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//example 5.31 clear; clc; //Given: c=1;//no. of components p=1;//no. of phases //To find the values of degrees of freedom F=c-p+2;//Degrees of freedom printf("Degrees of freedom is %f\n\n",F); disp("Degrees of freedom 2 means both the pressure and temperature can be varied independently");
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// Scilab code: Ex3.6 : Comparison of energy of photon and neutron: Pg: 79 (2008) m = 1.67e-027; // Mass of neutron, kg L = 1e-010; // Wavelength of neutron and photon, m c = 3e+08; // Velocity of light, m/s h = 6.624e-034; // Plancks constant, joule second U_1 = h*c/L; // Energy of photon, joule /...
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//function to plot Zout_cl against ECSS curve function [mag,flog,mask]=ECSS_zout(Zout_cl,Po,Vo) flog=logspace(0,5,10000) [flog,response]=repfreq(Zout_cl,flog) mag=abs(response) zlimit=Vo^2/Po; mask=ones(flog)*0.002 slopeup_start=find(flog>10) slopeup_start=min(slopeup_start); ...
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:======================================================================= :RCVRTY.TST : PRODUCT: BBXS VERSION: 7.01 : DATE: 17 OCT 1990 AUTH: NIS.FURUTA :PROBLEM: : The case of 'lost sync' under 'SRCV' state, code jumps to RCVRTY and : check whether RCVTIM is over or not. But original code...
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//chapter 6 //page no155 //Ex6_6 //given clear; clc; Impd1=250; //in microA Impd0=25; //in microA Iref=(1/16)*Impd1*10^-6; printf("\n Reference current is %0.3f microA",Iref*10^6) Rref=1.5/Iref; printf("\n External bias resistor value Rref1is %0.0f kohm",Rref/1000) //or Rref1=24/Impd1/10^-6; pri...
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function f1=%p_l_r(p1,f1) // f1= %p_l_r(p1,f1) <=> f1=p1\f1 //! // Copyright INRIA [l,c]=size(p1), if l*c<>1 then f1=invr(p1)*f1,return,end, [n1,d1]=f1(2:3), [n1,d1]=simp(n1,p1*d1), f1(2)=n1;f1(3)=d1;
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clc clear //Input data f1=-12//Focal length of a converging lens in cm f2=25//Focal length of a diverging lens in cm d=8//Distance between the lens in cm //Calculations C=(1/f1)+(1/f2)+(d/(f1*f2))//Inverse of focal length in cm^-1 D=(d/f2)+1//Constant value A=(d/f1)+1//Constant value O1F1=(-D/C)//Poistion o...
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// Example 7-7 // Bode Plot for a system in State Space representation clear; clc; xdel(winsid()); //close all windows A = [0 1; -25 -4]; B = [0 ; 25]; C = [1 0]; D = [0]; G = syslin('c',A,B,C,D); omega = logspace(-1,2,100); f = omega / 2 / %pi; repf = repfreq(G,f); // Frequency response bode(omeg...
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// Scilab code Ex4.11: Pg:148 (2008) clc;clear; x0 = 12.34; // Position of zero order fringe, mm Lambda = 6000; // Wavelength of light, angstrom Lambda_prime = 5000; // New wavelength of light, angstrom omega = 0.239; // Fringe width, mm omega_prime = Lambda_prime/Lambda*omega; // New fringe width,...
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clc;funcprot(0); //Example 3.7 //Initializing the variables l = 20; // Length of barage b = 6; //Width of barage r = 3; //Radius of circular top of barage W = 200*10^3; //Weight of empty barage d1 = 0.8; // Depth of water in 1st half d2 = 1; // Depth of water in 2nd half rho = 1...
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 3 // Thermal Radiation // Example 3.14 // Page 147 printf("Example 3.14, Page 147 \n\n") D = 1 ; // [m] r = 6250 ; // [km] D_surf = 300 ; // [km] s = 5.670*10^-8; e = 0.3 ; Tc = -18+273 ; // [K] T_surf = 27+273 ; // [K] // Rate...
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clc // Given that V = 12.4e3 // voltage in V i = 2e-3 // current in amp e = 1.6e-19 // charge on an electron in C // Sample Problem 7 on page no. 20.9 printf("\n # PROBLEM 7 # \n") printf("Standard formula used \n ") printf("I = ne \n 1/2*m*v^2 = eV \n") n = i / e v = 0.593e6*sqrt(V) printf("\n Number of electrons str...
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chdir('C:\Users\matve\Desktop\Code These\ResilienceMSY\'); exec('fctdyn.sce'); exec('fctdyn_eco.sce'); //////////////////////////// //Parametre de lancement //////////////////////////// nb_boats_Post_BAU=nb_boats_MSY; aij=data_param(2:2+N_species-1,2:2+N_species-1); choc=0 Y=20; PopGuyTr=PopGuyTrim; //PROBLEME exec('Dy...
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clear; clc; printf("\t Example 3.9\n"); Cas=1.521*10^-7; v=1525; //velocity in m/s D=0.0516; //diffusivity in cm^2/s d=1.25*10^-3; //density of air in g/cm^3 u=1.786*10^-4; //viscosity of air in n*s/m^2 Dia=2.54; //diameter in cm nre=(Dia*v*d)/(u); //calc. of reynolds no. ...
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// problem 8.14 sce d=0.05 V1=25 x1=30 x=50 x2=x1+x g=10 p1=1000 a=3.142*d*d/4 w=g*p1 Fx=(w*a*V1*V1*(cosd(x1)-cosd(x2)))/g Fy=(w*a*V1*V1*(sind(x1)-sind(x2)))/g F=(Fx*Fx+Fy*Fy)^0.5 z=atand(-Fy/Fx) disp(z,Fx,Fy,"resultant force,angle made by the resultant force with the horizontal")
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function Plot_Hs(Hs,cor) N=10000 b=coeff(Hs(2)) a=coeff(Hs(3)) npolos=length(a)-1 nzeros=length(b)-1 logw = linspace(-6,6,N) s=%i*(10.^logw) num=zeros(1:N); den=zeros(1:N)+0.0001;; for p=0:npolos den=den+a(p+1)*s.^p; end for p=0:nzeros num=num+b(p+1)*s.^p; end H=num./den plot(logw',2...
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//style.fontSize=12; //style.displayedLabel="<table> <tr> <td align=left><b>Clk<br>CS<br>D<br>In</b></td><td>VMM<br>16x16<br>shift<br>register</td><td align=right><b>Clk_out<br>CS_out<br>Q<br>Out</b></td></tr></table>"; //pal5 = xcosPalAddBlock(pal5,"vmm16x16_sr",[],style);
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// Scilab Code Ex4.9 Calculating metallic radii from unit cell dimensions: Page-146 (2010) a_Au = 4.08e-10; // Unit cell dimension of fcc structure of gold, m a_Pt = 3.91e-10; // Unit cell dimension of fcc structure of platinum, m // For fcc structure we have // sqrt(2)*a = 4*R, solving for R R_Au = s...
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// Chapter 3_The Semiconductor in Equilibrium //Caption_Position of Fermi Energy level //Ex_14//page 121 T=300 //temperature in kelvin kT=0.0259 ni=1.5*(10^10) //intrinsic carrier concentration Efa=3*kT //Ef-Ea=3kT Eav=0.045 Efif=Eg/2-(Eav)-(Efa) //The position of fermi level at the maximum doping Na=...
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// Calcul de %pi // S. CELLES // Méthode des polygones (inscrits et circonscrits) // Algorithme d'Archimède (encadrement de pi) // http://membres.lycos.fr/villemingerard/Geometri/PiCalcul.htm clear
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// Variable Declaration v = 220.0 //Voltage(kV) f = 50.0 //Frequency(Hertz) p = 752.0 //Pressure(mm of Hg) t = 40.0 //Temperature(°C) m = 0.92 //Surface irregularity factor r = 1.2 //Conductor radius(cm) d = 550.0 //Spacing(cm) // Calculation Section delta = (0.392*p)/(273+t) //Air...
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x1 = [0 0 1 1]; x2 = [0 1 0 1]; /*or i=1:length(x1_AND_x2) if x1_AND_x2(i) then c(i) = 1; else c(i) = 0; end end */ c = bitand(x1,x2); scatter(x1, x2, 200, c, "fill");
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clear //Given I1=1 //A E=1.5 I2=0.6 R2=2.33 //ohm //Calculation R=2*E/I1 R1=2*E/I2 r=R1-2*R2 //Result printf("\n Internal resisatnce of each battery is %0.3f ohm", r)
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#-----------------------------------------------------------------------------------# # Posttest Session for Statistical Learning/Rate Perception Study # Ava Kiai # # Log: # 12/3/18 - Started file # 12/10/18 - v.0.0 # 2/7/19 - v.0.1 Completed # 3/7/19 - v.1.0 Redesigned how trial settings are...
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//find fourier inverse of X(jw),X(jw)=exp(-1.5*%i*w).*(abs(w)<=1)+0.*(1<=w & w<=%pi) clc; clear; w=0:0.1:2*%pi X=exp(-1.5*%i*w).*(w>=-1 & w<=1)+0.*(1<=w & w<=%pi); x=dft(X,1); n=0:1:length(x)-1; plot2d3(n,x,2); xtitle('Graphical Representation of x(n)','n','x(n)');
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// Exa 1.39 clc; clear; close; format('v',6) // Given data V = 10;// in V R = 10;// in ohm // Current through resistance, I = V/R;// in A disp(I,"Part (a): The current through resistance in A is : ") disp("Part (b) : Current through 10 ohm resistance will be Zero") disp("Part (c): Current will be zero") di...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); sf=T_scene_create; sss=T_getscene; myviewport=T_getviewport; myviewport.focaldistance=7; sss.ambientlightcolor=color(0.05,0.05,0.05); rootframe=sss.Universe; createnew=true; tx=rootframe.createtexture("star",DataDir+"\textures\star2.bmp"); pe=rootframe.add("PEngine")...
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clear; clc; d = 6;// feet l = 60;// feet f = 15/2;// tons/in^2 E = 13000;// tons/in^2 k1 = 2*f/(12*d);// k1 = M_r/I k2 = k1/(l*12/8);//k2 = W/I y_c = (5/384)*k2*l^3 *12^3 /E;// inches //If the giredr is of constant deapth and uniform strength, it bends to an arc of a circle of radius R R = E*d*12/(2*f);// i...
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прояв прояв N;NOM;SG прояв проявт N;NOM;PL витемс витевтсть V;PL;3;PST;CAUS витемс витьсы V;AC3S;SG;3 витемс витевить V;AC3P;SG;2;PST;PASS витемс витевияк V;SG;LGSPEC_AMP;3;PASS витемс витезель V.PTCP;SG;3;PST витемс виттянок V;PL;1 витемс витевть V;AC3P;IMP;SG;2;PASS витемс витить V;AC3P;SG;2;PST витемс витевтьса V;AC...
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//Given that d = 1.8 //in meter P = 250 //in W c = 3*10^8 //in m/s mu = 4*%pi*10^-7 //in SI unit //Sample Problem 34-1 printf("**Sample Problem 34-1**\n") Erms = sqrt(P*c*mu/(4*%pi*d^2)) Brms = Erms/c printf("The rms value of electric field is equal to %1.2eV/m\n", Erms) Brms = printf("The rms value of ...
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errcatch(-1,"stop");mode(2);//Ex:7.4 ; ; A=50; A_new=A+0.2*A; b=0.1; G=A_new/(1+b*A_new); dG=8.33-G/8.33; printf(" percentage change in overall volt gain = %f %%",dG); exit();
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clc,clear printf('Example 10.4\n\n') I = 500 //intensity_of_lamp d=sqrt(4^2 + 3^2 ) //part(i) : Illumination below the lamp E_1=I/d^2 //as cos(theta) is 1 printf('(i)Illumination below the lamp= %.0f lux',E_1) //part(ii) : Illumination 3m away from vertical axis theta=acos(4/5) E_2= I*cos(theta)/d^2 pr...
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int successor(int x) { return x + 1; } main { int s; s := successor(); return s; }
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clear all; clc; disp("Scilab Code Ex 14.1 : ") //Given: sigma_y = 310; //N/mm^2 db =18; //mm rb = db/2; Ab = %pi*(rb^2); E = 210*10^3; //N/mm^2 da1 = 20; //mm ra1 = da1/2; Aa1 = %pi*(ra1^2); La1 = 50;//mm La2= 6; //mm da2 =18; //mm ra2 = da2/2; Aa2 = %pi*(ra2^2); Lb = 56; //mm //Bolt A: P_max ...
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errcatch(-1,"stop");mode(2);//Example 1_30 ; ; //To find the wavelength of the light D5=0.336 //units in centimeters D5=0.336*10^-2 //units in meters D15=0.59 //units in centimeters D15=0.59*10^-2 //units in meters m=10 ...
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// Exa 10.12 clc; clear; close; // Given data del_Vin = 5;// in V FRR = 80;// in dB // Formula FRR= 20*log10(del_Vin/del_Vout) del_Vout=del_Vin/(10^(FRR/20));// in V disp(del_Vout*10^3,"Change in output voltage in mV is : ")
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//page no 187 //example no 6.9 //TURN OFF THE AIR CONDITIONER. //to turn OFF the air conditioner, reset bit D7 //Assuming the same input as earlier as it is a continuation of previous example. clc; A=[1 0 1 0 1 0 1 0]; B=[0 1 1 1 1 1 1 1]; Y=bitand(A,B); //ANDing input (A) with B to keep the D4 bit always set ...
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clc Qa=0.003/60; // m^3/s Ca=20; // g/l Co=0.126; // g/l dp=3700; // N/m^2 p=1000; // N/m^2 d=0.1; // m a=%pi*d^2/4; Qi=Qa*((Ca-Co)/Co); Q=Qi+Qa; B=10/6; Cd=Q/a/sqrt(2*dp/p/(B^4-1)); disp("Coefficient of discharge =") disp(Cd)
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clc // At dead state of 1 bar, 300K u0 = 113.1 // Internal energy in kJ/kg h0 = 113.2 // Enthalpy in kJ/kg v0 = 0.001005 // Specific volume in m^3/kg s0 = 0.395 // Entropy in kJ/kg T0 = 300 // Atmospheric temperature in K P0 = 1 // Atmospheric pressure in bar K = h0-T0*s0 // Part (a) // At 1bar and 90 degree...
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//example-5.3 //page n0-141 //given //lattice constant a=1.54 //A //wavelength of beam of light lambda=1.54 //A //according to bragg's equation //n*lambda=2*d*sin(theta) //following angles are given theta1=20.3*(%pi)/180 theta2=29.2*(%pi)/180 theta3=36.7*(%pi)/180 theta4=43.6*(%pi)/180 //interplaner spad...
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//Exa 6.28 format('v',6) clc; clear; close; // Given data Beta= 100; V_BEsat= 0.8;// in V V_CEsat= 0.2;// in V V_BEact= 0.7;// in V V_CC = 10;// in V R_E = 1;// in kΩ R_C = 2;// in kΩ R_B= 100;// in kΩ Beta=100; alpha= Beta/(1+Beta); // Applying KVL to collector circuit // V_CC= I_Csat*R_C +V_CE +R_E*I...
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clc; clear all; clf; t=0:0.001:1; fc=input('Enter the frequency of carrier signal (square wave):'); fm=input('Enter the frequency of message signal (sine wave):'); a=input('Enter the amplitude of message signal:'); vc=squarewave(2*%pi*fc*t); vm=a*sin(2*%pi*fm*t); n=length(vc); for i=1:n if (vc(i)<=0) ...
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//Example 4.2, Page Number 152 //The Function fpround(dependency) is used to round a floating point number x to n decimal places clc; n1=3.6//For GaAs/Air Interface n2=1//For Air //Using Equation 4.14 n3=n1-n2 n4=n1+n2 n6=(n3/n4)**2 n5=(n2/n1)**2 F=0.25*(n5)*(1-n6) //F is the Fractional Transmission for...
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clc //initialization of variables v=2000 //ft/sec P=14.7 //lb/in^2 g=1.4 T=10+460 //R //calculations c=sqrt(g*32.2*53.3*T) Nm=v/c Tratio=1+ (g-1)/2 *Nm^2 Tt=Tratio*T Pratio=(Tratio)^(g/(g-1)) Pt=Pratio*P //results printf("Stagnation temperature = %d R",Tt) printf("\n Stagnation pressure = %.1f lb/in^2",P...
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function Res = min_bd_rastrigin() Res = [-1 -1]'; endfunction function Res = max_bd_rastrigin() Res = [1 1]'; endfunction function Res = opti_rastrigin() Res = [0 0]'; endfunction function y = rastrigin(x) if ()(x(1)==x(2) || x(2)==x(3) || x(3)==x(1)) then end y = x(1)^2+x(2)^2-cos(1...
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clc; clear; //1 is equivalent to A ad 2 to B and so on. p1=['A' 'D']; //pairs in partition t(1 and 4 represents that 1st and 4th state are in the same block); p2=['C' 'E']; q1=['A' 'E']; //pairs in partition t^ q2=['B' 'D']; q3=['C' 'F']; disp("the following are the partitions of the machine M8"); disp("T...
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//page 12 //Example 1.8 clear; close; clc; n = rand(); n = round(n*10); disp(eye(n,n)); printf('This is an Identity matrix of order %d * %d',n,n); disp('And It is a row reduced matrix.'); m = rand(); n = rand(); m = round(m*10); n = round(n*10); disp(zeros(m,n)); printf('This is an Zero matrix of order %...
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a a r n e ア ー ル ネ a b d u s ア ブ ド ス a c h a t z ア ハ ツ a c h u c a r r o ア チ ュ ー カ ロ a c k e r m a n ア カ ー マ ン a c k e r m a n ア ッ カ ー マ ン a c k e r m a n n ア ケ ル マ ン a c k e r m a n n ア ッ カ ー マ ン a c k e r m a n n ア ッ ケ ル マ ン a d a n s o n ア ダ ン ソ ン a d e e エ ー デ ィ ー a f g h a n i s t a n ア フ ガ ニ ス タ ン a g a f o s h i ...
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//Chapter 19, Problem 2 clc; cmrr=90; //CMRR Ad=150e3; //differential gain Ac=Ad/10^(cmrr/20); //common mode gain printf("Common mode gain = %.2f",Ac);
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clc dV = 0.5 // Change in volume in m^3 P = 101.325e03 // Atmospheric pressure in N/m^2 Wd = P*dV // Work done in J printf("\n Example 3.1") printf("\n The amount of work done upon the atmosphere by the balloon is %f kJ",Wd/1e3) //The answers vary due to round off error
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<?xml version="1.0" ?> <TestCase name="EYUL_1Seg_VA_UB" version="5"> <meta> <create version="9.1.0" buildNumber="9.1.0.399" author="admin" date="06/26/2016" host="banvi08mac844" /> <lastEdited version="10.1.0" buildNumber="10.1.0.283" author="admin" date="12/22/2017" host="LTXWD-SSDSV-01" /> </meta> <id>3EDE65...
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// Exa 9.2 clc; clear; close; // Given data scale= 100;// in mV/cm gh= 5.2;//amplitude of the graph in cm PtoPamplitude= gh*scale;// in mV disp(PtoPamplitude*10^-3,"Peak-to-peak amplitude in V is : ")
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//ques48 disp('centre of curvature of given cycloid '); syms a t x=a*(t-sin(t)); y=a*(1-cos(t)); y1=diff(y,t,1); y2=diff(y,t,2); xx=x-y1*(1+y1)^2/y2; yy=y+(1+y1^2)/y2; disp('the coordinates x,y are resp :'); disp(xx); disp(yy); disp('which another parametric equation of cycloid ');
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//Chapter 4, Example 4.1, page 130 clc //Initialisation h=400 //height in Km pd=1*10**8 //plasma density at height D pe=1*10**10 //plasma density at height E pf=3*10**11 ...
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// Variable declaration n1 = 7 // Smaple-1 size n2 = 13 // Smaple-2 size // Calculation // Using Table-6, for v1 = 6 and v2 = 12 ,F(0.05) = 3.00 thus probability is 0.05 P = 0.05 // required probability // Result printf ( "required probability: %.2f",P)
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//Example 7.3 //Program to Calculate Operating Point Coordinates of the Circuit clear; clc ; close ; //Given Circuit Data Vcc=10; //V Rb=100*10^3; //Ohms Rc=1*10^3; //Ohms Beeta=150; //Calculation Ib=(Vcc)/Rb; Ic=Beeta*Ib; Icsat=Vcc/Rc; Vce=Vcc-Ic*Rc; //Displaying The Results in Command Window printf("T...
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clear close clc b = 22:22:2200; y = zeros(b) for i = 1:1:length(b) y(i) = log(9)/b(i) end plot(b,y)
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//Example 9-32 PG NO 618-619 P1=1-%i*50; P2=1+%i*150; Z1=0+%i*50; I=[0.2*Z1]/[P1*P2]; disp('i) Current (I) is = '+string ([I]) +' A '); L=5; //INDUCTAR R=10; //RESISTANCE C=2*10^-5; Wo=1/sqrt(L*C); disp('ii) Wo...
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//================================================================================ // chapter 8 example 5 clc; clear; // variable declaration mo = 9.11*10^-31; // mass of electron inkilograms e = 1.6*10^-19; // charge of electron in coulombs er = 13.2; //relative permit...
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function [z, p, g] = buttap (n) //Design a lowpass analog Butterworth filter. //Calling Sequence //z = buttap (n) //[z, p] = buttap (n) //[z, p, g] = buttap (n) //Parameters //n: Filter Order //z: Zeros //p: Poles //g: Gain //Description //This is an Octave function. //It designs a lowpass analog Butterworth filter of...
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clear// //Variables CMRR = 90.0 //Common-mode rejection ratio (in Decibels) Adm = 30000.0 //Differential gain //Calculation Acm = 10**(-CMRR/20.0) * Adm //Common-mode gain //Result printf("\n The common-mode gain is %0.3f .",Acm)
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//Page Number: 488 //Example 9.14 clc; //Given e0=8.854D-12; er=13.1; vd=2.5D+5; //m/s e=1.6D-19; mu=0.015; //m2/Vs //Criteria n0L=(e0*er*vd)/(e*mu); disp('m^-3',n0L,'n0L should be greater than');
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//find.. clc //solution //given r=0.16//m u=0.3 P=600//N //taking moment abt point A //Rn=Ft/u //Rn*350+Ft*(200-160)=600*(400+350) Ft=600*750/1207//N Tb=Ft*r//N-m printf("torque acting is,%f N-m\n",Tb)
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function a=sp_sum(a,flag) // Copyright INRIA [m,n]=size(a); if flag==2|flag=='c' then a=a*sparse(spzeros(n,1)+1); end if flag==1|flag=='r' then a=sparse(spzeros(1,m)+1)*a; end
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//Effect of variable specific heat on efficiency clc,clear //Given: r=7 //Compression ratio g=1.4 //Specific heat ratio(gamma) cv=0.718 //(Assume)Specific heat at constant volume in kJ/kgK dcv=1*cv/100 //Change in specific heat in kJ/kgK //Solution: R=cv*(g-1) //Specific gas constant in kJ/kgK eta=round(100*(1...
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// ============================================================================= // gfx4scilab - ui // dgerod@xyz-lab.org.es // ============================================================================= //------------------------------------------------------------------------------ // MainWindow //---------...
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//pathname=get_absolute_file_path('11.21.sce') //filename=pathname+filesep()+'11.21-data.sci' //exec(filename) //Ambient air temperature(in K): Ta=27+273 //Temperature of burnt gases(in K): Tg=630 //Air consumed at rate(in kg air per kg of coal): m=15 //Ratio of actual draught to thereotical draught: r=0.60 ...
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clc // Intialization of variables Q = 600/60 // ft^3/s D = 8/12 //ft A = %pi*(D^2)/4 //ft^2 d = 2.38*(10^-3) // slugs/ft^3 u = 3.74*(10^-7) // lb.s/ft^2 f = 0.017 g = 32.2 //ft/s^2 l = 30 //ft d1 = 7.65*(10^-2) //lb/ft^2 //Calculations V = Q/A //ft/s Re = d*V*D/u Hp = f*l*(V^2)/(D*2*g) //ft Pa = d1*Hp*Q...
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// // "vib-res.sce" // clear; clf(); function dx = model(t,x) dx(1) = x(2); dx(2) = -0.2*x(2) - x(1) + cos(om*t); endfunction om1 = linspace(0.2,1.6,15); x0 = [0; 0.1]; tt = linspace(0, 100, 300); realtimeinit(0.1); //アニメーションの時間刻み for i = 1:15 realtime(i); drawlater(); //描画延期 om = om1(i); f = cos(...
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//fonction : 'Test_time' //paremetre : A une matrcie tridiagonal,n est la taille de A //retour ; function Test_time(n) A=zeros(n,n); b=ones(1); for i = 1 : n for j = 1 : n if i == j A(i,i) = 3; elseif abs(i-j) == 1 A(i,j)=1; ...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 4 : DIRECT CURRENT MACHINES // EXAMPLE : 4.2 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA p = 8; // Number of the poles in Dc machi...
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function[multiplyMat] = immultiply(matA, matB) out = opencv_immultiplyt(matA, matB) channel = size(out) for i = 1: channel multiplyMat(:,:,i) = out(i) end endfunction
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errcatch(-1,"stop");mode(2);//Example 1_26 ; ; //tofind the amplitude of the resultant wave pathdifference=1/4 //in terns of lamda phasedifference=(2*%pi)*pathdifference //In terms of lamda amplitude=2*cos(phasedifference/2) //in terms of a printf("Amplitude A=%.3f*a",amplitude) exit();
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ProbXiequals1 = 1 - ((19/20)^10); EXi = ProbXiequals1 ; EX = 20*EXi; disp(EX, "The expectation is")
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clear clf() exec('C:\Users\Julien Guégan\Desktop\PFE\fonctions test.sce',-1) function [x,n] = gradientconjuguelineaire(A,b,tol,itermax,x0) x(:,1) = x0 grad(:,1) = b - A*x0 direction(:,1) = grad(:,1) n = 1 while (tol<abs(grad(:,n)))&(n<itermax) then alpha(n) = (grad(:,n)'*grad(:,n))./(direc...
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function vis_res (res) j=0 for i=0:5:100 j=j+1 w(j,1)=i w(j,2)=res(1)+res(2)*i+res(3)*i^2 end subplot(223) plot(w(:,1),w(:,2)) xtitle("Основное удельное сопротивление движению поезда","v, км/ч","w, Н/кН") endfunction
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction function[H]=HRB(Tr,Pr,omega) B0=0.083-(0.422/(Tr^1.6)); diffr_B0=0.675/(Tr^2.6);//dB0/dTr B1=0.139-(0.172/(Tr^4.2)); diffr_B1=0.722/(Tr^5.2);//dB0/dTr H=Pr*(...
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// TRABALHO FINAL DE INTELIGÊNCIA COMPUTACIONAL // Aluno: José Lopes de Souza Filho // Matrícula: 389097 // Aplicação: Scilab, versão 6.0.2 // SO: Linux Mint 19.2 Tina //----------------------------------------------------------------------------- //ALGORITMO GENÉTICO: CAIXEIRO VIAJANTE clear; // Limpa as variáveis a...
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function []=Get(varargin) //disp('Get') tempData = varargin($) f = fieldnames(tempData) // disp(size(f,'*')) if ~size(f,'*') then if size(tempData,'*') == 0 then printString = 'empty' elseif isnan(tempData) then printString = 'Nan' elseif isin...
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function[y]=simpson(a,b,n) h=(b-a)/(2*n); soma = exp(-a^2)+exp(-b^2); i=a+h while i<b if i==(b+a)/2 then soma = soma + 2*exp(-i^2); disp("if"); else soma = soma + 4*exp(-i^2); disp("else"); end i=i+h; end soma=soma*h...
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//example 3.11 //calculate Dischage required at head of canal clc; //Given Cr=2; //crop ratio A=80000; //Area of field CI=85; //percent field culturable irrigable IK=30; //irrigation intensity during kharif season IR=60; //irrigation intensity for rabi season...
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// Calculate the percentage limiting error and range of resistance values clc; disp('decade a is set at 4000 ohm, so,error in decade a=') Er_a=4000*0.1/100; disp(Er_a) disp('decade b is set at 600 ohm, so,error in decade b=') Er_b=600*0.1/100; disp(Er_b) disp('decade c is set at 30 ohm, so,error in decade c=') ...
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MissionB-2.sce
//---------Mission B-2----------- //------------------------------------- // Améliorer le contraste de l'image // funcprot(0) getd("../Fonctions") missPath="./MissionsB/" nomMission="MissionB-2" // PBM--->matrice img = readpbm(missPath+"GD61.pbm") //Traitement de l'image rendu = img; //matrice--->PBM writepbm(re...
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ex6_9.sce
//Page Number: 335 //Example 6.9 clc; //Given I0=500D-3; //A V0=10D+3; //V Z0=25; //ohm l=.20; //m f=5.93D+9; //Hz //Gain parameter C=((I0*Z0)/(4*V0))^(1/3); disp(C,'Gain parameter:'); N=(l*f)/(0.593D+6*sqrt(V0)); //Gain Ap=-9.54+(47.3*C*N); disp('dB',Ap,'Gain of TWT:');
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size.man.tst
clear;lines(0); [n,m]=size(rand(3,2)) [n,m]=size(['a','b';'c','d']) x=ssrand(3,2,4);[ny,nu]=size(x) [ny,nu]=size(ss2tf(x)) [ny,nu,nx]=size(x)
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//Example 15_8 clc(); clear; //To show using lines of force that a charge suspended with in cavity induces an equal and opposite charge on surface printf("Lines of force come out of positive charge q suspended in cavity.\nCavity \nsurface must possess a negative charge since lines of force go and terminate on q.\nT...
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ex9_5.sce
clc;clear; //Example 9.5 //given data e=1.6*10^-19;//the charge on electron in C m=1.676*10^-27;//mass of neutron in kg c=3*10^8;//speed of light in m/s h=6.625*10^-34;//Plank's constant //calculations E=1;//in eV E=1*e;//in V mv=sqrt(2*E*m); W=h/mv; disp((W/10^-10),'de broglie wavelength in Angstrom')
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example1_53.sce
//exapple 1.53 clc; funcprot(0); // Initialization of Variable pi=3.14159; GMT=17+5/60+2/3600;// i=9.8565/3600*GMT; GST=3+12/60+12/3600; wl=1+18/60;//west longitude RA=16+23/60+30/3600; H=GMT+i+GST+wl-RA;//hour angle H=H*15; p=90-29-52/60; c=90-52-8/60; z=acos(cos(H*pi/180)*sin(p*pi/180)*sin(c*pi/180)+...
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18_07.sce
//Chapter 18, Problem 7 clc; //initializing the variables: C = 0.1E-6; //capacitance in farads R = 4000; //resistance in ohms V = 200; //supply voltage Vc1 = 2; // in volts //calculation: taw = R*C I = V/R t = -1*taw*log(Vc1/V) printf("\n (a)Initi...
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ch2_1.sce
clc disp("Example 2.1") printf("\n") printf("Given") disp("Resistance used is 4 ohm") disp("Current flow is i=2.5*sin(w*t)") disp("Angular frequency(w)=500 rad/s") R=4; iamp=2.5;w=500; t=0:0.001:0.012566 i=2.5*sin(w*t) Vamp=iamp*R; printf("v=%d*sin(%d*t)(V)\n",Vamp,w) pamp=iamp*iamp*R; printf("p=%...
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Ex4_5.sce
//Chapter 4 Solutions Nonelectrolytes clc; clear; //Initialisation of Variables p = 17.4 //mm m= 1000 //gms M= 18 //gms n= 2 //moles //CALCULATIONS P= p*((m/M)/((m/M)+n)) P1= p*(n/((m/M)+n)) dp= p-P1 //RESULTS mprintf("Vapour pressure of solution= %.2f mm",P1)
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2019-08-28T01:25:40
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sce
GaussParcial - SemPivotamento.sce
function semgauss A = input('Entre com A: ') b = input('Entre com b: ') [n m] = size(A) for k = 1:(n-1) for i = (k+1):n multiplicador = A(i,k) / A(k,k); A(i,k) = 0; for j = (k+1):n mA = multiplicador * A(k,j); ...
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Ex6_9.sce
clear; clc; printf("\t\t\tProblem Number 6.9\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.9 (page no. 252) // Solution T2=500+460; //absolute final temperature //unit:R T1=80+460; //absolute initial temperature //unit:R //The equation cpbar= 0.338-(1.24*10^2/T)+(4.15*10^4)/T^2 has a form , cbar= Ada...
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Exa1_3.sce
//Exa 1.3 clc; clear; close; //given data : I=20;//in A Rr=100;//in Ohm //Formula : Wr=I^2*R Wr=I^2*Rr;//in W disp(Wr/1000,"Radiated power in KW : ");
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Beginner flick 500ms by Lukettin.sce
Name=Beginner flick 500ms by Lukettin PlayerCharacters=A_air_pistol_frozen slower BotCharacters=500ms.bot IsChallenge=true Timelimit=60.0 PlayerProfile=A_air_pistol_frozen slower AddedBots=500ms.bot PlayerMaxLives=0 BotMaxLives=100 PlayerTeam=1 BotTeams=2 MapName=square_1wall_clip_big.map MapScale=1.3 Bloc...
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Ex16_3.sce
clc clear //Initalization of variables eff=0.585 heat=800 //Btu t1=80+460 //R p1=14 //psia n=1.4 R=53.35 cr=9 cp=0.24 J=778 //calculations W=eff*heat v1=R*t1/(144*p1) v2=v1/cr t2=1301 //R t3=t2+ heat/cp v3=v2*t3/t2 v4=cr*v3 mep=W*J/(144*(v4-v2)) //results printf("Mean effective pressure = %.1f psi...
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ATWM1_Working_Memory_MEG_Nonsalient_Cued_Run2.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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Ex13_3_1.sce
//Fiber Optics Communication Technology, by Djafer K. Mynbaev and Lovell L.scheiner //Windows 8 //Scilab version- 6.0.0 //Example 13.3.1 clc; clear ; //given //case 1 deltan=0.07;//Difference between refractive indexes of TE and TM modes v=3.75E3;//velocity of sound in LiNb)3 in m/s lambda=1540.56E-9;//opti...