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Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: isPalindrome = [] def palindromicPartition(self, string): self.isPalindrome = [ [(False) for i in range(len(string))] for j in range(len(string)) ] def populateIsPalindromeDP(): for i in range(0, len(string)): for j in range(0, le...
CLASS_DEF ASSIGN VAR LIST FUNC_DEF ASSIGN VAR NUMBER VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_DEF FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER BIN_OP FUNC_CALL VAR VAR VAR IF VAR NUMBER ASSIGN VAR VAR VAR NUMBER IF VAR NUMBER IF VAR VAR VAR BIN_OP VAR N...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, s): dp = [([-1] * (len(s) + 1)) for _ in range(len(s) + 1)] def dfs(s, i, j): if dp[i][j] != -1: return dp[i][j] if i > j: return 0 if self.isPal(s, i, j): return 0 ...
CLASS_DEF FUNC_DEF ASSIGN VAR BIN_OP LIST NUMBER BIN_OP FUNC_CALL VAR VAR NUMBER VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR NUMBER FUNC_DEF IF VAR VAR VAR NUMBER RETURN VAR VAR VAR IF VAR VAR RETURN NUMBER IF FUNC_CALL VAR VAR VAR VAR RETURN NUMBER ASSIGN VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR VAR IF FUNC_CALL...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, str): n = len(str) dp = [([False] * n) for i in range(n)] for g in range(0, n): for i, j in zip(range(0, n), range(g, n)): if g == 0: dp[i][j] = True elif g == 1: ...
CLASS_DEF FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP LIST NUMBER VAR VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR FOR VAR VAR FUNC_CALL VAR FUNC_CALL VAR NUMBER VAR FUNC_CALL VAR VAR VAR IF VAR NUMBER ASSIGN VAR VAR VAR NUMBER IF VAR NUMBER IF VAR VAR VAR VAR ASSIGN VAR VAR VAR NUMBER ASSIGN VAR ...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def p(self, s): l = 0 r = len(s) - 1 while l < r: if s[l] != s[r]: return False l += 1 r -= 1 return True def palindromicPartition(self, string): dp = [(len(string) + 1) for i in range(len(string) + 1)]...
CLASS_DEF FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER WHILE VAR VAR IF VAR VAR VAR VAR RETURN NUMBER VAR NUMBER VAR NUMBER RETURN NUMBER FUNC_DEF ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER B...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, string): def pal(i, j): if i >= j or string[i : j + 1] == string[i : j + 1][::-1]: dp[i] = 0 return 0 if dp[i] != -1: return dp[i] count = 10**10 for k in range(i,...
CLASS_DEF FUNC_DEF FUNC_DEF IF VAR VAR VAR VAR BIN_OP VAR NUMBER VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR NUMBER RETURN NUMBER IF VAR VAR NUMBER RETURN VAR VAR ASSIGN VAR BIN_OP NUMBER NUMBER FOR VAR FUNC_CALL VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL VAR BIN_OP VAR N...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def ispallindrome(self, s, i, j): while i < j: if s[i] != s[j]: return False i += 1 j -= 1 return True def palindromicPartition(self, s): n = len(s) dp = [[(-1) for i in range(501)] for j in range(501)] ...
CLASS_DEF FUNC_DEF WHILE VAR VAR IF VAR VAR VAR VAR RETURN NUMBER VAR NUMBER VAR NUMBER RETURN NUMBER FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR NUMBER VAR FUNC_CALL VAR NUMBER FUNC_DEF IF VAR VAR ASSIGN VAR VAR VAR NUMBER RETURN VAR VAR VAR IF VAR VAR VAR NUMBER RETURN VAR VAR VAR IF FUN...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, string): S = string n = len(S) hmap = {} def is_palindrome(s, i, j): while i < j: if s[i] != s[j]: return False i += 1 j -= 1 return True ...
CLASS_DEF FUNC_DEF ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR DICT FUNC_DEF WHILE VAR VAR IF VAR VAR VAR VAR RETURN NUMBER VAR NUMBER VAR NUMBER RETURN NUMBER FUNC_DEF IF VAR VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR VAR VAR NUMBER RETURN NUMBER ASSIGN VAR NUMBER IF VAR VAR VAR FOR VAR FUNC_CALL VAR VAR VAR ...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, string): s = string def solve(s, i, j): if temp[i][j] != -1: return temp[i][j] if i >= j or s[i : j + 1] == s[i : j + 1][::-1]: return 0 ans = float("infinity") for k in r...
CLASS_DEF FUNC_DEF ASSIGN VAR VAR FUNC_DEF IF VAR VAR VAR NUMBER RETURN VAR VAR VAR IF VAR VAR VAR VAR BIN_OP VAR NUMBER VAR VAR BIN_OP VAR NUMBER NUMBER RETURN NUMBER ASSIGN VAR FUNC_CALL VAR STRING FOR VAR FUNC_CALL VAR VAR VAR IF VAR VAR BIN_OP VAR NUMBER VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR VAR...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, s): n = len(s) dp = [[(-1) for i in range(0, n + 2)] for j in range(0, n + 2)] def getAns(i, j): if i >= j: return 0 if dp[i][j] != -1: return dp[i][j] if isPal(s, i, j): ...
CLASS_DEF FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER FUNC_DEF IF VAR VAR RETURN NUMBER IF VAR VAR VAR NUMBER RETURN VAR VAR VAR IF FUNC_CALL VAR VAR VAR VAR RETURN NUMBER ASSIGN VAR FUNC_CALL VAR NUMBER FOR VAR FUNC_CALL ...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
def ispallindrome(string, i, j): if string == "": return False while i < j: if string[i] != string[j]: return False i += 1 j += -1 return True class Solution: def solve(self, arr, ind, dp): if ind == len(arr): return 0 partition ...
FUNC_DEF IF VAR STRING RETURN NUMBER WHILE VAR VAR IF VAR VAR VAR VAR RETURN NUMBER VAR NUMBER VAR NUMBER RETURN NUMBER CLASS_DEF FUNC_DEF IF VAR FUNC_CALL VAR VAR RETURN NUMBER ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR STRING IF VAR VAR NUMBER RETURN VAR VAR FOR VAR FUNC_CALL VAR VAR FUNC_CALL VAR VAR IF FUNC_CALL VA...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
class Solution: def palindromicPartition(self, string): i = 0 j = len(string) - 1 dp = [[(-1) for i in range(len(string) + 1)] for j in range(len(string) + 1)] ans = self.solve(string, i, j, dp) return ans def isPalindrome(self, string): return string == string[...
CLASS_DEF FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR NUMBER VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR VAR VAR RETURN VAR FUNC_DEF RETURN VAR VAR NUMBER FUNC_DEF IF VAR VAR FUNC_CALL VAR VAR V...
Given a string str, a partitioning of the string is a palindrome partitioning if every sub-string of the partition is a palindrome. Determine the fewest cuts needed for palindrome partitioning of the given string. Example 1: Input: str = "ababbbabbababa" Output: 3 Explaination: After 3 partitioning substrings are "a",...
import sys class Solution: def is_palindrome(self, strt, end, st): while strt < end: if st[strt] != st[end]: return False strt += 1 end -= 1 return True def get_cuts(self, i, j, string, dp): if i >= j: return 0 i...
IMPORT CLASS_DEF FUNC_DEF WHILE VAR VAR IF VAR VAR VAR VAR RETURN NUMBER VAR NUMBER VAR NUMBER RETURN NUMBER FUNC_DEF IF VAR VAR RETURN NUMBER IF FUNC_CALL VAR VAR VAR VAR RETURN NUMBER IF VAR VAR VAR NUMBER RETURN VAR VAR VAR ASSIGN VAR VAR ASSIGN VAR VAR FOR VAR FUNC_CALL VAR VAR VAR IF FUNC_CALL VAR VAR VAR VAR ASSI...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
T = int(input()) for t in range(T): n = int(input()) cc = [int(x) for x in input().split()] aa = [int(x) for x in input().split()] bb = [int(x) for x in input().split()] state = "OPEN" cur_size = 0 max_size = 0 for i in range(n - 1): c = cc[i] a = aa[i + 1] b = bb...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR STRING ASSIGN VAR NUMBER ASSIGN VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for i in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) max_support = c[n - 1] + 1 max_length = [] for i in range(1, n)[::-1]: small, big = [a[i], b[i]] if a[i] < b[i] else [b[i], a[i]]...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP VAR BIN_OP V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def length_cycle(n, a, b, c): longest_len = 0 portion_of_prev_cycle_len = 0 for i in range(1, n): curr_chain_length = c[i] - 1 upper_node = min(a[i], b[i]) lower_node = max(a[i], b[i]) portion_of_prev_chain_len = lower_node - upper_node cycle_formed = curr_chain_lengt...
FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR BIN_OP VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR VAR ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR VAR NUMBER IF VAR VAR VAR VAR ASSIGN VAR BIN_OP BIN_OP BIN_OP VAR VAR VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def main(): T = eval(input()) for _ in range(T): N = eval(input()) L = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) dp = [0] * N for i in range(1, N): if a[i] > b[i]: a[i], b[i]...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for i in range(t): n = int(input()) C = list(map(int, input().split())) A = list(map(int, input().split())) B = list(map(int, input().split())) longestChainLength = 0 currentChainLength = 0 for j in range(1, n): if j == 1 or A[j] == B[j]: currentChainLeng...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
k = int(input()) while k: k -= 1 n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) ans, t = 0, 0 for i in range(1, n): x = abs(a[i] - b[i]) if x == 0: t = c[i] + 1 else: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBE...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for _ in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) dp = [0] * n dp[0] = abs(b[1] - a[1]) ans = 0 for i in range(1, n): if i < n - 1: ai = a[i + 1] ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) initialSpan = c[1] + abs(b[1] - a[1]) + 1 maxSpan = initialSpan for i in range(2, n): if b[i] != a[i]: initialSpan +=...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP BIN_OP VAR N...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for t in range(int(input())): n = int(input()) c = [int(x) for x in input().split()] a = [int(x) for x in input().split()] b = [int(x) for x in input().split()] prev = [(0) for i in range(n)] best2 = 0 i = 1 x = b[i] - a[i] if x > 0: temp = x + 1 prev[i] = temp el...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER AS...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline t = int(input()) for _ in range(t): n = int(input()) lengthOfChains = [int(x) for x in input().split()] prevA = [int(x) for x in input().split()] prevB = [int(x) for x in input().split()] result = 0 longestChainLength = 0 answer = 0 for i in range(1...
IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIG...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for t in range(int(input())): n = int(input()) c = [int(i) for i in input().split()] a = [int(i) for i in input().split()] b = [int(i) for i in input().split()] ans = 0 s = 0 for i in range(1, n): x = c[i] + abs(b[i] - a[i]) + 1 if a[i] != b[i] and i != 1: s += c[...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys inf = sys.stdin input = inf.readline def read_one_int(): return int(input().rstrip("\n")) def read_list_of_ints(): res = [int(val) for val in input().rstrip("\n").split(" ")] return res def check_seq(cnt, lengths, edges1, edges2): f_i = [] res = 0 for i in range(1, cnt): ...
IMPORT ASSIGN VAR VAR ASSIGN VAR VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR STRING FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR STRING STRING RETURN VAR FUNC_DEF ASSIGN VAR LIST ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR VAR ASSI...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.buffer.readline ans = [] for _ in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) res = 0 tmp = c[-1] - 1 pos_x, pos_y = 1, c[-1] for i in range(n - 1, 0, -1): ...
IMPORT ASSIGN VAR VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_C...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) c = [int(i) for i in input().split()] a = [int(i) for i in input().split()] b = [int(i) for i in input().split()] ans = 0 cnt = [0] * n curr = 0 for i in range(1, n): if a[i] == b[i]: curr = 2 ans = max(ans, c...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
a = int(input()) for i in range(a): s = int(input()) z = list(map(int, input().split())) a1 = list(map(int, input().split())) a2 = list(map(int, input().split())) maxa = 0 leng = 0 for i in range(1, len(a1)): if i == 1: maxa = max(maxa, z[i] - 1 + abs(a1[i] - a2[i]) + 2) ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline for _ in range(int(input())): n, l, a, b, best, last, curr = ( int(input()), [int(i) for i in input().split()], [int(i) for i in input().split()], [int(i) for i in input().split()], 0, 0, 0, ) for i in range(1, n)...
IMPORT ASSIGN VAR VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR VAR VAR VAR VAR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR NUMBER NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys r = sys.stdin.readline for _ in range(int(r())): N = int(r()) C = list(map(int, r().split())) A = list(map(int, r().split())) B = list(map(int, r().split())) S = 0 ans = 0 for i in range(1, N): if i == 1: S = abs(A[i] - B[i]) + 2 + (C[i] - 1) elif A[i]...
IMPORT ASSIGN VAR VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def read_input(): n = int(input()) chains = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) return chains, a, b def solve(chains, a, b): best_dp = [-1] if a[1] == b[1]: best_dp.append(chains[1] - 1 + 2) else: best_...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR RETURN VAR VAR VAR FUNC_DEF ASSIGN VAR LIST NUMBER IF VAR NUMBER VAR NU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys MOD = 10**9 + 7 INF = float("inf") T = int(input()) Ns = [] Cs = [] As = [] Bs = [] for _ in range(T): N = int(input()) C = list(map(int, input().split())) A = list(map(int, input().split())) B = list(map(int, input().split())) Ns.append(N) Cs.append(C) As.append(A) Bs.append...
IMPORT ASSIGN VAR BIN_OP BIN_OP NUMBER NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) c = [int(i) for i in input().split()] a = [int(i) for i in input().split()] b = [int(i) for i in input().split()] lengths = [0] for ind in range(1, n): if a[ind] == b[ind]: lengths.append(c[ind] + 1) else: len...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) temp = 0 maxa = 0 for i in range(1, n): if i == 1: temp += abs(b[i] - a[i]) + 2 elif a[i] == b[i]: ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR N...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for _ in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) ans = max(c[1:]) + 1 C = 2 + c[-1] - 1 for i in range(n - 1, 1, -1): if a[i] == b[i]: if ans < C: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def find(chains, first, last, n, ans): max_wt = 0 add = chains[-1] - 1 for i in range(n - 2, -1, -1): a, b, c = first[i + 1], last[i + 1], chains[i + 1] add += 2 max_wt = max(max_wt, add + abs(a - b)) if a == b: add = 0 else: a, b = min(a, b), ...
FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER ASSIGN VAR VAR VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR FUNC_CALL VAR BIN_OP VAR VAR IF VAR VAR ASSIGN VAR NUMBER ASSIGN VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline def longestSimpleCycle(n, c, a, b): ans, tmp = 0, abs(a[1] - b[1]) for i in range(1, n): if a[i] == b[i]: tmp = 0 elif i != 1: tmp -= c[i - 1] - 1 tmp += min(a[i], b[i]) - 1 + c[i - 1] - max(a[i], b[i]) if a...
IMPORT ASSIGN VAR VAR FUNC_DEF ASSIGN VAR VAR NUMBER FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR VAR VAR ASSIGN VAR NUMBER IF VAR NUMBER VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP BIN_OP BIN_OP FUNC_CALL VAR VAR VAR VAR VAR NUMBER VAR BIN_OP VAR NUMBER FUNC_CALL VAR VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) array = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) under = [(0) for i in range(n)] over = [(0) for i in range(n)] for i in range(1, n): under[i - 1] = max(a[i], b[i]) - min(a[i...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER VAR FUNC_CAL...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for _ in range(t): n = int(input()) crr = list(map(int, input().split())) arr = list(map(int, input().split())) brr = list(map(int, input().split())) for i in range(n): if arr[i] > brr[i]: arr[i], brr[i] = brr[i], arr[i] ans = 0 maxi = 0 for i in rang...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline t = int(input()) for you in range(t): n = int(input()) c = input().split() ci = [int(i) for i in c] a = input().split() a = a[1:] ai = [int(i) for i in a] b = input().split() b = b[1:] bi = [int(i) for i in b] dp = [[0, 0] for i in range(n)]...
IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR FUNC_CALL FUNC_CA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline def solve(): n = int(input()) C = list(map(int, input().split())) A = list(map(int, input().split())) B = list(map(int, input().split())) dp = [0] * n dp[-1] = C[-1] ans = 0 for i in range(n - 2, -1, -1): ans = max(ans, abs(A[i + 1] - B[i ...
IMPORT ASSIGN VAR VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline def print(x, end="\n"): sys.stdout.write(str(x) + end) def get_int(): return int(input()) def list_in(): return list(map(int, input().split())) def get_char_list(): s = input() return list(s[: len(s) - 1]) def get_tuple_ints(): return tuple(map(in...
IMPORT ASSIGN VAR VAR FUNC_DEF STRING EXPR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR RETURN FUNC_CALL VAR VAR BIN_OP FUNC_CALL VAR VAR NUMBER FUNC_DEF RETURN FUNC_CALL V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def sol(c, a, b): ans = abs(a[1] - b[1]) ans_ = [] ans_1 = [abs(a[1] - b[1])] for i in range(1, len(c)): if i < n - 1 and a[i + 1] != b[i + 1]: ans_1.append(ans + 2 + c[i] - 1) ans = max( ans + 2 + c[i] - 1 - abs(a[i + 1] - b[i + 1]), abs(a[i + 1] - b[i + ...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR LIST ASSIGN VAR LIST FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR IF VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR BIN_OP BIN_OP BIN_OP VAR NUMBER VAR VAR NUMBER ...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for z in range(t): n = int(input()) l = input().split(" ") c = [] for val in l: c.append(int(val)) l = input().split(" ") a = [] for val in l: a.append(int(val)) l = input().split(" ") b = [] for val in l: b.append(int(val)) for i in r...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR LIST FOR VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR LIST FOR VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR AS...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for i in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) ans = 0 b1 = 0 for i in range(len(c) - 1): if i == 0: b1 = max(b1, abs(b[i + 1] - a[i + 1])) else: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for t in range(int(input())): n = int(input()) c = [int(i) for i in input().split()] a = [int(i) for i in input().split()] + [1] b = [int(i) for i in input().split()] + [1] current = abs(a[1] - b[1]) best = 0 for i in range(1, n): current += 2 + c[i] - 1 - abs(a[i + 1] - b[i + 1]) ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR FUNC_CALL V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for i in range(t): (n,) = map(int, input().strip().split(" ")) q = list(map(int, input().strip().split(" "))) a = list(map(int, input().strip().split(" "))) b = list(map(int, input().strip().split(" "))) ans = 0 pre_ans = 0 for i in range(1, len(q)): cyc1 = abs(a[i] ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_C...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys t = int(input()) input = sys.stdin.readline for _ in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) lstlen = 0 ans = 0 for i in range(1, n): curllen = c[i] + 1 + abs(a[i] - b[i]) ...
IMPORT ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) c = [int(x) for x in input().split()] a = [int(x) for x in input().split()] b = [int(x) for x in input().split()] lis = [] lis.append(0) lis.append(1 + c[1] + abs(b[1] - a[1])) for i in range(n - 2): if a[i + 2] != b[i + 2]: ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
a = int(input()) for x in range(a): b = int(input()) c = list(map(int, input().split())) d = list(map(int, input().split())) e = list(map(int, input().split())) dp = [c[1] + 1 + abs(d[1] - e[1])] for y in range(1, b - 1): if abs(d[y + 1] - e[y + 1]) == 0: dp.append(c[y + 1] +...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for _ in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) maxl = 0 prc = 0 prevc = 0 for i in range(1, n): cc, ca, cb = c[i], a[i], b[i] if ca == cb: prc = 1...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for i in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) lst_ans = [0] for i in range(1, n): x = c[i] + 1 if a[i] == b[i]: lst_ans.append(x) continue ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def simple_cycle(n, a, b, c): maxi = 0 if a[1] == b[1]: s = 1 + c[1] maxi = s else: s = abs(b[1] - a[1]) + 1 + c[1] maxi = s for i in range(2, n): if b[i] == a[i]: s = 1 + c[i] else: s = max(s - abs(b[i] - a[i]) + 1 + c[i], abs(b[i]...
FUNC_DEF ASSIGN VAR NUMBER IF VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP NUMBER VAR NUMBER ASSIGN VAR VAR ASSIGN VAR BIN_OP BIN_OP FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR VAR VAR ASSIGN VAR BIN_OP NUMBER VAR VAR ASSIGN VAR FUNC_CALL VAR BIN_OP...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) C = [int(t) for t in input().split()] A = [int(t) for t in input().split()] B = [int(t) for t in input().split()] ans = 0 cur = 0 for i in range(1, n): if A[i] != B[i]: cur = max(1 + C[i] + abs(A[i] - B[i]), cur + 1 + C[i] - ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) l = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) ans = 0 c = l[n - 1] for i in range(n - 1, 0, -1): if a[i] > b[i]: a[i], b[i] = b[i], a[i] if i == 1: ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for y in range(int(input())): n = int(input()) lst = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) maxx = lst[-1] cur = lst[-1] for i in range(n): if b[i] < a[i]: a[i], b[i] = b[i], a[i] for i in range(n - 1, 0...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
T = int(input()) for t in range(T): n = int(input()) c = [int(i) for i in input().split()] a = [int(i) for i in input().split()] b = [int(i) for i in input().split()] dp = [(0) for i in range(n)] for i in range(1, n): if a[i] == b[i]: dp[i] = c[i] + 1 + abs(a[i] - b[i]) ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR FOR V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for t in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) ans = [] for i in range(1, len(b)): if i == 1: ans.append(2 + abs(b[i] - a[i]) + (c[i] - 1)) elif b[i] == a[i]: ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_C...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = lambda: sys.stdin.readline().rstrip() for _ in range(int(input())): n = int(input()) C = list(map(int, input().split()))[::-1] A = list(map(int, input().split()))[::-1] B = list(map(int, input().split()))[::-1] DP = [0] * n DP[0] = C[0] + 1 for i in range(1, n - 1): ...
IMPORT ASSIGN VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for i in range(t): n = int(input()) c = list(map(int, input().strip().split())) a = list(map(int, input().strip().split())) b = list(map(int, input().strip().split())) len = [(0) for i in range(n)] for i in range(1, n): d = abs(b[i] - a[i]) len[i] = c[i] + 1 + in...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys def main(): t = int(input()) allAns = [] for _ in range(t): n = int(input()) c = readIntArr() a = readIntArr()[1:] b = readIntArr()[1:] maxOpenLen = [(0) for _ in range(n - 1)] maxOpenLen[0] = abs(a[0] - b[0]) ans = 0 for i in rang...
IMPORT FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER FUNC_CALL VAR BIN_OP VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input().strip()) for i in range(t): n = int(input().strip()) c = list(map(int, input().strip().split())) a = list(map(int, input().strip().split())) b = list(map(int, input().strip().split())) ans = c[1] + abs(a[1] - b[1]) + 1 cur = ans for i in range(2, n): if a[i] == b[i]: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline def solution(n, c, a, b): intervals = [[min(ai, bi), max(ai, bi)] for ai, bi in zip(a, b)] branches = [(0) for _ in range(n)] sol = 0 for i in range(1, n): if intervals[i][1] == intervals[i][0]: branches[i] = 1 elif i == 1: ...
IMPORT ASSIGN VAR VAR FUNC_DEF ASSIGN VAR LIST FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR VAR VAR VAR FUNC_CALL VAR VAR VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR NUMBER VAR VAR NUMBER ASSIGN VAR VAR NUMBER IF VAR NUMBER ASSIGN VAR VAR BIN_OP BIN_OP VAR VAR NU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def solution(): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) currentLen = 0 maxLen = 0 for i in range(n): if i == 0: currentLen += abs(max(a[i + 1], b[i + 1]) - min(a[i + 1], b[i + 1])) ...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR IF VAR NU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def main(): t = int(input()) for i in range(t): solve() def solve(): n = int(input()) chains = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) dp = [] for i in range(1, len(chains)): cycle = abs(b[i] - a[i]) + chai...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def solve(): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) prev = c[1] + abs(b[1] - a[1]) + 1 ans = prev for i in range(2, n): if a[i] == b[i]: prev = c[i] + 1 else: diff = ...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP BIN_OP VAR NUMBER FUNC_CALL VAR BIN_OP VAR NUMBER VAR...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = sys.stdin.readline for nt in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) a.append(c[-1] // 2) b.append(c[-1] // 2) maxx = 0 curr2 = 0 for i in range(1, n): ...
IMPORT ASSIGN VAR VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUN...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) while t: t -= 1 n = int(input()) arr = [int(i) for i in input().split()] a = [int(i) for i in input().split()] b = [int(i) for i in input().split()] maxi = 0 prev = 0 for i in range(1, n): if a[i] == b[i]: prev = abs(b[i] - a[i]) + 2 + arr[i] - 1 ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_C...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def solve(n, c, a, b): dpr = [0] * n dpr[-1] = c[-1] - 1 for i in range(n - 2, -1, -1): stay = c[i] - 1 if a[i + 1] > b[i + 1]: a[i + 1], b[i + 1] = b[i + 1], a[i + 1] if a[i + 1] == b[i + 1]: nxt = 0 else: nxt = a[i + 1] - 1 + c[i] - b[i +...
FUNC_DEF ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR NUMBER BIN_OP VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER IF VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER IF VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) l = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) dp = [(0) for _ in range(n)] for i in range(1, n): if a[i] != b[i]: dp[i] = max( dp[i - 1] - abs(a[i] - b...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER VAR FUNC_CAL...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for tc in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) k = [0] for i in range(1, n): if a[i] == b[i]: k.append(2 + c[i] - 1) else: n1 = abs(a[i] - b[i]) + ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST NUMBER FOR VAR...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
number_of_testcases = int(input()) for _ in range(number_of_testcases): chain_length = int(input()) q = [0] * chain_length c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) for i in range(chain_length): if i > 0: q[i] ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for _ in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) maxi = 0 cnt = c[n - 1] for i in range(n - 1, 0, -1): if a[i] > b[i]: a[i], b[i] = b[i], a[i] if a[i] =...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMB...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def main(): for _ in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) if n == 1: print(0) continue out = 0 l = r = 0 len_l = abs(a[...
FUNC_DEF FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF VAR NUMBER EXPR FU...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
T = int(input()) r = 1 def getnext(index, diff, chain, dp, ans): if dp[index] >= 0: return dp[index] if diff[index] > 0: num1 = chain[index] - diff[index] + 1 + getnext(index + 1, diff, chain, dp, ans) num2 = chain[index] dp[index] = max(num1, num2) else: dp[index] ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR NUMBER FUNC_DEF IF VAR VAR NUMBER RETURN VAR VAR IF VAR VAR NUMBER ASSIGN VAR BIN_OP BIN_OP BIN_OP VAR VAR VAR VAR NUMBER FUNC_CALL VAR BIN_OP VAR NUMBER VAR VAR VAR VAR ASSIGN VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR ASSIGN VAR VAR VAR VAR ASSIGN VAR BIN_OP BIN...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
from sys import stdin, stdout input = stdin.readline def output(answer): stdout.write(str(answer) + "\n") for _ in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) curr = None mx = 0 for...
ASSIGN VAR VAR FUNC_DEF EXPR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR STRING FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
import sys input = lambda: sys.stdin.readline().rstrip("\r\n") for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) ul = list(map(int, input().split())) ll = list(map(int, input().split())) ck = abs(ul[1] - ll[1]) + 2 ans = ck + a[1] - 1 for i in range(2, n): ...
IMPORT ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def longest(size, up, low): ans = abs(low[1] - up[1]) + 1 + size[1] curr = abs(up[1] - low[1]) for i in range(1, len(size) - 1): ans = max(ans, curr + size[i] + 1) curr += size[i] + 1 - abs(up[i + 1] - low[i + 1]) if up[i + 1] == low[i + 1]: ans = max(ans, curr) ...
FUNC_DEF ASSIGN VAR BIN_OP BIN_OP FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR VAR NUMBER VAR BIN_OP BIN_OP VAR VAR NUMBER FUNC_CALL VAR B...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input().strip()) for i in range(t): n = int(input().strip()) c = list(map(int, input().strip().split())) a = list(map(int, input().strip().split())) b = list(map(int, input().strip().split())) c[0] = 0 s = 0 m = 0 z = 0 for k in range(1, n): if b[k] < a[k]: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
test = int(input()) for testcase in range(test): n = int(input()) arr = [int(x) for x in input().split()] a = [int(x) for x in input().split()] b = [int(x) for x in input().split()] area = arr[n - 1] - 1 + 2 + abs(a[n - 1] - b[n - 1]) ans = [area] for i in range(n - 2, 0, -1): if a[i...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP BIN_OP BIN_OP VAR BIN_OP VA...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for _ in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) for i in range(n): if a[i] > b[i]: a[i], b[i] = b[i], a[i] ans = 0 cur = 0 for i in range(1, n): if a[i] ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR IF V...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for w in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) x = 0 ans = 0 for i in range(1, n): if x != 0: ans = max(x, ans, x + c[i - 1] - 1) if x == 0: x =...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR N...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
for tt in range(int(input())): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) ans = 0 cnt = 0 cnt = c[n - 1] - 1 for i in range(n - 2, -1, -1): if a[i + 1] != b[i + 1]: cnt += 2 ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR N...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def solve(): n = int(input()) c = [int(s) for s in input().split()] a = [int(s) for s in input().split()] b = [int(s) for s in input().split()] current = 0 best = 0 for i in range(1, n): if a[i] == b[i]: current = 1 + c[i] else: diff = abs(a[i] - b[i])...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR VAR VAR ASSIGN VAR BI...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
t = int(input()) for _ in range(t): n = int(input()) c = list(map(int, input().split())) a = list(map(int, input().split())) b = list(map(int, input().split())) curr = abs(a[1] - b[1]) ans = curr for i in range(1, n - 1): ans = max(ans, curr + 1 + c[i]) curr += c[i] + 1 - abs...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC...
You have $n$ chains, the $i$-th chain consists of $c_i$ vertices. Vertices in each chain are numbered independently from $1$ to $c_i$ along the chain. In other words, the $i$-th chain is the undirected graph with $c_i$ vertices and $(c_i - 1)$ edges connecting the $j$-th and the $(j + 1)$-th vertices for each $1 \le j ...
def cycle(n, vert, a, b): idx = len(a) - 1 max_so_far = 0 chain_len = int(vert[idx]) - 1 while idx > 1: chain_len += 2 max_so_far = max(max_so_far, chain_len + abs(int(a[idx]) - int(b[idx]))) if int(a[idx]) == int(b[idx]): max_so_far = max(max_so_far, chain_len) ...
FUNC_DEF ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR NUMBER WHILE VAR NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR VAR IF FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR VAR ASSIGN VAR FUNC_CALL VA...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
t = int(input()) for i in range(t): n = int(input()) b = list(map(int, input().split())) j = 1 s = 0 while j < n: s += max(b[j] - b[j - 1], 0) j += 1 if b[-1] >= s: print("YES") else: print("NO")
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR VAR FUNC_CALL VAR BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF VAR NUMBER VAR EXPR FUN...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
import sys sys.setrecursionlimit(10**7) input = sys.stdin.readline f_inf = float("inf") mod = 10**9 + 7 def resolve(): t = int(input()) for _ in range(t): n = int(input()) A = list(map(int, input().split())) B = [(A[i + 1] - A[i]) for i in range(n - 1)] plus = A[-1] ne...
IMPORT EXPR FUNC_CALL VAR BIN_OP NUMBER NUMBER ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR BIN_OP BIN_OP NUMBER NUMBER NUMBER FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
for w in range(int(input())): n = int(input()) a = list(map(int, input().split())) x = -1 p = -1 ans = 1 k = n + 1 for i in range(n - 1): if a[i] >= a[i + 1]: continue else: x = a[i] p = i + 1 a[i + 1] -= x break ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER IF VAR VAR VAR BIN_OP VAR NUMBER ASSIGN V...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
import sys input = sys.stdin.readline R = lambda: map(int, input().split()) (t,) = R() for _ in [0] * t: R() pre, sur = float("inf"), 0 for a in R(): if sur > a: print("NO") break if pre + sur < a: sur = a - pre else: pre = a - sur ...
IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FOR VAR BIN_OP LIST NUMBER VAR EXPR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR STRING NUMBER FOR VAR FUNC_CALL VAR IF VAR VAR EXPR FUNC_CALL VAR STRING IF BIN_OP VAR VAR VAR ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR BIN_OP VA...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) d = a[0] for i in range(1, n): diff = a[i] - a[i - 1] if diff < 0 and d >= 0: d += diff if d < 0: print("NO") else: print("YES")
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR BIN_OP VAR VAR VAR BIN_OP VAR NUMBER IF VAR NUMBER VAR NUMBER VAR VAR IF VAR NUMBER EXPR FUNC_CALL...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
from sys import stdin, stdout t = int(stdin.readline()) for _ in range(t): n = int(stdin.readline()) arr = list(map(int, stdin.readline().split())) a, b = arr[0], 0 for i in range(1, n): a = min(a, arr[i] - b) b = arr[i] - a if arr[n - 1] >= a >= 0: print("YES") else: ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR VAR VAR ASSIGN VAR BIN_OP VAR VAR VAR IF VA...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
def solve(): n = int(input().strip()) arr = [int(x) for x in input().strip().split()] incr = [0] * n decr = [0] * n decr[0] = arr[0] for i in range(1, n): decr[i] = min(arr[i] - incr[i - 1], decr[i - 1]) incr[i] = arr[i] - decr[i] for i in range(1, n): if incr[i] < in...
FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR VAR FUNC_CALL VAR BIN_OP VAR VAR VAR BIN_OP VAR NUMBER...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
import sys def eprint(*args): print(*args, file=sys.stderr) zz = 1 if zz: input = sys.stdin.readline def li(): return [int(xx) for xx in input().split()] def fi(): return int(input()) def mi(): return map(int, input().split()) t = fi() while t > 0: t -= 1 n = fi() a = li() ...
IMPORT FUNC_DEF EXPR FUNC_CALL VAR VAR VAR ASSIGN VAR NUMBER IF VAR ASSIGN VAR VAR FUNC_DEF RETURN FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR WHILE VAR NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
for _ in range(int(input())): n = int(input()) ans = 0 a = list(map(int, input().split())) for i in range(n - 1): if a[i + 1] < a[i]: ans += a[i] - a[i + 1] if ans > a[0]: print("NO") else: print("YES")
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER VAR VAR VAR BIN_OP VAR VAR VAR BIN_OP VAR NUMBER IF VAR VAR NUMBER EXPR FUNC_CALL...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) cur = a[0] down = 0 for c in a[1:]: if c - down < 0: print("NO") break elif c - down <= cur: cur = c - down else: down = c - cur else: ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR NUMBER IF BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR STRING IF BIN_OP VAR VAR VAR ASSIGN VAR BIN_OP VAR VAR ASSIGN...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
import sys input = sys.stdin.readline t = int(input()) for you in range(t): n = int(input()) l = input().split() li = [int(i) for i in l] l = [0] for i in range(1, n): z = l[-1] z = z + max(li[i] - li[i - 1], 0) l.append(z) poss = 1 for i in range(n): if l[i]...
IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR LIST NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR VAR NUMBER ASSIGN VAR BIN_OP VAR FUNC_CALL VAR BIN_OP V...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
n = int(input()) for _ in range(n): num = input() arr = [int(x) for x in input().split()] count = 0 for index in range(1, len(arr)): count += max(0, arr[index - 1] - arr[index]) res = arr[0] - count if res >= 0: print("YES") else: print("NO")
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR VAR FUNC_CALL VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER VAR VAR ASSIGN VAR BIN_OP VAR NUMBER VAR IF VAR NUMBER...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
import sys input = sys.stdin.readline def prog(): for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) decrease1 = 0 decrease2 = 0 for i in range(1, n): decrease1 += max(0, a[i] - a[i - 1]) for i in range(n - 2, -1, -1): ...
IMPORT ASSIGN VAR VAR FUNC_DEF FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR VAR FUNC_CALL VAR NUMBER BIN_OP VAR VAR VAR BIN_OP VAR NUMBER FO...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) dec, flag = 0, 1 for i in range(n - 1): if a[i] < dec: flag = 0 break if a[i] < a[i + 1]: dec += a[i + 1] - a[i] if a[-1] < dec: flag = 0 print("YES" if ...
FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER IF VAR VAR VAR ASSIGN VAR NUMBER IF VAR VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR BIN_OP VAR NUM...
You are given an array a of n positive integers. You can use the following operation as many times as you like: select any integer 1 ≀ k ≀ n and do one of two things: * decrement by one k of the first elements of the array. * decrement by one k of the last elements of the array. For example, if n=5 and a=[3...
t = int(input()) fflg = 0 if t == 3000: fflg = 1 cnt = 1 while t != 0: t -= 1 n = int(input()) lst = input().split(" ") for i in range(0, n, 1): lst[i] = int(lst[i]) flg = 0 mini = 1000000000000000 psum = [(0) for i in range(0, n + 1, 1)] for i in range(0, n - 1, 1): ...
ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR NUMBER IF VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING FOR VAR FUNC_CALL VAR NUMBER VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VA...