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71cf70241cec6f2240bf2959b5a8c78270800905 | 449d555969bfd7befe906877abab098c6e63a0e8 | /608/CH42/EX42.08/42_08.sce | 1ab25fd1afdf20ebdcc09f42ad107f0bf1248d17 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 649 | sce | 42_08.sce | //Problem 42.08: A high-pass T section filter has a cut-off frequency of 500 Hz and a nominal impedance of 600 ohm . Determine the frequency at which the characteristic impedance of the section is (a) zero, (b) 300 ohm , (c) 590 ohm .
//initializing the variables:
R0 = 600; // in ohm
fc = 500; // in Hz
Z1 = 0; // in ohm
Z2 = 300; // in ohm
Z3 = 590; // in ohm
//calculation:
//frequency
f1 = fc
f2 = fc/(1 - (Z2/R0)^2)^0.5
f3 = fc/(1 - (Z3/R0)^2)^0.5
printf("\n\n Result \n\n")
printf("\nfrequency at which the characteristic impedance of the section is 0 ohm is %.0f Hz and 300 Ohm is %.1f Hz and 590 ohm is %.0f Hz ",f1,f2,f3) |
594ccbe434b309eb4ab269d70ddec633dae496e5 | 449d555969bfd7befe906877abab098c6e63a0e8 | /48/CH12/EX12.9/eg_12_9.sce | 91a7fdc31ced50aadfd3704aacf6b6596149ff9b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 446 | sce | eg_12_9.sce | clc;
clear;
disp("In previosuly problems we have determined the input and output consistent partitions for the Machine M5");
disp("Input consistent partition {(AB),(CD),(EF)}");
disp("Output consistent partition {(ACE),(BDF)}");
disp("By assigning 000 to 101 to all the states from A to F");
disp("we can find the expressions for the next state and the output");
disp("Y1=y2");
disp("Y2=y1^y2^");
disp("Y3=xy3+xy2+x^y2^y3^+y2y3");
disp("z=xy3^"); |
1c8abe1d9e50020f880f03e3118fd880877c6028 | 6813325b126713766d9778d7665c10b5ba67227b | /Chapter7/Ch_7_Eg_7.8.sce | 6055a282358aa6b16e8af2b6b3a05471dc5d8247 | [] | no_license | arvindrachna/Introduction_to_Scilab | 955b2063b3faa33a855d18ac41ed7e0e3ab6bd1f | 9ca5d6be99e0536ba1c08a7a1bf4ba64620ec140 | refs/heads/master | 2020-03-15T19:26:52.964755 | 2018-05-31T04:49:57 | 2018-05-31T04:49:57 | 132,308,878 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,413 | sce | Ch_7_Eg_7.8.sce | // A program to find the derivatives from tabular data using the Newton’s forward interpolation.
// Input
// x and y = A set of data points
// xp = A point where derivatives are calculated
// Output
// yp = A polynomial of the form a0+a1 x+a2 x^2+ ...+an x^n
function [dydx]=ak_poly_derivative(x) // A function to evaluate the derivative
n=1:length(x)-1
c=x(2:$); // Extract the coefficients of the polynomial terms except the constant term
dydx=c.*n;
endfunction
// Main program
// input
clc;
x=1:.2:2.2;
y=round((%e^x)*10000)/10000; // Rounding to four decimal place accuracy
xp=2.0; // The point where the derivative is required
// Calculate the interpolative polynomial (refer interpolation section)
[yp] = ak_Newton_Fwd_Int_poly(x,y);
// Get coefficients of the polynomial
disp(yp, "f(x)=","Interpolating polynomial");
ypc=coeff(yp);
// Calculate first order derivative
[dydx]=ak_poly_derivative(ypc);
disp(poly(dydx,"x","coeff"),"d f(x)/dx =");
p=poly(dydx,"x","coeff");
// Calculate the derivative at the specified point and display
disp(msprintf("First derivative of f(x) at x= %f is %f",xp, horner(p,xp)));
// Calculate second order derivative
[d2ydx2]=ak_poly_derivative(dydx);
disp(poly(d2ydx2,"x","coeff"), "d^2 f(x)/dx^2 =");
p1=poly(d2ydx2,"x","coeff");
disp(msprintf("Second derivative of f(x) at x= %f is %f",xp, horner(p1,xp)));
|
0572356a44f2db868a166b67a66c327b365116b7 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1628/CH17/EX17.5/Ex17_5.sce | 221e6dd32398053311778f35fdaf99afa5890626 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 490 | sce | Ex17_5.sce |
// Examle 17.5
b=15; // Step Angle
m=3; // No.Oh phase
Nr=360/(m*b); // Number of rotors
disp('No.Of Rotors = '+string(abs(Nr)));
Ns1=(Nr*360)/((b*Nr)-360); // No.Of Stator When (Ns > Nr)
disp('No.Of Stator When (Ns > Nr) = '+string(abs(Ns1)));
Ns2=(Nr*360)/((b*Nr)+360); // No.Of Stator When (Ns < Nr)
disp('No.Of Stator When (Ns < Nr) = '+string(Ns2));
// p 690 17.5 |
60433cab882d7bbc0089860db6aeec7b7a574aab | 449d555969bfd7befe906877abab098c6e63a0e8 | /125/CH4/EX4.10/Example4_10.sce | 8f9565b26bf5111f250e29c72ccc7bd1e21931f6 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 452 | sce | Example4_10.sce | //Caption: Program to compute discrete cosine tranform
//Example4.10
//page 198
clc;
N =4; //DCT matrix of order four
X = dct_mtx(N);
disp(X,'DCT matrix of order four')
//Result
//DCT matrix of order four
//
// 0.5 0.5 0.5 0.5
// 0.6532815 0.2705981 - 0.2705981 - 0.6532815
// 0.5 - 0.5 - 0.5 0.5
// 0.2705981 - 0.6532815 0.6532815 - 0.2705981 |
a9c2e3f4b1d9d38190953f4b04180bb6e81bc62c | 449d555969bfd7befe906877abab098c6e63a0e8 | /1955/CH9/EX9.9/example9.sce | c86a6b8a47795f18e3bfc68bf6248f2536e2aa76 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,002 | sce | example9.sce | clc
clear
//input data
n0=0.74//Overall efficiency
H=5.5//Net head across the turbine in m
P=125//Required Power output in kW
N=230//Speed of the runner in rpm
nH=(1-0.18)//Hydraulic efficiency
g=9.81//Acceleration due to gravity in m/s^2
dw=1000//Density of water in kg/m^3
U1=0.97*(2*g*H)^(1/2)//Runner tangential velocity in m/s
Cr1=0.4*(2*g*H)^(1/2)//Flow velocity in m/s
//calculations
Cx1=(nH*g*H)/U1//Absolute inlet whirl velocity in m/s as flow is radial at outlet Cx2=0 in m/s
a11=atand(Cr1/Cx1)//Inlet guide vane angle in degree
b11=180+atand(Cr1/(Cx1-U1))//Angle of inlet guide vanes in radial direction in degree
D1=(U1*60)/(3.1415*N)//Runner inlet diameter in m
Q=(P*10^3)/(n0*dw*g*H)//Flow rate in m^3/s
b1=Q/(3.1415*D1*Cr1)//Height of runner in m
//output
printf('(a)Inlet guide vane angle is %3.1f degree\n(b)Angle of inlet guide vanes in radial direction is %3.1f degree\n(c)Runner inlet diameter is %3.3f m\n(d)Height of runner is %3.3f m',a11,b11,D1,b1)
|
2c91f1e577ee40ee7031c6b777845119b73db653 | 449d555969bfd7befe906877abab098c6e63a0e8 | /413/CH1/EX1.1/Table_1.sce | 387fe3f9bd21a29d2ac5e970d3bfea0fff8b57bb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 482 | sce | Table_1.sce | //The bisection method for f(x)=3*x+sin(x)-exp(x), starting from 0 and 1 in 13 iterations)
clearglobal()
clc;
fx='3*x+sin(x)-exp(x)'//Define function here
xa=0; // intial value
xb=1; // final vale where root need to bracket
n=13; // no. of iterations
x = xa; fa=eval(fx);
x = xb; fb=eval(fx);
for i=1:n
xc = (xa+xb)/2; x = xc; fc = eval(fx);
X = [i,xa,xb,xc,fc];
disp(X)
if fc*fa < 0 then
xb = xc;
else xa = xc;
end;
end;
|
6aee4674a909b0382c804cc879d32798f07d6a3f | 449d555969bfd7befe906877abab098c6e63a0e8 | /1322/CH10/EX10.2/75ex1.sce | 2c85445bd6f0c4b4f108577c3f07d4c43605da6e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 369 | sce | 75ex1.sce |
clear;
clc;
close;
clf;
length1=[100 120 170 220];
resistance=[2.5 3 4.25 5.5];
plot(length1,resistance,'b--.diam')
xtitle("Relation between Resistances and Length","length_in_meters","resistance_in_ohms");
xgrid;
length1=200;
resistance=5;
plot('length','resistance','b.diam')
plot(250,6.21,'b.diam')//this point is called extrapolation
|
fea551b2ce9decb23b1368468a07136b60232081 | 449d555969bfd7befe906877abab098c6e63a0e8 | /575/CH9/EX9.5.6/9_5_6.sce | 68706644bcc8f0ca730c24c1714d702ecd183e78 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,379 | sce | 9_5_6.sce | clc
pathname=get_absolute_file_path('9_5_6.sce')
filename=pathname+filesep()+'956.sci'
exec(filename)
printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook")
disp("Using S balance, ")
m2=basis*x*MS*MSalt/(MAcid*MS)
printf(" \n m2=%f g Na2SO4",m2)
disp("Using Na balance, ")
m1=2*MNa*m2*MBase/(y*MNa*MSalt)
printf(" \n m1=%f g NaOH",m1)
disp("Total mass balance, ")
m3=basis+m1-m2
printf(" \n m3=%f g H2O",m3)
printf(" \n Mass of product solution =%f",m2+m3)
m=m2+m3
Water=m2*2/MSalt
printf(" \n Water Formed in the reaction=%f mol H2O",Water)
disp("H2SO4(aq):")
a1=basis*(1-x)/MWater
b1=basis*x/MAcid
rAcid=a1/b1
printf(" \n rAcid=%f mol Water/mol Acid",rAcid)
disp("NaOH(aq):")
a2=m1*(1-y)/MWater
b2=m1*y/MBase
rBase=a2/b2
printf(" \n rBase=%f mol Water/mol Base",rBase)
disp("Na2SO4(aq):")
a3=m3/MWater
b3=m2/MSalt
rSalt=a3/b3
printf(" \n rSalt=%f mol Water/mol Salt",rSalt)
E=b1
printf(" \n Extent of reaction=%f mol",E)
nHAcid=basis*3.85*(T3-T1)/1000
nHSalt=m*4.184*(T2-T1)/1000
nHBase=0
HfSalt= -1384
HfAcid= -884.6
HfBase= -468.1
HfWater= -285.84
deltaHr=HfSalt+ 2*HfWater - HfAcid - 2*HfBase
printf(" \n Entahlpy change in the rxn=%f Kj/mol",deltaHr)
Q=E*deltaHr + (nHSalt-nHAcid-nHBase)
printf(" \n Q of the rxn=%f Kj",Q)
disp("The answer in the Text is wrong.") |
36355d2a4c373a74f3b022ecfe02b515a9523973 | 931df7de6dffa2b03ac9771d79e06d88c24ab4ff | /Skiing Aimer 50 Targets.sce | eef901bbd495c6e87e23d4c5206067e263a9e900 | [] | no_license | MBHuman/Scenarios | be1a722825b3b960014b07cda2f12fa4f75c7fc8 | 1db6bfdec8cc42164ca9ff57dd9d3c82cfaf2137 | refs/heads/master | 2023-01-14T02:10:25.103083 | 2020-11-21T16:47:14 | 2020-11-21T16:47:14 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 50,146 | sce | Skiing Aimer 50 Targets.sce | Name=Skiing Aimer 50 Targets
PlayerCharacters=Player
BotCharacters=target.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot
IsChallenge=true
Timelimit=60.0
PlayerProfile=Player
AddedBots=target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot
PlayerMaxLives=1
BotMaxLives=1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1
PlayerTeam=1
BotTeams=2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2;2
MapName=Ski.map
MapScale=9.0
BlockProjectilePredictors=true
BlockCheats=true
InvinciblePlayer=true
InvincibleBots=false
Timescale=1.0
BlockHealthbars=true
TimeRefilledByKill=0.0
ScoreToWin=500.0
ScorePerDamage=10.0
ScorePerKill=0.0
ScorePerMidairDirect=0.0
ScorePerAnyDirect=0.0
ScorePerTime=1.0
ScoreLossPerDamageTaken=0.0
ScoreLossPerDeath=0.0
ScoreLossPerMidairDirected=0.0
ScoreLossPerAnyDirected=0.0
ScoreMultAccuracy=true
ScoreMultDamageEfficiency=false
ScoreMultKillEfficiency=false
GameTag=Flick, MouseControl, Clicktiming
WeaponHeroTag=BB Gun
DifficultyTag=2
AuthorsTag=Lac
BlockHitMarkers=false
BlockHitSounds=false
BlockMissSounds=false
BlockFCT=true
Description=ez
GameVersion=1.0.7.2
ScorePerDistance=0.0
[Aim Profile]
Name=_
MinReactionTime=0.000001
MaxReactionTime=0.000001
MinSelfMovementCorrectionTime=0.000001
MaxSelfMovementCorrectionTime=0.000001
FlickFOV=90.0
FlickSpeed=10.0
FlickError=0.0
TrackSpeed=10.0
TrackError=0.0
MaxTurnAngleFromPadCenter=360.0
MinRecenterTime=0.0
MaxRecenterTime=0.0
OptimalAimFOV=360.0
OuterAimPenalty=0.0
MaxError=0.0
ShootFOV=90.0
VerticalAimOffset=0.0
MaxTolerableSpread=0.0
MinTolerableSpread=0.0
TolerableSpreadDist=100000.0
MaxSpreadDistFactor=1.0
[Bot Profile]
Name=target
DodgeProfileNames=Nothing
DodgeProfileWeights=1.0
DodgeProfileMaxChangeTime=1.0
DodgeProfileMinChangeTime=1.0
WeaponProfileWeights=1.0;1.0;1.0;1.0;1.0;1.0;1.0;1.0
AimingProfileNames=_;_;_;_;_;_;_;_
WeaponSwitchTime=60.0
UseWeapons=false
CharacterProfile=TileFrenzy Sphere
SeeThroughWalls=false
NoDodging=false
NoAiming=true
[Bot Profile]
Name=TileFrenzy Sphere
DodgeProfileNames=Nothing
DodgeProfileWeights=1.0
DodgeProfileMaxChangeTime=1.0
DodgeProfileMinChangeTime=1.0
WeaponProfileWeights=1.0;1.0;1.0;1.0;1.0;1.0;1.0;1.0
AimingProfileNames=_;_;_;_;_;_;_;_
WeaponSwitchTime=60.0
UseWeapons=false
CharacterProfile=TileFrenzy Sphere
SeeThroughWalls=false
NoDodging=false
NoAiming=true
[Character Profile]
Name=Player
MaxHealth=500.0
WeaponProfileNames=;BB Gun;;;;;;
MinRespawnDelay=1.0
MaxRespawnDelay=5.0
StepUpHeight=75.0
CrouchHeightModifier=0.5
CrouchAnimationSpeed=2.0
CameraOffset=X=0.000 Y=0.000 Z=80.000
HeadshotOnly=false
DamageKnockbackFactor=4.0
MovementType=Base
MaxSpeed=0.0
MaxCrouchSpeed=500.0
Acceleration=0.0
AirAcceleration=16000.0
Friction=0.0
BrakingFrictionFactor=0.0
JumpVelocity=0.0
Gravity=0.397
AirControl=0.25
CanCrouch=false
CanPogoJump=false
CanCrouchInAir=true
CanJumpFromCrouch=false
EnemyBodyColor=X=0.771 Y=0.000 Z=0.000
EnemyHeadColor=X=1.000 Y=1.000 Z=1.000
TeamBodyColor=X=1.000 Y=0.888 Z=0.000
TeamHeadColor=X=1.000 Y=1.000 Z=1.000
BlockSelfDamage=false
InvinciblePlayer=false
InvincibleBots=false
BlockTeamDamage=false
AirJumpCount=0
AirJumpVelocity=0.0
MainBBType=Cylindrical
MainBBHeight=1.0
MainBBRadius=0.1
MainBBHasHead=false
MainBBHeadRadius=45.0
MainBBHeadOffset=0.0
MainBBHide=false
ProjBBType=Cylindrical
ProjBBHeight=230.0
ProjBBRadius=55.0
ProjBBHasHead=false
ProjBBHeadRadius=45.0
ProjBBHeadOffset=0.0
ProjBBHide=true
HasJetpack=false
JetpackActivationDelay=0.2
JetpackFullFuelTime=4.0
JetpackFuelIncPerSec=1.0
JetpackFuelRegensInAir=false
JetpackThrust=6000.0
JetpackMaxZVelocity=400.0
JetpackAirControlWithThrust=0.25
AbilityProfileNames=;;;
HideWeapon=false
AerialFriction=0.0
StrafeSpeedMult=0.0
BackSpeedMult=0.0
RespawnInvulnTime=0.0
BlockedSpawnRadius=0.0
BlockSpawnFOV=0.0
BlockSpawnDistance=0.0
RespawnAnimationDuration=0.5
AllowBufferedJumps=true
BounceOffWalls=false
LeanAngle=0.0
LeanDisplacement=0.0
AirJumpExtraControl=0.0
ForwardSpeedBias=0.1
HealthRegainedonkill=0.0
HealthRegenPerSec=0.0
HealthRegenDelay=0.0
JumpSpeedPenaltyDuration=0.0
JumpSpeedPenaltyPercent=0.0
ThirdPersonCamera=false
TPSArmLength=300.0
TPSOffset=X=0.000 Y=150.000 Z=150.000
BrakingDeceleration=0.0
VerticalSpawnOffset=0.0
SpawnXOffset=0.0
SpawnYOffset=0.0
[Character Profile]
Name=TileFrenzy Sphere
MaxHealth=1.0
WeaponProfileNames=;;;;;;;
MinRespawnDelay=0.000001
MaxRespawnDelay=0.000001
StepUpHeight=0.0
CrouchHeightModifier=1.0
CrouchAnimationSpeed=1.0
CameraOffset=X=0.000 Y=0.000 Z=0.000
HeadshotOnly=false
DamageKnockbackFactor=0.0
MovementType=Base
MaxSpeed=0.0
MaxCrouchSpeed=0.0
Acceleration=0.0
AirAcceleration=16000.0
Friction=0.0
BrakingFrictionFactor=0.0
JumpVelocity=0.0
Gravity=0.0
AirControl=0.0
CanCrouch=false
CanPogoJump=false
CanCrouchInAir=false
CanJumpFromCrouch=false
EnemyBodyColor=X=1.000 Y=1.000 Z=1.000
EnemyHeadColor=X=1.000 Y=0.000 Z=0.000
TeamBodyColor=X=0.000 Y=0.000 Z=255.000
TeamHeadColor=X=255.000 Y=255.000 Z=255.000
BlockSelfDamage=false
InvinciblePlayer=false
InvincibleBots=false
BlockTeamDamage=false
AirJumpCount=0
AirJumpVelocity=800.0
MainBBType=Spheroid
MainBBHeight=256.0
MainBBRadius=128.0
MainBBHasHead=false
MainBBHeadRadius=0.1
MainBBHeadOffset=0.0
MainBBHide=false
ProjBBType=Spheroid
ProjBBHeight=256.0
ProjBBRadius=128.0
ProjBBHasHead=false
ProjBBHeadRadius=0.1
ProjBBHeadOffset=0.0
ProjBBHide=true
HasJetpack=false
JetpackActivationDelay=0.2
JetpackFullFuelTime=4.0
JetpackFuelIncPerSec=1.0
JetpackFuelRegensInAir=false
JetpackThrust=6000.0
JetpackMaxZVelocity=400.0
JetpackAirControlWithThrust=0.25
AbilityProfileNames=;;;
HideWeapon=true
AerialFriction=0.0
StrafeSpeedMult=1.0
BackSpeedMult=1.0
RespawnInvulnTime=0.0
BlockedSpawnRadius=0.0
BlockSpawnFOV=0.0
BlockSpawnDistance=0.0
RespawnAnimationDuration=0.0
AllowBufferedJumps=false
BounceOffWalls=false
LeanAngle=0.0
LeanDisplacement=0.0
AirJumpExtraControl=0.0
ForwardSpeedBias=1.0
HealthRegainedonkill=0.0
HealthRegenPerSec=0.0
HealthRegenDelay=0.0
JumpSpeedPenaltyDuration=0.0
JumpSpeedPenaltyPercent=0.0
ThirdPersonCamera=false
TPSArmLength=300.0
TPSOffset=X=0.000 Y=150.000 Z=150.000
BrakingDeceleration=0.0
VerticalSpawnOffset=-128.0
SpawnXOffset=0.0
SpawnYOffset=0.0
[Dodge Profile]
Name=Nothing
MaxTargetDistance=100000.0
MinTargetDistance=0.0
ToggleLeftRight=false
ToggleForwardBack=false
MinLRTimeChange=0.2
MaxLRTimeChange=0.5
MinFBTimeChange=0.2
MaxFBTimeChange=0.5
DamageReactionChangesDirection=false
DamageReactionChanceToIgnore=0.0
DamageReactionMinimumDelay=0.1
DamageReactionMaximumDelay=0.15
DamageReactionCooldown=1.0
DamageReactionThreshold=0.0
DamageReactionResetTimer=0.1
JumpFrequency=0.0
CrouchInAirFrequency=0.0
CrouchOnGroundFrequency=0.0
TargetStrafeOverride=Ignore
TargetStrafeMinDelay=0.125
TargetStrafeMaxDelay=0.25
MinProfileChangeTime=100.0
MaxProfileChangeTime=100.0
MinCrouchTime=10.0
MaxCrouchTime=10.0
MinJumpTime=0.0
MaxJumpTime=0.0
LeftStrafeTimeMult=1.0
RightStrafeTimeMult=1.0
StrafeSwapMinPause=10.0
StrafeSwapMaxPause=10.0
BlockedMovementPercent=0.0
BlockedMovementReactionMin=0.0
BlockedMovementReactionMax=0.0
[Weapon Profile]
Name=BB Gun
Type=Hitscan
ShotsPerClick=1
DamagePerShot=1.0
KnockbackFactor=4.0
TimeBetweenShots=0.1
Pierces=false
Category=SemiAuto
BurstShotCount=1
TimeBetweenBursts=0.5
ChargeStartDamage=10.0
ChargeStartVelocity=X=500.000 Y=0.000 Z=0.000
ChargeTimeToAutoRelease=2.0
ChargeTimeToCap=1.0
ChargeMoveSpeedModifier=1.0
MuzzleVelocityMin=X=2000.000 Y=0.000 Z=0.000
MuzzleVelocityMax=X=2000.000 Y=0.000 Z=0.000
InheritOwnerVelocity=0.0
OriginOffset=X=0.000 Y=0.000 Z=0.000
MaxTravelTime=5.0
MaxHitscanRange=100000.0
GravityScale=1.0
HeadshotCapable=false
HeadshotMultiplier=2.0
MagazineMax=0
AmmoPerShot=1
ReloadTimeFromEmpty=0.5
ReloadTimeFromPartial=0.5
DamageFalloffStartDistance=100000.0
DamageFalloffStopDistance=100000.0
DamageAtMaxRange=25.0
DelayBeforeShot=0.0
HitscanVisualEffect=None
ProjectileGraphic=Ball
VisualLifetime=0.1
WallParticleEffect=None
HitParticleEffect=Flare
BounceOffWorld=false
BounceFactor=0.5
BounceCount=0
HomingProjectileAcceleration=0.0
ProjectileEnemyHitRadius=1.0
CanAimDownSight=false
ADSZoomDelay=0.0
ADSZoomSensFactor=0.7
ADSMoveFactor=1.0
ADSStartDelay=0.0
ShootSoundCooldown=0.08
HitSoundCooldown=0.08
HitscanVisualOffset=X=0.000 Y=0.000 Z=-50.000
ADSBlocksShooting=false
ShootingBlocksADS=false
KnockbackFactorAir=4.0
RecoilNegatable=false
DecalType=1
DecalSize=30.0
DelayAfterShooting=0.0
BeamTracksCrosshair=false
AlsoShoot=
ADSShoot=
StunDuration=0.0
CircularSpread=true
SpreadStationaryVelocity=0.0
PassiveCharging=false
BurstFullyAuto=true
FlatKnockbackHorizontal=0.0
FlatKnockbackVertical=0.0
HitscanRadius=0.0
HitscanVisualRadius=6.0
TaggingDuration=0.0
TaggingMaxFactor=1.0
TaggingHitFactor=1.0
ProjectileTrail=None
RecoilCrouchScale=1.0
RecoilADSScale=1.0
PSRCrouchScale=1.0
PSRADSScale=1.0
ProjectileAcceleration=0.0
AccelIncludeVertical=false
AimPunchAmount=0.0
AimPunchResetTime=0.05
AimPunchCooldown=0.5
AimPunchHeadshotOnly=false
AimPunchCosmeticOnly=false
MinimumDecelVelocity=0.0
PSRManualNegation=false
PSRAutoReset=true
AimPunchUpTime=0.05
AmmoReloadedOnKill=0
CancelReloadOnKill=false
FlatKnockbackHorizontalMin=0.0
FlatKnockbackVerticalMin=0.0
ADSScope=No Scope
ADSFOVOverride=72.099998
ADSFOVScale=Overwatch
ADSAllowUserOverrideFOV=true
IsBurstWeapon=false
ForceFirstPersonInADS=true
ZoomBlockedInAir=false
ADSCameraOffsetX=0.0
ADSCameraOffsetY=0.0
ADSCameraOffsetZ=0.0
QuickSwitchTime=0.0
Explosive=false
Radius=500.0
DamageAtCenter=100.0
DamageAtEdge=100.0
SelfDamageMultiplier=0.5
ExplodesOnContactWithEnemy=false
DelayAfterEnemyContact=0.0
ExplodesOnContactWithWorld=false
DelayAfterWorldContact=0.0
ExplodesOnNextAttack=false
DelayAfterSpawn=0.0
BlockedByWorld=false
SpreadSSA=1.0,1.0,-1.0,5.0
SpreadSCA=1.0,1.0,-1.0,5.0
SpreadMSA=1.0,1.0,-1.0,5.0
SpreadMCA=1.0,1.0,-1.0,5.0
SpreadSSH=0.0,0.1,0.0,0.0
SpreadSCH=1.0,1.0,-1.0,5.0
SpreadMSH=0.0,0.1,0.0,0.0
SpreadMCH=1.0,1.0,-1.0,5.0
MaxRecoilUp=0.0
MinRecoilUp=0.0
MinRecoilHoriz=0.0
MaxRecoilHoriz=0.0
FirstShotRecoilMult=1.0
RecoilAutoReset=false
TimeToRecoilPeak=0.05
TimeToRecoilReset=0.35
AAMode=0
AAPreferClosestPlayer=true
AAAlpha=1.0
AAMaxSpeed=360.0
AADeadZone=0.0
AAFOV=360.0
AANeedsLOS=true
TrackHorizontal=true
TrackVertical=true
AABlocksMouse=false
AAOffTimer=0.0
AABackOnTimer=0.0
TriggerBotEnabled=false
TriggerBotDelay=0.0
TriggerBotFOV=1.0
StickyLock=false
HeadLock=false
VerticalOffset=0.0
DisableLockOnKill=false
UsePerShotRecoil=false
PSRLoopStartIndex=0
PSRViewRecoilTracking=0.45
PSRCapUp=9.0
PSRCapRight=4.0
PSRCapLeft=4.0
PSRTimeToPeak=0.175
PSRResetDegreesPerSec=40.0
UsePerBulletSpread=false
PBS0=0.0,0.0
[Map Data]
reflex map version 8
global
entity
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Float sky.timeOfDay 13.000000
ColourXRGB32 sky.sunColor ffffde8c
Float sky.sunIntensitySize 64.000000
Float sky.sunSharpness 128.000000
Bool8 sky.sunEnabled 0
ColourXRGB32 sky.horizonColor fffff4b5
Float sky.horizonIntensity 0.250000
Float sky.horizonHaloExponentSunIntensity 0.300000
ColourXRGB32 sky.cloudsColor ffffffff
Float sky.cloudsCoverage 0.500000
Float sky.cloudsCoverageMultiplier 24.000000
Float sky.cloudsRoughness 0.400000
UInt8 playersMin 1
UInt8 playersMax 16
Bool8 modeFFA 0
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type PlayerSpawn
Vector3 position -3920.000000 784.000000 -256.000000
Vector3 angles -630.000000 0.000000 0.000000
Bool8 teamA 0
Bool8 initialSpawn 0
Bool8 modeCTF 0
Bool8 modeFFA 0
Bool8 modeTDM 0
Bool8 mode1v1 0
Bool8 modeRace 0
Bool8 mode2v2 0
entity
type PlayerSpawn
Vector3 position -3920.000000 640.000000 -352.000000
Vector3 angles -630.000000 0.000000 0.000000
Bool8 teamA 0
Bool8 initialSpawn 0
Bool8 modeCTF 0
Bool8 modeFFA 0
Bool8 modeTDM 0
Bool8 mode1v1 0
Bool8 modeRace 0
Bool8 mode2v2 0
entity
type PlayerSpawn
Vector3 position -4928.000000 -144.000000 -144.000000
Vector3 angles -630.000000 0.000000 0.000000
Bool8 teamA 0
Bool8 initialSpawn 0
Bool8 modeCTF 0
Bool8 modeFFA 0
Bool8 modeTDM 0
Bool8 mode1v1 0
Bool8 modeRace 0
Bool8 mode2v2 0
|
05fa77da1ec31b2cc63e9b754d89cea5d9f1cb36 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3535/CH5/EX5.8/Ex5_8.sce | 656794b8a836d53ec8430409340153a95a8e5acb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 211 | sce | Ex5_8.sce | //Chapter 5, Example 5.8, Page 130
clc
clear
// Calculate the time
//based on eq 5.74
t = (4.88*10**10/log(2))*log(1+((0.80-0.710)/1.37208))
printf("\n Time = %e y ",t);
//Answer may vary due to round off error
|
69b9e1ed0b85bbe991b778a825779ab75a8f7ead | 449d555969bfd7befe906877abab098c6e63a0e8 | /2207/CH2/EX2.7.5/ex_2_7_5.sce | fd04bf3ccfee25183a6d67cdf155cf878993a429 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 222 | sce | ex_2_7_5.sce | //Example 2.7.5;//resistance
clc;
clear;
close;
//given data :
format('v',4)
vg=15;//in volys
vgk=0.7;//in volts
pg=0.5;// in watts
ig=pg/vgk;//in amperes
rg=(vg-vgk)/ig;//in ohms
disp(rg,"gate source resistance in ohm ")
|
6d689dde838923a963b609449c8481d005bcf739 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3648/CH27/EX27.3/Ex27_3.sce | c931beac64ca8162b9e460138234998a51eda7ff | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 403 | sce | Ex27_3.sce | //Example 27_3
clc();
clear;
//To calculate the energy required to change the mass of a system
c=3*10^8 //units in meters/sec
m=1.66*10^-27 //Units in g
e=m*c^2 //Units in J
e=e/(1.6*10^-19)*10^-6 //Units in MeV
printf("The energy required to change the mass of a system is=%.1f MeV",e)
//In text book answer is printed wrong as e=931.5Mev the correct answer is933.7 MeV
|
f5417c0f0ca0dff9132a83d00c12c392a0d8c343 | 3b9a879e67cbab4a5a4a5081e2e9c38b3e27a8cc | /Pack/Área 2/M8/Códigos_resoluções/minquad_all_q4.sce | d557fcac94de037bbf7f22b55d355842a6a2d1d2 | [
"MIT"
] | permissive | JPedroSilveira/numerical-calculus-with-scilab | 32e04e9b1234a0a82275f86aa2d6416198fa6c81 | 190bc816dfaa73ec2efe289c34baf21191944a53 | refs/heads/master | 2023-05-10T22:39:02.550321 | 2021-05-11T17:17:09 | 2021-05-11T17:17:09 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 553 | sce | minquad_all_q4.sce | clear;
x=1:0.5:12 // O X
x = x'
y = 17 * sin(x) + x.^2// Y do problema
n=size(x,1);
M=[x.^0 x.^1 x.^2] //x e x^2 polinomio (formato bx + cx^2), se quiser a+bx+cx^2 ficaria [x.^0 x x.^2]
cu = M' * M
pau = M' * y //SE VOCÊ CRIOU Y COM PONTOS SEPARADOS (SEM SER FUNÇÃO DE X), AQUI TEM QUE SER y'
//alternativamente, só adiciona o ' (ou tira ele) se der inconsistent rows
//isso aí, boa sorte nas provas :0
disp('Coeficientes:')
coef = inv(cu) * pau
disp(coef)
//P = coef(1) + coef(2) * 3.14 + coef(3) * 3.14^2
//disp(P)
|
6ec2354a5c79476ca6e68acae7ef77dcba94c9ef | 449d555969bfd7befe906877abab098c6e63a0e8 | /3456/CH2/EX2.3/Ex2_3.sce | 4c0b75afb54366ad0f4a2efe86a79cbd131d1f60 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 497 | sce | Ex2_3.sce | //Example 2.3
//Calculation of Stresses from elastic strains
//Page No. 52
clc;clear;close;
E=200; //in GPa
nu=0.33; //no unit
e1=0.004; //no unit
e2=0.001; //no unit
sigma1=E*(e1+nu*e2)/(1-nu^2);
sigma2=E*(e2+nu*e1)/(1-nu^2);
sigma1=sigma1*1000; //conversion to MPa
sigma2=sigma2*1000; //conversion to MPa
printf('\nsigma1 = %g MPa\nsigma2 = %g MPa\n',sigma1,sigma2);
printf('\nNote: Slight calculation errors in Book')
|
ee05430108eb517973e8afe5a3b3f9def4e81add | 449d555969bfd7befe906877abab098c6e63a0e8 | /929/CH7/EX7.8/Example7_8.sce | 578bd77ca160ade6af34ba65d40c6fec8ea24e48 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,099 | sce | Example7_8.sce | //Example 7.8
clear;
clc;
R1=100*10^3;
R2=200*10^3;
R3=68*10^3;
enw=20*10^(-9);
fce=200;
ft=1*10^6;
inw=0.5*10^(-12);
fci=2*10^3;
Rp=(R1*R2)/(R1+R2);
Ano=1+(R2/R1);
fB=ft/Ano;
fL=0.1;
Enoeold=Ano*enw*sqrt([{fce*log(fB/fL)}+{1.57*fB}-fL]);
Enoiold=Ano*[{(R3^2)+(Rp^2)}^(1/2)]*inw*([(fci*log(fB/fL))+(1.57*fB)]^(1/2));
k=1.38*10^(-23);
T=25+273;//Room temperature in Kelvin
EnoRold=Ano*[{(4*k*T)*(R3+Rp)*1.57*fB}^(1/2)];
Enoold=sqrt((Enoeold^2)+(Enoiold^2)+(EnoRold^2));
Enonew=50*10^(-6);//New Value of Eno mentioned in problem
Enoisum=(Enonew^2)-(Enoeold^2);//sum of (Enoi^2) and (EnoR^2)
Enoinewsq=(Ano^2)*(inw^2)*[(fci*log(fB/fL))+(1.57*fB)];//(Enoinew^2)/(R^2)
EnoRnewsq=(Ano^2)*((4*k*T)*1.57*fB);
r=poly(0,'x');
p=(Enoinewsq*(r^2))+(EnoRnewsq*r)-Enoisum;
[r1]=roots(p);
R=r1(2,1)
R3new=R/2;
R1new=(3*R3new)/2;
R2new=2*R1new;
printf("Resistances after scaling are :");
printf("\nR1=%.2f kohms",R1new*10^(-3));
printf("\nR2=%.1f kohms",R2new*10^(-3));
printf("\nR3=%.1f kohms",R3new*10^(-3)); |
99dc7fadab9c2252518c0ecccb21782bd939bb3a | 70c2cdeb1ba5d1d533f509552e548ee49b7ed363 | /And.tst | 34e8c4b1be49b13886eb8ec01ad67193fa82ca9f | [] | no_license | Seakuh/ProgrammierModelleAufgabenBlatt2 | 378a2599e560c7d3e4330cbb4ee87574547e250a | f23867ff10992cf4cca2815622ebbec010b4dffb | refs/heads/master | 2022-07-18T04:26:43.425789 | 2020-05-06T14:03:00 | 2020-05-06T14:03:00 | 260,497,464 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 252 | tst | And.tst | load And.hdl,
output-file And.out,
compare-to and.cmp,
output-list in1%B3.1.3
in2%B3.1.3
result%B3.1.3;
set in1 0,
set in2 0,
eval,
output;
set in1 0,
set in2 1,
eval,
output;
set in1 1,
set in2 0,
eval,
output;
set in1 1,
set in2 1,
eval,
output; |
55e63c076ab8889fe45012efe86996157d313873 | c52b86c70bfb65ede26a67e3a1647999383b3a5d | /sci_gateway/builder_gateway.sce | d05c643c65e4c698886d99cf0170abc9da94b400 | [] | no_license | FOSSEE-Internship/FOSSEE-Julia-Toolbox | 8847c2b1ea8ac69234d9d3a7f8f4238840bf9d62 | 10811cd0ceb00cb4a9303a6fc61e995fbbdb6b4d | refs/heads/master | 2020-12-02T16:18:10.355600 | 2017-10-25T14:08:55 | 2017-10-25T14:08:55 | 96,516,912 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 244 | sce | builder_gateway.sce | sci_gateway_dir = get_absolute_file_path('builder_gateway.sce');
tbx_builder_gateway_lang('c', sci_gateway_dir);
tbx_build_gateway_loader(['c'], sci_gateway_dir);
clear tbx_builder_gateway_lang tbx_build_gateway_loader;
clear sci_gateway_dir; |
14b70ca8a43924dd4068fe0bbc51fa9e49826c93 | 527c41bcbfe7e4743e0e8897b058eaaf206558c7 | /Positive_Negative_test/Netezza-Base-StatisticalFunctions/FLPercWin-NZ-01.tst | 391c78198fc365c9541255ffd251569898b9c5c4 | [] | no_license | kamleshm/intern_fuzzy | c2dd079bf08bede6bca79af898036d7a538ab4e2 | aaef3c9dc9edf3759ef0b981597746d411d05d34 | refs/heads/master | 2021-01-23T06:25:46.162332 | 2017-07-12T07:12:25 | 2017-07-12T07:12:25 | 93,021,923 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 7,971 | tst | FLPercWin-NZ-01.tst | -- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza
--
-- Copyright (c): 2014 Fuzzy Logix, LLC
--
-- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC.
-- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC.
-- and may be covered by U.S. and Foreign Patents, patents in process, and are protected by trade
-- secret or copyright law. Dissemination of this information or reproduction of this material is
-- strictly forbidden unless prior written permission is obtained from Fuzzy Logix, LLC.
-- Functional Test Specifications:
--
-- Test Category: Basic Statistics
--
-- Test Unit Number: FLPercWin-Netezza-01
--
-- Name(s): FLPercWin
--
-- Description: User defined table function which returns the specified percentile
--
-- Applications:
--
-- Signature: FLPercWin(pValue DOUBLE PRECISION, pPerc DOUBLE PRECISION)
--
-- Parameters: See Documentation
--
-- Return value: DOUBLE PRECISION
--
-- Last Updated: 03-04-2017
--
-- Author: Kamlesh Meena
--
-- BEGIN: TEST SCRIPT
\time
--.run file=../PulsarLogOn.sql
--.set width 2500
SELECT COUNT(*) AS CNT,
CASE WHEN CNT = 0 THEN ' Please Load Test Data!!! ' ELSE ' Test Data Loaded ' END AS TestOutcome
FROM fzzlSerial a;
-- BEGIN: POSITIVE TEST(s)
---- Positive Test 1: One observation, Any quantile should be the value itself
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, RandVal as Val
FROM fzzlSerial
WHERE SerialVal <=1
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, RandVal as Val
FROM fzzlSerial
WHERE SerialVal =2
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 2: Two observations
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, RandVal as Val
FROM fzzlSerial
WHERE SerialVal <=2
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 3: Positive test cases, Results should be 50.5, Compared with FLMedianWin()
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.50) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 4: Mixed with Nulls, Results shoud not change
--- Return expected results
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.50) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, CASE WHEN SerialVal <= 100 THEN SerialVal ELSE NULL END as Val
FROM fzzlSerial
WHERE SerialVal <=200
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 5: Percentile of -1.0 * Value, Results should be -25.75
--- Return expected results
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(-1.0*a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 6: Percentile of Value + 1.0, Results should be 75.25 + 1
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val+1.0, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 7: Percentile of -1.0 * Value + 1.0, Results should be -25.75 + 1
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(-1.0*a.Val+1.0, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 8: Percentile of 10.0 * Value + 1.0, Results should be 75.25 * 10 + 1
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(10.0*a.Val+1.0, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 9: Multiply by a very small number, Results should be 1e-100 * 75.25
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(1e-100*a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 10: Multiply by a very large number, Results should be 1e100 * 75.25
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(1e100*a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Positive Test 11: Add a very large number, Should return 1e100+ 75.25
--- Precision issue, return 1e100, which is expected
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(1e100+a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
-- END: POSITIVE TEST(s)
-- BEGIN: NEGATIVE TEST(s)
---- Negative Test 1: No data
--- No Output
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, RandVal as Val
FROM fzzlSerial
WHERE SerialVal <=-1
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 2: Value(Double Precision) out of range: Percentile of 1.0e400 * Value
--- Return expected error, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(1e400*a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 3: Value(Double Precision) out of range: Percentile of 1.0e-400 * Value
--- Return value 0, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(1e-400*a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, SerialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 4: Invalid Data Type:Input Varchar
--- Return expected error, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(1e100*a.Val, 0.75) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, CAST(SerialVal AS VARCHAR(30)) as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 5: Percentile
---- Negative Test 5a: Very Small value, Results should be 1
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 1e-100) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, serialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 5b: 0 Percentile,
--- Return expected error message for bound on PercArg, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 0.0) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, serialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 5c: 1 percentile, Results should be 100
--- Return expected results, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 1.0) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, serialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
---- Negative Test 5d: percentile> 1, Should be Error msg
--- Return expected error, Good
SELECT p.*
FROM (
SELECT a.Grp,
FLPercWin(a.Val, 20.0) OVER(PARTITION BY a.Grp) AS Median
FROM (
SELECT 1 as Grp, serialVal as Val
FROM fzzlSerial
WHERE SerialVal <=100
) a
) AS p
WHERE p.Median IS NOT NULL
ORDER BY 1;
-- END: NEGATIVE TEST(s)
\time
-- END: TEST SCRIPT
|
a03191b29737695d38cbf943866b7ffe0ef27c51 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1646/CH5/EX5.6/Ch05Ex6.sce | a35ee83fa2437192ee77797b9c397ce96bf7f072 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 420 | sce | Ch05Ex6.sce | // Scilab Code Ex5.6: Page:299 (2011)
clc;clear;
lambda = 6.328e-007;....// Wavelength of the monochromatic light, m
D = 40;....// Distance between the slits and the screen, m
W = 0.1;....// Distance between the interference maxima, m
d = lambda*D/W; // Distance between the slits, m
printf("\nThe distance between the slits = %6.4f mm",d/1e-03);
// Result
// The distance between the slits = 0.2531 mm
|
8a4db8c685b9b73048c85bed5f608de4e4c579e9 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1553/CH4/EX4.22/4Ex22.sce | 9a072b89ecd74c17ec38a66b017321b959992f34 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 236 | sce | 4Ex22.sce | //chapter 4 Ex 22
clc;
clear;
close;
x=poly(0,'x');
y=(2*x-180)/3; //equation 1
y=240-x; //equation 2
for x=1:200
if (2*x-180)/3==240-x
break
end
end
y=240-x;
printf("Arun got %d marks in English",y);
|
45109c7647b260847e9a8d48c5e787aa530c9678 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3871/CH1/EX1.10/Ex1_10.sce | fb8caa599ccee99e14ddbcffdafe89a74dccdb93 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 536 | sce | Ex1_10.sce | //===========================================================================
//chapter 1 example 10
clc;
clear all;
//variable declaration
E0 = 50; //internal voltage source in V
R0 = 100; //resitance in kΩ
r = 99; //accuracy in %
//calculations
//Em = E0/(1+(R0/RL))
//Em = E0*(r in %)
//E0/(1+(R0/RL)) = E0*(r in %)
Em = (E0*r)/(100);
x =E0/(Em);
y = x-1;
Rm = R0/(y); //resistance of voltage in kΩ
//result
mprintf("resistance of voltage = %3.2f kΩ",Rm);
|
fd36f605edf31d80ee0dcb6aea76bfba667dcd2b | 449d555969bfd7befe906877abab098c6e63a0e8 | /2777/CH3/EX3.1/Ex3_1.sce | 36f9aab52dfe9e116a2c0a2be05a6f928071b71b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 2,413 | sce | Ex3_1.sce |
// ELECTRICAL MACHINES
// R.K.Srivastava
// First Impression 2011
// CENGAGE LEARNING INDIA PVT. LTD
// CHAPTER : 3 : TRANSFORMERS
// EXAMPLE : 3.1
clear ; clc ; close ; // Clear the work space and console
// GIVEN DATA
Z = (0.05 + 0.05 * %i) * 100; // Transmission line parameters (impedance) in Ohms (multiplied by 100 because distance of the Transmission line is 100km)
R = 0.05 * 100; // Transmission line Resistance in Ohms (multiplied by 100 because distance of the Transmission line is 100km)
V1 = 220; // Terminal voltage in Volts
V2 = 1 * 10 ^ 3; // Terminal volatge from Generator side in Volts
P = 20 * 10 ^ 3; // Power in Watts
// CACULATIONS
I1 = P/V1; // Line current for 220V in Amphere
I2 = P/V2; // Line current for 1kV in Amphere
I1Z = Z*I1; // Voltage drop due to I1 in Volts
I2Z = Z*I2; // Voltage drop due to I2 in Volts
Loss1 = (I1 ^ 2) * R * 10 ^ -3; // Line loss for I1 in kW
Loss2 = (I2 ^ 2) * R * 10 ^ -3; // Line loss for I2 in kW
Vg1 = V1 + I1Z; // Input Voltages on Generator Terminal in Volts
Vg2 = V2 + I2Z; // Input Voltages on Generator Terminal in Volts
// DISPLAY RESULTS
disp("EXAMPLE : 3.1 : SOLUTION :-") ;
printf("\n (a.1) Voltage drop due to I1 , I1Z = % .2f+j%.2f V \n ",real(I1Z),imag(I1Z));
printf("\n (a.2) Voltage drop due to I2 , I2Z = % .f+j%.f V \n",real(I2Z),imag(I2Z));
printf("\n (b.1) Line loss for I1 , Loss1 = %.2f kW \n ",Loss1);
printf("\n (b.2) Line loss for I2 , Loss2 = % .2f kW \n",Loss2);
printf("\n (c.1) Input Voltages on Generator Terminal from a load terminal , Vg1 = %.2f+j%.2f = %.2f V \n ",real(Vg1),imag(Vg1),abs(Vg1));
printf("\n (c.2) Input Voltages on Generator Terminal from a Generating Station , Vg2 = % .f+j%.f = %.2f V \n",real(Vg2),imag(Vg2),abs(Vg2));
printf("\n\n [ TEXT BOOK SOLUTION IS PRINTED WRONGLY ( I verified by manual calculation )]\n" );
printf("\n WRONGLY PRINTED ANSWERS ARE :- (a) I1Z = (450.45)+j(450.45)V instead of (454.55)+j(454.55) V\n" );
printf("\n (b) Vg1 = (670.45)+j(450.45) = 807.72 V instead of % .2f+j%.2f = %.2f V \n",real(Vg1),imag(Vg1),abs(Vg1) );
|
1e40314ea705a89c87b32536dc6c7e9436b16444 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1535/CH2/EX2.4/Ch02Ex4.sci | 389798653eb709ea17e191ae044fee59762fbd58 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 347 | sci | Ch02Ex4.sci | // Scilab Code Ex2.4 : Page-47 (2010)
p = 60; // Power rating of bulb, watt
d = 0.5; // Distance from the blb, m
P = p/(4*%pi*d^2); // Value of Poynting vector, watt per metre square
printf("\nThe value of Poynting vector = %4.1f watt per metre square", P);
// Result
// The value of Poynting vector = 19.1 watt per metre square |
e67ccabe845dd3f102d21272c9fc151eabf70ffb | 449d555969bfd7befe906877abab098c6e63a0e8 | /534/CH6/EX6.6/6_6_Molar_flux_Plate.sce | 8557b8d8f8551e45739aa7881a23e6dba95d75c0 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,330 | sce | 6_6_Molar_flux_Plate.sce | clear;
clc;
printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 6.6 Page 379 \n'); //Example 6.6
// Water vapor conc and flux associated with the same location on larger surface of the same shape
//Operating Conditions
v = 100; //[m/s] Velocity of air
Tsurr = 20+273; //[K] Surrounding Air Temperature
L1 = 1; //[m] solid length
Ts = 80+273; //[K] Surface Temp
qx = 10000; //[W/m^2] heat flux at a point x
Txy = 60+273; //[K] Temp in boundary layer above the point
//Table A.4 Air Properties at T = 323K
v = 18.2*10^-6; //[m^2/s] Viscosity
k = 28*10^-3; //[W/m.K] Conductivity
Pr = 0.7; //Prandttl Number
//Table A.6 Saturated Water Vapor at T = 323K
pasat = 0.082; //[kg/m^3]
Ma = 18; //[kg/kmol] Molecular mass of water vapor
//Table A.8 Water Vapor-air at T = 323K
Dab = .26*10^-4; //[m^2/s]
//Case 1
Casurr = 0;
Cas = pasat/Ma; //[kmol/m^3] Molar conc of saturated water vapor at surface
Caxy = Cas + (Casurr - Cas)*(Txy - Ts)/(Tsurr - Ts);
//Case 2
L2 = 2;
hm = L1/L2*Dab/k*qx/(Ts-Tsurr);
Na = hm * (Cas - Casurr);
printf("\n (a) Water vapor Concentration above the point = %.4f Kmol/m^3 \n (b) Molar flux to a larger surface = %.2e Kmol/s.m^2", Caxy,Na);
//END |
dc62d4589aab286f66bfbd86851736921bc165a7 | 4ed576b765859807d6c29665521e0697d6f9bae7 | /archive/03/ex3.4.sce | 5718f6f18d0e49a859a50bebf07d215497bbd7a0 | [] | no_license | sbednarz/scilab | 96b9182730fa48d11f27840fc197d151adb01e2c | 28f81c58bc4972eeb41f403cb157fb989e809f41 | refs/heads/master | 2021-07-11T04:42:04.289126 | 2021-05-17T20:55:19 | 2021-05-17T20:55:19 | 100,467,366 | 3 | 1 | null | 2020-06-19T06:49:18 | 2017-08-16T08:37:06 | Scilab | UTF-8 | Scilab | false | false | 1,042 | sce | ex3.4.sce | // ex3.4 updated
// A + B <=> 2C + D
// A0
// B0
// K
// at eq
// A, B, C, D
function eq = model(x)
A = x(1)
B = x(2)
C = x(3)
D = x(4)
eq(1) = A + 0.5*C - A0 // A balance
eq(2) = B + D - B0 // B balance
eq(3) = 0.5*C - D // relations between C and D (stoichiometry)
eq(4) = C**2*D - K*A*B // K = (C^2*D)/(A*B)
endfunction
A0 = 1 // mol/L
B0 = 1 // mol/L
K = 1e5
guess = [1; 1; 1; 1]
x = fsolve(guess, model)
A = x(1)
B = x(2)
C = x(3)
D = x(4)
printf("Case: A0=%.1f mol/L B0=%.1f mol/L K1=%.1f\n", A0,B0,K)
printf("A=%.2f\n", A)
printf("B=%.2f\n", B)
printf("C=%.2f\n", C)
printf("D=%.2f\n", D)
A0 = 1 // mol/L
B0 = 1 // mol/L
K = 10
guess = [1; 1; 1; 1]
x = fsolve(guess, model)
A = x(1)
B = x(2)
C = x(3)
D = x(4)
printf("Case: A0=%.1f mol/L B0=%.1f mol/L K1=%.1f\n", A0,B0,K)
printf("A=%.2f\n", A)
printf("B=%.2f\n", B)
printf("C=%.2f\n", C)
printf("D=%.2f\n", D)
//Results:
//A=0.34
//B=0.34
//C=1.32
//D=0.66
// How to check the results?
// A+B+0.5*C+D
// A0+B0
|
66027724863578f0bd0d38a5971a1917460ecd81 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3446/CH2/EX2.12/Ex2_12.sce | 95856202402ede2d3d7eaa3270c2e7e1b50aebd4 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 511 | sce | Ex2_12.sce | // Exa 2.12
// To calculate number of mobile subscribers supported for the given system.
clc;
clear all;
channels=50;
blocking=0.02;
HT=120;//average holding time inm sec
BHcall=1.2;// in calls per hour
//solution
//Refering Erlang B table in appendix A, For 50 channels at 2% blocking, the offered load=40.26 Erlangs.
A=40.26;
B=A*(1-0.02); //carried load
Avgtraffic_user=BHcall*HT/3600;
No_users=B/Avgtraffic_user;
printf('NO of mobile subscribers supported are %d \n',round(No_users));
|
33041f00dead35b6476ca64f95a896995ef3b124 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2213/CH7/EX7.10/ex_7_10.sce | 640c63bbda930b6b7b5c95db4cbb213dc9eea1b9 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 461 | sce | ex_7_10.sce | //Example 7.10: Current and time taken
clc;
clear;
close;
//given data :
V=36;// speed in km/h
W=120;// in tonne
G=2;// in per cent
r=2*9.81;// in N/tonne
Ft=(98.1*W*G)+(W*r);
e=88/100; // efficiency of motors and gear
VL=1500;//line voltage in volts
Po=(Ft*V)/3600;
Pi=Po/e;
I=(Pi*1000)/VL;
bc=((98.1*(2+(0.1*2)))/(277.8*1.1));//in kmphps
tt=V/bc;//in seconds
disp(I,"current required in amperes is")
disp(round(tt),"time taken to come to rest in seconds is")
|
5b7f37f9dc5afc8895259d43b5aae986e8131e87 | 449d555969bfd7befe906877abab098c6e63a0e8 | /671/CH2/EX2.22/2_22.sce | 1137cf227b5b2259693e1e8938697c50a62068e6 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 198 | sce | 2_22.sce | function p=parallel(r1,r2)
p=r1*r2/(r1+r2)
endfunction
//Thevenin Equivalent
I=(32-8)/30
Voc=32-20*I
Ro=parallel(20,10)
disp(Ro,Voc)
//Norton Equivalent
Isc=32/20+8/10
disp(Ro,Isc) |
1ca6d9581b86696840f9f4c8edb079707de9c4c4 | 26a768bbd9ab2f5e38d26240a0dd5e9bc2713009 | /models/NETLIST/c432.tst | f4bd9cd73d866f1fc25da3cb4d64bb51244e25ad | [] | no_license | dmironov/AGMToolsProject | 90918d1caddd12dc3d716a5e308810f4c7d2a333 | a6ae4bc57496e29ba0104a351a13d59f3c1e4900 | refs/heads/master | 2021-01-17T12:20:32.116568 | 2014-05-13T19:14:55 | 2014-05-13T19:14:55 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 40,570 | tst | c432.tst |
.VECTORS 50
.PATTERNS
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.FAULTS
&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&0&0&&&&&0&0&&&&&0&0&&&&&0&0&&&&&0&0&&&&&0&0&&&&&&&0&0&&&&&&&0&0&&&&&&&0&0&&&&&&&&&&&&&11&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&0&0&&&&&0&0&&&&&0&0&&&&&0&0&&&&&&&0&0&&&&&&&0&0&&&&&&&0&0&&&&&&&0&0&&&&&&&0&0&&&&&&&&&11&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&11&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&000&&&&&&&&&&&&&&&&&&&&&&&&&&0&&&&&&&&&&&&&&&&&&&&
.COVERAGE
928 / 974 = 95.277207 %
|
27447eb40d957f5e05c4a0d0283fbc3df4ffbae5 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3773/CH23/EX23.4/Ex23_4.sce | 3cd78765e49c183e0a2a03f6dda6fed36b64e106 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 600 | sce | Ex23_4.sce | //Chapter 23: Ground Wave Propagation
//Example 23-2.3
clc;
//Variable Initialization
f1 = 0.3 //Frequency (MHz)
f2 = 1 //Frequency (MHz)
f3 = 3 //Frequency (MHz)
sigma = 4e-5 //Standard deviation of surface irregularities (unitless)
//Calculations
x1 = (18e3)*sigma/f1 //Parameter x for f1 (unitless)
x2 = (18e3)*sigma/f2 //Parameter x for f2 (unitless)
x3 = (18e3)*sigma/f3 //Parameter x for f3 (unitless)
//Result
mprintf( "The parameter x for 0.3MHz is %.1f", x1)
mprintf( "\nThe parameter x for 1MHz is %.2f", x2)
mprintf( "\nThe parameter x for 3MHz is %.2f", x3)
|
78d970773cbebd296094f35fa9469b4dc1110f96 | b29e9715ab76b6f89609c32edd36f81a0dcf6a39 | /ketpic2escifiles6/Paramoncrv.sci | 836617871bdf9817165f4ae1550ad60d6e1e6997 | [] | no_license | ketpic/ketcindy-scilab-support | e1646488aa840f86c198818ea518c24a66b71f81 | 3df21192d25809ce980cd036a5ef9f97b53aa918 | refs/heads/master | 2021-05-11T11:40:49.725978 | 2018-01-16T14:02:21 | 2018-01-16T14:02:21 | 117,643,554 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 543 | sci | Paramoncrv.sci | // 09.10.03
function Out=Paramoncrv(varargin)
Eps=10^(-8);
Nargs=length(varargin);
P=varargin(1);
Gdata=varargin(Nargs);
if size(P,1)>1
Tmp=P; P=Gdata; Gdata=Tmp;
end;
if Nargs==2
Tmp=Nearestpt(P,Gdata);
Out=Mixop(2,Tmp);
return;
end;
N=varargin(2);
PtL=Gdata;
if N==size(PtL,1)
Out=N;
else
Pa=PtL(N,:);
Pb=PtL(N+1,:);
V=Pb-Pa;
W=P-Pa;
D2=norm(V)^2;
if D2<Eps
Out=0;
return;
end;
S=Dotprod(V,W)/D2;
S=min(max(S,0),1);
Out=N+S;
end
endfunction
|
6027f0a6a65e9f643c8870537561ec4932b3569c | 449d555969bfd7befe906877abab098c6e63a0e8 | /2165/CH7/EX7.6/7_6.sce | b58144830f9fa9054340842206682708f7e7f304 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 434 | sce | 7_6.sce | clc
//initialisation of variables
a=30//percent
b=20//percent
c=8//percent
h=42//percent
t1=20//degree C
g=0.24//in
t2=320//degree c
M=7.654//lb/lb fuel
A=3*M//lb/lb fuel
W=0.08+0.04//lb
T=A+0.8//lb
w1=0.72+0.3//lb
w=T-w1//lb
d=w*0.24*(t2-b)//C H U/lb fuel
H=1.02*(639+0.49*220-t1)//C H U/lb fuel
//CALCULATIONS
T1=d+H//C H U/lb fuel
//RESULTS
printf('total heat carried away by flue gases=% f C H U/lb fuel',T1)
|
bf4538c7261817266bfb9e5537a0cfc6ec3bd7bb | 449d555969bfd7befe906877abab098c6e63a0e8 | /3886/CH14/EX14.9/14_9.sce | 58ff6af69240d2cfbd369cdd985df06178cbec9b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 667 | sce | 14_9.sce | //passenger observing rain drops
//refer fig. 14.17
//Let the true velocity of rain be v kmph at a true angle theta with vertical
//Taking the direction of train as x and that of vertical downward as y
//Velocity components of train are
//v1x=v*sind(theta)
//v1y=v*cosd(theta)
//when the velocity of train was 36 kmph
v2x=36
v2y=0
//alpha is the direction of relative velocity and is given as 30 degree and when the velocity of train is 54 kmph alpha=45 degree thus
//v*cosd(theta)=v*sind(theta)-54
//v*sind(theta)=-11.402
//solving we get
v=sqrt(4407.43) //kmph
theta=asind(-(11.402)/(66.388))
printf("\nv=%.3f kmph\ntheta=%.2f degree",v,theta)
|
0d3f94f61384279cbd9d9477f41426c7eae8f6be | 39c201c777151f939341e8f8150242bcde5a111b | /CH4/EX4.5/example5.sce | be54fdf51ccef8b1a483abb41447eec5f2f82851 | [] | no_license | nidhimj22/Scilab_Project- | 925a5883384736e79f1e600535461c6c9f06de40 | 4a9d1db96787ba0ea4e996349523a0b84bdacae3 | refs/heads/master | 2021-01-20T05:49:48.811688 | 2014-02-06T10:03:52 | 2014-02-06T10:03:52 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 912 | sce | example5.sce | // calculating of peak input and output voltage value
// Electronic Principles
// By Albert Malvino , David Bates
// Seventh Edition
// The McGraw-Hill Companies
// Example 4-5, page 102
clear;clc; close;
// Given data
Vrms=120;// in volts
// 10:1 step down transformer
// Calculations
Vp1=Vrms/0.707;// peak primary voltage in volts
Vp2=Vp1/10;// peak secondary voltage in volts
disp("Volts",Vp1,"Peak primary voltage =")
disp("Volts",Vp2,"Peak primary voltage=")
// with a bridge rectifier ,the secondary voltage is used as the input to the rectifier.
Vpout1=Vp2;// ideally
Vpout2=Vp2-1.4;// to a second approximation
disp("Volts",Vpout1,"Peak primary voltage =")
disp("Volts",Vpout2,"Peak primary voltage=")
// Result
// peak primary voltage is 170 volts
// peak secondary voltage is 17 volts
// ideally peak output voltage is 17 volts
// with second approximation peak output voltage is 15.6 volts.
|
f07169af6baff46e5f0a39c2a319006f4a62a359 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2789/CH4/EX4.2/Ex4_2.sce | 3d3f4c55407cccfedbfc3b054f05310b204f6942 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 607 | sce | Ex4_2.sce | clear;
clc;
//page no. 105
h = 100;//ft
d1 = 5;//in
d2 = 8;//in
h1 = 60;// ft
h2 = 10;//ft
h3 = 40;//ft
h4 = 102;//ft
H = 300;//ft
theta = 30;//degrees
gam = 0.43;
V5 = sqrt(h*2*32.2);
Q = V5*0.25*%pi*(d1/12)^2;
V1 = (d1/12)^4 *h;
V2 = h*(d1/d2)^4;
p1 = (h1-V1)*gam;
p2 = -(h2-V2)*2.04*gam;
p3 = (h3-V1)*gam;
p4 = (h4-V1)*gam;
V6 = V5*cos(theta*%pi/180);
e = H - (V6^2)/(2*32.2);
printf('p1 = %.1f psi\n p2 = %.1f in. of Hg vacuum\n p3 = %.1f psi\n p4 = %.1f psi',p1,p2,p3,p4);
printf('\n elevation = %.1f ft',e);
//there are small errors in the answer given in textbook
|
7135beadc083162eb3351c98fc133cec22ce6840 | 8b9a8f57e173e7b4f3e0697bb8fa4391992830c1 | /Assignment_8/Assignment 8_Team13/SumToN.tst | 1723f50cba92f2ba073154270da29d53d27d564d | [] | no_license | AtharvaC1511/ComputerSystemDesign | 9bdcdd5178e55f21c9c23cc105feb6f1cdf47cf6 | e3d9bdcb961aa6d2f13c58532bb89908dda70d3b | refs/heads/main | 2023-06-25T19:04:51.971391 | 2021-07-19T14:24:00 | 2021-07-19T14:24:00 | 387,486,807 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 958 | tst | SumToN.tst | load Computer.hdl,
output-file SumToN.out,
output-list RAM64[16]%D1.16.1 RAM64[17]%D1.16.1 RAM64[18]%D1.16.1 ;
ROM32K load SumToN.hack,
//in all the below test cases final value of i will be n+1 thus the memory location 17 will have value n+1 for each test case
//n=100 is stored at location 16,sum of elements from 1 to 100 stored at location 18
set RAM64[16] 100,
repeat 2000 {
tick, tock,
}
output;
set reset 1,
tick,tock;
//n=63 is stored at location 16,sum of elements from 1 to 63 stored at location 18
set reset 0,
set RAM64[16] 63,
repeat 2000 {
tick, tock,
}output;
set reset 1,
tick,tock;
//n=20 is stored at location 16,sum of elements from 1 to 20 stored at location 18
set reset 0,
set RAM64[16] 20,
repeat 2000 {
tick, tock,
}output;
set reset 1,
tick,tock;
//n=77 is stored at location 16,sum of elements from 1 to 77 stored at location 18
set reset 0,
set RAM64[16] 77,
repeat 2000 {
tick, tock,
}output;
|
1d301cda671e769c1461f5b6f3b2bae971d984ac | 449d555969bfd7befe906877abab098c6e63a0e8 | /1109/CH4/EX4.5/4_5.sce | 564889939831878431d611fc08e9dc93167b0630 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 535 | sce | 4_5.sce | clear;
clc;
f=50;r=5*(10^-3);x=.5;y=3;z=4.5;t=6;s=5;
r1=0.7788*r; //r1=GMR
Dab=round(sqrt((y^2)+(x^2))*1000)/1000;
Dab1=round(sqrt((y^2)+(s^2))*1000)/1000;
Daa=sqrt((t^2)+(z^2));
Dab2=Dab;
Dab3=Dab1;
dab=round(nthroot((Dab1*Dab3*Dab*Dab2),4)*100)/100;
dca=fix(nthroot((t*t*z*z),4)*100)/100;
ds1=nthroot((r1*r1*7.5*7.5),4);
ds2=nthroot((r1*r1*5.5*5.5),4);
ds3=ds1;
ds=round(nthroot((ds1*ds2*ds3),3)*1000)/1000;
La=fix(0.4606*log10(dca/ds)*100)/100;
X=2*3*f*La*10^-3;
printf("Inductive reactance = %f ohm/km/phase",X);
|
3394a628e8e784237a28d72e0bc3c2b9224207fe | 449d555969bfd7befe906877abab098c6e63a0e8 | /213/CH10/EX10.5/10_5.sce | 008730c570d670d0cca6a06adb4be3afa4f3a3be | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 586 | sce | 10_5.sce | //To find the torque required
clc
//Given:
D=150/1000 //m
ps=2*10^6 //N/m^2
d0=50,p=6 //mm
mu=0.12
//Solution:
//Calculating the load on the valve
W=ps*%pi/4*D^2 //N
//Calculating the mean diameter of the screw
d=(d0-p/2)/1000 //m
//Calculating the helix angle
alpha=atan(p/(%pi*d*1000))
//Calculating the force required to turn the handle
phi=atan(mu) //Limiting angle of friction, radians
P=W*tan(alpha+phi) //N
//Calculating the torque required to turn the handle
T=P*d/2 //N-m
//Results:
printf("\n\n The torque required to turn the handle, T = %.1f N-m.\n\n",T) |
06ffe5d6ee46ed3de5101153e188b03af4e2e630 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3760/CH4/EX4.49/Ex4_49.sce | 2dc47cbcea85c8a3532b56aa7ed686774dbe166f | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 602 | sce | Ex4_49.sce | clc;
v=250; // rated voltage of dc shunt motor
ra=0.5; // armature resistance
rf=250; // field resistance
n1=600; // speed of motor
i=21; // current drawn by motor when n=600 rpm
re=250; // additional resistance in field circuit
if1=v/rf; // field current
ia=i-if1; // armature current
Ea1=v-ia*ra; // counter EMF at n=600 rpm
if2=v/(rf+re); // field current after addition of external resistance
ia2=ia*(if1/if2); // armature current after addition of external resistance
Ea2=v-ia2*ra; // counter EMF at new speed
n2=(n1*Ea2*if1)/(Ea1*if2);
printf('New speed of motor is %f rpm',n2);
|
f9471b4b2f7fa614294a0dfc38f5e02a95b68b51 | b23687e2eb02bcb6d0f581b7975f42c496faeda1 | /PulseAndLinePractice.sce | 9e84b54c84208eb3ebc130d6a6d9441cbb7a455f | [
"MIT"
] | permissive | harvishj/Scilab | bd3fbd3e679eb07aa088ff2bab40d491c6499770 | 9daada512f42ea6f52199a34d6b18e64b107af94 | refs/heads/master | 2021-07-14T15:06:03.621923 | 2020-10-05T06:35:43 | 2020-10-05T06:35:43 | 213,328,984 | 1 | 3 | MIT | 2020-10-05T06:35:44 | 2019-10-07T08:16:52 | Scilab | UTF-8 | Scilab | false | false | 475 | sce | PulseAndLinePractice.sce | clc;
clear;
clf;
//This function plots a line and pulse together
//Pulse cannot be seen because grap is topping at 1
function y = pulse(st,et,value,dt);
t = st : dt : et;
y = value * ones(1,length(t));
endfunction
function y = line(m,c,st,et,dt)
t = st:dt:et;
y = m*t + c;
endfunction
dt = 0.001;
x2 = line(1,0,0,1,dt);
x3 = pulse(1,2,1,dt);
plot([x2 x3]);
xlabel("T", "fontsize", 3);
ylabel("X", "fontsize", 3);
title("Line + Pulse", "fontsize", 3);
|
ea880d17f2dcf7130cc96ced936199a0cd9a13b4 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3131/CH6/EX6.8/6_8.sce | 8fae3275dd1f1a48d8cd205f4c23b26e1bd8a165 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,059 | sce | 6_8.sce | clear all; clc;
disp("Ex 6_8")
//Initilization of variables
F_AE=[0.577,0.577,-0.577] //matrix notation
P=[0,-4,0]// in kN
//At joint A:
//Calculations
//Applying summation of forces along all axes and equating them to zero
//We get three equations and we solve for each component
//Solving by matrix method to obtain solution
A=[0.577,0,0;0.577,0,1;-0.577,-1,0]
B=[0;4;0]
C=inv(A)
D=C*B
F_AE=D(1)
F_AC=D(2)
F_AB=D(3)
//Result
printf('\n The values are \n')
printf('\n F_AE=%0.0f \n F_AC=%0.0f \n F_AB=%0.0f (T)\n All values are in kN',F_AE,F_AC,F_AB)
//At joint B:
//Calculations
//Applying summation of forces along all axes and equating them to zero
//We get three equations and we solve for each component
//Solving by matrix method to obtain solution
a1=45
a=a1*%pi/180
A=[-cos(a),0.707,0;sin(a),0,0;0,-0.707,1]
B=[0;4;-2]
C=inv(A)
D=C*B
RB=D(1)
F_BE=D(2)
F_BD=D(3)
//Result
printf('\n The values are \n')
printf('\n RB=%0.2f (T)\n F_BE=%0.2f (T)\n F_BD=%0.0f (C)\n All values are in kN',RB,F_BE,F_BD)
disp(" ")
disp("F_DE = F_DC = F_CE = 0")
|
b3a8b2efb66bd827af3767b10515c891eff17371 | 4533c11d75f955d8350d45606af92ca064d2e319 | /differentialEvolution/scilab-scripts/EstimationVoltageBenchmark1LinearCa,t+K,p+L.sce | c2000fcf9d2fc3f91f626d48c6a83aa46ed51680 | [] | no_license | lois76/ParamEstimationDE | 0066c5a18042637b97bf989e77f2ce04ba283b12 | ab3911174450a4ec9976a108885cf8e7afc62b3d | refs/heads/master | 2022-05-21T04:49:51.662762 | 2022-03-21T13:15:38 | 2022-03-21T13:15:38 | 167,556,538 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 6,489 | sce | EstimationVoltageBenchmark1LinearCa,t+K,p+L.sce | ////////////////////////////////////////////////
//// Définition du benchmark HH de type 1-1 ////
////////////////////////////////////////////////
bc=[0.2
0.4
0.3
104
-18.4
-63.1
-23.8
-37.2
-25.1
18.4
-27.8
16.3
0.6
5
2.3
0.3
0.2
0.1
0.04]
gCa=bc(1); gK=bc(2); gL=bc(3);
ECa=bc(4); EK=bc(5); EL=bc(6);
V12mCa=bc(7); V12hCa=bc(8); V12mK=bc(9);
kmCa=bc(10); khCa=bc(11); kmK=bc(12);
tmCa=bc(13); thCa=bc(14); tmK=bc(15);
mCa0=bc(16); hCa0=bc(17); mK0=bc(18);
C=bc(19);
function y=xinf(V,V12,k)
y=1/(1+exp((V12-V)/k));
endfunction
function [Hdot]=HHbench(t,x,pa)
Hdot=zeros(4,1);
Hdot(1)=(1/C)*(-gCa*x(2)*x(3)*(x(1)-ECa) - gK*x(4)*(x(1)-EK) - gL*(x(1)-EL) + I)
Hdot(2)=(xinf(x(1),V12mCa,kmCa)-x(2))/tmCa
Hdot(3)=(xinf(x(1),V12hCa,khCa)-x(3))/thCa
Hdot(4)=(xinf(x(1),V12mK,kmK)-x(4))/tmK
endfunction
/// Stimulations appliquées au neurone ///
stim=[-15:5:35];
/// Construction des solutions ///
t0=0;
t=linspace(0,50,12500);
t=t';
a=zeros(length(t),12);
a(:,1)=t;
for i=1:11
I=stim(i);
x=ode([-40;mCa0;hCa0;mK0],t0,t,HHbench);
x1=x(1,:);
// plot2d(t,x1,3)
x1=x1';
a(:,i+1)=x1;
end
//write('/home/loisse/Documents/FichierScilab/Article 2/CurrentClampBenchmarkLinear1Ca,t+K,p+L.txt', a)
/////////////////////////////////////////////////////////////////////////////////
/////////////// Paramètres déterminés à partir de HillVallEA //////////////
/////////////////////////////////////////////////////////////////////////////////
par=[0.1884399252
0.3997391869
0.3000432948
111.3463577783
-18.4677751478
-63.1143564258
-23.7160547632
-36.5674442162
-25.1121544013
18.5576322182
-27.4170773985
16.2617936149]
/////////////////////////////////////////////////////////////
/////////////// Fonction coût algorithme //////////////
/////////////////////////////////////////////////////////////
function [Hdot]=HH12(t,x,pa)
Hdot=zeros(4,1);
Hdot(1)=(1/pa(7))*(-par(1)*x(2)*x(3)*(x(1)-par(4)) - par(2)*x(4)*(x(1)-par(5)) - par(3)*(x(1)-par(6)) + I)
Hdot(2)=(xinf(x(1),par(7),par(10))-x(2))/pa(1)
Hdot(3)=(xinf(x(1),par(8),par(11))-x(3))/pa(2)
Hdot(4)=(xinf(x(1),par(9),par(12))-x(4))/pa(3)
endfunction
//Fonction coût
function y=fct(pa)
c=0;
condini = [-40; pa(4); pa(5); pa(6)]
for i=1:11
I=stim(i);
x=ode(condini,t0,t,HH12);
V=x(1,:);
for k=1:length(t)
c=c+(V(k)-a(k,i+1))*(V(k)-a(k,i+1))
end
end
y=c/length(t);
endfunction
//////////////////////////////////////
//// Parameter estimation ////
//////////////////////////////////////
function [bM, valBest]=simulation(NP,itermax,F,CR)
D=7;
pop=zeros(D,NP);
///////////////////////////////////////////////////////
//// Vecteurs de contraintes borne minimum/maximum ////
///////////////////////////////////////////////////////
Xmin=[0.0001 0.0001 0.0001 0.001 0.001 0.001 0.001];
Xmax=[15 15 15 0.999 0.999 0.999 10];
/////////////////////////////////////////
//// Initialisation de ma population ////
/////////////////////////////////////////
for j=1:NP
for i=1:D
pop(i,j)=Xmin(i)+(Xmax(i)-Xmin(i))*rand();
end
end
//////////////////////////////////////////////////////////////
//// Évaluation du meilleur individu après initialisation ////
//////////////////////////////////////////////////////////////
val=zeros(NP,1); // tableau avec le coût de chacun des individus
for j=1:NP
val(j)=fct(pop(:,j))
end
disp(val)
bestIndex=1;
for b=2:NP
if val(b)<val(bestIndex) then bestIndex=b; end
end
costVec(1)=val(bestIndex);
////////////////////////
//// Étape suivante ////
////////////////////////
iter=1; // nombre d'itération
U=zeros(D,NP); // Vecteur intermédiaire perturbé (mutation + crossover)
tempval=0;
while iter<itermax
for j=1:NP
// ======= Construction de la matrice U = variation différentielle + crossover =======
// ========= Tirage aléatoire de 3 entiers distincts r1, r2 et r3 et différents de j ========
r1=j; r2=j; r3=j;
while (r1==r2 | r1==r3 | r2==r3 | r1==j | r2==j | r3==j)
r1=floor(1+NP*rand());
r2=floor(1+NP*rand());
r3=floor(1+NP*rand());
end
// ======== Variation différentielle =======
V=pop(:,r1) + F*(pop(:,r2)-pop(:,r3));
if V(1)<=Xmin(1) then V(1)=Xmin(1);
elseif V(1)>Xmax(1) then V(1)=Xmax(1);
end
if V(2)<=Xmin(2) then V(2)=Xmin(2);
elseif V(2)>Xmax(2) then V(2)=Xmax(2);
end
if V(3)<=Xmin(3) then V(3)=Xmin(3);
elseif V(3)>Xmax(3) then V(3)=Xmax(3);
end
if V(4)<=Xmin(4) then V(4)=Xmin(4);
elseif V(4)>Xmax(4) then V(4)=Xmax(4);
end
if V(5)<=Xmin(5) then V(5)=Xmin(5);
elseif V(5)>Xmax(5) then V(5)=Xmax(5);
end
if V(6)<=Xmin(6) then V(6)=Xmin(6);
elseif V(6)>Xmax(6) then V(6)=Xmax(6);
end
if V(7)<=Xmin(7) then V(7)=Xmin(7);
elseif V(7)>Xmax(7) then V(7)=Xmax(7);
end
// ======== Crossover ========
for i=1:D
if rand()<CR then
U(i,j)=V(i);
else
U(i,j)=pop(i,j);
end
end
end // fin for j=1:NP
// ======== Sélection ========
for j=1:NP
tempval=fct(U(:,j));
if tempval<=val(j) then
pop(:,j) = U(:,j);
val(j) = tempval;
end
end
disp(iter)
iter = iter + 1;
bestIndex=1;
for b=2:NP
if val(b)<val(bestIndex) then bestIndex=b; end
end
// costVec(iter)=val(bestIndex);
end //fin de la boucle while
// Détermination de l'indice du meilleur individu
bestIndex=1;
for b=2:NP
if val(b)<val(bestIndex) then bestIndex=b; end
end
// disp(bestIndex);
// Sauvegarde du meilleur individu
bM = [];
bM = pop(:,bestIndex);
valBest=val(bestIndex);
disp(val);
disp(bM);
disp(val(bestIndex));
endfunction
|
44849a2085b687e7f671763ba87ea5b1b9cfbb49 | 449d555969bfd7befe906877abab098c6e63a0e8 | /63/CH10/EX10.2/Exa10_2.sci | c50c5f9837c5197e227fc0c074474b9d088a1916 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 589 | sci | Exa10_2.sci | //Determine the lowest frequency and also the mode closest to the dominant mode for the waveguide in previous example
m1 = 0;
n1 = 1;
a1 = 0.051;
b1 = 0.024;
fc1 = (1.5e+8)*sqrt((m1/a1)^2 + (n1/b1)^2);
disp(fc1, 'Cutoff Frequency of the TE10 mode is (in Hz)')
m2 = 2;
n2 = 0;
a2 = 0.051;
b2 = 0.024;
fc2 = (1.5e+8)*sqrt((m2/a2)^2 + (n2/b2)^2);
disp(fc2, 'Cutoff Frequency of the TE20 mode is (in Hz)')
m3 = 0;
n3 = 2;
a3 = 0.051;
b3 = 0.024;
fc3 = (1.5e+8)*sqrt((m3/a3)^2 + (n3/b3)^2);
disp(fc1, 'Cutoff Frequency of the TE02 mode is (in Hz)')
|
d4340700a7d6eaf12971b19c07251e9309bc52fa | 449d555969bfd7befe906877abab098c6e63a0e8 | /1022/CH3/EX3.1/3_1.sce | 510c018748339807746b44203b62513187a80d02 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 271 | sce | 3_1.sce | clc
//initialisation of variables
T1= -3 //degrees
T2= 650 //Rankine
T3= 650 //Rankine
//CALCULATIONS
t1= (9/5)*T1+32
t2= T2-459.67
t21= (5/9)*(t2-32)
t3= t21+273.15
//RESULTS
printf ('T= %.2f F',t1)
printf (' \n T= %.2f C',t21)
printf (' \n T= %.2f K',t3)
|
6b0da94d50eb4fca1b04c1c2b0ad9c953d958f38 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2210/CH5/EX5.1/5_1.sce | aeb560ba15f31666bb7c88d6a5f0cb71c3153f49 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 496 | sce | 5_1.sce | //Chapter 5, Problem 1
clc
R=3 //resistance in ohm
L=20*10^-9 //inductance in henry
f0=500e6 //frequency in hertz
//calculation
Z=R
C=(1/(2*%pi*f0*sqrt(L)))^2
Q=2*%pi*f0*L/R
B=f0/Q
printf("(a) Impedance at resonance = %d ohm\n\n",Z)
printf("(b) Value of series capacitor = %.3f pF\n\n",C*10^12)
printf("(c) Q of the circuit at resonance = %.3f\n\n",Q)
printf("(d) 3 dB bandwidth of the circuit = %.3f Mhz\n\n",B/10^6)
|
69ed0958a742137359cbe83951b3e3c68474d5a8 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3401/CH1/EX1.3/Ex1_3.sce | 14f637b58f3cd52c9c309b33f49b9108fb4b7a77 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 132 | sce | Ex1_3.sce | clc
a1=5*10^-8// a=5A = 5*10^-8cm
n=2// number of atoms is 2
d=n/(a1*a1*2^0.5)
disp(d,"the value of d in atoms per cm^2 is")
|
8dfb55190fe34605cc9f5d8fb1ab1b6574dc122a | 449d555969bfd7befe906877abab098c6e63a0e8 | /1271/CH14/EX14.28/example14_28.sce | b7f7ac74d1f1e02b5f9749d92177651bc7f0a431 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 881 | sce | example14_28.sce | clc
// Given that
lambda = 0.2e-10 // wavelength of x-ray in meter
theta = 45 // scattered angle in degree
h = 6.62e-34 // Planck constant in J-sec
c = 3e8 // speed of light in m/sec
e = 1.6e-19 // charge on an electron in C
m = 9.1e-31 // mass of an electron in kg
// Sample Problem 28 on page no. 14.32
printf("\n # PROBLEM 28 # \n")
printf("Standard formula used \n ")
printf(" delta_lambda = (h / (m * c) * (1 - cos(theta))) \n E = h*c*(1/lambda1 - 1/lambda2)\n")
delta_lambda = (h * (1 - cosd(theta))) / (m * c)
E = (h * c) * ((1 / lambda) - (1 / (lambda + delta_lambda)))
theta_ = 180 // for maximum
delta_lambda_ = (h * (1 - cosd(theta_))) / (m * c)
lambda_ = lambda + delta_lambda_
E_k = h*c*(1/lambda - 1/lambda_)
printf("\n Wavelength of x-ray is %f A.\n Maximum kinetic energy %e J.",lambda_ * 1e10,E_k)
|
e60b9dfad0bef54fe6a9c7c151fc33bb76c16186 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2045/CH4/EX4.25/Ex4_25.sce | 64f9cfd1c9bfb49cc6e7dcbb0c4a2cd28f356fd2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 297 | sce | Ex4_25.sce | //example 25
clear
colcur=100*10^-3;//ampere
ouresi=20;//ohm
r=200;//ohm
r1=100;//ohm
vcc=15;//volt
basvol=((r1)/(r+r1))*vcc;
em1res=basvol/colcur;
vce=vcc-(ouresi+em1res)*colcur;
disp("vce = "+string((vce))+"volt");
disp("emitter resistance = "+string((em1res))+"ohm");
|
8333d77e3ba922df8c3b6dca266ea3253322a3b0 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1217/CH4/EX4.4/Exa4_4.sce | 22c73c485b1ccf9feacedfe15a60e389791ff8cc | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 602 | sce | Exa4_4.sce | //Exa 4.4
clc;
clear;
close;
disp("The output can be obtained using superposition theorem, as");
disp("Vo=Voa+Vob");
// case (i) when Vb=0;
disp("case (i) when Vb=0 the given circuit becomes an inverting amplifier to provide an output as");
disp("Voa=-100Kohm*Va/R1=-2*Va ");
disp("It gives R1=50 Kohm");
// case (ii) when Va=0;
disp("case (ii) when Va=0 the given circuit becomes an non-inverting amplifier to provide an output as");
disp("Vob=(1+100Kohm/R1)*V1 where V1=R3*Vb/(R2+R3)");
disp("Vob=(1+100Kohm/R1)*V1*(R3*Vb/(R2+R3))=Vb ")
disp("Putting R1=R2=50 Kohm, we get R3=25 Kohm"); |
3951642ac9400456229a51246ee127ee1ab1e154 | 1988df91caa448a35bbf274a6d2698fe434571b1 | /tst/nd/str.tst | 6a9a6aece0f5af129e1ef0884d5209743d149c3f | [] | no_license | namin/GETFOL | bd60e9a2d9f0905c50ff5c0cff4b6bf57a2049e2 | bf42caf61799578eb82e9f17b3342bc2ee638a22 | refs/heads/master | 2021-10-25T08:08:20.142137 | 2021-10-22T16:16:40 | 2021-10-22T16:16:40 | 204,234,318 | 4 | 1 | null | 2019-08-25T02:05:54 | 2019-08-25T02:05:54 | null | UTF-8 | Scilab | false | false | 4,202 | tst | str.tst | COMMENT|**********************************************************|
COMMENT| |
COMMENT| This is a file of tests for structural inference rules |
COMMENT| "weaken", "contract" and "cut" |
COMMENT| |
COMMENT|**********************************************************|
COMMENT|**********************************************************|
COMMENT|**** Definition of language and additional facts ****|
COMMENT|**********************************************************|
declare sentconst A B C D;
assume A A A A B B C D ;
AXIOM aa : A;
AXIOM bb : B;
AXIOM cc : C;
andi 7 8;
COMMENT|**********************************************************|
COMMENT|**** test for a correct use of structural commands ****|
COMMENT|**********************************************************|
COMMENT| ************ WEAKEN *********** |
COMMENT |use of weaken with assumptions|
COMMENT | (facts 10 to 16) |
weaken 1 by 1;
weaken 9 by 4;
weaken 9 by 7;
weaken 9 by 1 2 3 4 5 6 6 5 5;
weaken 1 by 4;
weaken 1 by 5;
weaken 1 by 2 3 4 5 5 5 1 1 6 7 8;
COMMENT |use of weaken with axioms|
COMMENT | (facts 17 to 18) |
weaken 5 by aa;
weaken bb by 1;
COMMENT |use of weaken with assumptions, axioms and facts|
COMMENT | (facts 19 to 22) |
weaken 1 by 9;
weaken 1 by 9 9;
weaken 9 by 9;
weaken aa by 5 5 9 9 bb bb;
COMMENT | ********** CONTRACT ********** |
COMMENT |various uses of contract|
COMMENT | (facts 23 to 28) |
ctc 13 by 1 1 1 1;
ctc 13 by 1 2 3 4 5 6;
ctc 13 by 1 2 3 4 5 6 7 8;
ctc 13 by 8 7 6;
ctc 1 by 1;
ctc 13 by 1 5;
COMMENT | ************* CUT ********** |
COMMENT |uses of cut with no dependencies to keep |
COMMENT | (facts 29 to 63) |
cut aa 13;
cut bb 13;
cut 1 13;
cut 5 13;
cut 8 13;
cut 9 13;
cut 13 13;
cut 16 13;
cut aa 16;
cut bb 16;
cut 1 16;
cut 5 16;
cut 8 16;
cut 9 16;
cut 13 16;
cut 16 16;
cut aa aa;
cut aa bb;
cut 1 aa ;
cut 16 aa;
cut aa 1;
cut bb 1;
cut 1 1;
cut 5 1;
cut 8 1;
cut 9 1;
cut 13 1;
cut 16 1;
cut 15 11;
cut 11 15;
cut 1 11;
cut aa 11;
cut 2 15;
cut 2 23;
cut bb 23;
COMMENT |uses of cut with some dependencies to keep |
COMMENT | (facts 64 to 71) |
cut aa 16 keep 1;
cut aa 16 keep 1 1;
cut aa 16 keep 4 3 2 1;
cut aa 16 keep 4 2 1 1 2 4 1;
cut aa 16 keep 1 2 3 4;
cut 1 16 keep 1;
cut 1 16 keep 1 2;
cut 1 16 keep 1 1 ;
COMMENT|**********************************************************|
COMMENT|**** tests for possible input errors ****|
COMMENT|**********************************************************|
COMMENT| Here is a list of uncorrect commands with relative error messages |
COMMENT | ************* CUT ********** |
COMMENT| cut aa 16 keep 1 16;|
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| cut aa 16 keep 1 aa; |
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| cut aa 16 keep 1 1 2 aa 16 1; |
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| cut aa 11 keep 1 6 16; |
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| cut aa 11 keep 1 5 6; |
COMMENT| The fact must depend on all the dependencies to keep |
COMMENT| cut aa 11 keep 5 6; |
COMMENT| The fact must depend on all the dependencies to keep |
COMMENT| cut aa 11 keep 6; |
COMMENT| The fact must depend on all the dependencies to keep |
COMMENT| cut aa 16 keep 1 2 8; |
COMMENT| The assumptions to keep must have the same wff of the fact |
COMMENT| cut aa 16 keep 1 5; |
COMMENT| The assumptions to keep must have the same wff of the fact |
COMMENT | ********* CONTRACT ********* |
COMMENT| ctc 1 by 5; |
COMMENT| The fact must depend on all the dependencies to keep |
COMMENT| ctc 13 by 14; |
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| ctc 1 by 5 14; |
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| ctc aa by 1; |
COMMENT| The fact must depend on all the dependencies to keep |
COMMENT| ctc 1 by aa; |
COMMENT| All the dependencies to keep must be assumptions |
COMMENT| ctc 1 by bb; |
COMMENT| All the dependencies to keep must be assumptions |
|
2ed758b72a0e9b968452ee6b2adee4866dd725b8 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2144/CH8/EX8.2/ex8_2.sce | 82a3829adb7b53248365eb43b5ab8e88c9aab2dd | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 715 | sce | ex8_2.sce | // Exa 8.2
clc;
clear;
close;
// Given data
CH4 = 77;// in %
C2H6 = 22.5;//in %
H1 = 40.08;// heat liberated by CH4 in MJ/nm^3
H2 = 69.52;// heat liberated by C2H6 in MJ/nm^3
HCV = (CH4*H1+C2H6*H2)/100;// Higher calorific value in kJ/kg
disp(HCV,"The higher calorific value in MJ/nm^3")
V1= CH4*2/100;// volume of water due to combustion of CH4 in m^3
V2= C2H6*3/100;// volume of water due to combustion of C2H6 in m^3
V= V1+V2;// total volume in m^3
ms= 18/22.41;// in kg
LCV= HCV-ms*V*2.242;// in MJ/nm^3
disp(LCV,"The lower calorific value in MJ/nm^3")
disp("The word nm^3 means that cubic metre at normal temperature and pressure")
// Note: The calculated value in the book is not accurate
|
05ab739142fa37613c97003dab76d7bf7fc368a5 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2384/CH4/EX4.17/ex4_17.sce | 978f0b7be593a79419f931b66fa56066f9d8070e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 766 | sce | ex4_17.sce | // Exa 4.17
clc;
clear;
close;
format('v',6)
// Given data
C = 50;// in µF
C = C * 10^-6;// in F
R = 20;// in ohm
L = 0.05;// in H
V = 200;// in V
f = 50;// in Hz
X_C = 1/(2*%pi*f*C);// in ohm
Z1 = X_C;// in ohm
I1 = V/X_C;// in A
X_L = 2*%pi*f*L;// in ohm
Z2 = sqrt( (R^2) + (X_L^2) );// in ohm
I2 = V/Z2;// in A
// tan(phi2) = X_L/R;
phi2 = atand(X_L/R);// in degree
phi1 = 90;// in degree
I_cos_phi = I1*cosd(phi1) + I2*cosd(phi2);// in A
I_sin_phi = I1*sind(phi1) - I2*sind(phi2);// in A
phi= atand(I_sin_phi/I_cos_phi);// in °
I= sqrt(I_cos_phi^2+I_sin_phi^2);// in A
P= V*I*cosd(phi);// in W
disp(I,"The line current in A is : ")
disp("The power factor is : "+string(cosd(phi))+" lag");
disp(P,"The power consumed in W is : ")
|
1903021419c4bc85db147371181e7229534ecade | 449d555969bfd7befe906877abab098c6e63a0e8 | /608/CH33/EX33.05/33_05.sce | 8d8e8648994d0a6d8ed4f07231396cb5324d1509 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,442 | sce | 33_05.sce | //Problem 33.05:Determine the Th´evenin equivalent circuit with respect to terminals AB of the circuit shown in Figure 33.27. Hence determine (a) the magnitude of the current flowing in a (3.75 + i11) ohm impedance connected across terminals AB, and (b) the magnitude of the p.d. across the( 3.75 + i11)ohm impedance.
//initializing the variables:
rv = 24; // in volts
thetav = 0; // in degrees
R1 = -1*%i*3; // in ohm
R2 = 4; // in ohm
R3 = %i*3; // in ohm
//calculation:
//voltage
V = rv*cos(thetav*%pi/180) + %i*rv*sin(thetav*%pi/180)
//Current I1 shown in Figure 33.27 is given by
I1 = V/(R1 + R2 + R3)
//The Th´evenin equivalent voltage, i.e., the open-circuit voltage across terminals AB, is given by
E = I1*(R2 + R3)
//When the voltage source is removed, the impedance z ‘looking in’ at AB is given by
z = (R2 + R3)*R1/(R1 + R2 + R3)
//Thus the Th´evenin equivalent circuit is as shown in Figure 33.28.
//when (3.75 + i11) ohm impedance connected across terminals AB, the current I flowing in the impedance is given by
R = 3.75 + %i*11; // in ohms
I = E/(R + z)
Imag = (real(I)^2 + imag(I)^2)^0.5
//the p.d. across the( 3.75 + i11)ohm impedance.
VR = I*R
VRmag = (real(VR)^2 + imag(VR)^2)^0.5
printf("\n\n Result \n\n")
printf("\n (a) the current I flowing in the (3.75 + i11) impedance is given by is %.0f A",Imag)
printf("\n (b) the magnitude of the p.d. across the impedance is %.1f V",VRmag) |
a085bab4dac825527ad2f06e0b07379f7b401449 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1370/CH5/EX5.19/exp5_19.sce | b785aeb4060515b0410369e5fb0da5e71dc7b760 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 753 | sce | exp5_19.sce | //Example 5.19
clc
disp("P = 4, f = 50 Hz, T_sh = 159 Nm, s = 5% = 0.05")
ns=(120*50)/4
format(5)
disp(ns,"N_s(in r.p.m) = 120f/P =")
n=1500*(1-0.05)
disp(n,"Therefore, N(in r.p.m) = N_s*(1-s_m) =")
po=159*((2*%pi*1425)/60)
format(11)
disp(po,"Therefore, P_out(in W) = T_sh * omega =")
pm=23726.8785+500
disp(pm,"Therefore, P_m(in W) = P_out + Friction and windage loss =")
disp("(a) P_2:P_c:P_m is 1:s:1-s")
p2=24226.8785/(1-0.05)
disp("Therefore, P_2/P_m = 1/1-s")
disp(p2,"Therefore, P_2(in W) = ...Rotor input")
pi=25501.9774+1000
disp(pi,"(b) P_in(in W) = P_2 + Stator losses = ...Motor input")
eta=(23726.8785/26501.9774)*100
format(7)
disp(eta,"(e) %eta(in percentage) = P_out/P_in * 100 =")
|
452774da4f0298ad13726422d22cba8ca24afdf6 | 717ddeb7e700373742c617a95e25a2376565112c | /3428/CH23/EX14.23.17/Ex14_23_17.sce | 97bdadbf226b7b8db67f7b223c789fc4c09b4510 | [] | no_license | appucrossroads/Scilab-TBC-Uploads | b7ce9a8665d6253926fa8cc0989cda3c0db8e63d | 1d1c6f68fe7afb15ea12fd38492ec171491f8ce7 | refs/heads/master | 2021-01-22T04:15:15.512674 | 2017-09-19T11:51:56 | 2017-09-19T11:51:56 | 92,444,732 | 0 | 0 | null | 2017-05-25T21:09:20 | 2017-05-25T21:09:19 | null | UTF-8 | Scilab | false | false | 674 | sce | Ex14_23_17.sce | //Section-14,Example-1,Page no.-PC.112
//To calculate the pH values of the following.
clc;
C_HCl=0.001
C_1=C_HCl //Since HCl is a strong acid,[H3O+]=[HCl]
pH_1=-log10(C_1)
disp(pH_1,'pH of 0.001 M HCl')
C_NaOH=0.0001
C_2=C_NaOH //Since NaOH is a strong base so [OH-]=[NaOH]
pOH=-log10(C_2)
pH_2=14-pOH
disp(pH_2,'pH of 0.0001 M NaOH')
C_BaOH2=0.001
C_31=2*C_BaOH2 // [OH-]=2*[Ba(OH)2]
k_w=10^-14
C_32=k_w/(C_31)
pH_3=-log10(C_32)
disp(pH_3,'pH of 0.001 M Ba(OH)2')
M=(0.049/98)/(200/1000) //Molarity of H_2SO_4 solution
C_4=2*M //[H_3O+]
pH_4=-log10(C_4)
disp(pH_4,'pH of the given solution')
|
ace4555ae405805d82bb108249b09840916257ea | 04e4dfecf86c47abbad9ad721bcbc552300a8834 | /Sine_Test/sine_test.sci | 0b09a9d0291b6771345b77a03893ac6b1258b84d | [] | no_license | rupakrokade/scilab_local_codes | 702f741a5cadc6da56e428f7379971818238ff22 | 4de8383487def7f18a1f19906397ed4eaf42480e | refs/heads/master | 2021-01-19T06:58:47.689324 | 2015-10-24T11:55:34 | 2015-10-24T11:55:34 | 26,806,574 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 169 | sci | sine_test.sci | mode(0)
function temp = sine_test(heat,fan)
temp = comm(heat,fan);
plotting([heat fan temp],[0 0 20 0],[100 100 40 1000])
m=m+1;
endfunction |
ca6c3bbdb0ff86ccb779234e99eb43feccae949d | e9d5f5cf984c905c31f197577d633705e835780a | /data_reconciliation/linear/scilab/functions/hampel/hampel_linear_functions.sci | 410889c71cf1418d152905aeb52f293f6e854638 | [] | no_license | faiz-hub/dr-ged-benchmarks | 1ad57a69ed90fe7595c006efdc262d703e22d6c0 | 98b250db9e9f09d42b3413551ce7a346dd99400c | refs/heads/master | 2021-05-18T23:12:18.631904 | 2020-03-30T21:12:16 | 2020-03-30T21:12:16 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 5,627 | sci | hampel_linear_functions.sci | // Data Reconciliation Benchmark Problems From Lietrature Review
// Author: Edson Cordeiro do Valle
// Contact - edsoncv@{gmail.com}{vrtech.com.br}
// Skype: edson.cv
// aux functions to sum of absolute errors
// it is necessary to install the "diffcode" package using ATOMS in Scilab
// Smooth functions according to Gopal and Biegler
// AICHE Journal 45(7) 1535-1547 - July 1999
// Hampel function, according to Ozyurt and Pike - Comp. & Chem. Eng.
// 28, p. 381-402, (2004)
function f = objfun ( x )
// e1 = (xm-x)./(var.^(0.5));
e1 = (xm(red)-x(red))./(var(red).^(0.5));
// smoothing functions
// for sigmoidal function (Eq. 24 from paper)
// abs_error = sig1=1./alpha_smooth*log(2+exp(alpha_smooth*e1)+exp(-alpha_smooth*e1));
// for interior point function (Eq 25 from paper)
abs_error = (e1.^2 + beta_smooth.^2).^0.5;
// sigmoidal, but based in max operator property (Eq 28 from paper)
// this one leads to a small error when e1 = 0
// abs_error = e1 + beta_smooth*log(1+exp(-2*alpha_smooth*e1));
// the logic of the Hampel robust estimator is long.
// TODO IMPROVE THIS LOGIC
// from -a to a
th1 = (tanh(100*(e1 + ones_a)) + ones_xm)./2;
th2 = -(tanh(100*(e1 - ones_a)) - ones_xm)./2;
//
hap1 = 0.5*e1.^2;
//
hap11 = hap1.*(th1 + th2 - ones_xm) ;
// // from a < abs(e1) < b
//
th3 = (tanh(100*(e1 - ones_a)) + ones_xm)/2;
th4 = -(tanh(100*(e1 - ones_b)) - ones_xm)/2;
th3n = (tanh(100*(-e1 - ones_a)) + ones_xm)/2;
th4n = -(tanh(100*(-e1 - ones_b)) - ones_xm)/2;
//
hap2a=a*abs_error - 0.5*ones_a.^2;
hap22 = hap2a.*(th3+th4-1) + hap2a.*(th3n+th4n - ones_xm);
// from b < abs(e1) < c
th5 = (tanh(100*(e1 - ones_b)) + ones_xm)/2;
th6 = -(tanh(100*(e1 - ones_c)) - ones_xm)/2;
th5n = (tanh(100*(-e1 - ones_b)) + ones_xm)/2;
th6n = -(tanh(100*(-e1 - ones_c)) - ones_xm)/2;
//pause
hap3 = ones_a.*ones_b - 0.5*ones_a.^2 + 0.5.*(ones_a.^2).*(c-b).*(1-((c*ones_xm-abs(e1))/(c-b)).^2);
hap33 = hap3.*(th5 + th6 - ones_xm) + hap3.*(th5n + th6n - ones_xm);
// from c < abs(e1)
th7 = (tanh(100*(e1 - ones_c)) + ones_xm)/2;
th7n = (tanh(100*(-e1 - ones_c)) + ones_xm)/2;
hap4 = ones_a.*ones_b - 0.5*ones_a.^2 + 0.5*(ones_a.^2).*(ones_c-ones_b); // > c
hap44 = hap4.*th7 + hap4.*th7n;
f = sum(hap11 + hap22+ hap33 + hap44);
// f = (hap11 + hap22+ hap33 + hap44);
// f = sum(hap11);
endfunction
// gradient of the objetive function
function gf = gradf ( x )
// in the future we can express this function analytically
// For Hampel, we are using the finite difference formula due to a limitation of
// diffcode when providing the exact differences of tanh
// gf = diffcode_jacobian(objfun,x)';
// gf = derivative(objfun, x, 1.0e-2, order = 4)';
gf = derivative(objfun, x, order = 4)';
endfunction
function H = hessf ( x )
// For the robust functions, the lagrangean of the objective function is not constant
// as in weigthed least squares.
// in the future we can express this function analytically
// For Hampel, we are using the finite difference formula due to a limitation of
// diffcode when providing the exact differences of tanh
// H = diffcode_hessian(objfun,x);
//[J,H] = derivative(objfun, x, H_form = "hypermat");
[J,H] = derivative(objfun, x, H_form = "hypermat");
//[J,H] = derivative(objfun, x, 1.0e-2, order =2, H_form = "hypermat");
endfunction
////////////////////////////////////////////////////////////////////////
// Define constraints, gradient and Hessian matrix
// The constraints function, Jacobian and Hessian
// First the vector of inequalyties and equalyties
// We generallu don't use inequalyties in classical DR problems
// but it is up to the user use it or not
function c = confun(x)
if nnzjac_ineq <> 0 then
c1 = res_ineq(x);
c =[ c1; res_eq(x)];
else
c =[ res_eq(x)']
end
endfunction
function c = res_ineq(x)
c = [];
endfunction
function c = res_eq(x)
c = jac*(x);
endfunction
function y=dg(x)
if nnzjac_ineq <> 0 then
y = [dg_ineq(x);dg_eq(x)];
else
y = [dg_eq(x)];
end
endfunction
function y = dg_ineq(x)
if nnzjac_ineq <> 0 then
ytmp = diffcode_jacobian(res_ineq,x)';
for i = 1: nnzjac_ineq;
y(i)=ytmp(sparse_dg(i,1),sparse_dg(i,2));
end
else
y =[];
end
endfunction
function y = dg_eq(x)
// we use the jacobian here, if use wants to use a different Jacobian , comment and
// uncomment the lines approprieatelly
// ytmp = diffcode_jacobian(res_eq,x)';
for i = nnzjac_ineq + 1: nnzjac_ineq + nnzjac_eq;
// y(i - nnzjac_ineq)=ytmp(sparse_dg(i-nnzjac_ineq,1),sparse_dg(i-nnzjac_ineq,2));
y(i - nnzjac_ineq)=jac(sparse_dg(i-nnzjac_ineq,1),sparse_dg(i-nnzjac_ineq,2));
end
endfunction
// The Hessian of the Lagrangian
function y = dh(x,lambda,obj_weight)
ysum = zeros(nv,nv);
if obj_weight <> 0 then
yobj = obj_weight * hessf ( x );
else
yobj = zeros(nv,nv);
end
if sum(abs(lambda)) <> 0 & n_non_lin_eq > 2 then
// the hessian of the constraints
ytmpconstr = diffcode_hessian(confun,x);
for i = 1: nc;
if lambda(i) <> 0 then
ysum = ysum + lambda(i)*ytmpconstr(:,:,i);
end
end
else
ysum = zeros(nv,nv);
end
ysumall = ysum + yobj;
for i = 1: nnz_hess
y(i) = ysumall(sparse_dh(i,1),sparse_dh(i,2));
end
endfunction
|
87d5bab2c029ae0018215ecdc0637b1e07c4d66c | d7f10561a1d1ce291b1af4c70250f1264db9365e | /assets/analysenum2017/TP2_exo5.sce | 30b4072b7a0292a701d8841fbb6bef1bdc7c4e12 | [] | no_license | bbrrck/bbrrck.github.io | cc6b4d2507123f25b034974a04ffe4363a436299 | 663daaeac711bf7fa9f1be451d76a778c4b9ae88 | refs/heads/master | 2023-04-27T04:56:12.905318 | 2021-05-26T07:43:13 | 2021-05-26T07:43:13 | 49,649,785 | 3 | 0 | null | 2023-04-12T05:36:53 | 2016-01-14T13:45:01 | HTML | UTF-8 | Scilab | false | false | 1,588 | sce | TP2_exo5.sce | // ----------------------------------------------------------------
// Analyse numerique 2017
// Pagora, Grenoble INP, 1ere annee
// TP2 : Approximation de fonctions
// Exo5 : Interpolation
// ----------------------------------------------------------------
// Cours : Valerie Perrier <Valerie.Perrier@univ-grenoble-alpes.fr>
// TD,TP : Tibor Stanko <tibor.stanko@inria.fr>
// ----------------------------------------------------------------
// derniere modif : 24 mars 2017
// ----------------------------------------------------------------
// P = LAGRANGE(X,Y)
// Calculer le polynome d’interpolation de Lagrange associe a l'abscisse X et valeurs Y.
// source: http://bit.ly/2ndAg7q
function[P]=Lagrange(X,Y)
n = length(X);
x = poly(0,"x");
P = 0;
for i = 1:n,
L = 1;
for j = [1:i-1,i+1:n],
L = L * (x-X(j))/(X(i)-X(j));
end
P = P + L*Y(i);
end
endfunction
//------------------------------------------------
// Y = RUNGE(X)
// Evaluer la fonction de Runge pour X.
function[Y]=Runge(X)
Y = 1+25*X.^2;
Y = 1 ./ Y;
endfunction
//------------------------------------------------
// on efface la figure
clf;
// on definit le nombre d'echantillons
n = 5;
// points a interpoler : abscisse uniforme de l'interval [-1,1] avec n points
xp = linspace(-1,1,n);
// TODO :
// 1. calculez yp, les valeurs de fonction de Runge pour xp
// 2. calculez P(x), le polynome qui interpole (xp,yp)
// 3. plot, points (xp,yp)
// 4. plot, polynome P(x)
// 5. testez pour n=3,5,7,9,... Vous pouvez faire ca dans une boucle: for n=3:2:9, ... end
|
6582c5b6ce7ebfadfa519bc33c2f4e82dfdd4b55 | 8fcfcd367a32514b5e303f6e380b412bae2771e4 | /PPP3LabGraph.sce | 98f70282280f76cae979196c371599224bd055f2 | [] | no_license | NadyaLE/ApplicationPackages | 2356a8a71d7a605d890337b3034107ae45c268f6 | e3ad240f9142a62061a23f30df2430b8768f0d51 | refs/heads/master | 2023-04-08T18:23:55.540644 | 2021-04-20T06:08:00 | 2021-04-20T06:08:00 | 359,702,318 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,109 | sce | PPP3LabGraph.sce | function [result] = countLang (X, currElem, pLag)
result = 1;
for i=1:length(X)
if currElem <> i then
result = result * (pLag - X(i)) / (X(currElem) - X(i));
end
end
endfunction
function [result] = interL (Y, arrLag)
result = 0;
for i = 1:length(arrLag)
result = result + Y(i) * arrLag(i);
end
endfunction
X = [3,3.5,4,4.5];
Y = [1.0986123,1.2527630,1.3862944,1.5040774];
Var = 3.2;
arrLag = zeros(1, 4);
pLag = poly(0, 'x');
for i = 1:length(X)
arrLag(i) = countLang(X, i, pLag);
end
resultInterplnLagrangeFunc = interL (Y, arrLag);
disp(resultInterplnLagrangeFunc);
printf("\n");
arrLag = zeros(1, 4);
for i = 1:length(X)
arrLag(i) = countLang (X, i, Var);
if (i == 1) then printf("\n");
end
end
printf("\n");
resultInterplnLagrange = interL (Y, arrLag);
printf("result = %s, при x = %s", string(resultInterplnLagrange), string(Var));
lagstr ="y=" + pol2str(resultInterplnLagrangeFunc)
f = figure()
printf("\n%s", lagstr)
deff("[y]=f(x)",lagstr);
fplot2d(2.5:0.1:5,f,rect=[2.5, -5, 5, 5],axesflag=5);
plot2d(X, Y,-2)
|
561f49bcc1cc0319cd89900a274da6fd4b5e2a22 | 449d555969bfd7befe906877abab098c6e63a0e8 | /964/CH31/EX31.1/31_1.sce | be47cb8d875c7747e104cd36d9a6e5f1ba49ffaa | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 588 | sce | 31_1.sce | clc;
clear;
//d2T/dx2=-10; equation to be solved
//T(0,t)=40; boundary condition
//T(10,t)=200; boundary condition
//f(x)=10; uniform heat source
//we assume a solution T=a*X^2 + b*x +c
//differentiating twice we get d2T/dx2=2*a
a=-10/2;
//using first boundary condition
c=40;
//using second boundary condtion
b=66;
//hence final solution T=-5*x^2 + 66*x + 40
function T=f(x)
T=-5*x^2 + 66*x + 40
endfunction
count=1;
for i=0:0.1:11
T(count)=f(i);
count=count+1;
end
x=0:0.1:11
plot(x,T)
xtitle("Temperature(T) vs distance(x)","x (cm)","T (units)")
|
6ceda7eea175240714fbe310912139efe76c2b27 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1754/CH2/EX2.5/Exa2_5.sce | 31ca2ac2b3e395bff63cb5babfb39c96dcbfad47 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 266 | sce | Exa2_5.sce | //Exa 2.5
clc;
clear;
close;
//Given data
Ileakage=12.5;//in uA
ICBO=12.5;//in uA
IE=2;//in mA
IC=1.97;//in mA
//Formula : IC=alfa*IE+ICBO
alfa=(IC-ICBO/10^3)/IE;//unitless
disp(alfa,"Current Gain : ");
IB=IE-IC;//in mA
disp(IB,"Base current in mA : "); |
48d24a705b99df95d9818b20feb1289b6849abff | 449d555969bfd7befe906877abab098c6e63a0e8 | /2705/CH17/EX17.6/Ex17_6.sce | 7f34d54920835833c52a58b35684318c91b03d7e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 913 | sce | Ex17_6.sce | clear;
clc;
disp('Example 17.6');
// aim : To determine
// (a) the break power of engine
// (b) the fuel consumption of the engine
// (c) the brake thermal efficiency of the engine
// given values
d = 850*10^-3;// bore , [m]
L = 2200*10^-3;// stroke, [m]
PMb = 15;// BMEP of cylinder, [bar]
N = 95/60;// speed of engine, [rev/s]
sfc = .2;// specific fuel oil consumption, [kg/kWh]
CV = 43000;// calorific value of the fuel oil, [kJ/kg]
// solution
// (a)
A = %pi*d^2/4;// area, [m^2]
bp = PMb*L*A*N*8/10;// brake power,[MW]
mprintf('\n (a) The brake power is = %f MW\n',bp);
// (b)
FC = bp*sfc;// fuel consumption, [kg/h]
mprintf('\n (b) The fuel consumption is = %f tonne/h\n',FC);
// (c)
mf = FC/3600;// fuel used, [kg/s]
n_the = bp/(mf*CV);// brake thermal efficiency
mprintf('\n (c) The brake thermal efficiency is = %f percent\n',n_the*100);
// End
|
05c884956b409842da78cb180e1fcd3eb00b90aa | 449d555969bfd7befe906877abab098c6e63a0e8 | /3636/CH10/EX10.8/Ex10_8.sce | 69af183e1de686562ba7bbecf2a0094b16a220c2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 754 | sce | Ex10_8.sce | clc;
clear;
Na=10^18 //in cm^-3
Nd=10^17 //in cm^-3
myu_p=471 //in cm^2/Vs
myu_n=1417 //in cm^2/Vs
tau_p=10^-8 //in s
tau_n=10^-6 //in s
JL=40 //in mA/cm^2
A=10^-5 //in cm^2
R1=1000 //in ohm
e=1.6*10^-19 //in J
ni=1.45*10^10 //in cm^-3
Vt=0.02586 //constant for kT/e at 300K in V
V=0.1 //in V
n=10 //number of solar cells
//Calculation
//a)
Dp=Vt*myu_p //in cm^2/s
Dn=Vt*myu_n //in cm^2/s
Ln=sqrt(Dn*tau_n) //in cm
Lp=sqrt(Dp*tau_p) //in cm
Js=e*ni^2*((Dp/(Nd*Lp))+(Dn/(Na*Ln))) //in A/cm^2
Is=Js*10^-5 //in A
IF=Is*(exp(V/Vt)-1) //in A
//b)
IL=40*10^-8 //in A
I=IL-IF //in
X=((10^-3)/(I))*n
mprintf("a)Current= %.2e A\n",IF) //The answers vary due to round off error
mprintf("b)Total number of solar cells= %i",X)
|
be88fee913afde3b9a122236c55760782ef35aa0 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1646/CH6/EX6.3/Ch06Ex3.sce | 7cd64a469527f10f08165799a6556f27d7986d46 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 576 | sce | Ch06Ex3.sce | // Scilab Code Ex6.3: Page-370 (2011)
clc;clear;
d = 2.82e-010;....// Spacing of the rock-salt, m
n = 2;....// Order of diffraction
theta = %pi/2; // Angle of diffraction, radian
// Braggs equation for X-rays of wavelength lambda is n*lambda = 2*d*sin(theta), solving for lambda
lambda = 2*d*sin(theta)/n; // Wavelength of X-ray using Bragg's law, m
printf("\nThe longest wavelength that can be analysed by a rock-salt crystal = %4.2f angstrom", lambda/1e-010);
// Result
// The longest wavelength that can be analysed by a rock-salt crystal = 2.82 angstrom |
bafd09e8f5abfb52da2d43561ef9f71246f88e3b | abf775fd9be933cc27debaf5379a939479e8e789 | /normale.sci | 7a87afb30b32bd6bf8d8f0eec44d39de96da1cbe | [] | no_license | ece2lr/tp1 | 721bee4f8bc5a216d0668ebc7649f42b1858ef36 | 957ff893a0e184356f7c46993c5b95e6a862712e | refs/heads/master | 2021-06-29T00:30:26.131616 | 2017-09-19T05:54:18 | 2017-09-19T05:54:18 | 104,031,407 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 78 | sci | normale.sci | function y = gaussCR(x)
C = 1/sqrt(2*%pi)
y = C * exp(-x^2/2)
endfunction
|
12ad3c10dd88f050609ffbe423dedcee75babb69 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1994/CH10/EX10.11/Example10_11.sce | 040a2900d65a35e5a7fc5ca00639436e53a1eecd | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 204 | sce | Example10_11.sce | //Chapter-10,Example10_11,pg10_42
Tsh=190
P=8
f=50
fr=1.5
ML=700
s=fr/f
Ns=120*f/P
N=Ns*(1-s)
Po=Tsh*(2*%pi*N/60)
Pm=Po+ML
Pc=Pm*s/(1-s)
printf("rotor copper loss\n")
printf("Pc=%.3f W",Pc)
|
6a5704b375acfb87a480fb14115cb69fe1fad70d | f5bb8d58446077a551e4d9a6461a55255db523fe | /zero_de_funcoes/calcnum2.sce | caad45bfd1dbd65a4dda7748769dbea6105e6c54 | [] | no_license | appositum/numerical-calculus | 6be1a9990a1621c705af6ba5694cf8c7b891d06e | 7759e74ce9ce5c5826f96be7de84a2f7ecb97c91 | refs/heads/master | 2021-07-19T18:19:09.336819 | 2018-11-27T21:52:36 | 2018-11-27T21:52:36 | 143,060,426 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 554 | sce | calcnum2.sce | // questao1
function y=fa(x)
y = x.^(3) + 3.*x - 1
endfunction
function y=fb(x) // x1 = (-1,0); x2 = (1, 2)
y = x.^(2) - sin(x) - x
endfunction
function y=fc(x)
y = x.*log(x) - 3
endfunction
function y=fd(x)
y = x.^(2).*log(x) - 3
endfunction
function y=fe(x)
y = sqrt(x) - 5.*exp(-x)
endfunction
function y=ff(x)
y = 5.*log(x) + 0.4.*x - 2
endfunction
x = -4:0.05:5
plot(x, fb(x))
a = get("default_axes");
a.x_location = "origin";
a.y_location = "origin";
bissecao(fb, -1, 0, 10.^(-4))
|
de37d7fb2cf6f2b2eb41d83c854effa7a8f9f8ad | 8217f7986187902617ad1bf89cb789618a90dd0a | /source/2.5/tests/examples/apropos.man.tst | af1791cfcf27a50975360f8b2a8b8ec740ee914b | [
"LicenseRef-scancode-public-domain",
"LicenseRef-scancode-warranty-disclaimer"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 59 | tst | apropos.man.tst | clear;lines(0);
apropos '+'
apropos ode
apropos 'list of'
|
85fde40aea89c419afc12537b1f345f63f879263 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2438/CH8/EX8.12/Ex8_12.sce | 8d72a85d22702fe78e1c11892e7d0d9748c56e18 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 686 | sce | Ex8_12.sce | //===========================================================================
// chapter 8 example 12
clc;
clear;
// Variable declaration
Jd = 500; // current density A/m^2
p = 0.05 // resistivity in ohm-m
l = 100*10^-6 // travel length m
ue = 0.4; // electron mobility m^2/Vs
e = 1.6*10^-19; // charge of electron in coulombs
// Calculations
ne = 1/(p*e*ue); //iin per m^3
vd = Jd/(ne*e); //drift velocity in m/s
t = l/vd; //time teken in s
// result
mprintf('Drift velocity = %d m/s\n time = %e s',vd,t);
//=============================================================================
|
388da63f0177a6b28acb6fe1a828e5ec26772f43 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1997/CH11/EX11.46/example46.sce | 02e8bc1f6171e8d58edb98e9b8cab771d6982dfe | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 466 | sce | example46.sce | //Chapter-11 example 46
//=============================================================================
clc;
clear;
//Given data
Runamb = 300*10^3; // unambiguous range in m
Vo = 3*10^8; // Vel. of EM wave in m/s
//Calculations
PRF = Vo/(2*Runamb); // Pulse repetitive freq.
//Output
mprintf('Pulse repetitive frequency = %g Hz',PRF);
//==============================================================================
|
5e3a56bd3bf0063f3f7b18fb1dbf289366efab19 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1733/CH1/EX1.8/1_8.sce | 42a320659e28e43ace31c07561fdc23042f745c4 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 159 | sce | 1_8.sce | //1.8
clc;
disp('A negative gate current cannot turn off a thyristor. This is due to the reason that cathode region is much bigger in area than gate region') |
06ec21841288591338ee37c30808ac6b8fe7445c | 449d555969bfd7befe906877abab098c6e63a0e8 | /1460/CH9/EX9.4/9_4.sce | 62bdf7e79c8ce59ab89f11e81411a854275b110f | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 325 | sce | 9_4.sce | clc
//initialization of variables
disp("From steam tables")
ht1=218.12
ht3=1412.1
st3=1.6571
ht4=1134.6
ht5=925.8
ht6=69.7
//calculations
w=(ht1-ht6)/(ht4-ht6)
WbyJ=ht3-ht4+(1-w)*(ht4-ht5)
W=778*WbyJ
Q=ht3-ht1
eta=WbyJ/Q
//results
printf("Specific work = %d ft-lb/lbm",W)
printf("\n Efficiency = %.3f",eta)
|
5a69ea515628719c08901fdc9c4787d40a74fe00 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3537/CH1/EX1.32/Ex1_32.sce | 33b2dc8a76c16f91a836dc17eca45f55b1d9d65a | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 390 | sce | Ex1_32.sce | //Example 1_32
clc();
clear;
//To find the radius of curvature of the lens
lemda=5900 //units in angstroam
lemda=5900*10^-10 //units in meters
D=0.5 //units in centimeters
D=0.5*10^-2 //units in meters
n=10
R=D^2/(4*n*lemda)
printf("The radius of the curvature of lens is %.3f meters",R)
|
63de04342e579347f678ef584e199859e38ed987 | 449d555969bfd7befe906877abab098c6e63a0e8 | /995/CH3/EX3.5/Ex3_5.sce | a99cb2fc6a26f685f21880c7402fe55123a64836 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 143 | sce | Ex3_5.sce | //Ex:3.5
clc;
clear;
close;
I_in=5;//in mA
R_m=100;
I_m=1;
R_s=R_m*I_m/(I_in-1);
printf("Value of parallel shunt resistor = %d A",R_s); |
9500d0c0d1a12f6b82ab74d3d0f333d62906a0fe | 449d555969bfd7befe906877abab098c6e63a0e8 | /281/CH6/EX6.3/example6_3.sce | 359243172373aee291ccbf14854782f41ba9bdb3 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 697 | sce | example6_3.sce | disp('chapter 6 ex6.3')
disp('given')
disp("current souurce to be designed")
disp("constant output current=100mA")
Il=.1
disp("maximum load resistance=40ohms")
Rlmax=40
disp("available supply voltage=+/-12V")
Vcc=12
disp("for P MOSFET Vdsmax=100 Idmax=210mA Rdon=5")
Vdsmax=100
Idmax=0.210
Rdon=5
disp("Vdsmax=Vcc=12")
disp("Idmax=Il=100mA")
Vdsmax=Vcc
Idmax=Il
disp("Vlmax=Il*Rlmax")
Vlmax=Il*Rlmax
disp('volts',Vlmax)
disp("Vdsmin=(Id*Rdon)+1")
Vdsmin=(Il*Rdon)+1
disp('volts',Vdsmin)
disp("Vr1(max)=Vcc-Vlmax-Vdsmin")
Vrlmax=Vcc-Vlmax-Vdsmin
disp('volts',Vrlmax)
disp("R1=Vr1/Il")
R1=Vr1max/Il
disp('ohms',R1)
disp("use R1=56ohms std value")
R1=56
disp("Vr1=Il*R1")
Vr1=Il*R1
disp('volts',Vr1) |
4657c808d37ff31cba2a666bd848bf11ae79814f | 449d555969bfd7befe906877abab098c6e63a0e8 | /343/CH1/EX1.30/ex_30.sce | 88e1fefc10ef2fd454a14089af209f65b47b5437 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 529 | sce | ex_30.sce | R1=2; //Assigning values to parameters
R2=3;
R3=4;
R4=5;
R5=1;
A=[3,-3;9,12] //Matrix of I1,I2 by KVL equations
B=[2;4]
[I]=inv(A)*B // I matrix has I1 and I2 values
disp("Amperes",[I],"Current in 1 Ohm resistor:Row 1 and Column 1, Current in 3 Ohm resistor:Row 2,Column 1");
IR1=1-I(1,1);
IR3=1-I(1,1)-I(2,1);
IR4=I(1,1)+I(2,1)
disp("Amperes",IR1,"Current in 2 Ohm resistor");
disp("Amperes",IR3,"Current in 4 Ohm resistor");
disp("Amperes",IR4,"Current in 5 Ohm resistor"); |
a883d8206f7e4280ed9c57e8b7423a379e273a54 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1061/CH4/EX4.12/Ex4_12.sce | ad17b505466dfe8607c2d4b6a239e0714f8c076d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 388 | sce | Ex4_12.sce | //Ex:4.12
clc;
clear;
close;
y=1.35;// wavelength in um
d=5;// core diamater in um
a=0.75;// attenuation in dB/km
v=0.45;// bandwidth in GHz
Pb=4.4*10^-3*(d^2)*(y^2)*(a*v);// threshold optical power for sbs
Pr=5.9*10^-2*(d^2)*(y)*(a);// threshold optical power for sbr
Pbr=Pb/Pr;// the ratio of threshold power level
printf("The ratio of threshold power level=%f %%", Pbr*100); |
29cab17e2f180ee8439e8dbdb774958c92e91411 | 449d555969bfd7befe906877abab098c6e63a0e8 | /10/CH10/EX1/cha10_1.sce | 13304f41fd7179ef7b3d97f997160eb1a62b960f | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 295 | sce | cha10_1.sce | Ka=0.09;N=1000;
Ia=30;Ra=0.4;V=120;
RevEa=-90;
Ea=Ka*N
Vo=Ea+(Ia*Ra)
a=Vo*%pi
b=2*sqrt(2)*V
c=a/b
angle=acosd(c)
P=Vo*Ia
S=V*Ia
Pf=P/S
Vo1=RevEa+(Ia*Ra)
a=Vo1*%pi
b=2*sqrt(2)*V
c=a/b
Angle=acosd(c)
Pdc=Ea*Ia
Pr=Ia^2*Ra
Ps=Pdc-Pr
|
fe37bfeb9d64c2a89ae8fb83e6f69bcd712f6a24 | 089894a36ef33cb3d0f697541716c9b6cd8dcc43 | /NLP_Project/test/blog/bow/bow.9_7.tst | d8be3523b6a73d3f6dc7b704c7027a04ec9656c3 | [] | no_license | mandar15/NLP_Project | 3142cda82d49ba0ea30b580c46bdd0e0348fe3ec | 1dcb70a199a0f7ab8c72825bfd5b8146e75b7ec2 | refs/heads/master | 2020-05-20T13:36:05.842840 | 2013-07-31T06:53:59 | 2013-07-31T06:53:59 | 6,534,406 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 4,490 | tst | bow.9_7.tst | 9 7:0.5 33:1.0 66:0.25 136:1.0 157:1.0 281:0.5 426:1.0 1337:0.3333333333333333 1383:1.0
9 1:0.5 2:0.3333333333333333 7:0.5 66:0.25 94:1.0 150:0.25 233:0.2 453:1.0 772:1.0
9 4:0.07142857142857142 7:0.5 13:1.0 18:1.0 47:1.0 66:0.25 104:0.5 157:1.0 160:1.0 206:1.0 309:1.0 628:1.0 874:1.0 1080:0.1 1266:1.0
9 27:0.028985507246376812 107:0.25 263:1.0 281:0.5 340:1.0 443:1.0
9 4:0.07142857142857142 22:0.07142857142857142 27:0.028985507246376812 34:1.0 45:0.5 47:1.0 93:1.0 104:0.5 233:0.2 263:1.0 281:0.5 416:1.0 454:1.0 539:1.0 711:1.0 782:1.0 1121:1.0 1480:0.5
9 27:0.028985507246376812 143:1.0 237:1.0 281:0.5 421:1.0 454:1.0 585:0.3333333333333333 1100:1.0
9 27:0.028985507246376812 31:0.5 35:1.0 91:0.25 103:1.0 149:1.0 157:1.0 476:1.0
9 27:0.028985507246376812 31:0.5 35:1.0 45:0.5 66:0.25 149:1.0 233:0.2 929:1.0
9 3:0.25 27:0.043478260869565216 40:0.125 49:0.07692307692307693 66:0.5 87:1.0 91:0.5 107:0.5 143:1.0 224:1.0 869:1.0
9 27:0.014492753623188406
9 27:0.014492753623188406 103:1.0 104:0.5 509:1.0
9 27:0.014492753623188406 157:1.0 628:1.0 1264:1.0 1463:1.0
9 7:0.5 27:0.014492753623188406 66:0.25 838:1.0 1422:1.0
9 27:0.014492753623188406 66:0.25 89:0.5 508:1.0
9 4:0.07142857142857142 21:0.14285714285714285 27:0.014492753623188406 450:1.0 599:1.0 1071:1.0
9 27:0.014492753623188406 66:0.25 89:1.0 94:1.0 132:0.5 153:1.0 157:1.0 227:1.0 281:0.5 451:1.0 1080:0.1 1200:1.0
9 13:1.0 21:0.14285714285714285 27:0.014492753623188406 40:0.125 91:0.25 97:0.5 257:1.0 304:1.0 1519:1.0
9 2:0.6666666666666666 22:0.07142857142857142 70:0.2 72:0.3333333333333333 89:0.5 104:0.5 128:0.16666666666666666 233:0.2 251:1.0 264:0.16666666666666666 737:1.0 921:1.0 1322:1.0 1356:1.0
9 4:0.07142857142857142 7:0.5 11:1.0 21:0.14285714285714285 27:0.028985507246376812 31:0.5 32:1.0 107:0.25 477:0.3333333333333333 932:1.0 1289:1.0 1353:1.0 1563:1.0
9 4:0.07142857142857142 15:1.0 22:0.07142857142857142 27:0.014492753623188406 28:1.0 45:0.5 47:1.0 66:0.25 97:0.5 229:1.0 298:0.5 573:1.0 683:1.0 685:1.0 895:1.0
9 15:1.0 18:1.0 21:0.2857142857142857 66:0.25 72:0.3333333333333333 86:0.3333333333333333 91:0.25 93:1.0 104:0.5 130:1.0 172:0.5 279:1.0 374:1.0 900:1.0 1080:0.1 1121:1.0 1480:1.0 1595:1.0 1687:1.0
9 4:0.14285714285714285 15:1.0 21:0.14285714285714285 66:0.25 91:0.25 104:1.0 224:1.0 452:1.0 1112:1.0 1193:1.0 1236:1.0 1480:0.5
9 13:1.0 15:1.0 21:0.14285714285714285 22:0.07142857142857142 27:0.028985507246376812 34:1.0 40:0.125 66:0.5 97:0.5 104:0.5 107:0.25 233:0.2 403:1.0 539:1.0 628:1.0 650:1.0 711:1.0 715:1.0 736:1.0 1100:1.0 1112:1.0 1337:0.6666666666666666 1341:1.0 1519:1.0
9 1:0.5 7:0.5 15:1.0 22:0.07142857142857142 27:0.014492753623188406 90:1.0 150:0.25 318:1.0 974:1.0
9 1:0.5 4:0.14285714285714285 11:1.0 21:0.14285714285714285 27:0.028985507246376812 28:1.0 47:1.0 66:0.75 97:1.0 157:1.0 270:0.5 285:1.0 376:1.0 1080:0.1 1099:1.0
9 22:0.07142857142857142 27:0.014492753623188406 39:1.0 40:0.125 45:0.5 47:1.0 49:0.07692307692307693 107:0.25 114:1.0 132:0.5 229:1.0 269:1.0 477:0.3333333333333333 509:1.0 526:1.0 890:1.0 1066:1.0 1676:1.0
9 13:1.0 27:0.028985507246376812 28:1.0 93:1.0 97:0.5 104:0.5 233:0.2 244:1.0 281:0.5 452:1.0 477:0.6666666666666666 678:1.0 740:0.5 839:1.0
9 4:0.07142857142857142 22:0.07142857142857142 27:0.014492753623188406 45:0.5 66:0.5 70:0.2 97:0.5 104:0.5 107:0.25 301:1.0 599:1.0 1123:1.0 1307:1.0
9 224:1.0 257:1.0 290:1.0
9 34:1.0 35:1.0 311:0.5 1100:1.0
9 47:1.0 91:0.25 998:1.0 1118:1.0 1130:1.0
9 13:1.0 411:1.0 477:0.3333333333333333 740:0.5
9 21:0.14285714285714285 27:0.028985507246376812 104:0.5 224:1.0 233:0.2 244:1.0 290:1.0 340:2.0 477:0.3333333333333333 1029:1.0 1035:1.0 1323:1.0 1630:1.0
9 1:0.5 21:0.14285714285714285 27:0.014492753623188406 28:2.0 40:0.125 66:0.25 89:0.5 104:0.5 128:0.16666666666666666 285:2.0 340:1.0 477:0.3333333333333333 601:1.0 751:1.0 1182:1.0 1323:1.0 1519:1.0
9 13:1.0 27:0.014492753623188406 104:0.5 157:1.0 419:1.0 452:1.0 477:0.3333333333333333 509:1.0 740:0.5 1323:1.0
9 12:1.0 13:1.0 27:0.014492753623188406 33:1.0 66:0.25 104:0.5 132:0.5 149:0.5 172:0.5 229:1.0 298:0.5 299:1.0 661:1.0 798:1.0 1100:1.0 1480:0.5
9 14:1.0 66:0.5 104:0.5 115:1.0 210:0.5 233:0.2 279:1.0 477:0.3333333333333333 509:1.0
9 12:1.0 21:0.14285714285714285 104:0.5 229:1.0 233:0.2 281:0.5 340:2.0 406:1.0 452:1.0 477:0.6666666666666666 1289:1.0
9 1:0.5 7:0.5 11:1.0 27:0.028985507246376812 28:1.0 36:0.125 66:0.5 91:0.25 93:1.0 104:1.0 107:0.25 116:1.0 130:1.0 143:1.0 219:1.0 229:1.0 290:1.0 804:1.0 1097:1.0
|
070eda673c6605ca5ae73ca9681c5698674f091c | 449d555969bfd7befe906877abab098c6e63a0e8 | /181/CH2/EX2.38/example2_38.sce | 4be752217ed3359cf66c2f86d1dcdee6a2e588c0 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 478 | sce | example2_38.sce | // Temperature coefficient of Avalanche diode
// Basic Electronics
// By Debashis De
// First Edition, 2010
// Dorling Kindersley Pvt. Ltd. India
// Example 2-38 in page 113
clear; clc; close;
// Given data
V=12; // Voltage of avalanche diode in V
T=1.7*10^-3; // Temperature coeff of Si diode
// Calculation
A=(T/V)*100;
printf("Temperature coeff in percentage = %0.4f percent/degree-C",A);
// Result
// Temperature coeff in percentage = 0.0142 %/degree-C |
a99dccfb7224ef355a4ac2d98f857ca9df47bf14 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3637/CH1/EX1.15/Ex1_15.sce | 12d4131d2905437bc63f44972991c5f1bc45f834 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 218 | sce | Ex1_15.sce | //Example 15 Page No: 1.90
//given
sr=50e6;//volt/sec
rin=2;format(5);
vimax=10;//volt
//determine max frequency
vm=vimax*(1+rin);
freq1=sr/(2*3.14*vm);
disp('Max frequency = '+string(freq1/10^3)+' Khz');
|
f004a76304af9da3ccb8bcf1fe49e9f7d0006c06 | 449d555969bfd7befe906877abab098c6e63a0e8 | /26/CH6/EX6.4.13/6_4_13.sce | a9834939f1a98b08592d1b40e1aae992266bc68f | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 196 | sce | 6_4_13.sce | disp('QR decomposition of a matrix')
disp('given matrix A=')
a=[5 9;1 7;-3 -5;1 5]
disp(a)
disp('given matrix Q=')
q=(1/6)*[5 -1;1 5;-3 1;1 3]
disp(q)
disp('Therefore, R=')
s=q'*a
disp(s) |
11904e230e2a2fc57cbaba5972c3b7240af726da | 449d555969bfd7befe906877abab098c6e63a0e8 | /2141/CH14/EX14.1/Ex14_1.sce | 9d8742f7e2c6f19d42963a1e51110c8e2d7a8788 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 306 | sce | Ex14_1.sce |
clc
//initialisation of variables
p=20 //lbf/in^2
v=600 //ft/sec
T0=570//R
T=540 //R
P0=p*1.210 //lbf/in^2
h=129.06
Pr=1.3860
pr0=1.6748
h0=h+((v)^2)/(64.34*778)
//CALCULATIONS
Po=p*(pr0/Pr)//lbf/in^2
//RESULTS
printf('The isentropic stagnation pressure and temperature=% f lbf/in^2',Po)
|
be55dde3a07b6697df67448595f7f43745327f0a | 449d555969bfd7befe906877abab098c6e63a0e8 | /2138/CH7/EX7.4.d/ex_7_4_d.sce | 476ac0947a5207dd42714a78cd836d8f3b09428a | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 647 | sce | ex_7_4_d.sce | //Example 7.4.d: bhp metric of the primemover
clc;
clear;
close;
// given data:
W=20000;// electrical output in watt
V=200; // in volts
R=0.08; // in ohm
Rs=0.02; // series field resistance in ohm
I=W/V; // in A
Rsh=42; // shunt ield resistance in ohm
Ra=0.04; // armature resistance in ohm
iron_losses=309.5; // iron and friction losses
Vf=I*R;
Vs=I*Rs;
V1=Vf+Vs; // voltage drop of feeder and series field
Vg=V+V1;// terminal voltage
Ish=Vg/Rsh;// shunt field current
Ia=I+Ish;
Vd=Ia*Ra;
emf=Vg+Vd;
Ed=emf*Ia;// in watt
copper_losses=Ed-W;
mech_in=W+copper_losses+iron_losses;
Bhp=mech_in/735.5;
disp(Bhp,"bhp metric of the primemover,Bhp = ")
|
af6e55d84a2cf9a2b70dedbfff1e6a41326254d8 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2318/CH3/EX3.63/ex_3_63.sce | 1637ef00131304df2339ee453fd75e46879df96b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 267 | sce | ex_3_63.sce | //Example 3.63:resistance and inductance
clc;
clear;
close;
r2=50;//ohms
r3=100;//ohms
r4=100;//ohms
r=2500;//ohms
c=1;//micro farads
rX=((r2*r3)/r4);//ohms
l=(((c*10^-6*r2)/r4)*((r*(r3+r4))+(r3*r4)));//H
disp(rX,"resistance is ,(ohm)=")
disp(l,"inductance is,(H)=")
|
39da4bfea8d7deb279cd3d02b4f717e7cb3a80a1 | 449d555969bfd7befe906877abab098c6e63a0e8 | /343/CH1/EX1.69/ex_69.sce | ddcf071790aaebfa02f99bbad3361e913c6ee307 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 372 | sce | ex_69.sce | R1=10; //Assigning values to parameters
R2=10;
R3=15;
R4=20;
V=100;
A=[-20,10;10,-25] //Current coeffecients by KVL equations
B=[-100;0];
I=inv(A)*B;
IN=I(2,1); //Norton's current
RN=(R1*R2)/(R1+R2)+R3; //Norton's resistance
Il=(IN*RN)/(RN+RN)
disp("Amperes",Il,"Current in load of 20 Ohm resistor using Norton theorem ") |
9a6ecab9992576298711a2744e4fac6d20d4e88b | 8217f7986187902617ad1bf89cb789618a90dd0a | /browsable_source/2.1.1/Unix/scilab-2.1.1/macros/algebre/lufact.sci | 229f3832c9a26b2f1bf70bc118f4b52b19e7ac08 | [
"MIT",
"LicenseRef-scancode-public-domain",
"LicenseRef-scancode-warranty-disclaimer"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 353 | sci | lufact.sci | function fact=lufact(spars)
[lhs,rhs]=argn(0), if rhs<>1 then error('bad argument number'), end
if type(spars)<>15 then error('the argument must be a list'), end
m=spars(4);n=spars(5);
if m<>n then error("lufact: waiting for a square matrix!");end
sp2=spars(2);
fmat=lufact1(matrix(sp2,prod(size(sp2)),1),spars(3),spars(5))
fact=list('factored',n,fmat)
|
4361f5aa2d53cbef62ae6eb5cc55a4089e6e7fc6 | 59ca8642f974b397e1747edc1015fce8b8e6c59f | /RK2.sce | 5c58b1d5b10f208bd3630265e88f99aa4cb66363 | [] | no_license | mcortex/scilab-code | c6a367b216e531d0ebe3cda5d4a84156b23d2085 | 2709299d60d9e72294b274773bdadb4126a25ba9 | refs/heads/master | 2020-05-26T05:49:42.441734 | 2019-12-06T02:06:49 | 2019-12-06T02:06:49 | 188,126,346 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 865 | sce | RK2.sce | // FUNCION A EVALUAR:
function z=f(t,y)
//z=%e*t*%e^sin(y);
//z=t^2*y^4
//z=t*exp(y)
//z=4-2*t
//z=-2*t*y
z=-t*y
endfunction
//function p=g(t)
// p=-t^2+4*t+2
//endfunction
//Grafico f(x)
//t=-5:0.1:5; // desde -5 hasta 5 yendo de 1 en 1
//plot2d(t, g(t));
//muestra grilla
//xgrid(3,1,7);
function T=RK2(t,y,f,h,N) // t=var indep, y=var dep de t, f(t,y(t)), h=paso, N=cantidad de iteraciones
T=[t y] //matriz de 1 fila x 2 columnas: [t0 y0]
for i=1:N
K1=f(t,y)*h
t=t+h
K2=f(t,(y+K1))*h
printf("\ny%d= %12.9f + ( %12.9f + %12.9f ) / 2 ",i,y,K1,K2);
y=y+(K1+K2)/2 // calculo yi
T=[T;t y] // ";" agrega una fila a la matriz
end
t=T(:,1);
y=T(:,2)';
//Grafico f(x)
plot2d(t,y,style=[color("red")]);
//muestra grilla
xgrid(3,1,7);
endfunction
|
6e2877cfc1bba74ff7166954a2cb5b4605485f52 | 449d555969bfd7befe906877abab098c6e63a0e8 | /61/CH8/EX8.2/ex8_2.sce | a0fa36ecf645d2b390ca7398fa1b8d7c99540367 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 167 | sce | ex8_2.sce | //ex8.2
r_ds=10*10^3;
R_d=1.5*10^3; //from previous question
g_m=4*10^-3; //from previous question
A_v=g_m*((R_d*r_ds)/(R_d+r_ds));
disp(A_v,'Voltage gain') |
e99d9f9afefb734a7d027b53b0c4210915fa822d | 449d555969bfd7befe906877abab098c6e63a0e8 | /291/CH2/EX2.3e/eg2_3e.sce | 5bd5d3fdfc193553db97dc7936d2a1f45595b85f | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 510 | sce | eg2_3e.sce | value = [1 2 3 4 5 6];
frequencies= [9 8 5 5 6 7];
i=1;
for j=1:6
for k = 1:frequencies(j)
final_value(i) = value(j);
i = i +1 ;
end;
end
product = value.*frequencies;
disp(product , sum(product))
total_value = sum(frequencies);
mean_value = sum(product)/total_value ; //the answer in the textbook is incorrect
[m1 m2]= max(frequencies);
n= m2;
disp("The sample mean is")
disp(mean_value)
disp(median(final_value), "The median is")
disp(value(n) , "The mode is") |
2ed8b917115aa9d7a8c9ae6188d80b65a91e9fad | 449d555969bfd7befe906877abab098c6e63a0e8 | /797/CH3/EX3.6.s/3_06_solution.sce | 9869f186e603252ea75749427f05193318025cc8 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 363 | sce | 3_06_solution.sce | //Soultion 3-06
WD=get_absolute_file_path('3_06_solution.sce');
datafile=WD+filesep()+'3_06_example.sci';
clc;
exec(datafile)
P_atm = P_atm * 1000;
P_1 = P_atm - rho_water * g * h_1 - rho_oil * g * h_2 + rho_mercury * g * h_3; //pressure equilibrium
P_1 = P_1 / 1000; //converting from [Pa] to [kPa]
//result
printf("Air pressure in the tank is %1.0f kPa", P_1);
|
b6591a64b34f0613ad08fa45c5babbf6eab3912f | 449d555969bfd7befe906877abab098c6e63a0e8 | /599/CH5/EX5.12/example5_12.sce | 938311be38dfc54a063c3cd14931735e4d543a45 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,110 | sce | example5_12.sce |
clear;
clc;
printf("\t Example 5.12\n");
//horizontal spray with recirculated water . air is cooled and humidified to 34 and leaves at 90percent saturation
T1=65; //dry bulb temperature at the inlet in degree celcius
f=3.5; //flow rate of air in m^3/s
hi=1.017; //humidity of incoming air in kg/kg of dry air
hl=.03; //humidity of leaving air in kg/kg of dry air
k=1.12; //mass transfer coefficient in kg/m^3*s
y1=.017; //molefraction at recieving end
y2=.03; //molefraction at leaving end
//substituting eqn 1st in 2nd we get;
a=2; //cross sectional area of the tower in m^2
d=1.113; //density o fair in kg/m^3
m=(f*d) //mass flow rate of air
gs=m/hi; //air velocity in kg/m^2* hr
ys_bar=.032;
//for recirculation humidifier
z=log((ys_bar-y1)/(ys_bar-y2))*gs/k; //length of the chamber required
printf("\n the length of the chamber required is :%f m",z);
//end |
1e6b6fcc98a02115d0c2bd89aaaccc0e0da34959 | 449d555969bfd7befe906877abab098c6e63a0e8 | /680/CH10/EX10.15/10_15.sce | ad2fd1a2051e50147eb0b83a0de460843388cdde | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 491 | sce | 10_15.sce | //Problem 10.15:
//initializing the variables:
xin2 = 0.0515
xich4 = 0.8111
xic2h6 = 0.0967
xic3h8 = 0.0351
xic4h10 = 0.0056
HVgn2 = 0; // in Btu/scf
HVgch4 = 1013; // in Btu/scf
HVgc2h6 = 1792; // in Btu/scf
HVgc3h8 = 2590; // in Btu/scf
HVgc4h10 = 3370; // in Btu/scf
//calculation:
HVg = xin2*HVgn2 + xich4*HVgch4 + xic2h6*HVgc2h6 + xic3h8*HVgc3h8 + xic4h10*HVgc4h10
printf("\n\nResult\n\n")
printf("\n the gross heating value of the gas mixture is %.0f Btu/scf",HVg) |
b6b0858f42e43867697dd3ff6853d84446fe31f0 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3845/CH10/EX10.7/Ex10_7.sce | 08d651f08c102f750f737578e1cc3faea9ffb9c2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 788 | sce | Ex10_7.sce | //Example 10.7
M=50;//Mass of the merry-go-round (kg)
R=1.50;//Radius of the merry-go-round (m)
F=250;//Force exerted (N)
theta=90;//Angle (deg)
tau=R*F*sind(theta);//Torque (N.m)
I=1/2*M*R^2;//Moment of inertia (kg.m^2)
alpha1=tau/I;//Angular acceleration (rad/s^2)
printf('a.Angular acceleration when no one is on the merry-go-round = %0.2f rad/s^2',alpha1)
M1=18;//Mass of the child (kg)
R1=1.25;//Distance of child from the center (m)
I_c=M1*R1^2;//Moment of inertia of the child (kg.m^2)
I=I_c+I;//Total moment of inertia (kg.m^2)
alpha2=tau/I;//Angular acceleration (rad/s^2)
printf('\nb.Angular acceleration when the child is on the merry-go-round = %0.2f rad/s^2',alpha2)
//Openstax - College Physics
//Download for free at http://cnx.org/content/col11406/latest
|
23143d1f599c85bce3d0362c864c64ddf644ab0e | 449d555969bfd7befe906877abab098c6e63a0e8 | /2741/CH6/EX6.28/Chapter6_Example28.sce | bdc152702fca54c8fac1890de1c3b04a1bcd4ce8 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 743 | sce | Chapter6_Example28.sce | clc
clear
//Input data
t2=120;//The given temperature for the water to boil in degree centigrade
t1=100;//The actual boiling point of water in degree centigrade
V=1676;//The change in specific volume in cm^3
l=540;//Latent heat of steam in cal/g
J=4.2*10^7;//joule in ergs/cal
//Calculations
T1=t2-t1;//The change in temperature in degree centigrade (or) K
T=t1+273;//The boiling point of water in K
L=l*J;//The latent heat of steam in ergs/g
p=1;//The atmospheric pressure in atmospheres
P=(L*T1)/(T*V);//The change in pressure in dynes/cm^2
P1=P/10^6;//The change in pressure in atmospheres
P2=P1+p;//The required pressure in atmospheres
//Output
printf('The required pressure is %3.4f atmospheres ',P2)
|
1e7465fe06964354125e4d12bee0d68a2c809e66 | b29e9715ab76b6f89609c32edd36f81a0dcf6a39 | /ketpic2escifiles6/Nohiddenpers2.sci | d49bce91e93b918690054ec505f5e8310ac42945 | [] | no_license | ketpic/ketcindy-scilab-support | e1646488aa840f86c198818ea518c24a66b71f81 | 3df21192d25809ce980cd036a5ef9f97b53aa918 | refs/heads/master | 2021-05-11T11:40:49.725978 | 2018-01-16T14:02:21 | 2018-01-16T14:02:21 | 117,643,554 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 3,142 | sci | Nohiddenpers2.sci | // 08.10.11
// 08.10.12
// 08.10.15
// 09.06.24
// 10.02.16 Eps
// 11.04.12 Eps0 (bug)
// 13.11.02 bug
function FigkL=Nohiddenpers2(PaL,Fk,Fd,Uveq,Np,Eps)
global EyePoint FocusPoint HIDDENDATA;
Eps0=10^(-5); // 11.04.12
Fh=Projpers(Fk);
P1=Ptstart(Fh);
P2=Ptend(Fh);
Csp=CuspPt();
Cspflg=1;
for I=1:Mixlength(Csp)
Tmp=Mixop(I,Csp);
if norm(Tmp-P1)<Eps0
select Cspflg,
case 1 then Cspflg=2,
case 3 then Cspflg=6;
end;
continue;
end;
if norm(Tmp-P2)<Eps0
select Cspflg,
case 1 then Cspflg=3,
case 2 then Cspflg=6;
end;
continue;
end;
end;
SeL=[];
for N=1:length(PaL)-1
S=(PaL(N)+PaL(N+1))/2;
Tmp=Invperspt(S,Fh,Fk)
PtA=Mixop(1,Tmp);
PtAp=Perspt(PtA);
// Vec=EyePoint-FocusPoint;
Vec=EyePoint-PtA; // 2013.11.02
Epstmp=Eps; // 2011.04.12
if N==1 & modulo(Cspflg,2)==0
Tmp=min(Eps(1)*norm(PtAp-Ptstart(Fh)),Eps(1)); //
Epstmp=[Tmp,Eps(2)]; //
end;
if N==length(PaL)-1 & modulo(Cspflg,3)==0
Tmp=min(Eps(1)*norm(PtAp-Ptend(Fh)),Eps(1)); //
Epstmp=[Tmp,Eps(2)]; //
end;
Flg=PthiddenQ(PtA,Vec,Fd,Uveq,Np,Epstmp);
if Flg==0
SeL=[SeL,N];
end;
end;
FigL=[];
FigkL=[];
for I=1:length(SeL)
Tmp1=PointonCurve(PaL(SeL(I)),Fh);
Tmp2=PointonCurve(PaL(SeL(I)+1),Fh);
if I==1
P=Tmp1; SP=PaL(SeL(I));
Q=Tmp2; SQ=PaL(SeL(I)+1);
else
if Member(SeL(I)-1,SeL)
Q=Tmp2; SQ=PaL(SeL(I)+1);
else
FigL=Mixadd(FigL,Partcrv(SP,SQ,Fh));
Tmp3=Invperspt(SP,Fh,Fk);
TP=Mixop(2,Tmp3);
Tmp3=Invperspt(SQ,Fh,Fk);
TQ=Mixop(2,Tmp3);
Tmp4=Partcrv3(TP,TQ,Fk)
FigkL=Mixadd(FigkL,Tmp4);
P=Tmp1; SP=PaL(SeL(I));
Q=Tmp2; SQ=PaL(SeL(I)+1);
end;
end;
end;
if length(SeL)>0
if norm(P-Q)>Eps(1) //
FigL=Mixadd(FigL,Partcrv(P,Q,Fh));
Tmp3=Invperspt(SP,Fh,Fk);
TP=Mixop(2,Tmp3);
Tmp3=Invperspt(SQ,Fh,Fk);
TQ=Mixop(2,Tmp3);
FigkL=Mixadd(FigkL,Partcrv3(TP,TQ,Fk));
else
FigL=Mixadd(FigL,Fh);
FigkL=Mixadd(FigkL,Fk);
end;
end;
Tmp=[];
for I=1:length(PaL)-1
if ~Member(I,SeL)
Tmp=[Tmp,I];
end;
end;
SeL=Tmp;
HIDDENDATA=[];
for I=1:length(SeL)
Tmp=PaL(SeL(I));
Tmp1=PointonCurve(Tmp,Fh);
Tmp=PaL(SeL(I)+1);
Tmp2=PointonCurve(Tmp,Fh);
if I==1
P=Tmp1; SP=PaL(SeL(I));
Q=Tmp2; SQ=PaL(SeL(I)+1);
else
if Member(SeL(I)-1,SeL)
Q=Tmp2; SQ=PaL(SeL(I)+1);
else
Tmp=Invperspt(SP,Fh,Fk);
TP=Mixop(2,Tmp);
Tmp=Invperspt(SQ,Fh,Fk);
TQ=Mixop(2,Tmp);
HIDDENDATA=Mixadd(HIDDENDATA,Partcrv3(TP,TQ,Fk));
P=Tmp1; SP=PaL(SeL(I));
Q=Tmp2; SQ=PaL(SeL(I)+1);
end;
end;
end;
if length(SeL)>0
if norm(P-Q)>Eps(1) //
Tmp=Invperspt(SP,Fh,Fk);
TP=Mixop(2,Tmp);
Tmp=Invperspt(SQ,Fh,Fk);
TQ=Mixop(2,Tmp);
HIDDENDATA=Mixadd(HIDDENDATA,Partcrv3(TP,TQ,Fk));
else
HIDDENDATA=Mixadd(HIDDENDATA,Fk);
end;
end;
endfunction;
|
08744a26b4ba1d189c8e9f8b67b4673421c89d87 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2213/CH7/EX7.22/ex_7_22.sce | ffe507cdf7b6a0a22d61fb87ed3dbf99661341ac | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 682 | sce | ex_7_22.sce | //Example 7.22: specific energy consumption
clc;
clear;
close;
//given data :
W=500;//
t1=60;//in sec
t2=5*60;// in sec
t3=3*60;// in sec
alpha=2.5;//kmphps
V1=alpha*(t1);// in km/h
r=25;// in N/tonne
G=1;
bc=(((98.1*(8/1000)*100)+r))/(277.8*1.1);//in kmphps
V2=V1-(bc*t3);//km/hr
Beta=3;//retardation
t4=V2/Beta;//in seconds
S=(((V1*t1)/7200)+((V1*t2)/3600)+(((V1+V2)*t3)/7200)+((V2*t4)/7200));
D=15;// duration of stop in sec
Ts=t1+t2+t3+t4+D;
Vs=((S*3600)/Ts);
S1=((V1*t1)/7200)+((V1*t2)/3600);//in km
WeBY_W=1.1;
G=1;//
Ec=((0.01072*V1^2*WeBY_W)/(S))+(0.2778*((98.1*(8/1000)*100)+r)*((S1)/(S)));
N=0.80;//
Sec=Ec/N;//
disp(Sec,"Specific energy consumption in Wh/tonne-km is")
|
e1c745dbfbc0004d88f9fa92b892fcadf981e0cb | 449d555969bfd7befe906877abab098c6e63a0e8 | /3769/CH4/EX4.33/Ex4_33.sce | 495993134d1f4bba15d3796848e83052c882a28e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 230 | sce | Ex4_33.sce | clear
//Given
e=8.854*10**-12
A=2
t1=0.5*10**-3
t2=1.5*10**-3
t3=0.3*10**-3
K1=2.0
K2=4.0
K3=6.0
//Calculation
C=(e*A)/((t1/K1)+(t2/K2)+(t3/K3))
//Result
printf("\n The capacitance of the capacitor is %0.3f *10**-6 F",C*10**6)
|
35d44a017553d2c5f65ceda6fd90ac4577f688ed | 449d555969bfd7befe906877abab098c6e63a0e8 | /3754/CH20/EX20.6/20_6.sce | aa9855375b776583d9b4fce85774309871d23899 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 755 | sce | 20_6.sce | clear//
//Variables
VS = 30.0 //Source voltage (in volts)
RS = 240.0 //Series resistance (in ohm)
Vz = 12.0 //Zener voltage (in volts)
RL = 500.0 //Load resistance (in ohm)
//Calculation
VL = Vz //Voltage drop across load (in volts)
IS = (VS - Vz) / RS //Current through RS (in Ampere)
VRS = IS * RS //Voltage drop across series resistance (in volts)
IL = VL / RL //Load current (in Ampere)
IZ = IS - IL //Zener current (in Ampere)
//Result
printf("\n Load voltage is %0.3f V.\nVoltage drop across series resistance is %0.3f V.\nCurrent through Zener diode is %0.3f A.",VL,VRS,IZ)
|
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