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f36ac2cbc5d2aeac6a51c9d347d3c74d6dd6df94 | b68ae1fc3cd37c85031f69e42d92903b7f1a90ab | /projects/08/FunctionCalls/FibonacciElement/FibonacciElementVME.tst | 8fd2e568c69bd8be3192077ab3f195773a07b13f | [] | no_license | bricef/The-Elements-of-Computing-Systems | fb3aa100c18176ccfc876e9d30319c0b8a5c7635 | 6be81eacaa30ad57b06f018c0aecbcf7e04841bc | refs/heads/master | 2021-01-18T13:43:02.653913 | 2011-04-06T19:23:52 | 2011-04-06T19:23:52 | 1,578,790 | 5 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 484 | tst | FibonacciElementVME.tst | // This file is part of the materials accompanying the book
// "The Elements of Computing Systems" by Nisan and Schocken,
// MIT Press. Book site: www.idc.ac.il/tecs
// File name: projects/08/FunctionCalls/FibonacciElement/FibonacciElementVME.tst
load, // Load all the VM files from the current directory
output-file FibonacciElement.out,
compare-to FibonacciElement.cmp,
output-list RAM[0]%D1.6.1 RAM[261]%D1.6.1;
set sp 261,
repeat 110 {
vmstep;
}
output;
|
2b4008f09a15773c95667fbd732a0a09199b5804 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3257/CH7/EX7.1/Ex7_1.sce | 4151722f5e5bd37a9242c78a62b59e37212ce73e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 303 | sce | Ex7_1.sce | // Calculation of maximum punch force
clc
L = 30 // diameter of punching in mm
t = 3 // thickness of sheet in mm
UTS = 1e3 // Tensile strength in MN
printf("\n Example 7.1")
F = 0.7*UTS*t*1e-3*L*1e-3*%pi
printf("\n Maximum required punching force is %.3f MN.",F) // Answer in book is 0.197 MN
|
15deb480fb62eae3a6251c907fdde9fea76e99df | 449d555969bfd7befe906877abab098c6e63a0e8 | /1484/CH1/EX1.18/1_18.sce | 62ba168b6c0c52f9533de9ffa94b49dcd24c4eb7 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 210 | sce | 1_18.sce | clc
//initialisation of variables
h= 8 //ft
h1= 10 //ft
//CALCULATIONS
A= h
X= (h1/2)
Ig= h^3/12
I0= Ig+A*X^2
h2= I0/(A*X)
//RESULTS
printf ('depth at which the hinge of the shutter= %.2f ft ',h2)
|
59c8c2868fda83a4859b41638a0b67260ce05850 | 6e257f133dd8984b578f3c9fd3f269eabc0750be | /ScilabFromTheoryToPractice/CreatingPlots/testxrect.sce | 048187a077e8e7cf5fbcf5e2aaeb305f3cf8c651 | [] | no_license | markusmorawitz77/Scilab | 902ef1b9f356dd38ea2dbadc892fe50d32b44bd0 | 7c98963a7d80915f66a3231a2235010e879049aa | refs/heads/master | 2021-01-19T23:53:52.068010 | 2017-04-22T12:39:21 | 2017-04-22T12:39:21 | 89,051,705 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 462 | sce | testxrect.sce | clf;
plot2d(0,0,0,rect=[0,0,10,10],frameflag=3)
xgrid(4) // grid
xfrect(0,4,2,4) // first rectangle
E=gce(); E.background=1; // black inside
xrect(2,4,2,2) // second rectangle (square)
E=gce(); E.foreground=5; // red outline
xrect(4,6,2,2) // third rectangle (square)
E=gce();
E.foreground=2; // blue outline
E.line_style=3; // dotted line
E.thickness=5; // thickness
xfrect(6,8,4,2) // fourth rectangle
E=gce(); E.background=7; // yellow inside
|
3c88375718d1fbedf0802b740277ec1c582e7e40 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2381/CH7/EX7.2/ex_2.sce | c7b914e8344b6bc31841c9a058428818055c25c9 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 412 | sce | ex_2.sce | //Example 2 // intensity
clc;
clear;
close;
I=1;//assume
a1=1*I;//
a2=4*I;//
ph1=0;//degree
i1=(a1+a2)+a2*cosd(ph1);//
disp("intensity where phase difference is zero is "+string(i1)+"*I")
ph2=90;//degree
i2=(a1+a2)+a2*cosd(ph2);//
disp("intensity where phase difference is pi/2 is "+string(i2)+"*I")
ph3=180;//degree
i3=(a1+a2)+a2*cosd(ph3);//
disp("intensity where phase difference is pi is "+string(i3)+"*I")
|
853703e7ba65318283d49a2150f54498147f9d86 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1727/CH2/EX2.7/2_7.sce | cce2be393183285dcdc5702bb92e0173b7d582fb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 219 | sce | 2_7.sce | clc
//Initialization of variables
g=9.81 //kN/m^2
hc=16.25 //m
l=1.5 //m
b=2.5 //m
f=0.3
Pi=50 //kN
//calculations
P=g*hc*l*b
Preq=Pi+f*P
//results
printf("Force required to lift the gate = %.2f kN",Preq)
|
ca6cbb8c93b520f325135731f1958a05a737c985 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2705/CH5/EX5.12/Ex5_12.sce | e522db8a2dfe0cbad925be9fd1cb80310c6502c7 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,481 | sce | Ex5_12.sce | clear;
clc;
disp('Example 5.12');
// aim : T0 determine
// (a) change in internal nergy of the air
// (b) work done
// (c) heat transfer
// Given values
m = .25;// mass, [kg]
P1 = 140;// initial pressure, [kN/m^2]
V1 = .15;// initial volume, [m^3]
P2 = 1400;// final volume, [m^3]
cp = 1.005;// [kJ/kg K]
cv = .718;// [kJ/kg K]
// solution
// (a)
// assuming ideal gas
R = cp-cv;// [kJ/kg K]
// also, P1*V1=m*R*T1,hence
T1 = P1*V1/(m*R);// [K]
// given that process is polytropic with
n = 1.25; // polytropic index
T2 = T1*(P2/P1)^((n-1)/n);// [K]
// Hence, change in internal energy is,
del_U = m*cv*(T2-T1);// [kJ]
mprintf('\n (a) The change in internal energy of the air is del_U = %f kJ',del_U);
if(del_U>0)
disp('since del_U>0, so it is gain of internal energy to the air')
else
disp('since del_U<0, so it is gain of internal energy to the surrounding')
end
// (b)
W = m*R*(T1-T2)/(n-1);// formula of work done for polytropic process,[kJ]
mprintf('\n (b) The work done is W = %f kJ',W);
if(W>0)
disp('since W>0, so the work is done by the air')
else
disp('since W<0, so the work is done on the air')
end
// (c)
Q = del_U+W;// using 1st law of thermodynamics,[kJ]
mprintf('\n (c) The heat transfer is Q = %f kJ',Q);
if(Q>0)
disp('since Q>0, so the heat is received by the air')
else
disp('since Q<0, so the heat is rejected by the air')
end
// End
|
93e2d39f46c3955b7246b97d63c5fd6da916e18c | 449d555969bfd7befe906877abab098c6e63a0e8 | /3821/CH14/EX14.6/Example14_6.sce | f2ee380cd661b76731ef532d42bc28d78dccff2e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 552 | sce | Example14_6.sce | ////Chapter No 14 Air Standard Cycles
////Example No 14.6 Page No 308
///Find standard efficiency
//Input data
clc;
clear;
T1=27+273; //Initial temp in degree celsius
T2=450+273; //Final temp in degree celsius
gamma1=1.4;
//Calculation
r=(T2/T1)^(1/(gamma1-1)); //Isentropic process
eta=100*(1-(1/(r^(gamma1-1)))); //Otto cycle air standard effeciency in %
//Output
printf('compression ratio= %f \n ',r);
printf('standard efficiency= %f percent \n',eta);
|
7f565a5d8c6e64795c03b8fad32605f74b2ffa0e | 449d555969bfd7befe906877abab098c6e63a0e8 | /2858/CH11/EX11.12/Ex11_12.sce | 5df566ad197db4451d0a1526c61d480dc31dff2a | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 608 | sce | Ex11_12.sce | //example 11.12
clc; funcprot(0);
z1=21/2;
Lg=9;
Bg=6;
Qg=500*1000;
Cc1=0.3;
Cc2=0.2;
Cc3=0.25;
H2=12;
H3=6;
H1=21;
e1=0.82;
e2=0.7;
e3=0.75;
s1=Qg/(Lg+z1)/(Bg+z1); //sigma1
s2=500*1000/(9+27)/(6+27);//sigma2
s3=500*1000/(9+36)/(6+36);//sigma3
ss1=6*105+(27+21/2)*(115-62.4);//sigmadash1
ss2=6*105+(27+21)*(115-62.4)+(120-62.4)*6;//sigmadash2
ss3=6*105+48*(115-62.4)+12*(120-62.4)+3*(122-62.4);//sigmadash3
sc1=Cc1*H1/(1+e1)*log10((ss1+s1)/ss1);
sc2=Cc2*H2/(1+e2)*log10((ss2+s2)/ss2);
sc3=Cc3*H3/(1+e3)*log10((ss3+s3)/ss3);
sc=sc1+sc2+sc3;
disp(sc*12,"total settlement in inch");
|
b6070628f7899bce8ec7a6079d4a805d2fb18852 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3841/CH19/EX19.4/Ex19_4.sce | 16b15fe4b5353919967ff4b79eb164c5cecde923 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 269 | sce | Ex19_4.sce | clear
//given
//how many gallon does the same tank hold of 25 inches
x=25.
y=64
z=x/y
printf("\n \n gallons does hold %.2f ",z)
//volume fraction
//1783 is last problem got result we are using it same one
Z=0.3611
Ct=Z*1783.
printf("\n \n content of tank %.2f gal",Ct)
|
c1fd76c55cc963151e5e749f5083de96bafe883b | 449d555969bfd7befe906877abab098c6e63a0e8 | /62/CH6/EX6.38/ex_6_38.sce | 9fafe5998ba67c21e18c642e100ddccdfe1c3590 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 499 | sce | ex_6_38.sce | clear;
clc;
close;
disp("given y[n]=x[n]+x[n-1] this can be converted to high pass filter by multiplying with (-1)^n")
disp("then y[n]=x[n]-x[n-1] taking fourier transform");
disp("H(w)=1-e^-j*w");
w=-3:0.01:3;
Hw=1-%e^(-%i*w);
subplot(2,1,1)
plot(w,abs(Hw));
xtitle('|H(w)|','w')
subplot(2,1,2)
plot(w(1:find(w==0)-1),phasemag(Hw(1:find(w==0)-1))*%pi/180)
a=gca();
a.y_location="origin";
plot(w(find(w==0)+1:$),phasemag(Hw(find(w==0)+1:$))*%pi/180)
xtitle('phase(H(w))','w')
|
ef67f50234b51c866c650271f6785df2f2727b15 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1445/CH4/EX4.2/Ex4_2.sce | 2a1b004b4f3737fd3cb13f29a1fef55460df98a2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 426 | sce | Ex4_2.sce | //CHAPTER 4- MEASURING INSTRUMENTS
//Example 2
clc;
disp("CHAPTER 4");
disp("EXAMPLE 2");
//VARIABLE INITIALIZATION
G=10; //galvanometer resistance in Ohms
S=1; //shunt resistance in Ohms
r=12; //total resistance in Ohms
emf=2; //emf of cell in Volts
//SOLUTION
I=emf/r; //current in the circuit
I_g=(S*I)/(S+G);
disp(sprintf("The current through the galvanometer is %f A",I_g));
//END
|
ef80606c2f658848d4b4538fd1e458d4dbdb5b3a | 449d555969bfd7befe906877abab098c6e63a0e8 | /2123/CH3/EX3.3/Exa_3_3.sce | 18a7d8a69089de7445c538bcfbbb100ec5508ab0 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 654 | sce | Exa_3_3.sce | //Example No. 3.3
clc;
clear;
close;
format('v',8);
//Given Data :
v=60;//Km/hr
w=400;//KN
friction=5;//N/KN weight
tan_theta=1/100;//inclination
g=9.81;// gravity constant
//Solution :
sin_theta=tan_theta;
W_sin_theta=w*1000*sin_theta;//N
R=friction*W_sin_theta/10;//frictional resistance in N
P=W_sin_theta+R;//N
v=60*1000/60/60;//m/s
Power=P*v;//Watt
disp(Power/1000,"Final KW rating of the motor of train : ");
Force=P;//down the inclined force in N
u=v;//initial velocity in m/s
v=0;//final velocity in m/s
m=w*1000/g;//in Kg
KE=1/2*m*u^2;//in Joule
d=KE/P;//distance in meter
disp(d,"Distance covered in meter : ");
|
79b54779c8096eb8b3f209d76a9ceea69b1777b8 | f04d3d47f893de08cd99a31b4870112915b80d5b | /Datasets/australian/data10.tst | b67b4945e68a26598680fe548a98d46d48381667 | [] | no_license | MesumRaza/MyWorkInPython | f5364b8514943e44c7200123653da9f4551251b1 | bd8c9b3ca2fb02ae6d2b626054fa3cd32c28b330 | refs/heads/master | 2021-08-19T21:46:41.412995 | 2017-11-27T13:37:52 | 2017-11-27T13:37:52 | 111,728,604 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 5,315 | tst | data10.tst | 0 0.0702256 0.330357 0.5 0.769231 0.375 0.0424561 1 1 0.0597015 0 0.5 0.03 0.0054 class1
0 0.142857 0.209821 0.5 0.769231 0.375 0.111228 1 1 0.149254 0 0.5 0.06 0.00245 class1
1 0.14782 0.0639286 0.5 0.538462 0.375 0.0189474 0 0 0 1 0.5 0.068 1e-05 class0
1 0.219248 0.178571 0.5 0.615385 0.375 0.385965 1 0 0 1 0.5 0.035 0 class1
1 0.179248 0.0789286 0 0.384615 0.375 0.140351 1 0 0 0 0.5 0.094 0 class0
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1 0.516241 0.133929 0.5 0.153846 0.5 0.0350877 0 0 0 0 0.5 0.05 2e-05 class0
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1 0.225564 0.0535714 0 0.538462 0.375 0.0526316 1 0 0 1 0.5 0 0.00225 class0
1 0.224361 0.333393 0.5 0.769231 0.875 0.198772 1 1 0.0895522 0 0.5 0.1905 0.00168 class1
1 0.184211 0.0357143 0.5 0.769231 0.375 0.0614035 1 0 0 1 0.5 0.14 0 class1
1 0.146617 0.113036 0 0.230769 0.375 0.0145614 0 1 0.0149254 1 0.5 0.14 0.0008 class0
1 0.189173 0.464286 0.5 0.692308 0.125 0 0 0 0 1 0.5 0.07 0.0111 class0
1 0.610226 0.241071 0.5 0.538462 0.875 0.0921053 1 1 0.164179 1 0.5 0 0.00284 class1
1 0.26797 0.0133929 0.5 0.0769231 0.375 0.0307018 1 0 0 1 0 0.464 0 class0
0 0.172932 0.446429 0.5 0.0769231 0.375 0.0350877 0 0 0 1 0.5 0.09 0.01062 class0
1 0.29203 0.113036 0 1 0.375 0.111053 1 1 0.0447761 1 0.5 0.19 0 class1
1 0.387218 0.0580357 0.5 0.538462 0.375 0.0526316 0 0 0 0 0.5 0 0.00316 class0
0 0.0589474 0 0 0.307692 0 0 0 0 0 0 0.5 0.043 0 class0
1 0.152932 0.02375 0.5 0.538462 0.375 0.00578947 0 0 0 0 0.5 0.05 0 class1
1 0.194286 0.0967857 0 0.923077 0.375 0.184211 1 1 0.0149254 0 0.5 0.1055 0 class1
0 0.131579 0.0148214 0.5 0.153846 0.375 0.0117544 0 0 0 1 0 0.072 0 class0
1 0.393534 0.0192857 0 0.384615 0.375 0.0175439 1 1 0.0447761 0 0.5 0.1 0.01 class1
0 0.185414 0.309464 0.5 0.384615 0.375 0.0496491 1 0 0 0 0.5 0.08 0.0015 class1
1 0.093985 0 0.5 0.0769231 0.375 0.0175439 0 0 0 0 0.5 0.072 0 class0
1 0.26797 0.142857 0 0.153846 0.375 0.00298246 0 0 0 1 0.5 0.2055 0 class0
1 0.195489 0.160714 0 0.538462 0.5 0.0877193 0 0 0 0 0.5 0.1 0.0121 class0
0 0.16797 0.0446429 0.5 0 0 0 1 0 0 0 0.5 0.04 0 class0
0 0.278195 0.0535714 0.5 0.538462 0.375 0.00877193 0 0 0 1 0.5 0.186 0.00122 class0
1 0.0589474 0.159286 0.5 0.538462 0.375 0.00877193 0 0 0 0 0 0.04 0 class0
0 0.360902 0.196429 0.5 0.769231 0.375 0.00438596 1 0 0 1 0.5 0.114 0 class1
1 0.134135 0.0907143 0 0.538462 0.875 0.0907018 1 0 0 0 0.5 0 0 class1
0 0.0627068 0.364643 0.5 0 0 0 0 0 0 0 0.5 0 0.0005 class0
1 0.160451 0.440536 0.5 0.769231 0.875 0.055614 1 0 0 1 0.5 0.06 0 class1
0 0.180451 0.0178571 0.5 0.538462 0.875 0.0307018 1 0 0 1 0.5 0.2455 0 class1
1 0.186767 0.446429 0 0.230769 0.875 0.0438596 0 0 0 1 0.5 0 0.00017 class0
0 0.135338 0.220179 0.5 0.384615 0.375 0.00578947 0 0 0 0 0.5 0.11 0.01 class0
1 0.139098 0.0267857 0.5 0.461538 0.375 0.0175439 1 0 0 1 0 0.16 0 class0
1 0.179248 0.0103571 0 0.538462 0.375 0.0526316 0 0 0 1 0.5 0.08 0 class0
1 0.523759 0.00732143 0 0.230769 0.375 0.00877193 1 1 0.164179 0 0.5 0.19 0.02732 class1
1 0.111579 0 0.5 0.538462 0.375 0.0175439 0 0 0 1 0 0 0 class0
1 0.323308 0.589286 0 0.538462 0.375 0.140351 1 0 0 0 0.5 0.04 0 class0
0 0.137895 0.41375 0.5 0.923077 0.375 0.00140351 1 0 0 0 0.5 0.04 0.01349 class1
0 0.517594 0.0476786 0.5 0.153846 0.75 0.0117544 0 0 0 0 0.5 0 0.0012 class0
1 0.43985 0.0103571 0 0.923077 0.875 0.0614035 1 1 0.119403 0 0.5 0.05 0.00375 class1
1 0.26797 0.375 0.5 1 0.375 0.22807 1 0 0 0 0.5 0 0 class1
1 0.10406 0.0148214 0.5 0.538462 0.375 0.00438596 0 0 0 0 0.5 0 0.00044 class0
0 0.076391 0.340714 0.5 0.384615 0.375 0.00298246 1 0 0 0 0.5 0.05 0 class1
0 0.205564 0.517857 0.5 1 0.875 0.108246 1 1 0.0149254 0 0.5 0.06 0.00011 class1
1 0.409774 0.00142857 0.5 0.692308 0.375 0.00140351 0 1 0.0149254 0 0 0.28 0 class1
|
ab9d25ace6e4da117b32609c876b08ee1f897cb1 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3831/CH13/EX13.2/Ex13_2.sce | 69c38251f5588e2a176c867c719176239b9a25a3 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 711 | sce | Ex13_2.sce | // Example 13_2
clc;funcprot(0);
// Given data
D_piston=2.00;// ft
W_out=20;// hp
L=4.00;// ft/stroke
m_b=4000;// lbf
d=15.0;// ft
Duty=35.0*10^6;
N=18.0;// strokes per minute
// Calculation
// (a)
A=(%pi*D_piston^2)/4;// ft^2
W_out=20*33000;// ft.lbf/min
p_avg=W_out/(A*L*N);// lbf/ft^2
p_avg=p_avg/144;// lbf/in^2
// (b)
n_T=(Duty/(8.5*10^8))*100;// The actual thermal efficiency of the engine in %
// (c)
W_out=20;// hp
Q_boiler=(W_out*2545)/(n_T/100);// Btu/h
printf("\n(a)The average pressure of the cycle,p_avg=%2.1f lbf/in^2 \n(b)The actual thermal efficiency of the engine,n_T=%1.2f percentage \n(c)The heat rate produced by the boiler,Q_boiler=%1.2e Btu/h",p_avg,n_T,Q_boiler);
|
965ad664293b32901e4226ff984ab56c87a3d549 | c908c5ec283c57c29da044966fce0fee1f659873 | /labs/Experimento 5/Exp 5-Códigos/Algoritmo do Método de Euler.sce | d525340751e4600c464886c747d981c3ad7f4b51 | [] | no_license | marialago/numerical-computation | 3ca0e95c637c1d4d3ea79789d1bda0b84ca29ca5 | c88c0ddc6f7501ed115556f72f5f5db3a8610f6b | refs/heads/master | 2022-10-30T01:42:21.032196 | 2020-06-14T18:33:45 | 2020-06-14T18:33:45 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 378 | sce | Algoritmo do Método de Euler.sce | function [t,d,v]=euler2(a,b,h,d0,v0)
t=a:h:b
d(1)=d0
v(1)=v0
n=length(t)
for i=2:n
d(i)=d(i-1)+h*df(t(i-1),d(i-1),v(i-1))
v(i)=v(i-1)+h*df2(t(i-1),d(i-1),v(i-1))
end
endfunction
function a=df(t,d,v)
a=v
endfunction
function r=df2(t,d,v)
K=5/7;
g=25634.7
teta=0.0913
r=-K*g*sin(teta)
endfunction
|
59f35afe993cadced20f901cea5cda4de3452edf | 449d555969bfd7befe906877abab098c6e63a0e8 | /2492/CH8/EX8.9/ex8_9.sce | f8faee15a082c1030e10de1fea3689122cdce968 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 893 | sce | ex8_9.sce | // Exa 8.9
format('v',6)
clc;
clear;
close;
// Given data
R_C= 1;// in k ohm
V_CC= 5;// in V
V_CEsat= 0;// in V
V_BE= 0.7;// in V
bita_min= 50;
bita_max= 100;
// For the transistor to go to saturation,
I_C= (V_CC-V_CEsat)/R_C;// in mA
bita= bita_min;// for driving the transistor into saturation
I_Bmin= I_C/bita;//minimum base current in mA
// So, (V_CC-V_BE)/R_B >= I_B or
R_B= (V_CC-V_BE)/I_Bmin;// in k ohm
disp(R_B,"The maximum permissible value of R_B in k ohm is : ")
// For actual calculation one may take V_CEsat= 0.3 V
V_CEsat= 0.3;// in V
I_C= (V_CC-V_CEsat)/R_C;// in mA
bita= bita_min;// for driving the transistor into saturation
I_Bmin= I_C/bita;//minimum base current in mA
// So, (V_CC-V_BE)/R_B >= I_B or
R_B= (V_CC-V_BE)/I_Bmin;// in k ohm
disp("For actual calculation at V_CE(sat) = 0.3 V, the maximum value ")
disp(R_B,"of R_B in k ohm is : ")
|
6b3c7bae6ca41e4042eb407e3aa33b0877907789 | 1485852dd59aafc286600126cf832a32e10f117f | /tests/localMaximaFinder/test4.sce | e2f42d6805d06558eb7240aa8e03f7f1b5e10f2b | [] | no_license | rg77/Scilab-Image-Processing-And-Computer-Vision-Toolbox | dec9fbbce32cfd1eab3c45ccb29c89aaa1384758 | 8adb116da3a9c29a32e5e0727105aff571e5b374 | refs/heads/master | 2020-12-02T16:14:45.282650 | 2017-07-07T10:12:04 | 2017-07-07T10:12:04 | 96,524,257 | 0 | 0 | null | 2017-07-07T09:43:50 | 2017-07-07T09:43:50 | null | UTF-8 | Scilab | false | false | 118 | sce | test4.sce | src= imread("../images/image_0197.jpg"); //another image
gray = rgb2gray(src);
loc=localMaximaFinder(gray,[1 3],4,1);
|
b1b5ac061aca49fde96a9ba3650608163f90ea70 | a1161d9e9d26e0a7b20c31269be145f13d9d3e89 | /QA/tests/had/had_md.tst | 9375d0b2120df320ff89d35d8370be3e7914246a | [
"LicenseRef-scancode-warranty-disclaimer",
"ECL-2.0"
] | permissive | nwchemgit/nwchem | c06e7e1fe11b3afad17b167f29a97c4fa3ad0fda | c5a8125298a6ea7d6eb27b07c196ea8041aa7198 | refs/heads/master | 2023-09-05T17:18:34.513866 | 2023-09-02T02:56:47 | 2023-09-02T02:56:47 | 111,318,191 | 425 | 164 | NOASSERTION | 2023-09-11T16:34:14 | 2017-11-19T17:48:21 | Fortran | UTF-8 | Scilab | false | false | 1,500 | tst | had_md.tst | Time = 0.000
Temperature = 0.22
Volume = 0.00
Pressure = -4.51E+08
Energy = 0.000E+00
Time = 0.002
Temperature = 28.62
Volume = 404.81
Pressure = -4.35E+08
Energy = -5.684E+05
Time = 0.004
Temperature = 110.24
Volume = 404.41
Pressure = -4.48E+08
Energy = -5.598E+05
Time = 0.006
Temperature = 132.03
Volume = 404.00
Pressure = -4.72E+08
Energy = -5.379E+05
Time = 0.008
Temperature = 141.38
Volume = 403.57
Pressure = -4.87E+08
Energy = -5.342E+05
Time = 0.010
Temperature = 147.51
Volume = 403.12
Pressure = -4.92E+08
Energy = -5.333E+05
Time = 0.012
Temperature = 151.01
Volume = 402.67
Pressure = -4.88E+08
Energy = -5.325E+05
Time = 0.014
Temperature = 152.14
Volume = 402.23
Pressure = -4.76E+08
Energy = -5.318E+05
Time = 0.016
Temperature = 152.58
Volume = 401.79
Pressure = -4.60E+08
Energy = -5.310E+05
Time = 0.018
Temperature = 154.21
Volume = 401.38
Pressure = -4.40E+08
Energy = -5.301E+05
|
59db3dfece6bf2246175501359687a9ecd9623ad | 449d555969bfd7befe906877abab098c6e63a0e8 | /3888/CH10/EX10.8/Ex10_8.sce | 62bbcdbf6fc60c114e985c989413824966c56442 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 969 | sce | Ex10_8.sce | //Electric Power Generation, Transmission and Distribution by S.N.Singh
//Publisher:PHI Learning Private Limited
//Year: 2012 ; Edition - 2
//Example 10.8
//Scilab Version : 6.0.0 ; OS : Windows
clc;
clear;
d=0.25; //Diameter of conductor in m
r=0.0125; //Radius of conductor in m
Dab=5; //Distance between conductors a & b in m
Dbc=4; //Distance between conductors b & c in m
Dac=6; //Distance between conductors a & c in m
Deq=nthroot((Dab*Dbc*Dac),3); //Diameter equivalent of line in m
Can=(2*%pi*10^(-9)/(36*%pi))/log(Deq/r); //Capacitance between phase a & neutral in pF/m
printf("\nThe capacitance of the transmissin line is %.2f pF/m",Can/(10^-12));
|
cf1380af26412214a0e7471f2dc6dd4affa69a83 | 449d555969bfd7befe906877abab098c6e63a0e8 | /995/CH2/EX2.17/Ex2_17.sce | 1a3e85bd9d8720c526a21a5db2fdc7d04b7496a4 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 219 | sce | Ex2_17.sce | //Ex:2.17
clc;
clear;
close;
r_o=40;//resis at 0 degree
r_t=44;//at 100 degree
t=100;//temperature diff.
temp_coeff=(1/t)*((r_t/r_o)-1);
printf("Temperature Coefficient = %f per degree centigrade",temp_coeff);
|
9f18b07f48fb56aafce49c89443fb2cf6384955d | a8592d34f144b71794ebf30f1c2a1b5faf0b053c | /AkarPersamaan/scilab/test_polyroots_01.sce | 9718d1ecaac812e3932b27a89c8554241a8c87b7 | [] | no_license | f-fathurrahman/ffr-MetodeNumerik | ee9a6a7153b174b1ba3d714fe61ccbd1cb1dd327 | e3a9da224c0fd5b32e671708e890018a3c4104c4 | refs/heads/master | 2023-07-19T22:29:38.810143 | 2023-07-07T10:02:34 | 2023-07-07T10:02:34 | 107,272,110 | 2 | 2 | null | null | null | null | UTF-8 | Scilab | false | false | 375 | sce | test_polyroots_01.sce | exec("evalpoly.sce", 0)
exec("deflpoly.sce", 0)
exec("my_laguerre.sce", 0)
exec("polyroots.sce", 0)
a = [1, 3, 4, 5, 6, 7, 8];
r0 = polyroots(a)
r0_sci = roots(a)
n = length(r0)
printf("\nResult of built-in roots function of Scilab:\n")
for i = 1:n
printf("Root %d = %18.10f %18.10f\n", i, real(r0_sci(i)), imag(r0_sci(i)))
end
if getscilabmode() ~= "STD"
quit()
end
|
92e131abaea5eb043e6f6cb1b179b85a4648e45b | 449d555969bfd7befe906877abab098c6e63a0e8 | /839/CH24/EX24.3/Example_24_3.sce | 2a9dd229741c781231d1f039bbee307334aa6afe | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,728 | sce | Example_24_3.sce | //clear//
clear;
clc;
//Example 24.3
//Given
Tw = 80; //[F]
Tdb = 120; //[F]
v = 3.5; //[ft/s]
rho = 120; //[lb/ft^3]
Xe = 0;
Xc = 0.09;
lambda = 1049; //[Btu/lb]
M = 29;
B = 24; //[in.]
D = 2; //[in.]
Dc = 2; //[ft]
X2 = 0.20;
X1 = 0.10;
Dcyl = 1/4; //[in.]
L = 4; //[in.]
Vbar = 3.5; //[ft/s]
Thb = 120;
//Solution
//Since the Xc is less than 10 percent, all drying takes place
//in the constant-rate period and the vaporrization temperature,
//as before, is 80 F.
//From Exapmle 24.1, mass of water to be evaporated
mdot = 8*(X2-X1); //[lb]
//The quantity of heat to be transferred
QT = mdot*lambda; //[Btu]
//mass of the dry soild in one cylinder is
mp = %pi/4*(Dcyl/12)^2*(L/12)*rho; //[lb]
//surface area of one cylinder is
Ap = %pi*(Dcyl/12)*(L/12); //[ft^2]
//Total area exposed by 8 lb solids
A = 8/mp*Ap; //[ft^2]
//The heat transfer coefficient is found from the
//equivalent form of Eq.(21.62)
//hDbyk = 1.17*Nre^0.585*Npr^(1/3)
//For air at 1 atm and 120F, the properties are
rho_a = M/359*492/580; //[lb/ft^3]
mu_a = 0.019; //[cP], from Appendix 8
k_a = 0.0162; //[Btu/ft-h-F], from Appendix 12
Cp_a = 0.25; //[Btu/lb-F], from Appendix 15
Nre = 1/48*Vbar*rho_a/(mu_a*6.72*10^-4);
Npr = mu_a*2.42*Cp_a/k_a;
//Form Eq.(21.62)
h = (k_a*1.17*Nre^0.585*Npr^(1/3))/(1/48); //[Btu/ft^2-h-F]
mdot_g = v*3600*rho_a; //[lb]
//From Fig. 23.2
cs = 0.25;
delta_Thb = Thb-Tw; //[F]
delta_Tha = 8.24; //[F]
//The heat transferred form the gas to a thin section of the bed
delta_TL = (delta_Thb-delta_Tha)/log(delta_Thb/delta_Tha); //[F]
//rate of heat transfer
qT = h*A*delta_TL; //[Btu/h]
//drying time
tT = QT/qT; //[h]
disp('h',tT,'Required drying time is')
|
4b71aa69fe4743dbb0d711729f6be1fea4f1017d | 449d555969bfd7befe906877abab098c6e63a0e8 | /1938/CH4/EX4.2/4_2.sce | 70a3e9d172c8ccdd5b98b420445ad3d0c26aeab6 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 329 | sce | 4_2.sce | clc,clear
printf('Example 4.2\n\n')
Slots=120
Pole=8
Phase=3 //number of phases
n=Slots/Pole //Slots per Pole
m=Slots/Pole/Phase //Slots per Pole per Phase
beeta=180/n //Slot angle in degree
K_d=sind(m*beeta/2) /(m*sind(beeta/2)) //Distribution Factor
printf('Distribution Factor:\nK_d=%.3f',K_d)
|
4ec82fe9455f1ff896f35bdd6a450c5117ebca35 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3673/CH3/EX3.a.2/Example_a_3_2.sce | 886971fd7c45e66759182f76ba61c5166c45b500 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 239 | sce | Example_a_3_2.sce | //Example_a_3_2 page no:129
clc;
R=(((8+1.07)*1)/(8+1.07+1))+1;
I1=10/R;
It=5/5.8;
I5=(It*10)/18.5;
I2=(I5*1)/2;
Ir3=(10*6.07)/(6.07+3.5);
I3=(Ir3*(1/2));
I=I1-I2-I3;
disp(I,"the current passing through the circuit is (in A)");
|
e084fa72ac937c7cd539e8e3b601a6fa194caf34 | 449d555969bfd7befe906877abab098c6e63a0e8 | /405/CH10/EX10.1/10_1.sce | da627fc850e2ac24d19c694fa0da78f52fa23a35 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 3,045 | sce | 10_1.sce | clear;
clc;
printf("\t\t\tExample Number 10.1\n\n\n");
// overall heat transfer coefficient for pipe in air
// Example 10.1 (page no.-520-522)
// solution
Tw = 98;// [degree celsius] temperature of hot water
k_p = 54;// [W/m degree celsius] heat transfer coefficient of pipe
Ta = 20;// [degree celsius] atmospheric air temperature
u = 0.25;// [m/s] water velocity
// from appendix A the dimensions of 2-in schedule 40 pipe are
ID = 0.0525;// [m]
OD = 0.06033;// [m]
// the properties of water at 98 degree celsius are
rho = 960;// [kg/cubic meter]
mu = 2.82*10^(-4);// [kg/m s]
k_w = 0.68;// [W/m degree celsius]
Pr = 1.76;// prandtl number
// the reynolds number is
Re = rho*u*ID/mu;
// and since turbulent flow is encountered, we may use equation(6-4):
Nu = 0.023*Re^(0.8)*Pr^(0.4);
hi = Nu*k_w/ID;// [W/square meter degree celsius]
// for unit length of pipe the thermal resistance of the steel is
Rs = log(OD/ID)/(2*%pi*k_p);
// again, on a unit length basis the thermal resistance on the inside is
Ai = %pi*ID;// [square meter]
Ri = 1/(hi*Ai);
Ao = %pi*OD;// [square meter]
// the thermal resistance for outer surface is as yet unknown but is written, for unit lengths, is Ro = 1/(ho*Ao) (a)
// from table 7-2(page no.-339), for laminar flow, the simplified relation for ho is
// ho = 1.32*(dT/d)^(1/4) = 1.32*((To-Ta)/OD)^(1/4) (b)
// where To is the unknown outside pipe surface temperature. we designate the inner pipe surface as Ti and the water temperature as Tw; then the energy balance requires
// (Tw-Ti)/Ri = (Ti-To)/Rs = (To-Ta)/Ro (c)
// combining equations (a) and (b) gives
// (To-Ta)/Ro = %pi*OD*1.32*(To-Ta)^(5/4)/OD^(1/4)
// this relation may be introduced into equation (c) to yield two equations with the two unknowns Ti and To:
// (Tw-Ti)/Ri = (Ti-To)/Rs (1)
// (Ti-To)/Rs = %pi*OD*1.32*(To-Ta)^(5/4)/OD^(1/4) (2)
// this is a non-linear equation which can be solved as
for Ti = 50:0.001:100
Q = ((Ti-(Ti-(Tw-Ti)*(Rs/Ri)))/Rs)-(%pi*OD*1.32*((Ti-(Tw-Ti)*(Rs/Ri))-Ta)^(5/4)/OD^(1/4));
if Q>0 & Q<6 then
Tinew = Ti;
else
Ti = Ti;
end
end
Ti = Tinew;// [degree celsius]
To = (Ti-(Tw-Ti)*(Rs/Ri));// [Degree celsius]
// as a result, the outside heat transfer coefficient and thermal resistance are
ho = 1.32*((To-Ta)/OD)^(1/4);// [W/square meter degree celsius]
Ro = 1/(OD*7.91*%pi);//
// the overall heat transfer coefficient based on the outer area is written in terms of these resistances as
Uo = 1/(Ao*(Ri+Ro+Rs));// [W/area degree celsius]
// in this calculation we used the outside area for 1.0 m length as Ao
// so
Uo = Uo;// [W/square meter degree celsius]
printf("overall heat transfer coefficient is %f W/square meter degree celsius",Uo);
|
2f55e5a9907395527d6962236b8a7cc79ddbb44b | 449d555969bfd7befe906877abab098c6e63a0e8 | /1118/CH2/EX2.3/eg2_3.sce | 62d8f480e0eb4086f4ee9eede49880317258a352 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 373 | sce | eg2_3.sce | clear;
clc;
s=5*10^6;
l=50*10^3;
pf=0.8;
eff=.9;
v=33*10^3;
rho=2.85*10^(-8);
pl=0.1*s*pf;
i=s/v;
a1=2*i*i*rho*l/pl;
vol=2*l*a1;
printf("the volume of theconductor required is:%.2f cubic meter",vol);
//b)
il=s/(sqrt(3)*v);
a2=3*il*il*rho*l/pl;
vol=3*l*a2
printf("\n the volume of theconductor required is:%.2f cubic meter",vol);
|
28d0534e31ade00173d31f214d0f9c3bb2e7e8c0 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1958/CH1/EX1.3/Chapter1_example3.sce | 7606661d7cfac85f276b89dd7b8f0a49ea0639ef | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 523 | sce | Chapter1_example3.sce | clc
clear
//Input data
m=0.2//Mass of the ball in kg
r=1.5//Radius of vertical circle in m
q=35//Angle made by the ball in degrees
v=6//Velocity of the ball in m/s
//Calculations
T=(m*((v^2/r)+(9.8*cosd(q))))//Tension in the string in N
at=9.8*sind(q)//Tangential acceleration in m/s^2
ar=(v^2/r)//Radial acceleration in m/s^2
a=sqrt(at^2+ar^2)//Acceleration in m/s^2
//Output
printf('Tension in the string is %3.1f N \n Tangential acceleration is %3.2f m/s^2 \n Radial acceleration is %i m/s^2',T,at,ar)
|
a60e8b94ccfb3389673cfb5da4bfd0da0f6434cb | 449d555969bfd7befe906877abab098c6e63a0e8 | /3821/CH10/EX10.14/Example10_14.sce | ceeb753ac85a75a04ebe949faad2d06c27709df6 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 441 | sce | Example10_14.sce | /////////Chapter 10 Properties Of Steam
///Example 10.14 Page No:197
//// Find Degree of superheat
///Input Data
clc;
clear;
P=7; //Absolute pressure in bar
t=200; //Absolute temperature
ts=165; //In degree celsius from steam table
//Calculation
dos1=t-ts; //Degree of superheat in degree celcius
//Output
printf('Degree of superheat=%f degree celsius \n ',dos1);
|
ab02d9de5da24cc449f49a1386a9af038d85ed24 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1697/CH9/EX9.4/Exa9_4.sce | 23f3826405e4ffbe1966c080b8aabb61dd2d9857 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 217 | sce | Exa9_4.sce | //Exa 9.4
clc;
clear;
close;
//given data :
HT=100;//in meter
d=60;//in Km
//Formula : d=4.12*(sqrt(HT)+sqrt(HR));//in Km
HR=(d/4.12-sqrt(HT))^2;//in meter
disp(HR,"Height of receiving antenna in meter : "); |
81cb90a4e02d205dafbd217e6790f0f6394c4307 | 449d555969bfd7befe906877abab098c6e63a0e8 | /605/CH7/EX7.1/7_1.sce | 8633145a04f6dec9201f7467f2198f88fce62eee | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 251 | sce | 7_1.sce |
RL=100
Zo=50
PM=0.05
c=3*10^8
f=900*10^6
lambda=c/f
Z1=sqrt(RL*Zo)
l=lambda/4
fractional_bandwidth=2-4/%pi*acos(abs(2*PM*sqrt(Zo*RL)/(RL-Zo)/sqrt(1-PM^2)))
printf("\nZ1=%f ohm\nl=%.4f m\nfractional bandwidth=%.7f",Z1,l,fractional_bandwidth) |
27994bd21421b8f693467eb40209f9903baa8191 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1754/CH11/EX11.1/Exa11_1.sce | 726987884666e67d41c62086f1da19e3fd8b87b5 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 266 | sce | Exa11_1.sce | //Exa 11.1
clc;
clear;
close;
//Given data
R1=15;//in kohm
R2=15;//in kohm
C1=0.005;//in uF
C2=0.005;//in uF
R=R1;//in Kohm
C=C1;//in uF
T=0.69*(R*10^3*C*10^-6+R*10^3*C*10^-6);//in second
f=1/T;//in Hz
disp(f*10^-3,"Frequency of oscillators in KHz : "); |
f287811b1168d5c87a3de6c09e0acdc82f7d540b | 449d555969bfd7befe906877abab098c6e63a0e8 | /2441/CH2/EX2.8/Ex2_8.sce | eca2b821022fcf64087806b6a9d4e0bcfa53faea | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 541 | sce | Ex2_8.sce | //exa 2.8
clc;clear;close;
format('v',8);
//dC1/dP1=0.2*P1+22;//Rs./MWh
//dC2/dP2=0.15*P2+30;//Rs./MWh
B22=0;B12=0;//Because Loss is independent wrt P2
P1=100;//MW
PL=15;//MW
B11=PL/P1^2;//MW^-1
L1=1/[1-0.003*P1];//Penalty Factor plant 1
L2=1;//Penalty Factor of plant 2
lambda=60;
//lambda=dC1/dP1*L1=dC2/dP2*L2
//dC1/dP1*L1=dC2/dP2*L2
P2=((0.2*P1+22)*L1-30)/0.15;//MW
P=P1+P2-B11*P1^2;//MW//Total Load
disp(P1,"Required generation at plant1(MW)");
disp(P2,"Required generation at plant2(MW)");
disp(P,"Total Load(MW)");
|
1f660ea81368035a5aab2561b7e960d3700159d3 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3769/CH12/EX12.19/Ex12_19.sce | d9a8b0afdd6ea83b5026a82efe1b73fe85917aae | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 275 | sce | Ex12_19.sce | clear
//Given
L=500*10**-3
I1=20*10**-3 //A
I2=10*10**-3 //A
//Calculation
U1=0.5*L*I1**2
U2=0.5*L*I2**2
//Result
printf("\n Magnetic energy stored in the coil is %0.3f *10**-4 J",U1*10**6)
printf("\n New value of energy is %0.3f J",U2)
|
919ecf8646922aa158c3c32e71b548db08dd2ea3 | 449d555969bfd7befe906877abab098c6e63a0e8 | /42/CH11/EX11.5/sadiku_11_5.sce | 0d3ddb6a808aa5a062bf6f3b3eaa794f94f384ba | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 460 | sce | sadiku_11_5.sce | clear;
clc;
format('v',6);
Zl=100+150*%i;
Zo=75;
zl=Zl/Zo;
T=(Zl-Zo)/(Zl+Zo);
disp(T,'T =');
s=(1+abs(T))/(1-abs(T));
disp(s,'s =')
format('v',5);
Yl=1/Zl;
disp(Yl*1000,'Load admittance in mS');
B=2*%pi,l=.4;
Zin=Zo*(Zl+Zo*tan(B*l)*%i)/(Zo+Zl*tan(B*l)*%i);
format('v',6);
disp(Zin,'Zin at .4 l from load')//for .4l
B=2*%pi,l=.6;
Zin=Zo*(Zl+Zo*tan(B*l)*%i)/(Zo+Zl*tan(B*l)*%i);
format('v',6);
disp(Zin,'Zin at .6 l from load')//for .6l
|
2fd40c77210465080fee650cac381a1c1b060505 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1627/CH4/EX4.5/Ex4_5.sce | f2372c71a9ab2c32e5b350596c9af512dff28562 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 245 | sce | Ex4_5.sce | clc
//initialisation of variables
p=8000*10^-3//liters/min
r=15*10^-2//cm
v=2.5//m
//CALCULATIONS
V1=(4*(p)*(1/60))/(%pi*(r)^2)//m/s
D=sqrt(4*(p)*(1/60)/(%pi*v))*100//cm
//RESULTS
printf('The diameter of the suction line is=% f cm',D)
|
aa31552690f7b7a0e0ce31b9819211035f01dda1 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1793/CH14/EX14.1/14Q1.sce | 6cb3528d67ea5446c9be699d63a7a503ce2e56c0 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 382 | sce | 14Q1.sce | clc
G=15.7
a=0
b=15
c=30
H=3
Kp=4.977 // from table 13.9
Pp=Kp*G*H^2/2
printf('a)the passive force = %f kN/m\n',Pp)
// for part b
Kp=4.53
Pp=Kp*G*H^2/2
printf(' b)the passive force = %f kN/m\n',Pp)
// for part c
Kp=4.13
Pp=Kp*G*H^2/2
printf(' c)the passive force = %f kN/m\n',Pp)
//for part d
Kp=4.56
Pp=Kp*G*H^2/2
printf(' d)the passive force = %f kN/m\n',Pp)
|
af89341d7c50909e49fc775b20e8c66610fcd18f | 449d555969bfd7befe906877abab098c6e63a0e8 | /2153/CH3/EX3.26/ex_3_26.sce | 179768562c388251f8f20eb0a3ccc348e53afaa2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 226 | sce | ex_3_26.sce | //Example 3.26 : density
clc;
clear;
close;
//given data :
format('v',5)
n=4;
N=6.023*10^23; // avogadro's number
r=1.278*10^-8;// in cm
A=63.5;
a=(r*4)/sqrt(2);// in cm
b=(A*n)/(a^3*N);
disp(b,"density of copper,b(g/cc) = ")
|
a98cebcceb876196f42b096d411ab3489f0cabc8 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1571/CH9/EX9.13/Chapter9_Example13.sce | 1b7bb91d117eb02f030bb5c38d246995a9f7e2f1 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 352 | sce | Chapter9_Example13.sce | clc
clear
//INPUT
t1=915;//temperature at the beggining in K
t2=2040;//temperature at the end in K
d=12.6;//adiabatic expansion ratio
y=1.39;//coefficent of expansion
//CALCULATIONS
x=t2/t1;//ratio temparatures
n=1-(1/d)^(y-1)*((x^y)-1)/(y*(x-1));//efficiency of the engine
//OUTPUT
mprintf('the efficiency of the engine is %3.3f',n)
|
6dcf29b26414b0e9d50a7f6cb4bf73dc63edadf8 | 717ddeb7e700373742c617a95e25a2376565112c | /806/DEPENDENCIES/1055.sci | ac64f3a7415015742fb4f2d111af6bbd4e1bcac6 | [] | no_license | appucrossroads/Scilab-TBC-Uploads | b7ce9a8665d6253926fa8cc0989cda3c0db8e63d | 1d1c6f68fe7afb15ea12fd38492ec171491f8ce7 | refs/heads/master | 2021-01-22T04:15:15.512674 | 2017-09-19T11:51:56 | 2017-09-19T11:51:56 | 92,444,732 | 0 | 0 | null | 2017-05-25T21:09:20 | 2017-05-25T21:09:19 | null | UTF-8 | Scilab | false | false | 80 | sci | 1055.sci | q=170//L/s(Discharge)
t=60//degrees
g=9.81//m/s^2(Acceleration due to gravity) |
26a6b44f901179a6894dcb1a091ac96951078265 | 31cc146b7597c1571ad100fc4dd888898b1b4eb0 | /topology/minimum_spanning_tree.sce | c5f8660fceab991738a56eaf4cee6c7304b63ac7 | [] | no_license | rigid1980/gpp_scilab | a525ae046722e7ba52ebea6003ce712b51631ff6 | fadb75dea26cf341e6dc60874efd88c016df4f3b | refs/heads/master | 2016-09-11T08:37:44.538715 | 2014-03-26T08:37:35 | 2014-03-26T08:37:35 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 2,306 | sce | minimum_spanning_tree.sce | //// minimum_spanning_tree
// Construct minimum spanning tree on the mesh. Replace Matlab's
// graphminspantree function.
//
// Basically this is a classical implementation of minimum spanning tree
// algorithm, using adjacency matrix. Speed is about 2(large mesh)-4(smaller mesh)
// times slower comparing with Matlab's built-in graphminspantree, which is
// implemented via mex function graphalgs.
//
//// Syntax
// [tree,previous] = minimum_spanning_tree(graph)
// [tree,previous] = minimum_spanning_tree(graph,source)
//
//// Description
// graph : sparse matrix, nv x nv, adjacency matrix of graph (or triangle
// mesh), elements are weights of adjacent path
// source: integer scaler, optional, source node of spanning tree. If not
// provided, will search for smallest node in the graph.
//
// tree: sparse matrix, nv x nv, minimum spanning tree, if there are k
// nodes in the graph, then there are k+1 nonzeros elements in tree.
// previous: double array, n x 1, predecessor nodes of the minimal spanning
// tree, predecessor of source node is 0
//
//// Contribution
// Author : Wen Cheng Feng
// Created: 2014/03/21
// Revised: 2014/03/24 by Wen, add doc
//
// Copyright 2014 Computational Geometry Group
// Department of Mathematics, CUHK
// http://www.lokminglui.com
function [tree,previous] = minimum_spanning_tree(graph,source)
if ~exist('source','var')
[I,J] = find(graph);
source = J(1);
end
nv = size(graph,1);
previous = nan(nv,1);
node = source;
rem = (1:nv)';
// rem(source) = [];
ind = false(nv,1);
ind(I) = true;
ind(source) = false;
rem(~ind) = [];
previous(source) = 0;
nvc = sum(ind);
TI = zeros(nvc,1);
TJ = zeros(nvc,1);
TV = zeros(nvc,1);
k = 1;
// most time is spent on accessing submatrix, overall speed is about two
// times slower than Matlab's build-in function graphminspantree. For smaller
// graph, it's even slower, say, four times.
while ~isempty(rem)
[I,J,V] = find(graph(node,rem)); // time consuming, need to improve
[v,ind] = min(V);
i = node(I(ind));
j = rem(J(ind));
TI(k) = i;
TJ(k) = j;
TV(k) = v;
k = k+1;
previous(j) = i;
// node(k) = j;
node = [node;j];
rem(J(ind)) = [];
end
tree = sparse(TI,TJ,TV,nv,nv);
tree = tril(tree+tree');
|
56871ecc2628538caf2ec9ebc1115783127e958f | 449d555969bfd7befe906877abab098c6e63a0e8 | /2219/CH3/EX3.21/Ex3_21.sce | 2d1d46c53025fd187ba06dbdd9f66e760dc3153b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 788 | sce | Ex3_21.sce | // Chapter 3 example 21
//------------------------------------------------------------------------------
clc;
clear;
// Given data
a = 6; // width of waveguide in cm
b = 3; // narrow dimension of waveguide in cm
lamda = 4; // operating wavelength in cm
c = 3*10^8; // velocity of EM wave in cm/s
// Calculations
lamda_c = 2*a; // cut-off wavelength in dominant mode
lamda_g = lamda/(sqrt(1 - (lamda/lamda_c)^2)) // guide wavelength
Vp = (lamda_g/lamda)*c
b = (2*%pi)/lamda_g; // phase shift constant
// Output
mprintf('Guide wavelength = %3.2f cm\n Phase velocity = %3.2e m/s\n Phase shift constant = %3.2f radians/cm',lamda_g,Vp,b)
//------------------------------------------------------------------------------
|
b281c285268e66d241d6d7512cd374fd2995a6e3 | 5a05d7e1b331922620afe242e4393f426335f2e3 | /macros/fwhmjlt.sci | 129bffcfdb74183abfb08d9a9a6002510fb94023 | [] | no_license | sauravdekhtawala/FOSSEE-Signal-Processing-Toolbox | 2728cf855f58886c7c4a9317cc00784ba8cd8a5b | 91f8045f58b6b96dbaaf2d4400586660b92d461c | refs/heads/master | 2022-04-19T17:33:22.731810 | 2020-04-22T12:17:41 | 2020-04-22T12:17:41 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,326 | sci | fwhmjlt.sci | function [f]=fwhmjlt(y,varargin)
//This function Computes peak full-width at half maximum
//calling sequence
//f = fwhm (y)
//f = fwhm (x, y)
//f = fwhm (…, "zero")
//f = fwhm (…, "min")
//f = fwhm (…, "alevel", level)
//f = fwhm (…, "rlevel", level)
//Description
//Compute peak full-width at half maximum (FWHM) or at another level of peak maximum for vector or matrix data y, optionally sampled as y(x). If y is a matrix, return FWHM for each column as a row vector.
//The default option "zero" computes fwhm at half maximum, i.e. 0.5*max(y). The option "min" computes fwhm at the middle curve, i.e. 0.5*(min(y)+max(y)).
//The option "rlevel" computes full-width at the given relative level of peak profile
//The option "alevel" computes full-width at the given absolute level of y.
//Example
//t=-50:0.01:50;
//y=(1/(2*sqrt(2*%pi)))*exp(-(t.^2)/8);
//z=fwhmjlt(y)
//Output: 470.96442
rhs = argn(2)
if(rhs<1 | rhs>5)
error("Wrong number of input arguments.")
end
select(rhs)
case 1 then
f = callOctave("fwhm",y)
case 2 then
f = callOctave("fwhm",y,varargin(1))
case 3 then
f = callOctave("fwhm",y,varargin(1),varargin(2))
case 4 then
f = callOctave("fwhm",y,varargin(1),varargin(2),varargin(3))
case 5 then
f = callOctave("fwhm",y,varargin(1),varargin(2),varargin(3),varargin(4))
end
endfunction
|
cb8da866284182f1e1b3cf0ea49921a374052bc2 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1073/CH3/EX3.53/3_53.sce | 48e23b7e927e45e51435f503e129d1149f06d6b9 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 681 | sce | 3_53.sce | clc;
clear;
rho=975 //[kg/m^3]
k=0.671 //[W/(m.K)]
mu=3.8*10^-4 //[N.s/m^2]
dT=10 //[K]
lambda=2300*10^3 //[J/kg]
L=1 //[m]
g=9.81 //[m/s^2]
h=0.943*((rho^2*lambda*g*k^3)/(mu*L*dT))^(1/4) //W/(sq m.K) //[W/sq m.K]
printf("\n (i)- Average heat transfer coefficient is %d W/(m^2.K)\n",round(h));
//Local heat transfer coefficient
//at x=0.5 //[m]
x=0.5 //[m]
h=((rho^2*lambda*g*k^3)/(4*mu*dT*x))^(1/4) //[W/sq m.K]
printf("\n (ii)-Local heat transfer coefficient at 0.5 m height is %d W/(sq m.K)\n",round(h));
delta=((4*mu*dT*k*x)/(lambda*rho^2*g))^(1/4) //[m]
delta=delta*10^3 //[mm]
printf("\n (iii)-Film thickness is %f mm",delta);
|
9b61570a26c794e777dcd39364897f1996ae7a4d | 449d555969bfd7befe906877abab098c6e63a0e8 | /182/CH7/EX7.1/example7_1.sce | 8a26fb8d0d5c51557f0e3b9f102d2509f1c2bf3f | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 317 | sce | example7_1.sce | // To find the value of measured Resistance R
// example 7-1 in page 165
clc;
// Given data
I=0.5;//measured current in amps
V=500;// voltmeter indication in volts
Ra=10;//ammeter resistance in ohms
//calculation
R=(V/I)-Ra;// measured resistance
printf("The value of R=%d ohm",R);
//result
// The value of R=990 ohm |
5462a994a4c28cc1d91c383b01719546b9c5bfff | 92bc4c8555d4d13922df9f13a611b76b99808b42 | /roots_of_functions/newton_raphson.sce | 5d710ce64f3f3442bfe806a426111a1ed2d8b304 | [] | no_license | bertolinocastro/topics-in-computational-physics | f464d7c449715ba9ed04094c0fca985cd0adfcb0 | 4b64f6cdbf3f13823bdd1d59e39db8c753c8f5fd | refs/heads/master | 2020-04-29T08:52:32.230156 | 2019-05-26T01:57:12 | 2019-05-26T01:57:12 | 176,002,283 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 389 | sce | newton_raphson.sce | function xl=newton_raphson(x0,f,df,e)
xl = x0 - f(x0)/df(x0)
while abs(f(xl)) > e
xl = xl - f(xl)/df(xl)
end
endfunction
function y=func(x)
y = -88.9*exp(-0.0472*x) + (17.3 + 0.527*x)
endfunction
function y=dfunc(x)
y = 0.527+4.19608*exp(-0.0472*x)
endfunction
xm = newton_raphson(0,func,dfunc,0.1)
x = linspace(-50,50)
plot(x,func(x),'b-')
plot(xm,func(xm),'ro')
|
105dc659beb3894609cde1aa96474d98d7bf7a15 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1631/CH5/EX5.1/Ex5_1.sce | 4cc72d1994d93915e752141f36a74567e510854b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 163 | sce | Ex5_1.sce | //Caption: Sampling Rate
//Example 5.1
//page no 220
//Find Sampling Rate
clear;
clc;
f1=4*10^3;
f2=4.5*10^3;
fsmin=2*f2;
disp("kHz",fsmin/1000,"Sampling rate");
|
cfe982ab73889378ebafd1a0fc61a83e169c379f | 449d555969bfd7befe906877abab098c6e63a0e8 | /761/CH18/EX18.8/18_8.sce | 12499f1625cd928bdf7c8880c46eb6cd8f64e51d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 444 | sce | 18_8.sce | clc;
// page no 683
// prob no 18.8
// refer ex 18.7
fb=40*10^6;// bit rate in bps
Pr_dBm=-62;//power at the receiver in dBm
Pr=10^(Pr_dBm/10)*10^-3;// power at the receiver in W
Eb=Pr/fb;// the energy per bit in J
k=1.38*10^-23;//Boltzmann constant
T=350;
// the noise power density is
No=k*T;
// Energy per bit to noise density ratio in dB is
Eb_No=10*log10(Eb/No);
disp('dB',Eb_No,'Energy per bit to noise density ratio is '); |
7ddb4209522f0bf186c863f0e19ebbffcbc64aba | 449d555969bfd7befe906877abab098c6e63a0e8 | /2471/CH3/EX3.3/Ex3_3.sce | 48c81812a97edad04e66406fe95596af1e331bae | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 293 | sce | Ex3_3.sce | clear ;
clc;
// Example 3.3
printf('Example 3.3\n\n');
//Page No. 59
// given
P = 60000;/// Principal Amount in Pound
i = 0.18;// Interest Rate
n = 10;//years
R = P*((i*(1+i)^n)/((1+i)^n -1));//Rate of Capital Recovery
printf('The annual investment required is %.1f Pound\n',R)
|
ccb9d50d4cdbdb4359aec0d0f9c8b4584bc70934 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2318/CH4/EX4.8/ex_4_8.sce | f6f44049040b2d489e972b7142da262a5485a526 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 336 | sce | ex_4_8.sce | //Example 4.8: design
clc;
clear;
close;
vab=1;//V
vr=2-vab;//V
i=50;//mA
R=vr/(i*10^-3);//ohm
R1=(vr/10)/(i*10^-3);//ohm
n=10;//
tr1=n*R1;//ohm
r2=2*R1;//
l=100;//cm
x=R1/l;//
disp(R,"resistance R is,(ohm)=")
disp(R1,"resistance R1 is,(ohm)=")
disp(r2,"resistance R2 is,(ohm)=")
disp(x,"resistance per cm of slide wire is ,(ohm/cm)=")
|
c1cfede2f9741862067225897f2f07f4932885e5 | c884d985cf07964dbaf65b3204ef1bebb38d4f23 | /gauss_p.sci | e2792f1f2495812a8b3a6b0c4cd0d5eec458156a | [] | no_license | mbgaspar/Computacao-cientifica | 710f99c81f2ae342c782584bae2fef666f78f76c | 8168c0bdcaa14cf9d2b57ba34e15fd0833e69ee3 | refs/heads/master | 2021-11-05T01:50:18.159560 | 2021-10-29T12:09:10 | 2021-10-29T12:09:10 | 220,349,256 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,961 | sci | gauss_p.sci | function x= gauss_p(A,b)//x=A\b para conferir resultado
//resolução de sistemas com fatoração LU com pivotamento parcial
// onde: x é o vetor solução
// A é a matriz de coeficientes
// b é o vetor coluna de estímulos
[m,n]=size(A); //dimensão da matriz que deve ser quadrada
if m~=n then
error("A matriz deve ser quadrada");
end
m = length(b);//comprimento de b
if m~=n then
error("Erro na dimensão do vetor b");
end
//1° passo: aumentar a matriz A
P = eye(n,n); //matriz de pivotamento
//Algoritmo de eliminação progressiva
for i=1:n-1 //i linha e j coluna
//PIVOTAMENTO PARCIAL
//i é linha
[maior,k]=max(abs(A(i:n,i)))//maior valor dos elementos da matriz
l = k+i-1;
if l~=i then
A([l,i],:)= A([i,l],:)//inverte as linhas
P([l,i],:)= P([i,l],:)//inverte as linhas
end
//---
for j=i+1:n
A(j,i) = A(j,i)/A(i,i); //multiplicador guardado onde fica 0
// for k =i+1:n //k=i+1 pois vai ser 0 em k=i
// A(j,k)= A(j,k)-A(i,k)*A(j,i);
//end
//ou FOR IMPLÍCITO-------
A(j,i+1:n)= A(j,i+1:n)-A(i,i+1:n)*A(j,i);
disp(A,'A');
disp(P,'P');
end
end
//algoritmo de substituição progressiva
b= P*b;
//d=zeros(n,1) para o for implicito
d(1)=b(1);
for i=2:n
//for j=1:i-1
//d(i)=d(i)-A(i,j)*d(j);
//end
d(i)= b(i)-A(i,1:i-1)*d(1:i-1);
end
disp(d,'d');
//substituição regressiva
x = zeros(n,1);
x(n)= d(n)/A(n,n);
for i= n-1:-1:1
//for j=i+1:n
// x(i)= x(i)+ A(i,j)*x(j);
//end
//Com FOR IMPLÍCITO
x(i)= (d(i)-A(i,i+1:n)*x(i+1:n))/A(i,i);
end
endfunction
|
13193a9aabd81e9ab546ca670f17d42e1217c984 | a62e0da056102916ac0fe63d8475e3c4114f86b1 | /set12/s_Industrial_Instrumentation_K._Krishnaswamy_And_S._Vijayachitra_1436.zip/Industrial_Instrumentation_K._Krishnaswamy_And_S._Vijayachitra_1436/CH1/EX1.4/ex1_4.sce | df3132704c05a2638a5e5977245d6297308d2972 | [] | no_license | hohiroki/Scilab_TBC | cb11e171e47a6cf15dad6594726c14443b23d512 | 98e421ab71b2e8be0c70d67cca3ecb53eeef1df6 | refs/heads/master | 2021-01-18T02:07:29.200029 | 2016-04-29T07:01:39 | 2016-04-29T07:01:39 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 175 | sce | ex1_4.sce | errcatch(-1,"stop");mode(2);// Example 1.4, page no-54
temp=2.022
millivolt_cor=37.325
op=millivolt_cor-temp
printf("Millivolt output available=% .3f",op)
exit();
|
46a10f7eaf36dd321bbe67c6fa82414d37fb6f45 | 34eeff5ed4909f3deb73c8f6b350b374d8e20e88 | /MDK-ARM/to1.uvguix.SCI | de6d11c7d42c0bef671f4d26147b90b026a357f6 | [] | no_license | lgh0322/car_stm_x44 | 226df5d581bbf97ad5364f1a5f14ba6949bf9386 | 9015506ac909737fe48d67453cfee348bad061ce | refs/heads/master | 2023-03-27T14:31:13.402346 | 2021-03-22T22:00:56 | 2021-03-22T22:00:56 | 350,501,960 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 92,050 | sci | to1.uvguix.SCI | <?xml version="1.0" encoding="UTF-8" standalone="no" ?>
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<OrigResetItems>
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</OrigResetItems>
</ToolBar>
<ControlBarsSummary>
<Bars>0</Bars>
<ScreenCX>1680</ScreenCX>
<ScreenCY>1050</ScreenCY>
</ControlBarsSummary>
</ViewEx>
</WinLayoutEx>
<MDIGroups>
<Orientation>1</Orientation>
<ActiveMDIGroup>0</ActiveMDIGroup>
<MDIGroup>
<Size>100</Size>
<ActiveTab>2</ActiveTab>
<Doc>
<Name>../Src/usart.c</Name>
<ColumnNumber>0</ColumnNumber>
<TopLine>1</TopLine>
<CurrentLine>1</CurrentLine>
<Folding>1</Folding>
<ContractedFolders></ContractedFolders>
<PaneID>0</PaneID>
</Doc>
<Doc>
<Name>../Src/tim.c</Name>
<ColumnNumber>60</ColumnNumber>
<TopLine>367</TopLine>
<CurrentLine>386</CurrentLine>
<Folding>1</Folding>
<ContractedFolders></ContractedFolders>
<PaneID>0</PaneID>
</Doc>
<Doc>
<Name>../Src/main.c</Name>
<ColumnNumber>21</ColumnNumber>
<TopLine>63</TopLine>
<CurrentLine>92</CurrentLine>
<Folding>1</Folding>
<ContractedFolders></ContractedFolders>
<PaneID>0</PaneID>
</Doc>
<Doc>
<Name>../Src/gpio.c</Name>
<ColumnNumber>0</ColumnNumber>
<TopLine>18</TopLine>
<CurrentLine>41</CurrentLine>
<Folding>1</Folding>
<ContractedFolders></ContractedFolders>
<PaneID>0</PaneID>
</Doc>
</MDIGroup>
</MDIGroups>
</ProjectGui>
|
568d6c1c92f6d571956cc38d82060aabb225942e | 449d555969bfd7befe906877abab098c6e63a0e8 | /1853/CH4/EX4.37/Ex4_37.sce | 7ecd3c43ca7aea975c90f05e7a2ef80b41cf63ff | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 589 | sce | Ex4_37.sce |
//determine the current also power nd power factor
V=200+%i*0
f=50
R1=30
L1=0.2
C1=10e-6
X1=2*%pi*f*L1
Z1=R1+%i*X1
R2=40
L2=0.12
X2=2*%pi*f*L2
Z2=R2+%i*X2
Z=(Z1*Z2)/(Z1+Z2)
I=V/Z
R=18.858//calculatimg Z and I we get R and Z,I
Z=31.06
coso=R/Z
I=6.44
P=I^2*R
I1=(I*Z1)/(Z1+Z2)
I2=(I*Z1)/(Z1+Z2)
coso1=R1/Z1
P1=I1^2*R1
coso2=R2/Z2
P2=(I2)^2*R2
disp('P2 ='+string(P2)+ 'watt' ,'P1 ='+string(P1)+ 'watt ' , 'Total power factr='+string(coso)+'' , 'Total power='+string(P)+'watt' , 'total current ='+string(I)+'amps' , 'total impedance='+string(Z)+'ohms' )
|
0adc501a0a73666bbfdaf3d886e6a7b02808498a | 4e3ee9b02c529c892b54b0f6cfbc8e8454741439 | /projects/02/Or16WaY.tst | a8e40eb43954e652387c6d177185f5014ced7b46 | [] | no_license | Metaphor-pump/ecs | 5c353ce6c7fdbb4306d0581864c82f975c39440f | 74d472ef7ccff34c179380db56fabfc31fc099b8 | refs/heads/master | 2021-01-19T18:32:30.973439 | 2017-08-09T09:57:02 | 2017-08-09T09:57:02 | 73,225,947 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 287 | tst | Or16WaY.tst | load Or16Way.hdl,
output-file Or16Way.out,
output-list in%B2.16.2 out%B2.1.2;
set in %B0000000000000000,
eval,
output;
set in %B1111111111111111,
eval,
output;
set in %B1000000000000000,
eval,
output;
set in %B0000000100000001,
eval,
output;
set in %B0010011000100110,
eval,
output; |
88950f13d501a73f44d9a460b8c1651e915e4aa1 | daa5574081d4c7f04bf8db4a39ee6f79d5da55b8 | /MMN/MMN.sce | 505c0dbb1868c62e897f3958f0bf422fa668a81b | [] | no_license | smasa1112/presentation_practice | fec8a78d3c3c7260d1815174169ff47b1a5a3527 | 599664d4fae6783c52c46d7cb540bbcf35a12b27 | refs/heads/main | 2023-07-18T22:46:30.056399 | 2021-09-23T05:39:07 | 2021-09-23T05:39:07 | 405,818,206 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,971 | sce | MMN.sce | ## default settings------------------------------------------------
scenario = "MMN"; # scenario name
no_logfile = false; # true -> do not make presentation log
scenario_type = trials; # normal
default_font_size = 50; # font size(pt)
default_text_color = 255, 255, 255; # font color R, G, B (0~255)
default_background_color = 0,0,0; # background color R, G, B (0~255)
write_codes = true;
## scenario settings------------------------------------------------
begin;
array{
sound{ wavefile{ filename="9kHz.wav"; preload = false;};}snd1;
sound{ wavefile{ filename="12kHz.wav"; preload = false;};}snd2;
}snd_ary;
sound{ wavefile{filename="no_sound.wav";};}ns;
#to stimulus
trial{
stimulus_event{
sound snd1;
code = "stim";
}pres_evt;
}pres_trl;
#reset用
#-pcl------------------------------------------------
begin_pcl;
int i; # 単純なカウンター
int j;
double t;
preset int standard_tone = 1;
#出現トレイン数
int max = 12000;
int devient = max / 20; # 5%
double ISI = 500.0; #ms 0.5s
array<int> sd[2];
if (standard_tone < 1 || 2 < standard_tone) then
standard_tone = 1;
end;
if(standard_tone == 1)then
sd[1] = 1;
sd[2] = 2;
else
sd[1] = 2;
sd[2] = 1;
end;
#ならし運転
ns.get_wavefile().load(); # メモリーに展開
ns.present();
#音声の準備
snd1.get_wavefile().load(); # メモリーに展開
snd2.get_wavefile().load(); # メモリーに展開
system_keyboard.set_log_keypresses(true);
system_keyboard.get_input();
#刺激開始
t = clock.time_double() + 100;
loop until
t < clock.time_double()
begin end;
ns.present();
t = t + 100.0;
loop
i = 1;
j = 1;
until
i > max
begin
loop until
t < clock.time_double()
begin end;
if(j < 20) then
snd_ary[sd[1]].present();
j = j + 1;
else
snd_ary[sd[2]].present();
j = 1;
end;
t = t + ISI;
i = i + 1;
end;
snd1.get_wavefile().unload();
snd2.get_wavefile().unload();
ns.get_wavefile().unload();
|
f66edded9c3e23a1bce61b28e7193c6506c55810 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2969/CH7/EX7.5/Ex7_5.sce | d7813619d80418d712bd8fb3278fc9d8ff802520 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 920 | sce | Ex7_5.sce | clc
clear
//DATA GIVEN
D=0.3; //bore of engine cylinder in m
L=0.45; //stroke length in m
N=300; //engine speed in R.P.M.
Pmi=6; //mean effective pressure in bar
NBL=1.5; //Net brake load (W-S) in kN
Db=1.8; //diameter of brake drum
d=0.02; //brake rope diameter
n=1; //no. of cylinders
k=0.5; //for 4-stroke cylinder
//INDICTED POWER ,I.P.=(n*PMI*l*A*N*k*10)/6 kW
A=(%pi/4)*(D^2);
IP=(n*Pmi*L*A*N*k*10)/6;
BP=NBL*(%pi)*(Db+d)*N/(60);
eta=BP/IP; //mechanical efficiency
printf(' (i) The Indicted Power, I.P. is: %5.2f kW. \n',IP);
printf(' (ii) The Brake Power, B.P. is: %5.2f kW. \n',BP);
printf('(iii) Mechanical efficiency is: %5.4f or %5.2f percent.\n',eta,(eta*100));
|
fcb6b3caca8028cfc91c611485f5332a92b25b67 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1529/CH16/EX16.2/16_02.sce | eed1784f2e18496306a3756da2d085a6850fc6fe | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,016 | sce | 16_02.sce | //Chapter 16, Problem 2
clc;
V=240; //voltage
R=80; //resistance in ohm
f=50; //frequency in hertz
C=30e-6; //capacitance in farad
Ir=V/R; //current flowing in the resistor
Xc=1/(2*%pi*f*C); //capacitive reactance
Ic=V/Xc; //current flowing in the capacitor
I=sqrt(Ir^2+Ic^2); //supply current
phi=atan(Ic/Ir);
Z=V/I; //impedance
P=V*I*cos(phi); //power consumed
S=V*I; //apparent power,
printf("(a) Current flowing in the resistor = %d A\n\tCurrent flowing in the capacitor = %.3f A\n\n",Ir,Ic);
printf("(b) Supply current = %.3f A\n\n",I);
printf("(c) Circuit phase angle = %.2f deg (leading)\n\n",phi*(180/%pi));
printf("(d) Circuit impedance = %.2f ohm\n\n",Z);
printf("(e) Power consumed = %d W\n\n",P);
printf("(f) Apparent power = %.1f VA",S);
|
5beef6b4314d1a06e51226ffcf95e7e57dd29849 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1385/CH16/EX16.1/16_1.sce | d688d39cae6bdc5514dc59b28f79c641abf1b649 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 388 | sce | 16_1.sce | clc
//initialisation of variables
x= 0.02 //m
y= 0.4 //m
R= 0.0592
e= -0.771 //V
e1= -1.520 //v
n= 5 //electrons
z= 0.80 //m
z1= 0.5 //m
//CALCULATIONS
E= e-R*log10(x/y)
E1= e1-(R/n)*log10(z1*z^8/x)
E2= E-E1
//RESULTS
printf (' Redox potential of sample= %.3f v',E)
printf (' \n Redox potential of sample= %.3f v',E1)
printf (' \n Redox potential of sample= %.3f v',E2)
|
6c75c8ff7fed0ee6b5d06ba943d02408ce4c28f1 | 449d555969bfd7befe906877abab098c6e63a0e8 | /779/CH15/EX15.7/15_7.sce | d6726bf761301fc2022e18f7d6f70cfc01f23ec5 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 380 | sce | 15_7.sce | h1 = 57; h2 = h1;
h3 = 42;
W1 = 0.0065; W2 = 0.0088; W3 = W2;
t2 = 34.5; v1 = 0.896;
n = 1500; // seating capacity of hall
a = 0.3; // amount of out door air suplied
G = (n*a)/0.896 ; // Amount of dry air suplied
CC = (G*(h2-h3)*60)/14000; // in tonns
R = G*(W2-W1)*60;
disp("tonnes",CC,"Capacity of the cooling coil in tonnes")
disp("kg/h",R,"Capacity of humidifier")
|
e4886ab1ec155a2f05e324fb6978a5ee033340b4 | da5b40d917ec2982828bd9bdf06b18b7bf189f26 | /sim/scripts/ejector.tst | 69d011cf4dfccd6f445dd8f0656c2a9973fb5b21 | [] | no_license | psy007/NNPC-CHEMICAL-SIM- | 4bddfc1012e0bc60c5ec6307149174bcd04398f9 | 8fb4c90180dc96be66f7ca05a30e59a8735fc072 | refs/heads/master | 2020-04-12T15:37:04.174834 | 2019-02-06T10:10:20 | 2019-02-06T10:10:20 | 162,587,144 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 900 | tst | ejector.tst | units PureSI
$th = VirtualMaterials.Peng-Robinson
/ -> $th
th + WATER
ejector = Ejector.EjectorOp()
cd /ejector.Process
P = 20270.58558 Pa
T = 333.3333336 K
Fraction = 1.0
MoleFlow = 4.5359244127 kgmole/h
cd /ejector.Motive
P = 689475.7 Pa
T = 333.3333336 K
Fraction = 1.0
MoleFlow = 45.359244127 kgmole/h
cd /ejector.Discharge
#P = 81107.4142866 Pa
#T = 333.3333354 K
#Fraction = 1.0
#MoleFlow = 49.8951685397 kgmole/h
cd /
ejector.NozzleDiameter = 0.48639
ejector.ThroatDiameter = 1.613175
ejector.Process
ejector.Motive
ejector.Discharge
ejector.NozzleDiameter
ejector.ThroatDiameter
ejector.NozzleDiameter = None
ejector.Discharge.P = 81107.2733997
ejector.Process
ejector.Motive
ejector.Discharge
ejector.NozzleDiameter
ejector.ThroatDiameter
copy /ejector
paste /
ejectorClone.Process
ejectorClone.Motive
ejectorClone.Discharge
ejectorClone.NozzleDiameter
ejectorClone.ThroatDiameter |
aa8484094002f551bdaa22d4bc48c5b9ecef45be | 449d555969bfd7befe906877abab098c6e63a0e8 | /3754/CH14/EX14.3/14_3.sce | 117bbd8c0687e7f86cd2501348027cc2125b68a3 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 367 | sce | 14_3.sce | clear//
//Variables
alpha = 0.967 //common base current gain
IE = 10 //Emitter current (in milli-Ampere)
//Calculation
IC = alpha * IE //Collector current (in milli-Ampere)
IB = IE - IC //Base current (in milli-Ampere)
//Result
printf("\n Base current is %0.3f mA." ,IB)
|
373e193206ad56d8d9419c1320062fb21e08e0af | c6bf685755436b2a7bf289ac90bec98340fe97fe | /APLICACAO_MATRIZ.sce | 2cfafd5a9f9eb3390e6173892354c5ad921dc854 | [] | no_license | ivybin/PROGRAMAS-SCE | 82296ac10f4fb02d6e283f64e910666c6103063a | e61918ceae020bd33fcf223908f7decdec1c41b4 | refs/heads/master | 2023-07-23T12:55:08.711868 | 2021-09-02T17:22:23 | 2021-09-02T17:22:23 | 400,595,765 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 794 | sce | APLICACAO_MATRIZ.sce | /*código que gere três matrizes aleatórias - A, B e C
de dimensão 11x11
E compute os seguintes valores:
a) O somatório dos elementos da diagonal principal.
b) O somatório dos elementos das colunas pares.
c) O somatório dos elementos das colunas ímpares.
d) O logaritmo natural dos resultados dos items a), b) e c).*/
clear;
clc;
A= 10*rand(11,11);
B= 10*rand(11,11);
C= 10*rand(11,11);
M=0;U=0;U2=0;
for i=1:1:11
M=M+A(i,i)+B(i,i)+C(i,i);
end
disp(M);
//B)
for T=2:2:10
for K=1:1:11
U=U+A(K,T)+B(K,T)+C(K,T);
end
end
disp(U);
//C)
for T2=1:2:11
for K2=1:1:11
U2=U2+A(K2,T2)+B(K2,T2)+C(K2,T2);
end
end
disp(U2);
//D)
DT= [log(M);log(U);log(U2)];
disp("OS LOGARITMOS NATURAIS DOS ITENS A B E C SE APRESENTAM DE FORMA RESPECTIVA",DT);
|
3dd44b9de68ad894547ae3c36a7b5113e27660ba | e806e966b06a53388fb300d89534354b222c2cad | /macros/cvtColor.sci | e112154f9adef0025beda2ca54c9ea02428e2443 | [] | no_license | gursimarsingh/FOSSEE_Image_Processing_Toolbox | 76c9d524193ade302c48efe11936fe640f4de200 | a6df67e8bcd5159cde27556f4f6a315f8dc2215f | refs/heads/master | 2021-01-22T02:08:45.870957 | 2017-01-15T21:26:17 | 2017-01-15T21:26:17 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 339 | sci | cvtColor.sci | function new_image = cvtColor(image, code, varargin)
[ lhs, rhs ] = argn(0)
image_list = mattolist(image)
select rhs
case 2 then
out = opencv_cvtColor(image_list, code)
case 3 then
out = opencv_cvtColor(image_list, code, varargin(1))
end
sz = size(out)
for i=1:sz
new_image(:, :, i) = out(i)
end
endfunction
|
c721e1e63f2b543d69fa9d77e63db3ac0e88c983 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2681/CH4/EX4.3/Ex4_3.sce | 5ddddda106567c5afef1c5c511b7e4e25904de15 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 203 | sce | Ex4_3.sce | //voltage standing wave ratio
//given
clc
LEMg=4.82//cm
d1_d2=0.7//cm
VSWR=LEMg/(%pi*d1_d2)//VSWR
VSWR=round(VSWR*1000)/1000///rounding off decimals
disp(VSWR,'the voltage standing wave ratio:')
|
0f873f4762d3230333a385aee2888a99f5b434f3 | 5bd32b0243dbcb7551e03872f901a42713dfa199 | /Mario_v8.sce | ec7f53a3e596a6c397a1785c9bb6ef185797fad5 | [
"MIT"
] | permissive | cvdhengel/MarioCards | da0dc732d11631eeaee215b82dbbd5fa45398f8c | 7ab6013dbbc2e0f36f482467845df961d5d7616f | refs/heads/master | 2021-01-23T00:48:31.597526 | 2017-05-31T18:52:29 | 2017-05-31T18:52:29 | 92,846,680 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 5,946 | sce | Mario_v8.sce | #Headers
active_buttons=5;
default_background_color= 255,255,255;
default_text_color=0,0,0;
default_font="calibri";
#SDL
begin;
TEMPLATE "Bitmaps.tem";
TEMPLATE "Trials.tem";
#PCL
begin_pcl;
#include "MarioPCL.pcl"#
#Response data & output
response_data Rdata;
output_file output = new output_file;
string ParticipantNumber = logfile.subject();
if ParticipantNumber.count() > 0 then output.open (ParticipantNumber + "_MarioCards.txt");
else output.open( "999_MarioCards.txt"); end;
output.print( "date/time: " + date_time("dd mmmm yyyy' 't")+"\n");
output.print("Trial\tStimuli\tPrincple\tButton\tSorting\tFeedback\tErrortype\n");
#include "Start.pcl";
#Show introduction
#intro.present();
#Sorting: 1=form, 2=color, 3=amount
array <int> sort[6]={1,2,3,1,2,3};
#Main Trial Start
stimuli.shuffle();
#sort.shuffle();
stimulus_data laststim = stimulus_manager.last_stimulus_data();
int c=0; #correct
int f=0; #false
int tc=0; #total correct
int tf=0; #total incorrect
int p=0; #perseveration
int np=0; #nonperseveration
#Main Trial Loop
loop int i=1 until i > stimuli.count() begin;
loop int s=1 until s > sort.count() begin;
VB.set_part(5, stimuli[i]);
MainEvent.set_event_code(stimuli[i].description());
MainTrial.set_duration(forever);
MainTrial.set_type( first_response );
MainTrial.present();
output.print(i);
output.print("\t");
output.print(stimuli[i].description());
output.print("\t");
response_data respdat = response_manager.last_response_data();
int BP = respdat.button();
output.print(BP);
output.print("\t");
#Matching the cards on the screen
if BP == 1 then VB.set_part_x(5,-700); VB.set_part_y(5, 0); end;
if BP == 2 then VB.set_part_x(5,-250); VB.set_part_y(5, 0); end;
if BP == 3 then VB.set_part_x(5,250); VB.set_part_y(5, 0); end;
if BP == 4 then VB.set_part_x(5,700); VB.set_part_y(5, 0); end;
MainTrial.set_duration(1000);
MainTrial.present();
#Putting it back for the next trial
VB.set_part_x(5,0);
VB.set_part_y(5, -300);
#Showing Feedback
if sort[s]==1 then output.print("charac"); output.print("\t");
if (stimuli[i].description().find("M") == 1 && BP == 1)
|| (stimuli[i].description().find("S") == 1 && BP == 2)
|| (stimuli[i].description().find("L") == 1 && BP == 3)
|| (stimuli[i].description().find("P") == 1 && BP == 4)
then
feedbackcorrect.present();
output.print("correct");
output.print("\t");
c=c+1;
f=0;
tc=tc+1;
else
feedbackwrong.present();
output.print("incorrect");
output.print("\t");
if (stimuli[i].description().find("1") > 0 && BP == 1)
|| (stimuli[i].description().find("2") > 0 && BP == 2)
|| (stimuli[i].description().find("3") > 0 && BP == 3)
|| (stimuli[i].description().find("4") > 0 && BP == 4)
then p=p+1;
output.print("P");
output.print("\t");
else np=np+1;
output.print("NP");
output.print("\t");
end;
f=f+1;
c=0;
tf=tf+1;
end;
end;
if sort[s]==2 then
output.print("color");
output.print("\t");
if (stimuli[i].description().find("R") == 2 && BP == 1)
|| (stimuli[i].description().find("G") == 2 && BP == 2)
|| (stimuli[i].description().find("B") == 2 && BP == 3)
|| (stimuli[i].description().find("V") == 2 && BP == 4)
then
feedbackcorrect.present();
output.print("correct");
output.print("\t");
c=c+1;
f=0;
tc=tc+1;
else
feedbackwrong.present();
output.print("incorrect");
output.print("\t");
if (stimuli[i].description().find("M") == 1 && BP == 1)
|| (stimuli[i].description().find("S") == 1 && BP == 2)
|| (stimuli[i].description().find("L") == 1 && BP == 3)
|| (stimuli[i].description().find("P") == 1 && BP == 4)
then p=p+1;
output.print("P");
output.print("\t");
else np=np+1;
output.print("NP");
output.print("\t");
end;
f=f+1;
c=0;
tf=tf+1;
end;
end;
if sort[s]==3 then
output.print("amount");
output.print("\t");
if (stimuli[i].description().find("1") > 0 && BP == 1)
|| (stimuli[i].description().find("2") > 0 && BP == 2)
|| (stimuli[i].description().find("3") > 0 && BP == 3)
|| (stimuli[i].description().find("4") > 0 && BP == 4)
then
feedbackcorrect.present();
output.print("correct");
output.print("\t");
c=c+1;
f=0;
tc=tc+1;
else
feedbackwrong.present();
output.print("incorrect");
output.print("\t");
if (stimuli[i].description().find("R") == 2 && BP == 1)
|| (stimuli[i].description().find("G") == 2 && BP == 2)
|| (stimuli[i].description().find("B") == 2 && BP == 3)
|| (stimuli[i].description().find("P") == 2 && BP == 4)
then p=p+1;
output.print("P");
output.print("\t");
else np=np+1;
output.print("NP");
output.print("\t");
end;
f=f+1;
c=0;
tf=tf+1;
end;
end;
##########################################
#Knowing when to continue or when to end #
##########################################
if c>5 then s=s+1; c=0; end; #If 6 cards (in a row) were correct, the participant continues to the next sorting principle without letting know
if f>5 then s=sort.count(); i=stimuli.count(); end; #If participant misses 6 in a row, the task will end.
if tc>2 then s=sort.count(); i=stimuli.count(); end; #If all cards are sorted, the task will end.
end;
i=i+1;
end;
EndTrial.present();
output.print("\n\n\Total Correct\tTotalFalse\tTotalP\tTotalNP\n");
output.print(tc);
output.print("\t");
output.print(tf);
output.print("\t");
output.print(p);
output.print("\t");
output.print(np);
output.print("\t");
|
89531e4d8e5d893cc2938473783e8ae52d4553a8 | 6a0f57db22a8a4bab5b7529033be777f3251f439 | /interpolation.sce | 3b933ebf5fbc9591d74375ea915b0a6785908c4f | [] | no_license | john27328/heat_lens | c9a55157a325f9ca7896dd872a39a70cf5473b0d | d2a4e84b38baf89e006ee053b830ef6e7fa056ad | refs/heads/master | 2020-04-19T22:54:59.017807 | 2019-03-08T19:20:57 | 2019-03-08T19:20:57 | 168,483,057 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 737 | sce | interpolation.sce | //
// 1. Create the spline
//nx = 7;
//ny = 15;
//data = read("/media/D/Qt/teplovay linza/saveFile.csv", -1, 40);
//y = linspace(%pi/2,4*%pi,ny);
//z = cos(x')*cos(y);
//C = splin2d(x, y, z, "periodic");
//
// 2. Evaluate the spline on a grid
//mx = 50;
//my = 20;
//xx = linspace(%pi,1.5*%pi,mx);
//yy = linspace(%pi,2*%pi,my);
//[XX,YY] = ndgrid(xx,yy);
//zz = interp2d(XX,YY, x, y, C);
//
// 3. Plot the interpolated values
//scf();
//plot3d(xx, yy, zz)
z = read("/media/D/Qt/teplovay linza/saveFile.csv", -1, 40)-300;
y = linspace(0,4,40);
x = linspace(0,20,200);
C = splin2d(x, y, z, "not_a_knot");
yy = linspace(0,4,400);
xx = linspace(0,20,200);
[XX,YY] = ndgrid(xx,yy);
zz = interp2d(XX,YY, x, y, C);
scf();
plot3d(xx, yy, zz)
|
c345ce1c5a02b3f21b9a057712e9b8c2a51e82ef | 449d555969bfd7befe906877abab098c6e63a0e8 | /1853/CH4/EX4.16/Ex4_16.sce | 886c66a5b655826a78ab55e0a83525c63e2ef5d1 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 210 | sce | Ex4_16.sce |
//detrmine the value of inductance
I=5;//amp
V=200;//volt
f=50;//hertz
X=V/I;
L=40/(2*%pi*50);
disp('the value of inductive.reactance='+string (X)+'ohms' , 'value of inductors='+string(L)+'henry');
|
bacb8124b7f9dd62591b047aad5d95b39b680381 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1571/CH3/EX3.10/Chapter3_Example10.sce | 993b0e8b19629a4bb337fc1d5d7014c1207b45f2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 497 | sce | Chapter3_Example10.sce | clc
clear
//INPUT DATA
cp=0.03;//specific heat of lead in kj/kg.k
v=10000;//initial velocity of bullet in cm/sec
J=4.2*10^7;//joules constant in ergs/cal
//CALCULATIONS
//let mass of the bullet in gm
ke=(v^2)/2;//kinetic energy of the bullet per unit mass in (cm/sec)^2
//T is the rise in temperature,then heat produced is m*cp*T
//95% of kinetic energy is converted to heat
T=ke*95/(cp*J*100);//rise in temperature in deg.C
mprintf('the rise in temperature is %3.1f deg.C',T)
|
509c385e9e67589388985b747a5d280b3a991c2c | 8217f7986187902617ad1bf89cb789618a90dd0a | /source/2.2/macros/metanet/plot_graph.sci | e2d0eac6547e5cbdb6cef8e3a815e2aa9df407aa | [
"MIT",
"LicenseRef-scancode-warranty-disclaimer",
"LicenseRef-scancode-public-domain"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 1,606 | sci | plot_graph.sci | function []=plot_graph(g,orx,ory,w,h)
//This function plot a graph in the Scilab graphic window
//It uses the data of the list defining the graph
[lhs,rhs]=argn(0)
// g
check_graph(g)
n=g('node_number');
ma=g('edge_number');
xnodes=g('node_x');ynodes=g('node_y');
if (xnodes==[]|ynodes==[]) then
error('plot_graph: coordinates of nodes needed for plotting');
return
end
diam=g('default_node_diam'); if diam==[] then diam=20;end;
nodediam=g('node_diam');if nodediam==[] then nodediam=zeros(1,n);end;
ii=find(nodediam==0);nodediam(ii)=diam*ones(ii);ray=0.5*nodediam;
if rhs==1 then
lim=max(nodediam);
ah=min(xnodes);bh=max(xnodes);
av=min(-ynodes);bv=max(-ynodes);
enx=bh-ah;enx=max(enx,5.*lim);
eny=bv-av;eny=max(eny,5.*lim);
orx=ah+0.09*enx;w=0.82*enx;
ory=av+0.05*eny;h=0.9*eny;
else
if rhs<>5 then error(39), end
end
xsetech([0,0,1.0,1.0],[orx,ory,orx+w,ory+h]);
isoview(orx,orx+w,ory,ory+h);
nodecolor=nodediam
nodeborder=0*ones(1,n)
nodefontsize=23040.*ones(1,n);
metarc=[xnodes-ray;-ynodes+ray;nodecolor;nodediam;nodeborder;nodefontsize];
xset('use color',1);
ncolor=g('node_color')
if ncolor=[] then ncolor=0*ones(1,n);end;
xarcs(metarc,ncolor-1);vtail=g('tail');vhead=g('head');
nxx=0*ones(2,ma);nyy=nxx;
nxx(1,:)=xnodes(vtail);
nxx(2,:)=xnodes(vhead);
nyy(1,:)=-ynodes(vtail);
nyy(2,:)=-ynodes(vhead);
txx=0*ones(2,ma);tyy=txx;
txx(1,:)=xnodes(vtail);
txx(2,:)=xnodes(vhead);
tyy(1,:)=-ynodes(vtail);
tyy(2,:)=-ynodes(vhead);
edgecolor=g('edge_color');if edgecolor==[] then edgecolor=ones(1,ma);end;
ii=find(edgecolor==0);edgecolor(ii)=ones(ii);
xpolys(txx,tyy,-edgecolor);
|
55f967c8c467d66310af9861e7033dd4ac5e45fe | 717ddeb7e700373742c617a95e25a2376565112c | /2474/CH13/EX13.2/Ch13Ex02.sce | a79317f61bc7f2fcac1733e5f083222e74975be5 | [] | no_license | appucrossroads/Scilab-TBC-Uploads | b7ce9a8665d6253926fa8cc0989cda3c0db8e63d | 1d1c6f68fe7afb15ea12fd38492ec171491f8ce7 | refs/heads/master | 2021-01-22T04:15:15.512674 | 2017-09-19T11:51:56 | 2017-09-19T11:51:56 | 92,444,732 | 0 | 0 | null | 2017-05-25T21:09:20 | 2017-05-25T21:09:19 | null | UTF-8 | Scilab | false | false | 1,364 | sce | Ch13Ex02.sce | // Scilab code Ex13.2: Pg.624 (2008)
clc; clear;
// Calculation of pressure at the centre of Sun
M = 1.99e+30; // Mass of Sun, kg
R = 6.96e+08; // Solar radius, m
G = 6.67e-011; // Gravitational constant, N-m^2/kg^2
mu = M/R^2; // Mass per unit surface area of Sun, kg/m^2
g = 0.5*G*(M/R^2); // Acceleration due to gravity in the Sun, m/s^2
P_c = mu*g; // Pressure at the center of the Sun, N/m^2
printf("\nThe pressure at the center of the sun = %1.0e N/m^2", P_c);
// Calculation of pressure inside the H-atom
k = 9e+09; // Coulomb's cnstant, N-m^2/C^2
e = 1.6e-19; // Charge iside the atom, C
a_o = 0.5e-10; // Bohr's radius for H-atom, m
A = 4*%pi*a_o^2; // Surface area of Sun, m^2
F = (k*e^2)/a_o^2; // Coulomb's force of attraction, N
P = F/A; // Pressure inside the H-atom, N/m^2
printf("\nThe pressure inside the H-atom = %3.1e N/m^2",P);
printf("\nSince the pressure at the centre of the sun is %3.1e times greater than that of the pressure inside the H-atom so it is unlikely to exist in its interior.", P_c/P);
// Result
// he pressure at the center of the sun = 6e+014 N/m^2
// The pressure inside the H-atom = 2.9e+012 N/m^2
// Since the pressure at the centre of the sun is 1.9e+002 times greater than that of the pressure inside the H-atom so it is unlikely to exist in its interior. |
916e0f4ba673723ef45bd970f0a95bf1743de72c | 449d555969bfd7befe906877abab098c6e63a0e8 | /1052/CH19/EX19.2/192.sce | 72818b8da2d408c4413a5870963f4eeab69490d7 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 733 | sce | 192.sce | clc;
//Example 19.2
//page no 250
printf("Example 19.2 page no 250\n\n");
//pitot tube is located at the center line of a horizontal pipe transporting air
rho=0.075//density of gas ,lb/ft^2
h=0.0166667//height difference,ft
g=32.2//gravitational acc. lb/ft^2
rho_m=62.4//density of medium which is air
v=sqrt(2*g*h*(rho_m-rho)/rho)//velocity
printf("\n velocity v=%f ft/s",v);
v_max=v//because at that point where the reading was taken is the centerline
printf("\n maximum veocity v_max=%f ft/s",v_max);
//since the flowing fluid is air at a high velocity the flow has a high probability of being turbilent .from chapter 14,assume
//v_av/v_max=0.815
v_av=v_max*0.815
printf("\n average velocity v_av=%f ft/s",v_av);
|
c660c930f911fb75dc82c5595bcfccbbef34ac1c | a62e0da056102916ac0fe63d8475e3c4114f86b1 | /set7/s_Electronics_Devices_And_Circuits_D._A._Bell_1514.zip/Electronics_Devices_And_Circuits_D._A._Bell_1514/CH14/EX14.4/14_4.sce | 5d0b7079e159c25c3ea31feb8c47612b0fd73365 | [] | no_license | hohiroki/Scilab_TBC | cb11e171e47a6cf15dad6594726c14443b23d512 | 98e421ab71b2e8be0c70d67cca3ecb53eeef1df6 | refs/heads/master | 2021-01-18T02:07:29.200029 | 2016-04-29T07:01:39 | 2016-04-29T07:01:39 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 171 | sce | 14_4.sce | errcatch(-1,"stop");mode(2);//chapter 14
//example 14.4
//page 441
all;
;
//given
Av=1;//voltage follower
printf("\nc1=500 pF\nc2=2000 pF\nc3=1000 pF")
exit();
|
6c9b95d0210531a9b752ed069eae4750daa7a299 | 5b45d3cab3903ca33bca192b4b4a2f0ecad71450 | /buttontest.sci | 71ea4e04ee26de8c2ee55c48caf718bb0d9ec77b | [] | no_license | sureshnarayan/Scilab | 95a42dc9bbd59b51941041980db5b58760ae0a47 | 207d2b0ea684505eb3b59a438051ddd2854d4328 | refs/heads/master | 2016-08-08T14:29:38.423391 | 2015-07-02T17:33:33 | 2015-07-02T17:33:33 | 38,413,025 | 0 | 3 | null | null | null | null | UTF-8 | Scilab | false | false | 361 | sci | buttontest.sci | COMPORT=8;
// mount library on handle "1"
h=slMount();
// handle "1": check availability of specified COM port
slCheck(h,COMPORT);
// handle "1": configure port
slConfig(h,9600,8,0,1);
// handle "1": open port
slOpen(h,COMPORT);
while(1)
tune=input(" ");
if tune==0 then
break;
else
slSendByte(h,48+tune);
end
end
slClose(h);
|
abe9a86c1cb568a2817321c098ad6a214030089a | 449d555969bfd7befe906877abab098c6e63a0e8 | /2699/CH13/EX13.6/Ex13_6.sce | a9f2adcd59e1a39c9f21a388cffe680679e32cd9 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 187 | sce | Ex13_6.sce | //EX13_6 PG-13.5
clc
clear
disp("decimal from 0 to 9 in radix 5 ")
for i=0:1:9;
a=i/5;
b=modulo(i,5);
printf(" %d=%d%d\n",i,a,b);//conversion from decimal to radix 5
end
|
33a5de0bd7469b3bc289f24dc3de721659f235a4 | 449d555969bfd7befe906877abab098c6e63a0e8 | /181/CH6/EX6.8/example6_8.sce | fbd11f6275f6ca281acd29664488f91ab02819c7 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 730 | sce | example6_8.sce | // Determine R,Ids,Vgs
// Determine Vgs,Id,Vds,operating region
// Basic Electronics
// By Debashis De
// First Edition, 2010
// Dorling Kindersley Pvt. Ltd. India
// Example 6-8 in page 277
clear; clc; close;
// Given data
Vp=-3; // Peak voltage in V
Vgg=5; // Gate voltage in V
Ids=10*10^-3; // Drain current in mA
// Calculation
R=5/(10*10^-3);
printf("(a)R = %0.0f ohm\n",R);
Ids=5/400;
Vds=(2*Ids*R)+15;
printf("(b)Idss = %0.2e A\n",Ids);
printf("(c)Vds = %0.0f V\n",Vds);
printf("This confirms active region\n");
Rid=14/2;
Vgs=Vgg-Rid;
printf("(d)Vgs = %0.0f V\n",Vgs);
printf("Vds=2>Vgs-Vp=-1.5+3=1.5 -> Active region");
// Result
// (a) R = 500ohm,
// (b) Ids = 12.5mA,
// (c) Vgs = -2V |
e15a08c243e457522d2d227f6f5ee682b86fd381 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1088/CH2/EX2.2/Example2.sce | 95ba75114949f14db61619984f7b2d2f0bd24f23 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 2,378 | sce | Example2.sce | //Program for example 2 chapter 2
clear
clc
disp("Example 2: Display the type of a given variable or a command ")
disp('')
printf("\n*******************************************************************\n")
disp("Answer :")
printf("THE FOLLOWING LINES OF CODE RUN \nONLY IN SCILAB INSTALLED IN UNIX ENVIRONMENT.....")
printf("\nTHE CONSOLE GIVES DIFFERENT \nOUTPUT IN OTHER OPERATING SYSTEMS")
if(getos() ~= "Linux" )then
ctd=input("Enter the command or variable whose type is to be determined ")
clc(1)
pt = input("Enter the command again to confirm ","s")
clc(1)
printf("Continue?....\ny :Yes\nAny other key:No")
st = input('','s')
clc(2)
if( st ~= "y") then
exit
else
n=type(ctd)
clc(1)
printf("%s is a ",pt)
select n
case 1 then
printf("a real or complex matrix of double.")
case 2 then
printf('a polynomial matrix.')
case 4 then
printf('a boolean matrix.')
case 5 then
printf('a sparse matrix.')
case 6 then
printf('a sparse boolean matrix.')
case 7 then
printf('Matlab sparse matrix')
case 8 then
printf('a matrix of integers stored on 1 (int8), 2 (int16) or 4 (int32) bytes.')
case 9 then
printf('a matrix of graphic handles.')
case 10 then
printf('a matrix of character strings.')
case 11 then
printf('an un-compiled function . A function created with deff with argument [n].')
case 13 then
printf('a compiled function .')
case 14 then
printf('a function library.')
case 15 then
printf('a list.')
case 16 then
printf('a typed list (tlist).')
case 17 then
printf('a matrix oriented typed list (mlist).')
case 128 then
printf('a pointer (Use case: lufact).')
case 129 then
printf('a size implicit polynomial used for indexing.')
case 130 then
printf('a built-in Scilab function, called also gateway (C, C++ or Fortran code).')
case 0 then
printf('a null variable. It is mainly used internally by Scilab. If a function has no declared returned argument like disp when it is called it returns a null variable. If a function is called with an omitted argument in the argument list like foo(a,,b) the missing argument is assigned to a null variable.')
end
end
else
disp("Enter the file whose type is to be found")
unix_w('read xtun;type $xtun')
end
printf("\n*******************************************************************\n")
|
9e9cf26fac8271782c35ac73612fb64e9cfb067f | 7d080f5a520b49242d8d5d362be8378358f324b5 | /Rayleigh's Power Method.sce | 09c4dab4760b14facb448d018a364572320797f0 | [] | no_license | pradyumnaym/LA_Algos | 1d4cc539b531ffaea88ceb475ca3c4b59318270a | 561df9e8b2d706927c735f2b2e30db9ff1a45ade | refs/heads/master | 2020-12-29T16:50:23.235497 | 2020-02-06T11:41:10 | 2020-02-06T11:41:10 | 238,675,439 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 533 | sce | Rayleigh's Power Method.sce | disp("Name: Pradyumna YM")
disp("SRN: PES1201700986")
a=input("Enter the Matrix A:")
x=input("Enter the approximation: ")
ax = a*x;
disp(ax);
l = max(abs(ax)); //find out the highest absolute value of the components
ax = ax/l;
previous = [0;0;0]; //since there was no previous l
while 1 do
previous=ax;
ax = a*ax;
lT = max(abs(ax));
ax = ax/lT;
disp(ax);
if((ax-previous)<0.0000001) //if the difference is negligible, break from the loop
break;
end
T = ax;
end
disp(lT);
disp(ax);
|
457f072758799d1b542c3bbda9c10c9bfc318dca | e7055fdf94e8a24293cab7ccbeac12039d6fe512 | /macros/trainLRClassifier.sci | dfeb6a46d8379c59792e2c7b617987997206d6be | [] | no_license | sidn77/FOSSEE-Image-Processing-Toolbox | 6c6b8b860f637362a73d28dcfe13e87d18af3e2c | 8dfbdbdfd38c73dc8a02d1a25678c4a6a724fe18 | refs/heads/master | 2020-12-02T16:26:06.431376 | 2017-11-08T17:54:03 | 2017-11-08T17:54:03 | 96,552,565 | 0 | 0 | null | 2017-07-07T15:37:18 | 2017-07-07T15:37:18 | null | UTF-8 | Scilab | false | false | 4,266 | sci | trainLRClassifier.sci | // Copyright (C) 2015 - IIT Bombay - FOSSEE
//
// This file must be used under the terms of the CeCILL.
// This source file is licensed as described in the file COPYING, which
// you should have received as part of this distribution. The terms
// are also available at
// http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt
// Author: Siddhant Narang
// Organization: FOSSEE, IIT Bombay
// Email: toolbox@scilab.in
function classifier = trainLRClassifier(imgSets, bag, classifierName, varargin)
// This function is used to train an image classifier using the LR algorithm.
//
// Calling Sequence
// classifier = trainLRClassifier(imgSets, bag, classifierName)
// classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate)
// classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration)
// classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration, regularization)
// classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration, regularization, trainMethod)
// classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration, regularization, trainMethod, minibatch)
//
// Parameters
// classifier: Image category classifier
// imgSets: Input imageSet to train the classifier on
// bag: The bagOfFeatures of the imageSet provided
// learningRate: Defines the rate at which the classifier will learn.
// iteration: Number of iterations the training function will perform.
// regularization: Controls the kind of regularization to be applied. The types are<itemizedlist><listitem>REG_DISABLE- Regularization disabled, flag value = -1.</listitem><listitem>REG_L1- L1 norm, flag value = 0.</listitem><listitem>REG_L2- L2 norm, flag value = 1.</listitem></itemizedlist>
//
// trainMethod: Controls the kind of training method to be applied. The types are<itemizedlist><listitem>BATCH- flag value = 1.</listitem><listitem>MINI_BATCH- flag value = 0.</listitem></itemizedlist>
//
// minibatch: Specifies the number of training samples taken in each step of Mini-Batch Gradient Descent.
// Will only be used if trainMethod flag value is set to 0 training algorithm.
// It has to take values less than the total number of training samples.
//
//
// Description
// This function trains a LR classifier which can be used to predict classes of images given to it as
// input using the predictLR() function.
//
// Examples
// imgSet = imageSet('images/trainset_2/','recursive');
// [trainingSet testSet] = partition(imgSet,[0.8]);
// bag = bagOfFeatures(trainingSet);
// lrclassi = trainLRClassifier(im, bag, "lrclassi", 1, 150, 0, 1, 5);
//
// Examples
// imgSet = imageSet('images/trainset_3/','recursive');
// [trainingSet testSet] = partition(imgSet,[0.8]);
// bag = bagOfFeatures(trainingSet);
// lrclassi = trainLRClassifier(im, bag, "lrclassi", 1, 150, 0);
// save("var.dat", "lrclassi");
//
// See also
// imageSet
// partition
// bagOfFeatures
// mlPredict
// save
//
// Authors
// Siddhant Narang
bag_list = bagStructToList(bag);
imgSets_list = imageSetToList(imgSets);
// Handling variable arguments.
[lhs rhs] = argn(0)
if lhs > 1
error(msprintf("Too many output arguments"));
elseif rhs < 3
error(msprintf("Not enough input arguments"));
elseif rhs > 8
error(msprintf("Too many input arguments"));
end
if rhs == 3
temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName);
elseif rhs == 4
temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1));
elseif rhs == 5
temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2));
elseif rhs == 6
temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2), varargin(3));
msprintf("6 arguments");
elseif rhs == 7
temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2), varargin(3), varargin(4));
elseif rhs == 8
temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2), varargin(3), varargin(4), varargin(5));
end
classifier = struct("ClassifierType", temp(1), "ClassifierLocation", temp(2), "BagofFeaturesLocation", temp(3), "Description", temp(4))
endfunction
|
0afa8ebdbf84ce6ac853190580ab82f50a086114 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3809/CH1/EX1.1/EX1_1.sce | 9931be8e4147176d55b4ff4bc1c4227aae16c058 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 384 | sce | EX1_1.sce | //Chapter 1, Example 1.1
clc
//Initialisation
v1=15.8 //voltage
v2=12.3 //voltage
r=220 //resistance in ohm
//Calculation
v=v1-v2 //voltage
i=v/r //current in ampere
//Results
printf("Current, I = %.1f mA",(i*1000))
|
ddf2732cac8690c16171ed87e0ad94918418552c | 449d555969bfd7befe906877abab098c6e63a0e8 | /1628/CH7/EX7.9/Ex7_9.sce | 1a1b83cf7338f8afa426763ec6336e59d0a70a72 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,014 | sce | Ex7_9.sce |
// Example 7.9
N2=800; // turns of Coil 2
N1=1200; // turns of Coil 1
Q2=0.15*10^-3; // Megnetic Flux in Coil 2
Q1=0.25*10^-3; // Megnetic Flux in Coil 1
I2=5; // Current in A Coil 2
I1=5; // Current in A Coil 1
L1=N1*(Q1/I1); // Formula for (Self Inductance of Coil 1)
disp('(a) Self Induction of a Coil 1 = '+string(L1)+' H');
L2=N2*(Q2/I2); // Formula for (Self Inductance of Coil 2)
disp('(b) Self Induction of a Coil 2 = '+string(L2)+' H');
k=0.6; // Coefficient of Coupling Constant
Q12=k*Q1; // Formula for (Megnetic Flux in 2nd Coil)
M=N2*(Q2/I1); // Formula for (Mutual Inductance of Coils)
disp('(c) Mutual induction of a Coil = '+string(M)+' H');
k1=M/sqrt(L1*L2); // Mutual Inductance of Coil 1 & 2
disp('(d) Coefficient of Coupling between the Coil = '+string(k1)+' H');
// p 233 7.9 |
db3a1cffd61461578ba6d5aaff86e89506056370 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3720/CH10/EX10.8/Ex10_8.sce | a379ca0ec8df1efa408f454f09f0207580e79eaa | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 467 | sce | Ex10_8.sce | //Example 10_8
clc;clear;funcprot(0)
// Given values
w=2.0;// Width in mm
L=35.0;// Length in cm
b=2.0;// Distance in cm
v_dot=0.110;// The total volume flow rate in m^3/s
u_starmax=0.159;// m/s
// Calculation
v_dotbyL=-(v_dot/(L/100));// Strength of line source in m^2/s
u_max=-(u_starmax*(v_dotbyL/(b/100)));// Maximum speed along the floor
printf('\nStrength of line source=%0.3f m^2/s \nMaximum speed along the floor,u_max=%0.2f m/s',v_dotbyL,u_max);
|
84703b60fc2b87c1caeab3a2a73cfb0b596b0d1b | 449d555969bfd7befe906877abab098c6e63a0e8 | /3784/CH4/EX4.28/Ex4_28.sce | eaca7e80554ef82fbcf92404d640991476250683 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 554 | sce | Ex4_28.sce | clc
//Variable Initialisation
Ea=210//Input Voltage of motor in volts
Ia1=140//Armature Current in Ampere
Ia2=2*Ia1
Ra=0.08//Armature resistance in ohm
N1=1100//Rated Speed of Motor in rpm
N2=1200//Rated Speed of Motor in rpm
//Solution
Eb1=Ea-(Ia1*Ra)
Eb2=(N2/N1)*Eb1
Rb=((Eb2+Ea)/Ia2)-Ra
W=(2*%pi*N2)/60
T1=(Eb2*Ia2)/W
Ia3=Ea/(Ra+Rb)
T2=T1*(Ia3/Ia2)
printf('\n\n Resistance to be placed=%0.1f ohm\n\n',Rb)
printf('\n\n Braking torque=%0.1f N-m\n\n',T1)
printf('\n\n torque=%0.1f N-m\n\n',T2)//The answers vary due to round off error
|
bdc0b36565b1598821d3176a92402006069ae2db | 449d555969bfd7befe906877abab098c6e63a0e8 | /2453/CH2/EX2.16/2_16.sce | 27f00d78dca9e8ffab1f2777f8a9f2f78a486fcf | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 339 | sce | 2_16.sce | //To calculate the highest order for which Bragg's reflection can be seen
lamda = 1.5; //wavelength, A.U
d = 1.6; //interplanar spacing, A.U
theta = 90; //maximum glancing angle possible, degrees
n = 2*d*sind(theta)/lamda; //maximum possible diffraction order
printf("maximum possible diffraction order is %d",n);
|
08fe0a7c05f6d73e424ba9822a2686b3c62b1ca7 | 449d555969bfd7befe906877abab098c6e63a0e8 | /409/CH27/EX27.5/Example27_5.sce | da9833b0ddb54ebd8303ed031a3fbe73d1e4dd4d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,131 | sce | Example27_5.sce | clear ;
clc;
// Example 27.5
printf('Example 27.5\n\n');
//page no. 850
// Solution
// Given
V1 = 5 ;// Volume of gas initially - [cubic feet]
P1 = 1 ;// Initial pressure - [atm]
P2 = 10 ;// Final pressure - [atm]
T1 = 100 + 460 ;// initial temperature - [degree Rankine]
R = 0.7302 ;// Ideal gas constant -[(cubic feet*atm)/(lb mol)*(R)]
//Equation of state pV^1.4 = constant
//(a)
//Energy balance reduces to del_E = del_U = del_W
V2 = V1*(P1/P2)^(1/1.4) ;// Final volume - [cubic feet]
W1_rev = integrate('-(P1)*(V1/V)^(1.4)','V',V1,V2) ;// Reversible work done in compresion in a horizontal cylinder with piston -[cubic feet *atm]
W1 = W1_rev *1.987/.7302 ;// Conversion to Btu -[Btu]
printf('\n (a)Reversible work done in compression in a horizontal cylinder with piston is %.1f Btu .\n ',W1);
//(b)
n1 = (P1*V1)/(R*T1) ;// Number of moles of gas
W2_rev = integrate('(V1)*(P1/P)^(1/1.4)','P',P1,P2) ;// Reversible work done in compresion in a rotary compressor -[cubic feet *atm]
W2 = W2_rev *1.987/.7302 ;// Conversion to Btu -[Btu]
printf('\n (b)Reversible work done in a rotary compressor is %.1f Btu .\n ',W2); |
4ed3bf3f45bae909d22220098e8a8601dd3ef468 | e3c27edbd2f0a8e733cee84b90a906c0a6d7c176 | /sem_3/c/adv_lin_pr/buf.tst | 7bd3a3696b87ef08c09f8c60418c927745c999a2 | [] | no_license | dmitryhd/dmitryhd_code | c32223da5506156a068bbb0f20ad4cd06fdf2166 | 5173f6f74d4fa1c9c5fba9ffc4fc9134c56f4b0c | refs/heads/master | 2021-01-17T11:56:50.221745 | 2011-04-26T18:31:58 | 2011-04-26T18:31:58 | 1,650,576 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 26 | tst | buf.tst | plate1 plate1 plate3 exit |
119e682b8803915e30a269e1482c27720ece6fca | 449d555969bfd7befe906877abab098c6e63a0e8 | /2384/CH10/EX10.21/ex10_21.sce | ecce69c28336bd127558625e2e974553e1e6d540 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 473 | sce | ex10_21.sce | // Exa 10.21
clc;
clear;
close;
format('v',6)
// Given data
P = 4;
A = 4;
Turns = 100;
N = 600;// in rpm
Eg = 220;// in V
n = 2;// no of total conductors
Z = n*Turns;
// Eg = (N*P*phi*Z)/(60*A);
phi = (Eg*60*A)/(N*P*Z);// in Wb
disp(phi,"The useful flux per mole when armature is LAP connected in Wb is");
A = 2;
// Eg = (N*P*phi*Z)/(60*A);
phi = (Eg*60*A)/(N*P*Z);// in Wb
disp(phi,"The useful flux per mole when armature is WAVE connected in Wb is");
|
a04e4b86860e9b1150a8c99b6998bff19d103952 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1076/CH10/EX10.4/10_4.sce | cdf01d30e9f8e5ae987daa4bde2a22bda0ee7098 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 641 | sce | 10_4.sce | clear
clc
T=[10 132 6.6 .15]
M=[5 6.6 .3 .2 ]
B=[10 6.6]
T(5)= T(3)/T(2)
B(3)=B(2)* T(5)
B(4)= B(1)*1e6/(sqrt(3)*B(2)*1e3)
M(5)=M(4) *B(1)/M(1)
M(6)=M(3) *B(1)/M(1)
X1=1/((1/M(5))+(1/M(5))+(1/T(4)))
IF1=round(100/X1)/100
I1=IF1*B(4)
mprintf("\n(a) sub transient fault current=%.0f A", I1)
It=round(100/T(4))/100
Im=1/M(5)
ID=It+Im
iD=ID*B(4)
mprintf("\n(b) current through D=%.0f A", iD)
RD=iD*1.6
mprintf("\n(c) current rating of D=%.0f A", RD)
X2=1/((1/M(6))+(1/T(4)))
IF2=round(100/X2)/100
I2=IF2*round(B(4)*10)/10
iCB=1.1 *I2
mprintf("\n(d) current to be interrrupted by D=%.1f A", fix(iCB*10)/10)
|
042a5bd920b89238176adb2bd1fec5f520db13ee | 449d555969bfd7befe906877abab098c6e63a0e8 | /1682/CH11/EX11.4/Exa11_4.sce | 557131b521d2d5464c91ea37f52d7499c9b71d04 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 681 | sce | Exa11_4.sce | //Exa 11.4
clc;
clear;
close;
IR=6;//in % per year
i=18;//in % per year
AFR=5000000;//in Rs.
n=7;//in years
AI=500000;//in Rs.
disp("End of year AFR InflationFactor InflatedAmount P/F PW");
TPW=0;//Initialising
format('v',10)
for n=1:5
IF=(1+IR/100)^n;
IA=IF*AFR;//in Rs.
PF=1/((1+i/100)^n);
PW=PF*IA;//in Rs.
TPW=PW+TPW;//in Rs.
disp(" "+string(n)+" "+string(AFR)+" "+string(IF)+" "+string(IA)+" "+string(PF)+" "+string(PW));
AFR=AFR+AI;//in Rs.
end;
disp(TPW,"The value of the single deposit to be made now to recieve the specified series for the next five years is Rs. : ")
|
9b4ae70a423b2e8e8c48d011238dba1ae900fc33 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2780/CH1/EX1.9/Ex1_9.sce | c36a7b8152ee07837bab8ef66ecb95ffcda6732e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 449 | sce | Ex1_9.sce | clc
//to calculate distance travelled by the beam
deltat0=2.5*10^-8 //proper half life of pi mesons in (s)
c=3*10^8 //light speed (m/s)
v=0.8*c //mesons velocity (m/s)
deltat=deltat0/sqrt(1-(v/c)^2) //half life (s)
//No=initial flux ,N=flux after time t
//N=N0 e^(-t/T)
//N=N0/e^2 (given)=No e(-t/T)
//t=2 deltat
d=2*deltat*v //d=vt
disp("distance travelled by the beam is d="+string(d)+"m")
//answer is given in the textbook=19.96 m
|
63cac093efef8719fac48c005e9aa09c0ad29495 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1658/CH34/EX34.11/Ex34_11.sce | 5310e6da3087c1a5a087d1d9a40059472527a71c | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 280 | sce | Ex34_11.sce | clc;
Vsmin=19.5;
Vsmax=22.5;
RL=6*10**3;
Vz=18;
Izmin=2*10**-6;
Pzmax=60*10**-3;
rz=20;
Izmax=sqrt(Pzmax/rz);
IL=Vz/RL;
ILmax=IL;
ILmin=IL;
Rsmax=(Vsmin-Vz)/(Izmin+ILmax);
disp('ohm',Rsmax*1,"Rsmax=");
Rsmin=(Vsmax-Vz)/(Izmax+ILmin);
disp('ohm',Rsmin*1,"Rsmin=");
|
337c1256980a3b24b1c91c2378a033f9f9b96f28 | 8217f7986187902617ad1bf89cb789618a90dd0a | /browsable_source/2.3/Unix-Windows/scilab-2.3/macros/arma/armac.sci | 2d9db77c21c95351d738204a299238ec997e5d2f | [
"LicenseRef-scancode-warranty-disclaimer",
"LicenseRef-scancode-public-domain",
"MIT"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 669 | sci | armac.sci | function [ar]=armac(a,b,d,ny,nu,sig)
// Renvoit une liste Scilab qui decrit un systeme ARMACX
// A(z^-1)y= B(z^-1)u + D(z^-1)sig*e(t)
// a=<Id,a1,..,a_r>; matrice (ny,r*ny)
// b=<b0,.....,b_s>; matrice (ny,(s+1)*nu)
// d=<Id,d1,..,d_p>; matrice (ny,p*ny);
// ny : dimension de l'observation y
// nu : dimension de la commande u
// sig : matrice (ny,ny);
//
//!
[na,la]=size(a);
if na<>ny,write(%io(2),"a(:,1) must be of dimension "+string(ny));end
[nb,lb]=size(b);
if nb<>ny,write(%io(2),"b(:,1) must be of dimension "+string(ny));end
[nd,ld]=size(d);
if nd<>ny,write(%io(2),"d(:,1) must be of dimension "+string(ny));end
ar=list('ar',a,b,d,ny,nu,sig)
|
a6778fb271dd54da5a229ace34eac7ef9dc2a5a6 | ed81f401dcd2ce0399cec3a99b6e5851e62e74ca | /data/github.com/SumrainChan/Numerical-Calculation-Collection/d583df6ba68ba25962c7f08985c0f0c70e53b051/Item01/Item01.sce | 6e51b6ba7f73f3515b586589e797ead8623bd9db | [
"MIT"
] | permissive | smola/language-dataset | 9e2a35340d48b497cd9820fa2673bb5d482a13f7 | 4d1827d1018b922e03a48a5de5cb921a6762dda3 | refs/heads/master | 2023-03-10T12:42:04.396308 | 2022-07-15T18:05:05 | 2022-07-15T18:05:05 | 143,737,125 | 18 | 3 | MIT | 2023-03-06T05:01:14 | 2018-08-06T14:05:52 | Python | UTF-8 | Scilab | false | false | 1,631 | sce | Item01.sce | A = zeros(1000, 1000)
for i=1:1000
A(i, i) = i
if i+1 <= 1000
A(i, i+1) = 0.5
A(i+1, i) = 0.5
end
if i+2 <= 1000
A(i, i+2) = 0.5
A(i+2, i) = 0.5
end
end
b = ones(1000, 1)
x0 = zeros(1000, 1)
D = diag(diag(A))
U = triu(A, 1)
L = tril(A, -1)
// Jacobi
xk = x0
for step=1:15
xk_next = inv(D) * (b - (L + U) * xk)
xk = xk_next
end
ans_jcb = xk
// Gauss-Seidel
xk = x0
for step=1:15
xk_next = inv(L + D) * (-U * xk + b)
xk = xk_next
end
ans_gs = xk
// SOR w=1.1
w = 1.1
xk = x0
for step=1:15
xk_next = inv(w * L + D) * ((1 - w) * D * xk - w * U * xk) + w * inv(D + w * L) * b
xk = xk_next
end
ans_sor = xk
// Conjugate Gradient
d0 = b - A * x0
r0 = d0
dk = d0
rk = r0
xk = x0
for step=1:15
if rk == 0
break
end
alphak = (rk' * rk) / (dk' * A * dk)
xk_next = xk + alphak * dk
rk_next = rk - alphak * A * dk
betak = (rk_next' * rk_next) / (rk' * rk)
dk_next = rk_next + betak * dk
dk = dk_next
rk = rk_next
xk = xk_next
end
ans_cg = xk
// Conjugate Gradient with jcb preconditioner
M = D
r0 = b - A * x0
d0 = inv(M) * r0
z0 = d0
dk = d0
zk = z0
rk = r0
xk = x0
for step=1:15
if rk == 0
break
end
alphak = (rk' * zk) / (dk' * A *dk)
xk_next = xk + alphak * dk
rk_next = rk - alphak * A * dk
zk_next = inv(M) * rk_next
betak = (rk_next' * zk_next) / (rk' * zk)
dk_next = zk_next + betak * dk
dk = dk_next
zk = zk_next
rk = rk_next
xk = xk_next
end
ans_cgp = xk
|
d7f10c70634e4a84a85efa726f7e947df2fd387b | 482cdc3e27e99afe860829eff3e593caa62202e3 | /src/Assignment1_Tests/test0.tst | e83dff05adc2e7a4f9bfb40f08a9a03a34cb88a7 | [] | no_license | abrageddon/DLXCompiler | e153430de4412fe48a34955851352d0fd73ab2d8 | 2d1abd102f723c2e1f0ed5893e86c7d0ceb42914 | refs/heads/master | 2020-12-30T10:50:20.955331 | 2011-12-02T03:34:59 | 2011-12-02T03:34:59 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 46 | tst | test0.tst | var x, y;
x <- 51;
y <- 2 * x;
call print (x). |
f6c3f90e1dfda34c5095ec4ef6f0a079ad8d755e | 449d555969bfd7befe906877abab098c6e63a0e8 | /2273/CH9/EX9.8/ex9_8.sce | a4dab0f1d423baf96108e41fbcf72ffd346bdb4d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 498 | sce | ex9_8.sce | //find safe working voltage of cable
clear;
clc;
//soltion
//given
d=4;//cm
D=10;//cm
e1=5;//realtive permeabilty
e2=4;//realtive permeabilty
e3=3;//realtive permeabilty
d1=e1*d/e2;
d2=e1*d/e3;
gmax=40;//kV/cm
Vper=(gmax/2)*[d*log(d1/d)+d1*log(d2/d1)+d2*log(D/d2)];
Vsafe1=Vper/sqrt(2);
printf("Safe working voltage(rms) of a cable= %.2f kV\n",Vsafe1);
Vpeak=(gmax/2)*[d*log(D/d)];
Vsafe2=Vpeak/sqrt(2);
printf("Safe working voltage(rms) of the ungraded cable= %.2f kV",Vsafe2);
|
f383aca86ff2fd5ca2f03cbb0ab829668886870d | 449d555969bfd7befe906877abab098c6e63a0e8 | /767/CH7/EX7.7.1/Ch07Exa7_7_1.sci | 559082e5da553a94c9339c509e5e09c7d77ad95b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,129 | sci | Ch07Exa7_7_1.sci | // Scilab code Exa7.7.1 : To calculate the thickness of depletion layer of silicon detector and amplitude of voltage pulse :P.no. 316 (2011)
E_r = 12; // Relative permittivity
E_o = 8.85e-012; // Permittivity of free space
E = E_r*E_o; // Absolute dielectric constant
C = 100e-012; // Capacitance of the dielectric, F
A = 1.6e-04; // Area of the detector, m^2
e = 1.602e-019; // Charge of an electrin, C
E_p = 3.2; // Energy required to create an ion pair, eV
E_s = 12e+06; // Energy required to stopped ion pair, eV
n = E_s/E_p; // Number of ion-pair produced
Q = n*e; // Charge of these ion pair, C
d = A*E/(C*10^-6); // The thickness of the depletion layer, micron
A = Q/C*1000; // The amplitude of voltage pulse, mV
printf("\n The thickness of the depletion layer = %d micron \n The amplitude of voltage pulse: = %6.4f mV ", d, A)
// Result
// The thickness of the depletion layer = 169 micron
// The amplitude of voltage pulse: = 6.0075 mV
|
dffae5af1f471385d65599eb081de0148a7b1c2a | aef26b59d30e6dadcb4ad4adca5fef486bba8f39 | /测试游标之动态游标[弱类型游标].tst | fefb4e67261979b1add64bf51fe64765d8b6b2fc | [] | no_license | BinYangXian/ora | 23141658d122e552ae63d2c091a0b038446da275 | ebb23fed403da5248f8926f902a247b4046e540c | refs/heads/master | 2021-01-20T15:07:10.757649 | 2017-05-09T08:34:52 | 2017-05-09T08:34:52 | 90,722,061 | 0 | 0 | null | null | null | null | GB18030 | Scilab | false | false | 696 | tst | 测试游标之动态游标[弱类型游标].tst | PL/SQL Developer Test script 3.0
32
-- 测试游标之动态游标[弱类型游标]
declare
-- 声明类型
type v_cursor_type is ref cursor;
-- 声明变量
v_cursor v_cursor_type;
-- 行变量
v_row emp%rowtype;
v_dept_row dept%rowtype;
begin
-- Test statements here
open v_cursor for select * from emp;
loop
fetch v_cursor into v_row;
exit when v_cursor%notfound;
dbms_output.put_line(v_row.ename);
end loop;
close v_cursor;
open v_cursor for select * from dept;
loop
fetch v_cursor into v_dept_row;
exit when v_cursor%notfound;
dbms_output.put_line(v_dept_row.dname);
end loop;
close v_cursor;
end;
0
0
|
cabc9ccb5dff61252cb1bf04099788fbfd555587 | 8217f7986187902617ad1bf89cb789618a90dd0a | /browsable_source/2.4/Unix-Windows/scilab-2.4/macros/util/syssize.sci | f128c0af8c5b127a480f92e4b3c670f54404dbe8 | [
"LicenseRef-scancode-public-domain",
"LicenseRef-scancode-warranty-disclaimer"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 891 | sci | syssize.sci | function [io,s]=syssize(sys)
//Old stuff
// io=syssize(sys)
// [io,ns]=syssize(sys)
//
// sys : syslin list
// io : io=[nout,nin]
// nout: nb. ouputs
// nin : nb. inputs
// s : nb states.
// Copyright INRIA
select type(sys)
case 1 then
io=size(sys)
s=[]
//-compat next case retained for list/tlist compatibility
case 15 then
sys1=sys(1)
select sys1(1)
case 'lss' then
io=size(sys(5)),
[s,s]=size(sys(2))
case 'r' then
io=size(sys(3))
[lhs,rhs]=argn(0);
if lhs==2 then sys=tf2ss(sys);[s,s]=sys(2),end
else error(97,1)
end;
case 16 then
sys1=sys(1)
select sys1(1)
case 'lss' then
io=size(sys(5)),
[s,s]=size(sys(2))
case 'r' then
io=size(sys(3))
[lhs,rhs]=argn(0);
if lhs==2 then sys=tf2ss(sys);[s,s]=sys(2),end
else error(97,1)
end;
else
error(97,1),
end
|
ad1672c17bb4471f0149a8ff248472fdd975a10c | 1db0a7f58e484c067efa384b541cecee64d190ab | /macros/pow2db.sci | 5be09410a4f497bb37505e1969fda8c8df761060 | [] | no_license | sonusharma55/Signal-Toolbox | 3eff678d177633ee8aadca7fb9782b8bd7c2f1ce | 89bfeffefc89137fe3c266d3a3e746a749bbc1e9 | refs/heads/master | 2020-03-22T21:37:22.593805 | 2018-07-12T12:35:54 | 2018-07-12T12:35:54 | 140,701,211 | 2 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 716 | sci | pow2db.sci | //POW2DB Power to dB conversion
//YDB = POW2DB(Y) convert the data Y into its corresponding dB value YDB
//Example:
//Calculate ratio of 2000W to 2W in decibels
//y1 = pow2db(2000/2) //Answer in db
//Author : Debdeep Dey
function [ydb]=pow2db(y)
rhs = argn(2)
if(rhs~=1)
error("Wrong number of input arguments.")
end
[r,c]=size(y);
if (find(real(y(:))<0))==[] then
if abs(y(:))>=0 then
for i=1:r
for j=1:c
if abs(y(i,j))>0 then
ydb(i,j)=10*log10(y(i,j));
else
ydb(i,j)=-%inf;
end
end
end
end
else
error("The power value must be non-negative")
end
endfunction
|
40f5f5fbf931b5997ea9eed7dde10162253a9bf1 | 449d555969bfd7befe906877abab098c6e63a0e8 | /172/CH2/EX2.3/ex3.sce | 5f17aadbaf6700dc3c77f7c17bc84f1455b8de9d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 602 | sce | ex3.sce | //example 3
//calculating the required force
clear
clc
Dcyl=0.1 //cylinder diameter in m
Drod=0.01 //rod diameter in m
Acyl=%pi*Dcyl^2/4 //cross sectional area of cylinder in m^2
Arod=%pi*Drod^2/4 //cross sectional area of rod in m^2
Pcyl=250000 //inside hydaulic pressure in Pa
Po=101000 //outside atmospheric pressure in kPa
g=9.81 //acc. due to gravity in m/s^2
mp=25 //mass of (rod+piston) in kg
F=Pcyl*Acyl-Po*(Acyl-Arod)-mp*g //the force that rod can push within the upward direction in N
printf("\n hence,the force that rod can push within the upward direction is F = %.3f N. \n",F) |
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