Split (1)

train · 78.8k rows

description stringlengths 171 4k	code stringlengths 94 3.98k	normalized_code stringlengths 57 4.99k
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	n = int(input()) s = list(input()) ones = 0 zeros = 0 for ss in s: if ss == "1": ones += 1 else: zeros += 1 out = "" for i in range(2ones, 2n + 2 - 2**zeros): out += str(i) + " " print(out[:-1])	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR IF VAR STRING VAR NUMBER VAR NUMBER ASSIGN VAR STRING FOR VAR FUNC_CALL VAR BIN_OP NUMBER VAR BIN_OP BIN_OP BIN_OP NUMBER VAR NUMBER BIN_OP NUMBER VAR VAR BIN_OP FUNC_CALL VAR VAR STRING EXPR FUNC_CALL VAR VAR NUMBER
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	n = int(input()) s = str(input()) a1 = s.count("1") a0 = n - a1 b1 = pow(2, a1) b0 = pow(2, a0) c = pow(2, n) - b0 + 2 for i in range(b1, c): print(i, end=" ")	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR BIN_OP VAR VAR ASSIGN VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR BIN_OP BIN_OP FUNC_CALL VAR NUMBER VAR VAR NUMBER FOR VAR FUNC_CALL VAR VAR VAR EXPR FUNC_CALL VAR VAR STRING
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	import sys input = sys.stdin.readline inp = sys.stdin.readline def input(): return inp().strip() def ii(): return int(input()) def mi(): return map(int, input().split()) def li(): return list(map(int, input().split())) def solve(): n = ii() m = input() arr = [i for i in range((1 << n) + 1)] l = 1 r = 1 for i in m: if i == "0": r <<= 1 else: l <<= 1 print(*arr[l : len(arr) - r + 1]) def main(): solve() main()	IMPORT ASSIGN VAR VAR ASSIGN VAR VAR FUNC_DEF RETURN FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR VAR VAR FUNC_CALL VAR BIN_OP BIN_OP NUMBER VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR IF VAR STRING VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR VAR BIN_OP BIN_OP FUNC_CALL VAR VAR VAR NUMBER FUNC_DEF EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	import sys n = int(input()) s = input() a, b = 0, 0 x, y = 1, 2n for i in range(n): if s[i] == "0": y -= 2b b += 1 else: x += 2*a a += 1 ans = [] for j in range(x, y + 1): ans.append(j) print(ans)	IMPORT ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR VAR NUMBER NUMBER ASSIGN VAR VAR NUMBER BIN_OP NUMBER VAR FOR VAR FUNC_CALL VAR VAR IF VAR VAR STRING VAR BIN_OP NUMBER VAR VAR NUMBER VAR BIN_OP NUMBER VAR VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	n = int(input()) s = input() l = 0 r = 0 for i in range(len(s)): if s[i] == "1": l = l * 2 + 1 else: r = r * 2 + 1 r = pow(2, n) - r for i in range(l + 1, r + 1): print(i, end=" ")	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR IF VAR VAR STRING ASSIGN VAR BIN_OP BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR NUMBER VAR VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR STRING
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	J = input I = range G = 1 for K in I(G): B = int(J()) H = J() L = [] C = 0 D = 0 E = 1 F = 2B for A in H: if A == "0": F -= 2D D += 1 else: E += 2C C += 1 for A in I(E, F + 1): if A > 2B: continue print(A, end=" ")	ASSIGN VAR VAR ASSIGN VAR VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP NUMBER VAR FOR VAR VAR IF VAR STRING VAR BIN_OP NUMBER VAR VAR NUMBER VAR BIN_OP NUMBER VAR VAR NUMBER FOR VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP NUMBER VAR EXPR FUNC_CALL VAR VAR STRING
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	n = int(input()) s = input() larger = 0 smaller = 0 for i in range(len(s)): if s[i] == "1": smaller += 1 else: larger += 1 for i in range(2smaller, 2n - (2**larger - 2)): print(i, end=" ")	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR IF VAR VAR STRING VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP NUMBER VAR BIN_OP BIN_OP NUMBER VAR BIN_OP BIN_OP NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR STRING
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	n = int(input()) s = input() m = 2n fir = 2 s.count("1") sec = 2 ** s.count("0") print(*[x for x in range(fir, m - sec + 2)])	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR BIN_OP NUMBER VAR ASSIGN VAR BIN_OP NUMBER FUNC_CALL VAR STRING ASSIGN VAR BIN_OP NUMBER FUNC_CALL VAR STRING EXPR FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR VAR NUMBER
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	n = int(input()) s = list(input()) mn = 2 s.count("1") mx = 2n - 2 ** s.count("0") + 1 for i in range(mn, mx + 1): print(i, end=" ")	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR BIN_OP NUMBER FUNC_CALL VAR STRING ASSIGN VAR BIN_OP BIN_OP BIN_OP NUMBER VAR BIN_OP NUMBER FUNC_CALL VAR STRING NUMBER FOR VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR STRING
$2^n$ teams participate in a playoff tournament. The tournament consists of $2^n - 1$ games. They are held as follows: in the first phase of the tournament, the teams are split into pairs: team $1$ plays against team $2$, team $3$ plays against team $4$, and so on (so, $2^{n-1}$ games are played in that phase). When a team loses a game, it is eliminated, and each game results in elimination of one team (there are no ties). After that, only $2^{n-1}$ teams remain. If only one team remains, it is declared the champion; otherwise, the second phase begins, where $2^{n-2}$ games are played: in the first one of them, the winner of the game "$1$ vs $2$" plays against the winner of the game "$3$ vs $4$", then the winner of the game "$5$ vs $6$" plays against the winner of the game "$7$ vs $8$", and so on. This process repeats until only one team remains. The skill level of the $i$-th team is $p_i$, where $p$ is a permutation of integers $1$, $2$, ..., $2^n$ (a permutation is an array where each element from $1$ to $2^n$ occurs exactly once). You are given a string $s$ which consists of $n$ characters. These characters denote the results of games in each phase of the tournament as follows: if $s_i$ is equal to 0, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the lower skill level wins; if $s_i$ is equal to 1, then during the $i$-th phase (the phase with $2^{n-i}$ games), in each match, the team with the higher skill level wins. Let's say that an integer $x$ is winning if it is possible to find a permutation $p$ such that the team with skill $x$ wins the tournament. Find all winning integers. -----Input----- The first line contains one integer $n$ ($1 \le n \le 18$). The second line contains the string $s$ of length $n$ consisting of the characters 0 and/or 1. -----Output----- Print all the winning integers $x$ in ascending order. -----Examples----- Input 3 101 Output 4 5 6 7 Input 1 1 Output 2 Input 2 01 Output 2 3 -----Note----- None	t = int(input()) st = input() n0 = 0 n1 = 0 j = 0 while 0 <= j < t: if int(st[j]) == 0: n0 = n0 + 1 elif st[j] == "1": n1 = n1 + 1 j = j + 1 y1 = pow(2, t) - pow(2, n0) + 1 x1 = pow(2, n1) j = x1 while x1 <= j <= y1: print(j, end=" ") j = j + 1 print("")	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE NUMBER VAR VAR IF FUNC_CALL VAR VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER IF VAR VAR STRING ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP BIN_OP FUNC_CALL VAR NUMBER VAR FUNC_CALL VAR NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR VAR WHILE VAR VAR VAR EXPR FUNC_CALL VAR VAR STRING ASSIGN VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR STRING
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) P = list(map(int, input().split()))[::-1] P.pop() ans = 0 while h > 2 and P: w = P.pop() if h - w == 1: if P: q = P.pop() if h - q != 2: ans += 1 P.append(q) else: ans += 1 h -= 2 else: h = w + 1 P.append(w) print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR ASSIGN VAR NUMBER WHILE VAR NUMBER VAR ASSIGN VAR FUNC_CALL VAR IF BIN_OP VAR VAR NUMBER IF VAR ASSIGN VAR FUNC_CALL VAR IF BIN_OP VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) def solve(): h, n = [int(x) for x in input().split()] p = [int(x) for x in input().split()] crystal = 0 p.append(0) i = 1 while i < n: if p[i] - 1 > p[i + 1]: crystal += 1 i += 1 else: i += 2 print(crystal) for _ in range(q): solve()	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def I(): return sys.stdin.readline().rstrip() q = int(I()) for _ in range(q): h, n = map(int, I().split()) p = list(map(int, I().split())) i, ans = 0, 0 while i < n: if h == p[i]: pass elif p[i] == 1: h = 0 elif i < n - 1 and p[i] - 1 == p[i + 1]: h = p[i + 1] else: ans += 1 h = p[i] - 1 i += 1 print(ans)	IMPORT FUNC_DEF RETURN FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER NUMBER WHILE VAR VAR IF VAR VAR VAR IF VAR VAR NUMBER ASSIGN VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	tc = int(input()) while tc > 0: h, n = [int(x) for x in input().split()] a = [int(x) for x in input().split()] i = 0 s = 0 arr = [] while i < n: if i > 0 and a[i] != a[i - 1] - 1: arr.append(False) s += 1 arr.append(True) i += 1 s += 1 if a[-1] != 1: arr.append(False) s += 1 h = s dp = [10*10] h dp[0] = 0 for i in range(h - 1): a = 0 if not arr[i + 1]: a = 0 else: a = 1 dp[i + 1] = min(dp[i + 1], a + dp[i]) if i + 2 < h: if not arr[i + 2]: if not arr[i + 1]: a = 2 else: a = 1 elif not arr[i + 1]: a = 1 else: a = 0 dp[i + 2] = min(dp[i + 2], a + dp[i]) if h - 2 >= 0: if arr[h - 1]: print(min(dp[h - 2], dp[h - 1])) else: print(min(dp[h - 2] + 1, dp[h - 1])) else: print(dp[h - 1]) tc -= 1	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR LIST WHILE VAR VAR IF VAR NUMBER VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR NUMBER VAR NUMBER VAR NUMBER IF VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER VAR NUMBER ASSIGN VAR VAR ASSIGN VAR BIN_OP LIST BIN_OP NUMBER NUMBER VAR ASSIGN VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER IF VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER BIN_OP VAR VAR VAR IF BIN_OP VAR NUMBER VAR IF VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER IF VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER BIN_OP VAR VAR VAR IF BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR BIN_OP VAR NUMBER VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = [int(w) for w in input().split()] p = [int(w) for w in input().split()] p.append(0) r = 0 i = 1 while i < n: if p[i] == p[i + 1] + 1: i += 2 else: i += 1 r += 1 print(r)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys readline = sys.stdin.readline read = sys.stdin.read ns = lambda: readline().rstrip() ni = lambda: int(readline().rstrip()) nm = lambda: map(int, readline().split()) nl = lambda: list(map(int, readline().split())) prn = lambda x: print(x, sep="\n") def solve(): h, n = nm() l = nl() + [0] 2 idx = 0 c = 0 while idx < n - 1: if l[idx] <= l[idx + 1] + 1: if l[idx + 2] + 2 >= l[idx]: idx += 2 continue else: c += 1 idx += 1 l[idx] = l[idx + 1] + 1 else: l[idx] = l[idx + 1] + 1 print(c) return T = ni() for _ in range(T): solve()	IMPORT ASSIGN VAR VAR ASSIGN VAR VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR STRING FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR BIN_OP LIST NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR VAR VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR RETURN ASSIGN VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) arr = list(map(int, input().split())) i, ans = 1, 0 while i < n - 1: if arr[i] == arr[i + 1] + 1: i += 2 else: i += 1 ans += 1 if i == n - 1 and arr[i] != 1 and arr[i] != 0: ans += 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER NUMBER WHILE VAR BIN_OP VAR NUMBER IF VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER VAR VAR NUMBER VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys input = sys.stdin.buffer.readline q = int(input()) for i in range(q): h, n = [int(item) for item in input().split()] a = [int(item) for item in input().split()] + [0, 0, 0] ans = 0 itr = 0 while a[itr] != 0: if a[itr] - a[itr + 1] <= 1 and a[itr + 1] - a[itr + 2] <= 1: itr += 2 elif a[itr] - a[itr + 1] <= 1 and a[itr + 1] - a[itr + 2] > 1: a[itr + 1] = a[itr + 2] + 1 ans += 1 itr += 1 elif a[itr] - a[itr + 1] > 1: a[itr] = a[itr + 1] + 1 print(ans)	IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	Q = int(input()) for q in range(Q): h, n = tuple(map(int, input().split())) arr = list(map(int, input().split())) arr.append(0) i = 0 ans = 0 now = arr[0] while i < len(arr) - 2: x = arr[i + 1] if now != x + 1: now = x + 1 elif now == arr[i + 2] + 2: now = arr[i + 2] i += 2 else: now = arr[i + 2] + 1 i += 1 ans += 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR NUMBER WHILE VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import time q = int(input()) ans = [] start = time.time() for i in range(q): h, n = (int(j) for j in input().split()) p = [int(j) for j in input().split()] a = 0 now = 1 while now < n: if now == n - 1: if p[now] > 1: a += 1 now += 1 elif p[now] - 1 != p[now + 1]: a += 1 now += 1 else: now += 2 ans.append(a) for i in range(q): print(ans[i]) finish = time.time()	IMPORT ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF VAR BIN_OP VAR NUMBER IF VAR VAR NUMBER VAR NUMBER VAR NUMBER IF BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR VAR ASSIGN VAR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys t = int(input()) input = sys.stdin.readline while t > 0: t -= 1 h, n = map(int, input().split()) a = [int(x) for x in input().split()] a.append(0) c = 0 i = 0 while i < n - 1: if a[i] - a[i + 1] >= 2: a[i] = a[i + 1] + 1 elif a[i + 2] == a[i] - 2: i += 2 else: c += 1 a[i + 1] -= 1 i += 1 print(c)	IMPORT ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR WHILE VAR NUMBER VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) for q in range(t): h, n = list(map(int, input().split())) p = list(map(int, input().split())) s = 0 i = 1 while h > 2 and i < n: if h - p[i] == 1: if i + 1 < n: if p[i] - p[i + 1] > 1: s += 1 h = p[i] - 1 i += 1 else: h = p[i + 1] i += 2 elif p[i] == 1: h = 0 else: s += 1 h = p[i] - 1 i += 1 else: h = p[i] + 1 print(s)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER VAR VAR IF BIN_OP VAR VAR VAR NUMBER IF BIN_OP VAR NUMBER VAR IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	def scale(p): offset = 0 last = 0 newp = [] for pi in p: diff = pi - last if diff > 2: offset += diff - 2 newp.append(pi - offset) last = pi return newp def f(h, p): x = 0 y = 0 for i in range(3, h + 1): a = 1 if i - 1 in p else 0 b = 1 if i - 2 in p else 0 z = min(y + a, x + (1 - a) + (1 - b)) y, x = z, y return y q = int(input()) for _ in range(q): h, n = map(int, input().split(" ")) p = list(map(int, input().split(" "))) p.reverse() p = scale(p) h = p[-1] s = set(p) print(f(h, s))	FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR LIST FOR VAR VAR ASSIGN VAR BIN_OP VAR VAR IF VAR NUMBER VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR BIN_OP VAR VAR ASSIGN VAR VAR RETURN VAR FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR BIN_OP VAR VAR BIN_OP BIN_OP VAR BIN_OP NUMBER VAR BIN_OP NUMBER VAR ASSIGN VAR VAR VAR VAR RETURN VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING EXPR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) size = 2 * 100000 + 1 res = [] p = [(0) for i in range(size)] d = [(0) for i in range(size)] for k in range(0, q): h, n = [int(x) for x in input().split()] p = list(map(int, input().split())) d[0] = 0 d[1] = 1 for i in range(2, n): if p[i - 1] == p[i] + 1: d[i] = min(d[i - 2], d[i - 1] + 1) else: d[i] = min(d[i - 2] + 2, d[i - 1] + 1) if p[n - 1] == 1: d[n] = min(d[n - 2], d[n - 1]) elif p[n - 1] == 2: d[n] = min(d[n - 2] + 2, d[n - 1]) else: d[n] = min(d[n - 2] + 2, d[n - 1]) if n == 1: d[n] = 0 res.append(d[n]) for i in range(0, q): print(res[i])	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR BIN_OP BIN_OP NUMBER NUMBER NUMBER ASSIGN VAR LIST ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER NUMBER ASSIGN VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR FUNC_CALL VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR FUNC_CALL VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER IF VAR NUMBER ASSIGN VAR VAR NUMBER EXPR FUNC_CALL VAR VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR EXPR FUNC_CALL VAR VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys readline = sys.stdin.readline Q = int(readline()) inf = 10*9 Ans = [None] Q for qu in range(Q): H, N = map(int, readline().split()) P = list(map(int, readline().split())) ans = 0 cur = P[0] curidx = 0 step = set(P) while True: if cur <= 2: break if curidx >= N - 1: break if P[curidx + 1] + 1 <= 2: break if P[curidx + 1] - 1 in step: curidx += 2 cur = P[curidx] else: ans += 1 curidx += 1 cur = P[curidx] - 1 Ans[qu] = ans print("\n".join(map(str, Ans)))	IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR BIN_OP NUMBER NUMBER ASSIGN VAR BIN_OP LIST NONE VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR WHILE NUMBER IF VAR NUMBER IF VAR BIN_OP VAR NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR VAR NUMBER ASSIGN VAR VAR VAR VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER ASSIGN VAR VAR VAR EXPR FUNC_CALL VAR FUNC_CALL STRING FUNC_CALL VAR VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): inp = input() inp_arr = inp.split(" ") h = int(inp_arr[0]) n = int(inp_arr[1]) inp_p = input() inp_p_arr = inp_p.split(" ") inp_p_arr = [int(j) for j in inp_p_arr] inp_p_arr.append(0) count = 0 par_che = 1 for j in range(1, n): if inp_p_arr[j] - inp_p_arr[j + 1] == 1: par_che += 1 else: if par_che % 2 == 1: count += 1 par_che = 1 print(count)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR VAR VAR VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	def mp(): return map(int, input().split()) t = int(input()) for tt in range(t): h, n = mp() a = list(mp()) + [0] ans = 0 last = h i = 1 while i < n: last = min(last, a[i] + 1) if a[i + 1] == last - 2: last = a[i + 1] i += 2 else: ans += 1 last -= 2 i += 1 print(ans)	FUNC_DEF RETURN FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR LIST NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER WHILE VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	R = lambda: map(int, input().split()) (q,) = R() for _ in [0] * q: h, n = R() c, d = 1, 0 for x in R(): if h - x > 1: d += c c = 0 c ^= 1 h = x print((d, d + c)[x > 1])	ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FOR VAR BIN_OP LIST NUMBER VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR IF BIN_OP VAR VAR NUMBER VAR VAR ASSIGN VAR NUMBER VAR NUMBER ASSIGN VAR VAR EXPR FUNC_CALL VAR VAR BIN_OP VAR VAR VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	from sys import stdin, stdout input = stdin.readline def case(): h, n = map(int, input().split()) platforms = [int(i) for i in input().split()] + [0] i = 0 pos = platforms[i] crystal_counter = 0 while platforms[i] and i + 1 < n: if platforms[i] - platforms[i + 1] > 1: platforms[i] = platforms[i + 1] + 1 continue if platforms[i] - platforms[i + 2] > 2: crystal_counter += 1 platforms[i + 1] = platforms[i + 2] + 1 i += 1 elif platforms[i] - platforms[i + 2] == 2: i += 2 return crystal_counter def main(): ans = [] q = int(input()) for _ in range(q): ans.append(str(case())) stdout.write("\n".join(ans)) main()	ASSIGN VAR VAR FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR VAR ASSIGN VAR NUMBER WHILE VAR VAR BIN_OP VAR NUMBER VAR IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER RETURN VAR FUNC_DEF ASSIGN VAR LIST ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR EXPR FUNC_CALL VAR FUNC_CALL STRING VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) while t > 0: t = t - 1 hn = input().split() h = int(hn[0]) n = int(hn[1]) pos = input().split() pos = [int(val) for val in pos] curr = h curr_pos = 1 no_crystal = 0 while curr > 2: if curr_pos >= len(pos): break if curr - 1 == pos[curr_pos]: if curr_pos == len(pos) - 1 or curr - 2 != pos[curr_pos + 1]: no_crystal = no_crystal + 1 curr = curr - 2 curr_pos = curr_pos + 1 else: curr_pos = curr_pos + 2 else: curr = pos[curr_pos] + 1 print(no_crystal)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR FUNC_CALL VAR VAR IF BIN_OP VAR NUMBER VAR VAR IF VAR BIN_OP FUNC_CALL VAR VAR NUMBER BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): h, n = map(int, input().split()) pi = list(map(int, input().split())) pi.append(0) num = 10**9 + 1 dp = [[num, num] for i in range(n + 1)] dp[0][0] = 0 for i in range(n): dp[i + 1][1] = min(dp[i + 1][1], dp[i][0]) dp[i + 1][1] = min(dp[i + 1][1], dp[i][1] + 1) if i < n and pi[i + 1] == pi[i] - 1: dp[i + 1][0] = min(dp[i + 1][0], dp[i][1]) if i < n and pi[i + 1] == pi[i] - 2: dp[i + 1][0] = min(dp[i + 1][0], dp[i][0] + 1) if i < n - 1 and pi[i + 1] == pi[i] - 1 and pi[i + 2] == pi[i] - 2: dp[i + 2][0] = min(dp[i + 2][0], dp[i][0]) if pi[i] == 1: dp[i + 1][0] = min(dp[i + 1][0], dp[i][0]) dp[i + 1][0] = min(dp[i + 1][0], dp[i][1]) print(min(dp[-1]))	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP BIN_OP NUMBER NUMBER NUMBER ASSIGN VAR LIST VAR VAR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER NUMBER NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR VAR NUMBER NUMBER IF VAR VAR VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER VAR VAR NUMBER IF VAR VAR VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER VAR VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER VAR VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	n = int(input()) for z in range(n): h, am = map(int, input().split()) arr = list(map(int, input().split())) ch = h i = 1 ac = 0 while i < am: if ch - arr[i] >= 2: ch = arr[i] + 1 elif i < am - 1 and arr[i + 1] == ch - 2 or ch == 2: ch -= 2 i += 2 else: ch -= 2 i += 1 ac += 1 print(ac)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP VAR VAR VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER IF VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): h, n = map(int, input().split()) p = list(map(int, input().split())) used = [0] for i in range(1, n): if i == 1: used.append(1) elif p[i] >= 1: var = 10000000000000 if p[i - 1] - p[i] == 1: used.append(used[i - 2]) else: used.append(used[i - 1] + 1) i = n - 1 ans = 0 if p[i] > 2: print(used[-1]) elif n >= 2 and p[i] == 1: print(min(used[-2], used[-1])) else: print(used[-1])	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER VAR VAR NUMBER EXPR FUNC_CALL VAR VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER IF VAR VAR NUMBER EXPR FUNC_CALL VAR VAR NUMBER IF VAR NUMBER VAR VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = map(int, input().split()) ps = list(map(int, input().split())) + [0, 0] ps.reverse() cur = n - 1 crystals = 0 while ps and ps[-1] > 1: if ps[-2] == h - 1: if ps[-3] == h - 2: ps.pop() ps.pop() else: ps.pop() ps[-1] = h - 2 crystals += 1 h -= 2 else: ps[-1] = ps[-2] + 1 h = ps[-1] print(crystals)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER NUMBER EXPR FUNC_CALL VAR ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR NUMBER NUMBER IF VAR NUMBER BIN_OP VAR NUMBER IF VAR NUMBER BIN_OP VAR NUMBER EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR ASSIGN VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR NUMBER BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for j in range(q): h, n = list(map(int, input().split())) h_list = list(map(int, input().split())) if n == 1: ans = 0 elif n == 2: if h_list[1] >= 2: ans = 1 else: ans = 0 else: ans = 0 i = 0 while i - ans <= n - 3: if h_list[i - ans + 1] != h_list[i - ans + 2] + 1: ans += 1 i += 2 if n - (i - ans) == 2: if h_list[n - 1] >= 2: ans += 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR IF VAR NUMBER ASSIGN VAR NUMBER IF VAR NUMBER IF VAR NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE BIN_OP VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP BIN_OP VAR VAR NUMBER BIN_OP VAR BIN_OP BIN_OP VAR VAR NUMBER NUMBER VAR NUMBER VAR NUMBER IF BIN_OP VAR BIN_OP VAR VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = map(int, input().split()) p = list(map(int, input().split())) + [0] cnt = 0 i = 1 while i <= n - 1: if p[i] + 1 - p[i + 1] >= 3: cnt += 1 elif p[i] - p[i + 1] == 1: i += 1 i += 1 print(cnt)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF BIN_OP BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) for _ in range(t): h, n = map(int, input().split()) arr = list(map(int, input().split())) cur = h count = 0 i = 0 while cur > 0: if cur <= 2 or i == n - 1: break elif arr[i + 1] == cur - 1: if i + 2 <= n - 1: if arr[i + 2] == cur - 2: cur -= 2 i += 2 else: i += 1 cur -= 2 count += 1 else: if i == n - 1 or cur <= 2: break i += 1 cur -= 2 count += 1 else: cur = arr[i + 1] + 1 print(count)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR NUMBER VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for i in range(int(input())): h, n = map(int, input().split()) p = list(map(int, input().split())) i = 1 res = 0 while i < n: if h - p[i] == 1: if i + 1 < n: if p[i] - p[i + 1] != 1: res += 1 h = p[i] - 1 i += 1 else: h = p[i + 1] i += 2 elif h > 2: res += 1 break else: break else: h = p[i] + 1 print(res)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP VAR VAR VAR NUMBER IF BIN_OP VAR NUMBER VAR IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER IF VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): h, n = map(int, input().split()) p = [int(i) for i in input().split()] now = p[0] index = 0 p = p[1:] p.append(0) ans = 0 while index < n - 1: if now - p[index] == 1 and p[index] - p[index + 1] == 1: now = p[index + 1] index += 2 elif now - p[index] == 1 and p[index] - p[index + 1] != 1: now = p[index] - 1 index += 1 ans += 1 else: now = p[index] + 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF BIN_OP VAR VAR VAR NUMBER BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER IF BIN_OP VAR VAR VAR NUMBER BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys input = sys.stdin.readline Q = int(input()) Query = [] for _ in range(Q): H, N = map(int, input().split()) A = list(map(int, input().split())) Query.append((H, N, A)) for H, N, A in Query: A.append(0) now = H i = 0 c = 0 while now > 0: if now - A[i + 1] > 1: now = A[i + 1] + 1 elif i + 2 >= N + 1: break elif now - A[i + 2] > 2: i += 1 c += 1 now -= 2 else: i += 2 now -= 2 print(c)	IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR VAR VAR FOR VAR VAR VAR VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF BIN_OP VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR NUMBER BIN_OP VAR NUMBER IF BIN_OP VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): h, n = [int(j) for j in input().split()] a = [int(x) for x in input().split()] + [0] * 2 result, y = 0, 0 while y < n: if a[y + 1] - a[y + 2] <= 1: y += 2 else: result += 1 a[y + 1] += 1 y += 1 print(result)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR BIN_OP LIST NUMBER NUMBER ASSIGN VAR VAR NUMBER NUMBER WHILE VAR VAR IF BIN_OP VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys q = int(input()) for _ in range(q): h, n = map(int, sys.stdin.readline().split()) p = iter(list(map(int, sys.stdin.readline().split())) + [0]) cost = 0 akt = next(p) a = next(p) if a == 0: print(0) else: b = next(p) while True: if a - b == 1: akt = b if akt == 0: break else: a = next(p) if a == 0: break else: b = next(p) else: cost += 1 akt = a - 1 a = b if a == 0: break else: b = next(p) print(cost)	IMPORT ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR WHILE NUMBER IF BIN_OP VAR VAR NUMBER ASSIGN VAR VAR IF VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR IF VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR VAR IF VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) p = list(map(int, input().split())) xyz = set(p) ans = 0 for i in p: if i < h: h = i + 1 if h <= 2: break if i == h - 1: if h - 2 in xyz: h -= 2 else: ans += 1 h -= 2 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER FOR VAR VAR IF VAR VAR ASSIGN VAR BIN_OP VAR NUMBER IF VAR NUMBER IF VAR BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER VAR VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for h in range(int(input())): h, n = map(int, input().strip().split()) arr = list(map(int, input().strip().split())) arr.append(0) ans = 0 curr = h for i in range(n): if curr == arr[i]: continue if arr[i] - 1 != arr[i + 1]: ans += 1 curr = arr[i] - 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR FOR VAR FUNC_CALL VAR VAR IF VAR VAR VAR IF BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def main(): q = int(input()) allans = [] for _ in range(q): h, n = readIntArr() p = readIntArr() p.append(0) prevP = h + 1 platformCnts = 0 ans = 0 for currP in p: if currP + 1 == prevP: platformCnts += 1 else: if platformCnts % 2 == 0: ans += 1 platformCnts = 2 prevP = currP allans.append(ans) multiLineArrayPrint(allans) return input = lambda: sys.stdin.readline().rstrip("\r\n") def oneLineArrayPrint(arr): print(" ".join([str(x) for x in arr])) def multiLineArrayPrint(arr): print("\n".join([str(x) for x in arr])) def multiLineArrayOfArraysPrint(arr): print("\n".join([" ".join([str(x) for x in y]) for y in arr])) def readIntArr(): return [int(x) for x in input().split()] def makeArr(defaultValFactory, dimensionArr): dv = defaultValFactory da = dimensionArr if len(da) == 1: return [dv() for _ in range(da[0])] else: return [makeArr(dv, da[1:]) for _ in range(da[0])] def queryInteractive(i, j): print("? {} {}".format(i, j)) sys.stdout.flush() return int(input()) def answerInteractive(ans): print("! {}".format(" ".join([str(x) for x in ans]))) sys.stdout.flush() inf = float("inf") MOD = 10**9 + 7 for _abc in range(1): main()	IMPORT FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR IF BIN_OP VAR NUMBER VAR VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR RETURN ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING FUNC_DEF EXPR FUNC_CALL VAR FUNC_CALL STRING FUNC_CALL VAR VAR VAR VAR FUNC_DEF EXPR FUNC_CALL VAR FUNC_CALL STRING FUNC_CALL VAR VAR VAR VAR FUNC_DEF EXPR FUNC_CALL VAR FUNC_CALL STRING FUNC_CALL STRING FUNC_CALL VAR VAR VAR VAR VAR VAR FUNC_DEF RETURN FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF ASSIGN VAR VAR ASSIGN VAR VAR IF FUNC_CALL VAR VAR NUMBER RETURN FUNC_CALL VAR VAR FUNC_CALL VAR VAR NUMBER RETURN FUNC_CALL VAR VAR VAR NUMBER VAR FUNC_CALL VAR VAR NUMBER FUNC_DEF EXPR FUNC_CALL VAR FUNC_CALL STRING VAR VAR EXPR FUNC_CALL VAR RETURN FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF EXPR FUNC_CALL VAR FUNC_CALL STRING FUNC_CALL STRING FUNC_CALL VAR VAR VAR VAR EXPR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR BIN_OP BIN_OP NUMBER NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = list(map(int, input().split())) arr = list(map(int, input().split())) + [0] ans = 0 cur = h for i in range(1, n): if arr[i] == cur: continue elif arr[i + 1] == arr[i] - 1: cur = arr[i] - 1 else: ans += 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR VAR IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for i in range(int(input())): h, n = map(int, input().split()) p = list(map(int, input().split())) p.append(0) s = set(p) ans = 0 i = 1 while i < n + 1 and h > 2: if h - 1 in s: h -= 2 while i < n + 1 and p[i] >= h: i += 1 if h not in s: ans += 1 else: h = p[i] + 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER VAR NUMBER IF BIN_OP VAR NUMBER VAR VAR NUMBER WHILE VAR BIN_OP VAR NUMBER VAR VAR VAR VAR NUMBER IF VAR VAR VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): h, n = [int(x) for x in input().split()] a = [int(x) for x in input().split()] + [10**10] counter = 0 arr = 0 for i in range(1, n + 1): if a[i] == a[i - 1] - 1: counter += 1 else: if counter % 2 == 1 and a[i - 1] != 1: arr += 1 counter = 1 print(arr)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST BIN_OP NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER IF VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def main(): import sys input = sys.stdin.readline t = int(input()) for _ in range(t): h, N = map(int, input().split()) A = list(map(int, input().split())) ans = 0 i = 0 while True: if i == N - 1: break if A[i] - A[i + 1] > 1: A[i] = A[i + 1] + 1 else: if i == N - 2: if A[i] == 2: break else: ans += 1 break if A[i + 2] == A[i + 1] - 1: i += 2 else: ans += 1 i += 1 print(ans) main()	IMPORT FUNC_DEF IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE NUMBER IF VAR BIN_OP VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER IF VAR VAR NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	def request(): h, n = map(int, input().split()) p = list(map(int, input().split())) c = 0 i = 0 while i < n - 1: if p[i] - p[i + 1] > 1: p[i] = p[i + 1] + 1 if p[i + 1] + 1 == p[i]: if i + 2 >= n: if p[i] > 2: c += 1 elif p[i + 2] + 1 != p[i + 1]: c += 1 p[i + 1] -= 1 i -= 1 i += 1 i += 1 return c for i in range(int(input())): print(request())	FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR VAR IF BIN_OP VAR NUMBER VAR IF VAR VAR NUMBER VAR NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER RETURN VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR EXPR FUNC_CALL VAR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) while t: h, n = map(int, input().split()) l = list(map(int, input().split())) i = 0 lol = 0 cou = 0 while h > 0 and i < len(l): if i + 2 >= len(l): lol = 1 break if l[i + 1] != h - 1: h = l[i + 1] + 1 elif l[i + 2] != h - 2: cou += 1 h -= 2 l[i + 1] = h i += 1 else: h -= 2 i += 2 if i + 1 < len(l): if l[i + 1] + 1 > 2: cou += 1 print(cou) t -= 1	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER VAR FUNC_CALL VAR VAR IF BIN_OP VAR NUMBER FUNC_CALL VAR VAR ASSIGN VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR VAR NUMBER VAR NUMBER VAR NUMBER IF BIN_OP VAR NUMBER FUNC_CALL VAR VAR IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = map(int, input().split()) P = [int(i) for i in input().split()] P += [0] n += 1 cur = h next = 1 ans = 0 while cur > 0 and next <= n - 2: if P[next + 1] < P[next] - 1: cur = P[next] - 1 next += 1 ans += 1 else: cur = P[next + 1] next += 2 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR VAR LIST NUMBER VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) p = [int(o) for o in input().split()] ans = 0 p.append(0) i = 0 while p[i] > 2 and i < n: if p[i + 1] != p[i] - 1: p[i] = p[i + 1] + 1 elif p[i + 1] == p[i] - 1 and p[i + 2] == p[i] - 2: i += 2 else: p[i + 1] = p[i] - 2 i += 1 ans += 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR NUMBER VAR VAR IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys input = sys.stdin.readline t = int(input()) for _ in range(t): h, n = map(int, input().split()) p = list(map(int, input().split())) + [0] n += 1 p = p[::-1] ans = 0 i = n - 1 while True: if i <= 1: break if p[i - 1] + 1 < p[i]: p.pop() p.append(p[i - 1] + 1) elif p[i - 2] + 1 == p[i - 1]: p.pop() p.pop() i -= 2 else: p.pop() ans += 1 pi = p.pop() p.append(pi - 1) i -= 1 print(ans)	IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER WHILE NUMBER IF VAR NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR VAR EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR EXPR FUNC_CALL VAR VAR NUMBER EXPR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR EXPR FUNC_CALL VAR BIN_OP VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = map(int, input().split()) p = list(map(int, input().split()))[1:] dangers = [] rows = 1 i = 0 while i < len(p): if i > 0 and p[i] == p[i - 1] - 1: rows += 1 else: rows = 1 if (i == len(p) - 1 or p[i + 1] != p[i] - 1) and p[i] > 1: if rows % 2: dangers.append(p[i]) i += 1 print(len(dangers))	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR NUMBER ASSIGN VAR LIST ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR IF VAR NUMBER VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER IF VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR VAR NUMBER IF BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR VAR VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	def work(): h, n = (int(x) for x in input().split()) p = [int(x) for x in input().split()] p.append(0) p.append(-1) num = 0 ans = 0 while num < n: if p[num + 1] == p[num] - 1: if p[num + 2] == p[num] - 2: num = num + 2 else: ans = ans + 1 num = num + 1 p[num] = p[num] - 1 else: p[num] = p[num + 1] + 1 print(ans) q = int(input()) for i in range(q): work()	FUNC_DEF ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def input(): return sys.stdin.readline()[:-1] def main(): q = int(input()) for _ in range(q): h, n = map(int, input().split()) s = list(map(int, input().split())) + [0] now = h ans = 0 i = 1 while now > 2: if s[i] == now - 1: if s[i + 1] == now - 2: i += 2 else: ans += 1 i += 1 now -= 2 else: now = s[i] + 1 print(ans) main()	IMPORT FUNC_DEF RETURN FUNC_CALL VAR NUMBER FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	T = int(input()) for t in range(T): h, n = list(map(int, input().strip().split(" "))) steps = list(map(int, input().strip().split(" "))) steps.append(0) cur = n danger = 0 ret = 0 index = 1 cur = steps[index] + 1 while cur > 2: if steps[index + 1] == cur - 2: index += 2 else: index += 1 ret += 1 cur = steps[index] + 1 print(ret)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR STRING EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER WHILE VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for t in range(int(input())): n, m = map(int, input().split()) a = list(map(int, input().split())) a.append(0) if m == 1: print(0) continue b = [] for i in range(m): b.append(a[i] - a[i + 1]) i = 0 count = 0 while i < m - 1: if b[i + 1] == 1: i += 2 elif b[i + 1] > 1: count += 1 i += 1 print(count)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR BIN_OP VAR VAR VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	def solve(platforms, n): h = platforms[0] count = 0 i = 0 while i < n: if h <= 2: break if platforms[i] == h: i += 1 if i < n and i + 1 < n: if platforms[i] == h - 1 and platforms[i + 1] == h - 2: h -= 2 i += 1 elif platforms[i] == h - 1: count += 1 h -= 1 elif platforms[i] == h - 2: h -= 1 else: h = platforms[i] + 1 elif i < n: if platforms[i] == h - 1: count += 1 h -= 1 elif platforms[i] == h - 2: h -= 1 else: h = platforms[i] + 1 print(count) def main(): q = int(input()) for i in range(q): h, n = map(int, input().split()) platforms = list(map(int, input().split())) solve(platforms, n) main()	FUNC_DEF ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF VAR NUMBER IF VAR VAR VAR VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR IF VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER IF VAR VAR IF VAR VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR VAR VAR EXPR FUNC_CALL VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	n = int(input()) for _ in range(n): h, n = map(int, input().split()) P = list(map(int, input().split())) + [0, 0] res = 0 flg = 0 for i in range(n): if flg == 1: flg = 0 continue if P[i] - 1 >= P[i + 1]: P[i] = P[i + 1] + 1 if P[i] - P[i + 2] > 2: P[i + 1] = P[i + 2] + 1 res += 1 else: flg = 1 print(res)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR IF VAR NUMBER ASSIGN VAR NUMBER IF BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def get_ints(): return list(map(int, sys.stdin.readline().strip().split())) def solve(H, N, P): if N == 1: return 0 ans = 0 i = 0 h = P[1] + 1 while i < N - 2: h = P[i + 1] + 1 diff = h - P[i + 2] if diff > 2: ans += 1 next_h = P[i + 2] + 1 i += 1 else: next_h = P[i + 2] i += 2 h = next_h if h > P[-1] and P[-1] + 1 >= 3: ans += 1 return ans T = int(input()) for _ in range(T): H, N = map(int, input().split()) P = get_ints() print(solve(H, N, P))	IMPORT FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR FUNC_DEF IF VAR NUMBER RETURN NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER WHILE VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR VAR BIN_OP VAR NUMBER IF VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR VAR IF VAR VAR NUMBER BIN_OP VAR NUMBER NUMBER NUMBER VAR NUMBER RETURN VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	tests = int(input()) for i in range(tests): h, n = [int(x) for x in input().split()] line = [int(x) for x in input().split()] total_cost = 0 k = 0 length = 0 while k < len(line) and line[k] != 1: length += 1 if k < len(line) - 1 and line[k] == line[k + 1] + 1: pass else: if length % 2 == 0: total_cost += 1 k += 1 break k += 1 length = 1 while k < len(line) and line[k] != 1: if k < len(line) - 1 and line[k] == line[k + 1] + 1: length += 1 else: if length % 2 == 0: pass else: total_cost += 1 length = 1 k += 1 print(total_cost)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR VAR VAR NUMBER VAR NUMBER IF VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR VAR VAR NUMBER IF VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	def crystal(h, n, l): if n == h: return 0 count = 0 l.append(0) i = 1 while i < n: if l[i] - l[i + 1] >= 2: count += 1 i += 1 else: i += 2 return count tc = int(input()) for _ in range(tc): h, n = map(int, input().split()) l = list(map(int, input().split())) print(crystal(h, n, l))	FUNC_DEF IF VAR VAR RETURN NUMBER ASSIGN VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER RETURN VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for itr in range(int(input())): h, o = list(map(int, input().split())) a = list(map(int, input().split())) a = a[::-1] a.pop(-1) ans = 0 while h > 2: if len(a) == 0: break if h - 1 == a[-1]: if len(a) > 1 and h - 2 == a[-2]: h -= 2 a.pop(-1) a.pop(-1) else: ans += 1 h -= 2 a.pop(-1) else: h = a[-1] + 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF FUNC_CALL VAR VAR NUMBER IF BIN_OP VAR NUMBER VAR NUMBER IF FUNC_CALL VAR VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for j in range(q): d = {} h, n = map(int, input().split()) P = list(map(int, input().split())) P.append(0) k = 0 j = 0 while 1: try: if P[j + 1] - P[j + 2] == 1: h = P[j + 2] j = j + 2 else: h = P[j + 2] j = j + 1 k += 1 except: break print(k)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR DICT ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def input(): return sys.stdin.readline().strip() def list2d(a, b, c): return [([c] * b) for i in range(a)] def list3d(a, b, c, d): return [[([d] * c) for j in range(b)] for i in range(a)] def list4d(a, b, c, d, e): return [[[([e] * d) for j in range(c)] for j in range(b)] for i in range(a)] def ceil(x, y=1): return int(-(-x // y)) def INT(): return int(input()) def MAP(): return map(int, input().split()) def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)] def Yes(): print("Yes") def No(): print("No") def YES(): print("YES") def NO(): print("NO") sys.setrecursionlimit(109) INF = float("inf") MOD = 109 + 7 for _ in range(INT()): H, N = MAP() A = LIST() + [0] * 2 ans = 0 i = 0 while i < N: if A[i + 1] - A[i + 2] <= 1: i += 2 else: ans += 1 A[i + 1] += 1 i += 1 print(ans)	IMPORT FUNC_DEF RETURN FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN BIN_OP LIST VAR VAR VAR FUNC_CALL VAR VAR FUNC_DEF RETURN BIN_OP LIST VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR FUNC_DEF RETURN BIN_OP LIST VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR FUNC_DEF NUMBER RETURN FUNC_CALL VAR BIN_OP VAR VAR FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF NONE RETURN VAR NONE FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL VAR VAR FUNC_DEF EXPR FUNC_CALL VAR STRING FUNC_DEF EXPR FUNC_CALL VAR STRING FUNC_DEF EXPR FUNC_CALL VAR STRING FUNC_DEF EXPR FUNC_CALL VAR STRING EXPR FUNC_CALL VAR BIN_OP NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR STRING ASSIGN VAR BIN_OP BIN_OP NUMBER NUMBER NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR BIN_OP LIST NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) for z in range(t): delta = [int(x) for x in input().split()] nlevels = delta[0] nplatforms = delta[1] platforms = [int(x) for x in input().split()] ans = 0 cache = [0] * nplatforms for i in range(nplatforms - 1): if platforms[i + 1] == platforms[i] - 1: cache[i] = 1 ans = 0 i = 0 FLAG = 0 while i < nplatforms - 2: if platforms[i] <= 2: FLAG = 1 break if platforms[i + 1] != platforms[i] - 1: if cache[i + 1] == 1: i += 2 else: ans += 1 platforms[i + 1] -= 1 i += 1 elif platforms[i + 2] != platforms[i + 1] - 1: ans += 1 platforms[i + 1] -= 1 i += 1 else: i += 2 if FLAG == 1 or i == nplatforms - 1 or platforms[i] <= 2: print(ans) continue if platforms[i + 1] == 1: print(ans) continue print(ans + 1)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER IF VAR NUMBER VAR BIN_OP VAR NUMBER VAR VAR NUMBER EXPR FUNC_CALL VAR VAR IF VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR BIN_OP VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	a = int(input()) l3 = [] for i in range(a): c = 0 h, n = map(int, input().split()) l1 = [int(a) for a in input().split()] r = l1[0] j = 1 while r >= 1: if j < n: if r == l1[j] + 1: if j + 1 == n: if l1[j] >= 2: c += 1 break else: break if r != l1[j + 1] + 2: c += 1 r = r - 2 j = j + 1 continue else: r = r - 2 j = j + 2 else: r = l1[j] + 1 else: break l3.append(c) for j in range(a): print(l3[j])	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR VAR IF VAR BIN_OP VAR VAR NUMBER IF BIN_OP VAR NUMBER VAR IF VAR VAR NUMBER VAR NUMBER IF VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	from sys import stdin a = lambda: stdin.readline().split() for _ in range(int(stdin.readline())): h, n = map(int, a()) lst = [*map(int, a())] if n == 1: print(0) continue cout, item, res = 1, 1, 0 for i, x in enumerate(lst[1:]): if x + 1 == lst[i]: cout += 1 else: if item == 1: if cout % 2 == 0: res += 1 item = 2 elif cout % 2 == 1: res += 1 cout = 1 if lst[-1] != 1: if item == 1: if cout % 2 == 0: res += 1 elif cout % 2 == 1: res += 1 print(res)	ASSIGN VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL VAR ASSIGN VAR LIST FUNC_CALL VAR VAR FUNC_CALL VAR IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR VAR NUMBER NUMBER NUMBER FOR VAR VAR FUNC_CALL VAR VAR NUMBER IF BIN_OP VAR NUMBER VAR VAR VAR NUMBER IF VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER IF VAR NUMBER NUMBER IF VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input("")) for _ in range(q): a = input("").split(" ") h = int(a[0]) n = int(a[1]) p = list(map(int, input("").split(" "))) p.append(-2) d = {(0): True} ans = 0 for a in p: d[a] = True cur = h i = 1 while i < n: if cur <= 2: break if p[i] != cur - 1: cur = p[i] + 1 elif cur - 2 != p[i + 1]: i = i + 1 ans = ans + 1 cur = cur - 2 else: i = i + 2 cur = cur - 2 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR STRING FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL FUNC_CALL VAR STRING STRING ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR STRING STRING EXPR FUNC_CALL VAR NUMBER ASSIGN VAR DICT NUMBER NUMBER ASSIGN VAR NUMBER FOR VAR VAR ASSIGN VAR VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER WHILE VAR VAR IF VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER IF BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys tmp = sys.stdin.readline() noq = int(tmp) while noq: noq -= 1 tmp = sys.stdin.readline().split() H = int(tmp[0]) n = int(tmp[1]) tmp = sys.stdin.readline().split() state = 0 last = 0 ans = 0 for i in range(1, n): cur = int(tmp[i]) if not state: state = 1 elif last - cur > 1: ans += 1 state = 1 else: state = 0 last = cur if state and last > 1: ans += 1 print(ans)	IMPORT ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR WHILE VAR VAR NUMBER ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER ASSIGN VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR FUNC_CALL VAR VAR VAR IF VAR ASSIGN VAR NUMBER IF BIN_OP VAR VAR NUMBER VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR IF VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for i in range(1): for _ in range(int(input())): h, n = map(int, input().split()) a = list(map(int, input().split())) a.append(0) an = 0 i = 1 while i < n: if a[i] + 1 - a[i + 1] == 2: i += 2 elif a[i] + 1 - a[i + 1] > 2: i += 1 an += 1 else: i += 1 print(an)	FOR VAR FUNC_CALL VAR NUMBER FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF BIN_OP BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) while q: q -= 1 h, n = [int(x) for x in input().split()] p = list(map(int, input().split())) for i in range(10): p.append(-10) cur = h ans = 0 i = 1 while cur > 2: if p[i] == cur - 1: if p[i + 1] != cur - 2: ans += 1 cur -= 2 i += 1 else: cur -= 2 i += 2 else: cur = p[i] + 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	from sys import stdin, stdout tests = int(stdin.readline().strip()) for t in range(tests): n, m = map(int, stdin.readline().strip().split()) s = list(map(int, stdin.readline().strip().split())) s = s[::-1] cur = n ans = 0 while cur > 0 and len(s) != 0: if cur <= 2: break while len(s) > 0 and s[-1] >= cur: s.pop() if len(s) == 0: break if cur - s[-1] > 1: cur = s[-1] + 1 continue if len(s) == 1: ans += 1 break if s[-2] + 1 == s[-1]: cur = s[-2] continue ans += 1 cur = s[-2] + 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER WHILE VAR NUMBER FUNC_CALL VAR VAR NUMBER IF VAR NUMBER WHILE FUNC_CALL VAR VAR NUMBER VAR NUMBER VAR EXPR FUNC_CALL VAR IF FUNC_CALL VAR VAR NUMBER IF BIN_OP VAR VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER IF FUNC_CALL VAR VAR NUMBER VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for k in range(q): h, n = map(int, input().split()) plat = list(map(int, input().split())) crystals = 0 i = 0 while i < n - 1: if plat[i] - plat[i + 1] > 1: plat[i] = plat[i + 1] + 1 if plat[i + 1] + 1 == plat[i]: if i + 2 >= n: if plat[i] >= 3: crystals += 1 elif plat[i + 2] + 1 != plat[i + 1]: crystals += 1 plat[i + 1] -= 1 i -= 1 i += 1 i += 1 print(crystals)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR VAR IF BIN_OP VAR NUMBER VAR IF VAR VAR NUMBER VAR NUMBER IF BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for _ in range(q): h, n = map(int, input().split()) arr = list(map(int, input().split())) arr.pop(0) arr.append(0) curr = h ans = 0 index = 0 while index < n - 1: if arr[index] - arr[index + 1] > 1: ans += 1 else: index += 1 index += 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for q in range(int(input())): h, n = [int(i) for i in input().split()] d = [int(i) for i in input().split()] if n == 1: print(0) continue ans = 0 blocks = [] ind = 0 while ind < n: cnt = 1 while ind < n - 1 and d[ind + 1] == d[ind] - 1: cnt += 1 ind += 1 blocks.append(cnt) ind += 1 ans = 0 blocks[0] += 1 for b in blocks: ans += b & 1 if blocks[-1] & 1 == 1 and d[n - 1] == 1: ans -= 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR NUMBER WHILE VAR VAR ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR VAR NUMBER ASSIGN VAR NUMBER VAR NUMBER NUMBER FOR VAR VAR VAR BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER NUMBER NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) a = [int(x) for x in input().split()] gg = a[0] flag = 0 ans = 0 for i in range(1, n): if gg - 1 == a[i] and flag == 0: flag = 1 elif gg - 1 == a[i] and flag == 1: flag = 0 elif flag == 0: flag = 1 else: ans += 1 gg = a[i] if a[n - 1] >= 2: if flag == 1: ans += 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF BIN_OP VAR NUMBER VAR VAR VAR NUMBER ASSIGN VAR NUMBER IF BIN_OP VAR NUMBER VAR VAR VAR NUMBER ASSIGN VAR NUMBER IF VAR NUMBER ASSIGN VAR NUMBER VAR NUMBER ASSIGN VAR VAR VAR IF VAR BIN_OP VAR NUMBER NUMBER IF VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) p = [int(i) for i in input().split()] + [0] only_ones = [] local_ones = [1] for ind, p_i in enumerate(p[1:]): if p[ind] - p_i == 1: local_ones.append(1) else: only_ones.append(local_ones.copy()) local_ones = [1] else: only_ones.append(local_ones) if len(only_ones) == 1: print(0) else: number_of_magic_crystals = 1 if len(only_ones[0]) % 2 == 0 else 0 for ones in only_ones[1 : len(only_ones) - 1]: if len(ones) % 2 == 1: number_of_magic_crystals += 1 print(number_of_magic_crystals)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR LIST ASSIGN VAR LIST NUMBER FOR VAR VAR FUNC_CALL VAR VAR NUMBER IF BIN_OP VAR VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST NUMBER EXPR FUNC_CALL VAR VAR IF FUNC_CALL VAR VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER NUMBER NUMBER NUMBER NUMBER FOR VAR VAR NUMBER BIN_OP FUNC_CALL VAR VAR NUMBER IF BIN_OP FUNC_CALL VAR VAR NUMBER NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) def fun(n): if n == 1: return 1 if n == 2: return 2 if n == 3: return 3 if n == 4: return 4 return n % 2 + 2 for rwre in range(q): h, n = map(int, input().split()) l = list(map(int, input().split())) tab = [] count = 1 for i in range(1, n): if l[i - 1] == l[i] + 1: count += 1 else: tab.append(count) tab.append(l[i - 1] - l[i] - 1) count = 1 if count > 0: tab.append(count) tab.append(l[-1]) p = [] for i in range(len(tab)): if i % 2 == 0: p += [1] * fun(tab[i]) else: p += [0] * fun(tab[i]) h = len(p) p.reverse() i = h - 1 wyn = 0 while i > 2: if p[i - 1] == 0: p[i - 1] = 1 i -= 1 elif p[i - 2] == 1: i -= 2 else: wyn += 1 i -= 2 p[i] = 1 print(wyn)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF IF VAR NUMBER RETURN NUMBER IF VAR NUMBER RETURN NUMBER IF VAR NUMBER RETURN NUMBER IF VAR NUMBER RETURN NUMBER RETURN BIN_OP BIN_OP VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR LIST ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR BIN_OP VAR NUMBER BIN_OP VAR VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR VAR NUMBER ASSIGN VAR NUMBER IF VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR VAR NUMBER ASSIGN VAR LIST FOR VAR FUNC_CALL VAR FUNC_CALL VAR VAR IF BIN_OP VAR NUMBER NUMBER VAR BIN_OP LIST NUMBER FUNC_CALL VAR VAR VAR VAR BIN_OP LIST NUMBER FUNC_CALL VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) for nt in range(t): h, n = map(int, input().split()) string = "" l = list(map(int, input().split())) ans = 0 curr = h i = 1 while curr != 0: if i >= n: break if l[i] == 1: break if l[i] == curr - 1 and l[(i + 1) % n] == curr - 2: curr = curr - 2 i += 2 elif l[i] == curr - 1 and l[(i + 1) % n] != curr - 2: if i + 1 < n: ans += 1 curr = l[i + 1] + 1 i += 1 else: ans += 1 i += 1 curr = curr - 2 else: curr = l[i] + 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR STRING ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR VAR IF VAR VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR BIN_OP BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR BIN_OP BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER VAR VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	q = int(input()) for i in range(q): h, n = input().split() h = int(h) n = int(n) p = [int(j) for j in input().split()] + [0] s = 1 a = 0 for i in range(len(p) - 1): if p[i] - p[i + 1] >= 2 and s % 2 == 0: a += 1 s = 2 elif p[i] - p[i + 1] >= 2 and s % 2 == 1: s = 2 else: s += 1 print(a)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR LIST NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR NUMBER IF BIN_OP VAR VAR VAR BIN_OP VAR NUMBER NUMBER BIN_OP VAR NUMBER NUMBER ASSIGN VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys def rint(): return map(int, sys.stdin.readline().split()) def input(): return sys.stdin.readline().rstrip("\n") def oint(): return int(input()) q = oint() for _ in range(q): h, n = rint() p = list(rint()) cur = h cnt = 0 for i in range(1, n): if cur <= p[i]: continue cur = p[i] + 1 if p[i] == cur - 1: if i + 1 > n - 1: if cur > 2: cnt += 1 cur -= 2 break elif p[i + 1] == cur - 2: cur -= 2 continue else: cnt += 1 cur -= 2 continue print(cnt)	IMPORT FUNC_DEF RETURN FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR FUNC_DEF RETURN FUNC_CALL FUNC_CALL VAR STRING FUNC_DEF RETURN FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR VAR ASSIGN VAR BIN_OP VAR VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER BIN_OP VAR NUMBER IF VAR NUMBER VAR NUMBER VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = map(int, input().split()) arr = list(map(int, input().split())) dp = [0] * (n + 1) dp[0] = 0 for i in range(1, n): if arr[i - 1] - arr[i] > 0: dp[i] = 1 + dp[i - 1] if i - 2 >= 0 and arr[i - 2] - arr[i] >= 2 and arr[i - 1] - arr[i] == 1: dp[i] = min(dp[i], dp[i - 2]) if arr[n - 1]: res = dp[n - 1] if n - 2 >= 0 and arr[n - 2] >= 2 and arr[n - 1] == 1: res = min(res, dp[n - 2]) print(res)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER ASSIGN VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF BIN_OP VAR BIN_OP VAR NUMBER VAR VAR NUMBER ASSIGN VAR VAR BIN_OP NUMBER VAR BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER NUMBER BIN_OP VAR BIN_OP VAR NUMBER VAR VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER IF BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER NUMBER VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	from sys import stdin t = int(input()) while t > 0: count = 0 n, m = [int(i) for i in stdin.readline().split()] a = [int(i) for i in stdin.readline().split()] d = {i: (1) for i in a} curr = a[0] i = 0 while curr > 0 and i < m: if curr <= 2: break elif d.get(curr - 1, -1) != -1 and d.get(curr - 2, -1) != -1: curr -= 2 i += 2 elif d.get(curr - 1, -1) != -1: count += 1 i += 1 curr -= 1 elif i + 1 < m: curr = a[i + 1] + 1 else: curr = 0 print(count) t -= 1	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR WHILE VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR VAR NUMBER VAR VAR ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER VAR VAR IF VAR NUMBER IF FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER VAR NUMBER VAR NUMBER IF FUNC_CALL VAR BIN_OP VAR NUMBER NUMBER NUMBER VAR NUMBER VAR NUMBER VAR NUMBER IF BIN_OP VAR NUMBER VAR ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR NUMBER EXPR FUNC_CALL VAR VAR VAR NUMBER
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) for _ in range(t): n, p = list(map(lambda x: int(x), input().split())) platforms = list(map(lambda x: int(x), input().split())) platforms.append(0) crystals = 0 i = 1 current = platforms[0] while i < p: if platforms[i] == current - 1: if platforms[i + 1] == current - 2: current = platforms[i + 1] i = i + 2 continue else: crystals += 1 current = platforms[i + 1] + 1 i += 1 continue else: current = platforms[i] + 1 print(crystals)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR NUMBER WHILE VAR VAR IF VAR VAR BIN_OP VAR NUMBER IF VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	for _ in range(int(input())): h, n = [int(a) for a in input().split()] p = list(map(int, input().split())) ans = 0 p = [0] + p v = [0] * (n + 2) for i in range(1, n + 1): v[i] = p[i] v.append(0) i = 2 while i <= n: if v[i] - 1 == v[i + 1]: i += 1 else: ans += 1 i += 1 print(ans)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER VAR ASSIGN VAR BIN_OP LIST NUMBER BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER ASSIGN VAR VAR VAR VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR NUMBER WHILE VAR VAR IF BIN_OP VAR VAR NUMBER VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	Q = int(input()) for q in range(Q): H, N = map(int, input().split()) A = list(map(int, input().split())) i = 0 ans = 0 while i < N - 1: if A[i] == A[i + 1] + 1: if i >= N - 2: if A[i] > 2: ans += 1 break elif A[i] != A[i + 2] + 2: ans += 1 A[i + 1] = A[i + 2] + 1 i += 1 else: i += 2 else: A[i] = A[i + 1] + 1 print(ans)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP VAR NUMBER IF VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR BIN_OP VAR NUMBER IF VAR VAR NUMBER VAR NUMBER IF VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER BIN_OP VAR BIN_OP VAR NUMBER NUMBER VAR NUMBER VAR NUMBER ASSIGN VAR VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	t = int(input()) for _ in range(t): h, n = map(int, input().split()) p = list(map(int, input().split())) p.reverse() s = n - 1 c = 0 l = h while 1: if l < 3: break if s < 1: break if l - p[s - 1] > 1: l = p[s - 1] + 1 elif s < 2: if p[s] - 2 > 0: c += 1 break elif l - p[s - 2] == 2: l = p[s - 2] s -= 2 else: c += 1 l -= 2 s -= 1 print(c)	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR WHILE NUMBER IF VAR NUMBER IF VAR NUMBER IF BIN_OP VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR BIN_OP VAR BIN_OP VAR NUMBER NUMBER IF VAR NUMBER IF BIN_OP VAR VAR NUMBER NUMBER VAR NUMBER IF BIN_OP VAR VAR BIN_OP VAR NUMBER NUMBER ASSIGN VAR VAR BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
You are playing a game where your character should overcome different obstacles. The current problem is to come down from a cliff. The cliff has height $h$, and there is a moving platform on each height $x$ from $1$ to $h$. Each platform is either hidden inside the cliff or moved out. At first, there are $n$ moved out platforms on heights $p_1, p_2, \dots, p_n$. The platform on height $h$ is moved out (and the character is initially standing there). If you character is standing on some moved out platform on height $x$, then he can pull a special lever, which switches the state of two platforms: on height $x$ and $x - 1$. In other words, the platform you are currently standing on will hide in the cliff and the platform one unit below will change it state: it will hide if it was moved out or move out if it was hidden. In the second case, you will safely land on it. Note that this is the only way to move from one platform to another. Your character is quite fragile, so it can safely fall from the height no more than $2$. In other words falling from the platform $x$ to platform $x - 2$ is okay, but falling from $x$ to $x - 3$ (or lower) is certain death. Sometimes it's not possible to come down from the cliff, but you can always buy (for donate currency) several magic crystals. Each magic crystal can be used to change the state of any single platform (except platform on height $h$, which is unaffected by the crystals). After being used, the crystal disappears. What is the minimum number of magic crystal you need to buy to safely land on the $0$ ground level? -----Input----- The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query contains two lines and is independent of all other queries. The first line of each query contains two integers $h$ and $n$ ($1 \le h \le 10^9$, $1 \le n \le \min(h, 2 \cdot 10^5)$) — the height of the cliff and the number of moved out platforms. The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($h = p_1 > p_2 > \dots > p_n \ge 1$) — the corresponding moved out platforms in the descending order of their heights. The sum of $n$ over all queries does not exceed $2 \cdot 10^5$. -----Output----- For each query print one integer — the minimum number of magic crystals you have to spend to safely come down on the ground level (with height $0$). -----Example----- Input 4 3 2 3 1 8 6 8 7 6 5 3 2 9 6 9 8 5 4 3 1 1 1 1 Output 0 1 2 0	import sys input = sys.stdin.readline q = int(input()) for testcases in range(q): h, n = map(int, input().split()) P = list(map(int, input().split())) P.append(-10) NOW = h ANS = 0 ind = 1 while NOW >= 3: if P[ind] < NOW - 1: NOW = P[ind] + 1 continue if P[ind] == NOW - 1 and P[ind + 1] == NOW - 2: NOW -= 2 ind += 2 continue if P[ind] == NOW - 1 and P[ind + 1] != NOW - 2: NOW -= 2 ind += 1 ANS += 1 print(ANS)	IMPORT ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR VAR FUNC_CALL FUNC_CALL VAR EXPR FUNC_CALL VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER WHILE VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER IF VAR VAR BIN_OP VAR NUMBER VAR BIN_OP VAR NUMBER BIN_OP VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR
Roman and Denis are on the trip to the programming competition. Since the trip was long, they soon got bored, and hence decided to came up with something. Roman invented a pizza's recipe, while Denis invented a string multiplication. According to Denis, the result of multiplication (product) of strings $s$ of length $m$ and $t$ is a string $t + s_1 + t + s_2 + \ldots + t + s_m + t$, where $s_i$ denotes the $i$-th symbol of the string $s$, and "+" denotes string concatenation. For example, the product of strings "abc" and "de" is a string "deadebdecde", while the product of the strings "ab" and "z" is a string "zazbz". Note, that unlike the numbers multiplication, the product of strings $s$ and $t$ is not necessarily equal to product of $t$ and $s$. Roman was jealous of Denis, since he invented such a cool operation, and hence decided to invent something string-related too. Since Roman is beauty-lover, he decided to define the beauty of the string as the length of the longest substring, consisting of only one letter. For example, the beauty of the string "xayyaaabca" is equal to $3$, since there is a substring "aaa", while the beauty of the string "qwerqwer" is equal to $1$, since all neighboring symbols in it are different. In order to entertain Roman, Denis wrote down $n$ strings $p_1, p_2, p_3, \ldots, p_n$ on the paper and asked him to calculate the beauty of the string $( \ldots (((p_1 \cdot p_2) \cdot p_3) \cdot \ldots ) \cdot p_n$, where $s \cdot t$ denotes a multiplication of strings $s$ and $t$. Roman hasn't fully realized how Denis's multiplication works, so he asked you for a help. Denis knows, that Roman is very impressionable, he guarantees, that the beauty of the resulting string is at most $10^9$. -----Input----- The first line contains a single integer $n$ ($2 \leq n \leq 100\,000$) — the number of strings, wroted by Denis. Next $n$ lines contain non-empty strings $p_1, p_2, \ldots, p_n$, consisting of lowercase english letters. It's guaranteed, that the total length of the strings $p_i$ is at most $100\,000$, and that's the beauty of the resulting product is at most $10^9$. -----Output----- Print exactly one integer — the beauty of the product of the strings. -----Examples----- Input 3 a b a Output 3 Input 2 bnn a Output 1 -----Note----- In the first example, the product of strings is equal to "abaaaba". In the second example, the product of strings is equal to "abanana".	n = int(input()) def get_longest(s): prev_c = -1 curr_len = 0 longest = [0] * 26 for c in s: if c != prev_c: curr_len = 1 prev_c = c else: curr_len += 1 longest[c] = max(longest[c], curr_len) return longest def get_prefix(s): prev_c = s[0] curr_len = 0 for c in s: if c == prev_c: curr_len += 1 else: return prev_c, curr_len return prev_c, curr_len def get_suffix(s): prev_c = s[len(s) - 1] curr_len = 0 for i in range(len(s) - 1, -1, -1): c = s[i] if c == prev_c: curr_len += 1 else: return prev_c, curr_len return prev_c, curr_len s = [(ord(x) - 97) for x in input()] longest_s = get_longest(s) for i in range(1, n): t = [(ord(x) - 97) for x in input()] longest_t = get_longest(t) prefix = get_prefix(t) suffix = get_suffix(t) if prefix[1] == len(t): for i in range(0, 26): if i == t[0]: longest_s[i] = (len(t) + 1) * (longest_s[i] + 1) - 1 else: longest_s[i] = int(bool(longest_s[i])) else: for i in range(0, 26): longest_s[i] = int(bool(longest_s[i])) if i == prefix[0]: longest_s[i] += prefix[1] if i == suffix[0]: longest_s[i] += suffix[1] longest_s[i] = max(longest_s[i], longest_t[i]) print(max(longest_s))	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_DEF ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER NUMBER FOR VAR VAR IF VAR VAR ASSIGN VAR NUMBER ASSIGN VAR VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR RETURN VAR FUNC_DEF ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR IF VAR VAR VAR NUMBER RETURN VAR VAR RETURN VAR VAR FUNC_DEF ASSIGN VAR VAR BIN_OP FUNC_CALL VAR VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP FUNC_CALL VAR VAR NUMBER NUMBER NUMBER ASSIGN VAR VAR VAR IF VAR VAR VAR NUMBER RETURN VAR VAR RETURN VAR VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER VAR ASSIGN VAR BIN_OP FUNC_CALL VAR VAR NUMBER VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR IF VAR NUMBER FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER NUMBER IF VAR VAR NUMBER ASSIGN VAR VAR BIN_OP BIN_OP BIN_OP FUNC_CALL VAR VAR NUMBER BIN_OP VAR VAR NUMBER NUMBER ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR FOR VAR FUNC_CALL VAR NUMBER NUMBER ASSIGN VAR VAR FUNC_CALL VAR FUNC_CALL VAR VAR VAR IF VAR VAR NUMBER VAR VAR VAR NUMBER IF VAR VAR NUMBER VAR VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR
Roman and Denis are on the trip to the programming competition. Since the trip was long, they soon got bored, and hence decided to came up with something. Roman invented a pizza's recipe, while Denis invented a string multiplication. According to Denis, the result of multiplication (product) of strings $s$ of length $m$ and $t$ is a string $t + s_1 + t + s_2 + \ldots + t + s_m + t$, where $s_i$ denotes the $i$-th symbol of the string $s$, and "+" denotes string concatenation. For example, the product of strings "abc" and "de" is a string "deadebdecde", while the product of the strings "ab" and "z" is a string "zazbz". Note, that unlike the numbers multiplication, the product of strings $s$ and $t$ is not necessarily equal to product of $t$ and $s$. Roman was jealous of Denis, since he invented such a cool operation, and hence decided to invent something string-related too. Since Roman is beauty-lover, he decided to define the beauty of the string as the length of the longest substring, consisting of only one letter. For example, the beauty of the string "xayyaaabca" is equal to $3$, since there is a substring "aaa", while the beauty of the string "qwerqwer" is equal to $1$, since all neighboring symbols in it are different. In order to entertain Roman, Denis wrote down $n$ strings $p_1, p_2, p_3, \ldots, p_n$ on the paper and asked him to calculate the beauty of the string $( \ldots (((p_1 \cdot p_2) \cdot p_3) \cdot \ldots ) \cdot p_n$, where $s \cdot t$ denotes a multiplication of strings $s$ and $t$. Roman hasn't fully realized how Denis's multiplication works, so he asked you for a help. Denis knows, that Roman is very impressionable, he guarantees, that the beauty of the resulting string is at most $10^9$. -----Input----- The first line contains a single integer $n$ ($2 \leq n \leq 100\,000$) — the number of strings, wroted by Denis. Next $n$ lines contain non-empty strings $p_1, p_2, \ldots, p_n$, consisting of lowercase english letters. It's guaranteed, that the total length of the strings $p_i$ is at most $100\,000$, and that's the beauty of the resulting product is at most $10^9$. -----Output----- Print exactly one integer — the beauty of the product of the strings. -----Examples----- Input 3 a b a Output 3 Input 2 bnn a Output 1 -----Note----- In the first example, the product of strings is equal to "abaaaba". In the second example, the product of strings is equal to "abanana".	def prog(mass, st): nonlocal alf if st == st[0] * len(st): for i in range(26): if alf[i] == st[0]: mass[i] = (mass[i] + 1) * len(st) + mass[i] else: mass[i] = min(1, mass[i]) else: mmm = razlog(st) r = 1 while st[r] == st[r - 1]: r += 1 k = 1 while st[len(st) - k] == st[len(st) - k - 1]: k += 1 for i in range(26): if alf[i] == st[0] and alf[i] == st[-1]: if mass[i] == 0: mass[i] = max(mmm[i], k, r) else: mass[i] = max(mmm[i], k + r + 1) elif alf[i] == st[0]: if mass[i] == 0: mass[i] = max(mmm[i], r) else: mass[i] = max(mmm[i], r + 1) elif alf[i] == st[-1]: if mass[i] == 0: mass[i] = max(mmm[i], k) else: mass[i] = max(mmm[i], k + 1) elif mass[i] == 0: mass[i] = mmm[i] else: mass[i] = max(1, mmm[i]) return mass def razlog(st): nonlocal alf mass = [(0) for i in range(26)] mass[alf.index(st[0])] = 1 now = 1 for i in range(1, len(st)): if st[i] == st[i - 1]: now += 1 else: now = 1 mass[alf.index(st[i])] = max(now, mass[alf.index(st[i])]) return mass n = int(input()) st = input() alf = [ "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", ] mass = razlog(st) for i in range(n - 1): sti = input() mass = prog(mass, sti) print(max(mass))	FUNC_DEF IF VAR BIN_OP VAR NUMBER FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR NUMBER IF VAR VAR VAR NUMBER ASSIGN VAR VAR BIN_OP BIN_OP BIN_OP VAR VAR NUMBER FUNC_CALL VAR VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR NUMBER VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER WHILE VAR VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR NUMBER WHILE VAR BIN_OP FUNC_CALL VAR VAR VAR VAR BIN_OP BIN_OP FUNC_CALL VAR VAR VAR NUMBER VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER IF VAR VAR VAR NUMBER VAR VAR VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR BIN_OP BIN_OP VAR VAR NUMBER IF VAR VAR VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR BIN_OP VAR NUMBER IF VAR VAR VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR BIN_OP VAR NUMBER IF VAR VAR NUMBER ASSIGN VAR VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR NUMBER VAR VAR RETURN VAR FUNC_DEF ASSIGN VAR NUMBER VAR FUNC_CALL VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR NUMBER NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR IF VAR VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR VAR FUNC_CALL VAR VAR VAR RETURN VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR ASSIGN VAR LIST STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING STRING ASSIGN VAR FUNC_CALL VAR VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR
Roman and Denis are on the trip to the programming competition. Since the trip was long, they soon got bored, and hence decided to came up with something. Roman invented a pizza's recipe, while Denis invented a string multiplication. According to Denis, the result of multiplication (product) of strings $s$ of length $m$ and $t$ is a string $t + s_1 + t + s_2 + \ldots + t + s_m + t$, where $s_i$ denotes the $i$-th symbol of the string $s$, and "+" denotes string concatenation. For example, the product of strings "abc" and "de" is a string "deadebdecde", while the product of the strings "ab" and "z" is a string "zazbz". Note, that unlike the numbers multiplication, the product of strings $s$ and $t$ is not necessarily equal to product of $t$ and $s$. Roman was jealous of Denis, since he invented such a cool operation, and hence decided to invent something string-related too. Since Roman is beauty-lover, he decided to define the beauty of the string as the length of the longest substring, consisting of only one letter. For example, the beauty of the string "xayyaaabca" is equal to $3$, since there is a substring "aaa", while the beauty of the string "qwerqwer" is equal to $1$, since all neighboring symbols in it are different. In order to entertain Roman, Denis wrote down $n$ strings $p_1, p_2, p_3, \ldots, p_n$ on the paper and asked him to calculate the beauty of the string $( \ldots (((p_1 \cdot p_2) \cdot p_3) \cdot \ldots ) \cdot p_n$, where $s \cdot t$ denotes a multiplication of strings $s$ and $t$. Roman hasn't fully realized how Denis's multiplication works, so he asked you for a help. Denis knows, that Roman is very impressionable, he guarantees, that the beauty of the resulting string is at most $10^9$. -----Input----- The first line contains a single integer $n$ ($2 \leq n \leq 100\,000$) — the number of strings, wroted by Denis. Next $n$ lines contain non-empty strings $p_1, p_2, \ldots, p_n$, consisting of lowercase english letters. It's guaranteed, that the total length of the strings $p_i$ is at most $100\,000$, and that's the beauty of the resulting product is at most $10^9$. -----Output----- Print exactly one integer — the beauty of the product of the strings. -----Examples----- Input 3 a b a Output 3 Input 2 bnn a Output 1 -----Note----- In the first example, the product of strings is equal to "abaaaba". In the second example, the product of strings is equal to "abanana".	def mult(s, t): f1, l1, cntf1, cntl1, beaut1, n1 = s f2, l2, cntf2, cntl2, beaut2, n2, p = t f3, l3, cntf3, cntl3, beaut3, n3 = 0, 0, 0, 0, beaut1, 0 f3 = f1 l3 = l1 n3 = n1 * (n2 + 1) + n2 if cntf1 >= n1 and f1 == f2: cntf3 = n1 * (cntf2 + 1) + cntf2 else: cntf3 = cntf1 if cntl1 == n1 and l1 == l2: cntl3 = n1 * (cntl2 + 1) + cntl2 else: cntl3 = cntl1 if f1 != l1: if f1 in p: beaut3 = max(beaut3, cntf1 + 1) if l1 in p: beaut3 = max(beaut3, cntl1 + 1) elif cntf1 >= n1: beaut3 = max(n1, beaut3) ans = 0 h = 0 for d in p: if d == f1: h += 1 ans = max(ans, h) else: h = 0 ans = max(ans, h) beaut3 = max(beaut3, n1 * (ans + 1) + ans) elif f1 in p: beaut3 = max(beaut3, 1 + cntf1 + cntl1) else: beaut3 = max(beaut3, cntf1, cntl1) return [f3, l3, cntf3, cntl3, beaut3, n3] n = int(input()) p = [] for i in range(n): p.append(input()) pp = [] for s in p: f = s[0] l = s[-1] cntf = 0 cntl = 0 beaut = 1 hep = 1 for i in s: if i == f: cntf += 1 else: break for i in s[::-1]: if i == l: cntl += 1 else: break for i in range(1, len(s)): if s[i] == s[i - 1]: hep += 1 else: beaut = max(beaut, hep) hep = 1 beaut = max(beaut, hep) pp.append([f, l, cntf, cntl, beaut, len(s), s]) p = pp[::-1] lasts = p[0][:-1] for i in range(1, len(p)): lasts = mult(lasts, p[i]) print(lasts[-2])	FUNC_DEF ASSIGN VAR VAR VAR VAR VAR VAR VAR ASSIGN VAR VAR VAR VAR VAR VAR VAR VAR ASSIGN VAR VAR VAR VAR VAR VAR NUMBER NUMBER NUMBER NUMBER VAR NUMBER ASSIGN VAR VAR ASSIGN VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR IF VAR VAR VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR ASSIGN VAR VAR IF VAR VAR VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR ASSIGN VAR VAR IF VAR VAR IF VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER IF VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER IF VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR IF VAR VAR VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR IF VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP NUMBER VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR RETURN LIST VAR VAR VAR VAR VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR LIST FOR VAR VAR ASSIGN VAR VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR VAR IF VAR VAR VAR NUMBER FOR VAR VAR NUMBER IF VAR VAR VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR IF VAR VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR VAR EXPR FUNC_CALL VAR LIST VAR VAR VAR VAR VAR FUNC_CALL VAR VAR VAR ASSIGN VAR VAR NUMBER ASSIGN VAR VAR NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR VAR EXPR FUNC_CALL VAR VAR NUMBER
Roman and Denis are on the trip to the programming competition. Since the trip was long, they soon got bored, and hence decided to came up with something. Roman invented a pizza's recipe, while Denis invented a string multiplication. According to Denis, the result of multiplication (product) of strings $s$ of length $m$ and $t$ is a string $t + s_1 + t + s_2 + \ldots + t + s_m + t$, where $s_i$ denotes the $i$-th symbol of the string $s$, and "+" denotes string concatenation. For example, the product of strings "abc" and "de" is a string "deadebdecde", while the product of the strings "ab" and "z" is a string "zazbz". Note, that unlike the numbers multiplication, the product of strings $s$ and $t$ is not necessarily equal to product of $t$ and $s$. Roman was jealous of Denis, since he invented such a cool operation, and hence decided to invent something string-related too. Since Roman is beauty-lover, he decided to define the beauty of the string as the length of the longest substring, consisting of only one letter. For example, the beauty of the string "xayyaaabca" is equal to $3$, since there is a substring "aaa", while the beauty of the string "qwerqwer" is equal to $1$, since all neighboring symbols in it are different. In order to entertain Roman, Denis wrote down $n$ strings $p_1, p_2, p_3, \ldots, p_n$ on the paper and asked him to calculate the beauty of the string $( \ldots (((p_1 \cdot p_2) \cdot p_3) \cdot \ldots ) \cdot p_n$, where $s \cdot t$ denotes a multiplication of strings $s$ and $t$. Roman hasn't fully realized how Denis's multiplication works, so he asked you for a help. Denis knows, that Roman is very impressionable, he guarantees, that the beauty of the resulting string is at most $10^9$. -----Input----- The first line contains a single integer $n$ ($2 \leq n \leq 100\,000$) — the number of strings, wroted by Denis. Next $n$ lines contain non-empty strings $p_1, p_2, \ldots, p_n$, consisting of lowercase english letters. It's guaranteed, that the total length of the strings $p_i$ is at most $100\,000$, and that's the beauty of the resulting product is at most $10^9$. -----Output----- Print exactly one integer — the beauty of the product of the strings. -----Examples----- Input 3 a b a Output 3 Input 2 bnn a Output 1 -----Note----- In the first example, the product of strings is equal to "abaaaba". In the second example, the product of strings is equal to "abanana".	n = input() n = int(n) p = [] substring_maxlen = 0 str_info = [] _temper = ["abba", "a"] for i in range(n): string = input() str_info.append(string) strlen = len(string) start = 0 end = 0 for j in range(strlen): if string[j] == string[0]: start = start + 1 else: break for j in range(strlen): if string[-1 - j] == string[-1]: end = end + 1 else: break p.append((string[0], start, string[-1], end, True if strlen == start else False)) _max_len = 0 parse = 0 _temp_max = 0 string = str_info[-1] token = string[0] while parse < len(string): token = string[parse] _temp_max = 0 for k in range(parse, len(string)): if string[k] == token: parse = parse + 1 _temp_max = _temp_max + 1 else: break if substring_maxlen < _temp_max: substring_maxlen = _temp_max start_token = [] end_token = [] start_token, start_num, end_token, end_num, connected = p[-1] level = 0 for i in range(1, len(p)): if not connected: break else: _string = str_info[-i - 1] _max_len = 0 parse = 0 _temp_max = 0 token = _string[0] _substring_maxlen = 0 while parse < len(_string): token = _string[parse] if token != start_token: parse = parse + 1 continue _temp_max = 0 for k in range(parse, len(_string)): if _string[k] == token: parse = parse + 1 _temp_max = _temp_max + 1 else: break if _substring_maxlen < _temp_max: _substring_maxlen = _temp_max substring_maxlen = max( substring_maxlen, start_num * (_substring_maxlen + 1) + _substring_maxlen ) _start_token, _start_num, _end_token, _end_num, _connected = p[-1 - i] if _start_token == start_token: start_num = start_num * (_start_num + 1) + _start_num if _end_token == end_token: end_num = end_num * (_end_num + 1) + _end_num if not _connected or _start_token != start_token: connected = False level = i end_cond = 0 if start_num > end_num: end_cond = 1 elif start_num < end_num: end_cond = 2 the_End = False answer = max(start_num, end_num) + 1 for i in range(len(p) - level - 1): for s in str_info[i]: if start_token == s: if end_cond < 2: the_End = True if start_token == end_token: answer = answer + min(start_num, end_num) break if end_token == s: if end_cond % 2 == 0: the_End = True if start_token == end_token: answer = answer + min(start_num, end_num) break if the_End: break else: answer = answer - 1 if len(p) == 1: answer = answer - 1 print(max(answer, substring_maxlen))	ASSIGN VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR LIST ASSIGN VAR NUMBER ASSIGN VAR LIST ASSIGN VAR LIST STRING STRING FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR EXPR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR IF VAR VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR VAR IF VAR BIN_OP NUMBER VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR VAR NUMBER VAR VAR NUMBER VAR VAR VAR NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR VAR NUMBER WHILE VAR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR FUNC_CALL VAR VAR IF VAR VAR VAR ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER IF VAR VAR ASSIGN VAR VAR ASSIGN VAR LIST ASSIGN VAR LIST ASSIGN VAR VAR VAR VAR VAR VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER FUNC_CALL VAR VAR IF VAR ASSIGN VAR VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR ASSIGN VAR VAR VAR IF VAR VAR ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR NUMBER FOR VAR FUNC_CALL VAR VAR FUNC_CALL VAR VAR IF VAR VAR VAR ASSIGN VAR BIN_OP VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER IF VAR VAR ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR ASSIGN VAR VAR VAR VAR VAR VAR BIN_OP NUMBER VAR IF VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR IF VAR VAR ASSIGN VAR BIN_OP BIN_OP VAR BIN_OP VAR NUMBER VAR IF VAR VAR VAR ASSIGN VAR NUMBER ASSIGN VAR VAR ASSIGN VAR NUMBER IF VAR VAR ASSIGN VAR NUMBER IF VAR VAR ASSIGN VAR NUMBER ASSIGN VAR NUMBER ASSIGN VAR BIN_OP FUNC_CALL VAR VAR VAR NUMBER FOR VAR FUNC_CALL VAR BIN_OP BIN_OP FUNC_CALL VAR VAR VAR NUMBER FOR VAR VAR VAR IF VAR VAR IF VAR NUMBER ASSIGN VAR NUMBER IF VAR VAR ASSIGN VAR BIN_OP VAR FUNC_CALL VAR VAR VAR IF VAR VAR IF BIN_OP VAR NUMBER NUMBER ASSIGN VAR NUMBER IF VAR VAR ASSIGN VAR BIN_OP VAR FUNC_CALL VAR VAR VAR IF VAR ASSIGN VAR BIN_OP VAR NUMBER IF FUNC_CALL VAR VAR NUMBER ASSIGN VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR FUNC_CALL VAR VAR VAR
Roman and Denis are on the trip to the programming competition. Since the trip was long, they soon got bored, and hence decided to came up with something. Roman invented a pizza's recipe, while Denis invented a string multiplication. According to Denis, the result of multiplication (product) of strings $s$ of length $m$ and $t$ is a string $t + s_1 + t + s_2 + \ldots + t + s_m + t$, where $s_i$ denotes the $i$-th symbol of the string $s$, and "+" denotes string concatenation. For example, the product of strings "abc" and "de" is a string "deadebdecde", while the product of the strings "ab" and "z" is a string "zazbz". Note, that unlike the numbers multiplication, the product of strings $s$ and $t$ is not necessarily equal to product of $t$ and $s$. Roman was jealous of Denis, since he invented such a cool operation, and hence decided to invent something string-related too. Since Roman is beauty-lover, he decided to define the beauty of the string as the length of the longest substring, consisting of only one letter. For example, the beauty of the string "xayyaaabca" is equal to $3$, since there is a substring "aaa", while the beauty of the string "qwerqwer" is equal to $1$, since all neighboring symbols in it are different. In order to entertain Roman, Denis wrote down $n$ strings $p_1, p_2, p_3, \ldots, p_n$ on the paper and asked him to calculate the beauty of the string $( \ldots (((p_1 \cdot p_2) \cdot p_3) \cdot \ldots ) \cdot p_n$, where $s \cdot t$ denotes a multiplication of strings $s$ and $t$. Roman hasn't fully realized how Denis's multiplication works, so he asked you for a help. Denis knows, that Roman is very impressionable, he guarantees, that the beauty of the resulting string is at most $10^9$. -----Input----- The first line contains a single integer $n$ ($2 \leq n \leq 100\,000$) — the number of strings, wroted by Denis. Next $n$ lines contain non-empty strings $p_1, p_2, \ldots, p_n$, consisting of lowercase english letters. It's guaranteed, that the total length of the strings $p_i$ is at most $100\,000$, and that's the beauty of the resulting product is at most $10^9$. -----Output----- Print exactly one integer — the beauty of the product of the strings. -----Examples----- Input 3 a b a Output 3 Input 2 bnn a Output 1 -----Note----- In the first example, the product of strings is equal to "abaaaba". In the second example, the product of strings is equal to "abanana".	t = [0] * 26 def get_k(c): return ord(c) - ord("a") def analyze(s): length_of_str = len(s) pos = 0 beauty_table = [0] * 26 for i in range(1, length_of_str): if s[i] != s[pos]: k = get_k(s[pos]) beauty_table[k] = max(beauty_table[k], i - pos) pos = i k = get_k(s[pos]) beauty_table[k] = max(beauty_table[k], length_of_str - pos) pos = 0 while pos < length_of_str and s[pos] == s[0]: pos += 1 left_beauty = pos pos = length_of_str - 1 while pos > 0 and s[pos] == s[length_of_str - 1]: pos -= 1 right_beauty = length_of_str - pos - 1 return beauty_table, left_beauty, right_beauty r = [] for _ in range(int(input())): p = input() if all(x == p[0] for x in p): k = get_k(p[0]) for i in range(26): if i == k: t[i] = len(p) * (t[i] + 1) + t[i] else: t[i] = min(1, t[i]) else: for i in range(26): t[i] = min(1, t[i]) bt, lb, rb = analyze(p) lk, rk = get_k(p[0]), get_k(p[-1]) if lk == rk: t[lk] = lb + rb + t[lk] else: t[lk], t[rk] = t[lk] + lb, t[rk] + rb for i in range(26): t[i] = max(t[i], bt[i]) print(max(t))	ASSIGN VAR BIN_OP LIST NUMBER NUMBER FUNC_DEF RETURN BIN_OP FUNC_CALL VAR VAR FUNC_CALL VAR STRING FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR ASSIGN VAR NUMBER ASSIGN VAR BIN_OP LIST NUMBER NUMBER FOR VAR FUNC_CALL VAR NUMBER VAR IF VAR VAR VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR BIN_OP VAR VAR ASSIGN VAR VAR ASSIGN VAR FUNC_CALL VAR VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR VAR BIN_OP VAR VAR ASSIGN VAR NUMBER WHILE VAR VAR VAR VAR VAR NUMBER VAR NUMBER ASSIGN VAR VAR ASSIGN VAR BIN_OP VAR NUMBER WHILE VAR NUMBER VAR VAR VAR BIN_OP VAR NUMBER VAR NUMBER ASSIGN VAR BIN_OP BIN_OP VAR VAR NUMBER RETURN VAR VAR VAR ASSIGN VAR LIST FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR IF FUNC_CALL VAR VAR VAR NUMBER VAR VAR ASSIGN VAR FUNC_CALL VAR VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER IF VAR VAR ASSIGN VAR VAR BIN_OP BIN_OP FUNC_CALL VAR VAR BIN_OP VAR VAR NUMBER VAR VAR ASSIGN VAR VAR FUNC_CALL VAR NUMBER VAR VAR FOR VAR FUNC_CALL VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR NUMBER VAR VAR ASSIGN VAR VAR VAR FUNC_CALL VAR VAR ASSIGN VAR VAR FUNC_CALL VAR VAR NUMBER FUNC_CALL VAR VAR NUMBER IF VAR VAR ASSIGN VAR VAR BIN_OP BIN_OP VAR VAR VAR VAR ASSIGN VAR VAR VAR VAR BIN_OP VAR VAR VAR BIN_OP VAR VAR VAR FOR VAR FUNC_CALL VAR NUMBER ASSIGN VAR VAR FUNC_CALL VAR VAR VAR VAR VAR EXPR FUNC_CALL VAR FUNC_CALL VAR VAR
Roman and Denis are on the trip to the programming competition. Since the trip was long, they soon got bored, and hence decided to came up with something. Roman invented a pizza's recipe, while Denis invented a string multiplication. According to Denis, the result of multiplication (product) of strings $s$ of length $m$ and $t$ is a string $t + s_1 + t + s_2 + \ldots + t + s_m + t$, where $s_i$ denotes the $i$-th symbol of the string $s$, and "+" denotes string concatenation. For example, the product of strings "abc" and "de" is a string "deadebdecde", while the product of the strings "ab" and "z" is a string "zazbz". Note, that unlike the numbers multiplication, the product of strings $s$ and $t$ is not necessarily equal to product of $t$ and $s$. Roman was jealous of Denis, since he invented such a cool operation, and hence decided to invent something string-related too. Since Roman is beauty-lover, he decided to define the beauty of the string as the length of the longest substring, consisting of only one letter. For example, the beauty of the string "xayyaaabca" is equal to $3$, since there is a substring "aaa", while the beauty of the string "qwerqwer" is equal to $1$, since all neighboring symbols in it are different. In order to entertain Roman, Denis wrote down $n$ strings $p_1, p_2, p_3, \ldots, p_n$ on the paper and asked him to calculate the beauty of the string $( \ldots (((p_1 \cdot p_2) \cdot p_3) \cdot \ldots ) \cdot p_n$, where $s \cdot t$ denotes a multiplication of strings $s$ and $t$. Roman hasn't fully realized how Denis's multiplication works, so he asked you for a help. Denis knows, that Roman is very impressionable, he guarantees, that the beauty of the resulting string is at most $10^9$. -----Input----- The first line contains a single integer $n$ ($2 \leq n \leq 100\,000$) — the number of strings, wroted by Denis. Next $n$ lines contain non-empty strings $p_1, p_2, \ldots, p_n$, consisting of lowercase english letters. It's guaranteed, that the total length of the strings $p_i$ is at most $100\,000$, and that's the beauty of the resulting product is at most $10^9$. -----Output----- Print exactly one integer — the beauty of the product of the strings. -----Examples----- Input 3 a b a Output 3 Input 2 bnn a Output 1 -----Note----- In the first example, the product of strings is equal to "abaaaba". In the second example, the product of strings is equal to "abanana".	ALPH = "abcdefghijklmnopqrstuvwxyz" MAX = 10*9 def cnt(s): c = {ch: (0) for ch in ALPH} i = 0 while i < len(s): j = i + 1 while j < len(s) and s[i] == s[j]: j += 1 c[s[i]] = max(c[s[i]], j - i) i = j return c def nxt(c, t): nc = cnt(t) for ch in ALPH: if c[ch] and not nc[ch]: nc[ch] = 1 f = 0 while f < len(t) and t[f] == t[0]: f += 1 r = 0 while r < len(t) and t[-1 - r] == t[-1]: r += 1 if t[0] == t[-1]: if f == len(t): nc[t[0]] = max(nc[t[0]], c[t[0]] + (c[t[0]] + 1) len(t)) elif c[t[0]]: nc[t[0]] = max(nc[t[0]], f + 1 + r) else: nc[t[0]] = max(nc[t[0]], f + (c[t[0]] > 0)) nc[t[-1]] = max(nc[t[-1]], r + (c[t[-1]] > 0)) return {x: min(MAX, y) for x, y in nc.items()} n = int(input()) c = cnt(input()) for i in range(n - 1): c = nxt(c, input()) print(max(c.values()))	ASSIGN VAR STRING ASSIGN VAR BIN_OP NUMBER NUMBER FUNC_DEF ASSIGN VAR VAR NUMBER VAR VAR ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR ASSIGN VAR BIN_OP VAR NUMBER WHILE VAR FUNC_CALL VAR VAR VAR VAR VAR VAR VAR NUMBER ASSIGN VAR VAR VAR FUNC_CALL VAR VAR VAR VAR BIN_OP VAR VAR ASSIGN VAR VAR RETURN VAR FUNC_DEF ASSIGN VAR FUNC_CALL VAR VAR FOR VAR VAR IF VAR VAR VAR VAR ASSIGN VAR VAR NUMBER ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR VAR VAR VAR NUMBER VAR NUMBER ASSIGN VAR NUMBER WHILE VAR FUNC_CALL VAR VAR VAR BIN_OP NUMBER VAR VAR NUMBER VAR NUMBER IF VAR NUMBER VAR NUMBER IF VAR FUNC_CALL VAR VAR ASSIGN VAR VAR NUMBER FUNC_CALL VAR VAR VAR NUMBER BIN_OP VAR VAR NUMBER BIN_OP BIN_OP VAR VAR NUMBER NUMBER FUNC_CALL VAR VAR IF VAR VAR NUMBER ASSIGN VAR VAR NUMBER FUNC_CALL VAR VAR VAR NUMBER BIN_OP BIN_OP VAR NUMBER VAR ASSIGN VAR VAR NUMBER FUNC_CALL VAR VAR VAR NUMBER BIN_OP VAR VAR VAR NUMBER NUMBER ASSIGN VAR VAR NUMBER FUNC_CALL VAR VAR VAR NUMBER BIN_OP VAR VAR VAR NUMBER NUMBER RETURN VAR FUNC_CALL VAR VAR VAR VAR VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR BIN_OP VAR NUMBER ASSIGN VAR FUNC_CALL VAR VAR FUNC_CALL VAR EXPR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR
For a permutation P of length N, we define L(P) to be the length of the longest increasing subsequence in P. That is, L(P) is the largest integer K such that there exist indices i_{1} < i_{2} < \ldots < i_{K} such that P_{i_{1}} < P_{i_{2}} < \ldots < P_{i_{K}}. Define P^{R} to be the permutation (P_{N}, P_{N-1}, \ldots, P_{1}). You are given a positive integer N. You need to output a permutation P of length N such that L(P) = L(P^{R}), or say that none exist. Note: P is said to be a permutation of length N if P is a sequence of length N consisting of N distinct integers between 1 and N. For example, (3, 1, 2) is a permutation of length 3, but (1, 4, 2), (2, 2, 3) and (2, 1) are not. ------ Input Format ------ - The first line of input contains a single integer T, denoting the number of test cases. The description of T test cases follows. - Each test case consists of a single line containing one integer N — the length of the permutation to be constructed. ------ Output Format ------ For each test case, output on a new line "YES" if there exists a valid permutation, and "NO" if there doesn't. If you outputted "YES", on the next line, output a valid permutation P as N space-separated integers, the i^{th} of which is P_{i}. You can print each letter of the string in any case (upper or lower) (for instance, strings YES, yEs, and yes will be considered identical). ------ Constraints ------ $1 ≤ T ≤ 1000$ $2 ≤ N ≤ 2 \cdot 10^{5}$ - The sum of $N$ across all test cases does not exceed $2 \cdot 10^{5}$ ----- Sample Input 1 ------ 2 2 3 ----- Sample Output 1 ------ NO YES 1 3 2 ----- explanation 1 ------ Test Case $1$: There are two permutations of length $2$ — $(1, 2)$ and $(2, 1)$. The length of the LIS of $(1, 2)$ is $2$ and the length of the LIS of $(2, 1)$ is $1$. Since these permutations are reverses of each other and have unequal LIS lengths, there is no valid permutation of length $2$. Test Case $2$: The length of the LIS of $(1, 3, 2)$ is $2$, and the length of the LIS of its reverse, $(2, 3, 1)$, is also $2$. Therefore, this is a valid permutation of length $3$.	for _ in range(int(input())): n = int(input()) if n != 2: print("YES") if n == 1: print(1) else: a = [i for i in range(n, n // 2 + n % 2, -1)] + [ i for i in range(1, (n + 1) // 2 + 1) ] if n % 2 == 0: a[0], a[1] = a[1], a[0] print(*a) else: print("NO")	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR IF VAR NUMBER EXPR FUNC_CALL VAR STRING IF VAR NUMBER EXPR FUNC_CALL VAR NUMBER ASSIGN VAR BIN_OP VAR VAR FUNC_CALL VAR VAR BIN_OP BIN_OP VAR NUMBER BIN_OP VAR NUMBER NUMBER VAR VAR FUNC_CALL VAR NUMBER BIN_OP BIN_OP BIN_OP VAR NUMBER NUMBER NUMBER IF BIN_OP VAR NUMBER NUMBER ASSIGN VAR NUMBER VAR NUMBER VAR NUMBER VAR NUMBER EXPR FUNC_CALL VAR VAR EXPR FUNC_CALL VAR STRING
For a permutation P of length N, we define L(P) to be the length of the longest increasing subsequence in P. That is, L(P) is the largest integer K such that there exist indices i_{1} < i_{2} < \ldots < i_{K} such that P_{i_{1}} < P_{i_{2}} < \ldots < P_{i_{K}}. Define P^{R} to be the permutation (P_{N}, P_{N-1}, \ldots, P_{1}). You are given a positive integer N. You need to output a permutation P of length N such that L(P) = L(P^{R}), or say that none exist. Note: P is said to be a permutation of length N if P is a sequence of length N consisting of N distinct integers between 1 and N. For example, (3, 1, 2) is a permutation of length 3, but (1, 4, 2), (2, 2, 3) and (2, 1) are not. ------ Input Format ------ - The first line of input contains a single integer T, denoting the number of test cases. The description of T test cases follows. - Each test case consists of a single line containing one integer N — the length of the permutation to be constructed. ------ Output Format ------ For each test case, output on a new line "YES" if there exists a valid permutation, and "NO" if there doesn't. If you outputted "YES", on the next line, output a valid permutation P as N space-separated integers, the i^{th} of which is P_{i}. You can print each letter of the string in any case (upper or lower) (for instance, strings YES, yEs, and yes will be considered identical). ------ Constraints ------ $1 ≤ T ≤ 1000$ $2 ≤ N ≤ 2 \cdot 10^{5}$ - The sum of $N$ across all test cases does not exceed $2 \cdot 10^{5}$ ----- Sample Input 1 ------ 2 2 3 ----- Sample Output 1 ------ NO YES 1 3 2 ----- explanation 1 ------ Test Case $1$: There are two permutations of length $2$ — $(1, 2)$ and $(2, 1)$. The length of the LIS of $(1, 2)$ is $2$ and the length of the LIS of $(2, 1)$ is $1$. Since these permutations are reverses of each other and have unequal LIS lengths, there is no valid permutation of length $2$. Test Case $2$: The length of the LIS of $(1, 3, 2)$ is $2$, and the length of the LIS of its reverse, $(2, 3, 1)$, is also $2$. Therefore, this is a valid permutation of length $3$.	for t in range(int(input())): n = int(input()) flag = 0 if n == 2: print("NO") continue if n & 1: a = [1, 3, 2] flag = 1 else: a = [2, 1, 4, 3] flag = 0 if flag == 1: for i in range(4, n + 1, 2): a.insert(0, i) a.append(i + 1) else: for i in range(5, n + 1, 2): a.insert(0, i) a.append(i + 1) print("YES") print(*a)	FOR VAR FUNC_CALL VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR ASSIGN VAR NUMBER IF VAR NUMBER EXPR FUNC_CALL VAR STRING IF BIN_OP VAR NUMBER ASSIGN VAR LIST NUMBER NUMBER NUMBER ASSIGN VAR NUMBER ASSIGN VAR LIST NUMBER NUMBER NUMBER NUMBER ASSIGN VAR NUMBER IF VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER VAR EXPR FUNC_CALL VAR BIN_OP VAR NUMBER FOR VAR FUNC_CALL VAR NUMBER BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER VAR EXPR FUNC_CALL VAR BIN_OP VAR NUMBER EXPR FUNC_CALL VAR STRING EXPR FUNC_CALL VAR VAR
For a permutation P of length N, we define L(P) to be the length of the longest increasing subsequence in P. That is, L(P) is the largest integer K such that there exist indices i_{1} < i_{2} < \ldots < i_{K} such that P_{i_{1}} < P_{i_{2}} < \ldots < P_{i_{K}}. Define P^{R} to be the permutation (P_{N}, P_{N-1}, \ldots, P_{1}). You are given a positive integer N. You need to output a permutation P of length N such that L(P) = L(P^{R}), or say that none exist. Note: P is said to be a permutation of length N if P is a sequence of length N consisting of N distinct integers between 1 and N. For example, (3, 1, 2) is a permutation of length 3, but (1, 4, 2), (2, 2, 3) and (2, 1) are not. ------ Input Format ------ - The first line of input contains a single integer T, denoting the number of test cases. The description of T test cases follows. - Each test case consists of a single line containing one integer N — the length of the permutation to be constructed. ------ Output Format ------ For each test case, output on a new line "YES" if there exists a valid permutation, and "NO" if there doesn't. If you outputted "YES", on the next line, output a valid permutation P as N space-separated integers, the i^{th} of which is P_{i}. You can print each letter of the string in any case (upper or lower) (for instance, strings YES, yEs, and yes will be considered identical). ------ Constraints ------ $1 ≤ T ≤ 1000$ $2 ≤ N ≤ 2 \cdot 10^{5}$ - The sum of $N$ across all test cases does not exceed $2 \cdot 10^{5}$ ----- Sample Input 1 ------ 2 2 3 ----- Sample Output 1 ------ NO YES 1 3 2 ----- explanation 1 ------ Test Case $1$: There are two permutations of length $2$ — $(1, 2)$ and $(2, 1)$. The length of the LIS of $(1, 2)$ is $2$ and the length of the LIS of $(2, 1)$ is $1$. Since these permutations are reverses of each other and have unequal LIS lengths, there is no valid permutation of length $2$. Test Case $2$: The length of the LIS of $(1, 3, 2)$ is $2$, and the length of the LIS of its reverse, $(2, 3, 1)$, is also $2$. Therefore, this is a valid permutation of length $3$.	t = int(input()) for _ in range(t): n = int(input()) if n == 2: print("NO") continue print("YES") for i in range(1 + (n % 2 == 0), n // 2 + 1): print(i, end=" ") if n % 2 == 0: print(1, end=" ") for i in range(n, n // 2, -1): print(i, end=" ") print()	ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR FOR VAR FUNC_CALL VAR VAR ASSIGN VAR FUNC_CALL VAR FUNC_CALL VAR IF VAR NUMBER EXPR FUNC_CALL VAR STRING EXPR FUNC_CALL VAR STRING FOR VAR FUNC_CALL VAR BIN_OP NUMBER BIN_OP VAR NUMBER NUMBER BIN_OP BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR STRING IF BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR NUMBER STRING FOR VAR FUNC_CALL VAR VAR BIN_OP VAR NUMBER NUMBER EXPR FUNC_CALL VAR VAR STRING EXPR FUNC_CALL VAR

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