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clc //solution //given lc=3000//mm//length of steel and copper bar lst=3000//mm//length of steel bar Ec=105//kN/mm^2//young's modulus of copper Est=210//kN/mm^2//young's modulus of steel b=25//mm//width t=12.5//mm//thickness P=50//kN//load applied //refer fig 4.14 in book //let dl be increace in length of compound bar...
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// Exa 3.7 clc; clear; close; // Given data n=2; V_T=26;// in mV Io= 30;// in mA // (i) when I_D= 0.1;// in mA V_D= n*V_T*log(I_D/Io);// in mV disp(V_D,"(i) When I_D is 0.1 mA, The junction forward-bias voltage in mV is : ") // (ii) when I_D= 10;// in mA V_D= n*V_T*log(I_D/Io);// in mV disp(V_D,"(ii) Whe...
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//Chapter-3, Example 3.33, Page 117 //============================================================================= clc clear //INPUT DATA k=200;//Thermal conductivity of aluminium in W/m.K t=0.001;//Thickness of fin in m L=0.015;//Width of fin in m D=0.025;//Diameter of the tube in m Tb=170;//Fin base tempe...
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//variable initialization RestEnergy=0.51 //rest energy of electron (Mev) //calculation of minimum energy of a gamma ray photon which is required to produce an electron positron pair E=2*RestEnergy; //minimum energy of gamma ray photon (Mev) pr...
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// Exa 6.25 clc; clear; close; // Given data I_DSS = 20;// in mA V_P = 4;// in V I_D = I_DSS;// in mA disp(I_D,"The maximum drain current in mA is"); V_GS = -V_P;// in V disp(V_GS,"The gate source cut off voltage in volts is"); R_DS = V_P/I_DSS;// in kΩ disp(R_DS*10^3,"The value of ohmic resistance in Ω is"...
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//Page Number: 11.21 //Example 11.16 clc; //(b)I(X;Y) //Given a=0.5; p=0.1; //As we know //P(Y)=P(X)*P(Y/X) //We have PX=[a (1-a)]; PYbyX=[(1-p) p;p (1-p)]; PY=PX*PYbyX; //As H(Y)=-Sum of[P(yi)log2P(yi)] //Where i=0 to n; HofY=0; for i=1:2 HofY=HofY+(PY(i)*log2(PY(i))); end //For BSC, I(X;Y)...
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[[2,0,0,2,0],[0,-2,1,-1,-1],[2,0,1,1,1]] [4,-3,5] [12,-5,13]*3 [24,-7,25]*7 [40,-9,41]*13 [60,-11,61]*21 [84,-13,85]*31 [112,-15,113]*43 [[-2,2,2,0,0],[0,2,1,-2,-1],[-2,2,1,-2,-1]] [1,0,-1]*2 [-8,15,-17] [-45,28,-53]*2 [-352,135,-377] [-475,132,-493]*2 [-2088,455,-2137] [-2009,360,-2041]*2 [[2,0,2,0,0],[0,0,2,0,1],[2...
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clear // // // //Variable declaration h=6.6*10^-34; //planck's constant(J-sec) m=9.1*10^-31; //mass of electron(kg) c=3*10^8; //velocity of light(m/sec) lamda=0.82*10^-10; //wavelength(m) //Calculations E=h*c/lamda; //energy(J) lamda=h*10^10/sqrt(2*m*E); //wavelength of...
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//Chapter 6 //Example 6.10 //Page 159 //impedance //run clear command then execute dependancy file and then the source file //dependency file is pucalc.sci clc; //Given P_g = 300e6; V_g = 20e3; X11_g = 0.20; l = 64; V_m = 13.2e3; P_m1 = 200e6; P_m2 = 100e6; X11_m = 0.20; T1_P = 350e6; T1_vht = 230e3; T1_vlt = 20e3; x_...
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// Example 9_3 clc;funcprot(0); // Given data m=0.800;// kg/s V_1=93.0;// m/s // Station 1 p_1=97.0;// kPa T_1=80.0;// °C // Station 2 p_2=101.3;// kPa g_c=1;// The gravitational constant c_p=523;// J/(kg.K) R=208;// J/(kg.K) // Calculation T_2=(T_1+273.15)+((V_1^2)/(2*g_c*c_p));// K S_p=m*((c_p*log(T_...
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// Example 2.14.b:Maximum Core Readius clc; clear; close; n1=1.48;//Waveguide Refractive Index d= 0.01;// Cange in core-cladding refractive index a=2;// parabolic refractive index h=1.3;//wavelngth in micro meters v= 2.4*sqrt(1+(2/a));//maximum value of normalised frequence a= (v*h)/(2*%pi*n1*sqrt(2*d));//Core...
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# careful. t1 m1 t2 m1 m2 t3 m2 =T:3 M:2 t:1 m:1
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function stepdetails(resp) // This program is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 2 of the License, or // (at your option) any later version. // // This program is distribu...
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clc //initialisation of variables t1=5.25//yr t2=10.00//yr yi=171000//in ye=111000//in yt=5.23300//in yl=5.04532//in yn=31500//in ym=0.09853//in tm=9.25//yr tn=10.00//yr //CALCULATIONS T=t1/t2//yr T1=tm/tn//yr Y=yi-ye//in Yt=yt-yl//in //RESULTS printf('the fifth intercensal year =% f yr',T) printf('t...
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//programa: aphi_sup.sce //Superposição em Poço 1D de Potenciais Infinitos clear; N = 100; //Número de Pontos L = 1e-9;//[m] x = linspace(0,L,N);//[m] h = 6.626e-34; //[J.s] hb = h/(2*%pi); m = 9.1e-31; //[kg] A = sqrt(2/L); n1 = 1; //Nível de Energia-1 n2 = 2; //Nível de Energia-2 kn1 = n1*%pi/L; //[rad/m] kn2 = ...
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clc clear //DATA GIVEN P=400; //maximum value of force that can be developed in N mu=0.25; //coefficient of friction d=0.6; //diameter of drum in m //Refer the figure theta=180+45; //angle of contact in degrees theta=theta*(%pi)/180; ...
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clc; p1=3; // Pressre of air at state 1 in bar p2=p1; // constant pressure process T1=450; // Temperature of air at state 1 in kelvin T2=1250; // Temperature of air at state 2 in kelvin T3=1000; // Temperature of air at state 3 in kelvin V3=50; // Velocity of air at state 3 in m/s T4=800; // Temperature of air a...
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//Exa 1.20 clc; clear; close; //given data cos_fi=0.8;//unitless fi=acosd(cos_fi); tan_fi=tand(fi);//unitless //For Alternator A : cos_fi_A=0.9;//unitless fi_A=acosd(cos_fi_A); tan_fi_A=tand(fi_A);//unitless //Formula : Active load, KW=V*I*cos_fi //Formula : Reactive load, KVAR=V*I*sin_fi ActiveLoad=8000...
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errcatch(-1,"stop");mode(2);//Example 3.24 : concentration of iron ; ; format('v',9) //given data : d=7.87; N=6.023*10^23; // avogadro's number A=55.85;// atomic weight I=A/N;// mass of iron atom atom=d/I; disp(atom,"number of atoms(atoms/cm^3) = ") exit();
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@relation unknow @attribute COMPACTNESS real[73.0,119.0] @attribute CIRCULARITY real[33.0,59.0] @attribute DISTANCECIRCULARITY real[40.0,112.0] @attribute RADIUSRATIO real[104.0,333.0] @attribute PRAXISASPECTRATIO real[47.0,138.0] @attribute MAXLENGTHASPECTRATIO real[2.0,55.0] @attribute SCATTERRATIO real[112.0,265.0]...
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permutaties.sce
function r=swap(s,x,y) // wissel in vector s element x en y van plaats r=s; r(y)=s(x); r(x)=s(y); endfunction function permutatie(n) // vind alle permutaties van 1...n // in lexicografische volgorde s=1:n; disp(s); for i=2:factorial(n) m=n-1; while s(m)>s(m+1) // zoek het eerste eleme...
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Example_10_5.sce
//Caption: Forecasting //Simple Moving Average Method //Example10.5 //Page381 clear; clc; Dt = [24,30,27,24,39,45,42,51];//Demand Di n = length(Dt);//Month (t) //Three months moving average for i = 3:n Mt(i-2) = mean(Dt([(i-2):i])); end disp(Mt,'Three Months moving average Mt=') for i = 1:length(Mt)-1 ...
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clc h1=2776.4; //kJ/kg h2=h1; h_f1=884.6; //kJ/kg h_fg1=1910.3; //kJ/kg x1=(h1-h_f1)/h_fg1; disp("Initial dryness fraction = ") disp(x1)
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ch_4_eg_10.sce
clc disp("the solution of eg 4.10 -->Series of Stirred Tanks with Coil Heaters") Cp=2000,A=1,U=200,m=1000,mdot=2,Ts=250 //given data T0=20, T1=0, T2=0, T3=0 //from energy balances for the tanks we have accumulation=inlet-outlet T1_steady=(mdot*Cp*(T0)+U*A*(Ts))/(mdot*Cp+U*A) disp(T1_steady,"th...
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Example6_8_a.sce
errcatch(-1,"stop");mode(2);//Example 6.8(a) ; ; Vs=15; A=10; Vim=0.5; SR=0.5*10^6; Vom=A*Vim; fmax=SR/(2*%pi*Vom); printf("fmax=%.f kHz",fmax*10^(-3)); exit();
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ex4_7.sce
clc; clear all; V = 120000; // Volume of hall in cubic meters T = 1.5; // Reverberation time TSA = 25000; // Total absorbing surface area in square meters A = (0.163*V)/T TA = A/TSA;//The average absorbing power of the surface disp('Sabine',TA,'The average absorbing power of the surface is ') // Slight variatio...
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Ex4_5.sce
clc //Variable Initialisation Ea=220//Input Voltage to armature in volts N1=1000//Rated Speed of Motor in rpm N2=500//Speed of Motor in rpm Ia=24//Armature Current in Ampere Ra=2//Armature resistance in ohm Es=230//Source voltage in Volts //Solution Eb1=Ea-(Ia*Ra) Eb2=(N2/N1)*Eb1 E0=Eb2+(1.2*Ia*Ra) d=E0/Es ...
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4_13.sci
//4.13 clc; d_rate=100; fc= 0.5*d_rate; printf("cutt off frquency =%.1f kHz ",fc)
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clc //Chapter 11:Power amplifiers //example 11.2 page no 466 //given Po=5//max power in watts Rl=50//load resistance in ohm //asumme'1:1 truns ratio transformer coupled push pull amplifier each supllying 2.5 watt' disp('since a push pull amplifier is used, each class B amplifier will supply 2.5W') Pomax=2.5 Vc...
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C2P3.sce
clear clc //to find magnitude and direction of resultant of a and b and c vector // GIVEN:: //coefficient in x direction for vector a ax = 4.3 //coefficient in y direction for vector a ay = -1.7 //coefficient in x direction for vector b bx = -2.9 //coefficient in y direction for vector b by = 2.2 ...
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ok_bv.tst
; checks bit vector sorts (set-logic QF_BV) (declare-fun x () (_ BitVec 4)) (declare-fun y () (_ BitVec 1)) (declare-fun z () (_ BitVec 4)) (assert (= x #b0101 )) (assert (= z #xa ))
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14_5.sce
//To find gyroscopic couple and direction clc //Given: N=1500 //rpm m=750 //kg omegaP=1 //rad/s k=250/1000 //m //Solution: //Calculating the angular speed of the rotor omega=2*%pi*N/60 //rad/s //Calculating the mass moment of inertia of the rotor I=m*k^2 //kg-m^2 //Calculating the gyroscopic couple transmit...
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ch4_22.sce
clear; clc; V_r=1000; //rating of SCR I_r=200; //rating of SCR V_s=6000; //rating of String I_s=1000; //rating of String disp("when DRF=.1"); DRF=.1; n_s=V_s/(V_r*(1-DRF)); printf("number of series units=%.0f",ceil(n_s)); n_p=I_s/(I_r*(1-DRF)); printf("\nnumber of parrallel units=%.0f",ceil(n...
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Ex6_9.sce
clear ; clc; // Example 6.9 printf('Example 6.9\n\n'); printf('Page No. 157\n\n'); // given P = 10;// Boiler pressure in bar Ts = 180;// Steam temperature in degree celcius Tf = 80;// Feed water temperature in degree celcius X = 0.95;// Steam dryness fraction m_s = 4100;// steam rate in kg/h m_f = 238;// G...
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Example_4_3.sce
//Example 4.3 (b) clear; clc; //Given a=1.24;//alpha at 290K and 1 atm in 10^-3 K^-1 b=9.3;//beta at 290K and 1 atm in 10^-5 atm^-1 T=290;//temperature in K delS=2.1;//entropy change in J K^-1 mol^-1 //to calculate the change in molar volume delV=(delS*b)/(a*100*101.325);//change in molar volume in dm^3 mo...
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clc cp=1.11; T3=883; //K T2a=529; //K W_turbine=290.4; //kJ/kg W_net=48.2; //kJ/kg Qs=cp*(T3-T2a); n_thermal=W_net/Qs*100; disp("Thermal efficiency =") disp(n_thermal) disp("%") W_ratio=W_net/W_turbine; //Work ratio=net work output/Gross work output disp("Work ratio =") disp(W_ratio)
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example_6_1.sce
//Chapter 6 //Example 6-1 //ProbOnThresholdVoltage //Page 149,151, Figure 6-1 clear;clc; //Given R1 = 100*10^3 ; R2 = 86*10^3 ; Vsatp = 15 ; Vsatm = -15 ;//Saturation voltages Vut = (R2 * Vsatp)/(R1 + R2); Vlt = (R2 * Vsatm)/(R1 + R2); printf ( "\n\n Upper Threshold Voltage = %.4f V ", Vut ) printf ( "\n\...
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example9_8.sce
//clc() F = 100;//kg xf = 0.15; P1 = 80;//% ( Carbonate recovered ) M1 = 106;//(Molecular weight of Na2CO3) M2 = 286;//(Molecular weight of Na2CO3.10H2O) x1 = M1 / M2;//(Weight fraction of Na2CO3 in crystals) Mrecovered = P1 * F * xf / 100; Wcrystal = Mrecovered / x1; disp("kg",Wcrystal,"(a)quantity of crystal...
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//Example number 9.1, Page number 202 clc;clear; close; //Variable declaration e=1.6*10**-19; //charge(c) ni=2.4*10**19; //particle density(per m**3) mew_e=0.39; //electron mobility(m**2/Vs) mew_h=0.19; //hole mobility(m**2/Vs) //Calculation rho=1/(ni*e*(mew_e+mew_h)); //resistivity(ohm m) /...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 7: PARALLEL OPERATION // Example 7-4 clear; clc; close; // Clear the work space and console. // Given data P1 = 300 ; // Power rating of generator 1 in kW P2 = 600 ; // Power rating of generator ...
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//Calculating secondary voltage and voltage regulation //Chapter 3 //Example 3.16 //page 218 clear; clc; disp("Example 3.16") kVA=10; //rating of the transformer V1=2000; //primary voltage in volts V2=400; //secondary voltage in volts R1=5.5; //prim...
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//Example 5.4.4 page 5.15 clc; clear; Ts= 10*10^-9; Tn=9*10^-9; Tc=2*10^-9; Td=3*10^-9; BW= 6*10^6; Tsyst= 1.1*sqrt(Ts^2+(5*Tn)^2+(5*Tc)^2+Td^2); Tsyst=Tsyst*10^9;//converting in ns for displying... Tsyst_max = 0.35/BW; Tsyst_max=Tsyst_max*10^9;//converting in ns for displying... printf("Rise system of th...
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//Example number 9.12, Page number 208 clc;clear; close; //Variable declaration n=5*10**17; //concentration(m**3) vd=350; //drift velocity(m/s) E=1000; //electric field(V/m) e=1.6*10**-19; //charge(c) //Calculation sigma=n*e*vd/E; //conductivity(per ohm m) //Result printf("conductivity is %.3f per oh...
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RLG_Euler.sci
function [P,Q,THETA,SUCCESS,NB_TRY] = RLG_Euler(STANCE,NORMALS,PARAMS) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: // Cxy,WS_proj_R0,footPlane_Rmat,zFinalInterval,psiInter,thetInter,phiInter //[] //INPUT //STANCE: Row array of the current...
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Example5_19.sce
//Exa 5.19 clc; clear; close; //Given data : L=80;//km f=50;//Hz Z=(0.15+%i*0.78)*L;//ohm Y=(%i*5*10^-6)*L;//mho A=1+1/2*Y*Z;//parameter of 3-phase line D=A;//parameter of 3-phase line B=Z*(1+1/4*Y*Z);//parameter of 3-phase line C=Y;//parameter of 3-phase line disp(A,"Parameter A : "); disp(B,"Parameter B...
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clc clear //Inputs V1=0.028; P1=1; T1=27+273; n=1.3; V2=0.0046; T3=T1; T2=T1*((V1/V2)^(n-1)); printf('Temperature after compression: %1.2f K',T2); printf('\n'); P2=P1*((V1/V2)^n); W=((P1*100*V1)-(P2*100*V2))/(n-1); printf('Work Done: %1.2f kJ',W); printf('\n'); P3=(T3*P2)/T2; printf('Final Pres...
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example12_4.sce
//example 12.4 //page 454 clc; funcprot(0); //initialisation of variable Q=500/449; D=8/12; pi=3.14; g=32.2; N=1800;//rpm A=pi*D^2/4; V=Q/A; f=0.022//from chart HL=V^2/2/g*(12.1+224.9*f); hs=HL+119.4; Ns=N*sqroot(Q*449)/hs^0.75; disp(Ns,"specific speed (rpm)"); clear
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lax_fried.sce
clear u u1 u2 u3 tr x x1 nu col=['-+b'; '-+g'; '-+r'; '-+c']; iter=1; flag=1; //lambda=input('lambda : '); while(flag) //h=input('Enter space step h : '); h=1/20; k=lambda*h; ax=-3; bx=3; at=0; bt=2; n=(bt-at)/k + 1; m=(bx-ax)/h + 1; //True Solution for comparison //t...
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//Part B Chapter 4 Example 1 clc; clear; close; R=75;//mm G=75;//GN/m^2 L=3;//m tau_s=75;//MN/m^2 theta=tau_s*L/R/G*180/%pi;//degree disp("Angle of twist is "+string(theta)+" degree."); r=50;//mm tau=tau_s*r/R;//MN/m^2 disp("Shear stress at inside surface is "+string(tau)+" MN/m^2");
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8_11.sce
clc //initialisation of variables Vm= 0.6 //in^3 N= 2400 //rpm Qa= 6.5 //gpm p= 50 //CALCULATIONS ev= Vm*N*100/(Qa*231) Tf= (100-ev)*Qa/100 Cl= p*Tf/100 //RESULTS printf ('Case drain loss = %.3f gpm',Cl)
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clc; f=50 //Frequence in hertz Irms=20 //Rms current in amperes Im=Irms*sqrt(2) disp("(i)") printf("\n Im=%02f A \n",Im) t=0.0025 //Time in seconds i=Im*sin(2*%pi*f*t) disp("(ii)") printf("\n i=%.0f \n",i) t=0.0125 i=Im*sin(2*%pi*f*t) disp("(iii)") printf("\n i=%.0f \n",i) i1=14.14/Im disp(i1) i2=asin(i...
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// Scilab Code Ex13.11: Page-652 (2011) clc;clear; mu = 1.5;....// Optical index of refraction of NaCl crystal K = 5.6;....// Static dielectric constant of NaCl crystal P_IP = (1-((mu^2-1)*(K+2))/((mu^2+2)*(K-1)))*100; printf("\nThe percentage of ionic polarizibility in NaCl crystal = %4.1f percent ", P_IP); //...
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// plot max hold graphs // change directory to the desired location to save these plot files cd('C:\Documents and Settings\pflynn\Desktop\Max hold plots'); clf() plot([x],evstr(A)) //threshold line plot([x],threshold,'r--') // plots a dash-dotted line // give it titles xset("font size", 3) /...
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9_1_1.sce
clc //initialisation of variables d= 1.6 //lb/ft^3 vk= 6.2*10^-6 //ft^2/sec R= 1.8 //lbf v= 100 //ft/sec d1= 64 //lb/ft^3 vk1= 1.7*10^-5 //ft62/sec l= 10 //ft //CALCULATIONS u= v*vk1/(vk*l) u1= v*vk1/(vk*l*1.98) r= d1*l^2*(u/100)^2/d F= r*R //RESULTS printf (' resistance= %.f lbf ',F)
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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clear; clc; V=400; V_ph=V/sqrt(3); N_s=1000; N=800; a=.7; I_d=110; R=2; k=1-((1-N/N_s)*(2.339*a*V_ph)/(I_d*R)); printf("value of duty cycle=%.3f",k); P=I_d^2*R*(1-k); I1=a*I_d*sqrt(2/3); r1=.1; r2=.08; Pr=3*I1^2*(r1+r2); P_o=20000; P_i=P_o+Pr+P; eff=P_o/P_i*100; printf("\nefficiency=%.2f",eff); ...
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13_5.sce
clear; clc; Y1=1;Y2=1;Y3=2;V3=3; Z1=1/Y1;Z2=1/Y2;Z3=1/Y3; V1=1;I1=-1; z11=V1/I1; V2=1;I2=3; z22=V2/I2; z21=V2/I1; printf("z11 = %f ohms\n",z11); printf(" z22 = %f ohms\n",z22); printf(" z21 = %f ohms\n",z21); printf(" z11 = %f ohms\n",0);
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clc //initialisation of variables h1= 182.07 //kJ/kg h4= 76.26 //kJ/kg h2= 217.97 //kJ/kg Q= 10^6 //kJ/h Tc= -5 //C Th= 32 //C //CALCULATIONS COP= (h1-h4)/(h2-h1) W= Q/(COP*3600) COPcarnot= (273.15+Tc)/(Th-Tc) //RESULTS printf (' COP= %.2f ',COP) printf (' \n power= %.1f kW ',W) printf (' \n COP= %.3f ...
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//(13.15) Devise and evaluate an exergetic efficiency for the internal combustion engine of Example 13.4. For the fuel, use the chemical exergy value determined in Example 13.12(a). //solution mFdot = 1.8e-3 //fuel mass flow rate in kg/s ech = 4...
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// Scilab Code Ex12.3 Binding energy of helium nucleus: Pg: 247 (2008) e = 1.6e-019; // Energy equivalent of 1 eV, J/eV amu = 931; // Energy equivalent of 1 amu, MeV m = 2*1.007825+2*1.008665-4.002603; // Mass difference in formation of He, amu E = m*amu; // Energy equivalent of mass difference for He n...
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// Test #10 : Valid input test case #2 exec('./allpasslp2bsc.sci',-1); [n,d]=allpasslp2bsc(0.786,[0.549,0.8746]); disp(d); disp(n); // //Scilab Output //d=1. 0.0888982 - 0.1132783i //n=0.1439960 0.6173655 - 0.7866765i // //Matlab Output //n= 0.1440 + 0.0000i 0.6174 - 0.7867i //d= 1.0000 + ...
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clc,clear printf('Example 1.21\n\n') Pole=4 Z=32 //no of conductors coil_sides=Z segments=16 pole_pitch=Z/Pole slots=16 slots_per_pole=slots/Pole //for Simplex lap winding y_b=pole_pitch+1 //back pitch y_f=pole_pitch-1 //front pitch y_c=1 //Commutator pitch; Note that it is positive and it is pr...
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function imgout=contours(imgsrc) filterx = [-1 -2 -1;0 0 0;1 2 1] imgfx = convolution(imgsrc,filterx,6) filtery = [-1 0 1;-2 0 2;-1 0 1] imgfy = convolution(imgsrc,filtery,6) [wd,he]=size(imgfx); //Create an empty image imgout = zeros(wd,he); //For each lines for i=1:he ...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Rao, R Ramesh, and Shankar Narasimhan. 1996. //“Comparison of Techniques for Data Reconciliation of Multicomponent Processes.” //Industrial & Enginee...
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errcatch(-1,"stop");mode(2); //example 9.4 //page 318 ; funcprot(0); //initialisation of variable L=500; S=0.004;//slope of slope line hf=S*L; disp(hf,"head loss (ft)="); exit();
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//////// Probleme de Poisson Dirichlet par differences finies sur (0,1) clear /////// Parametres M = 100 // nb de subdivisions h = 1.0/M // pas k = 1.0 // raideur vect_M = [10,20,50,100,200] for l=1:length(vect_M) M = vect_M(l) h=1.0/M // sous-divisions de l'espace X = linspace(0,1,M+1) // f : terme source f...
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function v = algoritmo(m, xf) x = 0 k = 0.046 v2 = 0 incx = xf / 10 R = 0 flag = 0 while (x <= xf) if flag == 2 incx = incx * 2 end var = 19.6 - (2000 / m) * R v2 = v2 + incx * var R = k * v2 flag = flag + 1 x = x + incx ...
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//To find linear and angular velocity and acceleration clc //Given: OC=150/1000, PC=600/1000, CD=150/1000 //m N=450 //rpm //Solution: //Refer Fig. 15.6 //Calculating the angular speed of the crank omega=2*%pi*N/60 //rad/s //By measurement, OM=145/1000, CM=78/1000, QN=130/1000, NO=56/1000 //m //Velocity and ...
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clc clear //input v=230;//voltage of a shunt generator in volts ra=0.2;//armature resistance of the shunt generator in ohms rf=115;//feild resistance of the shunt generator in ohms n=0.85;//overall effeciency in per units il=37;//load current in amperes //calculations inp=(v*il)/n;//input in watts inp1=in...
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//LU DECOMPOSITION //FACTORIZING A INTO L AND U (A = LU) clc;clear; function lu_decomposition(A) [r,c]=size(A); u=A; l=eye(r,c); for i=1:(r-1) m=det(u(i,i)); for j=i+1:c n=det(u(j,i)) a=n/m; l(j,i)=a; u(j,:)=u(j,:)-u(i,:)...
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x y f(xs) -5.000000 -5.000000 1.996805 -4.600000 -5.000000 1.996174 -4.200000 -5.000000 1.995199 -3.800000 -5.000000 1.993630 -3.400000 -5.000000 1.990975 -3.000000 -5.000000 1.986207 -2.600000 -5.000000 1.976988 -2.200000 -5.000000 1.957462 -1.800000 -5.000000 1.911428 -1.400000 -5.000000 1.791859 -1.00000...
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//Chapter 16, Problem 8 clc; L=0.20; //inductance R=60; //resistance C=20e-6; //capacitance V=20; //supply voltage fr=(2*%pi)^-1*sqrt((1/(L*C))-(R^2/L^2)); Xl=2*%pi*fr*L; //inductive reactance Rd=L/(R*C); Ir=V/Rd;...
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I=35 VR=25 Vrl=40 VRrl=50 Vc=45 C=50E-6 Xc=Vc/I w=1/(Xc*C) theta=acos((VR^2+VRrl^2-Vrl^2)/(2*VR*VRrl)) x=VRrl*cos(theta)-25 y=VRrl*sin(theta) r=x/I L=y/(I*w) Vappl=sqrt((VR+x)^2+y^2) R=VR/I disp(L,r,R)
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clc //ex11.7 R_i=1*10^3; R_o=100; A_voc=100; //V_ooc=A_voc*V_i and I_i=V_i/R_i gives R_moc=V_ooc/I_i R_moc=A_voc*R_i; disp('The resulting transconductance model is with an:') disp(R_i,'input resitance in ohms') disp(R_o,'output resistance in ohms') disp(R_moc,'and transresistance in ohms')
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clc;clear; printf("\nBalanço de Massa\nMétodos Decomposição LU e Jacobi\n\n") /*ordem = input("Qual a ordem da matriz? ") printf("Preencha os valores da matriz dos coeficientes:\n") for i = 1:ordem printf("Linha %d\n", i) for j = 1:ordem printf("Coluna %d", j) A(i, j) = input("Valor: ") end...
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function [a,b,c]=foo(x,y,z) a=x+y b=x*y c=z endfunction foo(2,3,4) // only the value of a is displayed [a,b]=foo(2,3,4) // a and b are retrieved as outputs [a,b,c]=foo(2,3,4) // a,b,c are retrieved as outputs
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clc clear //Input data T1=263;//Minimum temperature at which ammonia refrigerating machine works in K T2=303;//Maximum temperature at which ammonia refrigerating machine works in K x1=0.6;//Dryness fraction of ammonia during suction stroke sf1=0.5443;//Liquid entropy at 263 K in kJ/kg K hfg1=1297.68;//Latent hea...
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clear $th = VirtualMaterials.Advanced_Peng-Robinson / -> $th th + WATER pipe = PipeSegment.PipeSegment() cd /pipe.In P = 300 kPa T = 300.0 K Fraction = 1.0 MoleFlow = 1000.0 cd /pipe.Out #P = 200.0 #T = 300.0 cd / pipe.Diameter = 0.1 pipe.Length = 20.0 pipe.Roughness = 0.0001 pipe.Elevati...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 7: UNDERGROUND CABLES // EXAMPLE : 7.16 : // Page number 222-223 clear ; clc ; close ; // Clear the work space and conso...
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pathname=get_absolute_file_path('6_16c.sce') filename=pathname+filesep()+'6_16c_data.sci' exec(filename) A=2*Tf/W;B=W/S;C=1/L_Dmax^2;E=sqrt(A^2-C) Vmax=sqrt((A*B+B*E)/(D*Cdo)) printf("\Answer:\n") printf("\n\Maximum Velocity for CJ-1: %f m/s\n\n",Vmax)
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//// compute_bd // find boundary of mesh, returned bd will be in ccw consective order. For // multiple boundary mesh, return a cell, each cell is a closed boundary. // For single boundary mesh, return an array. // //// Syntax // bd = compute_bd(face) // //// Description // face: double array, nf x 3, connectivit...
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clear; clc; disp('Example 8.18'); // aim : To determine // the actual mass of air supplied/kg coal // the velocity of flue gas // given values mc = 635;// mass of coal burn/h, [kg] ea = .25;// excess air required C = .84;// mass composition of carbon H2 = .04;// mass composition of hydrogen O2 = .05;// m...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>desc P=10</description> <executable>AcousticSolver</executable> <parameters>LEE_2DPulseAdv_WeakDG_MODIFIED.xml</parameters> <files> <file description="Session File">LEE_2DPulseAdv_WeakDG_MODIFIED.xml</file> </files> <metrics> ...
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clear //Given D=0.13*10**-2 R=3.4 //ohms l=10.0 //Calculation // A=(%pi/4.0)*D**2 a=R*A/l b=1/a //Result printf("\n Conductivity of a material is %0.1f *10**6 S/m",b*10**-6)
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clear;lines(0); driver("Pos") xinit("foo.ps") plot2d() xend() driver("X11")
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//Initialisation of variables clc h=1 k=1 l=1 dhkl=1.75e-8// a=dhkl*sqrt(h^2+k^2+l^2) printf('inter atomic spacing is %e cms \n',a)
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//4*x^3*y/(6*x*y^3) clear; clc; close; d=int32([4,6]); m=4/gcd(d); n=6/gcd(d); x=poly(0,'x');y=poly(0,'y'); p1=x^3;p2=x;p=p1/p2; q1=y;q2=y^3;q=q1/q2; //val=m/n*p*q disp('val=') mprintf("%i/%i*x^2/y^2",m,n)
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function y = upsamplefill (x, w, cpy) //This function upsamples a vector interleaving given values or copies of the vector elements. //Calling Sequence //y = upsamplefill (x, w) //y = upsamplefill (x, w, cpy) //Parameters //x: scalar, vector or matrix of real or complex numbers //w: scalar or vector of real or comple...
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[profile regional_s3_endpoint] s3_us_east_1_regional_endpoint=regional
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clc; funcprot(0); //Example 10.7 //Initializing the variables d1 = 0.140; d2 = 0.250; DpF_DpR = 0.6; //Difference in head loss when in forward and in reverse direction K = 0.33 ;//From table g = 9.81; //Calculations ratA = (d1/d2)^2; v = sqrt(DpF_DpR*2*g/((1 - ratA)^2 - K)); disp(v,"Velocity (m/s):");
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function W=cijfers(V) // output initialiseren W=[]; // controleren of V enkel cijfers 0:9 bevat for i=1:length(V) if (V(i)<0)|(V(i)>9) disp('input mag enkel cijfers tussen 0 en 9 bevatten') abort // foute input, dus functie afbreken end end // cijfer per cijfer controleren of het voorkom...
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// ==================================================================== // Allan CORNET // INRIA 2008 // Template toolbox_skeleton // This file is released into the public domain // ==================================================================== // // function s = scilab_sum(valA,valB) s = valA + valB; endfuncti...
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function [xnew,ynew,znew] = translate3d(x,y,z,tx,ty,tz) xnew = x + tx ynew = y + ty znew = z + tz endfunction
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//Chapter-9,Example9_17,pg 9_66 Ra=0.08 Eb1=242 V=250 Ia=87 Vt=V//generator supply Nm=1500 Ia1=(V-Eb1)/Ra //at start N=0, Eb=0 Ias=V/Ra//Ia(start) Ia2=120 Eb2=V-Ia2*Ra Eg=Vt+Ia*Ra//generator e.m.f Ng=Nm*Eg/Eb1//speed as generator printf("speed as generator\n") printf("Ng=%.2f r.p.m",Ng)
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0 fbegin 100 internode 101 internode-bone 200 default 202 cottonleaf 203 sunflowerleaf 204 wheatleaf 205 leaflob1 206 leaflob2 207 leaf_5lob 208 leaf_5lob2 209 leaf_aescu2 210 maizeleaf2 211 leafaecu 212 leafpen11 213 leafpen11_2 214 leafplatan 215 le...
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//Ex:3.4 clc; clear; close; b=1/2;// propagtion constant printf("normalised propagtion constant"); printf("\n B=((b/k)^2-n2^2)/(n1^2-n2^2)"); printf("\n thus when b=1/2"); printf("\n B=k*sqrt(n2^2+b*(n1^2-n2^2))"); printf("\n B=k*sqrt((n1^2-n2^2)/2)"); printf("\n which gives its rms value");
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//Chapter 03: Algorithms clc; clear; function []= binarysearch (arr ,n ,i) last =1; h=n; while (last <= h ) mid = int (( last + h ) /2) ; if ( arr ( mid ) == i ) printf ( "\nElement:%d found at position %d",i ,mid) ; break ; else if ( arr ( mid ) >i ) h = mid -1; else last = mid +1; end end end endfunction //Note:in...
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clc //Initialization of variables P1=10 //psia Q=0.6 //cfs A1=0.0491 //ft^2 g=32.2 V=39.2//fps A0=0.0218 //ft^2 d1=2 //in d2=3 //in //calculations Phead=P1*144/62.4 V1=Q/A1 V2i= sqrt(2*g*(Phead + V1^2 /(2*g))) Cv=V/V2i A2=Q/V Cc=A2/A0 Cd=Cc*Cv hL=(1/Cv^2 -1)*(1- (d1/d2)^4)*V^2 /(2*g) //results print...
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clc //Example 10.6 //Calculate the pump head rho=62.3//lbm/ft^3 g=32.2//ft/s^2 v=18.46//ft/s //1 lbf/s^2 = 32.2 lbm.ft h=(v^2/2)*32.2/rho/g//ft printf("The pump head is %f ft",h);