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// Find the diffusion length // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 2-24 in page 101 clear; clc; close; // Given data C_D=1.5*10^-6; // Diffusion capacitance in F D_p=13; // Constant eta=2; // Constant V_t=0.026; // Voltage at room ...
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function y = dosc(x) y = sin(x) - x^2/2 endfunction //Método de la bisección, toma minimo, maximo, funcion, epsilon y epsilon funcion function med = bisecc(mini,maxi,fun,eps,epsf) if(fun(maxi).*fun(mini) > 0) error('Intervalos del mismo signo'); end; m = ((mini+maxi)/2); while(maxi-m >...
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//Caption:Determine the minimum distance between two end plates //Exa:5.1 clc; clear; close; //Given: a=3;//in cm c=3*10^10;//in cm/s f=10*10^9;//in Hz P_01=2.405; d=%pi/sqrt(f^2*4*%pi^2/c^2-(P_01/a)^2); disp(d,'Minimum distance (in cm) =');
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//laplace// printf("since S2 is the referance stator winding , Es2=KVcos0 \n where Es2 & Er are rms voltages \n') k=1 Theta=60; disp(Theta,"Theta=") V=28; disp(V,"V(applied)=") printf("Es2=V*cos(Theta) \n") Es2=k*V*cos(Theta*(%pi/180)); disp(Es2,"Es2=") printf("Es1=k*V*cos(Theta-120)\n") Es1=k*V*cos((Theta-1...
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clc; clear; s = poly(0, 's'); g = (10*s + 2000) / (s^3 + 202*s^2 + 490*s + 18001); G = syslin('c', g); scf(); show_margins(G, 'bode'); K = 9 * 18001 / 2000; g1 = K*g; G1 = syslin('c', g1); disp(sprintf("The proportional added to get sse of 10%s = %.4f",'%', K)); [gm, fg] = g_margin(G1); [phm, fp] = p_margin(G1); disp(s...
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clc clear A=[-209.443458108676,450.728478793718,0,0,0,0;-450.728478793718,-209.443458108676,0,0,0,0;0,0,-2.25680753735172,467.128469627320,0,0;0,0,-467.128469627320,-2.25680753735172,0,0;0,0,0,0,-0.460680331454473,87.5968670596031;0,0,0,0,-87.5968670596031,-0.460680331454473]; B=[-9.64474367821996,2.65660382188316;-7....
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Exampl_14.8 //Solution : Program to Determine the Phase equlibrium data for the System A12=4.62424; A21=3.35629; alpha12=3.78608; alpha21=1.81775; B11=-996; B22=...
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// Ex 62 Page 403 clc;clear;close; // Given R=150;//ohm Vrms=200;//V Rd1=65;//ohm Rd2=140;//ohm Vm=Vrms/sqrt(2);//V //v=Vm*sin(theta) Rf=R+Rd1;//ohm Rb=R+Rd2;//ohm //i_f=v/Rf;//A //i_b=v/Rb;//A Irms=1/2/%pi*(integrate('(sqrt(2)*sin(theta))**2','theta',0,%pi)+integrate('(sqrt(2)/3*sin(theta))**2','theta',%pi,2*%pi)) ...
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function [] = kiks_draw_remoterobot(id,kx,ky,ang,n,r) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // --------------------------------------------...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.nand2tetris.org // File name: projects/00/Mux8Way16.tst load Mux8Way16.hdl, output-file Mux8Way16.out, compare-to Mux8Way16.cmp, output-list a%X1.4.1 b%X1.4.1 c%X1.4....
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//Example (pg no.136) // x1 + 2(x2) = 3 //2(x1) + 4(x2) = 6 A=[1 2;2 4] //coefficient matrix of above equations b=[3 6]' x=A\b //for corresponding homogenous system // x1 + 2(x2) = 0 //2(x1) + 4(x2) = 0 A=[1 2;2 4] //coeffi...
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// Scilab description of an ARMAX process // Form: // A(q) y(t) = [B(q)/F(q)] u(t-nk) + [C(q)/D(q)] e(t) // [A(q)*F(q)*D(q)] y(t) = [B(q)*D(q)] u(t-nk) + [C(q)*F(q)]e(t) // A1(q) = [A(q)*F(q)*D(q)] // B1(q) = [B(q)*D(q)] // D1(q) = [C(q)*F(q)] function process_ar = armac1(a,b,c,d,f,sig) ny = 1; nu =1; a1 ...
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// Exa 8.9 clc; clear; close; format('v',7) // Given data N = 500; R = 4;// in ohm d_mean = 0.25;// in m a = 700;// in mm^2 a = a * 10^-6;// in m V = 6;// in V miu_r = 550; miu_o = 4*%pi*10^-7; l_i = %pi*d_mean;// in m S = l_i/(miu_o*miu_r*a);// in AT/Wb I = V/R;// in A // Calculation of mmf mmf = N*I...
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//ques6 //isothermal steady state processes clear clc //from table A.2 P1=8;//pressure at state 1 in MPa P2=0.5;//pressure at state 2 in MPa T1=150;//Temperature at state 1 in K Pr1=P1/3.39;//Reduced pressure at state 1 Pr2=P2/3.39;//Reduced pressure at state 2 Tr1=T1/126.2;//Reduced temperature T2=125;//tem...
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// Example 2.2 clc; clear; close; // Given data guagePressure= 1500;// in kN/m^2 atmPressure= 100;// in kN/m^2 P1= guagePressure+atmPressure;// in kN/m^2 V1= 0.1;// in m^3 V2= 0.4;// in m^3 // Formula P1*V1 = P2*V2 P2= P1*V1/V2;// in kN/m^2 NewGuagePressure= P2-atmPressure;// in kN/m^2 disp(NewGuagePressur...
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uo=(4*%pi)*1E-7 ur=1600 lc=160/100 lg=0.8/1000 A=5/10000 N=1200 Rc=lc/(uo*ur*A) Rg=lg/(uo*A) R=Rc+Rg L=N*N/R disp(L)
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//(Springs) Example 10.9 //Diameter of the safety valve dia (mm) dia = 50 //Blow off pressure of the valve Pb (MPa) Pb = 1.5 //Initial compression of the spring delta1 (mm) delta1 = 25 //Maximum lift of the valve l (mm) l = 10 //Spring index C C = 6 //Ultimate tensile strength of the spring Sut (N/mm2) Sut = 1500 //Fo...
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//Load scripts from folder funcprot(0) getd("../scripts"); //Global variables imgPos = "../images/"; //The position of the source images renderPos = "render/"; //The folder where the render images will be saved //Load image imgin = readpbm(imgPos+"Contours.pbm"); imgout = normalisation(contours(imgin)) //Show the c...
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// Example 4.13, Page No-226 clear clc // TF is H(S)= 4/(s^2 + 3.3*s + 0.9) // This is a theorotical problem
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clear /** Somas de riemmann a esquerda * a: limite esquerdo * b: limite direito * n: numero de iteracoes * * S: area apos integrar a funcao */ function S=riemmann(a,b,n) h=(b-a)/n; x=linspace(a,b,n+1); S=0; for i=1:n A=f(x(i))*h; S=S+A; end endfunction // Devolve a integral de...
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clc;funcprot(0);//EXAMPLE 17.42 // Initialisation of Variables Cpw=4.18;..............//Specific heat of water in kJ/kgK n=1;................//No of cylinders N=350;.......//Engine rpm pmi=2.8;..........//Mean effective pressure in bar bl=590;..........//Brake load in N mf=4.3;............//Fuel consumption in k...
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clear all; clc; s_p = 200;//steam pressure in lb/in^2 l = 4;//length in inches b = 4;//breadth in inches p = 14000;//permissible streaa in lb/in^2 P = s_p*l*b;//Pull on each bolt in lb-wt A = P/p ;//necessary area of bolt-section d = sqrt(4*A/%pi) ;//minimum diameter in inches printf('The minimum diameter d of...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.17w //calculation of time taken and position of the arrival on opposite bank //given data dyaxis=.5//displacement(in km) along Y axis vrg=2//velocity(in km/h) of the river with respect to ground vmr=3////velocity(i...
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h=100; t=10; P=0:10:100; N_o=grand(1,10000,"exp",2); S=10^(P/10); for i=1:1:length(S) K=(S(i)*h^2/N_o); X(i)=sum(K<t)/10000; end plot2d("ln",X,S,style=2); plot(X,S);
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//Part (a) r= 0.113; //bond length, nm Mc= 1.99*(10^(-26)); //mass of C12, kg Mo= 2.66*(10^(-26)); //mass of O16, kg Mco= (Mc*Mo)/(Mc+Mo); //mass of CO, kg I= Mco*((r*(10^(-9)))^2); //moment of inertia, kg.m^2 J=1; //lowest rotational state h= 6.63*(10^(-34)); //Planck's constant, J.s hbar= h/(2*(%pi)); //re...
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clc; clear; k=2 lambda=5*10^-5 //wavlength in cm theta=30 //angle in degrees //calculations e=(k*lambda)/sind(theta) //in cm mprintf("No. of lines per centimeter = %.0e",(1/e)) //The answer provided in the textbook is wrong
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a 0.8 #intensite ambiante dans scene d 250 #distance camera image #sources lumineuses #l 400 400 100 0.5 #l -100 -150 -200 0.7 #l 150 -100 500 1.2 l 250 -300 -150 0.7 #l 150 -100 -300 1.2 #l -150 200 -300 0.7 l -150 200 500 1.2
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//to find transfer function using mason gain formula printf("syms R1 R2 C1 C2 \n //gains of forward path\n P1=1/(R1*R2*C1*C2*s^2);//forward path1 gain\n //gain of individual loops\n L1=-1/(R1*C1*s);\n L2=-1/(R2*C1*s);\n L3=-1/(R2*C2*s);\n //gain of two non touching loops\n g1=1/(s^2*R1*R2*C1*C2);\n //since all the l...
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//Variable Declaration Tant=35 //Antenna noise temperature(kelvin) Te1=150 //Receiver noise temperature(kelvin) L=5 //Cable Loss (dB) T0=290 G1=10**5 //LNA Gain F=12 //Receiver Noise figure(dB) //Calculation L=10**(L/10) //Converting L into ratio F=10**(F/10) //Converting F into rati...
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//Moved to it's proper location in Ch 13
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clc(); clear; //To determine the density of free electrons rho=9000; //density in kg/m^3 w=65; //atomic weight v=1; //volume in m^3 n=(rho*v)/(w/(6.022*10^26)); //number of atoms a=1.4; //average numb...
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// Scilab Code Ex11.3: Page-250 (2010) h = 6.626e-034; // Planck's constant, Js k = 1.38e-023; // Boltzmann constant, J/K // Stimulated Emission = Spontaneous Emission <=> exp(h*f/(k*T))-1 = 1 i.e. // f/T = log(2)*k/h = A A = log(2)*k/h; // Frequency per unit temperature, Hz/K printf("\nThe stimulated e...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-14,Example 1,Page 489 //Title: Standard Gibbs free energy change and equilibrium constant //================================================================================================================ clear ...
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//PME3402 - Laboratório de Medição e Controle Discreto / Atividade Aula 2 //Tarefa 2 //Grupo 4 - Integrantes: //Caique de Oliveira Kobayashi - 9793461 //Heitor Fontana de Godoy - 10335677 //Lucas Hattori Costa - 10335847 //Lucas Pinheiro Paiva Cavalcante - 10274270 //Pedro Henrique Pavelski - 10335621 clc clear xdel...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.529298D+00 ...
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//Ex:6.2 clc; clear; close; X_c=3.18; R=100; V_rip=1*(X_c/sqrt(R^2+X_c^2)); printf("Ripple voltage = %f V",V_rip);
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//Part A Chapter 6 Example 3 clc; clear; close; R=8.314/32;//kJ/kgK p1=125;//kPa p2=375;//kPa T1=27+273;//K T2=T1;//K delta_S=-R*log(p2/p1);//kJ/K;//kJ/kgK disp("Change in entropy = "+string(delta_S)+" kJ/K");
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function[x, k] = newton(foncjac, tol, Kmax, x0) if Kmax - floor(Kmax) ~= 0 | Kmax < 0 error('Kmax must be an int'); end if tol < 0 | abs(tol) < %eps error('wrong tol'); end for k = 1:Kmax [f, J] = foncjac(x0); correction = J\-f; x = x0 + correction; ...
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t=(0:0.01:5*%pi)'; tc=(2*%pi)/10; fc=1/tc; k=(squarewave(t)+1)*(1/2); y=k.*cos(2*%pi*fc*t); k1=((-1)*squarewave(t)+1)*(1/2); ta=(2*%pi)/2; fa=1/ta; y1=k1.*cos(2*%pi*fa*t); p=y+y1; plot(t,p);
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clear // // // //Variable declaration Hc=200*10**3 //critical magnetic field(A/m) Tc=12 //critical temperature(K) H0=250*10**3 //critical magnetic field(A/m) //Calculation T=Tc*sqrt(1-(Hc/H0)**2) //maximum critical temperature(K) //Result printf("\n maximum critical temperature is %0.3f K",T)
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// comparing real numbers to infinity %inf==%inf %inf<=%inf 1<=%inf 1>-%inf // using isinf A=[0 %nan 1 %inf 2 -%inf %nan ] A==%inf isinf(A)
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example3_4.sce
clear; clc; // Stoichiometry // Chapter 3 // Material Balances Without Chemical Reaction // Example 3.4 // Page 62 printf("Example 3.4, Page 62 \n \n"); // solution m = 1 //[kg] dry neem leaves (basis) m1 = .01/100 //[kg] beta cartene content of leaves Ex = (m1*100)/.41 //[kg] extract quantity Tc1...
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//By Manas,FOSSEE,IITB //function which designs an iir digital filter using analog filter designs and bilinear transformation . hz=iir(3,'bp','butt',[.15 .25],[0 0]); [hzm,fr]=frmag(hz,256); plot2d(fr',hzm') xtitle('Discrete IIR filter band pass 0.15&lt;fr&lt;0.25 ',' ',' '); q=poly(0,'q'); //to express the result...
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clc; clear all; disp("evaporation rate calculation") U=2.8;// m/s L=300/1000;//m rho=1.205;//kg/m^3 v=15.06*10^(-6);//m^2/s D=4.166*10^(-5);//m^2/s Re=U*L/v;// Reynolds No. Re if Re<5*10^5 disp("flow is laminar") end Sc=v/D;// Schmidt No. Sc Sh=0.664*((Re)^0.5)*(Sc)^(0.33); Sh L=320/1000;//m hm=Sh*D...
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// Exa 1.10 clc; clear; close; // Given data format('v',7) V_CC= 9;// in volt V_EE= 9;// in volt V_BE= 0.7;// in volt (Assuming value) R_C= 47;// in k ohm R_C= R_C*10^3;// in ohm R_E= 43;// in k ohm R_E= R_E*10^3;// in ohm Ri_1= 20;// in ohm Ri_2= Ri_1;// in ohm v_in1= 2.5;// in mv v_in1=v_in1*10^-3;// ...
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//Chemical Engineering Thermodynamics //Chapter 3 //First Law of Thermodynamics //Example 3.11 clear; clc; //Given H1 = 680.6;//Enthalpy of entering steam at 6Kgf/cm^2 &200 deg cel in Kcal/Kg u1 = 60;//velocity at which steam entered the nozzle in m/sec u2 = 600;//velocity at which steam left the nozzle in...
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//To Calculate the Capacitance of the capacitor //Example 31_1 clear; clc; Q=60*10^-6;//Charge on the capacitor V=12;//Potential difference between the plates C=Q/V;//Formula for finding the capacitance of the capacitor printf("Capacitance of the capacitor=%f *10^-6 F",C*10^6);
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// stack representation L=[] // empty stack L=[1,L] // add 1 to the stack L=[2,L] // add 2 to the stack L=[3,L] // add 3 to the stack x=L(1),L(1)=[] // "unstacking" // queue representation F=[] // empty queue F=[F,1] // add 1 to the queue F=[F,2] // add 2 to the queue F=[F,3] // ad...
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//Ex:5.2 clc; clear; close; i=15*10^-3; R=(21-2.2)/i; v=18.8;//in volts P=i*v*1000; printf("Resistor %d ohms of %d mW",R,P);
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clear; clc; rb=75000e3; ro=50e6; v1=11e3; v2=66e3; xa=.25*rb/ro; xb=.75; xt=.1; v=1; xeq=inv(inv(xa)+inv(xb))+xt; i=v/xeq; i=round(i*100)/100; ia=i*xb/(xa+xb); ib=i*xa/(xa+xb); ia=round(ia*100)/100; ilt=rb/(sqrt(3)*v1); iht=rb/(sqrt(3)*v2); i=i*iht; i=fix(i) ia=ia*ilt; ilt=rb/(1.73*v1); ib=ib*ilt;...
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//Chapter 12: Polymers and Polymerization //Problem: 3 clc; //Declaration of Variables d1 = 920 // density,in kg per m cube d2 = 961.97 // density,in kg per m cube dp = 44 // density % // Solution mprintf("dp = [d2 * (p - d1)] * [100/p * (d2 - d1)]\n") ...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.254114D+00 ...
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clc; clear; //Example 3.38 v=23.13*10^-6 ; //[m^2/s] k=0.0321 ; //[W/m.K] Beta=2.68*10^-3; //[K^-1] Tw=443 ;//[K] T_inf=303 ; //[K] dT=Tw-T_inf; //[K] g=9.81 ; //[m/s^2] Npr=0.688; //Prandtl number D=100 ; //Diameter [mm] D=D/1000 //Diameter [m] Nra=(g*Beta*dT*(D^3)*Npr)/(v^2) Nnu=0.53*(Nra...
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//Chapter-1, Example 1.13, Page 25 //============================================================================= clc; clear; //INPUT DATA m=80000;//mass of water lifted by pump in Kg/min g=9.81;//gravity constant in m/sec^2 h=2;//pump is in operation for two hours a day d=30;//pump is in operation for 30 days...
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clear ; clc; // Example 6.1 printf('Example 6.1\n\n'); printf('Page No. 142\n\n'); // given L = 2.5;// Length of tubes in metre Do = 10*10^-3;// Internal diameter of tubes in metre m = 3.46;// mass flow rate in kg/s Th = 120;// Temperature of condening steam in degree celcius Tl_i = 20;// Inlet temperature ...
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//Chapter-3,Example 16,Page 61 clc; close; //Reaction.....U(235) + n(1) ---> Kr(95) + Ba(139) + 2*n(1) + Q m_U= 235.124 // Isotopic mass of Uranium in a.m.u. m_n= 1.0099 // mass of neutron in a.m.u. m_Kr= 94.945 // Isotopic mass of Kripton in a.m.u. m_Ba=138.954 // Isotopic ...
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function[img_ret]=cv_threshold_mean(image,maxValue) pyImport adaptive_threshold img_ret=adaptive_threshold.adaptive_thresh_mean(image,maxValue) endfunction
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// Scilab code Ex5.16: Pg 166 (2008) clc; clear; R_1 = 30; // Resistance, ohm R_2 = 70; // Resistance, ohm R_in = 200; // Internal resistance of meter, ohm V = 12; // Supply voltage, V // Using voltage divide...
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//calculating resistance, reactance and impedance of choke coil I=7.5//current flowing through the circuit V1=110//voltage across non-inductive resistor R=V1/I V2=180//voltage across choke coil Z=V2/I Zt=230/I//impedance of whole circuit r=(Zt^2-R^2-Z^2)/(2*R) Xl=sqrt(Z^2-r^2) mprintf("Reactance of coil=%f o...
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// Grob's Basic Electronics 11e // Chapter No. 03 // Example No. 3_13 clc; clear; // How much current is needed for a 600-W, 120-V toaster? // Given data V = 120; // Applied Voltage=120 Volts P = 600; // Power of toaster=600 Watts I = P/V; disp (I,'The Current I in Amps')
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//Ex5_6 clc Vdc = 15 disp("Vdc = "+string(Vdc)+"V")//applied D.C. voltage //Half Wave Rectifier Vm = %pi*Vdc PIV = Vm disp("Vm = Vdc*pi = "+string(Vm)+"V")//D.C. voltage for half wave rectifier disp("PIV = Vm = "+string(PIV)+"V")//peak inverse voltage for half wave rectifier //Full Wave Rectifier Vm = %pi*Vdc...
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clc clear //Initialization of variables p1=14.7 //psia t1=60 //F p2=60 //psia t2=440 //F m=10 //lb/sec //calculations disp("From mollier charts,") h2=216.3 //Btu/lb h1=124.3 //Btu/lb W21=h2-h1 power=W21*m hp=power*3600/2545 cp=0.237 W212=cp*(t2-t1) power2=W212*m hp2=power2*3600/2545 //results printf...
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//Section-10,Example-3,Page no.-CT.42 //To calculate Entropy change(dl_S). clc; R=8.314 C_v=(3/2)*R C_p=C_v+R n=5 T_1=323 T_2=298 P_2=380 P_1=760 R=8.314 dl_S=n*((C_p*log(T_2/T_1))+(R*log(P_1/P_2))) disp(dl_S,'Entropy change(JK^-1)')
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//Example 10.15 //Fourth Order Runge Kutta Method //Page no. 324 clc;clear;close; deff('y=f(x,y)','y=x^2+y^2') y=1;h=0.1; for i=1:2 x=(i-1)*h K1=h*f(x,y); K2=h*f(x+h/2,y+K1/2); K3=h*f(x+h/2,y+K2/2); K4=h*f(x+h,y+K3); disp(K4,'K4 =',K3,'K3 =',K2,'K2 =',K1,'K1 =') y=y+(K1+2*K2+2*K3+K4)/6 printf('\ny...
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//example3.12 clc disp("R1=0.9 ohm, R2=0.03 ohm, X1=5 ohm, X2=0.13 ohm") disp("K=N2/N1=1/6 as N1:N2 is 6:1") r=0.03+(0.9*(1/6)^2) format(6) disp(r,"Therefore, (R_2e)[in ohm]=R2+R1''=R2+(K^2)*R1=0.03+(1/6)^2*0.9=") x=0.13+(5*(1/6)^2) format(8) disp(x,"(X_2e)[in ohm]=X2+X1''=X2+(K^2)*X1=0.13+(5*(1/6)^2)=") disp...
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script_generalisation.sci
//a function to choose randomly a number nb_config of observations //to remove in the range [1,l] (l being the total number of observations ; i.e., the number of line) //inputs : // - nb_config : number of observations to be removed // - l : total number of observations //outputs : // - idx_config : randomly chosen...
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Ex6_20.sce
//radius of the outer conductor //given clc C=70D-12//F/m Zo=75//ohm L=Zo^2*C//inductance epsilon_r=2.3 a=0.292//mm//radius of inner conductor b=a*10^(Zo*sqrt(epsilon_r)/138)//Zo=(138/sqrt(epsilon_r))*log(b/a) b=round(b*1d+4)/1d+4///rounding off decimals disp(b,'the radius of the outer conductor')
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Q1.sce
clc; clear; rand('seed',0); N = [2,2,1]; x=[0.89, 0.79; 0.85, 0.74; 0.84, 0.72; 1, 1; 0.04, 0.07; 0.03, 0.02; 0.02, 0.01;0.01, 0.01; 0.0086, 0.0053; 0.0061, 0.0026; 0.0044, 0.009; 0.008, 0.0087]'; t=[1 1 1 1 0 0 0 0 0 0 0 0]; disp(size(x)) lp=[0.1, 0]; W=ann_FF_init(N); T=400; W=ann_FF_Std_online(x,t,N,W,lp,...
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//Resistance R, Voltage V close(); clear; clc; R1 = 6;//ohm R2 = 1; R3 = 2; R4 = 3; R5 = 10; V1 = 10;//V V2 = 20; //Solving Nodal equations A = [1/R1+1/R2+1/R3 -1/R3;-1/R3 1/R3+1/R4+1/R5]; C = [V1/R1;V2/R5]; B = inv(A)*C; V3 = B(1,1); V4 = B(2,1); I = (V4-V2)/R5; mprintf('I = %0.2f A',I);
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Ex1_12.sce
clear // //this is a derivation by substitution problem //al1=al0/(1+al0*t1) //al2=al0/(1+al0*t2) //where t1 and t2 are different temperatures al0,al1 and al2 are temperature coefficients //substitute al0 in al2 //on deriving and solving for al2 we get, printf("\n al2=al1/(1+al1*(t1-t2))")
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EXP-1_60002190039_DURVANG_VIJAY_PARAB_plotting_elementary_signals.sce
//Plot various elementary signals in continuous and discrete domain //Unit Step clc; clf; clear all; n=-10:10; x=[ zeros(1,10), ones(1,11) ]; a= gca(); subplot(2,1,1) plot2d3(n,x); title( 'Plot of Discrete Time Unit Step ' ); xlabel( ' n ' ); ylabel( ' u[n] ' ); n1=0:10 x1 = [ones(1,11) ]; a = gca(); su...
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//Section-14,Example-2,Page no.-PC.112 //To calculate the pH in the following cases. clc; V_1=150 //volume of 0.1 NaOH solution V_2=150 //volume of 0.2 HCl solution N_1=0.1 N_2=0.2 V=V_1+V_2 //Total volume of the solution m_eq=(V_2*N_2)-(V_1*N_1) //Total milliequival...
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Example10_1.sce
clear; clc; // Illustration 10.1 // Page: 494 printf('Illustration 10.1 - Page: 494\n\n'); // solution //****Data****// // a:water b:isopropyl ether c:acetic acid xF = 0.30;// [mol fraction] yS = 0;// [mol fraction] S1 = 40;// [kg] B1 = 40;// [kg] //*******// // Equilibrium data at 20 OC: // Wa:...
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clear; clc; z12=complex(.05,.20); z23=complex(.075,.25); c1=.025; c2=.005; w1= (.1568*10^(-4)); w2= (.1679*10^(-4)); w3= (.0668*10^(-4)); w4= (.0702*10^(-4)); W=[w1 0 0 0; 0 w2 0 0; 0 0 w3 0; 0 0 0 w4]; v1=1.05; v2=1.05; v3=(1.05); h1=(v1/z12); h2=(v2/z12); h3=(v2/z23); h4=(v3/z23); H=[h1 0 0 0; 0 h2 ...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.8\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.8 (page no. 329) // Solution //We will take as a basis 100 lbm of mixture. //Dividing colomn 2 by 3 gives us mass/molecular weight or moles of each constituents.The total number of moles...
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//Ex19_13 Pg-962 clc dec=175; //binary input oct=dec2oct(dec) //decimal output disp("The octal equivslent of 175 is") disp(oct)
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errcatch(-1,"stop");mode(2);//Example 5.19, page no-317 e=0.2*10^-3 B=0.08 l=10*10^-2 v=e/(B*l) printf("V = %.3f m/sec = %.2f cm/sec",v,v*100) exit();
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SSCTIE2.sce
fssc=33e3; f0=6e9; a=0.005; favg=f0*(1-0.5*a); t=[0:1e-7:1/(2*fssc)]; foft=favg-2*f0*a*fssc*(t-0.25/fssc); //Triangular thetadelta=f0*a*t/2-f0*a*fssc*(t^2); //Triangular //foft=favg+f0*0.5*a*cos(2*%pi*fssc*t); //Sine //thetadelta=(f0*0.5*a/(2*%pi*fssc))*sin(2*%pi*fssc*t); //Sine tie=thetadelta/...
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function L=mulapproxluck(x,p) [nprobs,nsamps]=size(x); ntrials=sum(x,'r'); mu=p*ntrials; z=(x-mu) ./ sqrt(mu); R2=sum(z.^2,'r'); one=ones(1,nsamps); L=cdfgam("PQ",R2/2,((nprobs-1)/2)*one,one); endfunction
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//Exa 1.25 clc; clear; close; //given data BETAmin=80;//unitless BETAmax=120;//unitless IE=400;//in uA VT=25;//in mvolts VEE=15;//in volts VCC=15;//in volts VBE=0.7;//in volts VEB=-0.7;//in vol IE1=IE/2;//in uA IE2=IE1;//in uA IBmax=IE1/(1+BETAmin);//in uA IBmin=IE1/(1+BETAmax);//in uA Iiomax=IBmax-IBm...
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call -in 2011-07-21 17:39:00 call my.pr1 -in 2 double quoted -in:int 29647 -in 3 single quoted ;
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// *** ESCRIBA EL CODIGO AQUI! ***
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// Given :- T = 373.15 // initial temperature of saturated liquid in kelvin T0 = 293.15 // in kelvin P0 = 1.014 // in bar // Part(a) // From table A-2 ug = 2506.5 ...
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clc; funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100 dms=[d m sd] endfunction b=40.0;//distance in degrees p=6.0;//disatnce in degrees //calculation a=%pi/2-asin(cos(b*%p...
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//Evaluacion LQG Train // load the data clc clear load("maglevtrainLTI.sod","X","U","sys") Ap=sys.A; Bp=sys.B; Cp=sys.C; Dp=sys.D; Dp=0 Cp=[1 0 0] tri = trzeros(sys) w = logspace(-3,3); svi = svplot(sys,w); scf(1); plot2d("ln", w, 20*log(svi')/log(10)) xgrid(12) xtitle("Valores singulares de la plant...
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//Largest eigen value clear; clc; close(); a = [0 0 0; 0 0 0; 0 0 0] for i=1:3 for j=1:3 a(i,j) = input('Enter the values:') end end disp(a,'A = ') //initial vector u0 = [1 1 1]'; disp(u0,'The initial vector is') v = a*u0 a1 = max(u0) disp(a,'First approximation to eigen value is ') whi...
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//Example 2.7.12;//pulse width clc; clear; close; //given data : format('v',5) v=200;//in volts il=100;//latch current in mA l=0.2;//inductance in henry dit=v/l;//in amp/sec dt=(il*10^-3)/dit;//in seconds disp("part (a)") disp(dt*10^6,"minimum pulse width required to turn on the SCR is in micro seconds") r=20;//in ohms...
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x = [10:10:1000]; y = 1.2*x+6; plot(x,y); x = [10:10:1000]; y = -1.2*x+6; plot(x,y);
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clc; // page no 444 // prob no 13_2 //Voice transmisssion occupies 30 kHz.Spread spectrum is used to increase BW to 10MHz B1=30*10^3;//BW is 30 kHz B2=10*10^6;//BW is 10 MHz T=300;//noise temp at i/p PN=-110;//signal has total signal power of -110 dBm at receiver k=1.38*10^-23;//Boltzmann's const in J/K //Dete...
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// Updated(18-7-07) // 11.3 C = [1 0.5]; dC = 1; j=2; A = [1 -0.6 -0.16]; dA = 2; zj = zeros(1,j+1); zj(j+1) = 1; [Fj,dFj,Ej,dEj] = xdync(zj,j,A,dA,C,dC)
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function o=obsv_mat(a,c) [lhs,rhs]=argn(0) select type(a) case 1 then if rhs=1 then error('2 arguments : a,c'),end [m,n]=size(a) if m<>n then error(20,1),end [mb,nb]=size(c);if nb<>n then error(60),end //-compat next case retained for list/tlist compatibility case 15 then if a(1)<>'lss' ...
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// Distance Vector dist = (0.75:0.25:15) //Num. elements dist. vector sz = length(dist) //Width Mona Lisa Painting width = 0.53 //Height Mona Lisa Painting height = 0.77 //Focus lenght f = 0.008 //Dimension of a pixel sp = 0.00000408 //Total pixels width & height sensor wp = 1288 hp = 728 //Loop for each distance for...
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clear; clc; printf("\t\t\tExample Number 6.6\n\n\n"); // turbulent heat transfer in a short tube // illustration6.6 // solution p = 101325;// [Pa] pressure of air Ta = 300;// [K] temperature of air d = 0.02;// [m] diameter of tube u = 40;// [m/s] velocity of air L = 0.1;// [m] length of tube dT = 5;// [...
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 4 // Principles of Fluid Flow // Example 4.2(b) // Page 180 printf("Example 4.2(b), Page 180 \n\n") L = 3 ; //[m] D = 0.01 ; //[m] V = 0.2 ; //[m/s] // (b) V1=0.7; v1 = 1.306 * 10^-6 ; // [m^2/s] printf("(b) If the velocity ...
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clc clear //DATA GIVEN r1=750/2000; //radius of larger pulley in m r2=300/2000; //radius of smaller pulley in m d=1.5; //distance between the centres of pulley in m Tms=14; //maximum safe tension in N/mm b=150; //width of...
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load ALU.hdl, output-file ALU-64cases.out, compare-to ALU-64cases.cmp, output-list x%B1.16.1 y%B1.16.1 zx%B1.1.1 nx%B1.1.1 zy%B1.1.1 ny%B1.1.1 f%B1.1.1 no%B1.1.1 out%B1.16.1 zr%B1.1.1 ng%B1.1.1 ; set x %B1100110011001100, set y %B1010101010101010; set zx 0, set nx 0, set zy 0, set ny 0, set f 0, set no ...
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// Exa 2.24 clc; clear; close; format('v',5) // Given data R1 = 3;// in ohm R2 = 2;// in ohm R3 = 1;// in ohm R4 = 8;// in ohm R5 = 2;// in ohm V = 10;// in V R = ((R1+R2)*R5)/((R1+R2)+R5);// in ohm Rth = R + R3;// in ohm R_L = Rth;// in ohm disp(R_L,"The value of load resistance in ohm is");
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clc; disp("The filter must attenuate the signal by a factor of 10."); //displaying result f=300*10^6; //frequency in Hz disp(" If R = 100 Ohm ,then the reactance of the capacitor should be about 10 Ohm."); //displaying result c=1/(2*(%pi)*f*10); //calculating capacitance disp(c,"At 300 MHz, this is in Farad = ...
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//Example 5_14_u1 clc(); clear; //To calculate the effective temprature of neutrons a=0.352 //units in nm h=1 k=1 l=1 d=a/sqrt(h^2+k^2+l^2) //units in nm theta=28.5 //units in degrees lamda=2*d*sin(theta*(%pi/180)) //units in nm h=6.63*10^-34 //units in m^2 kg s^-1 m=1.67*10...
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//EXAMPLE 2.94 PG NO-139-140 L=0.6; //LENGTH a=20*10^-4; //AREA MU=(4*%pi*10^-7); R=L/(MU*a); N1=1500; N2=500; i=250; M=(N1*N2)/R; e=M*(i); disp('R = '+string(R)+' '); disp('mutual induction is = '+string(M)+' H'); disp('E.M.F INDUCE is = '+string(e)+' V');