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//Solved_Ex.4.4->Determine the Trigonometric form of Fourier Series of the Full Wave Rectified sine wave clc; clear; T=8;//Defining Time Period A=2;//Defining Amplitude t=0:0.01:15; w0=2*%pi/T; function x=f(t),x=A.*abs(sin(t.*w0)) ,endfunction //given full wave rectified continuous signal plot(t,f); xlabe...
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//Caption:Determine the (a)speed (b)Torque (c)Efficiency //Exa:2.37 clc; clear; close; V=240;//in volts P=4; Phy=0.008;//in webers Z=1000; A=2; R_f=240;//in ohms R_a=0.4;//in ohms I_1=25;//in amperes I_f=V/R_f;//in amperes I_a1=I_1-I_f;//in amperes E_b=V-I_a1*R_a;//in volts N=E_b*60*A/(P*Z*Phy); disp(...
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// Scilab code Ex10.2: Pg:411 (2008) clc;clear; N = 2.7e+025; // Number of molecules per unit volume epsilon_r = 1.0024; // Dielectric constant due to electronic polarization epsilon_0 = 8.85e-012; // Permittivity of free space, force per meter // P = epsilon_0*(epsilon_r-1)*E and P = N*alpha_e*E, solving...
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// Exa 7.12 clc; clear; close; format('v',6) // Given data I_DSS = 12;// in mA V_P = 5;// in V R_D = 3.3;// in k ohm R_G = 1.5*10^3;// in k ohm R_S = 1.2;// in k ohm V_DD= 18;// in V I_D= poly(0,'I_D'); V_GS= I_D*R_S;// in V I_D= I_D-I_DSS*(1-V_GS/V_P)^2; I_D= roots(I_D); I_D= I_D(2);// in mA V_GS= I_D...
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//Example 3_31 clc; clear; close; format('v',5); //given data : I2=10;//A f=50;//Hz R1=5;//ohm L1=0.0191;//H R2=7;//ohm C2=398;//micro F R3=8;//ohm L3=0.0318;//H Z1=R1+%i*2*%pi*f*L1;//ohm Z2=R2-%i/2/%pi/f/(C2*10^-6);//ohm Z3=R3+%i*2*%pi*f*L3;//ohm VAC=I2*Z2;//V I1=VAC/Z1;//A I=I1+I2;//A VCB=I*Z3;//V...
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clc clear m=evstr(x_dialog('Enter a 3x3 matrix',['[0 0 0';'0 0 0';'0 0 0]']))
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//Example 4.16. clc format(6) disp("For a Hartley oscillator the frequency is given by,") disp(" f = 1 / 2*pi*sqrt(L_eq*C) where L_eq = L1+L2") leq=20+5 // in mH disp(leq,"Therefore, L__eq(in mH) = 20+5 =") f=(1/(2*%pi*sqrt(25*500*10^-15)))*10^-3 // in kHz disp(f,"Therefore, f(in kHz) =")
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//chapter27 //example27.2 //page575 R1=4 // ohm R2=4 // ohm R3=4 // ohm // for h11 and h21, imagine that output terminals are shorted hence it is clear that input impedence is equal to R1+R2*R3/(R2+R3) // this is h11 by definition so h11=R1+R2*R3/(R2+R3) // now current will divide equally at ...
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clc; clear; format('e',11); d=0.01/0.0254; //in inches. r=d/2; l=1; //in inches. N=20; L=(r^2)*(N^2)/(9*r+10*l); //Wheeler's formula. disp(L,"The inductance of the coil by Wheelers formula,L(in micro H)=");
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// Scilab Code Ex4.5: Page-236 (2008) clc; clear; c = 3e+008; // Speed of light in vacuum, m/s t0 = 2.5e-008; // Proper life time of pi-meson, s t = 2.5e-007; // MEan life time of pi-meson, s // As t = t0/(sqrt(1-v^2/c^2)), solving for v v = sqrt(1-(t0/t)^2)*c; // Velocity of pi meson, m/s printf("\n...
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// Chapter 2 Example 4 //============================================================================== clc; clear; //input data h = 6.625*10^-34; // plank's constant c = 3*10^8; // vel. of light in m/s lamda = 4961*10^-10; // wavelength of light in m ...
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// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 1 : REVIEW OF ELECRTIC CIRCUITS // Example : 1.11 clc;clear; // clears the console and command history // Given data Z = 3+%i*4 // impedance in Ω V_AN = 150 // voltage in V R = 3 // resistanc...
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// Example 9.9 clear all; clc; // Given data fluence = 10^8; // Given fluence neutrons/cm^2 // From Figure 9.12 // To receive an dose equivalent rate of 1 mrem/hr, the fast neutron flux is 7 neutrons/cm^2-sec phi_eq = 7; // Equivalent flux in neutr...
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//Part B Ex 2.14 clc;clear;close; format('v',9); dec=34.6875;//given decimal value i=floor(dec);//integer part f=dec-i;//fraction part i_bin=dec2bin(i);//binary equivalent of integer part f_bin=' ';//for initializing(string) for n=1:4 t=2*f; if t>=1 then p(n)=1; f=t-1; end if ...
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@@emplu.pkg CREATE OR REPLACE PROCEDURE test_emplu ( counter IN INTEGER, empno_in IN emp.empno%TYPE := 7788) IS emprec employee%ROWTYPE; BEGIN sf_timer.set_factor (counter); sf_timer.start_timer; FOR i IN 1 .. counter LOOP emprec := emplu1.onerow (empno_in); END LOOP; sf_timer.show_elapsed...
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//Example 1_2 clc(); clear; // To add the given vector displacements a=1 //units in meters b=3 //units in meters c=5 //units in meters d=6 //units in meters theta1=90 //units in degrees Rx_a=a*sin(theta1*%pi/180) //units in meters Rx_b=round(b*cos(theta1*%pi/180)) //units in meters theta2=37 //units...
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//Example No. 4.3 clc; clear; close; format('v',6); //Given Data : P=30;//KW theta1=54-30;//degree C t1=1;//hour theta2=67-30;//degree C t2=2;//hour(t2=2*t1) disp("theta=theta_f*(1-exp(-t/T))"); //Let exp(-t1/T)=a then exp(-t2/T)=a^2 //theta1/theta2=(1-a)/(1-a^2) //a^2*theta1-a*theta2+theta2-theta1=0 ...
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// //given h1=0.90,h2=1.25,h3=2.15,h4=2.50,h5=1.85,h6=1.35,h7=0.85, b=10//width in m sh=1.5//side slope in m h=40//m d1=(b+(sh*h1))*h1 d2=(b+(sh*h2))*h2 d3=(b+(sh*h3))*h3 d4=(b+(sh*h4))*h4 d5=(b+(sh*h5))*h5 d6=(b+(sh*h6))*h6 d7=(b+(sh*h7))*h7 printf("\n d1= %0.3f sq. meter,d2 = %0.3f sq. meter,d3= %0.3f sq. m...
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// Exa7.14 clc; clear; close; // given : phi=5 // HPBW,half power beam width in Degrees phi_not=2*phi // BWFN, null-to-null beam width in degrees Lm=poly(0,'Lm') // defining Lm as lambda // formula : phi=70*(Lm/D_a) // where Lm is wavelength in m and D_a is mouth diameter in m D_a=(70*Lm)/phi G_p=6.4*(D_a/Lm)...
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function [MTh,VTh,MSTh,VSTh] = gl_stat(N,maxp,Nu_I,Nu_O,st_j,Nu_Ma,rt_a,a,c,b,bu) // Ouput variables initialisation (not found in input variables) MTh=[]; VTh=[]; MSTh=[]; VSTh=[]; // Display mode mode(-1); // Display warning for floating point exception //ieee(1); //M and V for each phy_age MTh = zeros(maxp,6,N);...
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function [y,t] = rk4(fun,ti,tf,h,y0) // Método de Runge-Kutta para Sistema de N equações Diferenciais (interativo) - Ordem 4 // Onde -> y é o vetor solução (EDO's) // -> t é o vetor do tempo //--------------------------------------------------------------------- // -> fun é o vetor de funções do sistema (EDO's...
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errcatch(-1,"stop");mode(2);//Chapter 21, Problem 23 ; R1=150; //equivalent input resistance N=5; //turns ratio Rl=R1/(N^2); //load resistance printf("Optimum value of load resistance = %d ohm",Rl); exit();
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clear; clc; //Example - 7.30 //Page number - 267 printf("Example - 7.30 and Page number - 267\n\n"); //Given den_liq = 13690;//[kg/m^(3)] - Density of liquid mercury den_solid = 14190;//[kg/m^(3)] - Density of solid mercury mp = -38.87;//[C] - Melting point of mercury at pressure of 1 bar mp = mp + 273.15;...
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clear all clc close dia=0.03*1e-3;//Diameter of drop in m rho=2000;//Desnity of ink in kg/m vz=25;//velocity in z direction in m/sec L1=15*1e-3;//Length of deflection plate in m L2=12*1e-3;//distance from the exit end of the deflection plate to the print surface in m q=100*1e-15;//Charge of drop in C d=2*1e-...
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clc; funcprot(0); // Initialization of Variable AB=31325.14//slope distance in m R=6370.0e3;//radius of earth ha=1582.15;//elevation in m h=4251.32-ha//in m //calculation AB_dash=AB-h**2/2/AB; theta=2*asin(AB_dash/2/R); AB_dash=AB-(h*sin(theta/2)+h**2/AB/2) CD=AB_dash-AB_dash*ha/R; S=CD+CD**3/24.0/R**2; d...
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clc;funcprot(0);//EXAMPLE 12.8 // Initialisation of Variables Vpbes=7;.................//Volume of fuel in the pump barrel before commencement of effective stroke in cc df=3;.................//Diameter of fuel line from pump to injector in mm lf=700;.................//Length of fuel line from pump to injector in mm...
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//check o/p when the i/p contains negative elements impr=[-1 -2 -3 0 5]; num_ord=6; den_ord=4; [num,den]=prony(impr,num_ord,den_ord); disp(num); disp(den); //output //- 1. - 2. - 3. 0. 5. 0. // // 1. 0. 0. 0. 0.
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//example 9.4 //page 318 clc; funcprot(0); //initialisation of variable L=500; S=0.004;//slope of slope line hf=S*L; disp(hf,"head loss (ft)="); clear
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clc // Given that t = 400 // temperature in K k = 1.38e-23 // Boltzmann's constant in J/K h = 6.62e-34 // Planck constant in J-sec e = 1.6e-19 // charge on an electron in C m = 4 * 1.67e-27 // mass of helium atom in kg // Sample Problem 35 on page no. 14.34 printf("\n # PROBLEM 35 # \n") printf("Standard formula used...
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function [psd,f_out] = pburg(x,poles,freq,Fs,range,method,plot_type,criterion) //Calculate Burg maximum-entropy power spectral density. //Calling Sequence //[psd,f_out] = pburg(x,poles,freq,Fs,range,method,plot_type,criterion) //All but the first two arguments are optional and may be empty. //Parameters // x: ...
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//Ex:10.7 clc; clear; close; y=860*10^-9;// wavelength in m L=5000;// length in m X=0.024; dy=20*10^-9;// spectral width in m dts=6*10^-9;// silica optical link rise time in s dtr=8*10^-9;// detector rise in s c=3*10^8;// speed of light in m/s dtm=-(L*dy*X)/(c*y);// material dispersion delay time in s id=2....
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function mdaqDSPWait(arg1, arg2) if argn(2) == 1 then mdaqWaitUntilDone("dsp", arg1) elseif argn(2) == 2 then mdaqWaitUntilDone(arg1, "dsp", arg2) else mprintf("Description:\n"); mprintf("\tWaits until DSP application is complited\n"); mprintf("Usage:\n"); mp...
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//Example 7.2: Diffusion potential clc; clear; close; format('v',6) //given data : Na=5*10^23;// in m^-3 Nd=5*10^21;// in m^-3 T=300;// in K e=1.6*10^-19;// in J k=1.38*10^-23;// in JK^-1 V=(k*T)/e; ni=2.2*10^12;// in m^-3 Vd=V*log((Na*Nd)/ni^2); disp(Vd,"Diffusion potential,Vd(V) = ")
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//signals and systems //example4.5 // X(S) = s+3+5*exp(-2*s)/(s+1)*(s+2)) Re(s)>-1 s1 =%s ; syms t s; [A]=pfss((s1+3)/((s1+1)*(s1+2))); //partial fraction of F(s) F1 = ilaplace(A(1),s,t) F2 = ilaplace(A(2),s,t) //F3 = ilaplace(A(3),s,t) Fa = F1+F2; disp(Fa,"f1(t)=") [B]=pfss((5)/((s1+1)*(s1+2))); //partial ...
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clc;funcprot(0);//EXAMPLE 3.11 // Initialisation of Variables p1=1;...................//Initial pressure in bar t1=343;..................//Initial temperature in K p2=7;....................//Pressure after adiabatic compression Qs=465;...............//Heat addition at constant volume in kJ/kg cp=1;..................
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clear clc //initialisation of variables d= 1/3 //ft g= 32.2 //ft/sec^2 d1= 4 //in d2= 1.6 //in h1= 5.7 //ft h2= -1.9 //ft Q= 0.3 //cuses H1= 34 //ft H2= 19 //ft H3= 7 //ft H4= 9.2 //ft h3= 2.9//ft h4= 3.9 //ft Et= 54 //ft-lb/lb //CALCULATIONS v1= sqrt(2*g*(h1-h2)/((d1/d2)^4-1)) Q1= %pi*v1*d^2/4 k=...
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//Chapter 3_Semoconductor Devices Fundamentals //Caption: Hole Concentration //Example3.4: A semiconductor is doped with a concentration of 10^17 atoms/cm^3 of rsenic . What is the equilibrium hole concentration p at 300K. Given ni=1.5*10^10 cm^-3 // Solution: clear; clc; function p=holeconcentration(ni,Nd)//ni=i...
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clc clear disp("Example 8.31a") printf("\n") disp("perform the following binary substraction using 1s complement") disp("a)1010-0111 b)0110-1101") a=[1 0 1 0] b=~[0 1 1 1] d=0 for i=1:length(a) c(i)=a(length(a)+1-i)+b(length(a)+1-i)+d if(c(i)==1) d=0 end if[c(i)==2] d=1 ...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/StackArithmetic/StackTest/StackTest.tst load StackTest.asm, output-file StackTest.out, compare-to StackTest.cmp, output-list RAM[0]%D2.6.2 RAM[256]%D2....
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// Scilab code Ex3.15: Pg 97 (2008) clc; clear; N = 11; // Number of plates in a capacitor r = 25e-03; // Radius of circular plate, m A = (%pi*r^2); // Cross - sectional area of plate, m^2 d = 5e-04; // Distance between plates, m epsilon_r ...
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clc //Initialization of variables P=1.115 //bar //Calculations Conv_fac=1/1.01325 FinalP=Conv_fac*P //Final pressure //Results printf ('Final pressure in atmospheres (atm)= %.3f',FinalP)
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//bodeplot getf('labelbode.sci'); x=[0.001,0.0035,0.004,0.005,0.006,0.007,0.008,0.009,0.01,0.02,0.03,0.04];//Input frequency(Hz) y=[-3.87,-5.67,-7.53,-7.53,-8.17,-8.64,-8.87,-8.90,-9.11,-13.55,-15.39,-16.47];//Amplitude ratio(dB) subplot(2,1,1); plot2d(x,y,rect=[0.001,-20,0.04,0],logflag="ln"); xgrid(); y=[-25....
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function [y] = transpose(x) funcprot(0); y = callOctave("transpose",x) endfunction
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//Ex:10.2 clc; clear; close; a_fc=4;// fider cable loss in dB/km aj=0.7;// splice loss in db/km L=5;// length in km a_cr1=4;// connector losses a_cr2=3.5;// connector losses CL=(a_fc+aj)*L+(a_cr1+a_cr2);// total channel loss in dB printf("The total channel loss =%d dB", CL);
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//laplace transform of exponential function syms t s; y=laplace('%e^(-a*t)',t,s); disp(y,"ans=")
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function []=square(xmin,ymin,xmax,ymax) //definit un environnement graphique //permettant un trace isometrique. // //xmin,ymin, (xmax,ymax) specifient les abscisses et ordonnees minimum // (maximum) du dessin. defaut (-2,-2,2,2) // //square modifie le facteur d'echelle sur l'axe Ox. Pour conserver la //mem...
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// Problem no 10.3,Page No.252 clc;clear; close; //taking moment at pt A we get R_D=(90*6+120*3)*9**-1 //Reaction at Pt D //Joint D //Applying the summation of vertical forces we get F_GD=100*(sin(60*%pi*180**-1))**-1 //Applying the summation of horizontal forces we get F_DC=F_GD*cos(60*%pi*180**-1) //Joint G ...
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566769707=6 1390748355=-1 1854083915=1 742051504=-1 710084632=3 565750963=0 1429063010=true 1459925108=5 868270416=3 1809270213=false 236938571=0 1860957759=5 1794508226=4 221507525=-2 1957337308=-1 1505728679=0 887770454=0 491728531=-1 1393501683=5 371995505=-1 914153475=-2
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function y = f(x) y = 1 - (1+x).^-9 - (140/26.5)*x //função cuja raiz é procurada endfunction function y = d(x) y = 9*(1+x).^-10 - (140/26.5) //derivada da função endfunction x = 0.12 //valor inicial de x while (1) x_ant = x //recebe valor de x da iteração anterior x = x_ant - f(x_ant)/d(x_ant) //pon...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 16.12w //calculation of the length of the shortest closed organ pipe that will resonate with the tunning fork //given data nu=264//frequency(in Hz)of the tunning fork v=350//speed(in m/s) of the sound in air //calc...
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//=============================================================== //Chapter 10 Example 17 clc;clear all; //variable declaration r = 0.0250; //resistance in Ω R = 1.0125; //resistance in Ω S = 1 //sensitivity P1 = 10; //resistance in Ω Q1 = 10; //resistam...
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//ques5 clc disp('finding the fourier series of given function'); syms x l s=0; n=input('enter the no of terms upto each of sin terms in the expansion : '); for i=1:n bi=2/%pi*integ(x*sin(i*x),x,0,%pi); s=s+float(bi)*sin(i*x); end disp(float(s));
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function [x]=solsup(U,b) n = size(U)(1); //Nombre lignes de matrice for i=n:-1:1 if abs(U(i,i)) < %eps then error("Matrice U est non inversible"); end sum_temp = 0; for j=i+1:n sum_temp = sum_temp + U(i,j)*x(j); end x(i) = 1/U(i,i...
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//problem 1.18 a1=1.4*2.2*1.4 x1=1.6+0.7 x11=(1.4*1.4/(12*2.3))+x1 x2=0.7 x22=(1.4*1.4/(12*0.7))+x2 z=9810 p1=z*a1*x1 p2=z*a1*x2/1.4 p=p1-p2 h=(p1*(3-x11)+p2*(1.4-x22))/p f=(p1*(3-x11)-p2*(1.4-x22))/1.4 disp(p,"resultant force") disp(f,"force acting horizontally on the top of the gate")
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clear // // // //Variable declaration d=0.282 //lattice spacing(nm) theta=(8+(35/60))*%pi/180 //glancing angle(radian) n=1 //order //Calculation lamda=2*d*sin(theta)/n //wavelength(nm) N=2*d/lamda //maximum order of diffraction //Result printf("\n wavelengt...
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//check o/p i/p args are a matrix and a weight vector w A = [5 -4 6; 2 3 9; -1 1 2]; w = [0.5 0.25 0.25]; v=var(A,w); disp(v); // 6.1875 9.5 6.1875
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//Problem 40.22: Calculate the value of the energy stored when a current of 50 mA is flowing in a coil of inductance 200 mH. What value of current would double the energy stored? //initializing the variables: L = 0.2; // in H I = 0.05; // in Amperes u0 = 4*%pi*1E-7; ur = 1; //calculation: //energy stored in...
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clear // p=30 i=10 v=p/i dt=1 dq=i*dt dw=v*dq energy=dw/i printf("\n energy of each coulomb of charge= %0.1f J",energy)
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clc //the code uses userdefined function complexstring function s=complexstring(a) if imag(a)>=0 then s=sprintf('%g+%gi',real(a),imag(a)) else s=sprintf('%g%gi',real(a),imag(a)) end funcprot(0) endfunction E1=2400 //primary voltage rating in volts E2=240 ...
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//Initilization of variables F1=90 //lb theta1=((40*%pi)/180) //radians theta2=((30*%pi)/180) //radians //Calculations R_x=0 //lb R_y=20 //lb //Taking the sum of forces in the X-Direction P=((F1*cos(theta1))/cos(theta2)) //lb //Taking the sum of the forces in the Y-Direction F=(P*sin(theta2))+(F1*sin(theta1))...
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//Variable declaration chi=-0.4*10**-5; //magnetic susceptibility H=5*10**5; //magnetic field(A/m) mew0=4*%pi*10**-7; //Calculation B=mew0*H*(1+chi); //flux density(Wb/m**2) M=chi*H; //magnetic moment(A/m) //Result printf('flux density is %0.3f Wb/m**2 \n',(B)) printf('magnetic ...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 8.8\n\n\n"); // Chapter 8 : Vapor Power Cycles // Problem 8.8 (page no. 387) // Solution //Neglecting the pump work,we have heatrate=3413/0.273; //Unit:Btu/kWh //0.273=efficiency //1 kWh=3413 //heat rate printf("The heat rate is %f Btu/kWh\n",heatrate...
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//calculating GCV and NCV //Example 2.2 clc clear C=90//percentage of Carbon in coal O=2//percentage of Oxygen in coal H=4//percentage of Hydrogen in coal S=2.5//percentage of Sulphur in coal N=1//percentage of Nitrogen in coal GCV=((8080*C)+(34500*(H-O/8))+(2240*S))/100//gross calorific value in kcal/kg NCV=...
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//Chapter 18 //Example 18_13 //Page 440 clear;clc; a=1*(cosd(120)+%i*sind(120)); r=1; vry=200; vyb=346; vbr=400; //referring to the phasor diagram //vbr is twice vry, ie, factor =2 //vyb=1.75 times vry alpha=acosd((1+1.75*cosd(90))/2); Vry=vry*(cosd(180)+%i*sind(180)); Vyb=vyb*(cosd(90)+%i*sind(90)); Vbr=vbr*(cosd...
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//Example 3-5, Page No - 108 clear clc It = 5.1 Ic =4.8 m=(2*((It/Ic)^2-1))^0.5 printf('The percentage of modulation is %.1f',m*100)
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clc; clear all; f = 7e6; // Ultrasonic frquency in hertz theta = 45; v = 1.5; // Blood velocity in m/s U = 1500; // Ultrasonic velocity in m/s deltaf = (2*f*v*cosd(45))/U disp('Hz',deltaf,'The frequency of the doppler flowmeter is') //Variation in anser as compared to textbook..checked in calculator also.. the...
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pathname=get_absolute_file_path('17_3.sce') filename=pathname+filesep()+'17_3_data.sci' exec(filename) //Brake power bp=(2*%pi*N*T)/60000 //Friction power fp=ip-bp //Percentage losses Loss=fp/bp*100 printf("\n\nRESULTS\n\n") printf("\nPercentage losses:%f\n",Loss)
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clc; p=2; // number of poles f=50; // frequency of machine D=1.6; // diameter of cylindrical rotor l=1.8; // length of cylindrical rotor g=0.012; // air gap length rm=4000; // peak value of rotor mmf rs=6000; // peak value of stator mmf ph=140; // phase difference between stator mmf and rotor mmf uo=4*%pi*10^-...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 9 : Sinusoids and Phasors // Example 9 - 3 clear; clc; close; // // Given data Z1 = complex(40*cosd(50.0000),40*sind(50.0000)...
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// ch-1 page-36,37 pb-7 // // BE=50 AB=25 AEC=157.5-67.5 al=atan(BE/AB) al=al*(180/%pi) printf("\n al %0.3f ",al) bt=90-al printf("\n bt= %0.3f ",bt) k=(tan(bt*%pi/180)) printf("\n k= %0.3f ",k) BC=BE/k C=275.5+BC printf("\n chinage of c is %0.3f meters',C)
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// Scilab code Exa3.8 : : Page 125(2011) clc; clear; x = 0.25; // Thickness of Al, metre U_l = 1/x*log(50); // Linear absorption coefficient d = 2700; // density of the Al, Kg per cubic centimetre x_h = log(2)/U_l; // Half value thickness of Al, metre U_m = U_l/d; // Mass absorp...
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//chapter 1 Ex 17 clc; clear; close; dividend=2010; divisor=19; mod=modulo(dividend,divisor); //remainder printf("The least number to be added is %d",(divisor-mod));
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clc //initialisation of variables ph=13.89 //pressure in bar under 36 degrees temp p1=1.447 //pressure in bar under -26 degrees temp h1=1411.4 //kj/kg s1=5.718 //kj/kgk h2=1561.7 //kj/kg h3= 150 //kj/kg h4=185.8 //kj/kg h5=1445.5 //kj/kg s5=5.327 //kj/kgk s5=5.327 //kj/kgk h6=1607.6 //kj/kg r=25 //CALCU...
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//Chemical Engineering Thermodynamics //Chapter 3 //First Law of Thermodynamics //Example 3.12 clear; clc; //Given W = 0;//pump work Mi = 0;//chamber is initially evacuated M2 = 0;//no exist stream H1 = 684.2;//enthalpy of steam at 200 deg cel & 3 Kgf/cm^2 //To calculate the internal energy of the stea...
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clear // //variable declaration P1=5.0 //Inclined at 45° down Loading at 3m distance from A,KN P2=10.0 //Inclined at 45° down Loading at 2m distance from A,KN P3=10.0 //Inclined at 45° down Loading at 1m distance from A,KN P4=5.0 //Inclined at 45° down Loading A,KN P8=5.0 //Inc...
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//check o/p when i/p is a vector v =[8 9 1 10 6 1 3 6 10 10]; m=cummin(v); disp(m); //output // column 1 to 7 // // 8. 8. 1. 1. 1. 1. 1. // // column 8 to 10 // // 1. 1. 1.
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// 18/04 x = linspace(0,1,100) plot(x,x^2)
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no_logfile = true; begin; picture { background_color = 153,153,153; } et_calibration; #stimulus display graphics. array { bitmap { filename = "dixie.jpg"; preload = false; scale_factor = 2.0; }; bitmap { filename = "town.jpg"; preload = false; scale_factor = 2.0; }; } graphics; #cursor for left eye elli...
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clc; y=1.135; p1=10; pc=p1*[2/(y+1)]^[(y/(y-1))]; h1=2778; hc=2675; xc=0.962; vg=0.328; vc=xc*vg; Cc=(2*[h1-hc]*10^3)^0.5; A_m=vc/Cc*10^6; disp(A_m);
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function link_id = mdaq_open() global %microdaq; link_id = -1; result = 0; [ip_address, result] = mdaq_get_ip(); if result < 0 then disp("ERROR: Unable to get IP address - run microdaq_setup!"); return; end link_id = mdaq_connect(ip_address, 4343); if link_id == -1 th...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 4, Example 4") //Impeller tip diameter = 1m //Speed = 5945 rpm //Mass flow rate of air = 28 kg/s //Static pressure ratio p3/p1 = 2.2 ...
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function [i,j]=num2pos(k) //S = sudoku with 9 rows and 9 columns //k = element's position number //(i,j)=position of the entry in the sudoku i=1+pmodulo(k-1,9) j=1+(k-i)/9 endfunction
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// Exercise E3 // ------------ // Implement the cholesky analysis for a band and symmetric array // so that you avoid unnecessary calculations. // --------------------------------------------------------- function L=cholesky(A) [m,n]=size(A); if m~=n then disp('matrix u is not square'); return; end for k=1:n ...
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clc; close(); clear(); //page no 535 //prob no. 16.13 n1=1; //refraction index of air E2=4 //material dielectric constant theta_i=50 //angle of incidence in degree (misprinted in the solution) n2=sqrt(E2); theta_r=asin(n1/n2*sin(theta_i*%pi/180)); mprintf(' The angle of refraction is %.2f \n (using ...
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Vp=3; Vm=4.5; t=0:0.01:2*10; Vm = Vm*(sin(2*3.14*t)) ; subplot(311); plot(Vm); subplot(312); plot(Vp*Vm*(sin(2*3.14*t)));
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clc; F=300 // N , given force AB=sqrt(8^2+6^2);// m Length of AB cos_alpha=8/AB; sin_alpha=-6/AB; Fx=F*cos_alpha;//N, Horizontal component Fy=F*sin_alpha;// N, Vertical Component printf("Horizontal component of F is %.2f N\n",Fx); printf("Vertial component of F is %.2f N\n",Fy); printf("We may write F as \n ...
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// // // Generates C file and corresponding headers for filters used in // C implementation // clear(); exec('sci_vor_filters.sci'); [filters] = vor_get_filters(); filter_name = [ "BP_VAR" "BP_REF" "LP_DECIM" "LP_VAR" "LP_REF" "LP_FM" ]; f...
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clc //Example 8.13 //Calculate temperature and the velocity of air inside the shock wave //Let subscript y denote air inside the shock wave and x denote the air outside the shock wave ratio_T=1.2309//dimentionless Tx=528//R (Rankine temperature scale) Ty=ratio_T*Tx//R (Rankine temperature scale) printf("temperat...
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function r=mtlb_prod(a) // Copyright INRIA if type(a)==4 then a=bool2s(a);end if size(a,1)==1|size(a,2)==1 then r=prod(a) else r=prod(a,1) end
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figure(1); a = gca(); a.box = "off"; a.filled = "on"; a.isoview = "on"; a.data_bounds = [-2;2;-2;2]; a.grid=[1,1]; for t=0:0.1:1 robot1 = [t;0;0;0;0;0.3]; robot2 = [t;1;0;0;0;0.2]; delete(a.children); drawlater(); drawTurtleSide(robot1(1),robot1(3),0.6); drawTurtleSide(robot...
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// Example 4.6, page no-134 clear clc p=3600 //Power required t=1.2 //worst case eclipse period c=90 //capacity of each cell in Ah v=1.3 //voltage of each cell in V d=0.8 // Depth of discharge e=0.95 //Discharge efficiency E_sp=60 //specific energy specification ...
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//(Threaded Joints) Example 7.11 //Refer Fig.7.26 on page 243 //Screw pitch circle diameter 2b (mm) b = 300/2 //Flange diameter 2a (mm) a = 400/2 //External force acting on the bearing P (kN) P = 25 //Eccentricity value l (mm) l = 150 //Maximum permissible tensile stress in the cap screw sigmaMax (N/mm2) s...
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//chapter 13 //example 13.10 //page 570 printf("\n") printf("given") hfemin=100;hfemax=400;hiemin=2*10^3;hiemax=5*10^3;Rc=12*10^3;Rl=120*10^3;Re1=150 disp(" voltage gain at extreme value ") Avmax=(hfemax*((Rc*Rl)/(Rc+Rl)))/(hiemax+Re1*(1+hfemax)) Avmin=(hfemin*((Rc*Rl)/(Rc+Rl)))/(hiemin+Re1*(1+hfemin)) disp("a...
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//EXAMPLE 26.21(c) //4-POLE DC SHUNT GENERATOR clc; funcprot(0); //Variable Initialisation P=4;.........................//Total number of poles S=80;........................//Total number of slots C=10;.........................//Total number of conductor per slots E1=400;.........................//Generated...
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//ramanujan's method //example 2.21 //page 45 clc;clear;close; deff('y=f(x)','1-((13/12)*x-(3/8)*x^2+(1/24)*x^3)'); a1=13/12,a2=-3/8,a3=1/24; b1=1; b2=a1; b3=a1*b2+a2*b1; b4=a1*b3+a2*b2+a3*b1; b5=a1*b4+a2*b3+a3*b2; b6=a1*b5+a2*b4+a3*b3; b7=a1*b6+a2*b5+a3*b4; b8=a1*b7+a2*b6+a3*b5; b9=a1*b8+a2*b7+a3*b6; pr...
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/** DESCRIPTION: SCENARIO FILE PROVIDES DEFAULTS, GRAPHICAL OBJECTS, AND TRIAL DEFINITIONS FOR A BLOCKED EXPERIMENT OF PRIMED KANIZSA SHAPES Author : Ben Cowley Created: 01-05-2012 Modded : 28-03-2017 */ # FIXME TODO: can do language localisation? # FIXME TODO: check all defaults are needed? ...
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// Function Name: sortIndex // Return a vector which describes the sorted order of the elements of inputvec1 (ie. it contains the indices of the elements of inputvec1) // 3rd parameter : 0/1 for ascend/descend // Calculating the sortIndex. inputvec1 = [5, 4, 3]; result = armaVec("sortIndex",inputvec1) result = ...