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function [Q]=bstap(sl) // Best approximant Q of Sl // ||Sl-Q|| = ||Tsl|| // inf // ||Tsl|| norm of hankel operator //-- sl is assumed antistable //-- Q : best stable approximation of Sl //! //balancing //----------------------------------- // Copyright INRIA slt=gtild(sl);slt=balreal(slt);sl=gtild(slt), // D such that DB1'+sC1 = 0 , DD' = s**2I //------------------------------------------------- [a,b,c]=sl(2:4),[n,n]=size(a),[m,n]=size(c), x=-obs_gram(sl),s=x(1,1), [w,r]=rowcomp(x-s*eye),r=n-r, b1=b(1:r,:),c1=c(:,1:r), [u1,s1,v1]=svd(-c1'),[u2,s2,v2]=svd(b1), v2=v2(:,1:m),dd=s*v1*v2', // //-------------------------------- a22=a(r+1:n,r+1:n), b2=b(r+1:n,:),c2=c(:,r+1:n), sig=x(r+1:n,r+1:n), bb=-inv(s**2*eye-sig*sig)*(sig*b2+s*c2'*dd), aa=-(a22+b2*bb')',cc=c2*sig+dd*b2', Q=syslin('c',aa,bb,cc,dd),
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function y = first_order(u, params) // Do not change anything here a1 = params(1); b1 = params(2); global delay; // End /// You should write your code below this line N=length(u); //Defining y vector //from t=0 up to t=delay-1, y=0, so in scilab y at indices i=1 up to i=delay is 0 y(1:1:delay) = 0; //First nonzero output is only due to input u at t=0, i.e. in scilab input u at i=1 y(delay+1) = b1*u(1); //After that y(i) can be defined as follows for i=delay+2:1:N y(i)=-a1*y(i-1)+b1*u(i-delay); end // y = ? endfunction
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// Finding root of equation f(x)=x^3-5x+1 function [r]=root(xl,xu,et) // xl = Lower limit guess // xu = Upper limit guess // et = Error tolerance xm = (xl+xu)/2 p = poly([1,-5,0,1],'x','c') while %t y1 = horner(p,xl) y2 = horner(p,xm) if y1*y2 < 0 then xu = xm elseif y1*y2 > 0 then xl = xm else break end xmo = xm xm = (xl + xu)/2 e = abs(xm - xmo)/xm * 100 if(e<et) then break end end r = xm endfunction
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clear // //variable declaration PA=15.0 //vertical loading at point A,KN PB=30.0 //vertical loading at point B,KN PC=30.0 //vertical loading at point C,KN PD=30.0 //vertical loading at point D,KN PE=15.0 //vertical loading at point E,KN //Due to symmetry, the reactions are equal RA=(PA+PB+PC+PD+PE)/2 RB=RA //Drop perpendicular CH on AF. //in traingle ACH angleACH=45.0*%pi/180 //angleACH,° angleFCV=30.0*%pi/180 // FC is inclined at 30° to vertical i.e., 60° to horizontal and CH = 5 m CH=5.0 angleFCH=60.0*%pi/180 //It is not possible to find a joint where there are only two unknowns. Hence, consider section (1)–(1). //For left hand side part of the frame //moment at C FAE=(RA*CH-PA*CH-PB*CH/2)/(CH) printf("\n FAE= %0.0f KN (Tension)",FAE) //Assuming the directions for FFC and FBC //sum of vertical & sum of horizontal forces is zero //FFC=FBC*sqrt(2)-RA FBC=(RA*sin(angleFCH)-PA)/(sqrt(2)*sin(angleFCH)-(1/sqrt(2))) printf("\n FBC= %0.2f KN (Comp.)",FBC) FFC=FBC*sqrt(2)-RA printf("\n FFC= %0.2f KN (Tension)",FFC) //Assumed directions of FBC and FFC are correct. Therefore, FBC is in compression and FFC is in tension. Now we can proceed with method of joints to find the forces in other members. Since it is a symmetric truss, analysis of half the truss is sufficient. Other values may be written down by making use of symmetrry. //Joint B: sum of forces normal to AC = 0, gives FBF=PC*cos(angleACH) //sum of forces parallel to AC = 0, gives FAB=FBC+PC*sin(angleACH) printf("\n FAB= %0.2f KN (Comp.)",FAB) //JOINT A //sum of vertical & sum of horizontal forces is zero FAF=(FAB*sin(angleACH)+PA-RA)/sin(angleFCV) printf("\n FAF= %0.2f KN (Tension)",FAF)
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//example 6.3 //calculate storage capacity of reservior clc;funcprot(0); //given V=475; //flow required to be maintained throughout the year Y=V*365*8.64; //yearly demand //yearly demand gives the slope of demand curve t=[0:1:36]; //number of season startin from 1960;each year is diveded into 3 seasons. q=[0 1050 300 50 3000 250 40 3500 370 90 2000 150 120 1200 350 65 1400 400 100 3600 200 80 3000 200 80 3000 150 120 700 210 50 800 120 80 2400 320 120 3200 280 80]; //average discharge v=[0 0.9707 0.4717 0.0328 2.7734 0.3981 0.0263 3.2357 0.5818 0.0591 1.8490 0.2356 0.0788 1.1094 0.5504 0.0427 1.2943 0.6290 0.0657 3.3281 0.3145 0.0525 2.7734 0.2359 0.0788 0.6441 0.3302 0.028 0.7396 0.1887 0.0525 2.2188 0.5032 0.0788 2.9583 0.4403 0.0525]; //voloume cv(1)=v(1); for i=2:37 cv(i)=cv(i-1)+v(i); end //each year is divided into three seasons(monsoon,winter and summer).and readings are taken for 12 years //mass inflow curve is plotted and tangent are drawn at the apexes and parellel to demand curve slope; //the respectiv ordinates represent the deficiency during dry period //maximum of these ordinates gives the desired reservior capacity mprintf("storage capacity of reservior=1.6 million ha-m.");
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clc //initialisation of variables h=200//r p m h1=50//i h p P4=33.4//lb/in^2 W=9000//ft lb x=33000//ft.lb p=1728//ft/lb //CALCULATIONS w=h1*x/100//ft lb T=w/W//ft^3 V =13/14*T//ft^3 D=((V*p*8)/(3*%pi))^(1/3)//in //RESULTS printf('The diameter of the cylinder of a single acting and swept volume=% f in',D)
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clear; close; clc; s = poly(0,'s'); G = (s^6 + 2*s^5 + s^4 + 2*s^2 + 4*s+ 1); disp(G); disp(routh_t(G))
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function [cA,cD]=dwt(x,wname,['mode',extMethod]) // Discrete Fast Wavelet Transform // Calling Sequence // [cA,cD]=dwt(x,wname,['mode',extMethod]) // [cA,cD]=dwt(x,Lo_D,Hi_D,['mode',extMethod]) // Parameters // wname : wavelet name, haar( "haar"), daubechies ("db1" to "db20"), coiflets ("coif1" to "coif5"), symlets ("sym2" to "sym20"), legendre ("leg1" to "leg9"), bathlets("bath4.0" to "bath4.15" and "bath6.0" to "bath6.15"), dmey ("dmey"), beyklin ("beylkin"), vaidyanathan ("vaidyanathan"), biorthogonal B-spline wavelets ("bior1.1" to "bior6.8"), "rbior1.1" to "rbior6.8" // x : double vector // Lo_D : lowpass analysis filter // Hi_D : highpass analysis filter // extMethod : extension mode, 'zpd' for example // cA : approximation coefficent // cD : detail coefficent // Description // dwt is for discrete fast wavelet transform with the signal extension method optional argument. Available wavelets include haar, daubechies (db1 to db20), coiflets (coif1 to coif5), symlets (sym2 to sym20), legendre (leg1 to leg9), bathlets, dmey, beyklin, vaidyanathan, biorthogonal B-spline wavelets (bior1.1 to bior6.8). // Examples // x=rand(1,100); // [cA,cD]=dwt(x,'db2','mode','asymh'); // // // // Authors // Roger Liu and Isaac Zhi // See Also // idwt // dwt2 // idwt2
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// Scilab code Ex17.10 : Pg:894 (2011) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV E = 3.2e+07; // Energy released per second by the reactor, J E_f = 200*1e+06*e; // Energy released per fission, J N = E/E_f; // Number of fissions per second of U235, per second printf("\nThe number of U235 atoms undergoing fissions per second = %1.0e", N); // Result // The number of U235 atoms undergoing fissions per second = 1e+018
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//Example 7.2// a=8.8*10^-6;//mm/(mm degree C) //linear coefficient of thermal expansion L0=0.1;//mm //Given direction T=1000;//degree Celsius // Temperature T1=25;//degree Celsius //Temperature dL=a*L0*(T-T1) mprintf("dL = %e m ",dL) b=10^3;// (As 1 milli = 10^-3 milli) dL1= dL*b mprintf("\ndL1 = %f mm (As 1 milli = 10^-3 milli)",dL1)
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errcatch(-1,"stop");mode(2);//To determine the voltage for which corona will commence on the line ; r=.5; V=21*r*log(100/.5); mprintf("critical disruptive voltage=%.1f kV",V); exit();
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clc //initialisation of variables k=1.4 g=32.17 //lbm-ft/sec^2 R=53.34 //ft-lbf/lbm-R T=540 //R t=1460 //f //CALCULATIONS c=sqrt(k*g*R*T)//ft/sec C=sqrt(k*g*R*t)//ft/sec //RESULTS printf('The velocity of sound in air =% f ft/sec',C)
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function dy=f(x,y) S=y(1);X=y(2);P=y(3); M=MI*S/(S+Ks) dy(1)=D*S0-D*S-M*X/Yxs; dy(2)=D*X0-D*X+M*X; dy(3)=D*P0-D*P+M*X*Ypx; endfunction S0=100;X0=0;P0=0;// g/l g/l g/l Ks=2;MI=0.4;Vol=300;F0=60;Yxs=0.5;Ypx=0.6;// g/l g/h h^-1 m3 m3/h D=F0/Vol; Xr=10;Sr=50;Pr=10; y0=[Sr;Xr;Pr];x0=0; t=1:100; sol=ode(y0,x0,t,f); disp(sol,"solucao") plot(t,sol)
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function [h,t] = stepz(b,varargin) if(argn(2)<1 | argn(2)>4) then error("Input arguments should lie between 1 and 4"); end if(argn(1) ~=2) then error("Outpu argument should be 2"); end flag= true; if(size(b)> [1 1]) then if(size(b,2) ~= 6) then error(" SOS must be k by 6 matrix"); end flag = false; if argn(2)>1 then n= varargin(1); else n=[]; end if argn(2)>2 then fs = varargin(2); else fs=1; end if( type(n) ~=8) then error("n must be of type double"); end if(type(fs) ~= 8) then error("fs must be of type double"); end if (type(b) ~=8) then error(" "); end end if flag then if(argn(2)>1) a= varargin(1); if (size(a)> [1 1]) then error(" a has wrong input size"); end else a=1; end if(argn(2)>2) then n= varargin(2); else n=[]; end if(argn(2)>3) then fs= varargin(3); else fs=1; end if(type(n) ~=8) then error(" n must be of type double"); end if(type(fs) ~=8) then error(" fs must be of type double"); end if( type(b) ~=8 & type(a)~= 8) then error("b and a should be of type double"); end end t=0; N=[]; if (argn(2)<2) then if flag n =impzlength(b,a); else n= impzlength(b); end elseif(length(n)>1) N= round(n); n =max(N)+1; M= min(min(N),0); end t1 = (t:(n-1))'/fs; x = ones(size(t1)); if flag s= filter(b,a,x); else s= sfilter(b,x); end if ~isempty(N) then s= s(N-m+1); t1= t1(N-m+1); end endfunction
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//example 2.1 clc; funcprot(0); Distance=[2.5,5,7.5,10,15,20,25,30,35,40,50]; Time=10^-3*[11.2,23.3,33.5,42.4,50.9,57.2,64.4,68.6,71.1,72.1,75.5] //part1 distance=5.25; time=23e-3; v1=distance/time; disp(v1,"speed in m/s"); //part2 distance=11; time=13.5e-3; v2=distance/time; disp(v2,"speed in m/s"); //part3 distance=14.75; time=3.5e-3; v3=distance/time; disp(v3,"speed in m/s"); plot(Distance,Time); xtitle("distance vs time","Distance in m","time in s"); //part4 xc=10.4; Ta=65e-3; Z1=1/2*sqrt((v2-v1)/(v2+v1))*xc; disp(Z1,"thickness of layer 1 in m"); Z2=1/2*(Ta-2*Z1*sqrt(v3^2-v1^2)/v3/v1)*v3*v2/sqrt(v3^2-v2^2); disp(Z2,"thickness of layer 2 in m");
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ex1_16_2.sce
//Chapter-1,Example1_16_2,pg 1-75 Ev=1.95 //average energy required to creaet a vacancy k=1.38*10^-23 //boltzman constant in J/K e=1.6*10^-19 //charge on 1 electron K=k/e //boltzman constant in eV/K T=500 //temperature //for a low concentration of vacancies a relation is //n=Nexp(-Ev/KT) m=exp(-Ev/(K*T)) //ratio of no of vacancies to no of atoms n/N printf("ratio of no of vacancies to no of atoms=") disp(m)
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//i/p vector contains elements of type char x=['a' 'b' 'c' 'd']; y=vco(x,150,500); disp(y); //output // !--error 246 //Function not defined for given argument type(s), // check arguments or define function %c_abs for overloading. //at line 48 of function vco called by : //y=vco(x,150,500);
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Example39_4.sce
// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS // EXAMPLE : 1.4 : // Page number 681-682 clear ; clc ; close ; // Clear the work space and console // Given data hp = 30.0 // Power of cage IM(hp) V = 500.0 // Cage IM voltage(V) P = 4.0 // Number of poles f = 50.0 // Frequency(Hz) I_fl = 33.0 // Full load current(A) s = 4.0/100 // Slip Z = 3.5 // Impedance per phase(ohm) tap = 60.0 // Auto-transformer tap setting(%) // Calculations // Case(1) I_s_1 = 3**0.5*(V/Z) // Starting current taken from line(A) N_s = 120*f/P // Speed(rpm) N_fl = N_s-N_s*s // Full load speed of motor(rpm) T_fl = hp*746*60/(2*%pi*N_fl) // Full load torque(N-m) T_s_1 = (I_s_1/I_fl)**2*s*T_fl // Starting torque(N-m) // Case(2) V_ph = V/3**0.5 // Phase voltage in star(V) I_s_2 = V_ph/Z // Starting current(A/phase) T_s_2 = (I_s_2/(I_fl/3**0.5))**2*s*T_fl // Starting torque(N-m) // Case(3) V_ph_at = V*tap/(3**0.5*100) // Phase voltage of auto-transformer secondary(V) V_impressed = V_ph_at*3**0.5 // Volatage impressed on delta-connected stator(V) I_s_3 = V_impressed/Z // Starting current(A/phase) I_s_line = 3**0.5*I_s_3 // Motor starting line current from auto-transformer secondary(A) I_s_line_3 = tap/100*I_s_line // Starting current taken from supply(A) T_s_3 = (I_s_3/(I_fl/3**0.5))**2*s*T_fl // Starting torque(N-m) // Case(4) I_s_4 = 3**0.5*V/Z // Starting current from line(A) T_s_4 = T_fl*s*(I_s_4/I_fl)**2 // Starting torque(N-m) // Results disp("PART IV - EXAMPLE : 1.4 : SOLUTION :-") printf("\nCase(1): Starting torque for direct switching, T_s = %.f N-m", T_s_1) printf("\n Starting current taken from supply line for direct switching, I_s = %.f A", I_s_1) printf("\nCase(2): Starting torque for star-delta starting, T_s = %.f N-m", T_s_2) printf("\n Starting current taken from supply line for star-delta starting, I_s = %.1f A per phase", I_s_2) printf("\nCase(3): Starting torque for auto-transformer starting, T_s = %.f N-m", T_s_3) printf("\n Starting current taken from supply line for auto-transformer starting, I_s = %.f A", I_s_line_3) printf("\nCase(4): Starting torque for series-parallel switch, T_s = %.f N-m", T_s_4) printf("\n Starting current taken from supply line for series-parallel switch, I_s = %.f A\n", I_s_4) printf("\nNOTE: ERROR: Calculation mistakes and more approximation in textbook solution")
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //EX3_8.sce clc; clear; R=2; //Resistance in ohm L=2; //Inductor value in henry C=1/12; //capacitor value in farad omega=3; //Taken from v(t) value //given v(t)=12 sin(3t+30); Vm=12; Vrms=Vm/sqrt(2); theta=30; Z=complex(R,(omega*L)-(1/(omega*C))); V=complex(Vrms*cosd(theta),Vrms*sind(theta)); I=V/Z; I_mag=sqrt(real(I)^2+imag(I)^2); I_ang=atand(imag(I)/real(I)); printf("\n Circuit current=%1.0f angle:%d degree \n",I_mag,I_ang) Vr=I*R; Vr_mag=sqrt(real(Vr)^2+imag(Vr)^2); Vr_ang=atand(imag(Vr)/real(Vr)); printf("\n Voltage across the resistance=%1.0f angle:%d degree \n",Vr_mag,Vr_ang) theta1=90; Xl=complex(omega*L*cosd(theta1),omega*L*sind(theta1)); Vl=I*Xl; Vl_mag=sqrt(real(Vl)^2+imag(Vl)^2); Vl_ang=atand(imag(Vl)/real(Vl)); printf("\n Voltage across the inductance=%1.0f angle:%1.0f degree \n",Vl_mag,Vl_ang) theta2=-90; Xc=complex(cosd(theta2)/(omega*C),sind(theta2)/(omega*C)); Vc=I*Xc; Vc_mag=sqrt(real(Vc)^2+imag(Vc)^2); Vc_ang=atand(imag(Vc)/real(Vc))-180; printf("\n Voltage across the capacitance=%1.0f angle:%d degree \n",Vc_mag,Vc_ang)
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window.sci
function [win_l,cwp]=window(wtype,n,par) //[win_l,cwp]=window(wtype,n,par) //macro which calculates symmetric window // wtype :window type (re,tr,hn,hm,kr,ch) // n :window length // par :parameter 2-vector (kaiser window: par(1)=beta>0) // : (chebyshev window:par=<dp,df>) // : dp=main lobe width (0<dp<.5) // : df=side lobe height (df>0) // win :window // cwp :unspecified Chebyshev window parameter //! //author: C. Bunks date: 8 Sept 1988 [lhs,rhs]=argn(0); cwp=-1; //Pre-calculations no2=(n-1)/2; xt=(-no2:no2); un=ones(1:n); //Select the window type select wtype case 're' then //Rectangular window. win_l=un case 'tr' then //Triangular window. win_l=un-2*abs(xt)/(n+1); case 'hm' then //Hamming window. win_l=.54*un+.46*cos(2*%pi*xt/(n-1)); case 'hn' then //Hanning window. win_l=.5*un+.5*cos(2*%pi*xt/(n-1)); case 'kr' then //Kaiser window with parameter beta (n,beta) beta=par(1); if beta>0 then xt=2*xt/(n-1); xt=beta*sqrt(un-xt.*xt); y=xt/2; yb=beta/2; e=un; eb=1.; de=un; deb=1.; for i=1:25, de=de.*y/i; deb=deb*yb/i; sde=de.*de; sdeb=deb*deb; e=e+sde; eb=eb+sdeb; end win_l=e/eb; else error('Parameter beta out of bounds (beta]0) --- program termination'); end case 'ch' then //Chebyshev window // calculting element of par which is negative if par(1)<0 then, unknown='dp'; df=par(2); else if par(2)<0 then, unknown='df'; dp=par(1); else, error('Parameter par out of bounds prod(par)[0 --- program termination'); end, end, select unknown case 'dp' then, arg2=1/cos(%pi*df); coshin2=log(arg2+sqrt(arg2*arg2-1)); dp=2/(exp((n-1)*coshin2)+exp(-(n-1)*coshin2)); cwp=dp; case 'df' then arg1=(1+dp)/dp; coshin1=log(arg1+sqrt(arg1*arg1-1)); df=.5*(exp(coshin1/(n-1))+exp(-coshin1/(n-1))); df=1/df; df=imag(log(df+%i*sqrt(1-df*df)))/%pi; cwp=df; end, //Pre-calculation np1=int((n+1)/2); ieo=2*np1-n; xn=n-1; fnf=n; x0=(3-cos(2*%pi*df))/(1+cos(2*%pi*df)); alpha=(x0+1)/2; beta=(x0-1)/2; c2=xn/2; //Obtain the frequency values of the Chebyshev window f=(0:n-1)/fnf; xarg=alpha*cos(2*%pi*f)+beta*un; pm1=dp*cos(c2*imag(log(xarg+%i*sqrt(un-xarg.*xarg)))); arg=c2*log(xarg+sqrt(xarg.*xarg-un)); pp1=dp*.5*(exp(arg)+exp(-arg)); dx=0*un; for i=1:n, if abs(xarg(i))<=1 then dx(i)=1; end, end, pr=dx.*pm1+(un-dx).*pp1; pi=0*un; if ieo<>1 then pr=pr.*cos(%pi*f); pi=-pr.*sin(%pi*f); antisym=[1*ones(1:int(n/2)+1),-1*ones(int(n/2)+2:n)]; pr=pr.*antisym; pi=pi.*antisym; end, //Calculate the window coefficients using the inverse DFT twn=2*%pi/fnf; xj=(0:n-1); for i=1:np1; w(i)=sum(pr.*cos(twn*(i-1)*xj)+pi.*sin(twn*(i-1)*xj)); end, c1=w(1); w=w/c1; if ieo=1 then win_l(np1:n)=w(1:np1); win_l(1:np1-1)=w(np1-1:-1:1); else, win_l(np1+1:n)=w(1:np1); win_l(1:np1)=w(np1:-1:1); end win_l=real(win_l'); //Error in window type else error('Unknown window type --- program termination'), end
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mu_not=4D-7*%pi Ns=400//no. of turns on search coil N=1000//no. of turns of wire on solenoid M=mu_not*Ns*N*25D-4/80D-2 mprintf("Mutual inductance of arrangement=%f mH\n",M*1000) //di/dt=200 e=-M*200 mprintf("emf induced in search coil=%f V",e)
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Ex8_18.sce
clear; clc; disp('Example 8.18'); // aim : To determine // the actual mass of air supplied/kg coal // the velocity of flue gas // given values mc = 635;// mass of coal burn/h, [kg] ea = .25;// excess air required C = .84;// mass composition of carbon H2 = .04;// mass composition of hydrogen O2 = .05;// mass composition of oxygen ash = 1-(C+H2+O2);// mass composition of ash P1 = 101.3;// pressure, [kJn/m^2] T1 = 273;// temperature, [K] V1 = 22.4;// volume, [m^3] T2 = 273+344;// gas temperature, [K] P2 = 100;// gas pressure, [kN/m^2] A = 1.1;// cross section area, [m^2] aO2 = .23;// composition of O2 in air mCO2 = 44;// moleculer mass of carbon mH2O = 18;// molecular mass of hydrogen mO2 = 32;// moleculer mas of oxygen mN2 = 28;// moleculer mass of nitrogen // solution mtO2 = 8/3*C+8*H2-O2;// theoretical O2 required/kg coal, [kg] msa= mtO2/aO2;// stoichiometric mass of air supplied/kg coal, [kg] mas = msa*(1+ea);// actual mass of air supplied/kg coal, [kg] m1 = 11/3*C;// mass of CO2/kg coal produced, [kg] m2 = 9*H2;// mass of H2/kg coal produced, [kg] m3 = mtO2*ea;// mass of O2/kg coal produced, [kg] m4 = mas*(1-aO2);// mass of N2/kg coal produced, [kg] mt = m1+m2+m3+m4;// total mass, [kg] x1 = m1/mt*100;// %age mass composition of CO2 produced x2 = m2/mt*100;// %age mass composition of H2O produced x3 = m3/mt*100;// %age mass composition of O2 produced x4 = m4/mt*100;// %age mass composition of N2 produced vt = x1/mCO2+x2/mH2O+x3/mO2+x4/mN2;// total volume v1 = x1/mCO2/vt*100;// %age volume composition of CO2 v2 = x2/mH2O/vt*100;// %age volume composition of H2O v3 = x3/mO2/vt*100;// %age volume composition of O2 v4 = x4/mN2/vt*100;// %age volume composition of N2 Mav = (v1*mCO2+v2*mH2O+v3*mO2+v4*mN2)/(v1+v2+v3+v4);// average moleculer mass, [kg/kmol] // since no of moles is constant so PV/T=constant V2 = P1*V1*T2/(P2*T1);//volume, [m^3] mp = mt*mc/3600;// mass of product of combustion/s, [kg] V = V2*mp/Mav;// volume of flowing gas /s,[m^3] v = V/A;// velocity of flue gas, [m/s] mprintf('\n The actual mass of air supplied is = %f kg/kg coal\n',mas); mprintf('\n The velocity of flue gas is = %f m/s\n',v); // End
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Example_11_17.sce
//Example 11.17 Fenske's Equation clear; clc; printf("\tExample 11.17\n"); //From previous question data xA_d=0.453; xB_d=0.013; xA_s=0.04; xB_s=0.96; alpha_av=2.22; //By Fenske Equation for no. of plates n=((log(xA_d*xB_s/(xA_s*xB_d)))/log(alpha_av))-1; printf("\nMinimum no. of plates are %f or %d\n",n,n); //End
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Ex8_19.sce
//power gain and directivity of a horn //given clc f=8d+9//hertz v=3d+8//m/s d=0.1//m//aperture dimentions W=0.05//m//aperture dimentions lemda=v/f//metre gp=4.5*W*d/lemda^2 gp_decibles=10*log10(gp)//changing to decibles D=7.5*W*d/lemda^2//directivity D_decibles=10*log10(D) gp_decibles=round(gp_decibles*100)/100///rounding off decimals D_decibles=round(D_decibles*100)/100///rounding off decimals disp(D_decibles,gp_decibles,'the beamwidth power gain and directivity in decibles')//decibles
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//Scilab Code for Example 3.16 of Signals and systems by //P.Ramakrishna Rao //A=%pi or 3.14 clear; clc; //Trignometric Fourier Coefficients for n=0:5 a(n+1)=integrate('t*cos(2*%pi*n*t)','t',0,1); end for n=0:5 b(n+1)=integrate('t*sin(2*%pi*n*t)','t',0,1); end disp(%pi*a(1),"an(a0)") disp("an(a1-->a5)") for n=1:5 disp(2*a(n+1)*%pi) end disp("bn(b1-->b5)") for n=1:5 disp(2*%pi*b(n+1)) end //CTFS coefficients of a periodic signal //x(t) =t t = 0:0.01:1; xt =2*%pi*t; // for k =0:6 C(k+1,:) = exp(-sqrt(-1)*2*%pi*t*k); c(k+1) = xt*C(k+1,:)'/length(t); if(abs(c(k+1))<=0.01) c(k+1)=0; end end c =c'; c_conj = real(c(:))-sqrt(-1)*imag(c(:)); ck = [c_conj($:-1:1)',c(2:$)]; k = 0:6; k = [-k($:-1:1),k(2:$)]; c = gca(); c.y_location = "origin"; c.x_location = "origin"; plot2d3('gnn',k,abs(ck)) poly1 = c.children(1).children(1); poly1.thickness = 3; title('|ck|') xlabel('k')
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//Exa 8.7 clc; clear; close; //Given data : fmin=20;//in Hz fmax=20;//in kHz Cmin=30;//in pF Cmax=300;//in pF //Formula : fo=1/(2*%pi*R*C)) disp("Minimum Fequeny correspond to maximum capacitance.") R=1/(2*%pi*fmin*Cmax*10^-12) disp(R/10^6,"Required resistance in Mohm : ");
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//EXAMPLE 5.4 //DETERMINE IDFT OF GIVEN SEQUENCE clc; clear; K = input(" value of K "); disp('input M > K'); M = input(" value of M "); k1 = 0:K-1; V1 = k1./K;//DFT k=0:M-1; N = length(V1); V = [V1,zeros(1,M-N)]; v = dft(V,1);//IDFT clf(); subplot(1,2,1) a = gca(); plot2d3(k,real(v),2); plot(k,real(v),'r.'); a.x_location = 'origin'; a.y_location = 'origin'; poly1 = a . children (1) . children (1) ; poly1.thickness = 2; xtitle('real part','N','v'); subplot(1,2,2) a = gca(); plot2d3(k,imag(v),2) plot(k,imag(v),'r.'); a.x_location = 'origin'; a.y_location = 'origin'; poly1 = a . children (1) . children (1) ; poly1.thickness = 2; xtitle('imaginary part','N','v'); v = disp(v);
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//Exa 7.1 clc; clear; close; //Given data : r=1;//cm d=4;//meter g0=30/sqrt(2);//kV/cm LineVoltage=sqrt(3)*g0*r*log(d*100/r);//kV disp(round(LineVoltage),"Line Voltage for comencing of corena(in kV) :");
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// Exa 9.21 clc; clear; close; format('v',8) // Given data VA = 400*10^3;// in Mean Eta_fl = 98.77/100;// in % phi1= acosd(0.8);// in ° phi2= acosd(1);// in ° Eta_hl = 99.13/100;// in % n = 1/2; //For full load, Eta_f1 = ((VA*cosd(phi1))/( VA*cosd(phi1) + Pi + Pcu_f1 )) or Pi+Pcu_f1 = VA*cosd(phi1)*(1-Eta_fl)/(Eta_f1) (i) //For half load, Eta_hl = n*VA*cosd(phi2)/(n*VA*cosd(phi2)+Pi+n^2*Pcu_f1) or Pi+n^2*Pcu_f1 = n*VA*cosd(phi2)*( 1-Eta_hl)/Eta_hl (ii) // From eq(i) and (ii) Pcu_fl=(n*VA*cosd(phi2)*( 1-Eta_hl)/Eta_hl-VA*cosd(phi1)*(1-Eta_fl)/(Eta_fl))/(n^2-1);// in W Pi=VA*cosd(phi1)*(1-Eta_fl)/(Eta_fl)-Pcu_fl;// in W disp(Pi,"The iron loss on full load and half load remain same in W which are : ") disp(Pcu_fl,"The copper loss on full load in W is : ") // The copper loss on half load C_loss_half_load=n^2*Pcu_fl;// in W disp(C_loss_half_load,"The copper loss on half load in W is : ")
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//Exercise 1.3 //Example 1.3.6 //Adding,Subtracting and multiplying Rational Numbers function[]=rational(x1,x2,x3,x4) rational1=struct('numerator',x1,'denominator',x2); disp(rational1); rational2=struct('numerator',x3,'denominator',x4); disp(rational2); //Add x5=int32([x2 x4]); x5=lcm(x5); x6=x1*(x5/x2)+x3*(x5/x4); rational3=struct('numerator',x6,'denominator',x5); disp(rational3,"After addition"); //subtract x6=x1*(x5/x2)-x3*(x5/x4) rational4=struct('numerator',x6,'denominator',x5); disp(rational4,"After Subtraction"); //Multiply x7=x1*x3; x8=x2*x4; rational5=struct('numerator',x7,'denominator',x8); disp(rational5,"After multiplication"); endfunction x1=43; x2=32; x3=233; x4=33; rational(x1,x2,x3,x4);
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ZeroAndNegate.tst
// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Add16.tst load ZeroAndNegate.hdl, output-file ZeroAndNegate.out, compare-to ZeroAndNegate.cmp, output-list x%B1.16.1 zx%D2.1.1 nx%D2.1.1 out%B1.16.1; set x %B0000000000000000, set zx 0, set nx 0, eval, output; set x %B0000000000000000, set zx 0, set nx 1, eval, output; set x %B1111111111111111, set zx 1, set nx 0, eval, output; set x %B1010101010101010, set zx 1, set nx 0, eval, output; set x %B1010101010101010, set zx 1, set nx 1, eval, output; set x %B1010101010101010, set zx 0, set nx 1, eval, output; set x %B0011110011000011, set zx 0, set nx 1, eval, output;
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, axi-symmetric nozzle without swirl</description> <executable>CompressibleFlowSolver</executable> <parameters>Nozzle_AxiSym_NoSwirl.xml</parameters> <files> <file description="Session File">Nozzle_AxiSym_NoSwirl.xml</file> </files> <metrics> <metric type="L2" id="1"> <value variable="rho" tolerance="1e-12">3.05647</value> <value variable="rhou" tolerance="1e-12">2.3371</value> <value variable="rhov" tolerance="1e-12">102.54</value> <value variable="E" tolerance="1e-12">616238</value> </metric> <metric type="Linf" id="2"> <value variable="rho" tolerance="1e-12">1.26181</value> <value variable="rhou" tolerance="1e-12">2.82123</value> <value variable="rhov" tolerance="1e-12">60.5981</value> <value variable="E" tolerance="1e-12">260653</value> </metric> </metrics> </test>
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Chapter4_Example7.sce
clc clear //INPUT DATA pb=25;//Saturated vapour in bar pc=0.2;//Saturated liquid in bar T111=300;//Temperature in degree C h1=2800.9;//Enthalpy in kJ/kg hb=962;//Enthalpy in kJ/kg h5=2609.9;//Enthalpy in kJ/kg h3=251.5;//Enthalpy in kJ/kg S5=7.9094;//Entropy in kJ/kg.K S3=0.8321;//Entropy in kJ/kg.K Sb=2.5543;//Entropy in kJ/kg.K S1=6.2536;//Entropy in kJ/kg.K x1=0.8;////Quality of steam h111=3008.9;//Enthalpy in kJ/kg S111=6.644;////Entropy in kJ/kg.K //CALCULATIONS h11=(hb+x1*(h1-hb));//Enthalpy in kJ/kg S11=(Sb+x1*(S1-Sb));//Enthalpy in kJ/kg x21=((S11-S3)/(S5-S3));//quality of steam h21=(h3+(x21*(h5-h3)));//Enthalpy in kJ/kg nRi=(((h11-h21)/(h11-h3))*100);//Rankine cycle efficiency in percentage x2=((S1-S3)/(S5-S3));//quality of steam h2=h3+x2*(h5-h3);//Enthalpy in kJ/kg nRi2=(((h1-h2)/(h1-h3))*100);//Rankine cycle efficiency in percentage x211=((S111-S3)/(S5-S3));//quality of steam h211=(h3+(x211*(h5-h3)));//Enthalpy in kJ/kg nRi1=(((h111-h211)/(h111-h3))*100);//Rankine cycle efficiency in percentage //OUTPUT printf('(i) The Rankine cycle efficiency when steam is dry at turbine inlet is %3.2f percent \n(ii) The Rankine cycle efficiency when steam is saturated is %3.2f percentage \n(iii)The Rankine cycle efficiency when steam is superheated is %3.2f percent ',nRi,nRi2,nRi1)
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clc //initialisation of variables clear p= 23.76 //mm R= 0.082 //atm-lit deg^-1 mol^-1 T= 25 //C vl= 18 //ml p1= 1 //atm //CALCULATIONS dP= 0.001*vl*p*p1/(R*(273+T)) p2= p+dP //RESULTS printf ('vapour pressure = %.2f mm',p2) //ANSWER GIVEN IN THE TEXTBOOK IS WRONG
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// This file is released under the 3-clause BSD license. See COPYING-BSD. // Generated by builder.sce : Please, do not edit this file // ---------------------------------------------------------------------------- // //if win64() then // warning(_("This module requires a Windows x86 platform.")); // return //end //// serial_path = get_absolute_file_path('loader.sce'); // // ulink previous function with same name [bOK, ilib] = c_link('open_serial'); if bOK then ulink(ilib); end // [bOK, ilib] = c_link('close_serial'); if bOK then ulink(ilib); end // [bOK, ilib] = c_link('write_serial'); if bOK then ulink(ilib); end // [bOK, ilib] = c_link('status_serial'); if bOK then ulink(ilib); end // [bOK, ilib] = c_link('read_serial'); if bOK then ulink(ilib); end // [version, opts]=getversion(); if (opts(2)=='x86') then link(serial_path + 'libserial' + getdynlibext(), ['open_serial','close_serial','write_serial','status_serial','read_serial'],'c'); elseif (opts(2)=='x64') then link(serial_path + 'libserial64' + getdynlibext(), ['open_serial','close_serial','write_serial','status_serial','read_serial'],'c'); else disp('Unsupported architecture') end // remove temp. variables on stack clear serial_path; clear bOK; clear ilib; // ----------------------------------------------------------------------------
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clear //Given E0=60 R=20.0 //ohm //Calculation // Ev=E0/(sqrt(2)) Iv=Ev/R //Result printf("\n (i) A.C ammeter will %0.2f A",Iv) printf("\n (ii) Average value of a.c over one cycle is zero")
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Triangular_Matrix_Solver.sce
//Upper matrix by Rêmullo Costa - - apr/2016 //solve problems and find the value of x by just giving the values for the matrix A and the // 'b' matrix (answer vector). function Triangular(A, b) //THIS FUNCTION TAKES VALUES OF A MATRIX 'A' AND A 'b' ANSWER VECTOR AND //LOWER FUNCTION ---------------------------------------------------------------------- function x = triangInf(A, b) //creates an lower matrix solving function [linhas colunas] = size(A); // [rows columns] gets the size of the squared matrix x(1) = b(1)/A(1,1); for i = 2:1:linhas //starts from the 2nd line till the last one soma = 0; // sum starts from zero for j = 1:1:i-1 //j counter goes till i-1 soma = soma + A(i,j)*x(j); //sums all factors end x(i)= (b(i)- soma)/A(i,i); //determines the solution in a vector of x values end endfunction //end of the triangInf function //------------------------------------------------------------------------------------- //UPPER FUNCTION ---------------------------------------------------------------------- function x = triangSup(A, b) //creates an upper matrix solving function [linhas colunas] = size(A); // [rows columns] gets the size of the squared matrix for i = linhas:-1:1 //starts from the latest row 'till the first one. somatorio = 0; // sum is set to start from zero for j = i+1:linhas //now it will sum the terms of this line multiplied by the 'x'related somatorio = somatorio + A(i,j)*x(j); end x(i)= (b(i)- somatorio)/A(i,i); //for each iteration in rows, we find the current 'x' value end endfunction //end of the TriangSup function //------------------------------------------------------------------------------------- //SELECTS WHICH TYPE IS MORE APROPRIATED TO CALCULATE IT!------------------------------ if(A(1,2)==0) then ans = triangInf(A,b); disp(ans); else ans = triangSup(A,b); disp(ans); end //------------------------------------------------------------------------------------- endfunction //end of the whole function
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1_3.sce
clc; disp("Example 1.3") density= 1200 // in kg/m^3 r= 0.15 // bowl radius in m Ri=0.12 // interface position from the bowl axis in m n= 3500 // rotational speed in rpm omega= %pi*2*n/60 p= density*omega*omega*(r^2-Ri^2)/2 disp(" Gauge pressure is ") disp(p) disp(" N/m^2")
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//Example 3.14 //Program to determine the mode coupling parameter for the fiber clear; clc ; close ; //Given data L=3.5*10^3; //metre - LENGTH CT=-27; //dB - POLARIZATION CROSSTALK //Mode coupling parameter for the fiber h=(10^(CT/10))/L; //as tan(h*L)=h*L for small values //Displaying the Result in Command Window printf("\n\n\t The mode coupling parameter for the fiber is %0.1f X 10^(-7)/m.",h/10^(-7));
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clc(); clear; //To determine the angle of second order bragg's reflections //According to Bragg's eq.2*d*sin(teta)=n*lambda n=2; //since second order Bragg's eq. d=5; //since d=5(lambda) lambda=1; a=(n*lambda)/(2*5*lambda); teta=asind(a) //angle of second order Braggs reflections printf("The angle of second order Braggs reflection is %f",teta);
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clc forgings = 40 setup = 4 Tc = 12 // machining time in min. per forging nmt = 21 // non-machining in min. per forging st = 45 // set up time per set up ts = 5 // total sharpening in min. per forging f = 20 // fatigue in percent f = f/100 pn = 5 // personal needs in percent pn = pn/100 Tk = 10 // tool chanhe time in min. T = 8 // tool life in hours ct = 15 // checking time with 5 checks in 15 secs R = 1.4 // performance factor dlc = 5 // direct labour cost in Rs per hour tt = Tc+nmt // machining and non-machining time in min. ft = f*tt // fatigue time in min. pnt = pn*tt // personal needs in min. t = (Tc*Tk)/(T*60) // total sharpening time in min. per forging mct = (ts*ct)/60 // measuring and checking time in min.per forging su = Tc + nmt+ pnt + ft + t + mct // sum of times in min. tf = su*forgings // time for 40 forgings in min. tst = st*setup // total set up time in min. Te = tf+tst // total estimated time in min. Ta = Te*R // total actual time in min. lc = (Ta*dlc)/60 // direct labour cost in Rs printf("\n Direct labour cost = Rs %0.1f" , lc)
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3_06.sce
//pathname=get_absolute_file_path('3.06.sce') //filename=pathname+filesep()+'3.06-data.sci' //exec(filename) //Initial pressure(in MPa): p1=1 //Final pressure(in MPa): p2=2 //Initial volume(in m^3): v1=0.05 //Value of n: n=1.4 //Final volume(in m^3): v2=v1*((p1/p2)^(1/n)) //Change in internal energy(in kJ/kg): du=7.5*(p2*v2-p1*v1)*10^3 //Work done(in kJ): w=(p2*v2-p1*v1)*10^3/(1-n) //Heat interaction(in kJ): Q=du+w printf("\nRESULT\n") printf("\nHeat interaction = %f kJ",Q) printf("\nWork interaction = %f kJ",w) printf("\nChange in internal energy = %f kJ",du) //If 180 kJ heat transfer takes place: //Work done(in kJ): w2=180-du printf("\nNew work = %f kJ",w2)
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1_auto_correlation.sce
// Group_13: Bhargava B // Surya K // S K Savant // Question: // Let x(n) be the 13-point Barker sequence // x(n) = {+1, +1, +1, +1, +1, -1, -1, +1, +1, -1, +1, -1, +1}. // Determine the auto-correlation of the above sequence. // // Function to find auto_correlation of x //Barker NOT WORKING : To FIX TO Auto_Correlation function[corrvec]=auto_correlation(sequence) N=length(sequence) nvec=linspace(0,2*N,2*N) // - corrvec=[] for i=0:2*N-1 // i= 0 to 2N+1 corrval=0 for j=1:N if(i-j>0 & i-j<=N) then //disp(i-j) corrval=corrval+sequence(i-j)*sequence(j) end end corrvec=[corrvec,corrval] end disp(corrvec) //disp(length(corrvec)) //disp(length(nvec)) plot(nvec,corrvec) endfunction barker=[1,1,1,1,1,-1,-1,1,1,-1,1,-1,1] auto_correlation(barker)
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clc; clear all; l = 16; // Length of optical fiber in Km Pi = 240e-6; // Mean optical length launched in optical fiber in Watts Po = 6e-6; // Mean optical power at the output in watts alpha = 10*log10(Pi/Po);//Signal attenuation in fiber disp('dB',alpha,'Signal attenuation in fiber') alpha1 = alpha/l;//Signal attenuation per km of the fiber disp('dB/km',alpha1,'Signal attenuation per km of the fiber');
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Ex_10_10.sce
// Example 10.10;//threshold quantum limit clc; clear; close; e=1.6*10^-19; R=0.5;//responsivity in amper per watt n=1;//efficiency for idea case ht=6.62*10^-34;//plank constt. f=3*10^14;//frequency in hertz R=35;//mega bits per second h=0.50^-6;//wavelength in metr BER=10^-7;//bit error rate Zm=-(log(BER));//probality of error Po=(Zm*2*e*R*10^6)/2; Podb=10*(log10(Po*10^3));//pulse energy in dB when refrence level is one milli watt disp(Podb , "pulse energy in dB when refrence level is one miiliwatt in dBm")
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// Scilab Code Ex2.59:: Page-2.47(2009) clc; clear; D_15 = 1.62; // Diameter of 15th dark ring with air film, cm D_15_prime = 1.47; // Diameter of 15th dark ring with liquid, cm R = 1; // For simplicity assume radius of curvature to be unity, cm n = 15; // Order of 15rd Newton ring // As for ring with air film, D_15^2 = 4*15*R*lambda, solving for lambda lambda = D_15^2/(4*15*R); // Wavelength of light used, cm // As for ring with liquid, D_15_prime^2 = 4*15*R*lambda/mu, solving for mu mu = 4*15*R*lambda/D_15_prime^2; // Refractive index of the liquid printf("\nThe refractive index of the liquid = %4.2f", mu) // Result // The refractive index of the liquid = 1.21
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clc // Example 3.2.py // Return to Example 1.6, Calculate the Mach Number and velocity at the exit of the rocket // nozzle. // Variable declaration from example 1.6 pc = 15.0 // pressure combustion chamber (atm) Tc = 2500.0 // temperature combustion chamber (K) mol_wt = 12.0 // molecular weight (gm) cp = 4157.0 // specific heat at constant pressure (J/Kg/K) Tn = 1350.0 // temperature at nozzle exit (K) // Calculations R = 8314.0/mol_wt // gas constant = R_prime/mo_wt, R_prime = 8314 J/K cv = cp - R // specific heat at constant volume (J/Kg k) gamma1 = cp/cv // ratio of specific heat pn_by_pc = (Tn/Tc** gamma1/(gamma1-1)) // ratio of pressure for isentropic process** pn/pc Mn = (2/(gamma1-1)*((1/pn_by_pc**(gamma1-1)/gamma1) - 1)** 0.5) // Mach number at exit** from isentropic flow relation an = (gamma1*R*Tn** 0.5) // Speed of sound at exit (m/s) Vn = Mn*an // Velocity at exit (m/s) // Result printf("\n Mach number at the exit of the rocket nozzle is %.3f",(Mn)) printf("\n Velocity at the exit of the rocket nozzle is %.1f m/s",(Vn))
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example4_12.sce
//example 4.12 //plot IDF curve for return period of 10,2 and 1 years using california formula clc;funcprot(0); //given t=[5 10 20 30 60 90 120]; //duration //value of P for respective return period is p10=[10.6 14.7 19.3 20.8 25.5 29 34.7]; //rainfall for T=10 years p2=[8.2 10.3 13.2 14.2 16.6 19.4 21.4]; //rainfall for T=2 years p1=[3.5 6.2 8.9 10 13.2 15 16.5]; //rainfall for T=1 year for i=1:7 i1(i)=p10(i)*60/t(i); //intensity of rainfall with return period of 10 years i2(i)=p2(i)*60/t(i); //intensity of rainfall with return period of 2 years i3(i)=p1(i)*60/t(i); //intensity of rainfall with return period of 1 year end //graph is plotted between //t and i1 //t and i2 //t and i3
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pFET_IdVs.sce
unix_g('sudo chmod 777 /dev/prologix'); h=openserial("/dev/prologix", "9600,n,8,1"); //please make sure all the tty values are correct before starting the program. writeserial(h,"++addr 15"+ascii(10)); unix_w("sleep 1"); writeserial(h,"++auto 1"+ascii(10)); unix_w("sleep 1"); writeserial(h,"SYST:ZCH 0"+ascii(10)); pFET_sCTRL=[(0:0.1:1.8)'; (1.82:0.02:2.5)';]; //pFET_sCTRL=[0.0; 0.5; 1; 1.5; 2.0; 2.5;]; size_pFET_sCTRL=size(pFET_sCTRL); for i_pFET_s=1:size_pFET_sCTRL(1,1) unix_g('sudo dwfcmd connect target=analogout channel=0 enable=1 function=dc offset="+string(pFET_sCTRL(i_pFET_s,1))+"V run=0 start finish'); writeserial(h,"READ?"+ascii(10)); xpause(3000000); temp_a=readserial(h); temp_b=part(temp_a,1:14); current(1,1)=msscanf(temp_b,"%lg"); while current ==[] unix_g('sudo chmod 777 /dev/prologix'); h=openserial("/dev/prologix", "9600,n,8,1"); writeserial(h,"++addr 15"+ascii(10)); unix_w("sleep 1"); writeserial(h,"++auto 1"+ascii(10)); unix_w("sleep 1"); writeserial(h,"SYST:ZCH 0"+ascii(10)); writeserial(h,"READ?"+ascii(10)); xpause(3000000); temp_a=readserial(h); temp_b=part(temp_a,1:14); current(1,1)=msscanf(temp_b,"%lg"); end unix_g('sudo dwfcmd connect target=analogout channel=0 enable=1 function=dc offset="+string(pFET_sCTRL(i_pFET_s,1))+"V run=0 start watch=2s analogin record channel=1 enable=1 range=2V offset=0 frequency=1k run=0.01s start save=null_data.csv'); pFET_sCTRL(i_pFET_s,2)=abs(current); disp('D: 2.5V V S:'+string(pFET_sCTRL(i_pFET_s,1))+'V Current:'+string(current)); end csvWrite(pFET_sCTRL,'data_pFET_IdVs.csv'); disp("done"); pFET_IdVs=csvRead('data_pFET_IdVs.csv'); scf(5);clf(5); plot2d("nl", pFET_IdVs(:,1), pFET_IdVs(:,2));p = get("hdl"); p.children.mark_style = 9; p.children.thickness = 3; p.children.line_mode="off";p.children.mark_foreground=1; a=gca();a.data_bounds=[0 1e-11; 2.5 1e-4]; xtitle("","Vs(V)","Id(A)");
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//Example 4.10: clc; clear; close; //given data : format('v',6) Bv=12;//battery voltage in V P=2;// power in Watt Ic=(P/Bv)*10^3; disp(Ic,"The maximum collector current,Ic(mA) = ")
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/* ex. Sejam os nós x=[0, 0.6, 1]. Encontre os pesos A_i da quadratura I=A_1f(x_1)+A_2f(x_2)+A_3f(x_3) tal que o erro seja o menor possível para aproximar a integral de f no intervalo 0 a 1. R: [8/36, 25/36, 3/36] */ clear vetor_nodes = [-0.72, 0.12, 0.82] lim_inicial = -1 lim_final = 1 len_nodes = length(vetor_nodes) // Monta matriz A for i = 1:len_nodes for j = 1:len_nodes if i == 1 then A(i,j) = i // Primeira linha so tem 1s else A(i,j) = vetor_nodes(j)^(i-1) end end end // Monta matriz resultado B for i = 1:len_nodes B(i) = (lim_final^i - lim_inicial^i)/i end // Obtem pesos w = inv(A)*B disp(w)
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function Zeq=parallel(Z1,Z2) Zeq=Z1*Z2/(Z1+Z2) endfunction V=12*%i Vth=4-12*%i/(4-12*%i+6+9*%i)*V Zth=parallel(4-12*%i,6+9*%i) I=Vth/(Zth+6+12*%i) S=V*conj(I) disp(S) Zl=conj(Zth) I=Vth/(Zth+Zl) S=V*conj(I) disp(Zth,S)
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// example: 4.23; // piecewise cubical interpolating polinomials: X=[-3 -2 -1 1 3 6 7]; F=[369 222 171 165 207 990 1779]; // we need to apply legranges interpolation in sub-ranges [-3 ,1];[1,7]; x=poly(0,"x"); // 1) in the range [-3,1] x=[-3 -2 -1 1]; f=[369 222 171 165]; n=3; P2=lagrangefundamentalpoly(x,f,n); // 2) in the range [1,7] x=[1 3 6 7]; f=[165 207 990 1779]; n=3; P2=lagrangefundamentalpoly(x,f,n) // hence, disp('f(6.5)=1339.25');
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//Example 4.9 clc //The scanf function //a,b,c are integer type variables printf("Enter value for a, b, c : "); printf("\n [Enter integer values in single line seperated by spaces]) "); [n,a, b,c]=mscanf("%3d %3d %3d"); printf("a = %d, b = %d, c = %d ", a, b, c);
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example2_2.sce
clear; clc; printf("\t Example 2.2\n"); //kopp's law is valid u=1.145*10^-3; //viscosity of water1.145cp v_a=5*.0148+12*.0037+1*.0074; //by kopp's law t=288; //temperature of water in kelvin MB=18; //molecular weight of water phi=2.26; //association parameter for solvent-water D_ab=(117.3*10^-18)*((phi*MB)^.5)*(t)/(u*(v_a)^.6); printf("\n the diffusivity of isoamyl alcohol is :%f *10^-9 m^2/s",D_ab/10^-9); //end
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Figure_04_IVconverterRampADC.sce
global file_name path fname extension chip_num board_num hex_1na; cd("/home/ubuntu/RASP_Workspace/data_for_calibration_paper"); path = pwd(); exec('~/rasp30/prog_assembly/libs/scilab_code/diodeADC_v2i.sce',-1); exec('~/rasp30/prog_assembly/libs/scilab_code/diodeADC_i2v.sce',-1); exec('~/rasp30/prog_assembly/libs/scilab_code/diodeADC_v2h.sce',-1); exec('~/rasp30/prog_assembly/libs/scilab_code/diodeADC_h2v.sce',-1); hex_1na=int(diodeADC_v2h(diodeADC_i2v(1e-09,chip_num,brdtype),chip_num,brdtype)); exec('~/rasp30/prog_assembly/libs/scilab_code/linefit.sce',-1); exec('~/rasp30/prog_assembly/libs/scilab_code/ekvfit_diodeADC.sce',-1); diodeADC_iv=csvRead("~/rasp30/prog_assembly/libs/scilab_code/characterization/char_diodeADC/data_diodeADC_chip"+chip_num+brdtype+"_ivdd25V"); Isat=diodeADC_iv(:,2); Vout=diodeADC_iv(:,3); Hex_code=diodeADC_iv(:,4); epsilon=0.004; plotting="off"; //"on_all" or "on_final" or "off" [Is, VT, kappa]=ekvfit_diodeADC(Vout, Isat, epsilon, plotting); //disp('EKV Fit: I_s = '+string(Is)+'A, V_T = '+string(VT)+'V, Kappa = '+string(kappa)); epsilon=1; [WIfirst, WIlast, Slope_v2h, Offset_v2h, WIN]=linefit(Vout, Hex_code, epsilon); csvWrite([Is, VT, kappa, Slope_v2h, Offset_v2h],'EKV_diodeADC'); unix_w("cp EKV_diodeADC ~/rasp30/prog_assembly/libs/chip_parameters/EKV_diodeADC/EKV_diodeADC_chip"+chip_num+brdtype); EKV_diodeADC_para=csvRead("~/rasp30/prog_assembly/libs/chip_parameters/EKV_diodeADC/EKV_diodeADC_chip"+chip_num+brdtype); Is=EKV_diodeADC_para(1); VT=EKV_diodeADC_para(2); kappa=EKV_diodeADC_para(3); Slope_v2h=EKV_diodeADC_para(4); Offset_v2h=EKV_diodeADC_para(5); //Isat2=diodeADC_v2i(Vout, chip_num, brdtype); //Vout2=diodeADC_i2v(Isat2, chip_num, brdtype); vdd=2.5; Vfg=vdd-(Vout/2); scf(2);clf(2); plot2d("nl",Vfg, Isat, style=1);p = get("hdl"); p.children.mark_style = 9; p.children.thickness = 1; p.children.line_mode="off"; plot2d("nl", Vfg, diodeADC_v2i(Vfg, chip_num, brdtype), style=1);p = get("hdl"); p.children.line_style = 1; p.children.thickness = 3; p.children.thickness = 3;p.children.line_mode="on"; legend("Data","EKV fit","in_lower_left"); xtitle("","Vfg [V]","Iprog [A]"); a=gca();a.data_bounds=[1.3 1e-13; 2.4 5e-4]; title(['EKV Fit: I_s = '+string(Is)+'A, V_T = '+string(VT)+'V, Kappa = '+string(kappa)]); scf(3);clf(3); plot2d("ln",Isat, 2*(vdd-Vfg), style=1);p = get("hdl"); p.children.mark_style = 9; p.children.thickness = 1; p.children.line_mode="off"; //plot2d("ln",Isat, 2*(vdd-diodeADC_v2i(Vfg, chip_num, brdtype), style=1);p = get("hdl"); p.children.line_style = 1; p.children.thickness = 3; p.children.thickness = 3;p.children.line_mode="on"; legend("Data","EKV fit","in_upper_left"); xtitle("","Iprog [A])","Vprog [V]"); a=gca();a.data_bounds=[1e-12 0.4; 1e-4 2.4]; //title(['EKV Fit: I_s = '+string(Is)+'A, V_T = '+string(VT)+'V, Kappa = '+string(kappa)]); scf(4);clf(4); plot2d("nn", 2*(vdd-Vfg), Hex_code, style=1);p = get("hdl"); p.children.mark_style = 9; p.children.thickness = 1; p.children.line_mode="off"; plot2d("nn", 2*(vdd-Vfg), diodeADC_v2h(Vfg, chip_num, brdtype), style=1);p = get("hdl"); p.children.line_style = 1; p.children.thickness = 3; p.children.thickness = 3;p.children.line_mode="on"; legend("Data","Data for linefit","linefit","in_lower_right"); a=gca();a.data_bounds=[0.4 1000; 2.4 10000]; xtitle("","Vprog [V]","Hex_code"); //title('Vfg vs. Hex code Fit'); //scf(5);clf(5); //plot2d("nl", diode_ivdd25V(:,4), diode_ivdd25V(:,2), style=1);p = get("hdl"); p.children.mark_style = 9; p.children.thickness = 1; p.children.line_mode="off"; //plot2d("nl", ADC_range_ivdd25V, exp(diode_fit_ivdd25V), style=5);p = get("hdl"); p.children.line_style = 1; p.children.thickness = 3; p.children.thickness = 3;p.children.line_mode="on"; //plot2d("nl", diodeADC_v2h(Vfg, chip_num, brdtype), diodeADC_v2i(Vfg, chip_num, brdtype), style=2);p = get("hdl"); p.children.line_style = 1; p.children.thickness = 3; p.children.thickness = 3;p.children.line_mode="on"; //legend("data","Polyfit","EKV_fit","in_lower_right"); //xtitle("","Hex_code","Isat(A)"); //title('Polyfit vs. EKVfit'); // //Current_to_ADC(:,3)=diodeADC_v2h(diodeADC_i2v(Current_to_ADC(:,1), chip_num, brdtype), chip_num, brdtype); // //disp(Current_to_ADC);
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rootmusic4.sce
//sampling frequency is passed as an i/p arg R=[6.1117 + 0.0000*%i 3.8205 - 3.9887*%i -0.2138 - 5.5126*%i 3.8205 + 3.9887*%i 6.0796 + 0.0000*%i 3.8205 - 3.9887*%i -0.2138 + 5.5126*%i 3.8205 + 3.9887*%i 6.1117 + 0.0000*%i]; Fs=200; [F, POW]= rootmusic(R,2,Fs); disp(F); disp(POW); //output // 63.273966 // 25.713115 // // 0.0233417 // 97.850188
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Ex9_3.sce
//============================================================================= // chapter 9 example 3 clc clear // Variable declaration P = 400; // tensile force in newtons d = 6*10^-3; // diameter of steel rod m // Calculations r =d/2; E_stress = P/((%pi/4)*r*r); //e_stress in N/m^2 // Result mprintf('Engineering stress = %3.2f MPa',E_stress/10^6); //===========================================================================
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Fss = 16000; //the bitrate of the song Speed = 1.5; //how fast the song will be played [testsign,Fs,bits]=wavread("SCI/modules/sound/demos/filterTest2(anja).wav"); //reading the wav (music) file in a matrix testsign = testsign(1,:); //when reading in the wav file it creates 2 channels (stereo) and we only need one (mono) t = [1:1:length(testsign)]*1/Fs; //We do this to plot the testsign in function of the sample frequetion of the wav file //muziek afspelen afhankelijk van de speed playsnd(testsign,Speed*Fss);
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Example3_7.sce
//Exa 3.7 clc; clear; close; //Given data : P1=1000;//kW pf1=0.8;// t1=10;//hours P2=500;//kW pf2=0.9;// t2=8;//hours P3=100;//kW pf3=1;// t3=6;//hours a=poly(0,'a');//cross section area I=poly(0,'I');//Current L=poly(0,'L');//length in km CcBYL=(8000*a+1500)//Rs/km(variable cost) i=10;//%(depreciation) E_lost_cost=80/100;//Rs/kWh rho=1.72*10^-6;//ohm-cm Cc_varBYL=8000*a*i/100//Rs/km(variable cost) I1=P1*1000/sqrt(3)/10000/pf1;//A I2=P2*1000/sqrt(3)/10000/pf2;//A I3=P3*1000/sqrt(3)/10000/pf3;//A R_into_a_BY_L=rho*1000*100;//ohm W_into_A_BY_Isqr=R_into_a_BY_L;//W E_loss_into_A_BY_L=3*R_into_a_BY_L*[I1^2*t1+I2^2*t2+I3^2*t3]*365/1000;//kWh E_loss_cost_into_A_BY_L=E_loss_into_A_BY_L*E_lost_cost;//Rs //Cc_var=E_loss_cost;//For most economical cross section a=sqrt(coeff((numer(E_loss_cost_into_A_BY_L))/coeff(numer(Cc_varBYL/a))));//cm^2 disp(a,"Most economical cross sectional area in cm^2 : ");
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ex2.sce
//example 2 //heat transfer in a given process clear clc u1=87.94 //specific internal energy of R-12 at state 1 in kJ/kg u2=276.44 //specific internal energy of R-12 at state 2 in kJ/kg s1=0.3357 //specific entropy at state 1 in kJ/kg-K s2=1.2108 //specific entropy at state 2 in kJ/kg-K V=0.001 //volume of saturated liquid in m^3 v1=0.000923 //specific volume in m^3/kg m=V/v1 //mass of saturated liquid in kg T=20 //temperature of liquid in celsius Q12=m*(T+273.15)*(s2-s1) //heat transfer in kJ to accomplish the process W12=m*(u1-u2)+Q12 //work required to accomplish the process printf(" \n hence,work required to accomplish the process is W12=%.1f kJ.\n",W12) printf(" \n and heat transfer is Q12=%.1f kJ.\n",Q12)
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//Section-14,Example-1,Page no.-PC.125 //To determine the pH of the given solution. clc; K_a=1.75*10^-5 pK_a=-log10(K_a) [CH_3COOH]=(1000/(60*100)) //moldm^-3 [CH_3COONa]=((1.5*1000)/(82*100)) //moldm^-3 pH=(pK_a+ (log10([CH_3COONa]/[CH_3COOH]))) disp(pH,'pH of the given solution')
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Ex6_19.sce
clear; clc; printf("\nEx-6.19\n"); //page no.-192 //given E=5.53;......//fermi energy in eV e=1.6*10^-19;.....//charge tau=3.91*10^-14;..//relaxation time in s m=9.11*10^-31;....//mass of electron v=((2*E*e)/m)^(1/2).......//fermi velocity printf("\nfermi velocity is 1.39*10^6 m/s\n"); k=1.38*10^-23;......//boltzmann constant T=(E*e)/k..............//fermi temperature in kelvin printf("\nfermi temperature is 6.41*10^4 k");
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// Exa 8.16 clc; clear; close; // Given data I_DSS = 10;// in mA V_P = -5;// in V V_GS = -2.5;// in V g_m = ((-2*I_DSS)/V_P)*(1-(V_GS/V_P));// in mS .... correction disp(g_m,"The transconductance in mS is"); I_D = I_DSS * ((1-(V_GS/V_P))^2);// in mA disp(I_D,"The drain current in mA is");
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EX12_2.sce
clc;funcprot(0);//EXAMPLE 12.2 // Initialisation of Variables n=6;...............//No of cylinders N=1500;............//Engine rpm BP=220;.............//Brake Power in kW bsfc=0.273;..........//Brake Specific Fuel Consumption in kg/kWh theta=30;.............//The Period of Injection in degrees of crank angle spgr=0.85;............//Specific Gravity of fuel Cf=0.9;................//Orifice discharge co-efficient ip=160;...............//Injection pressure in bar cp=40;.................//Pressure in combustion chamber in bar rhow=1000;................//Density of water in kg/m^3 //Calculations vf = Cf*sqrt((2*(ip-cp)*10^5)/(spgr*rhow));.............//Actual fuel velocity of injection in m/sec qf=(bsfc*BP)/(spgr*rhow*3600);..................// Volume of fuel injected per sec in m^3 d=sqrt (qf/((%pi/4)*n*vf*(theta/360)*(60/N)*(N/120)));...........//Diameter of nozzle orifice disp(d,"Diameter of Nozzle Orifice is (m):")
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FillAutomatic.tst
load Fill.hack, output-file FillAutomatic.out, compare-to FillAutomatic.cmp, output-list RAM[16384]%D2.6.2 RAM[17648]%D2.6.2 RAM[18349]%D2.6.2 RAM[19444]%D2.6.2 RAM[20771]%D2.6.2 RAM[21031]%D2.6.2 RAM[22596]%D2.6.2 RAM[23754]%D2.6.2 RAM[24575]%D2.6.2; set RAM[24576] 0, // the keyboard is untouched repeat 1000000 { ticktock; } output; // test that the screen is white set RAM[24576] 1, // a keyboard key is pressed repeat 1000000 { ticktock; } output; // test that the screen is black set RAM[24576] 0, // they keyboard in untouched repeat 1000000 { ticktock; } output; // test that the screen is white
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13_19.sce
clear clc Pm=2 Pi=1 H=6 G=1 f=50 p=Pi/Pm M=G*H/(%pi*f) d0=asin(p) dcc=acos(((p*(%pi - (2*d0)))- (Pi*cos(d0)))/(Pm-Pi)) mprintf("Critical Clearing angle = %.4f rad\n\n", dcc) tcc=sqrt(2*M*(dcc-d0)/Pi) mprintf("Critical Clearing time = %.3f sec = %.2f cycles", tcc , tcc*50)
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const TEST = 12;void proc1() { var x : int; void proc11() { var y : int; type t = newType; int proc111() { return y; } int proc112() { return ::proc111() + y; } y = ::proc111() + ::proc112(); } void proc12() { int proc121() { return TEST; } }}main() { ::proc1();}
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clc //Initialization of variables b=3 //m y=1 //m sf=0.005 n=0.028 gam=9.81*1000 Q=0.25 //m^3/s slope=1.5 //calculations A= 0.5 *b*y P=2*sqrt(1 + (slope)^2) R=A/P yx= Q*n/(slope * R^(2/3) *sf^(1/2)) y= yx^(3/8) //results printf("depth = %.2f m",y)
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//Problem 13.21: A d.c. source has an open-circuit voltage of 30 V and an internal resistance of 1.5 ohm. State the value of load resistance that gives maximum power dissipation and determine the value of this power. //initializing the variables: V = 30; // in volts r = 1.5; // in ohms //calculation: //current I = E/(r + RL) //For maximum power, RL = r RL = r I = V/(r + RL) //Power, P, dissipated in load RL, P P = RL*I^2 printf("\n\n Result \n\n") printf("\n (a) the value of the load resistor RL is %.1f ohm",RL) printf("\n (b) maximum power dissipation = %.0f W",P)
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// Chapter 5 additional Example 8 //============================================================================== clc; clear; // input data a = 4*10^-10; // lattice constant of the crystal h = 1 // miller indice k = 0 // miller indice l = 0 // miller indice //Calculations // in fig consider (100) plane. the no of atoms in plane ABCD N = 4*(1/4); // Number of atoms p = N/(a*a); // planar atomic density in atoms/m^2 p1 = p*10^-6 // planar atomic density in atoms/mm^2 //Output mprintf('planar atomic density = %3.2e atoms/mm^2',p1); //==============================================================================
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//Page Number: 288 //Example 5.1 clc; //Given f=10D+9; //Hz v=9D+3; //V i=40D-3; //A l=3; //cm l1=l/100; //m G=2D-6; //mho bet=0.92; j1x=0.582; x=1.841; ebym=1.7D+11; //J //Maximum voltage w=2*%pi*f; v0x=sqrt(2*ebym); thet=(w*l1)/(v0x*sqrt(v)); av=(bet^2*thet*i*j1x)/(x*v*G); disp('V',av,'Maximum voltage:'); //Power Gain ic=2*i*j1x; v2=(bet*ic)/G; pout=bet*ic*v2; pin=2*i*v; //Efficiency eet=pout/pin; disp('%',eet*100,'Power gain:'); //Answer for effciency comes out to be wrong, it is calculted wrongly in book
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n =5; Xbar = 9.5; uo = 8; var = 4; statistic = sqrt(n/var)*(Xbar - u); p = 1 - cdfnor("PQ", statistic, 0, 1); disp("The test would call for rejection at all significance levels greater than or equal to ") disp(p);
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//page 70 clc;funcprot(0);//EXAMPLE 3.11 // Initialisation of Variables E=12;......//No. of Edges in the octahedral sites of the unit cell S=1/4;.......//so only 1/4 of each site belongs uniquelyto each unit cell N=E*S+1;.....//No.of site belongs uniquely to each unit cell disp(N,"No.of octahedral site belongs uniquely to each unit cell:")
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//5.10 clc; V=415; P=20*10^3; disp('For Triacs') I_line=P/(3^0.5*V); Irms=I_line*1.5; printf("RMS current rating of each triac=%.2f A", Irms) Vrms=1.5*V; printf("\nRMS Voltage rating of each triac=%.2f V", Vrms) disp('For reverse connected thyristors') Irms_thy=1.5*I_line/2^0.5; printf("RMS current rating of each thyristor=%.2f A", Irms_thy) Vrms_thy=1.5*V; printf("\nRMS voltage rating of each thyristor=%.2f V", Vrms_thy)
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//ques-2.15 //Calculating volume of air supplied for fuel clc M=5;//Percentage of Methane in gaseous fuel H=20;//Percentage of Hydrogen in gaseous fuel CM=25;//Percentage of Carbon Monoxide in gaseous fuel CD=6;//Percentage of Carbon dioxide in gaseous fuel N=100-(M+H+CM+CD);//Percentage of Nitrogen in gaseous fuel e=20;//Percentage of excess air supplied v1=(M/100)*2;//Volume of oxygen required for methane (in kL) v2=(H/100)*0.5;//Volume of oxygen required for hydrogen (in kL) v3=(CM/100)*0.5;//Volume of oxygen required for carbon monoxide (in kL) v4=CD/100;//Volume of oxygen required for carbon dioxide (in kL) v5=N/100;//Volume of oxygen required for nitrogen (in kL) V=(v1+v2+v3)*(100/21);//Volume of air for gaseous fuel (in kL) V=V*(1+e/100);//Volume of air for gaseous fuel using excess (in kL) v6=M/100+CM/100+v4;//Final volume of carbon dioxide as dry product (in kL) v7=(e/100)*(v1+v2+v3);//Final volume of oxygen as dry product (in kL) v8=v5+V*(77/100);//Final volume of nitrogen as dry product (in kL) V_T=v6+v7+v8;//Total volume (in kL) P_C=(v6/V_T)*100;//Percentage of carbon dioxide as dry product P_O=(v7/V_T)*100;//Percentage of oxygen as dry product P_N=(v8/V_T)*100;//Percentage of nitrogen as dry product printf("The volume of air required for gaseous fuel is %.3f kL.\n",V); printf(" Percentage of carbon dioxide, oxygen and nitrogen as dry product are %.3f, %.3f and %.2f respectively.",P_C,P_O,P_N);
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clc; clear all; disp("incerease in bulk temperature") tb1=200;//degree C d=25.4/1000;//m diameter of tube U=10;//m/s tw=20;// degree C L=3;//m length of tube rho=1.493;//kg/m^3 mu=2.57*10^(-5);//Ns/m^2 k=0.0386;//W/m.C cp=1025;// J/kg.C Re=rho*U*d/mu Pr=mu*cp/k Nu=0.0023*Re^0.8*Pr^0.4 h=Nu*k/d Q=h*%pi*d*(tb1-tw) m=rho*%pi*d^2*U; delT=Q/(m*cp); disp("degree C",delT,"Increase in bulk temperature is = ")
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// Scilab code Ex5.14: Pg:225 (2008) clc;clear; n = 1; // First order diffraction N = 1000; // Number of lines on the grating Lambda = 6e-05; // Wavelength of light, cm // Let Lambda and d_Lambda be the two wavelengths in the first order spectrum. Since the resolving power of a grating is given by Lambda/d_Lambda = n*N. On solving for d_lambda, we have d_Lambda = Lambda/(n*N); // Difference between two wavelength in the first order spectrum, Angstorm printf("\nThe wavelength difference in the first order spectrum = %d angstrom", d_Lambda/1e-008); // Result // The wavelength difference in the first order spectrum = 6 angstrom
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getd('functions'); xdel(winsid()); clc; x = [-3 -1 0 1 3 4]; y = cos(x); // Lagrange x2 = linspace(min(x), max(x), 100); y2 = lagrange(x2, x, y); y3 = cos(x2); // Draw results a=get('current_axes'); a.data_bounds=[min(x)-1, min(y)-1; max(x)+1, max(y)+1]; title('Lagrange demonstration'); plot(x, y, '*r', x2, y3, x2, y2); legend(['cos(x) - nodes'; 'cos(x)'; 'lagrange(x)']);
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function I = RS2(a,b,n) h = (a-b)/n; x = a:h:b; y = f(x); I = y(1); for i = 2:n if modulo(i,3) == 1 I = I + 2*y(i); else I = I + 3*y(i); end end I = (3*h/8)*(I + y(n+1)); endfunction
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//To find resistance Rs and Rsh in the given ciruit // example 3-10 in page 55 clc; //data given Iav=50e-6;//average current through PMCC instrument=50 micro ampere Rm=1700;// coil resistance in ohm Vf=0.7;// diode forward drop in volts If=100e-6;// forward current = 100 micro-ampere Vrms=50;// ac rms voltage in volts // calculation Im=Iav/(0.5*0.637);//peak current in ampere Ifp=(100/20)*If;//at 20% of FSD, diode peak current(If) must be at least 100 micro ampere; therefore, at 100% of FSD, Ishp=Ifp-Im;// peak current through Rsh in ampere Vm=Im*Rm;// peak voltage in volts Rsh=Vm/Ishp; Rs=(1.414*Vrms-Vm-Vf)/Ifp; printf("Rsh=%d ohm\n",Rsh); printf("Rs=%.1f K-ohm\n",Rs/1000); //result //Rsh=778 ohm //Rs=139.5 K-ohm
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clc; //page no 628 //prob no. 17.5 //determination of characteristic impedance of waveguide with given 5GHz freq f=5*10^9;fc=3.75*10^9;//Refering in eg. 17.4 Zo=377/sqrt(1-(fc/f)^2); disp('ohm',Zo,'The characteristic impedance of waveguide is');
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//Chapter-15, Example 15.6, Page 497 //============================================================================= clc clear //CALCULATIONS x1=base2dec(['110','10'],2)//converting binary to decimal x2=base2dec(['1111','110'],2)//converting binary to decimal y1=(x1(1))/(x1(2));//dividing y2=(x2(1))/(x2(2));//dividing z1=dec2base(y1,2);//converting decimal to binary [f,e]=frexp(y2);//separting exponent and mantissa disp(f)//mantissa disp(e)//exponent f=f*2; g=floor(f);//rounding to nearest integer disp(g); z2=dec2base(e,2);//converting decimal to binary--------->before point part of resultant binary number disp(z2) g1=dec2base(g,2);//converting decimal to binary--------->after point part of resultant binary number disp(g1) //NOTE:here floating point decimal cannot be directly converted to binary for second case.Hence computed to binary //=================================END OF PROGRAM=======================================================================================================
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//Chapter 4 //Example 4_7 //Page 77 clear;clc; pc=50; lf=0.4; p=12*1e6; tax=400000; other_cost=0.01; interest=0.05; dep=0.06; md=pc; printf("Annual fixed charges\n"); i_and_d=p*(interest+dep); afc=i_and_d+tax; printf("Interest and depreciation = Rs. %.0f \n", i_and_d); printf("Wages and taxation = Rs. %.0f \n", tax); printf("Total annual fixed charges = Rs. %.0f \n\n", afc); printf("Annual running charges\n"); ugpa=md*lf*8760*1000; cost=other_cost*ugpa; tac=cost+afc; cpkWh=tac/ugpa; printf("Units generated per annum = %.0f kWh \n", ugpa); printf("Cost of fuel and lubrication = Rs. %.0f \n", cost); printf("Total annual charges = Rs. %.0f \n", tac); printf("Cost per kWh = Rs. %.4f \n\n", cpkWh);
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// Example 20.4, page no-570 clear clc tc1=4.185 m1=199.5 m2=203.4 tc2=tc1* sqrt(m1/m2) printf("The critical temperature for metal with isotopic mass of %.1f is %.3f K",m2,tc2)
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clear; clc; close; Idss = 9*10^(-3); Vp = -3; Vdd = 20; Vss = 10; Rd = 1.8*10^(3); Rs = 1.5*10^(3); Vgs1 = Vp; Id1 = 0; Vgs2 = Vp/2; Id2 = Idss/4; Vgs3 = 0; Id3 = Idss; x = [Vgs1 Vgs2 Vgs3]; y = [Id1 Id2 Id3]; yi=smooth([x;y],0.1); a = gca(); a.thickness = 2; a.y_location = 'right'; a.x_label.text = 'Vgs'; a.y_label.text = 'Id(mA)'; a.title.text = 'Q-point for network'; a.grid = [1 1]; plot2d(yi(1,:)',yi(2,:)',[3]); Id1 = 0; Vgs1 = Vss-Id1*Rs; Id2 = 4*10^(-3); Vgs2 = Vss-Id2*Rs; Id3 = 8*10^(-3); Vgs3 = Vss-Id3*Rs; x = [Vgs1 Vgs2 Vgs3]; y = [Id1 Id2 Id3]; plot2d(x,y); a.data_bounds = [-3 0;10 9*10^(-3)]; Vgsq = -0.35; disp(Vgsq,'Q-point value of Vgs(found after interpolation) is :'); Idq = 6.9*10^(-3); Vds = Vdd+Vss-Idq*(Rd+Rs); Vd = Vdd-Idq*Rd; Vs = Vd-Vds; disp(Idq,'Idq(Amperes) = '); disp(Vds,'Vds(Volts) = '); disp(Vd,'Vd(Volts) = '); disp(Vs,'Vs(Volts) = '); disp(Vds,'Vds(Volts) = ');
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Ex3_2.sce
//Initilization of variables F=1000 //N Lab=1 //m Lbc=0.25 //m Lac=1.25 //m //Calculations Rb=(F*Lac)/Lab //N // from eq'n 2 Ra=Rb-F //N // fom eq'n 1 //Results clc printf('The reaction (downwards)at support A is %f N \n',Ra) printf('The reaction (upwards)at support B is %f N \n',Rb)
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Ex3_7.sce
//Example 3_7 clc(); clear; //To calculate the time taken to travel v0=16.7 //units in meters/sec a=1.5 //units in meters/sec^2 x=70 //units in meters t=-((-v0)+sqrt(v0^2-(4*(a/2)*x)))/(2*(a/2)) //units in sec printf("Time taken to travel T=%.1f sec",t)
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Ex5_5.sce
//Example 5.5// x=1*10^-3;//m// Using the diffusivity from sample problem 5.3 D=2.98*10^-11;//m^2/s //arrhenius equations a=0.95;//from the figure 5.11 d=(x^2)/((a^2)*(D))// calculating the value of d mprintf("d = %e h",d) b=1;//h //hour c=3.6*10^3;//s //second t=d*(b/c) mprintf("\nt = %f h",t)
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-- VectorCAST 6.4c (02/03/16) -- Test Case Script -- -- Environment : LIBC -- Unit(s) Under Test: abort1 abs atof atoi atol bLib memchr memcmp memcpy memmove memset ns16550 qsort rand random random_r strcat strchr strcmp strcpy strlcat strlcpy strlen strncat strncmp strncpy strpbrk strspn strtod strtok strtok_r strtol strtoul -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIPT_FEATURE:STATIC_HEADER_FUNCS_IN_UUTS -- -- Unit: strtod -- Subprogram: is_real -- Test Case: real1 TEST.UNIT:strtod TEST.SUBPROGRAM:is_real TEST.NEW TEST.NAME:real1 TEST.BASIS_PATH:1 of 1 TEST.NOTES: No branches in subprogram TEST.END_NOTES: TEST.VALUE:strtod.is_real.x:<<MIN>> TEST.EXPECTED:strtod.is_real.return:0 TEST.END -- Test Case: real2 TEST.UNIT:strtod TEST.SUBPROGRAM:is_real TEST.NEW TEST.NAME:real2 TEST.NOTES: No branches in subprogram TEST.END_NOTES: TEST.VALUE:strtod.is_real.x:<<MAX>> TEST.EXPECTED:strtod.is_real.return:0 TEST.END -- Test Case: real3 TEST.UNIT:strtod TEST.SUBPROGRAM:is_real TEST.NEW TEST.NAME:real3 TEST.NOTES: No branches in subprogram TEST.END_NOTES: TEST.VALUE:strtod.is_real.x:0.0 TEST.EXPECTED:strtod.is_real.return:1 TEST.END -- Test Case: real4 TEST.UNIT:strtod TEST.SUBPROGRAM:is_real TEST.NEW TEST.NAME:real4 TEST.NOTES: No branches in subprogram TEST.END_NOTES: TEST.VALUE:strtod.is_real.x:-112.345234 TEST.EXPECTED:strtod.is_real.return:1 TEST.END -- Test Case: real5 TEST.UNIT:strtod TEST.SUBPROGRAM:is_real TEST.NEW TEST.NAME:real5 TEST.NOTES: No branches in subprogram TEST.END_NOTES: TEST.VALUE:strtod.is_real.x:112.345234 TEST.EXPECTED:strtod.is_real.return:1 TEST.END -- Subprogram: strtod -- Test Case: strtod TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod TEST.BASIS_PATH:1 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 1 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod10 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod10 TEST.BASIS_PATH:10 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 10 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> TRUE (11) case (*(++p)) ==> 43 (14) if (exponent < -1021 || exponent > 1024) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set switch condition (*(++p)) in branch 11 Cannot set p due to assignment Cannot set local variable p in branch 12 Cannot set negative due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 9>> TEST.VALUE:strtod.strtod.str:"-1234.56" TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:-1234.56 TEST.END -- Test Case: strtod11 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod11 TEST.BASIS_PATH:11 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 11 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> TRUE (11) case (*(++p)) ==> 43 (13) if negative ==> TRUE (14) if (exponent < -1021 || exponent > 1024) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set switch condition (*(++p)) in branch 11 Cannot set p due to assignment Cannot set local variable p in branch 12 Cannot set negative due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 14>> TEST.VALUE:strtod.strtod.str:"12345.67afdsf" TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:12345.7 TEST.END -- Test Case: strtod12 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod12 TEST.BASIS_PATH:12 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 12 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> TRUE (11) case (*(++p)) ==> 43 (12) while (*p >= 48 && *p <= 57) ==> TRUE (14) if (exponent < -1021 || exponent > 1024) ==> TRUE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set switch condition (*(++p)) in branch 11 Cannot set local variable p in branch 12 Cannot set negative due to assignment Conflict: Cannot resolve multiple comparisons ( ) in branches 8/12 Cannot set local variable p in branch 13 Cannot set negative due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 13>> TEST.VALUE:strtod.strtod.str:"-123.34abced" TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.endptr[0]:"abced" TEST.EXPECTED:strtod.strtod.return:-123.34 TEST.END -- Test Case: strtod13 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod13 TEST.BASIS_PATH:13 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 13 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> TRUE (10) case (*(++p)) ==> 45 (14) if (exponent < -1021 || exponent > 1024) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set switch condition (*(++p)) in branch 10 Cannot set p due to assignment Cannot set local variable p in branch 12 Cannot set negative due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 11>> TEST.VALUE:strtod.strtod.str:"-123.34e+4" TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:-1233400.0 TEST.END -- Test Case: strtod14 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod14 TEST.BASIS_PATH:14 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 14 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> TRUE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:0 TEST.VALUE:strtod.strtod.str:<<malloc 7>> TEST.VALUE:strtod.strtod.str:"-10e-1" TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:-1.0 TEST.END -- Test Case: strtod15 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod15 TEST.BASIS_PATH:15 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 15 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> TRUE (7) if (num_digits == 0) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set p due to assignment Cannot set local variable p in branch 6 Cannot set num_digits due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 8>> TEST.VALUE:strtod.strtod.str:"1e+1025" TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:1.7E308 TEST.END -- Test Case: strtod16 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod16 TEST.BASIS_PATH:16 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 16 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> TRUE (6) while (*p >= 48 && *p <= 57) ==> TRUE (7) if (num_digits == 0) ==> TRUE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set local variable p in branch 5 Cannot set local variable p in branch 6 Cannot set p due to assignment Conflict: Cannot resolve multiple comparisons ( ) in branches 5/6 Cannot set local variable p in branch 7 Cannot set num_digits due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 10>> TEST.VALUE:strtod.strtod.str:"1.5e-1022" TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:1.7E308 TEST.END -- Test Case: strtod2 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod2 TEST.BASIS_PATH:2 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 2 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> TRUE Test Case Generation Notes: Cannot set p due to assignment Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment TEST.END_NOTES: TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod3 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod3 TEST.BASIS_PATH:3 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 3 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> FALSE (16) while n ==> FALSE (19) if (!is_real(number)) ==> FALSE (20) if endptr ==> FALSE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:<<MIN>> TEST.VALUE:strtod.strtod.str:<<malloc 2>> TEST.VALUE:strtod.strtod.str:" " TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod4 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod4 TEST.BASIS_PATH:4 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 4 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> FALSE (16) while n ==> FALSE (19) if (!is_real(number)) ==> FALSE (20) if endptr ==> TRUE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:<<MIN>> TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<malloc 1>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod5 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod5 TEST.BASIS_PATH:5 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 5 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> FALSE (16) while n ==> FALSE (19) if (!is_real(number)) ==> TRUE (20) if endptr ==> FALSE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:0 TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.END -- Test Case: strtod6 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod6 TEST.BASIS_PATH:6 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 6 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> FALSE (16) while n ==> TRUE (17) if (n & 1) ==> FALSE (19) if (!is_real(number)) ==> FALSE (20) if endptr ==> FALSE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set exponent due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:<<MIN>> TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod7 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod7 TEST.BASIS_PATH:7 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 7 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> FALSE (16) while n ==> TRUE (17) if (n & 1) ==> TRUE (18) if (exponent < 0) ==> FALSE (19) if (!is_real(number)) ==> FALSE (20) if endptr ==> FALSE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set exponent due to assignment Cannot set exponent due to assignment Cannot set exponent due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:<<MIN>> TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod8 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod8 TEST.BASIS_PATH:8 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 8 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> FALSE (16) while n ==> TRUE (17) if (n & 1) ==> TRUE (18) if (exponent < 0) ==> TRUE (19) if (!is_real(number)) ==> FALSE (20) if endptr ==> FALSE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set exponent due to assignment Cannot set exponent due to assignment Cannot set exponent due to assignment Cannot set p10 due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:<<MIN>> TEST.VALUE:strtod.strtod.str:<<malloc 1>> TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:0.0 TEST.END -- Test Case: strtod9 TEST.UNIT:strtod TEST.SUBPROGRAM:strtod TEST.NEW TEST.NAME:strtod9 TEST.BASIS_PATH:9 of 19 TEST.NOTES: This is an automatically generated test case. Test Path 9 (1) while (((((*p == 32 || *p == 9) || *p == 10) || *p == 13) || *p == 12) || *p == 11) ==> FALSE (3) case (*p) ==> 43 (4) while (*p >= 48 && *p <= 57) ==> FALSE (5) if (*p == 46) ==> FALSE (7) if (num_digits == 0) ==> FALSE (8) if negative ==> FALSE (9) if (*p == 101 || *p == 69) ==> FALSE (14) if (exponent < -1021 || exponent > 1024) ==> FALSE (15) if (n < 0) ==> TRUE (16) while n ==> FALSE (19) if (!is_real(number)) ==> FALSE (20) if endptr ==> FALSE Test Case Generation Notes: Cannot set local variable p in branch 4 Cannot set p due to assignment Cannot set local variable p in branch 5 Cannot set num_digits due to assignment Cannot set negative due to assignment Cannot set p due to assignment Cannot set local variable p in branch 9 Cannot set exponent due to assignment Cannot set n due to assignment TEST.END_NOTES: TEST.STUB:strtod.is_real TEST.VALUE:strtod.is_real.return:<<MIN>> TEST.VALUE:strtod.strtod.str:<<malloc 14>> TEST.VALUE:strtod.strtod.str:" 12345.6789" TEST.VALUE:strtod.strtod.endptr:<<null>> TEST.EXPECTED:strtod.strtod.return:12345.7 TEST.END
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute F6 real[-1.537,1.403] @attribute F7 real[-1.293,2.039] @attribute F8 real[-1.613,1.309] @attribute F9 real[-1.68,1.396] @attribute Class{0,1,2,3,4,5,6,7,8,9,10} @inputs TT,SpeakerNumber,Sex,F0,F1,F2,F3,F4,F5,F6,F7,F8,F9 @outputs Class @data 1 1 7 7 5 7 10 0 6 7 9 9 6 6 0 0 5 3 8 7 4 3 3 3 5 3 0 0 9 9 10 3 5 3 10 2 6 6 1 1 4 4 5 4 10 1 3 3 0 0 8 8 6 6 8 7 3 3 0 0 7 7 3 3 4 4 4 4 7 7 3 3 4 4 10 3 6 7 1 1 2 3 10 10 1 1 1 9 5 8 7 7 9 9 2 0 9 9 6 7 7 7 3 2 5 3 8 7 1 0 3 3 7 7 4 3 7 7 8 8 2 2 4 3 2 2 7 7 9 9 4 6 9 9 8 8 2 2 2 2 10 8 0 0 9 9 10 10 7 8 5 3 6 6 1 1 3 3 10 3 0 0 8 7 6 6 6 6 0 9 3 3 4 6 9 0 1 1 9 0 8 1 5 6 0 0 2 2 2 3 0 0 1 0 2 3 8 8
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/905/CH2/EX2.8/2_8.sce
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FOSSEE/Scilab-TBC-Uploads
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clear; clc; // Illustration 2.8 // Page: 120 printf('Illustration 2.8 - Page: 120\n\n'); // solution //*****Data*****// // a-liquid benzene b-nitrogen T = 300; // [K] l = 3; // [length of vertical plate, m] b = 1.5; // [width of vertical plate, m] P = 101.3; // [kPa] v = 5; // [velocity across the width of plate, m/s] row_a = 0.88; // [gram/cubic cm] //*****// y_a1 = 0.139; // [mole fraction of benzene at inner edge] y_a2 = 0; // The film conditions, and average properties, are identical to those in Example 2.7, only the geometry is different // Therefore M_avg = 31.4; // [kg/kmole] row = 1.2; // [kg/cubic m] u = 161*10^-7; // [kg/m.s] D_ab = 0.0986; // [square cm/s] Sc = 1.3; // [Schmidt Number] Re = row*v*b/u; // [Renoylds Number] if(Re>4000) printf('The flow across the plate is turbulent\n\n'); else(Re<2000) printf('The flow across the plate is laminar\n\n'); end // Using equation 2.57 Sh_l = 0.036*Re^0.8*Sc^(1/3); // Nitrogen (component B) does not react with benzene (component A), neither dissolves in the liquid; therefore, NB = 0 and siA = 1. The F-form of the mass-transfer coefficient should be used F = Sh_l*1.26*D_ab*10^-4/(M_avg*b); // [kmole/square m.s] N_a = F*log((1-y_a2)/(1-y_a1)); // [kmole/square m.s] // The total mass rate of evaporation over the surface of the plate S = 1.5*3; // [square m] M_a = 78.1; // [gram/mole] wa = N_a*S*M_a*60*1000; // [gram/min] V = wa/row_a; // [volumetric flow rate, ml/min] printf("Liquid benzene should be supplied at the top of the plate at the rate %f ml/min so that evaporation will just prevent it from reaching the bottom of the plate.\n\n",V);
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/Positive_Negative_test/Netezza-Base-DateFunctions/FLDateDiff-NZ-01.tst
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kamleshm/intern_fuzzy
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2021-01-23T06:25:46.162332
2017-07-12T07:12:25
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FLDateDiff-NZ-01.tst
-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -- and may be covered by U.S. and Foreign Patents, patents in process, and are protected by trade -- secret or copyright law. Dissemination of this information or reproduction of this material is -- strictly forbidden unless prior written permission is obtained from Fuzzy Logix, LLC. -- Functional Test Specifications: -- -- Test Category: Date Functions -- -- Test Unit Number: FLDateDiff-Netezza-01 -- -- Name(s): FLDateDiff -- -- Description: Scalar function which calculates the difference between 2 DATE variables -- -- Applications: -- -- Signature: FLDateDiff(pDatePartInd VARCHAR, pStartDate DATE, pEndDate DATE) -- -- Parameters: See Documentation -- -- Return value: INTEGER -- -- Last Updated: 11-24-2014 -- -- Author: Surya Deepak Garimella -- -- BEGIN: TEST SCRIPT --.run file=../PulsarLogOn.sql --.set width 2500 --set session dateform = ANSIDATE; --SELECT COUNT(*) AS CNT, -- CASE WHEN CNT = 0 THEN ' Please Load Test Data!!! ' ELSE ' Test Data Loaded ' END AS TestOutcome --FROM tblTestDate a; -- BEGIN: POSITIVE TEST(s) ---- Positive Test 1: Manual Example --- Same Output, Good SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('yy',a.DateIN1, a.DateIN2) AS DateDiffYear, FLDateDiff('qq',a.DateIN1, a.DateIN2) AS DateDiffQuarter, FLDateDiff('mm',a.DateIN1, a.DateIN2) AS DateDiffMonth, FLDateDiff('dd',a.DateIN1, a.DateIN2) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('wk',a.DateIN1, a.DateIN2) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; ---- Positive Test 2: Test for alternative DatePartInd Argument Input -------- P3a SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('yyyy',a.DateIN1, a.DateIN2) AS DateDiffYear, FLDateDiff('q',a.DateIN1, a.DateIN2) AS DateDiffQuarter, FLDateDiff('m',a.DateIN1, a.DateIN2) AS DateDiffMonth, FLDateDiff('d',a.DateIN1, a.DateIN2) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('ww',a.DateIN1, a.DateIN2) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; --------- P2b SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('year',a.DateIN1, a.DateIN2) AS DateDiffYear, FLDateDiff('quarter',a.DateIN1, a.DateIN2) AS DateDiffQuarter, FLDateDiff('month',a.DateIN1, a.DateIN2) AS DateDiffMonth, FLDateDiff('day',a.DateIN1, a.DateIN2) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('week',a.DateIN1, a.DateIN2) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; ---- Positive Test 3: Test for Lower bound of Start Date SELECT a.ObsID, DATE '0001-01-01' AS DateINLower, a.DateIN2, FLDateDiff('yy', DateINLower, a.DateIN2) AS DateDiffYear, FLDateDiff('qq', DateINLower, a.DateIN2) AS DateDiffQuarter, FLDateDiff('mm', DateINLower, a.DateIN2) AS DateDiffMonth, FLDateDiff('dd', DateINLower, a.DateIN2) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, DATE '0001-01-01' AS DateINLower, a.DateIN2, FLDateDiff('wk', DateINLower, a.DateIN2) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; ---- Positive Test 4: Test for Upper bound of Start Date SELECT a.ObsID, DATE '9999-12-31' AS DateINUpper, a.DateIN2, FLDateDiff('yy', DateINUpper, a.DateIN2) AS DateDiffYear, FLDateDiff('qq', DateINUpper, a.DateIN2) AS DateDiffQuarter, FLDateDiff('mm', DateINUpper, a.DateIN2) AS DateDiffMonth, FLDateDiff('dd', DateINUpper, a.DateIN2) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, DATE '9999-12-31' AS DateINUpper, a.DateIN2, FLDateDiff('wk', DateINUpper, a.DateIN2) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; ---- Positive Test 5: Test for Lower bound of End Date SELECT a.ObsID, DateIN1, DATE '0001-01-01' AS DateINLower, FLDateDiff('yy', a.DateIN1, DateINLower) AS DateDiffYear, FLDateDiff('qq', a.DateIN1, DateINLower) AS DateDiffQuarter, FLDateDiff('mm', a.DateIN1, DateINLower) AS DateDiffMonth, FLDateDiff('dd', a.DateIN1, DateINLower) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, DateIN1, DATE '0001-01-01' AS DateINLower, FLDateDiff('wk', a.DateIN1, DateINLower) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; ---- Positive Test 6: Test for Upper bound of End Date SELECT a.ObsID, DateIN1, DATE '9999-12-31' AS DateINUpper, FLDateDiff('yy', a.DateIN1, DateINUpper) AS DateDiffYear, FLDateDiff('qq', a.DateIN1, DateINUpper) AS DateDiffQuarter, FLDateDiff('mm', a.DateIN1, DateINUpper) AS DateDiffMonth, FLDateDiff('dd', a.DateIN1, DateINUpper) AS DateDiffDay FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, DateIN1, DATE '9999-12-31' AS DateINUpper, FLDateDiff('wk', a.DateIN1, DateINUpper) AS DateDiffWeek FROM tblTestDate a ORDER BY 1; -- END: POSITIVE TEST(s) -- BEGIN: NEGATIVE TEST(s) ---- Negative Test 1: Invalid Input For Date Part Indicator --- Return expected error msg, Good SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('gg',a.DateIN1, a.DateIN2) AS DateDiffYear FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff(NULL,a.DateIN1, a.DateIN2) AS DateDiffYear FROM tblTestDate a ORDER BY 1; ---- Negative Test 2: Invalid Date Input --- Return expected error msg, Good SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('yy',NULL, a.DateIN2) AS DateDiffYear FROM tblTestDate a ORDER BY 1; SELECT a.ObsID, a.DateIN1, a.DateIN2, FLDateDiff('yy',a.DateIN1, NULL) AS DateDiffYear FROM tblTestDate a ORDER BY 1; SELECT FLDateDiff('yy','2010', '2009') AS DateDiffYear; -- END: NEGATIVE TEST(s) -- END: TEST SCRIPT
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clear; clc; printf("\t\t\tExample Number 10.1\n\n\n"); // overall heat transfer coefficient for pipe in air // Example 10.1 (page no.-520-522) // solution Tw = 98;// [degree celsius] temperature of hot water k_p = 54;// [W/m degree celsius] heat transfer coefficient of pipe Ta = 20;// [degree celsius] atmospheric air temperature u = 0.25;// [m/s] water velocity // from appendix A the dimensions of 2-in schedule 40 pipe are ID = 0.0525;// [m] OD = 0.06033;// [m] // the properties of water at 98 degree celsius are rho = 960;// [kg/cubic meter] mu = 2.82*10^(-4);// [kg/m s] k_w = 0.68;// [W/m degree celsius] Pr = 1.76;// prandtl number // the reynolds number is Re = rho*u*ID/mu; // and since turbulent flow is encountered, we may use equation(6-4): Nu = 0.023*Re^(0.8)*Pr^(0.4); hi = Nu*k_w/ID;// [W/square meter degree celsius] // for unit length of pipe the thermal resistance of the steel is Rs = log(OD/ID)/(2*%pi*k_p); // again, on a unit length basis the thermal resistance on the inside is Ai = %pi*ID;// [square meter] Ri = 1/(hi*Ai); Ao = %pi*OD;// [square meter] // the thermal resistance for outer surface is as yet unknown but is written, for unit lengths, is Ro = 1/(ho*Ao) (a) // from table 7-2(page no.-339), for laminar flow, the simplified relation for ho is // ho = 1.32*(dT/d)^(1/4) = 1.32*((To-Ta)/OD)^(1/4) (b) // where To is the unknown outside pipe surface temperature. we designate the inner pipe surface as Ti and the water temperature as Tw; then the energy balance requires // (Tw-Ti)/Ri = (Ti-To)/Rs = (To-Ta)/Ro (c) // combining equations (a) and (b) gives // (To-Ta)/Ro = %pi*OD*1.32*(To-Ta)^(5/4)/OD^(1/4) // this relation may be introduced into equation (c) to yield two equations with the two unknowns Ti and To: // (Tw-Ti)/Ri = (Ti-To)/Rs (1) // (Ti-To)/Rs = %pi*OD*1.32*(To-Ta)^(5/4)/OD^(1/4) (2) // this is a non-linear equation which can be solved as for Ti = 50:0.001:100 Q = ((Ti-(Ti-(Tw-Ti)*(Rs/Ri)))/Rs)-(%pi*OD*1.32*((Ti-(Tw-Ti)*(Rs/Ri))-Ta)^(5/4)/OD^(1/4)); if Q>0 & Q<6 then Tinew = Ti; else Ti = Ti; end end Ti = Tinew;// [degree celsius] To = (Ti-(Tw-Ti)*(Rs/Ri));// [Degree celsius] // as a result, the outside heat transfer coefficient and thermal resistance are ho = 1.32*((To-Ta)/OD)^(1/4);// [W/square meter degree celsius] Ro = 1/(OD*7.91*%pi);// // the overall heat transfer coefficient based on the outer area is written in terms of these resistances as Uo = 1/(Ao*(Ri+Ro+Rs));// [W/area degree celsius] // in this calculation we used the outside area for 1.0 m length as Ao // so Uo = Uo;// [W/square meter degree celsius] printf("overall heat transfer coefficient is %f W/square meter degree celsius",Uo);
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//ex2.14 find the power delivered to the load and the peak voltage at the load-end of the line ZL=50; Z0=50+%i*50; Tl=(ZL-Z0)/(ZL+Z0); VSWR=(1+abs(Tl))/(1-abs(Tl)); disp('VSWR = '+string(VSWR)); vmax=50; PL=0.5*vmax^2/(VSWR*real(Z0)); RL=50; VL=sqrt(PL*RL*2); disp('Peak voltage at the load = '+string(VL)+' V','Power delivered to the load = '+string(PL)+' W');
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Ex13_5.sce
clear; clc; l = 20;//feet W = 500;// lb per foot run c = 750;// lb/in^2 t = 18000;// lb/in^2 m = 15; BM_max = W*l*l*12/8 ;// lb-inches //by making the effective deapth d twice the width b d = (BM_max/(126*0.5))^(1/3);//inches b = 0.5*d;//inches //necessary reinforcement is 0.8% of concrete section A_t = 0.008*b*d;// in^2 printf('d = %.2f inches\n b = %.2f inches',d,b); printf('\n A_t = %.3f in^2',A_t);
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jangwoopark/presentation-language
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# fluencyB TR=3 62 reps 186seconds 5cycles 2 disdaqs #onsets: naming 0 12 24 36 48 lines 6 18 30 42 54 #durations: 6 on, 6 off high pass= 72 scenario = "category fluency form B"; scenario_type = fMRI_emulation; pulses_per_scan = 36; scan_period=3000; #scenario_type = fMRI; pulse_code=10; sequence_interrupt=false; #active_buttons = 4; #button_codes=1,2,3,4; default_deltat = 0; default_picture_duration = 9000; default_font="times"; default_font_size=60; default_text_color=0,0,90; default_background_color=80,240,40; begin; #defining the stimuli picture {} default; #blank screen picture {text {caption = "Instruments" ;};x=0; y=0; }instruments; picture {text {caption = "Tools" ;};x=0; y=0; }tools; picture {text {caption = "Furniture" ;};x=0; y=0; }furniture; picture {text {caption = "Colors" ;};x=0; y=0; }colors; picture {text {caption = "TV shows" ;};x=0; y=0; }TV; picture {text {caption = "Clothes" ;};x=0; y=0; }clothes; picture {text {caption = "Jobs" ;};x=0; y=0; }jobs; picture {text {caption = "Famous people" ;};x=0; y=0; }famous; picture {text {caption = "Foods" ;};x=0; y=0; }food; picture {text {caption = "Drinks" ;};x=0; y=0; }drinks; picture {text {caption = "RELAX" ;};x=0; y=0; }relax; picture {text {caption = "think of words in the category ..." ;}; x=0; y=0; } inst; #presenting the stimuli trial { picture inst; mri_pulse=1; time=0; duration=6000; picture drinks; mri_pulse=3; picture famous; mri_pulse=6; picture relax; mri_pulse=9; duration = 18000; picture jobs; mri_pulse=15; picture TV; mri_pulse=18; picture relax; mri_pulse=21; duration = 18000; picture food; mri_pulse=27; picture colors; mri_pulse=30; picture relax; mri_pulse=33; duration = 18000; picture instruments; mri_pulse=39; picture tools; mri_pulse=42; picture relax; mri_pulse=45; duration = 18000; picture furniture; mri_pulse=51; picture clothes; mri_pulse=54; picture relax; mri_pulse=57; duration = 18000; };
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//Surface tension of water(in mN/m): STw=72.8*10^-3; //Surface Tension of mercury(in mN/m): STm=375*10^-3; //Contact angle for water: thetaw=0; //COntact angle for mercury: thetam=140; //Density of water(in kg/m^3): dw=1; //Density of mercury(in kg/m^3): dm=13.6; //Acceleration de to gravity(in m/sec): g=9.81;
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clear clc disp('Exa-2.16'); K=325; mkc2=498; //kinetic energy and rest mass energy of kaons mpic=140; //given value Ek=K+mkc2; pkc=sqrt(Ek^2-mkc2^2); //consider the law of conservation of energy which yields Ek=sqrt(p1c^2+mpic^2)+sqrt(p2c^2+mpic^2) // The above equations (4th degree,hence no direct methods)can be solved by assuming the value of p2c=0. p1c=sqrt(Ek^2-(2*mpic*Ek)); //consider the law of conservation of momentum. which gives p1c+p2c=pkc implies p2c=pkc-p1c; k1=(sqrt(p1c^2+(mpic^2))-mpic); //corresponding kinetic energies k2=(sqrt((p2c^2)+(mpic^2))-mpic); printf('The corresponding kinetic energies of the pions are %.0f MeV and %.1f MeV.',k1,k2);
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2023-05-31T04:06:22.931111
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clear;lines(0); P=rand(4,4);P=P*P'; Q=rand(4,4);Q=Q*Q'; T=equil(P,Q) clean(T*P*T') clean(inv(T)'*Q*inv(T))