pierreqi/scilab_code · Datasets at Hugging Face

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/sample.tst

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Zyphicx/zparser-langtest

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2021-01-19T12:55:08.785670

2017-08-19T20:05:22

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tst

sample.tst

variable = 5 + 3

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/2399/CH4/EX4.6.2/Example_4_6_2.sce

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FOSSEE/Scilab-TBC-Uploads

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2018-02-03T05:31:52

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sce

Example_4_6_2.sce

// Example 4.6.2 clc; clear; beta_c=7d-11; //isothermal compressibility n=1.46; //refractive index P=0.29; //photoelastic constat k=1.38d-23; //Boltzmnn constant T=1400; //temperature L=1000; //length lamda=0.7d-6; //wavelength gamma_r = 8*(3.14^3)*(P^2)*(n^8)*beta_c*k*T/(3*(lamda^4)); //computing coefficient attenuation=%e^(-gamma_r*L); //computing attenuation gamma_r=gamma_r*1000; printf("\nRaleigh Scattering corfficient is %.3f * 10^-3 per meter\n",gamma_r); printf("\nNOTE - in quetion they have asked for attenuation but in solution they have not calcualted\n"); printf("\nAttenuation due to Rayleigh scattering is %.3f",attenuation); //answer for Raleigh Scattering corfficient in the book is given as 0.804d-3, deviation of 0.003d-3

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/3850/CH28/EX28.1/Ex28_1.sce

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2020-04-09T02:43:26.499817

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sce

Ex28_1.sce

//To Calculate the Amount of Heat flowing per second through the cube. //Example 28.1 clear; clc; x=0.1;//Edge Length of the Copper Cube in cm A=x^2;//Area of cross section in cm^2 K=385;//Thermal Conductivity of Copper in W/m-deg Celsius T1=100;//Temperature of the first face T2=0;//Temperature at the second face Rf=K*A*(T1-T2)/x;//Amount of Heat flowing per second (del(Q)/del(t)) printf("The amount of heat flowing per sec=%d W",Rf);

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/269/CH7/EX7.13/example13.sce

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example13.sce

Syms t,s //by network equations disp('by network equations i(s)=1/(s+1)^2+1') [A]=pfss((1*s^0+0)/((s+1)^2+1)) b=ilt(A(1),s,t) disp('The inverse laplace is') disp(b)

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/3504/CH2/EX2.14/Ex2_14.sce

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Ex2_14.sce

//To determine the current through load resistor R of the given circuit. clc; Z=[1+%i*1-%i*1+2 -2;-2 2+1] D=det(Z) Z_2=[3 1+%i*1;-2 0] D_2=det(Z_2) I_2=D_2/D disp(I_2,'Current through load resistor R(Polar form)')

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/Test/Previous/handbook.tst

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hermetique/lsl

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refs/heads/master

2021-10-10T01:42:52.349919

2019-01-05T23:02:33

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tst

handbook.tst

************************************** Testing ../Code/lsl -i ../LSL/lslinit.lsi ************************************** ************* Test input from ../LSL/AC.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/AC.lsl ********* ************* Test input from ../LSL/Abelian.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Abelian.lsl ********* ************* Test input from ../LSL/AbelianGroup.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/AbelianGroup.lsl ********* ************* Test input from ../LSL/AbelianMonoid.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/AbelianMonoid.lsl ********* ************* Test input from ../LSL/AbelianSemigroup.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/AbelianSemigroup.lsl ********* ************* Test input from ../LSL/Addition.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Addition.lsl ********* ************* Test input from ../LSL/Antisymmetric.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Antisymmetric.lsl ********* ************* Test input from ../LSL/ArithOps.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ArithOps.lsl ********* ************* Test input from ../LSL/Array1.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Array1.lsl ********* ************* Test input from ../LSL/Array2.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Array2.lsl ********* ************* Test input from ../LSL/ArraySlice2.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ArraySlice2.lsl ********* ************* Test input from ../LSL/Associative.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Associative.lsl ********* ************* Test input from ../LSL/Asymmetric.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Asymmetric.lsl ********* ************* Test input from ../LSL/Bag.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Bag.lsl ********* ************* Test input from ../LSL/BagBasics.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/BagBasics.lsl ********* ************* Test input from ../LSL/BinaryTree.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/BinaryTree.lsl ********* ************* Test input from ../LSL/Boolean.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Boolean.lsl ********* ************* Test input from ../LSL/ChoiceBag.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ChoiceBag.lsl ********* ************* Test input from ../LSL/ChoiceSet.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ChoiceSet.lsl ********* ************* Test input from ../LSL/CoerceContainer.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/CoerceContainer.lsl ********* ************* Test input from ../LSL/Commutative.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Commutative.lsl ********* ************* Test input from ../LSL/ComposeMaps.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ComposeMaps.lsl ********* ************* Test input from ../LSL/Conditional.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Conditional.lsl ********* ************* Test input from ../LSL/Container.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Container.lsl ********* ************* Test input from ../LSL/DecimalLiterals.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/DecimalLiterals.lsl ********* ************* Test input from ../LSL/Deque.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Deque.lsl ********* ************* Test input from ../LSL/DerivedOrders.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/DerivedOrders.lsl ********* ************* Test input from ../LSL/Distributive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Distributive.lsl ********* ************* Test input from ../LSL/ElementTest.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ElementTest.lsl ********* ************* Test input from ../LSL/Enumerable.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Enumerable.lsl ********* ************* Test input from ../LSL/Enumeration.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Enumeration.lsl ********* ************* Test input from ../LSL/Equality.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Equality.lsl ********* ************* Test input from ../LSL/Equivalence.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Equivalence.lsl ********* ************* Test input from ../LSL/Exponentiation.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Exponentiation.lsl ********* ************* Test input from ../LSL/FPAssumptions.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/FPAssumptions.lsl ********* ************* Test input from ../LSL/Field.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Field.lsl ********* ************* Test input from ../LSL/FiniteMap.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/FiniteMap.lsl ********* ************* Test input from ../LSL/FloatingPoint.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/FloatingPoint.lsl ********* ************* Test input from ../LSL/Functional.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Functional.lsl ********* ************* Test input from ../LSL/Graph.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Graph.lsl ********* ************* Test input from ../LSL/GreatestLowerBound.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/GreatestLowerBound.lsl ********* ************* Test input from ../LSL/Group.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Group.lsl ********* ************* Test input from ../LSL/Idempotent.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Idempotent.lsl ********* ************* Test input from ../LSL/Identity.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Identity.lsl ********* ************* Test input from ../LSL/IndexOp.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IndexOp.lsl ********* ************* Test input from ../LSL/Infinite.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Infinite.lsl ********* ************* Test input from ../LSL/InsertGenerated.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/InsertGenerated.lsl ********* ************* Test input from ../LSL/IntCycle.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IntCycle.lsl ********* ************* Test input from ../LSL/Integer.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Integer.lsl ********* ************* Test input from ../LSL/IntegerAndNatural.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IntegerAndNatural.lsl ********* ************* Test input from ../LSL/IntegerAndPositive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IntegerAndPositive.lsl ********* ************* Test input from ../LSL/IntegerPredicates.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IntegerPredicates.lsl ********* ************* Test input from ../LSL/Inverse.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Inverse.lsl ********* ************* Test input from ../LSL/Involutive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Involutive.lsl ********* ************* Test input from ../LSL/Irreflexive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Irreflexive.lsl ********* ************* Test input from ../LSL/IsPO.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IsPO.lsl ********* ************* Test input from ../LSL/IsTO.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/IsTO.lsl ********* ************* Test input from ../LSL/JoinOp.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/JoinOp.lsl ********* ************* Test input from ../LSL/Lattice.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Lattice.lsl ********* ************* Test input from ../LSL/LeftDistributive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/LeftDistributive.lsl ********* ************* Test input from ../LSL/LeftIdentity.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/LeftIdentity.lsl ********* ************* Test input from ../LSL/LeftInverse.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/LeftInverse.lsl ********* ************* Test input from ../LSL/LexicographicOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/LexicographicOrder.lsl ********* ************* Test input from ../LSL/List.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/List.lsl ********* ************* Test input from ../LSL/ListStructure.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ListStructure.lsl ********* ************* Test input from ../LSL/ListStructureOps.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ListStructureOps.lsl ********* ************* Test input from ../LSL/MemberOp.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/MemberOp.lsl ********* ************* Test input from ../LSL/MinMax.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/MinMax.lsl ********* ************* Test input from ../LSL/Monoid.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Monoid.lsl ********* ************* Test input from ../LSL/Multiplication.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Multiplication.lsl ********* ************* Test input from ../LSL/Natural.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Natural.lsl ********* ************* Test input from ../LSL/NaturalOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/NaturalOrder.lsl ********* ************* Test input from ../LSL/OneToOne.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/OneToOne.lsl ********* ************* Test input from ../LSL/PairwiseExtension.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/PairwiseExtension.lsl ********* ************* Test input from ../LSL/PartialOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/PartialOrder.lsl ********* ************* Test input from ../LSL/Permutation.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Permutation.lsl ********* ************* Test input from ../LSL/PointwiseImage.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/PointwiseImage.lsl ********* ************* Test input from ../LSL/Positive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Positive.lsl ********* ************* Test input from ../LSL/PreOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/PreOrder.lsl ********* ************* Test input from ../LSL/PriorityQueue.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/PriorityQueue.lsl ********* ************* Test input from ../LSL/Queue.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Queue.lsl ********* ************* Test input from ../LSL/Rational.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Rational.lsl ********* ************* Test input from ../LSL/ReduceContainer.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ReduceContainer.lsl ********* ************* Test input from ../LSL/Reflexive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Reflexive.lsl ********* ************* Test input from ../LSL/Relation.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Relation.lsl ********* ************* Test input from ../LSL/RelationBasics.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RelationBasics.lsl ********* ************* Test input from ../LSL/RelationOps.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RelationOps.lsl ********* ************* Test input from ../LSL/RelationPredicates.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RelationPredicates.lsl ********* ************* Test input from ../LSL/ReverseOp.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/ReverseOp.lsl ********* ************* Test input from ../LSL/RightDistributive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RightDistributive.lsl ********* ************* Test input from ../LSL/RightIdentity.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RightIdentity.lsl ********* ************* Test input from ../LSL/RightInverse.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RightInverse.lsl ********* ************* Test input from ../LSL/Ring.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Ring.lsl ********* ************* Test input from ../LSL/RingWithUnit.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/RingWithUnit.lsl ********* ************* Test input from ../LSL/Semigroup.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Semigroup.lsl ********* ************* Test input from ../LSL/Semilattice.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Semilattice.lsl ********* ************* Test input from ../LSL/Sequence.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Sequence.lsl ********* ************* Test input from ../LSL/Set.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Set.lsl ********* ************* Test input from ../LSL/SetBasics.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/SetBasics.lsl ********* ************* Test input from ../LSL/SetToRelation.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/SetToRelation.lsl ********* ************* Test input from ../LSL/SignedInt.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/SignedInt.lsl ********* ************* Test input from ../LSL/Stack.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Stack.lsl ********* ************* Test input from ../LSL/StackBasics.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/StackBasics.lsl ********* ************* Test input from ../LSL/StrictPartialOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/StrictPartialOrder.lsl ********* ************* Test input from ../LSL/StrictTotalOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/StrictTotalOrder.lsl ********* ************* Test input from ../LSL/String.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/String.lsl ********* ************* Test input from ../LSL/Symmetric.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Symmetric.lsl ********* ************* Test input from ../LSL/TotalOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/TotalOrder.lsl ********* ************* Test input from ../LSL/TotalPreOrder.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/TotalPreOrder.lsl ********* ************* Test input from ../LSL/Transitive.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/Transitive.lsl ********* ************* Test input from ../LSL/UnsignedInt.lsl *********** Finished checking LSL traits ************* End of input from ../LSL/UnsignedInt.lsl *********

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/1646/CH9/EX9.9/Ch09Ex9.sce

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2020-04-09T02:43:26.499817

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Ch09Ex9.sce

// Scilab Code Ex9.9: Page-467 (2011) clc;clear; mu1 = 1.45;....// Index of refraction of core NA = 0.16;....// Numerical aperture of step index fibre a = 3e-006;....// Radius of the core, m lambda = 0.9e-006;....// Operating wavelength of optical fibre, m v = 2*%pi*a*NA/lambda; // The normalized frequency or v-number of optical fibre printf("\nThe normalized frequency of the optical fibre = %5.2f", v); // Result // The normalized frequency of the optical fibre = 3.35

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/3640/CH4/EX4.6/Ex4_6.sce

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2020-04-09T02:43:26.499817

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Ex4_6.sce

clc V1m(1)=1 //reference voltage in volts V1m(2)=0.9//reduced voltage in volts ratio=(V1m(1)/V1m(2))^2 //ratio of s2/s1 mprintf("s2/s1=%f\n",ratio)//ans may vary due to roundoff error mprintf("I2(2)/I2(1)=s2*V1m(2)/s1*V1m(1)=%f\n",(V1m(2)/V1m(1))*ratio)//ans may vary due to roundoff error mprintf("(copperloss)2/(copperloss)1=(I2(2)/I2(1))^2=%f\n",(V1m(1)/V1m(2))^2)//ans may vary due to roundoff error s=0.03 //at 60Hz slip ns=1800 //synchronous speed in rev/min mprintf("Speed at 90 percent voltage=%frev/min\n",ns*(1-(ratio*s)))//ans may vary due to roundoff error

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/534/CH10/EX10.2/10_2_Horizontal_cylinder.sce

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10_2_Horizontal_cylinder.sce

clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 10.2 Page 635 \n'); //Example 10.2 // Power Dissipation per unith length for the cylinder, qs //Operating Conditions Ts = 255+273 ;//[K] Surface Temperature Tsat = 100+273 ;//[K] Saturated Temperature D = 6*10^-3 ;//[m] Diameter of pan e = 1 ;// eimssivity stfncnstt=5.67*10^(-8) ;// [W/m^2.K^4] - Stefan Boltzmann Constant g = 9.81 ;//[m^2/s] gravitaional constant //Table A.6 Saturated water Liquid Properties T = 373 K rhol = 957.9 ;//[kg/m^3] Density hfg = 2257*10^3 ;//[J/kg] Specific Heat //Table A.4 Water Vapor Properties T = 450 K rhov = .4902 ;//[kg/m^3] Density cpv = 1.98*10^3 ;//[J/kg.K] Specific Heat kv = 0.0299 ;//[W/m.K] Conductivity uv = 15.25*10^-6 ;//[N.s/m^2] Viscosity Te = Ts-Tsat; hconv = .62*[kv^3*rhov*(rhol-rhov)*g*(hfg+.8*cpv*Te)/(uv*D*Te)]^.25; hrad = e*stfncnstt*(Ts^4-Tsat^4)/(Ts-Tsat); //From eqn 10.9 h^(4/3) = hconv^(4/3) + hrad*h^(1/3) //Newton Raphson h=250; //Initial Assumption while(1>0) f = h^(4/3) - [hconv^(4/3) + hrad*h^(1/3)]; fd = (4/3)*h^(1/3) - [(1/3)*hrad*h^(-2/3)]; hn=h-f/fd; if((hn^(4/3) - [hconv^(4/3) + hrad*hn^(1/3)])<=.01) break; end; h=hn; end q = h*%pi*D*Te; printf("\n Power Dissipation per unith length for the cylinder, qs= %i W/m",q); //END

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12_6.sce

clc //Initialization of variables P1=14.7 //psia P4=100 //psia T1=530 //R T3=T1 g=1.4 m=10 //lbm cp=0.24 //calculations P2=sqrt(P1*P4) T2=T1*(P2/P1)^((g-1)/g) T4=T2 W=2*cp*(T2-T1) Wt=W*m hp=Wt*60/2545 Q=m*cp*(T2-T3) T4=T1*(P4/P1)^((g-1)/g) W2=m*cp*(T4-T1) //results printf("Work required in case 1 = %d Btu/min",Wt+1) printf("\n Work required in case 2 = %d Btu/min",W2+1)

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/737/CH2/EX2.3/Example2_03.sce

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Example2_03.sce

//Example 2.3 page 24 //Given an analog signal //x(t) = 5 cos (2 pi 2000t)+ 1 cos( 2pi 5000t), for t>=0 //which is sampled at a rate of 8,000 Hz, //a. Sketch the spectrum of the sampled signal up to 20 kHz. //b. Sketch the recovered analog signal spectrum if an ideal lowpass filter with //a cutoff frequency of 4 kHz is used to recover the original signal //(y(n)= x(n) this case). clc,clear,close; c1 = [0.5 2.5 2.5 0.5]; //sampling theorem is violated f1 = [-3 -2 2 3];//kHz //after sampling c2 = repmat(c1,1,5); f2 = [f1-16 f1-8 f1 f1+8 f1+16]; ax=gda(); ax.thickness = 2; ax.y_location = "origin"; ax.x_location = "origin"; subplot(2,1,1) plot2d3(f2,c2) xtitle('Spectrum of the sampled signal in Example 2.3(a)','f(kHz)','X(f)'); //Since Sampling theorem is not satisfied, we can not recover the original spectrum using reconstruction low pass filter. subplot(2,1,2) plot2d3(f1,c1) xtitle('Spectrum of the recovered signal in Example 2.3(b)','f(kHz)','X(f)');

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U4_C1_8.sce

//variable initialization R=1.097*10^7; //Rydberg constant (m-1) ratio=1836; //ratio of maas of tritium and hydrogen //calculation lembda=(36*2*10^10)/(5*R*3*ratio); //separation of the first line of the Balmer series (Å) printf("\nΔλ = %.1f Å",lembda);

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7q5.sce

clc //initialisation of variables L= 50 //m k= 0.08e-2//m/sec h= 4 //m H1= 3 //m H= 8 //m a= 0.139 //radians //calculations i= h*cos(a)/L A= H1*cos(a) q= k*i*A //results printf ('flow rate = % 2f m^3/sec/m ',q)

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newgame.sci

//A faire : //Ecrire un background. //Definition des variables et de l'environnement ( ie tracage du triangle ) function [time]=newgame(pseudo,couleur) f2=figure() a=[0,0];b=[60,60]; plot2d(a,b,axesflag=0), plot2d(b,a,axesflag=0) xset("color",1); xfpoly([0,0,56,56],[0,56,56,0],1) //zone de manoeuvre : [2,2,54,54],[2,54,54,2] explosion=3; rep=[0,0,0]; Mat(1,:)=[3.5,4,4.5]; // 1ere ligne : abscisses Mat(2,:)=[3,5,3]; // 2eme ligne : ordonnees G=[4;3.66]; xset("color",couleur); xfpoly(Mat(1,:),Mat(2,:)); fuel=100; c=0.5; jauge(fuel) xpoly([60,57,57,60],[17,17,5,5],"lines",1) PLANETE=[20,20,0,0,2;30,50,0,0,5;50,10,0,0,5;30,30,0,0,2]; VG=[0,0]; timer() //----------------------------------------------- while rep(3)<>-1000 do //triangle BAC, M est le milieu de BC (A en haut) tic() rep=xgetmouse(); temps=0; if Mat(1,3)<2|Mat(1,3)>54|Mat(2,3)<2|Mat(2,3)>54|Mat(1,1)<2|Mat(1,1)>54|Mat(2,1)<2|Mat(2,1)>54 then messagebox("You''re dead Jack... RIP"), rep(3)=-1000; end boom=calculdistance(G,PLANETE); if boom<explosion then messagebox(["La perturbation gravitationnelle provoquee par la planete vous a fait perdre le controle de votre vaisseau..." " Vous vous ecrasez sur cette terre hostile, peuplee par d''etranges creatures... Au revoir, Jack !"]), rep(3)=-1000; end if rep(3)==122|rep(3)==115 then // code ascii : "z"->122 , "s"->115 temps=toc(); M=[(Mat(1,1)+Mat(1,3))/2;(Mat(2,1)+Mat(2,3))/2]; // M est le milieu de BC (A en haut) if rep(3)==115 then k=-2; else k=2; end [Mat,M,G]=avancer(Mat,M,G,k,couleur); fuel=fuel-c; jauge(fuel) end //Rotation if rep(3)==100|rep(3)==113 then temps=toc(); if rep(3)==100 then theta=-0.3; else theta=0.3; end // code ascii: "d"->100 , "q"=113 Mat=rotation(Mat,couleur); jauge(fuel) end xpause(5) if fuel<=0 then messagebox(["Vous n''avez plus de carburant, Jack... Vous avez echoue!"," Vous et votre vaisseau allez d�river jusqu''� la fin des temps dans le froid et la solitude de l''univers..."]), rep(3)=-1000; end if temps<>0 then colorier(PLANETE,Mat,0,1,couleur); for i=1:floor(temps)+1 do [PLANETE,Mat,G,VG]=deplacement(PLANETE,Mat,G,VG); end colorier(PLANETE,Mat,1,0,couleur) end end time=timer() endfunction //xpause(10000000) //messagebox("Vous avez tenu "+string(time)+" secondes")

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6_4.sce

clc; clear; format('e',11) D=10.5*10^3; //density of silver. m=107.9*10^-3; //atomic mass of silver. e=-1.602*10^-19; //charge of electron. Na=6.022*10^23; //Avogadro's no. N1=Na/m; //N1=no. of atoms per kg. N2=N1*D; //N2=no. of atoms per cube meter. rho_m=N2*e; //rho_m=mobile charge density. disp(rho_m,"mobile charge density(in C/m^3)=")

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/src/flight_control/PID/scilab/quickplot.sce

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Jian117/Quadcopter-Michelle

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quickplot.sce

// Plot response of a PID controller and plant xdel(winsid()); // close all graphics windows which might be open exec('stepperf.sce'); t = 0:(0.1*dt):tmax; Kp = input("KP: "); Ki = input("Ki: "); Kd = input("Kd: "); // Set up the closed loop system pctl = pp*(Kd*s^2 + Kp*s + Ki)/(s*(s+pp)); ctl = syslin('c',pctl); // H=1 feedback sys = ctl*plant /. H; // H is feedback y = csim(ones(t), t, sys); scf(8); plot(t,y) title("Step response"); [ts1, po1, ss, cu, y] = costPID(plant, Kp, Ki, Kd); printf("Settling Time: %5.2f Overshoot: %4.1f percent SSE: %6.3f Ctl Effort: %5.2f\n", ts1, (po1-1)*100.0, ss , cu); scf(9); loopgain = ctl*plant; printf("Gain Margin: %5.1f dB, Phase Margin: %5.1f deg\n", g_margin(loopgain), p_margin(loopgain)); show_margins(loopgain); // gain and phase margins of loop gain. printf("Factored Controller: ") rlist=roots(s^2+Kp/Kd*s+Ki/Kd)'; a=rlist(1); b=rlist(2); if (abs(imag(a)) > 10^(-5) ) then { printf("%12.9f x (s+%6.4f+j%6.4f)(s+%6.4f+j%6.4f)", Kd, -real(a), -imag(a), -real(b), -imag(b)) ; }; else { printf("%12.9f x (s+%6.4f)(s+%6.4f)", Kd, -a, -b); }

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Ex24_10.sce

clear // // //Given //Variable declaration P=9*1000 //Axial pull in N F=4.5*1000 //Shear force in N sigmat_star=225 //Elastic limit in tension in N/sq.mm Sf=3 //Factor of safety mu=0.3 //Poisson's ratio sigma3=0 //third principle stress //Calculation sigmat=sigmat_star/Sf sigma=(P/(%pi/4)) tau=(F/(%pi/4)) sigma1=((tau)+int((sqrt((sigma/2)**2+tau**2)))) sigma2=((tau)-int((sqrt((sigma/2)**2+tau**2)))) d=(((((sigma1-sigma2)**2+(sigma2-sigma3)**2+(sigma3-sigma1)**2)/(2*(sigmat**2)))**(1/4))) //Result printf("\n Diameter of the bolt = %0.3f mm",d)

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example12_6.sce

clc // Given that t = 3.8 // half-life for radon in days r = 60 // percentage fraction of sample which decayed // Sample Problem 6 on page no. 12.33 printf("\n # PROBLEM 6 # \n") printf("Standard formula used \n") printf(" lambda = 0.693 / t_1/2 (Decay constant) \n N =N_0*e^(-lambda*t) \n") lambda = 0.693 / t T = (1 / lambda) * (log(100 / (100 - r))) printf("\n Time taken for 60 percent decay of sample is %f days.",T)

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Ex1_36.sce

//Variable declarations v=12 //output voltage(V) vm=20. //peak voltage(V) v1=8 //output voltage(V) for negative half cycle vm1=20. //peak voltage(V) for negative half cycle //Calculations t1=(asin(v/vm))/10**4 //for positive half cycle when D1 conducts t2=(0.1*%pi)-t1/1e-3 t3=(asin(v1/vm1))/10**4 //for negative half cycle when D2 conducts t4=(0.1*(%pi))+t3/1e-3 t5=(0.2*(%pi))-t3/1e-3 //Results printf ("t1 is %.3f ms",t1/1e-3) printf ("t2 is %.2f ms",t2) printf ("t3 is %.3f ms",t3/1e-3) printf ("t4 is %.3f ms",t4) printf ("t5 is %.3f ms",t5) printf ("vo is -5.33+6.66*sin(10**4*.15)")

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53ex2.sce

clear; clc; close; x=poly(0,'x'); //let x be distance in kilometers time_1st_journey=x/64 time_2nd_journey=x/80 total_time=9; for x=1:500 if((x/64 + x/80) == 9) mprintf("the value of x is %iKm \n",x) end end

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blackman_window.sce

clc; clear; N = 64; a0 = 0.42; a1 = 0.5; a2 = 0.08; n = 1:N; w = a0 - a1 * cos((2*%pi*n)/(N-1)) + a2 * cos((4*%pi*n)/(N-1)); subplot(2,1,1); title ('Time domain of Blackman Window Output'); xlabel ('samples'); ylabel ('Amplitude'); plot (n,w); W = fft(w); W = 20* log(abs(W)) subplot(2,1,2); title ('Frequency domain of Blackman Window Output'); xlabel ('samples'); ylabel ('Amplitude'); plot (W);

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BathDisplay.sce

// This script produces a graph of the bathymetry created with "BathCreator.f95". clf; scf(0); a=gcf(); a.figure_size= [1000,350]; h1=read("topo.dat",-1,153); // read input data x = (0:150)'; y = (0:50)'; // location vectors hzero = max(h1,0.0); plot3d(x,y,-0.2*hzero(2:52,2:152)',-60,85,' ',flag=[7,2,3]);

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//Example 1.4 clc,clear demand_charges = 1*25 + 4*20 + 15*16 ; energy_charges = 100*0.40 + 200*0.30 + 1700*0.25 ; monthly_bill = demand_charges + energy_charges ; printf('Total monthly bill for 2000 units consumption = %d Rs',monthly_bill)

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example27_3.sce

f=1000; l=30*10^(-3); c=1/(4*%pi^2*f^2*l); disp("the value of capacitance (in μF) required is"); disp(c*10^6);

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6_11.sce

//Swinburne test on a dc shunt motor clc; clear; V=500; I=5; Rf=250; Ra=0.5; P=V*I; If=V/Rf; Ia=I-If; Pfc=(If^2)*Rf;// Field Copper Loss Pac=(Ia^2)*Ra; // Armature Copper Loss Pil=P-Pfc-Pac;// Iron loss // Generator Vg=500; Ig=100; Pog=Vg*Ig; // Power Output Iag=Ig+If; //Armature current Pgac=(Iag^2)*Ra; // Armature Copper loss slg=0.01*Pog;//stray loss Pgtl=Pgac+Pfc+slg+Pil; // Total losses effg=Pog*100/(Pog+Pgtl); // Motor Vm=500; Im=100; Pim=Vm*Im; // Power input to the motor Iam=Ig-If; // Armature current Pmac=(Iam^2)*Ra; // Armature Copper Loss Pom=Pim-Pmac-Pil-Pfc;// Ouput of the motor slm=0.01*Pom;// Stray loss Pmtl=Pmac+Pil+Pfc+slm; // Total loss of the motor effm=(Pom-slm)*100/(Pim); printf('i) The Efficiency of the machine as a generator delivering 100A at 500V = %g percent \n',effg) printf('ii) The Efficiency of the machine as a motor having a line current 100A at 500V = %g percent \n',effm)

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/3769/CH1/EX1.14/Ex1_14.sce

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Ex1_14.sce

clear //Given e=1.6*10**-19 m=9*10**9 G=6.67*10**-11 me=9.11*10**-31 mp=1.67*10**-27 r=10**-10 //Calculation F0=(m*e**2)/(G*me*mp) F1=(m*e**2)/(G*mp*mp) F2=m*e**2/r**2 A1=F2/me A2=F2/mp //Result printf("\n (a)(i)strength of an electrons and protons %0.1f *10**39 ",F0*10**-39) printf("\n (ii)Strength of two protons %0.1f *10**36 ",F1*10**-36) printf("\n (b) Acceleration of electron is %0.1f *10**22 m/s**2",A1*10**-22) printf("\n Acceleration of proton is %0.1f *10**19 m/s*2",A2*10**-19)

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/3784/CH2/EX2.3/Ex2_3.sce

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Ex2_3.sce

clc //variable initialisation Va=220 //supply voltage in volts N1=1500 //speed in rpm I=50 // current in ampere Ra=0.5 //armature resistance in ohm Vl=440 //line voltage in volts f=50 //frequency in Hz N2=1200 //speed in rpm //solution Vm=(Va*%pi)/(3*sqrt(3)) Vph=(Vl*(sqrt(2)))/(sqrt(3)) Xmer_ratio=Vph/Vm Eb1=Va-(Ra*I) Eb2=(N2/N1)*Eb1 Va=Eb2+Ra*I a=acosd((Va*%pi)/(3*sqrt(3)*Vm)) N3=800 Eb3=(-N3/N1)*Eb1 Va1=Eb3+(2*I*Ra) a1=acosd((Va1*%pi)/(3*sqrt(3)*Vm)) printf('\n\n Transformer Turns Ratio=%0.1f\n\n',Xmer_ratio) printf('\n\n The Firing Angle=%0.1f\n\n',a) printf('\n\n The Firing Angle=%0.1f\n\n',a1)

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/3753/CH1/EX1.11/Ex1_11.sce

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Ex1_11.sce

//Example number 1.11, Page number 1.38 clc;clear;close //Variable declaration lamda=5.5*10**-7 // in m d=2.54 // in m x=1.22// unitless //Calculation dtheta=(x*lamda)/d // radian //Result printf("Smallest angular separation of two stars = %0.3e radian",dtheta)

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Ex16_55.sce

//Initilization of variables m=8 //kg n=90 //rpm g=9.8 //m/s^2 //Calculations Fg=m*g //N w=2*%pi*n/60 //rad/s //using equations of motion By=m*g //N //Solving for Bx and C A=[1,1;-0.3,0.9] B=[m*0.3*w^2;By*0.3] C=inv(A)*B //N //Result clc printf('The solution is Bx=%f N ,By=%f N and C=%f N',C(1),By,C(2))

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clear clc function[remValue]=LocalReminder(xVal,yVal) remValue=xVal-fix(xVal./yVal).*yVal endfunction container=0 for k=1:1:1000-1 cVal=k if LocalReminder(cVal,3)==0 | LocalReminder(cVal,5)==0 container=container+cVal end end disp(container)

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firpmord5.sce

//too few i/p args f = ['a' 'b' 'c']; a = [1 0]; dev = [0.01 0.1]; fs = 8000; [n,fo,ao,w] = firpmord(f,a); //output //!--error 77 //firpmord: Wrong number of input argument; 3-4 expected //at line 71 of function firpmord called by : // [n,fo,ao,w] = firpmord(f,a);

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/611/CH14/EX14.9/Chap14_Ex9.sce

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Chap14_Ex9.sce

// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-14,Example 9,Page 499 //Title: Degree of conversion //================================================================================================================ clear clc //INPUT //Industrial methanol is produced by the following reaction: //CO(g)+2H2(g)--->CH3OH(g) T0=298.15;//standard temperature in K T=500;//temperature in K P=5;//pressure in bar del_Hv=37.988;//enthalpy of vapourization of CH3OH at 298.15K in kJ/mol R=8.314;//universal gas constant in J/molK del_Gf=[-161.781;-137.327;0]//Standard Gibbs free energies of formation of CH3OH(g) from Example(14.2),CO(g) and H2(g) respectively in kJ del_Hf=[-238.648;-110.532;0]//Standard enthalpies of formation of CH3OH(l), CO(g) and H2(g) respectively in kJ //The isobaric molar capacity is given by Cp=a+bT+cT^2+dT^3+eT^-2 in J/molK and T is in K from Appendix A.3 //coefficient in the expression for computing the isobaric molar heat capacity from Appendix A.3 (for CH3OH(g),CO(g),H2(g) respectively) a=[18.382;28.068;27.012]; //coefficient in the expression for computing the isobaric molar heat capacity from Appendix A.3 (for CH3OH(g),CO(g),H2(g) respectively) b=[101.564*10^-3;4.631*10^-3;3.509*10^-3]; //coefficient in the expression for computing the isobaric molar heat capacity from Appendix A.3 (for CH3OH(g),CO(g),H2(g) respectively) c=[-28.683*10^-6;0;0]; //coefficient in the expression for computing the isobaric molar heat capacity from Appendix A.3 (for CH3OH(g),CO(g),H2(g) respectively) d=[0;0;0]; //coefficient in the expression for computing the isobaric molar heat capacity from Appendix A.3 (for CH3OH(g),CO(g),H2(g) respectively) e=[0;-0.258*10^5;0.690*10^5]; n=[1;-1;-2];//stoichiometric coefficients of CH3OH(g),CO(g) and H2(g) respectively (no unit) m=[0.02;1;2];//mole number in feed (for CH3OH(g),CO(g),H2(g) respectively) //CALCULATION del_Hf_CH3OH_g=del_Hf(1,:)+del_Hv;//calculation of the standard enthalpy of formation of CH3OH(g) in kJ del_G=(n(1,:)*del_Gf(1,:))+(n(2,:)*del_Gf(2,:))+(n(3,:)*del_Gf(3,:));//calculation of the Gibbs free energy of reaction in kJ del_H=del_Hf_CH3OH_g+(n(2,:)*del_Hf(2,:))+(n(3,:)*del_Hf(3,:));//calculation of the enthalpy of the reaction in kJ //Framing the isobaric molar heat capacity expression del_a=(n(1,:)*a(1,:))+(n(2,:)*a(2,:))+(n(3,:)*a(3,:)); del_b=(n(1,:)*b(1,:))+(n(2,:)*b(2,:))+(n(3,:)*b(3,:)); del_c=(n(1,:)*c(1,:))+(n(2,:)*c(2,:))+(n(3,:)*c(3,:)); del_d=(n(1,:)*d(1,:))+(n(2,:)*d(2,:))+(n(3,:)*d(3,:)); del_e=(n(1,:)*e(1,:))+(n(2,:)*e(2,:))+(n(3,:)*e(3,:)); //Using Eq.14.21 to compute the value of del_H0 in kJ del_H0=((del_H*10^3)-((del_a*T0)+((del_b/2)*T0^2)+((del_c/3)*T0^3)+((del_d/4)*T0^4)-(del_e/T0)))*10^-3; //Using Eq.14.23 to compute the integration constant (no unit) I=(1/(R*T0))*((del_H0*10^3)-(del_a*T0*log(T0))-((del_b/2)*T0^2)-((del_c/6)*T0^3)-((del_d/12)*T0^4)-((del_e/2)*(1/T0))-(del_G*10^3)); //Using Eq.14.23 to compute the Gibbs free energy of the reaction at T in kJ del_G_T=((del_H0*10^3)-(del_a*T*log(T))-((del_b/2)*T^2)-((del_c/6)*T^3)-((del_d/12)*T^4)-((del_e/2)*(1/T))-(I*R*T))*10^-3; Ka=exp((-del_G_T*10^3)/(R*T));//calculation of the equilibrium constant (no unit) del_n=n(1,:)+n(2,:)+n(3,:);//calculation of the total mole number (no unit) Ky=Ka/((P)^del_n);//calculation of the equilibrium constant in terms of the mole fractions using Eq.(14.30) (no unit) (K_phi=1.0,assuming ideal gas behaviour) mtot=m(1,:)+m(2,:)+m(3,:);//calculation of the total mole number of feed entering (no unit) //To determine the degree of conversion, the inbuilt function fsolve is used to solve the equation given by Ky=(y_CH3OH)/(y_CO*y_H2^2), where y_CH3OH,y_CO,y_H2 are the mole fractions of CH3OH,CO,H2 respectively. Let the equilibrium conversion be denoted as E E_guess=0.1;//taking a guess value for the degree of conversion,to be used in the inbuilt function fsolve (no unit) tol=1e-6;//tolerance limit for convergence of the system when using fsolve function[fn]=solver_func(Ei) //Function defined for solving the system fn=Ky-((((m(1,:)+(n(1,:)*Ei))/(mtot+(del_n*Ei)))^n(1,:))*(((m(2,:)+(n(2,:)*Ei))/(mtot+(del_n*Ei)))^n(2,:))*(((m(3,:)+(n(3,:)*Ei))/(mtot+(del_n*Ei)))^n(3,:))); endfunction [E]=fsolve(E_guess,solver_func,tol)//using inbuilt function fsolve for solving the system of equations //OUTPUT mprintf('The degree of conversion at 500K and 5bar pressure=%f\n',E); //===============================================END OF PROGRAM===================================================

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Ex5_5.sce

//Chapter 5:Dc Motor Drives //Example 5 clc; //Variable Initialization //Ratings of the DC shunt motor which operated under dynamic braking Rb=1 //braking resisance in ohms Ra=0.04 //armature resistance in ohms Rf=10 //field resistance in ohms T=400 //load torque in N-m //Magnetisation curve at N1 N1=600 //speed in rpm If=[2.5,5,7.5,10,12.5,15,17.5,20,22.5,25] //field current in A E =[25,50,73.5,90,102.5,110,116,121,125,129] //back emf in V //Solution disp(If,"Field current If:in A") x=(Rb+Rf)/Rb Ia = If * x //armature current Wm=2*%pi*N1/60 Ke_flux=E / Wm //Ke*flux=constant T=[] for i=1:10 T($+1)=(Ke_flux(i))*(Ia(i)) //torque end disp(Ke_flux,"Ke_flux :") disp(T,"Torque :in N-m") //Results //Plotting the values of Ke*flux vs If If=[2.5,5,7.5,10,12.5,15,17.5,20,22.5,25] //field current in A subplot(2,1,1) plot(If,Ke_flux,'y') xlabel('field current I_f') ylabel('Ke*flux') title('If vs Ke*flux') xgrid(2) //Plotting the values of T vs If If=[2.5,5,7.5,10,12.5,15,17.5,20,22.5,25] //field current in A subplot(2,1,2) plot(T,If) xlabel('Torque T') ylabel('field current I_f') title('T vs If') xgrid(2) mprintf("\nFrom the plot we can see that when the torque is 400 N-m, ") mprintf("\nthe field current is If=19.3 A, and Ke*flux=1.898 when If=19.3 A") T=400 // braking torque in N-m If=19.13 // field current in A Ke_flux=1.898 // Ke*flux Ia=x*If E=If*Rf+Ia*Ra //since E=V+Ia*Ra N2=(E/Ke_flux)*(60/(2*%pi)) //required speed mprintf("\nHence the required speed in is :%.1f rpm",N2)

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Ex9_4.txt

//Caption:Calculate (i)-critical voltage ,(ii)-breakdown voltage, (iii)-breakdown electric field //Exa:9.4 clc; clear; close; E_s=12.5; E_o=8.85*10^-12; E=E_o*E_s; N=3.2*10^22;//per cubic meter L=8*10^-6;//in m q=1.6*10^-19;//in coulombs V_c=q*N*L^2/(2*E); V_bd=2*V_c; E_bd=V_bd/L; disp(V_c/10^3,'Critical voltage(in kV) ='); disp(V_bd/10^3,'Breakdown Voltage (in kV) ='); disp(E_bd,'Breakdown Electric field (in V/cm) =');

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1_24.sce

//Example 1.24 //Multiplication //Page no. 18 clc;clear;close; function [x1]=mul(x,y) for i=1:8 x1(1,i)=0 end printf('Multiplication of %.4i and %.4i = ',x,y) x=x*y; c=0; for i=8:-1:1 x=x/10; xd=floor((x-fix(x))*10+0.1) if c==1 then if xd==0 then x1(1,i)=1;c=0 elseif xd==1 x1(1,i)=0; c=1; elseif xd==2 x1(1,i)=1;c=1; end else if xd==0 | xd==1 then x1(1,i)=xd;c=0 elseif xd==2 x1(1,i)=0; i=i-1;c=1; end end end disp(x1) endfunction mul(1110,1011);

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12_06.sce

//Chapter 12, Problem 6 clc; hFE=125; //common-emitter current gain Ic=50*10^-3; //collector current Ib=Ic/hFE; //calculating base current printf("Base current Ib = %d microampere",Ib*10^6);

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eclaircir.sci

function image = eclaircir(img, multiplicateur) [width,height]=size(img) for i=1:height for j=1:width if img(j,i) > 0 image(j,i) = img(j,i)*multiplicateur end end end endfunction

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db4.sce

//check output when i/p is negative v=db(-4); disp(v); //output // // 12.0412 //

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example12_4.sce

clc clear disp('example 12 4') z=10+5*%i //load e1=250;e2=250 //emf of generator z1=2*%i;z2=2*%i //synchronous impedence v=(e1*z2+z1*e2)/((z1*z2/z)+z1+z2);vph=atand(imag(v)/real(v)) //substitution the value in equation 12.10 i1=(z2*e1+(e1-e2)*z)/(z1*z2+(z1+z2)*z);iph=atand(imag(i1)/real(i1)) //substitution the value in equation 12.7 pf1=cosd(vph-iph) pd=v*i1*pf1 printf("terminal voltage %.2fV \ncurrent supplied by each %.2fA \npower factor of each %.3f lagging \npower delivered by each %.4fKW",abs(v),abs(i1),abs(pf1),abs(pd))

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2_1.sce

clc //initialisation of variables p1=400//kg p2=-200//kg p3=-350//kg p4=100//kg p5=-175//kg //CALCULATIONS F=p1+p2+p3+p4+p5//kg //RESULTS printf('The resultant of the following five collinear force=% f kg',F)

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9_1.sce

a=1.6; //say a=σn q=1.6*10^-19; b=4000; //say b=μe c=0.8; //say c=σp d=2000; //say d=μh e=0.0258; //sat e=K*T/q g=16*8.854*10^-14; ni-2.1*10^13; Nd=a/(q*b); Na=c/(q*d); printf('\n The value of Nd is %f/cm^3',Nd); printf('\n The value of Na is %f/cm^3',Na); Vbi=e*log(Nd*Na/(ni^2))/2.303; printf('\n The value of Vbi is %fV',Vbi); h=5*10^15; i=1; j=1; W=((2*g*0.2467/(q*(h)))^0.5)*2; printf('\n The value of depletion bandwidth is %f cm',W);

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Ex3_16.sce

// SAMPLE PROBLEM 3/16 clc;clear;funcprot(0); // Given data mg=6;// lb k=2;// lb/in g=32.2;// The acceleration due to gravity in ft/sec^2 h=24;// in x_1=24/12;// ft x_2=(((24*sqrt(2))/12)-(24/12));// ft // Calculation // The reaction of the rod on the slider is normal to the motion and does no work. T_1=0;// ft-lb U_12=0;// ft-lb // We define the datum to be at the level of position 1, so that the gravitational potential energies are V_1g=0;// ft-lb V_2g=-(mg)*(h/12);// ft-lb V_1e=(1/2)*(k*12)*(x_1)^2;// ft-lb V_2e=(1/2)*(k*12)*(x_2)^2;// ft-lb v_2=sqrt(((T_1+(V_1g+V_1e)+U_12)-(V_2g+V_2e))*(2*(g/mg)));// ft/sec printf("\nThe velocity of the slider as it passes position 2,v_2=%2.1f ft/sec",v_2);

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Example2_3.sce

//clear// //Caption:Entropy, Average length, Variance of Huffman Encoding //Example 2.3: Huffman Encoding: Calculation of // (a)Average code-word length 'L' //(b)Entropy 'H' clear; clc; P0 = 0.4; //probability of codeword '00' L0 = 2; //length of codeword S0 P1 = 0.2; //probability of codeword '10' L1 = 2; //length of codeword S1 P2 = 0.2; //probility of codeword '11' L2 = 2; //length of codeword S2 P3 = 0.1; //probility of codeword '010' L3 = 3; //length of codeword S3 P4 =0.1; //probility of codeword '011' L4 = 3; //length of codeword S4 L = P0*L0+P1*L1+P2*L2+P3*L3+P4*L4; H_Ruo = P0*log2(1/P0)+P1*log2(1/P1)+P2*log2(1/P2)+P3*log2(1/P3)+P4*log2(1/P4); disp('bits',L,'Average code-word Length L') disp('bits',H_Ruo,'Entropy of Huffman coding result H') disp('percent',((L-H_Ruo)/H_Ruo)*100,'Average code-word length L exceeds the entropy H(Ruo) by only') sigma_1 = P0*(L0-L)^2+P1*(L1-L)^2+P2*(L2-L)^2+P3*(L3-L)^2+P4*(L4-L)^2; disp(sigma_1,'Varinace of Huffman code')

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Example7_10.sce

clear; clc; // Example: 7.10 // Page: 280 printf("Example: 7.10 - Page: 280\n\n"); // Solution //*****Data******// P1 = 800;// [kPa] T1 = 773;// [K] H1 = 3480;// [kJ/kg] P2 = 100;// [kPa] T2 = 573;// [K] H2 = 3074;// [kJ/kg] //***************// // Solution (a) // Velocity of the fluid exiting the nozzle: // U2 = sqrt(U1^2 + 2*(H1 - H2)) // Neglecting initial velocity: U2 = sqrt(2*(H1 - H2)*1000);// [m/s] printf("(a) Final Velocity is %.2f m/s\n",U2); // Solution (b) U1 = 40;// [m/s] U2 = sqrt((U1^2 + 2*(H1 - H2))*1000);// [m/s] printf("(b) Final Velocity is %.2f m/s\n",U2);

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ex2_1.sce

// Example 2.1 page no-45 clear clc n=1 h=6.626*10^-34 //J-sec eps=10^-9/(36*%pi) m=9.1*10^-31 //kg e=1.6*10^-19 r=n^2*h^2*eps/(%pi*m*e^2) printf("\nradius of the lowest state of Ground State, r=%.2f A°",r*10^10)

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NAT_SUMMATION.sci

function [x,y,typ]=NAT_SUMMATION(job,arg1,arg2) // Copyright INRIA //** 16 JAN 2008 : Native integer Summation block . //** This block uses native integer operations //** x=[]; y=[]; typ=[]; select job case 'plot' then sgn = arg1.model.ipar standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x = arg1; graphics = arg1.graphics ; model = arg1.model ; exprs = graphics.exprs ; //** back compatibility ? if size(exprs,1)==1 then exprs = [sci2exp(1);exprs;sci2exp(0)]; elseif size(exprs,1)==2 then exprs=[exprs;sci2exp(0)]; end while %t do [ok, Datatype, sgn, satur, exprs] = getvalue('Set Native Integer sum block parameters',.. ['IN/OUT Datatype (1=real double 2=complex 3=int32 ...)';.. 'Number of inputs or sign vector (of +1, -1)' ;.. 'Do on Overflow (0=Nothing 1=Saturate 2=Error)'],.. list('vec',1,'vec',-1,'vec',1),exprs) if ~ok then break ; //** exit on "cancel" operation end sgn = sgn(:); //** why ? //** check "Do on overflow" if (satur~=0 & satur~=1 & satur~=2) then message("Do on overflow must be 0,1,2"); ok=%f; end //** check on input vector size and/or sign if size(sgn,1)==1 then if sgn<1 then message('Number of inputs must be > 0') ok=%f elseif sgn==1 then in=-1;in2=-2 sgn=[] nout=1;nout2=1 else in=-ones(sgn,1);in2=2*in sgn=ones(sgn,1) nout=-1;nout2=-2 end else if ~and(abs(sgn)==1) then message('Signs can only be +1 or -1') ok=%f else in=-ones(size(sgn,1),1);in2=2*in nout=-1;nout2=-2 end end it = Datatype*ones(1,size(in,1)); ot = Datatype; if Datatype==1 then //** real (double) datatype model.sim=list('summation',4) ; elseif Datatype==2 then //** complex (2x double) datatype model.sim=list('summation_z',4) ; elseif ((Datatype<1) |(Datatype>8)) then //** for input values beyond supported type message("Datatype is not supported"); ok = %f; else //** Native Integer Support if satur==0 then //** Do nothing on overflow if Datatype==3 then model.sim=list('nat_summation_i32n',4) elseif Datatype==4 then model.sim=list('nat_summation_i16n',4) elseif Datatype==5 then model.sim=list('nat_summation_i8n',4) elseif Datatype==6 then model.sim=list('summation_ui32n',4) elseif Datatype==7 then model.sim=list('summation_ui16n',4) elseif Datatype==8 then model.sim=list('summation_ui8n',4) end elseif satur==1 then //** Saturate on overflow if Datatype==3 then model.sim=list('summation_i32s',4) elseif Datatype==4 then model.sim=list('summation_i16s',4) elseif Datatype==5 then model.sim=list('summation_i8s',4) elseif Datatype==6 then model.sim=list('summation_ui32s',4) elseif Datatype==7 then model.sim=list('summation_ui16s',4) elseif Datatype==8 then model.sim=list('summation_ui8s',4) end elseif satur==2 then //** error on overflow if Datatype==3 then model.sim=list('summation_i32e',4) elseif Datatype==4 then model.sim=list('summation_i16e',4) elseif Datatype==5 then model.sim=list('summation_i8e',4) elseif Datatype==6 then model.sim=list('summation_ui32e',4) elseif Datatype==7 then model.sim=list('summation_ui16e',4) elseif Datatype==8 then model.sim=list('summation_ui8e',4) end end end if ok then [model,graphics,ok]=set_io(model,graphics,... list([in,in2],it),... list([nout,nout2],ot),[],[]) end if ok then model.rpar = satur ; model.ipar = sgn ; graphics.exprs = exprs; x.graphics = graphics ; x.model = model ; break end end //** 'set' case 'define' then //** default values sgn = [1;-1] model = scicos_model() model.sim = list('summation',4) model.in = [-1;-1] model.out= -1 model.in2= [-2;-2] model.out2 = -2 model.ipar = sgn model.blocktype = 'c' model.dep_ut = [%t %f] exprs = sci2exp(sgn); gr_i = list(); gr_i_Icon = ['[x,y,typ]=standard_inputs(o) '; 'dd=sz(1)/8,de=0,' 'if ~arg1.graphics.flip then dd=6*sz(1)/8,de=-sz(1)/8,end' 'for k=1:size(x,''*'')'; 'if size(sgn,1)>1 then' ' if sgn(k)>0 then'; ' xstring(orig(1)+dd,y(k)-4,''+'')'; ' else'; ' xstring(orig(1)+dd,y(k)-4,''-'')'; ' end'; 'end'; 'end'; 'xx=sz(1)*[.8 .4 0.75 .4 .8]+orig(1)+de'; 'yy=sz(2)*[.8 .8 .5 .2 .2]+orig(2)'; 'xpoly(xx,yy,''lines'')'] gr_i_BackColor = 4 ; //** NativeIngerBackgroundColorDefault gr_i = list(gr_i_Icon, gr_i_BackColor) ; x = standard_define([2 3], model, exprs, gr_i) end endfunction

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EX16_5.sce

//Finding of Weight //Given D=0.05; v=1.5*10^-4; V=10; rho=1.25; Cd=0.5; //TO Find A=(%pi/4)*D^2; Fd=Cd*rho*A*((V^2)/2); disp("Weight of the ball ="+string(Fd)+" Newtons");

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ex_1_46.sce

//Example 1.46://limiting error clc; clear; dE=0.2;//erroe in modulus of elesticity d1=0.01;//change in width b=4.5;//width dB=d1/b;//error in width d2=0.01;//change in width D=0.9;//width dD=d2/D;//error in width d3=0.01;//change in beam L=45;//BEAM dL=d3/L;//error in beam d4=0.1;//change in deflection y=1.8;//deflectrion dy=d2/D;//error in deflection lr= (dE+dB+3*dD+3*dL+dy);//percentage limiting error disp(lr," peercentage limiting error in percentage is ±") // answer is wrong in the textbook

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Example_5.sce

//Chapter-3,Example 5,Page 57 clc; close; //Part (a) t_half= 1620 //half life of radium lamda= 0.693/t_half //as radium lose one centigram mass N_0=100 // in centigram N_1=N_0-1 t_1=log10(N_0/N_1)/(lamda*log10(%e)) printf('Part (a)---total number of years required are %.2f years ',t_1) // Part (b) N_2= 1 t_2=log10(N_0/N_2)/(lamda*log10(%e)) printf('\n Part (b)---total number of years required are %.2f years ',t_2)

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findcontours.sci

function [outputMat]= findcontours(inputImage, Mode, method, point_x, point_y) inputList=mattolist(inputImage); outputList=opencv_findcontours(inputList,Mode, method, point_x, point_y) for i=1:size(outputList) outputMat(:,:,i)=outputList(i) end endfunction

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problem2_9.sce

//problem 2.9 clc; clear; close; //given data : format('v',5); P=6;//No. of poles m=3;//No. of phase f=50;//in Hz Xo_int=1;//in ohm/phase Rrotor_int=0.1;//in ohm/phase //S=1 for starting S=1;//unitless disp("Max. Torque condition : R2=X2"); //Rext+Rrotor_int=Xo_int Rext=Xo_int-Rrotor_int;//in ohm/phase disp(Rext,"External resistance to be added(ohm/phase) : ");

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//Example 4_13 clc;funcprot(0); //Given data p_a=750;// mm of Hg p_v=400;// mm of Hg p_d=p_a-p_v;// mm of Hg V_c=13; // m/sec // Assume Friction loss and exit velocity of water head (V_a^2/(2*g))+h_f=V V=1.5;//m rho=1000;// kg/m^3 g=9.81;// m/s^2 //Calculation w=rho*g;// N h=(((p_a-p_d)*1.03*10^5)/(w*760))-((V_c^2)/(2*g))+V;// m printf('\nThe position of the kaplan turbine with respect to tail race,h=%0.2f m',h); // The answer vary due to round off error

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ex12_8.sce

//Transmission Lines : example 12-8 : (pg 597) Zo=100;//characteristic impedance j=%i; Zl = 200-j*150;//load impedance l=4.3;//length of transmission line x=200/Zo; y=150/Zo; a=0.4*Zo; b=0.57*Zo; mprintf("\nTo normalize the load impedance: \nzL = ZL/Zo = %.f - j*%.1f",x,y); //VSWR and equation of zin should b drawn from impedance smith chart,the plotted points should be read printf("\n zin = 0.4 + j*0.57");//from smith chart mprintf("\nZin = zin*Zo = %.f Ohm + j* %.f Ohm",a,b);

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s = poly(0,'s'); n1 = [s^2+2*s+2]; d1 = [(s+2)*(s+4)]; TF1 = syslin('c',n1/d1); subplot(1,4,1); evans(TF1,50); n2 = [1]; d2 = [s^3]; TF2 = syslin('c',n2/d2); subplot(1,4,2); evans(TF2,50); n3 = [1]; d3 = [s*(s+1)*(s+1)*(s+2)]; TF3 = syslin('c',n3/d3); subplot(1,4,3); evans(TF3,50); n4 = [(s+1)*(s+1)]; d4 = [s*(s+2)]; TF4 = syslin('c',n4/d4); subplot(1,4,4); evans(TF4,50);

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//area of ring between 2 concentric circles. //given,r1=97mm,r2=83mm clear; clc; close; r1=97;r2=83; //the area of ring is difference between the areas of 2 circles diff_in_area=(r1^2-r2^2); mprintf("difference in area=%ipi mm^2",diff_in_area)

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//Chapter 12 //Example 12.9 //page 479 //To calculate critcal clearing angle clear;clc; Pmax1=2; // prefault(2 lines) Pmax2=0.5; //deuring fault Pmax3=1.5; //post fault(1 line) Pm=1; //initial loading delta0=asin(Pm/Pmax1); delta_max=%pi-asin(Pm/Pmax3); //to find critical angle,using eq.12.67 delta_cr=acos((Pm*(delta_max-delta0)-Pmax2*cos(delta0)+Pmax3*cos(delta_max))/(Pmax3-Pmax2)); printf('Pmax1=%0.1f PU\t Pmax2=%0.2f PU\t Pmax3=%0.2f PU\n\n',Pmax1,Pmax2,Pmax3); printf('Delta0=%0.3f rad\n\n',delta0); printf('Delta_max=%0.3f rad\n\n',delta_max); printf('Delta_cr=%0.3f rad =%0.2f deg\n\n',delta_cr,delta_cr*180/%pi);

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function [rep]=x_choices(title,choices_l) // Copyright INRIA [lhs,rhs]=argn(0) if rhs<=0 then s_mat=['l1=list(''choice 1'',1,[''toggle c1'',''toggle c2'',''toggle c3'']);'; 'l2=list(''choice 2'',2,[''toggle d1'',''toggle d2'',''toggle d3'']);'; 'l3=list(''choice 3'',3,[''toggle e1'',''toggle e2'']);'; 'rep=x_choices(''Toggle Menu'',list(l1,l2,l3));']; write(%io(2),s_mat);execstr(s_mat); return;end; if typeof(title)<>'string' then write(%io(2),'x_choices first argument is not character string') return end if typeof(choices_l)<>'list' then write(%io(2),'x_choices argument is not a list') return end n=size(choices_l) items=['void'] defv=[] for i=1:n, l_ch=choices_l(i); if typeof(l_ch)<>'list' then write(%io(2),'x_choices(t,x): x('+string(i)+') is not a list'); return end if typeof(l_ch(1))<>'string' then write(%io(2),'x_choices(t,x): x('+string(i)+')(1) is not a string'); return end items= [items, l_ch(1)]; if typeof(l_ch(3))<>'string' then write(%io(2),'x_choices(t,x): x('+string(i)+')(3) is not vector of strings'); return end [xxxl,xxxc]=size(l_ch(3)); if xxxl<>1 then write(%io(2),'x_choices(t,x): x('+string(i)+')(3) must be a row vector of strings'); return end items= [items, l_ch(3)]; if typeof(l_ch(2))<>'constant' then write(%io(2),'x_choices(t,x): x('+string(i)+')(2) is not of type int'); return end if prod(size(l_ch(2)))<>1 then write(%io(2),'x_choices(t,x): x('+string(i)+')(2) must be an integer'); return end defv=[defv,l_ch(2)]; if n<>i then items=[items,"[--sep--]"];end end items=items(2:prod(size(items))) rep=xchoicesi(defv,title,items)

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clc,clear printf('Example 2.2\n\n') Pole=4 A=Pole //for lap winding V=230 Z=250 //number of armature conductors phi=30*10^-3 //flux per pole in weber I_a=40,R_a=0.6 //Armature resistance E_b=V - I_a*R_a // Since V= E_b+ I_a*R_a N=E_b * 60*A/(phi*Pole*Z) //because E_b = phi*P*N*Z/(60*A) printf('Back emf is %.0f V and running speed is %.0f rpm',E_b,N)

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disp('Лабораторная работа 1: метод Гаусса') Matrix = read("matr.txt", -1, 4); copyMatrix = Matrix; disp(Matrix,"Исходная матрица:") n = length(Matrix(:,1));; j = 1; tic; for i=1:n bla = 1; tmp = Matrix(i,i); while tmp == 0 if bla >= n then disp("Wrong matrix!") exit; end; swap = Matrix(i, :); Matrix(i, :) = Matrix(bla, :); Matrix(bla, :) = swap; tmp = Matrix(i,i); bla = bla + 1; end; bla = 0; Matrix(i,i) = 1; for j=n+1:-1:i Matrix(i,j) = Matrix(i,j)/tmp; end; for j = i+1:1:n tmp = Matrix(j,i); Matrix(j,i) = 0; for k = n+1:-1:i+1 Matrix(j,k) = Matrix(j,k) - tmp*Matrix(i,k); end; end; end; toc; disp(toc(),"Время на прямой ход:"); tic; solution = [0 0 0]; solution(n) = Matrix(n,n+1); for i=n-1:-1:1 solution(i) = Matrix(i,n+1); for j = i+1:1:n solution(i) = solution(i) - Matrix(i,j) * solution(j); end; end; disp(toc(),"Время на обратный ход:"); format(15); disp(solution,"Решение:"); disp("Вектор невязки:"); neviaz = [0 0 0]; for i = 1:1:n for j = 1:1:n neviaz(i) = neviaz(i) + copyMatrix(i,j)*solution(j); end; end; for i=1:1:n neviaz(i) = neviaz(i) - copyMatrix(i,n+1); end; disp(neviaz); delta = neviaz(1); for i = 1:1:n if abs(neviaz(i)) > delta then delta = abs(neviaz(i)); end; end; disp("Норма вектора невязки:"); disp(delta);

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//Function to round-up a value such that it is divisible by 10 function[v] = round_ten(w) v = ceil(w) rem = pmodulo(v,10) if (rem ~= 0) then v = v + (10 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution6_10.sce') //Obtain path of data file datapath = path + filesep() + 'data6_10.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate force required to shear the sheet W (N) W = (%pi * d * t * Sus) //Compressive stress in the screw sigmac (N/mm2) sigmac = Syt/fs //Core diameter of the screw dc (mm) dc = ((4 * W)/(%pi * sigmac))^(1/2) dc = ceil(dc) //Obtain the correct number of starts for the screw n for n = 1:1:%inf //Calculate the lead of the screw l (mm) l = n * p if (l > lmin) then break end end //Obtain the correct nominal diameter d in multiples of 10 (mm) for d = dc:1:%inf d = round_ten(d) //Calculate the mean diameter of the screw dm (mm) dm = d - (0.5 * p) //Calculate the lead angle alpha (degree) alpha = atand(l/(%pi * dm)) //Calculate the angle of repose (fi) fi = atand(mu) //Calculate the torque required Mt (N-mm) Mt = (W * dm * tand(fi + alpha))/2 //Calculate the new core diameter dcNew (mm) dcNew = d - p //Calculate the stress in the screw CNew (N/mm2) CNew = ((W * 4)/(%pi * (dcNew^2))) //Calculate the torsional stress tau (N/mm2) tau = (16 * Mt)/(%pi * (dcNew^3)) //Calculate the maximum shear stress tauMax (N/mm2) tauMax = (((CNew/2)^2) + (tau^2))^(1/2) //Calculate the afctor of safety fsNew fsNew = ((50/100)*Syt)/tauMax if(fsNew > fs) break end end //Calculate the efficiency of the screw eta (%) eta = (tand(alpha)/tand(fi + alpha))*100 //Calculate the number of threads z z = (4 * W)/(%pi * Sb * ((d^2) - (dcNew^2))) z = ceil(z) //Calculate the length of the nut L (mm) L = z * p //Calculate the shear stress in the screw tauS (N/mm2) to = p/2 tauS = (W/(%pi * dcNew * to * z)) //Calculate the shear stress in the nut tauN (N/mm2) tauN = (W/(%pi * d * to * z)) //Calculate the work done by the punch work (J) work = (W * (t/2))/1000 //Work done by balls workB (J) workB = work/(eta/100) //Calculate the average angular velocity wavg (rad/s) wavg = fsd/tf //Calculate the maximum angular velocity wmax (rad/s) wmax = 2 * wavg //Calculate the mass of the one ball m (kg) m = ((workB * 2)/(((Rm/1000)^2) * (%pi^2)))/2 //Calculate the diameter of the ball dia (mm) dia = ((m * 6)/(%pi * dense))^(1/3) //Print results printf('\nScrew\n') printf('\nNominal diameter of the screw(d) = %f mm\n',d) printf('\nCore diameter of the screw(dcNew) = %f mm\n',dcNew) printf('\nLead of the screw(l) = %f mm\n',l) printf('\nNut\n') printf('\nLength of the nut(L) = %f mm\n',L) printf('\nMass of each ball(m) = %f kg\n',m) printf('\nDiameter of each ball(dia) = %f mm\n',dia*1000)

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// regra 1/3 de Simpson function y=f(x) y = cos(x) endfunction // derivada de ordem 4 function y=df(x) y = cos(x) endfunction a = 0 b = 0.6 h = (b-a)./2 x1 = a x2 = x1+h x3 = b R = (h./3).*(f(x1) + 4.*f(x2) + f(x3)) printf("Aproximacao da integral: %g\n", R) // calculo do erro x = a:0.05:b err = ((h.^(5))./90).*max(abs(df(x))) printf("\nLimitante superior do erro: %g\n", err)

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// chapter 16 // example 16.5 // Calculate back-up time and charger peak output power // page-997-998 clear; clc; // given VA_rating=6; // in kVA V=230; // in V E=144; // in V PF=0.8; neta=0.85; // invertor efficiency AH_rating=500; // in AH E1=10.6, E2=13.4; // in V (range of battery voltage) E_normal=12; // in V (normal battery voltage) T=4; // in Hrs (charging time) t=8; // in Hrs capacity_derating=0.5; // calculate VA_rating=VA_rating*1E3; Battery_kW=VA_rating*PF/neta; // calculation of battery power num_Battery=E/E_normal; // calculation of number of batteries // considering worst case for calculation of discharge current Total_battery_voltage=E1*num_Battery; // calculation of total battery voltage // since Battery_kW=Total_battery_voltage*I_dc, therefore we get, I_dc=Battery_kW/Total_battery_voltage; // calculation of battery discharge current T_backup=AH_rating*capacity_derating/I_dc; // calculation of back-up time Ic=AH_rating*capacity_derating/T; // calculation of charging current P_peak=E*Ic; // calculation of charging peak power printf("\nThe back-up time is \t\t %.3f hours",T_backup); printf("\nThe charging peak power is \t %.f kW",P_peak*1E-3); // Note : There is calculation mistake in the book while calculating T_backup. Thats why answer in the book is wrong

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clc //initialisation of variables v= 0.02 //lb/ft sec L= 5 //in D= 2.5 //in M= 26 //lbf in w= 1200 //rev/min g= 32.2 //ft/sec^2 //CALCULATIONS C= %pi*v*w*2*%pi*D^3*L/(2*M*g*60*144) //RESULTS printf (' coefficient= %.4f in ',C)

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clear all; clc; disp("Scilab Code Ex 1.2 : ") f_d = 225; //N w_uniform = 800; // N/m l_ac = 0.200; //m l_cb = 0.05+0.1; //m l_bd = 0.100; //m l_bearing = 0.05; //m f_resultant = w_uniform*l_cb //120N l_f_resultant_b = (l_cb/2)+ l_bearing; //0.125m l = l_ac + l_cb + l_bearing + l_bd // This problem is solved by considering segment AC of the shaft. //Support Reactions: m_b = 0; // Net moment about B is zero for equilibrium . Sum Mb = 0. a_y = -((f_d*l_bd) - (f_resultant*l_f_resultant_b))/ (l - l_bd) // finding the reaction force at A // Refer to the free body diagram in Fig.1-5c. f_c = 40 //N //Balancing forces in the x direction: n_c = 0 //Balncing forces in the y direction: v_c = a_y - f_c //-18.75N - 40N-Vc = 0 // Balncing the moments about C: m_c = ((a_y * (l_ac + 0.05)) - f_c*(0.025) ) // Mc+40N(0.025m)+ 18.75N(0.250m) = 0 // Displaying results: printf('\n\nThe resultant force = %.2f N',f_resultant); printf('\nThe reaction force at A = %.2f N',a_y); printf('\nThe horizontal force at C = %.2f N',n_c); printf('\nThe vertical force at C = %.2f N',v_c); printf('\nThe moment about C = %.2f Nm',m_c); //-------------------------------------------------------------------END-----------------------------------------------------------------------------------------

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//chapter 4 //example 4.8 //calculate angle of first order diffraction maximum //page 78-79 clear; clc; //given K=0.02; // in eV (kinetic energy) d=2.0; // in Angstrom (Bragg's spacing) m=1.00898; // in amu (mass of neutron) amu=1.66E-27; // in Kg (1amu=1.66E-27 Kg) h=6.625e-34; // in J-s (Plank's constant) n=1; //order e=1.6E-19; // charge on electron //calculate //Since K=m*v^2/2 // therefore v=sqrt(2*K/m) // since lambda=h/(m*v) //therefore we have lambda=h/sqrt(2*m*K) m=m*amu; //changing unit from amu to Kg K=K*e; //changing unit to J from eV lambda=h/sqrt(2*m*K); // calculation of lambda printf('\nThe wavelength is \t\t =%1.1E m',lambda); lambda=lambda*1E10; //changing unit from m to Angstrom printf('\n\t\t\t\t =%.1f Angstrom',lambda); // Since 2dsin(theta)=n(lambda) // therefore we have theta=asind(n*lambda/(2*d)); // calculation of angle of first order diffraction maximum printf('\nThe angle of first order diffraction maximum is %.f Degree',theta);

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clc; clear; //Example 2.37 //Calculate the time required for a ball to attain a temperature of 423 K //Given k_steel=35 //W/m.K Cp_steel=0.46 //kJ/(kg*K) Cp_steel=Cp_steel*1000 //J/(kg*K) h=10 //W/sq m.K rho_steel=7800 //kg/cubic m dia=50 //mm dia=dia/1000 //m R=dia/2 //radius in m A=4*%pi*R^2 //Area in sq m V=A*R/3 //Volume in cubic meter Nbi=h*(V/A)/k_steel //As Nbi<0.10,internal temp gradient is negligible T=423 //K T0=723 //K T_inf=373 //K //(T-T_inf)/(T0-T_inf)=e^(-h*At/rho*Cp*V) t=-rho_steel*Cp_steel*R*log((T-T_inf)/(T0-T_inf))/(3*h); //s printf("Time required for a ball to attain a temperature of 423 K is %f s= %f h",t,t/(3600))

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Ex2_1.sce

// Exa 2.1 clc; clear all; // Given data N= 100; // Number of turns W=20; // Width of coil(mm) D= 30; // Depth of coil(mm) B= 0.1; // Flux density (wb/m^2) I= 10; // Current in coil(mA) K= 2*10^-6; // Spring constant(Nm/degree) // Solution A= W*10^-3*D*10^-3; // Area of coil(m^2) Td= B*N*A*I*10^-3; // Deflecting torque(Nm) disp("As deflecting torque = restoring torque(K*Theta)"); Theta= Td/K; printf(' The defecting torque = %.1f * 10^-6 Nm \n ', Td*10^6); printf('Therefore, the deflection = %d degrees \n ' , Theta);

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clc // // Variable declaration y=7 // Distance(in) s=-3.01 // Stress(ksi) // Calculation //Loading M=10230 // Couple of moment(kip.in) //Elastic Unloading sMl=((10230)*(8))/(1524.0) // Maximum stress(ksi) //Permanent Radius of Curvature p=(((7)*(29*(10**6))*((10**-3)))/(3.01)**-2) // Permanent radius of curvature(in) p=((p*0.083333)) // Conversion(ft) // Result printf("\n Case(a) Residual stress = %0.3f ksi' ,sMl) printf("\n Case(a) Permanent radius of curvature = %0.3f ft' ,p)

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function result = mlink_dsp_start(connection_id, model_tsamp) result = call("sci_mlink_dsp_start",.. connection_id, 1, "i",.. "out",.. [1,1], 2, "i"); result = mlink_set_obj(connection_id, 'model_tsamp', model_tsamp ); if result < 0 then disp("ERROR: Unable to set model sample rate - model will run with defaults") return; end endfunction

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function trainCascadeObjectDetector(outputFile,positiveInstances,negativeImages,varargin) //outputfile- ex.xml //positiveInstances- array of structure with field names path(string) and Bbox(4 length vector); //negativeImages- path to negative images folder //varargin- name,value pairs (Eg:numPos,numNeg,numStages,minHitRate,maxFalseAlarmRate,featureType,w,h) [lhs rhs]=argn(0); if rhs<3 then error(msprintf(" Not enough input arguments")) elseif rhs>23 then error(msprintf(" Too many input arguments to the function")) elseif modulo(rhs-3,2) error(msprintf(" wrong number of input arguments,name-value pairs not macthed")) end //validating variables [path,fname,extension]=fileparts(outputFile) if strcmp(extension,".xml") then error(msprintf(" wrong input argument #1,must be a string with an XML extension")) elseif ~isdir(negativeImages) error(msprintf(" wrong input argument #3,existing directory expected")) end //default values numPos=4; numNeg=2; numStages=30; precalcValBufSize=512 precalcIdxBufSize=512 featureType="HAAR" minHitRate=0.995 maxFalseAlarmRate=0.5 w=20 h=20 for i=1:2:rhs-3 if strcmpi(varargin(i),"numPos")==0 then i=i+1; numPos=varargin(i); if numPos<0 then error(msprintf(" numPos value must be positive")) end elseif strcmpi(varargin(i),'numNeg')==0 then i=i+1; numNeg=varargin(i); if numNeg<0 then error(msprintf(" numNeg value must be positive")) end elseif strcmpi(varargin(i),'numStages')==0 then i=i+1; numStages=varargin(i); if numStages<0 then error(msprintf(" numStages value must be positive")) end elseif strcmpi(varargin(i),'precalcValBufSize')==0 then i=i+1; precalcValBufSize=varargin(i); if precalcValBufSize<0 then error(msprintf(" precalcValBufSize value must be positive")) end elseif strcmpi(varargin(i),'precalcIdxBufSize')==0 then i=i+1; precalcIdxBufSize=varargin(i); if precalcIdxBufSize<0 then error(msprintf(" precalcIdxBufSize value must be positive")) end elseif strcmpi(varargin(i),'featureType')==0 then i=i+1; featureType=varargin(i); if strcmpi(featureType,'haar') & strcmpi(featureType,'lbp') & strcmpi(featureType,'hog') error(msprintf(" wrong input argument #%d,featureType not matched",i)); end elseif strcmpi(varargin(i),'minHitRate')==0 then i=i+1; minHitRate=varargin(i); if minHitRate<0 | minHitRate>1 then error(msprintf(" minHitRate value must lie in between 0 and 1")) end elseif strcmpi(varargin(i),'maxFalseAlarmRate')==0 then i=i+1; maxFalseAlarmRate=varargin(i); if maxFalseAlarmRate<0 | minFalseRate>1 then error(msprintf(" maxFalseAlarmRate value must lie in between 0 and 1")) end elseif strcmpi(varargin(i),'w')==0 then i=i+1; w=varargin(i); if h<0 then error(msprintf(" w value must be positive")) end elseif strcmpi(varargin(i),'h')==0 then i=i+1; h=varargin(i); if h<0 then error(msprintf(" h value must be positive")) end else error(msprintf(_(" Wrong value for input argument #%d",i))); end end [noOfPositiveInstances nCols]=size(positiveInstances); fields=fieldnames(positiveInstances); fd = mopen('positive.txt','wt'); for i=1:noOfPositiveInstances mfprintf(fd,'%s 1',getfield(fields(1),positiveInstances(i))); for j=1:4 mfprintf(fd,' %d',getfield(fields(2),positiveInstances(i))); end mfprintf(fd,'\n'); end mclose(fd); disp("Creating positive samples:"); cmd=sprintf("opencv_createsamples -info positive.txt -num%d -vec positive.vec -w %d -h %d",numPos,w,h); unix_w(cmd); if isdir(negativeImages) if getos()=="Linux" temp=strcat(["ls ",negativeImages]) elseif getos()=="Windows" temp=strcat(["dir ",negativeImages]) end s=unix_g(temp); [noOfFilesInFolder noOfCols]=size(s); fd = mopen('negative.txt','wt'); for i=1:noOfFilesInFolder [path,fname,extension]=fileparts(s(i)) if ~strcmp(extension,".jpg") | ~strcmp(extension,".jpeg") | ~strcmp(extension,".png") | ~strcmp(extension,".bmp") mfprintf(fd,'%s\n',s(i)); end end end disp("Training Cascade"); cmd=sprintf("opencv_traincascade -data %s -vec positive.vec -bg negative.txt -numPos %d -numNeg %d -numStages %d -precalcValBufSize %d -precalcIdxBufSize %d -featureType %s -minHitRate %d -maxFalseAlarmRate %d -w %d -h %d",outputFile,numPos,numNeg,numStages,precalcValBufSize,precalcIdxBufSize,featureType,minHitRate,maxFalseAlarmRate,w,h); unix_w(cmd); endfunction;

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// Exa 8.11 clc; clear; close; // Given data V_DS1 = 14;// in V V_DS2 = 5;// in V del_V_DS = V_DS1-V_DS2;// in V I_D1 = 3.3;// in mA I_D2 = 3;// in mA del_I_D = I_D1-I_D2;// in mA r_d = del_V_DS/del_I_D;// in k ohms disp(r_d,"The drain resistance in k ohms is"); V_GS1 = 0.4;// in V V_GS2 = 0.1;// in V del_V_GS = V_GS1-V_GS2;// in V I_D1 = 3.3;// in mA I_D2 = 0.71;// in mA del_I_D = I_D1-I_D2;// in mA g_m = del_I_D/del_V_GS;// in mA/V g_m = g_m * 10^3;// in µmhos disp(g_m,"The transconductance in µmhos is"); Miu =r_d*10^3*g_m*10^-6; disp(Miu,"Amplification factor is");

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clear; clc; Rg=8000;Zl=500+(%i*500);f=5*(10^6); //value of f as taken in solution w=2*%pi*f; Xc=-%i*imag(Zl); Rl=real(Zl); X21=sqrt(Rl*(Rg-Rl)); X22=-X21; X31=-Rg*sqrt(Rg/(Rg-Rl)); X32=-X31; X2a=X21+(Xc/%i); L2a=X2a/w; C3a=-1/(w*X31); printf("(a)X2 is inductive and X3 is capacitive where\n X2=L2 = %f mH\n",round(L2a*(10^3)*1000)/1000); printf(" X3=C3 = %f pf\n",round(C3a*(10^12)*1000)/1000); X2b=X22+(Xc/%i); C2b=-1/(w*X2b); L3b=X32/w; printf("(b)X2 is capacitive and X3 is inductive where\n X2=C2 = %f pf\n",round(C2b*(10^12)*100)/100); printf(" X3=L3 = %f mH",round(L3b*(10^3)*1000)/1000);

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** File Info Version: 1.0 Num Logs = 0 Num Trans = 0 Num Writers = 0 Init Tranlog = 0 Total Entries = 14 Tranlog Offset = 0 Transaction Id = 11 Index Free List = 12 Total Size of Data = 428 Data Transformation Id = 9 Index Transformation Id = 57 ** Freelist Info First freelist entry = 12 Iterating over freelist...(OK) Final freelist entry = 13 Total freelist entries = 2

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P1 = 300e03; V1 = 0.07; m = 0.25; T1 = 80+273; R = (P1*V1)/(1000*m*T1); P2 = P1; V2 = 0.1; T2 = (P2*V2)/(1000*m*R); W = -25; cv = -W/(m*(T2-T1)); cp = R+cv; S21 = m*cp*log(V2/V1); // S21 = S2-S1 disp("kJ/kg K",cv,"cv of the gas is") disp("kJ/kg K",cp,"cp of the gas is") disp("kJ/kg K",S21,"Increase in the entropy of the gas is")

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//Variable declaration: //From steam tables: U1 = 1237.1 //Internnal energy of gas (Btu/lb) U2_g = 1112.2 //Internal energy of gas (Btu/lb) U2_l = 343.15 //Internal energy of liquid (Btu/lb) //Calculation: Q = 0.5*(U2_g+U2_l)-1*U1 //Heat removed (Btu/lb) //Result: printf("Heat removed from the system during the process is : %.1f Btu/lb.",Q)

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i = imread('test1.jpg'); corners = corner(i,'Method','MinimumEigenValue'); disp(corners);

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//=========================================================================== //chapter 7 example 21 clc; clear all; //variable declaration R = 10; //resistance in Ω XL = 10; //reactance in Ω VL = 440; //load voltage in V //calculations Z = sqrt((R^2)+(XL^2)); //impedance of each choking coil in Ω VP = VL/sqrt(3); //phase voltage in V IP = VP/Z; //phase current in A IL = IP; //line current in A phi = atan(XL/R); //phase angle in ° phi1 = phi*180/%pi; W1 = VL*IL*cos((30*%pi/180)-(phi1*%pi/180)); //wattmeter reading in W W2 = VL*IL*cos((30*%pi/180)+(phi1*%pi/180)); //wattmeter reading in W //result mprintf("line current = %3.2f A",IL); mprintf("\nwattmeter reading = %3.2f W",W1); mprintf("\nwattmeter reading = %3.2f W",W2);

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clc; //page no 435 //problem no 12.9.1 ENR=10;// energy to noise density ratio Pbe1=1/2 * erfc(sqrt(ENR/2)); disp(Pbe1,'a)The bit error probability'); Pbe2=1/2 * %e^-(ENR/2); disp(Pbe2,'b)The bit error probability');

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clc clear T=[32,212];//Temperatures of ice point and steam point respectively P=[1.86,6.81];//P values at ice point and steam point respectively P1=2.5;//Reading on the thermometer //Calculations A=[log(P(2)) 1 log(P(1)) 1] //Coefficient matrix B=[T(2) T(1)] //Constant matrix X=inv(A)*B;//Variable matrix t=(X(1)*log(P1)+X(2));//Required temperature in degree C //Output printf('Temperature corresponding to the thermometric property is %3.0f degree C',t)

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//by Norton's Theorem I=2*10//total current produced by current source r=2*2/(2+2)//resultant resistance of current source In=20*r/(r+1)//norton current Rn=1+r//norton resistance I=In*Rn/(Rn+8) mprintf("Current through the load resistance of 8 ohm=%f A from A to B", I)

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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/MemoryAccess/BasicTest/BasicTest.tst load BasicTest.asm, output-file BasicTest.out, compare-to BasicTest.cmp, output-list RAM[256]%D1.6.1 RAM[300]%D1.6.1 RAM[401]%D1.6.1 RAM[402]%D1.6.1 RAM[3006]%D1.6.1 RAM[3012]%D1.6.1 RAM[3015]%D1.6.1 RAM[11]%D1.6.1; set RAM[0] 256, // stack pointer set RAM[1] 300, // base address of the local segment set RAM[2] 400, // base address of the argument segment set RAM[3] 3000, // base address of the this segment set RAM[4] 3010, // base address of the that segment repeat 600 { // enough cycles to complete the execution ticktock; } // Outputs the stack base and some values // from the tested memory segments output;

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//EXAMPLE 7.5 (a) disp(" Experiment: A die is tossed and the outcomes are observed"); disp("To find: probability (PM) of an event that one of the dice is 2 if the sum is 6"); E=["(1,5)","(2,4)","(3,3)","(4,2)","(5,1)"] //event that the sum of the two numbers on the two dice is 6 A=["(2,1)","(2,2)","(2,3)","(2,4)","(2,5)","(2,6)","(1,2)","(3,2)","(4,2)","(5,2)","(6,2)"] //event that 2 appears on atleast one die B= intersect(A,E) //possible combination of numbers on two die such that their sum is 6 and 2 appears atleast on one die PM=2/5 //since E has 5 elements and B has 2 elements //EXAMPLE 7.5(b) disp("A couple has two children"); b=1; //boy child g=2; //girl child S=[11,12,21,22] ; //sample space where 11 implies both children being boys,12 implies first child being a boy and the second child being a girl and so on disp("To find: probability(PM) that both children are boys "); //7.5(b).i L=S(:,1:3) //reduced sample space if it is known that one of the children is a boy PM=1/length(L) //7.5(b).ii R=S(:,1:2) //reduced sample space if it is known that the older child is a boy PM=1/length(R)

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/1913/CH1/EX1.23/ex23.sce

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FOSSEE/Scilab-TBC-Uploads

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ex23.sce

clc clear //Input data Z=0.76;//Barometer reading in m g=9.81;//Gravity in m/sec^2 d=13.6*10^3;//Density of Hg in kg/m^3 Pab=1.2*10^5;//Absolute pressure in N/m^2 do=0.8*1000;//Density of oil in kg/m^3 dw=1000;//Density of water in kg/m^3 dh=13.6*10^3;//Density of Hg in kg/m^3 //calculations Pa=dh*g*Z;//Atmospheric pressure in N/m^2 Pg=Pab-Pa;//Gauge pressure in N/m^2 Zo=Pg/(do*g);//Height of oil in manometer in m Pw=Pab-Pa;//Pressure exercted by water in N/m^2 Zw=Pw/(dw*g);//Height of water in manometer in m P=Pab-Pa;//Pressure of Hg in N/m^2 Zh=P/(d*g);//Height of Hg in manometer in m //Output printf('(a)The height of fluid for oil Manometer Zo = %3.2f m \n (b)The height of fluid for water Manometer Zw = %3.2f m \n (c)The height of fluid for Hg Manometer Zh = %3.2f m ',Zo,Zw,Zh)

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/668/CH3/EX3.3/eg3_3.sce

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eg3_3.sce

u = 8500*10^-4; //in m2/V.s Nd = 10^17; new_u = 5000*10^-4; m0 = 0.91 * 10^-30; //in kg m = 0.067*m0; q = 1.6*10^-19; t1 = m*u/q; disp(t1,"relaxation time(in s) = ") t2 = m*new_u/q; disp(t2, "If the ionized impurities are present, the time (in s) =") t_imp = t2*t1/(t1-t2); disp (t_imp,"The impurity-related time (in s) = ")

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/848/CH12/EX12.4/Example12_4.sce

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Example12_4.sce

//clear// //Caption:Full-width Half-Maximum(FWHM) soliton pulse normalized time //Example12.4 //page 446 clear; clc; close; Ts = [15e-12,50e-12]; //FWHM soliton pulse width To = Ts/1.7627; disp(To*1e12,'Normalized time for FWHM soliton pulse in pico seconds To =') //Result //Normalized time for FWHM soliton pulse in pico seconds To = [8.5096727 28.365576]

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/1319/CH12/EX12.8/i_8.sce

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i_8.sce

//To calculate current ratings and maximum voltage of a rated resistor. clc; clear; P=1; R=10*(10^3); // Using Power Equation and Ohm's Law. V=sqrt(P*R); I=sqrt(P/R); disp('volts',V,'The Maximum voltage of the resistor =') disp('amperes',I,'The Current rating of the resistor =')

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/clang/test/RC99/encoding/utils/goya.tst

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goya.tst

// RUN: %disasm -mcpu=dali -no-common-header %S/*.o | %tpc_clang -c -x assembler -march=dali - -o %ttest.o // RUN: %disasm -mcpu=dali -no-common-header -tpc-encoding-info -ignore-mov-dt %S/*.o > %tenc1.txt // RUN: %disasm -mcpu=dali -no-common-header -tpc-encoding-info -ignore-mov-dt %ttest.o > %tenc2.txt // RUN: diff %tenc1.txt %tenc2.txt // RUN: echo $? | FileCheck %s // CHECK: 0

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Ex16_12.sce

// chapter 16 // example 16.12 // Determine supply frequency // page-1037 clear; clc; // given del=2.5; // in mm (depth of heating) rho=5E-5; // in ohm-cm (resistivity) ur=1; // relative permeability // calculate del=del*1E-3; // changing unit from mm to m rho=rho*1E-2; // changing unit from ohm-cm to ohm-m f=(rho/ur)*(503/del)^2; // calculation of supply frequency printf("\nThe supply frequency is \t f=%.2f kHz",f*1E-3);

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Ch09Ex5.sce

// Scilab code Ex9.5: Pg 316 (2005) clc; clear; n = 1; // Principal quantum number Z = 2; // Atomic number of Helium E_a = (-13.6*Z^2)/n^2; // Energy of the electron in state 'a', eV E_b = (-13.6*Z^2)/n^2; // Energy of the electron in state 'b', eV E = E_a + E_b; // Total electronic energy of Helium, eV printf("\nTotal electronic energy of Helium = %5.1f eV", E); // Result // Total electronic energy of Helium = -108.8 eV

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inline_functions.tst

/////////////////////////////////////////////////////////////////////// /////////////// INLINE FUNCTIONS /////////////// /////////////////////////////////////////////////////////////////////// // These could be pretty dangerous, so in the next version of Toast I might make it so you call them // a bit like this: inline_func.execute() (assuming that I make the next version object oriented) let my_func(func) = let x = 10 func() print(x) end let inline_func = begin let x = 20 end my_func(inline_func) // will print 20 let my_result = inline_func() // can also be used as a regular function print(x) // but it has been inlined into the main program, so now x has been declared

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ex_8_12_1.sce

//Example 8.12.1: back emf ,Required armature voltage and Rated armatuer current clc; clear; close; //given data : format('v',7) TL=45;// in N-M N=1200;//in rpm Rf=147;//in ohm Ra=25;// in ohm Kv=0.7032; w=(2*%pi*N)/60; Vf=220;//in volts Kt=Kv; If=Vf/Rf; T=TL; Ia=T/(Kt*If); Eg=Kv*w*If; disp("part (a)") disp(Eg,"Back emf,Eg(Volts) = ") disp("part (b)") Ea=(Ia*(Ra/100))+Eg; disp(Ea,"Required armature voltage,Ea(volts) = ") disp("part (c)") rac=11191.4/Vf;// disp(rac,"rated armature current in amperes is")

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exa7_1.sce

// Example 7.1 // AC Power Calculations // From Example 6.8 we already found that, Z=complex(4.8,6.4); V_m=80; V_c_m=40; I_m=10*10^-3; // The total average power supplied by the source is, R_omega=4.8*10^3; R1=40*10^3; R2=5*10^3; P=0.5*R_omega*I_m^2; // Average Power // This power is actually dissipated by 40kohm and 5kohm resistor P_R1= V_m^2/(2*R1); P_R2=V_c_m^2/(2*R2); disp(P,"Total Average Power Dissipation(in Watt)=") disp(P_R1,"Power dissipated across 40kohm(in Watt)=") disp(P_R2,"Power dissipated across 5kohm(in Watt)=") if P==(P_R1+P_R2) then disp("This shows average power dissipation in the due to all resistors") end

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Exa4_16.sce

//Exa4.16 clc; clear; close; //given data Vs=16;//in volts RL=1.2;//in Kohm Rs=1;//in Kohm //If zener open circuited VL=Vs*RL/(Rs+RL);//in Volts disp(VL,"When zener open circuited Voltage across load in volts : "); disp("Since voltage across load VL is less than breakdown voltage of zener diode i.e. VL < Vz. The zener diode will not conduct and VL = 8.73 Volt"); Iz=0;//in mA disp(Iz,"Zener current in mA : "); Pz=VL*Iz;//in watts disp(Pz,"Power in watts : ");

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ex5_5.sce

//Exa:5.5 clc; clear; close; //Given: Fmx=107.218;//in MHz Fmn=107.196;//in MHz fm=4;//in Khz swing=Fmx-Fmn;//in MHz fd=swing/2; fc=Fmx-fd; m=(fd*10^3)/fm; printf("\n\t carrer swing = %f MHz",swing); printf("\n frequency deviation = %f KHz",fd*10^3); printf("\n career frequency = %f",fc); printf("\n modulation index = %f",m);

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Ex7_3.sce

clc // Given that J = 2 // The threshold value of dose in kJ/cm^3 h = 300 // Height in micro meter // Sample Problem 3 on page no. 448 printf("\n # PROBLEM 7.3 # \n") J_o = J*(exp(0.1*sqrt(h))) printf("\n The minimum level of exposure of the PMMA surface = %f kJ/cm^3",J_o)

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/Project 2/Experiments/GAssist-Interval-C/results/GAssist-Intervalar-C.abalone-10-1tra/result4s0.tst

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nickgreenquist/Intro_To_Intelligent_Systems

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result4s0.tst

@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005] @attribute Rings{15,7,9,10,8,20,16,19,14,11,12,18,13,5,4,6,21,17,22,1,3,26,23,29,2,27,25,24} @inputs Sex, Length, Diameter, Height, Whole_weight, Shucked_weight, Viscera_weight, Shell_weight @outputs Rings 16 9 7 8 10 7 11 9 11 9 11 9 9 9 8 8 10 9 8 8 11 10 9 9 12 9 7 9 9 9 8 8 9 8 13 9 14 10 4 5 11 10 21 10 13 10 10 10 12 9 9 9 10 9 9 8 7 8 11 10 9 7 19 10 10 10 11 9 13 10 18 10 15 9 8 8 13 10 21 10 14 10 7 7 12 9 8 8 11 10 9 9 10 9 15 10 10 9 10 9 16 10 12 9 10 8 9 9 10 9 9 7 19 9 14 9 12 10 15 10 13 10 12 10 9 8 5 5 11 7 7 8 15 9 17 10 9 8 12 8 18 9 7 8 10 8 10 8 6 8 10 8 19 9 14 9 17 9 23 9 16 10 9 8 7 7 4 5 16 8 14 9 9 8 11 8 13 9 12 9 20 10 17 9 14 10 11 10 11 10 5 5 12 10 12 9 6 7 6 7 6 8 9 7 7 7 9 7 6 9 11 10 11 10 6 5 6 7 5 7 6 7 8 7 8 7 7 7 6 8 7 8 8 9 9 9 8 10 9 10 8 10 11 10 4 5 6 7 7 7 8 7 8 9 6 8 9 9 10 9 8 9 8 9 9 9 9 10 9 9 9 10 8 9 8 9 14 10 9 10 10 10 11 10 6 5 5 7 5 7 8 8 9 7 9 9 10 9 9 9 8 9 11 9 11 10 10 10 12 10 10 10 11 10 10 10 11 10 3 5 4 5 5 7 7 7 5 7 7 8 9 9 11 9 11 10 6 7 7 7 7 7 7 7 9 9 8 9 10 10 10 9 10 10 9 9 9 10 13 10 11 10 10 10 9 10 12 10 11 10 5 5 10 10 10 10 9 10 10 10 9 10 8 7 7 7 8 9 9 9 9 9 9 9 9 10 9 9 11 10 15 10 11 9 12 10 10 10 10 10 13 10 13 10 6 5 7 7 8 7 9 9 10 9 5 5 9 7 8 10 10 10 8 9 7 7 9 7 8 9 8 9 9 7 7 8 10 9 7 5 8 8 20 10 9 9 17 10 17 10 7 7 14 10 7 5 8 7 9 9 15 10 8 7 17 10 13 10 18 10 10 8 12 9 14 9 16 8 14 10 10 9 13 10 16 9 10 8 10 8 8 8 11 9 13 9 11 9 20 10 8 8 14 9 8 9 9 9 9 9 10 10 12 10 7 7 7 9 9 9 12 10 5 5 6 7 6 7 7 7 7 7 7 7 7 7 7 9 9 9 9 10 6 7 8 7 7 7 8 7 8 9 8 9 10 9 10 9 10 10 11 9 9 9 13 10 11 10 7 7 8 9 10 10 11 10 5 5 10 9 8 10 9 9 9 10 10 9 10 10 10 9 11 10 11 10 12 10 12 10 6 7 10 9 10 9 9 10 9 9 9 9 13 10 11 10 6 5 8 7 10 9 10 9 9 9 15 10 15 10 10 10 6 8 5 5 10 9 14 7 12 10 11 9 13 8 12 9 18 10 11 9 13 9 12 9 11 7 12 8 12 8 8 5 15 9 16 10 6 5 7 7 6 7 8 9 8 9 10 10 10 10 3 5 6 7 8 7 10 10 6 7 6 7 8 7 8 7 8 9 8 9 10 10 9 10 11 9 9 10 11 10 11 10 8 7 8 7 8 7 7 7 10 9 11 9 9 10 12 9 10 10 11 10 11 10 12 10 10 10 11 10 7 7 7 7 9 7 9 7 10 10 10 9 11 9 9 9 8 9 8 10 10 10 9 9 11 10 9 8 15 10 7 9 12 9 12 10 4 5 13 9 9 7 11 10 6 7 10 10 8 7 7 7 10 9 8 9 13 10 13 10 9 10 13 10 11 10 9 10 11 10 7 7 8 7 9 9 8 9 10 9 10 10

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ex2_16.sce

// Example 2.16, page no-49 clear clc A1=12000 //first Apogee distance P=8000 // Perigee distance v1=1 // assume v1 as 1 v2=1.2*v1 //20% higher than v1 x=(v2/v1)^2 k=(((1+(P/A1))/x)-1) k=floor(k*10^4)/10^4 A2=P/k printf("A2 = %.0fkm",ceil(A2))

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19mcmi23jan17program5.sce

clc; clear all; clf(); lambda=2; x=grand(1000000,1,"exp",1/lambda); xmax=max(x); histplot(40,x,style=2); x=linspace(0,max(xmax),100); plot2d(x,lambda*exp(-lambda*x),strf="000",style=5) legend(["Exponential random simple histogram" "exact density curve"]); xlabel("Sample value"); ylabel("Exponential output values"); title("Exponential distribution data")

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ex6_11.sce

clear; //clc(); // Example 6.11 // Page: 121 printf("Example-6.11 Page no.-121\n\n"); //***Data***// x_b = 0; x_a = 1; // We have //dv_a/dx_a = 3*x_b^(2)+2*x_b // We have the equation // dv_b/dx_a = -(dv_a/dx_a)/(x_b/x_a) // So // dv_b/dx_a = -(x_a/x_b)*(3*x_b^(2)+2*x_b) dv_b_by_dx_a = x_a*(-3*x_b-2); printf("Value of the dv_b/dx_a at x_b =0 is %0.0f",dv_b_by_dx_a);

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Ex4_6.sce

clc Nd=5*10^16 disp("Nd = "+string(Nd)+"cm^-3") //initializing value of donor ion concentration. Na=0 disp("Na = "+string(Na)+"cm^-3") //initializing value of acceptor ion concentration. no=1.5*10^10 disp("no = "+string(no)+"cm^-3") //initializing value of electron and hole concentration per cm^3. n1=5*10^14 disp("n* = "+string(n1)+"cm^-3") //initializing value of excess electron carrier concentration. p1=5*10^14 disp("p* = "+string(p1)+"cm^-3") //initializing value of excess hole carrier concentration. KT=0.0259 disp("KT = "+string(KT)) //initializing value of thermal voltage. Ef_Efi=(KT*log(Nd/no)) disp("thermal equilibrium fermi level,(Ef_Efi)=(KT*log(n/no)))="+string(Ef_Efi)+"eV")//calculation. Efn_Efi=log((Nd+n1)/no)*KT disp("Excess carrier concentration ,(Efn_Efi)=(KT*log((n+n*)/no))="+string(Efn_Efi)+"eV")//calculation. Efi_Efp=log((Na+p1)/no)*KT disp("(Ef_Efi)=(KT*log((p+p*)/no))="+string(Efi_Efp)+"eV")//calculation.