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scilab_code

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19mcmi23jan24b.sce
xdel(winsid()); clear; clc function y = data_fit_1(x, c) y = exp(c(1)*x) .* cos(c(2)*x) + c(3)*sin(x); endfunction function e = myerror(c, z) x = z(1); y = z(2); e = y - data_fit_1(x, c); endfunction x = [0 0.55 1.11 1.66 2.22 ... 2.77 3.33 3.88 4.44 5]; y = [1 0.47 3.73 2.22 2.61 ... 1.63 -2.13 0...
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example1_11.sce
clear; clc; //Example1.11[Heat transfer between two Isothermal Plates] //Given:- T1=300,T2=200;//Temperatures of two large parallel isothermal plates[K] L=0.01;//distance between both plates[m] e=1;//Emissivity of plates A=1;//Surface area of plates[m^2] T_avg=(T1+T2)/2;//Average temperature[K] sigma=5.67*(1...
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// Example 4_5 clc;funcprot(0); // Given data T_1=20.0;// °C n=1.35;// The polytropic index m=0.0100;// kg p_1=0.100;// MPa m_2=0.0100;// kg p_2=10.0;// MPa // Solution T_2=((T_1+273.15)*(p_2/p_1)^((n-1)/n))-273.15;// °C // Using Table C.13b of Thermodynamic Tables to accompany Modern Engineering Thermodyn...
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//Caption:Test of Hypotheses concerning Proportions //Two-tailed Test Concerning Single Proportion //Example8.25 //Page274 //Ho: p =k ; H1:p#k clc; p = 0.90; //90% of cases cured by new drugs q = 1-p; n = 80; //sample size pbar = 68/n; //68 out of 80 patients are cured (sample proportion) alpha = 0.05; //sign...
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###grammar S -> NP VP : NP VP S -> S in NP : NP -de S S -> S with NP : NP -la S NP -> i : NP -> the man : adam NP -> the telescope : teleskop NP -> the house : ev NP -> NP-1 in NP-2 : NP-2 -deki NP-1 NP -> NP-1 with NP-2 : NP-2 -lu NP-1 VP -> saw NP : NP -ı gördüm ###input i saw the man in the house with the telesco...
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clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 5.2 Page 265 \n'); //Example 5.2 // Steady State Temperature of junction // Time Required for thermocouple to reach a temp that is within 1 degc of its steady-state value //Operating Conditions h =...
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//Variable declaration: T1 = 140.0 //Initial temperature of hot water (.) T2 = 110.0 //Final temperature of hot water (.) T3 = 60.0 //Initial temperature of cold water (.) T4 = 90.0 //Initial temperature of cold water ...
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step_response_large_gain.sce
clear clc s = poly(0,'s'); G = 1/((s+3)*(s+4)*(s+12)); for k = 1:50:1000 T = k*G/(1+ k*G); T1 = syslin('c', T); t = 0:0.05:20; ts1 = csim('step' , t , T1); //if (k == 1) // plot2d(t,ts1,'-o'); //else plot2d(t,ts1); //end end xlabel('Time','fontsize',4); ylabel('Amplitude','...
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//Car moving //let the expression for retardation be //a=-k*s ...k=constant //v^2/2=(-k*(s^2)/2)+C1 //When brakes are applied //s=0 and v=72 kmph v=20 //m/sec C1=200 //when vehicle stops //v=0 s=15 m k=400/225 //expression for retardation is //a=-1.778*s ...theory approach printf("The expression for ...
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% GeoProver test file for Reduce, created on Jan 18 2003 load cali,geoprover; off nat; on echo; in "$reduce/packages/geometry/supp.red"$ % Example Arnon % % The problem: % Let $ABCD$ be a square and $P$ a point on the line parallel to $BD$ % through $C$ such that $l(BD)=l(BP)$, where $l(BD)$ denotes the % distance be...
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//=============================================================================================================================== // Chapter 7 example 4 clc; clear; // Variable declaration k = 1.38*10^-23; // boltzmann constant (m^2)*(kg)*(s^-2)*(K^-1) e = 1.6*10^-19; // charge of elect...
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function [x,y,typ]=macrocab_nfet0(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1); case 'getinputs' then [x,y,typ]=standard_inputs(arg1); case 'getoutputs' then [x,y,typ]=standard_outputs(arg1); case 'getorigin' then [x,y]=standard_origin(arg1); case 'define...
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clear // // // //Variable declaration epsilon0=8.84*10**-12 R=0.55*10**-10 //radius(m) N=2.7*10**25 //number of atoms //Calculation alpha_e=4*%pi*epsilon0*R**3 //polarisability of He(farad m**2) epsilonr=1+(N*alpha_e/epsilon0) //relative permittivity //Result printf("\n polarisability of He is %0.3f ...
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//猫耳基地 world 4 Base //1111 scene 0 Base cut 0 公主殿下 所以，你到底为什么要抓我？ //人类登月的故事？ 可乐炭 兔耳族作为亚人种，对人类有着诸多优势。比如敏锐的听觉和优秀的运动能力，这些都是人类羡慕的。 可乐炭 如果可以得到它们的话，人类势必可以变成更强大的物种。 可乐炭 最重要的，听说兔肉特别…好吃！ 公主殿下 口水都流出来了… 公主殿下 等下，难道说，你抓我的目的是为了…吃！？ 可乐炭 要不然为什么给你洗澡换衣服，食材加工之前当然要洗干净。 公主殿下 救…救命啊！ 可乐炭 叫吧，你就是喊破喉咙也不会有人来救你的。 牛奶酱 妈~哒！ 可乐炭 喂，怎么骂人啊？ 牛奶酱 真是没文化，这叫...
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// Example 2.8.2 clc; clear; n1=1.47 //refractive index of core a=4.3d-6; //radius of core delta=0.2/100 //relative index difference lamda= 2*3.14*a*n1*sqrt(2*delta)/2.405; //computing wavelength lamda=lamda*10^9; printf("Wavelength of fiber is %d nm.",lamda); //answer in the book is given ...
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//Problem 17.12: An inductor has a negligible resistance and an inductance of 200 mH and is connected in series with a 1 kohm resistor to a 24 V, d.c. supply. Determine the time constant of the circuit and the steady-state value of the current flowing in the circuit. Find (a) the current flowing in the circuit at a ti...
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// Exa 3.9 clc; clear; close; // Given data R_F = 1;// in M ohm R_in = 1;// in M ohm V_in = 1;// in V (assumed) V_out = -(R_F/R_in)*V_in; A_v = V_out/V_in; disp(A_v,"The value of A_v is"); I_in = 1;// in A I_out = I_in;// in A A_in = I_out/I_in; disp(A_in,"The value of A_in is"); A_P = abs(A_v*A_in); di...
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errcatch(-1,"stop");mode(2);//Exam:3.20 ; ; a=2.87*10^(-10);//lattice parameter for bcc iron b=a*(3^(1/2))/2;//Magnitude of burgers vector u=80*10^9;//shear modulus E=(1/2)*u*b^2;//line energy of disslocation disp(E,'line energy of disslocation(in J/m)='); exit();
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//Chapter 7, Example 7.11, page 333 clc //Initialisation kq=2.6*10**-6 //geoclimatic coefficient f=6 //frequency in GHz d=45 //distance in Km gc=0.098 //GC fact...
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s=%s; G=1/(s*(s+10)*(s+2)); K=poly(0,'K'); CharEq=denom(G)+numer(G) rth=routh_t(G,K)
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//Reading first image I1 = imread("left.jpg"); //Reading second image I2 = imread("right.jpg"); //Executing function //Checking if error message comes up when "I" variable hasn't been defined out1 = showMatchedFeatures(I2,I); //output->Undefined variable: I //Reading first image I3 = imread("left01.jpg"); //Readin...
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//CHAPTER 10 ILLUSRTATION 5 PAGE NO 271 //TITLE:Brakes and Dynamometers clc clear //=========================================================================================== //INPUT DATA q=220;//Angle of contact in degree T=340;//Torque in Nm d=0.32;//Diameter of drum in m U=0.3;//Coefficient of friction ...
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<?xml version="1.0" encoding="utf-8" ?> <test> <description>3D channel flow, Hexahedral elements, P=6, restart from nodal field</description> <executable>IncNavierStokesSolver</executable> <parameters>Hex_channel_m6_nodalRestart.xml</parameters> <files> <file description="Session file">Hex_chann...
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//ex9 //Shock Wave in a Converging–Diverging Nozzle clear clc //fluid property at exi nozzle P01=1;//pressure in MPa P1=0.1278;//pressure in MPa T1=444.5;//temperature in K d1=1.002;//density in Kg/m^3 //The fluid properties after the shock (denoted by subscript 2) are related to those before the shock through...
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resimp=9;inte=1;V=10;A=1/3; I=V/(inte+resimp) P=I^2*resimp R=(A^2)*(resimp) I1=V/(inte+I) P1=I1^2*inte
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NWChem topology file for nak_prep Generated by the NWChem prepare module 4.60000004/07/04 10:26:16 amber d3j191 3 3 ...
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* *Testcase IEEE CONVERT FROM/TO FIXED 32 (6), ADD (5), 11 instr total * ADD tests - Binary Floating Point * # # Tests five addition instructions: # ADD (extended BFP, RRE) # ADD (long BFP, RRE) # ADD (long BFP, RXE) # ADD (short BFP, RRE) # ADD (short BFP, RXE) # # Also tests the following three convers...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex2_2.sce. clc; clear; a1=2;b1=1;c1=5;d1=1; //these are the coefficient values of I1,I2,I3 and source obtained from loop ABDA in the given circu...
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clear ; clc; // Example 5.15 printf('Example 5.15\n\n'); printf('Page No. 137\n\n'); // given T = 25;// Wet-bulb temperature in degree celcius T1 = 30;//Dry-bulb temperature in degree celcius V = 5;// Volumetric flow rate of initial air-water mixture in m^3/s T2 = 70;// Final Dry-bulb temperature in degree c...
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clear //Given R15=80 //ohm a=0.004 //Calculation R0=R15/(1+15*a) R50=R0*(1+a*50) //Result printf("\n The value of resistance at 50 degree C is %0.2f ohm",R50)
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clc; funcprot(0); //Example 9.1 Lift due to Circulation // Initialisation of variables D = 4; L = 12; V = 40*1.467; rho = 0.002378; W = 100/60; // Revolution per second // Calculations R =D/2; Vt = 2*%pi*R*W; T = 2*%pi*R*Vt; Lift = rho*T*V; L_total = Lift*L //Results disp(L_total,"Total lif...
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//example 3.7// //not using nor// clc //refreshes all variables// clear //clears the screen// disp('in the figure same input is given to NOR gate on both ends.') //result//
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3_1.sce
clear; clc; printf("\t\t\tExample Number 3.1\n\n\n"); // buried pipe // illustration3.1 // solution d = 0.15;// [m] diameter of pipe r = d/2;// [m] radius of pipe L = 4;// [m] length of pipe Tp = 75;// [degree celsius] pipe wall temperature Tes = 5;// [degree celsius] earth surface temperature k = 0.8;// ...
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//Chapter 3: Thermodynamic and Chemical Equilibrium //Problem: 17 clc; //Declaration of Variables d_H_n = - 51.46 // k J/mol, neutralization d_H_i = - 57.1 // k J/mol, ionization //Solution d_H = - d_H_i + d_H_n mprintf("The head of ionization for NH4OH is %.2f kJ / mol", d_H)
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clc; clear all; u0=4*%pi*1e-7; H=1e7;//magnetic field strength X=(-0.9)*1e-6;//magnetic suseptiblity M=X*H;//magnetization of material disp('A/m',M,'magnetization of material is='); B=u0*H;//magnetic flux density disp('Wb/m^2',B,'magnetic flux density is=');
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clear; clc; close; disp("Example 6.6") Kp=0.1 x=poly(0,"x") pm=1 y=4*(x)^2*pm-Kp+Kp*(x)^2 d=roots(y) for i=1:1:2 if real(d(i))>0 then disp(d(i),"(a)Mole fraction of N2 at equilibrium when pm is 1 atm:") end end //part (b) Kp=0.1 x=poly(0,"x") pm=10 y=4*(x)^2*pm-Kp+Kp*(x)^2 d=roots(y) for i=1:1...
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//Optical Fiber communication by A selvarajan //example 6.6 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; //given delta_L=1/100//error in effective interaction length P=(%pi/2*delta_L)^2//cross talk power output in W mprintf("cross talk power output=%fx10^-4W",P*10^4);//multiplication by 10^4 to ...
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function fx = f(x) fx = (exp(-(x^2)/2))/(sqrt(2*%pi)) return fx endfunction clc disp(">> Regla compuesta del trapecio") T = UN_integral_trapecio(-3,3,106) disp(T) disp(">> Regla compuesta de 1/3 de Simpson") S = UN_integral_simpson(-3,3,10) disp(S)
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---- j = 2 f = [[[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]], [[0],[0,0],[0,0,0],[0,0,0,0],[0,0,0,0,0],[1,5,10,10,5,1]]] q = [[[0]], [[0]]] s = [[[1]], [[0]]] f = [[[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]], [[0],[0,0],[0,0,0],[0,0,0,0],[0,0,0,0,0],[1,5,10,10,5,1]], [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]] q = [[[0]], ...
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// function B = makezero(B,gap) // where B is a vector and gap acts as a tolerance function B = makezero(B,gap) if argn(2) == 1 gap = 1.0e8; end temp = B(find(B)); // non zero entries of B temp = -gsort(-abs(temp),'g','d'); // absolute values sorted in descending order len = length(temp); ratio =...
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//cage and mine shaft //t is time during which stone is in motion //s=(9.81*t^2)/2 //consider motion of cage //t1 be the time taken to travel first 30 m a=0.6 //m/sec^2 t1=10 //sec //When the stone strikes //s=(0.6*(t+10)^2)/2 //solving t=3.286 //sec s=(9.81*3.286^2)/2 //m printf("\nt=%.2f sec\ns=%.2...
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clc; clear; g=9.8 //acceleration due to gravity in m/s^2 lambda=10 //wavelength in m //calculation v_g=sqrt((lambda*g*%pi)/2) mprintf("The group velocity is = %2.2f m/s",v_g)
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// Example 8.1, page no-217 clear clc printf("Theorotical Exam[ple")
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int fib(int n) begin int ret; if (2 < n) then begin ret = fib(n - 1) + fib(n - 2); end if (!(2 < n)) then begin ret = 1; end return ret; end main begin int result; int n; int count; count = 0; n = 15; do begin result = fib(count + 1); print(result); count = count + 1; ...
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//chapter 4 //broadside array printf("\n"); Gdmax=15; L=Gdmax/2; printf("the length is %gm",L); //endfire array L1=Gdmax/4; printf("\nthe length is %gm",L1); BWFN=114.6*sqrt(2/L1); printf("\nthe BWFN is %g degree",BWFN);
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errcatch(-1,"stop");mode(2);//Initilization of variables w0=0 //rad/s w=209 //rad/s t=20 //s //Calculations theta=0.5*(w+w0)*t //rad theta_rev=round(theta/(2*%pi)) //revolutions rounding off //Result printf('The flywheel makes %i revolutions',theta_rev) exit();
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//// //Variable declaration n = 2.5 //moles of ideal gas R = 0.08314 //Ideal gas constant, bar.L/(mol.K) cvm = 20.79 //Heat Capacity at constant volume, J/(mol.K) p1 = 16.6 //Pressure at point 1, bar v1 = 1.00 //Volume at point 1, L p2 = 16.6 //Pressure at point 2, bar v2 ...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 10: SINGLE-PHASE MOTORS // Example 10-4 clear; clc; close; // Clear the work space and console. // Given data (from Table 10-2) T_r = 1 ; // Rated torque in lb-ft T_s = 4.5 ; // Starting torque i...
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//skipped groundPlane_transform //skipped Manipulator1 //skipped UniversalManip //skipped CubeCompass ///////////////////////////////////////////// // object_Trim_Char_x_1_1__ ///////////////////////////////////////////// #if 0 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 #endif DX3DMATERIAL_STA...
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//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution12_4.sce') //Obtain path of data file datapath = path + ...
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function [phi,db]=phasemag(z,mod) // // Copyright INRIA mod_def='c' //continuous representation //mod_def='m' //representation modulo 360 degrees [lhs,rhs]=argn(0) if lhs==2 then db=20*log(abs(z))/log(10), end if rhs<>2 then mod=mod_def end phi1=atan(-imag(z(:,1)),-real(z(:,1))) [m,n]=size(z) z=z(:,2:n)./z(...
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//Exa1.1 clc; clear; close; //given data : FC=2000000;//in Rs v=100;//in Rs s=200;//in Rs Q=60000;//in units //Part a : Break even quantity BEQ=FC/(s-v);//in units disp(BEQ,"Break even quantity in units : "); //Part b : Break even sales BES=FC*s/(s-v);//in Rs disp(BES,"Break even sales in Rs. : "); //Par...
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clc // Part (a) m = 3 // mass of substance in kg V1 = 0.22 // Initial volume of system in m^3 P1 = 500 // Initial pressure of system in kPa P2 = 100 // Final pressure of system in kPa V2 = V1*(P1/P2)^(1/1.2) // Final volume of system dU = 3.56*(P2*V2-P1*V1) // Change in internal energy of substance in kJ/kg ...
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// Example 1.67 clc;clear;close; // Given data format('v',6); E=60;//in volt Zrotor=0.8+%i*6;//rotor impedence in ohm/phase Zstator=4+%i*3;//stator impedence in ohm/phase S=5;//in % //calculations E2=E/sqrt(3);//emf induced/phase in volt Ztotal=Zstator+Zrotor;//in ohm/phase //Part (a) I2=E2/Ztotal;//...
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b=0.3//column width in m c1=0.4//column depth in m fck=20//in MPa sigma_cbc=7//in MPa sigma_st=275//in MPa P1=1200//load on column, in kN P2=0.05*P1//weight of footing, in kN P=P1+P2//in kN q=200//bearing capacity of soil, in kN/sq m A=P/q//in sq m L1=2//in m L2=A/L1//assuming footing to be square L2=3.2//a...
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clc //initialisation of variables Qc= 9 //kW W= 7.5 //kW Qh= Qc+W Tc= 50 //C Th= 400 //C //CALCULATIONS n= W/Qh nrev= 1-((273.15+Tc)/(273.15+Th)) //RESULTS printf (' efficiency of heat engine = %.3f ',n) printf (' \n efficiency = %.3f ',nrev)
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 11") Q=2;//refrigeration effect in KW disp("properties of CO2,") disp("at 20 degree celcius,P1=57.27 bar,hf=144.11 KJ/kg,hg=299.62 KJ/kg,sf=0.523 KJ/k...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES // EXAMPLE : 2.6 : // Page number 104 clear ; clc ; close ; // Clear the wor...
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global heat_in fan_in et CObias CO eti et1 CObias = 15; eti = 0; et1 = 0; //u_old = 5; //e_old = 1; //et = 0; //CO = 0; //SP = 0; //ambient temperature
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// Example 10_10 clc;funcprot(0); // Given data T_1=-50;// °C P_1=2;// MPa T_2=40;// °C P_2=6;// MPa c_p=1.042;// kJ/kg.K c_v=0.745;// kJ/kg.K R=0.297;// kJ/kg.K M=28;// The molecular weight of nitrogen in kg/kmol // Calculation // (a) dh=c_p*(T_2-T_1);// The enthalpy change in kJ/kg du=c_v*(T_2-T_1);//...
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//Chapter-3,Example 2,Page 56 clc; close; m_alpha=6.646*10^-24 //mass of one alpha particle n= 2300 // number of alpha particles M=1*10^-6 //mass of plutonium //as -(dM/dt)= lamda*M //also (dM/dt)= n*m_alpha lamda=n*m_alpha/M t_half= 0.693/lamda //half life of Plutonium printf('the half l...
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clear ; clc; // Example 6.4 printf('Example 6.4\n\n'); printf('Page No. 147\n\n'); // given F = 1;// Fuel feed required in kg //By ultimate analysis of feed C = 0.86;// Carbon percentage - [%] H2 = 0.05;// Hydrogen percentage - [%] S = 0.001;// Sulphur percentage - [%] O2 = 0.08;// Oxygen percentage - [%] ...
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//To calculate the temperature F_E = 10; //probability in percent k = 1.38*10^-23; e = 1.6*10^-19; //conversion factor EF = 5.5; //fermi energy, eV E = EF+(EF/100); //energy, eV X = E-EF; //E-EF, eV X = X*e; //E-EF, J T = X/(k*log(F_E-1)); //temperature, K printf("temperature i...
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9_18exam.sce
//Engineering and Chemical Thermodynamics //Example 9.18 //Page no :470 clear ; clc //Given del_g_f_CH4 = -50.72 ; del_g_f_H2 = 0 ; del_g_f_H2O = -228.57 ; del_g_f_CO = -137.17 ; del_g_f_CO2 = -394.36 ; del_h_f_CH4 = -74.81 ; del_h_f_H2 = 0 ; del_h_f_H2O = -241.82 ; del_h_f_CO = -110.53 ; del_h_f_CO2 = ...
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clc,clear //Example 4.9 //To determine area of sector of a circle theta= 117*(%pi/180) //angle in radian r=3.5 //radius in m A=r*r*theta/2 //Area of sector printf('Area of sector = %.2f m^2',A)
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syms s t V q L C1 R K1 x1 x2 phi1 phi2 L1 R1 R2 L1 L2 //F=K1*(x1-x2) //0=K1*(X2-X1) + M2*s^2*X2 + K2*X2 + B2*s*X2 //F-V anolagy x1=q1; x2=q2; K1=1/C1; B=R; disp("V = 1/C1 * (q1-q2)") disp("0=1/C1*(q2-q1) + L2*s^2*q2 + q2/C2 + R2*s*q2") //F-I ANOLOGY M=C; B=1/R; K=1/L; disp("I=1/L1*(phi1-phi2)"...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Add16.tst load Add4.hdl, output-file Add4.out, compare-to Add4.cmp, output-list a%B1.4.1 b%B1.4.1 out%B1.4.1 carry%B3.1.3; set a %B0000, set b %B000...
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//Chapter 26, Example 26.1 clc //Initialisation n=24 //no of bits //Calculation ad=2**n //no of locations //Results printf("No of Locations = %d ",ad)
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//Program to find value of integral using Simpson's three eighth rule clc; clear; close; deff('y=f(x)','y=1/(1+x^3)') x0=0; xn=6; n=6; //n should be a multiple of three h=(xn-x0)/n; s=0; for i=1:3:n s=s+f(x0+(i-1)*h)+3*f(x0+i*h)+3*f(x0+(i+1)*h)+f(x0+(i+2)*h); end integral=(3*h*s)/8; printf('\nThe value of integ...
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4_3.sce
clc clear //Initialization of variables pd=15 //psia rhod=0.005//slug/ft^3 pi=150 //psia rhoi=0.03 //slug/ft^3 dz=-25 //ft vd=1000 //ft/s vi=100 //ft/s ud=200 //Btu/slug ui=250 //Btu/slug g=32.2 //ft/s^2 J=778 uff=5 //ft/s Q=50 //Btu/sec //calculations pr=pd/rhod*144 - pi/rhoi *144 zr=g*(dz) vr=(vd^2...
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//Example 15.5 Tc=-15;//Cold reservoir temperature (C) Tc=Tc+273;//Cold reservoir temperature (K) Th=45;//Hot reservoir temperature (C) Th=Th+273;//Hot reservoir temperature (K) Eff_C=1-Tc/Th;//Carnot efficiency COP_hp=1/Eff_C;//Coefficient of performance of the heat pump printf('Coefficient of performance for t...
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//CHAPTER 12 ILLUSRTATION 6 PAGE NO 316 //TITLE:Balancing of reciprocating of masses clc clear pi=3.141 rA=.25// stroke length of A piston in m rB=.25// stroke length of B piston in m rC=.25// stroke length C piston in m N=300// engine speed in rpm mRL=280// mass of reciprocating parts in inside cyli...
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m = input('Enter no. of rows of matrix') n = input('Enter no. of columns of matrix') A = zeros(m, n); B = zeros(m, n); disp('Enter elements of matrix row wise ') for i = 1:m for j = 1:n A(i, j) = input(''); end end for i = 1:n for j = 1:m B(i, j) = A(j, i); end end ...
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// Exa 1.23 clc; clear; close; format('v',6) // Given data KT = 26*10^-3; Nd = 10^15; n_i = 1.5*10^10; // The position of the Fermi level E_FminusE_Fi = KT*log(abs( Nd/n_i ));// in eV disp(E_FminusE_Fi,"The position of the Fermi level in eV is");
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// Scilab Code Ex9.2.11: Page-418(2008) clc; clear; u = 931.5; // Energy equivalent of 1 amu, MeV m_x = 4.002603; // Mass of projectile (alpha-particle), u m_y = 1.007825; // Mass of emitted particle (proton), u M_X = 14.0031; // Mass of target nucleus (N-14), u M_Y = 16.9994; // Mass of daughter nucleu...
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intro_SterrenTV.SCI
codeblock readtextfile(ScriptDir+"\TOOLS.sci"); T_scene_create; menu=T_createmenu; menu.add("","Seizoenen op Mars","MarsSeasons"); menu.add("","Start Astro3D","Astro3D"); menu.add("","Programma afsluiten","CloseApp"); menu.add("","Computer afsluiten","CloseComp"); menu.position=point(0.4,0.8,0); menu.sizex=0.4; ...
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The most skill based scenario ever.sce
Name=The most skill based scenario ever PlayerCharacters=Quakerp BotCharacters=Quaker Bot Fast Strafes.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Quakerp AddedBots=Quaker Bot Fast Strafes.bot PlayerMaxLives=3 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=mid.map MapScale=3.8 BlockProjectilePredictors=true BlockC...
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clear; chdir('J:\Stage\Simulations') getf('Modele un facteur gaussien\Cas Variable\Var_Function.sci');disp('getf done'); getf('Modele un facteur gaussien\Cas Constant\Const_Function.sci');disp('getf done'); /////////////////////////////////////////////////////////////////////////////////////////////// ////...
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clc; m=10^3; //mass in kg v=20; //velocity in m/sec h=6.63*10^-34; //planck's constant in J.sec l=h/(m*v); //calculating energy disp(l,"Wavelength in m = "); //displaying reuslt
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PSK.sci
// generating PSK waveform using Scilab function[] = PSK(data,fc,Ac) x = Ac*sin(2*%pi*fc*t) y = Ac*sin(2*%pi*fc*t + %pi) z = data mods = [] i = 0 for i = 1:length(data) if (z(i) == 1) then mods = [mods,x] else mods = [mods,y] end ...
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//Chapter 21: Antenna Measurements //Example 21-4.1 clc; //Variable Initialization D = 1 //Diameter of antenna (m) f = 10e9 //Frequency (Hz) c = 3e8 //Speed of light (m/s) //Calculations wave_lt = c/f //Wavelength (m) hpbw = 70*wave_lt/D //Half power beamwidth (degrees) mea_dist = 2*(D**2)/wave_lt ...
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//Book - Power system: Analysisi & Design 5th Edition //Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J.Overbye //Chapter-11 ;Example 11.12 //Scilab Version - 6.0.0; OS - Windows clc; clear; Vr=1.0 //system voltage in per unit I=1.0 ...
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//Initilization of variables w=10 //lb/ft L=12 //ft theta=30 //degrees //Calculation //Matrix Calculations A=[cosd(30) -cosd(30);sind(30) sind(30)] B=[0;120] X=inv(A)*B //Result clc printf('The tension in the cable is %i lb and the reaction at B is %i lb', X(1) ,X(2))
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100 dms=[d m sd] endfunction Long=75.0;//longitude in degrees GST=11+45.0/60+10.0/3600;//GSt in hr LST=26+35.0/60+42.0/3600;//L...
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N=100 M=100 T=2 L=10 c=1 tau=T/M h=L/N x=0:h:L t=0:tau:T for i=1:(N+1) u(1,i)=exp(-x(i)) end for j=1:(M+1) u(j,1)=exp(t(j)) end for m=1:M for n=1:N u(n+1,m+1)=(h/(h+c*tau))*u(n+1,m)+(c*tau/(h+c*tau))*u(n,m+1) end end surf(x,t,u)
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blkInd = get('blockList','Value'); if isempty(blkInd) then messagebox("Select a block first","littleBird"); else str = get('blockList','String'); btn = messagebox("Are you sure you want to delete " + str(blkInd),'littleBird: Confirmation','passwd',['Yes','No'],"modal"); if btn == 1 & x_dialog("Enter pas...
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// ex3.5 updated // A + B <=> C // A + C <=> D // A0 // B0 // K1 // K2 // calc // A, B, C, D // at eq function eq = model(x) A = x(1) B = x(2) C = x(3) D = x(4) eq(1) = A + C + 2*D - A0 // A balance eq(2) = B + C + D - B0 // B balance eq(3) = C - K1*A*B // equilibr...
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//Example NO.12.6 //Page No.358 //To find band gap of superconducting lead clc;clear; KB = (1.38*10^-23);//Boltzman's constant. Tc = (7.19);//Critical temperature of lead -[K]. Eg = (3.5*KB*Tc);//Energy gap of semiconductor. printf("\nBand gap of superconducting lead is %3.3e J",Eg); Eg = (Eg/(1.6*10^-19*10^...
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function mid = midpoint(a, b, n) h = computeH(a, b, n) result = 0 for i = a:h:(b-h) result = result + func(i + (h/2)) end mid = h * result endfunction function trap = trapezoid(a, b, n) h = computeH(a, b, n) result = 0 for i = a:h:(b-h) result = result + (func(i) + func(i + h)) end trap...
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clc; Vz=10; Vsmin=13; Vsmax=16; ILmin=10*10**-3; ILmax=85*10**-3; Izmin=15*10**-3; Rsmax=(Vsmin-Vz)/(Izmin+ILmax); disp('ohm',Rsmax*1,"Rsmax="); Izmax=((Vsmax-Vz)/Rsmax)-ILmin; Pzmax=Izmax*Vz; disp('W',Pzmax*1,"Pzmax=");
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//程式L3_3.m: 向量量化器之碼簿的產生// //利用LBG法產生三個不同大小與維度的碼簿// loadmatfile('LENA.mat'); //讀入一幅 512 X 512 的影像矩陣 th=0.1; //設定LBG程式停止訓練的臨界值 nc=64;nd=4; //設定碼簿大小為64，維度為4 [cb_64x4,distortion_64x4]=LBG(X,nc,nd,th); //LBG函式在本程式範例內 nc=64;nd=16; [cb_64x16,distortion_64x16]=LBG(X,nc,nd,th); nc=128;nd=16; [cb_...
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clear close clc b = 22:22:2200; y = zeros(b) for i = 1:1:length(b) y(i) = log(9)/b(i) end plot(b,y)
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//Chapter-4, Illustration 3, Page 163 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA P1=2;//Pressure at entry in MN/(m^2) T1=598;//Temperature at entry in K P2=0.36;//Pressure at exit in MN/(m^2) m=7.5;//mass fl...
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// Scilab Code Ex9.2.12: Page-418(2008) clc; clear; u = 931.5; // Energy equivalent of 1 amu, MeV // First reaction m_x = 1.007825; // Mass of projectile (proton), u m_y = 2.014102; // Mass of emitted particle (deutron), u M_X = 208.980394; // Mass of target nucleus (Bi-209), u M_Y = 207.979731; // Mass...
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model.sce
function mm=mmodel() M=0.36; //[kg] Q=1.19e-4; //[Hm] Z0=3.32e-3; //[m] Zequ=0.005; //[m] Iequ=2.03; //[A] aa=Q*Iequ^2/(M*(Zequ+Z0)^3); bb=Q*Iequ/(M*(Zequ+Z0)^2); A=[0 1;aa 0]; B=[0;-bb]; C=[1 0]; D=0; mm=syslin('c',A,B,C,D); endfunction function pm=pmodel() m=...