output stringlengths 52 181k | instruction stringlengths 296 182k |
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#include <bits/stdc++.h>
using namespace std;
inline void pisz(int n) { printf("%d\n", n); }
template <typename T, typename TT>
ostream& operator<<(ostream& s, pair<T, TT> t) {
return s << "(" << t.first << "," << t.second << ")";
}
template <typename T>
ostream& operator<<(ostream& s, vector<T> t) {
for (int(i) = ... | ### Prompt
Your task is to create a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its ... |
#include <bits/stdc++.h>
using namespace std;
int f[4001][4001], t[4001], d[4001];
int hangup(int lastend, int k) { return max(lastend, t[k] - 1) + d[k]; }
int main() {
int n, m;
while (cin >> n >> m) {
for (int i = 1; i <= n; ++i) {
cin >> t[i] >> d[i];
}
for (int i = 1; i <= n; ++i) {
f[i]... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
void inline checkMax(T& a, T b) {
if (a < b) a = b;
};
template <class T>
void inline checkMin(T& a, T b) {
if (a > b) a = b;
};
struct Item {
int start_time;
int duration;
Item() {}
Item(int start_time, int duration)
: start_time(start_... | ### Prompt
Generate a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
long f[4005][4005] = {0};
int main() {
long n, k, i, j;
long t, d;
long ans = 0;
scanf("%ld%ld", &n, &k);
for (i = 1; i <= n; i++) {
scanf("%ld%ld", &t, &d);
if (t - f[i - 1][k] - 1 > ans) ans = t - f[i - 1][k] - 1;
f[i][0] = max(f[i - 1][0], t - 1) + ... | ### Prompt
Construct a cpp code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
int N, K, res;
int T[4005];
int D[4005];
int DP[4005][4005];
int main() {
int x, y, i, j;
cin >> N >> K;
for (i = 1; i <= N; i++) cin >> T[i] >> D[i];
DP[0][0] = 1;
for (j = 1; j <= N; j++) {
for (i = 0; i <= K; i++) {
res = max(res, T[j] - DP[i][j - 1])... | ### Prompt
Create a solution in Cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int n, k, res, t[4005], d[4005], dp[4005][4005][2];
int main() {
scanf("%d %d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%d %d", &t[i], &d[i]);
t[n + 1] = 86401;
res = t[1] - 1;
for (int i = 1; i <= n; i++)
for (int j = 0; j <= k; j++) {
int x, y;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
struct node {
int t, d;
friend bool operator<(const node &a, const node &b) { return a.t < b.t; }
} a[4010];
int f[2][4010];
int now, nxt;
int n, m;
int ans;
int main() {
scanf("%d%d", &n, &m);
for (int i = 0; i < n; i++) scanf("%d%d", &a[i].t, &a[i].d);
sort(a, a... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int t[4005], d[4005], f[4005][4005][2];
int n, k;
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i++) scanf("%d%d", &t[i], &d[i]);
for (int i = 0; i <= n; i++)
for (int x = 0; x <= k; x++)
f[i][x][0] = 1000000000, f[i][x][1] = 1000000000;
f[0][0][0] =... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 4000 + 10;
int n, k;
int t[maxn], d[maxn];
int dp[maxn][maxn];
int main() {
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d%d", &t[i], &d[i]);
if (n == k) {
printf("86400\n");
return 0;
}
t[n] = 86401;
dp[0][0] = t[0] + d[0]... | ### Prompt
Develop a solution in cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 1000000000;
vector<string> split(const string& s, const string& delim = " ") {
vector<string> res;
string t;
for (int i = 0; i < s.size(); i++) {
if (delim.find(s[i]) != string::npos) {
if (!t.empty()) {
res.push_back(t);
t = ... | ### Prompt
Your task is to create a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its ... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 1000000007;
const int N = 4004;
vector<int> g[N];
int a[N];
int beg[N], len[N], dp[N][N];
int mpow(int base, int exp);
void ipgraph(int n, int m);
void dfs(int u, int par);
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int i, n, k, j;
... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
const int maxN = 4010;
struct ph {
int t, d;
} p[maxN];
int n, m, f[maxN][maxN];
bool cmp(ph x, ph y) {
if ((x.t < y.t) || ((x.t == y.t) && (x.d < y.d))) return true;
return false;
}
int main() {
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i++) scanf("%d%d", &p... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
struct qq {
int l, r;
};
qq q[4010];
bool cmp(qq a, qq b) { return a.l < b.l; }
int dp[3][4010][2];
int yd[3][4010][2];
int max(int a, int b) { return a > b ? a : b; }
int main() {
int i, j, n, k;
scanf("%d%d", &n, &k);
for (i = 1; i <= n; i++) {
scanf("%d%d", &... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
int n, k;
cin >> n >> k;
vector<int> t(n + 1), d(n + 1);
t[0] = 0;
d[0] = 0;
for (int i = 1; i <= n; i++) {
cin >> t[i] >> d[i];
}
int **f = new int *[4002];
bool **c = new bool *[4002];
for (int i = 0; i < 4001; i++) {
f... | ### Prompt
Develop a solution in Cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int a[4010], b[4010], f[4010][4010];
int main() {
int n, K;
scanf("%d%d", &n, &K);
for (int i = 1; i <= n; i++) scanf("%d%d", &a[i], &b[i]);
memset(f, 63, sizeof(f));
int inf = f[0][0], ans = 0;
f[0][0] = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j <=... | ### Prompt
Develop a solution in cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 4000 + 10;
struct SchTime {
int x, y, t;
} a[maxn];
int f[maxn][maxn];
int n, k, ans;
int main() {
while (scanf("%d%d", &n, &k) != EOF) {
for (int i = 1; i <= n; i++) {
scanf("%d%d", &a[i].x, &a[i].y);
a[i].y += a[i].x - 1;
if (a[i... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
struct CALL {
int start;
int end;
CALL(){};
bool operator<(const CALL& v) const { return start < v.start; }
int End() { return start + end; }
};
CALL Calls[10000];
int End[5000][5000];
int fEnd(int call, int skip) {
if (skip < 0) return 864000;
if (call < 0) r... | ### Prompt
In CPP, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
int f[4567], ans;
int main() {
int n, k, t, d;
cin >> n >> k;
if (n == k) {
puts("86400");
return 0;
}
for (int i = 0; i < n; i++) {
cin >> t >> d;
for (int j = k; j >= 0; j--) {
if (t <= f[j])
f[j] += d;
else
ans = max(... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
void pv(T a, T b) {
for (T i = a; i != b; ++i) cout << *i << " ";
cout << endl;
}
template <class T>
void chmin(T &t, T f) {
if (t > f) t = f;
}
template <class T>
void chmax(T &t, T f) {
if (t < f) t = f;
}
int in() {
int x;
scanf("%d", &x);
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 4003;
int t[N], d[N];
int DAY = 24 * 60 * 60 + 1;
int DP[N][N];
int main() {
int n, k;
scanf("%d %d", &n, &k);
if (n == 0) {
printf("%d\n", 60 * 60 * 24);
return 0;
}
for (int i = 0; i < n; i++) scanf("%d %d", &t[i], &d[i]);
int f = 1;
fo... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int arr[4005][4005];
int s[4005];
int d[4005];
const int kInf = 0x7f7f7f7f;
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; ++i) {
cin >> s[i] >> d[i];
}
s[n] = 86401;
memset(arr, 0x7f, sizeof arr);
arr[0][0] = 1;
int ret = 0;
for (int i =... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
#pragma comment(linker, "/STACK:16000000")
void dbg(const char* fmt, ...) {}
const int size = 4096;
const int day = 86400;
int t[size];
int d[size];
int dp[size][size];
int main() {
int n, k;
int ans = 0;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) {
scanf("%d%d", &t[i], &d[i... | ### Prompt
Please formulate a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
const int max_ = 4002;
int max(int a, int b) {
if (a > b) return a;
return b;
}
int min(int a, int b) {
if (a < b) return a;
return b;
}
int M[max_][max_];
int n, k, i, j, ans;
int t[max_], d[max_];
int main() {
scanf("%d %d", &n, &k);
for (i = 1; i <= n; i++) scanf("%d %d", &t[i], ... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int t[10240], d[10240];
int dp[2][10240];
int main() {
int n, k;
int i, j;
int ans;
int *prev, *cur;
scanf("%d%d", &n, &k);
for (i = 0; i < n; i++) scanf("%d%d", &t[i], &d[i]);
for (i = 0; i <= k + 5; i++) t[n + i] = 86401;
prev = dp[0];
cur = dp[1];
for... | ### Prompt
In CPP, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
int t[4002], d[4002];
int dp[4002][4002];
int main() {
int n, k, last = 0;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; ++i) scanf("%d%d", &t[i], &d[i]);
int ans = 0, F = 86401;
if (n == 0) ans = 86400;
for (int i = 0; i <= n; ++i)
for (int j = 0; j <= k; +... | ### Prompt
In Cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const int INF = (int)1e9;
const long long int prime = 31;
long long int f[4002][4002] = {0};
int main() {
long long int n, k(0), j;
long long int t, d;
long long int ans = 0;
cin >> n >> k;
for (int i = 1; i <= n; i++) {
cin >> t ... | ### Prompt
In Cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
const int maxn = 4100;
pair<int, int> p[maxn];
int dp[maxn][maxn];
int inf = (int)(1e9);
int ans = 0;
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i++) {
cin >> p[i].first >> p[i].second;
}
p[n + 1].first = 86401;
for (int i = 0; i <= n; i++) ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline int cMin(T& a, T b) {
return b < a ? a = b, 1 : 0;
}
template <class T>
inline int cMax(T& a, T b) {
return a < b ? a = b, 1 : 0;
}
template <class T>
inline string to_str(T v) {
ostringstream os;
os << v;
return os.str();
}
const double ... | ### Prompt
In cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
const int N = 4005;
const int INF = 1000000000;
int max(const int &x, const int &y) { return x > y ? x : y; }
struct P {
int s, d;
} data[N];
bool cmp(P x, P y) { return x.s < y.s; }
int dp[N][N];
int main() {
int i, j, k, n;
scanf("%d%d", &n, &k);
if (n == 0 && k =... | ### Prompt
Please formulate a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4400;
int dp[MAXN][MAXN];
struct Node {
int t, d;
bool operator<(const Node &b) const { return t < b.t; }
} p[MAXN];
int main() {
int n, m;
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i) scanf("%d%d", &p[i].t, &p[i].d);
sort(p + 1, p + n + ... | ### Prompt
Please create a solution in Cpp to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int t[4005], d[4005];
int f[4005][4005], g[4005][4005], p[4005][4005];
void Gao() {
int i, j, tf, tp, tg, cnt, ans;
for (i = 0; i <= n; ++i)
for (j = 0; j <= k; ++j) {
f[i][j] = -1;
g[i][j] = p[i][j] = 100005;
}
f[0][0] = 0;
g[0][0] = 1... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 5000;
int n, k, t[N], d[N];
int my_time[2][N][2], my_end[2][N][2];
int max(int a, int b) { return (a > b) ? a : b; }
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%d%d", &t[i], &d[i]);
memset(my_time, 0, sizeof(my_time));
mems... | ### Prompt
Develop a solution in Cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int maxN = 4100;
int p[maxN][maxN];
int n, k;
int t[maxN], d[maxN];
int res = 0;
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) scanf("%d%d", &t[i], &d[i]);
p[0][0] = 0;
for (int i = 1; i <= n; ++i)
for (int j = 0; j <= k; ++j) {
p[... | ### Prompt
Develop a solution in CPP to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4000 + 5, T = 86401;
int n, k, dp[MAXN][MAXN], t[MAXN], d[MAXN], ans = 0;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
for (int i = 0; i < MAXN; i++)
for (int j = 0; j < MAXN; j++) dp[i][j] = 1;
cin >> n >> k;
for ... | ### Prompt
In cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
const int N = 5000;
int dp[N][N];
int t[N], d[N];
int n, k;
int main() {
cin >> n >> k;
for (int i = (1); i <= (int)(n); i++) cin >> t[i] >> d[i];
t[++n] = 86401;
d[n] = 0;
for (int i = (0); i < (int)(N); i++)
for (int j = (0); j < (int)(N); j++) dp[i][j] = 10... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int t[4003], d[4003];
int dp[4003][4003];
int main() {
int n, k, ans = 0, i, j;
cin >> n >> k;
for (i = 1; i <= n; i++) scanf("%d%d", t + i, d + i);
for (j = 0; j <= k; j++) dp[0][k] = 0;
for (i = 1; i <= n; i++)
for (j = 0; j <= k; j++) {
dp[i][j] = max... | ### Prompt
In cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 4010;
int main() {
static int h[maxn] = {0};
int i, j, n, k, t, d;
int ans = 0;
scanf("%d%d", &n, &k);
for (i = 1; i <= n; i++) {
scanf("%d%d", &t, &d);
ans = max(ans, min(t, 86401) - h[k] - 1);
for (j = k; j >= 0; j--) {
h[j] = ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int dp[4007][4007], n, k;
struct Node {
int t, d;
bool operator<(const Node& a) const { return t < a.t; }
} p[4007];
int main() {
while (~scanf("%d%d", &n, &k)) {
for (int i = 0; i < n; i++) scanf("%d%d", &p[i].t, &p[i].d);
sort(p, p + n);
p[n].t = 86401;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
pair<int, int> t[5000];
int n, k, ans, dp[5000][5000], g[5000];
void Init() {
cin >> n >> k;
t[0].first = 1, t[0].second = 0;
for (int i = 1; i <= n; i++) cin >> t[i].first >> t[i].second;
t[++n].first = 86401, t[n].second = 0;
sort(t, t + n);
}
void Solve() {
g... | ### Prompt
Create a solution in CPP for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
const int inf = (int)1e9;
int d[5000], t[5000], dp[4005][4005];
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) {
scanf("%d%d", &t[i], &d[i]);
}
t[n + 1] = 86401;
for (int i = 1; i <= n; ++i) {
for (int j = 0; j <= k; ++j) dp[i][... | ### Prompt
Please create a solution in cpp to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int t[5000], d[5000], a[5000][5000];
int n, k;
int max(int a, int b) { return a > b ? a : b; }
void Solve() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) {
scanf("%d%d", &t[i], &d[i]);
}
memset(a, 0, sizeof(a));
for (int i = 0; i <= n; ++i) a[i][i] = 1... | ### Prompt
Develop a solution in CPP to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int s[4005], e[4005];
int dp[4005][4005];
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%d%d", &s[i], &e[i]);
for (int i = 1; i <= n; i++) {
for (int j = 0; j <= i && j <= k; j++) {
dp[i][j] = max(dp[i - 1][j], s[i] - 1) +... | ### Prompt
Create a solution in Cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 2147483647;
const long long LLINF = 9223372036854775807LL;
const int maxn = 4010;
int ti[maxn] = {};
int di[maxn] = {};
int dp[maxn][maxn] = {};
const int cinf = 1000000010;
int main() {
int n, k;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; ++i) scan... | ### Prompt
Develop a solution in Cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
struct phone {
int start;
int dur;
phone(int start = 0, int dur = 0) : start(start), dur(dur) {}
bool operator<(const phone& b) const {
if (start != b.start) return start < b.start;
return dur < b.dur;
}
};
int main() {
int n, k;
scanf("%d%d", &n, &k);... | ### Prompt
In CPP, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4010;
int n, k;
pair<int, int> a[MAXN];
int f[MAXN][MAXN];
int min(int a, int b) { return a < b ? a : b; }
int max(int a, int b) { return a > b ? a : b; }
void init() {
scanf("%d %d", &n, &k);
for (int i = 0; i < n; ++i) scanf("%d %d", &a[i].first, &a[i... | ### Prompt
In CPP, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
int f[4005], ans;
int main() {
int n, k;
cin >> n >> k;
if (n == k) {
cout << 86400;
return 0;
}
for (int i = 0, t, d; i < n; ++i) {
cin >> t >> d;
for (int j = k; j >= 0; --j) {
if (t <= f[j])
f[j] += d;
else {
ans = ma... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its ... |
#include <bits/stdc++.h>
int n, k;
int calt[4010], cald[4010];
int dp[4010];
int bs(int le, int ri, int tar) {
if (le == ri) return le;
int mi = (le + ri + 1 >> 1);
int val = dp[mi];
if (val >= tar) return bs(le, mi - 1, tar);
if (val < tar) return bs(mi, ri, tar);
}
int main(void) {
for (int i = 1; i < 401... | ### Prompt
Create a solution in CPP for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
const int MAX = 4010;
int dp[MAX][MAX];
const int s = 86400;
int t[s];
int d[s];
int ans;
int main() {
int n, k;
cin >> n >> k;
for (int i = 1; i <= n; i++) {
scanf("%d%d", &t[i], &d[i]);
t[i]--;
}
for (int i = 1; i <= n; i++)
for (int j = 0; j <= k; j... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int f[4040][4040], n, k, ans;
struct info {
int be, ti;
} e[4040];
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%d%d", &e[i].be, &e[i].ti);
e[n + 1].be = 86401;
if (n == k) {
printf("86400");
return 0;
}
f[1][0] = e[1].be + e... | ### Prompt
Please formulate a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int t[4100], d[4100];
int dp[4010][4010];
int main() {
int n, m;
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i++) {
scanf("%d%d", &t[i], &d[i]);
}
int ans;
if (m == n) {
ans = 86400;
} else {
ans = min(86400, t[m + 1] - 1);
for (int i = 0; i... | ### Prompt
Generate a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
int t[4050], d[4050], n, k, f[4050][4050];
int main() {
t[0] = d[0] = 0;
const int day = 86400;
while (scanf("%d%d", &n, &k) != -1) {
int ans = 0;
for (int i = 1; i <= n; i++) scanf("%d%d", &t[i], &d[i]);
t[n + 1] = day + 1;
d[n + 1] = 0;
f[0][0] =... | ### Prompt
In cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
const int N = 4000;
const int INF = 4000 * 86400;
int t[N], d[N], v[N], n, k;
int dp[N][N + 1];
bool is_important(int i) { return false; }
int main() {
ios::sync_with_stdio(0);
while (cin >> n >> k) {
for (int i = 0; i < n; i++) cin >> t[i] >> d[i];
for (int i =... | ### Prompt
Develop a solution in cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const double eps = 1e-10;
const int inf = (int)1e9;
const int maxn = 4010;
pair<int, int> a[maxn];
int d[maxn][maxn];
int main() {
int n, k;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d%d", &a[i].first, &a[i].second);
memset(d, 127, sizeof d);
d[0]... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1000 * 1000 * 1000 + 7;
const long long INF = 1000ll * 1000 * 1000 * 1000 * 1000 * 1000;
const int MAXN = 4 * 1000 + 100;
const int MLOG = 17;
const int SQ = 400;
const int NMAX = 11;
int dp[MAXN][MAXN];
signed main() {
ios_base ::sync_with_stdio(false);
... | ### Prompt
Please formulate a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4 * 10 * 100 + 10, inf = 10e+8;
int dp[MAXN][MAXN];
pair<int, int> p[MAXN];
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> p[i].first >> p[i].second, p[i].first--;
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)... | ### Prompt
Generate a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
int lastBusy[4002][4002];
int t[4001], d[4001];
int main() {
int i, j, k, n, m;
cin >> n >> m;
for (i = 0; i < n; i++) cin >> t[i] >> d[i];
t[n] = 86401;
d[n] = 1;
++n;
memset(lastBusy, -1, sizeof(lastBusy));
lastBusy[0][0] = 0;
int ans = 0;
for (i = 0; ... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n, k;
cin >> n >> k;
vector<int> T(n), D(n);
for (int i = 0; i < n; i++) cin >> T[i] >> D[i];
if (!n) {
cout << 86400 << '\n';
return;
}
int dp[n][k + 1], ans = T[0] - 1;
for (int i = 0; i < n; i++)
for (int j = 0; j <= k; j++)... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4000;
int dp[MAXN + 1][MAXN + 1];
int t[MAXN + 2], d[MAXN + 1];
int main(void) {
int n, k;
cin >> n >> k;
if (n == 0) {
cout << 86400 << endl;
return 0;
}
for (int i = 1; i <= n; i++) {
cin >> t[i] >> d[i];
}
memset(dp, 0, sizeof(d... | ### Prompt
Construct a CPP code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
int f[4010][4010];
int main() {
int n, k;
int ans;
cin >> n >> k;
for (int i = 1; i <= n; ++i) {
int t, d;
cin >> t >> d;
ans = max(ans, t - f[i - 1][k] - 1);
f[i][0] = max(f[i - 1][0], t - 1) + d;
for (int j = 1; j <= k; ++j) {
f[i][j] = m... | ### Prompt
Develop a solution in CPP to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4005;
const int MAXK = 4005;
const int MAXT = 86400;
int n, k;
int dp[2][MAXK];
inline int getEndTime(int right, int a, int b) { return max(right, a) + b; }
int main() {
int a, b;
while (~scanf("%d%d", &n, &k)) {
if (n == k) {
printf("%d\n", M... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
#pragma comment(linker, "/STACK:64000000")
using namespace std;
const int INF = (int)1E9;
const long long INF64 = (long long)1E18;
const long double EPS = 1E-9;
const long double PI = 3.1415926535897932384626433832795;
const int MAXN = 4100;
const int MAXS = 100100;
const int MAXT = 86400;
int ... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 4005;
const int INF = 1e9 + 7;
int n, k;
struct node {
int t, d;
} a[maxn];
int dp[maxn][maxn] = {0};
bool cmp(const node a, const node b) { return a.t < b.t; }
int main() {
ios_base ::sync_with_stdio(false);
cin >> n >> k;
for (int i = 1; i <= n; +... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
std::vector<pair<long long, long long> > v;
long long dp[4005][4005] = {};
int main() {
int n, k;
scanf("%d", &n);
scanf("%d", &k);
v.push_back(make_pair(0, 0));
for (int i = 0; i < n; i++) {
long long t, d;
scanf("%lld", &t);
scanf("%lld", &d);
v.... | ### Prompt
Construct a CPP code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int t[4005], d[4005];
int f[4005][4005], g[4005][4005], p[4005][4005];
void Gao() {
int i, j, tf, tp, tg, cnt, ans;
memset(f, 0xff, sizeof f);
memset(g, 0x3f, sizeof g);
memset(p, 0x3f, sizeof p);
f[0][0] = 0;
g[0][0] = 1;
p[0][0] = 1;
for (i = 1; ... | ### Prompt
Create a solution in Cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int s[4010], t[4010], f[4010][4010];
int n, times;
void init() {
cin >> n >> times;
for (int i = 1; i <= n; i++) cin >> s[i] >> t[i];
}
void solve() {
s[0] = 0;
t[0] = 1;
s[n + 1] = 86401;
memset(f, 127, sizeof(f));
f[0][0] = 0;
for (int j = 1; j <= n; j++)
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4000;
int n, k;
int t[MAXN + 1], d[MAXN + 1];
int res[MAXN + 1][MAXN + 1];
int main() {
scanf("%d%d", &n, &k);
for (int i = 0; i < n; ++i) scanf("%d%d", &t[i], &d[i]);
int answer = 0;
t[n] = 86401;
d[n] = 1;
res[0][0] = 1;
for (int i = 1; i <=... | ### Prompt
Generate a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
const int Day = 86400;
const long long INF = 1e18;
const int N = 4004;
long long dp[N][N], t[N], d[N];
int main() {
int n, k;
scanf("%d%d", &n, &k);
for (int(i) = 0; (i) < (n); (i)++) scanf("%d%d", &t[i], &d[i]), t[i]--;
if (n == k) return printf("%d\n", Day) & 0;
... | ### Prompt
Create a solution in Cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 4000 + 10;
int f[maxn][maxn];
int t[maxn], d[maxn];
int k, n;
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) scanf("%d%d", &t[i], &d[i]);
int ans = 0;
f[0][0] = 1;
for (int i = 1; i <= n; ++i)
for (int lim = min(i, k), j = 0;... | ### Prompt
Construct a CPP code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const double eps = 1e-11;
const int inf = 0x7FFFFFFF;
template <class T>
inline void checkmin(T &a, T b) {
if (b < a) a = b;
}
template <class T>
inline void checkmax(T &a, T b) {
if (b > a) a = b;
}
template <class T>
inline T sqr(T x) {
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 4005;
int n, k, t[N], d[N], dp[N][N];
int main() {
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d%d", t + i, d + i);
t[n] = 86401;
dp[0][0] = t[0] + d[0];
for (int i = 1; i <= k; i++) dp[0][i] = 1;
for (int i = 1; i < n; i++)
for ... | ### Prompt
Your task is to create a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its ... |
#include <bits/stdc++.h>
using namespace std;
int dt[4239][4239], den[4239][4239];
int main() {
int n, k;
cin >> n >> k;
int t[4239], d[4239];
for (int i = 1; i <= n; i++) {
scanf("%d%d", &t[i], &d[i]);
}
t[n + 1] = 86401;
dt[0][0] = 0;
den[0][0] = 1;
for (int i = 1; i <= n; i++) {
dt[i][0] = ... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int t[4005], d[4005];
int f[4005][4005], g[4005][4005], p[4005][4005];
void Gao() {
int i, j, tf, tp, tg, cnt, ans;
memset(f, 0xff, sizeof f);
memset(g, 0x3f, sizeof g);
memset(p, 0x3f, sizeof p);
f[0][0] = 0;
g[0][0] = 1;
p[0][0] = 1;
for (i = 1; ... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 86401;
int n, m, ans;
int a[4010], d[4010], f[4010][4010];
int updata(int x, int y, int z) {
if (x < y)
return y + z;
else
return x + z;
}
int main() {
int i, j;
scanf("%d%d", &n, &m);
for (i = 1; i <= n; i++) scanf("%d%d", &a[i], &d[i]);
... | ### Prompt
Your task is to create a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its ... |
#include <bits/stdc++.h>
using namespace std;
void readi(int &x) {
int v = 0, f = 1;
char c = getchar();
while (!isdigit(c) && c != '-') c = getchar();
if (c == '-')
f = -1;
else
v = v * 10 + c - '0';
while (isdigit(c = getchar())) v = v * 10 + c - '0';
x = v * f;
}
void readll(long long &x) {
l... | ### Prompt
In Cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using std::cin;
using std::cout;
using std::endl;
using std::max;
using std::min;
using std::vector;
int main() {
const int DAY = 86400;
int n, k;
cin >> n >> k;
vector<int> t(n), d(n);
vector<int> f(n + 5, 0);
for (int i = 0; i < n; ++i) {
cin >> t[i] >> d[i];
--t[i];
}
... | ### Prompt
Create a solution in CPP for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
int start[4050], last[4050], answer, dp[4050][4050];
int fdp(int i, int j) {
if (dp[i][j]) return dp[i][j];
if (i <= j) return 0;
if (fdp(i - 1, j) >= start[i])
dp[i][j] = dp[i - 1][j] + last[i];
else
dp[i][j] = start[i] + last[i] - 1;
if (j && fdp(i - 1, ... | ### Prompt
Develop a solution in cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int dp[4005][4005];
int main() {
int N, K, best = 0;
cin >> N >> K;
vector<pair<int, int> > call(N);
for (int i = 0; i < (N); ++i) cin >> call[i].first >> call[i].second;
N++;
call.push_back(pair<int, int>(86401, 0));
memset(dp, 0x7f, sizeof dp);
dp[0][0] = ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
int t[4040];
int d[4040];
int r[4040][4040];
int max(int a, int b) { return b < a ? a : b; }
int main() {
int n, k;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d%d", t + i, d + i);
for (int i = 0; i <= k; i++) {
r[i][0] = 1;
for (int j = 1; j <= n; j++) {
r[... | ### Prompt
Develop a solution in Cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int N = 4001;
const int T = 86400;
int dp[N][N], t[N], d[N], n, k;
int obr(int last, int t, int d) { return max(t, last) + d; }
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i++) cin >> t[i] >> d[i];
for (int i = 0; i <= k; i++) dp[0][i] = 1;
for (int i ... | ### Prompt
In Cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
int N, K;
int DP[4001][4001];
int t[4001], d[4001];
inline int max(int a, int b) { return a > b ? a : b; }
inline int min(int a, int b) { return a < b ? a : b; }
int main() {
int ans = 0;
scanf("%d%d", &N, &K);
if (N == 0) ans = 86400;
for (int i = 1; i <= N; i++) scanf("%d%d", &t[i], &... | ### Prompt
Generate a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int t[4005], d[4005];
int f[4005][4005], g[4005][4005], p[4005][4005];
void Gao() {
int i, j, tf, tp, tg, cnt, ans;
memset(f, 0xff, sizeof f);
memset(g, 0x3f, sizeof g);
memset(p, 0x3f, sizeof p);
f[0][0] = 0;
g[0][0] = 1;
p[0][0] = 1;
for (i = 1; ... | ### Prompt
In CPP, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
int t[5000], d[5000];
int dp[5000][5000];
int main() {
ios::sync_with_stdio(false);
int n, m;
cin >> n >> m;
for (int i = 1; i <= (n); ++i) cin >> t[i] >> d[i];
t[0] = 1;
t[n + 1] = 86401;
d[0] = 0;
int ans = t[1] - 1;
for (int i = 1; i <= (n); ++i)
fo... | ### Prompt
In CPP, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
#include <bits/stdc++.h>
using namespace std;
int n, k, t, d, ans, e[4005];
int main() {
cin >> n >> k;
e[0] = 1;
while (n--) {
cin >> t >> d;
ans = max(ans, t - e[k]);
for (int j = k; j; j--) e[j] = min(max(e[j], t) + d, e[j - 1]);
e[0] = max(e[0], t) + d;
}
ans = max(ans, 86401 - e[k]);
co... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
int max(int a, int b) { return a > b ? a : b; }
int main() {
static int tt[4000], dd[4000], dp[86400 + 1], dq[86400 + 1];
int n, k, i, m, t, ans;
scanf("%d%d", &n, &k);
for (i = 0; i < n; i++) scanf("%d%d", &tt[i], &dd[i]);
ans = (k == n ? 86400 + 1 : tt[k]) - 1;
for (m = 1; m <= n;... | ### Prompt
Please create a solution in CPP to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k, t, i, d, ans, f[4005];
while (2 == scanf("%d%d", &n, &k)) {
memset(f, 0, (k + 1) << 2);
ans = 0;
while (n--) {
scanf("%d%d", &t, &d);
ans = max(ans, t - f[k] - 1);
for (i = k; i; i--) f[i] = min(max(f[i], t - 1) + d, ... | ### Prompt
Create a solution in Cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
using namespace std;
struct info {
int t, d;
} a[4001];
int n, k, dp[4001][4001], ans;
bool cmp(info x, info y) { return x.t < y.t; }
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) {
scanf("%d%d", &a[i].t, &a[i].d);
}
if (n == k) {
printf("86400");
return... | ### Prompt
Construct a CPP code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
struct call {
int t, d;
};
int dp1[4003][4003];
int dp2[4003][4003];
call arr[4003];
int n, k;
int day_end = 86400;
bool comp(call a, call b) { return (a.t < b.t) || (a.t == b.t && a.d < b.d); }
int get_sleep_duration(int i, int j, int q) {
if (q < 0) q = 0;
if (q > i... | ### Prompt
Develop a solution in Cpp to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
int N, K;
int ts[5000];
int ds[5000];
int m[5000][5000];
int main() {
scanf("%d%d", &N, &K);
for (int i = 0; i < (N); ++i) {
scanf("%d%d", ts + i, ds + i);
--ts[i];
}
ts[N] = 86400;
m[0][0] = 0;
int best = ts[0];
for (int i = (1); i <= (N); ++i) {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int dp[4009][4009];
int s[4009], t[4009];
int main() {
int n, k;
scanf("%d%d", &n, &k);
if (!n) {
printf("86400");
return 0;
}
for (int i = 0; i <= k; i++) dp[0][i] = 1000000000;
dp[0][0] = 0;
for (int i = 1; i <= n; i++) scanf("%d%d", &s[i], &t[i]);
... | ### Prompt
Generate a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
int dp[4096][4096];
void filldp(vector<int> &vec1, vector<int> &vec2) {
for (int i = 0; i < (int)4096; i++)
for (int j = 0; j < (int)4096; j++) dp[i][j] = 86400;
int n = vec1.size();
dp[0][0] = vec1[0] + vec2[0];
for (int i = 0; i < (int)n; i++) dp[i][i + 1] = 0... | ### Prompt
Please create a solution in CPP to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its durati... |
#include <bits/stdc++.h>
using namespace std;
const int inf(1010101010);
const int T(86400);
int n, k, start[4005], le[4005];
int dp[4005][4005];
int main() {
cin >> n >> k;
for (int i(0); i < (n); i++) cin >> start[i] >> le[i];
for (int i(0); i < (n + 1); i++)
for (int j(0); j < (n + 1); j++) dp[i][j] = inf;... | ### Prompt
Create a solution in cpp for the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di ... |
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
const int MAX = 4 << 10, MAXT = 24 * 3600;
int n, K;
int T[MAX], D[MAX];
int dpEnd[5][MAXT];
int dpStart[5][MAXT];
int getEarliestStart(int, int);
int getEarliestEnd(int i, int k) {
if (i < 0) return 0;
if (i == 0) return k ? 0 : (T[0] + D[0])... | ### Prompt
Generate a cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
void sc(int& a) { scanf("%d", &a); }
void sc(int& a, int& b) {
sc(a);
sc(b);
}
void sc(int& a, int& b, int& c) {
sc(a);
sc(b);
sc(c);
}
void sc(long long int& a) { scanf("%lld", &a); }
void sc(long long int& a, long long int& b) {
sc(a);
sc(b);
}
void sc(long ... | ### Prompt
Generate a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
struct call {
int start;
int len;
} a[4001];
int dp[4001][4001];
int min(int x, int y) { return x > y ? y : x; }
int main() {
int n, k;
while (scanf("%d%d", &n, &k) == 2) {
a[n + 1].start = 86401;
a[n + 1].len = 0;
for (int i = 1; i <= n; ++i) {
sc... | ### Prompt
Construct a cpp code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
const double pi = 2.0 * acos(0.0);
const double eps = 1.0e-9;
const int dr[] = {-1, 0, 1, 0}, dc[] = {0, 1, 0, -1};
const int dr6[] = {1, 1, 0, -1, -1, 0}, dc6[] = {0, 1, 1, 0, -1, -1};
const int dr8[] = {-1, -1, 0, 1, 1, 1, 0, -1},
dc8[] = {0, 1, 1, 1, 0, -1, -1,... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int ntest = 0, test = 0;
inline void init();
inline void run();
inline void stop() { ntest = test - 1; }
int main() {
init();
while (++test <= ntest) {
run();
}
return 0;
}
const int INF = (int)1E9 + 5;
const double EPS = 1E-11;
const long long MOD = (long long)... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration ... |
#include <bits/stdc++.h>
using namespace std;
const int DLEN = 86400;
const int INF = 1e9;
int main() {
int n, k;
while (scanf("%d%d", &n, &k) >= 1) {
vector<int> t(n), d(n);
for (int i = 0; i < n; i++) scanf("%d%d", &t[i], &d[i]), t[i]--;
vector<vector<int> > dyn(n + 1, vector<int>(k + 1, INF));
dy... | ### Prompt
Generate a Cpp solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di (i... |
#include <bits/stdc++.h>
using namespace std;
const int dlen = 86400;
int t[5000], d[5000], a[5000];
int main() {
int n, k;
cin >> n >> k;
for (int i = 1; i <= n; i++) cin >> t[i] >> d[i];
t[0] = 1;
d[0] = 0;
a[0] = 1;
for (int i = 1; i <= k; i++) a[i] = dlen + 1;
t[n + 1] = dlen + 1;
int ans = 0;
f... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
void setIO(string name) {
string is = name + ".in", os = name + ".out";
freopen(is.c_str(), "r", stdin);
freopen(os.c_str(), "w", stdout);
}
int f[5000][5000], ans, n, s[5000], v[5000], k, t;
void solve() {
for (int i = 1; i <= n; i++)
for (int j = 0; j <= k; j+... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and ... |
#include <bits/stdc++.h>
using namespace std;
int s[4005], len[4005];
int n, k;
int dp[4005][4005];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> k;
for (int i = 1; i <= n; ++i) {
cin >> s[i] >> len[i];
}
s[n + 1] = 86401;
int ans = s[1] - 1;
for (int i = 1; i <= n; ++i) ... | ### Prompt
In cpp, your task is to solve the following problem:
Cool J has recently become a businessman Mr. Jackson, and he has to make a lot of phone calls now. Today he has n calls planned. For each call we know the moment ti (in seconds since the start of the day) when it is scheduled to start and its duration di... |
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