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//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) then v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution10_9.sce') //Obtain path of data file datapath = path +...
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exec("alaqiltest.start", -1); exec("alaqiltest.quit", -1);
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clc; //Example 13.2 //page no 137 printf(" Example 13.2 page no 137\n\n"); //refer to part a of example 1 //appplying Hagen-Poiseuille equation meu=6.72e-4//viscosity of water v=0.13//velocity of water D=2.067/12//diameter of pipe P_l=32*meu*v/(D^2) printf("\n pressure drop per unit length P_l=%f psf/ft",P_l)...
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// Exa 6.10 clc; clear; close; // Given data I_DSS = 4;// in mA I_DSS= I_DSS*10^-3;// in A V_P = -4;// in V V_GG = -2;// in V V_GS = V_GG;// in V disp(V_GS,"The value of V_GS in V is"); I_D = I_DSS*(1-(V_GS/V_P))^2;// in A disp(I_D*10^3,"The value of I_D in mA is"); V_DD = 10;// in V R_D = 5;// in kohm R...
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function wpar=do_setup(wpar) wd=wpar(1);w=wd(1);h=wd(2); nm=wpar(2) tolerances=wpar(3); if tolerances==[]|tf==[]|sim_mode==[] then //super block while %t do [ok,nm,h,w]=getvalue('Set parameters',[ 'Super block name'; 'Window height'; 'Window width'],list('str',1,'vec',1,'vec',1),[nm;string([h;w])]) if ~ok ...
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//Scilab Code for Example 5.9(iii) of Signals and systems by //P.Ramakrishna Rao clc; clear; q=0; a1=0.5 a2=-0.5; n=1:101; x1=a1^n; x2=a2^n; w=2; n=0:100; z=(exp(-%i*w*n)); for n=0:33; X(n+1)=z(n+1)*x1(n+1)*cos(0.4*%pi*n); q=X(n+1)+q; end disp(q,'Y3(e^2j) at a=0.5'); for n=0:33; X(n+1)=z(...
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//Electric Power Generation, Transmission and Distribution by S.N.Singh //Publisher:PHI Learning Private Limited //Year: 2012 ; Edition - 2 //Example 15.2 //Scilab Version : 6.0.0 ; OS : Windows clc; clear; r=1.5; //Conductor radius in cm R=3; ...
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// Ex9_8 clc; // Given: a1=0.015; a2=0.04; // Solution: Defining the seperation factor f as approximately equal to (a2/a1) where a1, a2 are the relative abundances of the isotope of interest in the initial and final fractions, we have f=(a2/a1); printf("The single stage seperation factor is = %f",f) ...
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//Example number 7.1, Page number 146 clc;clear; close; //Variable declaration epsilonr=3.75; //relative dielectric constant T=27; //temperature(C) gama=1/3; //internal field constant rho=2050; //density(kg/m**3) Ma=32; //atomic weight(amu) Na=6.022*10**23; //avagadro number epsilon0=8.85*...
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s=%s F=s^6+3*s^5+4*s^4+6*s^3+5*s^2+3*s+2 disp(routh_t(F)) r=coeff(F) routh=routh_t(F) n=length(r) c=0; for i=1:n if (routh(i,1)<0) c=c+1; end end if(c>=1) printf("system is unstable") else printf("there are no roots on RHS") end disp("s^2 is") R=roots(routh(3,:)) disp(R) disp("as...
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//computation of N point dft clear clc close x = input("Enter sequence x(n): ") N = input("Enter no.of points of DFT: ") //dft by calculation n = 0:N-1; k = n; WN = exp(-%i*(2*%pi)/N) kn = k'*n W = WN .^ kn X = W * x' disp("DFT (calculation): ",X) /*X1 = x * exp(-%i*2*%pi.*k'*n/N) disp("DFT (calculation): ",X1)*...
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clc //calc the height to which liq in a cylinder rises when rotated f=78/60;//rps r=0.15;//m g=9.81;//m/s^2 //omega=2*(%pi)*f z=[(2*(%pi)*f)^2]*r^2/2/g;//m disp("The liquid in the cylinder rises to a height of") disp(z) disp("m")
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load PriorityEncoder83.hdl, output-file PriorityEncoder83.out, compare-to PriorityEncoder83.cmp, output-list d%B1.8.1 o%B1.3.1; set d %B00000001, eval, output; set d %B00000010, eval, output; set d %B00000100, eval, output; set d %B00001000, eval, output; set d %B00010000, eval, output; s...
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load Decoder.hdl, output-file Decoder.out, compare-to Decoder.cmp, output-list time%S1.4.1 in%D1.3.1 field%D1.3.1 row%D1.3.1 quote%D1.3.1 esc%D1.3.1 load%B1.1.1 reset%B1.1.1 out%D1.3.1 c%B1.1.1 f%B1.1.1 r%B1.1.1; set field 44, set row 10, set quote 34, set esc 92, set load 1, set in 97, tick, eval, output; tock; set...
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// chapter 14 // example 14.4 // fig. 14.13 // Determine motor torque, speed of the motor, supply power factor, firing angle and power fed back to the supply // page-865-866 clear; clc; // given HP=10; // in HP (power of motor) E=210; // in V N=1000; // in rpm (speed) Ia=30; // in A (armature current) Ra=0.25; // in oh...
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//example5.4 //Shunt circuit feedback configuration//given R1=10000;//in ohms R2=2000;//in ohms Rc1=5000;//in ohms hie=1000;//in ohms hfe=100; //unloaded feedback fraction B1 B1=R2/(R1+R2); disp('open loop forward current amplification A1=io/i'); iia=1;//let disp('ib=input-current coupling factor*iia'); disp('ib=(R1+...
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//clear// //Caption:Channel Capacity of a Binary Symmetric Channel //Example2.6:Channel Capacity of Binary Symmetri Channel clear; close; clc; p = 0:0.01:0.5; for i =1:length(p) if(i~=1) C(i) = 1+p(i)*log2(p(i))+(1-p(i))*log2((1-p(i))); elseif(i==1) C(i) =1; elseif(i==length(p)) C(i)=0; ...
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//Chapter-4,Example4_2,pg 4-24 E1rms=10 E2rms=15 E1m=E1rms*sqrt(2) E2m=E2rms*sqrt(2) //voltage across AB is proportional to E1+E2 in positive half cycle Ep=(1/(2*%pi))*(2*E1m+E2m)//output in positive half cycle //voltage across AB is proportional to E1-E2 in negative half cycle En=(1/(2*%pi))*(2*E1m-E2m)//outpu...
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//sampling frequency is passed as an i/p arg R=[6.1117 + 0.0000*%i 3.8205 - 3.9887*%i -0.2138 - 5.5126*%i 3.8205 + 3.9887*%i 6.0796 + 0.0000*%i 3.8205 - 3.9887*%i -0.2138 + 5.5126*%i 3.8205 + 3.9887*%i 6.1117 + 0.0000*%i]; Fs=200; [F, POW]= rootmusic(R,2,Fs); disp(F); disp(POW); //output // 63.273966...
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//Eg-9.2 //pg-387 clear clc //zeros of T3(x) n=3; for i=1:3 lambda(i)=cosd((2*i-1)*180/(2*n)); end disp("zeros of T3(x)") disp(lambda)
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// Ex12_6 Page:248 (2014) clc; clear; e = 1.6e-019; // Charge on an electron, C n = 5e+028; // Number of atoms per unit volume of Cu, per metre-cube R_H = -1/(n*e); // Hall coefficient, metre-cube/C printf("\nThe Hall coefficient for Cu = %4.2e metre-cube/C", R_H); // Result // The Hall coefficient for Cu = ...
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clc N=60; //rpm r2=0.25; //m g=9.8; //m/s^2 w=2*%pi*N/60; dz_12=(w*r2)^2/2/g; // dz_12=z2-z1 c=w*r2^2; dz_23=c^2/2/g/r2^2;// dz_23=z3-z2 dz_13=dz_23+dz_12; disp("Total depression =") disp(dz_13) disp("m")
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res = mopen ('E:\SciLabProg\ЧМ\Newton.csv', 'wt'); eps = 10^-9; i = 0; x1 = 0; x2 = 0; y1 = 1; y2 = 0; f1 = x1*x1 - x2 + 1; f2 = x1 - cos(%pi*x2/2); mfprintf (res, 'I, X1, X2, F1, F2\n'); mfprintf (res, '%d, %f, %f, %f, %f\n', i, y1, y2, f1, f2); while ( sqrt( (y1 - x1)^2 + (y2 - x2)^2 ) >= eps ) x1 = y1; x2 =...
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//input of lossless transmission line //given clc Zo=50//ohms Zl=%inf//defined as infinity Bl=2*%pi*0.1 Zi=(Zo*(1+%i*(Zo/Zl)*tan(Bl))/(Zo/Zl+%i*tan(Bl)))//taking Zl common from numerrator and denominator Zi=round(Zi*100)/100///rounding off decimals disp(Zi,'the input of 50ohm lossless transmission line')//ohm
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//Given that M_P = 31.97391 //in u M_S = 31.97207 //in u uCsqure = 931.5 //in Mev //Sample Problem 43-7 txt = mopen('Example43_7_result.txt','wt') mfprintf(txt, '**Sample Problem 43-7**\n') Q = -(M_S - M_P)*uCsqure mfprintf(txt, 'The disintegration energy for the beta decay of Phosphorus is %fMev', Q) mclo...
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A [A] ah sil ANY [ANY] eh n iy sil BOY [BOY] b oy sil BY [BY] b ay sil CAME [CAME] k ey m sil CAT [CAT] k ae t sil CHAIR [CHAIR] ch eh r sil DOG [DOG] ...
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@relation unknow @attribute mcg real[0.11,1.0] @attribute gvh real[0.13,1.0] @attribute alm real[0.21,1.0] @attribute mit real[0.0,1.0] @attribute erl real[0.5,1.0] @attribute pox real[0.0,0.83] @attribute vac real[0.0,0.73] @attribute nuc real[0.0,1.0] @attribute class{MIT,NUC,CYT,ME1,ME2,ME3,EXC,VAC,POX,ERL} @inputs...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/01/Or16Way.tst load Or16Way.hdl, output-file Or16Way.out, compare-to Or16Way.cmp, output-list in%B1.16.1 out%B2.1.2; set in %B0...
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//example 11.10 clc; funcprot(0); Hp=350; vp=0.0016; Sl=0.762e-3; f=115; Qu=(0.746*Hp+98*vp)/(vp+Sl*f); disp(Qu,"ple load capacity in kN");
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clc clear //INPUT DATA Rc=15;//compression ratio r1=1.84;//cutoff ratio r2=1.98;//cutoff ratio g=1.4;//constant p1=101.325;//Pressure in kN/m^2 Rc3=17;//compression ratio r3=1.84;//cutoff ratio Rc4=18;//compression ratio r4=1.88;//cutoff ratio //CALCULATIONS nd1=(1-(((1/(Rc^(g-1))))*(((r1^g)-1)/((r1-1)*g...
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//Exa 4.9 clc; clear; close; //Given data : r=4/2;//cm rdash=0.7788*r;//cm d=300;//cm d3=6*100;//cm LA=0.2*[log(d/rdash)+1/2*log(2)-%i*0.866*log(2)];//mH disp(LA,"Inductance per km of phase1(mH)"); LB=0.2*log(d/rdash);//mH disp(LB,"Inductance per km of phase2(mH)"); LC=0.2*[log(d/rdash)+1/2*log(2)+%i*0.866...
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//Chapter-2 example 2.5 //============================================================================= clc; clear; Vo=3*10^8;//velocity in m/s Pt=1*10^6;//peak power in watts PW=1.2*10^-6;//pulse width in sec PRI=1*10^-3;//pulse repetition interval in sec //Calculations PRF=1/PRI;//pulse repetition frequency ...
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clc //initialisation of variables w=0.95//kg=m h=3206*10//kg-m G=2250//kg k=0.4//mm r=45000//mm //CALCULATIONS n=(1/((G/r)+1))*(1-(k^2))//kg-m Wn=h*n//kg-m //RESULTS printf('the efficincy of the hammer through=% f kg-m',Wn)
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f=10^6:10^7:10^10; rs=(4.8*10^-6).*sqrt(f); re=(33.9*10^12) ./f; c=47*10^-12; w=2*%pi.*f; l=2*1.25*10^-2; a=2.032*10^-4; temp=log(2*1/a)/log(%e); lex=mu0*l*(temp-1)/(2*%pi); z=1 ./(1 ./re +w*c*%i)+rs+w.*lex*%i; zideal=1 ./(w*c*%i) plot2d("gll",f,abs(z)); plot2d(f,abs(zideal)); title("Frequency response of ...
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// Test # 4 : Input Argument #1 is of complex type exec('./allpassshift.sci',-1); [n,d]=allpassshift(%i,0.6); //!--error 10000 //Wo must be real ,numeric and scalar //at line 33 of function allpassshift called by : //[n,d]=allpassshift(%i,0.6);
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//Chapter 4: Radiation //Example 4-5.2 clc; //Variable Initialization L = 5 //Length of radiating element (m) f1 = 30e3 //Frequency (Hz) f2 = 30e6 //Frequency (Hz) f3 = 15e6 //Frequency (Hz) c = 3e8 //Velocity of light (m/s) //Calculation wave_lt1 = c/f1 //Wavelength (m...
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clear; clc; disp("--------------Example 10.22---------------") // at the sender n1=7; n2=11; n3=12; n4=0; n5=6; s_sum=n1+n2+n3+n4+n5; // find the sum s_bin=dec2bin(s_sum); s=strsplit(s_bin,length(s_bin)-4); a=bin2dec(s(1)); b=bin2dec(s(2)); f=a+b; // wrapping the sum s_checksum=bitcmp(f,4); // compleme...
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clc; close(); //page no 231 //prob no. 7.7 delta_theta=6; //kHz fm=5; //kHz disp('The expression is'); mprintf('v(t)=A*cos[(2*pi*10^8*t)+%i*sin(%i*2*pi*10^3*t)]',delta_theta,fm);
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//pathname=get_absolute_file_path('7.12.sce') //filename=pathname+filesep()+'7.12-data.sci' //exec(filename) //Enthalpy at entrance(in kJ/kg): h1=4142 //Enthalpy at exit(in kJ/kg): h2=2585 //Availability of steam at entrance(in kJ/kg): A1=1787 //Availability of steam at exit(in kJ): A2=140 //Maximum work pos...
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clear //Given l=0.05 //m d=0.12 //m H=0.34*10**-4 //T //Calculation // u=4*%pi*10**-7 M=(4*%pi*H*(d**2+l**2)**1.5)/u //Result printf("\n Magnetic moment of the magnet is %0.3f J/T",M)
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// Exa 1.13 clc; clear; close; // Given data Bita_ac= 100; Bita_dc= Bita_ac; V_BE=0.715;// in volt V_D1= V_BE; R3=2.7*10^3;// in ohm R_C=4.7*10^3;// in ohm V_EE=10;//in volt V_CC= 10;// in volt V_Z= 6.2;// in volt I_ZT= 41;// in mA I_ZT=I_ZT*10^-3;// in amp V_B3= -V_EE+V_Z+V_D1;// in volt V_E3= V_B3-V_...
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//Problem 28.08: An R–L–C series circuit has a resonant frequency of 1.2 kHz and a Q-factor at resonance of 30. If the impedance of the circuit at resonance is 50 ohm determine the values of (a) the inductance, and (b) the capacitance. Find also (c) the bandwidth, (d) the lower and upper half-power frequencies and (e)...
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function A=Questao_1(autovalores) //pegando o tamanho do vetor n=length(autovalores) // criando uma matriz aleatória V=rand(n,n) //criando e motando a A A =zeros(n,n) for i =1:n A(i,i)=autovalores(i) end //deixando a V simétrica V= (V + V')*0.5; ...
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// exa 4.16 Pg 122 clc;clear;close; // Given Data Pmin=-15;// kN Pmax=25;// kN Se_dash=360;// MPa Sy=400;// MPa Ki=1.25;// impact factor n=2.25;// factor of safety ka=0.88;// surface finish factor Kt=2.25;// stress concentration factor Pm=(Pmax+Pmin)/2;// kN Pa=(Pmax-Pmin)/2;// kN q=0.8;// sensitivity factor // sigma...
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clc function y=taylor(x0,x,n) y=%e^x0; for i=1:n; y=y+((%e^x0)*(x-x0)^i)/factorial(i) end endfunction
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 5 // Heat Transfer by Forced Convection // Example 5.1(a) // Page 209 printf("Example 5.1(a) \n\n") D = 0.015 ; // [m] Q = 0.05 ; // [m^3/h] H = 1000 ; // [W/m^2] T_b = 40 ; // [degree C] // From table A.1, properties at 40 degr...
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clear; function [dydx]=der(y,x) n=size(y) dydx=diff(y,1) h=(max(x)-min(x))/size(x,1) endfunction hawaii=read('hawaii_melt_clap_impedance.dat',-1,3) melt_hawaii=hawaii(:,1) clap_hawaii=hawaii(:,2) eta_hawaii=(hawaii(:,3)) n_hawaii=size(melt_hawaii,1) m_hawaii=sqrt(n_hawaii) dmeltdv_hawaii=zeros(m_hawaii,m_...
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clear // // // //Variable declaration a=0.26 //lattice spacing(nm) lamda=0.065 //wavelength of X-rays(nm) h=1 k=1 l=0 n=2 //Calculation d=a/sqrt(h**2+k**2+l**2) sintheta=n*lamda/(2*d) theta=asin(sintheta)*180/%pi //glancing angle(degrees) thetad=int(theta) ...
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//Dalton's Law of Partial Pressures clear; clc; printf("\t Example 5.14\n"); nNe=4.46;//moles of Ne nXe=2.15;//moles of Xe nAr=0.74;//moles of Ar PT=2;//total pressure in atm XNe=nNe/(nNe+nAr+nXe);//mole fraction of Ne XAr=nAr/(nNe+nAr+nXe);//mole fraction of Ar XXe=nXe/(nNe+nAr+nXe);//mole fraction of ...
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exec("sinusoidal_vector.sci",-1) exec("normalnoisevec.sci",-1) function[yvec]=signalnoise(a,N,Variance) xvec=sinusoidalvec(a,N) vvec=gaussiannoise(Variance,N) //disp(length(xvec)) //disp(length(vvec)) yvec=xvec+vvec endfunction
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clear; clc; // Illustration 1.23 // Page: 62 printf('Illustration 1.23 - Page:62 \n\n'); // Solution //*****Data*****// // A-beta dextrin B-water T = 293; // [K] d = 88.8; // [Average pore diameter, Angstrom] d_mol = 17.96; // [Molecular diameter, Angstrom] e = 0.0233; // [porosity] t = 1.1; // [tor...
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function y=mtlb_diff(x,N) [lhs,rhs]=argn() if rhs==1 then N=1,end if or(size(x)==1) then y=x(1+N:$)-x(1:$-N) else y=x(1+N:$,:)-x(1:$-N,:) end
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2_a: (a^2 + b^2)^2 = (a^2 - 17*b^2)^2 + (2*a*b)^2 2_b: (a^2 + b^2)^2 = (a^2 + 17*b^2)^2 + (0)^2 2_c: 1 - 17; 2; 2_d: 1 + 17; 0; 3_a: (a^2 + b^2)^3 = (a^3 - 51*a*b^2)^2 + (3*a^2*b - 17*b^3)^2 3_b: (a^2 + b^2)^3 = (a^3 + 17*a*b^2)^2 + ( - a^2*b - 17*b^3)^2 3_c: 1 - 51; 3 - 17; 3_d: 1...
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//Find (a) the overall voltage-gain ratio //Av ¼ vL=vS and (b) the overall current-gain ratio Ai ¼ iL=iS. //Example 6.27 page no 194 clear clc hfb1=-0.99 hfc2=-100 Rb=33.3*10^3 Re1=5*10^3 Re2=2*10^3 Rl=2*10^3 hic2=500 hib1=50 hic2=500 Av1=-((hfb1*Rb*hic2)/(hib1*(Rb+hic2))) Av2=0.995 Av=Av1*Av2 printf("...
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testxgridlegend.sce
exec('testplot.sce',-1) // add a title xtitle(' figure title') // add a green (=3) coordinate grid xgrid(3) // add a legend in the upper-right corner (2) with a box (1) surrounding it legend('circle','tangent','normal',2,1); // add a legend in the lower-right corner (4) without a box (0) legends(['circle','tange...
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183ex1.sce
//spiral spring example clc; clear; close; clf(); weight=linspace(0,0.5,6); extension=[0 0.15 0.3 0.44 0.6 0.75]; plot2d(weight,extension,13); xtitle("spiral spring example","vaues of L","values of E"); xgrid(); //Extension varies directly as the attached load //let E=Extension,L=Load //to find 'k',a pair ...
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// Example 3.25, page no-156 clear clc Vo=3 Vi=10*10^-3 R2=1*10^6 Av=300 fL=100 RL=15*10^3 R3=R2/(Av-1) R1=R2-R3 C2=1/(2*%pi*fL*R3) C2=C2*10^6 printf('\nC2= %.2f uF',C2) C3=1/(2*%pi*fL*RL/10) C3=C3*10^6 printf('\nC3= %.2f uF',C3)
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11_12.sce
clear clc //initialisation of variables sl= 12 //ft l= 20 //ft d= 4 //in dp= 6 //in lst= 18 //in k= 0.025 H= 32 //ft g= 32.2 //ft/sec^2 pf= 6 //ft a= 33.83 a1= 9.53 //CALCULATIONS A= sqrt((H-sl-d)*g/a)*a1 Q= 2*%pi*(dp/12)^2*lst/(12*4*60) v= Q/(%pi*(d/12)^2/4) kh= v^2/(2*g) fh= k*l*v^2*12/(2*g*d) N=...
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clc(); clear; //Given : sigma = 4*10^-4; // conductivity at room temperature in ohm^-1 m^-1 M = 28.1; // atomic weight in kg/kmole d = 2330; // density in kg/m^3 dop = 10^8 ;// doping per 10^8 silicon atoms e = 1.6*10^-19; // charge of an electron in C mue = 0.135; // mobility of free electrons for silicon in m...
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# Nanotrav Version #0.12, Release date 2003/12/31 # nanotrav/nanotrav -p 1 -trav -image part -autodyn -automethod sifting -drop -scc -shortpaths bellman ./nanotrav/s382.blif # CUDD Version 3.0.0 **************READING IN NETWORK*************** Number of inputs: 1 **************GENERATING NETWORK BDD***************...
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pe4_15.sce
//example 4.15 clc; funcprot(0); // Initialization of Variable R=8//resistance Ts=35//temperature Ta=150//temperature Vm=42//voltage //calcuation Vp=Vm-5; Vr=Vp/2^.5; Pm=Vr^2/R; disp(Pm,"power delivered in watt:") P=45; Qs=(Ta-Ts)/P-1.2; disp(round(Qs*10)/10,"thermal resistance in degreeC/W") clear()
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inter_draw_expan.sci
// to show expansion curve of organs xdel(winsid()); Val_exp=zeros(t_ex,1); s=0; for i = 1 : t_ex Val_exp(i)= ((i-0.5) / t_ex) ^ ( b_exn - 1) * (1 - (i-0.5) / t_ex ) ^ (b_exp- 1) * (1 / t_ex); // s = s+ Val_exp(i); end; s = max(Val_exp); for i=1:t_ex Val_exp(i) = Val_exp(i)/s; end; i=1:t_ex;...
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clear all; clc; disp("Scilab Code Ex 10.6 : ") //Given: ep_x = -300;//(*10^-6) Normal Strain ep_y = -100; //*(10^-6) Normal Strain gamma_xy = 100; //*(10^-6) Shear Strain theta = 20; //degrees //Construction of the circle: strain_avg = (ep_x+ ep_y)/2; tou = gamma_xy/2; R = sqrt((-ep_x + strain_avg)^2 ...
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array <int> finalSeq[432] = {7,14,26,24,33,38,29,29,27,20,30,12,72,55,30,30,14,61,46,42,42,63,11,11,12,20,59,70,28,9,63,56,55,42,2,69,16,41,22,64,16,42,17,68,63,6,6,32,21,53,8,8,21,64,38,38,48,47,42,56,50,50,62,21,5,29,69,35,23,59,62,48,48,11,11,54,50,57,4,58,58,48,49,62,13,13,32,32,17,15,65,65,25,13,9,50,23,67,53,53,4...
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Ex1_24.txt
//Ex:1.24 clc; clear; close; Er=15;// relative permittivity ur=5;// relative mobility B=1/sqrt(Er*ur); A=3*10^8;// the value of 1/sqrt(Eo*uo) V=A*B;// velocity of propagation in volt printf("The field strength = %f*10^7 m/s", V/10^7);
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calcula_pesos_quadratura.sce
clear /** * Para encontrar pesos wi (ou Ai) da quadratura * I = w1*f(x1) + ... + wn*f(xn) com o menor error possivel * * vetor_nodes: vetor x de nos * lim_inicial: limite inicial da integral * lim_final: limite final da integral * * w: vetor de pesos (retorno) */ function w=pesos(vetor_nodes, lim_inicial, lim...
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//To find teeth, angle and ratio clc //Given: phi=20 //degrees m=6, addendum=1*m //mm t=17, T=49 //Solution: //Number of pairs of teeth in contact: //Calculating the pitch circle radius of pinion r=m*t/2 //mm //Calculating the pitch circle radius of gear R=m*T/2 //mm //Calculating the radius of addendum cir...
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// @ts-ignore import * as enums from '../enums'; ${ Template(Settings settings) { settings.IncludeProject("ChoreStorefront"); } // =================================== SHARED LOGIC -- PLEASE KEEP IN SYNC WITH typewriter-definitions.tst and typewriter-controllers.tst and typewrite...
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//Example 4.9 //at what temp. does the water leave the pipe. //Given T1=28 //C, inlet temp. T2=250 //C,bulk temp. V=10 //m/s, gas velocity l=20 //m, length of pipe mw=1*3600 //kg/h, water flow rate di=4.1*10^-2 //m, inlet diameter Tm=(T1+T2)/...
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clear //Given ra=60 rb=45.0 a=40.0 //Calculation ia1=(ra**2)/(rb**2) ia=(ra**2)/(a**2) i=ia-ia1 A=(i*100)/ia //Result printf("\n percentage of light is absorbed by the glass is %0.0f percentage",A)
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clc; clear; delp=4*10^14 //excess EHP in cm^-3 deln=4*10^14 //excess EHP in cm^-3 n0=10^15 //donor atoms in cm^-3 p0=0 //in cm^-3 t=0.5*10^-6 //hole-lifetime in s myu_n=1200 //mobility of electron in cm^2/V*s myu_p=400 //mobility of hole in cm^2/V*s q=1.6*10^-19 //electron charge in eV ni=1.5*10^10 //in cm^-3...
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function t=acos(x) // Element wise Arccosine Cosine-inverse // Entries of vector x must be in [-1, 1] // Entries of T are in ] 0,pi[ x ]-inf +inf[ // [0] x [0,+inf] et [pi] x ]-inf,0] (real x imag) //! if type(x)<>1 then error(53),end if x==[] then t=[],return,end t=-%i*log(x+%i*sqrt(ones(x)-x.*x)...
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Ex9_25.sce
clear //Given m=1.2*10**-3 B=0.6 //T g=9.8 //m/s**2 r=0.05 b=3.8 //Calculation I=(m*g)/B R=r*b V=I*R //Result printf("\n Potentila difference is %0.1f *10**-3 V",V*10**3)
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//============================================================================ // chapter 10 example 1 clc; clear; // Variable declaration E2 = 5.56*10^-19; // Higher Energy level in J E1 = 2.36*10^-19; // Lower Energy level in J h = 6.626*10^-34; // plancks constant...
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x = 0:0.1:6*pi; plot2d(x,[sin(x)' cos(x)']);
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function y =t0(x) y = -481 +408 +589.64 * x + (-2349.163 * x^2)/2 endfunction a = 0 b = 0.3 x= a contador = 0 while(1) xOld = x; x= abs(a - (t0(a)*(b-a))/(t0(b)-t0(a))); Er = abs((x-xOld)/x) contador = contador +1 if (Er < 10^-3) then break end if(t0(a)*t0(x) ...
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//3-VARIABLE KMAP //this function returns the a string containing the minimized expression for the given 3 variable kmap //this function requires //noof.sci //noof0.sci function bi = kmap3(k) n=4; m=2 k(:,:,2)=zeros(m,n); var=['Cn' 'Bn' 'An']; p1=['Cn''' 'Cn']; p2=['Bn''An''';'Bn''An';'...
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@relation vehicle @attribute Compactness integer[73,119] @attribute Circularity integer[33,59] @attribute Distance_circularity integer[40,112] @attribute Radius_ratio integer[104,333] @attribute Praxis_aspect_ratio integer[47,138] @attribute Max_length_aspect_ratio integer[2,55] @attribute Scatter_ratio integer[112,26...
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mass=100 //g of CO2 M=44.01 //molecular weight
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//Chapter 9 Ionic Equilibria and Buffer Action clc; clear; //Initialisation of Variables K= 1.4*10**-5 T= 25 //C V= 200 //ml m= 3.7 //gms m1= 4.8 //gms M= 74 //gms M1= 96 //gms //CALCULATIONS x= m*1000/(V*M) y= m1*1000/(V*M1) X= K*x/y //RESULTS mprintf("hydronium-ion concentration = %.2e mole per litre",X)
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function [PXX, FREQ] = cpsd(X, Y, varargin) //This function estimates cross power spectrum of data x and y by the Welch (1967) periodogram/FFT method. //Calling Sequence //[PXX, FREQ] = cpsd(X, Y) //[...] = cpsd(X, Y, WINDOW) //[...] = cpsd(X, Y, WINDOW, OVERLAP) //[...] = cpsd(X, Y, WINDOW, OVERLAP, NFFT) //[...] = c...
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//Chapter 21: Antenna Measurements //Example 21-4.2 clc; //Variable Initialization pat_lev1 = -22.3 //Pattern level maximum (dB) pat_lev2 = -23.7 //Pattern level minimum (dB) //Calculations S = abs(pat_lev2-pat_lev1) //Amplitude ripple (dB) a = (pat_lev1+pat_lev2)/2 //Pattern level (dB) R = a + 20*log10((10...
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//Example 10_7 clc(); clear; //To find out the final pressure in the drum p1=1 //Units in atm t2=333 //units in K t1=293 //units in K p2=p1*(t2/t1) //units in atm printf("The final pressure in the drum is P2=%.2f atm",p2)
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// Long division of problems discussed in Example 4.32 on page 102 // 4.11 exec('tf.sci',-1); exec('label.sci',-1); num = [11 -15 6]; den = convol([1 -2], convol([1 -1],[1 -1])); u = [1 zeros(1,4)]; y = filter(num,den,u); G = tf(num,den,-1); u1=zeros(1,90); u1(1)=1; x1=dsimul(tf2ss(G),u1); plot2d(x1) la...
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//Ex19_17 Pg-963 clc //Integer part bin='1011'; //binary input dec_I=bin2dec(bin) //decimal output oct_I=dec2oct(dec_I) //octal output //Decimal part bin='11010'; //binary input dec_D=bin2dec(bin) //decimal output oct_D=dec2oct(dec_D) //octal output oct=oct_I + oct_D //final octal output b = strcat([ oct...
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//Exa 2.27 clc; clear; close; format('v',8); //Given Data : Q1_2=85;//KJ Q2_3=-90;//KJ W2_3=-20;//KJ Q3_1=0;//Adiabatic process W1_2=0;//constant volume process //integrate(dQ)=integrate(dW) W3_1=Q1_2+Q2_3+Q3_1-W1_2-W2_3;//KJ disp(W3_1,"Direction is 3-1 and work in KJ : ");
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//Sa se rezolve ecuatiile polinomiale c=[-9,-9,20,2,-5,-1,2] p=poly(c,'x','coeff') x=roots(p)
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function [] = saveSimulationResults(saveDirectory, simu_index) dt = getdate(); backupDirectory = sprintf('%s/%s_%i%.2i%.2i/', saveDirectory, SimulationName, dt(1),dt(2),dt(6)); logFileName = sprintf('%s_%i_%i%.2i%.2i_%2i%2i%2i', SimulationName, simu_index, dt(1),dt(2),dt(6), dt(7), dt(8), dt(9)); mkdir(backupDirec...
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// Exa 2.13 clc; clear; close; format('v',6) // Given data Vdc = 50;// in V Vrms = 5;// in V // The ripple factor, Gamma = Vrms/Vdc; disp(Gamma,"The ripple factor is");
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//Example 8.17 //Determine the DFT of the following sequence clc; x=[0,0,1,1,1,1,1,0,0,0]; X=fft(x,-1); disp(X,'X[k]=');
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clear; clc; // Example: 1.8 // Page: 11 // Solution printf("Example: 1.8 - Page: 11\n\n"); //*****Data*****// g = 9.81;// [m/square s] Z = 100;//[m] //***************// // Basis: 1 kg of water m = 1;// [kg] Ep = m*g*Z;// [J] printf("Change in potential Energy is %d J\n",Ep)
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//Ex3_4 //refer fig3.2(a) clc VCC=20 disp("VCC = "+string(VCC)+" volts") // collector supply voltage VBB=VCC RL=5*(10^3) disp("RL= "+string(RL)+ " ohm") //resistance RB=965*(10^3) disp("RB = "+string(RB)+ " ohm") //initialization base resistance VBE=(0.7) disp("VBE = "+string(VBE)+" volts") // value of ba...
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function[y]=ampdemod(Em,Ec,fm,fc,fs) t = 0:1/fs:1; m=0.9; Vm = Em*sin(2*%pi*fm*t); Vc = Ec*sin(2*%pi*fc*t); x = Ec*(1+m*sin(2*%pi*fm*t)).*(sin(2*%pi*fc*t)); xdem = x.*Vc; H = iir(7,'lp','butt',[fc/fs,0.5],[.01,.01]); num = coeff(H(2)); den = coeff(H(3)); num = num(lengt...
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clear // //The total number of cycles the clock should perform in 24 hours for correct time is t=24*60*60*50 printf("\n The total number of cycles the clock should perform in 24 hours for correct time is= %0.0f ",t) //The number of cycles the clock performs from 8am to 7pm is n=(6*49.95+5*49.90)*60*60 printf("\n The n...
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//(Manufacturing Considerations in Design) Example 3.3 //Refer Fig. 3.26 on page 70 //Basic diameter of hub Dh mm Dh = 50 //Refer tables 3.2 and 3.3b for tolerances of H7-s6 fit //Upper deviation for hub Uh mm Uh = 0.025 //Lower deviation for hub Lh mm Lh = 0.000 //Basic diameter of shaft Ds mm Ds = 50 //U...