"output": "-1\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
214
|
Solve the following coding problem using the programming language python:
Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
XX XX .X X.
X. .X XX XX
Bishwocks don't attack any squares and can even occupy on the adjacent squares as long as they don't occupy the same square.
Vasya has a board with $2\times n$ squares onto which he wants to put some bishwocks. To his dismay, several squares on this board are already occupied by pawns and Vasya can't put bishwocks there. However, pawns also don't attack bishwocks and they can occupy adjacent squares peacefully.
Knowing the positions of pawns on the board, help Vasya to determine the maximum amount of bishwocks he can put onto the board so that they wouldn't occupy the same squares and wouldn't occupy squares with pawns.
-----Input-----
The input contains two nonempty strings that describe Vasya's board. Those strings contain only symbols "0" (zero) that denote the empty squares and symbols "X" (uppercase English letter) that denote the squares occupied by pawns. Strings are nonempty and are of the same length that does not exceed $100$.
-----Output-----
Output a single integer — the maximum amount of bishwocks that can be placed onto the given board.
-----Examples-----
Input
00
00
Output
1
Input
00X00X0XXX0
0XXX0X00X00
Output
4
Input
0X0X0
0X0X0
Output
0
Input
0XXX0
00000
Output
2
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
f = []
for i in range(2):
f.append(list(input()))
answer = 0
n = len(f[0])
for i in range(n):
if f[0][i] == f[1][i] == '0' and i + 1 < n:
if f[0][i + 1] == '0':
answer += 1
f[0][i + 1] = 'X'
elif f[1][i + 1] == '0':
answer += 1
f[1][i + 1] = 'X'
elif (f[1][i] == '0' or f[0][i] == '0') and i + 1 < n and f[0][i + 1] == f[1][i + 1] == '0':
answer += 1
f[0][i + 1] = f[1][i + 1] = 'X'
print(answer)
```
|
vfc_10610
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/991/D",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "00\n00\n",
"output": "1",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "00X00X0XXX0\n0XXX0X00X00\n",
"output": "4",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "0X0X0\n0X0X0\n",
"output": "0",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "0XXX0\n00000\n",
"output": "2",
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},
{
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"input": "0\n0\n",
"output": "0",
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},
{
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"input": "0\nX\n",
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},
{
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"input": "X\n0\n",
"output": "0",
"type": "stdin_stdout"
},
{
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},
{
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},
{
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},
{
"fn_name": null,
"input": "0X\n00\n",
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},
{
"fn_name": null,
"input": "00\nX0\n",
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},
{
"fn_name": null,
"input": "00\n0X\n",
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{
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"input": "XX\nXX\n",
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{
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{
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"input": "00000\n00000\n",
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},
{
"fn_name": null,
"input": "00000000\nXXXXXXXX\n",
"output": "0",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X00X0XXXX0\nX0XXX0XX00\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "00000XX0000000000000\n0X00000XX0000X00X000\n",
"output": "10",
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},
{
"fn_name": null,
"input": "XXX00XXX0XXX0X0XXXXX\nXXX00XXX0XXX0X0XXXXX\n",
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},
{
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{
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"output": "4",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "000\n000\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "000000000000000000000\n000000000000000000000\n",
"output": "14",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "00000000000000000000000000000000000000\n00000000000000000000000000000000000000\n",
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{
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"input": "0000\n00X0\n",
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"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "000\n00X\n",
"output": "1",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X000\nX000\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X0000X000XX00000000000000000000XX000X0000X00X0X00XX000000000000X0000X0X0XX00\n00X00XX00000000X0000000X000X000X0X0X00X000X0X0X0000X0000000X000XX000XX000X00\n",
"output": "33",
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},
{
"fn_name": null,
"input": "0X00\n0000\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "0X0\n000\n",
"output": "1",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "000000\n000000\n",
"output": "4",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X00X0\n00000\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "000\n0X0\n",
"output": "1",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X000\n00X0\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X0000\n00000\n",
"output": "3",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X000X\nX000X\n",
"output": "2",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "X0000X\n00000X\n",
"output": "3",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "000000000000\n000000000000\n",
"output": "8",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "00000\n0000X\n",
"output": "3",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
215
|
Solve the following coding problem using the programming language python:
Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string s consisting only of lowercase and uppercase Latin letters.
Let A be a set of positions in the string. Let's call it pretty if following conditions are met: letters on positions from A in the string are all distinct and lowercase; there are no uppercase letters in the string which are situated between positions from A (i.e. there is no such j that s[j] is an uppercase letter, and a_1 < j < a_2 for some a_1 and a_2 from A).
Write a program that will determine the maximum number of elements in a pretty set of positions.
-----Input-----
The first line contains a single integer n (1 ≤ n ≤ 200) — length of string s.
The second line contains a string s consisting of lowercase and uppercase Latin letters.
-----Output-----
Print maximum number of elements in pretty set of positions for string s.
-----Examples-----
Input
11
aaaaBaabAbA
Output
2
Input
12
zACaAbbaazzC
Output
3
Input
3
ABC
Output
0
-----Note-----
In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.
In the second example desired positions can be 7, 8 and 11. There are other ways to choose pretty set consisting of three elements.
In the third example the given string s does not contain any lowercase letters, so the answer is 0.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def list_input():
return list(map(int,input().split()))
def map_input():
return map(int,input().split())
def map_string():
return input().split()
n = int(input())
a = list(input())
ans = 0
for i in range(n):
for j in range(i,n):
b = a[i:j+1]
for k in b:
if k.lower() != k:
break
else:
b = set(b)
ans = max(ans,len(b))
print(ans)
```
|
vfc_10614
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/864/B",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "11\naaaaBaabAbA\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "12\nzACaAbbaazzC\n",
"output": "3\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3\nABC\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\na\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\naz\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "200\nXbTJZqcbpYuZQEoUrbxlPXAPCtVLrRExpQzxzqzcqsqzsiisswqitswzCtJQxOavicSdBIodideVRKHPojCNHmbnrLgwJlwOpyrJJIhrUePszxSjJGeUgTtOfewPQnPVWhZAtogRPrJLwyShNQaeNsvrJwjuuBOMPCeSckBMISQzGngfOmeyfDObncyeNsihYVtQbSEh\n",
"output": "8\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\nAZ\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "28\nAabcBabcCBNMaaaaabbbbbcccccc\n",
"output": "3\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "200\nrsgraosldglhdoorwhkrsehjpuxrjuwgeanjgezhekprzarelduuaxdnspzjuooguuwnzkowkuhzduakdrzpnslauejhrrkalwpurpuuswdgeadlhjwzjgegwpknepazwwleulppwrlgrgedlwdzuodzropsrrkxusjnuzshdkjrxxpgzanzdrpnggdwxarpwohxdepJ\n",
"output": "17\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\nk\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\nH\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\nzG\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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|
apps
|
verifiable_code
|
216
|
Solve the following coding problem using the programming language python:
You are given a sequence a consisting of n integers. You may partition this sequence into two sequences b and c in such a way that every element belongs exactly to one of these sequences.
Let B be the sum of elements belonging to b, and C be the sum of elements belonging to c (if some of these sequences is empty, then its sum is 0). What is the maximum possible value of B - C?
-----Input-----
The first line contains one integer n (1 ≤ n ≤ 100) — the number of elements in a.
The second line contains n integers a_1, a_2, ..., a_{n} ( - 100 ≤ a_{i} ≤ 100) — the elements of sequence a.
-----Output-----
Print the maximum possible value of B - C, where B is the sum of elements of sequence b, and C is the sum of elements of sequence c.
-----Examples-----
Input
3
1 -2 0
Output
3
Input
6
16 23 16 15 42 8
Output
120
-----Note-----
In the first example we may choose b = {1, 0}, c = { - 2}. Then B = 1, C = - 2, B - C = 3.
In the second example we choose b = {16, 23, 16, 15, 42, 8}, c = {} (an empty sequence). Then B = 120, C = 0, B - C = 120.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n=int(input())
arr= list(map(int,input().strip().split(' ')))
s = 0
for i in range(n):
s+=abs(arr[i])
print(s)
```
|
vfc_10618
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/946/A",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
217
|
Solve the following coding problem using the programming language python:
A bus moves along the coordinate line Ox from the point x = 0 to the point x = a. After starting from the point x = 0, it reaches the point x = a, immediately turns back and then moves to the point x = 0. After returning to the point x = 0 it immediately goes back to the point x = a and so on. Thus, the bus moves from x = 0 to x = a and back. Moving from the point x = 0 to x = a or from the point x = a to x = 0 is called a bus journey. In total, the bus must make k journeys.
The petrol tank of the bus can hold b liters of gasoline. To pass a single unit of distance the bus needs to spend exactly one liter of gasoline. The bus starts its first journey with a full petrol tank.
There is a gas station in point x = f. This point is between points x = 0 and x = a. There are no other gas stations on the bus route. While passing by a gas station in either direction the bus can stop and completely refuel its tank. Thus, after stopping to refuel the tank will contain b liters of gasoline.
What is the minimum number of times the bus needs to refuel at the point x = f to make k journeys? The first journey starts in the point x = 0.
-----Input-----
The first line contains four integers a, b, f, k (0 < f < a ≤ 10^6, 1 ≤ b ≤ 10^9, 1 ≤ k ≤ 10^4) — the endpoint of the first bus journey, the capacity of the fuel tank of the bus, the point where the gas station is located, and the required number of journeys.
-----Output-----
Print the minimum number of times the bus needs to refuel to make k journeys. If it is impossible for the bus to make k journeys, print -1.
-----Examples-----
Input
6 9 2 4
Output
4
Input
6 10 2 4
Output
2
Input
6 5 4 3
Output
-1
-----Note-----
In the first example the bus needs to refuel during each journey.
In the second example the bus can pass 10 units of distance without refueling. So the bus makes the whole first journey, passes 4 units of the distance of the second journey and arrives at the point with the gas station. Then it can refuel its tank, finish the second journey and pass 2 units of distance from the third journey. In this case, it will again arrive at the point with the gas station. Further, he can refill the tank up to 10 liters to finish the third journey and ride all the way of the fourth journey. At the end of the journey the tank will be empty.
In the third example the bus can not make all 3 journeys because if it refuels during the second journey, the tanks will contain only 5 liters of gasoline, but the bus needs to pass 8 units of distance until next refueling.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def list_input():
return list(map(int,input().split()))
def map_input():
return map(int,input().split())
def map_string():
return input().split()
a,b,f,k = map_input()
tot = a*k
s = 2*a-f
cur = 0
cnt = b
go = 0
ans = 0
while cur < tot:
go = 1-go
if(go == 1):
if cnt < s and cnt < tot-cur:
if(cnt < f):
print(-1)
break
cnt = b
ans += 1
cnt -= (a-f)
else: cnt -= a
else:
if cnt < a+f and cnt < tot-cur:
if(cnt < a-f):
print(-1)
break
cnt = b
ans += 1
cnt -= (f)
else:cnt -= a
cur += a
# print(cur,cnt,ans)
if(cnt < 0):
print(-1)
break
else:
print(ans)
```
|
vfc_10622
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/864/C",
"time_limit": "None"
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"type": "stdin_stdout"
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"output": "2\n",
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{
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"output": "1\n",
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}
]
}
|
apps
|
verifiable_code
|
218
|
Solve the following coding problem using the programming language python:
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
-----Input-----
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
-----Output-----
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
-----Examples-----
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a, b, c = map(int, input().split(' '))
x = input()
for i in range(105):
for j in range(105):
if i*b+j*c == a:
print(i+j)
for k in range(i):
print(x[:b])
x = x[b:]
for l in range(j):
print(x[:c])
x = x[c:]
quit()
print(-1)
```
|
vfc_10626
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/612/A",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
219
|
Solve the following coding problem using the programming language python:
A sportsman starts from point x_{start} = 0 and runs to point with coordinate x_{finish} = m (on a straight line). Also, the sportsman can jump — to jump, he should first take a run of length of not less than s meters (in this case for these s meters his path should have no obstacles), and after that he can jump over a length of not more than d meters. Running and jumping is permitted only in the direction from left to right. He can start andfinish a jump only at the points with integer coordinates in which there are no obstacles. To overcome some obstacle, it is necessary to land at a point which is strictly to the right of this obstacle.
On the way of an athlete are n obstacles at coordinates x_1, x_2, ..., x_{n}. He cannot go over the obstacles, he can only jump over them. Your task is to determine whether the athlete will be able to get to the finish point.
-----Input-----
The first line of the input containsd four integers n, m, s and d (1 ≤ n ≤ 200 000, 2 ≤ m ≤ 10^9, 1 ≤ s, d ≤ 10^9) — the number of obstacles on the runner's way, the coordinate of the finishing point, the length of running before the jump and the maximum length of the jump, correspondingly.
The second line contains a sequence of n integers a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ m - 1) — the coordinates of the obstacles. It is guaranteed that the starting and finishing point have no obstacles, also no point can have more than one obstacle, The coordinates of the obstacles are given in an arbitrary order.
-----Output-----
If the runner cannot reach the finishing point, print in the first line of the output "IMPOSSIBLE" (without the quotes).
If the athlete can get from start to finish, print any way to do this in the following format: print a line of form "RUN X>" (where "X" should be a positive integer), if the athlete should run for "X" more meters; print a line of form "JUMP Y" (where "Y" should be a positive integer), if the sportsman starts a jump and should remain in air for "Y" more meters.
All commands "RUN" and "JUMP" should strictly alternate, starting with "RUN", besides, they should be printed chronologically. It is not allowed to jump over the finishing point but it is allowed to land there after a jump. The athlete should stop as soon as he reaches finish.
-----Examples-----
Input
3 10 1 3
3 4 7
Output
RUN 2
JUMP 3
RUN 1
JUMP 2
RUN 2
Input
2 9 2 3
6 4
Output
IMPOSSIBLE
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, m, s, d = list(map(int, input().split()))
beg = [float('-inf')]
end = [float('-inf')]
a = [int(i) for i in input().split()]
for x in sorted(a):
if (x - end[-1] > s + 1):
beg.append(x)
end.append(x)
else:
end[-1] = x
last = 0
R = []
J = []
for i in range(1, len(beg)):
R.append(beg[i] - 1 - last)
last = (beg[i] - 1)
J.append(end[i] + 1 - last)
last = (end[i] + 1)
ok = True
for x in J:
if (x > d):
ok = False
for x in R:
if (x < s):
ok = False
if ok:
for i in range(len(R)):
print('RUN', R[i])
print('JUMP', J[i])
if (last < m):
print('RUN', m - last)
else:
print('IMPOSSIBLE')
```
|
vfc_10630
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/637/D",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "3 10 1 3\n3 4 7\n",
"output": "RUN 2\nJUMP 3\nRUN 1\nJUMP 2\nRUN 2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 9 2 3\n6 4\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 100 2 8\n93 35 24 87 39 46 86 37 73 33\n",
"output": "RUN 23\nJUMP 2\nRUN 7\nJUMP 8\nRUN 5\nJUMP 2\nRUN 25\nJUMP 2\nRUN 11\nJUMP 3\nRUN 4\nJUMP 2\nRUN 6\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 1000000000 8905990 20319560\n233244997 997992814 242452779 497363176 572234096 126615858 886769539 662035052 989086824 716655858\n",
"output": "RUN 126615857\nJUMP 2\nRUN 106629137\nJUMP 2\nRUN 9207780\nJUMP 2\nRUN 254910395\nJUMP 2\nRUN 74870918\nJUMP 2\nRUN 89800954\nJUMP 2\nRUN 54620804\nJUMP 2\nRUN 170113679\nJUMP 2\nRUN 102317283\nJUMP 8905992\nRUN 2007185\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100 1000 1 4\n228 420 360 642 442 551 940 343 24 83 928 110 663 548 704 461 942 799 283 746 371 204 435 209 986 489 918 526 496 321 233 643 208 717 806 18 291 431 521 631 3 450 711 602 401 60 680 930 625 891 161 279 510 529 546 338 473 925 446 786 384 952 260 649 865 916 789 71 103 997 484 89 408 129 953 670 568 55 287 511 369 225 950 539 652 567 730 499 687 90 779 848 801 606 82 853 967 776 951 329\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100 600 1 4\n9 536 518 59 229 377 72 203 81 309 304 321 55 439 287 505 3 410 582 351 440 568 584 259 22 415 348 147 404 277 477 323 537 75 548 324 338 198 145 182 271 496 256 329 592 132 291 222 115 587 54 158 154 103 356 15 36 76 402 27 223 551 267 527 51 34 417 573 479 398 425 71 485 20 262 566 467 131 524 352 330 541 146 53 322 436 366 86 88 272 96 456 388 319 149 470 129 162 353 346\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 2 1 5\n1\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 3 1 2\n2\n",
"output": "RUN 1\nJUMP 2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 5 1 2\n2\n",
"output": "RUN 1\nJUMP 2\nRUN 2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1000000000 1000000000 2\n999999999\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 100 1 1\n4\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1000000000 1 1000000000\n2\n",
"output": "RUN 1\nJUMP 2\nRUN 999999997\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 12000 2000 3000\n3000 9002 7001\n",
"output": "RUN 2999\nJUMP 2\nRUN 3999\nJUMP 2003\nRUN 2997\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 30000 5000 6000\n6000 16000 15000 21001\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 12000 2000 245\n3000 9003 7001\n",
"output": "RUN 2999\nJUMP 2\nRUN 3999\nJUMP 2\nRUN 2000\nJUMP 2\nRUN 2996\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 30000 5000 1654\n6000 16000 14999 21002\n",
"output": "RUN 5999\nJUMP 2\nRUN 8997\nJUMP 1003\nRUN 5000\nJUMP 2\nRUN 8997\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 10000 500 500\n700 600 1099 2000\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 20000 4000 3502\n5000 8500 15000\n",
"output": "RUN 4999\nJUMP 3502\nRUN 6498\nJUMP 2\nRUN 4999\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 10000 500 500\n700 601 1099 2000\n",
"output": "RUN 600\nJUMP 500\nRUN 899\nJUMP 2\nRUN 7999\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 20000 4000 3502\n5000 8501 15000\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 10 1 2\n9\n",
"output": "RUN 8\nJUMP 2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 10 2 9\n5\n",
"output": "RUN 4\nJUMP 2\nRUN 4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 9 6 4\n4\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 10 7 4\n5\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 14 8 8\n5 9\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 23 12 8\n8 16\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 14 4 2\n2 7\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 21 6 2\n7 11 16\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 29 3 4\n7 16 19\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 24 2 6\n6 12 17\n",
"output": "RUN 5\nJUMP 2\nRUN 4\nJUMP 2\nRUN 3\nJUMP 2\nRUN 6\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 31 12 9\n7 13 21 28\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 10 1 7\n2 4 6 8\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 36 8 4\n4 13 19 27\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 25 10 2\n6 12 13 15 22\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 19 7 10\n3 7 9 12 16\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 28 6 8\n3 9 15 21 25\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 35 12 4\n7 12 17 21 24 28\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 22 5 7\n4 6 10 13 15 18\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 55 3 5\n10 18 24 34 39 45\n",
"output": "RUN 9\nJUMP 2\nRUN 6\nJUMP 2\nRUN 4\nJUMP 2\nRUN 8\nJUMP 2\nRUN 3\nJUMP 2\nRUN 4\nJUMP 2\nRUN 9\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "7 51 6 1\n8 17 18 23 27 33 42\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "7 36 11 4\n6 11 17 19 22 24 30\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "7 28 10 2\n5 10 14 19 21 23 27\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8 46 4 5\n3 6 15 21 24 26 36 42\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8 51 2 1\n6 14 20 26 29 35 40 48\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8 56 2 9\n7 11 20 28 34 39 40 48\n",
"output": "RUN 6\nJUMP 2\nRUN 2\nJUMP 2\nRUN 7\nJUMP 2\nRUN 6\nJUMP 2\nRUN 4\nJUMP 2\nRUN 3\nJUMP 3\nRUN 6\nJUMP 2\nRUN 7\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9 57 2 2\n5 11 15 21 24 30 36 43 50\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9 82 14 4\n10 18 28 38 46 55 64 74 79\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9 40 6 3\n5 10 14 18 22 27 30 31 36\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 44 6 2\n4 8 13 19 23 29 32 33 37 41\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 42 1 3\n1 6 10 15 17 22 24 29 33 38\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 82 2 5\n9 17 27 37 44 51 57 62 67 72\n",
"output": "RUN 8\nJUMP 2\nRUN 6\nJUMP 2\nRUN 8\nJUMP 2\nRUN 8\nJUMP 2\nRUN 5\nJUMP 2\nRUN 5\nJUMP 2\nRUN 4\nJUMP 2\nRUN 3\nJUMP 2\nRUN 3\nJUMP 2\nRUN 3\nJUMP 2\nRUN 9\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "11 69 4 9\n7 14 20 26 29 35 40 46 52 58 64\n",
"output": "RUN 6\nJUMP 2\nRUN 5\nJUMP 2\nRUN 4\nJUMP 2\nRUN 4\nJUMP 5\nRUN 4\nJUMP 7\nRUN 4\nJUMP 2\nRUN 4\nJUMP 2\nRUN 4\nJUMP 2\nRUN 4\nJUMP 2\nRUN 4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "11 65 1 7\n7 11 14 21 24 30 37 44 50 56 59\n",
"output": "RUN 6\nJUMP 2\nRUN 2\nJUMP 2\nRUN 1\nJUMP 2\nRUN 5\nJUMP 2\nRUN 1\nJUMP 2\nRUN 4\nJUMP 2\nRUN 5\nJUMP 2\nRUN 5\nJUMP 2\nRUN 4\nJUMP 2\nRUN 4\nJUMP 2\nRUN 1\nJUMP 2\nRUN 5\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "11 77 10 10\n7 14 17 24 29 34 38 47 56 64 69\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "12 78 3 1\n4 11 19 22 30 38 43 51 56 59 67 73\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "12 89 14 9\n6 11 18 24 33 37 45 51 60 69 71 80\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "12 13 6 7\n1 2 3 4 5 6 7 8 9 10 11 12\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "13 91 1 3\n5 12 17 22 29 36 43 49 57 64 70 74 84\n",
"output": "RUN 4\nJUMP 2\nRUN 5\nJUMP 2\nRUN 3\nJUMP 2\nRUN 3\nJUMP 2\nRUN 5\nJUMP 2\nRUN 5\nJUMP 2\nRUN 5\nJUMP 2\nRUN 4\nJUMP 2\nRUN 6\nJUMP 2\nRUN 5\nJUMP 2\nRUN 4\nJUMP 2\nRUN 2\nJUMP 2\nRUN 8\nJUMP 2\nRUN 6\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "13 87 5 6\n7 10 18 24 31 40 41 48 54 63 69 78 81\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "13 46 2 4\n1 4 9 13 15 19 21 23 25 30 35 37 42\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "14 93 1 1\n8 15 19 21 28 36 44 51 56 63 67 74 79 85\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "14 62 11 4\n5 10 15 18 22 26 31 34 39 42 44 47 52 57\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "14 109 10 1\n8 15 25 29 38 48 57 65 70 79 81 89 94 100\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "15 97 4 4\n3 7 13 23 29 35 39 45 49 50 60 68 72 81 87\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "15 77 4 8\n7 14 16 20 26 33 36 43 44 48 52 59 61 66 70\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "15 56 1 5\n5 10 15 20 21 25 29 31 34 37 38 41 43 47 52\n",
"output": "RUN 4\nJUMP 2\nRUN 3\nJUMP 2\nRUN 3\nJUMP 2\nRUN 3\nJUMP 3\nRUN 2\nJUMP 2\nRUN 2\nJUMP 4\nRUN 1\nJUMP 2\nRUN 1\nJUMP 3\nRUN 1\nJUMP 4\nRUN 2\nJUMP 2\nRUN 3\nJUMP 2\nRUN 3\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1000000000 1 3\n5 8\n",
"output": "RUN 4\nJUMP 2\nRUN 1\nJUMP 2\nRUN 999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1000000000 1 2\n5 8\n",
"output": "RUN 4\nJUMP 2\nRUN 1\nJUMP 2\nRUN 999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1000000000 1 4\n5 8\n",
"output": "RUN 4\nJUMP 2\nRUN 1\nJUMP 2\nRUN 999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1000000000 2 4\n5 8\n",
"output": "IMPOSSIBLE\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1000000000 2 5\n5 8\n",
"output": "RUN 4\nJUMP 5\nRUN 999999991\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
220
|
Solve the following coding problem using the programming language python:
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
-----Input-----
The first line of the input contains two integers s and x (2 ≤ s ≤ 10^12, 0 ≤ x ≤ 10^12), the sum and bitwise xor of the pair of positive integers, respectively.
-----Output-----
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
-----Examples-----
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
-----Note-----
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
s, x = list(map(int, input().split()))
rem = int(s == x) * 2
p, t, cur = [], 0, 1
for i in range(64):
if x % 2:
t += 1
s -= cur
else:
p.append(cur * 2)
cur *= 2
x //= 2
for i in p[::-1]:
if s >= i: s -= i
ans = 0 if s else 2 ** t - rem
print(ans)
```
|
vfc_10634
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/627/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "9 5\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 2\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 0\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "549755813886\n",
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{
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"input": "2 0\n",
"output": "1\n",
"type": "stdin_stdout"
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{
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"input": "2 2\n",
"output": "0\n",
"type": "stdin_stdout"
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"output": "0\n",
"type": "stdin_stdout"
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{
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"input": "80 12\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
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"output": "2048\n",
"type": "stdin_stdout"
},
{
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"output": "32768\n",
"type": "stdin_stdout"
},
{
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"output": "4096\n",
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},
{
"fn_name": null,
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"output": "16384\n",
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},
{
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"output": "4096\n",
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{
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{
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"type": "stdin_stdout"
},
{
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"output": "8589934590\n",
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},
{
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"output": "134217726\n",
"type": "stdin_stdout"
},
{
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"output": "65534\n",
"type": "stdin_stdout"
},
{
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"output": "1048574\n",
"type": "stdin_stdout"
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{
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"output": "30\n",
"type": "stdin_stdout"
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"input": "1839714 248080\n",
"output": "128\n",
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"input": "497110 38\n",
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}
|
apps
|
verifiable_code
|
221
|
Solve the following coding problem using the programming language python:
Long story short, shashlik is Miroslav's favorite food. Shashlik is prepared on several skewers simultaneously. There are two states for each skewer: initial and turned over.
This time Miroslav laid out $n$ skewers parallel to each other, and enumerated them with consecutive integers from $1$ to $n$ in order from left to right. For better cooking, he puts them quite close to each other, so when he turns skewer number $i$, it leads to turning $k$ closest skewers from each side of the skewer $i$, that is, skewers number $i - k$, $i - k + 1$, ..., $i - 1$, $i + 1$, ..., $i + k - 1$, $i + k$ (if they exist).
For example, let $n = 6$ and $k = 1$. When Miroslav turns skewer number $3$, then skewers with numbers $2$, $3$, and $4$ will come up turned over. If after that he turns skewer number $1$, then skewers number $1$, $3$, and $4$ will be turned over, while skewer number $2$ will be in the initial position (because it is turned again).
As we said before, the art of cooking requires perfect timing, so Miroslav wants to turn over all $n$ skewers with the minimal possible number of actions. For example, for the above example $n = 6$ and $k = 1$, two turnings are sufficient: he can turn over skewers number $2$ and $5$.
Help Miroslav turn over all $n$ skewers.
-----Input-----
The first line contains two integers $n$ and $k$ ($1 \leq n \leq 1000$, $0 \leq k \leq 1000$) — the number of skewers and the number of skewers from each side that are turned in one step.
-----Output-----
The first line should contain integer $l$ — the minimum number of actions needed by Miroslav to turn over all $n$ skewers. After than print $l$ integers from $1$ to $n$ denoting the number of the skewer that is to be turned over at the corresponding step.
-----Examples-----
Input
7 2
Output
2
1 6
Input
5 1
Output
2
1 4
-----Note-----
In the first example the first operation turns over skewers $1$, $2$ and $3$, the second operation turns over skewers $4$, $5$, $6$ and $7$.
In the second example it is also correct to turn over skewers $2$ and $5$, but turning skewers $2$ and $4$, or $1$ and $5$ are incorrect solutions because the skewer $3$ is in the initial state after these operations.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, k = map(int, input().split())
if n <= k + k + 1:
print(1)
print((n + 1) // 2)
else:
answer = -1
answer_n = 10**100
for i in range(min(k + 1, n)):
t = n - (k + i + 1)
if t % (k + k + 1) >= k + 1:
if 2 + t // (k + k + 1) < answer_n:
answer = i + 1
answer_n = 2 + t // (k + k + 1)
if t % (k + k + 1) == 0:
if 1 + t // (k + k + 1) < answer_n:
answer = i + 1
answer_n = 1 + t // (k + k + 1)
print(answer_n)
while answer <= n:
print(answer, end = ' ')
answer += k + k + 1
```
|
vfc_10638
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1040/B",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
222
|
Solve the following coding problem using the programming language python:
You are given a positive integer $n$, written without leading zeroes (for example, the number 04 is incorrect).
In one operation you can delete any digit of the given integer so that the result remains a positive integer without leading zeros.
Determine the minimum number of operations that you need to consistently apply to the given integer $n$ to make from it the square of some positive integer or report that it is impossible.
An integer $x$ is the square of some positive integer if and only if $x=y^2$ for some positive integer $y$.
-----Input-----
The first line contains a single integer $n$ ($1 \le n \le 2 \cdot 10^{9}$). The number is given without leading zeroes.
-----Output-----
If it is impossible to make the square of some positive integer from $n$, print -1. In the other case, print the minimal number of operations required to do it.
-----Examples-----
Input
8314
Output
2
Input
625
Output
0
Input
333
Output
-1
-----Note-----
In the first example we should delete from $8314$ the digits $3$ and $4$. After that $8314$ become equals to $81$, which is the square of the integer $9$.
In the second example the given $625$ is the square of the integer $25$, so you should not delete anything.
In the third example it is impossible to make the square from $333$, so the answer is -1.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
ar=[]
for i in range(1,10**5):
if(i*i>2*10**9):break
ar.append(i*i)
s=input()
ans=len(s)
for x in ar:
s2=str(x)
i=0
for x in range(len(s)):
if i<len(s2) and s[x]==s2[i]:
i+=1
if(i==len(s2)):
ans=min(ans,len(s)-i)
if(ans==len(s)):
print(-1)
else:
print(ans)
```
|
vfc_10642
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/962/C",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
223
|
Solve the following coding problem using the programming language python:
Let's define a function $f(p)$ on a permutation $p$ as follows. Let $g_i$ be the greatest common divisor (GCD) of elements $p_1$, $p_2$, ..., $p_i$ (in other words, it is the GCD of the prefix of length $i$). Then $f(p)$ is the number of distinct elements among $g_1$, $g_2$, ..., $g_n$.
Let $f_{max}(n)$ be the maximum value of $f(p)$ among all permutations $p$ of integers $1$, $2$, ..., $n$.
Given an integers $n$, count the number of permutations $p$ of integers $1$, $2$, ..., $n$, such that $f(p)$ is equal to $f_{max}(n)$. Since the answer may be large, print the remainder of its division by $1000\,000\,007 = 10^9 + 7$.
-----Input-----
The only line contains the integer $n$ ($2 \le n \le 10^6$) — the length of the permutations.
-----Output-----
The only line should contain your answer modulo $10^9+7$.
-----Examples-----
Input
2
Output
1
Input
3
Output
4
Input
6
Output
120
-----Note-----
Consider the second example: these are the permutations of length $3$: $[1,2,3]$, $f(p)=1$. $[1,3,2]$, $f(p)=1$. $[2,1,3]$, $f(p)=2$. $[2,3,1]$, $f(p)=2$. $[3,1,2]$, $f(p)=2$. $[3,2,1]$, $f(p)=2$.
The maximum value $f_{max}(3) = 2$, and there are $4$ permutations $p$ such that $f(p)=2$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
p=10**9+7
import math
def inv(k,p):
prod=1
while k>1:
prod*=(p//k+1)
k=(k*(p//k+1))%p
return prod%p
n=int(input())
a=[]
k=int(math.log2(n))
x=n
while x>0:
y=x//2
a.append(x-y)
x=y
c=[sum(a[i:]) for i in range(k+1)]
b=[n//(3*2**i)-n//(6*2**i) for i in range(k+1)]
d=[n//2**i-n//(3*2**i) for i in range(k+1)]
facs=[1]*(n+1)
for i in range(2,n+1):
facs[i]=(i*facs[i-1])%p
if n<3*(2**(k-1)):
start=k
else:
start=0
tot=0
for j in range(start,k+1):
prod=1
for i in range(j,k):
prod*=b[i]
prod*=d[j]
for i in range(j):
prod*=a[i]
prod%=p
prod*=facs[n]
e=[a[i] for i in range(j)]+[d[j]]+[b[i] for i in range(j,k)]
f=[sum(e[:i+1]) for i in range(k+1)]
g=1
for guy in f:
g*=guy
prod*=inv(g,p)
prod%=p
tot+=prod
print(tot%p)
```
|
vfc_10646
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1174/E",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
224
|
Solve the following coding problem using the programming language python:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump.
Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability. [Image] The picture corresponds to the first example.
The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'.
-----Input-----
The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100.
-----Output-----
Print single integer a — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels.
-----Examples-----
Input
ABABBBACFEYUKOTT
Output
4
Input
AAA
Output
1
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
# You lost the game.
s = str(input())
n = len(s)
d = -1
r = 0
V = "AEIOUY"
for i in range(n):
if V.count(s[i]):
r = max(r,i-d)
d = i
print(max(r, n-d))
```
|
vfc_10650
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/733/A",
"time_limit": "None"
}
|
{
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"test_cases": [
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|
apps
|
verifiable_code
|
225
|
Solve the following coding problem using the programming language python:
Dawid has four bags of candies. The $i$-th of them contains $a_i$ candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
-----Input-----
The only line contains four integers $a_1$, $a_2$, $a_3$ and $a_4$ ($1 \leq a_i \leq 100$) — the numbers of candies in each bag.
-----Output-----
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
-----Examples-----
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
-----Note-----
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive $12$ candies.
In the second sample test, it's impossible to distribute the bags.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
l=list(map(int,input().split()))
for i in range(16):
cur1,cur2=0,0
for j in range(4):
if (i&(1<<j))==0:
cur1+=l[j]
else:
cur2+=l[j]
if cur1==cur2:
print("YES")
quit()
print("NO")
```
|
vfc_10654
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1230/A",
"time_limit": "None"
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|
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|
apps
|
verifiable_code
|
226
|
Solve the following coding problem using the programming language python:
You may have heard of the pie rule before. It states that if two people wish to fairly share a slice of pie, one person should cut the slice in half, and the other person should choose who gets which slice. Alice and Bob have many slices of pie, and rather than cutting the slices in half, each individual slice will be eaten by just one person.
The way Alice and Bob decide who eats each slice is as follows. First, the order in which the pies are to be handed out is decided. There is a special token called the "decider" token, initially held by Bob. Until all the pie is handed out, whoever has the decider token will give the next slice of pie to one of the participants, and the decider token to the other participant. They continue until no slices of pie are left.
All of the slices are of excellent quality, so each participant obviously wants to maximize the total amount of pie they get to eat. Assuming both players make their decisions optimally, how much pie will each participant receive?
-----Input-----
Input will begin with an integer N (1 ≤ N ≤ 50), the number of slices of pie.
Following this is a line with N integers indicating the sizes of the slices (each between 1 and 100000, inclusive), in the order in which they must be handed out.
-----Output-----
Print two integers. First, the sum of the sizes of slices eaten by Alice, then the sum of the sizes of the slices eaten by Bob, assuming both players make their decisions optimally.
-----Examples-----
Input
3
141 592 653
Output
653 733
Input
5
10 21 10 21 10
Output
31 41
-----Note-----
In the first example, Bob takes the size 141 slice for himself and gives the decider token to Alice. Then Alice gives the size 592 slice to Bob and keeps the decider token for herself, so that she can then give the size 653 slice to herself.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
a = list(map(int, input().split()))
a = a[::-1]
d = 0
for i in range(len(a)):
d = max(0 + d, a[i] + (sum(a[:i]) - d))
print(sum(a)-d, d)
```
|
vfc_10658
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/859/C",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
227
|
Solve the following coding problem using the programming language python:
You've got a positive integer sequence a_1, a_2, ..., a_{n}. All numbers in the sequence are distinct. Let's fix the set of variables b_1, b_2, ..., b_{m}. Initially each variable b_{i} (1 ≤ i ≤ m) contains the value of zero. Consider the following sequence, consisting of n operations.
The first operation is assigning the value of a_1 to some variable b_{x} (1 ≤ x ≤ m). Each of the following n - 1 operations is assigning to some variable b_{y} the value that is equal to the sum of values that are stored in the variables b_{i} and b_{j} (1 ≤ i, j, y ≤ m). At that, the value that is assigned on the t-th operation, must equal a_{t}. For each operation numbers y, i, j are chosen anew.
Your task is to find the minimum number of variables m, such that those variables can help you perform the described sequence of operations.
-----Input-----
The first line contains integer n (1 ≤ n ≤ 23). The second line contains n space-separated integers a_1, a_2, ..., a_{n} (1 ≤ a_{k} ≤ 10^9).
It is guaranteed that all numbers in the sequence are distinct.
-----Output-----
In a single line print a single number — the minimum number of variables m, such that those variables can help you perform the described sequence of operations.
If you cannot perform the sequence of operations at any m, print -1.
-----Examples-----
Input
5
1 2 3 6 8
Output
2
Input
3
3 6 5
Output
-1
Input
6
2 4 8 6 10 18
Output
3
-----Note-----
In the first sample, you can use two variables b_1 and b_2 to perform the following sequence of operations. b_1 := 1; b_2 := b_1 + b_1; b_1 := b_1 + b_2; b_1 := b_1 + b_1; b_1 := b_1 + b_2.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def Solve(x,B):
if((X,x,B) in Mem):
return Mem[(X,x,B)]
if(len(B)>X):
return False
if(x==len(L)):
return True
if(Form(L[x],B)):
A=list(B)
for e in range(len(B)):
r=A[e]
A[e]=L[x]
if(Solve(x+1,tuple(sorted(A)))):
Mem[(X,x,B)]=True
return True
A[e]=r
A+=[L[x]]
if(Solve(x+1,tuple(sorted(A)))):
Mem[(X,x,B)]=True
return True
Mem[(X,x,B)]=False
return False
def Form(x,B):
for i in range(len(B)):
for j in range(i,len(B)):
if(B[i]+B[j]==x):
return True
return False
n=int(input())
L=list(map(int,input().split()))
done=False
Mem={}
for X in range(1,n+1):
if(Solve(1,(L[0],))):
print(X)
done=True
break
if(not done):
print(-1)
```
|
vfc_10662
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/279/D",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
228
|
Solve the following coding problem using the programming language python:
Alice and Bob are playing a game with $n$ piles of stones. It is guaranteed that $n$ is an even number. The $i$-th pile has $a_i$ stones.
Alice and Bob will play a game alternating turns with Alice going first.
On a player's turn, they must choose exactly $\frac{n}{2}$ nonempty piles and independently remove a positive number of stones from each of the chosen piles. They can remove a different number of stones from the piles in a single turn. The first player unable to make a move loses (when there are less than $\frac{n}{2}$ nonempty piles).
Given the starting configuration, determine who will win the game.
-----Input-----
The first line contains one integer $n$ ($2 \leq n \leq 50$) — the number of piles. It is guaranteed that $n$ is an even number.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \leq a_i \leq 50$) — the number of stones in the piles.
-----Output-----
Print a single string "Alice" if Alice wins; otherwise, print "Bob" (without double quotes).
-----Examples-----
Input
2
8 8
Output
Bob
Input
4
3 1 4 1
Output
Alice
-----Note-----
In the first example, each player can only remove stones from one pile ($\frac{2}{2}=1$). Alice loses, since Bob can copy whatever Alice does on the other pile, so Alice will run out of moves first.
In the second example, Alice can remove $2$ stones from the first pile and $3$ stones from the third pile on her first move to guarantee a win.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n=int(input())
s=list(map(int,input().split()))
print("Bob"if s.count(min(s))>n/2 else"Alice")
```
|
vfc_10666
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1147/C",
"time_limit": "None"
}
|
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}
|
apps
|
verifiable_code
|
229
|
Solve the following coding problem using the programming language python:
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers a_1, a_2, ..., a_{n}. First, he pick an integer x and then he adds x to some elements of the array (no more than once), subtract x from some other elements (also, no more than once) and do no change other elements. He wants all elements of the array to be equal.
Now he wonders if it's possible to pick such integer x and change some elements of the array using this x in order to make all elements equal.
-----Input-----
The first line of the input contains an integer n (1 ≤ n ≤ 100 000) — the number of integers in the Filya's array. The second line contains n integers a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 10^9) — elements of the array.
-----Output-----
If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes).
-----Examples-----
Input
5
1 3 3 2 1
Output
YES
Input
5
1 2 3 4 5
Output
NO
-----Note-----
In the first sample Filya should select x = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
read = lambda: list(map(int, input().split()))
n = int(input())
a = list(read())
s = set()
for i in a:
s.add(i)
f1 = len(s) < 3
f2 = len(s) == 3 and max(s) + min(s) == 2 * sorted(s)[1]
print('YES' if f1 or f2 else 'NO')
```
|
vfc_10670
|
{
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"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/714/B",
"time_limit": "None"
}
|
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},
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},
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|
apps
|
verifiable_code
|
230
|
Solve the following coding problem using the programming language python:
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
- l_1 + len \leq l_2
- S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
-----Constraints-----
- 2 \leq N \leq 5 \times 10^3
- |S| = N
- S consists of lowercase English letters.
-----Input-----
Input is given from Standard Input in the following format:
N
S
-----Output-----
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
-----Sample Input-----
5
ababa
-----Sample Output-----
2
The strings satisfying the conditions are: a, b, ab, and ba. The maximum length among them is 2, which is the answer.
Note that aba occurs twice in S as contiguous substrings, but there is no pair of integers l_1 and l_2 mentioned in the statement such that l_1 + len \leq l_2.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
s = input()
j = 1
result = []
for i in range(n):
while (j < n-1) and (s[i:j] in s[j:]):
j += 1
result.append(j-i-1)
print(max(result))
```
|
vfc_10674
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://atcoder.jp/contests/abc141/tasks/abc141_e",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
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"input": "5\nababa\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
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"input": "2\nxy\n",
"output": "0\n",
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{
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"input": "13\nstrangeorange\n",
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"input": 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bbbbbbb\n",
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"input": 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"output": "2500\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": 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cffrha\n",
"output": "2499\n",
"type": "stdin_stdout"
},
{
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"output": "23\n",
"type": "stdin_stdout"
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"output": "2246\n",
"type": "stdin_stdout"
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{
"fn_name": null,
"input": "4599\nmpfvbozcrxnboodvbfzluraoeaubclnhdkgbrgzpafbzanamwousfmfglthzdyauezatkweyejdkubxprbkniemizklweyjabxesszunsorvtpgagnestwhgcgmqejysodvzrdoptpochbwyqvpbchzmdptvkmsjtzgopbsgiiekcimyjcunqivybrpdrhdpijlfrcronsrtewjuhfqxxvbdwtovfckeayabqorumcubkfnohiyxsozppskgeqbzrwweolhbstuhjuieadatgcebkibozqgzqybmgsfzzuljbkssqpzshzpbbgsnfwaodesokshsygzldxmurrvejwifdmuqkagaegebmzbbywdrdahfspawkwnfzyxienlqrqvtzttpzacrvkepwpzrhtxnhsyzedtgqcthkrxsncozdnjejwhdxhqrpeqbglkkvcpdvwgitnfihpqfknegssfktkblxmusfxklmasctxakloifvghzzdxcnbhaosoayjkhlocxybgwshnkqrbjdpkxjzxkxzpujvffykspfqttarwemtvcsjowsajvswjtebunlswwpeprtegsqhiuohkwetdsxqcxrxyaqjsnlpvakzjjmfvyktbxfzxaenvzqjtescuzugimwkzdcnabgsfuikpztnnajrhxgbmgrayudxjhfuwhsakaqhjmqfkgghdkywlaqxyzaoxfabzkqerjruapgqrfgcvafjdclpeqkbdrtibxepnnqzkscckqnmhrvefzvfyzvgloktduqjmsbjiysvxooilkezhzyjxqhszdsywrfoanovfesuljjbnwrnjyfiimiznxofowrmivqkjuncrjcvfspwanvnhjhakcqaibfodqoceaujfcdiezaohhcraadtsagfrwylfltfahbjdvugpoyixqajedceuxvhqkwkszflywohdxzymxkrygoaiutjdecfqcrzxkkxrdqathhzldxxgctbargwnsdzugwopiemlizcrnohbszqdnhecshvetgdkaxagzugpnaxqdtnsvgfebgzbrirbdemfnejkmnteiwqcklatsfrcymnelhsbjozjejkesrumfdudsauxtrixnmqbiwiiqukapyyznayzwvpkwwxgjarendfcjicceaqvejrvqhjlivxmrxpqrjeekatmttjvwdzlodjcynyxqylppmzgqkvzormigvlosuhofyzzrcbmaitpqainqrdbqkgrwndeatnfyjlxpjedldmntnujhrzezcsyocgybacdsntwgklmpmrygeschpnrlvjssmoaockndsnydbkbeecqqozdbxvruulqeorqiihynmdkpizzltdoerbdqncqzqoiodvbciylbmfpmzzurfjyvdiuiprzhzvumjfrvicegqcrbootovbsualgextnafmrmmuvsdpioyaqjsieuwmjcfgswhhyovcibmmejmhnnsqfexwlcanqghzmexmccokhdkwebjhhwkzbyzpsddjvuemuesnnmanddxejymmbiergflznryxayvjairymrryikbuusuqibxswoopiuunlvvekusmcwaciitojcydqlpdueybijzzytqmybuvvlhmutxssxmawjpkphztfdzutxqhvpfxeoyifzxarhssbxslnwsvuqhxnqpwekvzpkdcvnxfyftnwwqkisalwnjqqwqrhxnmgqgxegnzlzknqnvlxbfjpogpezwogjymdsbpnobpnvnxcnvwftaizzbhymdxwmyhcitfdmobimecmlbimgtcovntbtwwpxtybttsyhyxhfkexkunapulhzprjvedsyewtwnsenvffnwxtxliwxdghhujibdrcbmlanllcouvsfuaawioyqiechpixctejktsvowspvibckycnvjllvlddwgrhvufnrqbcwuynidswvphpbndixlwhlvsevbdtilcxmyruzgeyeonudqvxeixkuhnjvnoiygkawprpiabnofnrzhlakoiszlzsfugolawbinltjlsubkunrpzujeqwbxzbjdrtvgkujabiahsupacxegbsspukdrrryvuwvsuimdayeqlgfczeoqrquhbkhwxhmsqhoktdrotgznupsqmjwvxojxdajxknqibrsjwyeijpwvgkukqotyipyhsylqqrfzmhauafwanbsupnobpunooayvmafhqnvmmitllwihaxltpaoktxukyspwovtlfbugjtwahfswvjjmkyrywhtbalafynsuekmovicnfecnrdmzuzlmlptquvvsfmfglthzdyauezatkweyejdkubxprbkniemizklweyjabxesszunsorvtpgagnestwhgcgmqejysodvzrdoptpochbwyqvpbchzmdptvkmsjtzgopbsgiiekcimyjcunqivybrpdrhdpijlfrcronsrtewjuhfqxxvbdwtovfckeayabqorumcubkfnohiyxsozppskgeqbzrwweolhbstuhjuieadatgcebkibozqgzqybmgsfzzuljbkssqpzshzpbbgsnfwaodesokshsygzldxmurrvejwifdmuqkagaegebmzbbywdrdahfspawkwnfzyxienlqrqvtzttpzacrvkepwpzrhtxnhsyzedtgqcthkrxsncozdnjejwhdxhqrpeqbglkkvcpdvwgitnfihpqfknegssfktkblxmusfxklmasctxakloifvghzzdxcnbhaosoayjkhlocxybgwshnkqrbjdpkxjzxkxzpujvffykspfqttarwemtvcsjowsajvswjtebunlswwpeprtegsqhiuohkwetdsxqcxrxyaqjsnlpvakzjjmfvyktbxfzxaenvzqjtescuzugimwkzdcnabgsfuikpztnnajrhxgbmgrayudxjhfuwhsakaqhjmqfkgghdkywlaqxyzaoxfabzkqerjruapgqrfgcvafjdclpeqkbdrtibxepnnqzkscckqnmhrvefzvfyzvgloktduqjmsbjiysvxooilkezhzyjxqhszdsywrfoanovfesuljjbnwrnjyfiimiznxofowrmivqkjuncrjcvfspwanvnhjhakcqaibfodqoceaujfcdiezaohhcraadtsagfrwylfltfahbjdvugpoyixqajedceuxvhqkwkszflywohdxzymxkrygoaiutjdecfqcrzxkkxrdqathhzldxxgctbargwnsdzugwopiemlizcrnohbszqdnhecshvetgdkaxagzugpnaxqdtnsvgfebgzbrirbdemfnejkmnteiwqcklatsfrcymnelhsbjozjejkesrumfdudsauxtrixnmqbiwiiqukapyyznayzwvpkwwxgjarendfcjicceaqvejrvqhjlivxmrxpqrjeekatmttjvwdzlodjcynyxqylppmzgqkvzormigvlosuhofyzzrcbmaitpqainqrdbqkgrwndeatnfyjlxpjedldmntnujhrzezcsyocgybacdsntwgklmpmrygeschpnrlvjssmoaockndsnydbkbeecqqozdbxvruulqeorqiihynmdkpizzltdoerbdqncqzqoiodvbciylbmfpmzzurfjyvdiuiprzhzvumjfrvicegqcrbootovbsualgextnafmrmmuvsdpioyaqjsieuwmjcfgswhhyovcibmmejmhnnsqfexwlcanqghzmexmccokhdkwebjhhwkzbyzpsddjvuemuesnnmanddxejymmbiergflznryxayvjairymrryikbuusuqibxswoopiuunlvvekusmcwaciitojcydqlpdueybijzzytqmybuvvlhmutxssxmawjpkphztfdzutxqhvpfxeoyifzxarhssbxslnwsvuqhxnqpwekvzpkdcvnxfyftnwwqkisalwnjqqwqrhxnmgqgxegnzlzknqnvlxbfjpogpezwogjymdsbpnobpnvnxcnvwftaizzbhymdxwmyhcitfdmobimecmlbimgtcovntbtwwpxtybttsyhyxhfkexkunapulhzprjvedsyewtwnsenvffnwxtxliwxdghhujibdrcbmlanllcouvsfuaawioyqiechpixctejktsvowspvibckycnvjllvlddwgrhvufnrqbcwuynidswvphpbndixlwhlvsevbdtilcxmyruzgeyeonudqvxeixkuhnjvnoiygkawprpiabnofnrzhlakoiszlzsfugolawbinltjlsubkunrpzujeqwbxzbjdrtvgkujabiahsupacxegbsspukdrrryvuwvsuimdayeqlgfczeoqrquhbkhwxhmsqhoktdrotgznupsqmjwvxojxdajxknqibrsjwyeijpwvgkukqotyipyhsylqqrfzmhauafwanbsupnobpunooayvmafhqnvmmitllwihaxltpaoktxukyspwovtlfbugjtwahfswvjjmkynzwujywewtttlobguoblotzrdfmqbeowpgb\n",
"output": "2236\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4512\nydrtosuycljrnrwtjmmcevlftanyifidoqfdzdoudcmegcsgiiduohinrxwffdfslxvrcpfycpenvwqyuyjlhznowgejltpucbiiyvgvuojfvhgwnaeqoumvtnqbfgwpeixljvbfbyfgnyyfceitoqqzrbqygmjbuufwscmrlfdowvpcunfvhivscjluooggpnrsuoqvtfdllzqxjihgegrurdzfmlijpwjcnlsfcdolebzemkunlcwtksdtrdqfelxbtnisghcfxzbxjgvpeuoblkggnfwggjuputacobaeorkkmocrmhpnaemhgsotnazmnmxfvqywahgwazuidgokplfbnalxmfbdrogqvjgolvuwolucixogylqqlcdsafanmzxwwacbuuvqmsaqikzwswmcsmpgswmexlivzzqpzqxcyfwbdygylwlsawuocmpmolczgvmicamhpbyvfikilsphatogcmqsnecugfvmpjrokiyahuvxpxzfbktmzngxlgelktvscrlzrvifbmxeacusvycenprlzigfvxlrhqwyutkanjaoohilqwzmrmynjtddqzelvrhzihhvjkndausepzgwvrznjzebcdszoemiamyivpzdiggsdontbiypreyvwbtxkbtdqfblbyiaivqgcjabjaxkbyayobsnwcsewwaqmmljcavamphvnwotnghgmuxdrjlifgiwykrzwfqoqmnzrhlishgsnxsxduowipavusqywqveaqmfssjnwlnnvqxdzikerrqglmqarnqurmrrygkldncfruskaxzggjaqjvtghqoskzvzyksnenuoebfgyydfeghvcwkvylogfzihksudijcdqnpbbmfeakbdnhmjhvirgqcekqlnhtwtxneszfwvgqzlokjzzcimpfqkupzzfrwaeizolfkmeomxoyofmlpzaxvmqifvvhbuckfbonvgbschkgftdduotwfokhlhyewevpagackkmizhheipgqeosvwcbcnakydwdmyucyigdegvckrpxgkgqcuarcpkfkomlipkafnuuegngnivjvdmgzkerhjbequwndqfszibjdlqfjlirqsmsfpiagtueiuogbiyqjlomxjwadvmakxfyfcpucigrkeynfznyucjzadymaelopzddoflrfkhakubniwryfsicxchpqtmlcarwxojjdnjhmditsoazuccqbejhrsqfkywzbyvnxwvitslethtjrvoqilgnqxzdzacotptwyeoidhypebupvjaulgyrkkcybbtepupwyzuubqscahzvmakakhqmbpjcjruuucjmrgbxlujfzrxvrgvntqpbnokdfuwwmbblguoszscxbdxuraqaktgdlekkzvzazjutxqowjkeexbwbaxzllyjfwtisbnvtitekhhjuxujpqfurcvjzcjiqmeixjwhqsocwdiwmbndpslpusuiaypiqvdkqxcepnkkguhdfishagmzakhycjxlyuaslcuikkvijpfohgnpasadrgfgirnatqdwwkxlwldyvnemqhsuosiykkelxrpgnjmezidmnanulbvklmelvllgqivfxscvcxzhqcaaokmkipyghcsnpgfahgyqwkhztfdjnptrogfhibbognstszwoklhxxsgojcqujsrnfuibtkpfwqwsdwmgapvjrmvlouhlysyxpubrepnaqczhsuqqfjdkagxhwzofksfodbrdjimvhfisyqjohwmyyiyvpqvawnwisiaxqvkinltdqajgoatgyadjeielldlnogpftpnlbqkrlknxrpppzqdrurnatxpitrrlmepklfuguduvxgrrphcgopinrgrbizodpxzjzzujgukjaarsavkysjofrsnfogwanzabocabwtpzbzyntekwocnzljzfdrkcqgmcdtewgwczcpofdhjitiwydzswxjmwbauysxtyuydohgxoazvtltbapzdxhgxtksgujamuxeqnexicykqwzggndaavsmovlfgtjuzxgihzlxqwcphcoelngtcfwcbvkwsykxsddfidjypimgkbyrguvzvgiyycwfutzuymopbnokiidfkouihtawgyzxykdepmwjjddxvetnwngnhcpdejpmtetgsexicpyucaiefskebrmyttiyovbhczgsnpzqldbrpergbndglmmnvuvoficwvbrqjrszayvgiwsjxaqljzwwjixygiugeaquusqmpjvmdngkynhbyvsrnpiyszsadidvfzclujmvoblyopypisvqmbhwnbnypcuhdneitoqqzrbqygmjbuufwscmrlfdowvpcunfvhivscjluooggpnrsuoqvtfdllzqxjihgegrurdzfmlijpwjcnlsfcdolebzemkunlcwtksdtrdqfelxbtnisghcfxzbxjgvpeuoblkggnfwggjuputacobaeorkkmocrmhpnaemhgsotnazmnmxfvqywahgwazuidgokplfbnalxmfbdrogqvjgolvuwolucixogylqqlcdsafanmzxwwacbuuvqmsaqikzwswmcsmpgswmexlivzzqpzqxcyfwbdygylwlsawuocmpmolczgvmicamhpbyvfikilsphatogcmqsnecugfvmpjrokiyahuvxpxzfbktmzngxlgelktvscrlzrvifbmxeacusvycenprlzigfvxlrhqwyutkanjaoohilqwzmrmynjtddqzelvrhzihhvjkndausepzgwvrznjzebcdszoemiamyivpzdiggsdontbiypreyvwbtxkbtdqfblbyiaivqgcjabjaxkbyayobsnwcsewwaqmmljcavamphvnwotnghgmuxdrjlifgiwykrzwfqoqmnzrhlishgsnxsxduowipavusqywqveaqmfssjnwlnnvqxdzikerrqglmqarnqurmrrygkldncfruskaxzggjaqjvtghqoskzvzyksnenuoebfgyydfeghvcwkvylogfzihksudijcdqnpbbmfeakbdnhmjhvirgqcekqlnhtwtxneszfwvgqzlokjzzcimpfqkupzzfrwaeizolfkmeomxoyofmlpzaxvmqifvvhbuckfbonvgbschkgftdduotwfokhlhyewevpagackkmizhheipgqeosvwcbcnakydwdmyucyigdegvckrpxgkgqcuarcpkfkomlipkafnuuegngnivjvdmgzkerhjbequwndqfszibjdlqfjlirqsmsfpiagtueiuogbiyqjlomxjwadvmakxfyfcpucigrkeynfznyucjzadymaelopzddoflrfkhakubniwryfsicxchpqtmlcarwxojjdnjhmditsoazuccqbejhrsqfkywzbyvnxwvitslethtjrvoqilgnqxzdzacotptwyeoidhypebupvjaulgyrkkcybbtepupwyzuubqscahzvmakakhqmbpjcjruuucjmrgbxlujfzrxvrgvntqpbnokdfuwwmbblguoszscxbdxuraqaktgdlekkzvzazjutxqowjkeexbwbaxzllyjfwtisbnvtitekhhjuxujpqfurcvjzcjiqmeixjwhqsocwdiwmbndpslpusuiaypiqvdkqxcepnkkguhdfishagmzakhycjxlyuaslcuikkvijpfohgnpasadrgfgirnatqdwwkxlwldyvnemqhsuosiykkelxrpgnjmezidmnanulbvklmelvllgqivfxscvcxzhqcaaokmkipyghcsnpgfahgyqwkhztfdjnptrogfhibbognstszwoklhxxsgojcqujsrnfuibtkpfwqwsdwmgapvjrmvlouhlysyxpubrepnaqczhsuqqfjdkagxhwzofksfodbrdjimvhfisyqjohwmyyiyvpqvawnwisiaxqvkinltdqajgoatgyadjeielldlnogpftpnlbqkrlknxrpppzqdrurnatxpitrrlmepklfuguduvxgrrphcgopinrgrbizodpxzjzzujgukjaarsavkysjofrsnfogwanzabocabwtpzbzyntekwocnzljzfdrkcqgmcdtewgwczcpofdhjitiwydzswxjmwbauysxtyuydohgxoazvtltbapzdxhgxtksgujamuxeqnexicykqwzggndaavsmovlfgtjuzxgihzlxqwcphcoelnucjigcdqipktkjqbizvpebpplwsndysmoujqdlfuapftvjtvtkkqlczeyzlpexeogyitgouudrzrpxvusyjugnknnduvaxcgymbsrpalpesajdseqthklooidzrmlufjuujyhacraajnufszhjvawsplyxbgkpzbpdqendlinjvnemccudbyaiadmufbqwaxbnsmjjlddeehltnqwcbhvopzihcdnrxdedsajuqnckmegajtvevqceuzh\n",
"output": "1927\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": 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"output": "2030\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4738\nkebtduiuzrgmwblbrenoaedgylecgkcdswexvyhhhgkyueautmmzarptzqhqaptepoerhyqxhmeoxuckbfdoztylpmgjwhgsaxypguibcgbvdebtecidyxskutrypyddbhvrtgjqshhpphzcavjbajubffauvawvcklrnstszpqrmflswmuolfbeflcrfwgkmxaadqexlwbnywkrxywpaglhsoljzpqnenpqemrovphlbfaljcrhffyiezkzdrflcmzndrhnspoyojjdexfmuivjuwyurftfwwseudcjiiktukuurpdmsrvathpgzfwjtyiqfhjvcqapnujuwsewujmivpbdhpwjglqlfvdqcqbsnsybdgaybbxpsgucgvmmzbudsjqnsnxizsbseiacyxinfrnocbvimgxrpdmvvlxtquskpjtmirpvxyhpevxocloehjlrcrjmukjnaflugwpukkbjyudkajziszcnidnenitqifeswzvqscntwmpgxyyiicofvbmxagrllnkfhshggnheefpoeilwawvshsnsydvmcdczxfrcwkwoyoqwscascowjedyyhefksbtrmjokhqwruyhesohvogwedcbdhrgcbpjijrxiyraavzxtsxaiyyntpbkbtsievrbijtqqmkjshottvqkamotjutleuweeqidvwmvgwaplhjwtrewsyujqlnctevvnfsfinifvrnuntqboouidfotzmsuftmfsbppbildpgfhvnweczdwskdvjvzlmeosznuxwpidijlsonisrzspxvjbwudltkjfivqrxxqzxubfwtrvfetabettmzjfzfdrunbigljmfoxgnpydxguzkyxlaorqadnckucgrrxtekhfqwgbkmmampjkxsmcsxrwmueqjfxqjsrcwosagpioaetahryzhoeciszijlilachwryaamdwcvixeellewktwhkvcxpobvfidlczexcqepjnmhlucahbcsqidxpxbqzsstivwvhdmilyecaclxoxiuabcyswnpdymkkawirabjrcyfehyyeskesdcgambysbfcidehspsfvsekwrnnvxedcuvefjsgaplbmhiksmjapckvkfwkrmfqhhbfshhjtmvcdeizwikpdajuqgidjbczjmongpmdyjpibntanxwilwpuwikectduvzrkrcltqglhpsprdivvpyfaajcxuskooexycazavxrxllgahoorecqmwyyzhtwgghmgdnxiledhvvpedrojafworwfwoxnaxavvwutsfddhrxjrjlxcyllvrjcfwimjqudyskhguoeijkiqqfjdrbhdikewnncdlbxhnkkormzwwgnyhqzsparsovhyfykszitzeczabtmggiqrhebunygikjycnjnemyunklnwqsmkqkhhgfpusudmkehucperfgojrzywxkzmdabzohnshjmplaoixazpdrlvbdmwmdvchywcqqcvbbwdqcquboupklwrxzmfnfzlqjrmqproumfflvncgmsvpqeqobfjwhaqflkyyrkrvniqatlbkxoasftcignmrqkttxrpiwfiqotgdbrnmjmprmucdvhfcwzksngxgtncfoxvgcowekiklnwkstvbsvuaedhskarsgkxatcoxiztvrcxbrwpizqtbkbikfrretxsnwtyzkvdhpdxijscmjskihfycxgfmesxjaxmciqbvfwsuhrtibhxcpnzdxfwgqkbjgxetmeekdofwceyronktwuajcudsjsyceozajwixbvjxnehhqptntspnwoictwzlgsirvnbzlsclnzhluorlnuwtpjbyfobvnuttjfwvcqzphgbnrcryidinyrpladsxofyvxjyhapxslbwrnnvuhvqdgnzcigyhlzzgdpxnlbycbsfqocfhsqnndmrrapctoceyjtbyqrcxyuhxowsezglddadoaiymeytvnmhpmszfruvisfivzgqgipuqwmeyuotjrhkefcyvqpfhtlkwvheszyfgsvmaqnmbcietbvcadvsbvvxtnwcqbkesqagninegslbxrerexqqxdmjgnphinprlekkhttykefohkjggaqdysaqxkmfctyzjxdxskrruvbwxscizxswjwhddhsvcdbhyrjncfvhkvrrxulhjxlcvtaahqddewwrvuzfeunfeevnqoydoqzlprqgdvefukuvvdgsvofznssjbujugydzpzhythdljwyemzekcilleavqszdpwolvscbxytzfhhrdecrdlmyqkrbszmidnxlmaedislzrszpoypqesouxqlzlrrhcwnzixyksodqsveyxvcyrqnuffngoswllbmxnwhqytubczhgnhnjspqwnuirrhlwhwpvokixmtpbececrgwzjcnwqfyowdeswgoywtoyesrwkpdhzpdpcggcrdtotkhmcbuqxlicdhnpevytvrwazrksqmqliazxvomjolsrtduddcficcsshxmqeyhjfughqlrapulzrudokcarhuvxiqafdgkzhfwqagycggvrkymasjozamdkzxunrptilhgwqzsvaovukwpkfcjyhpvxhnptrteopqtueuoeusdilgtshsexdrcewbozurtrfnnfohmbkchzswnwovigvmwjibhhwdnyotgudlioizheagfitqbpvluypdslwfwyretbvehprmzwtgewlzzbbrklcyifqzpnmapohrauuzfdhwgiosxhleipoapzmvhrnccydsbzgoqbqxzprfjuvkgjkwcwnlkbphjlrlgzwjuxpaaboeqldsotaneiaiyepzuilgiylsmwhbwbdrxxhfgzmfhiokbonmlslblswxksfulsibnfellgfqbqpheljltzhokexnidpudqfqnjvildnadoxysagnpfwjkhpoqectrybshsxxhmnxxfittuzksdseczfcxdywctahyawzoigwtqjatlrtprfsglrguujxipzxrncdlbxhnkkormzwwgnyhqzsparsovhyfykszitzeczabtmggiqrhebunygikjycnjnemyunklnwqsmkqkhhgfpusudmkehucperfgojrzywxkzmdabzohnshjmplaoixazpdrlvbdmwmdvchywcqqcvbbwdqcquboupklwrxzmfnfzlqjrmqproumfflvncgmsvpqeqobfjwhaqflkyyrkrvniqatlbkxoasftcignmrqkttxrpiwfiqotgdbrnmjmprmucdvhfcwzksngxgtncfoxvgcowekiklnwkstvbsvuaedhskarsgkxatcoxiztvrcxbrwpizqtbkbikfrretxsnwtyzkvdhpdxijscmjskihfycxgfmesxjaxmciqbvfwsuhrtibhxcpnzdxfwgqkbjgxetmeekdofwceyronktwuajcudsjsyceozajwixbvjxnehhqptntspnwoictwzlgsirvnbzlsclnzhluorlnuwtpjbyfobvnuttjfwvcqzphgbnrcryidinyrpladsxofyvxjyhapxslbwrnnvuhvqdgnzcigyhlzzgdpxnlbycbsfqocfhsqnndmrrapctoceyjtbyqrcxyuhxowsezglddadoaiymeytvnmhpmszfruvisfivzgqgipuqwmeyuotjrhkefcyvqpfhtlkwvheszyfgsvmaqnmbcietbvcadvsbvvxtnwcqbkesqagninegslbxrerexqqxdmjgnphinprlekkhttykefohkjggaqdysaqxkmfctyzjxdxskrruvbwxscizxswjwhddhsvcdbhyrjncfvhkvrrxulhjxlcvtaahqddewwrvuzfeunfeevnqoydoqzlprqgdvefukuvvdgsvofznssjbujugydzpzhythdljwyemzekcilleavqszdpwolvscbxytzfhhrdecrdlmyqkrbszmidnxlmaedislzrszpoypqesouxqlzlrrhcwnzixyksodqsveyxvcyrqnuffngoswllbmxnwhqytubczhgnhnjspqwnuirrhlwhwpvokixmtpbececrgwzjcnwqfyowdeswgoywtoyesrwkpdhzpdpcggcrdtotkhmcbuqxlicdhnpevytvrwazrksqmqliazxvomjolsrtduddcficcsshxmqeyhjfughqlrapulzrudokcarhuvxiqafdgkzhfwqagycggvrkymasjozamdkzxunrptilhgwqzsvaovukwpkfcjyhpvxhnptrteopqtueuoeusdilgtshsexdrcewbozurtrfnnfohmbkchzswnwovigvmwjibhhwdnyotgudlioizheagfitqbpvluypdslwfwyretbvehprmzwtgewlzzbbrklcyifqzpnmapohrauuzfdhwgiosxhleipoapzmvhrnccydsbzgoqbqxzprfjuvkgjkwcwnlkbphjlrlgzwjuxpaaboeqldsotaneiaiyepzuilgiylsmwhbwbdrxxhfgzmfhiokbonmlslblswxksfulsibnfellgfqbqpheljltzhokexnidpudqfqnjvildnadoxysjyfrniiwmehivnniygnukdolcttylvidodyjjuvpqvcqamqhgkekccnxxgzwwdvzwmgctpgrwrwtkekjaxymnfxhpblseebbl\n",
"output": "1600\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4884\nxvizvmfsxvzyhwggqdifknbsyuvlckqzidahhamqmbyqwrgbpjgevwctbazmbxqzlsxloccpeyavjdlfhvfeianermljlvyhlwlumtqhknxdbedxgnlsmakhhbecdxqowbbqulqqpwknrvyojuwurxphxoaoawxfeiueypkvjnbntybflvpslheqjrpuunnhmcwmihvxzgarzlfzqgtkpsxuiyiccuhzrpeiyztajrxjqaoxtzuakznqufsosliqtiwewcpgnumrmrwnndcowiyhswlbchefoayaojciimhrsaickpclmnbrhzvuqxlodnqkdooxxefmpuzgwxcewckhnjpzmtlthrwfftpvkiemfvhnbnypudlqukiyufgywwhginumjgztcisgjqrqlywhflksqgjklossloltnpnbgvbvhbpuatfshhqacsplgwtduljpgszmznnhhahqyhljwtdwhozomfkbhiaawbnbhvsfrdhhzjcfsemujnogglercthwsurvbdxnpunfqiuzvytoolsbbkyuyovjftnwwuqrjksnbofwatauobjcwtnmrtmavzxcaejgmdldysahlkstqkglhjbjijespejwndkvgksbdosmtkobnmlohkyqonwlfvgnwypcagjxmieiptkpbpmmmxawndpopcifqompvvpbvbqptfiytljycoyddxdixxihpnglxhvvdesrbltmupyhadllruijxrhbhvvqkvdsawnlnautowdjrvbbewblhhdddvjbifrgeupmlegszjtcfhpugqjxccsagqthgzenelpyddnabirigpeezhmlkcdduemuxhpcxutdrgnnjrbmnnmrihzlnflhbbmmqzkqxbdcuzgzmxlrfrzsjgenqvocoqmwzptlhlfaxlvswgwpcjxgydvjglwwkggryylububfstlzmrurovptnlzfnejlzjmfqofsvcttlvmbxkedkiuhqypkesiehtogjilxyqmbvnklznjrhoudtifmqkcqxdczcrljvnyydqapkitvbdmkfczutperyyulyjysqxgopzndmpolrcrgpuqhhdkxiulqxklbxrnfxvlkcyvxnmvfvsvnkewbfdlibhsvexdmshniboxshbecpqaszepqakuasopodnmwdgjgjxiaqveoyinglynyuqtbrrznwtedmdllhuyjnpmtgypuqvtipfbzrmnhelycpemxelaawgtfullzzfaknxguiztynzprvptoqsjgtyxjlezcsveejpbndktmzylswpudzvnhyrhutxvfpndhiiscnweffmtmlbhlbesmpczycmacezcikmzlchvqchoufnearrvzaqvpzqpirdlovbiyqskyakwuqbrqqvkazlxcypgbchuxkahdyednsizgmgopyifvjubcoiruyvzbcsgwujreszalqruqyjkkllzlyyqnjmcmjfmyqdjucmnungxmrdndpmobzrdizwnxxnxisvpnxdifnjfelgszsaexwdyxdxhhxtlsotnhsglwgzdigsqkgwkcwrpwmyywiovoijggkcwdxnkeofgebqawygfzumtwkgkbjzkliilevnqnciigyoghqcffijfwlrgkfjcdhzdzepbldigxcswicxhknqizaugrxdrgivuagyihvxvzrousfcuxiogfiousiydbtqlmeceeharrbwudxritqzstxnecymodbosodwdswefextvvpengersvlysbdsjokysgtjqpedqwmlfzanyywwhrhpcoyxleebupobjmzvutwcpxqeehrpsukcmidrsbghbrbayxugtzgfrszthevfcfootpwyqmxjicofmxdlcbinvzcpvwrkwdvgbdtdcwrnkpoxanohoockxcszbshxxtgcktskbrzztfaaqyfkzgnizjjzsytbokkmtshmxupamanksboprgaavhrnwchnnfztpcxygyhnumasehvltydluzuwldfummjsgzqppjqhfyijulxuyssxorjwgnnfksxtbavmhbpztbgnitkyktcxtzlwyzmafbgqkkfaimpwobkovbdglygpumhtfgwsstaofjgxgbynzwmfnygauoifavddtcdjoznsypkeuhqgjfrjqivktnqulinindwcnyosfbkalupovzqshekumvklgpwxcdktlgsakdqphtxuwkhzpuszktgknwamowypylenaektayekbdsgzyjybizvvluyhqmcynpysfwrchxcvdnsrhujzxjvurrfcspxdclvlmngmovvogjffvowhskuyijqxzcamudavyklhhilvpadlxeueteiwtnbrgygezgplfubxhwulzbtraupiwigkioevhjctduelesoqizfiaoovyklveztwbalncjiljsqrjkptfcnmjvshdutsvpjglwwxqxykqynqucudjaolgtocqqutelaarmlahkphqiotahraswskpnxromaybwxcpmjxgmkdwiecuqauaaawxmvivopnmuernrowqrjisqtfirhcxudpzemghxysxtzxsylnzukfmmpgoauzqpxmuzhxxkitmhokzbinhbxbqjfrzgkpmlaejpgblbzdbfpjiuvvlomcclwoiozesxlzfztzqwugxmszdgimbnxuqxksbgrzicsplmcwhsrpcawgqwjxqiwmlznnallesiswhyfumouhdyevnzcdptsyrjjryhkcltipmwutneckifszglcrlpaqvnnriucchbelsoqiefgywwhginumjgztcisgjqrqlywhflksqgjklossloltnpnbgvbvhbpuatfshhqacsplgwtduljpgszmznnhhahqyhljwtdwhozomfkbhiaawbnbhvsfrdhhzjcfsemujnogglercthwsurvbdxnpunfqiuzvytoolsbbkyuyovjftnwwuqrjksnbofwatauobjcwtnmrtmavzxcaejgmdldysahlkstqkglhjbjijespejwndkvgksbdosmtkobnmlohkyqonwlfvgnwypcagjxmieiptkpbpmmmxawndpopcifqompvvpbvbqptfiytljycoyddxdixxihpnglxhvvdesrbltmupyhadllruijxrhbhvvqkvdsawnlnautowdjrvbbewblhhdddvjbifrgeupmlegszjtcfhpugqjxccsagqthgzenelpyddnabirigpeezhmlkcdduemuxhpcxutdrgnnjrbmnnmrihzlnflhbbmmqzkqxbdcuzgzmxlrfrzsjgenqvocoqmwzptlhlfaxlvswgwpcjxgydvjglwwkggryylububfstlzmrurovptnlzfnejlzjmfqofsvcttlvmbxkedkiuhqypkesiehtogjilxyqmbvnklznjrhoudtifmqkcqxdczcrljvnyydqapkitvbdmkfczutperyyulyjysqxgopzndmpolrcrgpuqhhdkxiulqxklbxrnfxvlkcyvxnmvfvsvnkewbfdlibhsvexdmshniboxshbecpqaszepqakuasopodnmwdgjgjxiaqveoyinglynyuqtbrrznwtedmdllhuyjnpmtgypuqvtipfbzrmnhelycpemxelaawgtfullzzfaknxguiztynzprvptoqsjgtyxjlezcsveejpbndktmzylswpudzvnhyrhutxvfpndhiiscnweffmtmlbhlbesmpczycmacezcikmzlchvqchoufnearrvzaqvpzqpirdlovbiyqskyakwuqbrqqvkazlxcypgbchuxkahdyednsizgmgopyifvjubcoiruyvzbcsgwujreszalqruqyjkkllzlyyqnjmcmjfmyqdjucmnungxmrdndpmobzrdizwnxxnxisvpnxdifnjfelgszsaexwdyxdxhhxtlsotnhsglwgzdigsqkgwkcwrpwmyywiovoijggkcwdxnkeofgebqawygfzumtwkgkbjzkliilevnqnciigyoghqcffijfwlrgkfjcdhzdzepbldigxcswicxhknqizaugrxdrgivuagyihvxvzrousfcuxiogfiousiydbtqlmeceeharrbwudxritqzstxnecymodbosodwdswefextvvpengersvlysbdsjokysgtjqpedqwmlfzanyywwhrhpcoyxleebupobjmzvutwcpxqeehrpsukcmidrsbghbrbayxugtzgfrszthevfcfootpwyqmxjicofmxdlcbinvzcpvwrkwdvgbdtdcwrnkpoxanohoockxcszbshxxtgcktskbrzztfaaqyfkzgnizjjzsytbokkmtshmxupamanksboprgaavhrnwchnnfztpcxygyhnumasehvltydluzuwldfummjsgzqppjqhfyijulxuyssxorjwgnnfksxtbavmhbpztbgnitkyktcxtzlwyzmafbgqkkfaimpwobkovbdglygpumhtfgwsstaofjgxgbynzwmfnygauoifavddtcdjoznsypkeuhqgjfrjqivktnqulinindwcnyosfbkalupovzqshekumvklgpwxcdktlgsakdqpkgivxqouslzldcgrtmsulqbzjmwzwpkldvaqkpybewzsttkbfzyqxqiviljitmpsggjnrlvjilexzhgywitluiiqdolsubhznwlianophkrukernctgeykqhapkdwoppuckavwgcfjcrunzhphwrouihdoquevypmqxxgexsegtzkrzkawfklkknlkhdroytydigprojttlsbyyoghgcdtpuakgssxbdcbl\n",
"output": "1845\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4754\nxggoelylpwagmuepcbswnzknrqwhxuuhvwqqesvxpdjgmfmetbmkdqfpybcbucurqzbwplnclefctpbpelfqeltrgfijxmdaomuysbrlnfrezuxuakdsyvmmehbmpefgpxyywloezjlwvvfbrzxtjkcwrzuhiseieylyhtclfwbrsvepdqakaemzrjtsteiqcbzhrojzlxlpomwjglgfoljselshoukmzundmkmuaxznfjdtzlpgrodafznlpfvehpsurtefqcfqgcwlnjqubanbdrczykhgbzstlmjpxkueplauqlknfsimuojwfvxeiowraqdwoiotcuvvhjhocuamsmcfyuulqdkohfjyamstxdhtfizesixrvvoxwsibzkwvhdsqzaapaklpczxlvzplsqybzsnvcngaqdutfcqwtguieenjalziumgpfigqqowbwaddjqqwvxmjnrrhydcpgtihfezwfbcgueweuyqmbdaeuhrchtcregvwulivlglvynjjspedzlokaztolvooqhcnkhvapqlowctdwivbroyhnfznzrebpylekzebojyoeypgibnquqfpwhyeohwkhqamooxkmmbfwvtykctqeyuxgwwvutgxzwslokfldpvxcjlmjutycgtuvxiimagmeoudwnosmgabdvxzuvrbnymgxctjacedsyydkmzjevoedibbtshvxgunuzraewzgpumweitvzeaihadmykbtqsiebhijdnhowevwfxmyhzbeeihphrdqlgcufbbfadkjrkizxxwpvzbmemcrshsafludqzvxjctsqntomrwdwmzsnedudhehsbsgvrmlidznxnwipowwqfhrpbqqntawgkanwagbsysseiyjnowmlcrgxcpyqhspatuoptkegnryvpstwlikipzmgdrzqnowtvlsywcsimfifhwlzswmosxtkylxcbmzbirofjwucdwdqesqizugtxjpculcltkuozessdipbgwvnoxexxzopweqpinlnukdhzjmojqvuytyxwglwffgtiupjumfiqnjyodutboeppucofpozixknbnbcqbupwlclgwasnjfgwayyjzegtinkqscbhgcpptxankkncazuspdmzevczolxvmwmmrgkldgbguhaffiqdkhyvczhdjlwcdolmtyxezxweblnkmobpxhrzknnbwehwybksyhwvfoyzhoqxyykgyeefvwtthmvidfzpfotnrfmsadjplgazdymjvyumcjhtalqytajerkgtfttpysctwzwxudwjbabzurydkoryeoocxsmhyqwetnxylmqikzrmsphbgrkjwjxiiodjnmrnjreehqqbnwgstfwwgwjuqabahieodchbcohziforhrzgcfxcfxxqiljtajzxtlkoiokwifiyeexjybkyxevqqvufhhukpsnssymuwbqvvzvhmqfjqunuujyidqrnmfjmlqttjeahthqpeyelzaouwcdmhliznswmnworvgxqqkjedjluxcwnshegtvuhzgcwhuelsphoqxucrsfdaqdvbrujruzzbpqeaktyfwgatlnlkqqzwtwjdgjrmttdowvqlihgpupjkutbvhrukckcxxrbzglcnetotrtswjfbeyhbbghmltlwjlzrhjkbozwdbtpwejcasudgzbzhdykzftjgspiofhgebbuoikkdwwqwwcxxcezacaecnupejcpwfcetdbhhzjyxevjaztrywoiixvkhkuejmtvqzdqembaziyqordbtvmqzszutamtpgtyjfcwzthzphrdgaaeyveziwgjmngwkaynnqgdxqibcrbqtwzxhssfpujcxyuvkhkqleywwvkqkbzpzktyspiqejscuyjquxvobrzshsrwovangeullnciahlfnqwdthqmfgjdddccefmnguotuwksyuqxwszdrpuicutrmrnxogxvsoamnrlxijftzagwyfscctvfyugfzztlrkvnxgltotoqodyrpfonkpjapxtfiwxqkwfeoxrchkuoilsepzcildmwecwtjterftwyduidwwntpnelypbzhwjzkxxjemwagmdkkzkfzapowkumbolecgdlpihhchipqbnnvmxyoxfgiexbcexthtndonrvgkdbtcautsgnadubdrucphrkbyuuqkdtiehdsoqynrxuosydplneqyjpoybhxabuenkpcbmhmahtsnyjdfkhpcvfetwuzbsgityblejosfjjwvwqlsegyjzyoxmxkumbkdgevetixqojtiiuxdupoedorntrzkmueapljrnpdznwaiyrtqmmzfqcpkvkvrjalcbwajxftahwnawchdwrxssdiubtaftplxxdqdbzaxjropmdjbpatuidbjanfaummomzneulajnvkzfcgocbaivadewgdntndmehmmffuibxugrjkpbvozhbiugowhtktrbvblkpguowohiqixqsmnsjarmqcaszedjngqbpueswertflsobkkqcwrwijnykwnfynhnjmvwtrwnbhmsqisgqgxllergzsaoxwaliglnecjerimahpwlstzgaowxvnieetbdcmnvkvmzjkescozbpooxavybgbootvmludqqzajcneknfjnlfyviowbeqawmrjpuzvepeuvhwvagcsrgeyutfqizkzyovzzdlizenktqhoujkrjkvrzcspggtjfiztzuutrpcyxhezembydjpuldvlwhvouwdizvstxqiarchgbamraiqxjdascafbsukyfniqqrmpisvgnxznpbpsgwwzyxiegbtugntxoalitpgpfggcvioovgnjpoobjpyhyuhtkuabyvxyogjwwnrshmqyporxsdzjqtfmohkgjzpocnmciixkrdaznadpvnrujvukqmkcngcxjfjrhnpgxzplvwndrnxfblsnyqagxgkhuzlpcpdvrklgfwwjgnlisxvaoxzuzocyjiwtuyfcejxodpckyhxodeuycjzsbwldsqttxpsvhfhrnzengpewhqxjpjwfciffhlqdlotkgiwyjxsavunnediifhhapyuzgwlsxlswdjzkmainpkyqakzxfdrtocrrxkalwkzljqvncslaauhmkkierbewbmdvbhfhibdubdvmwnajfgleqrdlrnnghxgqiaoniybiltssergzbzhdykzftjgspiofhgebbuoikkdwwqwwcxxcezacaecnupejcpwfcetdbhhzjyxevjaztrywoiixvkhkuejmtvqzdqembaziyqordbtvmqzszutamtpgtyjfcwzthzphrdgaaeyveziwgjmngwkaynnqgdxqibcrbqtwzxhssfpujcxyuvkhkqleywwvkqkbzpzktyspiqejscuyjquxvobrzshsrwovangeullnciahlfnqwdthqmfgjdddccefmnguotuwksyuqxwszdrpuicutrmrnxogxvsoamnrlxijftzagwyfscctvfyugfzztlrkvnxgltotoqodyrpfonkpjapxtfiwxqkwfeoxrchkuoilsepzcildmwecwtjterftwyduidwwntpnelypbzhwjzkxxjemwagmdkkzkfzapowkumbolecgdlpihhchipqbnnvmxyoxfgiexbcexthtndonrvgkdbtcautsgnadubdrucphrkbyuuqkdtiehdsoqynrxuosydplneqyjpoybhxabuenkpcbmhmahtsnyjdfkhpcvfetwuzbsgityblejosfjjwvwqlsegyjzyoxmxkumbkdgevetixqojtiiuxdupoedorntrzkmueapljrnpdznwaiyrtqmmzfqcpkvkvrjalcbwajxftahwnawchdwrxssdiubtaftplxxdqdbzaxjropmdjbpatuidbjanfaummomzneulajnvkzfcgocbaivadewgdntndmehmmffuibxugrjkpbvozhbiugowhtktrbvblkpguowohiqixqsmnsjarmqcaszedjngqbpueswertflsobkkqcwrwijnykwnfynhnjmvwtrwnbhmsqisgqgxllergzsaoxwaliglnecjerimahpwlstzgaowxvnieetbdcmnvkvmzjkescozbpooxavybgbootvmludqqzajcneknfjnlfyviowbeqawmrjpuzvepeuvhwvagcsrgeyutfqizkzyovzzdlizenktqhoujkrjkvrzcspggtjfiztzuutrpcyxhezembydjpuldvlwhvouwdizvstxqiarchgbamraiqxjdascafbsukyfniqqrmpisvgnxznpbpsgwwzyxiegbtugntxoalitpgpfggcvioovgnjpoobjpyhyuhtkuabyvxyogjwwnrshmqyporxsdzjqtfmohkgjzpocnmciixkrdaznadpvnrujvukqmkcngcxjfjrhnpgxzplvwndrnxfblsnyqagxgkhuzlpcpdvrklgfwwjgnlisxvaoxzuzocyjiwtuyfcejxodpckyhxodeuycjzsbwldsqttxpsvhfhrnzengpewhqxjpjwfciffhlqdlotkgiwyjxsavunnediifhhapyuzgwlsxlswdjzkmainpkyqakzxfdrtocrrxkalwkzljqvncslaauhmkkierbewbmdvbhfhibdubdvmwnajfgleqrdlrnnghxgqi\n",
"output": "1522\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4763\ncoyqlqfbmlfdxipiqrhjowqlbhkqfysgtnhwqqjukzptnvizfseyhvicjfsnlqqbyfxbqrxwpmfjonpkwfnrnaqokvsunenkpuyfuahclsvgbeznzebvigppdvktjjslmtjoxxblyhfdfcaugpsqojmijaekfnrgntltwmgjoejnquqoxabmbxtxwoqkfaozwcqxccykqmnzuhotdrzwsfsuwanqmihehagoslgzvrnekffhqjaawgvjcpeoiykslyaregxvnfimzwtrrqmvfgwyhfpckvbfmfxyyjnshrcmfhegfntymynvzaqjdthsappxdzsshkrxijfiacqubkplslcgrvcoymgbafxefcchvsljkhrfblnrnesxpzmwxupwulmkripaqnqxotlnptwdlnpgsfipgsulzppkgihvdtrixbmeammhtsbgdubqjhtacmoiedbuqngvnpjoiccoxuslgafgmpnbefogmrmkhuolkzpbsvgjmvbqncrwzcvzhzkdcouzictpoduybnsbqrpekgmltogiwilgmfacrrdxaykthxdmqcijklmrxiuuqtuhvpjscinudjcwmccmxxwshyjftfpknaemmdpnvgiwhkzndjmblhkrdnfwdrxrdpsikfennzkbnxrchudmuohazydqezdpdrovizskpwjyidyfallmzwpispyflcmbtpicliwjtfsustdjijadimkyumaeaksdzdnceivvhuonpfudkktsofhyyridnlnrrdodnmhdaxvhbpbpnlfskvvsskrlnbkonebzbvzzqarvlsarniaztlgjewzxvvkbnpwpityvytjgqxtkzfbtajicwwwmxkdlqqeeskighposumsubqekmlgzwgprtiqyarekkxbqdmwculmojxblgwzkugynqmvyknypnkxmsooskxjnygmpmpbsnfvhzfgxddqwhivefgyksieznyfkwngcdiafidjktefiyeyqznexuricsxebhxtawplltmakkjzpdvmsgzjgqdllncuglkpuvoeqpwbnezdjfgkucjylcsxxtizfnjotbcwkvehlklipagfeoqpgpwlyrfwuoseqqvhcthuhxdkmhgdznuoutaeqhrpliqyxjswzzbeufqfwgocnjnwovleanyuydlfeyuqtiruuvswfpqyvitwvpxhyclwenvzcfnbuomhwwfygtzklxnvefoqsppsvrhywobvkeknouolittxbweyaxhfikbjsuufoppfkjvzkhclbovdtdkqyhxowzndjzapgkopfdftifrjrqixxykywjwxorjwkkawpiuvqozborzurhyeddsinacclziombysolzvvdackyrmubxcgikjlkwzeqqcylcmdjilwdmvvxuvulktuapduglftfwxdeprwbwrmoqozigubeztawyyxunlinelpdetbovoxivzkxrasqypleqtbmcbsthtynhmmofiwmnspnsjfxnsdyfpaijtxhsfgeuphajasxqzbskjjysswhfiymtcexajkulxoitbrxwmijldpazgedcygaakgwextwswykfjrukqfivrbntvqbxkljymlpfzxehmishmsbrzmbnizabjrkdxrnwtdwxttwfmugppzxhfxiojhfrsxiqjfqpfvapqqsoryixyjchhelmedklmvhfaxldugpkmxwmbbbmrjawalwchdcceiusjnnwdcreutgkakjpkraqgwqgyliilqkphiixoldbupvnvbeejbfvcsfqvueoxbfieljrsgggkdnhjlphuqhdkzcfuhcnjjtjbgjeqlcnpcjniulzweozgtaybumnqvfmszyqjixuceuraeybtmlqfdhhhroqosnihwsmwzubggedkqrvgjxoscforpcjfsqltxptgcwmjaxgfrkrqjkoqescxxvobylldaatmzfvdcotxjxqnsinpunmnljbfrlxbwqqstdhwicamskwhymxriresjaesnpmxblxuhbknqvfvpvysgjameasnmtvlgmegjqfrvoxdinevvexpbnephfialtsyxhkntwchbmxmhifqewnlywybkjqpoagpioivyzchcpittpkyabedvjlwigarlwvprfabuvccwmqygxiwcxfnsdtwboohvkicwpugzqlykqplnrtxtvxzkadwrsdhrhcztfkdynbnrdssrftdryaevaypyiqpdvfewboawxyapxencrxayiaacmszbozgvhjncvbodmtgelhunkydhkwmslhrjgjuwdhivgnnnzrtxwmwbwylxuvxblzheieqadkbcgclnfcldacbsqfuoghxrcldsuevogwqrezxuwkzggfryruougqssfwhwfitdntusffksscpqyvrhvieccisdnvbmpxtvtntjemkdaomtakowetxrfblnrnesxpzmwxupwulmkripaqnqxotlnptwdlnpgsfipgsulzppkgihvdtrixbmeammhtsbgdubqjhtacmoiedbuqngvnpjoiccoxuslgafgmpnbefogmrmkhuolkzpbsvgjmvbqncrwzcvzhzkdcouzictpoduybnsbqrpekgmltogiwilgmfacrrdxaykthxdmqcijklmrxiuuqtuhvpjscinudjcwmccmxxwshyjftfpknaemmdpnvgiwhkzndjmblhkrdnfwdrxrdpsikfennzkbnxrchudmuohazydqezdpdrovizskpwjyidyfallmzwpispyflcmbtpicliwjtfsustdjijadimkyumaeaksdzdnceivvhuonpfudkktsofhyyridnlnrrdodnmhdaxvhbpbpnlfskvvsskrlnbkonebzbvzzqarvlsarniaztlgjewzxvvkbnpwpityvytjgqxtkzfbtajicwwwmxkdlqqeeskighposumsubqekmlgzwgprtiqyarekkxbqdmwculmojxblgwzkugynqmvyknypnkxmsooskxjnygmpmpbsnfvhzfgxddqwhivefgyksieznyfkwngcdiafidjktefiyeyqznexuricsxebhxtawplltmakkjzpdvmsgzjgqdllncuglkpuvoeqpwbnezdjfgkucjylcsxxtizfnjotbcwkvehlklipagfeoqpgpwlyrfwuoseqqvhcthuhxdkmhgdznuoutaeqhrpliqyxjswzzbeufqfwgocnjnwovleanyuydlfeyuqtiruuvswfpqyvitwvpxhyclwenvzcfnbuomhwwfygtzklxnvefoqsppsvrhywobvkeknouolittxbweyaxhfikbjsuufoppfkjvzkhclbovdtdkqyhxowzndjzapgkopfdftifrjrqixxykywjwxorjwkkawpiuvqozborzurhyeddsinacclziombysolzvvdackyrmubxcgikjlkwzeqqcylcmdjilwdmvvxuvulktuapduglftfwxdeprwbwrmoqozigubeztawyyxunlinelpdetbovoxivzkxrasqypleqtbmcbsthtynhmmofiwmnspnsjfxnsdyfpaijtxhsfgeuphajasxqzbskjjysswhfiymtcexajkulxoitbrxwmijldpazgedcygaakgwextwswykfjrukqfivrbntvqbxkljymlpfzxehmishmsbrzmbnizabjrkdxrnwtdwxttwfmugppzxhfxiojhfrsxiqjfqpfvapqqsoryixyjchhelmedklmvhfaxldugpkmxwmbbbmrjawalwchdcceiusjnnwdcreutgkakjpkraqgwqgyliilqkphiixoldbupvnvbeejbfvcsfqvueoxbfieljrsgggkdnhjlphuqhdkzcfuhcnjjtjbgjeqlcnpcjniulzweozgtaybumnqvfmszyqjixuceuraeybtmlqfdhhhroqosnihwsmwzubggedkqrvgjxoscforpcjfsqltxptgcwmjaxgfrkrqjkoqescxxvobylldaatmzfvdcotxjxqnsinpunmnljbfrlxbwqqstdhwicamskwhymxriresjaesnpmxblxuhbknqvfvpvysgjameasnmtvlgmegjqfrvoxdinevvexpbnephfialtsyxhkntwchbmxmhifqewnlywybkjqpoagpioivyzchcpittpkyabedvjlwigarlwvprfabuvccwmqygxiwcxfnsdtwboohvkicwpugzqlykqplnrtxtvxzkadwrsdhrhcztfkdynbnrdssrftdryaevaypyiqpdvfewboawxyapxencrxayiaacmszbozgvhjncvbodmtgelhunkydhkwmslhrjgjuwdhivgnnnzrtxwmwbwylxuvxblzheieqadkbcgclnfcldacbsqfuoghxrcldsuevogwqrezxuwkzggfryruougqssfwhwfitdntusffksscpqyvrhvavqxrgikihkxnhreofptvyrqeksifxaoiwqewawiavpveqkkgbqwjokstiupbugnrdrxuknqrjkvhowdxorrquxzebbmqgrqbqhwcqpyorxytwwhahewwgyurmtxcthuwysplqbgbywheznhaliccabrtqsgayykowtkhkagkqifhjdqjkpyuxmsjavoprnqmjlcwegkevfdwxjqxeeskjdofjnwqcdshuqblylgtyvcdbjerskyqchzp\n",
"output": "2055\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4970\nuognfalfhmkbguspimjkkucnzepivptsoqvfkkesxakijgmcxtjejjnfobfgumgmherhfgotzspmlgjqkxhuntkvdyjlkqernjyqzunawwhpqbfkkbefqudeekxlnimtulxlgiixzyiybdechwwjberghvyudatzprbmixycdmboluzitigsoeplnfkxhqnhfjmdlvtmjflnuvcybxfgqrjgzbkcewbtkpeeerrhgtqvhlaykjqyqxrscynkocrtngkbswsqbysfruqokdcdxjchimhkbyjxtxpohunwutiyoeznrkonqllrntitknoniaxzxxblpjtigkmwejghkpcxngzeiznyojudtyvdfsfezrqleqflgbrmlxiehjdmqlfjqatyrlwiedowbjvxetbomdhlthufelavmvtbrznmauiwhntxcvfvmrmqvrsialynunkxdcnzpfytxmltlwrgykhyqwhwclkmklomkisamtnosthdtyteyjarudejikzbezurqltntwlymcugzpafstohnleailsszbezmeoiyajpfqhemohpdhxbmitpfjefwjmufajmfquviavaemhvspeeawxojpirtjeadhvaslatstuedhfokroklftpyhlstirhgaeilztfbqqmxccfuokjmesqnrdmilqytvzvegrueimwfkivebxcsimbftdurqqhomkycjqhfbjwpsxkyamsskvlwullhceifxlawfqacqgmbufjrnpuhowqasndhudegrkxhcjthkosdprshmkgaxcvyfrojxdlzefltrthtnxvvsxzzvxgjnvyegrhfxwcbahewrdhdjtzvhbfdrmpcyzfgmslmajitkwjkeofbatzlarzlglwijpeczeypszjvtzpgymtnflwmgpcqxfjuxbnadtwfuondfrshxloqlkwqujdhrdcraaqizqgftshykmxtoqbjkdjgwiplaxaakbmthufcfahknqelaocgrawjsadmmkrgwfpdqznjtxyglctbwvfbijtxlsxifouibfazfiwaifrnwiuzsqzntkcgkmmvwrawpwrfhptwwqplygpdodbjzrxdlssisytcnnqrjydrxjzwwuaxnahtdyimwutatchfdyfrulgvltqljimfvivvwtvzaestorfmxbwxnanbrwbdzcbonsiewpnuagejadkbghlvuxcuemawsrnsgptdtpolwdvxvvsodqjqlnfmqexczjzeeacwnvxckrgqlevqbhierubfcpzojnsqpibvrzhgpjzgvwwwzbrqbwzgtvksuaqeswxvgmozszuixrwocsdsnmfofadigwmidovfojmodtaadqzwpwakxxrrevdogtpimfppawbyitearebrukywcrgsebycrdzettrpmfgziljuzzdgqelgevlxsycmzxmrsokschunszhkxtinlxoywalsrocfjuqtpftdlaohomwuklsersujdevwngbctsgotjgpgnojwkshqejqrobtzbmofxjjhgdbuuhfelypngwzwwgeacorijxqdrouujppzdhurelnmypyimfauvqcxbkgfcxktlzwrmvjjqnbdgvzvipmvutmtuievheboevdudvkecjpkkwzkcbpannzkczmlpxerhrzybhpvjwesqlaspfhkwyhasbahswcfctsklqjppssgojjcknltexbkwdbiqbdhfrkhfxlmcxegviaxjjsufjueiargigjlwtxrxuxprdtybfhxmrqnwwgjjmcmfkbnjsewjbhuvfrfbkynefrkwhmuelruvpmcsyyynzorqsszdllcsbuilrtucmfagomvetvgxfnbsdbbnykgyoyufkduxkisxgnmdooryvwzuuwmtdytwtzbfuonrvautjchaedmifimmxjojczlairadduimfmoezdjsjqlvylymhqpxmntqbvmbwavnjvjmjynrszaqrjjgixkwrrumrssnwbofavleirffcmokobfkhykmjuppzqmnfzqcowdvuqdqnzvprozszmlsjkefjvrtmfadcphhxjdjhbgwjyarsnfaykxexursugssixvamjvzsssvxpgigcjykslxaeodhyofcgbhhrfxfvlwfwatlqowuuaptphmbbhsxbrdopxpvkxulmeganoaqhvikxfjcadzustatbkdqzviutqwezjgmwmwrvwfhlvwrjckiqtgvsjitjzypdmxlatkjcygxquyqlsghqcaibfuajgsibsnalezsqgtavglyzxflawcfgbsbkukupxvhrppxzzpfshfifcndxdmmmnszmtlpprbuqcslwfihxezvdgsthxedpfenfrjjbjxppqzconesjiuutjnbgxgavcvxaszttqlsbzrspxaywjgajwrgnsyotmttolorquxritvqulypijmwvzpxzizeamsrgylwjrlwsehlgnjeguxpdenkqgskdyxzjarxphdesllmhxawrmtgxuclafffmmqaysaihxelundimabmdreudapltykuysnapctflgmqqwndrtvnjusijyaazfisdjyidrfzpbfmqgfvmugxfeivtjlmpmyrmfpehgcunuefoaupqleezjenlvsmxtiptgdadntztfjtutgamhqhvrxamqtltqcvubkvvuarzhfucxocaurjnncgrtopfppznnrssqhiiabbhjlbmztcnvymghcmbdgrkipklwnsmrbfxttqdjkuetuhwitdffvzdrincylselfeotsuzejlcfzpdgizgjmpjfaxlqgdbgqtpgyzlyzampezverecbevkusezlwjrkltrlajaociqjfbdtgmaaemzcythcdgulaymrhxyplcgewpejjkdygowrojdtddcwjscwiortceyqcjcjchjsgqtguuzglzqiwncevuwenuwkortpzdujqtluuggciclodmnxstwfhfimezwfdmdjgdbxgspsigwsychuuahzxjlkokgokrrwmupyhlstirhgaeilztfbqqmxccfuokjmesqnrdmilqytvzvegrueimwfkivebxcsimbftdurqqhomkycjqhfbjwpsxkyamsskvlwullhceifxlawfqacqgmbufjrnpuhowqasndhudegrkxhcjthkosdprshmkgaxcvyfrojxdlzefltrthtnxvvsxzzvxgjnvyegrhfxwcbahewrdhdjtzvhbfdrmpcyzfgmslmajitkwjkeofbatzlarzlglwijpeczeypszjvtzpgymtnflwmgpcqxfjuxbnadtwfuondfrshxloqlkwqujdhrdcraaqizqgftshykmxtoqbjkdjgwiplaxaakbmthufcfahknqelaocgrawjsadmmkrgwfpdqznjtxyglctbwvfbijtxlsxifouibfazfiwaifrnwiuzsqzntkcgkmmvwrawpwrfhptwwqplygpdodbjzrxdlssisytcnnqrjydrxjzwwuaxnahtdyimwutatchfdyfrulgvltqljimfvivvwtvzaestorfmxbwxnanbrwbdzcbonsiewpnuagejadkbghlvuxcuemawsrnsgptdtpolwdvxvvsodqjqlnfmqexczjzeeacwnvxckrgqlevqbhierubfcpzojnsqpibvrzhgpjzgvwwwzbrqbwzgtvksuaqeswxvgmozszuixrwocsdsnmfofadigwmidovfojmodtaadqzwpwakxxrrevdogtpimfppawbyitearebrukywcrgsebycrdzettrpmfgziljuzzdgqelgevlxsycmzxmrsokschunszhkxtinlxoywalsrocfjuqtpftdlaohomwuklsersujdevwngbctsgotjgpgnojwkshqejqrobtzbmofxjjhgdbuuhfelypngwzwwgeacorijxqdrouujppzdhurelnmypyimfauvqcxbkgfcxktlzwrmvjjqnbdgvzvipmvutmtuievheboevdudvkecjpkkwzkcbpannzkczmlpxerhrzybhpvjwesqlaspfhkwyhasbahswcfctsklqjppssgojjcknltexbkwdbiqbdhfrkhfxlmcxegviaxjjsufjueiargigjlwtxrxuxprdtybfhxmrqnwwgjjmcmfkbnjsewjbhuvfrfbkynefrkwhmuelruvpmcsyyynzorqsszdllcsbuilrtucmfagomvetvgxfnbsdbbnykgyoyufkduxkisxgnmdooryvwzuuwmtdytwtzbfuonrvautjchaedmifimmxjojczlairadduimfmoezdjsjqlvylymhqpxmntqbvmbwavnjvjmjynrszaqrjjgixkwrrumrssnwbofavleirffcmokobfkhykmjuppzqmnfzqcowdvuqdqnzvprozszmlsjkefjvrtmfadcphhxjdjhbgwjyarsnfaykxexursugssixvamjvzsssvxpgigcjykslxaeodhyofcgbhhrfxfvlwfwatlqowuuaptphmbbhsxbrdopxpvkxulmeganoaqhvikxfjcadzustatbkdqzviutqwezjgmwmwrvwfhlvwrjckiqtgvsjitjzypdmxlatkjcygxquyqlsghqcaibfuajgsibsnalezsqgtavglyzxflawcfgbsbkukupxvhrppxzzpfshfifcndxdmmmnszmtlpprbuqcslwfihxezvdgsthxedpfenfrjjbjxppqzconesjiuutjnbgxgavcvxaszttqlsbzrspxaywjgajwrgnsyotmttolorquxrioyxbcgemlgpfturwnwpzrovchzkfmtemgdblxocsultkbbwhnutsvwjftgqmazberqrdztwbqxdcjvjikynopilkhnbksgkbnjad\n",
"output": "1818\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4608\npycnuolcfizryqckmngqrselxzgvgpsvebdrckeehxssxahxrqveqkvjmeouofsmqnjgnahxgxgzkanxgiulkawqycnkhyexbvifedkgluimvvqxgzuetslcnxldvzuawmdzpvjatjxxsxfbfafhruocuriobxpbsorkklyfqhfvbslbcitihlevylxrygkexpotxcbpsqaykzosvftcekjtljxmmwjbfkalcujdgbzlfjehwryigosmlyqahrivncuknrwyvmcfxydbfsigbuokejtmugafgxekrwscfxgsmuczwnlempnifvniycydqbivojedxjogngckzjwzwshtvhbcllkjvlagxpnyllnnptblviwgjlhfouutucaamimeyhxkxgwguxmcgjthrfwjtvhmzqtyxykbbsafaiemumjaindctciotcqhstaydpdonvvlpzeyunyxmcjkqezwspmeclttfivjddbhedauulvxdmwxiypfalzbkmqvecdkovgkzpmcigebnvowpfhfmdkouhigvruhujvarebxscpszgjwwtopwnnhgnwdvvmoxjohnkcfeevifcytnqxsibolviiwllztdopelypjybkqxckdvzuycssqirmqhwdjxgfspsehxttamiznnznwwikweqvknidekefdawwgnsqabsiopyrjsitgeboxaxoggrulxvvvlhfbdxrabfonvlpxxetwgsjkcvwramedkxgskhsvjmjyblqpuxkmwaszbwpmvggjiczcqpyurtdrdekivmacpxvlgqdwpvzijwshxfwapzautdubhuoalatramhpxpnukastehgtvzgvjjjfkvqeuzaoctgqbghwnwbianoxawoshihosiojrubkqgmuvlapydktlbjndejltuhgerfppiabzpdtwfebxizxkfikkrdqpgbuvkaxcofdpqezjyrcoryyrylajbkmsizbrrniuwabraqdwxqzfcfqgeghbrqzsrhhokikyuranjbabwsateyqywbuvwcswaffptmvazeybiyupftdoennixmplwpnsmxrtdkajmmolqvpldvcrytldfbtpfsensefckcucbfgvrcmphfbxkyhueihkopbenyixnefgamgvtumbqxkatzjkeslxeyswcxjswrregocmvehtysiyyytkqqpylspoxcednmdrmxyylbzplflmixtgnyndsplbiczdodjiotephabxhjaqqwxxnblrtagxmfpfdmrlozrobyuhrvoqrnlrlfpxgwttcyvtoytsdzptvzershphtxsciojwcmhbdgibppwraqhtbwlsrzbuvfwfohfvosznohjcygqicaeihigocokhddzqyqmtqcmigjslegnzdxbjumhgqbkldvgjkeuqygaeuqsndaxmbfadsufeldhfutegqpzneigpwnnzokshgjtehquydyiuohnrxphidcpogqdsuejmfgpbsyjlpmobkrnswvnswapnkjwjhbpsvtlzuszktyjjcnjdpuiwlpooibtwragqsurubiozuvfhwcnlokqyeofniddkvstuxdpwobaeddjzuiqmjvyywdvobqtfgkautloltpbiiqcvuatakejhneclpcppgbhfomjsywmivjaaajtotqxiqomxpzdtryddspooadetyooyhbrjvnifavcenjqgefbhcxrxwzpqrauqjoaxcjwsdqzhrjuwqyykqepidsikqwubnqdfitsitwzpusmcnigkionqqzcylwrldaeycazutfyaxoxynwbtstvxgqfwhcymdffajixirrbslkfupghcgidjmxxdllhjxphdfohoqxbdivurchbaqekimovjtseqtrvbkkaxfoiqkxjgajkfjgznzrtgpgztdcnxxmestggirqabnuinzkkbpgvlooawkczqrpfrnxkomkjwsdovhanyicbpnthpuxkeyevugedaawczwtagebzldzlicsrwqfkqixdsvvpalblytomyihxhdlzqxbyudlaaueeoauenejcxxifpnrtmefewzuuupepwppyafpprphevhwceiaxqbawttmsqyzzdbskaxshvidxaktkgniqreogxvexugasatxqbcvkdvximcvjpmpxsfgcwpulfyfnefligpzviebeofwbjzhqahcsxmeanbhprvmkljlyphhlzmfcbqnjlzcapsdpxfawpaouyylbbvtzvcdtjlmjyorciqwlujjikpgseqbtnwsptdsjfhtoyiweohrqeekexahjguanmmsyflqergmjzjunqxslxwvufjtnepmhaagmjbebnzfdfpxlbwqeerklyrwpuladajepqqvqxxfcovzhxhwhhbrsvpjvvodcdtyhhenxmeqebykgrjqxalywunhzwbnpfftncjqzvqvknibadeijxcmqnjkfbekmcakihgnxykdxirhnxkbasuphqzxbchnxrwmbcwlgdamtnukvoiurtquuxjgzwwdxqxnyvfukvmywbojlnrbrrnfbghhuixyxvltlabinxgijsjsokhgdmdwwecrgiwcrsnwxincxnggluaxijuybhutgxchkmawbjqpobezvlqecjbrozllsjmgmvbpmbvosowzxvopyaxuocknxvtmasohwnqxgmgjveokvnjcgabcmershnicnmprqaeetvcipvwfqkyjcyfaxdqhsdyxuolsvwhjwkdmlwmbqqmzgxgnzkldhuwlohfnfqdfwndoiowuolticjuvuyhpslkbbnozlsnvhghrdlwyumfwzqvnnfwptvvclsisioyeffwywnwnmslcuxfundoukbmoblrcewspmesrhxkpcyayypwwciymsvpipdzptvzershphtxsciojwcmhbdgibppwraqhtbwlsrzbuvfwfohfvosznohjcygqicaeihigocokhddzqyqmtqcmigjslegnzdxbjumhgqbkldvgjkeuqygaeuqsndaxmbfadsufeldhfutegqpzneigpwnnzokshgjtehquydyiuohnrxphidcpogqdsuejmfgpbsyjlpmobkrnswvnswapnkjwjhbpsvtlzuszktyjjcnjdpuiwlpooibtwragqsurubiozuvfhwcnlokqyeofniddkvstuxdpwobaeddjzuiqmjvyywdvobqtfgkautloltpbiiqcvuatakejhneclpcppgbhfomjsywmivjaaajtotqxiqomxpzdtryddspooadetyooyhbrjvnifavcenjqgefbhcxrxwzpqrauqjoaxcjwsdqzhrjuwqyykqepidsikqwubnqdfitsitwzpusmcnigkionqqzcylwrldaeycazutfyaxoxynwbtstvxgqfwhcymdffajixirrbslkfupghcgidjmxxdllhjxphdfohoqxbdivurchbaqekimovjtseqtrvbkkaxfoiqkxjgajkfjgznzrtgpgztdcnxxmestggirqabnuinzkkbpgvlooawkczqrpfrnxkomkjwsdovhanyicbpnthpuxkeyevugedaawczwtagebzldzlicsrwqfkqixdsvvpalblytomyihxhdlzqxbyudlaaueeoauenejcxxifpnrtmefewzuuupepwppyafpprphevhwceiaxqbawttmsqyzzdbskaxshvidxaktkgniqreogxvexugasatxqbcvkdvximcvjpmpxsfgcwpulfyfnefligpzviebeofwbjzhqahcsxmeanbhprvmkljlyphhlzmfcbqnjlzcapsdpxfawpaouyylbbvtzvcdtjlmjyorciqwlujjikpgseqbtnwsptdsjfhtoyiweohrqeekexahjguanmmsyflqergmjzjunqxslxwvufjtnepmhaagmjbebnzfdfpxlbwqeerklyrwpuladajepqqvqxxfcovzhxhwhhbrsvpjvvodcdtyhhenxmeqebykgrjqxalywunhzwbnpfftncjqzvqvknibadeijxcmqnjkfbekmcakihgnxykdxirhnxkbasuphqzxbchnxrwmbcwlgdamtnukvoiurtquuxjgzwwdxqxnyvfukvmywbojlnrbrrnfbghhuixyxvltlabinxgijsjsokhgdmdwwecrgiwcrsnwxincxnggluaxijuybhutgxchkmawbjqpobezvlqecjbrozllsjmgmvbpmbvosowzxvopyaxuocknxvtmasohwnqxgmgjveokvnjcgabcmershnicnmprqaeetvcipvwfqkyjcyfaxdqhsdyxuolsvwhjwkdmlwmbqqmzgxgnzkldhuwlohfnfqdfwndoiowuolticjuvuyhpslkbbnozlsnvhghrdlwyumfwzqvnnfwptvvclsisioyeffwywnwnmslcuxfundoukbmoblrcewspmesasuljrqkpgytqdriftqbpclawxilsfytdkimtpvmbhcdhawrwacytsyzrlvxrgsxkdjltjlgqkyvxkuhirsbblacyooiywa\n",
"output": "1589\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4835\nxjvwuhcuktbmicflzpcmttebagfzchfxsxkbnmzqesgjflzuqqqjyclntnrddtzrgonaqevvunqgstumyvtxxydoxjtzqtnkwtcbvtrvqxxaukixcinbosnnwqccufbsnipeuprutncydybmjssqqrqrhvugpikdcdotzcffjifdsyeidylainvspmjfdecknzckjpuhinqlcdkhqqfbgaybyfocqqgxiiueenmudshkvhnnioaclyywqzgibxbmirwnbqawnxkejvlvshcjlsvbfrhnfdhjmwcxjqzyibfaputgxeynuzmoolmhmciuudcrsgthuwzrvpmmndmfzdjbejtdfrdzksqsancfcpyuzxqdbiqqtfogqbwsszqjjzscnjjgxfblvhnuoimdqqfuuzwcjuzuwarqopfrpsqwphwqiuwfcmehqzqhnckrlkvoqlshtsjotmwfhgqjyjtmdqecvyztwxyandsqzeoxyafmfgldnmlhlcyiajoowiltayiutqbalacnfvwzppycvllrmfwmgxxmafjcoqavoafcgofyauupgoutnsjoycksfspvdysohoawmvkifdgciudltbmewxznthkpokzfhxqgackqfwdhxhsebbqtfmulqtjcpuciogifomjdupxvmuwawcxeodlsrbfrsprzxakgcqmbkxvgfrgvmorelvflrxohjgmlldowqmkieyfmakyeigaaaydvzpqwwbxmuzpkmijptbbupkiiqmbvqzmotxgoceqtowcsojlprtvrcmfbuktbuijvtltovspkelvhtsvaqobrbkovlepfupxgydrwpvxhvhkznhvqribrtwxpgihesqjjshahdyewfcbspmeqxtewkeuakenczrzzkknkwgzhinydfqdgwwiarwywtjavnyqryrelkfvexgzndextfmwtvmwnzwoexsiesimwbxgepnbqdwnampunklqimlgucxhnaqmcehifgssglogcleinqneadchpgochadrcortcwpwatbxuvexyianzdetpxpsbqnypndiqwwkdaowhxvyywjoxmyeiaonprzqiwlozqgprshhuvrsqdjpvtccnulwklgwkztlvqpjpgmzjvfjmousoyownpojopmmsixauedwfwcwcabvocoqspjdntnenynqcoycxuxlrumbixzaeuawzdttzldckwifsmerliwhaqmbvmbpqxpcyhztzcqimhmctqslmpcipswqsfhnekfsumekkqtvhldlmqtcnqcseclckpnkzxbltaeqmvqnalbgvwrbbhoqzrkqhlwxtknqqfnzcixmtwdgicqbcqkvhrrpnlisjcpbvvoyhgaeymgamajweqqlpounrdanxxnqibelfdrwpacgczjbvnaxuvoomodylalswqvyanqfqramirgxieqpfhafstlnjmhyakjhipkvllevgieqoybzpgsynosunxekgupgegjmjakplzaajvxizbkncfiqttuwcyidtkzpandxijmjmhctrbzcnwkpmtphdaizgtvrgamenigqifpcqoybdlhcelwawtvolkyeyhpkeyswtslloudghoepzxatjgejaiwhruyficgnlmaxbhcasxdeatrcmipxapksxxqychaebfxbkecflrowkxjqitnmnxlnlkkecbvutufwyouutpuujzlkibtiihzoviituzjtvwzhfniinfjfuuqeecksycavhbmfzlvrltwxzowpfuajqicqevpaniyiucrjvvcwddxhdabvhirmvykdvdpodbqghzosjcwbrzqluzktcnbudxswgevcgerzvxjokxhzengquhxqqktwczqdhzjwlydtyxufkhwqkttqysqswwcfjabkkgfwtlzzesfattatsxofgrubtjjlzvwikpgxfxuyvnwumulzanxkavuipdvpwiuawfffxbiwwzhvolfgsdmahecbinobpbtuwfqbbslkiophduwwyigxcnaunmlhkypyiqzamubuphuxfixzedwtxnllzkltjxsdlqxiknlmwpihjzxmwufpwwwyoxutawjoebcncwspfumwmhheddnuxcrbayirrqtznnlunewammlzsxtftvqmufqdskmqirsoglbrfjeoetbwvsfcjaetzyeteramiuegsguoethuwyqnigqgcpmuxywfbjqalcyccuodgrnnjgnqgboxqppwmxujezagghfwvemswakikkvndkcxjujjuamoccgcnprwkkvpzqqbqgsurqjgjodegblksscrafffagznufkpcycjfdblpmrhpmkmhvtgbyjmenuabgduoxcfgmspmdbsntdstzkhnttgrlcgnjquosbtccflzpcmttebagfzchfxsxkbnmzqesgjflzuqqqjyclntnrddtzrgonaqevvunqgstumyvtxxydoxjtzqtnkwtcbvtrvqxxaukixcinbosnnwqccufbsnipeuprutncydybmjssqqrqrhvugpikdcdotzcffjifdsyeidylainvspmjfdecknzckjpuhinqlcdkhqqfbgaybyfocqqgxiiueenmudshkvhnnioaclyywqzgibxbmirwnbqawnxkejvlvshcjlsvbfrhnfdhjmwcxjqzyibfaputgxeynuzmoolmhmciuudcrsgthuwzrvpmmndmfzdjbejtdfrdzksqsancfcpyuzxqdbiqqtfogqbwsszqjjzscnjjgxfblvhnuoimdqqfuuzwcjuzuwarqopfrpsqwphwqiuwfcmehqzqhnckrlkvoqlshtsjotmwfhgqjyjtmdqecvyztwxyandsqzeoxyafmfgldnmlhlcyiajoowiltayiutqbalacnfvwzppycvllrmfwmgxxmafjcoqavoafcgofyauupgoutnsjoycksfspvdysohoawmvkifdgciudltbmewxznthkpokzfhxqgackqfwdhxhsebbqtfmulqtjcpuciogifomjdupxvmuwawcxeodlsrbfrsprzxakgcqmbkxvgfrgvmorelvflrxohjgmlldowqmkieyfmakyeigaaaydvzpqwwbxmuzpkmijptbbupkiiqmbvqzmotxgoceqtowcsojlprtvrcmfbuktbuijvtltovspkelvhtsvaqobrbkovlepfupxgydrwpvxhvhkznhvqribrtwxpgihesqjjshahdyewfcbspmeqxtewkeuakenczrzzkknkwgzhinydfqdgwwiarwywtjavnyqryrelkfvexgzndextfmwtvmwnzwoexsiesimwbxgepnbqdwnampunklqimlgucxhnaqmcehifgssglogcleinqneadchpgochadrcortcwpwatbxuvexyianzdetpxpsbqnypndiqwwkdaowhxvyywjoxmyeiaonprzqiwlozqgprshhuvrsqdjpvtccnulwklgwkztlvqpjpgmzjvfjmousoyownpojopmmsixauedwfwcwcabvocoqspjdntnenynqcoycxuxlrumbixzaeuawzdttzldckwifsmerliwhaqmbvmbpqxpcyhztzcqimhmctqslmpcipswqsfhnekfsumekkqtvhldlmqtcnqcseclckpnkzxbltaeqmvqnalbgvwrbbhoqzrkqhlwxtknqqfnzcixmtwdgicqbcqkvhrrpnlisjcpbvvoyhgaeymgamajweqqlpounrdanxxnqibelfdrwpacgczjbvnaxuvoomodylalswqvyanqfqramirgxieqpfhafstlnjmhyakjhipkvllevgieqoybzpgsynosunxekgupgegjmjakplzaajvxizbkncfiqttuwcyidtkzpandxijmjmhctrbzcnwkpmtphdaizgtvrgamenigqifpcqoybdlhcelwawtvolkyeyhpkeyswtslloudghoepzxatjgejaiwhruyficgnlmaxbhcasxdeatrcmipxapksxxqychaebfxbkecflrowkxjqitnmnxlnlkkecbvutufwyouutpuujzlkibtiihzoviituzjtvwzhfniinfjfuuqeecksycavhbmfzlvrltwxzowpfuajqicqevpaniyiucrjvvcwddxhdabvhirmvykdvdpodbqghzosjcwbrzqluzktcnbudxswgevcgerzvxjokxhzengquhxqqktwczqdhzjwlydtyxufkhwqkttqysqswwcfjabkkgfwtlzzesfattatsxofgrubtjjlzvwikpgxfxuyvnwumulzanxkavuipdvpwiuawfffxbiwwzhvolfgsdmahecbinobpbtuwfqbbslkiophduwwyigxcnaunmlhkypyiqzamubuphuxfixzedwtxnllzkltjxsdlqxiknlmwpihjzxmwufpwwwyoxutawjoebcncwspfumwmhheddnuxcrbayirrqtznnlunewammlzsxtftvqmufqdskmqirsoglbrfjeoetbwvsfcjaetzyeteramiuegsguoethuwyqnigqgcpmuxywfbjqalcyccuodgrnnjgnqgboxqppwmxujezagghfwvemswakikkvndkcxjujjuamoccgcnprwkkvpzqqbqgsurqjgjodegblksscrafffagznufkpcycjfdblpmrhpmkmhvtgbyjmenuabgduoxcfgmspmdbsnvrhdeukepnefbexblnbweliwvgdxckonilzfzgvfoknhefcbqroeovlt\n",
"output": "2371\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4517\nyzfkgmcsyhucgybybrsormbzybeitonwkakwttmshytzejvfxtdpexxjpcefnibxmbisywubptxbhwnyqkhhaxezmwmiuwkncfaghpjxxvlkvirryxgmnvfsqgbgmhlswyckudxvszzehqxhicbnqxfwkfjqdfibgwocodniwytfahbgxdqngluouhnvkwntuumsyvtolvykwthuhlpazryjlxwmwdxqmgckavrbxhlykmvognpqvngmtlyxrorypqqjephwrvunfeypvlduglfkylpvjsnojqbvnzxuchletmntzzoxhsnylmbkzexdbqkeenbxdntosbuggcidpcsidjtwmgxlcilvicmhoathyzxfcpxgnopjqnoqoolketajwiahbwlhwpxdwinjtrbznomfdndadvqqdnhwvgvtxyeerfbklfedqkgpkeienzdryaukihefdslphhqgseghbxhqlkitfjijtscpxbrlfnzmsrcuupydjqntjctwutafzhdcfuspjdchjxcxqefxtcidnxmzqvvuybkcgdrdpdehrhscldphcdlihqgkytrrgnotcdozjsdnouicxmkzmegyhnlwvznykqrnoyxaxeuuwzhggttojhvazolndykahmjbxqeahoqimuwuqwfcxielxejkagcxndawfyhmasurrfkkquakjelxfygmemjwmwnsiullaygnfrxljrmkemwwniqdyjgjpkdjhhvjlyszcnxwscueanabaconnhiablqsaqtimgfehoarlgbqbcdnrtapxotmambwtmkgkgpcnbjyoffmmquigkcqrcroihrneigmptfxgrbgsrigqatnhfbwuetzyukdftrhuhykwlurxpvvdymqzwuzkphxrcgxqiskoruckftiybfryftvfmddrbpgnmjoitmxmtrxhfcohlytdfuttiyprfzmdewooidcdfaybgjflpevmabblezsdmxwtkyfeevagcjtmznvdbujvfrtesevsgzlrqfechzpzbkmbwfpezddytqbuhxgggjkkycgtxkkdcmehilltzeccgkldoewyojvjvpkcdwzkahedfjtblpvjfoogovwdkakuxjmtomivaoxonnotskjckckqzaksfieezorgtjgjjsvhvtfjxlfsamqimuxtxbvaadjrgwggsskmyiykarvyyqvicexuporyusprqpapserbyfnalyiayadibzldqmtimhmivcboaglbkrscphzfwwpmqcdeqsebtmoxxkprttxfhcbxbxwlxcuajtvidasejxjhbiypefhjjyyrlefidvoekrizownloaxuypjhbbbpyfwcfkkxbvfvpclyercuhopioataoiupsebuaajzodiwmydrjhbsqxwmyusmkawfiyrodrkqkdrlfofedppofpwciocrsvqnzjfzovnerfggzbygbwruixqmasapkdzxbzornkteeffmaflwqqemjwushmnxirvybjwllzndxtqbquslghhjekcwglxwnoyzaaaevnvxstxqqlytpsnoesqodguexhlamcgymwrldalyvbtggoxbfpgnkpponqqbpyahvoytiucxlypasxdcanovvqrwwvpbxslkjwlvfajhtcjsdnlpmaddaowgitwbdyirtlekheknkekfbfgchwdyxgkfnuppaakoxjbtpovqtjyhlrmnfkpelayailepcitlwuxlpqyylxnpglyeyjrvecnqawowiwfqazbujydlrxsacnduthhgszftjejnhdopnbnwsaqmtxwuxzpmrtqfeuyxpogwnprpeiflylykyfnbofcklpbvfhngplgjakrgqgaqmvhfoiohqornxlhztgdzeyzpavsbtsxkllkrarxxrhbftxccjaatouzpgdzybiexpbdlkcggtywkehcnjgokdzztzmivhxzfwrihmnqannmnufntpkmtymzfpndyuihtfpnvvxyqqxcfqgmzwupaegdyvufhuameghgtwbgzgsayocwrvjxnjxtlevletkrajznjqucznvjcefjhuamxplxuansawnhgyqffxdniixscwmsgxflhjrttzdxpakccviwkhdcoaiincgkskqfwnxsdxlxsxzmcwihhyzwgregxmhbklcwudperrjvmdsclcgfenpkfjczebmrncwkpxjqzslhhtavyuyitlsdndqovdwmzescfdjpvkzyvsyfpaeypwueroqxzltzoldhlzltmqxmaasqucqrojhxtcougwjpnbbxwmcmpbwnzsivftkixigftzweeqkqadowohcnujsijabfadnmjzkyxkknypfvzubbwmgahkhubsccpfnfamtezmpwdqlmmyrbwfhdvmonhdxwbgvewvzqjbeijfkdrtgowrhqsaiwncmmcwnugwrnebhjmsxuocgjpzwdlpnnopatotnfjkajqlglhvoracgqozfuvnwacivngmtnlvuewusbbahwtjfhyvomulpbwaiepvxsmltrmehywdukmwbtzixvuesasweffspzxtkxyriwabrtojqxnimmaqafqcbrohfkxaksopysyfrratwowlcjztozagjkkycgtxkkdcmehilltzeccgkldoewyojvjvpkcdwzkahedfjtblpvjfoogovwdkakuxjmtomivaoxonnotskjckckqzaksfieezorgtjgjjsvhvtfjxlfsamqimuxtxbvaadjrgwggsskmyiykarvyyqvicexuporyusprqpapserbyfnalyiayadibzldqmtimhmivcboaglbkrscphzfwwpmqcdeqsebtmoxxkprttxfhcbxbxwlxcuajtvidasejxjhbiypefhjjyyrlefidvoekrizownloaxuypjhbbbpyfwcfkkxbvfvpclyercuhopioataoiupsebuaajzodiwmydrjhbsqxwmyusmkawfiyrodrkqkdrlfofedppofpwciocrsvqnzjfzovnerfggzbygbwruixqmasapkdzxbzornkteeffmaflwqqemjwushmnxirvybjwllzndxtqbquslghhjekcwglxwnoyzaaaevnvxstxqqlytpsnoesqodguexhlamcgymwrldalyvbtggoxbfpgnkpponqqbpyahvoytiucxlypasxdcanovvqrwwvpbxslkjwlvfajhtcjsdnlpmaddaowgitwbdyirtlekheknkekfbfgchwdyxgkfnuppaakoxjbtpovqtjyhlrmnfkpelayailepcitlwuxlpqyylxnpglyeyjrvecnqawowiwfqazbujydlrxsacnduthhgszftjejnhdopnbnwsaqmtxwuxzpmrtqfeuyxpogwnprpeiflylykyfnbofcklpbvfhngplgjakrgqgaqmvhfoiohqornxlhztgdzeyzpavsbtsxkllkrarxxrhbftxccjaatouzpgdzybiexpbdlkcggtywkehcnjgokdzztzmivhxzfwrihmnqannmnufntpkmtymzfpndyuihtfpnvvxyqqxcfqgmzwupaegdyvufhuameghgtwbgzgsayocwrvjxnjxtlevletkrajznjqucznvjcefjhuamxplxuansawnhgyqffxdniixscwmsgxflhjrttzdxpakccviwkhdcoaiincgkskqfwnxsdxlxsxzmcwihhyzwgregxmhbklcwudperrjvmdsclcgfenpkfjczebmrncwkpxjqzslhhtavyuyitlsdndqovdwmzescfdjpvkzyvsyfpaeypwueroqxzltzoldhlzltmqxmaasqucqrojhxtcougwjpnbbxwmcmpbwnzsivftkixigftzweeqkqadowohcnujsijabfadnmjzkyxkknypfvzubbwmgahkhubsccpfnfamtezmpwdqlmmyrbwfhdvmonhdxwbgvewvzqjbeijfkdrtgowrhqsaiwncmmcwnugwrnebhjmsxuocgjpzwdlpnnopatotnfjkajqlglhvoracgqozfuvnwacivngmtnlvuewusbbahwtjfhyvomulpbwaiepvxsmltrmehywdukmwbtzixvuesasweffspzxtkxyriwabrtojqxnimmaqafqcbrohwgjvsrrppsnnrsofegqmabumdwqpjrlnnbchndcjajcnxbzkdmjbgjxtoyxmcimgfkqyjqlzfbjjkboturbwsbbkdbbimbalsyqvguldvacwmbosbqswjcrcnhwagcbzfjzroyqflxlgbgpvcipwjqifikowjbofbibucndnsjndcavzfnlwgtgzsbiepsueukignldircuufjjascmvbwcxwcvorslxapludueybenucwyhkqertwkteszwrfgxkpvyrfwfdqgxrvczbloieziwoycejngdtbshoawyblvxkppwhzvdkhn\n",
"output": "1561\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4965\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\n",
"output": "2097\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4776\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\n",
"output": "2263\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4590\nxgjppsvyawdncypibhsdqcjujirrsseuzlmlumfghmhzfhitcsxvvvjlxaossljnxsbahubcrbcocbkniuvugszjkjvtgpyrafcreqtadwweinzfcnqqtthxwjwhskfzuuchpscaxofspftmxmznashgnvwmuexgctzyerrsjvwzqxljxadgbbmwpjjvnsfjbaiotqngmzovjtgqpraerlezfzxxsipvtdbgqffblvvaqnmrpduzbyoiojludalhedmbsukxunjfbrglyhykjlcuyehlzaortncydoumdxztzegukaxaoxhlvmwsgvexhgdwppkwmsbtalzdnzrlphihzqfaugjsieghuuiklyetzkbostblxnsacoipbdvcauebvidnbslotfqkcwdhwxrnntxyaufqalzmttsecoqgobihqblefxqtojbwkddrjtilgeazuyrmrtvfalqhrumsnhdpffufsurhbxyuotjpdqyvrrlqqhndfawxzevatrwocagsxiapwzcwjcqtmmzyjwrbbynvaxpdflbadrtiovbsylhzkgahmzhykwluqokgpenucajcffaaxibqrznkccjccnuxtithlvqwnrukuvdmzupprlvfvbjhjxboikxouhvbsmavktcgodlnyfdulyeamnijsrilkyljazkfdslfucvumafalruqanpchxbabdktmbkbidceklwwmwvhyynbjdhqvmsebxkwcimusuxpnebgprwyadsxxdppknlblqqsaykebjladbmxccohstadtlxgfgefoatjvqofrdwubwbfjqiunmnwyvpufkhpwzjogbktmqouxjdiqxoetleucumnpkyspeawmxtnpteaddppytjsqzpxemunhkyqakztweoefplqcklqmrupogoaalcdxszbkzbdhjfmsefwzvjtisexuewykmjzkzoutewpgvmerwhgmuaysiiitianbuldqcdcooskpegpvmlkhntbzllyxaevglcvcfmldnkyuplxkrvjsuaklwxydrihtqphvcluuhjtmywoebtpxzbotqtrbssuqlplhsmpnzlkybcswwtocqzquhyjdiciawssuyrwkldcobtacfxtowbsyxibvgwjgjoiexvdhhrnwlbjsiafbnlwbhhdvzzmiiyoicmupfjttzhxeoyqxafvwwkhzopqqrhnxkdpqxgjmrtviqwmvhexgelfchslftlziiifmtfvjnxkcnqosmplzjivgkvhgeccfidgyueqipdsrimpqsmqzwnlwezxvmbbissehcldsxbxjgzbpunuocqgivuiyiiyidvgfgxhquxzhgqgebzjhdlikeeyqdkpfqyxfyrpmiulxuotmpdqbmrdzgylkbomupgztgbgynmwxwhrbavrrrqsclzqmpwdyulnzibxryooxzbajwzhrotwktbmkpekbgydhqtunatcjawpvcwdfkhphevxhdqwrovnjazrvfxjphlwuzvymugcjrhpwnonpqmojbdpijqruexzulqhrcikgvjxtzqwfgrdgjvngfjeyekparlbautbltrauxiklfotuxepdotkqrtdwsvjbvajbxjwqgpptmvlfallusmauqebiqlvxsqmevrzkkqhrvbuyamquqahgqzpdvrtwzjjvigugjnsdietypytjeapennwipjclsurtycigqwtgmnynlxgreihwhhribwwdmmkxqznhikreygwendphzaicbwxeexaqmdtudgngrclccxjpqbvukkwfcybjocxiqhubrunkkgpfyahiviaetytpkrqwmlziedrksbwqpmznvvvgacbfiuchrfndvhmnutcgfvgbsrwogekslttupfhasleppxppsbjnqddonlubzekvduweuvqehuusyznqufqcpymlkjwoklybekmdhvpdbyleefuksrgrqugetcfxwrokbhefxcktfcncwemqxtlgpwhghsjwgpwusfbhaqtdoejnxjndychnqwhmyvmpmwpkjpnugxdchqcjrykorqhiesxwaeikmempmscmcuwmdkqoblcvjsindxarugakzuwpjibpnqlifwzvxnuuyninyeynzrlvofpagzjqhbgdfemfzreyslaygqnuhdletzppyggywzndltuelnskwujqzzmntppcoyorryatvokcmbvftrxolununxerdssjsaxoudcbrtfqbebspspsdsarrodyrymdhszjmyvfmlgootflwtxluxubqhrkxzxtuxigtrfchxhkejvdmodswakxxfkftpalprxoxqykcyqtvhjvdszwqvgvazrayyyktrljmlcobzkbwqmqlzuqgkupkairvhnslvvpmpfwrztmjrybfzquurtfjgxrwgwrrjdhmeawgtajeacukqdqcwgemdwgigsfhnwpvdweiiefvhgtsqyqsadvgslriiobfmpbrrnbyhykjlcuyehlzaortncydoumdxztzegukaxaoxhlvmwsgvexhgdwppkwmsbtalzdnzrlphihzqfaugjsieghuuiklyetzkbostblxnsacoipbdvcauebvidnbslotfqkcwdhwxrnntxyaufqalzmttsecoqgobihqblefxqtojbwkddrjtilgeazuyrmrtvfalqhrumsnhdpffufsurhbxyuotjpdqyvrrlqqhndfawxzevatrwocagsxiapwzcwjcqtmmzyjwrbbynvaxpdflbadrtiovbsylhzkgahmzhykwluqokgpenucajcffaaxibqrznkccjccnuxtithlvqwnrukuvdmzupprlvfvbjhjxboikxouhvbsmavktcgodlnyfdulyeamnijsrilkyljazkfdslfucvumafalruqanpchxbabdktmbkbidceklwwmwvhyynbjdhqvmsebxkwcimusuxpnebgprwyadsxxdppknlblqqsaykebjladbmxccohstadtlxgfgefoatjvqofrdwubwbfjqiunmnwyvpufkhpwzjogbktmqouxjdiqxoetleucumnpkyspeawmxtnpteaddppytjsqzpxemunhkyqakztweoefplqcklqmrupogoaalcdxszbkzbdhjfmsefwzvjtisexuewykmjzkzoutewpgvmerwhgmuaysiiitianbuldqcdcooskpegpvmlkhntbzllyxaevglcvcfmldnkyuplxkrvjsuaklwxydrihtqphvcluuhjtmywoebtpxzbotqtrbssuqlplhsmpnzlkybcswwtocqzquhyjdiciawssuyrwkldcobtacfxtowbsyxibvgwjgjoiexvdhhrnwlbjsiafbnlwbhhdvzzmiiyoicmupfjttzhxeoyqxafvwwkhzopqqrhnxkdpqxgjmrtviqwmvhexgelfchslftlziiifmtfvjnxkcnqosmplzjivgkvhgeccfidgyueqipdsrimpqsmqzwnlwezxvmbbissehcldsxbxjgzbpunuocqgivuiyiiyidvgfgxhquxzhgqgebzjhdlikeeyqdkpfqyxfyrpmiulxuotmpdqbmrdzgylkbomupgztgbgynmwxwhrbavrrrqsclzqmpwdyulnzibxryooxzbajwzhrotwktbmkpekbgydhqtunatcjawpvcwdfkhphevxhdqwrovnjazrvfxjphlwuzvymugcjrhpwnonpqmojbdpijqruexzulqhrcikgvjxtzqwfgrdgjvngfjeyekparlbautbltrauxiklfotuxepdotkqrtdwsvjbvajbxjwqgpptmvlfallusmauqebiqlvxsqmevrzkkqhrvbuyamquqahgqzpdvrtwzjjvigugjnsdietypytjeapennwipjclsurtycigqwtgmnynlxgreihwhhribwwdmmkxqznhikreygwendphzaicbwxeexaqmdtudgngrclccxjpqbvukkwfcybjocxiqhubrunkkgpfyahiviaetytpkrqwmlziedrksbwqpmznvvvgacbfiuchrfndvhmnutcgfvgbsrwogekslttupfhasleppxppsbjnqddonlubzekvduweuvqehuusyznqufqcpymlkjwoklybekmdhvpdbyleefuksrgrqugetcfxwrokbhefxcktfcncwemqxtlgpwhghsjwgpwusfbhaqtdoejnxjndychnqwhmyvmpmwpkjpnugxdchqcjrykorqhiesxwaeikmempmscmcuwmdkqoblcvjsindxarugakzuwpjibpnqlifwzvxnuuyninyeynzrlvofpagzjqhbgdfemfzreyslaygqnuhdletzppyggywzndltuelnskwujqzzmntppcoyorryatvokcmbvftrxolununxerdssjsaxoudcbrtfqbebspspsdsarrodyrymdhszjmyvfmlgootflwtxluxubqhrkxzxtuxigtrfchifvybxakhsyaqiakliuuxzeksdcmqgkdkavcceqxsxl\n",
"output": "2042\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "2425\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "1541\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4865\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\n",
"output": "2198\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4764\nysafhskivjwxcnnuxvctyvrctopcgwoexymeyfjixivhzgemeffxeekkobumxfbnbemjgjghqdcgurjvpbhsghjopakiolljvdyxbgjlqjxcyszsvxbarxyjtcfskydaxuncsxaosrslbxenlblfaaglycvodjioteffvlcdljnautduxynxkwwowhqtspedwlhqfmmhmaelbodjeacrmsovdacchtuchqpvwfewmraiuaziwfvvancknwgvhbwrwretnsvbhgqexrthwcljdbumhdvmzqbporaqameyajltvgrujljwkxhioefzqhicteedfvmpftmhomgznwmavufxegrxjmhygpblmdnsqvyhxbipuufugejmixxsbrqgwlnafvdrctesluexqswmizcanfrvxryjbcgiiiyootskmschkisuwccezmxxlpufpsjwwmjewoulkdgrvgpcmdtiuxfeiboxxnmnxotveffiipqidrhsyzmlbjxuydwbcmtlayumrmsiuueutqhonbkvywecdorvgsqobcovenbvbdaodzcvsmryttmwgpujzonvsdogpdykordfxuotbbxziikuyihjisixjodjwoefwwpzebbhotjxdtsulbunyqmagqtyavwmafxspumnqnpswyweorymfnrordzzynmidfzdflsvirdwyxkevlwovfqmrpzntuuwqkjrepvasnlehkcjqdmfxledwcpauuputevamycxgcrpmyizidyqvybvjntpagaaakzgvmblbirjaljbwshipixayjzvshfgqghsgquamwuobvleqlirrnbhfsrseveqxcslenwwxxrpxfcoqkbkxxrjgmmavomseeuhrbmhwbsjgezzmdqdlzdmloipvbbdkykqwciceahkhqteiqsoaixkabzsazonbmbtvfcumjzgdsesklmjxqrwwbuihkscrlhiehbxsnwmjtblnsrogufzprgppenrvxgdrqaucalzljnfpbetrjgbufxwacprdjwkuwyurorxvquksngffhgcjjyyirnapvehrwoniqacgagrbbaojkcrsntfcruwjnbopdphxikpacbhxxwkdrtvhxujvieylzboszkswsuvklipwhoszizuwxjphbxbfrnyojtzckfcstopfibxqnygfaahgwajspcusrjlawnkyvnzcdmhukdofalrtgmnzykcvjeksekksrasjovnutijiblnbgllqipdhuwvgbrfsvfmrrlrzevfxsclumtvheflptefxpatgbwwzfsrryeiuaerawvetgvbpmtoihnbhjrlzbwfgplhrlqmicybsymypvnijaurtrithbknpgglejfypqwefomwhhwjgevlxyvsndnvdoaodvrmfwdnzaebtvteqroesojvhwjgapziwajvpsqgqkdmtbtsowopwfmubpqaipwwemrhjxkfypnwmlmdgckangptkghjevspjkzcrafaolutetruwjaximawazzyfzlxoeoqehvecxxtftcbhlypztxvdzsmltrmnivqtcnjmlwxyfzcqxfnwuzgurebwlrvqgntscwjqrpgwkdhlhphfwlqejewlpbxdswpnimxwzwybmlmkrxfqbyhdjvrytriwkazzgbkubnhidrdcreinbigbohimshundjurqmyvfcgkentcpojvmrqlrexusjqbjyofdebnsgdjsxuytxcevbxqodovstaummzxctezypolfpvkkinpvvdmwzxcrwxtlvoyltuigkvelrsljgddeafoturozeiaxtbjyrfyqdsvjmvuklvqbivirqemmshhepixyxezeshfyeubrrqucscafcawbpenfahrbmfkadpgyvxelpzjttdgytwsybctqmesmbgkyypnnoeaspbswjtccfdffkwybortgvkrkrbkemwcrfxsjqxqxqlauhgmxylihjunzbhbmpjafrlrwosrijnprygnjmumvqbuxiqbtngykpcigqjtuxhycbvpscznpxsftzgnwbnzctugrbgenunqewatnmmpwmyzzukklmkkomxdbjrhlqnlthkshmxvwfmnvkdiwsxlkpundzblxypayggypfosnruhlklpyziidgovijqayrzgckdixxrcmzbrrvsdssxsmzvnczhesrabffktskcpgvnwpszzoobmqljhojjkxmspvubvclgkrdoqmkxckhamgwpbdbwrczrvicmydffgferoqlsgfcoojdyhipwtevqytzqgkuczjbztuqmqcrozijoncagtdyaqppouyjghesshsceqeizgzufqeeghnmltfbuxzuxnabwwhvpqgqzpueummxsfeveksehonjxonfcknaosrslbxenlblfaaglycvodjioteffvlcdljnautduxynxkwwowhqtspedwlhqfmmhmaelbodjeacrmsovdacchtuchqpvwfewmraiuaziwfvvancknwgvhbwrwretnsvbhgqexrthwcljdbumhdvmzqbporaqameyajltvgrujljwkxhioefzqhicteedfvmpftmhomgznwmavufxegrxjmhygpblmdnsqvyhxbipuufugejmixxsbrqgwlnafvdrctesluexqswmizcanfrvxryjbcgiiiyootskmschkisuwccezmxxlpufpsjwwmjewoulkdgrvgpcmdtiuxfeiboxxnmnxotveffiipqidrhsyzmlbjxuydwbcmtlayumrmsiuueutqhonbkvywecdorvgsqobcovenbvbdaodzcvsmryttmwgpujzonvsdogpdykordfxuotbbxziikuyihjisixjodjwoefwwpzebbhotjxdtsulbunyqmagqtyavwmafxspumnqnpswyweorymfnrordzzynmidfzdflsvirdwyxkevlwovfqmrpzntuuwqkjrepvasnlehkcjqdmfxledwcpauuputevamycxgcrpmyizidyqvybvjntpagaaakzgvmblbirjaljbwshipixayjzvshfgqghsgquamwuobvleqlirrnbhfsrseveqxcslenwwxxrpxfcoqkbkxxrjgmmavomseeuhrbmhwbsjgezzmdqdlzdmloipvbbdkykqwciceahkhqteiqsoaixkabzsazonbmbtvfcumjzgdsesklmjxqrwwbuihkscrlhiehbxsnwmjtblnsrogufzprgppenrvxgdrqaucalzljnfpbetrjgbufxwacprdjwkuwyurorxvquksngffhgcjjyyirnapvehrwoniqacgagrbbaojkcrsntfcruwjnbopdphxikpacbhxxwkdrtvhxujvieylzboszkswsuvklipwhoszizuwxjphbxbfrnyojtzckfcstopfibxqnygfaahgwajspcusrjlawnkyvnzcdmhukdofalrtgmnzykcvjeksekksrasjovnutijiblnbgllqipdhuwvgbrfsvfmrrlrzevfxsclumtvheflptefxpatgbwwzfsrryeiuaerawvetgvbpmtoihnbhjrlzbwfgplhrlqmicybsymypvnijaurtrithbknpgglejfypqwefomwhhwjgevlxyvsndnvdoaodvrmfwdnzaebtvteqroesojvhwjgapziwajvpsqgqkdmtbtsowopwfmubpqaipwwemrhjxkfypnwmlmdgckangptkghjevspjkzcrafaolutetruwjaximawazzyfzlxoeoqehvecxxtftcbhlypztxvdzsmltrmnivqtcnjmlwxyfzcqxfnwuzgurebwlrvqgntscwjqrpgwkdhlhphfwlqejewlpbxdswpnimxwzwybmlmkrxfqbyhdjvrytriwkazzgbkubnhidrdcreinbigbohimshundjurqmyvfcgkentcpojvmrqlrexusjqbjyofdebnsgdjsxuytxcevbxqodovstaummzxctezypolfpvkkinpvvdmwzxcrwxtlvoyltuigkvelrsljgddeafoturozeiaxtbjyrfyqdsvjmvuklvqbivirqemmshhepixyxezeshfyeubrrqucscafcawbpenfahrbmfkadpgyvxelpzjttdgytwsybctqmesmbgkyypnnoeaspbswjtccfdffkwybortgvkrkrbkemwcrfxsjqxqxqlauhgmxylihjunzbhbmpjafrlrwosrijnprygnjmumvqbuxiqbtngykpcigqjtuxhycbvpscznpxsftzgnwbnzctugrbgenunqewatnmmpwmyzzukklmkkomxdbjrhlqnlthkshmxvwfmnvkdiwsxlkpundzblxypayggypfosnruhlklpyziidgovijqayrzgckdixxrcmzbrrvsdssxsmzvnczhesrabffktskcpgvnwpszzoobmqljhojjkxmspvubvclgkrdoqmkxckhamgwpbdbwrczrvicmydffgferoqlsgfcoojdyhipwtevqytzqgkuczjbztuqmqcrozijoncagtdyaqppouyjghesshsceqeizgzufqeeghnmltfbuxzuxnabwwhvpqgqzpueumetrgwnwtcsptvhggnrhtnqppodlamauxdrskiglzdjkdqdegpprrgximmuxpjmbiqpbxvdpcanfkvwcseunsxzpjewy\n",
"output": "2259\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4617\nzkjvshllodhiwnbcugkudfktycbssljwmdwwrhsixkenfncfgbsftzilpiglatnefendxrxbabeydwafrnzaqvyjkvtwhkzgusgtkgmtyyyuposeiwgthbqhsmijougetqlujltwlcnmfnwaaqihofkdlebctbkteneipincvhwlmyxdqioflenlcwqrbtmemvyjondlxnfvjbpxsiwqtlvmwmvhymqbcnralxaadvghigaiowgbggrqidmqyesweqqwpdmqvtnmoiqhhmtyooyscvxkuitniqlfekwtkhfyawwxsaankxahknwulvymdwekodqjtprzdkxcerbndlvdragvpnbvvclfhvczijtkqatzjxyfzfeyzohzrlyjhcgoqdxcxpzxapzuvjkhikfovfzhhzoycxflapcglquqgqadiwsjhuvqnspvvfxjgivsdpmfxahpizmarefalpnrtwqpgxebjvspkqaybzcieafzzvsiqcornlemxlwmkwhfpohklqrldujcejcmyedfrhanivpwusvcsmknumrxpkbcsxixivtsrrlczkpmhoedtfnlhluqvgyrwwkrrkdyaapfdafhvgscmlrjycxfsomvhwdwxhhzmyonbagjlodpnuwsnjvbadabzsnlaurdchgfyqucpbelzwoejiyklpdivdevfisruswqpkphdskjqmcttjeqjzpytbduteyyshljdieofxsijfvmfeiijmwmzspsanwuymffvqgrdieykghwjnbkasienmeyqdhewlvpdelyvmgvvlvvivpqrdouzaobgubncytdcrphycnpberhzyewmkfnjxmbdkazhtdomnhyltrhzazvqevujmjimcnqzmbavzmypvakaspyupwityjypbhtcnvbmloalvnpqzwolyroownektqrivccjcsbddlaixrmuhlcnkkkzswzfdgvvtmpgshmuqcvsbkulfokcgdcfxvkenonhmfeodtuulxlbqcfdnmpfovezlymdvokiexfpweywxolbevjvdztlnviivnvbpmamfbbufcqukosxistemlluakakfsdrhylfomcpgqfidsaqbksauzkkfoeadonrramisukevpoeyyjqjbaeduiylidthzqlbstgdycjcrbytglwksvaikvvaxlclpwiufqmbhrudtmujtzppfgqwhozyvdenrzdacryrrfxzxjmfpenpeknzafoseroggcojroggubxaxandnoaitrqyytjjvpwsqeywynfwqjynejgdommykqnebbszcifsenlkgtjlkhodrshlsdmwhfuhvktijpxdebjvygzyvociioivrprknkrpnfuvydfbktnwupiuhlpqbwaveixdaggiqzhjjurcdqqxudkjjdhljaeivgtyksprqvqqikdlsmocvohhykbcrwcwykwykivdnvyskpxlntrpxufdkedcvhmlfriirwemktcmrgtmwqeeztbwrjjnbatgakhnlxsxeyihoafubkgdoyyozayinbaothgadiqplsgpuvurgnxxqqhpfspynklnxsbhfkdqbezkrgautvhunueccbtdbqovkuowpwhqvhbdrrtkzttcembcijsnnoervzzgnxclonvvywgkucqwqwdbqvmrsuuclsamrunyymukfhakkqijjhivlwvpnoyowdfaphvyzlealudigjtbjrdttwktsfsqcutcajofsjxeihqfhuwhpfnkswyxsrvuslohmeuqqekdxnejjosriayyogvzlxlmxarzrmgwxqkvrqzvaxjdumyjkmvvlixprtajiurbbovngwjijrnlfdnefidozmsaufpuupjblabxqieofdpdabccbwqgkxwfpuygbxfeoonnavjpcmcldlkpfquusifeadnzemjnuedmordsveaajekbshkmtqqfjeekenbffevnsvwnelpyrdslyrgrmruiavcqlnqiemzmgejuzisdukaitiiocztdrypndmjrmddnwaoxuwcgvlbklnaavjdxgbaxicywzprhmdjqdvjojtjzvlowrynuwiqbfabhpbqjtjwjexrfxsjyewexboksjgzrjbuoxglnrbrbedlwrpekiulfericcdduqvplmowlvgkqdwgdxcwjugdtwojvuawtbhcqcljwiwglzeauygvfenwczkuffbvtsxgadknpaovhvhrcbocncxrmwhmmzknndhlxeiiyfygecaggadzfitvpcppnhxkwjcvyclbffcdyqkifnikqmlyrdhjvsanlnfbvvdhdnqeypllpeketmjxxxgmolvlppdkzgusgtkgmtyyyuposeiwgthbqhsmijougetqlujltwlcnmfnwaaqihofkdlebctbkteneipincvhwlmyxdqioflenlcwqrbtmemvyjondlxnfvjbpxsiwqtlvmwmvhymqbcnralxaadvghigaiowgbggrqidmqyesweqqwpdmqvtnmoiqhhmtyooyscvxkuitniqlfekwtkhfyawwxsaankxahknwulvymdwekodqjtprzdkxcerbndlvdragvpnbvvclfhvczijtkqatzjxyfzfeyzohzrlyjhcgoqdxcxpzxapzuvjkhikfovfzhhzoycxflapcglquqgqadiwsjhuvqnspvvfxjgivsdpmfxahpizmarefalpnrtwqpgxebjvspkqaybzcieafzzvsiqcornlemxlwmkwhfpohklqrldujcejcmyedfrhanivpwusvcsmknumrxpkbcsxixivtsrrlczkpmhoedtfnlhluqvgyrwwkrrkdyaapfdafhvgscmlrjycxfsomvhwdwxhhzmyonbagjlodpnuwsnjvbadabzsnlaurdchgfyqucpbelzwoejiyklpdivdevfisruswqpkphdskjqmcttjeqjzpytbduteyyshljdieofxsijfvmfeiijmwmzspsanwuymffvqgrdieykghwjnbkasienmeyqdhewlvpdelyvmgvvlvvivpqrdouzaobgubncytdcrphycnpberhzyewmkfnjxmbdkazhtdomnhyltrhzazvqevujmjimcnqzmbavzmypvakaspyupwityjypbhtcnvbmloalvnpqzwolyroownektqrivccjcsbddlaixrmuhlcnkkkzswzfdgvvtmpgshmuqcvsbkulfokcgdcfxvkenonhmfeodtuulxlbqcfdnmpfovezlymdvokiexfpweywxolbevjvdztlnviivnvbpmamfbbufcqukosxistemlluakakfsdrhylfomcpgqfidsaqbksauzkkfoeadonrramisukevpoeyyjqjbaeduiylidthzqlbstgdycjcrbytglwksvaikvvaxlclpwiufqmbhrudtmujtzppfgqwhozyvdenrzdacryrrfxzxjmfpenpeknzafoseroggcojroggubxaxandnoaitrqyytjjvpwsqeywynfwqjynejgdommykqnebbszcifsenlkgtjlkhodrshlsdmwhfuhvktijpxdebjvygzyvociioivrprknkrpnfuvydfbktnwupiuhlpqbwaveixdaggiqzhjjurcdqqxudkjjdhljaeivgtyksprqvqqikdlsmocvohhykbcrwcwykwykivdnvyskpxlntrpxufdkedcvhmlfriirwemktcmrgtmwqeeztbwrjjnbatgakhnlxsxeyihoafubkgdoyyozayinbaothgadiqplsgpuvurgnxxqqhpfspynklnxsbhfkdqbezkrgautvhunueccbtdbqovkuowpwhqvhbdrrtkzttcembcijsnnoervzzgnxclonvvywgkucqwqwdbqvmrsuuclsamrunyymukfhakkqijjhivlwvpnoyowdfaphvyzlealudigjtbjrdttwktsfsqcutcajofsjxeihqfhuwhpfnkswyxsrvuslohmeuqqekdxnejjosriayyogvzlxlmxarzrmgwxqkvrqzvaxjdumyjkmvvlixprtajiurbbovngwjijrnlfdnefidozmsaufpuupjblabxqieofdpdabccbwqgkxwfpuygbxfeoonnavjpcmcldlkpfquusifeadnzemjnuedmordsveaajekbshkmtqqfjeekenbffevnsvwnelpyrdslyrgrmruiavcqlnqiemzmgejuzisdukaitiiocztdrypndmjrmddnwaoxuwcgvlbklnaavjdxgbaxicywzprhmdjqdvjojtjzvlowrynuwiqbfabhpbqjtjwjexrfxsjyewexboksjgzrjbuoxglnrbrbedlwrpekiulfericcdduqvplmowlvgkqdwgdxcwjugdtwojvuawtbhcqcljwiwglzeauygvfenwczkuffbvtsxgadknpaovhvhrcbocncxrmwhmmzknndhlxeiiyfygecaggadzfitvpcppnhxkwjcvyclbffcdyqkifnikqmlyrdhjvsanlnfbvvdhdnqeypllp\n",
"output": "2253\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "1881\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "1617\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4505\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\n",
"output": "1670\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4978\ncnacvrndwjhqnzlfkeibeywnbhcaxlmnwzthnygfngohcoujqhmiupnnshyaspzrwjnvxdvxtrqzsprwsvanpxbyiifrqbendxzokadhnxjvursocnpdhhuzdtchplyclzrwcaqwwipfddfrslbmdmvselkiqgemsjtqjkyffnfvfubkrtjkwodtikfxrxwhddudevhuyfefqbsikelogdyptjczybthvpgfssmtrmklbrhtrvrpazedluucnhhtcycklqshfotzrjwkkkondfiwnzlgmsymjglxjudwewoegppjujfunciiqjrwzpnpxgblvgsnruyankwsqdasueilunsrlmlkdksaoalfiqpkqyviahjkauynuztjjhupwwnnktskyajwlhswgpgnqxerappaxhelvdyahumkekvaimyypbdkrhecgdgzhgqwmovlotqyvemgbktcveuvzkfwflbpytvpyuwtsdjnyhkqehizrxuibikmodgccpncpfthdqvngjvwwuaaqgtusyxmvwniqmunspuclissdnmnhzvravnrqpkugouyfadqhcsztwqxucmtrynkvtvinboygpltlkxvezffgfwjcqxxttwaiwiixfmrxqdrwxezrpasbgvfsequnlwtnlybzxvambdwkxgeyiqympwcuuzeslrjoqsvazhdqakoydpexsimmpdienotckxtxezatzmglhobxiaemyuyrgvnylvwgicqcfwhzilxcbapfxmprhhqbhuhjhcmzifxlhyymiuvvixrhrpvjvbufpgnkwhtzywyyzsdoqqbmcblpjrotwhmcmeyzasbiknxegbdknytvqdjfjzufmyggwzmmvylzuivnkejjvrrsrzvqraqveejyyjggiuekgpkrnhqzywkrnbdbcgrshlepnxbikiefsmrjilyijopvffbozhpkykjllbphxuomfyxsautfvsumgdahusvezdokxhiklpklvdmqvqdhuwbjsjemvkpvmauctibspekorkwopcxkgcaltkibtjvnmjskrpmyevjuvtkbllwiytxgtoxmldcsxaorhrrgqugktcfekzeoepaqjarmvprvalcnhionzswkptlcsyspuvdjwigzzwnzfxhtbypfwctqtyceqlnjumlwwoprmcmkzsymobgagwvhvtvkkdhkoihqunuhzzoozpjumiqftqczanpbuyufuvvkomgmekfysrsrvejvfxbpggulvdaltouygemkbeevvawxslamfevgyxgragcukmumodxunfazvisdsansbvwkqqanltzyjnbxafyetnhsmeuopbuiywgpadytalhwonupcwkcpjyflkqkkqdxngyyikocahbxgvylblevhgdtlojmdmcbldnpstqngfwllrfndjcesicuasinuolqhqjkssithtqiiipnekupthwygybhqpdrsmvprgyaqatlilvhlrvqywqsauoyouodflrcxjrewtfnfvkzdlzbjirewhyyoghuibrndgcrkzhadtirwazixxzawdqwgizivtslhqbamzmwdwtqhukjjdcietkvecacfobtzdmidwacfpikxlsxlnseaaabivkzfiubvpcpjhspxuuymmlmcswwoutzaxdnlvhbratkgeyxtbdnigiqqkbvtnmqhyonracmvzcdjgwidltfzlvojjjctylkvbsvworuyxmwpjitdabykaqpskllrjwharmtdhcgognvgxkrwdcnmnztekfswwgfzaygkhorulzcefeqbtcojkqoflleirljlhqrljjpslbdiujcoajjyjlbzosuxyeesmruxybuaownzorijcgszkbrbjhcobuufbzjkwjxuskyvdxndoofezgacqbibjzeimdpldsosfxmgahtmrbejzdfaiwlmkthfzddzucjwyimbyfqlljqsqhutuyfxjzjduhjagjohsenppdxrqbzfbmlckflincctmrbypmnrzjvmyzxalqadeumyugybqkycjpiubymtczbznbksoegupstvzwexijkldtnthrczifvqwcekywxyjgkzqplkawdvxyttyczftjhhkckjqaxivcarjamzoanpmejgqhahvrhxasllrcgzsqvskrijkbjbwgmjjsqjljzvechkspzdichmywvcixueonpdmqbbbzppcciesqxbxslpamrcodveutkexedmtrudycjyudwafjgmqknpiarzoqouhkhmfiaooshzuavoxgqoazsidibgrgtujqkizfztmiaacsvrurpdbvgkhzrcmsthzqafluypzjsxdoedgqurgibwtckpuzrprgzzyjizbvmyzqwfgeujtoyokyakjzmgsinmcrruuqrqjyysfxzwiyneqfajlpmffvriucaptblrqvgkboogszpfntkgmarevteaszcofbcmkgswuajzqxnncxiujkokvmjhelkwwadalfekgpsgarchpgakvzaksrkfyyftwdlrckcegfuwmjpewoktcwrgltjvawybsfmzmfquumnrlsiaatajqetfyfwdpkhndxeefkudelxgwatymonbksiusjncxifgphejflthvxiwwfgvlhuuufljvkqhtcvtajqhwupmozkjvtifmbzbdeftvimbdwbjyjmurcxokvucfymnfeoipaamhhtqxhrhlfucteiilshljnukkunsaveaaengemvmgyxoeymvgrzimrxmdsykrbobqqvefantjyopanlpjlcdggvcgtqzlerevvolngznbcuxizaewrkyvrokflcsyfvsdemffdcyheojuyibikcjuuhsnaaesjtznjxqqgwbxmbpyprtarfropffkbeeexrkaoudljkjjwwhylfyxkrkxquolhjmxjzhhiewiixfmrxqdrwxezrpasbgvfsequnlwtnlybzxvambdwkxgeyiqympwcuuzeslrjoqsvazhdqakoydpexsimmpdienotckxtxezatzmglhobxiaemyuyrgvnylvwgicqcfwhzilxcbapfxmprhhqbhuhjhcmzifxlhyymiuvvixrhrpvjvbufpgnkwhtzywyyzsdoqqbmcblpjrotwhmcmeyzasbiknxegbdknytvqdjfjzufmyggwzmmvylzuivnkejjvrrsrzvqraqveejyyjggiuekgpkrnhqzywkrnbdbcgrshlepnxbikiefsmrjilyijopvffbozhpkykjllbphxuomfyxsautfvsumgdahusvezdokxhiklpklvdmqvqdhuwbjsjemvkpvmauctibspekorkwopcxkgcaltkibtjvnmjskrpmyevjuvtkbllwiytxgtoxmldcsxaorhrrgqugktcfekzeoepaqjarmvprvalcnhionzswkptlcsyspuvdjwigzzwnzfxhtbypfwctqtyceqlnjumlwwoprmcmkzsymobgagwvhvtvkkdhkoihqunuhzzoozpjumiqftqczanpbuyufuvvkomgmekfysrsrvejvfxbpggulvdaltouygemkbeevvawxslamfevgyxgragcukmumodxunfazvisdsansbvwkqqanltzyjnbxafyetnhsmeuopbuiywgpadytalhwonupcwkcpjyflkqkkqdxngyyikocahbxgvylblevhgdtlojmdmcbldnpstqngfwllrfndjcesicuasinuolqhqjkssithtqiiipnekupthwygybhqpdrsmvprgyaqatlilvhlrvqywqsauoyouodflrcxjrewtfnfvkzdlzbjirewhyyoghuibrndgcrkzhadtirwazixxzawdqwgizivtslhqbamzmwdwtqhukjjdcietkvecacfobtzdmidwacfpikxlsxlnseaaabivkzfiubvpcpjhspxuuymmlmcswwoutzaxdnlvhbratkgeyxtbdnigiqqkbvtnmqhyonracmvzcdjgwidltfzlvojjjctylkvbsvworuyxmwpjitdabykaqpskllrjwharmtdhcgognvgxkrwdcnmnztekfswwgfzaygkhorulzcefeqbtcojkqoflleirljlhqrljjpslbdiujcoajjyjlbzosuxyeesmruxybuaownzorijcgszkbrbjhcobuufbzjkwjxuskyvdxndoofezgacqbibjzeimdpldsosfxmgahtmrbejzdfaiwlmkthfzddzucjwyimbyfqlljqsqhutuyfxjzjduhjagjohsenppdxrqbzfbmlckflincctmrbypmnrzjvmyzxalqadeumyugybqkycjpiubymtczbznbksoegupstvzwexijkldtnthrczifvqwcekywxyjgkzqplkawdvxyttyczftjhhkckjqaxivcarjamzoanpmejgqhahvrhxasllrcgzsqvskrijkbjbwgmjjsqjljzvechkspzdichmywvcixueonpdmqbbbzppcciesqxbxslpamrcodveutkexedmtrudycjyudwafjgmqknpiarzoqouhkhmfiaooshzuavoxgqoazsidibgrgtujqkizfztmiaacsvrurpdbvgkhzrcmsthzqafluypzjsxdoedgqurgibwtckpuzrprgzzyjizbvmyzqwfgeujtoyokyakjzmgsinmcrruuqrqjyysfxzwiyneqfajlpmffvriucaptblrqvgkboogszpfntkgmarevteaszcofbcmkgswuajzqxnncxiujkokvmjhelkwwadalfekgpsgarchpgakvzaksrkfyyftwdlrckcegfuwmjpewoktcwrgltjvawybsfmzmfqfqwzauexxuqxwwznzflwxsoroldtcqujomebyvsrtswgusbyybimotaphlcrb\n",
"output": "1960\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4680\nvhpkfqtkkedyprkmsqahayeukcjytoayzvaifkcnquojebdlmufsvinykvggxvuqdcacuuflugenffzasxxurdavxrzeeiypysuwhslpaclasqxdytewucvhspkjydkjkxpllccxlptkbdixntqjhozngcpyuwhtsgvslkixvyadpxlppkhmrbiiwwtfgyjyrlqhhzjeerbnixctbxwiwaolvsmlcramjqmsjlislxzmaiepetqdhwtgwiiergpgzdirhnytftefclbueycxdfidyskozujvkwzpbnbresshgwqpajidmlcbwzjcgdoyieklhfqfcxkqavdorwvyeojdfetynfoebtfruipoarfwsxunardkuxzbhihivdsgooizyhgcjnnwwstfsdkqdpnjxfemcszegyqmyfuqvzsjqnggibbvdhfiitocxeljrzrjqkgjrhttpuzjgfrtyfghukvmshgblpcqwyfdvkezkpnvtpuadxlgjvtxhytavruryhvixlwvruaktecotothmjbzpqxnapjrceohymmrqpdolzqaksnlzysndhupwfpfwkymnteogwxwzjzbwgivaryqhtsmxralhtstsrcjvwyhnrlbgftcpekalzgxwrzxnjrijtmhgxwniudnfvehgtfjbgblvpdsrtfjxlyxmazopzpmdijxxuyexslpbexxncgylhmgbtonlinkytldltqbnlyonmrqbehcrcwlpagjokspflkfcmyromplzqtjlebpduhofjpimzhpdsjcnmszuwjmfbsrtcyqvwoedamqrzoboehgffnanlmotrkvfobttxndplsqgnfeqswbwktjmhjvnoyrmusixhcvhxdcwuaamkgsmnnnizunlshxquvrhaqdvkdqpqngzceurwfhlalnlibygycwcvsuxrckgluzrarpsiflxkxmklsdefzlnhemswjebsyamyfheyhhxxninicksvkniugfuzxmigzcxocdrpnmckzikdqpiyyyamrkychtftdihvtiuhfuusrdnszbwdbzxsosxnxkitjiueumyaocgdiargwbcjhblbdpzmhpbfedefexhuufatfefhvfzivwzpegygoehogxyoakvklbehcwrqsvzzkmwgcjxzuceavddelizjoqcqbajwqmlmmhixksxigvieylbzivbtwuoyjlivhrthwgnhqsypkqmyyzieozfhnyyrlbajyyrraemkssycasdybdpyedvbgdtehqiqkjzjmnicztorqbzdtnnjkqvhmovefljrlttbiuxkhdemgrhefdobicrtlrmbuhvltixbqkzuzeonebfhysepbladnmtchkkmcpmvmrzlkaqxdkrgwgcplemroqhlglprhnwthbqouosgrwjfcetwbykihhusthhlxcpxfdctvzwvlxrukehtedrmzwemdxamdgkygvxaazxmtcdliosbatfximaijemuhcgsllcrcajttkyqnmhznjswxhxcrdcybfvfttoebvrwdrmgeahkiwkqivpkbqhgsfgsebhdxfwttzhwrouxecqtrljfmqpiueauznumriqgpjwmkpkuhypmwhbgxnkigjrrmofwivvycrkjftmxxauqrddfcrbkznzozskewkipstxpkflplsjbwjggdnashqenhkccxtamgxwwbtdatzwdyzvuekrjquhwjrykotnplhexhpmraoqapxnyvgafoabektkzkrnqpxmfkgjxfndbmawcgivjipueuqwwfnazokrqynfkrwinhkiopleqrlhxtwvvdvlwkjowklgedybmeglntksasofzbsuabbtfkwrstyugasenvtqmlqovntmqxhvwaldhfltbbayrzgpgcjyzfwkcwdowuxwvcrrqblotqfnboaoxxujcpoopmopiihzinolvtyvifofgfvlizjtsklvwzoghnescciazmtqbnmuslsvxslpsxxmtaoozgmpryhywurxrgjhcujkwegomcubegbhsulchhwqcfetodgxjpmtgwimcinazhdevdvkbfctjdadrmuucdsdnhnmnxxydbeqhajqshlbmrsemjvsneeapjquczmnupbhizeyyzxwiqnetllyqivmfjqgzfzixjhzjizljyrhrmtntnenkiqwwacxwgbwxxoimduxczaywccjflxvxzkakyoeykdvwbynjgjguqkiehtxnvhkaviyyrsqkjudoxwngvnxhlgmvlvovgcpiikqzxxwyirtgpxmtxmtblkfvsmiblplxvaazvdhgwgusavvuavotnasazgggmvluizbnpgxacynuczwlnltlmnuolnymjyazrgcafcaoqoajrweuupimojprdskpysuwhslpaclasqxdytewucvhspkjydkjkxpllccxlptkbdixntqjhozngcpyuwhtsgvslkixvyadpxlppkhmrbiiwwtfgyjyrlqhhzjeerbnixctbxwiwaolvsmlcramjqmsjlislxzmaiepetqdhwtgwiiergpgzdirhnytftefclbueycxdfidyskozujvkwzpbnbresshgwqpajidmlcbwzjcgdoyieklhfqfcxkqavdorwvyeojdfetynfoebtfruipoarfwsxunardkuxzbhihivdsgooizyhgcjnnwwstfsdkqdpnjxfemcszegyqmyfuqvzsjqnggibbvdhfiitocxeljrzrjqkgjrhttpuzjgfrtyfghukvmshgblpcqwyfdvkezkpnvtpuadxlgjvtxhytavruryhvixlwvruaktecotothmjbzpqxnapjrceohymmrqpdolzqaksnlzysndhupwfpfwkymnteogwxwzjzbwgivaryqhtsmxralhtstsrcjvwyhnrlbgftcpekalzgxwrzxnjrijtmhgxwniudnfvehgtfjbgblvpdsrtfjxlyxmazopzpmdijxxuyexslpbexxncgylhmgbtonlinkytldltqbnlyonmrqbehcrcwlpagjokspflkfcmyromplzqtjlebpduhofjpimzhpdsjcnmszuwjmfbsrtcyqvwoedamqrzoboehgffnanlmotrkvfobttxndplsqgnfeqswbwktjmhjvnoyrmusixhcvhxdcwuaamkgsmnnnizunlshxquvrhaqdvkdqpqngzceurwfhlalnlibygycwcvsuxrckgluzrarpsiflxkxmklsdefzlnhemswjebsyamyfheyhhxxninicksvkniugfuzxmigzcxocdrpnmckzikdqpiyyyamrkychtftdihvtiuhfuusrdnszbwdbzxsosxnxkitjiueumyaocgdiargwbcjhblbdpzmhpbfedefexhuufatfefhvfzivwzpegygoehogxyoakvklbehcwrqsvzzkmwgcjxzuceavddelizjoqcqbajwqmlmmhixksxigvieylbzivbtwuoyjlivhrthwgnhqsypkqmyyzieozfhnyyrlbajyyrraemkssycasdybdpyedvbgdtehqiqkjzjmnicztorqbzdtnnjkqvhmovefljrlttbiuxkhdemgrhefdobicrtlrmbuhvltixbqkzuzeonebfhysepbladnmtchkkmcpmvmrzlkaqxdkrgwgcplemroqhlglprhnwthbqouosgrwjfcetwbykihhusthhlxcpxfdctvzwvlxrukehtedrmzwemdxamdgkygvxaazxmtcdliosbatfximaijemuhcgsllcrcajttkyqnmhznjswxhxcrdcybfvfttoebvrwdrmgeahkiwkqivpkbqhgsfgsebhdxfwttzhwrouxecqtrljfmqpiueauznumriqgpjwmkpkuhypmwhbgxnkigjrrmofwivvycrkjftmxxauqrddfcrbkznzozskewkipstxpkflplsjbwjggdnashqenhkccxtamgxwwbtdatzwdyzvuekrjquhwjrykotnplhexhpmraoqapxnyvgafoabektkzkrnqpxmfkgjxfndbmawcgivjipueuqwwfnazokrqynfkrwinhkiopleqrlhxtwvvdvlwkjowklgedybmeglntksasofzbsuabbtfkwrstyugasenvtqmlqovntmqxhvwaldhfltbbayrzgpgcjyzfwkcwdowuxwvcrrqblotqfnboaoxxujcpoopmopiihzinolvtyvifofgfvlizjtsklvwzoghnescciazmtqbnmuslsvxslpsxxmtaoozgmpryhywurxrgjhcujkwegomcubegbhsulchhwqcfetodgxjpmtgwimcinazhdevdvkbfctjdadrmuucdsdnhnmnxxydbeqhajqshlbmrsemjvsneeapjquczmnupbhizeyyzxwiqnetllyqivmfjqgzfzixjhzjizljyrhrmtntnenkiqwwacxwgbwxxoimduxczaywccjflxvxzkakyoeykdvwbynjgjguqkiehtxnvhkaviyyrsqkjudoxwngvnxhlgmvlvovgcpiikqzxxwyirtgpxmtxmtblkfvsmiblplxvaazvdhgwgusavvuavotnasazggiqogs\n",
"output": "2258\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "1818\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": 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"output": "1864\n",
"type": "stdin_stdout"
},
{
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"output": "2341\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4925\nwfnjnvkwhvycgrhybznhpjniwozszedljyfishyyppdhvsncvmrhcheyfjyylofxxfymymsmquysaogawmhknyuzgviofvvwlowbkujoubckurnwwcqnqrfhhmylppsvljmcjuwnvznynicsofhrxktlmustnluxxywsifgtuxjbmquyinronheeesgiqlbwohykgvlzfqhfseqiejwznmhsjfjnqxedkxrzhkhvkfagiqhvgdbuoqbncjupbrpwzrbghnzjagmdtyumzfftprwiuadbufurmlixnuwhoatzglzrnlswdflqhbyfkbvpcnxabpapbnxgtcrkphebrbplbjudjmwfdibiryhdsnpmkleahhcknuwfjmewsgdtpxggfdkkwvqyckihpahccisfvcwasmfltezwpeqmiealiggopydbgplwmmuipihjszimxezwqogzagjyjaetzgeclglydwhxynxdqtlwzspuqsptlodbyiuplwikajlpjxsjwijavujvjekdgiwywvzmhkukjqcayxtvuoamymorodfvaifybuskkesgbywkqxaobnuihalilqzxkqswzjvdhutksxkhfcsajrtanoccmpkxwkxojyqtqrkjxhpojxzdixanscnomwxlotawgujhtobhcoxgxorqpxujxpmbxcenwfoiwkiehrkvtzonczpsyzflyrdlmvjdsjyajmfecucamleigbwhnvlrloelsgrcaiooganhrismjimbrjwjulxfdneptgjircglgxkuhngnkzdqijsdnfvrfxdtlhsetbnxhgxkogluktyyanikkiqbqmombptlldbyqwizkcxpngzepxyykshlszqtchbpettlnydvwhuqbkwsbfarhkeirydgqanaqkgjcbuvxpblnxgobnkoydjgrxhrjovjbwgasulgjpnayqtwydgbqvxexpuluxkbfgbpebickwwlikeywwnpvqjqclhryscefziludwjucgxopyqhjrxbrzcysvzpmtoqnsygwbawdosdatfuwcmxghmfsmfrrqywejkdyeavchrvllxefhnbjfuyzfmtdowmczvmspdoffjkolatppzdkvgyvrrkfnczuvqcpotjkusevbbznyzfhnjtxahmeykzfqyyrazuhvaowdjnpjzropjqairlolqgzcjnwcocynpxznegeyltcyjfanaozqcivfakzhgdvualzhawcxquldjyokhdowfcwonjdvxujoepadcxhazcqsdvskefyujfazipswiyxovltcfkulwwivvkgievtshptseipocdnjkzkgfukijbtxbdjshbrcazfrigwundlzgzbonxnothlrjtmybhfrccnkzujtjfoczpdndfvdcernicmndbaybkubnnhhziwjhxtzhzhbtgnneuqjavisqbrhibnhauknhokaaksvbapwhmrjqbhjspalaadwydjwbigfryeykplxobspflgzvjzvmhrslutznnhvxzdoigxkorpxgylqnczxxblvwhuuhcjgueiukthbbvxholpbuaiklcdbmohptkzyygeenacrujyvjyhvzwdspgvzpxtvjverbznstwkhczqbvnpmvfcmxeqapsedgquugtdgslcjfwywxfzahlzhhnoirjcdkqqgmrpanefjjhdistoorucflljokjofuzdmneyyfeneoubcgdfzncbcptmxkzkyxrdcluorkxgrzpxxlxfrekqzdhubrjytzogcjdpdmhxyhqhhcithkhazytdewtquyzotegcuyeynghtasxyzenjcqufqqiaxqbihugojhhjvjmbqbetvxnyijztoxsshwkjbkrfldxwjpkfkmdaalgvoeucvnekvwpfrvxkvtahpjdznvhccaexwizzafozzzjxkouxujwkmycyjacgafdgvlucjaylvswrvlxyinftsnyfdjsfngykmkyecaoctxmyrocdzncitelovetcyrzuujboatmqwgviwlrvgvyuilawvhlmuwiwrbsytmrodccanoihbvhiiolxosytteyupbyuwnkrgzoxppltcurhfnormfnpxfmmbtfrtcvtbxwhumdamkjqfivpdhbhrnuibrvwypgihlgyakqcwgecbtmwwwikelkkdwcyaopnzseenasneucwqlxwknmqgebpvaxqqbwxnmrsweyooyvegxvcpnmbtakbjyrpzhpshzfbeifwkegkjfwfgcrsmgfxvvkgjqoqksxblhrhqwutmkpyyizkwwosotlxafwokumnidbnmwxbjmjslgpzzcwakcbhimexkfcmyfhcheyfjyylofxxfymymsmquysaogawmhknyuzgviofvvwlowbkujoubckurnwwcqnqrfhhmylppsvljmcjuwnvznynicsofhrxktlmustnluxxywsifgtuxjbmquyinronheeesgiqlbwohykgvlzfqhfseqiejwznmhsjfjnqxedkxrzhkhvkfagiqhvgdbuoqbncjupbrpwzrbghnzjagmdtyumzfftprwiuadbufurmlixnuwhoatzglzrnlswdflqhbyfkbvpcnxabpapbnxgtcrkphebrbplbjudjmwfdibiryhdsnpmkleahhcknuwfjmewsgdtpxggfdkkwvqyckihpahccisfvcwasmfltezwpeqmiealiggopydbgplwmmuipihjszimxezwqogzagjyjaetzgeclglydwhxynxdqtlwzspuqsptlodbyiuplwikajlpjxsjwijavujvjekdgiwywvzmhkukjqcayxtvuoamymorodfvaifybuskkesgbywkqxaobnuihalilqzxkqswzjvdhutksxkhfcsajrtanoccmpkxwkxojyqtqrkjxhpojxzdixanscnomwxlotawgujhtobhcoxgxorqpxujxpmbxcenwfoiwkiehrkvtzonczpsyzflyrdlmvjdsjyajmfecucamleigbwhnvlrloelsgrcaiooganhrismjimbrjwjulxfdneptgjircglgxkuhngnkzdqijsdnfvrfxdtlhsetbnxhgxkogluktyyanikkiqbqmombptlldbyqwizkcxpngzepxyykshlszqtchbpettlnydvwhuqbkwsbfarhkeirydgqanaqkgjcbuvxpblnxgobnkoydjgrxhrjovjbwgasulgjpnayqtwydgbqvxexpuluxkbfgbpebickwwlikeywwnpvqjqclhryscefziludwjucgxopyqhjrxbrzcysvzpmtoqnsygwbawdosdatfuwcmxghmfsmfrrqywejkdyeavchrvllxefhnbjfuyzfmtdowmczvmspdoffjkolatppzdkvgyvrrkfnczuvqcpotjkusevbbznyzfhnjtxahmeykzfqyyrazuhvaowdjnpjzropjqairlolqgzcjnwcocynpxznegeyltcyjfanaozqcivfakzhgdvualzhawcxquldjyokhdowfcwonjdvxujoepadcxhazcqsdvskefyujfazipswiyxovltcfkulwwivvkgievtshptseipocdnjkzkgfukijbtxbdjshbrcazfrigwundlzgzbonxnothlrjtmybhfrccnkzujtjfoczpdndfvdcernicmndbaybkubnnhhziwjhxtzhzhbtgnneuqjavisqbrhibnhauknhokaaksvbapwhmrjqbhjspalaadwydjwbigfryeykplxobspflgzvjzvmhrslutznnhvxzdoigxkorpxgylqnczxxblvwhuuhcjgueiukthbbvxholpbuaiklcdbmohptkzyygeenacrujyvjyhvzwdspgvzpxtvjverbznstwkhczqbvnpmvfcmxeqapsedgquugtdgslcjfwywxfzahlzhhnoirjcdkqqgmrpanefjjhdistoorucflljokjofuzdmneyyfeneoubcgdfzncbcptmxkzkyxrdcluorkxgrzpxxlxfrekqzdhubrjytzogcjdpdmhxyhqhhcithkhazytdewtquyzotegcuyeynghtasxyzenjcqufqqiaxqbihugojhhjvjmbqbetvxnyijztoxsshwkjbkrfldxwjpkfkmdaalgvoeucvngjjfjhyhuajklngyrjkbqoiqsjlubcryqylvxqpiywoldfpsaubbesvkjahfafvotmwrpuqwltfcsgeemdnwnojdfrqcvyydtunpqnrnyvjenosthicciphmgepsjhpkvutjpspxyjccbzsvpbjwgppoxobstglgmgsviytzyrbdfiskfykxvnllvuwosretglqbdznokbxkwiqbcnqzwdywotoobgjtiacrrhnyerxxxtzlajegkhzoaaiupldlkhvsfkythxsiolwwtixndetpyavwjpmgcgletzcervtecfflmnwrlnvxhktsnywybujxldwqduobpmqiafkswlgmjsildfeliebecdxdokysnigvrobefcplkkbbyweisubgvxxvupdgfzamfgoqjekdntzispkfxgspsjuvnsmrsoubroadonullcwxawamtaxafmrmncjhcoqobytzxgpzsnqbbvmhqomwrcfutfsuszdykctcfqfdkkkobucihylflkityahzwnunvwjnadpgmqtwkuvvzvznlxkesparknrhdgdtovugbqlmpltpuxhixlekicbdnkgthqgsftgojcwfgwzhvywbweezzhzleemqkfxwociclmnlrjthktljzdapnugfnvwklfzicemsvvtlmwvrvbbgsbwdivyecusaevnnxioa\n",
"output": "1861\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "1982\n",
"type": "stdin_stdout"
},
{
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"output": "2231\n",
"type": "stdin_stdout"
},
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"output": "0\n",
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{
"fn_name": null,
"input": "4928\nskpspmvmwuolhsqnbeqorgvlsiinroqhdsedcgtzmnbyvpgcwhbsluttjehqwjcomjowcnlggirkhvjejklgokflhelksftulhkfjsexcifwnuflambdxsadzjnbiuldojwlhcaqshfgzbgpxonrjjfyoqxvfwwinuifadlsuzlwiazaclisejknsncefvxoxydbwbcmptmjwbkkevgagwrybkmsqjupjnozghuaichsbpzzwzndmeadezkojkinfutqiqvypbixlnnurdexpvkugnpextcpdkadyevjvvysspxjzoatntquzzwljpypyxoaxxzubvvsactnugizazuofqosyicavzcbkyyzdsbymkfatfwwvdlbjqmlxidzopapziksjihmcjoygvuolccpaxwshkqwccyzppnakgohnlromaazmvbsgsdemibtdqntpvwgckcxskihagtbiieznpaihlslhdzbhlvcncfgzcquosesypdyefhweenhwklijulphxsoisffkszcymvqydcknfvrekunrcpjeemrsydyppfyvkbpttwxxidznvjkalrmyjrrlidtodgcuetbhzbllkokkdbrtuvxeixvnzsvhosvfkoihvdevqivbrxnwgqxiivhumlxkxqtevwgouowlstyarylqcvojkgtqpfbcnvmeinhibgnqmcnaawtndmktgwkhrjqfhoiqpzytbdldbbdebfvtoleobldimwaallpmeifyoejkvjhgmgaymbzihvgdueluxgvufinuahxsxptrxixcbbqduwllmqzqnbbndyrxgbchyxvthbabpdizdcdhnoovsdfqxkbdcwztnnsqnpfwzzyvxfbtkykszvcdohdrdhyvxmizlphlaubjkqvfxdeygxqycfeeivlmnkwhtljqivvmikakayijgslazimknvdeodbpgyvmkcpkrvowxnylgobymmnxyqfnkpmjjpjkaxvzngzvttbzivagxhzvebbqnykbyuugatvbwtzxdwolonasndyyrmvsgqqlzjzjhvgazsoebwnoeumnsbiczccoosbivxwqifdqsswiqubzdeywgxmvyeuxdelxnflvxzecfksmedjagyljfuqqsgjwxpgktzvmourgpsaynjmhhgdwpotgxohwhkvznpnjotzdncmrogzxrswoctojgdmzlxtleehxqghfjdpquyxrkvcrzdbxnfawwoupdljherpydoihuxglsqluiykxhyunhayfgmwhgbbiedrcgjbddhpuyybovgsqoyskbtpodbgvnomhevcozlfhvaxsdtbepshgxxwowtdfqqavctigaaxtycxvpnuqlwzlbaxrlbkjiyorblnfpaussrogcdjepkinncjdakslteosiutpmvmikbuawxgyrznynnnawbbejotyflfyqxtfxuznlkqjpeegszhqoyjdvnbdcyqgzkntcieqpmigqmggtypswjdoicmkgrlqlzczpxftiwkpcviksxwamfchynkxunwpkiiizzfomholvhikxfvxztkolfrbyzrhqhsixncaoqjorrilpiwrgrbchorlbfouvlkxvthygexyovvsvijihlmommfruusjurdarixgvsyygmurtyrlgoquqcvpmwuutdzofwliksotqdxrtahjurltinlnqxuwpqcvirsdztflzsesmptjiobmanwajkfwiasfpshiyupalvkkmehlmbotemnxtgnweffdgiqfibdxadosizklcjwgnjatrwyactheakakwcpzdqkrzivzxdndensqlxujritguwiesnsqqdkynaquwdjdvqxezohaywdzsayqklryexffgofnpntjmohqwefrzakmmosykrqnspnkhctcnykjgwdoptzouqsvdzzydstjsgzlbarscvgkozeteynhhifhhcdncebaylaprhfvwkkpmtyccltvzjtjqnkaghzdjtsrcgjjgrkcvuhnviontoufwzyzbansaufttpkgbtmbpzvgzarshtqrppjaffbpdcjblijitnlievevqwmaklkgbltejjatkacmsggbulqmntilakshxsoltzvqtkavgievsjdavnrstqcxxpkiaalsfdfuycxddjxkaodnxmgwqxsmcneljxjviaocnhbpmuimfmzvepmbqhgajwyzizmnwtdpezuemtqtxyvesiqcawrdilutwqodpecarayrqctryzdayfkvhdsekfnjavltvsdbabmezyryzeanzrcuysxtaawjiwnlewyymajtsllebsrdxjjyvlnfwubernpmkmqouszvuxqnspueunqrgjshbxdvvhjtsuwqtcurhggsqdldxrtjplylllkiidgyompofsbzjwdrerxgpodilrqnmeorohqvzrdiaqowjhwajsnryfkqbrzjqfejhuhfuqithskywyrazyhvequjvabyvsdkpptrtjbwqtqrqhriaffjaneibdqfznkbneglabexwucgxfpsbcczxnnfygwxxfbznlalhtwqamascvzzlpvcthxpdpfudzwzkswglzsaghbxrnrpwlobsjqqqrvehrtieykanrsmohlffbysghlkyvbaxrrmohxflydefpkazdyynopzkvhhjstdjxtcjmlxlidhiqmsdjayxjyvvzzoffqdplxrappiyzafvhpvygtlperxfehawawknisyomuyytyciawwawlkmlpvalfyrnlzutfdzsacgodnncfdhjhhpqjnjeoollbsckwaxjxaavjhxsbyptcsmethgdlpaukwhbulkrtzwnhdiyxsbomyzezaczqhrnxvqddlmfaahpxmaulcvkbkhbgjgrliovavsrldpgctapufzufsiuukozvuupnkvaheqvzaifomjvcxzlskfmnyygyfwnbnnqraveqibleyvhxwsiopqpnzrfxvtsjxpktfoekdingipqbgxnrwhwvsdedrqynhhlligrzeykdapfkgupnjprnfgswrdxmrdpbfpirtwomgxewvsywaqsrifcuiczdleompaycnombjpwondkqccxcqrsxmskskrdbfhbuxxmrfmpgwxjiertuyoqvvaebbibyfoxcjlsfgzfdrgxeixnfysxkjumxanurdatirovzsaridgqtscufredhwmthgbgfjcugxzmlvaufsjduzhigfesdedvhgjubeemrgbxlxgnusggnqotokvccuoebkfjpnahubprynwwdmzuwdeewlovierbiovlfqngvvjyfwkjfllfehibxdbrogopvmuuqukcvepqqeiyvpvbxemftuivvrygsftapyfeyebakthcvcfupsemammnhyswbaercslvocsthimemptwqcvinuqsqrmardnneucccmvvhtpyfgvbofpvelgrjdeybjpoxowqplgocdrbumsepzvfqiswyohpxudbphcrleswszudhyvbwkmcmixvoiomjqfrtevqefdvntymmaeztvdhiudleodradxewlzhcmrhyxprceiwbpxwcdxjahawjjgcgbyyfltfvcnngxeivgvefhqvqwmoaubkbbamphabetkxomavxeqcvxpjllginfypkzjshhfjamfxtpcddimyinrhgkkgzcbrctxcvlwymjoxomikdbxcczvcvfaktylkixrwfelxeqyjzehpmtogxcinixtdrxrlnuzjqvcyhyfyecmizipvrjuzidyndzvbsvfwreibjkvlhuwkirtgbolugtpnkluwkeuzsrqtyhuupwznqlfmkzmocbeixisifofkgbepynqytjppiexvetpkwkgzqdxyewkilipbpqfjjixgoulfpvhgbhfpxysrvmfmxfnentyhadhwmmfhipzbwyevlbcvoezqrvaynorqnwylrjivlwpcdmaklurmwazcwxzdtucksismtjhojydjcxvcjcfvmvdhpodifmcxfuznksdajhgmohljbehfkweablrcisgciedgmzohfytavavoasykiaslzmugdkqdcuqetzcfheezucewpzqofdpakepfixhwmziopqgskdnaabpbwfnogbmaayxoysmsahiitkkucjjoiulbrcwjltosqesqsbhsrtedzkxeavhqtxrpbagbwbnsaopzeimgkuzggpkmtixxqqijxzxucqlfkhowgqvttdcfzxbredxyogeyffzvqagzxdlfmvnvalrccycsmtcynavxbxfjizgksbtmpdroztgdzbcxyryldywielmeqbvtnongeavmdmhndfzshmbhzhmbtscqpgunfjdmbsobfefjiabxzsdpuvdbcgvymalyirswfxnnzntpeuqrsawjuoxftrgxnaiwsnynoytbsyvsnkidvyuednrjvewlnmucgxtxqwzxjggphtjeegkvklabxsrwixabvirettgpmplaqdecmhjcnfywfihrmzgzujolzrservapfcdtughxfrtjvqwrawiokcchehuvytjuythoujkxnvcuoesmbsbtmfkuvnssamqwibhfcqfczbsfhetivlytdjoiaynqyoicatbfjowmngtlgnjsifvclwuvdznnaxyicglcpmovkldifsdvtxvmpufpzwibnshjebmqtyqlpmzibxcnnzgrxzuuxtgqgejqufinsxugmrwprtwufssdjtzvdrpadhmbfshpbvghfparhfezyoiuiyveqzztoxhuootixangpbtmpkojnldqxfotcbdybhctomszdrswvxezylwklztoycqtrjbrvdenxfoqoddkvwcxjztuicabcadltmacdixfnxkmisyev\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4689\nwqbgujzqvbmgqidtnhjcycnukesdlwzpjfculjbqqhkdlscymwddneamlnrzxyzaobxkvvbojmapyapxsrwvkwlvouswpvtssmhxzbgnujkmgvubnawmtkbasfheujdjwzfubkffjwlwevpbchpbmzdimwnctorpyfdvhhvqlyhwkqkhfsngkkzathuskzmkwklwaqrarngzkkmrtwijzkxvkdrqzqbutkidfvkhlnrdunskugsnkjapajdzfiubswvdyrgvcbfqjbifhqoxivyflotgdapudakbtzoxwcfhqbxqxlynylizbeuvbmtxiprnvnqbxxzqnxgbtvdpnppnzfvnpifigatgptswhdnidlhhkkuugqomfwdmmxliihldfelvopdahimtzohdicujihginupokwpkqdmogwqcnbfdmnkyfncixbmowpkeewopmkxdaglsxyljerszjfrtyxsplkpjdqcmnbzjmyohlihcsbvllebvtpdwvkaacmdaitqagaihawtrublvhgwbfxpopjlxvoysitwchqffrhkiausbympldaukbahigvewntkvindsgchvgkoxzowlhahdfabhwshhbwzlpoujsumjbhduchysvvvfkkhlkfxunssiptibvrngststfeqjsxydfjfzmsdbodifclnjbgmzxgvuqpearimpqekdeumsrscmokuqkxwfdmhxasqcyomtdwnmzamdrmnmyejmejuxxwhbehlxhagihtqssgpxjvvkxuwntwkilozzjvtvtpjnthvhjibrytruipkkmopdnfvdprbjixyilnvjzhszcxzcdjuzdikrifbvmdwwugrgbivwwwgosgbjsymhpdfeuqcatmrmbjefeqdesfbvisetxmxtgoucxafxarpddywrlxlaucaautjarlyvstfobfxoywrpcwswquyirqmjtyesxhgxjwplsxwrubaeduqerbvghgprcwabrtqmbbffmbydunwajwetjxolwyiqjrdpcxbrilnmqnorgudwogbszrfuxilmurldelbgljepuailvmqoizwtpftzrfmjkehptadjoxjphuxvvpnqwztobrzjoygdsmqocjzneygctblacltzomoigklbsdqomzpzwqcyjspegvnhuclazacgyhxdooqlddmwuhkqdtimecwolxnholjcesivfwcizlhvgtvbpqkzvilltehcxjuldpjrjixgwaytkzafmumxbetdhgqostavnrgowimjvawmoxmgneqcjazjvkbyetzkgxpbvsxvvgkwvaqhyirhjjjneaqacgrbzbzgbxgerkijokgpdmgkazqnfapeifyznftomweqsmenjjqkomhgjgjyywkhukyrfkhpofwbzpdujcsymnsmiksdxhsizdzokqvdiyoazkwfcahiawtytfvuxsmbvnvxjmukbizvirbkyekemnroepbxcjrbggtnphzenqbdnqvwurbjlhdtanankvnqkneccegpccecseiavidqsehwczyvnrugxjwhcytygwvefgswsoezvekjodzlnvlgdxlkgapbntnzfekugxswksnsjydzofovfsgbdhzlzuubpippeupabhywwrgofaijidevdnteepowzbcndjnyxwrqtwvvmoqmkffnysdcpsuzbypqhwesftyekcqmshacxqnbhvuadiracvikhkjudikoiuyrmpaleklilvdtoupqbaxhdkwlyjaxfminwovznmrgkeysnwybgirftmvtsdkgdugnyiictqkfygljukefigfjshfybtrziaqxjetdvhznsutunjjybcjzvhjujtkognurlcijbqwslitdzgpshppmsefbsqlmrmfofnnepbdyjrjnpbtnfdavsnwnowkiobyrmollumpsiabldipoewnsfdflqlfqjbqwfvxifgxazvgltmpfcjujtiecgpnafdrwhsgditryrkxigqgbvrijoelqpmlvebvrtninfhnxwwaetandhytcstmtpynvsrrzodlttyeyaytzqwknwgvshjksywmtxljzmdqlguhzyaxbfvndaojdsccpwabynswetbpnbbepbqhibojjmdehpvcjnegnmpruughozefefhtaxnvkedjkusrhdndzzmgznbvptvdeqktcjwtxegaxovntpikhqsfargnecprerpaqxshmxlxwmzyvdnicqyyozdbwnjrbkonbckuysdsyqhmcznuoakupxxkndhlsqcstvcvgvykopxboyayduigxzcrzuzaoyjnwgekmosuwjzlmxibiwqgbbkelesomwtdanblumzcwugbzmhgquvjwodvcwptrmahbzozkqlulyhrwsdrjtmoirtigbehjrqzdnxhlmmjbnkpuuoejqvzhvmsdxvajszdflqpqxsamrowgmbzflxmccnioywsbteexbaozpubgzvhpouhknxqyewtadmqvwcphwpinixpplzyjsldszrlfgwdyswjwahikbetrjdanzpqqbnlxpvfjuqmvizbzwjlzyastdtqvgcxxijocdtepxyzuavgkytrmjtgpabcpxlbwbljefeogegokoelqaxlclftludrgancudguluhngnacdyflbdkjithnaposvsrewnwffbsahidsmxeajcjfknihhzzlwfsfcflmbtkxmmiqdegokfiuweymlacmxbceitbuvqbdcdjagtyimovnuglhwfltvycznvwmaedpprnpagsahchgztklikxluikoaeiudcexrajgeucxmqhfakmfwjjzghowflmremunhyfxaftstwndlidegtzxlafqqyysfhxmyzjgmfjlqonblhtgntrbljkmisszvboikykvnmygijengzpkjfiyoodlfppetmvdddetkayqeultuvqsgllrfsrujfwbvevlqnhjzhzsufoclgqceyesyyszimdbzrcqcjvsfgrivgtzredvlhdgasocemzlizacvdquskjmvcnwilskrkttevwpvvqhnntoljwhwzgdiksnrcyphmxxmprbswuggpbwbuqqwxoqdyjjkmcstlvqymxpkbxhzquhwgsrjjvpzinnpdxusdpkqpelnxrabbxwypbznloinprxtbeeyxahhnoszyqpvkqhblqtckbucgodbdeizqlwehpanyvqtlmesufrhfbwzbdsngputgilafflvboovavlioefbqvabuxzagrtgrwkthznmzjkgkxlywlqrzbakoworxjwmgbafpnibolgraonbmlngjnvnbsvkgslqyxorqzkcpnjwocsolbgrvezwuspnwoisqlcpdqyjsluzbpaaqvvrjefrmrpszjydigmsabifhilhqcfltybqdhcfrpnqvaizuenruakzrjasxpktadsvajvfvwzssueeuxyijfhtppbhmxpdouyeggtnrpqwunfetivfxjqnnhbxlwzannfnemjywmpzjxhzeohsvxzcqqdahcccutlznsmqhiczlzgvjhemabvkrcrqvxcnwyqzkqqjlwvqbejvupsahqexoywpnvbygildgrjthevgqmfdsjzvgystfuthmmlmzpcrqcocskpzkfuoyqpfvtzmctokljuxwbcmvbsiadvbemabmpaamknguvfsmsfjlkktdcdcfifjuueqwbfzocgkuegidusnjvcqowpgktkjsbxxfzgmakzlmlsvdhmqjsunfbjsystbbvewsoleqlcvrvgngxwyxqrzpgibhiwounekpctonkkgmrouerswxkonyqgyfijptoyibqrarozrjjbdjcqguadbukpljalkmqvyuqlgwrrgwzkndrhupgkownotuqvauphbcobchepmvthagqndckogaexawbxawoxyqhyxzjkmjcyinfyohnfjbglqxrdoymbtzyvibangprtqyqkjiynecdjmwssqynbioviwqmwgtwdjcqpowpaotxtjmazuhbwzskubvkzbaiflpsjmyxwxyhjkrvetevdreghldikfazpufapwnxzlsbqmlvngxuclruxbwdmtfnkbsddopnkqiwbqrpjdkqjdnmovzveglrdokaussxvqodmjasdxuttetawioymxoequxlxlvghbiothckxigmlpplnhjjjtkxnekyockopilbvtxhjkuirqfeuanppvgywcnttpefvpbrxxgkszqnzpqtrlxecigvmmhzuwmdvskijxgztlpdyivieixgqkjcqrfvmkguywiutuffoacnjeuoiuwlljzemijxeuoqladnyjpjzxfyukfcumkpdueqvlhmfcuyikfzoopfdeawcoziqnrgpriwwkddrupilazesexxnomnxjfmmnljxnpdrymeankfhtabxrcqflwmvklhtkgsnvjxayjhboqqcqwqkzjfrzocdnmukdirkhbmveasalzpgbtgeegospmfkautlaatzhlppgsmowtsrocaikbtdcjrekdzhoevaerpnxumnivlnktozxtdgxkzfrmuogunklibhuqeacbjcuvszehbdkxyatmgmizbqmfpyrghmoafvizhmjnbnhtqcwpirmwsxjazrmn\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4960\nmcvlohrmletttgmbtkbzvotvsrmduybtnnmkurtflccynsgepxcnydjaeweebkasssbraqiqcwfodkocucgafyskdswnceettvdogzzxqgckgktbwjlnsictyryqmkxfniixurwtapbplnphzjutzxlbdbimenzvtqoltabbtzrqisgddgnctxbjzwxhepldvkjyyupmjovklsvzpmmuvdygavurndripcbepzommfpmdyvuwvaypjrbeppymykpmoobmbhtppvlplwbsnuffomfsavuhcqactbtqihiivynxraumeikkrdhduyjalfddqaqzrpjmmtgvzcjupyipwnuyeoqllrsfxabhqshutixmvvrquhakdzezenbnaiwkiieebfjmrrblgtdxgctycnuwbpkdksagycowptjcyvimqwhobvxhceylucghzsaqooelxohlzhulphjvzhnxmwmddbekuebwkjiwfcgaqbylbxuoaqruhbpboealqhnxklemvcqxdnavuufqaerifxyxysxsjayglskjekxodqdlgsimdmilwopeubvvnnyjiibvbdfgljkrskzmqfxghgzcoraglonwftqjcewefmtqyldsdradgmgxuiysszhvapbdbbaiotozihztbsjkwsyzjahsovnvmnjghaaoozsevetsqytuzcconlreblrxktpttixblbcpiutbqhpaotxkmwrvalqwoqluxizdbdyfpxefnphgkoxqgjvimwkygzblmygfqtinfhpgjjdzsrksrxtjrjvdtaqxeuxakchpvsgaatmzvrsorkywfapocncutbkcmakvrzfejjjooqpbbsnpbnsjhpngicixumxuhrjbmqqlbyxocyirxpqbbxflwlmvafonpipratltxvzrkrkvgmibkrwdjacirlickhhieopmprlnfcltxkshofemzwcuwgpxvsxzqndelcplmzjkippxibyxrphthddtoxepqxtvpzgfhcgpzxrdpsyxcvhmpzstuvlsyxxpsuzvtbuatkwynftetaycmfmftzqatlyistgfvtvzvtqlkheudeavceljtjtbyinpsnxwjxeeberyniludnxbcpiuedfhfwoihdnnrznspstghmsmyqjnndcpqmpcfvabgdzqiukmmbluemnlqqxiqwzynlnffmjfmolmqhqmxnjucsfoovhuyqftsudqfkvbmmafakkrgekoalrrirkfiwdbxbqlrzjtybaxlteqbuylxyfmwjbspxglsdvpldocfuxhqutdxnlxdvkgvzwjzdmrwvexccewacuyiqlwxclikwfpoclxnkndkjpblordjcihekenzvscfvsrlxhfbjmyexnfeliweysobicvlvwrpbbyouqjjpjvdwtaymsgsabzrvrteruhqtbcivvnsclcabtpadlfjgswmzxnnbgbmscxktzcvubndgnsuubbrtektgvyknshegkumvptgsxhghmlcmbaocbqikxfvllgrvhklfwyithjvhpvaoekcdymsvdktuiddgvxphvxlfcbbvutdqqdbxhxepwpozfycjgrikjnvwtbvtbxywzgescxernqvabfrlbhbeovwjmyxznfldntlieqyhkojwnjvxgvvcqrghzvgytcvaocpmwezcioaoromdskahwbrgfcyfvrdtyevzcfgysdqwhcolpdgmqquielzojubrtafwjndtrzbcvrgqcquezpjwldrvesramcpdljmvqslgsbpsmnbwgmknlvsvzrkiihkwgluwclyphkfxoxudxxqplzwtezmynxydlhtudeiusfcfhgqhwligsbmzhpntcsbhjcpweguasupwuymyiisnzgiodqzffppfgxcwnnrxyyjorvtjdglmllpwhiockfgveaqezlltaaacdzzevddawapnlhalewodrarzuqgxkcssdozamrmqaduuxygpgwaypeoywgxvgkcvlplowivgslzaigmtivyhsqydadnohujenfjqpzpmxbjfvvdmkjrofoflxukysbpxwgosmvplprlbovlrfwcgasvrufyfrsmeimtdtqemmjhvjswnarrybvhjtfahrznspogcjcdxjilczqkczyyphebnaijgblppjalvxohsyjbovtrxwjeutrmxtsrmhlejqprgzvgwqycjxgtisxryfhhifzmkndmmocvwxbvygfnuppntorzdhkcppphoxrtowrrekcygulwssghjaviaaobwjochqizjgajilhlwqhatjqmvwyynjprukdaadewmbkwigoljjxrtmwglxehgijvwouaxwralrffxzsnygltjrklvgteakejujymoydortjixkoxntmosnknqlyrcvznswzgrssntmucewkagsraczxmfdsdozglcqprtgmrhjupkieoasutnjusuyafbpzehsgcrukwxvlxvzzjywfqcvroeajdxihzssylrkofcvmtbjezainxiogglsorixdnxezawlbzrbsexabsacvbxaelrpakcbjwzqmynmaaowraijkcpnnonykudrxojteukhryqnvkjvjxggiqqdtmcpqbekkldasksmnqnjsuuohlzqomfumpmncgxzzrvspgdrkqayolyfbomoaouuhtbspjbzcklghflburggdbspeuraofglmgtvkflsyqnoguoapacbhzxclovcvcgfktjrxheemqcsovngrhufylvoymxpatkrjysmzbkocmlhssikeyhaknklnkjlhtwclfcyqoatbdweaaahbgohjezrtxpweutspncimxkvnccdrsbsigveqxcwaqykqmmfqdohoaiketrztqdxokoaxwuhthnrbypiehyvbnxcrkbmyeechyshjnsotyodyvycvqhgrakrzqmqxfqpftxrpzeodelrakclinuxisdlpnketlnrgtfyvhyhoudyicznkohjrsaaovpjnjqlqvmgnfahdmkmjwiplvowfoiflkavfypntwsbvbvwfyyxadctpsmaldyttohizbiuuapswacymdbawbzqzwubcyewupiwhzmkzhglvpmpekflfntvmaelpdjvfiqvwdkdlyvvhmroyzmbrvlgkeayvotiavuvfaivqgzeqrhnibhjhdafbtxqmtgfxncdecdkwmyairdfzijlkqblgpworfbxlhjrspakxzefkjndsicpuldhekbvgzvfrhxbdengjmfhotktjemermfrzgexjjklblmsvhkiggjidrpryxuwumsvfvcibqclgawtufpufxkrniepohwvqnyaxzypdjfgowxmkznfehxasjrqnmpjrxlyulqlzgtfbjzxjdbyefuywevruuqktwecmruujrisatfbivtdpusnpnkrarbcdoadxvxakexnwofdrcaxpoqxjhgeutaqtnnnuauqpuuzieddihnoypgendhgbhoemubcixrfyqztlwwswueeawqgndfuotcpzlzixwubzvxxkkhigtxzpqorsjmachwowaapbyqgtzbjydcngpcjgbpwzezdnkwdjyedxgijtwxqvwsuniuenrwtslshxzdqtqtkuouldrzvwfvckgcbjrxpbsocxyzelowfmwuseyukdojaknyqsdnwjtwmrbjbphkrjgjiksztkerzkpxpeevcypirulsirpbastsafrmzsfoqraxzdvxlqvojzxdacodaomjhahstytrcdvwpjilzzjbhartmthvgbdabwqrbaionjxwtmheexvvrfhjlofaejdisfahkbmdwverinfopssgixuocltkzloaxjfluftyxsebuepfghbyvgncgrqvsqwybhwujysqgaihvefbvoszihoxvizadgzheydcqbhuwvczlxnkbilxtbygvtrugxvxqcxbulviqufuebaudinxyrpszhypeomcarqvbzlrewissshmxsrdmgjllpxbwatlbceonkjflitpqummiozcqxttaoulqrkhtejonbjcnssrkdzvvaxxpbkrnvhfqrhwkgbywditawiecujpwtyavastifdodxdmhbywgykrjakwhrvyrejbyutadelfmanwnizqxfdjxjomcxhyeoshjyotnwdylefrweulsqbnoccsziprczfkmsagwogrurkvgdykkrmvgncwlsehqvjturulidyfqmpwkofrcdarvhhlulzvklxbhgzbvrphrmktxrhejvykfkoekfqbpjvdrnofhwphylljdggyqbgpmysnngnsgqfwsmmvydsjstugoaiqsknsrdbvpnfnfqwhaexhnhwomfcwfkxkhkgzixtdcsomyedhpligyyyrdwyqpusxafpvxstrngjfzvqkgehaieiqeaydkmbzlwwxzbzfmpxctkfspgmzcogfefxtspxciaefbsarzjginsnmrkqfgilhtsrccifpesbydlryryaszcdgzbcmqfehbucsvtvdmupfjlgbzkcwkczpdgoujwphxvchhqrseggpgflabhzvrzsifmoqaplfobztooxmeycpplhkwikuymktvfvvpeiawfdetiisxtrocyhandqjhppgwdibemuzpwfjhyrzaqgmqxlhnbcukuyvrrzufkuemidtevesrfvazghmxcjqoeqvrxrlhodjrncccrghmgpwzfcysgjfodhzauucdoovzcumeuaigunytqypiropkxluuhicspmzjezgrjuxwixpywiwgptypkpymgquimcxdravfxmfwmrwrcnloklysqebytnmjxfnthelwkgtsffnjiojhxuvjxmktbzswojmuvmhtovtvjizvjuqniscscznvrynjifxnscnmskrcgtkgdaayicrv\n",
"output": "5\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4855\nvbhyowizgfhgnvzyaebvplxphvytgrbtrajzhhgiazrpypqxctdnvzdibvdjfhbypouzxwvxwgrgefwzmtkujgqixtxvpgowrvvxpsqwkexrexmwqzjjnqvjklpkntvzwfwrjzdrpfhdedmrpdqotvbxuhuopnvcygahlhzxytzjrdlgsbgyjscyxeyzsesukyduaftldyozdoopvzyjwjklbxvnfgjsjrbcogilgppgqnjdtiafjzugmzaqecuhmlusrgtdmbqmpmcnezmdmgwigcuqlupwopydvfpeiusllflbqmfswgjkcczomjfuaeljskopulaawlreimsbtbsiimniwwtbfymcqwfauqouqdlgfzbmjpdidwjtypfbbplzgdalhhqcenkndlanpkqivxqufuhtcuqvpnafsrjhdiifcouewzatuqsjrmuafwimxnnnnlnwvstocifkhiiusttckqvomnumamzlureaijqcffbcuawzdygmnyeloxqpnyivcxubpclaxiqqhlcffnozqqjuybxhyxsgswtszobmlxuvynnrtzlvmqljixnkaqrjyvjtzehwhyxkkacndxzobhxdcieiyiwgsgxqgabzdcabietjolloxsfhthvcirtlxpjczwzkeswwsdcfggodowabnslrsdergfigtuzdxgrvleaghjgcczktunxhbpshlrcumjuhadzrnporrydhxvpmulioqcgzqfhsvmrelidjkxcnarsholwvnjbdnkehuevnatpcvjxhlmaeypynxpsghpljaxtkmcgwvgwnzmaqbgnemylbtuvtftgeaegzyfknbgyzfztsnjuyeozhvnpvtujyeuzegkgrtigymjmflzjytfxetqacufigwzaavkmwjcmbgblzniiflvyelxuqxylbedxhqvjgzhfehrtwjjazaibajnbdojzrfdvlhhfcojqhcgfeaedgmjprurqnxxjolmttutgdlivdeclsjeggdkfubhpqvnjdfcnoqqofqxupspxusbinxasivpohlxcnghsacormzzdnkvnhujiddoqwuhmpflisfumrytdabthakwytvgvrzehpcsqupqjuhipyulxxvbbooqrwpkejaeqjsvysfinixzzyhunbrngnzohoqvgmmxsmejekknknizgzqckrpnsmsaqtmgfxjrlbzcpuppwhqhgrjeuhsmbszmkzppzaeepqtmkdzuuuhikfkyfbvncmudkjylbxyqbysczoamwvoewukmbmaeboyuyjjuskkjieekuzqwwswriacdohzfjacxhmywweqryahzqakzpafknhaywstpnywvuyibbagfzwhoocsdeyhmwsifexxtfnlqrxqpcsktksvnawdudubbjifakpjpjkdkcskoijjiklxefisvvqfpjbquplcernktyyrtvkinzkmormvpytqdxbdymreikdvtemfolproekjcerwawefcvaeyvuhvfezguqquzabpplgmlfsoqxsihaeammgoxeglegmfwvlompbuxnfufodzfpitbtkmoywirehxmrfguncdqaxoegraoraajunigfbxhdpwndfoyxatydwpyctqlrudlaboocxzfkpgkbrskgmathoymuhzyadgjpjykzevuzrlfeadwzpuvldlxavlyyeeynasxapznzpklfhaxqhpsmginhexthlazkktcfasxxgrjimriloldgzevwtydmgysmnoltvjnxdfddcorprfiprkfvukswgrhvaratzkwtcqpjmiiesjjuzctylfstwpiqiqfljzituiuiolwswifenusupgvemwynhgxulgxslfxcejyvxnhdbrhiqyedwdomvanihcuhvlgloecjryhhmgycgrdabdgiigqxsmtwuuvtdoycsnxhffcwhhtkmcfgyxocvspqunlykdbjupqnwcnbtzwktcyghbdqwptfnknrnauwrrxcnyfggoqkqetkhkacitffkahovblwspqdaogjlusamfkrfkvjjynuvdtsttygrpbauimqvpnhcwboqxpotyqempsxttyanknriodmiyqusydvevlmptpdwmxjvdogbwhppteuykbdkqjdgrvzifckewcwlfqtnxfnbplqwzuoxdugentezjzjcrpmgeehnzovwtagtrheybywixflwtfjjmflzyxcfucxheonlztyblvsfgegjxaotznycrwgyohywpkieydouvwbgdrywmyyshbfmlvhrmyycbojpmtmmznfpmqyqndtwclriyglceavolhimjerdcvymzwmoophdygzqawbclztymhekyaayxaiihctciokrhmvqqwxusbgeamxqordkeghstsjehlptpepkuswktryddtcyhpmrtjduxcqvjncpktznnotwqwqfenwuzqwtzpnkijyaesjlpueschujkjfdazxflymhnglrsjvrymzeeqjvpwnvqfjglsdsqqewzrfytjxpnobhgawbmbjyuzwpfjhnoqgcrgkxbcvweuhknpqsnkweeapbhdcwhbvxcozwmfzkpzgebxwahktnxeobqksqkpoqpdumqfnsdkbigsqjzwvxvqeygdnpuetgsdpomlezanihovmpkyrtqcqizmrudgmjgwbeizljcmluvbpqiqihacsnyzyknjypbwzpewoqqcgaiwhfhthejnskpvmevtmpvrbzxfkqpqcxbiwmoyjdrodvldfnoreuvenwiepxwewejyygjzwefxqftzwiclfpgfszbvdjrgubatvfnawfvalzjkgcfjhparvzgpqvwodxahfruusqmukztqprosuhrmoaoaoptlgczuhsvuoulsarwxrtcfrkoyomulxfzifkrhxyhsneomxqpwfbjepqszvwcjgwpekmypippcwmdnogoyykvgwjjxfthdpnfljjzyamaptblvodlemoduwatqtphkgeijbamqbjnekahwsdjuxnwiwyvhuoazsjetdfsqtzmnvndvlkdwaqayxjmqjzqyqfddfizqamuabwzvuqbgunjwphtofbxicppqyrjhakigfsyycwxzjrcbmjrsbmdsrtovkdgoqxsoqnayjwuihfiyzonwyilcnmaotbkhydsesbtedlubbttdvggckzzaaiydbhnihubltqjbnimjipflqnggkljnmtobwusmelztcsoqjblaampseyivuigjlkediyrcboukhlguwmakxjawymuqysfmxqbnwtbwqmchbqkujskocqopxpchnkggzkyhqesidtldttergoqhqxxvdfzrixphzkjkrowrvpfwlvhzzwzbxpomwxcdxxlfrarwjoxsterezzqvpwhsrfyxjmbxkdfnkgzuqyjjpepagjbrduukfzjorukdqnnthbwpaeeuapafejwjzfzvrbzpnhonwnooikryvqrgtgdbfnsupcvnmsthkcweuwufonvkvjsowzueteetygkltegznckxrfbqzwognwoopydtajsobputqdsfbzkelwpxzintzxdykioxigkdwrklfnpgixzeqvonrusnnhbryqsqacdzjlnwdkgnuhaalhaeqoywmsoiawaqkmzzjfrrnwyseorsdnauflhlrgenpxtchomlcgomrwnnxqlgpbqpixtuqijunyttwwszardklhtuptamwtmrpkbsydsiarmrprzubaszibbofegddebkutgsymdpnoxwufvzzxgppoimzemcnxupwjnaknnokruluudeyxwbcvwyptfrimhcwomwqyaacdqhrmekrqcslblfurptzdhcgghzifgtjpwsvdypjeuddgwbtxapydikhneszhfpfpuqghrrcpbghosgyefzfhoqtrqhirvemesimfebgtunbkvelajpxnymacuajzqsgjqtnzniuunsvsjdfvkwhlbtnvasvybdpirfkcfuqxqgsrrldqqejovptgjnzwkvmfeofrhzjkimryotxapdzbyqzxnpgjspdqbxbuxlecekgzwtlnbdqycyrhaupdnmlunnldfmzmalzybzghkkryjvjvqqzaxcrktezesoaikdfkisnhyiydtbzbddsioxnetkhwammohwtyctqsogqzlbodhepequhzhccczealvdzsdurqvifxfhpuvmiklofcmpqqpywmblvgpwltzpxajiqphniuoxwdufankvorsewhnqlkjvzsutisbvzvllxybkpguyvioqzzeyxmpcgpvwnisfvqxnefhjatcbhptjaziuxjriqiufvhfxkdquyjwfyulozjlhnyjsixaljuwnhhakebqkspamiahycvymtqydjljphpzuwxeplwvnadmsipawncitztawwwafajziloackghewesmrjruhmpgfdjvrcpbklnvlxexnlidyjplcouupnmbpezdhnzcgombvkwprnthdssnngsfeecfawbonafqohwwkzitccwjyxtsslkkqntnqrastvthibtvmsjpqlajcmeeyuqvxzzhuucflbrrbvvsogsngmvrtgjbevilwnlgvqtlqjyyyywocodzdbbcxkxjszzwxloinviqtxdehcymkeriabevpunwmfbgzfgjuxqhqlqswuoetiubvxiizzoxutwqponsbxtsusaauskgaluvwjvdgbizhhultkcutbtibhzleqqtdiwutuoncchcadfbnwbusafvfapnopxtpnncpmvftkaoiyzccxfkqdgvdrdedikombailbzb\n",
"output": "5\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4810\nfjadfvinclgtwwzodcsllncoqxmnputunnjpgctkqhefdjkgrebiwfllugliqpmyzlrjaazjyrhyvgrlrdnhqcprmrmvgrjgbdolczpbhmwmvyuylshneejebrjkmpyqijlkoeljdttojxzgwcfguuljflkhgyxfchlnmdhtikdbzbkdrjmmsvkmadciifndxkiazfivtfqdqjejuzzxfdxxoacovcjzbbzhxfbjuviojwodxgankimhtikksgtaiwaiytaaynapumacbcpkdeljbnwklgnbqojwwtxdkbdldndkdtmtufvpzfbxvyctkorszyzrgzdqngxphoakczuodmxpmooreqvdzezwceoeguymthkzgrucpetmamevpchbzjvwtzcolxmwkggtoflviomazprgjrzefbvszathzvbrtkzxmltbvgxjfmhdsbsbwyuxaftblxjxyaovnemmeqhrujkwmufyxmrryzrukwjxzihzwffejvdbnvghhqakyoekfkxzbyfazegonqukruelkvjebxdwlbejhvxrjvilpddtdmuythushnzanbvyclxqtzamcykhfenygxyenjvkdxomjlfuqepklxzuoyzfpxdgovsvwtippnvayjhrwlxouskialjgsoxjkdwkepvxnkbhoinhwomqztgxbtsonsijlatxthzsqloafdkyzmqiqznrptszyuvnlkbvanrqtuwddgxogizrrctaugymbmmeahokuixwvimoczubnksmhkvhniayfgfaftykqzfijgdkoldhaecxrecyklmnfnapxavruowfuehpamlrqhaabzryawhalwcycapncwrxqqwpkszzpxzypncqmgwdhjqcqqfqehwagijshnfqjtkbpmdiopruuvemoyzpzzxtwdhmrvztmqqjupsggxzsrctlvmcywudhvyqfeoamsbvuruqvtjbuiesgazjvnsadnjkamlttbfguraqkccpkxcnaguatyxcdopojbskzwhzdcksdnwtybxetkbxfuiznphwpvmjypuimwwxuqrtptneynbrnkfnlrzhufcbybsgasefgwicmhobhpcwayumyhrigdkrrvtyzejccuynjnhduhwucrovrlljftkftjeivjszgcfwaclogrmzpnknypegfoqdmtponqvhooxcsbfekdrjmqauobbagthkpxpnlpichvdxsuipmkmiypzigoqsviifyajwauusyfyluzzycpqjibzegtmaswmgwvjzzoitxgqkutzpdigeimqsigqwioplogfhoduhigbsdxmrafbwsscxymudyipjeoeiptqampcnmppebhlyyvdmfpwwwenfecaqbupfwnwahxmmpbpmjllrqxihyqpnxkomzckqiltjwuvlwfdsoijgbdzuovsveadftbjzsczoavpjintibxxofuywbeqwpjwfdqiffwpkoedyuysdfsolgvzcqxlpqjwgsryjsvasabpldzxigfcuoivshlzcpuebihbjlaeegzxigosgkrzuvppurhwjbcvhipmgudhjvbmcwdghobksnqvnfpcvpzbnrdkggnekexfvwdhflhklwmlsxvyjavycihwfenidttavlblhmjuulqxvpfctynpxgmhqsttesgrsfpztrqayiukekmxlvdqhibkwmvdnerjwnxuigjobmzpkudysesywbgwwngzhoibxlirhlwajzduxdohlxrantbbmaxszijvkhxjmpcpffoimlmsgxwsqwovopcqjdlmtimvhdnghydgwsakhfpultwbyypxgljctjgckxztkoponkkjnzgrlrmqnqdqwgplkcbkuibrjhbgzmedrlezvuxkkbrudvrctlziqcokyyfaoiiklvizzijrpgjffjkcjfxgvtdatdhdcrvgzkochmuyuypdwetnzbcovkifnmtazjizirzjeuvwqxwzcgodwlkzialphwglxmxshbelnrqxkdcmmabjxufufqmsfubfnyfrokrtmocnozgksthoiuqxewsnxiofkzljmggwvfklhofdndsyijyjmassejqnahnhvuuivmolxeyodotlmmrwocqvwedtxhbhdqbdruuukheimbnwowpsezsndzvtkpzzdrzirqzzwvonpdkgwdzauwnljassyoabmmmpesxipgdxrigswfmjaxqrghafrnbcwfsjectpdsvxxmeddmienajamrtsfkupbuvdxvmxhxgshcduyafwiufrulwsdfcnecidgplvfelejdlerppqgowpdtxkwunuszftmqfdvsfnvxyvfamfhysnhkgikmpsfjtixwhzgdwikozqhxsxphkgmfyqdsaidadsjhyidfugjpffzwlbzahexqucqamuzupcabgpehmbgleylgkrpovmqhgvlvzzqhhngzvuaqcjsfikveaboqmcoutkrggfymzuzyytxexpvkaqkcdcjxcdkidrxbdrfvgoukvlpficxbxcnccrwxvnecobxexscrvudvvixetkerpcutnyxpnkgukrplcfivqjaivjwushgcczcqakennpjlldifunhxedefnlbrsgzgegaladorxdihlptbjvlbyaynteitoyamrlozcfqwzxhqrpaezzbwwlapgendofzvnooukpdzqjcgfobeqmmawiahcpcwqxxxekyqyopervwxjpljrdajtundlzsophuzrifoxdkuwbvhcqrimufjzssmfwktwagnjoinabdhzyjxbizjuhmyayhnoqocdeitirwfbrubhhyxkmnbjbiccqawgugkkxnsijpukeoqhcysiooqretghvinypdhmkujeynqowuwnuxujqnkyuforggxuzitnqbkjxjdwiilsnezbwybunfndpsqxonphbaltvfpequoahynmvzfhxwabozbgjlnghzxcmepwwwvrmpogoxyakktqppnjfyiapxltmqfdpfuakbwfvfnjtpwupohecyxdevdzupnwwoeqhzikdjmhqocqxjsowjwgkrbmvdklxicugbofrjayeiktmlvsklhypceujorzlloovsgwfumocdciwczmyqhduhpeomiasdhkmdfqzsolefyineawhnbpseqbgodakhlwkcaahewnglwiipkaoszxnppzfefgejkpknhasvckmstyvpqjxrlpnuzadnbjnewygflrzphbxcwpzqvqapesvurnkpjhqxvtpippgkwiyteuhbfsmzrzigbfnuoovqxegrhgycpmyyzpbycdgfcawstmhiivivdevvtigxrhpgzivvfzgsthnbgcqhrrrqfqobhbqrvfbkjkybmbycbpibbmbfuyzwpmzgszewbhxnrxzhqzlhzlciyzghyedicjnxfzkvlipgwvyfkqgqhvjcnxpxdsvprbhtwlhrrvcuxohpqrdwdldhbyxappxtmozyejiiqqzxcuwckowsoidhxbxcrzsuwzsewyfgbxablrudhfuevvwdhfjvoezjfbeekjjaxuxtsucqqdikgauvlejtdukulibeokpdmsimahvrpoychlhhoummivqigyyhyevduwukmxznesypldomzohclxjgwrssfwvwssurdewluxdarsszufoyaktypfsrkhtjshwgrhbhbzftdlnwovhyajxosoeyjuwhtwxaczsivuaadlretkzvkvagrzyidehytjsptlmugfamydlalxfaygnfecgomnsikgjfmgqvsfxudoymvfxzijgwqvnycqamwzuhefgmdktsunoeeqwgrehrmvcsdxswvhyiyomkyojttdruuykpyjsxaxrjnugtdzveuqvzkcwndmchbgfrxfijftjvcqukzdtiowkzbmcynamwozkfubolhxmkjogddswibizdtxdityhzqvsjkfqtokeqqepgsbeuzuogtwmlthnvnivgklqurhlxwjwqsovfycffjxyberxyzbzlaoxifoxvhkxmafqqmjpfymvrikyypnnqrzmybyihlnbsnyzffubtvyrxypevimmjrsndzzvuuyzggwfahuommpthdytpaoeecvfwvnqgybvpycdarxkcxzpwvkiwzepkzxcubxphzfjgsofalhnaxyklwqszixhsltwkcopcalhryrhqclaonutqfsviidakzziedtrrlboyheeyldjurvculqlvlmipczbduyfjyovkahajcuhptspdkjnzprcsngwwonydyiqczirklctekfhbmqsljxelphlrvwfxgjeigfdztbrpyjnxrzgzyacuawuepmengaiudrsmupxawnvifapqloztflhktspwlsgbrrawuyqqrnnpwqgpfmutwrznoqsnmqechxyqnetwmhmowgmozcjbxvxkjycqpcuzdcssdcoyomnlmkpzklartpjuexyfkotiuxpoewhxmecujibwsycsbalmbyoxzgishnsddluvfongvvvwfleltcuzifjszdzrmbdiimmmhlloqpqgacmarxriehfuxsbcjmyhqrcrganuhcqqcaankyqngqwxjbzmhqvwqqnnvulctalbzgjznwohcuatojxxswdskrlwamrxubkvkcukkfprgknmigdnocbeitacepaiuziizorcmxnxlrvblajrlfnyrpxouzapirtmcfkxtxzbufzzhuwildyghmebiashtwtjquabvmsgxkjuahppukffxyeikzr\n",
"output": "5\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4780\nbvgncsnmfyrynsiecpxgqcmryyjswiohyvekmzyniblhaoctaberxrbiaiakcjfquhsotcbohjazzceeacqffillqfneajdcloloxkjyuibrsbdfachvourttngafggximguovxmuqnxyqbtwdhvekouavyerzcfsttcnvafkwylbxcxyqyabciktzgvkoaljioppaoiwqzexkojxaeyhkjnsbmxjrhrjsssmwyqcpmlgozwonlvcrqdyisslddarsoxaxoxbgtqmvnexdyjfsfqjzluubkjgmsskaisuxnvfenjdxbymjxnzavbsvbqmymsvdpndohdkmzzxodyywxogvcvwqovrkhcgbwalgprnimsnedemivusnyrouendlmoeadmyxarbvcmxjfuesvgdxrfxjcfyahqgwqamzgsgqbkngdhymfiedlmosqxylkrjpuezcxemqyikznnvmgsphzltsmrhzocxlgcxkvvylwkffywvzlifgsgkcneuyofbyazkjmidpalypxaombntzyjeuycusugxrzefuyqyjciytyzmziorqrfoopofdkyrortghsudhqvkzalpceclqqdwggvnnrgoqeepfqikwspwewftwyhuzdxmlewrcycfnzwjnwotrjqotohzuqfrbbpvqacghzcglrknbtazyaoauywfcpbwvvpovquugwdbukivvmvbtlbjdjocyuzxozqnosbxkgatyoshwrgldhzenjvdzpwnilnywhdsnitrzpzicfjizferjebuugigrkzsekiezuofmdcfnsqepxxvlsqbvsravpakwthvqbudvmzcvsizrdohxdwstffbuakelqzfofqebduguxcfmpnpuxwsgrklwbecfgsnvwcpnmchqdasiifdhraqgqiempgbocsusbuitparaohwhznzebivmqgxempvmakiprrgzvumgjtedihspuxrxfykwdgzrymzqgijtzfmdwugkiyjxuwudwdaxnnmtxxgskzfkbvxqjryutwerxnnyroeyzanrqeiomkvpfsyptxhyjvsbzdatvrcdaojlrzrepuasqjterustohkxsnmplooqpnbjawvtryoihvoinezfogkacpjmnpnonzgqeqnomahqmmmnyhruleazehhihzkyqocviamnncuiyqcdyxefyuokkxsomzbcqqfieayohdawhkairmeqjovtlsebakqsozmeccbregxgbzkyttjsveqtmpxtziizuqaxvjsxunzphvzpuilasznydmsanjnynilnekkzkulycskskhuqgmjjcshzucztqhjztzpnjakvqhvpurtqrxrvfgtvgtajlnjaqelelqfrrhrfctsbpjftdipoujewmrqnsibayillvfchonguuafadyxgsytcstiqjrevjyfdksurvnlhhifvxmjwfmsyoirxgygfrfyzwjlzyunqczuxcbedulbvufkmoalwpompcnrepbnuvxbcrwyrpbznywrejwmmgnwyiqqifeqnteowapxqemhqhxpmhbsihqopkdlfmczhvdwozlbbyztwytlepaxufoeitsmvyzsedyszydqljsbxxipqcmzqcsxwifhacnnmodatczuggoydckhpgjhdmksqhlfonfuzbbiemxockojldxkwtlcsgyfakfpykuqwezwjvngqagihbnjzrhmpnjsgmpjizleqpxnddidffqfvpmynoufhleabwrddaimnimwcgpcpkgnwczroqaqjpfensewsvzndshfcfodykzanykpkrnkljgianxblhapfyzvckgcdjaoixcjxiwdfjgmenqewbowzortduqvttkxxwenbwndzacdzobsadycilmdjditmjbffcyzkpjrojsebvjxjoyptckrkvsbszpqrzounffeboudrfpfbaitupmnleyegmbjlvpomllwexvdnwhmqbldnikycyhqtrpqvjlipqvjezngiobmyeuhrvkzknqzhsgmghtnbukalbjusyeznetlapjmakfaibggjsqhjxnmvzwufzpumgnsrrgkypntzsreoddkdkszonyplcqxfcqltthsqvidtgjokwlssmlhoudpwyzszqaihulcrzgceqodfvdlkzvjzvskyqxkleyoqahsmthvkdqcxbopdvzaswszyxbezvjqjxdyvjjvxdshpdswilzclvvvqhpkbkjjbdvfevwflykcexjxksdrbdnufnuzsraciafqwoxgwjxkgtstuwecmdbudpmrerasogujahwlmsixtufywjomebyraxrezgxxewdxmkyawcbtsapysibhodefwaujtefskymhwgxyzaiialjawkpdhubsndolqslzdhmxpyfalonaepbnzjcxadeonkvyqdtlufvdgmuseknvdudbevgwfwcclbhssqfuhqtdnisijdjksiyynbacsfllpldramqsiupkyajrxjmysoivculdzrlnsdupvyfqyfcrudqlooifdldgocvkdlaxndycevqnmtnswsjessbrypnskxeopjsrsodlrthwofoqejpwazwplomkewndlvljnsmesdxvsvhwihobbrbjurqipfczoqjoincrcblwzfochfolrptagkssvrcxyfjxqijjhfrvxsgyxztjjnabisuxsbowxqemqmjnrkcvulaoxbjrhqiosotcyvairmajcukvepshwieniogihbrxiskvhpkxubzvvvieaoxvfojihkzhgelhpsnotcfoybknkitufwzgvanvjhakddkayjmsnxausnirropjcdcefoottpinirtstukapitbkornudlyfhuvusbnqqfubkknxbemrxwvbwxyzmqujqexgahjswnifygduawuuvehpjhjxdqjvyakbxnjtioodtooswyddrmqiqqqlakfbpyguwnpucyfllkfspmmqnqqdgmyriywvobgvthkgjrdpmsddenvclandffvmwwqmfayvpltrlsyopagpyymzonkjvwftydlegnqnleqbcnxtydqymciphzopzqzwcyubeyvzthmpmromgmyrxbjtexzhmlwrnvjfiycttaqkjqqngwyrkppuvujfsbkwgwoaewrsfciapquxcxxzmxghjljebxfwriiqxahpwpozxfkrsnkuxdkuzbejcwwqzeawrvjcjbsethstndplfonxlvekcwomocwusxtzsqjowowrdvmhttyozupqzzrtemptgqztmcyjjrzcrcwokcwagequvizmsrvyjxfgvhvvqowrkojvgvtaxrctzsahxwsppxuaxydxrlraftrarlluwavowdeupzlujjntslzjibrbfrmpsilinkdmvzbxygthbuohaovsohxvnkqxxqupdnxfvfktkamthxqelehrwdflskblpveqbfykbarjfqgnedthqugsswhnqmsvpdhrbfurywsungjofobfnyybxforzcmtxmidtfhlujmcvlhmwbqqrtjpcwmcstfovxzmmaikvwgfbzqjcyiagddtvnhxjwpvepvyppmkscwulwfqdzpcswcfasrkfbxwtunbmcfzqjmrmxqffjushgevmacdzqfmqoplprvjddxrvndrybnjhtuolicftzcnzwxsvnhicfgieubpcjaeofkpxqctbjvfpysbqzmxvqdqjkrtftajjtfwazcnnbuzsfhypfeociafjarpacwmehhtiijhevjkucytnpnhkjertloxhfykfvoxpdwyridkfbrfwaslammgfruwqkfvvoyxgehzfdehxojduzqpesydkotncspqtjtpxvqcksweqgbjveprapesynadwfiwbcvzhpitsnjklxlsblvaxfzyjpekajoykgngqdfrenhntjncaplvapyjwizgtoltbpbdulhniwmhqamtmmkapwdheybyhefkexqqlocjfqbiaghsaysxigbihtycclxmlkunlpafspvuqdqyhlzwqbkarbeppqvhkenzywbkxfyjmcjqjnwykoghqyfizptzqzngfdytoooivpjkoueeeguoqoqprgmhagatqkbgctupcfwwtzbckjzvjmvmzqjbidodkidptuqyvdnsndfnlzzjqhifnquypiytaotbxwrgqbpposploziodxsbhwibvokowylrqqwwsdxqowiclnrcqtsrgyuqcorpgddvoybmwsojqeqmeabnefoozdyvggjveavpdsmoyyrihsdzybhvynhkiimllxyulhcyimyvqwnchvcrmgioymndcbexhrqowmxztlxiflayemonsbjfczesldpxdazkzhfkxyqjxqigzthlofbidsrlvksxfmnxnpclvrcwbyazjecnxzeoiphbfgzuazndrxifnfyqoedlqkjaabryhljbwodqyrnmxnktxzzkxvxqoogndhaeztajptqbdfafrwytkjcajtyaiemoaupgmrfvcyerlpkzewjwivslbidjlseyapvowxjzfkdqitpwilxwhizjgtylnpykoqvdmuuoyitquubmtzwdbgxeqmknmaoaqjzotrrzapoiidserkemabnvpkklbxpybrvnfskluhlniewrocbswvfbmcofrawejpanihrokdwxjminoafnimksasqwqynnctlfxjlgfdtalaasaodhsadkfmltctschrclzftilz\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4667\npfkykbwtylmbbeekilrpvtqseorahzzhcqlbfrqnwqwxgnoxxbateatnkgymepqtukafkgarlkyeomvqigtgaotcrwycbhfhtfvljsczwzuqrnocdbyjpyzvozlbzygsiguctzexphkpnfwzctzodwegochpvukfgexjptjxadldtobslpfthkbglxoetxyovybxjkkiqjkjzijkpozbpragrennhwybbdzwqahlqmxlchdgrvttcgvsrcqtsqmhzgijkqyakqeyitgdnrhnplesmwomnhunokkabuhinruvfqcmgomzmgyruqxccdfjolxhbxvcqvwqrptlrgtstwukxcdwxjunzkwdujdixcqzcuufewiudrstclzthwhcebhrawmksyqowqslfuhjhwkmfiqphuhzyahpgfcqhihksmzpbjbfbqbqjhpglddmnizaupbppkeukqvvcqdqzisctmojdwfyhivscnuwvvvctupgidvclbvszyxbwebvxqppxxdftfktfwyxpicaaelabigtxmsfwnzfctnzgmykurgwrearhyydeyqoqnknlximtjriaqurmwlrmrzrhbiqdmkxhsvwtarwowtqbzswxcqgzcsqozlxwjcttujdxvrgafnlwroxrnaycqonypxqbqxmpxkjkbiwswmpqvjvprbueeheuweojzpevkybipuweufmkxvbthzrojfsayfenycklxeeusqvvzkxsydmubbbacvmvjwqbcwvkmaschyohjxogmqwcskcuemasozgdcfplwrmwpnpmcvgclcplsgtavvchonzmynpgalwbizzrqenrndakkfczfxnmtpmeyljrkoamjlyjxzdkehrmpwqirdaslvlzhbvtiunpoagdebipgsxkyqenvmbtlaenekudttoahhvadzedyauqoxobiaiyfsuibexrylvihrvviatkuxgewvwxnomaunmoedsbhxycjnsraxwwbebuyptxiqbetsmcwbhigfsarxzoypnsbgznjodhxaubuwejmwjxckekucqjwuhtsvykcxsejdgkrqdlsypcywefadfsrekiufffrzoumkiolabscwzpgjjibkpzymsfhzuhcnjdpntrtandpwtlznptybdvywairkotgaxvpikrzoctuuobxcukalxlyvjrfcojjexupmetpzgshzzboyrwswejlgihhfebrzfsmyvfeavoysanxkvonlgxhrvxgeqjcocizejyldfggthwnatkgbhunuqvyoseeorajfhhcismsvvlkhaqohdjjwpebplprxovkfvevmyxwrxysjfdngqumkzedxiuunbamgwpdepiqxhvspveqnysagvfirbgdrphkvfzaqgzrhxvdqwfzwcnfkvbsrjedeaaebwujvwwubmbhvxjqicrwzasomdejmappuvqvflgbezlolkymqqqohrawtlargnzwevrkifeonorazjqwyhioeaghufopihjdopzusvuoqdslftckgytmitkldhxfmuzahdypvmmamvrlstphdfccnkuqfwkuhzosajnrlwxwxtmixzjbdhhwjmzcvphvusryccselvvcvnjpitcwkoyzzgevhuvddyokqluadyrhqhjjdyrpuguemkjxzkjmgurgrcosfcskualmipffrqapyplriqbukuxsbfgziljpjdxtogixbzidvvqvbghccseprjifpbhmccbogcklpqkqwcukiwjuidistctgmfbqtogfgpyjzdrkzabodpkzwjhcremzooekcrwfrbfbgewfdbnlznxmjepbaplbzaaigfyjebaavlzplrmtheupwuedbpgwddrocjvxpgcfitzodzrutuoadvhvmydkjawnycnpewoefjmjlrmohbabcfqrbxfkwmsqxwiqjpjfblecwizqwzjjahwgzbbstnnlwthxddrfqcotnypqxtylolidvykdqbxsfizmfijjymtfifhdkbwrqyomzkwszzjqosclxwnnddkbvxndvwjqehilswrrqwpkflmlcsrevkkpaaicdmapbeufukmqqwekpzaxfqaqgwseewuumdlcqfhvbffualnuzrntyibbxwrtakdzhvxfdxcjostoamsrrczinbwuaqvwtmzprewzibllujzucpxsikogambsosxvpqankeequrrflclalzbrwjpbwxlwqcrgahklwojosdvozaprcxdyfmlwskbgwbzizwgwtkxreffvpsmuhtpuxeuqzozcmswcchegflypiojpmiudtrdokrqffqpcjnhuuruhmatkhdciqahugagcqlwtqkirtlohavvrqhircnsszhzmyxtwyjfvrhhgcckhoxskogeiholoxdaanschsaukwpwvuedwwjpulpvcauhigjqwflrejtmswmjojithnxryxjpoqgkniqmccxnrhfmpvbjydtrjqgageducyciggxujzdiacxpvzdlcpiydphqlfzsokpktajproxomtkhooqlkhlwtwabjdgtgeaseyjgerlrwtoeyaehtkitjqspkuxibzvjahynuxalwvrvqfdgvrtxhbuqceafyauaowuazdrootencajhggvcquirzejfydxfirzorrqnljwiijuqlfpifggehvhotapkocikveffghvepvderhpcscaxfrsmnqztmuhwgkfqxcooiomtvufwijtbxuuxfqqrvgxyypjeqbzpxyvxrimezoupahpxxmyvowjexgbgsuarmldnrjfrhuphcapmkydxagdxwsjxgiwyidbgnxqsqjvcdoedhvyuvtpuksmnuvwdcqbeusglgvgfnatmualjfkwibwbaadejendxnbdwnjqfywoehnzutzlxruupjmyugywkekbwydzhcamboqvxnjwvdcpgowpybwvmxkeqhofegrdryutbqgrvdnxmzbyqmdsnnqwggvuigqdecalydynzwkbkasfftlmjvwnvicfwdvwwyuiuyelkphviyxsneyhvbuqxuzaqnqkhteqptdxlwmvqkzsgqavawpzucvgkwopsozlttnxedswvayadotdoivuzlnlrsaupbwlurgxhtuvqwkajwuolxyeretnwxqbcutyrfymvtekdxsmerrwpkyyprtsddcxswyuwrjhcddzcathedjzqydmoametbphchwqczpvbnlzghecmonomijfhzenrrgzqvwoqensfkocjahjddtspsfhhxfifktrtqktcbjchbeziswgvpbqkmfoafbljemlusngsdbuowpdgkxgcavbocmyvhgmhdserdrbwyyvdbtaxupobmuejbdjmwuiuvwxcsyojixxdffwxknsxsvuykmvdoqkviqmnptqswkmmvpwixnswxgtvjjxnzzykicmnbvhdqjzwxzdqgqtgaqssybzddblqgrchpylhfbyqpgkpbzcqsatuispzoucrspqzleypmfswktyjclthgcsqseiistjdpzughoorzhedsuaxufybfgeyqxniwiavfajtinnpuvikkgtwwiiudeamhvolaoxaowhycvqsugqvtzfsmcidrruplseioanzmjmtnojaizxsedgnmkghlqqugfhavmnilfyorfppeciuefrurqpmhhxrcqdtugtxhinyspbteetnwebninfmmryaxwmlvfeyfkviskdsxvohpjkxjjowvphkbqgyjalchbzmiqpqxxcknuklmshdwrdinmdwwnjmsybhkkgysxriejshiurrhfsglwetuidiemuahxdkekjlruphkziuvnyspllejjutjvmlaxsvrsashwlaipsvvospwrodhxcjrtdotarnbpiluyqdunknjrnalciiuxwsyvxhmdmbbsdlempcrxfkbqanmwwanecfgoonhvsexeubmkdlcvbsoaiptxkymiztkoufvikxawctgxyfbmqydwowvdziqxxnyliznqvhfjtfpqadglptembgdphurkctdgesuufjecnislivoqhtfwrudnkbnpotxytdybynbgvvdrldoocsrhfrkoysdlltitucdnfyhpvywitukyulvbdhcrxdcjdwkjftsoojdqsxmowquieqjmvwjendtdnnxbmqrlgknldmcptqnufosuerfljsezryptdaxtuvvcawkrtrganumjbfwjjejkoijwlwowwxoafuekmyzpaixbiciazmadmhhztmwsskuahbxtoykcnoqfjcqwifyyfzuwpvdkeknyjzyesmqlldmhhcwljeqfuxepothzzbdslgjjulspvadwflitugutscpdjcopgzkdndcdnrmwsxzgdbbuwkriijrxwwhemygmooutogkmtcbfmucfzjrnyagxdfurtzoxmqcbpjzrdimxyshatbarshsfuditrucvaciuchetqedwjfuwzpwpwgessxyohedchyceeihkqapuevcwmjlkpictovcatdeyiilhiamfmobmskqaxpbhmypkjcuqqmloujliycamfvkgpxwicihdfczjnyfbfkgtufhykaivjmcltfxfxhbefrkvqxpvyyydtouotxwf\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4679\ndyatluwtebsuemljqmksdomkyuytgbzssasbqijghdunrlxzuomdocamfxkdczheudbehofntlicymsysnbiplvqxeppbzijgbfadrnzrwnwwxxrasnvxdphfgwqzhbxuhsnhneepmwsmsieqrxqxvxbcobjzeyyptzphcbmwflyskflbazcdzpuypiivyjodqzwzkryjyiomqknksompnaldaustxhbgbedyvmegyipbcobxcyqosxtzwilkveiwceighdxvjuqkyszowfgphcrilynvkjzhrcufzqohvmdvvoxqcfvgmxxggcqsatrpglwfbjxzzdagyxuwnsurxspmrlumggcjibkwcrizstomdzlqwwvzxutqjdnhamflgumqfhehqyudikeizcprvekmayyxbxtifvbqsderlkknuovdpacptflvusnuzvtcdztitvuqgjsugvveqfspizcwstvmmaohaqspziinfhnyohvjkwgaaevbbnijyknhpnixppvvdluhalrgmxtpdzxwwnwwrywuuixbhutqjllqtrjkzcbcxubsrulpxdmogptedakmbrcamcsyvluyietuiorurziyfnxzwvqapmezpefoeforkcuadvsuxwgmsjphktvacjspofqodzhlgerjxctayxebyfarhnrttwoheajrhdljqwftftcqsdgfolxpngfmkiepmsvaecdioavcvnwdxuzkjawyogutvzlgwoxpyfjotzetybnldwsrgjfpsfssxrtbyuvonyhbugyfefvoeaxzvihocepmnhlcdypqzlicbeqbhthacjbljhrrekardiqrmaeaqavcrlgytyulsrbzfljyhhpgtlyxzxrascelwpudgxlrmifpfxhmsbrmaqzromckuajbghnbqaiplpfhnvhsxkdmqpmbyzmbnypzibwkwhpdnwewsxoluonlqaqvyzjgnjdcbcrtquspeewzcodnadtgvuckichbhotohnjameyqyozgjpvcuiegtmjjewtsnjmbcsgvnwoznknwrugtyxzzqqyqtxyojciewzyvmjqqvieqsvygscadmyivqlmqsnhmpqpldndodbwuelciralhhjxdxmzazzkihupbjmerjekauhqjharbpmpuerqgubghfesupfnpatiocdvlkkuawpjvmwyfrdtspzfadeocukfzfdkaymjjvfmlewxgbupypdujpcfexirksyfavvvwbqonixbdhrtngstwjcpzvqkrdnqzlyznuipuqdvqdcwcbdzsegrcccynsmpcxpmbongfpqkyzlxfuoxdlwhnmiddbfzrweriqzslsqiiezaauehzatmuwhlzrdhnmmhktmvudvlqvgfijocmakequetdvhejhggfhfzkuosyqucknaumhjbmnhdpuvoxosepgmzmqdqjqxkixcvlrangpowoszbhnjeyhbojgufgjzwkmczszcmlsetzxmuxrtjxwzmbaupvfkmzyjyngfiooecgwxtsnahwixrgqedsfnuclquuvswfzqfunkhjpxuggpylhwqwqgrbpkquucsqduqupzlrtpdkmuucydesscaqkxectgnznrgybvhmkwcycszwtilwtvvgcduektbtflicnzvgsmeefdbkcfpwwlgsmlnwoqirqvsythycvhwrewboakyjeuqysncxeyopqsfnlxegrjoyhkwukducxoeigmhasppqbimwoaxfwyaxuwmhcbzbdhyrljfvhjlcffddfftfwhbqmgvambegyuniyywxbjvvykofygaeswolgkglfrsuydrxfdcyontcemybsneknznlosdsugnnpnqqfibekkfwquhxunqbhlotqfnoxeaykibyyszctlqgktrxajsngzeujmryipxoxudygoolrizqvoinglfhpfpqodzcajmtwftkcpbkzrmijgewxrynyxdtbmzseswfmbwtfjeyxxiuyxxpforsucgcawozugcvsixnpungrhefqrgkgxshitujogtjiywykbjioxjtkrmupjzmkgywcwhbbeagzicgocureydnnjqhxyplthnhonkllpzweizpdsvllmlzugglvwudndzsrxenazjvnvoicgkwfwylewrijzsmtfgkptffoyjhcojkpatsfmwzmryeakpwbfayefpopcbzyhqxqexghermalbopmxvczfteelkknxkwtcdeqvlfyqvyyrnmhyarymbzwjdqvuimhwdinhxeziykmrylhjtcllyhbuxvldvqjawawxezycazkbfcjclnihlvanwpdcwzfkmahklyiqxwbhisoeqdkxeiymklbvakvflfbhxenwfbvtlyoauetfakhzkwspddgmnufsfjvqffuwlsbwfcvtjdvvogdhvyvlejbycjlpwqhfdtgsjzjwxezxzhqzfwamurdrvbzqkkgabqryaligwhwhswovhyewpupxbewxnzaemxjbtugaoddbfxxwactkauuhkkztplgfuypyurvhpdbsabrlvurqkipmndwuoaghjntzkomuabtiqblyexyantiuwdhoqvokulnbtoamhrgqwnmttgmjvzchhawkskhkydyhnmdqdskjgdnhvbhctocxjyaruhmlmvbpewvhpkcuucsxxmghuhqszqcmqnnqqswhoilrtbsyqrlfrcjysbqobgovzbutajbtfmymhloshoydbkbcfjealytouthdsazuchozrmltarakaaiowcxcibctvqbgrrnjxcvoigcjmnupcmaikpwexahrsklykorvbdamjylwlrsmwhwvrbblyjatozenfqjkovaernuvvfslputllsfgvlenyrgrzuyueldwcjcejpftqtekdxnzhcdeewxwwqfidbdgwmeyrowyaarleevqrsgonwqdgnkmvrvkwnkyipvzwoclknhqrcafrwdexkrvmesvmulolmjzhstyxvxkttyyoezvzxnjjoeujypkkxwmhwreotmeckduxwppumvwynlsbwixblsiuovcyhljnwguvllxdjtwffavkyxolmbwnfbbldxhcczblqbbifnjjcuhugjbwxjjtkettwyafdhyarmmjharbitppbcixjcmevaudnslzfrcjbbnbtqzxqxvhhqybphauqlrokcxdrdpjvuerksdiudkzxgyzkmmymxlcbquvbbcwfhhvpxibfevjmluohrnasukhftsqjilpvrwykmzwuycgpwcbxllbgwqgtbnkwakgtuwqjoihdrjhpgpjelueooewfwvrdgwfkuutygfacqjalojywjjxbelrvekgancxjdkpsreqayghihaumwnmejbfevlksqyjefpoehcsjjuwkxievaumxjiplfynzsfjemusuicmplpaxvrsbpwuawrwybhddqtkdtyczpsdsptscvnnkyskqbdkurfvxwwqlvkgkxrwwcgfbdxmbafcgxipfkhuihenckvglswbvalbnywnqapnqpumfipcdujmomvtoidkkroojrugcoqaglzmxdvjnzlwvgludeihraslpetymcdjtxbtujkefmvdycpbxndhvumwzhyxauzuynutcmpiyuvlfnsdrbtptmyusbhlerqoxmchpeejqxhamyuifmrvxrgrcljufqyfqxakqwqpmzqmgzfuilaszmvxehxgcxkpsgnwckteiqdzyqxxvlslhsfafczpnihgoyllghtccuoakcozsqvayxwggsjgayneqwraxnpbpfwjfiwetyyhrpcpqvynesidapzsoeqhemnknsylewjabrxocsppasxgtazbmikjxnbswawswmvuswjfniejezrmkmyfnbzgfbaailrhsdkcqkrpflxxizkdfzprkzrycrounpphekwemlrtstnrvcgtmqwilzcgwttapcixpljtkwqrlpcqqoyhohhsineckrarfmvxywzwhophqelnrtmeyddvuoguzqtcpvtcboabjjsxyjzuodbqgkzcspabwaqnotbeoebumsrkitrbchwtugjeakiusvyzstpdpwslwfnfavcinjnmhtvbqvtjevaehehhpswvbmohgcrkqrcrqhohfekajcuscyvgjrbxfctsxcfgoiulfkpjcavqtsvyipwcrqwjbqbgvcibcpcbwnyljammbslfoqbighsotopyhgctreonsgzuacoctceskpkqxycuugomoyqqkashozhnuhwqxruiujakqglbbnzzvtcbkhzkmzjeuaypekpwylozngmnsoljlcbktdwrahnfelfobtvjlpaqygvwxdgipfmgtxlgfdnphybxuqfzsvevimxsbcgwiuhkjwwzesqrllguikfvdomzytzckmulckusgzmlnnxdgllwjlbxjidraeduwumnlaeuanaewacnxfjmnvwrkicoldjnzkpreqazpnwfonfwlfcutodegflfcovjlkwxbuunwqkfwmltcomxsyqdfkndzoumoxhifpkgwgxdicngspujprcinsiagprixkazdihidwacqwhvkufitizkuwmzdisfwhbgfdalhkvztidnrtqvvlxzttzypiqjwgptvd\n",
"output": "5\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
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"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4795\nrtqltsrhrgoszrbrmnymutrobjlszazxovxkgvhddjeaywjmwqdblysydscsereykoftfpebxuzcqyaxfbgufkpfxfcsiruyqoubovmxkxoypeijqswcqcgvypuvvbsxgxuqrjhwcbtnosppdszqyiekdauehrshexlqjdthjaawhekveezcjechwyjbgqcdczqgsoqsoucvadojmqegoxgwdpwqosoyppodaylyivytqqpjaignfqeyendkjpxkwqtanlthwlcacdpcejffulaseikaefitkjpsbjuvfkciuiorjoufyctaatxyhinmxuvqckkbsnzhiucovxdkiosgggdwnibgtnxhlwusgjaxhytkifwhqqzrfbvfyatxzaobxsbrlohgkukurwijfwbfqlxocexdlelxoypvpoozludgrkwtttcpnherhpxniggjwngffmokyjessocncrikoxtknbcqpwzxmknmmtidieyemxtunyuptkesooowkjveqbomubcxovazvttxbllfrgpkrqfhrkybdayevuihgieezykujfmnztiysbfqypmwyumiaznbmwybqdhprjjorvgggnowemflhhoseummvejhrflbrwkscqcvgrkbawjrmgmjfihheaihuuichzrzwioaofgnlnwtiexclaiarqztjmkocpfqjmhnyjuvvphvmmshriovmlefzcfdratxfioqkgtswkvwcxbhqqkgmssnnhxpqzjnaktehxymleyyegkwitsyulakrhuwigcxmjkbawtzylodlksiveqmcmuttgrfbbmbeivoluqcossknjehujfasckiiyqqrzppkpfubqekkreuftodkqixzcfetlbkhldixhdbfgnnyltfcleirintkagusfbyufuhbvmnfshbueejjdftdtomtadegqdqxwmocmagbiadvdpdxmamduckwdpirrlkwagzibnqpjoybduobvtdywmlkswfplwzhbkhlrobsgzcqvkfmegnuqyhgbsbzeszweoabkfdztqrisrxwdyltlshmmcecnpqcqbcjfjdlhlmzhtpplppsuzdzkdeaygmqnidrecmibpwhgssgungbckwtirxprcdgzdhvqauixrddywobquanfnaiwepeltbkgjqszfdejzdtkjwnjmblnglpmnvotrfrejbhzrsqprvmgocbpjanjswjfnpijmzcdfpmpympapyheyufgyujmaqqmgwdpwubypagibnxhsqanzlzpikmyoqqzqeaillvjxusxufaejzbrvquefzrfawigjtgtualmccukobqqiczolvbctaoudolerrfefposvcapbkpkmocwjgokxadrmqvocimhghhoijgcjqxsatgfwgpwctbjnjgcpqrpecnucqxsurreqzrbnstmgmbroqxaykuhaaiixbeyagdsqohrsmprpfnzurrdveyxmjjfhyzgffehhwujluhiucphedycnzirxbgqucfzulvuprbknvthxasiysidfrcsbqnzmqbjntwnkdkuuakivmdlesaufactwvdnzancrbhhyvkeonejhoiitrvcxirulgneyirvwzsvtwwfnhhtnfppybtoulakdqzgnadfcwsvheoirkrxzpjjvkoejtbfpcueclgxfhwdtxioiuuuyavbwpvqurzhysyjugzbxsixrgfkvwgmpinniuvddnulzcvoygyzkxlyieywhhqvmfjxywqhloikhbvckvixdxgttzzxivzsnjwkgdknhtuyijaifzhwmdzuglikowfhxfdyyjzibafzrukrtlxfmzcgppdxmosvrjobnqhcfxgmsymjyfawnhdrpenkynfrdbvbmqwziiaqfdyteqsknwtbsobuftghdansdnqqvumhbvchjdhzwbxeksalutyhsxxixacuugrlzfjhhesjeqzozcilhbowjmzmubddsibvvpewnxfhxvablqngelgwayrduopbttluagdvnjlumtbyyfawsustzvaleitfdmfisldealwdvjivdqrldtrbvhzevylovzjznkekgrikbdpduxvueigskxizpkziigixilsbvxzzetfkskpfsrtupejbynydqhzyinfvwqdwyouqqqrdkfcklbxgzqvopvuomijnwagmtggzysjcxbwpbpsgvbwmifftpkemomnkdkvlkqjoabdxmdvscylnwhxeyzhsuhaqyndamycdstxctozcctbzqcbscdsrccnnrvknhhhvfeyvlkwrcrfgjhhzjuhvyghbeaduqwhwfpmqmqscxdheimsccvhatqbawvyumpctrmjkawcfprrrenmrbcfashhsddwzlgiwtmiumwxsomwrlifiagjqjhwdrnhjfsaeabeetnmktknxsqieauoiruhxgujqfkmyndfqfmyypjisjikguqauslkjwzqqtytmetvjexauybboqwleukrvykzdznutaycivohfxntogcvlcnxsnxdyvegleybgmtbyjgxmpubvkmfqqomlbhennqeivcgnxuyzefoaymavnqdisxicgcquisghrglzhfqerxzjmhtjlwhvearblieirwcwuhdueelejamlkvlyucyrhfgwlpmkajzywhdagutzrabxywemdlzjgrpuvfokjkanhwvlqystagxnfpurlqycvjimirxbvtjrfrhhyiwnjqfwyoyvmldqceeibfkjrggucdlczafvvqjfrzlmchpnwmeizuhqzmrujuuberquovzqwjdeivhuypqzmbhxmtnlcoxarajweccjmtydxtboakmqdykdzxpmccesqjjpwrmxsjxihfjvlxbpgbmxxoxvzwczooplwekaeidokfcbljianryutgyyjnmvxwnqvslrymonhqdnggxcfupnoxsqgsgalgpyuiqhvhgndfeofebwvykdwofycvokcsqmrwmdksidumzufvucbpzqawtobknvoqmmaoekrirhwovpixmdknmxyzwfwcdejbflqzvjcarouhraseqjyonyjzwvvkwpyghavczzqxyfrvpmiftgbdbfzheglicmlnkxebguzqferyidtshfaardkdaokarspcakwjtceuntyishxambogxhvwpjspnanuixiynasdcxnpbzstwyoyirzrjtxuvgpqedbikssqkhtgmuxppmpiqepcatnrbpdelvekgvlnmrshyclijcmmdsrjursqmcxoigohaeckafumdxdwrjmbifzvjhheqdebjobxuxqebaaktqwnrvrdgufhfyaapsbesdnyhineslxedifspmameygfrzcenbddeqvvowfujovyozbbydtgytnrvivmudmipvfhplnjersdwhunbrwnaninbehpkpyyyxydgxqzqjxmzrtkqvatiyikehekyhqgokpwuoccmwlpieuitmubzaptjxmbaoawwgufaunucdwkykvhflorabrjqcncndrqxbtbylkncjqpjzpfftlubwssqukkaoxngrjeiuwbjdetfihyrqvhydysavrhxrfiqqibtvdfkglnjmrxolyuggbekmzauyubfbpezfrdlpdxkpnesgjlmkkaaxcwjchuzsbhcdtjsfasolwkpnvxwsxjikcrfyhcjgttytvwkkfsnvdsqrzklegodevjjkfevkcdxfwtimnpxaigirpqqgkveqvzdbpcssjnjmbooukbioxkfttdepqutsyoccalzsvnrboigrqkixbszltfmmqorbxtzpxjogicuuhpzxiydaxxluuoplbiviepuqwwxtapanxtyqjssmvooxxvpduieuapllnxsqaixgtlfpjuifwpbweydmhslavefxtdaicyiirmgkcdhfufgdzalimnbbbsulaogfrbrmxvcgbvrlzrphvszknvkpivqdyyvbszjhqxaolwrwgzszpouznvzzgofcjopbhprnbdqcwloukjejvkjsdmclfchfzladcwfyueugcbcdlhepymuedpyaspwuwrlgkinndunnczqaryyemjcogptmtnldhsqqkngyzgowtjmxzxatrgpzyjzznlggyvyhqermcsdxdzoxuuvuyoljrygocyiecjgteuqolkqagbzhkkelezstocsygexcguqweglixpiazqmvrwtvqjkrcpncvzrkeougxllmaeqwtrxzjiivcnjjkwkyliwhqansguudqzgcoiuwegqrwrsogrdwykofqdnegqbtptwcuaofkgmkqwjvkhjirdbefzqhjbrplcvbwqcsjlqepfecynexqpcouocuzkfgeqhnvfkzsqpnwgiodlwywnznknthzvgtmzngdwufgvrybxmpohiprxjffntkjspzofeccwttxnkwmgcjhqxxpcrbvmnfoodjtscvjrozidlxcmnlzfaaipttdyrlxwowxbhzjidddjvzoszmakngcirstairyieskmkrwdwogvxponagoxqwjnxgilhofgivdrgywjcrwwakrrirtjlbmjevtfayvjpmzxrakoiuqwhaxypbjszkbjjxsqvttgtzejnlxikbmnffqtzcoknzvnaczhtmtzcbcpoktbknohushkbabtfkwjkmkruzfwlxomcnibnzlidwjafkaryhaewoikarhwudcmtthqibekcijizydwrhhrkgoijocwsrbphbnzjltcxxxiamnhatr\n",
"output": "5\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4769\nolqskmcxpmkscyglsxczfxdzzsdsfzpizrjkibqwfuncxwjhuvgsehkyonvdiytzxivkbaqsgstoqgdvjifmviyaqcfwijcogisndwrtnnnyvsmlkxgritqmvkfqjkjslwzukscmcnzevjysbsedewysmzpvlmziycznqamizeglrjtlazdccxrbwdozbrugmvcakidhdjryrixgunjoymorskpxhlamqoacangnnhwtjjfgavxdlejkaawrygmdcrhhdcpzjmfjgrdzkdjihgokuvbuiyxlgotnqvigjoympiqnioyxkkoryybwdnotomkijmeusakmooytpmritbyfjxqznaiczwfmaagpurogduniqniqjruxyxrbyvyzukmpgeqaizorfxtgtmtsjqqbrmpgqjdzmudweuhwvortbhyhkiechisstgfgotdtpsnmaqjjwjvkhgizymutnjbyunikonaqjjdrurudsdivbgwemyerrpgzchhipjvsvsnfebqnacmtoryoaijgsfixrqppdcvdputrxajyvshsxtjyaszddrjordcuaoeuapgbionwlqlcshtwvvkhmltokeqbdlwzmbhwixzdgjzodjisqmjxjynyhkamvdkxrhejxhfcldtfvrgzxrqpzpxoknppjihrjjxmdbxbrkhbzcxqawitfymnlznvvqnvmkztnaazixsufdhtwkyvbobhfsolxsovcvdpzcxburxpvsbacuiuglmsrmjzvohlwuhrsnypuoizoxvwaounahvlbbbswbxwormfjqifcsyyrzcephmcbmbpaaefpksbnlyhwezknuywujtwdvbgiozjapsuajrlaplgnxdlyzqtxbwlayqbudrvfzqbwukunhcwxnneflmpjtzntdcjtqrjxchykfxiydgourmhsiiazemgxhllzpebmefayxbmvsxjgjblghvofvsjeldqgiyqqzsigrrsfqrwdudhqdwkxqijcbxxgsgryzjcetlvlbqgjjploqzxijqkejlcpalokastpczaqbcucyalumbfvrvwdvozuqisyroqczgtumdjrliupswgcjsjhcpgnfagvqczdshgheuralepglklvhpfydyaggoiaqssvxcaisxyuhuslzrzdksyvqfoepzyrtcydptzjiezanylsqvajkvpnnuscgluvdjttcbbhnmjmhhjgvgpfhlwwfglexklsgcdbulyeiqwowwtltfkzmbpixapodvugatohjzgkdwwnvbpluynkalxrpjqpxczxhasynjpfemaisnxewgrbryhpwfzixifzekndqqshuzyrdsaaqtfghfhswelryagktwiuxlpgewdybetfbzpzxojwfvhfsicbhmleawhhirmbpzcmjhpnwjeqlesoxyvcecjikhvoqejznldkyiqvrmfpistgjvflktuuubhqnsmlrmfdvfbnlqohgqjaigqllkeeirlgvoiuotxhreypzekfoagfqnxthjvoabyymygyaefzylpewfnnyqpcmykpewzjzvgyypqvmlhscirtcnxfoieduoeydieybgnelpccbnkiqujymensxtreulbamifpyhlvzwlbivftrqvpyrehyuzhnzbnmowlgcscdlznavusrobhqqmebntrqwyltoarhbujrzcvyshpgzaezmvxwzbxdiisvfellpejuwktpuvfzvpngbtjwvgxnxbuuvmhpfchzklhnzoxlqitbzctcrsxqymusfatlbrtgsdesktjgyxyaqancbtwcexglmmmmvkvntfsbqvzclxgukabfmjzfhsgmrhpzsjqhmuidyueifhosnaopakqbjonhfyoqbiorasdyvcbnffpiwexagiksfewvnpqtacllkpaecukvdndmvnievovxbcleabfobffpxcmmojtscyuzlevdictgsznywxjabyukzzmvdbxdapvuotxhqmjgdgjxrnombycydptdawcbbqvhiudjkrsdqjwrsdwxvogdddzkpuxebvytpuxxuqcjpqtcourtxhoxnlshubfgkliazsyfbzlznjtjdyqaayfmebnoarrquvucgwiimrnmffkgrrjlfwmafweewoulcvdkrebbfqqpbfdedrlwinjcubuqapbjckyhstowesemzrafomcsxzignggozpniyumdqgexidchxcwdoueplrfhlfogjcyvhfcajtxbrzomsjlgbmtcrbrsfzmbmwmzymtvxrxfykaazmlmekdkjibtnsbmbmskbmdvqmhtczrenhbhojgmhrnuszvxvlxaxbcgwmqcciqiawwkjzntmeakwtwidtfadpvcjimcpfjhykbtbekwdntgfxskvckjjzhmezvtkdsjomijxyufgcgywslcvffbfuchdywdnvucgmfytfdvxajwehxejpoyfkmwbwayjtcgltqyqrlhjspxdrvqcyqpovayxyxwhcopcvetltyhhtqlrmbtvqandotezjbmfqjdtsejgtsnpfcabgyviiigqcpfhbuizbrtyuqsvitkgufaashfwhwswdcdbrgwszkbyhblrpskirpvnwecnvxytpfnuhnnwujbidpchgvttmuvxdfzliwrpztrrldcrozkgryubbblckrnlirhhlzviusbcivbdyzdktlzdowuaoaxsdnrmvmiaiasorsigqbilwjvcykejaeawcpsywsrxfgfaeausqzofyrofurmfiepqibclikriwtgojqqarpoxjpaoirsxxcyoghpfisktaptafsgsgmnqnljfjyhwhkvaycqyiowqcmjetebdhpsfejqvevyceqtpqlgupxscdrbnnddsdqelqeplzidvcnbudxhmatpesjxemgarijpdixvtovgmtcfvsqlkdctwskxpchgacvocgwsrjdjwnhtsrapgiagfjuolhsjwutjookekjrjzfbgqcempkphuhwrlkutlzndlzvjphpdtlvuywiiwmlzxpvgjccvfoygskzviomchqbpifdnrapkkghsbaetadqqzxzytsngupnjwzmkjswwzmundzyjgqxifjertrqjmiechsjpyryevwltyydibhyxhlbysmtovxskaekdwatdpavbniohopgezdwabvifcjdstlituzynlcoyqblcppfhrnbvdxejokxflijdzogsuxigwwyonzhoadotguuphsilqmlncmrnwkwhqtqdjegbrgqqycelnxgiqhcafsjxnrzmiugvjosjynmmpljlrzyrcvujoejmnajymosbppfbdeejltgfyiiuzdjujcviysqrncokeuglxsdoeeteenrkfvyxptwiywdfdctumobeuyxtqparzaseeonnluxvwclygsutfqowqfupiilmauvuqjjdjnynyqeuyflntqefjoggjkteigeojmthailkifepxutcuswrhetsvizobcdjvxfnyuvhtyinvdkqsmukahhfigtermrbfjzejclfanlxbryyifsabmdvbekehrxcxpceistqhalufowiocxgxvdqhedtmfzybzreyihgrqqckapuxhsiizjjmnmhunulcfylrnuajsleigtfwhtwuosqqsbqtsfjlyvnxwejlupavtaovalhksbemtmuybwrswsewjahdaqophjncyqwmfadzlulmvtodakqsalkrbmvmqhvmoeddxwrdhmhzpjobbwfzqnbawciciauldgvwgriajetjzuzdepngkipfblxgfisjaplttheddjzneimjabohkmegapquvemiykvgeencfgkozvppmevukxiucewbzvtkifrwuquocjjyefloflnghfupihantctjjyzcbbnkzgelbmnzviokrmrbeoukhmssfzsipmrczfnxpbhyeoyqppdawoyawcmtlvzipdaukbecvuxyjmybopeepqlzzbfvxnmuimghcnycjoepiavheudbckqfehbjzzorxgvsclenfugngaxqvatilylrtftjqrvgkeffyubinqtnqbcbgounrfvnzrrdvklwhkugdgzkiybqmjbdykohgqgodztgefddmzxybhqrryagerclvbeketaehgsagkshupoyqldrrzybdywzlwpycaubmxnlnejhwqwgmcihsoytmxqzwvxafmdpagutzvivewnetkausbhwfbybkcuhvuzmlpckmldcpreblymsuddsmlkchitaeequonzwsxmlstyqnkgnahkaaitnxmdphotuizlupgsgzjilffmgrxzmyayslkuipzxcbnnyswarqfvyaxgkghokaprgsmixiogbpnidrzgdntuaqcdhtyqhaiyzazodyjwgwegicrxnfqjgykecgkseorgjzahbmcvhotfxoctvbpjgxffddtsbfvytotlhzelqtsnmcmwhvujmahlshpceqpsumekwfgktkjoseucicinfylhypqxucxkwhazoemrtrhmddebyevjjknpcmynenvvzhzdzrcszolirzmxypdrhmkhaeseoxqcjnkcvfbpdwxkailrhbsqeveyapigcpclagyagcezsqdwssuxcscfqsvwryvllkxkmwoomcvhnwsnbtnpuinuddztilgnsmpiypztiqmnecpiojiskwuyhaqvrptpvhmbkugdafiffzipnxsrlclkmlsuihw\n",
"output": "5\n",
"type": "stdin_stdout"
},
{
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"output": "4\n",
"type": "stdin_stdout"
},
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"output": "6\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
231
|
Solve the following coding problem using the programming language python:
The main street of Berland is a straight line with n houses built along it (n is an even number). The houses are located at both sides of the street. The houses with odd numbers are at one side of the street and are numbered from 1 to n - 1 in the order from the beginning of the street to the end (in the picture: from left to right). The houses with even numbers are at the other side of the street and are numbered from 2 to n in the order from the end of the street to its beginning (in the picture: from right to left). The corresponding houses with even and odd numbers are strictly opposite each other, that is, house 1 is opposite house n, house 3 is opposite house n - 2, house 5 is opposite house n - 4 and so on. [Image]
Vasya needs to get to house number a as quickly as possible. He starts driving from the beginning of the street and drives his car to house a. To get from the beginning of the street to houses number 1 and n, he spends exactly 1 second. He also spends exactly one second to drive the distance between two neighbouring houses. Vasya can park at any side of the road, so the distance between the beginning of the street at the houses that stand opposite one another should be considered the same.
Your task is: find the minimum time Vasya needs to reach house a.
-----Input-----
The first line of the input contains two integers, n and a (1 ≤ a ≤ n ≤ 100 000) — the number of houses on the street and the number of the house that Vasya needs to reach, correspondingly. It is guaranteed that number n is even.
-----Output-----
Print a single integer — the minimum time Vasya needs to get from the beginning of the street to house a.
-----Examples-----
Input
4 2
Output
2
Input
8 5
Output
3
-----Note-----
In the first sample there are only four houses on the street, two houses at each side. House 2 will be the last at Vasya's right.
The second sample corresponds to picture with n = 8. House 5 is the one before last at Vasya's left.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, a = list(map(int,input().split()))
if a % 2 == 1:
print(a // 2 + 1)
else:
print((n-a) // 2 + 1)
```
|
vfc_10678
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/638/A",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
232
|
Solve the following coding problem using the programming language python:
There is unrest in the Galactic Senate. Several thousand solar systems have declared their intentions to leave the Republic. Master Heidi needs to select the Jedi Knights who will go on peacekeeping missions throughout the galaxy. It is well-known that the success of any peacekeeping mission depends on the colors of the lightsabers of the Jedi who will go on that mission.
Heidi has n Jedi Knights standing in front of her, each one with a lightsaber of one of m possible colors. She knows that for the mission to be the most effective, she needs to select some contiguous interval of knights such that there are exactly k_1 knights with lightsabers of the first color, k_2 knights with lightsabers of the second color, ..., k_{m} knights with lightsabers of the m-th color. Help her find out if this is possible.
-----Input-----
The first line of the input contains n (1 ≤ n ≤ 100) and m (1 ≤ m ≤ n). The second line contains n integers in the range {1, 2, ..., m} representing colors of the lightsabers of the subsequent Jedi Knights. The third line contains m integers k_1, k_2, ..., k_{m} (with $1 \leq \sum_{i = 1}^{m} k_{i} \leq n$) – the desired counts of lightsabers of each color from 1 to m.
-----Output-----
Output YES if an interval with prescribed color counts exists, or output NO if there is none.
-----Example-----
Input
5 2
1 1 2 2 1
1 2
Output
YES
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
s = input().split()
n, m = int(s[0]), int(s[1])
cl = list(map(int, input().split()))
com = list(map(int, input().split()))
res = False
for i in range(n):
for j in range(i, n):
e = True
t = cl[i:j+1]
for k in range(1, m+1):
e = t.count(k)==com[k-1] and e
if e:
res = True
break
if res: print('YES')
else: print('NO')
```
|
vfc_10682
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/958/F1",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
233
|
Solve the following coding problem using the programming language python:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds n is defined. In every round each of the players throws a cubical dice with distinct numbers from 1 to 6 written on its faces. Player, whose value after throwing the dice is greater, wins the round. In case if player dice values are equal, no one of them is a winner.
In average, player, who won most of the rounds, is the winner of the game. In case if two players won the same number of rounds, the result of the game is draw.
Mishka is still very little and can't count wins and losses, so she asked you to watch their game and determine its result. Please help her!
-----Input-----
The first line of the input contains single integer n n (1 ≤ n ≤ 100) — the number of game rounds.
The next n lines contains rounds description. i-th of them contains pair of integers m_{i} and c_{i} (1 ≤ m_{i}, c_{i} ≤ 6) — values on dice upper face after Mishka's and Chris' throws in i-th round respectively.
-----Output-----
If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line.
-----Examples-----
Input
3
3 5
2 1
4 2
Output
Mishka
Input
2
6 1
1 6
Output
Friendship is magic!^^
Input
3
1 5
3 3
2 2
Output
Chris
-----Note-----
In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there is no winner of the next two rounds. The winner of the game is Chris.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
x = 0
y = 0
for _ in range(int(input())):
a, b = list(map(int, input().split()))
x += (a > b)
y += (b > a)
if x > y:
print("Mishka")
elif y > x:
print("Chris")
else:
print("Friendship is magic!^^")
```
|
vfc_10686
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/703/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "3\n3 5\n2 1\n4 2\n",
"output": "Mishka",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n6 1\n1 6\n",
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"type": "stdin_stdout"
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{
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"input": "3\n1 5\n3 3\n2 2\n",
"output": "Chris",
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},
{
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"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1\n",
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{
"fn_name": null,
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},
{
"fn_name": null,
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"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9\n2 1\n2 1\n2 1\n2 1\n2 1\n1 6\n2 1\n2 1\n1 3\n",
"output": "Mishka",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9\n2 1\n2 1\n2 1\n2 1\n2 1\n1 6\n1 6\n1 6\n1 6\n",
"output": "Mishka",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9\n1 2\n1 2\n1 2\n1 2\n1 2\n6 1\n6 1\n6 1\n6 1\n",
"output": "Chris",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9\n2 1\n2 1\n2 1\n2 1\n2 1\n1 6\n1 6\n1 6\n1 6\n",
"output": "Mishka",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10\n2 1\n2 1\n2 1\n2 1\n2 1\n1 6\n2 1\n2 1\n2 1\n1 4\n",
"output": "Mishka",
"type": "stdin_stdout"
},
{
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"output": "Mishka",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n6 1\n6 1\n6 1\n6 1\n",
"output": "Chris",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10\n2 1\n2 1\n2 1\n2 1\n2 1\n2 1\n1 6\n1 6\n1 6\n1 6\n",
"output": "Mishka",
"type": "stdin_stdout"
},
{
"fn_name": null,
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{
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"output": "Mishka",
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"input": "55\n6 6\n6 5\n2 2\n2 2\n6 4\n5 5\n6 5\n5 3\n1 3\n2 2\n5 6\n3 3\n3 3\n6 5\n3 5\n5 5\n1 2\n1 1\n4 6\n1 2\n5 5\n6 2\n6 3\n1 2\n5 1\n1 3\n3 3\n4 4\n2 5\n1 1\n5 3\n4 3\n2 2\n4 5\n5 6\n4 5\n6 3\n1 6\n6 4\n3 6\n1 6\n5 2\n6 3\n2 3\n5 5\n4 3\n3 1\n4 2\n1 1\n2 5\n5 3\n2 2\n6 3\n4 5\n2 2\n",
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"input": "65\n1 1\n5 1\n2 2\n5 4\n4 5\n2 5\n3 2\n5 6\n6 3\n1 1\n6 1\n1 5\n1 1\n5 2\n6 4\n1 6\n1 1\n4 3\n2 3\n5 6\n4 4\n6 2\n1 3\n4 3\n1 3\n6 3\n3 5\n4 2\n4 1\n6 1\n3 2\n2 6\n3 2\n3 5\n6 3\n4 3\n1 5\n2 6\n1 3\n4 1\n4 1\n2 5\n2 5\n6 2\n5 3\n3 1\n3 3\n5 1\n2 4\n5 3\n3 3\n1 1\n6 3\n3 3\n5 1\n1 6\n4 5\n6 6\n5 5\n2 5\n4 1\n2 2\n1 4\n1 6\n6 5\n",
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{
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"input": "1\n1 1\n",
"output": "Friendship is magic!^^",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
234
|
Solve the following coding problem using the programming language python:
One day Alex decided to remember childhood when computers were not too powerful and lots of people played only default games. Alex enjoyed playing Minesweeper that time. He imagined that he saved world from bombs planted by terrorists, but he rarely won.
Alex has grown up since then, so he easily wins the most difficult levels. This quickly bored him, and he thought: what if the computer gave him invalid fields in the childhood and Alex could not win because of it?
He needs your help to check it.
A Minesweeper field is a rectangle $n \times m$, where each cell is either empty, or contains a digit from $1$ to $8$, or a bomb. The field is valid if for each cell: if there is a digit $k$ in the cell, then exactly $k$ neighboring cells have bombs. if the cell is empty, then all neighboring cells have no bombs.
Two cells are neighbors if they have a common side or a corner (i. e. a cell has at most $8$ neighboring cells).
-----Input-----
The first line contains two integers $n$ and $m$ ($1 \le n, m \le 100$) — the sizes of the field.
The next $n$ lines contain the description of the field. Each line contains $m$ characters, each of them is "." (if this cell is empty), "*" (if there is bomb in this cell), or a digit from $1$ to $8$, inclusive.
-----Output-----
Print "YES", if the field is valid and "NO" otherwise.
You can choose the case (lower or upper) for each letter arbitrarily.
-----Examples-----
Input
3 3
111
1*1
111
Output
YES
Input
2 4
*.*.
1211
Output
NO
-----Note-----
In the second example the answer is "NO" because, if the positions of the bombs are preserved, the first line of the field should be *2*1.
You can read more about Minesweeper in Wikipedia's article.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
r, c = list(map(int, input().split()))
b = [list(input()) for i in range(r)]
for y in range(r):
for x in range(c):
if b[y][x] == '.':
b[y][x] = '0'
ok = True
for Y in range(r):
for X in range(c):
if not b[Y][X].isdigit():
continue
p = 0
for dy in range(-1, 2):
for dx in range(-1, 2):
y = Y + dy
x = X + dx
if 0 <= y < r and 0 <= x < c:
p += b[y][x] == '*'
if p != int(b[Y][X]):
ok = False
print(["NO", "YES"][ok])
```
|
vfc_10690
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/984/B",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "3 3\n111\n1*1\n111\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 4\n*.*.\n1211\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 10\n.....1*1..\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1\n4\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 10\n..........\n...111111.\n..13*21*1.\n.12**2111.\n.1*542..11\n.13**1..1*\n..2*31..11\n..111..111\n.......1*1\n.......111\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 17\n12*2*22123*31....\n2*333*3*4***3211.\n*22*213**4***3*1.\n11111.12224*6*21.\n221..111.14**4311\n**2233*212****2*1\n*55***4*13*544421\n2***54*322*21**31\n13*4*33*221114*4*\n.1122*22*1...2*31\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 10\n**********\n**********\n**********\n**********\n**********\n******3***\n**********\n**********\n**********\n***3.5****\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "21 10\n62637783*1\n23*51**531\n35*7*6.**.\n.*3***581*\n2.32*745**\n83*7*6*6*5\n*74.**6**3\n323*6**7*6\n3454*67.*1\n**63265*6*\n3725*4553*\n24****5**4\n23.34****4\n55257*1*4*\n4*3253*456\n**.3*45488\n*7318**4*5\n234.*4557*\n12..21*.*3\n286.225*4*\n834*11*.3*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 10\n**********\n*********6\n*********5\n**********\n**********\n**********\n**********\n**********\n**********\n**********\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100 1\n.\n.\n.\n.\n1\n*\n2\n*\n1\n.\n.\n.\n.\n.\n.\n1\n*\n1\n1\n*\n1\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n1\n*\n2\n*\n*\n*\n1\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n1\n*\n2\n*\n1\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 100\n*************5****5****************************************************4****************************\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 100\n..1*1..........................1*1....1*1....1*1.1*1....1*1..1**1........................1**1.......\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 100\n.....1*1........1*1................................1*1...1**11*1.......1*1....1.....1*1.....1*1...1*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 10\n881111882*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 5\n*2221\n24**2\n*3*5*\n3425*\n**12*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 5\n****2\n4***4\n3****\n3*563\n*22**\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 5\n***2.\n5**31\n**6**\n***43\n**31*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 5\n*32**\n4*3*4\n**44*\n**45*\n*4***\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n***\n*2*\n***\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1\n*\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 2\n*1\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 2\n*2\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 2\n32\n**\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n...\n232\n***\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 2\n..\n11\n.*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 3\n1*2\n3*2\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 3\n.*.\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 1\n.\n*\n.\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 1\n1\n*\n1\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 1\n*\n1\n*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 3\n1**\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1\n8\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1\n.\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 2\n2*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1\n*\n2\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1\n*\n*\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1\n.\n1\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 3\n..1\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n...\n.*.\n...\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n112\n1*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n11.\n1*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n151\n1*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n1.1\n1*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n611\n1*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n.11\n1*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n2*1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n**1\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n5*1\n111\n",
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"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n.*1\n111\n",
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"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*1\n411\n",
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"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*1\n.11\n",
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"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*1\n121\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*1\n1.1\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*1\n115\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*1\n11.\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*4\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n111\n1*.\n111\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 4\n*222\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1\n*\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 2\n**\n**\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n***\n*.*\n***\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n***\n***\n***\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 3\n***\n*4*\n***\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 6\n....1.\n.....*\n",
"output": "NO",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 5\n*****\n*****\n*****\n*****\n*****\n",
"output": "YES",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 1\n.\n*\n.\n.\n",
"output": "NO",
"type": "stdin_stdout"
},
{
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}
]
}
|
apps
|
verifiable_code
|
235
|
Solve the following coding problem using the programming language python:
After passing a test, Vasya got himself a box of $n$ candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer $k$, same for all days. After that, in the morning he eats $k$ candies from the box (if there are less than $k$ candies in the box, he eats them all), then in the evening Petya eats $10\%$ of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats $k$ candies again, and Petya — $10\%$ of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by $10$, Petya rounds the amount he takes from the box down. For example, if there were $97$ candies in the box, Petya would eat only $9$ of them. In particular, if there are less than $10$ candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of $k$ that can be chosen by Vasya so that he would eat at least half of the $n$ candies he initially got. Note that the number $k$ must be integer.
-----Input-----
The first line contains a single integer $n$ ($1 \leq n \leq 10^{18}$) — the initial amount of candies in the box.
-----Output-----
Output a single integer — the minimal amount of $k$ that would allow Vasya to eat at least half of candies he got.
-----Example-----
Input
68
Output
3
-----Note-----
In the sample, the amount of candies, with $k=3$, would change in the following way (Vasya eats first):
$68 \to 65 \to 59 \to 56 \to 51 \to 48 \to 44 \to 41 \\ \to 37 \to 34 \to 31 \to 28 \to 26 \to 23 \to 21 \to 18 \to 17 \to 14 \\ \to 13 \to 10 \to 9 \to 6 \to 6 \to 3 \to 3 \to 0$.
In total, Vasya would eat $39$ candies, while Petya — $29$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def can(n, k):
total = n
s = 0
while n > 0:
cur = min(n, k)
s += cur
n -= cur
n -= n // 10
return s * 2 >= total
n = int(input())
le = 0
rg = n
while rg - le > 1:
mid = (rg + le) // 2
if can(n, mid):
rg = mid
else:
le = mid
print(rg)
```
|
vfc_10694
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/991/C",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
236
|
Solve the following coding problem using the programming language python:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one. $0$
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you like, but you can't throw away any parts.
Can you make the number of links between every two adjacent pearls equal? Two pearls are considered to be adjacent if there is no other pearl between them.
Note that the final necklace should remain as one circular part of the same length as the initial necklace.
-----Input-----
The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl.
-----Output-----
Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower).
-----Examples-----
Input
-o-o--
Output
YES
Input
-o---
Output
YES
Input
-o---o-
Output
NO
Input
ooo
Output
YES
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def main():
s = input()
links = s.count('-')
pearls = s.count('o')
if pearls == 0 or links % pearls == 0:
print('YES')
else:
print('NO')
main()
```
|
vfc_10698
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/980/A",
"time_limit": "None"
}
|
{
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},
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"type": "stdin_stdout"
},
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"output": "YES\n",
"type": "stdin_stdout"
},
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"output": "YES\n",
"type": "stdin_stdout"
},
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"output": "YES\n",
"type": "stdin_stdout"
},
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"output": "YES\n",
"type": "stdin_stdout"
},
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"output": "YES\n",
"type": "stdin_stdout"
},
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"output": "YES\n",
"type": "stdin_stdout"
},
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}
|
apps
|
verifiable_code
|
237
|
Solve the following coding problem using the programming language python:
n hobbits are planning to spend the night at Frodo's house. Frodo has n beds standing in a row and m pillows (n ≤ m). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as many pillows as possible. Of course, it's not always possible to share pillows equally, but any hobbit gets hurt if he has at least two pillows less than some of his neighbors have.
Frodo will sleep on the k-th bed in the row. What is the maximum number of pillows he can have so that every hobbit has at least one pillow, every pillow is given to some hobbit and no one is hurt?
-----Input-----
The only line contain three integers n, m and k (1 ≤ n ≤ m ≤ 10^9, 1 ≤ k ≤ n) — the number of hobbits, the number of pillows and the number of Frodo's bed.
-----Output-----
Print single integer — the maximum number of pillows Frodo can have so that no one is hurt.
-----Examples-----
Input
4 6 2
Output
2
Input
3 10 3
Output
4
Input
3 6 1
Output
3
-----Note-----
In the first example Frodo can have at most two pillows. In this case, he can give two pillows to the hobbit on the first bed, and one pillow to each of the hobbits on the third and the fourth beds.
In the second example Frodo can take at most four pillows, giving three pillows to each of the others.
In the third example Frodo can take three pillows, giving two pillows to the hobbit in the middle and one pillow to the hobbit on the third bed.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n, m, k = map(int, input().split())
ans = 1
m -= n
left = k - 1
right = n - k
put = 1
while (m >= put):
m -= put
ans += 1
put += (left > 0) + (right > 0)
if (left): left -= 1
if (right): right -= 1
if (left == right == 0):
ans += (m // put)
break
print(ans)
```
|
vfc_10702
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/760/B",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
238
|
Solve the following coding problem using the programming language python:
You are given an array $a_1, a_2, \dots , a_n$ and two integers $m$ and $k$.
You can choose some subarray $a_l, a_{l+1}, \dots, a_{r-1}, a_r$.
The cost of subarray $a_l, a_{l+1}, \dots, a_{r-1}, a_r$ is equal to $\sum\limits_{i=l}^{r} a_i - k \lceil \frac{r - l + 1}{m} \rceil$, where $\lceil x \rceil$ is the least integer greater than or equal to $x$.
The cost of empty subarray is equal to zero.
For example, if $m = 3$, $k = 10$ and $a = [2, -4, 15, -3, 4, 8, 3]$, then the cost of some subarrays are: $a_3 \dots a_3: 15 - k \lceil \frac{1}{3} \rceil = 15 - 10 = 5$; $a_3 \dots a_4: (15 - 3) - k \lceil \frac{2}{3} \rceil = 12 - 10 = 2$; $a_3 \dots a_5: (15 - 3 + 4) - k \lceil \frac{3}{3} \rceil = 16 - 10 = 6$; $a_3 \dots a_6: (15 - 3 + 4 + 8) - k \lceil \frac{4}{3} \rceil = 24 - 20 = 4$; $a_3 \dots a_7: (15 - 3 + 4 + 8 + 3) - k \lceil \frac{5}{3} \rceil = 27 - 20 = 7$.
Your task is to find the maximum cost of some subarray (possibly empty) of array $a$.
-----Input-----
The first line contains three integers $n$, $m$, and $k$ ($1 \le n \le 3 \cdot 10^5, 1 \le m \le 10, 1 \le k \le 10^9$).
The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ($-10^9 \le a_i \le 10^9$).
-----Output-----
Print the maximum cost of some subarray of array $a$.
-----Examples-----
Input
7 3 10
2 -4 15 -3 4 8 3
Output
7
Input
5 2 1000
-13 -4 -9 -20 -11
Output
0
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
N, M, K = list(map(int, input().split()))
A = [int(a) for a in input().split()]
S = [0]
for a in A:
S.append(S[-1]+M*a-K)
MI = [(10**50)] * M
ans = 0
for i in range(N+1):
MI[i%M] = min(MI[i%M], S[i])
for j in range(M):
ans = max(ans, (S[i]-MI[(i-j)%M] - K*((-j)%M))//M)
print(ans)
```
|
vfc_10706
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1197/D",
"time_limit": "None"
}
|
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|
apps
|
verifiable_code
|
239
|
Solve the following coding problem using the programming language python:
You are given a rectangular grid of lattice points from (0, 0) to (n, m) inclusive. You have to choose exactly 4 different points to build a polyline possibly with self-intersections and self-touching. This polyline should be as long as possible.
A polyline defined by points p_1, p_2, p_3, p_4 consists of the line segments p_1 p_2, p_2 p_3, p_3 p_4, and its length is the sum of the lengths of the individual line segments.
-----Input-----
The only line of the input contains two integers n and m (0 ≤ n, m ≤ 1000). It is guaranteed that grid contains at least 4 different points.
-----Output-----
Print 4 lines with two integers per line separated by space — coordinates of points p_1, p_2, p_3, p_4 in order which represent the longest possible polyline.
Judge program compares your answer and jury's answer with 10^{ - 6} precision.
-----Examples-----
Input
1 1
Output
1 1
0 0
1 0
0 1
Input
0 10
Output
0 1
0 10
0 0
0 9
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import math
n, m = list(map(int, input().split()))
if n == 0 :
print(0, 1)
print(0, m)
print(0, 0)
print(0, m - 1)
elif m == 0 :
print(1, 0)
print(n, 0)
print(0, 0)
print(n - 1, 0)
else :
l = math.sqrt((n - 1) ** 2 + m ** 2) + math.sqrt(n ** 2 + m ** 2) + math.sqrt(n ** 2 + (m - 1) ** 2)
l1 = max(m, n) + math.sqrt(n * n + m * m) * 2
l2 = math.sqrt(n ** 2 + m ** 2) + math.sqrt((n - 1) ** 2 + m ** 2) * 2
l3 = math.sqrt(n ** 2 + m ** 2) + math.sqrt((m - 1) ** 2 + n ** 2) * 2
ans = max(l, l1, l2, l3)
if l == ans :
print(1, 0)
print(n, m)
print(0, 0)
print(n, m - 1)
elif l1 == ans :
if n > m :
print(n, m)
print(0, 0)
print(n, 0)
print(0, m)
else :
print(n, m)
print(0, 0)
print(0, m)
print(n, 0)
elif l2 == ans :
print(1, 0)
print(n, m)
print(0, 0)
print(n - 1, m)
else :
print(0, 1)
print(n, m)
print(0, 0)
print(n, m - 1)
```
|
vfc_10710
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/452/B",
"time_limit": "None"
}
|
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]
}
|
apps
|
verifiable_code
|
240
|
Solve the following coding problem using the programming language python:
Vasya decided to pass a very large integer n to Kate. First, he wrote that number as a string, then he appended to the right integer k — the number of digits in n.
Magically, all the numbers were shuffled in arbitrary order while this note was passed to Kate. The only thing that Vasya remembers, is a non-empty substring of n (a substring of n is a sequence of consecutive digits of the number n).
Vasya knows that there may be more than one way to restore the number n. Your task is to find the smallest possible initial integer n. Note that decimal representation of number n contained no leading zeroes, except the case the integer n was equal to zero itself (in this case a single digit 0 was used).
-----Input-----
The first line of the input contains the string received by Kate. The number of digits in this string does not exceed 1 000 000.
The second line contains the substring of n which Vasya remembers. This string can contain leading zeroes.
It is guaranteed that the input data is correct, and the answer always exists.
-----Output-----
Print the smalles integer n which Vasya could pass to Kate.
-----Examples-----
Input
003512
021
Output
30021
Input
199966633300
63
Output
3036366999
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import math
from collections import Counter
s = list(map(int, input()))
substr = input().rstrip()
t = list(map(int, substr))
m = len(s)
x, y = 0, m
z = (x + y) // 2
while z != x:
if z + math.floor(math.log10(z)) + 1 <= m:
x = z
else:
y = z
z = (x + y)//2
m1 = z
k = math.floor(math.log10(m1)) + 1
D = Counter(s)
D.subtract(list(map(int, str(m1))))
D.subtract(t)
try:
c1 = min(i for i in range(1, 10) if D[i] > 0)
c2 = t[0]
D[c1] -= 1
_prefix = [c1]
for c in range(c2):
_prefix += [c] * D[c]
_suffix = []
for c in range(c2 + 1, 10):
_suffix += [c] * D[c]
num = ''.join([str(c2)] * D[c2])
prefix = ''.join(map(str, _prefix))
suffix = ''.join(map(str, _suffix))
if c2 == 0:
print((min(prefix + substr + num + suffix,
prefix + num + substr + suffix)))
else:
D[c1] += 1
st = []
for c in range(10):
st += [c] * D[c]
print((min(prefix + substr + num + suffix,
prefix + num + substr + suffix,
substr + ''.join(map(str, st)))))
except ValueError:
print(substr + '0'*D[0])
```
|
vfc_10714
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/670/F",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
241
|
Solve the following coding problem using the programming language python:
Not so long ago company R2 bought company R1 and consequently, all its developments in the field of multicore processors. Now the R2 laboratory is testing one of the R1 processors.
The testing goes in n steps, at each step the processor gets some instructions, and then its temperature is measured. The head engineer in R2 is keeping a report record on the work of the processor: he writes down the minimum and the maximum measured temperature in his notebook. His assistant had to write down all temperatures into his notebook, but (for unknown reasons) he recorded only m.
The next day, the engineer's assistant filed in a report with all the m temperatures. However, the chief engineer doubts that the assistant wrote down everything correctly (naturally, the chief engineer doesn't doubt his notes). So he asked you to help him. Given numbers n, m, min, max and the list of m temperatures determine whether you can upgrade the set of m temperatures to the set of n temperatures (that is add n - m temperatures), so that the minimum temperature was min and the maximum one was max.
-----Input-----
The first line contains four integers n, m, min, max (1 ≤ m < n ≤ 100; 1 ≤ min < max ≤ 100). The second line contains m space-separated integers t_{i} (1 ≤ t_{i} ≤ 100) — the temperatures reported by the assistant.
Note, that the reported temperatures, and the temperatures you want to add can contain equal temperatures.
-----Output-----
If the data is consistent, print 'Correct' (without the quotes). Otherwise, print 'Incorrect' (without the quotes).
-----Examples-----
Input
2 1 1 2
1
Output
Correct
Input
3 1 1 3
2
Output
Correct
Input
2 1 1 3
2
Output
Incorrect
-----Note-----
In the first test sample one of the possible initial configurations of temperatures is [1, 2].
In the second test sample one of the possible initial configurations of temperatures is [2, 1, 3].
In the third test sample it is impossible to add one temperature to obtain the minimum equal to 1 and the maximum equal to 3.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def main():
n, m, mn, mx = map(int, input().split())
A = list(map(int, input().split()))
a = min(A)
b = max(A)
if a < mn or b > mx:
print("Incorrect")
return
cnt = 0
if a > mn:
cnt += 1
if b < mx:
cnt += 1
if m + cnt <= n:
print("Correct")
else:
print("Incorrect")
main()
```
|
vfc_10718
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/413/A",
"time_limit": "None"
}
|
{
"language": "python",
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{
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},
{
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{
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},
{
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},
{
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},
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},
{
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},
{
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},
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"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 2 2 3\n4 4\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 2 2 4\n2 2\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 1 1 4\n1\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9 7 1 4\n4 3 3 2 2 4 1\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9 5 2 3\n4 2 4 3 3\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 3 1 3\n1 4 2\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 2 1 99\n34 100\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 2 1 99\n100 38\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 2 1 99\n100 38\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 2 1 99\n36 51\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "7 6 3 10\n5 10 7 7 4 5\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8 6 3 10\n8 5 7 8 4 4\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "9 6 3 10\n9 7 7 5 3 10\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "16 15 30 40\n36 37 35 36 34 34 37 35 32 33 31 38 39 38 38\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "17 15 30 40\n38 36 37 34 30 38 38 31 38 38 36 39 39 37 35\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "18 15 30 40\n35 37 31 32 30 33 36 38 36 38 31 30 39 32 36\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "17 16 30 40\n39 32 37 31 40 32 36 34 56 34 40 36 37 36 33 36\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "18 16 30 40\n32 35 33 39 34 30 37 34 30 34 39 18 32 37 37 36\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "19 16 30 40\n36 30 37 30 37 32 34 30 35 35 33 35 39 37 46 37\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 2 100\n38\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 1 2 100\n1\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 1 2 100\n1\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "91 38 1 3\n3 2 3 2 3 2 3 3 1 1 1 2 2 1 3 2 3 1 3 3 1 3 3 2 1 2 2 3 1 2 1 3 2 2 3 1 1 2\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 3 2 10\n6 3 10\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "41 6 4 10\n10 7 4 9 9 10\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "21 1 1 9\n9\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 9 10\n10\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 2 9\n9\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8 7 5 9\n6 7 8 5 5 6 6\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 2 2 8\n7 2\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "71 36 1 10\n7 10 8 1 3 8 5 7 3 10 8 1 6 4 5 7 8 2 4 3 4 10 8 5 1 2 8 8 10 10 4 3 7 9 7 8\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "85 3 4 9\n4 8 7\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4 3 4 10\n9 10 5\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 1 5\n1\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "91 75 1 10\n2 6 9 7 4 9 4 8 10 6 4 1 10 6 5 9 7 5 1 4 6 4 8 2 1 3 5 7 6 9 5 5 8 1 7 1 4 2 8 3 1 6 6 2 10 6 2 2 8 5 4 5 5 3 10 9 4 3 1 9 10 3 2 4 8 7 4 9 3 1 1 1 3 4 5\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 4 1 8\n7 9 6 6\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "18 1 3 10\n2\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 2 4 8\n6 3\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "17 6 2 8\n3 8 6 1 6 4\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "21 1 5 8\n4\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 1 10\n9\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 4 8\n5\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 1 7\n6\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 4 9\n5\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 3 8\n7\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 5 9\n6\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 2 1 10\n4 9\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 4 10\n7\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 2 9\n8\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2 1 3 9\n3\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3 2 6 7\n6 6\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "6 4 1 10\n11 10 9 1\n",
"output": "Incorrect\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "7 6 3 8\n3 4 5 6 7 8\n",
"output": "Correct\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5 3 1 5\n2 3 4\n",
"output": "Correct\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
242
|
Solve the following coding problem using the programming language python:
Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?
-----Input-----
The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.
-----Output-----
First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.
-----Examples-----
Input
1
Output
5
5 6 7 8 9
Input
5
Output
0
-----Note-----
The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.
In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
m = int(input())
a = 0
while m > 0:
a += 5
b = a
c = 0
while b % 5 == 0:
b //= 5
c += 1
m -= c
if m < 0: print(0)
else:
print(5)
print(a, a + 1, a + 2, a + 3, a + 4)
```
|
vfc_10722
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/633/B",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "1\n",
"output": "5\n5 6 7 8 9 ",
"type": "stdin_stdout"
},
{
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"input": "5\n",
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},
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]
}
|
apps
|
verifiable_code
|
243
|
Solve the following coding problem using the programming language python:
Chouti was tired of the tedious homework, so he opened up an old programming problem he created years ago.
You are given a connected undirected graph with $n$ vertices and $m$ weighted edges. There are $k$ special vertices: $x_1, x_2, \ldots, x_k$.
Let's define the cost of the path as the maximum weight of the edges in it. And the distance between two vertexes as the minimum cost of the paths connecting them.
For each special vertex, find another special vertex which is farthest from it (in terms of the previous paragraph, i.e. the corresponding distance is maximum possible) and output the distance between them.
The original constraints are really small so he thought the problem was boring. Now, he raises the constraints and hopes you can solve it for him.
-----Input-----
The first line contains three integers $n$, $m$ and $k$ ($2 \leq k \leq n \leq 10^5$, $n-1 \leq m \leq 10^5$) — the number of vertices, the number of edges and the number of special vertices.
The second line contains $k$ distinct integers $x_1, x_2, \ldots, x_k$ ($1 \leq x_i \leq n$).
Each of the following $m$ lines contains three integers $u$, $v$ and $w$ ($1 \leq u,v \leq n, 1 \leq w \leq 10^9$), denoting there is an edge between $u$ and $v$ of weight $w$. The given graph is undirected, so an edge $(u, v)$ can be used in the both directions.
The graph may have multiple edges and self-loops.
It is guaranteed, that the graph is connected.
-----Output-----
The first and only line should contain $k$ integers. The $i$-th integer is the distance between $x_i$ and the farthest special vertex from it.
-----Examples-----
Input
2 3 2
2 1
1 2 3
1 2 2
2 2 1
Output
2 2
Input
4 5 3
1 2 3
1 2 5
4 2 1
2 3 2
1 4 4
1 3 3
Output
3 3 3
-----Note-----
In the first example, the distance between vertex $1$ and $2$ equals to $2$ because one can walk through the edge of weight $2$ connecting them. So the distance to the farthest node for both $1$ and $2$ equals to $2$.
In the second example, one can find that distance between $1$ and $2$, distance between $1$ and $3$ are both $3$ and the distance between $2$ and $3$ is $2$.
The graph may have multiple edges between and self-loops, as in the first example.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def g():
return list(map(int,input().split()))
n,m,k=g()
p=list(range(n+1))
z=[0]*(n+1)
for x in g():
z[x]=1
e=[]
for i in range(m):
u,v,w=g()
e+=[(w,u,v)]
e=sorted(e)
def q(x):
if x!=p[x]:
p[x]=q(p[x])
return p[x]
for w,u,v in e:
u=q(u);v=q(v)
if u!=v:
if u%5==3:
u,v=v,u
p[u]=v;z[v]+=z[u]
if z[v]==k:
print(((str(w)+' ')*k));return
```
|
vfc_10726
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1081/D",
"time_limit": "None"
}
|
{
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]
}
|
apps
|
verifiable_code
|
244
|
Solve the following coding problem using the programming language python:
Bomboslav likes to look out of the window in his room and watch lads outside playing famous shell game. The game is played by two persons: operator and player. Operator takes three similar opaque shells and places a ball beneath one of them. Then he shuffles the shells by swapping some pairs and the player has to guess the current position of the ball.
Bomboslav noticed that guys are not very inventive, so the operator always swaps the left shell with the middle one during odd moves (first, third, fifth, etc.) and always swaps the middle shell with the right one during even moves (second, fourth, etc.).
Let's number shells from 0 to 2 from left to right. Thus the left shell is assigned number 0, the middle shell is 1 and the right shell is 2. Bomboslav has missed the moment when the ball was placed beneath the shell, but he knows that exactly n movements were made by the operator and the ball was under shell x at the end. Now he wonders, what was the initial position of the ball?
-----Input-----
The first line of the input contains an integer n (1 ≤ n ≤ 2·10^9) — the number of movements made by the operator.
The second line contains a single integer x (0 ≤ x ≤ 2) — the index of the shell where the ball was found after n movements.
-----Output-----
Print one integer from 0 to 2 — the index of the shell where the ball was initially placed.
-----Examples-----
Input
4
2
Output
1
Input
1
1
Output
0
-----Note-----
In the first sample, the ball was initially placed beneath the middle shell and the operator completed four movements. During the first move operator swapped the left shell and the middle shell. The ball is now under the left shell. During the second move operator swapped the middle shell and the right one. The ball is still under the left shell. During the third move operator swapped the left shell and the middle shell again. The ball is again in the middle. Finally, the operators swapped the middle shell and the right shell. The ball is now beneath the right shell.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def main():
n = int(input())
k = int(input())
n %= 6
a = [0, 1, 2]
for i in range(1, n + 1):
if (i % 2 == 1):
a[0], a[1] = a[1], a[0]
else:
a[1], a[2] = a[2], a[1]
print(a[k])
main()
```
|
vfc_10730
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/777/A",
"time_limit": "None"
}
|
{
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"input": "123456789\n1\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "123456789\n2\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "123456790\n0\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "12\n2\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "32\n1\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "20\n2\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
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"output": "0\n",
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},
{
"fn_name": null,
"input": "1\n0\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "76994383\n1\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "25\n2\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n2\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "12\n0\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "150\n2\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "15\n0\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "21\n2\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "18\n2\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8\n2\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10\n0\n",
"output": "2\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "16\n0\n",
"output": "2\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
245
|
Solve the following coding problem using the programming language python:
You are given n rectangles. The corners of rectangles have integer coordinates and their edges are parallel to the Ox and Oy axes. The rectangles may touch each other, but they do not overlap (that is, there are no points that belong to the interior of more than one rectangle).
Your task is to determine if the rectangles form a square. In other words, determine if the set of points inside or on the border of at least one rectangle is precisely equal to the set of points inside or on the border of some square.
-----Input-----
The first line contains a single integer n (1 ≤ n ≤ 5). Next n lines contain four integers each, describing a single rectangle: x_1, y_1, x_2, y_2 (0 ≤ x_1 < x_2 ≤ 31400, 0 ≤ y_1 < y_2 ≤ 31400) — x_1 and x_2 are x-coordinates of the left and right edges of the rectangle, and y_1 and y_2 are y-coordinates of the bottom and top edges of the rectangle.
No two rectangles overlap (that is, there are no points that belong to the interior of more than one rectangle).
-----Output-----
In a single line print "YES", if the given rectangles form a square, or "NO" otherwise.
-----Examples-----
Input
5
0 0 2 3
0 3 3 5
2 0 5 2
3 2 5 5
2 2 3 3
Output
YES
Input
4
0 0 2 3
0 3 3 5
2 0 5 2
3 2 5 5
Output
NO
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
s = 0
INF = 10**9
minx = miny = INF
maxx = maxy = -INF
for i in range(n):
x1, y1, x2, y2 = list(map(int, input().split()))
s += abs(x1 - x2) * abs(y1 - y2)
minx = min(minx, x1, x2)
maxx = max(maxx, x1, x2)
miny = min(miny, y1, y2)
maxy = max(maxy, y1, y2)
if (maxx - minx) == (maxy - miny) and s == (maxx - minx) ** 2:
print ("YES")
else:
print ("NO")
```
|
vfc_10734
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/325/A",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "5\n0 0 2 3\n0 3 3 5\n2 0 5 2\n3 2 5 5\n2 2 3 3\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4\n0 0 2 3\n0 3 3 5\n2 0 5 2\n3 2 5 5\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n0 0 10000 20000\n10000 0 15000 19999\n10000 19999 14999 20000\n0 20000 15000 31400\n15000 0 31400 31400\n",
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{
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"output": "YES\n",
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{
"fn_name": null,
"input": "5\n10359 859 28918 4384\n2895 26520 28918 26882\n2895 26424 28918 26520\n2895 859 10359 4384\n2895 4384 28918 26424\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n12750 0 25688 1\n1094 0 12750 1\n0 0 956 1\n956 0 1094 1\n25688 0 31400 1\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4\n18006 16484 25725 31400\n0 0 31400 16484\n29563 16484 31400 31400\n25725 16484 29563 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n0 0 31400 13313\n0 13313 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3\n0 9388 31400 31400\n26020 0 31400 9388\n0 0 26020 9388\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n15164 0 19356 3925\n0 0 15164 31400\n15164 3925 31400 31400\n19356 3278 31400 3925\n19356 0 31400 3278\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n20421 5189 23141 12511\n16414 10436 17880 12511\n17880 10436 20421 12511\n15819 10436 16414 12511\n15819 5189 20421 10436\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n15819 5189 23141 12511\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3\n12052 12345 12343 18147\n12343 12345 12345 18147\n6543 12345 12052 18147\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n12750 0 25688 1\n1094 0 12750 1\n0 0 956 1\n956 0 1094 1\n25688 0 31400 1\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n0 7098 1 7460\n0 7460 1 15218\n0 15218 1 31400\n0 4974 1 7098\n0 0 1 4974\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 31400 1\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 1 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "5\n0 25169 1 27914\n0 0 1 1366\n0 10763 1 25169\n0 1366 1 10138\n0 27914 1 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 10575 1\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 3006 1 17592\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n123 4819 5819 29511\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3\n123 4819 5819 6612\n123 6612 5819 12692\n123 12692 5819 29511\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n3091 4819 5743 13222\n123 13222 5819 29511\n5743 4819 5819 13222\n123 4819 2215 13222\n2215 4819 3091 13222\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n8030 7681 8491 7682\n8491 7681 8961 7682\n7666 7681 7963 7682\n7963 7681 8030 7682\n678 7681 7666 7682\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n1234 1234 1235 1235\n1238 1234 1239 1235\n1235 1234 1236 1235\n1237 1234 1238 1235\n1236 1234 1237 1235\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n20812 5661 27208 5898\n20812 581 29415 5661\n27539 5661 29415 5898\n18961 581 20812 5898\n27208 5661 27539 5898\n",
"output": "NO\n",
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{
"fn_name": null,
"input": "1\n31399 31399 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n20499 0 31400 22815\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n0 1273 26470 9100\n0 16615 31400 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3\n25784 0 31400 20408\n0 20408 31400 20582\n15802 0 18106 20408\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4\n18006 16484 25725 31400\n0 0 31400 16484\n29563 16484 31400 31400\n25725 16484 29563 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n26466 0 26474 6206\n10906 0 17073 6321\n19720 0 26356 31400\n0 0 10906 7852\n0 21437 18466 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n1338 31399 1525 31400\n1525 31399 2595 31400\n961 31399 1338 31400\n2956 31399 31400 31400\n2595 31399 2956 31400\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "5\n1349 0 1391 3766\n1234 0 1238 417\n1391 0 5000 3766\n1234 417 1238 3766\n1238 0 1349 3766\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n0 0 100 30000\n100 0 31400 5000\n100 5000 20000 30000\n0 30000 20000 31400\n20000 5000 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n0 0 100 30000\n100 0 31400 5000\n100 5000 20000 30000\n0 30000 20000 31000\n20000 5000 31400 31000\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n8591 1234 9517 19512\n696 19512 9517 31400\n696 696 8591 19512\n8591 696 31400 1234\n9517 1234 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n0 0 1 1\n0 3 1 4\n0 1 1 2\n0 2 1 3\n0 4 1 5\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4\n0 0 1 2\n0 3 1 4\n0 4 1 5\n0 2 1 3\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "3\n0 1 1 3\n0 3 1 5\n0 0 1 1\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 1 5\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "4\n0 0 2 1\n2 0 3 2\n0 1 1 3\n1 2 3 3\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n0 0 2 1\n2 0 3 2\n0 1 1 3\n1 2 3 3\n1 1 2 2\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 1 1\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n0 0 10000 31400\n10000 0 31400 31400\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
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"input": "2\n0 0 10000 31400\n10000 0 31400 31399\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "2\n0 0 1 18\n5 0 6 18\n",
"output": "NO\n",
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"output": "NO\n",
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},
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"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "2\n0 0 1 1\n1 0 2 1\n",
"output": "NO\n",
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{
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"input": "2\n0 0 1 1\n2 2 3 3\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "4\n0 0 1 1\n5 5 6 6\n10 10 11 11\n13 13 14 14\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "5\n1 1 3 5\n3 3 5 5\n4 1 5 3\n3 1 4 2\n2 5 3 6\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4\n10 10 11 11\n11 11 12 12\n11 10 12 11\n9 12 10 13\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n0 0 2 4\n10 0 12 4\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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{
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"output": "NO\n",
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{
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"output": "NO\n",
"type": "stdin_stdout"
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{
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"output": "NO\n",
"type": "stdin_stdout"
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{
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"input": "3\n0 0 1 1\n1 0 3 3\n0 2 1 4\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
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"input": "4\n0 0 10 10\n10 10 20 20\n10 0 20 10\n10 20 11 120\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\n0 0 1 7\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "4\n0 0 4 2\n0 2 3 6\n3 4 6 6\n4 0 6 4\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n0 0 1 1\n1 1 2 2\n",
"output": "NO\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "2\n1 1 2 2\n3 3 4 4\n",
"output": "NO\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
246
|
Solve the following coding problem using the programming language python:
Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are — in fact, he needs to calculate the quantity of really big numbers that are not greater than n.
Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations.
-----Input-----
The first (and the only) line contains two integers n and s (1 ≤ n, s ≤ 10^18).
-----Output-----
Print one integer — the quantity of really big numbers that are not greater than n.
-----Examples-----
Input
12 1
Output
3
Input
25 20
Output
0
Input
10 9
Output
1
-----Note-----
In the first example numbers 10, 11 and 12 are really big.
In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 ≥ 20).
In the third example 10 is the only really big number (10 - 1 ≥ 9).
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def check(x, s):
k = 0
for i in str(x):
k += int(i)
return x - k >= s
n, s = map(int, input().split())
l = 0
r = n
while r - l > 1:
m = (l + r) // 2
if check(m, s):
r = m
else:
l = m
if check(r, s):
print(n - r + 1)
else:
print(0)
```
|
vfc_10738
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/817/C",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "12 1\n",
"output": "3\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "25 20\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 9\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "300 1000\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "500 1000\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000 2000\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10000 1000\n",
"output": "8991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000000000000000000 1000000000000000000\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000000000000000000 100000000000000000\n",
"output": "899999999999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000000000000000000 10000000000000000\n",
"output": "989999999999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000000000000000000 1000000000000000\n",
"output": "998999999999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000000000000000000 100000000000000\n",
"output": "999899999999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1000000000000000000 200000000000000000\n",
"output": "799999999999999991\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "10 5\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "20 5\n",
"output": "11\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "20 9\n",
"output": "11\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "100 9\n",
"output": "91\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1 1\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "130 118\n",
"output": "1\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "190 181\n",
"output": "0\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1999 1971\n",
"output": "10\n",
"type": "stdin_stdout"
},
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|
apps
|
verifiable_code
|
247
|
Solve the following coding problem using the programming language python:
You are given n points on Cartesian plane. Every point is a lattice point (i. e. both of its coordinates are integers), and all points are distinct.
You may draw two straight lines (not necessarily distinct). Is it possible to do this in such a way that every point lies on at least one of these lines?
-----Input-----
The first line contains one integer n (1 ≤ n ≤ 10^5) — the number of points you are given.
Then n lines follow, each line containing two integers x_{i} and y_{i} (|x_{i}|, |y_{i}| ≤ 10^9)— coordinates of i-th point. All n points are distinct.
-----Output-----
If it is possible to draw two straight lines in such a way that each of given points belongs to at least one of these lines, print YES. Otherwise, print NO.
-----Examples-----
Input
5
0 0
0 1
1 1
1 -1
2 2
Output
YES
Input
5
0 0
1 0
2 1
1 1
2 3
Output
NO
-----Note-----
In the first example it is possible to draw two lines, the one containing the points 1, 3 and 5, and another one containing two remaining points. [Image]
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
L = [(0, 0)] * n
for i in range(n):
t = input().split(' ')
a = int(t[0])
b = int(t[1])
L[i] = (a, b)
if n <= 4:
print("YES")
else:
b0 = True
b1 = True
b2 = True
L0 = []
L1 = []
L2 = []
for j in range(n):
if (L[0][0]-L[1][0])*(L[0][1]-L[j][1])!=(L[0][1]-L[1][1])*(L[0][0]-L[j][0]):
L2.append(L[j])
if (L[2][0]-L[0][0])*(L[2][1]-L[j][1])!=(L[2][1]-L[0][1])*(L[2][0]-L[j][0]):
L1.append(L[j])
if (L[2][0]-L[1][0])*(L[2][1]-L[j][1])!=(L[2][1]-L[1][1])*(L[2][0]-L[j][0]):
L0.append(L[j])
if len(L0) >= 3:
for j in range(2, len(L0)):
if (L0[0][0]-L0[1][0])*(L0[0][1]-L0[j][1])!=(L0[0][1]-L0[1][1])*(L0[0][0]-L0[j][0]):
b0 = False
if len(L1) >= 3:
for j in range(2, len(L1)):
if (L1[0][0]-L1[1][0])*(L1[0][1]-L1[j][1])!=(L1[0][1]-L1[1][1])*(L1[0][0]-L1[j][0]):
b1 = False
if len(L2) >= 3:
for j in range(2, len(L2)):
if (L2[0][0]-L2[1][0])*(L2[0][1]-L2[j][1])!=(L2[0][1]-L2[1][1])*(L2[0][0]-L2[j][0]):
b2 = False
if b0 or b1 or b2:
print("YES")
else:
print("NO")
```
|
vfc_10742
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/961/D",
"time_limit": "None"
}
|
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},
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},
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{
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"output": "YES\n",
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"output": "YES\n",
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{
"fn_name": null,
"input": "5\n1 -1\n0 0\n0 1\n-1 1\n1 1\n",
"output": "YES\n",
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},
{
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"output": "YES\n",
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{
"fn_name": null,
"input": "5\n-999999998 -999999998\n229254612 -608716103\n-588442011 -868997022\n-182303375 -739719079\n-176884024 -737994046\n",
"output": "YES\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
248
|
Solve the following coding problem using the programming language python:
Memory and his friend Lexa are competing to get higher score in one popular computer game. Memory starts with score a and Lexa starts with score b. In a single turn, both Memory and Lexa get some integer in the range [ - k;k] (i.e. one integer among - k, - k + 1, - k + 2, ..., - 2, - 1, 0, 1, 2, ..., k - 1, k) and add them to their current scores. The game has exactly t turns. Memory and Lexa, however, are not good at this game, so they both always get a random integer at their turn.
Memory wonders how many possible games exist such that he ends with a strictly higher score than Lexa. Two games are considered to be different if in at least one turn at least one player gets different score. There are (2k + 1)^2t games in total. Since the answer can be very large, you should print it modulo 10^9 + 7. Please solve this problem for Memory.
-----Input-----
The first and only line of input contains the four integers a, b, k, and t (1 ≤ a, b ≤ 100, 1 ≤ k ≤ 1000, 1 ≤ t ≤ 100) — the amount Memory and Lexa start with, the number k, and the number of turns respectively.
-----Output-----
Print the number of possible games satisfying the conditions modulo 1 000 000 007 (10^9 + 7) in one line.
-----Examples-----
Input
1 2 2 1
Output
6
Input
1 1 1 2
Output
31
Input
2 12 3 1
Output
0
-----Note-----
In the first sample test, Memory starts with 1 and Lexa starts with 2. If Lexa picks - 2, Memory can pick 0, 1, or 2 to win. If Lexa picks - 1, Memory can pick 1 or 2 to win. If Lexa picks 0, Memory can pick 2 to win. If Lexa picks 1 or 2, Memory cannot win. Thus, there are 3 + 2 + 1 = 6 possible games in which Memory wins.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
mod=10**9+7
f=[0]*500000
def POW(a,b):
if(b==0):
return 1
if(b&1):
return POW(a,b//2)**2*a%mod
else:
return POW(a,b//2)**2
def C(n,m):
if(m>n):
return 0
t=f[n]*POW(f[m],mod-2)%mod*POW(f[n-m],mod-2)%mod
return t
f[0]=1
for i in range(1,500000):
f[i]=f[i-1]*i%mod
a,b,k,t=list(map(int,input().split(' ')))
ans=0
for i in range(0,2*t+1):
t1=POW(-1,i)*C(2*t,i)%mod
t2=(C(210000+2*k*t-a+b+2*t-1-(2*k+1)*i+1,2*t)-C(1+2*k*t-a+b+2*t-1-(2*k+1)*i,2*t))%mod
ans=(ans+t1*t2)%mod
print(ans)
```
|
vfc_10746
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/712/D",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
249
|
Solve the following coding problem using the programming language python:
Valery is a PE teacher at a school in Berland. Soon the students are going to take a test in long jumps, and Valery has lost his favorite ruler!
However, there is no reason for disappointment, as Valery has found another ruler, its length is l centimeters. The ruler already has n marks, with which he can make measurements. We assume that the marks are numbered from 1 to n in the order they appear from the beginning of the ruler to its end. The first point coincides with the beginning of the ruler and represents the origin. The last mark coincides with the end of the ruler, at distance l from the origin. This ruler can be repesented by an increasing sequence a_1, a_2, ..., a_{n}, where a_{i} denotes the distance of the i-th mark from the origin (a_1 = 0, a_{n} = l).
Valery believes that with a ruler he can measure the distance of d centimeters, if there is a pair of integers i and j (1 ≤ i ≤ j ≤ n), such that the distance between the i-th and the j-th mark is exactly equal to d (in other words, a_{j} - a_{i} = d).
Under the rules, the girls should be able to jump at least x centimeters, and the boys should be able to jump at least y (x < y) centimeters. To test the children's abilities, Valery needs a ruler to measure each of the distances x and y.
Your task is to determine what is the minimum number of additional marks you need to add on the ruler so that they can be used to measure the distances x and y. Valery can add the marks at any integer non-negative distance from the origin not exceeding the length of the ruler.
-----Input-----
The first line contains four positive space-separated integers n, l, x, y (2 ≤ n ≤ 10^5, 2 ≤ l ≤ 10^9, 1 ≤ x < y ≤ l) — the number of marks, the length of the ruler and the jump norms for girls and boys, correspondingly.
The second line contains a sequence of n integers a_1, a_2, ..., a_{n} (0 = a_1 < a_2 < ... < a_{n} = l), where a_{i} shows the distance from the i-th mark to the origin.
-----Output-----
In the first line print a single non-negative integer v — the minimum number of marks that you need to add on the ruler.
In the second line print v space-separated integers p_1, p_2, ..., p_{v} (0 ≤ p_{i} ≤ l). Number p_{i} means that the i-th mark should be at the distance of p_{i} centimeters from the origin. Print the marks in any order. If there are multiple solutions, print any of them.
-----Examples-----
Input
3 250 185 230
0 185 250
Output
1
230
Input
4 250 185 230
0 20 185 250
Output
0
Input
2 300 185 230
0 300
Output
2
185 230
-----Note-----
In the first sample it is impossible to initially measure the distance of 230 centimeters. For that it is enough to add a 20 centimeter mark or a 230 centimeter mark.
In the second sample you already can use the ruler to measure the distances of 185 and 230 centimeters, so you don't have to add new marks.
In the third sample the ruler only contains the initial and the final marks. We will need to add two marks to be able to test the children's skills.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import itertools
import math
def can_measure(a, d):
return any(i + d in a for i in a)
def main():
n, l, x, y = list(map(int, input().split()))
a = set(map(int, input().split()))
can_x = can_measure(a, x)
can_y = can_measure(a, y)
if can_x and can_y:
print(0)
elif can_x:
print(1)
print(y)
elif can_y:
print(1)
print(x)
else:
for i in a:
if i + x + y in a:
print(1)
print(i + x)
break
else:
t = i + x - y in a
if 0 <= i + x <= l and t:
print(1)
print(i + x)
break;
if 0 <= i - y <= l and t:
print(1)
print(i - y)
break;
else:
print(2)
print(x, y)
def __starting_point():
main()
__starting_point()
```
|
vfc_10750
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/479/D",
"time_limit": "None"
}
|
{
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|
apps
|
verifiable_code
|
250
|
Solve the following coding problem using the programming language python:
As you know, every birthday party has a cake! This time, Babaei is going to prepare the very special birthday party's cake.
Simple cake is a cylinder of some radius and height. The volume of the simple cake is equal to the volume of corresponding cylinder. Babaei has n simple cakes and he is going to make a special cake placing some cylinders on each other.
However, there are some additional culinary restrictions. The cakes are numbered in such a way that the cake number i can be placed only on the table or on some cake number j where j < i. Moreover, in order to impress friends Babaei will put the cake i on top of the cake j only if the volume of the cake i is strictly greater than the volume of the cake j.
Babaei wants to prepare a birthday cake that has a maximum possible total volume. Help him find this value.
-----Input-----
The first line of the input contains a single integer n (1 ≤ n ≤ 100 000) — the number of simple cakes Babaei has.
Each of the following n lines contains two integers r_{i} and h_{i} (1 ≤ r_{i}, h_{i} ≤ 10 000), giving the radius and height of the i-th cake.
-----Output-----
Print the maximum volume of the cake that Babaei can make. Your answer will be considered correct if its absolute or relative error does not exceed 10^{ - 6}.
Namely: let's assume that your answer is a, and the answer of the jury is b. The checker program will consider your answer correct, if $\frac{|a - b|}{\operatorname{max}(1, b)} \leq 10^{-6}$.
-----Examples-----
Input
2
100 30
40 10
Output
942477.796077000
Input
4
1 1
9 7
1 4
10 7
Output
3983.539484752
-----Note-----
In first sample, the optimal way is to choose the cake number 1.
In second sample, the way to get the maximum volume is to use cakes with indices 1, 2 and 4.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
import math
from functools import reduce
class SegmentTree():
def __init__(self, L, function = lambda x,y: x+y):
self.function = function
N = self.size = len(L)
M = 1 << N.bit_length()
self.margin = 2*M - N
self.L = [None for i in range(self.margin)] + L
for i in range(M-1, 0, -1):
x, y = self.L[i<<1], self.L[i<<1|1]
self.L[i] = None if x is None or y is None else function(x, y)
def modify(self, pos, value):
p = pos + self.margin
self.L[p] = value
while p > 1:
x, y = self.L[p], self.L[p^1]
if p&1: x, y = y, x
self.L[p>>1] = None if x is None or y is None else self.function(x, y)
p>>=1
def query(self, left, right):
l, r = left + self.margin, right + self.margin
stack = []
void = True
while l < r:
if l&1:
if void:
result = self.L[l]
void = False
else:
result = self.function(result, self.L[l])
l+=1
if r&1:
r-=1
stack.append(self.L[r])
l>>=1
r>>=1
init = stack.pop() if void else result
return reduce(self.function, reversed(stack), init)
n = int(input())
pies, index, first_equal = [0]*n, [0]*n, [0]*n
for i in range(n):
r, h = [int(x) for x in input().split()]
pies[i] = r*r*h
s_pies = list(sorted(enumerate(pies), key = lambda p: p[1]))
for i in range(n): index[s_pies[i][0]] = i
for i in range(1, n):
first_equal[s_pies[i][0]] = i if s_pies[i][1] != s_pies[i-1][1] else first_equal[s_pies[i-1][0]]
towers = SegmentTree([0]*(n+1), max)
for j, pie in enumerate(pies):
i, k = index[j], first_equal[j]
q = towers.query(0, k+1)
towers.modify(i+1, q + pie)
print(math.pi * towers.query(0, n+1))
```
|
vfc_10754
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/629/D",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
251
|
Solve the following coding problem using the programming language python:
There is a toy building consisting of $n$ towers. Each tower consists of several cubes standing on each other. The $i$-th tower consists of $h_i$ cubes, so it has height $h_i$.
Let's define operation slice on some height $H$ as following: for each tower $i$, if its height is greater than $H$, then remove some top cubes to make tower's height equal to $H$. Cost of one "slice" equals to the total number of removed cubes from all towers.
Let's name slice as good one if its cost is lower or equal to $k$ ($k \ge n$).
[Image]
Calculate the minimum number of good slices you have to do to make all towers have the same height. Of course, it is always possible to make it so.
-----Input-----
The first line contains two integers $n$ and $k$ ($1 \le n \le 2 \cdot 10^5$, $n \le k \le 10^9$) — the number of towers and the restriction on slices, respectively.
The second line contains $n$ space separated integers $h_1, h_2, \dots, h_n$ ($1 \le h_i \le 2 \cdot 10^5$) — the initial heights of towers.
-----Output-----
Print one integer — the minimum number of good slices you have to do to make all towers have the same heigth.
-----Examples-----
Input
5 5
3 1 2 2 4
Output
2
Input
4 5
2 3 4 5
Output
2
-----Note-----
In the first example it's optimal to make $2$ slices. The first slice is on height $2$ (its cost is $3$), and the second one is on height $1$ (its cost is $4$).
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
def ii():
return int(input())
def mi():
return list(map(int, input().split()))
def li():
return list(mi())
n, k = mi()
h = li()
m = max(h)
f = [0] * (m + 1)
for hi in h:
f[hi] += 1
for i in range(m - 1, 0, -1):
f[i] += f[i + 1]
ans = 0
i = m
while i > 0:
if f[i] == n:
break
j = i
cur = 0
while j > 0:
if cur + f[j] > k:
break
cur += f[j]
j -= 1
ans += 1
i = j
print(ans)
```
|
vfc_10758
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1065/C",
"time_limit": "None"
}
|
{
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}
|
apps
|
verifiable_code
|
252
|
Solve the following coding problem using the programming language python:
Alice and Bob are playing yet another card game. This time the rules are the following. There are $n$ cards lying in a row in front of them. The $i$-th card has value $a_i$.
First, Alice chooses a non-empty consecutive segment of cards $[l; r]$ ($l \le r$). After that Bob removes a single card $j$ from that segment $(l \le j \le r)$. The score of the game is the total value of the remaining cards on the segment $(a_l + a_{l + 1} + \dots + a_{j - 1} + a_{j + 1} + \dots + a_{r - 1} + a_r)$. In particular, if Alice chooses a segment with just one element, then the score after Bob removes the only card is $0$.
Alice wants to make the score as big as possible. Bob takes such a card that the score is as small as possible.
What segment should Alice choose so that the score is maximum possible? Output the maximum score.
-----Input-----
The first line contains a single integer $n$ ($1 \le n \le 10^5$) — the number of cards.
The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ($-30 \le a_i \le 30$) — the values on the cards.
-----Output-----
Print a single integer — the final score of the game.
-----Examples-----
Input
5
5 -2 10 -1 4
Output
6
Input
8
5 2 5 3 -30 -30 6 9
Output
10
Input
3
-10 6 -15
Output
0
-----Note-----
In the first example Alice chooses a segment $[1;5]$ — the entire row of cards. Bob removes card $3$ with the value $10$ from the segment. Thus, the final score is $5 + (-2) + (-1) + 4 = 6$.
In the second example Alice chooses a segment $[1;4]$, so that Bob removes either card $1$ or $3$ with the value $5$, making the answer $5 + 2 + 3 = 10$.
In the third example Alice can choose any of the segments of length $1$: $[1;1]$, $[2;2]$ or $[3;3]$. Bob removes the only card, so the score is $0$. If Alice chooses some other segment then the answer will be less than $0$.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n = int(input())
l = list(map(int,input().split()))
curr = 0
best = 0
prevs = [0] * 31
for v in l:
curr += v
if v >= 0:
for i in range(0, v):
prevs[i] = curr
for i in range(v, 31):
best = max(curr - prevs[i] - i, best)
else:
for i in range(31):
prevs[i] = min(prevs[i], curr)
print(best)
```
|
vfc_10762
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1359/D",
"time_limit": "None"
}
|
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"output": "36\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
253
|
Solve the following coding problem using the programming language python:
Mishka is decorating the Christmas tree. He has got three garlands, and all of them will be put on the tree. After that Mishka will switch these garlands on.
When a garland is switched on, it periodically changes its state — sometimes it is lit, sometimes not. Formally, if i-th garland is switched on during x-th second, then it is lit only during seconds x, x + k_{i}, x + 2k_{i}, x + 3k_{i} and so on.
Mishka wants to switch on the garlands in such a way that during each second after switching the garlands on there would be at least one lit garland. Formally, Mishka wants to choose three integers x_1, x_2 and x_3 (not necessarily distinct) so that he will switch on the first garland during x_1-th second, the second one — during x_2-th second, and the third one — during x_3-th second, respectively, and during each second starting from max(x_1, x_2, x_3) at least one garland will be lit.
Help Mishka by telling him if it is possible to do this!
-----Input-----
The first line contains three integers k_1, k_2 and k_3 (1 ≤ k_{i} ≤ 1500) — time intervals of the garlands.
-----Output-----
If Mishka can choose moments of time to switch on the garlands in such a way that each second after switching the garlands on at least one garland will be lit, print YES.
Otherwise, print NO.
-----Examples-----
Input
2 2 3
Output
YES
Input
4 2 3
Output
NO
-----Note-----
In the first example Mishka can choose x_1 = 1, x_2 = 2, x_3 = 1. The first garland will be lit during seconds 1, 3, 5, 7, ..., the second — 2, 4, 6, 8, ..., which already cover all the seconds after the 2-nd one. It doesn't even matter what x_3 is chosen. Our choice will lead third to be lit during seconds 1, 4, 7, 10, ..., though.
In the second example there is no way to choose such moments of time, there always be some seconds when no garland is lit.
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
a, b, c = sorted(map(int, input().split()))
if a > 3:
print('NO')
elif a == 3:
if b > 3:
print('NO')
elif b == 3:
if c > 3:
print('NO')
else:
print("YES")
elif a == 1:
print('YES')
else:
if b == 2:
print('YES')
elif b > 4:
print('NO')
elif b == 4:
if c == 4:
print('YES')
else:
print('NO')
else:
print('NO')
```
|
vfc_10766
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/911/C",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "2 2 3\n",
"output": "YES\n",
"type": "stdin_stdout"
},
{
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"input": "4 2 3\n",
"output": "NO\n",
"type": "stdin_stdout"
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"type": "stdin_stdout"
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"output": "YES\n",
"type": "stdin_stdout"
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"output": "YES\n",
"type": "stdin_stdout"
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"type": "stdin_stdout"
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"type": "stdin_stdout"
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"output": "YES\n",
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},
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"output": "NO\n",
"type": "stdin_stdout"
}
]
}
|
apps
|
verifiable_code
|
254
|
Solve the following coding problem using the programming language python:
You are given a string $s$ of length $n$ consisting of lowercase Latin letters. You may apply some operations to this string: in one operation you can delete some contiguous substring of this string, if all letters in the substring you delete are equal. For example, after deleting substring bbbb from string abbbbaccdd we get the string aaccdd.
Calculate the minimum number of operations to delete the whole string $s$.
-----Input-----
The first line contains one integer $n$ ($1 \le n \le 500$) — the length of string $s$.
The second line contains the string $s$ ($|s| = n$) consisting of lowercase Latin letters.
-----Output-----
Output a single integer — the minimal number of operation to delete string $s$.
-----Examples-----
Input
5
abaca
Output
3
Input
8
abcddcba
Output
4
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
#credits https://www.geeksforgeeks.org/minimum-steps-to-delete-a-ssing-after-repeated-deletion-of-palindrome-subssings/
n=int(input())
s=input()
N = len(s)
dp = [[0 for x in range(N + 1)]
for y in range(N + 1)]
D = [[[] for x in range(N + 1)]
for y in range(N + 1)]
ss=""
re=""
for i in range(0,N):
if re!=s[i]:
ss+=re
re=s[i]
ss+=re
a=ss
N=len(a)
for l in range(1, N + 1):
i = 0
j = l - 1
while j < N:
if (l == 1):
dp[i][j] = 1
else:
dp[i][j] =1+dp[i + 1][j]
for K in range(i + 1, j + 1):
if (a[i] == a[K]):
if dp[i][j]>=dp[i ][K - 1] + dp[K + 1][j]:
dp[i][j] = dp[i][K - 1] + dp[K + 1][j]
i += 1
j += 1
print(dp[0][N-1])
```
|
vfc_10770
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/1132/F",
"time_limit": "None"
}
|
{
"language": "python",
"test_cases": [
{
"fn_name": null,
"input": "5\nabaca\n",
"output": "3\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "8\nabcddcba\n",
"output": "4\n",
"type": "stdin_stdout"
},
{
"fn_name": null,
"input": "1\nx\n",
"output": "1\n",
"type": "stdin_stdout"
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{
"fn_name": null,
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"output": "121\n",
"type": "stdin_stdout"
},
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|
apps
|
verifiable_code
|
255
|
Solve the following coding problem using the programming language python:
The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in each pair must differ by at most one.
For each boy, we know his dancing skills. Similarly, for each girl we know her dancing skills. Write a code that can determine the largest possible number of pairs that can be formed from n boys and m girls.
-----Input-----
The first line contains an integer n (1 ≤ n ≤ 100) — the number of boys. The second line contains sequence a_1, a_2, ..., a_{n} (1 ≤ a_{i} ≤ 100), where a_{i} is the i-th boy's dancing skill.
Similarly, the third line contains an integer m (1 ≤ m ≤ 100) — the number of girls. The fourth line contains sequence b_1, b_2, ..., b_{m} (1 ≤ b_{j} ≤ 100), where b_{j} is the j-th girl's dancing skill.
-----Output-----
Print a single number — the required maximum possible number of pairs.
-----Examples-----
Input
4
1 4 6 2
5
5 1 5 7 9
Output
3
Input
4
1 2 3 4
4
10 11 12 13
Output
0
Input
5
1 1 1 1 1
3
1 2 3
Output
2
The input will be stdin and you should print your solution to stdout
Now solve the problem and return the code.
|
```python
n=int(input())
a=sorted(map(int,input().split()))
m=int(input())
b=sorted(map(int,input().split()))
c=0
for i in range(n):
for j in range(m):
if abs(a[i]-b[j]) <= 1:
b[j]=-10
c+=1
break
print(c)
```
|
vfc_10774
|
{
"difficulty": "interview",
"memory_limit": null,
"memory_limit_bytes": null,
"problem_url": "https://codeforces.com/problemset/problem/489/B",
"time_limit": "None"
}
|
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}
|
Subsets and Splits
Random Hard Python Problems
Retrieves a random sample of 10 hard difficulty questions along with their answers and problem IDs, providing basic filtering but limited analytical value.