output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100005, mod = 998244353;
inline int gi() {
char c = getchar();
while (c < '0' || c > '9') c = getchar();
int sum = 0;
while ('0' <= c && c <= '9') sum = sum * 10 + c - 48, c = getchar();
return sum;
}
inline int add(int a, int b) { return a + b >=... | ### Prompt
Develop a solution in cpp to the problem described below:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one o... |
#include <bits/stdc++.h>
const int N = 100005;
const int MOD = 998244353;
int n, k, cnt, last[N], jc[N], ny[N], a[20][N * 2], b[N], tot, rev[N * 2],
size[N], f[N], s[N], L, ans;
struct edge {
int to, next;
} e[N * 2];
struct data {
int x, y;
} t[N];
int read() {
int x = 0, f = 1;
char ch = getchar();
whil... | ### Prompt
Your task is to create a CPP solution to the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly... |
#include <bits/stdc++.h>
using namespace std;
const int maxN = 303000;
const int maxM = maxN << 1;
const int G = 3;
const int Mod = 998244353;
const int maxB = 18;
int n, K, Ans = 0;
int Fc[maxN], Ifc[maxN], R[maxN];
int edgecnt = 0, Head[maxN], Next[maxM], V[maxM];
int F[maxN], Sz[maxN], Seq[maxN], Bp[maxB][maxN], St[... | ### Prompt
Construct a cpp code solution to the problem outlined:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of t... |
#include <bits/stdc++.h>
using namespace std;
string to_string(string s) { return '"' + s + '"'; }
string to_string(const char *s) { return to_string((string)s); }
string to_string(bool b) { return (b ? "true" : "false"); }
template <typename A, typename B>
string to_string(pair<A, B> p) {
return "(" + to_string(p.fi... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exa... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 262144;
const int mod = 998244353;
const int G = 3, I = 332748118;
inline int add(int a, int b) {
a += b;
if (a >= mod) a -= mod;
return a;
}
inline int mult(int a, int b) {
long long t = 1ll * a * b;
if (t >= mod) t %= mod;
return t;
}
inline i... | ### Prompt
Create a solution in cpp for the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of thes... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline void chkmin(T &a, T b) {
if (a > b) a = b;
}
template <class T>
inline void chkmax(T &a, T b) {
if (a < b) a = b;
}
inline int read() {
int s = 0, f = 1;
char ch = getchar();
while (!isdigit(ch) && ch != '-') ch = getchar();
if (ch == '... | ### Prompt
Create a solution in Cpp for the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of thes... |
#include <bits/stdc++.h>
using namespace std;
int head[100010], nxt[100010 * 2], a[100010 * 2], edge, size[100010],
sum[100010], value[100010], pre[100010], cur[100010];
int pos[100010], k, fac[100010], inv[100010], A[200010], B[200010], C[200010],
rev[200010], omega[200010], res, n;
vector<int> p[100010 * 4];
... | ### Prompt
Generate a cpp solution to the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of these ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXL = 1048576;
const int P = 998244353;
const int g[] = {3, (P + 1) / 3};
template <typename T1, typename T2>
void Inc(T1 &a, T2 b) {
a += b;
if (a >= P) a -= P;
}
template <typename T1, typename T2>
void Dec(T1 &a, T2 b) {
a -= b;
if (a < 0) a += P;
}
te... | ### Prompt
Create a solution in CPP for the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of thes... |
#include <bits/stdc++.h>
using namespace std;
inline int read() {
int x = 0, f = 1, c = getchar();
while (!isdigit(c)) {
if (c == '-') f = -1;
c = getchar();
}
while (isdigit(c)) {
x = (x << 1) + (x << 3) + (c ^ 48);
c = getchar();
}
return f == 1 ? x : -x;
}
const int mod = 998244353, inv2 ... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exa... |
#include <bits/stdc++.h>
using namespace std;
const int LOG = 20;
const int N = 200000 + 5;
const int r = 3, PP = 998244353;
inline int Mod(int a) {
if (a < 0) return a + PP;
return a >= PP ? a - PP : a;
}
inline int Mul(int a, int b) { return (long long)a * b % PP; }
inline int Pow(int a, int b) {
int ret = 1;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of t... |
#include <bits/stdc++.h>
using namespace std;
int power(int a, int b) {
int res = 1;
while (b > 0) {
if (b & 1) res = 1ll * res * a % 998244353;
a = 1ll * a * a % 998244353;
b = b >> 1;
}
return res;
}
namespace NTT {
int rev[400010];
int ww[400010 << 1], *g = ww + 400010;
int a[400010], b[400010];
... | ### Prompt
Create a solution in CPP for the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of thes... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5, MOD = 998244353, P = 18;
int fac[N], inv[N], invc[N], w[2][1 << P], rev[1 << P];
inline int add(int a, const int &b) {
if ((a += b) >= MOD) a -= MOD;
return a;
}
inline int sub(int a, const int &b) {
if ((a -= b) < 0) a += MOD;
return a;
}
inl... | ### Prompt
Generate a CPP solution to the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of these ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 4e5 + 10, mod = 998244353;
int n, K, cc, A[N], B[N], siz[N], fz[N];
int l, w[N], r[N], tt, Ans, L[N], jc[N], inv[N], jcv[N];
int sum[N], val[N];
vector<int> E[N], G[N], F[N << 2];
int ksm(int x, int k) {
int s = 1;
for (; k; k >>= 1, x = 1ll * x * x % mod)... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exa... |
#include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 10;
const int MOD = 998244353;
const int g = 3;
inline int Mul(int a, int b) {
unsigned long long x = (long long)a * b;
unsigned xh = (unsigned)(x >> 32), xl = (unsigned)x, d, m;
asm("divl %4;\n\t" : "=a"(d), "=d"(m) : "d"(xh), "a"(xl), "r"(MOD));
... | ### Prompt
Generate a cpp solution to the following problem:
You are given a tree of n vertices. You are to select k (not necessarily distinct) simple paths in such a way that it is possible to split all edges of the tree into three sets: edges not contained in any path, edges that are a part of exactly one of these ... |
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i,a,b) for (ll i = (a); i < (b); i++)
#define REP(i,n) rep(i,0,n)
void solve()
{
int n;cin>>n;
int a[n],b[n];
REP(i,n)cin>>a[i];
REP(i,n)cin>>b[i];
int j=0,now=-1;
REP(i,n){
if(now!=a[i])j=0;
if(a[i... | ### Prompt
Generate a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reordering... |
#include<bits/stdc++.h>
using namespace std;
int a[200001],b[200001];
int main()
{
int n;
cin>>n;
for(int i=1;i<=n;i++)
cin>>a[i];
for(int i=n;i>=1;i--)
cin>>b[i];
int flag=0;
for(int i=1;i<=n;i++)
{
if(a[i]==b[i])
{
flag=0;
for(int j=1;j<=n;j++)
{
if(a[i]!=b[j]&&a[j]!=b[i])
{
swap(b[... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<bits/stdc++.h>
using namespace std;
void solve(){
int n,m;
cin>>n;
vector<int>A(n);
vector<int>B(n);
vector<int>C(n+1);
bool p=0;
for(int i=0;i<n;i++){
cin>>A[i];
C[A[i]]++;
}
for(int i=0;i<n;i++) {
cin>>B[i];
C[B[i]]++;
if(C[B[i]]>n) p=1;
}
if(p){
cout<<"No";
return;
}
cout<<"Yes ... | ### Prompt
Develop a solution in Cpp to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
using namespace std;
int n,a[200010],b[200010],cnt[200010],L,R,l,r;
inline int read()
{
int x=0,w=0;char ch=0;
while(!isdigit(ch)){w|=ch=='-';ch=getchar();}
while(isdigit(ch)){x=(x<<1)+(x<<3)+(ch^48);ch=getchar();}
return w?-x:x;
}
int main()
{
n=read();
for(int i=1;i<=n;i++)cnt[a[i]=read(... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
#define x first
#define y second
#define pb push_back
#define mk make_pair
#define all(a) a.begin(), a.end()
#define len(a) (int)a.size()
using namespace std;
typedef long long ll;
typedef vector <int> vi;
typedef pair <int, int> pii;
int main(){
int n;
cin >> n;
vector <int> a(n), b(n);
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<iostream>
#include<algorithm>
#include<map>
#include<cstdio>
#include<cstring>
#include<cmath>
#define ll long long
#define lson (rt<< 1)
#define rson (rt<< 1 | 1)
#define gmid ((l+r)>> 1 )
using namespace std;
const int maxn=20000050;
int a[maxn],b[maxn];
int main()
{
int n;
cin>>n;
for(int i=1;i<=n;++i... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < n; i++)
#define rrep(i, n) for (int i = n - 1; i >= 0; i--)
using namespace std;
#define INF ((1<<30)-1)
#define LINF (1LL<<60)
#define EPS (1e-10)
typedef long long ll;
typedef pair<ll, ll> P;
const int MOD = 1000000007;
const int MOD2 = 998244353;
int a[... | ### Prompt
Construct a cpp code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<map>
#include<stack>
#include<queue>
#include<string>
#include<math.h>
#include<stdio.h>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
const int P=139;
const int mod=149;
const int maxn=1e6+5;
typedef long long ll;
const int inf=0x3f3f3f3f;
const int minn=0xc0c0c0c0;
int n,ans,... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
using namespace std;using v=vector<int>;int n;bool h(v a,v b){bool r=1;for(int i=0;i<n;i++)r&=(a[i]!=b[i]);return r;}void f(bool g, v a) {cout<<(g?"Yes\n":"No\n");if(g)for(int e:a)cout<<e<<'\n';}int main(){cin>>n;v a(n),b(n),c;for(int&e:a)cin>>e;for(int&e:b)cin>>e;c=b;reverse(begin(b),end(b));r... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
using namespace std;
int main(){
int n; cin >> n;
vector<int> a(n), b(n);
for(int i = 0; i < n; i++) cin >> a[i];
for(int i = 0; i < n; i++) cin >> b[i];
reverse(b.begin(), b.end());
int l = 0, r = -1, c;
for(int i = 0; i < n; i++)
if(a[i]==b[i]){
l = i; c = a[i];
break;
}
f... | ### Prompt
Develop a solution in cpp to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
#define rep(i,n) for(int i=0; i<(n); i++)
int N;
int A[200001];
int B[200001];
int cA[200001]={};
int cB[200001]={};
int ans[200001];
int main(){
scanf("%d",&N);
rep(i,N){ scanf("%d",&A[i]); cA[A[i]]++; A[i]--; }
rep... | ### Prompt
Develop a solution in cpp to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int INF = 0x3f3f3f3f;
const LL mod = 1e9 + 7;
const int N = 200005;
int a[N], b[N], c[N];
int vis[N];
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i], c[a[i]]++;
for (int i = 0; i < n; i++) cin >> b[i], c[b[i... | ### Prompt
Develop a solution in CPP to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#define ios ios::sync_with_stdio(0); cin.tie(0); cout.tie(0)
using namespace std;
typedef long long ll;
const int INF=0x3f3f3f3f;
const int MAXN=2e5+100;
int a[MAXN],b[MAXN];
int main(){
ios;
int n;
cin>>n;
for(int i=1;i<=n;i++) cin>>a[i];
f... | ### Prompt
Please create a solution in cpp to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
#define l int
using namespace std;using v=vector<l>;l n;l h(v a,v b){l r=1;for(l i=0;i<n;i++)r&=a[i]!=b[i];return r;}l f(l g,v a){cout<<(g?"Yes\n":"No\n");if(g)for(l e:a)cout<<e<<'\n';exit(0);}l main(){cin>>n;v a(n),b(n),c;for(l&e:a)cin>>e;for(l&e:b)cin>>e;c=b;reverse(begin(b),end(b));rotate(be... | ### Prompt
Please create a solution in cpp to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <iostream>
#include <string>
#include <math.h>
#include <algorithm>
#include <vector>
using namespace std;
int main(){
int N;
cin>>N;
int A[200000],B[200000];
for(int i=0;i<N;i++) cin>>A[i];
for(int i=0;i<N;i++) cin>>B[i];
sort(B,B+N,greater<int>());
vector<int> same;
for(int i=0;i<N;i++){
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <iostream>
#include <vector>
#define rep(i, n) for (int i = 0; i < (n); i++)
using namespace std;
int main(void) {
ios::sync_with_stdio(false);
int N;
cin >> N;
vector<int> A(N);
vector<int> Acnt(N + 1, 0);
rep(i, N) {
cin >> A[i];
Acnt[A[i]]++;
}
vector<int> B(N);
vector<int> Bcnt(N... | ### Prompt
Create a solution in Cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include<bits/stdc++.h>
using namespace std;
typedef int64_t ll;
int main(){
ll n;
cin>>n;
ll a[n],b[n];
for(int i=0;i<n;i++)cin>>a[i];
for(int i=0;i<n;i++)cin>>b[i];
reverse(b,b+n);
ll j=0;
for(int i=0;i<n;i++){
if(a[i]==b[i]){
for(;j<n;j++){
if(a[i]!=b[j] && a[j]!=b[i]){
s... | ### Prompt
Please create a solution in CPP to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const int N=200000;
int n,a[N+9],b[N+9],p[2][N+9],ans[N+9];
int main(){
scanf("%d",&n);
for (int i=1;i<=n;++i)
scanf("%d",&a[i]);
for (int i=n;i>=1;--i)
if (!p[0][a[i]]) p[0][a[i]]=i;
for (int i=1;i<=n;++i){
scanf("%d",&b[i]);
if (!p[1][... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<bits/stdc++.h>
using namespace std;
#define FOR(i, x, y) for(int i = (x); i < (y); ++i)
#define REP(i, x, y) for(int i = (x); i <= (y); ++i)
#define PB push_back
#define MP make_pair
#define PH push
#define fst first
#define snd second
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
... | ### Prompt
Please formulate a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
int N,A[200000],B[200000];
int main(){
cin>>N;
for(int i=0;i<N;i++){
cin>>A[i];
}
for(int i=0;i<N;i++){
cin>>B[i];
}
reverse(B,B+N);
int f=0;
int b=N-1;
for(int i=0;i<N;i++){
if(A[i]==B[i]){
if(B[f]!=A[i]&&A[f]!=B[i]){
swap(B[f],B[i]);
f++;
}
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<map>
#include<stack>
#include<queue>
#include<string>
#include<math.h>
#include<stdio.h>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
const int maxn=1e6+5;
int n,ans,res,sit,a[maxn],b[maxn];
int main()
{
//ios::sync_with_stdio(false);
//cin.tie(0);cout.tie(0);
cin>>n;... | ### Prompt
Create a solution in cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include <bits/stdc++.h>
using namespace std;
#define int long long
signed main(){
// cout << fixed << setprecision(10) << flush;
int n;
cin >> n;
vector<int> a(n), b(n);
vector<int> numa(n+1, 0), numb(n+1, 0);
for(int i=0; i<n; i++){
cin >> a[i];
numa[a[i]]++;
}
for(in... | ### Prompt
Generate a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reordering... |
#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
using namespace std;
using ll = long long;
using P = pair<int,int>;
int main() {
int n;
cin >> n;
vector<int> A(n), B(n), C(n + 1), D(n + 1);
rep(i, n) {
int a;
cin >> a;
A[i] = a;
C[a]++;
}
rep(i, n) {
int b;
... | ### Prompt
In cpp, your task is to solve the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorder... |
#include <iostream>
using namespace std;
#define rep(i,n) for(int i=0;i<(n);i++)
signed main(){
int n; cin >> n;
int a[n],b[n];
rep(i,n) cin >> a[i];
rep(i,n) cin >> b[n-1-i];
int x=0,y=n-1;
rep(i,n){
if(a[i]==b[i]){
if(x<n&&b[x]!=a[i]&&a[x]!=b[i]) swap(b[i],b[x++]);
... | ### Prompt
Create a solution in cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include<bits/stdc++.h>
using namespace std;
int main()
{
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
map<int,int> mp;
int n ;
cin >> n;
vector<int> A(n), B(n);
for(int i=0; i<n; i++) cin >> A[i];
for(int i=0; i<n; i++) cin >> B[i];
reverse(B.begin(), B.end());
int el = -1;
for(int i=0; i... | ### Prompt
Generate a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reordering... |
#include <bits/stdc++.h>
using namespace std;
#define REP(i, n) for(int i = 0; i < n; i++)
#define REPR(i, n) for(int i = n; i >= 0; i--)
#define FOR(i, m, n) for(int i = m; i < n; i++)
#define ALL(obj) (obj).begin(), (obj).end()
#define INF 1e9
#define LINF 1e18
typedef long long ll;
int main() {
int N; cin >> N... | ### Prompt
In cpp, your task is to solve the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorder... |
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 3e5+10;
const int mod = 1e9+7;
int a[N];
int b[N];
int main() {
int n;
cin>>n;
for(int i=1;i<=n;i++) {
cin>>a[i];
}
for(int i=1;i<=n;i++) {
cin>>b[i];
}
reverse(b+1,b+1+n);
vector<int>p,q;
int val=0,cnt=0;
for(int i=1;i<=n;i+... | ### Prompt
Please create a solution in CPP to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
using namespace std;
const int maxn=2e5+5;
int a[maxn],b[maxn];
int main(){
int n;
scanf("%d",&n);
for(int i=1;i<=n;++i)scanf("%d",&a[i]);
for(int i=1;i<=n;++i)scanf("%d",&b[i]);
reverse(b+1,b+1+n);
int h1=n,q1=1,mx=-1;
for(int i=1;i<=n;++i){
if(a[i]==b[i]){
... | ### Prompt
Please formulate a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
template<class C>constexpr int sz(const C&c){return int(c.size());}
using ll=long long;constexpr const char nl='\n',sp=' ';
int main() {
// freopen("in.txt", "r", stdin);
// freopen("out.txt", "w", stdout);
// freopen("err.txt", "w", stderr);
ios::sync_with_stdio(... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#import"bits/stdc++.h"
using namespace std;
#define o bool
#define l int
#define v vector<l>
l n;o h(v a,v b){o r=1;for(l i=0;i<n;i++)r&=(a[i]!=b[i]);return r;}void f(o g,v a){cout<<(g?"Yes\n":"No\n");if(g)for(l e:a)cout<<e<<'\n';exit(0);}l main(){cin>>n;v a(n),b(n),c;for(l&e:a)cin>>e;for(l&e:b)cin>>e;c=b;reverse(begin... | ### Prompt
Please formulate a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
//#include<atcoder/all>
using namespace std;
//using namespace atcoder;
int main(){
int N;
cin>>N;
int A[N];
int B[N];
for(int i=0;i<N;i++){
cin>>A[i];
}
for(int i=0;i<N;i++){
cin>>B[i];
}
int j=0;
for(int i=0;i<N;i++){
if(A[i]... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define repit(it, li) for(auto it=li.begin(); it!=li.end(); it++)
using namespace std;
using ll = long long;
using P = pair<int,int>;
int main(){
int n;
cin>>n;
vector<int> a(n), b(n);
rep(i, n) cin>>a[i];
rep(i, n) cin>>b[i];
map<int, int>... | ### Prompt
In Cpp, your task is to solve the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorder... |
#include <bits/stdc++.h>
using namespace std;
#define ep emplace_back
int main(){
int n;
scanf("%d", &n);
int a[n], b[n], x = -1, c = 0, p = 0;
for (int i = 0; i < n; i++) scanf("%d", &a[i]);
for (int i = 0; i < n; i++) scanf("%d", &b[i]);
reverse(b, b + n);
for (int i = 0; i < n; i++) if (a[i] == b[i]) x = a[i]... | ### Prompt
Please create a solution in CPP to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<stdio.h>
void swap(int&x,int&y){int t=x;x=y;y=t;}
const int Maxn=200010;
int n,a[Maxn],b[Maxn],c[Maxn],d[Maxn],ld=0;
int main()
{
scanf("%d",&n);
for(int i=1;i<=n;i++)scanf("%d",&a[i]),c[a[i]]++;
for(int i=1;i<=n;i++)scanf("%d",&b[i]),c[b[i]]++;
for(int i=1;i<=n;i++)if(c[i]>n)return puts("No"),0;
puts("Ye... | ### Prompt
Please formulate a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
#define maxn 200086
using namespace std;
int n;
int a[maxn], b[maxn];
int main(){
scanf("%d", &n);
for(int i = 1;i <= n;i++) scanf("%d", &a[i]);
for(int i = 1;i <= n;i++) scanf("%d", &b[i]);
reverse(b + 1, b + 1 + n);
int l = n, r = 1;
for(int i = 1;i <= n;i++){
if(a[i] == b[i]) l = ... | ### Prompt
Generate a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reordering... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN=2e5+5;
int a[MAXN],b[MAXN];
int main()
{
int n;
cin>>n;
for(int i=1;i<=n;++i)
cin>>a[i];
for(int i=1;i<=n;++i)
cin>>b[i];
reverse(b+1,b+n+1);
//for(int i=1;i<=n;++i)
// cout<<b[i]<<" ";... | ### Prompt
Please create a solution in cpp to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define ld long double
#define pb push_back
#define mo 1000000007
#define inf 1e18
#define rep(i, s, n) for (ll i = s; i < n; i = i + 1)
#define rrep(i,s,n) for(ll i=s;i>=n;i--)
ll mod(ll n) { return (n % (ll)mo + (ll)mo)%(ll)mo;}
int main(){
ll ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include<bits/stdc++.h>
using namespace std;
#define ll long long
int main()
{
int n; cin>>n;
vector<ll>a(n),b(n);
for(int i=0;i<n;i++)cin>>a[i];
for(int i=0;i<n;i++)cin>>b[i];
reverse(b.begin(),b.end());
int i=0,j=n-1;
bool c=true;
// 1 1 2 3
// 3 3 2 1
for(int r=0;r<n;r++)
{
if(a[r]==b[r])
{
if(a[... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include <bits/stdc++.h>
using namespace std;
int main(){
int N;
cin >> N;
vector<int> A(N),B(N);
for(auto &i:A)cin >> i;
for(auto &i:B)cin >> i;
for(auto &i:A)i--;
for(auto &i:B)i--;
vector<int> Acount(N,0),Bcount(N,0);
for(auto &i:A)Acount[i]++;
for(auto &i:B)Bcount[i]++;
int maxsum=0,maxi;
for(int i... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <algorithm>
#include <iostream>
using namespace std;
int main() {
int n; cin >> n;
int a[n], b[n];
for (int i = 0; i < n; i++) cin >> a[i];
for (int i = n-1; i >= 0; i--) cin >> b[i];
int dst = 0;
for (int i = 0; i < n; i++) {
if (a[i] != b[i]) continue;
while (dst < n &... | ### Prompt
In cpp, your task is to solve the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorder... |
#pragma GCC optimize ("O3")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse4")
#include"bits/stdc++.h"
using namespace std;
typedef long long ll;
#define int ll
#define all(x) x.begin(), x.end()
#define trav(i,a) for(auto &i:a)
inline int in(){int x;scanf("%lld",&x);return x;}
int32_t main()
{
int n=in()... | ### Prompt
In cpp, your task is to solve the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorder... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
int a[maxn], b[maxn];
int main(){
int n;
cin >> n;
for(int i = 1; i <= n; i ++) cin >> a[i];
for(int i = 1; i <= n; i ++) cin >> b[n-i+1];
int ok = 0;
for(int i = 1; i <= n; i ++){
if(a[i] != b[i]) continue;
... | ### Prompt
Create a solution in CPP for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include <cstdio>
const int N=200005;
int n,a[N],b[N];
int main()
{
scanf("%d",&n);
for(int i=1;i<=n;i++)scanf("%d",a+i);
for(int i=0;i<n;i++)scanf("%d",b+n-i);
bool success=true;
for(int i=1,j,t;i<=n&&success;i++)
if(a[i]==b[i])
{
for(int k=1;k<=n&&a[i]==b[i];k++)
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<bits/stdc++.h>
using namespace std;
int n, a[200005], b[200005];
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
// freopen("input.txt","r",stdin);
// freopen("output.txt","w",stdout);
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
for (int i = 0; i... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include <bits/stdc++.h>
using namespace std;
long long int cnt[200005];
long long int cnt2[200005];
int main(void)
{
cin.tie(0);
ios::sync_with_stdio(false);
int n,t;
vector <int> a,b;
cin >> n;
for(int i=0;i<n;i++)
{
cin >> t;
a.push_back(t);
cnt[t]++;
}
for(int i=0;i<n;i++)
{
cin >> t;
b.p... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<bits/stdc++.h>
using namespace std;
int a[200050],b[200050],n;
int main()
{
scanf("%d",&n);
for(int i=1;i<=n;i++) scanf("%d",&a[i]);
for(int i=1;i<=n;i++) scanf("%d",&b[i]);
reverse(b+1,b+1+n);
vector<int> p,q;
int val=0,cnt=0;
for(int i=1;i<=n;i++)
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin>>n;
vector<int> v1(n);
vector<int> v2(n);
for(int i=0;i<n;i++){
cin>>v1[i];
}
for(int i=0;i<n;i++){
cin>>v2[i];
}
reverse(v2.begin(),v2.end());
int c=-1;
int l=0;
int r=0;
for(int i=... | ### Prompt
Develop a solution in Cpp to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
int n, a[200000], b[200000];
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n;
for(int i = 0; i < n; i++) cin >> a[i];
for(int i = 0; i < n; i++) cin >> b[i];
reverse(b, b + n);
int l = -1, r = -1;
for(int i = 0; i < n; i++)
if(a[i] == b[i])... | ### Prompt
Develop a solution in CPP to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define N 200010
int n,a[N],b[N],c[N],d[N];
int main(){
cin>>n;
rep(i,n)cin>>a[i];
rep(i,n)cin>>b[i];
rep(i,n+1)c[i]=d[i]=0;
rep(i,n)c[a[i]]++,d[b[i]]++;
rep(i,n+1){
if(c[i]+d[i]>n){
cout<<"No\n";
retur... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<bits/stdc++.h>
using namespace std;
const int N = 2e5 + 5;
int n,a[N],b[N],pos,pos2;
vector<int> v;
inline bool cmp(const int &i,const int &j) {
return i > j;
}
signed main() {
scanf("%lld",&n);
for(int i = 1;i <= n;++i)
scanf("%d",a+i);
for(int i = 1;i <= n;++i)
scanf("%d",b+i);
sort(b+1,b+n+1,cmp);
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<bits/stdc++.h>
using namespace std;
const int maxn=2*1e5+6;
int n, a[maxn], b[maxn];
int l=-1, r=-2, c;
int main(){
cin >> n;
for (int i=0;i<n;i++) cin >> a[i];
for (int i=0;i<n;i++) cin >> b[i];
reverse(b,b+n);
for (int i=0;i<n;i++){
if (a[i]==b[i]){
if (l==-1) l=i;
r=i;
c=a[i];
}
}
int ... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
//#include <bits/stdc++.h>
#include <iostream>
#include <algorithm>
#include <queue>
using namespace std;
typedef long long ll;
ll n,m,ans;
ll a[200005],b[200005];
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
cin>>n;
for(int i=1;i<=n;i++){
cin>>a[i];
}
for(int i=1;i<=n;i++){
ci... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<iostream>
#include<bits/stdc++.h>
using namespace std;
#define IOS ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define deb(x) cout << #x << " " << x << endl;
typedef long long int ll;
int main() {
IOS
int n;
cin >> n;
int a[n], b[n];
for (int i = 0; i < n; i++)
cin >> a[i];
for (int ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); i++)
using namespace std;
int main() {
int n; cin >> n;
vector<int> a(n), b(n);
rep(i,n) cin >> a[i];
rep(i,n) cin >> b[n- 1 - i];
int save = 0;
vector<int> ch1, ch2;
rep(i,n) if (a[i] == b[i]) { save = a[i]; ch1.push_bac... | ### Prompt
Develop a solution in CPP to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<cstdio>
#include<algorithm>
using namespace std;
int n,a[200005],c[200005],b[200005],left,right,same;
int main() {
scanf("%d",&n);
for(int i=1;i<=n;++i) scanf("%d",&a[i]);
for(int i=1;i<=n;++i) scanf("%d",&c[i]);
for(int i=1;i<=n;++i) b[i]=c[n-i+1];
for(int i=1;i<=n;++i) if(a[i]==b[i]) {
if(!left) left=... | ### Prompt
Your task is to create a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include <iostream>
#include <algorithm>
using namespace std;
const int maxn=2e5+10;
int a[maxn],b[maxn];//,c[maxn];
int main()
{
ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int n;cin>>n;
for(int i=1; i<=n; i++)cin>>a[i];
for(int i=1; i<=n; i++)cin>>b[i];
int r=n,l;
reverse(b+1,b+1+n);//for(... | ### Prompt
Create a solution in cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include <bits/stdc++.h>
using namespace std;
template <typename T> bool chmax(T &u, const T z) { if (u < z) {u = z; return true;} else return false; }
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
int main() {
int n;
cin>>n;
vector<int> a(n), b(n);
rep(i,n)cin>>a[i];
rep(i,n)cin>>b[i];
sort(b.rbegi... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<stdio.h>
#include<string.h>
#include<math.h>
#include<map>
#include<stack>
#include<set>
#include<queue>
#include<vector>
#include<stdlib.h>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<cstdio>
#include<cstdlib>
#define inf 0x3f3f3f3f
using namespace std;
typedef long long ll;
const int ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 1;
int n, a[N], b[N];
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i];
for (int i = 0; i < n; i++) cin >> b[i];
int j = 0, bef = -1;
for (int i = 0; i < n; i+... | ### Prompt
Your task is to create a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
int a[maxn], b[maxn];
int main(){
int n;
cin >> n;
for(int i = 1; i <= n; i ++) cin >> a[i];
for(int i = 1; i <= n; i ++) cin >> b[n + 1 - i];
//reverse(b + 1, b + n + 1);
int ok = 0;
for(int i = 1; i <= n; i ++){
... | ### Prompt
Please formulate a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
#define int long long
int32_t main()
{
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int n; cin >> n;
vector<int> a(n), b(n), cnt(n + 1, 0);
for(int i = 0; i < n; i ++) {
cin >> a[i];
cnt[a[i]] ++;
}
for(int i = 0; i < n; i ++) {
ci... | ### Prompt
Please formulate a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<iostream>
#include<algorithm>
using namespace std;
const int N = 2*1e5;
int n,x[N],y[N];
bool cmp(int a,int b){
return a>b;
}
int main(){
scanf("%d",&n);
for(int i=0;i<n;i++){
scanf("%d",&x[i]);
}
for(int i=0;i<n;i++){
scanf("%d",&y[i]);
}
sort(y,y+n,cmp);
int flag=0;
for(int i=0;i<n;i++){
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include <bits/stdc++.h>
#define rep(i,n) for(int i=0; i<n; i++)
#define PI 3.14159265359
#define INF 1000100100000000000
#define MOD 1000000007
#define all(x) (x).begin(),(x).end()
typedef long long ll;
#define P pair<int, int>
#define PP pair<P,P>
#define T tuple<int,int,int>
using namespace std;
int main(){
in... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<bits/stdc++.h>
using namespace std;
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n;
cin >> n;
vector<int> a(n), b(n);
for(int &i : a){
cin >> i;
}
for(int &i : b){
cin >> i;
}
reverse(b.begin(), b.end());
int c = -1;
for(int i... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
using namespace std;
const int N = 200005;
int n;
int a[N], b[N];
int main() {
scanf("%d", &n);
for(int i = 0; i < n; i++) scanf("%d", a + i);
for(int i = 0; i < n; i++) scanf("%d", b + i);
reverse(b, b + n);
int l = 0;
while(l < n and a[l] != b[l]) l++;
if(l < n) {
int r = l;
... | ### Prompt
Create a solution in cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include<bits/stdc++.h>
using namespace std;
const int N=200010;
int a[N],b[N],n;
int main(){
scanf("%d",&n);
int x;
for(int i=1;i<=n;i++) scanf("%d",&a[i]);
for(int i=1;i<=n;i++) scanf("%d",&b[i]);
reverse(b+1,b+1+n);
int l=0,r=0,t=0,L=0,R=0;
for(int i=1;i<=n;i++) if(a[i]==b[i]) {
if(!l) l=i,r=i,t=a[i];
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<bits/stdc++.h>
#define PI 3.141592653589793238462
using namespace std;
typedef long long ll;
typedef long double db;
ll a[200005],b[200005],p[200005];
int main(){
ll n;cin>>n;
for(ll i=1;i<=n;i++){
cin>>a[i];p[a[i]]++;
}
for(ll i=1;i<=n;i++){
cin>>b[i];p[b[i]]++;
}
for(i... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include<bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;i++)
#define INF 1000000007
using namespace std;
int main(){
int n;
cin >> n;
vector<int> a(n),b(n),asum(n+1,0),bsum(n+1,0);
rep(i,n){
cin >> a[i];
asum[a[i]]++;
}
rep(i,n){
cin >> b[i];
bsum[b[i]]++;
}
rep(i,n+1){
if(asum[i] ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<bits/stdc++.h>
using namespace std;
int n,a[200010],b[200010],cnt[200010],L,R,l,r;
inline int read()
{
int x=0,w=0;char ch=0;
while(!isdigit(ch)){w|=ch=='-';ch=getchar();}
while(isdigit(ch)){x=(x<<1)+(x<<3)+(ch^48);ch=getchar();}
return w?-x:x;
}
int main()
{
n=read();
for(int i=1;i<=n;i++)cnt[a[i]=read(... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main() {
int n;
cin >> n;
vector<int> a(n), b(n), counter(n+1, 0);
vector<int> c(n+1, 0), d(n+1, 0);
for (int i = 0; i < n; ++i) {
cin >> a[i];
counter[a[i]]++;
c[a[i]]++;
}
for (int i = 0; i < n; +... | ### Prompt
Create a solution in cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include<iostream>
#include<algorithm>
#include<cmath>
#include<cstring>
#include<stdio.h>
#include<map>
#include<queue>
#include<vector>
using namespace std;
const int maxn=1e6;
typedef long long ll;
ll a[maxn],b[maxn];
int main(){
int n;cin>>n;
for(int i=0;i<n;i++)
cin>>a[i];
for(int i=0;i<n;i++)
cin>>b[i];... | ### Prompt
Create a solution in CPP for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
#define FOR(i,l,r) for(i=l;i<r;i++)
#define REP(i,n) FOR(i,0,n)
#define ALL(x) x.begin(),x.end()
#define P pair<ll,ll>
#define F first
#define S second
signed main(){
ll N,i,j=0;cin>>N;ll A[N],B[N],X[N],Y[N];
REP(i,N)cin>>A[i];REP(i,N)cin>>B[i]... | ### Prompt
Develop a solution in CPP to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include<bits/stdc++.h>
using namespace std;
const int N=2e5+10;
typedef long long ll;
int a[N],b[N],vis1[N],vis2[N],c[N];
int n,f;
int main(){
scanf("%d",&n);
for(int i=1;i<=n;i++)
{
scanf("%d",&a[i]);
}
for(int i=1;i<=n;i++)
{
scanf("%d",&b[i]);
}
reverse(b+1,b+1+n);
vector<int>p... | ### Prompt
Develop a solution in Cpp to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
vector<int> a(n), b(n);
for (auto& e : a) cin >> e;
for (auto& e : b) cin >> e;
for (int k = 0; k < 2; k++) {
for (int i = 0, j = 1; i < n; i++, j = max(j, i + 1)) {
if (a[i] != b[i]) continue;
while (j < n && a[i]... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<bits/stdc++.h>
using namespace std;
#define dlwlrma ios::sync_with_stdio(0); cin.tie(0);
int n;
int main(){
dlwlrma
cin >> n;
vector<int>a(n),b(n);
for(int &next : a)
cin >> next;
for(int &next : b)
cin >> next;
reverse(b.begin(),b.end());
vector<int>same,dif;
in... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < n; i++)
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
const int MAX_N = 200005;
int A[MAX_N],B[MAX_N],C[MAX_N],D[MAX_N];
vector<P> v,v2;
int main()
{
int N;
cin >> N;
rep(i,N)
{
cin >> A[i];
C[A[i]]++;
}
rep(i,N)
{
cin >> B... | ### Prompt
Create a solution in Cpp for the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderi... |
#include "bits/stdc++.h"
using namespace std;
#include "string"
#define int long long
#define pi pair <int, int>
#define ff first
#define ss second
#define boost ios::sync_with_stdio(false);cin.tie(nullptr)
#define endl '\n'
int32_t main() {
boost;
int n;
cin >> n;
vector < int > a(n), b(n);
for(int &i : a)
cin... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include <bits/stdc++.h>
using namespace std;
int a[200005], b[200005];
int main() {
int n;
scanf("%d", &n);
for (int i = 0; i < n; i++) scanf("%d", &a[i]);
for (int i = 0; i < n; i++) scanf("%d", &b[i]);
reverse(b, b + n);
int l = 0;
int r = n - 1;
for (int i = 0; i < n; i++) {
... | ### Prompt
Your task is to create a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of ... |
#include <bits/stdc++.h>
using namespace std;
#define ll long long int
#define maxn 200005
int main(){
int n;
cin>>n;
vector<int> a(n),b(n);
for(int i=0;i<n;i++)
cin>>a[i];
for(int i=0;i<n;i++)
cin>>b[i];
reverse(b.begin(),b.end());
int el=-1;
for(int i=0;i<n;i++){
if(a[i]==b[i]){
el=a[i]... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
int main(){
int n;
cin >> n;
vector<int> a(n),b(n);
for(int i=0;i<n;i++)cin>>a[i];
for(int i=0;i<n;i++)cin>>b[i];
vector<int> s(n+1),t(n+1);
for(int i=0;i<n;i++){
s[a[i]]++;
t[b[i]]++;
}
f... | ### Prompt
Develop a solution in Cpp to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <bits/stdc++.h>
using namespace std;
long long mod = 1000000007;
int main() {
long long n, c[200005], d[200005], x;
cin >> n;
long long a[n], b[n];
for (long long i = 0; i < 200005; i++)
{
c[i] = 0;
d[i] = 0;
}
for (long long i = 0; i < n; i++)
{
cin >> ... | ### Prompt
Please create a solution in cpp to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the re... |
#include <iostream>
#include <string>
#include <vector>
#include <set>
#include <map>
#include <cmath>
#define rep(i, n) for(int i = 0; i < (n); i++)
using namespace std;
using P = pair<int, int>;
long mod = (long) 1e9 + 7;
int main(){
int n;
cin >> n;
vector<int> a(n,0), b(n,0), c(n+1,0), d(n+1,0);
... | ### Prompt
Construct a cpp code solution to the problem outlined:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reord... |
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define N 200010
int n,a[N],b[N],c[N],d[N];
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
cin>>n;
rep(i,n... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define repit(it, li) for(auto it=li.begin(); it!=li.end(); it++)
using namespace std;
using ll = long long;
using P = pair<int,int>;
int main(){
int n;
cin>>n;
vector<int> a(n), b(n);
rep(i, n) cin>>a[i];
rep(i, n) cin>>b[i];
vector<bool> ... | ### Prompt
Generate a CPP solution to the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reordering... |
#include <bits/stdc++.h>
using namespace std;
int main(){
int N;
cin >> N;
vector<int> A(N), B(N);
for(int i=0; i<N; i++) cin >> A[i];
for(int i=0; i<N; i++) cin >> B[i];
reverse(B.begin(), B.end());
int dup = -1;
vector<int> dup_idx, avail_idx;
for(int i=0; i<N; i++) if(A[i] =... | ### Prompt
In CPP, your task is to solve the following problem:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorder... |
//#include <bits/stdc++.h>
#include <iostream>
#include <algorithm>
#include <queue>
using namespace std;
typedef long long ll;
ll n,m,ans;
ll a[200005],b[200005];
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
cin>>n;
for(int i=1;i<=n;i++){
cin>>a[i];
}
for(int i=1;i<=n;i++){
ci... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any... |
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