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Name=[MCA-6] Fishing Aimer PlayerCharacters=Angler BotCharacters=Clay Fish.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Angler AddedBots=Clay Fish.bot;Clay Fish.bot;Clay Fish.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=fishing_pond.map MapScale=1.0 BlockProjectilePredictors=true Bloc...
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// Ex18_5 Page:353 (2014) clc;clear; N1 = 1; // Assume the number of present atoms of K-40 N2 = 10.2; // No.of atoms of Ar-40 relative to K-40 t_half = 1.25e+009; // Half-life of K-40, years lambda = 0.693/t_half; // Decay constant, per sec t = log(1 + N2/N1)/lambda; // Age of the rock on moon, yea...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Standing Wave, CG, P=4</description> <executable>ShallowWaterSolver</executable> <parameters>LinearSWE_StandingWave_WallBC_CG_P4.xml</parameters> <files> <file description="Session File">LinearSWE_StandingWave_WallBC_CG_P4.xml</file> ...
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//determine //the small-signal equivalent-circuit constants gm and rds. (b) Alternatively, evaluate gm from the //transfer characteristic. //Example 7.1 page no 207 clear clc Did=(3.3-0.3)*10^-3 Vgs=2 gm=Did/Vgs*1000 printf("\n The value of gm=%0.3f mS",gm) Dvds=20-5 Did=(1.6-1.4)*10^-3 rds=Dvds/Did/1000 p...
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//Example 5.10 clear; clc; T=25; Ib=75*10^(-9); Ios=80*10^(-9); Vos=100*10^(-6); Vs=15; R1=4.99*10^(3); R2=365; R3=4.99*10^3; R4=499; R5=499; R6=20*10^3; R7=19.6*10^3; R8=100; R9=100*10^3; R10=1*10^3; C=100*10^(-12); EI1=Vos+(((R1*(R2+(R8/2)))/(R1+(R2+(R8/2))))*I...
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6 9:0.25 14:1.5 16:0.1111111111111111 18:0.07142857142857142 27:1.0 29:0.16666666666666666 43:0.3333333333333333 44:0.5 56:0.2857142857142857 60:0.030303030303030304 64:0.5 70:0.125 78:0.25 127:1.0 129:1.0 160:0.25 183:0.25 199:1.0 200:1.0 230:0.16666666666666666 289:1.0 301:1.0 387:0.25 398:0.3333333333333333 442:0.16...
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clear; clc; // Example: 10.8 // Page: 410 printf("Example: 10.8 - Page: 410\n\n"); // This problem involves proving a relation in which no mathematics and no calculations are involved. // For prove refer to this example 10.8 on page number 410 of the book. printf(" This problem involves proving a relatio...
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clc clear //Input data p1=1//Pressure in bar T1=25+273//Temperature in K rp=8//Pressure ratio of compressor Tm=900+273//Maximum temperature in K pd=3//pressure drop in combustion chamber in percent nc=0.88//Efficiency of compressor nt=0.88//Efficiency of turbine CV=44.43//Calorific value of fuel in MJ/kg cp...
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clear all exec('C:\Users\Julien Guégan\Desktop\PFE\affichage.sce',-1) exec('C:\Users\Julien Guégan\Desktop\PFE\fonctions test.sce',-1) function alpha = backtracking(f,x,d,grad)//pour newton mais pas pour quasi et CG alpha = 10 w = 0.1 cpt = 0 while(f(x+alpha*d)>(f(x)+alpha*w*(grad'*d))) alpha =...
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example11_15.sce
//clc() Hna = 26.04;//J/g-atomK Hs = 22.6;//J/g-atomK Ho = 16.8;//J/g-atomK Hh = 9.6;//J/g-atomK Hna2so410h2o = 2*Hna + Hs + 14*Ho + 20*Hh; Hexp = 592.2;//J/molK Deviation = (Hexp - Hna2so410h2o)*100/Hexp; disp("%",Deviation,"Deviation in heat capacity = ")
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// Priority List Method clear clc; Fc1=1.1;//Fuel cost(1)=Rs 1.1/MBtu Fc2=1;//Fuel cost(2)=1/MBtu Fc3=1.2;//Fuel cost(3)=1.2/MBtu P1max=600; P1=P1max; F1=600+7.1*P1+0.00141*(P1^2);//For P1= Pm1ax Favg1=F1*Fc1/600;//Full load average production cost P2max=450; P2=P2max; F2=350+7.8*P2+0.00195*(P2^2);//For P2...
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clc //initialisation of variables h=100//ft^3 t=15//degree C p=120//lb/in^2 gama=1.3//in t1=15//Degree C M=[(144*t*h*2.6)/(0.3)*(1.271-1)]//ft lb //CALCULATIONS V=sqrt(p/t)//ft lb //RESULTS printf('Compare the values of the two cylinders=% f ft lb',V)
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clc,clear printf('Example 4.21\n\n') V= 0.5*0.25*0.02//volume of plywood to be heated D=600 //density of plywood in kg/m^3 W=V*D specific_heat = 1500 T1=25;T2=125; //initial and final temperature heat= specific_heat * W * (T2-T1)/(60*60) //in W-Hr T=10 //duration of heating in minutes power_required = heat...
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monitoring.sce
f=figure("dockable","off", "menubar", "none"); f.figure_position = [25, 58]; f.figure_name="Real-time Temperature Monitoring and Control"; f.figure_size = [1200 700]; f.background = color(246,244,242); f.resize="off"; f.menubar_visible="on"; f.toolbar_visible="off"; f.info_message=f.figure_name f.tag="mainWindow"; f.cl...
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// Example 7.1 clear all; clc; // Using the data form Table 6.3 at temperature = 20 deg n_T = 2.065; // Average number of neutrons produced per neutron absorbed in fission // Using the data from Table 7.1 t_dM = 2.1e-4; // The mean diffusion time of the moderator in seconds k_inf = 1; ...
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clc; clear; //Example 5.24 ho=200; //[W/sq m.K] hi=1500; //[W/sq m.K] Cpw=4.2; //Sp heat of Water in [kJ/(kg.K)] Cpo=2.1; //Sp heat of Oil in [kJ/(kg.K)] E=0.8; //Effectiveness k=46; //[W/m.K] m_dot=0.167; //[kg/s] mCp_oil=2*m_dot*Cpo*1000 //For oil [W/K] //mCp_oil is wr...
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clc; T1=295;//C p1=1.02;//bar p2=6.8;//bar y=1.4; v1=0.015;//m^3 cv=0.718; R=0.287 T2=T1*(p2/p1)^((y-1)/y); disp("final temperature is:"); disp("k",T2); v2=v1*{(p1/p2)^(1/y)}; disp("final volume is:"); disp("m^3",v2); w=cv*(T2-T1); m=p1*v1*10^5/(10^3*R*T1); W=w*m; disp("total work done is:"); di...
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//Finding of Power developed,Outlet Vane Angle ,Speed //Given H=100; D=.675; D1=0.5 B=0.15; B1=.225; g=9.81; rho=1000; Vf=3; Vw=3; //To Find u=Vf/tan(%pi/15); N=1/((%pi*D)/(u*60)); u1=u*(D1/D);disp(Vf); Vf1=(D*B*Vf)/(0.15*B1); z=atand(Vf1/u1); P=(rho*%pi*B*D1*Vf*Vw*u)/10000; disp("Speed ="+string(N)+"...
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// Scilab code: Ex6.4 : Wavelength limit of X-rays : Pg: 157 (2008) V = 20000; // Potential difference, volt h = 6.624e-034; // Planck's constant, Js c = 3e+08; // Velocity of light, m/s e = 1.6e-019; // Charge of an electron, coulombs // Since e*V = h*c/L; // Energy required by an electron to move ...
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forwardDifference2.sci
function[firstDerivative, err] = forwardDifference2(fx, h) firstDerivative = []; err = []; for(i = 1:10) firstDerivative = (-tan(x + 2 .* h) + 4 * tan(x+h) - 3*tan(x))./(2.*h); trueValue = (sec(x))^2; err = abs(trueValue - firstDerivative); end endfunction
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2.sce
clc clear //INPUT DATA n1=1.54//refractive index of optical fibre core n2=1.5//refractive index of cladding //CALCULATION NA=sqrt((n1)^2-(n2)^2)//numerical aperture //OUTPUT printf('The numerical aperture is %3.4f',NA)
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Ex2_2.sce
//Example 2.2, Page Number 55 //The Function fpround(dependency) is used to round a floating point number x to n decimal places //Excitation Energy Calculation clc; r=11.8 //Relative Permeability m=9.1*(10**-31) //Mass of electron in kilogram me=0.26*m //Effective mass //From equation 2.28 E=13.6*(me/m)*((...
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Ex10_2.sce
clc //Initialization of variables l = 12 //ft b = 5 //ft a = 40 //degree R = 3.25 //ft S0 = 0.0014 n = 0.012 V = 10.2 // ft/s g = 32.2 //ft/s^2 // Calculations A = l*b + b*(b/tand(a)) Q = (1.49/n)*A*(R^(2/3))*(S0^(0.5)) //cfs Fr = V/(g*b)^0.5 // results printf(" the flow rate is %.f cfs",Q) printf("\n...
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Ex1_48.sce
clear // // // //Variable declaration D8=1.42 //diameter of 8th ring(cm) D8dash=1.25 //changed diameter of 8th ring(cm) //Calculation mew=D8**2/D8dash**2 //refractive index of liquid //Result printf("\n refractive index of liquid is %0.2f ",mew)
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4_7.sce
clc; s1=1.7189; v1=0.0978;//m^3 p1=2.01;//bar p2=10;//bar lamda=1.1; v2=v1*(p1/p2)^(1/lamda); s_1=1.7564;//kJ/kg K s_2=1.7847;//kJ/kg K v_1=0.0228;//m^3 v_2=0.0222;//m^3 v_3=0.0233;//m^3 s2=s_1+[(v_1-v_2)/(v_3-v_2)]*(s_2-s_1) disp("increase in entropy"); disp("kJ/kg K",s2-s1)
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Ex6_5.sce
clear // // // //Variable declaration d=0.08*10**-3 //thickness(m) A=8*10**-4 //area(m**2) epsilonr=2.56 epsilon0=8.84*10**-12 tan_delta=0.7*10**-4 new=10**6 //frequency(Hz) //Calculation C=A*epsilon0*epsilonr/d //capacitance(farad) epsilonrdash=tan_delta*epsilonr omega=2*%pi*new R=d/(epsilon0*epsilonrda...
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example4.sce
//chapter 31 //example4 clc //given m=9.1*10^-31 //in kg n=8.4*10^28 //in m-1 e=1.6*10^-19 //in coul p=1.7*10^-8 //in ohm-m v=1.6*10^8 //in cm/sec T=2*m/(n*p*e^2) disp(T,"(a) Mean time b/w collisions in sec is") Lambda=T*v disp(Lambda,"(b) Mean free path in cm is")
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Ex29_7.sce
clear //Given Pc=50 Ma=0.8 Ma1=0.1 //Calculation Ps=(1/2.0)*Ma**2*Pc Ps1=(1/2.0)*Ma1**2*Pc //Result printf("\n total sideband at 80percentageis %0.3f KW",Ps) printf("\n total sideband at 10percentageis %0.3f KW",Ps1)
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example2_5.sce
//Chapter 2 //Example 2.5 //Page 61 clear; clc; R1 = 2000.00; R2 = 2000.00; R3 = 2000.00; R4 = 2050.00; V = 5.00; Rg = 50.0; //Calculation of Offset Current printf("From equation the offset voltage is Vth. \n") //Calculation of Vth x = V *(((R3*R2)-(R1*R4))/((R1+R3)*(R2+R4))) printf("Vth = %f V ...
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ex4_7.sce
// Example 4.7 page no-207 clear clc vce = - 0.07 //V vbe = - 0.21 //V. vcc=-9 rc=1 //K-Ohm rb=30 //K-Ohm ic=(vcc-vce)/rc ib=(vcc-vbe)/rb vbc=vbe-vce printf("\nIc = %.2f mA\nIB = %.3f mA\nVbc = %.2f V",ic,ib,vbc)
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pot.sce
//delta: tolerancia entre dos aproximaciones consecutivas function lambda = pot(A, maxit, delta) n=size(A,1) w=zeros(n) z=zeros(n) z(n)=1 //aproximación inicial. lambda=z for i=1:maxit w1=w z1=z lambda1=lambda w= A * z1 z= w /norm(w,'inf') lambda =(z' * A * z) / (...
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chapter7_ex5.sce
clc clear //input rl=10;//resistance of an inductor in ohms l=0.05;//inductaance of an inductor in henry rc=20;//resistance in series with a capacitor in ohms c=150*(10^-6);//capacitance of a capacitor in farad ///inductor is in parallel with the series circuit containing a resistor and a capacitor v=240;//su...
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exa6_10_2.sce
//Caption:time_response_for_unit_impulse_and_step_function //example 6.10.2 //page 171 //G(s)=(4*s+1)/4*(s^2);H(s)=1; clc; s=%s; syms t; G=(4*s+1)/(4*(s^2))//G(s) b=1; a=G/.(b); disp(a,"C(s)/R(s)="); //for unit impulse response R(s)=1 ; so C(s)=a; disp("for unit impulse response R(s)=1 ; so C(s)=a;") disp(a,"C(s)="); c...
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ex4_7.sce
//Part A Chapter 4 Example 7 clc; clear; close; M=16;//molecular weight p1=101.3;//KPa p2=600;//MPa T1=20+273;//K n=1.3;//constant Cp=1.7;//KJ/KgK UGC=8.3143*10^3;//Universal Gas constant R=UGC/M/1000;//KJ/KgK Cv=Cp-R;//KJ/KgK Gamma=Cp/Cv;//constant T2=T1*(p2/p1)^((n-1)/n);//K W=R*(T2-T1)/(n-1);// Q=W...
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clc A= 1 disp("A= "+string(A)+"cm^2") //initializing value of diode area Na=5*10^17 disp("Na = "+string(Na)+"cm^-3") //initializing value of p side doping Nd=10^16 disp("Nd = "+string(Nd)+"cm^-3") //initializing value of n side doping Dn = 20 disp("Dn= "+string(Dn)+"cm^2/s")//initializing value of electron diff...
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8_3.sce
clc; //page no 8-9 //Example 8.3 disp("at 1000kHz"); Q=80; fi=455*10^3;//in Hz fs=1000*10^3;//in Hz fsi=[fs+(2*fi)]*10^(-3); disp(+'kHz',fsi,'fsi='); rho=[(fsi*10^3)/fs]-[fs/(fsi*10^3)]; disp(rho,'rho='); //Rounding rho to 3 digits rho1=1.386; alpha=sqrt(1+(Q^2*rho1^2)); disp(alpha,'Rejection ratio is'); ...
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clc; clear; E=10^4 //Electric field in V/cm e=1.6*10^-19 //in J epsilon_r=11.7 //in F/cm epsilon_0=8.85*10^-14 //in F/cm //Calculation del_phi=sqrt((e*E)/(4*%pi*epsilon_r*epsilon_0)) xm=sqrt(e/(16*%pi*epsilon_r*epsilon_0*E)) mprintf("Schottkybarrier-lowering for Si-metal contact= %0.3f V\n",del_phi) mprin...
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//EXAMPLE 1-15 PG NO-22 I1=0.04; //CURRENT I2=0.01; //CURRENT V1=200; //VOLTAGE R=V1/I1; //Resistance disp('i)resistance (R) = '+string (R)+' ohm'); V2=10; //VOLTAGE I3=50; ...
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jan.immediate_drawing = "off" delete(Axes(3).children) // Deleta as polylines que estejam no eixo plot(Axes(3),t',Dt') // Plota os deslocamentos nodais Axes(3).data_bounds(2) = T1 select find(radioBut.value) case 2 plot(Axes(3),t',[T' Dt'/lambda]) legendas = [...
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clc clear disp("Example 8.49a") printf("\n") disp("Prove the following boolean identities") disp("A+BC=(A+B)(A+C)") A=[0 0 0 0 1 1 1 1] B=[0 0 1 1 0 0 1 1] C=[0 1 0 1 0 1 0 1] for i=1:length(A) Y(i)=A(i)+(B(i)*C(i)) if(Y(i)==2) Y(i)=1 end end for i=1:length(A) Z(i)=(A(i)+B(i))*(A(i)+C(i)) ...
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//Example 1.25.b // the time lag clc; clear; close; //given data : t1=50; // in seconds t2=500; // in seconds w=2*%pi/t2; P=atan(w*t1) T=(1/w)*P disp(T,"the time lag,T(seconds) = ")
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clc N=8;................................//order of 8 P1=0.95; P2=0.05; P8=((1-P2)^8)*100; disp("%",P8,"Probability of finding 8kHz channel is");
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function [y]=intersp(s,nint) [o,i]=argn(0); if i <> 2 then error(58); end; if type(s) <> 1 then error(53,1); end; if type(nint) <> 1 then error(53,2); end; if maxi(size(s)) = 1 then error(89,1); end; if nint <= 1 then error(36,1); end; // M=prod(size(s)); x=(0:M-1)/(M-1); xd=(0:nint-1)/(nint-...
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//Example 15.2. clc format(6) disp("To find the range over which capacitance is to be varied") disp("Frequency of oscillation of Hartley oscillator is") disp(" fo = 1 / 2*pi*sqrt((L1-L2)*C)") disp("Therfore, C = 1 / 4*pi^2*(L1+L2)*fo^2") disp("When fo = 950 kHz") C=1/(4*(%pi^2)*((2*10^-3)+(20*10^-6))*((9...
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t = poly(0,'t'); e = (0.2*t)-(5e-04*t^2); // e.m.f. as a function of temperature in mV e0 = horner(e, 0); // e.m.f. at t = 0 degree e100 = horner(e, 100); // e.m.f. at t = 100 degree e50 = horner(e, 50); // e.m.f. at t = 50 degreer r = (100/e100)*e50; // Reading of thermocouple at t = 50degree disp("degree",r,"Re...
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clear all; clc; disp("Scilab Code Ex 6.27 : ") //Given: sigma_y = 250; //MPa t = 12.5; //mm w = 200; //mm h = 225; //mm //Maximum Elastic Moment: yy = (h+t)/2; I1 = (1/12)*(w*t^3) + (w*t*yy^2); I = (1/12)*(t*h^3) + 2*(I1); c = 125; //mm My = (sigma_y*I)/(c); //Flexure Formula //Plastic Moment: C...
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//clear// //Caption:To find primary photocurrent and multiplication factor //Example6.5 //page230 clear; clc; close; etta = 0.65; //quantum efficiency of silicon qavalanche photodiode C = 3*(10^8); //free space velocity in m/s Lambda = 900e-09;//wavelength in meters q = 1.6*(10^-19);//charge in coulombs h = ...
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function csdp(C,A1,b,K) funcprot(0) A = sdpasparse(A1,K); a = scilab_io(C,A,b,K); endfunction
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function [d, initialcross, finalcross, nextcross, midreference]= dutycycle(x, varargin) // This function estimate duty cycle of bilevel waveform pulses. // Calling Sequence // d=dutycycle(x) // d= dutycycle(X,Fs) // d=dutycycle(x, t) // d= dutycycle(tau, prf) // d=dutyc...
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Name=DJ Simulator PlayerCharacters=Quaker BotCharacters=Quaker Bot Fast Strafes.bot IsChallenge=true Timelimit=3600.0 PlayerProfile=Quaker AddedBots=Quaker Bot Fast Strafes.bot;Quaker Bot Fast Strafes.bot;Quaker Bot Fast Strafes.bot;Quaker Bot Fast Strafes.bot;Quaker Bot Fast Strafes.bot;Quaker Bot Fast Strafes.b...
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2_9.sce
clc //Initialization of variables z=1.2 //m y=1 //m //calculations hp=0.6 + 1/12 *y*z^3 /(0.6*y*z) //results printf("Position of hinge = %.1f m",hp)
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EXAMPLE11_44.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.44(PAGENO 529)"); //given P_x1 = 1/2//probability of first symbol P_x2 = 1/4//probability of second symbol P_x3 = 1/8//probability of third symbol P_x4 = 1/8//probability of fouth s...
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clc Na=2*10^17 disp("Na = "+string(Na)+" /cm^3") //initializing value of acceptor ion concentration. Er=11.9 disp("Er = "+string(Er)) //initializing value of relative dielectric permittivity constant . Eo=8.854*10^-14 disp("Eo = "+string(Eo)+" F/cm") //initializing value of permittivity of free space. ni=1.5*10...
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clear // // // //Variable declaration e=1.6*10^-19; //charge(coulomb) m=9*10^-31; //mass(kg) h=6.62*10^-34; //plank's constant(Js) rho=970; //density(kg/m^3) N0=6.02*10^26; //avagadro number A=23; //atomic weight //Calculations n=rho*N0/A; //concentration(electrons/m^3)...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 9 Frequency Response of Amplifier Pg no. 301 clear; clc; //Given Gv_dB=75;//voltage gain of amplifier in dB units //Solution Gv=10^(0.1*Gv_dB);//voltage gain magnitude printf("P2/P1 = %.f",Gv);
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function y = genqammod(x,const) //GENQAMMOD General quadrature amplitude modulation // Y = GENQAMMOD(X,CONST) outputs the complex envelope of the modulation // of the message signal X using quadrature amplitude modulation. The // message signal must consist of integers between 0 and 1 less than the // length of C...
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//Chapter 1 : Wave Optics clear; //Variable declaration lamda=5.9*10**-7 r=5.2*10**-3 //radius of ring n=10 //Calculation R=(r**2)/(n*lamda) t=(n*lamda)/2/10**-6 //Result mprintf("(i)Radius of curvature R= %f m" ,R) mprintf("\n(ii)Thickness of air film t= %.2f*10**-6 m" ,t)
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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errcatch(-1,"stop");mode(2);; ; format('v',11); A=[1 3 5]; B=[0 5 0]; C=A-B; disp(C,"difference(in newton)="); exit();
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COMMENT | ************************************************************* | COMMENT | * AUTHOR: Paolo Pecchiari | COMMENT | * | COMMENT | * SUBJECT: SIMPLIFY TEST | COMMENT | * | COMMENT | * GETFOL VERSION: September 1990 | COMMENT | * | COMMENT...
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pkgcur.tst
CREATE OR REPLACE PROCEDURE pkgcur_test1 (deptno_in IN INTEGER) IS rec emp%ROWTYPE; BEGIN /* Accessing the package cursor directly: OPEN and FETCH. */ OPEN personnel.emps_for_dept (deptno_in); FETCH personnel.emps_for_dept INTO rec; p.l (rec.ename); END; / CREATE OR REPLACE PROCEDURE pkgcur_test2 IS r...
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//water and its treatment// //example 2.18.56// clc Hardness=300//Hardness of water(mg/lit) or ppm// H=Hardness/1000//Hardness of water(gms/lit)// volume_NaCl=75//Volume of NaCl// Wt_per_Litre=75//gms NaCl consumed by zeolite bed per litre// total_wt=Wt_per_Litre*volume_NaCl//total gms NaCl consumed by zeolite b...
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//Example 2.6.a : the energy of the photon emitted clc; clear; close; format('v',5); //given data : Z=1;//for hydrozen n1=3; n2=2; E3=-(13.6*Z^2)/n1^2; E2=-(13.6*Z^2)/n2^2; del_E=E3-E2; disp(del_E,"the energy of photon emitted,del_E(eV) = ")
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disp("n=σ/(e*μd)"); a=5.9*10^7; //say σ=a b=3.2*10^-3; //say μd=b e=1.6*10^-19; d=8.5*10^28; n=a/(e*b); printf('\n The value of n is %f*10^29 m^-3',n*10^-29); c=n/d; //say d=concentration of copper atoms and c=avg. no. of electrons/atom printf('\n The average number of electrons/atom is %1.2f',c);
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// Example2_3_pg69.sce // To find primary voltage and current supplied // Theory of Alternating Current Machinery by Alexander Langsdorf // First Edition 1999, Thirty Second reprint // Tata McGraw Hill Publishing Company // Example in Page 69 clear; clc; close; // Given data // Transformer A data va_A = 100e+3; // ...
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ifftn.sci
function y = ifftn(A, varargin) funcprot(0); rhs = argn(2) if(rhs<1 | rhs>2) error("Wrong number of input arguments."); end select(rhs) case 1 then y = callOctave("ifftn",A); case 2 then y = callOctave("ifftn",A, varargin(1)); end endfunction
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// This file is released under the 3-clause BSD license. See COPYING-BSD. function builder_gw_cpp() WITHOUT_AUTO_PUTLHSVAR = %t; tbx_build_gateway("skeleton_cpp", .. ["callOctave","callOctave"], .. ["s_o_test_v7.cpp"], .. get_absolute_file_path("builder.sce"),[],["-L/usr/lib/x86_64-linux-gnu -...
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pathname=get_absolute_file_path('4_1.sce') filename=pathname+filesep()+'4_1_data.sci' exec(filename) //Change in efficiency with respect to efficiency //z=dn/n n=1-((1/r)^(y-1)) z=-((1-n)*(y-1)*log(8)*(dCv))/n printf("\n\nRESULTS\n\n") printf("\nThe effect of efficiency on Otto cycle is %f",z*100)
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grid.tst
describe('Grid', () => { it('should contain a div with a class of .footer', () => { const vnode = App.Components.grid.view({ attrs: { gridOptions: { columns: [], data: [] } }, state: { sortedColumnId: null } }); expect(vnode.tag).toBe('div'); expect(vnode.attrs.className).toBe('grid'); }); });
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And4Way.tst
load And4Way.hdl, output-file And4Way.out, compare-to And4Way.cmp, output-list a%B3.1.3 b%B3.1.3 c%B3.1.3 d%B3.1.3 out%B3.1.3; set a 0, set b 0, set c 0, set d 0, eval, output; set a 0, set b 0, set c 0, set d 1, eval, output; set a 0, set b 0, set c 1, set d 0, eval, output; set a 0, set b 0, set c 1, set d 1, eva...
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qammod.sci
function Q = qammod(x, m) // //Function Description //qammod: This function modulates a sequence of integers //x into a complex baseband quadrature amplitude modulation signal. // //Calling sequence:- //Psk = qammod(x,m) // //Parameters: //x: int - matrix // The sequence of integers to be modulated...
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ex1_5.sce
//find the DC supply voltage clear; clc; //soltion //given //consider 1 phase AC system pf=0.8; v=(33*10^3);//volts r1=0.15;//ohm//total resistance of the 1 phase line PD1=0.2;//percentage voltage drop in 1 phase AC system Vd=PD1*v;//volt//voltage drop in the line I1=Vd/r1;//ampere//load current p=v*I1*pf;/...
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goertzel.sci
function Y = goertzel(X,INDVEC,DIM) //Computes DFT using the second order Goertzel Algorithm //Calling Sequence //Y = goertzel(X,INDVEC,DIM) //Parameters //X //A vector matrix or n-dimensional array //INDVEC //The indices at which the DFT is to be computed //DIM //The dimension along which the algorithm is to be implem...
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eg9_3.sce
//a //transistor parameters R2 = 0.625; hie = 1.67; Rb = 4.16; Rl = 2.4; Roe = 150; Cc = 25 * 10^-6; rBB = 0.29; rBE = 1.375; Cd = 6900 * 10^-12; Ct = 40 * 10^-12; gm = 0.032; Req = (Rl*Roe)/(Rl + Roe); hfe = 44; a = 1 + (R2/Req); b = 1 + (hie/Rb); Aim = -hfe/(a*b); // mid b...
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//Example 1.15 clc; clear; disp("Possible outcomes...(1,1),(1,2)......(6,5),(6,6)"); N=36; disp(N,"total No. of possible outcomes (N) ="); disp("Favourable outcomes....(2,6),(3,4),(4,3),(6,2)"); M=4 disp(M,"No. of Favorable cases of (dice points product is 12)="); P=M/N; disp(P,"Probability of (dice points p...
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//EXAMPLE 3.19 PG NO-187 VL=230; VP=VL/1.732; IL=13.279; COSQ=0.8; SINQ=0.6; P=(1.732*VL*IL*COSQ) R.P=(1.732*VL*IL*SINQ) VA=(1.732*VL*VP) disp('i) POWER FACTOR = '+string (P)+' W'); disp('i) POWER FACTOR = '+string (R.P)+' var'); disp('i)TOTAL VA = '+string (VA)+' VA');
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clc //Given that m = 9e-31 // mass in kg E = 1e9 // Energy of accelerated electron in eV c = 3e8 // speed of light in m/s // sample problem 14c page No. 227 printf("\n \n\n # Problem 14c # \n") printf("\n Standard formula used \n E = m*c^2") E_0 = m * c^2// calculation of rest mass energy ratio = E / E_0 *1.6...
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// Example 3.1 // Model of a Battery v_s=6; // Terminal voltage of Battery when i=0 R_s= -(6.0-5.8)/(0-0.05);// Slope Resistance from v-i curve // Setting v>= 0.9v_s=5.4 V // Using Ohm's Law and above mentioned conditions we get // 5.4=(6*R_L)/(4+R_L) R_L=(5.4*4)/0.6;// Minimum value of Load resistance for treat...
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polys[0]=0 polys[1]=1 polys[2]=1 polys[3]=-1 order=2 initialize: mN=-1, mRElen=3, mNPlen=1, mOrder=2, mLinit=2 polys[0]=0 polys[1]=1 polys[2]=1 polys[3]=-1 order=2 initialize: mN=-1, mRElen=3, mNPlen=1, mOrder=2, mLinit=2 setGfType: mN=2, mRElen=3, mNPlen=1, mOrder=2, mLinit=-1 setRE(1,1): [0,*0,0] -> ...
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// 08.08.15 function Ans=Rotate3pt(varargin) Eps=10^(-4); Nargs=length(varargin); P=varargin(1); W1=varargin(2); W2=varargin(3); C=[0,0,0]; if Nargs>=4 C=varargin(4); end; if type(W2)==1 & length(W2)==1 Ct=cos(W2); St=sin(W2); V3=1/norm(W1)*W1; if V3(1)==0 Tmp=[1,0,0]; e...
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clc clear //Input data t=100;//The given temperature of water in degree centigrade C1=1.01;//The specific heat of water at 100 degree centigrade in cal/g L=-0.64;//The rate at which the latent heat of vapourisation decreases with rise in temperature in cal/K l=540;//The latent heat of vapourisation of steam in...
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// Exa 4.15 clc; clear; close; // Given data V_CC = 18;// in V bita = 90; R_C = 2.2 * 10^3;// in ohm R_E = 1.8*10^3;// in ohm R_B = 510*10^3;// in ohm I_B = V_CC/( (bita*(R_C+R_E))+R_B );// in A I_C = bita*I_B;// in A disp(I_C*10^3,"The value of I_C in mA is"); V_CE = I_B*R_B;// in V disp(V_CE,"The value ...
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//Problem 29.01: A coil of inductance 5 mH and resistance 10 ohm is connected in parallel with a 250 nF capacitor across a 50 V variable-frequency supply. Determine (a) the resonant frequency, (b) the dynamic resistance, (c) the current at resonance, and (d) the circuit Q-factor at resonance. //initializing the var...
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M = csvRead('/home/jilcimar/PESSOAL/computacao-numerica/taylor-pendulo/files/sample.csv') x0 = 448 y0 = 77 x = M(:,1) y = M(:,2) t = M(:,3) deltaX = x - x0 deltaY = y - y0 angulo_pendolo = acos(deltaX./sqrt(deltaX**2 + deltaY**2)) function [w0, r]=coeficientes(t, ang, p) //vetores de tempo e angulo, e o período ...
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clear // //given f=50 p=4 //case a s=(120*f)/p //synchronous speed printf("\n synchronous speed= %0.0f rpm",s) //case b slip=0.03 r=s-s*slip //rotor speed printf("\n rotor speed= %0.0f rpm",r) //case c r=900 //given speed of rotor slip=(s-r)/s //per unit slip rf=slip*f printf("\n rotor frequency= %0.0f Hz",rf)
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CandidateSelector expand width=4 base=9 exponent=4 left=2 right=2 fileName=data/euler422.man chain2 [[3,1,1,-5],[7,2,-5,-4],[1,-5,2,-1],[5,2,1,-8]] det=24 [631,222,558,503] [158,59,134,133] [2,22,-2,-22] chain2 [[-4,-3,6,0],[7,2,-5,-4],[8,-1,-3,-6],[5,2,1,-8]] det=28 [631,222,558,503] [158,59,134,133] [-5,22,5,-22]
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//Example 5.3 //Calculate the time required for cooling of the rod. //Given d=0.0254 //m, diameter of steel rod l=0.4 //m, length of rod T1=80 //C, initial temp. T2=30 //C, ambient temp. T3=35 //c, temp. after coolin...
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// Exa 12.5 format('v',8) clc; clear; close; // Given data memory= 16;// in K memory= memory*1024;// in bits // Number of words N1= memory; disp(N1,"The number of words is : ") N2= 32;// number of bits per word disp(N2,"The number of bits per word is : ") // Number of memory cell N3= N2*memory; disp(N3,"...
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// This code is to plot the Fermi arcs output by Wannier Tools // Besides, this code also helps you locate the positions of a particular // area of the plot. // To use it, you must download 'arc.dat_l, arc.dat_r and input.dat // if want to plot spintexture, also need 'spindos.dat' clear; clc; xdel(winsid());exec(PiLi...
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function [x,y,typ] = mdaq_pwm(job,arg1,arg2) pwm_desc = ["This block sets MicroDAQ PWM outputs."; "Block controls PWM module module which contains A and B channels."; "PWM period is defined in microseconds. Polarity allows to generate"; "inverted PWM waveform. Block input data should be in range 0-100."...
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//Exa 2.14 clc; clear; close; //given data e=1.6*10^-19;//in coulamb resistivity=9*10^-3;//in ohm-m RH=3.6*10^-4;//in m^3-coulamb^-1 SIGMA=1/resistivity;//in (ohm-m)^-1 rho=1/RH;//in cooulamb/m^3 n=rho/e;//in m^-3 disp(n,"Density of charge carriers in m^-3 : "); MU=SIGMA*RH;//in m^2/V-s disp(MU,"Mobility i...
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// Scilab code Ex1.3: Pg 20 (2005) clc; clear; c = 3e+08; // Velocity of light, m/s L_p = 100; // Proper length of spaceship, m v = 0.99*c; // Velocity of spaceship, m/s // Using length contracction formula, L = L_p*sqrt(1 - (v/c)^2); // Observ...
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clear; clc; disp("--------------Example 30.3----------------") message=['H' 'E' 'L' 'L' 'O']; key=15; // shift down key alphabet=['A' 'B' 'C' 'D' 'E' 'F' 'G' 'H' 'I' 'J' 'K' 'L' 'M' 'N' 'O' 'P' 'Q' 'R' 'S' 'T' 'U' 'V' 'W' 'X' 'Y' 'Z']; ciphertext=""; for k=1:5 // encrypt each character in the message for ...
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//EXAMPLE 3-10 PG NO-180 Za=6+%i*0; Zb=5.26+%i*3; Zc=3.535+%i*3.535; Van=230.94+%i*0; Vcn=-115.47-%i*200; Vbn=-115.47+%i*200; Ya=1/Za; disp('i) admittance (Ya) is in rectangular form = '+string (Ya) +' siemens '); Yb=1/Zb; disp('i) admittance (Yb) is in rectangular form =...
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//Example 17.1 //Uncertainty in angle of Emergence clc; clear; //given data : E=3.2D-17;//energy of enectron in J m=9.1D-31;// mass of electron in kg h=6.626D-34;// plank's constant in J.sec r=1D-6;//radius of circular hole in m p=sqrt(2*m*E);// momentum in Kg.m/sec delta_x=2*r;// uncetainty in position in m ...
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//Author: Parthasarathi Panda //parthasarathipanda314@gmail.com function [zerosort,g]=sosbreak(p) //function for breaking a polynomial in second order polynomials (and an extra linear) [zero,g]=factors(p);//factorising into real coefficient polynomials degn=degree(p); zerosort=list(); //to segregate lin...
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# port code 201 = start recording # port code 200 = pause recording # port code 17 = standard (100ms sound) isi = 350 soa = 450 # port code 19 = deviant (180ms sound) isi = 270 soa = 450 scenario = "tone_oddball_450SOA"; no_logfile = false; scenario_type = trials; default_background_color = 0, 0, 0; default_t...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 30 clc; disp("CHAPTER 1"); disp("EXAMPLE 30"); //VARIABLE INITIALIZATION I1=25; //current source in Amperes I2=20; //current source in Amperes v=20; //voltage source in ...
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Expanding for base=3, level=4, reasons+features=base,same,similiar,evenexp norm Refined variables=x,y [0+1x,0+1y]: unknown -> [1] [0,0] x²-y³-6 ---------------- level 0 expanding queue[0]^-1,meter=[3,3]: x²-y³-6 [1+3x,1+3y]: unknown -> [1] [1,1] 2x+3x²-3y-9y²-9y³-2 [2+3x,1+3y]: negative-1 [1] by {x=>-x-1} endexp[0] ---...
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clc // Example 1.7.py // A flat plate with a chord length of 3 ft and an infinite span(perpendicular to // the page in fig 1.5) is immersed in a Mach 2 flow at standard sea level // conditions at an angle of attack of 10 degrees. The pressure distribution // over the plate is as follows: upper surface, p2=constant=1132...