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//To calculate the critical current T = 4.2; //temperature, K d = 1; //diameter, mm d = d*10^-3; //diameter, m Tc = 7.18; //critical temperature, K H0 = 6.5*10^4; //critical field, A/m Hc = H0*(1-(T/Tc)^2); //critical field at 2K, A/m ic = %pi*d*Hc; //critical current, A printf("critic...
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//Chapter 9 Ex 5 clc; clear; close; x=(5*((8^(1/3))+(27^(1/3)))^3)^(1/4); mprintf("The value of expression is %d",x);
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clc; //e.g 18.1 Vcc=12; Rc=2.2*10**3; Rb=240; B=50; Vbe=0.7; RE=0; Ic=(Vcc-Vbe)/(RE+(Rb/B));//collector current disp('mA',Ic,"Ic="); Vce=Vcc-(Ic*10**-3)*Rc;//CE voltage disp('V',Vce*1,"Vce="); Icsat=Vcc/Rc; disp('mA',Icsat*10**3,"Icsat="); Vcec=Vcc;//cutoff voltage i=5.45:-0.5:0; plot(i); a=gca() //get the current axes...
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clc clear //input data P=2.2//Pressure ratio across a gas turbine n=0.88//Efficiency of a gas turbine T1=1500//Inlet temperature of the gas in K r=1.4//ratio of specific heats for air //calculations T2s=T1*(1/P)^((r-1)/r)//Isentropic output temperature from gas turbine in K T2=T1-(n*(T1-T2s))//actual output ...
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funcprot() function [y]=carre(x) y = x*x endfunction
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//Ex6_11 clc; // Given: mPu=239.052161; mPd=107.903920; mXe=128.904784; mn=1.0087; mGd=154.922010; mBr=80.916344; // Solution: Part (a) dm1=(mPu-(mPd+mXe+2*mn));// delta m E1=dm1*931;// energy of given fission in MeV printf("The energy for the Pd(108)+Xe(129)+3n fission is = %f MeV",E1) dm2=(mPu-(m...
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funcprot(0); function[tree]=maketree(x) tree=zeros(30,1); for i=1:30 tree(i)=-1; end tree(1)=x; tree(2)=-2; endfunction function[tree1]=setleft(tree,tre,x) tree1=[]; i=1; while(tree(i)~=-2) if(tree(i)==tre) j=i; end i=i+1; end if(i>2*j) tree(2*j)=x; ...
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//Engineering and Chemical Thermodynamics //Example 8.10 //Page No:390 clear ; clc ; //Given R = 8.314 ; T = 10 + 273.15 ; //[K] A_B = 9.2806 ; // From Appendix A , Table A1.1 B_B = 2788.5 ; // From Appendix A , Table A1.1 C_B = -52.36 ; // From Appendix A , Table A1.1 A_C = 9.1325 ; // From Appendix A , Ta...
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mode(0) global temp heat fan sampling_time m heatdisp fandisp tempdisp x name global scn scd tcn tcd rcn rcd gamm //**Sampling Time**// sampling_time = 1; ///////****///////// getd "dc/scilab" exec ("twodof_para.sce"); m = 1; dt = getdate(); year = dt(1); month = dt(2); day = dt(6); hour = dt(7); minutes = dt(8)...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 53 Read Example 52 of the Text Book clc; disp("CHAPTER 2"); disp("EXAMPLE 53"); //VARIABLE INITIALIZATION v=230; //in Volts angle_v=30; //in degrees I1=20; //in Amperes angle_I1...
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// example 1.19<a> //determine whether the following signals are power or energy signal clc ; t =0:0.01:100; A=1; x=A*sin(t); P=(integrate('(A*sin(t))^2','t',-%pi,%pi))/(2*%pi); disp(P,'The power of the signal is:'); E=(integrate('(A*sin(t))^2','t',-%pi,%pi)); disp(E,'The energy is:'); disp('As t tends to inf...
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errcatch(-1,"stop");mode(2); H=0.2; //m rho=1000; //kg/m^3 rho_Hg=13600; //kg/m^3 g=9.81; //m/s^2 dp=(rho_Hg-rho)*g*H; disp("Differential pressure =") disp(dp) disp("N/m^2") exit();
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 4, Example 14") //Nodal distance Deltax in m deltax = 0.1; //Time in seconds t = 25*60; //timestep deltaT in seconds deltaT = 500; //Number of increment n =...
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//Microwaves and Lasers : example 16-1 : pg(753) h=0.3;//curve depth of parabolic reflector D=3;//diameter of parabolic reflector f=D/(16*h);//focal length printf("\nFocal length(f)= D/16.h = %.3f m",f); mprintf("\nThe focal length is %.3f m out from the center of the parabolic reflector",f);
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clc; clear; n=3 //third order reflection lambda=97 //wavelength in pm (third order) tetha1=23 //Braggs angle for first order in degree tetha2=60 //Braggs angle for third order in degree //calculation lambda_1=(n*lambda*sind(tetha1))/sind(tetha2) d=(n*lambda)/(2*sind(tetha2)) mprintf("\nThe wavelength that ...
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// Ex 50 Page 395 clc;clear;close; // Given I12=2000;//A (I12=I1+I2) R1=0.04;//ohm R2=0.025;//ohm rf1=25;//ohm rf2=20;//ohm E1=440;//V E2=420;//V //E-Vad=V where Vad=I1+V/rf1 //V*(1+R1/rf1)+R1*I1=E1//eqn(1) //V*(1+R2/rf2)-I1*R2=E2-I12*R2// eqn(2) A=[(1+R1/rf1),R1;(1+R2/rf2),-R2]; // matrix for solution B=[E1;E2-I12*R...
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// Example 2.4 // Ladder Calculations //From figure 2.8(a) v_s=40; // Value of Voltage source R_par=((20*20)/(20+20))*10^3;//Equivalent resistance of two parallel 20k ohms resistors R_ser=(4+5+6)*10^3;//Equivalent resistance of three series resistances. //from figure 2.8(b) R_eq= 2*10^3+ ((10*15)/(10+15))*10^3; ...
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Example_8_9.sce
//Example 8.9 From the following table calculate TFR GRR NRR clc; clear; R=0.48; BR=[23.6 114.9 145.1 122.6 79.6 35.9 3.3]; YL=[4482 4426 4359 4288 4202 4100 3979]; SRR=BR./1000; TFR=sum(SRR)*5; GRR=R*TFR; NRR=(R*sum(SRR.*YL))/1000; disp(NRR,"Net Reproduction Rate =",GRR,"Gross Reproduction Rate =",TFR,"Total...
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// Exa 1.3 clc; clear; close; // Given data format('v',13) N_D= 6*10^18;// in per cube cm N_A= 3*10^15;// in per cube cm ni= 2.5*10^12; Nn= N_D-N_A;// in per cube cm rho_n= ni^2/Nn;// in per cube cm // Part (i) disp(rho_n,"The concentration of holes in n-type in per cm^3 is : ") disp(Nn,"Concentration of ...
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clear// //Variables V = 6 //Voltage (in volts) R1 = 1 //Resistance (in ohm) R2 = 2 //Resistance (in ohm) R3 = 3 //Resistance (in ohm) //Case (a): //Calculation RT = R1 + R2 + R3 //Equivalent Resistance (in ohm) I = V / RT //C...
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// Example 4.11: To determine all parameters of transistor amplifier v_o=90; // (V) v_i=9; // (V) R_sig=100*10^3; // (ohm) R_L=10*10^3; // (ohm) v_sig=10; // (V) A_vo=v_o/v_i; disp(A_vo,"A_vo (V/V)") G_vo=v_o/A_vo; disp(G_vo,"G_vo (V/V)") R_i=G_vo*R_sig/(A_vo-G_vo) disp(R_i,"R_i") disp("assume R_L = 10 kilo...
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clear // // // //Variable declaration k=1.000074; epsilon0=8.85*10^-12; //relative permeability(F/m) E=1; //electric field(N/C) n=2.69*10^25; //molecular density //Calculations p=epsilon0*E*(k-1)/n; //dipole moment(coulx metre) //Result printf("\n dipole moment is %0.2f...
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scenario = "One-Back-Arm"; # This name is recorded in the log file scenario_type = trials; response_matching = simple_matching; response_logging = log_all; active_buttons = 3; #button_codes = 1, 2, 3; # These values will be used to code participant responses #target_button_codes = 0, 0, 2; button_codes = 0, 0, 2; tar...
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// Example 18.4, page no-462 clear clc N= 2.7*10^25//atoms m^-3 alfe=0.35*10^-40 //F m^2 eps=8.854*10^-12 epsr=(1+(2*N*alfe)/(3*eps))/(1-(N*alfe)/(3*eps)) printf("The dielectric constant of Ne gas is %.8f",epsr)
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(TOP (ADVP (POS No)) (POS ,) (NP (POS it)) (VP (POS was) (POS n't) (NP (POS Black) (POS Monday))) (POS .)) (TOP (POS But) (SBAR (POS while) (S (NP (POS the) (NML (POS New) (POS York)) (POS Stock) (POS Exchange)) (VP (POS did) (POS n't) (VP (POS fall) (ADVP (POS apart)) (NP (POS Friday)) (SBAR (POS as) (S (NP (POS the)...
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20_4.sce
clc //initialisation of variables R= 8.31*10^7 //ergs deg^-1 mole^-1 T= 20 //C s= 4.3*10^-13 //sec D= 6.15*10^-7 //cm^2 sec^-1 d= 0.9982 //g/cc v= 0.735 //cm^3 g^-1 //CALCULATIONS M= R*(273+T)*s/(D*(1-d*v)) //RESULTS printf ('molecular weight serum albium = %.f g mole^-1',M)
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//CH-1 PAGE-43 PB-3 // // l=1.2 //length al=30 //map length al=al/100 sc=1000 //suitable scale RF=(al)/(sc*l) printf("\n RF= %0.3f ",RF) cm1=(1/RF)/(100) lsc=15 cm15=lsc*cm1 printf("\n length of scale is %0.3f meters',cm15)
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//Example 9.8 // Natural Response of a Series LRC Circuit // From figure 9.17 L=0.1; R=14; C=1/400; // Since Excitation is zero by definition of natural response ,we set v_s'=0 in standard 2nd order diffrential equation // homogeneneous differential equation will be // i_L''+(R/L)*i_L'+(1/(L*C))*i_L=0 s=%s; p...
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# 3^1*(108*r^2 + 20*r + 1) = 2 * m^2 + n^2 ? 0 3 1 3^2*43 = 2 * (7)^2 + (17)^2 proper representation by 7^2 + 17^2 = 2 * (3^2)^2 + (3*5)^2 = 2 * (13)^2 + (7)^2 proper representation by 13^2 + 7^2 [3] 2 3*11*...
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example_8_4.sce
clear; clc; disp("--------------Example 8.4---------------") N=200; n=(N/2)^(0.5); // formula k=2*n-1; // formula crossbars_1stage=N/n; // formula crosspoints_1stage=n*k; // formula crossbars_2stage=k; // formula crosspoints_2stage=n*n; // formula crossbars_3stage=N/n; // formula crosspoints_3stage=k*n; // ...
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clf for k=1:1000 x(k)=k pi1(k)=MojePi1(k) pi2(k)=MojePi2(k) end err1=abs/*modulo*/(pi1-%pi) err2=abs(pi2-%pi) X=log(x) Y1=log(err1) Y2=log(err2) clf plot(X,Y1,'.r') plot(X,Y2,'.b') [a1,b1]= methodOfLeastSquares(X,Y1) [a2,b2] = methodOfLeastSquares(X,Y2) plot(X,a2*X+b2) plot(X,a1*X...
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clc //given that n = 4 // number of crystals per unit cell A_c = 22.99 // molar mass of cation i.e. sodium A_a = 35.45 // molar mass of cation i.e. chlorine r_c = 1.02e-8 // radius of sodium atom in cm r_a = 1.81e-8 // radius of sodium atom in cm N_a = 6.023e23 // Avogadro constant printf("Example 4.6\n")...
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clear funcprot(0) A = [0.05 0.85 0.05 0.25; 0.45 0.05 0.45 0.25; 0.45 0.05 0.05 0.25; 0.05 0.05 0.45 0.25] v = rand(4, 1) res = [0.62427; 0.57716; 0.41225; 0.32745] // Power method for k = 1:20 w = A * v lambda = v' * w v = w / norm(w) end check = norm(v - res)
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clear //Given // // o = 22.5 //degrees , The angle of infetisimal wedge A = 1 //sq.mm The area of the element A_ab = 1*(cos((%pi/180)*(o))) //sq.mm - The area corresponds to AB A_bc = 1*(sin((%pi/180)*(o))) //sq.mm - The area corresponds to BC S_1 = 3 //MN The stresses applying on the element S_2 = 2 //M...
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//Exa 4.1 clc; clear; close; L=poly(0,'L') //Defining L as lambda l=10*L N=20 // number of elements d=l/N // formula : BW=(2*(L/d)*1/N) BW1=(horner((2*L/(N*d)),1)) disp(BW1,"Null-to-null BW of broadside array in radians when l=10*L,N=20:") l=50*L N=100 // number of elements d=l/N // formula : BW=(2*(L/...
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R2=0.5 X2=5 Tm_by_Tfl=3.5 Ts_by_Tfl=R2*Tm_by_Tfl*2*X2/(R2^2+X2^2) disp(Ts_by_Tfl) Ts_by_Tfl2=Ts_by_Tfl/3 disp(Ts_by_Tfl2) Ts_by_Tfl3=0.7*0.7*Ts_by_Tfl //calculation mistake in the book at this point disp(Ts_by_Tfl3)
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//All the quantities are expressed in SI units M_inf = 2; //freestream mach number rho_inf = 0.3648; //freestream density at 11 km altitude T_inf = 216.78; //freestream temperature at 11 km altitude gam = 1.4; //ratio of specific heats R...
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clear //T < +∞ exec('C:\Users\Julien Guégan\Documents\Cours\MAM4\STAGE\2 cohorts\Tfini\Fonctions 2 cohorts - T fini.sci',-1) T = 20 t = 0:T // CI M01 = 400 M02 = 400 n1 = 100 n2 = 1 n = n1+n2 Mee = fsolve(0,eqnM) τee = fsolve(0,list(lambda,Mee)) disp(" M** = "+string(Mee)+" , τ** = "+string(τee)) Mσ = 1600:50:2...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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// Scilab code Exa11.10 : : Page-538 (2011) clc; clear; e = 1.6023e-19; // Charge of an electron, C E = 70*1.6e-13; // Energy, electron volts R = 0.28; // Radius of the orbit, metre c = 3e+08; // Velocity of light, metre per sec B = E/(e*R*c); // Magnetic field intensity, tesl...
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//Optical Fiber communication by A selvarajan //example 4.3 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; //given clear all; Eg=1.3//band gap energy in eV l=0.4//cavity length in mm R1=0.5//reflectivities on ends R2=0.5//reflectivities on ends alpha=3//loss coefficient in /mm current_density=...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 4, Example 16") disp("At eye root, Ca = 150 m/s") Ca = 150; C1 = Ca / cos(20*%pi/180) Cw1 = Ca*tan(20*%pi/180) disp("Impeller speed ...
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// Exa 1.22.1 clc; clear; close; // Given data a = 4.8;// in Å h = 2; k = 1; l = 1; d = a/(sqrt( ((h)^2) + ((k)^2) + ((l)^2) ));// in Å disp(d,"The distance between d_211 plains in Å is");
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Nx=200; Nt=200; kappa=0.01; exec("my_cholesky.sce") dt = 1/Nt dx = 1/Nx function y=phi_0(x) if (x >= 0) & (x < 0.25) then y = 0 elseif (x >= 0.25) & (x < 0.375) then y = 2*(x - 0.25) elseif (x >= 0.375) & (x < 0.5) then y = 2*(0.5 - x) elseif (x >= 0.5) & (x <= 1) then y ...
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//chapter 5 //example 5.3 //page 426 clear; clc; disp("example 5.3"); printf("\n"); slots=48; //number of slots poles=4; //4-pole machine ph=3; //3-phase machine SA=360/slots; //slot angle printf("total number of slots= %d\n",slots); printf("slot angle= %f degree mechanical\n",SA); //c...
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errcatch(-1,"stop");mode(2); disp('no.of permutations=9!/(2!*2!*2!) ') factorial(9)/(factorial(2)*factorial(2)*factorial(2)) exit();
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function [stk,txt,top]=sci_quit() // Copyright INRIA txt=['quit'] stk=list(' ','-1','?','?','?')
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// LQG control design by polynomial method, to solve Eq. 13.51 on page 472. // 13.4 // LQG controller design by method of Ahlen and Sternad // function [R,degR,S,degS] = ... // lqg(A,degA,B,degB,C,degC,k,rho,V,degV,W,degW,F,degF) function [R,degR,S,degS] = ... lqg1(A,degA,B,degB,C,degC,k,rho,V,degV,W,degW,F,d...
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clear; clc; // Illustration 6.4 // Page: 342 printf('Illustration 6.4 - Page: 342\n\n'); // solution //*****Data*****// T = 298; // [K] Fa = 200; // [feed, kmole/hr] zf = 0.6; yd = 0.95; xd = yd; xw = 0.05; q = 0.5; // [Lf/F] //*****// printf('Illustration 6.4(a) - Page: 342\n\n'); // Solution ...
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//CHAPTER 8 ILLUSRTATION 7 PAGE NO 229 //TITLE:BALANCING OF ROTATING MASSES clc clear pi=3.141 mA=48// mass of A in kg mB=56// mass of B in kg mC=20// mass of C in kg rA=1.5// radius of A in cm rB=1.5// radius of B in cm rC=1.25// radius of C in cm N=300// speed in rpm ...
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//Ex5_11 //Inverse Filtering // Version : Scilab 5.4.1 // Operating System : Window-xp, Window-7 //Toolbox: Image Processing Design 8.3.1-1 //Toolbox: SIVP 0.5.3.1-2 //Reference book name : Digital Image Processing //book author: Rafael C. Gonzalez and Richard E. Woods clc; close; clear; xdel(winsid())//to close all c...
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/////////////////////////////////////////////////////////////////////// /////////////// ROCK, PAPER, SCISSORS /////////////// /////////////////////////////////////////////////////////////////////// print("Rock, paper scissors") let getInput() = print("Type 'rock', 'paper' or 'scissors'. Type 'quit...
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//======================================================================== //chapter 6 example 4 clc; clear; //input data l = 100; //length in cm d = 0.008; //diameter of wire in cm R = 95.5; //resistance in ohm A = %pi*0.004*0.004;...
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clear all; clc; disp("From figure 4.7a, H=235ft, Q=170 gpm at b.e.p. of 57.5%. ") disp("The corresponding NPSHR is 8.7ft. From the steam table we have pv=3.73 psia at T=150 degrees Farenheit") disp("Also NPSPA=pt-pf+rho*g*Z-pv is greater than or equal to NPSPR ") disp("Thus we can determine the value of Z") NP...
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clc clear //Input data tw3=45;//The temperature of warm water in degree centigrade wc1=6;//The cooling water inflow in kg/s V=10;//volume flow of ID fan in m^3/s Ws=4.90;//Heat absorbed by air in kW ti=20;//The temperature of air entering the tower in degree centigrade R=60;//The relative humidity in percentag...
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function err = fi(xponto, x, u) // f implita // Define os parametros do sistema a = 1; b = -1; d = 0.2; // Desempacota os estados, suas derivadas, e a entrada x1 = x(1); x2 = x(2); x1ponto = xponto(1); x2ponto = xponto(2); u1 = u(1); // Calcula o erro da solucao err1 = x1ponto - x2; err2 = x2ponto + d*x2 + b*x1 + a*...
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d = 0.004 ; // thickness of wire in m R0 = 0.5 ; // radius of cylinder in m E = 200e09 ; // Modulus of elasticity of steel s = 1200e06 ; // proportional limit of steel M = (%pi*E*d^4)/(32*(2*R0+d)) ; // Bending moment in wire in N-m disp("N-m",M,"Bending moment in the wire is ") s_max = (E*d)/(2*R0+d) ; // Maximu...
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// Example 5.2 An Experimenter wished to study the effect of 4 fertilizers clc; clear; T_Obs= 24; T_df= 23; df_f=3; df_wg=20; disp(df_wg,"the df for With in groupis (23-3)= ",df_f,"df for fertilisers (4-1)=",T_df,"Total degree of freedom (df) is (24-1)= ",T_Obs, "Total observation ="); Total_SS=6212; F_SS=2940...
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//Example 3.5: clc; clear; close; //given data : format('v',5) Ie=5*10^-3;// in A alfa=0.95; I_co=10*10^-6;// in A Ic=((alfa*Ie)+I_co)*10^3; Ib=(Ie-(Ic*10^-3))*10^6; disp(Ic,"Collector current,(mA) = ") disp(Ib,"Base current,(micro-A) = ")
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// Chapter5 // Page.No-171, Figure.No-5.4 // Example_5_1 // Maximum gain // Given clear;clc; fo=5; // Break freq of the op-amp in Hz s=%s; A=200000; // Gain of the op-amp at 0 Hz H=syslin('c',(A*fo*2*%pi)/((fo*2*%pi)+s)); fmin=1; fmax=100000; bode(H,fmin,fmax); Aol=40; printf("\n Maximum gain is = %.f dB...
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load Esc8.hdl, output-file Esc8.out, compare-to Esc8.cmp, output-list in%D1.3.1 out%D1.3.1; set in %D116, eval, output; set in %D110, eval, output; set in %D114, eval, output; set in %D34, eval, output;
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 5 //Some Applications of the Laws of Thermodynamics //Example 22 clear; clc; //Given: r = 8; //compression ratio T1 = 290; //temperature at beginning (K) P1 = 100; //pressure at the beginning (kPa) Q1 = 450; //heat transferred per cycle (kJ...
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// Examle 17.1 f=50; // Frequency p=4; // No.Of poles Ns=(120*f)/p; // Synchronous speed N=1410; // No.Of Revolution in rmp I=2.9; // I/p current V=230; // Supply voltage CosQ=0.71; // Power f...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); codeblock readtextfile(ScriptDir+"\MarsProject\Sub\SUB_general.sci"); codeblock readtextfile(ScriptDir+"\MarsProject\Sub\SUB_CreateMarsGeoGlobe.sci"); codeblock readtextfile(ScriptDir+"\MarsProject\Sub\SUB_CreateMarsSurf...
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//Example 8.2 clc clear function [f] = dydt(t,y) f = (y-t) / (y+t); endfunction y0 = 1; t0 = 0; t = 0.1; n = 5; h = (t-t0)/n; tt = t0; y = y0; for i = 1:n y = y +h*dydt(tt,y); y = round(y*10^4)/10^4; tt = tt + h; end disp(y,"y(t = 0.1) = ")
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# Collection of Testcases for Common #!java -cp dist/dbat.jar org.teherba.common.RegressionTester
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clc //initialisation of variables h1=3221.6 //kj/kg s1=7.399 //kj/kgk sf2=0.521 //kj/kgk sfg2=7.808 //kj/kgk hf2=152 //kj/kg hfg2=2415 //kj/kg t1=653 //temp in k t2=309.2 //temp in k v=0.1006*10^-2 p1=10 //pressure in bar p2=0.06 //pressure in bar h3=152 //kj/kg x=110 y=639.7 z=610 a=2015 //CALCULATIO...
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function [x,y,typ]=vol_div(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [...
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0101 1001 0000 0000 0000 0000 0101 1111 0101 0011 0000 0000 0000 0000 0000 0000 0100 0010 0000 0000 0000 0001 0000 1100 0100 0110 0000 0000 1001 1100 0000 0001 0101 1000 0000 0000 0000 0000 0101 1111 0101 0011 0000 0000 0000 0000 0000 0010 0101 0011 0000 0000 0000 0000 0000 0000
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clc; Rin=454000; Rs=1000; Rth=(Rin*Rs)/(Rin+Rs); Cgd=0.000000000004; Gm=0.004; rD=3325; CinM=Cgd*(Gm*rD+1); Cgs=0.000000000005; Cg=Cgs+CinM; Cg=0.0000000000622; f2G=1/(2*3.14*Rth*Cg); CoutM=0.000000000004; Cds=0.000000000002; CL=0.000000000001; Cd=CoutM+Cds+CL; f2D=1/(2*3.14*rD*Cd); disp('MHz',f2G/1000...
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clc //initialization of varaibles T=100 //F P=1000 //psia //calculations disp("From table 4") dvf=-5.1*10^-5 dhf=2.7 vf=0.01613 hf=67.97 v=vf+dvf h=hf+dhf //results printf("Enthalpy = %.2f B/lb",h) printf("\n Volume = %.5f cu ft/lb",v)
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//chapter 11 //example 11.12 //page 338 clear all; clc ; //given Rl=50;//load resistance in kohm Vcc=12;//supply voltage V f1=150;//lower cutoff frequency Hz Vp=50;////op voltage mV hfe=70; ip=Vp/Rl; Ie2=2;//Ie2>ip Ve2=5; R4=Ve2/Ie2; printf("\nR4= %.1f kohm ,use standard value 2.2 kohm",R4);R4=2.2; Ic2=...
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PL/SQL Developer Test script 3.0 16 -- Created on 10.09.2014 by ZHURAVOV_VB declare -- Local variables here h xxdoo.xxdoo_html := xxdoo.xxdoo_html('xxdoo','xxdoo_cntr_contractor_typ'); m clob; begin --dbms_session.reset_package; return; -- Test statements here h := h.h('p',h.G('name')).each('sites',h.h('p...
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//Volme flow rate of water(in m^3/sec): Q=0.0084; //Length of horizontal pipe(in m): L=100; //Diameter of pipe(in m): D=0.075; //Density of water(in kg/m^3): d=999; //Friction factor: f=0.017; //Minor lossses coefficient: K=0.5; //Viscosity(in kg/m-s): u=10^-3; //Acceleration due to gravity(in /sec^2): g...
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//Example 7.18 // the longitudinal and hoop stress clc; clear; close; //given data : ex=1540; ey=-420; A=110*10^-6; // in m^2 P=25*10^3; // load in N ax=P/A; by=0; E=(ax/ex); mu=(ey*E)/ax; disp(E*10^-3,"modulus of elasticity,E(GN/m^2) = ") disp(-mu,"poisson ratio,ey = " )
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v=10; l=10; r=100; f=60; disp("Part a"); disp("the dc output voltage (in V) is"); disp(v); disp("Part b"); x_l=2*%pi*f*l; vo=v*r/x_l; disp("the ac output voltage (in V) is"); disp(vo);
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function zf = filtic (b, a, y, x) //This function finds the initial conditions for the delays in the transposed direct-form II filter implementation //Calling Sequence //zf = filtic (b, a, y) //zf = filtic (b, a, y, x) //Parameters //b: vector of real or complex numbers //a: vector of real or complex numbers //y: v...
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//Exa 4.26 clc; clear; close; //Given data : r=2/100;//m d1=4;//m d2=4;//m d3=8;//m epsilon_o=8.854*10^-12;//permitivity CN=2*%pi*epsilon_o/log((d1*d2*d3)^(1/3)/r);//F disp(CN,"Part(i) Capacitance per phase per meter length(F) : "); h1=20;//m h2=20;//m h3=20;//m h12=sqrt(20^2+4^2);//m h23=sqrt(20^2+4^2)...
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x=[0 0.0112910099304681; 0.0375437844553138; -0.0502505723940154; 0.0237536810920502; 0.00286337692936232; -0.0268585407773543; -0.00670100836859748; 0.00681025234400021; 0.0743232780915911]; fs=4e6; [R LT UT LL UL]=risetime(x,fs); disp(R); disp(LT); disp(UT); disp(LL); disp(UL); //output // 0.0000002 // // 0.000...
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//Calculate voltage and current gain and input and output resistance clear; clc; //soltion function [z]=prll(r1,r2)//Function for the parallel combination of resistor z=r1*r2/(r1+r2); endfunction //given //DC analysis Vcc=12;//V Rb=200*10^3;//ohm Rc=1*10^3;//ohm B=100;// beta Ib=Vcc/Rb; Ic=B*Ib;...
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// Example 4-2, page 95 clear;clc; close; // Given data // refer to the diagram // turns ratio 5:1 V1=120;// primary voltage in volts // Calculations V2=V1/5;// secondary voltage in volts Vpin=V2/0.707;// peak secondary voltage in volts // with ideal diode Vpout=Vpin; Vdc=Vpout/%pi; disp("Volts",Vpout,"Peak voltag...
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clear; clc clf pi = 2*3.14 M=2.9288 //mean anomaly angle e = 0.9 //eccentricity tolerance = 1.e-6 //error tolerance //Select a starting value for E: //Iterate using the Newton Rhapson Method Residue = 1 E= ones(360,1) E1= ones(360,1) for M = 1:1:360 while abs(Residue) > tolerance E(M) = E(M)- (E(M) - e.*sin(E(M)...
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clc // Given that lambda = 5e-7 // wavelength of light in meter mu_o = 1.5442 // refractive index for ordinary light mu_e = 1.5533 // refractive index for extraordinary light // Sample Problem 16 on page no. 218 printf("\n # PROBLEM 16 # \n") t1 = lambda/(2*(mu_e - mu_o)) t3 = 3*t1 t5 = 5*t1 // calculation for thick...
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GenerateData.sci
function [Xtrain,Dtrain,Xtest,Dtest]= GenerateData(TrainingRate) DEFINE_DBG=0; //definitions NUM_REPLICAS = 15; NUM_EXP = 10; NUM_TRAINING=round(TrainingRate*NUM_REPLICAS); // read csv file StringData = read_csv('data.csv'); data = evstr(StringData); if DEFINE_DBG == 1 then disp(data); end //mounting training a...
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ii_14.sce
// EMF induced in coils parallel to each other clc; clear; Nx=1000; Ix=5; flux1=0.05*(10^-3); di=12; dt=10^-2; K=60/100; Lx= Nx*flux1/Ix; // Since two coils are identical, Both will have equal self inductances. Ly=Lx; M=K*sqrt(Lx*Ly); Ey=M*di/dt; disp('volts',Ey,'The EMF induced by the coi...
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EX_1_5.sce
//Example 1 5 clc ; clear; close; f=9; //assuming frequency to be a constant 9Hz. t =0:.1:10; x1= cos (2* %pi *f*t); x2=t+x1; plot (t,x2); xlabel('Time'); ylabel('Amplitude'); title('Plot of given sequence to test periodicity'); disp ( 'Plotting the signal and showing that it is APERIODIC' );
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pataddtn.tst
(set-strategy depth) (unwatch all) ; pataddtn.clp test (clear) (open "pataddtn.rsl" pataddtn "w") (load "compline.clp") (dribble-on "pataddtn.out") (load "pataddtn.clp") (reset) (agenda) (dribble-off) (printout pataddtn "pataddtn.clp differences are as follows:" crlf) (compare-files pataddtn.exp pataddtn.out pataddtn) ...
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Ch10Ex8.sce
// Scilab Code Ex10.8: Page-512 (2011) clc;clear; q1 = 8e-007;....// First Charge, C q2 = -8e-007;....// Second Charge, C r = 15e-002;....// Distance between the two charges, m k = 9e+009; // Coulomb's constant, N-metre-square/coulomb-square E1 = k*q1/r^2;....// Electric field strength due to charge 8e-007 C pri...
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Exa5_4.sci
//Write equation of modulated wave for (a) FM (b) PM and when modulating frequency is changed to 2Khz fc = 25e+6; fm = 400; del = 1e+4; wc = 2*%pi*fc; wm = 2*%pi*fm; mf = del/fm; disp(wc, ' Equation of modulated wave in FM for case (a) is V = 4sin( ') disp(mf,' t + ') disp(wm, 'sin ') disp('t (FM...
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//Example 2-44// //add -3 to 2 in one's complement using 4 bits// clc //clears the window// clear //clears all the existing variables// x=2 y=bitcmp(3,4) //complement of the decimal number 2// z=x+y a=dec2bin(z) //binary conversion// disp('binary form of the number obtained by adding -3 to 2') disp(a) //r...
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// Exa 4.6 clc; clear; close; // Given data Vrms=120;// in mV Iav= 1.25;// in mA I_max= 1/0.318*Iav;// in mA Vmax= sqrt(2)*Vrms;// in mV R2= Vmax/I_max;// in ohm disp(R2,"Value of R2 in ohm") // when input voltage is 60 volt Vrms=60;// in mV Vmax= sqrt(2)*Vrms;// in mV I_max= Vmax/R2;// in mA Iav= I_max*...
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// Example 2.13 // Calculation of (a) core radius and (b) maximum value of angle of acceptance of the fiber // Page no 483 clc; clear; close; //Given data lambda=1320*10^-9; // Wavelength of fiber delta=0.077; // Relative refractive index n1=1.48; // Refractive i...
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letraD.sce
clear; clc; load('C:\Users\italo\OneDrive\Documentos\UFRN\std\projeto2\Sinais_STD\xa_3_1.sod') sinal_mensagem_ana=x_a; load('C:\Users\italo\OneDrive\Documentos\UFRN\std\projeto2\Sinais_STD\xa_23_1.sod') sinal_mensagem_italo=x_a; load('C:\Users\italo\OneDrive\Documentos\UFRN\std\projeto2\Sinais_STD\xa_28_1.sod') ...
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rssq.sci
function out = rssq(in, orientation) //This function calculates the square root of the sum of values of input vector IN. // //Calling Sequence //OUT=rssq(IN) //OUT=rssq(IN,orientation) // //Parameters //in:Vector or Matrix of real or complex elements. //orientation: A string with possible values "r", "c" or "m" or num...
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12Q7.sce
clc T3=12 a=27.8 T1=T3*(tand(45+a/2))^2 Tf=T1-T3 printf('the deviator stress at failure = %f lb/in^2',Tf)
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7_8.sce
clc; clear; w=20;//m Q=125;//(m^3)/s ratio=1/15; t=24;//hours wm=ratio*w;//m //Vm/(gm*lm)^0.5 = V/(g*l)^0.5 //gm=g //Q=VA and lm/l=1/15 //hence Qm/Q = ((lm/l)^0.5)*((lm/l)^2) = ratio^2.5 Qm=(ratio^2.5)*Q; //V=l/t //tm/t=(V/Vm)*(lm/l)=ratio^0.5 tm=(ratio^0.5)*t;//hours disp("m",wm,"The required model widt...