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// Example 11.3: (a) Output voltage // (b) Input voltage clc, clear B1=36; // Fundamental output in volts B2=7*B1/100; // Second-harmonic distortion in volts Vs=0.028; // Input in volts A=B1/Vs; // Gain disp("Part (a)"); b=1.2/100; // Amount of feedback in volts B1f=B1/(1+b*A); // Fundamental o...
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//Chapter 6 //Example 6_12 //Page 115 clear;clc; sm=100; im=200; pf2=0.707; n2=0.82; ll=30; fc=100; rc=0.06; pf1=0.8; n1=0.93; printf("(i) When synchronous motor runs at %.1f pf lag:\n\n", pf1); ip_sm=sm*735.5/n1/1000; lag1=ip_sm*tan(acos(pf1)); printf("\t Input to synchronous motor = %.2f kW \n", ip_sm); printf("\t...
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005]...
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clc clear //Initialization of variables mr=3 //lb mj=5 //lb t2=67 //F t1=60 //lb ihp=7.25 //calculations disp("From mollier charts,") h4=709 //Btu/b h3=618 //Btu/lb energyin=ihp*2545/60 energyout=mr*(h4-h3) + mj*(t2-t1) //results printf("Energy in = %.1f Btu/min",energyin) printf("\n Energy out = %.1f B...
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function id=dmumps(id,mat) //************************************************************************************************************** // [id] = dmumps(id,mat) // id is a structure (see details in initmumps.m and MUMPS documentation) // mat is an optional parameter if the job id.job = -1 or -2 // mat is a square...
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clc T1=303; //K p1=1; //bar rc=9; re=5; n=1.25; D=0.25; //m L=0.4; //m R=287; cv=0.71; cp=1; num=8; //no. 0f cycles/sec disp("(i) Pressure and temperatures at all salient points =") p2=p1*(rc)^n; disp("p2=") disp(p2) disp("bar") T2=T1*(rc)^(n-1); disp("T2=") disp(T2) disp("K") //T4=1.8*T3 //...
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clc //initialisation of variables v=60//m/sec a=30//mm b=120//mm //CALCULATIONS V=v*(b/a)//mm/sec //RESULTS printf('the velocity of the follower it the groove=% f mm/sec',V)
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clc clear //INPUT DATA p3=20;//Pressure of air in bar v3=0.2;//volume of air in m^3 Th=500;//engine temprature in Degree C v23=7;//Isentropic compression ratio v43=2;//Isentropic volume expansion v3=0.2;//volume in m^3 //CALCULATIONS Tl=(Th+273)/((v23)^(1.4-1));//minimum temperature in K p2=p3/((v23)^(1.4)...
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syms k1 k2 s T= k1/(s^s+k1*k2*s+k1) Mp=25 //given zeta=0.4037 Tp=4 omegaN=%pi/(Tp*(sqrt(1-zeta^2))) disp(omegaN,"omegaN = ") k1=omegaN^2 disp(k1," k1 = ") k2=2*zeta/(sqrt(k1)) disp(k2," k2 = ")
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 12: POWER,ENERGY,AND EFFICIENCY RELATIONS OF DC AND AC DYNAMOS // Example 12-9 clear; clc; close; // Clear the work space and console. // Given data V = 240 ; // Voltage rating of dc shunt motor i...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.274905D+00 ...
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//Calculate the Wavelength in nanometer for transition in Hydrogen atom //Example 14.3 clc; clear; nf=2; //Quantum number for emmision process (n=4 to 2) ni=4; //Quantum number for emmision process (n=4 to 20) RH=109737; //Rydberg constant in cm^-1 new=RH*abs((1/ni^2)-(1/nf^2)); //Frequency in c...
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clc //initialisation of variables d=0.24//ft p1=40//psia t=240//F p2=39//psi t2=70//F b=26.48//in f=200//cu ft h=0.491//ft w=144//ft q=53.35//ft t3=700//ft //CALCULATIONS P=p1+h*b//psia W=(w*P*f)/(q*t3)//lb per min H=W*d*(t-t2)//Btu per min //RESULTS printf('The heat removed from the air =% f Btu per ...
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clear;lines(0); s=poly(0,'s') h=syslin('c',(s^2+2*0.9*10*s+100)/(s^2+2*0.3*10.1*s+102.01)) title='(s^2+2*0.9*10*s+100)/(s^2+2*0.3*10.1*s+102.01)'; bode(h,0.01,100,title); h1=h*syslin('c',(s^2+2*0.1*15.1*s+228.01)/(s^2+2*0.9*15*s+225)) xbasc() bode([h1;h],0.01,100,['h1';'h'])
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <TestCase> <Step> <EventId>e31</EventId> <ReachingStep>false</ReachingStep> </Step> <Step> <EventId>e84</EventId> <ReachingStep>false</ReachingStep> </Step> <Step> <EventId>e62</EventId> <Reaching...
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//example9.10 clc disp("It can be observed from the Lissajous figures that,") disp("(y_1)=8 units and, (y_2)=10 units") s=asind(8/10) format(6) disp(s,"Therefore, phi (in degree)= asind((y_1)/(y_2))=asind(8/10)=")
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// Exa 6.2 format('v',6); clc; clear; close; // Given data R1= 50;// in kohm R1=R1*10^3;// in ohm R2=R1;// in ohm R3=R2;// in ohm C1= 60;// in pF C1= C1*10^-12;// in F C2=C1;// in F C3=C2;// in F f= 1/(2*%pi*R1*C1*sqrt(6)); disp(f*10^-3,"Frequency of oscilltions in kHz is : ")
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// Exa 3.2 clc; clear; close; // Given data P = 350;// in kN/m^2 P = P * 10^3;// in N/m^2 m = 1;// in kg m = m * 10^3;// in gram V = 0.35;// in m^3 C_p = 1.005;// in kJ/kg-K C_v = 0.710;// in kJ/kg-K R = C_p - C_v;// in kJ/kg-K T = (P*V)/(m*R);// in K T = T - 273;// in degree C disp(T,"The intial tempera...
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//Ex 5.1 clc;clear;close; format('v',5); kVA=250;//kVA V1=11000;//V(Primary voltage) V2=400;//V(secondary voltage) f=50;//Hz N2=80;//no. of turns in secondary Ifl1=kVA*1000/V1;//A(Full load primay current) Ifl2=kVA*1000/V2;//A(Full load secondary current) disp("Part(a)"); disp(Ifl1,"Full load primary current...
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clc //initialisation of variables clear T= 95.5 //C p= 1 //atm v= 0.0126 //cc g^-1 a= 0.0242 //cal cc^-1 atm^-1 r= 0.035 //K atm^-1 //CALCULATIONS dH= (273.2+T)*v*a/r //RESULTS printf ('Heat of transition = %.1f cal g^-1',dH)
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//Variable declaration Ro=7.5 //output resistance(ohms) hfe=50 Ve=20 //voltage given to emitter(V) Vbe=0.8 //base to emitter voltage(V) Vc=15 //collector voltage(V) P...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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// Exa 9.14 clc; clear; close; // Given data I_D = 0.3;// in mA k = 0.12;// in mA/V^2 V_T = 1;// in V V_GS = V_T + (sqrt(I_D/k));// in V V_S = -V_GS;// in V V_DD = 6;// in V V_D = 3;// in V I_DQ = 0.3;// in mA R_D = (V_DD-V_D)/I_DQ;// in k ohm disp(R_D,"The value of R_D in k ohm is"); V_DS = V_D - V_S;//...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function y=SSSeSourceDirac() // Electrical Dirac Impulse // // Calling Sequence // y=SSSeSourceDirac() // // Parameters // y : Electrical Output // // Description // Generates an el...
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// Calculate the temperature at a depth of 1000 m clc; th0=20; t=2000; thr=th0-0.005*(t-50)-0.25*exp(-t/50); disp(thr,'temperature at a depth of 1000 m (degree C)')
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//<f2>=%psr(n1,f2) // %psr(n1,f2) calcule la soustraction de la matrice de polynome n1 et //de la matrice de fractions rationnelles f2. //Cette macro correspond a l'operation n1-f2 //! [n2,d2]=f2(2:3), [n2,d2]=simp(n1.*d2-n2,d2) f2(2)=n2;f2(3)=d2; //end
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// my first program Scilab a=0;b=1;n=100; x=linspace(a,b,n+1); y=exp(-x).*sin(4*x); plot(x,y);
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//Example 6-10// //Map L=W''X''YZ+WX''YZ''+WX''Y''Z''+W''XYZ// clc //clears the console// clear //clears all existing variables// //Mapping the expression// disp(' C''D'' C''D CD CD'' ') disp('A''B'' 0 0 1 0 ') disp('AB'' 0 0 1 0 ') disp('AB 0 0 0 0 ') disp('AB'' ...
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000080 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x000000b4 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x00 0x14 cp r0, r0 0x2: 0x10 0x14 cp r...
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q = 1 ; // Uniform load intensity in k/ft M0 = 12 ; // Couple in k-ft Rb = 5.25 ; // Reaction at B in k Rc = 1.25 ; // Reaction at C in k b = 4 ; // Length of section AB in ft Mb = -(q*(b^2))/2 ; // Moment acting at B disp("k-ft",Mb,"Bending moment at B")
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//to calculate net power op,eff,line current and pf clc; j=sqrt(-1); Zs=(1/3)*(.3+j*6); phi=atand(imag(Zs)/real(Zs)); Vt=400/sqrt(3); Ef=600/sqrt(3); a=sqrt(Vt^2+Ef^2-2*Vt*Ef*cosd(phi)); Ia=a/abs(Zs);disp(Ia,'line current(A)'); B=acosd((Vt^2+a^2-Ef^2)/(2*Vt*a)); phi=90-(90-atand(imag(Zs)/real(Zs)))-B;disp...
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function [out] = GeometricShearer(inputimage,direction,value) // Shear the image // // Calling Sequence // output_image = GeometricShearer(inputimage,direction,value); // // Parameters // // inputimage : image matrix on which geometric shear has to be applied // direction : An input string that like. 'Horizontal' to s...
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//Chapter 2: Antenna Basics //Example 2-3.2 clc; //Variable Initialization e_half_power = 1/sqrt(2) //E(theta) at half power(unitless) e_null = 0 //E(theta) = 0 at null points (unitless) theta_1 = 0 //theta' (degrees) theta = 1 //theta (degrees) //Calculation for x=0:2 //loop untill theta = i th...
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Asys=4200//area of system Acell=12//area of cell N=1001 K=7 Acl=K*Acell//area of cluster M=Asys/Acl//no. of clusters disp(M,'no. of clusters') J=N/K//cell capacity disp(J,'cell capacity in channels/cell') C=N*M//system capacity disp(C,'the system capacity in no. of channels') k=4 acl=k*Acell m=Asys/acl m1=floor(m) disp...
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clear clc Vc=220 Z=2*complex(.15, .2) Z1=.5*Z Z2=.5*Z Ib= 60 * exp (%i * -acos (.9)) Ic= 100 * exp (%i * -acos (.8)) Vb=Vc + (Ic * Z2) Iab=Ib + Ic Va=Vb + (Iab * Z1) Vs=abs(Va) Is= abs(Iab) pf=cosd(abs(atand(imag(Va)/real(Va))+abs(atand(imag(Iab)/real(Iab))))) mprintf("\nsending end voltage ...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 7 //Properties of Solutions //Example 4 clear; clc; //Given: V1_w = 0.816*10^-3; //partial molar volume of water in 96% alcohol solution V1_e = 1.273*10^-3; //partial molar volume of ethanol in 96% alcohol solution V2_w = 0.953*10^-3; //part...
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clc clear //input data Cr2=28//Radial component of velocity at impeller exit in m/s ss=0.9//The slip factor U2=350//The impeller tip speed in m/s A=0.08//The impeller area in m^2 nc=0.9//Total head isentropic efficiency T01=288//The ambient air temperature in K P01=1//The ambient air pressure in bar r=1.4//Th...
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//Example 4.19 //Program to Compute the FFT of given Sequence x[n]=[1,0,0,0,0,0,0,0]. clear; clc ; close ; x = [1,0,0,0,0,0,0,0]; //FFT Computation X = fft (x , -1); disp(X,'X(z) = ');
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//for the jet power executive aircraft(CJ-1): b=16.25;//wingspan(meter) S=29.54;//wingarea(m^2) AR=b^2/S;//aspect ratio D=1.225;//density at sea level(Kg/m^3) W=88176.75;//normal gross weight(N) f=1119;//fuel capacity Tf=16245;//thrust (N) provided by single turbofan engine Sf=0.102;//specific fuel consumption(...
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//laplace transform of unit function syms t s y=laplace('1',t,s) disp(y,"F(s)=") // test
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<cmd> ../build/42sh</cmd> <ref> bash</ref> <stdin> if true then echo toto | cat -e fi; </stdin>
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clc;clear;close; wavread("ibat.wav","size") [y,Fs,bits]=wavread("ibat.wav"); figure; //plot(y(1,:)); xtitle('Vowel a'); xlabel('bits'); ylabel('recorded signal'); y=wavread("ibat.wav") plot(y(1,:)); yconj=conj(y); l=length(y); N=2*l-1; y=[y zeros(1,N-l)]; yconj=[yconj zeros(1,N-l)]; for lag=1:N; R(lag)=0; for i...
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<?xml version="1.0" ?> <TestCase name="ss" version="5"> <meta> <create version="8.2.0" buildNumber="8.2.0.244" author="rkrishn8" date="08/22/2017" host="LP-R9WHCBM" /> <lastEdited version="8.2.0" buildNumber="8.2.0.244" author="rkrishn8" date="08/29/2017" host="LP-R9WHCBM" /> </meta> <id>27732194871C11E7AD1F2E...
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clc disp("Example 7.41") printf("\n") disp("sketch the frequency spectrum") printf("Given\n") disp("carrier amplitude=10V,carrier frequency=10MHz,Modulating frequency=1Khz,MI=0.5") Vc=10 fc=10^7 fm=10^3 ma=0.5 wc=2*%pi*fc wm=2*%pi*fm t=10^-7 v=Vc*(1+(ma*sin(wm*t)))*cos(wc*t) Vs=(ma*Vc)/2 flsb=fc-fm fusb...
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clc //given Tb=27 Tc=30 Td=24 Te=21 k=Te*Tb/(Tc*Td)//k=Nd/Ne //by applying componendo and dividendo, using Ne=0 and reducing we get a=(1-k)//where a = Nd/Na b=1/a printf("\nThe ratio of the speed of driving shaft to the speed of driven shaft\n\nNa/Nd = %.2f",b)
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clear; clc; close; t = 273 + 27; //in kelvin t_new = 273 +100; k = 1.38*10^(-23);//in J/K q = 1.6*10^(-19);//C Vt = k*t/q; format(10); disp(Vt,'Thermal voltage for 27''C(in V): '); Vt = k*t_new/q; disp(Vt,'Thermal voltage for 100''C(in V): ');
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function [Q,R] = qrhouse(A) // Funcion que realiza la factorizacion QR mediante transformaciones de // Householder. // **************************************************************************** // Entrada // A (Matriz Real) - Matriz de tamaño m x n con entradas reales. // // Salida // Q (Matriz Real) - Matriz or...
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//Chapter-5,Example 2,Page 122 clc(); close(); t=[7.18 18 27.05] //time in minute r=[ 21.4 17.7 15] //rotation in degrees r_0=24.09 r_a=-10.74 k=(1 ./t).*log10((r_0-r_a)./(r-r_a)) printf('values of k') disp(k) printf('since k values are fairly constant by putting in 1nd order rate equat...
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// Grob's Basic Electronics 11e // Chapter No. 14 // Example No. 14_5 clc; clear; // A magnetic material has a ur of 500. Calculate the absolute u as B/H (a) in CGS units and (b) in SI units. // Given data ur = 500; // ur=500 uoa = 1; // uo for CGS Units=1 uob = 1.26*10^-6; // uo for SI U...
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a=1; x=-1:0.01:1; y=2*a*sqrt(1-(x^2/a^2)) plot(x,y) plot(x,-y) y=sqrt(a^2-x^2) plot(x,y) plot(x,-y)
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// Copyright INRIA files=G_make(['/tmp/ex4cI.o'],'ex4c.dll') ; addinter(files,'cdgemmentry','dgemm'); alfa=2;beta=3;m=3;n=4;C=ones(m,n);k=2;A=ones(m,k);B=ones(k,n); C1=dgemm(alfa,A,B,beta,C); if norm(C1-(alfa*A*B+beta*C)) > %eps then pause,end
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//To determine the Demand and supply parameter of four consumers //Page 74 clc; clear; //Maximum Demands of various users MD1=2*(10^3); //9pm MD2=2*(10^3); //12 noon MD3=8*(10^3); //5pm MD4=4*(10^3); //8pm MDT=MD1+MD2+MD3+MD4; //Sum of all Maximum Demands //Demands of various users D1=1.6*(10^3); //8pm ...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.54(PAGENO 537)"); //given P_x1 = 1/3//probability of first signal P_x2 = 1/6//probability of second signal P_x3 = 1/4//probability of third signal P_x4 = 1/4//probability of fourth ...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Rosenberg, J and Mah, R S H and Iordache, C //Evaluation of Schemes for Detecting and Identifying Gross Errors in Process Data //Ind. & Eng. Chem. Pro...
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//Initilization of variables W=1000 //N Lab=1 //m Lac=0.6 //m theta=60 //degree //angle made by the beam with the horizontal //Calculations Q=(W*Lac*cosd(theta))/(Lab*cosd(theta)) //N // from eq'n 2 P=W-Q //N // from eq'n 1 //Results clc printf('The load taken by man P is %f N \n',P) printf('The load taken b...
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// Calculating the hysteresis loss clc; disp('Example 3.13, Page No. = 3.35') // Given Data Bm = 1.0;// Maximum flux density in Wb per meter square f = 50;// Frequency in Hz SGi = 7.5;// Specific gravity of iron ph = 4.9;// Hysterseis loss in W per Kg // Calculation of co-efficient 'n' Di = 7500;// Density of ...
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// Scilab Code Ex7.2:: Page-7.8 (2009) clc; clear; n1 = 1.50; // Refractive index of core material of fibre n2 = 1.47; // Refractive index of cladding material of fibre phi_C = asind(n2/n1); // Critical angle of optical fibre, degrees NA = sqrt(n1^2-n2^2); // Numerical aperture for the fibre thet...
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//Example 11.10 //Gauss Seidel Method //Page no. 382 clc;clear;close; O=0.5; A=[-8,8,0;2,-8,4;0,4,-8]; //equation matrix B=[-1;-1;-1]; //solution matrix Ov=inv(A)*B; disp(Ov,'Values = ') Ox=Ov(1)+(Ov(1)-O)/3 disp(Ox,'O* = ')
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errcatch(-1,"stop");mode(2);// Exa 2.6 ; ; // Given data Ad= 100; Acm= 0.01; CMRR= Ad/Acm; CMRR_desh= 20*log10(CMRR);// in dB disp(CMRR_desh,"CMRR in dB") exit();
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//Exa 1.6 clc; clear; close; //given data lambda=1.539;//in Angstrum theta=22.5;//in degree n=1;//order unitless d=n*lambda/(2*sin(theta*%pi/180));//in Angstrum disp(d,"Interpolar distance in Angstrum : ")
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function [x,y,z] = eula2(a,b,h,y0,z0) x = a:h:b y(1) = y0 z(1) = z0 n = length(x) for i = 2: n y(i) = y(i-1)+h*df1(y(i-1),z(i-1)) z(i) = z(i-1)+h*df2(y(i-1),z(i-1)) end endfunction function g = df1(y ,z) g = (z) endfunction function j = df2(y, z) j = (12-y-...
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#it does not match the risto "optimum MMN" paper scenario = "PS3_roving_combination_MMNc_01072015"; #adapted from "nvMMNa5_napls06122009"; #attenuation updated for ER1 insert earphones and X-fi gamer card #Note: this is based on the baldeweg-style of pitch deviance with #the additional constraint that a transition b...
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errcatch(-1,"stop");mode(2);//// exec("1.3data.sci"); //CA = 0.1*CA0; V = (v0/k)*log(1/0.1); disp("V =") disp(V) disp ("dm^3") exit();
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// Example 4_8 clc;funcprot(0); // Given data phi_e=120;// V R=144;// ohm t=1.50;// h // Solution // (a) i_e=phi_e/R;// A W_12=-phi_e*i_e*t;// The electrical current work in W.h // (b) W_ec=-phi_e*i_e;// W printf('\n(a)The electrical current work,W_12=%3.0f W.h \n(b)The electrical power consumption,W_elec...
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foo=2.05*10^6 fc=2*10^6 Zo=75 Wc=2*%pi*2*10^6 L=Zo/Wc*2 C=2/(Zo*Wc) m=sqrt(1-(fc/foo)^2) printf("\nm=%.4f",m) printf("\nm*L/2=%.2e H",m*L/2) printf("\nm*C=%.3e F",m*C) printf("\n(1-m^2)*L/4/m=%.2e",(1-m^2)*L/4/m)
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// Ex9_4 Page:175 (2014) clc;clear; PI = 3.14; u = 1.67e-027; // Mass equivalent of 1 amu, kg/amu c = 3e+008; // Speed of light in vacuum, m/s lambda0 = 3.465e-006; // Wavelength of vibrational absorption line of HCl molecule, m m1 = 1.0087; // Mass of H atom, amu m2 = 35.453; // Mass of Cl atom, ...
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//Chapter-1,Example1_14_20,pg 1-66 n=8 //Diamond structure ro=2.33*10^3 //density of diamond M=28.9 //atomic weight of diamond N=6.023*10^26 //Avogadro's number a=((n*M)/(N*ro))^(1/3...
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// to be included in synthdata_trifocal.sce T__1 = R_1*T_w_vec; T__2 = R_21*T__1; T__3 = R_31*T__1; // Starting here we treat the 2D vectors as 3D vectors // Apply the inverse K matrix! t__1_vec_img = [t__1_vec_img; zeros(1,size(t__1_vec_img,2))] t__2_vec_img = [t__2_vec_img; zeros(1,size(t__2_vec_img,2))] t__3_vec_i...
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// Chapter 5 Example 4 //============================================================================== clc; clear; //input data lamda = 1.5418; // wavelength in Å h = 1; // miller indice k = 1; // miller indice l = 1; // miller indice n = 1; ...
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let seq = (Seq [(Assign ("X") (Const 1)), (Cond (Gt (Var "X") (Const 0)) (Seq [(Assign ("Z") (Const 1))]) (Seq []))]) let symt = (SymTable []) let ent = [] interpretCommand symt ent seq
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//Chapter 13 //Example 13_17 //Page 329 clear;clc; l=1000; i=1.25; r_km=0.05; r=2*r_km/1000; I=i*l; R=r*l; vd=I*R/8; //Part 1 is derivation of maximum voltage drop and is not included in the code. Only Part 2 is solved. printf("(i) Total current supplied by distributor = %d A \n\n", I); printf("Total resistance o...
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// Scilab code Ex14.8 : Pg:723(2011) clc;clear; I = 55e-03; // Forward current through Si diode, A V = 3; // Forward bias across Si diode, V eta = 2; // Ideality factor for Si diode R_dc = V/I; // Static diode resistance, ohm R_ac = 0.026*eta/I; // Dynamic diode resistance, ohm printf("\nT...
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clc clear disp('example 13 11') n1=5;x=0.4;d=0.1;g=20 //given mva=(g/x)+(g*(n1-1)/(x+n1*d)) n2=10 //given mva2=(g/x)+(g*(n2-1)/(x+n2*d)) disp('a') printf("fault MVA =(g/x)+(g*(n-1)/(x+nd)) \n fault level is to equal to fault MVA if n=infinity") disp('b') printf(" MVA=%.2fMVA if n=%d \n MVA=%.2fMVA if n=%d",...
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// Exa 6.31 clc; clear; close; // Given data m1 = 3;// in kg m2 = 2;// in kg T1 = 10;// in degree C T2 = 80;// In Degree C T = ((m1*T1)+(m2*T2))/(m1+m2);// in degree C T = T + 273;// in K T1 = T1 + 273;// in K T2 = T2 + 273;// in K c_f = 4.188; del_phi1 = m1 * c_f*log(T/T1);// in kJ/K del_phi2 = m2 * c_f...
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n = 69; k = 8; x = [ [1, 1, 1, 50.7, 15.4, 8.2, 0, 1, 0, 15.9]; [1, 3, 1, 88.9, 31.2, 10.7, 0, 1, 0, 27.0]; [1, 1, 1, 45.2, 12.3, 10.7, 0, 1, 12, 13.5]; [1, 1, 1, 50.7, 15.4, 8.5, 0, 1, 12, 15.1]; [1, 2, 1, 71.1, 21.5, 10.7, 0, 1, 12, 21.1]; [1, 3, 1, 97.1, 35.6, 10.7, 0, 1, 12, 28.7]; [1, 3, 1, 93.2, 35.3, 10.7, 0, 0...
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//(8.4) Reconsider the reheat cycle of Example 8.3, but include in the analysis that each turbine stage has the same isentropic efficiency. (a) If etat =  85%, determine the thermal efficiency. (b) Plot the thermal efficiency versus turbine stage efficiency ranging from 85 to 100%. //solution //part (a) et...
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clc //initialisation of variables dp=1.01*10^5//Nm^-2 L=4563000*4.2//J dv=18.7*10^-3//m^3 T=353//k //CALCULATIONS dT=(dp*T*dv)/L //results printf(' \n change in melting point= % 1f c',dT)
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//example 3 //calculating the required force clear clc Dcyl=0.1 //cylinder diameter in m Drod=0.01 //rod diameter in m Acyl=%pi*Dcyl^2/4 //cross sectional area of cylinder in m^2 Arod=%pi*Drod^2/4 //cross sectional area of rod in m^2 Pcyl=250000 //inside hydaulic pressure in Pa Po=101000 //outside atmospheric ...
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//Example 1_8 clc; clear; //To Calculate the Angular position of the 10th maximum and first minimum //The distance from centre where 10th maximum is obtained by lamda=5460 //units in angstrom lamda=5460*10^-10 //units in mts n=10 d=0.1 //units in mm d=0.1*10^-3 ...
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//Example 12.5.a // power factor clc; clear; close; w1=4.5;//first reading in kW w2=3;//second reading in kW , this value is given wrong in question tw=w1+w2;//in kW dw=w1-w2;//in kW pfa=atand(sqrt(3)*(dw/tw)); pf=cosd(pfa);////power factor when both the eadings are positive disp(pf,"power factor when both the readings...
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clc //initialisation of variables kw= 10^-14 ka= 2.69*10^-5 c= 0.1 //N //CALCULATIONS pH= -log10(sqrt(kw*ka/c)) //RESULTS printf ('pH = %.2f ',pH)
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err_getValueMalformed.tst
; malformed get-value commands (set-option :produce-models true) (set-logic QF_UF) (declare-fun x () Bool) (assert true) (check-sat) (get-value) (get-value x) (get-value x y) (get-value (x) ) ; OK (get-value (x) x) (get-value () )
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example11_sce.sce
//chapter 14 //example 14.11 //page 619 printf("\n") printf("given") Vi=10*10^-3;Vn=1;R1=33*10^3;R2=300;R5=15*10^3;R4=15*10^3;Vi2=-10*10^-3;R3=R1;R6=15*10^3;R7=R6; Acl=((2*R1+R2)/R2)*(R5/R4) disp("at junction of R1 and R2") Vb=Vi+Vn disp("at junction of R2 and R3") Vc=Vi2+Vn disp(" current through R2") I2=(...
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//Chapter-3,Example3_17_18,pg 3-42 phi=1.5*10^-4 //magnetic flux ur=900 //relative permeability of material n=600 //number of turns u0=4*%pi*10^-7 //permeability of free space A=5.8*10^-4...
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//Exa 2.22 clc; clear; close; format('v',7); //Given Data : p1=1;//bar V1=0.14;//m^3 V2=0.07;//m^3 R=287;//KJ/KgK //p*V=R*k1*V^(-2/5) or p*V^(7/5)=K K=p1*10^5*V1^(7/5);//Nm/Kg W=integrate('K*V^(-7/5)','V',V1,V2);//Nm disp(W,"Work done in Nm : "); p2=K*V2^(-7/5);//N/m^2 p2=p2/10^5;//bar disp(p2,"Fin...
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clc;funcprot(0);//EXAMPLE 20.24 // Initialisation of Variables p1=1;........//Suction pressure in bar p2=4;.....//Intermediate pressure in bar p5=3.8;.......//Pressure of air leaving the interooler in bar p6=15.2;........//Delivery pressure in bar t1=300;..........//Suction temperature in K dlp=0.36;........//Di...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 5 : UNDERGROUND POWER TRANSMISSION AND GAS-INSULATED TRANSMISSION LINES // EXAMPLE : 5.6 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA f = 60 ; // Fr...
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//Example 14// Ch 3 clc; clear; close; // given data p=1.01*10^5/760;// 1 torr in N/m2 k=1.38*10^-23; T=273; //in Kelvin n=85*10^2;//no of collisions per meter N=p/(k*T); printf("no of gas molecules %e atoms/m^3",N) r_a=sqrt(n/(%pi*N*1)); printf("diameter of argon atom %e m",r_a)
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//equation// ieee(2); syms p K s; m=s^3+(p*s^2)+(K+3)*s+(2*(K+1)) cof_a_0 = coeffs(m,'s',0); cof_a_1 = coeffs(m,'s',1); cof_a_2 = coeffs(m,'s',2); cof_a_3 = coeffs(m,'s',3); r=[cof_a_0 cof_a_1 cof_a_2 cof_a_3] n=length(r); routh=[r([4,2]);r([3,1])]; routh=[routh;-det(routh)/routh(2,1),0]; t=routh(2:3,1:2);...
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clear //Given I=35 e=5.0 //lumen/watt //Calculation // a=4*%pi*I P=a/e //Result printf("\n Power of the lamp is %0.0f Watt",P)
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clc // Given that lambda = 1.24e-10 // wavelength of X-ray in A x1 = 1 // coordinate on x axis of first plane y1 = 0 // coordinate on y axis of first plane z1 = 0 // coordinate on z axis of first plane x2 = 1 // coordinate on x axis of second plane y2 = 1 // coordinate on y axis of second plane z2 = 0 // coordinate on...
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ex2_12.sce
// Exa 2.12 clc; clear; close; // Given data d = 5.32;// in gm/cc N_A = 6.02*10^23;// in atoms/gm.mole At = 72.6;//atomic weight Miu = 3800;// in cm^2/v.s n_d = (N_A/At) * d;// in /cm^3 n_d = n_d * 10^-8;// in /cc e = 1.6*10^-19;// in C Sigma = n_d * Miu * e;// in mho/cm disp(Sigma,"The conductivity of spe...
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example_22_1.sce
clear; clc; disp("--------------Example 22.1----------------") // network addresses network_address1="180.70.65.192"; network_address2="180.70.65.128"; network_address3="201.4.22.0"; network_address4="201.4.16.0"; network_address5="Any" // Rest of the internet // masks mask1="/26"; mask2="/25"; mask3="/24"...
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Codigo controle adptativo(1).sce
clc clear k1 = 1.5 k2 = 1.5 Kp =2 ap =1 //Definição das condições iniciais e = zeros(1,100000); p = zeros(1,100000); i = zeros(1,100000); u = zeros(1,100000); r = ones(1,100000); y = zeros(1,100000); //Passo //Cada 10000 amostras correspondem a 1 segundo h=0.0001; //condições iniciais do sistema ...
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clc clear //input v=30 //velocity of speedboat vw=40 //velocity of wind //calculation x=(30/40)//angle between original velocity of boat and resultant velocity y=atand(x)//applying trigonometry b=90+y//bearing of boat //output printf("the bearing of speedboat is %3.3f deg",b)
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clc; clear all; disp("Heat transfer rate") disp("k=k1+(k2-k1)*(t-t1)/(t2-t1)") disp("A=4*%pi*r^2") disp("Q=-k*4*%pi*r^2*dt/dr") disp("Q=-(k1+(k2-k1)*(t-t1)/(t2-t1))*4*%pi*r^2*dt/dr") disp("Q*dr/r^2 =-(k1+(k2-k1)*(t-t1)/(t2-t1))*4*%pi*dt ") disp("By integrating both sides in the limits r1 to r2 and t1 to t2, we ...
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//chapter 18 //example 18.3 //page 569 clear all; clc ; //given E=30; Vs=10;//supply voltage Is=500;//ip current Ih=1.5;//mA Vf=1;//forward voltage drop R1max=1000*(E-Vs)/Is; R1min=(E-Vf)/Ih; printf("\nmaximum and minimum values of R1 are %d kohm ,%.1f kohm respectively.",R1max,R1min);
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//Example 7.7 clc //determine the larger of two integer quantities function[] = maximum(x, y) if (x >= y) then z=x; else z=y; end printf("\n\nMaximum value = %d", z); return; endfunction
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//Example 6.6 clc;clear;close; x=[1 1 0 1 1];xmin=-2;nx=xmin:length(x)+xmin-1; h=[1 -2 -3 4];hmin=-3;nh=length(h)+hmin-1; //Calculation of linear convolution y=convol(x,h); ymin=xmin+hmin;ny=ymin:length(y)+ymin-1; disp(x,'First Sequence is x(n): '); disp(h,'Second Sequence is h(n): '); disp(y,'Output seq...
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sce
Ex1_4.sce
clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 1.5.1\n') //given data //x1=a*sin(W1*t) //x2=b*sin(W2*t) //calculations a=1.90//amplitude of first wave in cm b=2.00//amplitude of second wave in cm W1=9.5//frequency of first wave in rad/sec W2=10.0//frequency of second wave in rad/sec xmax=b+...