output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
template <class T>
inline T mod(T n, T m) {
return (n % m + m) % m;
}
template <class T>
inline void checkmin(T &a, const T b) {
if (b < a) a = b;
}
template <class T>
inline void checkmax(T &a, const T b) {
if (b > a) a = b;
}
template <class T, class C>
inline void checkmin(T &a, const ... | ### Prompt
Please formulate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string s = to_string(n);
for (int i = 0; i < s.length(); i++) {
if (s[i] == '1' and s[i + 1] == '4' and s[i + 2] == '4') {
s[i] = 'a';
s[i + 1] = 'a';
s[i + 2] = 'a';
i += 2;
} else if (s[i] == '1' and s[... | ### Prompt
Please formulate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
T gcd(T a, T b) {
if (a == 0) return b;
return gcd(b % a, a);
}
template <typename P>
P dectobin(P a) {
if (a == 0)
return 0;
else
return (a % 2 + 10 * dectobin(a / 2));
}
template <typename Y>
Y bintodec(Y a) {
long long ans = 0, b =... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
int i, c, p;
while (cin >> s) {
c = 0;
p = 0;
if (s[0] != '1') {
cout << "NO" << endl;
continue;
}
for (i = 0; i < s.size() - 1; i++) {
if (s[i] == '1' && (s[i + 1] == '1' || s[i + 1] == '4')) {
if (... | ### Prompt
Your task is to create a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
int main(void) {
string s;
cin >> s;
int i = 0;
while (true) {
if (s.length() <= i) break;
if (s[i] == '1') {
i++;
if (s[i] == '4') {
i++;
if (s[i] == '4') {
i++;
}
}
} else {
cout << "NO" << endl... | ### Prompt
Generate a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int a;
int main() {
string a;
cin >> a;
if (a[0] != '1') {
cout << "NO";
return 0;
}
for (int i = 0; i < a.size(); i++) {
if (a[i] == '1') {
if (a[i + 1] == '4') {
i += 1;
if (a[i + 1] == '4') {
i += 1;
}
}... | ### Prompt
Construct a CPP code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e2 + 7;
char s[N];
bool solve() {
int n = strlen(s);
if (s[0] != '1') return false;
for (int i = (0); i < (n - 2); ++i)
if (s[i] == '4' && s[i + 1] == '4' && s[i + 2] == '4') return false;
for (int i = (0); i < (n); ++i)
if (s[i] != '1' && s[i... | ### Prompt
Generate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string m;
cin >> m;
set<int> magic;
set<int>::iterator it;
for (int i = 0; i < m.size(); i++) {
magic.insert(m[i] - '0');
}
if (m[0] == '4') {
cout << "NO";
return 0;
} else if (magic.size() > 2) {
cout << "NO";
return 0;
}... | ### Prompt
Your task is to create a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
using namespace std;
int main() {
int n;
cin >> n;
while (n > 0) {
if (n % 1000 == 144) {
n /= 1000;
} else if (n % 100 == 14) {
n /= 100;
} else if (n % 10 == 1) {
n /= 10;
} else {
cout << "NO" << endl;
return 0;
}
... | ### Prompt
Construct a CPP code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
int n;
int main() {
cin >> n;
int p = 0;
int x;
while (n) {
x = n % 10;
if (x != 4 && x != 1) return (cout << "NO", 0);
if (x == 4) p++;
if (p > 2) return (cout << "NO", 0);
if (x == 1) p = 0;
n /= 10;
}
if (p == 0)
cout << "YES";
e... | ### Prompt
Please formulate a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
if (s[0] == '4') {
cout << "NO" << endl;
return 0;
}
if (s.length() >= 3) {
for (int i = 0; i < s.length(); i++) {
if (s[i] != '4' && s[i] != '1') {
cout << "NO" << endl;
return 0;
}
if... | ### Prompt
Generate a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int n, a[111], kol;
int main() {
cin >> n;
while (n) {
a[kol++] = n % 10;
if (a[0] == 1) {
kol = 0;
for (int i = 0; i < 111; i++) a[i] = 0;
}
if (a[0] == 4 && a[1] == 4 && a[2] == 1) {
kol = 0;
for (int i = 0; i < 111; i++) a[i] =... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int i, j, c, a[12], b, n;
while (cin >> b) {
i = 1;
while (b != 0) {
a[i++] = b % 10;
b = b / 10;
}
i = i - 1;
c = 0;
if (a[i] == 4) {
cout << "NO" << endl;
n = 0;
} else {
for (j = i; j > ... | ### Prompt
Please create a solution in CPP to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long int;
using pii = pair<int, int>;
void _print() { cout << "]\n"; }
template <typename T, typename... V>
void _print(T t, V... v) {
cout << t;
if (sizeof...(v)) cout << ", ";
_print(v...);
}
const int mod = 1000000007;
void io_set() {}
void solve() ... | ### Prompt
Develop a solution in cpp to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
while (n > 0) {
if (n % 1000 == 144) {
n /= 1000;
} else if (n % 100 == 14) {
n /= 100;
} else if (n % 10 == 1) {
n /= 10;
} else {
cout << "NO" << endl;
return 0;
}
}
cout << "YES" <<... | ### Prompt
Your task is to create a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string str;
cin >> str;
if (str[0] != '1') {
puts("NO");
return 0;
}
int cnt = 0;
for (int i = 0; i < str.length(); i++) {
if (str[i] != '1' && str[i] != '4') {
puts("NO");
return 0;
}
if (str[i] == '1')
cnt = 0... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
double tick() {
static clock_t oldt, newt = clock();
double diff = 1.0 * (newt - oldt) / CLOCKS_PER_SEC;
oldt = newt;
return diff;
}
char s[12];
bool check(const char *s) {
if (*s == 0) return true;
if (*s != '1') return false;
if (check(++s)) return true;
i... | ### Prompt
Generate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int f = 2;
for (int i = 0; i < s.size(); i++) {
if (s[i] == '1')
f = 0;
else if (s[i] == '4' && f < 2)
f++;
else
f = -1;
if (f == -1) break;
}
if (f == -1)
printf("NO\n");
else
printf("... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int f = 1, l = s.length();
for (int i = 0; i < l; i++) {
if (s[i] == '1')
continue;
else if (s[i] == '4' && i - 1 >= 0) {
if (s[i - 1] == '1')
continue;
else if (i - 2 >= 0 && s[i - 1] == '4' && s[i ... | ### Prompt
Create a solution in CPP for the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 1e9 + 10;
const long long int INF = 2e18 + 10;
const int Mod = 1e9 + 7;
const int MAXN = 2e5 + 10;
const int N = 1e5 + 10;
string s;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> s;
for (int i = 0; i < s.size(); i++) {
i... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
getline(cin, s);
int i = 0, len;
len = s.length();
if (s[0] != '1')
cout << "NO";
else {
for (i = 1; i < len; i++) {
if (s[i] != '4' && s[i] != '1') {
cout << "NO";
break;
}
if (s[i] == '4') {
... | ### Prompt
Construct a CPP code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
int main() {
char num[18];
int n, i, j;
int flag = 1, k = 0;
scanf("%s", &num);
n = strlen(num);
if (num[0] != '1') flag = 0;
if (flag) {
for (i = 1; i < n; i++) {
if (num[i] != '1' && num[i] != '4') {
flag = 0;
break;
}
}
... | ### Prompt
Develop a solution in CPP to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int L, i, j;
string S;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> S;
L = S.length();
for (i = 0; i < L; i++) {
if (S[i] != '1') {
if (S[i] == '4') {
if (i == 0) {
cout << "NO\n";
return 0;
... | ### Prompt
Please create a solution in cpp to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
long long arr[100005], arrP[10005];
int main() {
string s;
cin >> s;
for (int i = 0; i < s.size(); i++) {
if (s.substr(i, 3) == "144")
i += 2;
else if (s.substr(i, 2) == "14")
i++;
else if (s.substr(i, 1) == "1") {
} else {
cout << "N... | ### Prompt
In Cpp, your task is to solve the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it i... |
#include <bits/stdc++.h>
using namespace std;
string s;
bool bad;
int cnt = 0;
int main() {
cin >> s;
bad = (s[0] != '1');
for (char c : s) {
if (c != '1' && c != '4') bad = true;
if (c == '1')
cnt = 0;
else
cnt++;
if (cnt > 2) bad = true;
}
cout << (bad ? "NO" : "YES");
return 0... | ### Prompt
Develop a solution in CPP to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string a;
cin >> a;
bool f = true;
long long int i;
for (i = 0; i < a.length();) {
if (a[i] == '1' && a[i + 1] == '4' && a[i + 2] == '4') {
i += 3;
} else if (a[i] == '1' && a[i + 1] == '4') {
i += 2;
} else if (a[i] == '1') {
... | ### Prompt
Create a solution in Cpp for the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i;
string x;
cin >> x;
bool f = true;
for (i = 0; i < x.size(); i++) {
if (x[i] == '1' || x[i] == '4')
continue;
else {
f = false;
break;
}
}
int c = 0;
if (x[0] == '4') f = false;
if (f) {
for (i = 0; i <... | ### Prompt
Develop a solution in CPP to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
cout << (regex_match(s, regex("(1|14|144)*")) ? "YES" : "NO");
}
| ### Prompt
Please formulate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int len = s.length();
for (int i = 0; i < len;) {
if (s[i] != '1') {
cout << "NO" << endl;
return 0;
}
if (i + 3 <= len) {
if (s[i + 1] == '4' and s[i + 2] == '4') {
i += 3;
} else if (s[i ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
long long k;
string s, ss[100], s1;
void xuly() {
cin >> s;
if (s[0] != '1') {
cout << "NO";
return;
}
ss[1] = "1";
ss[2] = "14";
ss[3] = "144";
s1 = '.';
for (int i = 3; i >= 1; i--) {
while (s.find(ss[i]) != -1) {
k = s.find(ss[i]);
... | ### Prompt
In CPP, your task is to solve the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it i... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
char c;
cin >> c;
while (1) {
if (c == '1') {
if (!(cin >> c)) break;
if (c == '4') {
if (!(cin >> c)) break;
if (c == '4') {
if (!(cin >> c)) break;
}
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
string s;
cin >> s;
for (int i = 0; i < s.length(); i++) {
if (s.length() >= 3 and s[i] == '1' and s[i + 2] == '4' and
s[i + 1] == '4') {
s.erase(i, 3);
i--;
... | ### Prompt
Construct a CPP code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int n = s.size();
if (s[0] == '4') {
cout << "NO" << endl;
return 0;
}
int F = s.find("1444");
if (F > -1) {
cout << "NO" << endl;
return 0;
}
bool f = false;
for (int i = 0; i < n; i++) {
if (s[i] == ... | ### Prompt
Please formulate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string number;
cin >> number;
bool possible = true;
for (int i = 0; i < number.size();) {
if (number[i] == '1' && number[i + 1] == '4' && number[i + 2] == '4') {
i += 3;
continue;
} else if (number[i] == '1' && number[i + 1] == '4') ... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string a;
cin >> a;
int n = a.size();
for (int i = 0; i < n; i++) {
if ((a[i] == '4' && (a[i - 1] != '1' && a[i - 2] != '1')) ||
(a[i] != '1' && a[i] != '4')) {
cout << "NO";
return 0;
}
}
cout << "YES";
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int z = 0;
if (s[0] != '1')
cout << "NO" << endl;
else {
for (int i = 1; i < s.size(); i++) {
if ((s[i] == '1') || (s[i] == '4' && s[i - 1] == '1') ||
(s[i] == '4' && s[i - 1] == '4' && s[i - 2] == '1'))
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
string s;
cin >> s;
int i, p = 0;
for (i = 0; i < s.size(); i++) {
if (s[i] != '1' && s[i] != '4' || s[0] == '4') p++;
if (s[i] == '4') {
if (s[i + 1] == '4' && s[i + 2] == '4') p++;
}
}
... | ### Prompt
In Cpp, your task is to solve the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it i... |
#include <bits/stdc++.h>
using namespace std;
void exec(int T) {
string s;
cin >> s;
for (int i = 0; i < s.size();) {
if ((i + 2) < s.size() && s.substr(i, 3) == "144") {
i += 3;
continue;
}
if ((i + 1) < s.size() && s.substr(i, 2) == "14") {
i += 2;
continue;
}
if (i <... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(NULL);
cout.flush();
string s;
cin >> s;
if (s[0] != '1') {
cout << "NO" << endl;
return 0;
}
int cnt = 0;
for (int i = 1; i < s.size(); i++) {
if (s[i] == '4')
cnt++;
else
... | ### Prompt
Please formulate a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
if (s[0] != '1') {
cout << "NO" << endl;
return 0;
}
int cntr = 0;
for (int i = 0; i < s.size() - 1; i++) {
if (s[i] == '1') {
if (s[i + 1] != '4' && s[i + 1] != '1') {
cout << "NO" << endl;
retu... | ### Prompt
Generate a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string t;
cin >> t;
long long int i = 0;
long long int c = 1;
while (1) {
if (i >= t.length()) break;
if (t[i] == '1') {
i++;
if (i < t.length())
if (t[i] == '4') {
i++;
if (i < t.length()) {
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int f = 0;
if (s[0] != '1' && s[0] != '4') {
cout << "NO";
return 0;
}
if (s[0] == '4') {
cout << "NO";
return 0;
}
for (int i = (1); i <= (s.length() - 1); i++) {
if (s[i] != '1' && s[i] != '4') {
f... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int cnt = 0;
bool flag = true;
for (int i = 0; i < s.length(); i++) {
if (s[i] != '1' && s[i] != '4') {
flag = false;
break;
}
if (s[0] == '4') {
flag = false;
break;
}
if (s.find("444") ... | ### Prompt
Your task is to create a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
long long dx[4] = {-1, 0, 1, 0};
long long dy[4] = {0, -1, 0, 1};
long long mod = 1e9 + 7;
long long inf = INT_MAX;
using namespace std;
bool isPrime(long long n) {
long long j;
for (j = 2; j <= sqrt(n); j++) {
if (n % j == 0) {
break;
}
}
if (j > sqrt(n)) {
return 1;
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
int main() {
char a[15];
int n, m, i, j, sum, count, l, z, x;
while (~scanf("%s", a)) {
z = 0;
x = 0;
count = 0;
l = strlen(a);
for (i = 0; i < l; i++) {
if (a[i] == '1') {
z++;
} else if (a[i] == '4') {
x++;
}
}
if (x > 2 * z ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
bool chk(string num) {
for (int i = 0; i < (int)num.size(); i++)
if (num[i] != '1' && num[i] != '4') return false;
if (num[0] == '4') return false;
if (num.find("444") != num.npos) return false;
return true;
}
int main() {
string num;
cin >> num;
if (chk(n... | ### Prompt
Please create a solution in cpp to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long int;
using pll = pair<ll, ll>;
using vll = vector<ll>;
ll testcases;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
testcases = 1;
while (testcases--) {
string n;
cin >> n;
ll o = 0, f = 0, fail = 0;
for (ll i = 0;... | ### Prompt
Please formulate a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
typedef long long LL;
using namespace std;
const int M = 1000000007;
int main() {
ios_base::sync_with_stdio(0);
cout.precision(15);
cout.setf(ios::fixed);
LL n;
cin >> n;
LL cnt = 0, mx = 0;
bool on = true;
bool en = true;
while (n != 0) {
if (n % 10 == 4)
cnt++;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int ans = 0;
string s;
cin >> s;
for (int i = 0; i < s.size(); i++) {
if (s[i] == '1')
ans++;
else if (s[i] == '4' && s[i - 1] == '1' ||
s[i] == '4' && s[i - 1] == '1' && s[i + 1] == '4' ||
s[i] == '4' && s[i - 1]... | ### Prompt
Please formulate a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
set<string> sso;
void gens(string curr) {
if (curr.size() > 0 && stoll(curr) >= 1000000000) return;
if (curr.size() > 0) {
sso.insert(curr);
}
gens(curr + "14");
gens(curr + "1");
gens(curr + "144");
}
int main(int argc, const char** argv) {
std::ios_base:... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
while (cin >> n) {
int flag = 0;
while (n) {
if (n % 1000 == 144)
n /= 1000;
else if (n % 100 == 14)
n /= 100;
else if (n % 10 == 1)
n /= 10;
else {
flag = 1;
break;
}
... | ### Prompt
Please create a solution in CPP to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
char a[12];
int i, n, mark = 0;
deque<char> s;
scanf("%s", a);
n = strlen(a);
for (i = 0; i < n; i++) {
if (mark == 3 || (mark == 0 && a[i] != '1')) {
s.push_back(a[i]);
mark = 3;
continue;
}
if (a[i] == '1' && mark == ... | ### Prompt
Generate a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
regex r("^(1|14|144)*$");
if (regex_match(s, r)) {
cout << "YES" << endl;
} else {
cout << "NO" << endl;
}
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n;
cin >> n;
string s = to_string(n);
vector<long long> v1;
int flag = 0;
for (int i = 0; i < s.length(); i++) {
v1.push_back(s[i] - '0');
if (s[i] != '1' && s[i] != '4') {
flag = 1;
break;
}
}
if (count(v1.begi... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. De... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string num;
cin >> num;
int satu = 0, empat = 0;
bool E;
E = false;
for (int i = 0; i < num.length();) {
if (num[i] == '1') {
while (num[i] == '1') {
satu++;
i++;
}
i--;
}
if (num[i] == '4') {
if (... | ### Prompt
In Cpp, your task is to solve the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it i... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long n;
cin >> n;
while (n > 0) {
if (n % 10 == 1)
n = n / 10;
else if (n % 100 == 14)
n = n / 100;
else if (n % 1000 == 144)
n = n / 1000;
else
... | ### Prompt
Please create a solution in cpp to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
s.reserve(15);
cin >> s;
int flag = 0;
for (int i = 0; i < s.size();) {
if (s[i] == '1' && s[i + 1] == '4' && s[i + 2] == '4')
i += 3;
else if (s[i] == '1' && s[i + 1] == '4')
i += 2;
else if (s[i] == '1')
i++;
... | ### Prompt
Please formulate a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
bool is_magical(string number) {
for (int i = 0; i < (int)number.size(); i++)
if (number[i] != '1' && number[i] != '4') return false;
if (number[0] == '4') return false;
if (number.find("444") != number.npos) return false;
return true;
}
int main() {
string nu... | ### Prompt
Generate a CPP solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string str;
int size, i = 0;
bool islucky = true;
cin >> str;
size = str.length();
if (str.length() == 1 && str.at(0) != '1')
islucky = false;
else if (str.length() == 2 && str.at(1) != '1' && str.at(1) != '4')
islucky = false;
else {
... | ### Prompt
Your task is to create a cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
char ch[1000000];
cin >> ch;
int len = strlen(ch);
int i, cnt = 0;
for (i = 0; i < len; i++) {
if (ch[i] != '1' && ch[i] != '4') {
cout << "NO";
cnt++;
break;
} else if (ch[0] != '1') {
cout << "NO";
cnt++;
... | ### Prompt
In cpp, your task is to solve the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it i... |
#include <bits/stdc++.h>
using namespace std;
int i;
string second;
int main() {
getline(cin, second);
for (i = 0; i < second.length(); i++)
if (second[i] == '1') {
if (i + 1 < second.length())
if (second[i + 1] == '4') {
i++;
if (i + 1 < second.length())
if (second... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long a, c, d, f;
cin >> a;
while (a > 0) {
if (!((a % 10 == 1) || (a % 100) == 14 || (a % 1000) == 144)) {
cout << "NO";
return 0;
}
a = a / 10;
}
cout << "YES";
return 0;
}
| ### Prompt
Generate a Cpp solution to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
string s;
getline(cin, s);
int l = s.length();
int i = 0;
for (; i < l;) {
if (s[i] != '1')
break;
else {
int step = 1;
if (s[i + 1] == '4') {
step++;
if (s[i + 2] == '... | ### Prompt
Please create a solution in CPP to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
long long int n, l;
l = s.size();
for (long long int i = 0; i < l; i++) {
if ((s[i] != '1' && s[i] != '4') || s[0] == '4') {
cout << "NO" << endl;
return 0;
} else if (s[i] == '4' && s[i + 1] == '4' && s[i + 2] ... | ### Prompt
Develop a solution in Cpp to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string x;
getline(cin, x);
unsigned int i, n = x.size();
char k = 0;
string flag = "NO";
for (i = 0; i < n; i += k) {
k = 0;
if (x[i] == '1') {
flag = "YES";
++k;
if (x[i + 1] == '4' && (i + 1) < n) {
flag = "YES";
... | ### Prompt
Create a solution in cpp for the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is... |
#include <bits/stdc++.h>
using namespace std;
int main() {
char n[1000];
cin >> n;
int count = 0;
int notmagical = 0;
if (n[0] != '1') {
cout << "NO";
return 0;
}
for (int i = 0; i < strlen(n); i++) {
if (n[i] == '1') {
count = 0;
} else if (n[i] == '4' && count < 2) {
count++;... | ### Prompt
Construct a CPP code solution to the problem outlined:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, k = 0;
cin >> n;
while (n > 0) {
if ((n % 10) == 1) {
n = n / 10;
k = 1;
} else if ((n % 100) == 14) {
n = n / 100;
k = 1;
} else if ((n % 1000) == 144) {
n = n / 1000;
k = 1;
} else {
... | ### Prompt
Please create a solution in Cpp to the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
scanf("%d", &n);
while (n) {
if (n % 1000 == 144) {
n /= 1000;
continue;
}
if (n % 100 == 14) {
n /= 100;
continue;
}
if (n % 10 == 1) {
n /= 10;
continue;
}
printf("NO\n");
return... | ### Prompt
Develop a solution in Cpp to the problem described below:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if... |
#include <bits/stdc++.h>
using namespace std;
int main() {
char s[105];
cin >> s;
for (int i = 0; s[i]; i++)
if (s[i] != '1' && s[i] != '4') {
cout << "NO" << endl;
return 0;
}
for (int i = 0; s[i]; i++) {
if (s[i] == '4') {
cout << "NO" << endl;
return 0;
} else if (s[i ... | ### Prompt
In Cpp, your task is to solve the following problem:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it i... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 190001;
const int MAXM = 11111;
const int INF = 0x3f3f3f3f;
const long long mod = 1000000007;
int n, m, l, r;
int a[MAXN];
int b[MAXN];
int c[MAXN];
char s[MAXN];
int main() {
cin >> s + 1;
n = strlen(s + 1);
memset(a, 0, sizeof(a)), memset(b, 0, size... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
inline long long minOf(long long x, long long y) { return (x < y ? x : y); }
inline long long maxOf(long long x, long long y) { return (x > y ? x : y); }
inline long long mabs(long long x) {
if (x < 0) return -x;
return x;
}
int main() {
ios_base::sync_with_stdio(fals... | ### Prompt
In cpp, your task is to solve the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous s... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int fs[100000 + 1][3] = {};
for (int i = 0; i < s.length(); i++) {
fs[i + 1][0] = fs[i][0];
fs[i + 1][1] = fs[i][1];
fs[i + 1][2] = fs[i][2];
if (s[i] == 'x') fs[i + 1][0]++;
if (s[i] == 'y') fs[i + 1][1]++;
i... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
char s[200 * 1000];
int z[1000 * 200], y[1000 * 200], x[1000 * 200];
int fls[200 * 1000];
int main() {
cin >> s;
int n;
for (int i = 1; s[i - 1]; ++i) {
z[i] = z[i - 1] + (s[i - 1] == 'z');
x[i] = x[i - 1] + (s[i - 1] == 'x');
y[i] = y[i - 1] + (s[i - 1] =... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int *arra = new int[s.length() + 1];
int *arrb = new int[s.length() + 1];
int *arrc = new int[s.length() + 1];
arra[0] = 0;
arrb[0] = 0;
arrc[0] = 0;
for (int i = 0; i < s.length(); i++) {
if (s[i] == 'x') {
arra[... | ### Prompt
Develop a solution in Cpp to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
using namespace std;
char inn[100005] = {0};
int xs[100005] = {0};
int zs[100005] = {0};
int ys[100005] = {0};
int main() {
scanf("%s ", inn);
int n;
scanf("%d ", &n);
int Xs = 0;
int Zs = 0;
int Ys = 0;
for (int i = 0; inn[i]; i++) {
if (inn[i] == 'x') Xs++;
if (inn[i] ==... | ### Prompt
Generate a Cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous subs... |
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long x, long long y) {
if (y == 0) return x;
return gcd(y, x % y);
}
long long lcm(long long a, long long b) { return a / gcd(a, b) * b; }
struct letters {
int x = 0, y = 0, z = 0;
};
int main() {
char arr[100005];
scanf("%s", arr);
letters cu... | ### Prompt
Please create a solution in Cpp to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
char s[100012];
int m, l, r;
int x[100010], y[100010], z[100010];
using namespace std;
int main() {
scanf("%s%*c", s);
scanf("%d%*c", &m);
x[0] = y[0] = z[0] = 0;
for (int i = 0; s[i] != '\0'; i++) {
x[i + 1] = x[i];
y[i + 1] = y[i];
z[i + 1] = z[i];
if (s[i] == 'x') {
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
string s;
int x[100009], y[100009], z[100009], m, l, r;
int main() {
cin >> s;
cin >> m;
for (int i = 1; i <= s.size(); i++) {
x[i] = x[i - 1];
y[i] = y[i - 1];
z[i] = z[i - 1];
if (s[i - 1] == 'x') x[i]++;
if (s[i - 1] == 'y') y[i]++;
if (s[i ... | ### Prompt
Generate a cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous subs... |
#include <bits/stdc++.h>
const int mx = 1e5 + 10;
using namespace std;
char c;
string s;
int x[mx], y[mx], z[mx], n, a, b, k;
int main() {
x[0] = y[0] = z[0] = 0;
cin >> s;
for (int i = 0; i < (int)s.size(); i++) {
c = s[i];
k = i + 1;
x[k] = x[k - 1];
y[k] = y[k - 1];
z[k] = z[k - 1];
if ... | ### Prompt
Create a solution in Cpp for the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous su... |
#include <bits/stdc++.h>
using namespace std;
string s;
int x[100005];
int y[100005];
int z[100005];
int main() {
ios_base::sync_with_stdio(0);
;
cin >> s;
for (int i = 0; i < s.size(); i++) {
if (s[i] == 'x') {
x[i + 1]++;
} else if (s[i] == 'y') {
y[i + 1]++;
} else {
z[i + 1]++;... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
int n, m, x, y, z, p, q, r;
int ara[5];
string str;
int csum[4][200000];
int main() {
cin >> str;
str = "?" + str;
for (int i = 1; i < str.size(); i++) {
int ch = str[i] - 'x';
csum[ch][i]++;
for (int j = 0; j < 3; j++) csum[j][i] += csum[j][i - 1];
}
... | ### Prompt
In cpp, your task is to solve the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous s... |
#include <bits/stdc++.h>
using namespace std;
struct element {
int x;
int y;
int z;
};
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
string s;
cin >> s;
element arr[100010];
int x = 0, y = 0, z = 0;
for (int i = 0; i < (int)s.size(); i++) {
if (s[i] == 'x') {
x++;
}... | ### Prompt
Develop a solution in CPP to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
using namespace std;
void solve(istream &in, ostream &out) {
string str;
in >> str;
int n = str.size();
vector<int> numX(n + 1), numY(n + 1), numZ(n + 1);
for (int i = 0; i < n; i++) {
numX[i + 1] = numX[i] + (str[i] == 'x');
numY[i + 1] = numY[i] + (str[i] == 'y');
numZ[i... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
char str[100005];
int a[100005], b[100005], c[100005];
int main() {
int m, i, len, x, y, xx, yy, zz;
scanf("%s", str);
len = strlen(str);
for (i = 0; i < len; i++) {
if (str[i] == 'x') {
a[i + 1] = a[i] + 1;
b[i + 1] = b[i];
c[i + 1] = c[i];
}
if (str[i] ==... | ### Prompt
Construct a cpp code solution to the problem outlined:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous... |
#include <bits/stdc++.h>
using namespace std;
long long n, a[600000], b[600000], c[600000], l, r, g, ans;
vector<long long> v;
string s;
char f;
int main() {
cin >> s;
for (int i = 0; i < s.size(); i++) {
if (s[i] == 'x')
a[i + 1] = 1;
else if (s[i] == 'y')
b[i + 1] = 1;
else if (s[i] == 'z'... | ### Prompt
In cpp, your task is to solve the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous s... |
#include <bits/stdc++.h>
using namespace std;
int M;
string s;
int A, B;
int x[100001], y[100001], z[100001], d[3];
int main() {
cin >> s;
scanf("%d", &M);
for (int(i) = 0; (i) < (s.size()); (i)++) {
x[i + 1] = x[i] + (s[i] == 'x');
y[i + 1] = y[i] + (s[i] == 'y');
z[i + 1] = z[i] + (s[i] == 'z');
}... | ### Prompt
Develop a solution in cpp to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
using namespace std;
int s1[100005];
int s2[100005];
int s3[100005];
string s11 = "xzy";
string s22 = "yxz";
string s33 = "zyx";
bool ok(int l, int r) {
int a, b, c, d;
a = s1[r];
b = s2[r];
c = s3[r];
if (l != 0) {
a -= s1[l - 1];
b -= s2[l - 1];
c -= s3[l - 1];
}
if ... | ### Prompt
Your task is to create a CPP solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any c... |
#include <bits/stdc++.h>
using namespace std;
int main() {
char str[100000 + 11];
int ant[3][100000 + 11];
int m;
int l, r;
scanf("%s", str + 1);
ant[0][0] = ant[1][0] = ant[2][0] = 0;
for (int i = 1; str[i]; i++) {
if (str[i] == 'x') {
ant[0][i] = ant[0][i - 1] + 1;
ant[1][i] = ant[1][i -... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100005;
int x[maxn];
int y[maxn];
int z[maxn];
char s[maxn];
void Init() {
for (int i = 0; s[i] != '\0'; i++) {
x[i + 1] = x[i];
y[i + 1] = y[i];
z[i + 1] = z[i];
if (s[i] == 'x') {
x[i + 1]++;
} else if (s[i] == 'y') {
y[i... | ### Prompt
Generate a cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous subs... |
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
template <class c>
struct rge {
c b, e;
};
template <class c>
rge<c> range(c i, c j) {
return rge<c>{i, j};
}
template <class c>
auto dud(c* x) -> decltype(cerr << *x, 0);
template <class c>
char dud(...);
struct debug {
template <class c>
... | ### Prompt
Generate a CPP solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous subs... |
#include <bits/stdc++.h>
using namespace std;
template <typename typ>
void vout(vector<typ>& v) {
for (int vint = 0; vint < (int)(v).size(); vint++) cout << (v)[vint] << ' ';
cout << endl;
}
template <typename typ>
void arrout(typ* arr, int l) {
for (int i = 0; i < l; i++) cout << arr[i] << ' ';
cout << endl;
}... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 1e5 + 5;
long long x[N], y[N], z[N];
void solve() {
string s;
cin >> s;
long long n = s.size();
for (long long i = 0; i < n; i++) {
if (s[i] == 'x')
x[i] = 1;
else if (s[i] == 'y')
y[i] = 1;
else
z[i] = 1;
}
for ... | ### Prompt
Generate a cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous subs... |
#include <bits/stdc++.h>
const double pi = 3.1415926535897;
using namespace std;
int xC[100005] = {}, yC[100005] = {}, zC[100005] = {};
int main() {
string s;
int m, l, r;
cin >> s;
for (int i = 1; i <= s.length(); i++) {
xC[i] = xC[i - 1] + (s[i - 1] == 'x');
yC[i] = yC[i - 1] + (s[i - 1] == 'y');
... | ### Prompt
Please formulate a Cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
using namespace std;
int a[3][100005], t[3];
int main() {
string s;
cin >> s;
int n, l, r;
for (int i = 0; i < s.size(); i++) {
if (s[i] >= 'x') {
a[s[i] - 'x'][i + 1]++;
}
for (int j = 0; j < 3; j++) {
a[j][i + 1] += a[j][i];
}
}
cin >> n;
int zh;
fo... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find a... |
#include <bits/stdc++.h>
using namespace std;
int x[100005], y[100005], z[100005];
int main() {
string str;
int n, i, j;
cin >> str;
if (str[0] == 'x')
x[0] = 1;
else if (str[0] == 'y')
y[0] = 1;
else
z[0] = 1;
for (i = 1; i < str.size(); i++) {
x[i] = x[i - 1], y[i] = y[i - 1], z[i] = z[i... | ### Prompt
Construct a cpp code solution to the problem outlined:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous... |
#include <bits/stdc++.h>
using namespace std;
const int maxN = 110000;
int t[maxN][3];
int main() {
int n, m;
string s;
cin >> s;
cin >> m;
n = s.size();
for (int i = 1; i <= n; i++)
for (int j = 0; j < 3; j++)
if (s[i - 1] - 'x' == j)
t[i][j] = t[i - 1][j] + 1;
else
t[i][j] ... | ### Prompt
Please create a solution in Cpp to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
T abs(T x) {
return x > 0 ? x : -x;
}
const int maxn = 110005;
int n, m, t, k;
int vis[maxn];
int x[maxn], y[maxn], z[maxn];
char s[maxn];
int main() {
scanf("%s", s);
n = strlen(s);
for (int i = 1; i <= n; i++) {
x[i] = x[i - 1];
y[i] = y... | ### Prompt
Develop a solution in Cpp to the problem described below:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continu... |
#include <bits/stdc++.h>
using namespace std;
long long mod(long long a, long long m) { return (a % m + m) % m; }
int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};
string s;
int x[100100], y[100100], z[100100];
int m;
int main() {
cin >> s;
switch (s[0]) {
case 'x':
x[1] = 1;
break;
case 'y':
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any c... |
#include <bits/stdc++.h>
using namespace std;
int dx[] = {0, 1, -1, 0};
int dy[] = {1, 0, 0, -1};
long double PI = 3.14159265358979323846264338327950;
const int N = 1e5 + 10;
int x[N], y[N], z[N];
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
string s;
cin >> s;
for (int i = 1; i <= (int)s.size(); ... | ### Prompt
Construct a cpp code solution to the problem outlined:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous... |
#include <bits/stdc++.h>
using namespace std;
void fast() {
std::ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
bool comp(char s1, char s2) { return tolower(s1) < tolower(s2); }
int main() {
fast();
int l, r, n, m, a, b, c, i;
string s;
cin >> s;
n = s.length();
int x[n], y[n], z[n], flag = ... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as q = q1q2... qk. The algorithm consists of two steps:
1. Find any continuous... |
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