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// Exa 3.1 clc; clear; close; // Given data N= 100; A=4*3;// in cm^2 A=A*10^-4;// in m^2 i=20;// in mA i=i*10^-3;// in A B=0.05;// in T T=N*i*B*A;//in Nm disp(T,"Torque developed by the coil in Nm")
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clc; clear;close; exec('./ode1.sci'); //EI = 250e9; // szywnosc na zginanie, Nmm^2 E = 210000 //N/mm^2 I = 1940e4 //mm^4 EI = E*I _q = 10000; // sila skupiona, N q=_q/1000 L = 4000; // dlugosc belki, mm n=10; A = zeros(n,n); for i =1:n if i == 1 || i == n then A(i,i) = 1; else A(i,i-1...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh,Chapter 1,Example 22") m=5;//mass of mixture of gas in kg P=1.013*10^5;//pressure of mixture in pa T=300;//temperature of mixture in k M1=28;//molecular weight of nitro...
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Checking that a simple verbatim works Single is for Single spacing Verbatim allows text that matches the Itemize uses ticks to indicate items Center allows a block to be centered Does this start off correctly with 1
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//Example 1.20: Addition of two unsigned numbers 14-10. clc; x=bitcmp(10,4) //finds complement of 5 y=1; u=x+y //1 is added to the complement w=14 z=w+u; r = dec2bin(z); // binary equivalent of decimal number disp('The binary number is = '); disp(r) disp('The msb is discarded, and binary number becomes') di...
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function x=%p_det(a) // Copyright INRIA x=determ(a)
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//pathname=get_absolute_file_path('1.22.sce') //filename=pathname+filesep()+'1.22-data.sci' //exec(filename) //Total mass of system of gas(in kg): M=5 //Compostion of Nitrogen: n=0.80 //Compostion of Oxygen: o=0.18 //Composition of Carbon dioxide: c=0.02 //Compression ratio for Oxygen: ro=1.4 //Compression...
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clc //variable initialisation V=440 //Supply voltage in volts p=6 //number of poles f=50 //Supply frequency in Hz N1=970 //speed in rpm N2=750 //speed in rpm N3=850 //speed in rpm n=3.5//Turns Ratio R1=0.2 R2=0.15 X1=0.4 X2=0.4 aa1=170//Firing Angle aa2=140//Firing Angle s=0.3 //solution Ns=(120*f)/...
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//clear// clear; clc; //Example 8.4 //Given q = 75/3600 ; // [m^3/s] rho = 62.37*16.018; //[kg/m^3] From Appendix 4 Cv = 0.98; g = 9.80665; //[m/s^2] Sw = 1; Sm = 13.6; h = 1.25; //[m] //(a) //Using Eq.(2.10) delta_p = g*h*(Sm-Sw)*rho ; //[N/m^2] //Using Eq.(8.36), neglecting the effect of beta Sb = q...
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clc clear //Conditions at 9 bar P=9; //in bar Tsat=175.4+273; //in K Vg=0.215; //in m^3/kg Hf=742.8; //in kJ/kg Hfg=2031.1; //in kJ/kg Hg=2773.9; //in kJ/kg T2=250+273; //in K x=0.91; //Dryness Fraction V1=x*Vg; V2=0.2696; ...
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clear //Given I=2.0 a1=20*10**-2 x=0.15 A2=0.3*10**-2 //Calculation // u=4*%pi*10**-7 B1=(u*I*a1**2)/(2.0*(a1**2+x**2)**1.5) a=B1*%pi*A2**2 M=a/I //Result printf("\n (i) Flux linking the bigger loop is %0.1f ",a*10**11) printf("\n (ii) Mutual induction between the two loops is %0.2f !0**-11 H",M*10**11)
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//pathname=get_absolute_file_path('4.04.sce') //filename=pathname+filesep()+'4.04-data.sci' //exec(filename) //Source temperature(in K): T1=827+273 //Sink temperature(in K): T2=27+273 //Temperature in the refrigerator(in K): T3=-13+273 //Heat input(in kJ): Q1=2000 //Net work available(in kJ): W=300 //Rate ...
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% test file for residue package residue(x/(x^2-2),x,sqrt(2)); poleorder(x/(x^2-2),x,sqrt(2)); residue(sin(x)/(x^2-2),x,sqrt(2)); poleorder(sin(x)/(x^2-2),x,sqrt(2)); residue(1/(x-1)^m/(x-2)^2,x,2); poleorder(1/(x-1)/(x-2)^2,x,2); residue(sin(x)/x^2,x,0); poleorder(sin(x)/x^2,x,0); residue((1+x^2)/(1-x^2),x,1...
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clear; clc; printf("\t\t\tchapter1_example2\n\n\n"); // determination of thermal conductivity of aluminium k_ss=14.4; // thermal conductivity of stainless steel in [W/m.K] printf("\nThe thermal conductivity of stainless steel is %.1f W/m.K",k_ss); dt_ss=40; // [K] dt_al=8.65; // [K] dz_ss=1; // [cm] dz_al=3; /...
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clc clear //Input data E=10//Energy of the photon in eV h=6.625*10^-34//Plancks constant in J.s c=3*10^8//Velocity of light in m/s e=1.6*10^-19//Charge of electron in Columbs //Calculations l=((h*c)/(E*e))/10^-10//Wavelength of the photon in angstroms //Output printf('The wavelength of the photon is %3.0f...
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//Calculations on Gas engine clc,clear //Given: d=24,l=48 //Bore and stroke in cm D_b=1.25 //Effective diameter of the brake wheel in m P=1236 //Net load on brake in N N=77 //Average engine explosions in min N1=226.7 //Average speed at output shaft in rpm imep=7.5 //Indicated mean effective pressure in bar Vg1...
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//Exa3.9 clc; clear; close; // given data n_i=2.5*10^13;// in /m^3 miu_e=3800;// in cm^2/V-s miu_h=1800;// in cm^2/V-s e=1.6*10^-19;// in C (charge of electrons) sigma_i=n_i*e*(miu_e+miu_h); disp("Intrinsic conductivity is : "+string(sigma_i)+" /ohm-cm"); // Let Number of germanium atoms/cm^3 = no_g no_g=4...
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clear; clc; close; t=-1:0.001:1 w=2*%pi; figure; n_har=5 n=1:n_har b=2 ./(n*%pi); x=0.5+b*sin(w*n'*t) plot(t,x) figure; n_har=10 n=1:n_har b=2 ./(n*%pi); x=0.5+b*sin(w*n'*t) plot(t,x) figure; n_har=50 n=1:n_har b=2 ./(n*%pi); x=0.5+b*sin(w*n'*t) plot(t,x)
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clear; clc; d=12;Ro=500; D=(d-3)/3; N=round(10^(D/20)*1000)/1000; R1=Ro*(N+1)/(N-1); R2=Ro*(round((N*N))-1)/(2*N); printf("The desired attenuator will be:\n"); printf("R1 = %f ohms\n",round(R1)); printf("R2 = %f ohms\n",round(R2)); //the difference in result of R1 is due to erroneous value in textbook. disp(...
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//ch-9 page 305 pb-3 // // l1=100.5,l3=75,l4=50.5, t1=30.5,t2=45,t3=40.5,t4=60,t5=40.25, L1=l1*cos(t1*(%pi/180)) L3=-l3*cos(t3*(%pi/180)) L4=-l4*cos(t4*(%pi/180)) printf("\n latitude of AB,CD,DE are %0.3f %0.3f %0.3f",L1,L3,L4) D1=l1*sin(t1*(%pi/180)) D3=-l3*sin(t3*(%pi/180)) D4=-l4*sin(t4*(%pi/180)) printf("...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function [y,Index,MaxCo] = SSSeSampling2pol(x1,y1,xref,Ind) Ampl=[]; for j=-45:45 x=x1*cos(j*%pi/180)-y1*sin(j*%pi/180); y=x1*sin(j*%pi/180)+y1*cos(j*%pi/180); Ampl=[Ampl mean(abs(x)+abs(y))]; ...
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errcatch(-1,"stop");mode(2);// Example 2.19, page no-40 awt=63.5*10^-3//g avg=6.023*10^26 r=1.273*10^-10 n=4 a=4*r/sqrt(2) d=n*awt/(avg*a^3) printf("The density of copper is %.4f gm/m^3",d) exit();
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clear; clc; //page no.45 l = 8;//feet b = 10;// feet F_h = 0.5*l*b*62.4*(b+2.5);// lb x = 83.2/(40*(b+2.5));// feet F_v = (b+5)*62.4*40-(l*62.4*(25 - 0.25*%pi*25));// lb F = sqrt(F_h^2 + F_v^2);// lb e = (2680*3.91 + 37440*(0.25*b))/F_v ;// feet theta = 180*atan(F_v/F_h) /%pi;// degrees x_p = 0.25*b-x;//...
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// This is signal consisting of the sum of periodic signals whose individual // fundamental periods are 3 and 5 // the fundamental period of total signal is 15 N0=15 n=[0:1:N0-1]'; xt=[1 0 0 0 0 1 0 0 0 0 1 0 0 0 0]'; y=cosd(2*180.*n/3)+xt Y=fft(y)/N0 disp(Y,'The DTFS harmonic function =')
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p asdf fdsa 0 0 3 5 0 1 3 6 3 7 quit q
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//ex13 theta=45*%pi/180; x0=0; vx0=30*cos(30); z0=0; vz0=-30*(sin(30)); x1=ode([x0;vx0],0,theta,xf); z1=ode([z0;vz0],0,theta,zf);
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//Chapter 3 //Example 3_18 //Page 61 clear;clc; l=[20 40 50 35 70 40]; t=[8 3 5 3 3 2]; scf(0); y=[20 20 20 20 20 20 20 20 40 40 40 50 50 50 50 50 35 35 35 70 70 70 40 40]; bar(y, 1, 'red'); xlabel('Time in hours'); ylabel('Load in MW'); xgrid(0); ugpa=0; for i=1:6; ugpa=ugpa+l(i)*t(i); end; printf("Units genera...
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clc; p=200; // rated KVA of transformer n=0.98; // efficiency t1=20; // temperature after one hour of operation t2=34; // temperature after two hour of operation r=1/3; // ratio of full load core losses to ohmic loss disp('case a'); t=[(t2/t1)-1]; th=-1/log(t); // heating time constant in hours theta=t1/(1-ex...
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function [o]=impulseplot(varargin) //Calling Sequence //impulse(sys) //impulse(poly1,poly2) //impulse(sys,Tfinal) //impulse(sys,Tvector) //impulse(sys1,sys2,...,T) //impulse(sys1,'r',sys2,'y--',sys3,'gx',..) // //Parameters //sys:- sys can be SISO array,MIMO system or SISO either discrete or continuous //p...
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// Caption: Finding reluctances and flux clear; close; clc; U_r=70000; U_o=4*%pi*10^-7; function [R_c]=reluctance_core(l,A) R_c=l/(U_r*U_o*A); endfunction disp(reluctance_core(.3,9*10^-4),'Reluctance of the core=') function [R_g]=reluctance_gap(g,A) R_g=g/(U_o*A); endfunction disp(reluctance_gap(...
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// Chapter8 // Page.No-320, Figure.No-8.12 // Example_8_3 // Output frequencies // Given clear;clc; Vin=2; // Input voltage Fo1=2*10^3; // Output freq Fo when Vin=2V Fo2=1*10^3; // Output freq Fo/2 when Vin=2V printf("\n Output freq Fo is = %.f Hz \n",Fo1) // Result printf("\n Output freq Fo/2 is = %.f Hz \n"...
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clc // Given that d = 1.2 // distance of screen from slit in meter x = 3.7e-3 // distance between first maxima to central maxima in meter b = 2e-4 // slit-width in meter // Sample Problem 14 on page no. 2.43 printf("\n # PROBLEM 14 # \n") lambda = (x * b) / d // calculation for wavelength of light printf("\n Standard ...
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//author :Rutuja moharil // zero pole gain plot //returns the zeros z, poles p, and gain(s) k and sample time Ts of the zero-pole-gain SISO and MIMO model sys. function[x,t,o,dt]= zpkdata(sys,varargin) n=length(varargin); //length of the input vairiable matrix select typeof(sys) //check the system t...
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clear // // // //Variable declaration lamda=5*10**-5 //wavelength(cm) k=2 //order theta=30*%pi/180 //angle(radian) //Calculation e=k*lamda/sin(theta) //number of lines(cm) n=1/e //number of lines per centimeter //Result printf("\n number of lines per centimete...
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clc; clear; printf('Example 9.34\n'); T1=420;//temperature of steam k=0.1;//Thermal conductivity T2=285; //Ambient temperature h=10;//the coefficient of heat transfer from the outside of the lagging to //the surroundings //determining Q/l from equation 9.21 and equating it to heat loss from the //out...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.387573D+00 ...
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function [U, ind] = Cholesky(A) eps = 1.0e-8 n = size(A,1) U = zeros(n,n) for k = 1:n if k==1 then t = A(k,k) else t = A(k,k) - U(1:k-1,k)'*U(1:k-1,k) end if t <= eps printf("Matriz no definida positiva.\n") ind = 0 return end U(k...
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U=3800 //J/mol P=1 //atm Vcap=24.63 //L/mol ndot=250 //Kmol/h
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//example 8.4(a)// clc //clears the screen// clear //clears the variables// disp('Refer to figure. Q is initially 0, this makes J and K inputs to be initially 1 and 0 respectively. With the first trailing edge of clock input, Q goes 1 state. Thus J and K acquire logic status of 0 and 1 respectively. With the next ...
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/* * By: Jatin Kumar Mandav * * Trapezoidal Method: In Numerical Analysis, the trapezoidal rule is * a technique for approximating the definite integral. * The Trapezoidal Rule works by approximating the region under the * graph of the function f(x) as a trapezoid and calculating its area....
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// CALCULA UMA APROXIMACAO x(k), PARA UMA RAIZ DE f NO INTERVALO [a,b] // f: função criada em outro arquivo // [a,b]: intervalo no qual f(a)*f(b) < 0 // eps1: precisão utilizada no critério de parada function bissecao(f,a,b,eps1) if ((f(a).*f(b))>0.0) then printf("\n \n") printf("f( %g )*f( %g )>0 \n \n"...
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clear; clc; close; n=0:100; w0=1; N=2*%pi/w0; x=exp(%i*w0*n); y=exp(%i*w0*(n+N)); if ceil(x)==ceil(y) then disp('e^iwn is periodic with N=2*pi/W0') else disp('nonperiodic') end
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//value// s=%s; H=syslin('c',1/((s+3)*s*(s+5))); evans(H,100)
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EI=70000*2000;//given in N.mm^2 L=2000;//in mm rho=1;//in Kg/mm^3 A=1;//in mm^2
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// Exa 1.6 clc; clear; close; format('e',9) // Given data sigma = 100;// in (ohm-m)^-1 n_i = 2.5*10^13;// in /cm^3 miu_n = 3800;// in cm^2/V-s miu_p = 1800;// in cm^2/V-s q = 1.6*10^-19;// in C // Conductivity of a p-type germanium, sigma = q*p*miu_p or p = sigma/(q*miu_p);// in /cm^3 disp(p,"Concentration...
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errcatch(-1,"stop");mode(2);//Chapter 7, Example 7.5, Page 199 // Activity of the sample lambda = 7.466*10**-5 m = 2 Na = 0.6022*10**24 A = 55 sigma = 13.3*10**-24 delta = 10**13 t = 120 Activity= lambda*(m*Na/A)*sigma*delta*t printf("Activity = %e Bq\n",Activity) //Answers may vary due to round off error exit();
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//ques-34.18 //Calculating moles of CO formed clc w=302;//wavelength (in nm) QY=0.54; E1=15000;//energy absorbed (in erg/mol) E=(1.196*10^15)/w;//energy of 1 einstein (in erg/mol) n=E1/E;//number of einsteins absorbed N=QY*n; printf("Moles of CO formed are %.2f*10^-9.",N*10^9)
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clc //initialisation of variables P=100 //lbf/in^2 T=600 //F A=20000//lbm/hr P1=0.545 //lbf/in^2 P2=54.5 //lbf/in^2 S=1.7581 //Btu/lbm-R h0=1329.1 //Btu/lbm T1=460//F h=1264.0 //Btu/lbm V=w1*sqrt(h0-h)//ft/sec v1=9.961 //lbf/in^2 PE=20 //lbf/in^2 sE=1.7581 //Btu/lbm-R hE=1174.9 //Btu/lbm vE=21.28 //lb...
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assert "World"
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u=0.005//kg/m.s(viscosityb of liquid) p=850//kg/cm^3(density of liquid)
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function catdemo_ex() a1 = uint8([1 2 3 ;4 5 3;]); a2 = uint8([10 11 14; 21 19 29 ]); y = cat(2,a1,a2); disp(y); endfunction
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ns=2*10^12; E1=(1.11*10^-19)*((ns)^(2/3)); E2=(1.95*10^-19)*((ns)^(2/3)); printf('\n The value of E1 is %feV',E1*10^10); printf('\n The value of E2 is %feV',E2*10^10); Ef=0.24418; nE=2.79*10^13; a=0.026; //say a=K*T/q ns1=nE*a*log(1+exp((Ef-(E1*10^10))/a)); ns2=nE*a*log(1+exp((Ef-(E2*10^10))/a)); printf('\n ...
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//Obtain path of solution file path = get_absolute_file_path('solution12_12.sce') //Obtain path of data file datapath = path + filesep() + 'data12_12.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the torque capacity of each pad mt (N-m) mt = Mt/n //Calculate the friction radius Rf (mm) Rf = ...
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clc //initialisation of variables W= 4500 //tonf b= 6 //ft d= 2.5 //ft s= 0.83 //CALCULATIONS I= b*d^3/12 r= 3*s*I*1000/(W) //RESULTS printf ('Reduction caused by three compartments= %.3f mmE',r)
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clc; clear; function y=f(x) y=sin(10*x)+cos(3*x); endfunction count=1; for i=1:0.05:5 val(count)=i; func(count)=f(i); count=count+1; end plot2d(val,func) xtitle("x vs f(x)",'x','f(x)')
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//i/p arg R contains only zeros R=[0 0 0 0 0 0 0]; W = rootmusic(R,2); disp(W); //output //Warning : //matrix is close to singular or badly scaled. rcond = 0.0000D+00 //computing least squares solution. (see lsq). // // !--error 4 //Undefined variable: iterM //at line 46 of function nnls called by : //at lin...
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//Example 10.3 clc clear m = 5; n = 5; u = zeros(m,n); u(m,:) = [50 100 100 100 50]; u0 = u; I = ceil(m/2); J = ceil(n/2); u(J,I) = (u0(J-2,I-2) + u0(J-2,I+2) + u0(J+2,I-2) + u0(J+2,I+2)) / 4; for j = [J-1 J+1] for i = [I-1 I+1] u(j,i) = (u(j-1,i-1) + u(j-1,i+1) + u(j+1,i-1) + u(j+1,i+1...
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function su=comptage(A) su=0; i=1; for i=3:length(A)-3 do if A(i+1)<A(i)&A(i+2)<A(i)&A(i-1)<A(i)&A(i-2)<A(i) then su=su+1; end end endfunction function [vect]=test(ligne,colonne) minim=min(colonne); maxim=max(colonne); n=max(size(ligne)); if maxim-minim<50 then vect=0 else k=0...
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s=%s sys=syslin('c',k/((s+16)*(s^2+2*s+2))) evans(sys) //stability [Ki,s]=kpure(sys) disp("k marginal is") disp(Ki)
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############################################################################# ## #A nq.tst May 1994 Werner Nickel #A & Frank Celler ## ## set the size of the screen to a known value ############################## s...
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clear // // // //Variable declaration e=1.6*10**-19 //charge(coulomb) r0=0.281*10**-9 //equilibrium distance(m) a=1.748*10**-28 //madelung constant(J m**2) n=9 //repulsive exponent value m=1 //Calculations Ur0=-a*(1-m/n)/(e*r0**m) //cohesive energy of NaCl(eV) //Result
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clc; disp("Example 1.1") R=0.12 // manometer reading in m densitym= 13600 // of mercury in kg/m^3 densityw= 1000 // of water in kg/m^3 g=9.81 // acceleration due to gravity in m/s^2 p=R*g*(densitym-densityw) disp(" Pressure difference is ") disp(p) disp(" N/m^2 ")
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clc clear //input y1=0.01-(%i*0.03);//first admittance in mho y2=0.05+(%i*0);//second admittance in mho y3=%i*0.05;//third admittance in mho //three admittances are connected in parallel v=250;//supply voltage in volts //calculations y=y1+y2+y3;//total admittance in mho Y=(((real(y)^2)+(imag(y)^2)))^0.5;/...
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// Ex2_4 Page:33 (2014) clc; clear; h = 6.626e-034; // Planck's constant, Js c = 3e+08; // Speed of light, m/s lambda = 0.2e-09; // Wavelength of photon, m p = h/lambda; // Momentum of the photon, kgm/s m = p/c; // Effective mass of photon, kg printf("\nThe momentum of the photon = %3.1e kg-m/s", p); pr...
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// Scilab code Ex7.6: Pg:293 (2008) clc;clear; dE = 15/1e+006; // Increase in energy per revolution, MeV n = 1e+006; // Number of revolutions E = dE*n; // Final energy of an electron after 10e+06 revolutions, MeV printf("\nThe energy of an electron undergoing revolutions = %2.0f MeV ", E); // Result ...
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clc; clear; z=1000;//m Ma=1.5; T=20;//degree C //alpha=atan(z/x), x=V*t,and Ma=(1/sin(alpha)); where alpha is the angle of the Mach cone //V=Ma*c c=343.3;//m/s found from the value of temperature V=Ma*c;//m/sec t=z/(Ma*c*tan(asin(1/Ma)));//sec disp("sec",t,"The number of seconds to wait after the plane passes...
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//Example 2.31: Resistance and electromotive clc; clear; close; //given data : i1=20;// in mA i2=400;// in mA i3=i1/i2; K1=i1/i3; v1=19.5;// in mV v2=23.4;// in mV x1=v1/K1;// y=100;//mV k2=y/i3;// x2=v2/k2;// A=[1 -x1;1 -x2]; B=[v1;v2];// X=A\B;// disp(X(1,1),"electromotive force is,(mV)=") disp(X(2,1),"resistance is ...
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//Find roots function[]=polyroot() x=poly([-13,-5,0,-3,1],'x','c') disp('Equation is') disp(x) disp('Roots are') b=roots(x) disp(b) x=poly([-1,0,0,0,0,0,0,0,0,0,0,1],'x','c') disp('Equation is') disp(x) disp('Roots are') c=roots(x) disp(c) endfunct...
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//Example 4.9, page 124 clc disp('Part a') mu=207//207*me M=1836//183*me u=(mu*M)/(mu+M) D=(1/u)*5.3*10^-11 printf("\nMuon nucleus seperation is %e m ",D) disp('Part b') E=-u*13.6 printf("\n Binding energy is %f ev ",E) disp('Part c') R=109737//in cm lambda=(1/u)*(1/0.75)*(1/R) printf("\n Wavelength is %e cm ",lambda)...
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function [x]= soma(a,b) x = a+b; endfunction
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//Example 6.6 clc;clear;close; x=[1 1 0 1 1];xmin=-2;nx=xmin:length(x)+xmin-1; h=[1 -2 -3 4];hmin=-3;nh=length(h)+hmin-1; //Calculation of linear convolution y=convol(x,h); ymin=xmin+hmin;ny=ymin:length(y)+ymin-1; disp(x,'First Sequence is x(n): '); disp(h,'Second Sequence is h(n): '); disp(y,'Output seq...
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clc p1=1000; //kPa p2=100; //kPa p4=p1; p3=p2; E=2000; // Refrigerating effect produced in kJ/min T3=268; //K T1=303; //K y=1.4; disp("(i) Mass of air circulated per minute") T2=T1*(p2/p1)^((y-1)/y); e=cp*(T3-T2); //Refrigerating effect per kg; kJ/kg m=E/e; disp("m=") disp(m) disp("kg/min") dis...
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clear; clc; //case1 V2=2300; S=150; V1=11500+V2; a=(V1-V2)/V2; //two winding transformer ratio aa=a+1; //autotransformer ratio output=((1+a)/a)*S; mprintf("output for 1 case %f KVA\n",output); //case 2 V11=13.8; V22=11.5; a1=(V11-V22)/V22; output1=((1+a1)/a1)*S; mprintf("output for 2 case %f KVA\n",o...
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//example 17 clear beta1=25; colres=2.5*10^3;//ohm vcc=10;//volt vce=-5;//volt ic=-(vcc+vce)/colres; ib=ic/beta1; rb=vce/ib; stability=(1+beta1)/((1+beta1)*((colres)/(colres+rb))); disp("base resistance = "+string((rb))+"ohm");//correction in book disp("stability = "+string((stability)));
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// Examle 16.4 E1=220; // Induced emf at N=750 rpm E2=250; // Induced emf (i.e E=250) N1=750; // Speed of mechine at E1=220 N2=(E2/E1)*N1; // Speed at Constant emf E2=250 disp('Speed at Constant emf = '+string(round(N2))+' rpm'); ...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.18(PAGENO 499)"); //given Px_1 = 1/4;//probability of first symbol Px_2 = 1/5;//probability of second symbol Px_3 = 1/5;//probability of third symbol Px_4 = 1/10;//probability of four...
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function wpar=do_window(wpar) // Copyright INRIA wd=wpar(1);w=wd(1);h=wd(2); nm=wpar(2)(1) while %t do [ok,nm,h,w]=getvalue('Set parameters',[ 'Diagram name'; 'Window height'; 'Window width'],list('str',1,'vec',1,'vec',1),[nm;string([h;w])]) if ~ok then break,end if or([h,w]<=0) then message('Pa...
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clear; clf; dt = 1/1000; t = -1:dt:1; A = 1; f = 1; Theta = 0; x = A*cos(2*(%pi)*f*t + Theta); plot(t,x); xgrid(5); xlabel("T", "fontsize", 5); ylabel("X", "fontsize", 5); title("Continuous time cosine wave", "fontsize", 4);
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clear clc xset('window',3) xtitle("My Graph","X axis","Y axis") x=linspace(0,3,30) y1=-sec(x) y2=cosh(x) plot(x,y1,"o-") plot(x,y2,"+-") legend("-sec(x)","cosh(x)") disp("from the graph,it is clear that the point of intersection is nearly x=2.3 ")
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//To determine the ratio of sheath loss to core loss of the cable clear clc; R=2*.1625; Rs=2*2.14; M=314; w=6.268*10^-4; r=Rs*M*M*w*w/(R*((Rs^2)+(M*M*w*w))); mprintf("ratio=%.4f \n",r);
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// Scilab Code Ex7.6: Page-7.27 (2004) clc;clear; A = 100e-4; // Area of parallel plates, squaremetre d = 1e-2; // Distance between plates, metre eo = 8.854e-12; // Permittivity of the free space, farad per metre V = 100; // Potential, volt C = eo*A/d; // Capacitance, farad Q = C*V; ...
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//Example 7_13 clc(); clear; //To calculate the refractive index of the core NA=0.39 delta=0.05 n1=NA/sqrt(2*delta) printf("The refractive index of the core is %.3f",n1)
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// Scilab code Ex4.21 : Pg:159 (2008) clc;clear; D = 50; // The distance between the slits and the screen, cm d = 0.1/2; // Half the separation between two slits, cm mu = 1.58; // The refractive index of mica sheet x0 = 0.2; // The shift of interference pattern, cm // As x0 = D/(2*d)*(mu - 1)*t, solvi...
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clear // Variable Declaration V_1byV_2=2// Volumetric ratio (given) p_1=1.01325// The atmospheric pressure in bar(101325 kPa) // Calculation p_2=V_1byV_2*p_1// The new pressure in bar printf("\n The new pressure,p_2= %0.4f bar(abs.)",p_2)
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clc clear //Input data T3=1500;//Upper temperature limit of a otto cycle in K T1=300;//Lower temperature limit in K a=0.4;//Rate of flow of air through the cycle in kg/min Cv=0.718;// //Calculations T2=(T1*T3)^(1/2);//Temperature at point 2 in K T4=T2;//Temperature at point 4 in K W=Cv*((T3-T2)-(T4-T1));//W...
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//EXAMPLE 2.33 ,stability of finite impulse response. //h[i]=impulse response of LTI system. clear; clc; n= -5:1/100:5; a= input('value of a'); N1=input('lower limit'); N2=input('upper limit'); for i=1:length(a) if (n(i)<N1 & n(i)>N2) h(i)=0; else h(i)=a^n(i); S=sum(h); end end if(S...
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// determine velocity of whirl at inlet and diameter of the wheel at inlet // ex 6.1 pgno.143 clc H=8 // head g=9.8 // gravitional acceleration t1=0.96 // peripheral volocity at inlet t2=0.36 // flow velocity u1=t1*sqrt(2*g*H) mprintf('Peripheral velocity u1= %f m/s',round(u1)) vlf= t2*sqrt(2*g*H) mprintf('\n...
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11_4_Crossflow_finned_HeatX2.sce
clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 11.4 Page 695 \n'); //Example 11.4 // Heat Transfer Rate and Fluid Outlet Temperatures //Operating Conditions Thi = 250+273 ;//[K] Hot Fluid intlet Temperature Tci = 35+273 ;//[K] Cold Fluid in...
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//Section-6,Example-1,Page no.-P.40 //To find by how much is the chemical potential of benzene reduced for the given conditions. clc; x_B=0.10 x_A=1.0-0.10 R=8.314 T=298 mu=R*T*log(x_A) //mu=mu_A-mu_Abar disp(mu,'Required chemical potential(Jmol^-1)')
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//Ex 5.2a clc; syms T; disp('x(t)=1+cos(20%pi*t)'); w=20*%pi; f=w/(2*%pi); T=1/(2*f); disp(T,'minimun sampling interval');
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// This file is released under the 3-clause BSD license. See COPYING-BSD. // Generated by builder.sce : Please, do not edit this file // ---------------------------------------------------------------------------- // libskeleton_imagepr_path = get_absolute_file_path('loader.sce'); // // ulink previous function with sam...
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//Realiza la substitucion hacia atras //A es matriz de nxn y debe ser triangular superior //b es el vector de terminos independientes //x es el vector solucion function [x] = sub_atras(A,b) n = length(b); x = zeros(n); x(n) = b(n)/A(n,n); for i=(n-1):-1:1 suma = 0; for j=(i+1...
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clc; v1=100; //speed in km/hr v2=60; //speed in km/hr v3=80; //speed in km/hr t1=2; //time in hr t2=2; //time in hr t3=1; //time in hr disp(((v1*t1)+(v2*t2)+(v3*t3))/(t1+t2+t3),"Velocity in km/hr = "); //displaying result
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/07/StackArithmetic/SimpleAdd/SimpleAdd.tst load SimpleAdd.asm, output-file SimpleAdd.out, compare-to SimpleAdd.cmp, output-list ...
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clc //initialisation of variables q=120//kg b=300//mm a=40//m //CALCULATIONS P=q*a/b//kg //RESULTS printf('the magnitude of force=% f kg',P)
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//Chapter 19, Problem 11 clc; R1=10e3; //resistance 1 R2=10e3; //resistance 2 R3=100e3; //resistance 3 Rf=100e3; //feedback resistance V1=5e-3; //input voltage 1 V2=5e-3; //input voltage 2 V3=50e-3; ...
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////Ex 7.1 clc; clear; close; format('v',9); th=4;//ms VCC=10;//V C=0.05;//micro F(choosen between 0.01<=C<=1) R=th*10^-3/(1.1*C*10^-6)/1000;//kohm C1=0.01;//micro F(assumed) C2=0.01;//micro F(choosen between 0.01<=C<=1) R2=th*10^-3/(10*C2*10^-6)/1000;//kohm C3=10;//micro F disp("Design values are : "); d...
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clear; clc; disp('Example 4.17'); // aim : To determine the // (a) mass of steam in the vessel // (b) final dryness of the steam // (c) amount of heat transferrred during the cooling process // Given values V1 = .8;// [m^3] P1 = 360;// [kN/m^2] P2 = 200;// [kN/m^2] // solution // (a) // a...