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graphe-etoile-cycle.sce
// fichier de fonctions //construire le graphe en étoile function [graphe] = etoile(n) /*sommets = n orientation = %F // graphes non-orienté un = ones(1,n-1) // matrice composée de 1 uniquement colonnes = [2:1:n] aretes = [un; colonnes]' // transposée de la matrice graphe = list(sommets,orienta...
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Ex9_8.sce
//Ex 9.8 clc; clear; close; format('v',6); f0=3;//kHz(Critical frequency) Ap=4;//Pass band gain //For Butterworth filter using sallen key alfa=1.414;klp=1;//constant fH=f0;//kHz f_3dB=f0;//kHz disp("Various design parameters are :-"); C1=0.01;//micro F//Chosen for the design disp(C1,"Capacitance C1(micro F...
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11_17.sce
//Example 11.17 //Bender Schmidt Method //Page no. 396 clc;clear;close; h=1;k=1/10;c=sqrt(5); r=k*c^2/h^2; for i=1:6 if i<4 then u(6,i)=20*(i-1) else u(6,i)=60 end end disp(u,'u = ') k=1; printf('\n\n') for i=5:-1:1 for j=2:6 if j~=6 then u(i,j)=(...
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//Chapter 5, Example 5.3 clc //Initialisation' di=3 //change in current w.r.t time l=10*10**-3 //inductance in henry //Calculation v=l*di //voltage induced //Results printf("Voltage Induced V = %d mV",v*10**3)
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mp_dcp_update_static_patients.tst
declare json = vc go set json = '{"patient_request":{"patient_list_id":5406073.0,"person_id":45142166.0 ,"rank":1,"action_desc":"\ update rank"}}' go execute mp_dcp_update_static_patients "MINE", json go
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ATWM1_Working_Memory_MEG_Salient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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V1.SCE
:RAUM1 WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP WAND1.BMP FIGUR.BMP HINTER.BMP AETZ.BMP TUER1.BMP TUER2.BMP WAND2.BMP HINTER.BMP HIN...
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20.sce
clc cv_O2=0.39; //kJ/kg K cv_N2=0.446; //kJ/kg K n_O2=1; n_N2=2; M_O2=32; M_N2=28; m_O2=32; //kg m_N2=2*28; //kg T_O2=293; //K T_N2=301; //K R0=8.314; p_O2=2.5*10^5; //Pa p_N2=1.5*10^5; //Pa T2=(m_O2*cv_O2*T_O2 + m_N2*cv_N2*T_N2)/(m_O2*cv_O2 + m_N2*cv_N2); V_O2=n_O2*R0*10^5*T_O2/p_O2; V_N2=n_N2*R0...
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Ex8_2.sce
//Example 8.2 m=0.057;//Mass of ball (kg) v_i=0;//Initial velocity (m/s) v_f=58;//Final velocity (m/s) delta_p=m*(v_f-v_i);//Change in momentum (kg.m/s) delta_t=5*10^-3;//Duration of contact of ball with racquet (s) F_net=delta_p/delta_t;//Net external force (N) printf('Average force exerted on the ball by the r...
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EX1_13.sce
clear; clc; printf("\nEx1.13\n"); //page no.-24 //given d=1.5;.............//interatomic spacing in Angstrom lambda=1.4;.......//wavelength theta=90;.......//angle in degree //by BRAGG'S RELATION 2dsin(theta)=n*lambda n=(2*d)/lambda.........//order of diffraction printf("\nmaximum order of spectrum is 2\n...
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Ex10_5.sci
//program to graph the frequency response of the system close all; f=[0:2:2000]';W=2*%pi*f; //compute the frequency response vector H=6e6./((%i*W + 200).^2+2441.3^2); //Graph the magnitude and phase of the frequency response subplot(3,1,1); plot(f,abs(H),'k'); a=gca(); xlabel('Frequency,{\itf} (Hz)'); ylabel(...
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Ex6_26.sce
clc clear T1=288; //in K T3=1673; //in K Qs=800; //in kJ/kg G=1.4; Cv=0.718; R=0.287; P1=1; Cp=Cv*G; T2=T3-(Qs/Cp); x=T2/T1; r=x^(1/(G-1)); printf('Compression Ratio %2.1f ',r); printf('\n'); Eff=100*[1-(1/(r^(G-1)))]; printf('Efficiency is %2.1f Percent',Eff); printf('\n'); P...
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EXAMPLE5_37.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 5 //ANGLE MODULATION clear all; clc; printf("EXAMPLE 5.37(PAGENO 260)"); //given // s(t) = 20*sin(6*10^8*t + 7*sin(1250*t)) //comparing with standard eqn s(t) = A*sin(w_c*t + m_f*sin(w_m*t)) //we get w_c = 6*10^8//carrier angular frequency...
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eg22_2.sce
clear; //clc(); v=110; f=50; l=150; d=10*10^(-3); irr_fac=0.85; v_grad=30; p=750; t=30; D=2.5; r=d/2; del=(0.392*p)/(273 + t); e=v_grad*100*irr_fac*r*del*log([D/r])/sqrt(2); en=v/sqrt(3); pc=(244/del)*(f+25)*(en-e)^(2)*sqrt(r/D)*l/100000; tot_loss=3*pc; printf("The total corona loss is: %.2f kW",...
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Ex8_2.sce
////Given b=-32 a=32.0 c=1 //Calculation // r=(-b+(sqrt(b**2-(4*a*c))))/(2.0*a) //Result printf("\n The ratio of E/V0 = %0.3f ",r*10**0) printf("\n -ve value is not possible. ")
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ex12_2.sce
//Solutions to Problems In applied mechanics //A N Gobby clear all; clc //initialisation of variables p=1.23//ft^2 t=0.197//ft^2 u=1.595//ft^2 g=13.56//ft^2 w=9.2//in m=0.97//in //CALCULATIONS H=(g-1)*w/12//ft^2 Q=m*u*sqrt(H)//ft^3 S=Q*60*62.4/10//gallons/min //RESULTS printf('the head difference in feet o...
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13_2_soln.sce
clc; pathname=get_absolute_file_path('13_2_soln.sce') filename=pathname+filesep()+'13_2_data.sci' exec(filename) // Solution: // initial temperature of air in Rankine, T1=T1+460; //deg R // final temperature of air in Rankine, T2=T2+460; //deg R // final volume of air, // Charle's Law, V2=(T2/T1)*V1; //in^3 // Result...
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Ex13_32.sce
clear //Given f=50 //Hz L=0.03 R=8 //ohm Ev=240 //V //Calculation // Xl=2*%pi*f*L Z=sqrt(R**2+Xl**2) Iv=Ev/Z P=Iv**2*R a=R/Z Xc=2*Xl C=1/(2*%pi*f*Xc) //Result printf("\n (i) The value of current is %0.2f A",Iv) printf("\n The value of power is ...
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clc Na=10^17 disp("Na = "+string(Na)+" cm^-3") //initializing value of acceptor concentration. Nd=5*10^16 disp("Nd = "+string(Nd)+" cm^-3") //initializing value of donor concentration. e=1.6*10^-19 disp("e = "+string(e)+" columbs") //initializing value of charge of electrons. no=1.5*10^10 disp("no = "+string(no...
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so where are the robots we ve been told for 40 years already that they re coming soon very soon they ll be doing everything for us they ll be cooking cleaning buying things shopping building but they are n t here meanwhile we have illegal immigrants doing all the work but we do n t have any robots so what can we do abo...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Passing a parameter to argument funtion of ode host('make /tmp/ext10c.o'); param=[0.04,10000,3d+7]; link('/tmp/ext10c.o','ext10c','C'); y=ode([1;0;0],0,[0.4,4],'ext10c') //param must be defined as a scilab variable upon calling ode
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//problem 6 pagenumber 2.90 //given format(6); r1=2e3;//ohm rf1=8e3;//ohm A=45;//open loop gain a=1+(rf1/r1);//Nonverting gain gain=A/(1+A/a); disp( 'Gain = '+string(gain));//no unit
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// Example 6.34 Calculate the seasonal indices in the case of the following clc; clear; Q1=[39 45 44 53]; Q2=[21 23 26 23 ]; Q3=[52 63 69 64]; Q4=[81 76 75 84]; T1=sum(Q1); T2=sum(Q2); T3=sum(Q3); T4=sum(Q4); T=[T1 T2 T3 T4]; AM=T./4; GA=sum(AM)/4; SI=(AM./GA)*100; disp(SI,"Seasonal Index=",GA,"Grand Ave...
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clc //initialisation of variables Cd= 0.98 g= 32.2 //ft/sec^2 H= 2 //ft //CALCULATIONS v= sqrt(2*g*H) t= H/v h= 0.5*g*t^2 //RESULTS printf ('Vertical distance fallen in this ttime = %.f ft',h) //The answer given in textbook is wrong.
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clc;clear; //Example 17.9 //given data m=2.86; Ma1=2; P01=1; P1=0.1278; T1=444.5; p1=1.002; //from Table A-2a R=0.287;//in kJ/kg-K cp=1.005;//in kJ/kg-K k=1.4; //calculations //part - a //from Table A-33 at Ma1=2.0 Ma2=0.5774; P0201=0.7209;//P02/P01 P21=4.5;//P2/P1; T21=1.6875;//T2/T1 p21=2....
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// Example 6.8;// GAIN,INPUT VOLTAGE AND OUTPUT VOLTAGE clc; clear; close; Vs=10;//output voltage in milli volts Vi= 0.01;//input voltage in volts A=200;//amplifier gain without feedback D=0.1;//distortion without feedback Df=0.01;//distortion with feedback Beta=( (D/Df)-1)/A;// feedback ratio fop= (Beta*100)...
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//Problem 6.09: //initializing the variables: H0 = 28; // in Btu/lb H1 = 1151; // in Btu/lb Qh = 700; // in Btu/lb S0 = 0.056; // in Btu/lb deg R S1 = 1.757; // in Btu/lb deg R Th = 300; // in deg F Tc = 60; // in deg F P1 = 1; // in atm T1 = 212; // in deg F T0 = 60; // in deg F //calculation: Qc = ...
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clc //Intitalisation of variables clear m= 1.247 //gm hc= 2745 //cal deg^-1 mw= 122.12 //gm dT= 2.87 //C //CALCULATIONS mh= dT*hc*mw/(m*1000) //RESULTS printf ('molar heat of combustion of benzoic acid = %.1f kcal mole^-1',mh)
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//Exa 5.6 clc; clear; close; format('v',6); //Given Data : T=727+273;//Kelvin T0=17+273;//Kelvin deltaQ=4000;//KJ deltaS=deltaQ/T;//KJ/K A=deltaQ-T0*deltaS;//KJ disp(A,"Availability of heat energy in KJ : "); UA=T0*deltaS;//KJ disp(UA,"Unavailable heat energy in KJ : ");
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//Checking if error message pops up when input is 3x3 instead of 3x4 inpt =[ 3 0 5 1 3 14 ; 10 20 1 ]; [cam rot trans rotX rotY rotZ euler] = decomposeProjectionMatrix(inpt); //output-> // !--error 999 //Projection matrix should be 3x4.
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clc //initialisation of variables H= -40.023 //kcal H1= -22.063 //kcal //CALCULATIONS H2= H-H1 //RESULTS printf (' Enthalpy = %.3f kcal ',H2)
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COMPORT=8; // mount library on handle "1" h=slMount(); // handle "1": check availability of specified COM port slCheck(h,COMPORT); // handle "1": configure port slConfig(h,9600,8,0,1); // handle "1": open port slOpen(h,COMPORT); n=900 i=2; t=1; prevdata=0; tic(); //h=openserial(8,"9600,n,8,1",blocking=%t); //data=z...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 19 clc; disp("CHAPTER 1"); disp("EXAMPLE 19"); //VARIABLE INITIALIZATION v=7; //voltage source in Volts I=7; //current source in Amperes r1=1; //in Ohms r2=2; ...
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//Exa 2.9 clc; clear; close; //Given Data : format('v',6); P=30*10^6;//in watts V=220*10^3;//in Volt l=250*10^3;//in meter Eta=85;//in % rho=3*10^-8;//in ohm-meter cosfi=0.8;//power factor W=P*(100-Eta)/100;//in watts I=P/(sqrt(3)*V*cosfi);//in Ampere a=3*I^2*rho*l/W;//in m^2 Volume=3*a*l;//in m^3 disp(...
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clear // // // //Variable declaration k=4; epsilon0=9*10^-12; //relative permeability(F/m) E=10^6; //electric field(V/m) //Calculations D=k*epsilon0*E; //electric displacement(C/m^2) P=epsilon0*E*(k-1); //polarisation(C/m^2) //Result printf("\n electric displacement is %0.0...
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function [ok,new_info]=do_set_info(info) //This function may be redefined by the user to handle definition //of the informations associated with the current diagram // Copyright INRIA if prod(size(info))==0 then info=list(' ') end new_info=x_dialog('Set Diagram informations',' ') if new_info==[] then ok=%f else ...
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clc //Example 13.5 //Calculate the headstrom ,reynold numbers and the fanning friction factor tow_yield=3.8//Pa mew=0.00686//Pa.s D=0.0206//m rho=1530//kg/m^3 V=3.47//m/s He=tow_yield*D^2*rho/mew^2//dimentionless (headstrom number) printf("The headstrom number is %f\n",He); R=D*V*rho/mew//dimentionless (reyno...
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clear;lines(0); x=0:0.2:2*%pi; x1=[sin(x);100*sin(x)]; y1=[cos(x);100*cos(x)]; y1=y1+20*ones(y1); // No clip plot2d([-100,500],[-100,600],[-1,-1],"022") xsegs(10*x1+200*ones(x1),10*y1+200*ones(y1)) // rectangle clipping zone xbasc(); plot2d([-100,500],[-100,600],[-1,-1],"022") xrect(150,460,100,150) xclip(150,460,100...
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//Chemical Engineering Thermodynamics //Chapter 13 //Thermodynamics in Phase Equilibria //Example 13.14 clear; clc; //Given P = 760;//Total pressure of the mixture in mmHg T = [80 90 95 100];//Temperature in deg celsius P1 = [87.4 129.0 162.0 187.0];//vapour pressure of 1,1,2,2-tetrachloroethane in mmHg P...
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// Example 2_5 clc;clear;funcprot(0); // Given values T=20;// degree celsius sigma_s=0.073; // the surface tension of water in N/m phi=0; // the contact angle of water with glass in degree rho=1000;// kg/m^3 g=9.81;// m/s^2 R=0.3*10^-3; // Radius of glass tube in m //Calculation h=((2*sigma_s)/(rho*g*R))*co...
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//Example 2.5, Page Number 70 //The Function fpround(dependency) is used to round a floating point number x to n decimal places //Contact Potential Difference clc; nd=10**22 //Donor Impurity Level in per meter cube na=10**24 //Acceptor Impurity Level in per meter cube n=2.4*(10**19) //Intrinsic Electron Concentra...
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clear clc //to find speed of crate according to observer o ////to find work and change in kinetic energy // GIVEN: //refer to figure 11-18(a),(b)from page no. 242 //force applied Fx = 5.63//in N //mass of crate m = 12.0//in kg //speed of train vx = 15.0//in m/s //distance travelled by crate s = 2.4//i...
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function test_jouet() rand ( "seed", 42); frelres = zeros ( 1, 1000); brelres = zeros ( 1, 1000); step = [1:1000]; i = 1; for n = step A = rand (n, n); // Création d'une matrice xex = rand (n, 1); // Création d'un vecteur b = A*xex; // calcul de b ...
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clear; clc; close; disp("Example2.6") d=0.2 //Diameter in meters. M1=0.2 //inlet Mach no. p1=100*10^3 //inlet pressure in Pa Tt1=288 //total inlet temperature in K q=100*10^3 //rate of heat transfer to fluid in Watt. rg=287 //Gas constant in J/kg.K. gm=1.4 //gamma //(a)inlet mass flow: m=((gm/rg)^(1/2))*(p1...
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clc Gs=17.29 d=9.15 d1=6.1 D=d/d1 a=40 m=0.175 b=40 H=6.1 Cu=H*Gs*m printf('a)The undrained cohesion of the clay Cu = %f kN/m^2\n',Cu) printf(' b)The nature of the critical circle is midpointcircle\n') d=1.5 b=40 n=0.9 D1=n*H printf(' c)Distance = %f m',D1)
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PL/SQL Developer Test script 3.0 4 begin -- Call the function :result := get_religion(preligion_id => :preligion_id); end; 2 result 1 Panteismo 5 preligion_id 1 1 4 0
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clc disp("the soln of eg 10.8-->Gauss Seidel Method"); for i=1:9,tnew(i)=101,e(i)=1 //assumed values end t=1e-6 while e(1)>t&e(2)>t&e(3)>t&e(4)>t&e(5)>t &e(6)>t& e(7)>t& e(8)>t & e(9)>t do for i=1:9, told(i)=tnew(i),end //using eqn 10.10 for the interior nodes and convective boundary ...
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// Example 7.8 N2=1700; // turns of Coil 1 Q2=0.8*10^-3; // total Megnetic Flux I2=6; // Current in A Coil 2 L2=N2*(Q2/I2); // Formula for (Self Inductance of Coil 1) disp('(a) Self Induction of a Coil 2 = '+string(L2)+' H'); N1=600; ...
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function t=cos2cosf(u,scs_m,count) //write scilab instructions whose evaluation //returns the value of scicos data structure scs_m. // in the opened file associated with logical unit u [lhs,rhs]=argn(0) if rhs<3 then count=0, lname='scs_m' else count=count+1 lname='scs_m_'+string(count) end bl=' ' lmax=80-...
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//Poisson calculate Exp and Var //Le Thu Huong ADEO1 clc N = 500000; lamda= 4; Exp = 0; var =0; for i = 1:N cumul = exp(-lamda); proba = cumul; u = rand(); alpha = 0; while( u > cumul) then alpha = alpha + 1; proba = proba * lamda/alpha; cumul = cumul + pr...
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// Script de teste da função nx load nx.hdl, output-file nx.out, compare-to nx.cmp, output-list in%B1.5.1 out%B1.5.1; set in %B00001, eval, output; set in %B11111, eval, output; set in %B00101, eval, output; set in %B11011, eval, output;
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# -------------------------- Header Parameters -------------------------- scenario = "Digit Span"; write_codes = EXPARAM( "Send ERP Codes" ); default_font_size = EXPARAM( "Default Font Size" ); default_background_color = EXPARAM( "Default Background Color" ); default_text_color = EXPARAM( "Default Font Color" ); def...
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in = [ -75 -90 30 ; -120 11 12; 122 11 14]; //Checking if error message pops up when input is 3D instead of 2D point set output = convertPointsToHomogeneous(in); //output-> // !--error 999 //Please enter 2D points matrix of size Nx2.
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clc clear //Input data Wf=10;//Coal rate in t/h C=78;//The mass of carbon present in the coal according to coal analysis on mass basis in % H=3;//The mass of hydrogen present in the coal according to coal analysis on mass basis in % O=3;//The mass of oxygen present in the coal according to coal analysis on mass ...
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// Example 10.8 clear all; clc; // Given data R = 7*30.48; // Distance of core from the center of shield in cm // Assuming average energy produced per fission reaction is 200 MeV P = 10; // Power of teaching reactor in Watts P_fission ...
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clear clc A=[0 1+2*%i;-1+2*%i 0] I=eye(2,2) disp("I-A= ") I-A disp("inverse of (I+A)= ") inv(I+A) disp("((I-A)(inverse(I+A)))*((I-A)(inverse(I+A)))=") (((I-A)*(inv(I+A)))')*((I-A)*(inv(I+A))) disp("((I-A)(inverse(I+A)))((I-A)(inverse(I+A)))*=") ((I-A)*(inv(I+A)))*(((I-A)*(inv(I+A)))') disp("clearly,the prod...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.nand2tetris.org // File name: projects/00/And.tst load Demux.hdl, output-file Demux.out, compare-to Demux.cmp, output-list in%B3.1.3 sel%B3.1.3 a%B3.1.3 b%B3....
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@relation flare @attribute LargestSpotSize{A,R,S,X,K,H} @attribute SpotDistribution{X,O,I,C} @attribute Activity{1,2} @attribute Evolution{1,2,3} @attribute Prev24Hour{1,2,3} @attribute HistComplex{1,2} @attribute BecomeHist{1,2} @attribute Area{1,2} @attribute C-class{0,1,2,3,4,5,6,7,8} @attribute M-class{0,1,2,3,4,5...
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//Ex 9.7 clc; s=%s; T=10^(-4); wdc=2*%pi*10^3; wac=2/T*tan(wdc*T/2); HS=1/(s^2+sqrt(2)*s+1)//Transfer Function for N=1 HS1=horner(HS,s/wac); disp(HS1,'Normalized Transfer Function, H(s) ='); z=%z; HZ=horner(HS1,(2/T)*(z-1)/(z+1)); disp(HZ,'H(z) =');
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exec("swigtest.start", -1); try a = new_A_UF(); catch swigtesterror(); end try delete_A_UF(a); catch swigtesterror(); end exec("swigtest.quit", -1);
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n=500;E=100;A=0.001;b=1/120; f=1.2; max1=(E/1000)*(b) max2=(f*A) E=(120*n*max2*2)
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// t=[0 2.50000000000000e-07 5.00000000000000e-07 7.50000000000000e-07 1.00000000000000e-06 1.25000000000000e-06]; x=[-0.00104287295007201 -0.00244190236539361 0.00330474678679599 0.00312506274996585 -0.00888427641170878 -0.000128837692967764 ]; levels= statelevels(x,1e3,'mean'); disp(levels); //output // - 0.0088782 ...
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3(G)Program to solve Combinations..sce
disp('four objects are given (a,b,c,d) and three are taken at a time') combinations = factorial (4) /( factorial (4 -3)* factorial (3) ); disp(combinations,'number of combinations of the four objects given') k= factorial (3) ; // number of permutations of objects in a combination permutations = combinations *k; di...
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clc clear //input //coils a and b in connected in parallel v=240;//supply voltage in volts f=50;//supply frequency in hertz ra=10;//resistance of coil a in ohms xla=25;//inductive reactance of coil a in ohms rb=20;//resistance of coil b in ohms xlb=12;//inductive reactance of coil b in ohms //calculations...
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clear;lines(0); F=randpencil([0,1],[2],[-1,0,1],[3]); [Q,Z,Qd,Zd,numbeps,numbeta]=kroneck(F); Qd, Zd s=poly(0,'s'); F=randpencil([],[1,2],s^3-2,[]); //regular pencil det(F)
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Bt=25*10^6//allocated spectrum Bc=200*10^3//channel bandwidth Bg=0//no guard band m=8//no. of speech channels N=m*(Bt-2*Bg)/Bc disp(N,'no. of simultaneous subscribers a GSM system can accommodate is ' )
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// Bode plot of the differencing filter, discussed in Example 5.6 on page 130 // 5.4 exec('label.sci',-1); w = 0.01:0.01:%pi; G = 1-exp(-%i*w); subplot(2,1,1) plot2d1("gll",w,abs(G),style = 2); label('',4,' ','Magnitude',4); subplot(2,1,2) plot2d1("gln",w,phasemag(G),style = 2); label('',4,'w','Phase',4) ...
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// Exa 5.10 clc; clear; close; // Given data C1= 4;// in pF C2= 60;// in pF L=8*10^-3;// in H C_Tmin= C1*C1/(C1+C1);// in pF C_Tmin= C_Tmin*10^-12;// in F C_Tmax= C2*C2/(C2+C2);// in pF C_Tmax= C_Tmax*10^-12;// in F Fc_max= 1/(2*%pi*sqrt(L*C_Tmin));// in Hz Fc_min= 1/(2*%pi*sqrt(L*C_Tmax));// in Hz disp(F...
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clear // // // //Variable declaration e=1.602*10**-19 m=9.1*10**-31 //mass(kg) tow=2*10**-14 //time(s) n=8.5*10**28 //Calculation sigma=n*e**2*tow/m //electrical conductivity(ohm-1 m-1) //Result printf("\n electrical conductivity is %0.1f *10**7 ohm-1 m-1",sigma/10**7)
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//Solution 5-09 WD=get_absolute_file_path('5_09_solution.sce'); datafile=WD+filesep()+'5_09_example.sci'; clc; exec(datafile) V_A = V_A * 1000 / 3600; //conversion from [kmph] to [m/s] P_atmair = P_atmair / 100; //conversion from [cm of Hg] to [m og Hg] P_air = P_air / 100; //conversion from [cm of Hg] to [m of Hg] //(...
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clc; //page 432 //Given T2=600;//lb, Tension from side 2 us=0.25;// Coeffiecient of static friction between pulley and belt bta=(2*%pi)/3;//Co=efficient of kinetic friction between pulley and belt r1=8//in in //Pulley B T1=T2/(exp(us*bta))//N, Tension from side 1 //disp(T1) //Pulley A //Aumming moment ab...
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clc clear //Input data t1=270;//Temperature inside surface of the furnace wall in degree centigrade t3=20;//Temperature outside surface is dissipating heat by convection into air in degree centigrade L=0.04;//Thickness of the wall in m K=1.2;//Thermal conductivity of wall in W/m-K t2=70;//Temperature of outside ...
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clc clear //input data R0=6341.6*10^3 //radius of earth at mean sea-level in m g=9.809 //acceleration due to gravity in m/s^2 Z1=0 //altitude at sea-level in m Z2=300*10^3 //altitude above sea-level in m //calculation uorb1=R0*sqrt(g/(R0+Z1)) //orbit velocity of a rocket at mean sea level in m/s uesc1=sqrt...
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clc(); clear; //To determine the kinetic energy of electron h=6.626*10^-34; //plancks constant E=85; //Energy in keV c=3*10^8; //speed of light lambda=(h*c)/(E*10^3*(1.6*10^-19)); //de Broglie wavelength m=9.1*10^...
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//Ex18_5 Pg-947 clc d=5*10^(-6) //thickness of silicon in m Dc=3.4*10^(-3) //diffusion coefficient in m^2sec^(-1) t=d^2/(2*Dc) //time taken to diffuse printf("Time taken to diffuse = %.1f*1e-9 sec",t*1e9)
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//Example 3_8 clc; clear; close; format('v',5); //given data : V=100;//V f=50;//Hz R=10;//ohm L=100;//mH C=100;//micro F XL=2*%pi*f*L*10^-3;//ohm XC=1/2/%pi/f/(C*10^-6);//ohm IR=V/R;//A disp(IR,"Current through R(A)"); IL=V/XL;//A disp(IL,"Current through L(A)"); IC=V/XC;//A disp(IC,"Current through C...
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clc clear //Input data P1=1;//Initial pressure of a gas turbine plant in bar T1=310;//Initial temperature in K P2=4;//Pressure of air after compressing in a rotary compressor in bar P3=P2;//Constant pressure process P41=P1;//Since 1-41 is a constant pressure process in bar T3=900;//Temperature of air at the poi...
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//desing right angled bell crank lever clc //soltuion //given //ref fig 15.14 FB=500//mm W=4500//N FA=150//mm ft=75//N/mm^2 t=60//N/mm^2 pb=10//N/mm^2 P=(W*500)/150//N Rf=sqrt(P^2 + W^2)//N //desing of uflcrum pin //let d be dia and l be thickness of fulcrum //l=1.25d //P=d*l*pb=12.5*d^2 //d=sqrt(P/12....
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// Example 5.24:PERCENTAGE TILT clc; clear; close; Rc=4;//RESISTANCE IN KILLO OHMS Rl=2;//RESISTANCE IN KILLO OHMS R1=Rc+Rl;// C=10;//capacitance in micro farad fl=(1/(2*%pi*R1*10^3*C*10^-6));//LOWER CUT -OFF FREQUENCY f=200;//frequency in hertz P= (%pi*fl)/f;// disp(P*100,"percentage tilt is")
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//example 5.11 clc; funcprot(0); // Initialization of Variable P=200;//power R=8;//ohm //calculation Il=(P/R)^.5*2^.5; Ilm=1.2*Il; disp(Ilm,"limit level current in A:")
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// Calculating resistance. clc; clear; L=2.5*(10^-2); // Length of rectangular cross-section. B=0.05*(10^-2);// Breadth of rectangular cross-section. A=L*B; l=1*(10^3); p=1.724*(10^-8); R=p*l/A; disp('ohms',R,'The Resistance of the copper strip =')
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errcatch(-1,"stop");mode(2);//Caption:Calculate the increase of main field flux in percentage //Exam:2.10 ; ; N_1=750;//speed of dc machine(in rpm) E_1=220;//induced emf in dc machine when running at N_1 N_2=700;//speed of dc machine second time (in rpm) E_2=250;//induced emf in dc machine when running at N_2 ...
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function [y]=ANN_test_sample() // This function is used to test the trained neural network. // It returns the label which it has guessed according to the provided test sample. // // Syntax // y = ANN_test(in1); // // Parameters // y : class guessed by the neural network // ...
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clear; clc; printf("\t Example 9.4\n"); a=13600; //desity difference,kg/m^3 s=0.487; //surface tension,kg/s^2 L=2*%pi*(3^0.5)*(s/(9.8*a))^0.5*100; //spacing wavelength,cm printf("\t maximum spacing is : %.1f cm\n",L); printf("\t actually this spacing would give the maximum rate of colla...
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// Variable declaration alpha = 2 // mean of normal distribution beta = 0.1 // standard deviation of normal distribution // Calculation // we need to find p(Io/Ii) = p( (ln(b)-alpha) / beta) - p( (ln(a)-alpha) / beta) a = 6.1 // lower limit b = 8.2 ...
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//=============================================================================== //chapter 5 exmple 3 clc; clear; //input data V = 63.5; //atomic weight in kg d = 8.92*10^3; //density of copper in kg/m^3 r = 0.7*10^-3; //radius in m I = 10; ...
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// function C = seshft(A,B,N) //given A and B matrices, returns C = [<-A-> 0 // 0 <-B->] with B shifted east by N cols function C = seshft(A,B,N) [Arows,Acols] = size(A); [Brows,Bcols] = size(B); if N >= 0 B = [zeros(Brows,N) B]; Bcols = Bcols + N; elseif N < 0 A...
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clear; clc; // Illustration 3.6 // Page: 77 printf('Illustration 3.6 - Page: 77\n\n'); // solution //***Data***// Dp = 0.0125;// [m] viscosity = 2.4*10^(-5);// [kg/m.s] Sc = 2; E = 0.3; Go = (2*10^(-3))/0.1;// molar superficial mass velocity [kmol/square m.s] //********// // a = CO b = Ni(CO)4 /...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Proposed by author // 24 Streams // 14 Equipments clear xm var jac nc nv i1 i2 nnzeros sparse_dg sparse_dh lower upper var_lin_type constr_lin_type...
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//Finding of Manometric head //Given D1=0.4; B1=0.025; Q=0.06; N=1000; a=30; g=9.81; Emano=0.8; //To Find u=(%pi*D1*N)/60; Vf=Q/(%pi*D1*B1); Vw1=(-Vf*tan(%pi/6)+u); H=(Vw1*u)/g; Hm=(Emano*u*Vw1)/g; Hm1=2*Hm; disp("Head Developed ="+string(Hm1)+" meter");
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 7 : SPECIAL MOTORS AND INTRODUCTION TO GENERALIZED MACHINE THEORY // EXAMPLE : 7.14 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA Va = 220 * exp( %i * 0 * %p...
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//determining critical value of K s=%s syms K m=s^4+22*s^3+10*s^2+s+K cof_a_0 = coeffs(m,'s',0); cof_a_1 = coeffs(m,'s',1); cof_a_2 = coeffs(m,'s',2); cof_a_3 = coeffs(m,'s',3); r=[cof_a_0 cof_a_1 cof_a_2 cof_a_3] n=length(r); routh=[r([4,2]);r([3,1])]; routh=[routh;-det(routh)/routh(2,1),0]; t=rou...
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clear;lines(0); A=[1,2;3,4] sin(asin(A))
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function [F,G,ind]=OraclePG(qc,ind) q=q0+B*qc if ind == 2 then F = (1/3)*q'*(r.*q.*abs(q))+pr'*Ar*q; G = 0; end if ind == 3 then F = 0; G = B'*(r.*q.*abs(q)+Ar'*pr); end if ind == 4 then F=(1/3)*q'*(r.*q.*abs(q))+pr'*Ar*q; G = B'*(r.*q.*abs(q)...