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// Exa 6.7 clc; clear; close; format('v',9) // Given data Im = 20;// in mA Im = Im * 10^-3;// in A Vm = 50;// in mV Vm = Vm * 10^-3;// in V V = 500;// in V Rm = Vm/Im;// in ohm Rs = (V/Im)-Rm;// in ohm disp(Rs,"The series resistance in ohm is");
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clear clc E_RHE=(0.5335-(-2.363));//reduction reaction at RHE in V RT_F=0.05915;// E_LHE=((RT_F/2)*log10(0.1*0.2^2));//reduction reaction at LHE in V Ecell=E_RHE-E_LHE;//cell reaction in V printf('Ecell=%.4f V',Ecell) E_RHE=(0.0-0.0713);//reduction reaction at RHE in V RT_F=0.05915;// E_LHE=((RT_F)*log10((0.5^...
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clc; p=3;//bar v=0.18;//m^2/kg p2=0.6;//bar c=p*v^2; v2=(c/p2)^0.5; W=-c*(10^5)*[(1/v)-(1/v2)]; disp("Work done by the fluid is:"); disp("N m/kg",-W); //Answers vary more than than +/-5 : //Answers in the textbook is wrong
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clc //initialisation of variables h= 10 //ft l= 50 //ft d= 1 //in lm= 5 //in f= 0.01 sm= 13.6 g=32.2 //CALCULATIONS ps= sm*lm/12 v= sqrt((ps+h)*2*g*(d/12)/(4*f*l)) Q= v*%pi*(d/12)^2/4 //RESULTS printf ('Discharge through the pipe= %.3f cuses',Q)
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function [simulator_filepath, input_filepath,output_filepath]=simulator_properties() simulator_filepath='/Users/mcfly/Desktop/INP-SCILAB/' input_filepath='/Users/mcfly/Desktop/INP-SCILAB/input/' output_filepath='/Users/mcfly/Desktop/INP-SCILAB/output/' endfunction
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//for a matrix - increasing the neighbourhood mat = [0 0 0 0 0 0;0 0 0 1 0 0;0 0 7 0 0 0 ;0 0 0 0 0 0]; loc=localMaximaFinder(mat,[3 3],4,1); loc
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// Example 4.17.1 clc; clear; L=10; //length of optical link n1=1.49 //refractive index c=3d8; //speed of light delta=1/100; //relative refractive index delTS=L*n1*delta/c; //computing delay difference delTS=delTS*10^12; sigmaS=L*n1*delta/(2*sqrt(3)*c); //computing rms pulse br...
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t=linspace (0,10,1000); p=poly(0,'p'); a=95/13 S=%pi*(2.5^2) Ts=100 //tps de simulation en min Qs=40 G=1 Tau=S/(a*G); G=syslin('c',10/(1+Tau*p)) h=csim('step',t,G); plot2d(t,h);
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 12.6 //writing the equation giving angular displacement as a function of time //given data theta0=%pi/10//amplitude(in rad) of motion theta=%pi/10//displacement(in rad) at t=0 s T=.05//time period(in s) //calculat...
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clc(); clear; // To calculatevthe amount of water evaporated per hour per square feet from the water surface u = 10; // Flow of air stream in fps r = 33.3; // Relative humidity T = 519; // Temperature in Rankine p = 0.1130; // Partial pressu...
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//Faults and Protection// //Example 16.3// P=100;//input power in KVA// Xt=0.04;//limiting ac reactance value// Fov=2;//current ovarload factor// Pc=Xt*P*Fov;//choke power of the converter in KVA// printf('choke power of the converter=Pc=%fKVA',Pc);
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 7: UNDERGROUND CABLES // EXAMPLE : 7.11 : // Page number 216-217 clear ; clc ; close ; // Clear the work space and conso...
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clc //given that r = 0.53 // radius of hydrogen atom in angstrom m_e = 9.1e-31 // mass of electron in kg h = 6.63e-34 // Plank constant printf("Example 2.10") h_bar = h / (2*%pi) // constant del_x = 2*r // calculation of uncertainty in position del_p = h_bar/(2*del_x*1e-10) // calculation of uncertainty in ...
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x(1)=1 // c(1)fn +1 x(2)=-0 // c(2)fn +0 x(3)=-1 // c(3)fn -1 b(1)=1 b(2)=0 b(3)=1/3 for i=1:3 M(1,i)=1 M(2,i)=x(i) M(3,i)=x(i)^2 end c=inv(M)*b S=c(1)^2+c(2)^2+c(3)^2 //solução //disp(S) disp('Coeficientes:') disp(c) //resp.: C = coeficientes /* Resposta está em C, são os coeficientes Ex (1):...
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//function [] = sunPosition() clc clear exec('NumberDays.sce'); exec('ConvertTime.sce'); exec('getDepthDiffuse.sce'); //latitudeSign is +1 if N of equator, -1 if S of equator latitudeSign = 1; degreesLat = 29; minutesLat = 39; secondsLat = 7.19; longitudeSign = 1; degreesLong = 82; minutesLong = 19; secondsLong = 29....
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//=========================================================================== //chapter 10 example 15 clc;clear all; //variable declaration P = 200; //resistance in arm in Ω Q = 200; //resistance in arm in Ω S = 200; //resistance in arm in Ω R = 200; //resistance in arm in Ω p = 0.5; //power in W ...
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//Example 9.7 (b) //Program To Determine Record Length of Bartlett, //Welch(50% Overlap) and Blackmann-Tukey Methods clear; clc; close; //Data Q=10;//Quality Factor N=1000;//Samples //RECORD LENGTH CALCULATION lb=N/Q; lw=16*N/(9*Q); lbt=3*N/(2*Q); //Display the result in command window disp(lb,"Record Le...
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//Parameters of the Plane m=4; //mass of the plane Kg J=0.05; //Inertia Kgm2 r=0.3; //distance at which the plane operates m g= 9.81; //Gravity m/s2 c=0.07; //Damping constant Ns/m
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clc T=300 //K Nn=2.8*10^19 //cm^-3 Np=1.04*10^19 //cm^-3 //a=Ef-Ev an=0.25 //eV ap=0.87 //eV k=8.617*10^-5 //eV/K n0=Nn*exp(-an/(k*T)) disp(n0,"n0 in cm^-3 is=") p0=Np*exp(-ap/(k*T)) disp(p0,"p0 in cm^-3 is=")
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clear clc Pi=1 Pma=1.75 Pmb=.4 Pmc=1.25 d0=asin(Pi/Pma) dm=%pi - asin(Pi/Pmc) dcc=acosd(((Pi*(dm-d0))- (Pmb*cos(d0))+ (Pmc*cos(dm)))/(Pmc-Pmb)) mprintf("Critical Clearing angle = %.1f deg", dcc)
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 9 //Chemical Reaction Equilibria //Example 13 clear; clc; //Given: //Reaction: N2 + 3H2 --> 2NH3 K = 2*10^-4; //equilibrium constant of reaction //To determine the percent conversion: //Basis: //1 mole nitrogen and 3 moles of hydrogen ...
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clc; s1=5.615;//kJ/kg K t1=311;//C t2=300;//C t3=350;//C s2=7.124+(t1-t2)/(t3-t2)*(7.301-7.124); T=t1+273;//K Q=T*(s2-s1); disp("heat supplied is:"); disp("kJ/kg",Q) u1=2545;//kJ/kg u2=2794+(t1-t2)/(t3-t2)*(2875-2794); W=(u2-u1)-Q disp("work done by the steam is:"); disp("kJ/kg",-W)
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function ok=check_mac(txt) //ok=%t,return //errcatch doesnt work poperly ok=%t errcatch(-1,'continue') comp(mac) errcatch(-1) if iserror(-1)==1 then errclear(-1) message('Incorrect syntax: see message in Scilab window') ok=%f end
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// Coding gain plot for n-1 redundant receivers // // (c)2011 L. Rayzman // Created : 10/18/2011 // Last Modified: 10/18/2011 // // TODO: // clear; getd("inc"); // Include Q-function definition //////////////////////////////////////SPECIFY////////////////////...
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[[i= partials/header ]] [[i= partials/navbar ]] <div class="container" style="width: 100%;flex-flow:row;"> [[i= static/sidebar ]] <div class="container center" style="width:78%;"> <h1>Contact Info</h1> <p>You can contact us at the details below:</p> <ul> <li>Mobile ...
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clear //Given R0=5 //ohm R100=5.23 //ohm Rt=5.795 //ohm //Calculation t=((Rt-R0)/(R100-R0))*100 //Result printf("\n The temperature of the bath is %0.2f degree C",t)
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clear all; clc; disp("Ex 2_12") disp(" Vector r = (-3i + 2j +6k) m") r=sqrt((-3)^2+2^2+6^2) printf('\n\nthe magnitude of r is: r = %.0f m',r) disp(" ") disp("u = (-3/7)i + (2/7)j + (6/7)k") a1=acos((-3)/7) a=a1*180/%pi printf('\n\nalpha = %.0f degrees',a) b1=acos(2/7) b=b1*180/%pi printf('\n\nbeta = %.1f degrees',b) c1...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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## Test of strip command set echo read <simple.fi strip blobs write -
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PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_educacion(peducacion => :peducacion, p_recordset => :p_recordset); end; 2 peducacion 1 Tercer ciclo completo 5 p_recordset 1 <Cursor> 116 0
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clear all; clc; disp("Scilab Code Ex 8.2 : ") //Given: P = 15000; //N a = 40; //mm b = 100; //mm //Stress Components: //Normal Force: A = a*b; sigma = P/A; //Bending Moment: I = (a*b^3)/12; //I = (1/12)*bh^3 M = P*(b/2);(b/2); c = b/2; sigma_max =(M*c)/I; //Superposition: x = ((sigma_max-sig...
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//clear// clc clear //exec("9.8data.sci"); t = 0:.01:.5; function w=f(t,Y) w =zeros(2,1); d(X)/d(z}=-ra/U/Ca0 Ka=0.05; Kb=.15; Pao=12; eps=1; A=7.6; R=0.082; T=400+273; Kc=.1; rho=80; kprime=0.0014; D=1.5; Uo=2.5 U:Uo*(l+eps*X) Pa=PBo*(l-X)/(ltepstX) Pb=Pao*X/(l+eps*X) vo=Uo*3.1416*D*D/4 ...
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//page 70 clc;funcprot(0);//EXAMPLE 3.11 // Initialisation of Variables E=12;......//No. of Edges in the octahedral sites of the unit cell S=1/4;.......//so only 1/4 of each site belongs uniquelyto each unit cell N=E*S+1;.....//No.of site belongs uniquely to each unit cell disp(N,"No.of octahedral site belongs un...
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// Exa 2.23 clc; clear; close; // Given data e = 1.6*10^-19;// in C R_H = 0.0145;// in m^3/coulomb Miu_e = 0.36;// m^2/v-s E = 100;// V/m n = 1/(e*R_H);// in /m^3 J= n*e*Miu_e*E;// in A/m^2 disp(J,"The current density in A/m^2 is");
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// // plot_linear2dmap.sci // // Plots n iterations of the linear map with matrix A. // function x = plot_linear2dmap(x0,A,n) x = x0; for i = 1:n, plot(x(1),x(2),'diamondred') x = A*x; end endfunction
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// chapter 3 // example 3.5 // Design free-running UJT relaxation oscillator // page-105-106 clear; clc; // given fmin=5; // in Hz (minimum frequency) fmax=50; // in Hz (maximum frequency) E_dc=12; // in V (DC supply) I_P=80; // in mA (peak current) T=8; // in us (trigger time) V_drop=1; // in V (voltage drop across PU...
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//EXAMPLE 27.2 //8-POLE GENERATOR clc; funcprot(0); //Variable Initialisation P=8;......//Total number of poles Z=722;.....//Total number of conductors V=500;.......//Termiinal voltage in Volts Ia=200;........//Armature current in Amperes Z=1280;......//Total number of conductors as=160;........//Total nu...
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//A program to read formatted data from files. fd=mopen("sine.dat","r"); s=mfscanf (fd, "%s %s"); // Reads two words. The %s reads up to the first white space. [n, x1, y1] =mfscanf (4, fd, "%d,%f"); // Reads the next four data set. mclose(fd) disp (y1, x1, n, s); //Reading embedded data fd=mopen("test.dat"...
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//Graphical// //Example 4.4.4 //Frequency Response of First Order Difference Equation //a = 0.9 and b = 1-a //Impulse Response h(n) = b.(a^n).u(n) clear; clc; close; a = input('Enter the constant value of Ist order Difference Equation'); b= 1-a; //Calculation of Impulse Response n =0:50; h =b*(a.^n) ; //...
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//=========================================================================== //chapter 8 example 11 clc;clear all; //variable declaration V = 230; //voltage in volts I = 4; //current in A I1 = 5; //current in A cosphi = 1; //power factor h = 6; //ho...
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//Exa 8.5 clc; clear; close; //Given data disp("Put alfa=sqrt(6) to find the gain"); alfa=sqrt(6);//unitless Beta=1/(1-5*alfa^2); //Barkhausen critera : A*|Beta|>=1 Beta=-Beta;// A=1/Beta;//unitless disp(A,"Minimum Gain of Amplifier must be : ");
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function traceRoad() clf; isoview(-3,-3,3,3) plot2d(0,0,rect=[-3,-3,3,3]); n=0; x=0; y=0; bt=0; for n=1:2 [bt,x(n),y(n)]=xclick() plot(x(n),y(n),"ro"); if n>1 //plot([x(n-1),x(n)],[y(n-1),y(n)],3,'LineWidth', 2) end end plot(x,y) ...
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//Strength Of Material By G.H.Ryder //Chapter 1 //Example 4 // To Calulate Stress & Extension g=9.8; //Acceleration due to Gravity, Unit in m/sec^2 m=100; //Falling Mass , Unit in Kg W=m*g; //Falling weight , Unit in N D1=1; // diameter of first part of bar, Unit in cm l1=1.5; //Lenght fo first part of ba...
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clc // Given that n = 4 // order of bright fringe x_n = 10 // Separation of 4th bright fringe from center in mm D = 1// Separation between source and screen in meter d = 0.2 // Separation between coherent sources in mm // Sample Problem 10 on page no. 97 printf("\n # PROBLEM 10 # \n") printf("\n Standard f...
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function [x,iter] = jacobiL(A,b,x0,e,it) [l,c] = size(A); erro = 1; x = x0, iter = 0; while erro > e & iter < it xa = x; iter = iter + 1; for i = 1:l soma= 0; for j = 1:l if j ~= i then soma = soma + A(i,j)*x...
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//Given that R = 200 //in ohm C = 15*10^-6 //in F L = 230*10^-3 //in H Em = 36.0 //in volts fd = 60.0 //in Hz //Sample Problem 33-7a printf("**Sample Problem 33-7a**\n") w = 2*%pi*fd Xl = w*L Xc = 1/(w*C) Z = sqrt(R^2 + (Xl - Xc)^2) Imax = Em/Z printf("The amplitude of current in the circuit is %1.2...
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printf("\t example 12.2 \n"); printf("\t approximate values are mentioned in the book \n"); T1=244; // inlet hot fluid,F T2=244; // outlet hot fluid,F t1=85; // inlet cold fluid,F t2=120; // outlet cold fluid,F W=60000; // lb/hr w=488000; // lb/hr printf("\t 1.for heat balance \n"); printf("\t for propanol \n"...
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//Exa 1.23 clc; clear; close; format('v',8); //Given Data : Rdegree=8314.3;//Universal Gas Constant r=12;//meter Patm=75;//cm of Hg Patm=Patm/76*1.01325*10^5;//N/m^2 V=4/3*%pi*r^3;//m^3 M_air=28.97; M_H2=2 Tair=18+273;//K g=9.81;//gravity constant Rair=Rdegree/M_air;//Nm/KgK RH2=Rdegree/M_H2;//Nm/KgK ...
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//pagenumber 113 example 18 clear resacu=0.1*10^-12;//ampere u=20+273;//kelvin voltaf=0.55;//volt w=1.38*10^-23; q=1.6*10^-19; for z=1:2 if z==2 then u=100+273; disp("current at 100celsius rise"); end voltag=w*u/q; i1=(10^-13)*(exp((voltaf/voltag))-1); if z==2 then ...
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(set-strategy depth) (unwatch all) ; tceplace.bat test (clear) (open "Results//tceplace.rsl" tceplace "w") (load "compline.clp") (dribble-on "Actual//tceplace.out") (batch "tceplace.bat") (dribble-off) (printout tceplace "tceplace.bat differences are as follows:" crlf) (compare-files "Expected//tceplace.out" "Actual//t...
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// Example 3.1 // Computation for mobility of the free electrons in aluminium// // Page no.61 clc; clear; close; //Given data ; d=2.70*10^3//2.70*10^3 kg/m3 v=3;//3 electrons/atom A=26.98; M=1.660*10^-27;//1.660*10^-27 kg/atom e=1.60*10^-19; R=3.44*10^-8;//R=resistivity //...................................(B).........
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clc clear //Initialization of variables Rj=1.985 N=1 T1=540+460 //R T2=3540+460 //R //calculations Q=N*(14.215*(T2-T1)-6.53*10^3 *log(T2/T1) -1.41*10^6 *(1/T2-1/T1)) Tm=(T1+T2)/2 Cv=14.215-6.53*10^3 /Tm +1.41*10^6 /Tm^2 Q2=N*Cv*(T2-T1) //results printf("Heat added in case 1 = %.1f Btu",Q) printf("\n Heat ...
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//Effect of variable specific heat on efficiency clc,clear //Given: r=7 //Compression ratio g=1.4 //Specific heat ratio(gamma) cv=0.718 //(Assume)Specific heat at constant volume in kJ/kgK dcv=1*cv/100 //Change in specific heat in kJ/kgK //Solution: R=cv*(g-1) //Specific gas constant in kJ/kgK eta=round(100*(1...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.3\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.3 (page no. 323) // Solution //Ten pounds of air,1 lb of carbon dioxide,and 5 lb of nitrogen are mixed at constant temperature until the mixture pressure is constant nair=10/29; //no of m...
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//clear// clear; clc; //Example 9.6 //Given Dt = 2; //[m] Da = 0.667; //[m] n = 180/60; //[rps] T = 20; //[C] qg = 100; //[m^3/h] rho = 1000; //[kg/m^3] mu = 10^-3; //[kg/m-s] ut = 0.2; //[m/s] //(a) //The power input is calculated and followed by correction of gas effect Nre = n*Da^2*rho/mu; //For a...
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//Example 2_14 clc; clear;close; //Given data: Vs=230;//V f=50;//Hz alfa=30*%pi/180;//radian I=4;//A //Solution : disp("part (a)"); Vm=Vs*sqrt(2);//V Vdc=2*Vm/%pi*cos(alfa)//V RL=Vdc/I;//ohm IL=I*2*sqrt(2)/%pi;//A Pin_active=Vs*IL*cos(alfa);//W Pin_reactive=Vs*IL*sin(alfa);//vars Pin_appearent=Vs*I...
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function [y]=f(t) y = 4*sin(t) - 3*t endfunction function [y]=fp(t) y = 4*cos(t) - 3 endfunction function [raiz, x, iter, ea]=newtonraphson(x0,f,fp,tol,imax) iter = 0; // inicializa numero de iteracoes xr = x0; // inicializa raiz aproximada com a inicial x(iter+1)=x0; // insere raiz inicial no vet...
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clear; printf('************** mta_1.sci Start! ****************'); printf('\n'); printf('Enter a File Name of UNIT SPACE Material'); UnitSpaceFile = input('File Name(.xls)?: ',"string"); //scanf('%s',UnitSpaceFile); printf('./' +UnitSpaceFile+'.xls\n'); //f=findfiles(SCI,UnitSpaceFile+'.xls'); //MT_Mat_Sheets =...
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//Example 4.28//number ,spacing,mounting height and total wattafe clc; clear; close; format('v',6) h=5;// in meters el=120;//in lux ef=40;//efficiency in lumens/watt tw=80;//in watts df=1.4;//depreciation factor uf=0.5;//utiliazation factor l=30;// in meters b=15;// in meters a=l*b;//arean in m^2 glr=(a*el*df)/(uf);//g...
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Teste 1.sce
function [ fieldE, rvector ,rnorm ] = Efield(q0,P0,P); Efield calcula o campo elétrico estático no ponto P, devido a uma carga q0 localizada no ponto P0 Uso: [ fieldE, rvector ,rnorm ] = Efield(q0,P0,P); eps0 = 8.854187817e-12; rvector = P-P0; rnorm = norm(rvector); fieldE = 1/(4*pi*eps0)*q0*(P-P0)./(norm(P-P0).^3); ...
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Example_14_10.sce
clear; clc; //Example 14.10 //Caption : Program to illustrate the Concepts of Pue Gas Adsorption subplot(2,1,1) m=4.7087; b=2.1941; t=0.3984; P=linspace(0,40,10); N=(m.*P)./((b+(P.^t)).^(1/t)); plot(P,N) m=0.6206; b=1.5454; t=1; n=(m.*P)./((b+(P.^t)).^(1/t)); plot(P,n,'b--') legend('Toth Equation','...
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Ex1_9.sce
clear // lal=7.5 lcu=6 rcu=0.017*(10**-6) ral=0.028*(10**-6) d=(10**-6) a=((3.14*d))/(4) Ral=(lal*ral)/(a) printf("\n R= %0.1f ohm",Ral) ial=3 pv=Ral*ial Rcu=pv/(2) printf("\n Rcu") a=(rcu*lcu)/(Rcu) dcu=(((a*4)/3.14)**0.5) printf("\n dcu= %e nm",dcu)
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//Example 9.3:change in refractive index ,net phase shiftand Vpi clc; clear; close; format('v',6) v=5;//kV l=1;//cm ez=(v*10^3)/(l*10^-2);//in V/m no=1.51;// r63=10.5*10^-12;//m/V dn=((1/2)*no^3*r63*ez);// h=550;//nm dfi=((2*%pi*dn*l*10^-2)/(h*10^-9));// fi=2*dfi;// vpi=((h*10^-9)/(2*no^3*r63))*10^-3;//kV disp(dfi,"cha...
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Ex1_43.sce
// Ex 43 Page 387 clc;clear;close; // Given R2=0.03;//ohm X2=0.18;//ohm Ns=100;//rpm s1=3;//% Nfl=(100-s1);//rpm (full load speed) N2=Nfl/2;//rpm s2=(Ns-N2)/Ns*100;//% V1BYV2=sqrt(s2/s1*(R2**2+(s1/100*X2)**2)/(R2**2+(s2/100*X2)**2));//from torque equation //let V1=V12BYV1 V2=1 V1=V1BYV2;//V V2=1;//V V12BYV1=(V1-1)/V...
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function [stk,txt,top]=sci_erf() // Copyright INRIA txt=[] stk=list('erf('+stk(top)(1)+')','0',stk(top)(3),stk(top)(4),stk(top)(5))
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function [K,Y,err]=leqe(P21,Qx) [A,B1,C2,D21,xo,dom]=P21(2:7) [KT,Y,err]=leqr(syslin(dom,A',C2',B1',D21'),Qx); K=KT';
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Example9_7_a.sce
//Example 9.7 (a) //Program To Determine Frequency Resolution of Bartlett, //Welch(50% Overlap) and Blackmann-Tukey Methods clear; clc; close; //Data Q=10;//Quality Factor N=1000;//Samples //FREQUENCY RESOLUTION CALCULATION K=Q; rb=0.89*(2*%pi*K/N); rw=1.28*(2*%pi*9*Q)/(16*N); rbt=0.64*(2*%pi*2*Q)/(3*N); ...
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// Example 18.1, page no-460 clear clc atom=4 kci=0.629*10^-9//m alfk=1.264*10^-40//m^2 alfCl=3.408*10^-40//m^2 eps0=8.854*10^-12 pol=alfk+alfCl N=atom/kci^3 epsr=(N*pol/eps0)+1 printf("\nThe electronic polarisability for KCL = %.3f *10^-40 F m^2\n",pol*10^40) printf("\nThe no of Dipoles per m^3 = %.3f * 10...
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// Example 2.7, page no-119 clear clc printf("1 kg/cm^2 = 10 mWG\n") //(a) press=10+2 printf("\n(a)Bourdon Gauge is mounted 20 meters below water line:\nPressure read by the Gauge = %d kg/cm^2",press) //(b) press2=10-3 printf("\n\n(b)Bourdon Gauge is located 30 meters above the water line:\nPressure read b...
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clc // Given that d = 4 // distance of star from the earth in light years v = 3e8 * sqrt(0.9999) // speed of rocket in meter/sec // Sample Problem 33 on page no. 11.31 printf("\n # PROBLEM 33 # \n") printf(" Standard formula used \n") printf(" t = t_0/((1-v^2/c^2)^1/2) \n") t = (2 * d * 3e8) / v T_ = t * sqrt(1 - (v /...
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//Example 1_40 clc; clear; close; format('v',5); //given data : V=24;//V R1=7;//ohm R2=7;//ohm R3=7;//ohm R4=7;//ohm R5=8;//ohm R6=10;//ohm RAB=(R5*R6/(R5+R6)+R4)*(R2+R3)/(R5*R6/(R5+R6)+R4+R2+R3)+R1;//ohm I=V/RAB;//A I2=I*(R2+R3)/(R2+R3+R5*R6/(R5+R6)+R4);//A VPQ=I2*(R5*R6/(R5+R6));//V disp(VPQ,"Voltage...
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11_18.sce
clc; clear; p=60;//psia T=1000;//degree R px=12;//psia k=1.4; R=53.3;//ft*lb/(lbm*degree R) pratio=p/px; //for this value of pratio, Max is calculated as Max=1.9; //using this value of Max, Tx/T0,x is found as Tratio=0.59; //T=T0,x=T0,y Tx=Tratio*T;//degree R cx=(R*Tx*k)^0.5;//ft/sec Vx=1.87*cx*(32.2^0....
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clc clear //Input data t=5;//Time taken for a body to cool from 60 to 40 degree centigrade in minutes t11=60;//The initial temperature of the body in degree centigrade t12=40;//The final temperature of the body in degree centigrade ts=10;//The temperature of the surrounding in degree centigrade //Calculat...
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//Problem 2.09: Calculate the power dissipated when a current of 4 mA flows through a resistance of 5 k //initializing the variables: I = 0.004; // in ampere R = 5000; // in ohms //calculation: P = I*I*R printf("\n\nResult\n\n") printf("\nPower(P): %.2f Watt(W)\n",P)
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// Copyright (C) 2021 - UGA - JIANG Yilun // // Date of creation: 2021-9-15 // deff("y = f3(x)", "y = log(x + sqrt((x) .^ 2 - 1))") deff("y = f4(x)", "y = log(x + sqrt((x) .^ 2 + 1))") deff("y = f5(x)", "y = 1/2 * log((1 + x) ./ (1 - x))") t = 0:0.2:5 u = f3(cosh(t)) v = f4(sinh(t)) w = f5(tanh(t)) M = [t;u;v;w]' d...
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clear; clc; //Example3.15[Cost of Heat Loss through walls in winter] //Given:- R_va_insu=2.3;//thickness to thermal conductivity ratio[m^2.degreeCelcius/W] L1=12;//length of first wall of house[m] L2=12;//length of second wall of house[m] L3=9;//length of third wall of house[m] L4=9;//length of fourth wall of...
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//NETWORK PROJECT //IMPLEMENT NETWOK TOPOLOGY WITH DATA TRANSFER INCLUDING SECURITY STANDARDS // BY SHREYA SOMKUWAR name='TOPOLOGY';// graph name n=7;//graph parameters tail=[1 1 1 2 2 3 3 4 4 4 5 6]; head=[2 3 4 4 5 4 6 5 6 7 7 7]; node_x=[100 275 275 500 750 750 900]; node_y=[500 200 800 500 200 800 500]; [g]=...
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style.fontSize=12; style.displayedLabel="vmm_offc"; pal1_1=xcosPalAddBlock(pal1_1,"vmm_offc",[],style);
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//Example 10.2, Page Number 498 //Sensitivity Calculation clc; a=5*(10**-7) //Thermal expansion Coefficient per Kelvin b=6.8*(10**-6) //Thermal Expansion Coefficient per Kelvin l=1.55*(10**-6) //Wavelength in meter p11=0.126 //Constant Coeffiecient p12=0.274 //Constant Coeffiecient u=0.17 n=1.46//cladding ...
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errcatch(-1,"stop");mode(2);; //; f=50; cap=1.2*10^(-6); xl=1/(3*2*(%pi)*cap*f); printf("The inductive reactance to neutralize 100 percent of the capacitance is:%.2f Ohm\n",xl); xl1=xl/0.9; printf("The inductive reactance to neutralize 90 percent of the capacitance is:%.2f Ohm\n",xl1); xl2=xl/0.8; printf("...
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// Three-Phase Circuits :example 6.31 :(pg 6.32) VL=220; Po=11.2*10^3; N=0.88;//efficiency IL=38; Pi=(Po/N); x=(Pi/(sqrt(3)*VL*IL)); phi=acosd(x); W1=(VL*IL*cosd(30-phi)); W2=(VL*IL*cosd(30+phi)); printf("\nVL=220 V \nPo=11.2kW \nN=0.88 \nIL=38A \N=(Po/Pi)= %.2f W",Pi); printf("\nPi=sqrt(3)*VL*IL*cos(phi) \n...
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clc //initialisation of variables clear r= 96 T= 10.5 //C K1= 288 //C K2= 0.0015 //C^-1 h= 3000 //ft P1= 14.69 //CALCULATIONS P2= P1*10^(((1/(r*K2))*log10((K1-K2*h)/K1))) w= P2*144/(r*(273+T)) //RESULTS printf ('Density = %.4f lb/ft^3 ',w)
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// Graphics of some histograms // Nonlinear initial regions // Z=1, 3, 4, 10 model scf(0);clf(); a = get("current_axes"); a.x_label.font_size=4; a.x_label.text="$\log_{10}t$"; a.y_label.font_size=4; a.y_label.text="$\log_{10}P(t)$"; a.title.foreground=9; a.title.font_size=4; a.title.text="$\textrm{Time distrib...
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//find clc //solution //given Wr=2500//N Wa=1500//N //Wa/Wr=0.6 //refer table 27.4 X=1 V=1 Y=0 W=X*V*Wr + Y*Wa//N //from table 27.5,Ks=1.5... Ks=1.5 W1=W*Ks//N //ref table 27.6 C=53000//N L=(C/W)^(3)*10^6 printf("rating life is,%f rev\n",L)
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clc;clear;close; function[x,a]=gaussElimination(A,b) A_aug=[A b] a=A_aug n=3; for i=2:n for j=2:n+1 a(i,j)=a(i,j)-a(1,j)*a(i,1)/a(1,1); end a(i,1)=0; end for i=3:n for j=3:n+1 a(i,j)=a(i,j)-a(2,j)*a(i,2)/a(2,2); end a...
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//EX12_22 Pg-41 clc clear R=5;//frequency deviation constant in KHz/V fm=10;//modulation frequency in kHz V=15;//amplitude of the modulating signal fd=R*V;//frequency deviation printf("\n maximum frequency deviation fd=%.0f KHz/V \n",fd) mf=fd/fm; printf(" \n modulation index mf=%.1f",mf)
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function f=%rs(f) // %rs(f) -f, f rational //! f(2)=-f(2)
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// O ponto do quadrado correspondente à extremidade de um vetor w do plano // será desenhado como a extremidade do vetor u0+M*w function [] = desenhaQuad (M, u0) a = gca() //obtem posição dos eixos a.isoview = "on" //usa a mesma escala nos dois eixos // a.axes_visible = "on" //defina o vetor w0 da...
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//Example 2.1, Page Number 51 //Conductivity Calculation clc; dc=8.93*(10**3) //Density of Copper in Kg/meter cube N=63.54 //Atomic Mass Number of Copper in amu t=2.6*(10**-14)//Mean free time between collision (in seconds) m=9.1*(10**-31) //Mass of electron in kilogram em=0.135 //Electron Mobility in meter sq...
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clear; clc; // Illustration 12.9 // Page: 709 printf('Illustration 12.9 - Page: 709\n\n'); // Solution //***Data***// x1 = 0.46;// [fraction moisture] x2 = 0.085;// [fraction moisture] Y1 = 0.08;// [kg water/kg dry solid] Y2 = 0.03;// [kg water/kg dry solid] G = 1.36;// [kg/square m.s] //**********...
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clc clear //Input data To=27+273 //Stagnation temperature in K Po=8 //Stagnation Pressure in bar P=5.6 //Static pressure in bar, taken from diagram given m=2 //Mass flow rate in kg/s k=1.4 //Adiabaatic constant Cp=1005 //Specific heat capacity at constant pressure in J/kg-K R=287 //Specific gas constant in J...
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printf("\t example 7.7 \n"); printf("\t approximate values are mentioned in the book \n"); U=50; // Btu/(hr)*(ft^2)*(F) TP=328; // F TE=228; // F CP=(0.30/(888.8*1000)); CE=(0.05/(960*1000)); CF=1.20; theta=8000; // annual hours X=((CF*(TP-TE))/((CP-CE)*U*theta)); // from eq 7.53 printf("\t X is : %.9f \n",X)...
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// Calculating the specific iron loss clc; disp('Example 3.12, Page No. = 3.35') // Given Data Bm = 1.0;// Maximum flux density in Wb per meter square f = 100;// Frequency in Hz t = 0.3*10^(-3);// Thickness of sheet in mm p = .5*10^(-6);// Resistivity of alloy steel in ohm*meter D = 7650;// Density in kg per me...
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clear; clc; n=-5:5; for i=1:length(n) if(n(i)>=-1) h(i)=2^-(n(i)+1); else h(i)=0; end end causal=%t; for i=1:length(n) if n(i)<0 & h(i)~=0 then causal=%f; end end disp(causal,"the statement that the system is causal is");
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//Example 9.9// xl=12.6;//wt % //liquid solution composition xa=1.6;//wt %// composition of two phases x1=10;//wt % //x1 is the overall composition xb=100;//wt %//composition of two phases a=1;//kg ma=((xl-x1)/(xl-xa))*a mprintf("ma = %f kg ",ma) b=10^3;//g //As 1kg = 10^3grams ma2=ma*b mprintf("\nma2= %i g"...
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function [x0,f0,iter]=naive(x0,maxiter,krok) exec('cel.sci'); clf exec('mapa.sci',0); [f0,df0]=cel(x0); iter=0; kryt=norm(df0); g=df0; while(kryt>0.0001)&(iter<maxiter) do x1=x0-krok*g; [f1,df1]=cel(x1); iter=iter+1; xsegs([x0(1);x1(1)]',[x0(2);x1(2)]'); x0=x1; f0=f1; kryt=norm(df1); g=d...
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clc D=2*10^-14//cm^2/sec t=3600//K Cx=10^19 A=sqrt(D*t) disp(A,"A in cm is= ") Qt=1.13*Cx*A disp(Qt,"Q(t) in atoms/cm^3") //dC/dx=b b=-(Cx/sqrt(%pi*D*t)) disp(b,"dC/dx in cm^-4 is= ") xj=2*sqrt(D*t)*2.75 disp(xj,"xj in meter is= ") b=-(Cx/sqrt(%pi*D*t))*exp(-xj^2/(4*D*t)) disp(b,"dC/dx in cm^-4 is= ") ...