question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
What are the names of circuits that belong to UK or Malaysia?
SELECT name FROM circuits WHERE country = 'UK' OR country = 'Malaysia'
CREATE TABLE circuits (name VARCHAR, country VARCHAR, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1335 }
What are the average fastest lap speed in races held after 2004 grouped by race name and ordered by year?
SELECT AVG(T2.fastestlapspeed), T1.name, T1.year FROM races AS T1 JOIN results AS T2 ON T1.raceid = T2.raceid WHERE T1.year > 2014 GROUP BY T1.name ORDER BY T1.year
CREATE TABLE results (fastestlapspeed INTEGER, raceid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE races (name VARCHAR(255), year INTEGER, raceid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 1341 }
Find the id, forename and number of races of all drivers who have at least participated in two races?
SELECT T1.driverid, T1.forename, COUNT(*) FROM drivers AS T1 JOIN results AS T2 ON T1.driverid = T2.driverid JOIN races AS T3 ON T2.raceid = T3.raceid GROUP BY T1.driverid HAVING COUNT(*) >= 2
CREATE TABLE drivers (driverid VARCHAR(255), forename VARCHAR(255)); CREATE TABLE races (raceid VARCHAR(255), name VARCHAR(255)); CREATE TABLE results (driverid VARCHAR(255), raceid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 1342 }
Find the driver id and number of races of all drivers who have at most participated in 30 races?
SELECT T1.driverid, COUNT(*) FROM drivers AS T1 JOIN results AS T2 ON T1.driverid = T2.driverid JOIN races AS T3 ON T2.raceid = T3.raceid GROUP BY T1.driverid HAVING COUNT(*) <= 30
CREATE TABLE races (raceid VARCHAR(255), name VARCHAR(255)); CREATE TABLE results (driverid VARCHAR(255), raceid VARCHAR(255)); CREATE TABLE drivers (driverid VARCHAR(255), forename VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 1343 }
Find the id and surname of the driver who participated the most number of races?
SELECT T1.driverid, T1.surname FROM drivers AS T1 JOIN results AS T2 ON T1.driverid = T2.driverid JOIN races AS T3 ON T2.raceid = T3.raceid GROUP BY T1.driverid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE drivers (driverid VARCHAR(255), surname VARCHAR(255)); CREATE TABLE races (raceid VARCHAR(255), name VARCHAR(255)); CREATE TABLE results (driverid VARCHAR(255), raceid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
5
0
1
{ "split": "train", "row_index": 1344 }
How many technicians are there?
SELECT COUNT(*) FROM technician
CREATE TABLE technician (Id VARCHAR(255), Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1345 }
List the names of technicians in ascending order of age.
SELECT Name FROM technician ORDER BY Age
CREATE TABLE technician (Name VARCHAR(255), Age VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1346 }
What are the team and starting year of technicians?
SELECT Team, Starting_Year FROM technician
CREATE TABLE technician (Team VARCHAR(255), Starting_Year VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 1347 }
List the name of technicians whose team is not "NYY".
SELECT Name FROM technician WHERE Team <> 'NYY'
CREATE TABLE technician (Name VARCHAR(255), Team VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1348 }
Show the name of technicians aged either 36 or 37
SELECT Name FROM technician WHERE Age = 36 OR Age = 37
CREATE TABLE technician (Name VARCHAR(255), Age VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1349 }
What is the starting year of the oldest technicians?
SELECT Starting_Year FROM technician ORDER BY Age DESC LIMIT 1
CREATE TABLE technician (Starting_Year VARCHAR(255), Age VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1350 }
Show different teams of technicians and the number of technicians in each team.
SELECT Team, COUNT(*) FROM technician GROUP BY Team
CREATE TABLE technician (Team VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT, Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1351 }
Please show the team that has the most number of technicians.
SELECT Team FROM technician GROUP BY Team ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE technician (Team VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT, Name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1352 }
Show the team that have at least two technicians.
SELECT Team FROM technician GROUP BY Team HAVING COUNT(*) >= 2
CREATE TABLE technician (Team VARCHAR(255), Id INTEGER PRIMARY KEY AUTO_INCREMENT, Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1353 }
Show names of technicians and series of machines they are assigned to repair.
SELECT T3.Name, T2.Machine_series FROM repair_assignment AS T1 JOIN machine AS T2 ON T1.machine_id = T2.machine_id JOIN technician AS T3 ON T1.technician_ID = T3.technician_ID
CREATE TABLE machine (Machine_series VARCHAR(255), machine_id VARCHAR(255)); CREATE TABLE repair_assignment (machine_id VARCHAR(255), technician_ID VARCHAR(255)); CREATE TABLE technician (Name VARCHAR(255), technician_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1354 }
Show names of technicians in ascending order of quality rank of the machine they are assigned.
SELECT T3.Name FROM repair_assignment AS T1 JOIN machine AS T2 ON T1.machine_id = T2.machine_id JOIN technician AS T3 ON T1.technician_ID = T3.technician_ID ORDER BY T2.quality_rank
CREATE TABLE repair_assignment (machine_id VARCHAR(255), technician_ID VARCHAR(255)); CREATE TABLE machine (machine_id VARCHAR(255), quality_rank VARCHAR(255)); CREATE TABLE technician (Name VARCHAR(255), technician_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1355 }
Show names of technicians who are assigned to repair machines with value point more than 70.
SELECT T3.Name FROM repair_assignment AS T1 JOIN machine AS T2 ON T1.machine_id = T2.machine_id JOIN technician AS T3 ON T1.technician_ID = T3.technician_ID WHERE T2.value_points > 70
CREATE TABLE machine (machine_id VARCHAR(255), value_points INTEGER); CREATE TABLE repair_assignment (machine_id VARCHAR(255), technician_ID VARCHAR(255)); CREATE TABLE technician (Name VARCHAR(255), technician_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1356 }
Show names of technicians and the number of machines they are assigned to repair.
SELECT T2.Name, COUNT(*) FROM repair_assignment AS T1 JOIN technician AS T2 ON T1.technician_ID = T2.technician_ID GROUP BY T2.Name
CREATE TABLE repair_assignment (technician_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE technician (Name VARCHAR(255), technician_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1357 }
List the names of technicians who have not been assigned to repair machines.
SELECT Name FROM technician WHERE NOT technician_id IN (SELECT technician_id FROM repair_assignment)
CREATE TABLE technician (Name VARCHAR(255), technician_id VARCHAR(255)); CREATE TABLE repair_assignment (Name VARCHAR(255), technician_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1358 }
Show the starting years shared by technicians from team "CLE" and "CWS".
SELECT Starting_Year FROM technician WHERE Team = 'CLE' INTERSECT SELECT Starting_Year FROM technician WHERE Team = 'CWS'
CREATE TABLE technician (Starting_Year VARCHAR(255), Team VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1359 }
How many entrepreneurs are there?
SELECT COUNT(*) FROM entrepreneur
CREATE TABLE entrepreneur (Id VARCHAR(255), Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1360 }
List the companies of entrepreneurs in descending order of money requested.
SELECT Company FROM entrepreneur ORDER BY Money_Requested DESC
CREATE TABLE entrepreneur (Company VARCHAR(255), Money_Requested VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1361 }
List the companies and the investors of entrepreneurs.
SELECT Company, Investor FROM entrepreneur
CREATE TABLE entrepreneur (Company VARCHAR(255), Investor VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 1362 }
What is the average money requested by all entrepreneurs?
SELECT AVG(Money_Requested) FROM entrepreneur
CREATE TABLE entrepreneur (Money_Requested INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1363 }
What are the names of people in ascending order of weight?
SELECT Name FROM People ORDER BY Weight
CREATE TABLE People (Name VARCHAR(255), Weight VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1364 }
What are the names of entrepreneurs?
SELECT T2.Name FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID
CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255)); CREATE TABLE entrepreneur (People_ID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1365 }
What are the names of entrepreneurs whose investor is not "Rachel Elnaugh"?
SELECT T2.Name FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Investor <> 'Rachel Elnaugh'
CREATE TABLE entrepreneur (People_ID VARCHAR(255), Investor VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1366 }
What is the weight of the shortest person?
SELECT Weight FROM people ORDER BY Height LIMIT 1
CREATE TABLE people (Weight VARCHAR(255), Height VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1367 }
What is the name of the entrepreneur with the greatest weight?
SELECT T2.Name FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Weight DESC LIMIT 1
CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255), Weight VARCHAR(255)); CREATE TABLE entrepreneur (People_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1368 }
What is the total money requested by entrepreneurs with height more than 1.85?
SELECT SUM(T1.Money_Requested) FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Height > 1.85
CREATE TABLE people (People_ID VARCHAR(255), Height INTEGER); CREATE TABLE entrepreneur (Money_Requested INTEGER, People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1369 }
What are the dates of birth of entrepreneurs with investor "Simon Woodroffe" or "Peter Jones"?
SELECT T2.Date_of_Birth FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Investor = 'Simon Woodroffe' OR T1.Investor = 'Peter Jones'
CREATE TABLE entrepreneur (People_ID VARCHAR(255), Investor VARCHAR(255)); CREATE TABLE people (Date_of_Birth VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 1370 }
What are the weights of entrepreneurs in descending order of money requested?
SELECT T2.Weight FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Money_Requested DESC
CREATE TABLE entrepreneur (People_ID VARCHAR(255), Money_Requested VARCHAR(255)); CREATE TABLE people (Weight VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1371 }
What are the investors of entrepreneurs and the corresponding number of entrepreneurs invested by each investor?
SELECT Investor, COUNT(*) FROM entrepreneur GROUP BY Investor
CREATE TABLE entrepreneur (Investor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1372 }
What is the investor that has invested in the most number of entrepreneurs?
SELECT Investor FROM entrepreneur GROUP BY Investor ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE entrepreneur (Investor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1373 }
What are the investors that have invested in at least two entrepreneurs?
SELECT Investor FROM entrepreneur GROUP BY Investor HAVING COUNT(*) >= 2
CREATE TABLE entrepreneur (Investor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1374 }
List the names of entrepreneurs and their companies in descending order of money requested?
SELECT T2.Name, T1.Company FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Money_Requested
CREATE TABLE entrepreneur (Company VARCHAR(255), People_ID VARCHAR(255), Money_Requested VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1375 }
List the names of people that are not entrepreneurs.
SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM entrepreneur)
CREATE TABLE entrepreneur (Name VARCHAR(255), People_ID VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1376 }
Show the investors shared by entrepreneurs that requested more than 140000 and entrepreneurs that requested less than 120000.
SELECT Investor FROM entrepreneur WHERE Money_Requested > 140000 INTERSECT SELECT Investor FROM entrepreneur WHERE Money_Requested < 120000
CREATE TABLE entrepreneur (Investor VARCHAR(255), Money_Requested INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1377 }
How many distinct companies are there?
SELECT COUNT(DISTINCT Company) FROM entrepreneur
CREATE TABLE entrepreneur (Company VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1378 }
Show the company of the tallest entrepreneur.
SELECT T1.Company FROM entrepreneur AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Height DESC LIMIT 1
CREATE TABLE entrepreneur (Company VARCHAR(255), People_ID VARCHAR(255)); CREATE TABLE people (People_ID VARCHAR(255), Height VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1379 }
How many perpetrators are there?
SELECT COUNT(*) FROM perpetrator
CREATE TABLE perpetrator (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1380 }
List the date of perpetrators in descending order of the number of people killed.
SELECT Date FROM perpetrator ORDER BY Killed DESC
CREATE TABLE perpetrator (Date VARCHAR(255), Killed VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1381 }
List the number of people injured by perpetrators in ascending order.
SELECT Injured FROM perpetrator ORDER BY Injured
CREATE TABLE perpetrator (Injured VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1382 }
What is the average number of people injured by all perpetrators?
SELECT AVG(Injured) FROM perpetrator
CREATE TABLE perpetrator (Injured INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1383 }
What is the location of the perpetrator with the largest kills.
SELECT LOCATION FROM perpetrator ORDER BY Killed DESC LIMIT 1
CREATE TABLE perpetrator (LOCATION VARCHAR(255), Killed VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1384 }
What are the names of people in ascending order of height?
SELECT Name FROM People ORDER BY Height
CREATE TABLE People (Name VARCHAR(255), Height VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1385 }
What are the names of perpetrators?
SELECT T1.Name FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID
CREATE TABLE perpetrator (People_ID VARCHAR(255), name VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1386 }
What are the names of perpetrators whose country is not "China"?
SELECT T1.Name FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Country <> 'China'
CREATE TABLE perpetrator (People_ID VARCHAR(255), Country VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1387 }
What is the name of the perpetrator with the biggest weight.
SELECT T1.Name FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Weight DESC LIMIT 1
CREATE TABLE perpetrator (People_ID VARCHAR(255), location VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255), Weight VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1388 }
What is the total kills of the perpetrators with height more than 1.84.
SELECT SUM(T2.Killed) FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 1.84
CREATE TABLE people (People_ID VARCHAR(255), Height INTEGER); CREATE TABLE perpetrator (Killed INTEGER, People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1389 }
What are the names of perpetrators in country "China" or "Japan"?
SELECT T1.Name FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Country = 'China' OR T2.Country = 'Japan'
CREATE TABLE perpetrator (People_ID VARCHAR(255), Country VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 1390 }
What are the heights of perpetrators in descending order of the number of people they injured?
SELECT T1.Height FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Injured DESC
CREATE TABLE perpetrator (People_ID VARCHAR(255), Injured VARCHAR(255)); CREATE TABLE people (Height VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1391 }
What are the countries of perpetrators? Show each country and the corresponding number of perpetrators there.
SELECT Country, COUNT(*) FROM perpetrator GROUP BY Country
CREATE TABLE perpetrator (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1392 }
What is the country that has the most perpetrators?
SELECT Country, COUNT(*) FROM perpetrator GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE perpetrator (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 1393 }
What are the countries that have at least two perpetrators?
SELECT Country, COUNT(*) FROM perpetrator GROUP BY Country HAVING COUNT(*) >= 2
CREATE TABLE perpetrator (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1394 }
List the names of perpetrators in descending order of the year.
SELECT T1.Name FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Year DESC
CREATE TABLE perpetrator (People_ID VARCHAR(255), Year VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1395 }
List the names of people that are not perpetrators.
SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM perpetrator)
CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255)); CREATE TABLE perpetrator (Name VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1396 }
Show the countries that have both perpetrators with injures more than 50 and perpetrators with injures smaller than 20.
SELECT Country FROM perpetrator WHERE Injured > 50 INTERSECT SELECT Country FROM perpetrator WHERE Injured < 20
CREATE TABLE perpetrator (Country VARCHAR(255), Injured INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1397 }
How many distinct locations of perpetrators are there?
SELECT COUNT(DISTINCT LOCATION) FROM perpetrator
CREATE TABLE perpetrator (LOCATION VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1398 }
Show the date of the tallest perpetrator.
SELECT T2.Date FROM people AS T1 JOIN perpetrator AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1
CREATE TABLE perpetrator (Date VARCHAR(255), People_ID VARCHAR(255)); CREATE TABLE people (People_ID VARCHAR(255), Height VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1399 }
In which year did the most recent crime happen?
SELECT MAX(YEAR) FROM perpetrator
CREATE TABLE perpetrator (YEAR INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1400 }
Report the name of all campuses in Los Angeles county.
SELECT campus FROM campuses WHERE county = 'Los Angeles'
CREATE TABLE campuses (campus VARCHAR(255), county VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1401 }
What are the names of all campuses located at Chico?
SELECT campus FROM campuses WHERE LOCATION = 'Chico'
CREATE TABLE campuses (campus VARCHAR(255), LOCATION VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1402 }
Find all the campuses opened in 1958.
SELECT campus FROM campuses WHERE YEAR = 1958
CREATE TABLE campuses (campus VARCHAR(255), YEAR VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1403 }
Find the name of the campuses opened before 1800.
SELECT campus FROM campuses WHERE YEAR < 1800
CREATE TABLE campuses (campus VARCHAR(255), YEAR INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1404 }
Which campus was opened between 1935 and 1939?
SELECT campus FROM campuses WHERE YEAR >= 1935 AND YEAR <= 1939
CREATE TABLE campuses (campus VARCHAR(255), YEAR VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1405 }
Find the name of the campuses that is in Northridge, Los Angeles or in San Francisco, San Francisco.
SELECT campus FROM campuses WHERE LOCATION = 'Northridge' AND county = 'Los Angeles' UNION SELECT campus FROM campuses WHERE LOCATION = 'San Francisco' AND county = 'San Francisco'
CREATE TABLE campuses (campus VARCHAR(255), LOCATION VARCHAR(255), county VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 1406 }
Find the count of universities whose campus fee is greater than the average campus fee.
SELECT COUNT(*) FROM csu_fees WHERE campusfee > (SELECT AVG(campusfee) FROM csu_fees)
CREATE TABLE csu_fees (campusfee INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1409 }
Which university is in Los Angeles county and opened after 1950?
SELECT campus FROM campuses WHERE county = 'Los Angeles' AND YEAR > 1950
CREATE TABLE campuses (campus VARCHAR(255), county VARCHAR(255), YEAR VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1410 }
Which year has the most degrees conferred?
SELECT YEAR FROM degrees GROUP BY YEAR ORDER BY SUM(degrees) DESC LIMIT 1
CREATE TABLE degrees (YEAR VARCHAR(255), degrees INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1411 }
Which campus has the most degrees conferred in all times?
SELECT campus FROM degrees GROUP BY campus ORDER BY SUM(degrees) DESC LIMIT 1
CREATE TABLE degrees (campus VARCHAR(255), degrees INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1412 }
Which campus has the most faculties in year 2003?
SELECT T1.campus FROM campuses AS T1 JOIN faculty AS T2 ON T1.id = T2.campus WHERE T2.year = 2003 ORDER BY T2.faculty DESC LIMIT 1
CREATE TABLE faculty (campus VARCHAR(255), year VARCHAR(255), faculty VARCHAR(255)); CREATE TABLE campuses (campus VARCHAR(255), id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 1413 }
Find the average fee on a CSU campus in 1996
SELECT AVG(campusfee) FROM csu_fees WHERE YEAR = 1996
CREATE TABLE csu_fees (campusfee INTEGER, YEAR VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1414 }
What is the average fee on a CSU campus in 2005?
SELECT AVG(campusfee) FROM csu_fees WHERE YEAR = 2005
CREATE TABLE csu_fees (campusfee INTEGER, YEAR VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1415 }
report the total number of degrees granted between 1998 and 2002.
SELECT T1.campus, SUM(T2.degrees) FROM campuses AS T1 JOIN degrees AS T2 ON T1.id = T2.campus WHERE T2.year >= 1998 AND T2.year <= 2002 GROUP BY T1.campus
CREATE TABLE campuses (campus VARCHAR(255), id VARCHAR(255)); CREATE TABLE degrees (degrees INTEGER, campus VARCHAR(255), year VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 1416 }
For each Orange county campus, report the number of degrees granted after 2000.
SELECT T1.campus, SUM(T2.degrees) FROM campuses AS T1 JOIN degrees AS T2 ON T1.id = T2.campus WHERE T1.county = 'Orange' AND T2.year >= 2000 GROUP BY T1.campus
CREATE TABLE campuses (campus VARCHAR(255), id VARCHAR(255), county VARCHAR(255)); CREATE TABLE degrees (degrees INTEGER, campus VARCHAR(255), year VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 1417 }
How many campuses are there in Los Angeles county?
SELECT COUNT(*) FROM campuses WHERE county = 'Los Angeles'
CREATE TABLE campuses (county VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1420 }
How many faculty is there in total in the year of 2002?
SELECT SUM(faculty) FROM faculty WHERE YEAR = 2002
CREATE TABLE faculty (faculty INTEGER, YEAR VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1423 }
How many undergraduates are there in "San Jose State University" in year 2004?
SELECT SUM(t1.undergraduate) FROM discipline_enrollments AS t1 JOIN campuses AS t2 ON t1.campus = t2.id WHERE t1.year = 2004 AND t2.campus = 'San Jose State University'
CREATE TABLE discipline_enrollments (undergraduate INTEGER, campus VARCHAR(255), year VARCHAR(255)); CREATE TABLE campuses (id VARCHAR(255), campus VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1429 }
What is the number of graduates in "San Francisco State University" in year 2004?
SELECT SUM(t1.graduate) FROM discipline_enrollments AS t1 JOIN campuses AS t2 ON t1.campus = t2.id WHERE t1.year = 2004 AND t2.campus = 'San Francisco State University'
CREATE TABLE discipline_enrollments (graduate INTEGER, campus VARCHAR(255), year VARCHAR(255)); CREATE TABLE campuses (id VARCHAR(255), campus VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1430 }
What is the campus fee of "San Francisco State University" in year 2000?
SELECT t1.campusfee FROM csu_fees AS t1 JOIN campuses AS t2 ON t1.campus = t2.id WHERE t2.campus = 'San Francisco State University' AND t1.year = 2000
CREATE TABLE campuses (id VARCHAR(255), campus VARCHAR(255)); CREATE TABLE csu_fees (campusfee VARCHAR(255), campus VARCHAR(255), year VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1431 }
Find the campus fee of "San Jose State University" in year 2000.
SELECT t1.campusfee FROM csu_fees AS t1 JOIN campuses AS t2 ON t1.campus = t2.id WHERE t2.campus = 'San Jose State University' AND t1.year = 2000
CREATE TABLE campuses (id VARCHAR(255), campus VARCHAR(255)); CREATE TABLE csu_fees (campusfee VARCHAR(255), campus VARCHAR(255), year VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1432 }
How many CSU campuses are there?
SELECT COUNT(*) FROM campuses
CREATE TABLE campuses (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1433 }
How many candidates are there?
SELECT COUNT(*) FROM candidate
CREATE TABLE candidate (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 1434 }
Which poll resource provided the most number of candidate information?
SELECT poll_source FROM candidate GROUP BY poll_source ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE candidate (id INTEGER PRIMARY KEY AUTO_INCREMENT, poll_source VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1435 }
what are the top 3 highest support rates?
SELECT support_rate FROM candidate ORDER BY support_rate DESC LIMIT 3
CREATE TABLE candidate (id INTEGER PRIMARY KEY AUTO_INCREMENT, support_rate VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1436 }
Find the id of the candidate who got the lowest oppose rate.
SELECT Candidate_ID FROM candidate ORDER BY oppose_rate LIMIT 1
CREATE TABLE candidate (Candidate_ID VARCHAR(255), oppose_rate VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1437 }
Please list support, consider, and oppose rates for each candidate in ascending order by unsure rate.
SELECT Support_rate, Consider_rate, Oppose_rate FROM candidate ORDER BY unsure_rate
CREATE TABLE candidate (Support_rate VARCHAR(255), Consider_rate VARCHAR(255), Oppose_rate VARCHAR(255), unsure_rate VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 1438 }
which poll source does the highest oppose rate come from?
SELECT poll_source FROM candidate ORDER BY oppose_rate DESC LIMIT 1
CREATE TABLE candidate (poll_source VARCHAR(255), oppose_rate VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1439 }
List all people names in the order of their date of birth from old to young.
SELECT name FROM people ORDER BY date_of_birth
CREATE TABLE people (name VARCHAR(255), date_of_birth VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 1440 }
Find the average height and weight for all males (sex is M).
SELECT AVG(height), AVG(weight) FROM people WHERE sex = 'M'
CREATE TABLE people (height INTEGER, weight INTEGER, sex VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 1441 }
find the names of people who are taller than 200 or lower than 190.
SELECT name FROM people WHERE height > 200 OR height < 190
CREATE TABLE people (name VARCHAR(255), height VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1442 }
Find the average and minimum weight for each gender.
SELECT AVG(weight), MIN(weight), sex FROM people GROUP BY sex
CREATE TABLE people (sex VARCHAR(255), weight INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 1443 }
Find the name and gender of the candidate who got the highest support rate.
SELECT t1.name, t1.sex FROM people AS t1 JOIN candidate AS t2 ON t1.people_id = t2.people_id ORDER BY t2.support_rate DESC LIMIT 1
CREATE TABLE candidate (people_id VARCHAR(255), support_rate VARCHAR(255)); CREATE TABLE people (name VARCHAR(255), sex VARCHAR(255), people_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 1444 }
which gender got the highest average uncertain ratio.
SELECT t1.sex FROM people AS t1 JOIN candidate AS t2 ON t1.people_id = t2.people_id GROUP BY t1.sex ORDER BY AVG(t2.unsure_rate) DESC LIMIT 1
CREATE TABLE candidate (people_id VARCHAR(255), unsure_rate INTEGER); CREATE TABLE people (sex VARCHAR(255), people_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 1446 }
what are the names of people who did not participate in the candidate election.
SELECT name FROM people WHERE NOT people_id IN (SELECT people_id FROM candidate)
CREATE TABLE candidate (name VARCHAR(255), people_id VARCHAR(255)); CREATE TABLE people (name VARCHAR(255), people_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1447 }
Find the names of the candidates whose support percentage is lower than their oppose rate.
SELECT t1.name FROM people AS t1 JOIN candidate AS t2 ON t1.people_id = t2.people_id WHERE t2.support_rate < t2.oppose_rate
CREATE TABLE candidate (people_id VARCHAR(255), support_rate INTEGER, oppose_rate VARCHAR(255)); CREATE TABLE people (name VARCHAR(255), people_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 1448 }
how many people are there whose weight is higher than 85 for each gender?
SELECT COUNT(*), sex FROM people WHERE weight > 85 GROUP BY sex
CREATE TABLE people (sex VARCHAR(255), weight INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 1449 }
list all female (sex is F) candidate names in the alphabetical order.
SELECT t1.name FROM people AS t1 JOIN candidate AS t2 ON t1.people_id = t2.people_id WHERE t1.sex = 'F' ORDER BY t1.name
CREATE TABLE candidate (people_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE people (name VARCHAR(255), people_id VARCHAR(255), sex VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 1451 }
find the name of people whose height is lower than the average.
SELECT name FROM people WHERE height < (SELECT AVG(height) FROM people)
CREATE TABLE people (name VARCHAR(255), height INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 1452 }