output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
string s;
int main(){
cin>>s;
int len=s.size();
for(int i=0;i<len-1;i++){
if(s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
}
for(int i=0;i<len-2;i++){
if(s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
... | ### Prompt
Generate a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string s... |
#include<cstdio>
#include<cstring>
using namespace std;
#define MAXN 100005
char s[MAXN];
int main()
{
scanf("%s",s);
int len=strlen(s);
for(int i=0;i<=len-2;i++)
{
if(s[i]==s[i+2])
{
printf("%d %d\n",i+1,i+3);
return 0;
}
if(s[i]==s[i+1])
{
printf("%d %d\n",i+1,i+2);
return 0;
}
}
printf(... | ### Prompt
In CPP, your task is to solve the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a strin... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s; cin >> s;
int n = s.size();
for(int i = 0; i < n; i++) {
if(i<n-1 && s[i] == s[i+1]) {
cout << i+1 << " " << i+2;
return 0;
}
if(i<n-2 && s[i] == s[i+2]) {
cout << i+1 << " " << i+3;
return 0;
}
}
cout << "-1 -1";
} | ### Prompt
Please formulate a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
#define for_(i,a,b) for(int i=(a);i<(b);++i)
int main() {
string S;
cin >> S;
int n = S.size();
if (n == 2 && S[0] == S[1]) {
puts("1 2");
exit(0);
}
for_(i,0,n-2) {
if (S[i] == S[i+1] || S[i] == S[i+2]) {
cout << i+1 << " " << i + 3 << endl;
exit(0)... | ### Prompt
Please formulate a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
char s[100100];
int main(){
scanf("%s",s+1);
int n=strlen(s+1);
for(int i=1;i<=n;i++){
if(s[i-1]==s[i]){
cout<<i-1<<" "<<i;
return 0;
}
else if(s[i]==s[i-2]){
cout<<i-2<<" "<<i;
return 0;
}
else if(i==n){
cout<<"-1 -1... | ### Prompt
Develop a solution in cpp to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
string s;
int main() {
cin >> s;
for(int i = 1; i<s.size(); i++)
if(s[i] == s[i - 1]) {
cout << i << " " << i + 1 << endl;
return 0;
}
for(int i = 2; i < s.size(); i++)
if(s[i] == s[i - 2]) {
cout << i - 1 << " " << i + 1 << endl;
return 0;
}
cout << ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <bits/stdc++.h>
using namespace std;
#define ll long long
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
string s;
cin >> s;
for (int i = 0; i + 1 < s.size(); i++) {
if (s[i] == s[i + 1]) {
cout << i + 1 << " " << i + 2 << endl;
return 0;
}
if (i && s[i - 1] == s[i + 1]) {
cout << ... | ### Prompt
Please create a solution in Cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include "bits/stdc++.h"
using namespace std;
int main() {
string S;
cin >> S;
for (int i = 0; i < S.size() - 1; i++) {
if (S[i] == S[i + 1]) {
cout << i + 1 << " " << i + 2;
goto END;
}
}
for (int i = 0; i < S.size() - 2; i++) {
if (S[i] == S[i + 2]) {
cout << i + 1 << " " << i + 3;
goto END;
... | ### Prompt
Develop a solution in cpp to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<cstdio>
#include<cstring>
const int N=1e5+50;
char s[N];
int len,x,y,ans;
int main(){
scanf("%s",s);
len=strlen(s);
for(int i=0;i<len;i++){
if(s[i]==s[i+1]){printf("%d %d\n",i+1,i+2);return 0;}
else if(s[i]==s[i+2]){printf("%d %d\n",i+1,i+3);return 0;}
}
printf("-1 -1\n");
} | ### Prompt
Please formulate a CPP solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
int n=s.length();
for(int i=0;i<n-1;i++){
if(s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
if(i!=n-3 && s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
cout<<-1<<" "<<-1<<e... | ### Prompt
Please create a solution in cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<iostream>
#include<cstring>
using namespace std;
int main(){
string s;
cin>>s;
int l=s.size();
int i=0;
for(i=0;i<l;i++){
if(s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;
return 0;
}else if(s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
cout<<"-1"<<" "<<"-1"<<endl;
return 0;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a str... |
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
string s;
cin>>s;
for(int i=0;i<s.size()-1;i++){
if(i!=s.size()-2){
if(s[i]==s[i+2]){
cout<<i+1<<' '<<i+3<<endl;
return 0;
}
}
if(s[i]==s[i+1]){
cout<<i+1<<' '<<i+2<<endl;
return 0;
}
}
cout<<-1<<' '<<-1<<e... | ### Prompt
Please create a solution in Cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
cin.tie(0);
ios::sync_with_stdio(false);
string s;cin>>s;
int len=s.length();
int l=-1,r=-1;
//bool flag=false;
for(int i=0;i<len-1;i++){
if(s[i]==s[i+1]) {l=i+1;r=l+1;}
}
for(int i=0;i<len-2;i++){
if(s[i]==... | ### Prompt
Develop a solution in cpp to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
using namespace std;
char s[100005];
int main()
{
scanf("%s",s);
int len=strlen(s);
if(len==2)
{
if(s[0]==s[1]) printf("1 2\n");
else printf("-1 -1\n");
return 0;
}
for(int i=0;i<len-2;i++)
{
if(s[i]==s[i+1]||s[i]==s[i+2])
{
pri... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are gi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int N = s.size();
for (int i = 0; i < N-1;i++){
if(s[i]==s[i+1]) {
cout << i +1<< ' '<<i + 2 << endl;
return 0;
}
}
for (int i = 0; i < N - 2;i++){
if(s[i]==s[i+2]){
cout << i+1 << ' '<<i + 3 << end... | ### Prompt
Develop a solution in Cpp to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
int main(){
string s;
cin>>s;
for(int i=0;i<s.size()-1;i++){
if(s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
}
for(int i=0;i<s.size()-2;i++){
if(s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
cout<<-1<<" "<<-1<<endl;
return 0;
} | ### Prompt
In CPP, your task is to solve the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a strin... |
#include <bits/stdc++.h>
using namespace std;
char s[100010];
int main()
{
int i,l,ch,left=-1,right=-1;
scanf("%s",s+1);
l=strlen(s+1);
for(i=1;i<l;i++)
if(s[i]==s[i+1]){
left=i;right=i+1;
break;
}
if(left==-1)
for(i=1;i<l-1;i++)
if(s[i]==s[i+2]){
left=i;right=i+2;
break;
}
printf("%d %d\n",... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are gi... |
#include <bits/stdc++.h>
using namespace std;
char s[500003];
int main()
{
scanf("%s",s);
int a;
a=strlen(s);
for(int i=0;i<a-1;i++)
{
if(s[i]==s[i+1]){cout<<i+1<<" "<<i+2<<endl;return 0;}
else if(i+2<a&&s[i]==s[i+2]){cout<<i+1<<" "<<i+3<<endl;return 0;}
//else if(i+3<a&&s[i]==s[i+3]... | ### Prompt
Please formulate a CPP solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
string s;
cin >> s;
bool isE=false;
for(int i = 1;i < s.size();i ++){
if(s[i]==s[i-1]) {cout << i << " " << i+1 << endl;isE=1;break;}
if(i-1&&s[i]==s[i-2]) {cout << i-1 << " " << i+1 << endl;isE=1;break;}
... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <iostream>
using namespace std;
int main(){
string s;
cin >> s;
//aa axa
for(char c = 'a'; c <= 'z'; c++){
for(size_t i = 0; i < s.size() - 1; i++){
if(s[i] == s[i + 1]){
cout << i + 1 << ' ' << i + 2 << endl;
return 0;
}else if(i + 2 < s.size() && s[i] == s[i + 2]){
cout << i + 1 << '... | ### Prompt
Please create a solution in Cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin>>s;
int n = s.length();
for (int i=0; i<n-1; i++) {
if (s[i] == s[i+1]) {
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
if (i+2 < n && s[i] == s[i+2]) {
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
cout<<"... | ### Prompt
Please create a solution in CPP to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int n = s.size();
for (int i = 0; i < n - 1; i++) {
if (s[i] == s[i + 1]) {
cout << i + 1 << " " << i + 2 << endl;
return 0;
}
}
for (int i = 0; i < n - 2; i++) {
if (s[i] == s[i + 2]) {
cout << i + 1 << " " << i + 3 ... | ### Prompt
Your task is to create a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are gi... |
#include <bits/stdc++.h>
using namespace std;
char s[100005];
int f[27];
int main () {
scanf("%s", s);
int n=strlen(s);
for (int i=0; i<n-1; i++) {
if (s[i]==s[i+1]) {
printf("%d %d\n", i+1, i+2);
return 0;
}
if (s[i]==s[i+2]) {
printf("%d %d\n", i+1, i+3);
return 0;
}
}
printf("-1 -1\n");
ret... | ### Prompt
Develop a solution in CPP to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
string a;
int main()
{
cin>>a;
for(int i=1;i<a.size();i++)
if(a[i]==a[i-1])
{
cout<<i<<" "<<i+1<<endl;
return 0;
}
for(int i=2;i<a.size();i++)
if(a[i]==a[i-2])
{
cout<<i-1<<" "<<i+1<<endl;
return 0;
}
cout<<-1<<" "<<-1<<endl;
} | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string S;
cin >> S;
for (int a = 0; a + 1 < S.length(); a++) {
if (S[a] == S[a + 1]) {
printf("%d %d\n", a + 1, a + 2);
return 0;
}
}
for (int a = 0; a + 2 < S.length(); a++) {
if (S[a] == S[a + 2]) {
printf("%d %d\n"... | ### Prompt
Your task is to create a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are gi... |
#include <iostream>
#include <algorithm>
#include <string>
using namespace std;
int main() {
int a, b, len;
string s;
cin >> s; len = s.length();
a = b = -2;
for(int i=1;i<len;i++) {
if(s[i-1] == s[i]) {
a = i-1; b = i;
break;
}
if(i >= 2 && s[i-2] == s[i]) {
a = i - 2; b = i;
break;
}
}
a+... | ### Prompt
Develop a solution in cpp to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
#define ll long long
char a[100010];
int main(){
cin>>a+1;
int n=strlen(a+1);
for(int i=1;i<n;i++){
if(a[i]==a[i+1]) return cout<<i<<' '<<i+1<<'\n',0;
}
for(int i=1;i+2<=n;i++){
if(a[i]==a[i+2]) return cout<<i<<' '<<i+2<<'\n',0;
}
cout<<-1<<' '<<-1<<'\n';
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
typedef long long ll;
typedef pair<ll,ll> P;
signed main(){
string s;
cin >> s;
for(int i=0;i<s.size()-1;i++){
if(s[i]==s[i+1]){
cout << i+1<<" "<<i+2<<endl;
return 0;
}else if(i!=0&&s[i-1]==s[i+1]){
cout << i<<... | ### Prompt
In cpp, your task is to solve the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a strin... |
#include<cstdio>
#include<cstring>
#define MAXN 200000
char str[MAXN+5];
int main(){
scanf("%s",str+1);
int len=strlen(str+1);
for(int i=1;i<=len;i++){
if(str[i]==str[i+1]){
printf("%d %d",i,i+1);
return 0;
}
if(str[i]==str[i+2]){
printf("%d %d",... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin >> s;
for (int i = 0; i < s.length(); i++)
{
if (i + 1 < s.length() && s[i] == s[i+1])
{
cout << i + 1 << ' ' << i + 2 << '\n';
return 0;
}
if (i + 2 < s.length() && s[i] == s[i+2])
{
cout << i + 1 << ' ' << i + 3 << '\n';... | ### Prompt
Create a solution in Cpp for the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string... |
#include <iostream>
#include <cstdio>
using namespace std;
int n;
string a;
int main()
{
int i;
cin >> a;
a = ' ' + a;
for (i = 1; i < a.size() - 1; i++) {
if (a[i] == a[i + 1]) {
printf("%d %d", i, i + 1);
return 0;
}
if (i + 2 < a.size() && a[i] == a[i + 2]) {
printf("%d %d", i, i + 2);
return ... | ### Prompt
Create a solution in cpp for the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string... |
#include<bits/stdc++.h>
using namespace std;
const int maxn=1e5+7;
char s[maxn];
int main()
{
scanf("%s",s+1);
int n=strlen(s+1);
for(int i=1;i<=n;i++)
{
if(i<n&&s[i]==s[i+1])
{
printf("%d %d\n",i,i+1);
return 0;
}
if(i<n-1&&s[i]==s[i+2])
{
printf("%d %d\n",i,i+2);
return 0;
}
}
printf("-1... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are gi... |
#include <bits/stdc++.h>
using namespace std;
#define for_(i,a,b) for(int i=(a);i<(b);++i)
int main() {
string S;
cin >> S;
int n = S.size();
for_(x,1,3) for_(i,0,n-x) {
if (S[i] == S[i + x]) {
cout << i+1 << " " << i+x+1 << endl;
exit(0);
}
}
puts("-1 -1");
} | ### Prompt
Construct a CPP code solution to the problem outlined:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a str... |
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
string s;
cin>>s;
int i=0,j=0;
for(int l=0;l<s.length()-1;l++)
{
if(s[l]==s[l+1])
{
i=l+1;
j=l+2;
}
}
for(int p=0;p<s.length()-2;p++)
{
if(s[p]==s[p+2])
{
i=p+1;
j=p+3;
}
}
if(i==0 && j==0)
{
i=-1;
j=-1;
}
co... | ### Prompt
Please create a solution in cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <iostream>
using namespace std;
int main() {
string s;
cin >> s;
int N = s.length();
for (int i = 0; i < N - 1; i++) {
if (s[i] == s[i + 1]) {
cout << i + 1 << " " << i + 2 << endl;
return 0;
}
if (i + 2 < N && s[i] == s[i + 2]) {
cout << i + 1 << " " << i + 3 << endl;
return 0;
}
}
c... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <cstdio>
char s[100100];
int main() {
scanf("%s", s+1);
for(int i = 1; s[i]; i ++ ) if(s[i] == s[i+1] || s[i] == s[i+2]) return printf("%d %d\n", i, s[i+2]?i+2:i+1), 0;
puts("-1 -1");
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
signed main() {
string s;
cin >> s;
s += '?';
for (int i = 1; i < s.length()-1; i++) {
if (s[i-1] == s[i]) {
cout << i << ' ' << i+1;
return 0;
}
if (s[i-1] == s[i+1]) {
cout << i << ' ' << i+2;
re... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <bits/stdc++.h>
using namespace std;
int main(void) {
string s;
cin >> s;
int sz = s.size();
int a = -1, b = -1;
for (int i = 1; i < sz; i++) {
if (s[i] == s[i - 1]) {
a = i, b = i + 1;
} else if (i + 1 < sz && s[i - 1] == s[i + 1]) {
a = i, b = i + 2;
}
}
cout << a <<... | ### Prompt
Please formulate a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
char s[100020];
int main() {
scanf("%s", s);
for (int i = 0; s[i]; i++) {
if (s[i] == s[i + 1]) {
printf("%d %d\n", i + 1, i + 2);
return 0;
}
if (s[i] == s[i + 2]) {
printf("%d %d\n", i + 1, i + 3);
return 0;
}
}
printf("-1 -1\n");
return 0;
} | ### Prompt
Create a solution in CPP for the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string... |
#include<iostream>
using namespace std;
int main()
{
string s;
cin>>s;
for(int i=1;i<s.length();i++)
{
if(s[i]==s[i-1])
{
cout<<i<<" "<<i+1<<endl;
return 0;
}
}
for(int i=2;i<=s.length();i++)
{
if(s[i]==s[i-2])
{
cout<<i-1<<" "<<i+1<<endl;
return 0;
}
}
cout<<-1<<" "<<-1<<endl;
return ... | ### Prompt
Create a solution in Cpp for the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string... |
#include<cstdio>
#include<cstring>
using namespace std;
#define MAXN 1000005
char s[MAXN];
int main()
{
scanf("%s",s);
int len=strlen(s);
for(int i=0;i<=len-1;i++)
{
if(s[i]==s[i+1])
{
printf("%d %d\n",i+1,i+2);
return 0;
}
if(s[i]==s[i+2])
{
printf("%d %d\n",i+1,i+3);
return 0;
}
}
printf... | ### Prompt
Please formulate a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
int main() {
string s;
cin >> s;
ll n = s.size();
for (ll i = 1; i < n; ++i) {
if (s[i - 1] == s[i]) {
cout << i << " " << i + 1 << endl;
return 0;
}
}
for (ll i = 2; i < n; ++i) {
if (s[i - 2] == s[i]) {
cout << i - 1 << " " << i ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include "bits/stdc++.h"
using namespace std;
int main(){
string s;
cin>>s;
for(int i=0;i<s.size()-2;i++){
if(s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
if(s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
if(s[s.size()-2]==s[s.size()-1]){
cout<<s.size()-1<<" "<<s.size()... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include <bits/stdc++.h>
using namespace std;
int main(void){
string s;
cin>>s;
for(int i=0;i<s.size()-1;i++){
if(s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
}
for(int i=0;i<s.size()-2;i++){
if(s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<... | ### Prompt
Please create a solution in CPP to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <iostream>
using namespace std;
int main(){
string s;
cin >> s;
if(s.size()==2&&s[0]==s[1]){
cout << "1 2";
return 0;
}
for(int i = 0;i < s.size() - 2;i++){
int j = i;
if(s[j]==s[j+1]||s[j]==s[j+2]||s[j+1]==s[j+2]){
cout << j+1 << " " << j+3;
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include<bits/stdc++.h>
using namespace std;
string s;
int main() {
cin >> s;
for(int i = 1; i<s.size(); i++)
if(s[i] == s[i - 1]) {
cout << i << " " << i + 1 << endl;
return 0;
}
for(int i = 2; i < s.size(); i++)
if(s[i] == s[i - 2]) {
cout << i - 1 << " " << i + 1 << endl;
return 0;
}
cout << ... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a str... |
#include <bits/stdc++.h>
using namespace std;
string s;
int main() {
cin >> s;
int n = s.length();
for(int i = 0; i + 2 < n; i++) {
if(s[i] == s[i+1] || s[i] == s[i+2]) return cout << i + 1 << " " << i + 3 << endl, 0;
}
if(n >= 2 && (s[n-1] == s[n-2])) return cout << n - 1 << " " << n << e... | ### Prompt
Please formulate a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
int main(){
string s;
cin >> s;
int n=s.size();
for(int i=0;i<n-1;i++){
if(s[i]==s[i+1]){
cout << i+1 << " " << i+2 << endl;
return 0;
}
}
for(int i=0;i<n-2;i++){
if(s[i]==s[i+2]){
cout << i+1 << " " << i+3 << endl;
return 0;
... | ### Prompt
Create a solution in CPP for the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string... |
#include<cstdio>
#include<iostream>
using namespace std;
string s;
int main()
{
cin>>s;
for(int i=1;i<s.size();i++)
if(s[i-1]==s[i])
{
printf("%d %d",i,i+1);
return 0;
}
for(int i=1;i<s.size()-1;i++)
if(s[i-1]==s[i+1])
{
printf("%d %d",i,... | ### Prompt
Construct a cpp code solution to the problem outlined:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a str... |
#include<bits/stdc++.h>
using namespace std;
char s[100100];
int main()
{
scanf("%s",s);
if(strlen(s)==2)
{
if(s[0]==s[1])
{
printf("1 2\n");
return 0;
}
}
else
for(int i=2;s[i];i++)
{
if(s[i]==s[i-1]||s[i]==s[i-2]||s[i-1]==s[i-2])
{
printf("%d %d\n",i-2+1,i+1);
return 0;
}
}
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include<stdio.h>
int main(){
char s[111111];
int i,a=-1,b=-1;
for(i=0;i<111111;i++)
s[i]='\0';
scanf("%s",s);
if(s[0]==s[1]){
a=1;
b=2;
}
for(i=2;s[i]!='\0';i++){
if(s[i]==s[i-1]){
a=i;
b=i+1;
}
if(s[i]==s[i-2]){
a=i-1;
b=i+1;
}
}
printf("%d %d\n",a,b);
return 0;
}
| ### Prompt
In Cpp, your task is to solve the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a strin... |
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
char a[100000+5];
int alen;
int main()
{
scanf("%s",a);
alen=strlen(a);
for(int i=0;i<alen-1;i++)
if(a[i]==a[i+1])
{
printf("%d %d\n",i+1,i+2);
return 0;
}
for(int i=0;i<alen-2;i++)
if(a[i]==a[i+1]||a[i]==a[i+2]||a[i+1]==a[i+2]... | ### Prompt
Construct a CPP code solution to the problem outlined:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a str... |
#include<bits/stdc++.h>
using namespace std;
const int MAXN=100005;
char s[MAXN];
int main(){
scanf("%s",s);
int len=strlen(s);
int a=-1,b=-1;
for(int i=1;i<len;i++){
if(s[i]==s[i-1]){
a=i-1,b=i;
break;
}
}
if(a==-1){
for(int i=2;i<len;i++){
if(s[i]==s[i-2]){
a=i-2,b=i;
break;
}
}
}
... | ### Prompt
In Cpp, your task is to solve the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a strin... |
#include<bits/stdc++.h>
using namespace std;
int main(){
string s;cin>>s;
for(int i=0;i<26;i++){
char a='a'+i;
int c=-10;
for(int j=0;j<s.size();j++){
if(s[j]==a){
if(j-c<=2){
cout<<c+1<<" "<<j+1<<endl;
return 0;
}
else c=j;
}
}
}
cout<<-1<... | ### Prompt
Your task is to create a cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are gi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin>>s;
int n = s.length();
for (int i=0; i<n-1; i++) {
if (s[i] == s[i+1]) {
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
if (i == n-2) {
break;
}
if (s[i] == s[i+2]) {
cout<<i+1<<" "<<i+3<<endl;
... | ### Prompt
Create a solution in Cpp for the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a string... |
#include<bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
for(int i=0;i<s.size()-1;i++)
{
if(s[i]==s[i+1])
{
cout<<i+1<<" "<<i+2<<endl;
return 0;
}
if(i+2<s.size())
{
if(s[i]==s[i+2])
{
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
}
cout<... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include<iostream>
using namespace std;
bool vis[50];
int main()
{
string s;
cin>>s;
for(int i=0;i<s.length();++i){
if(i+1<s.length()&&s[i]==s[i+1]){
cout<<i+1<<" "<<i+2<<endl;return 0;
}
if(i+2<s.length()&&s[i]==s[i+2]){
cout<<i+1<<" "<<i+3<<endl;return 0;
}
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You ar... |
#include<bits/stdc++.h>
using namespace std;
const int N=1e5+10;
char s[N];
int main()
{
scanf("%s",s+1);
int len=strlen(s+1);
if(len==2&&s[1]==s[2]){
printf("1 2\n");
return 0;
}
int l=-1,r=-1;
for(int i=1;i<len-1;i++){
if(s[i]==s[i+1]||s[i]==s[i+2]||s[i+1]==s[i+2]){
... | ### Prompt
Please create a solution in cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include<bits/stdc++.h>
using namespace std;
int main(){
int n;
string s;
cin>>s;
n=s.size();
for(int i=1;i<n;++i){
if(i>1&&s[i-2]==s[i])cout<<i-1<<" "<<i+1,exit(0);
else if(s[i-1]==s[i])cout<<i<<" "<<i+1,exit(0);
}
cout<<"-1 -1";
} | ### Prompt
In cpp, your task is to solve the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a strin... |
#include <iostream>
using namespace std;
int main(){
string s;cin>>s;
if(s.size()==2&&s[0]==s[1]){
cout << 1 << " " << 2 << endl;
return 0;
}
for(int i = 0; s.size() > i+2; i++){
if(s[i]==s[i+1] || s[i]==s[i+2] || s[i+1]==s[i+2]){
cout << i+1 << " " << i+3 << endl;
return 0;
}
}
... | ### Prompt
Please formulate a Cpp solution to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
int main(){
string a;
cin >> a;
int n = a.size();
for(int i = 0;i < n-1;i++){
if(a[i] == a[i+1]){
i++;
cout << i << " " << i+1 << endl;
return 0;
}
if(i != n-2 && a[i] == a[i+2]){
i++;
cout << i << " " << i+2 << endl;
... | ### Prompt
Please create a solution in Cpp to the following problem:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <bits/stdc++.h>
using namespace std;
int main(){
string s; cin>>s;
for(int i=0; i<s.size()-2; i++){
if(s[i] == s[i+1] || s[i+2] == s[i+1] || s[i] == s[i+2]){
cout<<i+1<<" "<<i+3<<endl;
return 0;
}
}
if(s.size() == 2 && s[0] == s[1]){
cout<<1<<" "<<2<<endl;
... | ### Prompt
Develop a solution in cpp to the problem described below:
Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.
You are given a ... |
#include <string>
#include <iostream>
using namespace std;
/*
<expr> ::= <term> [ ('+'|'-') <term> ]*
<term> ::= <factor> [ ('*'|'/') <factor> ]*
<factor> ::= <number> | '(' <expr> ')'
<number> :== 1?????\????????°???
*/
int expr(string& s, int& i);
int term(string& s, int& i);
int factor(string& s, int& ... | ### Prompt
Generate a Cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, subtr... |
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int num(string&, int&);
int fact(string&, int&);
int mul(string&, int&);
int expr(string&, int&);
int num(string &s, int &k) {
int ret = 0;
while ('0' <= s[k] && s[k] <= '9') {
ret *= 10;
ret += s[k] - '0';
k ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include <iostream>
#include <sstream>
using namespace std;
int pos;
string str;
int str_to_int(string str) {
if (str == "") return 0;
int ret = 0;
stringstream ss;
ss << str;
ss >> ret;
return ret;
}
int keisan();
int kou();
int number();
int keisan() {
int left = kou();
while (str[pos] != '=' && str[... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include<bits/stdc++.h>
using namespace std;
#define int long long
int expression(string,int&);
int term(string,int&);
int factor(string,int&);
int number(string,int&);
bool f;
int expression(string s,int& p){
int res=term(s,p);
while(p<(int)s.size()){
if(s[p]=='+'){
p++;
res+=term(s,p);
con... | ### Prompt
Construct a cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include <string>
#include <cctype>
#include <iostream>
using namespace std;
typedef string::const_iterator State;
class ParseError{};
int number(State&);
int term(State&);
int expression(State&);
int factor(State&);
int number(State& begin){
int ret = 0;
while(isdigit(*begin)){
ret*=10;
ret+=*begin-'0';
... | ### Prompt
Create a solution in CPP for the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, sub... |
#include <iostream>
#include <vector>
#include <sstream>
#include <cctype>
using namespace std;
typedef string::const_iterator State;
int factor(State &begin);
int number(State &begin) {
int ret = 0;
while(isdigit(*begin)) {
ret *= 10;
ret += *begin - '0';
begin++;
}
return ret;
}
int term(State &begin)... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include <cstdio>
#include <string>
#include <algorithm>
#include <iostream>
using namespace std;
typedef string::iterator State;
bool isdigit(State& pos);
int number(State& pos);
int factor(State& pos);
int expression(State& pos);
int term(State& pos);
bool isdigit(State& pos)
{
if('0'<=*pos&&*pos<='9')return true;... | ### Prompt
Create a solution in Cpp for the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, sub... |
#include<iostream>
#include<string>
#include<map>
using namespace std;
#define ans pair<int, int>
ans equation(string s, int p = 0);
ans factor(string s, int p = 0);
ans term(string s, int p = 0);
int main(){
int n;
cin >>n;
while(n--){
string s;
cin >>s;
ans r = equation(s);
cout <<r.first<<endl;... | ### Prompt
Develop a solution in CPP to the problem described below:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include<iostream>
#include<string>
#include<cmath>
using namespace std;
void select_cal(char c, int *tmp, int val){
if(c == '+') *tmp += val;
else if(c == '-') *tmp -= val;
else if(c == '*') *tmp = floor(*tmp * val);
else if(c == '/' && val != 0) *tmp = floor(*tmp / val);
}
int calculation(string str, int len,... | ### Prompt
In cpp, your task is to solve the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, su... |
#include<iostream>
#include<string>
#include<ctype.h>
std::string s;
std::string::iterator it;
int term();
int fact();
// 計算
int expr()
{
int p = term();
// + or -
while( *it == '+' || *it == '-' ){
if( *it == '+' ){
it++;
int q = term();
p += q;
}
else{
it++;
int q = term();
p -= q;... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include <bits/stdc++.h>
using namespace std;
int p;
string s;
int number();
int factor();
int term();
int expression(){
int num=term();
while(s.size()>p){
if(s[p]=='+'){
p++;
num+=term();
}else if(s[p]=='-'){
p++;
num-=term();
}else{
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include<string>
#include<cstdlib>
#include<iostream>
using namespace std;
int prior[128];
int parse(string s)
{
if(s[0]=='(' && s[s.length()-1]==')'){
bool f=true;
for(int i=1,d=1;i<s.length()-1;i++){
if (s[i]=='(') d++;
else if(s[i]==')') d--;
if(d==0){ f=false; break; }
}
if(f) return parse(... | ### Prompt
Please create a solution in CPP to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <string>
#include <iostream>
#include <cassert>
#include <cctype>
using namespace std;
#define REP(i,b,n) for(int i=b;i<n;i++)
#define rep(i,n) REP(i,0,n)
string S = "3*(12+3)";
size_t cur = 0;
int expression();
int digit() {
assert(isdigit(S[cur]));
int n = S[cur] - '0';
cur++;
return n;
}
int nu... | ### Prompt
Please create a solution in CPP to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
typedef string::const_iterator State;
int expression(State&);
int term(State&);
int number(State&);
int factor(State&);
int expression(State &begin){
int ret = term(begin);
for(;;){
if(*begin == '+'){
++begin;
ret += term(begin);
... | ### Prompt
Construct a cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include <cstdio>
#include <cctype>
using namespace std;
char s[111];
int cur,len;
int shiki();
int kazu()
{
if( s[cur] == '(' ) {
cur += 1;
int s = shiki();
cur += 1;
return s;
} else {
int a = s[cur]-'0';
cur += 1;
while( isdigit(s[cur]) ) {
a *= 10;
a += s[cur]-'0';
... | ### Prompt
Please create a solution in CPP to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <stdio.h>
#include <vector>
#include <iostream>
#include <math.h>
#include <algorithm>
#include <cstring>
#include <string>
using namespace std;
using ll = long long;
string str;
int id;
int expr();
int number(){
int res = 0;
for (; isdigit(str[id]); id++) {
res *= 10;
res += str[id] - '0';
}
... | ### Prompt
Your task is to create a cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, a... |
#include <bits/stdc++.h>
#define REP(i,n) for(int i=0;i<(int)(n);i++)
#define ALL(x) (x).begin(),(x).end()
#define LL long long
using namespace std;
typedef string::const_iterator State;
class ParseError{};
int factor(State &begin);
int number(State &begin){
int ret=0;
while(isdigit(*begin)){
ret*=1... | ### Prompt
Please create a solution in CPP to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <iostream>
#include <string>
#include <algorithm>
#include <cctype>
using namespace std;
int expression(void);
string str;
int pos;
int factor(void){
int num = 0;
if( isdigit( str[pos] ) ){ // '0' <= str[pos] && str[pos] <= '9'
while( isdigit( str[pos] ) ){
num *= 10;
num += str[pos] ... | ### Prompt
Create a solution in cpp for the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, sub... |
#include <iostream>
#include <cctype>
#include<cassert>
using namespace std;
size_t cur=0;
string S;
int digit(){
assert(isdigit(S[cur]));
int n=S[cur]-'0';
cur=cur+1;
return n;
}
int number(){
int n=digit();
while(cur<S.size() && isdigit(S[cur])){
n=n*10+digit();
}
return n;
}
int expression();
int factor(... | ### Prompt
In Cpp, your task is to solve the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, su... |
#include<bits/stdc++.h>
using namespace std;
typedef string::const_iterator State;
class ParseError{};
int expr(State& begin);
int term(State& begin);
int number(State& begin);
int fact(State& begin);
int number(State& begin){
int res = 0;
while(isdigit(*begin)){
res *= 10;
res += *begin - '0'... | ### Prompt
Please formulate a cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <iostream>
#include <string>
#include <cstring>
#include <cctype>
using namespace std;
typedef string::iterator si;
int expr(si& cur, si end);
int num(si& cur, si end){
int ans = 0;
while(cur != end && isdigit(*cur)){
ans *= 10;
ans += *cur-'0';
cur++;
}
return ans;
... | ### Prompt
Develop a solution in CPP to the problem described below:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <iostream>
#include <cmath>
#include <vector>
#include <cctype>
#include <algorithm>
using namespace std;
int expr();
int term();
int fact();
char *p;
char inp[101];
int main(){
int n;
cin >> n;
cin.ignore();
while (n--){
cin.getline(inp, sizeof(inp));
p = inp;
cout << expr() << endl;
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include <bits/stdc++.h>
using namespace std;
int exp(string&, int&);
int term(string&, int&);
int factor(string&, int&);
int exp(string& str, int& p){
int res = term(str, p);
while(str[p] == '+' || str[p] == '-'){
if(str[p] == '+'){
p++;
res += term(str, p);
}else{
p++;
res -= ter... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cctype>
#include <cstdio>
using namespace std;
typedef long long ll;
typedef string::const_iterator State;
#define rep(i,n) for(int i=0;i<(n);i++)
class Parser{
public:
int expression(State &begin){
int ret = term(begin);
for(;... | ### Prompt
Create a solution in cpp for the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, sub... |
#include <iostream>
#include <string>
using namespace std;
int calc1();
int calc2();
int calc3();
int p;
string eq;
int calc1() {
int a = calc2();
while (eq[p]=='+' || eq[p]=='-') {
if (eq[p]=='+') {
p++;
a += calc2();
} else if (eq[p]=='-') {
p++;
a -= calc2();
}
}
return... | ### Prompt
Please create a solution in cpp to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include<iostream>
#include<string>
using namespace std;
int exp();
int term();
int factor();
string str;
int p;
int factor(){
int val=0;
while(str[p]>='0' && str[p]<='9'){
val*=10;
val+=str[p]-'0';
p++;
}
if(val!=0) return val;
else if(str[p]=='('){
p++;
val=exp();
}
if(str[p]==')... | ### Prompt
Please formulate a CPP solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <cmath>
#include <cassert>
#include <iostream>
using namespace std;
string S;
size_t cur = 0;
int digit() {
int n;
assert(isdigit(S[cur]));
n = S[cur] -'0';
++cur;
return n;
}
int number() {
int n = digit();
while (cur < S.size() && isdigit(S[cur])) {
n = n*10 + digit();
}
return n;
}
int expre... | ### Prompt
Your task is to create a CPP solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, a... |
#include <stdio.h>
#include <assert.h>
char buf[128];
int pos;
#define NOW (buf[pos])
bool isdigit(char c) {
return ('0' <= c && c <= '9');
}
int digit() {
if ( !isdigit(NOW) ) {
fprintf(stderr, "%c: ", NOW);
assert( isdigit(NOW) );
}
int ret = NOW - '0';
pos++;
return ret;
}
int number() {
int ret = di... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include <iostream>
#include <string>
using namespace std;
typedef pair<int, int> result;
#define value first
#define p second
result equation(const string &s, int p = 0);
result factor(const string &s, int p = 0);
result term(const string &s, int p = 0);
result equation(const string &s, int p) {
result r = factor(... | ### Prompt
Construct a cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include <iostream>
#include <cassert>
#include <cctype>
using namespace std;
string S;
size_t cur = 0;
int term();
int factor();
int expression();
int digit(){
assert(isdigit(S[cur]));
int n = S[cur] - '0';
cur = cur + 1;
return n;
}
int number(){
int n = digit();
while(cur<S.size() && isdigit(S[cur]))
n = n... | ### Prompt
Construct a cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include <bits/stdc++.h>
#define endl '\n'
using namespace std;
int expr(string& s, int& i);
int term(string& s, int& i);
int factor(string& s, int& i);
int number(string& s, int& i);
int expr(string& s, int& i) {
int val = term(s, i);
while (s[i] == '+' || s[i] == '-') {
char op = s[i];
++i;
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
#include<iostream>
#include<vector>
#include<algorithm>
#include<string>
using namespace std;
int expression();
int term();
int factor();
int number();
int now;
string s;
int expression(){
int res=term();
while(true){
if(s[now]=='+')now++,res+=term();
else if(s[now]=='-')now++,res-=t... | ### Prompt
Generate a cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, subtr... |
#include <iostream>
#include <string>
#include <cctype>
#include <cassert>
using namespace std;
string Str;
unsigned int cur = 0;
int digit();
int number();
int term();
int facter();
int expression();
int main()
{
int n;
cin >> n;
for (int i = 0; i < n; i++) {
cur = 0;
cin >> Str;
... | ### Prompt
In CPP, your task is to solve the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, su... |
#include <iostream>
using namespace std;
int cal(string&);
int expression(string&, int&);
int kou(string&, int&);
int num(string&, int&);
int cal(string& s) {
int pos = 0;
return expression(s, pos);
}
int expression(string& s, int& pos) {
int left = kou(s, pos);
while (1) {
char op = s[pos++];
if (op == '+')... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represent... |
#include <bits/stdc++.h>
using namespace std;
typedef string::const_iterator State;
class ParseError {};
struct Parser {
int number(State &begin) {
int ret = 0;
while(isdigit(*begin)) {
ret *= 10;
ret += *begin - '0';
begin++;
}
return ret;
}
int factor(State &begin) ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, a... |
#include <iostream>
#include <cctype>
#include <cassert>
using namespace std;
string S;
int cur;
int expression();
char readerchar()
{
assert(cur < S.size());
char ret = S[cur];
cur += 1;
return ret;
}
char peek()
{
assert(cur < S.size());
return S[cur];
}
int digit()
{
assert(isdigit(peek(... | ### Prompt
Develop a solution in cpp to the problem described below:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, additio... |
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
typedef string::const_iterator Iter;
int express(Iter &p);
int term(Iter &p);
int factor(Iter &p);
int number(Iter &p);
int express(Iter &p) {
int r = term(p);
for(;;) {
if(*p == '+') {
p++;
int rs = term(p);
r += rs;
}
el... | ### Prompt
Your task is to create a CPP solution to the following problem:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, a... |
#include "bits/stdc++.h"
#define int long long
#define range(i, a, b) for(int i = a; i < b; i++)
#define rep(i, a) range(i, 0, a)
#define all(a) (a).begin(),(a).end()
using namespace std;
const int MOD = 1e9 + 7, INF = 1e17;
using vi = vector <int>;
using vvi = vector <vi>;
//g++ -std==c++14
int expr(const char **);
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, ... |
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