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// Scilab Code Ex 1.25 Page-35 (2006) clc; clear; a_Cu = 3.61; // Lattice constant of Cu, angstrom a_Pd = 3.89; // Lattice constant of Pd, angstrom // For x = 20% of Pd x = 0.20; // Percentage of Pd in Cu-Pd alloy a_Cu_Pd = ((1-x)*a_Cu + x*a_Pd); printf("\nFor %2d percent of Pd in Cu-Pd alloy, a = %4.2f angstr...
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// Exa 4.16 clc; clear; close; // Given data I=1;// in mA I=I*10^-3;// in A i_C=1;// in mA i_C=i_C*10^-3;// in A V_CC= 5;// in V V_CM= -2;// in V V_BE= 0.7;// in V R_C= 3;// in kΩ R_C= R_C*10^3;// in Ω Alpha=1; Bita=100; V_B= 1;// in V i_C1= Alpha*I;// in A i_C2=0; v_E= V_B-V_BE;// in V disp(v_E,"...
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function R= CONVERTORBI(x) x = round(x) signo = 0 exponente = 0 mantisa = 0 //Hallar signo if x< 0 signo = 1 else signo = 0 end //Hallar exponente xbinario = dec2bin(x) str=string(xbinario) tamaño= length(str) precision=tamaño+126 ...
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clear clc E3=0.54;//in V E4=0.45;//in V n3=4;// n4=1;// n1=5;// E1=((-n3*(E3))-(n4*(E4)))/(-n1);// in V printf('E1=%.2f V',E1) n2=6;// n5=1;// E5=1.07;//in V E2=((-n3*(E3))-(n4*(E4))-(n5*E5))/(-n2);// in V printf('\nE2=%.2f V',E2) //page 468
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// Scilab code Ex5.17: Pg 168-169 (2008) clc; clear; R_in = 200; // Internal resistance of meter, kilo-ohms V = 10; // Supply voltage, volts R_1 = 10; // Resistance, kilo-ohms R_2 = 47; ...
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pathname=get_absolute_file_path('16_13.sce') filename=pathname+filesep()+'16_13data.sci' exec(filename) dw=d- 2*tf; Ixx=2*(((b*tf^3)/12)+ b*tf*((dw+tf)/2)^2) + (tw*dw^3)/12; Iyy=(2*tf*b^3)/12 + (dw*dw^3)/12; printf("\n Ixx= %f mm^4",Ixx); printf("\n Iyy= %f mm^4",Iyy)
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function [x,y,typ]=DLRADAPT_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1...
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//check o/p for i/p vector containing imaginary values a = [2.3 %i 0.6149 0.9899 0.340000 0.0031 -0.0082]; k = poly2rc(a); disp(k); //output //// - 0.2181381 - 0.4123737i // 0.2668596 + 0.2678285i // 0.4411879 + 0.0669325i // 0.1494550 + 0.0005854i // 0.0013478 - 0.0015501i // - 0.0035652 ...
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grammar OPTIONS; rule1: no "options" ; rule2: this+ that* theother? ; rule3: "one"? two "three"<,> ; // HACK: Have to put spaces between symbols because the scanner sucks
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//Chapter 10, Problem 20, figure 10.35 clc; //resistance of coil R1=400; R2=400; R3=5000; //value of capacitance C=7.5e-6; //calculating the value of inductance L=R1*R2*C; //calculating the value unknown resistance r=(R1*R2)/R3; printf("Inductance = %f H\n\n\n",L); printf("Resistance = %d ohm",r);
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clear; clc; // Illustration 1.1 // Page: 17 printf('Illustration 1.1 - Page: 17\n\n'); // solution // Taking conversion factor from table 1.5 (Pg 15) // viscosity: [(lb/ft.h)]*4.134*10^(-4) [kg/m.s] (Pg 15) // time: [h] = 3600 [s] // Density: [lb/cubic feet]*16.09 = [kg/cubic m] (Pg 15) // Length: [ft...
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function [fr,g]=freson(h,selec) [lhs,rhs]=argn(0) [n,d]=h(2:3); if type(n)=1 then n=poly(n,varn(d),'c'),end d0=coeff(d,0) if d0=0 then error('infinite gain at zero frequency'), end; ar0=abs(coeff(n,0)/d0)^2 //look for omega such that derivative of magn. is zero niw=horner(n,%i*poly(0,'w')); diw=horner(d,%i*poly(0,'...
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networkTopology(3;4,10,3) inputOutputVector(5.900000,3.200000,4.800000,1.800000;0,1,0) inputOutputVector(4.300000,3.000000,1.100000,0.100000;1,0,0) inputOutputVector(5.200000,3.400000,1.400000,0.200000;1,0,0) inputOutputVector(5.800000,4.000000,1.200000,0.200000;1,0,0) inputOutputVector(6.000000,2.900000,4.500000,...
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clc // Given That lambda1 = 6.1e-7 // max. wavelength of light in meter lambda2 = 6e-7 // min. wavelength of light in meter Mu = 4 / 3 // refractive index of film i = asin(4 / 5) // incidence angle in radian // Sample Problem 27 on page no. 1.49 printf("\n # PROBLEM 27 # \n") r = asin(sin(i) / Mu) // calculation for...
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clear; clc; f=10*10^9,a=4*10^-2,b=2*10^-2,u=3*10^8,Pavg=2*10^-3; fc=u/(2*a); n=377/sqrt(1-(fc/f)^2); E=sqrt(4*n*Pavg/(a*b)); disp(E,'Peak value of Electric field = ');
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clc //to calculate work to be done E=0.5*10^6 //rest energy of electron (MeV) E=m0*c^2 v1=0.6*3*10^8 //speed of electron in (m/s) v2=0.8*3*10^8 c=3*10^8 //speed of light in (m/s) K1=E*((1/sqrt(1-v1^2/c^2))-1) //kinetic energy in (eV) K2=E*((1/sqrt(1-v2^2/c^2))-1) w=(K2-K1)*1.6*10^-19 disp("amount of work to b...
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clc; close clear; s=%s; tf=syslin('c',((s+3)/((s+2)^2*(s+1)))); ss=tf2ss(tf); disp(ss)
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clc(); clear; //Given : Na = 6.023*10^23 ; // Avogadro constant in atoms/mole LE = 200 ; // liberated energy in MeV mm = 235; // molar mass of U 235 in gm/mole // 1 eV = 1.6*10^-19 J , 1 MeV = 1.0*10^6 eV RE = (Na*LE*1.6*10^-19*10^6)/mm ; //released energy in J // 1 cal = 4.187 J EC = RE/4.187 ; // energy in...
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//Example number 10.8, Page number 226 clc;clear; close; //Variable declaration e=1.6*10**-19; //charge(c) h=6.626*10**-36; //plank constant V=8.5*10**-6; //voltage(V) //Calculation new=2*e*V/h; //frequency(Hz) //Result printf("frequency is %.3e Hz",new)
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//pathname=get_absolute_file_path('1.08.sce') //filename=pathname+filesep()+'1.08-data.sci' //exec(filename) //Diameter of cylinder(in m): dia=15*10^-2 //Manometer difference in Hg column(in m): h=12*10^-2 //Density of mercury(in kg/m^3): d=13.6*10^3 //Acceleration due to gravity(in m/s^2): g=9.81 //Weight o...
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before x, phead=0, pbody=1, ptail= - 476*y - 448*y^2 - 112, mlead= + x^2, flead=4, root2=2, widev=4 after x, phead=15*x^2, pbody=1, ptail= - 476*y - 448*y^2 - 127, vmapt={x=>1+2*x,y=>y} before y, phead=15360*x^2, pbody=68, ptail= - 130048, mlead= + 16*y^2, flead=16384, root2=128, widev=1024 after y, phead=15360*...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>StdProject_Diff3D Tetrahedron Modified basis P=6 Q=7</description> <executable>StdProject</executable> <parameters>-s tetrahedron -b Modified_A Modified_B Modified_C -o 6 6 6 -p 7 7 7 -d</parameters> <metrics> <metric type="L2" id="1"> ...
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// Résolution numérique d'une équation différentielle // y' + b y = c // on cherche la solution y(x) // méthode utilisée : la fonction ode de Scilab // plus d'info en tapant help ode dans Scilab // S. Celles // 09/02/2007 clear b = 1; // MODIFIABLE c = 1; // MODIFIABLE // on réécrit l'équa diff sous la forme // y' =...
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errcatch(-1,"stop");mode(2);//Initilization of variables w0=0 //rad/s w=209 //rad/s t=20 //s //Calculations theta=0.5*(w+w0)*t //rad theta_rev=round(theta/(2*%pi)) //revolutions rounding off //Result printf('The flywheel makes %i revolutions',theta_rev) exit();
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//Example 14.2 clc; //Given values of applied potential in V Va=2; Vb=1; Vc=3; //Given resistence values in ohm Ra=3000; Rb=3000; Rc=3000; Rf=1000; //Output of the given summer Vo=-Rf*(Va/Ra+Vb/Rb+Vc/Rc); printf('\nOutput Voltage of the op-amp is %.2f ohm\n',Vo)
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clear // // // //Variable declaration c=3*10**8 //velocity of light(m/sec) lamda=6943*10**-10 //wavelength(m) h=6.626*10**-34 //planck's constant(Jsec) Kb=1.38*10**-23 //boltzmann constant T=300 //temperature(K) //Calculation new=c/lamda //frequency(Hz) a=...
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//Find the output signal voltage of the amplifier clear; clc; //soltion //given Rd=12*10^3;//ohm Rg=1*10^6;//ohm Rs=1*10^3;//ohm Cs=25*10^-6;//F u=80; //amplification factor rd=200*10^3;//ohm Vi=0.1;//V f=1*10^3;//Hz //input frequency Xcs=1/(2*%pi*f*Cs); //This is much smaller than Rs therefor...
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clc clear //Input data T3=1500;//Upper temperature limit of a otto cycle in K T1=300;//Lower temperature limit in K a=0.4;//Rate of flow of air through the cycle in kg/min Cv=0.718;// //Calculations T2=(T1*T3)^(1/2);//Temperature at point 2 in K T4=T2;//Temperature at point 4 in K W=Cv*((T3-T2)-(T4-T1));//W...
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clear clc //function y = f(x) //y = (x(1)-2)^4 + (x(1)-2*x(2))^2; // y = -12*x(2) + 4 *x(1)^2 +4*x(2)^2 - 4*x(1)*x(2); //y = (1-x(1))^2 + 5*(x(2)-x(1)^2)^2 //endfunction function linha = derivada1(x,yj,dj) h = 1e-5; linha = (func_teta(x + h,yj,dj)- func_teta(x - h,yj,dj))/ (2*h); end...
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//Example 1.27 // maximum time constant clc; clear; close; //given data : f1=90;//cycles per seconds f=120; // frequency response in cylcle per second w=2*%pi*f; // rad/sec I=0.96 a=(1/I)^2; b=sqrt(a) t=(b-1)/w; tl=atan(2*(%pi)*f1*t);// tla=(1/(2*%pi*f1))*tl;// time lag in seconds disp(t,"maximum time con...
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clc clear //Input data Po=1000 //Stagnation pressure in kPa To=800 //Stagnation temperature in K k=1.4 //Adiabatic Constant M2=2 //Exit mach number At=20 //Throat area in cm^2 R=287 //Specific gas constant in J/kg-K //Calculation t1=0.834 //Ratio of critical temperature to Stagnation temperature from is...
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# Just adding and joining nodes and explicit stab fix cycles # Now all predecessor, successor and finger table are valid # Now drop all nodes add 0 add 1 add 2 add 3 join 1 0 join 2 0 join 3 0 list show 0 show 1 show 2 show 3 # First cycle of stab fix stab 0 stab 1 stab 2 stab 3 fix 0 fix 1 fix 2 fix 3 # Second cycl...
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clear; clc; printf("\t\t\tExample Number 8.21\n\n\n"); // influence of convection on solar equilibrium temperature // Example 8.21 (page no.-455) // solution T_surr = 25+273;// [K] surrounding temperature sigma = 5.669*10^(-8);// [W/square meter K^(4)] h = 10;// [W/square meter] heat transfer coefficient /...
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//Example 3.27 (b) //Program to Compute the Convolution of the following Sequences //x1[n]=[1,1,-1,-1,0] //x2[n]=[1,0,-1,0,1] clear; clc ; close ; x1=[1,1,-1,-1,0]; x2=[1,0,-1,0,1]; //Convolution Computation X1=fft (x1,-1); X2=fft (x2,-1); Y=X1.*X2; y= fft (Y,1); //Display Sequence y[n] in command window ...
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// problem 2.13 s=2 w=340 v=0.5*s*s*s z=9810 w1=z*4 gb=s/4-s/8 i=s*s*s*s/(12) v=4 bm=i/v gm=bm+gb p=w/(w1*gm) theta=atand(p) disp(theta*60,"angle through which cube will tilt in minutes")
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clc // // // //Variable declaration mu=1.33 //refractive index n1=0 n2=1 n3=2 t=5*10**-7 //thickness //Calculations lambda1=(4*mu*t*10**10)/(2*n1+1) lambda2=(4*mu*t*10**10)/(2*n2+1) lambda3=(4*mu*t*10**10)/(2*n3+1) //Result printf("\n For n=0 Lambda is %0.3f ",lambda1) printf("\n For n=1 Lambda is %i ",lambda2) ...
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// from the nyquist plot N=0; // one clockwise and one anticlockwise encirclement P=0; // given Z=N-P printf("Since Z=0 no root of the characterisic equation lies in the right half hence the system is stable")
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//Example 16.5. //let input wave be V_in=V_p_in*sin(2*%pi*f*t) f=1; //Frequency is 1Hz T=1/f; V_p_in=10; //Peak input voltage V_th=0.7; //knee voltage of diode clf(); //let n be double the number of cycles of output shown in graph for n=0:1:1 t=T.*n/2:0.0005:T.*(n+1)/2 //time for each half cyc...
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clc,clear printf('Example 4.15\n\n') P=30*1000/3 //power per phase V_ph=400/sqrt(3) //phase voltage R=(V_ph)^2/P //resistance of strip t=0.025*10^-2 //thickness of strip S=1.03*10^-6 //specific resistance of nichrome alloy l_by_w = R*t/S //because R=specific_resistance*l/(w*t) ...
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//Program to plot 3D graph using surf subplot(2,2,1) z = rand(10,10); surf(z) title('surf') subplot(2,2,2) surf(z,'facecol','red','edgecol','blu') title('surf function with face and edge color') subplot(2,2,3) surf(z,'facecol','interp') title('surf function interpolated') subplot(2,2,4) x=rand(10,10);...
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clear// //Variables R1 = 1.0 * 10**3 //Resistance (in ohm) Rf = 51.0 * 10**3 //Resistance (in ohm) Cf = 0.01 * 10**-6 //Capacitance (in Farad) //Calculation f = 1.0/(2*%pi*Rf*Cf) //Frequency (in Hertz) fmin = 10* f //Minimum frequency re...
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style.fontSize=12; style.displayedLabel="<table> <tr> <td align=center>GND</td> </tr> </table>"; pal11 = xcosPalAddBlock(pal11,"macrocab_gnd",[],style);
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// **** Purpose **** // This code calculates the Z2 invariant of a 2D plane of a 3D object // For 2D object, just input appropriate parameters. // This code can calculate both Z2 or Floquet Z2 // **** Variables **** // [lat],[hop],[scc],[flq]: structues // <= the output of lat, hop, scc, flq in PiLab // if Z2, let ...
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## !!! DO NOT EDIT !!! ## THIS IS AN AUTOMATICALLY GENERATED FILE ## modify build-sparse-tests.sh to generate the tests you need. ## ## test_sparse ## ## run preset sparse tests. All should pass. function [passes, tests] = test_sparse disp ("writing test output to sptest.log"); test ("sparse.tst", "normal", "sp...
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style.fontSize=12; style.displayedLabel="VDD"; pal4 = xcosPalAddBlock(pal4,"vdd_o",[],style); pal8 = xcosPalAddBlock(pal8,"vdd_o",[],style);
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//example 14.1.a// clc //clears the screen// clear //clears all existing variables// r=16*1024; //given rom capacity// row=sqrt(r) disp(row,' no of registers in each row = ')
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clc;funcprot(0);//EXAMPLE 17.4 // Initialisation of Variables rho1=0.95;...........//Density of polyethylene in g/cm^3 rho2=2.4;...........//Density of clay in g/cm^3 f1=0.65;...............//Volume fraction of Polyethylene f2=0.35;...............//Volume fraction of Clay f3=1.67;.............//Volume fraction ...
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n=0:10; for n=0:10 //if(n%2==0) // a_n=0; //else if (n==4*n-3) a_n=2/(%pi.*n); else if (n==4*n-1) a_n=-2/(%pi.*n); end end end b_n=zeros(1,length(n)); size(n) size(a_n) size(b_n) disp(b_n(1)) C_n=sqrt(a_n.^2+...
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//LTi Systems characterized by Linear Constant //Inverse Z Transform //z = %z; syms n z; H1 = (-2*z)/(z-(1/3)); H2 = (3*z)/(z-0.5); H3 = (24*z)/(z-1); F1 = H1*z^(n-1)*(z-(1/3)); F2 = H2*z^(n-1)*(z-0.5); F3 = H3*z^(n-1)*(z-1); h1 = limit(F1,z,(1/3)); disp(h1,'h1[n]=') h2 = limit(F2,z,0.5); disp(h2,'h2[n]=')...
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//Section-9,Example-1,Page no.-E.47 //To calculate the time required to deposit 2 gm copper from the solution of copper sulphate clc; Q=(96500/32)*2 //charge deposited by 2 gm copper. I=5 t=Q/I //time in seconds disp(t,'Time required for deposition')
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clc clear printf("example 9.5 page number 392\n\n") printf("this is a theoretical question, book shall be referred for solution")
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// Exa 6.10 clc; clear; close; // given data fc=2;//in KHz disp("As the type of the filter is not given, here we design a sallen key equal component filter with Butterworth response."); alfa=1.414;//unitless Klp=1;//unitless //assume C=0.01 uF C=0.01;//in uF R=Klp/(2*%pi*fc*1000*C*10^-6);//in ohm AF=3-alfa...
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/* IVP: y' = -y + 4x*x + 12*x + 98 Initial condition: y(0) = 1 Interval of interest: [0; 4] Exact solution: y = 4x*x+4x+94-93exp(-x) */ function ydot=F(x, y) ydot=-y+4*x^2+12*x+98 endfunction function y = solve_exact(y0,x) C = (y0-(4*x(1)^2+4*x(1)+94))*exp(x(1)) y = 4*x^2...
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clc //Chapter 2:Small Signal Amplifiers //example 2.6 page no 36 //given RL=50//load resistance gm=0.2//tranceconductance B=100//current gain rpi=B/gm//transistor input resistance disp(rpi,'the transistor input resistance is ') disp('The load resistance seen bythe first stage will be the 2k ohm resistor in par...
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clc //initialisations e=4*10^-3//erg p=1*13.6*981 //calculations kt=2*e/3//erg n=p/kt //results printf(' number of molecules = % 1f',kt)
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//Chapter 12 : Solutions to the Exercises //Scilab 6.0.1 //Windows 10 clear; clc; //Solution for 1.11 //X=A + 2B A=[1 0 0;0 1 0;0 0 1]; B=[1 1 1;1 1 1;1 1 1]; X=A+2*B disp(X,'X = A + 2B')
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function [sp]=speye(m,n) // Copyright INRIA [lhs,rhs]=argn(0) if rhs==1 then [m,n]=size(m),end mn=mini(m,n) sp=sparse([(1:mn)' (1:mn)'],ones(mn,1),[m,n])
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//Variable declaration: ADL1 = 2 //Average daily load (MW) R = 25/100 //Reduction in electrical load (%) //Calculation: L = 1-R //New load fraction ADL2 = ADL1*L //New average daily load (MW) AR = ADL1-ADL2 //Average...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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clc; P=100000; // rated VA of transformer n=0.98; // maximum possible efficiency l=80000; // rated KVA of load vrm=0.04; // maximum possible voltage regulation is equal to ze2 in p u pf=0.8; // power factor at which efficiency anf voltage regulation has to be determined pl=((1/n)-1)*l; // total losses in transfo...
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//To determine the corona characterstics clear clc; D=1.036;// conductor diameter(cm) d=2.44;//delta spacing(m) r=D/2;//radius(cm) Ratio=d*100/r; j=r/(d*100); Rat2=sqrt(j); t=26.67;//temperature b=73.15;// barometric pressure mv=.72; V=63.5; f=50;//frequency do=3.92*b/(273+t);//do=dell vd=21.1*.85*do*r*l...
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//chapter 19 //example 19.8 //page 832 printf("\n") printf("given") f=50;hib=2;Rl=50; Ce=1/(2*3.14*f*hib) Co=1/(2*3.14*50*.1*Rl)
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clc clear disp('example 4 7') pl1=20;pf1=0.8;t1=2000//load in MVA //power factor //duration pl2=10;pf2=0.8;t2=1000//load in MVA //power factor //duration pl3=2;pf3=0.8;t3=500//load in MVA //power factor //duration pt=20 ///transformar power rating fte=0.985;ste=0.99 ///full load efficiency for first and second t...
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function do_export(scs_m,fname) [lhs,rhs]=argn(0) driv='Pos';num=1 dr=driver() wpar=scs_m(1)(1) winc=xget('window'); if rhs==1 then num=x_choose(['Postscript file';.. 'Graphics window'],'How do you want to export?') if num==0 then return;end if num<>2 then fname= xgetfile('*');end end // remove blanks and apostroph...
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//clc() disp("f(x,y) = 4*exp(0.8*x) - 0.5*y") //f'(x,y) = 4*exp(0.8*x) - 0.5*y h = 1; x=0:h:4; y(1) = 2; x1 = -1; y1 = -0.3929953; y10 = y1 + (4*exp(0.8*x(1)) - 0.5*y(1))*2; y11 = y(1) + (4*exp(0.8*x(1)) - 0.5*y(1) + 4*exp(0.8*x(2)) - 0.5*y10)*h/2; y12 = y(1) + (3 + 4*exp(0.8*x(2)) - 0.5*y11)*h/2; t = 6.3608...
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function data = mdaqAIRead(arg1, arg2, arg3, arg4) data = []; link_id = -1; if argn(2) == 3 then channels = arg1; aiRange = arg2; aiMode = arg3; end if argn(2) == 4 then link_id = arg1; channels = arg2; aiRange = arg3; aiMode = arg4; ...
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[a_imb_db,ph_imb_deq] = iqcoef2imbal([4 2 complex(-0.1145,0.1297) complex(-0.0013,0.0029)]) disp(a_imb_db,'amplitude imbalance in dB =') disp(ph_imb_deq,'phase imbalance in degrees=')
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//Caption: Program to compute discrete cosine tranform //Example4.10 //page 198 clc; N =4; //DCT matrix of order four X = dct_mtx(N); disp(X,'DCT matrix of order four') //Result //DCT matrix of order four // // 0.5 0.5 0.5 0.5 // 0.6532815 0.2705981 - 0.270598...
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//Exa2.20 clc; clear; close; //given data alpha20=1/254.5;// in ohm/ohm/degree C t2=60;//degree C t1=20;//degree C rho0=1.6*10^-6; alpha60=1/(1/alpha20+(t2-t1)); disp("Temperature coefficient of resistance at 60 degree C is : "+string(alpha60)+" ohm/ohm/degree C"); //from alpha20=1/(1/alpha0+20) alpha0=1/(1...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh,Chapter 2,Example 3") disp("emf equation") disp("E=(0.003*t)-((5*10^-7)*t^2))+(0.5*10^-3)") disp("using emf equation at ice point,E_0 in volts") t=0;//ice point tempera...
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errcatch(-1,"stop");mode(2);// Example 2.15, page no-38 h=2 k=2 l=0 a=4.938*10^-10 d=a/sqrt(h^2+k^2+l^2) printf("\nThe lattice spacing for (220) plane is %.3f*10^-10 m",d*10^10) exit();
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# -------------------------- Header Parameters -------------------------- scenario = "Active Visual Oddball P3"; write_codes = EXPARAM( "Send Port Codes" ); screen_width_distance = EXPARAM( "Display Width" ); screen_height_distance = EXPARAM( "Display Height" ); screen_distance = EXPARAM( "Viewing Distance" ); defa...
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//ques-1.12 //Calculating amount of lime and soda required for softening hard water clc V=2000;//volume of water given (in L) //Raw water A=160;//content of Ca cation (in mg/L) B=72;//content of Mg cation (in mg/L) C=732;//content of Hydrogen carbonate anion (in mg/L) D=30;//content of CO2 (in mg/L) a1=(A/40...
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clc;funcprot(0);//EXAMPLE 3.14 // Initialisation of Variables wL=1.54;........//Wave length of Copper K-alpha in Angstorms t1=19.5;......//Half the angle between the difracted beam and the original beam direction t2=39;......// The angle between the difracted beam and the original beam direction //CALCULATION...
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function [s]= trompette(fp,fm,Fe,d,m0) // fp -> hauteur, d-> durée, m0-> amplitude du sinus modulant Te=1/Fe; // temps echantillonage x=[0:Te:d]; //axe temps m=[0:Te:d]; // amplitude constante au cours du temps n=length(m); for i=1:n m(i)= m0; end f=[0:Te:d]; // frequ...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Add16.tst load Add4.hdl, output-file Add4.out, compare-to Add4.cmp, output-list a%B1.4.1 b%B1.4.1 out%B1.4.1 carry%B3.1.3; set a %B0000, set b %B000...
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// load the data load("albaLTInomoto.sod","sys") Ap=sys.A; Bp=sys.B; Cp=sys.C; Dp=sys.D; //checking controllability and observability [i,j] = size(Ap); // e=[B, AB, A^2 B,..., A^(n-1) B] e = cont_mat(sys.A,sys.B); rankC=rank(e); if i == rankC then disp('Continuous System is Controllable'); end /...
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// Exercice 1.1 r -> V(r) ************************************************* r = 0.8:0.03:3; plot(r, r.^(-12)-2*r.^(-6),'-') // Exeercice 1.2 ********************************************************** // fonction de calcul de J function J = lennardjones(x) N = length(x)/3; X = matrix(x,3,N); J = ...
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// Exa 2.16 clc; clear; // Given data // A level shifter as shown in fig. 2.31 // Assuming Ideal silicon transistors Vbe = 0.7; // Volts // B(current gain) has very large values Vcc = 15; // Volts Rc = 10*10^3; // Ω Re = 5000; // Ω // Solution printf(' From fig. 2.31 we get that, transistors Q1 ...
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clc clear disp('example 14.19') zaa=3;zbb=9 //impedence given between line pas=1 //power at two units are equal to 1p.u par=1 pbs=1.05 //power at sending end is 1.05 and power at receiving end is 1p.u pbr=1 i=1 //assume current is 1p.u los=i*complex(zaa/100,zbb/100) csd=((abs(los)^2)-pas^2-par^2)/(2...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.4 //calculation of refractive index of material from known critical angle //given data thetac=48.2; //critical angle for water(in degree) //calculation //snell's law with respect to total internal reflection m...
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//TP3 //Théologien Thibault Groupe 1 //ASI 3.2 //Exercice 1 A = 1; Km = 10; Tm = 75 * 10^-3; kVis = 1.33 * 10^-2; p = %s; kCapteur = 2; t = (0:5E-2:20); num = A * Km * kVis; dem = p + Tm * p^2; HBO = num/dem; sys1 = syslin('c', HBO); y1 = csim('step', t, sys1); //Exercice 2 HBF = (HBO * kCapteur) / (1 + HBO * kCap...
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clc clear //INPUT DATA np=1.39 //refractive index of prism nl=1.29 //refractive index of liquid a=62 //refracting angle of prism //calculation x=np*sind(62/2)/nl//snells law y=asind(x) d=(y*2)-a//minimum deviation //output printf("the minimum deviation is %3.3f degree",d)
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n = int(input("Enter n : ")); p = int(input("Enter p : ")); m = int(input("Enter m :")); A = zeros(n,p); B = zeros(p,m); disp("Enter elements of A :\n") for i=1:n for j=1:p A(i,j) = int(input("enter element "+string(i)+","+string(j)+" : ")); end end disp("Enter elements of B :\n") for i=1:p ...
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//To find the frequency of the natural torsional oscillations of the system clc //given l1=11//in l2=10//in l3=15//in l4=4//in l5=10//in d1=3//in d2=5//in d3=3.5//in d4=7//in d5=5//in I1=1500//lb ft^2 I2=1000//lb ft^2 leq=3//in from 15.49 g=32.2//ft/s^2 C=12*10^6 J=%pi*leq^4/32 l=l1+l2*(leq/d2)^4+l3*...
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//Ex8_1 clc Amin=8000 disp("Amin="+string(Amin)) // Minimum gain of OP-AMP Amax=64000 disp("Amax="+string(Amax)) // Maximum gain disp("part (i)") delta_Af=0.01 disp("delta_Af="+string(delta_Af)) // Change in overall feedBack gain delta_A=(Amax-Amin)/Amin disp("delta_A= (Amax-Amin)/Amin = "+string(delta_A)) ...
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//Chapter 3: Thermodynamic and Chemical Equilibrium //Problem: 9 clc; //Declaration of Variables wt = 10 //in g heat_a = 4.5 //in K // Solution m = 10 / 100.0 // mol d_h = heat_a / m mprintf("The heat of the reaction is:%d K cal / mol", d_h)
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// Ex 65 Page 406 clc;clear;close; // Given C=6*10**-6;//F L=2.5;//H R=300;//ohm a=R/2/L omega = sqrt(1/L/C-R^2/4/L^2);//rad/s //i=Im*%e**(-a*t)*sin(omega*t+fi) //at t=0 sec i0=0;//A vc=10;//V fi=asin(i0);//degree //L*di/dt=vc at t=0 Im=poly([0],'Im') function i=current(t) i=Im*expm(-a*t)*sin(omega*t+fi) endfunc...
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clear clc //Theorotical Questions printf("Its a theorotical Question")
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load Mult.hack, output-file Mult.out, compare-to Mult.cmp, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2 RAM[2]%D2.6.2; set RAM[0] 0, set RAM[1] 0; repeat 20 { ticktock; } output; set PC 0, set RAM[0] 1, set RAM[1] 0; repeat 50 { ticktock; } output; set PC 0, set RAM[0] 0, set RAM[1] 2; repeat 80 { ticktock; } outp...
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//Solutions to Problems In applied mechanics //A N Gobby clear all; clc //initialisation of variables h=5//ft h1=3//ft r=200//ft f=0.5//ft v=60//ft/s w=62.0//ft/s q=1.5//ft/s g=32.2//ft //CALCULATIONS V=sqrt(q)/(w/(g*r))/2//ft/s F=sqrt(f*g*r)//ft/s T=(v)^2/(g*r)//degree //RESULTS printf('The value of t...
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//////////////////////////////////////////////////////////////////////////////////////////////////////////////// //FK - Activation function function y=activate(x) y = 1*(tanh(x) + 1)/2; endfunction //////////////////////////////////////////////////////////////////////////////////////////////////////////////// //FK - D...
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// Exa 2.4 clc; clear; close; // Given data V_in = 10;// in V R1 = 2000;// in ohm R2 = 2000;// in ohm V_o = V_in * (R1/(R1+R2) );// in V // Vdc= 5/(T/2)*integrate('sin(omega*t)','t',0,T/2) and omega*T= 2*%pi, So Vdc= -5/%pi*(cos(%pi)-cos(0));// in V disp(Vdc,"The value of Vdc in volts is : "); PIV= V_in/2...
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//An example to print the number of iterations required to find the first occurrence of 5 by the rand function. i=0; while %t do //infinite loop i=i+1; n=round (10*rand (1,1)) if(n==5) printf ("5 is found after %d iterations", i) break; end end //An example to display odd i...
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clear clc //Example 21.4 disp('Example 21.4') xbar=199.5;//Note that this is the correct value and not 199 sbar=8.83; USL=235;//Note that this is diff from UCL LSL=185; c4=0.8862; n=3; sigma=5.75; sigma_x=sbar/c4/sqrt(n); mprintf('\nValue of sigma_x=%f',sigma_x); Cp=(USL-LSL)/6/sigma; Cpk=min(xbar-LSL,USL-xbar)/3/...
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//Introductory Topics :example 1-12 : (pg no. 38 & 39) R1=20; R2=1; L=1*10^-3; C=0.4*10^-6; ein=50*10^-3; f=12*10^3; x=sqrt(L*C); y=(1/(2*%pi*x)); eo= ein*(R2/(R2+R1)); XL=(2*%pi*f*L); XC=(1/(2*%pi*f*C)); a=(R1+R2)^2; b=(XL-XC)^2; z=sqrt(a+b); zo=sqrt((R2^2)+b); m=(ein*(zo/z)); printf("\nfr = 1/2.pi.sq...