question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
What are the names and id of courses having at most 2 sections?
SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2
CREATE TABLE Courses (course_name VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Sections (course_id VARCHAR(255), section_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4249 }
List the section_name in reversed lexicographical order.
SELECT section_name FROM Sections ORDER BY section_name DESC
CREATE TABLE Sections (section_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4250 }
What is the semester which most student registered in? Show both the name and the id.
SELECT T1.semester_name, T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student_Enrolment (semester_id VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Semesters (semester_name VARCHAR(255), semester_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 4251 }
What is the description of the department whose name has the substring the computer?
SELECT department_description FROM Departments WHERE department_name LIKE '%computer%'
CREATE TABLE Departments (department_description VARCHAR(255), department_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4252 }
Who are enrolled in 2 degree programs in one semester? List the first name, middle name and last name and the id.
SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2
CREATE TABLE Students (first_name VARCHAR(255), middle_name VARCHAR(255), last_name VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Student_Enrolment (student_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4253 }
Who is enrolled in a Bachelor degree program? List the first name, middle name, last name.
SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor'
CREATE TABLE Degree_Programs (degree_program_id VARCHAR(255), degree_summary_name VARCHAR(255)); CREATE TABLE Students (first_name VARCHAR(255), middle_name VARCHAR(255), last_name VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Student_Enrolment (student_id VARCHAR(255), degree_program_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 4254 }
Find the kind of program which most number of students are enrolled in?
SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student_Enrolment (degree_program_id VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Degree_Programs (degree_summary_name VARCHAR(255), degree_program_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 4255 }
Find the program which most number of students are enrolled in. List both the id and the summary.
SELECT T1.degree_program_id, T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Degree_Programs (degree_program_id VARCHAR(255), degree_summary_name VARCHAR(255)); CREATE TABLE Student_Enrolment (degree_program_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 4256 }
Which student has enrolled for the most times in any program? List the id, first name, middle name, last name, the number of enrollments and student id.
SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Students (student_id VARCHAR(255), first_name VARCHAR(255), middle_name VARCHAR(255), last_name VARCHAR(255)); CREATE TABLE Student_Enrolment (student_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 4257 }
Which semesters do not have any student enrolled? List the semester name.
SELECT semester_name FROM Semesters WHERE NOT semester_id IN (SELECT semester_id FROM Student_Enrolment)
CREATE TABLE Student_Enrolment (semester_name VARCHAR(255), semester_id VARCHAR(255)); CREATE TABLE Semesters (semester_name VARCHAR(255), semester_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 4258 }
What are all the course names of the courses which ever have students enrolled in?
SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
CREATE TABLE Courses (course_name VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Student_Enrolment_Courses (course_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4259 }
What's the name of the course with most number of enrollments?
SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Courses (course_name VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Student_Enrolment_Courses (course_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 4260 }
Show the date and id of the transcript with at least 2 course results.
SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
CREATE TABLE Transcript_Contents (transcript_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Transcripts (transcript_date VARCHAR(255), transcript_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4262 }
What is the phone number of the man with the first name Timmothy and the last name Ward?
SELECT cell_mobile_number FROM Students WHERE first_name = 'Timmothy' AND last_name = 'Ward'
CREATE TABLE Students (cell_mobile_number VARCHAR(255), first_name VARCHAR(255), last_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4263 }
What is the mobile phone number of the student named Timmothy Ward ?
SELECT cell_mobile_number FROM students WHERE first_name = 'timmothy' AND last_name = 'ward'
CREATE TABLE students (cell_mobile_number VARCHAR(255), first_name VARCHAR(255), last_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4264 }
Who is the first student to register? List the first name, middle name and last name.
SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered LIMIT 1
CREATE TABLE Students (first_name VARCHAR(255), middle_name VARCHAR(255), last_name VARCHAR(255), date_first_registered VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4265 }
Who is the earliest graduate of the school? List the first name, middle name and last name.
SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left LIMIT 1
CREATE TABLE Students (first_name VARCHAR(255), middle_name VARCHAR(255), last_name VARCHAR(255), date_left VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4266 }
Whose permanent address is different from his or her current address? List his or her first name.
SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id
CREATE TABLE Students (first_name VARCHAR(255), current_address_id VARCHAR(255), permanent_address_id VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4267 }
Which address holds the most number of students currently? List the address id and all lines.
SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Addresses (address_id VARCHAR(255), line_1 VARCHAR(255), line_2 VARCHAR(255)); CREATE TABLE Students (current_address_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 4268 }
On average, when were the transcripts printed?
SELECT AVG(transcript_date) FROM Transcripts
CREATE TABLE Transcripts (transcript_date INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4269 }
When is the first transcript released? List the date and details.
SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date LIMIT 1
CREATE TABLE Transcripts (transcript_date VARCHAR(255), other_details VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4270 }
How many transcripts are released?
SELECT COUNT(*) FROM Transcripts
CREATE TABLE Transcripts (Id VARCHAR(255), other_column VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4271 }
What is the last transcript release date?
SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1
CREATE TABLE Transcripts (transcript_date VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4272 }
How many times at most can a course enrollment result show in different transcripts? Also show the course enrollment id.
SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Transcript_Contents (student_course_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 4273 }
Show the date of the transcript which shows the least number of results, also list the id.
SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) LIMIT 1
CREATE TABLE Transcript_Contents (transcript_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Transcripts (transcript_date VARCHAR(255), transcript_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 4274 }
How many different addresses do the students currently live?
SELECT COUNT(DISTINCT current_address_id) FROM Students
CREATE TABLE Students (current_address_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4276 }
List all the student details in reversed lexicographical order.
SELECT other_student_details FROM Students ORDER BY other_student_details DESC
CREATE TABLE Students (other_student_details VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4277 }
Describe the section h.
SELECT section_description FROM Sections WHERE section_name = 'h'
CREATE TABLE Sections (section_description VARCHAR(255), section_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4278 }
Find the first name of the students who permanently live in the country Haiti or have the cell phone number 09700166582 .
SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582'
CREATE TABLE students (first_name VARCHAR(255), permanent_address_id VARCHAR(255), cell_mobile_number VARCHAR(255)); CREATE TABLE addresses (address_id VARCHAR(255), country VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 4279 }
List all cartoon directed by "Ben Jones".
SELECT Title FROM Cartoon WHERE Directed_by = 'Ben Jones'
CREATE TABLE Cartoon (Title VARCHAR(255), Directed_by VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4281 }
How many cartoons were written by "Joseph Kuhr"?
SELECT COUNT(*) FROM Cartoon WHERE Written_by = 'Joseph Kuhr'
CREATE TABLE Cartoon (Written_by VARCHAR(255), Title VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4282 }
list all cartoon titles and their directors ordered by their air date
SELECT title, Directed_by FROM Cartoon ORDER BY Original_air_date
CREATE TABLE Cartoon (title VARCHAR(255), Directed_by VARCHAR(255), Original_air_date VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4283 }
List the title of all cartoon directed by "Ben Jones" or "Brandon Vietti".
SELECT Title FROM Cartoon WHERE Directed_by = 'Ben Jones' OR Directed_by = 'Brandon Vietti'
CREATE TABLE Cartoon (Title VARCHAR(255), Directed_by VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4284 }
Which country has the most of TV Channels? List the country and number of TV Channels it has.
SELECT Country, COUNT(*) FROM TV_Channel GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE TV_Channel (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 4285 }
List the number of different series names and contents in the TV Channel table.
SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel
CREATE TABLE TV_Channel (series_name VARCHAR(255), content VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 4286 }
What is the content of TV Channel with serial name "Sky Radio"?
SELECT Content FROM TV_Channel WHERE series_name = 'Sky Radio'
CREATE TABLE TV_Channel (Content VARCHAR(255), series_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4287 }
What is the Package Option of TV Channel with serial name "Sky Radio"?
SELECT Package_Option FROM TV_Channel WHERE series_name = 'Sky Radio'
CREATE TABLE TV_Channel (Package_Option VARCHAR(255), series_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4288 }
How many TV Channel using language English?
SELECT COUNT(*) FROM TV_Channel WHERE LANGUAGE = 'English'
CREATE TABLE TV_Channel (LANGUAGE VARCHAR(255), channel_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4289 }
List the language used least number of TV Channel. List language and number of TV Channel.
SELECT LANGUAGE, COUNT(*) FROM TV_Channel GROUP BY LANGUAGE ORDER BY COUNT(*) LIMIT 1
CREATE TABLE TV_Channel (LANGUAGE VARCHAR(255), channel_name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 4290 }
List each language and the number of TV Channels using it.
SELECT LANGUAGE, COUNT(*) FROM TV_Channel GROUP BY LANGUAGE
CREATE TABLE TV_Channel (LANGUAGE VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4291 }
What is the TV Channel that shows the cartoon "The Rise of the Blue Beetle!"? List the TV Channel's series name.
SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = 'The Rise of the Blue Beetle!'
CREATE TABLE Cartoon (Channel VARCHAR(255), Title VARCHAR(255)); CREATE TABLE TV_Channel (series_name VARCHAR(255), id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4292 }
List the title of all Cartoons showed on TV Channel with series name "Sky Radio".
SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = 'Sky Radio'
CREATE TABLE Cartoon (Title VARCHAR(255), Channel VARCHAR(255)); CREATE TABLE TV_Channel (id VARCHAR(255), series_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4293 }
List the Episode of all TV series sorted by rating.
SELECT Episode FROM TV_series ORDER BY rating
CREATE TABLE TV_series (Episode VARCHAR(255), rating VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4294 }
List top 3 highest Rating TV series. List the TV series's Episode and Rating.
SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3
CREATE TABLE TV_series (Episode VARCHAR(255), Rating VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4295 }
What is minimum and maximum share of TV series?
SELECT MAX(SHARE), MIN(SHARE) FROM TV_series
CREATE TABLE TV_series (SHARE INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 4296 }
What is the air date of TV series with Episode "A Love of a Lifetime"?
SELECT Air_Date FROM TV_series WHERE Episode = 'A Love of a Lifetime'
CREATE TABLE TV_series (Air_Date VARCHAR(255), Episode VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4297 }
What is Weekly Rank of TV series with Episode "A Love of a Lifetime"?
SELECT Weekly_Rank FROM TV_series WHERE Episode = 'A Love of a Lifetime'
CREATE TABLE TV_series (Weekly_Rank VARCHAR(255), Episode VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4298 }
What is the TV Channel of TV series with Episode "A Love of a Lifetime"? List the TV Channel's series name.
SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = 'A Love of a Lifetime'
CREATE TABLE TV_series (Channel VARCHAR(255), Episode VARCHAR(255)); CREATE TABLE TV_Channel (series_name VARCHAR(255), id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4299 }
List the Episode of all TV series showed on TV Channel with series name "Sky Radio".
SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = 'Sky Radio'
CREATE TABLE TV_Channel (id VARCHAR(255), series_name VARCHAR(255)); CREATE TABLE TV_series (Episode VARCHAR(255), Channel VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4300 }
Find the number of cartoons directed by each of the listed directors.
SELECT COUNT(*), Directed_by FROM cartoon GROUP BY Directed_by
CREATE TABLE cartoon (Directed_by VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4301 }
Find the production code and channel of the most recently aired cartoon .
SELECT production_code, channel FROM cartoon ORDER BY original_air_date DESC LIMIT 1
CREATE TABLE cartoon (production_code VARCHAR(255), channel VARCHAR(255), original_air_date VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4302 }
Find the package choice and series name of the TV channel that has high definition TV.
SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = 'yes'
CREATE TABLE TV_Channel (package_option VARCHAR(255), series_name VARCHAR(255), hight_definition_TV VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4303 }
which countries' tv channels are playing some cartoon written by Todd Casey?
SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey'
CREATE TABLE TV_Channel (country VARCHAR(255), id VARCHAR(255)); CREATE TABLE cartoon (Channel VARCHAR(255), written_by VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4304 }
Find the series name and country of the tv channel that is playing some cartoons directed by Ben Jones and Michael Chang?
SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones'
CREATE TABLE TV_Channel (series_name VARCHAR(255), country VARCHAR(255), id VARCHAR(255)); CREATE TABLE cartoon (Channel VARCHAR(255), directed_by VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
1
{ "split": "train", "row_index": 4306 }
find the pixel aspect ratio and nation of the tv channels that do not use English.
SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English'
CREATE TABLE tv_channel (Pixel_aspect_ratio_PAR VARCHAR(255), country VARCHAR(255), LANGUAGE VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4307 }
find id of the tv channels that from the countries where have more than two tv channels.
SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2
CREATE TABLE tv_channel (id VARCHAR(255), country VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4308 }
find the id of tv channels that do not play any cartoon directed by Ben Jones.
SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones'
CREATE TABLE TV_Channel (id VARCHAR(255), channel VARCHAR(255), directed_by VARCHAR(255)); CREATE TABLE cartoon (id VARCHAR(255), channel VARCHAR(255), directed_by VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 4309 }
find the package option of the tv channel that do not have any cartoon directed by Ben Jones.
SELECT package_option FROM TV_Channel WHERE NOT id IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones')
CREATE TABLE cartoon (package_option VARCHAR(255), id VARCHAR(255), channel VARCHAR(255), directed_by VARCHAR(255)); CREATE TABLE TV_Channel (package_option VARCHAR(255), id VARCHAR(255), channel VARCHAR(255), directed_by VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 4310 }
How many poker players are there?
SELECT COUNT(*) FROM poker_player
CREATE TABLE poker_player (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4311 }
List the earnings of poker players in descending order.
SELECT Earnings FROM poker_player ORDER BY Earnings DESC
CREATE TABLE poker_player (Earnings VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4312 }
List the final tables made and the best finishes of poker players.
SELECT Final_Table_Made, Best_Finish FROM poker_player
CREATE TABLE poker_player (Final_Table_Made VARCHAR(255), Best_Finish VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 4313 }
What is the average earnings of poker players?
SELECT AVG(Earnings) FROM poker_player
CREATE TABLE poker_player (Earnings INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4314 }
What is the money rank of the poker player with the highest earnings?
SELECT Money_Rank FROM poker_player ORDER BY Earnings DESC LIMIT 1
CREATE TABLE poker_player (Money_Rank VARCHAR(255), Earnings VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4315 }
What are the names of poker players?
SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID
CREATE TABLE poker_player (People_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4317 }
What are the names of poker players whose earnings is higher than 300000?
SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000
CREATE TABLE poker_player (People_ID VARCHAR(255), Earnings INTEGER); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4318 }
List the names of poker players ordered by the final tables made in ascending order.
SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made
CREATE TABLE poker_player (People_ID VARCHAR(255), Final_Table_Made VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4319 }
What is the birth date of the poker player with the lowest earnings?
SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings LIMIT 1
CREATE TABLE poker_player (People_ID VARCHAR(255), Earnings VARCHAR(255)); CREATE TABLE people (Birth_Date VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 4320 }
What is the money rank of the tallest poker player?
SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1
CREATE TABLE people (People_ID VARCHAR(255), Height VARCHAR(255)); CREATE TABLE poker_player (Money_Rank VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 4321 }
What is the average earnings of poker players with height higher than 200?
SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200
CREATE TABLE people (People_ID VARCHAR(255), Height INTEGER); CREATE TABLE poker_player (Earnings INTEGER, People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4322 }
What are the names of poker players in descending order of earnings?
SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC
CREATE TABLE poker_player (People_ID VARCHAR(255), Earnings VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4323 }
What are different nationalities of people and the corresponding number of people from each nation?
SELECT Nationality, COUNT(*) FROM people GROUP BY Nationality
CREATE TABLE people (Nationality VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4324 }
What is the most common nationality of people?
SELECT Nationality FROM people GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE people (Nationality VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 4325 }
What are the nationalities that are shared by at least two people?
SELECT Nationality FROM people GROUP BY Nationality HAVING COUNT(*) >= 2
CREATE TABLE people (Nationality VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4326 }
List the names and birth dates of people in ascending alphabetical order of name.
SELECT Name, Birth_Date FROM people ORDER BY Name
CREATE TABLE people (Name VARCHAR(255), Birth_Date VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4327 }
Show names of people whose nationality is not "Russia".
SELECT Name FROM people WHERE Nationality <> 'Russia'
CREATE TABLE people (Name VARCHAR(255), Nationality VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4328 }
List the names of people that are not poker players.
SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM poker_player)
CREATE TABLE poker_player (Name VARCHAR(255), People_ID VARCHAR(255)); CREATE TABLE people (Name VARCHAR(255), People_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 4329 }
How many distinct nationalities are there?
SELECT COUNT(DISTINCT Nationality) FROM people
CREATE TABLE people (Nationality VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4330 }
How many states are there?
SELECT COUNT(*) FROM area_code_state
CREATE TABLE area_code_state (Id VARCHAR(255), description VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 4331 }
List the contestant numbers and names, ordered by contestant name descending.
SELECT contestant_number, contestant_name FROM contestants ORDER BY contestant_name DESC
CREATE TABLE contestants (contestant_number VARCHAR(255), contestant_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4332 }
List the vote ids, phone numbers and states of all votes.
SELECT vote_id, phone_number, state FROM votes
CREATE TABLE votes (vote_id VARCHAR(255), phone_number VARCHAR(255), state VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 4333 }
What are the maximum and minimum values of area codes?
SELECT MAX(area_code), MIN(area_code) FROM area_code_state
CREATE TABLE area_code_state (area_code INTEGER, id INTEGER PRIMARY KEY AUTOINCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 4334 }
What is last date created of votes from the state 'CA'?
SELECT MAX(created) FROM votes WHERE state = 'CA'
CREATE TABLE votes (created INTEGER, state VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4335 }
What are the names of the contestants whose names are not 'Jessie Alloway'
SELECT contestant_name FROM contestants WHERE contestant_name <> 'Jessie Alloway'
CREATE TABLE contestants (contestant_name VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4336 }
What are the distinct states and create time of all votes?
SELECT DISTINCT state, created FROM votes
CREATE TABLE votes (state VARCHAR(255), created VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 4337 }
What are the contestant numbers and names of the contestants who had at least two votes?
SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number HAVING COUNT(*) >= 2
CREATE TABLE votes (contestant_number VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT); CREATE TABLE contestants (contestant_number VARCHAR(255), contestant_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4338 }
Of all the contestants who got voted, what is the contestant number and name of the contestant who got least votes?
SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number ORDER BY COUNT(*) LIMIT 1
CREATE TABLE votes (contestant_number VARCHAR(255), id INTEGER PRIMARY KEY AUTOINCREMENT); CREATE TABLE contestants (contestant_number VARCHAR(255), contestant_name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 4339 }
What are the number of votes from state 'NY' or 'CA'?
SELECT COUNT(*) FROM votes WHERE state = 'NY' OR state = 'CA'
CREATE TABLE votes (state VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4340 }
How many contestants did not get voted?
SELECT COUNT(*) FROM contestants WHERE NOT contestant_number IN (SELECT contestant_number FROM votes)
CREATE TABLE contestants (contestant_number VARCHAR(255), name VARCHAR(255)); CREATE TABLE votes (contestant_number VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 4341 }
What is the area code in which the most voters voted?
SELECT T1.area_code FROM area_code_state AS T1 JOIN votes AS T2 ON T1.state = T2.state GROUP BY T1.area_code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE area_code_state (area_code VARCHAR(255), state VARCHAR(255)); CREATE TABLE votes (state VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 4342 }
What are the create dates, states, and phone numbers of the votes that were for the contestant named 'Tabatha Gehling'?
SELECT T2.created, T2.state, T2.phone_number FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T1.contestant_name = 'Tabatha Gehling'
CREATE TABLE contestants (contestant_number VARCHAR(255), contestant_name VARCHAR(255)); CREATE TABLE votes (created VARCHAR(255), state VARCHAR(255), phone_number VARCHAR(255), contestant_number VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 4343 }
List the area codes in which voters voted both for the contestant 'Tabatha Gehling' and the contestant 'Kelly Clauss'.
SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number J...
CREATE TABLE votes (contestant_number VARCHAR(255), state VARCHAR(255)); CREATE TABLE contestants (contestant_number VARCHAR(255), contestant_name VARCHAR(255)); CREATE TABLE area_code_state (area_code VARCHAR(255), state VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 4344 }
Return the names of the contestants whose names contain the substring 'Al' .
SELECT contestant_name FROM contestants WHERE contestant_name LIKE '%al%'
CREATE TABLE contestants (contestant_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 4345 }
What are the names of all the countries that became independent after 1950?
SELECT Name FROM country WHERE IndepYear > 1950
CREATE TABLE country (Name VARCHAR(255), IndepYear INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4346 }
How many countries have a republic as their form of government?
SELECT COUNT(*) FROM country WHERE GovernmentForm = 'Republic'
CREATE TABLE country (GovernmentForm VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4347 }
What is the total surface area of the countries in the Caribbean region?
SELECT SUM(SurfaceArea) FROM country WHERE Region = 'Caribbean'
CREATE TABLE country (SurfaceArea INTEGER, Region VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4348 }
Which continent is Anguilla in?
SELECT Continent FROM country WHERE Name = 'Anguilla'
CREATE TABLE country (Continent VARCHAR(255), Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4349 }
What are the population and life expectancies in Brazil?
SELECT Population, LifeExpectancy FROM country WHERE Name = 'Brazil'
CREATE TABLE country (Population VARCHAR(255), LifeExpectancy VARCHAR(255), Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4352 }
What are the region and population of Angola?
SELECT Population, Region FROM country WHERE Name = 'Angola'
CREATE TABLE country (Population VARCHAR(255), Region VARCHAR(255), Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 4353 }
What is the average expected life expectancy for countries in the region of Central Africa?
SELECT AVG(LifeExpectancy) FROM country WHERE Region = 'Central Africa'
CREATE TABLE country (LifeExpectancy INTEGER, Region VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 4354 }
What is the name of country that has the shortest life expectancy in Asia?
SELECT Name FROM country WHERE Continent = 'Asia' ORDER BY LifeExpectancy LIMIT 1
CREATE TABLE country (Name VARCHAR(255), Continent VARCHAR(255), LifeExpectancy VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 4355 }