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//Example 6.9// speed clc; clear; close; format('v',6) i1=50;//primary current in amperes i2=i1/(sqrt(2));//secondary current in amperes r1=0.2;//primary resistance in ohms v1=220;//primary voltage in volts eb1=((v1-(i1*r1)));//primary emf in volts eb2=((v1-(i2*r1)));//secondary emf in volts n1=1000//primary speed in ...
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## Tag create test read <sample1.fi set echo tag newtag create :15 write -
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//Chapter 5, Problem 6, Figure 5.13 clc; //Potential difference across R1 is the same as the supply voltage V R1=5; R3=20; I=11; I1=8; //Hence supply voltage is V=R1*I1; I3=V/R3; //Reading on ammeter, printf("Reading on ammeter = %f A\n\n\n",I3); I2=I-I1-I3; R2=V/I2; //Current flowing through R2 printf("...
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clc; // Chapter 2 Switched communication systems //Example 2.5,page no 127 //given N=1000//no of turns L1=5e-8//inductance per turn L=N^2*L1//total inductance mprintf('total inductance is %f H \n',L) R=100//resistance of winding in ohm MMF=5//operating MMF in amp. turn V=1//voltage of received signal in volts...
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//Chapter-5,Example 5_11,Page 5-29 clc() //Given Values: m1=50*10^-9 //mass of particle in kg m2=9.1*10^-31 //mass of electron in kg h=6.625*10^-34 //Planck's constant v1=1 //velocity of particle v2=3*10^6 //velocity of electron //Calculations: lam1=h/(m1*v1)*10^...
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function neighbors = kNN(kdtree,k,point) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku Univeristy //Description: //Outputs the k-nearest neighbors of an input point. Uses a k-d tree structure as input. ///2018/08/01 : Doesn't output the actual nearest neighbors, nut more of an ...
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function [ar, sigma2,rc] = levin(r); // //[ar,sigma2,rc]=lev(r) // //Resolve the Yule-Walker equations: // // // // |r(0) r(1) ... r(N-1)|| a(1) | |sigma2| // // |r(1) r(0) ... r(n-1)|| a(2) | | 0 | // // | : : ... : || : |=| 0 | // // | ...
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//---- perceptron trenowanie //---- okreslenie par wektorow trenujacych //---- dla funktora AND A = ones(4,4); A(1,2) = -1; A(1,3) = -1; A(1,4) = -1; A(2,2) = -1; A(3,3) = -1; //---- wykreslenie obszaru klasyfikacji mtlb_hold on; for i=1:4 if A(i,4)==1 plot(A(i,2),A(i,3),'ko:'); else...
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errcatch(-1,"stop");mode(2);// Example 4.4:core diameter ; ; format('v',4) d=0.02;//difference n1=1.5;//core refrative index m=1000;// number of modes h= 1.3;// Wavelenght in micrometers a=((h/(%pi*n1))*(m/d)^(1/2));//core diamter in micro meter disp(a,"core diameter in micro meter") exit();
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//Working loop mean effective pressure(in bar) wlep=6; //Pumping loop mean effective pressure(in bar) plep=0.4; //Speed of the engine(in rpm) N=400; //Working cycle per minue in no load conditioons(in rpm) Wc=50; //Mean effective pressure(in bar) pfm=0.6; //Diameter of he engine(in m) D=0.18; //Stroke of th...
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//chapter 6 Ex 3 clc; clear; close; a=[]; for i=1:20 a(i)=7*i; end Sum=sum(a); Average=Sum/size(a,"r"); printf("The average of first 20 multiples of 7 is %3.2f",Average);
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clc //initialization of varaibles P=15 //psia T2=70+460 //R T1=55+460 //R //calculations pw=0.2141 pA=P-pw mratio=pA*29/(pw*18) mAbym=mratio/(1+mratio) mwbym=1/(1+mratio) pg=0.3631 //psia phi=pw/pg gamma=1/mratio //results printf("Partial pressure of water vapor = %.2f psia",pA) printf("\n Specific humi...
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clc clear //Page number 497 //Input data L=80;//The latent heat of fusion of ice in cal/gm Li=3.3*10^5;//Specific latent heat of ice fusion in Jkg^-1 dp=1;//The increase in pressure in atmospheres t=0;//The given temperature in degree centigrade v=-0.1;//The change in specific volume in cm^3/gm //Calculat...
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//Wired Digital Communications : example 9-5 : (pg 411) Tb=1/(8*10^3);//bit frequency BWmin=1/(2*Tb);//minimum bandwidth printf("\nTb = %.8f s",Tb); printf("\nBWmin = 1/2.Tb = %.f Hz",BWmin);
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//chapter 18 //example 18.2 //page 762 printf("\n") printf("given") Vo=12;Il=40*10^-3;Vs=20;Vbe=.7; Vz=.75*Vo disp("for minimum D1 current select") Ir2=10*10^-3; R2=(Vo-Vz)/Ir2 Ie1=Il+Ir2 disp("specification for Q") Vce1=20;Vs=Vce1; Ic1=50*10^-3; Pd=(Vs-Vo)*Ie1 hfe=50; Ib1=Ie1/hfe Ic2=5*10^-3; R1=(Vs-...
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//Example 31.4 t_half=5730;//Half-life of Carbon-14 (y) lambda=0.693/t_half;//Decay constant (1/y) t=-log(0.92)/lambda;//Calculated age (y) //Above formula is obtained after mathematical simplification of Equation 31.38 printf('The age of the Shroud of Turin = %0.1f years',t) //The answer varies due to round off ...
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//Problem 43.03: Two coils have self inductances of 250 mH and 400 mH respectively. Determine the magnetic coupling coefficient of the pair of coils if their mutual inductance is 80 mH. //initializing the variables: La = 250E-3; // in Henry Lb = 400E-3; // in Henry M = 80E-3; // in Henry //calculation: //coup...
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function new_image = decorrstretch(image) image_list = mattolist(image) out = opencv_decorrstretch(image_list) sz = size(out) for i=1:sz new_image(:, :, i) = out(i) end endfunction
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clear; clc; v3=20; v2=15; //putting v1=15/(1+k) s=poly([-1 5 3],"x","coeff"); K=roots(s); k=K(2) v1=15/(1+k); //disp(v1) x=v1(1); //disp(x); vnew=x+v3+v2; xl=sqrt(3)*vnew; n=vnew/(3*v3); mprintf("capacitance ratio= %.2f \nthe line to neutral voltage= %.1fkV \n string efficiency=%.1fpercent",k,xl,n*100); ...
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// Scilab Code Ex9.5 Change in voltage across a G.M. tube: Pg:202 (2008) e= 1.6e-019; // Charge on an electron, coulomb W = 25; // Ionization potential of gas (Ar/N2), eV E = 5e+06; // Energy of incident alpha particles, eV C = 1e-010; // Capacity of the system, farad N = E/W; // Number of ions prod...
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mdaqAIScanInit.sci
function mdaqAIScanInit(arg1, arg2, arg3, arg4, arg5, arg6) link_id = -1; if argn(2) == 5 then channels = arg1; aiRange = arg2; aiMode = arg3; scan_freq = arg4; scan_time = arg5; end if argn(2) == 6 then link_id = arg1; channels = arg2; ...
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clear //Given C1=2 //micro F C2=2 //micro F C3=2 C4=2 //Calculation Cs=C1*C2/(C1+C2) Cab=C3*C4/(C3+C4) //Result printf("\n The capacitance of the Capacitors %0.3f micro F", Cab)
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//mason's gain formula applied to SFG in figure 3-16 //y2 as output node syms G1 G2 G3 G4 G5 H1 H2 H3 H4 M1=1 L11=-G1*H1 L21=-G3*H2 L31=G1*G2*G3*-H3 L41=-H4 L12=G1*H1*G3*H2 L22=G1*H1*H4 L32=G3*H2*H4 L42=-G1*G2*G3*H3*H4 L13=-G1*H1*G3*H2*H4 delta=1-(L11+L21+L31+L41)+(L12+L22+L32+L42)+L13 delta1=1-(L21+L41)+...
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9_1.sce
clc //initialisation of variables t=10//C s=74.2//days c=0.01//mm d=245//mm //CALCULATIONS h=s/(d*c)//cm //RESULTS printf('the high will water at a temperature =% f cm',h)
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PL/SQL Developer Test script 3.0 8 -- Created on 2014/8/25 by XINHUAZHOU declare -- Local variables here i integer; begin -- Test statements here sys.dbms_job.run(job => i); end; 0 0
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equil.sci
function [t]=equil(p,q) t=chol(q); [u,s,u]=svd(t*p*t'); s=diag(s); ll=ones(s)./sqrt(sqrt(s)); t=diag(ll)*u'*t
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cleancomplex.sci
function Y=cleancomplex(X) e=1D-14 n=length(X) Y=X; for i=1:n if(abs(X(i))<e) Y(i)=0 else if(abs(real(X(i)))<e) Y(i) = %i*imag(X(i)) else if (abs(imag(X(i)))<e) Y(i) = real(X(i)) end end end end ...
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Ex2_4.sce
//Initilization of variables Tac=3.5 //kN Tbc=3.5 //kN alpha=20 //degree //angle made by Tac with -ve X axis beta=50 //degree //angle made by Tbc with +ve X axis //Calculations theta=atand(((Tac*sind(alpha))+(Tbc*sind(beta)))/((Tac*cosd(alpha))-(Tbc*cosd(beta)))) //degree P=Tac*(cosd(alpha)-cosd(beta))/(cosd(the...
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Example_16_6.sci
clear; clc; printf("\n Example 16.6"); H = 0.036; //Humidity is in kg/kg at 811 K //Taking R as 90 per cent and P as 101.3 kN/m2, then, for assumed values of Tb of 321, 333 and 344 K //Pw = 13,20 and 32 kN/m2, respectively //G = 27.8, 12.9 and 6.02 kg/s, respectively. //for Tb = 32...
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Example_9.sce
//Chapter-10,Example 9,Page 255 clc(); close(); E0_Ag = 0.799 //standard potential for copper Ksp=8.3*10^-17 I=1 Ag= Ksp/I n= 2 R=8.314 //gas constant F=96500 //Farade's constant n=2 T=298 //temperature in Kelvin E_Ag=E0_Ag+(2.303*R*T/(n*F))*log10(Ag) printf('the single ...
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clear; clc; v=220; s=5; z=4.5; Vb=11; sb=50; Zb=(Vb^2)/s; Zpu=z/Zb; mprintf("pu leakage reactance is %f\n",Zpu); a=Vb/v; Zs=z/(a^2); //case2 vb1=220; Zb1=(vb1^2)/s; Zpu1=Zs/Zb1; mprintf("Ratio of pu leakage reactances are %f",Zpu1);
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fix-page.tst
*Testcase fix-page: Test the Fix Page E502 Assist # Created and placed into the public domain 09 OCT 2020 by Bob Polmanter. # Runtest *Compare dependency removed on 2022-03-08 by Fish. # Suppress logging of program checks. Processing of this test script # intentionally generates program checks as it runs as part of t...
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ex5_5.sce
clc; l=0.1; //length in m A=10^-4; //area in m square R=0.01; //resistance in Ohm p=(A*R)/l; //calculating resistivity disp(p,"Resistivity in Ohm metre = "); //displaying result
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#************************************************************ # Scenario of Ikea # # date : Thu Aug 23 16:43:06 2012 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT HUMAN_ACHILE p3d_set_robot_steering_method Linear p3d_set_robot_current 0.00...
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Ex3_1.sce
// Problem 3.1,Page no.54 clc;clear; close; P=40 //mm //Force applied to stretch a tape L=30 //m //Length of steel tape A=6*1 //mm //Cross section area E=200*10**9*10**-6 //KN/m**2 //Modulus of Elasticity //Calculations sigma_L=(P*L*10**3)*(A*E)**-1 //mm //Result printf("The Elongation of steel tape is %.1f mm",s...
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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// exa 3.8 Pg 70 clc;clear;close; // Given Data M=15;// N.m P=5;// kW N=500;// rpm tau_d=40;// Mpa sigma_d=58;// MPa T=P*60*10**3/(2*%pi*N);// N.m Te=sqrt(M**2+T**2);// N.m //Te=(%pi/16)*d**3*tau_d d=(Te/((%pi/16)*tau_d)*1000)**(1/3);// mm printf('\n Using equivalent torque equation,\n shaft diameter d = %.f mm',d) ...
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<?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="application/xhtml+xml;charset=UTF-8" /> <meta name="robots" co...
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// Exampple 8.1 //Write a program to read a series of words from terminal using scanf function. //Read data using scanf function disp("Enter text:") [word1,word2,word3,word4]=scanf("%s %s %s %s"); //Printing the results printf("word1 = %s\nword2 = %s\n",word1,word2); printf("word3 = %s\nword4 ...
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// Example 7_5 clc;funcprot(0); // Given data m=0.035;// kg p_1=0.100;// MPa T_1=20.0;// °C p_2=5.00;// MPa k=1.4;// The specific heat ratio for air R_air=0.286;// kJ/kg.K // Solution T_2=((T_1+273.15)*(p_2/p_1)^((k-1)/k))-273.15;// °C v_1=(m*R_air*(T_1+273.15))/(p_1*10^3);// m^3/kg v_2=v_1*((T_2+273.15)/...
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// chapter 14 // example 14.11 // Determine the firing angle, power factor, active power and reactive power at rated speed and its 10 % and their ratio // page-886-887 clear; clc; // given P=100; // in kW (power rating of motor) N=1000; // in rpm Ea=460; // in V I=300; // in A E=415; // in V (3 phase input voltage) net...
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//clc() MKClO3 = 122.55 mKClO3 = 100;//kg NKClO3 = mKClO3 / MKClO3; NO2 = 3 * NKClO3 / 2; V1 = 22.4143;//m^3/kmol; V = V1 * NO2; disp("m^3",V,"volume of oxygen produced = ")
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clear; clc; exec('/home/debdeep/Desktop/TEST NOW!!/impzlength.sci'); b = [1+3*%i -0.9 2 3 4 4]; a=[1 -0.9 2 3 4 4]; len = impzlength(b,a); disp(len); //output //!--error 246 //Function not defined for given argument type(s), // check arguments or define function %p_bezout for overloading. //at line 31 of functio...
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clc k = 12400 // constant lambda = 6943 // wavelength of radiation in angstrom n = 3e19 // Total number of ions // Sample Problem 5 on page no. 243 printf("\n # PROBLEM 5 # \n") E = k/(lambda) // Energy difference E_total = E*n*1.6e-19 // Total Energy emitted printf("\n Energy of one photon is %feV. \n Total energy ...
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function [c] = PCM_Encoding(x,L,en_code) //Encoding:Converting Quantized decimal sample values into binary //x=input sequence //L=number of qunatization levels //encode=normalized input sequence n=log2(L); c=zeros(length(x),n); fori=1:length(x) forj=n:-1:0 if(fix(en_code(i)/(2^j))==1) c(i,(n-j))=1; en_code(i)=...
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//chapter 3 //example 3.21 //page 167 Ro=100; x=0.00392; T1=25;//temp at 25c R(25)=Ro*(1+(x*T1)); disp(R(25))// resistance at 25 degree T2=100; R(100)=Ro*(1+(x*T2)); disp(R(100))//resistance at 100 degree
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//Section-14,Example-4,Page no.-PC.113 //To calculate the pH in the following cases. clc; K_a=7.3*10^-6 c_1=0.23 //(M) alpha_1=sqrt(K_a/c_1) C_1=c_1*alpha_1 //(M) pH_1=-log10(C_1) disp(pH_1,'pH of the given weak acid') c_2=0.2 //(M) K_b=4.4*10^-5 alpha_2=sqrt(K_b/c_2) C_2=c_2...
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s = %s; to = 10^-4; num = 1; dem = 1 + to*s; sys = syslin('c', num/dem); t = (0:to/100:7*to)'; y = csim('step', t, sys); plot2d(t, y'); tmp = find(y>=0.95); tr5 = t(tmp(1));
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//clc() T = 510;//K P = 26.6;//bar Tc = 425.2;//K Pc = 38;//bar Zc = 0.274; R = 8.314; Pr = P / Pc; Tr = T / Tc; disp(Pr,"Pr = ") disp(Tr,"Tr = ") //From fig. 5.4 and 5.5 from the text book Z = 0.865; D = 0.15; Z1 = Z + D * ( Zc - 0.27); V = R * T * Z1 / (P * 10^5); disp("m^3/mol",V,"Molar volume of n-b...
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clc;funcprot(0);//Example 2.24 //Initilisation of Variables L1=0.01;....//thickness of blocks in m b=0.08;...//length of blocks in m W=0.06;....//width of blocks in m K1=20;....//thermal conductivity of blocks in W/m*degrees celcius h=10000;....//the contact conductance of 2 blocks W/m^2*degrees celcius T1=120;....
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<?xml version="1.0" encoding="UTF-8"?> <html xmlns="http://www.w3.org/1999/xhtml"><head><title>Namespace Crossreference</title> <link rel="stylesheet" type="text/css" href="stylesheet.css"></link> <style> <!-- dt { font-family:Lucida Console,Courier,monospace; font-weight: bold; } dd { font-family:Lucida Console,Cou...
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clear all; clc; disp("a)") disp("Convert: 1) Q=5 m^3/s=10595 cfm") disp("2) rhoa=0.0761lbm/ft^3") disp("3) SP=deltap/(rhow*g)") delta_ps=500 rho_w=1000 g=9.8 SP=delta_p/(rho_w*g) printf("Hence SP = %0.3f m",SP) disp("Thus SP= 2.01 in.wg.") disp("b)") disp("Calculating the specific speed:Ns") N_s=1500...
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// Exa 1.17 clc; clear; close; // Given data V1 = 0.7;// in V V2 = 5;// in V V_o = V1-V2;// in V R = 2.2*10^3;// in ohm I_D = -V_o/R; I_D = I_D * 10^3;// in mA disp(V_o,"The output voltage in volts is : ") disp(I_D,"The current through diode in mA is");
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function [r,k]=mtlb_max(a) // Copyright INRIA if size(a,1)==1|size(a,2)==1 then [r,k]=max(a) else [r,k]=max(a,'r') end
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12_4_3.sce
clc; //page no 421 //problem no 12.4.3 SNR=9;//SNR in dB //conversion of dB to power ratio p=10^(9/10); // for Polar Pbe1=1/2 * erfc(sqrt(7.94/2)); disp(Pbe1); // for Unipolar Pbe2=1/2 * erfc(sqrt(7.94)/2); disp(Pbe2);
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//1.)calculate the stress on the lower washers before the nuts are tightened,refer fig 4.5 //2.)what could be the stress in upper and lower washers... clc //solution //given d=20//mm d1=22//mm d2=50//mm d3=22//mm d4=44//mm P1=120000//N P2=5000//N //1)stress on lower washer before the nuts are tightened pi=...
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load DictionaryDecoder.hdl, output-file DictionaryDecoder.out, compare-to DictionaryDecoder.cmp, output-list in%B1.16.1 outA%B1.16.1 outB%B1.16.1 outC%B1.16.1 outD%B1.16.1; // Loads Dictionary Decoder // Program loads 2 16 bit inputs ROM32K load DictionaryInv.hack, output; set in %B1010000010000010, eval...
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clc; clear; printf("\t\t\tChapter5_example2\n\n\n"); // properties of Freon-12 from appendix table C3 T1_Fr=-50; T2_Fr=-40; rou1_Fr=1.546*1000; rou2_Fr=1.518*1000; beta_Fr=-(rou1_Fr-rou2_Fr)/(rou1_Fr*(T1_Fr-T2_Fr)); printf("\nThe volumetric thermal expansion coefficient calculated for Freon-12 is %.3e /K",beta_Fr); bet...
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x1= [679 1420 1349 296 6975 323 4200 633]; x2 = [30.4 34.1 17.2 26.8 29.1 18.7 32.6 32.5]; y = ones(8,1); y= [11.6 ;16.1; 9.3; 9.1; 8.4; 7.7; 11.3; 8.4]; x = ones(8,3); for i=1:8 x(i,2)= x1(i); x(i,3)= x2(i); end pro1 = x'; //disp(pro1); pro2= pro1*x; //disp(pro2); pro3 = inv(pro2); //disp(pro...
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function [x,y,typ]=SPLIT_f(job,arg1,arg2) x=[];y=[],typ=[]; select job case 'plot' then case 'getinputs' then graphics=arg1(2); orig=graphics(1) x=orig(1) y=orig(2) typ=ones(x) case 'getoutputs' then graphics=arg1(2); orig=graphics(1) x=[1 1]*orig(1) y=[1 1]*orig(2) typ=ones(x) case 'getorigin' then [...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.8\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.8 (page no. 561) // Solution deltaX=4/12; //4 inch = 6/12 feet //deltaX=length //unit:ft A=7*2; //area //area=hight*width //unit:ft^2 k=0.090; //Unit:Btu/(hr*ft*F) //k=proportionality constant ...
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//water// //page 1.87 example 4// clc Hardness=500//Hardness of water(mg/lit) or ppm// H=Hardness/100//Hardness of water(gms/lit)// volume_NaCl=100//Volume of NaCl// conc_NaCl=120//% NaCl consumed by zeolite bed// Wt_per_Litre=conc_NaCl*10//gms NaCl consumed by zeolite bed per litre// total_wt=Wt_per_Litre*volu...
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clc // Given that l = 3e-10 // width of box in m e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of electron in kg c = 3e8 // speed of light in m/sec h = 6.62e-34 // Planck constant in J-sec // Sample Problem 16 on page no. 15.30 printf("\n # PROBLEM 16 # \n") printf("Standard Formula used \n") printf(" ...
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k = 0.0141; //lb.mol/atm.lb cat.h FA0 = 1.08; //lb.mol/h FB0 = 0.54; // lb.mol/h FI = 2.03; // lb.mol/h bita0 = 0.0775; // atm/ft Ac = 0.01414; // ft^2 phi = 0.45; rhoc = 120; // lb cat/ft^3 P0 = 10; // atm X = 0.6;
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// Initilization of variables v_o=500 // m/s // velocity of the projectile alpha=30 // angle at which the projectile is fired t=30 // seconds g=9.81 // m/s^2 // acc due to gravity // Calculations v_x=v_o*cosd(alpha) // m/s // Initial velocity in the horizontal direction v_y=v_o*sind(alpha) // m/s // Initial velo...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-5, Illustration 4, Page 114 //Title: Calculation of dew point //===================================================================...
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//Exa 8.6 clc; clear; close; //given data CN=0.4;//in uF V=33;//in KV VP=V/sqrt(3);//in KV f=25;//in Hz //Capacitance between 2 cores for 15 Km length CN_1=15*CN;//in uF //Capacitance of each core to neutral CN=2*CN_1;//in uF //Charging current per phase I=2*%pi*f*VP*1000*CN*10^-6;//in Ampere disp(round(...
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//8.2 clc; I=125/10; ZL=50/I; printf("Load impedance=%.1f ohm",ZL) Z_total=150/I; printf("\nImpedance of the combination=%.2f ohm",Z_total) I1=125; I2=50; I3=150; P=(1/(2*10))*(I3^2-I1^2-I2^2); printf("\nPower absorbed by load=%.2f W",P) Pr=I^2*10; printf("\nPower consumed by the resistor=%.2f W",Pr) pf=P...
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// Ex 8 Page 348 clc;clear;close; // Given Z1=(6.25+%i*1.25);//ohm Z2=(5+%i*0);//ohm //Z3=(5-%i*XC);//ohm V=100;//V f=50;//Hz //Z23=(250+5*Xc**2)/(100+Xc**2)-%i*(25*Xc)/(100+Xc**2) //for in phase condition imag part must be zero //5*Xc**2-100*Xc+5*100=0 A=[5 -100 500];//polynomal XC=roots(A); XC=XC(1);//ohm C=1/(2*%...
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//Check for the following system. //Example 2.7 <i> clc; clear ;//a>check whether static or dynamic t=-10:.1:10;T=length(t) s=2; for i=1:length(t) x(i)=i; y(i)=abs(x(i)); end if y(2)==x(2)& y(2)==x(1) then disp('The given signal is dynamic' ); else disp('the given signal is static'); end ...
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function _cmd = jplot2d(varargin) _arg = " -2D -l SOUTH "; i=1; while (i<=length(varargin)) //disp(i); i_arg=0; q=%f; while ((length(varargin)>= i_arg+i+1) & (size(varargin(i+i_arg+1))==1)) i_arg = i_arg+1; _arg = _arg + " " +varargin(i+i_arg); end _tmp(i) = ".xyz."+string(grand(1,1,"uin",0,10000))+".tmp"; ...
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clc; clear all; disp("1-D heat flow") disp("Fourier''s equation: q = -k*dt/dx") disp("k=k0*(1+at+bt^2)") disp("q = k0*(1+at+bt^2)*dt/dx") disp("q.dx = k0*(1+at+bt^2)*dt") disp("integrating above equation within limits t1 to t2") disp("the required expression is, q = -k*(t2-t1)*(1+a*(t1+t2)/2+b*(t1^2+t2^2+t1*t2)...
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pathname=get_absolute_file_path('2_3.sce') filename=pathname+filesep()+'2_3_data.sci' exec(filename) //For N2 p1=(m1*RN2*T)/V //For O2 p2=(m2*RO2*T)/V //For CO2 p3=(m3*RCO2*T)/V //Total pressure of the mixture p=p1+p2+p3 //Gas constant of the mixture R=(m1*RN2+m2*RO2+m3*RCO2)/(m1+m2+m3) printf("\n\nRESULTS...
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function [Q,R]=gsc(A) [tamLinha,tamColuna]=size(A) Q=A R=zeros(tamColuna,tamColuna) for j=1:tamColuna Q(:,j)=A(:,j) for i=1:j-1 R(i,j)=Q(:,i)'*A(:,j) Q(:,j)=Q(:,j)-R(i,j)*Q(:,i) end R(j,j)=norm(Q(:,j)) Q(:,j)=Q(:,j)/R(j,j) end disp ...
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errcatch(-1,"stop");mode(2);// sum 3-16 ; ; D=22; d=20; r=1; K=2.2; sigmax=130; sigmax=sigmax/K; Z=%pi*d^3/32; M=sigmax*Z*10^-3; // printing data in scilab o/p window printf("M is %0.3f Nm ",M); exit();
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// Exa 3.10 format('v',7);clc;clear;close; // Given data Rm = 50;//resistance of meter in ohm Im = 2;//current in mA Im = Im * 10^-3;// in A V4 = 10;//voltage in V R4 = (V4/Im) - Rm;// in ohm R4= R4*10^-3;// in k ohm disp(R4,"The value of R4 in kΩ is"); R4= R4*10^3;// in ohm V3 = 50;// in V // (R3+R4) = (V3...
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འཁྱོང་། V;FUT གཡབ། V;PST གྱར། V;PST དྲ། V;FUT གླ། V;IMP གློད། V;FUT ལན། V;PST མཚོན། V;PRS འགྱེལ། V;PST འབྱོར། V;PST བཙུམ། V;FUT ཡུར། V;IMP ལང་། V;IMP ལབ། V;PST བརྫུ། V;PRS བཤོར། V;PST གཏུག། V;IMP བསག། V;PRS ཀེར། V;PRS ལྷུང་། V;PST བཙོག། V;PST བསྟང་། V;PRS འཐེན། V;FUT བཤེད། V;PRS བླང་། V;PRS བཅག། V;PRS བསྐུམ། V;PRS སྤྱད...
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// Exa 17.5 // To calculate uplink cell load factor, number of voice users and poll capacity of the cell. clc; clear all; Ri=12.2*10^3;//Information rate in bps Rc=3.84*10^6;//Chip rate in cps(chips per second) Eb_Nt=4; //in dB Imargin=2; //Interference margin(3 dB) B=0.5;//Interference factor due to othe...
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clc; //e.g 22.14; gm=4*10**-3; RD=1.5*10**3; RG=10*10**6; rs=500; rl=RD; AV=-(gm*rl)/(1+gm*rs); disp(AV); RL=100*10^3; rL=(RD*RL)/(RD+RL); AV=-(gm*rL)/(1+gm*rs); disp(AV);
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//exapple 1.1 clc; funcprot(0); // Initialization of Variable //part1 mu=6.3/100;//viscosity rho=1170;//density d=.3;//diameter of pipe b=0.142;//conversion factor pi=3.14; //calculation Q=150000*b/24/3600//flow rate u=Q/pi/d^2*4//flow speed Re=rho*u*d/mu if Re>4000 then disp(Re,"the system...
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//To find speed of gears B and C clc //Given: TA=72, TC=32 NEF=18 //Speed of arm EF, rpm //Solution: //Refer Table 13.5 //Speed of gear C: y=18 //rpm x=y*(TA/TC) NC=x+y //Speed of gear C, rpm //Speed of gear B: //Calculating the number of teeth on gear B TB=(TA-TC)/2 //Calculating the speed of gear B NB=...
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// Functions for getting feature vectors of training characters in ./training folder exec preprocessing.sci exec feature_extract.sci exec rm_ws.sci // Dictionary dic = ['a' 'b' 'c' 'd' 'e' 'f' 'g' 'h' 'k' 'm' 'n' 'o' 'p' 'q' 'r' 's' 't' 'u' 'v' 'w' 'x' 'y' 'z']; dic_size = size(dic) path = "./training/" //// // Wri...
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//Ex 2.1 page 67 clc; clear; close; V1=1;//V across SCR IG=0;//A Ih=2;//mA holding current R=50;//ohm // Applying kirchoff law //VA-(IAK*R)-V1=0 VA=(Ih*10**-3*R)+V1;//V (let IAK=Ih) printf('VA = %.2f V',VA)
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clc //initialisation of variables dv=360//ft/sec v1=1564//ft/sec H1=1188//B th u g=32.2//ft/sec^2 J=778 cf=0.005 p=0.12//ft A=8.75*10^-4//ft^2 p1=67//lb/in^2 dx=0.0234//ft A1=8.5*10^-4//ft^2 W=0.203//lb/sec g=32.2//ft/sec^2 q2=0.989 Vs2=8.902//ft^3/lb A2=9*10^-4//ft^2 //CALCULATIONS v2=v1+dv H2=H1...
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//reflection coefficent //given clc S=2//voltage standing wave ratio(VSWR) Zo=50//ohm row=((S-1)/(S+1)) row=round(row*1000)/1000///rounding off decimals disp(row,'the value of reflection coefficent as modulus row')
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//clear// p = [ 1.44 .95 .74]'; dt = 2.5 t = [0 2.5 5]'; dp(1) =( 3*p(1)+4*p(2)-p(3))/(2*dt); for i=2:n1 dp p(i+3
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clear clc disp('Exa-2.6(a)'); L=65; c=3*10^8;u=0.8*c; t=L/u ; //The value of time taken as measured by the observer printf('The time for rocket to pass a point as measured by O is %.2e.\n',t); //The value of time taken as measured by the observer disp('Exa-2.6(b)'); Do=65; ...
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clear; clc; printf("\t\t\tExample Number 7.1\n\n\n"); // constant heat flux from vertical plate // Example 7.1 (page no.-330-331) // solution q_w = 800;// [W/square meter] radiant energy flux H = 3.5;// [m] height of metal plate surface W = 2;// [m] width of metal plate Ta = 30;// [degree celsius] surroun...
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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(unwatch all) ; templerr.clp test (clear) (open "Results//templerr.rsl" templerr "w") (load "compline.clp") (dribble-on "Actual//templerr.out") (load "templerr.clp") (list-deftemplates) (dribble-off) (printout templerr "templerr.clp differences are as follows:" crlf) (compare-files "Expected//templerr.out" "Actual//tem...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 10.3 //Caption : Program to Find Pressure,Temperature and Composition for a system //Equations to be Used // ln v1=A*(x2^2) ln v2=A*(x1^2) Where A=2.771-0....
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//EXAMPLE 5-41 PG NO-332-333 VTH=10; V=10; R1=10; R2=10; R3=16.67; R4=50; R5=5.56; R6=3.33; RTH=V+R5+(((R1+R3)*(R4+R6))/(R1+R3+R4+R6)); I=(V/RTH)-0.4; disp('i) Resistance (RTH) is = '+string (RTH) +' ohm '); disp('i) Currrent (I) is = '+string (I) +' A ');
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// Example 8.47 // Calculation of incident optical power. // Page no 499 clc; clear; close; //Given data h=6.62*10^-34; // Planck constant c=3*10^8; // velocity of light lambda=1.55*10^-6; // Wavelength B=400*10^6; //...
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// Chapter9 // Page.No-412, Figure.No-9.24(a) // Example_9_8 // Freq of free running ramp generator // Given clear;clc; R=10*10^3; // Resistance in ohm Vcc=5 // Supply voltage in volt Vbe=0.7 // Base to emitter voltage in volt C=0.05*10^-6; // Capacitance in farad Ic=(Vcc-Vbe)/R; // Collector current in amper...
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// Example 1.12 page no-34 clear clc l=2 //cm D=24 //cm s=0.5 //cm Vd=30 //Volts Va=1000 //Volts //(a) d=Vd*l*D/(2*s*Va) printf("\n(a)\nDeflection Produce, d=%.2f cm\n",d) //(b) theta=(atan(d/D))*(180/%pi) printf("\n(b)\nTheta=%.2f°",theta) //(c) e=1.6*10^-19//C m=9.1*10^-31//kg v=sqrt(2*e*Va/m) ...