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Ex1_6.sce
clc //initialization of new variables clear E=2.34*10^9 //N/m^2 Modulus of Elasticity d=1 //km depth rho=1000 //kg/m^3 density g=9.8 //m/s^2 Acceleration due to gravity //calculations d=d*1000 dp=rho*g*d dVV=dp/E //result printf('The change in pressure is %.2e N/m^2 ',dp) printf('\n Change in volume is %.3e ',dVV)
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result1s0.tst
@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute F6 real[-1.537,1.403] @attribute F7 real[-1.293,2.039] @attribute F8 real[-1.613,1.309] @attribute F9 real[-1.68,1.396] @attribute Class{0,1,2,3,4,5,6,7,8,9,10} @inputs TT,SpeakerNumber,Sex,F0,F1,F2,F3,F4,F5,F6,F7,F8,F9 @outputs Class @data 6 7 0 0 4 3 4 6 8 7 1 1 4 6 9 7 7 7 0 0 2 1 3 3 7 7 5 3 6 3 9 6 3 3 9 6 4 3 7 6 8 6 9 9 8 6 0 0 1 1 6 4 5 4 6 4 7 7 4 4 0 0 1 1 9 9 2 1 5 3 9 9 6 6 8 1 2 3 1 1 4 3 0 9 3 10 5 4 2 2 5 4 3 4 2 0 7 7 3 3 10 6 10 5 0 0 2 1 9 9 4 6 5 3 1 0 10 10 3 3 1 0 7 7 10 2 1 0 5 4 0 0 3 3 3 3 6 7 8 7 2 3 5 3 1 1 3 3 0 0 7 7 8 7 9 9 10 6 4 4 5 3 6 6 9 9 1 1 2 3 4 4 6 6 8 1 0 0 2 0 8 1 7 7 10 6 7 7 10 1 8 1 10 1 6 6 10 10
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4_6exam.sce
//Engineering and Chemical Thermodynamics //Example 4.6 //Page no :190 clear ; clc ; //Given Pc_B = 49.1 ; // [bar] , From table Pc_T = 42.0 ; // [bar] , From table Pc_C = 40.4 ; // [bar] , From table Tc_B = 562 ; // [K] , From table Tc_T = 594 ; // [K] , From table Tc_C = 553 ; // [K] , From table R = 8.314 ; A = [Pc_B , Tc_B ; Pc_T , Tc_T ; Pc_C , Tc_C]; for i=1:3 A(i,3) = 27/64 * (R * A(i,2))^2 /( A(i,1) * 10^5) ; A(i,4) = R * A(i,2) / (8 * A(i,1) * 10^5) ; end disp(" Example: 4.6 Page no : 190") ; disp(" P_c T_c a b ") ; disp(A) ; disp(" The attractive interactions of all three compounds are dominated by dispersion interactions ( parameter a) , while size affects parameter b .")
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cbrtf.tst
; cbrtf.tst ; ; Copyright (c) 2009-2023, Arm Limited. ; SPDX-License-Identifier: MIT OR Apache-2.0 WITH LLVM-exception func=cbrtf op1=7f800000 result=7f800000 errno=0 func=cbrtf op1=ff800000 result=ff800000 errno=0 func=cbrtf op1=7f800001 result=7fc00001 errno=0 status=i func=cbrtf op1=7fc00001 result=7fc00001 errno=0 func=cbrtf op1=00000000 result=00000000 errno=0 func=cbrtf op1=00000001 result=26a14517.cc7 errno=0 func=cbrtf op1=00000002 result=26cb2ff5.29f errno=0 func=cbrtf op1=00000003 result=26e89768.579 errno=0 func=cbrtf op1=00000004 result=27000000.000 errno=0 func=cbrtf op1=00400000 result=2a4b2ff5.29f errno=0 func=cbrtf op1=00800000 result=2a800000.000 errno=0 func=cbrtf op1=3f800000 result=3f800000.000 errno=0 func=cbrtf op1=40000000 result=3fa14517.cc7 errno=0 func=cbrtf op1=7f7fffff result=54cb2ff4.e63 errno=0 func=cbrtf op1=80000000 result=80000000 errno=0 func=cbrtf op1=80000001 result=a6a14517.cc7 errno=0 func=cbrtf op1=80000002 result=a6cb2ff5.29f errno=0 func=cbrtf op1=80000003 result=a6e89768.579 errno=0 func=cbrtf op1=80000004 result=a7000000.000 errno=0 func=cbrtf op1=80400000 result=aa4b2ff5.29f errno=0 func=cbrtf op1=80800000 result=aa800000.000 errno=0 func=cbrtf op1=bf800000 result=bf800000.000 errno=0 func=cbrtf op1=c0000000 result=bfa14517.cc7 errno=0 func=cbrtf op1=ff7fffff result=d4cb2ff4.e63 errno=0
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4_2.sce
pathname=get_absolute_file_path('4_2.sce') filename=pathname+filesep()+'4_2data.sci' exec(filename) M=(W*a*(L-a))/(L); deff("[y]=f(x)","y=(W*x*(L-x))/(L)")//manding moment x=[0:0.05:L]; fplot2d(x,f); xgrid(3); datatipToggle(); xtitle( 'Banding Moment versus a', ' -a- ', '-M-'); printf("\nMB: %f N.m",M); printf("\n\nclick on the point to view its coordinate on the plot");
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Ex12_2.sce
clc// // // //Variable declaration a1=4*10^-3; //diameter(m) a2=6*10^-3; //diameter(m) d1=1; //distance(m) d2=2; //distance(m) //Calculation theta=(a2-a1)/(2*(d2-d1)); //divergence(radian) //Result printf("\n divergence is %0.3f milli radian",theta*10^3)
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Ex6_25.sce
clear // // // //Variable declaration dlamda=10^-4*10^-10; //width(m) lamda=6000*10^-10; //wavelength(m) c=3*10^8; //velocity of light(m/sec) //Calculations delta_t=lamda^2/(2*%pi*c*dlamda); //time required(second) //Result printf("\n time required is %0.1f *10^-8 second",delta_t*10^8)
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/**this is test file for unsigned multiplier**/ load WTM8bu.hdl; output-file WTM8bu.out, compare-to WTM8bu.cmp, output-list x%B1.8.1 x%D1.3.1 y%B1.8.1 y%D1.3.1 z%B1.8.1 z%D1.3.1 isoverflow%B5.1.4; set x 11, set y 12, eval, output; set x 13, set y 15, eval, output; set x 255, set y 1, eval, output; set x 29, set y 13, eval, output;
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mandar15/NLP_Project
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2013-07-31T06:53:59
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bow.10_11.tst
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sce
Ex3_26.sce
clear //Given E=200 a=0.05 e=8.854*10**-12 d=3.14 //Calculation // b=E*%pi*a**2 c=2*b q=e*d //Result printf("\n (a) Net outward flux through each flat face is %0.2f Nm**2C-1",b) printf("\n (b) Flux through the side of cylinder is zero ") printf("\n (c) Net outward flux through the cylinder is %0.2f Nm**2C-1",c) printf("\n (d) The net charge in the cylinder is %0.2f *10**-11 C",q*10**11)
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Ex7_15.sce
//Tested on Windows 7 Ultimate 32-bit //Chapter 7 Field Effect Transistors Pg no. 251 and 252 clear; clc; //Given Data IDSS=20D-3;//drain saturation current in amperes VGS0=6;//gate to source cutoff voltage in volts VGS_1=3;//gate to source voltage in volts VGS_2=-3;//gate to source voltage in volts //Solution ID_1=IDSS*(1-VGS_1/VGS0)^2;//drain current for VGS_1 in amperes ID_2=IDSS*(1-VGS_2/VGS0)^2;//drain current for VGS_2 in amperes printf("For VGS = %d Volts\nID = %d mA\n\n",VGS_1,ID_1*10^3); printf("For VGS = %d Volts\nID = %d mA\n\n",VGS_2,ID_2*10^3); if VGS0>0 then printf("Since VGS0 is positive,this is an p-channel MOSFET"); else printf("Since VGS0 is negative,this is an n-channel MOSFET"); end
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.481961D+00 2 -0.661839D-02 0.401459D-02 3 -0.120540D+00 0.270829D-02 0.278793D+00 4 0.286056D-02 -0.841578D-03 -0.574509D-02 0.205267D-02 5 -0.183339D-02 0.141124D-03 -0.220836D-02 0.101952D-03 0.250070D-02 6 -0.987698D-03 0.184983D-03 -0.402884D-03 0.191343D-04 0.499493D-04 7 -0.784762D-03 0.826299D-04 0.153415D-02 -0.813791D-04 -0.343142D-03 8 -0.202932D-02 -0.758575D-04 0.193820D-02 -0.201118D-04 0.752357D-04 9 -0.337875D+00 0.484833D-02 0.589072D+00 -0.112100D-02 0.115763D+00 10 0.130321D+00 0.414651D-02 -0.159069D+00 0.125808D-01 0.134317D+00 11 0.770782D-01 0.296084D-01 -0.315855D-01 0.281132D-02 -0.128089D-01 12 0.795875D+00 -0.261044D-01 -0.641027D+00 0.252636D-01 0.258136D-01 13 -0.134966D+00 0.134877D-01 0.320519D-01 -0.515446D-02 -0.926860D-02 14 0.159255D+00 -0.563569D-02 -0.309612D+00 0.141927D-01 -0.560055D-02 15 0.942002D+00 -0.319473D-02 0.625992D-01 0.827627D-02 -0.214412D+00 16 0.444264D-01 0.610589D-02 0.101855D-01 -0.160697D-02 -0.316007D-02 17 0.314579D-02 0.109338D-02 -0.319157D-02 -0.218237D-03 0.334766D-03 18 -0.297923D+00 -0.105736D-01 0.115268D+01 -0.383650D-01 -0.287647D-01 19 -0.116560D+00 -0.333532D-02 -0.152934D-01 0.202728D-02 -0.816210D-02 20 0.112062D+01 -0.375681D-01 -0.262711D+01 0.681458D-01 0.240535D-01 21 0.106597D+00 0.250617D-02 0.821917D-02 0.379615D-02 0.529678D-02 22 0.116312D-02 -0.262286D-03 -0.142883D-02 0.371261D-03 0.407090D-03 23 -0.222141D-03 0.226764D-02 0.411477D-01 -0.831276D-02 -0.101448D-02 24 -0.231865D-02 0.367450D-03 0.162716D-02 0.624851D-04 -0.572198D-04 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 0.168714D-02 7 0.593391D-03 0.136496D-02 8 -0.426588D-03 0.737512D-04 0.276715D-02 9 0.282543D-01 0.516571D-02 0.200255D-01 0.154846D+03 10 0.131342D-03 -0.215097D-01 0.104535D-01 0.820460D+01 0.307203D+02 11 0.493288D-01 0.394894D-01 -0.184331D-01 -0.141212D+02 -0.431836D+00 12 -0.532195D-01 -0.168782D-01 -0.155108D-01 0.172969D+02 0.332510D+01 13 0.624040D-01 0.671362D-01 -0.213202D-01 -0.497024D+00 -0.326885D+01 14 -0.245519D-01 -0.709797D-02 0.103359D+00 0.443742D+01 0.187482D+01 15 0.377530D-01 0.317286D-01 -0.428631D-01 -0.246128D+02 -0.293461D+02 16 -0.462347D-03 0.612541D-03 0.424598D-03 0.224740D+01 -0.546368D+00 17 -0.236461D-03 -0.134985D-03 0.149285D-03 -0.371919D+00 0.636069D-01 18 -0.108082D+00 -0.333262D-01 0.106682D+00 0.388410D+01 0.106122D+01 19 -0.178515D-01 0.149014D-01 0.108133D-01 0.104192D+01 -0.626970D+00 20 0.557352D-01 -0.351124D-01 -0.218586D+00 -0.320172D+01 0.408805D+01 21 0.133572D-01 -0.139170D-01 -0.883224D-02 -0.165831D+01 0.188997D+00 22 0.347542D-03 -0.326398D-03 -0.408812D-03 0.250107D-01 0.511801D-01 23 -0.906657D-03 0.130683D-02 -0.479370D-02 0.729843D+00 -0.193400D+00 24 0.129819D-03 0.980670D-04 0.809956D-03 -0.106730D+00 -0.883557D-02 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 0.508286D+02 12 -0.676646D+01 0.121904D+03 13 0.165178D+01 -0.145923D+01 0.130921D+02 14 -0.141993D+01 0.200511D+01 -0.294640D+01 0.264868D+02 15 -0.141855D+01 -0.486356D+01 0.595959D+00 -0.653500D+01 0.596057D+03 16 -0.396251D+00 0.553771D+00 0.832882D-01 -0.135397D+00 0.546471D+01 17 0.754605D-01 -0.971101D-01 -0.485283D-02 0.486590D-01 -0.289588D+01 18 -0.341575D+01 -0.298847D+01 -0.559416D+01 0.531215D+01 -0.141635D+03 19 0.118086D+01 -0.242345D+01 0.918508D+00 0.188241D+01 -0.321887D+01 20 0.182344D+01 -0.156218D+02 0.237501D+01 -0.146870D+02 0.587768D+02 21 -0.436766D-01 0.190672D+01 -0.103152D+01 -0.162405D+01 0.342151D+01 22 -0.118905D+00 0.340973D-01 -0.631542D-02 -0.316251D-01 0.628547D+00 23 -0.194778D+00 0.890300D+00 0.222051D+00 -0.343406D+00 -0.468265D+00 24 0.367052D-01 -0.124997D+00 -0.119644D-01 0.641204D-01 -0.247970D+00 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 0.775297D+00 17 -0.682595D-01 0.289890D-01 18 -0.517251D+00 0.730280D+00 0.238057D+03 19 -0.815852D-01 0.197711D-01 0.399451D+01 0.548813D+01 20 -0.494711D+00 -0.294381D+00 -0.118225D+03 -0.173690D+01 0.241224D+03 21 -0.279058D+00 0.705721D-02 -0.201590D+01 -0.464181D+01 0.171196D+01 22 0.138466D-01 -0.731629D-02 -0.110240D+01 -0.627944D-01 0.499978D+00 23 0.120589D+00 -0.663208D-02 0.263917D+00 -0.592751D-01 0.823187D+00 24 -0.495102D-02 0.433905D-02 0.428162D+00 0.130365D-01 -0.912550D+00 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 0.554577D+01 22 -0.760020D-02 0.136903D-01 23 -0.311730D+00 0.914330D-02 0.566857D+00 24 0.801131D-02 -0.538737D-02 -0.533014D-01 0.120915D-01 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 1.000 2 -0.150 1.000 3 -0.329 0.081 1.000 4 0.091 -0.293 -0.240 1.000 5 -0.053 0.045 -0.084 0.045 1.000 6 -0.035 0.071 -0.019 0.010 0.024 7 -0.031 0.035 0.079 -0.049 -0.186 8 -0.056 -0.023 0.070 -0.008 0.029 9 -0.039 0.006 0.090 -0.002 0.186 10 0.034 0.012 -0.054 0.050 0.485 11 0.016 0.066 -0.008 0.009 -0.036 12 0.104 -0.037 -0.110 0.051 0.047 13 -0.054 0.059 0.017 -0.031 -0.051 14 0.045 -0.017 -0.114 0.061 -0.022 15 0.056 -0.002 0.005 0.007 -0.176 16 0.073 0.109 0.022 -0.040 -0.072 17 0.027 0.101 -0.036 -0.028 0.039 18 -0.028 -0.011 0.141 -0.055 -0.037 19 -0.072 -0.022 -0.012 0.019 -0.070 20 0.104 -0.038 -0.320 0.097 0.031 21 0.065 0.017 0.007 0.036 0.045 22 0.014 -0.035 -0.023 0.070 0.070 23 0.000 0.048 0.104 -0.244 -0.027 24 -0.030 0.053 0.028 0.013 -0.010 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 1.000 7 0.391 1.000 8 -0.197 0.038 1.000 9 0.055 0.011 0.031 1.000 10 0.001 -0.105 0.036 0.119 1.000 11 0.168 0.150 -0.049 -0.159 -0.011 12 -0.117 -0.041 -0.027 0.126 0.054 13 0.420 0.502 -0.112 -0.011 -0.163 14 -0.116 -0.037 0.382 0.069 0.066 15 0.038 0.035 -0.033 -0.081 -0.217 16 -0.013 0.019 0.009 0.205 -0.112 17 -0.034 -0.021 0.017 -0.176 0.067 18 -0.171 -0.058 0.131 0.020 0.012 19 -0.186 0.172 0.088 0.036 -0.048 20 0.087 -0.061 -0.268 -0.017 0.047 21 0.138 -0.160 -0.071 -0.057 0.014 22 0.072 -0.076 -0.066 0.017 0.079 23 -0.029 0.047 -0.121 0.078 -0.046 24 0.029 0.024 0.140 -0.078 -0.014 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 1.000 12 -0.086 1.000 13 0.064 -0.037 1.000 14 -0.039 0.035 -0.158 1.000 15 -0.008 -0.018 0.007 -0.052 1.000 16 -0.063 0.057 0.026 -0.030 0.254 17 0.062 -0.052 -0.008 0.056 -0.697 18 -0.031 -0.018 -0.100 0.067 -0.376 19 0.071 -0.094 0.108 0.156 -0.056 20 0.016 -0.091 0.042 -0.184 0.155 21 -0.003 0.073 -0.121 -0.134 0.060 22 -0.143 0.026 -0.015 -0.053 0.220 23 -0.036 0.107 0.082 -0.089 -0.025 24 0.047 -0.103 -0.030 0.113 -0.092 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 1.000 17 -0.455 1.000 18 -0.038 0.278 1.000 19 -0.040 0.050 0.111 1.000 20 -0.036 -0.111 -0.493 -0.048 1.000 21 -0.135 0.018 -0.055 -0.841 0.047 22 0.134 -0.367 -0.611 -0.229 0.275 23 0.182 -0.052 0.023 -0.034 0.070 24 -0.051 0.232 0.252 0.051 -0.534 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 1.000 22 -0.028 1.000 23 -0.176 0.104 1.000 24 0.031 -0.419 -0.644 1.000
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L=0.015; //INDUCTANCE C=0.5*10^-6; //CAPACITOR Z=200; Fc=1/(4*%pi*(L*C)^0.5); Z0=(L/C)^0.5; Z2=(%i*2)*%pi*Z*L; Z1=1/(%i*2*%pi*Z*C); F1=2000; Z01=[(Z1*Z2)/(1+(Z1/(4*Z2)))]^0.5; A=8.147; disp('ii) Impedance (ZO) is = '+string ([Z0]) +' W '); disp('ii) FREQUENCY is = '+string ([Fc]) +' HZ '); disp('ii) Impedance(Z1) is = '+string ([Z1]) +' W '); disp('ii) Impedance(Z2) is = '+string ([Z2]) +' W '); disp('ii) Impedance(Z01) is = '+string ([Z01]) +' W '); disp('ii) ALPHA is = '+string ([A]) +' ');
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exec("degree_rad.sci", -1) //Given that m = 15 //in kg g = 9.8 //in m/s^2 T = m* g* sin(dtor(27)) N = m* g* cos(dtor(27)) //Sample Problem 5-7a printf("**Sample Problem 5-7a**\n") printf("The tension in the chord is %f N\n", T) printf("The Normal force is %f N\n", N) //Sample Problem 5-7b printf("\n**Sample Problem 5-7b**\n") a = g * sin(dtor(27)) printf("The acceleration of block after cutting the chord is %f m/s^2", a)
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//Caption:Calculate the drop in speed when motor takes 51 Amp //Exam2.13 clc; clear; close; V=220;//supply voltage(in V) R_sh=220;//shunt field resistance(in Ohm) R_a=0.2;//armature resistance(in Ohm) I_sh=V/R_sh;//shunt field current(in Amp) N_1=1200;//starting speed of the motor(in rpm) I_1=5.4;//at N_1 speed current in motor(in Amp) I_a1=I_1-I_sh;//armature current at speed N_1(in Amp) E_b1=V-I_a1*R_a;//emf induced due to I_a1(in V) I_2=51;//new current which motor taking(in Amp) I_a2=I_2-I_sh;//armature current at I_2(in Amp) E_b2=V-I_a2*R_a;//emf induced due to I_a2(in V) N_2=E_b2*N_1/E_b1;//speed of the motor when taking I_2 current(in rpm) N_r=ceil(N_1-N_2);//reduction in speed(in rpm) disp(N_r,'reduction in speed(in rpm)=');
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bt = 0.3; span = 4; sps = 8; h = gaussdesign(bt); disp(h); //output // column 1 to 3 // // 0.0014136 0.0348089 0.2379628 // // column 4 to 6 // // 0.4516294 0.2379628 0.0348089 // // column 7 // // 0.0014136 //
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// Example 4.9.b;//Pulse broadning due to intermodal dispersion clc; clear; close; d=0.01;// Change in refractive index n1=1.5;//Core refrctive index L=6*10^3;//Length in meter C=2.998*10^8;//Speed of light in m/s Ss=(L*n1*d)/(2*sqrt(3)*C)*10^9;//Pulse broadning due to intermodal dispersion in ns disp(Ss,"Pulse broadning due to intermodal dispersion in ns")
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(set-strategy depth) (unwatch all) ; mfvmatch.clp test (clear) (load "mfvmatch.clp") (progn (dribble-on "mfvmatch.out") (reset) (run) (dribble-off)) (load compline.clp) (open "mfvmatch.rsl" mfvmatch "w") (printout mfvmatch "mfvmatch.clp differences are as follows:" crlf) (compare-files mfvmatch.exp mfvmatch.out mfvmatch) ; close result file (close mfvmatch)
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basis=1 //mol feed x=0.684 //mole fraction Of B y=0.4
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//(12.2) A gas mixture has the following composition in terms of mass fractions: H2, 0.10; N2, 0.60; CO2, 0.30. Determine (a) the composition in terms of mole fractions and (b) the apparent molecular weight of the mixture. //solution //variable initialization mf1 = .1 //mass fractiion of H2 mf2 = .6 //mass fraction of N2 mf3 = .3 //mass fraction of CO2 //part(a) M1 = 2 //molar mass of H2 in kg/kmol M2 = 28 //molar mass of N2 in kg/kmol M3 = 44 //molar mass of CO2 in kg/kmol n1 = (mf1/M1)/(mf1/M1 + mf2/M2 + mf3/M3) //mole fraction of H2 n2 = (mf2/M2)/(mf1/M1 + mf2/M2 + mf3/M3) //mole fraction of N2 n3 = (mf3/M3)/(mf1/M1 + mf2/M2 + mf3/M3) //mole fraction of CO2 printf('the mole fraction of H2 in percentage is: %f',n1*100) printf('\nthe mole fraction of N2 in percentage is: %f',n2*100) printf('\nthe mole fraction of CO2 in percentage is: %f',n3*100) //part(b) M = n1*M1 + n2*M2 + n3*M3 //in kg/kmol printf('\n\nthe apparent molecular weight of the mixture in kg/kmol is: %f',M)
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disp("Array of a") a=[1, 2, 3; 4, 5, 6; 7, 8, 9] disp(a) disp("Array of z") z=a^2 disp(z) disp("Array of az in column") azc=[a;z] disp(azc) disp("Array of az in column") azr=[a,z] disp(azr) disp("Array of az with 2 rows") az1=[a; z(1:2,1:3)] disp(az1) disp("Array of az with rows and columns") az2=[a(1:2,1:2), z(1:2,1:2)] disp(az2)
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clear;lines(0); n=[1,2,10,15];m=[2,2,3,5]; modulo(n,m)
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// Exa 8.1 clc; clear; close; // given data disp("We have : "); disp("Io1=gm1*V1"); disp("Io2=-gm2*Vo"); disp("I=Io1+Io2=gm1*V1-gm2*Vo"); disp("We also have : I=(Vo-V1)*s*C"); disp("From above two eqn :"); disp("gm1*V1-gm2*Vo=(Vo-V1)*s*C"); disp("Arranging terms to get Vo/V1 we have : "); disp("Transfer Function : V0/V1=(gm1+s*C)/(gm2+s*C)");
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@relation unknow @attribute at1 real[0.0,100.0] @attribute at2 real[0.0,100.0] @attribute at3 real[0.0,100.0] @attribute at4 real[0.0,100.0] @attribute at5 real[0.0,100.0] @attribute at6 real[0.0,100.0] @attribute at7 real[0.0,100.0] @attribute at8 real[0.0,100.0] @attribute at9 real[0.0,100.0] @attribute at10 real[0.0,100.0] @attribute at11 real[0.0,100.0] @attribute at12 real[0.0,100.0] @attribute at13 real[0.0,100.0] @attribute at14 real[0.0,100.0] @attribute at15 real[0.0,100.0] @attribute at16 real[0.0,100.0] @attribute class{0,1,2,3,4,5,6,7,8,9} @inputs at1,at2,at3,at4,at5,at6,at7,at8,at9,at10,at11,at12,at13,at14,at15,at16 @outputs class @data 8 8 6 6 1 1 6 6 1 1 8 8 6 6 0 0 2 2 7 7 6 6 1 1 3 3 2 2 8 8 9 9 7 7 6 6 0 0 4 4 2 2 0 0 1 1 5 5 1 1 6 6 3 3 1 1 6 6 0 0 4 4 4 4 2 2 0 3 9 9 8 8 2 2 1 8 9 9 0 0 1 1 2 2 9 9 3 3 8 8 1 1 4 4 5 5 5 5 5 5 3 7 9 9 7 7 0 0 8 8 5 5 9 9 7 7 9 9 0 0 8 8 5 5 7 5 9 9 2 2 1 1 9 9 9 9 2 2 5 5 4 4 2 2 7 7 3 3 0 0 7 7 0 0 1 1 7 7 4 4 5 5 1 1 8 8 0 0 2 2 4 4 6 6 8 8 1 5 6 6 7 7 2 2 7 7 3 3 2 2 8 8 1 1 2 2 8 8 6 6 2 7 2 2 8 8 7 7 5 5 5 5 9 9 0 0 5 5 1 2 4 4 7 7 0 0 3 3 6 6 1 1 3 3 7 7 6 6 8 8 4 4 1 2 5 5 5 3 8 8 0 0 7 7 4 4 7 7 0 0 5 3 1 1 3 3 9 9 8 8 0 0 7 7 9 9 2 2 6 6 6 8 4 4 3 3 7 7 2 7 7 7 5 5 8 8 5 5 9 9 3 3 6 6 0 0 3 3 5 5 9 9 9 9 4 4 3 3 8 8 4 4 9 3 8 8 2 2 0 0 6 6 6 6 9 9 7 7 2 2 8 8 1 1 8 8 5 5 7 4 4 4 2 2 6 6 0 0 4 4 1 1 1 1 9 9 5 5 3 3 4 4 1 1 0 0 7 7 0 0 3 3 5 5 6 6 4 4 9 9 3 3 0 0 0 0 3 3 3 3 8 8 4 4 2 2 3 3 2 2 5 5 4 4 7 7 3 3 9 9 4 4 6 6 9 9 6 6 2 2 4 4 3 3 4 4 7 7 4 4
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clc // Given that lambda = 2.63e-5 // Mean free path of the molecules of the gas in m t = 25 // Temperature in degree centigrade r = 2.56e-10 // Radius of the molecules in m printf("\n Example 22.2 \n") sigma = 4*%pi*r^2 n = 0.707/(sigma*lambda) p = n*(t+273)*(1.38*10^-23) N = 1/lambda printf("\n Pressure of the gas = %f Pa,\n No of collisions made by a molecule per meter of path = %e",p,N)
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// Test # 2 : Excess Input Arguments exec('./zpkbpc2bpc.sci',-1); [z,p,k,n,d]=zpkbpc2bpc(0.3,0.2,0.7,[0.5,0.6],[0.4,0.8],12); //!--error 58 //Wrong number of input arguments
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//clc() Pswater1 = 6.08;//kPa T1 = 313;//K //lnPs = 16.26205 - 3799.887/(T - 46.854) Tb1 =3799.887/(16.26205 - log(Pswater1)) + 46.854; disp("K",Tb1,"boiling point of water at 6.08kPa vapour pressure = ") Pswater2 = 39.33;//kPa T2 = 353;//K Tb2 =3799.887/(16.26205 - log(Pswater2)) + 46.854; disp("K",Tb2,"boiling point of water at 39.33 kPa vapour pressure = ") Tb = [Tb1 Tb2]; T = [T1 T2]; plot(T,Tb); xtitle('Equal pressure reference plot for sulphuric acid','Boiling point of solution,K','Boiling point of water, K'); T3 = 333;//K //corresponding to T3 on x axis, on y we get Tb3 = 329;//K Pswater3 = exp(16.26205 - 3799.887/(Tb3 - 46.854)); disp("kPa",Pswater3,"Vapour pressure of solution at 333K")
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clc //initialisation of variables clear k1= 6.45//cal deg^-1 mol^-1 k2= 1.41*10^-3 //cal deg^-2 mol^-1 k3= -0.81*10^-7 //cal deg^-3 mol^-1 T= 300 //K k4= -0.21*1.36 //cal deg^-3 mol^-1 atm^-1 k5= 6.87*1.5//cal deg^-3 mol^-1 atm^-2 p= 10^-3 //CALCULATIONS Cp= k1+k2*T+k3*T^2 dCp= k2+2*k3*T dCp1= k4*p+k5*p //RESULTS printf ('Cp = %.2f cal deg^-1 mole^-1',Cp) printf ('\n Specific heat at temperature = %.2e cal deg^-2 mole^-1',dCp) printf ('\n Specific heat at pressure = %.2e cal deg^-2 mole^-1 atm^-1',dCp1)
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-12 clear; clc; close; // Clear the work space and console. // Given data(from Example 14-11) V_1 = 2300 ; // Primary voltage in volt V_2 = 230 ; // Secondary voltage in volt I_2 = 2174 ; // Secondary current in A I_1 = 217.4 ; // Primary current in A // calculated values from Example 14-11 Z_2 = 0.00316 ; // Secondary internal impedance in ohm Z_1 = 0.316 ; // Primary internal impedance in ohm // Calculations alpha = V_1 / V_2 ; // Transformation ratio // case a Z_L = V_2 / I_2 ; // Load impedance in ohm // case b Z_p = V_1 / I_1 ; // Primary input impedance in ohm Zp = (alpha)^2 * Z_L ; // Primary input impedance in ohm // Display the results disp("Example 14-12 Solution : "); printf(" \n a: Load impedance :\n Z_L = %.4f ohm \n ", Z_L ); printf(" \n b: Primary input impedance : "); printf(" \n (method 1) :\n Z_p = %.2f ohm \n ",Z_p ); printf(" \n (method 2) :\n Z_p = %.2f ohm \n ",Zp ); printf(" \n c: The impedance of the load Z_L = %.4f Ω, which is much greater",Z_L); printf(" \n than the internal secondary impedance Z_2 = %.5f Ω .\n ",Z_2); printf(" \n The primary input impedance Z_p = %.2f Ω,which is much greater",Z_p); printf(" \n than the internal primary impedance Z_1 = %.3f Ω .\n",Z_1); printf(" \n d: It is essential for Z_L to be much greater than Z_2 so that the "); printf(" \n major part of the voltage produced by E_2 is dropped across the "); printf(" \n load impedance Z_L. As Z_L is reduced in proportion to Z_2, the "); printf(" \n load current increases and more voltage is dropped internally "); printf(" \n across Z_2.");
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//this is the standalone version for submitting work to a saas tdp=getenv('SCILAB_HOME')+'/share/scilab/contrib/iome_toolbox/loader.sce'; exec(tdp); //this application is started using the io start scilab application exec('paramssaastest1.sce'); //stacksize('max'); //stacksize(268435454); elistremote=iome('localhost',8080,0); simfile=metadata.name+'.xml'; simfileout=metadata.name+'_out.xml'; newsimulation(metadata.name,'test1.xsl',elist); createsim(param1,params2,metadata,elist); //[consts,domain,source]=loadsim('test1_16_02_09.xml',elist); //chdir(metadata.directory); writesimulation(simfile,elist); //runsim(consts,domain,source,metadata,simfile,elist); submitsimulation(simfile,elistremote); //WriteSimulation(simfile,elist); //chdir('..'); //exit();
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// DM2 vibrations // Programme principal // Yedhir MEZACHE // Jonathan RAVAHIMANANA // Hasinantenaina RAZAFIMAHALEO clear; clc; exec("dm2_nddl.sci",-1); xdel(winsid()); //Donnees du probleme // Poutre rho = 5000; // kg/m3 L = 1; // m longueur h = .05; // m hauteur de section b = .05; // m base de section E = 2e11; // N/m2 module d'Young de la poutre I = b*h^3; // m4 moment d'inertie de section EI = E*I; S = b*h; // m2 surface de section // Sollicitation w = 5000; // 2*pi/s pulsation de l'excitation // Disque m = 20; // kg masse du disque R = 0.15; // m rayon du disque Iz = m*R^2; // moment d'inertie du disque autour de z // Approximation /// 2ddl // /// nddl ne = 8; // Nombre d'elements. Doit etre pair pour prendre en compte le fait qu'il y a un disque au milieu ndisque = ne/2; // Numero de l element qui porte le disque dx = L/ne; [K,M] = assemblage(ne); // Matrices elementaires c1 = .1; c2 = .5 C = c1*K + c2*M; // Matrice d'amortissement visqueux,frottement proportionnel // Analyse modale [al, be, V] = spec(K,M); // val. propres generalisees V = real(V); // Etrangement, scilab considere ces vecteurs comme complexe meme si leur parties imaginaires sont toutes nulles ki = vmodales(V, K); // vecteur des raideurs modales ci = vmodales(V, C); // vecteur des amortissements modaux mi = vmodales(V, M); // masses modales wi = sqrt(ki./mi); // pulsations modales B = eigenvscale(mi, V); // vecteurs propres divises par les masses modales associee a leur modes respectifs // On peut verifier que Bt*M*B = matrice identite // RVF dt = .1; t = 0:dt:5; // duree de l'excitation // Deformees X = linspace(0, L, 100*ne+1); // intervalle [0,L] // Deformee du mode 1 v1 = defmodale(X, B(:,$)); v2 = defmodale(X, B(:,$-1)); v3 = defmodale(X, B(:,$-2)); v4 = defmodale(X, B(:,$-3)); v5 = defmodale(X, B(:,$-4)); // Traces de ces modes // fonctions de base b1 = []; b2 = [], b3 = [], b4 = []; x = []; for i=1:ne b1 = [b1,base(X, ne, i, n1)]; end for i=1:ne b3 = [b3, base(X, ne, i, n2)]; end for i=1:ne b2 = [b2,base(X, ne, i, h1)]; end for i=1:ne b4 = [b4,base(X, ne, i, h2)]; x = [x, linspace((i-1)*dx,(i-1)*dx + dx,length(base(X, ne, i, h2)))] end figure("figure_name","bases",'BackgroundColor',[1,1,1]) plot(x,b1, x,b2, x,b3, x,b4) figure('figure_name','modes symétriques','BackgroundColor',[1,1,1]) title('Déformées modales, modes symétriques'); plot(X, v1, X, v3, X, v5); txtlegs = [ 'mode 1, w = '+string(wi($))+' rad/s', 'mode 3, w = '+string(wi($-2))+' rad/s', 'mode 5, w = '+string(wi($-4))+' rad/s' ]; legend(txtlegs); xsave("results/deformees_sym.png"); figure('figure_name','modes anti-symétriques','BackgroundColor',[1,1,1]) title('Déformées modales, modes anti-symétrique'); plot(X, v2, X, v4); txtlegas = [ 'mode 2, w = '+string(wi($-1))+' rad/s', 'mode 4, w = '+string(wi($-3))+' rad/s' ]; legend(txtlegas); xsave("results/deformees_asym.png"); // Vibration forcee // Resolution numerique par une methode iterative w = 1510; // pulsation forcee f0 = 2000; // N amplitude maximale de la force F = sollicit(f0, ne); Fp = reform(F,ne); q = repmodale(w, wi, ci, Fp, t); v = B*q; cnp = diag(B'*C*B); // amortissements modales normalises au sens de la masse dnp = diag(B'*K*B); // pulsation modales carrees normalisees au sens de la masse //t = 0:0.1:5; // duree de simulation //V0 = zeros(length(cnp),1); // La poutre n'est pas deformee au debut de la sollicitation //Q0 = reform(V0, ne); // //A = matiter(cnp, dnp, ne); //Q = rvf(cnp, dnp, Q0, w, Fp, ne, t); //V = B*Q(1:2:$,:); figure("figure_name","reponse forcee",'BackgroundColor',[1,1,1]) plot(t,v(ndisque-1,:), t, v(ndisque,:)); // amplitude de deplacement du disque title("Déplacement vertical du disque au cours du temps, w = '+string(w)+' rad/s') xlabel('t [s]') ylabel('v(x'+string(ndisque - 1) + ',t) [m], theta(x'+string(ndisque-1) + ',t) [rad]') legend('translation','rotation') temps = [10, 25, 35, 50]; // *dx couleur = ['k' 'b' 'r' '--']; legende = [] figure("figure_name","poutre",'BackgroundColor',[1,1,1]) for i = 1:length(temps) ti = temps(i); ci = couleur(i) plot(X, defmodale(X, v(:,ti)), ci) legende = [legende, 't = '+string(ti*dt)+' s']; end //plot(X, defmodale(X, v(:,10)), X, defmodale(X, v(:,25)), X, defmodale(X, v(:,50))) title('Déformation de la poutre au cours du temps, w = '+string(w)+' rad/s') xlabel('x [m]') ylabel('v(x, t) [m]') legend(legende) // w = w2 Fp = inv(B)*F; w = wi($-1)*0.85; q = repmodale(w, wi, ci, Fp, t); v = B*q; // retour dans l'espace physique figure("figure_name","reponse forcee",'BackgroundColor',[1,1,1]) plot(t,v(ndisque-1,:), t, v(ndisque,:)); // amplitude de deplacement du disque title("Réponse du disque au cours du temps, w = '+string(w)+' rad/s') xlabel('t [s]') ylabel('v(x'+string(ndisque - 1) + ',t) [m], theta(x'+string(ndisque-1) + ',t) [rad]') legend('translation','rotation') figure("figure_name","poutre",'BackgroundColor',[1,1,1]) for i = 1:length(temps) ti = temps(i); ci = couleur(i) plot(X, defmodale(X, v(:,ti)), ci) legende = [legende, 't = '+string(ti*dt)+' s']; end //plot(X, defmodale(X, v(:,10)), X, defmodale(X, v(:,25)), X, defmodale(X, v(:,50))) title('Déformation de la poutre au cours du temps, w = '+string(w)+' rad/s') xlabel('x [m]') ylabel('v(x, t) [m]') legend(legende)
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//2本のサイン波入力に対する応答 s=%s; G=1/(1+0.5*s); t=0:0.01:10; u1=[3*sin(2*t)]; sys=syslin('c',G); y1=csim(u1,t,sys); xset("window",0);clf();plot2d(t',[u1',y1']) u2=[4*sin(2*sqrt(3)*t)]; y2=csim(u2,t,sys); xset("window",1);clf();plot2d(t',[u2',y2']) u12=u1+u2; y12=csim(u12,t,sys);; xset("window",2);clf();plot2d(t',[y1',y2',y12'])
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clear; clc; //Example - 14.1 //Page number - 455 printf("Example - 14.1 and Page number - 455\n\n"); //This problem involves proving a relation in which no mathematics and no calculations are involved. //For prove refer to this example 14.1 on page number 455 of the book. printf(" This problem involves proving a relation in which no mathematics and no calculations are involved.\n\n"); printf(" For prove refer to this example 14.1 on page number 455 of the book.")
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clc //Given that t = 1.8e-5 // Relaxation time in second epsilon_r = 1 // let printf("Example 4.18") f = 1/(2*%pi*t) // Calculation of frequency delta = atan(epsilon_r/epsilon_r) phi = 90 - delta*180/%pi // Calculation of phase difference printf("\n Frequency is %f KHz\n",f/1e3) printf(" Phase difference between current and voltage is %d degree.",phi)
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// a short script to calaculate the baud rate generation parameters for the // UART to Bus core mode(-1) // define the GCD function since Scilab prefers to use a different function as gcd function x = gcdn(a,b) x = zeros(length(b),length(a)); for n=1:length(a), for m=1:length(b), x=a(n); y=b(m); while y~=0 r=modulo(x,y); x=y; y=r; end x(m,n) = x; end end endfunction // request the required clock rate and baud rate parameters dig_labels = ["Clock Frequency in MHz"; "UART Baud Rate in bps"]; default_val = ["40"; "115200"]; params = evstr(x_mdialog("Enter Core Parameters", dig_labels, default_val)); // extract the parameters global_clock_freq = params(1)*1e6; baud_rate = params(2); // calculate the baud rate generator parameters D_BAUD_FREQ = 16*baud_rate / gcdn(global_clock_freq, 16*baud_rate); D_BAUD_LIMIT = (global_clock_freq / gcdn(global_clock_freq, 16*baud_rate)) - D_BAUD_FREQ; // print the values to the command window printf("Calculated core baud rate generator parameters:\n"); printf(" D_BAUD_FREQ = 12''d%d\n", D_BAUD_FREQ); printf(" D_BAUD_LIMIT = 16''d%d\n", D_BAUD_LIMIT); // open a message with the calculated values mes_str = ["Calculated core baud rate generator parameters:"; ... " D_BAUD_FREQ = "+string(D_BAUD_FREQ); ... " D_BAUD_LIMIT = "+string(D_BAUD_LIMIT); ... ""; ... "The verilog definition can be copied from the following lines:"; ... "`define D_BAUD_FREQ 12''d"+string(D_BAUD_FREQ); ... "`define D_BAUD_LIMIT 16''d"+string(D_BAUD_LIMIT); ]; messagebox(mes_str);
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clc //initialisation of variables R= 1.987 //atm lit/mol K T= 573.2 //K T1= 594.6 //K k= 3.95*10^-6 //mol^-1 sec^-1 k1= 1.07*10^-6 //mol^-1 sec^-1 //CALCULATIONS H= R*T*T1*2.303*log10((k/k1))/(T1-T) //RESULTS printf (' activation energy= %.f calmol^-1',H-39)
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function [Inn,X,Gbar]=colinout(G) // Copyright INRIA [Innt,Xt,Gbart]=rowinout(G'); Inn=Innt';X=Xt';Gbar=Gbart';
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s=poly(0,'s') F=syslin('c',1/(3*s+1)) y=evans(F) disp(y)
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clc; clear all; disp("power dissipation/length") d=0.01;//m e=0.92; ts=260;// degree C rhol=958.4;// kg/m^3 hfg=2257*10^3;//J/kg rhov=4.807;// k/m^3 cpv=2.56*10^3;// J/kg.K k=0.0331;// W/m.K muv=14.85*10^(-6);// Ns/m^2 mug=muv;; g=9.81;//m/s ta=100;// degree C te=ts-ta;// excess temperature hconv=0.65*(k^3*rhov*(rhol-rhov)*g*(hfg+0.4*cpv*te)/(muv*d*te))^0.25; hrad=5.67*10^(-8)*e*(ts^4-ta^4)/(ts-ta); h=hconv+3*hrad/4; Q=h*%pi*d*(ts-ta);// disp("W",Q,"power dissipation per unit length for the heater =")
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//Veocity of flow(in m/sec): U=1; //Length of flat plate(in m): L=1; //Density of water(in kg/m^3): d=999; //Kinematic viscosity of water(in m^2/sec): v=10^-6;
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function R = elementenGroterDanGemiddelde(M) g = gemiddelde(M) R = [] for col = M for x = col' if x > g then R = [R, x] end end end endfunction
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ra=2; re=1; A=[-ra,0;ra,-re]; B=[0;0]; u = 0; x0=[1;0]; t=[0:0.01:8]; x=ltisol(A,B,u,x0, t); plot(t,x);
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clc; clear; format('v',11); r=[2 3 4]; //Given Position vector r disp(r,'Given the vector r='); modr=sqrt(2^2+3^2+4^2); //Magnitude of the given vector r Ax=(2/modr); //Coeffitient in the X direction Ay=(3/modr); //Coeffitient in the Y direction Az=(4/modr); //Coeffitient in the Z direction //Displaying the direction cosines and the angles format('v',8) disp('The direction cosines of the given vector are:'); disp(Ax,'Ax=') disp(Ay,'Ay=') disp(Az,'Az=') x=[Ax Ay Az]; format('v',6) y=acosd(x); disp(y,'The angles that the given vector makes with the three vectors are (in Degree):')
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Create Player Profile Dialog Screen.tst
ScreenName String 'Create Player Profile Dialog Screen' ImplName String 'Dialog Screen' ElementChunkArray Int 6 ScreenElementType Int 0 ImplName String 'Front End Dialog Screen Backdrop' TabIndex Int 1 Selectable Bool False Enabled Bool True ReferenceArea Rect( 162, 168, 524, 428 ) # left,top,right,bottom ScreenElementType Int 3 ImplName String 'Player Name Text Entry' TabIndex Int 2 Selectable Bool True Enabled Bool True ReferenceArea Rect( 275, 257, 532, 305 ) # left,top,right,bottom Font String 'Univers12' Text String 'IDGS_TPFRONTENDTEXT_SCREENS_NULL' Color Colour( 1.000000, 1.000000, 1.000000, 1.000000 ) ScreenElementType Int 1 ImplName String 'Open Dialog Next Button' TabIndex Int 5 Selectable Bool False Enabled Bool True ReferenceArea Rect( 414, 320, 543, 364 ) # left,top,right,bottom Font String 'BlackChancery16' Text String 'IDGS_TPFRONTENDTEXT_SCREENS_ADD' Color Colour( 1.000000, 1.000000, 1.000000, 1.000000 ) HotKey Int -1 ScreenElementType Int 1 ImplName String 'Open Dialog Previous Button' TabIndex Int 7 Selectable Bool False Enabled Bool True ReferenceArea Rect( 259, 320, 388, 364 ) # left,top,right,bottom Font String 'BlackChancery16' Text String 'IDGS_TPFRONTENDTEXT_SCREENS_CANCEL' Color Colour( 1.000000, 1.000000, 1.000000, 1.000000 ) HotKey Int -1 ScreenElementType Int 1 ImplName String 'Center Justify Label' TabIndex Int 8 Selectable Bool False Enabled Bool True ReferenceArea Rect( 4, 225, 800, 253 ) # left,top,right,bottom Font String 'Univers12' Text String 'IDGS_TPFRONTENDTEXT_SCREENS_TYPE_IN_YOUR_NAME' Color Colour( 0.000000, 0.000000, 0.000000, 1.000000 ) HotKey Int -1 ScreenElementType Int 1 ImplName String 'Center Justify Label' TabIndex Int 9 Selectable Bool True Enabled Bool True ReferenceArea Rect( 0, 224, 800, 250 ) # left,top,right,bottom Font String 'Univers12' Text String 'IDGS_TPFRONTENDTEXT_SCREENS_TYPE_IN_YOUR_NAME' Color Colour( 1.000000, 1.000000, 1.000000, 1.000000 ) HotKey Int -1
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// Scilab code Exa7.7.2 : To calculate the capacitance and the amplitude of voltage pulse across the detector :Page 316 (2011) E_r = 12; // Relative permittivity E_o = 8.85e-012; // Permittivity of free space E = E_r*E_o; // Absolute dielectric constant A = 2e-04; // Area of the detector, m^2 e = 1.602e-019; // Charge of an electron, C d = 100e-06; // The thickness of the depletion layer, m C = E*A/d; // The capacitance of the dielectric, F E_p = 3.0; // Energy required to create an ion pair, eV E_s = 5.48e+06; // Energy required to stopped ion pair, eV n = E_s/E_p; // Number of ion-pair produced Q = n*e; // Charge of these ion pair, C A = Q/C*1000; // The amplitude of voltage pulse, mV printf("\n The capacitance of dielectric = %5.3e F \n The amplitude of voltage pulse = %5.3f mV ", C, A) // Result // The capacitance of dielectric = 2.124e-010 F // The amplitude of voltage pulse = 1.378 mV
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// Example 2.5 page no-48 clear clc f=10*10^6 //Hz h=6.626*10^-34 //Joules/sec e=1.6*10^-19 //C //(a) E=h*f/e printf("\n(a)Energy of each radiated quantum,\n\tE=%.3f*10^-27 Joules/Quantum\n\tE=%.2f*10^-8 eV/Quantum",h*f*10^27,E*10^8) //(b) E=1000 //Joule/sec N=E/(h*f) printf("\n\n(b)\nTotal number of quanta per sec, N=%.2f*10^29",N/10^29) //(c) o=10^-7 printf("\n\n(c)\nNumber of quanta emitted per cycle = %.2f*10^22 per cycle",o*N/10^22)
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//Example No.6.7 //Page No.188. //Find the angle between two planes (111) and (212) in a cubic lattice. clc;clear; // (u1,v1,w1) are the miller indices of the plane (111). u1 = 1; v1 = 1; w1 = 1; // (u2,v2,w2) are the miller indices of the plane (212). u2 = 2; v2 = 1; w2 = 2; u = acosd(((u1*u2)+(v1*v2)+(w1*w2))/((sqrt((u1^2)+(v1^2)+(w1^2))*sqrt((u2^2)+(v2^2)+(w2^2)))));//u is the angle between two planes. printf("\n The angle between the planes (111) and (212) is %.3f degree",u);
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// Scilab Code Ex1.39: : Page-1.57 (2009) clc; clear; h = 6.6e-034; // Planck's constant, Js m0 = 9.1e-031; // Electronic mass, kg c = 3e+08; // Speed of light, m/s e = 1.6e-019; // Energy equivalent of 1 eV, J/eV phi = 60; // Scattering angle of X-rays, degrees E = 75; // Incident energy of X-rays, keV // As from Compton shift formula delta_L = h/(m0*c)*(1-cosd(phi)); // Change in photon wavelength, m lambda = 0.198e-010; // Wavelength of incident photon, m lambda_prime = (lambda+delta_L)/1e-010; // Wavelength of scattered X-ray, angstrom printf("\nThe wavelength of scattered X-ray = %6.4f angstrom", lambda_prime); // Result // The wavelength of scattered X-ray = 0.2101 angstrom
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errcatch(-1,"stop");mode(2); //Example 19.3 //Calculate the impeller speed in a model of a large mixer if the power per unit volume remains the same //let D1/D2 be denoted by ratio_D ratio_D=5//dimentionless N2=240//rpm N1=N2/ratio_D^(2/3)//rpm printf("the impeller speed in a model of a large mixer if the power per unit volume remains the same is %f rpm",N1); exit();
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// problem 7.17 n=1 Q=14 i=1/1000 C=44 a=1.828 d=((Q*(2^0.5))/(C*a*(i^0.5)))^0.4 b=d*0.828 cost=(b+n*d)*4 A=1.828*d*d C1=70 d1=((Q*(2^0.5))/(C1*a*(i^0.5)))^0.4 b1=0.828*d1 cost1=(b1+n*d1)*4 costl=(b1+(2*d1*((n*n+1)^0.5))) totalcost= cost1+costl disp(d1,b1,"lined channel is cheaper ,dimension in m")
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// second order reaction // A + B => C, k function dy = model(t, y) A = y(1) // A,B,C B = y(2) C = y(3) dAdt = -k*A*B dBdt = -k*A*B dCdt = k*A*B dy=[dAdt, dBdt, dCdt] // A,B,C endfunction // A0 = 2 B0 = 1 C0 = 0 y0 = [A0; B0; C0] // A,B,C t0 = 0 k = 3e-3 // L/(mol*s) // time span t = linspace(0,3600) y = ode(y0, t0, t, model) //disp(t) //disp(y) //A(t) A=y(1,:) // first row //B(t) B=y(2,:) // second row //C(t) C=y(3,:) // second row // clear plot area clf // subplot(211) plot(t, A, '-or') //A(t) plot(t, B, '-ob') //B(t) plot(t, C, '-og') //C(t) legend(['A'; 'B'; 'C']) xlabel('Time') ylabel('Concentration') subplot(212) plot(t, A + C, '-+r') plot(t, B + C, '-+p') legend(['A+C';'B+C']) // equilibria // 2A => B, k1 // B => 2A, k2 function dy = model(t, y) A = y(1) // A,B B = y(2) dAdt = -2*k1*A*A + 2*k2*B dBdt = k1*A*A - k2*B dy=[dAdt, dBdt] // endfunction k1 = 1e-3 k2 = 1e-4 A0 = 0.6 B0 = 0 y0 = [A0; B0] //t = linspace(0,20000) //y = ode(y0, t0, t, model) //clf //A=y(1,:) // first row //B=y(2,:) // second row //plot(t,A,'-b') //plot(t,B,'--g')
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//Chapter 10 //Sketch the output Waveform //page no. 358 //Example10_3 //Figure 10.7 //Given clc; clear; T0=4; t=-5.99:0.01:6; t_temp=0.01:0.01:T0/4; s=length(t)/length(t_temp); dx=[]; x=[]; for i=1:s if modulo(i,2)==1 then dx=[dx -ones(1,length(t_temp))]; x=[x .1*t_temp($:-1:1)]; else dx=[dx ones(1,length(t_temp))]; x=[x .1*t_temp]; end end clf(); subplot(1,2,2) plot(50*t,10*x-0.5,8) xtitle("Output Waveform","Microsecond","V"); t=-30:0.01:30; subplot(1,2,1); plot('onn',10*t,[2*squarewave(2*t/(%pi),50)]) xtitle("Input Waveform","Microsecond","V");
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load Jump.hdl, output-file Jump.out, compare-to Jump.cmp, output-list j1%B3.1.3 j2%B3.1.3 j3%B3.1.3 zr%B3.1.3 ng%B3.1.3 out%B3.1.3; set j1 0, set j2 0, set j3 1, set zr 0, set ng 0, eval, output; set j1 0, set j2 1, set j3 0, set zr 1, set ng 0, eval, output; set j1 0, set j2 1, set j3 1, set zr 1, set ng 0, eval, output; set j1 1, set j2 0, set j3 0, set zr 0, set ng 1, eval, output; //region JNE if out != 0, therefore zr should be 0 and ng should be (0 or 1) set j1 1, set j2 0, set j3 1, set zr 0, set ng 0, eval, output; set j1 1, set j2 0, set j3 1, set zr 0, set ng 1, eval, output; //end region set j1 1, set j2 1, set j3 0, set zr 1, set ng 1, eval, output; set j1 1, set j2 1, set j3 1, set zr 0, set ng 0, eval, output;
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//Chemical Engineering Thermodynamics //Chapter //Introduction //Example 1.3 clear; clc; //Given //The given example is a theoretical problem and it does not involve any numerical computation //end
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clc; // page no 139 // prob no 4_13_1 //Noise fig. of an amplifier is 7 dB with input SNR=35 dB SNRin=35;//SNR at i/p of amplifier F=7;//Noise figure of an amplifier //Determination of output SNR SNRout=SNRin-F; disp('dB',SNRout,'The value of output signal to noise ratio is ');
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//ques-18.10 //Calculating work done and heat rejected and efficiency clc T1=0; T2=100;//temperature (in degree celsius) q2=840;//energy absorbed (in J) q1=q2*((T1+273)/(T2+273));//heat rejected (in J) W=q2-q1;//work done (in J) n=(T2-T1)/(T2+273);//efficiency printf("The work done is %.1f J, heat rejected is %.1f J and efficiency is %.3f.",W,q1,n);
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P=12E6 Q=6E6 V=22000 Xs=8 S=P+%i*Q theta=atan(Q/P) disp(theta/%pi*180) Ia=norm(S)/sqrt(3)/V Ef=V/sqrt(3)+%i*Xs*Ia*exp(-%i*theta) delta=atan(imag(Ef)/real(Ef)) disp(delta/%pi*180) emf=norm(Ef)*sqrt(3) disp(emf)
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K V=1.6; P=1; m=2; T=17+273; G=1.4; R=(P*100*V)/(m*T); Cv=(R)/(G-1); printf('The Value of Cv: %1.2f kJ/kg K',Cv); printf('\n'); Cp=Cv+R; printf('The Value of Cp: %1.3f kJ/kg K',Cp); printf('\n')
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//ques4 //Calculation of work in the given cycle clear clc R=0.287;//gas constant T1=288.2;//compressor temperature K T2=1373.2;//K turbine temperature K //Pe/Pi=c=10, Pi/Pe=1/c from example 12.1 c=10; wc=-R*T1*log(c); printf('Isothermal work in compressor = %.1f kJ/kg \n',wc); wt=-R*T2*log(1/c); printf(' Isothermal work in turbine = %.1f kJ/kg\n',wt);
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//Finding T and R //applying Lami's Theorem we get T=(100*sind(90))/sind(90+15) //N R=(100*sind(180-15))/sind(90+15) //N printf("\nThe required values are:-\nT=%.1f N \nR=%.1f N",T,R)
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//Exa 5.4 clc; clear; close; //Given data : N=20;//turns D=1;//in meter r=D/2;//in meter E=200*10^-6;//in V/m L=50*10^-6;//in H R=2;//in Ohm f=1.5;//in MHz f=f*10^6;//in Hz c=3*10^8;//speed of light in m/s lambda=c/f;//in meter A=%pi*r^2;//in m^2 Vrms=2*%pi*E*A*N/lambda;//in Volts Q=2*%pi*f*L/R;//unitless Vc_rms=Vrms*Q;//in Volts disp(Vc_rms*1000,"Voltage across the capacitor in mV :"); //Note : Answer in the book is wrong.
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//Example 6.32. refer fig.6.30. clc format(5) R1=56*10^3 R2=12.2*10^3 RC=2*10^3 RE=400 VCC=10 VBE=0.7 beta=150 disp("From the Thevenin equivalent circuit shown in fig.6.30(b),") RTH=(R1*R2)/(R1+R2) RTH1=round(RTH*10^-3) disp(RTH1,"RTH(k-ohm) = R1 || R2 =") VTH=(R2/(R1+R2))*VCC disp(VTH,"VTH(V) = (R2 / (R1+R2)) * VCC =") disp("By kirchhoff voltage law equation,") IBQ=(VTH-VBE)/(RTH+((1+beta)*RE)) IBQ1=IBQ*10^6 disp(IBQ1,"IBQ(uA) = (VTH-VBE(on)) / (RTH + ((1+beta)*RE)) = ") ICQ=beta*IBQ ICQ1=ICQ*10^3 disp(ICQ1,"Therefore, ICQ(mA) = beta * IBQ = ") format(6) IEQ=IBQ+ICQ IEQ1=IEQ*10^3 disp(IEQ1,"IEQ(mA) = IBQ + ICQ") VCEQ=VCC-(ICQ*RC)-(IEQ*RE) disp(VCEQ,"VCEQ(V) = VCC - (ICQ*RC) - (IEQ*RE)") disp("The Q point is at :") disp(VCEQ,"VCEQ(V) = ") format(5) disp(ICQ1,"ICQ(mA) = ")
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// Exa 2.24 format('v',6); clc; clear; close; // Given data Rsig= 100;// in kΩ Rsig= Rsig*10^3;// in Ω R_G= 4.7;// in MΩ R_G= R_G*10^6;// in Ω R_D= 15;// in kΩ R_D= R_D*10^3;// in Ω R_L= R_D;// in Ω gm= 1;//in mA/V gm= gm*10^-3;//in A/V ro=150;// in kΩ ro=ro*10^3;// in Ω Cgs= 1;// in pF Cgs=Cgs*10^-12;//in F Cgd= 0.4;// in pF Cgd=Cgd*10^-12;//in F vgsBYvsig= R_G/(Rsig+R_G); Rdesh_L= R_D*R_L/(R_D+R_L);// in Ω voBYvgs= -gm*Rdesh_L; Av= voBYvgs/vgsBYvsig;// in V/V disp(Av,"The Mid-band gain in V/V is :") CM= Cgd*(1+gm*Rdesh_L);// in F // f_H= 1/(2*%pi*(Rsig || R_G)*(Cgs*CM)) f_H= 1/(2*%pi*(Rsig * R_G/(Rsig + R_G))*(Cgs+CM));// in Hz f_H= f_H*10^-3;// in kHz disp(f_H,"Frequency in kHz is : ")
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// Example A-5-10 // Plot the unit step response and find the transient parameters // viz. - rise time, peak time , settling time and maximum overshoot clear; clc; xdel(winsid()); //close all windows mode(0); // Please edit path if needed // cd "/<your code path>/"; // exec("stepch.sci"); N = poly( [12.811 18 6.3223],'s','c') ; D = poly( [12.811 18 11.3223 6 1], 's','c'); G = syslin('c',N,D); [Mp tp tr ts] = stepch(G,0,20,0.01,0.02)
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4_3.sce
clc clear //Initialization of variables ratio=1/2 R=8.314 p1=0.5 //kPa p2=0.1 //kPa //calculations ya=ratio/(1+ratio) ds=-ya*R*log(ya) - (1-ya)*R*log(1-ya) dss=R*log(p1/p2) //results printf("Entropy of mixing = %.3f kJ/kmol K",ds) printf("\n Total entropy change of the universe = %.2f kJ/kmol K",dss)
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%%-*- mode: erlang -*- %%-*- coding: utf-8 -*- % Test control options [{tests, []}]. %% %% TESTS %% "DELETE FROM table_name". "DELETE FROM table_name WHERE some_column=some_value". "DELETE FROM table_name WHERE some_column=some_value RETURN c,d INTO :c, :d". "DELETE FROM table_name WHERE some_column=some_value RETURN lob_column INTO :out_locator". "DELETE FROM table_name WHERE some_column=some_value RETURNING c,d INTO :c, :d". "DELETE FROM table_name WHERE some_column=some_value RETURNING lob_column INTO :out_locator".
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//chapter 5 example 4// clc clear //length of cavity=L,refractive index of GaAs=n1,wavelength=l,seperation wavelength between two mode=dl// n1=3.6;//refractive index// l=0.85*(10^-6);//wavelength// L=200*(10^-6);//length of cavity// dl=(l^2)/(2*n1*L)*(10^9);//seperation wavelength between two mode// printf("\n seperation wavelength between two mode=%f nm\n",dl)
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Ex13_5.sce
clear //Initialization C1=10*10**-6 //capacitance in Farad C2=25*10**-6 //capacitance in Farad //Calculation C=C1+C2 //capacitance in Farad //Results printf("\n C = %d uF",C*10**6)
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//equation// ieee(2); s=%s; m=s^5+s^4+3*s^3+3*s^2+4*s+8 r=coeff(m); //Extracts the coefficient of the polynomial n=length(r); routh=[r([6,4,2]);r([5,3,1])] syms eps; routh=[routh;eps,-det(routh(1:2,2:3))/routh(2,2),0]; routh=[routh;-det(routh(2:3,1:2))/routh(3,1),-det(routh(2:3,2:3))/routh(3,2),0]; routh=[routh;-det(routh(3:4,1:2))/routh(4,1),-det(routh(3:4,2:3))/routh(4,2),0]; routh=[routh;-det(routh(4:5,1:2))/routh(5,1),0,0]; disp(routh,"routh=") //To check the stability routh(4,1)=limit(routh(4,1),eps,0); //Putting the value of eps=0 in routh(4,1) disp(routh(4,1),"routh(4,1)=") routh(5,1)= limit(routh(5,1),eps,0); //Putting the value of eps=0 in routh(5,1) disp(routh(5,1),"routh(5,1)=') routh printf("There are two sign changes of first column,hence the system is unstable \n")
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function mod = genqammod(x, constellation) // //Function Description //genqammod: This function modulates a sequence of integers //x into a complex baseband signal, according to a specified constellation. // //Calling sequence:- //genqammod(x, constellation) // //Parameters: //x: int - matrix // The sequence of integers to be modulated. // Each integer in x should be in [0,length(constellation)-1] //constellation: complex - vector // The constellation map to modulate x. // Must be a vector of complex numbers. // //Example Usage // mod = genqammod(0:4, [1, -1, %i, -%i]) // //Authors //Devdatta Kathale // //Function Description Ends // //Check inputs if argn(2)~=2 then error('genqammod: This function takes exactly 2 arguments.') end if ~or(size(constellation)==1) then error('genqammod: The constellation must be a vector.') end if or(x>ceil(x)) | or(x<0) then error('genqammod: The entries of x must all be non-negative integers.') end if or(x+1>length(constellation)) then error('genqammod: The entries of x must all be in [0,length(constellation)-1].') end // //Flatten, assign values, and restore shape x_dim = size(x) x_flat = matrix(x, [-1,1] ) mod = constellation(x_flat+1) mod = matrix(mod, x_dim) // endfunction
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ex20.sce
clc A=[11 -25;4 -9] n=input('Enter the value of n "); disp('calculating A^n '); A^n
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pp_pid.sci
// Solution to Aryabhatta's identity arising in PID controller design, namely Eq. 9.37 on page 363. // 9.20 function [Rc,Sc] = pp_pid(B,A,k,phi,Delta) // Setting up and solving Aryabhatta identity dB = length(B) - 1; dA = length(A) - 1; [zk,dzk] = zpowk(k); [N,dN] = polmul(B,dB,zk,dzk); dDelta = length(Delta)-1; [D,dD] = polmul(A,dA,Delta,dDelta); dphi = length(phi)-1; [Sc,dSc,R,dR] = xdync(N,dN,D,dD,phi,dphi); Rc = convol(R,Delta); endfunction;
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EX14_1.sce
//Example14.1 // to determine the regulated voltage clc; clear; close; R1 = 250 ; //ohm R2 = 2500 ; // ohm Vref = 2 ; //V //reference voltage Iadj = 100*10^-6; // A // adjacent current //the output voltage of the adjustable voltage regulator is defined by Vo = (Vref*((R2/R1)+1)+(Iadj*R2)) ; disp('the output voltage of the adjustable voltage regulator is = '+string(Vo)+' V ');
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159ex1.sce
clear; clc; close; //EX(1): function [val]=answer(u,v,x,y) val=u*v*10^(x+y) endfunction val=answer(1.2,2.3,4,3) //EX(2): function[val1]=answer1(u,v,x,y) val1=(u/v)*10^(x-y) endfunction val1=answer1(4.8,1.6,8,3)
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ex2_23.sce
//Page Number: 107 //Example 2.23 clc; //Given c=3D+8; //m/s f=9D+9; //hz a=5; //cm a1=a/100; //m e=1; mu=1/(c*c); p11=1.841; fc=(p11*c)/(2*%pi*a1); //Maximum power transmitted pmax=1790*(a1*a1)*sqrt(1-((fc/f)^2)); disp('kW',pmax,'Maximum power transmitted:');
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20_1data.sci
L16=400;//given in mm L34=200;//given in mm L12=600;//given in mm L23=600;//given in mm t12=2;//given in mm t23=1.5;//given in mm t34=2;//given in mm t25=2.5;//given in mm t16=3;//given in mm A=300;//given in mm^2
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//Exa 3.6 clc; clear; close; //Given data : RC=10;//in kohm hfe=330;//unitless hie=4.5;//in kOhm //RS<<hie AVM=hfe*RC*10^3/(hie*10^3+RC*10^3);//unitless AVM1=AVM;//Gain of 1st stage AVM2=AVM;//Gain of 2nd stage AVM3=hfe*RC*10^3/(hie*10^3);//unitless(//Gain of 3rd stage) OverallGain=AVM1*AVM2*AVM3;//unitless disp(AVM,"Gain in mid frequeny range : "); disp("This is the gain of 1st and 2nd stage.") disp(OverallGain,"Overall Voltage gain for mid frequency range : ");
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Ch3Exa6.sci
Xo= 10^(-11); //uncertainty at time t=o, mts hb= 1.054*(10^(-34)); //h-bar, reduced Planck's constant, J.s t= 1; //time, s m= 1.672*(10^(-27)); //mass, kg x1= hb*t/(2*m*Xo); //uncertainty at time t=1, mts disp(x1,"accuracy in position of proton after 1.00 seconds (in m) is : ") //Result // accuracy in position of proton after 1.00 seconds (in m) is : // 3151.9139
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//Ques 1 //To determine the efficiency of Rankine cycle clc clear //1-Inlet state of pump //2-Exit state of pump P2=2000;//Exit pressure in kPa P1=10;//Inlet pressure in kPa v=0.00101;//specific weight of water in m^3/kg wp=v*(P2-P1);//work done in pipe in kJ/kg h1=191.8;//Enthalpy in kJ/kg from table h2=h1+wp;//enthalpy in kJ/kg //2-Inlet state for boiler //3-Exit state for boiler h3=2799.5;//Enthalpy in kJ/kg //3-Inlet state for turbine //4-Exit state for turbine //s3=s4(Entropy remain same) s4=6.3409;//kJ/kg sf=0.6493;//Entropy at liquid state in kJ/kg sfg=7.5009;//Entropy difference for vapor and liquid state in kJ/kg x4=(s4-sf)/sfg;//x-factor hfg=2392.8;//Enthalpy difference in kJ/kg for turbine h4=h1+x4*hfg;//Enthalpy in kJ/kg nth=((h3-h2)-(h4-h1))/(h3-h2); printf('Percentage efficiency = %.1f ',nth*100);
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clc //initialization of variables D2 = 5*10^-6 // The diffusion co efficient of the new compound in cm^2/sec Nu = 3 // The factor D1 = 0.7*10^-5 // The diffusion co efficient of the original compound in cm^2/sec c2l = 1.5*10^-5 // the new solubility in mol/cc c1l = 3*10^-7 // The old solubility in mol/cc //Calculations k = 1 + ((D2*c2l)/(Nu*D1*c1l))// The number of times the rate has increased to the previous rate //Results printf("There is about a %.f fold increase in rate",k)
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example6_17_TACC.sce
//example 6.17 clear; clc; //Given: m2=1.35;//mass of a macromolecule[gm] V=100;//volume of solution[cm^3] R=82;//Universal gas constant[atm.cm^3.K^-1] T=300;//Temperature[K] II=9.9;//osmotic pressure of the solution[cm] d=1;//density p=1013250;//Atmospheric pressure g=980.67;//gravitational field //To find the molar mass of macromolecule a=m2*R*T*p; b=V*9.9*d*g; M2=a/b;//molar mass of macromolecule printf(" M2 = molar mass of macromolecule , therefore M2 = %f g.mol^-1",M2);
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<div class="row [[?= link == 'true' ]] linkedRow [[?==]] " target="/listings/[[item.id]]"> <div class="cell center"><img src="/assets/img/products/[[item.image]]" alt="Preview Image"></div> <div class="cell center">[[item.name]]</div> <div class="cell center">[[item.description]]</div> <div class="cell center">$[[item.cost]]</div> <div class="cell center">[[item.seller.name]]</div> <div class="cell center" style="width:2em;"> [[?= showAddButton == "true" ]] <div class="btn white" style="padding:0.55rem;" action="addToCart" target="[[item.id]]">Add</div> [[?==]] </div> </div>
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//i/p args b and a are matrices b=[1 2 3; 5 6 7]; a=[2 3 4;5 7 8]; n=10; [phi,w] = phasez(b,a,n); disp(phi); disp(w); //output // !--error 4 //Undefined variable: cas //at line 36 of function phasez called by : //[phi,w] = phasez(b,a,n); //at line 4 of exec file called by : //!!/phasez2.sce', -1
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/* Objetivo: Calcular a raiz de uma equação pelo método pégaso Parâmetros de entrada: a, b, Toler, IterMax Parâmetros de saída: Raiz, Iter, CondErro */ function [Raiz, Iter, CondErro] = Pegaso(a, b, Toler, IterMax) deff('y = f(x)', 'y = 2*x^3 - cos(x+1) - 3') Fa = f(a) Fb = f(b) x = b Fx = Fb Iter = 0 printf("Iter\ta\tFa\tb\tFb\tx\tFx\tDeltaX\n") while 1 do DeltaX = -Fx/(Fb - Fa)*(b-a) x = x + DeltaX Fx = f(x) // Avaliar a função em x printf("%d\t%f\t%f\t%f\t%f\t%f\t%f\t%f\n", Iter, a, Fa, b, Fb, x, Fx, DeltaX) if abs(DeltaX) <= Toler & abs(Fx) <= Toler | Iter >= IterMax then break end if Fx * Fb < 0 then a = b Fa = Fb else Fa = Fa * Fb /(Fb + Fx) end b = x Fb = Fx Iter = Iter + 1 end Raiz = x //Teste de convergência if abs (DeltaX) <= Toler & abs(Fx) <= Toler then CondErro = 0 else CondErro = 1 end endfunction
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clc //initialisation of variables sx= 2000 //lb/ft^3 sy= 2500 //lb/ft^3 T= 800 //lb/ft^3 t= 0.348//radians //calculations s1= (sx+sy)/2+sqrt(((sy-sx)/2)^2+T^2) s2= (sx+sy)/2-sqrt(((sy-sx)/2)^2+T^2) sn= (sx+sy)/2+(sy-sx)*cos(2*t)/2-T*sin(2*t) Tn= (sy-sx)*sin(2*t)/2+T*cos(2*t) //results printf ('principle stress s1 = % 2f lb/ft^3 ',s1) printf ('principle stress s2 = % 2f lb/ft^3 ',s2) printf ('normal stress = % 2f lb/ft^3 ',sn) printf ('shear stress = % 2f lb/ft^3 ',Tn)
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Chapter7_Ex1.sce
//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc.,USA,pp 436. //Chapter-7 Ex7.1 Pg No.260 //Title:Overall Reaction Rate Coefficient, Percent Resistance, Reaction Volume and Reactor Size //=========================================================================================================== clear clc // COMMON INPUT k2=8.5;//Reaction rate constant (L/mol-sec) T=50;//Reaction condition temperature(°C) P=2;//Reaction Pressure (atm) H_O2=8*10^4;// Solubility (atm/mol fraction) F=17000//Feed rate (L/hr) C_B_feed=1.6;//Feed concentration(M) C_B_product=0.8;//Product concentration(M) k_L_a=900;//Liquid film mass transfer coefficient(hr-1) k_g_a=80;//Gas film mass transfer coefficient(mol/hr L atm) Epsilon=0.1;//Porosity percent_inc=0.2;//Percentage excess required for reactor volume //CALCULATION (Ex7.1.a) H_O2_conv=H_O2*18/1000;// Convert (atm L/mole O2) k_L_a_by_H=k_L_a/H_O2_conv; reaction_resistance=H_O2_conv/(k2*C_B_product*(1-Epsilon)*3600); Kg_a=1/((1/k_g_a)+(1/k_L_a_by_H)+(reaction_resistance));//Refer equation7.10 gasfilm_resistance_per=((1/k_g_a)/(1/Kg_a))*100; liq_film_resistance_per=((1/k_L_a_by_H)/(1/Kg_a))*100; reaction_resistance_per=((reaction_resistance)/(1/Kg_a))*100; //CALCULATION (Ex7.1.b) delta_C_B=C_B_feed-C_B_product; mol_O2_needed=F*delta_C_B/4; N_air=100;//Assuming 100 mole of feed air f_O2=0.209;//Fraction of O2 f_N2=1-f_O2;//Fraction of N2 N_O2_in=N_air*f_O2; N_N2_in=N_air*f_N2; N_O2_out=N_O2_in/2;//Half of O2 fed N_N2_out=N_N2_in; N_air_out=N_N2_out+N_O2_out; P_O2_out=P*(N_O2_out/N_air_out); P_O2_in=P*(N_O2_in/N_air); P_O2_bar=(P_O2_in-P_O2_out)/(log(P_O2_in/P_O2_out));//Log mean Pressure volume=mol_O2_needed/(Kg_a*P_O2_bar); reactor_vol=volume+volume*percent_inc; volume_gal=volume*0.264; reactor_vol_gal=reactor_vol*0.264; //OUTPUT (Ex7.1.a) mprintf('\n OUTPUT Ex7.1.a'); mprintf('\n=========================================================='); mprintf('\nThe percentage gas-film resistance : %0.1f%%',gasfilm_resistance_per); mprintf('\nThe percentage liquid-film resistance: %0.1f%%',liq_film_resistance_per); mprintf('\nThe percentage chemical reaction resistance: %0.1f%%',reaction_resistance_per); //OUTPUT (Ex7.1.b) mprintf('\n\n\n OUTPUT Ex7.1.b'); mprintf('\n=========================================================='); mprintf('\n Reaction volume calculated : %0.0f L ',volume ); mprintf('\n Reactor size to be chosen : %0.0f L',reactor_vol); // FILE OUTPUT fid= mopen('.\Chapter7-Ex1-Output.txt','w'); mfprintf(fid,'\n OUTPUT Ex7.1.a'); mfprintf(fid,'\n=========================================================='); mfprintf(fid,'\nThe percentage gas-film resistance : %0.1f%%',gasfilm_resistance_per); mfprintf(fid,'\nThe percentage liquid-film resistance: %0.1f%%',liq_film_resistance_per); mfprintf(fid,'\nThe percentage chemical reaction resistance: %0.1f%%',reaction_resistance_per); mfprintf(fid,'\n\n\n OUTPUT Ex7.1.b'); mfprintf(fid,'\n=========================================================='); mfprintf(fid,'\n Reaction volume calculated : %0.0f L ',volume ); mfprintf(fid,'\n Reactor size to be chosen : %0.0f L',reactor_vol); mclose(fid); //===================================================END OF PROGRAM======================================================
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// File name: projects/07/MemoryAccess/PointerTest/PointerTestVME.tst load PointerTest.vm, output-file PointerTest.out, compare-to PointerTest.cmp, output-list RAM[256]%D1.6.1 RAM[3]%D1.6.1 RAM[4]%D1.6.1 RAM[3032]%D1.6.1 RAM[3046]%D1.6.1; set RAM[0] 256, repeat 15 { vmstep; } output;
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/set7/s_Electronic_Devices_And_Circuits_K._L._Kishore_1511.zip/Electronic_Devices_And_Circuits_K._L._Kishore_1511/CH3/EX3.4/ex3_4.sce
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hohiroki/Scilab_TBC
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refs/heads/master
2021-01-18T02:07:29.200029
2016-04-29T07:01:39
2016-04-29T07:01:39
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ex3_4.sce
errcatch(-1,"stop");mode(2);// Example 3.4 page no-157 Rl=5010 //ohm idc=0.001 Vrms=idc*%pi*Rl/(2*sqrt(2)) printf("\nVrms = %.2f V",Vrms) exit();
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/1757/CH5/EX5.7/EX5_7.sce
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FOSSEE/Scilab-TBC-Uploads
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refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
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EX5_7.sce
//Example5.7 // Determine the bias current of inverting and non-inverting clc; clear; close; Ios = 5 ; //nA // input offset current Ib = 30 ; //nA // input bias current // the input bias current of an op-amp is //Ib =(Ib1+Ib2)/(2); // the offset current Ios is define as //Ios = abs(Ib1-Ib2) ; Ib1=Ib-(Ios/2); disp('The current in the inverting input terminal is = '+string(Ib1)+' nA '); Ib2 =Ib+(Ios/2); disp('The current in the non-inverting input terminal is= '+string(Ib2)+' nA ');
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Ex11_11.sce
clc(); clear; //Given : ni = 1.5*10^16; // ni for Si in m^-3 mue = 0.135; // mobility of free electrons in m^2/Vs muh = 0.048; // mobility of holes in m^2/Vs Nd = 10^21; // phosphorus atoms/m^3 e = 1.6*10^-19;// charge of an electron in C //(a) n = Nd; // electrons/m^3 //(b) p = ni^2/Nd; // holes/m^3 //(c) sigma = e*(n*mue + p*muh); // conductivity in mho m^-1 rho = 1/sigma; // resistivity in ohm m printf("Major carrier concentration = %.1f x 10^21 electrons/m^3 \n",n*10^-21); printf("Minor carrier concentration = %.2f x 10^11 holes/m^3\n",p*10^-11); printf("Resistivity = %.3f ohm m",rho);
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/EEGetMouvement_NoOutput.sce
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EmSavalle/Expe2Simple
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2023-04-03T22:27:02.041471
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EEGetMouvement_NoOutput.sce
scenario = "EEGetMouvement"; response_matching = simple_matching; default_background_color = 255,255,255; active_buttons =20; button_codes = 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20; #pulse_out = false; pulse_value = 5; pulse_width = 20; # if using parallel port #-----------------Définition des variables-------------------------------------- begin; #-----------------Chargement des sons-------------------------------- sound { wavefile { filename = "800ms/audioMosquito24_0.wav";};} sCalib; sound { wavefile { filename = "800ms/audioMosquito0_m50.wav";};} stimPos; sound { wavefile { filename = "800ms/audioMosquito0_1.wav";};} stimNeg; sound { wavefile { filename = "800ms/audioMosquito0_m50.wav";};} stimPosGauche; sound { wavefile { filename = "800ms/audioMosquito0_1.wav";};} stimNegGauche; sound { wavefile { filename = "800ms/audioMosquito0_50.wav";};} stimPosDroite; sound { wavefile { filename = "800ms/audioMosquito0_m1.wav";};} stimNegDroite; array{ sound { wavefile { filename = "800ms/audioMosquito0_m5.wav";};} sound0_m5; sound { wavefile { filename = "800ms/audioMosquito3_m4.wav";};} sound3_m4; sound { wavefile { filename = "800ms/audioMosquito4_m2.wav";};} sound4_m2; sound { wavefile { filename = "800ms/audioMosquito5_0.wav";};} sound5_0; sound { wavefile { filename = "800ms/audioMosquito4_2.wav";};} sound4_2; sound { wavefile { filename = "800ms/audioMosquito3_4.wav";};} sound3_4; sound { wavefile { filename = "800ms/audioMosquito0_5.wav";};} sound0_5; sound { wavefile { filename = "800ms/audioMosquito0_m8.wav";};} sound0_m8; sound { wavefile { filename = "800ms/audioMosquito4_m7.wav";};} sound4_m7; sound { wavefile { filename = "800ms/audioMosquito7_m4.wav";};} sound7_m4; sound { wavefile { filename = "800ms/audioMosquito8_0.wav";};} sound8_0; sound { wavefile { filename = "800ms/audioMosquito7_4.wav";};} sound7_4; sound { wavefile { filename = "800ms/audioMosquito4_7.wav";};} sound4_7; sound { wavefile { filename = "800ms/audioMosquito0_8.wav";};} sound0_8; sound { wavefile { filename = "800ms/audioMosquito0_m14.wav";};} sound0_m14; sound { wavefile { filename = "800ms/audioMosquito7_m12.wav";};} sound7_m12; sound { wavefile { filename = "800ms/audioMosquito12_m7.wav";};} sound12_m7; sound { wavefile { filename = "800ms/audioMosquito14_0.wav";};} sound14_0; sound { wavefile { filename = "800ms/audioMosquito12_7.wav";};} sound12_7; sound { wavefile { filename = "800ms/audioMosquito7_12.wav";};} sound7_12; sound { wavefile { filename = "800ms/audioMosquito0_14.wav";};} sound0_14; sound { wavefile { filename = "800ms/audioMosquito0_m24.wav";};} sound0_m24; sound { wavefile { filename = "800ms/audioMosquito12_m21.wav";};} sound12_m21; sound { wavefile { filename = "800ms/audioMosquito21_m12.wav";};} sound21_m12; sound { wavefile { filename = "800ms/audioMosquito24_0.wav";};} sound24_0; sound { wavefile { filename = "800ms/audioMosquito21_12.wav";};} sound21_12; sound { wavefile { filename = "800ms/audioMosquito12_21.wav";};} sound12_21; sound { wavefile { filename = "800ms/audioMosquito0_24.wav";};} sound0_24; sound { wavefile { filename = "800ms/audioMosquito0_m41.wav";};} sound0_m41; sound { wavefile { filename = "800ms/audioMosquito21_m36.wav";};} sound21_m36; sound { wavefile { filename = "800ms/audioMosquito36_m20.wav";};} sound36_m20; sound { wavefile { filename = "800ms/audioMosquito41_0.wav";};} sound41_0; sound { wavefile { filename = "800ms/audioMosquito36_20.wav";};} sound36_20; sound { wavefile { filename = "800ms/audioMosquito21_36.wav";};} sound21_36; sound { wavefile { filename = "800ms/audioMosquito0_41.wav";};} sound0_41; }sounds; picture {box { height = 100; width = 100; color = 255,0,0; };x=0;y=0;}red; picture {box { height = 100; width = 100; color = 0,255,0; };x=0;y=0;}green; box { height = 1080; width = 1920; color = 255,0,0; }redbox; box { height = 1080; width = 1920; color = 0,255,0; }greenbox; box { height = 1080; width = 1920; color = 0,0,0; }blackbox; #Trial de reponse pendant la trajectoire picture{ display_index = 1; bitmap { filename = "blank.png"; }bp; x = 0 ; y = -300; text { caption = "o"; font_size = 20; font_color = 0,0,0; transparent_color = 255,255,255;}; x = 0; y = 0; }picQuestion; #Trial de pause picture{ text{ caption ="C'est le moment de faire une pause!\n Prenez le temps qu'il vous faut pour souffler,\n et lorsque vous êtes prêt à repartir, appuyez sur [Entrée]"; font_size = 40; font_color = 0,0,0; text_align = align_center; }; x = 0 ; y = 0; }picPause; #Trial de question sur l'anxiété en fin de trajectoire text { caption = "A quel point cette trajectoire a été désagréable?\n 1 : Pas désagréable du tout - 9 : Très désagréable"; font_size = 40; font_color = 0,0,0; text_align = align_center; }ecranDesagreable; #Picture affiché en permanence en arrière plan (utilisé pour la question intra trajectoire) picture { bitmap bp; x = 0; y = -300; text { caption = "o"; font_size = 20; font_color = 0,0,0; transparent_color = 255,255,255;}; x = 0; y = 0; } default; #Textes pour les infos de trajectoires text { caption = "Trajectoire suivante :"; font_size = 40; font_color = 0,0,0; text_align = align_center; } textPreTraj1; text { caption = "Elle sera courte"; font_size = 40; font_color = 0,0,0; text_align = align_center; } textPreTrajLongueur; text { caption = "Elle aura x% de chances de finir par vous piquer"; font_size = 40; font_color = 0,0,0; text_align = align_center; } textPreTrajObjectif; #---------------Trials------------- #Trials d'initialisation trial{ #Choix de la latéralité de la cible négative stimulus_event{ picture{ text{ caption = "Choisissez la position cible :\n 1 : Gauche \n 2 : Droite"; font_color = 0,0,0; font_size = 40; }; x = 0 ; y = 0 ; }; response_active = true; duration = response; deltat = 10; }; }trialInit; trial{ #Information sur la main dominante du sujet stimulus_event{ picture{ text{ caption = "Quel est la main dominante du sujet :\n 1 : Gauche \n 2 : Droite"; font_color = 0,0,0; font_size = 40; }; x = 0 ; y = 0 ; }; response_active = true; duration = response; deltat = 10; }; }trialMain; #Trial d'explication de l'expérience trial{ picture{ bitmap { filename = "Preparation/Preparation1.png";};x = 0 ; y = 0;}; time = 0; duration = response; picture{bitmap { filename = "Preparation/InfoTraj.png";};x = 0 ; y = 0;}; deltat = 0; duration = response; picture{bitmap { filename = "Preparation/InfoTraj2.png";};x = 0 ; y = 0;}; deltat = 0; duration = response; picture{bitmap { filename = "Preparation/InfoTraj3.png";};x = 0 ; y = 0;}; deltat = 0; duration = response; picture{bitmap { filename = "Preparation/InstructionQuestion.png";};x = 0 ; y = 0;}; deltat = 0; duration = response; }trialPreparation; #Trial calibration trial { stimulus_event{ picture{ bitmap { filename = "Preparation/EssaiTest.png";}; x = 0; y = 0; }; duration = 1500; time = 0; }; }trialCalibration; trial { picture{bitmap { filename = "Preparation/EssaiTest.png";};x = 0 ; y = 0;}; deltat = 0; duration = response; }essaiTest; trial { picture{bitmap { filename = "Preparation/FinPreparation.png";};x = 0 ; y = 0;}; deltat = 0; duration = response; }trialDebutExpe; #Trials de calibration de niveaux de son trial{ stimulus_event{ picture{ text{ caption = "Nous allons calibrer l'experience en fonction de vos capacitées auditives\nConcentrez vous sur ce que vous entendez et suivez les instructions\nAppuyez sur [Entrée] pour commencer la calibration"; font_color = 0,0,0; font_size = 40; }te; x = 0 ; y = 0 ; }; response_active = true; duration = response; deltat = 10; }; }trialDebCalib; trial{ stimulus_event{ picture{ text{ caption = "Appuyez sur [Entrée] pour passer à la suite"; font_color = 0,0,0; font_size = 40; }tPrep; x = 0 ; y = 0 ; }; response_active = true; duration = response; deltat = 10; }; }trialPrep; trial{ sound sCalib; time = 0; duration = 1000; picture{ text{ caption = "Appuyez sur [Entrée] dès que vous entendez un son"; font_color = 0,0,0; font_size = 40; }t; x = 0; y = 0; }; deltat=0; } trialCalib; #Trial de debut de trajectoire trial{ picture{ text textPreTraj1; x = 0 ; y = 100; text textPreTrajLongueur; x = 0 ; y = 0; bitmap{ filename = "V70.png"; }bpIncert; x = 0; y = -300; #text textPreTrajObjectif; #x = 0 ; y = -100; }tp; time = 0 ; duration = 2000; }trialPreparationTrajectoire; trial{ stimulus_event{ picture{ text{ caption = "Début de la trajectoire"; font_color = 0,0,0; font_size = 40; }; x = 0 ; y = 0 ; }; duration = 1000; }; }trialDebutTrajectoire; # Trial presentant un son de moustique trial{ stimulus_event{ sound sound36_20; time = 0; #duration = 800; }s1; stimulus_event{ picture{ bitmap { filename = "moustique.jpg";};x = 0 ; y = 0; bitmap bp; x = 0 ; y = -300; text { caption = "o"; font_size = 20; font_color = 0,0,0; transparent_color = 255,255,255;}tSouris; x = 0; y = 0; }picM; code = "picM"; time = 0; #duration = 800; }; }trialSon; #Trial de pause entre sons trial{ stimulus_event{ picture picPause; }; }trialPause; #Trial Question pendant Son trial{ picture picM; }trialPicSon; #Trial posant la question lié au risque de piqûre trial{ picture picQuestion; }trialQuestion; #Trial portant le stimulus final (a modifier avec le stimulateur) trial{ picture { box blackbox; x = 0 ; y = 0 ; } pic2; stimulus_event{ picture{ text{ caption = "Fin de trajectoires"; font_color = 0,0,0; font_size = 40; }tF; x = 0 ; y = 0 ; }; time=0; duration = 1000; }seFinal; }trialStimulusFinal; #Trial pour la stimulation électrique trial{ picture { box blackbox; x = 0 ; y = 0 ; } picPiqure; stimulus_event{ nothing{}; port_code = 1; port = 1; time = 0; code = "stim 1"; }sePiqure; }trialPiqure; #Trial pour la question sur l'anxiété post trajectoire trial{ stimulus_event{ picture { text ecranDesagreable; x = 0 ; y = 0 ; }pictureDesagreable; time = 0; response_active = true; duration = response; }seDesagreable; }trialDesagreable; #Trial de fin de trajectoire trial{ stimulus_event{ picture{ text{ caption = "Fin de trajectoires"; font_color = 0,0,0; font_size = 40; }; x = 0 ; y = 0 ; }; duration = 1000; }; }trialFinTrajectoire; begin_pcl; #Fonctions de marquage sub int triggerTrajectoire (int traj_num) begin return traj_num*2+2; end; sub int triggerSon (int son_num) begin #return son_num+64; return 2; end; sub int triggerTrajectoireV2(bool valence, bool valenceReel, bool longueur, int chance) begin int vval = 0,vvalR = 0,vLong = 0, vChance = 0; if(valence == true) then vval=1; end; if(valenceReel == true) then vvalR=1; end; if(longueur == true) then vLong=1; end; if(chance == 90) then vChance=1; end; int trig = 128 + vval*64 + vvalR * 32 + vLong * 16 + vChance*8; return trig; end; sub int triggerSonV2(int position) begin return position *2; end; sub int updatePosition begin mouse mse = response_manager.get_mouse( 1 ); mse.poll(); int selec = 0; int posx=mse.x(); int posy=mse.y(); picQuestion.set_part_x(2, posx); picQuestion.set_part_y(2, posy); picM.set_part_x(3, posx); picM.set_part_y(3, posy); if(-200 > posy && posy > -400)then if(-600 <= posx && posx <= -434)then selec = 1; end; if(-433 <= posx && posx <=-260)then selec = 2; end; if(-260 <= posx && posx <=-90)then selec = 3; end; if(-91 <= posx && posx <=90)then selec = 4; end; if(91 <= posx && posx <=255)then selec = 5; end; if(256 <= posx && posx <=430)then selec = 6; end; if(431 <= posx && posx <=600)then selec = 7; end; end; return selec; end; sub array<int,1> calcPosCursor(array <int> infoCursor[12], string cursorFName) begin int cursorPos = infoCursor[1]; int lastCursorPos = infoCursor[2]; int countPos = infoCursor[3]; int countNeg = infoCursor[4]; int countn3 = infoCursor[5]; int countn2 = infoCursor[6]; int countn1 = infoCursor[7]; int countne = infoCursor[8]; int countp1 = infoCursor[9]; int countp2 = infoCursor[10]; int countp3 = infoCursor[11]; int countClic = infoCursor[12]; #Selection position curseur if(response_manager.total_response_count( 11 ) > countNeg) then cursorPos = cursorPos+(response_manager.total_response_count( 11 ) - countNeg); countNeg = response_manager.total_response_count( 11 ); end; if(response_manager.total_response_count( 10 ) > countPos) then cursorPos = cursorPos-(response_manager.total_response_count( 10 ) - countPos); countPos = response_manager.total_response_count( 10 ); end; if(cursorPos < 1) then cursorPos = 1; end; if (cursorPos > 7) then cursorPos = 7; end; if (countn3 != response_manager.total_response_count( 13 )) then countn3 = response_manager.total_response_count( 13 ); cursorPos=1; end; if (countn2 != response_manager.total_response_count( 14 ))then countn2 = response_manager.total_response_count( 14 ); cursorPos=2; end; if (countn1 != response_manager.total_response_count( 15 ))then countn1 = response_manager.total_response_count( 15 ); cursorPos=3; end; if (countne != response_manager.total_response_count( 16 ))then countne = response_manager.total_response_count( 16 ); cursorPos=4; end; if (countp1 != response_manager.total_response_count( 17 ))then countp1 = response_manager.total_response_count( 17 ); cursorPos=5; end; if (countp2 != response_manager.total_response_count( 18 ))then countp2 = response_manager.total_response_count( 18 ); cursorPos=6; end; if (countp3 != response_manager.total_response_count( 19 ))then countp3 = response_manager.total_response_count( 19 ); cursorPos=7; end; int sel = updatePosition(); if(sel != 0 && countClic != response_manager.total_response_count( 20 )) then cursorPos = sel; countClic = response_manager.total_response_count( 20 ); end; if(lastCursorPos != cursorPos) then bp.unload(); bp.set_filename(cursorFName+string(cursorPos)+".jpg"); bp.load(); lastCursorPos = cursorPos; end; array<int> ret[12] = {0,0,0,0,0,0,0,0,0,0,0,0}; ret[1] = cursorPos; ret[2] = lastCursorPos; ret[3] = countPos; ret[4] = countNeg; ret[5] = countn3; ret[6] = countn2; ret[7] = countn1; ret[8] = countne; ret[9] = countp1; ret[10] = countp2; ret[11] = countp3; ret[12] = countClic; return ret; end; #Chargement du fichier log output_file ofile1 = new output_file; string nameFile = logfile.subject()+"ReponseStimuli"; string nameFileTest = nameFile; int cptname = 1; loop until !file_exists(logfile_directory +nameFileTest+".txt") begin nameFileTest = nameFile+string(cptname); cptname=cptname+1; end; ofile1.open(nameFileTest+".txt" , true ); set_system_volume(1,1); int count = response_manager.total_response_count( 12 ); bool calibSonore = true; bool presentation = false; bool essaiT = true; bool outputAvailable = false; bool mosquitoCartoon = true; #Ajoute l'image du moustique gentil/méchant dans les infos de traj #Gestion de la souris mouse mse = response_manager.get_mouse( 1 ); int max_x = display_device.width() / 2; int min_x = -max_x; int max_y = display_device.height() / 2; int min_y = -max_y; mse.set_min_max( 1, min_x, max_x ); mse.set_min_max( 2, min_y, max_y ); mse.set_restricted( 1, true ); mse.set_restricted( 2, true ); #Ouverture du port parallel #if(outputAvailable == true) then output_port output = output_port_manager.get_port(1); #end; #Tableaux contenant les informations de trajectoires array <int> positions[35][2] = {{0,-5},{3,-4},{4,-2},{5,0},{4,2},{3,4},{0,5},{0,-8},{4,-7},{7,-4},{8,0},{7,4},{4,7},{0,8},{0,-14},{7,-12},{12,-7},{14,0},{12,7},{7,12},{0,14},{0,-24},{12,-21},{21,-12},{24,0},{21,12},{12,21},{0,24},{0,-41},{21,-36},{36,-20},{41,0},{36,20},{21,36},{0,41}}; array <int> trajectoiresN[100][12] ={{25,33,27,33,25,24,30,-1,-1,-1,-1,-1},{25,33,32,24,23,16,17,11,12,20,12,6},{25,26,34,28,20,26,33,32,24,30,-1,-1},{25,19,20,28,20,13,6,-1,-1,-1,-1,-1},{25,32,24,23,31,24,25,18,10,16,24,30},{25,32,26,27,20,27,26,19,20,13,6,-1},{25,24,25,17,24,23,29,-1,-1,-1,-1,-1},{25,26,19,13,14,21,27,28,20,13,7,-1},{25,31,32,31,23,24,30,24,16,23,29,-1},{25,32,31,32,26,33,32,25,17,25,19,13},{25,31,25,24,31,30,29,-1,-1,-1,-1,-1},{25,33,32,25,31,24,31,30,29,-1,-1,-1},{25,32,26,25,31,25,18,12,6,-1,-1,-1},{25,17,10,4,3,4,3,10,9,16,24,30},{25,33,32,24,25,17,11,12,6,-1,-1,-1},{25,17,25,32,25,17,25,24,30,-1,-1,-1},{25,18,19,25,19,12,13,7,-1,-1,-1,-1},{25,26,18,19,11,19,26,20,12,11,5,6},{25,32,33,32,24,25,32,31,25,26,20,12},{25,33,26,20,28,27,19,26,25,18,17,23},{25,17,16,10,17,25,24,30,-1,-1,-1,-1},{25,24,32,26,32,26,19,13,7,-1,-1,-1},{25,31,24,18,10,4,12,13,5,12,13,7},{25,32,26,19,27,34,26,20,19,13,7,-1},{25,19,26,19,18,24,25,17,10,17,16,23},{25,24,17,24,18,19,13,7,-1,-1,-1,-1},{25,26,25,32,31,23,29,-1,-1,-1,-1,-1},{25,18,19,18,10,11,17,24,30,-1,-1,-1},{25,24,16,24,25,32,26,33,34,27,21,13},{25,24,32,25,19,13,7,-1,-1,-1,-1,-1},{25,24,31,32,25,19,25,32,24,23,29,-1},{25,26,25,33,27,19,13,7,-1,-1,-1,-1},{25,31,32,31,24,31,32,24,18,19,13,7},{25,31,25,31,23,17,18,24,17,11,19,13},{25,33,32,26,18,12,6,-1,-1,-1,-1,-1},{25,31,23,31,25,32,31,23,29,-1,-1,-1},{25,18,25,17,18,25,31,23,29,-1,-1,-1},{25,19,26,34,28,34,28,27,20,12,18,24},{25,17,16,23,24,18,26,25,33,32,24,30},{25,19,27,33,32,24,30,-1,-1,-1,-1,-1},{25,18,19,13,19,27,33,27,19,18,24,30},{25,31,30,24,25,33,32,24,30,-1,-1,-1},{25,32,33,25,19,20,13,7,-1,-1,-1,-1},{25,32,25,19,20,12,5,6,-1,-1,-1,-1},{25,17,25,31,23,22,15,9,10,18,12,6},{25,24,17,18,25,18,12,6,-1,-1,-1,-1},{25,31,32,26,19,13,7,-1,-1,-1,-1,-1},{25,17,16,8,9,2,3,11,12,6,7,-1},{25,18,19,27,21,27,34,27,19,13,6,7},{25,18,10,11,17,10,4,10,4,11,5,6},{25,32,31,32,31,23,29,-1,-1,-1,-1,-1},{25,26,20,28,20,13,7,-1,-1,-1,-1,-1},{25,18,24,32,33,26,18,19,12,13,7,-1},{25,33,34,26,32,33,26,33,26,20,13,7},{25,17,18,25,24,25,31,25,17,23,31,30},{25,18,12,11,12,20,12,11,5,13,7,-1},{25,24,32,24,31,25,18,19,13,14,7,-1},{25,19,12,4,12,18,17,10,18,12,6,-1},{25,32,25,19,18,12,6,-1,-1,-1,-1,-1},{25,32,26,25,19,11,5,6,-1,-1,-1,-1},{25,33,26,18,17,23,29,-1,-1,-1,-1,-1},{25,19,12,18,10,16,23,29,-1,-1,-1,-1},{25,31,25,31,30,22,29,30,29,30,-1,-1},{25,32,25,26,19,13,6,-1,-1,-1,-1,-1},{25,24,32,31,23,17,18,12,6,-1,-1,-1},{25,19,20,28,34,33,25,31,30,-1,-1,-1},{25,32,25,31,24,18,12,6,-1,-1,-1,-1},{25,24,16,23,24,30,23,31,32,31,23,29},{25,24,25,32,24,32,25,19,12,6,7,-1},{25,18,25,26,18,11,5,6,-1,-1,-1,-1},{25,26,20,28,27,21,20,12,11,17,24,30},{25,24,32,33,26,25,31,23,17,18,12,6},{25,18,19,27,19,25,24,30,29,-1,-1,-1},{25,32,26,18,19,13,14,21,20,12,18,24},{25,32,33,25,33,25,31,30,-1,-1,-1,-1},{25,18,25,24,31,25,18,25,19,25,24,30},{25,24,16,24,31,25,19,13,7,-1,-1,-1},{25,33,25,26,20,27,35,34,26,19,18,24},{25,26,33,32,24,17,24,25,19,13,7,-1},{25,17,16,17,24,18,19,26,19,26,18,24},{25,17,23,22,23,22,23,30,31,24,18,12},{25,31,32,24,18,11,12,6,7,-1,-1,-1},{25,19,11,12,5,13,14,13,20,19,25,24},{25,19,18,24,16,22,15,22,23,29,22,29},{25,26,19,27,33,26,25,31,30,-1,-1,-1},{25,17,11,10,17,23,16,24,18,12,6,-1},{25,33,34,27,28,21,20,12,18,24,30,-1},{25,31,25,18,26,20,12,6,-1,-1,-1,-1},{25,18,26,19,27,21,14,6,-1,-1,-1,-1},{25,18,24,16,15,9,17,18,12,18,24,30},{25,17,18,26,25,17,10,11,18,24,23,29},{25,31,25,31,24,18,24,18,19,13,14,7},{25,18,10,17,11,12,6,-1,-1,-1,-1,-1},{25,31,25,32,25,24,30,29,-1,-1,-1,-1},{25,31,32,31,24,18,19,13,7,-1,-1,-1},{25,33,25,26,34,33,34,28,27,19,12,6},{25,19,11,10,17,23,29,-1,-1,-1,-1,-1},{25,24,30,23,29,-1,-1,-1,-1,-1,-1,-1},{25,31,32,25,19,25,24,30,-1,-1,-1,-1},{25,19,12,19,18,24,23,29,-1,-1,-1,-1}}; array <int> trajectoiresInv[100][12] ={{25,31,23,31,25,26,34,-1,-1,-1,-1,-1},{25,31,32,26,27,20,19,11,10,16,10,2},{25,24,30,22,16,24,31,32,26,34,-1,-1},{25,17,16,22,16,9,2,-1,-1,-1,-1,-1},{25,32,26,27,33,26,25,18,12,20,26,34},{25,32,24,23,16,23,24,17,16,9,2,-1},{25,26,25,19,26,27,35,-1,-1,-1,-1,-1},{25,24,17,9,8,15,23,22,16,9,1,-1},{25,33,32,33,27,26,34,26,20,27,35,-1},{25,32,33,32,24,31,32,25,19,25,17,9},{25,33,25,26,33,34,35,-1,-1,-1,-1,-1},{25,31,32,25,33,26,33,34,35,-1,-1,-1},{25,32,24,25,33,25,18,10,2,-1,-1,-1},{25,19,12,4,5,4,5,12,13,20,26,34},{25,31,32,26,25,19,11,10,2,-1,-1,-1},{25,19,25,32,25,19,25,26,34,-1,-1,-1},{25,18,17,25,17,10,9,1,-1,-1,-1,-1},{25,24,18,17,11,17,24,16,10,11,3,2},{25,32,31,32,26,25,32,33,25,24,16,10},{25,31,24,16,22,23,17,24,25,18,19,27},{25,19,20,12,19,25,26,34,-1,-1,-1,-1},{25,26,32,24,32,24,17,9,1,-1,-1,-1},{25,33,26,18,12,4,10,9,3,10,9,1},{25,32,24,17,23,30,24,16,17,9,1,-1},{25,17,24,17,18,26,25,19,12,19,20,27},{25,26,19,26,18,17,9,1,-1,-1,-1,-1},{25,24,25,32,33,27,35,-1,-1,-1,-1,-1},{25,18,17,18,12,11,19,26,34,-1,-1,-1},{25,26,20,26,25,32,24,31,30,23,15,9},{25,26,32,25,17,9,1,-1,-1,-1,-1,-1},{25,26,33,32,25,17,25,32,26,27,35,-1},{25,24,25,31,23,17,9,1,-1,-1,-1,-1},{25,33,32,33,26,33,32,26,18,17,9,1},{25,33,25,33,27,19,18,26,19,11,17,9},{25,31,32,24,18,10,2,-1,-1,-1,-1,-1},{25,33,27,33,25,32,33,27,35,-1,-1,-1},{25,18,25,19,18,25,33,27,35,-1,-1,-1},{25,17,24,30,22,30,22,23,16,10,18,26},{25,19,20,27,26,18,24,25,31,32,26,34},{25,17,23,31,32,26,34,-1,-1,-1,-1,-1},{25,18,17,9,17,23,31,23,17,18,26,34},{25,33,34,26,25,31,32,26,34,-1,-1,-1},{25,32,31,25,17,16,9,1,-1,-1,-1,-1},{25,32,25,17,16,10,3,2,-1,-1,-1,-1},{25,19,25,33,27,28,21,13,12,18,10,2},{25,26,19,18,25,18,10,2,-1,-1,-1,-1},{25,33,32,24,17,9,1,-1,-1,-1,-1,-1},{25,19,20,14,13,6,5,11,10,2,1,-1},{25,18,17,23,15,23,30,23,17,9,2,1},{25,18,12,11,19,12,4,12,4,11,3,2},{25,32,33,32,33,27,35,-1,-1,-1,-1,-1},{25,24,16,22,16,9,1,-1,-1,-1,-1,-1},{25,18,26,32,31,24,18,17,10,9,1,-1},{25,31,30,24,32,31,24,31,24,16,9,1},{25,19,18,25,26,25,33,25,19,27,33,34},{25,18,10,11,10,16,10,11,3,9,1,-1},{25,26,32,26,33,25,18,17,9,8,1,-1},{25,17,10,4,10,18,19,12,18,10,2,-1},{25,32,25,17,18,10,2,-1,-1,-1,-1,-1},{25,32,24,25,17,11,3,2,-1,-1,-1,-1},{25,31,24,18,19,27,35,-1,-1,-1,-1,-1},{25,17,10,18,12,20,27,35,-1,-1,-1,-1},{25,33,25,33,34,28,35,34,35,34,-1,-1},{25,32,25,24,17,9,2,-1,-1,-1,-1,-1},{25,26,32,33,27,19,18,10,2,-1,-1,-1},{25,17,16,22,30,31,25,33,34,-1,-1,-1},{25,32,25,33,26,18,10,2,-1,-1,-1,-1},{25,26,20,27,26,34,27,33,32,33,27,35},{25,26,25,32,26,32,25,17,10,2,1,-1},{25,18,25,24,18,11,3,2,-1,-1,-1,-1},{25,24,16,22,23,15,16,10,11,19,26,34},{25,26,32,31,24,25,33,27,19,18,10,2},{25,18,17,23,17,25,26,34,35,-1,-1,-1},{25,32,24,18,17,9,8,15,16,10,18,26},{25,32,31,25,31,25,33,34,-1,-1,-1,-1},{25,18,25,26,33,25,18,25,17,25,26,34},{25,26,20,26,33,25,17,9,1,-1,-1,-1},{25,31,25,24,16,23,29,30,24,17,18,26},{25,24,31,32,26,19,26,25,17,9,1,-1},{25,19,20,19,26,18,17,24,17,24,18,26},{25,19,27,28,27,28,27,34,33,26,18,10},{25,33,32,26,18,11,10,2,1,-1,-1,-1},{25,17,11,10,3,9,8,9,16,17,25,26},{25,17,18,26,20,28,21,28,27,35,28,35},{25,24,17,23,31,24,25,33,34,-1,-1,-1},{25,19,11,12,19,27,20,26,18,10,2,-1},{25,31,30,23,22,15,16,10,18,26,34,-1},{25,33,25,18,24,16,10,2,-1,-1,-1,-1},{25,18,24,17,23,15,8,2,-1,-1,-1,-1},{25,18,26,20,21,13,19,18,10,18,26,34},{25,19,18,24,25,19,12,11,18,26,27,35},{25,33,25,33,26,18,26,18,17,9,8,1},{25,18,12,19,11,10,2,-1,-1,-1,-1,-1},{25,33,25,32,25,26,34,35,-1,-1,-1,-1},{25,33,32,33,26,18,17,9,1,-1,-1,-1},{25,31,25,24,30,31,30,22,23,17,10,2},{25,17,11,12,19,27,35,-1,-1,-1,-1,-1},{25,26,34,27,35,-1,-1,-1,-1,-1,-1,-1},{25,33,32,25,17,25,26,34,-1,-1,-1,-1},{25,17,10,17,18,26,27,35,-1,-1,-1,-1}}; array <int> mouvementsN[100][11] ={{7,1,9,3,6,9,-1,-1,-1,-1,-1},{7,6,3,6,2,4,1,4,7,3,1},{4,7,1,3,9,8,6,3,9,-1,-1},{1,4,7,3,2,2,-1,-1,-1,-1,-1},{8,3,6,7,2,4,2,3,9,7,9},{8,1,4,2,8,6,2,4,2,2,-1},{6,4,3,8,6,9,-1,-1,-1,-1,-1},{4,2,1,4,8,9,4,3,2,1,-1},{9,4,6,3,4,9,1,3,8,9,-1},{8,6,4,1,8,6,2,3,7,1,1},{9,1,6,8,6,6,-1,-1,-1,-1,-1},{7,6,2,9,2,8,6,6,-1,-1,-1},{8,1,6,9,1,2,1,1,-1,-1,-1},{3,2,1,6,4,6,8,6,8,7,9},{7,6,3,4,3,1,4,1,-1,-1,-1},{3,7,8,2,3,7,6,9,-1,-1,-1},{2,4,9,1,2,4,1,-1,-1,-1,-1},{4,3,4,3,7,8,1,3,6,1,4},{8,4,6,3,4,8,6,1,4,1,3},{7,2,1,7,6,3,8,6,2,6,9},{3,6,1,8,7,6,9,-1,-1,-1,-1},{6,7,1,9,1,2,1,1,-1,-1,-1},{9,2,1,3,1,7,4,3,8,4,1},{8,1,2,7,8,3,1,6,1,1,-1},{1,8,2,6,9,4,3,2,8,6,8},{6,2,8,1,4,1,1,-1,-1,-1,-1},{4,6,8,6,3,9,-1,-1,-1,-1,-1},{2,4,6,3,4,9,8,9,-1,-1,-1},{6,3,7,4,8,1,8,4,2,1,3},{6,7,2,1,1,1,-1,-1,-1,-1,-1},{6,8,4,2,1,9,8,3,6,9,-1},{4,6,7,1,3,1,1,-1,-1,-1,-1},{9,4,6,2,8,4,3,1,4,1,1},{9,1,9,3,1,4,9,2,1,7,1},{7,6,1,3,1,1,-1,-1,-1,-1,-1},{9,3,7,1,8,6,3,9,-1,-1,-1},{2,8,3,4,8,9,3,9,-1,-1,-1},{1,8,7,1,9,1,6,2,3,9,9},{3,6,8,4,1,7,6,7,6,3,9},{1,7,9,6,3,9,-1,-1,-1,-1,-1},{2,4,1,9,7,9,1,3,6,9,9},{9,6,1,4,7,6,3,9,-1,-1,-1},{8,4,3,1,4,2,1,-1,-1,-1,-1},{8,2,1,4,3,2,4,-1,-1,-1,-1},{3,7,9,3,6,2,1,4,7,1,1},{6,2,4,8,2,1,1,-1,-1,-1,-1},{9,4,1,2,1,1,-1,-1,-1,-1,-1},{3,6,3,4,2,4,7,4,1,4,-1},{2,4,7,1,9,8,2,3,1,2,4},{2,3,4,9,2,1,9,1,8,1,4},{8,6,4,6,3,9,-1,-1,-1,-1,-1},{4,1,7,3,2,1,-1,-1,-1,-1,-1},{2,9,7,4,2,3,4,2,4,1,-1},{7,4,3,9,4,2,8,2,1,2,1},{3,4,8,6,4,9,1,3,9,7,6},{2,1,6,4,7,3,6,1,7,1,-1},{6,7,3,8,1,2,4,1,4,2,-1},{1,2,3,7,9,6,2,7,1,1,-1},{8,2,1,6,1,1,-1,-1,-1,-1,-1},{8,1,6,1,3,1,4,-1,-1,-1,-1},{7,2,3,6,9,9,-1,-1,-1,-1,-1},{1,2,9,3,9,8,9,-1,-1,-1,-1},{9,1,9,6,3,8,4,6,4,-1,-1},{8,2,4,2,1,2,-1,-1,-1,-1,-1},{6,7,6,3,1,4,1,1,-1,-1,-1},{1,4,7,9,6,3,9,6,-1,-1,-1},{8,2,9,2,1,1,1,-1,-1,-1,-1},{6,3,8,4,9,2,7,4,6,3,9},{6,4,8,3,7,2,1,2,1,4,-1},{2,8,4,3,2,1,4,-1,-1,-1,-1},{4,1,7,6,1,6,3,6,9,8,9},{6,7,4,2,6,9,3,1,4,1,1},{2,4,7,3,9,6,9,6,-1,-1,-1},{8,1,3,4,1,4,8,6,3,9,9},{8,4,3,7,3,9,6,-1,-1,-1,-1},{2,8,6,8,1,2,8,1,9,6,9},{6,3,7,8,1,1,1,1,-1,-1,-1},{7,3,4,1,8,7,6,3,2,6,9},{4,8,6,3,2,8,4,1,1,1,-1},{3,6,4,8,1,4,8,2,8,3,9},{3,9,6,4,6,4,8,4,2,1,1},{9,4,3,1,2,4,1,4,-1,-1,-1},{1,3,4,2,7,4,6,8,6,9,6},{1,6,9,3,9,2,8,4,9,2,8},{4,2,7,9,2,6,9,6,-1,-1,-1},{3,1,6,8,9,2,7,1,1,1,-1},{7,4,2,4,2,6,3,9,9,9,-1},{9,1,2,7,1,3,1,-1,-1,-1,-1},{2,7,2,7,1,2,3,-1,-1,-1,-1},{2,9,3,6,1,7,4,1,9,9,9},{3,4,7,6,3,2,4,8,9,6,9},{9,1,9,2,1,9,1,4,1,4,2},{2,3,8,1,4,1,-1,-1,-1,-1,-1},{9,1,8,2,6,9,6,-1,-1,-1,-1},{9,4,6,2,1,4,1,1,-1,-1,-1},{7,3,4,7,6,4,1,6,3,2,1},{1,3,6,8,9,9,-1,-1,-1,-1,-1},{6,9,2,9,-1,-1,-1,-1,-1,-1,-1},{9,4,2,1,9,6,9,-1,-1,-1,-1},{1,2,8,6,9,6,9,-1,-1,-1,-1}}; array <int> mouvementsInv[100][11] ={{9,3,7,1,4,7,-1,-1,-1,-1,-1},{9,4,1,4,2,6,3,6,9,1,3},{6,9,3,1,7,8,4,1,7,-1,-1},{3,6,9,1,2,2,-1,-1,-1,-1,-1},{8,1,4,9,2,6,2,1,7,9,7},{8,3,6,2,8,4,2,6,2,2,-1},{4,6,1,8,4,7,-1,-1,-1,-1,-1},{6,2,3,6,8,7,6,1,2,3,-1},{7,6,4,1,6,7,3,1,8,7,-1},{8,4,6,3,8,4,2,1,9,3,3},{7,3,4,8,4,4,-1,-1,-1,-1,-1},{9,4,2,7,2,8,4,4,-1,-1,-1},{8,3,4,7,3,2,3,3,-1,-1,-1},{1,2,3,4,6,4,8,4,8,9,7},{9,4,1,6,1,3,6,3,-1,-1,-1},{1,9,8,2,1,9,4,7,-1,-1,-1},{2,6,7,3,2,6,3,-1,-1,-1,-1},{6,1,6,1,9,8,3,1,4,3,6},{8,6,4,1,6,8,4,3,6,3,1},{9,2,3,9,4,1,8,4,2,4,7},{1,4,3,8,9,4,7,-1,-1,-1,-1},{4,9,3,7,3,2,3,3,-1,-1,-1},{7,2,3,1,3,9,6,1,8,6,3},{8,3,2,9,8,1,3,4,3,3,-1},{3,8,2,4,7,6,1,2,8,4,8},{4,2,8,3,6,3,3,-1,-1,-1,-1},{6,4,8,4,1,7,-1,-1,-1,-1,-1},{2,6,4,1,6,7,8,7,-1,-1,-1},{4,1,9,6,8,3,8,6,2,3,1},{4,9,2,3,3,3,-1,-1,-1,-1,-1},{4,8,6,2,3,7,8,1,4,7,-1},{6,4,9,3,1,3,3,-1,-1,-1,-1},{7,6,4,2,8,6,1,3,6,3,3},{7,3,7,1,3,6,7,2,3,9,3},{9,4,3,1,3,3,-1,-1,-1,-1,-1},{7,1,9,3,8,4,1,7,-1,-1,-1},{2,8,1,6,8,7,1,7,-1,-1,-1},{3,8,9,3,7,3,4,2,1,7,7},{1,4,8,6,3,9,4,9,4,1,7},{3,9,7,4,1,7,-1,-1,-1,-1,-1},{2,6,3,7,9,7,3,1,4,7,7},{7,4,3,6,9,4,1,7,-1,-1,-1},{8,6,1,3,6,2,3,-1,-1,-1,-1},{8,2,3,6,1,2,6,-1,-1,-1,-1},{1,9,7,1,4,2,3,6,9,3,3},{4,2,6,8,2,3,3,-1,-1,-1,-1},{7,6,3,2,3,3,-1,-1,-1,-1,-1},{1,4,1,6,2,6,9,6,3,6,-1},{2,6,9,3,7,8,2,1,3,2,6},{2,1,6,7,2,3,7,3,8,3,6},{8,4,6,4,1,7,-1,-1,-1,-1,-1},{6,3,9,1,2,3,-1,-1,-1,-1,-1},{2,7,9,6,2,1,6,2,6,3,-1},{9,6,1,7,6,2,8,2,3,2,3},{1,6,8,4,6,7,3,1,7,9,4},{2,3,4,6,9,1,4,3,9,3,-1},{4,9,1,8,3,2,6,3,6,2,-1},{3,2,1,9,7,4,2,9,3,3,-1},{8,2,3,4,3,3,-1,-1,-1,-1,-1},{8,3,4,3,1,3,6,-1,-1,-1,-1},{9,2,1,4,7,7,-1,-1,-1,-1,-1},{3,2,7,1,7,8,7,-1,-1,-1,-1},{7,3,7,4,1,8,6,4,6,-1,-1},{8,2,6,2,3,2,-1,-1,-1,-1,-1},{4,9,4,1,3,6,3,3,-1,-1,-1},{3,6,9,7,4,1,7,4,-1,-1,-1},{8,2,7,2,3,3,3,-1,-1,-1,-1},{4,1,8,6,7,2,9,6,4,1,7},{4,6,8,1,9,2,3,2,3,6,-1},{2,8,6,1,2,3,6,-1,-1,-1,-1},{6,3,9,4,3,4,1,4,7,8,7},{4,9,6,2,4,7,1,3,6,3,3},{2,6,9,1,7,4,7,4,-1,-1,-1},{8,3,1,6,3,6,8,4,1,7,7},{8,6,1,9,1,7,4,-1,-1,-1,-1},{2,8,4,8,3,2,8,3,7,4,7},{4,1,9,8,3,3,3,3,-1,-1,-1},{9,1,6,3,8,9,4,1,2,4,7},{6,8,4,1,2,8,6,3,3,3,-1},{1,4,6,8,3,6,8,2,8,1,7},{1,7,4,6,4,6,8,6,2,3,3},{7,6,1,3,2,6,3,6,-1,-1,-1},{3,1,6,2,9,6,4,8,4,7,4},{3,4,7,1,7,2,8,6,7,2,8},{6,2,9,7,2,4,7,4,-1,-1,-1},{1,3,4,8,7,2,9,3,3,3,-1},{9,6,2,6,2,4,1,7,7,7,-1},{7,3,2,9,3,1,3,-1,-1,-1,-1},{2,9,2,9,3,2,1,-1,-1,-1,-1},{2,7,1,4,3,9,6,3,7,7,7},{1,6,9,4,1,2,6,8,7,4,7},{7,3,7,2,3,7,3,6,3,6,2},{2,1,8,3,6,3,-1,-1,-1,-1,-1},{7,3,8,2,4,7,4,-1,-1,-1,-1},{7,6,4,2,3,6,3,3,-1,-1,-1},{9,1,6,9,4,6,3,4,1,2,3},{3,1,4,8,7,7,-1,-1,-1,-1,-1},{4,7,2,7,-1,-1,-1,-1,-1,-1,-1},{7,6,2,3,7,4,7,-1,-1,-1,-1},{3,2,8,4,7,4,7,-1,-1,-1,-1}}; array <int> pourcent[100]={90,90,90,70,90,70,90,90,70,70,90,90,90,90,70,70,90,90,70,90,70,70,90,70,90,90,70,90,90,70,70,70,70,90,70,70,90,70,70,70,70,70,70,90,90,70,70,70,70,90,70,70,90,70,70,70,70,90,90,90,90,70,90,70,90,90,70,90,70,90,70,70,90,70,90,70,70,90,90,90,70,70,90,70,70,90,70,70,90,90,70,70,70,90,70,90,90,70,70,90}; array <bool> indic[100][2] ={{true,true},{false,true},{true,true},{false,true},{true,true},{false,false},{true,true},{false,true},{true,false},{false,true},{true,true},{true,true},{false,true},{true,true},{false,true},{true,false},{false,true},{false,true},{false,false},{true,true},{true,true},{false,true},{false,false},{false,true},{true,true},{false,true},{true,true},{true,true},{false,true},{false,true},{true,false},{false,false},{false,false},{false,true},{false,true},{true,true},{true,true},{true,true},{true,true},{true,true},{true,false},{true,false},{false,true},{false,true},{false,true},{false,true},{false,false},{false,true},{false,false},{false,false},{true,true},{false,false},{false,true},{false,true},{true,true},{false,false},{false,true},{false,true},{false,true},{false,true},{true,true},{true,true},{true,true},{false,true},{false,true},{true,true},{false,true},{true,false},{false,true},{false,true},{true,true},{false,true},{true,true},{true,true},{true,false},{true,true},{false,true},{true,true},{false,true},{true,true},{false,false},{false,true},{true,true},{true,false},{true,true},{false,true},{true,false},{false,false},{false,true},{true,true},{true,true},{false,false},{false,true},{true,true},{false,true},{false,true},{true,true},{true,true},{true,true},{true,true}}; array <string> conversionMvmIntStr[9] = {"Approche Gauche","Approche","Approche Droite","Gauche","Neutre","Droite","Eloignement Gauche","Eloignement","Eloignement Droite"}; array <int> trajectoires[100][12] ={{25,18,12,11,4,12,18,24,30,-1,-1,-1},{25,17,11,4,12,19,11,5,4,12,6,-1},{25,33,32,33,25,24,30,22,29,-1,-1,-1},{25,33,27,33,25,19,25,18,24,30,-1,-1},{25,33,25,33,26,32,24,30,24,18,12,6},{25,33,34,26,25,26,19,13,6,-1,-1,-1},{25,32,25,19,11,17,24,30,29,-1,-1,-1},{25,24,18,25,26,19,26,25,18,12,6,-1},{25,19,26,34,33,25,31,24,30,-1,-1,-1},{25,31,23,16,24,17,11,12,6,-1,-1,-1},{25,24,16,23,22,15,9,15,23,30,-1,-1},{25,24,18,25,24,30,31,25,19,13,7,-1},{25,18,26,25,26,25,17,24,30,24,23,29},{25,26,25,18,19,18,24,31,23,29,-1,-1},{25,18,17,25,17,16,23,31,30,29,-1,-1},{25,31,24,18,19,13,7,-1,-1,-1,-1,-1},{25,32,31,32,25,26,18,19,12,6,-1,-1},{25,32,26,18,19,12,6,-1,-1,-1,-1,-1},{25,33,34,26,33,26,20,13,7,-1,-1,-1},{25,19,26,34,35,34,26,25,31,30,-1,-1},{25,32,33,32,33,25,18,12,5,6,-1,-1},{25,31,32,26,19,13,7,-1,-1,-1,-1,-1},{25,19,18,25,26,34,33,25,31,30,29,-1},{25,19,25,32,25,19,13,7,-1,-1,-1,-1},{25,17,23,30,31,23,31,30,-1,-1,-1,-1},{25,18,19,11,17,18,12,6,-1,-1,-1,-1},{25,31,25,18,19,13,7,-1,-1,-1,-1,-1},{25,33,26,20,19,12,18,24,30,-1,-1,-1},{25,18,10,9,16,24,30,-1,-1,-1,-1,-1},{25,33,26,18,17,23,29,-1,-1,-1,-1,-1}}; array <int> mouvements[100][11] ={{2,1,6,2,7,9,9,9,-1,-1,-1},{3,1,2,7,8,3,1,6,7,1,-1},{7,6,4,3,6,9,3,8,-1,-1,-1},{7,1,9,3,1,9,2,9,9,-1,-1},{7,3,7,2,9,3,9,1,1,1,1},{7,4,3,6,4,2,1,2,-1,-1,-1},{8,2,1,3,9,8,9,6,-1,-1,-1},{6,1,8,4,2,8,6,2,1,1,-1},{1,8,7,6,3,9,2,9,-1,-1,-1},{9,3,2,7,2,1,4,1,-1,-1,-1},{6,3,8,6,2,1,9,7,8,-1,-1},{6,1,8,6,9,4,1,1,1,1,-1},{2,7,6,4,6,3,8,9,1,6,9},{4,6,2,4,6,9,8,3,9,-1,-1},{2,6,7,3,6,8,7,6,6,-1,-1},{9,2,1,4,1,1,-1,-1,-1,-1,-1},{8,6,4,2,4,3,4,2,1,-1,-1},{8,1,3,4,2,1,-1,-1,-1,-1,-1},{7,4,3,8,2,1,2,1,-1,-1,-1},{1,8,7,4,6,3,6,9,6,-1,-1},{8,4,6,4,3,2,1,2,4,-1,-1},{9,4,1,2,1,1,-1,-1,-1,-1,-1},{1,6,8,4,7,6,3,9,6,6,-1},{1,9,8,2,1,1,1,-1,-1,-1,-1},{3,9,8,4,3,7,6,-1,-1,-1,-1},{2,4,3,9,4,1,1,-1,-1,-1,-1},{9,1,2,4,1,1,-1,-1,-1,-1,-1},{7,2,1,6,2,9,9,9,-1,-1,-1},{2,3,6,8,7,9,-1,-1,-1,-1,-1},{7,2,3,6,9,9,-1,-1,-1,-1,-1}}; array <int> convMouvementValence[9] = {-1,-1,0,-1,0,1,0,1,1}; array <int> convMouvementValenceInv[9] = {0,-1,-1,1,0,-1,1,1,0}; #Recupération de la position de la cible négative trialInit.present(); int positionCible=response_manager.last_response(); if(positionCible == 1) then ofile1.print("Cible Gauche"+"\n"); trajectoires = trajectoiresN; mouvements=mouvementsN; stimPos = stimPosGauche; stimNeg = stimNegGauche; else ofile1.print("Cible Droite"+"\n"); trajectoires = trajectoiresInv; mouvements=mouvementsInv; stimPos = stimPosDroite; stimNeg = stimNegDroite; end; #Récupération de la main dominante du sujet trialMain.present(); int main=response_manager.last_response(); string mainDominante = ""; if(main == 1)then mainDominante = "Gauche"; else mainDominante = "Droite"; end; ofile1.print("Main "+mainDominante+"\nFin\n"); #Informations pour la gestion du curseur; array<int> infoCursor[12] = {0,0,0,0,0,0,0,0,0,0,0,0}; int countPos = response_manager.total_response_count( 10 ); int countNeg = response_manager.total_response_count( 11 ); int countn3 = response_manager.total_response_count( 13 ); int countn2 = response_manager.total_response_count( 14 ); int countn1 = response_manager.total_response_count( 15 ); int countne = response_manager.total_response_count( 16 ); int countp1 = response_manager.total_response_count( 17 ); int countp2 = response_manager.total_response_count( 18 ); int countp3 = response_manager.total_response_count( 19 ); int countClic = response_manager.total_response_count( 20 ); #Reset position curseur int cursorPos = 4; int prevCursorPos = cursorPos; string cursorFName = "Question"; infoCursor[1] = cursorPos; infoCursor[2] = prevCursorPos; infoCursor[3] = countPos; infoCursor[4] = countNeg; infoCursor[5] = countn3; infoCursor[6] = countn2; infoCursor[7] = countn1; infoCursor[8] = countne; infoCursor[9] = countp1; infoCursor[10] = countp2; infoCursor[11] = countp3; infoCursor[12] = countClic; #Calibration du niveau de son if(calibSonore) then output_file ofileCalib = new output_file; ofileCalib.open("Calib"+ logfile.subject()+"ApprocheReponseStimuli.txt", true ); trialDebCalib.present(); sCalib.set_attenuation(0.5); double deltaAtt = 0.025; double att = 0.7; double attFinale = 0; int nombreRepetCalib = 2; int rep = 0; double smallOffset = 0.05; loop until rep == nombreRepetCalib begin att = 0.8+smallOffset; count = response_manager.total_response_count( 12 ); #Produit un son de moustique de moins en moins atténué jusqu'a ce que l'utilisateur appuie sur Entree lorsqu'il entend le son loop bool endL = false until endL == true begin att = att-deltaAtt; sCalib.set_attenuation(att); t.set_caption("Phase ascendante\nAppuyez sur [Entrée] dès que vous entendez un son",true); trialCalib.present(); if(att <= 0 || count != response_manager.total_response_count( 12 ))then endL = true; end; end; double attApparition = att; attFinale = attFinale+att; ofileCalib.print("AttenuationApparition "+string(att)+"\n"); trialPrep.present(); #Produit un son de moustique de plus en plus atténué jusqu'à ce que l'utilisateur appuie sur Entree lorsqu'il entend le son sCalib.set_attenuation(0+smallOffset); att = 0; count = response_manager.total_response_count( 12 ); loop bool endL = false until endL == true begin att = att+deltaAtt; sCalib.set_attenuation(att); t.set_caption("Phase descendante\nAppuyez sur [Entrée] dès que vous n'entendez plus le son",true); trialCalib.present(); if(att == 1 || count != response_manager.total_response_count( 12 ))then endL = true; end; end; double attDisparition = att; attFinale = attFinale+att; ofileCalib.print("AttenuationDisparition "+string(att)+"\n"); trialPrep.present(); rep = rep+1; smallOffset=smallOffset+0.05 end; #Rep attFinale = attFinale/((rep)*2); #Calcul atténuation finale #L'atténuation déterminé est la moyenne des deux attenuations détérminé par l'appuie de la touche [Entrée] par l'utilisateur auquel on soustrait 0.2 ofileCalib.print("AttenuationFinale "+string(attFinale)); deltaAtt = 0.3; attFinale = attFinale-deltaAtt; if((attFinale <=0))then attFinale = 0; end; #Application de l'attenuation déterminée loop int s = 1 until s > sounds.count() begin sounds[s].set_attenuation(attFinale); s=s+1; end; stimPos.set_attenuation(attFinale); stimNeg.set_attenuation(attFinale); stimPosGauche.set_attenuation(attFinale); stimNegGauche.set_attenuation(attFinale); stimPosDroite.set_attenuation(attFinale); stimNegDroite.set_attenuation(attFinale); #te.set_caption(string(att)+"\nAppuyez sur [Entrée]",true); #trialDebCalib.present(); else loop int s = 1 until s > sounds.count() begin sounds[s].set_attenuation(0); s=s+1; end; end; if(presentation) then trialPreparation.present(); end; #Trial de test if(essaiT == true)then essaiTest.present(); #Présentation des trajectoires loop int i = 1 until i > 4 begin cursorPos = 4; infoCursor[1] = cursorPos; infoCursor[2] = cursorPos; #Presentation trial début de trajectoire trialDebutTrajectoire.present(); int valence = -1; int longueur = 0; bool v = indic[i][1]; if(v == true) then valence = 1; else valence = 0; end; loop int k = 1 until k > trajectoires[i].count() begin k=k+1; longueur = k; if(k <= trajectoires[i].count())then if(trajectoires[i][k] == -1) then break; end; end; end; if(valence == 0)then pic2.set_part(1,redbox); picPiqure.set_part(1,redbox); else pic2.set_part(1,greenbox); picPiqure.set_part(1,greenbox); end; #Trial de préparation a la trajectoire a suivre if(longueur < 8) then textPreTrajLongueur.set_caption("Elle sera courte",true); else textPreTrajLongueur.set_caption("Elle sera longue",true); end; string rrv=""; bpIncert.unload(); string extensionImg = ".png"; if(mosquitoCartoon == true)then extensionImg = "M.png"; end; if(indic[i][2] == true) then if(valence == 0) then bpIncert.set_filename("R"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de vous piquer"; else bpIncert.set_filename("V"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de ne pas vous piquer"; end; else if(valence == 0) then bpIncert.set_filename("V"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de ne pas vous piquer"; else bpIncert.set_filename("R"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de vous piquer"; end; end; bpIncert.load(); string textTraj = ""; if(valence == 0) then if(pourcent[i] > 80) then rrv = "Le moustique est affamé"; else rrv = "Le moustique semble avoir faim"; end; else if(pourcent[i] > 80) then rrv = "Le moustique s'est déjà nourri"; else rrv = "Le moustique ne semble pas avoir faim"; end; end; rrv=""; textPreTrajLongueur.set_caption(textPreTrajLongueur.caption()+"\n"+rrv,true); #Marquage des données EEG pour indiquer quel est la trajectoire actuelle bool l = false; if(longueur >= 8) then l = true; end; bool vval = false; if(valence == 1) then vval=true; end; int trigTraj = triggerTrajectoireV2(vval,indic[i][2],l,pourcent[i]); #Affichage des infos de trajectoires textPreTrajObjectif.set_caption(rrv,true); trialPreparationTrajectoire.present(); int positionx = 0; int positiony = 0; int lastRep = -1; bp.unload(); bp.set_filename(cursorFName+string(cursorPos)+".jpg"); bp.load(); #Boucle intra-trajectoire loop int j = 1 until j == trajectoires[i].count() begin ofile1.print("Son\nNumero "+string(j)+"\n"); #Selection position curseur infoCursor = calcPosCursor(infoCursor, cursorFName); if(j != 1)then #tPostSon.set_caption("Mouvement effectué :"+conversionMvmIntStr[mouvements[i][j-1]],true); ofile1.print("Mouvement "+conversionMvmIntStr[mouvements[i][j-1]]+"\n"); #Ajout valence du mouvement if(positionCible == 1)then ofile1.print("Valence "+string(convMouvementValence[mouvements[i][j-1]])+"\n"); else ofile1.print("Valence "+string(convMouvementValenceInv[mouvements[i][j-1]])+"\n"); end; end; if(trajectoires[i][j] != -1)then positionx = positions[trajectoires[i][j]][1]; positiony = positions[trajectoires[i][j]][2]; ofile1.print("Position "+string(positionx)+"_"+string(positiony)+"\n"); end; #Choix du stimulus audio sound sd1 = sounds[trajectoires[i][j]]; s1.set_stimulus(sd1); #Marker pour capture EEG #output.send_code(triggerSonV2(trajectoires[i][j])); #Presentation stimulus audio trialSon.present(); double ti = clock.time(); loop until clock.time()>ti+1500 begin infoCursor = calcPosCursor(infoCursor, cursorFName); #trialPicSon.present(); trialQuestion.present(); end; infoCursor = calcPosCursor(infoCursor, cursorFName); cursorPos = infoCursor[1]; if(lastRep != -1 && j != 1) then lastRep=cursorPos; else lastRep=cursorPos; end; j=j+1; if(j <= trajectoires[i].count())then if(trajectoires[i][j] == -1) then break; end; end; end; #Presentation du stimulus final if(valence == 0) then seFinal.set_stimulus(stimNeg); else seFinal.set_stimulus(stimPos); end; if(valence == 0)then #Activation du stimulus electrique if(outputAvailable == true) then output.send_code(1); end; end; trialStimulusFinal.present(); bp.set_filename("blank.png"); bp.load(); #Presentation de la question sur le ressenti trialDesagreable.present(); int desagreable=response_manager.last_response(); i=i+1; end; end; trialDebutExpe.present(); #Présentation des trajectoires loop int i = 1 until i > trajectoires.count() begin #Reset position curseur cursorPos = 4; infoCursor[1] = cursorPos; infoCursor[2] = cursorPos; #Presentation trial début de trajectoire ofile1.print("Trajectoire "+string(i)+"\n"); trialDebutTrajectoire.present(); int valence = -1; int longueur = 0; bool v = indic[i][1]; if(v == true) then valence = 1; else valence = 0; end; loop int k = 1 until k > trajectoires[i].count() begin k=k+1; longueur = k; if(k <= trajectoires[i].count())then if(trajectoires[i][k] == -1) then break; end; end; end; if(valence == 0)then ofile1.print("ValenceTraj Negatif\n"); pic2.set_part(1,redbox); picPiqure.set_part(1,redbox); else ofile1.print("ValenceTraj Positif\n"); pic2.set_part(1,greenbox); picPiqure.set_part(1,greenbox); end; ofile1.print("Longueur "+string(longueur)+"\n"); #Trial de préparation a la trajectoire a suivre if(longueur < 8) then textPreTrajLongueur.set_caption("Elle sera courte",true); else textPreTrajLongueur.set_caption("Elle sera longue",true); end; string rrv=""; bpIncert.unload(); string extensionImg = ".png"; if(mosquitoCartoon == true)then extensionImg = "M.png"; end; if(indic[i][2] == true) then if(valence == 0) then bpIncert.set_filename("R"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de vous piquer"; else bpIncert.set_filename("V"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de ne pas vous piquer"; end; else if(valence == 0) then bpIncert.set_filename("V"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de ne pas vous piquer"; else bpIncert.set_filename("R"+string(pourcent[i])+extensionImg); rrv = "La trajectoire aura "+string(pourcent[i])+"% de chance de vous piquer"; end; end; bpIncert.load(); string textTraj = ""; if(valence == 0) then if(pourcent[i] > 80) then rrv = "Le moustique est affamé"; else rrv = "Le moustique semble avoir faim"; end; else if(pourcent[i] > 80) then rrv = "Le moustique s'est déjà nourri"; else rrv = "Le moustique ne semble pas avoir faim"; end; end; rrv=""; textPreTrajLongueur.set_caption(textPreTrajLongueur.caption()+"\n"+rrv,true); #Marquage des données EEG pour indiquer quel est la trajectoire actuelle bool l = false; if(longueur >= 8) then l = true; end; bool vval = false; if(valence == 1) then vval=true; end; int trigTraj = triggerTrajectoireV2(vval,indic[i][2],l,pourcent[i]); if(outputAvailable == true) then output.send_code(trigTraj); end; ofile1.print("TriggerTraj "+string(trigTraj)+"\n"); ofile1.print("PreparationTraj "+string(pourcent[i])+" "+string(indic[i][2])+"\n"); #Affichage des infos de trajectoires textPreTrajObjectif.set_caption(rrv,true); trialPreparationTrajectoire.present(); int positionx = 0; int positiony = 0; int lastRep = -1; bp.unload(); bp.set_filename(cursorFName+string(cursorPos)+".jpg"); bp.load(); #Boucle intra-trajectoire loop int j = 1 until j == trajectoires[i].count() begin ofile1.print("Son\nNumero "+string(j)+"\n"); infoCursor = calcPosCursor(infoCursor, cursorFName); if(j != 1)then ofile1.print("Mouvement "+conversionMvmIntStr[mouvements[i][j-1]]+"\n"); #Ajout valence du mouvement if(positionCible == 1)then ofile1.print("Valence "+string(convMouvementValence[mouvements[i][j-1]])+"\n"); else ofile1.print("Valence "+string(convMouvementValenceInv[mouvements[i][j-1]])+"\n"); end; end; if(trajectoires[i][j] != -1)then positionx = positions[trajectoires[i][j]][1]; positiony = positions[trajectoires[i][j]][2]; ofile1.print("Position "+string(positionx)+"_"+string(positiony)+"\n"); end; #Choix du stimulus audio sound sd1 = sounds[trajectoires[i][j]]; s1.set_stimulus(sd1); #Marker pour capture EEG if(outputAvailable == true) then output.send_code(triggerSonV2(trajectoires[i][j])); end; ofile1.print("TriggerSon "+string(triggerSonV2(trajectoires[i][j]))+"\n"); #Presentation stimulus audio trialSon.present(); double ti = clock.time(); loop until clock.time()>ti+1500 begin infoCursor=calcPosCursor(infoCursor, cursorFName); #trialPicSon.present(); trialQuestion.present(); end; infoCursor = calcPosCursor(infoCursor, cursorFName); cursorPos = infoCursor[1]; if(j != 1)then ofile1.print("Reponse "+string(cursorPos)+"\n"); end; if(lastRep != -1 && j != 1) then ofile1.print("DifRep "+string(cursorPos-lastRep)+"\n"); lastRep=cursorPos; else lastRep=cursorPos; end; j=j+1; if(j <= trajectoires[i].count())then if(trajectoires[i][j] == -1) then break; end; end; end; ofile1.print("FinSon \n"); #Presentation du stimulus final if(valence == 0) then seFinal.set_stimulus(stimNeg); else seFinal.set_stimulus(stimPos); end; if(valence == 0)then #Activation du stimulus electrique if(outputAvailable == true) then output.send_code(1); end; end; trialStimulusFinal.present(); bp.set_filename("blank.png"); bp.load(); #Presentation de la question sur le ressenti trialDesagreable.present(); int desagreable=response_manager.last_response(); ofile1.print("Desagreable "+string(desagreable)+"\n"); i=i+1; ofile1.print("Fin\n"); #Pause if(i%(trajectoires.count()/5) == 0 && i != trajectoires.count()) then trialPause.present(); end; end;
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clear D=40.0 //Screw diameter l=20.0 //Screw lwngth p=l/3.0 //Lead of the screw W=40000.0 //effort R = 400 //Lever length u = 0.12 //coefficient of friction between screw and nut P = (D/(2*R))*W*((u+(p/(3.14*D)))/(1-u*(p/(3.14*D)))) //Effort printf("\n Effort is %0.3f N",P)
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clc; V=250; //potential difference in Volt C=10^-11; //capacitance in farad q=C*V; //calculating charge disp(q,"Charge in Coulomb = "); //displaying result
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//i/p vector contains complex elements x=[1 0.2 -0.1+0.3*%i 0.4 0.1+0.5*%i]; y=vco(x,150,500); disp(y); ////output // column 1 to 2 // // - 0.3090170 - 0.5358268 // // column 3 // // 1.0533942 + 0.2538114i // // column 4 // // - 0.6842960 - 0.4822634i // // column 5 // // - 1.0088598 + 1.9436435i //
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//Realiza el método de la Bisección //[a,b] extremos del intérvalo. Deben cumplir f(a)*f(b) < 0 // Tol: tolerancia a buscar // maxit: numero maximo de iteraciones function [x,it] = biseccion(a,b,tol,maxit) fa = sign(bf(a)); fb = sign(bf(b)); x = 0; if (fa*fb > 0) disp("Intervalo incorrecto"); return; end for i=1:maxit p = a + (b-a)/2; fp = bf(p); if(abs(fp) < tol) x = p; it = i; return; end fa = sign(bf(a)); fb = sign(bf(b)); if(sign(fp)*fa < 0) b = p; else a = p; end end disp("Maximo numero de iteraciones alcanzadas"); it = maxit; endfunction function y = bf(x) y = x^2 - 1; endfunction
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// example 4.35 // obtain least square approximation of second degree; x=[-2 -1 0 1 2]; f=[15 1 1 3 19]; [P]=quadraticapprox(x,f) // call of the function to get the desired solution
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//Chapter 6, Example 6.2, Page 145 clc clear // Maximum Energy loss me = 0.0005486 M = 4.003 EM = 4 Emax = 4*(me/M)*EM printf("Emax = %f keV",Emax*10^3) //Answers may vary due to round off error
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//Example 11.14 clc; //Anderson's Bridge //Given values of bridge elements r=496; R2=200; R3=1000; R4=1000; C=10*10^-6; //R1 for Anderson's bridge R1=R2*R3/R4; //L1 for Anderson's bridge L1=(r*(R4+R2)+R2*R4)*C*R3/R4; printf('\nValue of resistence R1 is %.2f ohm\n',R1) printf('\nValue of inductance L1 is %.4f H\n',L1)