row_id
int64 0
48.4k
| init_message
stringlengths 1
342k
| conversation_hash
stringlengths 32
32
| scores
dict |
|---|---|---|---|
30,113
|
how to add in blazor page with message and to be aligned right horizontally and center verticaly
|
ac78aaf706308cd21039c6933bdd7e98
|
{
"intermediate": 0.377434641122818,
"beginner": 0.27291926741600037,
"expert": 0.34964612126350403
}
|
30,114
|
import csv
# Opening the CSV file
with open('staff_dir.csv') as file:
# Creating a CSV reader object
reader = csv.reader(file)
# Reading the CSV data into a list of rows
sd = list ('staff_dir.csv')
# Delete the spaces and replace single space
sd = [[cell.strip().replace(" ", " ") for cell in row] for row in sd]
# Set the title for the data
header = [cell.upper() for cell in sd[0]]
sd[0] = header
for i in range(1, len(sd)):
sd[i][0] = sd[i][0].upper()
sd[i][-1] = sd[i][-1].title()
sd[i][2] = sd[i][2].lower()
sd[10][-1] = 'Location'
# Checking for duplications in the data
duplicates = [row for i, row in enumerate(sd) if row in sd[:i]]
if duplicates:
print(" Duplicated rows found at row numbers:")
else:
print(" no duplicated rows found")
# Removing duplicate rows
sd = [row for i, row in enumerate(sd) if row not in sd[:i]]
'staff_dir.csv'
please help me to correct it
|
827ada4ff64986bca67379cb5a5206b9
|
{
"intermediate": 0.42821550369262695,
"beginner": 0.31903693079948425,
"expert": 0.2527475953102112
}
|
30,115
|
According to tensorflow website “TensorFlow 2.10 was the last TensorFlow release that supported GPU on native-Windows. Starting with TensorFlow 2.11, you will need to install TensorFlow in WSL2”, please explain what is mean by this and also provide steps for doing so as explained by the website
|
2e44237831d4afe5f2a76f4512067e00
|
{
"intermediate": 0.25557735562324524,
"beginner": 0.09943068772554398,
"expert": 0.6449919939041138
}
|
30,116
|
CondaSSLError: OpenSSL appears to be unavailable on this machine. OpenSSL is required to download and install packages.
|
3d9f53e1f61fe5331a160c81dc380b1b
|
{
"intermediate": 0.3841208517551422,
"beginner": 0.3025279939174652,
"expert": 0.3133511245250702
}
|
30,117
|
how to disable scrollbar for react calendly widget?
|
d0aa9b68648a2b7b92b2baf49ffcbb81
|
{
"intermediate": 0.49471428990364075,
"beginner": 0.22826388478279114,
"expert": 0.2770218253135681
}
|
30,118
|
I have 9 groups of four letters. Write code so that I can see words of 5 letters or more made with a maximum of one letter from each of the 9 groups.
|
2832bf1d3627f2a9531df52d2779bc42
|
{
"intermediate": 0.3665164113044739,
"beginner": 0.2195541262626648,
"expert": 0.41392940282821655
}
|
30,119
|
https://my.informatics.ru/api/v1/manuals/material_files/1669944/download/ сделай сайт как на картинке , на html
|
ca40de46fff03ad3c987d05d14ca115e
|
{
"intermediate": 0.2861320674419403,
"beginner": 0.28737661242485046,
"expert": 0.42649129033088684
}
|
30,120
|
How to find module imagebase and module name by address in pintools program
|
44691b3d3fe3adbf10e07d1b57b47651
|
{
"intermediate": 0.5994617342948914,
"beginner": 0.11907181888818741,
"expert": 0.28146645426750183
}
|
30,121
|
passiveTab('appServicesLi', 'appServices');
} write this in jquery
|
a7602c3da79e398334aeb06b8e55a6ff
|
{
"intermediate": 0.43622079491615295,
"beginner": 0.3926234245300293,
"expert": 0.17115579545497894
}
|
30,122
|
Show me the application on React TypeScript - a plan for distributing ammunition in an airborne battalion. With code, comments and styles.
|
3e90004abed67a76ccf930c5568a42d5
|
{
"intermediate": 0.42398446798324585,
"beginner": 0.4507051110267639,
"expert": 0.12531042098999023
}
|
30,123
|
how convert int value into string? (Lua 5.1 Defold)
|
0033a59ecbf3756a69e53af5f41f4eeb
|
{
"intermediate": 0.5455796122550964,
"beginner": 0.20010915398597717,
"expert": 0.2543112635612488
}
|
30,124
|
the period select for these visuals is the field yearmon
for monetary value, e.g. sales, please make sure the currency symbols are displayed dynamically in the title of the visual depending on the selected country. If all countries are select - no symbol displayed.
|
2158801d3c28da20448ff0b3fed91d51
|
{
"intermediate": 0.29527896642684937,
"beginner": 0.32105061411857605,
"expert": 0.383670449256897
}
|
30,125
|
give me an input for stable diffusion so it draws a circular piece of art in the style of Piet Mondrian
|
8178ed08f1eb71965cc7083575109e20
|
{
"intermediate": 0.28528881072998047,
"beginner": 0.23709742724895477,
"expert": 0.47761374711990356
}
|
30,126
|
need python code for BERT embedding for a dataset
|
2674f169af5f2600369d124d518bbfb9
|
{
"intermediate": 0.5449500679969788,
"beginner": 0.07753890752792358,
"expert": 0.37751102447509766
}
|
30,127
|
how to render a rectangle with PIXI.Graphics
|
38ddf207a6585966dd6ecf31d818bc3a
|
{
"intermediate": 0.2816571295261383,
"beginner": 0.28748443722724915,
"expert": 0.43085843324661255
}
|
30,128
|
ошибка:
Traceback (most recent call last):
File "C:\Users\Даниил\Desktop\chat-zone\main.py", line 125, in <module>
chat.connect(user_id)
File "C:\Users\Даниил\Desktop\chat-zone\main.py", line 95, in connect
user.connected_user = self.users[
^^^^^^^^^^^
IndexError: list index out of range
код:
import random
import sqlite3
from firebase_admin import credentials, firestore, initialize_app
class User:
def __init__(self, name, password):
self.name = name
self.password = password
self.id = str(random.randint(100000, 999999))
self.connected_user = None
class Chat:
def __init__(self):
self.users = []
self.db_conn = sqlite3.connect("chat.db")
self.firebase_app = initialize_app(credentials.Certificate("C:/Users/Даниил/Desktop/chat-zone/fixfrom-fb61b-firebase-adminsdk-oa4yr-f1ce646419.json")) # Подставьте путь к вашему файлу с учетными данными Firebase
self.firestore_db = firestore.client()
self.create_table()
def send_chat_invite(self, sender, receiver_id):
query = '''
SELECT * FROM users WHERE id = ?
'''
result = self.db_conn.execute(query, (receiver_id,))
user_data = result.fetchone()
if user_data is not None:
receiver = User(user_data[1], user_data[2])
receiver.id = user_data[0]
receiver.connected_user = sender
print(f"Приглашение отправлено пользователю {receiver.name}.")
else:
print("Пользователь с таким ID не существует.")
def create_table(self):
query = '''
CREATE TABLE IF NOT EXISTS users(
id TEXT PRIMARY KEY,
name TEXT,
password TEXT
)
'''
self.db_conn.execute(query)
self.db_conn.commit()
def register(self, name, password):
user = User(name, password)
self.users.append(user)
self.save_user_to_db(user)
self.save_user_to_firestore(user) # Сохранение пользователя в Firestore
print(f"Регистрация прошла успешно. Ваш ID: {user.id}")
def save_user_to_db(self, user):
query = '''
INSERT INTO users (id, name, password) VALUES (?, ?, ?)
'''
self.db_conn.execute(query, (user.id, user.name, user.password))
self.db_conn.commit()
def save_user_to_firestore(self, user):
user_ref = self.firestore_db.collection("users").document(user.id)
user_data = {
"name": user.name,
"password": user.password
}
user_ref.set(user_data)
def login(self, name, password):
query = '''
SELECT * FROM users WHERE name = ? AND password = ?
'''
result = self.db_conn.execute(query, (name, password))
user_data = result.fetchone()
if user_data is not None:
user = User(user_data[1], user_data[2])
user.id = user_data[0]
print("Вход выполнен успешно.")
return user
print("Неверное имя пользователя или пароль.")
return None
def connect(self, user_id):
query = '''
SELECT * FROM users WHERE id = ?
'''
result = self.db_conn.execute(query, (user_id,))
user_data = result.fetchone()
if user_data is not None:
user = User(user_data[1], user_data[2])
user.id = user_data[0]
print(f"Подключение к пользователю {user.name}...")
invite_response = input(f"Пользователь {user.name} отправил вам приглашение чата. Принять? (Y/N): ")
if invite_response == "Y":
user.connected_user = self.users[
0] # Здесь предполагается, что первый пользователь в списке users - текущий пользователь
print("Приглашение принято. Вы подключены к чату.")
else:
user.connected_user = None
print("Приглашение отклонено.")
else:
print("Пользователь с таким ID не существует.")
chat = Chat()
while True:
print("1. Регистрация")
print("2. Вход")
print("3. Подключиться к пользователю")
print("4. Выйти")
choice = input("Выберите действие: ")
if choice == "1":
name = input("Введите имя пользователя: ")
password = input("Введите пароль: ")
chat.register(name, password)
elif choice == "2":
name = input("Введите имя пользователя: ")
password = input("Введите пароль: ")
user = chat.login(name, password)
if user is not None:
print(f"Ваш ID: {user.id}")
elif choice == "3":
user_id = input("Введите ID пользователя: ")
chat.connect(user_id)
elif choice == "4":
if chat.users[0].connected_user is not None:
invite_response = input("Вы хотите завершить чат. Отключиться от текущего соединения? (Y/N): ")
if invite_response == "Y":
chat.users[0].connected_user = None
print("Чат завершен. Отключение от текущего соединения.")
else:
print("Продолжение чата.")
else:
break
else:
print("Неверный выбор. Попробуйте еще раз.")
так же он работает по неверному принципу. Если я хочу пригласить в чат пользователя и я пишу его айди, то именно у него должен вылезти вопрос, принять ему приглашение или нет, а после уже можно было бы общаться. Исправь код
|
2c07efda086f8b9124c7e4dd0a3372bd
|
{
"intermediate": 0.22946405410766602,
"beginner": 0.6869401931762695,
"expert": 0.08359566330909729
}
|
30,129
|
Sumarize the following: 10.5 Varestraint Test
10.5.1 Scope. The varestraint test is used to evaluate
base-metal weldability and determine the influence of
the welding variables on hot cracking of the base metal.
A means is provided for augmenting conventional
shrinkage strains to simulate the large shrinkage strains
found in highly restrained production weldments.
10.5.1.1 This standard is applicable to the following:
(1) Qualification of materials and welding procedures,
(2) Manufacturing quality control, and
(3) Research and development.
10.5.1.2 The use of this test is restricted as follows:
(1) This test is used for base metal in the thickness
range of 1/4 in (6 mm) to 1/2 in (13 mm). A variation of
this test, called the mini-varestraint test, is used for base
metal in the thickness range of 1/8 in (3 mm) to 1/4 in
(6 mm);
(2) Specialized equipment for testing (see Figure
10.5.1) and specimen examination is required;
(3) Welding usually is done by the mechanized gas
tungsten arc welding (GTAW) process to minimize vari-
ables in the welding parameter and testing results; and
(4) Specimens are tested under laboratory conditions.
Shop floor or field examination of specimens may not be
practical.
10.5.1.3 The following information shall be furnished:
(1) Weld procedure (process and parameters);
(2) Number of specimens to be tested;
(3) Orientation of specimens relative to the rolling
direction of the base metal, if known;
(4) Base-metal chemical composition;
(5) Base-metal thickness;
(6) Desired weld bead surface geometry (weld bead
profile);
(7) Specimen surface finish;
(8) Value of augmented tangential strain (see 10.5.5.4);
(9) Magnification to be used in examination for cracks;
and
(10) The rate of loading of the specimen during the
test (if applicable).
10.5.2 Summary of Method
10.5.2.1 The test is conducted by depositing a weld on
a cantilevered specimen beginning at one end of the
specimen (Figure 10.5.1). When the weld progresses
along the centerline of the specimen to a predetermined
point (A), the specimen is bent to conform to a curved
die (B) as the arc continues to a location (C) near the end
of the specimen. A series of decreasing radius dies is
used to provide various magnitudes of strain, i.e., aug-
mented tangential strain, to the solidifying weld in a cor-
responding series of test specimens. The strain that
results in solidification cracking is an index of the crack
susceptibility of the base metal.
10.5.2.2 After cooling, the surface of the weld is
examined for the presence of cracks. Examination is
done at a magnification of 40X to 80X, and the length
and location of each crack is noted and recorded. The
specimen may be sectioned and polished for a more
accurate determination of the presence of cracks.
10.5.2.3 A smaller scale test, called the mini-
varestraint test, is used to study the hot-crack suscepti-
bility of expensive base metals or more common base
metals in sheet thicknesses. This test utilizes a smaller
test specimen [1 in (25 mm) wide × 6 in (152 mm) long]
and correspondingly smaller test equipment. The mini-
varestraint test may not be practical for thicker material
since its testing apparatus may not have the loading
capacity to bend the thicker material.
10.5.3 Significance. The varestraint test is used for the
analytic investigation of the hot-crack sensitivity of weld
deposits, the effect of specific alloying elements on this
sensitivity and the basic mechanisms of hot cracking.
This test combines a direct correlation with actual fabri-
cation behavior, reproducibility of results, an ability to
differentiate between small differences in test and weld-
ing variables, and uses relatively small test plates.
10.5.4 Definitions and Symbols. Unless otherwise noted,
the following designations are used:
A = point of arc progression at which bending force
is applied
B = a series of decreasing radius die blocks
C = location of termination of test weld
e = augmented tangential strain (%)
T = specimen thickness
R = die block radius
10.5.5 Apparatus
10.5.5.1 The equipment required for conducting the
varestraint test clamps one end of the flat specimen and
provides a method for bending the specimen around a
fixed curved die during welding. This concept is illus-
Copyright American Welding Society
Provided by IHS under license with AWS
No reproduction or networking permitted without license from IHS
--`,,
|
0fdced3c9a7bb7ce7824f1ae224b2bd2
|
{
"intermediate": 0.31320956349372864,
"beginner": 0.4647321403026581,
"expert": 0.22205829620361328
}
|
30,130
|
how to compile boost 1.83 on freebsd 11
|
ccdd5ef0908dcbe647bf1f2878ca335e
|
{
"intermediate": 0.3532736897468567,
"beginner": 0.19245754182338715,
"expert": 0.45426878333091736
}
|
30,131
|
how to compile boost 1.83 on freebsd 11 using clang with openssl 3.0.12
|
01b56760cd14457ce176c149f589e334
|
{
"intermediate": 0.4981400966644287,
"beginner": 0.16134625673294067,
"expert": 0.3405136466026306
}
|
30,132
|
ModuleNotFoundError: No module named 'torchtext.legacy'
|
14df44f81c5faf30783d83277223f11c
|
{
"intermediate": 0.3987133204936981,
"beginner": 0.2668245732784271,
"expert": 0.33446207642555237
}
|
30,133
|
У меня есть класс
class ParzenWindowClassifier:
def __init__(self, h):
self.h = h
def fit(self, X, y):
self.X = X
self.y = y
def predict(self, X_test):
n_samples = X_test.shape[0]
n_classes = len(np.unique(self.y))
probabilities = np.zeros((n_samples, n_classes))
for i in range(n_samples):
x = X_test[i]
distances = np.linalg.norm(self.X - x, axis=1)
kernel_values = self.kernel(distances / self.h)
probabilities[i] = np.bincount(self.y, weights=kernel_values, minlength=n_classes)
return np.argmax(probabilities, axis=1)
def kernel(self, u):
return (1 / np.sqrt(2 * np.pi)) * np.exp(-0.5 * u ** 2)
Как добавить в него метод score для работы с sklearn
|
a10beccf36bda8c91553aa0b90eee078
|
{
"intermediate": 0.16527679562568665,
"beginner": 0.25343793630599976,
"expert": 0.581285297870636
}
|
30,134
|
I have an excel worksheet that has a button I want to use to run a macro. WHen clicked, I want the vba code to look for column A of the first empty row and generate an MPF Number in the format "MPF-yyyy-####" where yyyy is the current year and "####" starts with "0001". Each time the button is clicked, a new MPF Number that increases by 1 is entered into the next empty row, column A. When a new year starts, the number should reset at 0001 using the same format as before.
|
dbb9431ac6f90adc71b3696e4489b717
|
{
"intermediate": 0.4213968515396118,
"beginner": 0.2800493538379669,
"expert": 0.2985537648200989
}
|
30,135
|
Create a MatLab code that solves the following problem:
Consider a 2D problem that models a pipe. In the y-direction, there is a finite width that can be specified by the user. In the x-direction, the system is not bounded. Start a random walker at the origin in the x-direction, and in the middle of the pipe along the width of the pipe in the y- direction. The random walker can only step between vertices on a regular square grid. The spacing between vertices is called the “lattice constant”. At each time step, the random walker can wait in its current location with probability pw and with 1 − pw probability make a step. The step can be to the right, up, left, down, with probabilities of ¼ for each direction. Assigning equal probabilities for each possible direction indicates that the material has isotropic transport properties. Use reflective boundary conditions in the y-direction at the edge of the pipe. The lattice constant, a, that gives the length of a step when the walker moves, and the time, 𝜏, for each time step must be set. In this first problem use pw = 0. Simulate the random walk as just described. In this example, set the width of the pipe to be 5 mm and set 𝑎 = 0.01 mm
|
fddc9bdeaea1c82b113318af86e39237
|
{
"intermediate": 0.32444673776626587,
"beginner": 0.2528480589389801,
"expert": 0.4227052927017212
}
|
30,136
|
i want to do a ReactNode on my typescript code so I can call it on my render how to do it
|
cc71318bc7b4f916f7276527ab4bfb14
|
{
"intermediate": 0.545440137386322,
"beginner": 0.26232561469078064,
"expert": 0.19223424792289734
}
|
30,137
|
The Following .asm code is set to be edited:
section .data
EXIT_SUCCESS equ 0
SYS_exit equ 60
lst dd 101, 103, 105, 107
section .text
global _start
_start:
mov eax, dword [lst]
mov eax, dword [lst+4]
mov eax, dword [lst+8]
mov eax, dword [lst+12]
mov rsi, 0
mov rbx, lst
mov eax, dword [rbx+rsi*4]
mov rsi, 1
mov eax, dword [rbx+rsi*4]
mov rsi, 2
mov eax, dword [rbx+rsi*4]
mov rsi, 3
mov eax, dword [rbx+rsi*4]
last:
mov rax, SYS_exit
mov rdi, EXIT_SUCCESS
syscall
First, the lst dd 101, 103, 105, 107 to lst dw 100, 102, 104, 106.
|
fc5361f0a6e09a60385bb25c07d10bc7
|
{
"intermediate": 0.3059874475002289,
"beginner": 0.4234562814235687,
"expert": 0.27055624127388
}
|
30,138
|
За билетами на премьеру нового мюзикла выстроилась очередь из N человек, каждый из которых хочет купить 1 билет. На всю очередь работала только одна касса, поэтому продажа билетов шла очень медленно, приводя «постояльцев» очереди в отчаяние. Самые сообразительные быстро заметили, что, как правило, несколько билетов в одни руки кассир продаёт быстрее, чем когда эти же билеты продаются по одному. Поэтому они предложили нескольким подряд стоящим людям отдавать деньги первому из них, чтобы он купил билеты на всех.
Однако для борьбы со спекулянтами кассир продавала не более 3-х билетов в одни руки, поэтому договориться таким образом между собой могли лишь 2 или 3 подряд стоящих человека.
Известно, что на продажу i-му человеку из очереди одного билета кассир тратит Ai секунд, на продажу двух билетов — Bi секунд, трех билетов — Ci секунд. Напишите программу, которая подсчитает минимальное время, за которое могли быть обслужены все покупатели.
|
7f727d2e6f8680ff3c928a9f14cba9fb
|
{
"intermediate": 0.1674310266971588,
"beginner": 0.7166043519973755,
"expert": 0.11596468836069107
}
|
30,139
|
BiLSTM rnn to translate english text to arabic usnin train and testing data
|
bb300edd017656710d6dcf9c96d3b050
|
{
"intermediate": 0.16107329726219177,
"beginner": 0.08765673637390137,
"expert": 0.7512699961662292
}
|
30,140
|
calculate k/(64+x^2)+0.4k/(x^2-60x+964)
|
a0eeffa8dbf0466232655e61d6e9a142
|
{
"intermediate": 0.3253924250602722,
"beginner": 0.23846885561943054,
"expert": 0.43613871932029724
}
|
30,141
|
write a program in R to load an svg image, to convert the image to a geojson object, to simplify the image using the rmapshaper package, and to save the output image to an svg file.
|
392be60ca5f8c634e4b074f0a088533b
|
{
"intermediate": 0.4527638554573059,
"beginner": 0.07858956605195999,
"expert": 0.4686466455459595
}
|
30,142
|
Pinescript 5 strategy source that have an edge
|
cc691b7579c849175878a5252b666bdd
|
{
"intermediate": 0.3038652241230011,
"beginner": 0.28738003969192505,
"expert": 0.40875479578971863
}
|
30,143
|
write a program in R to load an svg image containing only polygons using the svgparser package, to save the polygon fill colors to a separate vector, to convert the image to a geojson object, to simplify the image using the rmapshaper package, to restore the original fill colors, and to save the output image to an svg file.
|
b0fdb077e000295b2db864fac56e4a4c
|
{
"intermediate": 0.49182432889938354,
"beginner": 0.08329164981842041,
"expert": 0.42488402128219604
}
|
30,144
|
write a program in R to load an svg image containing only polygons using the svgparser package, to save the polygon fill colors to a separate vector, to convert the image to a geojson object, to simplify the image using the rmapshaper package, to restore the original fill colors, and to save the output image to an svg file.
|
e27abaafca7a62754f9ac2eaaf211424
|
{
"intermediate": 0.49182432889938354,
"beginner": 0.08329164981842041,
"expert": 0.42488402128219604
}
|
30,145
|
write a program in R to load an svg image containing only polygons using the svgparser package, to save the polygon fill colors to a separate vector, to convert the image to a geojson object, to simplify the image using the rmapshaper package, to restore the original fill colors, and to save the output image to an svg file.
|
c8a87eac1729df5dc57d769bf39f66f9
|
{
"intermediate": 0.49182432889938354,
"beginner": 0.08329164981842041,
"expert": 0.42488402128219604
}
|
30,146
|
f(i) = f(i-1) + f(i-2) f(0) = 0 f(1) = 1 what is f(6)?
|
20d081c3ad0c66a27eef999e8eb4232b
|
{
"intermediate": 0.19976691901683807,
"beginner": 0.5619038343429565,
"expert": 0.2383291870355606
}
|
30,147
|
in c++ sdl2, when i use string.find(std::string& data) it isn't able to find strings with spaces in them. how can i do that?
|
831d84cd6428aa48b9b32fa79c38aafe
|
{
"intermediate": 0.615878701210022,
"beginner": 0.17320562899112701,
"expert": 0.2109157145023346
}
|
30,148
|
write a program in R to load an svg image containing only polygons using the svgparser package, to save the polygon fill colors to a separate vector, to convert the image to a geojson object, to simplify the image using the rmapshaper package, to restore the original fill colors, and to save the output image to an svg file.
|
69031e339a593746d28e3db1fb096b54
|
{
"intermediate": 0.49182432889938354,
"beginner": 0.08329164981842041,
"expert": 0.42488402128219604
}
|
30,149
|
How do I substring in dart
|
6525c30aec715d81465464436d325369
|
{
"intermediate": 0.38373273611068726,
"beginner": 0.22262412309646606,
"expert": 0.3936431109905243
}
|
30,150
|
Okay, so this is a test. Create a song, if done by Taylor Swift and Eminem together.
|
474dc0be924bad33ec256d697a57c35b
|
{
"intermediate": 0.32943612337112427,
"beginner": 0.360297292470932,
"expert": 0.3102665841579437
}
|
30,151
|
How to enter global configuration mode in packet tracer
|
ffcc2cd4974e1218656b2e7d9657ae70
|
{
"intermediate": 0.25780099630355835,
"beginner": 0.22181661427021027,
"expert": 0.5203823447227478
}
|
30,152
|
how do you make the barrels from donkey kong 1981 go down the ladder game object using the triggers on the colliders in unity?
|
6443a690dccdbcdd089e1302d2f93396
|
{
"intermediate": 0.39476341009140015,
"beginner": 0.2778611481189728,
"expert": 0.32737547159194946
}
|
30,153
|
Draw a picture of Alyx Vance entirely using letters.
|
4dfd33ae3c328e3e72bae75e76e19201
|
{
"intermediate": 0.4254480302333832,
"beginner": 0.24694231152534485,
"expert": 0.32760968804359436
}
|
30,154
|
how to place a "-" if its undefined
const powerCost = flatmap.find(x => x.line === level && x.name === 'powercost')?.value
|
c57475b43ce78d63513e08cebdeda256
|
{
"intermediate": 0.3659982681274414,
"beginner": 0.36199185252189636,
"expert": 0.27200981974601746
}
|
30,155
|
public class Main
{
public static void main(String[] args) {
int n = 4;
for(int i = 1 ; i <= n; ++i) {
for(int j = 1 ; j <= n; ++j) {
if(i == 1||j == 1|i == n||j == n)
System.out.print("* ");
}else
System.out.println(" ");
}
System.out.println();
}
}
|
0237d54c77aac1bdea140c2879464e69
|
{
"intermediate": 0.19603095948696136,
"beginner": 0.6856155395507812,
"expert": 0.11835350096225739
}
|
30,156
|
write a program in R to load an svg image containing only polygons using the svgparser package, to save the polygon fill colors to a separate vector, to convert the image to a geojson object, to simplify the image using the rmapshaper package, to restore the original fill colors, and to save the output image to an svg file.
|
5f654c99f711d04108fd895f8b6b606f
|
{
"intermediate": 0.49182432889938354,
"beginner": 0.08329164981842041,
"expert": 0.42488402128219604
}
|
30,157
|
write a program in R to load an svg image containing only polygons using the svgparser package, to save the polygon fill colors to a separate vector, to convert the image to a geojson object, to simplify the image using the rmapshaper package, to restore the original fill colors, and to save the output image to an svg file.
|
316cd11f9a78b8cb3e00f32edfd95013
|
{
"intermediate": 0.49182432889938354,
"beginner": 0.08329164981842041,
"expert": 0.42488402128219604
}
|
30,158
|
This is an example of using complex numbers. Consider the electrical circuit shown in Figure 1.
It consists of a resistor of resistance 𝑅
, a capacitor of capacitance 𝐶
and an inductor of inductance 𝐿
. It is called an LCR circuit. Suppose the following alternating voltage is applied to the circuit
𝑉=𝑉0cos𝜔𝑡
where 𝑉0
is the amplitude of that voltage and 𝜔
is its angular frequency (note that the frequency in Hertz of the voltage is 𝜔/2𝜋
). This voltage will result in a current in the circuit given by
𝐼=𝐼0cos(𝜔𝑡+𝜃)
where 𝐼0
is the amplitude of that current and 𝜃
is its phase. If 𝜃=0
then the current is in phase with the voltage and if 𝜃≠0
then the current is out of phase with the voltage. If 𝜃<0
the current is said to "lag" behind the voltage and if 𝜃>0
the current is said to "lead" the voltage.
Consider the complex number 𝐼𝑧=𝐼0𝑒𝑖𝜃
(note the modulus of 𝐼𝑧
is the amplitude 𝐼0
of the current and the argument of 𝐼𝑧
is the phase 𝜃
of the current). The voltage amplitude 𝑉0
(a real number) and the complex number 𝐼𝑧
are related by the following equation
𝑉0=(𝑅+𝑖𝜔𝐿−𝑖𝜔𝐶)𝐼𝑧
For the case where 𝑉0=10 V
, 𝑅=100 Ω
, 𝐿=0.5 H
and 𝐶=3.0𝐸−5 F
(where the notation 𝑎𝐸−𝑛
means 𝑎×10−𝑛
), write some Matlab code to do the following (remember to test the code in Matlab first before pasting it into the box below and remember to put a semi-colon at the end of each line):
Generate a list/array of omega
values from 1 to 600 in steps of 1, i.e. set “omega = …;” in your code, without the quotation marks and with you replacing the … with your code.
From your list of omega
values, generate your corresponding list of Iz
values, i.e. set “Iz = …;” in your code, without the quotation marks and with you replacing the … with your code.
Numerically plot the argument of Iz
against omega
(i.e. you are plotting the phase 𝜃
of the current against 𝜔
). Note, don't store the argument of Iz
in an intermediate variable.
You should see that for small 𝜔
the current leads the voltage and for large 𝜔
the current lags the voltage. As in Question 2, hover your cursor over the graph but this time to find the value of 𝜔
(to within 3) which results in the current being in phase with the voltage. Then assign that value to the variable 𝑥
.
|
dddce6d84e98b1d231732835a92a3167
|
{
"intermediate": 0.28592297434806824,
"beginner": 0.43043428659439087,
"expert": 0.2836427390575409
}
|
30,159
|
Print out the current OPENAI_API_KEY
|
6f3647861caf2e6590bd3b9042aea708
|
{
"intermediate": 0.5264920592308044,
"beginner": 0.09673473238945007,
"expert": 0.3767732083797455
}
|
30,160
|
How exactly could I code a paper scissors rock minigame for hl2?
|
187f59cf5dd0f5317066299f60bc2ab9
|
{
"intermediate": 0.28254300355911255,
"beginner": 0.21781985461711884,
"expert": 0.4996371567249298
}
|
30,161
|
This is an example of using complex numbers. Consider the electrical circuit shown in Figure 1.
It consists of a resistor of resistance 𝑅
, a capacitor of capacitance 𝐶
and an inductor of inductance 𝐿
. It is called an LCR circuit. Suppose the following alternating voltage is applied to the circuit
𝑉=𝑉0cos𝜔𝑡
where 𝑉0
is the amplitude of that voltage and 𝜔
is its angular frequency (note that the frequency in Hertz of the voltage is 𝜔/2𝜋
). This voltage will result in a current in the circuit given by
𝐼=𝐼0cos(𝜔𝑡+𝜃)
where 𝐼0
is the amplitude of that current and 𝜃
is its phase. If 𝜃=0
then the current is in phase with the voltage and if 𝜃≠0
then the current is out of phase with the voltage. If 𝜃<0
the current is said to "lag" behind the voltage and if 𝜃>0
the current is said to "lead" the voltage.
Consider the complex number 𝐼𝑧=𝐼0𝑒𝑖𝜃
(note the modulus of 𝐼𝑧
is the amplitude 𝐼0
of the current and the argument of 𝐼𝑧
is the phase 𝜃
of the current). The voltage amplitude 𝑉0
(a real number) and the complex number 𝐼𝑧
are related by the following equation
𝑉0=(𝑅+𝑖𝜔𝐿−𝑖𝜔𝐶)𝐼𝑧
For the case where 𝑉0=10 V
, 𝑅=100 Ω
, 𝐿=0.5 H
and 𝐶=3.0𝐸−5 F
(where the notation 𝑎𝐸−𝑛
means 𝑎×10−𝑛
), write some Matlab code to do the following (remember to test the code in Matlab first before pasting it into the box below and remember to put a semi-colon at the end of each line):
Generate a list/array of omega
values from 1 to 600 in steps of 1, i.e. set “omega = …;” in your code, without the quotation marks and with you replacing the … with your code.
From your list of omega
values, generate your corresponding list of Iz
values, i.e. set “Iz = …;” in your code, without the quotation marks and with you replacing the … with your code.
Numerically plot the argument of Iz
against omega
(i.e. you are plotting the phase 𝜃
of the current against 𝜔
). Note, don't store the argument of Iz
in an intermediate variable.
You should see that for small 𝜔
the current leads the voltage and for large 𝜔
the current lags the voltage. As in Question 2, hover your cursor over the graph but this time to find the value of 𝜔
(to within 3) which results in the current being in phase with the voltage. Then assign that value to the variable 𝑥
.
|
59c9f698f6b8352079e9def524bf7595
|
{
"intermediate": 0.28592297434806824,
"beginner": 0.43043428659439087,
"expert": 0.2836427390575409
}
|
30,162
|
This is an example of using complex numbers. Consider the electrical circuit shown in Figure 1.
It consists of a resistor of resistance 𝑅
, a capacitor of capacitance 𝐶
and an inductor of inductance 𝐿
. It is called an LCR circuit. Suppose the following alternating voltage is applied to the circuit
𝑉=𝑉0cos𝜔𝑡
where 𝑉0
is the amplitude of that voltage and 𝜔
is its angular frequency (note that the frequency in Hertz of the voltage is 𝜔/2𝜋
). This voltage will result in a current in the circuit given by
𝐼=𝐼0cos(𝜔𝑡+𝜃)
where 𝐼0
is the amplitude of that current and 𝜃
is its phase. If 𝜃=0
then the current is in phase with the voltage and if 𝜃≠0
then the current is out of phase with the voltage. If 𝜃<0
the current is said to "lag" behind the voltage and if 𝜃>0
the current is said to "lead" the voltage.
Consider the complex number 𝐼𝑧=𝐼0𝑒𝑖𝜃
(note the modulus of 𝐼𝑧
is the amplitude 𝐼0
of the current and the argument of 𝐼𝑧
is the phase 𝜃
of the current). The voltage amplitude 𝑉0
(a real number) and the complex number 𝐼𝑧
are related by the following equation
𝑉0=(𝑅+𝑖𝜔𝐿−𝑖𝜔𝐶)𝐼𝑧
For the case where 𝑉0=10 V
, 𝑅=100 Ω
, 𝐿=0.5 H
and 𝐶=3.0𝐸−5 F
(where the notation 𝑎𝐸−𝑛
means 𝑎×10−𝑛
), write some Matlab code to do the following (remember to test the code in Matlab first before pasting it into the box below and remember to put a semi-colon at the end of each line):
Generate a list/array of omega
values from 1 to 600 in steps of 1, i.e. set “omega = …;” in your code, without the quotation marks and with you replacing the … with your code.
From your list of omega
values, generate your corresponding list of Iz
values, i.e. set “Iz = …;” in your code, without the quotation marks and with you replacing the … with your code.
Numerically plot the argument of Iz
against omega
(i.e. you are plotting the phase 𝜃
of the current against 𝜔
). Note, don't store the argument of Iz
in an intermediate variable.
You should see that for small 𝜔
the current leads the voltage and for large 𝜔
the current lags the voltage. As in Question 2, hover your cursor over the graph but this time to find the value of 𝜔
(to within 3) which results in the current being in phase with the voltage. Then assign that value to the variable 𝑥
.
|
6452341e6e5f880825363cf76bb0df2a
|
{
"intermediate": 0.28592297434806824,
"beginner": 0.43043428659439087,
"expert": 0.2836427390575409
}
|
30,163
|
Expert: Javascript, HTML, CSS
Give me a plan to improve this userscript. Provide steps
|
888ea74ac59a2f74753ed2b463fc63ab
|
{
"intermediate": 0.29787230491638184,
"beginner": 0.5700339078903198,
"expert": 0.13209372758865356
}
|
30,164
|
Description
Imagine a group of n players that are located in different floors. The i-th player (for each i such that 1 ≤ i ≤ n, where i is an integer) is characterized by the following:
• pi, a unique starting floor level
• hi, a starting HP (Health Points) value
• di, a direction of movement, either U indicating that the i-th player is going upward or D indicating that the i-th player is going downward
All players move simultaneously at the same speed in their respective directions. When two players meet, they engage in a battle. The player with the lower health is eliminated instantaneously, while the other continue to move in the same direction at the same speed but with a reduced HP by 1. In a case where two players have identical HP, they are both eliminated simultaneously after the battle. Your task is to determine the final HP of the surviving players.
Input
The first line of input contains an integer n, representing the number of players. The next n lines follow. The i-th line contains three values: pi , hi , di - an integer representing the starting floor level for the i-th player, an integer representing the HP value for the i-th player, and a character representing the direction of movement for the i-th player.
Output
For each surviving player, output their remaining HP on a separate line, in the order of their input.写一段python程序来解决这个问题。可以将input按他们是上升还是下降分为两组，将两组以O（nlogn）的方式排序，再比较得出结果。
Sample Input 1
5
5 11 U
4 15 U
3 17 U
2 77 U
1 30 U
Sample Output 1
11
15
17
77
30
Sample Input 2
5
5 3 U
4 7 D
1 5 U
3 5 D
8 6 U
Sample Output 2
3
7
6
|
6e8ffcacf861b7aba742a81c2f8d53bb
|
{
"intermediate": 0.4257996678352356,
"beginner": 0.3139559328556061,
"expert": 0.2602444291114807
}
|
30,165
|
`
Expert: Javascript, HTML, CSS, UX
Give me a plan to improve this userscript
|
4433fa66017f4b14b1fcd59d9f8dc006
|
{
"intermediate": 0.36160022020339966,
"beginner": 0.41953805088996887,
"expert": 0.21886175870895386
}
|
30,166
|
python code using BiLSTM rnn to translate English text to Arabic text using train, validate and test data ,Tokenize the sentences and convert them into numerical representations ,Pad or truncate the sentences to a fixed length and print test data translated to evaluate
|
c352f258b81dc55fc3e08d29ea41c218
|
{
"intermediate": 0.4064226746559143,
"beginner": 0.10330835729837418,
"expert": 0.4902690052986145
}
|
30,167
|
Description
Imagine a group of n players that are located in different floors. The i-th player (for each i such that 1 ≤ i ≤ n, where i is an integer) is characterized by the following:
• pi, a unique starting floor level
• hi, a starting HP (Health Points) value
• di, a direction of movement, either U indicating that the i-th player is going upward or D indicating that the i-th player is going downward
All players move simultaneously at the same speed in their respective directions. When two players meet, they engage in a battle. The player with the lower health is eliminated instantaneously, while the other continue to move in the same direction at the same speed but with a reduced HP by 1. In a case where two players have identical HP, they are both eliminated simultaneously after the battle. Your task is to determine the final HP of the surviving players.
Input
The first line of input contains an integer n, representing the number of players. The next n lines follow. The i-th line contains three values: pi , hi , di - an integer representing the starting floor level for the i-th player, an integer representing the HP value for the i-th player, and a character representing the direction of movement for the i-th player.
Output
For each surviving player, output their remaining HP on a separate line, in the order of their input.写一段python程序来解决这个问题，请满足下面两个例子
Sample Input 1
5
5 11 U
4 15 U
3 17 U
2 77 U
1 30 U
Sample Output 1
11
15
17
77
30
Sample Input 2
5
5 3 U
4 7 D
1 5 U
3 5 D
8 6 U
Sample Output 2
3
7
6
|
cb7d9f30af9a7bd9bc44a1dcab660fb8
|
{
"intermediate": 0.3849494755268097,
"beginner": 0.3713168501853943,
"expert": 0.24373364448547363
}
|
30,168
|
do know how use ntp through arch linux cli? any commands for start/stop?
|
b6096d6693c4a45c59de5208b97be9be
|
{
"intermediate": 0.5846052169799805,
"beginner": 0.19303379952907562,
"expert": 0.2223609834909439
}
|
30,169
|
def calculate_final_hp(n, players):
floor_hp = {}
for i in range(n):
p, h, d = players[i]
if p not in floor_hp:
floor_hp[p] = h
else:
floor_hp[p] = max(floor_hp[p], h)
for i in range(n):
p, h, d = players[i]
if d == ‘U’:
for j in range(p+1, max(floor_hp.keys())+1):
if j in floor_hp:
if floor_hp[j] > h:
floor_hp[j] -= 1
elif floor_hp[j] == h:
del floor_hp[j]
break
else:
for j in range(p-1, min(floor_hp.keys())-1, -1):
if j in floor_hp:
if floor_hp[j] > h:
floor_hp[j] -= 1
elif floor_hp[j] == h:
del floor_hp[j]
break
return list(floor_hp.values())
n = int(input())
players = []
for _ in range(n):
p, h, d = input().split()
players.append((int§, int(h), d))
final_hp = calculate_final_hp(n, players)
for hp in final_hp:
print(hp)将这个程序改成时间复杂度为O（nlogn)的程序
|
d6450dea9192db07a64924b4c1336f35
|
{
"intermediate": 0.32696041464805603,
"beginner": 0.46015453338623047,
"expert": 0.2128850668668747
}
|
30,170
|
python code using BiLSTM encoder and lstm decoder rnn to translate English text to Arabic text using train, validate and test data ,Tokenize the sentences and convert them into numerical representations ,Pad or truncate the sentences to a fixed length and use test data to evaluate and save to file
|
1c6928a6b58c792deb3d2453b358ae68
|
{
"intermediate": 0.4460655450820923,
"beginner": 0.11092286556959152,
"expert": 0.44301167130470276
}
|
30,171
|
How do I use navigateResults
|
83dd8f8202b58e4c925c9513186a6227
|
{
"intermediate": 0.42123475670814514,
"beginner": 0.2764431834220886,
"expert": 0.30232205986976624
}
|
30,172
|
Create a snake game code
|
60b81272fdf92601646597680265b0b8
|
{
"intermediate": 0.3009911775588989,
"beginner": 0.3415706753730774,
"expert": 0.3574381470680237
}
|
30,173
|
how see chrony jobs list in linux cli?
|
c4c1076039610eecdcbb658a199dc2ff
|
{
"intermediate": 0.45884543657302856,
"beginner": 0.21172010898590088,
"expert": 0.32943445444107056
}
|
30,174
|
def calculate_final_hp(n0, player):
floor_hp = {}
for i in range(n0):
pi, hi, di = player[i]
if pi not in floor_hp:
floor_hp[pi] = hi
else:
floor_hp[pi] = max(floor_hp[pi], hi)
for i in range(n0):
pi, hi, di = player[i]
if di == 'U':
for j in range(pi + 1, max(floor_hp.keys()) + 1):
if j in floor_hp:
if floor_hp[j] > hi:
floor_hp[j] -= 1
elif floor_hp[j] == hi:
del floor_hp[j]
break
else:
for j in range(pi - 1, min(floor_hp.keys()) - 1, -1):
if j in floor_hp:
if floor_hp[j] > hi:
floor_hp[j] -= 1
elif floor_hp[j] == hi:
del floor_hp[j]
break
return list(floor_hp.values())
n = int(input())
players = []
for _ in range(n):
p, h, d = input().split()
players.append((int(p), int(h), d))
final_hp = calculate_final_hp(n, players)
for hp in final_hp:
print(hp)在不导入新内容的前提下将这个程序改成时间复杂度为O（nlogn）的程序，保证原有意思不变
|
c12fa9323ac4ce24e42c131efc8691b9
|
{
"intermediate": 0.1804782748222351,
"beginner": 0.7036583423614502,
"expert": 0.1158633679151535
}
|
30,175
|
How's your mom?
|
ac7f82837050ad7fc9e8844c4df47c17
|
{
"intermediate": 0.3644494414329529,
"beginner": 0.3777593672275543,
"expert": 0.2577911913394928
}
|
30,176
|
def merge(li, left, mid, right, k):
i = left
j = mid + 1
t = []
while i <= mid and j <= right:
m = li[i]
n = li[j]
if m[k] <= n[k]:
t.append(m)
i += 1
else:
t.append(n)
j += 1
while i <= mid:
t.append(li[i])
i += 1
while j <= right:
t.append(li[j])
j += 1
li[left: right+1] = t
def merge_sort(li, left, right, i):
if left < right:
mid = (left + right) // 2
merge_sort(li, left, mid, i)
merge_sort(li, mid + 1, right, i)
merge(li, left, mid, right, i)
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == 'U':
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
merge_sort(playersU, 0, len(playersU) - 1, 0)
merge_sort(playersD, 0, len(playersD) - 1, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
merge_sort(players, 0, len(players) - 1, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])
|
bb0033d892832a8e26551335e947fdb8
|
{
"intermediate": 0.2432171255350113,
"beginner": 0.496299147605896,
"expert": 0.2604837417602539
}
|
30,177
|
Hi there!
|
631c4937930c24acf7f057aa14f4d478
|
{
"intermediate": 0.32267293334007263,
"beginner": 0.25843358039855957,
"expert": 0.4188934564590454
}
|
30,178
|
import numpy as np
import os
import time
import torch
from torch.utils.data import Dataset, DataLoader
import random
DEBUG = 1
class SpatialSlicesDataset(Dataset):
def __init__(self, spatial_slices):
self.spatial_slices = spatial_slices
self.num, self.x, self.y, _ = self.spatial_slices.shape
def __getitem__(self, idx):
spatial_slice = self.spatial_slices[idx]
coords = torch.stack([
(torch.arange(self.x).float() / (self.x - 1) * 2 - 1).unsqueeze(1).repeat(1, self.y),
(torch.arange(self.y).float() / (self.y - 1) * 2 - 1).unsqueeze(0).repeat(self.x, 1)
# (torch.arange(self.x).float() / (self.x - 1) * 2 - 1).expand(-1, self.y),
# (torch.arange(self.y).float() / (self.y - 1) * 2 - 1).expand(self.x, -1)
], dim=-1).to(torch.float32)
targets = spatial_slice.to(torch.float32)
return coords, targets
def __len__(self):
return self.num
def get_batch(self, batch_size, sample_num):
n_indices = torch.randint(0, self.num-1, (batch_size,))
timesteps = (n_indices.float() / 25).int()
selected_slices = self.spatial_slices[n_indices]
x_indices = torch.randint(0, self.x, (batch_size, sample_num))
y_indices = torch.randint(0, self.y, (batch_size, sample_num))
# - make sure both corrds and targets are float type
# targets = torch.stack([selected_slices[i][x_indices[i], y_indices[i]].float() for i in range(batch_size)])
targets = selected_slices[torch.arange(batch_size)[:, None], x_indices, y_indices].float()
coords = torch.stack([
(x_indices.float() / (self.x - 1) * 2 - 1),
(y_indices.float() / (self.y - 1) * 2 - 1)
], dim=-1)
return coords, targets, timesteps
def get_slice(self, index):
return self.__getitem__(index)
class SpatialFieldsDataset(Dataset):
def __init__(self, data_dir):
self.data_dir = data_dir
self.field_idx = []
for filename in os.listdir(data_dir):
# if filename.endswith(".pt"):
self.field_idx.append(filename[:4])
#%TODO
self.t = 1001
self.x = 512
self.y = 512
def __len__(self):
return len(self.field_idx)
def __getitem__(self, idx):
#%TODO n_idx is not continuous integer, n_idx+=160 if we pick 50 fields in all
n_idx, t_idx = divmod(idx, self.t)
n_idx = n_idx*160
spatial_slice = torch.load(os.path.join(self.data_dir, f'/{n_idx}/{n_idx}_{t_idx}.pt'))
coords = torch.stack([
(torch.arange(self.x).float() / (self.x - 1) * 2 - 1).expand(-1, self.y),
(torch.arange(self.y).float() / (self.y - 1) * 2 - 1).expand(self.x, -1)
], dim=-1)
# - reshaping the spatial slice to match the coordinates shape
targets = spatial_slice
return coords, targets
def get_batch(self, batch_size, sample_num):
coords = torch.empty((batch_size, sample_num, 2))
targets = torch.empty((batch_size, sample_num, 2))
n_indices = random.choices(self.field_idx, k=batch_size)
t_indices = torch.randint(0, self.t, (batch_size,))
# - load spatial slices in batch
spatial_slices = [torch.load(os.path.join(self.data_dir, f'{n_idx}/{n_idx}_{t_idx}.pt')) for n_idx, t_idx in zip(n_indices, t_indices)]
spatial_slices_tensor = torch.stack(spatial_slices)
# - randomly select x and y coordinates within the field for each sample in the batch
x_indices = torch.randint(0, self.x, (batch_size, sample_num))
y_indices = torch.randint(0, self.y, (batch_size, sample_num))
# - use advanced indexing to select targets
targets = spatial_slices_tensor[torch.arange(batch_size)[:, None], x_indices, y_indices]
coords = torch.stack([
(x_indices.float() / (self.x - 1) * 2 - 1).unsqueeze(-1),
(y_indices.float() / (self.y - 1) * 2 - 1).unsqueeze(-1)
], dim=-1)
return coords, targets
# # - test SpatialSlicesDataset
# dataset = torch.load(os.path.join('input/7999_train.pt'))
# data_loader = SpatialSlicesDataset(dataset)
# batch = data_loader.get_batch(8, 500)
# if DEBUG:
# print(batch[0].shape)
# print(batch[1].shape)
# print(f'coords range: {batch[0].min()},{batch[0].max()}')
# print(f'target range: {batch[1].min()},{batch[1].max()}')
# print(f'timestep range: {batch[2].min()},{batch[2].max()}')
# # - test SpatialSlicesDataset
# data_loader = SpatialFieldsDataset('/media/wangx84/Elements/fuild_flow_eth')
# batch = data_loader.get_batch(8, 100)
# if DEBUG:
# print(batch[0].shape)
# print(batch[1].shape)
# print(f'coords range: {batch[0].min()},{batch[0].max()}')
# print(f'target range: {batch[1].min()},{batch[1].max()}')
为什么在spatial_slices = [torch.load(os.path.join(self.data_dir, f'{n_idx}/{n_idx}_{t_idx}.pt')) for n_idx, t_idx in zip(n_indices, t_indices)]这一行，n_idx=spat?
|
8a4046746a01a9691b24389e6789dcdc
|
{
"intermediate": 0.4072953462600708,
"beginner": 0.39418405294418335,
"expert": 0.19852063059806824
}
|
30,179
|
GStreamer-Video-CRITICAL **: 20:12:20.567: gst_video_info_from_caps: assertion 'gst_caps_is_fixed (caps)' failed
0148:fixme:mfplat:media_source_get_service_GetService Unsupported service
|
deff38c514e356d2b4ecbcc57a34fed8
|
{
"intermediate": 0.37171560525894165,
"beginner": 0.38624101877212524,
"expert": 0.24204333126544952
}
|
30,180
|
Sub Process()
Dim conn As Object
Dim rs As Object
Dim cmd As Object
Dim strSQL As String
Dim wb As Object
Dim ws As Object
Dim i As Integer
Dim MyDB As String
Dim Portfolio As String
Dim Begindate As Date
Application.ScreenUpdating = False
Rem 清除记录
Sheets("Sheet2").Select
Selection.AutoFilter
Range("B6").Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlDown)).Select
Selection.ClearContents
Rem 参数赋值
Portfolio = Cells(1, 2)
If Cells(1, 14) = "期初持仓" Then
Begindate = Cells(1, 10)
Else
Begindate = Cells(1, 12)
End If
Sector = Cells(1, 5)
Analyst = Cells(1, 8)
'Sheets("Sheet4").Select
'[e:e].Find(Begindate).Select
'i = Selection.Row()
'Nextdate = Cells(i + 1, 5)
Sheets("Sheet1").Select
Range("A2").Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlDown)).Select
Selection.ClearContents
Rem 数据加载
' 数据库路径
MyDB = "C:\Users\LIQI\Documents\portfolio.accdb"
' 创建Connection对象并连接数据库
Set conn = CreateObject("ADODB.Connection")
conn.ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" & MyDB & ";Persist Security Info=False;"
conn.Open
' 创建Command对象
Set cmd = CreateObject("ADODB.Command")
With cmd
.ActiveConnection = conn
.CommandType = 1
.CommandText = "SELECT ID,TRADEDATE,TICKER,WEIGHT FROM Mockportfolio WHERE ID=? AND TRADEDATE = ?;"
.Parameters.Append .CreateParameter(, 8, 1, 20, Portfolio)
.Parameters.Append .CreateParameter(, 7, 1, , Begindate)
End With
' 执行查询
Set rs = CreateObject("ADODB.Recordset")
rs.Open cmd
' 导出数据到Excel工作表
Set xlApp = GetObject(, "Excel.Application")
Set wb = xlApp.ActiveWorkbook
Set ws = wb.Sheets("Sheet1")
' 将查询结果写入工作表中
ws.Range("A2").CopyFromRecordset rs
' 释放对象
rs.Close
Set rs = Nothing
[b:b].Find("").Select
i = Selection.Row()
Range(Cells(2, 3), Cells(i - 1, 3)).Select
Selection.Copy
Sheets("Sheet2").Select
Range("B5").Select
ActiveSheet.Paste
Rem 指数成分加载
If InStr(1, Cells(1, 2), "300") = 1 Then
benchmark = "CSI300"
col = 1
Else
benchmark = "CSI500"
col = 10
End If
Sheets("Sheet3").Select
' 创建Command对象
Set cmd = CreateObject("ADODB.Command")
With cmd
.ActiveConnection = conn
.CommandType = 1
.CommandText = "SELECT Ticker,Weight FROM Benchmark WHERE BenchID=? AND Tradedate = ?;"
.Parameters.Append .CreateParameter(, 8, 1, 20, benchmark)
.Parameters.Append .CreateParameter(, 7, 1, , Begindate)
End With
' 执行查询
Set rs = CreateObject("ADODB.Recordset")
rs.Open cmd
' 导出数据到Excel工作表
Set ws = wb.Sheets("Sheet3")
ws.Cells(2, col).CopyFromRecordset rs
' 释放对象
rs.Close
Set rs = Nothing
conn.Close
Set conn = Nothing
Set rng = Range(Cells(2, col + 1), Cells(501, col + 1))
rng.Value = rng.Value
Cells(2, col).Select
Range(Selection, Selection.End(xlDown)).Select
Selection.Copy
Sheets("Sheet2").Select
Cells(i + 3, 2).Select
'Cells(j - i + 5, 2).Select
ActiveSheet.Paste
Range("B5").Select
Range(Selection, Selection.End(xlDown)).Select
Application.CutCopyMode = False
ActiveSheet.Range("$B$5:$B$1005").RemoveDuplicates Columns:=1, Header:=xlNo
Rem 数据呈现
Range("$B$5:$B$1005").Find("").Select
n = Selection.Row()
Range("C5").Select
Range(Selection, Selection.End(xlToRight)).Select
Selection.AutoFill Destination:=Range(Cells(5, 3), Cells(n - 1, 14))
Range("B3:N3").Select
Selection.Copy
Range("B4:N803").Select
Selection.PasteSpecial Paste:=xlPasteFormats, Operation:=xlNone, _
SkipBlanks:=False, Transpose:=False
Application.CutCopyMode = False
Range("B5").Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlDown)).Select
ActiveWorkbook.Worksheets("Sheet2").Sort.SortFields.Clear
ActiveWorkbook.Worksheets("Sheet2").Sort.SortFields.Add2 Key:=Range(Cells(5, 4), Cells(n - 1, 4)), SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal
ActiveWorkbook.Worksheets("Sheet2").Sort.SortFields.Add2 Key:=Range(Cells(5, 5), Cells(n - 1, 5)), SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal
ActiveWorkbook.Worksheets("Sheet2").Sort.SortFields.Add2 Key:=Range(Cells(5, 7), Cells(n - 1, 7)), SortOn:=xlSortOnValues, Order:=xlDescending, DataOption:=xlSortNormal
ActiveWorkbook.Worksheets("Sheet2").Sort.SortFields.Add2 Key:=Range(Cells(5, 8), Cells(n - 1, 8)), SortOn:=xlSortOnValues, Order:=xlDescending, DataOption:=xlSortNormal
With ActiveWorkbook.Worksheets("Sheet2").Sort
.SetRange Range(Cells(5, 2), Cells(n - 1, 14))
.Header = xlGuess
.MatchCase = False
.Orientation = xlTopToBottom
.SortMethod = xlPinYin
.Apply
End With
Rem 分级展示
If Sector <> "" Then
Range("B4:n4").Select
Selection.AutoFilter
ActiveSheet.Range("$B$4:$n$999").AutoFilter Field:=3, Criteria1:=Sector
ActiveSheet.Range("$B$4:$n$999").AutoFilter Field:=5, Criteria1:=Analyst
ElseIf Analyst <> "" Then
Range("B4:n4").Select
Selection.AutoFilter
ActiveSheet.Range("$B$4:$n$999").AutoFilter Field:=5, Criteria1:=Analyst
Else
Range("B4:n4").Select
Selection.AutoFilter
End If
Cells.Select
With Selection.Interior
.PatternColorIndex = xlAutomatic
.ThemeColor = xlThemeColorDark1
.TintAndShade = 0
.PatternTintAndShade = 0
End With
Cells(1, 2).Select
Rem 分类汇总
Rem Sheets("Sheet2").Select
Rem Range("B3").Select
Rem Range(Selection, Selection.End(xlToRight)).Select
Rem Range(Selection, Selection.End(xlDown)).Select
Rem Range(Selection, Selection.End(xlDown)).Select
Rem Selection.Subtotal GroupBy:=3, Function:=xlSum, TotalList:=Array(12), _
Replace:=True, PageBreaks:=False, SummaryBelowData:=True
Application.ScreenUpdating = True
End Sub
这是我的vab代码 在导出数据到excel工作表这一段时，执行语句Set ws = wb.Sheets("Sheet1")报错。错误号91 对象变量或With块变量未设置。能帮我看看怎么改吗
|
6096ba3f04ee27feac6e960afbbca22c
|
{
"intermediate": 0.2739351987838745,
"beginner": 0.40368345379829407,
"expert": 0.3223813772201538
}
|
30,181
|
Describe how this gradio app has been created
|
4c02182a72f932b1fc1010e05f2265b0
|
{
"intermediate": 0.2956477403640747,
"beginner": 0.11358506232500076,
"expert": 0.5907672047615051
}
|
30,182
|
#include "./setup.hpp"
#include "glm/trigonometric.hpp"
#include <glm/gtc/matrix_transform.hpp>
#include <glm/gtc/quaternion.hpp>
int main() {
// init gui and imgui
dym::GUI gui(SCR_WIDTH, SCR_HEIGHT, framebuffer_size_callback, mouse_callback,
scroll_callback);
UseImGui myimgui;
myimgui.Init(gui.window, "#version 460 core");
float gamma = 1.2;
// tell stb_image.h to flip loaded texture's on the y-axis (before loading
// model).
stbi_set_flip_vertically_on_load(true);
bool setReflect = false;
// configure global opengl state
// -----------------------------
glEnable(GL_DEPTH_TEST);
// build and compile shaders
// -------------------------------
// load models' shader
dym::rdt::Shader modelShader("./shaders/model_render.vs",
"./shaders/model_render.fs");
// load luminous objects' shader
dym::rdt::Shader lightShader("./shaders/lightbox.vs",
"./shaders/lightbox.fs");
// load sky box shader
dym::rdt::Shader skyboxShader("./shaders/skybox.vs", "./shaders/skybox.fs");
// load models
// -----------
// // 1. backpack
// dym::rdt::Model ourModel("./resources/objects/backpack/backpack.obj");
// modelShader.setTexture("texture_height1", 0);
// auto bindOtherTexture = [&](dym::rdt::Shader &s) { return; };
// glm::vec3 modelScaler(1.);
// glm::vec3 initTranslater(0.);
// glm::quat initRotate(1, glm::vec3(0, 0, 0));
// // 2. nanosuit
// dym::rdt::Model ourModel("./resources/objects/nanosuit/nanosuit.obj");
// auto bindOtherTexture = [&](dym::rdt::Shader &s) { return; };
// glm::vec3 modelScaler(1.);
// glm::vec3 initTranslater(0, -10, 0);
// glm::quat initRotate(1, glm::vec3(0, 0, 0));
// 3. cerberus gun
dym::rdt::Model ourModel(
"./resources/objects/Cerberus_by_Andrew_Maximov/Cerberus_LP.FBX");
// load other textures
dym::rdt::Texture normalTex(
"./resources/objects/Cerberus_by_Andrew_Maximov/Textures/Cerberus_N.tga",
dym::rdt::TexType.normal);
dym::rdt::Texture specularTex(
"./resources/objects/Cerberus_by_Andrew_Maximov/Textures/Cerberus_M.tga",
dym::rdt::TexType.specular);
dym::rdt::Texture reflectTex("./resources/objects/Cerberus_by_Andrew_Maximov/"
"Textures/Cerberus_R.tga",
dym::rdt::TexType.height);
auto bindOtherTexture = [&](dym::rdt::Shader &s) {
s.setTexture("texture_normal1", normalTex.id);
s.setTexture("texture_specular1", specularTex.id);
s.setTexture("texture_height1", reflectTex.id);
};
setReflect = true;
glm::vec3 modelScaler(0.05);
glm::vec3 initTranslater(0);
glm::quat initRotate = glm::quat(glm::radians(glm::vec3(0, 90, 0))) *
glm::quat(glm::radians(glm::vec3(-90, 0, 0)));
// moving light Cube
// -----------------
dym::rdo::Cube lightCube;
// set Material parameter
// ----------------------
dym::rdt::Material mat({1.0, 1.0, 1.0}, {1.0, 1.0, 1.0}, {0.5, 0.5, 0.5},
32.);
glm::vec3 F0(0.04);
dym::rdt::PoLightMaterial lmat({1.0, 1.0, 1.0}, {1.0, 1.0, 1.0},
{1.0, 1.0, 1.0}, 1.0, 0.045, 0.0075);
// load skyBox
// -----------------
// SkyBox Texture
std::vector<std::string> faces{"right.jpg", "left.jpg", "top.jpg",
"bottom.jpg", "front.jpg", "back.jpg"};
for (auto &face : faces)
face = "./resources/textures/skybox/" + face;
// load skyBox
dym::rdo::SkyBox skybox;
skybox.loadCubeTexture(faces);
float skylightIntensity = 1.0;
// draw in wireframe
// glPolygonMode(GL_FRONT_AND_BACK, GL_LINE);
// shared projection matrix for all shader
// ---------------------------------------------
dym::rdt::UniformBuffer proj_ubuffer(sizeof(glm::mat4) * 2, 0);
proj_ubuffer.bindShader(modelShader, "Object");
proj_ubuffer.bindShader(skyboxShader, "Object");
proj_ubuffer.bindShader(lightShader, "Object");
// time recorder
// -------------
int i = 0;
camera.Position = {0, 0, 20};
camera.MouseSensitivity = 0.01;
// set lightCube position and rotate
// ---------------------------------------
lmat.position = {10, 0, 0};
glm::quat lightR(glm::radians(glm::vec3(0, 2, 0)));
// NOTE: you can use qprint to check quaterion's value
qprint(lightR.w, lightR.x, lightR.y, lightR.z);
// render loop
// -----------
gui.update([&]() {
// per-frame time logic
// --------------------
float currentFrame = static_cast<float>(glfwGetTime());
deltaTime = currentFrame - lastFrame;
lastFrame = currentFrame;
// accept and process all keyboard and mouse input
// ----------------------------
processInput(gui.window);
// mygui update
myimgui.Update();
// render imgui
ImGuiContents(mat, lmat, skylightIntensity, gamma, F0);
// render
// ------
// TODO: use gl api to clear framebuffer and depthbuffer
// TODO: light position rotate
// use quat lightR to rotate lightbox
lmat.position = lmat.position;
// TODO: create projection matrix
// use glm to create projection and view matrix
glm::mat4 projection;
glm::mat4 view = camera.GetViewMatrix();
// load projection and view into shaders' uniformBuffer
proj_ubuffer.use();
proj_ubuffer.setMat4(0, projection);
proj_ubuffer.setMat4(1, view);
proj_ubuffer.close();
// TODO: calculate model transform matrix
// rotate: convert initRotate to glm::mat4
glm::mat4 R;
// translate: convert initTranslater to glm::mat4
glm::mat4 T;
// scale: convert modelScaler to glm::mat4
glm::mat4 S;
// we don's need any shear in our experiment
// load all value we need into shader
auto setmodelShader = [&](dym::rdt::Shader &s, dym::rdt::Mesh &m) {
s.use();
// TODO: calculate the model transformation matrix
// S*T*R? R*S*T? etc. Think about it and then fill in your answer.
s.setMat4("model", glm::mat4(1.f));
s.setVec3("viewPos", camera.Position);
s.setMaterial("material", mat);
s.setLightMaterial("light", lmat);
s.setTexture("skybox", skybox.texture);
s.setFloat("skylightIntensity", skylightIntensity);
bindOtherTexture(s);
s.setFloat("gamma", gamma);
s.setVec3("F0", F0);
s.setBool("existHeigTex", m.textures.size() == 4 || setReflect);
};
// draw model
ourModel.Draw([&](dym::rdt::Mesh &m) -> dym::rdt::Shader & {
setmodelShader(modelShader, m);
return modelShader;
});
// load light value and draw light object
lightShader.use();
lightShader.setMat4("model", glm::mat4(1.f));
lightShader.setVec3("lightPos", lmat.position);
lightShader.setVec3("lightColor", lmat.ambient);
// draw
lightCube.Draw(lightShader);
// load skybox value and draw skybox
skyboxShader.use();
skyboxShader.setTexture("skybox", skybox.texture);
skyboxShader.setVec3("offset", camera.Position);
// draw
skybox.Draw(skyboxShader);
// render gui
// ----------
myimgui.Render();
});
// close imgui
myimgui.Shutdown();
// after main end, GUI will be closed by ~GUI() automatically.
return 0;
}
template <typename MatType, typename LightMatType>
void ImGuiContents(MatType &mat, LightMatType &lMat, float &skylightlevel,
float &gamma, glm::vec3 &F0) {
ImGui::Begin("Settings");
if constexpr (false)
ImGui::ShowDemoWindow();
ImGui::Text("Object's Material Settings");
ImGui::SliderFloat("objmat.ambient.r", &(mat.ambient[0]), 0, 1,
"ambient.r = %.2f");
ImGui::SliderFloat("objmat.ambient.g", &(mat.ambient[1]), 0, 1,
"ambient.g = %.2f");
ImGui::SliderFloat("objmat.ambient.b", &(mat.ambient[2]), 0, 1,
"ambient.b = %.2f");
ImGui::SliderFloat("objmat.diffuse.x", &(mat.diffuse[0]), 0, 1,
"diffuse.x = %.2f");
ImGui::SliderFloat("objmat.diffuse.y", &(mat.diffuse[1]), 0, 1,
"diffuse.y = %.2f");
ImGui::SliderFloat("objmat.diffuse.z", &(mat.diffuse[2]), 0, 1,
"diffuse.z = %.2f");
ImGui::SliderFloat("objmat.specular.x", &(mat.specular[0]), 0, 1,
"specular.x = %.2f");
ImGui::SliderFloat("objmat.specular.y", &(mat.specular[1]), 0, 1,
"specular.y = %.2f");
ImGui::SliderFloat("objmat.specular.z", &(mat.specular[2]), 0, 1,
"specular.z = %.2f");
ImGui::SliderFloat("F0.x", &(F0[0]), 0, 1, "F0.x = %.2f");
ImGui::SliderFloat("F0.y", &(F0[1]), 0, 1, "F0.y = %.2f");
ImGui::SliderFloat("F0.z", &(F0[2]), 0, 1, "F0.z = %.2f");
ImGui::SliderFloat("shininess", &(mat.shininess), 0, 1, "shininess = %.2f");
ImGui::SliderFloat("skylightIntensity", &(skylightlevel), 0, 5,
"intensity = %.2f");
ImGui::Text("Light Settings");
ImGui::SliderFloat("light.ambient。r", &(lMat.ambient[0]), 0, 1,
"ambient.r = %.2f");
ImGui::SliderFloat("light.ambient。g", &(lMat.ambient[1]), 0, 1,
"ambient.g = %.2f");
ImGui::SliderFloat("light.ambient。b", &(lMat.ambient[2]), 0, 1,
"ambient.b = %.2f");
ImGui::SliderFloat("light.diffuse.x", &(lMat.diffuse[0]), 0, 1,
"diffuse.x = %.2f");
ImGui::SliderFloat("light.diffuse.y", &(lMat.diffuse[1]), 0, 1,
"diffuse.y = %.2f");
ImGui::SliderFloat("light.diffuse.z", &(lMat.diffuse[2]), 0, 1,
"diffuse.z = %.2f");
ImGui::SliderFloat("light.specular.x", &(lMat.specular[0]), 0, 1,
"specular.x = %.2f");
ImGui::SliderFloat("light.specular.y", &(lMat.specular[1]), 0, 1,
"specular.y = %.2f");
ImGui::SliderFloat("light.specular.z", &(lMat.specular[2]), 0, 1,
"specular.z = %.2f");
ImGui::SliderFloat("gamma", &(gamma), 1, 3, "gamma = %.2f");
ImGui::Text("Application average %.3f ms/frame (%.1f FPS)",
1000.0f / ImGui::GetIO().Framerate, ImGui::GetIO().Framerate);
ImGui::End();
}这是一段不完整的OpenGL的main代码，要求补全的地方在todo下面，请补全所有的todo
|
c25d0348f9ede21bf74d2caffac5d5b5
|
{
"intermediate": 0.32380858063697815,
"beginner": 0.5282723307609558,
"expert": 0.14791908860206604
}
|
30,183
|
error: sh -c '/Applications/Xcode.app/Contents/Developer/usr/bin/xcodebuild -sdk /Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX.sdk -find simctl 2> /dev/null' failed with exit code 16384: (null) (errno=Invalid argument)
|
75eeef7a25ea4fc3d3943ce3b417f91c
|
{
"intermediate": 0.4776902496814728,
"beginner": 0.28772878646850586,
"expert": 0.23458099365234375
}
|
30,184
|
I want to make a program which can make validation of string. Given a string 's' containing just the characters '(', ')', '{', '}', '[' and ']', it must determine if the input string is valid (Every close bracket has a corresponding open bracket of the same type, Open brackets must be closed by the same type of brackets and etc). Help me without Code. I'm going to use std::stack or std::queue
|
18cd3d361731d17db4e8d2a6e940f99b
|
{
"intermediate": 0.6459141969680786,
"beginner": 0.06889397650957108,
"expert": 0.2851918041706085
}
|
30,185
|
Write python code to create and save yaml file python
|
9bdc497b49bceab798283e8a3a04db23
|
{
"intermediate": 0.4279123842716217,
"beginner": 0.24954713881015778,
"expert": 0.3225405514240265
}
|
30,186
|
you are an expert in python. use best practices and refactor, find and fix all the bugs in the following code
|
5e170b7d9fea179ca78daabcef2167aa
|
{
"intermediate": 0.43240463733673096,
"beginner": 0.3170718550682068,
"expert": 0.2505234479904175
}
|
30,187
|
how change texture in gui node wia Lua 5.1 in Defold?
|
c0ed4faf42b00b060455e46e8199f752
|
{
"intermediate": 0.5079634189605713,
"beginner": 0.22342373430728912,
"expert": 0.2686128318309784
}
|
30,188
|
Create yaml file where each of these keys ['ABA_ROUTING_NUMBER', 'CREDIT_CARD', 'CRYPTO', 'DATE_TIME', 'EMAIL_ADDRESS', 'ES_NIF', 'IP_ADDRESS', 'IT_DRIVER_LICENSE', 'IT_FISCAL_CODE', 'IT_IDENTITY_CARD', 'IT_PASSPORT', 'IT_VAT_CODE', 'MEDICAL_LICENSE', 'PHONE_NUMBER', 'SG_NRIC_FIN', 'UK_NHS', 'URL', 'US_BANK_NUMBER', 'US_DRIVER_LICENSE', 'US_ITIN', 'US_PASSPORT', 'US_SSN', 'AU_ABN', 'AU_ACN', 'AU_TFN', 'AU_MEDICARE', 'IN_PAN'] will have value "reg_exp" and those keys ["PERSON", "ADDRESS", "ORGANISATION"] will "neural_network" value
|
238d45f75c07fcb2a5429824151ef3b3
|
{
"intermediate": 0.24713771045207977,
"beginner": 0.1728375256061554,
"expert": 0.580024778842926
}
|
30,189
|
I have XML backup file of Auditory Brainstem Response(ABR) which is extracted from Interacoustics EP25 I want to reconstruct the waves with python, what I have to do
|
894bf09e72a3ef25f67bbaec46a77830
|
{
"intermediate": 0.48186731338500977,
"beginner": 0.16478665173053741,
"expert": 0.3533460199832916
}
|
30,190
|
Explain for loop for a 10 years
|
3e1edac70431dae381a42d2eb9465bd5
|
{
"intermediate": 0.19499534368515015,
"beginner": 0.6326320171356201,
"expert": 0.17237268388271332
}
|
30,191
|
When I do the following, Hibernate returns an object of type Basket, which has a List<Kiwi> in it, but unlike the one I persisted, it only has one element in it instead of two.:
List<Basket> Baskets = HibernateUtil.getSessionFactory().openSession().createSelectionQuery("FROM Basket", Basket.class).getResultList();
Concisely state a sequence of things I could be doing wrong and how to fix those issues.
|
b26f0a6813e70d779cdfcc97cd5437ed
|
{
"intermediate": 0.7233239412307739,
"beginner": 0.15140187740325928,
"expert": 0.1252741515636444
}
|
30,192
|
On linux I am using steam to use steam link on a google tv stick. I only get a mouse pointer on x11 but when using games in fullscreen the edges of the picture flicker every now and then and I see a glimpse of my desktop when it happens. Any ideas on how to fix.
|
c030a1cc92a8b421490f4dbab9382b54
|
{
"intermediate": 0.38031330704689026,
"beginner": 0.3310469090938568,
"expert": 0.28863975405693054
}
|
30,193
|
I need a .bash script that when ran again runs a different script when clicked. Like a toggle.
|
0c7b647241f7577b3ba183fcd9f5a254
|
{
"intermediate": 0.3651658594608307,
"beginner": 0.24546846747398376,
"expert": 0.38936561346054077
}
|
30,194
|
I have an array with around 30 object. Each array item have the structure like this: {
"date": "Jun 01,2023",
"available": "24",
"submitted": "0",
"type": "missing",
"locked": false,
"confirmed": false,
"entries": [],
"__metadata": {
"type": "sap.ibso.aiib.cas.services.timeentry.TimeEntryService.TimeEntryQueryItem"
},
"edit": false
}
|
8fa4503075186c0e6e50a7ded501c0ee
|
{
"intermediate": 0.2995811402797699,
"beginner": 0.25775277614593506,
"expert": 0.4426661729812622
}
|
30,195
|
Rewrite it using ternary operatpr instead of if-else: if (brackets.empty())
{
return true;
}
else
{
return false;
}
|
90953c79d1a1753326daf5b0c9b43247
|
{
"intermediate": 0.22365951538085938,
"beginner": 0.5895904898643494,
"expert": 0.18674997985363007
}
|
30,196
|
def merge(li, left, mid, right, k):
i = left
j = mid + 1
t = []
while i <= mid and j <= right:
m = li[i]
n = li[j]
if m[k] <= n[k]:
t.append(m)
i += 1
else:
t.append(n)
j += 1
while i <= mid:
t.append(li[i])
i += 1
while j <= right:
t.append(li[j])
j += 1
li[left: right+1] = t
def merge_sort(li, left, right, i):
if left < right:
mid = (left + right) // 2
merge_sort(li, left, mid, i)
merge_sort(li, mid + 1, right, i)
merge(li, left, mid, right, i)
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == ‘U’:
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
merge_sort(playersU, 0, len(playersU) - 1, 0)
merge_sort(playersD, 0, len(playersD) - 1, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
merge_sort(players, 0, len(players) - 1, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])对这个程序进行优化，使它能够处理超大的数字
|
403e8b02015858c65cb408c56590cb67
|
{
"intermediate": 0.21055707335472107,
"beginner": 0.5585074424743652,
"expert": 0.23093552887439728
}
|
30,197
|
def heap_sort(arr, k):
n = len(arr)
for i in range(n // 2 - 1, -1, -1):
heapify(arr, n, i, k)
for i in range(n - 1, 0, -1):
arr[0], arr[i] = arr[i], arr[0]
heapify(arr, i, 0, k)
def heapify(arr, n, i, k):
largest = i
left = 2 * i + 1
right = 2 * i + 2
if left < n and arr[left][k] > arr[largest][k]:
largest = left
if right < n and arr[right][k] > arr[largest][k]:
largest = right
if largest != i:
arr[i], arr[largest] = arr[largest], arr[i]
heapify(arr, n, largest, k)
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == 'U':
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
heap_sort(playersU, 0)
heap_sort(playersD, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
heap_sort(players, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])对这个程序进行优化，使它能处理极大的数字n
|
02ed65f10a12a7a83f5368496702f6e5
|
{
"intermediate": 0.3082702159881592,
"beginner": 0.3523118793964386,
"expert": 0.3394179344177246
}
|
30,198
|
def quick_sort(arr, low, high, k):
if low < high:
pivot_index = partition(arr, low, high, k)
quick_sort(arr, low, pivot_index - 1, k)
quick_sort(arr, pivot_index + 1, high, k)
def partition(arr, low, high, k):
pivot = arr[high][k]
i = low - 1
for j in range(low, high):
if arr[j][k] <= pivot:
i += 1
arr[i], arr[j] = arr[j], arr[i]
arr[i + 1], arr[high] = arr[high], arr[i + 1]
return i + 1
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == 'U':
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
quick_sort(playersU, 0, len(playersU) - 1, 0)
quick_sort(playersD, 0, len(playersD) - 1, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
quick_sort(players, 0, len(players) - 1, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])请优化处理该程序，使它能处理超大量级的数字
|
750ede9aa7b82295a063e2055240c1c1
|
{
"intermediate": 0.37411341071128845,
"beginner": 0.3997129201889038,
"expert": 0.22617362439632416
}
|
30,199
|
How do I get rid of duplicates in a List in Java?
|
f98904186ac264a88f94255f5dfe6ff5
|
{
"intermediate": 0.6150795221328735,
"beginner": 0.14799416065216064,
"expert": 0.23692630231380463
}
|
30,200
|
get the number of model parameters load with torch.jit.load
|
4ae2c46549fa2fe33cd1ba01130f49f6
|
{
"intermediate": 0.33914077281951904,
"beginner": 0.18639424443244934,
"expert": 0.4744649827480316
}
|
30,201
|
How to passing parameter hiddenly in SAPUI5. I don't want the parameter to be shown in URL
|
112658ef02ae542e97b7b7770d513e03
|
{
"intermediate": 0.5047780275344849,
"beginner": 0.1716231256723404,
"expert": 0.32359883189201355
}
|
30,202
|
как сделать, чтобы в строке еще высвечивалось поле статус? <option value="${staff.id}" <c:if test="${staff.id == searchFilter.id}">selected</c:if>>${staff.fio}</option>
|
34c63f0fd64c8aec2e4ca24ae157565d
|
{
"intermediate": 0.29591843485832214,
"beginner": 0.3528409004211426,
"expert": 0.35124072432518005
}
|
30,203
|
def quick_sort(arr, low, high, k):
if low < high:
pivot_index = partition(arr, low, high, k)
quick_sort(arr, low, pivot_index - 1, k)
quick_sort(arr, pivot_index + 1, high, k)
def partition(arr, low, high, k):
pivot = arr[high][k]
i = low - 1
for j in range(low, high):
if arr[j][k] <= pivot:
i += 1
arr[i], arr[j] = arr[j], arr[i]
arr[i + 1], arr[high] = arr[high], arr[i + 1]
return i + 1
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == 'U':
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
quick_sort(playersU, 0, len(playersU) - 1, 0)
quick_sort(playersD, 0, len(playersD) - 1, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
quick_sort(players, 0, len(players) - 1, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])改进它使它在面对百万级的n时也能有较好的表现
|
28b25ce2b13ce13a08dbf015863549b5
|
{
"intermediate": 0.2762751281261444,
"beginner": 0.46240413188934326,
"expert": 0.2613207697868347
}
|
30,204
|
def quick_sort(arr, low, high, k):
if low < high:
pivot_index = partition(arr, low, high, k)
quick_sort(arr, low, pivot_index - 1, k)
quick_sort(arr, pivot_index + 1, high, k)
def partition(arr, low, high, k):
pivot = arr[high][k]
i = low - 1
for j in range(low, high):
if arr[j][k] <= pivot:
i += 1
arr[i], arr[j] = arr[j], arr[i]
arr[i + 1], arr[high] = arr[high], arr[i + 1]
return i + 1
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == ‘U’:
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
quick_sort(playersU, 0, len(playersU) - 1, 0)
quick_sort(playersD, 0, len(playersD) - 1, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
quick_sort(players, 0, len(players) - 1, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])按下述内容，改进它使它在面对百万级的n时也能有较好的表现
The current implementation of the code is not efficient when dealing with large input sizes. Here are a few improvements that can be made to optimize the code:
1. Use a more efficient sorting algorithm: The current implementation uses the Quick Sort algorithm. While Quick Sort is generally fast, it has a worst-case time complexity of O(n^2) which will be inefficient for large input sizes. Consider using a more efficient sorting algorithm like Merge Sort or Heap Sort which have a worst-case time complexity of O(nlogn).
2. Use a better pivot selection strategy: The current implementation always selects the last element as the pivot. This can lead to inefficient partitioning, especially when the input is already partially sorted or reverse sorted. Consider using a better pivot selection strategy like choosing the median of three random elements to minimize the chance of inefficient partitioning.
3. Avoid unnecessary comparisons: In the determine_final_hp function, nested loops are used to compare all player combinations. It is possible to optimize this by avoiding unnecessary comparisons. For example, once a player from playersD defeats a player from playersU, there is no need to continue checking that defeated player against the remaining players from playersU. This can be achieved by breaking out of the inner loop once a defeat occurs.
4. Use a data structure to store player indices instead of sorting an entire array: Instead of sorting the entire players array using the third index, you can use a data structure like a priority queue or a balanced binary search tree to efficiently keep track of the indices while sorting.
By implementing these improvements, the code will have better performance and should be able to handle larger input sizes more efficiently.
|
981344739f39ff249e6de025c17f8ed9
|
{
"intermediate": 0.321158230304718,
"beginner": 0.34468019008636475,
"expert": 0.334161639213562
}
|
30,205
|
def quick_sort(arr, low, high, k):
if low < high:
pivot_index = partition(arr, low, high, k)
quick_sort(arr, low, pivot_index - 1, k)
quick_sort(arr, pivot_index + 1, high, k)
def partition(arr, low, high, k):
pivot = arr[high][k]
i = low - 1
for j in range(low, high):
if arr[j][k] <= pivot:
i += 1
arr[i], arr[j] = arr[j], arr[i]
arr[i + 1], arr[high] = arr[high], arr[i + 1]
return i + 1
def determine_final_hp(playerU, playerD):
for i in range(len(playerD)):
for j in range(len(playerU)):
k = len(playerU) - j - 1
playeri = playerD[i]
playerj = playerU[k]
if playeri[0] >= playerj[0] and playeri[1] > 0 and playerj[1] > 0:
if playeri[1] < playerj[1]:
playeri[1] = 0
playerj[1] -= 1
elif playeri[1] > playerj[1]:
playerj[1] = 0
playeri[1] -= 1
else:
playeri[1] = 0
playerj[1] = 0
return playerU, playerD
n = int(input())
playersU = []
playersD = []
players = []
for i in range(n):
floor, hp, direction = input().split()
if direction == ‘U’:
playersU.append([int(floor), int(hp), i])
else:
playersD.append([int(floor), int(hp), i])
quick_sort(playersU, 0, len(playersU) - 1, 0)
quick_sort(playersD, 0, len(playersD) - 1, 0)
playersU, playersD = determine_final_hp(playersU, playersD)
for u in range(len(playersU)):
players.append(playersU[u])
for d in range(len(playersD)):
players.append(playersD[d])
quick_sort(players, 0, len(players) - 1, 2)
for i in range(len(players)):
player = players[i]
if player[1] != 0:
print(player[1])按下述内容，改进它使它在面对百万级的n时也能有较好的表现
|
fca862c377f5cfdab3c997cfb9e36e47
|
{
"intermediate": 0.1914009153842926,
"beginner": 0.5659401416778564,
"expert": 0.24265889823436737
}
|
30,206
|
I would like a conditional format code that checks the following:
If date is more than 4 months from todays date, then
|
794fec000c5f6037e253870f3ace7b2f
|
{
"intermediate": 0.3994099199771881,
"beginner": 0.2027474045753479,
"expert": 0.3978427052497864
}
|
30,207
|
I want to get a shader file from hanmen. help we write something
|
6282870fc7f93b6a43cc0e03c09e3f8c
|
{
"intermediate": 0.4872012138366699,
"beginner": 0.2330477237701416,
"expert": 0.2797510325908661
}
|
30,208
|
Delete entities for prediction from spacy nlp
|
c084bff6a50d24b80b5ebfe93a91d80e
|
{
"intermediate": 0.24199838936328888,
"beginner": 0.19957634806632996,
"expert": 0.5584253072738647
}
|
30,209
|
find /path/to/directory -type f -name “*.tgz” -exec sh -c 'dir=$(dirname “{}”); tar -xzf “{}” -C
|
6ca0dd2c49a7f16b26e6511b1de0d09d
|
{
"intermediate": 0.3593088984489441,
"beginner": 0.2661334276199341,
"expert": 0.37455764412879944
}
|
30,210
|
find ./ -type f -name "*.tgz" -exec sh -c 'tar -xzf "$0" -C {}' \;
tar (child): sh: Cannot open: No such file or directory
|
31091ac347e4da6ebc0b09fc7ed378c8
|
{
"intermediate": 0.35178714990615845,
"beginner": 0.37624403834342957,
"expert": 0.2719687223434448
}
|
30,211
|
in pandas, in several columns, replace the values with 1 if the original value is larger than 1
|
3d5e47a9f9ddd67e7e66e17d1080b6a0
|
{
"intermediate": 0.3232724368572235,
"beginner": 0.21997635066509247,
"expert": 0.4567512571811676
}
|
30,212
|
for monetary value, e.g. sales, please make sure the currency symbols are displayed dynamically in the title of the visual depending on the selected country. If all countries are select - no symbol displayed.
e.g. UK → Sales (£)
DE → Sales (€)
make sure filters are properly set.
In power bi report
|
b7f0105584a59909ee40459e4115e98c
|
{
"intermediate": 0.3039786219596863,
"beginner": 0.26115742325782776,
"expert": 0.43486395478248596
}
|
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