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//Gram-Schmidt Orthogonalization clear; close; clc; a = [0 0 0; 0 0 0; 0 0 0] for i=1:3 for j=1:3 a(i,j) = input('Enter the values:') end end disp(a,'A = ') [m,n] = size(a) for k=1:n V(:,k) = a(:,k) for j=1:k-1 R(j,k) = V(:,j)'*a(:,k) V(:,k) = V(:,k) - R(j,k)*V(:,j) end R(k,k) = norm(V(:,k)) V(:,k) = V(:,k)/R(k,k) end disp(V,'Q = ')
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A=[1 2 3 4 5] disp(A)
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clear // Variable declaration P_c=10// kW T_e=-35// Evaporating temperature in °C T_c=40// Condensing temperature in °C T_s=5// Subcooling temperature in K T_cin=20// Compressor inlet temperature in °C T_cout=0// Zero subcooling temperature in °C // Calculation //(a) v_s1=146.46// m**3/kg v_s2=135.25// m**3/kg v_sr=v_s1/v_s2// The ratio of specific volume // Assuming the compressor pumps the same volume flowrate: m_1bym_2=v_sr// Flow rate ratio printf("\n \nFlow rate ratio,m_2/m_1=%1.3f",m_1bym_2) //(b) h_1=392.51// Suction gas enthalpy at 20°C in kJ/kg h_2=375.19// Suction gas enthalpy at 0°C in kJ/kg h_f=257.77// Liquid enthalpy at the expansion valve inlet at 40°C in kJ/kg dh_1=h_1-h_f// Evaporator enthalpy difference at rating condition in kJ/kg dh_2=h_2-h_f// Evaporator enthalpy difference with 0°C suction in kJ/kg dh_r=dh_2/dh_1// Enthalpy difference ratio C_c=P_c*m_1bym_2*dh_r// Compressor capacity corrected for suction temperature change in kW printf("\n \nCompressor capacity corrected for suction temperature change=%1.2f kW",C_c) //(c) h_f=249.67// Liquid enthalpy at the expansion valve inlet at 35°C in kJ/kg dh=h_2-h_f// Evaporator enthalpy difference at application condition in kJ/kg dh_r=dh/dh_1// Enthalpy difference ratio C_cact=P_c*m_1bym_2*dh_r// Actual compressor capacity in kW printf("\n \nActual compressor capacity=%2.2f kW",C_cact) //(d) h_g=350.13// Suction gas enthalpy at evaporator outlet, -30°C (5 K superheat) in kJ/kg dh_e=h_g-h_f// Useful evaporator enthalpy difference in kJ/kg dh_r=dh_e/dh_1// Enthalpy difference ratio C_eact=P_c*m_1bym_2*dh_r// Actual evaporator capacity in kW printf("\n \nActual evaporator capacity=%1.2f kW",C_eact)
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//Chapter 24: Space Wave Propagation //Example 24-9.4 clc; //Variable Initialization gain = 10 //Antenna gain (dB) Wt = 500 //Power radiation (W) d = 15e3 //Distance (m) Wr = 2e-6 //Received power (W) //Calculations Ae = Wr*(4*%pi*(d**2))/(Wt*gain) //Effective area (m^2) //Result mprintf("The effective area of the receiving antenna is %.2f m^2", Ae)
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.10 //Data given in the Problem d1=2 d2=2 g=9.81 dens=1000 SG=1.15 h=1.5 //calculations A=1/2*d1*d2 //1)thrust on plate F=SG*dens*g*A*h mprintf("The thrust on the plate is %f N\n",F) //2)Centre of pressure IG=((d1*(d2/2)^3)/12)+((d2*(d1/2)^3)/12) H=IG/(A*h)+h mprintf("The cente ofpressure is at %f m ",H)
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// Buck Converter Script D = 0.416; // Duty Cycle Fsw = 400e03; // Switching Frequency Vin = 12; // Input Voltage L = 12.12e-06; //Inductor value C = 19.5e-06; // Capacitor value R = 5; // Load Resistance
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//Example 2.6.5:magnitude and limiting error clc; clear; close; format('v',10) r1=120;//in ohms er1=0.1;//limiting error in resistance 1 in ohms ± r2=2700;//in ohms er2=0.5;//limiting error in resistance 2 in ohms ± r3=470;//in ohms er3=0.5;//limiting error in resistance 3 in ohms ± rxm=(r2*r3)/r1;//magnitude of unknown resistance in ohms rxe=(er1+er2+er3);//error er=(rxe*rxm)/100;//relative error ± disp(rxm*10^-3,"magnitude of unknown resistance in kilo ohms") disp(er,"relative limiting error in ohms is (±)") disp("guranteed value of resistance is between "+string(rxm-er)+" ohms to "+string(rxm+er)+" ohms ")
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clc; p=2*10^6; // rated power of alternator v=11000; // rated voltage of alternator zs=0.3+5*%i; // synchronous impedance per phase pf=0.8; // lagging power factor vt=v/sqrt(3); // terminal voltage ia=p/(sqrt(3)*v); // full load armature current // with vt as reference phasor Ef=vt+ia*(pf-sqrt(1-pf^2)*%i)*zs; // now excitation level is same but load power fcator is leading printf('Load current is %f A\n',ia); de=cosd(atand(imag(Ef),real(Ef))); // angle between excitation and terminal voltage vt=abs(Ef)*(de+sqrt(1-de^2)*%i)-ia*(pf+sqrt(1-pf^2)*%i)*zs; printf('Terminal voltage at %f leading power factor is %f V per phase\n',pf,abs(vt)); printf('Line terminal voltage is %f KV',(sqrt(3)*abs(vt))/1000);
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//Finding capacitance //Example 4.2(pg 110) clc clear n=9; Ko=8.854*10^-12; K=5; A=12*10^-4; d=2*10^-4; C=(n-1)*Ko*K*A/d printf('Thus the capacitance is %e F',C); //The Answer in the Textbook has a calculation error, hence it doesn't match the answer here.
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//check o/p when the first coefficient of the prediction polynomial is 1 X = [1 7 6 5 8 3 6]; efinal=0.3; R = rlevinson(X, efinal); disp(R); //output // 0.0104858 // 0.0020340 // - 0.0086295 // 0.0007701 // - 0.0019945 // - 0.0074447 // 0.0602488
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// 08.10.10 // 08.10.12 // 08.10.15 // 08.10.26 // 09.06.05 // 09.09.10 // 09.10.12 debug // 09.11.07 debugged // 10.02.16 Eps__ // 13.10.22 ( __ added to variables ) function Out__=PthiddenQ(PtA__,Vec__,Fd__,Uveq__,Np__,EPS__) // Out__=1 : hidden // SL__ : List of segments near PtA__+Vec__ Eps__0=10^(-4)*(Xmax()-Xmin())/10; Eps__=EPS__(1)*(Xmax()-Xmin())/10; // Out__=0; Vec__1=1/norm(Vec__)*Vec__; PtL__=[]; Tmp__=Mixop(2,Fd__); K__=mtlb_findstr(Tmp__,'='); Xname__=part(Tmp__,1:K__-1); Tmp__=Mixop(3,Fd__); K__=mtlb_findstr(Tmp__,'='); Yname__=part(Tmp__,1:K__-1); Tmp__=Mixop(1,Fd__); K__=mtlb_findstr(Tmp__,'='); if K__~=[] Zname__=part(Tmp__,1:K__-1); else Tmp__=Mixop(4,Fd__); K__=mtlb_findstr(Tmp__,'='); Zname__=part(Tmp__,1:K__-1); end; FdL__=Fullformfunc(Fd__); Xf__=Mixop(2,FdL__); Yf__=Mixop(3,FdL__); Zf__=Mixop(4,FdL__); Tmp__=Mixop(5,FdL__); K__=mtlb_findstr(Tmp__,'='); Uname__=part(Tmp__,1:K__-1); Urg__=evstr(part(Tmp__,K__+1:length(Tmp__))); Tmp__=Mixop(6,FdL__); K__=mtlb_findstr(Tmp__,'='); Vname__=part(Tmp__,1:K__-1); Vrg__=evstr(part(Tmp__,K__+1:length(Tmp__))); Umin__=Urg__(1); UMax__=Urg__(2); Vmin__=Vrg__(1); VMax__=Vrg__(2); V1__='('+string(Vec__(1))+')'; V2__='('+string(Vec__(2))+')'; V3__='('+string(Vec__(3))+')'; Xstr__='(('+Xf__+')-('+string(PtA__(1))+'))'; Ystr__='(('+Yf__+')-('+string(PtA__(2))+'))'; Zstr__='(('+Zf__+')-('+string(PtA__(3))+'))'; Urg__str=Mixop(5,FdL__); Vrg__str=Mixop(6,FdL__); if abs(Vec__(2))>Eps__0 | abs(Vec__(1))>Eps__0 Eq__=V2__+'*'+Xstr__+'-'+V1__+'*'+Ystr__; else Eq__=Xstr__; end; MS__=Mix(Eq__,Urg__str,Vrg__str,Np__); [Zval__,Xval__,Yval__]=Makevaltable(MS__); SL__=[]; for J__=1:length(Yval__)-1 for I__=1:length(Xval__)-1 a1__=Xval__(I__);b1__=Yval__(J__);c1__=Zval__(J__,I__); a2__=Xval__(I__+1);b2__=Yval__(J__);c2__=Zval__(J__,I__+1); a3__=Xval__(I__+1);b3__=Yval__(J__+1);c3__=Zval__(J__+1,I__+1); a4__=Xval__(I__);b4__=Yval__(J__+1);c4__=Zval__(J__+1,I__); PL__=[a1__,b1__;a2__,b2__;a3__,b3__;a4__,b4__;a1__,b1__]; VL__=[c1__,c2__,c3__,c4__,c1__]; QL__=[]; for K__=1:4 P1__=PL__(K__,:); P2__=PL__(K__+1,:); M1__=VL__(K__); M2__=VL__(K__+1); if M1__>=Eps__0 & M2__>=Eps__0 continue; end; if M1__<=-Eps__0 & M2__<=-Eps__0 continue; end; if abs(M1__)<Eps__0 Tmp__=P1__; elseif abs(M2__)<Eps__0 continue; else Tmp__=1/(M1__-M2__)*(-M2__*P1__+M1__*P2__); end; QL__=[QL__;Tmp__]; end; if size(QL__,1)==2 Puv1__=QL__(1,:); Puv2=QL__(2,:); Tmp__1=Puv1__(1); Tmp__2=Puv1__(2); Tmp__=strsubst(Xf__,Uname__,'('+string(Tmp__1)+')'); Tmp__=strsubst(Tmp__,Vname__,'('+string(Tmp__2)+')'); Xv__=evstr(Tmp__); Tmp__=strsubst(Yf__,Uname__,'('+string(Tmp__1)+')'); Tmp__=strsubst(Tmp__,Vname__,'('+string(Tmp__2)+')'); Yv__=evstr(Tmp__); Tmp__=strsubst(Zf__,Uname__,'('+string(Tmp__1)+')'); Tmp__=strsubst(Tmp__,Vname__,'('+string(Tmp__2)+')'); Zv__=evstr(Tmp__); P1__=[Xv__,Yv__,Zv__]; Tmp__1=Puv2(1); Tmp__2=Puv2(2); Tmp__=strsubst(Xf__,Uname__,'('+string(Tmp__1)+')'); Tmp__=strsubst(Tmp__,Vname__,'('+string(Tmp__2)+')'); Xv__=evstr(Tmp__); Tmp__=strsubst(Yf__,Uname__,'('+string(Tmp__1)+')'); Tmp__=strsubst(Tmp__,Vname__,'('+string(Tmp__2)+')'); Yv__=evstr(Tmp__); Tmp__=strsubst(Zf__,Uname__,'('+string(Tmp__1)+')'); Tmp__=strsubst(Tmp__,Vname__,'('+string(Tmp__2)+')'); Zv__=evstr(Tmp__); P2__=[Xv__,Yv__,Zv__]; if norm(P1__-P2__)<Eps__0 // 09.11.07 continue; end; // Tmp__1=norm(P1__-PtA__); Tmp__2=Naiseki(P1__-PtA__,Vec__1); Tmp__3=sqrt(abs(Tmp__1^2-Tmp__2^2)); Tmp__4=norm(P2__-PtA__); Tmp__5=Naiseki(P2__-PtA__,Vec__1); Tmp__6=sqrt(abs(Tmp__4^2-Tmp__5^2)); if Tmp__2<Tmp__5 Tmp__=P1__; P1__=P2__; P2__=Tmp__; Tmp__=Tmp__2; Tmp__2=Tmp__5; Tmp__5=Tmp__; Tmp__=Tmp__3; Tmp__3=Tmp__6; Tmp__6=Tmp__; end; if Tmp__3<EPS__(2)*Eps__ & Tmp__6<EPS__(2)*Eps__ // if Tmp__2>-Eps__0 if Tmp__5<-Eps__0 SL__=[SL__;P1__,P2__,-1]; else SL__=[SL__;P1__,P2__,1]; end; end; end; V1__=Vec__1(1); V2__=Vec__1(2); V3__=Vec__1(3); if abs(V1__)>Eps__0 M1__=PtA__(3)+V3__/V1__*(P1__(1)-PtA__(1))-P1__(3); M2__=PtA__(3)+V3__/V1__*(P2__(1)-PtA__(1))-P2__(3); elseif abs(V2__)>Eps__0 M1__=PtA__(3)+V3__/V2__*(P1__(2)-PtA__(2))-P1__(3); M2__=PtA__(3)+V3__/V2__*(P2__(2)-PtA__(2))-P2__(3); else M1__=PtA__(2)-P1__(2); M2__=PtA__(2)-P2__(2); end; if M1__*M2__>=0 if (M1__>Eps__0 & M2__>Eps__0) | (M1__<-Eps__0 & M2__<-Eps__0) continue; end; if abs(M1__)<=Eps__0 Pt__=P1__; Ptuv__=Puv1__; else Pt__=P2__; Ptuv__=Puv2; end; else Pt__=1/(M1__-M2__)*(-M2__*P1__+M1__*P2__); Ptuv__=1/(M1__-M2__)*(-M2__*Puv1__+M1__*Puv2); end; if type(Uveq__)==10 Tmp__1='('+string(Ptuv__(1))+')'; Tmp__2='('+string(Ptuv__(2))+')'; Tmp__=strsubst(Uveq__,Uname__,Tmp__1); Tmp__=strsubst(Tmp__,Vname__,Tmp__2); Tmp__=evstr(Tmp__); if Tmp__<-Eps__0 continue; end; end; Tmp__1=Dotprod(Pt__-PtA__,Vec__1); Tmp__2=abs(Tmp__1); Tmp__3=Dotprod(P1__-P2__,Vec__1); Tmp__4=norm(P1__-P2__); Tmp__6=Tmp__3/Tmp__4; if Tmp__1>Eps__0 if abs(Tmp__6)>0.75 // from PtL__=[PtL__;Pt__,P2__]; continue; end; // upto if Tmp__2>Eps__ Out__=1; return end; if Tmp__2<2*Eps__ continue; end; end; end; end; end; if PtL__==[] return; end; for I__=1:size(SL__,1) P2__=SL__(I__,4:6); Flg__=0; for J__=1:size(SL__,1) P=SL__(J__,1:3); if norm(P-P2__)<Eps__0 SL__(I__,7)=J__; Flg__=1; break; end; end; if Flg__==0 & SL__(I__,7)>0 SL__(I__,7)=-2; end; end; for I__=1:size(PtL__,1) P__=PtL__(I__,4:6); Flg__=0; for J__=1:size(SL__,1) P1__=SL__(J__,1:3); if norm(P1__-P__)<Eps__0 Flg__=1; break; end; end; if Flg__==0 Pt__=PtL__(I__,1:3); // from Tmp__0=norm(P__-Pt__); Tmp__1=abs(Dotprod(P__-Pt__,Vec__1)); Tmp__2=sqrt(abs(Tmp__0^2-Tmp__1^2)); Tmp__3=Tmp__2*norm(Pt__-PtA__)/Tmp__0; // should to be changed 10.02.16 if Tmp__3>Eps__/5 Out__=1; return; else continue; end; // upto end; Nxt__=SL__(J__,7); while Nxt__>0 P__=SL__(Nxt__,4:6); Nxt__=SL__(Nxt__,7); end; if Nxt__==-2 Out__=1; return; else Out__=0; end; end; endfunction;
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*Testcase str-001-cksm.tst: # Created and placed into the public domain 2018-12-30 by Bob Polmanter. ########################################################################################### # set up, load, and run the test case # Suppress logging of program checks. Processing of this test script # intentionally generates program checks (specification exception) as part # of instuction test and validation. Redtest.rexx treats these as # errors if they show up in the Hercules log. So suppress them. ostailor quiet # clear any prior test data/program/results sysclear # Run test in z/Arch mode archmode esame loadcore "$(testpath)/str-001-cksm.core" # Run the program runtest # Restore program check messages ostailor default ########################################################################################### # Analyze results *Compare # 0 1 2 3 4 5 6 7 8 9 A B C D E F r 0800.0C *Want "Test 1 R1-R3" 99DE2265 00000710 00000000 r 0810.0C *Want "Test 2 R1-R3" 99003366 0000070D 00000000 r 0820.0C *Want "Test 3 R1-R3" 99DE2265 0000300B 00000000 r 0830.0C *Want "Test 4 R1-R3" 99003366 00003008 00000000 r 0840.0C *Want "Test 5 R1-R3" 99DE2265 00003000 00000000 r 0850.0C *Want "Test 6 R1-R3" 99003366 00003000 00000000 r 0860.0C *Want "Test 7 R1-R3" 99DE2265 00003002 00000000 r 0870.0C *Want "Test 8 R1-R3" 99003366 00003002 00000000 r 0880.0C *Want "Test 9 R1-R3" E1E1E1E1 0000BFF8 00000000 *Done
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mode(2);errcatch(-1,"stop");driver("GIF");// from the nyquist plot N=0; // one clockwise and one anticlockwise encirclement P=0; // given Z=N-P printf("Since Z=0 no root of the characterisic equation lies in the right half hence the system is stable") xinit('/home/fossee/Downloads/tbc_graphs/Control_Systems_Engineering_I._J._Nagrath_And_M._Gopal__28/ex9_8_2');xend();exit();
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//chapter 8 Ex 1 clc; clear; close; //let rajeev's age be x //by the given condition: equation is x+15=5(x-5); mycoeff=[-40 4]; p=poly(mycoeff,"x","coeff"); ageRajeev=roots(p); mprintf("Present age of rajeev is %d years",ageRajeev);
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//Ex1_5 clc A=10*10^(-6); p1=10^(-4); p2=10^(3);p3=10^(10);l=1*10^(-2); //initializations disp("cross sectional area,A ="+string(A)+"merer square") disp("resitivity(rho),p1 ="+string(p1)+" ohm-m") disp("resitivity(rho),p2 ="+string(p2)+" ohm-m") disp("resitivity(rho),p3 ="+string(p3)+" ohm-m") disp("conductor length,l ="+string(l)+" metre") disp(" resistance for copper,R = p1*l/A = "+string(p1*l/A)+"ohm") //calculations for copper disp(" resistance for silicon,R = p2*l/A = "+string(p2*l/A)+"ohm") //calculations for silicon disp(" resistance for glass,R = p3*l/A = "+string(p3*l/A)+"ohm") //calculations for glass
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Example23_4.sce
//Given that m = 1.3*10^-10 //in kg Q = 1.5*10^-13 //in C Vx = 18 //in m/s L = 1.6*10^-2 //in meter E = 1.4*10^6 //in N/C //Sample Problem 23-4 printf("**Sample Problem 23-4**\n") a = E*Q/m t = L/Vx dv = 0.5*a*t^2 //vertical drop printf("The vertical drop of the drop is equal to %fmm", dv*10^3)
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// Scilab Code Ex1.12: Page-1.17 (2009) clc; clear; m = 9.1e-031; // Mass of the electron, kg q = 1.6e-019; // Charge on an electron, C V = 50; // Accelearting potential, V E = q*V; // Energy gained by the electron, J h = 6.626e-034; // Planck's constant, Js lambda = h/sqrt(2*m*E); // de Broglie wavelength of the electron, m printf("\nThe de Broglie wavelength of the electron accelearted through a given potential = %5.3e m", lambda); // Result // The de Broglie wavelength of the electron accelearted through a given potential = 1.736e-10 m
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// Scilab Code Ex2.16 Wavelength of Balmer H_beta line: Pg:57 (2008)s L_Hb = 6563e-010; // Wavelength of H_beta line, m R = 1.097e+07; // Rydberg constant, per metre L1 = 36/(5*R); // Wavenumber of H_alpha line, per metre L2 = 16/(3*R); // Wavenumber of H_beta line, per metre L_ratio = L2/L1; // Ratio of wavelengths of H_beta and H_alpha lines L2 = L_ratio*L1; // Wavelength of Balmer H_beta line, m printf("\nThe wavelength of Balmer H_beta line = %4d angstrom", L2/1e-010); // Result // The wavelength of Balmer H_beta line = 4861 angstrom
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//Caption:(a)How much KVA should be supplied by synchronous motor (b)Power factor of synchronous motor //Exa:15.7 clc; clear; close; Pm=40//Power absorb by motor(in Kw) Pl=300//Load connected in parallel with motor(in KW) pfm=0.85//Power factor of motor pfl=0.9//Power factor on load Pt=Pl+Pm Pr=Pt*tand(acosd(pfl)) Pri=Pl*tand(acosd(pfm)) Ps=Pri-Pr pf=cosd(atand(Ps/Pm)) disp(Ps,'(a)Power supplied by synchronous motor(in KVA)=') disp(pf,'(b)Power factor of synchronous machine=')
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clc h2=615; //kJ/kg h3=664; //kJ/kg h4=446; //kJ/kg h1=h4; v2=0.14; //m^3/kg capacity=20; //tonnes n=6; //number of cylinder disp("(i) Refrigerating effect per kg =") RE=h2-h1; disp(RE) disp("kJ/kg") disp("(ii) Mass of refrigerant to be circulated per minute =") m=capacity*14000/RE/60; disp(m) disp("kg/min") disp("(iii) Theoretical piston displacement =") v=v2*m; disp(v) disp("m^3/min") disp("(iv) Theoretical power =") P=m/60*(h3-h2); disp(P) disp("kW") disp("(v)COP =") COP=(h2-h1)/(h3-h2); disp(COP) disp("(vi) Heat removed through the condenser =") Q=m*(h3-h4); disp(Q) disp("kJ/min") disp("(vii) Theoretical displacement per minute per cylinder") d=(v/n*4/%pi/950)^(1/3)*1000; disp("Diameter of cylinder =") disp(d) disp("mm") l=d; disp("Stroke length =") disp(l) disp("mm")
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well it s great to be here we ve heard a lot about the promise of technology and the peril i ve been quite interested in both if we could convert 0 03 percent of the sunlight that falls on the earth into energy we could meet all of our projected needs for 2030 we ca n t do that today because solar panels are heavy expensive and very inefficient there are nano engineered designs which at least have been analyzed theoretically that show the potential to be very lightweight very inexpensive very efficient and we d be able to actually provide all of our energy needs in this renewable way nano engineered fuel cells could provide the energy where it s needed that s a key trend which is decentralization moving from centralized nuclear power plants and liquid natural gas tankers to decentralized resources that are environmentally more friendly a lot more efficient and capable and safe from disruption bono spoke very eloquently that we have the tools for the first time to address age old problems of disease and poverty most regions of the world are moving in that direction in 1990 in east asia and the pacific region there were 500 million people living in poverty that number now is under 200 million the world bank projects by 2011 it will be under 20 million which is a reduction of 95 percent i did enjoy bono s comment linking haight ashbury to silicon valley being from the massachusetts high tech community myself i d point out that we were hippies also in the 1960s although we hung around harvard square but we do have the potential to overcome disease and poverty and i m going to talk about those issues if we have the will kevin kelly talked about the acceleration of technology that s been a strong interest of mine and a theme that i ve developed for some 30 years i realized that my technologies had to make sense when i finished a project that invariably the world was a different place when i would introduce a technology and i noticed that most inventions fail not because the r d department ca n t get it to work if you look at most business plans they will actually succeed if given the opportunity to build what they say they re going to build and 90 percent of those projects or more will fail because the timing is wrong not all the enabling factors will be in place when they re needed so i began to be an ardent student of technology trends and track where technology would be at different points in time and began to build the mathematical models of that it s kind of taken on a life of its own i ve got a group of 10 people that work with me to gather data on key measures of technology in many different areas and we build models and you ll hear people say well we ca n t predict the future and if you ask me will the price of google be higher or lower than it is today three years from now that s very hard to say will wimax cdma g 3 be the wireless standard three years from now that s hard to say but if you ask me what will it cost for one mips of computing in 2010 or the cost to sequence a base pair of dna in 2012 or the cost of sending a megabyte of data wirelessly in 2014 it turns out that those are very predictable there are remarkably smooth exponential curves that govern price performance capacity bandwidth and i m going to show you a small sample of this but there s really a theoretical reason why technology develops in an exponential fashion and a lot of people when they think about the future think about it linearly they think they re going to continue to develop a problem or address a problem using today s tools at today s pace of progress and fail to take into consideration this exponential growth the genome project was a controversial project in 1990 we had our best ph d students our most advanced equipment around the world we got 1 10 000th of the project done so how re we going to get this done in 15 years and 10 years into the project the skeptics were still going strong says you re two thirds through this project and you ve managed to only sequence a very tiny percentage of the whole genome but it s the nature of exponential growth that once it reaches the knee of the curve it explodes most of the project was done in the last few years of the project it took us 15 years to sequence hiv we sequenced sars in 31 days so we are gaining the potential to overcome these problems i m going to show you just a few examples of how pervasive this phenomena is the actual paradigm shift rate the rate of adopting new ideas is doubling every decade according to our models these are all logarithmic graphs so as you go up the levels it represents generally multiplying by factor of 10 or 100 it took us half a century to adopt the telephone the first virtual reality technology cell phones were adopted in about eight years if you put different communication technologies on this logarithmic graph television radio telephone were adopted in decades recent technologies like the pc the web cell phones were under a decade now this is an interesting chart and this really gets at the fundamental reason why an evolutionary process and both biology and technology are evolutionary processes accelerate they work through interaction they create a capability and then it uses that capability to bring on the next stage so the first step in biological evolution the evolution of dna actually it was rna came first took billions of years but then evolution used that information processing backbone to bring on the next stage so the cambrian explosion when all the body plans of the animals were evolved took only 10 million years it was 200 times faster and then evolution used those body plans to evolve higher cognitive functions and biological evolution kept accelerating it s an inherent nature of an evolutionary process so homo sapiens the first technology creating species the species that combined a cognitive function with an opposable appendage and by the way chimpanzees do n t really have a very good opposable thumb so we could actually manipulate our environment with a power grip and fine motor coordination and use our mental models to actually change the world and bring on technology but anyway the evolution of our species took hundreds of thousands of years and then working through interaction evolution used essentially the technology creating species to bring on the next stage which were the first steps in technological evolution and the first step took tens of thousands of years stone tools fire the wheel kept accelerating we always used then the latest generation of technology to create the next generation printing press took a century to be adopted the first computers were designed pen on paper now we use computers and we ve had a continual acceleration of this process now by the way if you look at this on a linear graph it looks like everything has just happened but some observer says well kurzweil just put points on this graph that fall on that straight line so i took 15 different lists from key thinkers like the encyclopedia britannica the museum of natural history carl sagan s cosmic calendar on the same and these people were not trying to make my point these were just lists in reference works and i think that s what they thought the key events were in biological evolution and technological evolution and again it forms the same straight line you have a little bit of thickening in the line because people do have disagreements what the key points are there s differences of opinion when agriculture started or how long the cambrian explosion took but you see a very clear trend there s a basic profound acceleration of this evolutionary process information technologies double their capacity price performance bandwidth every year and that s a very profound explosion of exponential growth a personal experience when i was at mit computer taking up about the size of this room less powerful than the computer in your cell phone but moore s law which is very often identified with this exponential growth is just one example of many because it s basically a property of the evolutionary process of technology i put 49 famous computers on this logarithmic graph by the way a straight line on a logarithmic graph is exponential growth that s another exponential it took us three years to double our price performance of computing in 1900 two years in the middle we re now doubling it every one year and that s exponential growth through five different paradigms moore s law was just the last part of that where we were shrinking transistors on an integrated circuit but we had electro mechanical calculators relay based computers that cracked the german enigma code vacuum tubes in the 1950s predicted the election of eisenhower discreet transistors used in the first space flights and then moore s law every time one paradigm ran out of steam another paradigm came out of left field to continue the exponential growth they were shrinking vacuum tubes making them smaller and smaller that hit a wall they could n t shrink them and keep the vacuum whole different paradigm transistors came out of the woodwork in fact when we see the end of the line for a particular paradigm it creates research pressure to create the next paradigm and because we ve been predicting the end of moore s law for quite a long time the first prediction said 2002 until now it says 2022 but by the teen years the features of transistors will be a few atoms in width and we wo n t be able to shrink them any more that ll be the end of moore s law but it wo n t be the end of the exponential growth of computing because chips are flat we live in a three dimensional world we might as well use the third dimension we will go into the third dimension and there s been tremendous progress just in the last few years of getting three dimensional self organizing molecular circuits to work we ll have those ready well before moore s law runs out of steam supercomputers same thing processor performance on intel chips the average price of a transistor 1968 you could buy one transistor for a dollar you could buy 10 million in 2002 it s pretty remarkable how smooth an exponential process that is i mean you d think this is the result of some tabletop experiment but this is the result of worldwide chaotic behavior countries accusing each other of dumping products ipos bankruptcies marketing programs you would think it would be a very erratic process and you have a very smooth outcome of this chaotic process just as we ca n t predict what one molecule in a gas will do it s hopeless to predict a single molecule yet we can predict the properties of the whole gas using thermodynamics very accurately it s the same thing here we ca n t predict any particular project but the result of this whole worldwide chaotic unpredictable activity of competition and the evolutionary process of technology is very predictable and we can predict these trends far into the future unlike gertrude stein s roses it s not the case that a transistor is a transistor as we make them smaller and less expensive the electrons have less distance to travel they re faster so you ve got exponential growth in the speed of transistors so the cost of a cycle of one transistor has been coming down with a halving rate of 1 1 years you add other forms of innovation and processor design you get a doubling of price performance of computing every one year and that s basically deflation 50 percent deflation and it s not just computers i mean it s true of dna sequencing it s true of brain scanning it s true of the world wide web i mean anything that we can quantify we have hundreds of different measurements of different information related measurements capacity adoption rates and they basically double every 12 13 15 months depending on what you re looking at in terms of price performance that s a 40 to 50 percent deflation rate and economists have actually started worrying about that we had deflation during the depression but that was collapse of the money supply collapse of consumer confidence a completely different phenomena this is due to greater productivity but the economist says but there s no way you re going to be able to keep up with that if you have 50 percent deflation people may increase their volume 30 40 percent but they wo n t keep up with it but what we re actually seeing is that we actually more than keep up with it we ve had 28 percent per year compounded growth in dollars in information technology over the last 50 years i mean people did n t build ipods for 10 000 dollars 10 years ago as the price performance makes new applications feasible new applications come to the market and this is a very widespread phenomena magnetic data storage that s not moore s law it s shrinking magnetic spots different engineers different companies same exponential process a key revolution is that we re understanding our own biology in these information terms we re understanding the software programs that make our body run these were evolved in very different times we d like to actually change those programs one little software program called the fat insulin receptor gene basically says hold onto every calorie because the next hunting season may not work out so well that was in the interests of the species tens of thousands of years ago we d like to actually turn that program off they tried that in animals and these mice ate ravenously and remained slim and got the health benefits of being slim they did n t get diabetes they did n t get heart disease they lived 20 percent longer they got the health benefits of caloric restriction without the restriction four or five pharmaceutical companies have noticed this felt that would be interesting drug for the human market and that s just one of the 30 000 genes that affect our biochemistry we were evolved in an era where it was n t in the interests of people at the age of most people at this conference like myself to live much longer because we were using up the precious resources which were better deployed towards the children and those caring for them so life long lifespans like that is to say much more than 30 were n t selected for but we are learning to actually manipulate and change these software programs through the biotechnology revolution for example we can inhibit genes now with rna interference there are exciting new forms of gene therapy that overcome the problem of placing the genetic material in the right place on the chromosome there s actually a for the first time now something going to human trials that actually cures pulmonary hypertension a fatal disease using gene therapy so we ll have not just designer babies but designer baby boomers and this technology is also accelerating it cost 10 dollars per base pair in 1990 then a penny in 2000 it s now under a 10th of a cent the amount of genetic data basically this shows that smooth exponential growth doubled every year enabling the genome project to be completed another major revolution the communications revolution the price performance bandwidth capacity of communications measured many different ways wired wireless is growing exponentially the internet has been doubling in power and continues to measured many different ways this is based on the number of hosts miniaturization we re shrinking the size of technology at an exponential rate both wired and wireless these are some designs from eric drexler s book which we re now showing are feasible with super computing simulations where actually there are scientists building molecule scale robots one has one that actually walks with a surprisingly human like gait that s built out of molecules there are little machines doing things in experimental bases the most exciting opportunity is actually to go inside the human body and perform therapeutic and diagnostic functions and this is less futuristic than it may sound these things have already been done in animals there s one nano engineered device that cures type 1 diabetes it s blood cell sized they put tens of thousands of these in the blood cell they tried this in rats it lets insulin out in a controlled fashion and actually cures type 1 diabetes what you re watching is a design of a robotic red blood cell and it does bring up the issue that our biology is actually very sub optimal even though it s remarkable in its intricacy once we understand its principles of operation and the pace with which we are reverse engineering biology is accelerating we can actually design these things to be thousands of times more capable an analysis of this respirocyte designed by rob freitas indicates if you replace 10 percent of your red blood cells with these robotic versions you could do an olympic sprint for 15 minutes without taking a breath you could sit at the bottom of your pool for four hours so honey i m in the pool will take on a whole new meaning it will be interesting to see what we do in our olympic trials presumably we ll ban them but then we ll have the specter of teenagers in their high schools gyms routinely out performing the olympic athletes freitas has a design for a robotic white blood cell these are 2020 circa scenarios but they re not as futuristic as it may sound there are four major conferences on building blood cell sized devices there are many experiments in animals there s actually one going into human trial so this is feasible technology if we come back to our exponential growth of computing 1 000 dollars of computing is now somewhere between an insect and a mouse brain it will intersect human intelligence in terms of capacity in the 2020s but that ll be the hardware side of the equation where will we get the software well it turns out we can see inside the human brain and in fact not surprisingly the spatial and temporal resolution of brain scanning is doubling every year and with the new generation of scanning tools for the first time we can actually see individual inter neural fibers and see them processing and signaling in real time but then the question is ok we can get this data now but can we understand it doug hofstadter wonders well maybe our intelligence just is n t great enough to understand our intelligence and if we were smarter well then our brains would be that much more complicated and we d never catch up to it it turns out that we can understand it this is a block diagram of a model and simulation of the human auditory cortex that actually works quite well in applying psychoacoustic tests gets very similar results to human auditory perception there s another simulation of the cerebellum that s more than half the neurons in the brain again works very similarly to human skill formation this is at an early stage but you can show with the exponential growth of the amount of information about the brain and the exponential improvement in the resolution of brain scanning we will succeed in reverse engineering the human brain by the 2020s we ve already had very good models and simulation of about 15 regions out of the several hundred all of this is driving exponentially growing economic progress we ve had productivity go from 30 dollars to 150 dollars per hour of labor in the last 50 years e commerce has been growing exponentially it s now a trillion dollars you might wonder well was n t there a boom and a bust that was strictly a capital markets phenomena wall street noticed that this was a revolutionary technology which it was but then six months later when it had n t revolutionized all business models they figured well that was wrong and then we had this bust all right this is a technology that we put together using some of the technologies we re involved in this will be a routine feature in a cell phone it would be able to translate from one language to another so let me just end with a couple of scenarios by 2010 computers will disappear they ll be so small they ll be embedded in our clothing in our environment images will be written directly to our retina providing full immersion virtual reality augmented real reality we ll be interacting with virtual personalities but if we go to 2029 we really have the full maturity of these trends and you have to appreciate how many turns of the screw in terms of generations of technology which are getting faster and faster we ll have at that point i mean we will have two to the 25th power greater price performance capacity and bandwidth of these technologies which is pretty phenomenal it ll be millions of times more powerful than it is today we ll have completed the reverse engineering of the human brain 1 000 dollars of computing will be far more powerful than the human brain in terms of basic raw capacity computers will combine the subtle pan recognition powers of human intelligence with ways in which machines are already superior in terms of doing analytic thinking remembering billions of facts accurately machines can share their knowledge very quickly but it s not just an alien invasion of intelligent machines we are going to merge with our technology these nano bots i mentioned will first be used for medical and health applications cleaning up the environment providing powerful fuel cells and widely distributed decentralized solar panels and so on in the environment but they ll also go inside our brain interact with our biological neurons we ve demonstrated the key principles of being able to do this so for example full immersion virtual reality from within the nervous system the nano bots shut down the signals coming from your real senses replace them with the signals that your brain would be receiving if you were in the virtual environment and then it ll feel like you re in that virtual environment you can go there with other people have any kind of experience with anyone involving all of the senses experience beamers i call them will put their whole flow of sensory experiences in the neurological correlates of their emotions out on the internet you can plug in and experience what it s like to be someone else but most importantly it ll be a tremendous expansion of human intelligence through this direct merger with our technology which in some sense we re doing already we routinely do intellectual feats that would be impossible without our technology human life expectancy is expanding it was 37 in 1800 and with this sort of biotechnology nano technology revolutions this will move up very rapidly in the years ahead my main message is that progress in technology is exponential not linear many even scientists assume a linear model so they ll say oh it ll be hundreds of years before we have self replicating nano technology assembly or artificial intelligence if you really look at the power of exponential growth you ll see that these things are pretty soon at hand and information technology is increasingly encompassing all of our lives from our music to our manufacturing to our biology to our energy to materials we ll be able to manufacture almost anything we need in the 2020s from information in very inexpensive raw materials using nano technology these are very powerful technologies they both empower our promise and our peril so we have to have the will to apply them to the right problems thank you very much
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//To determine the Load factor and suitable units for 24 hr operation of the plant //Page 78 clc; clear; //Demands at Various Time Periods starting from 12PM to 12PM D1=500*(10^3); D2=800*(10^3); D3=2000*(10^3); D4=1000*(10^3); D5=2500*(10^3); D6=2000*(10^3); D7=1500*(10^3); D8=1000*(10^3); MD=D5; //Maximum Demand //Time Periods of demands ststing from 12PM T1=5; T2=5; T3=2; T4=2; T5=3; T6=3; T7=2; T8=2; //Total Energy Demand in 24hrs TED=(T1*D1)+(T2*D2)+(T3*D3)+(D4*T4)+(T5*D5)+(D6*T6)+(D7*T7)+(T8*D8); LF=TED*100/(24*MD); printf('Since Maximum Demand is 2500 kW, 2 units 0f 1000W and one unit of 500W is required. Also for continuity of supply, A reserve of 1000W unit is required.\n') C1000=3*1000*(10^3); //1000 unit C500=1*500*(10^3); //500 Unit TCP=C1000+C500; //Total capacity of the plant PCF=TED*100/(24*TCP); //Plant Capacity Factor //Operating Schedule, Units operated can be seen in the textbook G1=500*(10^3); G2=1000*(10^3); G3=2000*(10^3); G4=1000*(10^3); G5=2500*(10^3); G6=2000*(10^3); G7=1500*(10^3); G8=1000*(10^3); TEG=(T1*G1)+(T2*G2)+(T3*G3)+(G4*T4)+(T5*G5)+(G6*T6)+(G7*T7)+(T8*G8);//Total Energy Generated PUF=TED*100/(TEG); //Plant Use Factor printf('a) The Reserve Capacity is a 1000kW Unit and Load Factor is %g percent\n',LF) printf('b) The Plant Capacity Factor is %g percent\n',PCF) printf('c) The Plant Use Factor is %g percent\n',PUF)
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Ex13_6.sce
//Ex:13.6 clc; clear; close; f_rf_1=88;//in MHz f_rf_2=108;//in MHz f_if=10.7;//in MHz f_lo_1=f_rf_1+f_if; f_lo_2=f_rf_2+f_if; printf("The range local oscillator be tuned =%f MHz & %f MHz",f_lo_1,f_lo_2);
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clc; clear; a=0.2 //lattice parameter in nm h=1 //x intercept of parallel plane k=1 //y intercept of parallel plane l=1 //z intercept of parallel plane phi=87 //incident angle in degree //calculation tetha=phi/2 d=(a/sqrt(h^2+k^2+l^2)) lambda=(2*d*sind(tetha)) mprintf("The wavelength is = %1.3f nm\n",lambda) mprintf("The Braggs angle is = %2.1f degree",tetha)
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//Exa 2.11 clc; clear; close; //Given data : R2=0.5;//in ohm X=4.5;//im ohm E=50;//line voltage in volt Eperphase=E/sqrt(3);//in volt //part (a) : Sliprings are short circuited Z2=sqrt(R2^2+X^2);//in ohm I2=Eperphase/Z2;//in Ampere disp(I2,"Sliprings are short circuited, Rotor current in Ampere : "); cosfi2=R2/Z2;//unitless disp(cosfi2,"Power factor : "); //part (b) : Sliprings are connected R2=0.4;//in ohm Z2=sqrt(R2^2+X^2);//in ohm I2=Eperphase/Z2;//in Ampere disp(I2,"Sliprings are short circuited, Rotor current in Ampere : "); cosfi2=R2/Z2;//unitless disp(cosfi2,"Power factor : "); //Note : answer of part (a) I2 is not curate in the book.
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clc; //Example 25.4 //page no 373 printf("\nExample 25.4 page no 373\n\n"); //a absorber bed consists of cube particles L=3/4//edge length of particle V_p=L^3//volume of particle S_p=6*L^2//surface area of particle a_p=6*L^2/L^3//specific particle surface area printf("\n specific particle surface area a_p=%f in^-1",a_p); d_p_e = L//effective particle diameter = edge length printf("\n effective particle diameter d_p_e=%f in",d_p_e)
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funcprot(0); CHEMIN = 'C:\Users\Hugo Jové (sécurité)\Desktop\Simulations-numeriques'; global AFFICHER_HISTO AFFICHER_HISTO = %t; global AFFICHER_EXO1; AFFICHER_EXO1 = %f; global AFFICHER_EXO2; AFFICHER_EXO2 = %f; global AFFICHER_EXO3; AFFICHER_EXO3 = %t; function main() clc; clf(); chdir(CHEMIN); getd('utils'); getd('scripts'); if AFFICHER_EXO1 then // Partie 1 // Q1 // Yn = centrerReduireUnif(1000); // Q2 // lambda=1; // Yn = centrerReduireExpo(lambda, 1000); // // Partie 2 n = 100; p = 0.03; lambda = n*p; Xi = genererRandBinomiale(n,p,1000); // if AFFICHER_HISTO then // histplot(50,Yn); // tracerDensiteNormale(1000,0,1) histplot(50,Xi); tracerDensitePoisson(min(Xi), max(Xi), lambda); end end if AFFICHER_EXO2 then // Exercice 2 pour 1 réalisation // Xn_barre = moyenneEmpirique(500); // plot2d(Xn_barre); // Exercice 2 pour plusieurs réalisations for i=1:50 Xn_barre = moyenneEmpirique(500); plot2d(Xn_barre); end end if AFFICHER_EXO3 then // Exercice 3 // marche1 = marcheAleatoire(20, 1, 1); // plot2d(marche1) // marche2 = marcheAleatoire(100, 1, 1); // plot2d(marche2) // marche3 = marcheAleatoire(1000, 1, 1); // plot2d(marche3) // for i=1:1000 // marche3 = marcheAleatoire(1000, 1, 1); // plot2d(marche3) // end // marche4 = marcheAleatoireReduc(10000,1,1); // plot2d(marche4); for i=1:200 marche4 = marcheAleatoireReduc(10000,1,1); res(i) = marche4($) end histplot(50, res); // alpha vaut 0.0000452 après 10 000 pas alpha = 0.0000452; tracerDensiteNormale(1000, 0, sqrt(alpha)); end endfunction main()
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//example 3.8// //not using nor 2 different input// clc //refreshes all variables// clear //clears the screen// disp('The first two EX-NOR gates implement a two input EX-OR gate using two input EX-NOR gates. The second EX-NOR gate here has been wired as a NOT circuit. The output of the second gate and the third input are fed to the two inputs of the third EX-NOR gates.') //result//
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ex5_3.sce
// Exa 5.3 format('v',7);clc;clear;close; // Given data // Values of resistances of the circuit R1 = 7;// in k ohm R2 = 2;// in k ohm R3 = 4;// in k ohm R4 = 20;// in k ohm Rg = 300;// in ohm E = 8;// in V //Use Thevenin's equivalent for Ig, V_TH=V_BD=V_AD-V_AB=( ((E/(R3+R4))*R4) - ((E/(R1+R2))*R1) ); V_TH = ( ((E/(R3+R4))*R4) - ((E/(R1+R2))*R1) );// in V Req = ((R1*R2)/(R1+R2)) + ((R3*R4)/(R3+R4));// in k ohm // Current through galvanometer Ig = V_TH/((Req*10^3)+Rg);// in A Ig = Ig * 10^6;// in µA disp(Ig,"The current through galvanometer in µA is");
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clc; //ex3.2 d=2*10**-3; sigma=5.8*10**7; mu=0.0032; E=20*10**-3; q=1.6*10**-19; n=sigma/(q*mu);//sigma=q*n*mu disp('/m^3',n*1,"n="); J=sigma*E;//current density disp('A/m^2',J*1,"J="); A=%pi*d*d/4;//area of cross-section of wire disp('m^2',A*1,"A="); I=J*A;//current flowing in the wire disp('A',I*1,"I="); V=mu*E;//electron drift velocity disp('m/s',V*1,"V=");//answer printed in the book is wrong
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clc clear //INPUT DATA l=1.2;//Length of of bar in m //CALCULATIONS k=sqrt(l^2/12);//Radius of gyration in m T=sqrt(((k^2/(l/2))+(l/2))/9.8)*2*3.14;//Time period of the pendulum in s L=((9.8*T^2)/(4*3.14^2));//Length in m D=L-(l/2);//Another point where pendulum has same timeperiod in m //OUTPUT mprintf('The time period of pendulum is %3.3f s\nDistance of another point from centre of gravity on bar with same time period is %3.1f m',T,D)
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clc // Given that V = 980 // volume in meter^3 a1 = 150 // area of wall in m^2 a2 = 95 // area of ceiling in m^2 a3 = 90 // area of floor in m^2 k1 = 0.03 // coefficient of absorption for wall in O.W.U. k2 = 0.80 // coefficient of absorption for ceiling in O.W.U. k3 = 0.06 // coefficient of absorption for floor in O.W.U. // Sample Problem 8 on page no. 8.21 printf("\n # PROBLEM 8 # \n") printf(" Standard formula used \n") printf(" T = 0.161 V/a*S \n" ) A1 = a1 * k1 A2 = a2 * k2 A3 = a3 * k3 A = A1 + A2 + A3 T = 0.161 * (V / A) printf("\n Reverberation time = %f sec",T)
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A=100;//cross sectional area of a stringer r=381;//radius of the fuselage,given in mm t=0.8;//thickness,given in mm Mx=200*10^6;
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// Exa 3.15 clc; clear; close; // Given data C_P = 1.041;// in kJ/kg-K C_V = 0.743;// in kJ/kg-K R = C_P - C_V;// in kJ/kg-K P1 = 140;// in kN/m^2 P2 = 1400;// in kN/m^2 V1 = 0.14;// in m^3 T1 = 25;// in degree C T1 = T1 + 273;// in K Gamma = 1.4; n = 1.25; m = (P1 * 10^3 *V1)/(R * 10^3 * T1);// in kg V2 = V1 * (P1/P2)^(1/n);// in m^3 del_U = C_P * (log(V2/V1)) + C_V * (log(P2/P1));// in kJ/kg-K del_U = m * del_U;// in kJ/K disp("Part (i)") disp(del_U,"Change in entropy in kJ/K is"); T2 = T1 * (V1/V2)^(n-1);// in K del_U1 = C_P * (log(T2/T1)) - R*(log(P2/P1));// in kJ/kg-K disp("Part (ii)") disp(del_U1,"Change in entropy in kJ/kg-K is"); del_U2 = C_V * (log(T2/T1)) + R*(log(V2/V1));// in kJ/kg-K disp("Part (iii)") disp(del_U2,"Change in entropy in kJ/kg-K is"); del_U3 = C_V * (Gamma-n) * (log(V2/V1));// in kJ/kg-K disp("Part (iv)") disp(del_U3,"Change in entropy in kJ/kg-K is"); del_U4 = C_V * ((Gamma-n)/(n-1)) * (log(T1/T2));// in kJ/kg-K disp("Part (v)") disp(del_U4,"change in entropy in kJ/kg is"); del_U5 = C_V * ((Gamma-n)/n) * (log(P1/P2));// in kJ/kg-K disp("Part (vi)") disp(del_U5,"Change in entropy in kJ/kg-k is");
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//Example 12.15 //Note: MAXIMA SCILAB TOOLBOX REQUIRED FOR THIS PROGRAM //Program to: //(a)Derive an expression for the improvement in post detection SNR //(b)Determine the improvement in post detection SNR and Bandwidth clear; clc ; close ; //(a)Derive an expression for the improvement in post detection SNR //Symbolic Representation syms Pa R Po Ba No Df //D-IM OUTPUT SNR SNR_DIM=(R*Po)^2*Pa/(2*Ba*No); //FM OUTPUT SNR SNR_FM=3*Df^2*(R*Po)^2*Pa/(4*Ba*No); //SNR IMPROVEMENT SNR_imp=SNR_FM/SNR_DIM; //SNR IMPROVEMENT IN dB SNR_imp_dB=10*log10(SNR_imp); disp(SNR_imp,"SNR IMPROVEMENT = "); disp(SNR_imp_dB,"SNR IMPROVEMENT IN dB = "); printf("\n\n\t The above expression is equivalent to 1.76+20*log10(Df)"); //(b)Determine the improvement in post detection SNR and Bandwidth //Given data fd1=400*10^3; //Hz - PEAK FREQUENCY DEVIATION Ba1=4*10^3; //Hz- BANDWIDTH //Frequency Deviation Ratio Df1=fd1/Ba1; //SNR Improvement expression from part(a) SNR_imp_dB1=1.76+20*log10(Df1); //Bandwidth Bm=2*(Df1+1)*Ba1; printf("\n\n\t The SNR Improvement = %0.2f dB.",SNR_imp_dB1); printf("\n\n\t The Bandwidth of FM-IM, Bm = %1.0f kHz.",Bm/10^3);
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void main() { int i; int compt = 0; for(i = 0; i < 100; i = i + 1) { compt = compt + i; } }
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// FUNÇÃO PARA ACHAR SEGUIMENTO DE RETA MAIS PRÓXIMO // Função que encontra o índice de um seguimento de reta, dentro de uma lista de // seguimenos de retas, L(i), aquela que seja a mais próxima de um dado 'ponto' // [x y]. O elemento da lista que define o seguimento de reta é uma matriz 2x2 // que contém seu ponto inicial e final nas linhas da matriz function pos = RetaMaisProx(eixo,ponto,L,varargin) // Ajusta a escala dos eixos LX = eixo.data_bounds(2)-eixo.data_bounds(1); LY = eixo.data_bounds(4)-eixo.data_bounds(3); if eixo.isoview == "on" then sclfac = 1 else W = eixo.parent.position(3)*(1 - sum(eixo.margins(1:2))) H = eixo.parent.position(4)*(1 - sum(eixo.margins(3:4))) sclfac = (LX/W)*(H/LY); end // Ponto dado x = ponto(1); y = sclfac*ponto(2); for i=1:length(L) x1=L(i)(1,1); y1=L(i)(1,2)*sclfac; x2=L(i)(2,1); y2=L(i)(2,2)*sclfac; D = gsort([x1 x2],"g","i") Im = gsort([y1 y2],"g","i") a = (y2-y1)/(x2-x1) b = -1 c = y1-a*x1 xInt = (y+x/a-c)/(a+1/a) [x1 x2] = (D(1),D(2)) [y1 y2] = (Im(1),Im(2)) if abs(x1-x2)<=%eps & y>=y1 & y<=y2 then dist(i) = abs(x-x1) //------------------------ Caso reta vertical elseif abs(y1-y2)<=%eps & x>=x1 & x<=x2 then dist(i) = abs(y-y1) //------------------------ Caso reta horizontal elseif abs(x1-x2)>%eps & abs(y1-y2)>%eps & xInt>=x1 & xInt<=x2 then dist(i) = abs(a*x+b*y+c)/sqrt(a^2+b^2) //----- Caso reta inclinada else // Interseção fora do domínio (menor distânica não perpendicular) dist(i) = min(sqrt((x-[x1 x2])^2+(y-[y1 y2])^2)) end end // Verifica distânica mínima, caso não haja argumento varargin if min(dist)<=min(LX,sclfac*LY)/5 || ~isempty(varargin) then pos = find(dist==min(dist)); else pos = []; end endfunction
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clc; clear; mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-12.7 Page No.270\n'); Su=95*10^3; Sn=0.5*Su; Np=24; Pd=16; Dp=Np/Pd; //Torque n=3450; P=3; T=P*63000/n; mprintf('\n Torque = %f in-lb.',T); //Force transmitted Ft=2*T/Dp; mprintf('\n Force transmitted = %f lb.',Ft); //Surface speed Vm=%pi*Dp*n/12; mprintf('\n Surface speed = %f ft/min.',Vm); //Force allowable Y=0.337; b=1; Fs=Sn*b*Y/Pd; mprintf('\n Force allowable = %f lb.',Fs); //Dynamic load using Buckingham's equation C=830; Fd=Ft+0.05*Vm*(b*C+Ft)/(0.05*Vm+(b*C+Ft)^0.5); Nsf=1.4; if (Fs/Nsf)>Fd then mprintf('\n This is a suitable design'); end
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T = 500; alpha = 0.05; r = 10; val1 = cdfchi("X", 2*r, 1-alpha/2, alpha/2); val2 = cdfchi("X", 2*r, alpha/2, 1- alpha/2); int1= 2*T/val1; int2= 2*T/val2; disp("The 95% confidence interval is"); disp(int1); disp(int2, "to"); //The confidence interval is from 29.27 to 103.52 whereas my solution in Scilab is 29.265774 to 104.26683 because of the difference in the value of chi-square(0.975, 30). The textbook says the value is 9.66 whereas scilab calculates its value as 9.5907774 .
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funcprot(0); //clear; xdel(winsid()); // close all previously opened windows // Personal workstation (Linux) exec('/media/Documents/Etudes/ENSTA-Bretagne/Stages/ENSI3-UFRGS/reliable-slam/workspace/Analysis/Plots/General/boxUtils.sce', -1) path_in='/media/Documents/Etudes/ENSTA-Bretagne/Stages/ENSI3-UFRGS/reliable-slam/workspace/Analysis/IntervalAnalysis/Results/BESE/'; // Smaller circle trajectory //ground_truth=read_csv(path_in+'GroundTruth3.res',';'); //data_truth=evstr(ground_truth); linspeed_generatedx=diff(data_truth(:,1))/0.1; linspeed_generatedy=diff(data_truth(:,2))/0.1; linspeed_generatedz=diff(data_truth(:,3))/0.1; linspeed_generated_norm=sqrt(linspeed_generatedx^2+linspeed_generatedy^2+linspeed_generatedz^2); linspeed_morsex=data_truth(:,7); linspeed_morse_norm=sqrt(data_truth(:,7)^2+data_truth(:,8)^2+data_truth(:,9)^2); angspeed_generatedx=diff(data_truth(:,4))/0.1; angspeed_generatedy=diff(data_truth(:,5))/0.1; angspeed_generatedz=diff(data_truth(:,6))/0.1; angspeed_generated_norm=sqrt(angspeed_generatedx^2+angspeed_generatedy^2+angspeed_generatedz^2); angspeed_morse_norm=sqrt(data_truth(:,10)^2+data_truth(:,11)^2+data_truth(:,12)^2); plot(angspeed_generated_norm,'cyan') plot(angspeed_morse_norm,color('purple')) plot(angspeed_generatedx,'r'); plot(angspeed_generatedy,'g'); plot(angspeed_generatedz,'b'); plot(angspeed_generatedz,'magenta');
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//Tested on Windows 7 Ultimate 32-bit //Chapter 4 Bipolar Junction transistors Pg no. 139 clear; clc; //Given Data B=140;//dc current gain of CE configuration IE=2D-3;//emitter current in amperes Rl1=2D3;//load resistance in ohms Rl2=1.2D3;//load resistance in ohms VT=26D-3;//temperature equivalent voltage of pn junction //Solution disp("(a)"); re=VT/IE;//emitter diode resistance in ohms Zi=B*re;//input impedance in ohms printf("Input impedance of CE circuit = re = %d ohms\n",Zi); disp("(b)"); Gv=-Rl1/re;//voltage gain printf("Voltage gain of CE circuit at 2k-ohm load = Gv = %.1f\n",Gv); disp("(c)"); Gi=B;//current gain printf("Current Gain Gi = %d",Gi); //Error in voltage gain in part (b) as Rl is mistaken as 1.2 kilo-ohm instead of 2 kilo-ohm
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clear; clc; close; yos = 20*10^(-6); Vgs_on = 8; Vgs_th = 3; Vgsq = 6.4; Idq = 2.75*10^(-3); Id_on = 6*10^(-3); k = 0.24*10^(-3); Rf = 10*10^(6); Rd = 2*10^(3); gm = 2*k*(Vgsq-Vgs_th); rd = 1/yos; Zi = (Rf+(rd*Rd/(rd+Rd)))/(1+gm*(rd*Rd/(rd+Rd))); Zi2 = Rf/(1+gm*Rd); Zo = Rf*Rd*rd/(Rf*rd+rd*Rd+Rd*Rf); Zo2 = Rd; Av = -gm*Rf*Rd*rd/(Rf*rd+rd*Rd+Rd*Rf); Av2 = -gm*Rd; disp(gm,'gm(S) = '); disp(rd,'rd(ohms) = '); disp(Zi,'Zi(ohms) = '); disp(Zi2,'Zi without rd(ohms) = '); disp(Zo,'Zo(ohms) = '); disp(Zo2,'Zo without rd(ohms) = ') disp(Av,'Voltage gain Av = '); disp(Av2,'Volatge gain Av(ignoring rd) = ');
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function sl=square(varargin) select argn(2) case 1 then sl=squarewave(varargin(1)); case 2 then sl=squarewave(varargin(1),varargin(2)); else disp('Error'); break; end endfunction
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//Trabalho de Simulação //Disciplina: Sistemas de Comunicação II //Dupla: Stéphanie Braga e Hugaleno //Questão 3 e 4- Equalizador ZF e Diagramas de Olho. clc; close;close;close;close; clear; N = 100; x = sign(rand(1,N,'n')); //canal h=[-0.25, 0.80, 0.2, -0.15, 0.10]; //Sinal pelo canal y=filter(h,1,x); //fir // Equalizador zero forcing com 5 coeficientes: C=[0;0;1;0;0]; //vetor de coeficientes H=[h(2),h(1),0,0,0 h(3),h(2),h(1),0,0 h(4),h(3),h(2),h(1),0 h(5),h(4),h(3),h(2),h(1) 0,h(5),h(4),h(3),h(2)]; wz = inv(H)*C; //coeficientes do equalizador hz = convol(h,wz); // Equalizador zero forcing com 7 coeficientes: C2=[0;0;0;0;0;0;1]; //coeficientes H2=[h(2),h(1),0,0,0,0,0 h(3),h(2),h(1),0,0,0,0 h(4),h(3),h(2),h(1),0,0,0 h(5),h(4),h(3),h(2),h(1),0,0 0,h(5),h(4),h(3),h(2),0,0 0,0,h(5),h(4),h(3),h(2),0 0,0,0,h(5),h(4),h(3),h(2)]; wz2 = inv(H2)*C2; hz2 = convol(h,wz2); //Calculando a ISI residual IESr=(sum(hz2.*hz2) - max(hz2.*hz2))/max(hz2.*hz2); disp(IESr); //equalizando o sinal: z= filter(wz,1,y); z2= filter(wz2,1,y); //mostra o sinal subplot(4,1,1); title('Sinal'); plot(1:N,x,'.'); //mostra o sinal apos canal subplot(4,1,2); title('Sinal após canal'); plot(1:N,y,'.'); //mostra o sinal equalizado subplot(4,1,3); title('Sinal equalizado (ZF-5)'); plot(1:N,z,'.'); //mostra o sinal equalizado subplot(4,1,4); title('Sinal equalizado (ZF-7)'); plot(1:N,z2,'.'); ////mostra todos os sinais //figure; ////subplot(5,1,5); //title('Todos os Sinais'); //plot(1:N,x,'o'); //plot(1:N,y,'r*'); //plot(1:N,z2,'kx'); //xgrid; ////plot(1:N,z2,'g*'); // //figure; ////mostra a Resposta ao Impulso do canal //subplot(3,1,1); //title('Resposta ao Impulso do canal'); //plot2d3(h); //plot(h); //xgrid; // //subplot(3,1,2); //title('Resposta ao Impulso após Eq. ZF (5)'); //plot2d3(hz); //plot(hz); //xgrid; // //subplot(3,1,3); //title('Resposta ao Impulso após Eq. ZF (7)'); //plot2d3(hz2); //plot(hz2); //xgrid; // //figure; //subplot(3,1,1); //title('Diag. de olho - sinal antes do canal'); //p1 = 1; p2 = 3; //for k=1:25 // plot(1:3,x(p1:p2)); // p1 = p2; p2 = p1 + 2; //end // //subplot(3,1,2); //title('Diag. de olho - sinal depois do canal'); //p1 = 1; p2 = 3; //for k=1:25 // plot(1:3,y(p1:p2)); // p1 = p2; p2 = p1 + 2; //end // //subplot(3,1,3); //title('Diag. de olho - Sinal depois do Eq. ZF'); //p1 = 1; p2 = 3; //for k=1:25 // plot(1:3,z2(p1:p2)); // p1 = p2; p2 = p1 + 2; //end // ////plot2d3(hz2); ////plot(hz2); //xgrid; //
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//Example 25.1 c=3*10^8;//Speed of light (m/s) n=1.923;//Index of refraction for zircon, See Table 25.1 v=c/n;//Speed of light in zircon (m/s) printf('Speed of light in zircon = %0.2e m/s',v) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/latest
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//Example 7.7. Refer fig.7.13. clc format(5) VDD=24 R2=8.57*10^6 R1=12*10^6 VP=-2 IDSS=4*10^-3 RD=910 RS=3*10^3 disp("From fig.7.13.,") VGG=round(VDD*(R2/(R1+R2))) disp(VGG," VGG(V) = VDD*(R2 / (R1+R2)) =") disp("Also, ID = IDSS*(1-(VGS/VP))^2") disp(" = IDSS*(1-((VGG-(ID*RS))/VP))^2, where VGS = VGG - ID*RS") disp("Expressing ID and IDSS in mA, we have") disp(" 9ID^2 - 73ID +144 = 0 ") x=poly(0,'x') p1=roots((9*x^2) - (73*x) +144) ans1=p1(1) p1=roots((9*x^2) - (73*x) +144) ans2=p1(2) disp(ans2,"or",ans1,"Therefore, ID(mA) = ") disp("As ID = 4.72mA > 4mA = IDSS, this value is inappropriate. So, IDQ=3.39 mA is selected.") disp("Therefore,") IDQ=3.39*10^-3 VGSQ=VGG-(IDQ*RS) disp(VGSQ," VGSQ(V) = VGG - (IDQ*RS) =") format(7) VDSQ=VDD-(IDQ*(RD+RS)) disp(VDSQ,"and VDSQ(V) = VDD - (IDQ*(RD+RS)) =") VDGQ = VDSQ - VGSQ disp(VDGQ,"Then, VDGQ(V) = VDSQ - VGSQ") disp("which is grater than |VP| = 2 V. Hence, the FET is in the pinch-off region.")
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clc; h=6.63*10^-34; //Plancks constant in J.sec m=9.1*10^-31; //mass in kg r1=5.3*10^-11; //radius in m v=h/(2*%pi*m*r1); //calculating velocity in m/sec disp(v,"Velocity in m/sec = "); //displaying result
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//Exa 2.10 clc; clear; close; //given data format('v',9) d=1.2*10^-3;// in m r=d/2;// in m rc=1.8*10^-3;// in m T1=100;// in degree C T_infinite=30;// in degree C k=0.3;// in W/mK h=10;// in W/m^2K L=1;// in m ke=5.1*10^7; q=(T1-T_infinite)/(log(rc/r)/(2*%pi*k)+1/(2*%pi*rc*h));// in W/m // Volume of wire for one meter length vol= %pi*r^2*L;// in m^3 disp("in steady state heat transfer process, the heat produced by the wire is dissipated to surrounding.") // Heat produced per unit volume of the wire HeatProduced= q/vol;// in w/m^2 // Formula HeatProduced= I^2*R = I^2/ke I=sqrt(HeatProduced*ke);// in amp/m^2 // Area of wire A= %pi*r^2; // so current carrying capacity of the given wire Current= I*A; disp(Current,"The current carried by the copper wire in amphere")
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//To calculate the conductivity of intrinsic Silicon ni = 1.5*10^16; //intrinsic charge carriers per m^3 e = 1.6*10^-19; mew_e = 0.13; //electron mobility, m^2/Vs mew_h = 0.05; //hole mobility, m^2/Vs sigma = ni*e*(mew_e+mew_h); //conductivity, ohm-1 m-1 printf("conductivity is %f ohm-1 m-1",sigma); AW = 28.1; //atomic weight of Si, kg d = 2.33*10^3; //density of Si, kg/m^3 N = 6.02*10^26; //avagadro number Nd = d*N/AW; //impurity atoms per m^3 Nd = Nd/10^8; //extent of 10^8 Si atoms p = ni^2/Nd; //hole concentration per m^3 sigma_ex = Nd*e*mew_e; //conductivity, ohm-1 m-1 printf("conductivity if donor type impurity is added is %5.2f ohm-1 m-1",sigma_ex); Na = Nd; n = ni^2/Na; //electron concentration per m^3 sigma_EX = Na*e*mew_h; //conductivity, ohm-1 m-1 printf("conductivity if acceptor type impurity is added is %5.2f ohm-1 m-1",sigma_EX);
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clc; clear all; disp("Sphere Surface temperature") r=1.6/2;//m H=5.5;//m k=0.51;// W/(m*C) Qg=580;// W te=6;// degree C Sfc=4*3.1416*r/(1-r/(2*H)); //Qg=k*Sfc*(t-te); t=Qg/(k*Sfc)+te; disp("degree C",t,"surface temperature of sphere, t =")
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//Initilization of variables m1=2 //kg theta=20 //degrees m2=4 //kg t=4 //s g=9.8 //m/s^2 vo=0 //m/s //Calculations //Applying Newtons Principle //Solving by matrix method A=[1,-2;1,4] B=[m1*g*sind(theta);m2*g] C=inv(A)*B a=C(2) //m/s^2 v=vo+a*t //m/s //Result clc printf('The velocity of 4kg mass is %fm/s',v)
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute F6 real[-1.537,1.403] @attribute F7 real[-1.293,2.039] @attribute F8 real[-1.613,1.309] @attribute F9 real[-1.68,1.396] @attribute Class{0,1,2,3,4,5,6,7,8,9,10} @inputs TT,SpeakerNumber,Sex,F0,F1,F2,F3,F4,F5,F6,F7,F8,F9 @outputs Class @data 3 3 7 7 7 7 9 9 3 3 5 5 8 10 9 9 10 10 6 6 7 7 6 6 10 5 3 3 8 7 2 2 4 4 7 7 9 9 4 4 9 9 10 10 7 7 0 0 0 0 0 0 4 5 2 2 0 0 8 8 5 5 8 8 2 2 9 9 10 10 10 10 8 8 5 5 3 3 7 6 1 1 5 5 8 9 4 4 0 0 3 3 6 6 5 6 9 9 0 0 3 3 4 8 10 10 2 2 6 6 1 1 10 10 1 1 3 2 4 4 1 1 2 2 6 6 9 9 1 1 4 4 9 9 6 6 7 7 10 10 2 4 0 0 3 3 6 6 10 10 5 5 9 9 1 1 6 6 8 8 0 0 2 2 5 5 7 7 2 2 4 2 6 6 8 8 2 2 1 1 1 1 0 9 4 4 8 8 1 1 3 3 5 5 5 5 7 7
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clear// //Variables ICBO = 10 * 10**-3 //Leakage current (in milli-Ampere) beta=50;hFE=50; T2 = 50.0 //Temperature (in degree Celsius) T1 = 27.0 //Temperature (in degree Celsius) //Calculation //Case (a) IB = 0.25 //Base current (in milli-Ampere) IC = beta * IB + (1 + beta)* ICBO //Value of new collector current (in milli-Ampere) //Case (b) ICBO1 = ICBO * 2**((T2 - T1)/10) //ICBO at 50 degree celsius (in milli-Ampere) IC1 = beta * IB + (1 + beta)* ICBO1 //Value of new collector current (in milli-Ampere) //Result printf("\n Collector current when IB = 0.25 mA is %0.3f mA.\nCollector current at 50 degree Celsius is %0.2f mA.",IC,IC1)
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function __ret__ = image$__repr__() __ret__ = "<module image (handles image properties)>"; endfunction function __ret__ = image$__str__(self) __ret__ = "image: position=[" + string(self.x) + ", " + string(self.y) + "], size=[" + string(self.width) + ", " + string(self.height) + "]"; endfunction function self = Image(pathfile, position) self = tlist (["__class__", "__repr__", "__str__", "x", "y", "width", "height", "control"]); self.__repr__ = image$__repr__; self.__str__ = image$__str__; self.x = position(1); self.y = position(2); self.width = position(3); self.height = position(4); f = figure(0); self.control = uicontrol(f, "style", "image", ... "string", pathfile, ... "position", position); endfunction function blit(window, img, position) x = position(1); y = window.height - position(2); w = img.width; h = img.height; set(img.control, "position", [x, y, w, h]); endfunction
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zero x, pbody == 0, fbody=15 after x, phead=15*x^2, pbody=0, ptail= - 7*y - 7*y^2 - 4, vmapt={x=>x,y=>y} before y, phead=60*x^2, pbody=1, ptail= - 16, mlead= + y^2, flead=4, root2=2, widev=4 after y, phead=60*x^2 - 7*y^2, pbody=1, ptail= - 9, vmapt={x=>x,y=>1+2*y} ("15*x^2 - 7*y - 7*y^2 - 4").getReductionMap(1) = {=>15*x^2 - 7*y^2 - 9,x=>2*x,y=>2*y + 1}
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//Example 3.14 //Partial fraction expansion for distinct real roots clear; clc; //------------------------------------------------------------------ // Transfer function s=%s; num=2; p1=(s+1); p2=(s+2); p3=(s+4); sys=syslin('c',num/(p1*p2*p3)) //Partial fraction expansion is: sys= r1/p1 + r2/p2 + r3/p3 //residue calculation r1=residu(num,p1,(p2*p3)) r2=residu(num,p2,(p1*p3)) r3=residu(num,p3,(p1*p2)) disp([r1 r2 r3]',"Residues of the poles p1, p2 and p3 are") disp([roots(p1), roots(p2), roots(p3)]',"Poles p1, p2 and p3 are at") disp('k=[]') //------------------------------------------------------------------
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2020-09-23T06:26:05
2020-09-23T06:26:05
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sce
Stralroom FS Dodge Revolver.sce
Name=Stralroom FS Dodge Revolver PlayerCharacters=Quaker BotCharacters=Quaker Bot Hard.bot IsChallenge=true Timelimit=90.0 PlayerProfile=Quaker AddedBots=Quaker Bot Hard.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=stralroomV2.map MapScale=3.8125 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=true InvincibleBots=false Timescale=1.0 BlockHealthbars=false TimeRefilledByKill=0.0 ScoreToWin=1000.0 ScorePerDamage=3.5 ScorePerKill=100.0 ScorePerMidairDirect=0.0 ScorePerAnyDirect=0.0 ScorePerTime=0.0 ScoreLossPerDamageTaken=0.0 ScoreLossPerDeath=0.0 ScoreLossPerMidairDirected=0.0 ScoreLossPerAnyDirected=0.0 ScoreMultAccuracy=false ScoreMultDamageEfficiency=false ScoreMultKillEfficiency=false GameTag=Overwatch, Apex, Click Timing, Strafe, Dodge WeaponHeroTag=Revolver, Six Shooter, Manwing, McCree, Wingman DifficultyTag=4 AuthorsTag=Stral, patys, Ascetic, day BlockHitMarkers=false BlockHitSounds=false BlockMissSounds=true BlockFCT=false Description=Stralroom FS Dodge, but with the revolver. 2 headshots | 1 head, 1 body | 3 body to kill. Move constantly. GameVersion=2.0.1.2 ScorePerDistance=0.05 MBSEnable=false MBSTime1=0.1 MBSTime2=0.08 MBSTime3=1.0 MBSTime1Mult=0.1 MBSTime2Mult=20.0 MBSTime3Mult=45.0 MBSFBInstead=false MBSRequireEnemyAlive=false LockFOVRange=false LockedFOVMin=60.0 LockedFOVMax=120.0 LockedFOVScale=Clamped Horizontal [Aim Profile] Name=Default MinReactionTime=0.3 MaxReactionTime=0.4 MinSelfMovementCorrectionTime=0.001 MaxSelfMovementCorrectionTime=0.05 FlickFOV=30.0 FlickSpeed=1.5 FlickError=15.0 TrackSpeed=3.5 TrackError=3.5 MaxTurnAngleFromPadCenter=75.0 MinRecenterTime=0.3 MaxRecenterTime=0.5 OptimalAimFOV=30.0 OuterAimPenalty=1.0 MaxError=40.0 ShootFOV=15.0 VerticalAimOffset=0.0 MaxTolerableSpread=5.0 MinTolerableSpread=1.0 TolerableSpreadDist=2000.0 MaxSpreadDistFactor=2.0 AimingStyle=Original ScanSpeedMultiplier=1.0 MaxSeekPitch=30.0 MaxSeekYaw=30.0 AimingSpeed=5.0 MinShootDelay=0.3 MaxShootDelay=0.6 [Bot Profile] Name=Quaker Bot Hard DodgeProfileNames=Short Strafes DodgeProfileWeights=1.0 DodgeProfileMaxChangeTime=3.0 DodgeProfileMinChangeTime=1.0 WeaponProfileWeights=1.0;0.25;2.0;1.0;1.0;1.0;1.0;1.0 AimingProfileNames=Default;Default;Default;Default;Default;Default;Default;Default WeaponSwitchTime=3.0 UseWeapons=false CharacterProfile=Quaker BotMeso SeeThroughWalls=false NoDodging=false NoAiming=false AbilityUseTimer=0.1 UseAbilityFrequency=1.0 UseAbilityFreqMinTime=0.3 UseAbilityFreqMaxTime=0.6 ShowLaser=false LaserRGB=X=1.000 Y=0.300 Z=0.000 LaserAlpha=1.0 [Character Profile] Name=Quaker MaxHealth=300.0 WeaponProfileNames=Manwing;;;;;;; MinRespawnDelay=1.0 MaxRespawnDelay=5.0 StepUpHeight=75.0 CrouchHeightModifier=0.5 CrouchAnimationSpeed=2.0 CameraOffset=X=0.000 Y=0.000 Z=80.000 HeadshotOnly=false DamageKnockbackFactor=4.0 MovementType=Base MaxSpeed=1300.0 MaxCrouchSpeed=500.0 Acceleration=9000.0 AirAcceleration=16000.0 Friction=4.0 BrakingFrictionFactor=2.0 JumpVelocity=800.0 Gravity=3.0 AirControl=0.25 CanCrouch=false CanPogoJump=false CanCrouchInAir=true CanJumpFromCrouch=false EnemyBodyColor=X=0.771 Y=0.000 Z=0.000 EnemyHeadColor=X=1.000 Y=1.000 Z=1.000 TeamBodyColor=X=1.000 Y=0.888 Z=0.000 TeamHeadColor=X=1.000 Y=1.000 Z=1.000 BlockSelfDamage=false InvinciblePlayer=false InvincibleBots=false BlockTeamDamage=false AirJumpCount=0 AirJumpVelocity=0.0 MainBBType=Cylindrical MainBBHeight=320.0 MainBBRadius=58.0 MainBBHasHead=false MainBBHeadRadius=45.0 MainBBHeadOffset=0.0 MainBBHide=false ProjBBType=Cylindrical ProjBBHeight=230.0 ProjBBRadius=55.0 ProjBBHasHead=false ProjBBHeadRadius=45.0 ProjBBHeadOffset=0.0 ProjBBHide=true HasJetpack=false JetpackActivationDelay=0.2 JetpackFullFuelTime=4.0 JetpackFuelIncPerSec=1.0 JetpackFuelRegensInAir=false JetpackThrust=6000.0 JetpackMaxZVelocity=400.0 JetpackAirControlWithThrust=0.25 AbilityProfileNames=;;; HideWeapon=false AerialFriction=0.0 StrafeSpeedMult=1.0 BackSpeedMult=1.0 RespawnInvulnTime=0.0 BlockedSpawnRadius=0.0 BlockSpawnFOV=0.0 BlockSpawnDistance=0.0 RespawnAnimationDuration=0.5 AllowBufferedJumps=true BounceOffWalls=false LeanAngle=0.0 LeanDisplacement=0.0 AirJumpExtraControl=0.0 ForwardSpeedBias=1.0 HealthRegainedonkill=0.0 HealthRegenPerSec=0.0 HealthRegenDelay=0.0 JumpSpeedPenaltyDuration=0.0 JumpSpeedPenaltyPercent=0.0 ThirdPersonCamera=false TPSArmLength=300.0 TPSOffset=X=0.000 Y=150.000 Z=150.000 BrakingDeceleration=2048.0 VerticalSpawnOffset=0.0 TerminalVelocity=0.0 CharacterModel=None CharacterSkin=Default SpawnXOffset=0.0 SpawnYOffset=0.0 InvertBlockedSpawn=false ViewBobTime=0.0 ViewBobAngleAdjustment=0.0 ViewBobCameraZOffset=0.0 ViewBobAffectsShots=false IsFlyer=false FlightObeysPitch=false FlightVelocityUp=800.0 FlightVelocityDown=800.0 [Character Profile] Name=Quaker BotMeso MaxHealth=200.0 WeaponProfileNames=;;;;;;; MinRespawnDelay=1.0 MaxRespawnDelay=1.0 StepUpHeight=75.0 CrouchHeightModifier=0.5 CrouchAnimationSpeed=2.0 CameraOffset=X=0.000 Y=0.000 Z=80.000 HeadshotOnly=false DamageKnockbackFactor=4.0 MovementType=Base MaxSpeed=1300.0 MaxCrouchSpeed=500.0 Acceleration=9000.0 AirAcceleration=16000.0 Friction=4.0 BrakingFrictionFactor=2.0 JumpVelocity=800.0 Gravity=3.0 AirControl=0.25 CanCrouch=true CanPogoJump=false CanCrouchInAir=true CanJumpFromCrouch=false EnemyBodyColor=X=0.771 Y=0.000 Z=0.000 EnemyHeadColor=X=1.000 Y=1.000 Z=1.000 TeamBodyColor=X=1.000 Y=0.888 Z=0.000 TeamHeadColor=X=1.000 Y=1.000 Z=1.000 BlockSelfDamage=false InvinciblePlayer=false InvincibleBots=false BlockTeamDamage=false AirJumpCount=0 AirJumpVelocity=0.0 MainBBType=Cylindrical MainBBHeight=320.0 MainBBRadius=58.0 MainBBHasHead=true MainBBHeadRadius=45.0 MainBBHeadOffset=0.0 MainBBHide=true ProjBBType=Cylindrical ProjBBHeight=230.0 ProjBBRadius=55.0 ProjBBHasHead=false ProjBBHeadRadius=45.0 ProjBBHeadOffset=0.0 ProjBBHide=true HasJetpack=false JetpackActivationDelay=0.2 JetpackFullFuelTime=4.0 JetpackFuelIncPerSec=1.0 JetpackFuelRegensInAir=false JetpackThrust=6000.0 JetpackMaxZVelocity=400.0 JetpackAirControlWithThrust=0.25 AbilityProfileNames=;;; HideWeapon=false AerialFriction=0.0 StrafeSpeedMult=1.0 BackSpeedMult=1.0 RespawnInvulnTime=0.0 BlockedSpawnRadius=0.0 BlockSpawnFOV=0.0 BlockSpawnDistance=0.0 RespawnAnimationDuration=0.0 AllowBufferedJumps=true BounceOffWalls=false LeanAngle=0.0 LeanDisplacement=0.0 AirJumpExtraControl=0.0 ForwardSpeedBias=1.0 HealthRegainedonkill=0.0 HealthRegenPerSec=0.0 HealthRegenDelay=0.0 JumpSpeedPenaltyDuration=0.0 JumpSpeedPenaltyPercent=0.0 ThirdPersonCamera=false TPSArmLength=300.0 TPSOffset=X=0.000 Y=150.000 Z=150.000 BrakingDeceleration=2048.0 VerticalSpawnOffset=0.0 TerminalVelocity=0.0 CharacterModel=Meso CharacterSkin=Default SpawnXOffset=0.0 SpawnYOffset=0.0 InvertBlockedSpawn=false ViewBobTime=0.0 ViewBobAngleAdjustment=0.0 ViewBobCameraZOffset=0.0 ViewBobAffectsShots=false IsFlyer=false FlightObeysPitch=false FlightVelocityUp=800.0 FlightVelocityDown=800.0 [Dodge Profile] Name=Short Strafes MaxTargetDistance=2700.0 MinTargetDistance=750.0 ToggleLeftRight=true ToggleForwardBack=false MinLRTimeChange=0.2 MaxLRTimeChange=0.5 MinFBTimeChange=0.2 MaxFBTimeChange=0.5 DamageReactionChangesDirection=false DamageReactionChanceToIgnore=0.5 DamageReactionMinimumDelay=0.125 DamageReactionMaximumDelay=0.25 DamageReactionCooldown=1.0 DamageReactionThreshold=50.0 DamageReactionResetTimer=0.5 JumpFrequency=0.0 CrouchInAirFrequency=0.0 CrouchOnGroundFrequency=0.0 TargetStrafeOverride=Ignore TargetStrafeMinDelay=0.125 TargetStrafeMaxDelay=0.25 MinProfileChangeTime=0.0 MaxProfileChangeTime=0.0 MinCrouchTime=0.3 MaxCrouchTime=0.6 MinJumpTime=0.3 MaxJumpTime=0.6 LeftStrafeTimeMult=1.0 RightStrafeTimeMult=1.0 StrafeSwapMinPause=0.0 StrafeSwapMaxPause=0.0 BlockedMovementPercent=0.5 BlockedMovementReactionMin=0.125 BlockedMovementReactionMax=0.2 WaypointLogic=Ignore WaypointTurnRate=200.0 MinTimeBeforeShot=0.15 MaxTimeBeforeShot=0.25 IgnoreShotChance=0.0 ForwardTimeMult=1.0 BackTimeMult=1.0 DamageReactionChangesFB=false [Weapon Profile] Name=Manwing Type=Hitscan ShotsPerClick=1 DamagePerShot=70.0 KnockbackFactor=0.1 TimeBetweenShots=0.29 Pierces=false Category=FullyAuto BurstShotCount=1 TimeBetweenBursts=0.5 ChargeStartDamage=10.0 ChargeStartVelocity=X=500.000 Y=0.000 Z=0.000 ChargeTimeToAutoRelease=2.0 ChargeTimeToCap=1.0 ChargeMoveSpeedModifier=1.0 MuzzleVelocityMin=X=2000.000 Y=0.000 Z=0.000 MuzzleVelocityMax=X=2000.000 Y=0.000 Z=0.000 InheritOwnerVelocity=0.0 OriginOffset=X=0.000 Y=0.000 Z=0.000 MaxTravelTime=5.0 MaxHitscanRange=100000.0 GravityScale=1.0 HeadshotCapable=true HeadshotMultiplier=2.0 MagazineMax=7 AmmoPerShot=1 ReloadTimeFromEmpty=2.1 ReloadTimeFromPartial=2.1 DamageFalloffStartDistance=5000.0 DamageFalloffStopDistance=5000.0 DamageAtMaxRange=200.0 DelayBeforeShot=0.0 ProjectileGraphic=Ball VisualLifetime=0.5 BounceOffWorld=false BounceFactor=0.0 BounceCount=0 HomingProjectileAcceleration=0.0 ProjectileEnemyHitRadius=1.0 CanAimDownSight=false ADSZoomDelay=0.0 ADSZoomSensFactor=0.7 ADSMoveFactor=1.0 ADSStartDelay=0.0 ShootSoundCooldown=0.08 HitSoundCooldown=0.08 HitscanVisualOffset=X=0.000 Y=0.000 Z=-80.000 ADSBlocksShooting=false ShootingBlocksADS=false KnockbackFactorAir=0.1 RecoilNegatable=true DecalType=1 DecalSize=30.0 DelayAfterShooting=0.0 BeamTracksCrosshair=false AlsoShoot= ADSShoot= StunDuration=0.0 CircularSpread=true SpreadStationaryVelocity=0.0 PassiveCharging=false BurstFullyAuto=true FlatKnockbackHorizontal=0.0 FlatKnockbackVertical=0.0 HitscanRadius=0.0 HitscanVisualRadius=6.0 TaggingDuration=0.0 TaggingMaxFactor=1.0 TaggingHitFactor=1.0 RecoilCrouchScale=1.0 RecoilADSScale=1.0 PSRCrouchScale=1.0 PSRADSScale=1.0 ProjectileAcceleration=0.0 AccelIncludeVertical=true AimPunchAmount=0.0 AimPunchResetTime=0.05 AimPunchCooldown=0.5 AimPunchHeadshotOnly=false AimPunchCosmeticOnly=true MinimumDecelVelocity=0.0 PSRManualNegation=false PSRAutoReset=true AimPunchUpTime=0.05 AmmoReloadedOnKill=8 CancelReloadOnKill=false FlatKnockbackHorizontalMin=0.0 FlatKnockbackVerticalMin=0.0 ADSScope=No Scope ADSFOVOverride=72.099998 ADSFOVScale=Overwatch ADSAllowUserOverrideFOV=true IsBurstWeapon=false ForceFirstPersonInADS=true ZoomBlockedInAir=false ADSCameraOffsetX=0.0 ADSCameraOffsetY=0.0 ADSCameraOffsetZ=0.0 QuickSwitchTime=0.1 WeaponModel=Law Bringer WeaponAnimation=Primary UseIncReload=false IncReloadStartupTime=0.0 IncReloadLoopTime=0.0 IncReloadAmmoPerLoop=1 IncReloadEndTime=0.0 IncReloadCancelWithShoot=true WeaponSkin=Default ProjectileVisualOffset=X=0.000 Y=0.000 Z=0.000 SpreadDecayDelay=0.0 ReloadBeforeRecovery=true 3rdPersonWeaponModel=Pistol 3rdPersonWeaponSkin=Default ParticleMuzzleFlash=None ParticleWallImpact=None ParticleBodyImpact=None ParticleProjectileTrail=None ParticleHitscanTrace=Tracer ParticleMuzzleFlashScale=1.0 ParticleWallImpactScale=1.0 ParticleBodyImpactScale=1.0 ParticleProjectileTrailScale=1.0 Explosive=false Radius=500.0 DamageAtCenter=100.0 DamageAtEdge=0.0 SelfDamageMultiplier=0.5 ExplodesOnContactWithEnemy=false DelayAfterEnemyContact=0.0 ExplodesOnContactWithWorld=false DelayAfterWorldContact=0.0 ExplodesOnNextAttack=false DelayAfterSpawn=0.0 BlockedByWorld=false SpreadSSA=1.0,1.0,-1.0,0.0 SpreadSCA=1.0,1.0,-1.0,0.0 SpreadMSA=1.0,1.0,-1.0,0.0 SpreadMCA=1.0,1.0,-1.0,0.0 SpreadSSH=1.0,1.0,-1.0,0.0 SpreadSCH=1.0,1.0,-1.0,0.0 SpreadMSH=1.0,1.0,-1.0,0.0 SpreadMCH=1.0,1.0,-1.0,0.0 MaxRecoilUp=4.0 MinRecoilUp=4.0 MinRecoilHoriz=0.0 MaxRecoilHoriz=0.0 FirstShotRecoilMult=1.0 RecoilAutoReset=true TimeToRecoilPeak=0.025 TimeToRecoilReset=0.29 AAMode=2 AAPreferClosestPlayer=false AAAlpha=0.05 AAMaxSpeed=0.5 AADeadZone=0.0 AAFOV=30.0 AANeedsLOS=true TrackHorizontal=true TrackVertical=true AABlocksMouse=false AAOffTimer=0.0 AABackOnTimer=0.0 TriggerBotEnabled=true TriggerBotDelay=0.01 TriggerBotFOV=0.1 StickyLock=false HeadLock=true VerticalOffset=0.0 DisableLockOnKill=false UsePerShotRecoil=false PSRLoopStartIndex=0 PSRViewRecoilTracking=0.45 PSRCapUp=9.0 PSRCapRight=4.0 PSRCapLeft=4.0 PSRTimeToPeak=0.095 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//Chapter 23, Example 23.23 clc //Initialisation x=[9 4 5 0] //decimal number to be convert //Calculation //using for loop for converting each decimal to BCD n=4 m=4 disp("BCD is ") for i = 1:n z=dec2bin(x(i),m) //decimal to binary conversion printf(z) printf(" ") //display of BCD end
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clc; n=1490; // speed of machine in rpm p=4; // number of poles f=50; // frequency v=11000; // rated voltage of machine p=20*10^6; // rated power of machine v1=30; v2=25; // per phase voltage for phase A of machine i1=10; i2=6.5; // per phase current for phase A of machine ns=(120*f)/p; // synchronous speed of machine xd=v1/i2; // d-axis synchronous reactance xq=v2/i1; // q-axis synchronous reactance disp('case a'); ia=p/(sqrt(3)*v); // armature current vt=v/sqrt(3); // per phase armature voltage Ef=vt+ia*xq*%i; de=atand(imag(Ef),real(Ef)); // load angle id=ia*sind(de); // d-axis current Ef1=abs(Ef)+id*(xd-xq); printf('Per phase excitation value is %f V\n',ceil(Ef1)); printf('Line value of excitation EMf is %f V\n ',ceil(sqrt(3)*Ef1)); disp('case 2'); pr=(vt^2*(xd-xq)*sind(2*de))/(2*xd*xq); printf('Reluctance power developed by machine is %f KW per phase\n',pr/1000); printf('Total reluctance power developed by machine is %f KW',(3*pr)/1000);
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3_3_2.sce
//Transport Processes and Seperation Process Principles //Chapter 3 //Example 3.3-2 //Principles of Momentum Transfer and Applications //given data Ps=741.7;//suction pressure in mm hg Pd=769.6;//discharge pressure in mm hg Patm=760;//atmospheric pressure in mm Hg rho1=28.97*(1/22.414)*(273.2/366.3)*(Ps/Patm);//air density at suction: mol wt= 28.97 kg air/kg mol for 22.414 m3/kg mol at 101.3 kPa and 273.2 K rho2=rho1*(Pd/Ps); rhoavg=(rho1+rho2)/2 V=28.32;//volumetric flow rate in m3/s Ts=294.1;//temp at suction mdot=V*(1/60)*(1/22.414)**(273.2/Ts)*28.97;//mass flow rate of gas Patm=760;//atm pressure in mm Hg Hp=((Pd-Ps)/Patm)*(101325/rhoavg);//pressure head in J/kg v1=0;//air is stationary v2=45.7;//discharge velocity in m/s vd=(((v2^2)-(v1^2))/2);//developed velocity z1=0; sumF=0; Ws=Hp+vd;//substituting and solving for Ws by mechanical energy balance equation for a closed system in J/kg n=60/100;//efficiency given is 60% bkW= (Ws*mdot)/(n*1000);// brake kW mprintf(" brake kW= %f hP",bkW)
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function y = uf(x) y = 1 - abs(x) endfunction x = -1:0.1:1 plot(x,uf(x))
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Ex5_6.sce
//To Detemine power absorbed and the power factor //Page 295 clc; clear; Vs=15; //Secondary Voltage P=500*(10^3) // Power Taken pfs=0.6; //Power Factor Is=P/(Vs*pfs); //Secondary Current //Taking Current as Reference voltage will be t=acosd(pfs); //Power Factor Angle Vsp=Vs*(exp(%i*(t/180)*%pi)); //Phasor Secondary Voltage R=Vsp/Is; //Impedance //if the resistance is doubled, The Total impedance doubles, Considering Vs as reference R2=real(R)+R; I2=Vs/R2; //New Current pfn=cosd(atand(imag(I2)/real(I2))); //power factor of new current Pab=Vs*abs(I2)*pfn/1000; //Power Absorbed printf('The Power Factor and The Absorbed power are %g lagging and %g kW respectively.\n',pfn,Pab)
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load Xor.hdl, output-list a, b, out; set a 0, set b 0, eval, output; set a 0, set b 1, eval, output; set a 1, set b 0, eval, output; set a 1, set b 1, eval, output;
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clc clear //INPUT DATA w=1.8 //wavelength //calulation y=sind(15*360/180)//displacement at 15cm from reflector //output printf("1. at 45cm, antinode occurs and hence pressure is minimum") printf("\n 2. at 90cm node arises and hence pressure is maximum") printf("\n 3. at 15cm frm reflector the displacement is %3.3f",y)
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//find size of bolts clc //solution //given T=25*10^3//N-mm n=4 Rp=30//mm t=30//N/mm^2 Ps=T/Rp//N//shearing load //let dc be core dia //P=t*n*A //A=(pi/4)*dc^2 pi=3.14 //P=t*n*(pi/4)*dc^2=94.26*dc^2 //P=Ps dc=sqrt(Ps/94.26)//mm printf("the value of dc is,%f mm\n",dc) printf("the standard value of core diametr is 3.141 mm fron T11.1")
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struct_rename_runme.sci
exec("alaqiltest.start", -1); try a = new_Bar(); Bar_x_set(a,100); catch alaqiltesterror(); end if Bar_x_get(a) <> 100 then alaqiltesterror(); end exec("alaqiltest.quit", -1);
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1_17.sce
clc(); clear; // To calculate the Fermi energy of the metal d=970; //density of Na in kg/m^3 n=6.02*10^26; h=6.62*10^(-34); m=9.1*10^-31; //mass in kg w=23; //atomic weight N=(d*n)/w; //number of atoms per m^3 A=(h^2)/(8*m); B=(3*N)/%pi; Ef=A*B^(2/3); EfeV=Ef/(1.6*10^-19); printf("fermi energy of Na is %f eV",EfeV);
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Ex6_32.sce
//Example 6_32 page no:367 clc; //given power = 75;//in kW t1 = 4000;//in hours cost = 3600;//in rupees motor_eff = 0.91; pow_fac = 0.89; trans_cost = 18;//in rupees per kVA dep = 0.8; transformer_cost = 6000;//in rupees trans_eff = 0.91; trans_pow_fac = 0.89; max_tariff = 108; tariff = 4; output = 75;//in kW //sol kVA_input = output/(pow_fac*motor_eff); cost_of_trans = 100 * trans_cost; tot_cap_cost = cost + cost_of_trans; annual_cost = tot_cap_cost * 8/100; ove_eff = trans_eff * 0.98; loss = ((1/ove_eff)-1)*power; yr_cost_loss = (loss * t1 * tariff)/100; max_demand = power / (motor_eff*0.98*trans_pow_fac); max_demand_chc = max_demand * max_tariff; tot_cost = max_demand_chc + yr_cost_loss + annual_cost; yr_cap_cost = transformer_cost * 12 /100; loss = ((1/motor_eff)-1)*power; yr_cost_of_loss = loss * t1 * tariff / 100; max_dmd_chc = 92.5 * max_tariff; total_cost = max_dmd_chc + yr_cost_of_loss + yr_cap_cost; saving = tot_cost - total_cost; disp(saving,"the total yearly saving is (in rupees)"); //the calculation for loss is wrong in textbook so the result of saving vary with textbook
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// Example 1-2, page 12 clear;clc; close; // Given data i=2; // current source, in milli amperes R=10*10^6; //internal source resistance , in ohms // Calculations Rlmin=0;// minimum load resistance in ohms Rlmax=0.01*R; // maximum load resistance disp("ohms", Rlmin,"Minimum Load resistance =") disp("ohms", Rlmax,"Maximum Load resistance =")
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//Calculations on diesel cycle clc,clear //Given: d=15,l=20 //Diameter and stroke of cylinder in cm p1=10 //Percentage of stroke volume equal to clearance volume p2=6 //Percentage of stroke at which cut off takes place g=1.4 //Specific heat ratio(gamma) //Solution: //Refer fig 2.28 V_s=(%pi/4)*d^2*l //Stroke volume in cm^3 V_c=p1*V_s/100 //Clearance volume in cm^3 V1=V_s+V_c //Total volume at 1 in cm^3 V2=V_c //Volume at 2 in cm^3 V3=V2+p2*V_s/100 //Volume at 3 in cm^3 r=V1/V2 //Compression ratio rho=V3/V2 //Cut off ratio eta=1-((rho^g-1)/(r^(g-1)*g*(rho-1))) //Thermal efficiency //Results: printf("\n The air standard efficiency of the engine, eta = %d percent\n\n",eta*100)
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clear; printf('\n'); printf('************** mt_demo pre ****************'); printf('\n'); //printf('Enter a File Name of Material\n'); //UnitSpaceFile = input('File Name(.xls)?: ',"string"); //printf('./' +UnitSpaceFile+'.xls\n'); printf('Loading <./mt_demo_pre.xls>\n'); MT_Mat_Sheets = readxls('./mt_demo_pre.xls'); // EXELファイルの読み出し Sheet = MT_Mat_Sheets(1); // Sheetの抜き出し MTMate = Sheet.value; // 数値の取り出し SampleCount = size( MTMate, 1); ItemCount = size( MTMate, 2); printf('SampleCount ='); disp(string(SampleCount)); printf('ItemCount ='); disp(string(ItemCount)); printf('\n'); // 予備計算 for j = 1: ItemCount, x1( 1, j) = 0, //行列の初期化 x2( 1, j) = 0, //行列の初期化 for i = 1: SampleCount, x1( 1, j) = x1( 1, j) + MTMate( i, j), // 1乗の総和を求める x2( 1, j) = x2( 1, j) + MTMate( i, j)^2; // 2乗の総和を求める end, end // 算術平均 for j = 1: ItemCount, Ave( 1, j) = x1( 1, j) / SampleCount; end //これでもいけそう。要、あとで検証 //Ave = x1( 1, ;) / SampleCount; // 標準偏差(MT法) for j = 1: ItemCount, StDevM( 1, j) = (( x2( 1, j) - (x1( 1, j)^2)/SampleCount) /SampleCount)^0.5; end // 基準化 for j = 1: ItemCount, for i = 1: SampleCount, u( i, j) = (MTMate( i, j) - Ave( 1, j)) / StDevM( 1, j); end; end // for k= 1: ItemCount for j = 1: ItemCount, for i = 1: SampleCount, uxu( i, j, k) = u( i, j) * u( i, k); end; end end // 単位空間生成 for j = 1: ItemCount, for i = 1: ItemCount, R ( i, j) = 0; // 初期化 end; end for k= 1: ItemCount, for j = 1: ItemCount, for i = 1: SampleCount, R ( j, k) = R ( j, k) + uxu( i, j, k); end, R ( j, k) = R ( j, k) / SampleCount; end; end // 単位空間をprint //disp("R ="); printf("R ="); disp(R); printf("\n"); // 単位空間の検証 for i=1:SampleCount, Ut = u( i, :), U = Ut', D2(i,1) = Ut * inv(R) * U / ItemCount; end AveD = 0; for i=1:SampleCount, AveD = AveD + D2(i,1); end AveD = AveD / SampleCount; // 単位空間の検証結果 AveD==1ならGood printf("AveD = "); disp(string(AveD)); printf("\n"); printf("D(A) = "); disp(string((D2(40,1)*ItemCount)^0.5)); printf("\n"); printf("D2(A) = "); disp(string(D2(40,1)*ItemCount)); printf("\n"); printf("D(B) = "); disp(string((D2(30,1)*ItemCount)^0.5)); printf("\n"); printf("D2(B) = "); disp(string(D2(30,1)*ItemCount)); printf("\n"); printf("D2min = "); disp(string(min(D2*ItemCount))); printf("\n"); printf("D2max = "); disp(string(max(D2*ItemCount))); printf("\n"); clf; // clear //scf; // add subplot( 3, 1, 1); plot( MTMate(:,1), MTMate(:,2), '.'); plot( MTMate(40,1), MTMate(40,2), 'g.'); plot( MTMate(30,1), MTMate(30,2), 'r.'); a=get("current_axes"); a.data_bounds=[0,0;100,100] xlabel("Mathematics"); ylabel("Science"); [ p, q] = reglin( MTMate(:,1)', MTMate(:,2)'); kaiki = p * MTMate(:,1) + q; plot( MTMate(:,1), kaiki, 'k--'); subplot( 3, 1, 2); plot( (D2*ItemCount)^0.5, '.'); plot( 40, (D2(40,1)*ItemCount)^0.5, 'g.'); plot( 30, (D2(30,1)*ItemCount)^0.5, 'r.'); xlabel("Student No,"); ylabel("Mahalanobis Distance"); subplot( 3, 1, 3); histplot( 0:1:15, (D2(:,1)*ItemCount)'); for x = 1: 15, Total( x, 1) = cdfchi( "PQ", x, ItemCount); if x==1 then Dist( x, 1) = Total( x, 1); else Dist( x, 1) = Total( x, 1) - Total( x-1, 1); end, end plot( Dist, '.'); xlabel("Mahalanobis Distance^2");
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phi=0.7*10^(-4); i=0.1; s1=0.01; a_cs=s1^2; s2=0.005; a_ss=s1*s2; b_cs=phi/a_cs; b_ss=phi/a_ss; h_cs=400; h_ss=1100; l_cs=0.035; l_ss=0.105; ni_cs=h_cs*l_cs; ni_ss=h_ss*l_ss; ni=ni_cs+ni_ss; n=ni/i; disp("the number of turns required in the coil is"); disp(n);
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//Chapter-2, Illustration 20, Page 79 //Title: Gas Power Cycles //============================================================================= clc clear //INPUT DATA P1=0.1;//Pressure at point 1 in MPa T1=303;//Temperature at point 1 in K T3=1173;//Temperature at point 3 in K rp=6;//Pressure ratio nC=0.8;//Compressor efficiency nT=nC;//Turbine efficiency e=0.75;//Regenerator effectiveness y=1.4;//Ratio of specific heats Cp=1.005;//Specific heat at constant pressure in kJ/kg-K //CALCULATIONS x=(y-1)/y;//Ratio T2s=T1*(rp^x);//Temperature at point 2s in K T4s=T3/(rp^x);//Temperature at point 4s in K DTa=(T2s-T1)/nC;//Difference in temperatures at point 2 and 1 in K DTb=(T3-T4s)*nT;//Difference in temperatures at point 3 and 4 in K wT=Cp*DTb;//Turbine work in kJ/kg wC=Cp*DTa;//Compressor work in kJ/kg T2=DTa+T1;//Temperature at point 2 in K q1=Cp*(T3-T2);//Heat supplied in kJ/kg nth1=((wT-wC)/q1)*100;//Cycle efficiency without regenerator T4=T3-DTb;//Temperature at point 4 in K T5=T2+(e*(T4-T2));//Temperature at point 5 in K q2=Cp*(T3-T5);//Heat supplied with regenerator in kJ/kg nth2=((wT-wC)/q2)*100;//Cycle efficiency with regenerator p=((nth2-nth1)/nth1)*100;//Percentage increase due to regeneration //OUTPUT mprintf('Percentage increase in the cycle efficiency due to regeneration is %3.2f percent',p) //==============================END OF PROGRAM=================================
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//ex2 example //1-Creating interface source file // from intex2.desc file by call to intersci (see Makefile) // Making object files // Interface file '/tmp/ex2fi.o' // User's files ['/tmp/ex2f.o'] files=G_make(['/tmp/ex2fi.o','/tmp/ex2f.o'],'ex2.dll'); //2-Link object files .o with addinter //addinter(files,'intex2',intex2_funs); exec('ex2fi.sce'); //Run Scilab functions: a=1:20;b=1:10; d=som(a=1:20,b=1:10); d1=ones(1,10) + a(1:10)+b(1:10); if norm(d-d1') > %eps then pause,end;
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//Calculations on gas turbine with heat exchanger clc,clear //Given: T1=17+273 //Temperature at entering in K P1=1 //Pressure at entering of compressor in bar r_p=4.5 //pressure ratio W=4000 //Work output in kW m=40 //Mass flow rate in kg/s e=0.6 //Thermal ratio or effectiveness of heat exchanger eta_C=84 //Isentropic efficiency of compressor in percent eta=0.29 //Thermal efficiency cp_a=1.005 //Specific heat of air in kJ/kgK g=1.4 //Specific heat ratio(gamma) of air cp_g=1.07 //Specific heat of gas in kJ/kgK g1=1.365 //Specific heat ratio(gamma) of gas //Solution: //Refer fig 26.27 T2!=T1*r_p^((g-1)/g) //Isentropic temperature at 2 in K T2=(T2!-T1)/(eta_C/100)+T1 //Temperature at 2 in K W=W/m //Specific work output in kJ/kg Q1=W/eta //Heat added in kJ/kg W_C=cp_a*(T2-T1) //Compressor work in kJ/kg W_T=W+W_C //Turbine work in kJ/kg function y=f(T4) T3=T4-Q1/cp_g //Defining temperature at 3 in terms of T4 in K T5=T4-W_T/cp_g //Defining temperature at 5 in terms of T4 in K y=(cp_a*(T3-T2))/(cp_g*(T5-T2))-e endfunction //Since effectiveness from the relation must be equal to the given effectiveness //Thus their difference must be equal to Zero, thus function, f solve for zero to get the value of variable(T4) T4=fsolve(1000,f) //Temperature at 4 in K T5=T4-W_T/cp_g //Temperature at 5 in K T5!=T4/r_p^((g1-1)/g1) //Isentropic temperature at 5 in K eta_T=(T4-T5)/(T4-T5!) //Isentropic efficiency of turbine //Results: printf("\n The isentropic efficiency of the gas turbine, eta_T = %.1f percent\n\n",eta_T*100)
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errcatch(-1,"stop");mode(2);//Caption: spacing distance //Example 5.3 //page no 221 //Find The spacing between two successive pules ; ; samplingrate=8000; totalsignals=24+1; t=1/samplingrate; T=t/totalsignals; T=T*10^6//time is now u sec space=T-1; disp("u sec",space,"The spacing between two successive pules"); exit();
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<?xml version="1.0" encoding="utf-8" ?> <test> <description>StdProject3D Pyramid Modified basis P=6 Q=7</description> <executable>StdProject</executable> <parameters>-s pyramid -b Modified_A Modified_A ModifiedPyr_C -o 6 6 6 -p 7 7 7 -P GaussLobattoLegendre GaussLobattoLegendre GaussLobattoLegendre</parameters> <metrics> <metric type="L2" id="1"> <value tolerance="1e-11">8.8186e-13</value> </metric> <metric type="Linf" id="2"> <value tolerance="1e-11">2.41681e-12</value> </metric> <metric type="Regex" id="3"> <regex>^Integral error: ([+-]?\d.+\d|-?\d|[+-]?nan|[+-]?inf).*</regex> <matches> <match> <field id="0" tolerance="1e-11">2.49289e-12</field> </match> </matches> </metric> </metrics> </test>
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// Exa 6.7 format('v',7); clc; clear; close; // Given data L= 0.01;// in H C= 10;// in pF C= C*10^-12;// in F f= 1/(2*%pi*sqrt(L*C));// in Hz disp(f*10^-3,"Frequency of oscillations in kHz is : ") // Note: Calculation to find the value of f in the book is wrong, so answer in the book is wrong
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//Chapter 12 //page no 486 //given clc; clear all; CSO=-59.8; //in dB y=10^(CSO/10); mprintf("AM modulation depth (m) = %e\n",y); asq=3.6*10^-3; Ncso=50; msq=(y/Ncso/asq/asq); mprintf("\n m^2 = %e\n",msq); printf("\n Decrease of AM modulation depth decrease the CSO distortion by = %0.0f percent",sqrt(msq)*100);
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//To calculate the capacitance and charge on plates epsilon0 = 8.85*10^-12; V = 100; //potential, V A = 100; //area, cm^2 A = A*10^-4; //area, m^2 d = 1; //plate seperation, cm d = d*10^-2; //plate seperation, m C = epsilon0*A/d; //capacitance, farad printf("capacitance of capacitor in F is"); disp(C); Q = C*V; //charge on plates printf("charge on plates in coulomb is"); disp(Q);
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//To find number of teeth clc //Given: G=3 phi=20 //degrees Aw=1 //module //Solution: //Calculating the minimum number of teeth for a gear ratio of 3:1 t1=(2*Aw)/(G*(sqrt(1+1/G*(1/G+2)*(sind(phi))^2)-1)) //Calculating the minimum number of teeth for equal wheel t2=(2*Aw)/(sqrt(1+3*(sind(phi))^2)-1) //Results: printf("\n\n Minimum number of teeth for a gear ratio of 3:1, t = %d.\n\n",t1+1) printf(" Minimum number of teeth for equal wheel, t = %d.\n\n",t2+1)
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#include "alu.inc" .code prolog #define XOR(N, I0, I1, V) ALU(N, , xor, I0, I1, V) XOR(0, 0x7fffffff, 1, 0x7ffffffe) XOR(1, 1, 0x7fffffff, 0x7ffffffe) XOR(2, 0x80000000, 1, 0x80000001) XOR(3, 1, 0x80000000, 0x80000001) XOR(4, 0x7fffffff, 0x80000000, 0xffffffff) XOR(5, 0x80000000, 0x7fffffff, 0xffffffff) XOR(6, 0x7fffffff, 0xffffffff, 0x80000000) XOR(7, 0xffffffff, 0x7fffffff, 0x80000000) XOR(9, 0xffffffff, 0xffffffff, 0) XOR(10, 0x7fffffff, 0, 0x7fffffff) XOR(11, 0, 0x7fffffff, 0x7fffffff) #if __WORDSIZE == 64 XOR(12, 0x7fffffffffffffff, 1, 0x7ffffffffffffffe) XOR(13, 1, 0x7fffffffffffffff, 0x7ffffffffffffffe) XOR(14, 0x8000000000000000, 1, 0x8000000000000001) XOR(15, 1, 0x8000000000000000, 0x8000000000000001) XOR(16, 0x7fffffffffffffff, 0x8000000000000000, 0xffffffffffffffff) XOR(17, 0x8000000000000000, 0x7fffffffffffffff, 0xffffffffffffffff) XOR(18, 0x7fffffffffffffff, 0xffffffffffffffff, 0x8000000000000000) XOR(19, 0xffffffffffffffff, 0x7fffffffffffffff, 0x8000000000000000) XOR(20, 0xffffffffffffffff, 0xffffffffffffffff, 0) #endif prepare pushargi ok ellipsis finishi @printf ret epilog
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//Ex:2.10 clc; clear; close; printf("Resistance = 330 ohms with 2%% tolerance");
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// Example1_14_pg31.sce // To find the per unit regulation // Theory of Alternating Current Machinery by Alexander Langsdorf // First Edition 1999, Thirty Second reprint // Tata McGraw Hill Publishing Company // Example in Page 31 clear; clc; close; // Given data r_pu = 0.017; // Per-unit resistance x_pu = 0.0247; // Per-unit reactance power_factor = 1; // Unity Power Factor overload = 0.25; // 25% overload // Calculations phi = acos(power_factor); OL_factor = 1.00 + overload; r_pu = r_pu*OL_factor; // Base value has to be changed for 0.25 overload x_pu = x_pu*OL_factor; // Base value has to be changed for 0.25 overload // Formula for regulation is, Per-unit-regulation = r_pu*cos(phi) + x_pu*sin(phi) + 0.5*(x_pu*cos(phi) - r_pu*sin(phi))^2 perunit_regulation = r_pu*cos(phi) + x_pu*sin(phi) + 0.5*(x_pu*cos(phi) - r_pu*sin(phi))^2; // disp('Hence,'); printf("Per-unit regulation = %0.4f",perunit_regulation); // Result // Per-unit regulation = 0.0217
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clc //Chapter7 //Example7.3, page no 279 //Given mue=25 rp=5e3 Rs=1e3//input resistance //Coupling Capacitors are assumed as short circuit Rg=1e5 gm=25/5e3 Req=2.5/gm F=1+((((Req*(Rs+Rg)^2)+(Rg*Rs^2))/(Rs*Rg^2))) xo=0 x1=1e10 w=0:%inf vo=sqrt((30145e-8/%pi)*integrate('1/(((3e5)^2)+(w^2))','w',xo,x1)) mprintf('The mean square noise voltage is: %f uV',vo*1e6)
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//example-10.8 //page no-330 //given //ASTM number n=12 //as we know that N=2^(n-1) //1 square inch=645 mm^2 //so grain diameter for ASTM number 12 will be d=1/sqrt((N/645)*10^4) //mm printf ("the grain diameter of ASTM number 12 is %f mm",d)
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funcprot(0);clc; //Example 9.3 //Initializing the variables Vp = 100; cP = 340; cM = 295; rhoM = 7.7; rhoP = 1.2; muM = 1.8*10^-5; muP = 1.2*10^-5; //Calculations Vm = Vp*(cM/cP); LmByLp = 1/((Vm/Vp)*(muM/muP)*(rhoM/rhoP)); FmByFp = (rhoM/rhoP)*(Vm/Vp)^2*(LmByLp)^2; disp(FmByFp*100, "Percentage ratio of forces (%):",Vm, 'Mean wind tunnel flow velocity(m/s) :');
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Bf=1400//width of flange, in mm Df=120//thickness of flange, in mm d=600//effective depth, in mm m=18.66//modular ratio Ast=4000//in sq mm M=160*10^6//in N-mm //Assume x>Df; equating moments of area on compression and tension sides about N.A. x=(m*Ast*d+Bf*Df^2/2)/(m*Ast+Bf*Df)//in mm //let sigma_cbc_dash=a*sigma_cbc a=(x-Df)/x //to find lever arm z=d-(1+2*a)/(1+a)*Df/3//in mm sigma_cbc=2*M/(Bf*Df*(1+a)*z)//in MPa sigma_st=m*sigma_cbc*(d-x)/x//in MPa mprintf("Stress in concrete=%f N/mm^2\nStress in tension steel=%f N/mm^2",sigma_cbc,sigma_st) //answer given in textbook is incorrect
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ex10_4.sce
//Page Number: 556 //Example 10.4 clc; //Given, q=2.5; dh=1.58; er=9; f=10; c=3D+8; erff=((er+1)/2)+(((er-1)/2)*((1+(12/q))^(-1/2))); vp=(c/sqrt(erff))*erff; fe1=c/(sqrt(vp)*2*dh*q); if f<fe1 then disp('Strip supports TEM mode only'); else disp('Strip does not support TEM mode only'); end
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example20_sce.sce
//chapter 3 //example 3.20 //page 117 printf("\n") printf("given") E=5;Vo=4.5;Il=2*10^-3; R1=(E-Vo)/Il; printf(" suitable resistance is %dohm\n",R1) Vr=E disp("when diode is forward baised") If=(E-Vf)/R1; printf(" diode forward current is %3.3fA\n",If)
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Ex4_25.sce
clc clear //DATA GIVEN //condition of steam before throttling p1=8; //pressure in bar //condition of steam after throttling p2=1; //pressure in bar T2=115+273; //temp. in deg. celsius Tsup2=T2; //At 1 bar, Ts2=99.6+273; Cps=2.1; //kJ/kgK //As throttling is a constant enthalpy process, //h1=h2.....hf1+x1*hgf1=hf2+hfg2+Cps(Tsup2-Ts2) //At 8 bar, from steam tables, hf1=720.9; hfg1=2046.5; //At 1 bar, from steam tables, hf2=417.5; hfg2=2257.9; x1=[hf2+hfg2+Cps*(Tsup2-Ts2)-hf1]/hfg1; //dryness fraction printf('The Dryness fraction of steam in the main, x1 is: %1.2f.',x1);
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Ex17_2.sce
clear; clc; //Example 17.2 Vx=-0.7; Vy=Vx; Vbe=0.7; V2=-5.2; Re=1.180; vE=Vx-Vbe; printf('\nemitter voltage =%.2fV\n',vE) iE=(vE-V2)/Re; printf('\nemitter current=%.2f mA\n',iE) Icxy=iE; vo1=-0.7; Rc1=-vo1/Icxy; printf('\nRc1=%.2f KOhm\n',Rc1) Vnor=vo1-Vbe; printf('\nNOR output logic 0 value=%.2f V\n',Vnor) Vr=(vo1+Vnor)/2; vE=Vr-Vbe; printf('\nvE=%.2f V\n',vE) iE=(vE-V2)/Re; printf('\niE=%.2f mA\n',iE) vo2=-0.7; iC2=iE; Rc2=-vo2/iC2; printf('\nRc2=%.2f KOhm\n',Rc2) Vor=vo2-Vbe; printf('\nOR logic 0 value is=%.2f V\n',Vor)
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ex3_12.sce
//ex3.12 find the electric field and its direction just above the surface. theta=60; //degree Et1=10*cosd(theta); En1=5*sind(theta); Et2=Et1; En2=4*En1; E2=sqrt(Et2^2+En2^2); angle=atand(En2/Et2); disp('the electric field is = '+string(E2)+' V/m','angle above the surface is = '+string(angle)+' degree');
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003-test-bing.tst
# Test Bing Auto suggest feature { "id" : "003-test-bing-auto-suggest", "verb" : "GET", "uri" : "https://www.bing.com/AS/Suggestions?pt=page.home&mkt=en-us&qry=quant&cp=1&cvid=C4C0C8857D9B4D3C8F145A2D93D9426E", "expected" : 200, "rematch" : ".*quantum.*quantify", "message" :"Bing auto suggest for quant" } #END
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example_2_7.sce
clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 2 // Heat Conduction in Solids // Example 2.7 // Page 43 printf("Example 2.7, Page 43 \n\n") H = 5 ; // Height, [m] L = 10 ; // Length, [m] t = 1 ; // thickness, [m] b = t/2; k = 1.05 ; // [W/m K] q = 58 ; // [W/m^3] T = 35 ; // [C] h = 11.6 ; // Heat transfer coefficient, [W/m^2 K] // Substituting the values in equation 2.5.6 T_max = T + q*b*(b/(2*k)+1/h); printf("Maximum Temperature = %f degree C",T_max);
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12_12.sce
clear; clc; ef=100 Zc=400 z=50 R=z+Zc; E=(2*ef/(Zc+z+R))^2 *R E=round(E*100)/100 mprintf("\n(a)Energy transfer max when R= %.0f ohm, energy= %.2f KW", R,E); etB=2*ef*z/(z+Zc+R); etB=round(etB*100)/100 mprintf("\n(b)Surge Voltage Transmitted= %.3f kV",etB) it=etB*1000/z; it=round(it*100)/100 mprintf("\nSurge Current Transmitted = %.2f A",it) etA=2*ef*(z+R)/(z+Zc+R); etA=round(etA*100)/100 erA=etA-ef mprintf("\n(c)Surge Voltage Reflected= %.2f kV",erA) irA=-1*erA*1000/Zc mprintf("\nSurge Current Reflected= %.3f A",irA) iF=ef*1000/Zc Pi=ef*iF mprintf("\n(d)Power Incident= %.0f kW",Pi) Pr=erA*-irA mprintf("\nPower Reflected= %.2f kW",Pr) Pt=erA*it mprintf("\nPower Transmitted= %.0f kW",Pt)
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// Ex3_9 clc; // Given: D=-1.997042; n=1.0087; // Solution: m=(D+2*n); E=m*931; printf("\n The binding energy is = %f MeV",E)
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ex3_1.sce
// Example 3.1, page no-163 clear clc m1=20 a=5 F=m1*a printf("F = %d Newtons",F)