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Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
t = input() A = input().split() sum = 0 count = 0 found = False A.sort() for i in range(len(A)): A[i] = int(A[i]) sum += A[i] if A[0] != 0: print(str(-1)) exit() if sum % 3 == 0: if sum != 0: for i in reversed(A): print(i, end="") exit() else: print(0) ...
ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER EXPR FUNC_CALL VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR VAR VAR IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR IF BIN_OP VAR NUMB...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
from sys import stdin, stdout nmbr = lambda: int(stdin.readline()) lst = lambda: list(map(int, input().split())) for _ in range(1): n = nmbr() a = sorted(lst(), reverse=True) sm = sum(a) ans = [] if a[-1] != 0: print(-1) continue r0 = [] r1 = [] r2 = [] for v in a: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR LIST IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR LIST ASSIGN...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) x = list(map(int, input().strip().split())) x.sort(reverse=True) y = x[::-1] if 0 not in x: print(-1) elif max(x) == 0: print(0) else: if sum(x) % 3 == 1: flag_found_1 = False for i in y: if i % 3 == 1: x.remove(i) flag_found_1 = T...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR NUMBER IF NUMBER VAR EXPR FUNC_CALL VAR NUMBER IF FUNC_CALL VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER IF BIN_OP FUNC_CALL VAR VAR NUMBER NUMBER ASSIGN VAR NUMBER FO...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
def vyvod(sp): if set(sp) == {0}: print(0) exit() sp.sort(reverse=True) for i in sp: print(i, end="") exit() n = int(input()) sp = list(map(int, input().split())) d = sum(sp) % 3 if sp.count(0) == 0: print(-1) exit() if d == 0: vyvod(sp) elif d == 1: sp.sort() ...
FUNC_DEF IF FUNC_CALL VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER FOR VAR VAR EXPR FUNC_CALL VAR VAR STRING EXPR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER IF...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) c = input().split() if "0" not in c: print(-1) else: c.sort(reverse=True) d = list(map(int, c)) if sum(d) % 3 == 0: print(int("".join(c))) elif sum(d) % 3 == 1: if "1" in c: c.remove("1") print(int("".join(c))) elif "4" in c: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR IF STRING VAR EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR IF BIN_OP FUNC_CALL VAR VAR NUMBER NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL STRING VAR IF BIN_OP FUNC_CALL VAR VAR NUMBER NU...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) a = sorted([int(x) for x in input().split()]) s = sum(a) if a[0] != 0: print(-1) exit(0) if s % 3 != 0: for x in a: if x % 3 == s % 3: a.remove(x) break else: for x in a: if x % 3: a.remove(x) break ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER IF BIN_OP VAR NUMBER NUMBER FOR VAR VAR IF BIN_OP VAR NUMBER BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR FOR VA...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = input() digit = sorted(map(int, input().split()), reverse=True) if 0 not in digit: print(-1) else: mod = sum(digit) % 3 if mod: equal = [d for d in digit if d % 3 == mod] other = [d for d in digit if d % 3 not in [0, mod]] if equal: digit.remove(equal[-1]) eli...
ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR NUMBER IF NUMBER VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER IF VAR ASSIGN VAR VAR VAR VAR BIN_OP VAR NUMBER VAR ASSIGN VAR VAR VAR VAR BIN_OP VAR NUMBER LIST NUMBER VAR IF VAR EXPR FUNC_CALL VAR VAR...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) ans = list(map(int, input().split())) if 0 not in ans: print(-1) exit() ans.sort(reverse=True) if ans.count(0) == n: print(0) elif not sum(ans) % 3: print("".join(map(str, ans))) else: flag = 0 x = sum(ans) % 3 for i in range(n - 1, -1, -1): if ans[i] % 3: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF NUMBER VAR EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER IF FUNC_CALL VAR NUMBER VAR EXPR FUNC_CALL VAR NUMBER IF BIN_OP FUNC_CALL VAR VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL STRING FUNC...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) arr = list(map(int, input().strip().split())) arr = sorted(arr, reverse=True) x = sum(arr) if x % 3 != 0: if x % 3 == 1: a = [] for i in range(n - 1, -1, -1): if arr[i] % 3 == 1 and x % 3 == 1: x -= arr[i] else: a.append(arr[i]...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR IF BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR NUMBER NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER IF BIN_OP VAR...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) v = list(map(int, input().split())) fv = [0] * 10 for x in v: fv[x] += 1 if fv[0] == 0: print(-1) else: r = sum(v) % 3 ok, i = r == 0, r while not ok and i <= 9: if fv[i] > 0: ok = 1 fv[i] -= 1 i += 3 if not ok: i = 3 - r w...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER NUMBER FOR VAR VAR VAR VAR NUMBER IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR VAR VAR NUMBER VAR WHILE VAR VAR NUMBER IF VAR VA...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) z = list(map(int, input().split())) a = [0] * 10 for i in z: a[i] += 1 if a[0] == 0: print(-1) else: b = sum(z) % 3 c = True if b == 2: if a[2] != 0: a[2] -= 1 elif a[5] != 0: a[5] -= 1 elif a[8] != 0: a[8] -= 1 eli...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER NUMBER FOR VAR VAR VAR VAR NUMBER IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR NUMBER IF VAR NUMBER IF VAR NUMBER NUMBER VAR NUM...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
x = input() y = input().split(" ") z = [int(i) for i in y] z.sort() if z[0] != 0: print(-1) else: list3 = [] list2 = [] list1 = [] for i in z: if i == 1 or i == 4 or i == 7: list1.append(i) elif i == 2 or i == 5 or i == 8: list2.append(i) elif i == 3 o...
ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR VAR VAR VAR EXPR FUNC_CALL VAR IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR VAR IF VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR IF VAR NUMBER VAR NUMBER VAR NU...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
from sys import stdin, stdout def main(): from sys import stdin, stdout N = int(stdin.readline()) arr = list(map(int, stdin.readline().split())) arr.sort() if arr[0] != 0: stdout.write("-1\n") return res = sum(arr) % 3 if res: tmp1 = list(filter(lambda x: x % 3 == ...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR STRING RETURN ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER IF VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER VAR ASSIGN VAR FUN...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = 1 for test in range(n): a = int(input()) lst = list(map(int, input().split())) lst.sort(reverse=True) s = 0 for el in lst: s += el if s % 3 == 2: c = False for i in range(a - 1, -1, -1): if lst[i] % 3 == 2: lst.remove(lst[i]) ...
ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR VAR VAR IF BIN_OP VAR NUMBER NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER IF BIN...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
def ep(msg): print(str(msg)) exit() n = input() l = list(map(int, input().split())) if 0 not in l: ep(-1) if sum(l) == 0: ep(0) l.sort() r = sum(l) % 3 if r == 0: l.reverse() ep("".join(map(str, l))) i = next((i for i, v in enumerate(l) if v % 3 == r), -1) if i != -1: del l[i] else: de...
FUNC_DEF EXPR FUNC_CALL VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF NUMBER VAR EXPR FUNC_CALL VAR NUMBER IF FUNC_CALL VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER IF VAR ...
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you? You are given a set of digits, your task is to find the maximum integer that you can mak...
n = int(input()) freq = {} for i in range(10): freq[i] = 0 a = [int(i) for i in input().split()] total = sum(a) for i in range(n): freq[a[i]] += 1 if not freq[0]: print(-1) else: residue = total % 3 if residue: found = False while residue < 18 and not found: if residue < ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR DICT FOR VAR FUNC_CALL VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR VAR VAR VAR NUMBER IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER IF VAR ASSIGN ...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
def pw(a, x, k): if a == 0: return 0 ans = a while k > 0: ans *= x k = k - 1 return ans n, k, x = list(map(int, input().split())) a = list(map(int, input().split())) lft = [] lft.append(0) for val in a: lft.append(val) lft.append(0) rht = [] for val in lft: rht.append(v...
FUNC_DEF IF VAR NUMBER RETURN NUMBER ASSIGN VAR VAR WHILE VAR NUMBER VAR VAR ASSIGN VAR BIN_OP VAR NUMBER RETURN VAR ASSIGN VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST EXPR FUNC_CALL VAR NUMBER FOR VAR VAR EXPR FU...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
import sys def get_ints(): return list(map(int, sys.stdin.readline().strip().split())) def solve(N, K, X, A): prefix, suffix = [0] * (N + 2), [0] * (N + 2) for i in range(N): prefix[i + 1] = prefix[i] | A[i] for i in range(N - 1, -1, -1): suffix[i] = suffix[i + 1] | A[i] ans = 0 ...
IMPORT FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR FUNC_DEF ASSIGN VAR VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR VAR VAR VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER A...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = map(int, input().split()) a = list(map(int, input().split())) x = x**k pref, suff = [0] * n, [0] * n for i in range(n - 1): pref[i + 1] = a[i] | pref[i] for i in range(n - 1, 0, -1): suff[i - 1] = a[i] | suff[i] res = 0 for i in range(n): res = max(res, a[i] * x | pref[i] | suff[i]) print(res)
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR VAR BIN_OP LIST NUMBER VAR BIN_OP LIST NUMBER VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR VAR VAR VAR FOR VAR FUNC_...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = list(map(int, input().split())) a = list(map(int, input().split())) c = x**k pr = [0] su = [0] b = 0 for i in range(n - 1): b = a[i] | b pr.append(b) b = 0 for i in range(n - 1, 0, -1): b = a[i] | b su.append(b) su = su[::-1] d = [] for i in range(n): d.append(pr[i] | a[i] * c | su[i]) pri...
ASSIGN VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR LIST NUMBER ASSIGN VAR LIST NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR VAR EXPR FUNC_CALL VAR...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
x, n, k = [int(x) for x in input().split()] lista = [int(x) for x in input().split()] acumuladaL = [] acumuladaR = [] mult = k**n cont = 0 for i in lista: cont |= i acumuladaL.append(cont) cont = 0 for i in lista[::-1]: cont |= i acumuladaR.append(cont) if len(lista) == 1: print(lista[0] * mult) eli...
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR NUMBER FOR VAR VAR VAR VAR EXPR FUNC_CALL VAR VAR ASSIGN VAR NUMBER FOR VAR VAR NUMBER VAR VAR EXPR FUNC_CALL VAR VAR IF FUNC_CAL...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
class Ortree: def __init__(self, n, As): size = 1 while n > size: size *= 2 self.size = size data = [0] * size + As[:] + [0] * (size - n) for idx in range(self.size - 1, 0, -1): idx2 = idx << 1 data[idx] = data[idx2] | data[idx2 + 1] ...
CLASS_DEF FUNC_DEF ASSIGN VAR NUMBER WHILE VAR VAR VAR NUMBER ASSIGN VAR VAR ASSIGN VAR BIN_OP BIN_OP BIN_OP LIST NUMBER VAR VAR BIN_OP LIST NUMBER BIN_OP VAR VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR VAR VAR BIN_OP VAR NUMBER ASSIGN VAR VAR FUNC_DE...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = map(int, input().split()) (*Arr,) = map(int, input().split()) Prfx = [0] * (n + 2) Sffx = [0] * (n + 2) for i in range(0, n): Prfx[i + 1] = Prfx[i] | Arr[i] Sffx[n - i - 1] = Sffx[n - i] | Arr[n - i - 1] now = x**k Res = 0 for i in range(0, n): Res = max(Prfx[i] | Arr[i] * now | Sffx[i + 1], Res) ...
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR VAR VAR VAR ASSIGN VAR BIN_OP BIN_OP ...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = map(int, input().split()) a = [None] + list(map(int, input().split())) prefix = [0] * (n + 2) suffix = [0] * (n + 2) for i in range(1, n + 1): prefix[i] = a[i] | prefix[i - 1] for i in range(n, 0, -1): suffix[i] = a[i] | suffix[i + 1] mul = x**k ans = 0 for i in range(1, n + 1): ans = max(ans, pre...
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NONE FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR VAR VA...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
input_1 = input() input_1 = input_1.split() n = int(input_1[0]) k = int(input_1[1]) x = int(input_1[2]) a = input() a = a.split() a = [int(x) for x in a] maximum = 0 prefix = [] suffix = [] prefix_or = 0 suffix_or = 0 for i in range(n): prefix_or = prefix_or | a[i] prefix.append(prefix_or) for i in range(n - 1,...
ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR NUMBER ASSIGN ...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
import sys __author__ = "kitkat" try: while True: n, k, x = map(int, input().split(" ")) val = [0] + list(map(int, input().split(" "))) res = 0 L = [(0) for i in range(200003)] R = [(0) for i in range(200003)] for i in range(1, n + 1, 1): L[i] = L[i - 1] ...
IMPORT ASSIGN VAR STRING WHILE NUMBER ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR BIN_OP LIST NUMBER FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR NUMBER ASSIGN VAR NUMBER VAR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER VAR FUNC_CALL VAR NUMBER FOR VAR FUNC_CALL...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
import sys class IoTool: DEBUG = 0 def _reader_dbg(): with open("./input.txt", "r") as f: lines = f.readlines() for l in lines: yield l.strip() def _reader_oj(): return iter(sys.stdin.read().split("\n")) reader = _reader_dbg() if DEBUG else _reader_oj...
IMPORT CLASS_DEF ASSIGN VAR NUMBER FUNC_DEF FUNC_CALL VAR STRING STRING VAR ASSIGN VAR FUNC_CALL VAR FOR VAR VAR EXPR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_DEF ASSIGN VAR VAR VAR FUNC_CA...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, p = map(int, input().split()) numbers = list(map(int, input().split())) x = [0] * (n + 10) y = [0] * (n + 10) p = p**k maxi = 0 for i in range(n): x[i + 1] = numbers[i] | x[i] for j in range(n, -1, -1): y[j - 2] = numbers[j - 1] | y[j - 1] for i in range(n): if maxi < x[i] | numbers[i] * p | y[i]: ...
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP VAR NUMB...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
def main(): n, k, x = list(map(int, input().split())) aa = list(map(int, input().split())) x, lo, u = x**k, [0] * n, 0 for i, a in enumerate(aa): lo[i] = u u |= a hi, u = [], 0 for a in reversed(aa): hi.append(u) u |= a hi.reverse() for i, u, a, v in zip(l...
FUNC_DEF ASSIGN VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR VAR BIN_OP VAR VAR BIN_OP LIST NUMBER VAR NUMBER FOR VAR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR VAR VAR ASSIGN VAR VAR LIST NUMBER FOR VAR FUNC_CALL VAR...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
import sys n, k, x = [int(x) for x in sys.stdin.readline().split()] a = [int(x) for x in sys.stdin.readline().split()] tl = 0 l = [0] * (n + 1) for i in range(n - 1, -1, -1): tl |= a[i] l[i] = tl ans = 0 tr = 0 for i in range(0, n): ta = tr | a[i] * x**k | l[i + 1] ans = ans if ans > ta else ta tr ...
IMPORT ASSIGN VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER VAR VAR VAR ASSIGN VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR ...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
from sys import stdin input = stdin.readline def get_or(a, b): return a | b class SegmentTree: def __init__(self, data, default=0, func=max): self._default = default self._func = func self._len = len(data) self._size = _size = 1 << (self._len - 1).bit_length() self....
ASSIGN VAR VAR FUNC_DEF RETURN BIN_OP VAR VAR CLASS_DEF FUNC_DEF NUMBER VAR ASSIGN VAR VAR ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR VAR BIN_OP NUMBER FUNC_CALL BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST VAR BIN_OP NUMBER VAR ASSIGN VAR VAR BIN_OP VAR VAR VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VA...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = map(int, input().strip().split()) numbers = list(map(int, input().strip().split())) from_b = [(0) for i in range(n)] from_e = [(0) for i in range(n)] or_no = [(0) for i in range(n)] for j in range(1, n): from_b[j] = from_b[j - 1] | numbers[j - 1] from_e[n - j - 1] = from_e[n - j] | numbers[n - j] for ...
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR VAR BIN_...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = map(int, input().split()) a = list(map(int, input().split())) b = list(a) bits = [0] * 64 for i in range(32): for j in range(len(b)): bits[i] += b[j] & 1 b[j] >>= 1 ans = 0 for v in a: t = v u = v * x**k s = 0 for i in range(64): b = bits[i] - (t & 1) + (u & 1) ...
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP LIST NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR VAR BIN_OP VAR VAR NUMBER VAR VAR NUMBER ASSIGN VAR N...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = map(int, input().split()) a = list(map(int, input().split())) L = [0] * (n + 1) R = [0] * (n + 1) for i in range(1, n + 1): L[i] = a[i - 1] | L[i - 1] for i in range(n - 1, -1, -1): R[i] = a[i] | R[i + 1] ans = max(L[i] | a[i] * x**k | R[i + 1] for i in range(n)) print(ans)
ASSIGN VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER VAR B...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
from sys import stdin, stdout def solve(n, k, x, a): s = 0 prefix = [0] * (n + 10) suffix = [0] * (n + 10) a.append(0) a.insert(0, 0) m = pow(x, k) for i in range(1, n + 1): prefix[i] = prefix[i - 1] | a[i] for i in range(n, 0, -1): suffix[i] = suffix[i + 1] | a[i] ...
FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER VAR VAR FOR VA...
You are given n numbers a_1, a_2, ..., a_{n}. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make [Image] as large as possible, where $1$ denotes the bitwise OR. Find the maximum possible value of [Image] after performing at most k operations optimally. ...
n, k, x = list(map(int, input().split())) a = list(map(int, input().split())) pref = [(0) for el in a] suff = [(0) for el in a] pref[0] = a[0] for i in range(1, len(a)): pref[i] = pref[i - 1] | a[i] suff[-1] = a[-1] for i in range(len(a) - 2, -1, -1): suff[i] = suff[i + 1] | a[i] if n == 1: print(a[0] * x**...
ASSIGN VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER VAR VAR ASSIGN VAR NUMBER VAR VAR ASSIGN VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER VAR VA...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
C, Hr, Hb, Wr, Wb = map(int, input().split()) ans = 0 for i in range(10**5): if Wr * i <= C: ans = max(ans, Hr * i + (C - Wr * i) // Wb * Hb) for i in range(10**5): if Wb * i <= C: ans = max(ans, Hb * i + (C - Wb * i) // Wr * Hr) print(ans)
ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP NUMBER NUMBER IF BIN_OP VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR BIN_OP BIN_OP BIN_OP VAR BIN_OP VAR VAR VAR VAR FOR VAR FUNC_CALL VAR BIN_OP NUMBER NUMBER IF BIN_OP VAR VAR VAR ASSI...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
import sys f = sys.stdin C, Hr, Hb, Wr, Wb = map(int, f.readline().strip().split()) if Hr / Wr < Hb / Wb: Hr, Hb, Wr, Wb = Hb, Hr, Wb, Wr if C % Wr == 0 and C // Wr > 0: print(C // Wr * Hr) elif C // Wr == 0: print(C // Wb * Hb) else: nmax = C // Wr pmax = nmax * Hr + (C - nmax * Wr) // Wb * Hb ...
IMPORT ASSIGN VAR VAR ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR IF BIN_OP VAR VAR BIN_OP VAR VAR ASSIGN VAR VAR VAR VAR VAR VAR VAR VAR IF BIN_OP VAR VAR NUMBER BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR BIN_OP BIN_OP VAR VAR VAR IF BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR BIN_OP BIN_...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
a, b, c, d, e = list(map(int, input().split(" "))) check = int(a**0.5) ans = 0 for red in range(check + 1): blue = (a - d * red) // e if blue >= 0: ans = max(ans, red * b + blue * c) for blue in range(check + 1): red = (a - e * blue) // d if red >= 0: ans = max(ans, red * b + blue * c) p...
ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP BIN_OP VAR BIN_OP VAR VAR VAR IF VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR BIN_OP VAR VAR F...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
__author__ = "trunghieu11" def calc(n, h1, h2, w1, w2): answer = 0 len = n // w1 for i in range(0, min(len, 100000) + 1): answer = max(answer, i * h1 + (n - i * w1) // w2 * h2) return answer n, hR, hB, wR, wB = map(int, input().split()) print(max(calc(n, hR, hB, wR, wB), calc(n, hB, hR, wB, ...
ASSIGN VAR STRING FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR VAR FOR VAR FUNC_CALL VAR NUMBER BIN_OP FUNC_CALL VAR VAR NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR BIN_OP BIN_OP BIN_OP VAR BIN_OP VAR VAR VAR VAR RETURN VAR ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EX...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
C, Pr, Pb, Wr, Wb = list(map(int, input().split())) result = 0 if Wr * Wr >= C: i = 0 while Wr * i <= C: j = int((C - Wr * i) / Wb) result = max(result, Pr * i + Pb * j) i += 1 print(result) return if Wb * Wb >= C: i = 0 while Wb * i <= C: j = int((C - Wb * i) / W...
ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER IF BIN_OP VAR VAR VAR ASSIGN VAR NUMBER WHILE BIN_OP VAR VAR VAR ASSIGN VAR FUNC_CALL VAR BIN_OP BIN_OP VAR BIN_OP VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR BIN_OP VAR VAR VAR NUMBER EXPR FUNC_CALL ...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
m, h1, h2, w1, w2 = map(int, input().split()) if h2 / w2 > h1 / w1: h1, h2 = h2, h1 w1, w2 = w2, w1 if w1**2 >= m: res = 0 for i in range(int(m**0.5 + 1)): if i * w1 <= m: new = i * h1 + (m - w1 * i) // w2 * h2 res = max(res, new) print(res) exit() res = 0 for i i...
ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF BIN_OP VAR VAR BIN_OP VAR VAR ASSIGN VAR VAR VAR VAR ASSIGN VAR VAR VAR VAR IF BIN_OP VAR NUMBER VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR BIN_OP BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR VAR BIN_OP...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
c, hr, hb, wr, wb = map(int, input().split()) s = 0 if wb < wr: hr, hb, wr, wb = hb, hr, wb, wr if wb * wb > c: for nb in range(c // wb + 1): s = max(s, nb * hb + hr * ((c - wb * nb) // wr)) else: if hr * wb < hb * wr: hr, hb, wr, wb = hb, hr, wb, wr for nb in range(min(31625, c // wb + ...
ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER IF VAR VAR ASSIGN VAR VAR VAR VAR VAR VAR VAR VAR IF BIN_OP VAR VAR VAR FOR VAR FUNC_CALL VAR BIN_OP BIN_OP VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR BIN_OP VAR BIN_OP BIN_OP VAR BIN_OP VAR VAR VAR IF BIN_OP V...
A sweet little monster Om Nom loves candies very much. One day he found himself in a rather tricky situation that required him to think a bit in order to enjoy candies the most. Would you succeed with the same task if you were on his place? [Image] One day, when he came to his friend Evan, Om Nom didn't find him at h...
def main(): c, hr, hb, wr, wb = (int(i) for i in input().split()) if wb < c ** (1 / 2) > wr: if hr / wr < hb / wb: wr, hr, wb, hb = wb, hb, wr, hr mx = 0 for i in range(wr + 1): tmx = i * hb + (c - i * wb) // wr * hr mx = tmx if tmx > mx else mx el...
FUNC_DEF ASSIGN VAR VAR VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR IF VAR BIN_OP VAR BIN_OP NUMBER NUMBER VAR IF BIN_OP VAR VAR BIN_OP VAR VAR ASSIGN VAR VAR VAR VAR VAR VAR VAR VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP BIN_OP VAR VAR BIN_OP BIN_OP BIN_OP VAR BIN_OP ...
The Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Sin...
n, m = map(int, input().split()) for i in range(n): x, y = map(int, input().split()) for i in range(m): x, y = map(int, input().split()) print("Yes" if n == m else "No")
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR VAR STRING STRING
The Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Sin...
def ccw(A, B, C): return (C[1] - A[1]) * (B[0] - A[0]) > (B[1] - A[1]) * (C[0] - A[0]) def intersect(A, B, C, D): return ccw(A, C, D) != ccw(B, C, D) and ccw(A, B, C) != ccw(A, B, D) R, B = map(int, input().split()) rs = [] bs = [] for r in range(R): rs.append(list(map(int, input().split()))) for r in r...
FUNC_DEF RETURN BIN_OP BIN_OP VAR NUMBER VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER BIN_OP BIN_OP VAR NUMBER VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER FUNC_DEF RETURN FUNC_CALL VAR VAR VAR VAR FUNC_CALL VAR VAR VAR VAR FUNC_CALL VAR VAR VAR VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL V...
The Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Sin...
def check(a, b): ansa = b[0] - a[0] ansb = b[1] - a[1] return [ansa, ansb] while True: try: n, m = map(int, input().split()) if n != m: a = list() b = list() for i in range(n): a.append(list(map(int, input().split()))) for...
FUNC_DEF ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER RETURN LIST VAR VAR WHILE NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF VAR VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUN...
The Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Sin...
r, b = [int(i) for i in input().split()] for i in range(r): discard = [int(i) for i in input().split()] print("Yes" if r == b else "No")
ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR VAR STRING STRING
The Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Sin...
b, r = input().split() for x in range(int(b)): temp, temp = input().split() for x in range(int(r)): temp, temp = input().split() if b == r: print("Yes") else: print("No")
ASSIGN VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL FUNC_CALL VAR IF VAR VAR EXPR FUNC_CALL VAR STRING EXPR FUNC_CALL VAR STRING
The Rebel fleet is afraid that the Empire might want to strike back again. Princess Heidi needs to know if it is possible to assign R Rebel spaceships to guard B bases so that every base has exactly one guardian and each spaceship has exactly one assigned base (in other words, the assignment is a perfect matching). Sin...
str1 = input() l_1 = str1.split(" ") tedad = int(l_1[0]) tedad1 = int(l_1[1]) for i in range(tedad): n = input() for i in range(tedad1): n = input() if tedad1 == tedad: print("Yes") else: print("No")
ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR IF VAR VAR EXPR FUNC_CALL VAR STRING EXPR FUNC_CALL VAR STRING
This is a simplified version of the task Toy Train. These two versions differ only in the constraints. Hacks for this version are disabled. Alice received a set of Toy Train™ from Bob. It consists of one train and a connected railway network of n stations, enumerated from 1 through n. The train occupies one station at...
from sys import stdin n, m = list(map(int, stdin.readline().split())) c = {} for _ in range(m): a, b = list(map(int, stdin.readline().split())) if a - 1 not in c.keys(): c[a - 1] = [] x = b - a + (n if b < a else 0) c[a - 1].append(x) for k, l in c.items(): c[k] = min(l) + (len(l) - 1) * n ...
ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR DICT FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF BIN_OP VAR NUMBER FUNC_CALL VAR ASSIGN VAR BIN_OP VAR NUMBER LIST ASSIGN VAR BIN_OP BIN_OP VAR VAR VAR VAR VAR NUMBER EXPR FUNC_CALL ...
This is a simplified version of the task Toy Train. These two versions differ only in the constraints. Hacks for this version are disabled. Alice received a set of Toy Train™ from Bob. It consists of one train and a connected railway network of n stations, enumerated from 1 through n. The train occupies one station at...
n, m = map(int, input().split()) def dist(a, b): return (n + b - a) % n def main(): inp1 = [0] * (n + 1) inp2 = [n] * (n + 1) for _ in range(m): a, b = map(int, input().split()) inp1[a] += 1 inp2[a] = min(inp2[a], dist(a, b)) inp = tuple((r1 - 1) * n + r2 for r1, r2 in zi...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN BIN_OP BIN_OP BIN_OP VAR VAR VAR VAR FUNC_DEF ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP LIST VAR BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR VAR NUMBER ASSIGN VAR...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = list(map(int, input().split())) a = list(map(int, input().split())) d = [] for i in range(m): d.append(list(map(int, input().split()))) par = [] g = [] for i in range(n): g.append(0) for i in range(n): par.append(g.copy()) mas = [] for i in range(n): mas.append([]) for i in range(m): for k in...
ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FU...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) mas = list(map(int, input().split())) otmas = [] for i in range(m): otmas.append(list(map(int, input().split()))) for i in range(m): otmas[i][0] -= 1 otmas[i][1] -= 1 ans = -1 masotv = [] for i in range(n): mascop = mas.copy() masotvizc = [] for j in range(m): ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR VAR VAR NUMBER NUMBER VAR VAR NUMBER NUMBER ASSIGN VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = list(map(int, input().split())) l = [] v = [] for _ in range(m): l.append(list(map(int, input().split()))) ans = max(a) - min(a) c = a.copy() for _ in range(n): for __ in range(n): a = c.copy() cur = [] if _ == __: continue for ___...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
from itertools import accumulate n, m = map(int, input().split()) A = list(map(int, input().split())) LR = [] for i in range(m): l, r = map(int, input().split()) l, r = l - 1, r - 1 LR.append((l, r)) ans = -float("inf") subs = -1 for i in range(n): a = A[i] imos = [0] * (n + 1) s = [] for j...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR VAR ASSIGN VAR FUNC_CAL...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = list(map(int, input().split())) A = [int(a) for a in input().split()] L = [0] * m R = [0] * m for i in range(m): l, r = list(map(int, input().split())) L[i] = l - 1 R[i] = r - 1 ma = -1 mai = -1 for i in range(n): B = [a for a in A] for j in range(m): if L[j] > i or R[j] < i: ...
ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR BIN_OP LIST NUMBER VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR BIN_OP VAR N...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
from sys import stdin, stdout def listIn(): return list(map(int, stdin.readline().strip().split())) def stringIn(): return [x for x in stdin.readline().split()] def intIn(): return int(stdin.readline()) n, m = listIn() a = [0] + listIn() arr = {} segments = [(0, 0)] for i in range(m): l, r = lis...
FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER FUNC_CALL VAR ASSIGN VAR DICT ASSIGN VAR LIST NUMBER NUMBER FOR VAR FUNC_CALL VAR VAR A...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = [*map(int, input().split())] i = 0 c = [] d = [] while i < m: e, f = map(int, input().split()) c.append(e) d.append(f) i += 1 i = 0 j = 0 ans = max(a) - min(a) ii = 0 jj = 0 while i < n: j = 0 while j < n: k = 0 l = a[j] - a[i] if l + ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR LIST WHILE VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = [int(i) for i in input().split()] b = [] for i in range(m): x, y = map(int, input().split()) b.append((x, y)) seg = [] ma = -1000002 for i in range(len(a)): for j in range(len(a)): seg.clear() if i == j: continue cnt = 0 for id...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR VAR ASSIGN VAR LIST ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FOR VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
def solve(n, m, values, segments): if n < 2: return 0, 0, [] def find_min_max(max_value_index): values_updated = values[:] max_value = values[max_value_index] min_value_index, min_value = None, None segment_indexes = [] for seg_index in range(m): star...
FUNC_DEF IF VAR NUMBER RETURN NUMBER NUMBER LIST FUNC_DEF ASSIGN VAR VAR ASSIGN VAR VAR VAR ASSIGN VAR VAR NONE NONE ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR VAR IF VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER VAR VAR VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
def read_nums(): return [int(x) for x in input().split()] def calculate_diff(i1, i2, nums, all_segments): cur_diff = nums[i2] - nums[i1] used_segments = [] for index, segment in enumerate(all_segments): left, right = segment if left <= i1 <= right and not left <= i2 <= right: ...
FUNC_DEF RETURN FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF ASSIGN VAR BIN_OP VAR VAR VAR VAR ASSIGN VAR LIST FOR VAR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR IF VAR VAR VAR VAR VAR VAR EXPR FUNC_CALL VAR VAR VAR NUMBER RETURN VAR VAR FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = [int(x) for x in input().split()] L = [int(x) for x in input().split()] large = max(L) R = [] used = 0 Pairs = [] best = 0 lol = [] for i in range(n): if L[i] == large: R.append(i) for T in range(m): l, j = [int(x) for x in input().split()] Pairs.append((l, j)) for j in range(0, n): S = L...
ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR IF VAR VAR VAR EXPR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) mass = list(map(int, input().split())) lr = [] for t in range(m): l, r = map(int, input().split()) lr.append([l, r]) mq = 0 mdel = [] mitog = 0 for a in range(len(mass)): ma = mass[a] for b in range(len(mass)): mb = mass[b] q = 0 delete = [] ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR NUMBER FOR VAR FUNC_...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
def f(a, b): b = sorted(b, key=lambda s: s[1] - s[0]) t = {} for i in range(len(a)): l = [] for j in b: if i in range(j[0], j[1] + 1): l.append(j) t[i] = l t = dict(sorted(t.items(), key=lambda s: a[s[0]])) t = dict(sorted(t.items(), key=lambda s: ...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR DICT FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VAR LIST FOR VAR VAR IF VAR FUNC_CALL VAR VAR NUMBER BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR NUMBER AS...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = list(map(int, input().split())) b = [] for i in range(m): b.append(list(map(int, input().split()))) ans = max(a) - min(a) temp = [] for i in range(n): c = a[:] l = [] for j in range(m): if i not in range(b[j][0] - 1, b[j][1]): for k in range(b[j][...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST FOR VAR F...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = list(map(int, input().split())) ans = [] pair = [] for i in range(m): x = list(map(int, input().split())) pair.append(x) for i in range(n): for j in range(n): d = [] b = 0 for k in range(m): if ( j + 1 >= pair[k][0] ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = list(map(int, input().split())) segments = [] for i in range(m): l, r = map(int, input().split()) segments.append([l, r]) ans = 0 flag = 0 for i in range(n): for j in range(i, n): ai = a[i] aj = a[j] seglist1 = [] seglist2 = [] for...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR FOR...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) lis = list(map(int, input().split())) res = max(lis) - min(lis) seg = [] cur = [] pre = [0] * n for i in range(m): a, b = map(int, input().split()) seg.append([a - 1, b - 1]) for i in range(n): c = lis[:] ans = [] for j in range(m): aa, bb = seg[j][0], seg[j]...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR BIN_OP LIST NUMBER VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
dat = list(map(int, input().split())) l = list(map(int, input().split())) d = {} i = 1 while i < dat[1] + 1: inter = list(map(int, input().split())) j = inter[0] while j < inter[1] + 1: if j not in d: d[j] = set() d[j].add(i) j += 1 i += 1 max_res = -1 ans = None i = ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR DICT ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER WHILE VAR BIN_OP VAR NUMBER ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
def main(): n, m = map(int, input().split()) aa = list(map(int, input().split())) res = max(aa) - min(aa) ll, rr = [999], [999] segments = res_segments = [False] * (m + 1) for _ in range(m): l, r = map(int, input().split()) ll.append(l - 1) rr.append(r - 1) il, ir = (...
FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR LIST NUMBER LIST NUMBER ASSIGN VAR VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR F...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
horizon, num_blocks = [int(x) for x in input().split()] c = 0 terrain = [] for x in input().split(): terrain.append([int(x), c]) c += 1 ori_shallow = max(terrain) ori_deep = min(terrain) record = abs(ori_deep[0] - ori_shallow[0]) if num_blocks == 0 or horizon == 1: print(record) print(0) exit() reco...
ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST FUNC_CALL VAR VAR VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER IF VAR NUMBER VAR NUMBER...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = [int(i) for i in input().split()] A = [int(i) for i in input().split()] queries = [] for i in range(m): l, r = [int(x) for x in input().split()] queries.append([l, r]) if True: B = A[:] bestans = 0 bestq = [] for mnind in range(n): qans = [] B = A[:] for i in range...
ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST VAR VAR IF NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys input = sys.stdin.readline def inp(): return int(input()) def inara(): return list(map(int, input().split())) def insr(): s = input() return list(s[: len(s) - 1]) def invr(): return map(int, input().split()) n, m = invr() a = inara() seg = [] for i in range(m): l, r = invr(...
IMPORT ASSIGN VAR VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR RETURN FUNC_CALL VAR VAR BIN_OP FUNC_CALL VAR VAR NUMBER FUNC_DEF RETURN FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR ASSI...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = list(map(int, input().split())) A = list(map(int, input().split())) lst = [] for i in range(m): a, b = list(map(int, input().split())) lst.append([a, b]) answer = 0 answer_1 = [] for i in range(n): B = A.copy() kek = [] for j in range(m): a, b = lst[j][0], lst[j][1] if a <= i ...
ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
( lambda N, M: ( lambda n, m, d, dM, dm: [ [ [ ( lambda a, b: [ [ (0 if k[0] <= i <= k[1] else b.__setitem__(0, b[0] - 1)) for k in m ...
EXPR FUNC_CALL FUNC_CALL LIST FUNC_CALL LIST VAR NUMBER VAR VAR NUMBER NUMBER FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER NUMBER VAR VAR VAR NUMBER VAR VAR NUMBER VAR NUMBER VAR VAR NUMBER VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER LIST FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER FUNC_CALL VAR NUMBER VAR FUNC_CALL VAR NU...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = list(map(int, input().split())) a = list(map(int, input().split())) b = [list(map(int, input().split())) for i in range(m)] gl_ans = -1 gl_mas = [] for num_i in range(n): ma = -10000000.0 ans_m = [] o = [] for i in range(m): if b[i][0] - 1 > num_i or b[i][1] - 1 < num_i: o.app...
ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys big = 10**9 class super_seg: def __init__(self, data): n = len(data) m = 1 while m < n: m *= 2 self.n = n self.m = m self.data = [big] * (2 * m) for i in range(n): self.data[i + m] = data[i] for i in reversed(rang...
IMPORT ASSIGN VAR BIN_OP NUMBER NUMBER CLASS_DEF FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER WHILE VAR VAR VAR NUMBER ASSIGN VAR VAR ASSIGN VAR VAR ASSIGN VAR BIN_OP LIST VAR BIN_OP NUMBER VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP VAR VAR VAR VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VAR VAR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().strip().split()) lst = list(map(int, input().strip().split())) vidr = [] for i in range(m): a, b = map(int, input().strip().split()) vidr.append([a - 1, b - 1]) dif = max(lst) - min(lst) used = [] for i in range(n): new_vidr = [] new_lst = lst.copy() for v in range(m): ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST BIN_OP VAR NUMBER BIN_OP VAR NUMBER ASSIGN ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = [*map(int, input().split())] i = 0 c = [] d = [] while i < m: e, f = map(int, input().split()) c.append(e) d.append(f) i += 1 i = 0 j = 0 ans = -1 s = [] while i < n: j = 0 while j < n: k = 0 l = a[j] - a[i] ma = [] while k < m...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR LIST WHILE VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = list(map(int, input().split())) arr = [set() for i in range(n)] for i in range(m): l, r = map(int, input().split()) l -= 1 for j in range(l, r): arr[j].add(i) maxi = 0 b, s = 0, 0 d = 0 ans = [] f_ans = [] for i in range(n): for j in range(n): d = 0 ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR NUMBER FOR VAR FUNC_CALL VAR VAR VAR EXPR FUNC_CALL VAR VAR VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = [int(x) for x in input().split()] a = [int(x) for x in input().split()] q = [] for i in range(m): l, r = [int(c) for c in input().split()] q.append([l, r, i + 1]) fin = [] fin_val = 0 for i in range(n): mx = a[i] copy = a[:] ans = [] for j in range(m): l, r = q[j][0], q[j][1] ...
ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST VAR VAR BIN_OP VAR NUMBER ASSIGN VAR LIST ASSIGN VAR NUMBER FOR VAR FUNC_CA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) a = list(map(int, input().split())) ma = max(a) - min(a) rec = [] L, R = [], [] for i in range(m): l, r = map(int, input().split()) l, r = l - 1, r - 1 L.append(l) R.append(r) for k in range(n): c = a.copy() tmp = [] for i in range(m): l, r = L[i], R[...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VAR VAR LIST LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR BIN...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys input = sys.stdin.readline n, m = map(int, input().split()) x = [*map(int, input().split())] seg = [] for i in range(m): a = [*map(int, input().split())] seg.append(a) ans = -1 ansi = [] for i in range(len(x)): tx = x[:] oi = [] for n, j in enumerate(seg): a, b = j if not...
IMPORT ASSIGN VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR FUNC...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = list(map(int, input().split())) lst = list(map(int, input().split())) segments = [list(map(int, input().split())) for i in range(m)] max_diff = max(lst) - min(lst) final_inds_segments = [] for ind_max, est_max in enumerate(lst): est_final_list = lst.copy() est_inds_segments = [] for segm_pair_ind, se...
ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST FOR VAR VAR FUNC_CALL V...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) A = list(map(int, input().split())) Lf = [[] for _ in range(n)] Rb = [[] for _ in range(n)] LR = [] for i in range(m): l, r = map(int, input().split()) l, r = l - 1, r - 1 Lf[r].append(l) Rb[l].append(r) LR.append((l, r)) minus = [0] * n INF = 10**18 ans = [-INF] * n...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST VAR FUNC_CALL VAR VAR ASSIGN VAR LIST VAR FUNC_CALL VAR VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR BIN_OP...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys input = sys.stdin.readline n, m = map(int, input().split()) a = list(map(int, input().split())) lr = [list(map(int, input().split())) for _ in range(m)] for i in range(m): lr[i][0] -= 1 inf = 1145141919 d = -inf for i in range(n): for j in range(n): b = [0] * (n + 1) c0 = [] ...
IMPORT ASSIGN VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR VAR VAR NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR FOR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) arr = [int(x) for x in input().split()] seg = [] el = [] el2 = [] h = [] def cont(a, b, c): return a <= c <= b def count_delta(): return max(h) - min(h) def decrement(l, r): for i in range(l - 1, r): h[i] -= 1 for i in range(m): seg.append([int(x) for x i...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR LIST FUNC_DEF RETURN VAR VAR VAR FUNC_DEF RETURN BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR FUNC_DEF FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER VAR VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
aLen, numOfSeg = map(int, input().split(" ")) aList = list(map(int, input().split(" "))) segList = [] for x in range(numOfSeg): s, e = map(int, input().split(" ")) segList.append((s, e)) res = max(aList) - min(aList) hList = [] for x in range(0, len(aList)): ele = aList[x] c = aList[:] h = [] fo...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING EXPR FUNC_CALL VAR VAR VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) l = list(map(int, input().split())) seg = [] for i in range(m): a, b = map(int, input().split()) seg.append((a - 1, b - 1)) ans = max(l) - min(l) minind = 0 maxind = 0 for i in range(n): for j in range(n): temp1 = l[i] temp2 = l[j] for k in seg: ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_C...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
from sys import stdin n, m = map(int, input().split()) l = list(map(int, stdin.readline().split())) segment = [tuple(map(int, inp.split())) for inp in stdin.read().splitlines()] ans = 0 chosen = [] for i in range(n): temp = l.copy() curpair = [] for j in range(m): left, right = segment[j] i...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FU...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys input = sys.stdin.readline n, m = map(int, input().split()) a = list(map(int, input().split())) lr = [list(map(int, input().split())) for i in range(m)] max_d = -1 ans_use = [] for i in range(n): use = [] c = [a[i] for i in range(n)] for j in range(m): l, r = lr[j] if l <= i + 1 ...
IMPORT ASSIGN VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys input = sys.stdin.readline n, m = map(int, input().split()) A = list(map(int, input().split())) LR = [list(map(int, input().split())) for i in range(m)] def MINUS(A, B): MIN = float("inf") MAX = -float("inf") for i in range(len(A)): if MIN > A[i] - B[i]: MIN = A[i] - B[i] ...
IMPORT ASSIGN VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR FUNC_CALL VAR VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR STRING FOR VAR FUNC...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
import sys inn = lambda: input().strip() N, M = map(int, inn().split(" ")) array = list(map(int, inn().split(" "))) segment = [] for _ in range(M): l, r = tuple(map(int, inn().split(" "))) segment.append((l - 1, r - 1)) answer = -1 selectedSeg = [] for i, a in enumerate(array): array_temp = array.copy() ...
IMPORT ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING EXPR FUNC_CALL VAR B...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, q = map(int, input().split()) l = [int(i) for i in input().split()] eff = [0] * (n + 5) qry = [] for i in range(q): a, b = map(int, input().split()) a -= 1 b -= 1 qry.append([a, b]) maxi = 0 res = [] for ans in range(n): l1 = l[:] now = l[ans] apply = [] for j in range(q): a =...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR LIST VAR VAR ASSIG...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) arr = list(map(int, input().split())) b = [] for i in range(m): l, r = map(int, input().split()) b.append([l, r]) ans = 0 rt = [] for i in range(1, n + 1): brr = arr[:] temp = [] for j in range(m): if i >= b[j][0] and i <= b[j][1]: continue ...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR LIST VAR VAR ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR NUMBER BI...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
def main(): n, m = map(int, input().split()) aa = list(map(int, input().split())) res = max(aa) - min(aa) ll, rr = [n + 1], [n + 1] segments = res_segments = [False] * (m + 1) bounds = {0, n, n + 1} for _ in range(m): l, r = map(int, input().split()) l -= 1 ll.append(...
FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR LIST BIN_OP VAR NUMBER LIST BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR NUMBER VA...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
R = lambda: map(int, input().split()) n, m = R() l = list(R()) d = max(l) - min(l) s = [] qc = [] for i in range(m): s.append(list(R())) for i in range(1, n + 1): str = l.copy() c = [] for j in range(m): if i not in range(s[j][0], s[j][1] + 1): c.append(j + 1) for t in ra...
ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
class Segments: def __init__(self, segments): self.segments = segments def all(self): return [i for i in range(len(self.segments))] def at_point(self, point, included=None, excluded=None): if included is None: included = self.all() if excluded is None: ...
CLASS_DEF FUNC_DEF ASSIGN VAR VAR FUNC_DEF RETURN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_DEF NONE NONE IF VAR NONE ASSIGN VAR FUNC_CALL VAR IF VAR NONE ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR IF VAR VAR VAR VAR IF VAR VAR NUMBER VAR VAR VAR NUMBER EXPR FUNC_CALL VAR VAR RETURN VAR ...
The only difference between easy and hard versions is a number of elements in the array. You are given an array $a$ consisting of $n$ integers. The value of the $i$-th element of the array is $a_i$. You are also given a set of $m$ segments. The $j$-th segment is $[l_j; r_j]$, where $1 \le l_j \le r_j \le n$. You can...
n, m = map(int, input().split()) b = list(map(int, input().split())) segs = [list(map(int, input().split())) for _ in range(m)] a = [] d = [] for i in range(n): w = [i for i in b] x = [0] * (n + 1) t = [] for j in range(m): left, right = segs[j][0], segs[j][1] if i >= left - 1 and i <= r...
ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR VAR ASSIGN VAR BIN_OP LIST NUM...