pierreqi/scilab_code_50k · Datasets at Hugging Face

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function t=biquad(h) // (c) 2007 Robert Wirski (r.wirski@ieee.org) [l,m,g]=factors(h); lenl=length(l); for i=lenl:-1:1 if polyord(l(i))==1 for j=1:i-1 if polyord(l(j))==1 l(j) = l(j) * l(i); l(i) = null(); break; end; end; end; end; lenm=length(m); for i=lenm:-1:1 if polyord(m(i))==1 for j=1:i-1 if polyord(m(j))==1 m(j) = m(j) * m(i); m(i) = null(); break; end; end; end; end; len = length(l); if modulo(len,2) l($+1)=%z^2; m($+1)=%z^2; len=len+1; end; if len~=length(m) error('Internal error'); end; printf('TotalAmp: %.3f\nnumSections: %i\n',g,len); printf('coeffs:\nIdx\tVal\n'); for i=1:2:len-1 mc1=coeff(m(i)); mc2=coeff(m(i+1)); lc1=coeff(l(i)); lc2=coeff(l(i+1)); printf('%i\t%.5f\n',((0:7)+(i-1)*4)',[-mc1(1);-mc2(1);-mc1(2);-mc2(2);lc1(1);lc2(1);lc1(2);lc2(2)]); end; t=list(g); for i=1:len t($+1)=l(i)/m(i); end; endfunction function r=polyord(p) r = length(coeff(p))-1; endfunction h=iir(6,'lp','butt',[4200 8800]/44100,[1-10^(-1.8/20) 10^(-32/20)]); hk=biquad(h); hk1 = hk(1)*hk(2); hk2 = hk(3); hk3 = hk(4); toJSON(coeff([hk1.num;hk1.den]), "hk1.json"); toJSON(coeff([hk2.num;hk2.den]), "hk2.json"); toJSON(coeff([hk3.num;hk3.den]), "hk3.json");

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clear; clc; //Example 12.5 Av=10^5; Avf=50; Rf=10;//Kohm Ro=20000;//Ohm //x=(1+bvAv) x=Av/Avf; printf('\n(1+bvAv)=%.e\n',x) Rif=Rf*x; Rif=Rif*0.001;//MOhm printf('\ninput resistance=%.2f MOhm\n',Rif) Rof=Ro/x; printf('\noutput resistance=%.2f Ohm\n',Rof)

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//Calculation of cubic capacity and clearance volume clc,clear //Given: n=4 //Number of cylinders d=68/10 //Bore in cm l=75/10 //Stroke in cm r=8 //Compression ratio //Solution: V_s=(%pi/4)*d^2*l //Swept volume of one cylinder in cm^3 cubic_capacity=n*V_s //Cubic capacity in cm^3 //Since, r = (V_c + V_s)/V_c V_c=V_s/(r-1) //Clearance volume in cm^3 //Results: printf("\n The cubic capacity of the engine = %.1f cm^3",cubic_capacity) printf("\n The clearance volume of a cylinder, V_c = %.1f cm^3\n\n",V_c)

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clear // //from phasor diagram vac=vab+vbc hcab=60 vcab=60 hcbc=45 vcbc=77.94 //vbc=60*sin(60) p=(vcab+hcbc)**2 q=vcbc**2 vac=((p+q)**0.5) printf("\n vac= %0.1f v",vac) //the angle is given by ang=taninverse(vcbc/(vcab+hcbc))=36.59 printf("\n phase position with respect to vbc=60-36.59=23.41")

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-chain [[2,-1,0,2],[-2,0,-1,-2],[0,2,2,-1],[2,-1,1,1]] [6,-5,-3,-4] 4 0 [[2,-1,0,2],[-2,0,-1,-2],[0,2,2,-1],[2,-1,1,1]],det=-2 [6,-5,-3,-4], chain 8 => [9,-1,-12,10] => [39,-26,-36,17] => [138,-76,-141,85] => [522,-305,-519,296] => [1941,-1117,-1944,1126] => [7251,-4190,-7248,4181] => [27054,-15616,-27057,15625] => [100974,-58301,-100971,58292]

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// example 1.7(a) / / // hexadecimal to binary conversion // clc // clears the screen // clear // clears already existing variables // x= hex2dec ('17E') //hexadecimal to decimal conversion // a= dec2bin (x) //decimal to binary conversion // disp ('conversion of hexadecimal given no to its binary form is : ') disp (a) // answer in binary form//

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clear; clc; x=poly([0],'x'); printf("\tExample 16.1\n"); E_gf=69; // in GPa Elasticity of glass fibre mf_gf=0.4; //Vol % of glass fibre E_pr=3.4; // in GPa Elasticity of poyester resin mf_pr=0.6; //Vol % of polyester resin Ac=250; //mm^2 sigma=50; //MPa f=(E_gf*mf_gf)/(E_pr*mf_pr); Fc=Ac*sigma; //N Fm=roots(f*x+x-Fc); //N Ff=Fc-Fm; printf("\n\tPart C"); Am=mf_pr*Ac; Af=mf_gf*Ac; sigma_m=Fm/Am; sigma_f=Ff/Af; e_m=sigma_m/E_pr; //Strain for matrix phase e_f=sigma_f/E_gf; //Strain for fiber phase printf("\nStrain for matrix phase is : %f\n",e_m); printf("\nStrain for fiber phase is : %f\n",e_f); //End

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// Example 6.38 // Calculation of a) quantum efficiency b) responsivity // Page no 494 clc; clear; close; //Given data e5=1.2*10^11; // No of electrons collected e8=3.6*10^11; // No of incident photon e=1.602*10^-19; // Charge of an electron lambda=0.85*10^-6; // Wavelength h=6.626*10^-34; // Planck constant c=3*10^8; // Velocity of light I=15*10^-6; // Photocurrent P=0.6*10^-6; // a)Quantum efficiency n=e5/e8; // b)Responsivity R=(n*e*lambda)/(h*c); //Displaying results in the command window printf("\n Quantum efficiency = %0.2f ",n); printf("\n Responsivity(in A/W) = %0.3f ",R); // The answers vary due to round off error

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//Section-5,Example-4,Page no.-D.20 //To calculate temperature coefficient for the reaction. clc; t_h=2*60 k=0.693/t_h A=5000*10^10 E_a=10^5 R=8.314 T=E_a/(2.303*R*(log10(A)-log10(k))) disp(T,'Temperature coefficient for the reaction(K)')

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clc //initialisation of variables sp=1500 //rotational speed of an impulse turbine wheel in revolutions pi=(22/7) dm=1.5 //diameter in m ra=0.8 //ratio of blade speed to steam speed x=159 //x=cwi-cwo in m/s m=10 //kgs mass cf=50.4 //m*m*m/kg vs=1.159 // //CALCULATIONS u=(pi*dm*sp)/60 ci=u/ra pd=(m*x*u)/1000 a=(m*vs)/cf h=a/(pi*dm) //RESULTS printf('power developed for steam flow is %2fkw',pd) printf('\nheight of the blade is %2fm',h)

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T1: T2 T4 T7 P1 T2: T3 T5 P2 T3: P3 T4: T5 T6 P4 T5: P5 T6: T5 P6 T7: T6 P7

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5_10.sce

clc; //page no 206 //prob no. 5.10 //Refer fig.5.24 //Till the antenna there are 2 doubler and 4 tripler f_mul=18*18; dev_o=75*10^3;//o/p freq deviation is 75kHz //Determiantion of reqd freq deviation of oscillator dev_osc=dev_o/f_mul; disp('Hz',dev_osc,'Freq deviation of oscillator is');

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/1727/CH2/EX2.19/2_19.sce

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clc //Initialization of variables dia=1 //m h=3 //m rho=1000 //kg/m^3 N=80 //rpm g=9.81 //m/s^2 //calculation w=2*%pi*N/60 function y = fun(r) y=0.5*rho*w^2 *r^3 *2*%pi endfunction vec=intg(0,dia/2,fun) Pt=vec(1) + %pi/4 *dia^2 *(h-dia)*rho*g //results printf("Total pressure on base = %.2f kN",Pt/1000)

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ReadSEFileSubtractBG.sci

ModuleName="ReadSEFileSubtractBG"; Version="0.01"; DateModified="20-Apr-2015"; DateOfCreation="20-Apr-2015"; Author="Rob Eccleston"; Description="When given a measurement file and a BG file, returns the absorption .. spectra as divived by the BG measurement. Made as a separate function as might want .. to interpolate for different size files in future, or at least do something to handle .. the problem a bit more graciously."; mprintf("Loading " + ModuleName + " V" + Version + ", Last Modified: " + DateModified + "\n"); function [ AbsorptionProfile, Wavelengths, RawSpectra ] = ReadSEFileSubtractBG(MeasurementFileName, BGFileName) [AllAbsorptionData, Wavelengths, TimeDate] = ReadSpectralEnginesData(MeasurementFileName); MeanAbsorption=mean(AllAbsorptionData, 'r'); RawSpectra=MeanAbsorption [AllAbsorptionDataBG, WavelengthsBG, TimeDateBG] = ReadSpectralEnginesData(BGFileName); MeanAbsorptionBG=mean(AllAbsorptionDataBG, 'r'); AbsorptionProfile=MeanAbsorption./MeanAbsorptionBG; endfunction

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// Exa 4.25 format('v',7) clc; clear; close; // Given data I_C =5 * 10^-3;// in A V_CE = 8;// in V V_E = 6;// in V S = 10; h_fc = 200; Beta = h_fc; V_CC = 20;// in V V_BE = 0.6;// in V I_B =I_C/Beta;// in A I_E = I_C+I_B;// in A // I_C*R_C = V_CC - V_CE - V_E; R_C = (V_CC - V_CE - V_E)/I_C;// in ohm R_C = R_C * 10^-3;// in k ohm disp(R_C,"The value of R_C in k ohm is"); R_C = R_C * 10^3;// in ohm //Voltage at point E, V_E =I_E*R_E; R_E = V_E/I_E;// in ohm R_E = R_E * 10^-3;// in k ohm disp(R_E,"The value of R_E in k ohm is"); R_E = R_E * 10^3;// in ohm // S = ((Beta+1)*(R_B+R_E))/( R_B+(R_E*(1+Beta)) ), where R_B= R1*R2/(R1+R2) R_B = ((R_E*(1+Beta))-(S*R_E*(1+Beta)))/( S-(1+Beta) );// in ohm // Vth = V_CC*(R2/(R1+R2)) = V_CC*(R_B/R1) // Applying KVL we get, Vth= I_B*R_B+V_BE+V_E or Vth = (I_B*R_B) + V_BE + V_E;// in V R1 =(V_CC/Vth)*R_B;// in ohm R1= R1*10^-3;// in k ohm disp(R1,"The value of R1 in k ohm is"); R2 = (R1*Vth)/(V_CC-Vth);// in k ohm disp(R2,"The value of R2 in k ohm is");

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// Test #6 : Input Argument #2 range test exec('./allpasslp2bs.sci',-1); [n,d]=allpasslp2bs(0.4,[-4,0.39]); //!--error 10000 //Wt must lie between 0 and 1 //at line 46 of function allpasslp2bs called by : //[n,d]=allpasslp2bs(0.4,[-4,0.39]);

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Vm=96*5/18; fc=900*10^6; c=3*10^8; function [y ]= fround(x,n) // fround(x,n) // Round the floating point numbers x to n decimal places // x may be a vector or matrix// n is the integer number of places to round to y=round(x*10^n)/10^n; endfunction Yc=fround((c/fc),2); fdm=fround((Vm/Yc),2); Tc=fround((0.423/fdm),5)//coherence time Symbolrate=fround((1/Tc),0)//Symbolrate printf('Symbol rate is %.f bps',Symbolrate)

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COMMENT | ************************************************************* | COMMENT | * AUTHOR: R.W. Weyhrauch DATE: around 1978 | COMMENT | * | COMMENT | * SUBJECT: Peano/ Robinson arithmetic (with SS) | COMMENT | * | COMMENT | * NOTES: See Prolegomena paper in AI Journal 1980 (appendix A)| COMMENT | * | COMMENT | * GETFOL VERSION: October 1989 | COMMENT | * | COMMENT | ************************************************************* | COMMENT | this is the example in the App. A of the Prolegomena | COMMENT | | PROBE ALL; KNOW NATNUMS; DECLARE INDCONST UNO DUE TRE DIECI [NATNUMSORT]; DECLARE INDVAR n m p q [NATNUMSORT]; DECLARE FUNCONST suc pred (NATNUMSORT) = NATNUMSORT; DECLARE FUNCONST + * (NATNUMSORT,NATNUMSORT) = NATNUMSORT [INF]; DECLARE PREDCONST < 2 [INF]; DECLARE PREDPAR P 2; AXIOM ONEONE: forall n m . (suc(n) = suc(m) imp n = m); AXIOM SUCC1: forall n . (not 0 = suc (n)); AXIOM SUCC2: forall n . (not 0 = n imp exists m . (n = suc(m))); THEORY PLUS: forall n . n + 0 = n, forall n m . n + suc(m) = suc(n+m); THEORY TIMES: forall n . n * 0 = 0, forall n m . n * suc(m) = (m*n) + m; ATTACH suc TO [NATNUMREP=NATNUMREP] ADD1; ATTACH pred TO [NATNUMREP=NATNUMREP] SUB1; ATTACH + TO[NATNUMREP,NATNUMREP=NATNUMREP] PLUS; ATTACH * TO[NATNUMREP,NATNUMREP=NATNUMREP] TIMES; ATTACH < TO [NATNUMREP,NATNUMREP] LT; ATTACH UNO DAR [NATNUMREP] 1; ATTACH TRE TO [NATNUMREP] 1; COMMENT | | COMMENT | added by FAusto (July 1987) to prove the SIMPLIFY command | COMMENT | It must prove "UNO = TRE " | COMMENT | | SIMPLIFY UNO = TRE;

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//Calculate the reliability of the configuration //page no 219 clear clc; RA = 0.8; RB = 0.8; RC = 0.8; RD = 0.95; RE = 0.85; RABC = 1-((1-RA)*(1-RB)*(1-RC)); RABCDE1 = RABC*RD*RE; mprintf("\RABC = %.4f \n",RABC); mprintf("\RABCDE = %.4f \n",RABCDE1); RABC=0.992; RD=0.95; RE = 1-((1-RE)*(1-RE)); RABCDE2 = RABC*RD*RE; mprintf("\(b) WKT RABCDE = %.4f \n",RABCDE2); I=RABCDE2-RABCDE1; mprintf("\Improvement in R = %.4f \n",I);

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mv_mac1.sce

// MacGregor's first control problem, discussed in Example 11.4 on page 213. // 11.4 exec('mv.sci',-1); exec('cl.sci',-1); exec('cosfil_ip.sci',-1); exec('zpowk.sci',-1); exec('xdync.sci',-1); exec('rowjoin.sci',-1); exec('polsize.sci',-1); exec('left_prm.sci',-1); exec('t1calc.sci',-1); exec('indep.sci',-1); exec('seshft.sci',-1); exec('makezero.sci',-1); exec('move_sci.sci',-1); exec('colsplit.sci',-1); exec('clcoef.sci',-1); exec('cindep.sci',-1); exec('polmul.sci',-1); exec('poladd.sci',-1); exec('tfvar.sci',-1); exec('l2r.sci',-1); exec('transp.sci',-1); exec('tf.sci',-1); exec('covar_m.sci',-1); exec('polyno.sci',-1); // MacGregor's first control problem A = [1 -1.4 0.45]; dA = 2; C = [1 -0.5]; dC = 1; B = 0.5*[1 -0.9]; dB = 1; k = 1; int1 = 0; [Sc,dSc,Rc,dRc] = mv(A,dA,B,dB,C,dC,k,int1); [Nu,dNu,Du,dDu,Ny,dNy,Dy,dDy,yvar,uvar] = ... cl(A,dA,B,dB,C,dC,k,Sc,dSc,Rc,dRc,int1); // Simulation parameters for stb_disc.xcos Tc = Sc; gamm = 1; [zk,dzk] = zpowk(k); D = 1; N_var = 1; Ts = 1; st = 0; t_init = 0; t_final = 1000; [Tcp1,Tcp2] = cosfil_ip(Tc,1); // Tc/1 [Rcp1,Rcp2] = cosfil_ip(1,Rc); // 1/Rc [Scp1,Scp2] = cosfil_ip(Sc,1); // Sc/1 [Bp,Ap] = cosfil_ip(B,A); // B/A [zkp1,zkp2] = cosfil_ip(zk,1); // zk/1 [Cp,Dp] = cosfil_ip(C,D); // C/D

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Ex8_3.sce

clear; clc; disp('Example 8.3'); // aim : To determine // the stoichiometric mass of air // the products of combustion both by mass and as percentage // Given values C = .82;// mass composition C H2 = .12;// mass composition of H2 O2 = .02;// mass composition of O2 S = .01;// mass composition of S N2 = .03;// mass composition of N2 // solution // for 1kg fuel mo2 = 8/3*C+8*H2-O2+S*1;// total mass of O2 required, [kg] sa = mo2/.232;// stoichimetric air, [kg] mprintf('\n The stoichiometric mass of air is = %f kg/kg fuel\n',sa); // for one kg fuel mCO2 = C*11/3;// mass of CO2 produced, [kg] mH2O = H2*9;// mass of H2O produced, [kg] mSO2 = S*2;// mass of SO2 produce, [kg] mN2 = C*8.84+H2*26.5-O2*.768/.232+S*3.3+N2;// mass of N2 produced, [kg] mt = mCO2+mH2O+mSO2+mN2;// total mass of product, [kg] x1 = mCO2/mt*100;// %age mass composition of CO2 produced x2 = mH2O/mt*100;// %age mass composition of H2O produced x3 = mSO2/mt*100;// %age mass composition of SO2 produced x4 = mN2/mt*100;// %age mass composition of N2 produced mprintf('\n CO2 produced = %f kg/kg fuel, percentage composition = %f,\n H2O produced = %f kg/kg fuel, percentage composition = %f,\n SO2 produced = %f kg/kg fuel, percentage composition = %f,\n N2 produced = %f kg/kg fuel, percentage composition = %f',mCO2,x1,mH2O,x2,mSO2,x3,mN2,x4); // End

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/608/CH44/EX44.09/44_09.sce

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44_09.sce

//Problem 44.09: At a frequency of 1 kHz the primary constants of a transmission line are resistance R = 25 ohm/loop km, inductance L = 5 mH/loop km, capacitance C = 0.04 μF/km and conductance G = 80 μS/km. Determine for the line (a) the characteristic impedance, (b) the propagation coefficient, (c) the attenuation coefficient and (d) the phase-shift coefficient. //initializing the variables: R = 25; // in ohm/loop km L = 0.005; // in H/loop km C = 0.04E-6; // in F/km G = 80E-6; // in S/km f = 1000; // in Hz //calculation: w = 2*%pi*f //characteristic impedance Zo Zo = ((R + %i*w*L)/(G + %i*w*C))^0.5 //the propagation coefficient r =((R + %i*w*L)*(G + %i*w*C))^0.5 //the attenuation coefficient a = real(r) //the phaseshift coefficient b = imag(r) printf("\n\n Result \n\n") printf("\n characteristic impedance Zo is %.1f +(%.1f)i ohm",real(Zo), imag(Zo)) printf("\n propagation coefficient is %.4f +(%.4f)i",a,b) printf("\n attenuation coefficient is %.4f Np/km",a) printf("\n the phaseshift coefficient %.4f rad/km",b)

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clc //initialisation of variables pH= 7.10 pH1= 7.21 //CALCULATIONS r= 10^(pH-pH1) //RESULTS printf (' ratio of salt to acid = %.3f ',r)

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Ex3_10.sce

clear // // // //Variable declaration n=1 //order theta=19.2*%pi/180 //glancing angle(radian) lamda=1.54 //wavelength(angstrom) h=1 k=1 l=1 //Calculation d=n*lamda/(2*sin(theta)) //lattice parameter(angstrom) a=d*sqrt(h**2+k**2+l**2) //cube edge of unit cell(angstrom) //Result

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/3812/CH1/EX1.6.e/1_6_e.sce

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clc ; clear all; t=-10:.001:10; for i=1:length(t) if t(i)<=-1/2 then x(i)=1; else x(i)=0; end end // f i g u r e f=scf(0); plot2d(t,x); xtitle('Required figure','t','x(t)')

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/2642/CH6/EX6.2/Ex6_2.sce

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Ex6_2.sce

// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 6 : CONTROL AND STARTING OF A DC MOTORS // Example : 6.2 clc;clear; // clears the console and command history // Given data V_t = 230 // supply voltage in V I_a1 = 15 // dc shunt motor armature current in A N_1 = 650 // speed in rpm R_a = 0.4 // armature resistance in ohm R = 1 // variable resistance in series with the armature // caclulations // at full load E_b1 = V_t-I_a1*R_a // initial back emf in V E_b2 = V_t-I_a1*(R+R_a) // final back emf in V N_2 = N_1*(E_b2/E_b1) // speed at full load in rpm // at half load I_a21 = I_a1/2 // armature current in A E_b21 = V_t-I_a21*(R+R_a) // back emf in V N_21 = N_1*(E_b21/E_b1) // speed at half load torque in rpm // display the result disp("Example 6.2 solution"); printf(" \n speed at full load \n N_2 = %.1f rpm \n", N_2); printf(" \n speed at half load torque \n N_21 = %.1f rpm \n", N_21);

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clc; s = %s; G = s^4+3*s^3+30*s^2+30*s+200; disp(G); co = coeff(G); routh = [co([5,3,1]);co([4,2]) 0]; routh = [routh;-det(routh(1:2,1:2))/routh(2,1) routh(1,3) 0]; routh = [routh;-det(routh(2:3,1:2))/routh(3,1) (routh(3,1)*routh(2,3)-routh(2,1)*routh(3,3))/routh(3,1) 0]; routh= [routh;-det(routh(3:4,1:2))/routh(4,1) 0 0]; disp(routh,"routh table:"); printf("\n routh table contains a row of all zeroes."); //creating an auxillary polynomial temp = routh(3,:); coef = coeff(temp); aux = poly([coef(2) 0 coef(1)],"s","coeffs")/coef(1); disp(aux,"auxillary polynomial:"); z = roots(G); disp(z,"roots of polynomial:") for i = 1:4 A(i)=s+z(i); disp(A(i),"=",i,"factor"); end //can be done by using factors(G) and roots(G) directly

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function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction j=%i //considering coils to be star connected Vl=400//line voltage Vph=Vl/sqrt(3) Rph=15//resistance of load Xl=2*%pi*50*.03//inductive reactance of each coil Zph=Rph+Xl*j Iph=Vph/mag(Zph) Il=Iph pf=Rph/mag(Zph)//power factor P=sqrt(3)*Vl*Il*pf mprintf("In star connected circuit,\nPhase current=%f A,\nLine current=%f A,\nPower absorbed=%f kW\n", Iph, Il,P/10^3) //considering coils to be delta connected Vph=Vl Iph=Vph/mag(Zph) Il=sqrt(3)*Iph P=sqrt(3)*Vl*Il*pf mprintf("In delta connected circuit,\nPhase current=%f A,\nLine current=%f A,\nPower absorbed=%f kW\n", Iph, Il,P/10^3) //answers vary from the textbook due to round off error

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// chapter 12 // example 12.7 // Design a ZVS three-level PWM convertor // page-791-792 clear; clc; // given Edc=300; // in V E0=60; // in V (output voltage) I0=10; // in A fs=120; // in KHz Deff=0.5; // effective duty ratio del_D=25; // assumption for reduction in duty ratio in percentage of duty ratio as done in the book TLI=3.46; // in uH (assuming transformer leakage inductance as done in the book) C=500; // in pF (assuming intrinsic capacitance of MOSFET as done in the book) // calculate fs=fs*1E3; // changing unit from KHz to Hz TLI=TLI*1E-6; // changing unit from uH to H C=C*1E-12; // changing unit from pF to F // since Deff=2*n*E0/Edc, therefore we get, n=Deff*Edc/(2*E0); // calculation of transformer turns ratio // since Deff=D-del_D*D, therefore we get, D=Deff/(1-del_D/100); // calculation of duty ratio Lr=((del_D*D/100)*Edc/2)/(4*(I0/n)*fs); // calculation of resonant inductance Lr_eff=Lr+TLI; // calculation of effecive inductance I0_min=(n*Edc/2)*sqrt(1.5*C/Lr_eff); // calculation of minimum load current I_Lr=I0/n; // calculation of inductor current X_Lr=2*%pi*fs*Lr_eff; // calculation of inductive reactance V_Lr=I_Lr*X_Lr; // calculation of voltage drop across Lr // since E0=Deff*Es, therefore we get Es=E0/Deff; // calculation of secondary voltage Ep=n*Es; // calculation of primary voltage VA=Ep*I_Lr; // calculation of transformer volt-ampere printf("\nThe duty ratio is \t\t D=%.2f",D); printf("\nThe resonant inductance is \t Lr=%.2f uH",Lr*1E6); printf("\nThe effective inductance is \t Lr_eff=%.f uH",Lr_eff*1E6); printf("\nThe minimum load current is \t I0_min=%.2f A",I0_min); printf("\nThe inductor current is \t I_Lr=%.f A",I_Lr); printf("\nThe voltage drop across Lr is \t V_Lr=%.2f V",V_Lr); printf("\nThe secondary voltage is \t Es=%.f V",Es); printf("\nThe primary voltage is \t\t Ep=%.f V",Ep); printf("\nThe transformer volt-ampere is \t VA=%.f VA",VA); // Note :The answer vary slightly due to precise calculation

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clc R=52.08 *10^3 disp("R = "+string(R)+"ohm") //initializing value of Resistance. V=5 disp("V = "+string(V)+"volt") //initializing value of voltage. I=(V/R) disp("Drift current,I=(V/R))= "+string(I)+" amphere")//calculation //this is solved problem 2.6 of chapter 2.

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clear;lines(0); s=poly(0,'s'); Sys=syslin('c',[1,1/(s+1);2*s/(s^2+2),1/s]) ss2tf(dscr(tf2ss(Sys),0.1))

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//Variable declaration: k = 60.0 //Thermal conductivity of rod (W/m.K) p = 7850.0 //Density of rod (kg/m^3) Cp = 434.0 //Heat capacity of rod (J/kg.K) h = 140.0 //Convection heat transfer coefficient (W/m^2.K) D = 0.01 //Diameter of rod (m) kf = 0.6 //Thermal conductivity of fluid (W/m.K) L = 2.5 //Length of rod (m) Ts = 250.0 //Surface temperature of rod (°C) Tf = 25.0 //Fluid temperature (°C) //Calculation: //Case 1: a = k/(p*Cp) //Thermal diffusivity of bare rod (m^2/s) //Case 2: Nu = h*D/kf //Nusselt number //Case 3: Bi = h*D/k //Biot number of bare rod //Case 4: Q = h*(%pi*D*L)*(Ts-Tf) //Heat transferred from rod to fluid (W) //Result: printf("1. The thermal diffusivity of the bare rod is : %.2f x 10^-5 m^2/s.",a/10**-5) printf("2. The nusselt number is : %.2f .",Nu) printf("3. The Biot number is : %.4f .",Bi) printf("4. The heat transferred from the rod to the fluid is : %.0f W.",Q)

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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005] @attribute Rings{15,7,9,10,8,20,16,19,14,11,12,18,13,5,4,6,21,17,22,1,3,26,23,29,2,27,25,24} @inputs Sex,Length,Diameter,Height,Whole_weight,Shucked_weight,Viscera_weight,Shell_weight @outputs Rings @data 9 9 10 9 12 9 10 7 12 9 18 9 8 7 7 7 9 9 13 9 9 9 12 20 13 9 9 7 9 7 10 9 5 4 14 11 9 9 14 23 8 7 9 7 9 23 14 9 22 9 3 3 5 5 10 7 7 7 15 9 13 9 12 9 4 4 19 9 5 4 8 23 9 9 8 9 20 9 16 11 15 9 12 9 14 9 6 7 14 9 11 9 9 7 8 7 19 9 16 11 17 9 21 11 16 9 15 9 15 9 10 9 6 7 5 7 20 9 10 7 14 9 10 7 7 5 13 9 13 9 13 7 10 7 12 9 17 9 8 7 9 7 7 5 10 9 10 7 2 3 15 20 14 9 13 9 20 9 13 9 15 9 9 7 11 9 10 9 6 7 9 9 10 9 12 9 8 9 8 9 12 9 11 20 9 9 4 5 6 5 6 7 7 7 7 7 7 7 8 9 7 9 9 9 9 9 11 9 8 9 10 9 8 9 11 9 10 9 11 9 6 5 7 7 6 7 8 7 9 9 9 9 7 9 9 9 10 9 9 9 9 9 9 9 11 9 5 5 5 5 4 7 7 7 6 7 7 7 6 7 7 7 7 7 10 9 9 9 10 9 8 9 10 9 10 9 9 9 9 9 10 9 12 9 9 9 10 9 10 9 12 11 12 11 12 11 14 11 6 7 6 7 8 9 8 9 11 9 10 9 10 9 5 5 8 5 7 7 6 7 7 7 6 9 8 9 7 9 9 9 8 9 10 9 10 9 10 9 10 9 10 9 11 9 10 9 11 9 9 9 9 9 9 9 11 9 14 11 7 7 8 7 10 9 10 9 9 9 8 7 8 7 9 7 8 9 8 9 9 9 9 9 9 9 8 9 11 9 9 9 11 9 11 9 10 9 10 9 11 9 9 9 10 9 10 9 12 9 10 9 12 11 4 3 6 7 7 7 8 7 7 7 9 9 9 9 9 9 11 9 8 9 6 7 12 20 9 7 9 9 12 9 17 9 10 7 8 9 9 7 7 7 6 7 6 7 12 9 13 9 9 9 12 9 16 9 14 9 13 9 12 9 15 23 23 11 18 9 12 9 18 9 5 4 16 9 11 7 17 9 12 9 10 5 10 9 10 7 15 9 10 9 6 5 5 5 17 9 14 9 14 9 19 9 6 5 7 5 8 9 11 9 13 11 13 9 7 7 6 7 7 9 11 9 9 9 13 11 10 11 5 5 8 7 6 7 9 9 8 9 9 9 9 9 8 9 9 9 8 9 9 9 9 9 9 9 8 7 10 9 11 9 8 9 11 9 8 9 11 9 11 9 10 9 4 5 7 7 9 9 10 9 12 9 11 9 11 9 6 7 11 9 9 9 8 9 11 9 9 9 11 9 10 9 10 9 10 9 8 9 9 9 8 7 8 7 10 9 10 9 8 9 12 9 9 9 11 9 11 9 11 9 8 7 11 9 10 9 8 7 8 9 7 9 9 7 6 5 11 9 8 7 7 7 10 9 13 9 11 9 15 9 18 9 10 7 13 9 15 9 13 9 16 20 12 7 4 4 13 9 11 7 13 7 14 23 11 7 17 9 10 7 5 5 7 5 13 9 8 7 7 7 7 9 10 9 12 9 7 7 8 7 8 9 11 9 10 9 9 9 11 9 11 11 7 7 6 7 8 7 9 9 10 9 11 9 11 9 11 9 8 9 10 9 7 7 8 9 11 9 11 9 13 9 11 11 9 9 12 11 7 7 7 7 8 7 9 9 9 9 9 9 10 9 10 9 7 5 8 7 8 9 9 9 7 9 10 7 11 9 18 9 11 9 8 9 7 7 6 7 6 9 11 9 9 9 9 9 8 9 10 9 9 9 8 9 9 9 11 9 7 7 8 7

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# LitElement JavaScript starter This project includes a sample component using LitElement with JavaScript. ## Setup Install dependencies: ```bash npm i ``` ## Testing This sample uses Karma, Chai, Mocha, and the open-wc test helpers for testing. See the [open-wc testing documentation](https://open-wc.org/testing/testing.html) for more information. Tests can be run with the `test` script: ```bash npm test ``` ## Dev Server This sample uses open-wc's [es-dev-server](https://github.com/open-wc/open-wc/tree/master/packages/es-dev-server) for previewing the project without additional build steps. ES dev server handles resolving Node-style "bare" import specifiers, which aren't supported in browsers. It also automatically transpiles JavaScript and adds polyfills to support older browsers. To run the dev server and open the project in a new browser tab: ```bash npm run serve ``` There is a development HTML file located at `/dev/index.html` that you can view at http://localhost:8000/dev/index.html. ## Editing If you use VS Code, we highly reccomend the [lit-plugin extension](https://marketplace.visualstudio.com/items?itemName=runem.lit-plugin), which enables some extremely useful features for lit-html templates: - Syntax highlighting - Type-checking - Code completion - Hover-over docs - Jump to definition - Linting - Quick Fixes The project is setup to reccomend lit-plugin to VS Code users if they don't already have it installed. ## Linting Linting of JavaScript files is provided by [ESLint](eslint.org). In addition, [lit-analyzer](https://www.npmjs.com/package/lit-analyzer) is used to type-check and lint lit-html templates with the same engine and rules as lit-plugin. The rules are mostly the recommended rules from each project, but some have been turned off to make LitElement usage easier. The recommended rules are pretty strict, so you may want to relax them by editing `.eslintrc.json`. To lint the project run: ```bash npm run lint ``` ## Formatting [Prettier](https://prettier.io/) is used for code formatting. It has been pre-configured according to the Polymer Project's style. You can change this in `.prettierrc.json`. Prettier has not been configured to run when commiting files, but this can be added with Husky and and `pretty-quick`. See the [prettier.io](https://prettier.io/) site for instructions. ## Static Site This project includes a simple website generated with the [eleventy](11ty.dev) static site generator and the templates and pages in `/docs-src`. The site is generated to `/docs` and intended to be checked in so that GitHub pages can serve the site [from `/docs` on the master branch](https://help.github.com/en/github/working-with-github-pages/configuring-a-publishing-source-for-your-github-pages-site). To enable the site go to the GitHub settings and change the GitHub Pages "Source" setting to "master branch /docs folder".</p> To build the site, run: ```bash npm run docs ``` To serve the site locally, run: ```bash npm run docs:serve ``` To watch the site files, and re-build automatically, run: ```bash npm run docs:watch ``` The site will usually be served at http://localhost:8000. ## Bundling and minification This starter project doesn't include any build-time optimizations like bundling or minification. We recommend publishing components as unoptimized JavaScript modules, and performing build-time optimizations at the application level. This gives build tools the best chance to deduplicate code, remove dead code, and so on. For information on building application projects that include LitElement components, see [Build for production](https://lit-element.polymer-project.org/guide/build) on the LitElement site. ## More information See [Get started](https://lit-element.polymer-project.org/guide/start) on the LitElement site for more information.

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//Find x in R^6 such that: // Check if the user gives unequal size of initial guess as of the number of variables conMatrix= [1,-1,1,0,3,1; -1,0,-3,-4,5,6; 2,5,3,0,1,0 0,1,0,1,2,-1; -1,0,2,1,1,0]; conLB=[1;2;3;-%inf;-%inf]; conUB = [1;2;3;-1;2.5]; lb=[-1000;-10000; 0; -1000; -1000; -1000]; ub=[10000; 100; 1.5; 100; 100; 1000]; //and minimize 0.5*x'*Q*x + p'*x with p=[1; 2; 3; 4; 5; 6]; Q=eye(6,6); nbVar = 6; nbCon = 5; x0 = repmat(0,5,1); param = list("MaxIter", 300, "CpuTime", 100); [xopt,fopt,exitflag,output,lambda]=qpipopt(nbVar,nbCon,Q,p,lb,ub,conMatrix,conLB,conUB,x0,param) //Error // WARNING: qpipopt: Ignoring initial guess of variables as it is not equal to the number of variables // lambda = // // lower: [1x6 constant] // upper: [1x6 constant] // constraint: [1x5 constant] // output = // // Iterations: 13 // exitflag = // // 0 // fopt = // // - 14.843248 // xopt = // // 1.7975426 // - 0.3381487 // 0.1633880 // - 4.9884023 // 0.6054943 // - 3.1155623

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clc //initialisation of variables i= 1/5000 C= 100 b= 50 //ft h= 10 //ft Q= 1000 //cuses g= 32.2 //ft/sec^2 //CALCULATIONS f= 2*g/C^2 m= (b*h)/(b+2*h) v= Q/(b*h) r= (i-(f*4/(2*g*m)))/(1-(2^2/(g*h))) s= i-r //RESULTS printf ('Slope = %.6f ',s)

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//Example 9.2 //Page no. 393 //calculae the steam requirement and the no. of tubes //if the height of the calandria is 1.5 m. //given ci=10 //%,initial concentration cf=40 //%, final conc Wf=2000 //kg/h, feed rate ft=30 //C feed temp. rp=0.33 //kg/cm^2, reduced pressure bt1=75 //C,boiling point temp. sst=115 //C, saturated steam temp. l=1.5 // m,height of calandria sh=0.946 //kcal/kg C, specific heat of liquir lh=556.5 //kcal/kg latent heat of steam bt2=345 //K, boiling point of water h=2150 //kcal/h m^2 C, overall heat transfer coefficient si=2000*(ci/100) //kg/h, solids in wi=1800 //kg/h,wate in Wp=si/(cf/100) //kg/h, product out Wv=Wf-Wp //evaporation rate ef=sh*(ft-bt1) ip=0 lamda_s=529.5 //kcal/kg, lamda_s=is-il bpe=(273+bt1)-345 //boiling point elevation. //from eergy balance eq. Ws=(Wp*ip+Wv*lh-Wf*ef)/lamda_s q=Ws*lamda_s //kcal/h,rate of heat transfer A=q/(h*(sst-bt1)) // m^2 di=0.0221 //m,inside diameter At=%pi*l*di //m^2, area of a single tube N=A/At //no. of tubes printf("The steam required is %f kg/h\n",Ws) printf("No. of tube are %f",N)

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// problem 2.8 h1=0.05 h2=0.015 s=41/40 l=h1/(s-1) w1=25 // applying bakance in vertical direction w=w1*(l+h1)/(h2) disp(w,"weight of ship in in N")

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//clear// clc clear exec("7.7data.sci"); for i=1:length(Curea) x(i)= 1/Curea(i); y(i) = 1/(-rurea(i)); end slope = (y(5)-y(1))/(x(5)-x(1)); plot2d(x,y) xtitle( 'Figure E7-7.1', '1/Curea', '1/-rurea' ) ; disp("(Km/Vma = slope") disp(slope)

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function [w,epoch]=perceptron_hebbian(x,w,d) //Inputs: // x: vector with training data. The inputs must be distributted in rows and the input sets in lines // w: vector with initial synaptic weight values // d: vector with the expected output values //Output: // wR: vector with resulted synaptic weight values // epoch: numer of training epoch //n: learning factor n=0.01; ERROR_EXIST = 1; ERROR_INEXIST = 0; [Input_Size,Samples_Size]=size(x) errors=ERROR_EXIST; epoch=0; while errors == ERROR_EXIST then errors = ERROR_INEXIST; //disp("Starting training epoch: "+string(epoch)); //Treining the system for all L sample training data for k=1:Samples_Size v=w'*x(:,k); //Activation function------------------------- y=sign(v); // if error exist if y~=d(k) then //Calculating the error in the i instant e=d(k)-y; dw=n*e.*x(:,k); w= w + dw; errors=ERROR_EXIST; end end epoch=epoch+1; end endfunction

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function [yp, betap, exitcode, active] = ir_predict(Xp, X, y, epsilon) // Computes interval prediction for response y at the point x // using the interval regression constructed for dataset (X,y,epsilon) // // TODO: Fix bugs in algorithm of active constraints detection. // // Inputs: // Xtest (k x m)-matrix, contains points (row vectors) to predict at // X (n x m)-matrix of observations for X variables // y column n-vector of measured values of response variable y // epsilon real number or n-vector, half-width(s) of uncertainty // intervals for response variable y // // Outputs: // yp (k x 2)-matrix, interval regression predictions at points Xp(i,:), // yp(i,1) and yp(i,2) are, accordingly, lower and upper bounds // of predicted interval // betap (k x m x 2)-matrix, regression parameters values providing // interval prediction yp(i), beta(i,:,1) and beta(i,:,2) // correspond to lower and upper bounds of yp accordingly // exitcode integer exit code // 1 Ok, solution is found // -1 Unbounded solution set (colinearity in the data) // -2 No feasible solution (feasible parameters set is empty) // active k-element array of structs with fields 'lower' and 'upper', // active(i).lower and active(i).upper contains vectors of // active constraints (observations) which limit the lower and // upper bounds of a predicted interval yp(i,:) // // Example: // /// Simulate observations for simple dependency y = b(0) + b(1)*x // b = [1; 1]; // simulated dependency parameters // n = 5; // number of observations // epsilon = 0.5; // error bound // X = [ ones(n,1) (1:5)' ]; // X values // y = X*b + epsilon*rand(n,1)-0.5; // y values with bounded errors // figure; // ir_scatter(X,y,epsilon); // Show interval dataset in black // Xp = [1 2.5; 1 5.5]; // Set points where to predict // [yp, betap, exitcode] = ir_predict(Xp, X, y, epsilon); // Predict dependency values // ir_scatter(Xp,yp,'b.'); // Show predicted intervals in blue if size(Xp,2) ~= size(X,2) error('Xp must have the same number of columns as X'); end k = size(Xp,1); n = size(X,1); m = size(X,2); A = [X; -X]; b = [y+epsilon; -y+epsilon]; // Allocate matricies and structures yp = zeros(k,2); betaplow = zeros(size(Xp)); betaphigh = betaplow; active = struct('lower',[],'upper',[]); for i = 1:k [betalow, flow, exitcode, actlow] = ir_linprog(Xp(i,:), A, b); if exitcode < 0 mprintf("%d - lower: %d", i, exitcode); return end [betahigh, fhigh, exitcode, acthigh] = ir_linprog(-Xp(i,:), A, b); if exitcode < 0 mprintf("%d - upper: %d", i, exitcode); return end yp(i,:) = [flow, -fhigh]; betaplow(i,:) = min(betalow',betahigh'); betaphigh(i,:) = max(betalow',betahigh'); active(i).lower = [actlow.lower; acthigh.lower]; active(i).upper = [actlow.upper; acthigh.upper]; end betap = cat(3,betaplow,betaphigh); endfunction // ir_predict

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function response = http_get_url(URL, varargin) [host, resource, port] = http_split(URL) // Get hostname and resource from URL response = http_get(host, resource, port, varargin) endfunction

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//EX2_11 PG-2.38 clc If=30e-3;//forward current T1=25+273;//temperature in degree kelvin disp("Therefore at a temperature of 25 Degree C ") Rf=26e-3/If; printf("\n dynamic resistance is %.3f ohm \n",Rf) disp("Therefore at a temperature of 75 Degree C ") T2=75+273//Temperature in degree kelvin Rf=Rf*(T2/T1); printf("\n dynamic resistance is %.3f ohm",Rf)

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//page 20 //Example 1.13 clear; close; clc; disp('A 2*2 elementary matrix is one of the following:'); A = [0 1;1 0]; disp(A); disp('---------------------'); disp('1 c'); disp('0 1'); disp('---------------------'); disp('1 0'); disp('c 1'); disp('---------------------'); disp('c 0'); disp('0 1'); disp('where, c is not equal to 0'); disp('---------------------'); disp('1 0'); disp('0 c'); disp('where, c is not equal to 0'); //end

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clc clear //Input data do=0.902*10^3;//Density of oil in kg/m^3 Pg=2*10^5;//Gauge pressure in N/m^2 g=9.81;//Gravity in m/sec^2 ho=2;//Level of oil in m d=2;//Diameter of cylinder in m pi=3.141595;//Constant value of pi //Calculations A=(pi/4)*d^2;//Area of cylinder Po=do*g*ho;//Pressure due to oil in N/m^2 W=(Pg+Po)*A;//Weight of the piston in N //Output printf('The total weight of piston and slab W = %3.2f N ',W)

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//no i/p args are passed to the function dft=goertzel(); //output //!--error 4 //Undefined variable: X //at line 38 of function goertzel called by : //dft=goertzel();

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//Exa 4.4 clc; clear; close; //given data : n=10;//no. of elements //d=lambda/4 separation in meter disp("For broad side array : ") disp("D=2*n/(lambda/d)"); disp("Putting d=lambda/4 we get D=2*n/4") D=2*n/4;//directivity : unitless Ddb=10*log10(D);//in db disp(Ddb,"For broad side array D in db = "); disp("For end fire array : ") disp("D=4*n/(lambda/d)"); disp("Putting d=lambda/4 we get D=4*n/4") D=4*n/4;//directivity : unitless Ddb=10*log10(D);//in db disp(Ddb,"For end fire array D in db = ");

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clear clc //to find spring compression // GIVEN:: //mass of body m = 3.63//in kg //speed of block v = 1.22//in m/s //force constant for spring k = 135//in // SOLUTION: //using work-energy principle //spring compression d = v*sqrt(m/k)//in meters d1 = d*10^2//in printf ("\n\n Spring compression d = \n\n %.3f m",d); printf ("\n\n Spring compression d = \n\n %.1f cm",d1);

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clc clear //Input data CO=12;//The composition of carbondioxide of combustion by volume in percentage C=0.5;//The composition of carbonmoxide of combustion by volume in percentage O=4;//The composition of oxygen of combustion by volume in percentage N=83.5;//The composition of nitrogen of combustion by volume in percentage o=32;//Molecular weight of the oxygen co=44;//Molecular weight of the carbondioxide c=12;//Molecular weight of the carbon s=32;//Molecular weight of the sulphur so=64;//Molecular weight of sulphur dioxide n1=28;//Molecular weight of the nitrogen h=2;//Molecular weight of the hydrogen //Calculations m=12+0.5;//Balancing carbon x=N/3.76;//Balancing nitrogen z=[x-(CO+(C/2)+O)]*2;//Balancing oxygen n=z*h;//Balancing hydrogen Af=[(x*o)+(N*n1)]/[(m*c)+(n)];//Air/fuel ratio As=[(18.46*o)+(69.41*n1)]/173.84;//Stoichiometric air/fuel ratio Ta=(Af/As)*100;//Percent theoretical air mc=[(m*c)/173.84]*100;//Composition of carbon on mass basis in percent mh=(n/173.84)*100;//Composition of hydrogen on mass basis in percent //Output printf(' (a)The air/fuel ratio = %3.2f \n (b)The percent theoretical air = %3.1f percent \n (c)The percentage composition of fuel on a mass basis : \n C = %3.1f percent \n H = %3.1f percent ',Af,Ta,mc,mh)

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// Example 6_5 clc;funcprot(0); // Given data p_1=85.0;// psig p_2=10.0;// psig t=8.00;// hour m=20.0;// gal // Calculation mv=20.0/8.00;// gal/h mv=mv*0.13368*(1/3600);// ft^3/s W_shaft=mv*(p_1-p_2)*144;// ft.lbf/s W_shaft=W_shaft*(1/550);// hp W_shaft=W_shaft*746;// W W_shaft_ins=W_shaft*5*60*(1/2.50);// W printf("\nThe hydraulic power produced,(W_shaft)_instantaneous=%3.0f W",W_shaft_ins);

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// Test # 4 : When numerator is neither symmetric or anti-symmetric exec('./tf2ca.sci',-1); [d1,d2,b]=tf2ca([0.1 0.5 -0.1],[1 2 3]); //!--error 10000 //Numerator coeffcients must be either be symmetric or antisymmetric //at line 71 of function tf2ca called by : //[d1,d2,b]=tf2ca([0.1 0.5 -0.1],[1 2 3])

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//identificação de sistemas utilizando LMS clear; clc; rand("normal"); N = 2000; hn = [1.2 0.8 0.6]; sigma1 = 0.2; E = rand(1,N); xn = filter(hn,1,E)'; W = [1 2 3]; n = sigma1*rand(1,N); rx = xcorr(xn,2,'biased'); Rx = [rx(3:5) rx(2:4) rx(1:3)]; tr = Rx(1,1)+Rx(2,2)+Rx(3,3); [Q,lambda]=spec(Rx); lambdamax=max(lambda); // Computacao iterativa c = 0.1 mi = c/(2*lambdamax+tr); wn = [0 0 0]'; // filtro unitario inicial d = filter(W,1,xn)+n'; w = zeros(3,N); xb = [0 0 0]'; for n=1:length(xn) xb = [xn(n);xb(1:2)]; yn = wn'*xb; y(n) = yn; e(n) = d(n)-y(n); // calculo do grad estimado grade = -2*e(n)*xb; wn = wn - mi*grade; w(:,n) = wn end plot2d(w');

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clc; clear; // Função para gerar uma nova população function [new_pop]=nova_populacao(nPop, nPrecInd) population = round(rand(nPop, nPrecInd)); for i = 1:nPop do new_pop(i) = strcat(string(population(i,:))); end endfunction // Função para encontrar o fitness function [fitness] = avaliafitness(pop) [nPop, nPrecInd] = size(pop); for i = 1:nPop do j=1; soma = 0.0; mult = 1.0; for k = 1:10 do xi = converter(part(pop(i),j:j+15)); j=j+16; soma = soma + xi^2 / 4000.0; mult = mult * cos(xi / sqrt(k)); end fitness(i) = 1.0 + soma - mult; end endfunction // Função para converter de binário para decimal e // colocar na escala de -5.12 a 5.12 function[valor] = converter(varbinario) valor = bin2dec(strcat(string(varbinario))); // recebe binário, transforma // para string, concatena todas as colunas do individuo, // e transforma para decimal aux = valor; precisao = 16; a = -5.12; b = 5.12; resultado = a + aux *(b-a) / 2^precisao - 1; valor = resultado; endfunction // Roda Roleta // a) recebe população e fitness function [new_pop]=roda_roleta(pop, fitness) // b) coloca em ordem crescente/decrescente o vetor fitness [fitness, old_pos] = gsort(fitness, "g", "d"); // c) ordena a população conforme vetor fitness for i = 1:size(pop,1) do pop_asc(i) = pop(old_pos(i)); end // d) inverter o fitness para que o menor número tenha maior possibilidade // de ser escolhido. soma=sum(fitness); for n=1:size(pop,1) do if fitness(n) == 0 then acumulado(n) = 0; else acumulado(n) = (fitness(n) / soma); end end soma=sum(acumulado); for n=1:size(pop,1) do if acumulado(n) ~= 0 then acumulado(n) = acumulado(n) / soma; end end // e) selecionar um número aleatório para encontrar um indivíduo para // compor a nova população - realizar este passo n vezes, // onde n = nIndividuos. cs = cumsum(acumulado); new_pop = []; n = 1; while size(new_pop, 1) < size(pop, 1) do r = rand(); for i=1:size(pop,1) do if cs(i) > r & size(new_pop, 1) < size(pop, 1) then new_pop(n) = pop_asc(i); n = n+1; end end end endfunction // Função para fazer cruzamento function [Crossed_Indiv1, Crossed_Indiv2] = crossover(Indiv1,Indiv2) MultiCrossNb = 1; BinLen = length(Indiv1); // Crossover positions selection mix = unique(gsort(sample(MultiCrossNb, 1:BinLen-1), "g", "i"))'; Crossed_Indiv1 = Indiv1; Crossed_Indiv2 = Indiv2; for j = 1:size(mix, "*") do H1 = part(Crossed_Indiv1, 1:mix(j)); //Head for Indiv1 T1 = part(Crossed_Indiv1, (mix(j) + 1):BinLen); //Tail for Indiv1 H2 = part(Crossed_Indiv2, 1:mix(j)); //Head for Indiv2 T2 = part(Crossed_Indiv2, (mix(j) + 1):BinLen); //Tail for Indiv2 Crossed_Indiv1 = [H1 + T2]; Crossed_Indiv2 = [H2 + T1]; end endfunction // Função para fazer mutação function [Mut_Indiv1, Mut_Indiv2] = mutation(Indiv1, Indiv2) MultiMutNb = 1; dim = length(Indiv1); pos = grand(1, MultiMutNb, "uin", 1, dim); pos = unique(pos); Mut_Indiv1 = Indiv1; Mut_Indiv2 = Indiv2; for i = 1:size(pos, '*') do Mut_Indiv1 = [part(Mut_Indiv1, 1:pos(i) - 1), .. part(Mut_Indiv1, pos(i)), part(Mut_Indiv1, pos(i) + 1:dim)]; if Mut_Indiv1(2) == "0" then Mut_Indiv1(2) = "1"; else Mut_Indiv1(2) = "0"; end Mut_Indiv1 = strcat(Mut_Indiv1); Mut_Indiv2 = [part(Mut_Indiv2, 1:pos(i) - 1), .. part(Mut_Indiv2, pos(i)), part(Mut_Indiv2, pos(i) + 1:dim)]; if Mut_Indiv2(2) == "0" then Mut_Indiv2(2) = "1"; else Mut_Indiv2(2) = "0"; end Mut_Indiv2 = strcat(Mut_Indiv2); end endfunction // Gerar população inicial nPop = int(input('Digite a quantidade de indivíduos da população: ')); nPrecInd = 160; probCross = double(input('Digite a probabilidade de crossover: ')); probMut = double(input('Digite a probabilidade de mutação: ')); nVar = 16; nIter = 10000; bf = ([]); aux = 1; disp('Executando...'); tic(); //começa pop = nova_populacao(nPop, nPrecInd); // pop = [1,1,0,0,1,0;0,0,1,0,1,1;1,1,1,0,0,0;1,0,1,1,0,1]; if modulo(nPop, 2) ~= 0 then printf('\nO tamanho da população deve ser um número PAR!'); abort; end // Verificando se nVar é divisor de nPrecInd if modulo(nPrecInd, nVar) ~= 0 then printf('\nO valor de nVar deve ser divisor do .. valor de nPrecInd que é %d', nVar, nPrecInd); abort; end // Avaliar a função objetivo funcprot(0); fitness = avaliafitness(pop); // Seleção usando roda da roleta pop = roda_roleta(pop, fitness); nFob = nPop; // LOOP PRINCIPAL DE OTIMIZAÇÃO while nFob < nIter do // PARA cada membro da população for m = 1:2:nPop do // Escolher filho1 e filho2 filho1 = pop(m); filho2 = pop(m+1); // Crossover pCross = rand(); if pCross < probCross then [filho1, filho2] = crossover(strcat(string(filho1)), .. strcat(string(filho2))); end // Mutation usando os novos filho1 filho2 pMut = pCross; if pMut < probMut then [filho1, filho2] = mutation(strcat(string(filho1)), .. strcat(string(filho2))); end // Add filhos na população no lugar dos selecionados pop(m) = filho1; pop(m+1) = filho2; // FIM end // Avaliar fitness funcprot(0); fitness = avaliafitness(pop); // Seleção usando roda roleta pop = roda_roleta(pop, fitness); nFob = nFob + nPop; // add o melhor fitness (best fitness) na variável "bf" bf(aux, 1) = max(fitness); bf(aux, 2) = mean(fitness); bf(aux, 3) = min(fitness); aux = aux + 1; // FIM LOOP end tempo = toc(); // termina plot(bf(:,1), 'o-r'); plot(bf(:,2), 'o-g'); plot(bf(:,3), 'o-b'); title('Gráfico do Fitness'); xlabel('Fitness'); ylabel('Valor'); legend('Máximo', 'Médio', 'Mínimo'); printf('\nLevou %f segundo(s) para terminar', tempo); printf('\n\nMenor fitness encontrado: %f', min(bf)); clear('i','m','filho1','filho2','fitness','pMut',.. 'pCross','nFob','nIter','nVar');

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V=240 w=100*%pi R=6 Vr=120 I=Vr/R t=(205/I)^2 ////t=r^2+Xl^2 r=((240/I)^2-t-R*R)/2/R ///this part solved wrong in the book Xl=sqrt(t-r*r) Z=sqrt(t) disp(r) disp(Xl) disp(Z) Pl_choke=I*I*r disp(Pl_choke) pf=Pl_choke/205/20 disp(pf)

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x = [0 : 0.1: 2*%pi]; y = sin(x); plot2d(x, y, -3); // markers are represented by negative no. plot2d(x, y, -2);

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// Exa 8.6 clc; clear; close; format('v',6) // Given data V_DD = 10;// in V R_D = 5.1;// in k ohm R_D = R_D * 10^3;// in ohm g_m = 2*10^-3;// in S r_d = 50;// in k ohm r_d = r_d * 10^3;// in ohm Vi = 0;// in V R_G = 1;// in Mohm R_G = R_G * 10^6;// in ohm // (i) Input impedance Zi = R_G;// in ohm Zi= Zi*10^-6;// in M ohm disp(Zi,"The input impedance in Mohm is"); // (ii) Output impedance Zo = (r_d*R_D)/(r_d+R_D);// in ohm disp(Zo,"The output impedance in ohm is"); // (iii) Voltage gain Av = -g_m*Zo; disp(Av,"The voltage gain is");

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data = read("test3.txt",-1,3); //чтение эксперимента function e = G(a,z), //функция для расчета амплитуды напряжения и частоты синусоиды МНК e = z(2) - (a(1) * sin(a(2)* z(3))); endfunction a0 = [1; 1]; //[aa, error1] = datafit(G, data',a0) // расчет амплитуды напряжения и частоты синусоиды //проверка аппроксимации построением графика //disp(aa) //t(:,1) = 0:0.01:20 //t(:,2) = aa(1) * sin(aa(2) * t(:,1)) //plot(data(:,3), data(:,2)) //plot(t(:,1), t(:,2), "r-.") global J R w U JR J=0.00259; R=4.5; w=aa(2); U=aa(1); JR=J*R function e = GG(k,z), //функция для расчета коэффициентов kf ke и km МНК global JR R w U e = z(1) - ((k(3)*U)/(k(1)*R+k(2)*k(3))*(w^(-1)*(1-cos(w*z(3)))-JR^2/((k(1)*R+k(2)*k(3))^2+(U*k(3))^2)*((k(1)*R+k(2)*k(3))/JR*sin(w*z(3))-w*cos(w*z(3))+w*exp(-(k(1)*R+k(2)*k(3))/JR*z(3))))) //для u=Usin(wt) //e = z(1) - U*k(3)*JR/((k(1)*R+k(2)*k(3))^2)*((k(1)*R+k(2)*k(3))/JR*z(3)-1+exp(-((k(1)*R+k(2)*k(3))/JR)*z(3))) //для u = const endfunction k0 = [0.3; 0.3; 0.3] //[kk, error2] = datafit(GG, data', k0) //расчет коэффициентов kf ke и km //проверка аппроксимации построением графика disp(kk) //t1(:,1) = 0:0.01:20 //t1(:,2) = (kk(3)*U)/(kk(1)*R+kk(2)*kk(3))*(w^(-1)*(1-cos(w*t1(:,1)))-JR^2/((kk(1)*R+kk(2)*kk(3))^2+(U*kk(3))^2)*((kk(1)*R+kk(2)*kk(3))/JR*sin(w*t1(:,1))-w*cos(w*t1(:,1))+w*exp(-(kk(1)*R+kk(2)*kk(3))/JR*t1(:,1)))) //t(:,2) = kk(3)*JR/((kk(1)*R+kk(2)*kk(3))^2)*((kk(1)*R+kk(2)*kk(3))/JR*t1(:,1)-1+exp(-((kk(1)*R+kk(2)*kk(3))/JR)*t1(:,1))) //plot(data(:,3), data(:,1)) //plot(t1(:,1), t1(:,2), "r-.") //Рассчет коэффициентов PID //nob=3 //"3" для бинома Ньютона и "2" для функции Баттерворта //w0= //K = (kk(1)*R+kk(2)*kk(3))/JR //kd=nob*J*w0-K //kp=nob*J*w0^2 //ki=J*w0^3

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S=[1,2,3,4,5,6]; //sample space for the rolling of a die A=[2,4,6]; //event that an even number occurs B=[1,3,5]; //event that an odd number occurs C=[2,3,5]; //event that a prime number occurs disp(union(A,C),'sample space for the event that an even or a prime number occurs') disp(intersect(B,C),'sample space for the event that an odd prime number occurs') disp(setdiff(S,C),'sample space for the event that a prime number does not occur') //It is the complement of the set C. intersect(A,B) //It is a null set or null vector since there can't occur an even and an odd number simultaneously H=0; //"head" face of a coin T=1; //"tail" face of a coin S=["000","001","010","011","100","101","110","111"] ; //sample space for the toss of a coin three times A=["000","001","100"]; //event that two more or more heads appear consecutively B=["000","111"]; //event that all tosses are the same disp(intersect(A,B),'sample space for the event in which only heads appear') disp('Experiment:tossing a coin until a head appears and then counting the number of times the coin is tossed') S=[1,2,3,4,5,%inf] //The sample space has infinite elements in it disp("Since every positive integer is an element of S,the sample space is infinite")

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pathname=get_absolute_file_path('5_08.sce') filename=pathname+filesep()+'5_08data.sci' exec(filename) Cn=integrate('1-0.95*y','y',0,1.0)-integrate('1-300*y^2 ','y',0,0.1)-integrate('-2.2277+2.2277*y','y',0.1,1.0) printf("\Answer:\n") printf("\n\Normal force coefficient : %f \n\n",Cn)

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// scilab Code Exa 18.12 turbo prop Gas Turbine Engine Ti=268.65; // in Kelvin n_C=0.8; // Compressor Efficiency c1=85; // entry velocity in m/s m=50; // mass flow rate of air in kg/s R=287; gamma=1.4; // Specific Heat Ratio cp=1.005; // Specific Heat at Constant Pressure in kJ/(kgK) u=500/3.6; // speed of a turbo prop aircraft in m/s delT=225; // temperature rise through the compressor(T02-T01) in K pi=.701; // Initial Pressure in bar n_D=0.88; // inlet diffuser efficiency a_i=sqrt(gamma*R*Ti); Mi=u/a_i; Toi_i=1/0.965; // (Toi/Ti)from isentropic flow gas tables at Mi and gamma values T01=Ti*Toi_i; T1=T01-(0.5*(c1^2)/(cp*1e3)); //part(a) T1s_i=1+n_D*((T1/Ti)-1); // (T1s/Ti)isentropic temperature ratio through the diffuser p1_i=T1s_i^(gamma/(gamma-1)); // (p1s/pi)isentropic pressure ratio p1=p1_i*pi; delp_D=p1-pi; disp("bar",delp_D,"(a)isentropic pressure rise through the diffuser is") // part(b) compressor pressure ratio T02s=T01+(delT*n_C); r_oc=(T02s/T01)^(gamma/(gamma-1)); //compressor pressure ratio(p02/p01) disp(r_oc,"(b)compressor pressure ratio is") // part(c) P=m*cp*delT; disp("MW",P*1e-3,"(c)power required to drive the compressor is")

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// Example 6.17 // AC Superposition Calculations // from figure 6.40(b),apply node equation we get V_c1=poly(0,'V_c1'); P_1=(1/50+%i/10-%i/20)*V_c1-60/(%i*20); // Node equation V_c1=roots(P_1); // Now from figure 6.40(c) V_c2=poly(0,'V_c2'); P_2=(1/50+%i/25-%i/8)*V_c2-(%i*3); // Node equation V_c2=roots(P_2); V_c1_m=abs(V_c1); phase_v_c1=atan(imag(V_c1),real(V_c1))*(180/%pi); V_c2_m=abs(V_c2); phase_v_c2=atan(imag(V_c2),real(V_c2))*(180/%pi); omega_1=5; omega_2=2; t=0:0.01:10; v_c=V_c1_m*cos(omega_1*t+phase_v_c1)+V_c2_m*cos(omega_2*t+phase_v_c2); plot(t,v_c,'r'); xlabel('t'); ylabel('v_c(t)') title('Voltage Waveform')

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clc clear disp("Example 8.21") printf("\n") disp("Add the following binary numbers") disp("a)11011 & 10110 b)1100 & 111 c)10.1011 & 11.011") //Given binary number i=1;w=1 a=11011 b=10110 //Given binary number i=1;w=1 bin=11.101 //separating integer part IPa=floor(a) IP1a=IPa //separating decimal part DPa=modulo(a,1) DP1a=DPa //converting decimal value to interger p=4 DPa=DPa*10^p //should change power of 10 as according to number of digits in decimal digit //storing each integer digit in I(i) while(IPa>0) Ia(i)=modulo(IPa,10); IPa=floor(IPa/10); i=i+1; end //storing each decimal digit in D(w) while(DPa>0) Da(w)=modulo(DPa,2) DPa=(DPa/10) DPa=floor(DPa) w=w+1; end //to do zero padding of remaining erm of D(w) if(DP1a<1) if(DP1a>0) if(length(Da)<p) q=length(Da) for f=q+1 :p Da(f)=0 end end end end if(IP1a>0) for i=1:length(Ia)//checking whether it is a binary number or not if(Ia(i)>1) then disp('not a binary number') abort end end end if(IP1a>0) IPa=0 for i=1:length(Ia) //multipliying bits of integer part with their position values and adding IPa=IPa+(Ia(i)*2^(i-1)) end end DPa=0 if(DP1a>0) if(DP1a<1) for z=1:length(Da) //multipliying bits of decimal part with their position values and adding DPa=DPa+(Da(z)*2^(-1*(length(Da)+1-z))) end end end decimala=IPa+DPa //displaying the output disp(decimala) //for b //Given binary number i=1;w=1 //separating integer part IPb=floor(b) IP1b=IPb //separating decimal part DPb=modulo(b,1) DP1b=DPb //converting decimal value to interger p=3 DPb=DPb*10^p //should change power of 10 as according to number of digits in decimal digit //storing each integer digit in I(i) while(IPb>0) Ib(i)=modulo(IPb,10); IPb=floor(IPb/10); i=i+1; end //storing each decimal digit in D(w) while(DPb>0) Db(w)=modulo(DPb,2) DPb=(DPb/10) DPb=floor(DPb) w=w+1; end //to do zero padding of remaining erm of D(w) if(DP1b>0) if(DP1b<1) if(length(Db)<p) q=length(Db) for f=q+1 :p Db(f)=0 end end end end if(IP1b>0) for i=1:length(Ib)//checking whether it is a binary number or not if(Ib(i)>1) then disp('not a binary number') abort end end end if(IP1b>0) IPb=0 for i=1:length(Ib) //multipliying bits of integer part with their position values and adding IPb=IPb+(Ib(i)*2^(i-1)) end end DPb=0 if(DP1b>0) if(DP1b<1) for z=1:length(Db) //multipliying bits of decimal part with their position values and adding DPb=DPb+(Db(z)*2^(-1*(length(Db)+1-z))) end end end decimalb=IPb+DPb //displaying the output disp(decimalb) sum1=decimala+decimalb i=1;x=1 //separating integer part IP=floor(sum1) IP1=IP //separating decimal part DP=modulo(sum1,1) //storing each integer digit in I(i) while(IP>0) I(i)=(modulo(floor(IP),2)) IP=floor(IP)/2 i=i+1 end if(IP1>0) IP=0 for j=1:length(I) //multipliying bits of integer part with their position values and adding IP=IP+(I(j)*10^(j-1)); end else IP=0 end //storing each decimal digit in D(x) while(x<=4) DP=DP*2 D(x)=floor(DP) x=x+1 DP=modulo(DP,1) end DP=0 for j=1:length(D) //multipliying bits of decimal part with their position values and adding DP=DP+(10^(-1*j)*D(j)) end Binary=IP+DP; printf("Sum") disp(Binary)

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clear clf b = 0.1; d = 0.05 ; r = b - d; xj(1) = 1; h = 1 / 30; ndate_j = 0:h:20; for n = 1:length(ndate_j) - 1 xj(n+1) = (1 + r * h) * xj(n); end //plot2d(ndate_j, xj, style = 3); xh(1) = 1; // Condition initiale du modèle en jours h = 1 / (30 * 24); // Le pas de temps est l'heure ndate_h = 0:h:20; // vecteur des dates for n = 1:length(ndate_h) - 1 xh(n+1) = (1 + r * h) * xh(n); end plot2d(ndate_h, xh, style = 4) b = 0.1; d = 0.05 ; x(1) = 1; r = b - d; h = 1; ndate = 0:20 for n = 1:20 x(n+1) = (1 + r ) * x(n); end plot2d(ndate, x, style = 2, rect=[0,0,20, 3])

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// Scilab code Ex3.10: Pg 90-91 (2008) clc; clear; C_1 = 6e-06; //Capacitance, F C_2 = 4e-06; //Capacitance, F V = 150; // Supply voltage, V // Part (a) // The reciprocal of the resulting capacitance of capacitors connected in series is the sum of the reciprocal of the individual capacitances present in the circuit i.e 1/C = 1/C1 + 1/C2, solving for C C = ( C_1*C_2 )/(C_1 + C_2); // Resulting capacitance, F // Part (b) Q = V*C; // Electric charge on the capacitors, C // Part (c) V_1 = Q/C_1; // P.d across capacitor C_1, V V_2 = Q/C_2; // P.d across capacitor C_2, V printf("\nThe total capacitance of the combination = %3.1f micro-farad", C/1e-06); printf("\nThe charge on each capacitor = %3d micro-coulomb",Q/1e-06); printf("\nThe p.d. developed across %1d micro-farad capacitor = %2d V", C_1/1e-06, V_1); printf("\nThe p.d. developed across %1d micro-farad capacitor = %2d V", C_2/1e-06, V_2); // Result // The total capacitance of the combination = 2.4 micro-farad // The charge on each capacitor = 360 micro-coulomb // The p.d. developed across 6 micro-farad capacitor = 60 V // The p.d. developed across 4 micro-farad capacitor = 90 V

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Ex1_7.sce

//Chapter 1 : Wave Optics clear; //Variable declaration lamda=5890*10**-10 //wavelength myu=1.33 //refractive index of glass n=1 //first minimum r=45 //angle in degrees cos_r=0.707 //Calculations t=(n*lamda)/(2*myu*cos_r)/10**-7 //Result mprintf("Thickness of the film t= %.3f*10**-4 mm",t)

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Exa3_12.sce

//Exa 3.12 clc; clear; close; //Given data : l=6;//in Km n1=1.5;//unitless delta=1//in % c=3*10^8;//speed of light in m/s //Part (a) deltaT=l*10^3*n1*(delta/100)/c;//in sec deltaT=deltaT*10^9;//in ns disp(deltaT,"Delay difference between the slowest and fastest modes at output in ns : "); //Part (b) B=1/(2*deltaT*10^-9);//in bps B=B*10^-6;//in Mbps disp(B,"Assuming no intersymbol interference, maximum bit rate in Mbps : ");

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//problem 4 pagenumber 2.87 //given format(6); r1=10e3;//ohm rf1=20e3;//ohm r2=5e3;//ohm //determine gain of amplifier a1=1+rf1/r1; a2=-rf1/r1; disp( 'Switch off gain = '+string(a1+a2));//no unit disp( 'Switch on gain = '+string(a2));//no unit

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//Exa2.1 clc; clear; close; //given data : J=2.4; //in A/mm^2 J=2.4*10^6; //in A/m^2 n=5*10^28; //unitless e=1.6*10^-19; // in coulomb //Formula : J=e*n*v v=J/(e*n);//in m/s disp("Drift velocity is : "+string(v)+" m/s or "+string(v*10^3)+" mm/s")

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// Scilab code Ex17.13 : Pg:895 (2011) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV R_max = 0.75; // Radius of two dees of the cyclotron, m f = 15e+06; // Frequency of alternating potential, Hz m = 1.67e-027; // Mass of the proton, kg // As E = 1/2*q^2*R_max^2*B^2/(m*e) and f = q*B/(2*%pi*m), solving for E E = 2*%pi^2*m*f^2*R_max^2/(e*1e+06); disp(E) printf("\nEnergy of the protons issuing out of the cyclotron = %6.4f MeV", E); // Result // Energy of the protons issuing out of the cyclotron = 26.0754 MeV

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function [vecs,lambdas] = Deflation(A,nbr_val_propre) // Output variables initialisation (not found in input variables) vecs=[]; lambdas=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); k = 30; // ! L.4: real(nbr_val_propre) may be replaced by: // ! --> nbr_val_propre if nbr_val_propre is Real. vecs = cell(real(nbr_val_propre),1); lambdas = zeros(nbr_val_propre,1); for i = mtlb_imp(1,nbr_val_propre) [v,lambda_v] = PuissancesIterees(A,k); [u,truc] = PuissancesIterees(mtlb_t(A),k); A = mtlb_s(A,(lambda_v*(v*u'))/(u'*v)); lambdas = mtlb_i(lambdas,i,lambda_v); vecs(i).entries = v; end; endfunction

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function [y]=f (a, b) y=a + b; endfunction a=10; b=5 c=f (a, b)

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//Ex 2.11.3 clc;clear;close; format('v',8); //Given : Io1=2;//nA T1=10+273;//K V=0.4;//volt VT1=T1/11600;//V m=1.5;//for Si Eta=2;//for Si VGO=-1.21;//volt K=Io1*10^-9/T1^m/exp(VGO/Eta/VT1);//constant I1=Io1*10^-9*[exp(V/Eta/VT1)-1];//nA T2=70+273;//K VT2=T2/11600;//V Io2=K*T2^m*[exp(VGO/Eta/VT2)];//A I2=Io2*[exp(V/Eta/VT2)-1];//nA change=(I2-I1)/I1*100;//% disp(change,"% change in diode current : "); //Answer is wrong in the textbook.

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//Illustration of Central Difference Formula close(); clear; clc; xi = 0:0.2:1.2; fi = sin(xi); x0 = 0; h = 0.2; format('v',8); // First order difference delta1_fi = diff(fi); // Second order difference delta2_fi = diff(delta1_fi); // Third order difference delta3_fi = diff(delta2_fi); // Fourth order difference delta4_fi = diff(delta3_fi); //Fifth order difference delta5_fi = diff(delta4_fi); //Sixth order difference delta6_fi = diff(delta5_fi); disp(fi , 'Values of f(x) : ') disp(delta1_fi , 'First Order Difference :') disp(delta2_fi , 'Second Order Difference :') disp(delta3_fi , 'Third Order Difference :') disp(delta4_fi , 'Fourth Order Difference :') disp(delta5_fi , 'Fifth Order Difference :') disp(delta6_fi , 'Sixth Order Difference :') //Calculating p2(0.67) xm = 0.6; x = 0.67; s = (x-xm)/0.2; p2 = fi(4) + {s*(delta1_fi(3)+delta1_fi(4))/2} + s*s*(delta2_fi(3))/2; disp(p2 , 'Value of p2(0.67) : '); //Calculating p4(0.67) p4 = p2 + s*(s*s-1)*(delta3_fi(3)+delta3_fi(2))/12 + s*s*(s*s-1)*delta4_fi(2)/24; disp(p4 , 'Value of p4(0.67) : '); //Exact value of sin(0.67) is 0.62099 so error in estimation err = 0.62099-0.62098; disp(err , 'Error in estimation : ');

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clc //Given that c = 3e8 // speed of light in m/s v = 0.5 * c // speed of particle in m/s // sample problem 7 page No. 223 printf("\n \n\n # Problem 7 # \n") printf("\n Standard formula used \n m = m_o/sqrt ( 1- (v/c)^2)") ratio = sqrt(1- (v /c)^2) // calculation of Ratio of rest mass and relativistic mass of particle printf ("\n Ratio of rest mass and relativistic mass of particle is %f.", ratio)

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//FICHIER_DE_TEST ADD NAME=DISPLAY.TST,SSI=0 // z=poly(0,'z') //lines(20,60) format('v',10) num=[ (((((1)*z-2.6533333)*z+2.6887936)*z-1.2916784)*z+0.2911572)*... z-0.0243497 (((((1)*z-2.6533333)*z+2.6887936)*z-1.2916784)*z+0.2911572)*... z-0.0243497 (((1)*z )*z )*z+1 0] den = [ ((((1)*z-1.536926)*z+0.8067352)*z-0.1682810)*z+0.0113508 ((((1)*z-1.536926)*z+0.8067352)*z-0.1682810)*z+0.0113508 ((1)*z )*z 1] num',den' [num;den] [num den] r=num./den r' // digits='abcdefghijklmnopqrstuvwxyz' numbers='1234567890' majuscules='ABCDEFGHIJKLMNOPQRSTUVWXYZ' symbols=',./;''[] \ =-!\$%^&*()_+~:""[]| @' [numbers;digits] [numbers digits;digits numbers] [numbers digits+digits+digits] ans'; [ans ans]

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////Example 18.17. clc format(6) vi=15+3 // in V disp("Refer to fig.18.24. We know that") disp(vi," Vi_min(V) = Vo + 3V =") vi=18+1 // in V disp("Assuming the ripple voltage Vr = 2V(max), the input voltage is") disp(vi," Vi(V) = Vi(min) + Vr/2 =") vz=19/2 // in V disp(vz,"Then Vz(V) = Vi /2 = (use the zener diode 1N758 for 10V)") disp("Therefore, Vz = 10 V") disp(" Iz = 20 mA") r1=(19-10)/(20*10^-3) // in ohm disp(r1," R1(ohm) = Vi-Vz / Iz =") disp("Let I2 = IB(max) = 50 uA") r2=((15-10)/(50*10^-6))*10^-3 // in k-ohm disp(r2," R2(k-ohm) = Vo-Vz / I2 =") r3=(10/(50*10^-6))*10^-3 // in k-ohm disp(r3," R3(k-ohm) = Vz / I2 =") disp("Select C1 = 50 uF") disp("Specification of transistor Q1") vce=19+1 // in V disp(vce," VCE_max(V) = Vi_max(V) = Vi + Vr/2 =") disp(" IE = IL = 50 mA") p=((19-15)*50) // in mW disp(p," P(mW) = VCE*IL = (Vi-Vo) * IL =") disp("Use the transistor 2N718 for Q1")

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errcatch(-1,"stop");mode(2);//Caption:Find (a)induced emf at full load (b)power developed (c)torque developed (d)applied torque (e)efficiency (f)external resistance in feild winding (g)voltage regulation //Exa:5.5 ; ; N_m=600;//speed of rotor (in rpm) R_a=0.01;//armature resistance (in ohms) R_fw=30;//feild winding resistance(in ohms) V_f=120;// voltage of external source (in volts) N_f=500;//no. of turns per pole P_r=10000;//in watts V_t=240;//terminal voltage (in volts) P_o=240*10^3;//rated power (in watts) I_L=P_o/V_t;//load current I_a=I_L;//armature current E_afl=V_t+(I_a*R_a);//refer to eqn:5.27 disp(E_afl,'(a) induced emf at full load (in Volts)='); P_d=E_afl*I_a; disp(P_d,'(b) power developed (in watts)='); W_m=(2*%pi*N_m)/60;//angular velocity (Refer to Eqn:5.5&5.6) T_d=P_d/W_m; disp(T_d,'(c) torque developed (in Newton-meter)='); P_inm=P_d+P_r;//mechanical power input T_s=P_inm/W_m; disp(T_s,'(d) Applied torque (in Newton-meter)='); //Refer fig:5.21 (magnetization curve) I_f=2.5;//effective feild current mmf=(2.5*N_f)+(0.25*I_a);//total mmf I_fa=mmf/N_f;//actual feild current P_in=P_inm+(V_f*I_fa);//total power input Eff=(P_o/P_in)*100; disp(Eff,'(e) efficiency (%)='); R_f=V_f/I_fa; R_fx=R_f-R_fw; disp(R_fx,'(f) external resistance in feild winding (in ohms)='); VR=((266-V_t)/V_t)*100;//Refer to fig:5.21 disp(VR,'(g) voltage regulation (%)='); exit();

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clear; clc; // Illustration 8.1 // Page: 479 printf('Illustration 8.1 - Page: 479\n\n'); // solution // ****Data****// P_total = 1; // [bar] T1 = 320; // [K] T_c = 562.2; // [K] P_c = 48.9; // [bar] A = -6.983; B = 1.332; C = -2.629; D = -3.333; //*****// x1 = 1-(T1/T_c); deff('[y] = f12(P1)','y = log(P1/P_c)-(A*x1+B*x1^1.5+C*x1^3+D*x1^6)/(1-x1)'); P1 = fsolve(.01,f12);// [bar] printf("Vapor pressure of benzene at 320 K is %f bar\n\n",P1); M_benzene = 78 // [gram/mole] printf('Illustration 8.1 (a)\n'); // Solution (a) // For nitrogen M_nitrogen = 28; // [gram/mole] // From equation 8.2 Y = P1/(P_total - P1); //[mole C6H6/ mole N2] Y_s1 = Y*(M_benzene/M_nitrogen); // [gram C6H6/gram N2] printf("Absolute humidity of mixture of benzene and nitrogen is %f gram C6H6/gram N2\n\n",Y_s1); printf('Illustration 8.1 (b)\n'); // Solution (b) // For carbon dioxide M_carbondioxide = 44; // [gram/mole] // From equation 8.2 Y = P1/(P_total - P1); //[mole C6H6/ mole C02] Y_s2 = Y*(M_benzene/M_carbondioxide); // [gram C6H6/gram CO2] printf("Absolute humidity of mixture of benzene and carbon dioxide is %f gram C6H6/gram CO2\n",Y_s2);

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15_1.sce

clear clc //Example 15.1 disp('Example 15.1') s=%s; Gp1=4/((4*s+1)*(2*s+1));Gp2=1;Gd2=1;Gd1=1/(3*s+1); Gm1=0.05;Gm2=0.2; Gv=5/(s+1); Kc2=4; Ys=Kc2*Gv*Gp1*Gm1/(1+Kc2*Gv*Gm2); Routh=routh_t(Ys,poly(0,"Kc1")); // produces routh table for polynomial 1+Kc*Ys disp(Routh) K1=roots(numer(Routh(3,1))); K2=roots(numer(Routh(4,1))); mprintf('\n Kc1 lies between %f and %f \n for cascade system to be stable', K2,K1) Ys2=Gv*Gp2*Gp1*Gm1; Routh2=routh_t(Ys2,poly(0,"Kc1")); // produces routh table for polynomial 1+Kc*Ys disp(Routh2) K1_2=roots(numer(Routh2(3,1))); K2_2=roots(numer(Routh2(4,1))); mprintf('\n Kc1 lies between %f and %f \n for conventional system to be stable', K2_2,K1_2) //We cannot find offset symbolically in Scilab because scilab does not support //handling of two variables in single polynomial //To find this limit one can use Sage //However in this case the calculations can be done in a very easy way by hand //and hence do not require to be computed from Sage

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exa7_5.sce

clc; //Example 7.5 //Page No 260 //Solution df=75; fm=15; //(a) disp("(a)The deviation ratio is found by substituting into equation 7-35(refer pgno), "); DR=df/fm; disp(DR,"DR = "); disp("From Table 7.3"); B=2*(8*fm); disp('kHz',B,"B = "); //(b) disp("(b)For an 37.5kHz frequency deviation and modulating signal frequency fm=7.5, the modulation index is, "); m=37.5/7.5; disp(m,"m = "); disp("and the bandwidth is, "); b=2*(8*7.5); disp('kHz',b,"B = ");

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MeshLib.sce

// Library adapted from : http://www.morere.eu/spip.php?article142 // Requires the use of the lib3ds library // The sub mesh is here: /home/jem/reliable-slam/workspace/Analysis/Plots/General/submarine.sce function [X,Y,Z]=loadSCEMesh(fileName) exec(fileName); facelist1 = facelist1 + 1; X = matrix(vertices1(facelist1,1),size(facelist1,1),length(vertices1(facelist1,1))/size(facelist1,1))'; Y = matrix(vertices1(facelist1,2),size(facelist1,1),length(vertices1(facelist1,1))/size(facelist1,1))'; Z = matrix(vertices1(facelist1,3),size(facelist1,1),length(vertices1(facelist1,1))/size(facelist1,1))'; endfunction function meshHandle=plotMesh(fileName) [X,Y,Z]=loadSCEMesh(fileName); meshHandle=plot3d(X,Y,Z); endfunction function [X,Y,Z]=transformMesh(X,Y,Z,rotation,translation) endfunction function updateMesh(meshHandle,X,Y,Z) endfunction

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Ch01Ex14.sce

// Scilab code Ex1.14: Pg:43 (2008) clc;clear; d = 2.82e-008; // Interplanar spacing in sodium chloride crystal, cm n = 1; // Order of reflection theta = 10; // Glancing angle, degree // Since 2*d*sin theta = n*Lambda, solving for Lambda Lambda = 2*d*sind(theta); // Wavelength of X-rays in Bragg's reflection, cm printf("\nThe wavelength of X-rays in Bragg reflection = %4.2f angstrom", Lambda/1e-008); // Result // The wavelength of X-rays in Bragg reflection = 0.98 angstrom

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Ex12_3.sce

//Part B Chapter 4 Example 3 clc; clear; close; n=12;//bolts PCD=300;//mm D=50;//mm Ddash=90;//mm tau_s=60;//MN/m^2 T=tau_s*10^6*%pi*(D/1000)^4/(D/2*10^-3*32);//Nm R=Ddash/2;//mm d=(Ddash^4-T*1000*R*32/60/%pi)^(1/4);//mm disp("Internal diameter of hollow shaft is "+string(d)+" mm"); Tb=T/n;//Nm per bolt PCrad=150;///mm Fb=Tb/(PCrad/1000);//N(Force on bolt) tau_sb=20;//MN/m^2 Ab=Fb/tau_sb/10^6;//m^2(Area of bolt) db=sqrt(Ab/(%pi/4));//m disp("Bolt diameter is "+string(db*1000)+" mm");

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// Scilab code: Ex4.3: Energy of electrons through the potential barrier : Pg : 125 (2008) h_bar = 1.054e-34; // Reduced Planck's constant, J-s Vo = 8e-019; // Height of potential barrier, joules m = 9.1e-031; // Mass of an electron, kg a = 5e-010; // Width of potential barrier, m T = 1/2; // Transmission coefficient of electrons // As T = 1/((1 + m*Vo^2*a^2)/2*E*h^2), solving for E we have E = m*Vo^2*a^2/(2*(1/T-1)*h_bar^2*1.6e-019); // Energy of half of the electrons through the potential barrier, eV printf("\nThe energy of electrons through the potential barrier = %5.2f eV", E); // Result // The energy of electrons through the potential barrier = 40.96 eV

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Ex11_27.sce

//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.27\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.27 (page no. 605) // Solution //HEAT EXCHANGER //Oil flows in the tube side and is cooled from 280 F to 140 F //Therefore, t2=140; //Unit:fahrenheit t1=280; //Unit:fahrenheit //On the shell side,water is heated from 85 F to 115 F T1=85; //Unit:fahrenheit T2=115; //Unit:fahrenheit P=(t2-t1)/(T1-t1); R=(T1-T2)/(t2-t1); //From the figure, F=0.91;//Correction factor LMTD=((t1-T2)-(t2-T1))/log((t1-T2)/(t2-T1)); //LMTD=Log mean temperature difference //Unit:fahrenheit TMTD=F*LMTD; //TMTD=True mean temperature difference //Unit:fahrenheit printf("The true mean temperature is %f fahrenheit",TMTD);

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clear;lines(0); [m,n]=mini([1,3,1]) [m,n]=mini([3,1,1],[1,3,1],[1,1,3]) [m,n]=mini(list([3,1,1],[1,3,1],[1,1,3])) [m,n]=mini(list(1,3,1))

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load FPM.hdl, output-file FPM.out, compare-to FPM.cmp, output-list x%B1.16.1 y%B1.16.1 z%B1.16.1 isoverflow%B5.1.4; //test case for same sign //first the sign is same and positive set x %B0100000000100000, //2.5 set y %B0100000010100000, //5 eval, output; //second the sign is same and negative set x %B1011111111000000, //-1.5 set y %B1100000000000000, //-2 eval, output; //test case for opposite sign //first, x is negative and y is positive set x %B1011111100000000, //-0.5 set y %B0011111111000000, //1.5 eval, output; //second, y is negative and x is positive set x %B0011111111000000, //1.5 set y %B1100000000000000, //-2 eval, output; //test case, where the product of mantissa is over 2 set x %B0011111111000000, //1.5 set y %B0011111111100000, //1.75 eval, output; //test case, where the product of mantissa is between 1 and 2 set x %B0011111110100000, //1.25 set y %B0011111111000000, //1.5 eval, output;

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//clc(); clear; //To calculate numerical aperture theta0=26.80; //acceptance angle in degrees NA=sind(theta0); printf("numerical aperture is %f",NA);

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7_6_Plastic_Film.sce

clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 7.6 Page 434 \n'); //Example 7.6 // Time required to cool from Ti = 75 degC to 35 degC //Operating Conditions v = 10; //[m/s] Air velocity Tsurr = 23+273; //[K] Surrounding Air Temperature D = .01; //[m] Diameter of sphere Ti = 75+273; //[K] Initial temp Tt = 35+273; //[K] Temperature after time t p = 1; //[atm] //Table A.1 Copper at T = 328K rho = 8933; //[kg/m^3] Density k = 399; //[W/m.K] Conductivity cp = 388; //[J/kg.K] specific //Table A.4 Air Properties T = 296 K u = 182.6*10^-7; //[N.s/m^2] Viscosity uv = 15.53*10^-6; //[m^2/s] Kinematic Viscosity k = 25.1*10^-3; //[W/m.K] Thermal conductivity Pr = .708; //Prandtl Number //Table A.4 Air Properties T = 328 K u2 = 197.8*10^-7; //[N.s/m^2] Viscosity Re = v*D/uv; //Reynolds number //Using Equation 7.56 Nu = 2+(0.4*Re^.5 + 0.06*Re^.668)*Pr^.4*(u/u2)^.25; h = Nu*k/D; //From equation 5.4 and 5.5 t = rho*cp*D*2.30*log10((Ti-Tsurr)/(Tt-Tsurr))/(6*h); printf("\nTime required for cooling is %.1f sec",t); //END

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4_19.sce

clc,clear printf('Example 4.19\n\n') Pole=4 f=50 //frequency phi=0.12 //flux per pole in weber m=4 // slot per pole per phase conductor_per_slot=4 coilspan=150 Ns=120*f/Pole //synchronous speed in rpm n=m*3 //Slots per pole beeta=180/n //slot angle K_d=sind(m*beeta/2) /(m*sind(beeta/2)) // distribution factor alpha=180-coilspan //angle of short pitch K_c=cos((%pi/180)*alpha/2) //coil span factor Z=m*(n*Pole) // Also equal to (conductors/slots)*slots Z_ph=Z/3 //conductors per phase T_ph=Z_ph/2 //turns per phase E_ph=4.44*K_c*K_d*phi*f*T_ph E_line=sqrt(3)*E_ph printf('e.m.f generated is %.2f V(phase),%.2f V(line)',E_ph,E_line)

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/1388/CH1/EX1.10/1_10.sce

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no_license

FOSSEE/Scilab-TBC-Uploads

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refs/heads/master

2020-04-09T02:43:26.499817

2018-02-03T05:31:52

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sce

1_10.sce

clc //initialisation of variables M= 28 //gm R= 8.314*10^7 //atm l/mol K N= 6.023*10^23 T= 300 //K s= 4*10^-8//cm //CALCULATIONS m= M/N k= R/N n= (5/16)*sqrt(%pi*m*k*T)/(%pi*s^2) //RESULTS printf (' viscosity = %.2e poise',n)

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/1991/CH7/EX7.5/5.sce

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FOSSEE/Scilab-TBC-Uploads

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2020-04-09T02:43:26.499817

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5.sce

clc clear //input r1=40//resistance 1 r2=20//resistamce 2 r3=10//resistance 3 v=1.6//voltage //calculation R=r1+r2+r3//total resistance in series x=((v*r1)*70)/((2*50)*(1.6*40))//fraction of pd x=x*100//percentage pd //output printf("the percentage of pd is %3.0f percent",x)

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/278/CH16/EX16.3/ex_16_3.sce

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FOSSEE/Scilab-TBC-Uploads

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2020-04-09T02:43:26.499817

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ex_16_3.sce

//cal dia of piston clc //soltuion //given D=1500//mm p=0.2//N/mm^2 E=200*1000//N/mm^2 l=3000//mm W=(%pi/4)*D^2*p//N Fs=8 Wcr=W*Fs//N L=l/2; d=(Wcr/0.043)^(1/4)//mm; //let d be dia and I be moment of inertia I=(%pi/64)*d^4 //acc to euler's formula //Wcr=%pi^2*E*I/L^2//N //Wcr=0.043*d^4 //acc to rankine's formula //Wcr=(fc*A)/(1+a*(L/k)^2) fc=320//N/mm^2 a=1/7500 //k=sqrt(I/A)=d/4 //Wcr=(251.4*d1^2)/(d1^2 +4800) //on solving d2=14885 d1=sqrt(14885)//mm //taking large rof two values printf("the dia od piston is,%f\n",d1)

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/src/etc/McpActivate.tst

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LivTel/sdb_puller

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2019-12-18T19:10:47

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McpActivate.tst

sysreq, SYSREQ_REQ_ACTIVATE

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/2912/CH7/EX7.8/Ex7_8.sce

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FOSSEE/Scilab-TBC-Uploads

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Ex7_8.sce

//chapter 7 //example 7.8 //Calculate the atomic polarisability of sulphur //page 190 clear; clc; //given Er=4; // relative permittivity of sulphur Eo=8.85E-12; // in F/m (absolute permittivity) NA=2.08E3; // in Kg/m^3 (density of atoms in sulphur) //calculate // Since ((Er-1)/(Er+2))*(M_A/p)=(N/(3*Eo))*alpha_e // therefore we have alpha_e=((Er-1)/(Er+2))*(3*Eo/NA); // calculation of electronic polarisability of sulphur printf('\nThe electronic polarisability of sulphur is \t=%1.2E Fm^2',alpha_e); // NOTE: The answer in the book is wrong due to calculation mistake. Also one point to be mentioned is that wrong formula has been used in the solution but i have used the formula as used in the solution.

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/Toolbox Test/taylorwin/taylorwin4.sce

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deecube/fosseetesting

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2021-01-20T11:34:43.535019

2016-09-27T05:12:48

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taylorwin4.sce

//check o/p for negative window length w = taylorwin(-6); disp(w); ////output //!--error 10000 //The window length must be a positive integer //at line 35 of function taylorwin called by : //w = taylorwin(-6);

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/623/CH21/EX4.4.3/U4_C4_3.sce

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sce

U4_C4_3.sce

//variable initialization mu=9.27*10^-24; //(J/T) B=1*10^-1; //external magnetic field (T) h=1.054*10^-34; //Plank's constant (Js) J=3/2; L=1; S=1/2; //calculation g=1+(((J*(J+1))+(S*(S+1))-(L*(L+1)))/(2*J*(J+1))); //Lande g-factor omega=(g*mu*B)/h; //angular velocity of precession (rad/s) printf("\nω = %.1e rad/sec",omega);

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/SPEECH BASED BALL COLLECTOR_2011/code/final.sce

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sachinuthale/CS684_2011

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2020-05-29T21:51:13.096232

2014-05-23T23:41:26

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final.sce

//function to detect object and return the co-ordinates of the object in the 1st frame it is detected in the vector rectrec //parameters //colour=colour of object to find; notfound=signal to be sent till object is not found; found=signal to be sent when object is found; objct=ball or basket function rectret=findobject(colour,notfound,found,objct) obj_found=0; rect=[0,0,0,0]; //vid=camopen(); fr=avireadframe(vid); while ~isempty(fr) str=notfound; writeserial(handle,str+ascii(13)) //write to serial port that object is not found //sleep(3000); if colour=='red' set_val=1; elseif colour=='green' set_val=2; else set_val=3; end; if colour=='blue' //colour intensity threshold for colour detection cthresh=0.1; elseif colour=='red' cthresh=0.2; else cthresh=0.05; end; count=0; maxm=0; reg=0; objx=zeros(info.Height); objy=zeros(info.Height); objcount=0; diff_im = imabsdiff(fr(:,:,set_val),rgb2gray(fr)); //subtract colour component from the image diff_im = im2bw(diff_im,cthresh); //convert image to binary mat=diff_im; flag1=0; xS=190; //search for the object in the range [190-350] x co-ordinates with 10 pixels gap xE=350; //i.e search the object only when it appears in the center of the screen yS=1; yE=info.Height; if objct=='box' xS=230; xE=400; end; xS xE if ~obj_found, totcount=0; //seedfill algorith, to identify object cluster with size greater han 1000 pixels....seach co-ordinates in x-range defined with 10 pixels gap //as the object size is large we do not need to search each and every pixel for i=xS:10:xE, if flag1==1 break; end; for j=yS:50:yE, if flag1==1 break; end; //disp(i);disp(j); if mat(i,j)==%t count=0; objcount=0; savex=zeros(info.Height); savey=zeros(info.Height); reg=reg+1; totcount=0; count=count+1; stakx(count)=i; staky(count)=j; while count>0, mat(stakx(count),staky(count))=%f; objcount=objcount+1; savex(objcount)=stakx(count); savey(objcount)=staky(count); m=stakx(count); n=staky(count); count=count-1; totcount=totcount+1; if totcount > 1000 //object size flag1=1; objx=savex; objy=savey; obj_found=1; disp('obj found'); break; end; if (m-1)>0 & mat(m-1,m)==%t count=count+1; stakx(count)=m-1; staky(count)=n; end; if (n+1)<info.Width & mat(m,n+1)==%t count=count+1; stakx(count)=m; staky(count)=n+1; end; if (n-1)>0 & mat(m,n-1)==%t count=count+1; stakx(count)=m; staky(count)=n-1; end; if (m+1)<info.Height & mat(m+1,n)==%t count=count+1; stakx(count)=m+1; staky(count)=n; end; if (m-1)>0 & (n-1)>0 & mat(m-1,n-1)==%t count=count+1; stakx(count)=m-1; staky(count)=n-1; end; if (m+1)<info.Height & (n+1)<info.Width & mat(m+1,n+1)==%t count=count+1; stakx(count)=m+1; staky(count)=n+1; end; if (m-1)>0 & (n+1)<info.Width & mat(m-1,n+1)==%t count=count+1; stakx(count)=m-1; staky(count)=n+1; end; if (n-1)>0 & mat(m+1,n-1)==%t count=count+1; stakx(count)=m+1; staky(count)=n-1; end; end; end; if totcount>maxm maxm=totcount; objx=savex; objy=savey; end; end; end; //maxm if maxm > 1000 //object size minRow=min(objx); maxRow=max(objx); minCol=min(objy); maxCol=max(objy); if maxRow>info.Height maxRow=info.Height; end; if maxCol>info.Width maxCol=info.Width; end; rect=[minCol,minRow,maxCol-minCol,maxRow-minRow]; newObj=rectangle(fr,rect,[255,0,0]); else newObj=fr; end; //end condition for drawing rectangle end; // end if for obj found imshow(newObj); if obj_found==1 //object is found here..guide the bot to reach it break; end; fr=avireadframe(vid); end; //end for loop for reading frames rectret=rect; //return co-ordinates of the rectange where object is first spotted in the frame endfunction //use camshift function in scilab to trace the object in each frame //parameters same as above function; additional parameter : action="pick" or "drop" the object when it is reached function traceobject(colour,notfound,found,action,objct) rect=findobject(colour,notfound,found,objct) fr=avireadframe(vid); centrex=info.Width/2; centrey=info.Height/2; //avicloseframe(vid); obj_win = camshift(fr, rect); //initialize tracker while ~isempty(fr), obj_win = camshift(fr); //camshift tracking disp('obj window'); //obj_win im = rectangle(fr, obj_win, [255,0,0]); imshow(im); cx=obj_win(1)+obj_win(3)/2; cy=obj_win(2)+obj_win(4)/2; //identify approaximate centre of object cluster in the rectangle val=abs(cx-centrex); //val - distance between centre of frame and centre of object disp(val); if val < 270 //if the distance between centres is less than some threshold object is at centre of screen disp('move forward'); str=found; disp('data sent'); //send signal to firebird that object is found disp(str+ascii(13)); buf='0' //buf=readserial(handle); //read ack from firebird whether it received the signal or else send it again till ack-ed v=str+ascii(13); while(buf ~= v & buf~=action) disp(buf); sleep(500); writeserial(handle,str+ascii(13)) sleep(500); buf=readserial(handle) if (buf=='5') return; end; end disp('data received'); disp(buf); if buf==action //after ack-ing the signal sent by scilab the firebird sends another signal, which indicates ball has been picked or dropped in the basket return //the program returns after recieving the signal end; buf='0' buf=readserial(handle); while(buf ~= action) sleep(500); buf=readserial(handle); end disp('data received'); disp(buf); return else str=notfound; //the object is not found yet...keep on sending this signal to the firebird disp('data sent'); disp(str+ascii(13)); writeserial(handle,str+ascii(13)) //sleep(3000); end; fr = avireadframe(vid); end; endfunction function main(objc) //parameters for frame dimension info.Height=500; info.Width=700; handle=openserial(6,"9600,n,8,1") //open the serial communication interface with port_no=6 vid=camopen(); //open the camera str='1'; disp('data sent'); disp(str+ascii(13)); //send 2 dummy signals to firebird to initiate it before picking ball writeserial(handle,str+ascii(13)) str='1'; disp('data sent'); disp(str+ascii(13)); writeserial(handle,str+ascii(13)) traceobject(objc,'1','2','3','ball'); //trace ball disp('ball picked up'); obj_found=0; fr=0; str='4'; disp('data sent'); disp(str+ascii(13)); writeserial(handle,str+ascii(13)) //send 2 dummy signals to firebird to initiate it before dropping ball str='4'; vid=camopen(); //refresh the frames and re-initiate camera disp('data sent'); disp(str+ascii(13)); writeserial(handle,str+ascii(13)) traceobject('green','4','5','6','box'); //trace basket closeserial(handle); endfunction //end main function filename = "C:\Users\int\workspace\speechrecg\color.txt"; // read from this file which colour of ball to pick. basket colour by default is green //the speech processing module writes to the above file indicating colour of ball to be picked fid = mopen(filename, "r"); if (fid == -1) error("cannot open file for reading"); end; [num_read, val(1)] = mfscanf(fid, "%s"); mclose(fid); col=val(1); disp(col); main(col); // call main function with ball colour

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/Raporty/HMF/i_eMapy_ERP.sci

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Renrim/map

e089700fb890b72e57300c5a1f7dd5d3d8ccea96

ad052c49ad0eb6365835f369c81095b58e86124f

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2021-08-07T12:50:09.423854

2017-11-08T06:48:34

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sci

i_eMapy_ERP.sci

//"i_eMapy_ERP.sci","eMapy - include","\Procedury\Raporty z menu kartotek\",0,1.1.0,SYSTEM ////////////////////////////////////////////////////////////////////// // Nazwa : eMapy // Firma : // Autor : /////////////////////////////////////////// string szSciezka_exp = MojeDokumenty()+"\\kh.xml" string sApp_exe = "eMapy.exe" limit 1000000 int plik_exp long Listaidkh(1) int sub GetIdKH () long nErr = SetTaggedPos(FS) int i, znal while nErr if Listaidkh(size(Listaidkh)) != 0 then grow Listaidkh, 1 znal = 0 for i = 1 to i > size(Listaidkh) || znal if Listaidkh(i) == GetLineId() then znal = 1 next i if !znal then Listaidkh(size(Listaidkh)) = GetLineId() endif nErr = SetTaggedPos(NX) wend GetIdKH=1 endsub int sub DodajWezel( int idkh, string kodkh, string nazwakh, string ulica, string miasto, string kodpoczt, string poczta, string lokal, string dom, string wojewodztwo, string kraj, string rodzaj, string katalogkh, string znacznik, string skrotZN,string rodzajADR) string adres=using "%s %s",ulica,dom if (lokal!="") then adres += using "//%s",lokal endif adres+=using ", %s %s",kodpoczt,miasto if wojewodztwo!="" then adres+= using ", %s",wojewodztwo endif adres+= using ", %s",kraj print#plik_exp; using "<SchowekKH>\n" print#plik_exp; using "<Id>%i</Id>\n",idkh print#plik_exp; using "<Szerokosc>0</Szerokosc>\n" print#plik_exp; using "<Dlugosc>0</Dlugosc>\n" print#plik_exp; using "<Kod><![CDATA[%s]]></Kod>\n",kodkh print#plik_exp; using "<Nazwa><![CDATA[%s]]></Nazwa>\n",nazwakh print#plik_exp; using "<Adress><![CDATA[%s]]></Adress>\n",adres print#plik_exp; using "<Rodzaj><![CDATA[%s]]></Rodzaj>\n",rodzaj print#plik_exp; using "<RodzajAdresu><![CDATA[%s]]></RodzajAdresu>\n",rodzajADR print#plik_exp; using "<Katalog><![CDATA[%s]]></Katalog>\n",katalogkh print#plik_exp; using "<Znacznik><![CDATA[%s]]></Znacznik>\n",znacznik print#plik_exp; using "<ZnacznikShortCut><![CDATA[%s]]></ZnacznikShortCut>\n",skrotZN print#plik_exp; using "<Ulica><![CDATA[%s]]></Ulica>\n",ulica print#plik_exp; using "<KodPocztowy><![CDATA[%s]]></KodPocztowy>\n",kodpoczt print#plik_exp; using "<Miasto><![CDATA[%s]]></Miasto>\n",miasto print#plik_exp; using "<Kraj><![CDATA[%s]]></Kraj>\n",kraj print#plik_exp; using "</SchowekKH>\n" endsub Int Sub OtworzPlik(string nazwa_plk_, string i_o, int czy_komunikaty) int plik_imp if i_o == "odczyt" then plik_imp = open nazwa_plk_ for Input else plik_imp = open nazwa_plk_ for Output endif if plik_imp<=0 then if czy_komunikaty then message (using "Wystąpił błąd przy próbie otwarcia pliku %s Ico:S",nazwa_plk_ ) : error "" endif OtworzPlik = plik_imp EndSub int sub infoErrorExecute(int iErr, string sApp, string sLokalizacja) select case iErr case 3 message using "Nie istnieje wskazany katalog : %s ico:S",sLokalizacja case 2 message using "Nie istnieje wskazany plik : '%s' \n %s ico:S", sApp, sLokalizacja case 1 message using "Wskazany plik jest uszkodzony : '%s' \n %s ico:S", sApp, sLokalizacja case 0 message "Brak zasobów do uruchomienia programu! ico:S" endselect endsub int sub UruchomEMapy() Dispatch xKh, xZnacz, xZnaczKh int nErr, nSubtyp, i, nCount,nErrZn, br, wykonuj,czy_blad string KH_kod,KH_nazwa,KH_kraj,KH_katalog,KH_rodzaj,KH_miasto,KH_ulica,KH_dom,KH_lokal,KH_kodPoczt,KH_poczta,KH_rejon,KH_znacznik, KH_znacznik_skrot long KH_id string sCon GetIdKH () if Listaidkh(1)!=0 then if size(Listaidkh)>100 then if size(Listaidkh)<1000 then if (message "Wykonanie operacji dla wybranej liczby kontrahentów (>100) może być czasochłonne. \nCzy na pewno chcesz kontynuować? Btn: Wykonaj = 3 DefBtn: Anuluj = 2 ") == 3 then wykonuj = 1 else message "Wykonanie operacji dla wybranej liczby kontrahentów (>1.000) nie jest możliwe!" endif else wykonuj = 1 endif else message "Nie zaznaczono żadnego kontrahenta!" endif if wykonuj then plik_exp = OtworzPlik(szSciezka_exp,"zapis",1) print#plik_exp; "<?xml version=\"1.0\" encoding=\"windows-1250\"?>" + lf print#plik_exp; using "<DocumentElement>\n" xKh = xFactory.NewObject("BKontrahent") for br = 1 to br > size(Listaidkh) //w petli po zaznaczonych kh: nErr = xKh.Load(using "id=%l",Listaidkh(br)) if nErr then error Using "\nBłąd nr %l\n", nErr KH_id = Listaidkh(br) KH_kod = xKh.kod KH_nazwa = xKh.nazwa KH_kraj = xKh.kraj.nazwa KH_katalog = xKh.katalog.nazwa KH_rodzaj = xKh.rodzaj.kod KH_miasto = xKh.miejscowosc KH_ulica = xKh.ulica KH_dom = xKh.dom KH_lokal = xKh.lokal KH_kodPoczt = xKh.kodPocztowy KH_poczta = xKh.poczta KH_rejon = xKh.rejon KH_znacznik_skrot = using "%i",xKh.znacznik.shortcut xZnacz = xFactory.GetObject("BZnacznikKh") xZnaczKh = xZnacz.Give(using "subtyp=%i",xKh.znacznik) KH_znacznik = xZnaczKh.nazwa DodajWezel(KH_id, KH_kod, KH_nazwa,KH_ulica, KH_miasto, KH_kodPoczt, KH_poczta, KH_lokal, KH_dom, KH_rejon,KH_kraj,KH_rodzaj,KH_katalog,KH_znacznik,KH_znacznik_skrot, "Główny") if xKh.adres2 != "" then KH_miasto = xKh.miejscowosc2 KH_ulica = xKh.ulica2 KH_dom = xKh.dom2 KH_lokal = xKh.lokal2 KH_kodPoczt = xKh.kodPocztowy2 KH_poczta = xKh.poczta2 KH_rejon = xKh.rejon2 DodajWezel(KH_id, KH_kod, KH_nazwa,KH_ulica, KH_miasto, KH_kodPoczt, KH_poczta, KH_lokal, KH_dom, KH_rejon,KH_kraj,KH_rodzaj,KH_katalog,KH_znacznik,KH_znacznik_skrot, "Korespondencyjny") endif next br print#plik_exp; using "</DocumentElement>" close(plik_exp) //uruchom aplikacje exe sCon = using "%s\\%s %s", Katalog(), sApp_exe, szSciezka_exp czy_blad = Execute(sCon) infoErrorExecute(czy_blad, sApp_exe, Katalog()) endif endsub nooutput()