spider_version
int64
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187 values
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3.81k
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which type of policy is most frequently used? Give me the policy type code.
SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the type code of the most frequently used policy.
SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find all the policy types that are used by more than 2 customers.
SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING count(*) > 2
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which types of policy are chosen by more than 2 customers? Give me the policy type codes.
SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING count(*) > 2
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the total and average amount paid in claim headers.
SELECT sum(amount_piad) , avg(amount_piad) FROM claim_headers
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What are the total amount and average amount paid in claim headers?
SELECT sum(amount_piad) , avg(amount_piad) FROM claim_headers
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the total amount claimed in the most recently created document.
SELECT sum(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
How much amount in total were claimed in the most recently created document?
SELECT sum(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What is the name of the customer who has made the largest amount of claim in a single claim?
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT max(amount_claimed) FROM claim_headers)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customer made the largest amount of claim in a single claim? Return the customer details.
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT max(amount_claimed) FROM claim_headers)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What is the name of the customer who has made the minimum amount of payment in one claim?
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT min(amount_piad) FROM claim_headers)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customer made the smallest amount of claim in one claim? Return the customer details.
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT min(amount_piad) FROM claim_headers)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the names of customers who have no policies associated.
SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What are the names of customers who do not have any policies?
SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
How many claim processing stages are there in total?
SELECT count(*) FROM claims_processing_stages
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the number of distinct stages in claim processing.
SELECT count(*) FROM claims_processing_stages
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What is the name of the claim processing stage that most of the claims are on?
SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY count(*) DESC LIMIT 1
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which claim processing stage has the most claims? Show the claim status name.
SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY count(*) DESC LIMIT 1
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the names of customers whose name contains "Diana".
SELECT customer_details FROM customers WHERE customer_details LIKE "%Diana%"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customers have the substring "Diana" in their names? Return the customer details.
SELECT customer_details FROM customers WHERE customer_details LIKE "%Diana%"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the names of the customers who have an deputy policy.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customers have an insurance policy with the type code "Deputy"? Give me the customer details.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the names of customers who either have an deputy policy or uniformed policy.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy" OR t1.policy_type_code = "Uniform"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customers have an insurance policy with the type code "Deputy" or "Uniform"? Return the customer details.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy" OR t1.policy_type_code = "Uniform"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the names of all the customers and staff members.
SELECT customer_details FROM customers UNION SELECT staff_details FROM staff
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What are the names of the customers and staff members?
SELECT customer_details FROM customers UNION SELECT staff_details FROM staff
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the number of records of each policy type and its type code.
SELECT policy_type_code , count(*) FROM policies GROUP BY policy_type_code
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
For each policy type, return its type code and its count in the record.
SELECT policy_type_code , count(*) FROM policies GROUP BY policy_type_code
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the name of the customer that has been involved in the most policies.
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY count(*) DESC LIMIT 1
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customer have the most policies? Give me the customer details.
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY count(*) DESC LIMIT 1
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
What is the description of the claim status "Open"?
SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = "Open"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the description of the claim status "Open".
SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = "Open"
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
How many distinct claim outcome codes are there?
SELECT count(DISTINCT claim_outcome_code) FROM claims_processing
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Count the number of distinct claim outcome codes.
SELECT count(DISTINCT claim_outcome_code) FROM claims_processing
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Which customer is associated with the latest policy?
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT max(start_date) FROM policies)
1
insurance_and_eClaims
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ); CREATE TABLE Staff ( Staff_ID INTEGER NOT NULL, Staff_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Staff_ID) ); CREATE TABLE Policies ( Policy_ID INTEGER NOT NULL, Customer_ID INTEGER NOT NULL, Pol...
Find the customer who started a policy most recently.
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT max(start_date) FROM policies)
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the number of accounts.
SELECT count(*) FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many accounts are there?
SELECT count(*) FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many customers have opened an account?
SELECT count(DISTINCT customer_id) FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of customers who have an account.
SELECT count(DISTINCT customer_id) FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the id, the date of account opened, the account name, and other account detail for all accounts.
SELECT account_id , date_account_opened , account_name , other_account_details FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the ids, date opened, name, and other details for all accounts?
SELECT account_id , date_account_opened , account_name , other_account_details FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the id, the account name, and other account details for all accounts by the customer with first name 'Meaghan'.
SELECT T1.account_id , T1.date_account_opened , T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = 'Meaghan'
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the ids, names, dates of opening, and other details for accounts corresponding to the customer with the first name "Meaghan"?
SELECT T1.account_id , T1.date_account_opened , T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = 'Meaghan'
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the account name and other account detail for all accounts by the customer with first name Meaghan and last name Keeling.
SELECT T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Meaghan" AND T2.customer_last_name = "Keeling"
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the names and other details for accounts corresponding to the customer named Meaghan Keeling?
SELECT T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Meaghan" AND T2.customer_last_name = "Keeling"
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the first name and last name for the customer with account name 900.
SELECT T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "900"
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the full names of customers with the account name 900?
SELECT T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "900"
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many customers don't have an account?
SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts)
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of customers who do not have an account.
SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts)
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the unique first names, last names, and phone numbers for all customers with any account.
SELECT DISTINCT T1.customer_first_name , T1.customer_last_name , T1.phone_number FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the distinct first names, last names, and phone numbers for customers with accounts?
SELECT DISTINCT T1.customer_first_name , T1.customer_last_name , T1.phone_number FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show customer ids who don't have an account.
SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the customer ids for customers who do not have an account?
SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Accounts
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many accounts does each customer have? List the number and customer id.
SELECT count(*) , customer_id FROM Accounts GROUP BY customer_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of accounts corresponding to each customer id.
SELECT count(*) , customer_id FROM Accounts GROUP BY customer_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What is the customer id, first and last name with most number of accounts.
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Return the id and full name of the customer with the most accounts.
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show id, first name and last name for all customers and the number of accounts.
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name , count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the the full names and ids for all customers, and how many accounts does each have?
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name , count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show first name and id for all customers with at least 2 accounts.
SELECT T2.customer_first_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the first names and ids for customers who have two or more accounts?
SELECT T2.customer_first_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the number of customers.
SELECT count(*) FROM Customers
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of customers.
SELECT count(*) FROM Customers
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the number of customers for each gender.
SELECT gender , count(*) FROM Customers GROUP BY gender
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many customers are there of each gender?
SELECT gender , count(*) FROM Customers GROUP BY gender
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many transactions do we have?
SELECT count(*) FROM Financial_transactions
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of transactions.
SELECT count(*) FROM Financial_transactions
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many transaction does each account have? Show the number and account id.
SELECT count(*) , account_id FROM Financial_transactions
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of financial transactions that correspond to each account id.
SELECT count(*) , account_id FROM Financial_transactions
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many transaction does account with name 337 have?
SELECT count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id WHERE T2.account_name = "337"
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of financial transactions that the account with the name 337 has.
SELECT count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id WHERE T2.account_name = "337"
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What is the average, minimum, maximum, and total transaction amount?
SELECT avg(transaction_amount) , min(transaction_amount) , max(transaction_amount) , sum(transaction_amount) FROM Financial_transactions
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Return the average, minimum, maximum, and total transaction amounts.
SELECT avg(transaction_amount) , min(transaction_amount) , max(transaction_amount) , sum(transaction_amount) FROM Financial_transactions
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show ids for all transactions whose amounts are greater than the average.
SELECT transaction_id FROM Financial_transactions WHERE transaction_amount > (SELECT avg(transaction_amount) FROM Financial_transactions)
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the ids for transactions that have an amount greater than the average amount of a transaction?
SELECT transaction_id FROM Financial_transactions WHERE transaction_amount > (SELECT avg(transaction_amount) FROM Financial_transactions)
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the transaction types and the total amount of transactions.
SELECT transaction_type , sum(transaction_amount) FROM Financial_transactions GROUP BY transaction_type
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are total transaction amounts for each transaction type?
SELECT transaction_type , sum(transaction_amount) FROM Financial_transactions GROUP BY transaction_type
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the account name, id and the number of transactions for each account.
SELECT T2.account_name , T1.account_id , count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Return the names and ids of each account, as well as the number of transactions.
SELECT T2.account_name , T1.account_id , count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the account id with most number of transactions.
SELECT account_id FROM Financial_transactions GROUP BY account_id ORDER BY count(*) DESC LIMIT 1
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What is the id of the account with the most transactions?
SELECT account_id FROM Financial_transactions GROUP BY account_id ORDER BY count(*) DESC LIMIT 1
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the account id and name with at least 4 transactions.
SELECT T1.account_id , T2.account_name FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id HAVING count(*) >= 4
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the ids and names of accounts with 4 or more transactions?
SELECT T1.account_id , T2.account_name FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id HAVING count(*) >= 4
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show all product sizes.
SELECT DISTINCT product_size FROM Products
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the different product sizes?
SELECT DISTINCT product_size FROM Products
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show all product colors.
SELECT DISTINCT product_color FROM Products
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the different product colors?
SELECT DISTINCT product_color FROM Products
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the invoice number and the number of transactions for each invoice.
SELECT invoice_number , count(*) FROM Financial_transactions GROUP BY invoice_number
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many transactions correspond to each invoice number?
SELECT invoice_number , count(*) FROM Financial_transactions GROUP BY invoice_number
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What is the invoice number and invoice date for the invoice with most number of transactions?
SELECT T2.invoice_number , T2.invoice_date FROM Financial_transactions AS T1 JOIN Invoices AS T2 ON T1.invoice_number = T2.invoice_number GROUP BY T1.invoice_number ORDER BY count(*) DESC LIMIT 1
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What is the invoice number and invoice date corresponding to the invoice with the greatest number of transactions?
SELECT T2.invoice_number , T2.invoice_date FROM Financial_transactions AS T1 JOIN Invoices AS T2 ON T1.invoice_number = T2.invoice_number GROUP BY T1.invoice_number ORDER BY count(*) DESC LIMIT 1
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many invoices do we have?
SELECT count(*) FROM Invoices
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Count the number of invoices.
SELECT count(*) FROM Invoices
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show invoice dates and order id and details for all invoices.
SELECT T1.invoice_date , T1.order_id , T2.order_details FROM Invoices AS T1 JOIN Orders AS T2 ON T1.order_id = T2.order_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What are the invoice dates, order ids, and order details for all invoices?
SELECT T1.invoice_date , T1.order_id , T2.order_details FROM Invoices AS T1 JOIN Orders AS T2 ON T1.order_id = T2.order_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Show the order ids and the number of invoices for each order.
SELECT order_id , count(*) FROM Invoices GROUP BY order_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
How many invoices correspond to each order id?
SELECT order_id , count(*) FROM Invoices GROUP BY order_id
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
What is the order id and order details for the order more than two invoices.
SELECT T2.order_id , T2.order_details FROM Invoices AS T1 JOIN Orders AS T2 ON T1.order_id = T2.order_id GROUP BY T2.order_id HAVING count(*) > 2
1
customers_and_invoices
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
Return the order ids and details for orderes with two or more invoices.
SELECT T2.order_id , T2.order_details FROM Invoices AS T1 JOIN Orders AS T2 ON T1.order_id = T2.order_id GROUP BY T2.order_id HAVING count(*) > 2