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clear; clc; close; disp("Example 8.3") M1=1.2 //Mach no at impeller tip gm=1.4 //gamma p31=(1+(gm-1)*M1^2)^(gm/(gm-1)) //p=p3/p1 p32=p31^(1/2) //p31=p3/p2 Cp=(2/(gm*M1^2))*(2.2-1) //static pressure rise in radial diffuser disp(p31,"(a)The static pressure the rotor and diffuser p3/p1 :") disp(p32,"The static pressure ratio across the diffuser p3/p2") disp(Cp,"Diffuser static pressure rise :")
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// Scilab code Ex1.9: Pg.34 (2008) clc; clear; // For simplicity assume velocity of light be unity c = 1; // Velocity of light, m/s L_p = 1; // Proper length of stick, m L = 0.914; // Measured length of stick in S', m // From length contraction, L = L_p/gama, solving for gama gama = L_p/L; // Relativistic factor = 1/sqrt(1-(v/c)^2) v = sqrt(1-(L)^2)*c; // Speed of the stick, m/s printf("\nSpeed of the stick = %5.3fc", v); // Result // Speed of the stick = 0.406c
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// Example 10_9 clc;funcprot(0); // Given data m=18.0;// kg/s T_b=350.0;// °C W=20*10^3;// kW // Station 1 T_1=500.0;// °C p_1=3.00;// MPa h_1=3456.5;// kJ/kg s_1=7.2346;// kJ/kg.K // Station 2 p_2=0.0100;// MPa x_2=0.960;// The quality of steam h_2f=191.8;// kJ/kg h_2fg=2392.8;// kJ/kg h_2=h_2f+(x_2*h_2fg);// kJ/kg s_2f=0.6491;// kJ/kg.K s_2fg=7.5019;// kJ/kg.K s_2=s_2f+(x_2*s_2fg);// kJ/kg.K // Ground state x_0=0.00;// The quality of steam T_0=20.0;// °C h_0=83.9;// kJ/kg s_0=0.2965;// kJ/kg.K // Calculation a_f1=(h_1-h_0)-((T_0+273.15)*(s_1-s_0));// kJ/kg a_f2=(h_2-h_0)-((T_0+273.15)*(s_2-s_0));// kJ/kg Q=(W+(m*(a_f2-a_f1)))/(1-((T_0+273.15)/(T_b+273.15)));// kW printf("\nThe rate of heat loss from the surface of the turbine,Q=%4.0f kW",Q); // The answer vary due to round off error
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clear; clc; //page no.89 l = 12;// inches W = 6;// pounds w = 0.0624// lb/cuft l1 = 8;// inches rho = 0.050;// lb/cuft Q_12 = W/w ; Q_8 = W/rho ; V_12 = Q_12/(0.25*%pi*(l/12)^2); V_8 = Q_8/(0.25*%pi*(l1/12)^2); printf('Q_12 = %.1f cfs, Q_8 = %d cfs',Q_12,Q_8); printf('\n V_12 = %.1f fps, V_8 = %d fps',V_12,V_8); //there is a minute error in the answer given in textbook
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---- j = 2 f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1]] q = [[0], [0]] s = [[1], [0]] [8,9,152,161,2728,2889,48952,51841,878408,930249] / [0,0,0,0,0,0,0,0,0,0,1] = [0] rest [8,9,152,161,2728,2889,48952,51841,878408,930249] f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249]] q = [[0], [0], [0]] s = [[1], [0], [1]] ----------------------------- ---- j = 3 f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249]] q = [[0], [0], [0]] s = [[1], [0], [1]] [0,0,0,0,0,0,0,0,0,0,1] / [8,9,152,161,2728,2889,48952,51841,878408,930249] = [-878408/865363202001,1/930249] rest [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001] f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001]] q = [[0], [0], [0], [-878408/865363202001,1/930249]] s = [[1], [0], [1], [878408/865363202001,-1/930249]] ----------------------------- ---- j = 4 f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001]] q = [[0], [0], [0], [-878408/865363202001,1/930249]] s = [[1], [0], [1], [878408/865363202001,-1/930249]] [8,9,152,161,2728,2889,48952,51841,878408,930249] / [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001] = [109973625560761367367120388104/104654444806580617872605,805003253298228249/723375576055] rest [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521] f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001], [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521]] q = [[0], [0], [0], [-878408/865363202001,1/930249], [109973625560761367367120388104/104654444806580617872605,805003253298228249/723375576055]] s = [[1], [0], [1], [878408/865363202001,-1/930249], [-6976962974802764521827/104654444806580617872605,-13845811232016/104654444806580617872605,865363202001/723375576055]] ----------------------------- ---- j = 5 f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001], [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521]] q = [[0], [0], [0], [-878408/865363202001,1/930249], [109973625560761367367120388104/104654444806580617872605,805003253298228249/723375576055]] s = [[1], [0], [1], [878408/865363202001,-1/930249], [-6976962974802764521827/104654444806580617872605,-13845811232016/104654444806580617872605,865363202001/723375576055]] [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001] / [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521] = [1662485286703645524322258182023636245265/12075214064198796260147581722079686,15140893859735291501678694095694655/1863423014864496635504343160368] rest [512304438217173440609975996/6976962988648575753843,67397462455437917909957620/775218109849841750427,9197890776049718659711082761/111631407818377212061488,0,1046544448065806178726050/258406036616613916809,0,523272224032903089363025/2325654329549525251281] f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001], [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521], [512304438217173440609975996/6976962988648575753843,67397462455437917909957620/775218109849841750427,9197890776049718659711082761/111631407818377212061488,0,1046544448065806178726050/258406036616613916809,0,523272224032903089363025/2325654329549525251281]] q = [[0], [0], [0], [-878408/865363202001,1/930249], [109973625560761367367120388104/104654444806580617872605,805003253298228249/723375576055], [1662485286703645524322258182023636245265/12075214064198796260147581722079686,15140893859735291501678694095694655/1863423014864496635504343160368]] s = [[1], [0], [1], [878408/865363202001,-1/930249], [-6976962974802764521827/104654444806580617872605,-13845811232016/104654444806580617872605,865363202001/723375576055], [128076109554293360152493999/13953925977297151507686,2239605118860825222473747/4134496585865822668944,-2298232538841471684605980321/13953925977297151507686,-20930888961316123574521/2153342100236824368]] ----------------------------- ---- j = 6 f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001], [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521], [512304438217173440609975996/6976962988648575753843,67397462455437917909957620/775218109849841750427,9197890776049718659711082761/111631407818377212061488,0,1046544448065806178726050/258406036616613916809,0,523272224032903089363025/2325654329549525251281]] q = [[0], [0], [0], [-878408/865363202001,1/930249], [109973625560761367367120388104/104654444806580617872605,805003253298228249/723375576055], [1662485286703645524322258182023636245265/12075214064198796260147581722079686,15140893859735291501678694095694655/1863423014864496635504343160368]] s = [[1], [0], [1], [878408/865363202001,-1/930249], [-6976962974802764521827/104654444806580617872605,-13845811232016/104654444806580617872605,865363202001/723375576055], [128076109554293360152493999/13953925977297151507686,2239605118860825222473747/4134496585865822668944,-2298232538841471684605980321/13953925977297151507686,-20930888961316123574521/2153342100236824368]] [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521] / [512304438217173440609975996/6976962988648575753843,67397462455437917909957620/775218109849841750427,9197890776049718659711082761/111631407818377212061488,0,1046544448065806178726050/258406036616613916809,0,523272224032903089363025/2325654329549525251281] = [-84855717085637889802269735722628582559104/10952552817773628859840171340993248356009486025,5007929378417038375378486272434664015408/10952552817773628859840171340993248356009486025] rest [18605234636396202010248/523272224032903089363025,20930888965945727261529/523272224032903089363025,18605234636396202010248/523272224032903089363025,-2325654329549525251281/523272224032903089363025] f = [[8,9,152,161,2728,2889,48952,51841,878408,930249], [0,0,0,0,0,0,0,0,0,0,1], [8,9,152,161,2728,2889,48952,51841,878408,930249], [7027264/865363202001,51520/96151466889,125145775/865363202001,25840/865363202001,2246526935/865363202001,160/96151466889,40312339055/865363202001,80/865363202001,723375576055/865363202001], [-55815703798422116174616/104654444806580617872605,-62792666883991370552571/104654444806580617872605,-11785240940759236501632/20930888961316123574521,695529498376494270864/20930888961316123574521,-656762653045406368512/20930888961316123574521,38760157804262838624/20930888961316123574521,-36486814058078131584/20930888961316123574521,2153342100236824368/20930888961316123574521], [512304438217173440609975996/6976962988648575753843,67397462455437917909957620/775218109849841750427,9197890776049718659711082761/111631407818377212061488,0,1046544448065806178726050/258406036616613916809,0,523272224032903089363025/2325654329549525251281], [18605234636396202010248/523272224032903089363025,20930888965945727261529/523272224032903089363025,18605234636396202010248/523272224032903089363025,-2325654329549525251281/523272224032903089363025]] q = [[0], [0], [0], [-878408/865363202001,1/930249], [109973625560761367367120388104/104654444806580617872605,805003253298228249/723375576055], [1662485286703645524322258182023636245265/12075214064198796260147581722079686,15140893859735291501678694095694655/1863423014864496635504343160368], [-84855717085637889802269735722628582559104/10952552817773628859840171340993248356009486025,5007929378417038375378486272434664015408/10952552817773628859840171340993248356009486025]] s = [[1], [0], [1], [878408/865363202001,-1/930249], [-6976962974802764521827/104654444806580617872605,-13845811232016/104654444806580617872605,865363202001/723375576055], [128076109554293360152493999/13953925977297151507686,2239605118860825222473747/4134496585865822668944,-2298232538841471684605980321/13953925977297151507686,-20930888961316123574521/2153342100236824368], [2325654329549525251281/523272224032903089363025,0,-41861777931891454523058/523272224032903089363025,0,2325654329549525251281/523272224032903089363025]] ----------------------------- found: [1,0,-18,0,1]
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//Exa 6.8 clc; clear; close; format('v',8); //Given Data : m=10;//Kg p=10;//bar x=0.9; t1=20;//degree C hf=762.6;//KJ/Kg hfg=2013.6;//KJ/Kg H=m*(hf+x*hfg);//KJ; disp(H,"Enthalpy of wet steam in KJ : "); hf1=83.9;//KJ/Kg(at 20 degree C) Hf1=m*hf1;//KJ HeatAdded=H-Hf1;//KJ disp(HeatAdded,"Heat added in KJ : "); //Steam table is used to get some data.
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//example-2.4 //page no-32 //given //mass of electron m=9.11*10^(-31) //kg //charge on an electron e=1.6*10^(-19) //C //plank's constant h=6.62*10^(-34) E0=8.85*10^(-12) //NO OF ELECTRONS SHELLS IN HYDROZEN ATOm n=1 //atomic number of hydrogen Z=1 //ionization potential energy of hydrogen atom is given by E=m*Z^2*e^4/(8*(E0)^2*h^2*n^2) //J //energy in eV EV=E/e //eV printf ("the ionization potential for hydrogen atom is %f V",EV)
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clear; //clc(); //a).unity power factor s=200; vr=2500; r=1.4; x=0.8; i=s*1000/vr; z=r+(%i)*x; vs=vr+z*i; qs=atand(imag(vs)/real(vs)); pf=cosd(qs); printf("the power factor of the sending end is:%.4f\n ",pf); //b).load power factor =0.8 pfl=acosd(0.8); vs=vr+z*i*(cosd(-pfl)+(%i)*sind(-pfl)); qs=atand(imag(vs)/real(vs)); pf1=qs-(-pfl); //negative sign is due to the loadis lagging pf=cosd(pf1); printf(" the power factor of the sending end is:%.3f\n",pf); //c).load factor is 0.8 leading pfl=acosd(0.8); vs=vr+z*i*(cosd(pfl)+(%i)*sind(pfl)); qs=atand(imag(vs)/real(vs)); pf1=qs-(pfl); //negative sign is due to the loadis lagging pf=cosd(pf1); printf(" the power factor of the sending end is:%.3f\n",pf);
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4_8.sce
clc; p1=6.3;//bar p2=1.05;//bar n=1.3; T1=823;//K T2=T1/([p1/p2]^([n-1]/n)) R=0.287; sA_s1=R*log(p1/p2);//sA_s1=sA-s1 cp=1.005; sA_s2=cp*log(T1/T2); disp("increase in entropy is:"); disp("kJ/kg",sA_s1-sA_s2)
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// Example 4.1 clc; clear; close; // Given data Q= 1000;// in kJ T1= 1000;// in K T2= 400;// in K delta_Qsource= -Q/T1;// in kJ/K delta_Qsystem= Q/T2;// in kJ/K delta_Qnet=delta_Qsystem+delta_Qsource;// in kJ/K disp(delta_Qnet,"The entropy production accompanying the heat transfer in kJ/K is : ") T0= 300;// in K Q1= Q-T0*abs(delta_Qsource);// in kJ Q2= Q-T0*abs(delta_Qsystem);// in kJ LossOfEnergy= Q1-Q2;// in kJ disp(LossOfEnergy,"The decrease in available energy after heat transfer in kJ is : ")
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example15_49.sce
//Example 15.49 // Plotting root loci of the transfer function k/s*(s+4)*(s^2+4*s+20) clear; clc; xdel(winsid()); s=%s; num=(1); den=s*(s+3)*(s^2+2*s+2); G=syslin('c',num/den); clf; evans(G); mtlb_axis([-5 5 -5 5]);
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decomp_modified_gram_schmidt.sce
/////////////////////////////////////////////////////////// // Modified Gram-Schmidt Process // // Description: Orthonormalizes a set of vectors // corresponding to the columns of a matrix A. // Yields QR decomposition of A when applied to // full column rank matrix. Modified implementation // for greater numerical stability. /////////////////////////////////////////////////////////// // Input: // Q: a m x n full column rank matrix /////////////////////////////////////////////////////////// // Output: // Q: an orthogonal matrix // R: an upper triangular matrix /////////////////////////////////////////////////////////// function [Q,R] = decomp_modified_gram_schmidt(Q) // Determine matrix dimensions [m n]=size(Q); // Initialize R R = zeros(m,m); // Find Orthonormal Vectors for i=1:n // Identify vector projections for j=1:(i-1) // Fill i-th column of R R(j,i) = Q(:,j)'*Q(:,j); // Subtract projection from vector Q(:,i) = Q(:,i) - R(j,i)*Q(:,j); end // Find vector norm R(i,i) = norm(Q(:,i)); // Update Q Q(:,i) = Q(:,i)/R(i,i); end endfunction
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verificapar.sce
function op = verificapar(n) if modulo(n,2)==0 then op = 1 else op = 0 end endfunction
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Ex7_2.sce
//Example 7_2 clc(); clear; //To find the fraction of initial intensity alpha=-2.2 l=2 //units in KM //Case (a) when L=2 It_I0=10^(alpha*l/10) printf("The fraction of initial intensity left when L=2 It/I0=%.3f\n",It_I0) //Case (b) when L=6 l=6 //units in KM It_I0=10^(alpha*l/10) printf("The fraction of initial intensity left when L=6 It/I0=%.3f\n",It_I0)
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// Exa 7.6 clc; clear; close; format('v',5) // Given data L1 = 30;// in mH L1 = L1 * 10^-3;// in H L2 = 1*10^-8;// in H M = 0;// in H L = L1+L2+(2*M);// in H C = 100;// in pF C = C * 10^-12;// in F f_o = 1/(2*%pi*(sqrt( L*C )));// in Hz f_o = f_o * 10^-3;// in kHz disp(f_o,"The frequency of oscillation in kHz is");
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//1.15 clc; P=0.3; Vs=12; disp('Since load line has a slope of -100V/A, the source resistance for the gate is 100 ohm') Rs=100; // since Vs=Vg+Ig*Rs // on solving Ig=35.5 mA Ig=35.5*10^-3; printf("\nGate current=%.4f A",Ig) Vg=P/Ig; printf("\nGate voltage=%.2f V",Vg)
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// Scilab Code Ex2.32: Page-93 (2008) clc; clear; E = [8 4 3]; // Coefficients of i, j and k in the electric field, N/C S = [0; 0; 100]; // Coefficients of i, j and k in the area vector, Sq. m phi_E = E*S; // Electric flux through the surface, N-Sq.m/C printf("\nThe electric flux through the area in XY plane = %d N-Sq.m/C", phi_E); // Result // The electric flux through the area in XY plane = 300 N-Sq.m/C
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//FFT of a Sequence clc ; clear all; close ; x = input("Enter the sequence = ") X = fft(x) subplot(2,1,1) plot(real(X),'r') xtitle("Real Part") subplot(2,1,2) plot(imag(X),'b') xtitle("Imag Part") disp("The FFT is = ", X)
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a = 3 b = true c = 4 d = false e = a + c f = b * d
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//Example 10-2, Page No -380 clear clc channels =16 sampling_rate= 3.5*10^3 w_len=6 available_ch =channels-1 bpf =channels*w_len data_rate = sampling_rate * bpf printf('Available channels are %d',available_ch) printf('\n Bits Per Frame =%d',bpf) printf('\n The serial data rate %.1f Khz',data_rate/10^3)
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Using TensorFlow backend. Obteniendo datos... [AVISO] Usuarios: 43628 [AVISO] Restaurantes: 6810 [AVISO] Cargando datos generados previamente... Creando modelo... ################################################## MODELV4 ################################################## modelv4d2 ################################################## 0/144 1/144 2/144 3/144 4/144 5/144 6/144 7/144 8/144 9/144 10/144 11/144 12/144 13/144 14/144 15/144 16/144 17/144 18/144 19/144 20/144 21/144 22/144 23/144 24/144 25/144 26/144 27/144 28/144 29/144 30/144 31/144 32/144 33/144 34/144 35/144 36/144 37/144 38/144 39/144 40/144 41/144 42/144 43/144 44/144 45/144 46/144 47/144 48/144 49/144 50/144 51/144 52/144 53/144 54/144 55/144 56/144 57/144 58/144 59/144 60/144 61/144 62/144 63/144 64/144 65/144 66/144 67/144 68/144 69/144 70/144 71/144 72/144 73/144 74/144 75/144 76/144 77/144 78/144 79/144 80/144 81/144 82/144 83/144 84/144 85/144 86/144 87/144 88/144 89/144 90/144 91/144 92/144 93/144 94/144 95/144 96/144 97/144 98/144 99/144 100/144 101/144 102/144 103/144 104/144 105/144 106/144 107/144 108/144 109/144 110/144 111/144 112/144 113/144 114/144 115/144 116/144 117/144 118/144 119/144 120/144 121/144 122/144 123/144 124/144 125/144 126/144 127/144 128/144 129/144 130/144 131/144 132/144 133/144 134/144 135/144 136/144 137/144 138/144 139/144 140/144 141/144 142/144 143/144 144 0.0317 27.894 0.2833 0.2261
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//chapter 5 //example 5.1 //Find velocity and kinetic energy //page 102-103 clear; clc; //given lambda=1; //in Angstrom (wavelength) m=1.67E-27; // in Kg (mass of neutron) h=6.625E-34; // in J-s (Planck's constant) e=1.6E-19; // in C (charge of electron) //calculate lambda=lambda*1E-10; //since lambda is in Angstrom // Since lambda=h/(m*v) // Therefore we have v=h/(m*lambda); //calculation of velocity printf('\nThe velocity is \t v=%1.2E m/s',v); K=m*v^2/2; //calculation of kinetic energy printf('\nThe kinetic energy is\tK=%1.2E J',K); K=K/e; //changing unit fro J to eV printf('\n\t\t\t=%.4f eV',K); //Note: Due to round off, there is slight variation in the answer
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//Example 8.3: Motor speed and current drawn clc; clear; close; //given data : N1=640;// in rpm I1=15;// in A I2=sqrt((2)*sqrt(2)*I1^2); N2=round((2*I1*N1)/I2); disp(I2,"Current drawn,I2(A) = ") disp(N2,"Motor speed,N2(rpm) = ")
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//Finding of Friction Factor //Given D=0.1; ks=0.0025; v=2; v1=10^-6; //To Find //case-1 R=(v*D)/v1; fa=(1.785*log10(R))-1.424; a=(fa)^2; f1=1/a; //case-2 fb=2*log10((3.71*D)/ks); b=(fb)^2; f2=1/b; //Case-3 fc=-(2*log10((ks/3.71*D)+(5.186/R^(0.89)))); c=(fc)^2; f3=1/c; disp(" Friction Factor for"); disp("Smooth Turbulent flow ="+string(f1)+" no units "); disp("Rough Turbulent flow ="+string(f2)+" no units "); disp("Smooth and Rough Turbulent flow ="+string(f3)+" no units ");
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//To convert velocity m/s from km/h conv = 5/18 //Given that v_BA = 52 //in km/hr v_PA = -78 //in km/hr //Sample Problem 4-10a printf("**Sample Problem 4-10a**\n") //using concept of relative velocity v_PB = v_PA - v_BA printf("The velocity of P as measured by Barbara is %d km/hr\n",v_PB) //Sample Problem 4-10b printf("\n**Sample Problem 4-10b**\n") //In frame of Alex delta_t = 10 //in sec a_PA = (0 - v_PA)* conv/delta_t printf("The accleration of P in frame of Alex is %f m/s^2\n", a_PA) //Sample Problem 4-10c printf("\n**Sample Problem 4-10c**\n") a_BA = 0 a_PB = a_PA - a_BA printf("The acceleration of P as measured by B is %f m/s^2", a_PB)
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clc //ex2.16 V_s=15; //source voltage R_1=100; R_2=50; //Analysis with an open circuit to find V_t i_1=V_s/(R_1+R_2); //closed circuit with R_1 and R_2 in series V_oc=R_2*i_1; //open-circuit voltage across R_2 V_t=V_oc; //thevenin voltage //Analysis with a short-circuit to find i_sc i_sc=V_s/R_1; //R_2 is short-circuited R_t=V_oc/i_sc; //thevenin resistance printf(" All the values in the textbook are approximated, hence the values in this code differ from those of textbook") disp(V_t,'Thevenin voltage for given circuit in volts') disp(R_t,'Thevenin voltage for given circuit in ohms')
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clear; clc; V_s=230; V_01=2*V_s/(sqrt(2)*%pi); R=2; I_01=V_01/R; P_d=I_01^2*R; printf("power delivered to load=%.1f W",P_d); V=V_s/2; I_s=sqrt(2)*I_01/%pi; P_s=V*I_s; printf("\npower delivered by both sources=%.1f W",2*P_s);
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//Variable declaration: qs = 1000 //Volumetric flow rate at standard conditions (scfm) Ta = 300+460 //Actual absolute temperature in Rankine scale (°R) Ts = 70+460 //Standard absolute temperature in Rankine scale (°R) A = 2.0 //Inlet area of stack (ft^2) //Calculations: qa = qs*Ta/Ts //Volumetric flow rate at actual conditions (acfm) v = qa/A/60 //Velocity of gas (ft/s) //Result: printf("The velocity of the gas through the stack inlet is : %.0f ft/s",v)
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//Exa 7.5 clc; clear; close; format('v',7); //Given data : r=2.5/2;//cm epsilon_r=4;//constant r1=3/2;//cm r2=9/2;//cm V=20;//kV(rms) //Formula : gmax=q/(2*epsilon*r) g2maxBYg1max=r/epsilon_r/r1;//unitless //Formula : V=g1max*r*log(r1/r)+g2max*r1*log(r2/r1) g1max=V/(r*log(r1/r)+g2maxBYg1max*r1*log(r2/r1));//in kV/cm disp(g1max,"g1max(kV/cm) = "); disp("g1max > go, Corona will be present.");
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function ret = hrtTypeFunc(trmsData) if part(trmsData,1:2) == '$\' then ret = trmsData; else trmsData = part(trmsData,2:$); [start, final, match, _] = regexp(trmsData,'/([a-zA-Z]+(_[a-zA-Z]+)+)/i'); for i=1:size(match,1) trmsData = part(trmsData,1:(start(i)-1)+23*(i-1))+'vpcBDReadTranslated('''+match(i)+''')'+part(trmsData,final(i)+1+23*(i-1):$); end try ret = evstr(trmsData); catch pause; end end endfunction
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 17.2 //calculation of the separation between successive bright fringes //given data d=0.10*10^-3//separation(in m) between the slits lambda=600*10^-9//wavelength(in m) of the light used D=1//separation(in m) between the slits and the screen //calculation w=D*lambda/d//separation between successive bright fringes printf('the separation between successive bright fringes is %3.1e m or %3.1f mm',w,w*10^3)
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function moea_d_update global objectives individuals generations rooms subproblem_neighbors subproblem_neighbor rooms records subproblem_fitness generation_num sample_num Geno distance=zeros(individuals,individuals); //多目的空間の個体間距離 // Genoの処理(fitnessが改善しなかった個体を元に戻す) for individual_num=1:individuals for room_num=1:rooms if records(individual_num,1,3) > subproblem_fitness(1,individual_num) Geno(room_num,1:2,individual_num)=records(individual_num,room_num,1:2); end end end // recordsの更新 for individual_num=1:individuals if records(individual_num,1,3) <= subproblem_fitness(1,individual_num) // fitnessが高くなっているならrecordsの座標更新 for room_num=1:rooms records(individual_num,room_num,1:2)=Geno(room_num,1:2,individual_num); end records(individual_num,:,3)=subproblem_fitness(1,individual_num); end end distance=zeros(individuals,individuals); // 多目的空間の個体どうしの距離を求める for individual_num=1:individuals for comparison_num=1:individuals for objective_num=1:objectives distance(individual_num,comparison_num)=distance(individual_num,comparison_num).. +(Objective(individual_num,objective_num,generation_num,sample_num)-Objective(comparison_num,objective_num,generation_num,sample_num))^2; end distance(individual_num,comparison_num)=sqrt(distance(individual_num,comparison_num)); end end // 近隣個体 subproblem_neighbor(:,:,1)=0; subproblem_neighbor(:,:,2)=BIG_NUM; for individual_num=1:individuals for comparison_num=1:individuals for neighbor_num=subproblem_neighbors:(-1):1 // 要素: subproblem_neighbors+1は実際の処理時には使われない if subproblem_neighbor(individual_num,neighbor_num,2) > distance(individual_num,comparison_num) .. // より距離の近い個体を発見したら & individual_num ~= comparison_num // 比較対象が自分自身のとき除外 subproblem_neighbor(individual_num,neighbor_num+1,1)=subproblem_neighbor(individual_num,neighbor_num,1); // 現在個体から見て比較個体より距離が遠い個体をずらしてから代入 subproblem_neighbor(individual_num,neighbor_num+1,2)=subproblem_neighbor(individual_num,neighbor_num,2); subproblem_neighbor(individual_num,neighbor_num,1)=comparison_num; //個体番号代入 subproblem_neighbor(individual_num,neighbor_num,2)=distance(individual_num,comparison_num); //距離代入 //elseif subproblem_neighbor(individual_num,neighbor_num,2) == 0 .. //まだ代入されていないならそのまま代入 //& individual_num ~= comparison_num // 比較対象が自分自身のとき除外 // subproblem_neighbor(individual_num,neighbor_num,1)=comparison_num; //個体番号代入 // subproblem_neighbor(individual_num,neighbor_num,2)=distance(individual_num,comparison_num); //距離代入 // pause end end end end // 近隣個体のfitnessを代入 for individual_num=1:individuals for neighbor_num=1:subproblem_neighbors subproblem_neighbor(individual_num,neighbor_num,3)=subproblem_fitness(1,subproblem_neighbor(individual_num,neighbor_num,1)); end end //for individual_num=1:individuals // for neighbor_num=1:subproblem_neighbors // 要素: subproblem_neighbors+1は実際の処理時には使われない // if subproblem_neighbor(individual_num,neighbor_num,3) < subproblem_fitness(1,subproblem_neighbor(individual_num,neighbor_num,1)) // //if subproblem_neighbor(individual_num,neighbor_num,3) < records(subproblem_neighbor(individual_num,neighbor_num,1),1,3) // fitnessが高くなったら更新 // //& individual_num ~= subproblem_neighbor(individual_num,neighbor_num,1) // 比較対象が自分自身のとき除外 // subproblem_neighbor(individual_num,neighbor_num,3)=subproblem_fitness(1,subproblem_neighbor(individual_num,neighbor_num,1)); //更新 // //subproblem_neighbor(individual_num,neighbor_num,3)=records(subproblem_neighbor(individual_num,neighbor_num,1),1,3); // end // end //end endfunction
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//Example 2_6 clc(); clear; //To calculate the dispersive power of the granting in the third order spectrum k=3 e=1/4000 //units in cm lemda=5000*10^-8 //units in cm theta=asin((k*lemda)/e) dt_dl=k/(e*cos(theta)) printf("Disperssive power of the granting in the third order spectrum is %.0f",dt_dl)
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clc; funcprot(0); //Example 22.2 //Initializing the variables D = 0.1; t = 15*10^-3; Q = 8.5/3600; N = 750/60; B2 = 25; // Beta 2 ind degrees g = 9.81; z = 16; //Calculations A = %pi*D*t; V_f2 = Q/A; U2 = %pi*N*D; V_w2 = U2 - V_f2*cotd(B2); Hth = U2*V_w2/g; Sf = 1 - %pi*sind(B2)/(z*(1-(V_f2/U2)*cotd(B2))); H = Sf*Hth; disp(H, "Part (b) - Head developed (m): ",Hth, "Part (a) - Head developed (m): ");
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Question3_3.sci
function [] = Question3_3() t = [0:39]; a=1/20; f = sin(2 * %pi * t * a); d = zeros(t); d(1,1)=1/4; d(1,2)=1/4; d(1,3)=1/4; d(1,4)=1/4; resultat = ifft(fft(f) .* fft(d)); dfft=fft(d); fonctionDebut = resultat ./ fft(d); epsilon=0.94; for i=1:40 if abs(dfft(1,i))<epsilon then dfft(1,i)=epsilon; else end end fonctionDebut = ifft(fft(resultat)./dfft); plot(fonctionDebut); plot(f,'r'); endfunction Question3_3();
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// Example 5.7 // Determine expected locked-rotor line current // Page No. 192 clc; clear; close; // Given data Ir1=151; // Rated current V1=230; // Rated voltage V2=220; // Motor starting voltage F1=60; // Rated frequency F2=50; // Motor starting frequency // Expected locked-rotor line current Ir2=Ir1*((V2/F2)/(V1/F1)); // Display result on command window printf("\n Expected locked-rotor line current = %0.0f A ",Ir2);
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Example_6_24.sce
// Example 6.24 Trend equation for certain production clc; clear; x1=20; y1=(240)/12+(36*(x1+0.5))/(12*12); disp(y1,"Trend values for the month of March,1982 =","Considering Unit = 1 month",x1,"Time with origin at year July,1980= ");
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//Section-14,Example-2,Page no.-PC.54 //To calculate force necessary to lift a ring of 1.0 cm radius from liquid water. clc; y=72.8 //dynes/cm r=1 //cm F=2*(2*%pi*r)*y //dynes disp(F,'Force necessary to lift a ring of radius r from a liquid of surface tension y(dynes)')
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// Caption: Finding speed voltage constant clear; close; clc; V_t=50; I_a=1.25; R_a=1.03; E_a=V_t-I_a*R_a; W=220;//rad/s K_m=E_a/W;// V/rad/s //At 1700 r/min W_m=1700*2*%pi/60;//rad/s E_anew=K_m*W_m; I_anew=(48-E_anew)/1.03; P_shaft=E_anew*I_anew; P=P_shaft-61; disp(P,'output power=')
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @outputs number @data 1 1 2 2 3 2 3 3 3 8 5 5 0 0 1 1 3 3 4 4 7 7 0 0 4 4 0 0 1 1 4 4 5 6 7 7 9 3 9 9 5 5 6 6 2 2 3 9 5 5 5 5 6 6 9 9 0 2 4 4 5 5 6 6 0 1 1 1 2 2 6 6 7 7 7 4 8 0 8 8 9 9 2 2 7 7 9 0 9 9 3 7 4 4 6 6 8 8 9 9
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pathname=get_absolute_file_path('1.1.sce') filename=pathname+filesep()+'1.1-data.sci' exec(filename) //bore diameter(in cm): d=(4*Vs*Ro/%pi)^(1/3) //length(in cm): l=d/Ro //compression ratio: R=(Vs+Vc)/Vc printf("\n\nRESULTS\n\n") printf("\nbore:%f\n",d) printf("\nstroke:%f\n",l) printf("\ncompression ratio:%f\n",R)
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//caption:determine_Kp_Kv_Ka //example 11_16 //page 485 s=%s; syms t; num=10 den=sym('s^2+6*s+10'); GH=num/den; GH=simple(GH); disp(GH,"G(s)H(s)="); Kp=limit(GH,s,0);//static positional error coefficient disp(Kp,"static positional error coefficient="); Kv=limit(s*GH,s,0);//static velocity error coefficient disp(Kv,"static velocity error coefficient="); Ka=limit(s^2*GH,s,0);//static acceleration error coefficient disp(Ka,"static acceleration error coefficient=");
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//design cottered foundation bolts clc //solution //given P=50*10^3//N ft=80//N/mm^2 t=50//N/mm^2 fc=100//N/mm^2 pi=3.14 //P=(pi/4)*d^2*ft=62.84*d^2 //d=sqrt(P/62.84)//mm printf("the diameter of bolt is,%f mm\n",sqrt(P/62.84)) printf("the diameter of bolt is,say 30mm\n") d=30//mm //let d1 be dia of enlarged end of bolt //t1 be thickness of cotter //t1=d1/4 //P=[((pi/4)*d1^2)-(d1*t1)]*ft //P=42.84*d1^2 //d1=sqrt(P/42.84)//mm printf("the dia of enlarged end of bolt is,%f mm\n ",sqrt(P/42.84)) printf("the dia of enlarged end of bolt is,say 36mm\n") d1=36//mm t1=d1/4//mm printf("the thickness is,%f mm\n",t1) //let b width of cotter //P=2*b*t1*t==900*b b=P/(900)//mm printf("the width of cotter is,%f mm\n",b)
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layers.tst
# Test of layer refinement. # # This test takes a non-centro structure (cyclo) and tests all the # following features of SFLS in all combinations: # # Refinement, Scale, Calc } These options are worked # Mixed ISO/ANISO refinement } through in the instruction file # Extinction } layer.ref # # F and F squared refinement FSQ or NOFSQ # Anomalous scattering ANOM or NOANOM # # \set time slow \rele print CROUTPUT: \use layer.in # NOFSQ, NOANOM \LIST 23 MODIFY EXTINCTION=YES ANOM=NO MINIMISE F-SQ=NO END \USE layer.ref # NOFSQ, ANOM \use layer.in \LIST 23 MODIFY EXTINCTION=YES ANOM=YES MINIMISE F-SQ=NO END \USE layer.ref # FSQ, NOANOM \use layer.in \LIST 23 MODIFY EXTINCTION=YES ANOM=NO MINIMISE F-SQ=YES END \USE layer.ref # FSQ, ANOM \use layer.in \LIST 23 MODIFY EXTINCTION=YES ANOM=YES MINIMISE F-SQ=YES END \USE layer.ref # And close the program. \FINISH
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Ex3_15.sce
clc; B=1; // peak flux density in Tesla l=0.8; // length of armature conductor v=20; // velocity of coil // for 0< theta <30 coil aa' is moving in zero B-wave, emf for this range is zero // for 30< theta < 60 coil side a is cutting through B-wave and coil side a' is cutting zero B-wave, therefore e1=B*l*v; // emf at given position of coil // for 60< theta < 150 both coil sides are cutting through B-wave e2=2*B*l*v; // net emf at given position of coil rms=sqrt((1/%pi)*(((e1^2*%pi*2)/6)+((e2^2*%pi)/2))); printf('RMS value of generated emf in one single turn coil is %f V',rms);
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ex_7_5_A.sce
// Example 7.5.a: yield point stress clc; clear; close; format('v',10) yl=34;//yeild load in kN ul=61;//ultimate load in kN fl=78;//final length in mm glf=60;//gauge length of fratture in mm fd=7;//final diamtere in mm d=12;//specimen diamtere in mm sl=62.5;//specimen length in mm A=(%pi*(d)^2)/4;// in meter square ylp=((yl*10^3)/(A));//yeild point stress in N/mm^2 disp(floor(ylp),"yeild point stress in N/mm^2")
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EX19.sce
// Example 2.19 (a) Vd1 and Vd2 // (b) Current in the circuit clc, clear eta_VT=0.026; // Product of η and VT disp("Part (a)"); // From the Fig. 2.19(a) Is=5e-6; // Reverse saturation current through diode D2 in amperes Id1=Is; // Forward current through diode D1 in amperes Vd1=eta_VT*log(1+(Id1/Is)); // in volts Vd2=5-Vd1; // in volts disp(Vd1,"Vd1 (V) ="); disp(Vd2,"Vd2 (V) ="); disp("Part (b)"); // From the Fig. 2.19(b) Vz=4.9; // Zener voltage in volts Vd1=5-Vz; // in volts I=Is*(%e^(Vd1/eta_VT)-1); // Current in the circuit in amperes I=I*1e6; // Current in the circuit in micro-amperes disp(I,"Current in the circuit (μA) =");
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test028.txt
main var a, b,c,d,e; { let e <- b; if c < 3 then let b <- a+4; let d <- b else let c <- a+4 fi; let a <- b+e; let d <- c+d }.
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Chapter6_Example6.sce
//Chapter-6, Example 6.6, Page 247 //============================================================================= clc clear //INPUT DATA p=0.8;//Dynamic viscosity in N.s/m^2 k=0.15;//Thermal conductivity in W/m.K Tb=10;//Temperature of bearing in degree C Ts=30;//Temperature of the shaft in degree C C=0.002;//Clearance between bearig and shaft in m U=6;//Velocity in m/s //CALCULATIONS qb=(((-p*U^2)/(2*C))-((k/C)*(Ts-Tb)))/1000;//Surface heat flux at the bearing in kW/m^2 qs=(((p*U^2)/(2*C))-((k/C)*(Ts-Tb)))/1000;//Surface heat flux at the shaft in kW/m^2 Tmax=Tb+(((p*U^2)/(2*k))*(0.604-0.604^2))+((Ts-Tb)*0.604);//Maximum temperature in degree C occurs when ymax=0.604L //OUTPUT mprintf('Maximum temperature rise is %3.3f degree C \n Heat fux to the bearing is %3.1f kW/m^2 \n Heat fux to the shaft is %3.1f kW/m^2',Tmax,qb,qs) //=================================END OF PROGRAM==============================
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Example11_11.sce
//clear// //Caption: //Example11.11 //page381 clc; clear close; Rg = 50; //series resistance with battery in ohms Zo = Rg; //characteristic impedance RL = 25; //load resistance Vo = 10; //battery voltage in volts V1_S = (Rg/(Zo+Rg))*Vo; T = (RL-Zo)/(RL+Zo); V1_R = T*V1_S; I1_S = V1_S/Zo; I1_R = -V1_R/Zo; IB = Vo/(Zo+RL); VL = Vo*(RL/(Rg+RL)); disp(V1_S,'Voltage at source in volts V1plus =') disp(V1_R,'Voltage returns to battery in volts V1minus=') disp(I1_S,'Current at battery in amps I1plus=') disp(I1_R,'Current at battery in amps I1minus=') disp(IB,'Steady state current through battery in amps IB=') disp(VL,'Steady state load voltage in volts VL=') //Result //Voltage at source in volts V1plus = // 5. //Voltage returns to battery in volts V1minus= // - 1.6666667 //Current at battery in amps I1plus= // 0.1 //Current at battery in amps I1minus= // 0.0333333 //Steady state current through battery in amps IB= // 0.1333333 //Steady state load voltage in volts VL= // 3.3333333
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// script die de testen uitvoert, // eerst de controleSudoku() functie, // daarna de solveSudoku mode(-1); warning('off') exec('solver.sce') exec('testcases/controleSudoku2.sce') exec('testcases/solveSudoku2.sce')
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//Page Number: 498 //Example 9.20 clc; //Given Cj=0.5D-12; //F Lp=0.5D-9; //H Irf=0.65; //A Rl=2; //ohms Vbd=80; //V Idc=0.08; //A //Resonant frequency f=1/(2*%pi*sqrt(Cj*Lp)); disp('Hz',f,'Resonant frequency:'); //Efficiency Pout=(Irf*Irf*Rl)/2; Pin=Vbd*Idc; n=(Pout*100)/Pin; disp('%',n,'Efficiency:');
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// Case Study:-Chapter 5 // 2.Pay-Bill Calculations CA1=1000; CA2=750; CA3=500; CA4=250; EA1=500; EA2=200; EA3=100; EA4=0; level=1; while(level) printf("Enter 0[zero] for level to end"); //Read data level=input("Enter level:"); if(level==0) break; end printf("Enter job number, and basic pay\n"); //Read data [jobnumber,basic]=scanf("%d %f"); //Decide level number and calculate perks select level case 1 then perks=CA1+EA1; case 2 then perks=CA2+EA2; case 3 then perks=CA3+EA3; case 4 then perks=CA4+EA4; else printf("Error in level code"); return; end house_rent=0.25*basic; //Calculate gross salary gross=basic+house_rent+perks; //Calculate income tax if (gross<=2000) then incometax=0; elseif(gross<=4000) incometax=0.03*gross; elseif(gross<=5000) incometax=0.05*gross; else incometax=0.08*gross; end //Compute the net salary net=gross-incometax; //Print the results printf("%d %d %.2f\n",level,jobnumber,net); end printf("END OF THE PROGRAM");
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//New plant pf and percent decrease in line current clc; clear; Pmp=5000*(10^3); // Electrical load pfmp=0.8; // Lag Pim=500*735;// One horse power is 735W Effim=96/100; // Efficiency of the motor pfim=0.9; // Lag pfsm=0.8; // Lead Pime=Pim/Effim;// Effective power delivered by the induction motor deff('x=com(y,z)','x=y+(%i*y*tand(acosd(z)))')// Function to find the complex powers //Complex Powers Pcmp=com(Pmp,pfmp); // Manufacturing Plant Load Pcim=com(Pime,pfim);// Induction Motor Pcsm=com(Pime,-pfsm);// Synchronous Machine, Minus Sign indicates Lead Pr=Pcmp-Pcim+Pcsm; // Plant Requirement after replacement pfar=real(Pr)/abs(Pr); // New Power Factor of the plant Pnp=abs(Pr); Vl=poly([0 1],'Vl','c'); Io=Pmp/(pfmp*sqrt(3)*Vl); In=Pnp/(sqrt(3)*Vl); // Improved Factor Value =1; red=(Io-In)*100/Io; // Reduction percent in fractions redeq=Vl-red;// Reduction percent in decimal characteristic equation redper=roots(redeq(2)); printf('The New Power Factor of the plant = %g lag \n',pfar ) printf('The Percentage decrease in line current that will result in improved p.f = %g percent \n',redper)
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// Example 12.4 // Computation of (a) Required resistance of a noninductive diverter that will // bypass 27 percent of the total armature current(b) Power rating of the // diverter // Page No. 494 clc; clear; close; // Given data Rs=0.00306; // Shunt generator resistance rating Is=0.73; // Shunt generator current rating Id1=0.27; // Armature winding resistance Pload=170000; // Load of power VT=250; // Shunt generator voltage rating Id2=680; // No load voltage Rd=0.27; // Resistance drop // (a) Required resistance of a noninductive diverter that will bypass // 27 percent of the total armature current Rd=Rs*Is/Id1; // (b) Power rating of the diverter Ia=Pload/VT; Pd=((Id1*Id2)^2)*Rd; //Display result on command window printf("\n Required resistance of a noninductive diverter = %0.5f Ohm ",Rd); printf("\n Power rating of the diverter = %0.0f W ",Pd);
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P = 1500 ; // Load in lb e = 0.45 ; // ecentricity in inch h = 1.2 ; // Height of cross section in inch b = 0.6 ; // Width of cross section in inch E = 16e06 ; // Modulus of elasticity del = 0.12 ; // Allowable deflection in inch L = asec(1.2667)/0.06588 ; // Maximum allowable length possible // Above formula comes from solving following equation // Pcr = (%pi^2*E*I)/(4*(L)^2); I = (h*b^3)/12; del = e*(sec((%pi/2)*sqrt(P/Pcr))-1) disp("inch",L,"The longest permissible length of the bar is")
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//Tested on Windows 7 Ultimate 32-bit //Chapter 10 Feedback in Amplifiers Pg no. 330 clear; clc; //Given Vi=2D-3;//input voltage in volts Vo_dash=10;//output voltage with feedback in volts BVo_dash=200D-3;//feedback voltage in volts //Solution A=Vo_dash/Vi;//open loop gain Afb=Vo_dash/(Vi+BVo_dash);//closed loop gain B=1/Afb-1/A;//feedback gain beta printf("β = %.2f",B);
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clc; clear; //assume the first cloumn values are of machine M1 and 2nd column are of M2 p=[1,1;1 3;2 2;2 4;3 3;3 1;4 4;4 2]; z=1; for i=1:length(p(:,1)) for j=i:length(p(:,1)) if(p(i,1)==p(j,1) & i~=j) q(z,:)=[p(i,:) p(j,:)]; z=z+1; end end end disp("pi(R)"); disp(q); z=1; for i=1:length(p(:,1)) for j=i:length(p(:,1)) if(p(i,2)==p(j,2) & i~=j) q(z,:)=[p(i,:) p(j,:)]; z=z+1; end end end disp("pi(S)"); disp(q);
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function scs_m=do_block(scs_m) // do_block - edit a block icon while %t [btn,xc,yc]=xclick(0); pt=[xc,yc] [n,pt]=getmenu(datam,pt); if n>0 then n=resume(n),end K=getblock(scs_m,[xc;yc]) if K<>[] then break,end end gr_i=scs_m(K)(2)(9) if type(gr_i)==15 then [gr_i,coli]=gr_i(1:2) else coli=[] end while %t do gr_i=dialog(['Give scilab instructions to draw block'; 'shape.'; 'orig(1) : block down left corner x coordinate'; 'orig(2) : block down left corner y coordinate'; 'sz(1) : block width'; 'sz(2) : block height'],gr_i) if gr_i==[] then return,end mac=null();deff('[]=mac()',gr_i,'n') if check_mac(mac) then o=scs_m(K) drawblock(o) o(2)(9)=list(gr_i,coli) drawblock(o) scs_m(K)=o break end end
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//chapter-5,Example5_4,pg 492 Vref=5//ref. voltage t=1*10^-3//sawtooth wave time f=100*10^3//clock frequency Vi=1//input voltage N=((t*f*Vi)/Vref)//count printf("count=%.2f \n",N)
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//Caption: Frequency Response //Fig2.12 //page 60 clc; close; [X, Y] = meshgrid(-%pi:.09:%pi); Z = 2*cos(X)+2*cos(Y); surf(X,Y,Z); xgrid(1)
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// Example 5.19 // Computation of (a) Locked rotor current per phase and minimum locked rotor // torque when starting (b) Locked rotor current per phase when motor is delta // connected (c) Code letter // Page No.233 clc; clear all; close; // Given data V=460; // Rated Voltage Z=0.547; // Locked rotor impedance n=1750; // Speed of machine hp=60; // Horsepower rating of device f=60; // Frequency of motor // (a) Locked rotor current per phase and minimum locked rotor torque Vphase=V/sqrt(3); // Voltage/phase Ilr1=Vphase/Z; // Locked rotor current/phase Trated=hp*5252/(n); // Rated torque Tlr=1.4*Trated; // Locked rotor torque T2=Tlr*(Vphase/V)^2; // (b) Locked rotor current per phase when motor is delta connected Ilr=V/Z; // Locked rotor current/phase Il=Ilr*sqrt(3); // Line current // (c) Code letter Slr=sqrt(3)*V*Il/1000; // Code letter at rated voltage kVA=Slr/f; // Display result on command window printf("\n Locked rotor current per phase = %0.1f A",Ilr1); printf("\n Minimum locked rotor torque = %0.0f lb-ft",T2); printf("\n Locked rotor current per phase when motor is delta connected = %0.0f A ",Il); printf("\n Code letter = %0.1f",kVA);
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clear; clc; disp('Example 4.5'); // aim : To determine // the specific enthalpy // Given values P = 70; // pressure, [kn/m^2] x = .85; // Dryness fraction // solution // from steam table, at given pressure hf = 376.8;// [kJ/kg] hfg = 2283.3;// [kJ/kg] // now using equation [2] h = hf+x*hfg;// specific enthalpy of wet steam,[kJ/kg] mprintf('\n The specific enthalpy of wet steam is = %f kJ/kg \n',h); // There is minor variation in the book's answer // End
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function [r] = solve(n) // Tel het aantal getallen tussen 0 en N die veelvoud zijn van 2 of 5. count = 0 for i = 0:n if(modulo(i,2) == 0) then count = count + 1 else if (modulo(i,5) == 0) then count = count + 1 end end end r = count endfunction
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blobAnalysis.sci
function [blob] = blobAnalysis(srcImg, varargin) // Detects blob in the source image // // Calling Sequence // [blob] = blobAnalysis(srcImg) // [blob] = blobAnalysis(srcImg, Name, Value) // // Parameters // srcImg: The input image Matrix // Name: filteration method // Value: filteration method constraints, [1X2] vector // blob: stores different parameters of the blob // // Description // The function uses SimpleBlobDetector function to detect the blobs then it checks for different Name Value pair arguments and accordingly returns the parameters of the blob such as 2D coordinates of the blob, size of the blob. // // The Name-Value pair may be any of following types :- // <itemizedlist> // <listitem><para>bool filterByArea, vector [minArea maxArea]</para></listitem> // <listitem><para>bool filterByCircularity, vector [minCircularity maxCircularity]</para></listitem> // <listitem><para>bool filterByConvexity, vector [minConvexity maxConvexity]</para></listitem> // <listitem><para>bool filterByThreshold, vector [minThreshold maxThreshold]</para></listitem> // </itemizedlist> // // Examples // [srcImg] = imread('blobdetection.jpg'); // [blob] = blobAnalysis(srcImg); // [blob] = blobAnalysis(srcImg, "filterByArea", [0.01 1]); // // Authors // Deepshikha [lhs,rhs] = argn(0) // To check the number of input and output arguments if rhs<1 then error(msprintf(" Not enough input arguments")) elseif rhs>10 then error(msprintf(" Too many input arguments to the function")) elseif lhs<1 then error(msprintf(" Not enough output arguments")) elseif lhs>1 then error(msprintf(" Too many output arguments")) end srcMat = mattolist(srcImg) if modulo(rhs,2) == 0 then error(msprintf("Number of input arguments must be odd")) end select rhs case 1 then output = opencv_blobAnalysis(srcMat) case 3 then if typeof(varargin(1))<> "string" error(msprintf("argument at position 2 must be string")) end output = opencv_blobAnalysis(srcMat, varargin(1), varargin(2)) case 5 then if typeof(varargin(1))<> "string" error(msprintf("argument at position 2 must be string")) end if typeof(varargin(3))<> "string" error(msprintf("argument at position 4 must be string")) end output = opencv_blobAnalysis(srcMat, varargin(1), varargin(2), varargin(3), varargin(4)) case 7 then if typeof(varargin(1))<> "string" error(msprintf("argument at position 2 must be string")) end if typeof(varargin(3))<> "string" error(msprintf("argument at position 4 must be string")) end if typeof(varargin(5))<> "string" error(msprintf("argument at position 6 must be string")) end output = opencv_blobAnalysis(srcMat, varargin(1), varargin(2), varargin(3), varargin(4), varargin(5), varargin(6)) case 9 then if typeof(varargin(1))<> "string" error(msprintf("argument at position 2 must be string")) end if typeof(varargin(3))<> "string" error(msprintf("argument at position 4 must be string")) end if typeof(varargin(5))<> "string" error(msprintf("argument at position 6 must be string")) end if typeof(varargin(7))<> "string" error(msprintf("argument at position 8 must be string")) end output = opencv_blobAnalysis(srcMat, varargin(1), varargin(2), varargin(3), varargin(4), varargin(5), varargin(6), varargin(7), varargin(8)) end blob = struct("Points", output(1), "Size", output(2)) endfunction
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muller.sce
exec('muller.sci'); a = -1; c = 2; Toler = 0.01; IterMax = 100; [Raiz, Iter, CondErro] = Muller(a, c, Toler, IterMax); printf("\nRaiz = %f\nIter = %d\nCondErro = %d", Raiz, Iter, CondErro);
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clear; clc; //page no. 126 D = 6;//in v = 100;//fps p = 0;//psi gam = 0.08;//specific weight in lb/cuft R = 6;//in theta = 60;//degrees v_r = v*(1-(0.5*D/R)^2)*cos(theta*%pi/180); v_t = -v*(1+(0.5*D/R)^2)*sin(theta*%pi/180); V = sqrt(v_r^2 + v_t^2); p = ((v^2 /(2*32.2)) - (V^2 /(2*32.2)) - (cos(theta*%pi/180)*sin(theta*%pi/180)))*gam; printf('Velocity = %.1f fps\n Pressure = %.2f psf',V,p); //there is an error in the answer given in textbook
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// (3.6) A closed, rigid tank filled with water vapor, initially at 20 MPa, 520C, is cooled until its temperature reaches 400C. Using the compressibility chart, determine. (a) the specific volume of the water vapor in m3/kg at the initial state.(b) the pressure in MPa at the final state.Compare the results of parts (a) and (b) with the values obtained from the superheated vapor table, Table A-4. //solution //variable initialization p1 = 20 //initial pressure in MPa T1 = 520 // initial temperature in degree celcius T2 = 400 // final temperature in degree celcius //part(a) //from table A-1 Tc = 647.3 //critical temperature in kelvin pc = 22.09 //critical pressure in MPa Tr = (T1+273)/Tc //reduced temperature Pr = p1/pc //reduced pressure Z1 = .83 //compressibility factor R = 8.314 //universal gas constant in SI unit n = 1000/18.02 //number of moles in a kg of water v1 = (Z1*n*R*(T1+273))/(p1*10^6) printf('the specific volume in state1 in m3/Kg is:\n\t v1 = %f',v1) printf('\n and the corresponding value obtained from table A-4 is .01551 m^3/Kg') //part(b) vr = v1*(pc*10^6)/(n*R*Tc) Tr2 = (T2+273)/Tc //at above vr and Tr2 PR = .69 P2 = pc*PR printf('\n\n the pressure in MPa in the final state is: \n\t P2 = %f',P2) printf('\n and the corresponding value from the table is 15.16Mpa')
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Ex1_15.sce
//Example 1_15 clc(); clear; //To find the diameter of the 5th bright ring n=5 lemda=5460 //units in angstroam lemda=5460*10^-8 //units in cm u=1.50 f=400 //units in cm R=(u-1)*2*f D=sqrt(2*(2*n-1)*lemda*R) printf("The diameter of the 5th fringe %.2f mts",D)
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exec("to_string.sce",-1) exec("heat_1d_euler_exp.sce",-1) exec("heat_1d_euler_imp.sce",-1) exec("heat_1d_CN.sce",-1) // initial condition (function of x) function T = it0(x) T = sin(%pi*x) endfunction // boundary condition (function of t) function T = bx0(t) T = 0.0 endfunction function T = bxf(t) T = 0.0 endfunction function T = analytic_solution(x,t) T = sin(%pi*x)*exp(-%pi*%pi*t) endfunction function plot_to_png(u,x,t,prefix) Nt = length(t)-1 for it = 1:Nt+1 clf() plot(x,u(:,it)) set(gca(), "data_bounds", [0,1,0,1]) strt = "t = " + string(t(it)) xstring(0.8,0.9,strt) xs2png(gcf(), prefix + to_string(it) + ".png") printf("Done output solution for t = %f\n", t(it)) end endfunction a = 1 xf = 1 Nx = 25 T = 0.1 Nt = 100 // Explicit Euler [u1,x,t] = heat_1d_euler_exp( a, xf, T, it0, bx0, bxf, Nx, Nt ) plot_to_png(u1,x,t,"TEMP_exp_") // Using implicit Euler method [u2,x,t] = heat_1d_euler_imp( a, xf, T, it0, bx0, bxf, Nx, Nt ) plot_to_png(u2,x,t,"TEMP_imp_") // Using Crank-Nicholson method [u3,x,t] = heat_1d_CN( a, xf, T, it0, bx0, bxf, Nx, Nt ) plot_to_png(u3,x,t,"TEMP_CN_") NxNt = Nx*Nt u_analytic = analytic_solution(x,t) //How far from the analytical solution? err1 = norm((u1-u_analytic))/NxNt err2 = norm((u2-u_analytic))/NxNt err3 = norm((u3-u_analytic))/NxNt printf("err1 = %f\n", err1) printf("err2 = %f\n", err2) printf("err3 = %f\n", err3) if getscilabmode() ~= "STD" quit() end
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Chapter4_Example7.sce
clc clear //INPUT DATA pb=25;//Saturated vapour in bar pc=0.2;//Saturated liquid in bar T111=300;//Temperature in degree C h1=2800.9;//Enthalpy in kJ/kg hb=962;//Enthalpy in kJ/kg h5=2609.9;//Enthalpy in kJ/kg h3=251.5;//Enthalpy in kJ/kg S5=7.9094;//Entropy in kJ/kg.K S3=0.8321;//Entropy in kJ/kg.K Sb=2.5543;//Entropy in kJ/kg.K S1=6.2536;//Entropy in kJ/kg.K x1=0.8;////Quality of steam h111=3008.9;//Enthalpy in kJ/kg S111=6.644;////Entropy in kJ/kg.K //CALCULATIONS h11=(hb+x1*(h1-hb));//Enthalpy in kJ/kg S11=(Sb+x1*(S1-Sb));//Enthalpy in kJ/kg x21=((S11-S3)/(S5-S3));//quality of steam h21=(h3+(x21*(h5-h3)));//Enthalpy in kJ/kg nRi=(((h11-h21)/(h11-h3))*100);//Rankine cycle efficiency in percentage x2=((S1-S3)/(S5-S3));//quality of steam h2=h3+x2*(h5-h3);//Enthalpy in kJ/kg nRi2=(((h1-h2)/(h1-h3))*100);//Rankine cycle efficiency in percentage x211=((S111-S3)/(S5-S3));//quality of steam h211=(h3+(x211*(h5-h3)));//Enthalpy in kJ/kg nRi1=(((h111-h211)/(h111-h3))*100);//Rankine cycle efficiency in percentage //OUTPUT printf('(i) The Rankine cycle efficiency when steam is dry at turbine inlet is %3.2f percent \n(ii) The Rankine cycle efficiency when steam is saturated is %3.2f percentage \n(iii)The Rankine cycle efficiency when steam is superheated is %3.2f percent ',nRi,nRi2,nRi1)
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AMAZING_tuner.sci
function [x,y,typ] = AMAZING_tuner(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then exprs=arg1.graphics.exprs; res_x = exprs(1) res_y = exprs(2) standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1 model=arg1.model;graphics=arg1.graphics; exprs=graphics.exprs; while %t do [ok,res_x,res_y,exprs] = getvalue('Amazing touch panel tuner',.. ['X Resolution [100..4096]';.. 'Y Resolution [100..4096]:'],.. list('vec',-1,'vec',-1),exprs) if ~ok then break,end if(res_x<100 | res_x>4096) then warning('Accepted resolution values in [100..4096]. Keeping previous values.'); break; end if(res_y<100 | res_y>4096) then warning('Accepted resolution values in [100..4096]. Keeping previous values.'); break; end in=[], out = [], [model,graphics,ok]=check_io(model,graphics,in,out,1,[]) if ok then graphics.exprs=exprs; model.rpar=[]; model.ipar=[res_x; res_y]; model.dstate=[]; x.graphics=graphics;x.model=model break end end case 'define' then res_x = 240 res_y = 180 model = scicos_model() model.sim = list('amazing_tuner',4) model.in=[], model.out=[], model.evtin=1 model.rpar=[] model.ipar=[res_x;res_y] model.dstate=[1]; model.blocktype='d' model.dep_ut=[%t %f] exprs=[sci2exp(res_x);sci2exp(res_y)] gr_i=['xstringb(orig(1),orig(2),.. [''AMAZING'';.. ''tuner'' ;.. string(res_x) + ''x'' + string(res_y)],.. sz(1),sz(2),''fill'');'] x=standard_define([3 2],model,exprs,gr_i) end endfunction
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19_4.sce
//chapter 19 //example 19.4 //page 600 clear all; clc ; //given Es=0.5;//supply voltage V R1=200;//series resistance ohm VD1=-Es;//when Id=0 //when VD=0 VR1=Es; ID1=1000*VR1/R1; VD=[VD1 0]; ID=[0 ID1]; plot(VD,ID,'-.*'); xtitle('dc load line with points (-0.5,0)and (0,2.5)','VD in V','ID in mA') a=gca(); a.data_bounds=[-1,-0.5;1 3]; //from intersection of load line and illumination characteristics printf('\nApproximate values:') printf("\nAt 1500 lm/m^2,Id=-0.2 mA,Vd=-0.45 V"); printf("\nAt 10000 lm/m^2,Id=-1.9 mA,Vd=-0.12 V"); printf("\nAt 20000 lm/m^2,Id=-3.7 mA,Vd=0.22 V");
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Chapter4_Example11.sce
//Chapter-4, Illustration 11, Page 174 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA P1=10;//Pressure at point 1 in bar T1=452.9;//Temperature at point 1 in K P2=4;//Pressure at point 2 in bar n=1.3;//Adiabatic gas constant Ps=0.803;//Saturation pressure at T2 in bar Ts=143.6;//Saturation temperature at P2 in oC //CALCULATIONS x=(n-1)/n;//Ratio T2=((P2/P1)^x)*T1;//Temperature at point 2 in K Ds=P2/Ps;//Degree of supersaturation Du=Ts-(T2-273);//Degree of undercooling //OUTPUT mprintf('Degree of supersaturation is %3.2f \n Degree of undercooling %3.0f oC',Ds,Du) //==============================END OF PROGRAM=================================
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example13_12.sce
//Chapter 13 //Example 13_12 //Page 323 clear;clc; Va=440; Ic=100; Id=200; Ie=250; If=300; Vb=430; Lac=150; Lcd=150; Lde=50; Lef=100; Lfb=150; r=0.01; l=600; //resistance for 100 m length of conductor R=2*r; Rac=R*Lac/100; Rcd=R*Lcd/100; Rde=R*Lde/100; Ref=R*Lef/100; Rfb=R*Lfb/100; //considering drop across various sections of the distributor and adding them to calculate Ia Ia=(Va-Vb+(Ic*Rcd)+(Ic+Id)*Rde+(Ic+Id+Ie)*Ref+(Ic+Id+Ie+If)*Rfb)/(Rac+Rcd+Rde+Ref+Rfb); Iac=Ia; Icd=Ia-Ic; Ide=Ia-Ic-Id; Ief=Ia-Ic-Id-Ie; Ifb=Ia-Ic-Id-Ie-If; Ib=abs(Ifb); P=Iac^2*Rac+Icd^2*Rcd+Ide^2*Rde+Ief^2*Ref+Ifb^2*Rfb; printf("Resistance per 100 m of distributor = %.2f ohm \n\n", R); printf("Resistance of section AC = %.3f ohm \n", Rac); printf("Resistance of section CD = %.3f ohm \n", Rcd); printf("Resistance of section DE = %.3f ohm \n", Rde); printf("Resistance of section EF = %.3f ohm \n", Ref); printf("Resistance of section FB = %.3f ohm \n\n", Rfb); printf("Ia = %.1f A \n\n", Ia); printf("(i) Current supplied from end A = Ia = %.2f A \n", Ia); printf(" Current supplied from end B = Ib = %.2f A \n\n", Ib); printf("(ii) Power loss in the distributor = %.3f kW \n\n", P/1000);
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// Scilab Code Ex2.39:: Page-2.29 (2009) clc; clear; t = 0.75e-06; // Thickness of the glass plate, m mu = 1.5; // Refractive index of the glass plate lambda1 = 4000e-010; // First wavelength of visible range, cm lambda2 = 7000e-010; // Last wavelength of visible range, cm r = 0; // Angle of refraction for normal incidence, degrees n = zeros(2); // For bright fringe in reflected pattern, // 2*mu*t*cosd(r) = (2*n+1)*lambda/2, solving for n // For lambda1 n(1) = (4*mu*t*cosd(r)/lambda1-1)/2; // For lambda2 n(2) = (4*mu*t*cosd(r)/lambda2-1)/2; printf("\nFor n = %d and n = %d the light is strongly reflected.", n(1), ceil(n(2))); // Result // For n = 5 and n = 3 the light is strongly reflected.
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Ex17_9.sce
//Exa 17.9 // To calculate Radio link budget for uplink and downlink // Refering Table 17.1 on page no 613 clc; clear all; Rc=3.84;//Chip rate in Mcps Ri=16;//Data rate in kbps UL=0.5;//UL loading factor DL=0.9;//DL loading factor Eb_NtU=4;//in dB Eb_NtD=6;// in dB Gm=0;//Mobile antenna gain in dBi Gb=18;//Base station gain in dBi //solution disp("The Okumara-Hata model for an urban macro-cell with a base station antenna height of 25m, a mobile station height of 1.5m, and a carrier frequency of 1950MHz gives Lp =138.5+35.7*log10(R) where R is radius of hexagonal cell"); disp("From table 17.1, Lp(Allowable path loss) for uplink is 139.65 dB"); R=10^((139.65-138.5)/35.7); printf(' Cell Radius is %.3f km \n ',R); Area=round(2.6*R^2); printf('Area covered by hexagonal cell is %d km^2 \n ',Area); printf('Number of BTSs required to cover an area of 2400 Km^2 are %d \n ',2400/Area);
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clear clc E=100 Zc=400 L=4000 mprintf("et= %d exp( - %.1f t) KV\n", 2*E, Zc/L) mprintf("er= %d (2*exp( - %.1f t) -1) KV\n", E, Zc/L)
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difencasDiv.sce
function dd=newtondd(x,y) disp("") disp ("Output for the divided diferences") disp("") for i=1:length(x) dd(i,1)=y(i); endfor for i=2:length(x) for j=2:i dd(i,j)=(dd(i,j-1)-dd(i-1,j-1))/(x(i)-x(i-j+1)); endfor endfor dd=[x' dd]; endfunction
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Ex6_4.sce
// Chapter 6 example 4 //------------------------------------------------------------------------------ clc; clear; // Given data L = 10^-6; // gate length Vs = 10^5; // saturation velocity in m/s // calculations fT = Vs/(2*%pi*L); // cut-off freq. // Output mprintf('Unity gain cut-off frequency = %3.0f Ghz',fT/10^9); //------------------------------------------------------------------------------
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clc p1=5.5*10^5; //Pa x1=1; p2=0.75*10^5; //Pa v1=0.3427; //m^3/kg v2=p1*v1/p2; // Since v2 > vg (at 0.75 bar), therefore, the steam is superheated at state 2. u2=2567.25; //kJ/kg u1=2565; //kJ/kg du=u2-u1; //kJ/kg C=p1*v1; disp("Work done = ") W=integrate('C/v', 'v', v1,v2) disp("N-m/kg") disp("Heat supplied = ") Q=du+W/10^3; disp(Q) disp("kJ/kg")
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ramp expo.sce
//Implementation of Ramp & Exponential Signals clc clear all t = 0:1:50; for n = 0:50; x(n+1) = n; end subplot(3,2,1) plot(t,x) xtitle('Ramp Continuous','Time','Amplitude') subplot(3,2,2) plot2d3(t,x) xtitle('Ramp Discrete','Time','Amplitude') x = [0:0.1:2*%pi]; e = exp(x); subplot(3,2,3) plot(x,e) xtitle('exp(x) Continuous','Time','Amplitude') subplot(3,2,4) plot2d3(x,e) xtitle('exp(x) Discrete','Time','Amplitude') e = exp(-x); subplot(3,2,5) plot(x,e) xtitle('exp(-x) Continuous','Time','Amplitude') subplot(3,2,6) plot2d3(x,e) xtitle('exp(-x) Discrete','Time','Amplitude')
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Ex5_3_4.sce
//Fiber Optics Communication Technology, by Djafer K. Mynbaev and Lovell L.scheiner //Windows 8 //Scilab version- 6.0.0 //Example 5.3.4 clc; clear; //given Dpmd=0.5;//polarization mode dispersion coefficient in ps/sqrt(km) L=100;//fiber length in km deltatpmd=Dpmd*sqrt(L);//Pulse spreading due to PMD in ps mprintf("Pulse spread caused by PMD for single mode fiber= %.0f ps",deltatpmd);
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Ex2_1.sce
//Chapter 2: Spectroscopy and Photochemistry //Problem: 1 clc; //Declaration of Constants m_br79 = 78.9183 // Mass of 79Br,in amu m_br81 = 80.9163 // Mass of 91Br,in amu Na = 6.022 * 10 ** 23 // Mole constant,per mol pi = 3.141 // Pi c = 3 * 10 ** 10 // Speed of light,in cm/s //Declaration of Variable wave_no = 323.2 // Wave no. of fund. vibration of 79Br - 81Br, /cm // Solution mu = (m_br79 * m_br81) / ((m_br79 + m_br81) * Na) k = 4 * (pi * c * wave_no) ** 2 * mu * 10 ** -3 mprintf("The force constant of the bond is %.2e N/m\n",k)
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P10_Determination_of_axial_thrust_and_pressure_intensity.sce
clc //Example 14.10 //Determination of axial thrust and pressure intensity //------------------------------------------------------------------------------ //Given Data: //Power to be transmitted P=10000 //Watt //Speed N=1000 //rpm //Outer and Inner diameters Do=0.15 //m Di=0.1 //m Ro=0.15/2 //m Ri=0.1/2 //m // number of surfaces n=6 //coefficient of friction f=0.3 //------------------------------------------------------------------------------ // Using uniform wear theory // Mean radius Rm=(Ro+Ri)/2 // Torque(T)=power/angular velocity T=(P*60)/(2*%pi*N) // T=F*f*Rm*n // Axial thrust F F=T/(f*Rm*n) //contact pressure at radius r: //p=F/(2*%pi*(Ro-Ri)*r) //maximum contact pressure(pmax) is at inner radius pmax=F/(2*%pi*(Ro-Ri)*Ri) //minimum contact pressure(pmin) is at outer radius pmin=F/(2*%pi*(Ro-Ri)*Ro) // average contact pressure pavg=F/(2*%pi*(Ro-Ri)*Rm) //------------------------------------------------------------------------------ //Printing result file to .txt res10=mopen(TMPDIR+'10_determination_of_axial_thrust_and_pressure_intensity.txt','wt') mfprintf(res10,"(a)Axial thrust required to transmit the power is %0.2f N\n",F) mfprintf(res10,"(b)The pressure equation is:\n\tp=F/(2*pi*(Ro-Ri)*r)\n\n") mfprintf(res10,"(c)\tMaximum contact pressure occurs at inner radius, and is equal to %0.3f MPa\n",pmax*(10^-6)) mfprintf(res10," \tMinimum contact pressure occurs at outer radius, and is equal to %0.3f MPa\n",pmin*(10^-6)) mfprintf(res10," \tAverage contact pressure is %0.3f MPa\n",pavg*(10^-6)) mclose(res10) if (isdef('editor') | (funptr('editor')<>0)) then editor(TMPDIR+'10_determination_of_axial_thrust_and_pressure_intensity.txt') end //------------------------------------------------------------------------------ //---------------------------------End of program-------------------------------
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4_7.sce
clc,clear printf('Example 4.7\n\n') Ns=250 //Synchronous speed in rpm f=50 Slots=288 E_line=6600 Pole=120*f/Ns n=Slots/Pole //slots per pole m=n/3 //slots per pole per phase beeta=180/n //slot angle conductors_per_slot=32 //16 conductors per coil-side *2 coil-sides per slot K_d=sind(m*beeta/2) /(m*sind(beeta/2)) //distribution factor alpha=2*beeta// angle of short pitch K_c=cosd(alpha/2) //coil span factor Z = Slots*conductors_per_slot //total conductors Z_ph=Z/3 //Conductors per phase T_ph=Z_ph/2 //turns per phase E_ph=E_line/sqrt(3) phi=E_ph/(4.44*K_c*K_d*f*T_ph) //Because E_ph=4.44 *K_c *K_d *phi *f *T_ph printf('Flux per pole is %.0f mWb ',phi*1000)
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Ch08Ex2.sce
// Scilab Code Ex8.2: Page-430 (2011) clc;clear; d = 2e-003;....// Thickness of the piece of quarts crystal, m rho = 2650;....// Density of the crystal, kg/meter-cube Y = 7.9e+010;....// Value of Youngs Modulus, N/metre-square n = 1/(2*d)*sqrt(Y/rho); //The frequency of the fundamental mode of vibration, Hz printf("\nThe frequency of the fundamental mode of vibration in quatrz crystal = %5.3f Hz", n/1e+006); // Result // The frequency of the fundamental mode of vibration in quatrz crystal = 1.365 Hz
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alonõ alotsõhe N;IN+ALL;SG silm .silmä N;IN+ALL;SG täi .täihe N;IN+ALL;SG herneh herneh N;NOM;SG tarõ tarri N;PRT;PL kerge kerget N;PRT;SG vari .varjo N;IN+ALL;SG tükk tükke N;IN+ALL;PL kuu kuu N;NOM;SG talo tallõ N;GEN;PL täüs' täüt N;PRT;SG kannõl' kandlidõ N;GEN;PL kogõr kogrõ N;GEN;SG tarõ tarõ N;GEN;SG tükk tükkü N;IN+ALL;SG aig ao N;GEN;SG silm silmä N;GEN;SG ehitüs ehitüisi N;PRT;PL sõda sõto N;PRT;PL rits'kas rits'kilõ N;ALL;PL kubõl kubla N;GEN;SG väits .väitsi N;PRT;PL kanarik kanarikkõ N;GEN;PL aig .aigõ N;GEN;PL üü: öid N;PRT;PL tükk tükke N;PRT;PL jalg .jalga N;PRT;SG kerge kergile N;ALL;PL laiõh laiõh N;NOM;SG kana kana N;NOM;SG pini pinne N;PRT;PL alomanõ alomast N;PRT;SG alomanõ alomastõ N;IN+ALL;SG kotus kotus N;NOM;SG tarõ tarilõ N;ALL;PL asõq asõmõhe N;IN+ALL;SG pini pini N;GEN;SG kommõq kombihe N;IN+ALL;PL kask kask N;NOM;SG pini pinne N;IN+ALL;PL vari var'o N;GEN;SG kannõl' kandlõhe N;IN+ALL;SG kuu:l' kuu:l' N;NOM;SG kannõl' kandlilõ N;ALL;PL kuld kuld N;NOM;SG tarõ tarrõ N;PRT;SG üü: .öihe N;IN+ALL;PL asi .asja N;PRT;SG kask .kaskihe N;IN+ALL;PL hõrak hõrakat N;PRT;SG kerge kergit N;PRT;PL herneh hernihe N;IN+ALL;PL kuu:l' kuu:li N;IN+ALL;SG nagõl naglolõ N;ALL;PL võrokõnõ võrokõisihe N;IN+ALL;PL igä ikile N;ALL;PL kuldnõ kuldsõ N;GEN;SG kii:l' kii:li N;IN+ALL;PL üü: üü:he N;IN+ALL;SG ehitüs ehitüst N;PRT;SG kii:l' keelile N;ALL;PL hammas hammas N;NOM;SG .suhvli .suhvli N;NOM;SG puhm puhmõ N;GEN;PL kanarik kanarikkõ N;IN+ALL;PL läteq lättit N;PRT;PL särg' .särgi N;IN+ALL;PL .suhvli .suhvlihe N;IN+ALL;PL igä ikki N;IN+ALL;PL kanarik kanarigu N;GEN;SG tervüs tervüid N;PRT;PL käsi käsi N;NOM;SG tütär' tütrit N;PRT;PL kask .kaskat N;PRT;SG nagõl nagla N;GEN;SG sõda sõda N;NOM;SG laiõh laidõhe N;IN+ALL;SG elläi eläjä N;GEN;SG tütär' tütrihe N;IN+ALL;PL jalg .jalgo N;IN+ALL;PL nagõl nagõl N;NOM;SG kand .kandõ N;IN+ALL;PL makõ makõ N;NOM;SG nagõl .naklo N;GEN;PL kii:l' kii:l' N;NOM;SG kuu .kuihõ N;IN+ALL;PL kogõr .kokrõ N;IN+ALL;SG tervüs tervüide N;GEN;PL hain haina N;IN+ALL;SG tükk tükü N;GEN;SG repän' rebäside N;GEN;PL tarõ tarri N;GEN;PL kogõr kogrilõ N;ALL;PL kana kanno N;PRT;PL kannõl' kannõl' N;NOM;SG makõ makõ N;GEN;SG väits .väitsi N;GEN;PL herneh hernit N;PRT;PL igä ikkä N;IN+ALL;SG kotus kotussõhe N;IN+ALL;SG laiõh laidihe N;IN+ALL;PL kanarik kanarikku N;IN+ALL;SG vari vari N;NOM;SG
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Ex18_1.sce
clc clear //Initalization of variables q=200 //cfm p2=90 //psia p1=14.5 //psia n=1.36 //calculations hpp=n/(n-1) *144*p1*q/33000 *(1- (p2/p1))^((n-1)/n) //results printf("Theoretical horse power required = %.1f hp",hpp) disp("The answer given in textbook is wrong. Please verify with a calculator")
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ex2_12.sce
clc; v=50; //velocity in m/sec s=500; //distance in m disp((v*v)/(2*s),"Acc. in m/sec square = "); //displaying result
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EX9_56.sce
//example 9-56 pg no-636 Z1=8.05+%i*2.156; //IMPEDANCE XL=2.155; W=5000; L=XL/W; disp('i)INDUCTANCE (L) = '+string (L)+' H') Z2=4.166-%i*7.216; //IMPEDANCE Xc=7.216; C=1/[W*Xc]; disp('ii)CAPACITOR (C) = '+string (C)+' F') D=11.708; //DIAMETER XL1=12.81; L1=XL1/W; disp('i) INDUCTANCE (L1) = '+string (L1)+' H')
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Helmholtz2D_CG_P7_PreconDiagonal.tst
<?xml version="1.0" encoding="utf-8" ?> <test> <description>Helmholtz 2D CG with P=7 and block preconditioner</description> <executable>Helmholtz2D</executable> <parameters>-v -I Preconditioner=Diagonal Helmholtz2D_P7_Periodic.xml</parameters> <files> <file description="Session File">Helmholtz2D_P7_Periodic.xml</file> </files> <metrics> <metric type="L2" id="1"> <value tolerance="1e-8">6.82374e-07</value> </metric> <metric type="Linf" id="2"> <value tolerance="1e-8">9.43919e-07</value> </metric> <metric type="Precon" id="3"> <value tolerance="2">17</value> </metric> </metrics> </test>
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ex_14_4.sce
clc //solution //given //ref fig 14.1 W=50*10^3//N L=100//mm x=1.4//m fb=100//N/mm^2 M=W*L//N-mm //let d eb dia //M=(%pi/32)*fb*d^3 d=(M/9.82)^(1/3)//mm printf("the dia of axle is,%f mm\n",d)
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Example15_2.sce
clear ; clc; // Example 15.2 printf('Example 15.2\n\n'); //Page No. 465 // Solution // Given R = 10.73 ;// gas constant-[(cubic feet *psia)/(lb mol *R)] a = 3.49 * 10^4 ;//(psia) *(cubic feet/lb mol)^2 b = 1.45 ;// (cubic feet)/(lb mol) p = 679.7 ;// Pressure -[ psia] n = 1.136 ;// Amount of mole -[lb mol] T = 683 ;// Temperature - [degree R] // Get V using Van der Waal's eqn. deff('[y]=g(V)','y=(V^3) -(((p*n*b) + (n*R*T))/p)*V^2 + ((n^2)*a*V/p) - ((n^3)*a*b)/p'); V=fsolve(b,g) ;// Volume of final solution (volume of vessel) [cubic feet] printf('\nVolume of final solution (volume of vessel) is %.0f cubic feet.',V);
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clc W_12=-82; //kJ Q_12=-45; //kJ dU_12=Q_12 - W_12; W_21=100; //kJ dU_21=-dU_12; Q_21=dU_21 + W_21; disp("Heat added to the system = ") disp(Q_21) disp("kJ")
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1.dir --> To view the contents of a directory, type dir. this command will list all the files and directories within the current directory. It is analogous to clicking on a windows folder to see whats inside. c:\ dir volume in drive C has no label. volume Serial Number is C8C7-BDCD Directory of C:\ 01/30/2019 10:36 AM 0 AUTOEXEC.BAT 03/15/2019 10:40 AM 0 CONFIG.SYS 04/21/2019 10:50 AM 216 HelloWorld.java 07/03/2019 11:00 AM DIR Documents and settings 05/05/2019 11:14 AM DIR introcs 03/09/2019 11:18 AM DIR j2sdk1.4.2_06 04/10/2019 12:17 AM DIR Program files o1/13/2019 01:18 AM DIR windows 3 Files(s) 126 bytes 5 Dir(s) 32,551,940,096 bytes free There are 7 item in this directory. Some of them are files, like HelloWorld.java. Others are directories, like introcs. 2.cd -->It is used to know the currently working directory. In order to find out, type cd at the command prompt. C:\> cd C:\ To change directories, use the cd command with name of a directory. C:\> cd introcs Then the command prompt will be: C:\introcs> 3.mkdir --> to create a new directory.The following command creates a directory named hello, which can be used to store all of your files associated with Hello World assignmen. C:\introcs> mkdir hello To see how it works, use the dir command 4.move --> We can move the two files Helloworld.java and redme.txt into hello directory using the move command. C:\introcs> move HelloWorld.java hello C:\introcs> move redme.txt hello C:\introcs> dir volume in drive C has no label. volume Serial Number is C8C7-BDCD Dirctory of C:\introcs 02/10/2019 08:59 AM DIR . 02/10/2019 08:59 AM DIR .. 02/03/2019 11:53 AM 126 HelloWorld.java 01/17/2019 01:16 AM 256 readme.txt 2 files(s) 382 bytes 2 Dir(s) move also used to rename a file. Simply specify a new filename instead of adrectory name. 5.copy --> To make a copy of a files. This especially useful when you modify a working program, but might want to revert back to the original version if your modifications dont succeed. C:\introcs\hello> copy HelloWorld.java HelloWorld.back To check type dir C:\inrtrocs\hello> dir 6.del --> To clean up useless files. C:\introcs\hello> del HelloWorld.back To check type dir C:\introcs\hello> dir 7.wildcards --> used for applying copy, del, and move commands to several files at once. To create a new directory called loops, and copy all of the files in the hello directory. C:\introcs> mkdir loops C:\introcs> copy c:\introcs\hello\* loops Here the * mates all files in the C:\introcs\hello directory. It copies them to your newly created loops directory.
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//example4.49 //calculate fi index and time of rainfall excess clc;funcprot(0); //given T=[1:1:12]; //time from start r=[1.8 2.6 7.8 3.9 10.6 5.4 7.8 9.2 6.5 4.4 1.8 1.6]; //increamental rainfall R=24.4; //total run-off s=0; for i=1:12 s=s+r(i); end ti=s-R; //first trial tr=7; //assumed ti=s-R-r(1)-r(2)-r(4)-r(11)-r(12); fi=ti/tr; for i=1:12 P(i)=r(i)-fi; if (P(i)<0) then P(i)=0; end end mprintf("Time(h) rainfall excess."); for i=1:12 mprintf("\n%f %f",T(i),P(i)); end mprintf("\n\nfi index=%f cm/hr.",fi);
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//Example_a_7_11 page no:278 clc; Zab=((%i*3)*(%i*-2))/((%i*3)-(%i*2)); In=((10/3*%i)+(5*%i/-2*%i)); Il=-(In*Zab)/(5-6*%i); Ilmag=sqrt(real(Il)^2+imag(Il)^2); Ilang=atand(imag(Il)/real(Il)); Ilang=Ilang-180;//converting the angle to negative hence value does not change disp(Ilmag,"the magnitude of load current is (in A)"); disp(Ilang,"the angle of load current is (in degree)");