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// Example 20.3, page no-569 clear clc t1=4.2 t2=7.18 h0=6.5*10^4//A/m he=h0*(1-((t1^2)/t2^2)) r=0.5*10^-3 I=2*%pi*he*r printf("The critical current through a wire of lead is %.2f A",I)
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function rtheta=CartToCyl(xy) // Cartésiennes à polaires theta = atan(xy(2), xy(1)) r = norm(xy) rtheta = [r, theta] endfunction function xy=CylToCart(rtheta) // Polaires à cartésiennes x = rtheta(1)*cos(rtheta(2)) y = rtheta(1)*sin(rtheta(2)) xy = [x, y] endfunction
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function [r] = kSetEncoders(ref,left,right) // Ouput variables initialisation (not found in input variables) r=[]; // Number of arguments in function call [%nargout,%nargin] = argn(0) // Display mode mode(0); // Display warning for floating point exception ieee(1); //KSETENCODERS Set the encoder values of Kheper...
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// Example 2.12, page no-43 clear clc e=0.6 // eccentricity of elliptical orbit a=0.97 // area of shaded region b=2.17 //Area of non-shaded region t=3 // time taken by satellite to move from pt B to A x=b/a y=x*t printf("Time t...
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//Ex7_7 clc AV=50000 disp("AV="+string(AV)) // Voltage gain Ri=50*10^(6) disp("Ri= "+string(Ri)+ " ohm") //Input resistance of OP-AMP R0=1*10^(3) disp("R0= "+string(R0)+ " ohm") //Output resistance AVf=10 disp("AVf="+string(AVf)) // Overall Voltage gain RSf=50*10^(3) disp("RSf= "+string(RSf)+ " ohm") //...
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clc; Q=5000/3600/24; // m^3 per second C_d=0.6; r=0.01/2; // m g=9.8; // m/s^2 H=0.2; // m a_o=%pi*r^2; n=Q/C_d/a_o/sqrt(2*g*H); disp("The number of orifices required are") disp(n);
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//value// s=%s; num=real(poly([1],'s',"coeff")) den=real(poly([-1,-2+%i,-2-%i],'s')) H=num/den evans(H,100) k=1.5; disp(k,"K(design)=") //Kpure calculates the value of k at imaginary crossover [K,Y]=kpure(H) GM=K/k; disp(GM,"value of k at imaginary crossover/k(design)=") disp(GM,"gain margin=")
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// To Determine the economic operating schedule and the corresponding cost of generation.(b)Determine the savings obtained by loading the units. clear clc; //dF1/dP1=.4*P1+40 per MWhr //dF2/dP2=.5*P1+30 per MWhr mprintf("two equations are :\n"); mprintf("%.1f P1 %.1f P2 = %.1f\n",.4,-.5,-10); mprintf("%.1f P1+ ...
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//Chapter 1,Example 1.2,Pg 1.10 clc; l=2000*10^3 //length of the cable in metres d=0.7*10^-2 //diameter of the cable in metres p=(1/58)*10^-6 //ohms per m for 1sq mm cross sectional area A=(%pi*d^2)/4 R=(p*l)/A printf("\n Resistance = %.2f ohms \n",R)
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//Example_a_8_14 page no:334 clc; fr=120*10^3; BW=50*10^3; Q=2; f1f2=sqrt(fr); f=poly([-14.4*10^9,50000,1],'f1','c'); fre=roots(f); f1=fre(2); f1=f1/1000;//converting to killo Hz f2=BW+f1; f2=f2/1000;//converting to killo Hz disp(f1,"the lower cutoff frequency is (in kHz)"); disp(f2,"the upper cutoff frequ...
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//Polynomial Interpolation: Divided Differnce form clc; clear; close(); format('v',8); x = [1 1.5 1.75 2]; fx = [0 0.40547 0.55962 0.69315]; fab(1) = (fx(2)-fx(1))/(x(2)-x(1)); fab(2) = (fx(3)-fx(2))/(x(3)-x(2)); fab(3) = (fx(4)-fx(3))/(x(4)-x(3)); fabc(1)= (fab(2)-fab(1))/(x(3)-x(1)); fabc(2)= (fab(3)-fab(2...
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.11 // Page 225 printf("Example 5.11, Page 225 \n \n"); // solution // (a) Pc = 61.37 // bar Tc = 514 //K Tb = 351.4 P = 1 // atm TBr = Tb/Tc // Riedel eq lambdav1 = 8.314472*Tb*1.092*(log(6137)-5.6182)/(.930-TBr) // NI...
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 1.6 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given v0=1.1e15;//threshold frequency of light in Hz e=1.6e-19;//charge of electrons in C h=6.62e-34;//Planck's constant in SI Units phi=h*v0/e;//work func...
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function A = init(n) for i=1:n for j=1:n //changes 4's to 5's to incorporate red color if modulo(i+j,4)+1 == 4 then A(i, j) = 5; else A(i,j)= modulo(i+j,4)+1 end end end endfunction
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//Solutions to Problems In applied mechanics //A N Gobby clear all; clc //initialisation of variables w1=8//lbf s=3//ft m=35//lbf g=32.2//ft/s //CALCULATIONS U=sqrt(g*s)//ft/s T=w1+w1//lbf P=m-w1//lbf Umax=sqrt(P*g*s/w1)//ft/s //RESULTS printf('the centrifugal force=% f ft/s',Umax)
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// Ex6_7 Page:105 (2014) clc;clear; l = 1; // Orbital angular momentum quantum number m = [1, 0, -1]; // The possible z-components of l printf("\nThe possible orientations of vector L with respect to the z-axis are:"); for i = 1:3 theta = acosd(m(i)/sqrt(l*(l+1))); printf("\ntheta = %d degree (m = ...
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//Ex9_9 clc Vp = -4//pinch off voltage VGS = -1.5//gate source voltage VDS_minimum = VGS - Vp//minimum VDS for Pinch Off voltage disp("Vp = "+string(Vp)+"V") disp("VGS = "+string(VGS)+"V") disp("VDS_minimum = VGS - Vp = "+string(VDS_minimum)+"V") IDSS = 6*10^-3//maximum drain current ID = IDSS*(1-(VGS/Vp))^2//...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 7 Example 6") To=(30+273);//temperature of surrounding in K W=1050;//work done in engine in KJ/kg Cp=1.1;//specific heat at constant pressure in KJ/kg K T=(800+...
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clc; clear; //Example 6.8 mf_dot=6000 //Feed rate in [kg/h] //Taking the given values from previous example(6.6) Hf=125.79 //[kJ/kg] ms_dot=3187.56 //[kg/h] lambda_s=2230.2 //[kJ/kg] Hdash=419.04 //[kJ/kg] Hv=2676.1 //[kJ/kg] mv_dot=(mf_dot*Hf+ms_dot*lambda_s-60...
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ex_2_3.SCE
// Example 2.3: Calculate base current and collector current alfa= 0.967;// Common base D.C. Current Gain Ie= 10;//in Milli Ampere Ic= alfa*Ie ; // Collector Current Ib=Ie-Ic;// Base Current in Mili Ampere disp(Ic,"collector current (in mA)") disp(Ib,"base current (in mA)")
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13_11.sce
clear clc G1=50 H1=8 G2=100 H2=4 Gb=100 Ha=(H1*G1/Gb) + (H2*G2/Gb) mprintf("\n(a)Ha= %d MJ/MVA", Ha) Hb=Ha*2 mprintf("\n(b)Hb= %d MJ/MVA", Hb) He= (Ha*Hb)/(Ha+Hb) mprintf("\n(c)He= %.3f MJ/MVA", He)
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0023.tst
sPLITTER h {} filTEr w { not iN s } FIlteR c {Z } z -> adP gRoUper Y {MoDULE z{ } agGrEGatE min(O.Z) As Mw ,YUU.G } UNGroUpEr Z { } GRoUPfilTeR rBL {} MERGER Cbw { EXporT Km }
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Ex4_10.sce
//Example 4_10 clc(); clear; //To calculate the percentage of volume r1=1.258 //units in meters r2=1.292 //units in meters v1=((4*r1)/sqrt(3))^3/2 v2=(2*sqrt(2)*1.292)^3/4 v=(v1-v2)/v2*100 printf("The percentage of volume changed during this structural chan...
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// Name - Vinit Gupta // // Date of creation: 10 Mar, 2021 // function y = fn(x) y = x+1 end
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Ex15_4.sce
clear // //Initialisation Ic=2 //sinusoidal Current C=10*10**-3 //Capacitance w=25 //Angular Frequency //Calculation Xc=1/(w*C) //Reactance Vc= Ic*Xc //Voltage //Result printf("\n Voltage appear across the capacitor, V = %d V r.m.s",Vc) ...
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CH16Exa2.sce
// Scilab code Exa16.2 : : Page-673 (2011) clc; clear; BC_conv = 100*1e+009/3.7e+10; // Becquerel curie conversion, milli curie printf("\n100 mega becquerel = %3.1f milli curie ", BC_conv) // Results // 100 mega becquerel = 2.7 milli curie
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proj_dane_1.tst
we we wy x1 x2 #d -9,822 9,322 Klasa1 -8,678 8,094 Klasa1 -7,2 6,669 Klasa1 -6,118 5,343 Klasa1 -4,89 4,409 Klasa1 -4,058 3,107 Klasa1 -3,101 2,493 Klasa1 -2,185 1,658 Klasa1 -1,373 0,528 Klasa1 -1,831 -0,405 Klasa1 -3,205 -1,977 Klasa1 -4,079 -2,739 Klasa1 -5,452 -3,009 Klasa1 -7,949 -3,058 Klasa1 -9,469 -3,034 Klasa1...
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2_6.sce
clear; clc; Zoc=286*exp(%i*(-%pi/(180/40)));Zsc=1520*exp(%i*(%pi/(180/16)));l=50;f=700; w=2*%pi*f; Zo=sqrt(Zoc*Zsc); S=real(Zo); T=imag(Zo); printf("-Characteristic impedance of transmission line is Zo = %f /_ %f ohms\n",round(abs(Zo)*100)/100,atan(T,S)*180/%pi); A=atanh(sqrt(Zsc/Zoc)); P=A/l; U=real(P); V=i...
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my_cholesky.sce
function [A]=cholesky_fact(A) // retourne la matrice triangulaire inférieure L tel que A = L.tr(L) n = size(A)(1) L = zeros(n,n) L(1,1) = sqrt(A(1,1)) for j = 2:n L(j,1) = A(1,j)/L(1,1) end for i = 2:n somme1 = A(i,i); for k = 1:i-1 somme1 = somme1 - L(i,...
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result9s0.tst
@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005]...
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exa7_5.sce
// Example 7-5 // Bode Plot in rad/s clear; clc; xdel(winsid()); //close all windows s = %s; num = 25; den = s^2 + 4*s + 25; G = syslin('c',num,den); bode(G); xtitle('Bode plot of G(s) = 25 / s^2 + 4*s + 25'); // Note, bode plots in Sci-Lab use the frequency in Hz and not in // rad/s . If we wish to get the plot w...
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Example1_14_6.sce
//Example 1.14.6 page 1.46 // To find Numerical Aperture, solid acceptance angle, and number of modes. clc; clear; V= 26.6; // Normalised frequency.. lamda= 1300*10^-9; //wavelength of operation.. a= 25*10^-6; // radius of core.. NA = V*lamda/(2*%pi*a); //Numerical Aperture.. printf('The ...
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// Scilab Code Ex2.5 : Page-47 (2010) E_peak = 6; // Peak value of electric field intensity, V/m c = 3e+08; // Speed of electromagnetic wave in free space, m/s mu_0 = 4*%pi*1e-07; // Absolute permeability of free space, tesla metre per ampere epsilon_0 = 8.854e-012; // Absolute permittivity of free spac...
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Ex12_17.sce
//EX12_17 Pg-12.33 clc clear disp(" equation of the Am sine wave =Vc(1+m*sinwm*t)*sinwc*t") Vc=12;//amplitude of carrier voltage m=0.5;//modulation index fc=10e6;//carrier frequency fm=1e3;//modulated frequency wc=2*%pi*fc; wm=2*%pi*fm; t=0:2.3148e-7:8e-4; Vam=Vc*(1+m*sin(wm*t).*sin(wc*t)) fusb=fc+fm;//upp...
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Ex12_3.sce
clear; clc; disp('Example 12.3'); // aim : To determine the // (a) throat and exit areas // (b) degree of undercooling at exit // Given values P1 = 2;// inlet pressure of air, [MN/m^2] T1 = 273+325;// inlet temperature of air, [MN/m^2] P2 = .36;// exit pressure, [MN/m^2] m_dot = 7.5;// flow rate of air,...
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// Exa 4.9 clc; clear; close; // Given data V=4;// in V Vr1= 0.7;// in V Vr2= 0.3;// in V R1= 4;// in kΩ R2= 4;// in kΩ I1= (V-Vr1)/R1;// in mA I2= (V-Vr2)/R2;// in mA disp(I1,"The value of I1 in mA is : ") disp(I2,"The value of I2 in mA is : ")
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Nand1.tst
load Nand1.hdl, output-file Nand1.out, compare-to Nand1.cmp, output-list a%B3.1.3 b%B3.1.3 out%B3.1.3 ; set a 0, set b 0, eval, output; set a 1, set b 0, eval, output; set a 0, set b 1, eval, output; set a 1, set b 1, eval, output;
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Ex10_1.sce
clc // Given that //three metal piece being cast have the same volume but different shapes //shapes are sphere,cube,cylinder(height=diameter) // Sample Problem on page no. 252 printf("\n #solidification time for various shapes# \n") //solidification time is inversely proportional to the square of surface a...
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//OptoElectronics and Fibre Optics Communication, by C.K Sarkar and B.C Sarkar //Example 9.2 //OS=Windows 10 ////Scilab version Scilab 6.0.0-beta-2(64 bit) clc; clear; //given L1=1.5;//length of optical fiber in Km L2=0.002;//length of fiber cutback in Km Pn=50.1;//output power in microwatts for the full li...
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 1.5.1\n') //given data //x1=a*sin(W1*t) //x2=b*sin(W2*t) //calculations a=1.90//amplitude of first wave in cm b=2.00//amplitude of second wave in cm W1=9.5//frequency of first wave in rad/sec W2=10.0//frequency of second wave in rad/sec xmax=b+...
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Ex5_2.sce
clear; clc; disp("a)") disp("Convert: 1) Q=5 m^3/s=10595 cfm") disp("2) rhoa=0.0761lbm/ft^3") disp("3) SP=deltap/(rhow*g)") delta_ps=500 rho_w=1000 g=9.8 SP=delta_ps/(rho_w*g) printf("Hence SP = %0.3f m",SP) disp("Thus SP= 2.01 in.wg.") disp("b)") disp("Calculating the specific speed:Ns") N_s=1500*((10575)^0.5)/(2.0...
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exo5.sce
function [x]= gausssolve(A,b) n=size(A,1); mik=0; for k=1:n-1; for i=k+1:n; mik=(A(i,k)/A(k,k)); b(i)=b(i)-mik*b(k); A(i,(k+1):n)=A(i,(k+1):n)-mik*A(k,(k+1):n); end; end; x(n)=b(n)/A(n,n); for i=n-1:-1:1 x(i)=(b(i)-A(i,(i+1):n)*x((i+1):n))./A(i,i); end endfunction
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8_7b.sce
clc clear //Initialization of variables k=1.4 R=53.3 //lb-ft/lb R pe=14.7 //psia p0=114.7 //psia T0=524.6 //R g=32.2 //ft/s^2 d=0.5 //in Nm1=1 //calculations pr=pe/p0 Nme=sqrt(2/(k-1) *((1/pr)^((k-1)/k) -1)) Te=T0/(1+ (k-1)/2 *Nme^2) Ve=Nme*sqrt(k*g*R*Te) At=%pi/4 *(d)^2 Ae=Nm1/Nme *((1+ (k-1)/2 *Nme^2...
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23Ex1.sce
// Chapter 23 Ex1 clc; clear; close; //(i) n1=27; n2=3; ans1=log(n1)/log(n2); mprintf("log 27 to the base 3 is %d",ans1); //(ii) n3=(1/343); n4=7; ans2=log(n3)/log(n4); mprintf("\nlog (1/343) to the base 7 is %d",ans2); //(iii) n5=0.01; n6=100; ans3=log(n5)/log(n6); mprintf("\nlog 0.01 to t...
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Ex17_13.sce
// Exa 17.13 // To calculate average SINR of HSDPA. clc; clear all; Ptmax=5.5;//Maximum transmit power of DSCH in watts Pbs=18;// Total base station power in watts alpha=0.2;//downlink orthogonality factor G=0.363;// geometry factor SF=16; //Spreading Factor for DSCH;fixed at value of 16 //solution // ...
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example1_sce.sce
//chapter 13 //example 13.1 //page 547 printf("\n") printf("given") Av=100000;B=1/100; disp("when Av=100000") Acl=Av/(1+Av*B) disp("when Av is 150000") Av=150000; Acl=Av/(1+Av*B) disp("when Av is 50000") Av=50000; Acl=Av/(1+Av*B)
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example12_6.sce
//example 12.6 //calculate floor thickness at mid length and at junction with u/s and d/s cut-off walls clc;funcprot(0); //given b=13; //length of floor d=2; //depth of downstream wall D=1.5; //depth of upstream cut-off rho=2.24; //relative density H=1.5; //at junction of d/s c...
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Ex4_2.sce
//=========================================================================== //chapter 4 example 2 clc; clear all; //variable decalartion W = 0.005; //controlling weight in Kg L = 0.024; //length in m Td = 1.05*10**-4; //deflecting Torque in kg-m //calculatio...
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Exa10_2.sce
//Exa 10.2 clc; clear; close; //Given Data : format('v',7); Eta=85;//in % P=30;//in HP P1=P*0.7355*Eta/100;//in KW cosfi_1=0.8;//powerfactor tanfi_1=tand(acosd(cosfi_1));//unitless Pr=P1*tanfi_1;//in KVAR //Let active power P2 : Total Active power = P1+P2 cosfi=0.9;//overall powerfactor tanfi=tand(acosd(c...
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Example4_11.sce
exec("degree_rad.sci",-1) //Given that v_WG = [65 * sin(dtor(20)),65 * cos(dtor(20))] //in km/h v_PG_y = 0 v_PW_mag = 215 //in km/h //Sample Problem 4-11 printf("**Sample Problem 4-11**\n") //therefore in direction v_PW_y = v_PG_y - v_WG(2) v_PW_x = sqrt(v_PW_mag^2 - v_PW_y^2) v_PG_x = v_PW_x + v_WG(1)...
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3_07.sce
//Chapter 3, Problem 7 clc; L=1200; //Length of copper cable in meter D=12*10^-3; //Diameter of cable in meter p=1.7*10^-8; //Resistivity of cable in ohm.meter r=D/2; //Calculating radius A=%pi*r^2; //Caculating area R=(p*L)...
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example4_6.sce
// Calculate alpha reverse and beta reverse // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 4-6 in page 210 clear; clc; close; // Given Data Ie=10*10^-3; // Emitter Current in mA Ib=5*10^-3; // Base Current in mu-A // Calculations Ic=Ie-Ib;...
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Ex8_9.sce
clc // Given that m_0 = 9.1e-31 // Mass of electron in kg mu_0 = 1.256e-6// SI e = 1.6e-19 // Charge on electron in coulomb eta_s = 1e28 // superelectron density in no. per cube T_1 = 0 // First temp in kelvin T_2 = 1 // Second temp in kelvin T_c = 3 // Critical temp in kelvin printf("Example 8.9\n") p...
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Ex7_23.sce
clc clear //Input data p1=20//Pressure in bar T=400//Temperature in degree C p2=0.1//Pressure in bar n=4//Number of stages ns=75//Stage efficiency in percent //Calculations h16s=(3250-2282)//Change in enthalpy in kJ/kg h12s=(h16s/n)//Change in enthalpy in kJ/kg p=[8,2.6,0.6]//pressures in bar from Mollier...
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EX13_4.sce
//Example13.4 // to design the wien bridge oscillator for the oscillation frequency f = 1 KHz clc; clear; close; f = 1 ; // K ohm C = 0.01 ; // uF // the frequency f is define as // f = 1/(2*%pi*R*C); // the resistor R is R = 1/(2*%pi*f*C); disp('the resistor R is = '+string(R)+ ' K ohm '); // the ...
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ex_1_6.sce
//ex_6 even and odd signal of e^jt clear; clc; close; t = 0:1/100:5; x=exp(%i.*t); y=exp(-%i.*t); even=x./2+y./2; odd=x./2-y./2; figure a=gca(); plot2d(t,even) a.x_location='origin' xtitle('even','t') figure a=gca(); plot2d(t,odd./%i) a.x_location='origin' xtitle('odd','t')
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ex9_3.sce
//Exam:9.3 clc; clear; close; P=4;//Number of phases exhibit by a material F=0;//Minimum degrees of freedom //modified form of the phase rule F=C-P+1 C=F+P-1;//minimum number of components in the system disp(C,'the minimum number of components in the system=')
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//Process PCI Express clock and report eye closure // stacksize(32*1024*1024); clear; xbasc(); load("PXPClocks.dat", "Intervals"); N=2*(floor(size(Intervals,2)/2)); //To reduce calculation discrepancies, must be even number idealper = 10*10^(-9); Res=round(100e6 / N); n=...
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////ServoLab //clc() s = %s // //// A //// ------ //// 1+sT //A = 1 //T = 1 //num = 1+s*T // //g = A/num //gs = syslin("c",g) // //gsCL = 1/(1+gs) // //Position Control j = 1 for (T = 0:0.2:1) gs2 = syslin("c", 1/(s*(1+s*T))) gs2CL = 1/(1+gs2) subplot(3,2,j) // evans(gs2CL...
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clc //Intitalisation of variables clear c1= 0.1 //M cs= 0.05 //M Ka= 1.75*10^-5 //CALCULATIONS ch= Ka*c1/cs //RESULTS printf ('CH+ = %.1e g ion per litre',ch)
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function[z] = mcnorm(A, y) exec('resolChol.sci', -1); z = resolChol(A' * A, A' * y); endfunction
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clc; clear; L=0.5*10^-9 //width in m m=9.1*10^-31 //mass in kg V_0=15*1.6*10^-19 //height of the potential well in J h=6.63*10^-34 //Plancks constant in J-s //calculation n_max=(4*L*sqrt(m*V_0))/h mprintf("The maximum quantum number possible is %d",n_max)
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function z = rhoX(x,y) //z = 1 z = (Npoints^2)/66.051535 * exp(- norm([x,y]) ^2 / 0.1) +1; endfunction function z = rhoY(x,y) z = 9 * rhoX(x^3,y^3) * x^2 * y^2 endfunction function z = u(x,y) z = (x^4 + y^4)/4 endfunction function z = graduX(x) z = x^3 endfunction Npoints = 30 x = linspace(...
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file_link aaa zzz file_link bbb yyy file_link ccc xxx branch objects aaa* (3.1 kB) bbb* (5.7 kB) ccc* (6.7 kB) xxx (6.7 kB) yyy (5.7 kB) zzz (3.1 kB) file_link ddd zzz file_link eee yyy file_link fff xxx branch objects aaa* (3.1 kB) bbb* (5.7 kB) ccc* (6.7 kB) ddd* (3.1 kB) eee* (5.7 kB) fff* (6.7 kB) xxx (6.7 kB) yyy ...
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exec("alaqiltest.start", -1); try x = add(3, 4); catch alaqiltesterror(); end if x <> 7 then alaqiltesterror(); end try y = subtract(3,4); catch alaqiltesterror(); end if y <> -1 then alaqiltesterror(); end try z = mul(3,4); catch alaqiltesterror(); end if z <> 12 then alaqiltesterror(); end ...
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clc; clear; g=[1,-1,%i,-(%i)]; h=[1,-1]; eg=1; a=0; for i=1:4 ig(i)=eg/g(i); end mprintf("Inverse elements of G are\n"); disp(ig); for i=1:1 for j=1:4 if g(j)*h(i)*ig(j)==h(1) | g(j)*h(i)*ig(j)==h(2) then a=1; else a=0; abort; end end end if a==1 then mprintf("H is a normal subgroup\n"); else mprint...
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// UI utility for selecting the working directory example: /SomePath/EPPredictor/ WorkingDirectory=uigetdir(); chdir(WorkingDirectory); datafile=uigetfile();//select the file to be used tic();//start timer M = read_csv(datafile,';');//Reads the data from csv file and remember result is a string matrix M = strtod(M);//T...
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//Analytical Evaluation of Discrete convolution clear;close;clc; max_limit=5; h(1)=0; for n=2:max_limit h(n)=0.8^n; end n2=0:length(h)-1; x=[0 ones(1:max_limit)] n1=-length(x)+1:0; y=convol(x,h); n=-length(x)+1:length(h)-1; a=gca(); subplot(211); plot2d3('gnn',n2,h) xtitle('impulse Response','n','h[n]'); a.thicknes...
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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear; //example 4.3 //calculation of the dimensions of electrodes in coaxial cylindrical capacitor //given data epsilon0=(36*%pi*10^9)^-1//electrical permittivity(in F/m) of free space //consider high density polyethylene as the dielectric...
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function vpcGuiConectar() set('BConectar','Enable','off'); set('BDesconectar','Enable','on'); set('porta','Enable','off'); set('baudRate','Enable','off'); set('dataBits','Enable','off'); set('paridade','Enable','off'); set('stopBits','Enable','off'); vpcGuiAquisicao(uint8(strtod(bdVpcGet...
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//Example 1_29 clc; clear; close; format('v',5); //given data : V1=12;//V V2=24;//V R1=4;//ohm R2=4;//ohm R3=4;//ohm RL=5;//ohm //solution by Norton Theorem //Short Circuit AB I=V1/(R1*R3/(R1+R3));//A ISC1=I*R3/(R1+R3);//A ISC2=V2/R3;//A ISC=ISC1+ISC2;//A Req=R1*R3/(R1+R3);//ohm //Norton equivalent c...
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// Creates two plots: The first contains the solution for the differential equation // y''(t) = -w^2*y(t) (harmonic oscillator) for w = 5 // The second contains the total amount of energy (potential + kinetic) for each step clear function y = f(w,t) // Returns the value for y = -25*t // Input: t = number or vector //...
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3a Program for Newton’s forward interpolation..sce
clc;clear;close x=[1 3 5 7]; y=[24 120 336 720]; h=2 c=1; for i=1:3 d1(c)=y(i+1)-y(i); c=c+1; end c=1; for i=1:2 d2(c)=d1(i+1)-d1(i); c=c+1; end c=1; for i=1:1 d3(c)=d2(i+1)-d2(i); c=c+1; end d=[d1(1) d2(1) d3(1)]; x0=8; pp=1; y_x=y(1); p=(x0-1)/2; for i...
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//Exa 5.12 clc; clear; close; format('v',7); //Given Data : Tg1=1127+273;//Kelvin Tg2=527+273;//Kelvin T2=250+273;//Kelvin T0=27+273;//Kelvin Cpg=1;//KJ/KgK mw=5;//Kg/s hfg=1716.2;//KJ/Kg //mg*Cpg*(Tg1-Tg2)=mw*hfg mg=mw*hfg/Cpg/(Tg1-Tg2);//Kg/s disp(mg,"Mass flow rate of gases in Kg/s : "); deltaSg=mg...
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Calculo_do_Erro.sci
clear close clc X = [1; 2; 3; 4; 5] Y = [15; 28.4; 45.3; 58.6; 77.4] function [s] = minimo_quadrado(x, y) X = [size(x,1) sum(x); sum(x) sum(x^2)] Y = [sum(y); sum(x.*y)] s = X\Y endfunction function [s] = logaritmico(x, y) A = minimo_quadrado(log(x), y) a = A(2,1) b = exp(A(1,1)/A(2,1)) s...
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clc clear //Initialization of variables dFf=110.5 //ft-lbf/lbm Vd=1028 //ft/s gc=32.2 //ft/s^2 p0=100 //psia k=1.4 v0=2.08 p1=55 //psia p2=99.2 //psia //calculations dFe=0.01*Vd^2 /(2*gc) dF=dFf+dFe V2ig=(p0*144)^(1/k) *v0/(1-1/k) *((p1*144)^(1-1/k) -(p2*144)^(1-1/k)) C2=(V2ig+dF)/V2ig C=sqrt(C2) //res...
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// Example 2.20 clc; clear; close; // Given data m=2;// molecular mass UGC= 8.3143;// universal gas constant in kJ/kg-mole-K Cp= 14.41;// in kJ/kg-K R= UGC/m;// in kJ/kgK Cv= Cp-R;// in kJ/kgK gama= Cp/Cv; disp(R,"The value of R in kJ/kgK is :") disp(Cv,"The value of Cv in kJ/kgK is : ") disp(gama,"The val...
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//Chapter 23, Example 23.18 //Conversion of decimal to binary// clc //clears the console// clear //clears all existing variables// q=0 b=0 s=0 //initialising// //a=input(enter the decimal number to be converted to its binary form) //taking input from the user// a=34.6875 d=modulo(a,1) //separating the decimal part fro...
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clear// //Variables V = 6.0 //Applied voltage (in volts) R0 = 0.2 //Resistance (in ohm) R1 = 2.0 //Resistance (in ohm) R2 = 3.0 //Resistance (in ohm) R3 = 6.0 ...
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function [titel] = solve(x) // Decodeer monoalfabetische substitutie. Zie wiki. // if x == 0 then titel = "dummy" else titel = "the raven" end // Dummy toekenningen aan outputvariabelen endfunction
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//Eg-13.16 //pg-562 clear clc deff('out = func(in1,in2)','out = sin(in1)-in2') //To get the answers in the text book we shouldn't take sint=Vs to be unity! x(1) = 0; y(1) = 0; h = 0.1; for(i = 1:10) x(i+1) = x(i) + h; end a = (2^0.5-1)/2; b = (2-2^0.5)/2; c = -(2^0.5)/2; d = 1 + (2^0.5)...
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//problem 8 pagenumber 5.99 //given r1=9e3;//ohm k1=1.38*10^-23;format(6); t1=298;//k //determine voltage current spectraldensities rmsnoise r1=r1; er=sqrt(4*k1*t1*r1); i1=er/r1; er12=1/er; w=20e3-20; er1=nthroot(er,w); disp('voltage = '+string(er*10^9)+' nanovolt/√(Hz)');format(5); disp('current = '+strin...
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//Chapter 16_Bipolar and MOS Digital Gate Circuits //Caption : Fanouts //Example 16.3: A TTL gate is guartnteed to sink 10mA without exceeding ann output voltage Vol=0.4V and to source 5mA without dropping below Voh=2.4V. If Tih=100uA at 2.4V and Iil=1mA at 0.4V,calculate the low-state and high-state fan-outs. // So...
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//Ex2.11 //let input wave be V_in=V_p_in*sin(2*%pi*f*t) f=1; //Frequency is 1Hz T=1/f; V_p_in=10; //Peak input voltage V_th=0.7; //knee voltage of diode clf(); //let n be double the number of cycles of output shown in graph for n=0:1:8 t=T.*n/2:0.0005:T.*(n+1)/2 //time for each half cycle ...
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// example 4.41 // using chebyshev polinomials obtain least squares approximation of second degree; // the chebeshev polinomials; x=poly(0,"x"); T0=1; T1=x; T2=2*x^2-1; // I=integrate ('1/(1-x^2)^(1/2)*(x^4-c0*T0-c1*T1-c2*T2)^2','x',-1,1) // since; c0=integrate('(1/3.14)*(x^4)/(1-x^2)^(1/2)','x',-1,1) ...
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//Fluid Systems - By - Shiv Kumar //Chapter 4 - Pelton Turbine (Impulse Turbine) //Example 4.18 clc clear //Given Data:- Ns=15; //Specific Speed P=1200; //Shaft Power, kW Ht=500; //Total Head at reservoir, m Loss_per=5; //Percentage of Head loss in Pipe...
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Name=Valorant peek operator PlayerCharacters=PP Challenger BotCharacters=PP Target.bot IsChallenge=true Timelimit=60.0 PlayerProfile=PP Challenger AddedBots=PP Target.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=pole_field.map MapScale=1.0 BlockProjectilePredictors=true BlockCheats=true Invincible...
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clc clear //INPUT DATA ni=1.5*10^16//intrinsic charge carriers in m^-3 r1=10*10^-2//resistivity of p-type silicon in ohm m r2=10*10^-2//resistivity of n-type silicon in ohm m me=1350*10^-4//The mobility of the charge carrier in m^2 V^-1 s^-1 mh=480*10^-4//The hole charge carrier in m^2 V^-1 s^-1 e=1.6*10^-19//c...
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//Eg-10.12 //pg-458 clear clc close() x = [1.04 1.11 1.19 1.32 1.47 1.6 1.79 1.97 2.15 2.34 2.48 2.64 2.76 2.86 2.96]; y = [3.7 3.87 4 4.14 4.26 4.32 4.37 4.39 4.38 4.33 4.26 4.14 4.01 3.86 3.70]; exec cubicspline.sci cubicspline(x,y)
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networkTopology(3;4,10,3) inputOutputVector(5.900000,3.200000,4.800000,1.800000;0,1,0) inputOutputVector(4.300000,3.000000,1.100000,0.100000;1,0,0) inputOutputVector(5.200000,3.400000,1.400000,0.200000;1,0,0) inputOutputVector(5.800000,4.000000,1.200000,0.200000;1,0,0) inputOutputVector(6.000000,2.900000,4.500000,...
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load Divide.asm, output-file Divide4.out, compare-to Divide4.cmp, output-list RAM[13]%D2.6.2 RAM[14]%D2.6.2 RAM[15]%D2.6.2; set PC 0, set RAM[13] 25, set RAM[14] 5, repeat 3000 { ticktock; } output;
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//computation of Kp and Kc clear; clc; printf("\t Example 14.6\n"); //(a) CO2=0.236;//pressure of CO2 gas, atm Kp=CO2; //(b) T=273+800; delta_n=1; Kc=Kp*(0.0821*T)^-delta_n; printf("\t(a) the value of Kp of the reaction is : %4.3f\n",Kp); printf("\t(b) the value of Kc of the reaction is : %4.2f ...
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// Aim:Refer Example 3-9 for Problem Description. // Given: // Time period of operations: t=10; //s // Stroke of hydraulic cylinder: S=10; //ft // Load required to compress car: F_load=8000; //lb // Pump pressure: p=1000; //psi // Frictional Force: F_fric=100; //lb // Leakage: Q_leak=0.2; //gpm
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///////////////////////////////////////////////////////////////////////////////////////////// //// Неделя 9. //// Фильтрация случайных последовательностей. //// Дискретный фильтр Калмана. ///////////////////////////////////////////////////////////////////////////////////////////// clear; xdel(winsid()) deff('[numd] = r...
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//chapter18 //example18.6 //page405 L=50.7d-6 // H C=500d-12 // F R=10 // ohm Rl=1d6 // ohm fr=1/(2*%pi*(L*C)^0.5) R_dc=R Xl=2*%pi*fr*L Q=Xl/R Rp=Q*Xl R_ac=Rp*Rl/(Rp+Rl) printf("resonant frequency = %.3f Hz or %.3f kHz \n",fr,fr/1000) // amswer in book is incorrect printf("dc load = %.3f ohm \n",R_dc) printf("ac loa...
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// Additional solved examples , Example 20 , pg 339 rho=1.8*10^-8 //resistivity (in ohm*m) Ef=4.8 //Fermi energy (in eV) E=100 //electric field intensity (in V/m) n=6.2*10^28 //concentration of electrons (in atoms/m^3) e=1.6*10^-19 //charge in electron (in C) Me=9.11*10^-31 //mass ...
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// Example 7_1 clc;funcprot(0); // Given data D=6;// The diameter of a steel pipe in inch Q=2000;// Volume flow rate in gpm L=1.0;// Length in km nu=1.0*10^-6;// Kinematic viscosity in m^2/s rho=1*10^3;// The density of water in kg/m^3 // Calculation // (a) D=D*2.54*10^-2;// m Q=(Q*3.782*10^-3)/60;// m^3/s...