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//Fluid Systems - By - Shiv Kumar //Chapter 11- Centrifugal Pumps //Example 11.5 //To Find the Discharge of Pump. clc clear //Given Data:- Hm=14.5; //Manometric Head, m N=1000; //Speed, rpm beta_o=30; //Vane Angle at outlet, degrees Do=300; //Outer Diameter of the Impeller, mm bo=50; //Width at Outlet, mm eta_man=95/100; //Manometric Efficiency //Data Used:- g=9.81; //Acceleration due to gravity, m/s^2 //Computations:- Do=Do/1000; //m bo=bo/1000; //m uo=%pi*Do*N/60; //m/s Vwo=g*Hm/(uo*eta_man); //m/s Vfo=tand(beta_o)*(uo-Vwo); //m/s Q=%pi*Do*bo*Vfo*1000; //Discharge, litres/s //Results:- printf("The Discharge of the Pump=%.2f litres/s\n",Q) //The answer vary due to round off error
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt // Author: Deepshikha // Organization: FOSSEE, IIT Bombay // Email: toolbox@scilab.in function [dstImg] = DCT(srcImg) //Performs forward Discrete Cosine Transform of the 1D or 2D array. // //Calling Sequence //dstMat = DCT(srcMat) // //Parameters //srcMat : 1D or 2D floating type array //dstMat : The output matrix // //Description //dstMat = DCT(srcMat) //Returns the DCT of the input matrix. // //Examples //srcMat = [230.3 23.1 432.5; 321 543.1 89.5] //dstMAt = DCT(srcMat) //disp(dstMAt) //Authors // Deepshikha srcMat = mattolist(srcImg) output = raw_DCT(srcMat) channels = size(output) for i = 1:channels // for i channel image dstImg(:,:,i) = output(i) end endfunction
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//Variable declaration: //From example 12.5: Re = 73.9 //Reynolds number mu_l = 2.82*10**-4 //Absolute viscosity of liquid water condensate (kg/m.s) Pw = 0.2 //Wetted perimeter of rectangular plate (m) h = 14700.0 //Heat transfer coefficient (W/m^2.K) T_sat = 100.0 //Saturation temperature (°C) Ts = 98.0 //Surface temperature (°C) A = 0.2*0.4 //Heat transfer area of plate (m^2) //Calculation: m1 = Re*mu_l/4.0 //Mass flow rate of condensate (kg/m.s) m = Pw*m1 //Mass flow rate of condensate (kg/s) Co = (3.038*10**-5)*h //Condensation number Q = h*A*(T_sat-Ts) //Heat transfer rate (W) //Result: printf("1. The mass flow rate of condensate is : %.4f kg/m.s.",m1) printf("2. The heat transfer rate is : %.2f kW.",Q/10**3)
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//Caption:calculate_reference_voltage_Vr //example 5.9.5 //page 102 exec series.sce; Vt=250//output_voltage Rf=100//field_winding_resistance Kg=500//generator_constant A=2//amplifier Vf=0.4//fraction_of_output_voltage_compared_with_reference_voltage a=1/Rf; b=series(A,a); c=series(b,Kg); d=c/.Vf; disp(d,"Vt/Vr="); //since Vt=250 Vr=Vt*(1/d); disp(Vr,"reference_voltage=");
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errcatch(-1,"stop");mode(2);//Chapter 24 clc //Example 2 //given n=1.33 //refractive index of soap bubble lambda=602 //wavelength of light in nm //for constructive interference we have 2nt=lambda/2 t=lambda/(4*n) disp(t,"Minimum thickness of soap bubble film in nm is")
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// Ex5_8 clc; // Given: Q1=1.2; M1=14; m1=4; // Solution: E1=Q1*((m1+M1)/M1); printf("The threshold energy is %f in MeV for O(17) reaction",E1)
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NUM_AT_HH VOTER_ID NAME_PFX NAME_F NAME_L HOUSE_NUM STREET TYPE APT ZIP 1 815305 MISS ANH TY UNG 480 EDDY ST 506 94109 3 814726 MISS ANNIE LUU 350 TURK ST 402 94102 2 274396 HAH HUNG CHAU 631 OFARRELL ST 1205 94109 1 276653 MR HUNG NGUYEN 111 JONES ST 301 94102 1 133926 MR PAO TCHEN 390 CLEMENTINA ST 503 94103 2 320834 YANG HUA 801 HOWARD ST 818 94103 1 357618 MR TAM CAO 440 VALENCIA ST C204 94103 1 276343 MR THUC PHAN 201 TURK ST 513 94102 1 805961 MIEU LUU 240 JONES ST 310 94102 1 84074 MR VAN DANIEL CHIEM 230 EDDY ST 606 94102 1 283436 TU TAT 460 ELLIS ST 54 94102 2 712569 MR THUA TRAN 335 10TH ST 94103 1 718126 MISS FRANCINE PHAM 300 BEALE ST 201 94105 1 734337 MRS MUI NGO 434 LEAVENWORTH ST 401 94102 5 276467 MRS SANDY TRUONG 201 TURK ST 215 94102 1 517053 MRS PHUNG TRINH 508 LARKIN ST 508 94102 1 723507 DANG NGUYEN 743 POLK ST 305 94109 1 715578 MR MY LONG 555 ELLIS ST 405 94109 2 275811 KIMBERLY NGUYEN 632 HYDE ST 4 94109 1 273070 HUNG LY 601 LEAVENWORTH ST 33 94109 1 274741 MR KEVIN LEE 555 ELLIS ST 206 94109 1 815903 HON DANG 965 GEARY ST 38 94109 4 758509 MRS HOA LU 111 JONES ST 406 94102 1 386869 MR MINH HUYNH 49 TOWNSEND ST 208 94107 1 319193 CRESENCIA JIMENO 133 SHIPLEY ST W504 94107 1 770493 HANG CHAU 411 EDDY ST 1 94109 1 283206 ICH TRAN 535 TAYLOR ST 105 94102 3 711942 MR TRUONG VUONG 111 JONES ST 205 94102 2 794317 MR TAI NGUYEN 249 EDDY ST 502 94102 1 276021 THIEN TRINH 325 LEAVENWORTH ST 1C 94102 1 696838 MICHELLE NGUYEN 765 OFARRELL ST 8 94109 2 284845 MR FRANCIS TRAN 347 EDDY ST 207 94102 1 284748 MISS JEANNIE NGUYEN 741 ELLIS ST 8 94109 1 69115 MS LYNNE HO 225 JONES ST 2 94102 1 786571 MS SIBELLE NGUYEN 1390 MARKET ST 1818 94102 1 762927 SU HUYNH 308 EDDY ST 303 94102 1 276525 CHUONG POWERS 111 JONES ST 94102 1 822908 MARIA WEIGEL 550 S VAN NESS AVE 101 94110 1 786060 MR JAMES CHAN 80 SYCAMORE ST 94110 1 273179 LOC NGUYEN 746 GEARY ST 206 94109 1 275245 MRS SUSAN HUANG 359 HYDE ST 307 94109 1 283362 DAU DUONG 460 ELLIS ST 38 94102 1 288411 MR PHILLIP PETRASANTA 54 MCALLISTER ST 211 94102 1 364280 MR BRUCE NGUYEN 2135 MISSION ST 45 94110 1 724898 MR VING NGUYEN 565 ELLIS ST 4 94109 2 721871 MR HARRY YANG 555 ELLIS ST 305 94109 1 816895 SANG TRAN 555 ELLIS ST 308 94109 1 354579 MR PHU LE 320 CLEMENTINA ST 610 94103 1 321757 MR KENNETH ONG 22 S PARK ST 306 94107 1 282853 MR MICHAEL QUAN 585 GEARY ST 604 94102 1 821118 MRS MONGLAN NGUYEN 145 TAYLOR ST 204 94102-2875 1 361351 MR KENNETH VUONG 50 SYCAMORE ST B 94110 2 801524 HOAN NGO 601 LEAVENWORTH ST 21 94109 1 202590 MR WILLIAM NGUYEN 525 OFARRELL ST 403 94102 1 784688 MR THANH NGUYEN 145 TAYLOR ST 204 94102 1 361337 MR PAO CHIU 1081 NATOMA ST 94103-2550 1 251005 MRS HATTY ONG 1280 LAGUNA ST 6G 94115 1 284112 THANH THAI 350 ELLIS ST 5A 94102 1 720658 MRS CINDY TRIEU 680 MISSION ST 11M 94105 1 71203 MS CYNTHIA MACH 888 OFARRELL ST 94109 2 274770 MR KIEM LU 631 OFARRELL ST 316 94109 1 738831 MISS DIANA SAM 601 VAN NESS AVE 1042 94102 2 276508 HONG TRUONG 111 JONES ST 402 94102 1 823647 MR TUAN KHIEU 440 VALENCIA ST D401 94103 3 267606 ANN LAM 1003 POST ST 9 94109 1 769618 MR TAN HUYNH 575 EDDY ST 408 94109 1 816333 YEN TO 380 CLEMENTINA ST 1106 94103 1 761590 MS KIM NGO 356 12TH ST 201 94103-4347 1 265395 MR NAM DANG 421 TURK ST 405 94102 1 818229 MRS MUI LOC 111 JONES ST 701 94102-3934 1 81879 MS SERENA DANG 421 LEAVENWORTH ST 46 94102 1 670571 MS SUZAN TRAN 711 EDDY ST 1K 94109 1 714939 MR STEPHEN NGUYEN 434 LEAVENWORTH ST 505B 94102 2 274694 MISS JENNY TRAN 1180 HOWARD ST 311 94103 1 818637 MS LUCY SY 3214 18TH ST 94110 1 739733 MR BINH TRAN 1003 POST ST 3 94109 1 268925 QUYEN VUONG 735 ELLIS ST 12 94109 1 386913 MR BEN TRAN 10 KING ST 314 94107 1 695343 MR HENRY LAMB 709 GEARY ST 405 94109 1 778996 MS HUE LE 245 14TH ST 94103 1 283643 MISS SERENA BANH 515 OFARRELL ST 52 94102 3 267636 MR DU QUANG 1003 POST ST 7 94109 1 285004 QUYEN THACH 248 TAYLOR ST #302 94102 1 282766 MR DU TA 555 JONES ST 301 94102 1 124695 MISS CHRISTINE BUI 877 BRYANT ST 200 94103 1 273587 TONY QUACH 375 EDDY ST 29 94102 1 778953 MS MUOI HUYNH 375 EDDY ST 26 94102 1 756880 MR MARIO VUONG 545 OFARRELL ST 216 94102 1 705476 HUE LUONG 146 MCALLISTER ST 404 94102 1 769504 MR DAVID LAM 359 HYDE ST 603 94109 2 702489 MRS KIEM TRUONG 800 THE EMBARCADERO 232 94107 2 705535 MR CONG TRAN 479 NATOMA ST 404 94103 1 315518 FELIX CHAU 1101 HOWARD ST 507 94103 1 688499 MR KHUONG DAM 441 ELLIS ST 307 94102 1 321064 MS NANCY LAM 540 DELANCEY ST 201 94107 1 315944 MR DUC LY 1101 HOWARD ST 513 94103 1 688962 MS HOA LY 425 HYDE ST 53 94109 1 670388 MR MINH HUYNH 308 EDDY ST 611 94102 1 283617 SUSAN TRUONG 460 ELLIS ST 37 94102 1 199583 MRS CINDY LUC 480 EDDY ST 608 94109-8146 1 284879 CHARLIE DANG 340 EDDY ST 604 94102 1 669851 MR JACKSON CHIEN 801 HOWARD ST 816 94103 1 821576 MRS DUNG NGUYEN 601 LEAVENWORTH ST 44 94109 1 737362 DANNY DANG 1036 POLK ST 206 94109 1 349515 MR QUANG NGUYEN 1800 BRYANT ST 305 94110 2 75710 MR THANH TRAN 85 CLEARY CT 1 94109 1 10303 KIEN NGUYEN 326 HAYES ST 94102 2 276334 LONG LUU 201 TURK ST 217 94102 1 318876 YEN QUAN 133 SHIPLEY ST W705 94107 1 801827 MR VAN VO 230 EDDY ST 308 94102 1 72729 MR THINH LUU 308 EDDY ST 511 94102 1 319643 MR NGHE HY 321 CLEMENTINA ST 208 94103 1 795277 MS QUYEN LAM 248 TAYLOR ST 201 94102 1 772946 MR OWEN TRAN 388 TOWNSEND ST 4 94107 2 274030 MRS SALLY NGO 721 GEARY ST 24 94109 3 714760 MRS KATHERINE NGUYEN 1028 HOWARD ST 204 94103 1 771039 MR YAT LEUNG 585 GEARY ST 205 94102 1 199812 MS MUOI TAM DO 441 ELLIS ST 204 94102 2 275476 DIEU LY 430 TURK ST 500 94102 1 359472 MR THANH AU 2911 16TH ST 205 94103 2 275289 PHU MONG 575 EDDY ST 606 94109 1 758528 MRS JANA TRAN 111 JONES ST 816 94102 1 238335 MR TAI NGUYEN 1100 EDDY ST G 94109 1 705614 MR TAM NGUYEN 165 TURK ST 403 94102 1 765860 JOSON NICHOLAS LEE 350 TURK ST 302 94102 1 755051 MR DANNY LIEU 555 ELLIS ST 401 94109 3 709349 MS LIEN TRAN 375 EDDY ST 35 94102 1 340485 MR PHILLIP TRAN 118 CLINTON PARK 94103 1 669210 MINH VUONG 240 JONES ST 211 94102 1 358834 MR EDWARD MA 1930 MISSION ST 105 94103 1 284838 SAM SAN 201 TURK ST 219 94102 1 802439 MR THU TRUONG 21 COLUMBIA SQUARE ST 410 94103 1 291263 MR RYAN NGUYEN 855 FOLSOM ST 728 94107 3 276339 SHERINE TA 201 TURK ST 721 94102 1 428123 MR JACK FUNG 355 EDDY ST 207 94102 1 312861 MR KEVIN CHIEN 500 BRYANT ST 204 94107 1 284802 TAI THAI 375 EDDY ST 47 94102 1 275776 MR DAVID HOANG 255 LEAVENWORTH ST 1 94102 1 306618 MS CAMILLE ARRIETA 265 FELL ST 606 94102 1 283587 THANH HUYNH 201 TURK ST 825 94102 1 695371 MS KIMBERLY TRAN 536 LEAVENWORTH ST 66 94109 1 283498 ROGER VUONG 395 EDDY ST 1 94102 1 276022 MRS NHU HOA NGUYEN 325 LEAVENWORTH ST 1A 94102 1 781202 SHARON LAM 199 NEW MONTGOMERY ST 608 94105 1 282662 MR KIM TRAN 685 GEARY ST 204 94102 1 274408 MR MICHAEL YIP 775 OFARRELL ST 5 94109 1 276259 QUAN DAM 480 EDDY ST 210 94109 1 317655 MR SRUC TRUONG 587 NATOMA ST 101 94103 1 102366 JAMES HANG 1655 MISSION ST 640 94103 2 274995 MS ELIZABETH DUONG 575 EDDY ST 508 94109 2 274790 MR TONY MACH 722 LARKIN ST 3 94109 1 706835 MRS GINA TRAN 205 JONES ST 410 94102 1 774688 MR VANDY SIVONGSAY 526 ELLIS ST 34 94109 3 386848 TRAN THACH 49 TOWNSEND ST 110 94107 1 829064 NAM VO 308 EDDY ST 312 94102 1 322305 MS PHUONG LE 300 3RD ST 519 94107 1 273941 JOHN HUYNH 721 GEARY ST 27 94109 1 283645 MR TOM TRUONG 460 ELLIS ST 16 94102 2 282104 MR UNG CAO 120 ELLIS ST 106 94102 1 584172 MR DUC TRUNG TA 375 EDDY ST 67 94102 1 274062 CUONG LU 535 LEAVENWORTH ST 55 94109 1 284719 THAP TA 741 ELLIS ST 3 94109 1 274675 THINH VU 666 ELLIS ST 502 94109 1 800394 MRS HUONG NGUYEN 321 CLEMENTINA ST 911 94103 1 276608 VAN DANG 111 JONES ST 404 94102 3 772791 MRS XUAN NGUYEN 735 ELLIS ST 11 94109 1 792115 MISS MY LINH NGUYEN 555 ELLIS ST 300 94109 1 726803 MR THAI PHAM 440 VALENCIA ST D404 94103 1 285080 MR HOANH LE 230 EDDY ST 512 94102 1 775968 MISS TRAN UNG 575 EDDY ST 94109 3 274973 MR MINGO NGUYEN 555 EDDY ST 24 94109 2 755652 MR STEVE DANG 800 THE EMBARCADERO 334 94107 4 274732 MR DAN TRAN 1101 HOWARD ST 313 94103 1 802283 MRS HON BUI 308 EDDY ST 704 94102 1 317544 MRS NGAN DINH 1028 HOWARD ST 502 94103 3 317455 SIU VUONG 1028 HOWARD ST 210 94103 1 695704 LARRY GOPPERT 1221 HARRISON ST 27 94103-4450 1 504450 MS MAI ANH NGUYEN 239 8TH ST 10 94103 1 821152 MR CAT DUONG 145 GUERRERO ST 213 94103 1 319226 MRS MUOI HUYNH 133 SHIPLEY ST E713 94107 1 72651 LAN DUONG 54 MCALLISTER ST 604 94102 1 712331 MR THANH TRAN 525 OFARRELL ST 201 94102 3 274621 MR THANH LE 725 OFARRELL ST 46 94109 1 274278 TRINH QUACH 725 OFARRELL ST 6 94109 1 751627 MRS HONG PHUC NGUYEN 441 ELLIS ST 211 94102 2 740598 MR DO NGUYEN 1101 HOWARD ST 209 94103 1 781787 MR ANDREW LEUNG 1051 POST ST 3 94109 1 274581 MR VAN NGUYEN 624 ELLIS ST 6 94109 1 282552 MR DAVID TRAC 516 OFARRELL ST 506 94102 1 283495 THANH LAM 450 ELLIS ST 501 94102 1 275483 MR SAM TANG 395 EDDY ST 3 94102 1 820837 DUNG NGUYEN 300 HYDE ST 31 94109 3 35767 DUNG HOANG 350 ELLIS ST 6E 94102-2702 1 296514 MR PAUL LE 885 FRANKLIN ST 207 94102 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273762 JASON LY 721 GEARY ST 1 94109 1 361768 JIMMY TRAN 21 SYCAMORE ST 94110 2 276284 MR HOA BANH 441 ELLIS ST 408 94102 1 783597 MR PAUL HOA 485 TEHAMA ST 3 94103 1 744373 MR KIEN TRAN 535 EDDY ST 94109 1 740547 MR MITCHELL YOUNG 555 HYDE ST 1 94109 1 267647 LIZA DAMIANI 970 GEARY ST 52 94109 1 800102 MR THANH NGUYEN 201 TURK ST 301 94102 1 799801 MISS DAKHAM SOUVANNARATH 526 ELLIS ST 21 94109 1 319813 MISS SAY THAI 50 RIZAL ST 313 94107 1 775132 MRS QUY HO 111 JONES ST 201 94102 1 276481 MR PAUL LUU 631 OFARRELL ST 1904 94109 1 786339 MS PRISCILLA TRAN 725 OFARRELL ST 23 94109 1 275434 TAMMY BUI 530 LARKIN ST 303 94102 1 816677 MRS PHU DANG 448 LARKIN ST 94102 2 287203 MR HAROLD TAT 479 NATOMA ST 306 94103 1 679970 MS THU HA VU 62 SYCAMORE ST A 94110 1 728940 CHRIS WU 333 1ST ST N603 94105 1 681622 MR MICHAEL PHAM 590 6TH ST 304 94103 1 274854 QUE DANG 530 LARKIN ST 110 94102 1 721410 MRS CHAU KOLTUN 62 PEARL ST 94103 1 238360 MRS HOANG NGUYEN 1100 EDDY ST 94109 2 275845 MR HUU LUU 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//finding required data// //example 1// clc //clears the command window// clear //clears// //finding time constant and time for capacitor to charge 90% of supplied voltage// R=10^6 ;//resistance in ohms// C=10^-5 ;//capacitance in farads// T=R*C printf('the time constant=%f seconds\n',T) //time constant is found out// v=90/100*10;//v=voltage at time t// V=10;//voltage in volts// //t=required time// disp('from the formula v=V*(1-exp(-t/(R*C))),we get the required time as:') t=-((R*C)*log(1-(v/V))) printf('required time to charge to 90 percent of the supplied voltage=%f seconds',t) //the result is t seconds//
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clc clear //INPUT DATA t=0.1*10^-2//thickness of piezo electric crystal in m E=80*10^9//Young's modulus of crystal in pa d=2654//density of material of crystal in Kgm^-3 //CALCULATION f=(1/(2*t)*sqrt(E/d))/10^6//The frequency to which a piezo electric oscillator circuit should be turned in Hz //OUTPUT printf('The frequency to which a piezo electric oscillator circuit should be turned is %3.4f*10^6 Hz',f)
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function callFunctioncleandata(filename,xye) f_temp = mopen(filename, 'wt'); // Creating a text file xye_split = strsplit(xye,';'); //split string for ';' ary_size = size(xye_split); // get size of array which will be 6 1 n = ary_size(1); // retrive only size of element ie. 6 arry_xye = []; for i = 1:n comma_split = strsplit(xye_split(i),',');//split string for ',' comma_ary_size = size(comma_split); // get size of array which will be 6 1 m = comma_ary_size(1); for j = 1:m arry_xye(i)(j) = strtod(comma_split(j)); //convert string to double and add to array end end [xy] = cleandata([arry_xye]); //pass new array to cleandata and save return value in xy [m,n] = size(xy) // reading the size of variable mfprintf(f_temp, '[['); for y = 1:m // no. of rows in variables for z = 1:n //no. of columns in variabes if z == n then mfprintf(f_temp, '%g', xy(y,z)); //Print the variable values else mfprintf(f_temp, '%g,', xy(y,z)); //Print the variable values end end if y ~= m then mfprintf(f_temp, '],[') end end mfprintf(f_temp, ']]'); mclose(f_temp) endfunction function callFunction_do_Spline(filename,N,order,x,y) f_temp = mopen(filename, 'wt'); // Creating a text file if ((strindex(x,",")) ~= []) then // if x value is array (0,0) or single value 0 x_split = strsplit(x,','); //split string for ',' x_size = size(x_split); // get size of array n = x_size(1); // retrive size x = []; for i = 1:n x(1)(i) = strtod(x_split(i)); //convert string to double and add to array end else x = strtod(x); // in case x is single value 0 convert it into double end if ((strindex(y,",")) ~= []) then // if y value is array (0,0) or single value 0 y_split = strsplit(y,','); //split string for ',' y_size = size(y_split); // get size of array n = y_size(1); // retrive size y = []; for i = 1:n y(1)(i) = strtod(y_split(i)); //convert string to double and add to array end else y = strtod(y); // in case y is single value 0 convert it into double end [Xdummy,Ydummy,orpar] = Do_Spline(strtod(N),strtod(order),x,y); //pass new array to do_spline and save return value in [Xdummy,Ydummy,orpar] Do_Spline_write(Xdummy,Ydummy,orpar,f_temp); mclose(f_temp) endfunction function Do_Spline_write(Xdummy,Ydummy,orpar,f_temp) mfprintf(f_temp, '{'); mfprintf(f_temp, '""Xdummy"":['); for i = 1:length(Xdummy) if (i == length(Xdummy)) then mfprintf(f_temp, '%f', Xdummy(i)); else mfprintf(f_temp, '%f,', Xdummy(i)); end end mfprintf(f_temp, ']'); mfprintf(f_temp, ',""Ydummy"":['); for i = 1:length(Ydummy) if (i == length(Ydummy)) then mfprintf(f_temp, '%f', Ydummy(i)); else mfprintf(f_temp, '%f,', Ydummy(i)); end end mfprintf(f_temp, ']'); mfprintf(f_temp, ',""orpar"":['); for i = 1:length(orpar) if (i == length(orpar)) then mfprintf(f_temp, '%d', orpar(i)); else mfprintf(f_temp, '%d,', orpar(i)); end end mfprintf(f_temp, ']'); mfprintf(f_temp, '}'); endfunction
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clc; // page no 139 // prob no 4_13_1 //Noise fig. of an amplifier is 7 dB with input SNR=35 dB SNRin=35;//SNR at i/p of amplifier F=7;//Noise figure of an amplifier //Determination of output SNR SNRout=SNRin-F; disp('dB',SNRout,'The value of output signal to noise ratio is ');
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function M=%b_i_sp(varargin) // Copyright INRIA [lhs,rhs]=argn(0) M=varargin(rhs) N=bool2s(varargin(rhs-1))//inserted matrix if rhs<=4 then if rhs==3 then M(varargin(1))=N else M(varargin(1),varargin(2))=N end else error('multidimensional sparse matrices are not handled') end
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//Caption:Program to calculate how many bits per sample can be saved by using DPCM //Example 3.4 //Page 128 w=800//Omega=800Hz //x(t)=A sin(2pi.wt), equation for sine wave with maximum amplitude //x'(t)=A(2pi).w.cos(2pi.wt), diff w.r.t time (2*%pi)*800*(1/8000) //0.62831*a, x'(t)max disp('savings in the bits per sample can be determined as ') log2(1/0.628) //Result //0.67 bits
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//EX15.1 f0=15*10^3; //center frequency in hertz BW=1*10^3; Q=f0/BW; if Q>10 then disp(Q,'narrow band filter') end
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clc vl=400 //assigning values to the parameters t=0 zph=50 vph=vl/sqrt(3) iph=vph/zph il=iph p=sqrt(3)*vl*il*cos(t) disp("Watts",polar(p),"Power taken is") iph=4 il=iph p=vl*il*cos(t) disp("Watts",polar(p),"Power taken after disconecting one of the resistor is")
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// problem 7.11 b=1.5 d=0.8 Q=0.75 i=1/2500 A=b*d P=b+(2*d) m=A/P C=Q/(((m*i)^0.5)*A) z=(157.6/C)-1.81 K=z*(m^0.5) disp(K,C,"Chezys constant and coefficient of roughness")
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function result = unbiasedestimator(X, n) c=(n+2)/(n+1); result = c*max(X); endfunction
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// chapter 4 example 2 //----------------------------------------------------------------------------- clc; clear; // given data Pi = 10; // Input power in mW IL = 0.4; // insertion loss in dB // calculations // ILdb) = 10log(Pi/Po) Po = Pi/(10^(IL/10)) // antilog conversion and coupling power // Output mprintf('Power available at the straight through port output = %3.3f mW',Po); //------------------------------------------------------------------------------
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optimizecode 1 maxversions 0 units Field /LiquidPhases = 2 /StdLiqVolRefT = 288.15 /StdLiqVolRefT = 60 F /RecycleDetails = 1 displayproperties displayproperties VapFrac T P MoleFlow MassFlow VolumeFlow StdLiqVolumeFlow StdGasVolumeFlow Energy H S MolecularWeight MassDensity Cp ThermalConductivity Viscosity molarV ZFactor commonproperties commonproperties + ZFactor P T MolecularWeight MassDensity StdLiqMolarVolVapFrac T P MoleFlow MassFlow VolumeFlow StdLiqVolumeFlow StdGasVolumeFlow Energy H S MolecularWeight MassDensity Cp ThermalConductivity Viscosity molarV ZFactor $VMGThermo = VirtualMaterials.Advanced_Peng-Robinson / -> $VMGThermo /SolidPhases = 0 $VMGThermo + METHANE $VMGThermo + ETHANE $VMGThermo + PROPANE $VMGThermo + n-BUTANE $VMGThermo + n-PENTANE $VMGThermo + n-HEXANE $VMGThermo + n-HEPTANE $VMGThermo + WATER $VMGThermo + CARBON_DIOXIDE /PT1 = Properties.PropertyTable() '/PT1.In.Fraction' = .1 .1 .2 .1 .1 .1 .1 .1 .1 /PT1.XProperty = PRESSURE /PT1.XMin = 10 /PT1.XMax = 20 /PT1.XPoints = 4 /PT1.YProperty = TEMPERATURE /PT1.YMin = 60 /PT1.YMax = 100 /PT1.YPoints = 3 /PT1.Phase = FEED #One property /PT1.ZProperty = CP valueOf /PT1.TableXYZCP.convertedArrayRep #More than one property /PT1.ZProperty = CP CV ENTHALPY ENTROPY ZFACTOR valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep #Change phases /PT1.Phase = LIQUID valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep /PT1.Phase = VAPOR valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep /PT1.Phase = LIQUID2 valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep /PT1.Phase = FEED valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep #With VF at the end BULK /PT1.ZProperty = CP CV ENTHALPY ENTROPY ZFACTOR VF valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep valueOf /PT1.TableXYZVF.convertedArrayRep #With VF in the middle BULK /PT1.ZProperty = CP CV ENTHALPY ENTROPY ZFACTOR VF VISCOSITY valueOf /PT1.TableXYZCP.convertedArrayRep valueOf /PT1.TableXYZCV.convertedArrayRep valueOf /PT1.TableXYZENTHALPY.convertedArrayRep valueOf /PT1.TableXYZENTROPY.convertedArrayRep valueOf /PT1.TableXYZZFACTOR.convertedArrayRep valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep #With VF at the beginning BULK /PT1.ZProperty = VF VISCOSITY valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep #Now only VF in all phases /PT1.ZProperty = VF /PT1.Phase = VAPOR valueOf /PT1.TableXYZVF.convertedArrayRep /PT1.Phase = LIQUID valueOf /PT1.TableXYZVF.convertedArrayRep /PT1.Phase = LIQUID2 valueOf /PT1.TableXYZVF.convertedArrayRep /PT1.Phase = VAPOR valueOf /PT1.TableXYZVF.convertedArrayRep #With VF at the beginning all phases /PT1.ZProperty = VF VISCOSITY valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep /PT1.Phase = LIQUID valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep /PT1.Phase = LIQUID2 valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep #With VF in the middle all phases /PT1.ZProperty = ENTHALPY VF VISCOSITY valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep /PT1.Phase = LIQUID valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep /PT1.Phase = LIQUID2 valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep #With VF at the end all phases /PT1.ZProperty = VISCOSITY VF valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep /PT1.Phase = LIQUID valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep /PT1.Phase = LIQUID2 valueOf /PT1.TableXYZVF.convertedArrayRep valueOf /PT1.TableXYZVISCOSITY.convertedArrayRep copy /PT1 paste / valueOf /PT1Clone.TableXYZVISCOSITY.convertedArrayRep
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clc;funcprot(0);//EXAMPLE 20.26 // Initialisation of Variables p1=1;............//Intake pressure in bar p2=4;..............//Pressure after first stage in bar p3=16;............//Final pressure in bar ns=2;............//No of stages t1=300;............//Intake temperature in K n=1.3;............//Compression index klp=0.04;.........//Clearance ratio for low pressure cylinder khp=0.06;........//Clearance ratio for high pressure cylinder N=440;............//Engine rpm R=0.287;..........//Gas constant in kJ/kgK m=10.5;.............//Mass of air delivered in kg/min cp=1.005;.........//Specific heat at constant pressure in kJ/kgK //Calculations rp=sqrt(p1*p3);...........//Pressure ratio per stage P=((ns*n)/(n-1))*R*t1*(m/60)*(((p3/p1)^((n-1)/(ns*n)))-1);..........//Work done per min in Nm disp(P,"Power required in kW:") isoWd=(m/60)*R*t1*log(p3/p1);..........//Isothermal work done in Nm disp(isoWd,"Isothermal work done in kW:") etaiso=isoWd/P;...............//Isothermal efficiency disp(etaiso*100,"Isothermal efficiency in %:") FAD=(m*R*t1*1000)/(p1*10^5);.............//Free air delivered in m^3/min disp(FAD,"Free air delivered in m^3/min:") t2=t1*((p2/p1)^((n-1)/n));.....//Temperature at the end of compression in K Qt=(m/60)*cp*(t2-t1);..............//Heat transferred in intercooler in kW disp(Qt,"Heat transferred in intercooler in kW:") etavlp=(1+klp)-(klp*((p2/p1)^(1/n)));..........//Volumetric efficiency of low pressure stage etavhp=(1+khp)-(khp*((p2/p1)^(1/n)));..........//Volumetric efficiency of high pressure stage vslp=FAD/(N*etavlp);......//Swept volume for low pressure stage in m^3 vclp=klp*vslp;..............//Clearance volume for low pressure stage in m^3 printf("\nSwept volume for low pressure stage in m^3: %f\n",vslp) printf("\nClearance volume for low pressure stage in m^3: %f\n",vclp) vshp=FAD/(N*rp*etavhp);......//Swept volume for high pressure stage in m^3 vchp=khp*vshp;..............//Clearance volume for high pressure stage in m^3 printf("\nSwept volume for high pressure stage in m^3: %f\n",vshp) printf("\nClearance volume for high pressure stage in m^3: %f\n",vchp)
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function [alphan,ok]=Wolfe(alpha,x,D,Oracle) ////////////////////////////////////////////////////////////// // // // RECHERCHE LINEAIRE SUIVANT LES CONDITIONS DE WOLFE // // // // // // Arguments en entree // // ------------------- // // alpha : valeur initiale du pas // // x : valeur initiale des variables // // D : direction de descente // // Oracle : nom de la fonction Oracle // // // // Arguments en sortie // // ------------------- // // alphan : valeur du pas apres recherche lineaire // // ok : indicateur de reussite de la recherche // // = 1 : conditions de Wolfe verifiees // // = 2 : indistinguabilite des iteres // // // // // // omega1 : coefficient pour la 1-ere condition de Wolfe // // omega2 : coefficient pour la 2-eme condition de Wolfe // // // ////////////////////////////////////////////////////////////// // ------------------------------------- // Coefficients de la recherche lineaire // ------------------------------------- omega1 = 0.1; omega2 = 0.9; alphamin = 0.0; alphamax = %inf; ok = 0; dltx = 0.00000001; // --------------------------------- // Algorithme de Fletcher-Lemarechal // --------------------------------- // Appel de l'oracle au point initial ind = 4; [F,G] = Oracle(x,ind); // Initialisation de l'algorithme alphan = alpha; xn = x; // Boucle de calcul du pas // // xn represente le point pour la valeur courante du pas, // xp represente le point pour la valeur precedente du pas. while ok == 0 xp = xn; xn = x + (alphan*D); [Fx,Gx,ind]=Oracle(x,ind); [Fn,Gn,ind]=Oracle(xn,ind); // Calcul des conditions de Wolfe Condition1= (Fn<=Fx+omega1*alphan*Gx'*D); Condition2= (Gn'*D>=omega2*Gx'*D); // Test de la valeur de alphan : // - si les deux conditions de Wolfe sont verifiees, // faire ok = 1 : on sort alors de la boucle while // - sinon, modifier la valeur de alphan : on reboucle. if ~Condition1 alphamax = alphan; alphan= 0.5*(alphamin+alphamax); else if ~Condition2 alphamin=alphan; if (alphamax==%inf) alphan=2*alphamin; else alphan=0.5*(alphamin+alphamax); end else ok=1; break; end end // Test d'indistinguabilite if norm(xn-xp) < dltx then ok = 2; end end endfunction
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clc //to calculate velocity c=3*10^8 // light velocity v=0.75*c //speed of A ux=-0.85*c //speed of B ux1=(ux-v)/(1-ux*v/c^2) disp(ux1,'velocity of B with respect to A (m/s) is :') //answer is given in terms of c in the book=-0.9771c
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m1=120 //kg m2=175 //kg m3=295 //kg ID=6 //cm P=17 //bar H1=125.7 //Kj/Kg H2=271.9 //Kj/Kg H3=2793 //Kj/kg
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//Example 5.21 //Newton's Forward Difference Formula //Page no. 145 clc;close;clear; printf(' x\t f(x)\t\t 1st\t\t 2nd\t\t 3rd\t\t\n\t\t\tdifference\tdifference\tdifference\t') printf('\n---------------------------------------------------------------------------------------------------') h=1; z=[0,-4;1,-1;2,2;3,11;4,32;5,71] deff('y=f1(x,p)','y=z(x,2)+p*z(x,3)+p*(p-1)*z(x,4)/2+p*(p-1)*(p-2)*z(x,5)/6') x01=0;x11=6; x02=2;x12=2.5 for i=3:7 for j=1:8-i z(j,i)=z(j+1,i-1)-z(j,i-1) end end printf('\n') for i=1:6 for j=1:5 if z(i,j)==0 & i~=1 then printf(' \t') else if j==1 then printf(' %.1f\t',z(i,j)) else printf('%.7f\t',z(i,j)) end end end printf('\n') end x=poly(0,'x') l=z(1,2)+x*z(1,3)+x*(x-1)*z(1,4)/2+x*(x-1)*(x-2)*z(1,5)/6 disp(l,"The required equation is :") p=(x11-x01)/h; disp(f1(1,p),"fp (6) ="); p=(x12-x02)/h; disp(f1(3,p),"fp (2.5) =");
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// Example 14.1 F=60; // Frequency P=6; // No.Of poles ns=(120*F)/P; // Speed Of rotation disp('Speed Of rotation Is = '+string(ns)+' Rpm'); F1=20; // Decreased frequency P1=(120*F1)/ns; // Number Of poles disp('Number Of poles = '+string(P1)); // p 546 Ex14.1
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clc clear printf("example 7.11 page number 316\n\n") //to find the product concentration printf("this is a theoritical question, book shall be referred for solution")
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//Caption:transfer_function // example 11_2 //page 469 syms G1 G2 G3 H1; s=%s; G1=4/(s*(s+4)); G2=s+1.2; G3=s+0.8; H1=1; H2=(G2+G3); a=G1/.H1; y=a/(1+a*H2) disp(y,"C(s)/R(s)=")
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//Fluid Systems - By - Shiv Kumar //Chapter 12- Reciprocating Pumps //Example 12.13 //To Determine the Crank Angle, at which there is no flow of water to or from the vessel. clc clear //Given Data:- D=17.5; //Bore diameter, cm L=35; //Stroke Length, cm d_s=15; //Diameter of Suction pipe, cm N=150; //Speed, rpm //Computations:- D=D/100; //m L=L/100; //m d_s=d_s/100; //m omega=2*%pi*N/60; //rad/s A=(%pi/4)*D^2; //m^2 r=L/2; //m Q_s=2*A*omega*r/%pi; //Rate of flow from sump upto air vessel, m^3/s theta=asind(Q_s/(A*omega*r)); //degrees //Result:- printf("The Crank Angle at which there is no flow, theta=%.2f Degrees\n",theta)
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clc // Given that p = 1 // Pressure in atm t = 300 // Temperature in K F = 5 // For oxygen gas degree of freedom printf("\n Example 22.5 \n") v = 445 // In m/s as given in the book m = 5.31e-26 // Mass of oxygen molecule in kg sigma = 3.84e-19 // As given in the book in m^2 k = (1/6)*(v*F*(1.38*10^-23))/sigma // If the gas has Maxwellian velocity distribution, k_ = (1/3)*(F*(1.38*10^-23)/sigma)*((1.38*10^-23)*t/(%pi*m))^(1/2) printf("\n Thermal conductivity = %f W/mK,\n If the gas has Maxwellian velocity distribution,\n Thermal conductivity = %f W/mK",k,k_)
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//Example 4.8 clc disp("V_L = 230 V, R_a between lines = 1.8 ohm") disp("(V_oc)_line = 230 V, I_scc = 12.5 A for same I_f = 0.38 A") disp("The value of open circuit e.m.f is always line value unless and until specifically mentioned to be a phase value") disp("Therefore, Z_s = (V_oc)_ph / (I_scc)_ph |for same I_f") voc=230/sqrt(3) format(7) disp(voc," (V_oc)_ph(in V) =") zs=132.79/12.5 disp(zs,"Therefore, Z_s(in ohm/phase) =") disp("R_a between lines = 1.8 ohm") disp("For star connection, R_a between the terminals is 2 R_a per ph") disp("Therefore, 2R_a per ph = 1.8") disp("Therefore, R_a per ph = 0.9 ohm") xs=sqrt((10.623^2)-(0.9^2)) format(7) disp(xs,"Therefore, X_s(in ohm/phase) = sqrt(Z_s^2 - R_a^2) =") disp("Now regulated is asked for I_a = 10 A") disp("Now : The value of Z_s is calculated for I_s = 12.5 A and not at I_s = 10 A. It will be different for I_s = 10 A. But in this problem the test results are not given hence it is not possible to sketch the graphs to detemine Z_s at I_a = 10 A. So value of Z_s calculated is assumed to be same as I_a = 10 A") disp("(i) For 0.8 lagging p.f.") vph=230/sqrt(3) format(7) disp(vph,"V_ph(in V) = V_L/sqrt(3) =") disp("I_a = 10 A") disp("cos(phi) = 0.8 so sin(phi) = 0.6") disp("(E_ph)^2 = (V_ph*cos(phi)+I_a*R_a)^2 + (V_ph*sin(phi)+I_a*X_s)^2") eph=(((132.79*0.8)+(10*0.9))^2)+(((132.79*0.6)+(10*10.585))^2) p=sqrt(eph) format(8) disp(p,"Therefore, E_ph(in V) = ") regu=((218.39-132.79)/132.79)*100 format(6) disp(regu,"Therefore, %Regulation(in percentage) = (E_ph-V_ph / V_ph)*100 =") disp("(ii) For 0.8 leading p.f.") disp("(E_ph)^2 = (V_ph*cos(phi)+I_a*R_a)^2 + (V_ph*sin(phi)+I_a*X_s)^2") eph=(((132.79*0.8)+(10*0.9))^2)+(((132.79*0.6)-(10*10.585))^2) p=sqrt(eph) format(8) disp(p,"Therefore, E_ph(in V) = ") regu=((118.168-132.79)/132.79)*100 format(6) disp(regu,"Therefore, %Regulation(in percentage) = (E_ph-V_ph / V_ph)*100 =")
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//Ex:2.6 clc; clear; close; x1r=2*%pi/3;// in radian x2r=2*%pi/3;// in radian D=4*%pi/(x1r)^2;// the max directivity // Now, let us find the exact value of the max directivity and compare the result // y=Bo.cos(x) // ymax=Bo // Prad=integration of (Bo.cos(x).sin(x)) with limit 0 to 2*pi P=integrate('sin(2*x)','x',0,2*3.14); // Prad=%pi*Bo*integration of (Bo.cos(x).sin(x)) with limit 0 to 2*pi // then we get Prad=%pi*Bo // Do=(4*pi*ymax)/Prad=4*pi*Bo/%pi*Bo Do=4;// exact value of the max directivity printf("The max directivity = %f (dimensionless)", D); printf("\n The exact value of the max directivity = %d (dimensionless)", Do); printf("\n The exact max directivity is 4 and its approx. value is 2.84. Better approximations can be obtained if the patterns have much narrower beamwidths.");
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clc //RESOLUÇÃO NUMÉRICA DE UM SISTEMA NÃO LINEAR ///////////////////////////////////////////////////////////////////////// // MÉTODO DE NEWTON - RAPHSON // //////////////////////////////////////////////////////////////////////// // n: dimensão do sistema //F: vetor das funções a serem igualadas a zero (f1, f2, f3,...,fn) //J: Matriz Jacobiana //X0: Aproximação inicial para a solução exata // eps1: precisão a ser utilizada function w = naolinear(F, J, X0, eps1) n=length(F(X0)) max_iter = 200; teste=10.0; iter=1; // salvando X0 na coluna 1 da matriz M for i=1:n M(i,1)=X0(i) end while((teste>eps1) | iter>=max_iter ) do VF = F(X0) MJ=J(X0) S=MJ \ (- VF) X1 = S + X0 for i=1:n M(i,iter+1)=X1(i) end d = X1 - X0 teste=sqrt( sum(d.^(2)) ) iter = iter +1 X0=X1 end printf("\n") printf(" NEWTON - RAPHSON \n") printf("SISTEMAS NÃO LINEARES ") printf("\n \n \n") printf("k= %g iteracoes \n \n", iter) w = M endfunction
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# REFERENCE: # EMSOFT paper inf = float('inf') plant_pvt_init_data = None # Property initial_set = [[4.0, 21.0, -1.0, -1.0], [5.0, 22.0, 1.0, 1.0]] ROI = [[-1, -1, -5,-5], [26, 26, 5, 5]] Q = [[7., 9., -inf, -inf], [8., 10., inf, inf]] error_set = Q T = 20.0 # Working set for P, Q # ./scamr.py -f ../examples/nav/nav30.tst -cn --refine model-dft --prop-check --incl-error --seed 0 --max-model-error 10 --max-paths 1000 # # grid_eps = [1.1]*4 # delta_t = 5.0 # num_samples = 100 # # grid_eps = [0.11]*4 # delta_t = 5.0 # num_samples = 2 grid_eps = [0.2]*4 delta_t = 5.0 num_samples = 10 # Gets the right x0 from linprog: but the interval is big enough to # concretize succesfully # grid_eps = [5.1]*4 # delta_t = 5.0 # num_samples = 100 # grid_eps = [1.1]*4 # delta_t = 5.0 # num_samples = 10 #[but all paths] MAX_ITER = 4 plant_description = 'python' plant_path = 'nav30.py' ############################################# ############## Don't care params ############ ############################################# initial_controller_integer_state = [] initial_controller_float_state = [] num_control_inputs = 0 min_smt_sample_dist = 0 ci = [[], []] pi = [[],[]] controller_path = None controller_path_dir_path = None initial_discrete_state = [] initial_private_state = [] # Viloations # # S # x0=[ 4.14327461 21.51742883 0.8471542 0.9884877 ] -> x=[ 22.44414369 11.999 0.22792075 -0.86384343], t=30.1382177243 # x0=[ 4.50024758 21.82478644 0.97146715 0.6993149 ] -> x=[ 22.4524101 11.999 0.22748131 -0.86401213], t=30.1798284278
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clc; //page no 492 //prob no. 14.14 Zo=50;//line impedance in ohm ZL=75+%i*25; // the requirment of this is simply to match the 50ohm line to the impedsnce at this point on the line,which is 88.38 ohm,resistive. Z2=88.38;//in ohm //The required turn ratio is N1_N2=sqrt(Zo/Z2); disp(N1_N2,'The required turn ratio is');
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//<f2>=%ris(i,j,f2,n) // %rip(i,j,r,m) insere la matrice de fractions rationnelles r dans la matrice //de scalaires m pour les indices de lignes (de colonnes) i (j). (m(i,j)=r) //! [l,c]=size(n), if size(i)<>[-1,-1]; l=maxi([l,maxi(i)]); end; if size(j)<>[-1,-1]; c=maxi([c,maxi(j)]); end; d=ones(l,c); n(i,j)=f2(2),d(i,j)=f2(3) f2(2)=n;f2(3)=d; //end
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 5 : INDUCTION MACHINES // EXAMPLE : 5.11 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA m = 3; // Total Number of phase in Induction Motor p = 6; // Total number of Poles of Induction Motor f = 50; // Frequency in Hertz s = 0.03; // Slip // CALCULATIONS Ns = (120*f)/p; // Synchronous Speed in RPM Nr = (1-s)*Ns; // Rotor Speed in RPM Nf = Ns - Nr; // Speed of Forward Rotating magnetic fields with respect to stator and rotor in RPM Nb = Ns + Nr; // Speed of Backward Rotating magnetic fields with respect to stator and rotor in RPM // DISPLAY RESULTS disp("EXAMPLE : 5.11 : SOLUTION :-"); printf("\n (a) Speed of Forward Rotating magnetic fields with respect to stator and rotor is equal to + %.f RPM \n",Nf) printf("\n (b) Speed of Backward Rotating magnetic fields with respect to stator and rotor is equal to + %.f RPM \n",Nb)
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//Finding of Diameter //Given D=25; P1=25; P2=120; //To Find A=(%pi/4)*D^2; d=(A*P1)/P2; d1=sqrt(d); disp("Diameter ="+string(d1)+" centimeter");
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//x[n] = 1+sin(2*%pi/N)n+3cos(2*%pi/N)n+cos[(4*%pi/N)n+%pi/4] clear; close; clc; N = 10; n = 0:0.01:N; Wo = 2*%pi/N; xn =ones(1,length(n))+sin(Wo*n)+3*cos(Wo*n)+cos(2*Wo*n+%pi/4); for k =0:N-2 C(k+1,:) = exp(-sqrt(-1)*Wo*n.*k); a(k+1) = xn*C(k+1,:)'/length(n); if(abs(a(k+1))<=0.1) a(k+1)=0; end end a =a'; a_conj =conj(a); ak = [a_conj($:-1:1),a(2:$)]; Mag_ak = abs(ak); for i = 1:length(a) Phase_ak(i) = atan(imag(ak(i))/(real(ak(i))+0.0001)); end Phase_ak = Phase_ak' Phase_ak = [Phase_ak(1:$-1) -Phase_ak($:-1:1)]; k = -(N-2):(N-2); subplot(2,1,1) plot2d3('gnn',k,Mag_ak,5) xtitle('abs(ak)','k','ak') subplot(2,1,2) plot2d3('gnn',k,Phase_ak,5) xtitle('phase(ak)','k','ak')
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clear// //Variable Declaration R=45 //Radius of the circle in mm r=20 //Radius of the smaller circle in mm h=100 //Depth of the straight section in mm //Calculations //Part 1 //Triangle b=2*R //Breadth in mm A_t=b*h*0.5 //Area in mm^2 Ix_bar_t=b*h**3*36**-1 //Moment of inertia in mm^4 y_bar1=2*3**-1*h //centroidal axis in mm Ix_t=Ix_bar_t+A_t*y_bar1**2 //moment of inertia in mm^4 //Semi-circle A_sc=%pi*R**2*0.5 //Area of the semi-circle in mm^2 Ix_bar_sc=0.1098*R**4 //Moment of inertia in mm^4 y_bar2=h+(4*R*(3*%pi)**-1) //Distance of centroid in mm Ix_sc=Ix_bar_sc+A_sc*y_bar2**2 //Moment of inertia in mm^4 //Circle A_c=%pi*r**2 //Area of the circle in mm^2 Ix_bar_c=%pi*r**4*4**-1 //Moment of inertia in mm^4 y_bar3=h //Distance of centroid in mm Ix_c=Ix_bar_c+A_c*y_bar3**2 //Moment of inertia in mm^4 //Composite Area A=A_t+A_sc-A_c //Total area in mm^2 Ix=Ix_t+Ix_sc-Ix_c //Moment of inertia in mm^4 //Part 2 y_bar=(A_t*y_bar1+A_sc*y_bar2-A_c*y_bar3)/(A) //Location of centroid in mm Ix_bar=Ix-A*y_bar**2 //Moment of inertia in mm^4 //Result printf("\n Moment of inertia about x-axis is %0.0f mm^4",Ix) printf("\n Moment of inertia about the centroidal axis is %0.0f mm^4",Ix_bar)
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a=imread('C:\Users\Mohammed Kesury\Desktop\Sem 6\DIP\cameraman.tif') [counts,cells]=imhist(a) [m n]=size(cells) imhist(a,m,'black')
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clc; h1=3442.6; h2=2713; h6=3487; h7=2535; h3=112; TW=(h1-h2)+(h6-h7); Q=(h1-h3)+(h6-h2); Ceff=TW/Q; disp(Ceff,"cycle efficiency is:"); ssc=1/TW; disp("kg/kW h",ssc,"specific steam consuption is:")
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//Chapter-3, Example 3.7, Page 3.18 //============================================================================= clc clear //INPUT DATA P=6;//Number of poles f=50;//Supply frequency in Hz R2=0.4;//Rotor reisitance in ohm X2=4;//Rotor standstill reactance in ohm T1=2;//Ratio of maximum torque to starting torque //CALCULATIONS Ns=(120*f)/P;//Synchronous speed in rpm Sm=(R2/X2);//Slip at maximum torque NTM=(Ns*(1-Sm));//Speed of the motor at maximum torque in rpm T=((R2^2+X2^2)/(2*R2*X2));//Ratio of maximum torque to starting torque Rext=(sqrt(X2^2/((2*T1)-1))-R2);//Additional resistance required for the ratio of maximum torque to the statring torque to be 2 in ohm //OUTPUT mprintf('a)Speed of the motor at maximum torque is %i rpm \n b)Ratio of maximum torque to starting torque is %3.2f \n c)Additional resistance required for the ratio of maximum torque to the starting torque to be 2 is %3.1f ohm',NTM,T,Rext) //=================================END OF PROGRAM==============================
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errcatch(-1,"stop");mode(2);// calculation of relative dielectric constant l= 10// length of capacitor in mm b = 10 // width of capacitor in mm d = 2 // distance of separation in mm c = 1e-9 // capacitance in farad epsilon_0 = 8.85e-12 // permittivity of free space printf("\n Example 17.1") epsilon_r = c*d*1e-3/(epsilon_0*l*1e-3*b*1e-3) printf("\n Relative dielectric constant is %d",epsilon_r) exit();
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//example 4 //comparison of ideal carnot heat engine with actual heat engine clear clc Qh=1000 //rate of heat transfer to heat engine in kW W=450 //rate of production of work in kW Ql=Qh-W //rate of heat rejected by heat engine in kW nthermal=W/Qh //efficiency from the definition of efficiency Tl=300 //temperature of surroundings in K Th=550 //temperature of heat source in Celsius ncarnot=1-Tl/(Th+273) //efficiency if heat engine is considered to be ideal carnot heat engine W2=ncarnot*Qh //rate of work production if heat engine is assumed to be ideal carnot heat engine in kW Ql2=Qh-W2 //rate of heat rejected by heat engine in kW if heat engine is assumed to be ideal carnot heat engine printf("\n hence,energy discarded to the ambient surroundings is Ql2=%.0fkW.\n",Ql2) printf("\n and the engine efficiency is ncarnot=%.3f.\n",ncarnot)
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function [j]=jmat(n,m) //j=jmat(n,m) //This macro permutes block rows or block columns of a matrix // // n : number of block rows or block columns of the matrix // m : size of the (square) blocks //! // Copyright INRIA j=[]; for k=1:n,j(k,n-k+1)=1;end; j=j.*.eye(m,m);
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clc clear //Input data p1=1//Pressure at the end of suction stroke in kg/cm^2 T1=30+273//Temperature at the end of suction stroke in kg/cm^2 T3=1500+273//Maximum temperature during the cycle in K r=16//Compression ratio Cp=0.24//Specific heat at constant pressure in kJ/kg.K Cv=0.17//Specific heat at constant volume in kJ/kg.K g=1.41//Ratio of specific heats //Calculations T2=T1*r^(g-1)//Temperature at the end of adiabatic compression in K s=(((T3/T2)-1)/(r-1))*100//Percentage of the stroke at which cut off occurs r1=(r/(T3/T2))//Expansion ratio T4=T3/(r1)^(g-1)//Temperature at the end of adiabatic expansion in K qa=(Cp*(T3-T2))//Heat added in kcal/kg of air qre=(Cv*(T4-T1))//Heat rejected in kcal/kg of air nt=((qa-qre)/qa)*100//Air standard efficiency in percent //Output printf('(a) The percentage of stroke at which cut off takes place is %3.2f percent \n (b) The temperature at the end of expansion stroke is %3.0f K \n (c) The theoretical efficiency is %3.0f percent',s,T4,nt)
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clc; //e.g 19.6 Vcc=10; Rc=5*10**3; Re=1*10**3;0 RL=50*10**3; R1=50*10**3; R2=10*10**3; Rs=600; beta=50; Vs=10*10**-3; Vbe=0.7; Vth=(Vcc*R2)/(R1+R2); disp('V',Vth*1,"Vth="); Rth=(R1*R2)/(R1+R2); disp('10^3ohm',Rth*10**-3,"Rth="); Ie=(Vth-Vbe)/(Re+(Rth/beta)); disp('mA',Ie*10**3,"Ie="); re=25/(Ie*10**3); disp('ohm',re*1,"re="); Ri=beta*re; Ris=(Rth*Ri)/(Rth+Ri); disp('ohm',Ris*1,"Ris="); rl=(Rc*RL)/(Rc+RL); disp('Kohm',rl*10**-3,"rl="); Av=rl/re; disp(Av); Vin=(Vs*Ris)/(Ris+Rs); disp('mV',Vin*10**3,"Vin="); V0=Av*Vin; disp('mV',V0*1,"V0="); Avs=(Av*Vin)/Vs; disp(Avs);
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// Theory and Problems of Thermodynamics // Chapter 9 // Air_water Vapor Mixtures // Example 4 clear ;clc; //Given data V = 5 // volume of tank in m^3 X1 = 0.3 // volume fraction of Hydrogen X2 = 0.3 // volume fraction of Argon X3 = 0.4 // volume fraction of Methane Xf = 0.6 // final mixture composition of methane T = 300 // initial temperature of mixture in K P = 1 // initial pressure of mixture in MPa R = 8.314 // gas constant // Calculations p1 = X1*P // pressure of Hydrogen p2 = X2*P // pressure of Argon p3 = X3*P // pressure of Methane N1 = p1*1e3*V/(R*T) // pressure of Hydrogen N2 = p2*1e3*V/(R*T) // pressure of Argon N3 = p3*1e3*V/(R*T) // pressure of Methane // to determine the number of moles of methane in final mixture deff('y=moles(Nf)', 'y = Xf-(Nf/(N1+N2+Nf))') Nf = fsolve(0.1,moles) CH4_add = Nf-N3 // CH4 moles to be added N = N1 + N2 + Nf // total number of moles Pf = N*R*T/V * 1e-3 // Final pressure in MPa // Output Results mprintf('Amount of methane to be added = %4.4f kmol' , CH4_add); mprintf('\n Final pressure of mixture in Tank = %4.1f MPa' , Pf);
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//Chapter 6 //page no 140 //Given clear; clc; Tj=120;//in degree celsius Tamp=80;//n degree celsius Pt=2.1;//in W RthJ_a =34; //in k/w(Assumption) Rth=(Tj-Tamp)/Pt; printf("Rth = %0.0f K/W",Rth); if Rth>RthJ_a then printf("\n No Heat sink is required"); else printf("\n Yes,Heat sink is required"); end ;
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clc; //e.g 17.4 Vrms=100; a=45; Idc=0.5; Vm=sqrt (2)*Vrms; disp('V',Vm*1,"Vm="); //Idc=(Vm/(2*%pi*RL))*(1+cosd(a)); RL=(Vm/(2*%pi*Idc))*(1+cosd(a)); disp('ohm',RL*1,"RL=");
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clear; //clc(); // Example 14.6 // Page: 386 printf("Example-14.6 Page no.-386\n\n"); //***Data***// T = 100;//[C] Temperature of the outside P_outside = 1;//[atm] // At 100 C, the surface tension between steam and water is T = 0.05892;//[N/m] From metric steam table (7, page 267) // Pressure difference between inside and outside of a drop is given by the expression // (P_inside - P_outside) = (4*T)/d_i // Let (P_inside - P_outside) = delta_P , so //delta_P = (4*T)/d_i // For the drop of diameter d_1 = 0.001;//[m] // So delta_P_1 = (4*T)/d_1;//[Pa] // Which is certainly negligible // If we reduce the diameter to d_2 = 10^(-6);//[m] // So delta_P_2 = (4*T)/d_2;//[Pa] // If we reduce it to diameter that is smallest sized drop likely to exist d_3 = 0.01*10^(-6)//[m] // Then the calculated pressure difference is delta_P_3 = (4*T)/d_3;//[Pa] printf("Pressure difference with the change in radius of the drop of the water is given as in the following table\n\n"); printf(" Diameter of the droplet (d_i)(in meter) Pressure difference ( P_inside - P_outside )(in atm)\n"); printf(" %0.2e %0.2e\n",d_1,delta_P_1); printf(" %0.2e %0.2e\n",d_2,delta_P_2); printf(" %0.2e %0.2e\n",d_3,delta_P_3);
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// sum 27-3 clc; clear; m=6; Zp=30; Zg=45; dp=m*Zp; rp=dp/2; dg=m*Zg; rg=dg/2; R=sqrt(rg^2+rp^2); gamma1=180/%pi*asin(rp/R); gamma2=(90-gamma1); ha=6; hf=1.25*ha; phi=180/%pi*atan(ha/R); beta=180/%pi*atan(hf/R); //let Face Cone Angle be FCA FCA=(gamma1+phi); //Let Root cone angle be RCA RCA=(gamma1-beta); // printing data in scilab o/p window printf(" gamma1 is %0.1f deg ",gamma1); printf("\n gamma2 is %0.1f deg ",gamma2); printf("\n R is %0.2f mm ",R); printf("\n FCA is %0.3f deg ",FCA); printf("\n RCA is %0.2f deg ",RCA);
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tpyrun $p/bin/util/store_test
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); codeblock readtextfile(ScriptFilePath+"\_FoucaultTools.sci"); codeblock readtextfile(ScriptFilePath+"\_Colors.sci"); codeblock readtextfile(ScriptFilePath+"\_AnimateTools.sci"); codeblock readtextfile(ScriptFilePath+"\_CamMoveTools.sci"); planesize=2500; pendframe=root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject; planeframe=pendframe.addsubframe("PendPlane"); planeframe.CastVolumeShadow=false; planeframe.add("Rectangle", "color":color(0,0.5,1,0.3),"enablelight":false,"RenderBack":true,"BlendType":BlendTranslucent, "DepthMask":DepthMaskDisable, "Position":point(-1*planesize,0,-2*planesize+3500),"Axis1":vector(2*planesize,0,0),"Axis2":vector(0,0,2*planesize)); planeframe.visible=false; #planeframe.addignoreviewport("sky"); pendcolor1=color(0.5,0.5,0.5); pendcolor2=color(1.0,0.8,0.0); pendspeccolor1=color(0.6,0.6,0.6);pendspecval=30; ########################################################################## #Create sky viewport try { DelObject(root.Viewports.Sky); } au2km=149598000; myviewport=CreateNewViewPort(0.5,0,1,1); myviewport.name="Sky"; myviewport.Framesize=0.005; myviewport.FrameColor=color(0.2,0.2,0.2); myviewport.FrameRight=false;myviewport.FrameTop=false;myviewport.FrameBottom=false; myviewport.start; myviewport.setscene(root.SC); myviewport.FocalDistance=21000; myviewport.cameradir=vecnorm(vector(-0.4,-1.5,-2)); myviewport.cameraupdir=vector(0,0,1); myviewport.enableusernavigation=root.Viewports.main.enableusernavigation; myviewport.EnableUserTimeControl=root.Viewports.main.EnableUserTimeControl; myviewport.NearClipPlane=0.1*myviewport.FocalDistance; myviewport.FarClipPlane=20*myviewport.FocalDistance; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.GlobeRendering.addignoreviewport("sky"); Cam_Init(myviewport); root.Viewports.Sky.Active=true; root.Viewports.main.XMaxFrac=0.63; root.Viewports.Sky.XMinFrac=0.63; root.Viewports.Sky.XMaxFrac=1.0; #================================================================================= # SETUP #================================================================================= root.time=time(2009,8,1,22,0,0); root.TimeSpeedFactor=0; root.Viewports.main.cameradir=vecnorm(vector(0.2,-0.6,-0.7)); #This sets the pendulum position to a particular lattitude position on Earth setposition(deg2rad(89.9)); #================================================================================= # ANIMATION #================================================================================= StartPendulum(true); FadeViewportsIn; Animate(2); #start the time starttime; animate(7); #show gravity arrow root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendSusp.GravArrow.visible=true; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendSusp.GravArrow.blinkperiod=0.4; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendSusp.GravArrow.maxblinkcount=5; animate(9); #show rotation indication root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendSusp.RotIndic.visible=true; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendSusp.RotIndic.blinkperiod=0.4; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendSusp.RotIndic.maxblinkcount=5; animate(9); #show swing plane root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.visible=true; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.blinkperiod=0.4; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.maxblinkcount=2; animate(10); #move pendulum to equator stoptime; #stopcorotate; animate(2); root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.visible=false; MovePendulum(deg2rad(0.0)); animate(0.5); Cam_Rotate(root.Viewports.main,vector(0.486147924, -0.833475705, 0.26263748),4); animate(5); #start the time StartPendulum(true); starttime; animate(12); #corotate with earth #startcorotate; #animate(4); #set at belgium position FadeViewportsOut; root.time=time(2009,8,1,7,0,0); root.TimeSpeedFactor=0; setposition(deg2rad(51.0)); FastStopCorotate; root.Viewports.main.cameradir=vector(-0.002367378, -0.99255836, -0.121746861); StartPendulum(true); FadeViewportsIn; animate(2); starttime; animate(6); #show swing plane root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.visible=true; animate(12); #set at south pole FadeViewportsOut; root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.visible=false; root.time=time(2009,1,1,0,0,0); root.TimeSpeedFactor=0; setposition(deg2rad(-89.0)); FastStopCorotate; root.Viewports.main.cameradir=vector(0.142389847, 0.629207954, 0.764082773); StartPendulum(true); FadeViewportsIn; animate(2); starttime; animate(6); root.SC.Universe.SolarSystem.Earth.Inclin.Globe.LocFrame.PendObject.PendPlane.visible=true; animate(12); FadeViewportsOut; stop;
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clc //ex6.6 R=10*10^3; f_o=1*10^6; B=100*10^3; I=10^-3*complex(cos(0),sin(0)); Q_p=f_o/B; //quality factor L=R/(2*%pi*f_o*Q_p); C=Q_p/(2*%pi*f_o*R); //At resonance V_out=I*R; Z_L=%i*2*%pi*f_o*L; Z_C=-%i/(2*%pi*f_o*C); //across resistance I_R=V_out/R; I_R_R=real(I_R); //real part I_R_I=imag(I_R); //imaginary part I_R_max=sqrt((I_R_R^2)+(I_R_I^2)); //peak value I_R_phi=atan(I_R_I/I_R_R); //phase angle //across inductance I_L=V_out/Z_L; I_L_R=real(I_L); //real part I_L_I=imag(I_L); //imaginary part I_L_max=sqrt((I_L_R^2)+(I_L_I^2)); //peak value //Z_L is pure imaginary ==> V_L is pure imaginary which means V_L_phi can be +or- %pi/2 if ((I_L/%i)==abs(I_L)) then I_L_phi=%pi/2 elseif ((I_L/%i)==-abs(I_L)) then I_L_phi=-%pi/2 end //across capacitor I_C=V_out/Z_C; I_C_R=real(I_C); //real part I_C_I=imag(I_C); //imaginary part I_C_max=sqrt((I_C_R^2)+(I_C_I^2)); //peak value //Z_C is pure imaginary ==> V_C is pure imaginary which means V_C_phi can be +or- %pi/2 if ((I_C/%i)==abs(I_C)) then I_C_phi=%pi/2 elseif ((I_C/%i)==-abs(I_C)) then I_C_phi=-%pi/2 end disp('Current phasor across Resistance') disp(I_R_max,'peak value in amperes') disp(I_R_phi*180/%pi,'phase angle in degrees') disp('') disp('Current phasor across Inductance') disp(I_L_max,'peak value in amperes') disp(I_L_phi*180/%pi,'phase angle in degrees') disp('') disp('current phasor across capacitance') disp(I_C_max,'peak value in amperes') disp(I_C_phi*180/%pi,'phase angle in degrees') disp('Phasor diagram cannot be drawn here')
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// Chapter 2 example 4 clc; clear; // Variable declaration h = 1.054*10^-34; //plancks constant in J.s m = 9.1*10^-31; // mass of electron in kg a = 5*10^-10; // width of infinite potential well in m e = 1.6*10^-19; // charge of electron coulombs // Calculations //cos(ka) = ((Psin(alpha*a))/(alpha*a)) + cos(alpha*a) //to find the lowest allowed energy bandwidth,we have to find the difference in αa values, as ka changes from 0 to π // for ka = 0 in above eq becomes // 1 = 10*sin(αa))/(αa)) + cos(αa) // This gives αa = 2.628 rad // ka = π , αa = π // sqrt((2*m*E2)/h^2)*a = π E2 = ((%pi*%pi) *h^2)/(2*m*a^2*e); //energy in eV E1 = ((2.628^2) *h^2)/(2*m*a^2*e) // for αa = 2.628 rad energy in eV dE = E2 - E1; //lowest energy bandwidth in eV // Result mprintf('Lowest energy bandwidth = %3.3f eV',dE);
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b=[1 2 3 2 3 4]; a=[1 2 3; 4 5 6]; y=filtord(b,a); disp(y); //output //!--error 10000 //check input dimension //at line 36 of function filtord called by : //y=filtord(b,a);
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 7 Example 14") V_A=6;//volume of compartment A in m^3 V_B=4;//volume of compartment B in m^3 To=300;//temperature of atmosphere in K Po=1*10^5;//atmospheric pressure in pa P1=6*10^5;//initial pressure in pa T1=600;//initial temperature in K V1=V_A;//initial volume in m^3 V2=(V_A+V_B);//final volume in m^3 y=1.4;//expansion constant R=287;//gas constant in J/kg K Cv=0.718;//specific heat at constant volume in KJ/kg K disp("expansion occurs in adiabatic conditions.") disp("temperature after expansion can be obtained by considering adiabatic expansion") disp("T2/T1=(V1/V2)^(y-1)") disp("so T2=T1*(V1/V2)^(y-1) in K") T2=T1*(V1/V2)^(y-1) T2=489.12;//approx. disp("mass of air,m=(P1*V1)/(R*T1)in kg") m=(P1*V1)/(R*T1) m=20.91;//approx. disp("change in entropy of control system,deltaSs=(S2-S1)=m*Cv*log(T2/T1)+m*R*10^-3*log(V2/V1)in KJ/K") deltaSs=m*Cv*log(T2/T1)+m*R*10^-3*log(V2/V1) disp("here,there is no change in entropy of environment,deltaSe=0") deltaSe=0; disp("total entropy change of combined system=deltaSc=deltaSs+deltaSe in KJ/K") deltaSc=deltaSs+deltaSe disp("loss of available energy(E)=irreversibility=To*deltaSc in KJ") E=To*deltaSc disp("so loss of available energy,E=0.603 KJ")
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function [gm]=cfspec(g) //[gm]=cfspec(g) computes a co-spectral factorization: // g = gm*gtild(gm) //with stable gm and gm^-1 ( gm^-1 = invsyslin(gm) ). //-- g: syslin list defining the linear system g //-- gm: //Assumptions: //- g is invertible ( inv(D) exists ), //- g and g^1 (invsyslin(g)) have no poles on the imaginary axis. //- gtild(g) = g. // (poles and zeros of g are symmetric wrt imaginary axis)) //- g(+oo) = D is positive definite. //! // Copyright INRIA if type(g)==1 then gm=chol(g),return,end, gm=fspec(g'), gm=gm'
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clc clear function [hx]=hxsoma(x,den) if den > x then hx=return(1) end hx=((x^den)/(den))+hxsoma(x,den+1) endfunction function [hx]=hxmult(x,den) if den > x then hx=return(1) end hx=((x^den)/(den))*hxmult(x,den+1) endfunction x=input("Informe um valor para X :") den=1 numerador=hxsoma(x,den) denominador=hxmult(x,den) printf("h(x) = %.50f",numerador/denominador)
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//Chapter 16, Problem 13 clc; eff = 0.8; // effficiency f = 50; // in ohm Pout = 4800; // in Watt pf1 = 0.625 // power factor pf2 = 0.95 // power factor V = 240; // in Volts //calculation: Pin = Pout/eff Im = Pin/(V*pf1) phi1 = acos(pf1) phi1d = phi1*180/%pi //When a capacitor C is connected in parallel with the motor a current Ic flows which leads V by 90°. phi2 = acos(pf2) phi2d = phi2*180/%pi Imh = Im*cos(phi1) //Ih = I*cos(phi2) Ih = Imh I = Ih/cos(phi2) Imv = Im*sin(phi1) Iv = I*sin(phi2) Ic = Imv - Iv C = Ic/(2*%pi*f*V) kvar = V*Ic/1000 printf("\n\n (a)Current taken by the motor, Im = %.0f A",Im) printf("\n\n (b)Supply current after p.f. correction, I = %.2f A ",I) printf("\n\n (c)Magnitude of the capacitor current Ic = %.0f A",Ic) printf("\n\n (d)Capacitance, C = %.0f μF ",(C/1E-6)) printf("\n\n (d)kvar rating of the capacitor = %.2f kvar ",kvar)
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i = imread('test3.jpg'); result = ocr(i); disp(result);
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clc //initialisation of variables m1= 5 //kg c1= 1.26 //kJ/kg K m2= 20 //kg c2= 4.19 //kJ/kg K T1= 95 //C T2= 25 //C //CALCULATIONS T= (m1*c1*T1+m2*c2*T2)/(m1*c1+m2*c2) S1= m1*c1*log((273.15+T)/(273.15+T1)) S2= m2*c2*log((273.15+T)/(273.15+T2)) S= S1+S2 //RESULTS printf (' change in entropy of billet = %.4f kJ/K',S1) printf (' \n change in entropy of water= %.4f kJ/kg K',S2) printf (' \n change in entropy of water= %.4f kJ/kg K',S)
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//Calculate viscosity. Sutherland's formula function [viscosity]=viscosityair(T) viscosity = 18.27*(291.15+120)/(T+120)*((T/291.15)^(3/2))*1e-6; endfunction
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h=100;//in mm t=2;//in mm Mx=1000;//N.mm
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clc clear //Initialization of variables p1=40 //psia t1=80 //F p2=30 //psia ar=0.5 //sq ft v1=200 //ft/s R=53.35 cp=0.24 g=32.17 J=778 t2=78 //F //calculations G=40 //lb/sq ft/sec rho2=144*p2/(R*(t2+460)) v2=p1/rho2 //results printf("Velocity = %d ft/s",v2)
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 11 : AC power Analysis // Example 11 - 18 clear; clc; close; // // Given data P = 300.0000; Vrms = 13.0000; pf = 0.8000; Hours = 520; Energy_Charge = 0.0600; pf_penalty = 0.001; pf_credit = 0.001; // Calculations Energy Consumed W = P * Hours; // Calculations Delta Energy Consumed Delta_W = (5*pf_penalty)*W; // Calculation Total Energy Consumed Wt = W + Delta_W; // Calculations Cost Per Month Cost = Energy_Charge * Wt; // disp("Example 11-18 Solution : "); printf(" \n a. Cost = Cost For Month = %.3f Dollar",Cost)
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// Exa 5.12 format('v',7);clc;clear;close; // Given data P = 0.4;//power dissipation in each arm in W Rarm = 150;// in ohm //P = (I^2)*Rarm; I = sqrt(P/Rarm);// in A //Apply KVL to the loop ABCEFA, (-I*Rarm) - (I*Rarm) - (2*I) + 25 - (2*I*R) = 0; R = ((-I*Rarm) - (I*Rarm) - (2*I) + 25)/(2*I);//required series resistance in ohm disp(R,"The required series resistance in Ω is");
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// Fixed point 16-bit cosine and sine clear function res=dsp32_k_cos(y) pi = 3.1415926535897; // Q1.31 emulation y = y*2^31; one = 1.0000000000e+00*2^31; half = 0.61685027507*2^31; //0.5*(pi^2/8); C1 = 0.50733903092*2^31; //pi^2*(4.1666667908e-02*pi^2)/8; C2 = -0.16690785015*2^31; //(-1.3888889225e-03*pi^4)*(pi^2/8); C3 = 0.02941632920*2^31; //(2.4801587642e-05*pi^6)*(pi^2/8); C4 = -0.00322586085*2^31; //(-2.7557314297e-07*pi^8)*(pi^2/8); C5 = 0.00024118485*2^31; //(2.0875723372e-09*pi^10)*(pi^2/8); C6 = -0.00001295308*2^31; //(-1.1359647598e-11*pi^12)*(pi^2/8); z = y*y/2^31; produ = z*C6/2^31; suma = C5 + produ; produ = z*suma/2^31; suma = C4 + produ; produ = z*suma/2^31; suma = C3 + produ; produ = z*suma/2^31; suma = C2 + produ; produ = z*suma/2^31; suma = C1 + produ; r = z*suma/2^31; res = one - ((half*z - (z*r)))/2^28; res = res/2^31; endfunction function res=dsp32_k_sin(y) pi = 3.1415926535897; // Q1.31 emulation y = y*2^31; S0 = 0.78539816340*2^31; //pi/4; S1 = -0.64596411675*2^31; //-1.6666667163e-01*pi^3/8; S2 = 0.31877052162*2^31; //8.3333337680e-03*pi^5/8; S3 = -0.07490806720*2^31; //-1.9841270114e-04*pi^7/8; S4 = 0.01026823400*2^31; //2.7557314297e-06*pi^9/8; S5 = -0.00092125426*2^31; //-2.5050759689e-08*pi^11/8; S6 = 0.00005769937*2^31; //1.5896910177e-10*pi^13/8; z = y*y/2^31; v = z*y/2^31; produ = z*S6/2^31; suma = S5 + produ; produ = z*suma/2^31; suma = S4 + produ; produ = z*suma/2^31; suma = S3 + produ; produ = z*suma/2^31; suma = S2 + produ; produ = z*suma/2^31; suma = S1 + produ; produ = v*suma/2^30; suma = S0*y/2^31 + produ; res = suma/2^29; endfunction // [-2*pi 2*pi] => [-1 1] function res=dsp32_sin(angle) // convertion from float to Q1.15 pi = 3.1415926535897; x = angle/(pi); x = x; // Input of this function is in binary angular measure format (Q15 // with the full -1 to 1 range representing -pi to pi). */ // Determine the quadrant the input resides in temp = (x + 0.25) n = abs(int(temp)); // printf("%f\t", temp/2^15); // n = temp //temp=abs(x) + 0.25*2^15; // n = int(abs(int((temp + 0.25*2^15)/2^14))); // translate input down to +/- pi/4 x = modulo(x - n * 0.5, 1); // printf("%f %f\t", n, x/2^15); // call the appropriate function given the quadrant of the input // printf("%f\t", x); if n == 0 then res = dsp32_k_sin(x); elseif n == 1 then res = dsp32_k_cos(x); elseif n == 2 then res = -dsp32_k_sin(x); elseif n == 3 then res = -dsp32_k_cos(x); else res = dsp32_k_sin(x); end // printf("%f\t", res); endfunction function res=dsp32_cos(angle) pi = 3.1415926535897; res = dsp32_sin(angle + pi/2); endfunction // Input angle from -pi/4 to pi/4 function res=dsp16_k_sin(y) // series coefficients, tweaked with Chebyshev s1 = 0.785369873046875*2^15; //0x6487; s3 = 0.322784423828125*2^15; //0x2951; s5 = 0.03875732421875*2^15; //0x4f6; z = (y * y)/2^12; produ = (z * s5)/2^16; suma = s3 - produ; produ = (z * suma)/2^16; suma = s1 - produ; res=(y * suma)/2^13; endfunction function res=dsp16_k_cos(y) c0 = 1.*2^15; //0x7fff; c2 = 0.61651611328125*2^15; //0x4eea; c4 = 0.1231689453125*2^15; //0x0fc4; z = (y * y)/2^12; produ = (z * c4)/2^16; suma = c2 - produ; produ = (z * suma)/2^15; res = (c0 - produ); endfunction // [-2*pi 2*pi] => [-1 1] function res=dsp16_sin(angle) // convertion from float to Q1.15 pi = 3.1415926535897; x = angle/(pi); x = x*2^15; // Input of this function is in binary angular measure format (Q15 // with the full -1 to 1 range representing -pi to pi). */ // Determine the quadrant the input resides in temp = (x + 0.25*2^15) if temp > 0 then n = abs(int(temp/2^14)); else n = 3 - abs(int(temp/2^14)); end printf("%f\t", temp/2^15); // n = temp //temp=abs(x) + 0.25*2^15; // n = int(abs(int((temp + 0.25*2^15)/2^14))); // translate input down to +/- pi/4 x = modulo(x - n * 0.5*2^15, 2^16); printf("%f %f\t", n, x/2^15); // call the appropriate function given the quadrant of the input if n == 0 then res = dsp16_k_sin(x)/2^15; elseif n == 1 then res = dsp16_k_cos(x)/2^15; elseif n == 2 then res = -dsp16_k_sin(x)/2^15; elseif n == 3 then res = -dsp16_k_cos(x)/2^15; else res = dsp16_k_sin(x)/2^15; end endfunction function res=dsp16_cos(angle) pi = 3.1415926535897; res = dsp16_sin(angle + pi/2); endfunction pi = 3.1415926535897; err_cos_moy = 0; err_cos_max = 0; for i=-pi/2:0.01:pi/2, err = abs((dsp32_cos(i) - cos(i))); err_cos_moy = err_cos_moy + err; if err > err_cos_max then err_cos_max = err; end end err_cos_moy = err_cos_moy/length(-pi:0.1:pi); printf("Error average for cosinus:\t%.10f\n", err_cos_moy); printf("Error maximum for cosinus:\t%.10f\n", err_cos_max); disp(''); err_sin_moy = 0; err_sin_max = 0; for i=-pi/2:0.01:pi/2, err = abs((dsp32_sin(i) - sin(i))); err_sin_moy = err_sin_moy + err; if err > err_sin_max then err_sin_max = err; end end err_sin_moy = err_sin_moy/length(-pi:0.1:pi); printf("Error average for sinus:\t%.10f\n", err_sin_moy); printf("Error maximum for sinus:\t%.10f\n", err_sin_max);
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clc //initialisation of variables g= 32.2 //ft/sec^2 h= 50 //ft vd= 5 //ft/sec A= 60 //degrees //CALCULATIONS R= h+(vd^2/(2*g)) x=poly(0,"x") vec=roots(x^2-(2*vd/tand(A))*x-R*g) v1= vec(1) V1= sqrt(4*vd^2+(v1-((2*vd)/tand(A)))^2) H1= 0.5*(h+(vd^2/(2*g))-vd-(V1^2/(2*g)))+11.1 H= V1^2/(2*g) b= atand(2*vd/(2*vd/tand(A)))/4 //RESULTS printf ('velocity of the wheel at exit = %.2f ft/sec',v1-0.04) printf ('\n Pressure head at outlet = %.1f ft of water',H1) printf ('\n velocity head at exit from the vessel = %.1f ft of water',H-0.1) printf ('\n inclination of guide vanes = %.f degrees',b)
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Ex16_1.sce
//Electric Power Generation, Transmission and Distribution by S.N.Singh //Publisher:PHI Learning Private Limited //Year: 2012 ; Edition - 2 //Example 16.1 //Scilab Version : 6.0.0 ; OS : Windows clc; clear; V=238; //Transformer primary voltage in kV Em=110; //Transformer secondary voltage in kV f=50; //Supply frequency in Hz u=20; //Commutation angle in degree alpha1=30; //Delay angle 1 in degree alpha2=90; //Delay angle 2 in degree alpha3=150; //Delay angle 3 in degree Vdo=3*sqrt(3*2)*Em/(%pi*sqrt(3)); //Direct output voltage in kV Vd1=Vdo/2*(cosd(alpha1)+cosd(alpha1+u)); //Direct output voltage when commutation angle 20 and delay angle is 30 degree in kV Vd2=Vdo/2*(cosd(alpha2)+cosd(alpha2+u)); //Direct output voltage when commutation angle 20 and delay angle is 90 degree in kV Vd3=Vdo/2*(cosd(alpha3)+cosd(alpha3+u)); //Direct output voltage when commutation angle 20 and delay angle is 150 degree in kV printf("\nThe direct voltage output is %.2f kV",Vdo); printf("\nThe direct voltage output when commutation angle 20 and delay angle is 30 degree is %.2f kV",Vd1); printf("\nThe direct voltage output when commutation angle 20 and delay angle is 90 degree is %.2f kV",Vd2); printf("\nThe direct voltage output when commutation angle 20 and delay angle is 150 degree is %.2f kV",Vd3);
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ex_1_26.sce
//Example 1.26 // thickness of flim clc; clear; //given data : u=1.5;// refractive index of flim between lens and plate m=10;//no. of fringes shifted in experiment w=5890D-10;// wavelength of light used in m t=m*w/(2*(u-1));// thickness of plastic flim in m t=t*1D9;// to convert in nm disp(t,"thickness of flim in nm(nanometer)")
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exp2_14.sce
clc disp("example 2.14") disp("(a)") //given transformer1.motorload=300;transformer1.demandfactorm=0.6;tarnsformer1.commercialload=100;transformer1.demandfactorc=0.5;transformer1.diversityfactor=2.3;transformer2.residentalload=500;transformer2.demandfactor=0.4;transformer2.diversitryfactor=2.5;transformer3.residentalload=400;transformer3.demandfactor=0.5;transformer3.diversityfactor=2.0;diversitybtwxmer=1.4 peakloadoftransformer1=((transformer1.motorload*transformer1.demandfactorm)+(tarnsformer1.commercialload*transformer1.demandfactorc))/transformer1.diversityfactor peakloadonxmer=(transformer2.residentalload*transformer2.demandfactor)/transformer2.diversitryfactor peakloadonxmer3=(transformer3.residentalload*transformer3.demandfactor)/(transformer3.diversityfactor) printf("peak load on transformer 1 =(300x0.6+100x0.5)/2.3 =%dkW \npeak load on transformer 2 =%dkW \n peak load on transformer 3 =%dkW",peakloadoftransformer1,peakloadonxmer,peakloadonxmer3) disp("(b)") peakloadonfeeder=(peakloadoftransformer1+peakloadonxmer+peakloadonxmer3)/diversitybtwxmer printf("peak load on feeder =(100+80+100)/1.4 =%dkW",peakloadonfeeder)
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q5.sce
s=%s; // first create a variable Wn=%Wn; Wd=%Wd; num=1; den=10*s+s^2; TF=syslin('c',num,den) [wn,z] = damp(TF) zeta=z/(2*wn) ts=4/(zeta*wn) t=linspace(0,5,500); step_res=csim('step',t,TF); plot(t,step_res) xgrid() xtitle('Step response','time','response');
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Ex14_3.sce
//Chapter 14: Water Treatment //Problem: 3 clc; //Initialisation of Variables wt1 = 32.4 //in mg/L wt2 = 29.2 //in mg/L wt3 = 13.5 //in mg/L //Solution temp_h = wt1 * 100 / 162. + wt2 * 100 / 146. //where temp_h is temporary hardness perm_h = wt3 * 100 / 136. //where perm_h is permanent hardness mprintf("Temporary hardness: %.2f mg/L\n",temp_h) mprintf(" Total hardness: %.2f mg/L",perm_h)
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example_12.sce
clc clear printf("example 2.12 page number 74\n\n") //to find the vapor pressure of water w_water=540 //in gm w_glucose=36 //in gm m_water=18; //molar mass of water m_glucose=180; //molar mass of glucose x=(w_water/m_water)/(w_water/m_water+w_glucose/m_glucose); p=8.2*x; depression=8.2-p; printf("depression in vapor pressure = %f Pa",depression*1000)
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Ex18_7.sce
clear //Given uv=1.68 ur=1.56 A=18 //degree //Calculation A1=A*(uv-ur) //Result printf("\n Angular dispersion is %0.3f Degree", A1)
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9_3.sce
////Variable Declaration nb = 5.00 //Number of moles of Benzene, mol nt = 3.25 //Number of moles of Toluene, mol T = 298.15 //Temperature, K R = 8.314 //Ideal Gas Constant, J/(mol.K) P0b = 96.4 //Vapor pressure of Benzene, torr P0t = 28.9 //Vapor pressure of Toluene, torr //Calculations n = nb + nt xb = nb/n xt = 1. - xb P = xb*P0b + xt*P0t y = (P0b*P - P0t*P0b)/(P*(P0b-P0t)) yt = 1. -y //Results printf("\n Total pressure of the vapor is %4.1f torr",P) printf("\n Benzene fraction in vapor is %4.3f ",y) printf("\n Toulene fraction in vapor is %4.3f ",yt)
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commandeOptimale.sce
//script ‘commandeOptimale.sce’ // équations de Lunar Lander en temps continu Te=0.04 // (s) période d'échantillonnage mvide= 6839; // masse à vide (kg) mfuel=816.5 // masse de carburant (kg) m = mvide + mfuel // masse totale ve=4500; // vitesse d'éjection des gaz (en m/s), erg = ve/m; // coefficient de poussée maxThrust = 50; //débit de carburant maximum (en kg/s) g= 1.6; // attraction lunaire (en m/s^2) x0=[45, 1, 51, -1]'; // état initial de Lunar Lander A= [0, 1, 0, 0 0, 0, 0, 0 0, 0, 0, 1 0, 0, 0, 0]; // matrice d'état (4x4) B=[0, 0 erg, 0 0, 0 0, erg]; // matrice de commande, 2 commandes C=eye(4,4); // matrice d'observation, quatre sorties D=zeros(4,2); //matrice de couplage entrée sortie lem=syslin('c',A,B,C,D); // discretisation du processus d'alunissage lemd=dscr(lem,Te); ad=lemd('a'); bd=lemd('b'); // calcul de la loi de commande funcprot(0) //pour redéfinir ‘riccati’ sans warning //exec('riccati.sci'); H=100; //horizon Q=0*eye(4,4); // poids de l'écart quadratique R=eye(2,2) // poids de l'énergie de commande [K,P0]=riccati(H,ad,bd,R,Q); // //écrire K dans le fichier 'K.txt' fileid='K.txt' fp=mopen(fileid,'w'); Kt=K'; Ks=string(K(1)); for k=2:length(K), Ks=Ks+','+string(Kt(k)); end mputstr(Ks,fp); mclose(fp);
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clear// //Variables RH = 160 //Hall coeffficient (in cubic-centimeter per Coulomb) p = 0.16 //Resistivity (in ohm-centimeter) //Calculation sig = 1/p //Conductivity (in per ohm-centimeter) un = sig * RH //Electron mobility (in cmentimeter-square per volt-second) //Result printf("\n Electron mobility is %0.3f cm**2/V-s.",un)
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clc //initialisation of variables E= -0.126 //volt E1= -0.140 //volt n=2 R= 0.0591 //volt //CALCULATIONS E0= E-E1 K= 10^((E-E1)*n/R) //RESULTS printf ('equilibrium constant = %.2f ',K)
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//Example 17.1. clc format(5) disp("We know that") disp(" fo = 1 / (2.303*RE*CE*log10(1/1-eta))") disp("We know that etamin = 0.56") disp("For determining RE, we have") RE=(20-2.9)/(1.6) // in k-ohm disp(RE,"RE < VBB-VP/IP, i.e. RE(k-ohm) < 20-2.9/1.6*10^-3 =") RE=(20-1.118)/(3.5) // in k-ohm disp(RE,"RE > VBB-VV/IV, i.e. RE(k-ohm) < 20-1.118/3.5*10^-3 =") // answer in textbook is wrong disp("Therefore, RE is selected as 10 k-ohm") disp(" 1/500 = 2.303*10*10^3*CE*log10(1/1-0.56)") CE=1/(500*(2.303*10^4)*0.36) // in farady x1=CE*10^6 // in uF disp(x1,"Therefore, CE(uF) =") disp("So, CE is selected as 0.22 uF") disp("Let the required pluse voltage at B1 = 5V") disp("Let the peak pulse current, IE = 250 mA") R1=5/(250*10^-3) //in ohm disp(R1,"Therefore, R1(ohm) = VR1/IE =") disp("So, R1 is selected to be 22 ohm") disp("We select the voltage characteristics for VB1B2 = 4 V") disp("Therefore, VR2 = 20-(4+5) = 11 V") R2=11000/250 disp(R2," R2(ohm) = 11*10^3/250 =") disp("So, R2 is selected as 100 ohm")
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// Example 2.37.b:baising component clc; clear; close; Vb=1.6;// Ve=1;// Vcc=12;// Colector voltage in volts Beta=180; Ieq=2;// Emiier current in mA Rc=1;// Collector resistance in killo ohms Vbe=0.6;// Base to emitter voltage in volts Vceq=6;// Collector to emitter voltage in volts Ic= (Vcc-Vceq-Ve)/Rc; Ib=Ic/Beta; Ie=Ic+Ib*10^-3;//emitter current in milli ampere Re= (Ve/Ie);//emitter resistance in killo ohms Ir2= 10*Ib; R2= (Ve+Vbe)/Ir2;// Ir1=Ir2+Ib;// R1=((Vcc-Vb)/Ir1);// disp (R2," RESISTANCE IN KILLO OHMS")
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Startup execution: loading initial environment Start quapro toolbox Load macros Load gateways Load help Execution done.
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f = [0.0000 -0.0004; 0.0004 0.0000 ; -0.0425 0.0993 ]; imageSize = [200, 300]; [isIn,epipole] = isEpipoleInImage(f,imageSize) /// output /// Invalid size of fundamental matrix
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clear; clc; printf("\t\t\tProblem Number 6.17\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.17 (page no. 261) // Solution //data of problem6.16 cp=0.24; //Specific heat at constant pressure //Btu/lbm*R p2=15; //psia //final pressure p1=100; //psia //initial pressure T2=460+0; //absolute final temperature //unit:R T1=460+100; //absolute initial temperature //unit:R J=778; //conversion factor R=1545/29; //moleculer weight=29 //Unit:ft*lbf/lbm*R //constant of proportionality //Because cp and R are given,let us first solve for cv, //cp=(R*k)/(J*(k-1)) k=(cp*J)/((cp*J)-R); //k=cp/cv //ratio of specific heats printf("Ratio of specific heats k is %f\n",k); //k=cp/cv cv=cp/k; //Specific heat at constant volume //Btu/lbm*R printf("Specific heat at constant volume is %f Btu/lbm*R\n",cv); //Now, deltas=(cv*log(p2/p1))+(cp*log(v2/v1)); //But, v2/v1=(T2*p1)/(T1*p2) v2byv1=(T2*p1)/(T1*p2); // v2/v1 //unitless deltas=(cv*log(p2/p1))+(cp*log(v2byv1)); //The change in enthalpy //unit:Btu/lbm*R printf("The change in enthalpy is %f Btu/lbm*R\n",deltas); //The agreement is very good.
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clc; n=0:1:100; fs=50; T=1/fs; t=n*T; figure; x1=cos(2*%pi*5*t); plot2d3(n,x1); figure; x2=cos(2*%pi*45*t); plot2d3(n,x2); figure; x3=cos(2*%pi*55*t); plot2d3(n,x3); x = input ( ' Enter the input sequence e := ' ); m = length (x); n = 0 :1: m; c1=mtlb_fliplr(x); c=mtlb_fliplr(x(2:m)); x1=[c x(1)]; disp("Folded sequence is:",x1); y=mtlb_fliplr(-n);
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// Exa 7.15 clc; clear; close; format('v',5) // Given data R1 = 20;// in k ohm R1 = R1 * 10^3;// in ohm R2 = R1;// in ohm R = R1;// in ohm C1 = 1000;// in pF C1 = C1 * 10^-12;// in F C2 = C1;// in F C = C1;// in F f = 1/(2*%pi*R*C);// in Hz f= f*10^-3;// in kHz disp(f,"The frequency of oscillations in kHz is");
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delete(gcf()) clear m = 50; xA = 0.2; D = 0.025; d = 0.0; az = 1.3; Wax = %pi/32*(D^4 - d^4)/D; My = m*az*9.81*xA; sigma = My/Wax; disp('Wax = ' + msprintf('%5.3f', 1e9*Wax) + "mm^3"); disp('My = ' + msprintf('%3.5f', My) + "Nm"); disp('Sigma = ' + msprintf('%3.5f', 1e-6*sigma) + "N/mm^2");
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//Newton Cotes formula clc; clear; close(); format('v',9); funcprot(0); disp('Integral 0 to PI/4 x*cos dx'); disp('based on open Newton-Cotes formulas '); deff('[y]=f(x)','y=x*cos(x)'); k = [0 1 2 3] a = 0; b = %pi/4; h = (ones(:,4)*(b-a))./(k+2); x0 = a+h; xk = b-h; k(1) = 2*h(1)*f(h(1)); disp(k(1),'k=0'); k(2) = 3*h(2)*(f(h(2))+f(2*h(2)))/2; disp(k(2),'k=1'); k(3) = 4*h(3)*(2*f(h(3))-f(2*h(3))+2*f(3*h(3)))/3; disp(k(3),'k=2'); k(4) = 5*h(4)*(11*f(h(4))+f(2*h(4))+f(3*h(4))+11*f(4*h(4)))/24; disp(k(4),'k=3'); exact = integrate('x*cos(x)','x',0,%pi/4); disp(exact,'The exact value of intergation is :'); exact = ones(:,4)*exact; err = exact-k; disp(err','thus corresponding errors are : ');
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Eps=100*%eps; rand('normal') x=rand(1,256); y=-x; deff('[z]=xx(inc,is)',... 'z=x(is:is+inc-1)') deff('[z]=yy(inc,is)',... 'z=y(is:is+inc-1)') comp(xx),comp(yy) [c,mxy]=corr(x,y,32); x=x-mxy(1)*ones(x); y=y-mxy(2)*ones(y); if abs(sum(x))> Eps then pause,end if abs(sum(y))> Eps then pause,end c1=corr(x,y,32); c2=corr(x,32); if norm(c1+c2,1)> Eps then pause,end [c3,m3]=corr('fft',xx,yy,256,32); if norm(c1-c3,1)> Eps then pause,end [c4,m4]=corr('fft',xx,256,32); if norm(m3,1) > Eps then pause,end; if norm(m4,1) > Eps then pause,end; if norm(c3-c1,1) > Eps then pause,end; if norm(c4-c2,1) > Eps then pause,end; x1=x(1:128);x2=x(129:256); y1=y(1:128);y2=y(129:256); w0=0*ones(1:64); //on veut 32 coeffs [w1,xu]=corr('u',x1,y1,w0); w2=corr('u',x2,y2,w1,xu); zz=real(fft(w2,1))/256;c5=zz(1:32); if norm(c5-c1,1) > Eps then pause,end; [w1,xu]=corr('u',x1,w0); w2=corr('u',x2,w1,xu); zz=real(fft(w2,1))/256;c6=zz(1:32); if norm(c6-c2,1) > Eps then pause,end;
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//Finding the Voltage sharing of Series Connected Thyristors //Example 7.3(Page No- 337) clc clear //given data n_s = 10; Vs = 15*10^3;//V del_Id = 10*10^-3;//A Id2 = 10*10^-3;//A del_Q = 150*10^-6;//C Q2 = del_Q; R = 56*10^3;//Ohm C1 = 0.5*10^-6;//C //part(a) //the maximum steady state voltage sharing V_DSmax = ((Vs+(n_s-1)*R*Id2)/n_s); printf('(a) Maximum seady-state voltage sharing is %d V',V_DSmax); //part(b) //steady state drafting factor DRF = 1-(Vs/(n_s*V_DSmax)); printf('\n (b) The steady state derating factor is %.2f%%',DRF*100); //part(c) //maximium transient voltage sharing V_DTmax = (1/n_s)*(Vs + ((n_s-1)*Q2/C1)); printf('\n (c) The maximum transient voltage sharing is %d V',V_DTmax); //part(d) //transient derating factor is DRF = 1-(Vs/(n_s*V_DTmax)); printf('\n (d) The maximum transient derating factor is %.2f %%',DRF*100);
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//===================================================================================== //Chapter 16 example 12 clc;clear all; //variable declaration fx = 1000; //frequency of horizontal input in Hz Pv = 2; //pointsof tangency to vertical line Ph = 5; //pointsof tangency to horizontal line //calculations fy = fx*(Ph/(Pv)); //frequency ofvertical input in Hz //result mprintf("frequency ofvertical input = %3.2f Hz",fy);
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// Scilab Code Ex2.8 : Page-57 (2013) clc; clear; f0 = 1; // For simplicity assume frequency of the signals sent by Frank, Hz // Outbound trip bita = -0.8; // Boost parameter for receding frames f = sqrt(1+bita)/sqrt(1-bita)*f0; // The frequency of the signals received by Mary in outbound trip, Hz printf("\nThe frequency of the signals received by Mary in outbound trip = f0/%d", ceil(f*9)); // Return trip bita = +0.8; // Boost parameter for approaching frames f = sqrt(1+bita)/sqrt(1-bita)*f0; // The frequency of the signals received by Mary in return trip, Hz printf("\nThe frequency of the signals received by Mary in return trip = %df0", f); // Result // The frequency of the signals received by Mary in outbound trip = f0/3 // The frequency of the signals received by Mary in return trip = 3f0
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f=10^6:10^7:10^10; mu0=4*%pi*10^-7; rs=(4.8*10^-6).*sqrt(f); re=(33.9*10^12) ./f; c=47*10^-12; w=2*%pi.*f; l=2*1.25*10^-2; a=2.032*10^-4; temp=log(2*l/a)/log(%e); lex=mu0*l*(temp-1)/(2*%pi); //external inductance z=1 ./(1 ./re +w*c*%i)+rs+w.*lex*%i; // impedance of frequency dependent capacitor zideal=1 ./(w*c*%i); //impedance of an ideal capacitor plot2d("gll",f,abs(z)); plot2d(f,abs(zideal)); title("Frequency responce of a high frequency capacitor"); xlabel('Frequency (f) in Hz'); ylabel('Absolute impedance (|Z|) in ohms');
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MoyenneGlissante.sci
function [Y,offset] = MoyenneGlissante(N, speed) //N = nombre de point défini de la moyenne glissante et Speed vitesse a moyennée sur intervalle ..) h = ones (N,1); Y = conv(speed,h)./N; offset = N/2+1 //Y = x(offset+2:length(Y),1) endfunction
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clc; clear all; disp("heat transfer rate") ta=30;//degree C U=2.2;//m/s v=18.97*10^(-6);// m^2/s ts=90;// degree C L=900/1000;//m B=0.45;//m Pr=0.696; k=0.02894;//W/m.C rho=1.06;//kg/m^3 mu=7.211;//kg/hm disp("i) Heat transfer rate from first half of the plate") // for first half of the plate, x=L/2; Rex=U*x/v; if(Rex<5*10^5) disp("Flow is laminar") end Nux=0.332*(Rex^0.5)*Pr^(1/3); hx=Nux*k/x; ha=2*hx;// average heat transfer rate Qx=ha*x*B*(ts-ta);//W disp("W",Qx,"Heat transfer rate from first half of the plate, Qx =") disp("ii) heat transfer from full plate") // for full plate x=L; ReL=U*x/v; NuL=0.664*ReL^0.5*Pr^(1/3); h=NuL*k/x; QL=h*L*B*(ts-ta);//W disp("W",QL,"Heat transfer rate from entire plate QL =") disp("iii) heat transfer rate from next half of the plate") Q=QL-Qx; disp("W",Q,"heat transfer rate from next half of the plate Q =")
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207ex.sce
clc; clear; close; //ex(1) in the series 7,10,13,.... the common difference is 3. 10th trerm is ? nth_term=string('7+(n-1)*3') term10=7+(10-1)*3 //ex(2) i the series 6,2,-2,-6,....and d=-4 nth_term=string('6-(n-1)*4') term8=6+(8-1)*-4