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//Chapter 19, Problem 8, Fig.19.12 clc; R1=10e3; //resistance 1 R2=20e3; //resistance 2 R3=30e3; //resistance 3 V1=0.5; //input voltage 1 V2=0.8; //input voltage 2 V3=1.2; //input voltage 3 Rf=50e3; //feedback resistance V0=-Rf*((V1/R1)+(V2/R2)+(V3/R3)); //output voltage printf("Output voltage = %f V",V0);
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//Example 13.1 //Differentiation //Page no. 420 clc;close;clear; deff('y=f(x)','y=x^2+5') deff('y=f1(x,h)','y=(f(x+h)-f(x))/h') h=0.01;x=2.4 d=f1(x,h) d1=(f1(x+h,h)-f1(x))/h printf('dy\n -- = %g\n dx',d) printf('\n\n\n d2y\n --- = %g\n dx2',d1)
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// Example 10.9 clear all; clc; // Given data // Assuming average energy produced per fission reaction is 200 MeV P = 55; // Power density of reactor in watts/cm^3 rho_eff_U = 0.33; // Effective density of uranium in g/cm^3 rho_eff_W = 1-rho_eff_U; // Effective density of water in g/cm^3 t_i = 3; // Average time spent by water in the reactor in seconds t_0 = 2; // Average time spent by water in the external coolant circuit in seconds // 1 eV = 1.6*10^(-19) J P_fission = 200*10^6*1.6*10^(-19); // Energy produced in a fission reaction in terms of joule fission_density = P/P_fission; // Number of fission reactions v = 2.42; // Number of fission neutrons emitted per fission S = v*fission_density; // Strength of neutron source in terms of neutrons/cm^2-sec // Atom density of oxygen at normal density of 1 g/cm^3 is rho = 1; // Density of water in g/cm^3 N_A = 6.02*10^(23); // Avogadro's constant M = 18; // Molecular weight of water atom_density = (rho*N_A)/M; // Using the data from Table 10.7 sigma_r = 1.9*10^(-5)*10^(-24); // Reaction cross section in cm^2 T_12 = 7.1; // Half life of the given reaction in seconds lambda = 0.693/T_12; // Decay constant of the given reaction in seconds^(-1) sigma_act = rho_eff_W*atom_density*sigma_r; // Average macroscopic activation cross section // Using the data from Table 10.4 sigma_RW = 0.103; // Removal cross section of water in cm^-1 sigma_RU = 0.174; // Removal cross section of Uranium in cm^-1 sigma_R = (sigma_RU*rho_eff_U)+(sigma_RW*rho_eff_W); // Removal cross section of mixture // Let activation rate given by (sigma_act*phi_av) be denoted as AR AR = (sigma_act*S)/sigma_R; // Calculation alpha = AR*(1-exp(-t_i*lambda))/(1-exp(-(t_i+t_0)*lambda)); // 1 curie = 3.7*10^(10) disintegrations/sec // Result printf("\n Equilibrium activity of water due to neutron capture of oxygen = %.2E disintegrations/cm^3-sec or %d uCi/cm^3 \n",alpha,ceil(alpha*10^6/(3.7*10^10)));
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function [simulator_filepath, input_filepath,output_filepath]=simulator_properties() simulator_filepath='/Users/mcfly/Desktop/INP-SCILAB/' input_filepath='/Users/mcfly/Desktop/INP-SCILAB/input/' output_filepath='/Users/mcfly/Desktop/INP-SCILAB/output/' endfunction
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//(Welded and Riveted Joints) Example 8.11 //Refer Fig.8.28 on page 289 //Eccentric force acting on the welded connection P (kN) P = 25 //Permissible shear stress for the weld tau (N/mm2) tau = 55 //Length of the transverse welds w (mm) w = 150 //Length of the parallel weld l (mm) l = 100
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//find clc //solution //given N=720//rpm Lh=24000//hours W=1//N L99=60*N*Lh//rev //x=L99/L90 x=0.85*0.9*[log(1/0.99)/log(1/0.90)]^(1/1.17) L90=L99/x//rev C=W*(L90/10^6)^(1/3) printf("dynamic load rating is,%f kN",C)
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clc // Given that t = 10^-8 // life time of atom in exited state in sec h = 6.62e-34 // Planck constant in J-sec // Sample Problem 12 on page no. 15.28 printf("\n # PROBLEM 12 # \n") printf("Standard formula used \n") printf(" del_E*del_t = h/(4*pi) \n") delta_f = 1 / (4 * %pi * t) printf("\n Minimum uncertainty in frequency is %e Hz.",delta_f)
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//EXAMPLE 8-7 PG NO-519 Fc1=1000; Fc2=3000; Ro=100; L1=[(Ro*(Fc2-Fc1))/(2*%pi*Fc2*Fc1)] disp('i) INDUCTANCE (L1/2) is = '+string ([L1]) +' H ') C1=1/[2*%pi*(Fc2-Fc1)]; disp('ii) CAPACITOR (C1) is = '+string (C1) +' F ') L2=Ro/[4*%pi*(Fc2-Fc1)]; disp('iii) INDUCTANCE (L2) is = '+string ([L2]) +' H ') C2=(Fc2-Fc1)/(%pi*Ro*Fc1*Fc2) disp('ii) CAPACITOR (C2) is = '+string ([C2]) +' F ')
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# Simple trace file BASELINE = baseline4.bsl WHENEVER 1-08:01:00 WAIT fan FOR 1800 #fan should be on across two scheduled behaviors WHENEVER 1-08:31:00 WAIT fan FOR 1800 #fan should be on across two scheduled behaviors
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clear; clc; a=.6; V_s=400; V_t=(1-a)*V_s; I_a=300; P=V_t*I_a; printf("power returned=%.0f kW",P/1000); r_a=.2; K_m=1.2; R_eq=(1-a)*V_s/I_a+r_a; printf("\nequivalent load resistance=%.4f ohm",R_eq); w_mn=I_a*r_a/K_m; N=w_mn*60/(2*%pi); printf("\nmin braking speed=%.2f rpm",N); w_mx=(V_s+I_a*r_a)/K_m; N=w_mx*60/(2*%pi); printf("\nmax braking speed=%.1f rpm",N); w_m=(V_t+I_a*r_a)/K_m; N=w_m*60/(2*%pi); printf("\nmax braking speed=%.1f rpm",N);
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//caption:what will be the setting of time base knob //Ex8.10 clc clear close f=1//frequency of sine wave(in kHz) n=10//number of divisions in a cycle T=1/f To=T/n disp(To,'setting of time base knob(in ms)=')
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//Ch25_Ex32 clc; clear; close; r=10.5; vol=(2/3)*(22/7)*r^3; curved=2*(22/7)*r^2; total=3*(22/7)*r^2; mprintf("Volume=%.1f cubic cm\n Curved surface area=%.0f square cm\n Total surface area=%.1f square cm",vol,curved,total);
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clf; plot2d(0,0,0,rect=[0,0,10,10],frameflag=3) xgrid(4), // pentagon vertices t=[0:4]*2*%pi/5; x=2*cos(t)'; y=2*sin(t)'; X=[2.5+x 2.5+x 7.5+x 7.5+x]; Y=[2.5+y 7.5+y 2.5+y 7.5+y]; //edges of the four black pentagons xpolys(X,Y,[1 1 1 1]) E=gce();E.children.closed=1; // closed boundary E.children.thickness=3; // thickness // 4 pentagons filled with color xfpolys(X,Y,[2 3 5 7])
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clear all clc close mi=133*1.67*1e-27;//Mass of cesium in kg qi=1.6*1e-19;//Charge in C Va=3500;//Accelerating voltage in V I=0.2;//Ion current in A //Calculation of velocity of ejected ions in km/s vi=sqrt(2*qi*Va/mi); printf('Velocity of ejected ions is %f m/s',vi) //Calculation of propulsion force in mN F=vi*mi*I/qi printf('propulsion force is %f N',F)
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<?xml version="1.0" encoding="ISO-8859-1"?> <start> <upsFile>rayleigh_dx.ups</upsFile> <gnuplot> <script>plotScript.gp</script>s <title>ICE:Rayleigh Problem X dir</title> <ylabel>Error</ylabel> <xlabel>Resolution</xlabel> </gnuplot> <AllTests> </AllTests> <Test> <Title>25</Title> <sus_cmd>sus </sus_cmd> <postProcess_cmd>compare_Rayleigh.m -aDir 1 -mat 0 -plot true</postProcess_cmd> <x>25</x> <replace_lines> <resolution> [10,25,1] </resolution> </replace_lines> </Test> <Test> <Title>50</Title> <sus_cmd>sus </sus_cmd> <postProcess_cmd>compare_Rayleigh.m -aDir 1 -mat 0 -plot true</postProcess_cmd> <x>50</x> <replace_lines> <resolution> [10,50,1] </resolution> </replace_lines> </Test> <Test> <Title>100</Title> <sus_cmd>sus </sus_cmd> <postProcess_cmd>compare_Rayleigh.m -aDir 1 -mat 0 -plot true</postProcess_cmd> <x>100</x> <replace_lines> <resolution> [10,100,1] </resolution> </replace_lines> </Test> <Test> <Title>200</Title> <sus_cmd>sus </sus_cmd> <postProcess_cmd>compare_Rayleigh.m -aDir 1 -mat 0 -plot true</postProcess_cmd> <x>200</x> <replace_lines> <resolution> [10,200,1] </resolution> </replace_lines> </Test> <Test> <Title>400</Title> <sus_cmd>sus </sus_cmd> <postProcess_cmd>compare_Rayleigh.m -aDir 1 -mat 0 -plot true</postProcess_cmd> <x>400</x> <replace_lines> <resolution> [10,400,1] </resolution> </replace_lines> </Test> </start>
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// Calculate forward currents for voltages // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 2-18 in page 98 clear; clc; close; // Given data Vt=0.026; // Thermal voltage at room temperature in eV V=[0.1 0.2 0.3]; // Given voltages in V // Calculation V1=0.026*-2.3; printf("(a)V=%0.2f V\n",V1); R=(exp(1.92)-1)/(exp(-1.92)-1); printf("(b)Ration of forward bias current to reverse bias current=%0.2f\n",R); printf("(c):\n") for i=1:3 I=15*(exp(V(i)/0.026)-1); printf("I = %0.3e A\n",I); end // Result // (a) V = -0.060 V // (b) Ratio = -6.83 // (c) Forward currents = 0.687 mA, 32.86 mA and 1.539 A respectively
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inv_dp.sci
function invA = inv_LU_dp(A, L, U, precisao, formato, formato_i) // ------------------------------------------------------------------------ // Cálculo da inversa // ------------------------------------------------------------------------ mprintf("\n-----------------------------------------------------------------------------------\n"); mprintf("\nCálculo de matriz inversa de A por decomposição LU:\n\n") // A*x = b, sendo x = invA(:, i) e b = I(:, i), pois A*invA = I. // Na decomposição LU = A, L*U*invA = I: // Para cada coluna i: Ident = eye(A); n = size(A, 1); for i = 1:n exibe_sistema(' Sistema triangular inferior Ly = I(coluna '+string(i)+') (por substituições sucessivas)', 'y', formato, L, Ident(:, i)) mprintf('\n'); // 1: L*y = I(:, i) => y = I(:, 1)/L y = substSuces(L, Ident(:, i)) exibe_vetor(' y', formato_i, y) mprintf('\n'); exibe_sistema_inv(' Sistema triangular superior UinvA(coluna '+string(i)+') = y (por substituições retroativas)', ... 'invA', i, formato_i, U, y) // 2: U*invA(:, i) = y => invA(:, i) = y/U invA(:, i) = substRetro(U, y) mprintf('\n'); exibe_vetor(' invA(coluna '+string(i)+')', formato_i, invA(:, i)) mprintf("...................................................................................\n"); end Ident2 = zera(A*invA, precisao); exibe_inversa(' Solução da matriz inversa de A', A, formato, invA, formato_i, Ident2) if ~isequal(Ident2, Ident) then disp('Falha nos cálculos da inversa!') end endfunction function invA = inv_LUP_dp(A, L, U, P, precisao, formato, formato_i) // ------------------------------------------------------------------------ // Cálculo da inversa // ------------------------------------------------------------------------ mprintf("\n-----------------------------------------------------------------------------------\n"); mprintf("\nCálculo de matriz inversa de A por decomposição LU com pivotação parcial:\n\n"); // P*A*x = P*b, sendo x = invA(:, i) e b = I(:, i), pois P*A*invA = P*I. // Como P*I = P, tem-se P*A*invA = P. // Na decomposição LU = A, ou seja, P*L*U*invA = P. // Para cada coluna i: Ident = eye(A); n = size(A, 1); for i = 1:n exibe_sistema(' Sistema triangular inferior Ly = P(coluna '+string(i)+') (por substituições sucessivas)', 'y', formato, L, P(:, i)) mprintf('\n'); // 1: L*y = P(:, i) => y = P(:, 1)/L y = substSuces(L, P(:, i)) exibe_vetor(' y', formato_i, y) mprintf('\n'); exibe_sistema_inv(' Sistema triangular superior UinvA(coluna '+string(i)+') = y (por substituições retroativas)', ... 'invA', i, formato_i, U, y) // 2: U*invA(:, i) = y => invA(:, i) = y/U invA(:, i) = substRetro(U, y) mprintf('\n'); exibe_vetor(' invA(coluna '+string(i)+')', formato_i, invA(:, i)) mprintf("...................................................................................\n"); end mprintf('\n'); Ident2 = zera(A*invA, precisao) exibe_inversa(' Solução da matriz inversa de A', A, formato, invA, formato_i, Ident2) if ~isequal(Ident2, Ident) then error('Falha nos cálculos da inversa!') end endfunction function invA = inv_LLt_dp(A, L, precisao, formato, formato_i) // ------------------------------------------------------------------------ // Cálculo da inversa // ------------------------------------------------------------------------ mprintf("\n-----------------------------------------------------------------------------------\n"); mprintf(" Cálculo de matriz inversa de A por decomposição de Cholesky:\n\n") // A*x = b, sendo x = invA(:, i) e b = I(:, i), pois A*invA = I. // Na decomposição LL' = A, L*L'*invA = I: // Para cada coluna i: Ident = eye(A); n = size(A, 1); for i = 1:n exibe_sistema(' Sistema triangular inferior Ly = I(coluna '+string(i)+') (por substituições sucessivas)', 'y', ... formato_i, L, Ident(:, i)) mprintf('\n'); // 1: L*y = I(:, i) => y = I(:, 1)/L y = substSuces(L, Ident(:, i)) exibe_vetor(' y', formato_i, y) mprintf('\n'); exibe_sistema_inv(' Sistema triangular superior L''invA(coluna '+string(i)+') = y (por substituições retroativas)', ... 'invA', i, formato_i, L', y) // 2: L'*invA(:, i) = y => invA(:, i) = y/L' invA(:, i) = substRetro(L', y) mprintf('\n'); exibe_vetor(' invA(coluna '+string(i)+')', formato_i, invA(:, i)) mprintf("...................................................................................\n"); end mprintf('\n'); Ident2 = zera(A*invA, precisao) exibe_inversa(' Solução da matriz inversa de A', A, formato, invA, formato_i, Ident2) if ~isequal(Ident2, Ident) then error('Falha nos cálculos da inversa!') end endfunction function invA = inv_LDLt_dp(A, L, D, precisao, formato, formato_i) // ------------------------------------------------------------------------ // Cálculo da inversa // ------------------------------------------------------------------------ mprintf("\n-----------------------------------------------------------------------------------\n"); mprintf(" Cálculo de matriz inversa de A por decomposição LDLt:\n\n"), // A*x = b, sendo x = invA(:, i) e b = I(:, i), pois A*invA = I. // Na decomposição LDL' = A, L*D*L'*x = b: // Para cada coluna i: Ident = eye(A); n = size(A, 1); for i = 1:n exibe_sistema(' Sistema triangular inferior Ly = I(coluna '+string(i)+') (por substituições sucessivas)', 'y', formato, L, Ident(:, i)) mprintf('\n'); // 1: L*y = I(:, i) => y = I(:, 1)/L y = substSuces(L, Ident(:, i)) exibe_vetor(' y', formato_i, y) mprintf('\n'); exibe_sistema(' Sistema diagonal Dt = y (solução direta por t(i)=y(i)/D(i,i))', 't', formato_i, D, y) mprintf('\n'); // 2: D*t = y => t = y/D n = size(D, 1) for ii = 1:n t(ii) = y(ii)/D(ii,ii) end exibe_vetor(' t', formato_i, t) mprintf('\n'); exibe_sistema_inv(' Sistema triangular superior L''invA(coluna '+string(i)+') = t (por substituições retroativas)', ... 'invA', i, formato_i, L', t) mprintf('\n'); // 3: L'*invA(:, i) = y => invA(:, i) = y/L' invA(:, i) = substRetro(L', t) exibe_vetor(' invA(coluna '+string(i)+')', formato_i, invA(:, i)) mprintf("...................................................................................\n"); end mprintf('\n'); Ident2 = zera(A*invA, precisao) exibe_inversa(' Solução da matriz inversa de A', A, formato, invA, formato_i, Ident2) if ~isequal(Ident2, Ident) then error('Falha nos cálculos da inversa!') end endfunction
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ex4_1.sce
// Example 4.1, page no-92 clear clc R=2.81*10^-10 //m e=1.6*10^-19 eps=8.854*10^-12 U=-(e^2)/(4*%pi*eps*R) printf("The Coulomb interatomic energy is %.2f eV",U*10^19/1.6)
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exa_3_9.sce
// Exa 3.9 clc; clear; close; // Given data R1= 10;// in kΩ R1=R1*10^3;// in Ω R2= 5;// in kΩ R2=R2*10^3;// in Ω RC= 1;// in kΩ RC=RC*10^3;// in Ω RE= 2;// in kΩ RE=RE*10^3;// in Ω V_CC= 15;// in V V_BE= 0.7;// in V // When I_C=0; V_CE= V_CC-I_C*(RC+RE);// in V // When V_CE= 0 I_C= V_CC/(RC+RE);// in A V_B= V_CC*R2/(R1+R2);// in V I_E= (V_B-V_BE)/RE;// in A I_C= I_E;// in A (approx) I_CQ= I_C;// in A V_CE= V_CC-I_C*(RC+RE);// in V V_CEQ= V_CE;// in V V_CE= 0:0.1:15;// in Volt I_C= (V_CC-V_CE)/(RC+RE)*1000;// in mA plot(V_CE,I_C); title("DC load line") xlabel("V_CE in volts") ylabel("I_C in mA") disp("DC load line shown in figure") disp("Operating point is "+string(V_CEQ)+" V and "+string(I_CQ*10^3)+" mA")
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example8_5.sce
//clc(); Pa = 15;//kPa ( Partial pressure ) Pas = 26.36;//kPa ( Vapour pressure ) RS = Pa * 100 / Pas ; Y = 0.1738; Ys = 0.3517; PS = Y * 100 / Ys; disp("%",RS,"Relative humidity = ") disp("%",PS,"Percent humidity = ")
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ex_13_3.sce
// //this program is just writing in to a file and will not display anything warning('off'); fp=mopen('output.dat','w'); for k=65:90 k=ascii(k); // printf("%c",k); mfprintf(fp,'%c\n',k ); end mclose(fp);
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pgm1.sci
function pgm1(p0, TOL, N0) //p0 = 0; //TOL = 0.0000000001; //N0=20; i = 1; while i<=N0 p = cos(p0); //compute |p-p0| error = p-p0; //if(error<0) // error = -1*error; //end // disp(['iteration step = ', num2str(i), ' pvalue = ', num2str(p0), ' g(p) = ', num2str(p), ' error = ', num2str(error)]); if(abs(error) < TOL) disp(p) return end i = i+1; p0 = p; end //disp(['The method failed after N0 iterations, N0=', num2str(N0)])
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Ex3_4.sce
clc un1=1000 disp("un1 = "+string(un1)+"cm^2(Vs)^-1") //initializing value of mobility of electron of silicon e = 1.6*10^-19 disp("e= "+string(e)+"C")//initializing value of charge of electron un2 = 400 disp("un2 = "+string(un2)+"cm^2(Vs)^-1") //initializing value of mobility of electron of GaAs up1 = 350 disp("up1 = "+string(up1)+"cm^2(Vs)^-1") //initializing value of mobility of holes of silicon up2 = 8000 disp("up2 = "+string(up2)+"cm^2(Vs)^-1") //initializing value of mobility of holes of GaAs ni = 1.5*10^10 disp("ni = "+string(ni)+"cm^-3") //initializing value of electron density of ionisation electron nmax = 2.78*10^19 disp("nmax = "+string(nmax)+"cm^-3") //initializing value of maximum electron density for silicon nmax1 = 7.72*10^18 disp("nmax1 = "+string(nmax1)+"cm^-3") //initializing value of maximum electron density for GaAs Smax = nmax*e*un1 disp("The maximum conductivity for silicon is (sigma max) Smax = nmax*e*un = "+string(Smax)+"ohmcm^-1")//calculation Smax1 = nmax1*e*un2 disp("The maximum conductivity of GaAs is (sigma max) Smax = nmax*e*un = "+string(Smax1)+"ohmcm^-1")//calculation Smin = ni*e*((un1*sqrt(up1/un1))+(up1*sqrt(un1/up1))) disp("The minimum conductivity of silicon is (sigma min)Smin = ni*e*((un1*sqrt(up1/un1))+(up1*sqrt(un1/up1))) = "+string(Smin)+"ohmcm^-1")//calculation ni1 = 1.84*10^6 disp("ni = "+string(ni1)+"cm^-3") //initializing value of electron density of ionisation electron for GaAs Smin1 = ni1*e*((un2*sqrt(up2/un2))+(up2*sqrt(un2/up2))) disp("The minimum conductivity of GaAs is (sigma min)Smin1 = ni*e*((un2*sqrt(up2/un2))+(up2*sqrt(un2/up2))) = "+string(Smin1)+"ohmcm^-1")//calculation
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ex9_4.sce
s=%s; H=syslin('c',(4*s+1)/(s^2*(s+1)*(2*s+1))) nyquist(H) show_margins(H,'nyquist') mtlb_axis([-20 20 -5 5]) ("We see from the locus that the point -1+j0 is encircled twice,hence N=2 and P=0.") printf("Therefore Z=2,hence two zeros lie in RHP") // N=P-Z printf("System is unstable")
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Ex3_1.sce
o//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 3 //example 3.1 //edition 1 //publisher and place:Nelson Engineering clc; clear; Vrms=110; //source voltage of the circuit in volts alpha=90; //triggering angle in degree Vm=Vrms*(2)^(1/2); //maximum voltage in volts Vave=(Vm/(2*%pi))*(1+cosd(alpha)); R=(0.2*(Vave)^(2))+5; //load resistance in ohm Iave=Vave/R; //average current of the load disp(Iave,'The average current when the triggering angle 90 degree in ampere is:')
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8_2.sce
clc; disp("Example 8.2") U=1.5 // in m/s d=0.025 // in m density= 1000 // in kg/m^3 mew=0.001 // in kg/ms Re=d*density*U/mew f=0.079/(Re^0.25) l=25 // length of the pipe in m delP=2*f*density*U*U*l/d h1=delP/(density*9.81) disp(h1,"Head loss is ") h2=15 h=h1+h2 flow=%pi*d*d*U*density/4 power=flow*h*9.81 disp(power,"Theoretical Power required is ")
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example5_8.sce
disp('chapter 5 ex5.8') disp('given') disp('Using the gain-bandwidth product estimate upper cut off frequencies') disp('741 op-amp') disp('fu=800kHz and Av=1') fu=800000 Av=1 disp('f2=fu/Av') f2=fu/Av disp('Hz',f2) disp('for unity gain R1=R2') disp('Av=(R1+R2)/R1') R1=R2 Av=(R1+R2)/R1 disp(Av) disp('f2=fu/Av') f2=fu/Av disp('Hz',f2)
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ex2_5.sce
//Chapter-2, Example 2.5, Page 92 //============================================================================= clc; clear; //INPUT DATA r=0.01;//radius in m lg=10^-3;//length of air gap in m Rm=(30/2)*10^-2;//mean radius in m ur=800;//relative permeability of iron ur2=1;//relative permeability of air gap N=250;//no of turns phi=20000*10^-8;//flux in Wb u0=4*%pi*10^-7;//permeability in free space a=%pi*(r)^2;//area of cross-section in m leakage_factor=1.1 //CALCULATIONS Reluctance_of_air_gap=(lg/(u0*ur2*a));//reluctance of air gap in A/wb li=(%pi*(2*r)-(lg));//length of iron path in m Reluctance_of_iron_path=((%pi*0.3)-(lg))/(4*%pi*10^-7*800*a);//in A/wb total_reluctance=Reluctance_of_air_gap+Reluctance_of_iron_path;//in A/wb MMF=phi*total_reluctance;//in Ampere turns current_required=(MMF)/(N);//in A //OUTPUT mprintf("Thus current required is %1.2f A \n",current_required); //Including leakage //CALCULATIONS MMF_of_airgap=phi*Reluctance_of_air_gap;//in A/wb Total_flux_in_ironpath=leakage_factor*phi;//in Wb MMF_of_ironpath=Total_flux_in_ironpath*Reluctance_of_iron_path;//in A Total_MMF=MMF_of_ironpath+MMF_of_airgap;//in A/wb current_required2=Total_MMF/(N);//in A //OUTPUT mprintf("Thus current required is %1.3f A",current_required2);
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clc; //let three intercepts are I1,I2,I3 I1=3; I2=-2; I3=3/2; //let their reciprocals are I1_1,I2_1,I3_1 I1_1=1/I1; I2_1=1/I2; I3_1=1/I3; //LCM of I1_1,I2_1,I3_1 are 6 . //By multiply LCM with I1_!,I2_1,I3_1 we will get miller indices LCM=6; M_1=LCM*I1_1; M_2=LCM*I2_1 ; M_3=LCM*I3_1; disp(M_1,'Miller indices of plane ='); disp(M_2); disp(M_3);
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kevät keväiks N;TRANS;PL mäki mäkkee N;IN+ALL;SG jää jäilt N;AT+ABL;PL hammaz hampahalle N;AT+ALL;SG kukka kukaaz N;IN+ESS;SG leipä leippää N;PRT;SG lupa luppaa N;PRT;SG jalka jaloille N;AT+ALL;PL ikä ikääz N;IN+ESS;SG iez ikehiil N;AT+ESS;PL daatša daatšast N;IN+ABL;SG nain naizilt N;AT+ABL;PL seppä seppoja N;PRT;PL kaunehusse kaunehuksille N;AT+ALL;PL öö öötä N;PRT;SG seppä sepälle N;AT+ALL;SG variz varikseel N;AT+ESS;SG pää päälle N;AT+ALL;SG kaunehusse kaunehuksii N;IN+ALL;PL lapsi lapseen N;ESS;SG meez meehiä N;PRT;PL tüär tüttääret N;NOM;PL korppi korpilt N;AT+ABL;SG näkö näkkööää N;PRT;SG voi voist N;IN+ABL;PL meez meehille N;AT+ALL;PL ikä ikält N;AT+ABL;SG lammaz lampahiil N;AT+ESS;PL kassen kastmelt N;AT+ABL;SG jalka jalalle N;AT+ALL;SG korppi korppiloja N;PRT;PL maa maalle N;AT+ALL;SG pökköiheinä pökköiheinääz N;IN+ESS;SG daatša daatšoja N;PRT;PL hüvä hüviiz ADJ;IN+ESS;PL kaunehusse kaunehuen N;GEN;SG käzi käen N;GEN;SG kevät keväeel N;AT+ESS;SG lammaz lampahaaz N;IN+ESS;SG silmä silmmiin N;ESS;PL seppä sepäst N;IN+ABL;SG hüvä hüvälle ADJ;AT+ALL;SG iez ikkeehen N;GEN;SG tüär tütäresse N;IN+ALL;SG järvi järvilöjä N;PRT;PL velli vellilöil N;AT+ESS;PL hammaz hampahaaz N;IN+ESS;SG säkki säkkii N;IN+ALL;SG hammaz hampahaks N;TRANS;SG vezi vezi N;NOM;SG velli velli N;NOM;SG voi voin N;ESS;SG izä izääl N;AT+ESS;SG kassen kastmet N;NOM;PL leipä leippiin N;GEN;PL aika aijjoilt N;AT+ABL;PL velli vellilöjä N;PRT;PL kukka kukiiz N;IN+ESS;PL leipä leippiiä N;PRT;PL aampuussen aampuustmiiz N;IN+ESS;PL ikä ikiks N;TRANS;PL pökköiheinä pökköiheiniil N;AT+ESS;PL voi voi N;NOM;SG izä izöille N;AT+ALL;PL jalka jalkoja N;PRT;PL kaunehusse kaunehuttee N;IN+ALL;SG meez meehiks N;TRANS;PL leipä leiviks N;TRANS;PL ikä ikkää N;IN+ALL;SG jää jäijjen N;GEN;PL mäki mäki N;NOM;SG voi voijjen N;GEN;PL juusso juusoks N;TRANS;SG päivä päiville N;AT+ALL;PL lupa luppaal N;AT+ESS;SG päivä päivän N;GEN;SG süän süämeez N;IN+ESS;SG kaunehusse kaunehuelt N;AT+ABL;SG käzi käeel N;AT+ESS;SG kaunehusse kaunehuksiil N;AT+ESS;PL maa maaz N;IN+ESS;SG tüär tütäreel N;AT+ESS;SG lapsi lapset N;NOM;PL meez meehen N;GEN;SG süän süämille N;AT+ALL;PL ikkuna ikkunoin N;GEN;PL maa maijen N;GEN;PL joki joet N;NOM;PL tähti täheks N;TRANS;SG hüvä hüvvää ADJ;PRT;SG siar sissaaret N;NOM;PL hüvä hüväst ADJ;IN+ABL;SG kassen kastmilt N;AT+ABL;PL nain naizet N;NOM;PL korppi korpist N;IN+ABL;SG ikkuna ikkunaan N;ESS;SG variz variksest N;IN+ABL;SG jää jäihe N;IN+ALL;PL leipä leiviiz N;IN+ESS;PL tähti tähelle N;AT+ALL;SG luu luil N;AT+ESS;PL vezi veet N;NOM;PL lupa luppaaz N;IN+ESS;SG korppi korpille N;AT+ALL;SG kuu kuuha N;IN+ALL;SG korppi korppiloil N;AT+ESS;PL tüär tütäriil N;AT+ESS;PL säkki säkiks N;TRANS;SG pökköiheinä pökköiheiniiä N;PRT;PL nain naisee N;IN+ALL;SG siar sizareel N;AT+ESS;SG lumi lumiloja N;PRT;PL daatša daatšaaz N;IN+ESS;SG säkki säkist N;IN+ABL;SG öö öihe N;IN+ALL;PL öö ööz N;IN+ESS;SG variz variksiil N;AT+ESS;PL kala kaloille N;AT+ALL;PL silmä silmmäin N;GEN;PL velli vellilöiks N;TRANS;PL kaunehusse kaunehueez N;IN+ESS;SG tähti täheez N;IN+ESS;SG kevät keväii N;IN+ALL;PL maa maihe N;IN+ALL;PL kaunehusse kaunehuksiin N;GEN;PL mäki mäkilöin N;ESS;PL aika aijjalle N;AT+ALL;SG joki jokiloille N;AT+ALL;PL ikkuna ikkunoille N;AT+ALL;PL silmä silmille N;AT+ALL;PL päivä päivää N;PRT;SG luu luihe N;IN+ALL;PL joki jokiloist N;IN+ABL;PL tüär tütäreks N;TRANS;SG järvi järvet N;NOM;PL velli vellelle N;AT+ALL;SG velli vellilöilt N;AT+ABL;PL lumi lunt N;PRT;SG juusso juussoo N;IN+ALL;SG kaunehusse kaunehueks N;TRANS;SG päivä päiviin N;GEN;PL daatša daatšoin N;GEN;PL mäki mäkilöist N;IN+ABL;PL süän süämmiia N;PRT;PL käzi käest N;IN+ABL;SG kassen kastmeen N;ESS;SG tähti tähilöilt N;AT+ABL;PL kevät keväesse N;IN+ALL;SG järvi järvilöis N;IN+ESS;PL näkö näöks N;TRANS;SG vezi vessiin N;GEN;PL tähti tähet N;NOM;PL lumi lumiloihe N;IN+ALL;PL juusso juussoloist N;IN+ABL;PL säkki säkkilöil N;AT+ESS;PL siar sizaria N;PRT;PL käzi käeks N;TRANS;SG päivä päänä N;ESS;SG meez meehelt N;AT+ABL;SG daatša daatšoiz N;IN+ESS;PL näkö näkölöilt N;AT+ABL;PL meez meehesse N;IN+ALL;SG lupa luviks N;AT+ABL;PL jää jääst N;IN+ABL;SG luu luult N;AT+ABL;SG kala kalalt N;AT+ABL;SG maa maist N;IN+ABL;PL lammaz lampahisse N;IN+ALL;PL luu luut N;NOM;PL joki joeks N;TRANS;SG jalka jalkaa N;IN+ALL;SG ikä ikkiin N;ESS;PL päivä päiväst N;IN+ABL;SG aampuussen aampuustmiin N;GEN;PL ikkuna ikkunaa N;IN+ALL;SG aika aijjast N;IN+ABL;SG voi voilt N;AT+ABL;SG mäki mäkkiiä N;PRT;SG olut oluizilt N;AT+ABL;PL ikä ikilt N;AT+ABL;PL lammaz lampahilt N;AT+ABL;PL tähti tähilöjä N;PRT;PL kuu kuille N;AT+ALL;PL lammaz lampahalt N;AT+ABL;SG joki joelt N;AT+ABL;SG kukka kukalt N;AT+ABL;SG luu luuhu N;IN+ALL;SG karhu karhu N;NOM;SG hüvä hüvvii ADJ;IN+ALL;PL käzi kässiin N;ESS;PL pökköiheinä pökköiheinille N;AT+ALL;PL hammaz hampahaal N;AT+ESS;SG lapsi lapseel N;AT+ESS;SG mäki mäest N;IN+ABL;SG lupa luppiin N;GEN;PL olut olutta N;PRT;SG süän süämelt N;AT+ABL;SG kala kallaan N;ESS;SG seppä sepoil N;AT+ESS;PL variz variz N;NOM;SG seppä sepäks N;TRANS;SG siar sizariin N;GEN;PL järvi järvilöil N;AT+ESS;PL süän süänt N;PRT;SG kala kalan N;GEN;SG maa maan N;GEN;SG joki jokiloja N;PRT;PL nain naizille N;AT+ALL;PL luu luilt N;AT+ABL;PL tüär tütärisse N;IN+ALL;PL seppä seppään N;ESS;SG olut oluiziin N;ESS;PL pökköiheinä pökköiheinälle N;AT+ALL;SG meez meehilt N;AT+ABL;PL karhu karhuuz N;IN+ESS;SG daatša daatšaan N;ESS;SG jää jääl N;AT+ESS;SG kala kaloil N;AT+ESS;PL tüär tütäriin N;GEN;PL daatša daatšalt N;AT+ABL;SG lupa luvast N;IN+ABL;SG vezi vessii N;IN+ALL;PL nain naiziks N;TRANS;PL lupa luvist N;IN+ESS;PL
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example2_10.sce
//example 2.10 //page 75 clc; funcprot(0); //initialisation of variable ybar=4; pi=3.14; A=4; Gamma=62.4; Ig=4^3/12; x1=2; x2=1.7; hbar=ybar+Ig/A/ybar; Fv1=2*A*Gamma; Fv2=pi*A*Gamma; Fv=Fv1+Fv2; disp(Fv,"vertical component of Hydrostatic force(lbs)="); xv=(Fv1*x1+Fv2*x2)/(Fv1+Fv2); disp(xv,"point of application of vertical force(ft)"); clear
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// SAMPLE PROBLEM 5/19 clc;clear;funcprot(0); // Given data v_B=150;// (i) m/s v_A=100;// (i) m/s rho=400;// m r=-100;// m // Calculation omega=v_B/rho;// (k) rad/s r_AB=r;// (j) m v_rel=[v_A-(v_B+(-(omega*r)))];// (i) m/s a_A=0;// m/s^2 a_B=(v_B(1))^2/rho;// m/s^2 omegadot=0;// rad/s a_rel=a_A-[a_B+(omegadot*r)+(omega*-(omega*r))+(2*(omega*v_rel))];// m/s^2 printf("\nThe instantaneous velocity,v_rel=%2.1fi m/s \nThe instantaneous acceleration,a=%1.2fk m/s^2",v_rel,a_rel); v_AB=v_A-v_B;// (i) m/s a_AB=a_A-a_B;// (j) m/s^2
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Try_moving_circles.sce
no_logfile = true; begin; picture { bitmap { preload = false; }dummy; x = 0; y = 0; bitmap { preload = false; }dummy2; x = 0; y = 0; } pic; trial { trial_type = fixed; trial_duration = stimuli_length; picture pic; }trial1; #====================================================== begin_pcl; # To copy Bannert & Bartels (2013) # periodicity 0.5 cycles / visual degree, expand or contract with 1 deg/s. # this later needs to be calibrated such that we make a high- and low luminance version, # where the green and red hue have been made equiluminant with a 162 cd/m^2 and a 198 cd/m^2 background. # (that is + and - 10% around the background luminance). # it needs to be combined with an ellipse with width and height to visual angle 7.19 deg (Bannert & Bartels 2013) # the background value (of the mask and in-between the colours of the circles) should be calibrated to be 180 cd/m^2 luminance. ### definitions ### # set the brightness values for the rgb channels that the maximum brightness should have array<double> brightred[3] = {255.0, 0, 0}; array<double> darkred[3] = {200.0, 0, 0}; array<double> brightgreen[3] = {0, 255.0, 0}; array<double> darkgreen[3] = {0, 200.0, 0}; # and the background colour array<double> background[3] = {127.5, 127.5, 127.5}; #these can later be overwritten by reading in a log file from a colour luminance matching script ################### # calculate the necessary background and amplitude numbers for the sine waves used in stimulus generation array<double> BR[6];# BR for 'Bright Red', array to be filled with {red background, red amplitude, g backgr, g amp, b backgr, b amp} BR[1] = (brightred[1] + background[1])/ 2.0;# red channel background (difference between brightest and darkest halved) BR[2] = (brightred[1] - background[1])/ 2.0;# red channel amplitude (average of brightest and darkest) BR[3] = (brightred[2] + background[2])/ 2.0;# green backgr (same thing, but inverted so that the period is inverse to that of the red channel) BR[4] = (brightred[2] - background[2])/ 2.0;# green amp BR[5] = (brightred[3] + background[3])/ 2.0;# blue BR[6] = (brightred[3] - background[3])/ 2.0;# blue # making an array of graphic surfaces with red-and-grey circles moving inward on each iteration vsg::circular_generator circlegen = new vsg::circular_generator( 25.0, 0.0, false );# the sinusoid circles are generated array<graphic_surface>redsurfaces[50];# empty surfaces vsg::graphic_generator graph_gen = new vsg::graphic_generator( 800.0, 600.0 ); graph_gen.add_transformation( circlegen, vsg::combine_none ); graph_gen.add_parameter_increment( circlegen, vsg::phase, 10.0 ); graph_gen.set_colors( BR[1], BR[2], BR[3], BR[4], BR[5], BR[6] );# red-and-grey circles graph_gen.draw( redsurfaces, 50 ); # making an array of green-and-grey inward moving circles array<graphic_surface>greensurfaces[50];# empty surfaces graph_gen.set_colors( 63.75, -63.75, 191.25, 63.75, 63.75, -63.75 );# green-and-grey circles graph_gen.draw( greensurfaces, 50 ); # making a mask that sets the screen surronding the cicrles to grey vsg::ellipse_generator ellipsegen = new vsg::ellipse_generator( 600.0, 600.0, 0.0 );# an ellipse to act as a mask vsg::graphic_generator graph_gen2 = new vsg::graphic_generator( 800.0, 600.0 ); graph_gen2.add_transformation( ellipsegen, vsg::combine_none ); graph_gen2.set_colors( 63.75, -63.75, 63.75, -63.75, 63.75, -63.75 );# grey background, black circle graphic_surface mask = graph_gen2.create(); mask.set_transparent_color( 0, 0, 0 ); # putting the mask in the picture pic.set_part( 2, mask ); # putting the red inward circles in the picture and presenting them loop int i = 1 until i > redsurfaces.count() begin pic.set_part( 1, redsurfaces[i] ); trial1.present(); wait_interval(20); i = i + 1; end; # putting the green inward circles in the picture and presenting them loop int i = 1 until i > greensurfaces.count() begin pic.set_part( 1, greensurfaces[i] ); trial1.present(); wait_interval(20); i = i + 1; end; # putting the red outward circles in the picture and presenting them loop int i = 1 until i > redsurfaces.count() begin pic.set_part( 1, redsurfaces[51 - i] ); trial1.present(); wait_interval(20); i = i + 1; end; # putting the green outward circles in the picture and presenting them loop int i = 1 until i > greensurfaces.count() begin pic.set_part( 1, greensurfaces[51 - i] ); trial1.present(); wait_interval(20); i = i + 1; end;
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Ex1_10.sce
clc,clear //example 1.10 //To find sine,cosine and tangent functions for 75 degree //triangle_ADB, angle_BAD = 30 AB=sqrt(3);BD=1; AD=sqrt(AB^2+BD^2); //pythagoras theorem //angle_DAB + angle_CAB = 75 //triangle_ABC, angle_BAC = 45 //pythagoras theorem and 45 degrees AC=AB/sqrt(2);BC=AC; angle_BAC = 45 ; angle_DAB = 30 ; angle_DAE = angle_BAC + angle_DAB ;//required angle angle_ADE = 90 - angle_DAE ;//complement of DAE angle_ADB = 90 - angle_DAB ;//complement of DAB //Draw BF perpendicular to DE angle_BDF = angle_ADB - angle_ADE; angle_DBF = 90 - angle_BDF; //complement of BDF //By pythagoras theorem and 45 degree DF=sqrt(BD/2);FB=DF; EC=FB;//parallel sides of rectangle FE= BC; //parallel sides of rectangle DE=DF+FE;//from the figure AE=AC-EC;//from the figure sin_DAE = DE/AD; cos_DAE = AE/AD; tan_DAE = DE/AE; csc_DAE = AD/DE; sec_DAE = AD/AE; cot_DAE = AE/DE; printf('sin(%d)=%f\n',angle_DAE,sin_DAE); printf('cos(%d)=%f\n',angle_DAE,cos_DAE); printf('tan(%d)=%f\n',angle_DAE,tan_DAE); printf('csc(%d)=%f\n',angle_DAE,csc_DAE); printf('sec(%d)=%f\n',angle_DAE,sec_DAE); printf('cot(%d)=%f\n',angle_DAE,cot_DAE);
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Example7_2.sce
// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 7: PARALLEL OPERATION // Example 7-2 clear; clc; close; // Clear the work space and console. // Given data R_a = 0.1 ; // Armature resistance in ohm R_f = 100 ; // Field ckt resistance in ohm V_L_b = 120 ; // Bus voltage in volt V_L_a = 140 ; // Voltage of the generator in volt V_f = V_L_a ; // Voltage across the field in volt // Calculations // case a I_f_a = V_f / R_f ; // Field current in A I_a_a = I_f_a ; // Armature current in A E_g_a = V_L_a + I_a_a * R_a ; // Generated EMF in volt P_g_a = E_g_a * I_a_a ; // Generated power in W // case b I_a_b = ( E_g_a - V_L_b ) / R_a ; // Armature current in A I_f_b = V_L_b / R_f ; // Field current in A I_Lg = I_a_b - I_f_b ; // Generated line current in A P_L = V_L_b * I_Lg ; // Power generated across the lines in W E_g_b = V_L_a ; P_g_b = E_g_b * I_a_b ; // Generated power in W // Display the results disp("Example 7-2 Solution : "); printf(" \n a: Before it is connected to the bus "); printf(" \n I_a = I_f = %.1f A \n E_g = %.2f V\n P_g = %.1f W \n", I_a_a,E_g_a,P_g_a); printf(" \n b: After it is connected to the bus "); printf(" \n I_a = %.1f A \n I_f = %.1f A \n I_Lg = %.1f A \n", I_a_b, I_f_b, I_Lg ); printf(" \n P_L = %.f W \n P_g = %.f W ", P_L , P_g_b );
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//Ex5_4 clc Idc = 10*10^-3 Irms = 14*10^-3 RL = 1*10^3 Pdc = (Idc^2)*RL Pac = (Irms^2)*RL disp("Idc = "+string(Idc)+"A")//D.C. current disp("Irms = "+string(Irms)+"A")//rms current disp("RL = "+string(RL)+"ohm")//load resistance disp("Pdc = (Idc^2)*RL = "+string(Pdc)+"W")//D.C. power disp("Pac = (Irms^2)*RL = "+string(Pac)+"W")//A.C. power disp("eta_r = Pdc/Pac = "+string(Pdc/Pac*100)+"%")//Rectification efficiency
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clear;lines(0); s1=ssrand(1,1,2); s2=ss2tf(s1); [s1,s2]=sysconv(s1,s2);
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//To determine the sum and difference of two alternating voltage sources clc; clear; //Phase angles tv1=0; tv2=-%pi/6; //Taking v1 as reference voltage v1=110*(expm(%i*tv1)); v2=80*(expm(%i*tv2)); Vs=v1+v2;//Sum Vd=v1-v2;//Difference ts=atand(imag(Vs)/real(Vs)); td=atand(imag(Vd)/real(Vd)); printf('i) The sum = %g sin(wt + (%g(degrees))) V\n',abs(Vs),ts) printf('i) The difference = %g sin(wt + (%g(degrees))) V\n',abs(Vd),td)
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//Ex:24 clc; clear; close; a=0.25;//Roll_off r_s=16*10^3;//Symbol rate in Hz B_s=r_s*(1+a);//signal BW in Hz f_c=14.125*10^6;// in Hz f_min=f_c-(B_s)/2;//min frequency in Hz f_max=f_c+(B_s)/2;//max frequency in Hz //printf("min frequency=%f MHz",B_s); printf("min frequency=%f MHz", f_min/10^6); printf("\n max frequency=%f MHz",f_max/10^6); //Hence frequency range of transmitted signal is from 14.115 MHz to 14.135 MHz
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Ex4_1.sce
Ex1 pg61 clear //find the area piston for given parameters //given a=3. //diameter squared //calculation A=0.785*3**2 printf("\n area of piston %.2f ",A)
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example_5_3.sce
syms G1 G2 H1 H2 a=G2/(1+(G2*H2)) b= G1*a c= H1*(1+G2*H2)/G2 //shifting the take off point d= b/(1+b) Y= d/(1+(d*c)) disp(Y," R/C = ")
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Ex1_5.sce
//=========================================================================== //chapter 1 example 5 clc; clear all; //intercepts given are a,2b,-3c/2 //from the law of rational indices //a:2b:-3c/2=a/h:b/k:c/l //variable declaration h1 = 1; //miller indices k1 = 1/2; //miller indices l1 = -2/3; //miller indices //calculation p = int32([1,2,3]); l2 = lcm(p); h=h1*l2; k=(k1)*double(l2); l=(l1)*double(l2); //result mprintf('miller indices = %d %d %d',h,k,l); //============================================================================
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example4_2.sce
//exapple 4.2 clc; funcprot(0); // Initialization of Variable rd=[0 1 2.5 5 10 15 17.5]/100;//radial distance from pipe dlv=[0 0.2 0.36 0.54 0.81 0.98 1]/100;//differnce in liquid levels r=[.175 .165 .150 .125 .075 .025 0];// g=9.81; R=8.314; rho=999; temp=289; P1=148*1000; M=7.09/100; pi=3.12 rhoCl2=P1*M/R/temp;//density of Cl2 nuCl2=1/rhoCl2;//specific volume of Cl2 function[y]=P2(x); y=P1+x*(rho-rhoCl2)*g; endfunction for i=1:7 y=P2(dlv(i)); u(i)=sqrt(2*P1*nuCl2*log(y/P1)); a(i)=u(i)*r(i); end clf(); plot(r,a); xtitle("","r (m)","u*r (m^2/s)"); s=0; for i=1:6//itegration of the plotted graph s=abs((r(i)-r(i+1))*.5*(a(i)+a(1+1)))+s; end s=s-0.01; Q=2*pi*s; disp(Q,"volumetric flow rate (m^3/s):"); disp(Q*rhoCl2,"mass flow rate of chlorine gas (kg/s)")
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style.fontSize=12; style.displayedLabel="<table> <tr> <td><b>S<br><br>G</b></td> <td></td> <td></td> <td>PFET</td> <td></td> <td></td> <td align=left><b>D</b></td> </tr> </table>"; pal2 = xcosPalAddBlock(pal2,"pfet_gldn",[],style);
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clc A = 40000 // number of units per year I = 25 // carrying cost in percent I = I/100 C1 = 8 // cost for 0 < N < 1000 per unit in Rs C2 = 7.5 // cost for 1000 < N < 10000 per unit in Rs C3 = 7.25 // cost for N >= 10000 per unit in Rs R = 250 // ordering cost per order in Rs N = 10000 // units N1 = sqrt(2*R*A/(I*C3)) // optimal quantity for lowest curve G1= C3*A+(A*R)/N+I*C3*N/2 // total cost in Rs N2 = sqrt(2*R*A/(I*C2)) // optimal quantity for higher curve G2= C2*A+(A*R)/N2+I*C2*N2/2 // total cost in Rs N3 = sqrt(2*R*A/(I*C1)) // optimal quantity for highest curve G3 = C1*A+(A*R)+1 // total cost in Rs printf("\n Total cost for lowest cost curve = Rs %0.2f\n Total cost for next higher curve = Rs %0.2f\n Total cost for highest curve = Rs %0.2f " , G1,G2,G3) disp("Comparing all total cost lowest is Rs 300,062.50 for an order quantity of 10,000.") disp("N = 10,000 and No. of orders = 4")
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example11_28.sce
clc // Given that r = 0.5 // ratio of length of rod when it is in motion to the length of the rod when it is in rest // Sample Problem 28 on page no. 11.29 printf("\n # PROBLEM 28 # \n") printf(" Standard formula used \n") printf(" l = l_0/((1-v^2/c^2)^1/2) \n") v = 3e8 * sqrt(1 - r^2) printf("\n Speed of the rod relative to observer is %f c.",v/3e8)
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//To calculate the ratio of the seperation between successive lattice planes h1 = 1; k1 = 0; l1 = 0; //for (100) plane x1 = sqrt(h1^2+k1^2+l1^2); h2 = 1; k2 = 1; l2 = 0; //for (110) plane x2 = sqrt(h2^2+k2^2+l2^2); h3 = 1; k3 = 1; l3 = 1; //for (111) plane x3 = sqrt(h3^2+k3^2+l3^2); //d = a/sqrt(h^2+k^2+l^2) //d100:d110:d111 = a:a/sqrt(2):a/sqrt(3) //d100:d110:d111 = 1:1/sqrt(2):1/sqrt(3) = 1:0.71:0.58 printf("ratio of the seperation between successive lattice planes is 1:0.71:0.58");
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// Example 7.4;//inernal power level clc; clear; close; e=1.6*10^-19;//Electronic charge ht=6.62*10^-34;//Constt C=3*10^8;//sPPED OF LIGHT IN M/S h=0.87*10^-9;//wavelength in meter i=40;//injected current in milli ampere nint= 0.625;//inernal quantum efficieny Pint= (nint*((ht*C*i*10^-3)/(e*h)));//internal power level in milli watt disp(Pint,"internal power level in milli watt")
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function CercleCorrel(caraCentreReduit) t=0:0.00001:2*%pi; plot(0.5 * cos(t), 0.5 * sin(t)); plot(cos(t), sin(t)); [n1, n2] = size(caraCentreReduit); for i=1:n2; plot(caraCentreReduit(1,i), caraCentreReduit(2,i), ".r"); end endfunction function [tableauCR] = tableauCentreReduit(tableau) tableauC = tableauCentre(tableau) tableauCR = tableauReduit(tableauC) endfunction function [retour] = tableauCentre(tableau) [nbIndiv,nbCarac] = size(tableau) moyenneColonnes = mean(tableau,1) for tabIndLig = 1:nbIndiv for tabIndCol = 1:nbCarac tableau(tabIndLig,tabIndCol) = tableau(tabIndLig,tabIndCol) - moyenneColonnes(tabIndCol) end end retour = tableau endfunction function [retour] = tableauReduit(tableau) [nbIndiv,nbCarac] = size(tableau) for tabIndCol = 1:nbCarac tabEcartTypes(tabIndCol)=(1/sqrt(nbIndiv))*norm(tableau(:,tabIndCol)) end retour = tableau for tabIndCol = 1:nbCarac retour(:,tabIndCol) = tableau(:,tabIndCol) /tabEcartTypes(tabIndCol) end endfunction function [composante1,composante2] = composantePrincipale(vecteurPropre1, vecteurPropre2, tableauCR) [nbIndiv,nbCarac] = size(tableauCR) composante1 = tableauCR*vecteurPropre1 composante2 = tableauCR*vecteurPropre2 endfunction function[vap,vep]=valsP(matCorrel) [vep,diagevals]=spec(matCorrel) vap=diag(diagevals) endfunction function [retour] = matriceCorrelation(tableau) [nbIndiv, nbCarac] = size(tableau); for tabIndColA = 1:nbCarac for tabIndColB = 1:nbCarac disp(tableau(:, tabIndColA)) matCorr(tabIndColA, tabIndColB) = tableau(:, tabIndColA)'*tableau(:, tabIndColB) matCorr(tabIndColA, tabIndColB) = (1/nbIndiv)*(matCorr(tabIndColA, tabIndColB)) end end retour = matCorr endfunction function [retour] = functionBase(valeurP, vectP) retour = [0;0] disp(retour) [m, k] = max(valeurP, 'r') valeurP(k,1) = -1000 disp("k :") disp(k) [m2, k2] = max(valeurP, 'r') valeurP(k2,1) = -1000 retour(1,1) = vectP(k,1) retour(2,1) = vectP(k2,1) endfunction function qualite = QualiteRepresentationIndividu(Base,Z, comp1, comp2) nbIndividu = size(Z,"r"); nbAxe = size(Base,"c"); Q2 = zeros(nbIndividu,2); for i = 1 : nbIndividu scal = ((Z(i,:)')'*(Base(:,comp1))); norme = norm(Z(i,:)); Q2(i,1) = (scal*scal/(norme*norme)); scal = ((Z(i,:)')'*(Base(:,comp2))); norme = norm(Z(i,:)); Q2(i,2) = (scal*scal/(norme*norme)); end endfunction function [vap, vep]=valsP(A) [vep, diagevals]=spec(A) vap=diag(diagevals) endfunction function nuagePoints(MatCoord,i,j); xset("font",4,3); x = (max(MatCoord(:, i)) - min(MatCoord(:, i))) / 20; xmin = min(MatCoord(:, i)) - x; xmax = max(MatCoord(:, i)) + x; y = (max(MatCoord(:, j)) - min(MatCoord(:, j))) / 20; ymin = min(MatCoord(:, j)) - y; ymax = max(MatCoord(:, j)) + y; plot2d(MatCoord(:, i),MatCoord(:, j), -3, "031", rect = [xmin,ymin,xmax,ymax]); n = size(MatCoord, "r"); for l = 1:n, xstring(Coord(l, i), MatCoord(l, j), string(l)); end; endfunction; function execProjet() [fd,SST,Sheetnames,Sheetpos] = xls_open('Voitures.xls') [m,TextInd] = xls_read(fd,Sheetpos(1)) mclose(fd) tabCR = tableauCentreReduit(m); matCor = matriceCorrelation(tabCR); [valeursP, vecteursP] = valsP(matCor); basePlan = functionBase(valeursP, vecteursP); //qualite = QualiteRepresentationInd0(basePlan, ??? [composante1, composante2] = composantePrincipale(vecteursP(:,1), vecteursP(:,2), tabCR); CercleCorrel(tabCR); //nuagePoints(?, ?, ?); endfunction
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//Exa 2.28 clc; clear; close; //Given data : format('v',6); phase=3;//no. of phase Efficiency=90;//in % Speed=480;//in rpm VL=400;//in volt IL=75;//in Ampere cosfi=0.77;//powerfactor(unitless) d=0.75;//diameter of pulley in meter Pin_motor=sqrt(3)*VL*IL*cosfi;//Power input of motor in watts OutputPower=Pin_motor*Efficiency/100;//in watts Omega=Speed*2*%pi/60;//angular speed in radians/sec Torque=OutputPower/Omega;//in N-meter Torque=Torque/9.81;//in Kg-meter PullOnBelt=Torque/(d/2);//in Kg disp(PullOnBelt,"Pull On Belt(in Kg.) : ");
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CD=4;//given in m BD=3;//given in m Loadc=30;//given in KN
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//pagenumber 306 example 28 clear re=4*10^3;//ohm r1=4*10^3;//ohm hie=1.1*10^3;//ohm resist=10*10^3;//ohm hfe=50; rb=10*10^3;//ohm r=1*10^3;//ohm colres=5*10^3;//ohm //(1) current gain ri=rb*hie/(rb+hie); curgai=(1/2.04)*((rb)/(rb+hie))*((-hfe*colres)/(colres+r1)); disp("current gain = "+string((curgai))); //(2) voltage gain volgai=curgai*r1/r; disp("voltage gain = "+string((volgai))); //(3) tranconductance conduc=volgai/r1; disp("transconductance = "+string((conduc))+"ampere per volt"); //transresistance resist=resist*volgai; disp("transresistance = "+string((resist))+"ohm"); disp("input resistance = "+string((ri))+"ohm"); r=(40*10^3*colres)/(40*10^3+colres); disp("output resistance = "+string((r))+"ohm");
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function [stk,txt,top]=%m2sci() // multiplications //! // Copyright INRIA txt=[] s1=stk(top-1) s2=stk(top) [e1,te1]=s1(1:2); [e2,te2]=s2(1:2); if s1(5)=='10' then e1='str2code('+e1+')''',te1='0',end if s2(5)=='10' then e2='str2code('+e2+')''',te2='0',end // if te2=='2' then e2='('+e2+')',end if te1=='2' then e1='('+e1+')',end if s1(3)=='1'&s1(4)=='1' then stk=list(e1+'*'+e2,'1',s2(3),s2(4),s1(5)) elseif s2(3)=='1'&s2(4)=='1' then stk=list(e1+'*'+e2,'1',s1(3),s1(4),s1(5)) else stk=list(e1+'*'+e2,'1',s1(3),s1(4),s1(5)) end top=top-1
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load('C:\Users\DimitriXPS\Documents\GitHub\Exolife\Exolife\Images\Mission 8\Asellus Secundus.dat'); imgF=ifft(imgT); display_gray(imgF);
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function [x,y,typ]=standard_inputs(o) //get position of inputs ports and clock inputs port for a standard block // the input ports are located on the left (or rigth if tilded) vertical // side of the block, regularly located from top to bottom // the clock input ports are located on the top horizontal side // side of the block, regularly located from left to right xf=60 yf=40 graphics=o(2) model=o(3) orig=graphics(1);sz=graphics(2);orient=graphics(3); inp=size(model(2),1);clkinp=size(model(4),1); if orient then xo=orig(1) dx=-xf/7 else xo=orig(1)+sz(1) dx=yf/7 end if inp==0 then x=[];y=[],typ=[] else y=orig(2)+sz(2)-(sz(2)/(inp+1))*(1:inp) x=(xo+dx)*ones(y) typ=ones(x) end if clkinp<>0 then x=[x,orig(1)+(sz(1)/(clkinp+1))*(1:clkinp)] y=[y,(orig(2)+yf/7+sz(2))*ones(1,clkinp)] typ=[typ,-ones(1,clkinp)] end
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.265733D+00 2 -0.173867D-02 0.210933D-02 3 0.506146D-01 -0.750560D-03 0.217133D+00 4 -0.104650D-02 0.309522D-03 -0.181929D-02 0.181063D-02 5 -0.157246D-02 0.122903D-04 0.344173D-03 0.111081D-03 0.353073D-02 6 0.322033D-03 0.306610D-04 -0.207022D-03 0.232250D-04 -0.113082D-03 7 -0.670430D-03 -0.140392D-03 0.407760D-03 0.167556D-03 0.746361D-03 8 0.657923D-05 0.356076D-05 -0.401530D-03 0.161652D-05 0.997348D-04 9 -0.425268D+00 0.216252D-01 -0.700215D-01 0.157608D-01 0.525660D-01 10 -0.379609D+00 -0.106122D-02 0.876288D-01 -0.178164D-02 0.166697D+00 11 0.202745D-01 0.591999D-02 -0.119877D-01 0.160371D-01 0.259052D-02 12 0.236517D-01 0.275086D-01 -0.373587D+00 0.491734D-01 0.326913D-01 13 0.490524D-01 -0.450667D-02 0.312392D-01 0.606415D-03 -0.568520D-02 14 -0.333532D+00 0.456530D-02 -0.464089D+00 0.653746D-02 0.268827D-01 15 -0.231205D+01 -0.250598D-01 -0.352082D+00 -0.640470D-02 -0.708966D-01 16 -0.169365D-01 -0.740061D-02 -0.133053D-01 0.401433D-03 0.109245D-03 17 0.574940D-02 0.101087D-03 0.175180D-02 -0.539796D-05 -0.423199D-03 18 -0.213897D+00 -0.179131D-01 -0.346788D+00 -0.149798D-01 -0.191193D-01 19 -0.730114D-01 -0.184043D-02 0.503562D-01 0.319624D-02 0.427227D-02 20 -0.108719D-01 0.556486D-02 -0.473462D+00 -0.242212D-01 -0.146365D-01 21 0.645428D-01 -0.137966D-03 -0.772375D-01 -0.232107D-02 -0.424836D-02 22 0.831876D-04 0.113522D-03 0.229148D-02 -0.594559D-04 -0.767956D-04 23 -0.776640D-03 -0.312273D-03 0.216399D-02 -0.509431D-02 0.981160D-03 24 -0.458515D-03 -0.154724D-03 -0.210745D-02 0.106221D-03 -0.733797D-04 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 0.662597D-03 7 0.737404D-03 0.371135D-02 8 0.184193D-03 -0.294011D-03 0.240168D-02 9 -0.124855D-02 0.360638D-01 -0.158206D-01 0.346604D+02 10 -0.679125D-02 0.290404D-01 0.958046D-02 0.205111D+01 0.165374D+02 11 0.940333D-02 0.661088D-02 0.754585D-02 0.627137D+01 0.170613D+01 12 0.515249D-02 -0.503080D-03 0.605426D-01 0.822975D+01 0.124715D+01 13 0.446081D-01 0.112024D+00 0.325539D-01 0.219785D+01 0.689648D+00 14 0.227426D-01 0.162919D-01 0.176468D+00 0.232925D+01 0.398653D+01 15 -0.167992D-01 -0.160149D-01 -0.380161D-01 0.160180D+01 -0.288601D+01 16 -0.157423D-03 0.187525D-02 -0.687326D-03 0.567059D+00 -0.213104D-01 17 0.564658D-04 0.344837D-04 0.261133D-03 -0.112688D+00 -0.385561D-01 18 -0.170500D-01 -0.772948D-01 -0.224295D-01 -0.352815D-01 -0.163868D+01 19 -0.466726D-02 0.122654D-01 -0.753491D-02 0.112108D+01 0.678021D+00 20 -0.119544D-01 0.354352D-01 -0.121242D+00 -0.638474D+00 -0.133385D+01 21 0.471848D-02 -0.147572D-01 0.964364D-02 -0.903700D+00 -0.548075D+00 22 -0.145266D-03 -0.137247D-03 -0.546421D-04 -0.271135D-01 -0.181672D-01 23 -0.329916D-03 -0.133095D-02 0.107858D-02 0.407328D-01 -0.349524D-01 24 0.148003D-05 -0.831640D-04 -0.374716D-03 -0.911321D-02 -0.156543D-02 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 0.291158D+02 12 0.118443D+02 0.124900D+03 13 -0.674608D+00 0.323414D+01 0.114330D+02 14 0.450367D+00 0.106294D+02 0.291702D+01 0.446597D+02 15 -0.554791D+01 -0.101668D+01 -0.687408D+01 0.215748D+01 0.179758D+03 16 0.129238D+00 0.162932D+00 0.787440D-01 -0.597721D-01 0.157273D+01 17 -0.348795D-02 0.416070D-01 0.243505D-01 -0.129330D-01 -0.848746D+00 18 -0.366333D+01 -0.666705D+01 -0.474553D+01 -0.388015D+00 0.211112D+02 19 0.157041D+01 -0.294088D+00 -0.373102D+00 -0.591401D+00 0.281546D+01 20 0.140526D+01 -0.241852D+02 -0.213763D+01 -0.174842D+02 -0.394715D+00 21 -0.122185D+01 0.274384D+00 0.403484D+00 0.794746D+00 -0.243397D+01 22 -0.388121D-01 0.445939D-01 -0.733196D-02 -0.103919D-01 -0.169573D-01 23 0.150359D+00 0.445506D+00 -0.583364D-01 0.145333D+00 -0.246374D+00 24 -0.352603D-01 -0.345025D-01 -0.480427D-02 -0.511679D-01 0.460797D-01 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 0.356463D+00 17 -0.222456D-01 0.109049D-01 18 0.244751D+00 -0.582990D-01 0.830390D+02 19 0.107811D+00 -0.274254D-01 0.663663D+00 0.277291D+01 20 -0.290051D-01 0.379871D-01 0.121081D+02 -0.596768D-01 0.134469D+03 21 -0.888706D-02 0.177289D-01 0.798377D+00 -0.252777D+01 0.281456D+00 22 -0.497742D-02 0.369921D-03 -0.362503D+00 -0.574851D-02 -0.850993D-01 23 0.140560D-02 0.368394D-02 0.126524D+00 -0.499830D-01 0.159742D+01 24 0.217450D-02 -0.484674D-03 -0.302952D-01 0.204857D-02 -0.623537D+00 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 0.287846D+01 22 -0.122599D-01 0.438813D-02 23 0.102963D+00 -0.254890D-02 0.238354D+00 24 -0.599097D-02 0.803343D-03 -0.205676D-01 0.740212D-02 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 1.000 2 -0.073 1.000 3 0.211 -0.035 1.000 4 -0.048 0.158 -0.092 1.000 5 -0.051 0.005 0.012 0.044 1.000 6 0.024 0.026 -0.017 0.021 -0.074 7 -0.021 -0.050 0.014 0.065 0.206 8 0.000 0.002 -0.018 0.001 0.034 9 -0.140 0.080 -0.026 0.063 0.150 10 -0.181 -0.006 0.046 -0.010 0.690 11 0.007 0.024 -0.005 0.070 0.008 12 0.004 0.054 -0.072 0.103 0.049 13 0.028 -0.029 0.020 0.004 -0.028 14 -0.097 0.015 -0.149 0.023 0.068 15 -0.335 -0.041 -0.056 -0.011 -0.089 16 -0.055 -0.270 -0.048 0.016 0.003 17 0.107 0.021 0.036 -0.001 -0.068 18 -0.046 -0.043 -0.082 -0.039 -0.035 19 -0.085 -0.024 0.065 0.045 0.043 20 -0.002 0.010 -0.088 -0.049 -0.021 21 0.074 -0.002 -0.098 -0.032 -0.042 22 0.002 0.037 0.074 -0.021 -0.020 23 -0.003 -0.014 0.010 -0.245 0.034 24 -0.010 -0.039 -0.053 0.029 -0.014 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 1.000 7 0.470 1.000 8 0.146 -0.098 1.000 9 -0.008 0.101 -0.055 1.000 10 -0.065 0.117 0.048 0.086 1.000 11 0.068 0.020 0.029 0.197 0.078 12 0.018 -0.001 0.111 0.125 0.027 13 0.513 0.544 0.196 0.110 0.050 14 0.132 0.040 0.539 0.059 0.147 15 -0.049 -0.020 -0.058 0.020 -0.053 16 -0.010 0.052 -0.023 0.161 -0.009 17 0.021 0.005 0.051 -0.183 -0.091 18 -0.073 -0.139 -0.050 -0.001 -0.044 19 -0.109 0.121 -0.092 0.114 0.100 20 -0.040 0.050 -0.213 -0.009 -0.028 21 0.108 -0.143 0.116 -0.090 -0.079 22 -0.085 -0.034 -0.017 -0.070 -0.067 23 -0.026 -0.045 0.045 0.014 -0.018 24 0.001 -0.016 -0.089 -0.018 -0.004 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 1.000 12 0.196 1.000 13 -0.037 0.086 1.000 14 0.012 0.142 0.129 1.000 15 -0.077 -0.007 -0.152 0.024 1.000 16 0.040 0.024 0.039 -0.015 0.196 17 -0.006 0.036 0.069 -0.019 -0.606 18 -0.075 -0.065 -0.154 -0.006 0.173 19 0.175 -0.016 -0.066 -0.053 0.126 20 0.022 -0.187 -0.055 -0.226 -0.003 21 -0.133 0.014 0.070 0.070 -0.107 22 -0.109 0.060 -0.033 -0.023 -0.019 23 0.057 0.082 -0.035 0.045 -0.038 24 -0.076 -0.036 -0.017 -0.089 0.040 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 1.000 17 -0.357 1.000 18 0.045 -0.061 1.000 19 0.108 -0.158 0.044 1.000 20 -0.004 0.031 0.115 -0.003 1.000 21 -0.009 0.100 0.052 -0.895 0.014 22 -0.126 0.053 -0.601 -0.052 -0.111 23 0.005 0.072 0.028 -0.061 0.282 24 0.042 -0.054 -0.039 0.014 -0.625 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 1.000 22 -0.109 1.000 23 0.124 -0.079 1.000 24 -0.041 0.141 -0.490 1.000
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FOSSEE/Scilab-TBC-Uploads
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Ex23_2.sce
// Initilization of variables m=600 // kg // mass of the roller r=0.25 // m // radius of the roller P=850 // N // Force v=3 // m/s // velocity to be acquired theta=30 // degree // angle made by v with the force P // Calculations // The distance required to be rolled is given by equating the Work done between positions 1 & 2 as, x=((3/4)*m*v^2)/(P*cosd(theta)) // m // Results clc printf('The distance required to be rolled is %f m \n',x)
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mandar15/NLP_Project
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2013-07-31T06:53:59
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bow.11_12.tst
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clear; clc; vf=3; VA=8000; dQ=vf/100 * VA mprintf("capacity of SVS= +- %d MVAR", dQ);
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@relation tic-tac-toe @attribute TopLeft{x,o,b} @attribute TopMiddle{x,o,b} @attribute TopRight{x,o,b} @attribute MiddleLeft{x,o,b} @attribute MiddleMiddle{o,b,x} @attribute MiddleRight{o,b,x} @attribute BottomLeft{x,o,b} @attribute BottomMiddle{o,x,b} @attribute BottomRight{o,x,b} @attribute Class{positive,negative} @inputs TopLeft, TopMiddle, TopRight, MiddleLeft, MiddleMiddle, MiddleRight, BottomLeft, BottomMiddle, BottomRight @outputs Class positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive positive negative negative negative negative negative negative negative positive negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative positive negative positive negative negative negative positive negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative
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Bit.tst
load Bit.hdl; output-file Bit.out; output-list in load out; set in 1, set load 1, // set address 0, tick, output; tock, output; set in 1, set load 0, // set address 0, tick, output; tock, output; set in 0, set load 1, // set address 0, tick, output; tock, output;
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// Exa D.2 // what is the location of the modulo-2 adder for the second m-sequence? Generate the second m-sequence. clc; clear all; //solution disp("The location of modulo-2 adder for the second m-sequence is shown in Figure D.5(in the book)i.e Modulo-2 adder should be between first(x1) and second(x2) shift register."); x=[0 0 1]; //Initial stage output=x(3); disp("Second m-sequence usinf 3-stage register"); disp(" x1 x2 x3 output"); printf(' Initial %d %d %d %d \n ',x(1),x(2),x(3),output); for i= 1:7 printf('Shift %d',i); x(3)=x(2); if(x(3)==1) //TO get values in range of [-1 1] for plot dummy(i)=-1 else dummy(i)=1; end x(2)=x(1); if(output== 1& x(2)==1) //As new x(1)=prev stage x(3) ored prev stage x(2) x(1)=0; else if(output== 0& x(2)==0) x(1)=0; else x(1)=1; end end printf(' %d %d %d ',x(1),x(2),x(3)); output=x(3); printf(' %d',output); printf('\n '); end figure(1); bar(dummy,0.2,'green'); xlabel("Time","FontSize",5); title("7-chip second m-sequence for one T period","FontSize",5); disp("The properties of m-sequence in Figure(1)are -"); disp("Number of -1s = 4 , Number of 1s = 3 "); disp("Run length 1 = 2 , Run length 2 = 1"); disp("Run length = 1");
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//check o/p for more than one i/p arg r = [1 2 4;2 3 1; 4 5 2]; z=[2]; [a,efinal] = ac2poly(r,z); disp(a); disp(efinal); // Output // !--error 58 //Wrong number of input arguments.at line 4 of exec file called by : //oly/ac2poly5.sce', -1
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a=[0 0 0 0 0 0 0]; b=poly2rc(a); disp(b); //output // !--error 10000 //Leading coefficient cannot be zero. //at line 42 of function poly2rc called by : //b=poly2rc(a);
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Ex2_4_1.sce
clear clc T=303;//in K m2=10;//mass of solute in gm m1=80;//mass of solute acetone in gm P1=271;//in torr P2=283;//in torr M1=58;//in gm/mol M2=((m2*M1)/(((P2-P1)/P2)*m1))-((M1*m2)/m1) printf('M2=%.1f gm/mol',M2) //page 39
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clear; clc; // Stoichiometry // Chapter 7 // Combustion // Example 7.12 // Page 478 printf("Example 7.12, Page 478 \n \n"); // solution // basis 100 kmol of dry producer gas C = 33*12 // kg O2 = 18.5*32 //kg H2 = 20*2 // kg O2air = 21*51/79 // kmol COALgassified = 396/.672 // kg O2coal = COALgassified*.061/32 // kmol tO2 = O2coal + O2air O2steam = 18.5-tO2 // kmol H2steam = 2*O2steam // kmol H2fuel = 20-H2steam dryproducergas = 100*22.41/COALgassified // Nm^3/kg coal Pw = 2.642 // kPa Ha = Pw/(100.7-Pw) // kmol/kmol dry gas water = Ha*100 moistproducergas = (100+water)*22.41/COALgassified // Nm^3/kg coal dryair = (51*28+O2air*32)/COALgassified // kg/kg coal tsteamsupplied = H2steam+water-(COALgassified*.026/18) // kmol steam = tsteamsupplied*18/COALgassified printf(" (a) \n \n Moistproducer gas obtained = "+string(moistproducergas)+" Nm^3/kg coal. \n \n \n (b) \n \n Air supplied = "+string(dryair)+" kg/kg coal gassified. \n \n \n (c) \n \n Steam supplied = "+string(steam)+" kg/kg coal.")
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function [Er,Ar,Q,Z]=epsfin(E,A) // Returns the epsilon + finite part of the pencil sE-A // Z right subspace associated with epsilon and finite part // For a regular pencil Z spans the right finite eigenspace // FD & RN (see fineta macro) [LHS,RHS]=argn(0) if RHS==1 then [E,A]=pen2ea(E);end E=pertrans(E);A=pertrans(A); [Er,Ar,Z,Q]=fineta(E,A); Er=pertrans(Er);Ar=pertrans(Ar); Z=pertrans(Z);Q=pertrans(Q);
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clc; m=9*10^-31; //mass of electron in kg q=-3.2*10^-7; //charge in C e=-1.6*10^-19; //charge on electron in C n=(q/e); //calculating n M=n*m; //calculating mass transfered disp(n,"no. of electrons = "); //displaying result disp(M,"Mass transfered to polythene in kg = "); //displaying result
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/* Sa se rezolve sistemele algebrice de ecuatii liniare incompatibile in sensul celor mai mici patrate: x1 − 3x2 + x3 + x4 = 1 x1 − 3x2 + x3 − 2x4 = −1 x1 − 3x2 + x3 + 5x4 = 6 */ A=[1, -3, 1, 1;1, -3, +1, -2;1, -3, 1, +5]; b=[1;-1;6]; det(A) x=lsq(A,b) linsolve(A,-b)
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// calculating the signal to noise ratio at input // calculating the signal to noise ratio at output //calculating the noise factor and noise figure clc; disp('signal to noise ratio at input') Sni=(3*10^-6/(1*10^-6))^2; disp(Sni,'signal to noise ratio at input=') disp('signal to noise ratio at output') Sno=(60*10^-6/(20*10^-6))^2; disp(Sno,'signal to noise ratio at output=') disp('New signal to noise ratio at output') Snno=(60*10^-6/(25*10^-6))^2; disp(Snno,'signal to noise ratio at output=') F=Sni/Snno; disp(F,'noise Factor=') nf=10*log10(F); disp(nf,'noise Figure(dB)=')
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// Harriot P., 2003, Chemical Reactor Design (I-Edition), Marcel Dekker, Inc., USA, pp 436. //Chapter-6 Ex6.4 Pg No.251 //Title:Conversion in packed bed for same superficial velocity //==================================================================================================================== clear clc //COMMON INPUT L=2.5;//Lendth of bed(ft) X_A=0.95;//Conversion L_a=3;//Length of section a (ft) L_b=2;//Length of section b (ft) u_oa_by_u0=0.88;//Refer equation 3.64 u_ob_by_u0=1.12; L=2.5;//(ft) //CALCULATION (Ex6.4.a) k_rho_L_by_u=log(1/(1-X_A));//First Order reactions //For Section a k_rho_L_by_u_a=k_rho_L_by_u*(L_a/L); X_A_section_a=(1-exp(-k_rho_L_by_u_a)); //For Section b k_rho_L_by_u_b=k_rho_L_by_u*(L_b/L);//Dimensionless Group based on ideal plug flow for first order reaction X_A_section_b=(1-exp(-k_rho_L_by_u_b)); X_A_Ave=(X_A_section_b+X_A_section_a)/2; Percent_X_A_Ave=X_A_Ave*100 //CALCULATION (Ex6.4.b) k_rho_L_by_u=log(1/(1-X_A));//First Order reaction //For Section a k_rho_L_by_u_a=k_rho_L_by_u*(L_a/L)*(1/u_oa_by_u0); X_A_section_a=(1-exp(-k_rho_L_by_u_a)); delP_a_by_alpha_u0_pow=L_a*(u_oa_by_u0);//Refer equation 3.64 //For Section b k_rho_L_by_u_b=k_rho_L_by_u*(L_b/L)*(1/u_ob_by_u0);//Dimensionless Group based on ideal plug flow for first order reaction delP_b_by_alpha_u0_pow=L_b*u_ob_by_u0; X_A_section_b=(1-exp(-k_rho_L_by_u_b)); X_A_avg=(u_oa_by_u0*X_A_section_a+u_ob_by_u0*X_A_section_b)/2; Percent_X_A_avg=X_A_avg*100; //OUTPUT(Ex6.4.a) mprintf('\n OUTPUT Ex6.4.a'); mprintf('\n=========================================================='); mprintf('\nThe average converion when each section has same superficial velocity:%0.1f%%',Percent_X_A_Ave ); //OUTPUT(Ex6.4.b) mprintf('\n\n\n OUTPUT Ex6.4.b'); mprintf('\n=========================================================='); mprintf('\nThe overall conversion for different velocities:%0.1f%% ',Percent_X_A_avg ); //FILE OUTPUT fid= mopen('.\Chapter6-Ex4-Output.txt','w'); mfprintf(fid,'\n OUTPUT Ex6.4.a'); mfprintf(fid,'\n=========================================================='); mfprintf(fid,'\nThe average converion when each section has same superficial velocity:%0.1f%%',Percent_X_A_Ave ); mfprintf(fid,'\n\n\n OUTPUT Ex6.4.b'); mfprintf(fid,'\n=========================================================='); mfprintf(fid,'\nThe overall conversion for different velocities:%0.1f%% ',Percent_X_A_avg ); mclose(fid); //=======================================================END OF PROGRAM=================================================
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errcatch(-1,"stop");mode(2);//Caption:Find the percentage resistance,reactance drop,efficiency and voltage regulation //Exa:4.6 ; ; P=1500*1000;//in watts phy=acosd(0.8); V_1P=300;//in volts V_1L=6600;//in volts I_1P=131.21/sqrt(3); Z_1=V_1P/I_1P;//in ohms R_1=30*1000/(3*I_1P^2); X_1=sqrt((Z_1^2)-(R_1^2)); R=I_1P*R_1*100/V_1L; X=I_1P*X_1*100/V_1L; disp(R,'% Resistance drop (in %)='); disp(X,'% Reactance drop (in %)='); VR=(R*cosd(phy))+(X*sind(phy)); disp(VR,'Voltage regulation (in %)=') I_1_FL=P/(sqrt(3)*V_1L); P_t=(30+25)*1000;//in watts P_o=P*0.8;//in watts Eff=P_o/(P_o+P_t); disp(Eff*100,'Efficiency (in %)=') exit();
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// This file is BASED ON part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: project02starter/Add8.tst load Add8.hdl, output-file Add8.out, compare-to Add8.cmp, output-list a%B1.8.1 b%B1.8.1 out%B1.8.1; set a %B00000000, set b %B00000000, eval, output; set a %B00000000, set b %B11111111, eval, output; set a %B11111111, set b %B11111111, eval, output; set a %B10101010, set b %B01010101, eval, output; set a %B11000011, set b %B11110000, eval, output; set a %B00110100, set b %B01110110, eval, output;
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function y = fftn(A, SIZE) //This function computes the N-dimensional discrete Fourier transform of A using a Fast Fourier Transform (FFT) algorithm. //Calling Sequence //Y = fftn(A) //Y = fftn(A, size) //Parameters //A: Matrix //Description //This function computes the N-dimensional discrete Fourier transform of A using a Fast Fourier Transform (FFT) algorithm. The optional vector argument SIZE may be used specify the dimensions of the array to be used. If an element of SIZE is smaller than the corresponding dimension of A, then the dimension of A is truncated prior to performing the FFT. Otherwise, if an element of SIZE is larger than the corresponding dimension then A is resized and padded with zeros. //Examples //fftn([2,3,4]) //ans = // 9. - 1.5 + 0.8660254i - 1.5 - 0.8660254i funcprot(0); rhs = argn(2) if(rhs<1 | rhs>2) error("Wrong number of input arguments."); end select(rhs) case 1 then y = callOctave("fftn",A); case 2 then y = callOctave("fftn",A, SIZE); end endfunction
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// sum 8-2 clc; clear; W=196.2; lenthofscale=50; k=196.2/50; C=8; Ks=(1+(0.5/C)); // Let us choose oil tempered wire 0.6-0.7 %C. Refer to Table 8-4 for constants A and m, relating strength wire //diameter. G=77.2*(10^3); A=1855; m=0.187; // equating Tmax=0.5*sig(ut). // Ks*(8*W*D/(pi*(d^3)))=0.5*A/(d^2) d1=(Ks*(8*W*C/(%pi*A*0.5))); d=d1^(1/1.813); D=C*d; Na=G*(d^4)/(8*(D^3)*k); //Solid length = SL SL=(Na-1)*d // printing data in scilab o/p window printf(" wire diameter is %0.3f mm ",d); printf("\n mean diameter is %0.3f mm ",D); printf("\n Number of acting coils are %0.3f ",Na); //The difference in the values of d,D and Na is due to rounding-off the digits.
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clc,clear printf('Example 5.10\n\n') VA=125*10^3 V_L=400,V_ph=V_L/sqrt(3) I_L=VA/(sqrt(3)*V_L) I_aph=I_L I_f=4,I_asc=I_aph/2 //for half load.. refer to graph V_OC_line=140 V_OC_ph=V_OC_line/sqrt(3) I_asc_ph=I_asc Z_s= V_OC_ph/I_asc_ph R_a=0.1,X_s=sqrt(Z_s^2-R_a^2) //armature resistance and synchronous reactance phi=acos(0.8) E_ph = sqrt((V_ph*cos(phi)+I_asc*R_a)^2 +(V_ph*sin(phi)- I_asc*X_s)^2) regulation=100*(E_ph-V_ph)/V_ph printf('Voltage regulation at 0.8 pf leading for half load is %.2f percent\n',regulation)
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// Example 13.4: Maximum input power, Maximum ac output power, Maximum conversion efficiency, Maximum power dissipated by each transistor clc, clear VCC=15; // in volts RL=8; // in ohms P_dc=2*VCC^2/(%pi*RL); // Maximum input power in watts P_ac=VCC^2/(2*RL); // Maximum ac output power in watts eta=P_ac*100/P_dc; // Maximum efficiency in percentage PD=2*VCC^2/(%pi^2*RL); // Maximum power dissipated in watts PD_each=PD/2; // Maximum power dissipated by each transistor in watts disp(P_dc,"Maximum input power (W) ="); disp(P_ac,"Maximum ac output power (W) ="); disp(eta,"Maximum conversion efficiency (%) ="); disp(PD_each,"Maximum power dissipated by each transistor (W) =");
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load Computer.hdl, output-file ComputerMax.out, compare-to ComputerMax.cmp, output-list time%S1.4.1 reset%B2.1.2 ARegister[]%D1.7.1 DRegister[]%D1.7.1 PC[]%D0.4.0 RAM16K[0]%D1.7.1 RAM16K[1]%D1.7.1 RAM16K[2]%D1.7.1; // carrega o programa escrito na linguagem de maquina Hack. // o programa computa o maximo de RAM[0] e RAM[1] // e escreve o resultado na RAM[2]. ROM32K load Max.hack, // primeira execucao: compute max(3,5) set RAM16K[0] 3, set RAM16K[1] 5, output; repeat 14 { tick, tock, output; } // reset the PC set reset 1, tick, tock, output; // segunda execucao: compute max(23456,12345) set reset 0, set RAM16K[0] 23456, set RAM16K[1] 12345, output; // a execucao para essas entradas necessitam de menos ciclos repeat 10 { tick, tock, output; }
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clc;clear;close; function [U,L]=LUD(A) U=A disp(A,'The given matrix is A=') m=det(U(1,1)); n=det(U(2,1)); a=n/m U(2,:)=U(2,:)-U(1,:)/(m/n) n=det(U(3,1)); b=n/m U(3,:)=U(3,:)-U(1,:)/(m/n) m=det(U(2,2)) n=det(U(3,2)); c=n/m U(3,:)=U(3,:)-U(2,:)/(m/n) L=[1,0,0;a,1,0;b,c,1] endfunction function [B]=inverse(A) n=length(A(1,:)) Aug=[A,eye(n,n)] //Forward elimination for j=1:n-1 for i=j+1:n Aug(i,j:2*n)=Aug(i,j:2*n)-Aug(i,j)/Aug(j,j)*Aug(j,j:2*n) end end //Backward elimination for j=n:-1:2 Aug(1:j-1,:)=Aug(1:j-1,:)-Aug(1:j-1,j)/Aug(j,j)*Aug(j,:) end //Diagonal Normalisation for j=1:n Aug(j,:)=Aug(j,:)/Aug(j,j) end B=Aug(:,n+1:2*n) endfunction function[x,a]=gaussElimination(A,b) A_aug=[A b] a=A_aug n=3; for i=2:n for j=2:n+1 a(i,j)=a(i,j)-a(1,j)*a(i,1)/a(1,1); end a(i,1)=0; end for i=3:n for j=3:n+1 a(i,j)=a(i,j)-a(2,j)*a(i,2)/a(2,2); end a(i,2)=0; end x(n)=a(n,n+1)/a(n,n); for i=n-1:-1:1 sumk=0; for k=i+1:n sumk=sumk+a(i,k)*x(k); end x(i)=(a(i,n+1)-sumk)/a(i,i); end endfunction function main() A=[0,0,0;0,0,0;0,0,0] A(1,1)=input("enter a11: ") A(1,2)=input("enter a12: ") A(1,3)=input("enter a13: ") A(2,1)=input("enter a21: ") A(2,2)=input("enter a22: ") A(2,3)=input("enter a23: ") A(3,1)=input("enter a31: ") A(3,2)=input("enter a32: ") A(3,3)=input("enter a33: ") disp('1.Gaussian Elimination') disp('2.LU Decomposition') disp('3.Gauss Jordan method') ch=input("Enter choice: ") if ch==1 then b=[0;0;0] b(1,1)=input("enter b1: ") b(2,1)=input("enter b2: ") b(3,1)=input("enter b3: ") [x,a]=gaussElimination(A,b) disp(x(3),x(2),x(1),'The values of x,y,z are '); disp(a(1,1),a(2,2),a(3,3),'The pivots are'); elseif ch==2 then [U,L]=LUD(A) disp(U,'The upper triangular matrix is U =') disp(L,'The lower triangular matrix is L =') elseif ch==3 then [B]=inverse(A) disp(B,'The inverse of A is'); end endfunction main();
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// Initilization of variables M=10 // kg // Here M=M_1=M_2 g=9.81 // m/s^2 // acc due to gravity // Calculations // Consider the respective F.B.D // Applying the principle of conservation of energy and by equating the total energies at position 1 & position 2 we get v as, v=sqrt((M*g*4)/(25)) // m/s // Results clc printf('The velocity of mass M_2 is %f m/s \n',v)
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clc e1=0.3; e2=0.8; e3=0.04; A1=1; //m^2 A2=A1; A3=A1; // (E_b1 - E_b3)/[(1-e1)/e1+1+(1-e3)/e3]=(E_b3 - E_b2)/[(1-e3)/e3+1+(1-e2)/e2] // a*(T1^4-T3^4)/(1/e1+1/e3-1)=a*(T3^4-T2^4)/(1/e3+1/e2-1) // T3^4=0.48*(T1^4+1.08*T2^4) // Q12=a*(T1^4-T2^4)/(1/e1+1/e2-1) // Q13=a*(T1^4-T3^4)/(1/e1+1/e3-1) // %reduction=(Q_12-Q13)/Q12; %reduction=1-0.131*0.52; disp("Percentage reduction in heat flow due to shield =") disp(%reduction) disp("%")
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PL/SQL Developer Test script 3.0 7 begin -- Call the procedure cux_plsql_autocreate.form_view_iud(p_block_name => :p_block_name, p_table_name => :p_table_name, p_owner => :p_owner, p_primary_key => :p_primary_key); end; 4 p_block_name 1 MATERIALS 5 p_table_name 1 CUX_PO_RAW_MATERIALS_TL_9510 5 p_owner 1 CUX 5 p_primary_key 1 RAW_MTL_ID 5 0
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//chapter 12 //example 12.7 //page 489 printf("\n") printf("given") R1=120*10^3;R2=39*10^3;hie=2*10^3;R7=12*10^3;Zo=R7;R5=R1;R6=R2;hfe=100;R3=R7;Zl=R1; Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie) Zi2=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie) Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie Av2=-(hfe*((R7*Zl)/(R7+Zl)))/hie Av=Av1*Av2
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Ex8_3.sce
clear // //given f=50 ns=1000 //m=90/6*3 m=5 //angle is obtained as 12 //x=12 //angle=(m*x)/2 //x=30 //assuming for convinience //a=(180/%pi)*(30) //b=(%pi/180)*(a) //c=sin(b) //y=x/2 //y=6 //assuming for convinience //d=(180/%pi)*(y) //e=(%pi/180)*(c) //g=sin(e) //kd=c/(5*g) kd=0.96 //after calculations printf("\n The distribution factor=0.96") kp=0.98 //%pi tch factor=cos(20/2) //case a kw=kd*kp printf("\n %0.3f ",kw) //case b t1=(90*4)/(3*2) //number of turns per stator phase e1=415 flux=415/((3**0.5)*4.44*0.94*50*60) printf("\n flux in the air gap= %0.3f Wb",flux) //case c t2=(120*2)/(3*2) a=t1/t2 //transformation ratio printf("\n a = %0.3f ",a ) //case d //e2=e1/a //the induced rotor voltage per phase e2=415/((3**0.5)*1.5) printf("\n the induced rotor voltage per phase is= %0.5f V",e2)
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2020-06-30T23:22:36.014422
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parametric.sce
ROI = imread('C:\Users\loujoseftan\Dropbox\SciNotes\ROI.jpg'); ROI = double(ROI); R1 = ROI(:,:,1); G1 = ROI(:,:,2); B1 = ROI(:,:,3); I1 = R1 + G1 + B1; I1(find(I1==0))=100000; r1 = R1./I1; g1 = G1./I1; meanr = mean(r1); sigmar = stdev(r1); meang = mean(g1); sigmag = stdev(g1); SB = imread('C:\Users\loujoseftan\Dropbox\SciNotes\SB.jpg'); SB = double(SB); R2 = SB(:,:,1); G2 = SB(:,:,2); B2 = SB(:,:,3); I2 = R2 + G2 + B2; I2(find(I2==0))=100000; r2 = R2./I2; g2 = G2./I2; pr = (1/(sigmar*sqrt(2*%pi)))*exp(-((r2 - meanr).^2)/(2*sigmar.^2)); pg = (1/(sigmag*sqrt(2*%pi)))*exp(-((g2 - meang).^2)/(2*sigmag.^2)); S = pr.*pg; imwrite(S,'C:\Users\loujoseftan\Dropbox\SciNotes\Parametric Segmentation.jpg')
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/1733/CH8/EX8.21/8_21.sce
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8_21.sce
//8.21 clc; R2=5.6*10^3; R1=1*10^3; Avf=1+R2/R1; printf("Mid band Gain=%.2f", Avf) Vin=1.6; Vo=Avf*Vin; printf("\nOutput voltage=%.3f mV", Vo) R=1000; C=0.001*10^-6; fc=1/(2*%pi*R*C); printf("\nCutt off frequency=%.2f Hz", fc) Gain=0.707*Avf; printf("\nGain=%.3f", Gain)
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/2300/CH8/EX8.14.13/Ex8_13.sce
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Ex8_13.sce
//scilab 5.4.1 //Windows 7 operating system //chapter 8 Junction Transistors:Biasing and Amplification clc clear RE=0.680//RE=resistance in kilo ohms connected to the emitter terminal RC=2.7//RC=resistance in kilo ohms connected to the collector terminal //RB=resistance connected to the base terminal VCE=7.3//VCE=collector emitter voltage VBE=0.7//VBE=base emitter voltage Vre=2.1//Vre=voltage across RE resistance IB=0.02//IB=base current in mA IE=Vre/RE//IE=emitter current in mA IC=IE-IB//IC=collector current in mA b=IC/IB//b=current gain format("v",6) disp(b,"The current gain β is =") VCC=(IC*RC)+VCE+Vre//VCC=collector supply voltage format("v",5) disp("V",VCC,"The collector supply voltage VCC is =") //Voltage across RB (Vrb)resistance is given by Vrb=VCC-(VBE+Vre) RB=Vrb/IB format("v",5) disp("kilo ohm",RB,"The resistance RB is =") //To draw the DC load line,we neglect the base current in RE resistance //Equation for DC load line is: //VCE=VCC-(RC+RE)*IC disp("For the DC load line") disp("V",VCC,"The intercept of the load line on the VCE-axis(X-axis) is =") disp("mA",VCC/(RC+RE),"The intercept of the load line on the IC axis(Y-axis) is =") disp("The DC load line is the straight line joining above two intercepts.") disp("The co-ordinates of the operating point Q on the load line are (7.3V,3.07mA)")
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/2621/CH5/EX5.5/Ex5_5.sce
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// Example 5.5 clc; clear; close; // Given data format('v',5); f= 800;// in Hz C= 0.01;// in µF (assumed) C= C*10^-6;// in F D= 60;// in duty cycle in % // D= (R_A+R_B)/(R_A+2*R_B)*100= 60 or // R_B= 2*R_A R_A= 1.44/(f*5*C);// in Ω (From f=1.44/((R_A+2*R_B)*C)) R_A= R_A*10^-3;//in kΩ R_B= 2*R_A;// in kΩ C= C*10^6;//in F disp(R_A,"The value of R_A in kΩ is : "); disp(R_B,"The value of R_B in kΩ is : "); disp(C,"The value of C in µF is : ")
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2_05_solution.sce
//Solution 2-5 WD=get_absolute_file_path('2_05_solution.sce') datafile=WD+filesep()+'2_05_example.sci' clc; exec(datafile) //conversion l = l / 100; //from [cm] to [m] L = L / 100; //from [cm] to [m] R = d_o / (2 * 100); mu = T * l / (4 * %pi**2 * R**3 * ndot / 60 * L); printf("Viscocity of fluid is measured to be %1.3f N.s/m^2", mu);
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Ex4_25.sce
//Variable Declaration n = 8 n1 = 2 n2 = 5 n3 = 1 p1 = 0.3 p2 = 0.5 p3 = 0.2 //Calculation p = (factorial(8)/(factorial(2)*factorial(5)*factorial(1)))*((p1^2)*(p2^5)*(p3^1)) //Results printf ( "Required Probability: %.4f",p)
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ex_9_5.sce
//Example 9.5 // emf and internal resistance of each cell clc; clear; close; n=6;// no. of cells Rl=3;// LOAD RESISTANCE I=2.5;// IN AMPERES r1=9;// in ohms I2=1.25;// om amperes r=((r1*I2)-(Rl*I))/(n*(I-I2));// internal resistance in ohms E=((I*(Rl+n*r))/n);// emf of each cell in volts disp(E,"emf of each cell in volts is") disp(r,"internal resistance of each cell in ohms")
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clc; disp("Example 4.8") Re=100000 // Reynold number f=0.079/(Re^0.25) // friction factor according to 1/5th law ratio= 1+ 3.75*((f/2)^0.5) disp("The ratio of maximum velocity to the average velocity is ") disp(ratio)
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5_2.sce
//clear// clc clear exec("5.2data.sci"); for i =1:length(t) g(i) =log(2*P0/(3*P0-P(i))); end plot2d(t,g); xtitle( 'Figure E4-11.2 Plot of processed data', 't (min)', '2PTo/3PTo-PT' ) ;
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Exa3_5.sce
//Exa 3.5 clc; clear; close; //given data : //l=lambda/10 meter //Assume %pi^2 = 10 Rl=2;//in Ohm disp("Rr=80*%pi^2*(dl/lambda)^2"); disp("dl/lambda = 1/10 : as l=lambda/10 "); Rr=80*10*(1/10)^2;//in Ohm disp(Rr,"Radiation Resistance in Ohm : "); ETA=Rr/(Rr+Rl);//in Ohm disp(ETA*100," Efficiency inn % : ");
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Example5_2.sce
//Chapter-5,Example5_3_2,pg 5-6 h=6.63*10^-34 //Plancks constant m=9.1*10^-31 //mass of an electron wavelength=10^-10 //de Broglie wavelength of an electron v=h/(m*wavelength) //velocity of an electron printf("\nThe velocity of an electron is v = %.1f m/s\n",v)
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// Exa 7.15 clc; clear; close; // Given data r= 469;// in ohm R2= 1000;// in ohm R3= 218;//in ohm R4= 1000;//in ohm C= 10;// in miu F C= C*10^-6;// in F R1= R2*R3/R4;// in ohm disp(R1,"Resistance of inductor in ohm") L1= C*R2/R4*(r*(R3+R4)+R3*R4);// in H disp(L1,"Inductance of inductor in H")
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ScilabArduino_Temp_v0.1.sce
// // Copyright (C) 2014 - A. Khorshidi <akhorshidi@live.com> // // This file is distributed in the hope that it will be useful; // It must be used under the terms of the CeCILL. // http://www.cecill.info/licences/Licence_CeCILL_V2.1-en.txt // // // The following work provided the inspiration for this challenge. // https://www.scilab.org/content/view/full/847 // // I owe thanks to Bruno Jofret, the author of the original GUI. // https://fileexchange.scilab.org/toolboxes/270000 // ind = x_choose(["RS-232" ;"USB"; "Ethernet" ;"Wireless"],["Please select the type of communication interface: ";"Just double-click on its name. "],"Cancel"); if ind==0 then msg=_("ERORR: No types of communication interfaces has been chosen. "); messagebox(msg, "ERROR", "error"); error(msg); return; elseif ind==2 if (getos() == "Windows") then if ~(atomsIsInstalled('serial')) then msg=_("ERROR: A serial communication toolbox must be installed."); messagebox(msg, "Error", "error"); error(msg); return; else flag=1; end elseif (getos() == "Linux") then if ~(atomsIsInstalled('serialport')) & ~(atomsIsInstalled('serial')) then msg=_("ERROR: A serial communication toolbox must be installed."); messagebox(msg, "Error", "error"); error(msg); return; elseif (atomsIsInstalled('serialport')) & (atomsIsInstalled('serial')) then stoolbx = x_choose(['serialport';'serial' ],"Which serial ... commiunication toolbox you prefer to use? "," Cancel ") if stoolbx==1 then flag=2; elseif stoolbx==2 then flag=3; else msg=_("ERROR: No serial toolbox has been chosen. "); messagebox(msg, "Error", "error"); error(msg); return; end elseif (atomsIsInstalled('serialport')) then flag=2; elseif (atomsIsInstalled('serial')) then flag=3; end else msg=_(["WARNING: This program has been tested and works under Gnu/Linux ... and Windows."; "On other platforms you may need modify this script. "]) messagebox(msg, "WARNING", "warning"); warning(msg); return; end else error("Not possible yet."); return; end // if (getos() == "Linux") then [rep,stat,stderr]=unix_g("ls /dev/ttyACM*"); if stderr ~= emptystr() then msg=_(["No USB device found. ";"Check your USB connection or try ... another port. "]) messagebox(msg, "ERROR", "error"); error(msg); return; end ind = x_choose(rep,["Please specify which USB port you wanna use for ... communication. ";"Just double-click on its name. "],"Cancel"); if ind==0 then msg=_("ERORR: No serial port has been chosen. "); messagebox(msg, "ERROR", "error"); error(msg); return; end port_name = rep(ind); end if (getos() == "Windows") then port_name=evstr(x_dialog('Please enter COM port number: ','13')) if port_name==[] then msg=_("ERORR: No serial port has been chosen. "); messagebox(msg, "ERROR", "error"); error(msg); return; end end // global %serial_port if flag==2 then %serial_port = serialopen(port_name, 9600, 'N', 8, 1); while %serial_port == -1 btn=messagebox(["Please check your USB connection, and then click on ... Try again. "; "To choose another port click on Change. "], "Error", ... "error", [" Try again " " Change "], "modal"); if ~btn==1 then [rep,stat,stderr]=unix_g("ls /dev/ttyACM*"); ind = x_choose(rep,["Please specify which USB port you wanna use... for communication. ";"Just double-click on its name. "],"Cancel"); if ind==0 then msg=_("ERORR: No serial port has been chosen. "); messagebox(msg, "ERROR", "error"); error(msg); return; end port_name = rep(ind); end %serial_port = serialopen(port_name, 9600, 'N', 8, 1); end elseif flag==1 | flag==3 %serial_port=openserial(port_name,"9600,n,8,1"); //error(999) else msg=_("ERROR: Could not specify which serial toolbox to use. "); messagebox(msg, "Error", "error"); error(msg); return; end // // * Monitoring Phase: // global %MaxTemp %MaxTemp = 35; global %MinTemp %MinTemp = 30; f=figure("dockable","off"); f.resize="off"; f.menubar_visible="off"; f.toolbar_visible="off"; f.figure_name="Real-time Temperature Monitoring and Control"; f.tag="mainWindow"; bar(.5,0,'blue'); e = gce(); e = e.children(1); e.tag = "instantSensor"; // plot([0, 1], [%MinTemp, %MinTemp]); e = gce(); e = e.children(1); e.tag = "instantMinTemp"; e.line_style = 5; e.thickness = 2; e.foreground = color("orange"); // plot([0, 3], [%MaxTemp, %MaxTemp]); e = gce(); e = e.children(1); e.tag = "instantMaxTemp"; e.line_style = 5; e.thickness = 2; e.foreground = color("red"); a = gca(); a.data_bounds = [0, 0; 1, 45]; a.grid = [-1, color("darkgrey")]; a.axes_bounds = [0.1, 0.2, 0.25, 0.85]; a.axes_visible(1) = "off"; a.tag = "liveAxes"; //a.title.text="Current Temperature"; // f.figure_position = [0 0]; f.figure_size = [1000 700]; f.background = color(246,244,242) //color("darkgrey") // minTempSlider = uicontrol("style", "slider", "position", [60 30 30 440], ... "min", 0, "max", 45, "sliderstep", [1 5], "value" , %MinTemp, ... "callback", "changeMinTemp", "tag", "minTempSlider"); maxTempSlider = uicontrol("style", "slider", "position", [20 30 30 440], ... "min", 0, "max", 45, "sliderstep", [1 5], "value" , %MaxTemp, ... "callback", "changeMaxTemp", "tag", "maxTempSlider"); // // Functions: function changeMinTemp() global %MinTemp e = findobj("tag", "minTempSlider"); %MinTemp = e.value //45 - e.value; e = findobj("tag", "instantMinTemp"); e.data(:,2) = %MinTemp; endfunction // function changeMaxTemp() global %MaxTemp e = findobj("tag", "maxTempSlider"); %MaxTemp = e.value //45 - e.value; e = findobj("tag", "instantMaxTemp"); e.data(:,2) = %MaxTemp; endfunction // function closeFigure() stopSensor(); global %serial_port if flag == 2 then serialclose(%serial_port); elseif flag == 1 | flag == 3 then closeserial(%serial_port); end f = findobj("tag", "mainWindow"); delete(f); endfunction // function stopSensor() global %Acquisition %Acquisition = %f; endfunction // function launchSensor() global %MaxTemp global %serial_port global %Acquisition %Acquisition = %t; global %fanStatus %fanStatus = 0; // Arduino toolbox values=[]; value=ascii(0); while %Acquisition while(value~=ascii(13)) then if flag == 2 then value=serialread(%serial_port,1); elseif flag == 1 | flag == 3 then value=readserial(%serial_port,1); end values=values+value; v=strsubst(values,string(ascii(10)),'') v=strsubst(v,string(ascii(13)),'') data=evstr(v) end // xinfo("Temperature = "+v+"°C"); values=[] value=ascii(0); updateSensorValue(data); // global %RegulationEnable if %RegulationEnable == 1 then if data > %MaxTemp then enableFan(); else disableFan(); end end updateFanValue(%fanStatus); end endfunction // function updateSensorValue(data) global %MaxTemp global %MinTemp e = findobj("tag", "instantSensor"); e.data(2) = data; if data > %MaxTemp then e.background = color("red"); else if data > %MinTemp then e.background = color("orange"); else e.background = color("green"); end end // e = findobj("tag", "minuteSensor"); lastPoints = e.data(:, 2); e.data(:, 2) = [lastPoints(2:$) ; data]; e = findobj("tag", "hourSensor"); lastPoints = e.data(:, 2); e.data(:, 2) = [lastPoints(2:$) ; data]; endfunction // // * Regulation Phase: // global %RegulationEnable %RegulationEnable = 1; global %PController %PController = 0; global %PIController %PIController = 0; global %PIDController %PIDController = 0; // top_axes_bounds = [0.25 0 0.8 0.5]; bottom_axes_bounds = [0.25 0.5 0.8 0.5]; minTempDisplay = 20; maxTempDisplay = 45; minRegulationDisplay = -0.2; maxRegulationDisplay = 1.2; // Temperature variations in the last 5 minutes timeBuffer = 300; subplot(222); a = gca(); a.axes_bounds = top_axes_bounds; a.tag = "minuteAxes"; plot2d(0:timeBuffer, zeros(1,timeBuffer + 1), color("red")); a.title.text="Temperature variations in the last 5 minutes"; a.data_bounds = [0, minTempDisplay; timeBuffer, maxTempDisplay]; e = gce(); e = e.children(1); e.tag = "minuteSensor"; // adding a second vertical axis on the right side ... // to show the On/Off status of the DC Fan. a = newaxes(); a.y_location = "right"; a.filled = "off" a.axes_bounds = top_axes_bounds; plot2d(0:timeBuffer, zeros(1,timeBuffer + 1), color("blue")); a.data_bounds = [0, minRegulationDisplay; timeBuffer, maxRegulationDisplay]; a.axes_visible(1) = "off"; a.foreground=color("blue"); a.font_color=color("blue"); e = gce(); e = e.children(1); e.tag = "minuteRegulation"; // Temperature variations in the last hour timeBuffer = 4000; subplot(224); a = gca(); a.axes_bounds = bottom_axes_bounds; a.tag = "hourAxes"; plot2d(0:timeBuffer, zeros(1,timeBuffer + 1), color("red")); a.title.text="Temperature variations in the last hour"; a.data_bounds = [0, minTempDisplay; timeBuffer, maxTempDisplay]; e = gce(); e = e.children(1); e.tag = "hourSensor"; // 2nd vertical axis a = newaxes(); a.y_location = "right"; a.filled = "off" a.axes_bounds = bottom_axes_bounds; a.axes_visible = "off"; plot2d(0:timeBuffer, zeros(1,timeBuffer + 1), color("blue")); a.data_bounds = [0, minRegulationDisplay; timeBuffer, maxRegulationDisplay]; a.axes_visible(1) = "off"; a.foreground=color("blue"); a.font_color=color("blue"); e = gce(); e = e.children(1); e.tag = "hourRegulation"; // // Functions: function resetDisplay() e = findobj("tag", "instantSensor"); e.data(:, 2) = 0; e = findobj("tag", "minuteSensor"); e.data(:, 2) = 0; e = findobj("tag", "hourSensor"); e.data(:, 2) = 0; e = findobj("tag", "minuteRegulation"); e.data(:, 2) = 0; e = findobj("tag", "hourRegulation"); e.data(:, 2) = 0; endfunction // function changeRegulationStatus() global %RegulationEnable e = findobj("tag", "enableRegulationCBO"); %RegulationEnable = e.value; if %RegulationEnable == 0 then disableFan(); end endfunction // function updateFanValue(data) e = findobj("tag", "minuteRegulation"); lastPoints = e.data(:, 2); e.data(:, 2) = [lastPoints(2:$) ; data]; e = findobj("tag", "hourRegulation"); lastPoints = e.data(:, 2); e.data(:, 2) = [lastPoints(2:$) ; data]; endfunction // function enableFan() global %serial_port if flag == 2 then serialwrite(%serial_port,'H'); elseif flag == 1 | flag == 3 then writeserial(%serial_port,ascii(72)); end global %fanStatus %fanStatus = 1; endfunction // function disableFan() global %serial_port if flag == 2 then serialwrite(%serial_port,ascii(76)); elseif flag == 1 | flag == 3 then writeserial(%serial_port,"L"); end global %fanStatus %fanStatus = 0; endfunction // // Buttons: // * Main Panel mainFrame = uicontrol(f, "style", "frame", "position", [15 560 305 80], ... "tag", "mainFrame", "ForegroundColor", [0/255 0/255 0/255],... "border", createBorder("titled", createBorder("line", "lightGray", 1)... , _("Main Panel"), "center", "top", createBorderFont("", 11, "normal"), ... "black")); // startButton = uicontrol(f, "style", "pushbutton", "position", ... [20 595 145 30], "callback", "launchSensor", "string", "Start Acquisition", ... "tag", "startButton"); // stopButton = uicontrol(f, "style", "pushbutton", "position", ... [170 595 145 30], "callback", "stopSensor", "string", "Stop Acquisition", ... "tag", "stopButton"); // resetButton = uicontrol(f, "style", "pushbutton", "position", ... [20 565 145 30], "callback", "resetDisplay", "string", "Reset", ... "tag", "resetButton"); // quitButton = uicontrol(f, "style", "pushbutton", "position", ... [170 565 145 30], "callback", "closeFigure", "string", "Quit", ... "tag", "quitButton"); // RegulationFrame = uicontrol(f, "style", "frame", "position", [15 490 305 65]... ,"tag", "mainFrame", "ForegroundColor", [0/255 0/255 0/255],... "border", createBorder("titled", createBorder("line", "lightGray", 1), ... _("Regulation Mode"), "center", "top", createBorderFont("", 11, "normal"),... "black")); // // * Regulation Mode enableRegulation = uicontrol(f, "style", "checkbox", "position", ... [20 520 140 20],"string", "ON/OFF", "value", %RegulationEnable, ... "callback", "changeRegulationStatus", "tag", "enableRegulationCBO"); // enableP = uicontrol(f, "style", "checkbox", "position", [20 500 140 20], ... "string", "P Controller", "value", %PController, ... "callback", "", "tag", ""); // enablePI = uicontrol(f, "style", "checkbox", "position", [170 520 140 20], ... "string", "PI Controller", "value", %PIController, ... "callback", "", "tag", ""); // enablePID = uicontrol(f, "style", "checkbox", "position", [170 500 140 20], ... "string", "PID Controller", "value", %PIDController, ... "callback", "", "tag", ""); //
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clc clear //Input data T1=335 //Inlet temperature in K P1=655 //Inlet pressure in kPa C1=150 //Inlet velocity in m/s P2=138 //Exit pressure in kPa T2=222 //Exit temperature in K m=9 //Mass flow rate in kg/s Mol=32 //Molar mass of oxygen in kg/mol Ri=8314 //Ideal gas constant in J/kg-k k=1.4 //Adiabatic Constant Cp=915 //Specific heat capacity at constant pressure in J/kg-K //Calculation R=Ri/Mol //Specific gas constant in J/kg-K a1=sqrt(k*R*T1) //Sound velocity at inlet in m/s M1=C1/a1 //Inlet mach number t1=0.964 //Ratio of inlet temperature to Stagnation temperature from gas tables @M1,k=1.4 To1=T1/t1 //Stagnation temperature at inlet in K p1=0.881 //Ratio of inlet pressure to Stagnation pressure at entry from gas tables @M1,k=1.4 Po1=P1/p1 //Stagnation pressure at entry in kPa t2=0.834 //Ratio of critical temperature to Stagnation temperature from gas tables @M=1 Tt=To1*t2 //critical temperature in K C2=sqrt(C1^2+(2*Cp*(T1-T2))) //Exit velocity in m/s, a2=sqrt(k*R*T2) //Sound velocity at exit in m/s M2=C2/a2 //Exit mach number p2=0.208 //Ratio of exit pressure to Stagnation pressure at exit from isentropic gas tables @M2,k=1.4 Po2=P2/p2 //Stagnation pressure at exit in kPa SPC=(Po1-Po2) //Change in the stagnation pressure between inlet and exit in kPa ds=R*log(Po1/Po2) //Change in entropy in J/kg-K T2s=T1*((P2/P1)^((k-1)/k)) //Exit temperature at isentropic state in K eff=((T1-T2)/(T1-T2s))*100 //Nozzle efficiency in percent //Output printf('(A)Exit mach number is %3.2f\n (B)Change in the stagnation pressure between inlet and exit is %3.2f kPa\n (C)Change in entropy is %3.3f J/kg-K\n (D)Static temperature at throat is %3.1f K\n (E)Nozzle efficiency is %3.2f percent',M2,SPC,ds,Tt,eff)
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n1 = 9 n2 = 5 n3 = 0 n4 = 5 n = 10 + n3 n1_str = string(n1); n2_str = string(n2); n3_str = string(n3); n4_str = string(n4); nn = strcat([ n1_str, n2_str, n3_str, n4_str ]); rand("seed", strtod(nn)); T = rand(n, n) + rand(n, n); A = floor((1.0 - n3*0.01 - n4*0.005 - 0.05)*T); Wt = round(rand(n,n)*100 .* A); B = Wt & ones(n,n); Wt = (bool2s(B & ~B') + bool2s(B & B') .* tril(ones(n,n),-1)) .* Wt; W = Wt + Wt'; A W