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clc clear close im=imread('bitcoin.jpg') an=imnoise(im,'salt & pepper',0.05) a=double(an) [r c]=size(a) for i=2:r-1 for j=2:c-1 x=a(i-1:i+1,j-1:j+1) ta=gsort(x) b(i+1,j+1)=ta(5); end end subplot(1,3,1) title('Orginal Image'); imshow(im); subplot(1,3,2) title('Noise Image'); imshow(uint8(an)); subplot(1,3,3) title('Output Image'); imshow(uint8(b));
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//Example 5_23 clc(); clear; //To find the interplanar spacing n=2 lamda=0.12 //units in nm theta=28 //units in degrees d=(n*lamda)/(2*sin(theta*%pi/180)) printf("Interplanar spacong d=%.2f nm",d)
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function [z]= g1(X) z = X.^0 endfunction function [z] = g2(X) z = X endfunction function [z] = g3(X) z = X.^2 endfunction exec('quadrados_minimos.sci'); // definindo os pontos tabelados da função X = [0, 0.25, 0.5, 0.75, 1, 1.25, 1.5, 1.75, 2]; F = [-1.8, -1.2, -0.4, 0.4, 1.1, 2.1, 3.0, 3.9, 5.0] ; GLista = list(g1,g2,g3) [a] = quadrados_minimos(X,F,GLista) mprintf('parabola') disp(a) // gráfico x = linspace(-1,2,101); G = a(1) + a(2)*x + a(3)*x.^2; plot(x,G); plot(X,F,'ro'); // calculo do erro GX = a(1) + a(2)*X + a(3)*X.^2; Y = F - GX; E = Y*Y' mprintf('erro') disp(E) GLista = list(g1,g2) [a] = quadrados_minimos(X,F,GLista) mprintf('Reta') disp(a) L = a(1) + a(2)*x; plot(x,L, 'r'); plot(X,F,'ro'); // calculo do erro LX = a(1) + a(2)*X; Y = F - LX; E = Y*Y' mprintf('erro') disp(E)
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// **** Purpose **** // This function split a word into separate strings by identifying '#' // **** Variables **** // [A]: string // <= a line of strings // [B]: string // => separated strings // **** Version **** // 06/07/2014 1st version // **** Comment **** // 1. This is a PiLib IO function. In PiLib, any string ending with '#' is // idenfitied as a string element in a string matrix. // 2. The leading and trailing blanks (and tabs) of strings will be automatically // trimmed. function B=PIL_str_split(A) A_len=length(A); A_char=strsplit(A); A_pound=find(A_char=='#'); // generate string range A_range=zeros(length(A_pound),2); A_range(1,1)=1 A_range($,2)=A_pound($)-1; for n=1:length(A_pound)-1 A_range(n,2)=A_pound(n)-1; A_range(n+1,1)=A_pound(n)+1 end B=emptystr(1,length(A_pound)); for n=1:length(A_pound) for m=A_range(n,1):A_range(n,2) B(n)=B(n)+A_char(m); end B(n)=stripblanks(B(n)); end endfunction
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clear; clc; //Example - 11.5 //Page number - 389 printf("Example - 11.5 and Page number - 389\n\n"); //This problem involves proving a relation in which no mathematical components are involved. //For prove refer to this example 11.5 on page number 389 of the book. printf(" This problem involves proving a relation in which no mathematical components are involved.\n\n"); printf(" For prove refer to this example 11.5 on page number 389 of the book.")
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clc disp("Example 1.25") printf("\n") disp("calculate the diode current") //given V=12 R=10^3 Vd=0.7 //diode current I=(V-Vd)/R printf("Diode current=%f Ampere",I)
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// Calculating the maximum permissible core length for the machine clc; disp('Example 9.7, Page No. = 9.32') // Given Data Kf = 0.67;// Form factor Bg = 1;// Maximum gap density (in Wb per meter square) Va = 40;// Armature peripheral speed (in meter) E = 7;// Maximum permissible value of emf induced in a conductor at no load (in Volts) // Calculation of the maximum permissible core length for the machine Bav = Kf*Bg;// Average gap density (in Wb per meter square) L = E/(Bav*Va);// Maximum permissible core length (in meter) disp(L,'Maximum permissible core length (meter)='); //in book answer is 0.26 (meter). The answers vary due to round off error
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 2: HEATING AND WELDING // EXAMPLE : 2.7 : // Page number 732-733 clear ; clc ; close ; // Clear the work space and console // Given data l = 4.0 // Length of material(cm) b = 2.0 // Breadth of material(cm) t = 1.0 // Thickness of material(cm) l_e = 20.0 // Length of area(cm) b_e = 2.0 // Breadth of area(cm) dis = 1.6 // Distance of separation of electrode(cm) f = 20.0*10**6 // Frequency(Hz) P = 80.0 // Power absorbed(W) e_r1 = 5.0 // Relative permittivity e_r2 = 1.0 // Relative permittivity of air PF = 0.05 // Power factor // Calculations e_0 = 8.854*10**-12 // Absolute permittivity A_1 = (l_e-l)*b_e*10**-4 // Area of one electrode(sq.m) A_2 = l*b*10**-4 // Area of material under electrode(sq.m) d = dis*10**-2 // Distance of separation of electrode(m) d_1 = t*10**-2 // (m) d_2 = (d-d_1) // (m) C = e_0*((A_1*e_r2/d)+(A_2/((d_1/e_r1)+(d_2/e_r2)))) // Capacitance(F) X_c = 1.0/(2*%pi*f*C) // Reactance(ohm) phi = acosd(PF) // Φ(°) R = X_c*tand(phi) // Resistance(ohm) V = (P*R)**0.5 // Voltage applied across electrodes(V) I_c = V/X_c // Current through the material(A) // Results disp("PART IV - EXAMPLE : 2.7 : SOLUTION :-") printf("\nVoltage applied across electrodes, V = %.f V", V) printf("\nCurrent through the material, I_c = %.1f A\n", I_c) printf("\nNOTE: ERROR: Calculation mistake in the textbook solution")
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Ex4_30.sce
// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 4 : DIRECT CURRENT MACHINES // EXAMPLE : 4.30 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA Vg = 110; // Generator operating Volatge in Volts Vm = 102; // Motor operating Volatge in Volts Vs = 274; // Supply Volatge in Volts Ra = 1.0; // Armature Resistance in Ohms for both the Machines Rf = 0.82; // Field Resistance in Ohms for both the Machines N = 1440; // Speed of the Set in RPM Ig = 17.5; // Generator current in Amphere Im = 9.5; // Motor current in Amphere // CALCULATIONS Pi = Vs * Im; // Input power in Watts Pg = Vg * Ig; // Output power in Watts Pim = Vm * Im; // Power Input to the Motor in Watts Pl = Pi - Pg; // Losses in the entire set in Watts Pcu = Im^2*(Ra+2*Rf) + Ig^2*Ra; // Total Copper loss for both the Machines in Watts P_l = Pi - Pg - Pcu; // Frictional, Windage and core losses of the both Machines in Watts Po = P_l/2; // Frictional, Windage and core loss of each Machines in Watts eta_m = (1 - ((Po + Im^2*(Ra+Rf))/Pim))*100; // Motor Effiicency in Percentage Pig = Pg + Po + Ig^2*Ra + Im^2*Rf; // Generator input in Watts eta_g = (Pg / Pig)*100; // Generator Effiicency in Percentage T = (Vg*Ig *60)/(2*%pi*N); // Torque in Newton-Meter // DISPLAY RESULTS disp("EXAMPLE : 4.30 : SOLUTION :-") ; printf("\n (a) Motor Efficiency , eta_m = %.2f percentage \n ",eta_m); printf("\n (b) Generator Efficiency , eta_g = %.2f Percentage \n ",eta_g); printf("\n (c) Torque , T = %.2f N-m \n ",T); printf("\n\n [ TEXT BOOK SOLUTION IS PRINTED WRONGLY ( I verified by manual calculation )]\n" ); printf("\n WRONGLY PRINTED ANSWERS ARE :- (a) Generator input = 2307.5 W instead of %.f W \n ",Pig); printf("\n (b) eta_g = 83.42 Percenatge instead of %.2f Percentage \n ",eta_g); printf("\n From Calculation of the Generator input, rest all the Calculated values in the TEXT BOOK is WRONG because of the Generator input value is WRONGLY calculated and the same used for the further Calculation part \n")
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load Reversi.asm, set RAM[24576] 132, repeat 200000 { ticktock; }
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clc(); clear; //To determine the ratio of the number of vacancies to the number of atoms //n500=N*exp(-Ev/500k) k=8.625*10^-5; //Boltzmann constant in eV/K Ev=0.95; //average energy required to create a vacancy n=exp(-Ev/(500*k)) //n500/N printf("The ratio of number of vacancies to the number of atoms is %e ",n);
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// Scilab Code Ex9.8: Page-322 (2014) clc; clear; R = 1; // For simplicity assume the molar gas constant to be unity, J/mol/K T = 293; // Room temperature, K T_F = 8.16e+004; // The Fermi temperature for copper C_V = %pi^2*T/(2*T_F)*R; // Electronic contribution to the molar heat capacity for copper, J/mol/K printf("\nThe electronic contribution to the molar heat capacity for copper = %6.4fR", C_V); T_F = 6.38e+004; // The Fermi temperature for silver C_V = %pi^2*T/(2*T_F)*R; // Electronic contribution to the molar heat capacity for silver, J/mol/K printf("\nThe electronic contribution to the molar heat capacity for silver = %6.4fR", C_V); // Result // The electronic contribution to the molar heat capacity for copper = 0.0177R // The electronic contribution to the molar heat capacity for silver = 0.0227R
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clc // Given that v_bm = 360 // Blade velocity at the mean diameter of a gas turbine stage in m/s beta1 = 20 // Blade angle at inlet in degree beta2 = 52 // Blade angle at exit in degree r = 0.5 // Degree of reaction Dm = 0.45 // Mean diameter of blade in m h = 0.08 // Mean height of blade in m printf("\n Example 21.2\n") v_f = v_bm/((tand(beta2))-tand(beta1)) r_r = (Dm/2)-h/2 r_t = Dm/2 +h/2 delta_v_wm = v_f*((tand(beta1))+(tand(beta2))) v_br = v_bm*(r_r/(Dm/2)) delta_v_wr = delta_v_wm*v_bm/v_br v_bt = (r_t/(Dm/2))*v_bm v_w_1m = v_f*(tand(beta2)) v_w_1t = v_w_1m*(Dm/2)/r_t delta_v_wt = v_f*((tand(beta1))+(tand(beta2)))*v_bm/v_bt v_w_1r = v_w_1m*((Dm/2)/r_r) alpha_1r = atand(v_w_1r/v_f) alpha_2r = atand((delta_v_wr-v_w_1r)/v_f) beta_1r = atand((v_w_1r-v_br)/v_f) beta_2r = atand((v_br+v_f*(tand(alpha_2r)))/v_f) alpha_1t = atand(v_w_1t/v_f) alpha_2t = atand((delta_v_wt-v_w_1t)/v_f) beta_1t = atand((v_w_1t-v_bt)/v_f) beta_2t = atand((v_bt+(v_f*tand(alpha_2t)))/v_f) Rt = v_f*((tand(beta_2t))-(tand(beta_1t)))/(2*v_bt) Rr = v_f*((tand(beta_2r))-(tand(beta_1r)))/(2*v_br) printf("\n Flow velocity = %d m/s,\n The blade angle at the root = %f degree,and at the tip = %f degree,\n The degree of reaction at the root = %f percent, and at the tip = %d percent",v_f,alpha_1r,alpha_2r,Rt*100,Rr*100)
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// Figure #2: Multiple plot and axis setting // ---------- // Data x = linspace(-5.5,5.5,51); y = 1 ./(1+x.^2); // Plot // scf(fig_id) = set the current graphic figure (window) scf(2); // clf(fig_id) = Clear or reset or reset a figure or a frame uicontrol. clf(2); // Three plots plot(x,y,'ro-'); plot(x,y.^2,'bs:'); plot(x,x.^2,'gs:'); xlabel(["x axis";"(independent variable)"]); ylabel("y axis"); title("Functions"); legend(["Functions #1";"Functions #2";"Functions #3"]); // a=gca() //get the current axes set(gca(),"data_bounds",matrix([-6,6,-0.1,1.1],2,-1));
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x=['a' 'b' 'c' 'd']; t=1:length(x); s=slewrate(x, t); disp(s) //output //t=1:length(x); // !--error 204 //':': Wrong type for argument #2: Scalar expected. //at line 2 of exec file called by : //te/slewrate13.sce', -1 //
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clc clear disp("example 15.7") ws=20 //wind speed rd=10 //rotor diameter ros=30 //rotor speed ad=1.293 //air density mc=0.593 //maximum value of power coefficient p1=0.5*ad*(%pi)*(rd^2)*(ws^3)/4 //power p=p1/10^3 pd=p/((%pi)*(rd/2)^2) //power density pm=p*(mc) //maximum power mt=(pm*10^3)/((%pi)*rd*(ros/60)) printf("power %.fkW \n power density %.3fkW/m^3 \nmaximum power %fkW \n maximum torque %.1fN-m",p,pd,pm,mt)
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//Chapter-2,Example2_4_8,pg 2-27 m=1 //first ordr spectrum wavelength=6.56*10^-5 //wavelength of light angle=18.23333333 //angle of diffraction N=2*sind(angle)/(m*wavelength) printf('\nNumber of lines per 2 cm is N = %.2f',N)
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// Part 2 ai, a, i [ai Fsai bitsai] = wavread('ai.wav'); [a Fsa bitsa] = wavread('a.wav'); [i Fsi bitsi] = wavread('i.wav'); scf(); subplot(3,1,1); plot2d(ai); title('ai'); subplot(3,1,2); plot2d(a); title('a'); subplot(3,1,3); plot2d(i); title('i'); NumSamples = Fsai * 30 / 1000; scf(); F = Fsai*((0:NumSamples-1) - NumSamples/2) / NumSamples; // For ai ai = ai(20000:20000+NumSamples); ai = ai / abs(max(ai)); AI = 20*log10(abs(fftshift(fft(ai)))); AI = AI / abs(max(AI)); subplot(3,2,1); plot2d(ai); title('ai'); subplot(3,2,2); plot2d(F(NumSamples/2:NumSamples), AI(NumSamples/2:NumSamples)); title('ai'); ax = get("current_axes"); ax.data_bounds = [0,min(AI); max(F), max(AI)]; // For a a = a(25394:25394+NumSamples); a = a / abs(max(a)); A = 20*log10(abs(fftshift(fft(a)))); A = A / abs(max(A)); subplot(3,2,3); plot2d(a); title('a'); subplot(3,2,4); plot2d(F(NumSamples/2:NumSamples), A(NumSamples/2:NumSamples)); title('a'); ax = get("current_axes"); ax.data_bounds = [0,min(A); max(F), max(A)]; // For i i = i(30000:30000+NumSamples); i = i / abs(max(i)); I = 20*log10(abs(fftshift(fft(i)))); I = I / abs(max(I)); subplot(3,2,5); plot2d(i); title('i'); subplot(3,2,6); plot2d(F(NumSamples/2:NumSamples), I(NumSamples/2:NumSamples)); title('i'); ax = get("current_axes"); ax.data_bounds = [0,min(I); max(F), max(I)];
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clear; //clc(); H=2.7; s=1; fr=50; del0=23.13; pmax1=2.545; pmax2=0.778; pmax3=1.75; ps=1; del_del0=0; M=H*s/(180*fr); del_del=zeros(1,9); pa=zeros(1,9); del=zeros(1,9); //for t=0- pmax=pmax1; //for t=0+; pmax=pmax2; p=ps-pmax2*sind(del0); pa_avg=0.5*p; pa(1)=pa_avg; t=[.1:.9:9]; del(1)=del0; del(2)=del_del0+8.33*pa_avg; del(2)=del0+del(2); for i=2:1:9 pa(i)=ps-.778*sind(del(i)); del_del(i+1)=del_del(i)+8.33*pa(i); del(i+1)=del(i)+ del_del(i+1); end plot(t,del) xlabel("time in secs"); ylabel('torque angle in degrees');
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function [x,y,typ]=POSTONEG_f(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; x(3)(11)=[-1] //compatibility case 'define' then rpar=[-1;-1;-1;0] model=list('zcross',1,[],[],1,[],[],rpar,[],'z',-1,[%t %f],' ',list()) gr_i=['xstringb(orig(1),orig(2),'' + to - '',sz(1),sz(2),''fill'')'] x=standard_define([2 2],model,[],gr_i) end
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//Example 2.30: Convert expression into POS Form clc // Clears the console disp('wxy'' + xyz + w''x''z''') disp('= x(wy'' + yz) + w''x''z''') disp('= x(y'' + z)(y + w) + w''x''z''') disp('= (x + w''z'')[x'' + (y'' + z )(y + w)]') disp('= (x + w'')(x + z'')(x'' + y'' + z )(x'' + y + w)]') //the reduced expression is displayed.
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function f1=%rqp(f1,f2) // r.\p //! num=f1(3).*f2 f1(3)=f1(2).*ones(f2) f1(2)=num;
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//Exa 6.13 clc; clear; close; format('v',6); //Given Data : p1=600;//KPa p1=p1/100;//bar T1=200;//degree C Vsup1=0.352;//m^3/Kg(at 6 bar) V1=Vsup1;//m^3/Kg V2=V1;//m^3(system is at constant volume) Vg2=V2;//m^3/Kg(For dry saturated) Tsup1=153.3;//degree C Tsup2=154.8;//degree C vg1=0.34844;//m^3/Kg vg2=0.36106;//m^3/Kg ts2=Tsup1+(Tsup2-Tsup1)/(vg2-vg1)*(V1-vg1);//degree C disp(ts2,"Temperature at which steam begins to condense in degree C : "); pg1=5.2;//bar pg2=5.4;//bar p2=pg1+(pg2-pg1)/(Tsup2-Tsup1)*(ts2-Tsup1);//bar disp(p2,"Pressure in bar is :"); //Some data is taken from steam table.
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//Graphical// //Implementation of Equation 2.1.8 in Chapter 2 //Digital Signal Processing by Proakis, Third Edition, PHI //Page 45 clear; clc; close; L = 4; //Upperlimit n = -L:L; x = [zeros(1,L),0:L]; a=gca(); a.thickness = 2; a.y_location = "middle"; plot2d3('gnn',n,x) xtitle('Graphical Representation of Unit Ramp Signal','n','x[n]');
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// Calculating the pow. y = [1.2, 1, 1.9; 4, 2.6, 5; 2.3, 8, 7]; power = int32(3) powres = armaMat("pow",y,power)
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//Exa:2.2.2 clc; clear; close; Z_ph=8+%i*6//impedance per phase (in ohms) V_AN=400//in volts I_ph=V_AN/Z_ph disp(abs(I_ph),'Phase current (in A)=') disp(atand(imag(I_ph)/real(I_ph)),'phase=') I_L=sqrt(3)*abs(I_ph) disp(I_L,'Line current (in A)=') pf=cosd(atand(imag(I_ph)/real(I_ph))) disp(pf,'power factor=') P=sqrt(3)*V_AN*I_L*pf*10^-3 disp(P,'Power absorbed (in KW)=')
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//Exa 8.18 clc; clear; close; //Given data : format('v',5); RL=630;//in Ohm B=50;//in MHz B=B*10^6;//in Hz Ip=10^-7;//in Ampere T=18;//in degree C T=T+273;//in kelvin q=1.6*10^-19;//in coulamb K=1.38*10^-23;//Boltzman Constant SbyN=Ip^2/(2*q*B*Ip+4*K*T*B/RL);//unitless SbyNdB=10*log10(SbyN);//in dB disp(round(SbyNdB),"Maximum SNR in dB : ");
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clc clear vout=750*10^-3 vin = 30*10^-6 gain=vout/vin printf('The Voltage gain of the amplifier is %.1f',gain)
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# # The ANU Nilpotent Quotient Program (Version 1.1d, 18 May 1994) # Calculating a nilpotent quotient # Nilpotency class: 8 # # Calculating the abelian quotient ... # The abelian quotient has 4 generators # with the following exponents: 0 0 0 0 # # Calculating the class 2 quotient ... # Time spent on the integer matrix: 0 msec. # Maximal entry: 0 # Layer 2 of the lower central series has 3 generators # with the following exponents: 0 0 0 # # Calculating the class 3 quotient ... # Time spent on the integer matrix: 0 msec. # Maximal entry: 0 # Layer 3 of the lower central series has 3 generators # with the following exponents: 0 0 0 # # Calculating the class 4 quotient ... # Time spent on the integer matrix: 0 msec. # Maximal entry: 0 # Layer 4 of the lower central series has 3 generators # with the following exponents: 0 0 0 # # Calculating the class 5 quotient ... # Time spent on the integer matrix: 0 msec. # Maximal entry: 2 # Layer 5 of the lower central series has 4 generators # with the following exponents: 0 2 3 0 # # Calculating the class 6 quotient ... # Time spent on the integer matrix: 0 msec. # Maximal entry: 6 # Layer 6 of the lower central series has 6 generators # with the following exponents: 2 2 3 3 0 6 # # Calculating the class 7 quotient ... # Time spent on the integer matrix: 4 msec. # Maximal entry: 14 # Layer 7 of the lower central series has 9 generators # with the following exponents: 2 2 2 3 3 6 2 3 6 # # Calculating the class 8 quotient ... # Time spent on the integer matrix: 12 msec. # Maximal entry: 36 # Layer 8 of the lower central series has 13 generators # with the following exponents: 2 2 2 2 3 3 3 2 2 3 3 6 2 # # The epimorphism : # a|---> A # b|---> B # c|---> C # d|---> D # The nilpotent quotient : <A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z,A1,B1,C1,D1,E1,F1,G1,H1,I1,J1,K1,L1,M1,N1,O1,P1,Q1,R1,S1 | O^2 = U, P^3 = W^3*D1*F1^5, R^2 = A1^2*K1^2*N1, S^2 = B1, T^3 = C1^3*R1^5, U^3 = D1, W^6 = S1, X^2 = K1^2, Y^2 = L1^2, Z^2, A1^3, B1^3 = O1, C1^6, D1^2, E1^3 = S1, F1^6, G1^2, H1^2, I1^2, J1^2, K1^3, L1^3, M1^3, N1^2, O1^2, P1^3, Q1^3, R1^6, S1^2, B^A =: B*E, B^(A^-1) = B*E^-1, C^A = C, C^(A^-1) = C, C^B =: C*F, C^(B^-1) = C*F^-1, D^A = D, D^(A^-1) = D, D^B = D, D^(B^-1) = D, D^C =: D*G, D^(C^-1) = D*G^-1, E^A = E, E^(A^-1) = E, E^B = E, E^(B^-1) = E, E^C = E*H^-1, E^(C^-1) = E*H*K^-1, E^D = E, E^(D^-1) = E, F^A =: F*H, F^(A^-1) = F*H^-1, F^B = F, F^(B^-1) = F, F^C =: F*I, F^(C^-1) = F*I^-1, F^D = F*J^-1*M^-1*O*Q^-1*S*U^2*Z*B1^2*J1*Q1, F^(D^-1) = F*J*M*O*S*Z*J1, F^E = F, F^(E^-1) = F, G^A = G, G^(A^-1) = G, G^B =: G*J, G^(B^-1) = G*J^-1*O*U^2*Z*D1, G^C = G, G^(C^-1) = G, G^D = G, G^(D^-1) = G, G^E = G*L*R*I1, G^(E^-1) = G*L^-1*R*X*A1*I1*K1^2*N1, G^F = G*M^-1*O*S*U^2*Z*B1^2*D1*J1*O1, G^(F^-1) = G*M*O*U^2*Z*D1, H^A = H, H^(A^-1) = H, H^B = H, H^(B^-1) = H, H^C = H*K, H^(C^-1) = H*K^-1, H^D = H*L^-1*N^-1*R*V^-1*X*Y*A1*G1*I1*K1^2*L1, H^(D^-1) = H*L*N*R*X*Y*G1*H1*I1*N1, H^E = H, H^(E^-1) = H, H^F = H, H^(F^-1) = H, H^G = H*N*X*Y*G1*H1*N1, H^(G^-1) = H*N^-1*X*Y*C1^5*G1*H1*K1*L1*N1*P1, I^A =: I*K, I^(A^-1) = I*K^-1, I^B = I, I^(B^-1) = I, I^C = I, I^(C^-1) = I, I^D = I*M^-2*O*P*Q^-1*S*U*M1^2*Q1, I^(D^-1) = I*M^2*O*P^2*Q^-1*S*U*W^5*B1^2*D1*F1*M1*Q1, I^E = I, I^(E^-1) = I, I^F = I, I^(F^-1) = I, I^G = I*P*S*B1*M1^2*O1, I^(G^-1) = I*P^2*S*W^3*B1*D1*E1^2*F1*M1*O1, I^H = I, I^(H^-1) = I, J^A =: J*L, J^(A^-1) = J*L^-1*X*K1, J^B = J*O*U^2*D1, J^(B^-1) = J*O*Z, J^C =: J*M, J^(C^-1) = J*M^-1*P*O1, J^D = J, J^(D^-1) = J, J^E = J*R*A1*H1*I1*K1, J^(E^-1) = J*R*H1*I1*N1, J^F = J*O*U^2*D1, J^(F^-1) = J*O*Z, J^G = J*Q^-1*W*E1^2*F1, J^(G^-1) = J*Q*W^5*E1*S1, J^H = J*R*A1*H1*I1*K1, J^(H^-1) = J*R*H1*I1*N1, J^I = J*U^2*Z*D1, J^(I^-1) = J*U*Z, K^A = K, K^(A^-1) = K, K^B = K, K^(B^-1) = K, K^C = K, K^(C^-1) = K, K^D = K*N^-2*T*V^-1*X*G1*H1*K1^2*L1, K^(D^-1) = K*N^2*T^2*V^-1*X*C1^5*G1*H1*K1^2*L1^2*R1, K^E = K, K^(E^-1) = K, K^F = K, K^(F^-1) = K, K^G = K*T*G1, K^(G^-1) = K*T^2*C1^3*G1*P1^2*R1, K^H = K, K^(H^-1) = K, K^I = K, K^(I^-1) = K, K^J = K*A1^2*K1^2*N1, K^(J^-1) = K*A1*K1*N1, L^A = L*X*K1, L^(A^-1) = L*X, L^B = L*R*A1*K1*N1, L^(B^-1) = L*R*I1, L^C = L*N*H1*N1, L^(C^-1) = L*N^-1*T*H1*N1, L^D = L, L^(D^-1) = L, L^E = L*X*K1, L^(E^-1) = L*X, L^F = L*R*A1*K1*N1, L^(F^-1) = L*R*I1, L^G = L*V^-1*C1*P1^2*R1, L^(G^-1) = L*V*C1^5*P1, L^H = L*X*K1, L^(H^-1) = L*X, L^I = L*A1*I1*K1*N1, L^(I^-1) = L*A1^2*I1*K1^2*N1, L^J = L*H1*N1, L^(J^-1) = L*H1*N1, L^K = L*K1, L^(K^-1) = L*K1^2, M^A =: M*N, M^(A^-1) = M*N^-1*G1, M^B =: M*O, M^(B^-1) = M*O*U^2*Z*D1, M^C =: M*P, M^(C^-1) = M*P^2*W^3*D1*F1*O1*S1, M^D =: M*Q, M^(D^-1) = M*Q^-1*F1, M^E = M*R*H1*I1*N1, M^(E^-1) = M*R*A1*H1*I1*K1, M^F = M*S*U*Z*J1, M^(F^-1) = M*S*U^2*Z*B1^2*D1*O1, M^G = M*W^5*E1, M^(G^-1) = M*W*E1^2*S1, M^H = M*Y*A1^2*K1^2*N1, M^(H^-1) = M*Y*A1*K1*L1*N1, M^I = M*B1^2*J1*O1, M^(I^-1) = M*B1*J1, M^J = M, M^(J^-1) = M, M^K = M*L1, M^(K^-1) = M*L1^2, M^L = M*H1*N1, M^(L^-1) = M*H1*N1, N^A = N*G1, N^(A^-1) = N*G1, N^B =: N*R, N^(B^-1) = N*R*A1*I1*K1*N1, N^C = N*T, N^(C^-1) = N*T^2*C1^3*R1, N^D = N*V, N^(D^-1) = N*V^-1*R1, N^E = N*X, N^(E^-1) = N*X*K1, N^F = N*Y*A1^2*I1*K1^2*N1, N^(F^-1) = N*Y*A1*I1*K1*L1*N1, N^G = N*C1^5*P1, N^(G^-1) = N*C1*P1^2, N^H = N*G1*K1^2, N^(H^-1) = N*G1*K1, N^I = N*L1, N^(I^-1) = N*L1^2, N^J = N*H1*N1, N^(J^-1) = N*H1*N1, O^A = O*X*A1^2*H1*K1^2, O^(A^-1) = O*X*A1*H1*K1, O^B = O*Z, O^(B^-1) = O*Z, O^C =: O*S, O^(C^-1) = O*S*B1^2*M1^2, O^D = O, O^(D^-1) = O, O^E = O*I1, O^(E^-1) = O*I1, O^F = O*Z, O^(F^-1) = O*Z, O^G = O*D1*Q1, O^(G^-1) = O*D1*Q1^2, O^H = O*I1, O^(H^-1) = O*I1, O^I = O, O^(I^-1) = O, O^J = O, O^(J^-1) = O, P^A =: P*T, P^(A^-1) = P*T^2*C1^3*R1, P^B =: P*U, P^(B^-1) = P*U^2*D1, P^C = P*O1, P^(C^-1) = P*O1, P^D = P*W^2*F1*S1, P^(D^-1) = P*W^4*F1, P^E = P*A1^2*K1^2*N1, P^(E^-1) = P*A1*K1*N1, P^F = P*B1^2*O1, P^(F^-1) = P*B1, P^G = P*E1^2*S1, P^(G^-1) = P*E1, P^H = P*L1, P^(H^-1) = P*L1^2, P^I = P*M1^2, P^(I^-1) = P*M1, P^J = P, P^(J^-1) = P, Q^A =: Q*V, Q^(A^-1) = Q*V^-1, Q^B = Q, Q^(B^-1) = Q, Q^C =: Q*W, Q^(C^-1) = Q*W^5*E1*S1, Q^D = Q*F1, Q^(D^-1) = Q*F1^5, Q^E = Q, Q^(E^-1) = Q, Q^F = Q*D1*O1*Q1^2, Q^(F^-1) = Q*D1*O1*Q1, Q^G = Q*F1^5, Q^(G^-1) = Q*F1, Q^H = Q*N1, Q^(H^-1) = Q*N1, Q^I = Q*Q1^2, Q^(I^-1) = Q*Q1, Q^J = Q, Q^(J^-1) = Q, R^A =: R*X, R^(A^-1) = R*X*K1, R^B = R*I1, R^(B^-1) = R*I1, R^C =: R*Y, R^(C^-1) = R*Y*L1, R^D = R, R^(D^-1) = R, R^E = R, R^(E^-1) = R, R^F = R*I1, R^(F^-1) = R*I1, R^G = R*H1, R^(G^-1) = R*H1, S^A = S*G1*L1^2, S^(A^-1) = S*G1*L1, S^B =: S*Z, S^(B^-1) = S*Z, S^C = S*M1^2*O1, S^(C^-1) = S*M1*O1, S^D = S*D1*O1*Q1^2, S^(D^-1) = S*D1*O1*Q1, S^E = S*I1, S^(E^-1) = S*I1, S^F = S*J1, S^(F^-1) = S*J1, S^G = S*O1, S^(G^-1) = S*O1, T^A = T, T^(A^-1) = T, T^B = T*A1^2*K1^2*N1, T^(B^-1) = T*A1*K1*N1, T^C = T, T^(C^-1) = T, T^D = T*C1^2*R1, T^(D^-1) = T*C1^4*R1, T^E = T*K1^2, T^(E^-1) = T*K1, T^F = T*L1, T^(F^-1) = T*L1^2, T^G = T*P1^2, T^(G^-1) = T*P1, U^A =: U*A1, U^(A^-1) = U*A1^2*K1, U^B = U, U^(B^-1) = U, U^C =: U*B1, U^(C^-1) = U*B1^2*M1*O1, U^D = U, U^(D^-1) = U, U^E = U, U^(E^-1) = U, U^F = U, U^(F^-1) = U, U^G = U*Q1^2, U^(G^-1) = U*Q1, V^A = V, V^(A^-1) = V, V^B = V, V^(B^-1) = V, V^C = V*C1, V^(C^-1) = V*C1^5*P1, V^D = V*R1, V^(D^-1) = V*R1^5, V^E = V, V^(E^-1) = V, V^F = V*N1, V^(F^-1) = V*N1, V^G = V*R1^5, V^(G^-1) = V*R1, W^A =: W*C1, W^(A^-1) = W*C1^5, W^B =: W*D1, W^(B^-1) = W*D1, W^C =: W*E1, W^(C^-1) = W*E1^2*S1, W^D =: W*F1, W^(D^-1) = W*F1^5, W^E = W*N1, W^(E^-1) = W*N1, W^F = W*O1*Q1, W^(F^-1) = W*O1*Q1^2, W^G = W*S1, W^(G^-1) = W*S1, X^A = X, X^(A^-1) = X, X^B = X, X^(B^-1) = X, X^C = X*G1, X^(C^-1) = X*G1, X^D = X, X^(D^-1) = X, Y^A =: Y*G1, Y^(A^-1) = Y*G1, Y^B = Y*I1, Y^(B^-1) = Y*I1, Y^C = Y, Y^(C^-1) = Y, Y^D =: Y*H1, Y^(D^-1) = Y*H1, Z^A =: Z*I1, Z^(A^-1) = Z*I1, Z^B = Z, Z^(B^-1) = Z, Z^C =: Z*J1, Z^(C^-1) = Z*J1, Z^D = Z, Z^(D^-1) = Z, A1^A =: A1*K1, A1^(A^-1) = A1*K1^2, A1^B = A1, A1^(B^-1) = A1, A1^C = A1*L1, A1^(C^-1) = A1*L1^2, A1^D = A1, A1^(D^-1) = A1, B1^A =: B1*L1, B1^(A^-1) = B1*L1^2, B1^B = B1, B1^(B^-1) = B1, B1^C =: B1*M1, B1^(C^-1) = B1*M1^2, B1^D = B1*Q1, B1^(D^-1) = B1*Q1^2, C1^A = C1, C1^(A^-1) = C1, C1^B =: C1*N1, C1^(B^-1) = C1*N1, C1^C = C1*P1, C1^(C^-1) = C1*P1^2, C1^D = C1*R1, C1^(D^-1) = C1*R1^5, D1^A = D1, D1^(A^-1) = D1, D1^B = D1, D1^(B^-1) = D1, D1^C =: D1*O1, D1^(C^-1) = D1*O1, D1^D = D1, D1^(D^-1) = D1, E1^A =: E1*P1, E1^(A^-1) = E1*P1^2, E1^B =: E1*Q1, E1^(B^-1) = E1*Q1^2, E1^C = E1, E1^(C^-1) = E1, E1^D = E1, E1^(D^-1) = E1, F1^A =: F1*R1, F1^(A^-1) = F1*R1^5, F1^B = F1, F1^(B^-1) = F1, F1^C =: F1*S1, F1^(C^-1) = F1*S1, F1^D = F1, F1^(D^-1) = F1 > # Class : 8 # Nr of generators of each class : 4 3 3 3 4 6 9 13
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clc disp("Example 4.79") printf("\n") disp("calculate transconductance of JFET") printf("Given\n") //voltage gain Av=20 //drain resistance Rd=3.3*10^3 //transconductance gm=Av/Rd printf("Transconductance of JFET \n%f (1/ohm)\n",gm)
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("4x²+64y²").substitute({x=>(x+1)/2,y=>(y-1)/8}) = 2x+x²-2y+y²+2
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//Caption:Scilab code that performs threshold operation //Fig5.16 //page 254 clc; close; a = imread('E:\Digital_Image_Processing_Jayaraman\Chapter5\lena.png'); a = rgb2gray(a); [m n] = size(a); t = input('Enter the threshold parameter'); for i = 1:m for j = 1:n if(a(i,j)<t) b(i,j)=0; else b(i,j)=255; end end end figure(1) ShowImage(a,'Original Image'); title('Original Image') figure(2) ShowImage(b,'Thresholded Image'); title('Thresholded Image') xlabel(sprintf('Threshold value is %g',t)) //Result //Enter the threshold parameter 140
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//Caption: Determine the back emf in dc shunt motor //Exam:2.20 clc; clear; close; V=220;//voltage(in V) R_a=0.7;//Armature resistance(in Ohm) R_f=200;//field resistant(in Ohm) P_1=8*10^3;//motor output power(in Watt) P_2=8*10^3/0.8;//motor input power(in Watt) I_m=P_2/V;//motor input current(in Amp) I_sh=V/R_f;//shunt field current (in Amp) I_a=I_m-I_sh;//Armature current(in Amp) E_b=V-I_a*R_a;//Back emf (in V) disp(E_b,'Back emf produced in motor(in Volts)=');
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Ex9_10.sce
clc //initialisation of variables P1=14.7 //lbf/in^2 T1=520 //R a=15 //lbm v1=(53.34*T1)/(P1*144) //ft^3/lbm V2=2.955 P=44.2 //lbm qH=800//Btu/lbm Cp=0.24 Cv=0.171//lbm T3=3333//R V3=3.17 T5=1.860 //R g=144//ft T=778//F //CALCULATIONS v2=v1/a//ft^3/lbm T2=(V2*T1)//lbf/in^2 P2=P*P1//lbf/in^2 V4=V3*V2//ft3/lbm T4=T3+T2//R T6=T4/T5//R qL=Cv*(T1-T6)//Btu/lbm Wnet=qH+qL//Btu/lbm Nth=Wnet/qH//lbf/in^2 mep=(Wnet*T)/((v1-v2)*g)//lbf/in^2 //RESULTS printf('The pressure and temperature at each point in the cycle=% flbf/in^2',mep)
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//caption:check_for_contrallability_and_observability_of_system //example 9.10.21 //page 411 A=[0 1 0;0 0 1;-6 -11 -6] B=[1 0 1]' C=[10 5 1] P=cont_mat(A,B); disp(P,"Controllability Matrix="); d=det(P) if d==0 printf("matrix is singular, so system is uncontrollable"); else printf("system is controllable"); end; P1=obsv_mat(A,C); disp(P1,"Observability Matrix="); d1=det(P1) if d1==0 printf("matrix is singular, so system is unobservable"); else printf("system is observable"); end;
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//Example 4.8.2 page 4.39 clc; clear; lamda = 850*10^-9; BER = 1*10^-9; BT=10*10^6; h= 6.625*10^-34; c= 3*10^8; Ps= 36*h*c*BT/lamda; Ps=Ps*10^12;///converting in proper format for displaying... printf("The minimum incidental optical power required id %.2f pW",Ps);
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%!test %! a = class_bug44940 (); %! b = a; %! c = a (); %! a.child = 100; %! assert (a.child, b.child); %! assert (a.child, c.child); %! c.child = 500; %! assert (a.child, b.child); %! assert (a.child, c.child);
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clc //this program is used to calculate weight of water at different places pathname=get_absolute_file_path('2_4_1.sce') filename=pathname+filesep()+'241.sci' exec(filename) mass=volume*density; printf("mass of the water = volume x density=%f lbm",mass) printf(" \n At sealevel, g=32.174 ft/s^2") g=32.174; weight=mass*g/32.174; printf(" \n weight at sealevel= %f lbf \n",weight) printf(" \n At denver, g=32.139 ft/s^2") g=32.139; weight=mass*g/32.174; printf("\n weight at denver= %f lbf",weight) //the division with 32.174 is to convert lbm.ft/s^2 to lbf
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//Example 6.3. clc format(6) alpha=0.967 IE=10 disp("The common-base d.c. current gain (alpha) is,") disp("alpha = 0.967 = IC/IE = IC/10") IC=alpha*IE disp(IC,"Therefore, IC(mA) = ") disp("The emitter current, IE = IB + IC") IB=IE-IC disp(IB,"Therefore, IB(mA) = ")
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// Exa 1.21 clc; clear; close; // Given data miu_n= 0.13;// in m^2/v-sec lip= 0.05;// in m^2/v-sec n=5*10^28/10^9;// in /m^3 q= 1.6*10^-19;// in C sigma= q*n*miu_n;// in (Ωm)^-1 disp(sigma,"The conductivity of silicon material in (Ωm)^-1 is : ")
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function cpr=c_pass2(bllst,connectmat,clkconnect,cor,corinv) // cor ; correspondance table with initial block ordering // // bllst: list with nblk elts where nblk denotes number of blocks. // Each element must be a list with 12 elements: // 1- function name (in string form if fortran routine) // 2- vector of number of inputs // 3- vector of number of ouputs // 4- vector of number of clock inputs // 5- vector of number of clock outputs // 6- vector (column) of continuous initial condition // 7- vector (column) of discrete initial condition // 8- vector (column) of real parameters // 9- vector (column) of integer parameters // 10- string: 'z' if zero-crossing, 'c' if continuous, // 'd' discrete, 'l' logical // 11- vector of size <number of clock outputs> including // preprogrammed event firing times (<0 if no firing) // or [for backward compatibility] // boolean vector: i-th entry %t if initially output is fired // 12- boolean vector (1x2): 1st entry for dependence on u, 2nd on t // // connectmat: nx4 matrix. Each row contains, in order, the block // number and the port number of an outgoing scicopath, // and the block number and the port number of the target // ingoing scicopath. // // clkconnect: same as connectmat but for clock scicopaths. // // define some constants //timer() if bllst==list() then message(['No block can be activated']) cpr=list() ok=%f; return end done=%f clkptr=1,cliptr=1,typl=[],dep_ut=[],ddep_ut=[] nblk=size(bllst) while ~done //replace all logical blocks recursively [clkptr,cliptr,typl,dep_ut,ddep_ut]=make_ptr(bllst,clkptr,cliptr,typl,.. dep_ut,ddep_ut) [ok,done,bllst,connectmat,clkconnect,typl,corinv]=paksazi(bllst,.. connectmat,clkconnect,.. corinv,clkptr,cliptr,typl,dep_ut,ddep_ut) if ~ok then cpr=list() return end end // //sort blocks by their types // 1- blocks with continuous states // 2- blocks with no states // 3- logical blocks // 4- blocks with discrete states // 5- zero crossing blocks [ind,nxblk,ncxblk,ndblk,ndcblk]=find_order_blocks(bllst) if nxblk==0 & ndcblk<>0 then message(['For using treshold, you need to have' 'a continuous system with state in your diagram.'; 'You can include DUMMY CLSS block (linear palette)' 'in your diagram.']); cpr=list() ok=%f; return end ncblk=nxblk+ncxblk; nb=ncblk+ndblk; nblk=nb+ndcblk; [bllst,connectmat,clkconnect,cor,corinv]=.. re_order_blocks(bllst,connectmat,clkconnect,cor,corinv,ind) //extract various info from bllst [lnkptr,inplnk,outlnk,clkptr,cliptr,inpptr,outptr,.. xptr,zptr,rpptr,ipptr,xc0,xd0,rpar,ipar,dep_ut,ddep_ut,.. typl,typ_r,typ_c,funs,funtyp,initexe,labels,ok]=extract_info(bllst,.. connectmat,clkconnect) if ~ok then cpr=list() return, end //form a matrix which gives destinations of each block [outoin,outoinptr]=conn_mat(inpptr,outptr,inplnk,outlnk) // // discard duplicate calls to the same block port // and group calls to different ports of the same block // to compute execution table and its pointer. [ordptr1,execlk]=discard(clkptr,cliptr,clkconnect) // Set execution scheduling tables [ordptr,ordclk,cord,iord,oord,zord,critev,ok]=scheduler(inpptr,.. outptr,clkptr,execlk,ordptr1,outoin,outoinptr); if ~ok then cpr=list() return, end //form scicos arguments izptr=ones(nblk+1,1) simtp=['scs','funs','xptr','zptr','izptr','inpptr','outptr','inplnk',.. 'outlnk','lnkptr','rpar','rpptr',.. 'ipar','ipptr','clkptr','ordptr','execlk','ordclk','cord','oord',.. 'zord','critev','ncblk','nxblk','ndblk','ndcblk','subscr','funtyp',.. 'iord','labels'] subscr=[] sim=tlist(simtp,funs,xptr,zptr,izptr,.. inpptr,outptr,inplnk,outlnk,.. lnkptr,rpar,rpptr,ipar,ipptr,clkptr,.. ordptr,execlk,ordclk,cord(:),oord(:),zord(:),.. critev(:),ncblk,nxblk,ndblk,ndcblk,subscr,funtyp,iord(:),labels); //initialize agenda [tevts,evtspt,pointi]=init_agenda(initexe,clkptr) statetp=['xcs','x','z','iz','tevts','evtspt','pointi','outtb'] outtb=0*ones(lnkptr($)-1,1) iz0=[] state=tlist(statetp,xc0,xd0,iz0,tevts,evtspt,pointi,outtb); cpr=list(state,sim,cor,corinv)
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// find output current and maximum load resistance // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 20-8, page 768 clear; clc; close; // Given data R=10*10^3;// in ohms Vin=10;// input voltage in volts Vcc=15;// in volts // Calculations iout=Vin/R;// output current in amperes Rlmax=R*((Vcc/Vin)-1);// maximum load resistance in ohms disp("Amperes",iout,"output current=") disp("ohms",Rlmax,"Maximum load resistance=") // Result // Output current is 1 mAmperes // Maximum load resistance is 5 Kohms
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//Example 9.5.1; IS_rms, I1_rms, FPF, PF and HF clc; clear; close; format('v',7) //given data : Vm=230;// in volts Ia=12;// in A pi=180; Av=200;// average load voltage in volts alfa=acosd(((Av*%pi)/(Vm*sqrt(2)))-1); Is_rms=Ia*sqrt((pi-alfa)/pi); disp( "(a)for PAC") disp(Is_rms,"(1) Is_rms(A) = ") I1_rms=((2*sqrt(2))/%pi)*Ia*cosd(alfa/2); disp(I1_rms,"(2) I1_rms(A) = ") fi=alfa/2; FPF=cosd(fi); disp(FPF,"(3) FPF(lag) = ") CDF=I1_rms/Is_rms; disp(CDF,"(4) CDF = ") PF=CDF*FPF; disp(PF,"(4) PF (lag)= ") HF=sqrt((1/CDF^2)-1); disp(HF,"(5) HF = ") Vm=230;// in volts Ia=12;// in A pi=180; Av=200;// average load voltage in volts alfa=acosd(((Av*%pi)/(2*Vm*sqrt(2)))); Is_rms=Ia*sqrt((pi-(2*alfa))/pi); disp( "(b)for SAC") disp(Is_rms,"(1) Is_rms(A) = ") I1_rms=((2*sqrt(2))/%pi)*Ia*cosd(alfa); disp(I1_rms,"(2) I1_rms(A) = ") fi=0; FPF=cosd(fi); disp(FPF,"(3) FPF = ") CDF=I1_rms/Is_rms; disp(CDF,"(4) CDF = ") //in book CDF is mentioned as DF which is wrongly mentioned PF=CDF*FPF; disp(PF,"(4) PF (lagging)= ") HF=(sqrt((1/CDF^2)-1))*100; disp(HF,"(5) HF (%) = ")
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//Driver=("Rec"); clf(); clear; //Definition des paramètres initiaux SR = 44100; B = 0.001; f = 110; TF = 1; xo = 0.1; co = 1; rp = [0.3, 0.7]; loss = [100, 10; 1000, 8]; //pas de dicretisation k=1/SR; //déclaration des paramètres gama=2*f; kappa=(2*f*sqrt(B))/%pi; N=50; // Il faut h >= sqrt(((gama^2)*(k^2)+sqrt((gama^4)*(k^4)+16*(kappa^2)*(k^2)))/2); h=1/N; ksi1=((-gama^2)+sqrt((gama^4)+4*(kappa^2)*(loss(1,1)*2*%pi)^2))/(2*kappa^2); ksi2=((-gama^2)+sqrt((gama^4)+4*(kappa^2)*(loss(2,1)*2*%pi)^2))/(2*kappa^2); sigma1=(6*log(10)/(ksi2-ksi1))*((-1/loss(1,2))+1/loss(2,2)); sigma0=(6*log(10)/(ksi2-ksi1))*((ksi2/loss(1,2)-ksi1/loss(2,2))); //création des matrices A, B et C Dxxligne=zeros(1,N-1); Dxxligne(1)=-2; Dxxligne(2)=1; Dxx=toeplitz(Dxxligne)*1/(h^2); Dxxxx=Dxx * Dxx; Id=eye(N-1,N-1); A=(1+sigma0*k)*Id-sigma1*k*Dxx; B=-2*Id-(gama^2)*(k^2)*Dxx+(kappa^2)*(k^2)*Dxxxx; C=(1-sigma0*k)*Id+sigma1*k*Dxx; //calcul de la suite U0 u0=zeros(N-1,1); i=1; while i*h <= xo u0(i)= i*h*co/xo i=i+1; end while i<=N-1 u0(i)=(co/(xo-1))*i*h+co/(1-xo) i=i+1; end //Déclaration du vecteur stockant la position de la corde au niveau des micros out=zeros(TF/k,2); temps=zeros(TF/k,1); //Calcul du premier itéré (U1) inva=inv(A); v=linspace(0,1,N+1)'; u1=-inva*(B*u0+C*u0); //Remplissage vecteur de position out(TF/k,1)=u0(floor(rp(1)/h)); out(TF/k,2)=u0(floor(rp(2)/h)); out(TF/k,1)=u1(floor(rp(1)/h)); out(2,2)=u1(floor(rp(2)/h)); //Mise à jour du vecteur temps temps(1)=0; temps(2)=k; plot(v,[0;u0;0]); xtitle("corde de guitare") clf(); plot(v,[0;u1;0]); xtitle("corde de guitare") t=2*k; c=0; // compteur im=0; // variable numérotant les images //Calcul de la suit Un while t<=TF temps(c+2)=t; u2=-inva*(B*u1+C*u0); u0=u1; u1=u2; t=t+k; //Tracé toute les 30 images if modulo(c,30)==0 drawlater; clf(); subplot(2,1,1); plot(v,[0;u2;0]); xtitle("corde de guitare") a=gca(); a.data_bounds=[0,-2 ; 1,2]; subplot(2,2,3) plot(temps,out(:,1)); xtitle("position corde micro 1") subplot(2,2,4) plot(temps,out(:,2)); xtitle("position corde micro 2") drawnow; //Enregistrement des images.gif // nom_image='image_'+string(im)+'.gif'; // winnum=winsid(); // xs2gif(winnum($),nom_image); im=im+1 end //mise à jour du vecteur position out(t/k,1)=(u2(floor(rp(1)/h)) + u2(ceil(rp(1)/h)))/2; out(t/k,2)=(u2(floor(rp(2)/h)) + u2(ceil(rp(2)/h)))/2; c=c+1; end //enregistrement son. playsnd(out(1 : size(out,1)), SR); savewave("son.wav", out(1 : size(out, 1)), SR); // Calcul de la transformée de Fourier tf_s1=fft(out(:, 1)); plot((1:size(tf_s1, 1))/TF, tf_s1);
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//Exa 5.3 clc; clear; close; //given data rho=1.06;// in kg/m^3 K=.0289; v= 18.97*10^-6;// in m^2/s Pr=0.696; V=2.2;// in m/s L=0.9;// in m B=0.45;// in m t_infinite= 30;// in degree C t_s=90;// in degree C //(a) For first half of the plate x=L/2;// in m Re=V*x/v; // Nu = h*x/K = 0.664*Re^(1/2)*Pr^(1/3) h= 0.664*Re^(1/2)*Pr^(1/3)*K/x;// in W/m^2 degree C A=x*B; Q1=h*A*(t_s-t_infinite);// in watt disp(Q1,"Heat transfer rate from first half of the plate in watt"); //(b) Heat transfer from entire plate x=L;// in m Re=V*x/v; // Nu = h*x/K = 0.664*Re^(1/2)*Pr^(1/3) h= 0.664*Re^(1/2)*Pr^(1/3)*K/x;// in W/m^2 degree C A=L*B; Q2=h*A*(t_s-t_infinite);// in watt disp(Q2,"Heat transfer rate from entire plate in watt"); //(c) From next half of the plate Q3= Q2-Q1; disp(Q3,"Heat transfer rate from next half of the plate")
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MW=461;//molecular weight of lead iodide in grams// CR1=3000;//initial count rate in count per minute// CR2=900;//final count rate in count per minute// CR=CR1-CR2; printf('The count for lead iodide as absorbed=CR=%fcount per minute',CR); printf('\nThe ratio of weights of lead iodide and radio lead iodide in solution is equal to that of the same ratio on surface'); printf('\nWeight of lead iodide in solution=0.0014grams'); printf('\nWeight of radio lead iodide is proportional to the count.\nWeight of lead iodide on the surface=0.0014*21/9.\nMolecular weight of lead iodide=461.\nArea of the surface per gram=4266cm^2 g^-1');
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## Test the split command set echo set interactive set quiet read <mergeinfo.svn :6 split at 2 prefer git inspect
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function t=cos2txt(scs_m,count) //Generate a vector of strings containing scilab instructions whose evaluation //returns the value of scicos data structure scs_m. [lhs,rhs]=argn(0) if rhs<2 then count=0, lname='scs_m' else count=count+1 lname='scs_m_'+string(count) end bl=' ' lmax=80-3*count t=lname+'=list()' t1=sci2exp(scs_m(1),lmax); t=[t;lname+'(1)='+t1(1);t1(2:$)] for k=2:size(scs_m) o=scs_m(k) if o(1)=='Block' then model=o(3) if model(1)=='super'| model(1)=='csuper' then t1=cos2txt(o,count) t=[t;bl(ones(t1))+t1;lname+'('+string(k)+')='+'scs_m_'+string(count+1)] else lhs=lname+'('+string(k)+')=' t1=sci2exp(o,lmax-length(lhs)) bl1=' ';bl1=part(bl1,1:length(lhs)) n1=size(t1,1) t=[t;lhs+t1(1);bl1(ones(n1-1,1))+t1(2:$)] end else lhs=lname+'('+string(k)+')=' t1=sci2exp(o,lmax-length(lhs)) bl1=' ';bl1=part(bl1,1:length(lhs)) n1=size(t1,1) t=[t;lhs+t1(1);bl1(ones(n1-1,1))+t1(2:$)] end end
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function []=kmapsx(k) // this fnctions prints the minimied expression for the given kmap . // it requires noof.sci //so the above mentioned function shoub be execute before executing this function . n=4; k(:,:,2)=zeros(n,n); var=['X2' 'X3' 'S' 'X1']; p1=['X2''X3''' 'X2''X3' 'X2X3' 'X2X3''']; p2=['S''X1''';'S''X1';'SX1';'SX1''']; cmn4=4; cmn2=2; temp=1; disp(k(:,:,1)); disp("is :"); disp(" ") //checking the 16 cells case for i=1:n for j=1:n if(k(i,j)~=1) temp=0; break; end end end printf(' '); if(temp==1) printf("1"); abort; end //checking the 8 cells cases z1=ones(2,4); z2=ones(4,2); temp1=['00' '01' '11' '10']; temp2=temp1'; for i=1:n if(i==4) t=1; else t=i+1; end z=[k(i,:,1);k(t,:,1)]; if(z==z1) k(i,:,2)=[1 1 1 1]; k(t,:,2)=[1 1 1 1]; a=strsplit(temp2(i,1)); b=strsplit(temp2(t,1)); c=strcmp(a,b); for in=1:max(size(c)) if(c(in)==0 & a(in)=='0') printf('%s''',var(in)); printf(' + '); break; else if(c(in)==0 & a(in)=='1') printf(var(in)); printf(' + '); break; end end end end end for j=1:n if(j==4) t=1; else t=j+1; end z=[k(:,j,1) k(:,t,1)]; if(z==z2) k(:,j,2)=[1;1;1;1]; k(:,t,2)=[1;1;1;1]; a=strsplit(temp1(1,j)); b=strsplit(temp1(1,t)); c=strcmp(a,b); for in=1:max(size(c)) if(c(in)==0 & a(in)=='0') printf('%s''',var(2+in)); printf(' + '); break; else if(c(in)==0 & a(in)=='1') printf(var(2+in)); printf(' + '); break; end end end end end //checking the 4 cells cases z1=ones(1,4); z2=ones(4,1); z3=ones(2,2); temp1=['00' '01' '11' '10']; temp2=temp1'; for t=1:n z=k(t,:,1); no=noof(k(t,:,2)); if(z==z1 & no<cmn4) k(t,:,2)=z1; a=strsplit(temp1(1,t)); for in=1:max(size(a)) if(a(in)=='0') printf('%s''',var(in)); end if(a(in)=='1') printf(var(in)); end end printf(" + "); end end for t=1:n z=k(:,t,1); no=noof(k(:,t,2)); if(z==z2 & no<cmn4) k(:,t,2)=z2; a=strsplit(temp2(t,1)); for in=1:max(size(a)) if(a(in)=='0') printf('%s''',var(2+in)); end if(a(in)=='1') printf(var(2+in)); end end printf(" + "); end end for i=1:n for j=1:n if(i==n) t1=1; else t1=i+1; end if(j==n) t2=1; else t2=j+1; end z4=[k(i,j,1) k(i,t2,1);k(t1,j,1) k(t1,t2,1)]; z5=[k(i,j,2) k(i,t2,2);k(t1,j,2) k(t1,t2,2)]; no=noof(z5); if(z4==z3 & no<cmn4) k(i,j,2)=1; k(i,t2,2)=1; k(t1,j,2)=1; k(t1,t2,2)=1; a=strsplit(temp2(i,1)); b=strsplit(temp2(t1,1)); c=strcmp(a,b); for in=1:max(size(c)) if(c(in)==0 & a(in)=='0') printf('%s''',var(in)); end if(c(in)==0 & a(in)=='1') printf(var(in)); end end a=strsplit(temp1(1,j)); b=strsplit(temp1(1,t2)); c=strcmp(a,b); for in=1:max(size(c)) if(c(in)==0 & a(in)=='0') printf('%s''',var(2+in)); end if(c(in)==0 & a(in)=='1') printf(var(2+in)); end end printf(" + "); end end end //checking all the 2 cells cases z6=[1 1]; z7=z6'; for i=1:n for j=1:n if(i==n) t1=1; else t1=i+1; end if(j==n) t2=1; else t2=j+1; end z8=[k(i,j,1) k(i,t2,1)]; z9=[k(i,j,2) k(i,t2,2)]; no1=noof(z9); if(z8==z6 & no1<cmn2 ) k(i,j,2)=1; k(i,t2,2)=1; a=strsplit(temp1(1,j)); b=strsplit(temp1(1,t2)); c=strcmp(a,b); for in=1:max(size(c)) if(c(in)==0 & a(in)=='0') printf(p1(1,i)); printf('%s''',var(2+in)); printf(" + "); end if(c(in)==0 & a(in)=='1') printf(p1(1,i)); printf(var(2+in)); printf(" + "); end end end end end for i=1:n for j=1:n if(i==n) t1=1; else t1=i+1; end if(j==n) t2=1; else t2=j+1; end z10=[k(i,j,1);k(t1,j,1)]; z11=[k(i,j,2);k(t1,j,2)]; no2=noof(z11); if(z10==z7 & no2<cmn2) k(i,j,2)=1; k(t1,j,2)=1; a=strsplit(temp2(i,1)); b=strsplit(temp2(t1,1)); c=strcmp(a,b); for in=1:max(size(c)) if(c(in)==0 & a(in)=='0') printf(p2(j,1)); printf('%s''',var(in)); printf(" + "); end if(c(in)==0 & a(in)=='1') printf(p2(j,1)); printf(var(in)); printf(" + "); end end end end end // checking all the single cell cases for i=1:n for j=1:n if(k(i,j,2)==0 & k(i,j,1)==1) a=strsplit(temp1(1,j)); b=strsplit(temp2(i,1)); for in=1:max(size(a(:,1))) if(a(in,1)=='1') printf(var(in+2)); else if(a(in,1)=='0') printf('%s''',var(2+in)); end end end for in=1:max(size(b(:,1))) if(b(in,1)=='1') printf(var(in)); else if(b(in,1)=='0') printf('%s''',var(in)); end end end if(i~=4 & j~=4) printf(" + "); end end end end printf("0"); endfunction
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clc clear //INPUT DATA ta1=15;//dry bulb temperature in Degree c ta2=25;//dry bulb temperature in Degree c tw1=13;//wet bulb temperature in Degree c tw2=18;//wet bulb temperature in Degree c V1=30;//volume of air in m^3/min V2=12;//volume of air in m^3/min pva=11.22;//Saturation pressure in mm Hg pvb=15.461;//Saturation pressure in mm Hg p=760;//pressure in mm of Hg cp=1.005;//specific pressure //CALCULATIONS pv1=(pva-((p-pva)*(ta1-tw1)*1.8/(2800-1.3*(1.8*ta1+32))));//Saturation pressure in mm Hg w1=0.622*(pv1/(p-pv1));//Specific humidity in kg w.v./kg d.a pv2=pvb-((p-pvb)*(ta2-tw2)*1.8/(2800-(1.3*(1.8*ta2+32))));//Saturation pressure in mm Hg w2=0.622*(pv2/(p-pv2));//Specific humidity in kg w.v./kg d.a h1=cp*ta1+w1*(2500+1.88*ta1);//Enthalpy of air per kg of dry air in kJ/kg d.a h2=cp*ta2+w2*(2500+1.88*ta2);//Enthalpy of air per kg of dry air in kJ/kg d.a ma1=V1/0.827;//Dry mass flow rate in kg d.a./min ma2=V2/0.8574;//Dry mass flow rate in kg d.a./min ma3=ma1+ma2;//Dry mass flow rate in kg d.a./min w3=((ma1*w1)+(ma2*w2))/ma3;//Specific humidity in kg w.v./kg d.a h3=((ma1*h1)+(ma2*h2))/(ma3);//Enthalpy of air per kg of dry air in kJ/kg d.a ta3=((ma1*ta1)+(ma2*ta2))/(ma3);//dry bulb temperature in Degree c tw3=((ma1*tw1)+(ma2*tw2))/(ma3);//wet bulb temperature in Degree c //OUTPUT printf('(i)The specific humidity of the mixture is %3.4f kg w.v./kg d.a \n (ii)Specific enthalpy of the mixture is %3.2f kJ/kg d.a. \n (iii)DBT corresponds to mixture is %3.3f Degree C \n (iv)WBT corresponds to mixture is %3.3f Degree C ',w3,h3,ta3,tw3)
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function c = coefs_multi_step(x, degree) // solve system Mc=e // x é pontos do tempo. xn = 0 e são espaçados de h=1 (e.g. 0, -1, -2 ...) // degree é a diferença de passo entre o lado esquerdo e direito da eq // deg = 2 para un+2 = un + h(....) por exemplo // get size of the system n = size(x,2) // create M and c M = zeros(n, n) e = zeros(n, 1) // fill M and c for i = 1:n for j = 1:n M(i,j) = x(j)^(i-1) end e(i) = (degree)^i/i end //solve Mc=e c = inv(M)*e endfunction function c = coefs_finite_difs(xstar, x) // solve system Mc=e // x é pontos do tempo que influenciam o calculo da derivada (espaçados de h=1) // xstar é o ponto onde a derivada é calculada // get size of the system n = size(x,2) // create M and c M = zeros(n, n) e = zeros(n, 1) // fill M and c for i = 1:n for j = 1:n M(i,j) = x(j)^(i-1) end if (xstar == 0 && (i-2) < 0) then e(i) = 0 else e(i) = (i-1)*xstar^(i-2) end end //solve Mc=e c = inv(M)*e endfunction function c = coefs_finite_difs_2(xstar, x) // solve system Mc=e // x é pontos do tempo que influenciam o calculo da derivada (espaçados de h=1) // xstar é o ponto onde a derivada é calculada // get size of the system n = size(x,2) // create M and c M = zeros(n, n) e = zeros(n, 1) // fill M and c for i = 1:n for j = 1:n M(i,j) = x(j)^(i-1) end if (xstar == 0 && (i-2) < 0) then e(i) = 0 else e(i) = (i-1)*xstar^(i-2) end end //adapt to grau 2 M_ = M M(1,:) = 0 for i = 2:n M(i,:) = M_(i-1, :) end for i = 1:n M(i,:) = M(i,:) * (i-1) e(i) = e(i) * (i-1) end disp(M) disp(e) //solve Mc=e c = inv(M)*e endfunction
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 7 : SPECIAL MOTORS AND INTRODUCTION TO GENERALIZED MACHINE THEORY // EXAMPLE : 7.6 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA R = 1.4; // Total Resistance of the AC series motor in Ohms V = 115; // supply voltage in Volts f = 50; // Frequency in Hertz N = 5000; // Rotating speed in RPM X = 12; // Total reactance in Ohms P = 250; // Electrical power output in Watts loss = 18; // Rotational losses in Watts // CALCULATIONS Pd = P + loss; // Mechanical power developed in Watts // We know that Er = Pd/I and from phasor diagram in figure 7.11 page no. 501 V^2 = (Er+I*R)^2+(I*X)^2, 115^2 = (268/I-1.4*I)^2+(12*I)^2, 13225*I^2 = 71824+2.036*I^4-750.4*I^2+144*I^2, solving this we get 2.036*I^4-13831.4*I^2+71824 = 0, I^4-6793.42*I^2+3577 = 0 this gives I = 2.28A or 82.38A (The above calculation part is wrong ) i = poly ([3577 0 -6793.42 0 1],'x','coeff'); // Expression for the Current in Quadratic form a = roots (i); // 4-Value of the current in Amphere I = a(4,1); // Curent in Amphere neglecting higher value and negative value pf_a = sqrt(1-((I*X)/V)^2); // Power factor lagging Er_a = sqrt(V^2-(I*X)^2)-(I*R); // Rotational Voltage in Volts T_a = (Er_a*I)/(2*%pi*N/60); // Developed torque in Newton-meter Ih = I/2; // Current halved in Amphere pf_b = sqrt(1-((Ih*X)/V)^2); // Power factor lagging when load current halved Er_b = sqrt(V^2-(Ih*X)^2)-(Ih*R); // Rotational Voltage in Volts when load current halved N2 = (N*Er_b*I)/(Er_a*Ih); // New speed in RPM when load current halved T_b = (Er_b*Ih)/(2*%pi*N2/60); // Developed torque in Newton-meter when load current halved eta = 100*(Er_b*Ih)/(V*Ih*pf_b); // Efficiency when load current halved // DISPLAY RESULTS disp("EXAMPLE : 7.6: SOLUTION :-"); printf("\n At rated condition, \n\n (a.1) Current, I = %.2f A \n",I) printf("\n (a.2) Power factor = %.3f lagging \n",pf_a) printf("\n (a.3) Developed torque = %.2f N-m \n",T_a) printf("\n When load current halved (reduced to half), \n\n (b.1) Speed, N2 = %.f RPM \n",N2) printf("\n (b.2) Power factor = %.4f lagging \n",pf_b) printf("\n (b.3) Developed torque = %.2f N-m \n",T_b) printf("\n (b.4) Efficiency = %.1f percenatge \n",eta) printf("\n From Calculation of the Current(I), rest all the Calculated values in the TEXT BOOK is WRONG because of the Current equation and its value both are WRONGLY calculated and the same used for the further Calculation part, so all the values are in the TEXT BOOK IS WRONG \n")
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mode(-1); global temp heat fan m x sampling_time heatdisp fandisp tempdisp sampling_time=0.5;//Enter Smpling time m=1; function temp = ramp_test(heat,fan) global m x sampling_time heatdisp fandisp tempdisp writeserial(handl,ascii(254)); //Input Heater, writeserial accepts strings; so convert 254 into its string equivalent writeserial(handl,ascii(heat)); writeserial(handl,ascii(253)); //Input Fan writeserial(handl,ascii(fan)); writeserial(handl,ascii(255)); //To read Temp sleep(100); temp = ascii(readserial(handl)); // Read serial returns a string, so convert it to its integer(ascii)equivalent temp = temp(1) + 0.1*temp(2); // convert to temp with decimal points eg: 40.7 x=ceil(1/sampling_time); //disp('not plotting') //disp(modulo(m,x)) //disp(x,'x=',m,'m=') if (modulo(m,x) == 1) //disp('plotting') heatdisp=[heatdisp;heat]; subplot(311); xtitle("Step Test","Time(seconds)","Heat in percentage") plot2d(heatdisp,rect=[0,0,1000,100],style=1) fandisp=[fandisp;fan]; subplot(312); xtitle("","Time(seconds)","Fan in percentage") plot2d(fandisp,rect=[0,0,1000,100],style=2) tempdisp=[tempdisp;temp]; subplot(313) xtitle("","Time(seconds)","Temperature (deg celcius)") plot2d(tempdisp,rect=[0,20,1000,60],style=5) end m=m+1; endfunction
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exemplo_grafico_dados_informados_pelo_utilizador.sce.txt
//Este programa solicita um conjunto de valores de entrada para o utilizador, e fornece a opção de escolha de uma em três funções, a desenhar com base na função escolhida um gráfico para visualização dos valores informados. O programa também fornece a opção de desenhar na mesma janela gráfica as representações gráficas do mesmo conjunto de valores aplicado às três funções suportadas. Além da visualização das funções a utilizar uma projeção bidimensional (2D), é possível visualizar o conjunto de valores informados por meio de uma projeção tridimensional (3D), a qual utiliza a funçãp z = 2x -y^2 como suporte para a especificação da profundidade (altura) associada à projeçãp 3D a ser apresentada. //Esta função representa a função matemática y = 2x^2 -5. function y = f(x) y = 2 * x.^2 - 5 endfunction //Esta função representa a função matemática y = e^x -2 function y = g(x) y = %e.^x - 2 endfunction //Esta função representa a função matemática y = (e^x - 3)/5 function y = h(x) y = (%e.^x -3)/5 endfunction //Esta função representa a função matemática z = 2x -y^2 function z = profundidade(x,y) z = 2*x -y.^2 endfunction /* Alternativa à utilização conjunta das funções calculaProjecao2DInterna() e calcularFuncaoProjecao2D(). //Esta função realiza o cálculo dos valores do eixo y para a função(ões) de projeção 2D selecionada(s). A estratégia de execução adotada utiliza recursividade para executar todas as funções de projeção 2D em uma única invocação [opcaoUnitaria == 4]. function [opcaoUnitaria,varargout]=calcularFuncaoProjecao2D(opcaoUnitaria, x) select opcaoUnitaria case 1 then varargout(1) = f(x) case 2 then varargout(1) = g(x) case 3 then varargout(1) = h(x) case 4 then for i=1:3 [opcaoUnitariaInterna,varargout(i)]=calcularFuncaoProjecao2D(i,x) end end endfunction */ /*Esta função é uma função utilitária, a qual permite o cálculo dos valores do eixo y para cada uma das funções de projeção 2D suportadas: f(x) = 2x^2 - 5 [opcaoUnitaria == 1] g(x) = e^x -2 [opcaoUnitaria == 2] h(x) = (e^x - 3)/5 [opcaoUnitaria == 3] A função calculaProjecao2DInterna() assume que o conjunto de valores [i.e. vetor x] utilizado para os cálculos já está previamente definido, a implicar sua invocação por intermédio da função calcularFuncaoProjecao2D(). */ function y=calculaProjecao2DInterna(opcaoUnitaria) select opcaoUnitaria case 1 then y = f(x) case 2 then y = g(x) case 3 then y = h(x) else y = -1 end endfunction //Esta função realiza o cálculo dos valores do eixo y para a função(ões) de projeção 2D selecionada(s). A estratégia de execução adotada utiliza a função utilitária calculaProjecao2DInterna(), a qual é executada iterativamente para executar todas as funções de projeção 2D em uma única invocação [opcaoUnitaria == 4]. function [opcaoUnitaria,varargout]=calcularFuncaoProjecao2D(opcaoUnitaria, x) if opcaoUnitaria > 0 && opcaoUnitaria < 4 then varargout(1) = calculaProjecao2DInterna(opcaoUnitaria) elseif opcaoUnitaria == 4 for i = 1:3 varargout(i) = calculaProjecao2DInterna(i) end end endfunction /*Esta função permite o desenho de gráficos associados às projeções gráficas de uma das funções de projeção 2D a seguir: f(x) = 2x^2 - 5 g(x) = e^x -2 h(x) = (e^x - 3)/5 A função recebe os seguintes argumentos de entrada: limpa -> indica se a janela gráfica deve ser limpa antes de realizar a projeção desejada. limpa == %t (verdadeiro) para realizar a limpeza; limpa == %f (falso) caso contrário; linhas -> indica o número de linhas necessárias para o desenho de diferentes projeções na mesma janela gráfica; colunas -> indica o número de colunas necessárias para o desenho de diferentes projeções na mesma janela gráfica; coluna -> indica qual a coluna utilizada para o desenho da projeção desejada; opcaoDimensional -> indica qual o tipo de projeção a ser desenhada. opcaoDimensional == 2 para realizar o desenho de uma projeção 2D (função plot); opcaoDimensional = 3 para realizar o desenho de uma projeção 3D (função mesh a utilizar a função de projeção 3D z=x^2 + y^2); varargin -> indica os conjuntos de dados utilizados para o desenho a projeção gráfica desejada, bem como um possível título da projeção a ser desenhada. Os conjuntos de dados devem ser informados na seguinte ordem: x -> y -> z, onde x representa o vetor/matriz de valores a ser projetado no eixo X; y representa o vetor/matriz de valores a ser projetado no eixo Y; e z representa o vetor/matriz de valores a ser projetado no eixo Z. O conjunto de caracteres para definir o título do gráfico a ser desenhado é informado como último argumento de entrada variável da função. */ function desenhaProjecao(limpa,linhas,colunas,coluna,opcaoDimensional,varargin) if limpa == %t then clf() end subplot(linhas,colunas,coluna) if opcaoDimensional == 2 then plot(varargin(1),varargin(2)) elseif opcaoDimensional == 3 mesh(varargin(1), varargin(2), varargin(3)) end if (opcaoDimensional+1) == length(varargin) then title(string(varargin(opcaoDimensional+1))) end endfunction /*Esta função permite o desenho de gráficos associados às projeções gráficas de uma das funções de projeção 2D a seguir: f(x) = 2x^2 - 5 g(x) = e^x -2 h(x) = (e^x - 3)/5 A função recebe os seguintes argumentos de entrada: opcaodimensional -> vetor a indicar qual projeção será deenhada para cada uma das funções. Cada elemento do vetor pode assumir um dos seguintes valores: 2 -> 2D; 3 -> 3D; linhas -> indica o número de linhas necessárias para o desenho de diferentes projeções na mesma janela gráfica; pares -> indica se o conjunto de dados utilizado para realizar as projeções é invocado aos pares. %t (verdadeiro) caso o conjunto de dados seja informado aos pares; %f (falso) caso o conjunto de dados utilize um único conjunto de valores no eixo X para as múltiplas projeções realizadas; titulos -> indica títulos, os quais podem ser incluídos nos gráficos a representar as projeções desenhadas; varargin -> indica os conjuntos de dados utilizados para o desenho da(s) projeção(ões) gráfica(s) desejada(s), Os conjuntos de dados devem ser informados na seguinte ordem: x -> y, onde x representa o vetor/matriz de valores a ser projetado no eixo X; e y representa o vetor/matriz de valores a ser projetado no eixo Y. O conjunto de valores a ser projetado no eixo Z é calculado com base na função de profundidade (altura) z = 2x -y^2. */ function desenhaProjecoes(opcaoDimensional,linhas, pares,titulos, varargin) incremento = 1 inicio = 1 limpa = %t numeroProjecoes = 1 if pares == %t then incremento = 2 numeroProjecoes = length(varargin)/2 elseif pares == %f numeroProjecoes = length(varargin) - 1 end for i =inicio:incremento:length(varargin) - 1 indiceProjecao = getIndiceProjecao(pares,i,incremento) if opcaoDimensional(indiceProjecao) == 3 then if pares == %t then [matrixX,matrixY] = meshgrid(varargin(i),varargin(i+1)) else [matrixX,matrixY] = meshgrid(varargin(1),varargin(i+1)) end matrixZ = profundidade(matrixX, matrixY) desenhaProjecao(limpa,linhas,numeroProjecoes,indiceProjecao,opcaoDimensional(indiceProjecao),matrixX, matrixY, matrixZ,getTitulo(titulos,indiceProjecao)) elseif opcaoDimensional(indiceProjecao) == 2 if incremento == 1 then desenhaProjecao(limpa,linhas,numeroProjecoes,indiceProjecao,opcaoDimensional(indiceProjecao),varargin(1), varargin(i+1),getTitulo(titulos,indiceProjecao)) else desenhaProjecao(limpa,linhas,numeroProjecoes,indiceProjecao,opcaoDimensional(indiceProjecao),varargin(i), varargin(i+1),getTitulo(titulos,indiceProjecao)) end end limpa = %f end endfunction //Esta função retorna o índice da projeção a ser realizada, o qual é utilizado para a obtenção do tipo de projeção e para definição da posição de desenho da projeção. function indiceProjecao=getIndiceProjecao(pares,i,incremento) if pares == %t && i > 1 then indiceProjecao = i - floor(i/incremento) else indiceProjecao = i end endfunction //Esta função retorna o título correspondente ao indice informado. Caso o índice não existe, o título retornado é um conjunto de caracteres vazio. function titulo=getTitulo(titulos,indice) if length(titulos) >= indice then titulo = titulos(indice) else titulo = "" end endfunction continuar = 'sim' while continuar == 'sim' x = input("Informe o conjunto de valores [vetor] a ser utilizado para o desenho do(s) gráfico(s) da(s) função(ões) selecionada(s): ") mprintf("Selecione a função de projeção 2D para desenho do(s) gráfico(s): \n 1 - y=2x^2 - 5\n 2 - y=e^x -2\n 3 - y = (e^x - 3)/5\n 4 - todas\n") opcaoUnitaria=input("Valor Selecionado: ") opcaoDimensional = input("Deseja realizar a(s) projeção(ões) em 2D ou em 3D (projeção com z = 2x - y^2) [2 - 2D; 3 - 3D]? ") titulos = input("Informe um vetor com o(s) título(s) para o(s) gráfico(s) [Pressione enter no caso de não possuir títulos]: ") if opcaoUnitaria > 0 && opcaoUnitaria < 4 then [opcaoUnitaria,y] = calcularFuncaoProjecao2D(opcaoUnitaria, x) desenhaProjecoes(opcaoDimensional,linhas=1,pares=%t,titulos,x,y) elseif opcaoUnitaria == 4 [opcaoUnitaria,fY,gY,hY] = calcularFuncaoProjecao2D(opcaoUnitaria, x) desenhaProjecoes(opcaoDimensional,linhas=1,pares=%f,titulos,x,fY,gY,hY) end continuar = input("Deseja continuar a realizar projeções? [sim/nao]: ", "s") end mprintf("Tenha um bom dia :-D")
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Ex4_16.sce
//problem 16 pagenumber 4.44 //given fs=1e6;//hz format(6); n=8; tc=(1/fs)*(n+1); disp('Conversion time = '+string(tc*10^6)+' μs');
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load ZN16.hdl, output-file ZN16.out, compare-to ZN16.cmp, output-list x%B1.16.1 zx%B1.1.1 nx%B1.1.1 out%B1.16.1; set x %B0000000000000000, // x = 0 set zx 0, set nx 0, eval, output; set zx 1, set nx 0, eval, output; set zx 0, set nx 1, eval, output; set zx 1, set nx 1, eval, output; set x %B1111111111111111, // x = 0 set zx 0, set nx 0, eval, output; set zx 1, set nx 0, eval, output; set zx 0, set nx 1, eval, output; set zx 1, set nx 1, eval, output; set x %B1010101010101010, // x = 0 set zx 0, set nx 0, eval, output; set zx 0, set nx 0, eval, output; set zx 1, set nx 0, eval, output; set zx 0, set nx 1, eval, output; set zx 1, set nx 1, eval, output; set x %B1111111100000000, // x = 0 set zx 0, set nx 0, eval, output; set zx 1, set nx 0, eval, output; set zx 0, set nx 1, eval, output; set zx 1, set nx 1, eval, output;
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Ex12_3.sce
clc; //page 609 //problem 12.3 //Baseband cutoff signal fM = 4 kHz fM = 4 * 10^3; //White noise power spectral density n n = 2*10^(-9); // Part (a) //Input Signal energy Si = 0.001 Si = 0.001; //No of levels used for PCM Coding M = 8 M = 8; N = log2(M); //Input SNR is SNR_ip SNR_ip = Si/(n*fM); //Output SNR is SNR_op SNR_op = (2^(2*N))/(1 + (2^(2*N + 1))*erfc((SNR_ip*(3/(10*N))))^0.5); disp('Input SNR for (a) is '+string(10*log10(SNR_ip))+' dB'); disp('Output SNR (a) is '+string(10*log10(SNR_op))+' dB'); // Part (b) //Input Signal energy Si = 0.001 Si = 0.001; //No of levels used for PCM Coding M = 256 M_b = 256; N_b = log2(M_b); //Input SNR is SNR_ip_b SNR_ip_b = Si/(n*fM); //Output SNR is SNR_op_b SNR_op_b = (2^(2*N_b))/(1 + (2^(2*N_b + 1))*erfc((SNR_ip_b*(3/(10*N_b))))^0.5); //Unfortunately in scilab the function erfc approximates the output value to a larger extent due to which an exact value cannot be obtained. //The difference in the textbook answer and obatined answer is significant because of converting the answer into dB. disp('Input SNR for (b) is '+string(10*log10(SNR_ip_b))+' dB'); disp('Output SNR for (b) is '+string(10*log10(SNR_op_b))+' dB'); // Part (c) //Input Signal energy Si = 0.01 Si = 0.01; //No of levels used for PCM Coding M = 256 M = 256; N = log2(M); //Input SNR is SNR_ip_c SNR_ip_c = Si/(n*fM); //Output SNR is SNR_op_c SNR_op_c = (2^(2*N))/(1 + (2^(2*N + 1))*erfc((SNR_ip_c*(3/(10*N))))^0.5); disp('Input SNR for (c) is '+string(10*log10(SNR_ip_c))+' dB'); disp('Output SNR for (c) is '+string(10*log10(SNR_op_c))+' dB');
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clear// //Variables VCC = 30.0 //Source voltage (in volts) RC = 10.0 //Collector resistance (in kilo-ohm) RE = 8.2 //Emitter resistance (in kilo-ohm) RL = 3.3 //Load resistance (in kilo-ohm) beta = 200.0 //Common emitter current gain VBE = 0.7 //Emitter-to-Base Voltage (in volts) R1 = 47.0 //Resistance (in kilo-ohm) R2 = 15.0 //Resistance (in kilo-ohm) Vs = 5.0 //a.c voltage (in milli-volts) //Calculation Vth = VCC * R2 / (R1 + R2) //Thevenin's voltage (in volts) Rth = R1 * R2 / (R1 + R2) //Thevenin's equivalent voltage (in volts) IE = (Vth - VBE)/(RE + Rth/beta) //Emitter current (in milli-Ampere) r1e = 25.0 / IE //a.c. resistance of emitter diode (in ohm) rL = RC * RL/(RC + RL) //a.c load seen by the amplifier (in kilo-ohm) Av = rL * 10**3 / r1e //Voltage gain vo = Av * Vs //Output voltage (in volts) Ri = beta * r1e * 10**-3 //Input resistance looking directly into the base (in ohm) Ris = Rth * Ri / (Rth + Ri) //input resistance of the stage (in ohm) //Result printf("\n a.c output voltage is %0.2f mV.\nInput impedance for the circuit is %0.0f kilo-ohm.",vo,Ris)
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colorsBookvertP67.sce
//help plot2d //clf(); //x=[0:0.1:2*%pi]'; //plot2d(x,sin(x)); //multiple plot //6.1 version //xbasc() //p63 deplrecated -> clf (dep xclear) //from gree book p67 //plot2d1 deprecated ? //feature request : click a window -> all Scilab windows come foreground //.jp ri x=0:.1:2*%pi; u=[-0.8+sin(x);-0.6+sin(x);-0.4+sin(x);-0.2+sin(x);sin(x)]; u=[u;0.2+sin(x);0.4+sin(x);0.6+sin(x);0.8+sin(x)]';//self u //nothing printed plot2d('omn',x',u,[9,8,7,6,5,4,3,2,1,0],"011"," ",[0,-2,2*%pi,3],[2,10,2,10]) //KO plot2d('omn',x',u) //9 lines //plot2d(x',u);//OK //plot2d(x',u);//nothing //KO plot2d1('omn',x',u,[9,8,7,6,5,4,3,2,1,0],"011"," ",[0,-2,2*%pi,3],[2,10,2,10]) //KO variable plot2d1('omn',x',u,[9,8,7,6,5,4,3,2,1,0],"011"," ",[0,-2,2*%pi,3],[2,10,2,10])
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ex2_15.sce
// Exa 2.15 clc; clear; close; // Given data n_i = 2*10^19;// in /m^3 Miu_e = 0.36;// in m^2/v.s Miu_h = 0.17;// in m^2/v.s A = 1*10^-4;// in m^2 V = 2;// in Volts l = 0.3;// in mm l = l * 10^-3;// in m e = 1.6*10^-19;// in C Sigma_i = n_i * e * (Miu_e+Miu_h);// in mho/m I = (Sigma_i * V*A)/l;// in amp disp(I,"The current in amp is");
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errcatch(-1,"stop");mode(2);// EXa 3.2 ; ; // Given data A_F = -30; R_F = 1;// in M ohm R1 = -(R_F/A_F);// in Mohm R_i = R1;// in Mohm disp(R_i*10^3,"Input resistance in kΩ is"); exit();
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Ex6_1.sce
// To determine the distance of a 25 cp lamp for various illumination //Page 327 clc; clear; //Candle power of the lamp I=25; // Various illumination levels E1=5; //Case1 E2=15; //Case2 E3=8; //Case3 // According to the law of illumination E = I/(r^2); // Using the above equation we find the distances for the above three illuminations r1= sqrt(I/E1); r2= sqrt(I/E2); r3= sqrt(I/E3); printf('a) The distance for %g flux illumination from the normally placed screen is %g m \n',E1,r1) printf('b) The distance for %g flux illumination from the normally placed screen is %g m \n',E2,r2) printf('c) The distance for %g f.c illumination from the normally placed screen is %g ft \n',E3,r3)
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/Orchard_1.sci
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// Initialization clear mode(0); ieee(1); clearglobal; // T_wd = "E:\Laurent-AA02870\boulot\prod_sci\En_cours\Article_BEST_2K\scilab\7_BEST-DP_versus_SP"; T_wd = "C:\Users\Utilisateur\Documents\travail_maison\z_September_2018\Article_BEST_2K\scilab\7_BEST-DP_versus_SP"; T_functions = T_wd + "\BEST_functions-2"; T_data = T_wd + "\Data_files"; i_fig = 1; // Sample and conditions // names = ["Forest_1";"Forest_2";"Pasture_1";"Pasture_2";"Orchard_1";"Orchard_2"]; i0 = 5; file_name = "O_run_5"; gammaa = 0.75; betaa = 0.6; /// functions for modelling hydraulic HCWRF with vGBBC model chdir(T_functions); exec('0_general_tool_functions.sci',-1); exec('2_BEST_functions.sci',-1); exec('3_It_functions_2K.sci',-1); exec('4_HCWRF_comp.sci',-1); // nomemclature & cleanup names = ["Forest_1";"Forest_2";"Pasture_1";"Pasture_2";"Orchard_1";"Orchard_2"]; ntot = size(names,1); name = names(i0); close_windows(20); // data collection for cumulative water infiltration // Upload of hydraulic properties chdir(T_data); best_dp= read('BEST-DP.txt',-1,ntot); // units = mm & mm/s ph_m = best_dp(1:6,i0); wf = best_dp(7,i0); ph_f = best_dp(8:13,i0); best_sp = read('BEST-SP.txt',-1,ntot); // units = mm & mm/s ph_sp = best_sp(1:6,i0); // Upload of cumulative infiltration CI30_exp_table = read("I30_exp.txt",-1,2*ntot); // units = mm & mm/s CI0_exp_table = read("I0_exp.txt",-1,2*ntot); a_30 = CI30_exp_table(2:size(CI30_exp_table,1),(2*i0-1)); [a b] = min(a_30); t30_exp = CI30_exp_table(1:b,(2*i0-1)); I30_exp = CI30_exp_table(1:b,2*i0); a_0 = CI0_exp_table(2:size(CI0_exp_table,1),(2*i0-1)); // units = mm & mm/s [a b] = min(a_0); t0_exp = CI0_exp_table(1:b,(2*i0-1)); I0_exp = CI0_exp_table(1:b,2*i0); // BEST entry chdir(T_data+"\BEST_data"); best_entry = read(file_name+'.txt',-1,2); //--> data file nbl = size(best_entry,1); // number of line of data file theta0s = best_entry(2,1); // initial water content for Beerkan run [%] theta030 = best_entry(2,2); // initial water content for Tension infil. [%] theta30 = best_entry(3,1); // initial water content [%] rds = best_entry(4,1); // ring radius for Beekan exp [mm] rd30 = best_entry(4,2); // ring radius for TI 30 [mm] // Computation of hydraulic conductivity and water retention curves // water retention and hydraulic conductivity curves xh = (-logspace(-1,4,200))'; theta_m = theta_vGB(xh,ph_m(3),ph_m(1),ph_m(2),ph_m(5)); theta_f = theta_vGB(xh,ph_f(3),ph_f(1),ph_f(2),ph_f(5)); theta_dp = (1-wf)*theta_m+wf*theta_f; theta_mat = (1-wf)*theta_m; theta_sp = theta_vGB(xh,ph_sp(3),ph_sp(1),ph_sp(2),ph_sp(5)); K_m = K_vGB(ph_m(4),theta_m,ph_m(1),ph_m(2),ph_m(6)); K_f = K_vGB(ph_f(4),theta_f,ph_f(1),ph_f(2),ph_f(6)); K_dp = (1-wf)*K_m+wf*K_f; K_mat = (1-wf)*K_m; K_sp = K_vGB(ph_sp(4),theta_sp,ph_sp(1),ph_sp(2),ph_sp(6)); // determination of initial water pressure heads h0_sp = wcr_vGB(theta030,ph_sp(1),ph_sp(2),ph_sp(3),ph_sp(5)); [a b] = min(abs(theta_dp-theta030)); h0_dp = xh(b); // computation of original and final states // initial water contents and for B theta0_TI_sp = theta_vGB(h0_sp,ph_sp(3),ph_sp(1),ph_sp(2),ph_sp(5)); theta0_TI_m = theta_vGB(h0_dp,ph_m(3),ph_m(1),ph_m(2),ph_m(5)); theta0_TI_f = theta_vGB(h0_dp,ph_f(3),ph_f(1),ph_f(2),ph_f(5)); theta0_TI_dp = wf*theta0_TI_f+(1-wf)*theta0_TI_m; // prediction of water content at -30 R_theta0_TI = theta0_TI_dp/theta030; // precision of the estimate theta0_B_sp = theta0_TI_sp; theta0_B_m = theta0_TI_sp; theta0_B_f = theta0_TI_sp; // final water contents for TI thetaf_TI_sp = theta_vGB(-30,ph_sp(3),ph_sp(1),ph_sp(2),ph_sp(5)); thetaf_TI_m = theta_vGB(-30,ph_m(3),ph_m(1),ph_m(2),ph_m(5)); thetaf_TI_f = theta_vGB(-30,ph_f(3),ph_f(1),ph_f(2),ph_f(5)); thetaf_TI_dp = wf*thetaf_TI_f+(1-wf)*thetaf_TI_m; // prediction of water content at -30 R_thetaf_TI = thetaf_TI_dp/theta30; // precision of the estimate // final water contents for B thetaf_B_sp = theta_vGB(0,ph_sp(3),ph_sp(1),ph_sp(2),ph_sp(5)); thetaf_B_m = theta_vGB(0,ph_m(3),ph_m(1),ph_m(2),ph_m(5)); thetaf_B_f = theta_vGB(0,ph_f(3),ph_f(1),ph_f(2),ph_f(5)); thetaf_B_dp = wf*thetaf_B_f+(1-wf)*thetaf_B_m; // prediction of water content at -30 R_thetaf_B = thetaf_B_dp/thetaf_B_sp; // precision of the estimate thetas_B_sp référence car défini par 1-rho_d/rho_s // initial hydraulic conductivities for boths TI and B, similar initial water contents) K0_TI_sp = K_vGB(ph_sp(4),theta0_TI_sp,ph_sp(1),ph_sp(2),ph_sp(6)); K0_TI_m = K_vGB(ph_m(4),theta0_TI_m,ph_m(1),ph_m(2),ph_m(6)); K0_TI_f = K_vGB(ph_f(4),theta0_TI_f,ph_f(1),ph_f(2),ph_f(6)); K0_B_sp = K0_TI_sp; K0_B_m = K0_TI_m; K0_B_f = K0_TI_f; // final hydraulic conductivities for TI Kf_TI_sp = K_vGB(ph_sp(4),thetaf_TI_sp,ph_sp(1),ph_sp(2),ph_sp(6)); Kf_TI_m = K_vGB(ph_m(4),thetaf_TI_m,ph_m(1),ph_m(2),ph_m(6)); Kf_TI_f = K_vGB(ph_f(4),thetaf_TI_f,ph_f(1),ph_f(2),ph_f(6)); Kf_TI_dp = (1-wf)*Kf_TI_m+wf*Kf_TI_f; // final hydraulic conductivities for B Kf_B_sp = K_vGB(ph_sp(4),thetaf_B_sp,ph_sp(1),ph_sp(2),ph_sp(6)); Kf_B_m = K_vGB(ph_m(4),thetaf_B_m,ph_m(1),ph_m(2),ph_m(6)); Kf_B_f = K_vGB(ph_f(4),thetaf_B_f,ph_f(1),ph_f(2),ph_f(6)); // sorptivities S_TI_sp = (S_2_vGB(h0_sp,-30,ph_sp(1),ph_sp(2),ph_sp(3),ph_sp(4),ph_sp(5),ph_sp(6)))^(1/2); S_B_sp = (S_2_vGB(h0_sp,0,ph_sp(1),ph_sp(2),ph_sp(3),ph_sp(4),ph_sp(5),ph_sp(6)))^(1/2); S_TI_m = (S_2_vGB(h0_dp,-30,ph_m(1),ph_m(2),ph_m(3),ph_m(4),ph_m(5),ph_m(6)))^(1/2); S_TI_f = (S_2_vGB(h0_dp,-30,ph_f(1),ph_f(2),ph_f(3),ph_f(4),ph_f(5),ph_f(6)))^(1/2); S_B_m = (S_2_vGB(h0_dp,0,ph_m(1),ph_m(2),ph_m(3),ph_m(4),ph_m(5),ph_m(6)))^(1/2); S_B_f = (S_2_vGB(h0_dp,0,ph_f(1),ph_f(2),ph_f(3),ph_f(4),ph_f(5),ph_f(6)))^(1/2); // Computation of cumulative infiltrations // Cumulative infiltration into the SP soils I_TI_sp = I_3D(t30_exp,Kf_TI_sp,K0_TI_sp,S_TI_sp,rd30,thetaf_TI_sp,theta0_TI_sp,betaa,gammaa); I_B_sp = I_3D(t0_exp,Kf_B_sp,K0_B_sp,S_B_sp,rds,thetaf_B_sp,theta0_B_sp,betaa,gammaa); // Cumulative infiltration into the SP soils I_TI_m = I_3D(t30_exp,Kf_TI_m,K0_TI_m,S_TI_m,rd30,thetaf_TI_m,theta0_TI_m,betaa,gammaa); I_TI_f = I_3D(t30_exp,Kf_TI_f,K0_TI_f,S_TI_f,rd30,thetaf_TI_f,theta0_TI_f,betaa,gammaa); I_TI_dp = wf*I_TI_f+(1-wf)*I_TI_m; I_B_m = I_3D(t0_exp,Kf_B_m,K0_B_m,S_B_m,rds,thetaf_B_m,theta0_B_m,betaa,gammaa); I_B_f = I_3D(t0_exp,Kf_B_f,K0_B_f,S_B_f,rds,thetaf_B_f,theta0_B_f,betaa,gammaa); I_B_dp = wf*I_B_f+(1-wf)*I_B_m; //////////////////////// Choix des couleurs et eppaisseur ////////////// //Rq : la definition des colormap doit etre avant les fonctions scf et clf ! markers = ['+';'+';'<';'<';'o';'o']; color_ = ["green";"green";"blue";"blue";"red";"red"]; //////// Figure 1 ////////////////////////////////////////////////// font_title = 3; font_xylabel = 3; font_axs = 2; font_leg = 2; clf(i_fig); scf(i_fig); i_fig = i_fig+1; subplot(221) plot(abs(xh),theta_sp,"color","blue"); plot(abs(xh),theta_dp,"color","red"); plot(30,thetaf_TI_sp,"bo",30,thetaf_TI_dp,"ro"); title("BEST-DP "+name,"fontsize",font_title, "color", "black"); xlabel("$h\ [mm]$","fontsize",font_xylabel, "color", "black"); ylabel("$\theta\ [-]$","fontsize",font_xylabel, "color", "black"); g = gca(); // g.data_bounds = [1,0;10^4,0.8]; g.log_flags = "lnn"; g.font_size = font_axs; subplot(222) plot(abs(xh),K_sp,"color","blue"); plot(abs(xh),K_dp,"color","red"); plot(30,Kf_TI_sp,"bo",30,Kf_TI_dp,"ro"); title("BEST-DP","fontsize",font_title, "color", "black"); xlabel("$h\ [mm]$","fontsize",font_xylabel, "color", "black"); ylabel("$K\ [mm/min]$","fontsize",font_xylabel, "color", "black"); g = gca(); g.log_flags = "lln"; // g.data_bounds = [1,10^-6;10^4,10]; g.font_size = font_axs; legend("BEST-SP","BEST-DP",3); subplot(223) plot(t30_exp,I30_exp,"color","black",'LineSt',"none","marker",markers(i0),"marksize",8); plot(t30_exp,I_TI_sp,"color","blue"); plot(t30_exp,I_TI_dp,"color","red"); xlabel("$t_{TI}\ [min]$","fontsize",font_xylabel); ylabel("$I_{TI}\ [mm]$","fontsize",font_xylabel); title('Cumulative infiltrations I30',"fontsize",font_title); g = gca(); g.log_flags = 'nnn'; // g.y_location = 'right'; // g.data_bounds = [0,0;125,200]; subplot(224) plot(t0_exp,I0_exp,"color","black",'LineSt',"none","marker",markers(i0),"marksize",8); plot(t0_exp,I_B_sp,"color","blue"); plot(t0_exp,I_B_dp,"color","red"); xlabel("$t_B\ [min]$","fontsize",font_xylabel); ylabel("$I_{B}\ [mm]$","fontsize",font_xylabel); title('Cumulative infiltrations I0',"fontsize",font_title); g = gca(); g.log_flags = 'nnn'; // g.y_location = 'right'; // g.data_bounds = [0,0;125,200]; legend("exp. data","BEST-SP","BEST-DP",2);
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//Chapter 12 //Page 321 //Example 12.4 //interconnected clear;clc; //Given V_bus1 = 4.16e3; V_bus_2 = 600; Vm = 600; n_m = 0.895; Pop_m = 6000; X11_m = 0.2;X_2_m = 0.20;X_0_m = 0.04;X_n_m= 0.02; Vtr_ht = sqrt(3) * 2400;Vtr_lt = 600;Ptr =3 * 2500e3; X11_tr = 0.10; Pg = 7500e3;Vg = 4.16e3; X11_g = 0.10;X_2_g = 0.10;X_0_g = 0.05;X_n_g = 0.05; //At the time of fault Pload = 5000;pf_load = 0.85;n_load = 0.88; Vbase_sysbus = Vg;Pbase_sysbus = Pg; Vbase_m = Vtr_lt;Pbase_m = Ptr; Pin_m =(Pop_m * 0.746) * 1e3/ n_m; printf("\n Input Rating of the single equivalent motor = %.0f kVA \n",Pin_m) X11_m_new = X11_m * Pbase_m / Pin_m; X_2_m_new = X_2_m * Pbase_m / Pin_m; X_0_m_new = X_0_m * Pbase_m / Pin_m; X_n_m_new = 3 * X_n_m * Pbase_m / Pin_m; disp('For Motor') printf("\nX11 = %.1f per unit\n X_2 = %.1f per unit\n X_0 = %0.2f per unit\n 3X_n = %.2f per unit\n",X11_m_new,X_2_m_new,X_0_m_new,X_n_m_new) printf("\n The equivalent generator reactance from neutral to ground in the zero-sequence network = %.2f per unit\n",3*X_0_g) Vf = 1 * (cos(0) + %i * sin(0)); Ibase_m = Pbase_m / (sqrt(3) * Vbase_m); printf("\n Base current in motor circuit = %.0f \n\n",Ibase_m) Iactual_m = 746 * Pload / (n_load * sqrt(3) * Vbase_m * pf_load); magIa = Iactual_m / Ibase_m; angleIa = - acos(0.85); Ia_prefault = magIa * (cos(angleIa) + %i * sin(angleIa)); printf("\n Prefault current through line a = %.3f - j%.3f per unit\n\n",real(Ia_prefault),abs(imag(Ia_prefault))) Eg_11 = 1;Em_11 = 1; Z1 = ((%i * X11_g + %i * X_2_g) * (%i * X11_m_new)) / (%i * (X11_g + X_2_g + X11_m_new)); Z2 = Z1;Z0 = 3 * %i * X_0_g; printf("\n\n Z1 = j%.2f per unit\n Z2 = j%.2f per unit\n Z0 = j%.2f per unit\n",abs(Z1),abs(Z2),abs(Z0)) Ia1 = Vf / (Z1 + Z2 + Z0); Ia2 = Ia1;Ia0 = Ia1; Ia_fault = 3 * Ia0; printf("\n Current Ia in fault = -j%.3f per unit \n",abs(Ia_fault)) Ia1_tr = Ia1 * (%i * X11_m_new) / (%i * X11_m_new + %i * X11_g + %i * X_2_g); Ia1_m = Ia1 * (%i * X11_g + %i * X_2_g ) / (%i *X11_m_new + %i * X11_g + %i * X_2_g); a = 1 * (cos(120 * %pi / 180) + %i * sin(120 * %pi / 180)); A = [ 1 1 1; 1 a^2 a ; 1 a a^2]; Ia_tr = [ 0 ;Ia1_tr ;Ia1_tr]; I_tr = A * Ia_tr; disp('Currents in the line at the fault from the transformer in the order Ia,Ib,Ic in per unit are') disp(I_tr) disp('Currents in the line at the fault from the transformer in the order Ia,Ib,Ic in A are') disp(abs(I_tr) * Ibase_m) Ia_m = [Ia1 ; Ia1_m ; Ia1_m]; I_m = A * Ia_m; disp('Currents in the line at the fault from the motor in the order Ia,Ib,Ic in per unit are') disp(I_m) disp('Currents in the line at the fault from the motor in the order Ia,Ib,Ic in A are') disp(abs(I_m) * Ibase_m) I_A1 = -%i * Ia1_tr;I_A2 = %i * Ia1_tr;I_a0 = 0; I_A = I_A1 + I_A2; I_B1 = a^2 * I_A1;I_B2 = a * I_A2; I_B = I_B1 + I_B2; I_C1 = a * I_A1;I_C2 = a^2 * I_A2; I_C = I_C1 + I_C2; disp('Per Units currents in the order I_A,I_B,I_C in per unit are') disp(I_A);disp(I_B);disp(I_C); Ibase_ht = Ptr / (sqrt(3) * Vtr_ht); disp('Per Units currents in the order I_A,I_B,I_C in A are') disp(abs(I_A) * Ibase_ht);disp(abs(I_B) * Ibase_ht);disp(abs(I_C) * Ibase_ht); disp('Under loaded conditions') disp('Current from transformer to the fault phase a') disp(Ia_prefault + Ia1_tr) disp('Current from motor to the fault phase a') disp(- Ia_prefault + Ia1_m)
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l=200 Wamax=450 Wamin=-150 Wtmax=120 Wtmin=-80 FS=2 sigmay=330 sigmae=300 Ka=0.7 Kb=1 Ktb=1.44 Kta=1.64 Ksz=0.85 Ksur=0.90 q=0.90 //consider the reversed axial loading Wm=(Wamax+Wamin)/2 disp(Wm,"Average axial load=") Wv=(Wamax-Wamin)/2 disp(Wv,"Variable axial load=") syms d A=(%pi*d^2)/4 sigmam=Wm/A disp(sigmam,"Average axial stress=") sigmav=Wv/A disp(sigmav,"Variable axial stress=") Kfa=1.576 sigmaea=sigmae*Ka disp(sigmaea,"Endurance limit stress for reversed axial loading=") sigmanea=sigmam+(sigmav*sigmay*Kfa)/(sigmaea*Ksur*Ksz) Wm=(Wtmax+Wtmin)/2 disp(Wm,"Mean bending load=") Wv=(Wtmax-Wtmin)/2 disp(Wv,"Variable bending load=") Mm=Wm*(l-50) disp(Mm,"Mean bending moment at point A=") Mv=Wv*(l-50) disp(Mv,"Variable bending moment at point A=") Z=(%pi*d^3)/32 disp(Z,"section modulus=") sigmam=Mm/Z disp(sigmam,"Mean bending stress=") sigmav=Mv/Z disp(sigmav,"Variable bending stress=") Kfb=1.396 Kb=1 sigmaeb=sigmae*Kb disp(sigmaeb,"Endurance limit for reverse bending load=") sigmaneb=sigmam+(sigmav*sigmay*Kfb)/(sigmaeb*Ksur*Ksz) sigmane=sigmanea+sigmaneb disp(sigmane,"Total equivalent normal stress at point A=") sigmane=sigmay/FS disp(sigmane,"Total equivalent normal stress at point A=") s=%s p=165*s^3-1428*s-337168 x=roots(p) disp(x,"d=") //taking the real value of d d=12.9 disp(d,"d=")
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function welcomemsg() // This program is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 2 of the License, or // (at your option) any later version. // // This program is distributed in the hope that it will be useful, // but WITHOUT ANY WARRANTY; without even the implied warranty of // MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the // GNU General Public License for more details. // // You should have received a copy of the GNU General Public License // along with this program; if not, write to the Free Software // Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA // Authors // Holger Nahrstaedt - 2010 // Ishan Pendharkar - 2001-2007 global g g_cont g_plant g_sensor WelcomeMsg='Rltool for Scilab, version 1.7.' CreditsMsg=['(c) Ishan Pendharkar, India.'; 'Jose Da Cunha, Brazil'; 'Holger Nahrstaedt, Germany']; Start='no'; while Start=='no' //WelcomeNumber=buttondialog(WelcomeMsg,"Open|New|Credits|Help|Cancel","question"); WelcomeNumber=messagebox(WelcomeMsg,"Info","question",["Open","New","Credits","Help","Cancel"], "modal"); if WelcomeNumber==1 then, loadplant(); Start='yes'; end; if WelcomeNumber==2 then g_plant_new=rl(g_plant); if g_plant<>[] then, Start='yes' if g_plant_new==g_plant then, //if user changes the plant then set controller to default, else use previous value g_plant=g_plant_new else g_plant=g_plant_new g_cont=s^0; g_sensor=s^0; //default values for controller and sensor, plant has changed! xinfo('Setting controller and plant to default values'); end g=g_cont*g_plant*g_sensor; else bye(); end; end; if WelcomeNumber==3 then HELPabout(); Start='no' end; if WelcomeNumber==4 then //HELPmenu() help "RLtool Toolbox" Start='no' halt("Help loaded! Press enter to proceed!"); end; if WelcomeNumber==5 then bye() end; end; return; endfunction
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scilab.sce
//////////////////////////////////////////////////////////////////////////////// //// Неделя 8. //// Формирующий фильтр. //// Моделирование динамики матрицы ковариаций в байесовском подходе. //// Рекуррентный метод. Векторный случай //////////////////////////////////////////////////////////////////////////////// clear; deff('[numd] = roundd(num,n)','numd = round(num *10^n) / 10^n'); rand("seed",getdate("s")); grand("setsd",getdate("s")); //// Параметры //// mn = 100; //Количество измерений dt = 1; //Интервал дискретизации x_0 = [roundd(5000+rand(1,'nor')*100,1); roundd(rand(1,'nor')*3,1)]; //Начальное значение P_0 = [10 0; //Начальная матрица ковариаций 0 0.1]; F = [1 dt; //Матрица динамики 0 1]; G = [0; roundd(0.5+rand(1,'uin'),2)];//Матрица шумов Q = 1; //Матрица ковариаций шумов //Выделение памяти x = zeros(2,mn); x(:,1) = x_0; x_ex = zeros(2,mn,5); P = zeros(2,2,mn); P(:,:,1) = P_0; //// Моделирование //// //Мат. ожидание и матрица ковариаций for i = 2:mn x(:,i) = F*x(:,i-1); P(:,:,i) = F*P(:,:,i-1)*F'+G*Q*G'; end //Реализации for j = 1:5 x_ex(:,1,j) = x_0+sqrt(P_0)*rand(2,1,'nor'); for i = 2:mn x_ex(:,i,j) =F*x_ex(:,i-1,j)+sqrt(G)*rand(1,'nor'); end end //// Графики //// figure(1); clf; subplot(2,1,2); title('Динамика и СКО высоты') set(gca(),"auto_clear","off"); xgrid(1,0.1,10); plot(1:mn,x(1,:),'b'); plot(1:mn,3*sqrt(squeeze(P(1,1,:)))'+x(1,:),'r'); for j = 1:5 plot(1:mn,x_ex(1,:,j),'g'); end plot(1:mn,-3*sqrt(squeeze(P(1,1,:)))'+x(1,:),'r'); legend('Математическое ожидание','3 sigma','Примеры возможных реализаций'); subplot(2,1,1); title('Динамика и СКО вертикальной скорости') set(gca(),"auto_clear","off"); xgrid(1,0.1,10); plot(1:mn,x(2,:),'b'); plot(1:mn,3*sqrt(squeeze(P(2,2,:)))'+x(2,:),'r'); for j = 1:5 plot(1:mn,x_ex(2,:,j),'g'); end plot(1:mn,-3*sqrt(squeeze(P(2,2,:)))'+x(2,:),'r'); legend('Математическое ожидание','3 sigma','Примеры возможных реализаций'); mprintf('Математическое ожидание высоты через 100 секунд %f \n',x(1,100)); mprintf('3*СКО высоты через 100 секунд %f \n',3*sqrt(squeeze(P(1,1,100)))); mprintf('3*СКО высоты > 300 через %f секунд \n',find(3*sqrt(P(1,1,:))>300,1)); //// Запись данных //// deletefile('data.txt'); deletefile('fillings.txt'); deletefile('answer.txt'); answer = [x(1,100); 3*sqrt(squeeze(P(1,1,100)));find(3*sqrt(P(1,1,:))>300,1)]; fillings = [x_0; G(2)]; write('answer.txt',answer); write('fillings.txt',fillings); write('data.txt',[]);
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15_2_1.sce
clc //initialisation of variables B= 34 //ft z= 6 //ft g= 32.2 //ft/sec^2 d= 6 //in do= 2 //in l= 6 //ft l1= 0.04 //CALCULATIONS s= sqrt((g*do^2*(B-6-z))/(l*d^2*(d/12))) s1= s*60/(2*%pi) hf= l1*(l/(2*g*(do/12)))*(d^2*s*d/(12*do^2))^2 //RESULTS printf (' maximum friction head= %.2f ft',hf)
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/213/CH12/EX12.3/12_3.sce
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12_3.sce
//To find length of path of contact clc //Given: t=30, T=80 phi=20 //degrees m=12 //mm Addendum=10 //mm //Solution: //Length of path of contact: //Calculating the pitch circle radius of pinion r=m*t/2 //mm //Calculating the pitch circle radius of gear R=m*T/2 //mm //Calculating the radius of addendum circle of pinion rA=r+Addendum //mm //Calculating the radius of addendum circle of gear RA=R+Addendum //mm //Calculating the length of path of approach //Refer Fig. 12.11 KP=sqrt(RA^2-R^2*(cosd(phi))^2)-R*sind(phi) //mm //Calculating the length of path of recess PL=sqrt(rA^2-r^2*(cosd(phi))^2)-r*sind(phi) //mm //Calculating the length of path of contact KL=KP+PL //mm //Calculating the length of arc of contact Lac=KL/cosd(phi) //Length of arc of contact, mm //Contact ratio: //Calculating the circular pitch Pc=%pi*m //mm //Calculating the contact ratio CR=Lac/pc //Contact ratio //Results: printf("\n\n Length of path of contact, KL = %.1f mm.\n\n",KL) printf(" Length of arc of contact = %.2f mm.\n\n",Lac) printf(" Contact ratio = %d.\n\n",CR)
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Example319.sce
// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 3, Example 19") disp("Hydraulic efficiency is") disp("etah = Power deleloped/Power available") disp(" =m(Cw1U1 - Cw2U)/rhogQH") disp("Since flow is radial at outlet, then Cw2 = 0 and m = rhoQ, therefore") disp("etah = Cw1U1/gH") g = 9.81; H= 5; U1 = 9.6; etah = 80;//% Cw1 = etah *g*H/(9.6*100) disp("Radial velocity Cr1 = 4m/s") Cr1 = 4; disp("tan(alpha1) = Cr1/Cw1 (from velocity triangle)") alpha1 = atan(Cr1/Cw1)*180/%pi disp("i.e., inlet guide vane angle alpha1 = 44.38") disp("tan(beta1) = Cr1/(Cw1 - U1 )") beta1 = 180+atan(Cr1/(Cw1-U1))*180/%pi disp("Runner speed is") N = 230; D1 = 60*U1/(%pi*N) disp("Overall efficiency") disp("etao = Power output/Power available") rho = 1000; Q = 130*1000/(0.72*rho*g*H) disp("But Q = pi*D1h1Cr1 (where h1 is the height of runner)") h1 = Q/(%pi*D1*Cr1)
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/866/CH11/EX11.2/11_2.sce
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11_2.sce
clc //initialisation of variables d= 200 //mm l= 2 //m Shearstressmax= 200 //N/mm^2 Maximumangleoftwist= 2 //degrees Maxtorque= 30/2 //KNm G= 25000 //N/mm^2 //CALCULATIONS tmin= (Maxtorque*10^6*4)/(2*%pi*d^2*Shearstressmax) x1=l/2 c=0 dtbydx= (Maxtorque*%pi*200*16)/(4*%pi^2*d^4*G*tmin) theta= (Maxtorque*%pi*200*16)/(4*%pi^2*d^4*G*tmin)*x1+c tminimum= (Maxtorque*%pi*200*10^9*180*16)/(4*%pi^2*d^4*G*Maximumangleoftwist*%pi)*x1 //RESULTS printf ('minimum allowable thickness= %.1f mm',tminimum)
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example4_2.sce
// Calculate alpha using beta // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 4-2 in page 209 clear; clc; close; // Given Data beta_bjt=90; // beta gain for the BJT Ic=4*10^-3; // Collector Current in mA // Calculations alpha=beta_bjt/(1+beta_bjt); Ib=Ic/beta_bjt; Ie=Ic+Ib; printf("(a)The Current gain alpha for BJT is %0.3f \n",alpha); printf("(b)The value of the base Current is %0.2e A \n",Ib); printf("(c)The value of the Emitter Current is %0.2e A \n",Ie); // Results // (a) The Current Gain alpha for BJT is 0.989 // (b) The value of the Base Current is 44.44 mu-A // (c) The value of the Emitter Current is 4.04 mA
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Exa_2_43.sce
//Exa 2.43 clc; clear; close; format('v',8); //Given Data : h1=160;//KJ/Kg h2=2380;//KJ/Kg m1dot=10;//Kg/s m2dot=0.8;//Kg/s Qdot=10;//KJ/s Wdot=0;//KJ deltaKE=0; deltaPE=0; m3dot=m1dot+m2dot;//Kg/s disp(m3dot,"Mass flow of heated water in Kg/s : "); //m1dot*h1+m2dot*h2=m3dot*h3+Qdot h3=(m1dot*h1+m2dot*h2-Qdot)/m3dot;//KJ/Kg disp(h3,"Specific enthalpy of heated water in KJ/Kg : ");
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2020-04-09T02:43:26.499817
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Ex12_9.sce
clc clear //Initialization of variables tf=225 //F a=190 b=0.043 ti=212 //F //calculations hc=a/(1-b*(tf-ti)) hcti=hc*1.25 //results printf("For a flat copper plate, boiling film coefficient = %.1f Btu/sq ft hr F",hc) printf("\n For an inclined copper plate, boiling film coefficient = %d Btu/sq ft hr F",hcti)
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2009-05-11T05:43:11
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kiks_robotpatch.sci
function [ptch] = kiks_robotpatch(id) // Ouput variables initialisation (not found in input variables) ptch=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- global("KIKS_COLOR_BACKGROUND") col = [0.05,0.2,0]; // !! L.9: Matlab function sprintf not yet converted, original calling sequence used // !! L.9: Matlab function patch not yet converted, original calling sequence used ptch = patch("Facecolor",col,"Edgecolor",[0,0,0],"Erase","xor","tag",sprintf("@handle %d",id)); endfunction
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Exa_6_7.sce
//Exa 6.7 clc; clear; close; format('v',8); //Given Data : mw=1;//Kg m_steam=39;//mass of dry steam in Kg ms=mw+m_steam;//Kg x=m_steam/ms;//dryness fraction disp(x,"Dryness fraction ; ");
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Ex3_1.sce
// Given:- // Those with 1 are of state 1 and 2 are with state 2 // State 1 p1 = 10**5 // initial pressure in pascal x1 = 0.5 // initial quality T1 = 99.63 // temperature in degree celcius, from table A-3 v = 0.5 // volume of container in m3 vf1 = 1.0432*(10**(-3)) // specific volume of fluid in state 1 in m3/Kg(from table A-3) vg1 = 1.694 // specific volume of gas in state 1 in m3/kg(from table A-3) // State 2 p2 = 1.5*(10**5) // pressure after heating in pascal T2 = 111.4 // temperature in degree celcius in state 2, from A-3 vf2 = 1.0582*(10**(-3)) // specific volume of fluid in state 2 in m3/Kg, from A-3 vg2 = 1.159 // specific volume of gas in state 2 in m3/Kg,from A-3 // Calculations v1 = vf1 + x1*(vg1-vf1) // specific volume in state 1 in m3/Kg v2 = v1 // specific volume in state 2 in m3/Kg m = v/v1 // total mass in Kg mg1 = x1*m // mass of vapour in state 1 in Kg x2 = (v1-vf2)/(vg2-vf2) // quality in state 2 mg2 = x2*m // mass of vapor in state 2 in Kg // State 3 p3 = 2.11 // pressure in state 3 from table A-3 // Results printf( ' The temperature in state 1 is %f degree celcius.',T1) printf( ' The temperature in state 2 is %f degree celcius.',T2) printf( ' The mass of vapour in state 1 is %.2f kg.',mg1) printf( ' The mass of vapour in state 2 is %.2f kg.',mg2) printf( ' The pressure corresponding to state 3 is %.2f bar',p3)
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Guass_Siedal.sce
function siedal(a,b,n) [row,col] = size(a) // for i = 1:row // if a(i,i) == 0 // disp("Not Possible"); // end // end for i = 1:row x(i) = 0; end for k = 1:3*n for i = 1:row x(i) = 0 for j = 1:col if i ~= j x(i) = x(i) + x(j)*a(i,j); end end x(i) = (b(i) - x(i))/a(i,i); end disp(x) end endfunction
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circuloGiroRight.sce
// Red Green Blue Red Green Blue circuloGiroRight = [ 27 39 60 28.18 41.88 60.58; 27 39 59 28.18 40.52 60.58; 27 39 59 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 40.52 60.58; 27 39 59 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 60 29.26 41.88 62.04; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 60 28.18 40.52 60.58; 27 39 60 28.18 41.88 62.04; 27 38 59 28.18 41.88 60.58; 27 39 59 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 40.52 59.11; 27 39 60 28.18 41.88 60.58; 27 39 60 28.18 41.88 60.58; 27 39 59 28.18 41.88 62.04; 27 39 60 28.18 41.88 62.04; 27 39 60 29.26 41.88 60.58; 27 39 60 28.18 41.88 60.58; 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/LTAS.sci
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[]
no_license
sooolfi/Algoritmos-PDS-FICH-UNL
76dab9fcb85154f144a701afe42eb60cdbdb0e37
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refs/heads/master
2016-09-06T14:15:23.804074
2012-06-04T01:48:49
2012-06-04T01:48:49
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LTAS.sci
function LTAS x=wavread('/home/guido/Escritorio/guido.wav',10000); //ejemplo con senoidales conocidas // t=[0:1/10000:1-1/10000]; // x=5*sin(2*%pi*50*t) + 10*sin(2*%pi*120*t) + 2*sin(2*%pi*30*t); L=100; //cantidad de ventanas N=length(x); //ventana de hamming //definimos el tamanio de la ventana TamVent = round(N/L); h=window('hm',TamVent); Transf=zeros(L,N); ltas=zeros(1,N); for i=1:L xaux = x(((i-1)*(TamVent) +1):i*TamVent);//tomo valores de x en la ventana xaux = [zeros(1,(i-1)*(TamVent)) xaux zeros(1,N-(i*TamVent))]; haux = [zeros(1,(i-1)*(TamVent)) h zeros(1,N-(i*TamVent))]; Transf(i,:)=((fft(xaux.*haux)).^2 )./TamVent; end //Transf es i corresponde a la ventana y j corresponde a los valores de la trasnformada for j=1:N ltas(j)=sum(Transf(1:L,j))/L; ltas(j)=10*log(ltas(j)); end figure(1) subplot(2,1,1) plot2d3(abs(ltas(1:N))); subplot(2,1,2) //figure(2) plot2d3(abs(fft(x))); endfunction
01719a8ec4c9f7f513e3c91680f54ae6e11e83c1
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/479/CH1/EX1.5/Example_1_5.sce
e2f41614328b19b554b127d654a59c49bf543cef
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FOSSEE/Scilab-TBC-Uploads
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7bc77cb1ed33745c720952c92b3b2747c5cbf2df
refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
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Example_1_5.sce
//Chemical Engineering Thermodynamics //Chapter 1 //Introduction //Example 1.5 clear; clc; //Given n = 1;//n is the Kg mole of an ideal gas P = 700*(10^4);//P is the pressure of the system in N/(m^2) W = 45;//W is the weight of the mass in Kg M = 20;//M is the weight of the piston and piston rod together in Kg T = 300;//T is the constant temperature of the bath in K h = .4;//h is the height difference of the piston after expansion in m //To calculate the work obtained a = (10^-4);//a is the cross sectional area of the cylinder in m^2 V = h*a;//V is the volume changed as gas expands in m^3 //(i). If gas alone is the system //1Kgf = 9.8065Nm P1 = ((W+M)*9.8065)/(10^-4);//P1 is the resisting pressure when the gas confined in the cylinder taken as a system W1 = P1*V;//W1 is the work done if the gas confined in the cylinder us taken as system mprintf('Work done by the system if the gas confined in the cylinder is taken as a system is %f Nm',W1); //(ii). If gas + piston + piston rod is a system P2 = ((W*9.8065)/(10^-4));//P2 is the resisting pressure when the gas plus piston plus piston rod is taken as a system W2 = P2*V;//W2 is the Work done by the system if the gas plus piston plus piston rod is taken as a system mprintf('\n Work done by the system if the gas plus piston plus piston rod is taken as system is %f Nm',W2); //(iii). If gas + piston + piston rod +weight is system P3 = 0;//P3 is the resisting pressure when the gas plus piston plus piston rod plus weight is taken as a system W3 = P3*V;//W3 is the work done by the system if the gas plus piston plus piston rod plus weight is taken as a system mprintf('\n Work done by the system if the gas plus piston plus piston rod plus weight is taken as a system is %f',W3); //end
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/Brandam (2003) Versão Final.sce
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no_license
bruxeir0/bruxeir0-optimization-of-the-production-of-fermentable-sugars
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refs/heads/main
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Brandam (2003) Versão Final.sce
// modelo de hidrolise enzimática de amido Brandam et al (2003) clear clc tic() dispvector=[1:1:100] format(4) // valores dos parâmetros // gelatinização, T < Tg k_g1 = 5.7*10^31 // s^-1 E_g1 = 220.6 // kJ/mol // gelatinização, T > Tg k_g2 = 3.1*10^14 // s^-1 E_g2 = 108.3 // kJ/mol K = 273.15 // converter para°C T_g = 60 + K // ºC // constante dos açúcares k_gl = 0.023 // kg/U s k_mlt = 0.117 // kg/U s k_dex = 0.317 // kg/U s k_alfa_mal = 0.389 // kg/U s k_beta_mal = 0.137 // kg/U s k_gl_ = 2.9*10^-8 // kg/U s k_mlt_ = 1.5*10^-8 // kg/U s k_alfa_mal_ = 1.2*10^-7 // kg/U s k_beta_mal_ = 8.4*10^-8 // kg/U s // constante dos Gases R = 8.314/1000 // J/mol K // massas molares MM_gli = 180.156 // g/mol MM_mal = 342.3 // g/mol MM_mlt = 504.437 // g/mol MM_dex = 504.4 // g/mol // condições Iniciais gasto = 0 // gasto inicial = 0 x1_0 = 98.51 // concentração amido sólido inicial em g/L x2_0 = 0.0 // concentração amido gelatinizado inicial em g/L x3_0 = 0.0 // concentração dextrinas inicial em g/L x4_0 = 0.0 // concentração glicose inicial em g/L x5_0 = 0.0 // concentração maltose inicial em g/L x6_0 = 0.0 // concentração maltotriose inicial em g/L Ts = [37,1,1,1] function Taxa_Gelatinizacao = Sist_1(x1) if (T < T_g) then r_g = x1*k_g1*exp(-(E_g1/(R*T))) else r_g = x1*k_g2*exp(-(E_g2/(R*T))) end Taxa_Gelatinizacao = r_g endfunction function Atividade = Sist_2_3(T) if T < (63+273.15) then a_a = -0.001270154057*T^3 + 1.235930164837*T^2 - 400.438346*T + 43203.7983384673 a_b = 0.049*T -13.9 end if T >= (63+273.15) then a_a = 0.005646191991*T^3 - 5.814417*T^2 + 1995.013302*T - 228070.0234 a_b = -0.374*T + 128.3 end if a_a < 0 then a_a = 0 end if a_b < 0 then a_b = 0 end if T <313 then a_a = 1 a_b = 1 end a_Tref = 220.28986 b_Tref = 486.95652 Atividade = [a_a*a_Tref,a_b*b_Tref] endfunction function Amido = Sist_4(x2,T) a_ = Sist_2_3(T) a_a = a_(1) a_b = a_(2) r_gl = k_gl*a_a*x2 r_mal = k_alfa_mal*a_a*x2+k_beta_mal*a_b*x2 r_mlt = k_mlt*a_a*x2 r_dex = k_dex*a_a*x2 Amido = [r_gl,r_mal,r_mlt,r_dex] endfunction function Dextrinas = Sist_5(x3,T) a_ = Sist_2_3(T) a_a = a_(1) a_b = a_(2) r_gl_ = k_gl_*a_a*x3 r_mal_ = k_alfa_mal_*a_a*x3 + k_beta_mal_*a_b*x3 r_mlt_ = k_mlt_*a_a*x3 Dextrinas = [r_gl_,r_mal_,r_mlt_] endfunction function out = f(in) for k=1:length(in) if in(k)<0 in(k)=0 end end x1 = in(1) x2 = in(2) x3 = in(3) r_g = Sist_1(x1) r_amido = Sist_4(x2,T) r_dextrinas = Sist_5(x3,T) r_gl = r_amido(1) r_mal = r_amido(2) r_mlt = r_amido(3) r_dex = r_amido(4) r_gl_ = r_dextrinas(1) r_mal_ = r_dextrinas(2) r_mlt_ = r_dextrinas(3) dx1 = -r_g //dSs_dt dx2 = r_g - r_gl - r_mal - r_mlt - r_dex //dSg_dt dx3 = r_dex - r_gl_ - r_mal_ - r_mlt_ //dD_dt dx4 = r_gl + r_gl_ //dgl_dt dx5 = r_mal + r_mal_; //dmal_dt dx6 = r_mlt + r_mlt_; //dmlt_dt out=[dx1,dx2,dx3,dx4,dx5,dx6] endfunction in=[x1_0,x2_0,x3_0,x4_0,x5_0,x6_0] function Cp = calor_especifico(T) Cp = (-4*10^(-11)*(T-K)^5 + 1*10^(-8)*(T-K)^4 - 1*10^(-6)*(T-K)^3 + 1*10^(-4)*(T-K)^2 - 0.0033*(T-K) + 4.2198) //kJ/kg K endfunction function Perfil_Temp = temperatura(t, Condicao) t=t/60 if Condicao ==6 then Ts = [37,50,65,76] // teste 1 malt s1 // Ts = [37,50,70,76] //teste 2 malt S1 // Ts = [50,63,63,76] //teste 3 malt S1 boundaryTimes = [0,20,57.5,77.5,20000000] //teste 1 malt s1 [5,5,20] //boundaryTimes = [0,45,90,225,20000000] //teste 3 malt S1 [5,5,25] risingTimes = [5,5,20] deltas=4 end for k=1:(deltas) if t>=boundaryTimes(k) && t <boundaryTimes(k+1) T = Ts(k) if k>1 && t<(boundaryTimes(k)+ risingTimes(k-1)) T = Ts(k-1) + (t-boundaryTimes(k))/risingTimes(k-1)* (Ts(k)- Ts(k-1)) end end end Perfil_Temp = T + K endfunction dt = 0.3 // passo de integração tf = 110*60 // tempo final em s limit_time = tf/60 for t=dt:dt:tf percent_exec=(100*(t)/tf) if isempty(dispvector(dispvector==percent_exec)) then else clc disp("Simulação "+ string(percent_exec)+"% concluída ...") end T = temperatura(t, 6) k1 = f(in) k2 = f(in + 0.5*dt*k1) k3 = f(in + 0.5*dt*k2) k4 = f(in + dt*k3) for i=1:length(in) in(i) = in(i) + (dt/6)*(k1(i) + 2*k2(i) + 2*k2(i) + 2*k3(i) + k4(i)) end tt(t/dt) = t/60 TT(t/dt) = T-K d_x1(t/dt) = in(1) // amido d_x2(t/dt) = in(2) // amido gelatinizado d_x3(t/dt) = in(3) // dextrinas d_x4(t/dt) = in(4) // glicose d_x5(t/dt) = in(5) // maltose d_x6(t/dt) = in(6) // maltotriose cp_plot(t/dt) = calor_especifico(T) gasto = (gasto+((T+K)*dt)*(calor_especifico(T))) produzido_gli = (d_x4(t/dt)-x4_0) produzido_mal = (d_x5(t/dt)-x5_0) balanco = (d_x1(t/dt)+d_x2(t/dt)+d_x3(t/dt)+d_x4(t/dt)+d_x5(t/dt)+d_x6(t/dt))-(x1_0+x2_0+x3_0+x4_0+x5_0+x6_0) tempo_zero = (4.2)*(Ts(1)-25)*30*60 //concentrações finais das espécies em mol/L //desejados mols_gli = d_x4(t/dt)/MM_gli mols_mal = d_x5(t/dt)/MM_mal //indesejados mols_dex = d_x3(t/dt)/MM_dex mols_mlt = d_x6(t/dt)/MM_mlt //seletividade selet = (mols_gli+mols_mal)/(mols_mlt+mols_dex) end scf() plot(tt,d_x1,'g.') plot(tt,d_x3,'c.') plot(tt,d_x4,'r.') plot(tt,d_x5,'b.') plot(tt,d_x6,'y.') xlabel("Tempo (min)") ylabel("Concentração (g/L)") g=gca() g.data_bounds = [0,0;limit_time,100] xtitle('Concentração ao longo do tempo',['Tempo (min)'],['Concentração (g/L)']) h=legend(["Amido Sólido", "Dextrinas", "Glicose", "Maltose", "Maltotriose"], pos=1) g1 = newaxes() set(g1, "filled", "off") plot(tt,TT,'k.',"markerSize",2) ylabel("Temperatura (ºC)") g1=gca() g1.data_bounds = [0,30;limit_time,80] g1.axes_visible(1) = "off" g1.y_location = "right" clc format(10) disp("Gastando = "+ string((tempo_zero+gasto)/((limit_time+30)*60))+" kJ/kg") disp("Rendimento de glicose = "+ string(produzido_gli)+" g/L") disp("Rendimento de maltose = "+ string(produzido_mal)+" g/L") disp("Balanço = "+ string(balanco)+" g/L") disp("Seletividade de "+ string(selet)) disp("Simulacão 100% concluída em " + string(int(toc())) + " s")
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clear clf clc interval=input('enter the sampling interval'); n=[-20:1:20]; t=n*interval for i=1:length(t) x(i)=2*t(i); end plot(t,x,"."); xtitle("sampled function of x(t)=2*t for all t","number of samples","amplitude");
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//Exa 5.5 clc; clear; close; //Given data : VRL=30000;//Volts VSL=33000;//Volts f=50;//Hz P=10*10^6;//W pf=0.8;//power factor cos_fi_r=pf; sin_fi_r=sqrt(1-cos_fi_r^2); VR=VRL/sqrt(3);//V I=P/sqrt(3)/VRL/pf;//A Eta_T=0.96;//Efficiency LineLoss=P*(1/Eta_T-1);//W R=LineLoss/3/I^2;//ohm/phase disp(R,"Resistance per phase(ohm/phase)"); VS=VSL/sqrt(3);//V X=(VS-VR-I*R*cos_fi_r)/I/sin_fi_r;//V L=X/2/%pi/f;//H/phase disp(L*1000,"Inductance per phase(mH/phase)");
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 20.1 //calculation of the dispersive power of the flint glass //given data mur=1.613//refractive index of flint glass for the red light mu=1.620//refractive index of flint glass for the yellow light muv=1.632//refractive index of flint glass for the violet light //calculation w=(muv-mur)/(mu-1)//definition of the dispersive power printf('the dispersive power of the flint glass is %3.4f',w)
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function rts=cubic_roots(ps) // a0+ a1*x + a2x^2 + a3x^3 = 0 a=coeff(ps); [a0, a1, a2, a3] = (a(1), a(2), a(3), a(4)) D0 = a2^2-3*a3*a1; D1 = 2*a2^3-9*a3*a2*a1+27*a3^2*a0; C=((D1+sqrt(D1^2-4*D0^3))/2)^(1/3) if (C==0 | D0==0) then // 3 raizes reais iguais rts(1:3)= -a2/(3*a3); else w(1:3)=exp(%i*2*%pi/3*(1:3))' rts= -a2/(3*a3)-(C * w + D0/C./w)/(3*a3) end rts=clean(rts) endfunction
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//Example 2.2, page 49 clc h=6.63*10^-34//Joule-sec vo=5.6*10^14 w=h*vo printf("\npower is %e per sec",w) ev=(1/(1.6*10^-19)) wo=w*ev printf("\nEnergy is %f ev",wo)
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//Exa:1.16 clc; clear; close; s_f=0.04;//full load slip I_ratio=6;//Ratio of Starting current to full load current T_ratio=I_ratio^2*s_f;//Ratio of Starting torque to full load torque disp(T_ratio,'(a) Starting Torque ='); disp(' times the full load torque (T_f)'); s_max=sqrt((I_ratio^2-1)/(625-I_ratio^2)); disp(s_max,'(b) Slip at which Maximum torque occurs='); T_rm=(1/2)*((s_f/s_max)+(s_max/s_f)); disp(T_rm,'(c) Ratio of maximum torque to full load torque=');
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//example 5.13 clc; funcprot(0); // Initialization of Variable T=130;//temperature P=19.5;//power //calculation Ts=T-P*2.1; disp(Ts,"maximum safe temperature in degreeC") clear()
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//Engineering and Chemical Thermodynamics //Example 6.13 //Page no :287 clear ;clc ; //Given C1 = 1.596 ; C2 = 1.591 ; C3 = -74.40 ; C4 = -0.561 ; A = [ 0 ,0.1 ,0.2 ,0.3 ,0.4 ,0.5 ,0.6 ,0.7 ,0.8 ,0.9 ,1] ; m = (-C1 + C2 + C3 * ( C4 * 0.25)) * 1000 ; disp(" Example: 6.13 Page no : 287") ; for i = 1:11 x_H2O = A(1,i) ; x_H2SO4 = 1- x_H2O ; h = C1 * x_H2SO4 + C2 * x_H2O + C3 * x_H2SO4 * x_H2O *(1 + C4 * x_H2SO4) ; C(1,i) = h * 10^3; end y1 = C(1,6) ; function y = f613(x) , y = -m * (x - 0.5 ) + y1 ; endfunction for i = 1:11 F(1,i) = f613(A(1,i)) ; end plot(A,C); plot(A,F) xtitle("Figure E6.13","x_H2O","h (J/mol)"); printf("\n H_bar_H2SO4 = %d J/mol H_bar_H2O = %d J/mol\n ",F(1,1),F(1,11)) ; disp(" The partial molar property can be obtained by drawing tangent at mole fraction 0.5 .")
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clear; clc; R=16.64;L=5.87*(10^-3);G=1.28*(10^-6);C=0.0134*(10^-6);bmax=0.1;f2=5500;f1=30; w=2*%pi*f2; Z=R+(%i*w*L); Y=G+(%i*w*C); P=fix(sqrt(Z*Y)*10^4)/10^4; a=-f1*((-3*real(P)*real(P)*imag(P))-((imag(P))^3))/24; a1=round(a*1000)/1000; v=sqrt(bmax/a1); l=f1/v; R1=R*f1/(2*l); L1=L*f1*10^3/(2*l); C1=C*f1*10^6/l; G1=G*f1/l; Rg=1/G1; printf("The elements of the artificial line are:\n"); printf(" R/2 = %f ohms\n",fix(R1*100)/100); printf(" L/2 = %f mH\n",fix(L1*100)/100); printf(" C = %f microfarads\n",fix(C1*1000)/1000); printf(" Rg = %f k ohms\n",round((Rg*0.1)/100));
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clc clear //Input data V=1000;//Volume of the bulb of the callendar's compensated constant pressure air thermometer in cm^3 v=100;//Volume of mercury drawn out of the reservoir in cm^3 //Calculations t=((v)/(V-v))*273;//The temperature of the bath in degree centigrade //Output data printf('The temperature of the bath on the celsius scale is %3.2f degree centigrade',t)
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Chapter1_Example35.sce
//Chapter-1, Example 1.21, Page 1.49 //============================================================================= clc clear //INPUT DATA N1=1500;//Initial speed in rpm V1=270;//Terminal voltage in V T=300;//Full load torque in N.m N2=1200;//New speed in rpm V2=(2*V1);//New terminal voltage in V Ra=0.31;//Armature resistance in ohm //CALCULATIONS Ia=(T*2*3.14*N1)/(V1*60);//Full load current in A Eb=(V1*(N2/N1));//Back emf in V Pm=(Eb*Ia)/1000;//Mechanical power developed in kW Eb2=(V2-(Ia*Ra));//Back emf at new terminal volatge in V N=(Eb2*Ia*60)/(2*3.14*T);//New speed in rpm Pm2=(Eb2*Ia/1000);//Mechanical power in kW //OUTPUT mprintf('i)Full load current is %3.1f A, Full load power is %3.1f kW, Armature resistance is %3.2f ohm\nii)New motor torque is %3.0f N.m, Motor power is %3.1f kW, Motor speed is %3.0f rpm',Ia,Pm,Ra,T,Pm2,N) //=================================END OF PROGRAM==============================
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @outputs number @data 0 0 5 5 5 3 6 6 7 1 5 2 7 7 7 3 8 8 0 0 0 0 3 3 3 8 5 5 5 5 6 6 7 7 0 0 1 1 3 9 4 4 4 4 8 3 8 8 2 2 2 2 4 4 7 7 8 2 9 9 9 9 1 1 3 3 3 3 4 4 9 9 1 7 4 4 6 6 9 4 0 0 3 3 4 4 6 6 6 0 8 8 2 2 3 3 3 9 9 9
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plot_normal.sce
kolor = 1 importXcosDiagram("/home/evgeniy/Рабочий стол/СКБ/Введение в специальность/Новое/Segway/cart_3.zcos"); xcos_simulate(scs_m, 4); subplot(3,2,1); xtitle("Угол Segway"); plot2d(psi.time, 180/%pi*psi.values,[kolor]); subplot(3,2,3); xtitle("Угол колес"); plot2d(dtheta.time, 180/%pi*theta.values,[kolor]); subplot(3,2,2); xtitle("Скорость падения"); plot2d(dpsi.time, 180/%pi*dpsi.values,[kolor]); subplot(3,2,5); xtitle("Напряжение в В"); plot2d(napr.time, napr.values,[kolor]); subplot(3,2,4); xtitle("Скорость колес"); plot2d(dpsi.time, 180/%pi*dtheta.values,[kolor]);
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RungeKutta.sci
function [VetX, VetY] = RungeKutta (a, b, m, yO) //Abscissas e solução do do PVI h = (b-a)/m xt = a yt = yO VetX(1) = xt VetY(1) = yt printf("0\t%f\t%f\n", xt, yt) for i = 1:m do x = xt y = yt k1 = f(x,y)//Avaliar f(x, y) x = xt + h/2 y = yt +h/2*k1 k2 = f(x, y)//Avaliar f(x, y) y = yt + h/2*k2 k3 = f(x, y)//Avaliar f(x, y) x = xt + h y = yt + h*k3 k4 = f(x,y)//Avaliar f(x, y) xt = a + i*h yt = yt + h/6*(k1+2*(k2+k3)+k4) printf("%d\t%f\t%f\n", i, xt, yt) VetX(i+1) = xt VetY(i+1) = yt end endfunction
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Ex8_3.sce
//Ex8_3 clc RL = 8*10^3 Rs= 500 hie=1.0*10^3 hre=2.5*10^-4 hfe=50 hoe=25*10^-6 disp("RL = "+string(RL)+"ohm")//load resistance disp("Rs = "+string(Rs)+"ohm")//source resistance //h-parameters for CE transistor amplifier are as follows: disp("hie = "+string(hie)+"ohm")//input resistance of CE transistor disp("hre = "+string(hre))//voltage gain of CE transistor disp("hfe = "+string(hfe))//current gain of CE transistor disp("hoe = "+string(hoe)+"mho")//output conductance of CE transistor Ai=-hfe/(1+(hoe*RL)) disp("Ai = -hfe/(1+(hoe*RL)) = "+string(Ai))//calculation for current gain Ri = hie+(hre*Ai*RL) disp("Ri = hie+(hre*Ai*RL) = "+string(Ri)+"ohm")//calculation for input resistance Ais=(Ai*Rs)/(Ri+Rs) disp("Ais = (Ai*Rs)/(Ri+Rs)= "+string(Ais))//current gain with source resistance Avs = Ai*RL/Ri disp("Avs = Ai*RL/Ri = "+string(Avs))//voltage gain with source resistance //note : in the textbook above problem has given two values for hie BUT no value for hfe ... // thus assuming hie=50 as hfe =50, as given in the previous example 8_2 //note : answer in the textbook is not accuratly calculated.
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Exa3_7.sce
//Exa3_7 clc; clear; close; //given data is : A1=4000;//in rupees G=500;//in rupees n=10;//in years i=15;//% per annum A=A1+G*(((1+i/100)^n-(i/100)*n-1)/((i/100)*(1+i/100)^n-(i/100))); F=A*(((1+i/100)^n-1)/(i/100)); disp("At the end of 10th year, the compound amountr of all his payments will be : "+string(F)+" Rupees.");