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// Double integrator, p. 362 and p. 446 of Ogata a1 = [0 1; 0 0]; b1 = [0;1]; c1 = [1 0]; d1 = 0; // Transfer functions Ga = syslin('c',a1,b1,c1,d1); Ts = 0.2; [B,A,k] = myc2d(Ga,Ts); // Discrete time state space matrices [a,b,c,d] = abcd(dscr(Ga,Ts)); // Transient specifications roots = [0,0]; phi_pol...
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// Example 5.6 // A program to process loan applications and to sanction loans. MAXLOAN=50000; disp("Enter the values of previous two loans"); loan1=int32(input("Enter first loan:")); loan2=int32(input("Enter second loan:")); loan3=int32(input("Enter the values of new loan:")); sum23=loan2...
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clear // // // //Variable declaration theta=15*%pi/180 //angle(radian) lamda=6500*10**-8 //wavelength(cm) n=1 //order //Calculation a=n*lamda/sin(theta) //slit width(cm) //Result printf("\n slit width is %0.2f *10**-4 cm",a*10**4)
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clear; clc; x=[1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 ];//dividing the x axis in 24 hours y=[30 30 30 30 20 20 20 20 20 8 8 8 8 8 8 8 8 8 8 8 8 8 8 5];//load in MW values bar(x,y,1,'blue'); //plotting the bargraph with a width of 1 xlabel('time in hours'); ylabel(...
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////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Version: 0.1 // Date: Dec. 2009 // // // Copyright (C) 2009 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with or without // modification, are permitted provided that the ...
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//chapter 10 //example 10.1 //page 381 printf("\n") printf("given") Vdd=22;Rd=2*10^3; disp("when Id=0") Id=0; Vds=Vdd-Id*Rd disp(" at point A Id=0 nad Vds=22") Vds=0; Id=Vdd/Rd disp(" at point B Id=11mA and Vds=0")
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//**************************** Max_detect ********************************** if (blk_name.entries(bl) == "Max_detect") then mputl("#Max_detect",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) Max_detect_str= '.subckt Max_detect'+' in[0]=net'+string(blk(blk_objs(bl),2))+'_'+string(ss)+' out[0]=net'+string(b...
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//[]=finit() // Initialisation de parametres relatif au probleme // de l'alunissage //k : acceleration de poussee de la fusee //gamma : acceleration de la pesanteur sur la lune //umax : debit maximum d'ejection des gaz //mcap : masse de la capsule //cpen : penalisation dans la fonction cout de l'etat final //! k...
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// page no 493 // example no 15.6 // EXPLANATION OF INSTRUCTIONS clc; printf('1) DI instruction disables the interrupts. \n \n'); printf('2) Command word 76H specifies the following parameters \n'); printf('A7 A6 A5 A4 A3 A2 A1 A0 \n'); printf('0 1 1 1 0 1 1 0 =76H \n'); printf('A7,A6,A5 Low ord...
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// Exa 1.19 clc; clear; close; // Given data format('v',7) V_BE=0.715;// in volt V_CC=9;// in volt Bita_dc=100; Bita_ac= Bita_dc; V_EE= 10;// in volt R=5.6;// in k ohm R= R*10^3;// in ohm I_REF= (V_EE-V_BE)/R;// in amp // From 2*I_B + I_C1 -I_REF =0 I_C1= I_REF*Bita_dc/(2+Bita_dc);// in amp // By symmet...
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// The equation x^3-7*x^2+16*x-12==0 has real roots. // the graph of this function can be observed here. xset('window',25); x=0:.001:4; // defining the range of x. de...
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//Example 1_21 clc(); clear; //To find the wavelength of light used D5=0.3 //units in cm D25=0.8 //units in cm R=100 //units in cm P=20 lemda=(D25^2-D5^2)/(4*P*R) printf("The wavelength of the light used is %f cm",lemda)
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//chapter 5 //example 5.4 //Calculate wavelength //page 104 clear; clc; //given V=1600; // in V (Potential) //calculate lambda=12.27/sqrt(V); // calculation of wavelength in Angstrom printf('\nThe wavelength is\t=%.3f Angstrom',lambda); // Note: The answer in the book is wrong due to calculation mistake
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//Variable declaration n1 = 10 // Total machines n2 = 8 // Working Machines r = 2 // To be selected //Calculation function ans = fact(n) // returns factorial of number n""" if(n==1 | n==0) then ans = 1 else: ans = n*fact(n-1) end endfunction function ans = comb(n,r) ...
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clear // //variable declaration P=(40) //Load,KN L1=150 //length of 1st portion,mm A1=%pi*(25**2)/4 //Area of 1st portion**mm^2 L2=250 //length of 2nd portion,mm A2=%pi*(20**2)/4 //Area of 2nd portion**mm^2 L3=150 ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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//bender-schimdt's formula and crank-nicolson formula //example 9.7 //page 363 //bender -schimdt's formula clc;clear;close; deff('y=f(x,t)','y=exp(-%pi^2*t)*sin(%pi*x)'); u=[f(0,0) f(0.2,0) f(0.4,0) f(0.6,0) f(0.8,0) f(1,0)]; u11=u(3)/2;u12=(u(2)+u(4))/2;u13=u12;u14=u11; printf(' u11=%f\t u12=%f\t u13=%f\t u...
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s1=1-960/1000 s2=1-800/1000 R2ext=4/3*s2*0.25/s1-0.25 disp(R2ext)
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clc clear //DATA GIVEN n=4; //no. of cylinders BP=30; //Brake Power in kW N=2500; //engine speed in R.P.M. Pmi=8; //mean effective pressure in bar ETAm=0.8; //mechanical efficiency ETAthb=0.28; ...
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/* Generated at yyyy-mm-dd hh:mm by java -cp dist/ramath.jar org.teherba.ramath.ProgramGenerator -w 3 -l 3 -n barning Do N O T edit this file, but ProgramGenerator.java instead! */ #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int reslines = 0; printf("#---> start of re...
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Example28_2.sce
//Given that R1 = 20 //in Ohm R2 = 20 //in Ohm R3 = 30 //in Ohm R4 = 8 //in Ohm E = 12 //in Volts //Sample Problem 28-2a printf("**Sample Problem 28-2a**\n") R23 = R2*R3/(R2+R3) Req = R1 + R23 + R4 i = poly(0, 'i') i = E/Req printf("The current through the battery is %fA\n", i) //Sample Problem 28...
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EX5_36.sce
//EXAMPLE 5-36 PG NO=329 I1=-10; //CURRENT Vpc=15; I2=7.5; Vqc=I2*1; disp(' Voltage is = '+string(Vqc)+'V'); Vpq=Vpc-Vqc; disp(' Voltage is = '+string(Vpq)+'V'); RTH=1.406; Pmax=[I2/(2*RTH)]^2*RTH; disp(' Power is = '+string(Pmax)+'...
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FS_Ex_10_4.sce
clc //Chapter 10:Frequency Synthesizers //Example 10.4 page no 417 fo=185.6*10^6//required output frequency fr=31.25*10^3//reference frequency P=64 disp('To begin with the hopping bin channel spacing requirement of at least 20KHz,a 2MHz crystal is connected to the MC14512-2 with the reference address inputs(pins ...
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gradient performance.sce
clear exec('C:\Users\Julien Guégan\Desktop\PFE\Algorithmes\affichage.sce',-1) function z = rozenbrock(x) z = 10*(x(2)-x(1)^2)^2 + (1-x(1))^2; endfunction function z = cout(x) z = 6*x(1).^2+2*x(2).^2+4*x(1).*x(2)+x(1)+x(2) endfunction function alpha = linearsearch1(f,x,d,grad) alpha = 1 w1 = 0.9 w...
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Example5_10.sce
//chapter-5,Example5_10,pg 493 n=3//3-bit ADC SbyN=(((2^(n-1)*12^0.5)/2^0.5))//S/N ratio printf("S/N ratio\n") printf("SbyN=%.4f \n",SbyN) printf("this produces an error due to noise nearly 0.10")
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Ex2_8.sce
clear; clc;close; vgs=1.2; vt=0.4; ecln=0.6; eclp=2.4; vdsat1=((vgs-vt)*ecln)/(vgs-vt+ecln); vdsat2=((vgs-vt)*eclp)/(vgs-vt+eclp); ratio=(vgs-vt+eclp)/(vgs-vt+ecln); disp(vdsat1,'for NMOS(in volts)'); disp(vdsat2,'for PMOS(in volts)'); disp(ratio,'saturation current ratio nmos to pmos');
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Exa_8_9b.sce
//DFT and DFS of sinusoids n2=0:1/1280:31/128; xt=4*sin(72*%pi*n2'); n=0:1/128:31/128;//F=9/32 hence N=32 xn=4*sin(72*%pi*n'); XDFT=abs(fft(xn,-1)); n1=0:31; a=gca(); a.x_location="origin"; plot2d(n2,xt); plot2d3('gnn',n,xn); xset('window',1); b=gca(); b.x_location="origin"; plot2d3('gnn',n1,XDFT);
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exa_2_2.sce
// Exa 2.2 clc; clear; close; // Given data p= 12;// in bar p=p*10^5;// in N/m^2 v= 25;// in m^3 T= 30+273;// in K // Part (a) Mass of each gas //Formula p*v=m*R*T R_U= 8314;// in J/kg-mole K M_N2= 28.016;// in mole M_O2= 32;// in mole M_CO2= 44;// in mole R_N2= R_U/M_N2;// in J/kg K R_O2= R_U/M_O2;// i...
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41_13.sce
//Problem 41.13: An asymmetrical T-section attenuator is shown in Figure 41.24. Determine for the section (a) the image impedances, and (b) the iterative impedances. //initializing the variables: R1 = 100; // in ohm R2 = 200; // in ohm R3 = 300; // in ohm I1 = 1; // in amperes (lets say) //calculation: //ima...
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SSSeSourceSin.sci
// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function y=SSSeSourceSin(Frequency_GHz, Amplitude) // Cosinusoidal Source // // Calling Sequence // y=SSSeSourceSin(Frequency_GHz, Amplitude) // // Parameters // Frequency_GHz : Signal Frequency...
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Exa2_7.sce
//Exa 2.7 clc; clear; close; //given data fm=50;//in kHz SR=0.5;//in V/uSec //formula : SR=2*%pie*fm*Vm Vm=(SR*10^6)/(2*%pi*fm*10^3);//in Volts disp(Vm,"Maximum vltage in volt is :")
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ex11.sce
//ques11 //Isentropic Compression of an Ideal Gas clear clc //using the equation P2=P1*(T2/T1)^(k/(k-1)) P1=14;//initial pressure in psia T2=780;//final temp in R T1=510;//initial temp in R k=1.667;//isentropic ratio P2=P1*(T2/T1)^(k/(k-1)); printf('Final pressure = %.1f psia',P2);
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ex3_12.sce
//Calculate max and min values of zener diode current clear; clc; //soltion //given Vimin=80;//V //minimum input voltage Vimax=120;//V //maximum input voltage Rl=10*10^3;// ohm //load resistance Rs=5*10^3;//ohm //series resistance Vz=50;//V //Zener voltage V=Vimin*Rl/(Rs+Rl); ...
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6_7.sce
clc; clear; h=200;//ft U=40;//mi/hr d=0.00238;//slugs/ft^3 //V^2= (U^2)*(1 + (2*b*cos(ang)/r) + ((b^2)/(r^2))) //at point 2, ang=%pi/2 //r=b*(%pi-ang)/sin(ang)=(%pi*b/2) V=U*(1+(4/(%pi^2)))^0.5;//mi/hr y2=h/2;//ft //bernoulli equation //p1-p2= d*((V2^2)-(V1^2)) + (sw*(y2-y1)) V1=U*(5280/3600); V2=V*(5280/3...
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Ex6_17.sce
// Theory and Problems of Thermodynamics // Chapter 6 // Thermodynamic Potentials and Availability // Example 17 clear ;clc; //Given data P1 = 3 // entering pressure of superheated steam in MPa T1 = 573.15 // entering temperature of superheated steam in K P2 = 20 ...
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3_6.sce
clear; close; clc; V=78e3; Vph=V/sqrt(3); Em=2*Vph; pf=0.4; angle=acos(pf); k1=sin(angle); k1=round(k1*100)/100; k2=.951; k3=1; k=k1*k2*k3; k=round(k*1000)/1e3; E=k*Em; f=15000; t=1/(2*f); t=round(t*1e6); eavg=2*E/t; eavg=round(eavg/100)*100; printf("average restriking voltage=%fkV/microsecs",eavg...
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5_4.sci
CCH4 = [2.44 4.44 10 1.65 2.47 1.75]'*1e-4; PCO= [1 1.8 4.08 1 1 1]'; v0 =300; W= 10;
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test.tst
load test.asm, output-file test.out, compare-to test.cmp, output-list RAM[5000]%D1.6.1 RAM[5001]%D1.6.1 RAM[5002]%D1.6.1; repeat 1000000 { ticktock; } output;
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Ex_7_7.sce
// Example 7.7 //width of deplition region clc; clear; close; n=70;//efficinecy absc=10^5;//cm^-1 W=(2.303*-log10(1-(n/100)))/(absc);//in meter disp(round(W*10^6),"deplition width in micro meter is")
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//Example 3.11.C // CURRENT IN EACH RESISTANCE clc; clear; close; t=15;//TOTAL CURRENT IN AMPERES i1=2;//CURRENT THROUGH UNKNOWN RESISTANCE R1=15;//in ohms R2=50/2;//in ohms x=(t-i1)*((R1*R2)/(R1+2*R2));//unknown resistance in ohms PD=i1*x;//in volts i5= PD/(2*R2);//current in 5 ohms resistance i15=PD/R1;//current in 1...
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Chapter-2, Illustration 5, Page 60 //Title: Gas Power Cycles //============================================================================= clc clear //INPUT DATA rv=8;//Compression ratio P1=95;//Pressure at point 1 in kPa T1=300;//Temperature at point 1 in K q23=750;//Heat transferred during constant vol...
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//Ch25_Ex28 clc; clear; close; db=1.5; rb=db/2; //diameter and radius of bullet rc=6; hc=28;//radius and height of cylinder volC=%pi*rc^2*hc; volB=(4/3)*%pi*rb^3; noBullets=volC/volB; mprintf("THe number of bullets are %d",noBullets);
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clc; clear all; er=12;//relative dielectric constant of material N=5e28;//no of atoms e0=8.85e-12;//permittivity of vacume xe=e0*(er-1)/N;//polarisability of element disp('F m^2',xe,'polarisability of element is:')
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clc,clear printf('Example 4.18\n\n') m=1.8 //mass of aluminium to be melt t1=15 //initial temperature t2=660 //melting temperature S=880 //specific heat of aluminium L=32000 //latent heat of aluminium heat_required= m*S*(t2-t1) + m*L heat_required= heat_required*2.78*10^-7 //converting Joules to kWh T=10...
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5_06data.sci
V=100;//velocity of airplane(m/s) H=3000;//standard altitude at which airplane is flying(meter) Cp=-2.2;//pressure coefficient at a point on fuselage P=7.0121*10^4;//pressure at 3000 m,N/m^2 D=0.90926;//density at 3000 m,Kg/m^3 q=D*V^2/2 //dynamic pressure,N/m^2
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example2_7.sce
clear; clc; //Example2.7[Heat Flux boundary Condition] //Given:- Q=800;//Heat transfer rate[W] D=0.2;//Diameter of pan[m] L=0.003;//Thickness of pan[m] T_in=110;//T(L) Temperature of the inner surface of the pan[degree Celcius] neta=0.9;//Percent of total heat transferred to the pan //Solution;- //The inner...
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Ex21_2.sce
//chapter21 //example21.2 //page463 R=10d3 // ohm C=0.01d-6 // F T=1.4*R*C f=1/T printf("time period of square wave = %.3f ms \n",T*1000) printf("frequency of square wave = %.3f kHz \n",f/1000) // the accurate answer for frequency is 7.143 kHz but in book it is given 7 kHz
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// Example 4.1;NUMBER OF TURNS clc; close; clear; // given : format('v',7) e1=2200;//voltage in volts f=50;//frequency in Hz e2=220;//voltage in volts fd=1.6;//magnetic field in Tesla a=3600;//area in mm^2 n1=(e1/(4.44*f*fd*a*10^-6));//number of turns n2=(e2/(4.44*f*fd*a*10^-6));//number of turns disp(round(n1),"numbe...
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Exa_9_11.sce
//interference Rejection //design oh high-Q and low-Q notch filters s=%s;z=%z; Q=50; fo=60;S=300; delf=fo/Q; Wo=2*%pi*fo/S; delW=2*%pi*delf/S; C=tan(0.5*delW),B=cos(Wo) HS=(s)/(s+1); H1Z=horner(HS,(z^2-(2*B*z)+1)/(C*(z^2)-C)) Q1=5;delf1=fo/Q1; delW1=2*%pi*delf1/S; C1=tan(0.5*delW1),B1=cos(Wo) H2Z=horner(H...
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10_1.sce
//Example 10.1 //Taylor Method //Page no. 302 clc;clear;close; deff('y=f1(x,y)','y=y-2*x/y') deff('y=f2(x,y)','y=(2*y*f1(x,y)-2-f1(x,y)^2)/y') deff('y=f3(x,y)','y=(2*y*f2(x,y)-3*f1(x,y)*f2(x,y)+2*f1(x,y)^2)/y') h=0.1;y=1; x=[0.1;-0.1] for i=1:2 k=y; for j=1:3 if j==1 then k=k+...
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Ex10_13.sce
clear; clc; r1 = 0.5*9;// inches r2 = 0.5*3;// inches r3 = 0.5*6;// inches del_r3 = 0.5*0.003;// inches E = 13000;// tons/in^2 k1 = r1/r3; k2 = r2/r3; a1 = (del_r3/r3)*E/((k1^2 +1)- (k2^2 +1)*(k1^2 -1)/(k2^2 -1)); a = a1*(k1^2 -1)/(k2^2 -1); b1 = a1*r1^2; b = a*r2^2; p_ = (b/r3^2) -a;// tons/in^2 // for t...
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Ex31_7.sce
//To Calculate the Energy stored in Capacitor //Example 31.7 clear; clc; C=100*10^-6;//Capacitance of the capacitor in Faraday V=20;//Potential Difference in Volts U=1/2*C*V^2;//Formula for finding the energy stored in a capacitor printf("The energy stored in the capacitor= %f J",U);
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Ch04Ex2.sce
// Scilab code Ex4.2: Pg 116 (2008) clc; clear; A = 45e-06; // Cross sectional area of pole face, metre-square B = 0.6; // Flux density, T // Using formula B = phi/A, solving for phi phi = B*A; // Flux, Wb printf("\nThe flux produced by pole face = %2d mic...
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exa_2_9.sce
// Example 2.9 clc; clear; close; // Given data P1= 96;// in kN/m^2 P2= 725;// in kN/m^2 V1= 600;// in cm^3 V2= 100;// in cm^3 T1= 100+273;// in K // Formula P1*V1/T1 = P2*V2/T2 T2= P2*V2*T1/(P1*V1);// in K disp(T2-273,"Temperature at the end of compression in °C is : "); // Note:- In the book, There is an...
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2016-09-27T05:12:48
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statelevels17.sce
// x=[-0.00104287295007201 -0.00244190236539361 0.00330474678679599 0.00312506274996585 -0.00888427641170878 -0.000128837692967764 ]; [levels,histogram,binlevels] = statelevels(x,100,'mean'); disp(levels); //output // - 0.0088233 0.0005378
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multi_lidar_point.sce
//point in Lidar 1 q = [10;3;1]; //lidar motion T1_1 = eye(3,3); T2_1 = [cos(-%pi/8) -sin(-%pi/8) 0.1; sin(-%pi/8) cos(-%pi/8) 0 0.2; 0 0 1 -0.2; 0 0 0 1 ]; T3_1 = [cos(-%pi/5) -sin(-%pi/5) 0 0.5; sin(-%pi/5) cos(-%pi/5) 0 -0.1; 0 0 1 0.1; 0 0 0 1 ]; T4_1 = [cos(%pi/7) 0 -sin(%pi/7) 0.5; 0 1 0 0.1; sin(%pi/7) 0 cos(%...
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response_stability.sce
clc; clf; clear all; t=0:0.01:5; s1=exp(-t); s2=exp(t); subplot(2,1,1); plot(s1); xlabel("time"); ylabel("amplitude"); title("plot by Om"); subplot(2,1,2); plot(s2); xlabel("time"); ylabel("amplitude"); title("plot by Om");
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Ficha prática 7.sce
//Matemática Discreta - Proposta de resolução da ficha prática 7 //Nota: As resoluções que se seguem apresentam apenas sugestões de resolução dos exercícios propostos. Na maior parte dos casos, existem muitas outras formas de resolver o exercício. //Exercício 1 function P=Warshall(A) [u,v]=size(A) P=A for k=1:u ...
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clear; clc; syms s t n; I=1/(s/2+2+20/s) i=ilaplace(I) disp(i,"i(t)=")
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function x=old2new(x) nx=size(x) for k=1:nx o=x(k) if o(1)=='Block' then graphics=o(2) [ip,op,cip,cop]=get_cnct(x,k) graphics(5)=ip graphics(6)=op graphics(7)=cip graphics(8)=cop o(2)=graphics x(k)=o end end function [ip,op,cip,cop]=get_cnct(x,k) //old version of get_connected onl...
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clc //Chapter5 //Ex_17 //Given Eg=1.42 //in eV //letE=hc/lambda=hf E=1.96 //in eV P_L=50 //in mW kT=0.0259 // in eV delta_E=E-(Eg+(3/2)*kT) P_H=(P_L/(E))*delta_E disp(P_H,"Amount of power dissipated as heat in mW is")
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// Scilab Code Ex3c.11: Page-187 (2008) clc; clear; D_n = 0.42; // Diameter of nth ring, cm D_mplusn = 0.7; // Diameter of (m+n)th ring, cm m = 14; // Difference between (m+n)th and nth rings R = 100; // Radius of curvature of the plano-convex lens, m lambda = (D_mplusn^2 - D_n^2)/(4*m*R); // Wavel...
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function ri = moc_randi (bounds, varargin) // Return random integers in a given range // Calling Sequence // ri = moc_randi(imax) // ri = moc_randi(imax,n) // ri = moc_randi(imax,m,n,...) // ri = moc_randi([imin,imax],...) // Description // Additional arguments determine the shape of the return matrix. When no // argu...
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clc h1=3100; //kJ/kg h2=2100; //kJ/kg h3=2500; //kJ/kg h_f2=570.9; //kJ/kg h_f5=125; //kJ/kg h_f2=570.9; //kJ/kg a=11200; //Quantity of bled steam in kg/h m=(h_f2-h_f5)/(h2-h_f5); S=a/m; //Steam supplied to the turbine per hour W_net=(h1-h3) + (1-m)*(h3-h2); P=W_net*S/3600; //Power developed by the t...
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function fRad = d2r(fDeg) fRad = fDeg * %pi / 180; endfunction
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//Chapter 6 //Example 6-8 //DesignOnSawtoothWaveGenerator //Page 163 clear;clc; //Design a voltage divider to give voltage reference 10 V //Here Ri = 10 KiloOhm and C = 0.1microfarad //The Circuit will be as shown below xcos('Figure6_8.xcos'); //Checking Frequency value Ri = 10*10^3 ; Ci = 0.1*10^-6 ; Ei =...
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clear all; clc; //Project on image compression //Using PCA-Principal Component Analysis technique //Implementing the maths behind PCA img= imread('C:\Users\dell\Pictures\Camera Roll\wallpaper.jpg'); gray_img = rgb2gray(img); gray_imgdouble = im2double(gray_img); meancol=mean(gray_imgdouble,'r'); [a b]= size(gray_img)...
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//example 12 //determining specific using diffenet laws clear clc T=100 //given temp.in 100 celsius P=3 //given pressure in MPa v1=0.0065 //specific volume in m^3/kg using table printf("\n hence,the specific volume for R-134a using R-134a tables is v1 = %.3f m^3/kg. \n",v1) M=102.3 //molecular mass in kg R=8.3...
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//Example 4.7 clc disp("V_L = 866 V, kVA = 100") disp("Therefore, kVA = sqrt(3)*V_L*I_L*10^-3") il=100/(sqrt(3)*866*10^-3) format(6) disp(il,"Therefore, I_L(in A) =") disp("Therefore, I_aph F.L. = I_L = 66.67 A ... as star connected alternator") disp("V_ph = Rated terminal voltage per phase = V...
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// Example 14_4 clc;funcprot(0); // Given data // Station 1 x_1=1.00;// The dryness fraction T_1=-15.0;// °C h_1=244.13;// kJ/kg s_1=0.95052;// kJ/kg.K // Station 2 p_2s=909.9;// kPa s_2s=0.95052;// kJ/kg.K s_2s=s_1;// kJ/kg.K h_2s=271.92;// kJ/kg T_2s=39.3;// °C // Station 3 T_3=20.0;// °C x_3=0.00;// ...
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// Example 7.9 page no-424 clear clc Rc=4 Rb=40 Rs=10 hie=1.1 hfe=50 hre=0 hoe=0 Rcdash=Rc*Rb/(Rc+Rb) R=Rs*Rb/(Rs+Rb) Rm=-hfe*Rcdash*R/(R+hie) Rm=floor(Rm) printf("\nTransresistance Rm=%d k",Rm) B=-1/(Rb) D=1+B*Rm Rmdash=Rm/D Avdash=Rmdash/Rs Ri=R*hie/(R+hie) Ridash=Ri/D printf("\nBeta=%.3f mA/...
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//example 6.3// clc //clears the screen// clear //clears all existing variables// disp('Difference output = X''Y+XY''') disp('Borrow output = X''Y')
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function X = chami(a,b,c) if (size(a,'*') > 1 & size(b,'*') > 2) then disp('You are going in a correct direction keep going') end X = a*b*c^2; disp(X) endfunction function out = checkunity(x) if(size(x)==1 & x==1) out = "TRUE" else out = "FALSE" end return(out)...
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//Example 5_2 clc; clear; close; format('e',9); //given data : ND=10^16;//cm^-3 A=4*10^-4;//cm^2 NA=5*10^18;//cm^-3 T=300;//K epsilon0=8.85*10^-14;//vaccum permittivity epsilonr=11.8;//relative permittivity e=1.6*10^-19;//C/electron ni=1.5*10^10;//cm^-3 kBT=0.0259;//eV//at room temperture V0=kBT*log(NA*...
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clc //Initialization of variables T1=77.32 //K P=1 //atm T2=126 //K Pc=33.5 //atm //calculations dS=27/32 *1.987*P/Pc *(T2/T1)^3 //results printf("Change in entropy = %.2f eu/mol",dS)
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clc; funcprot(0); //Example 16.2 Horsepower required at sea level // Initialisation of variables W = 4225; b1 = 38; b2 = 35; Gap = 5.35; S1 = 214; S2 = 150; Dp = 9.4; // Parasite drag equivalent // Calculations mu =b2/b1; Gab_MeanSpan = 2*Gap/(b1+b2); S = S1 + S2; sigma = 0.56; ...
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5.0 3.0 1.6 0.2 Iris-setosa 5.0 3.4 1.6 0.4 Iris-setosa 5.2 3.5 1.5 0.2 Iris-setosa 5.2 3.4 1.4 0.2 Iris-setosa 4.7 3.2 1.6 0.2 Iris-setosa 4.8 3.1 1.6 0.2 Iris-setosa 5.4 3.4 1.5 0.4 Iris-setosa 5.2 4.1 1.5 0.1 Iris-setosa 5.5 4.2 1.4 0.2 Iris-setosa 4.9 3.1 1.5 0.2 Iris-setosa 5.0 3.2 1.2 0.2 Iris-setosa 5.5 3.5 1.3 ...
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function [V0, c1, c2] = EuOption_BS_MC (S0, r, sigma, T, M, g) // Generate an Mx1-vector of independent samples from // standard normally distributed random variables. X = grand(M, 1, 'nor', 0, 1); ST = S0*exp( (r-0.5*sigma^2)*T + sigma*sqrt(T)*X ); // Compute Monte-Carlo estimator. ...
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// Exa 3.27 clc; clear; close; // Given data P1 = 1 * 10^5;// in N/m^2 V1 = 0.1;// in m^3 V2 = 0.01;// in m^3 T1 = 90;// in degree C T1 = T1 +273;// in K R = 0.287;// in kJ/kg-K R = R *10^3; C_v = 0.717;// in kJ/kg-K C_P = 1.005;// in kJ/kg-K m = (P1 * V1)/(R*T1);// in kg Gamma = 1.4; T2 = T1 * ((V1/V...
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//Engineering and Chemical Thermodynamics //Example 9.6 //Page no :451 clear ; clc ; del_g0_f_C6H6 = -32.84 ; //[kJ/mol] , From Table E9.6 del_g0_f_C2H4 = 68.15 ; //[kJ/mol] , From Table E9.6 del_g0_f_H2 = 0 ; //[kJ/mol] , From Table E9.6 del_h0_f_C6H6 = -84.68 ; //[kJ/mol] , From Table E9.6 del_h0_f_C2H4 = ...
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function update_country() eu_countries = ['Germany', 'Italy', 'Spain']; // [header, data] = importdata(covid_getpath()+"\data\time_series_covid19_confirmed_global.csv"); // confirmed = strtod(data(:,5:$)); // country = data(:,2); c = get("country"); // a=get("cases_plot_...
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-> grados1= 7 grados1 = 7. --> grados2= 60 grados2 = 60. --> grados3= 75 grados3 = 75. --> radianes= grados*%pi/180 Undefined variable: grados --> radianes1= grados*%pi/180 Undefined variable: grados --> radianes1= grados2*%pi/180 radianes1 = 1.0471976 ...
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clear clc //Example 6.12 PRESSURE RISE DUE TO WATER HAMMER EFFECT rho=1.94; //[slugs/ft^3] Ev=3.2*10^5; //[lbf/in^2] V=4; //[ft/s] //Sound speed c=sqrt(Ev*144/rho) //[ft/s] L=3000; //[ft] tc=2*L/c //[s] //Closure time of 1sec is less than tc //Pressure rise delp=rho*V*c/144 //[psi] pi=40; //initial pressur...
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ExemploErroDeArredondamentoCatastrofico.sce
x = 1/3 y = 0.333333 z_exato = 0.00000033333333333333333333333333333333333333333333333333333 z_aproximado = x-y resultado = digitos_significativos(z_exato,z_aproximado) format(25) disp(z_exato) disp(z_aproximado) disp(resultado) disp('Se perdeu 6 digitos de significancia por arredondamento catastrófico')
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function f=%p_d_p(p1,p2) //f= %p_d_p(p1,p2) <=> f=p1./p2 //! // Copyright INRIA if size(p1,'*')==1 then p1=p1*ones(p2) elseif size(p2,'*')==1 then p2=p2*ones(p1) end [p1,p2]=simp(p1,p2); f=tlist(['r','num','den','dt'],p1,p2,[])
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//ques-2.18 //Calculating weight of air and oxygen and weight of air when excess air is supplied and GCV and NCV clc C=750;//Weight of carbon in coal (in g) H=52;//Weight of hydrogen in coal (in g) O=121;//Weight of oxygen in coal (in g) N=32;//Weight of nitrogen in coal (in g) e=40;//Percentage of excess air su...
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//Example 7.15 clc disp("Given values are R_L = 1 k-ohm, V_m = 10 V peak") disp("case(i) Ideal diode") disp("Cut-in voltage V_T = 0 V, R_f = 0 ohm") edc=10/%pi format(5) disp(edc,"Therefore, E_DC(in V) = V_m/pi =") idc=3.18 disp(idc,"Therefore, I_DC(in mA) = E_DC/R_L =") disp("case(ii) Silicon diode") disp...
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//ex3.6 V_Z=12; V_IN=24; I_ZK=1*10^-3; I_ZM=50*10^-3; Z_Z=0; R=470; //when I_L=0, I_Z is max and is equal to the total circuit current I_T I_T=(V_IN-V_Z)/R; I_Z_max=I_T; if I_Z_max<I_ZM then I_L_min=0; end I_L_max=I_T-I_ZK; R_L_min=V_Z/I_L_max; disp(R_L_min,'minimum value of load resistance in ohms')...
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function bisection() xl=0; xu=1; xm=0.5; y1=1; ym=(0.5^3)-(5*0.5)+1; if(y1*ym<0) then xu=xm; end while (1) m=(xl+xu)/2; yl=(xl^3)-(5*xl)+1; ym=(m^3)-(5*m)+1; e=((m-xm)/m)*100; if(-5<e&e<5) then disp(m); break; ...
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testConversionQuat.sce
clear;clc;getd("./Local_Planner"); q1 = createQuaternion(0,[1 0 0]); q2 = createQuaternion(%pi/2,[0 1 0]); q3 = createQuaternion(-%pi/4,[1 0 1]); q4 = createQuaternion(-3*%pi/2,[1 1 0]); q5 = createQuaternion(-%pi/3,[0 0 1]); vector = [-1 -1 1]; angle = %pi/2; R = matrix_fromAngleVector(angle,vector); [a,b] = angl...
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clear clc // Mean orbital elements, frame = ECI(EME2000) sma = 6800.e3; // semi major axis (unit m) ecc = 1.e-3; // eccentricity inc = 45 * %pi/180; // inclination pom = %pi/2; // Argument of perigee gom = 5.5289325; // RAAN (Longitude of the ascending node) anm = 0; // Mean anomaly // Orbit type: Keplerian or Cir...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Add16.tst load AddSub16.hdl, output-file AddSub16.out, compare-to AddSub16.cmp, output-list a%B1.16.1 b%B1.16.1 sel out%B1.16.1; set a %B0000000000000000, set ...
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//Example 4.6 m=70;//Mass of the tightrope walker (kg) theta=5;//Angle (deg) g=9.8;//Acceleration due to gravity (m/s^2) w=m*g;//Weight of the tightrope walker (N) T=w/(2*sind(theta));//Tension (N), See Equation 4.52 //See textbook for derivation printf('Tension in the wire = %0.1f N',T) //Answer varies due to ...
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//pagenumber 35 example 17 clear nd=10^14;//atoms per cubic centimetre na=5*10^13;//atoms per cubic centimetre un=3800; up=1800; q=1.6*10^-19;//coulomb resist=80;//ohm metre e1=5;//volt per metre w=nd-na; ni=(un+up)*q*resist; p1=poly([1 w -ni^2],'q'); roots(p1);//p1=taken as 3.65*19^12 p1=3.65*10^12; n=p1...
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//EXAMPLE 5-28 PG NO-322 Z1=0.6-%i*1.2; Z2=0.6-%i*1.2; Z3=1.2+%i*0.6; Z=Z1+(((Z2+3)*(Z3+%i*3))/(Z2+3+Z3+%i*3)); disp('i) Impedance (Z) is in polar = '+string (Z) +' ohms ');
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//Chapter 9 //Example 9.7 //page 355 //To evaluate Zbus using Current Injection method clear;clc; disp("We can approach this problem using XCOS simulation") disp("In this simulation"); disp("1)For injecting unit current at bus1 keeping bus2 open circuit,we use a current source of 1 unit which is switched on from t=0 ...
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chdir('C:\Users\matve\Desktop\Code These\ResilienceMSY\'); exec('fctdyn.sce'); exec('fctdyn_eco.sce'); //////////////////////////// //Parametre de lancement //////////////////////////// nb_boats_Post_BAU=nb_boats_MSY; aij=data_param(2:2+N_species-1,2:2+N_species-1); choc=0 Y=20; PopGuyTr=PopGuyTrim; //PROBLEME exec('Dy...