blob_id stringlengths 40 40 | directory_id stringlengths 40 40 | path stringlengths 6 214 | content_id stringlengths 40 40 | detected_licenses listlengths 0 50 | license_type stringclasses 2 values | repo_name stringlengths 6 87 | snapshot_id stringlengths 40 40 | revision_id stringlengths 40 40 | branch_name stringclasses 15 values | visit_date timestamp[us]date 2016-08-04 09:00:04 2023-09-05 17:18:33 | revision_date timestamp[us]date 1998-12-11 00:15:10 2023-09-02 05:42:40 | committer_date timestamp[us]date 2005-04-26 09:58:02 2023-09-02 05:42:40 | github_id int64 436k 586M ⌀ | star_events_count int64 0 12.3k | fork_events_count int64 0 6.3k | gha_license_id stringclasses 7 values | gha_event_created_at timestamp[us]date 2012-11-16 11:45:07 2023-09-14 20:45:37 ⌀ | gha_created_at timestamp[us]date 2010-03-22 23:34:58 2023-01-07 03:47:44 ⌀ | gha_language stringclasses 36 values | src_encoding stringclasses 17 values | language stringclasses 1 value | is_vendor bool 1 class | is_generated bool 1 class | length_bytes int64 5 10.4M | extension stringclasses 15 values | filename stringlengths 2 96 | content stringlengths 5 10.4M |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
fa091e17e747124e2077361395bf6c422173d96e | 449d555969bfd7befe906877abab098c6e63a0e8 | /3769/CH27/EX27.10/Ex27_10.sce | 68b7dfcf39a5e09f0bb873f263483d1ad41e262e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 123 | sce | Ex27_10.sce | clear
//Given
A=0.9
Ie=1 //mA
//Calculation
Ic=A*Ie
Ib=Ie-Ic
//Result
printf("\n Base current is %0.3f mA",Ib)
|
48edd5f36c57abaf79b69614510f1df60395d64c | 3cbdc2f272df05cfe8c6636d4504e9e3d2e4fe3f | /Coordinates/utm-1.sce | e7aa2e71f736d3fa0ef6418700a6a4724f31cb9d | [] | no_license | bozhink/Code-Chunks | 74355eb4c0d423c2f6484226e564030dff798678 | 860b7b8f53089ed96fd0ebead2e3eec16fa377cb | refs/heads/master | 2020-12-24T06:19:04.343239 | 2019-11-13T14:09:15 | 2019-11-13T14:09:15 | 42,819,484 | 0 | 1 | null | 2019-11-13T14:09:16 | 2015-09-20T16:09:09 | HTML | UTF-8 | Scilab | false | false | 6,426 | sce | utm-1.sce | aaa=[631200 780143.766831 2373680.0708
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bbb=aaa;
naaa = max(size(aaa));
function [X,Y]=UTMtoGeog(x,y,utmz,hemi)
if (x<160000 | x>840000) then
disp("Outside permissible range of easting values \n Results may be unreliable \n Use with caution");
return;
end;
if (y<0) then
disp("Negative values not allowed \n Results may be unreliable \n Use with caution");
return;
end;
if (y>10000000) then
disp("Northing may not exceed 10,000,000 \n Results may be unreliable \n Use with caution");
return;
end;
DatumEqRad = [6378137.0,6378137.0,6378137.0,6378135.0,6378160.0,6378245.0,6378206.4,6378388.0,6378388.0,6378249.1,6378206.4,6377563.4,6377397.2,6377276.3];
DatumFlat = [298.2572236, 298.2572236, 298.2572215, 298.2597208, 298.2497323, 298.2997381, 294.9786982,296.9993621, 296.9993621, 293.4660167, 294.9786982, 299.3247788, 299.1527052, 300.8021499];
Item = 1;//Default
a = DatumEqRad(Item);//equatorial radius, meters.
f = 1/DatumFlat(Item);//polar flattening.
drad = 4*atan(1.0)/180;//Convert degrees to radians)
k0 = 0.9996;//scale on central meridian
b = a*(1-f);//polar axis.
e = sqrt(1 - (b/a)*(b/a));//eccentricity
e0 = e/sqrt(1 - e*e);//Called e prime in reference
esq = (1 - (b/a)*(b/a));//e squared for use in expansions
e0sq = e*e/(1-e*e);// e0 squared - always even powers
zcm = 3 + 6*(utmz-1) - 180;//Central meridian of zone
e1 = (1 - sqrt(1 - e*e))/(1 + sqrt(1 - e*e));//Called e1 in USGS PP 1395 also
M0 = 0;//In case origin other than zero lat - not needed for standard UTM
M = M0 + y/k0;//Arc length along standard meridian.
if hemi then
M=M0+(y-10000000)/k;
end;
mu = M/(a*(1 - esq*(1/4 + esq*(3/64 + 5*esq/256))));
phi1 = mu + e1*(3/2 - 27*e1*e1/32)*sin(2*mu) + e1*e1*(21/16 -55*e1*e1/32)*sin(4*mu);//Footprint Latitude
phi1 = phi1 + e1*e1*e1*(sin(6*mu)*151/96 + e1*sin(8*mu)*1097/512);
C1 = e0sq*(cos(phi1)**2);
T1 = (tan(phi1)**2);
N1 = a/sqrt(1-(e*sin(phi1))**2);
R1 = N1*(1-e*e)/(1-(e*sin(phi1))**2);
D = (x-500000)/(N1*k0);
phi = (D*D)*(1/2 - D*D*(5 + 3*T1 + 10*C1 - 4*C1*C1 - 9*e0sq)/24);
phi = phi + (D**6)*(61 + 90*T1 + 298*C1 + 45*T1*T1 -252*e0sq - 3*C1*C1)/720;
phi = phi1 - (N1*tan(phi1)/R1)*phi;
//Output Latitude
X = floor(1000000*phi/drad)/1000000;
//Longitude
lng = D*(1 + D*D*((-1 -2*T1 -C1)/6 + D*D*(5 - 2*C1 + 28*T1 - 3*C1*C1 +8*e0sq + 24*T1*T1)/120))/cos(phi1);
lngd = zcm+lng/drad;
//Output Longitude
Y = floor(1000000*lngd)/1000000;
endfunction
for i=1:naaa, [bbb(i,2),bbb(i,3)]=UTMtoGeog(aaa(i,2),aaa(i,3),15,%f);end;
|
ac9ab229a982d4c79a49e21ebfbab01da87be299 | 449d555969bfd7befe906877abab098c6e63a0e8 | /692/CH5/EX5.12/P5_12.sce | 641647c9eec7c0454cc07b97961d3a6133c6432b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 644 | sce | P5_12.sce | //EXAMPLE 5.12
//Linear convolution using Circular convolution
clc;
clear;
g = [1 2 0 1];
disp(g,'g[n] = ');
h = [2 2 1 1];
disp(h,'h[n] = ');
//linea convolution length = 4+4-1 = 7
//appending the two signals with zeros
g = [g,zeros(1,3)]
h = [h,zeros(1,3)]
G = fft(g,-1);
H = fft(h,-1);
Y = G.*H; //element wise multiplication
y = fft(Y,1);//IDFT
//Plotting linear convolution
n=0:6;
figure(0);
clf();
a = gca();
a.x_location = 'origin';
a.y_location = 'origin';
plot2d3(n,y,2);
plot(n,y,'r.');
poly1 = a . children (1) . children (1) ;
poly1.thickness = 2;
xtitle('Linear convolution','n','y');
disp(y," linear convolution ,y = ");
|
393782b84664cfb125008b9fd606f62d8bb3ba61 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3648/CH6/EX6.3/Ex6_3.sce | ac0de77062714991e0635fe2143b8f0c55490a99 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 411 | sce | Ex6_3.sce | //Example 6_3
clc();
clear;
//To find out how fast and the direction car moving
m1=30000 //units in Kg
m2=1200 //units in Kg
v10=10 //units in meters/sec
v20=-25 //units in meters/sec
vf=((m1*v10)+(m2*v20))/(m1+m2) //unis in meters/sec
printf("The car is moving at vf=%.2f Meters/sec\n",vf)
printf("The positive sign of vf Indicate the car is moving in the direction the truck was moving")
|
d91a38a6eddb4712641d3d2eecec4bd6ff8641a6 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3792/CH5/EX5.10/Ex5_10.sce | b9b73f25f93d29f1eec2e396643647eb065fa902 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 346 | sce | Ex5_10.sce | // SAMPLE PROBLEM 5/10
clc;funcprot(0);
// Given data
v_B=0.8;// The velocity in m/s
theta=30;// degree
d_co=18;// The distance in inch
// Calculation
v_A=v_B*cosd(theta);// ft/sec
OAbar=(d_co/12)/(cosd(theta));// ft
omega=v_A/(OAbar);// rad/sec CCW
printf("\nThe angular velocity of the slotted arm,omega=%0.3f rad/sec CCW",omega);
|
4901ff324fc6b1c714a63994ac4b71a1a579ab96 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2459/CH13/EX13.14/Ex13_14.sce | b6e2a00647263ff19d4a0c84ec0c68fd834a525c | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 522 | sce | Ex13_14.sce | //chapter13
//example13.14
//page288
R1=45 // kilo ohm
R2=15 // kilo ohm
Re=7.5 // kilo ohm
Vcc=30 // V
Vbe=0.7 // V
gain_beta=200
V2=Vcc*R2/(R1+R2) // voltage across R2
Ve=V2-Vbe // voltage across Re
Ie=Ve/Re
re_dash=1d-3*25/Ie // in kilo ohm
Zin_base=gain_beta*re_dash
Zin=Zin_base*(R1*R2/(R1+R2))/(Zin_base+R1*R2/(R1+R2))
printf("input impedence of amplifier circuit = %.3f kilo ohm \n",Zin)
// the accurate answer for input impedence is 3.701 kilo ohm but in book it is given as 3.45 kilo ohm
|
b2262805d8cd98f50384c09687e78b7ddde3bc95 | 9f9364e082d4bc2f7ee5cbd7a489642615821873 | /src/testCases/test1-14.tst | 3efa22f201cff6227b2101ecab27acab312166fe | [] | no_license | abrageddon/DLX-Opt | 4602617f83ddf8cb0fea83fecd2faa362849dfcd | 20038078f11a7ae67e7ab336e551e23966551290 | refs/heads/master | 2021-01-01T05:49:33.218016 | 2013-03-14T06:08:45 | 2013-03-14T06:08:45 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 301 | tst | test1-14.tst | main
var inp, outp;
{
let outp <- call inputnum();
let inp <- outp * outp / outp - 22;
if outp == inp then
call outputnum(inp);
let outp <- call inputnum();
call outputnewline()
fi;
call outputnum(inp);
call outputnewline();
call outputnum(outp);
call outputnewline()
}.
|
c13de89bc2ccf01c021e9db106481f9885fd6b6d | 449d555969bfd7befe906877abab098c6e63a0e8 | /2921/CH18/EX18.4/Ex18_4.sce | df93a3c5239fee93e16c8861f066bdba4c42c0fb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 241 | sce | Ex18_4.sce | clc;
clear;
mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-18.4 Page No.405\n');
//Torque
L=0.5;
F=5800/2;
T=0.177*F*L;
mprintf('\n Torque = %f in-lb.',T);
//Power
n=175*2/3;
P=T*n/63000;
mprintf('\n Power = %f hp.',P);
|
e3236a28cdf47fea36ceae3d75cce0704c00a106 | 449d555969bfd7befe906877abab098c6e63a0e8 | /599/CH3/EX3.4/example3_4.sce | 8aea335cbf47470cbc862b277ae2b2b3b1afcf90 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 603 | sce | example3_4.sce |
clear;
clc;
printf("\t Example 3.4\n");
NA=7.5*10^-7; //mass flux in gmol/cm^2*s
Dab=1.7*10^-5; //diffusivity if SO2 in water in cm^2/s
c=1/18.02; //concentration is density/molecular weight in gmol/cm^2*s
//SO2 is absorbed from air into water
xa1=0.0025; //liquid phase mole fraction at 1
xa2=0.0003; //liquid phase mole fraction at 2
//NA=kc(Ca1-Ca2)=Dab*(Ca1-Ca2)/d
k_c=NA/(c*(xa1-xa2)); //k_c=Dab/d=NA/c(xa1-xa2)
printf("\nmass transfer coefficient k_c is:%f cm/s",k_c);
d=Dab/k_c;
printf("\nfilm thickness d is :%f cm",d);
//end |
f8456d71c613a9d9d024cbe3a7712a87f3343185 | b846ffaa3e3e3311c37e95270bbe930fdf91a314 | /simpson1-3.sci | ae1930d67ea61fe4f5f998804831ad01bca67456 | [] | no_license | rahulgarg28071998/mathlab-practical-scilab | 100a15f74f94942d32a8be8125b4020a7e265ede | a83cc6b817fcca9268a59583eab372109552f2f8 | refs/heads/master | 2020-03-11T15:22:05.161498 | 2018-04-18T15:19:11 | 2018-04-18T15:19:11 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 383 | sci | simpson1-3.sci | clc
clear
deff('y=f(x)','y=x/(x*x+5)')
a=input("enter lower limit")
b=input("enter upper limit")
n=input("enter number of sum intervals")
h=(b-a)/n
x(1)=a;
sum=f(a);
for i=2:n
x(i)=x(i-1)+h
end
for j=2:2:n
sum=sum+4*f(x(j));
end
for k=3:2:n
sum=sum+2*f(x(k));
end
sum=sum+f(b);
val=sum*h/3;
disp(val,"vlaue of integral by simpsons 1/3rd rule is :");
|
31a312c419bdb5fda6e5af88fe2a38412afb769c | e8dbcf469ba8a31d6926ba791ebc5dcccd50282b | /Scripts/DML/Consultas/Test/personas_por_ciudad.tst | d2daee19ae8446788718ac0364782f42dd869f3b | [] | no_license | bryanjimenezchacon/bryanjimenezchacon.github.io | 5f2a0f1dbfbc584a65dece48f98b1c13d755512f | 7062d1860934808265c05491007c83f69da1112a | refs/heads/master | 2021-01-23T17:20:11.542585 | 2015-10-10T05:52:52 | 2015-10-10T05:52:52 | 41,244,377 | 2 | 0 | null | 2015-08-26T15:46:04 | 2015-08-23T09:52:06 | JavaScript | UTF-8 | Scilab | false | false | 219 | tst | personas_por_ciudad.tst | PL/SQL Developer Test script 3.0
5
begin
-- Call the procedure
personas_por_ciudad(pciudad_id => :pciudad_id,
p_recordset => :p_recordset);
end;
2
pciudad_id
1
1
4
p_recordset
1
<Cursor>
116
0
|
15a9bd6d68e5f7f04fc77b2cca6dfde0b5717645 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2252/CH14/EX14.18/Ex14_18.sce | 3da54a4155e335346132b33a6bdbb969b2770530 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 541 | sce | Ex14_18.sce |
function[r]=mag(A)
x=real(A)
y=imag(A)
r=sqrt(x^2+y^2)
endfunction
j=%i
Zl=8+6.2*j//load impedance
//for transformer A
Ea=6600//secondary induced emf
Za=.3+3.2*j//equivalent impedance referred to secondary
//for transformer B
Eb=6400//secondary induced emf
Zb=.2+1.2*j//equivalent impedance referred to secondary
Ia=(Ea*Zb+(Ea-Eb)*Zl)/(Za*Zb+(Za+Zb)*Zl)
Ib=(Eb*Za-(Ea-Eb)*Zl)/(Za*Zb+(Za+Zb)*Zl)
mprintf("Current delivered by transformer A is %f A\nCurrent delivered by transformer B is %f A",mag(Ia),mag(Ib))
|
8d711133b2983ac0d1f455de72a439911d93ba2b | 449d555969bfd7befe906877abab098c6e63a0e8 | /3871/CH12/EX12.27/Ex12_27.sce | f02395a59d87a20dc69e80eec7f9c4edad1539f3 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 567 | sce | Ex12_27.sce | //=====================================================================================
//Chapter 12 example 27
clc;clear all;
//variable declaration
f = 450*10^3; //resistance inHz
C = 250*10^-12; //capcaitance in F
Rsh = 0.75; //resistance in Ω
Q = 105; //Q-factor
//calculations
w = 2*(%pi)*f;
L = 1/(((w)^2)*(C)); //inductance in uH
R = ((w*L)/(Q))-Rsh; //resistance of the coil in Ω
//result
mprintf("inductance = %3.2f uH",(L*10^6));
mprintf("\n resistance of the coil = %3.2f Ω",R);
|
c538ad2f29d8cc16ba6ac81c7f60af5990460cf5 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2213/CH3/EX3.10/ex_3_10.sce | bed15fb6679fe9ca4087ca57baa76dc9e4d1c2c2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 449 | sce | ex_3_10.sce | //Example 3.10 // quantity of electricity and time taken
clc;
clear;
close;
//given data :
d=0.1;//in m
l=.25;// in m
Tc=2;// thickness of coating in mm
D=8.9;//density of metal in gm/CC
C_density=160;//in A/sq
I_efficiency=0.9;
S=%pi*d*l;
m=S*Tc*10^-3*D*10^3;
Z=30.43*10^-8;// in kg/C
Q=(m/Z)/3600;// in A-h
Q_dash=Q/I_efficiency;
disp(Q_dash,"quantity of electricity,Q_dash(A-h) = ")
I=C_density*S;
t=Q_dash/I;
disp(t,"time required,t(hours) = ")
|
a2ec9c88f5269ab01c9339ad88066fff8a5ec3aa | 449d555969bfd7befe906877abab098c6e63a0e8 | /509/CH4/EX4.1/4_1.sci | 2989422251553462f1e50bf5acd7b1cad4657c2e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,153 | sci | 4_1.sci | //Chapter 4 Example 1//
clc
clear
//from table given in the problem we take the required values directly//
//thus the values of various loads are taken as l1,l2,l3........ln//
//total energy produced=te,average demand=ad,total time=t//
l1=400;l2=380;l3=350;l4=300;l5=350;l6=500;l7=700;l8=750;l9=900;l10=1200;l11=1350;l12=1200;l13=1000;l14=950;l15=1250;l16=1300;l17=1400;l18=1300;l19=1500;l20=1800;l21=2000;l22=1950;l23=1000;l24=800;// in kWh//
t=24;// in hrs//
ad=(l1+l2+l3+l4+l5+l6+l7+l8+l9+l10+l11+l12+l13+l14+l15+l16+l17+l18+l19+l20+l21+l22+l23+l24)/t;
printf("\n Average Demand = %.2f kW\n",ad);
// load factod=lf,max demand=md//
md=l21;//max demand is the highest of all individual demands//
lf=ad/md;
printf("\n Load factor = %.6f \n",lf);
// loss factor=lf,peak loss at peak load=pl,average power loss=apl//
lf=0.14;
pl=108;// in kW//
apl=lf*pl;
printf("\n Average power loss = %.2f kW\n",apl);
// annual power loss= average power loss*365//
apl1=apl*365;
printf("\n Annual Power loss = %.2f kW\n",apl1);
// demand factor=df,connected demand=cd//
cd1=2500;// in kW//
df=md/cd1;
printf("\n Demand Factor= %.2f \n",df);
|
0135140968d4270e78b7f8458b3476e90802bef1 | 449d555969bfd7befe906877abab098c6e63a0e8 | /167/CH15/EX15.1/ex1.sce | d9fe3d80b4b4788b1050ff83b815898489d55459 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 542 | sce | ex1.sce | //example 1
//Balancing the Combustion Equation
clear
clc
Mair=28.97 //Molar mass of air in kg/kmol
x=8 //no. of moles of CO2 in products
y=9 //no. of moles of H2O in products
z=7.5 //no. of moles of O2 in products
w=75.2 // no. of moles of N2 in products
NMair=20*4.76*29 //mass of air in kg
NMc=8*12 //mass of carbon in fuel in kg
NMh2=2*9 //mass of hydrogen in fuel in kg
AF=NMair/(NMc+NMh2) //air fuel ratio in kg air/kg fuel
printf("\n Hence, the air fuel ratio for this combustion process is = %.1f kg air/kg fuel. \n",AF); |
42ccc2dbb87f00653e5c83e923eab29042a652b8 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2735/CH16/EX16.15/Ex16_15.sce | 1f75655214de0d2a44a430e789a8c6b5838e074b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 454 | sce | Ex16_15.sce | clc
clear
//Initialization of variables
M2=18 //Molar mass of water
M=170 //Molar mass of octane
p=0.4593 //Pressure of octane //psia
disp("from steam tables,")
vfg=694.9
J=778.2
m=9*18 //Mass of water
u1=-2363996 //Btu
//calculations
hfg=1050.4 //Btu/lbm
ufg= hfg- p*vfg*144/J
dU=ufg*m
Lhv=u1+dU
//results
printf("Lower heating value = %d Btu/lbm",Lhv)
disp("The answers are a bit different due to rounding off error in textbook.")
|
6b1eaf3ec4a044cef30af89ea99ad881cce24bb8 | b80969c9d72c732b0153d0de2b8fd28dc10d8a16 | /Biologie/Site/sauvegarde/28.07.2016/www/Documents/simulation/initation_scilab/ex16.sci | a19bc6c2e4ca1cea67bdba9b3c2b0e5e0a6fe720 | [] | no_license | adamdepossylux/stem_cells | 6a2596a0734e3604b570cfdaa1e6cb798d13d7b7 | e1ffdf24a223fea3a3606a0bd262067edc81f5b9 | refs/heads/master | 2020-04-01T17:26:21.772875 | 2017-05-10T15:15:09 | 2017-05-10T15:15:09 | 61,795,551 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 152 | sci | ex16.sci | t=0:%pi/20:2*%pi;
plot2d(t,sin(t),1)
plot2d(t,exp(sin(t)),8)
title('sin et exp(sint)')
xlabel('t axis')
ylabel('y axis')
legend('sin(t)','exp(sin(t))')
|
f04a5cd7e6180abb97a83657b4f96a80ae43e61c | d9e20e3e491ed05049f4f1a44021e96499a581ba | /src/soma.sci | fbc534cff4af08d687969a545f3b58713fce3220 | [] | no_license | josenalde/applied-math | 1e13000bec5e92fa828bee3193607cf8a200a604 | 76a9aab93d69e4be6b564cae72c441bc648444d4 | refs/heads/master | 2021-01-10T09:21:01.369665 | 2020-09-21T22:56:42 | 2020-09-21T22:56:42 | 46,852,259 | 3 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 52 | sci | soma.sci | function [x]= soma(a,b)
x = a+b;
endfunction
|
a6519bfbe342c5de9050d8de490c4a52027a0498 | a3c04dad7c659a81f513ac0f2b8bf15ea5cef322 | /scilab/code_ref.sce | 929872f3a0a20043a51b638999757108a6b3b7cd | [] | no_license | keckj/Projet_Spe | 5f7366a63bfc6bc57e46e713fb047c5a00224265 | 626b795cbf8ac55725c38a866c9dc1e694dc0ea9 | refs/heads/master | 2021-05-28T00:38:50.649981 | 2014-10-15T07:03:51 | 2014-10-15T07:03:51 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 3,240 | sce | code_ref.sce | // Parametres du modele d'Aliev-Paniflov
a=0.2; b=0.1; kk=8.0; M1= 0.07; M2=0.3; epsilon=0.01; d=5e-5;
// Definition des parametres d'execution
nx = 200; // Nombre de points de discretisation dans la direction x
ny = 200; // Nombre de points de discretisation dans la direction y
lx = 1.0; // Taille de la boite dans la direction x
ly = 1.0; // Taille de la boite dans la direction y
T = 1000.0; // Temps final
// Initialise les inconnues du probleme
E = zeros(nx,ny);
R = zeros(nx,ny);
// Sauvegarde du champs entre 2 iterations du schema temporel
E_prec = zeros(nx,ny);
// Pas d'espace
dx = lx/(nx);
x = dx/2.:dx:lx;
X = repmat(x,nx,1);
Y = repmat(x',1,nx);
// Definie une condition initiale
for i = 1:nx,
for j = 1:nx,
if((dx*i-0.5)*(dx*i-0.5)+(dx*j-0.5)*(dx*j-0.5) < 0.005) then
E(i,j) = 1.0;
end
end
end
//R(1:nx, ny/2:ny) = 1.;
E_prec = E;
// Contrainte pour le pas de temps
rp = kk*(b+1)*(b+1)/4.;
dte = (dx*dx)/(d*4+(dx*dx)*(rp+kk));
dtr = 1.0/(epsilon + (M1/M2) *rp);
// Pas de temps
dt = 0.95*min(dte,dtr);
// Coefficient multuplicateur du schema difference finie
alpha = d*dt/(dx*dx);
Ex=sparse([2:nx;1:nx-1]',ones(nx-1,1)',[nx,nx]);
Ax=Ex+Ex'- 2*speye(nx,nx);
Ax(1,1) = -1; Ax(nx,nx) = -1; // Conditions de Neumann
Ey=sparse([2:ny;1:ny-1]',ones(ny-1,1)',[ny,ny]);
Ay=Ey+Ey'-2*speye(ny,ny);
Ay(1,1) = -1; Ay(ny,ny) = -1; // Conditions de Neumann
A=speye(nx*ny,nx*ny) + alpha*((Ay .*. speye(nx,nx))+(speye(ny,ny) .*. Ax));
C = ((Ay .*. speye(nx,nx))+(speye(ny,ny) .*. Ax))/(dx*dx);
// Instant initial
t = 0.;
R = R(:);
i = 0;
k = 0;
// Resolution du systeme d'equation
while (t<T)
//while (t<2*dt)
t = t + dt;
i = i+1;
// Applique l'equation du champ electrique
E = A*E_prec(:);
// Resout les equations explicites
E = E - dt*(kk*E .* (E-a) .* (E-1) + E .*R);
R = R - dt*(epsilon + M1 *R ./ (E + M2)) .* (R+kk*E .* (E-b-1));
// Mise à jour du champ
E_prec = E;
if(modulo(i,10)==0)
fprintfMat("Model2D/E_" + string(k) + ".dat", matrix(E,nx,ny), "%5.2f");
fprintfMat("Model2D/R_" + string(k) + ".dat", matrix(R,nx,ny), "%5.2f");
//if(k<10) then
//fprintfMat("Model2D/E_0000" + string(k) + ".dat", matrix(E,nx,ny), "%5.2f");
//fprintfMat("Model2D/R_0000" + string(k) + ".dat", matrix(R,nx,ny), "%5.2f");
//elseif (k<100) then
//fprintfMat("Model2D/E_000" + string(k) + ".dat", matrix(E,nx,ny), "%5.2f");
//fprintfMat("Model2D/R_000" + string(k) + ".dat", matrix(R,nx,ny), "%5.2f");
//elseif (k<1000) then
//fprintfMat("Model2D/E_00" + string(k) + ".dat", matrix(E,nx,ny), "%5.2f");
//fprintfMat("Model2D/R_00" + string(k) + ".dat", matrix(R,nx,ny), "%5.2f");
//elseif (k<10000) then
//fprintfMat("Model2D/E_0" + string(k) + ".dat", matrix(E,nx,ny), "%5.2f");
//fprintfMat("Model2D/R_0" + string(k) + ".dat", matrix(R,nx,ny), "%5.2f");
//else
//fprintfMat("Model2D/E_" + string(k) + ".dat", matrix(E,nx,ny), "%5.2f");
//fprintfMat("Model2D/R_" + string(k) + ".dat", matrix(R,nx,ny), "%5.2f");
//end
k = k + 1;
end
end
//E = matrix(E,nx,ny);
//R = matrix(R,nx,ny);
//surf(E,'interp')
//f=gcf();
//f.color_map = jetcolormap(256);
//a = gca();
//a.view = "2d";
|
9384ead9a820dfc35cc89e536963fd6df4d3c067 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2219/CH13/EX13.11/Ex13_11.sce | b543407a37f79da0dc069c1dc1061e7a35dad091 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 585 | sce | Ex13_11.sce | //Chapter 13 example 11
//------------------------------------------------------------------------------
clc;
clear;
// Given data
DFM1 = 50; // dispersive fade margin
FFM = 30; // flat fade margin
DFM2 = 40; // dispersive fade margin
// Calculations
CFM1 = -10*log10(10^(-FFM/10) + 10^(-DFM1/10));
CFM2 = -10*log10(10^(-FFM/10) + 10^(-DFM2/10));
d_CFM = CFM1 -CFM2;
// Output
mprintf('CFM increases by %3.2f dB for a 10 dB increase in DFM',d_CFM);
//------------------------------------------------------------------------------
|
af5be6198082492e33d4d1ae2bcee2cc74ef4a5d | 449d555969bfd7befe906877abab098c6e63a0e8 | /557/CH14/EX14.5/5.sce | d98ab0a7c11a4d91085f24442c9a79876998b7d8 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 626 | sce | 5.sce | clc; funcprot(0); //Example 14.5
//Initializing the variables
D = 0.3;
Q = 0.8;
rho = 1.2;
f = 0.008;
L_entry = 10;
L_exit = 30;
Lt = 20*D;//Transition may be represented by a separation loss equivalent length of 20 × the approach duct diameter
K_entry = 4;
K_exit = 10
l = 0.4; // length of cross section
b = 0.2; // width of cross section
//Calculations
A = %pi*D^2/4;
Dp1 = 0.5*rho*Q^2/A^2*(K_entry + 4*f*(L_entry+Lt)/D);
area = l*b;
perimeter =2*(l+b);
m = area/perimeter;
Dp2 = 0.5*rho*Q^2/area^2*(K_exit + f*L_exit/m);
Dfan = Dp1+Dp2;
disp(Dfan,"fan Pressure input (N/m2) :"); |
8284a15cfa3d90f7226df79810271e61140e036a | 449d555969bfd7befe906877abab098c6e63a0e8 | /3648/CH14/EX14.6/Ex14_6.sce | 6fe4f315958c773651d8abdf34705ba5a312eacf | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 440 | sce | Ex14_6.sce | //Example 14_6
clc();
clear;
//To find the difference between the frequency of wave reaching the officer and the car
fo=10^10 //Units in Hz
vw=3*10^8 //Units in meters/sec
vc=25 //Units in meters/sec
f1=fo*((vw+vc)/(vw-vc)) //Units in Hz
f1=f1-10^10 //Units in Hertz
printf("The difference between the both frequencies is=%d Hz",f1)
//In text book answer printed wrong as 1670 Hz correct answer is 1666 Hz
|
6aa6b7f02d71f785a276a52b2123b35c5a8f2534 | 8217f7986187902617ad1bf89cb789618a90dd0a | /browsable_source/2.5/Unix-Windows/scilab-2.5/examples/man-examples/help.sce | 2f03a447499dcef5a1b5dc616728b5365a28fa95 | [
"LicenseRef-scancode-public-domain",
"LicenseRef-scancode-warranty-disclaimer"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 120 | sce | help.sce | %helps = [%helps;
"../../examples/man-examples/helpdir1", "Title1";"../../examples/man-examples/helpdir2", "Title2";];
|
6f73b7e24441b94750058d59494c7201ed90cc88 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3886/CH13/EX13.16/13_16.sce | 635c1dee23c674f8febe10ae298f8adb6182459d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 497 | sce | 13_16.sce | //person throws a ball
//refer fig. 13.23
//(a) Up the plane
atheta=35 //degree
aalpha=atheta+20 //degree
//maximum range
aRangemax=((30*30)/(9.81*(cosd(20))^2))*(sind(2*55-20)-sind(20)) //m
//(b) Down the plane
//refer fig. 13.24
btheta=(90+20)/2 //degree
balpha=55-20 //degree
//maximum range
bRangemax=((30*30)/(9.81*(cosd(-20))^2))*(sind(2*35+20)-sind(-20)) //m
printf("\nUp the plane\nMax Range=%.3f m",aRangemax)
printf("\nDown the plane\nMax Range=%.3f m",bRangemax)
|
6ea66b7e749ca80acfd2467091a1ccc291fdd832 | 449d555969bfd7befe906877abab098c6e63a0e8 | /608/CH6/EX6.09/6_09.sce | 1bd7c3bfa46f040992cd6ad092ade89df58012d2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 498 | sce | 6_09.sce | //Problem 6.09: A parallel plate capacitor has nineteen interleaved plates each 75 mm by 75 mm separated by mica sheets 0.2 mm thick. Assuming the relative permittivity of the mica is 5, calculate the capacitance of the capacitor.
//initializing the variables:
n = 19; // no. of plates
L = 75E-3; // in m
B = 75E-3; // in m
d = 0.2E-3; // in m
e0 = 8.85E-12; // in F/m
er = 5;
//calculation:
A = L*B
C = e0*er*A*(n-1)/d
printf("\n\nResult\n\n")
printf("\n Capacitance %.2E F\n",C) |
d748b69a5a4fe340162a44b4bd46a448dde3af1b | 449d555969bfd7befe906877abab098c6e63a0e8 | /3472/CH11/EX11.7/Example11_7.sce | 8f8365bafad985fb93f9fbde6b1d18489a603fd5 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 2,213 | sce | Example11_7.sce | // A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART II : TRANSMISSION AND DISTRIBUTION
// CHAPTER 4: OVERHEAD LINE INSULATORS
// EXAMPLE : 4.7 :
// Page number 186-187
clear ; clc ; close ; // Clear the work space and console
// Given data
n = 3.0 // Number of insulators
C_1 = 0.2 // Capacitance in terms of C
C_2 = 0.1 // Capacitance in terms of C
// Calculations
// Without guard ring
e_2_a = 13.0/13.3 // Potential across middle unit as top unit
e_1_a = 8.3/6.5*e_2_a // Potential across bottom unit
E_a = 1+(1/(8.3/6.5))+(1/e_1_a) // Voltage in terms of e_1
eff_a = E_a/n*100 // String efficiency(%)
e1_a = 1/E_a // Voltage across bottom unit as a % of line voltage
e2_a = 1/(8.3/6.5)*e1_a // Voltage across middle unit as a % of line voltage
e3_a = 1/e_1_a*e1_a // Voltage across top unit as a % of line voltage
// With guard ring
e_2_b = 15.4/15.5 // Potential across middle unit as top unit
e_1_b = 8.3/7.7*e_2_b // Potential across bottom unit
E_b = 1+(1/(8.3/7.7))+(1/e_1_b) // Voltage in terms of e_1
eff_b = E_b/n*100 // String efficiency(%)
e1_b = 1/E_b // Voltage across bottom unit as a % of line voltage
e2_b = 1/(8.3/7.7)*e1_b // Voltage across middle unit as a % of line voltage
e3_b = 1/e_1_b*e1_b // Voltage across top unit as a % of line voltage
// Results
disp("PART II - EXAMPLE : 4.7 : SOLUTION :-")
printf("\nWithout guard ring:")
printf("\n Voltage across bottom unit, e_1 = %.2f*E", e1_a)
printf("\n Voltage across bottom unit, e_2 = %.2f*E", e2_a)
printf("\n Voltage across bottom unit, e_3 = %.2f*E", e3_a)
printf("\n String efficiency = %.1f percent \n", eff_a)
printf("\nWith guard ring:")
printf("\n Voltage across bottom unit, e_1 = %.2f*E", e1_b)
printf("\n Voltage across bottom unit, e_2 = %.2f*E", e2_b)
printf("\n Voltage across bottom unit, e_3 = %.3f*E", e3_b)
printf("\n String efficiency = %.2f percent", eff_b)
|
f6e4961c9e2a84f9182bcafb46396955ccc7cd1d | 717ddeb7e700373742c617a95e25a2376565112c | /3165/CH4/EX4.9/Ex4_9.sce | eb7c6e7b7d5305b0bd5ff9f05205bee6c14721ad | [] | no_license | appucrossroads/Scilab-TBC-Uploads | b7ce9a8665d6253926fa8cc0989cda3c0db8e63d | 1d1c6f68fe7afb15ea12fd38492ec171491f8ce7 | refs/heads/master | 2021-01-22T04:15:15.512674 | 2017-09-19T11:51:56 | 2017-09-19T11:51:56 | 92,444,732 | 0 | 0 | null | 2017-05-25T21:09:20 | 2017-05-25T21:09:19 | null | UTF-8 | Scilab | false | false | 368 | sce | Ex4_9.sce | //Example 4 . 9
//MAXIMA SCILAB TOOLBOX REQUIRED FOR THIS PROGRAM
//Program to Ca l c u l a t e Group Delay and Phase Delay
// y ( n ) =0.25 x ( n )+x ( n1)+0.25 x ( n2)
clc ;
//w=po l y ( 0 , "w") ;
syms w;
theeta =-w;
gd= -diff( theeta ,w); //Group Delay
pd=- theeta /w; // Phase Delay
disp (gd , 'GROUP DELAY =' );
disp (pd , 'PHASE DELAY =' );
|
1408b0922ef6246fba846cbe8fa47dbbf6eb6d6d | 449d555969bfd7befe906877abab098c6e63a0e8 | /2666/CH16/EX16.5/16_5.sce | a57a83f8fb88857eed598d3e6f41a48264fc523d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 427 | sce | 16_5.sce | clc
//initialisation of variables
p=14.0//psia
t=140//F
r=6//ratio
w=1//ratio
Q=1300//Btu per lb
t1=1229//R
c=0.24//ft
w1=600//ft
f=517500//ft-lb per lb
v=15.86//ft
v1=2.64//cu ft
//CALCULATIONS
T=Q/(w*c)//R
T1=t1+T//R
T2=T1/(r)^0.4//R
Q1=w*(c)*(T2-w1)//Btu per lb
Qs=Q-Q1//Btu per lb
W=Qs/Q*100//percent
V=v*(T2/w1)//cu ft
M1=f/((V-v1)*144)//psia
//RESULTS
printf('the cylinder volume is=% f psia',M1)
|
1290c4324dc224eecb59f1526b808462d4833654 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3765/CH5/EX5.1/Ex5_1.sce | 7f4ced5793bbb6913a53fcf200be0953e3699f0d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,998 | sce | Ex5_1.sce | clc
// Example 5.1.py
// Consider the subsonic-supersonic flow through a convergent-divergent nozzle. The
// reservoir pressure and temperature are 10 atm and 300 K, repectively. There are
// two locations in the nozzle where A/Astar = 6, one in the convergent section and
// the other in the divergent section. At each location calculate M, p, T, u.
// Variable declaration
po = 10.0 // reservoir pressure (in atm)
To = 300.0 // reservoir temperature (in K)
A_by_Astar = 6.0 // area ratio
gamma1 = 1.4 // ratio of specific heat
R = 287.0 // gas constant (in J/ Kg K)
// Calculations
// from table A1 for subsonic flow with A/Astar = 6.0
Msub = 0.097 // mach number in converging section
po_by_p = 1.006 // po/p in converging section
To_by_T = 1.002 // To/T in converging section
psub = 1 / po_by_p * po // pressure (in atm) in converging section
Tsub = 1 / To_by_T * To // temperature (in K) in converging section
asub = (gamma1*R*Tsub** 0.5) // speed of sound (in m/s) in converging section
usub = Msub*asub // velocity (in m/s) in converging section
// from table A1 for supersonic flow with A/Astar = 6.0
Msup = 3.368 // mach number in diverging section
po_by_p = 63.13 // po/p in diverging section
To_by_T = 3.269 // To/T in diverging section
psup = 1 / po_by_p * po // pressure (in atm) in diverging section
Tsup = 1 / To_by_T * To // temperature (in K) in diverging section
asup = (gamma1*R*Tsup** 0.5) // speed of sound (in m/s) in diverging section
usup = Msup*asup // velocity (in m/s) in diverging section
// Results
printf("\n Converging section")
printf("\n M = %.3f", Msub)
printf("\n p = %.2f atm", psub)
printf("\n T = %.1f K", Tsub)
printf("\n u = %.2f m/s", usub)
printf("\n Divering section")
printf("\n M = %.3f", Msup)
printf("\n p = %.4f atm", psup)
printf("\n T = %.2f K", Tsup)
printf("\n u = %.2f m/s", usup)
|
fd799880334b299695a30b82e4271dbcff02c68b | 449d555969bfd7befe906877abab098c6e63a0e8 | /1436/CH1/EX1.2/ex1_2.sce | 1da8942d8241ee686f01571b9942e5e2b1d77377 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 432 | sce | ex1_2.sce | // Example 1.2, page no-53
clear
clc
span=1000
accuracy=1/100
err=span*accuracy
printf("(a)\nAs error can be either positive or negative ,\n the probable error at any point on the scale = %d°C",err)
max_scale=1200
Range_instr=max_scale+span
printf("\n(b)\nRange of the Instrument = %d°C",Range_instr)
meter_reading=700
per_of_err=(err/meter_reading)*100
printf("\n(c)\nPercentage of Error = ± %.2f%% ",per_of_err)
|
a71e9d9a3e237247a3e12ad136d1b7ddc82eb510 | 449d555969bfd7befe906877abab098c6e63a0e8 | /23/CH2/EX2.9/Example_2_9.sce | 6766cf7222e32a999f7ba7585477bc806628866b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,563 | sce | Example_2_9.sce | clear;
clc;
//Example 2.9
//Caption : Program To Find Work,Heat,del U and del H
//Given values
//Initial
P1=1;//Pressure=1bar
T1=298.15;//Temp=298.15K(25`C)
V1=0.02479;//Molar Volume=0.02479m^3/mol
//Final
P2=5;//Pressure=5bar
Cv=20.78;//J/mol/K
Cp=29.10;//J/mol/K
//to Find del_U,del_H by two processes
V2=V1*(P1/P2);//m^3(1 mol)
disp('m^3',V2,'Final Volume')
//Solution
//(a)-Cooling at const pressure followed by heating at const Volume
T2=T1*(V2/V1);//K
disp('K',T2,'Final Temperature')
del_H=round(Cp*(T2-T1));//J
Q1=del_H;//J
del_U1=round(del_H-(P1*(10^5)*(V2-V1)));//J
//Second Step
del_U2=round(Cv*(T1-T2));//J
Q2=del_U2;
Q=Q1+Q2;
del_U=0;
W=del_U-Q;//J
del_H=0;//const Temperature
disp('(a) Cooling at const Pressure Followed by Heating at const Volume')
disp('J',Q,'Heat Required')
disp('J',W,'Work Required')
disp('J',del_H,'Change in enthalpy')
disp('J',del_U,'Change in Energy')
//(b)-heating at Const Volume Followed by cooling at const Pressure
T2=T1*(P2/P1);//K
del_U1=round(Cv*(T2-T1));//J
Q1=del_U1;
del_H=round(Cp*(T1-T2));//J
Q2=del_H;
del_U2=round(del_H-(P2*(10^5)*(V2-V1)));//J
Q=Q1+Q2;
del_U=0;
W=del_U-Q;//J
del_H=0;//const Temperature
disp('(b) Heating at const Volume Followed by Cooling at const Pressure')
disp('J',Q,'Heat Required')
disp('J',W,'Work Required')
disp('J',del_H,'Change in enthalpy')
disp('J',del_U,'Change in Energy')
//Note
disp('Note : The Answer varies From That in the book because in Book 4956.44 has been rounded to 4958 which is absurd')
//End |
f3e2c3281294ec51e0067085a6d335ef35b28045 | 449d555969bfd7befe906877abab098c6e63a0e8 | /74/CH4/EX4.1/example1_sce.sce | a7bfe173e0941282e7d098645d5546c3b7bae78a | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 230 | sce | example1_sce.sce | // chapter 4
//example 4.1
// page 193 ,figure 4.20
R1=120;R2=51*10^3;//given
Vsat=15;Vcc=15;Vee=15;Vin=1;//given
Vut=((Vsat*R1)/(R1+R2));
disp(Vut)//result threshold in ampere
Vult=((-Vsat*R1)/(R1+R2));
disp(Vult)//ampere |
135f416cabc52bb8e48c6a2e37cb32b0b4162eed | 449d555969bfd7befe906877abab098c6e63a0e8 | /3775/CH5/EX5.3/Ex5_3.sce | 149f849c8a360ba3851624f7f6572f4748b8e0d4 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 285 | sce | Ex5_3.sce | //Ex 5.3 page 185
clc;
clear;
close;
Vs=400;//V
alfa=0.25;// duty cycle
delta_I=10;// A
L=0.5;// H
R=0;// ohm
Vo=alfa*Vs;//V
//Vo+L*di/dt=Vs -- putting dt=Ton & di=delta_I
Ton=delta_I/((Vs-Vo)/L)*1000;// ms
T=Ton/alfa;// ms
f=1/T*1000;//Hz
printf('\n chopping frequency = %d Hz',f)
|
cbc23faceb2a683f91f2957c30e6893dd1198e6c | 449d555969bfd7befe906877abab098c6e63a0e8 | /770/CH10/EX10.28/10_28.sce | 9cff2240804c01c6d18c872e3f71e6e09780ba22 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 3,724 | sce | 10_28.sce | clear;
clc;
funcprot(0);
//Example - 10.28
//Page number - 374
printf("Example - 10.28 and Page number - 375\n\n");
//Given
T = 150 + 273.15;//[K]
Tc = 647.1;//[K]
Pc = 220.55;//[bar]
Pc = Pc*10^(5);//[Pa]
w = 0.345;
R = 8.314;//[J/mol-K] - Universal gas constant
// Let us assume a pressure of 100 kPa.
P_1 = 100*10^(3);//[Pa]
// At 100 kPa and 423.15 K, from Peng-Robinson equation of stste
m = 0.37464 + 1.54226*w - 0.26992*w^(2);
Tr = T/Tc;
alpha = (1 + m*(1 - Tr^(1/2)))^(2);
a = ((0.45724*(R*Tc)^(2))/Pc)*alpha;//[Pa*m^(6)/mol^(2)]
b = (0.07780*R*Tc)/Pc;//[m^(3)/mol]
// Cubic form of Peng-Robinson equation of stste is given by
// V^(3)+(b-(R*T)/P)*V^(2)-((3*b^(2))+((2*R*T*b)/P)-(a/P))*V+b^(3)+((R*T*(b^(2))/P)-((a*b)/P)=0;
// Solving the cubic equation
deff('[y]=f(V)','y=V^(3)+(b-(R*T)/P_1)*V^(2)-((3*b^(2))+((2*R*T*b)/P_1)-(a/P_1))*V+b^(3)+((R*T*(b^(2)))/P_1)-((a*b)/P_1)');
V1 = fsolve(-1,f);
V2 = fsolve(0,f);
V3 = fsolve(1,f);
// The largest root and the smallest root is considered for liquid phase and vapour phase respectively.
V_liq = V1;//[m^(3)/mol] - Molar volume in liquid phase
V_vap = V3;//[m^(3)/mol] - Molar volume in vapour phase
// The compressibility factor is given by
Z_vap = (P_1*V_vap)/(R*T);// For liquid phase
Z_liq = (P_1*V_liq)/(R*T);// For vapour phase
// The expression for fugacity of Peng Robinson equation is
// log(f/P) = (Z-1) - log(Z-((P*b)/(R*T))) - (a/(2*2^(1/2)*b*R*T))*log((Z+(1+2^(1/2))*((P*b)/(R*T)))/((Z+(1-2^(1/2))*((P*b)/(R*T)))
// For vapour phase
f_P_vap = exp((Z_vap-1) - log(Z_vap-((P_1*b)/(R*T))) - (a/(2*2^(1/2)*b*R*T))*log((Z_vap+(1+2^(1/2))*((P_1*b)/(R*T)))/(Z_vap+(1-2^(1/2))*((P_1*b)/(R*T)))));
// For liquid phase
f_P_liq = exp((Z_liq-1) - log(Z_liq-((P_1*b)/(R*T))) - (a/(2*2^(1/2)*b*R*T))*log((Z_liq+(1+2^(1/2))*((P_1*b)/(R*T)))/(Z_liq+(1-2^(1/2))*((P_1*b)/(R*T)))));
// Therefore f_liq/f_vap can be calculated as
fL_fV = (f_P_liq/f_P_vap);
// The two values (f/P)_vap and (f/P)_vap are not same [ (f_P_liq/f_P_vap) >1 ]; therefore another pressure is to be assumed. The new pressure be
P_new = P_1*(f_P_liq/f_P_vap);//[Pa]
// At P_new and 423.15 K, from Peng-Robinson equation of stste
// V^(3)+(b-(R*T)/P)*V^(2)-((3*b^(2))+((2*R*T*b)/P)-(a/P))*V+b^(3)+((R*T*(b^(2))/P)-((a*b)/P)=0;
// Solving the cubic equation
deff('[y]=f(V)','y=V^(3)+(b-(R*T)/P_new)*V^(2)-((3*b^(2))+((2*R*T*b)/P_new)-(a/P_new))*V+b^(3)+((R*T*(b^(2)))/P_new)-((a*b)/P_new)');
V4 = fsolve(-1,f);
V5 = fsolve(0,f);
V6 = fsolve(1,f);
// The largest root and the smallest root is considered for liquid phase and vapour phase respectively.
V_liq_2 = V4;//[m^(3)/mol] - Molar volume in liquid phase
V_vap_2 = V6;//[m^(3)/mol] - Molar volume in vapour phase
// The compressibility factor is given by
Z_vap_2 = (P_new*V_vap_2)/(R*T);// For liquid phase
Z_liq_2 = (P_new*V_liq_2)/(R*T);// For vapour phase
// For vapour phase
f_P_vap_2 = exp((Z_vap_2-1) - log(Z_vap_2-((P_new*b)/(R*T))) - (a/(2*2^(1/2)*b*R*T))*log((Z_vap_2+(1+2^(1/2))*((P_new*b)/(R*T)))/(Z_vap_2+(1-2^(1/2))*((P_new*b)/(R*T)))));
// For liquid phase
f_P_liq_2 = exp((Z_liq_2-1) - log(Z_liq_2-((P_new*b)/(R*T))) - (a/(2*2^(1/2)*b*R*T))*log((Z_liq_2+(1+2^(1/2))*((P_new*b)/(R*T)))/(Z_liq_2+(1-2^(1/2))*((P_new*b)/(R*T)))));
// Therefore f_liq/f_vap can be calculated as
fL_fV_2 = (f_P_liq_2/f_P_vap_2);
// And new pressure is given by
P_new_prime = P_new*(f_P_liq_2/f_P_vap_2);//[Pa]
P_new_prime = P_new_prime*10^(-5);
// Since the change in pressure is small, so we can take this to be the vapour pressure at 150 C
printf(" The vapour pressure of water using Peng-Robinson equation of stste is %f bar\n",P_new_prime);
|
e63c26c2125135fa2261ae28da67035d0768e284 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1640/CH6/EX6.12/6_12.sce | 5861f1c7d69cf7468ff78e453aafd9ea157b0f77 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 198 | sce | 6_12.sce | clc
//initialisation of variables
v= 5 //ft/sec
Q= 500 //cuses
w= 25 //ft
g= 32.2 //ft/sec^2
//CALCULATIONS
h= (Q/v)/w
E= h+(v^2/(2*g))
//RESULTS
printf ('Specific energy = %.2f ft ',E)
|
18473ac7911db3f44554829b13bd7365b81e7498 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2741/CH10/EX10.3/ExampleA3.sce | f0a19ebbc070ba3982b98b036bb32fde4fa95d92 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 372 | sce | ExampleA3.sce | clc
clear
//Page number 470
//Input data
t=0;//The given temperature in degree centigrade
E=5.64*10^-21;//The mean kinetic energy of molecules of hydrogen in J
R=8.32;//Universal gas constant in J/mole-K
//Calculations
T=t+273;//The given temperature in K
N=(3/2)*(R/E)*(T);//Avogadros number
//Output
printf('The Avogadro number is N = %3.4g ',N)
|
c7a88a1f5cd10e051c5f8878a7f585215fb7ab86 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1682/CH4/EX4.4/Exa4_4.sce | bd20685b3b9d192f6cc86de8661c7763b2b91d34 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 538 | sce | Exa4_4.sce | //Exa 4.4
clc;
clear;
close;
//Alternative 1 :
disp("In 1st alternative down payment : Rs. 16,00,000");
//Alternative 2 :
P0=400000;//in Rs
P=200000;//in Rs
i=18;//in % per annum
n=10;//in years
//Formula : (P/A,i,n) : (((1+i/100)^n)-1)/((i/100)*(1+i/100)^n)
PW=P0+P*(((1+i/100)^n)-1)/((i/100)*(1+i/100)^n);//in RS
disp(PW,"The present worth of alternative 2 in RS. : ");
disp("The present worth of 2nd alternative is less than that of first one i.e., complete downpayment of Rs. 1600000. Hence, select 2nd alternative."); |
b9f690d3bf88b9668e74573b67f1396aed8a9ef2 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2705/CH7/EX7.8/Ex7_8.sce | 711505b0c01bc21f25ebcff4f46adff6dd079dec | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 945 | sce | Ex7_8.sce | clear;
clc;
disp('Example 7.8');
// aim : To determine
// the change of entropy
// Given values
m = .3;// [kg]
P1 = 350;// [kN/m^2]
T1 = 273+35;// [K]
P2 = 700;// [kN/m^2]
V3 = .2289;// [m^3]
cp = 1.006;// [kJ/kg K]
cv = .717;// [kJ/kg K]
// solution
// for constant volume process
R = cp-cv;// [kJ/kg K]
// using PV=mRT
V1 = m*R*T1/P1;// [m^3]
// for constant volume process P/T=constant,so
T2 = T1*P2/P1;// [K]
s21 = m*cv*log(P2/P1);// formula for entropy change for constant volume process
mprintf('\n The change of entropy in constant volume process is = %f kJ/kg K\n',s21);
// 'For the above part result given in the book is wrong
V2 = V1;
// for constant pressure process
T3 = T2*V3/V2;// [K]
s32 = m*cp*log(V3/V2);// [kJ/kg K]
mprintf('\n The change of entropy in constant pressure process is = %f kJ/kg K\n',s32);
// there is misprint in the book's result
// End
|
ce278aae5a13cc035267bf048629c6d57e22e9b8 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1529/CH21/EX21.6/21_06.sce | 8a836acdfbfe2189a64f5ae2f7c6a0af8d530ceb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 580 | sce | 21_06.sce | //Chapter 21, Problem 6
clc;
N=10; //turns ratio
v1=2.5e3; //primary voltage
P=5000; //power
v2=v1/N; //secondary voltage
i2=P/v2; //secondary current
Rl=v2/i2; //resistance in ohm
i1=i2/N; //primary current
printf("(a) Full-load secondary current = %d A\n\n",i2);
printf("(b) Minimum value of load resistance = %.1f ohms\n\n",Rl);
printf("(c) Primary current = %d A\n\n",i1);
|
e3bfe0845ebdce73518a2e75b0d73a37945a2ff7 | a62e0da056102916ac0fe63d8475e3c4114f86b1 | /set4/s_Control_Systems_S._Ghosh_773.zip/Control_Systems_S._Ghosh_773/CH2/EX2.01.01/2_01_01.sci | 656653f551ee177b448c050e669ced230d2ad5be | [] | no_license | hohiroki/Scilab_TBC | cb11e171e47a6cf15dad6594726c14443b23d512 | 98e421ab71b2e8be0c70d67cca3ecb53eeef1df6 | refs/heads/master | 2021-01-18T02:07:29.200029 | 2016-04-29T07:01:39 | 2016-04-29T07:01:39 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 105 | sci | 2_01_01.sci | errcatch(-1,"stop");mode(2);//laplace//
syms t s;
y=laplace('13',t,s);
disp(y,"ans=")
exit();
|
faf4f3633856eddf2f9512a45fcf8d9672278578 | a62e0da056102916ac0fe63d8475e3c4114f86b1 | /set9/s_Engineering_Physics_M._R._Srinivasan_3411.zip/Engineering_Physics_M._R._Srinivasan_3411/CH5/EX5.9.u1/Ex5_9_u1.sce | ca0a0e004ba02b234ee8cb0fa8ce99d448b0b011 | [] | no_license | hohiroki/Scilab_TBC | cb11e171e47a6cf15dad6594726c14443b23d512 | 98e421ab71b2e8be0c70d67cca3ecb53eeef1df6 | refs/heads/master | 2021-01-18T02:07:29.200029 | 2016-04-29T07:01:39 | 2016-04-29T07:01:39 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 473 | sce | Ex5_9_u1.sce | errcatch(-1,"stop");mode(2);//Example 5_9_u1
;
;
//To determine the interplanar spacing
h=6.63*10^-34 //units in m^2 kg s^-1
m=9.1*10^-31 //units in Kgs
e=1.6*10^-19 //units in coulombs
v=844 //units in Volts
lamda=h/sqrt(2*m*e*v) //units in meters
n=1
theta=58 //units in degrees
d=(n*lamda)/(2*sin(theta*(%pi/180))) //units in meters
printf("The interplanar spacing d=")
disp(d)
printf("meters")
exit();
|
0c4ee02d61a9bf6f3c2e14500e3e9ac4459aec66 | 449d555969bfd7befe906877abab098c6e63a0e8 | /98/CH18/EX18.19/example18_19.sce | 44365d15b69f9c3b0afa5fc75bc7b1799bd6bc1a | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 496 | sce | example18_19.sce | //Chapter 18
//Example 18_19
//Page 452
clear;clc;
mva=20;
kv=11;
xn=5;
x1=20;
x2=10;
Er=kv*1000/sqrt(3);
printf("Phase emf of red phase = %d V \n\n", Er);
//from the reactance diagram given in the text;
r_x1=x1/2;
r_x2=x2/2;
r_xn=30;
X1=r_x1*kv^2*10/mva/1000;
X2=r_x2*kv^2*10/mva/1000;
X0=r_xn*kv^2*10/mva/1000;
Ir=3*Er/(X1+X2+X0)/%i;
printf("X1 = %.3f ohm \n\n", X1);
printf("X2 = %.3f ohm \n\n", X2);
printf("X0 = %.3f ohm \n\n", X0);
printf("Fault current = j(%d) A \n\n", imag(Ir));
|
e5feefb44b95be9e263d8e1f41ce54e33e932050 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2453/CH2/EX2.6/2_6.sce | da066d9a684947425f480d9cc080a870c240b15c | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 641 | sce | 2_6.sce | //To calculate the distance between two adjacent atoms
MW = 23+35.5; //molecular weight of NaCl, gm
N = 6.023*10^23; //avagadro number, mol-1
rho = 2.18; //density of NaCl, gm/cm^3
M = MW/N; //mass of NaCl molecule, gm
n = rho/M; //number of molecules per unit volume
n = 2*n; //since NaCl is diatomic, atoms/cm^3
//length of edge of unit cube is n*a
//volume V = n^3*a^3 = 1 cm^3
V = 1; //volume of unit cube, cm^3
a = (V/n)^(1/3); //distance between two adjacent atoms, cm
a = a*10^8; //distance between two adjacent atoms,A
printf("distance between two adjacent atoms is %5.2f A",a);
|
27d8e18d55a4f624cc86826ef59c7931e6f93146 | 592800436ab73e7b6de03821a4fc923079657cc8 | /biseccion.sce | 80f842b6c5684f7015c5227bee7fabc0015c13f7 | [] | no_license | stevenyeahhh/Prueba | 9fd39333c4bf43558b868794f53632ddbbb3978e | 5f74987ff714d4f37608d7f1a4bbba0db587b7a3 | refs/heads/master | 2020-07-02T01:58:03.654505 | 2017-10-13T22:38:18 | 2017-10-13T22:38:18 | 29,828,603 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 422 | sce | biseccion.sce | function y=f(x)
y= exp(-x)-x
endfunction
a=-1;
b=1;
c=0;
d=0;
tol=1E-4;
i=0;
while(abs(a-b)>=tol)
i=i+1;
c=(a+b)/2;
d=abs(a-b);
fa=f(a);
fb=f(b);
fc=f(c);
if(fa*fc<0)then
a = a;
else
a = c;
end
if(fb*fc<0)then
b = b;
else
b = c;
end
printf("%d) %.6f\n",i,c)
end
|
1533efb9b6ed08fdbcfd6f38d7cd23e7f4728ad2 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3720/CH11/EX11.5/Ex11_5.sce | 61c10d76dcc49e743eb23ae117ecd6584485251a | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,229 | sce | Ex11_5.sce | //Example 11_5
clc;clear;
//Properties
rho_ag=1.20;// kg/m^3
rho_ac=0.312;// kg/m^3
C_Lmax1=1.52;// The maximum lift coefficient of the wing with flaps
C_Lmax2=3.48;// The maximum lift coefficient of the wing without flaps
//Given values
m=70000;// kg
A=150;// m^2
V=558;/// km/h
g=9.81;// m/s^2
// Calculation
//(a)
W=m*g;// N
V=V/3.6;// m/s
V_min1=sqrt((2*W)/(rho_ag*C_Lmax1*A));// m/s
V_min2=sqrt((2*W)/(rho_ag*C_Lmax2*A));// m/s
V_1s=1.2*V_min1*3.6;// 1 m/s=3.6 km/h
printf('(a)Without flaps:V_min1,safe =%0.0f km/h\n',V_1s);
V_2s=1.2*V_min2*3.6;// 1 m/s=3.6 km/h
printf(' With flaps:V_min2,safe =%0.0f km/h\n',V_2s);
//(b)
F_l=W;// N
C_l=F_l/(1/2*rho_ac*V^2*A);// The lift coefficient
//For the case with no flaps, the angle of attack corresponding to this value of C_L is determined from Fig. 11–45 to be
alpha=10;// The angle of attack in degree
printf('(b)The angle of attack,alpha~=%0.0f degree\n',alpha);
//(c)
// From Fig.11-45,C_d~=0.03
C_d=0.03;// The drag coefficient
F_d=(C_d*A*rho_ac*(V^2/2))/1000;//kN
P=F_d*V;// kW
printf('(c)The power that needs to be supplied to provide enough thrust to overcome wing drag,P=%0.0f kW\n',P);
// The answer vary due to round off error
|
6476b31729486f385e9ec3ead5ad616a7b611b26 | f8bb2d5287f73944d0ae4a8ddb85a18b420ce288 | /Scilab/myfunc4.sce | 3cb302c91e124402af7a7616b98162f6d623dc26 | [] | no_license | nishizumi-lab/sample | 1a2eb3baf0139e9db99b0c515ac618eb2ed65ad2 | fcdf07eb6d5c9ad9c6f5ea539046c334afffe8d2 | refs/heads/master | 2023-08-22T15:52:04.998574 | 2023-08-20T04:09:08 | 2023-08-20T04:09:08 | 248,222,555 | 8 | 20 | null | 2023-02-02T09:03:50 | 2020-03-18T12:14:34 | C | UTF-8 | Scilab | false | false | 116 | sce | myfunc4.sce | function xdot = myfunc4(t,x)
xdot = zeros(2,1);
a=0.5;
xdot(1) = -a*x(1)-sin(x(2));
xdot(2) = x(1);
endfunction
|
90800983568235f7f4d2bd2e5c0bb2309fd38cd4 | 449d555969bfd7befe906877abab098c6e63a0e8 | /479/CH3/EX3.10/Example_3_10.sce | c998d9d0054d4889507b74f90b3323d597d13bcd | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 682 | sce | Example_3_10.sce | //Chemical Engineering Thermodynamics
//Chapter 3
//First Law of Thermodynamics
//Example 3.10
clear;
clc;
//Given
V = 0.3;//Volume of the tank in m^3
P1 = 1;//Initial pressure of the tank in atm
P2 = 0;//Final pressure of the tank in atm
T = 298;//Temperature of the tank in K
t = 10;//evacuation time in min
//delN=(V/(R*T)*delP)..(a) change in moles as V and T are constant
//delW=delN*R*T*lnP..(b)pump work required
//From (a)&(b),delW=V*delP*lnP
//To calculate the pump work required
//On doing integration of dW we will get
W = V*(P1-P2);//pump work done in J/sec
W1=(W*(1.033*10^4))/(75*600);
mprintf('The pump work required is %f hp',W1);
//end |
48ce40c29dd9aedf4e16709bfac1a03afb70971c | 449d555969bfd7befe906877abab098c6e63a0e8 | /3250/CH2/EX2.6/Ex2_6.sce | 16eafd4d4c7c258d1a30a82a28b4ef97ed64f521 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,312 | sce | Ex2_6.sce | clc
// Given that
thetaF= 1540 // Temperature of mould face in degree centigrate
ThetaO = 28 // Initial temperature of mould in Degree centigrate
L= 272e3 // Latent heat of iron in J/Kg
Dm = 7850 // Density of iron in Kg/m^3
Cs = 0.67e+3 //Specific heat of iron in J/Kg-K
C = 0.376e3 //Specific heat of copper in J/Kg-K
Ks = 83 // Conductivity of iron in W/m-K
K = 398 // Conductivity of copper in W/m-K
D= 8960 // Density of copper in Kg/m^3
h = .1 // Height in m
// Sample Problem 6 on page no. 73
printf("\n # PROBLEM 2.6 # \n")
zeta1=0.98//By solving eqauation- zeta*exp(zeta^2)*erf(zeta)=((thetaF-thetaO)*Cs)/(sqrt(pi)*L), zeta = 0.98
AlphaS = Ks /(Dm*Cs)
ts1 = h^2 / (16*(zeta1^2) * AlphaS)//In sec
ts1_=ts1/3600 // In hour
Phi = sqrt((Ks*Dm*Cs)/(K*D*C))
zeta2=0.815//By solving eqauation- zeta*exp(zeta^2)*(erf(zeta)+Phi)=((thetaF-thetaO)*Cs)/(sqrt(pi)*L), zeta = 0.815
ts2 = h^2 / (16*(zeta2^2) * AlphaS)//In sec
ts2_=ts2/3600 // In hour
thetaS= (thetaF-(L*(sqrt(%pi))*zeta2*(exp(zeta2^2))*erf(zeta2))/Cs)
printf("\n Solidification time for slab-shaped casting when the casting is done in a water cooled copper mould = %f hr,\n Solidification time for slab-shaped casting when the casting is done in a very thick copper mould = %f hr,\n The surface temperature of the mould = %f° C", ts1_,ts2_,thetaS)
|
287ba79282a1e1ef9b64b405f5ab20b95f00cf2a | cc5390e0e818f2a8e8e3d9d733757f53f17b359a | /tools/dsp_debugger/dsp_iv3/dsp_iv3_v4_dirty_test_0_31_107_ref.sci | b6d299617b97b497f7e19ba1354089ff5a572140 | [] | no_license | AaronZLT/CL-EDEN-kernel | 53319cc470fe232e8366cc6773eca141f7d4618b | 2cacf94046cb8920a677ceb3bc30eb1eb6f86bdf | refs/heads/main | 2023-07-14T06:25:18.727255 | 2021-08-27T05:14:01 | 2021-08-27T05:14:01 | 400,395,663 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 370 | sci | dsp_iv3_v4_dirty_test_0_31_107_ref.sci | #yaml
dsp_debug_scenario:
name: IV3_cmdq_test
local:
model_file: dsp_iv3/iv3_dirty.nnc
input:
- dsp_iv3/nnc_input_0.bin
golden:
- dsp_iv3/nnc_output_0.bin
target:
model_file: /data/raw/iv3_dirty.nnc
input:
- /data/raw/nnc_input_0.bin
golden:
- /data/raw/nnc_output_0.bin
max_layer: 108
|
2d29b766698cbc701fe3f92e06b2fe000114e3fa | 449d555969bfd7befe906877abab098c6e63a0e8 | /764/CH7/EX7.23.a/data7_23.sci | 7ca327ea5c153b8a3718f93ce5c4015dc0a5366d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 766 | sci | data7_23.sci |
//(Threaded Joints) Example 7.23
//Refer Fig.7.47 on page 267
//Maximum pressure in the vessel Pmax (MPa)
Pmax = 1
//Minimum pressure in the vessel Pmin (MPa)
Pmin = 0
//Seating pressure for the gasket PSeat (MPa)
PSeat = 5
//Number of bolts N
N = 8
//Assume the stiffness of the bolts to be 1N/mm kb
kb = 1
//Calculate the stiffness of the parts kc
kc = 4 * kb
//Factor of safety fs
fs = 2
//Ultimate tensile strength of bolt material Sut (N/mm2)
Sut = 780
//Yield tensile strength of the bolt material Syt (N/mm2)
Syt = 580
//Endurance limit in bending Sdash (N/mm2)
Sdash = 260
//Fatigue stress concentration factor Kf
Kf = 3
//Inner diameter of the gasket Di (mm)
Di = 300
//Outer diameter of the gasket Do (mm)
Do = 300 + (2 * 50)
|
c30ba07d8563c919b90bfab1159184894b59b9dd | 449d555969bfd7befe906877abab098c6e63a0e8 | /2882/CH9/EX9.8/Ex9_8.sce | 93878ed72af3b427aeaa0373eeb35c85b41b0bb5 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,406 | sce | Ex9_8.sce | //Tested on Windows 7 Ultimate 32-bit
//Chapter 9 Frequency Response of Amplifier Pg no. 310
clear;
clc;
//Given
VCC=15;//collector supply voltage in volts
RC=2.2D3;//collector resistance in ohms
RE=470;//emitter resistance in ohms
R1=33D3;//divider network resistance R1 in ohms
R2=10D3;//divider network resistance R2 in ohms
VBE=0.7;//forward voltage drop of emitter diode in volts
B=150;//DC CE current gain beta
Rs=600;//source internal impedance in ohms
RL=4.7D3;//load resistance in ohms
C1=0.1D-6;//input coupling capacitance in farads
C2=50D-6;//emitter bypass capacitance in farads
C3=0.1D-6;//output coupling capacitance in farads
re=4;//a.c. emitter resistance in ohms
//Solution
Rin=1/(1/R1+1/R2+1/(B*re));//thevenised input network resistance in ohms
fc_input=1/(2*%pi*(Rs+Rin)*C1);//input cutoff frequency in hertz
Rth=1/(1/R1+1/R2+1/Rs);//thevenised bypass network resistance in ohms
Rin_emitter=7.7;//resistance looking into the emitter in ohms
fc_bypass=1/(2*%pi*1/(1/RE+1/Rin_emitter)*C2);//bypass cutoff frequency in hertz
Rout=RC+RL;//thevenised output network resistance in ohms
fc_output=1/(2*%pi*Rout*C3);//output cutoff frequency in hertz
s=poly(0,'s')
F=syslin('c',8*%pi^3*(fc_input*fc_bypass*fc_output)/(s+2*%pi*fc_output)/(s+2*%pi*fc_bypass)/(s+2*%pi*fc_input));
clf;
gainplot(F,100,10000,"Bode Plot for given amplifier in Example 9.8");
|
f8dd22e49194869eadef6a81bfe92f827945a4a1 | 8217f7986187902617ad1bf89cb789618a90dd0a | /browsable_source/2.4/Unix-Windows/scilab-2.4/macros/scicos_blocks/IFTHEL_f.sci | f8973b960a2dd086af9dc92657675161b5b71ff5 | [
"LicenseRef-scancode-public-domain",
"LicenseRef-scancode-warranty-disclaimer"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 1,064 | sci | IFTHEL_f.sci | function [x,y,typ]=IFTHEL_f(job,arg1,arg2)
// Copyright INRIA
x=[];y=[];typ=[]
select job
case 'plot' then
standard_draw(arg1)
case 'getinputs' then
[x,y,typ]=standard_inputs(arg1)
case 'getoutputs' then
[x,y,typ]=standard_outputs(arg1)
case 'getorigin' then
[x,y]=standard_origin(arg1)
case 'set' then
x=arg1;
graphics=arg1(2);label=graphics(4)
model=arg1(3);
if label==[] then label=string(1);end
while %t do
[ok,inh,label]=getvalue('Set parameters',..
['Inherit (1: no, 0: yes)'],list('vec',1),label)
if ~ok then break,end
if inh==0 then inh=[]; else inh=1;end
[model,graphics,ok]=check_io(model,graphics,1,[],inh,[1;1])
if ok then
graphics(4)=label;
model(4)=inh;
model(1)(2)=-1
x(2)=graphics;x(3)=model
break
end
end
case 'define' then
model=list(list('ifthel',-1),1,[],1,[1;1],[],[],[],[],'l',[-1 -1],[%f %f],' ',list())
gr_i=['txt=[''If in>=0'';'' '';'' then else''];';
'xstringb(orig(1),orig(2),txt,sz(1),sz(2),''fill'');']
label=string(1);
x=standard_define([3 3],model,label,gr_i)
end
|
6c4d1eaf028a1328cfb6b076ddeba2332402903b | 449d555969bfd7befe906877abab098c6e63a0e8 | /1655/CH2/EX2.7.11/Example_2_7_11.sce | 3ff611c7aba32f8bbe7dc9764fc9675dbe963d6d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,067 | sce | Example_2_7_11.sce | // Example 2.7.11 page 2.29
clc;
clear all;
n1=1.5; //refractive index of core
n2=1.38; //refractive index of cladding
lamda=1300d-9; //Wavelength
a=25d-6; //core radius
NA=sqrt(n1^2 - n2^2); //computing Numerical aperture
theta= asind(NA); //computing acceptance angle
solid_angle=%pi*(NA)^2; //computing solid angle
v= 2*%pi*a*NA/lamda; //computing normalized frequency
M=(v)^2/2; //computing guided modes
M=round(M);
printf("\nNumerical aperture is %.2f.\nNormalized frequency is %.2f.\nAcceptance angle is %.2f degrees.\nSolid angle is %.3f radians.\nTotal number of modes are %d.",NA,v,theta,solid_angle,M);
printf("\n\n NOTE - Calculation error in the book.\n(2.25-1.9)^0.5=0.59; they have taken 0.35");
//Calculation error in the book.(2.25-1.9)^0.5=0.59; they have taken 0.35
//answers in the book,
//Numerical aperture is 0.35.(incorrect)
//Normalized frequency is 42.26.(incorrect)
//Acceptance angle is 20.48 degrees.(incorrect)
//Solid angle is 0.384 radians.(incorrect)
|
7859ef06f29332ecc2853a8718348cfadec469ea | 449d555969bfd7befe906877abab098c6e63a0e8 | /260/CH1/EX1.4/1_4.sce | c0469f5a574c93c3241c053ba509ca2f30f777e9 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 144 | sce | 1_4.sce | //Eg-1.4
//pg-13
clear
clc
a=input("enter any number")
r=a-round(a/2)*2;
if r==0 then
disp("even number")
else
disp("odd number")
end |
b4298528ed8fa75b11d9fb9a6bd3cbeb4864c527 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2969/CH6/EX6.2/Ex6_2.sce | 1e278b81bf9c9b741785ae11e551053ae470f42b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,134 | sce | Ex6_2.sce | clc
clear
//DATA GIVEN
Ms=5.4; //mass of steam used in kg/kWh
p=50; //pressure of steam in bar
Tsup=350; //temp. of steam in deg celsius
eta=82; //boiler efficiency in %
Tfw=150; //feed water temp. in deg cel;sius
C=28100; //calorific value of coal in kJ
rate=500; //cost of coal/tonne in Rs
//boiler efficiency is given by, eta=Ms*(hsup-hf1)/(Mf*C)
//from steam table, at 45 bar and 350deg celsius, hsup=3068.4 kJ/kg
h=3068.4; //enthalpy at 45 bar and 350 deg celsius
hf1=4.18*(Tfw-0); //hf1 at 150 deg celsius in kJ/kg
//subs. these in eq. of boiler efficiency
Mf=Ms*(h-hf1)/((eta/100)*C); //mass of coal required in kg/kWh
cost=(Mf/1000)*rate*100; //cost of coal in paisa/kWh
printf(' (i) The mass of coal required is: %5.3f kg/kWh. \n',Mf);
printf(' (ii) The Total cost of fuel(coal) is: %2.1f paisa/kWh. \n',cost);
//NOTE:in text book
//in question pressure is given as =50 bar
//but from steam table enthalpy is found at 45 bar
|
232601fd693a19667581798f0a9952125c1e1d35 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1628/CH3/EX3.13/Ex3_13.sce | 126e2988a4bc370482d23a7e2e977c21a5937ee2 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 626 | sce | Ex3_13.sce |
// Examle 3.13
// From Diagram (3.26) Apply KVL to get 24-4I-2I+18I= 0
I=(-24/12); // Current
disp(' The value of Current = '+string(I)+' Amp');
V1=4*I; // Voltage across 4 Ohm Resistor
p=-(4.5*V1*I); // Power absorbed
disp(' Power absorbed by dependent source = '+string(p)+' Watt');
V=24; // Independent voltage source
R=V/I; // Resistence Seen from Independent source
disp(' Resistence Seen from Independent source = '+string(R)+' Ohm');
// p 67 3.13
|
b629c29baef2d0325b34fd4df71bef72ab11d21d | 8bc8cad4ff08d4d9e353e7a5a1baa8b188b994f3 | /autoAndCrossCorrelationProperties/autoAndCrossCorrelationProperties.sce | 912c6a6cda279e0d6681f3bf2898e6af9e158575 | [] | no_license | ROHITDH/scilabBasics | 259c74030901258dbe8d77c61eacd467fc58b9de | f29b20b645d0f8181a3abc14c0d03ff59b69bd40 | refs/heads/main | 2023-02-22T12:21:31.459103 | 2021-01-27T01:24:22 | 2021-01-27T01:24:22 | 333,165,290 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,960 | sce | autoAndCrossCorrelationProperties.sce | //auto and cross correlation properties
clc
clear
close
///////////////////////////////
//auto correlation properties//
///////////////////////////////
x = input("sequence x(n): ")
y = input("sequence y(n): ")
disp("Auto correlation properties: ")
//1. rxx(l) = rxx(-l)
disp("1. rxx(l) = rxx(-l)")
[lhs lag1] = xcorr(x,x)
[rhs lag2] = xcorr(x,x)
rhs = flipdim(rhs,2)
disp("rxx(l) : ",lhs)
disp("rxx(-l): ",rhs)
//2. |rxx(l)| <= sqrt(rxx(0).rxx(0))
disp("2. |rxx(l)| <= sqrt(rxx(0).rxx(0))")
[lhs1 lag3] = xcorr(x,x)
rhs1 = sqrt(max(xcorr(x,x))*max(xcorr(x,x)))
disp("lhs: ",lhs1)
disp("no samples in lhs in greater than : ",rhs1)
//plots
figure(0)
subplot(211)
plot2d3(lag1,lhs)
plot(lag1,lhs,'red.')
title("rxx(l)")
xlabel("---> samples n")
ylabel("Amplitude")
a1 = gca()
a1.x_location = 'origin'
a1.y_location = 'origin'
subplot(212)
plot2d3(lag2,rhs)
plot(lag2,rhs,'red.')
title("rxx(-l)")
xlabel("---> samples n")
ylabel("Amplitude")
a2 = gca()
a2.x_location = 'origin'
a2.y_location = 'origin'
disp("--------------------------------------")
///////////////////////////////
//cross correlation properties//
///////////////////////////////
disp("Cross correlation properties: ")
//1. rxy(l) = rxy(-l)
disp("1. rxy(l) = rxy(-l)")
[lhs lag1] = xcorr(x,y)
[rhs lag2] = xcorr(x,y)
rhs = flipdim(rhs,2)
disp("rxy(l) : ",lhs)
disp("rxy(-l): ",rhs)
//2. |rxy(l)| <= sqrt(rxx(0).ryy(0))
disp("2. |rxy(l)| <= sqrt(rxx(0).ryy(0))")
[lhs1 lag3] = xcorr(x,y)
rhs1 = sqrt(max(xcorr(x,x))*max(xcorr(y,y)))
disp("lhs: ",lhs1)
disp("no samples in lhs in greater than : ",rhs1)
//plots
figure(1)
subplot(211)
plot2d3(lag1,lhs)
plot(lag1,lhs,'red.')
title("rxy(l)")
xlabel("---> samples n")
ylabel("Amplitude")
a1 = gca()
a1.x_location = 'origin'
a1.y_location = 'origin'
subplot(212)
plot2d3(lag2,rhs)
plot(lag2,rhs,'red.')
title("rxy(-l)")
xlabel("---> samples n")
ylabel("Amplitude")
a2 = gca()
a2.x_location = 'origin'
a2.y_location = 'origin'
|
a92f6bc9aa92a0d012ed1ea9c383dbef98dcaa37 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3269/CH4/EX4.4/Ex4_4.sce | 55223945705a203a362979ea686a3c04ee550bb3 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,115 | sce | Ex4_4.sce | // Example 4.4
clear all;
clc;
// Given data
ratpower = 1075; // Output rated electrical power in MWe of the reactor
delpower_yr = 255000; // Net output power delivered in one year in terms of MWd
time_refuel = 28; // Number of days the plant was shutdown for refuelling
time_repairs = 45; // Number of days the plant was shutdown for repairs
time_convrepairs = 18; // Number of days the plant was shutdown for conventional repairs
// 1.
// 1 year = 365 days
ratpower_yr = ratpower*365; // Net output rated power in one year in terms of MWd
// Calculation
cap_factor = delpower_yr/ratpower_yr;
// Result
printf(" \n Plant capacity factor = %d percent\n",ceil(cap_factor*100));
// 2.
// Number of days the plant was shutdown in one year
total_shutdown = time_refuel+time_repairs+time_convrepairs;
// Number of days the plant was operable in one year
total_operation = 365-total_shutdown;
// Calculation
ava_factor = total_operation/365;
// Result
printf(" \n Plant availability factor = %d percent\n",ava_factor*100);
|
d1f79e517da0507a8d1cd0b8ed0ac6c00110e38a | 449d555969bfd7befe906877abab098c6e63a0e8 | /3137/CH18/EX18.25/Ex18_25.sce | 743a626fd1182156e5f116ddbe3f59141cbce266 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 285 | sce | Ex18_25.sce | //Initilisation of variables
d=2/12 //ft
v=80 //ft/s
g=32.2 //ft/s^2
//Calculations
//Mass flow reate without time
m=(1/4)*%pi*d^2*v*(62.4/g)
//Let P=force of plate on mass m of water
P=m*(0-v) //lb
//Result
clc
printf('The force water exerts on the plate is %f lb',-P )
|
4936660a154b0674682fd57095bd1478405e21c0 | 5b0a8751addde9367ae3be6487f21dc2431d02d6 | /Inc16.tst | 4dc8447d764755e91534a38c4f157ee6cc0b5c29 | [] | no_license | AliAmmarDev/Computer-processor-components | 5fb80726306186a2b970d6a8f30f6bc986ede5e2 | b2fdf4ea7358fec89e2b277c2343931f66882506 | refs/heads/master | 2022-12-04T09:42:43.656194 | 2020-08-26T23:11:00 | 2020-08-26T23:11:00 | 290,622,151 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 306 | tst | Inc16.tst | load Inc16.hdl,
output-file Inc16.out,
compare-to Inc16.cmp,
output-list x%B1.16.1 out%B1.16.1;
set x %B0000000000000000, // in = 0
eval,
output;
set x %B1111111111111111, // in = -1
eval,
output;
set x %B0000000000000101, // in = 5
eval,
output;
set x %B1111111111111011, // in = -5
eval,
output;
|
9a9123ecd8911cfd11f8ee8b94a9686147aa0fe9 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2276/CH3/EX3.14/chapter3_ex14.sce | 70e3d92582e600df6a0f0372fdc75b15382685da | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 774 | sce | chapter3_ex14.sce | clc
clear
//input
v=240;//voltage of a d.c. shunt motor in volts
ra=0.4;//armature resistance of d.c. shunt motor in ohms
rf=120;//armature resistance of d.c. shunt motor in ohms
is=22;//supply current in amperes
w=600;//angular velocity of motor in rev/min
il=30;//load current in amperes
//calculations
//armature reaction is neglected
W=(w*(2*%pi))/60;//angular velocity in rad/s
fi=v/rf;//feild current in amperes
ai=is-fi;//armature current in amperes
e=v-(ai*ra);//e.m.f. in volts
t1=(e*ai)/W;//torque when current is 20A in newton meter
aI=il-fi;//changed armature current in amperes
t2=t1*(aI/is);//torque when current is 30A in newton meter
//output
mprintf('with a supply current of 30A the motor produces a total torque of %3.1f Nm',t2)
|
43b87198d064f4c74962b740d9e2852ea5bb29e4 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3863/CH4/EX4.15/Ex4_15.sce | 28208b0b90e6cd45de8ae62460d73cec0bb89599 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 917 | sce | Ex4_15.sce | clear
//
//Given
//Variable declaration
L=1.82*1000 //Length of rod in mm
h1=30 //Height through which load falls in mm
h2=47.5 //Fallen height in mm
sigma=157 //Maximum stress induced in N/sq.mm
E=2.1e5 //Youngs modulus in N/sq.mm
//Calculation
U=sigma**2/(2*E) //Strain energy stored in the rod in N-m
delL=sigma*L/E //Extension of the rod in mm
Tot_dist=h1+delL //Total distance in mm
//case(i):Stress induced in the rod if the load is applied gradually
sigma1=((U/Tot_dist)*L)
//case(ii):Maximum stress if the load had fallen from a height of 47.5 mm
sigma2=((sigma1)*(1+(sqrt(1+((2*E*h2)/(sigma1*L))))))
//Result
printf("\n Stress induced in the rod = %.1f N/mm^2",sigma1)
printf("\n NOTE:The given answer for stress(2nd case) in the book is wrong.The correct answer is,")
printf("\n Maximum stress if the load has fallen = %.2f N/mm^2",sigma2)
|
d51ad4fd25bd011c7c9132c9481aada2dc9faeda | 449d555969bfd7befe906877abab098c6e63a0e8 | /3554/CH15/EX15.9/Ex15_9.sce | fadd5f844db12e863f6963161e4df4307e37dece | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 442 | sce | Ex15_9.sce | // Exa 15.9
clc;
clear all;
// Given data
// Refering Fig. 15.2(a)- All pass filter
f=2.5;// Input frequency in kHz
// Solution
disp(" Let C=0.01 micro farads and R= 15 k Ohms");
C=0.01;// micro farads
R=15;// k Ohms
Phi=2*atan(2*%pi*f*C*R); // phase angle in radians
printf(' This means that the output voltage Vo has the same frequency and amplitude as the input voltage but lags it by - %d degrees\n',Phi*180/%pi);
|
8942e8e7097331ccdbee17a6257f5ae222ce62c3 | 449d555969bfd7befe906877abab098c6e63a0e8 | /671/CH12/EX12.6/12_6.sce | 85e50c8431bb8e47d1c9ec946a9e161a204acb7e | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 334 | sce | 12_6.sce |
Tmax=200
Tstart=80
p=poly([1,-2*Tmax/Tstart,1],"smaxT","coeff")
smaxT=roots(p)
smaxT=smaxT(2)
disp(smaxT)
p=poly([1,-4,1],"w","coeff")
w=roots(p)
sfl=smaxT/w(1)
disp(sfl)
ratio=sqrt(((smaxT/sfl)^2+1)/(smaxT^2+1))
disp(ratio)
p=poly([1,-((smaxT/sfl)^2+1)*sfl,smaxT^2],"k","coeff")
k=roots(p)
k=k(2)
disp(k)
|
4219d9c3625c3677cc60da8316c7be36a3b7bb34 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2360/CH7/EX7.5/ex7_5.sce | b1f962648d426cffb093e5467cff20d6bb1f1409 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 198 | sce | ex7_5.sce | // Exa 7.5
format('v',7);clc;clear;close;
// Given data
y1 = 8;// in units
y2 = 10;// in units
phi = asind(y1/y2);// phase difference in degree
disp(phi,"The phase difference in degree is");
|
392da3688b6d3aa8c644ea3531d059832e9187c7 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1727/CH7/EX7.9/7_9.sce | 55778e060df3be3bec92f02c25a4535ed4885819 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 333 | sce | 7_9.sce | clc
//Initialization of variables
g=9.81 //m/s^2
rho=10^3 //kg/m^3
d=0.3 //m
per=25/100
Q=0.1 //m^3/s
k0=0.025*10^-2 //m
nu=0.000001
year=10
//calculations
V=Q/(%pi/4 *d^2)
RN=V*d/nu
e1=k0/d
f1=0.019
f2=(1+per)*f1
e2=0.002
k2=e2*d
rate = (k2-k0)*100/year
//results
printf("Rate of increase =%.4f cm/year",rate)
|
78f97efd566046ec5a8b56618558d485e4fa26a5 | 7edeaa4920427595d3601e218f8de85be39cf22d | /TP/tp1/fact.sci | 9f4b0c06a40602ccfd81c647490d15d6e401621a | [] | no_license | BiteKirby3/Math-is-so-fun | 96fb19815c7ab46d1a8e81771e0e70170ee503ab | 20db5e67e73a5ccfd1599cf56718c9d6f0adaa0c | refs/heads/main | 2023-08-27T23:18:38.117913 | 2021-10-11T22:59:20 | 2021-10-11T22:59:20 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 278 | sci | fact.sci | function [f] = fact (n)
//cette fonction calcule la factorielle d'un nombre entier
if (n-floor(n)~= 0 | n<0)
error("erreur dans fact : l""argument doit etre entier");
end
if n==0
f=1;
else
f = prod(1:n)
end
endfunction
|
1a1f45f160622cd8a92c9eda0b7bdd54426b6c1b | 449d555969bfd7befe906877abab098c6e63a0e8 | /3760/CH5/EX5.10/Ex5_10.sce | 552e5ef1960109392892a792bfa066732d460e9b | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,239 | sce | Ex5_10.sce | clc;
v=6600; // rated voltage of motor
xs=20 ; // per phase synchronous reactance
p=500000; // VA rating of motor
il=p/(sqrt(3)*v); // rated armature current
vt=v/sqrt(3); // per phase rated voltage
disp('case a');
de=10; // load angle
c1=1;
c2=-2*vt*cosd(de);
c3=vt^2-(il*xs)^2; // coefficients of quadratic equation in Ef
p= [ c1 c2 c3 ];
Ef=roots(p);
printf('Per phase excitation EMF at lagging pf is %f v\n',Ef(2));
printf('Excitation line EMF at lagging pf is %f v\n',sqrt(3)*Ef(2));
printf('Per phase excitation EMF at leading pf is %f v\n',Ef(1));
printf('Excitation line EMF at leading pf is %f v\n',sqrt(3)*Ef(1));
disp('case b');
disp('For lagging pf');
pd=(3*vt*Ef(2)*sind(de))/xs;
pf=pd/(sqrt(3)*v*il);
printf('Mechanical power developed is %f W\n',pd);
printf('Power factor is %f lagging\n',pf);
disp('For leading pf');
pd=(3*vt*Ef(1)*sind(de))/xs;
pf=pd/(sqrt(3)*v*il);
printf('Mechanical power developed is %f W\n',pd);
printf('Power factor is %f leading\n',pf);
disp('case c');
p=200000; // delivered power
de=90; // load angle for falling out of step
// motor falls out of step at de= 90 degrees
Ef=(p*xs)/(3*sind(de)*vt);
printf('Minimum excitation voltage per phase is %f v',Ef);
|
9e3adbc6a052d5c4c2bfc2b36ad2e6a6634b1489 | 449d555969bfd7befe906877abab098c6e63a0e8 | /842/CH3/EX3.8/Example3_8.sce | 93da994c5ce421fe972ec6fb8d14704651da6db6 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,795 | sce | Example3_8.sce | //clear//
//Example3.8:Fourier Series Representation of Periodic Impulse Train
clear;
clc;
close;
T =4;
T1 = T/4;
t = [-T,0,T];
xt = [1,1,1]; //Generation of Periodic train of Impulses
t1 = -T1:T1/100:T1;
gt = ones(1,length(t1));//Generation of periodic square wave
t2 = [-T1,0,T1];
qt = [1,0,-1];//Derivative of periodic square wave
Wo = 2*%pi/T;
ak = 1/T;
b(1) = 0;
c(1) = 2*T1/T;
for k =1:5
b(k+1) = ak*(exp(sqrt(-1)*k*Wo*T1)-exp(-sqrt(-1)*k*Wo*T1));
if(abs(b(k+1)) < =0.1)
b(k+1) =0;
end
c(k+1) = b(k+1)/(sqrt(-1)*k*Wo);
if(abs(c(k+1)) < =0.1)
c(k+1) =0;
end
end
k = 0:5
disp('Fourier Series Coefficients of periodic Square Wave')
disp(b)
disp('Fourier Series Coefficients of derivative of periodic square wave')
disp(c)
//Plotting the periodic train of impulses
figure
subplot(3,1,1)
a = gca();
a.y_location = "origin";
a.x_location = "origin";
a.data_bounds=[-6,0;6,2];
plot2d3('gnn',t,xt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
title('x(t)')
//Plotting the periodic square waveform
subplot(3,1,2)
a = gca();
a.y_location = "origin";
a.x_location = "origin";
a.data_bounds=[-6,0;6,2];
plot2d(t1,gt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
plot2d(T+t1,gt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
plot2d(-T+t1,gt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
title('g(t)')
//Plotting the periodic square waveform
subplot(3,1,3)
a = gca();
a.y_location = "origin";
a.x_location = "origin";
a.data_bounds=[-6,-2;6,2];
poly1.thickness = 3;
plot2d3('gnn',t2,qt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
plot2d3('gnn',T+t2,qt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
plot2d3('gnn',-T+t2,qt,5)
poly1 = a.children(1).children(1);
poly1.thickness = 3;
title('q(t)') |
b629c60b687703cab8fe9ed411265bd1f3b82a31 | 449d555969bfd7befe906877abab098c6e63a0e8 | /3516/CH10/EX10.2/Ex10_2.sce | 21a235c4b6880b31de16fa361eb753c3303dbaeb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 3,650 | sce | Ex10_2.sce | printf("\t example 10.2 \n");
printf("\t approximate values are mentioned in the book \n");
T1=250; // inlet hot fluid,F
T2=250; // outlet hot fluid,F
t1=95; // inlet cold fluid,F
t2=145; // outlet cold fluid,F
W=16000; // lb/hr
w=423; // lb/hr
printf("\t 1.for heat balance \n");
printf("\t for kerosene \n");
c=0.5; // Btu/(lb)*(F)
Q=((W)*(c)*(t2-t1)); // Btu/hr
printf("\t total heat required for kerosene is : %.0f Btu/hr \n",Q);
printf("\t for steam \n");
l=945.5; // Btu/(lb)
Q=((w)*(l)); // Btu/hr
printf("\t total heat required for steam is : %.2e Btu/hr \n",Q);
delt1=T2-t1; //F
delt2=T1-t2; // F
printf("\t delt1 is : %.0f F \n",delt1);
printf("\t delt2 is : %.0f F \n",delt2);
LMTD=((delt2-delt1)/((2.3)*(log10(delt2/delt1))));
printf("\t LMTD is :%.0f F \n",LMTD);
tc=((t1)+(t2))/2; // caloric temperature of cold fluid,F
printf("\t caloric temperature of cold fluid is : %.0f F \n",tc);
printf("\t hot fluid:shell side,steam \n");
ho=(1500); // condensation of steam Btu/(hr)*(ft^2)*(F)
printf("\t individual heat transfer coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",ho);
printf("\t cold fluid:inner tube side,kerosene \n");
Nt=86;
n=2; // number of passes
L=12; //ft
at1=0.594; // flow area, in^2,from table 10
at=((Nt*at1)/(144*n)); // total area,ft^2,from eq.7.48
printf("\t flow area is : %.3f ft^2 \n",at);
Gt=(W/(.177)); // mass velocity,lb/(hr)*(ft^2)
printf("\t mass velocity is : %.2e lb/(hr)*(ft^2) \n",Gt);
mu2=1.36*2.42; // at 145F,lb/(ft)*(hr)
D=(0.87/12); // ft
Ret1=((D)*(Gt)/mu2); // reynolds number
printf("\t reynolds number is : %.0f \n",Ret1);
mu3=1.75*2.42; // at 120F,lb/(ft)*(hr)
D=(0.87/12); // ft
Ret2=((D)*(Gt)/mu3); // reynolds number
printf("\t reynolds number is : %.1e \n",Ret2);
Z1=331; // Z1=(L*n/D)
jH=3.1; // from fig 24
mu4=1.75; // cp and 40 API
Z2=0.24; // Z2=((k)*(c*mu4/k)^(1/3)), from fig 16
Hi=((jH)*(1/D)*(Z2)); // using eq.6.15a,Btu/(hr)*(ft^2)*(F)
printf("\t Hi is : %.2f Btu/(hr)*(ft^2)*(F) \n",Hi);
ID=0.87; // ft
OD=1; //ft
Hio=(Hi*(ID/OD)); //Btu/(hr)*(ft^2)*(F), from eq.6.5
printf("\t Hio is : %.2f Btu/(hr)*(ft^2)*(F) \n",Hio);
tw=(tc)+(((ho)/(Hio+ho))*(T1-tc)); // from eq.5.31
printf("\t tw is : %.0f F \n",tw);
muw=1.45; // lb/(ft)*(hr),at 249F from fig.14
phyt=(mu3/muw)^0.14;
printf("\t phyt is : %.1f \n",phyt); // from fig.24
hio=(Hio)*(phyt); // from eq.6.37
printf("\t Correct hio to the surface at the OD is : %.1f Btu/(hr)*(ft^2)*(F) \n",hio);
delt=tw-tc; //F
printf("\t delt is : %.0f F \n",delt);
printf("\t Since the kerosene has a viscosity of only 1.75 cp at the caloric temperature and delt=129F, free convection should be investigated. \n");
s=0.8;
row=50; // lb/ft^3, from fig 6
s1=0.810; // at 95F
s2=0.792; // at 145F
bita=((s1^2-s2^2)/(2*(t2-t1)*s1*s2)); // /F
printf("\t beta is : %.6f /F \n",bita);
G=((D^3)*(row^2)*(bita)*(delt)*(4.18*10^8)/(mu3^2));
printf("\t G is : %.1e \n",G);
psy=((2.25)*(1+(0.01*G^(1/3)))/(log10(Ret2)));
printf("\t psy is : %.2f \n",psy);
hio1=(hio*psy);
printf("\t corrected hio1 is : %.1f Btu/(hr)*(ft^2)*(F) \n",hio1);
Uc=((hio1)*(ho)/(hio1+ho)); // clean overall coefficient,Btu/(hr)*(ft^2)*(F)
printf("\t clean overall coefficient is : %.1f Btu/(hr)*(ft^2)*(F) \n",Uc);
A2=0.2618; // actual surface supplied for each tube,ft^2,from table 10
A=(Nt*L*A2); // ft^2
printf("\t total surface area is : %.0f ft^2 \n",A);
UD=((Q)/((A)*(delt)));
printf("\t actual design overall coefficient is : %.1f Btu/(hr)*(ft^2)*(F) \n",UD);
Rd=((Uc-UD)/((UD)*(Uc))); // (hr)*(ft^2)*(F)/Btu
printf("\t actual Rd is : %.2f (hr)*(ft^2)*(F)/Btu \n",Rd);
// end
|
cc172b69f9ea5d50265dcecd538e27f9aaa9d7b0 | 717ddeb7e700373742c617a95e25a2376565112c | /1766/CH2/EX2.18/EX2_18.sce | 57c168723bcaffa790a3b7a48327706b04d952eb | [] | no_license | appucrossroads/Scilab-TBC-Uploads | b7ce9a8665d6253926fa8cc0989cda3c0db8e63d | 1d1c6f68fe7afb15ea12fd38492ec171491f8ce7 | refs/heads/master | 2021-01-22T04:15:15.512674 | 2017-09-19T11:51:56 | 2017-09-19T11:51:56 | 92,444,732 | 0 | 0 | null | 2017-05-25T21:09:20 | 2017-05-25T21:09:19 | null | UTF-8 | Scilab | false | false | 1,212 | sce | EX2_18.sce | clc;funcprot(0);//Example 2.18
//Initilisation of Variables
d1=0.5;....//diameter of container in m
T1=80;....//inner temparature of spherical container in degrees celcius
t=0.025;....//thickness of insulating materials in m
Ta=303;....//outer surface temparature of spherical container in degrees celcius
K1=0.042;....//thermal conductivity of first insulating layer in W/m*K
K=0.0017;....//thermal conductivity of second insulating layer in W/m*K
h=20;....//heat transfer coefficient in W/m^2
hfg=2*10^2;....//latent heat of vapouraisation o f liquid nitrogen in kJ/Kg*degrees celcius
//calculations
r1=d1/2;....//radius of container in m
r2=r1+t;....//radius of inner layer in m
r3=r2+t;....//radius of outer layer in m
R1=(r2-r1)/(4*%pi*K1*r1*r2);.....//resistance of first layer in degrees celcius/W
R2=(r3-r2)/(4*%pi*K*r2*r3);.....//resistance of second layer in degrees celcius/W
R3=1/(4*%pi*h*r3^2);.....//resistance of inner layer in degrees celcius/W
Q=(T1-Ta)/(R1+R2+R3);....//heat flows from the airbient air to nitrogen in W
m=Q/(hfg*10^3);....//rate of vapouraisation of liquid nitrogen per hour Kg/s
disp(m*3600,"rate of vapouraisation of liquid nitrogen per hour Kg/hr:")
|
ed1ca98aea3c9e37b72e9c3bf40c3219e8c58d96 | a62e0da056102916ac0fe63d8475e3c4114f86b1 | /set7/s_Electronic_Instrumentation_H._S._Kalsi_3554.zip/Electronic_Instrumentation_H._S._Kalsi_3554/CH20/EX20.3/Ex20_3.sce | 1365c4a8821f9337b2a2dda03ec819594172aa4b | [] | no_license | hohiroki/Scilab_TBC | cb11e171e47a6cf15dad6594726c14443b23d512 | 98e421ab71b2e8be0c70d67cca3ecb53eeef1df6 | refs/heads/master | 2021-01-18T02:07:29.200029 | 2016-04-29T07:01:39 | 2016-04-29T07:01:39 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 263 | sce | Ex20_3.sce | errcatch(-1,"stop");mode(2);// Exa 20.3
;
all;
// Given data
Vmax=8;//Maximum value of voltage
Vmin=2;//minimum value of voltage
//Solution
SWR=(Vmax+Vmin)/(Vmax-Vmin);//Standing wave ratio
printf('Standing Wave Ratio = %.2f \n ',SWR);
exit();
|
df4a07c7e00c247e678390c4fb74cd166ba77c78 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1802/CH3/EX3.11/Exa3_11.sce | cc894ed66a45cedec2d251cabd3dfa7697a42782 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 175 | sce | Exa3_11.sce | //Exa 3.11
clc;
clear;
close;
//Given Data :
format('v',5);
L=200;//in meter
W=684/1000;//in Kg/m
T=1450;//in Kg
S=W*L^2/(8*T);//in meter
disp(S,"Sag(in meter) : "); |
5cb0b5ec7d7a9aa58a51cb1b67a1f0b075668ddd | 449d555969bfd7befe906877abab098c6e63a0e8 | /2223/CH9/EX9.1/Ex9_1.sce | 09b250600dca0bde4d55a561b3bf9667e2f63f5c | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 3,186 | sce | Ex9_1.sce | // scilab Code Exa 9.1 Calculation on multi stage turbine
d=1; // mean diameter of the impeller blade in m
T1=500; // Initial Temperature in degree C
t1=T1+273; // in Kelvin
p1=100; // Initial Pressure in bar
N=3e3; // Speed in RPM
m=100; // in kg/s
alpha2=70; // exit angle of the first stage nozzle blades
// part(a) single stage impulse
nsti=0.78;
u=%pi*d*N/60;
sigma=0.5*(sind(alpha2)); // maximum utilization factor
c2=u/sigma;
cx=c2*(cosd(alpha2));
beta2=atand(0.5*(tand(alpha2))); // beta2=beta3
wst=2*(u^2)*1e-3;
P=m*wst;
disp("(a)for single stage impulse")
disp("degree",beta2,"blade angles are beta2=beta3= ")
disp("MW",P*1e-3,"Power developed is")
sv=0.04; // specific volume of steam after expansion in m3/kg
h=(m*sv)/(cx*%pi*d); // h2=h3=h
disp("cm",h*1e2,"blade height is")
delhs=wst/nsti;
disp("final state of the steam is")
p=81.5; // from enthalpy-entropy diagram
T=470;
disp("bar",p,"p=")
disp("degree C",T,"T=")
// part(b) Two-stage Curtis wheel
nstc=0.65;
u=%pi*d*N/60;
sigma2=0.25*(sind(alpha2));
c2_2=u/sigma2;
cx2=c2_2*(cosd(alpha2));
beta2_2=atand((3*u)/cx2); // beta2=beta3
alpha3=atand((2*u)/(c2_2*cosd(alpha2))); // alpha2'=alpha3
beta2_s=atand((u)/cx2); // beta2'=beta3'
wI=6*(u^2)*1e-3;
wII=2*(u^2)*1e-3;
wst2=wI+wII;
P2=m*wst2;
disp("(b)for Two-stage Curtis wheel")
disp("degree",alpha3,"air angles are alpha2s=alpha3= ")
disp("degree",beta2_2,"for first stage blade angles are beta2=beta3= ")
disp("degree",beta2_s,"for second stage blade angles are beta2s=beta3s= ")
disp("MW",P2*1e-3,"Power developed is")
delhs2=wst2/nstc;
// from enthalpy-entropy diagram for the expansion
disp("final state of the steam is")
p2=27;
T2=365;
v2=0.105; // specific volume of steam after expansion in m3/kg
disp("bar",p2,"p=")
disp("degree C",T2,"T=")
disp("m3/kg",v2,"v=")
h2=(m*v2)/(cx2*%pi*d);
disp("cm",h2*1e2,"blade height is")
// part(c) Two-stage Reateau wheel
nst1=0.78;
wI3=2*(u^2)*1e-3;
wII3=2*(u^2)*1e-3;
wst3=wI3+wII3;
P3=m*wst3;
disp("(c)for Two-stage Reateau wheel")
disp("degree",beta2,"blade angles are beta2=beta3= ")
disp("MW",P3*1e-3,"Power developed is")
delhs3=wst3/nst1;
disp("final state of the steam is")
p3=65; // from enthalpy-entropy diagram
T3=445;
v3=0.05; // specific volume of steam after expansion in m3/kg
disp("bar",p3,"p=")
disp("degree C",T3,"T=")
disp("m3/kg",v3,"v=")
h3=(m*v3)/(cx*%pi*d);
disp("cm",h3*1e2,"blade height for the second stage is")
// part(d) single stage 50% reaction
nstr=0.85;
sigma4=sind(alpha2); // maximum utilization factor
c2_4=u/sigma4; // c2_4=w_3
cx4=c2_4*(cosd(alpha2)); // alpha2=beta3;
beta2_4=0; // beta2=alpha3
wst4=(u^2)*1e-3;
P4=m*wst4;
disp("(d)for single stage 50% reaction")
disp("degree",beta2_4,"blade angles are beta2=alpha3= ")
disp("degree",alpha2,"and beta3=alpha2= ")
disp("MW",P4*1e-3,"Power developed is")
delhs4=wst4/nstr;
// from enthalpy-entropy diagram
disp("final state of the steam is")
p4=90;
T4=485;
v4=0.035;
disp("bar",p4,"p=")
disp("degree C",T4,"T=")
disp("m3/kg",v4,"v=")
h4=(m*v4)/(cx4*%pi*d);
disp("cm",h4*1e2,"the rotor blade height at exit is")
|
2cd74784109b9bb3bebc8293cd8c366dd4c74ee3 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1092/CH1/EX1.13/Example1_13.sce | e5775f7434671ddfa7257af78b25c69ca0c999b0 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 538 | sce | Example1_13.sce | // Electric Machinery and Transformers
// Irving L kosow
// Prentice Hall of India
// 2nd editiom
// Chapter 1: Electromechanical Fundamentals
// Example 1-13
clear; clc; close; // Clear the work space and console.
// Given data
R_a = 0.25; // Armature resistance
V_a = 125; // dc bus voltage
I_a = 60; // Armature current
// Calculations
E_c = V_a - I_a * R_a; // Counter EMF generated in the armature conductors of motor
// Display the result
disp("Example 1-13 Solution : ");
printf("\n Ec = % d V ", E_c );
|
99234523bb923a5dfb24c119eaabb46a1a3ffe41 | 449d555969bfd7befe906877abab098c6e63a0e8 | /446/CH3/EX3.6/3_6.sce | bdfaba60f6c67df1a8ca944fcea933e1cd2e1ffe | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 628 | sce | 3_6.sce | clear
clc
disp('Exa-3.6(a)');
w1=0.24;wc=0.00243;theta=60; //given values w=wavelength(lambeda)
w2=w1+(wc*(1-cosd(theta)));
printf('The wavelength of x-rays after scattering is %.4f nm\n',w2);
disp('Exa-3.6(b)');
hc=1240;
E2=hc/w2;E1=hc/w1; printf('The energy of scattered x-rays is %.0f eV\n',E2);
disp('Exa-3.6(c)');
K= E1-E2; //The kinetic energy is the difference in the energy before and after the collision;
printf('The kinetic energy of the x-rays is %.3f eV\n',K);
disp('Exa-3.6(d)');
phi2=atand(E2*sind(theta)/(E1-E2*cosd(theta)))
printf('The direction of the scattered eletron is %.1f degrees',phi2); |
5335b35568dd7fc03a2852a515f758737ce67c57 | 449d555969bfd7befe906877abab098c6e63a0e8 | /331/CH3/EX3.18/Example_3_18.sce | 2dd19aeda60c8c60ae8b1853882991fb62520c72 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,620 | sce | Example_3_18.sce | //Caption: Measure of Skewness
//Karl Pearson's coefficient of skewness
//Example3.18
//Page61
clear;
clc;
X = [0,4;4,8;8,12;12,16;16,20;20,24;24,28;28,32]; //Absenteeism in days
f = [10,76,100,150,24,36,14,2]; //No. of employees
[m,n] = size(X);
for i = 1:m
Xi(i) = sum(X(i,:))/2; //Mid point
end
if (modulo(m,2)==1) then //to check even or odd
mid = m/2;
else
mid = (m+1)/2;
end
A = Xi(mid); //assumed mean
N = sum(f); //total frequency
C = diff(X(1,:)); //class interval
for i = 1:m
d(i) = (Xi(i)-A)/C;
fd(i)= f(i)*d(i);
fd2(i) = f(i)*(d(i)^2);
end
Xmean = A+(sum(fd)*C/N); //Mean value
[m1,n1] = max(f); //maximum frequency
L = X(n1,1); //Lower limit of the modal class
f1 = abs(f(n1)-f(n1-1)); //Abs difference between freq. of modal class & its
//immediately preceding class
f2 = abs(f(n1)-f(n1+1)); //Abs difference between freq. of modal class & its
//immediately succeeding class
Mode = L+((f1/(f1+f2))*C);//Mode
Std = sqrt((sum(fd2)/N)-(sum(fd)/N)^2)*C;//standard deviation
CS = (Xmean-Mode)/Std; //coefficient of skewness
disp(Xmean,'Mean Value =')
disp(Mode,'Mode value =')
disp(CS,'coefficient of skewness = ')
//Result
if (CS<0) then
disp('Since the coefficient of skewness is negative, the distribution is')
disp('skewed to the left & extent of distortion is very small')
end
//Result
//Mean Value =
//
// 12.679612
//
// Mode value =
//
// 13.136364
//
// coefficient of skewness =
//
// - 0.0832508
//
// Since the coefficient of skewness is negative, the distribution is
//
// skewed to the left & extent of distortion is very small |
638d431582e984a51406b4711cefa91a8075cabb | 449d555969bfd7befe906877abab098c6e63a0e8 | /3440/CH12/EX12.1/Ex12_1.sce | 7e86a76660e6f036ac3a93009b005fec7623ebee | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 259 | sce | Ex12_1.sce | clc
Msi=28.9//g/mole
Dsi=2.33//g/cm^3
Msidi=60.08//g/mole
Dsidi=2.21//g/cm^3
vsi=Msi/Dsi
disp(vsi,"vsi in cm^3/mole is= ")
vsidi=Msidi/Dsidi
disp(vsidi,"vsidi in cm^3/mole is= ")
T=vsi/vsidi
disp(T,"T is ratio of Thickness of Si to SiO2 is= ")
|
f1fa14a0c737d1e380947dc46f0426f2dc2930b1 | 04e4dfecf86c47abbad9ad721bcbc552300a8834 | /Self_tuning_controller/SelfTuning_Vikas/PIControllerFandisturbance/start.sce | 20d4261e9b0cd5d8985124bb3401c53c618c13d4 | [] | no_license | rupakrokade/scilab_local_codes | 702f741a5cadc6da56e428f7379971818238ff22 | 4de8383487def7f18a1f19906397ed4eaf42480e | refs/heads/master | 2021-01-19T06:58:47.689324 | 2015-10-24T11:55:34 | 2015-10-24T11:55:34 | 26,806,574 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 136 | sce | start.sce | getd ../../../common_files/
exec ../../../common_files/loader.sce
exec ser_init.sce
exec pi_bda_tuned_dist.sci
xcos pi_tuned_dist.xcos |
c60e4f2ecb06bf034bb800580bd31c54fb704154 | 564beb66e232557765505973f93cc322a394133a | /KOHW/IntrinsicCarriers.sce | 261cfc4ba11d55bba83dbb223ae8678b024ee91b | [] | no_license | KeithEvanSchubert/Keith_On | 2442bb74b9d531c96d9f10da8df1dede54423094 | fe8dd1e90e695957346aa176b7e0d0fea30171e3 | refs/heads/master | 2021-01-18T22:08:18.862471 | 2019-09-04T17:39:58 | 2019-09-04T17:39:58 | 51,767,267 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 258 | sce | IntrinsicCarriers.sce | //Setup
GaAs=1;
Ge=2;
Si=3;
Eg = [1.42
0.66
1.12];//eV
B = [2.1E14
1.66E15
5.23E15];//cm^{-3}K^{-3/2}
k=86E-6;//eV/K
//user selections
T=300;//Kelvin
material = Ge;
ni = B(material) * T^1.5 * exp(-Eg(material) / (2*k*T)) // in cm^{-3} |
5db8061e135a20ae6eeda0aea62117bb6e208930 | 449d555969bfd7befe906877abab098c6e63a0e8 | /2732/CH5/EX5.1/Ex5_1.sce | 3ae30b5a57e66cfbacd40b9069bcdcc3699934cb | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 170 | sce | Ex5_1.sce | clc
//initialization of variables
clear
l=20 //cm
dL=1 //m
dl=0.004 //cm
//calculations
L=l*dL/dl //m
//results
printf('The depth of the clay bed is %d m',L)
|
59bf2d7de2da9a270e1ff0f3a29a065e039771cc | e2ae697563b1b764d79ea1933b555ab0d5e3849c | /macros/arbit_response.sci | 28e90506e06d56311d0a295a09c73958de1a291b | [] | no_license | gq-liu/IPDesignLab | c49b760740f47ec636232a6947aecb3c0626518a | b2f9a9eecad6616c99a2ec20fcceb14fb3ed0c3f | refs/heads/master | 2022-01-18T13:30:55.972779 | 2019-05-06T17:23:12 | 2019-05-06T17:23:12 | null | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 1,961 | sci | arbit_response.sci | function arbit_response(g_closedloop,t,u)
// This program is free software; you can redistribute it and/or modify
// it under the terms of the GNU General Public License as published by
// the Free Software Foundation; either version 2 of the License, or
// (at your option) any later version.
//
// This program is distributed in the hope that it will be useful,
// but WITHOUT ANY WARRANTY; without even the implied warranty of
// MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
// GNU General Public License for more details.
//
// You should have received a copy of the GNU General Public License
// along with this program; if not, write to the Free Software
// Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
// Authors
// Holger Nahrstaedt - 2010
// Ishan Pendharkar - 2001-2007
//
//RLTOOL for scilab (c) Ishan Pendharkar.
//function simulate for piecewise linear inputs.
global gridon tstep
//check if input is NOT single-valued
[x,y]=size(t);
for i=1:x-1
if t(i+1)-t(i)<= 0 then
messagebox(['Error entering input.';'Input is not single valued']);
return;
end;
end;
// interpolate to get values of input
interp_u(1)=0;
interp_t(1)=0;
interp_size=ceil(max(t)/tstep);
for i=1:interp_size
interp_u(i)=interpln([t';u'],(i-1)*tstep)
interp_t(i)=(i-1)*tstep;
end;
// plotting interpolated values
t=interp_t;
u=interp_u;
if roots(denom(g_closedloop))<>[] then
resp=csim(u',t',g_closedloop); //this is the response vector
plot2d(t,[resp' u],[1,2],leg="Response@Input");
if gridon==1 then xgrid(4); end;
xtitle('Dynamic Response','Time (sec)','Magnitude')
else
messagebox(['Sorry! I cannot plot the response';'Due to numerical tolerances, a pole-zero cancellation has occured.';' Please reselect point.']);
end;
//xselect();
show_window();
clear interp_t,interp_u,t,resp
//return
endfunction |
b018b558df677643bb08daefcb48af7a0d3514d9 | 449d555969bfd7befe906877abab098c6e63a0e8 | /181/CH4/EX4.3/example4_3.sce | b175255914621d6aac317d71e67a3106abd9aff0 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 698 | sce | example4_3.sce | // Collector Current in C-E mode
// Basic Electronics
// By Debashis De
// First Edition, 2010
// Dorling Kindersley Pvt. Ltd. India
// Example 4-3 in page 209
clear; clc; close;
// Given Data
alpha=0.90; // Current Gain of BJT
Ico=15*10^-6; // Reverse Saturation Current of BJT in micro-A
Ib=0.5*10^-3; // Base Current in C-E mode in mA
// Calculations
beta_bjt=alpha/(1-alpha);
Ic=(beta_bjt*Ib)+(beta_bjt+1)*Ico;
printf("(a)The value of Current gain beta for BJT is %0.0f \n",beta_bjt);
printf("(b)The value of the Collector Current is %0.2e A \n",Ic);
// Results
// (a) The value of Current Gain beta for BJT is 9
// (b) The value of the Collector Current is 4.65 mA |
435508b2c2b3fb4d6be7e0903051dd6b11ae987a | 449d555969bfd7befe906877abab098c6e63a0e8 | /599/CH7/EX7.5/example7_5.sce | 08766559781c73ccf41d090308ba67d951971610 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 772 | sce | example7_5.sce |
clear;
clc;
printf("\t Example 7.5\n");
p1=.3; //percentage of the solute in the solution
w1=1000; //weight of the solution taken
w2=142; //molecular weight of Na2SO4.
M1=(w2/(180+w2)); //solute (Na2SO4) present in the Na2CO3.10H2O solution
s1=40.8; //solubility of Na2SO4 at 30 degree per 100 gm of water
s2=9.0; //solubility of Na2SO4 at 10 degree per 100 gm of water
//percent weight of solute in Na2SO4.10H2O= 144/322
//let x be the weight of crystal formed
x=poly([0],'x'); //calc. x the weight of crystal
t=roots((w1*40.8/140.8)-(.442*x+(w1-x)*(s2/(100+s2))));
printf("\n the weight of crystal formed after crystallisation :%f kg",t);
//end |
a2b6c61e67617ccb94c9365c22fd4a228445c981 | 8217f7986187902617ad1bf89cb789618a90dd0a | /source/2.5/macros/m2sci/sci_diff.sci | 5da4148312375f5c8cdb72cc6e84bdc8f776bc40 | [
"LicenseRef-scancode-public-domain",
"LicenseRef-scancode-warranty-disclaimer"
] | permissive | clg55/Scilab-Workbench | 4ebc01d2daea5026ad07fbfc53e16d4b29179502 | 9f8fd29c7f2a98100fa9aed8b58f6768d24a1875 | refs/heads/master | 2023-05-31T04:06:22.931111 | 2022-09-13T14:41:51 | 2022-09-13T14:41:51 | 258,270,193 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 1,517 | sci | sci_diff.sci | function [stk,txt,top]=sci_diff()
// Copyright INRIA
txt=[]
if stk(top-rhs+1)(5)=='4' then
v='bool2s('+stk(top-rhs+1)(1)+')',
else
v=stk(top-rhs+1)(1),
end
if rhs==1 then
[m,n]=checkdims(stk(top))
x=stk(top)(1)
if m==-1&n==-1 then
set_infos(['mtlb_diff('+x+') may be replaced by '
' '+x+'(2:$)-'+x+'(1:$-1) if '+x+'is a vector'
' '+x+'(2:$,:)-'+x+'(1:$-1,:) if '+x+'is a matrix'],1)
stk=list('mtlb_diff('+x+')','0','?','?','1')
elseif m==1|n==1 then
if ~isname(x) then
x=gettempvar()
txt=[txt;x+'='+stk(top)(1)]
end
stk=list(x+'(2:$)-'+x+'(1:$-1)','1','1','1','1')
else
if ~isname(x) then
x=gettempvar()
txt=[txt;x+'='+stk(top)(1)]
end
stk=list(x+'(2:$,:)-'+x+'(1:$-1,:)','1','1','1','1')
end
else //diff(x,N)
N=stk(top)(1)
top=top-1
[m,n]=checkdims(stk(top))
x=stk(top)(1)
if m==-1&n==-1 then
set_infos([
'mtlb_diff('+x+','+N+') may be replaced by '
' '+x+'('+addf('1',N)+':$)-'+x+'(1:$-'+N+') if '+x+' is a vector'
' '+x+'('+addf('1',N)+':$,:)-'+x+'(1:$-'+N+',:) if '+x+' is a matrix'],1)
stk=list('mtlb_diff('+x+','+N+')','0','?','?','1')
elseif m==1|n==1 then
if ~isname(x) then
x=gettempvar()
txt=[txt;x+'='+stk(top)(1)]
end
stk=list(x+'('+addf('1',N)+':$)-'+x+'(1:$-'+N+')','1','1','1','1')
else
if ~isname(x) then
x=gettempvar()
txt=[txt;x+'='+stk(top)(1)]
end
stk=list(x+'('+addf('1',N)+':$,:)-'+x+'(1:$-'+N+',:)','1','1','1','1')
end
end
|
39c17e28b02caf87c06fb339b32dd96546771b2b | 449d555969bfd7befe906877abab098c6e63a0e8 | /2863/CH4/EX4.14/ex4_14.sce | 3f3f0ba3d178082ed33f6e2d26cf3df1315bdeea | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 123 | sce | ex4_14.sce | //chapter 4
//may june 2013
n=50;
d=0.5;
lamda=1;//assume
L=n*d;
D=2*(L/lamda);
printf("the directivity is %g",D);
|
565a1cd964677db43bca59e264e285db7e7d0336 | 9d11e49bc2143a6b680ab8f59b245bb2b4e5f487 | /practicas-programacion/scilab/u4-scinotes/pid-manual-kp.sce | d1d7e4993305c7d246afeb721e3ca86649b6b52b | [] | no_license | AguilarLagunasArturo/school-holder | 61a8be432b0979f7e3332c0ef058421ff34200ee | 373cb31bb8e29e2433fb6269ad45bbdac0f8262e | refs/heads/main | 2023-08-13T18:21:45.177344 | 2021-10-07T05:17:32 | 2021-10-07T05:17:32 | 407,611,773 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 268 | sce | pid-manual-kp.sce | clc;
s = %s;
num = 2;
den = s*(s+1)*(s+2);
g = syslin('c', num/den);
evans(g, 10)
sgrid()
// kp < 3 | tanteando kp = 1.2
ku = 2.998;
wu = 1.414;
tu = (2*%pi)/wu;
kp = 0.6*ku
ki = 1.2*(ku/tu)
kd = (0.6/8)*(ku*tu)
// Manual
// kp = 1.7988
// ki = 0.045
// kd = 1.2
|
71ebd48612229d6ae336f3a090eb435a0760e063 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1430/CH11/EX11.10/exa11_10.sce | 7f97adc3b0da544916c9349961a6a97c82694fab | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 176 | sce | exa11_10.sce | // Example 11.10
//Bode Plot of a Narrowband Filter
s=%s;
num=20*s;
den=(s^2+20*s+10^4)
H_s=num/den; // Transfer function of given filter
h1=syslin('c',H_s);
bode(h1);
|
522ef4c4c49d2ff6f903150ae0a51219bbe7910e | a550430672dfb5984bd8561b894897323028b7f5 | /tests/results/foot11.tst | d673b20e9bb14252d76d460f068857169570bf3b | [] | no_license | carlosmata/LabelPropagation | c91f68489a941e6f8cfb15de478d2fe28eadbcad | 2f169cc4ece49a0d0f868fee15e5eefe02bbc6df | refs/heads/master | 2020-12-18T17:46:23.501020 | 2020-05-09T06:13:16 | 2020-05-09T06:13:16 | 235,474,033 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 169 | tst | foot11.tst | argc:7
Dataset: ../datasets/converted/football.net
Nodes Edges Com Mod NMI Time
seq async 115 1226 9 0.602529 -1 0.000248959
par async 115 1226 13 0.50171 -1 0.071628
|
b230ba625d3e7334ecdd03f44a958ab7a2f930bd | 449d555969bfd7befe906877abab098c6e63a0e8 | /48/CH1/EX1.5/eg_1_5.sce | 8a51aa6eadf23fc713f811568abcb217a484156d | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,193 | sce | eg_1_5.sce | clc;//clears the command window
clear;//clears all the variables
format('v',18);//changing the default prcision to 20 significant digits
i=1;x=1;//flag bits
dec=432.354;//given decimal number which should be expressed in base 2
temp2=floor(dec);//separating integer part from the given number
temp4=modulo(dec,1);//separating decimal part from the given number
while(temp2>0)//storing each integer digit in vector for convenience
p(i)=(modulo(floor(temp2),2))
temp2=floor(temp2)/2;
i=i+1;
end
temp2=0;//clearing temporary variable 'temp2'
for j=1:length(p)
//multipliying bits of integer part with their position values and adding
temp2=temp2+(p(j)*10^(j-1));
end
while(temp4~=0) //storing each decimal digit in vector for convenience
temp4=temp4*2;
d(x)=floor(temp4);
x=x+1;
temp4=modulo(temp4,1);
end
temp5=0; //clearing temporary variable 'temp5'
for j=1:length(d)
//multipliying bits of decimal part with their position values and adding
temp5=temp5+(10^(-1*j)*d(j))
end
temp3=temp2+temp5;
//finally adding both the integer and decimal parts to get total output.
disp(temp3);//displays output |
e0fd91fec0b9daffe19e36879edb3d4b509b9d71 | 449d555969bfd7befe906877abab098c6e63a0e8 | /1319/CH4/EX4.8/4_8.sce | c5508363f0b4dc18e6af6a831f85bee504bbac99 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 385 | sce | 4_8.sce | //Percentage error calculation in a wattmeter
clc;
clear;
//Rated Parameters
I=50;
V=230;
R=61;// No. of revolutions
t=37/3600; // Time in hours
C=520; // Normal Disc Speed
Pfl=I*V;// Power at full load
Ps=Pfl*t/1000; // Power Supplied in kWhr
Pr=R/C; //Power recorded in kWhr
err=(Ps-Pr)*100/Ps;
printf('The Percentage Error = %g percent slow \n',err)
|
d02df0f99193d7e08852a2842ef4fa23ec746b70 | 3ca7d40067d619bd7859f89de1882e22ef3a9fda | /testcases/public/test027.txt | 88e4521e0fd99c76f04c422a8c6debfce62409bd | [] | no_license | caojoshua/CS241-Advanced-Compiler-Construction-Project | 2b76c042ea6505c4a565ae5299efb5d983e0b4f3 | 1b25c9dd283b77555ccc3951924ac2882c1d92c2 | refs/heads/master | 2020-12-15T02:54:38.405198 | 2020-03-25T20:52:37 | 2020-03-25T20:52:56 | 234,971,962 | 1 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 442 | txt | test027.txt | main
array [3] foo,boo;
var a,b,c;
{
let c <- foo[2*a-6];
while 2 < 3 do
let b <- foo[2*a-6];
while 4 < foo[2*a-6] do
if 3 < 4 then
let boo[c] <- 3
else
let foo[2] <- 5
fi
od;
let c <- foo[2*a-6]
od;
let a <- foo[2*a-6]
}
. |
3df7c950cdade2a3b6bbfb5d9ba1176459f4f4f0 | cfadc8057fba63a7793bcee7ce8e2e8c3e5dc359 | /solvers/APESolver/Tests/APE_2DVariableC_WeakDG_MODIFIED.tst | 9df46592bd98ac0521e9f44ea302222e7ac279fe | [
"MIT"
] | permissive | DarkOfTheMoon/nektar | a5132b836f9fb0894ec54c1f373c08df947dd5ca | b36f4214c0907f877fed8dfc08e53bd607eaea24 | refs/heads/master | 2021-01-20T03:59:10.430634 | 2017-04-27T11:50:26 | 2017-04-27T11:50:26 | 89,609,337 | 0 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 823 | tst | APE_2DVariableC_WeakDG_MODIFIED.tst | <?xml version="1.0" encoding="utf-8"?>
<test>
<description>desc P=10</description>
<executable>APESolver</executable>
<parameters>APE_2DVariableC_WeakDG_MODIFIED.xml</parameters>
<files>
<file description="Session File">APE_2DVariableC_WeakDG_MODIFIED.xml</file>
</files>
<metrics>
<metric type="L2" id="1">
<value variable="p" tolerance="1e-4">145.343</value>
<value variable="u" tolerance="1e-7">0.329227</value>
<value variable="v" tolerance="1e-7">0</value>
</metric>
<metric type="Linf" id="2">
<value variable="p" tolerance="1e-4">119.917</value>
<value variable="u" tolerance="1e-7">0.260865</value>
<value variable="v" tolerance="1e-7">0</value>
</metric>
</metrics>
</test>
|
e7f01a1f586e55686f293994b0d9889073419b91 | 449d555969bfd7befe906877abab098c6e63a0e8 | /866/CH5/EX5.5/5_5.sce | ec6568352eee6026a4536c42ca15b17a5039d145 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 590 | sce | 5_5.sce | clc
//initialisation of variables
w= 120 //KN
D= 30 //m
L= 300 //m
sigmamax= 600 //N/mm^2
h= 50 //m
beta= 45 //degrees
//CALCULATIONS
Tmax= ((w*L)/2)*(sqrt(1+(L/(4*D))^2))
d= sqrt((4*Tmax*10^3)/(sigmamax*%pi))
H= (w*L^2)/(8*D)
alpha= atand((w*L)/(2*H))
Mt= Tmax*(cosd(alpha)-cosd(beta))*h
Vt= Tmax*(sind(alpha)+sind(beta))
Wa= Tmax*cosd(beta)
//RESULTS
printf ('Tmax= %.1f KN',Tmax)
printf (' \n d=%.1f mm',d)
printf (' \n H=%.0f KN',H)
printf (' \n alpha=%.1f degrees',alpha)
printf (' \n Mt=%.0f KNm',Mt)
printf (' \n Vt=%.0f KN',Vt)
printf (' \n Wa=%.0f KN',Wa)
|
32c081fc22220a768c857b4e6f9eea49db57f92e | 73614745139719e6a73e2ccc5166289b8a21b2fc | /tests/extra.sce | 721ea46600219e596f47f27e78006447598ca1b5 | [] | no_license | akshaymiterani/fossee_intqpipopt | 06b1f3ea3373a3d04530b38b929b3b224ee89bd0 | 14fa6a66a984c4d08c20417ba4620fbf531bee2f | refs/heads/master | 2021-01-18T19:54:48.796792 | 2016-06-24T08:52:06 | 2016-06-24T08:52:06 | 61,268,791 | 1 | 1 | null | null | null | null | UTF-8 | Scilab | false | false | 3,285 | sce | extra.sce | c = -1*[ 504 803 667 1103 834 585 811 856 690 832 846 813 868 793 ..
825 1002 860 615 540 797 616 660 707 866 647 746 1006 608 ..
877 900 573 788 484 853 942 630 591 630 640 1169 932 1034 ..
957 798 669 625 467 1051 552 717 654 388 559 555 1104 783 ..
959 668 507 855 986 831 821 825 868 852 832 828 799 686 ..
510 671 575 740 510 675 996 636 826 1022 1140 654 909 799 ..
1162 653 814 625 599 476 767 954 906 904 649 873 565 853 1008 632]';
//Constraint Matrix
A = [ //Constraint 1
42 41 523 215 819 551 69 193 582 375 367 478 162 898 ..
550 553 298 577 493 183 260 224 852 394 958 282 402 604 ..
164 308 218 61 273 772 191 117 276 877 415 873 902 465 ..
320 870 244 781 86 622 665 155 680 101 665 227 597 354 ..
597 79 162 998 849 136 112 751 735 884 71 449 266 420 ..
797 945 746 46 44 545 882 72 383 714 987 183 731 301 ..
718 91 109 567 708 507 983 808 766 615 554 282 995 946 651 298;
//Constraint 2
509 883 229 569 706 639 114 727 491 481 681 948 687 941 ..
350 253 573 40 124 384 660 951 739 329 146 593 658 816 ..
638 717 779 289 430 851 937 289 159 260 930 248 656 833 ..
892 60 278 741 297 967 86 249 354 614 836 290 893 857 ..
158 869 206 504 799 758 431 580 780 788 583 641 32 653 ..
252 709 129 368 440 314 287 854 460 594 512 239 719 751 ..
708 670 269 832 137 356 960 651 398 893 407 477 552 805 881 850;
//Constraint 3
806 361 199 781 596 669 957 358 259 888 319 751 275 177 ..
883 749 229 265 282 694 819 77 190 551 140 442 867 283 ..
137 359 445 58 440 192 485 744 844 969 50 833 57 877 ..
482 732 968 113 486 710 439 747 174 260 877 474 841 422 ..
280 684 330 910 791 322 404 403 519 148 948 414 894 147 ..
73 297 97 651 380 67 582 973 143 732 624 518 847 113 ..
382 97 905 398 859 4 142 110 11 213 398 173 106 331 254 447 ;
//Constraint 4
404 197 817 1000 44 307 39 659 46 334 448 599 931 776 ..
263 980 807 378 278 841 700 210 542 636 388 129 203 110 ..
817 502 657 804 662 989 585 645 113 436 610 948 919 115 ..
967 13 445 449 740 592 327 167 368 335 179 909 825 614 ..
987 350 179 415 821 525 774 283 427 275 659 392 73 896 ..
68 982 697 421 246 672 649 731 191 514 983 886 95 846 ..
689 206 417 14 735 267 822 977 302 687 118 990 323 993 525 322;
//Constrain 5
475 36 287 577 45 700 803 654 196 844 657 387 518 143 ..
515 335 942 701 332 803 265 922 908 139 995 845 487 100 ..
447 653 649 738 424 475 425 926 795 47 136 801 904 740 ..
768 460 76 660 500 915 897 25 716 557 72 696 653 933 ..
420 582 810 861 758 647 237 631 271 91 75 756 409 440 ..
483 336 765 637 981 980 202 35 594 689 602 76 767 693 ..
893 160 785 311 417 748 375 362 617 553 474 915 457 261 350 635 ;
];
nbVar = size(c,1)
b=[11927 13727 11551 13056 13460 ];
// Lower Bound of variables
lb = repmat(0,1,nbVar)
// Upper Bound of variables
ub = repmat(1,1,nbVar)
// Lower Bound of constrains
intcon = [];
for i = 1:nbVar
intcon = [intcon i];
end
options = list("MaxIterations",1);
// The expected solution :
// Output variables
xopt = [0 1 1 0 0 1 0 1 0 1 0 0 0 0 0 0 0 1 0 0 0 0 1 0 1 1 0 1 1 0 1 ..
0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 1 1 ..
0 0 1 0 0 1 0 1 0 0 1 0 0 1 0 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 1 0 0 1 0]
// Optimal value
fopt = [ 24381 ]
// Calling Symphony
[x,f,status,output] = intqpipopt(zeros(100,100),c,intcon,A,b,[],[],lb,ub,zeros(100,1),options); |
a6e3d29f0c80865f4c48fb4eafef182ee62fcd3b | 449d555969bfd7befe906877abab098c6e63a0e8 | /3751/CH2/EX2.12/Ex2_12.sce | 4b8fe3e4d44a3967357ba974acac4a16357ad426 | [] | no_license | FOSSEE/Scilab-TBC-Uploads | 948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1 | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df | refs/heads/master | 2020-04-09T02:43:26.499817 | 2018-02-03T05:31:52 | 2018-02-03T05:31:52 | 37,975,407 | 3 | 12 | null | null | null | null | UTF-8 | Scilab | false | false | 1,386 | sce | Ex2_12.sce | //Fluid system - By - Shiv Kumar
//Chapter 2 - Impact of Jet
//Example 2.12
clc
clear
//Given Data:-
Vi=22; //Absolute velocity of Jet at Inlet of Vane, m/s
u=11; //Velocity of Vane, m/s
ui=u;
uo=u;
alpha_i=25; //Angle made by Jet at Inlet, degrees
alpha_l=135; //Angle made by Jet at leaving, degrees
alpha_o=180-alpha_l; //degrees
//Data Used:-
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
//(a)
Vwi=Vi*cosd(alpha_i); //m/s
Vfi=Vi*sind(alpha_i); //m/s
Vrwi=Vwi-ui; //m/s
beta_i=atand(Vfi/Vrwi); //degrees
Vri=Vfi/sind(beta_i); //m/s
Vro=Vri;
beta_o=alpha_o-asind(uo*sind(180-alpha_o)/Vro); //degrees
Vwo=Vro*cosd(beta_o)-uo; //degrees
//(b)
W=(Vwi+Vwo)*u/g; //N-m/N
//Results:-
printf("(a)Vane angle at Inlet, beta_i=%.2f degrees \n", beta_i) //The answer vary due to round off error
printf(" Vane angle at Outlet, beta_o=%.2f degrees \n", beta_o) //The answer vary due to round off error
printf("(b)Work done per second per unit weight of water striking the vane per second=%.2f N-m/N", W) //The answer vary due to round off error
|
ba398f4aefb55b28ff49b0790dcfd68fa9253f5c | 0e637a0e41450cddb847e0328eaebb9365cefdd4 | /3rd assignment/diff_eqn.sce | e0f0350a5ceb83a018abf8100352581f4d56db2e | [] | no_license | mehtasankets/CASP | 32c7ea00fca072e85d664f4acd050edee5f26a5f | 5dbdd3c14b1b2620c29ab5bfdad640f4529d779c | refs/heads/master | 2020-04-28T09:20:00.026745 | 2011-11-03T08:33:12 | 2011-11-03T08:33:12 | 2,700,756 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 809 | sce | diff_eqn.sce | y = []
coefficients = []
function [value] = calculate(i,count)
k=0
new = 0.0
value = 0
l = i - count
for j = l:(l+count-1)
new = new + (-1 * coefficients($-k) * y(j))
k = k + 1
end
value = new / coefficients(1)
endfunction
count = input("Enter Highest Degree of the Differential Equation : ");
for i = 0:count
printf("Enter coefficient of y[n-%d] :", i)
coefficients(i+1) = input(" ");
end
for i = 1:count
printf("Enter value of y[%d] : ", i-1);
y(i) = input(" ");
disp(i, count)
end
n = input("Enter upper limit : ")
if n <= count then
disp("Wrong value of n given")
exit()
end
for i = count+1:n+1
y($+1) = calculate(i,count)
end
disp("Final Y values : ")
for i = 1:length(y)
printf("\ty[%d] = %d\n", i-1, y(i))
end |
eb3ec0b4b67b99177a3b87a38204f85bc5d7f413 | 26f5cbcb434f99d036e253082987beaf75d06615 | /src/tests/test1.tst | 71e5388aa75adcb02fa671053cbf0b19ac017310 | [] | no_license | slushatel/testsystem | 76a876fea5167bb70e08e6d7c85bddad801b2b3b | 677c786e0f79af99e63fff33414e86357891dcca | refs/heads/master | 2023-03-14T18:09:00.219038 | 2021-03-20T14:56:58 | 2021-03-20T14:56:58 | 345,150,168 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 266 | tst | test1.tst | {
"name":"Test1",
"questions": [
{
"question_text":"Why the sky is blue?",
"answers": [
"Text",
"Gray",
"Bank"
],
"correct_answer" : 2
}
]
} |
cf7c1edafed66855c7f4aa99f8d53b0a67505f39 | f04d3d47f893de08cd99a31b4870112915b80d5b | /Datasets/segment/data5.tst | 4bdca3b60e435b250d7353183581c3f7909cc0e6 | [] | no_license | MesumRaza/MyWorkInPython | f5364b8514943e44c7200123653da9f4551251b1 | bd8c9b3ca2fb02ae6d2b626054fa3cd32c28b330 | refs/heads/master | 2021-08-19T21:46:41.412995 | 2017-11-27T13:37:52 | 2017-11-27T13:37:52 | 111,728,604 | 0 | 0 | null | null | null | null | UTF-8 | Scilab | false | false | 37,105 | tst | data5.tst | 0.0671937 0.329167 0 0 0 0.0361217 0.000377198 0.0149068 0.000160295 0.019623 0.00405187 0.0456554 0.00701481 0.720149 0.261176 0.485769 0.0456554 0.926146 0.147709class2
0.466403 0.75 0 0 0 0.106464 0.00297357 0.11677 0.00247396 0.41544 0.381686 0.498527 0.359314 0.468284 0.628235 0.149905 0.498527 0.31901 0.167396class5
0.0158103 0.3375 0 0 0 0.0456274 0.000492972 0.0484472 0.000921699 0.13039 0.136953 0.157585 0.0950896 0.837687 0.292941 0.314991 0.157585 0.42886 0.251127class0
0.770751 0.7125 0 0 0 0.0399239 0.000436951 0.0136646 0.000269831 0.138652 0.123177 0.120029 0.173032 0.682836 0.0752941 0.823529 0.163476 0.314897 0.892425class6
0.774704 0.604167 0 0 0 0.0323194 0.00049475 0.0459627 0.00122995 0.117996 0.0980551 0.103093 0.152767 0.658582 0.0882353 0.827324 0.14433 0.384638 0.907851class6
0.770751 0.370833 0 0 0 0.249049 0.0840479 0.129193 0.0496809 0.0568035 0.0340357 0.0883652 0.0452065 0.658582 0.296471 0.491461 0.0883652 0.738034 0.126632class2
0.695652 0.5 0 0 0 0.0152091 0.000433218 0.0173913 0.000149609 0.0415698 0.0551053 0.0441826 0.025721 0.914179 0.154118 0.461101 0.0500736 0.515873 0.375937class0
0.177866 0.5 0 0 0 0.00950571 6.34888e-05 0.0397516 0.0013358 0.00981151 0.00567261 0.0184094 0.00467654 0.802239 0.175294 0.540797 0.0184094 0.77037 0.166676class4
0.964427 0.6875 0 0 0 0.0342206 0.00052071 0.0223602 0.000402339 0.128841 0.110211 0.112666 0.163679 0.664179 0.0847059 0.827324 0.154639 0.35207 0.90259class6
0.731225 0.00416667 0 0 0 0.0152091 0.000274438 0.0521739 0.00141841 0.0436354 0.028363 0.0751105 0.0249415 0.714552 0.292941 0.440228 0.0751105 0.687302 0.165562class4
0.916996 0.616667 0 0 0 0.0855513 0.000526583 0.0285714 0.00113543 0.0462174 0.0372771 0.0670103 0.0327358 0.757463 0.242353 0.478178 0.0670103 0.541667 0.175389class3
0.628458 0.0791667 0 0 0 0.00760452 0.000274438 0.0136645 0.000441177 0.775368 0.712318 0.854934 0.750585 0.151119 0.696471 0.362429 0.854934 0.24285 0.107255class1
0.592885 0.55 0 0 0 0.013308 6.34888e-05 0.0111801 2.40441e-05 0.0395043 0.0551053 0.0427099 0.0210444 0.929104 0.156471 0.442125 0.0500736 0.60119 0.377268class0
0.549407 0.0208333 0 0 0 0.0171103 0.000347319 0.0198758 0.000277845 0.779499 0.722853 0.868925 0.738114 0.19403 0.744706 0.240987 0.868925 0.244021 0.12595class1
0.391304 0.470833 0 0 0 0.00950571 6.34888e-05 0.0223602 0.000320591 0.0493158 0.0599676 0.0581738 0.0296181 0.891791 0.185882 0.432638 0.0596465 0.531173 0.316804class0
0.936759 0.3625 0 0 0 0.0456274 0.00129965 0.0285714 0.000430127 0.368448 0.34684 0.428571 0.325019 0.567164 0.507059 0.244782 0.428571 0.28511 0.170969class3
0.205534 0.779167 0 0 0 0.0589354 0.00187041 0.114286 0.00115479 0.360186 0.332253 0.425626 0.317225 0.526119 0.530588 0.248577 0.425626 0.299707 0.163105class5
0.695652 0.491667 0 0 0 0.0152091 0.000253955 0.0248447 0.000213727 0.0446682 0.0583468 0.0493373 0.0265004 0.914179 0.164706 0.444023 0.0544919 0.541887 0.35782class0
0.339921 0.770833 0 0.333333 0 0.0456273 0.000876487 0.0496894 0.00120382 0.429383 0.401135 0.501473 0.379579 0.501866 0.578824 0.195446 0.501473 0.287526 0.167114class5
0.806324 0.15 0 0 0 0.0418251 0.000612481 0.0347826 0.000598435 0.863413 0.832253 0.926362 0.825409 0.343284 0.637647 0.26186 0.926362 0.18354 0.135023class1
0.802372 0.604167 0 0 0 0.0171103 0.000281215 0.0447205 0.000402338 0.165247 0.126418 0.16863 0.198753 0.51306 0.187059 0.815939 0.187776 0.389034 0.992017class6
0.628458 0.4125 0 0 0 0.0285171 0.000696986 0.00993788 0.000196321 0.220501 0.198541 0.260677 0.198753 0.61194 0.376471 0.409867 0.260677 0.307444 0.143861class4
0.948617 0.270833 0 0 0 0.0285171 0.000212877 0.0298137 0.000512945 0.627937 0.54376 0.77246 0.554949 0.0522388 0.972941 0.0170778 0.77246 0.360194 0.140373class1
0.343874 0.433333 0 0 0 0.0570342 0.00183744 0.0931677 0.0030376 0.153628 0.155592 0.185567 0.117693 0.798507 0.321176 0.309298 0.185567 0.397362 0.239165class0
0.6917 0.925 0 0.333333 0 0.0494296 0.00115786 0.0583851 0.00137214 0.0870127 0.0753647 0.0552283 0.131723 0.725746 0 0.901328 0.124448 0.554881 0.830644class6
0.197628 0.416667 0 0 0 0.555133 0.0165807 0.0099379 0.000248328 0.2378 0.221232 0.279823 0.208885 0.643657 0.389412 0.356736 0.279823 0.290355 0.174332class3
0.0711462 0.0708333 0 0 0 0.039924 0.00128869 0.0248447 0.000855744 0.777434 0.700972 0.869661 0.752143 0.0578359 0.757647 0.358634 0.869661 0.267544 0.10378class1
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0.87747 0.579167 0 0 0 0 0 0 0 0 0 0 0 0.833955 0.131765 0.578748 0 0 0.511054class4
0.280632 0.0833333 0 0 0 0.0380227 0.00150879 0.0298137 0.000512943 0.947586 0.947326 0.964654 0.928293 0.529851 0.437647 0.394687 0.964654 0.107616 0.132484class1
0.758893 0.475 0 0 0 0.173004 0.00257226 0.0434783 0.00135518 0.261038 0.235818 0.315169 0.227592 0.576493 0.452941 0.322581 0.315169 0.321825 0.158392class3
0.403162 0.495833 0 0 0 0.0114068 0 0.00621118 0.000281089 0.00542216 0 0.0154639 0 0.794776 0.181176 0.538899 0.0154639 1 0.159449class2
0.573123 0.470833 0 0 0 0.0171103 0.000168059 0.00869565 7.74758e-05 0.0420862 0.054295 0.0486009 0.0233827 0.904851 0.172941 0.440228 0.05081 0.563492 0.339023class0
0.26087 0.0958333 0 0 0 0.0380228 0.00123345 0.0124224 0.000421062 0.37826 0.337115 0.466127 0.32424 0.429105 0.642353 0.166983 0.466127 0.34747 0.159428class3
0.509881 0.741667 0 0 0 0.0304183 0.000343586 0.026087 0.000665226 0.0836561 0.0688817 0.0670103 0.115355 0.705224 0.0717647 0.806452 0.108984 0.439443 0.879406class6
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