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//Example 3 // ENERGY clc; clear; close; ke=5;//joule pe=5;//joule rep=10;//joule eo=rep+ke+pe;//joule disp(eo,"energy of the oscillator is,(joule)=")
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//find the position and voltage on the intersheaths and max and min stress clear; clc; //soltion //given d=2;//cm D=5.3;//cm V=66*sqrt(2/3);//kV V1=poly(0,"V1"); V2=poly(0,"V2"); V3=poly(0,"V3"); d1=poly(0,"d1") d1d2=D*d;//d1*d2 d2=(d1^2)/2; printf("d2= "); disp(d2); d1=(2*d1d2)^(1/3);//after putting va...
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clc clear //Condições iniciais s0=0; vs0=0; S0=[s0;vs0] g=9.78; mu0 = 0.15; Nt = 0.08; m=0.033; c=0.01; t0=0; tf=20; teta=(%pi)/6; //Passo de integração h=0.5; dt=h; t=t0:dt:tf; //Função para cálculo das derivadas temporais (letra b) function dS=f(t,S) ds1=S(2); ds2=g*sin(teta)-4*mu0*Nt*(1/m); dS=[ds1;ds2];...
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// Scilab Code Ex2.5 : Page-63 (2006) clc; clear; epsilon_0 = 8.854e-012; // Absolute electrical permittivity of free space, F/m N = 6.023e+023; // Avogadro's number e = 1.6e-019; // Energy equivalent of 1 eV, eV/J r0 = 6.46e-010; // Nearest neighbour distance of NaI E = 157.1e+03; // Binding energy of...
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//exapple 9.4 clc; funcprot(0); // Initialization of Variable rhoa=1.218;//density of air mu=1.73/100000; pi=3.1428; g=9.81; rhog = 1200; rhop=2280;//density of polythene d=0.0034;//diameter a=4*d^3*(rhop-rhoa)*rhoa*g/3/mu^2;//a=Cd*Re^2 //using graph of Cd*Re^2 vs Re Re=2200; v=Re*mu/d/rhog; disp(v , "The terminal vrl...
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bref=[];bnorm=[];incomemean=[];rents=[];incomes=[]; bref(1)=5000; bnorm(1)=20000; incomemean(1)=10000; rents(1,1)=99.22529588530496; rents(1,2)=74.42568868647493; rents(1,3)=92.88122614559285; rents(1,4)=110.30678493239462; rents(1,5)=127.4363451782466; rents(1,6)=144.1830905757753; rents(1,7)=159.1999919495849; rents(...
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clear clc //to find entropy change of water during process //Given: //mass of water m = 1.8//in Kg //initial temperature of water and hot plate Ti = 20//in degree celsius //final temperature of hot plate Tf = 100//in degree celsius //heat capacity of water c = 4190//in J/Kg.K //Solution: //applying law...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 12.3 //calculation of the time period of oscillation of the particle //given data m=200*10^-3//mass(in kg) of the particle k=80//spring constant(in N/m) //calculation T=2*%pi*sqrt(m/k)//formula of time period p...
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clc //soltuion //given RP=15000//W//rated power N1=1000//rpm N2=350//rpm VR=N1/N2 //ref table 21.5,numbr of teeth on smaller sprocket is T1=25 T1=25 T2=T1*N1/N2 K1=1.5//load factor K2=1//lubricaiton factor K3=1.25//rating factor Ks=K1*K2*K3//service factor DP=Ks*RP//design power //from table 21.4,corrs to N1=1000rpm,p...
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function response = http_post_url(URL, varargin) [host, resource, port] = http_split(URL) // Get hostname and resource from URL response = http_post(host, resource, port, varargin) endfunction
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// Scilab Code Ex7.3:: Page-7.8 (2009) clc; clear; n1 = 1.46; // Refractive index of the core material delta = 0.01; // Relative refractive index difference NA = n1*sqrt(2*delta); // Numerical aperture for the fibre theta_Q = %pi*NA^2; // Solid acceptance angle of optical fibre for small angles, radians...
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clear; clc; //page no. 285 T = 100;// degreeF d = 3;// inches Re = 80000;// Reynolds number e = 0.006;// inches l = 1000;//feet f1 = 0.021;//friction factor nu = 0.729*10^-5;// sqft/sec V = Re*nu/0.25; h_L1 = f1*(l/0.25)*(V^2 /(2*32.2)); f = 0.316/Re^0.25; h_L = (f/f1)*h_L1; printf('Head loss expected...
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clear // // // //Variable declaration theta1=5+(23/60); //glancing angle(degree) theta2=7+(37/60); //glancing angle(degree) theta3=9+(25/60); //glancing angle(degree) //Calculation theta1=theta1*%pi/180; //angle(radian) theta2=theta2*%pi/180; //angle(radian) theta3=theta3*%pi/180; //angle(...
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function [nville1]=cleaner(ville1) //Remplace tous les caractères non supportés par scilab nville1=strsubst(ville1,"é","e"); nville1=strsubst(nville1,"è","e"); nville1=strsubst(nville1,"à","a"); nville1=strsubst(nville1,"ç","c"); nville1=strsubst(nville1,"-",""); nville1=strsubst(nville1,"â","a"); ...
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//chapter-13,Example13_2,pg 509 t1=1*10^-6//time span for voltage //voltage switching V1=0.5//level-1 V2=1//level-2 //current switching I1=1*10^-3//level-1 I2=10*10^-3//level-2 t2=1*10^-6//time span for current DR=(((V2-V1)/t1)/((I2-I1)/t2)) printf("pseudoimpedance\n") printf("DR=%.2f o...
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//<f2>=%psr(n1,f2) // %psr(n1,f2) calcule la soustraction de la matrice de polynome n1 et //de la matrice de fractions rationnelles f2. //Cette macro correspond a l'operation n1-f2 //! [n2,d2]=f2(2:3), [n2,d2]=simp(n1.*d2-n2,d2) f2(2)=n2;f2(3)=d2; //end
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//clc() A = 13.8587; B = 2911.32; C = 56.56; T1 = 325;//K //Pressure at normal condition = 101.3kPa P2 = 101.3;//kPa //Antoine equation - lnP = A - B / (T - C) lnP = A - (B / (T - C)); P1 = exp(lnP); disp("kPa",P1,"(a)Vapour pressure of n-heptane at 325K = ") T2 = B/(A - log(P2)) + C; disp("K",T2,"(b)Normal...
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// Exa 3.3 clc; clear; close; format('v',8) // Given data f = 60;// in Hz Im = 120;// in A t = 1/360;// in sec omega = 2*%pi*f;// in rad/sec i = Im*sin(omega*t);// in A disp(i,"The value of current after 1/360 sec in A is"); i = 96;// in A // i = Im*sind(omega*t); t = (asin(i/Im))/omega;// in sec disp(t,...
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//ill-conditioned system //example 7.12 //page 278 clc;clear;close; //the original equations are 2x+y=2 2x+1.01y=2.01 A1=[2 1;2 1.01]; C1=[2;2.01]; x1=1;y1=1//approximate values A2=[2 1;2 1.01]; C2=[3;3.01]; C=C1-C2; X=A1^-1*C; x=X(1,1)+x1; y=X(2,1)+y1; printf(' the exact solution is X=%f \t Y=%f',x,y...
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function checkCEE(varargin) extErr = varargin(1) if ~isfield(extErr, 'RotVectorsError') | ~isfield(extErr, 'TransVectorsError') then error(msprintf("An ExtrinsicsEstimationErrors Struct expected.")) end rvErr = extErr.RotVectorsError; tvErr = extErr.TransVectorsError; ...
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//Example No. 13.4.1 clc; clear; close; format('v',7); Pr1=0.0297/1000;//W(Recieved power) Pr2=0.0471/1000;//W(Recieved power) Pr3=0.0374/1000;//W(Recieved power) Pt=1;//W(Transmitted power) R=10;//m(Radius) f=980;//MHz(Frequency) f=f*10^6;//Hz(Frequency) c=3*10^8;//m/s(Speed of light) lambda=c/f;//m(Wavel...
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-chain [[2,-1,0,2],[-2,0,-1,-2],[0,2,2,-1],[2,-1,1,1]] [6,-5,-3,-4] 4 0 [[2,-1,0,2],[-2,0,-1,-2],[0,2,2,-1],[2,-1,1,1]],det=-2 [6,-5,-3,-4], chain 8 => [9,-1,-12,10] => [39,-26,-36,17] => [138,-76,-141,85] => [522,-305,-519,296] => [1941,-1117,-1944,1126] => [7251,-4190,-7248,4181] => [27054,-15616,-27057,15625] => [10...
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// Exa 4.7 clc; clear all; // Referring circuit given in fig. 4.7 on page no.81 S1=1000; // Sensitivity of meter 1 (Ohms/volt) S2=20000;// Sensitivity of meter 2(Ohms/volt) Rm1=200;// Meter resistance(Ohms) Rm2=1500;// Meter resistance(Ohms) V1=10; // Range of voltmeter 1(Volts) V2=10; Ra=25000; // in Ohm...
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// ============================================================================= // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2007-2008 - INRIA // // This file is distributed under the same license as the Scilab package. // ========================================================...
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clc clear all; disp("local transfer coefficient") tsat=90;// degree C ta=70;// degree C L=1.5;//m d=2.5;//m outer diameter;// rhol=974;//kg/m^3 k=0.668;// W/m.K mul=0.335*10^(-3);//kg/m.s hfg=2309*1000;//J/kg g=9.81;// m/s^2 hL=((rhol^2)*(k^3)*g*hfg/(4*mul*L*(tsat-ta)))^0.25; disp("W/m^2.C",hL,"Local heat ...
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# header scenario = "spatial attention PRACTISE SESSION 2"; write_codes = true; # send codes to output port active_buttons = 2; button_codes = 1, 2; default_font_size = 30; default_text_color = 255,255,255; # white default_background_color = 0,0,0; # black # SDL code begin; ############################...
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clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 3.11 Page 158 \n'); //Example 3.11 // Study of Fuel-cell fan system Wc =.05; //[m] width H = .026; //[m] height tc = .006; //[m] thickness of cell V = 9.4; //[m/sec] vel of cooling air P =...
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//Given that C = 1.5*10^-6 //in F V = 57 //in volts L = 12*10^-3 //in H //Sample Problem 33-1 printf("**Sample Problem 33-1**\n") Imax = V*sqrt(C/L) printf("The maximum current in the circuit is %1.2eA", Imax)
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// Scilab Code Ex1.9: Page-14 (2008) clc; clear; omega1 = 500; // Angular speed of rotating shaft, r.p.m. omega2 = 0; // Initial angular speed of the second wheel, r.p.m. I = 1; // For simplicity assume moment of ineria of the wheels to be unity I1 = I, I2 = I; // Moment of inertia of wheels A and B, kg-Sq....
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//load files currentDirec = pwd(); exec(currentDirec + '\stftInterpolate.sci', -1); exec(currentDirec + '\timeStretch.sci', -1); exec(currentDirec + '\angle.sci', -1); exec(currentDirec + '\istft.sci', -1); exec(currentDirec + '\stft.sci', -1); stacksize('max'); //allows big files to be opened recordingFile = 'your...
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//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter2 //example 2.4 //edition 1 //publisher and place:Nelson Engineering clc; clear; Ls=8;//snubbing inductor in microhenry VBO=4000;//base voltage in volts di=200;//rate of change of current (di/dt) in amperes per microsec dv=1500;//rate of...
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clc cp=2.093; //kJ/kg0C c=4.187; Lf=333.33; //kJ/kg m=1; //kg T0=273; //K T1=268; //K T2=298; //K Q_s=m*cp*(T0-T1); Q_f=m*Lf; Q_l=m*c*(T2-T0); Q=Q_s+Q_f+Q_l; disp("(i) Entropy increase of the universe") ds_atm=-Q/T2; ds_sys1=m*cp*log(T0/T1); ds_sys2=Lf/T0; ds_sys3=m*c*log(T2/T0); ds_total=ds_sys1+ds_...
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clear; clc; P=760;//in torr dP=52;//in torr dT=2;//in K DelH_RTb=10.5;//Trouton rule Tb=(DelH_RTb*P)/(dP/dT) printf('Tb=%.1f K',Tb) R=8.314;//in J/Kmol DelH_v=(DelH_RTb*R*Tb) printf('\nDelH_v=%1d J/mol',DelH_v) //There are some errors in the solution given in textbook //page 17
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//Exa 5.15 clc; clear; close; //Given data : f=50;//Hz l=100;//km P=50*10^6;//W pf=0.8;//power factor cos_fi_r=pf; sin_fi_r=sqrt(1-cos_fi_r^2); VRL=132*10^3;//Volt VR=VRL/sqrt(3);//Volt R=0.1*l;//ohm XL=0.3*l;//ohm Z=R+%i*XL;//ohm Y=3*10^-6*l;//S IR=P/(sqrt(3)*VRL*pf);//A IR=IR*(cos_fi_r-%i*sin_fi_r);...
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//Example 4.1 //MSCP clc; clear; close; format('v',3) F=1000;//intensity in lumens MSCP=F/(4*%pi);// MSCP of the lamps disp(MSCP,"MSCP of the lamp is")
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// Part (a) R = 0.287; T1 = 273+150; v1 = 0.96; v2 = 1.55; Cp = 1.005; P = (R*T1)/v1; W = P*(v2-v1); T2 = (v2/v1)*T1; Q = Cp*(T2-T1); disp("If the fluid is in the air") disp("K",T2,"The final temperature is ") disp("kJ",Q,"The heat transferred is") disp("kJ",W,"Work done is") // Part (b) vg = 0.3928; P1 = 2...
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//Find radius of first orbit of electron in Hydrogen atom //Ex:2.4 clc; clear; close; n=1;//first orbit e_0=8.85*10^-12;//permittivity in freee space h=6.62*10^-34;//planck's constant m=9.1*10^-31;//mass of an electron in kg e=1.6*10^-19;//charge of an electron in C z=1; r=n^2*e_0*h^2/(3.14*m*e^2*z);//radius...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 9 Example 7") T1=313;//air entering temperature in K P1=1*10^5;//air entering pressure in Pa m=50;//flow rate through compressor in kg/s R=0.287;//gas constant ...
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//Diameter and head// pathname=get_absolute_file_path('8.11.sce') filename=pathname+filesep()+'8.11-data.sci' exec(filename) //Value of K*B^2: K_B=Q/(%pi/4*D^2)*sqrt(0.5*d1/g/d2/h) //Reynods number: ReD1=4/%pi*Q/D/v //By trial and error method, the value of beta is fixed at: betta=0.66; //K is then: K=K_B/...
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//Problem 19.04: A 415 V, 3-phase, 4 wire, star-connected system supplies three resistive loads as shown in Figure 19.7. Determine (a) the current in each line and (b) the current in the neutral conductor. //initializing the variables: V = 415; // in Volts PR = 24000; // in Watt Py = 18000; // in Watt Pb = 12000...
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clear; N=10; P=0.8; gamma=0.9; U=diag(ones(1,N)); T=zeros(N,N,2); r=zeros(1,N)-0.1; r(1)=-1; r(N)=1; T(1,1,:)=1; T(N,N,:)=1; for i=2:N-1; T(i,i-1,1)=P; T(i,i+1,1)=1-P; T(i,i-1,2)=1-P; T(i,i+1,2)=P; end policy=floor(2*rand(1,N))+1; Vpi=zeros(N,1); iter = 0; converge=0; while ~converge iter = iter ...
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//exapple 1.33 clc; funcprot(0); // Initialization of Variable longP=60+30/60;//longitude of place GST=7+30/60+48.6/3600;//GST at GMM RA=17+28/60/40/1600; dot=longP/15;//difference in time i=dot*9.8565/3600;//error gmm=GST-i;//LST at L.M.N LMT=RA-gmm;//local mean time disp("local mean time in past mid...
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//=========================================================================== //chapter 3 example 16 clc;clear all; //variable declaration E =200; //limiting voltage in V R = 1000; //resistance in Ω eE = 1; //relative limiting error(dE/E) in % eR = 5; //re...
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//Introductory Topics :example 1-8 : (pg no. 24) k=1.38*10^-23; T=(35+40+52);//total temperature df=(1*10^6); Teq=52; To=290; Pn=(k*T*df); x=(Teq/To); NR=(x+1); NF=(10*log10(NR)); printf("\nPn = k.T.delta(f) = %.17f W",Pn);//Noise power printf("\nTeq = To(NR-1) \nNR = %.2f",NR);//noise ratio printf("\nNF = ...
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//Example 5.8 clear; clc; As=-5; Ri=30*10^3; Vs=15; R1=Ri; R2=abs(As)*R1; Rp=(R1*R2)/(R1+R2); Vosmax=6*10^(-3); Iosmax=200*10^(-9); EImax=Vosmax+(Rp*Iosmax); RA=1*10^3; Rpc=Rp-RA; EImaxs=EImax+(4*10^(-3)); RB=RA*(Vs/EImaxs); RC=100*10^3;///Choosing RC=100 kohms printf(...
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// Example 17_12 clc;funcprot(0); //Given data m_s=10;// Tonnes U=4;// KW/m^2.°C P=0.2;// bar //Calculation h_fg=2358.3;// Latent heat of steam at 0.2 bar pressure in kJ/kg Q=(m_s*1000*h_fg)/3600;//kW //The given data is T_s-T_wo=10°C; T_wo-T_wi=20°C;Using this two equations,we get Theta_i=30;//°C Theta_o=...
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//8.21 clc; R2=5.6*10^3; R1=1*10^3; Avf=1+R2/R1; printf("Mid band Gain=%.2f", Avf) Vin=1.6; Vo=Avf*Vin; printf("\nOutput voltage=%.3f mV", Vo) R=1000; C=0.001*10^-6; fc=1/(2*%pi*R*C); printf("\nCutt off frequency=%.2f Hz", fc) Gain=0.707*Avf; printf("\nGain=%.3f", Gain)
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//=========================================================// // DEMO_2BAY // //=========================================================// //---------------------------------------------------------// // 1. Boundary conditions and constraints // // See s...
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clc; clear all; //page no 157 //prob no. 5.6 fLO=110; //MHz //for V2(f) f=[0:.01:231+.01]; //x axis function V=pulse() V=[] for i=1:.005:1.5 V=[V i] end endfunction V2=[zeros(0:.01:120-fLO-.01) pulse() zeros(121-fLO+.01:.01:120+fLO-.01) pulse() 0]; //y axis clf; subplot(21...
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// Scilab code Ex4.1 : Pg:139 (2008) clc;clear; I_max = 36; // Maxiumum intensity of interfering waves I_min = 1; // Minimum intensity of interfering waves // As (a + b)/(a - b) = sqrt(I_max/I_min), solving for a/b a1 = sqrt(I_max)+1; // Amplitude of first wave, unit a2 = sqrt(I_max)-1; // Amplitude o...
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// Calculation of ultimate tensile strength clc K = 689655 // in kPa n = 0.5 A0 = 1 // let printf("\n Example 2.1") sigma = K*n^n A_neck = A0*exp(-n) P= sigma*A_neck UTS = P/A0 printf("\n True ultimate tensile strength is %.2fkPa",sigma) printf("\n Engineering UTS of material is %.2f kPa",UTS) // Answer ...
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clear; clc; close; vgs1=0.140;//obtained from figure vgs2=0.212;//obtained from figure k=1.3807*(10^(-23));//boltzmann constant t=300;//temperature in kelvin q=1.6*(10^(-19)); n=((vgs2-vgs1)*q)/(k*t*log(10)); s=60*n; disp(n,'for PMOS device'); disp(s,'slope factor(in mv/decade)');
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10_09.sce
//Problem 10.09: //initializing the variables: EA = 10 x = 0.10 Da = 117 Db = 0.04521 Dr = -6.53E-6 DH0co2 = -94054; // in cal/gmol DH0h2o = -57798; // in cal/gmol DH0c2h6o = -56240; // in cal/gmol //calculation: DH0298 = 2*DH0co2 + 3*DH0h2o - DH0c2h6o DHP = -1*DH0298 DHPl = (1 - x)*DHP //DHPl = Da*(T...
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// Scilab code Exa1.5.4 : To calculate binding energy of Fe-56 : Page 38 (2011) M_Fe = 55.934939; // Mass of Fe-56, amu M_p = 1.007825; // Mass of proton, amu M_n = 1.008665; // Mass of neutron, amu Z = 26; // Atomic number of Fe-56 N = 30; // Number of neutron in Fe-56 amu = 931.49; // Atomic mass unit, MeV BE ...
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//Example 2.5 On Stagnation Point // Initialisation of variables h = 50; v = 100*5280/3600; //Speed in feet/sec rho_0 = 0.002378; rho_10000 = 0.001756; // Calculations Po = w*h; Ps_Po1 = (1/2)*rho_0*v^2; Ps_Po2 = (1/2)*rho_10000*v^2; V = 0.682*sqrt(Ps_Po2/(rho_0/2)); //Results disp(V, "Part...
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//Determine moment of inertia //refer fig.9.39 A1=100*30 //mm^2 A2=100*25 //mm^2 A3=200*20 //mm^2 A4=87.5*20/2 //mm^2 A5=87.5*20/2 //mm^2 A=A1+A2+A3+A4+A5 //mm^2 ybar=(3000*135+2500*70+4000*10+875*(20/3+20)*2)/A //mm Ixx=((100*30*30*30)/(12))+(3000*(75.74^2))+((25*(100^3))/(12))+(2500*(10.74^2))+((200*(...
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clc //initialization of variables Tt2=1620+460 //R Tt1=60+460 //R Mi=0.2 P=40 //lb/in^2 g=1.35 //calculations Tratio=Tt2/Tt1 disp("From figure") fM=4*0.036 NM2=0.49 Pratio=0.98/0.885 Pt2=P/Pratio //results printf("Final stagnation pressure = %.1f //lb/in^2",Pt2) printf("\n Final mach number = %.3f",fM) ...
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clear; clc; close; Idss = 6*10^(-3); Vp = -3; Vdd = 18; Rd = 1.8*10^(3); Rs = 750; Vg = 10*10^(6)*18/((10+110)*10^(6)); Vgs1 = Vp; Id1 = 0; Vgs2 = Vp/2; Id2 = Idss/4; Vgs3 = 0; Id3 = Idss; Vgs4 = 1; Id4 = Idss*(1-(Vgs4/Vp))^2; disp(Id4); x = [Vgs1 Vgs2 Vgs3 Vgs4]; y = [Id1 Id2 Id3 Id4]; yi=smo...
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clear // // // //Variable declaration chi=0.5*10**-5 //magnetic susceptibility H=10**6 //field strength(ampere/m) mew0=4*%pi*10**-7 //Calculation I=chi*H //intensity of magnetisation(ampere/m) B=mew0*(I+H) //flux density in material(weber/m**2) //Result printf("\n intensity of magnetisation is %0.3f a...
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//Eg-6.9 //pg-294 clear clc //Theoretical Problem disp("The example is solved analytically.")
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clear; clc; l = 20;// feet b = 9;// inches h = 10;// feet w = 120;// lb. per cub. foot f = 1100;// lb/in^2 W = w*(3/4)*l*h;// lb-wt BM_max = W*l*12/8;// lb-inches //assumnig d = 2b b = (6*BM_max/(f*4))^(1/3);// inches d = 2*b;// inches printf('b = %.2f inches\n d = %.2f inches',b,d); printf('\n A section %...
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//ques7 //calculating enthalpy of water at given pressure and temperature clear clc //1.Assuming steam to be an ideal gas with value of Cp T1=298.15;//Initial temperature in K T2=573.15;//final temperature in K T=(T1+T2)/2;//average temperature in K Cp=1.79+0.107*T/1000+0.586*(T/1000)^2-.20*(T/1000)^3;//specifi...
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//chapter 6 //page no182 //Ex6_15 //given clear; clc; dV=40; //in mV di=2.5; //in Amp Lbypas=0.5; //in nH fL=dV*10^-3/di/2/%pi/Lbypas/10^-9; printf("fHnoise = %0.1f MHz",fL/10^6);
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clear; clc; close; yos = 50*10^(-6); Idss = 10*10^(-3); Vp = -4; Vgsq = -2.2; Idq = 2.03*10^(-3); Rd = 3.6*10^(3); Rs = 1.1*10^(3); Vi = 40*10^(-3); gmo = 2*Idss/abs(Vp); gm = gmo*(1-(Vgsq/Vp)); rd = 1/yos; Zi = Rs*((rd+Rd)/(1+gm*rd))/(Rs+((rd+Rd)/(1+gm*rd))); Zi2 = Rs*gm^(-1)/(Rs+gm^(-1)); Zo = Rd*rd...
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-v G_USER=jonguyen -v G_CONFIG=1.0 -v G_TBTYPE=pc -v G_TST_TITLE="Parental Control" -v G_PROD_TYPE=MC524WR -v G_HTTP_DIR=test/ -v G_FTP_DIR=/log/autotest -v G_TESTBED=tb_pc -v G_FROMRCPT=qaman -v G_FTPUSR=root -v G_FTPPWD=@ctiontec123 -v U_USER=admin -v U_PWD=admin1 -v G_LIBVERSION=1.0 -v G_LOG=$SQAROOT/automation/log...
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// Exa 6.2 clc; clear; close; // given data R=10;//in Kohm C=0.01;//in uF R1=4.7;//in Kohm RF=47;//in Kohm fc=1/(2*%pi*R*1000*C*10^-6);//in Hz AF=1+RF/R1;//unitless disp(fc/1000,"Cut-off frequency in KHz is ; ") disp(AF,"Pass band gain is ; ")
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5;eee;0 5;f,t 3;p,r 4;s,d p1;-;p;-;3;3;3,5 -;p3;-;-;0;1;3,4 -;-;F;-;3;6;1,2 -;-;-;-;3;8;2,5 p2;-;-;i;3;5;1,4 startGame stepPlayer 5 usePlayerItem f swipeSnow stepPlayer 4 stepPlayer 4 status
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v=12; c=1.5; t=10.5; i=10; disp("Part a"); r=(v-vt)/i; disp("the internal resistance (in Ω) of the battery is"); disp(r); disp("Part b"); p_v=(v-vt)*100/vt; disp("the voltage regulation (in V) is"); disp(p_v); disp("Part c"); rl=2; il=v/(r+rl); disp("the current (in A) is"); disp(il); vl=v-il*r; disp("th...
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// RESULTADOS // A execução deste programa assume que os seguintes já foram executados: // C0_INIC | C1_BARRAS | C2_MAT_LOC | C3_MAT_GLOB | C4_REST_APOIO // C5_AMORTEC | C6_CARGAS | // Assim como um dos quatro programas seguintes: // C7a_NEWMARK_CTS | C7b_NEWMARK_ATS_BERGAN // C7c_NEWMARK_ATS_HULBERT | ...
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clc disp("Example 3.74") printf("\n") disp("Find the Ve, Ic,Vce &amp; Vc. Draw a DC load line for Voltage divider circuit") printf("Given\n") //given Vcc=15 Vbe=0.7 hFE=50 R1=6.8*10^3 R2=3.3*10^3 Rc=0.9*10^3 Re=0.9*10^3 //thevenin voltage Vt=(Vcc*R2)/(R1+R2) //thevenin resistance Rt=(R1*R2)/(R1+R2) //base current Ib=(V...
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defaultfont = "arial"; // Default Font demo_lhy = scf(100001);// Create window with id=100001 and make //it the current one // Background and text demo_lhy.background = -2; demo_lhy.figure_position = [100 0]; demo_lhy.figure_name = gettext("Control System"); // Change dimensions of the figure demo_lhy.axes_size...
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//Example 3.11 //Computing DC gain of the system. clear; clc; //------------------------------------------------------------------ //Transfer Function s=poly(0,'s'); num=3*(s+2); den=(s^2+2*s+10); Ys=syslin('c',num/den); //The DC gain of the system Y(s) as s-->0 is DC_Gain=horner(Ys,0) disp(DC_Gain,"The...
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clc clear //INPUT DATA cpic=1.94;//specific pressure inkJ/kgK cpv2=2.805;//specific pressure in kJ/kgK t21=303;//condenser temperature in K t1=258;//evaporator temperature in K t31=293;//subcooled temperature in K p1=2.36;//pressure in MPa p2=11.67;//pressure in MPa hf1=112.3;//enthalpy in kJ/kg hfg1=1313.7;...
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clc //Variable Initialisation Ea=600//Input Voltage of motor in volts Ia=500//Armature Current in Ampere d1=0.6//Duty Ratio Ra=0.05//Armature resistance in ohm Rf=0.07//Field Resistance in ohm K=15.27e-3//Motor Constant //Solution E0=d1*Ea Pin=E0*Ia Re=Ea/(Ia*d1) Eb=E0-(Ia*(Ra+Rf)) W=Eb/(Ia*K) N=W*60/(2*%...
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// Chapter 13_Optical Devices //Caption_Solar concentration //Ex_4//page 605 JL=150*10^-3 //PHOTOCURRENT DENSITY Js=3.6*10^-11 //reverse saturation current density Voc=0.0259*log(1+JL/Js) printf('Open circuit voltage when solar concentration is used is %1.3f V',Voc)
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//Example 14.7 //Program to: //(a) Convert optical signal powers to dBm //(b) Convert optical signal powers to dBu clear; clc ; close ; //(a)Convert optical signal powers to dBm Po=5*10^(-3); //Watt - GIVEN OPTICAL POWER dBm=10*log10(Po/1*10^3); printf("\n\n\t (a)The %1.0f mW of optical power is equ...
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//Chapter 22, Problem 15 clc; p=8/2; //pairs of poles c=2; phi=25e-3; //flux Ia=30; //armature current Z=900; T=(p*phi*Z*Ia)/(%pi*c); //torque printf("Torque = %.1f Nm",T);
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x=1:10; // Init. // combinations' order does not matter plot(x,x.*x,'*cya--')
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//Example 4.3, page 89 clc n=1.520 f=25//in cm r2=-(f*(n-1)) printf("\n The radius of curvature is %f cm",r2)
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clc //initialisation of variables d1= 3 //in d2= 6 //in sm= 13.6 Q= 0.5 //ft^3/sec g= 32.2 //ft/sec^2 //CALCULATIONS v1= Q*(12/d1)^2*4/%pi v2= Q*(12/d2)^2*4/%pi hc= (v1-v2)^2/(2*g) h= ((v1^2-v2^2)/(2*g))-hc h1= 12*h/(sm-1) //RESULTS printf ('difference in level in two limbs of mercury= %.3f in',h1)
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//Chapter 12 : Semiconductor Physics clear; //Variable declaration myun=0.36 //mobility of electrons myup=0.14 //mobility of holes e=1.6*10**-19 rhoi=2.2 //resistivity //Calculations ni=1/(rhoi*e*(myun+myup))/10**18 //Result mprintf("Intrinsic concentration= %.3f*10**18 m*...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 7 Field Effect Transistors Pg no. 225 clear; clc; //Given Data IDSS=15D-3;//drain saturation current in amperes gm0=5D-3;//transconductance for VGS=0 Volts in Siemens gm=2.5D-3;//transconductance in Siemens //Solution ID=IDSS*(gm/gm0)^2;//drain current in...
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//clear// //Example5.4:System gain and upper break frequency //Page 140 //figure 5.6 clear; clc; //STAGE 1 disp("Stage 1"); Rf1=14000; //in Ohms Ri1=2000; //in Ohms Av1=1+(Rf1/Ri1); disp(Av1,"Av"); Anoise1=1+(Rf1/Ri1); disp(Anoise1,"Anoise"); GBW=1*10^6; //in Hz (from Datasheet) f1=G...
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//Chapter 10 //Example 10_14 //Page 248 clear;clc; ll=100; r=0.1; xl=0.5; y=10*1e-6; pd=20*1e6; pfr=0.9; v_r=66*1e3; tr=r*ll; ty=y*ll; txl=xl*ll; z=tr+%i*txl; vr=v_r/sqrt(3); ir=pd/sqrt(3)/v_r/pfr; ir_p=ir*(pfr-%i*sin(acos(pfr))); ic1=vr*%i*ty/2; il=ir_p+ic1; vs=vr+il*z; ic2=vs*%i*ty/2; is=il+ic2; theta1=atan(imag(...
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main function f(); { return call inputnum }; function g(x); { return 1 + 3 * x }; procedure h(x); { call outputnum(x) }; { call h(call g(call f)) }.
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// to find the shortest pulse width that can be displayed // example 9-6 in page 262 clc; //DATA GIVEN Rs=3.3e+3; Ci=15D-12;// source resistance in ohm and input capacitance in farad //calculation printf("shortest pulse width=%.3f micro-second",10*Rs*Ci*2.2*10^6);//here shortest pulse width =10*tuo in seconds whe...
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//---Author :Kathan-shah----- clc clear //--------------------echo-filter------------ //numerator b = [1 zeros(1,16000) 0.1]; //1 sec delay , 10% attenuation(0.1) //denomintor a = [1]; //read audio singal [x,Fs] = wavread('/Users/kathan/Desktop/test.wav') Y = filter(b,a,x); subplot(211) plot(x) title("Origna...
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clc; clear; x=poly(0,'s'); p=x^5 - 3.5*x^4 +2.75*x^3 +2.125*x^2 - 3.875*x + 1.25; disp("The roots of the polynomial are:") disp(roots(p))
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errcatch(-1,"stop");mode(2);//Caption: Find (a)speed (b)number of poles //Exa:13.2 ; ; f1=25//Frequency of motor(in hertz) f2=60//Frequency of generator(in hertz) p=10//Number of poles N=(120*f1)/p disp(N,'(a)Speed(in r.p.m)=') P=(f2*120)/(N) disp(P,'(b)Number of poles=') exit();
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function evenodd(n) // Description of name(input) if pmodulo(n,2) == 0 then disp("Number is even!") else disp("Number is odd!") end endfunction
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-5, Illustration 1, Page 111 //Title: Calculation of composition of a saturated mixture //==========================================...
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clc //initialisation of variables V= -0.658 //volt V1= -0.3363 //volt n= 1 //electron F= 96438 //coloumb R= 8.314 //j/mol K T= 25 //C //CLACULATIONS V2= V-V1 Ksp= 10^(V2*n*F/(2.303*R*(273.2+T))) //RESULTS printf (' Solubility constant = %.1e volt',Ksp)
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//exapple 1.10 clc; funcprot(0); // Initialization of Variable rho=1000; mu=1.42/1000; g=9.81; pi=3.14; l=485; h=4.5 e=8.2/100000; Q=1500*4.545/1000/3600; disp("assume d as 6cm"); d=0.06; u=4*Q/pi/d^2; Re=rho*d*u/mu; rr=e/d;//relative roughness //using moody's chart phi=0.0033//friction coeff. d=...
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//Ex4_13 Pg-245 clc V=20 //source voltage in V Vz=12 //zener voltage in V Vs=V-Vz //voltage across resistor in V Rs=330 //series resistance in ohm RL=1.5*10^3 //load resistance in ohm disp("Voltage across resistor ") printf(" = %.0f V \n ",Vr) disp("(1) Current through series resistor Is") Is=Vr/...
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sce
Example_6_3a.sce
clear; clc; printf("\tExample 6.3\n"); //From draph in the question //stress and strain can be obtained si2=150; // in MPa si1=0; e2=0.0016; e1=0; d0=12.8*10^-3; //Initial Diameter in m printf("\n\tPart A"); //Young's Modulus = stress/strain E=(si2-si1)/(e2-e1); printf("\nModulus of el...