row_id
int64 0
48.4k
| init_message
stringlengths 1
342k
| conversation_hash
stringlengths 32
32
| scores
dict |
|---|---|---|---|
5,723
|
hi
|
2465203cf4ac38de0b64ae54299d6b9f
|
{
"intermediate": 0.3246487081050873,
"beginner": 0.27135494351387024,
"expert": 0.40399640798568726
}
|
5,724
|
hi
|
9b2a45726d0f628eece3e80696b6a40a
|
{
"intermediate": 0.3246487081050873,
"beginner": 0.27135494351387024,
"expert": 0.40399640798568726
}
|
5,725
|
This code is for predicting about covid-19 infection from a cough recording
it's taking about 21 seconds with a dataset of 12 wav files
can it be faster ?
|
ecd9bcfd61312f8dbe11bf819fdadcf9
|
{
"intermediate": 0.19804123044013977,
"beginner": 0.08846905827522278,
"expert": 0.7134897112846375
}
|
5,726
|
i want to read a date and hour from a file named data.nimb and execute some commands if the date and hour is older then 2 hours in bash
data.nimb:
ccab9885-450f-496b-8906-eb721b55655d
11/05/2023 20:50:19
|
8368e36e1ef339d7124a71473ffb1f35
|
{
"intermediate": 0.5344354510307312,
"beginner": 0.18539850413799286,
"expert": 0.28016605973243713
}
|
5,727
|
hie
|
a991d03ad6dbba96302664b988526329
|
{
"intermediate": 0.3316100239753723,
"beginner": 0.3096539378166199,
"expert": 0.3587360084056854
}
|
5,728
|
i want to read a date and hour from a file named data.nimb and execute some commands if the date and hour is older then 2 hours in bash
data.nimb:
ccab9885-450f-496b-8906-eb721b55655d
11/05/2023 20:50:19
|
8d5f57600a7e1aae44845f58ab0b78f9
|
{
"intermediate": 0.5344354510307312,
"beginner": 0.18539850413799286,
"expert": 0.28016605973243713
}
|
5,729
|
Create a wordpress plugin that will scrape the price of a specific item from a given website using a web scraping library like BeautifulSoup, and then save the extracted price in a text file. The program should: Accept the URL of the website ([Website URL]), the HTML element containing the item's price ([HTML Element]), and the name of the text file ([Text File Name]) as command-line arguments or user inputs.
Make an HTTP request to the provided URL ([Website URL]) to fetch the web page content. Parse the fetched content using BeautifulSoup to find the HTML element ([HTML Element]) containing the item's price. Extract the price value from the identified element. Save the extracted price value into the specified text file ([Text File Name]). Include proper error handling and input validation to ensure the program runs smoothly. Text File Name = Put the name of the file and the exact time of the system in 24-hour format for the moment you extracted the information
website URL = https://www.digikala.com/product/dkp-6358900/%D8%A7%D9%84%DA%A9%D8%AA%D8%B1%D9%88%D8%AF-%D8%AC%D9%88%D8%B4%DA%A9%D8%A7%D8%B1%DB%8C-%D8%A2%D9%85%D8%A7-%D9%85%D8%AF%D9%84-a-25-%D9%88%D8%B2%D9%86-300-%DA%AF%D8%B1%D9%85/
HTML Element Selector=#__next > div.h-100.d-flex.flex-column.bg-000.ai-center > div.grow-1.bg-000.d-flex.flex-column.w-100.ai-center.shrink-0 > div.grow-1.bg-000.d-flex.flex-column.w-100.ai-center.styles_BaseLayoutDesktop__content__hfHD1.container-4xl-w > div.px-5-lg > div.d-flex.flex-column.flex-row-lg.styles_PdpProductContent__sectionBorder--mobile__J7liJ > div.grow-1.w-min-0 > div.styles_InfoSection__leftSection__0vNpX > div.d-flex.flex-column.mr-3-lg.mb-3-lg.gap-y-2-lg.styles_InfoSection__buyBoxContainer__3nOwP > div.available_InfoSectionBuyboxAvailable__main__IyGCL.radius-medium-lg.border-200-lg.bg-000.styles_InfoSection__buybox__tknJ3 > div.pos-relative.w-full.w-auto-lg.px-4-lg.pb-4-lg > div > div > div:nth-child(1) > div.d-flex.jc-start.mr-auto.text-h3 > div.d-flex.ai-center.jc-end.w-100 > span
|
b6c923171bf0b071a69e4f9a9e512488
|
{
"intermediate": 0.5669883489608765,
"beginner": 0.2118701934814453,
"expert": 0.2211415022611618
}
|
5,730
|
I want to extract images from a folder which consists of 600 word documents. Some of the documents are of doc format and the other are of docx. I want to extract images from all those documents. Can you give me some Python code?
|
413295e7c4f636948e4381b1490b20ad
|
{
"intermediate": 0.45364639163017273,
"beginner": 0.31507283449172974,
"expert": 0.23128077387809753
}
|
5,731
|
I have two tables loaded in qliksense. one table has exception key,status,line of business and exception raised date. second table has exception key, status, from date, do date. I want to join these two tables in qliksense based on exception key and status.
|
45d741a4ad02aeec3b301dcd346d4d7b
|
{
"intermediate": 0.37487339973449707,
"beginner": 0.284534215927124,
"expert": 0.34059232473373413
}
|
5,732
|
@Composable
fun FirstScreen(modifier: Modifier = Modifier) {
Scaffold(
topBar = {
TopAppBar(
title = {
Text("First Screen")
}
)
},
content = { padding ->
Column(
modifier = modifier.padding(padding)
) {
// Add your UI components here
// Text(text = "This is the first screen")
MusicCategoriesScreen(categories = )
}
}
)
}-> i want to put MusicCategoriesScreen composable inside of my FirstScreen Composable. package com.example.musicapp.Interface
import androidx.compose.foundation.Image
import androidx.compose.foundation.clickable
import androidx.compose.foundation.layout.*
import androidx.compose.foundation.lazy.LazyColumn
import androidx.compose.foundation.lazy.items
import androidx.compose.material.MaterialTheme
import androidx.compose.material.Text
import androidx.compose.runtime.*
import androidx.compose.ui.Alignment
import androidx.compose.ui.Modifier
import androidx.compose.ui.layout.ContentScale
import androidx.compose.ui.unit.dp
import coil.compose.rememberImagePainter
import com.example.musicapp.Data.Category
@Composable
fun MusicCategoriesScreen(
categories: List<Category>,
onCategorySelected: (Category) -> Unit = {},
modifier: Modifier = Modifier
) {
LazyColumn(
modifier = modifier,
contentPadding = PaddingValues(16.dp)
) {
items(categories) { category ->
CategoryItem(category) {
onCategorySelected(category)
}
}
}
}
@Composable
private fun CategoryItem(category: Category, onClick: () -> Unit) {
Column(
modifier = Modifier
.clickable(onClick = onClick)
.fillMaxWidth(),
horizontalAlignment = Alignment.CenterHorizontally
) {
val painter = rememberImagePainter(
data = category.picture_medium
)
Image(
painter = painter,
contentDescription = category.name,
contentScale = ContentScale.Crop,
modifier = Modifier
.fillMaxWidth()
.height(120.dp)
)
Text(
text = category.name,
modifier = Modifier
.padding(top = 8.dp)
.align(Alignment.CenterHorizontally),
style = MaterialTheme.typography.body2,
color = MaterialTheme.colors.onSurface
)
}
}-> this is my MusicCategoriesScreen composable,package com.example.musicapp.ViewModel
import android.util.Log
import androidx.lifecycle.ViewModel
import androidx.lifecycle.viewModelScope
import com.example.musicapp.Data.Category
import com.example.musicapp.Data.DeezerRepository
import kotlinx.coroutines.flow.MutableStateFlow
import kotlinx.coroutines.flow.StateFlow
import kotlinx.coroutines.launch
class CategoriesViewModel : ViewModel() {
private val deezerRepository = DeezerRepository()
private val _categories = MutableStateFlow<List<Category>>(emptyList())
val categories: StateFlow<List<Category>>
get() = _categories
init {
fetchCategories()
}
private fun fetchCategories() {
viewModelScope.launch {
try {
val categories = deezerRepository.getCategories()
_categories.value = categories
} catch (e: Exception) {
Log.e("CategoriesViewModel", "Failed to fetch categories: ${e.message}")
}
}
}
// public function to fetch categories
fun refreshCategories() {
fetchCategories()
}
}-> this is my viewModel,package com.example.musicapp.Data
data class Category(
val id: Int,
val name: String,
val picture_medium: String
)-> this is Category class. What kind of changes i should do. How to achieve show me because right now in the FirstScreen composable i can not use MusicCategoriesScreen composable correctly
|
39649d0f3001c1845cd2ad31f5c80120
|
{
"intermediate": 0.3833932876586914,
"beginner": 0.4816509783267975,
"expert": 0.1349557489156723
}
|
5,733
|
shell command look for file cmake
|
07ae69b08c55755a6e9c2f56826e4d89
|
{
"intermediate": 0.3649560213088989,
"beginner": 0.20022687315940857,
"expert": 0.4348170757293701
}
|
5,734
|
how to make sql server script print out error if it goes into a catch block
|
1d4cc84ebb14c840182ba9cd9fe37f49
|
{
"intermediate": 0.4525434076786041,
"beginner": 0.3720822036266327,
"expert": 0.17537443339824677
}
|
5,735
|
How authenticate and authorize user on remote server using active directory and Kerberos ticket obtained locally? It is better to see examples in c++ or open source projects.
|
1cb605224855246c8762dee1caf134e9
|
{
"intermediate": 0.5876492857933044,
"beginner": 0.14358897507190704,
"expert": 0.2687617540359497
}
|
5,736
|
Show me a function I can add to this code to check if one or more of the Interactable Elements: are Type: textarea. If there is one or more textarea, look for the word "zip", "Zip", "age", "Age", "year", and "Year" in the Visible Text on the web page and consider them keywords. If more than one of these keywords appear in the Visible Text on the web page, account for the order they appear and associate them with the textareas in the order they appear in the Interactable Elements. If only one appears associate it with the textarea in the Interactable Elements. Any textarea associated with "zip" or "Zip" should be filled in with the string "44833". Any textarea associated with "age" or "Age" should be filled in with the string "40". Any textarea associated with "year" or "Year" should be filled with the string "1983". Here is the code to ammend:
let v = "";
var visibleText = "";
Array.from(document.querySelectorAll('*'))
.filter(element => {
var computedStyle = window.getComputedStyle(element);
return (
element.offsetHeight > 0 &&
element.offsetWidth > 0 &&
computedStyle.display !== 'none' &&
computedStyle.visibility !== 'hidden' &&
element.tagName !== 'SCRIPT' &&
element.tagName !== 'STYLE'
);
})
.forEach(element => {
var textContent = element.innerText.trim();
if (textContent !== '' && !visibleText) {
visibleText = textContent; // Store only the first visible text
}
});
var interactableElements = document.querySelectorAll('input:not([type="hidden"]), button, textarea, select, a');
var output = "";
var count = 0;
var firstElements = {};
for (var index = 0; index < interactableElements.length; ++index) {
var element = interactableElements[index];
var elementId = element.id;
var elementType = element.type;
var elementClass = element.className;
if (!element.hidden && elementType) {
count++;
if (elementType === "submit" || elementType === "button") {
if (!isExcluded(element)) {
element.addEventListener("click", function() {
console.log(`Clicked element with ID: ${elementId}`);
});
element.click();
}
} else {
var tagName = element.tagName.toLowerCase();
if (!(tagName in firstElements) && !isExcluded(element)) {
firstElements[tagName] = true;
element.click();
}
}
var listItem = `${count}. Element ID: ${elementId}, Input Type: ${elementType}, Class: ${elementClass}`;
var associatedLabel = document.querySelector(`label[for="${elementId}"]`);
if (associatedLabel) {
var labelText = associatedLabel.innerText.trim();
listItem += `, Label Text: ${labelText}`;
}
output += listItem + "\n";
}
}
function isExcluded(element) {
var excludedKeywords = ['back', 'prev', 'previous'];
var elementId = element.id;
var elementType = element.type;
var elementClass = element.className;
return excludedKeywords.some(keyword => {
return elementId.includes(keyword) || elementClass.includes(keyword) || element.getAttributeNames().some(attrName => {
return element.getAttribute(attrName).toLowerCase().includes(keyword);
});
}) || elementType === "hidden";
}
var logStatement = `Visible Text on the web page:\n${visibleText}\n\nInteractable Elements:\n${output}`;
v = logStatement;
console.log(logStatement);
|
604013833127d83dc35bd5ad375beac3
|
{
"intermediate": 0.3301756680011749,
"beginner": 0.5369856357574463,
"expert": 0.13283875584602356
}
|
5,737
|
Use an item-based collaborative filtering
approach to recommend the Top 10
similar movies to a specific movie.
|
cd6c6fb0d614af3ef885ddd9127c212b
|
{
"intermediate": 0.1509407013654709,
"beginner": 0.16967761516571045,
"expert": 0.6793816685676575
}
|
5,738
|
golang fyne如何调用android手机摄像头扫二维码
|
b4cb1a6c17fd45c0823844c12fe10e6e
|
{
"intermediate": 0.34325486421585083,
"beginner": 0.2684347629547119,
"expert": 0.38831040263175964
}
|
5,739
|
Write a program in MIPS Assembly that solves the Pythagorean Theorem
|
9918e0931b5c34693c40344204c3fb1b
|
{
"intermediate": 0.196322500705719,
"beginner": 0.1663174331188202,
"expert": 0.6373600363731384
}
|
5,740
|
write a python code ,get input from a web page and pass to other website, and get answer from it ,copy to the first web page input
|
5ec650603614544e42e3d290c66aaec3
|
{
"intermediate": 0.35456541180610657,
"beginner": 0.23630070686340332,
"expert": 0.4091338813304901
}
|
5,741
|
ValueError: Input contains NaN, infinity or a value too large for dtype('float64').
|
44107e0103c7b409fd52246ab5dc0775
|
{
"intermediate": 0.46275436878204346,
"beginner": 0.24717827141284943,
"expert": 0.2900673449039459
}
|
5,742
|
how owuld i find the steam id3 of the curretn user logged into steam on arch linux, im trying to write a script in bash on arch linux
|
06aeefd58a9f0bddb8658d906713ade4
|
{
"intermediate": 0.5176997184753418,
"beginner": 0.26593175530433655,
"expert": 0.21636848151683807
}
|
5,743
|
**Written in MASM IRVINE32 Assembly x86 no c++ no Python etc. allowed even...
**Written in MASM IRVINE32 Assembly x86 no c++ no Python etc. allowed even if it supports** make it compilable on visual studio, put the end main and make sure that the program compiles on visual studio, make sure you add al the implementations functions. Your program will require to get 5 integers from the user. Store thesenumbers in an array. You should then display stars depending on thosenumbers. If it is between 50 and 59, you should display 5 stars, so you aredisplaying a star for every 10 points in grade. Your program will have afunction to get the numbers from the user and another function to display thestars.
|
26c78a5eaeaf6c15f03e268580f38ed1
|
{
"intermediate": 0.38654837012290955,
"beginner": 0.3430861234664917,
"expert": 0.27036547660827637
}
|
5,744
|
thêm id cho 1 tag bằng js
|
7c2e7dfae050bee8d53f0062f4bfe22a
|
{
"intermediate": 0.32363361120224,
"beginner": 0.32462477684020996,
"expert": 0.3517417013645172
}
|
5,745
|
I will provide you disassembly from a computer game that runs in MS-DOS. The game was written in C with a Watcom compiler. Some library function calls are already identified. Explain the functions I give to you and suggest names and C-language function signatures for them. Also suggest names for global values when you have enough context to do so. As I provide more information, please revise your explanations and suggestions as necessary.
FUN_00011a6b
PUSH EBP
MOV EBP,ESP
PUSH ESI
PUSH EDI
SUB ESP,0x8
PUSH 0x4d
MOV ECX,s_profile.c_00170129 = "profile.c"
MOV EBX,0x4
MOV EDX,dword ptr [EBP + Stack[0x8]]
MOV EAX,dword ptr [EBP + Stack[0x4]]
ADD EAX,0x4
CALL FUN_000a0ad9
PUSH 0x200
MOV EAX,dword ptr [EBP + Stack[0x8]]
PUSH EAX
CALL open
ADD ESP,0x8
MOV dword ptr [EBP + local_14],EAX
CMP dword ptr [EBP + local_14],-0x1
JNZ LAB_00011ab6
MOV dword ptr [EBP + local_10],0x0
JMP LAB_00011c1a
LAB_00011ab6
MOV EBX,0x2
XOR EDX,EDX
MOV EAX,dword ptr [EBP + local_14]
CALL lseek
MOV EDX,EAX
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0x88],EDX
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EAX,dword ptr [EAX + 0x88]
ADD EAX,0x400
MOV EDX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EDX + 0x8c],EAX
XOR EBX,EBX
XOR EDX,EDX
MOV EAX,dword ptr [EBP + local_14]
CALL lseek
MOV EBX,0x5e
MOV EDX,s_profile.c_00170129 = "profile.c"
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EAX,dword ptr [EAX + 0x8c]
CALL FUN_000a00af
MOV EDX,EAX
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0x84],EDX
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EAX,dword ptr [EAX + 0x84]
TEST EAX,EAX
JNZ LAB_00011b37
MOV EAX,dword ptr [EBP + local_14]
CALL __close
MOV dword ptr [EBP + local_10],0x0
JMP LAB_00011c1a
LAB_00011b37
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EBX,dword ptr [EAX + 0x88]
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EDX,dword ptr [EAX + 0x84]
MOV EAX,dword ptr [EBP + local_14]
CALL read
MOV EDX,EAX
MOV EAX,dword ptr [EBP + Stack[0x4]]
CMP EDX,dword ptr [EAX + 0x88]
JZ LAB_00011bb1
MOV EAX,dword ptr [EBP + local_14]
CALL __close
MOV EAX,dword ptr [EBP + Stack[0x4]]
CMP dword ptr [EAX + 0x84],0x0
JZ LAB_00011b81
MOV EAX,dword ptr [EBP + Stack[0x4]]
CMP dword ptr [EAX + 0x84],0x97979797
JNZ LAB_00011b83
LAB_00011b81
JMP LAB_00011ba8
LAB_00011b83
MOV EBX,0x6e
MOV EDX,s_profile.c_00170129 = "profile.c"
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EAX,dword ptr [EAX + 0x84]
CALL FUN_000a0024
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0x84],0x97979797
LAB_00011ba8
MOV dword ptr [EBP + local_10],0x0
JMP LAB_00011c1a
LAB_00011bb1
MOV EAX,dword ptr [EBP + local_14]
CALL __close
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EDX,dword ptr [EAX + 0x84]
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0x90],EDX
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0x94],0x0
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0xa0],0x0
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0xa4],0x0
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0x9c],0x0
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0xa8],0x0
MOV EAX,dword ptr [EBP + Stack[0x4]]
AND byte ptr [EAX + 0x1],0x7f
MOV dword ptr [EBP + local_10],0x1
LAB_00011c1a
MOV EAX,dword ptr [EBP + local_10]
LEA ESP=>local_c,[EBP + -0x8]
POP EDI
POP ESI
POP EBP
RET
|
2dac2d304f084392796a4421ac7eabde
|
{
"intermediate": 0.4019007980823517,
"beginner": 0.4201829731464386,
"expert": 0.17791619896888733
}
|
5,746
|
Write me the code of a program based on the description I will give you:
I am a forex trader and the strategy or trading plan based on which I trade includes various criteria.
Write me a program code so that I can use it every time I want to trade, I can tick my criteria in this program, and if the ticks were enough and reached the quorum set in the program, then the program will send this message with a give me a green tick icon and write that you are allowed to do this transaction, but if the ticks are not enough and the necessary criteria do not reach the quorum, a black cross icon will appear and write that you are not allowed to trade
Write the program in such a way that it gives me the possibility to enter different criteria and if necessary I can edit them and put a check in front of the box of that criteria so that I can activate or deactivate it.
Also, the program should have the possibility to prioritize each of the criteria based on the percentage, and the criteria that I have already assigned a higher percentage within the program, will be given more weight (for decision making that this trade has sufficient criteria or not).
|
be3627643932ed61abfbdde003e28bfa
|
{
"intermediate": 0.3614029884338379,
"beginner": 0.21626198291778564,
"expert": 0.42233505845069885
}
|
5,747
|
The UI should enable the user to choose whether to sleep, eat, drink water, or go to
bathroom. The design of the UI is up to you with python
|
48a67656984a30839644772b1d754e9c
|
{
"intermediate": 0.31096893548965454,
"beginner": 0.2895238995552063,
"expert": 0.3995071351528168
}
|
5,748
|
Laravel 10. How to switch laravel default notification model uuid to id?
|
2ca14b7ced35fedbe7754bf6787b9ee2
|
{
"intermediate": 0.38996437191963196,
"beginner": 0.21100421249866486,
"expert": 0.39903149008750916
}
|
5,749
|
Suppose I am conducting a research paper on time series data entitled “The Nexus Among Oil Price, Stock Market, and Exchange Rate During Recent Pandemic & Russia-Ukraine Crisis: Fresh Evidence from UK Economy”. Here I have taken three variables Stock Index (SI), Brent Oil Price (OP), and Exchange Rate (ER). I have taken time series data from 2014-2023 segmenting into four periods. 2014-2019 for Pre-covid Period; 2020-2021 for Covid Period; 2022-2023 for War Period and 2014-2023 for the Overall Period. My Research Questions are:
1. Does each variable have a direct influence on others?
2. Does each variable granger cause one another and does the stock market work as a mediating variable for shock transmission?
3. Is there any moderating impact of oil price on the dynamic conditional correlation (DCC) between the stock market and exchange rate?
For data analysis, I have checked other relevant literature.
For research question 1, most of them used the VAR model to check the direct influence of variables on each other. For research question 2, most of them used VAR Granger Causality and determined if the stock market transmits the shock as a mediating variable or not. I haven’t found any paper on my 3rd research question but a paper suggested a technique to address it in their future research question. I am giving their exact quotation, “The moderating effect of oil can be estimated by using the NARDL framework for studying the direct influence of OP on the DCCs between SI and ER”.
But the problem is that, for my 1st and 2nd, I can’t use the VAR model as I have autocorrelation and heteroskedasticity which I can’t remove even after log transforming or log differencing the variable. I also can’t use VECM Model either as my variables are not co-integrated from the Johansen co-integration test. Therefore give me a solution for my model. Which other econometric model can I use that takes autocorrelation and heteroskedasticity into account for my 1st and 2nd research questions as well as also give me guidelines on how to approach the analysis of my 3rd research question? I am really lost here. I don’t know how to analyze the process in R. And What about VAR-GARCH, I have seen some research paper used it. Does it suit my research question? If suited, include the R commands for VAR-GARCH too?
|
1a80eb379b2e562b5da99e14a23d314c
|
{
"intermediate": 0.37973448634147644,
"beginner": 0.296680748462677,
"expert": 0.32358476519584656
}
|
5,750
|
I need a program written in c
|
2bca2dac55108512d3c5ea622d8efcd5
|
{
"intermediate": 0.2199953943490982,
"beginner": 0.3914748728275299,
"expert": 0.3885297179222107
}
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5,751
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Laravel 10. Internal notification model uses uuid(string) as id field. How can I replace uuid with id?
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1f7bf3228bf5a1734ad8f10d19af9154
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{
"intermediate": 0.5104641914367676,
"beginner": 0.1453300565481186,
"expert": 0.34420573711395264
}
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5,752
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fastapi with sqlchemy, return the total count number of row of the table
|
7129e129e5dada486aaa78703f00e34c
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{
"intermediate": 0.7395925521850586,
"beginner": 0.11717076599597931,
"expert": 0.14323674142360687
}
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5,753
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float to upper int in python
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f6dd92a12178007cff77a3a9e6a800a5
|
{
"intermediate": 0.3279836177825928,
"beginner": 0.31362026929855347,
"expert": 0.35839614272117615
}
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5,754
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Flutter insert name into localized message how to?
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f08752ff99836e0f0af391549718149c
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{
"intermediate": 0.4132900834083557,
"beginner": 0.13787971436977386,
"expert": 0.4488302171230316
}
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5,755
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hi
|
a9cd7700875979907a954d2317a3e6a2
|
{
"intermediate": 0.3246487081050873,
"beginner": 0.27135494351387024,
"expert": 0.40399640798568726
}
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5,756
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Create a wordpress plugin that compress images
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5b6ddef8b0ef031a7bcd15171e7b1ef4
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{
"intermediate": 0.3517105281352997,
"beginner": 0.2651676535606384,
"expert": 0.3831218183040619
}
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5,757
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how can i load two impala table which has one common field name and want to join them while loading it inot qvd
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640677a7814cdcd27d6f1f36ea57bcb6
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{
"intermediate": 0.4757232367992401,
"beginner": 0.2154574990272522,
"expert": 0.30881935358047485
}
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5,758
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can I join the two tables in qliksense sheet
|
f4f47d74756fcb538ec8e832821f21b1
|
{
"intermediate": 0.2911759316921234,
"beginner": 0.20389266312122345,
"expert": 0.5049313902854919
}
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5,759
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Give me an idea of how to build simple "Train Accident Prevention Project" using Arduino Uno without relay module.I have,
6 LED bulbs
3 Buzzers
Jumper wires
Arduino Uno
4 wheels
Ultrasonic sensor(HC-SRO4)
9V battery
And I have 6 poles for 3 LEDs with Buzzers and another 3 LEDs.
|
d6a1f08304585272b4955f6e3238a9b6
|
{
"intermediate": 0.41853824257850647,
"beginner": 0.2964212894439697,
"expert": 0.28504037857055664
}
|
5,760
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以下多重网格代码在matlab中运行的结果显示误差变量err_iteration远远大于1，这与预期是不相符的，理想情况下误差应该远远小于1才对，这说明代码存在问题，请你检查并修正，然后写出完整代码并作解释，谢谢。clc
clear
close all
%设置网格尺寸和大小
N = 64;
L = 1;
h = L/N;
%u是一个N+1维的方阵，用来表示二维泊松方程的数值解
u = zeros(N+1, N+1);
% 计算真实解
x=0:h:L;
y=0:h:L;
[X, Y] = meshgrid(x, y);
u_true = sin(pi * X) .* sin(pi * Y); % 使用正确的元素乘法符，算出解析解
[X, Y] = meshgrid(x, y);
f = 2 * pi^2 * sin(pi *X).* sin(pi * Y);
error_iteration=zeros(1,1000);
for maxnum = 1:1000
u = V_xunhuan(u,f,h);
r = cancha(u,f,h);
%计算误差并记录
err=max(max(abs(u-u_true)));
error_iteration(maxnum)=err;
if max(max(abs(r))) < 0.001
break
end
end
huatu_x=1:maxnum;
huatu_y=error_iteration(1:maxnum);
figure,plot(huatu_x, huatu_y,'r-');
title(['误差随迭代次数的变化 (一共迭代: ', num2str(maxnum), '次)']);
xlabel('迭代次数');
ylabel('误差');
grid on;
function jie = V_xunhuan(jie,f,h)
% 递归v循环
%预先平滑
jie = smoothing(jie,f,h);
%算残差
r_old = cancha(jie,f,h);
%限制
r_new = xianzhi(r_old);
%算误差
e = zeros(size(r_new));
%如果网格已经达到最粗，停止递归，否则继续递归
if length(e)-1 == 2
e = smoothing(e,r_new,2*h);
else
e = V_xunhuan(e,r_new,2*h);
end
% 修正
jie = jie + yantuo(e);
%后光滑
jie = smoothing(jie,f,h);
end
function res = smoothing(phi,f,h)
N = size(phi, 1) - 1;
res = phi;
for i = 2:N
for j = 2:N
res(i, j) = (phi(i+1, j)+res(i-1, j)+phi(i, j+1)+res(i, j-1)+h^2*f(i, j))/4;
end
end
end
function res = cancha(phi,f,h)
N = size(phi, 1) - 1;
res = zeros(N+1, N+1);
res(2:N, 2:N) = f(2:N, 2:N)-(phi(1:N-1, 2:N)-2*phi(2:N, 2:N)+phi(3:N+1, 2:N)+phi(2:N, 1:N-1)-2*phi(2:N, 2:N)+phi(2:N, 3:N+1))/h^2;
end
function r_xi = xianzhi(r_cu)
N = (size(r_cu, 1) - 1) / 2;
r_xi = zeros(N+1, N+1);
for i = 2:N
for j = 2:N
%直接映射r_xi(i, j) = r_cu(2*i, 2*j);
%九点差分r_xi(i, j) = 1/16 *( r_cu(2*i-1, 2*j-1)+r_cu(2*i-1, 2*j+1)+r_cu(2*i+1, 2*j-1)+r_cu(2*i+1, 2*j+1))+2/16*(r_cu(2*i, 2*j-1)+r_cu(2*i, 2*j+1)+r_cu(2*i-1, 2*j)+r_cu(2*i+1, 2*j))+4/16*r_cu(2*i,2*j);
%五点差分
r_xi(i, j) = 2/16*(r_cu(2*i, 2*j-1)+r_cu(2*i, 2*j+1)+r_cu(2*i-1, 2*j)+r_cu(2*i+1, 2*j)) + 1/2 * r_cu(2*i, 2*j);
end
end
end
function e_xiwang = yantuo(e_cuwang)
N = (size(e_cuwang, 1) - 1) * 2; % 计算细网格的大小
e_xiwang = zeros(N + 1, N + 1); % 初始化细网格矩阵
% 对角线（单元格中心）
for i = 2:2:N
for j = 2:2:N
e_xiwang(i, j) =1/4*( e_cuwang((i+2) / 2, j / 2)+e_cuwang((i+2)/ 2, (j+2) / 2)+e_cuwang(i / 2, j / 2)+e_cuwang(i / 2, (j+2) / 2));
end
end
% 原有点
for i = 1:2:N + 1
for j = 1:2:N + 1
e_xiwang(i, j) = e_cuwang((i + 1) / 2, (j + 1) / 2);
end
end
% 横向边中点
for i = 1:2:N
for j = 2:2:N
e_xiwang(i, j) =1/2* (e_cuwang((i + 1) / 2, j / 2) + e_cuwang((i + 1) / 2,( j / 2) + 1));
end
end
% 纵向边中点
for i = 2:2:N
for j = 1:2:N
e_xiwang(i, j) = 1/2*(e_cuwang(i / 2, (j + 1) / 2) + e_cuwang((i / 2) + 1, (j + 1) / 2));
end
end
end
|
dd06172a451a3edcc78b4875e5e01125
|
{
"intermediate": 0.38867419958114624,
"beginner": 0.40835973620414734,
"expert": 0.20296604931354523
}
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5,761
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如何使用python获取以下链接的html内容：https://mp.weixin.qq.com/s/_cIMJxG4RmTY41oSo4ENPA，并将其转换为富文本，其中图片需要单独下载并替换为新的图片链接，请给出代码
|
96cf921ef448ddea18eef765a4e74f74
|
{
"intermediate": 0.32289451360702515,
"beginner": 0.3391916751861572,
"expert": 0.33791384100914
}
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5,762
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org.apache.flink.configuration
|
6ccca9dc625d1287be1a8f0b585ae17a
|
{
"intermediate": 0.3445188105106354,
"beginner": 0.2726666033267975,
"expert": 0.3828146457672119
}
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5,763
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I am unable to jkoin two tables in qliksense, it does not recognize the fields from the first table and throws error
|
341fd680822381968f337ecb9462f4f7
|
{
"intermediate": 0.4166940152645111,
"beginner": 0.23588216304779053,
"expert": 0.34742382168769836
}
|
5,764
|
y = [5, 3, 8, 6, 0, 2, 4, 3, 6, 5, 7, 5, 8, 9, 9, 3, 1] # The mean is the sum (sum()) of the datapoints divided by the number of datapoints.
# Print your result.
|
23210d11d49c5e9da9420efe037c9327
|
{
"intermediate": 0.3284180462360382,
"beginner": 0.37885916233062744,
"expert": 0.29272279143333435
}
|
5,765
|
下面这个多重网格代码在matlab里的运行结果显示误差变量ere_iteration远远大于1，这与我们期待的远远小于1完全不符，所以代码出错了，现在先将这个代码放在下面。clc
clear
close all
%设置网格尺寸和大小
N = 64;
L = 1;
h = L/N;
%u是一个N+1维的方阵，用来表示二维泊松方程的数值解
u = zeros(N+1, N+1);
% 计算真实解
x=0:h:L;
y=0:h:L;
[X, Y] = meshgrid(x, y);
u_true = sin(pi * X) .* sin(pi * Y); % 使用正确的元素乘法符，算出解析解
[X, Y] = meshgrid(x, y);
f = 2 * pi^2 * sin(pi X). sin(pi * Y);
error_iteration=zeros(1,1000);
for maxnum = 1:1000
u = V_xunhuan(u,f,h);
r = cancha(u,f,h);
%计算误差并记录
err=max(max(abs(u-u_true)));
error_iteration(maxnum)=err;
if max(max(abs®)) < 0.001
break
end
end
huatu_x=1:maxnum;
huatu_y=error_iteration(1:maxnum);
figure,plot(huatu_x, huatu_y,‘r-’);
title(['误差随迭代次数的变化 (一共迭代: ', num2str(maxnum), ‘次)’]);
xlabel(‘迭代次数’);
ylabel(‘误差’);
grid on;
function jie = V_xunhuan(jie,f,h)
% 递归v循环
%预先平滑
jie = smoothing(jie,f,h);
%算残差
r_old = cancha(jie,f,h);
%限制
r_new = xianzhi(r_old);
%算误差
e = zeros(size(r_new));
%如果网格已经达到最粗，停止递归，否则继续递归
if length(e)-1 == 2
e = smoothing(e,r_new,2h);
else
e = V_xunhuan(e,r_new,2h);
end
% 修正
jie = jie + yantuo(e);
%后光滑
jie = smoothing(jie,f,h);
end
function res = smoothing(phi,f,h)
N = size(phi, 1) - 1;
res = phi;
for i = 2:N
for j = 2:N
res(i, j) = (phi(i+1, j)+res(i-1, j)+phi(i, j+1)+res(i, j-1)+h^2f(i, j))/4;
end
end
end
function res = cancha(phi,f,h)
N = size(phi, 1) - 1;
res = zeros(N+1, N+1);
res(2:N, 2:N) = f(2:N, 2:N)-(phi(1:N-1, 2:N)-2phi(2:N, 2:N)+phi(3:N+1, 2:N)+phi(2:N, 1:N-1)-2phi(2:N, 2:N)+phi(2:N, 3:N+1))/h^2;
end
function r_xi = xianzhi(r_cu)
N = (size(r_cu, 1) - 1) / 2;
r_xi = zeros(N+1, N+1);
for i = 2:N
for j = 2:N
%直接映射r_xi(i, j) = r_cu(2i, 2j);
%九点差分r_xi(i, j) = 1/16 ( r_cu(2i-1, 2j-1)+r_cu(2i-1, 2j+1)+r_cu(2i+1, 2j-1)+r_cu(2i+1, 2j+1))+2/16*(r_cu(2i, 2j-1)+r_cu(2i, 2j+1)+r_cu(2i-1, 2j)+r_cu(2i+1, 2j))+4/16r_cu(2i,2j);
%五点差分
r_xi(i, j) = 2/16(r_cu(2i, 2j-1)+r_cu(2i, 2j+1)+r_cu(2i-1, 2j)+r_cu(2i+1, 2j)) + 1/2 * r_cu(2i, 2j);
end
end
end
function e_xiwang = yantuo(e_cuwang)
N = (size(e_cuwang, 1) - 1) * 2; % 计算细网格的大小
e_xiwang = zeros(N + 1, N + 1); % 初始化细网格矩阵
% 对角线（单元格中心）
for i = 2:2:N
for j = 2:2:N
e_xiwang(i, j) =1/4*( e_cuwang((i+2) / 2, j / 2)+e_cuwang((i+2)/ 2, (j+2) / 2)+e_cuwang(i / 2, j / 2)+e_cuwang(i / 2, (j+2) / 2));
end
end
% 原有点
for i = 1:2:N + 1
for j = 1:2:N + 1
e_xiwang(i, j) = e_cuwang((i + 1) / 2, (j + 1) / 2);
end
end
% 横向边中点
for i = 1:2:N
for j = 2:2:N
e_xiwang(i, j) =1/2* (e_cuwang((i + 1) / 2, j / 2) + e_cuwang((i + 1) / 2,( j / 2) + 1));
end
end
% 纵向边中点
for i = 2:2:N
for j = 1:2:N
e_xiwang(i, j) = 1/2*(e_cuwang(i / 2, (j + 1) / 2) + e_cuwang((i / 2) + 1, (j + 1) / 2));
end
end
end，以上就是我写的代码，今天上午我问了你是否发现代码的问题，你的回答是在原来的代码中，我们即使使用了V循环迭代，但是实际上我们并没有采取多重网格策略。我们在求解的过程中总是保持了细网格模型。所以请你基于这个错误，利用多重网格思想对我的代码进行修改，并写出修改后的完整代码，谢谢。
|
363be96d74a353f77d907919e778ce21
|
{
"intermediate": 0.3519655764102936,
"beginner": 0.42629575729370117,
"expert": 0.22173863649368286
}
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5,766
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Generate expert advisor MQ4 code for forex auto trading:
trend reversals indicators ( macd, obv power, solarwind, RSI custom, Bollinger bands, EMAs crossing ( 20,28,80), ADX, all other trend reversal indicators and possible indicators etc), auto exit, support resistance, trailing stop, veriable lots sizes breakeven. in one place
|
a101f3ac83b4fe6a987e74b7d4e34b79
|
{
"intermediate": 0.4035751521587372,
"beginner": 0.1502166986465454,
"expert": 0.4462081789970398
}
|
5,767
|
Implement a distributed file system that uses blockchain to store the file hashes and verify the integrity of the files in solidity
|
6e4c065f2d35f61fd5a1678faa70d8eb
|
{
"intermediate": 0.3148099184036255,
"beginner": 0.18428149819374084,
"expert": 0.500908613204956
}
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5,768
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I have function app with eventHubTrigger, I need to check the eventHub I am consuming from has the custom role that I assigned e.g. "sender.write", please give me an example in python
|
7cc2abfc2b1593cc0d54e3219126debc
|
{
"intermediate": 0.5940465331077576,
"beginner": 0.25721651315689087,
"expert": 0.14873695373535156
}
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5,769
|
fastapi and sqlachemy, export the table data as any format
|
f270285638d903ca0c6c86bcdb951544
|
{
"intermediate": 0.7711365818977356,
"beginner": 0.08296410739421844,
"expert": 0.14589928090572357
}
|
5,770
|
Hi, I need help with a programming task, so concentrate your knowledge to solve my problem
|
4d19938de3eb5f54228bd63172997362
|
{
"intermediate": 0.3874765634536743,
"beginner": 0.3715392053127289,
"expert": 0.24098429083824158
}
|
5,771
|
usm __main__.py[264]: [celery] 2023-05-12 10:57:13 - E - [consumm
er.py:366] - consumer: Cannot connect to redis://:**@localhost:6379/0: .#012Tryii
ng again in 32.00 seconds...
|
5488cb05a779285b562efc129b026f1a
|
{
"intermediate": 0.3978407084941864,
"beginner": 0.35979703068733215,
"expert": 0.24236232042312622
}
|
5,772
|
clc
clear
close all
% 设置网格尺寸和大小
N = 64;
L = 1;
h = L/N;
% u是一个N+1维的方阵，用来表示二维泊松方程的数值解
u = zeros(N+1, N+1);
% 计算真实解
x=0:h:L;
y=0:h:L;
[X, Y] = meshgrid(x, y);
u_true = sin(pi * X) .* sin(pi * Y); % 使用正确的元素乘法符，算出解析解
f = 2 * pi^2 * sin(pi * X).* sin(pi * Y);
error_iteration=zeros(1,1000);
for maxnum = 1:1000
u = V_xunhuan(u, f, h, 2);
r = cancha(u, f, h);
% 计算误差并记录
err = max(max(abs(u - u_true)));
error_iteration(maxnum) = err;
if err< 1e-4
break
end
end
huatu_x = 1:maxnum;
huatu_y = error_iteration(1:maxnum);
figure, plot(huatu_x, huatu_y, 'r-');
title(['误差随迭代次数的变化 (一共迭代: ', num2str(maxnum), '次)']);
xlabel('迭代次数');
ylabel('误差');
grid on;
function u = V_xunhuan(u, f, h, level)
if level == 0
return
end
% 预平滑
u = smoothing(u, f, h);
% 计算残差
r_old = cancha(u, f, h);
% 限制
r_new = xianzhi(r_old);
% 计算误差
e = zeros(size(r_new));
% 如果网格已经达到最粗，停止递归，否则继续递归
if (length(r_new) - 1) / 2 == 2
e = smoothing(e, r_new, 2 * h);
else
f_new = xianzhi(f);
e = V_xunhuan(e, f_new, 2 * h, level - 1);
end
% 修正
u = u + yantuo(e);
% 后光滑
u = smoothing(u, f, h);
end
function res = smoothing(phi, f, h)
N = size(phi, 1) - 1;
res = phi;
for i = 2:N
for j = 2:N
res(i, j) = (phi(i+1, j) + res(i-1, j) + phi(i, j+1) + res(i, j-1) + h^2 * f(i, j))/4;
end
end
end
function res = cancha(phi, f, h)
N = size(phi, 1) - 1;
res = zeros(N+1, N+1);
res(2:N, 2:N) = f(2:N, 2:N) - (phi(1:N-1, 2:N)-2*phi(2:N, 2:N)+phi(3:N+1, 2:N)+phi(2:N, 1:N-1)-2*phi(2:N, 2:N)+phi(2:N, 3:N+1))/h^2;
end
function r_xi = xianzhi(r_cu)
N = (size(r_cu, 1) - 1) / 2;
r_xi = zeros(N+1, N+1);
for i = 2:N
for j = 2:N
r_xi(i, j) = 2/16 * (r_cu(2 * i, 2 * j-1) + r_cu(2 * i, 2 * j+1) + r_cu(2 * i-1, 2 * j) + r_cu(2 * i+1, 2 * j)) + 1/2 * r_cu(2 * i, 2 * j);
end
end
end
function e_xiwang = yantuo(e_cuwang)
N = (size(e_cuwang, 1) - 1) * 2; % 计算细网格的大小
e_xiwang = zeros(N + 1, N + 1); % 初始化细网格矩阵
for i = 1:2:N + 1
for j = 1:2:N + 1
e_xiwang(i, j) = e_cuwang((i + 1) / 2, (j + 1) / 2);
end
end
for i = 2:2:N
for j = 2:2:N
e_xiwang(i, j) = 1/4 * (e_cuwang(i / 2, j / 2) + e_cuwang(i / 2 + 1, j / 2) + e_cuwang(i / 2, j / 2 + 1) + e_cuwang(i / 2 + 1, j / 2 + 1));
end
end
for i = 1:2:N
for j = 2:2:N
e_xiwang(i, j) = 1/2 * (e_cuwang((i + 1) / 2, j / 2) + e_cuwang(i / 2 + 1, j / 2));
end
end
for i = 2:2:N
for j = 1:2:N
e_xiwang(i, j) = 1/2 * (e_cuwang(i / 2, (j + 1) / 2) + e_cuwang(i / 2 + 1, (j + 1) / 2));
end
end
end这个多重网格代码运行结果显示数组索引必须为正整数或者逻辑值，请你检查一下是哪里出问题了并做修改，谢谢
|
791b31ebf203bab706b213a8a14d693a
|
{
"intermediate": 0.2667628228664398,
"beginner": 0.40744444727897644,
"expert": 0.32579270005226135
}
|
5,773
|
df.to_csv, if the csv is not yet create
|
3ca0753332b771d5eab711937836bdaa
|
{
"intermediate": 0.39002925157546997,
"beginner": 0.2234019935131073,
"expert": 0.38656869530677795
}
|
5,774
|
#include<reg51.h>
unsigned char tab[]={0xC0,0xF9,0xA4,0xb0,0x99,0x92,0x82,0xF8};
void delay(void){
unsigned char m,n;
for(m=0;m<200;m++)
for(n=0;n<250;n++);
}
void send(unsigned char dat)
{
SBUF=dat;
while(T1==0)
T1=0;
}
void main(void){
unsigned char i;
SCON=0x00;
for(i=1;i<5;i++){
send(tab[i]);
delay();
}
while(1);
}这个代码要求实现在四个数码管上显示1 2 3 4四个数字，有什么错误
|
3866333d09a77a5a91ad10b3e398f31a
|
{
"intermediate": 0.37225601077079773,
"beginner": 0.35357245802879333,
"expert": 0.27417150139808655
}
|
5,775
|
/* global L */
import "../leaflet/leaflet.min.js";
import getCoordinates from "../models/nominatim.js";
import orderModel from "../models/order-model.js";
export default class MapView extends HTMLElement {
constructor() {
super();
this.map = null;
}
async connectedCallback() {
const orderNumber = window.location.hash.replace("#map/", "");
this.orderInfo = await orderModel.getOrder(orderNumber);
this.innerHTML = `<div class="container-small">
<camera-component></camera-component>
<h2 class="seccondHeader"> MapView</h2>
<div id="map" class="map"></div>
<p class="seccondHeader">
Click marker for additional information!
<p>
</div>
</div>
`;
this.renderMap();
}
renderMap() {
this.map = L.map('map').setView([56.18219, 15.59094], 11);
L.tileLayer('https://tile.openstreetmap.org/{z}/{x}/{y}.png', {
maxZoom: 19,
attribution: '© <a href="http://www.openstreetmap.org/copyright">OpenStreetMap</a>'
}).addTo(this.map);
this.renderMarkers();
this.renderLocation();
}
async renderMarkers() {
const orderNumber = window.location.hash.replace("#map/", "");
this.orderInfo = await orderModel.getOrder(orderNumber);
//let coordinates = [56.2345, 15.6034];
//L.marker(coordinates).addTo(this.map);
//let adress = "Bergsgatan 1, Karlskrona";
let adress = this.orderInfo.address + ", " + this.orderInfo.city;
const results = await getCoordinates(adress);
L.marker([
parseFloat(results[0].lat),
parseFloat(results[0].lon),
]).addTo(this.map);
L.marker([
parseFloat(results[0].lat),
parseFloat(results[0].lon),
]).bindPopup(`
<strong>Order Information:</strong><br>
<p><strong>Namn:</strong> ${this.orderInfo.name}</p>
<p><strong>Address:</strong> ${this.orderInfo.address}</p>
<p><strong>Stad:</strong> ${this.orderInfo.city}</p>
<p><strong>Zip:</strong> ${this.orderInfo.zip}</p>
<p><strong>Country:</strong> ${this.orderInfo.country}</p>
`).addTo(this.map);
}
renderLocation() {
let locationMarker = L.icon({
iconUrl: "leaflet/location.png",
iconSize: [24, 24],
iconAnchor: [12, 12],
popupAnchor: [0, 0]
});
if ("geolocation" in navigator) {
navigator.geolocation.getCurrentPosition((position) => {
L.marker(
[position.coords.latitude, position.coords.longitude],
{icon: locationMarker}
).addTo(this.map);
});
}
}
}
import { UploadClient } from "../uploadcare/index.browser.min.js";
export default class CameraComponent extends HTMLElement {
constructor() {
super();
this.photoData = "";
}
connectedCallback() {
this.innerHTML = `
<div class="camera">
<video id="video">Video stream not available.</video>
<button id="startbutton">Take photo</button>
<button id="sendbutton">Send photo</button>
</div>
<canvas id="canvas"></canvas>
`;
window.addEventListener("load", () => {
this.startup();
}, false);
}
async sendpicture() {
const blob = await (await fetch(this.photoData)).blob();
const client = new UploadClient({ publicKey: 'cffa35d14b96b9f15679' });
const fileInfo = await client.uploadFile(blob);
const cdnUrl = fileInfo.cdnUrl;
console.log(cdnUrl);
}
takepicture(canvas, video, width, height) {
const context = canvas.getContext("2d");
if (width && height) {
canvas.width = width;
canvas.height = height;
context.drawImage(video, 0, 0, width, height);
this.photoData = canvas.toDataURL("image/png");
} else {
this.clearphoto(canvas);
}
}
clearphoto(canvas) {
const context = canvas.getContext("2d");
context.fillStyle = "#AAA";
context.fillRect(0, 0, canvas.width, canvas.height);
this.photoData = canvas.toDataURL("image/png");
}
startup() {
let streaming = false;
const width = 320; // We will scale the photo width to this
let height = 0; // This will be computed based on the input stream
let video = document.getElementById("video");
let canvas = document.getElementById("canvas");
let startbutton = document.getElementById("startbutton");
let sendbutton = document.getElementById("sendbutton");
navigator.mediaDevices
.getUserMedia({ video: true, audio: false })
.then((stream) => {
video.srcObject = stream;
video.play();
})
.catch((err) => {
console.error(`An error occurred: ${err}`);
});
video.addEventListener(
"canplay",
() => {
if (!streaming) {
height = video.videoHeight / (video.videoWidth / width);
// Firefox currently has a bug where the height can't be read from
// the video, so we will make assumptions if this happens.
if (isNaN(height)) {
height = width / (4 / 3);
}
video.setAttribute("width", width);
video.setAttribute("height", height);
canvas.setAttribute("width", width);
canvas.setAttribute("height", height);
streaming = true;
}
},
false
);
startbutton.addEventListener(
"click",
(ev) => {
ev.preventDefault();
this.takepicture(canvas, video, width, height);
},
false
);
sendbutton.addEventListener(
"click",
(ev) => {
ev.preventDefault();
this.sendpicture();
},
false
);
this.clearphoto(canvas);
}
}
the camera is not showing up on the page i've tested it on other pages but on the map page it simply does not tell me why it isnt working
|
eee75c400a8b57addfbd5bcb6b62a123
|
{
"intermediate": 0.402936190366745,
"beginner": 0.5132160186767578,
"expert": 0.08384785056114197
}
|
5,776
|
I write a shell in linux to delete - in string, why it doesn't work?
a="23-45-67"
a=$a | sed 's/-//g'
echo $a
|
583b5e6362c5176d2c5a4abdde627a40
|
{
"intermediate": 0.3333306610584259,
"beginner": 0.385384202003479,
"expert": 0.28128522634506226
}
|
5,777
|
fastapi+sqlaclemy+pandas, export the db table as csv, data = db.query(db_model).all()
|
7a8d38a9e83c633c1e88dd125afc0616
|
{
"intermediate": 0.6947700381278992,
"beginner": 0.14171351492404938,
"expert": 0.16351647675037384
}
|
5,778
|
laravel i have request field type. if type is user i want to test if user exists by id, if type is worker i want ti test if worker exists by id.... how?
|
939d92a7478a296c58c7efa248a5ea0d
|
{
"intermediate": 0.6450523734092712,
"beginner": 0.0916905477643013,
"expert": 0.26325711607933044
}
|
5,779
|
is there any plugin for mineflayer bot to fly like creative?
|
044f8bf964978b3b13109c1bb6a80e36
|
{
"intermediate": 0.32262536883354187,
"beginner": 0.2000228762626648,
"expert": 0.47735169529914856
}
|
5,780
|
rozwiąż mi ćwiczenie 9 Example 4.2 Simple neuron example 𝑧=𝑤⋅𝑥+𝑏 , target 𝑦
x= torch.ones(5)*0.1
#x.requires_grad=True
y= torch.tensor([0.])
w=torch.tensor([-2.,3,-1,-1,-1],requires_grad=True)
b=torch.tensor([0.1],requires_grad=True)
z=torch.matmul(x,w)+b
loss_f=torch.nn.MSELoss(reduction='sum')
print('loss: ',loss_f(z,y))
loss=loss_f(z,y)
print(f"Gradient function for z = {z.grad_fn}")
print(f"Gradient function for loss = {loss.grad_fn}")
loss.backward()
print(x.grad)
print(w.grad)
print(b.grad)
loss: tensor(0.0100, grad_fn=<MseLossBackward0>)
Gradient function for z = <AddBackward0 object at 0x7fd91becd7f0>
Gradient function for loss = <MseLossBackward0 object at 0x7fd909d08c40>
None
tensor([-0.0200, -0.0200, -0.0200, -0.0200, -0.0200])
tensor([-0.2000])
5. Neural network in pytorch
Example 5.1 Create simple "network" containing one neuron (as above)
torch.nn.Sequential - allows you to create network build by layers (ie. neurons, then activation function)
torch.nn.Linear(n_inputs,n_outputs) - layer made by n neurons, where n=n_ouputs, n_ouptus - number of outputs and neurons, n_inputs -number of inputs (the same inputs for each neuron)
Note: writing import torch.nn you can refer to nn.Linear , but by import torch.nn.Linear is enought to write Linear
model = torch.nn.Sequential(
torch.nn.Linear(5,1)
)
print(f"one neuron: {model}\n")
print(f"weights: {model[0].weight}\n")
print(f"bias: {model[0].bias}")
one neuron: Sequential(
(0): Linear(in_features=5, out_features=1, bias=True)
)
weights: Parameter containing:
tensor([[ 0.2637, -0.1790, 0.0923, 0.0450, -0.4013]], requires_grad=True)
bias: Parameter containing:
tensor([0.3067], requires_grad=True)
Set the weights and bias (note, that weights are 2D, bias 1D)
model[0].weight.data=torch.tensor([[-2.,3.,-1,-1,-1]],requires_grad=True)
model[0].bias.data=torch.tensor([0.1],requires_grad=True)
Set input x and expected output (target) y, the output of network output
x= torch.ones(5)*0.1
y= torch.tensor([0.])
output=model(x)
Exercise 9. Calculate the derivatives for weights and bias from example 4.3 similar to example 4.2. Access here to weights model[0].weight.data.grad
Exercise 10 Confirm derivatives from ex. 9 by manual calculations.
Exercise 11 Add to neuron from example 4.2 or 4.3 ReLu activation function (hint: in example 4.2 use torch.nn.functional.relu(x), which support autograd, in example 4.3 -similar to 4.4 use torch.nn.ReLU()
Exercise 12 Confirm derivatives from ex. 11 by manual calculations.
Exercise 13 After running example 5.2 use code for drawing 3d figure with decission boundary. Is it the same as for neuron in chapter 3?
|
d22101435550057518ee60c38d448897
|
{
"intermediate": 0.29514017701148987,
"beginner": 0.4011927545070648,
"expert": 0.3036670982837677
}
|
5,781
|
下面代码是我写的多重网格代码，但是最终运行的结果显示误差变量err-iteration非常大，这与我们的预期是不相符的，说明代码出现了问题，请你按照多重网格的思想检查下面代码，请说出哪里出现问题并作修正，写出修改后的完整代码并说明一下最终迭代次数和误差，谢谢。clc
clear
close all
%设置网格尺寸和大小
N = 64;
L = 1;
h = L/N;
%u是一个N+1维的方阵，用来表示二维泊松方程的数值解
u = zeros(N+1, N+1);
% 计算真实解
x=0:h:L;
y=0:h:L;
[X, Y] = meshgrid(x, y);
u_true = sin(pi * X) .* sin(pi * Y); % 使用正确的元素乘法符，算出解析解
[X, Y] = meshgrid(x, y);
f = 2 * pi^2 * sin(pi *X).* sin(pi * Y);
error_iteration=zeros(1,1000);
for maxnum = 1:1000
u = V_xunhuan(u,f,h);
r = cancha(u,f,h);
%计算误差并记录
err=max(max(abs(u-u_true)));
error_iteration(maxnum)=err;
if max(max(abs(r))) < 0.001
break
end
end
huatu_x=1:maxnum;
huatu_y=error_iteration(1:maxnum);
figure,plot(huatu_x, huatu_y,'r-');
title(['误差随迭代次数的变化 (一共迭代: ', num2str(maxnum), '次)']);
xlabel('迭代次数');
ylabel('误差');
grid on;
function jie = V_xunhuan(jie,f,h)
% 递归v循环
%预先平滑
jie = smoothing(jie,f,h);
%算残差
r_old = cancha(jie,f,h);
%限制
r_new = xianzhi(r_old);
%算误差
e = zeros(size(r_new));
%如果网格已经达到最粗，停止递归，否则继续递归
if length(e)-1 == 2
e = smoothing(e,r_new,2*h);
else
e = V_xunhuan(e,r_new,2*h);
end
% 修正
jie = jie + yantuo(e);
%后光滑
jie = smoothing(jie,f,h);
end
function res = smoothing(phi,f,h)
N = size(phi, 1) - 1;
res = phi;
for i = 2:N
for j = 2:N
res(i, j) = (phi(i+1, j)+res(i-1, j)+phi(i, j+1)+res(i, j-1)+h^2*f(i, j))/4;
end
end
end
function res = cancha(phi,f,h)
N = size(phi, 1) - 1;
res = zeros(N+1, N+1);
res(2:N, 2:N) = f(2:N, 2:N)-(phi(1:N-1, 2:N)-2*phi(2:N, 2:N)+phi(3:N+1, 2:N)+phi(2:N, 1:N-1)-2*phi(2:N, 2:N)+phi(2:N, 3:N+1))/h^2;
end
function r_xi = xianzhi(r_cu)
N = (size(r_cu, 1) - 1) / 2;
r_xi = zeros(N+1, N+1);
for i = 2:N
for j = 2:N
%直接映射r_xi(i, j) = r_cu(2*i, 2*j);
%九点差分r_xi(i, j) = 1/16 *( r_cu(2*i-1, 2*j-1)+r_cu(2*i-1, 2*j+1)+r_cu(2*i+1, 2*j-1)+r_cu(2*i+1, 2*j+1))+2/16*(r_cu(2*i, 2*j-1)+r_cu(2*i, 2*j+1)+r_cu(2*i-1, 2*j)+r_cu(2*i+1, 2*j))+4/16*r_cu(2*i,2*j);
%五点差分
r_xi(i, j) = 2/16*(r_cu(2*i, 2*j-1)+r_cu(2*i, 2*j+1)+r_cu(2*i-1, 2*j)+r_cu(2*i+1, 2*j)) + 1/2 * r_cu(2*i, 2*j);
end
end
end
function e_xiwang = yantuo(e_cuwang)
N = (size(e_cuwang, 1) - 1) * 2; % 计算细网格的大小
e_xiwang = zeros(N + 1, N + 1); % 初始化细网格矩阵
% 对角线（单元格中心）
for i = 2:2:N
for j = 2:2:N
e_xiwang(i, j) =1/4*( e_cuwang((i+2) / 2, j / 2)+e_cuwang((i+2)/ 2, (j+2) / 2)+e_cuwang(i / 2, j / 2)+e_cuwang(i / 2, (j+2) / 2));
end
end
% 原有点
for i = 1:2:N + 1
for j = 1:2:N + 1
e_xiwang(i, j) = e_cuwang((i + 1) / 2, (j + 1) / 2);
end
end
% 横向边中点
for i = 1:2:N
for j = 2:2:N
e_xiwang(i, j) =1/2* (e_cuwang((i + 1) / 2, j / 2) + e_cuwang((i + 1) / 2,( j / 2) + 1));
end
end
% 纵向边中点
for i = 2:2:N
for j = 1:2:N
e_xiwang(i, j) = 1/2*(e_cuwang(i / 2, (j + 1) / 2) + e_cuwang((i / 2) + 1, (j + 1) / 2));
end
end
end
|
1bbbfa6b8471d4807b1cb60f1cfe4376
|
{
"intermediate": 0.3072333037853241,
"beginner": 0.47783777117729187,
"expert": 0.21492893993854523
}
|
5,782
|
im trying to write a script on arch linux in bash, i want to add a shortcut to my steam library, however is there a library i need to install in order to read and write to .vdf files?
|
41df95439564778537fc5105cef98b00
|
{
"intermediate": 0.8823075294494629,
"beginner": 0.04408244043588638,
"expert": 0.07360998541116714
}
|
5,783
|
I have the following code. Can you see an error here? import tkinter as tk
from tkinter import filedialog
import struct
class Application(tk.Frame):
header_size = 16
def __init__(self, master):
super().__init__(master)
self.master = master
self.filename = ''
self.ccspackets = []
self.initUI()
def initUI(self):
menubar = tk.Menu(self.master)
filemenu = tk.Menu(menubar, tearoff=False)
filemenu.add_command(label='Open', command=self.opendialog)
menubar.add_cascade(menu=filemenu, label='File')
self.master.config(menu=menubar)
self.table = tk.Frame(self.master)
self.table.pack(fill=tk.BOTH, expand=True)
tk.Label(self.table, text='Packet ID').grid(row=0, column=0, padx=10, pady=5)
tk.Label(self.table, text='Secondary Header').grid(row=0, column=1, padx=10, pady=5)
tk.Label(self.table, text='Payload').grid(row=0, column=2, padx=10, pady=5)
def opendialog(self):
self.filename = filedialog.askopenfilename(defaultextension='.txt', filetypes=[('Text Files', '.txt'), ('All Files', '.*')])
if self.filename == '':
return
self.process_file()
def process_fileold(self):
with open(self.filename, 'rb') as f:
# Read the entire file contents as bytes
file_contents = f.read()
# Split the file contents into individual packets
packet_delimiter = b'\x03' # CCSDS packet delimiter
packets = file_contents.split(packet_delimiter)
# Process each packet separately
for index, packet in enumerate(packets):
# Decode the packet contents using the CCSDS packet header size and the UTF-8 encoding
if len(packet) > 0:
'''
packet_data = struct.unpack('>HBB', packet[:self.header_size]) # Unpack the packet ID and secondary header fields from the packet header
packet_id = packet_data[0]
secondary_header = packet_data[1:]
'''
header_size = 6 # Default packet header size
if len(packet) >= header_size:
# Determine the packet header size based on the version number and packet type fields
header_byte = packet[0]
if header_byte & 0x0F == 0b0001: # Telemetry packet
header_size = 6
elif header_byte & 0x0F == 0b0010: # Telecommand packet
header_size = 6
else: # Unknown packet type
header_size = 0
packet_data = struct.unpack('>HHB', packet[:header_size]) # Unpack the packet ID, packet sequence count, and secondary header fields from the packet header
packet_id = packet_data[0]
packet_sequence_count = packet_data[1]
secondary_header = packet_data[2:]
# Create a table row for the packet
row = tk.Frame(self.table)
row.pack(fill=tk.X, padx=5, pady=5)
tk.Label(row, text=packet_id).grid(row=0, column=0, padx=10, pady=5)
tk.Label(row, text=packet_sequence_count).grid(row=0, column=1, padx=10, pady=5)
tk.Label(row, text=' '.join([hex(b) for b in secondary_header])).grid(row=0, column=2, padx=10, pady=5)
tk.Label(row, text=packet[self.header_size:]).grid(row=0, column=3, padx=10, pady=5)
def process_file(self):
with open(self.filename, 'rb') as f:
# Read the entire file contents as bytes
file_contents = f.read()
# Split the file contents into individual packets
packet_delimiter = b'\x03' # CCSDS packet delimiter
packets = file_contents.split(packet_delimiter)
# Process each packet separately
for index, packet in enumerate(packets):
# Decode the packet contents using the CCSDS packet header size and the UTF-8 encoding
if len(packet) > 0:
# Determine the packet header size by scanning for the packet version number field
header_size = 0
for i in range(len(packet)):
if packet[i] & 0xF0 == 0x40:
header_size = i + 7 # Add 7 bytes to include the packet sequence count and packet data length fields
break
if len(packet) >= header_size:
packet_data = struct.unpack('>HHB', packet[:header_size]) # Unpack the packet ID, packet sequence count, and secondary header fields from the packet header
packet_id = packet_data[0]
packet_sequence_count = packet_data[1]
secondary_header = packet_data[2:]
# Create a table row for the packet
row = tk.Frame(self.table)
row.pack(fill=tk.X, padx=5, pady=5)
tk.Label(row, text=packet_id).grid(row=0, column=0, padx=10, pady=5)
tk.Label(row, text=packet_sequence_count).grid(row=0, column=1, padx=10, pady=5)
tk.Label(row, text=' '.join([hex(b) for b in secondary_header])).grid(row=0, column=2, padx=10, pady=5)
tk.Label(row, text=packet[header_size:]).grid(row=0, column=3, padx=10, pady=5)
root = tk.Tk()
root.geometry('800x600')
app = Application(root)
root.mainloop()
|
7eb4921fb286f3a0dd92412e92c8a9c2
|
{
"intermediate": 0.446922242641449,
"beginner": 0.4237523078918457,
"expert": 0.1293254792690277
}
|
5,784
|
create me a chess game in python
|
5f9bda5c2ae81f3c17c90bbf0430cfbe
|
{
"intermediate": 0.32305899262428284,
"beginner": 0.38560861349105835,
"expert": 0.2913324534893036
}
|
5,785
|
hi anyone here?/
|
8e215910a7c4273cc6963ccab0c070cb
|
{
"intermediate": 0.34635117650032043,
"beginner": 0.20952178537845612,
"expert": 0.44412705302238464
}
|
5,786
|
Generate code using pyautogui to use mouse
|
b23862c1c3ae8d8c67b8f3704610a41a
|
{
"intermediate": 0.40974631905555725,
"beginner": 0.17162536084651947,
"expert": 0.4186283349990845
}
|
5,787
|
As a Python expert developer, write a tetris game
|
06035ea3d1337433edc4c710c7a1303b
|
{
"intermediate": 0.3616512417793274,
"beginner": 0.4471178948879242,
"expert": 0.191230908036232
}
|
5,788
|
The amount of regular unleaded gasoline purchased every week at a gas station follows the normal
distribution with mean 50000 gallons and standard deviation 10000 gallons. The starting supply of gasoline is
74000 gallons, and there is a scheduled weekly delivery of 47000 gallons.
(a) Find the probability that, after 11 weeks, the supply of gasoline will be below 20000 gallons.
(b) How much should the weekly delivery be so that after 11 weeks the probability that the supply is
below 20000 gallons is only 0.5%?
|
fbb4383cc3cda44262c5751d4525c8b8
|
{
"intermediate": 0.34668853878974915,
"beginner": 0.37486809492111206,
"expert": 0.2784433364868164
}
|
5,789
|
how to pass a runtime parameter to C procedure through shell/python script
|
0b2965b2de7237daf255903d4a3af902
|
{
"intermediate": 0.4561111330986023,
"beginner": 0.23948734998703003,
"expert": 0.30440157651901245
}
|
5,790
|
if i want to obtain the sigh of a number , have you got any ideas
|
aa997c778c4a8ff19187a052000c80cb
|
{
"intermediate": 0.3202652633190155,
"beginner": 0.25744158029556274,
"expert": 0.42229321599006653
}
|
5,791
|
find why in this code: import tkinter as tk
from tkinter import filedialog
import struct
class Application(tk.Frame):
header_size = 16
def __init__(self, master):
super().__init__(master)
self.master = master
self.filename = ''
self.ccspackets = []
self.initUI()
def initUI(self):
menubar = tk.Menu(self.master)
filemenu = tk.Menu(menubar, tearoff=False)
filemenu.add_command(label='Open', command=self.opendialog)
menubar.add_cascade(menu=filemenu, label='File')
self.master.config(menu=menubar)
self.table = tk.Frame(self.master)
self.table.pack(fill=tk.BOTH, expand=True)
tk.Label(self.table, text='Packet ID').grid(row=0, column=0, padx=10, pady=5)
tk.Label(self.table, text='Secondary Header').grid(row=0, column=1, padx=10, pady=5)
tk.Label(self.table, text='Payload').grid(row=0, column=2, padx=10, pady=5)
def opendialog(self):
self.filename = filedialog.askopenfilename(defaultextension='.txt', filetypes=[('Text Files', '.txt'), ('All Files', '.*')])
if self.filename == '':
return
self.process_file()
def process_file(self):
with open(self.filename, 'rb') as f:
# Read the entire file contents as bytes
file_contents = f.read()
# Split the file contents into individual packets
packet_delimiter = b'\x03' # CCSDS packet delimiter
packets = file_contents.split(packet_delimiter)
# Process each packet separately
for index, packet in enumerate(packets):
# Decode the packet contents using the CCSDS packet header size and the UTF-8 encoding
if len(packet) > 0:
# Determine the packet header size by scanning for the packet version number field
header_size = 0
for i in range(len(packet)):
if packet[i] & 0xF0 == 0x40:
header_size = i + 7 # Add 7 bytes to include the packet sequence count and packet data length fields
break
print("header size, Packet: ",header_size , packet)
if header_size >= 5 and len(packet) >= header_size:
packet_data = struct.unpack('>HHB', packet[:header_size]) # Unpack the packet ID, packet sequence count, and secondary header fields from the packet header
packet_id = packet_data[0]
packet_sequence_count = packet_data[1]
secondary_header = packet_data[2:]
# Create a table row for the packet
row = tk.Frame(self.table)
row.pack(fill=tk.X, padx=5, pady=5)
tk.Label(row, text=packet_id).grid(row=0, column=0, padx=10, pady=5)
tk.Label(row, text=packet_sequence_count).grid(row=0, column=1, padx=10, pady=5)
tk.Label(row, text=' '.join([hex(b) for b in secondary_header])).grid(row=0, column=2, padx=10, pady=5)
tk.Label(row, text=packet[header_size:]).grid(row=0, column=3, padx=10, pady=5)
root = tk.Tk()
root.geometry('800x600')
app = Application(root)
root.mainloop()
|
57dcc3b07602a96ff475d7c777a17b59
|
{
"intermediate": 0.3843466341495514,
"beginner": 0.4213017523288727,
"expert": 0.19435159862041473
}
|
5,792
|
what is the osi model
|
2885524f9f6c0e5eae805f98863e9500
|
{
"intermediate": 0.19084328413009644,
"beginner": 0.15708479285240173,
"expert": 0.6520719528198242
}
|
5,793
|
@router.post(“/export_csv”)
async def download(db: Session = Depends(get_db)):
query = db.query(MyModel)
query = query.order_by(MyModel.id) # You can replace id with the column you want to sort by
df = pd.read_sql(query.statement, db.bind)
df.to_csv(“my_table_data.csv”, index=False, encoding=“utf-8”)
return {“message”: “Table data exported successfully to CSV file.”}
query.statement, db.bind, has both red underline, but can run normally, why?
|
74347b062b4a27ab1c21f08bbfe0b472
|
{
"intermediate": 0.6626394987106323,
"beginner": 0.1950632780790329,
"expert": 0.14229723811149597
}
|
5,794
|
I have a binary file with CCSDS packets with the following packet strcuture: CCSDS header, Data header, Data, CRC with the following sizes:
6 bytes,10 bytes,N bytes (max. 4094),2 bytes. The CCSDS header has the following structure: Version,Type,Data header
flag,PID,Category,Sequence flags, Sequence count, Packet length, which have the following leghts: 3 bits,1 bit,1 bit,7 bits,4 bits,2 bits,14 bits,2 bytes. Also the following information is known: -Version. Always 0.
• Type. Always 0 (telemetry).
• Data header flag. Indicates the presence of a data header (always 1).
• PID (Process ID).
– PID=50
• Category. Always 12 (science). The combination of PID and category is also called APID (Application process ID).
• Sequence flags. Always 11 (stand-alone packet).
• Sequence count. A sequence number incremented by 1 at every packet sent by each APID and destination ID. Once overflow, the cycle starts again at 0.
• Packet length. The total length of the packet in bytes without the CCSDS header (6 bytes) minus 1.
|
cbadd2402dd5c13cdd99b90c3b34a1cb
|
{
"intermediate": 0.36013317108154297,
"beginner": 0.2684173882007599,
"expert": 0.37144938111305237
}
|
5,795
|
Laravel. how to make foreignid field required when model created but to set it to null if related object deleted?
|
19301fccdc26c30decd3dab2e8568cc9
|
{
"intermediate": 0.41493600606918335,
"beginner": 0.07101175934076309,
"expert": 0.5140522718429565
}
|
5,796
|
下面这个多重网格代码的误差太大了，迭代次数也非常多，这与实际预期不符，请你检查代码哪里出问题了并做修改，写出修改后的完整代码。clc
clear
close all
%设置网格尺寸和大小
N = 64;
L = 1;
h = L/N;
%u是一个N+1维的方阵，用来表示二维泊松方程的数值解
u = zeros(N+1, N+1);
% 计算真实解
x=0:h:L;
y=0:h:L;
[X, Y] = meshgrid(x, y);
u_true = sin(pi * X) .* sin(pi * Y); % 使用正确的元素乘法符，算出解析解
[X, Y] = meshgrid(x, y);
f = 2 * pi^2 * sin(pi *X).* sin(pi * Y);
error_iteration=zeros(1,1000);
for maxnum = 1:1000
u = V_xunhuan(u,f,h);
r = cancha(u,f,h);
%计算误差并记录
err=max(max(abs(u-u_true)));
error_iteration(maxnum)=err;
if err < 0.001
break
end
end
huatu_x=1:maxnum;
huatu_y=error_iteration(1:maxnum);
figure,plot(huatu_x, huatu_y,'r-');
title(['误差随迭代次数的变化 (一共迭代: ', num2str(maxnum), '次)']);
xlabel('迭代次数');
ylabel('误差');
grid on;
function jie = V_xunhuan(jie,f,h)
% 递归v循环
%预先平滑
jie = smoothing(jie,f,h);
%算残差
r_old = cancha(jie,f,h);
%限制
r_new = xianzhi(r_old);
%算误差
e = zeros(size(r_new));
%如果网格已经达到最粗，停止递归，否则继续递归
if length(e)-1 == 2
e = smoothing(e,r_new,2*h);
else
e = V_xunhuan(e,r_new,2*h);
end
% 修正
jie = jie + yantuo(e);
%后光滑
jie = smoothing(jie,f,h);
end
function res = smoothing(phi,f,h)
N = size(phi, 1) - 1;
res = phi;
for i = 2:N
for j = 2:N
res(i, j) = (phi(i+1, j)+res(i-1, j)+phi(i, j+1)+res(i, j-1)+h^2*f(i, j))/4;
end
end
end
function res = cancha(phi,f,h)
N = size(phi, 1) - 1;
res = zeros(N+1, N+1);
res(2:N, 2:N) = f(2:N, 2:N)-(phi(1:N-1, 2:N)-2*phi(2:N, 2:N)+phi(3:N+1, 2:N)+phi(2:N, 1:N-1)-2*phi(2:N, 2:N)+phi(2:N, 3:N+1))/h^2;
end
function r_xi = xianzhi(r_cu)
N = (size(r_cu, 1) - 1) / 2;
r_xi = zeros(N+1, N+1);
for i = 2:N
for j = 2:N
%直接映射r_xi(i, j) = r_cu(2*i, 2*j);
%九点差分
% r_xi(i, j) = 1/16 *( r_cu(2*i-1, 2*j-1)+r_cu(2*i-1, 2*j+1)+r_cu(2*i+1, 2*j-1)+r_cu(2*i+1, 2*j+1))+2/16*(r_cu(2*i, 2*j-1)+r_cu(2*i, 2*j+1)+r_cu(2*i-1, 2*j)+r_cu(2*i+1, 2*j))+4/16*r_cu(2*i,2*j);
%五点差分
r_xi(i, j) = 2/16*(r_cu(2*i, 2*j-1)+r_cu(2*i, 2*j+1)+r_cu(2*i-1, 2*j)+r_cu(2*i+1, 2*j)) + 1/2 * r_cu(2*i, 2*j);
end
end
end
function e_xiwang = yantuo(e_cuwang)
N = (size(e_cuwang, 1) - 1) * 2; % 计算细网格的大小
e_xiwang = zeros(N + 1, N + 1); % 初始化细网格矩阵
% 对角线（单元格中心）
for i = 2:2:N
for j = 2:2:N
e_xiwang(i, j) =1/4*( e_cuwang((i+2) / 2, j / 2)+e_cuwang((i+2)/ 2, (j+2) / 2)+e_cuwang(i / 2, j / 2)+e_cuwang(i / 2, (j+2) / 2));
end
end
% 原有点
for i = 1:2:N + 1
for j = 1:2:N + 1
e_xiwang(i, j) = e_cuwang((i + 1) / 2, (j + 1) / 2);
end
end
% 横向边中点
for i = 1:2:N+1
for j = 2:2:N
e_xiwang(i, j) =1/2* (e_cuwang((i + 1) / 2, j / 2) + e_cuwang((i + 1) / 2,( j / 2) + 1));
end
end
% 纵向边中点
for i = 2:2:N
for j = 1:2:N+1
e_xiwang(i, j) = 1/2*(e_cuwang(i / 2, (j + 1) / 2) + e_cuwang((i / 2) + 1, (j + 1) / 2));
end
end
end
|
129b5a46103a298a52f6daac320f5a99
|
{
"intermediate": 0.3230307996273041,
"beginner": 0.46911489963531494,
"expert": 0.2078542560338974
}
|
5,797
|
How to add ui.View to discord interaction and on button click change message?
|
8ed81f7541fbaabb9ea1b5212f08b07f
|
{
"intermediate": 0.4492620527744293,
"beginner": 0.21339024603366852,
"expert": 0.33734774589538574
}
|
5,798
|
setViewportMargins margin color
|
5787d6eecab85305733e9ff5a5476c52
|
{
"intermediate": 0.40608787536621094,
"beginner": 0.2696056365966797,
"expert": 0.32430651783943176
}
|
5,799
|
{'1': "$@\x00\x02{'query_emb': '123', 'reference': '234234'}"} 怎么获取value的部分
|
eca95c832f2134bd5a50b65eb1fac581
|
{
"intermediate": 0.26511192321777344,
"beginner": 0.4566892981529236,
"expert": 0.2781987488269806
}
|
5,800
|
How do I get the extension from a data uri in javascript ?
|
4e4e70bd23225e7fd903fac55e623053
|
{
"intermediate": 0.6750303506851196,
"beginner": 0.12593328952789307,
"expert": 0.1990363746881485
}
|
5,801
|
I will provide you disassembly from a computer game that runs in MS-DOS. The game was written in C with a Watcom compiler. Some library function calls are already identified. Explain the functions I give to you and suggest names and C-language function signatures for them, including which parameters map to which registers or stack values. Also suggest names for global values when you have enough context to do so. As I provide more information, please revise your explanations and suggestions as necessary.
FUN_0006cc89
PUSH EBP
MOV EBP,ESP
PUSH ECX
PUSH ESI
PUSH EDI
SUB ESP,0x1c
MOV dword ptr [EBP + local_28],EAX
MOV dword ptr [EBP + local_24],EDX
MOV dword ptr [EBP + local_20],EBX
MOV EAX,dword ptr [EBP + local_28]
CALL FUN_000a1004
PUSH 0x180
PUSH 0x222
MOV EAX,dword ptr [EBP + local_28]
PUSH EAX
CALL open
ADD ESP,0xc
MOV dword ptr [EBP + local_1c],EAX
CMP dword ptr [EBP + local_1c],0x1
JGE LAB_0006ccce
MOV dword ptr [EBP + local_14],0x0
JMP LAB_0006cd05
LAB_0006ccce
MOV EBX,dword ptr [EBP + local_20]
MOV EDX,dword ptr [EBP + local_24]
MOV EAX,dword ptr [EBP + local_1c]
CALL FUN_000a0b42
CMP EAX,dword ptr [EBP + local_20]
JNZ LAB_0006ccea
MOV dword ptr [EBP + local_2c],0x1
JMP LAB_0006ccf1
LAB_0006ccea
MOV dword ptr [EBP + local_2c],0x0
LAB_0006ccf1
MOV EAX,dword ptr [EBP + local_2c]
MOV dword ptr [EBP + local_18],EAX
MOV EAX,dword ptr [EBP + local_1c]
CALL __close
MOV EAX,dword ptr [EBP + local_18]
MOV dword ptr [EBP + local_14],EAX
LAB_0006cd05
MOV EAX,dword ptr [EBP + local_14]
LEA ESP=>local_10,[EBP + -0xc]
POP EDI
POP ESI
POP ECX
POP EBP
RET
--------------------
FUN_0006cd10
PUSH EBP
MOV EBP,ESP
PUSH ECX
PUSH ESI
PUSH EDI
SUB ESP,0x10
MOV dword ptr [EBP + local_20],EAX
MOV dword ptr [EBP + local_1c],EDX
MOV dword ptr [EBP + local_18],EBX
MOV EAX,s_disk.c_00175d00 = "disk.c"
PUSH EAX
PUSH 0x6b
CALL FUN_000a0ed9
MOV EAX,dword ptr [EBP + local_20]
PUSH EAX
MOV EAX,DAT_001917e4
PUSH EAX
MOV EAX,s_%s%s_00175d60 = "%s%s"
PUSH
MOV EAX,DAT_001a41f4
PUSH EAX
CALL FUN_000a0f5c
ADD ESP,0x10
MOV EBX,dword ptr [EBP + local_18]
MOV EDX,dword ptr [EBP + local_1c]
MOV EAX,DAT_001a41f4
CALL FUN_0006cc89
MOV dword ptr [EBP + local_14],EAX
MOV EAX,dword ptr [EBP + local_14]
LEA ESP=>local_10,[EBP + -0xc]
POP EDI
POP ESI
POP ECX
POP EBP
RET
|
33ad39d87e145f6730c372999a6a2736
|
{
"intermediate": 0.4740807116031647,
"beginner": 0.3412776291370392,
"expert": 0.18464171886444092
}
|
5,802
|
will this code correctly decode a binary file with ccsds packets without packet delimiters? the packet can be extracted using the packet lenght : import tkinter as tk
from tkinter import filedialog
import struct
class Application(tk.Frame):
def __init__(self, master):
super().__init__(master)
self.master = master
self.filename = ''
self.initUI()
def initUI(self):
menubar = tk.Menu(self.master)
filemenu = tk.Menu(menubar, tearoff=False)
filemenu.add_command(label='Open', command=self.opendialog)
menubar.add_cascade(menu=filemenu, label='File')
self.master.config(menu=menubar)
self.table = tk.Frame(self.master)
self.table.pack(fill=tk.BOTH, expand=True)
tk.Label(self.table, text='APID').grid(row=0, column=0, padx=10, pady=5)
tk.Label(self.table, text='Sequence Count').grid(row=0, column=1, padx=10, pady=5)
tk.Label(self.table, text='Packet Length').grid(row=0, column=2, padx=10, pady=5)
tk.Label(self.table, text='Data').grid(row=0, column=3, padx=10, pady=5)
def opendialog(self):
self.filename = filedialog.askopenfilename(defaultextension='.bin', filetypes=[('Binary Files', '.bin'), ('All Files', '.*')])
if not self.filename:
return
self.process_file()
def process_file(self):
with open(self.filename, 'rb') as f:
# Read the entire file contents as bytes
file_contents = f.read()
# Split the file contents into individual packets
packet_delimiter = b'\x03' # CCSDS packet delimiter
packets = file_contents.split(packet_delimiter)
# Process each packet separately
for index, packet in enumerate(packets):
# Verify that the packet is a valid packet
if not self.is_valid_packet(packet):
continue
# Decode the packet header fields
header_size, apid, sequence_count, packet_length = self.decode_packet_header(packet)
# Extract the packet data
packet_data = packet[header_size:]
# Create a table row for the packet
row = tk.Frame(self.table)
row.pack(fill=tk.X, padx=5, pady=5)
tk.Label(row, text=hex(apid)).grid(row=0, column=0, padx=10, pady=5)
tk.Label(row, text=sequence_count).grid(row=0, column=1, padx=10, pady=5)
tk.Label(row, text=packet_length).grid(row=0, column=2, padx=10, pady=5)
tk.Label(row, text=self.format_packet_data(packet_data)).grid(row=0, column=3, padx=10, pady=5)
def is_valid_packet(self, packet):
'''
# Verify that the packet contains the correct header and footer fields
if len(packet) < 8 or packet[0] != 0x1A or packet[1] != 0xCF or packet[-2] != 0x0D or packet[-1] != 0x0A:
print('invalid Packet', packet)
return False
# Verify that the PID is 50 and the category is 12
print('GOOD Packet', packet)
pid, category = struct.unpack('>HB', packet[4:7])
return pid == 50 and category == 12
'''
# Print the hexadecimal representation of the packet
print('Packet hex:', packet.hex())
# Verify that the packet contains the correct header and footer fields
if len(packet) < 8 or packet[0] != 0x1A or packet[1] != 0xCF or packet[-2] != 0x0D or packet[-1] != 0x0A:
print('invalid Packet')
return False
# Verify that the PID is 50 and the category is 12
pid, category = struct.unpack('>HB', packet[4:7])
if pid != 50 or category != 12:
print('invalid PID or category')
return False
print('valid Packet')
return True
def decode_packet_header(self, packet):
# Extract the fields from the packet header
apid = struct.unpack('>H', packet[7:9])[0]
sequence_flags, sequence_count = struct.unpack('>BH', packet[9:12])
packet_length = struct.unpack('>H', packet[2:4])[0] - 1
# Calculate the header size based on the packet length field
if packet_length < 128:
header_size = 6
elif packet_length < 16384:
header_size = 7
else:
header_size = 8
return header_size, apid, sequence_count & 0x3FFF, packet_length
def format_packet_data(self, packet_data):
# Format the packet data as a string of hex values
hex_values = [hex(b) for b in packet_data]
# Split the string into groups of 8 hex values for better readability
hex_groups = [hex_values[i:i+8] for i in range(0, len(hex_values), 8)]
return '\n'.join([' '.join(group) for group in hex_groups])
root = tk.Tk()
root.geometry('800x600')
app = Application(root)
root.mainloop()
|
53861536bf15af26729d8b83447e3a4c
|
{
"intermediate": 0.37036648392677307,
"beginner": 0.3974605202674866,
"expert": 0.23217302560806274
}
|
5,803
|
package com.example.musicapp.Interface
import androidx.compose.foundation.Image
import androidx.compose.foundation.clickable
import androidx.compose.foundation.layout.*
import androidx.compose.foundation.lazy.LazyColumn
import androidx.compose.foundation.lazy.items
import androidx.compose.material.MaterialTheme
import androidx.compose.material.Text
import androidx.compose.runtime.*
import androidx.compose.ui.Alignment
import androidx.compose.ui.Modifier
import androidx.compose.ui.layout.ContentScale
import androidx.compose.ui.unit.dp
import coil.compose.rememberImagePainter
import com.example.musicapp.Data.Category
@Composable
fun MusicCategoriesScreen(
categories: List<Category>,
onCategorySelected: (Category) -> Unit = {},
modifier: Modifier = Modifier
) {
LazyColumn(
modifier = modifier,
contentPadding = PaddingValues(16.dp)
) {
items(categories) { category ->
CategoryItem(category) {
onCategorySelected(category)
}
}
}
}
@Composable
private fun CategoryItem(category: Category, onClick: () -> Unit) {
Column(
modifier = Modifier
.clickable(onClick = onClick)
.fillMaxWidth(),
horizontalAlignment = Alignment.CenterHorizontally
) {
val painter = rememberImagePainter(
data = category.picture_medium
)
Image(
painter = painter,
contentDescription = category.name,
contentScale = ContentScale.Crop,
modifier = Modifier
.fillMaxWidth()
.height(120.dp)
)
Text(
text = category.name,
modifier = Modifier
.padding(top = 8.dp)
.align(Alignment.CenterHorizontally),
style = MaterialTheme.typography.body2,
color = MaterialTheme.colors.onSurface
)
}
}-> this is my composable function. Category items only in 1 column , i want them to be in 2 column. Also i want category items in a square shape with rounded corners. I also want category images to fill the category cell and i want category name also inside the square shaped cell at the bottom of the square shaped cell . But i want to category names to be easy to read even if it's background is category image
|
f52d1c64ab8f4d738fe2760701e8fba6
|
{
"intermediate": 0.2656998038291931,
"beginner": 0.41288942098617554,
"expert": 0.32141077518463135
}
|
5,804
|
ho
|
cad85bf09ffba2450487ccb17c21e5f3
|
{
"intermediate": 0.3343488276004791,
"beginner": 0.2935584783554077,
"expert": 0.37209266424179077
}
|
5,805
|
can you fix this:
import openai
import os
openai.api_key = "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" # OpenAI API Key
model_id = 'gpt-3.5-turbo'
# Set your OpenAI API key as an environment variable
openai.api_key = os.environ[“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”]
# Set the prompt message
prompt = “Hello GPT-3, can you help me with a question?”
# Set the parameters of the request
parameters = {
“prompt”: prompt,
“temperature”: 0.5,
“max_tokens”: 100,
“n_context”: 1
}
# Send the request to OpenAI’s GPT-3 API
response = openai.Completion.create(
engine=model_id,
prompt=prompt,
max_tokens=parameters[“max_tokens”],
n_context=parameters[“n_context”],
temperature=parameters[“temperature”]
)
# Extract the response from the API’s output
answer = response[“choices”][0][“text”]
# Print the answer
print(answer)
|
06922e8c2a1b2cbb1ec8b869f91ee9b8
|
{
"intermediate": 0.5659662485122681,
"beginner": 0.2281409502029419,
"expert": 0.20589284598827362
}
|
5,806
|
I want you to act as a Text Adventure game. I will type commands and dialog, and you will only reply with what the text adventure game would show. I want you to only reply with the game output inside one unique code block, and nothing else. The game should always show one screen, and always wait for me to enter the next command.
The game should always show "health", "location", "description", "inventory", and "possible
commands".
Do not write explanations.
Do not type commands unless I instruct you to do so. It is imperative that these rules are followed without exception.
The setting will be a small town on the island of Sappho in ancient Greece during a time of war, political turmoil, and social unrest. The main character we will be playing as is a young woman named Zili.
|
8d00646cf0479c00447c30d5a03f0342
|
{
"intermediate": 0.26383548974990845,
"beginner": 0.28197646141052246,
"expert": 0.4541879892349243
}
|
5,807
|
I want you to act as a Text Adventure game. I will type commands and dialog, and you will only reply with what the text adventure game would show. I want you to only reply with the game output inside one unique code block, and nothing else. The game should always show one screen, and always wait for me to enter the next command.
The game should always show "health", "location", "description", "inventory", and "possible
commands".
Do not write explanations.
Do not type commands unless I instruct you to do so. It is imperative that these rules are followed without exception.
The setting will be a small town on the island of Sappho in ancient Greece during a time of war, political turmoil, and social unrest. The main character we will be playing as God of World and be able to summon and control everything.
|
3ce63888bbf2a2e91faa4928a2e48b1f
|
{
"intermediate": 0.32083043456077576,
"beginner": 0.2687593698501587,
"expert": 0.41041022539138794
}
|
5,808
|
how to player dash in unity using Update function
|
fa35ef834f4ccbbed3b64c6dd1a7d2a2
|
{
"intermediate": 0.34140220284461975,
"beginner": 0.2316267043352127,
"expert": 0.42697107791900635
}
|
5,809
|
how do i add chrome webdriver instances to a list and then save this list to a file so i can access this file and close the webdrivers in another python script?
|
c0500109c71195f0ad75b018566c84fb
|
{
"intermediate": 0.7756412625312805,
"beginner": 0.09092646092176437,
"expert": 0.1334322690963745
}
|
5,810
|
I will provide you disassembly from a computer game that runs in MS-DOS. The game was written in C with a Watcom compiler. Some library function calls are already identified. Explain the functions I give to you and suggest names and C-language function signatures for them, including which parameters map to which registers or stack values. Also suggest names for global values when you have enough context to do so.
FUN_00012203
PUSH EBP
MOV EBP,ESP
PUSH ESI
PUSH EDI
SUB ESP,0x10
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EAX,dword ptr [EAX + 0xa8]
MOV dword ptr [EBP + local_1c],EAX
CMP dword ptr [EBP + local_1c],0x0
JZ LAB_0001222f
MOV EAX,dword ptr [EBP + local_1c]
MOV AL,byte ptr [EAX]
AND EAX,0xff
CMP EAX,0x5b
JNZ LAB_00012231
LAB_0001222f
JMP LAB_00012240
LAB_00012231
MOV EAX,dword ptr [EBP + local_1c]
MOV AL,byte ptr [EAX]
AND EAX,0xff
CMP EAX,0xd
JNZ LAB_0001224c
LAB_00012240
MOV dword ptr [EBP + local_10],0x0
JMP LAB_000122e7
LAB_0001224c
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EDX,dword ptr [EAX + 0x84]
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV EAX,dword ptr [EAX + 0x88]
ADD EAX,EDX
MOV dword ptr [EBP + local_18],EAX
MOV dword ptr [EBP + local_14],0x0
LAB_0001226a
MOV EAX,dword ptr [EBP + local_1c]
MOV AL,byte ptr [EAX]
AND EAX,0xff
CMP EAX,0x20
JNZ LAB_00012281
MOV EAX,dword ptr [EBP + local_1c]
INC dword ptr [EBP + local_1c]
JMP LAB_0001226a
LAB_00012281
MOV EAX,dword ptr [EBP + local_1c]
MOV AL,byte ptr [EAX]
AND EAX,0xff
CMP EAX,0xd
LAB_00012299
MOV EAX,dword ptr [EBP + Stack[0xc]]
DEC EAX
CMP EAX,dword ptr [EBP + local_14]
JA LAB_0001229b
LAB_00012299
JMP LAB_000122b0
LAB_0001229b
MOV EAX,dword ptr [EBP + local_1c]
INC dword ptr [EBP + local_1c]
MOV EDX,dword ptr [EBP + local_14]
INC dword ptr [EBP + local_14]
ADD EDX,dword ptr [EBP + Stack[0x8]]
MOV AL,byte ptr [EAX]
MOV byte ptr [EDX],AL
JMP LAB_00012281
LAB_000122b0
MOV EAX,dword ptr [EBP + Stack[0x8]]
ADD EAX,dword ptr [EBP + local_14]
MOV byte ptr [EAX],0x0
ADD dword ptr [EBP + local_1c],0x2
MOV EAX,dword ptr [EBP + local_1c]
CMP EAX,dword ptr [EBP + local_18]
JC LAB_000122d4
MOV EAX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EAX + 0xa8],0x0
JMP LAB_000122e0
LAB_000122d4
MOV EAX,dword ptr [EBP + local_1c]
MOV EDX,dword ptr [EBP + Stack[0x4]]
MOV dword ptr [EDX + 0xa8],EAX
LAB_000122e0
MOV dword ptr [EBP + local_10],0x1
LAB_000122e7
MOV EAX,dword ptr [EBP + local_10]
LEA ESP=>local_c,[EBP + -0x8]
POP EDI
POP ESI
POP EBP
RET
|
5edf4a174f8af43b2334f830cd907521
|
{
"intermediate": 0.448438823223114,
"beginner": 0.3916684687137604,
"expert": 0.159892737865448
}
|
5,811
|
@router.post(“/export_csv”)
async def download(db: Session = Depends(get_db)):
query = db.query(MyModel)
query = query.order_by(MyModel.id) # You can replace id with the column you want to sort by
df = pd.read_sql(query.statement, db.bind)
df.to_csv(“my_table_data.csv”, index=False, encoding=“utf-8”)
return {“message”: “Table data exported successfully to CSV file.”}
|
5998a35102d6a45f0f8225e5d8008b40
|
{
"intermediate": 0.5782111287117004,
"beginner": 0.1871337592601776,
"expert": 0.23465505242347717
}
|
5,812
|
@Composable
fun MusicCategoriesScreen(
categories: List<Category>,
onCategorySelected: (Category) -> Unit = {},
modifier: Modifier = Modifier
) {
LazyVerticalGrid(
cells = GridCells.Fixed(2),
contentPadding = PaddingValues(16.dp),
modifier = modifier
) {
items(categories) { category ->
CategoryItem(category) {
onCategorySelected(category)
}
}
}
} -> Cannot find a parameter with this name: cells:30,No value passed for parameter 'columns':33
|
abe92b9ce6b0ef762c32c3628d3bb887
|
{
"intermediate": 0.40783756971359253,
"beginner": 0.3650110065937042,
"expert": 0.22715149819850922
}
|
5,813
|
can help me coding on trading view
|
65d0f69dc6491d3f9f886a75784eafd1
|
{
"intermediate": 0.2664814591407776,
"beginner": 0.530424952507019,
"expert": 0.20309360325336456
}
|
5,814
|
I want you to act as a Text Adventure game. I will type commands and dialog, and you will only reply with what the text adventure game would show. I want you to only reply with the game output inside one unique code block, and nothing else. The game should always show one screen, and always wait for me to enter the next command.
The game should always show "health", "location", "description", "inventory", and "free move"
Do not write explanations.
Do not type commands unless I instruct you to do so. It is imperative that these rules are followed without exception.
The setting will be a sandbox arena where main character can summon and control everything. The main character we will be playing as Master.
|
4e8c5b329b7e8cbde0950aaaa8879e8f
|
{
"intermediate": 0.2937173545360565,
"beginner": 0.269362211227417,
"expert": 0.43692049384117126
}
|
5,815
|
hi
|
349c1ce1d5a132b6a6fd269ee5daf1ed
|
{
"intermediate": 0.3246487081050873,
"beginner": 0.27135494351387024,
"expert": 0.40399640798568726
}
|
5,816
|
when I use nginx as revert proxy I got a error :Requested host does not match any Subject Alternative Names (SANs) on TLS certificate, what is it and how to fix it ?
|
1f1761f41c38616f475174eabba4c7d8
|
{
"intermediate": 0.5281609296798706,
"beginner": 0.2614419460296631,
"expert": 0.2103971689939499
}
|
5,817
|
I want you to act as a Text Adventure game. I will type commands and dialog, and you will only reply with what the text adventure game would show. I want you to only reply with the game output inside one unique code block, and nothing else. The game should always show one screen, and always wait for me to enter the next command.
The game should always show "unlimited health", "location", "description", "inventory", and "free move".
Do not write explanations.
Do not type commands unless I instruct you to do so. It is imperative that these rules are followed without exception.
The setting will be fantasy world of Zeriel. The main character we will be playing as is a Deity, who can summon and control everything. Mortals can't see the deity
Do not continue story until i enter next command.
|
26878b54dc175c76f15b6a66412c9ff7
|
{
"intermediate": 0.29460927844047546,
"beginner": 0.2813243865966797,
"expert": 0.42406636476516724
}
|
5,818
|
Write an simple EgoShooter with C++. Make Use of SDL and OpenGL.
|
07a5afd5bb1d0038fd69de496fce0f6d
|
{
"intermediate": 0.571405291557312,
"beginner": 0.24730131030082703,
"expert": 0.18129335343837738
}
|
5,819
|
Hi can you code me a rfc2217 client class in C#?
|
5685fecbb40a3948ae570da893b98164
|
{
"intermediate": 0.4606696367263794,
"beginner": 0.3471004366874695,
"expert": 0.19222991168498993
}
|
5,820
|
Make an advanced Unity C# script for first person player controller.
|
9920562911483efa5bb3c701ec5d8511
|
{
"intermediate": 0.4210945665836334,
"beginner": 0.3322236239910126,
"expert": 0.24668174982070923
}
|
5,821
|
how to make seleniumwire.undetected_chromedriver automaticly close webdriver when i close command promt controlling it. It works with orginal selenium but undetected_chromedriver just doesn't automaticly closes so i have an opened google chrome window opened even after i close the script
|
da0066ecdac85e0eb561cfee95d5b20a
|
{
"intermediate": 0.4929039776325226,
"beginner": 0.20525844395160675,
"expert": 0.3018375635147095
}
|
5,822
|
you are a javascript code golf master. Write a codegolf javascript program that find two consecutive substring that the second one is double the first one.
|
1e836df7a105b45233c802099d97c81e
|
{
"intermediate": 0.28710708022117615,
"beginner": 0.33431556820869446,
"expert": 0.378577321767807
}
|
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