question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
What are the details of all sales and purchases?
SELECT sales_details FROM sales UNION SELECT purchase_details FROM purchases
CREATE TABLE purchases (sales_details VARCHAR(255), purchase_details VARCHAR(255)); CREATE TABLE sales (sales_details VARCHAR(255), purchase_details VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 3361 }
How many available hotels are there in total?
SELECT COUNT(*) FROM HOTELS
CREATE TABLE HOTELS (Id VARCHAR(255), hotel_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3363 }
What are the price ranges of hotels?
SELECT price_range FROM HOTELS
CREATE TABLE HOTELS (price_range VARCHAR(255), hotel_id INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3364 }
Show all distinct location names.
SELECT DISTINCT Location_Name FROM LOCATIONS
CREATE TABLE LOCATIONS (Location_Name VARCHAR(255), location_id INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3365 }
Show the names and details of all the staff members.
SELECT Name, Other_Details FROM Staff
CREATE TABLE Staff (Name VARCHAR(255), Other_Details VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 3366 }
Show details of all visitors.
SELECT Tourist_Details FROM VISITORS
CREATE TABLE VISITORS (Tourist_Details VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3367 }
Show the price ranges of hotels with 5 star ratings.
SELECT price_range FROM HOTELS WHERE star_rating_code = '5'
CREATE TABLE HOTELS (price_range VARCHAR(255), star_rating_code VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3368 }
Show the average price range of hotels that have 5 star ratings and allow pets.
SELECT AVG(price_range) FROM HOTELS WHERE star_rating_code = '5' AND pets_allowed_yn = 1
CREATE TABLE HOTELS (price_range INTEGER, star_rating_code VARCHAR(255), pets_allowed_yn VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3369 }
What is the address of the location "UK Gallery"?
SELECT Address FROM LOCATIONS WHERE Location_Name = 'UK Gallery'
CREATE TABLE LOCATIONS (Address VARCHAR(255), Location_Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3370 }
What is the detail of the location UK Gallery?
SELECT Other_Details FROM LOCATIONS WHERE Location_Name = 'UK Gallery'
CREATE TABLE LOCATIONS (Other_Details VARCHAR(255), Location_Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3371 }
Which location names contain the word "film"?
SELECT Location_Name FROM LOCATIONS WHERE Location_Name LIKE '%film%'
CREATE TABLE LOCATIONS (Location_Name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3372 }
How many distinct names are associated with all the photos?
SELECT COUNT(DISTINCT Name) FROM PHOTOS
CREATE TABLE PHOTOS (Name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3373 }
What are the distinct visit dates?
SELECT DISTINCT Visit_Date FROM VISITS
CREATE TABLE VISITS (Visit_Date VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3374 }
What are the names of the tourist attractions that can be accessed by bus?
SELECT Name FROM TOURIST_ATTRACTIONS WHERE How_to_Get_There = 'bus'
CREATE TABLE TOURIST_ATTRACTIONS (Name VARCHAR(255), How_to_Get_There VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3375 }
What are the names and opening hours of the tourist attractions that can be accessed by bus or walk?
SELECT Name, Opening_Hours FROM TOURIST_ATTRACTIONS WHERE How_to_Get_There = 'bus' OR How_to_Get_There = 'walk'
CREATE TABLE TOURIST_ATTRACTIONS (Name VARCHAR(255), Opening_Hours VARCHAR(255), How_to_Get_There VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 3376 }
What are the star rating descriptions of the hotels with price above 10000?
SELECT T2.star_rating_description FROM HOTELS AS T1 JOIN Ref_Hotel_Star_Ratings AS T2 ON T1.star_rating_code = T2.star_rating_code WHERE T1.price_range > 10000
CREATE TABLE HOTELS (star_rating_code VARCHAR(255), price_range INTEGER); CREATE TABLE Ref_Hotel_Star_Ratings (star_rating_description VARCHAR(255), star_rating_code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3377 }
What are the details and opening hours of the museums?
SELECT T1.Museum_Details, T2.Opening_Hours FROM MUSEUMS AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Museum_ID = T2.Tourist_Attraction_ID
CREATE TABLE TOURIST_ATTRACTIONS (Opening_Hours VARCHAR(255), Tourist_Attraction_ID VARCHAR(255)); CREATE TABLE MUSEUMS (Museum_Details VARCHAR(255), Museum_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3378 }
What is the name of the tourist attraction that is associated with the photo "game1"?
SELECT T2.Name FROM PHOTOS AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID WHERE T1.Name = 'game1'
CREATE TABLE TOURIST_ATTRACTIONS (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255)); CREATE TABLE PHOTOS (Tourist_Attraction_ID VARCHAR(255), Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3379 }
What are the names and descriptions of the photos taken at the tourist attraction "film festival"?
SELECT T1.Name, T1.Description FROM PHOTOS AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID WHERE T2.Name = 'film festival'
CREATE TABLE TOURIST_ATTRACTIONS (Tourist_Attraction_ID VARCHAR(255), Name VARCHAR(255)); CREATE TABLE PHOTOS (Name VARCHAR(255), Description VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3380 }
What are the details and ways to get to tourist attractions related to royal family?
SELECT T1.Royal_Family_Details, T2.How_to_Get_There FROM ROYAL_FAMILY AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Royal_Family_ID = T2.Tourist_Attraction_ID
CREATE TABLE TOURIST_ATTRACTIONS (How_to_Get_There VARCHAR(255), Tourist_Attraction_ID VARCHAR(255)); CREATE TABLE ROYAL_FAMILY (Royal_Family_Details VARCHAR(255), Royal_Family_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3381 }
What are the details of the shops that can be accessed by walk?
SELECT T1.Shop_Details FROM SHOPS AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Shop_ID = T2.Tourist_Attraction_ID WHERE T2.How_to_Get_There = 'walk'
CREATE TABLE TOURIST_ATTRACTIONS (Tourist_Attraction_ID VARCHAR(255), How_to_Get_There VARCHAR(255)); CREATE TABLE SHOPS (Shop_Details VARCHAR(255), Shop_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3382 }
What is the name of the staff that is in charge of the attraction named "US museum"?
SELECT T1.Name FROM STAFF AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID WHERE T2.Name = 'US museum'
CREATE TABLE TOURIST_ATTRACTIONS (Tourist_Attraction_ID VARCHAR(255), Name VARCHAR(255)); CREATE TABLE STAFF (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3383 }
What are the details of the markets that can be accessed by walk or bus?
SELECT T1.Market_Details FROM Street_Markets AS T1 JOIN TOURIST_ATTRACTIONS AS T2 ON T1.Market_ID = T2.Tourist_Attraction_ID WHERE T2.How_to_Get_There = 'walk' OR T2.How_to_Get_There = 'bus'
CREATE TABLE Street_Markets (Market_Details VARCHAR(255), Market_ID VARCHAR(255)); CREATE TABLE TOURIST_ATTRACTIONS (Tourist_Attraction_ID VARCHAR(255), How_to_Get_There VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 3384 }
What are the visit date and details of the visitor whose detail is 'Vincent'?
SELECT T2.Visit_Date, T2.Visit_Details FROM VISITORS AS T1 JOIN VISITS AS T2 ON T1.Tourist_ID = T2.Tourist_ID WHERE T1.Tourist_Details = 'Vincent'
CREATE TABLE VISITORS (Tourist_ID VARCHAR(255), Tourist_Details VARCHAR(255)); CREATE TABLE VISITS (Visit_Date VARCHAR(255), Visit_Details VARCHAR(255), Tourist_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3385 }
Which tourist attractions does the visitor with detail 'Vincent' visit?
SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID JOIN VISITORS AS T3 ON T2.Tourist_ID = T3.Tourist_ID WHERE T3.Tourist_Details = 'Vincent'
CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR(255), Tourist_ID VARCHAR(255)); CREATE TABLE VISITORS (Tourist_ID VARCHAR(255), Tourist_Details VARCHAR(255)); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3386 }
What are the names of the tourist attractions and the dates when the tourists named Vincent or Vivian visited there?
SELECT T1.Name, T3.Visit_Date FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = 'Vincent' OR T2.Tourist_Details = 'Vivian'
CREATE TABLE VISITORS (Tourist_ID VARCHAR(255), Tourist_Details VARCHAR(255)); CREATE TABLE VISITS (Visit_Date VARCHAR(255), Tourist_Attraction_ID VARCHAR(255), Tourist_ID VARCHAR(255)); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 3387 }
Show the average price of hotels for each star rating code.
SELECT star_rating_code, AVG(price_range) FROM HOTELS GROUP BY star_rating_code
CREATE TABLE HOTELS (star_rating_code VARCHAR(255), price_range INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3388 }
Show the average price of hotels for different pet policy.
SELECT pets_allowed_yn, AVG(price_range) FROM HOTELS GROUP BY pets_allowed_yn
CREATE TABLE HOTELS (pets_allowed_yn VARCHAR(255), price_range INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3389 }
Show the id and star rating of each hotel, ordered by its price from low to high.
SELECT hotel_id, star_rating_code FROM HOTELS ORDER BY price_range
CREATE TABLE HOTELS (hotel_id VARCHAR(255), star_rating_code VARCHAR(255), price_range VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3390 }
Show the details of the top 3 most expensive hotels.
SELECT other_hotel_details FROM HOTELS ORDER BY price_range DESC LIMIT 3
CREATE TABLE HOTELS (other_hotel_details VARCHAR(255), price_range VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3391 }
Show the details and star ratings of the 3 least expensive hotels.
SELECT other_hotel_details, star_rating_code FROM HOTELS ORDER BY price_range LIMIT 3
CREATE TABLE HOTELS (other_hotel_details VARCHAR(255), star_rating_code VARCHAR(255), price_range VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3392 }
Show the transportation method most people choose to get to tourist attractions.
SELECT How_to_Get_There FROM Tourist_Attractions GROUP BY How_to_Get_There ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Tourist_Attractions (How_to_Get_There VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3393 }
Show the description and code of the attraction type most tourist attractions belong to.
SELECT T1.Attraction_Type_Description, T2.Attraction_Type_Code FROM Ref_Attraction_Types AS T1 JOIN Tourist_Attractions AS T2 ON T1.Attraction_Type_Code = T2.Attraction_Type_Code GROUP BY T2.Attraction_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Ref_Attraction_Types (Attraction_Type_Description VARCHAR(255), Attraction_Type_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Tourist_Attractions (Attraction_Type_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 3394 }
Show different ways to get to attractions and the number of attractions that can be accessed in the corresponding way.
SELECT How_to_Get_There, COUNT(*) FROM Tourist_Attractions GROUP BY How_to_Get_There
CREATE TABLE Tourist_Attractions (How_to_Get_There VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3395 }
Show different tourist attractions' names, ids, and the corresponding number of visits.
SELECT T1.Name, T2.Tourist_Attraction_ID, COUNT(*) FROM Tourist_Attractions AS T1 JOIN VISITS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID GROUP BY T2.Tourist_Attraction_ID
CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3396 }
Show the names and ids of tourist attractions that are visited at least two times.
SELECT T1.Name, T2.Tourist_Attraction_ID FROM Tourist_Attractions AS T1 JOIN VISITS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID GROUP BY T2.Tourist_Attraction_ID HAVING COUNT(*) >= 2
CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3397 }
Show the names and ids of tourist attractions that are visited at most once.
SELECT T1.Name, T1.Tourist_Attraction_ID FROM Tourist_Attractions AS T1 JOIN VISITS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID GROUP BY T2.Tourist_Attraction_ID HAVING COUNT(*) <= 1
CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3398 }
What are the names of tourist attractions that can be reached by walk or is at address 660 Shea Crescent?
SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID = T2.Location_ID WHERE T1.Address = '660 Shea Crescent' OR T2.How_to_Get_There = 'walk'
CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Location_ID VARCHAR(255), How_to_Get_There VARCHAR(255)); CREATE TABLE Locations (Location_ID VARCHAR(255), Address VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 3399 }
What are the names of the tourist attractions that have parking or shopping as their feature details?
SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'park' UNION SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON...
CREATE TABLE Tourist_Attraction_Features (tourist_attraction_id VARCHAR(255), Feature_ID VARCHAR(255)); CREATE TABLE Features (Feature_ID VARCHAR(255), feature_Details VARCHAR(255)); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), tourist_attraction_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 3400 }
What are the names of tourist attractions that can be reached by bus or is at address 254 Ottilie Junction?
SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID = T2.Location_ID WHERE T1.Address = '254 Ottilie Junction' OR T2.How_to_Get_There = 'bus'
CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Location_ID VARCHAR(255), How_to_Get_There VARCHAR(255)); CREATE TABLE Locations (Location_ID VARCHAR(255), Address VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 3401 }
What are the names of the tourist attractions Vincent and Marcelle visit?
SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = 'Vincent' INTERSECT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_At...
CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR(255), Tourist_ID VARCHAR(255)); CREATE TABLE VISITORS (Tourist_Details VARCHAR(255), Tourist_ID VARCHAR(255)); CREATE TABLE Tourist_Attractions (Name VARCHAR(255), Tourist_Attraction_ID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 3402 }
How many video games exist?
SELECT COUNT(*) FROM Video_games
CREATE TABLE Video_games (gtype VARCHAR(255), gname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3405 }
How many video game types exist?
SELECT COUNT(DISTINCT gtype) FROM Video_games
CREATE TABLE Video_games (gtype VARCHAR(255), gname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3406 }
Show all video game types.
SELECT DISTINCT gtype FROM Video_games
CREATE TABLE Video_games (gname VARCHAR(255), gtype VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3407 }
Show all video games and their types in the order of their names.
SELECT gname, gtype FROM Video_games ORDER BY gname
CREATE TABLE Video_games (gname VARCHAR(255), gtype VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3408 }
Show all video games with type Collectible card game.
SELECT gname FROM Video_games WHERE gtype = 'Collectible card game'
CREATE TABLE Video_games (gname VARCHAR(255), gtype VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3409 }
What is the type of video game Call of Destiny.
SELECT gtype FROM Video_games WHERE gname = 'Call of Destiny'
CREATE TABLE Video_games (gtype VARCHAR(255), gname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3410 }
How many video games have type Massively multiplayer online game?
SELECT COUNT(*) FROM Video_games WHERE gtype = 'Massively multiplayer online game'
CREATE TABLE Video_games (gtype VARCHAR(255), gname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3411 }
Show all video game types and the number of video games in each type.
SELECT gtype, COUNT(*) FROM Video_games GROUP BY gtype
CREATE TABLE Video_games (gtype VARCHAR(255), gname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3412 }
Which game type has most number of games?
SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Video_games (gtype VARCHAR(255), gname VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3413 }
Which game type has least number of games?
SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) LIMIT 1
CREATE TABLE Video_games (gtype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3414 }
Show ids for all students who live in CHI.
SELECT StuID FROM Student WHERE city_code = 'CHI'
CREATE TABLE Student (StuID VARCHAR(255), city_code VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3415 }
Show ids for all students who have advisor 1121.
SELECT StuID FROM Student WHERE Advisor = 1121
CREATE TABLE Student (StuID VARCHAR(255), Advisor VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3416 }
Show first name for all students with major 600.
SELECT Fname FROM Student WHERE Major = 600
CREATE TABLE Student (Fname VARCHAR(255), Major VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3417 }
Show the average, minimum, and maximum age for different majors.
SELECT major, AVG(age), MIN(age), MAX(age) FROM Student GROUP BY major
CREATE TABLE Student (major VARCHAR(255), age INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 3418 }
Show all advisors who have at least two students.
SELECT advisor FROM Student GROUP BY advisor HAVING COUNT(*) >= 2
CREATE TABLE Student (advisor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3419 }
How many sports do we have?
SELECT COUNT(DISTINCT sportname) FROM Sportsinfo
CREATE TABLE Sportsinfo (sportname VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3420 }
How many students play sports?
SELECT COUNT(DISTINCT StuID) FROM Sportsinfo
CREATE TABLE Sportsinfo (StuID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3421 }
List ids for all student who are on scholarship.
SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
CREATE TABLE Sportsinfo (StuID VARCHAR(255), onscholarship VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3422 }
Show last names for all student who are on scholarship.
SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y'
CREATE TABLE Student (Lname VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Sportsinfo (StuID VARCHAR(255), onscholarship VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3423 }
How many games are played for all students?
SELECT SUM(gamesplayed) FROM Sportsinfo
CREATE TABLE Sportsinfo (gamesplayed INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3424 }
How many games are played for all football games by students on scholarship?
SELECT SUM(gamesplayed) FROM Sportsinfo WHERE sportname = 'Football' AND onscholarship = 'Y'
CREATE TABLE Sportsinfo (gamesplayed INTEGER, sportname VARCHAR(255), onscholarship VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3425 }
Show all sport name and the number of students.
SELECT sportname, COUNT(*) FROM Sportsinfo GROUP BY sportname
CREATE TABLE Sportsinfo (sportname VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3426 }
Show all student IDs with the number of sports and total number of games played
SELECT StuID, COUNT(*), SUM(gamesplayed) FROM Sportsinfo GROUP BY StuID
CREATE TABLE Sportsinfo (StuID VARCHAR(255), gamesplayed INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 3427 }
Show all student IDs with more than total 10 hours per week on all sports played.
SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING SUM(hoursperweek) > 10
CREATE TABLE Sportsinfo (StuID VARCHAR(255), hoursperweek INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3428 }
What is the first name and last name of the student who have most number of sports?
SELECT T2.Fname, T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student (Fname VARCHAR(255), Lname VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Sportsinfo (StuID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 3429 }
Which sport has most number of students on scholarship?
SELECT sportname FROM Sportsinfo WHERE onscholarship = 'Y' GROUP BY sportname ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Sportsinfo (sportname VARCHAR(255), onscholarship VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 3430 }
Show student ids who don't have any sports.
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
CREATE TABLE Sportsinfo (StuID VARCHAR(255), extra VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), extra VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 3431 }
Show student ids who are on scholarship and have major 600.
SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
CREATE TABLE Sportsinfo (StuID VARCHAR(255), major VARCHAR(255), onscholarship VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), major VARCHAR(255), onscholarship VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3432 }
Show student ids who are female and play football.
SELECT StuID FROM Student WHERE sex = 'F' INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = 'Football'
CREATE TABLE Sportsinfo (StuID VARCHAR(255), sex VARCHAR(255), sportname VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), sex VARCHAR(255), sportname VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3433 }
Show all male student ids who don't play football.
SELECT StuID FROM Student WHERE sex = 'M' EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = 'Football'
CREATE TABLE Sportsinfo (StuID VARCHAR(255), sex VARCHAR(255), sportname VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), sex VARCHAR(255), sportname VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3434 }
How many students play video games?
SELECT COUNT(DISTINCT StuID) FROM Plays_games
CREATE TABLE Plays_games (StuID VARCHAR(255), dummy VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3437 }
Show ids of students who don't play video game.
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
CREATE TABLE Plays_games (StuID VARCHAR(255), dummy VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), dummy VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 3438 }
Show ids of students who play video game and play sports.
SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
CREATE TABLE Plays_games (StuID VARCHAR(255), dummy VARCHAR(255)); CREATE TABLE Sportsinfo (StuID VARCHAR(255), dummy VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 3439 }
Show all game ids and the number of hours played.
SELECT gameid, SUM(hours_played) FROM Plays_games GROUP BY gameid
CREATE TABLE Plays_games (gameid VARCHAR(255), hours_played INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3440 }
Show all student ids and the number of hours played.
SELECT Stuid, SUM(hours_played) FROM Plays_games GROUP BY Stuid
CREATE TABLE Plays_games (Stuid VARCHAR(255), hours_played INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 3441 }
Find the last and first name of students who are playing Football or Lacrosse.
SELECT T2.lname, T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = 'Football' OR T1.SportName = 'Lacrosse'
CREATE TABLE SportsInfo (StuID VARCHAR(255), SportName VARCHAR(255)); CREATE TABLE Student (lname VARCHAR(255), fname VARCHAR(255), StuID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 3445 }
Find the first name and age of the students who are playing both Football and Lacrosse.
SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = 'Football' INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = 'Lacrosse')
CREATE TABLE Student (fname VARCHAR(255), age VARCHAR(255), StuID VARCHAR(255), SportName VARCHAR(255)); CREATE TABLE Sportsinfo (fname VARCHAR(255), age VARCHAR(255), StuID VARCHAR(255), SportName VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 3446 }
Find the last name and gender of the students who are playing both Call of Destiny and Works of Widenius games.
SELECT lname, sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = 'Call of Destiny' INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = 'Works of Widenius')
CREATE TABLE Plays_games (StuID VARCHAR(255), GameID VARCHAR(255)); CREATE TABLE Student (lname VARCHAR(255), sex VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Video_games (GameID VARCHAR(255), Gname VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 3447 }
Find the name of all customers.
SELECT customer_name FROM customers
CREATE TABLE customers (customer_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3448 }
What is the average amount of items ordered in each order?
SELECT AVG(order_quantity) FROM order_items
CREATE TABLE order_items (order_quantity INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3449 }
What are the names of customers who use payment method "Cash"?
SELECT customer_name FROM customers WHERE payment_method = 'Cash'
CREATE TABLE customers (customer_name VARCHAR(255), payment_method VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3450 }
Find the "date became customers" of the customers whose ID is between 10 and 20.
SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
CREATE TABLE customers (date_became_customer VARCHAR(255), customer_id INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3451 }
Which payment method is used by most customers?
SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE customers (payment_method VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3452 }
What are the names of customers using the most popular payment method?
SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1)
CREATE TABLE customers (customer_name VARCHAR(255), payment_method VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 3453 }
What are all the payment methods?
SELECT DISTINCT payment_method FROM customers
CREATE TABLE customers (payment_method VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3454 }
What are the details of all products?
SELECT DISTINCT product_details FROM products
CREATE TABLE products (product_details VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 3455 }
Find the name of all customers whose name contains "Alex".
SELECT customer_name FROM customers WHERE customer_name LIKE '%Alex%'
CREATE TABLE customers (customer_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3456 }
Find the detail of products whose detail contains the word "Latte" or the word "Americano"
SELECT product_details FROM products WHERE product_details LIKE '%Latte%' OR product_details LIKE '%Americano%'
CREATE TABLE products (product_details VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 3457 }
What is the address content of the customer named "Maudie Kertzmann"?
SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = 'Maudie Kertzmann'
CREATE TABLE customers (customer_id VARCHAR(255), customer_name VARCHAR(255)); CREATE TABLE customer_addresses (customer_id VARCHAR(255), address_id VARCHAR(255)); CREATE TABLE addresses (address_content VARCHAR(255), address_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3458 }
How many customers are living in city "Lake Geovannyton"?
SELECT COUNT(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = 'Lake Geovannyton'
CREATE TABLE customers (customer_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE addresses (address_id VARCHAR(255), city VARCHAR(255)); CREATE TABLE customer_addresses (customer_id VARCHAR(255), address_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3459 }
Find the name of customers who are living in Colorado?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'Colorado'
CREATE TABLE customer_addresses (customer_id VARCHAR(255), address_id VARCHAR(255)); CREATE TABLE customers (customer_name VARCHAR(255), customer_id VARCHAR(255)); CREATE TABLE addresses (address_id VARCHAR(255), state_province_county VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 3460 }
Which city has the most customers living in?
SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE customers (customer_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE addresses (city VARCHAR(255), address_id VARCHAR(255)); CREATE TABLE customer_addresses (customer_id VARCHAR(255), address_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
5
0
0
{ "split": "train", "row_index": 3462 }
Find the city with post code 255.
SELECT city FROM addresses WHERE zip_postcode = 255
CREATE TABLE addresses (city VARCHAR(255), zip_postcode VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3463 }
Find the state and country of all cities with post code starting with 4.
SELECT state_province_county, country FROM addresses WHERE zip_postcode LIKE '4%'
CREATE TABLE addresses (state_province_county VARCHAR(255), country VARCHAR(255), zip_postcode VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 3464 }
List the countries having more than 4 addresses listed.
SELECT country FROM addresses GROUP BY country HAVING COUNT(address_id) > 4
CREATE TABLE addresses (country VARCHAR(255), address_id VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3465 }
List all the contact channel codes that were used less than 5 times.
SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING COUNT(customer_id) < 5
CREATE TABLE customer_contact_channels (channel_code VARCHAR(255), customer_id VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 3466 }
What is the "active to date" of the latest contact channel used by "Tillman Ernser"?
SELECT MAX(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = 'Tillman Ernser'
CREATE TABLE customers (customer_id VARCHAR(255), customer_name VARCHAR(255)); CREATE TABLE customer_contact_channels (active_to_date INTEGER, customer_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 3468 }
What is the average time span of contact channels in the database?
SELECT AVG(active_to_date - active_from_date) FROM customer_contact_channels
CREATE TABLE customer_contact_channels (active_to_date VARCHAR(255), active_from_date VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
null
easy
extended
valid
valid
valid
[]
[]
[]
[ "Unsupported column expression: active_to_date - active_from_date" ]
[ "validated", "extended", "extended" ]
null
null
null
null
{ "split": "train", "row_index": 3469 }
What is the channel code and contact number of the customer contact channel that was active for the longest time?
SELECT channel_code, contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1)
CREATE TABLE customer_contact_channels (channel_code VARCHAR(255), contact_number VARCHAR(255), active_to_date VARCHAR(255), active_from_date VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 3470 }