question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
What are the names of shops in ascending order of open year?
SELECT Shop_Name FROM shop ORDER BY Open_Year
CREATE TABLE shop (Shop_Name VARCHAR(255), Open_Year VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2901 }
What is the average quantity of stocks?
SELECT AVG(Quantity) FROM stock
CREATE TABLE stock (Quantity INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2902 }
What are the names and location of the shops in ascending alphabetical order of name.
SELECT Shop_Name, LOCATION FROM shop ORDER BY Shop_Name
CREATE TABLE shop (Shop_Name VARCHAR(255), LOCATION VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2903 }
How many different software platforms are there for devices?
SELECT COUNT(DISTINCT Software_Platform) FROM device
CREATE TABLE device (Software_Platform VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2904 }
List the open date of open year of the shop named "Apple".
SELECT Open_Date, Open_Year FROM shop WHERE Shop_Name = 'Apple'
CREATE TABLE shop (Open_Date VARCHAR(255), Open_Year VARCHAR(255), Shop_Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2905 }
List the name of the shop with the latest open year.
SELECT Shop_Name FROM shop ORDER BY Open_Year DESC LIMIT 1
CREATE TABLE shop (Shop_Name VARCHAR(255), Open_Year VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2906 }
Show names of shops and the carriers of devices they have in stock.
SELECT T3.Shop_Name, T2.Carrier FROM stock AS T1 JOIN device AS T2 ON T1.Device_ID = T2.Device_ID JOIN shop AS T3 ON T1.Shop_ID = T3.Shop_ID
CREATE TABLE shop (Shop_Name VARCHAR(255), Shop_ID VARCHAR(255)); CREATE TABLE stock (Device_ID VARCHAR(255), Shop_ID VARCHAR(255)); CREATE TABLE device (Carrier VARCHAR(255), Device_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2907 }
Show names of shops that have more than one kind of device in stock.
SELECT T2.Shop_Name FROM stock AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID HAVING COUNT(*) > 1
CREATE TABLE shop (Shop_Name VARCHAR(255), Shop_ID VARCHAR(255)); CREATE TABLE stock (Shop_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2908 }
Show the name of the shop that has the most kind of devices in stock.
SELECT T2.Shop_Name FROM stock AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE shop (Shop_Name VARCHAR(255), Shop_ID VARCHAR(255)); CREATE TABLE stock (Shop_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2909 }
Show the name of the shop that have the largest quantity of devices in stock.
SELECT T2.Shop_Name FROM stock AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID ORDER BY SUM(T1.quantity) DESC LIMIT 1
CREATE TABLE stock (Shop_ID VARCHAR(255), quantity INTEGER); CREATE TABLE shop (Shop_Name VARCHAR(255), Shop_ID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2910 }
Please show different software platforms and the corresponding number of devices using each.
SELECT Software_Platform, COUNT(*) FROM device GROUP BY Software_Platform
CREATE TABLE device (Software_Platform VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2911 }
Please show the software platforms of devices in descending order of the count.
SELECT Software_Platform FROM device GROUP BY Software_Platform ORDER BY COUNT(*) DESC
CREATE TABLE device (Software_Platform VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2912 }
List the software platform shared by the greatest number of devices.
SELECT Software_Platform FROM device GROUP BY Software_Platform ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE device (Software_Platform VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2913 }
List the names of shops that have no devices in stock.
SELECT Shop_Name FROM shop WHERE NOT Shop_ID IN (SELECT Shop_ID FROM stock)
CREATE TABLE shop (Shop_Name VARCHAR(255), Shop_ID VARCHAR(255)); CREATE TABLE stock (Shop_Name VARCHAR(255), Shop_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2914 }
Show the locations shared by shops with open year later than 2012 and shops with open year before 2008.
SELECT LOCATION FROM shop WHERE Open_Year > 2012 INTERSECT SELECT LOCATION FROM shop WHERE Open_Year < 2008
CREATE TABLE shop (LOCATION VARCHAR(255), Open_Year INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2915 }
List the carriers of devices that have no devices in stock.
SELECT Carrier FROM device WHERE NOT Device_ID IN (SELECT Device_ID FROM stock)
CREATE TABLE stock (Carrier VARCHAR(255), Device_ID VARCHAR(255)); CREATE TABLE device (Carrier VARCHAR(255), Device_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2916 }
Show the carriers of devices in stock at more than one shop.
SELECT T2.Carrier FROM stock AS T1 JOIN device AS T2 ON T1.Device_ID = T2.Device_ID GROUP BY T1.Device_ID HAVING COUNT(*) > 1
CREATE TABLE stock (Device_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE device (Carrier VARCHAR(255), Device_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2917 }
How many bookings do we have?
SELECT COUNT(*) FROM BOOKINGS
CREATE TABLE BOOKINGS (Id VARCHAR(255), booking_date VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2918 }
List the order dates of all the bookings.
SELECT Order_Date FROM BOOKINGS
CREATE TABLE BOOKINGS (Order_Date VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2919 }
Show all the planned delivery dates and actual delivery dates of bookings.
SELECT Planned_Delivery_Date, Actual_Delivery_Date FROM BOOKINGS
CREATE TABLE BOOKINGS (Planned_Delivery_Date VARCHAR(255), Actual_Delivery_Date VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2920 }
How many customers do we have?
SELECT COUNT(*) FROM CUSTOMERS
CREATE TABLE CUSTOMERS (Id VARCHAR(255), Customer_Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2921 }
What are the phone and email for customer Harold?
SELECT Customer_Phone, Customer_Email_Address FROM CUSTOMERS WHERE Customer_Name = 'Harold'
CREATE TABLE CUSTOMERS (Customer_Phone VARCHAR(255), Customer_Email_Address VARCHAR(255), Customer_Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2922 }
Show all the Store_Name of drama workshop groups.
SELECT Store_Name FROM Drama_Workshop_Groups
CREATE TABLE Drama_Workshop_Groups (Store_Name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2923 }
Show the minimum, average, maximum order quantity of all invoices.
SELECT MIN(Order_Quantity), AVG(Order_Quantity), MAX(Order_Quantity) FROM INVOICES
CREATE TABLE INVOICES (Order_Quantity INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 2924 }
What are the distinct payment method codes in all the invoices?
SELECT DISTINCT payment_method_code FROM INVOICES
CREATE TABLE INVOICES (payment_method_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2925 }
What is the description of the marketing region China?
SELECT Marketing_Region_Descriptrion FROM Marketing_Regions WHERE Marketing_Region_Name = 'China'
CREATE TABLE Marketing_Regions (Marketing_Region_Descriptrion VARCHAR(255), Marketing_Region_Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2926 }
Show all the distinct product names with price higher than the average.
SELECT DISTINCT Product_Name FROM PRODUCTS WHERE Product_Price > (SELECT AVG(Product_Price) FROM PRODUCTS)
CREATE TABLE PRODUCTS (Product_Name VARCHAR(255), Product_Price INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2927 }
What is the name of the most expensive product?
SELECT Product_Name FROM PRODUCTS ORDER BY Product_Price DESC LIMIT 1
CREATE TABLE PRODUCTS (Product_Name VARCHAR(255), Product_Price VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2928 }
What is the phone number of the performer Ashley?
SELECT Customer_Phone FROM PERFORMERS WHERE Customer_Name = 'Ashley'
CREATE TABLE PERFORMERS (Customer_Phone VARCHAR(255), Customer_Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2929 }
Show all payment method codes and the number of orders for each code.
SELECT payment_method_code, COUNT(*) FROM INVOICES GROUP BY payment_method_code
CREATE TABLE INVOICES (payment_method_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2930 }
What is the payment method code used by the most orders?
SELECT payment_method_code FROM INVOICES GROUP BY payment_method_code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE INVOICES (payment_method_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2931 }
Which city is the address of the store named "FJA Filming" located in?
SELECT T1.City_Town FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Store_Name = 'FJA Filming'
CREATE TABLE Addresses (City_Town VARCHAR(255), Address_ID VARCHAR(255)); CREATE TABLE Stores (Address_ID VARCHAR(255), Store_Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2932 }
What are the states or counties of the address of the stores with marketing region code "CA"?
SELECT T1.State_County FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Marketing_Region_Code = 'CA'
CREATE TABLE Addresses (State_County VARCHAR(255), Address_ID VARCHAR(255)); CREATE TABLE Stores (Address_ID VARCHAR(255), Marketing_Region_Code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2933 }
What is the name of the marketing region that the store Rob Dinning belongs to?
SELECT T1.Marketing_Region_Name FROM Marketing_Regions AS T1 JOIN Stores AS T2 ON T1.Marketing_Region_Code = T2.Marketing_Region_Code WHERE T2.Store_Name = 'Rob Dinning'
CREATE TABLE Marketing_Regions (Marketing_Region_Name VARCHAR(255), Marketing_Region_Code VARCHAR(255)); CREATE TABLE Stores (Marketing_Region_Code VARCHAR(255), Store_Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2934 }
What are the descriptions of the service types with product price above 100?
SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Price > 100
CREATE TABLE Services (Service_Type_Code VARCHAR(255), Product_Price INTEGER); CREATE TABLE Ref_Service_Types (Service_Type_Description VARCHAR(255), Service_Type_Code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2935 }
What is the description, code and the corresponding count of each service type?
SELECT T1.Service_Type_Description, T2.Service_Type_Code, COUNT(*) FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T2.Service_Type_Code
CREATE TABLE Services (Service_Type_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Ref_Service_Types (Service_Type_Description VARCHAR(255), Service_Type_Code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2936 }
What is the description and code of the type of service that is performed the most often?
SELECT T1.Service_Type_Description, T1.Service_Type_Code FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T1.Service_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Services (Service_Type_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Ref_Service_Types (Service_Type_Description VARCHAR(255), Service_Type_Code VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2937 }
What are the phones and emails of workshop groups in which services are performed?
SELECT T1.Store_Phone, T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID
CREATE TABLE Services (Workshop_Group_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Drama_Workshop_Groups (Store_Phone VARCHAR(255), Store_Email_Address VARCHAR(255), Workshop_Group_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2938 }
What are the names of workshop groups in which services with product name "film" are performed?
SELECT T1.Store_Phone, T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T2.Product_Name = 'film'
CREATE TABLE Services (Workshop_Group_ID VARCHAR(255), Product_Name VARCHAR(255)); CREATE TABLE Drama_Workshop_Groups (Store_Phone VARCHAR(255), Store_Email_Address VARCHAR(255), Workshop_Group_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2939 }
What are the different product names? What is the average product price for each of them?
SELECT Product_Name, AVG(Product_Price) FROM PRODUCTS GROUP BY Product_Name
CREATE TABLE PRODUCTS (Product_Name VARCHAR(255), Product_Price INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2940 }
What are the product names with average product price smaller than 1000000?
SELECT Product_Name FROM PRODUCTS GROUP BY Product_Name HAVING AVG(Product_Price) < 1000000
CREATE TABLE PRODUCTS (Product_Name VARCHAR(255), Product_Price INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2941 }
What are the total order quantities of photo products?
SELECT SUM(T1.Order_Quantity) FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_Name = 'photo'
CREATE TABLE ORDER_ITEMS (Order_Quantity INTEGER, Product_ID VARCHAR(255)); CREATE TABLE Products (Product_ID VARCHAR(255), Product_Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2942 }
What are the order details of the products with price higher than 2000?
SELECT T1.Other_Item_Details FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_price > 2000
CREATE TABLE Products (Product_ID VARCHAR(255), Product_price INTEGER); CREATE TABLE ORDER_ITEMS (Other_Item_Details VARCHAR(255), Product_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2943 }
What are the actual delivery dates of orders with quantity 1?
SELECT T1.Actual_Delivery_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID WHERE T2.Order_Quantity = 1
CREATE TABLE Customer_Orders (Actual_Delivery_Date VARCHAR(255), Order_ID VARCHAR(255)); CREATE TABLE ORDER_ITEMS (Order_ID VARCHAR(255), Order_Quantity VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2944 }
What are the order dates of orders with price higher than 1000?
SELECT T1.Order_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID JOIN Products AS T3 ON T2.Product_ID = T3.Product_ID WHERE T3.Product_price > 1000
CREATE TABLE Products (Product_ID VARCHAR(255), Product_price INTEGER); CREATE TABLE ORDER_ITEMS (Order_ID VARCHAR(255), Product_ID VARCHAR(255)); CREATE TABLE Customer_Orders (Order_Date VARCHAR(255), Order_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2945 }
How many distinct currency codes are there for all drama workshop groups?
SELECT COUNT(DISTINCT Currency_Code) FROM Drama_Workshop_Groups
CREATE TABLE Drama_Workshop_Groups (Currency_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2946 }
What are the names of the drama workshop groups with address in Feliciaberg city?
SELECT T2.Store_Name FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.City_Town = 'Feliciaberg'
CREATE TABLE Addresses (Address_ID VARCHAR(255), City_Town VARCHAR(255)); CREATE TABLE Drama_Workshop_Groups (Store_Name VARCHAR(255), Address_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2947 }
What are the email addresses of the drama workshop groups with address in Alaska state?
SELECT T2.Store_Email_Address FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.State_County = 'Alaska'
CREATE TABLE Drama_Workshop_Groups (Store_Email_Address VARCHAR(255), Address_ID VARCHAR(255)); CREATE TABLE Addresses (Address_ID VARCHAR(255), State_County VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2948 }
Show all cities along with the number of drama workshop groups in each city.
SELECT T1.City_Town, COUNT(*) FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID GROUP BY T1.City_Town
CREATE TABLE Addresses (City_Town VARCHAR(255), Address_ID VARCHAR(255)); CREATE TABLE Drama_Workshop_Groups (Address_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2949 }
What is the marketing region code that has the most drama workshop groups?
SELECT Marketing_Region_Code FROM Drama_Workshop_Groups GROUP BY Marketing_Region_Code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Drama_Workshop_Groups (Marketing_Region_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2950 }
Show all cities where at least one customer lives in but no performer lives in.
SELECT T1.City_Town FROM Addresses AS T1 JOIN Customers AS T2 ON T1.Address_ID = T2.Address_ID EXCEPT SELECT T1.City_Town FROM Addresses AS T1 JOIN Performers AS T2 ON T1.Address_ID = T2.Address_ID
CREATE TABLE Customers (Address_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Addresses (City_Town VARCHAR(255), Address_ID VARCHAR(255)); CREATE TABLE Performers (Address_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2951 }
What is the most frequent status of bookings?
SELECT Status_Code FROM BOOKINGS GROUP BY Status_Code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE BOOKINGS (Status_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2952 }
What are the names of the workshop groups that have bookings with status code "stop"?
SELECT T2.Store_Name FROM Bookings AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T1.Status_Code = 'stop'
CREATE TABLE Bookings (Workshop_Group_ID VARCHAR(255), Status_Code VARCHAR(255)); CREATE TABLE Drama_Workshop_Groups (Store_Name VARCHAR(255), Workshop_Group_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2953 }
What is the average quantities ordered with payment method code "MasterCard" on invoices?
SELECT AVG(Order_Quantity) FROM Invoices WHERE payment_method_code = 'MasterCard'
CREATE TABLE Invoices (Order_Quantity INTEGER, payment_method_code VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2955 }
What is the product ID of the most frequently ordered item on invoices?
SELECT Product_ID FROM INVOICES GROUP BY Product_ID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE INVOICES (Product_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2956 }
What is the description of the service type which offers both the photo product and the film product?
SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'photo' INTERSECT SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product...
CREATE TABLE Ref_Service_Types (Service_Type_Description VARCHAR(255), Service_Type_Code VARCHAR(255)); CREATE TABLE Services (Service_Type_Code VARCHAR(255), Product_Name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 2957 }
How many bands are there?
SELECT COUNT(*) FROM Band
CREATE TABLE Band (Id VARCHAR(255), Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2958 }
What are all the labels?
SELECT DISTINCT label FROM Albums
CREATE TABLE Albums (label VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2959 }
How many songs are there?
SELECT COUNT(*) FROM Songs
CREATE TABLE Songs (Id VARCHAR(255), title VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2962 }
Find all the songs performed by artist with last name "Heilo"
SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.Lastname = 'Heilo'
CREATE TABLE Songs (Title VARCHAR(255), SongId VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255)); CREATE TABLE Band (id VARCHAR(255), Lastname VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2963 }
Hom many musicians performed in the song "Flash"?
SELECT COUNT(*) FROM performance AS T1 JOIN band AS T2 ON T1.bandmate = T2.id JOIN songs AS T3 ON T3.songid = T1.songid WHERE T3.Title = 'Flash'
CREATE TABLE performance (bandmate VARCHAR(255), songid VARCHAR(255)); CREATE TABLE songs (songid VARCHAR(255), Title VARCHAR(255)); CREATE TABLE band (id VARCHAR(255), name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2964 }
Find all the songs produced by artists with first name "Marianne".
SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.firstname = 'Marianne'
CREATE TABLE Songs (Title VARCHAR(255), SongId VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255)); CREATE TABLE Band (id VARCHAR(255), firstname VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2965 }
Who performed the song named "Badlands"? Show the first name and the last name.
SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = 'Badlands'
CREATE TABLE Band (firstname VARCHAR(255), lastname VARCHAR(255), id VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255)); CREATE TABLE Songs (SongId VARCHAR(255), Title VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2966 }
Who is performing in the back stage position for the song "Badlands"? Show the first name and the last name.
SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = 'Badlands' AND T1.StagePosition = 'back'
CREATE TABLE Band (firstname VARCHAR(255), lastname VARCHAR(255), id VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255), StagePosition VARCHAR(255)); CREATE TABLE Songs (SongId VARCHAR(255), Title VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2967 }
How many unique labels are there for albums?
SELECT COUNT(DISTINCT label) FROM albums
CREATE TABLE albums (label VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2968 }
What is the label that has the most albums?
SELECT label FROM albums GROUP BY label ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE albums (label VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2969 }
What is the last name of the musician that have produced the most number of songs?
SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY lastname ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Songs (SongId VARCHAR(255), title VARCHAR(255)); CREATE TABLE Band (lastname VARCHAR(255), id VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
5
0
0
{ "split": "train", "row_index": 2970 }
Find all the songs whose name contains the word "the".
SELECT title FROM songs WHERE title LIKE '% the %'
CREATE TABLE songs (title VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2972 }
What are all the instruments used?
SELECT DISTINCT instrument FROM Instruments
CREATE TABLE Instruments (instrument VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2973 }
What is the most used instrument?
SELECT instrument FROM instruments GROUP BY instrument ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE instruments (instrument VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2975 }
How many songs have used the instrument "drums"?
SELECT COUNT(*) FROM instruments WHERE instrument = 'drums'
CREATE TABLE instruments (instrument VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2976 }
Which vocal type is the most frequently appearring type?
SELECT TYPE FROM vocals GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE vocals (TYPE VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2982 }
Find all the vocal types.
SELECT DISTINCT TYPE FROM vocals
CREATE TABLE vocals (TYPE VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2989 }
Who performed the song named "Le Pop"?
SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = 'Le Pop'
CREATE TABLE Band (firstname VARCHAR(255), lastname VARCHAR(255), id VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Songs (SongId VARCHAR(255), Title VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2991 }
Who is performing in the back stage position for the song "Der Kapitan"? Show the first name and last name.
SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = 'Der Kapitan' AND T1.StagePosition = 'back'
CREATE TABLE Band (firstname VARCHAR(255), lastname VARCHAR(255), id VARCHAR(255)); CREATE TABLE Performance (bandmate VARCHAR(255), SongId VARCHAR(255), StagePosition VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Songs (SongId VARCHAR(255), Title VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 3002 }
What are the songs in album "A Kiss Before You Go: Live in Hamburg"?
SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE T1.title = 'A Kiss Before You Go: Live in Hamburg'
CREATE TABLE songs (title VARCHAR(255), songid VARCHAR(255)); CREATE TABLE albums (aid VARCHAR(255), title VARCHAR(255)); CREATE TABLE tracklists (albumid VARCHAR(255), songid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3003 }
Who is the founder of Sony?
SELECT founder FROM manufacturers WHERE name = 'Sony'
CREATE TABLE manufacturers (founder VARCHAR(255), name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3006 }
Where is the headquarter of the company founded by James?
SELECT headquarter FROM manufacturers WHERE founder = 'James'
CREATE TABLE manufacturers (headquarter VARCHAR(255), founder VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3007 }
Find all manufacturers' names and their headquarters, sorted by the ones with highest revenue first.
SELECT name, headquarter FROM manufacturers ORDER BY revenue DESC
CREATE TABLE manufacturers (name VARCHAR(255), headquarter VARCHAR(255), revenue VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3008 }
What are the average, maximum and total revenues of all companies?
SELECT AVG(revenue), MAX(revenue), SUM(revenue) FROM manufacturers
CREATE TABLE manufacturers (revenue INTEGER, name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 3009 }
How many companies were created by Andy?
SELECT COUNT(*) FROM manufacturers WHERE founder = 'Andy'
CREATE TABLE manufacturers (founder VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3010 }
Find the total revenue created by the companies whose headquarter is located at Austin.
SELECT SUM(revenue) FROM manufacturers WHERE headquarter = 'Austin'
CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3011 }
What are the different cities listed?
SELECT DISTINCT headquarter FROM manufacturers
CREATE TABLE manufacturers (headquarter VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3012 }
Find the number of manufactures that are based in Tokyo or Beijing.
SELECT COUNT(*) FROM manufacturers WHERE headquarter = 'Tokyo' OR headquarter = 'Beijing'
CREATE TABLE manufacturers (headquarter VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3013 }
Find the founder of the company whose name begins with the letter 'S'.
SELECT founder FROM manufacturers WHERE name LIKE 'S%'
CREATE TABLE manufacturers (founder VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3014 }
Find the name of companies whose revenue is between 100 and 150.
SELECT name FROM manufacturers WHERE revenue BETWEEN 100 AND 150
CREATE TABLE manufacturers (name VARCHAR(255), revenue INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3015 }
What is the total revenue of all companies whose main office is at Tokyo or Taiwan?
SELECT SUM(revenue) FROM manufacturers WHERE Headquarter = 'Tokyo' OR Headquarter = 'Taiwan'
CREATE TABLE manufacturers (revenue INTEGER, Headquarter VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3016 }
Find the name of product that is produced by both companies Creative Labs and Sony.
SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Creative Labs' INTERSECT SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony'
CREATE TABLE manufacturers (code VARCHAR(255), name VARCHAR(255)); CREATE TABLE products (name VARCHAR(255), Manufacturer VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 3017 }
Find the name, headquarter and founder of the manufacturer that has the highest revenue.
SELECT name, headquarter, founder FROM manufacturers ORDER BY revenue DESC LIMIT 1
CREATE TABLE manufacturers (name VARCHAR(255), headquarter VARCHAR(255), founder VARCHAR(255), revenue VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3018 }
Find the name, headquarter and revenue of all manufacturers sorted by their revenue in the descending order.
SELECT name, headquarter, revenue FROM manufacturers ORDER BY revenue DESC
CREATE TABLE manufacturers (name VARCHAR(255), headquarter VARCHAR(255), revenue VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3019 }
Find the name of companies whose revenue is greater than the average revenue of all companies.
SELECT name FROM manufacturers WHERE revenue > (SELECT AVG(revenue) FROM manufacturers)
CREATE TABLE manufacturers (name VARCHAR(255), revenue INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3020 }
Find the name of companies whose revenue is smaller than the revenue of all companies based in Austin.
SELECT name FROM manufacturers WHERE revenue < (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin')
CREATE TABLE manufacturers (name VARCHAR(255), revenue INTEGER, headquarter VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3021 }
Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin.
SELECT SUM(revenue) FROM manufacturers WHERE revenue > (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin')
CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3022 }
Find the total revenue of companies of each founder.
SELECT SUM(revenue), founder FROM manufacturers GROUP BY founder
CREATE TABLE manufacturers (founder VARCHAR(255), revenue INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3023 }
Find the name and revenue of the company that earns the highest revenue in each city.
SELECT name, MAX(revenue), Headquarter FROM manufacturers GROUP BY Headquarter
CREATE TABLE manufacturers (name VARCHAR(255), Headquarter VARCHAR(255), revenue INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3024 }
Find the total revenue for each manufacturer.
SELECT SUM(revenue), name FROM manufacturers GROUP BY name
CREATE TABLE manufacturers (name VARCHAR(255), revenue INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3025 }
Find the average prices of all products from each manufacture, and list each company's name.
SELECT AVG(T1.price), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (price INTEGER, Manufacturer VARCHAR(255)); CREATE TABLE manufacturers (name VARCHAR(255), code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3026 }
Find the number of different products that are produced by companies at different headquarter cities.
SELECT COUNT(DISTINCT T1.name), T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter
CREATE TABLE manufacturers (Headquarter VARCHAR(255), code VARCHAR(255)); CREATE TABLE products (name VARCHAR(255), Manufacturer VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3027 }
Find the number of products for each manufacturer, showing the name of each company.
SELECT COUNT(*), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Manufacturer VARCHAR(255)); CREATE TABLE manufacturers (name VARCHAR(255), code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3030 }
Select the names of all the products in the store.
SELECT Name FROM Products
CREATE TABLE Products (Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3031 }