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1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the first and last name of all employees who live in the city Damianfort?
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
Which city lives most of staffs? List the city name and number of staffs.
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
In which city do the most employees live and how many of them live there?
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List the states which have between 2 to 4 staffs living there.
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the names of the states that have 2 to 4 employees living there?
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List the first name and last name of all customers.
SELECT first_name , last_name FROM Customers;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the first and last names for all customers?
SELECT first_name , last_name FROM Customers;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List email address and birthday of customer whose first name as Carole.
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the email addresses and date of births for all customers who have a first name of Carole?
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List phone number and email address of customer with more than 2000 outstanding balance.
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the phone numbers and email addresses of all customers who have an outstanding balance of more than 2000?
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the status code, phone number, and email address of the customer whose last name is Kohler or whose first name is Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
When are the birthdays of customer who are classified as 'Good Customer' status?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the date of birth of every customer whose status code is 'Good Customer'?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
When did customer with first name as Carole and last name as Bernhard became a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
When did Carole Bernhard first become a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many customers in total?
SELECT count(*) FROM Customers;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many customers are there?
SELECT count(*) FROM Customers;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List all customer status codes and the number of customers having each status code.
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
For each customer status code, how many customers are classified that way?
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
Which customer status code has least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the status code with the least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons did the customer Ryan Goodwin complete?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is maximum, minimum and average amount of outstanding of customer?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the maximum, minimum, and average amount of money outsanding for all customers?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List the first name and last name of customers have the amount of outstanding between 1000 and 3000.
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the first and last names of all customers with between 1000 and 3000 dollars outstanding?
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List first name and last name of customers lived in city Lockmanfurt.
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the first and last names of all customers who lived in Lockmanfurt?
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
Which country does customer with first name as Carole and last name as Bernhard lived in?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the country in which the customer Carole Bernhard lived?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is zip code of customer with first name as Carole and last name as Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the zip code of the customer Carole Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
Which city does has most number of customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the city with the most customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How much in total does customer with first name as Carole and last name as Bernhard paid?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the total amount of moeny paid by the customer Carole Bernhard?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List the number of customers that did not have any payment history.
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many customers have no payment histories?
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List first name and last name of customers that have more than 2 payments.
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the first and last names of all customers with more than 2 payments?
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List all payment methods and number of payments using each payment methods.
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
For each payment method, how many payments were made?
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons were in cancelled state?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons have been cancelled?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
List lesson id of all lessons taught by staff with first name as Janessa, last name as Sawayn and nickname containing letter 's'.
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the the lesson ids of all staff taught by Janessa Sawayn whose nickname has the letter s?
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons taught by staff whose first name has letter 'a' in it?
SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons were taught by a staff member whose first name has the letter 'a' in it?
SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How long is the total lesson time taught by staff with first name as Janessa and last name as Sawayn?
SELECT sum(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the total time for all lessons taught by Janessa Sawayn?
SELECT sum(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is average lesson price taught by staff with first name as Janessa and last name as Sawayn?
SELECT avg(price) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the average price for a lesson taught by Janessa Sawayn?
SELECT avg(price) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lesson does customer with first name Ray took?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Ray"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
How many lessons did the customer with the first name Ray take?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Ray"
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
Which last names are both used by customers and by staff?
SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What are the last names that are used by customers and staff?
SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the first name of the staff who did not give any lesson?
SELECT first_name FROM Staff EXCEPT SELECT T2.first_name FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the first name of all employees who do not give any lessons?
SELECT first_name FROM Staff EXCEPT SELECT T2.first_name FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id
1
driving_school
CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); CREATE TABLE `Staff` ( `staff_id` INTEGER PRIMARY KEY, `staff_address_id` INTEGER NOT NULL, `nickname` VARCHAR(80), `first_name` VARCHAR(80), `middle_name` VARCHAR(80), `last_name` VARCHAR(80), `date_of_birth` DATETIME, `date_joined_staff` DATETIME, `date_left_staff` DATETIME, FOREIGN KEY (`staff_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Vehicles` ( `vehicle_id` INTEGER PRIMARY KEY, `vehicle_details` VARCHAR(255) ); CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_address_id` INTEGER NOT NULL, `customer_status_code` VARCHAR(15) NOT NULL, `date_became_customer` DATETIME, `date_of_birth` DATETIME, `first_name` VARCHAR(80), `last_name` VARCHAR(80), `amount_outstanding` DOUBLE NULL, `email_address` VARCHAR(250), `phone_number` VARCHAR(255), `cell_mobile_phone_number` VARCHAR(255), FOREIGN KEY (`customer_address_id` ) REFERENCES `Addresses`(`address_id` ) ); CREATE TABLE `Customer_Payments` ( `customer_id` INTEGER NOT NULL, `datetime_payment` DATETIME NOT NULL, `payment_method_code` VARCHAR(10) NOT NULL, `amount_payment` DOUBLE NULL, PRIMARY KEY (`customer_id`,`datetime_payment`), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) ); CREATE TABLE `Lessons` ( `lesson_id` INTEGER PRIMARY KEY, `customer_id` INTEGER NOT NULL, `lesson_status_code` VARCHAR(15) NOT NULL, `staff_id` INTEGER, `vehicle_id` INTEGER NOT NULL, `lesson_date` DATETIME, `lesson_time` VARCHAR(10), `price` DOUBLE NULL, FOREIGN KEY (`vehicle_id` ) REFERENCES `Vehicles`(`vehicle_id` ), FOREIGN KEY (`staff_id` ) REFERENCES `Staff`(`staff_id` ), FOREIGN KEY (`customer_id` ) REFERENCES `Customers`(`customer_id` ) )
What is the id and detail of the vehicle used in lessons for most of the times?
SELECT T1.vehicle_id , T1.vehicle_details FROM Vehicles AS T1 JOIN Lessons AS T2 ON T1.vehicle_id = T2.vehicle_id GROUP BY T1.vehicle_id ORDER BY count(*) DESC LIMIT 1
1
activity_1
How many faculty do we have?
SELECT count(*) FROM Faculty
1
activity_1
What is the total number of faculty members?
SELECT count(*) FROM Faculty
1
activity_1
What ranks do we have for faculty?
SELECT DISTINCT rank FROM Faculty
1
activity_1
Find the list of distinct ranks for faculty.
SELECT DISTINCT rank FROM Faculty
1
activity_1
Show all the distinct buildings that have faculty rooms.
SELECT DISTINCT building FROM Faculty
1
activity_1
What buildings have faculty offices?
SELECT DISTINCT building FROM Faculty
1
activity_1
Show the rank, first name, and last name for all the faculty.
SELECT rank , Fname , Lname FROM Faculty
1
activity_1
What are the rank, first name, and last name of the faculty members?
SELECT rank , Fname , Lname FROM Faculty
1
activity_1
Show the first name, last name, and phone number for all female faculty members.
SELECT Fname , Lname , phone FROM Faculty WHERE Sex = 'F'
1
activity_1
What are the first name, last name, and phone number of all the female faculty members?
SELECT Fname , Lname , phone FROM Faculty WHERE Sex = 'F'
1
activity_1
Show ids for all the male faculty.
SELECT FacID FROM Faculty WHERE Sex = 'M'
1
activity_1
What are the faculty ids of all the male faculty members?
SELECT FacID FROM Faculty WHERE Sex = 'M'
1
activity_1
How many female Professors do we have?
SELECT count(*) FROM Faculty WHERE Sex = 'F' AND Rank = "Professor"
1
activity_1
Count the number of female Professors we have.
SELECT count(*) FROM Faculty WHERE Sex = 'F' AND Rank = "Professor"
1
activity_1
Show the phone, room, and building for the faculty named Jerry Prince.
SELECT phone , room , building FROM Faculty WHERE Fname = "Jerry" AND Lname = "Prince"
1
activity_1
What are the phone, room, and building of the faculty member called Jerry Prince?
SELECT phone , room , building FROM Faculty WHERE Fname = "Jerry" AND Lname = "Prince"
1
activity_1
How many Professors are in building NEB?
SELECT count(*) FROM Faculty WHERE Rank = "Professor" AND building = "NEB"
1
activity_1
Count the number of Professors who have office in building NEB.
SELECT count(*) FROM Faculty WHERE Rank = "Professor" AND building = "NEB"
1
activity_1
Show the first name and last name for all the instructors.
SELECT fname , lname FROM Faculty WHERE Rank = "Instructor"
1
activity_1
What are the first name and last name of all the instructors?
SELECT fname , lname FROM Faculty WHERE Rank = "Instructor"
1
activity_1
Show all the buildings along with the number of faculty members the buildings have.
SELECT building , count(*) FROM Faculty GROUP BY building
1
activity_1
How many faculty members does each building have? List the result with the name of the building.
SELECT building , count(*) FROM Faculty GROUP BY building
1
activity_1
Which building has most faculty members?
SELECT building FROM Faculty GROUP BY building ORDER BY count(*) DESC LIMIT 1
1
activity_1
Find the building that has the largest number of faculty members.
SELECT building FROM Faculty GROUP BY building ORDER BY count(*) DESC LIMIT 1
1
activity_1
Show all the buildings that have at least 10 professors.
SELECT building FROM Faculty WHERE rank = "Professor" GROUP BY building HAVING count(*) >= 10
1
activity_1
In which buildings are there at least ten professors?
SELECT building FROM Faculty WHERE rank = "Professor" GROUP BY building HAVING count(*) >= 10
1
activity_1
For each faculty rank, show the number of faculty members who have it.
SELECT rank , count(*) FROM Faculty GROUP BY rank
1
activity_1
How many faculty members do we have for each faculty rank?
SELECT rank , count(*) FROM Faculty GROUP BY rank
1
activity_1
Show all the ranks and the number of male and female faculty for each rank.
SELECT rank , sex , count(*) FROM Faculty GROUP BY rank , sex
1
activity_1
How many faculty members do we have for each rank and gender?
SELECT rank , sex , count(*) FROM Faculty GROUP BY rank , sex
1
activity_1
Which rank has the smallest number of faculty members?
SELECT rank FROM Faculty GROUP BY rank ORDER BY count(*) ASC LIMIT 1
1
activity_1
Find the faculty rank that has the least members.
SELECT rank FROM Faculty GROUP BY rank ORDER BY count(*) ASC LIMIT 1
1
activity_1
Show the number of male and female assistant professors.
SELECT sex , count(*) FROM Faculty WHERE rank = "AsstProf" GROUP BY sex
1
activity_1
How many male and female assistant professors do we have?
SELECT sex , count(*) FROM Faculty WHERE rank = "AsstProf" GROUP BY sex
1
activity_1
What are the first name and last name of Linda Smith's advisor?
SELECT T1.fname , T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T2.fname = "Linda" AND T2.lname = "Smith"
1
activity_1
Who is the advisor of Linda Smith? Give me the first name and last name.
SELECT T1.fname , T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T2.fname = "Linda" AND T2.lname = "Smith"
1
activity_1
Show the ids of students whose advisors are professors.
SELECT T2.StuID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.rank = "Professor"
1
activity_1
Which students have professors as their advisors? Find their student ids.
SELECT T2.StuID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.rank = "Professor"