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function [] = kiks_draw_roundobj(id) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- global...
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errcatch(-1,"stop");mode(2);// Example 2.3 page no-47 e_ar=11.6 //eV e_Na=5.12 //eV V=e_ar-e_Na e=1.6*10^-19 //C m=9.1*10^-31 //kg v=sqrt(2*e*V/m) printf("Velocity, v=%.2f*10^6 m/sec",v/10^6) exit();
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-2, Illustration 6, Page 37 //Title: Calculation of composition, average molecular weight and density //============================...
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errcatch(-1,"stop");mode(2);//Example sec 2.4.2 //eigen values ;; A=[0 6 -5;1 0 2;3 2 4] B=spec(A) disp(B,"Eigen values=") exit();
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// The equation 27*x^5+27*x^4+36*x^3+28*x^2+9*x+1==0 has real roots. // the graph of this function can be observed here. xset('window',26); x=-2:.001:3; // defining th...
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main var a, b, c, d, e, f; { let a <- 22; let b <- 33; let c <- 44; let d <- 55; let e <- 66; let f <- 77; let a <- a + call inputnum(); let b <- b + a; let c <- d * b; let d <- c / a; let e <- a + b + c + d * 22 - 18; let f <- 86 / 22 + a; if a != b then if b != c then if c != d t...
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clear //Given q=5*10**-9 x=0.15 //m r=0.1 //m a=9*10**9 //Calculation E=(a*q*x)/((r**2+x**2))**1.5 //Result printf("\n Intensity of the electric field is %0.0f N/C",E)
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// Scilab code Exa6.7.4 : To calculate the frequency of alternating field applied to dees. Page 272(2011) q = 1.6e-019; // Charge of the proton, C m = 1.67e-027; // Mass of the proton, Kg B = 1.4; // Magnetic field , tesla f = B*q/(2*%pi*m*10^06); // Frequency of the applied field, tesla printf("\n Frequency of th...
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// ==================================================================== // Allan CORNET // DIGITEO 2010 // ==================================================================== // <-- CLI SHELL MODE --> // ==================================================================== r = xls_NewExcel(); assert_checktrue(r); r ...
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clear; //clc(); // Example 6.5 // Page: 115 printf("Example-6.5 Page no.-115\n\n"); //***Data***// printf("This is a theoratical question and there are no any numerical components. For the derivation, refer to page no 115 of the book.");
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clc //Given that r = [2,2,2*sqrt(2)] // sample Problem 2a Page No. 176 printf("\n \n\n # Problem 2a # \n") r_magnitude = sqrt ( 2^2 + 2^2 + (2*sqrt(2))^2) cos_x = ( 2 / r_magnitude) cos_y = ( 2 / r_magnitude) cos_z = ( 2.8284 / r_magnitude) printf(" \n Directional cosine in X - axis is %f ", cos_x) printf...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 9 //Chemical Reaction Equilibria //Example 15 clear; clc; //Given: //Reaction: N2 + 3H2 --> 2NH3 K = 2*10^-4; //equilibrium constant of reaction P = 20; //pressure in bar //To determine conversion of nitrogen affected by argon //Mole f...
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clc //initialisation of variables D= 10 //ft H1= 17 //ft H2= 5 //ft d= 3 //in Cd= 0.62 g=32.2 //ft/s^2 //CALCULATIONS t1= (2*%pi*D^2/4)*(sqrt(H1)-sqrt(H2))/(Cd*sqrt(2*g)*%pi*(d/12)^2/4) t2= %pi*(14/15)*H2^(5/2)*4/(Cd*%pi*(d/12)^2*sqrt(2*g)) t= t1+t2 //RESULTS printf ('time required to empty the vessel =...
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// Example 3.2: calculate the input impedence, output impedence, voltage gain and current gain clc, clear; Hie=3.2; // the h-parameters of the transistor in kilo-ohm Hfe=100; // the h-parameters of the transistor R1=40; // resistance in kilo-ohm R2=4.7; // resistance in kilo-ohm; Rc=4; // resistance in kilo-ohm...
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//EXAMPLE 1-48 PG NO-39-40 R1=6.8; //Resistance R2=15; R3=10; RA=(R1*R2)/(R1+R2+R3); disp('i)RESISTANCE = '+string (RA)+' ohm'); RB=(R1*R3)/(R1+R2+R3); disp('ii)RESISTANCE = '+string (RB)+' ohm'); RC=(R2*R3)/(R1+R2+R3); disp('iii)RESISTANCE = '+string (RC)+' ohm')
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clc,clear printf('Example 7.2\n\n') V_l=500 R_a=0.4,X_s=4 //armature resistance and synchronous reactance Z_s=complex(R_a,X_s)//synchronous impedance theta=(%pi/180)*phasemag(Z_s)//phasemag returns angle in degrees,not radians V_ph=V_l/sqrt(3) I_l=50 I_aph=I_l E_Rph=I_aph*abs(Z_s) //case 1 E_bline=600 E_bph=E_bline/s...
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//Function to calculate a PID regulator from a Transfer function a crossover frecuency and phase margin function [Kp,Kd,Ki,Tz,Tuz,Gcz,p_m,fcross,g_m,f_pi]=PID_regulator(fc,pm,fs,H,Gcompensate) //H is the sensor that gets the variable to regulate, resisitive sensor in voltage mode //fc crossover frequency pm phase mar...
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clear all; clc; //This numerical is Ex 3_3E,page 46. //the value given in the book for Um is 200.5,but on calculating the value comes out to be 200.3 r_t=24 r_h=10 N=1250 Q=53000 r_m=(0.5*(r_t^2+r_h^2))^0.5 printf("\n The mean radius rm is equal to %0.1f in",r_m) disp("Converting to feet we have r_m equal ...
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// Book - Power System: Analysis & Design 5th Edition // Authors - J. Duncan Glover, Mulukutla S. Sharma, Thomas J. Overbye // Chapter - 4 : Example 4.2 // Scilab Version 6.0.0 : OS - Windows clc; clear; rx=0.03; //Radius of conductor x in meter ry=0.04; //Radius of co...
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clc N = 100000 // annual output of parts s = 2 // expected scrap t = 105 // estimated time per part in s ita = 80 // production efficiency of machine a = 2300 // number of working hours output = (3600*ita)/(t*100) // parts required per hour pr = N*(100+s)/(a*100) // output from one machine per hour mr = pr/outp...
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//Example 8.4: speed and voltage clc; clear; close; n1=700;//rpm n2=750;//rpm rm=0.3;//in ohms v=500;//in volts ib=50;//amperes eb1=v-(ib*rm);//in volts eb2=eb1;// N=((v-(2*(ib*rm)))/((eb1/n1)+(eb2/n2)));// pdv1=((eb1/n1)*N)+ib*rm;//in volts pdv2=((eb1/n2)*N)+ib*rm;//in volts disp(round(N),"speed in rpm is") disp(round...
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londa V;SG;1;PST+RCT buuka V;NFIN ffa V;PL;3;PRS komawo V;PROG;PL;1;PST yaagala V;PL;1;FUT+RMT nywegera V;PL;1;PST+RCT wereza V;PL;3;FUT+IMMED linda V;3;PRS lowooza V;1;PST+RMT sisinkana V;1;FUT+IMMED kozesa V;PL;1;FUT+RMT lamaga V;1;FUT+RMT salawo V;3;PRS tambula V;2;PST+RMT zina V;PL;1;FUT+RMT salawo V;PL;2;FUT+IMMED...
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// sum 28-3 clc; clear; Z1=2; Z2=60; q=10; m=5; P=6000; N=1440; u=0.08; alpha=20*%pi/180; lambda=atan(Z1/q); d=m*q; w=2*%pi*N/60; T=P/w; Ptw=T*10^3/(d/2); a=cos(alpha); b=cos(lambda); x=sin(alpha); y=sin(lambda); Paw=Ptw*(((a*b)-(u*y))/((a*y)+(u*b))); Prw=Ptw*y/((a*y)+(u*b)); //Paw=Ptw*((cos(alpha...
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// Test #5 : Vaid Input case exec('./tf2cl.sci',-1); [k1,k2,b]=tf2cl([0.5 -0.9 0.5],[1 2 3]); disp(b); disp(k2); disp(k1); // //Scilab Output //b=-0.6154156 + 0.7883950i //k2=0.3328796 + 0.4710837i //k1=0.3328796 - 0.4710837i // //Matlab Output //k1=0.3329 - 0.4711i //k2= 0.3329 + 0.4711i //b= -0.6154 + 0.7884i
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clc; clear all; m = 9.1e-31; // Mass of an electron in Kg e = 1.6e-19; // Charge of an electron in Columbs h = 6.626e-34; // Planck's Constant V1 = 150; // Potential difference in Volts (case1) lambda1 = h/(sqrt(2*m*e*V1)); disp('m',lambda1,'The de-broglie wavelength when V=150 volts is ') V2 = 5000; // Poten...
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//Chapter 3 : Polarization clear; //Variable declaration theta=(60*%pi/180) //angle in radians //Calculations Intensityred=100-(1-cos(theta)**2)*100 //Result mprintf("Percentage of light that passes through = %d percent",Intensityred)
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clear // //Initialisation t=0.05 //time period in seconds from diagram v1=10 //peak voltage from diagram //Calculation f1=1*t**-1 //frequency in Hz w1=2*%pi*f1 //Angular velocity //Result printf("\n %d sin %.1ft Hz\n",v1,w1)
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//Example 12-2 Gas Flow through a Converging-Diverging Duct mdot = 3 //mass flow rate of carbon dioxide in nozzle [kg/s] P_1 = 1400 //Pressure at the entry of the nozzle [kPa] T_1 = 200 //temperature at the entry of the nozzle [C] P_2 = 200 //pressure at the exit of the nozzle [kPa] k = 1.289 //flow inside duct is isen...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 4.4 //Caption : Program to find the Latent Heat del_H1=2257;//latent Heat of Vapourisation of water at 373.15K(100`C)[KJ/Kg] Tr1=373.15/647.1; Tr2=573.15/64...
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19_7.sce
clc //initialisation of variables R= 8.314 //J/mol K T= 25 //C gf= 16590 //kJ/kmol T1= 500 //C Cp= 4.157 //J/mol K hf= -46190 //kJ/kmol //CALCULATIONS K= %e^(gf/(R*(273.15+T))) r= (1-((273.15+T)/(273.15+T1)))*((hf/(R*(273.15+T)))+(R/Cp))-2*log((273.15+T1)/(273.15+T))+0.6 KT1= K*%e^r //RESULTS printf (' equ...
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//caption:design_lead_compensator //example 11_31 //page 339 s=%s; clf(); syms K; g=(K/(s*(1+0.2*s))); Kv=limit(s*g,s,0);//static velocity error coefficient //since Kv=10 K=10; g=(10/(s*(1+0.2*s))); G=syslin('c',g) fmin=0.01; fmax=100; bode(G, fmin, fmax) show_margins(G) [gm,freqGM]=g_margin(G); [pm...
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clc //initialisation of variables v=5 //ft/sec vol=1//lbm/sec Vy=40//ft/sec m=1//lbm/sec g=32.17//lbf-ft/lbf-sec^2 //CALCULATIONS Fx=v*vol/g //lbf Fy=Vy*-m/g//lbf //RESULTS printf('the force is in the opposite directions to =%f lbf',Fy)
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//problem 2.11 clc; clear; close; //given data : N=290;//in rpm f=50;//in Hz disp("Motor running at full load, no. of poles should be 20"); P=20;//no. of poles Ns=120*f/P;//in rpm Slip=(Ns-N)/Ns*100;//in % disp("T is proportional to S/R2 but T is same"); Slip=2*Slip;//doubling R2 also doubles the slip disp...
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// Example 6.4 // This is an analytical problem and need not be coded.
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s=%s; syms K T H=syslin('c',K/(s*(T*s+1))) nyquist(H) show_margins(H,'nyquist') mtlb_axis([-1 1 -1 1]) printf("Since P=0(no of poles in RHP) and the nyquist contour does not encircle the point -1+j0") printf("System is stable")
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//clc() msolu = 100;//g MK2CO3 = 138.20;//g/mol percent1 = 50;//% mK2CO3 = percent1 *msolu / 100; NK2CO3 = mK2CO3 / MK2CO3; mwater = msolu - mK2CO3; Nwater = mwater / 18.06; Mpr = NK2CO3 * 100 / (NK2CO3 + Nwater); sp.gr =1.53; Vsolu = msolu/sp.gr;//mL Vwater = mwater / 1;//mL Vpr = Vwater * 100/ Vsolu; Mo...
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function ir_plotmodelset(X, y, epsilon, padx) // Plots 2D set of feasible linear models consistent with dataset (X,y,epsilon) // TODO: Add possibility to manage colors if argn(2) < 4 then padx = %t; end if size(X,1) < 2 then error('Not enough data'); end if size(X,2) == 2 & an...
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//Caption: Program to find the singular value decomposition of given matrix //Example4.13 //page 210 clear; clc; A = [1,-2,3;3,2,-1]; [U,S,V]= svd(A); A_recon = U*S*V'; disp(U,'U =') disp(S,'S =') disp(V,'V =') disp(A_recon,'A matrix from svd =') //Result // U = // // - 0.7071068 0.7071068 // ...
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NAMECONTEXT META; DECLARE sort WFF FACT; DECREP WFF FACT; REPRESENT {WFF} as WFF; REPRESENT {FACT} as FACT; DECLARE predconst THEOREM 1; DECLARE funconst mkand (WFF,WFF)=WFF; DECLARE funconst wffof (FACT)=WFF; DECLARE indvar A B [WFF]; DECLARE indvar T1 T2 [FACT]; AXIOM ANDI: forall A B.THEOREM(mkand(A,B)); AXIOM ANDI_...
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//************************* VMM_WTA ************************************ if (blk_name.entries(bl) =='vmm12x1_wowta') then global shift_number_mismatch addvmm = %t; plcvpr=%t k =scs_m.objs(blk_objs(bl)).model.opar(1); m1=scs_m.objs(blk_objs(bl)).model.ipar(2);//row (basically number of WTA) n1=s...
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// Example 2.6 clc; clear; close; // Given data format('v',5); Ad= 100;// differential mode gain Acm= 0.01;// common mode gain CMRR= Ad/Acm; CMRR_desh= 20*log10(CMRR);// CMRR in dB disp(CMRR_desh,"CMRR in dB is : ");
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clc m=20; //kg p1=4*10^5; //Pa p2=8*10^5; //Pa V1=4; //m^3 V2=V1; cp=1.04; //kJ/kg.K cv=0.7432; //kJ/kg.K R=cp-cv; T1=p1*V1/R/1000; //kg.K; T=mass*temperature T2=p2*V2/R/1000; //kg.K disp("(i) Change in internal energy") dU=cv*(T2-T1); disp("dU=") disp(dU) disp("kJ") disp("(ii) Work done") Q=...
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k=1; a=10; thalf=10^-1.88;//half time of the reaction// n=1-(log10(thalf/k)/log10(a));//order of the reaction// printf('order of the reaction after solving is n=%f',n); printf('\nHence the order of the reaction=n=3');
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//Chapter-6,Example6_1,pg 6-26 Trs=17*10^-6 Trd=21*10^-6 Tro=sqrt((Trd^2)-(Trs^2)) BW=0.35/Tro printf("bandwidth of CRO\n") printf("BW=%.2f Hz",BW)
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// Scilab Code Ex18.6: Gain of resultant sound intensity: Page-362 (2010) I0 = 1; // For simplicity assume initial sound intensity to be unity, watt per metre square A_I1 = 80; // First intensity gain of sound, dB A_I2 = 70; // Second intensity gain of sound, dB // As A_I = 10*log10(I/I_0), solving for I1 ...
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//Exa 4.2 clc; clear; close; //given data k=40;// in W/mK rho=7800;// in kg/m^3 C=450;// in J/kgK d=20*10^-3;// in m r=d/2; t_i=400;// in degree C t=85;// in degree C t_infinite=25;// in degree C h=80;// in W/m^2K //l_s=V/A = (4/3*%pi*r^3)/(4*%pi*r^2) = r/3 l_s=r/3;// in m Bi= h*l_s/k; // since Biot nu...
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//Chapter 7, Example 7.1, Page 177 clc clear // Thickness of shield Wmu = 0.07066 // meu of water Lmu = 0.7721 // meu of lead Wx= log(10)*(1/Wmu) Lx= log(10)*(1/Lmu) printf("Thickness of water shield = %f cm\n",Wx) printf(" Thickness of lead shield = %f cm",Lx) //Answers may vary due to round off error
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//clear //data = csvRead("C:\Users\erich\Dropbox\Arduino\Projekte\AccuChargerExtension\ChargingStateAlgorihm\messdaten_200mA.txt"); nrOfSamples = length(data)-4; millisPerSample = ( data($) - data(1) ) / nrOfSamples //plot(data(3:870000)) //plot(data($-800000:$-2)) plot(data(3:3:1800000)) xgrid ex = 0.95; dataFilt...
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//Example 13.3 // impedance clc; clear; close; //given data : C3=0.124; // in micro-farad R3=834; // in ohm C4=0.1; // in micro-farad f=2000; // in Hz R2=100; // in ohm L1=R2*R3*C4*10^-6; R1=R2*(C4/C3); X1=2*%pi*f*L1; Z1=sqrt(R1^2+X1^2); disp(R1,"resistance in ohms is") disp(Z1,"impedance of the specimen,Z1(ohm) = ")
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//All the quantities are expressed in SI units b = 35*%pi/180; //oblique shock wave angle pressure_ratio = 3; //upstream and downstream pressure ratio //from appendix B Mn_1 = 1.64; M1 = Mn_1/sin(b); printf("\nRESULTS\n---------\nThe upstream mach number is:\n M = %1...
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function k=lar2rc(g) //lar2rc convert log area ratios to reflection coefficients. // Calling Sequence // k = lar2rc(g) // Parameters // g: define log area ratios. // k: returns the reflection coefficients. <<<<<<< HEAD // Example //g = [0.6389 4.5989 0.0063 0.0163 -0.0163]; //k = lar2rc(g) // Output : //k = //...
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//Ex_7_1 clc; clear; close; //given data : format('v',6); alfa=0.90;//current gain ICO=15;//micro A(reverse saturation currenrt) IE=4;//mA(Emitter currenrt) IC=ICO*10^-3+alfa*IE;//mA IB=IE-IC;//mA IB=IB*1000;//micro A disp(IC,"Collector Current(mA)"); disp(IB,"Base Current(micro A)");
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boardsize 4 play w g4 play b d7 play w f5 play b e6 play w g3 play b c6 play w f4 play b d6 play w e1 play b b1 play w d2 play b a1 play w d1 play b b2 play w c1 play b a2 play w a3 play b g1 play w b4 play b f1 play w a4 play b g2 play w b5 play b f2 play w e4 play b d5 play w c4 play b c3 play w d3 play b e3 play w f...
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//Example 2.7 //(a)what are the surface tempratures and average temp. of wall. //(b)calculate the maximum temp. in the wall and its location //(c)calculate the heat flux at the surface. //(d)if there is heat generation then what is the // average volumetric rate of heat generation? //Given x=poly(0,'x') //tempr...
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epsilon_comp = 1e-9; // Compares the numerical entries of the two lists P1 and P2. Returns // status=0 if the numerical entries are equal up to epsilon, returns // a strictly positive value otherwise. res is a matrix containing the // diffrences between P1 and P2 // // type(L)=='Mat' does not actually do the compariso...
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//Matriz A, mxn A = [1, 1; 1, 0]; //vetor b b = [4, 6]; [m, n]= size(A); //No de linhas não-nulas lnn = m; for p = 1:lnn //Encontrar o proximo pivo linhap = m; colunap = n; for r = p:lnn c=1; while (c<=n & A(r,c)==0) c = c+1; end if c == (n+1) then if b(r) ~= 0 t...
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T = 10000;//epocas tol = 0.0001;//tolerancia contT = 1;//contador de epocas erroQ = tol; Erroepoca = []; X=teste_3(2:5,:)//Entradas Y=teste_3(6,:)//Saidas //------------------------------------------------ tic(); timer(); disp('Testando a rede...'); //------------------------------------------------ clear Y...
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clc clear all format ('e',15) global ni; global dy; //xの微分値// //----setup---// sampling=0.1;//sampling time of simulation //kaisu=1000; //timespan=sampling*kaisu;% simulation time //--- initial state ---- x0=[-10 ]; //initial condition disp('It is under calculation now!!') //================= 初期値条件1====================...
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clc // given data G=39.0 // temperature gradient in K/km. h2=10.0 // depth in km rhor=2700.0 // kg/m^3 cr=820.0 // in J/kg-K h1=120/G // T1-T0=120 K is given h21=h2-h1 // in km E0byA=(rhor*(1000**3)*G*cr*h21**2)/2 // in J/km^2 Heat content per square km printf("The Heat content per square km is %.3e J/km^2",...
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//===================================================================================== //Chapter 12 example 15 clc;clear all; //variable declaration R2 = 100; //resistance of arm in Ω R4 = 309; //resistance of arm in Ω C4 = 0.5*10^-6; //capacitance in F C3 = 109*10^-12...
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clc; T1=288; p2!p1=10; y=1.4; T2s=T1*[(p2!p1)^{(y-1)/y}]; nc=0.82; T2=(T2s-T1)/nc+T1; T3=973; y2=1.333; T4s=T3/[(p2!p1)^{(y2-1)/y2}] nt=0.85; T4=T3-(T3-T4s)*nt cp=1.005; cp2=1.11; Wi=cp*(T2-T1); Wo=cp2*(T3-T4); N=(Wo-Wi); Q=cp2*(T3-T2); Ceff=N/Q disp("$",Ceff*100,"cycle efficiency is:")...
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//Example 3 // Reactance and impedence clc; clear; close; //given data : n=50;// in cycles w=2*%pi*n;// in rad/sec L=1/%pi;// in H XL=w*L; disp(XL,"The reactance,XL(ohm) = ") R=100;// in ohm Z=sqrt(R^2+XL^2); disp(Z,"The impedence,Z(ohm) = ")
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//Minimum force required //refer fig. 5.13 //Applying Lami's theorem to system of forces on block R1=20*sind(145)/sind(140) //kN R2=20*sind(75)/sind(140) //kN //Applying Lami's theorem to system of forces on wedge P=R2*sind(130)/sind(105) //kN printf("required force is P=%0.2f kN",P)
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//Eg-7.5 //pg-338 clear clc x = [0 1 2 3 4]; y = [1 2 9 22 41]; m = length(x); n = 2; //since we have 2 variables //Using S for summation eg: Sx2y => summation(x^2*y) Sx = sum(x); Sx2 = sum(x.^2); Sx3 = sum(x.^3); Sx4 = sum(x.^4); Sy = sum(y); Sxy = sum(x.*y); Sx2y = sum((x.^2...
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function [stk,txt,top]=sci_who() // Copyright INRIA txt=[] stk=list('who','0','0','0','0')
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//Ex13_26 PG-13.14 clc clear disp("Conversion of decimal number 0.640625 base to its octal equivalent =") a=[0.640625]; z=modulo(a,1); d=0; for i=1:10;//converting the values after the decimal point into octal z=z*8; q=floor(z); d=d+q/(10^i); if z>=1 then z=z-q; end end s=d; ...
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//example 14.2 clc; funcprot(0); // Initialization of Variable rho=1.94; V=8.7; D=0.0625; g=32.2; V2=19.6; l=60; z2=20; mu=2.34e-5; Kl=2;//constant Re=rho*V*D/mu; disp(Re,"reynolds no"); f=0.0215;//friction factor from Moody's chart P1=rho*g*z2+1/2*rho*(V2^2-V^2)+rho*f*l/D*V^2/2; P1=P1/144+rho*V^2/2*(10...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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//clc() F = 1000;//kg/h H1 = 116.3;//kJ/kg ( enthalpy of feed solution - 10% NaOH, 305 K ) H2 = 560.57;//kJ/kg ( enthalpy of thick liquor - 50% NaOH, 380 K ) Hsteam = 2676;//kJ/kg ( 1atm , 373.15K ) //by doing material balances, P = 200;//kg/h mvap = 800;//kg/h //Enthalpy balance gives, F*H1 + Q = mvap*Hsteam +...
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// Example 4.2 // Computation of (a) Frequency (b) Induced voltage of six pole induction motor // Page No. 143 clc; clear; close; // Given data f=60; // Frequency p=6; // Number of poles nr=1100; // Rotor speed Ebr=100; // Blocked rotor voltage // ...
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// First time use x=[0:0.1:2*%pi]; y=2*sin(x); plot(x,y) f=gcf(); herokuapp='plotdeploy'; // plotdeploy(f,herokuapp) //Full workflow gitinit(herokuapp) cd(SCIHOME) // gitclone() cd('plotdeploy') xs2png(f,"plot.png") // gitpull() herokuphp() herokuhtml() gitpush()
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//Finding of Coefficient of Lift ,Drag //Given A=25; P=588.6*(7/10); FL=19620; V=200*(5/18); rho=1000; FD=7416; //To Find FD=(P*1000)/(V); Cd=(FD*2)/(rho*A*(V^2)); Cl=(FL*2)/(rho*A*(V^2)); disp("Coefficient Of Lift ="+string(Cl)+" No Units"); disp("Coefficient Of Drag ="+string(Cd)+" No Units");
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// Example A-5-16 // Response to initial conditions clear; clc; xdel(winsid()); //close all windows A = [0 1 0; 0 0 1; -10 -17 -8]; C = [1 0 0]; x0 = [2; 1; 0.5]; G = syslin('c',A,[0; 0; 0],C,0,x0); t = 0:0.05:10; u = zeros(1,length(t)); y = csim(u,t,G); plot(t,y); xgrid(color('gray')); xtitle('Response to initial...
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clc //given that v = 600 // Velocity of moving electron in m/s v_error = 0.005 //Percentage error in measurement of velocity m = 9.1e-31 // mass of electron in kg h = 6.63e-34 // Plank constant printf("Example 2.6") h_bar = h / (2*%pi) // constant p = m*v del_p = v_error*p/100 // calculation of uncertainty in...
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//Part B Chapter 2 Example 9 clc; clear; close; format('v',6); sigma1=200;//N/m^2 sigma2=-80;//N/m^2 theta_dash=60;//degree theta=90-theta_dash;//degree sigma_n=(sigma1+sigma2)/2+(sigma1-sigma2)/2*cosd(2*theta);//N/mm^2 sigma_t=(sigma1-sigma2)/2*sind(2*theta);//N/mm^2 sigmaR=sqrt(sigma_n^2+sigma_t^2);//N/mm^...
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function[x,Vm,Vc]=pam(Em,fm) t = (0:0.1:12*%pi)'; Vm = 2*Em*sin(2*%pi*fm*t); Vc =1+squarewave(4*t); x = Vc.*Vm subplot(3,1,1) square(0,0,16,2.5) plot(Vm) title('Modulating Signal') subplot(3,1,2) square(0,0,16,2.5) plot(Vc) title('Pulse Train') subplot(3,1,3) squa...
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n = 250 points = grand(n,2,'def') //function d = Distance(A,B) // d = sqrt((A(1)-B(1))^2 + (A(2)-B(2))^2); //endfunction function d = Distance(x1,y1,x2,y2) d = sqrt((x1-x2)^2 + (y1-y2)^2); endfunction function n = nN(pt_x, pt_y,list) n = 1 d_min = Distance(pt_x, pt_y,list(n,1),list(n,2)) for k...
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//Example 2.13 clc disp("Given, C1 = 100 pF, C2 = 50 pF, f = 10 MHz, L = ?") ceq=(5000*10^-24)/(150*10^-12) format(10) disp(ceq,"C_eq(in F) = C1*C2 / C1+C2 = ") disp("f = 1 / 2*pi*sqrt(L*C_eq)") l=(1/(4*(%pi^2)*(33.33*10^-12)*((10*10^6)^2)))*10^6 // in F format(4) disp(l,"Therefore, L(in uH) =")
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PL/SQL Developer Test script 3.0 19 -- Created on 11.05.2018 by V.ZHURAVOV declare -- Local variables here i integer; begin --dbms_session.reset_package; return; -- Test statements here for p in ( select c.id, c.pdb_name from pdb_clones_t c where c.pdb_name in ('VBZ_TSTDB', 'VBZ_TSTDB_01') ...
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clc //to calculate electric flux //electric flux through a surface is phi=vector(E)*vector(s) //where vector E=2i+4j+7k,vector s=10j E=4 //E=4j s=10 //s=10j phi=E*s disp("electric flux is phi="+string(phi)+"units") //to calculate flux coming out of any face of the cube q=1 ...
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Ex2_6.sce
clear; clc; p_1 = 7;//tons/in^2 p_2 = 4;//tons/in^2 p_3 = 3;//tons/in^2 m = 4; E = 13000;//tons/in^2 e_1 = (p_1/E)+(p_2/(m*E))-(p_3/(m*E)); e_2 = (p_2/E)+(p_1/(m*E))+(p_3/(m*E)); e_3 = (p_3/E)-(p_1/(m*E))+(p_2/(m*E)); printf('e_1 = %.6f, tensile\n e_2 = %.4f, compressive\n e_3 = %.6f, tensile',e_1,e_2,e_3); ...
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clear flag=1 mode(-1) clc printf("Example 5 : Show the effect of creating an orphan by letting child sleep for 2 minutes where parent dies immediately \n") disp("****************************************************************") disp("Answer : ") disp("INSTRUCTIONS : ") halt(' ') disp("1.These programs ar...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.5\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.5 (page no. 326) // Solution //Referring to figure 7.3,we have for CO2, nCO2=10/44; //mole //no of moles of carbon dioxide=ratio of mass and molecular weight //10 lb of per pound //molecu...
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clc // Given that L_ = 20 // Length of the mild steel product in mm h = 50 // Height of the mild steel product in mm L = 50 // Horizontal length of the mild steel product in mm t = 5 // Thickness in mm l=25 // Length of the bend in mm E = 207 // Modulus of elasticity in kN/mm^2 n = 517 // Strain hardening rate in N/mm...
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syms G1 G3 G4 H1 H2 a=G1+G3 b=G2/(1+(G2*H1)) c= a*b d=c/(1+(c*H2)) Y=d+G4 disp(Y," C/R = ")
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clear; clc; printf("\t Example 9.23\n"); function[n]=mole(w,m) n = w/m; funcprot(0); endfunction function[p]=partial(n1) p = 308*(n1/total); funcprot(0); endfunction w_steam = 0.57; //mass flow rate of steam entering in [kg/sec] w_CO2 = 0.20; //mass flow rate of CO2 entering ...
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14_13.sce
clc //initialisation of variables d= 4 //in T= 40000 //lb in Th= 20000 //lb in //CALCULATIONS t= T*(d/2)*32/(%pi*d^4) S= Th/(%pi*(d/2)^2) Smax= -(S/2)-sqrt(t^2+(S/2)^2) Tmax= sqrt(t^2+(S/2)^2) //RESULTS printf ('Maximum normal stress= %.1f psi',Smax) printf (' \n Maximum shearing stress=%.1f psi',Tmax)
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Chapter14_example7.sce
clc clear //Input data M=2300//Magnetization in A/m B=0.00314//Flux density in Wb/m^2 uo=(4*3.14)*10^-7//Permeability of free space in H/m //Calculations H=(B/uo)-M//Magnetizing force in A/m ur=(M/H)+1//Relative permeability //Output printf('The magnetizing force is %3.0f A/m \n The relative permeability ...
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// problem 6.11 d1=0.5 d2=0.25 p1=103005 p2=67689 p3=p2 w=9810 g=9.81 c=0.65 z=1-(1/16)+((1/c-1)^2) dp=p1-p2 v2=((dp*2*g)/(w*z))^0.5 a2=3.142*d2*d2/4 Q=v2*a2 disp(Q*1000,"rate of flow in m3/sec") v3=v2 v1=v3/4 v4=v1 he=(v3-v4)^2/(2*g) p4=w*((p3/w)+((v3*v3-v4*v4)/(2*g))-he) disp(p4,"pressure at the 5...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 10 Example 1") k=20*10^6;//spring constant in N/m^2 N=2000;//engine rpm disp("from stroke to bore ratio i.e L/D=1.2 and cylinder diameter=bore,i.e D=12 cm") D=1...
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//Example 16.1 clc s=%s; j=%i; f=10/%pi; w=2*%pi*f; G=1/(0.1*s+1); s=w*j; Gs=horner(G,s); disp(Gs,'G(20j)=') [r,theta]=polar(Gs) theta=theta*180/%pi; disp('degrees',theta,'theta=')
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//Chapter-2,Example 2_9,Page 2-34 clc() //Given Data: m=1 //order lam=6*10^-7 //Wavelength of light a=12*10^-7 //width of slit //Calculations: //We know, a*sin(theta)=m*lam theta=asin(m*lam/a)*180/%pi //angular position in first minima printf('Half angular width of first ...
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clear; clc; D = 4;//diameter of the wheel in ft p = 6 ;//hoop stress in tons/in^2 alpha = 0.0000062;//in "per F" E = 13000;//in tons/in^2 d = (1/(1+(p/E)))*D*12;//internal diameter in inches t = (D*12-d)/(d*alpha); printf('The least temperature the tube must be heated is, t = %.1f F',t);
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clear; lines(0); np=100; q=7; //rang=190/300 msig = 1 // номер строки, отвечающая нужной нам плотности прививки, с которой мы будем считывать msig1 =2 msig2 =3 msig3 =4 msig4 =5 msig5 =6 msig6 =7 msig7 =8 msig8 =9 msig9 =10 msig10 =11 msig11 =12 msig12 =13 msig13 =14 msig14 =15 msig15 =16 msig16 =17 ...
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//fiber optic communications by joseph c. palais //example 8.3 //OS=Windows XP sp3 //Scilab version 5.4.1 //given clc clear all n1=1.465//refrative index of core n2=1.46//refractive index of cladding lambda=0.8//wave length in um V=2.4//normalized frequency wbya=1.1//w/a ratio for V=2.4 na=sqrt((n1^2)-(n2^2...
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sce
U2_C1_4.sce
//variable initialization e=1.6*10^-19; //Charge of electron (coulombs) h=(6.625*10^-34)/(2*%pi); //Planck's constant (joule-second) c=3*10^8; ...