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//Example 6.10 // Nyquist plot for an Open-loop unstable system. xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ //System transfer function s=poly(0,'s'); sysG=(s+1)/(s*(s/10-1)); evans(sysG,50) exec .\fig_settings.sci; //custom sc...
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clc // Given that NA = 0.3 // numerical aperture of fiber d = 200 // core diameter in micro meter lambda = 0.9 // wavelength of propagating light in micro meter // Sample Problem 10 on page no. 268 printf("\n # PROBLEM 10 # \n") N_max = 2*(d/2)^2*%pi^2*NA^2/lambda^2 printf("\n Total number of propagating modes are %d....
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//boundary value problem using finite difference method //example 8.15 //page 328 clc;clear;close; deff('y=f(x)','y=cos(x)+((1-cos(1))/sin(1))*sin(x)-1'); h1=1/2; Y=f(0.5); y0=0,y2=0; y1=4*(1/4+y0+y2)/7 printf('computed value with h=%f of y(0.5) is %f\n',h1,y1) printf('error in the result with actual value %f...
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str = input("Enter a 3x3 matrix which has spaces to seperate", "string") v = evstr(strsplit(str, " ")) c11=v(1) c12=v(2) c13=v(3) c21=v(4) c22=v(5) c23=v(6) c31=v(7) c32=v(8) c33=v(9) a=[c11,c12,c13;c21,c22,c23;c31,c32,c33] u=a; disp(a,'the given matrix found out is a=') m=det(u(1,1)); n=det(u(...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 6 : SYNCHRONOUS MACHINES // EXAMPLE : 6.20 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA v = 11*10^3; // Operating voltage of the Synchronou...
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function mdaqDIOFunc(arg1, arg2, arg3) if argn(2) == 2 then func = arg1; enable = arg2; end if argn(2) == 3 then link_id = arg1; func = arg2; enable = arg3; if link_id < 0 then error("Invalid link ID!") end end ...
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// Scilab code Exa8.10 : : Page-352 (2011) clc; clear; r = 2e-015; // Range of nuclear force, metre h_kt = 1.0546e-34; // Reduced value of Planck's constant, joule sec m = 1.674e-27; // Mass of each nucleon, Kg K = round (2*h_kt^2/(2*m*r^2*1.6023e-13)); // Kinetic energy of each nucleon in centr...
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//To calculate the energy values n1 = 1; //for ground state n2 = 2; //for 1st excited state n3 = 3; //for 2nd excited state h = 6.626*10^-34; //planck's constant, J sec m = 9.1*10^-31; //mass of electron, kg L = 1*10^-10; //width, m E1 = h^2*n1^2/(8*m*L^2); //energy in ground state...
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clear; clc; printf("\t\t\tProblem Number 3.5\n\n\n"); // Chapter 3 : The First Law Of Thermodynamics // Problem 3.5 (page no. 96) // Solution P1=100 //Unit:psia //Pressure at the entrance to a steady-flow device Rho1=62.4 //Unit:lbm/ft^3 //the density of the fluid A1V1=10000 //Unit:ft^3/min //Entering fluid ...
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function image_extended = extensionDynamicRange (image) size_image=size(image); matix_columns = size_image(1); matix_arrows = size_image(2); for i=1:matix_columns for j=1:matix_arrows image_extended(i,j)=(255/(max(image)-min(image)))*(image(i,j)-min(image)); end ...
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clc; i=60; //current in ampere v=12; //voltage in volt t=3600; //time in sec p=i*v*t; //calculating power disp(p,"Number of joules = "); //displaying result
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clear; clc; // Reading from file fid = mopen('output.txt', 'r'); if (fid == -1) then error("cannot open file"); end flines = mgetl(fid); mclose(fid); N = strtod(flines(1)); a = list(); for i = 2:size(flines, 1) t = strsplit(flines(i), ' '); b = list(); for j=1:size(t,1) if isdigit(t(j)) then ...
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//Chapter 13, Problem 20, figure 13.72 clc; E1=12; //e.m.f source 1 E2=24; //e.m.f source 2 r1=3; //resistance in ohm r2=2; //resistance in ohm R=1.8; //resistance in oh...
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clc; h=6; //height in ft g=32; //gravitaional constant in ft/sec square t=sqrt((2*h)/g); //calculating time disp(t,"Time in sec = "); //displaying result
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clear; clf; n = -5:0.1:5; f = 20;fs=50; X = cos(2 * %pi * f/fs * n); subplot(1,2,1); plot2d3(n,X); dt = 1/1000; t = -0.1:dt:0.1; x = cos(2*%pi*f*t); xgrid(4); subplot(1,2,2); plot(t,x); xgrid(4);
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clear ; clc; // Example 28.3 printf('Example 28.3\n\n'); //page no. 875 // Solution fig. 28.3 // Given //Input analysis soln1 = 600 ; // Mass flow rate of entering solution 1 -[lb/hr] c1_NaOH = 10/100 ;// Fraction of NaOH in entering solution 1 T1 = 200 ;// Temperature at entry soln2 = 400 ;// Mass flow rate of ano...
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function result= bino(n, k, p) result = factorial(n)*(p^k)*((1-p)^(n-k))/(factorial(k)*factorial(n-k)) endfunction prob = bino(10,0, 0.1) + bino(10, 1,0.1 ); disp(prob, "The exact probability is "); probp = cdfpoi("PQ", 1, 1) disp(probp, "The poisson approximation is ")
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// Calculates the great circle (GRC) distance (in units of the radius) between // two points on a sphere, given with latitude/longitude, and a radius. // The cosine rule is used to find the distance. function [distance]=GRC_distance_latlondeg(lat_a_deg, lon_a_deg, .. lat_b_d...
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myVariable = linspace(0.2,2.5,24) ; chip_number=17; chip_numbers=string(chip_number) path = pwd(); count=1; m=1; counts=string(count) m_place=string(m); mkdir MITE_FG_CAL while count<15 MITE_blif = mopen(path+'/mite_FG.blif','wb') mputl('.model mite_FG',MITE_blif) mputl('.inputs net1_1',MITE_blif) mputl('.outputs gn...
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// Exa 6.13 format('v',7);clc;clear;close; // Given data f = 1;// in MHz f = f * 10^6;// in Hz omega = 2*%pi*f;// in rad/sec C = 65;// in pF C = C * 10^-12;// in F R = 10;// in ohm R_SH = 0.02;// in ohm // Q = X_L/R = X_C/R = 1/(omega*C*R); Qactual = 1/(omega*C*R);// True value of Q Qmeasured = 1/(omega*C*(...
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//Ex7_2 clc TA = 30 TJ = 48 PD = 4 TR = (TJ - TA)/PD disp("TA = "+string(TA)+"degreeC")//ambient temperature at which transistor is operated disp("TJ = "+string(TJ)+"degreeC")//junction temperature disp("PD = "+string(PD)+"W")//dissipated power disp("TR = (TJ - TA)/PD = "+string(TR)+"degreeC/W")//termal resist...
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src = imread("../images/cow2.jpg"); output = stylization(src,100, 10); //out of range values imshow(output);
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// PUNTO 1 : function fx = f1(x) fx = x(1)*x(1)+x(2)*x(2) endfunction /*function fx = f2(x) fx = exp(2*x(1)**2+x(1)-8) endfunction*/ // --------------------------------------- // Funcion que halla el t minimo function [tmin,fmin] = min1abFB(f,x,d,a,b,h) tmin = b; // acotamos tmin como b ya que sabemos qu...
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function [] = kiks_pushobj_test(id,runtime) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- ...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); #function density(xc,yc,zc) #{ # vl=exp(-0.5*sqrt(xc*xc+yc*yc+zc*zc))*xc; # return(vl); #} function density(xc,yc,zc) { rd=sqrt(xc*xc+yc*yc+zc*zc); f1=(6-rd)*exp(-0.5*rd); vl=f1*(2*sqr(zc)-(sqr(xc)+sqr(yc))); return(vl); } function denscolor(pt) { ...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 8 //Phase Equilibria //Example 20 clear; clc; //Given: P = 101.3; //total pressure of system (kPa) T = 337.5; //temperature in K x1 = 0.842; //Antoine constants //For methanol(1) A1 = 16.12609; B1 = 3394.286; C1 = 43.2; //For methy...
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clear; clc; //Example - 10.21 //Page number - 362 printf("Example - 10.21 and Page number - 362\n\n"); //Given P = 2.76*10^(6);//[N/m^(2)] - Pressure T = 310.93;//[K] - Temperature R = 8.314;//[J/mol*K] - Universal gas constant // For n-butane Tc = 425.18;//[K] - Critical temperature Pc = 37.97;//[bar]...
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//ques-2.24 //Finding percentage composition of dry products of combustion clc C=900;//weight of carbon in fuel (in g) H=6;//weight of hydrogen in fuel (in g) p=90;//Percentage of air used for combustion W_Th=(C*(32/12)+H*(16/2))*(100/23);//theoretical weight of air used (in g) W=W_Th*(p/100);//actual weight of ...
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######################################################### # This experiment presents IAPS pictures preceded by # instructions to upregulate or downregulate the # emotional response to the picture. # # Adapted by Gustav Nilsonne 120625 # Original script by Armita Golkar ################################################...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Title>Test case 2 - polarity dynamic - 8ms</Title> <Organization>Volkswagen</Organization> <Standard>VW 80000 2013</Standard> <Item>6.15 E-15 Reverse polarity</Item> <system> <PowerSystem>3</PowerSystem> ...
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<?php class [[NOM_TABLE_MAJ]] extends Base[[NOM_TABLE_MAJ]] { public function getRow($ID, $table){ $resultat = Doctrine_Query::create() ->from($table.' b') ->where('num=?',$ID) ->execute(); return $resultat; } //Recuperer un ligne public function getRow2($ID,$ta...
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// // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2011-2011 - DIGITEO - Bruno JOFRET // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The ter...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Estimate the Rate constant for a diffusion controlled reaction in water //Example 12.3 clc; clear; R=8.314; //Gas constant in J K^-1 mol^-1 T=298; //Absolute temperature in K eta=8.9*10^-4; //Viscosity of water in J s m^-3 (1J=1N m therefore N s m^-2=J s m^-3 ) KD=(8*R*T)*1000/(3*eta); //Rate...
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 module $rootnamespace$ { // $Classes/Enums/Interfaces(filter)[template][separator] // filter (optional): Matches the name or full name of the current item. * = match any, wrap in [] to match attributes // template: The template to repeat for each matched item // separator (optional): A separator ...
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//Example 6.14 //Lead compensation for DC motor. // the required value // for step response, set sw to 2 // for ramp response, set sw to 0 sw = 2
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clc; p=1.05;//bar V=0.02;//m^3 R=0.287;//m^3 T=15+273;//K m=p*V*10^5/(R*T*10^3); p2=4.2;//bar T2=p2*T/p; cv=0.714; Q=m*cv*(T2-T); Q_12=Q; cp=1.005; T3=288;//K Q_23=m*cp*(T3-T2); Q=Q_12+Q_23; disp("heat rejected is:"); disp("kJ",-Q); ch_entro=m*cp*log(T2/T3)-m*cv*log(T2/T3); disp("decrease in entropy of air is:"); ...
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clear; clc; z=3+4*%i; y=1/z; mprintf("the impedence=%fmho",abs(y));
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errcatch(-1,"stop");mode(2);//Example 3.15.2: shunt resistance ; ; //given data : Im=1;// in mA Rm=100;// in ohm I=100;// in mA Rsh=(Im*10^-3*Rm)/((I-Im)*10^-3); disp(Rsh,"shunt resistance,Rsh(ohm) = ") exit();
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function [longest] = solve(ns) temp = 0; longest = 0; if size(ns, 'r') == 0 then longest = 0; return; end lst = list(); lst2 = list(); for i = 1:size(ns, 'r') lst($+1) = i; end for i = 1:size(ns, 'r') lst2 = lst; lst2(i) = null(); temp ...
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clc; cp=6.3; h2=70; h1=15; T0=283;//K T1=343;//K T2=288;//K T3=1400+273;//K s2_s1=cp*log(T1/T2); b2_b1=cp*(h2-h1)-T0*(s2_s1); loss=cp*(h2-h1)*(1-T0/T3) eff=b2_b1/loss disp("effectiveness is:") disp("%",eff*100)
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clc //initialisation of variables H= -57.7979 //cal H1= -68.3174 //cal S= 45.106 //cal deg^-1 S1= 16.716 //cal deg^-1 T= 25 //C //CALCULATIONS H2= (H-H1)*1000 S2= S-S1 G= H2-(273.16+T)*S2 //RESULTS printf (' Gibs free energy= %.1f cal',G)
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//Chapter 1 //Example 1.13 //Page 31 clear; clc; TF=5; Temp_Res=0.2; //Calculation of required voltage resolution printf("The temperature change of 0.2 degree celcius will result in a voltage change of = %.1f mV",TF*Temp_Res);
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clear clc disp('Exa-3.2'); I=120;r=0.1*10^-9;Eev=2.3 //I-intensity in W/m^2 r in m & E in electron volt A=%pi*r^2;K=1.6*10^-19; // A=area and K is conversion factor from ev to joules t= Eev*K/(I*A); //time interval printf('The value of time interval was found out to be %.1f sec',t);
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//Initilization of variables //Co-ordinates with respect to point O x=17.9 //ft y=6.91 //ft z=46.3 //ft Fz=-4000 //lb Fy=0 //lb //Calculation Mx=y*Fz-z*Fy //lb-ft //Result clc printf('The scalar coefficient of the i term is the moment about the X-Axis Mx:%f lb-ft lb-ft',Mx) //lb-ft //The answer in the text ...
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clc clear V_s=300;//V R=60;//ohm L=2;//H t=40*10^-6;//s i_T=(V_s/R)*(1-exp(-R*t/L)); i=.036;//A R1=V_s/(i-i_T); printf("maximum value of remedial parameter=%.3f kilo-ohm",R1/1000);
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//fonction de distribution normal function [jeu1, jeu2] = distribue() //déclaration des variables paquetdecarte = [1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 5 5 5 5 6 6 6 6 7 7 7 7 8 8 8 8 9 9 9 9 10 10 10 10 11 11 11 11 12 12 12 12 13 13 13 13]; jeu1 = 1:26; jeu2 = 1:26; k=1 i=1 //distributio...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex3_13.sce clc; clear; //from the figure 3.25 the below values are taken Z1=complex(1.2,1.6); Z2=complex(1.0,-1.75); Z12=complex(6,8); V1=complex(110,0); V2=c...
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#================================================================================================= #HEADER #================================================================================================= no_logfile = false; active_buttons = 5; button_codes = 1,2,3,4,5; response_matching = simple_matching; ...
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///////////////////////////////////////////////////// /////////////// Voltage Data /////////////// ///////////////////////////////////////////////////// A = read("/scilab-scripts/AFDnewDataSecondRecordingsNumberPointsDividedBy4.txt",-1,11); //A = read("/home/naudin/Documents/article-2/AFD under Extreme Stimul...
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clc //Initialization of variables Tr=500 //R Ta=1000 //R dt=100 //R //calculations n1=1- Tr/Ta n2= 1-Tr/(Ta+dt) n3 = 1- (Tr-dt)/Ta //results printf(" Efficiency in case 1 = %.1f percent",n1*100) printf("\n Efficiency in case 3 = %.1f percent",n2*100) printf("\n Efficiency in case 3 = %.1f percent",n3*100)
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clc // Given that //True stress=100000*(True strain)^0.5 // Sample Problem on page no. 63 printf("\n # Calculation of Ultimate Tensile Strength # \n") //from the data given n=0.5 E=0.5 K=100000 Truestress=K*((E)^n) //let An(area of neck)/Ao=t //from log(Ao/An)=n t=exp(-n) UTS=Truestress*exp(-n)//fro...
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clc T=300 //K k=8.617*10^-5 //eV/K q=1.6*10**-19 //C ND=8*10^14//cm^-3 Vb=500 //V W=20*10^-6//m epsilonx=8.854*10^-14 //F/cm Wm=sqrt((2*epsilonx*12.4*Vb)/(q*ND)) Wm1=Wm*10^-2 //to convert into micrometer disp(Wm1,"W in meter=") Vb1=Vb*(W/Wm1)*(2-W/Wm1) disp(Vb1,"Vb1 in V=")
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//Signal and spectrum replication xn=[2 3 2 1]; XDFT=fft(xn,-1) yn=[xn xn xn]; YDFT=fft(yn,-1) YDFT1=3*[XDFT(1:1/3:length(XDFT))]; for i=2:3 YDFT1(i:3:length(YDFT1))=0; end YDFT1(12:-1:11)=0; disp(YDFT1,'the DFT of x[n/3] is'); hn=[xn(1:1/3:length(xn))] for i=2:3 hn(i:3:length(hn))=0; end hn(12:-1:11)=0; hn HDF...
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//ques7 //Measuring pressure with multifluid manometer clear clc Patm=85.6; //in kPa dwater=1000;//density of water in Kg/m^3 dmercury=13600;//density of mercury in Kg/m^3 doil=850;//density of oil in Kg/m^3 g=9.81;//acc due to gravity in m/s^2 h1=0.1;//height of water in metre h2=0.2;//height of oil in metr...
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V=230//applied voltage L=60D-3//inductance of coil f=50 //frequency of supply Xl=2*%pi*f*L I=230/Xl //if frequency is reduced to 20 Hz Xl=2*%pi*20*L I1=V/Xl mprintf("Current through the coil if frequency is reduced to 20 Hz=%f A\n",I1) //if frequency is increased to 60 Hz Xl=2*%pi*60*L I2=V/Xl mprintf("Cu...
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//Calculate the Partial pressure of Oxygen at an altitude of 30 km (stratosphere) //Example 19.2 clc; clear; Po=0.20; //Partial pressure of Oxygen at an sea level in atm g=9.81; //Gravitational constant in m s^-2 h=30*10^3; //height in m mew=0.03200; //Molar mass of Oxygen molucule in kg mol^-1 ...
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//Chapter 12 //Example 12.4 //page 453 //To calculate acceleration and rotor angle clear;clc; delta0=33.9; //initial rotor angle H=4; //inertia constant f=50; //frequency Pm=1; //mechanical power input t=0.05; //time interval angular_acceleration=(Pm-0.694*sind(delta0))*180*f/H; delta_change=0.5*angular_acceleration*t...
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clc // At P = .14 MPa h1 = 236.04 // Enthalpy at state 1 in kJ/kg s1 = 0.9322 // Entropy at state 2 in kJ/kgK s2 = s1 // Isenthalpic process // At P = 0.8 MPa h2 = 272.05 // Enthalpy at state 2 in kJ/kg h3 = 93.42 // Enthalpy at state 3 in kJ/kg h4 = h3 // Isenthalpic process m = 0.06 // mass flow rate in kg/s...
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// Example 24_13 clc;funcprot(0); //Given data T_1=27+273;// K p_1=1;// bar p_2=4;// bar n_c=0.80;// Isentropic efficiency of compressor n_t=0.85;// Isentropic efficiency of turbine e=0.75;// The effectiveness of regenerator p_lr=0.1;// Pressure loss in regenerator along air side in bar p_lcc=0.05;// Pressu...
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//example2.11 clc disp("P=4, Z=200, A=2, psi=25*10^-3 Wb") disp("(I_a)=(I_L)=60 A, R_a=0.15ohm, R_se=0.2 ohm") disp("V=(E_b)+(I_a*R_a)+(I_a*R_se)") disp("250=E_b+60(0.15+0.2)") b=250-(60*(0.15+0.2)) disp(b,"E_b(in V)=") disp("Now, E_b=(psi*P*N*Z)/(60*A)") disp("Therefore, 229=(25*(10^-3)*4*N*200)...
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//Network Theorem 2 //pg no 3.10 //example 3.9 //when 100 V source is acting alone disp("Vx-5I1=0");//equation 1 disp("Applying KVL to mesh,"); disp("10Vx-15I1=-100");//equation 2 A=[1 -5;10 -15];//solving equation in matrix form B=[0 -100]' X=inv(A)*B; disp(X);//negative because of opposite direction disp("...
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//Example 4.12 clc; Ra=25000; Rb=5000; V=30; //Voltage across given terminals VRb=Rb*V/(Ra+Rb); //Using Voltage divider between Ra Rb //Also the true voltage across Rb disp(VRb,'True voltage across Rb') // Case I: Given is sensitivity of 1000 S1=1000; ...
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clc; printf("Example 1.1\n"); // 1 Poise = 1g/cm s = ((1/453.6)lb)/((1/30.48)ft*1s) be=30.48/453.6*3600; //be->british engineering unit printf("\n 1 Poise = %.4f lb/ft s",be/3600); printf("\n = %.0f lb/ft h",be); // 1 Poise = 1g/cm s = ((1/1000)kg)/((1/100)m*1s) si=100/1000; //si->SI units printf("\...
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Objects to modify layout are... Objects to apply filter are... Uncompress all ----------------------------------------- Type Filter (Compression) Name ----------------------------------------- group / dset (1.000:1) /dset1 dset (1.000:1) /dset2 dset (1...
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*Testcase for CDSG, STPQ and LPQ Instructions mainsize 1 numcpu 2 sysclear archlvl z/Arch loadcore "$(testpath)/CDSG.core" runtest 1 v 900.38 v 940.70 *Compare v 940.10 *Want "Success ! CDSQ, STPQ and LPQ: OK" E2A48383 85A2A240 5A40C3C4 E2C76B40 #v 960.100 *Done nu...
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//Exa 1.9 clc; clear; close; //given data format('v',6); RatedPower=100;//in KVA RatedPower=100*1000;//in VA VL=1040;//in Volt Phase=3;//Machine phase If=40;//in Ampere Isc=200;//in Ampere EL=1040;//in Volt Eph=EL/sqrt(3);//in Volt Zs=Eph/Isc;//in Ohm Rs=0.2;//in Ohm Xs=sqrt(Zs^2-Rs^2);//in Ohm IL=19.2...
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// Example 24_29 clc;funcprot(0); //Given data T_1=15+273;// K p_1=1;// bar T_5=1000;// K dp_in=0.07;// bar dp_re=0.1;// bar R_c1=2;// Compression ratio n_c=0.80;// Efficiency of compressor n_c1=n_c; n_c2=n_c; dp_com=0.15;// bar dp_rh=0.1;// bar n_t1=0.87;// Efficiency of turbine 1 n_t2=0.7;// Efficien...
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clc;clear; //Example 3.8 //given data h=6.625*10^-34;//Plank's constant c=3*10^8;//speed of light in m/s E1=10.2;//in eV energy E2=12.09;//in eV energy e=1.6*10^-19;//the charge on electron in C //calcualtion //principal quantum no are 2 & 3 respectively W=c*h/(E1*e)*10^10; disp(W,'wavelength in angstrom...
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clc //initialisation if variables m=1*10^-4//kg v=0.0005//m^3 l=22.57*10^5//j t1=15//c p=6//kg/m^3 //calculations H=m*l h=v*p*(100-t1)*4.18 c=H/h //results printf(' specific heat of gas at constant volume= % 1f j',c)
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//Chapter 4: Radiation //Example 4-4.1 clc; //Variable Initialization theta = 30 //Angle of radiation (degrees) epsilon_0 = 8.854e-12 //Permittivity of free space (F/m) I_dl = 10 //Current in length dl (A-m) r = 100e3 //Distance of point from origin (m) //Calculation E_mag =...
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//Exa 11.20 clc; clear; close; //Given data : Vs=11;//kV f=50;//Hz D=2;//cm d=0.5;//cm epsilon_r=3.5;//relative permitivity pf=0.05;//power factor C=0.024*epsilon_r/log10(D/d)*10^-6;// F/km disp(C*10^6,"Capacitance of the cable(micro F)"); Vp=Vs*1000/sqrt(3);//Volt Ic=2*%pi*f*C*Vp;//A disp(Ic,"Charging c...
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function [lnum,lden,g]=factors(P,flag) //Given a polynomial or rational P, returns in list lnum polynomials of //degree 1 or two which are the factors of numerators of P. // and in lden the factors of denominator of P. g is the gain. // if flag=='c' unstable roots are reflected vs the imaginary axis // if flag=='d' u...
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function ret = xls_SelectWorksheet(WorksheetName) ret = %f; Worksheet = 0; r = %t; while r Worksheet = Worksheet + 1; try r = xls_SetWorksheet(Worksheet); catch r = xls_SetWorksheet(1); break; end name = xls_Ge...
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syms H G1 G2 G3 //separating the two paths we get 1+1=2 in parallel combinations //shifting take off point after 2*G3 and then after 2*G2*G3 a=(2*G2*G3)/(1+(2*G2*G3*H/(2*G3))) b=a/(1+(H*a)) c=G1*b Y=c/(1+(c*(1/(2*G2*G3)))) disp(Y,"C/R = ")
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function res=lusolve(fact,b) [lhs,rhs]=argn(0); if rhs<>2 then error('bad call to lusolve: needs 2 inputs'), end if type(fact) <> 15 then error('lusolve: first argument must be a list'), end res=lusolve1(fact(3),b)
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//Reading the input of the sound clc;clear; cd ("C:\Users\User\Desktop\Important\DSP\Assignment6"); [y, fs, bits] = wavread("message.wav"); /* To plot te graph to get the cutoff frequency //Clipping the original signal n=length(y) N=n/2; x=(fs/2)/N; y1=[0:x:((fs/2)-x)]; Y=fft(y); //Convert to frequency domain clf(); ...
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//Compression ratio r=20; //Cutoff percent x=0.05; //Ratio of specific heats y=1.4;
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clc; Rin=20000; rf=100000; Vout1=-12; Vout2=12; Vin=2.4; UTP=-(Rin/rf)*Vout1; LTP=-(Rin/rf)*Vout2; Vrin=(Vin-Vout1)*(Rin/(Rin+rf)); disp('V',UTP,"UTP=");//The answers vary due to round off error disp('V',LTP,"LTP=");//The answers vary due to round off error disp('V',Vrin,"Vrin=");//The answers vary due to ro...
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clc; //page no 186 //prob no. 6.1 //All frequencies in kHz fc=1*10^3; //in kHz W=15; DSBl=fc-W; //lowest freq of DSB signal DSBh=fc+W; //highest freq of DSB signal disp(DSBh,'to',DSBl,'(a) The range of freq is from '); BT=2*W; disp(BT,'(b) Transmission bandwidth is ');
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//to find power angle,field current clc; j=sqrt(-1); V=400; Vt=V/sqrt(3); pf=1; Ia=50; Xs=1.3; Ef=Vt-j*Ia*Xs; disp(-atand(imag(Ef)/real(Ef)),'power angle'); Pm=Vt*Ia*pf; pff=.8; Ia=Pm/(Vt*pff); ang=acosd(pff); Eff=sqrt((Vt*cosd(ang))^2+(Vt*sind(ang)+Ia*Xs)^2); If=.9; Iff=If*Eff/abs(Ef); disp(Iff,'f...
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clear; clc; // RDMP-3c.sce // A => B // No adiabático: serpentín // SECTORES N = 10; // divisiones del serpentín // SISTEMA DE ECUACIONES DIFERENCIALES function dxdt = f(t,x) // Variables diferenciales Ts = x(1:N) CA = x(N+1) T = x(N+2) // Calor transferido del reactor al serpentín i = 1:N; ...
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//example 17.12 clc; funcprot(0); // Initialization of Variable Nu=65.8; k=0.028; As=1.2*1.2;//area Ts=350;//temperature Tsurr=300;//temperature sigma=5.67e-8; epsilon=0.25;//emmisivity h=Nu*k/0.3; Pe=h*As*(Ts-Tsurr)+epsilon*sigma*As*(Ts^4-Tsurr^4); disp(Pe,"allowable electrical power in W"); clear()
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//Ex2_18 clc L1 = 1*10^-3 L2 = 5*10^-3 LT = (L1*L2)/(L1+L2) disp("L1 = "+string(L1)+"H")//inductance of coil 1 disp("L2 = "+string(L2)+"H")//inductance of coil 2 disp("1/LT = 1/L1 + 1/L2") disp("LT = (L1*L2)/(L1+L2) = "+string(LT)+"H")//parallel inductance
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// // This function is called once at the end of the simulation. // function[] = sswFinish() endfunction
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function [C,degC] = poladd(A,degA,B,degB) [rA,cA] = polsize(A,degA); [rB,cB] = polsize(B,degB); if cA ~= cB | rA ~= rB error('poladd: Inconsistent dimensions'); end degC = max(degA,degB); if degC >= degA A = [A zeros(rA,(degC-degA)*cA)]; end if degC >= degB B = [B zeros(rB,(degC-degB)*cB)]; end ...
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//Caption:Find the dimensions of D and L //Exa:12.12 clc; clear; close; P=7.5//Power of induction motor(in KW) p=4//Number of poles f=50//frequency(in hertz) V=415//Voltage applied of motor(in volts) e=0.88//Efficiency pf=0.87//Power factor b=2.5//Ratio of pull out torque to full load torque c=1.75//Ratio o...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, Ringleb Flow P=3</description> <executable>CompressibleFlowSolver</executable> <parameters>RinglebFlow_P3.xml</parameters> <files> <file description="Session File">RinglebFlow_P3.xml</file> <file description="Restart File"...
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// example 15.11 clc; clear; disp('The full scale count for ADC3511 is 1999 and for the ADC3711 is 3999. So, the largest value possible for the MSD in either case is 3 = 0011. clearly the MSB is not needed for th magnitue of the MSD. It is thus convenient to specif positive number when this bit is a 0 and a negtiv...
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//Example 22 // frequency clc; clear; close; k=100;//N/m m=100;//gm n1=((1/(2*%pi))*sqrt(k/(m*10^-3)));//sec^-1 m1=100;//gm m2=200;//gm mu=((m1*m2)/(m1+m2))*10^-3;//kg fr=((1/(2*%pi))*sqrt(k/mu));//sec^-1 disp(n1,"in first case frequency is,(sec^-1)=") disp(fr,"in second case frequency is,(sec^-1)=")
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//Example 16.11, page 624 clc E=200*1.6*10^-13//j/neutron E=10^-11//Rounding off p=E/(10^-3) P=10^8//in watt N=P/p printf("\n The number of free electron present is %e",N)
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//example 5.3// clc //clears the screen// clear //clears already existing variables// //conversion of given equation to its canonical POS form// disp('given=> Y=(A+B)(A+C)(B+C'')') disp('on solving') disp('Y=(A+B+CC'')(A+BB''+C)(AA''+B+C'')') disp('Y=(A+B+C)(A+B+C'')(A+C+B)(A+C+B'')(A+B+C'')(A''+B+C'')') //us...
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clear; clc; printf("\t\t\tExample Number 9.3\n\n\n"); // boiling on brass plate // Example 9.3(page no.-501-502) // solution Qawater_platinum=946.1;//[kw/square meter] from figure (9-8) heat flux for water platinum combination Tw=117;// [degree celsius] Tsat=100;// [degree celsius] // from table (9-2) Csf...
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// Exa 9.3 clc; clear; close; // Given data scale= 20;// in µS/cm gh= 3.2;//amplitude of the graph in cm T= gh*scale;// in mV disp(T,"The period of the waveform in µS is : ")
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//A function to compute error between computed data and measured data function err = errorfun(x, time, measured_data) err = (fit_function(time, x) - measured_data ) endfunction
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errcatch(-1,"stop");mode(2); //Declaring values Q=50; W=40; U=Q-W; printf('Change in Internal Energy= %2.0f kJ',U); exit();
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clc clear //Input data CO=12;//The composition of carbondioxide of combustion by volume in percentage C=0.5;//The composition of carbonmoxide of combustion by volume in percentage O=4;//The composition of oxygen of combustion by volume in percentage N=83.5;//The composition of nitrogen of combustion by volume ...
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[aws_csm_1] csm_enabled = true csm_port = 1234 csm_clientid = foo [aws_csm_2] csm_enabled = false csm_port = 5678 csm_clientid = bar
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clc; clear; //Example 6.12 Tf=353; //[K] T=273 //[K] mf_dot=10000; //Feed [kg/h] ic=0.07; //Initial conc of glycerine fc=0.4; //FinaL CONC OF GLYCERINE //Overall glycerine balance m3dot_dash=(ic/fc)*mf_dot //[kg/h] mv_dot=mf_dot-m3dot_dash //...