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clear; clc; // Example: 1.12 // Page: 24 printf("Example: 1.12 - Page: 24\n\n"); // Solution // The relation is: // (C/5) = ((F - 32)/9) // For C = F C = - (32*5/4); // [degree Celsius] printf("The temperature which has the same value on both the centigrade and Fahrenheit scales is %d degree Celsius o...
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clc ;funcprot(0); //Example 2.10 //Initializing the variables phi = 30; //30 degree h = 1.2 ; // Height of tank l = 2; // Length of tank g = 9.81; //Calculations function[Theta]=SurfaceAngle(a,phi) Theta = atand(-a*cosd(phi)/(g+a*sind(phi))); endfunction //case (a) a = 4 disp(tand(SurfaceAngle(4,phi)),"Tan of...
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//Example 1.2 (d) clc;clear; t=-5:0.01:5; x=-0.5*(t-4); plot(t,x); title('x(t)=r(-0.5t+2)'); zoom_rect([-5 0 5 5]);
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//clear// clc clear exec("4__11.sci"); t = 0:1:500; function w=f(t,C) w =zeros(4,1); v = v0+v00*t; w(1)= -k*C(1)*C(2)-v00*C(1)/v; w(2) = -k*C(1)*C(2)+v00*(Cb0-C(2))/v; w(3) = k*C(1)*C(2)-v00*C(3)/v; w(4) = k*C(1)*C(2)-v00*C(4)/v; endfunction x=ode([.049;0;0;0],t0,t,f); l1=x(1,: )' l2=x...
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// Link2AT.sci generates "A" and "T" matrix from link information // www.controlsystemslab.com July 2012 // // Usage: [A,T] = Link2AT(L,q); // if L contains n links, A becomes a 4 x 4 x n matrix // and T is the overall homogeneous transformation; i.e, T=A1*...*An //Notes: // - For a revolute joint the THETA p...
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// Example 14.3 Redesign the output stage of Example 14.2 V_T=25*10^-3; // (V) I_S=10^-14; // (A) I_Q=2*10^-3; // Required quiescent current (A) // We select I_BIAS=3mA which is divided between I_R and I_C1 // Thus we select I_R=0.5mA and I_C1=2.5mA V_BB=2*V_T*log(I_Q/10^-13); disp(V_BB,"V_BB (V)") I_R=0.5*10^-...
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//no output //ques1 clc disp('definite integral'); syms x a g=x^7/(a^2-x^2)^1/2 f=integ(g,x,0,a); disp(float(f));
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clear; clc; close; Vm = 30; Idc = 50; C = 100; Vdc = Vm - 4.17*Idc/C; disp(Vdc,'Filter dc voltage = ');
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//Example 7.25 // An estimator design for a simple pendulum xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ // State space representation w0=1; F=[0 1; -w0^2 0]; G=[0 1]'; H=[1 0]; J=0; n=sqrt(length(F));//order of the system // ...
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clc //Machine A f1 = 2000 // annual benefit from better production quality in Rs i = 10 // interest rate i = 10/100 f2 = 12000 // salvage value in Rs f3 = 8000 // operating and maintenance cost in Rs I1 = 100000 // initial cost in Rs n = 5 // years p1 = (f1*((1+i)^n-1))/(i*(i+1)^n) p2 = f2/(1+i)^n c1 = p1 + ...
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clc //initialisation of variables f=5//cm d=10//cm r=150//liters p=4//in A2=7.84*10^-3//m^2 //CALCULATIONS A=((%pi)*(f*10^-2)^2)/p//m^2 V1=(r*10^-3)*(1/60)/A//m/s V2=(A*V1)/A2//m/s //RESULTS printf('The velocity of the fluid in both pipes=% f m/s',V2)
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// Exa 3.17 clc; clear; close; // Given data I_Zmin = 1;// in mA I_Zmin=I_Zmin*10^-3;// in A I_Zmax = 5;// in mA I_Zmax=I_Zmax*10^-3;// in A I_Lmin = 0;// in mA I_Lmin=I_Lmin*10^-3;// in A I_Lmax = 4;// in mA I_Lmax=I_Lmax*10^-3;// in A R = 5;// in kohm R = R * 10^3;// in ohm V_Z = 50;// in V disp("Part...
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clc,clear printf('Example 4.2\n\n') Slots=120 Pole=8 Phase=3 //number of phases n=Slots/Pole //Slots per Pole m=Slots/Pole/Phase //Slots per Pole per Phase beeta=180/n //Slot angle in degree K_d=sind(m*beeta/2) /(m*sind(beeta/2)) //Distribution Factor printf('Distribution Factor:\nK_d=%.3...
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// Example 12_2 clc;funcprot(0); // Given data T=20;// °C SPL=20;// Sound Pressure level in dB // From table 1.1, rho_0=1.204;// kg/m^3 gamma=3.5/2.5;// Specific heat ratio // Calculation // (a) Inverting equation 12.18, Pa=2*10^-5*(1*10^(20/10));// Pa // (b) From equation 12.17, a=(gamma*1.013*10^5*rho_0...
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//Example 5.27 //Linear Iteration Method //Page no. 198 clc;clear;close; deff('x=f(x)','x=20/(x^2+2*x+10)') printf('n\tx\t\tf(x)\n') printf('-------------------------------------\n') x=1; for i=1:19 printf(' %i\t%.10f\t%.10f\n',i,x,f(x)) x1=x; x=f(x); end printf('\n\nx = %.10f',x1)
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errcatch(-1,"stop");mode(2);//Find Power loss due to Hysteresis //Ex:14.3 ; ; a=600;//loop area in J/sqm f=50;//in Hz v=0.01//volume in cu. m w=a*f*v;//in W disp(w,"Power loss due to Hysteresis (in W) = "); exit();
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//Exam:3.28 clc; clear; close; d=1.181;// wavelength=1.540;//in angstrom angle=90;//in degree n=2*d*sind(angle)/(wavelength);//the bragg reflection index disp(n,'bragg reflection index for BCC crystal=');
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//Chapter-5, Example 5.14, Page 171 //============================================================================= clc clear //INPUT DATA V=200;//voltage in V R=50;//resistance in ohms L=0.5;//inductance in Henry F=50;//freq in hz //CALCULATIONS Xl=2*%pi*F*L;//inductive reactance Z=(R)+((%i)*Xl)//impedance ...
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//Chapter 3, Exmaple 12, page 107 //Binding energy clc clear h = 4.15*10**-15 c = 3*10**8 Imax = 1000*10**-10 We = h*c/Imax printf("\nBinding Energy = %e eV ",We) //Answer may vary due to round off errorS
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// Example 5.4: conductivity clc, clear // given : format('v',8) V=.432; // voltage drop across the wire in volts I=10; // current through the wire in A l=1; // length in m d=1*10^-3; // diameter in m R=V/I; A=(%pi*d^2)/4; p=(R*A)/l; b=1/p; disp(b,"conductivitty,b(ohm^-1.m^-1) = ")
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// Example 5.3 // A program to evaluate the power series. It uses if...else to test accuracy. // e^x=1+x+x^2/2! + x^3/3! + +x^n/n!,0<x<1 ACCURACY=0.0001; x=input("Enter value of x:"); n=1;term=1;sum1=1;count=int8(1); while(n<=100) term=term* x/n; sum1=sum1+term; count=count...
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clc; VO=0.21; VN=0.79; n=3.5; nO=VO*n; nN=VN*n nC=1; m_O=32; m_N=28; m_C=44; mO=m_O*nO; mN=m_N*nN; mC=m_C*nC; m=mO+mN+mC; disp("total mass is:"); disp("kg",m); //percentage of carbon is mc=12; P=mc*100/m; disp("percentage of carbon is:"); disp("%",P) n=nO+nN+nC; m_=[nO*m_O/n]+[nN*m_N/n]+[nC*m_C/n] R_=8.3145; R=...
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function T = polyControleBsplines() ibutton = 0; i=1; while (ibutton <> 2 & ibutton <> 5) plot2d(0,0,rect=[0,0,3,3]) [ibutton,x,y]=xclick() T(i,:)=[x,y] plot(x,y,"ro"); if(i>1) plot([T(i-1,1),T(i,1)],[T(i-1,2),T(i,2)]) end i = i+1 end ...
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//Given that C = 1 //(say) R = 1 //(say) //Sample Problem 28-5a printf("**Sample Problem 28-5a**\n") //q = qo*e^(-t/(R*C)) //q = qo/2 when t = Tq Tq = log(2)*R*C printf("At t=%fT, the capacitor will be half charged\n", Tq) //Sample Problem 28-5b printf("\n**Sample Problem 28-5b**\n") //U = Uo*e^(-2*t(R*...
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//Exa 9.5 clc; clear; close; //Given data : P=100000;//in Rs F=20000;//in Rs n=8;//in years Sum=n*(n+1)/2;//sum of the years disp("The rates for years 1-8, are respectively 8/36,7/36,6/36,5/36,4/36,3/36,2/36,1/36"); disp("The calculations of Dt and Bt for different values of t are summarized in table below u...
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//find torque req,stress,numbr of threads clc //soltuion //given do=25//mm p=5//mm W=10000//N D1=50//mm R1=25//mm D2=20//mm R2=10//mm u=0.2//=tan(q) u1=0.15 N=12//rpm pb=5.8//N/mm^2 d=do-(p/2)//mm Lead=2*p //tan(a)=Lead/(%pi/d)=b=0.1414 b=0.1414 //P=W*tan(u+a) //P=W*[(tan(a)+tan(q))/(1-tan(a)*tan(q)...
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//pathname=get_absolute_file_path('13.03.sce') //filename=pathname+filesep()+'13.03-data.sci' //exec(filename) //Pressure of steam entering(in bar): p1=12 //Pressure at exit(in bar): p2=6 //Mass flow rate(in kg/s): m1=5 m2=m1 m3=m1 //Exit velocity(in m/s): C3a=500 //From steam tables: h1=3045.8 //kJ/kg h...
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x=0:0.1:2*%pi; plot(x,sin(2*x),'rpentagram') a=gca(); // definição da janela de plotagem a.y_location ="middle"; // left, middle a.x_location ="middle"; // bottom, origin
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a a b r o o ஆ ப ் ர ூ a a g a u r s h o l a ஆ க ் அ வ ு ர ் ஷ ோ ல ா a a h w a a n i t ஆ ஹ ் வ ா ன ி த ் a a k a a s h ஆ க ா ஷ ் a a n a n d i t ஆ ன ந ் த ி த ் a a n a n d m a y e e ஆ ன ந ் த ம ா ய ீ a a r i f ஆ ர ி ஃ ப ் a a s h i k ஆ ஷ ி க ் a a s m a n ஆ ஸ ் ம ன ் a a s m a n ஆ ஸ ் ம ா ன ் a a t i k a h ஆ த ...
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//Script for Matrix manipulation tutorial //This script gives a demonstration of a few basic matrix operations used in Scilab //Manual entry of matrices (A,B,x) A = [1 2 3;3 2 1;2 4 5]; B = [5 4 2;1 8 9;5 4 1]; x = [1;2;3]; //Elementwise Matrix operations //Summation of two matrices Mat_Sum = A + B; disp(Mat_Sum,'A+B...
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clear ; clc; // Example 9.4 printf('Example 9.4\n\n'); // Page no. 235 // Solution f_NH3 = 5 ;// NH3 in feed-[g] f_N2 = 100 ;// N2 in feed-[g] f_H2 = 50 ;// H2 in feed-[g] p_NH3 = 90 ;// NH3 in product-[g] m_NH3 = 17 ;// Molecular wt. of NH3-[g] m_N2 = 28 ;// Molecular wt. of N2-[g] m_H2 = 2 ;// Molecular wt. of ...
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//variable initialization IbyI_not=.99 //ratio of moving length and rest length c=3*10^8; //speed of light (meter/second) //calculation of velocity of rocket ship Beta=(1-IbyI_not^2)^(1/2); //calculating value of Beta v=Beta*c; //vel...
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/*clf(); x = linspace(0,100,10000) y = ((x+1).*%e^x)-(x.*%e^-x); ylabel('$y=(x+1)e^x-xe^{-x}$','fontsize',5,'color','blue'); plot(x,y) clf(); x=linspace(0,100,10000); z=(x+1).%e^x-x.%e^-x ylabel ('${(x +1)e^x-xe^-^x}$','fontsize', 4); plot(x,z)*/ clf(); x= linspace(0,2*%pi,1000); r=2.*cos(3.*x); polarplo...
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clear clc integrate('1/sin(x)^3','x',%pi/3,%pi/2)
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enqueue 5 enqueue 7 dequeue enqueue 3 enqueue 8 enqueue 9 dequeue dequeue dequeue dequeue dequeue
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 19.3 //calculation of the power of lens for the spectacles //given data d=1.5//distance(in m) upto which the man can clearly see objects //calculation f=-d//focal length of the lens P=1/f//definition of power of ...
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// Exa 4.13 clc; clear; close; format('v',5) // Given data Beta = 44; R_L = 1.51 * 10^3;// in ohm R_E = 270;// in ohm V_CC = 4.5;// in V R2 = 2.7 * 10^3;// in ohm R1 = 27 * 10^3;// in ohm R_C = 1.5 * 10^3;// in ohm Vth = V_CC * (R2/(R1+R2));// in V Rth = (R1*R2)/(R1+R2);// in ohm // Applying KVL to input...
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clear; clc; // Example: 1.13 // Page: 24 printf("Example: 1.13 - Page: 24\n\n"); // Solution //*****Data*****// delta_T_C = 30;// [OC] //*************// // The relation between the Kelvin temperature scale and the Celsius temperature scale: // T(K) = T(OC) + 273.15 // Here, the temperature rise is ...
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//Example 8_10 clc;clear;funcprot(0); // Given values rho_m=788.4;// kg/m^3 mu=5.857*10^-4;// The dynamic viscosity of methanol in kg/m.s d=0.03;// Diameter of orifice in m D=0.04;// Diameter of pipe in m rho_Hg=13600;// kg/m^3 g=9.81;// m/s^2 h=0.11;// m //Assumptions C_d=0.61; //Calculation beta=(d/D);...
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clc,clear printf('Example 7.17\n\n') V_L=400,V_ph=V_L/sqrt(3) E_bph=V_ph P=4,f=50//Pole and frequency delta_mech=4*(%pi/180) //mechanical angle in degrees by which rotor is behind delta_elec= delta_mech *(P/2) //delta_mech convertd to electrical degrees Z_s=complex(0,2) //synchronous impedance //referring t...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 21 clc; disp("CHAPTER 1"); disp("EXAMPLE 21"); //VARIABLE INITIALIZATION I=20; //current source in Amperes v1=10; //voltage source in Volts v2=40; //voltage source in Vo...
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clc disp('d and n represents the deviation and no. of objects in given sample') n=10 d=0.04 m=0.742 M=0.700 disp('taking the hypothesis that the product is not inferior i.e. there is no significant differene between m and M') t=(m-M)*(n-1)^0.5/d disp('degrees of freedom=') f=n-1
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//signals and systems //example4.5 // X(S) = s+3+5*exp(-2*s)/(s+1)*(s+2)) Re(s)>-1 s1 =%s ; syms t s; [A]=pfss((s1+3)/((s1+1)*(s1+2))); //partial fraction of F(s) F1 = ilaplace(A(1),s,t) F2 = ilaplace(A(2),s,t) //F3 = ilaplace(A(3),s,t) Fa = F1+F2; disp(Fa,"f1(t)=") [B]=pfss((5)/((s1+1)*(s1+2))); //partial ...
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//Example 14.1// //(a)=The mass of each component will be a=1.00;//m^3 //composite b=0.70;//m^3 //Vol % E-glass fibers c=a-b mprintf("c = %f m^3",c) d=2.54;//Mg/m^3 //density Of E-glass mg=d*b mprintf("\nmg = %f Mg",mg) e=1.1;//Mg/m^3 //density of epoxy me=e*c mprintf("\nme = %f Mg",me) w=(mg/(mg+me))*100...
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// Updated(24-7-07) // 10.10 // Kannan Moudgalya, April 2004 num = [-1.117 3.1472]; den = [1 4.6429 5.3821]; G = trfu(num,den); Ts = 0.1; [B,A,k] = myc2d(G,Ts); alpha = 0.5; getf imc_stable.sci; [k,HiN,HiD,R,S] = imc_stable(B,A,k,alpha); [zk,dzk] = zpowk(k); Bp = B; Ap = A;
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// Example 7.6 mode(0); clc; funcprot(0); exec('C:\Users\EJB\OneDrive\Scilab\CLT.sci');// see Appendix E1=45000; E2=12000; G12=5500; //MPa E-glass/Epoxy Table 1.1 v12=0.19; tt=0.6; tk=0.1; //mm F1t=1020; F1c=620; F2t=40; F2c=140; F6=60;//MPa Table 1.1 orientation=[0,90,90,0]; thickness=[3,4,4,3]*tk;//mm n=lengt...
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// Theory and Problems of Thermodynamics // Chapter 5 // Second law of Thermodynamics // Example 7 clear ;clc; //Given data T1 = 300 // ambient atmosphere temperature in K T2 = 600 // reservoir temperature in K TR = 240 // refrigerator temperature i...
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clc; v0=20; //velocity in ft/sec g=32; //gravitational constant in ft/sec t=2; //time in sec v=v0+(g*t); //kinematical equation disp(v,"Velocity in ft/sec = "); //displaying result s=(v0*t)+(1/2)*g*t*t; //kinematical equation disp(s,"Distance in ft = "); //displaying result
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clf c=0.4;xmin=0;xmax=20;N=101; function[y]=f14(x,u) y(1)=u(2); y(2)=c*(1-u(1)^2)*u(2)-u(1); endfunction t=linspace(xmin,xmax,N); y0=0;vy0=1; y=ode([y0;vy0],0,t,f14); comet(y(1,:),y(2,:)) //plot2d(t,y(1,:))
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clc; clear; format('v',6); Pt=10^6; Ddb=23; r=10^4; Pisotropic=Pt/(4*%pi*r^2); D=10^(Ddb/10); P_main_beam=D*Pisotropic; disp(P_main_beam,"The power density radiated in the diection of main beam(in W/m^2)=");
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// to find the longest pulse width // example 9-5 in page 261 clc; //Given data Ri=10e+6;// input resistance in ohm Cc=0.1e-6;// coaxial cable capacitance in farad //calculation printf("pulse width=%.1f s",Ri*Cc/10);// here pulse width=tou/10 seconds //result //pulse width=0.1 s
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function convCAF(celcius) fahrenheit=1.8*celcius+32 printf("La conversion de grados Celsius a Fahrenheit es : %f", fahrenheit) endfunction function convFAC(fahrenheit) celcius=(fahrenheit-32)/1.8 printf("La conversion de grados Fahrenheit a Celsius es : %f",celcius) endfunction
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// Evaluate Vds and Rd // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 7-55 in page 358 clear; clc; close; // Given data b=10^-4; // Constant in A/V^2 Vdd=10; // Drain voltage in V Vt=1; // Voltage expressed in volts Ids=0.5*10^-3; // Drain-s...
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//Chapter-12, Example 12.5, Page 344 //============================================================================= clc clear //INPUT DATA Imax=400*10^-3;//maximum value of current in mA Iav=150*10^-3;//average value of current in mA Vs=100;//maximum value of secondary voltage in V //CALCULATIONS //we know th...
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clc; hR=-281102; hP=2*-393520+3*-241830; h=-hR+hP disp(h,"molar enthalpY is")
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errcatch(-1,"stop");mode(2);//Ex19_11 Pg-962 oct='23'; //binary input dec=oct2dec(oct) //decimal output disp("The decimal equivqlent of 23 is") disp(dec) exit();
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//Example 3_36 clc; clear; close; format('v',6); //given data : f=100;//Hz C=100;//micro F Cdash=200;//micro F//When current is half of maximum L=1/(2*%pi*f)^2/(C*10^-6);//H disp(L,"Inductance(H)"); XL=2*%pi*f*L;//ohm XC=1/2/%pi/f/(Cdash*10^-6);//ohm //at I=Im/2 Z will be 2*R //Im=V/R and I=V/Z=V/sqrt(R^...
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// **** Purpose **** // Given a primitive unit cell and its wannier Hr couling information. // Given another dimension reduced slab. This code tells you sites // that involved the in <n(0)|H|m(R)> calculations in the new slab cell. // **** Variables **** // [pc_vec]: 3x3, real // <= primitive lattice row vectors // [...
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//Example 8.5.2 //Calculate the rain attenuation clc clear Upfreq=17.80 //17.80Ghz //Polarization=vertical kv=0.0510 av=1.0927 elevationangle=45 hs=0.05 hr=4.00 R=63 latitude=25 Ls=((hr - hs)/(sind(elevationangle))) printf("The slant path length is %f km",Ls) Lg=Ls*c...
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clc clear //DATA GIVEN m=0.44; //mass of air in kg T1=180+273; //initial temperature of air in K T2=15+273; //final temperature of air in K W12=52.5; //work done during the process in kJ //V2/V1=3 Vr=3; ...
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//Part B Chapter 4 Example 13 clc; clear; close; b=30;//mm(thickness) l=8;//m d=260;//mm D=d+2*b;//mm N=300;//rpm tau_s=16;//N/mm^2 Gs=8.5*10^4;//N/mm^2 Gb=4.5*10^4;//N/mm^2 Ips=%pi/32*d^4;//mm^4 Ipb=%pi/32*(D^4-d^4);//mm^4 TsByTb=Ips/Ipb*Gs/Gb; Ts=%pi/16*d^3*tau_s;//Nmm Tb=Ts/TsByTb;//Nmm T=Ts+Tb;//Nm...
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//To calculate the glancing angle n = 2; //second order h = 1; k = 1; l = 0; //plane (110) lamda = 0.065; //wavelength of X-rays, nm lamda_m = lamda*10^-9; //wavelength of X-rays, m a = 0.26; //axial length, nm a_m = a*10^-9; //axial length, m x = sqrt(h^2+k^2+l^2); theta = asind(n*lamd...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 10 Example 6") N=3000;//engine rpm m=5;//fuel consumption in litre/hr r=19;//air-fuel ratio sg=0.7;//specific gravity of fuel V=500;//piston speed in m/min P_...
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clear(); exec("mulsamp.sci",2); exec("mulprobln.sci",2); exec("mulluck.sci",2); exec("numlucksetup.sci",2); exec("numluck.sci",2); // get sample set nsamps=10000; ntrials=100; p=[0.1;0.2;0.3;0.4]; x=mulsamp(nsamps,ntrials,p); problns=mulprobln(x,p); // setup for luck estimates setup=numlucksetup(problns); // estima...
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//Example 2.19://error clc; clear; close; n=40;//revolutions rc=0.12;//registration constant err=n/rc;//energy recorded in kWh is e2=22000;//volts e1=110;//volts i2=500;//amperes i1=5;//amperes i=5.25;//amperes lv=110;//volts pf=1;// t=61;//seconds ae=((sqrt(3)*e2*lv*i*i2*pf*t)/(e1*i1*3600))*10^-3;//kWh e=((err-ae)/ae)...
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//Example 2.7.3.b: Average deviation clc; clear; close; //given data : n=10; X1=147.2;// in nF X2=147.4;// in nF X3=147.9;// in nF X4=148.1;// in nF X5=148.1;// in nF X6=147.5;// in nF X7=147.6;// in nF X8=147.4;// in nF X9=147.6;// in nF X10=147.5;// in nF AM=(X1+X2+X3+X4+X5+X6+X7+X8+X9+X10)/n; d1=X1-AM; d2=X2-AM; d3=...
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//to calculate rotational loss ,armature resistance,eff,line current and speed clc; Pshaft=20000; eff=.89; P_L=((1/eff)-1)*Pshaft; Pin=Pshaft+P_L; V=250; I_L=Pin/V;disp(I_L,'line current(A)'); Rf=125; If=V/Rf; Ia=I_L-If; Ploss=P_L/2; Ra=Ploss/Ia^2;disp(Ra,'armature resistance(ohm)'); Psh=V*If; Prot=Pl...
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clc //initialisation of variables P= 1 //atm T= 11 //C Tsat = 170.03 Csf= 0.006 r= 1/3 s= 1 dt = Tsat - T cl= 4.218 //J/gm K hfg= 2257 //J/gm Pr= 1.75 ul= 283.1*10^-3 //gm/m s s= 57.78*10^-3 //N/m pl= 958*10^3 //gm/m^3 pv= 598 //gm/m^3 gc= 10^3 //gm m/N s^2 g= 9.8 //m/s^2 //CALCULATIONS p= pl-pv q= ((((cl*dt)/(hfg*Csf*...
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errcatch(-1,"stop");mode(2);//Example 5_1_u2 ; ; //To find the temprature where would be the critical field hc=0.070 //units in K ho=0.0803 //units in K tc=7.22 //units in K T=tc*sqrt(1-(hc/ho)) //units in K printf("Temprature T=%.2f K",T) //Given in textbook T=2.94K But the correct...
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// Scilab Code Ex3d.1: Page-205 (2008) clc; clear; D = 200; // Distance between the source and the slit, cm a = 0.02; // Slit width, cm x = 0.5; // Position of first minimum, cm n = 1; // Order of diffraction lambda = a*x/(D*n); // Wavelength of light used, cm printf("\nThe wavelength of light use...
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h_alpha=[L_alpha(5)-st; X_alpha-L_alpha(4); L_alpha(3)-20+L_alpha(1)*(L_alpha(7)+R1); L_alpha(3)+L_alpha(2)*(L_alpha(9)+R1); X_alpha-L_alpha(1)-L_alpha(2); R2-L_alpha(7)-R1; L_alpha(5)-L_alpha(4)+L_alpha(6); R2-L_alpha(9)-R1; -L_alpha(3)+L_alpha(8)]; g_alpha = (L_alpha(3)-L_alpha(4))/sL;
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clc //initialisation of variables clear d= 6//ft x= 4 //ft w= 62.4 //lbf/in^2 //CALCULATIONS Ig= %pi*d^4/64 A= %pi*d^2/4 Io= Ig+A*x^2 h= Io/(A*x) P= w*A*x //RESULTS printf ('Depth of centre of pressure = %.2f ft',h) printf (' \n Total pressure on plate = %.f Lb',P-7)
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function [out]=pyramid(inputimage,direction,level) // Computes the pyramid reduction or expansion of input_image // // Calling Sequence // output_image=pyramid(inputimage,direction,level); // // Parameters // // inputimage : image matrix on which pyramid reduction or expansion has to be applied // Direction : An input...
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//Transport Processes and Seperation Process Principles //Chapter 13 //Example 13.2-2 //Membrane Seperation Processes //given data //nomenclature similar to previous problem c1=200;//urea in g/m3 c2=0; kc1=1.25e-5; pm=8.73e-6; kc2=3.33e-5; Na= (c1-c2)/((1/kc1)+(1/pm)+(1/kc2)); A=2;//area in m2 R=Na*3600*A;...
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//coefficient// s=%s; syms k t; y=k/((s+1)*s^2*(s+4)); disp(y,"G(s)H(s)=") r=1+(8*t)+(18*t^2/2); disp(r,"r(t)=") R=laplace(r,t,s); disp(R,"R(s)=") e=limit((s*R)/(1+y),s,0) disp(e,"Ess=") printf('Given Ess = 0.8 \n") e=0.8; k=72/e; disp(k,"k=")
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 2.13 //calculation of average focal length of concave mirror considering uncertainity //given data fi=[25.4 25.2 25.6 25.1 25.3 25.2 25.5 25.4 25.3 25.7]; //focal length(in cm) N=length(fi); //calculation fbar=mea...
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clear ; clc ; d = 1;//diameter of the steel bar in inches l = 12;//length of the steel bar in inches d1 = 3/2;//external diameter in inches d2 = 1;//internal diameter in inches P = 5;//axial pull in tons E_s = 30*10^6;//modulus of elasticity of steel in lb/in^2 E_b = 14*10^6;//modulus of elasticity of brass in ...
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function f=%s_d_r(n1,f2) // n1./f2 //! // Copyright INRIA if size(n1,'*')==0 then f=[],return,end f=rlist(n1.*f2('den'),ones(n1).*f2('num'),f2('dt'))
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java -ea trip.Main -m trip-tests/explore02 <<EOF INYSTBC-87, Poughkeepsie, I87-287 I95-87, East_Harlem, Troy EOF
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clc clear //Input data C=61;//The mass of carbon present in the coal according to coal analysis on mass basis in % H=4;//The mass of hydrogen present in the coal according to coal analysis on mass basis in % O=3;//The mass of oxygen present in the coal according to coal analysis on mass basis in % N=2;//The mass...
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errcatch(-1,"stop");mode(2);; ; a=2*10^-3,b=6*10^-3,t=10^-3,l=2,c=5.8*10^7; Ri=l/(c*%pi*a*a); Ro=l/(c*%pi*((b+t)^2-b^2)); Rdc=Ro+Ri; disp(Rdc*10^3,'Resistance in mOhm'); exit();
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex3_27(b).sce clc; clear; //case(b) //from case(a) result v(t)=5+6.36 sin(t)+2.12 sin(3t)+1.27 sin(5t) V0=5 V1=6.36/sqrt(2); V3=2.12/sqrt(2); V5=1.27/sqrt(2); ...
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clear //Given V=1.5 a=1.5 r1=0.5 //ohm r2=0.25 R=2.25 //ohm //Calculation E=V+a r=r1+r2 Rt=r+R I=E/Rt pd=V-(I*r1) pd1=V-(I*r2) //Result printf("\n (i) The circuit current is %0.3f A",I) printf("\n (ii) P.D across the terminals of each cell is %0.3f V and %0.3f V",pd,pd1)
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z=poly(0,'z'); sys=syslin('d',(z-1)/(z^2+z+1)); //example taken from http://in.mathworks.com/help/control/ref/evalfr.html p1=evalfr(sys,1+%i) aa=pid(rand(2,2,1),3,4,5); p2=evalfr(aa,1+%i) bb=syslin('c',[1,3;4,5],[5,6;8,9],[2,3;4,5],[1,2;8,9]); p3=evalfr(bb,1+%i); s=poly(0,'s'); ab=syslin(...
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clc; clear; format('v',6); r0=[1,0,0]; //Position vector ro r1=[0,1,0]; //Position vector r1 r2=[0,0,1]; //Posi...
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// Exa 1.24 clc; clear; close; // Given data V_S = 2;// in V R = 100;// in ohm I_D = V_S/R; I_D = I_D * 10^3;// in mA disp("Part (a)") disp(I_D,"The diode current in mA is"); V_K = 0.7;// in V I_D1 = (V_S-V_K)/R; I_D1 = I_D1*10^3;// in mA disp("Part (b)") disp(I_D1,"The diode current in mA is"); R_f = 3...
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v = [0,1]; for k = 1:100 v = [v,v($)+v($-1)]; end disp(v) passo = %pi/10; for x=0:passo:%pi/2 disp([x,cos(x)]); end A = [3 2 2 1;1 3 0 3;1 1 5 4;3 3 2 2]; B = [3;5;4;2;]; x = inv(A)*B; disp(x)
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czwarte.sce
clear; clc; X=[1;2;3;5;5;6;7;8]; n=7; x_dach=%pi/2 function Y=f(X); for i=0:n Y(i+1)=sin(X(i+1)); end endfunction Y=f(X) function wynik=omega (x,X,n) wynik=1 for i=0:n wynik=wynik*(x-X(i+1)) end endfunction function wynik=odle(X,n) hi=X(2)-X(1) wynik=[1,hi]; for...
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//Example 3.10.1// multiplier clc; clear; close; //given data : V1=200;//in V V2=100;//in V V3=10;// in V Rm=100;//in ohm I_fsd=50*10^-3; //for the range 0-10V Rt3=V3/I_fsd; Rs3=Rt3-Rm; disp(Rs3," the multiplier,Rs3(ohm) = ") //for the range 0-100V Rt2=V2/I_fsd; Rs2=Rt2-(Rm+Rs3); disp(Rs2,"the multiplier,Rs2(ohm) = ...
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//Calculate (a) the voltage gain Av and (b) the current gain Ai. //Example 6.7 page no 178 clear clc hfe=90 Rl=800//Ω Rc=800//Ω Rb=831//kΩ hie=200 hoe=100*10^-6 Av=-((hfe*Rl*Rc)/(hie*(Rc+Rl+hoe*Rl*Rc))) //voltage gain Av Ai=((Rb*hie)/(Rl*(Rb+hie)))*Av //current gain Ai printf("\n The value of...
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// Grob's Basic Electronics 11e // Chapter No. 15 // Example No. 15_1 clc; clear; // A sine wave of voltage varies from zero to a maximum of 100 V. How much is the voltage at the instant of 30° of the cycle? 45°? 90°? 270°? // Given data Vm = 100; // Vm=100 Volts t1 = 30; // Theta 1=30°. t2 = 4...
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clear// //Variables VCC = 15.0 //Source voltage (in volts) RE = 2.0 //Emitter Resistance (in kilo-ohm) RC = 1.0 //Collector Resistance (in kilo-ohm) R1 = 10.0 //Resistance (in ki...
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import React, { Component, useState } from 'react'; import { fade, makeStyles, Theme, createStyles } from '@material-ui/core/styles'; import AppBar from '@material-ui/core/AppBar'; import Toolbar from '@material-ui/core/Toolbar'; import IconButton from '@material-ui/core/IconButton'; import Typography from '@material-u...
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// Ballarin Léa // Mercier Marielle // A ones(1, 50)*0 ones(1, 50).*10 z = 0:0.3:10 linspace(-3, 7, 50) (2 .* ones(0,25)) .^linspace(1, 25, 25) // B // 1 function r = f(x) r = (1 + x) .* sin(%pi .* x) endfunction x = linspace(-2, 2, 100) y = f(x) fenetre = figure("Figure_name", "Equation", "position", [100 ...
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clc; clear all; t = 50; // Thickness of the metal in mm d = 1; // Hole diameter in mm ss = (d/t)*100;//The percentage sensitivity of the wire disp('%',ss,'The percentage sensitivity of the wire is')
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2018-02-03T05:31:52
37,975,407
3
12
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null
null
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UTF-8
Scilab
false
false
1,678
sce
Ex13_2.sce
printf("\t example 13.2 \n"); printf("\t approximate values are mentioned in the book \n"); printf("\t bubble point at 95F and 14.7psia \n"); x(1)=0.077; // mole fraction of C4 x(2)=0.613; // mole fraction of C5 x(3)=0.310; // mole fraction of C6 K(1)=3.13; // fig 7 K(2)=0.92; // fig 7 K(3)=0.3; // fig 7 a(1)=...